Suppose we wait 100 ns...

T = 100 ns

Probability of failure =

p( |Vin(0)| < e-T/t ) = e-T/t

A

A

t = 1 ns

A = 10

Probability of failure =

e-100

10

= 3.72 x 10-45

At 108 input samples per second,

one failure every 1030 years!

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