Few Samples Needed
l
Suppose
k
clauses
l
Then
E
[sample] >
1/
k
»
1
£
satisfied clauses
£
k
»
1
³
sample value
³
1
/
k
l
Adding
O
(
k
log
n
/
e
2
)
samples gives
“large” mean
l
So Chernoff says sample mean is
probably good estimate