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Break edges into c /r random groups
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Each
looks like a sample at rate r / c
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O*( rm / c) edges
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each has min
expected cut r
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so theorem says
min-cut (1 – e) r
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So each has a
packing of size (1 – e) r
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[Gabow]
finds in time O*(r2m/c) per group
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so
overall time is c × O*(r2m/c) = O*(r2m)
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