6.824 2015 Lecture 2: Infrastructure: RPC and threads
Note: These lecture notes were slightly modified from the ones posted on the 6.824
course website from Spring 2015.
Remote Procedure Call (RPC)
- A key piece of distrib sys machinery; all the labs use RPC
- Goal: easy-to-program network communication
- hides most details of client/server communication
- client call is much like ordinary procedure call
- server handlers are much like ordinary procedures
- RPC is widely used!
RPC ideally makes net communication look just like an ordinary function call:
Client
------
z = fn(x, y)
Server
------
fn(x, y) {
compute
return z
}
RPC aims for this level of transparency
RPC message diagram
Client Server
------ ------
"fn", x, y
request ---------->
compute fn(x, y)
z = fn(x, y)
<------------- response
Software structure
Client Server
------ ------
client app handlers
stubs dispatcher
RPC lib RPC lib
net <-----------> net
Stubs are sort of the fake client-side functions that look like the real f(x, y)
but
they just take care of packaging the arguments, sending them over the
network and ask the server to compute f(x, y)
. The stub can then
receive the result over the network and return the value to the client
code.
Examples from lab 1:
A few details of RPC
- Marshalling: format data into packets
- Tricky for arrays, pointers, objects, etc.
- Go's RPC library is pretty powerful!
- some things you cannot pass/marshall: e.g., channels, functions
- Binding: how does client know who to talk to?
- Might be a name service -- e.g. DNS
- Threads:
- Client often has many threads, so
> 1
call outstanding, match up replies to calls
- Handlers may be slow, so server often runs each in a thread
RPC problem: what to do about failures?
- e.g. lost packets, broken network, crashed servers, slow servers
What does a failure look like to the client's RPC library?
- It never sees a response from the server
- It does not know if the server saw the request!
- Maybe server/net failed just before sending reply
Simplest scheme: "at least once" behavior
while true
send req
wait up to 10 seconds for reply
if reply arrives
return reply
else
continue
- RPC client library waits for response for a while
- If none arrives, re-send the request
- Do this a few times
- Still no response -- return an error to the application
Q: is "at least once" easy for applications to cope with?
Simple problem w/ at least once:
- Occurs with requests that are not side-effect free
- Client sends "deduct $10 from bank account" twice because
it did not hear back for the first one
More subtle problem: what can go wrong with this client program?
Put("k", "v")
overwrites the value at k
with v
Put("key", "value1")
-- an RPC to set key's value in a DB server
Put("key", "value2")
-- client then does a 2nd Put to same key
Example:
Client Server
------ ------
put k, 10
----\
\
put k, 20 ---------------------> k <- 20
\
-------------> k <- 10
get k --------------------->
10
<---------------------
Note: This situation where client sends a request, server does some work and
replies, but the reply is lost occurs frequently and will come up a lot
in labs.
Is at-least-once ever OK?
- Yes: if it's OK to repeat operations, e.g. read-only op
- Yes: if application has its own plan for detecting duplicates
- which you will need for Lab 1
Better RPC behavior: "at most once"
- Idea: server RPC code detects duplicate requests
- returns previous reply instead of re-running handler
- Client includes unique ID (XID) with each request
- uses same XID for re-send
- Server checks if XID has been seen before
Example:
if seen[xid]:
r = old[xid]
else
r = handler()
old[xid] = r
seen[xid] = true
Some at-most-once complexities
- How to ensure XID is unique?
- big random number?
- combine unique client ID (ip address?) with sequence #?
- Server must eventually discard info about old RPCs
- When is discard safe?
- Idea:
- unique client IDs
- per-client RPC sequence numbers
- client includes "seen all replies
<= X
" with every RPC
much like TCP sequence #s and ACKs
- or only allow client one outstanding RPC at a time s.t.
arrival of
seq+1
allows server to discard all <= seq
- or client agrees to keep retrying for
< 5
minutes
server discards after 5+ minutes
- How to handle duplicate request while original is still executing?
- Server doesn't know reply yet; don't want to run twice
- Idea: "pending" flag per executing RPC; wait or ignore
What if an at-most-once server crashes?
- if at-most-once duplicate info in memory, server will forget
- and accept duplicate requests
- maybe it should write the duplicate info to disk?
- maybe replica server should also replicate duplicate info?
What about "exactly once"?
- at-most-once semantics plus unbounded retries plus fault-tolerant service
Go RPC is "at-most-once"
- open TCP connection
- write request to TCP connection
- TCP may retransmit, but server's TCP will filter out duplicates
- no retry in Go code (i.e. will NOT create 2nd TCP connection)
- Go RPC code returns an error if it doesn't get a reply
- perhaps after a timeout (from TCP)
- perhaps server didn't see request
- perhaps server processed request but server/net failed before reply came back
Go's at-most-once RPC isn't enough for Lab 1
- it only applies to a single RPC call
- if worker doesn't respond, the master re-sends to it to another worker
- but original worker may have not failed, and is working on it too
- Go RPC can't detect this kind of duplicate
- No problem in lab 1, which handles at application level
- In lab 2 you will have to protect against these kinds of duplicates
Threads
- threads are a fundamental server structuring tool
- you'll use them a lot in the labs
- they can be tricky
- useful with RPC
- called goroutines in Go
Thread = "thread of control"
- threads allow one program to (logically) do many things at once
- the threads share memory
- each thread includes some per-thread state:
- program counter, registers, stack
Threading challenges:
- sharing data between thread
- what if two threads modify same variable at same time?
- what if one thread reads data another thread is changing?
- these problems are often called races
- need to protect invariants on shared data (Go: mutex)
- coordination between threads (Go: channels)
- e.g. wait for all Map threads to finish
- deadlocks
- thread 1 is waiting for thread 2
- thread 2 is waiting for thread 1
- easy detectable (unlike races)
- lock granularity
- goarse-grained
->
little concurrency/parallelism
- fine-grained
->
lots of concurrency, but race and deadlocks
- let's look at a toy RPC package to illustrate these problems
Look at today's handout -- l-rpc.go
Get it here.
- it's a toy RPC system
- illustrates threads, mutexes, channels
- it's a toy
- assumes connection already open
- only supports an integer arg, integer reply
- doesn't deal with errors
struct ToyClient
- client RPC state
- mutex per
ToyClient
- connection to server (e.g. TCP socket)
- xid -- unique ID per call, to match reply to caller
pending[]
-- multiple threads may call, need to find them
- channel on which caller is waiting
Call()
- application calls
reply := client.Call(procNum, arg)
procNum
indicates what function to run on server
WriteRequest
knows the format of an RPC msg
- basically just the arguments turned into bits in a packet
- Q: why the mutex in
Call()
? what does mu.Lock()
do?
- Q: could we move
xid := tc.xid
outside the critical section?
- after all, we are not changing anything
- [See diagram below]
- Q: do we need to
WriteRequest
inside the critical section?
- note: Go says you are responsible for preventing concurrent map ops
- that's one reason the update to pending is locked
Diagram:
Listener()
- runs as a background thread
- what is
<-
doing?
- not quite right that it may need to wait on chan for caller
Back to Call()
...
Q: what if reply comes back very quickly?
- could
Listener()
see reply before pending[xid]
entry exists?
- or before caller is waiting for channel?
Q: should we put reply := <-done
inside the critical section?
- why is it OK outside? after all, two threads use it.
Q: why mutex per ToyClient
, rather than single mutex per whole RPC pkg?
Server's Dispatcher()
- note that the Dispatcher echos the xid back to the client
- so that
Listener
knows which Call to wake up
- Q: why run the handler in a separate thread?
- Q: is it a problem that the dispatcher can reply out of order?
main()
- note registering handler in
handlers[]
- what will the program print?
When to use shared memory (and locks) vs when to use channels?
- here is my opinion
- use channels when you want one thread to explicitly wait for another
- often wait for a result, or wait for the next request
- e.g. when client
Call()
waits for Listener()
- use shared memory and locks when the threads are not intentionally
- directly interacting, but just happen to r/w the same data
- e.g. when
Call()
uses tc.xid
Go's "memory model" requires explicit synchronization to communicate!
This code is not correct:
var x int
done := false
go func() { x = f(...); done = true }
while done == false { }
It's very tempting to write, but the Go spec says it's undefined
use a channel or sync.WaitGroup
instead
Study the Go tutorials on goroutines and channels.