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Let Xi=1 if trial i is
a failure, else 0
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Let X = X1 +
… + Xt
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Then E[X] = t FAIL(p)
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Chernoff says X within relative e
of E[X]
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with probability
1-exp(e2 t FAIL(p)/4)
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So choose t to cancel other terms
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“High
probability” t
= O(log n / e2FAIL(p))
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Deviation by e probability < 1 / n
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