IndexTAG: 0
TitleTAG: omitted one letter from my middle name
Hello,
I have just log in and I saw that I have omitted one letter from my middle name. I have updated my name one left hand side but this did not change my name on the certificate. Do you know who I can contact regarding this?
Many thanks!!!
UserIdTAG: 1034281
UserNameTAG: mariyaracheva
CreateTimeTAG: 2013-04-08T18:41:10Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1
TitleTAG: wrong name prined
I have received my stat 2.1x certificate of course completion but my name is printed incorrectly and i do not know where to email for the rectification of the error..it would be really a great help if someone can tell me where i can email them regarding the error and its correction . thank you !
UserIdTAG: 1240577
UserNameTAG: tarunkhelani
CreateTimeTAG: 2013-04-08T12:30:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Send an email to Berkeley-stat2x@edx.org
Cheers!
FirstChildUserIdTAG: 609882
FirstChildUserNameTAG: ivojulca
FirstChildCreateTimeTAG: 2013-04-08T14:40:29Z
FirstChildVoteTAG: 0
IndexTAG: 2
TitleTAG: Percentile scores for the program
Hi
Is there a percentile score sheet for this program. Curious to see the distribution and where I stand :)
Cheers
UserIdTAG: 1049940
UserNameTAG: skarora1
CreateTimeTAG: 2013-04-08T09:01:48Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 3
TitleTAG: Will the course be open again?
Unfortunately I've missed this course, I just knew it was taking place just too late.
I've already registered for 2.2 course, but it would be great to know whether this course will open again to have all the 2.1 2.2 and 2.3 certificates.
It would be great to know some news on the subject as soon as they are available.
Thanks =)
UserIdTAG: 580211
UserNameTAG: george_climent
CreateTimeTAG: 2013-04-07T17:48:06Z
VoteTAG: 91
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 4
TitleTAG: I started this course 2 days ago
Hello!
I have started this course 2 days ago but the course is finished. Should I continue to learn the course or wait the new one?
UserIdTAG: 1534857
UserNameTAG: Skoglund
CreateTimeTAG: 2013-04-06T19:00:58Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: that depends on why you want to do it! You won't get a certificate if you continue, but you can still access the lectures and the exercises.
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-04-06T21:46:25Z
FirstChildVoteTAG: 2
SecondChildTAG: What does the certificate give for opportunities?
SecondChildUserIdTAG: 1534857
SecondChildUserNameTAG: Skoglund
SecondChildCreateTimeTAG: 2013-04-07T15:40:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Whatever the employer wishes. It's obviously a plus.
SecondChildUserIdTAG: 609882
SecondChildUserNameTAG: ivojulca
SecondChildCreateTimeTAG: 2013-04-08T14:41:36Z
SecondChildVoteTAG: 0
IndexTAG: 5
TitleTAG: Total load
I need a document that especify the total load of the course (like 40 hours load) or the load per week (like 4 hour/week). Where can i find it?
UserIdTAG: 910035
UserNameTAG: fseabra
CreateTimeTAG: 2013-04-05T17:37:30Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 6
TitleTAG: Allow 2 places of decimals
I'm surprised that the program marked my answers wrong because I wrote 22.22 and 11.11 rather than only a single place of decimals.
Hmm. Would be nice to have that allowed.
Thanks.
UserIdTAG: 1540506
UserNameTAG: rnx
CreateTimeTAG: 2013-04-05T13:33:41Z
VoteTAG: 25
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: This is strange. I was writing in some cases even up to 3 decimals if I remember correctly. Definitely two at least. I never got an answer marked wrong because of the number of decimals I was using.
FirstChildUserIdTAG: 897233
FirstChildUserNameTAG: makmanos
FirstChildCreateTimeTAG: 2013-04-05T15:15:21Z
FirstChildVoteTAG: 1
SecondChildTAG: Same here, 3 or 4 decimals and never had any problem.
SecondChildUserIdTAG: 632581
SecondChildUserNameTAG: GMendes
SecondChildCreateTimeTAG: 2013-04-05T20:25:28Z
SecondChildVoteTAG: 0
FirstChildTAG: The first set of questions had dp issues. But as the course has finished, it's not an issue any more.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-05T21:39:04Z
FirstChildVoteTAG: 1
IndexTAG: 7
TitleTAG: how to write emphasized text on discussion forum posts?
Please tell, while quoting some previous text, how to add emphasis to the quote?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-05T05:24:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: **Click on bold like this** or add two * symbols before and afterwards **like this**
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-04-05T12:55:43Z
FirstChildVoteTAG: 0
IndexTAG: 8
TitleTAG: syllabus not mentioned on 'about stat2.2x page'
Although we all know that it covers probability and random samples, detailed syllabus is not mentioned on the page.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-05T05:16:22Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 9
TitleTAG: Credit for Prof A's performance
I would like to give credit to Prof A for the superb execution of this course. Not only you are a mathematician (which alone is a great compliment) but a great teacher as well.
Thanks as well for your noble contribution and kind intention of sharing your knowledge even without gaining the equivalent financial reward for all the efforts you've exerted. ;)
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-04T22:56:39Z
VoteTAG: 9
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Yes thank you. And I am enjoying the blog.
FirstChildUserIdTAG: 1252009
FirstChildUserNameTAG: Emilyjch
FirstChildCreateTimeTAG: 2013-04-05T14:01:05Z
FirstChildVoteTAG: 1
FirstChildTAG: yes a thousand times thank you, to prof. adhikari and prof. stark and all the other people involved for all the good knowledge they shared so generously!
looking very much forward to stat 2.2x! =)
kindest greetings from austria!
FirstChildUserIdTAG: 1243466
FirstChildUserNameTAG: anoetos
FirstChildCreateTimeTAG: 2013-04-06T18:11:55Z
FirstChildVoteTAG: 2
IndexTAG: 10
TitleTAG: Certificate
unfortunately I receive this message: Your final grade: 70%.
Your certificate is being held pending confirmation that the issuance of your certificate is in compliance with strict U.S. embargoes on Iran, Cuba, Syria and Sudan. If you think our system has mistakenly identified you as being connected with one of those countries, please let us know by contacting info@edx.org.
UserIdTAG: 631533
UserNameTAG: Ahmedelzaki
CreateTimeTAG: 2013-04-04T16:51:21Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Correct. This is stated on the edX help page.
>Will I get a certificate for taking an edX course?
>Online learners who receive a passing grade for a course will receive a certificate of mastery at the discretion of edX and the underlying X University that offered the course. For example, a certificate of mastery for MITx’s 6.002x Circuits & Electronics will come from edX and MITx.
>If you passed the course, your certificate of mastery will be delivered online through edx.org. So be sure to check your email in the weeks following the final grading – you will be able to download and print your certificate. Note: At this time, edX is holding certificates for learners connected with Cuba, Iran, Syria and Sudan pending confirmation that the issuance is in compliance with U.S. embargoes.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-04-04T19:59:56Z
FirstChildVoteTAG: 2
FirstChildTAG: I am really sorry to hear that Ahmed. There should be no barriers to learning in this world.
I am not sure how EDX figures out that you are in one of these countries. Perhaps it is by your IP address? Do you have a trusted friend in a US friendly country that you could give your login details to? There might be a chance that they could download your certificate and then email it to you.
Ta much
FirstChildUserIdTAG: 1265802
FirstChildUserNameTAG: GMORRIS010
FirstChildCreateTimeTAG: 2013-04-05T09:18:45Z
FirstChildVoteTAG: 3
SecondChildTAG: Evading or trying to evade these international embargoes is a really bad idea, and probably a serious crime. It is possible that it will be legally determined that the embargoes don't apply to the certificates, so why not wait for that legal determination.
SecondChildUserIdTAG: 1284385
SecondChildUserNameTAG: EdMeasure
SecondChildCreateTimeTAG: 2013-04-08T10:40:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, thanks for your advice. If anyone wants me to get their certificates for them, I'm happy to do it.
Its a shit law designed to aid US imperialism, and as such it is a moral obligation for people around the world to circumvent it.
SecondChildUserIdTAG: 1265802
SecondChildUserNameTAG: GMORRIS010
SecondChildCreateTimeTAG: 2013-04-08T12:10:33Z
SecondChildVoteTAG: 0
IndexTAG: 11
TitleTAG: CERTIFICATE VALUE
Dear Professors,
thank you for the interesting course.
Do you have an estimation of how many hours the course consist of?
Or there is any estimate of the amount of ECTS points?
Thanks a lot
Cristiano
UserIdTAG: 1245634
UserNameTAG: cris10zinasco
CreateTimeTAG: 2013-04-04T12:27:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Note that ECTS are specific to some universities in Europe only. Moreover, the value of ECTS points in terms of workload differ between universities. I don't think Berkeley teachers will be able to give any estimates.
My private estimate based on my alma mater (Wroclaw University of Technology) would be: 1 ECTS point for every 5-week section, that is: 1 ECTS point for Stat2.1x, 1 ECTS point for Stat2.2x and 1 ECTS point for Stat2.3x.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-04-05T19:16:15Z
FirstChildVoteTAG: 1
IndexTAG: 12
TitleTAG: Donation for future courses ?
Dear Prof Ani and all who helped to develop this course,
thanks a lot for what I learned the last 6 weeks.
Is there any way to make a donation to support future courses?
Best Regards
Axel
UserIdTAG: 148610
UserNameTAG: schwanke
CreateTimeTAG: 2013-04-04T10:27:58Z
VoteTAG: 13
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Good thought
FirstChildUserIdTAG: 142494
FirstChildUserNameTAG: jaria101
FirstChildCreateTimeTAG: 2013-04-05T19:06:14Z
FirstChildVoteTAG: 0
IndexTAG: 13
TitleTAG: Not received the certificate yet :(
I did not get my certificate till now...will it take time.
Regards,
Rakesh
UserIdTAG: 979449
UserNameTAG: rak_003
CreateTimeTAG: 2013-04-04T06:10:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Did you watch your [dashboard][1]? It should have a link "Download Your PDF Certificate".
[1]: https://www.edx.org/dashboard
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-04-04T07:21:08Z
FirstChildVoteTAG: 1
SecondChildTAG: yhh! just click **dashboard** above.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-04-04T08:31:33Z
SecondChildVoteTAG: 0
FirstChildTAG: not gotten my certificate yet
FirstChildUserIdTAG: 627596
FirstChildUserNameTAG: achile
FirstChildCreateTimeTAG: 2013-04-06T22:29:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Have you looked on your dashboard? As has been said, there is a link to the certificate. If you qualified.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-04-06T23:52:54Z
SecondChildVoteTAG: 0
IndexTAG: 14
TitleTAG: Got my Certificate!
I felt so happy and the same time thankful when I got my Stat2.1X certificate, and to those who have theirs too my congratulations...we did it and hope to you you all in Stat2.2X. To Prof. Ani Adhikari and the rest of the staffs who made this online course possible please accept my sincere gratitude.
UserIdTAG: 1041173
UserNameTAG: jobusta
CreateTimeTAG: 2013-04-03T22:54:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Unfortunately, I am not awarded a certificate! I scored the final score of 75%. I submitted midterm, final and all except one weekly assignments. Any idea about what went wrong???
FirstChildUserIdTAG: 807792
FirstChildUserNameTAG: bhandariramjee
FirstChildCreateTimeTAG: 2013-04-07T16:46:00Z
FirstChildVoteTAG: 1
IndexTAG: 15
TitleTAG: A unique course...with the chicks
Well, this has been a unique course...I (and I know there are others) got to talk of chick weight and chick size without being labelled a pervert or a moron.
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-04-03T18:52:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 16
TitleTAG: New name on the certificate
I accidentally wrote my user name in personal details, instead of my real name. I received certificate today, but i would like to have my real name on it. Can someone from the course staff help me with this issue? Thank you!
UserIdTAG: 1170216
UserNameTAG: IrenaG21
CreateTimeTAG: 2013-04-03T18:15:36Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Same issue! I wrote just my name, without surname. Then I changed my name and still wait for new Certificate!
FirstChildUserIdTAG: 1246063
FirstChildUserNameTAG: Jexi
FirstChildCreateTimeTAG: 2013-04-03T19:46:48Z
FirstChildVoteTAG: 2
SecondChildTAG: Did you send them any letter? If yes, could you, please, leave me the link? I already post same question on different pages, still waiting for any response...
SecondChildUserIdTAG: 1170216
SecondChildUserNameTAG: IrenaG21
SecondChildCreateTimeTAG: 2013-04-03T22:31:11Z
SecondChildVoteTAG: 0
SecondChildTAG: There is option to rewrite full name (right box on the dashboard) and when you try to do that you should to explain why do you change your name and why to change name in Certificate...
I will inform you when they change my name.
SecondChildUserIdTAG: 1246063
SecondChildUserNameTAG: Jexi
SecondChildCreateTimeTAG: 2013-04-04T03:53:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Did the same thing.. Thank you!
SecondChildUserIdTAG: 1170216
SecondChildUserNameTAG: IrenaG21
SecondChildCreateTimeTAG: 2013-04-04T08:40:40Z
SecondChildVoteTAG: 0
FirstChildTAG: You could try and email edX. However, remember that there are many thousands enrolled across multiple courses. They might well have a policy that says a certificate is only released once, unless there are technical issues that affected every certificate (as has happened in the past).
It would be a nightmare for them if even just 1% decided that they wanted a different name on their certificate.
The sign-up page tells you that your real name is required for the certificate. So you just might have to accept it, and make sure your name is correct for the next course.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-03T21:33:38Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you.. hopefully, I will receive a new certificate :)
SecondChildUserIdTAG: 1170216
SecondChildUserNameTAG: IrenaG21
SecondChildCreateTimeTAG: 2013-04-03T22:32:51Z
SecondChildVoteTAG: 0
IndexTAG: 17
TitleTAG: Thanks a lot
Dear Prof Ani and staff,
Thanks a lot for this great experience.
Regards
UserIdTAG: 918707
UserNameTAG: nishasandeepkumar
CreateTimeTAG: 2013-04-03T17:59:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 18
TitleTAG: Haven't received the certificate yet
Hi,
I do not have my certificate yet.. :(
Do i need to download it ? link please someone...
Thanks
UserIdTAG: 1325261
UserNameTAG: snehasoni
CreateTimeTAG: 2013-04-03T17:44:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: it's on ur dashboard of edx.
FirstChildUserIdTAG: 1004532
FirstChildUserNameTAG: goelamit05
FirstChildCreateTimeTAG: 2013-04-03T17:49:38Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks.. got it
SecondChildUserIdTAG: 1325261
SecondChildUserNameTAG: snehasoni
SecondChildCreateTimeTAG: 2013-04-03T18:40:44Z
SecondChildVoteTAG: 0
IndexTAG: 19
TitleTAG: Thank you, great teaching & great course!
Many thanks from Romania! Best statistics course I took so far, and great teaching (and I am sure, not easy to deal with the lot of us). Looking froward to Stat 2.2X!:)
UserIdTAG: 1216723
UserNameTAG: Darkennoia
CreateTimeTAG: 2013-04-03T16:22:38Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 20
TitleTAG: querry regarding late joining of course
hi everyone,
i joined this course 2 days ago and i want to know if i can complete it now and get a certificate later on completion of course?
UserIdTAG: 701545
UserNameTAG: pharma2012
CreateTimeTAG: 2013-04-03T16:11:09Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Stat2.1x is now closed. You are welcome to watch videos and participate in the practice exercises, but will not be able to generate credit for a certificate.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-04-03T16:38:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you read the message at the top of the screen?
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-03T21:36:55Z
FirstChildVoteTAG: 0
FirstChildTAG: As for now, no.
If it is ever going to be reoffered in the future, then yes, you may try again, but nobody knows if it is actually going to be reoffered.
Don't worry about the certificate too much. It is not worth official credit and isn't taken very seriously. The actual lectures and exercises are the most valuable things you'll get from this course. So, I would recommend you to follow it even if you won't get the certificate!
FirstChildUserIdTAG: 504958
FirstChildUserNameTAG: Mouen
FirstChildCreateTimeTAG: 2013-04-07T08:52:59Z
FirstChildVoteTAG: 0
IndexTAG: 21
TitleTAG: Certificate date
Course was great
just one thing
certificate date April 1st, 2013 - Fools' Day :-)
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-03T15:54:45Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Seriously, couldn't it be April 2nd????
FirstChildUserIdTAG: 321955
FirstChildUserNameTAG: pfialho
FirstChildCreateTimeTAG: 2013-04-03T17:23:10Z
FirstChildVoteTAG: 1
FirstChildTAG: Yeah, I didn't see that coming either
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-04-03T19:21:22Z
FirstChildVoteTAG: 0
FirstChildTAG: Does it really matter?
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-04-04T04:41:05Z
FirstChildVoteTAG: 0
IndexTAG: 22
TitleTAG: Thank you !
Thank you, edx team and Prof A.
Greetings from Mongolia :)
UserIdTAG: 205091
UserNameTAG: Bibby
CreateTimeTAG: 2013-04-03T14:35:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 23
TitleTAG: Thank you to all the staff!
I want to thank Prof. A and all the other people that made this course be possible. It is a great opportunity for us to learn and learn more. Thank you for giving your time for free. Greetings from Paraguay, South America.
UserIdTAG: 224530
UserNameTAG: Java_Systems
CreateTimeTAG: 2013-04-03T13:45:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi from Serbia. I agree with your remarks, Java
FirstChildUserIdTAG: 911813
FirstChildUserNameTAG: vukasinbvasic
FirstChildCreateTimeTAG: 2013-04-03T16:15:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you Prof. and all team for the wonderful course!!!
-Ramjee Bhandari (NEPAL)
SecondChildUserIdTAG: 807792
SecondChildUserNameTAG: bhandariramjee
SecondChildCreateTimeTAG: 2013-04-07T16:50:03Z
SecondChildVoteTAG: 0
IndexTAG: 24
TitleTAG: the best
the best explanation ever!!!!!!!!!!!!!
UserIdTAG: 639284
UserNameTAG: grcinica
CreateTimeTAG: 2013-04-03T13:00:18Z
VoteTAG: 0
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 0
IndexTAG: 25
TitleTAG: Thank you
Thanks to all the staff of Edx and specially for our mentors!
UserIdTAG: 874761
UserNameTAG: dejwold
CreateTimeTAG: 2013-04-03T11:31:09Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 26
TitleTAG: Many THANKS
Thanks to all of you, specially the great teachers,it was wonderful course.
UserIdTAG: 919422
UserNameTAG: tarwateanas
CreateTimeTAG: 2013-04-03T10:12:48Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 27
TitleTAG: Impressive
I am really impressed with the quality of education given. When I joined this course, I was not expecting so much. I am just impressed with the stuff I have learnt and understood.
thanks a lot to the edx team for this opportunity
UserIdTAG: 1276014
UserNameTAG: Edwose
CreateTimeTAG: 2013-04-03T09:53:38Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 28
TitleTAG: thank you and congratulations
helo from Puerto Montt a rainy southern chilean city,well i only wanted to say thank you to all the staff, and congratulations because the course was a demonstration of knowledege, empathy and teamwork, so that see you at 2.2 .
UserIdTAG: 335901
UserNameTAG: moralmo
CreateTimeTAG: 2013-04-03T07:24:43Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Oooooooooooooooooooooooooooooooo, beautiful, thank so much.
We cannot wait for the next part. Let s go!
FirstChildUserIdTAG: 911813
FirstChildUserNameTAG: vukasinbvasic
FirstChildCreateTimeTAG: 2013-04-03T10:28:38Z
FirstChildVoteTAG: 0
IndexTAG: 29
TitleTAG: Hola
hola
UserIdTAG: 1517366
UserNameTAG: Mario18
CreateTimeTAG: 2013-04-03T06:56:40Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 30
TitleTAG: Gratitude rising at exponential growth
Thank you so much, I am just a kid and I received a certificate for something. I have to admit it makes me feel special. Thank you for exposing me to such a wonderful branch of mathematics.
UserIdTAG: 990423
UserNameTAG: George95
CreateTimeTAG: 2013-04-03T04:51:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Congratulations George :-) you must be really smart to get a certificate on this stats course! You can be a statistician when you grow up! :-)
FirstChildUserIdTAG: 1264070
FirstChildUserNameTAG: XenDavid
FirstChildCreateTimeTAG: 2013-04-03T15:55:45Z
FirstChildVoteTAG: 0
IndexTAG: 31
TitleTAG: Finally, The Certificate goes to Indonesia. Thanks to Prof A and the staff of BerkeleyX.
Thanks to Prof A and staff for the great course. And the certificate is in my hand now. and im so happy when i see it at the first time. a wow... thank you so much
UserIdTAG: 1193006
UserNameTAG: makmursp
CreateTimeTAG: 2013-04-03T04:38:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: congratulations! but why i just got the PDF certificate from the dashboard?
FirstChildUserIdTAG: 1391692
FirstChildUserNameTAG: elaine_wong
FirstChildCreateTimeTAG: 2013-04-03T10:59:18Z
FirstChildVoteTAG: 0
SecondChildTAG: You won't get a hard copy.
SecondChildUserIdTAG: 157670
SecondChildUserNameTAG: _Nelson_
SecondChildCreateTimeTAG: 2013-04-03T11:25:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Because that is how edX delivers the certificate. This is clearly explained in the edX policies.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-04-03T21:38:13Z
SecondChildVoteTAG: 0
SecondChildTAG: lol. i printed it out
SecondChildUserIdTAG: 1193006
SecondChildUserNameTAG: makmursp
SecondChildCreateTimeTAG: 2013-04-05T03:40:41Z
SecondChildVoteTAG: 0
IndexTAG: 32
TitleTAG: wow I pass Stat2.1X
wow wow I pass Stat2.1X getting 53%.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-03T04:10:14Z
VoteTAG: 4
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 1
FirstChildTAG: congratulations! :-) I feel happy for everyone who passed.
FirstChildUserIdTAG: 1264070
FirstChildUserNameTAG: XenDavid
FirstChildCreateTimeTAG: 2013-04-03T15:54:49Z
FirstChildVoteTAG: 0
IndexTAG: 33
TitleTAG: THANKS
It would be possible to put the equivalent in the certificates of study hours, here in my country are taken into account which have from 40 hours and more. The most important thing is learning, but than great get my certificate, ready for start edx 2.2
UserIdTAG: 1024935
UserNameTAG: N3
CreateTimeTAG: 2013-04-03T02:56:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thank you Dr Adhikari and all the faculty and staff! Its a wonderful course- I'm finally loving Biostatistics, which once used to scare me!
See you in Stats 2.2. Looking forward to a great experience!
menaal
FirstChildUserIdTAG: 498305
FirstChildUserNameTAG: menaal
FirstChildCreateTimeTAG: 2013-04-03T03:04:22Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you very much Dr.Adhikari and all other staff members ,and i'm looking forward to stat 2.2X .i think it will also a great experience.
Mass
SecondChildUserIdTAG: 1322084
SecondChildUserNameTAG: massuom
SecondChildCreateTimeTAG: 2013-04-03T04:34:29Z
SecondChildVoteTAG: 0
IndexTAG: 34
TitleTAG: Certificate arrived! Too bad this is not graded, but many thanks anyway!
Got a 94% grade.
Fantastic course and videos!
Without them, probably would have got less than 35%.
Cheers Prof Ani and see you in Stat2.2x
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-04-03T01:39:32Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: April 1st.
FirstChildUserIdTAG: 911813
FirstChildUserNameTAG: vukasinbvasic
FirstChildCreateTimeTAG: 2013-04-03T10:55:13Z
FirstChildVoteTAG: 0
FirstChildTAG: congratulations on your 94% Zacharie :-)
FirstChildUserIdTAG: 1264070
FirstChildUserNameTAG: XenDavid
FirstChildCreateTimeTAG: 2013-04-03T15:54:02Z
FirstChildVoteTAG: 1
IndexTAG: 35
TitleTAG: Got My certificate :-)
Thanks to you, edx !!!
Thank you so much, Prof Ani.
UserIdTAG: 898014
UserNameTAG: sundie
CreateTimeTAG: 2013-04-02T23:08:31Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Me too! Great! Thank you all for organizing such an interesting course.
FirstChildUserIdTAG: 1255577
FirstChildUserNameTAG: MiguelVG
FirstChildCreateTimeTAG: 2013-04-03T00:47:10Z
FirstChildVoteTAG: 3
SecondChildTAG: Thank you all,It was a great course.
Please,how can I get my certificate,?
SecondChildUserIdTAG: 918847
SecondChildUserNameTAG: Shibo97
SecondChildCreateTimeTAG: 2013-04-03T07:44:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Wait a few days/hours. You will see in your homepage of EDX, under the icon to enter to the course Stat2.1x a new link to get your certificate. It will be clearly visible, so you will notice. If you don't see the link in the next few days, maybe it is because you are not over the 35% of the students
SecondChildUserIdTAG: 1255577
SecondChildUserNameTAG: MiguelVG
SecondChildCreateTimeTAG: 2013-04-03T14:01:37Z
SecondChildVoteTAG: 0
FirstChildTAG: thank you, edx team and Prof A.
FirstChildUserIdTAG: 346234
FirstChildUserNameTAG: kavita2012
FirstChildCreateTimeTAG: 2013-04-03T09:45:09Z
FirstChildVoteTAG: 1
IndexTAG: 36
TitleTAG: New statistics course on Coursera
The coursera introductory statistics course has started:
https://www.coursera.org/course/introstats
From what I have seen so far, it is going to be fun!
UserIdTAG: 99863
UserNameTAG: pramode_ce
CreateTimeTAG: 2013-04-02T18:13:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Coursera has a lot of course they are really good. I already doing this course.
FirstChildUserIdTAG: 334968
FirstChildUserNameTAG: MCGEEC147
FirstChildCreateTimeTAG: 2013-04-02T20:08:53Z
FirstChildVoteTAG: 0
IndexTAG: 37
TitleTAG: mathematics
Well MIT cw is an alternative. Now you should get a head start on some theoretical math and physics. Game theory, linear geometry, quantum computation, etc
UserIdTAG: 990423
UserNameTAG: George95
CreateTimeTAG: 2013-04-02T15:38:34Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I made a post instead of a comment, sorry
FirstChildUserIdTAG: 990423
FirstChildUserNameTAG: George95
FirstChildCreateTimeTAG: 2013-04-02T15:40:06Z
FirstChildVoteTAG: 0
SecondChildTAG: You can delete and re-post in the right place, if you want.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-04-02T18:55:50Z
SecondChildVoteTAG: 0
IndexTAG: 38
TitleTAG: Query about the certificate
Hello everyone. I have successfully completed my stat course but haven't received the certificate on my mail yet. Has anyone of you got the mail?
UserIdTAG: 1142471
UserNameTAG: sanabhat
CreateTimeTAG: 2013-04-02T14:30:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Even i didn't get the certificate.
just waiting for it!
FirstChildUserIdTAG: 994416
FirstChildUserNameTAG: 97524059501
FirstChildCreateTimeTAG: 2013-04-02T14:39:23Z
FirstChildVoteTAG: 0
SecondChildTAG: log on to edx, you should be able to see the download link to your certificate on the dashboard by now:: .
SecondChildUserIdTAG: 439981
SecondChildUserNameTAG: enom200
SecondChildCreateTimeTAG: 2013-04-03T00:26:08Z
SecondChildVoteTAG: 0
SecondChildTAG: i have and got 67%. its not graded. but its ok..
SecondChildUserIdTAG: 1193006
SecondChildUserNameTAG: makmursp
SecondChildCreateTimeTAG: 2013-04-03T04:41:12Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't think anyone's received theirs yet, but I have another question: who pay$ to send out all of these certificates? 30 to 40,000 times postage adds up pretty quick.
FirstChildUserIdTAG: 950367
FirstChildUserNameTAG: catt9
FirstChildCreateTimeTAG: 2013-04-02T14:41:07Z
FirstChildVoteTAG: 0
SecondChildTAG: Betcha it's an e-mailed pdf file or such like ... saves on postage and you can print it if you want to ... I don't expect it before April 15th.
SecondChildUserIdTAG: 1287965
SecondChildUserNameTAG: ReadeDavis
SecondChildCreateTimeTAG: 2013-04-02T15:09:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I completed a programming course through MIT a while back and it was a pdf that I could download from the site, with an authentication web address to prove it's not just a reproduced certificate
SecondChildUserIdTAG: 77753
SecondChildUserNameTAG: ChrisC
SecondChildCreateTimeTAG: 2013-04-02T15:10:52Z
SecondChildVoteTAG: 0
FirstChildTAG: The certificate can be downloaded from the edX Dashboard. There will be a link/button where it currently says 'View Course'. (and this will also change to 'View Archived Course'). And it generally takes 1-2 weeks after the end of the course for edX to start issuing them.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-04-02T19:43:20Z
FirstChildVoteTAG: 0
FirstChildTAG: You will be waiting a long time. You have to download it yourself from your dashboard. It's there now.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-02T20:30:55Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi,
I got mine too.
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-04-03T07:17:05Z
FirstChildVoteTAG: 0
IndexTAG: 39
TitleTAG: [STAFF] Re Stat2.2x
Hello! Will the new course, Stat2.2x, provide an in depth understanding of experiment and analyses types like ANOVA? Thank you!
If no, I'd like to ask if such course may be offered here in edX this April to May 2013?
UserIdTAG: 16973
UserNameTAG: TerrEpic_Dude
CreateTimeTAG: 2013-04-02T14:16:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > in depth understanding of experiment and analyses types like ANOVA?
Basic probability according to the course description.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-02T20:32:20Z
FirstChildVoteTAG: 1
SecondChildTAG: Yep! I guess ANOVA and the like will be in Stat2.3x.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-04-02T22:42:11Z
SecondChildVoteTAG: 0
SecondChildTAG: The Online book referred in the class doesn't have ANOVA anywhere. So I don't think it will be covered.
http://www.stat.berkeley.edu/~stark/SticiGui/Text/reasoning.htm
SecondChildUserIdTAG: 752245
SecondChildUserNameTAG: GurmeetSaran
SecondChildCreateTimeTAG: 2013-04-03T08:14:01Z
SecondChildVoteTAG: 0
IndexTAG: 40
TitleTAG: Thank You Dear EDX and Professor A;
Thanks too much to edx.org for organizing such a wonderful opportunity for everyone in the world in search of knowledge. And thanks for the kind professor A.
UserIdTAG: 1119819
UserNameTAG: Hamraz
CreateTimeTAG: 2013-04-02T10:33:17Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 41
TitleTAG: Hello Dr Adhikari and everybody
hi every one i joined very late but iam very happy i joined this course.
thank you
UserIdTAG: 1515303
UserNameTAG: rajashekhark
CreateTimeTAG: 2013-04-02T09:39:22Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hi,
you shouldn't enroll in Stat2.1x. The course have finished last week. Instead, you may be interested in the second module of Stat2x, that begins next week: Stat2.2x (about probability):
https://www.edx.org/courses/BerkeleyX/Stat2.2x/2013_April/about
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-04-02T10:22:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks atopos! I have registered but not sure of pursuing it...I wish you good luck!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-04-02T10:54:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks atopos, I have registered See you soon.
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-04-02T12:26:12Z
SecondChildVoteTAG: 0
SecondChildTAG: See you, if I'm there. I hope!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-04-02T18:57:00Z
SecondChildVoteTAG: 0
FirstChildTAG: I would recommend you al least check Stat 2.1X to make sure that you're familiar with the material. Then when you do Stat 2.2X you will be sure to have the required background info....
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-04-04T01:02:44Z
FirstChildVoteTAG: 0
IndexTAG: 42
TitleTAG: Made my own plot!
Just thought I'd share a little scatterplot I made of July, 2012 Temperatures in Boston. For interest, I added the line of regression. The dataset was given to us in 6.00x just this week with a discussion of plotting charts and graphs. Fun stuff! Thanks Prof A.
![It's nice when courses intersect!][1]
[1]: https://edxuploads.s3.amazonaws.com/13648946485548295.png
This was done with Python using the PyLab module. I played around with custom objects all through the course to make it easier to crank out numbers based on our formulas. Can't wait to do Stat2.2!
UserIdTAG: 10241
UserNameTAG: bobok
CreateTimeTAG: 2013-04-02T09:26:06Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Good, what is the coefficient of determination of your line?
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-04-02T14:51:07Z
FirstChildVoteTAG: 0
SecondChildTAG: $R^2 = 0.56$
Here is my data:
Boston July Temperatures
-------------------------
Day High Low
------------
1 91 70
2 84 69
3 86 68
4 84 68
5 83 70
6 80 68
7 86 73
8 89 71
9 84 67
10 83 65
11 80 66
12 86 63
13 90 69
14 91 72
15 91 72
16 88 72
17 97 76
18 89 70
19 74 66
20 71 64
21 74 61
22 84 61
23 86 66
24 91 68
25 83 65
26 84 66
27 79 64
28 72 63
29 73 64
30 81 63
31 73 63
SecondChildUserIdTAG: 10241
SecondChildUserNameTAG: bobok
SecondChildCreateTimeTAG: 2013-04-02T19:53:51Z
SecondChildVoteTAG: 0
IndexTAG: 43
TitleTAG: Register with Stat 2.2x
The Stat 2.2x registration is open. I have just registered.
Steps to Register:
Short cut:
Goto https://www.edx.org/courses/BerkeleyX/Stat2.2x/2013_April/about
Click on Register.
Long way:
1) Login to edX
2) Dashboard top left -> Find Courses
link https://www.edx.org/courses
3) On the homepage or edX Scroll down and find the notice (see image below)
4) Click on the image to get to the About Stat2.2x page
5) Click on Register
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13648940481343622.png
UserIdTAG: 190804
UserNameTAG: rito
CreateTimeTAG: 2013-04-02T09:17:18Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 7
FirstChildTAG: Just signed up!
FirstChildUserIdTAG: 10241
FirstChildUserNameTAG: bobok
FirstChildCreateTimeTAG: 2013-04-02T09:34:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Just signed up :)
FirstChildUserIdTAG: 1053569
FirstChildUserNameTAG: nicola2003
FirstChildCreateTimeTAG: 2013-04-02T11:17:37Z
FirstChildVoteTAG: 0
FirstChildTAG: Just signed up. See you all soon
FirstChildUserIdTAG: 1002821
FirstChildUserNameTAG: Urimare
FirstChildCreateTimeTAG: 2013-04-02T12:27:38Z
FirstChildVoteTAG: 0
FirstChildTAG: i have just signed up.....expecting it will be more interesting
FirstChildUserIdTAG: 1157796
FirstChildUserNameTAG: mrityunjoy2012
FirstChildCreateTimeTAG: 2013-04-02T13:35:06Z
FirstChildVoteTAG: 0
FirstChildTAG: See you there guys!! :D
FirstChildUserIdTAG: 923593
FirstChildUserNameTAG: SaraMB
FirstChildCreateTimeTAG: 2013-04-02T15:31:06Z
FirstChildVoteTAG: 0
FirstChildTAG: Just registered, thank you, see you in stat2.2x :)
FirstChildUserIdTAG: 321537
FirstChildUserNameTAG: anand_30
FirstChildCreateTimeTAG: 2013-04-02T16:25:13Z
FirstChildVoteTAG: 0
FirstChildTAG: ditto
-gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-04-02T18:53:06Z
FirstChildVoteTAG: 0
IndexTAG: 44
TitleTAG: fyi: saylor.org Statistics courses
fyi - I randomly noticed this non-profit organization saylor.org . From what I can tell, Saylor offers free university-level courses for an autodidact (self-driven learner), that a student may start & complete on their own pace/discretion. It creates these courses by re-using existing OER when possible, & creating new OER when needed.
http://en.wikipedia.org/wiki/Open_educational_resources
After the instructor designs the course, it is peer-reviewed by 3 other instructors. Apparently student comprehension is tested via an online final exam (sounds similar to edX in this sense) & possibly also by assignments during the exam.
Saylor seems to offer a few stats courses
1 Intro to Stats
http://www.saylor.org/courses/ma121
no prerequisite
time estimate 96.25 hours
2 Stats 2
http://www.saylor.org/courses/ma251/
prerequisite MA121
uses R (free open source statistics software) in course
time est 188 hr
3 Intro to Probability Theory
http://www.saylor.org/courses/ma252/
note - an "Advanced Level course" in the Math major curriculum
http://www.saylor.org/majors/mathematics/
prerequisites MA101-103 Calculus, MA211 Linear Algebra, MA221 Differential Equations
time est 104 hr
-
**Have** any of **you completed** a Saylor course, especially a **Saylor statistics course**? Could you give your opinion/**feedback** on Saylor?
I really enjoyed this Stat2.1x course & feel Dr. Adhikari is a word-class Professor & teacher. Despite this, I'm also interested in Saylor Stats courses for the following reasons:
1 Saylor's approach of connecting their different courses together, via noting prerequisites. Between multiple MOOCs offered by multiple Profs/Univs/MOOC providers (eg edX & Coursera), IMHO it's often unclear if 1 MOOC is a sufficient preparation/pre-requisite for another MOOC. For example, presume a student completes the Stat2.X series, & is interested in a 2nd Stats-related MOOC
https://www.coursera.org/course/biostats
It is possible that as excellent as Stat2.X is, it is not sufficient preparation for this Biostats MOOC. On the other hand, the Biostats MOOC could be a "re-work" situation, where a student finds a big portion of Biostats MOOC is material she already mastered in the Stat2.X series. There is no coordination done between MOOCs to indicate their mutual compatibility in a manner that Saylor appears to do, especially if they are from different MOOC providers like Stat2.X's Berkeley/edX vs Biostats' Johns Hopkins Univ/Coursera. In principal, since Saylor & edX are both nonprofit orgs focused on offering free education to students, it's possible that they could indicate mutual compatibility between their courses, although I would guesstimate that is unlikely to happen soon.
2 student-driven pace - can go as fast or slow as one desires. Obviously this feature is useful in allowing a student to balance their self-study work with their other work/physical school/family duties. (Note: I understand that this may be a personal preference - some prefer a deadline-based MOOC, possibly partly because the massive web-based community that is part a MOOC where students help each other on the internet discussion forums.)
3 MA251 Stats 2 explicitly uses R software. I would much prefer to be able to increase my R programming & stats knowledge concurrently. My guesstimate is that is more efficient & effective to learn R & stats concurrently, than it is to learn both individually.
-
I wonder if an appropriate student strategy would be to use & "default to" Saylor when possible for the "base" courses, & use the other MOOC providers for a more advanced/specialty course subject that Saylor doesn't cover.
Anyways I would be interested in your (both fellow students & Stat2.X staff) thoughts/feedback on my post here. Thanks in advance!
UserIdTAG: 538198
UserNameTAG: A_P
CreateTimeTAG: 2013-04-02T09:13:07Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Thank you for letting us know. I am going to try one of the mathematics courses.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-04-02T09:38:33Z
FirstChildVoteTAG: 0
SecondChildTAG: you are welcome.
"I am going to try one of the mathematics courses." do you mind if I ask, is this 1 of the Stats courses (which Saylor categorizes in the "Math Department") or a non-Stats-related Math course?
SecondChildUserIdTAG: 538198
SecondChildUserNameTAG: A_P
SecondChildCreateTimeTAG: 2013-04-02T10:32:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks for the information.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-04-02T10:45:10Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi A_P, to begin with, tnaks for information given.
You mentioned R software, for some courses it is needed as prerequisite, do you know a free course (for beginners) to learn using this software?
thanks in advance
FirstChildUserIdTAG: 1002821
FirstChildUserNameTAG: Urimare
FirstChildCreateTimeTAG: 2013-04-02T12:40:51Z
FirstChildVoteTAG: 1
SecondChildTAG: Hi Urimare,
Here's what I'm aware of, although I am just guesstimating here to be honest.
like I mentioned, Saylor's MA251 Stats 2 appears to teaches R concurrently with the Stats. Unfortunately, its prerequisite MA121 Intro to Stats does not include R.
Similarly I've read that the Openintro Stats free textbook, has optional/additional R scripts & text instruction alongside the stats.
-
This MOOC (Dr Roger Peng from Johns Hopkins U on Coursera) teaches R computer programming, without teaching the Stats. It doesn't look like it's being offered currently, so you may not be able to access to materials via the Coursera website, in which case, it seems Peng's youtube channel has some of those Video Lectures
https://www.coursera.org/course/compdata
youtube.com/user/rdpeng
--
Although not free, I studied the initial chapters of the R for Dummies, (haven't had time to finish it yet). IMHO it a good useful resource. Similar to the Peng MOOC, R for Dummies covers the computer programming side of R, not stats theory.
http://rfordummies.com/
-
http://cran.r-project.org/
I recall that the R site has links to free digital/pdf R books/manuals. I downloaded a few of them, but haven't used them
-
Given the limited info I have currently, if I had to give an recommendation on how to learn R (something I'm not really qualified to do on this topic to be honest, actually I wrote this post to get better-informed others' advice), I'd recommend:
1 R for Dummies
2 Saylor's MA121 -> MA251 sequence
3 optional: also continue w Dr. Adhikari's 2.X MOOC series. Although it doesn't teach R, Adhikari afaict is both a world-class teacher of Stats & designer of a useful-to-the-student MOOC. Perhaps having finished 2.X before taking Saylor, would reduce the time estimate needed for completing the Saylor sequence.
Hope that helps
AP
SecondChildUserIdTAG: 538198
SecondChildUserNameTAG: A_P
SecondChildCreateTimeTAG: 2013-04-02T13:13:25Z
SecondChildVoteTAG: 0
SecondChildTAG: ^ I apologize for the odd formatting of my prior comment/reply to Urimare. It appears that this edX Discussion forum is not "what you see is what you get", & once you hit the Submit button, there's no chance for one to edit their comment.
SecondChildUserIdTAG: 538198
SecondChildUserNameTAG: A_P
SecondChildCreateTimeTAG: 2013-04-02T13:17:24Z
SecondChildVoteTAG: 0
SecondChildTAG: **Thank you very much given information is amazing. I´ll go to R project web site**
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-04-02T14:41:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I´ve achived R for Dummies as well, again thanks a lot.
See you in Stat2.2x
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-04-02T14:58:15Z
SecondChildVoteTAG: 0
SecondChildTAG: In spite of the "Dummies" in the book title I've read good reviews from trusted sources.
My choices as first books on R (I'm still there) were:
* N. Matloff, *The Art of R programming*, NoStarch Press
(An excellent book, believe me. But it's not easy and I think it's intended to people with certain programming experience. It's primarily about the language itself)
and a book of R + statistics, a very good one if you want the R perspective:
* P. Dalgaard, *Introduction to Statistics Using R*, Springer Verlag
Dalgaard is member of the core group of R developers. So it's a very trusted and relatively modern source. This book, however, requires a bit of statistics background, it's very concise.
Don't forget classics books, as those written by J. Chambers, member of the R core group and creator of the S language (the "father" of R). For example, this book on S is old but for the specialists it's still a main reference:
* Bekker, Chambers, Wilks, *The New S Language*, Wadsworth & Brooks/Cole
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-04-02T19:47:34Z
SecondChildVoteTAG: 0
SecondChildTAG: atopos said
" and a book of R + statistics, a very good one if you want the R perspective:
P. Dalgaard, Introduction to Statistics Using R, Springer Verlag
Dalgaard is member of the core group of R developers. So it's a very trusted and relatively modern source. This book, however, requires a bit of statistics background, it's very concise. "
atopos, do u know if the Stat2.X series would be sufficient "stat background required" for the Dalgaard book? Thx atopos for the tip.
SecondChildUserIdTAG: 538198
SecondChildUserNameTAG: A_P
SecondChildCreateTimeTAG: 2013-04-03T07:07:50Z
SecondChildVoteTAG: 0
SecondChildTAG: I think Stat2.X series is enough. One can get here a very firm conceptual basis.
A frequent approach in Intros to Statistics (Dalgaard's book as well) is to begin with probability and probability distributions (so the subject of Stat2.2x).
The only difficulty is with math equations, you can be intimidated by them (a bit of calculus are used once in a while), but I think they are written more for the sake of rigour (it's not a book on mathematical statistics) and a patient reader can go through the text without losing nothing important, even if she does not understand all of its equations.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-04-03T10:32:53Z
SecondChildVoteTAG: 0
IndexTAG: 45
TitleTAG: suggestion: optional more challenging problems
I am very grateful for this course. Interesting material, good pace, enough time to complete the homework, very good teacher.
I'd like to make one suggestion. I know it is an introductory course, for which you don't need a strong mathematical background. However, it would be interesting to get some more challenging problems on top of the usual exercises, just optional, without grading. Maybe the professors have these problems anyway. I would be interested to try them.
UserIdTAG: 1159651
UserNameTAG: KatrienJ
CreateTimeTAG: 2013-04-02T08:54:37Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: good suggestion!
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-04-02T10:02:45Z
FirstChildVoteTAG: 2
FirstChildTAG: This is the reason why I hesitate to register Stat 2.2X. I think I have to thorough the Stat 2.1X first. Hope that there will be Stat 2.2X in future too.
;-(
FirstChildUserIdTAG: 254503
FirstChildUserNameTAG: LaiLai
FirstChildCreateTimeTAG: 2013-04-02T13:09:39Z
FirstChildVoteTAG: 1
IndexTAG: 46
TitleTAG: stat2.2
hi there
just wondering if anybody has registered for the stat2.2?if so, can you please let me know how?
and many thanks for your wonderful course(stat2.1), that was great :)
M
UserIdTAG: 1245521
UserNameTAG: JustOnce
CreateTimeTAG: 2013-04-02T08:09:11Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: yeap, stat2.2 is available to register
https://www.edx.org/courses/BerkeleyX/Stat2.2x/2013_April/about
FirstChildUserIdTAG: 1201765
FirstChildUserNameTAG: alien10
FirstChildCreateTimeTAG: 2013-04-02T08:15:18Z
FirstChildVoteTAG: 3
FirstChildTAG: thanks a lot...I did register it:)
FirstChildUserIdTAG: 1245521
FirstChildUserNameTAG: JustOnce
FirstChildCreateTimeTAG: 2013-04-02T08:27:21Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you for link.
FirstChildUserIdTAG: 324397
FirstChildUserNameTAG: smjniv
FirstChildCreateTimeTAG: 2013-04-02T08:45:51Z
FirstChildVoteTAG: 0
IndexTAG: 47
TitleTAG: Got the Certificate ?`
Hello fellas,
Has anyone got the **certificate of completion** ? And anyways, this course was superb.
Kavish
UserIdTAG: 1212077
UserNameTAG: kavishahuja
CreateTimeTAG: 2013-04-02T06:55:42Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 10
FirstChildTAG: Not yet... but I believe they will send them shortly.
Enjoyed this course a lot too...
FirstChildUserIdTAG: 1208016
FirstChildUserNameTAG: TomFerech
FirstChildCreateTimeTAG: 2013-04-02T08:29:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Not yet :(
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-04-02T10:55:05Z
FirstChildVoteTAG: 0
FirstChildTAG: Noooope...
FirstChildUserIdTAG: 787465
FirstChildUserNameTAG: Andrey-Serge
FirstChildCreateTimeTAG: 2013-04-02T11:47:42Z
FirstChildVoteTAG: 0
FirstChildTAG: I am waiting, too...
FirstChildUserIdTAG: 1246063
FirstChildUserNameTAG: Jexi
FirstChildCreateTimeTAG: 2013-04-02T12:55:19Z
FirstChildVoteTAG: 0
FirstChildTAG: not yet:( still waiting...love this course and Pro A so much, though i signed up a bit late.
FirstChildUserIdTAG: 1391692
FirstChildUserNameTAG: elaine_wong
FirstChildCreateTimeTAG: 2013-04-02T13:01:23Z
FirstChildVoteTAG: 0
FirstChildTAG: weather the certificate will be send to our own mail id
FirstChildUserIdTAG: 1157796
FirstChildUserNameTAG: mrityunjoy2012
FirstChildCreateTimeTAG: 2013-04-02T13:22:21Z
FirstChildVoteTAG: 0
SecondChildTAG: No the certificate will be send to your dahsboard
SecondChildUserIdTAG: 932785
SecondChildUserNameTAG: PhyoThein
SecondChildCreateTimeTAG: 2013-04-03T04:17:31Z
SecondChildVoteTAG: 0
FirstChildTAG: not yet
FirstChildUserIdTAG: 1031722
FirstChildUserNameTAG: led21
FirstChildCreateTimeTAG: 2013-04-02T14:09:50Z
FirstChildVoteTAG: 0
FirstChildTAG: not yet too!
brahim from morocco
FirstChildUserIdTAG: 1157536
FirstChildUserNameTAG: PERIO81
FirstChildCreateTimeTAG: 2013-04-02T18:19:25Z
FirstChildVoteTAG: 0
FirstChildTAG: got it. just go to edx dashboard and download it.
FirstChildUserIdTAG: 1115908
FirstChildUserNameTAG: rochak_khandelwal
FirstChildCreateTimeTAG: 2013-04-02T20:26:45Z
FirstChildVoteTAG: 0
FirstChildTAG: I got my certificate today .
FirstChildUserIdTAG: 932785
FirstChildUserNameTAG: PhyoThein
FirstChildCreateTimeTAG: 2013-04-03T04:17:53Z
FirstChildVoteTAG: 0
IndexTAG: 48
TitleTAG: Feebdback Time !
A and P sweat while we learned and had fun. I believe everyone reading this had fun too. We all are thankful to faculty and staff who took pain to initiate a new way to learning and evaluation, and who know we are the torchbearer for the forthcoming changes in terms of how next generations going to learn.
Further, it would be only fair to share your constraints and challenges during the course - may be as pointers - which may help A & P to improvise the tool.
1. Like everyone else I too had my constraints as I am working and keep traveling to remote areas lacking adequate connectivity.
>> One solution could be to have more open-window for submission
>> Allow sequential downloading of all videos and reference material so to refer them off-line. I actually tried downloading and studied that way.
>> Demonstrate more examples and give reference/ cross references to learning to various sections being applied (may be as supplement) - to help recall and stay connected with the concept
Points to Praise:
1. Good relevant examples
2. Tutorial speed is adequate and adaptable for most of us
3. Accent is almost neutral for the global students
4. I like the special effects when you induce a graph while explaining a concept. Makes feel like home !
Many cheers,
Navneet
UserIdTAG: 1129606
UserNameTAG: navneetshrivastava
CreateTimeTAG: 2013-04-02T05:30:22Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hello Navneet
I fully agree to "Feedback time" and have already submitted my own - it's very important for improving. As I travelled during this five weeks I met very different internet infrastructures and had sometimes a lot of difficulty to reach adequate learning conditions because of technical circumstances. I like your solution and used your proposed method, too. Additional to video it could be helpful to provide audio possibility (less bandwith/energy needed) or the lectures available in .pdf format (for problems with internet connections).
Best E.
FirstChildUserIdTAG: 1240020
FirstChildUserNameTAG: Elibee
FirstChildCreateTimeTAG: 2013-04-02T07:04:02Z
FirstChildVoteTAG: 1
FirstChildTAG: Thank you very much Prof. Ani.
FirstChildUserIdTAG: 134233
FirstChildUserNameTAG: ralkhattab
FirstChildCreateTimeTAG: 2013-04-02T08:52:47Z
FirstChildVoteTAG: 0
IndexTAG: 49
TitleTAG: Certificate
I haven't got the certificate or any of it's link on my dashboard yet ! Has any one got it by now ?
UserIdTAG: 911001
UserNameTAG: akashdwivedi92
CreateTimeTAG: 2013-04-02T04:51:14Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: hi, i am also waiting for the certificate! pls inform us when can we check it out again?
FirstChildUserIdTAG: 498305
FirstChildUserNameTAG: menaal
FirstChildCreateTimeTAG: 2013-04-02T05:08:23Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi buddies :) At present no one of my friends don't get it...
SecondChildUserIdTAG: 787465
SecondChildUserNameTAG: Andrey-Serge
SecondChildCreateTimeTAG: 2013-04-02T08:19:18Z
SecondChildVoteTAG: 0
SecondChildTAG: I think they will send them like 3 weeks from final... at least some courses on coursera do it this way... but it all depends on staff. Either way, expecting them soon.
SecondChildUserIdTAG: 1208016
SecondChildUserNameTAG: TomFerech
SecondChildCreateTimeTAG: 2013-04-02T08:30:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Prof said that the system will start "cranking" out the certs by monday (all fools day :D). Maybe it means "printing" starts on monday and mailing starts at a later date :)
SecondChildUserIdTAG: 1320404
SecondChildUserNameTAG: sunilthapa5
SecondChildCreateTimeTAG: 2013-04-02T09:46:13Z
SecondChildVoteTAG: 0
SecondChildTAG: no printing and no mailing....just downloading and printing it yourself...
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-04-02T10:56:28Z
SecondChildVoteTAG: 0
SecondChildTAG: still waiting..
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-04-02T12:25:13Z
SecondChildVoteTAG: 0
SecondChildTAG: I got my certificate today
I hope all of you have too.
SecondChildUserIdTAG: 932785
SecondChildUserNameTAG: PhyoThein
SecondChildCreateTimeTAG: 2013-04-03T04:15:11Z
SecondChildVoteTAG: 0
FirstChildTAG: It's going to take a while - up to three weeks. Just be patient; there are a lot of us! :D
FirstChildUserIdTAG: 296450
FirstChildUserNameTAG: Termiteruler
FirstChildCreateTimeTAG: 2013-04-02T13:21:45Z
FirstChildVoteTAG: 0
FirstChildTAG: Patient lot.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-02T20:32:44Z
FirstChildVoteTAG: 0
IndexTAG: 50
TitleTAG: how to get complition certificate?
how to get course complition certificate
UserIdTAG: 795895
UserNameTAG: chiragshah51
CreateTimeTAG: 2013-04-02T04:19:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I belieeve they will be e:mailed to us week commencing 1st April (inauspicious date!)
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-04-02T06:17:50Z
FirstChildVoteTAG: 0
SecondChildTAG: you can see your certificate on your dashboard and download it.
SecondChildUserIdTAG: 932785
SecondChildUserNameTAG: PhyoThein
SecondChildCreateTimeTAG: 2013-04-03T04:14:11Z
SecondChildVoteTAG: 0
SecondChildTAG: yes. i find it on dashboard..:)
SecondChildUserIdTAG: 1193006
SecondChildUserNameTAG: makmursp
SecondChildCreateTimeTAG: 2013-04-03T04:42:42Z
SecondChildVoteTAG: 0
IndexTAG: 51
TitleTAG: Edx team ?
We know the Professors and immensely appreciate their efforts but can the rest of the Edx team introduce themselves.It would be nice to know who they are since they are slogging silently behind the scenes to make this possible.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-04-02T02:33:14Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: hi i have registered for stat2.1x course today.can i enroll myself in now and get a certificate later on completion?
thanks
ajay
FirstChildUserIdTAG: 701545
FirstChildUserNameTAG: pharma2012
FirstChildCreateTimeTAG: 2013-04-02T06:23:26Z
FirstChildVoteTAG: 0
SecondChildTAG: For 2.1x? The course is finished.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-04-02T07:09:10Z
SecondChildVoteTAG: 0
SecondChildTAG: You can go through the lectures of stat2.1x .get enrolled for stat2.2x ,which is going to start on 12th April.
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-04-02T08:26:17Z
SecondChildVoteTAG: 0
IndexTAG: 52
TitleTAG: Anyone received the certificate?
Any one received the certificate?would we be getting it in out registered email id?
UserIdTAG: 1234632
UserNameTAG: burnor92
CreateTimeTAG: 2013-04-02T00:47:26Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I havent't received the certificate yet, do We have our certificate in the emails or must we download in this blackboard?
FirstChildUserIdTAG: 1132096
FirstChildUserNameTAG: 1015427915
FirstChildCreateTimeTAG: 2013-04-02T00:59:18Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi Professor,
I haven't received the certificate. Please, where I can find it?
Thank you for the course and thank you in advance for your help
SecondChildUserIdTAG: 1153901
SecondChildUserNameTAG: Princemay
SecondChildCreateTimeTAG: 2013-04-02T01:08:31Z
SecondChildVoteTAG: 0
SecondChildTAG: No we don't... still waiting
SecondChildUserIdTAG: 787465
SecondChildUserNameTAG: Andrey-Serge
SecondChildCreateTimeTAG: 2013-04-02T08:20:18Z
SecondChildVoteTAG: 0
SecondChildTAG: i just got it on my dashboard
SecondChildUserIdTAG: 1193006
SecondChildUserNameTAG: makmursp
SecondChildCreateTimeTAG: 2013-04-03T04:43:07Z
SecondChildVoteTAG: 0
FirstChildTAG: I have finished another EDX course, and let me assure you, one day your EDX homepage (where your full name, e-mail, Stat2.1X logo appears, and Stat2.2X too if you have enrolled already, as well as any other EDX courses you've taken) will display this "download your PDF certificate" button.
Just make sure your full name is properly spelled, and you'll be able to download the certificate.
FirstChildUserIdTAG: 632581
FirstChildUserNameTAG: GMendes
FirstChildCreateTimeTAG: 2013-04-02T02:04:51Z
FirstChildVoteTAG: 2
SecondChildTAG: is that true? so, when will display this "download your PDF certificate" button? and how long should you waiting for as usual?
SecondChildUserIdTAG: 1391692
SecondChildUserNameTAG: elaine_wong
SecondChildCreateTimeTAG: 2013-04-02T13:57:28Z
SecondChildVoteTAG: 0
FirstChildTAG: As explained multiple times both here and on the edX faq. The certificate is a **digital download**. The link will appear on your dashboard.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-02T05:53:18Z
FirstChildVoteTAG: 0
IndexTAG: 53
TitleTAG: Grateful and Appreciation
Dear Professor A,
I really really loved your course! I never posted before but since this course is ending I just wanted to let you know how grateful I am for all the knowledge you shared and your wonderful teaching method. I usually do mathematics just for the fun of it and this course was really interesting. :)
Thankyou and hats off yo you and your team for a job well done :)
UserIdTAG: 83746
UserNameTAG: Mamoona
CreateTimeTAG: 2013-04-02T00:43:50Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Dear Professor,
Thank You.
We really enjoyed the course. We learned a lot for FREE.
May God Bless you and your full team
FirstChildUserIdTAG: 929881
FirstChildUserNameTAG: Anverali
FirstChildCreateTimeTAG: 2013-04-02T07:52:01Z
FirstChildVoteTAG: 1
IndexTAG: 54
TitleTAG: stat2.2x available for sign up
https://www.edx.org/courses/BerkeleyX/Stat2.2x/2013_April/about
UserIdTAG: 174100
UserNameTAG: markpolak
CreateTimeTAG: 2013-04-01T23:46:51Z
VoteTAG: 18
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: Thanks.
FirstChildUserIdTAG: 344400
FirstChildUserNameTAG: carlallen
FirstChildCreateTimeTAG: 2013-04-02T00:23:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks!
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-04-02T04:04:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks.
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-04-02T04:25:40Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks..
FirstChildUserIdTAG: 346234
FirstChildUserNameTAG: kavita2012
FirstChildCreateTimeTAG: 2013-04-02T04:35:37Z
FirstChildVoteTAG: 0
FirstChildTAG: See you there!
FirstChildUserIdTAG: 830835
FirstChildUserNameTAG: Zacharie
FirstChildCreateTimeTAG: 2013-04-02T07:42:55Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks.
FirstChildUserIdTAG: 324397
FirstChildUserNameTAG: smjniv
FirstChildCreateTimeTAG: 2013-04-02T08:49:13Z
FirstChildVoteTAG: 0
IndexTAG: 55
TitleTAG: Thank you very much (from Myanmar)
Dear Professor A,
Warm greetings from Myanmar !
Although I am interested in Research, I really understand that I need to understand statistics although it was very boring in class. We,a group of friend, wandered that there will be the book including the interesting problems directly related to application.
This course make my dream come true. Due to the IT infrastructure limitation of our country, I tried to adapt how to get the lecture videos, scripts and access to the course. These make me time consuming and reduce my learning hours.
I am sorry that I cant be the clever student in this class. But it make me understand well about the Statistics. I had to understand each basic concept with application in addition to the history. I think very wide knowledge of the humble professor make us ease to learn and get a precious knowledge at our convenience. (In our country, we use to say that the student can get 25% of knowledge, as the teacher can share her knowledge in 50% as the teacher has the 100% knowledge.)
In addition to the Statistics, I can learn about the freedom. When you talk about the regression line, you told us that "this is the country we can draw the line we want". Actually that is very new for me. We had to learn just what is mentioned in the book and did not know why happen like this. We cant know the result of our very innovative ideas ;-P of the topics. Actually I hate the Statistics class because of the Maths formula which made me crazy. I did not know the really meaning of these until you explained. But I really enjoyed your formula in simple English which I ever never know about it.
Your voice is very attractive and very nice to listen. I think this is an essential point of every professors. You anticipated to support us during the class in very details. Thank you very much.
Thanks and regards,
Lai Lai
UserIdTAG: 254503
UserNameTAG: LaiLai
CreateTimeTAG: 2013-04-01T22:39:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 56
TitleTAG: Final exam - 4B & 4C
I've made errors in both of those exercises. Can anyone please explain to me in details their solution? It looks like I have some gaps in understanding of correlation and its applications.
Thank you!
UserIdTAG: 255838
UserNameTAG: EngineerHrenov
CreateTimeTAG: 2013-04-01T21:32:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 4B: You can determine the new final score by taking the old exam score and adding 15 to it. Which means you can find the new score y by filling in x in the equation y=x+15, this is an upward straight line and all the new scores are on this line so the correlation is 1. (Summary: The relation between new scores and old scores is an upward straight line so the correlation is 1.)
4C: If you draw an image for the old correlation between the midterm and final scores you should get a football shaped scatter diagram. (It's just a sketch)
This means that you can draw a regression line through it but some (or all) plotted points will deviate from the line. Now replace the plotted points by the ones you get with the new final scores. The sketch will look exactly the same but it will be shifted upwards by 15. (because the midterm score for each point stays the same but the new final score = the old final score + 15)
The shape of the graph stays the same so the correlation stays the same. (since the deviation of the "best possible line = regression line" through the graph will stay the same)
Since the old regression was 0.63, the new one is as well.
I hope this helps, my explanation might be too long :(
Cheers
FirstChildUserIdTAG: 372474
FirstChildUserNameTAG: JeroenPinoy
FirstChildCreateTimeTAG: 2013-04-01T22:41:32Z
FirstChildVoteTAG: 1
SecondChildTAG: Very well explained @jereonPinoy. That is the best explanation one should get. R you a teacher?
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-04-02T16:15:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, no but I tutor and try to help people if I can ;) .
SecondChildUserIdTAG: 372474
SecondChildUserNameTAG: JeroenPinoy
SecondChildCreateTimeTAG: 2013-04-02T18:17:56Z
SecondChildVoteTAG: 0
IndexTAG: 57
TitleTAG: Math Past Calculus III?
I am currently enrolled in an American high school, and I have a friend who is taking Calculus III as a junior. Next year she has a problem: she has exhausted all available math courses offered by not only our county, but state for high schoolers. She would like to continue taking mathematics in high school, but she doesn't know what to study or where to do it, because after Calc III math diverges into separate branches. I have already pointed her to MIT's Online Course Ware and this; does anybody else have any suggestions for very high level math courses?
UserIdTAG: 296450
UserNameTAG: Termiteruler
CreateTimeTAG: 2013-04-01T21:22:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I'd suggest to take a look at Mit OCW, but you've done :) Books are always there, some free books included, even classics. And a lot of blogs. Maybe reading things about current trends can give her some hints. How about this one?:
http://gowers.wordpress.com/
It contains more links to active mathematicians blogs
But I cannot recommend anything in particular. I'm not a mathematician, only a math fan (once in a while ;-) )
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-04-01T21:57:47Z
FirstChildVoteTAG: 0
FirstChildTAG: There are some maths course on udacity and coursera. Check those in addition to MIT-OCW.
FirstChildUserIdTAG: 159507
FirstChildUserNameTAG: manirana
FirstChildCreateTimeTAG: 2013-04-02T09:23:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks, guys. :)
FirstChildUserIdTAG: 296450
FirstChildUserNameTAG: Termiteruler
FirstChildCreateTimeTAG: 2013-04-02T13:20:59Z
FirstChildVoteTAG: 0
IndexTAG: 58
TitleTAG: Is it April 1 GMT time or April 1 Berkeley (Center of Universe) time?
You know I am just kidding. See you all in 2.2. Cheers!
UserIdTAG: 523705
UserNameTAG: IITian
CreateTimeTAG: 2013-04-01T20:32:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: When should we receive certificate?
FirstChildUserIdTAG: 1302597
FirstChildUserNameTAG: neha_kaur
FirstChildCreateTimeTAG: 2013-04-01T21:07:51Z
FirstChildVoteTAG: 2
FirstChildTAG: The Prof said she **expected** certificates to be issued **from** 1 April.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-04-01T23:32:07Z
FirstChildVoteTAG: 0
FirstChildTAG: No **April 1 GMT time or April 1 Berkeley (Center of Universe) time**.
IT IS APRIL 1 FOOL's TIME
=========================
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-04-02T11:00:14Z
FirstChildVoteTAG: 1
IndexTAG: 59
TitleTAG: A Huge Thank You And an Unexpected Bonus
Many Thanks to Professors Adhikari and Stark and the Team that brought us Stat2.1x
For those of us who have been 'out of the educational system' for some time I'm sure it has been difficult meeting the deadlines. That said the course material has been both engaging and challenging. Just when I thought it was all over, I find that we may possibly have another TWO courses to do. YIPPEE! I love this stuff. Bring it on!
Thank You All Again for making this material accessible to everyone
Kindest Regards,
Haydar
UserIdTAG: 1257052
UserNameTAG: Haydarali
CreateTimeTAG: 2013-04-01T20:15:06Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 60
TitleTAG: thank you!
When I decided to take up Stat2.1x I wanted to refresh my knowledge. I have also hoped that I might discover that statistics is not just a bunch of boring formulas. Not only that my expectation was met to the full extent, but I have discovered many new and interesting things. Thank you very much to the prof. Adhikari and prof. Stark for showing who the statistics should be thought and for making it look so simple and logical!
I have really enjoyed this course!
UserIdTAG: 1226132
UserNameTAG: Jele
CreateTimeTAG: 2013-04-01T20:12:59Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 61
TitleTAG: Wow! I made it!
I Was and maybe still are quite a bit scare of statistics. I decided to take this course because if I fail badly it wouldn't be so shameful since nobody has to know about it!
The last topic, regression was pretty tough on me, but at the end I think I hold a pretty good understanding of it. As I was struggling with the exercises I came to the conclusion that I was torturing myself with this class! And of course, I was thinking to keep myself far away from this subject from now on!
Not even 24 hours later and just after reviewing my notes and doing some exercise and watching this video, I found myself wanting so much to learn more about statistic, amaze at how much I have learn in the past five weeks! But must of all getting a hold of how useful and relevant statistic really is to my everyday life!
So, before we are done I just wanted to say thank you for this excellent course and for your extraordinary professor Ani, who through her clever and incredible patient lessons made learning statistic possible even for a statistic-phobic person like me.
Thank you!
UserIdTAG: 759060
UserNameTAG: RocioRosado
CreateTimeTAG: 2013-04-01T20:05:21Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 62
TitleTAG: Thank you very much
I would like to thank Prof Ani and all staff, for this course, and also to edX for bring to us the opportunity of take these courses
UserIdTAG: 536841
UserNameTAG: Manalhassan
CreateTimeTAG: 2013-04-01T19:55:02Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 63
TitleTAG: Thanks, I'm waiting for stat 2.2X
I want to thank Professor Ani and her staff, for this incredible course, and also to edX for bring to us the opportunity of take these courses. I hope to see you in stat 2.2X, I'm sure that we are going to learn a lot of useful stat concepts.
Andy
UserIdTAG: 536285
UserNameTAG: AndyXM
CreateTimeTAG: 2013-04-01T18:44:04Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 64
TitleTAG: Where are the Completion Certificates Posted on the site?
Where are the Completion Certificates Posted on the site?
UserIdTAG: 1219598
UserNameTAG: Danielle1239
CreateTimeTAG: 2013-04-01T18:41:37Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Apparently you will get an email and there will then be a link from your dashboard page.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-04-01T19:52:04Z
FirstChildVoteTAG: 0
SecondChildTAG: For the unsure: Dashboard is the page you see immediately after logging in. It's the menu of the courses you've registered to.
SecondChildUserIdTAG: 438931
SecondChildUserNameTAG: pavemina
SecondChildCreateTimeTAG: 2013-04-01T20:03:01Z
SecondChildVoteTAG: 0
SecondChildTAG: but when?
SecondChildUserIdTAG: 1302597
SecondChildUserNameTAG: neha_kaur
SecondChildCreateTimeTAG: 2013-04-01T21:09:23Z
SecondChildVoteTAG: 0
SecondChildTAG: The Prof said she **expected** certificates to be issued **from** 1 April.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-04-01T23:33:52Z
SecondChildVoteTAG: 0
FirstChildTAG: The certificates are created by the edX staff. They will be ready when they have been generated. Could be today, could be next week/month/year/decade/century if there are tech issues. As has happened in the past.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-02T05:55:15Z
FirstChildVoteTAG: 2
IndexTAG: 65
TitleTAG: Reinforcing new learning
Many thanks to the Prof and staff for their teaching methodology.
The methodology seemed basic at first but I soon realized that it does an effective job of ensuring that subject misunderstandings are removed early which is really great for me in particular and suits MOOC.
UserIdTAG: 344400
UserNameTAG: carlallen
CreateTimeTAG: 2013-04-01T18:27:09Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 66
TitleTAG: certificate?
its aprl 1 so..
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-04-01T18:07:40Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Prof. A. said that she expected certificates to be issued **from** 1 April so...?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-04-01T19:53:00Z
FirstChildVoteTAG: 2
FirstChildTAG: Just be patient. They'll come in due time. My certificate for 3.091x came weeks after it was expected. There's lots of us taking the class! :)
FirstChildUserIdTAG: 296450
FirstChildUserNameTAG: Termiteruler
FirstChildCreateTimeTAG: 2013-04-01T21:23:24Z
FirstChildVoteTAG: 1
FirstChildTAG: April fools. There are no certificates.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-04-01T22:38:06Z
FirstChildVoteTAG: 1
SecondChildTAG: LOL, you beat me to it.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-04-02T05:55:50Z
SecondChildVoteTAG: 0
IndexTAG: 67
TitleTAG: A BIG Thank you to all
I would like to thank Prof. Ani Adhikari for such a great course, I really enjoyed it. Also thank you to Prof. Philip Stark for writing such an awesome interactive book and making it available on the internet for free. To the support staff who maintain the website and all the other things that goes on under the hood so as to make this course happen- you guys have done a great work.
And finally thank you to all fellow students, you guys always inspired me whenever I visited Discussion forums, it was great to see people wanting to know more and more.
Now its time for my little story:
My group is working on a project where if we get a relation between the length and breadth of cashew nut then that would help us in future work. I thought of curve fitting but never thought of first plotting a scatter plot (I know that sounds ridiculous :D).
Then came Stat2.1x. Previously I didn't know about the bivariate normal i.e football shaped distribution to estimate one variable from the other. I found this part very useful and went on to plot the scatter diagram for breath vs length for about 233 cashew nuts.
We have previously assumed them individually to be normally distributed by observing the histogram.
To my surprize this is how it looked:![Breadth vs. Length][1]
Then we calculated r which came about 0.8 and then finally we got the equation of regression line and plotted it.
![Regression Line][2]
And finally to make sure we were doing right thing by fitting a line, we plotted residual plot.
![enter image description here][3]
This blob made me happy.
Again Thank you.
P.S. 6.00x really helped me plot these and write python code to calculate slope and intercept. Edx is really shaping our lives. Thank you edx.
[1]: https://edxuploads.s3.amazonaws.com/13648741841343602.png
[2]: https://edxuploads.s3.amazonaws.com/13648742381343627.png
[3]: https://edxuploads.s3.amazonaws.com/13648742551343689.png
UserIdTAG: 321537
UserNameTAG: anand_30
CreateTimeTAG: 2013-04-01T17:54:07Z
VoteTAG: 8
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 5
FirstChildTAG: This is called application of the course. Thanx @Anand_30 for sgaring.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-04-01T18:20:45Z
FirstChildVoteTAG: 1
SecondChildTAG: Great
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-04-01T18:27:19Z
SecondChildVoteTAG: 0
FirstChildTAG: Great story!
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-04-01T23:35:23Z
FirstChildVoteTAG: 1
SecondChildTAG: Hey thanks, I recognize you 'atopos' from 6.00x offered last time, you helped a lot of students there including me. Great to have you here also. What other courses are you taking?
SecondChildUserIdTAG: 321537
SecondChildUserNameTAG: anand_30
SecondChildCreateTimeTAG: 2013-04-02T16:59:50Z
SecondChildVoteTAG: 0
FirstChildTAG: Terrific, anand_30! Isn't it wonderful to see the theory in action? Your regression is about as good as it gets in practice.
Let me recommend that you download R, the statistical system. It will do all of the calculations you need and more. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-04-02T03:32:36Z
FirstChildVoteTAG: 3
SecondChildTAG: Thank you professor for your advice about 'R', I will definitely look into it.
SecondChildUserIdTAG: 321537
SecondChildUserNameTAG: anand_30
SecondChildCreateTimeTAG: 2013-04-02T03:58:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Done with plotting using R, here are the plots for another variable![Thickness vs Breadth][1]
But the correlation between these variables is not as good as with the previous, here I get correlation coefficient of about 0.4 only.
Here is the residual plot
![Residual][2]
I don't know why I am getting a bit variation(after 2 decimal places) in values of r using my python code and using R, I think I would have to recheck my code there.
R is really easy in that matter but writing python code was just so much fun. :)
Again thank you prof A.
[1]: https://edxuploads.s3.amazonaws.com/13648818291343601.png
[2]: https://edxuploads.s3.amazonaws.com/13648819741343634.png
SecondChildUserIdTAG: 321537
SecondChildUserNameTAG: anand_30
SecondChildCreateTimeTAG: 2013-04-02T05:57:00Z
SecondChildVoteTAG: 0
FirstChildTAG: good work! My Best Wishes!
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-04-02T05:36:07Z
FirstChildVoteTAG: 1
FirstChildTAG: Great work, Anand!
It will be great if you can share your Python/R code!
FirstChildUserIdTAG: 99863
FirstChildUserNameTAG: pramode_ce
FirstChildCreateTimeTAG: 2013-04-02T15:55:17Z
FirstChildVoteTAG: 1
SecondChildTAG: Here is the python code(sorry it will be really hard to read, I know I write unnecessarily complex and badly documented code, but I am trying to improve):
[Scatterplot][1]
Note: you need the cashew_sizes.xls file to run code
Sorry I didn't write separate code for R but just executed few commands on it, still here they are in sequence
> read.table() #to read all dimensions
> plot(breadth, thickness, main = "Title", xlab = "Breadth", ylab = "Thickness") #or whatever your variables are
> regline = lm(thikness~breadth) #regression line in slope intercept form
> abline(regline, col = 'red') #plots the line
> residue = resid(regline) #gets the residue
> plot(breadth, residue) #to plot residue
> abline(0,0) #avg of residue line
[1]: https://github.com/anandtakawale/classcodes/tree/master/cashew
SecondChildUserIdTAG: 321537
SecondChildUserNameTAG: anand_30
SecondChildCreateTimeTAG: 2013-04-02T16:56:12Z
SecondChildVoteTAG: 0
IndexTAG: 68
TitleTAG: AM BLESSED BY THIS
I have been greatly endowed with so much knowledge from EDX AND MIT it has been a wonderful time. though i started quite a lot of other courses but this happens to be first that i completed, more grease to your elbow. I actually wanted to ask if this cert can be used as a booster towards somebody going to college or University. Thanks once again
UserIdTAG: 451586
UserNameTAG: Oluwatobiloba
CreateTimeTAG: 2013-04-01T17:47:33Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 69
TitleTAG: A Million Thanks
Great Job! A million thanks!
O.A.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-01T16:40:59Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 70
TitleTAG: Here's my feedback! What is yours? Summary of my learning experience, feedback to Stat2.1x (my perspective and perception)
Dear Prof. A. and team
Thanks a lot for this interesting and challenging course!
As improvement and learning is a matter of interactions and reciprocity (i.E. a dynamic process), I feel the urge to communicate you my personal stat2.1x learning experiences
Excellent
• Official Lectures by Prof. A. with examples, simple enough to be able to concentrate on the important points/understanding the principles
• Prof. comment/reaction on discussion/critical points
• Progression graphics
• Practice for exersices: good interactive solution tool (although in some cases not enough comments of solutions and/or references)
• interactive tools and applet function without internet connection !
Missing / To improve
• Fixed on only two browsers is a big restriction (above all in difficult internet situations)
• Avoid automatical (wrong) answers on technical questions (they are misleading).
• instead of only video you could provide also audio possibility (less bandwith/energy needed) or the lectures available in .pdf format (for problems with internet connections)
• Guidelines with (more) graphical help (e.g. tree, mindmap) for communication, network, discussion, forum
• More explanations/solutions of the exercises
• More links and references from questions to answers and/or part of the script with explanations/clarifications
• Maybe (interactive) overview with links
Best E.
UserIdTAG: 1240020
UserNameTAG: Elibee
CreateTimeTAG: 2013-04-01T15:42:05Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 71
TitleTAG: End results for Stats 2.1X
Hello Prof A.
I am wondering whether the end results of Stats 2.1X will be made known to all participants, irrespective of whether they've passed or not.
Thanks
Sylvain
UserIdTAG: 640408
UserNameTAG: sbagnack
CreateTimeTAG: 2013-04-01T15:31:28Z
VoteTAG: 4
CoursewareTAG: Section 1: Introduction / Lec 1.3. Bar graphs: describing categorical data
NumberOfReplyTAG: 0
IndexTAG: 72
TitleTAG: Thank you Staff!
Dear Professor Ani and Staff,
Thank you so much for making learning Statistics a very pleasurable experience for me and helping me gain many skills and insights about Statistics with the very well delivered lessons and the thought-provoking problems. It has indeed been a fun experience and I look forward to taking the next Statistics courses in the future.
-Daniel
UserIdTAG: 744649
UserNameTAG: SubconsciousObserver
CreateTimeTAG: 2013-04-01T15:31:05Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 73
TitleTAG: Thank you from Costa Rica
Thanks a lot for the excellent statistics course!
I enjoyed it very much and look forward to Stat 2.2X.
UserIdTAG: 1288995
UserNameTAG: olsolis
CreateTimeTAG: 2013-04-01T15:10:23Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 74
TitleTAG: many thanks
many thanks, it's so good to learn Statistics from professors at Berkeley and lives in romania
UserIdTAG: 1140440
UserNameTAG: ocantea
CreateTimeTAG: 2013-04-01T14:48:17Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 75
TitleTAG: Thanks from Costa Rica
I would like to thank the professors for this amazing course!!! Thanks for sharing with us your knowledge.
UserIdTAG: 1279047
UserNameTAG: loriase
CreateTimeTAG: 2013-04-01T14:39:57Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 76
TitleTAG: Special thanks for Professors,
Special thanks for the staff of this 6 Sigma Course!
UserIdTAG: 63180
UserNameTAG: ianton
CreateTimeTAG: 2013-04-01T13:31:56Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 77
TitleTAG: Thanks for a great course! But I need some followup work
This has been a great course! The challenge at times has pushed me to do more than I thought I could.
Having said that, I really need some more work on the whole regression topic. I just have not wrapped my mind around it. The last half of the final was a real struggle. Is there anywhere I could get some more insight into this topic?
UserIdTAG: 297742
UserNameTAG: GregDC
CreateTimeTAG: 2013-04-01T13:19:17Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Download the videos and slides.
Go through them carefully before the start of Stat 2.2x.
I went through the regression part three times, making notes, before feeling comfortable with the topic
FirstChildUserIdTAG: 344400
FirstChildUserNameTAG: carlallen
FirstChildCreateTimeTAG: 2013-04-01T15:31:24Z
FirstChildVoteTAG: 3
SecondChildTAG: I was in same situation. I read and watch video several times to get my understanding on the subject. I planning to going through Prof. AA's recommended book before the start of the 2.2X
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-04-01T15:37:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm glad I am not the only one that has a problem with this. thanks
SecondChildUserIdTAG: 297742
SecondChildUserNameTAG: GregDC
SecondChildCreateTimeTAG: 2013-04-02T14:08:54Z
SecondChildVoteTAG: 0
FirstChildTAG: That is up to you. There are plenty of books, webpages and even free courses. Or, shock, paid courses.
To really understand this topic requires working on complex assignments, something that moocs haven't yet figured out how to accomplish.
So if you are serious, you might have to enrol in a proper degree course where you will be given assignments that involve more than a single number answer.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-04-02T07:12:21Z
FirstChildVoteTAG: 0
IndexTAG: 78
TitleTAG: Course Estimate of Hours
Hello Professor A.
I am a Certified Public Accountant and would like to include this course as part of my general credits for my CPA license renewal. I noted that Berkeley X is not registered as a NASBA sponsor, so, I would need you or the staff to provide an estimate of the hours that this course takes (maybe using a pilot or an estimate based on how long it takes to take this course sitting in a normal classroom) so that I can use them to register them with NASBA in my next renewal.
I’m not sure if the certificate will have an estimate of hours, but I could use an answer in the Discussion Forum to supplement the certificate if it does not include them. I will really appreciate your answer.
Statistics kind of a “new requirement” for the banking industry’s model development in Puerto Rico therefore, this makes a very good match with the credits I need for the license. I will really appreciate if you could provide feedback; I am 7 months pregnant and will not have that much time to after the birth to engage in a lot of study sessions.
I will also enroll in Stat 2.2x and, so far, I expect to complete it before labor, so if you could, I will need an estimate of hours for the Stat2.2x course as well.
Thank you for the course, it has been of great help in refreshing concepts that I will need in the near future.
Best Regards, Danilisse.
UserIdTAG: 1067880
UserNameTAG: dpadilla
CreateTimeTAG: 2013-04-01T12:50:42Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 79
TitleTAG: Certificates
Has anyone got their certificate as of yet?
How about everyone reply to my post when they do get their certificates and we can study the receipt of certificates as a time-dependent stochastic statistical process?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-04-01T12:18:56Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For the record, I made that last bit up...I do not have any idea what it means
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-04-01T12:22:58Z
FirstChildVoteTAG: 0
IndexTAG: 80
TitleTAG: Thanks from Italy!
Thanks a lot to prof. Adhikari and the edX staff for this excellent course! It was a great chance for me to understand the physical meaning behind methods that we often use at work in a bit of a mechanical way. Also, being back in Uni was a nice sensation :) Looking forward to Stat 2.2X!
UserIdTAG: 407687
UserNameTAG: AndreaPi
CreateTimeTAG: 2013-04-01T11:06:40Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi ! I'm from Italy too :)
FirstChildUserIdTAG: 1128890
FirstChildUserNameTAG: RobertoSam
FirstChildCreateTimeTAG: 2013-04-02T08:44:34Z
FirstChildVoteTAG: 0
IndexTAG: 81
TitleTAG: Course material availability
Thanks a lot for this wonderful course!!!
I wanted to know if the course videos will be available after the close of the course?
UserIdTAG: 1111917
UserNameTAG: rajeswariv
CreateTimeTAG: 2013-04-01T10:37:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes, it will be available. Prof. AA wrote in the one of her blog (Check course info tab and March 29 post)
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-04-01T15:40:14Z
FirstChildVoteTAG: 0
IndexTAG: 82
TitleTAG: Million Thanks
One million thanks to you my able prof. You made statistics quite easy for me and I look forward to 2.2
UserIdTAG: 915660
UserNameTAG: decomrador
CreateTimeTAG: 2013-04-01T10:30:45Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I second this!
FirstChildUserIdTAG: 1017108
FirstChildUserNameTAG: LoriJG
FirstChildCreateTimeTAG: 2013-04-01T11:17:18Z
FirstChildVoteTAG: 1
IndexTAG: 83
TitleTAG: Many thanks Prof A!
Thanks a bunch Prof A.! Just saw the midterm data.
And a big THANK YOU for teaching this course. You are really one of those rare **excellent** teachers that people feel lucky they learned from!
Wish I had more time to complete the exercises and lectures this time, but now that I know how much time to put into 2.2, I'll be better prepared with my schedule. I'm glad there's a few days left, because now I can catch up on the material I couldn't get to this time.
Looking forward to learning more in 2.2!
Veena
UserIdTAG: 1347279
UserNameTAG: VeenaChatti
CreateTimeTAG: 2013-04-01T09:51:54Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Dear Prof. A,
Many many thanks for your extraordinarily clear lessons and unhurried explanations. You really gave me a new perspective on how to approach data analysis, such as the power a simple step of converting values to standard values.
I am looking forward eagerly to 2.2 :)
Vidya.
FirstChildUserIdTAG: 1238162
FirstChildUserNameTAG: JSVidya
FirstChildCreateTimeTAG: 2013-04-01T17:24:22Z
FirstChildVoteTAG: 0
IndexTAG: 84
TitleTAG: Thanks!
Thanks to Prof. A and all the staff at EdX for allowing us this wonderful opportunity! My father was a statistics professor. As a college student I helped him check the test papers of his students. It wasn't easy!
Seeing this wonderful new medium of learning and checking a student's progress opened up my eyes. No piles of papers! No headaches from checking! No need to go to the back of the class if you feel sleepy - listen to the lectures when your mind is a lot clearer. There were lots of chances to go back to lessons I didn't understand so well.
Dr. Ani's way of explaining stats is also good, as she has an "English" version and a "Math" version. I felt discouraged whenever I didn't have the chance to study the lessons on time, but somehow she made it very easy to learn and take the tests.
Didn't also know if my old iPhone 3Gs (which became a "brick" once, and was revived) would be up to the task. My work hours are unpredictable so I had to use this phone for the midterm using my cellular network. The font is small, the applet is harder to use, it is a nightmare opening lots of windows! :) But it worked! :)
Once again, a big THANKS, and congratulations to fellow students for doing the course.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-01T09:32:24Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I could not agree more... it was fun to be back at school, although in a different way. The "English" and "Math" versions, along with funny comments, made learning very easy. I can't wait for 2.2 course...
Congratulations to prof. A and her colleagues as well as to fellow students - and thanks to you all! I have found comments and useful tips from fellow students an invaluable learning tool.
FirstChildUserIdTAG: 1188102
FirstChildUserNameTAG: Mojca
FirstChildCreateTimeTAG: 2013-04-01T18:21:50Z
FirstChildVoteTAG: 0
IndexTAG: 85
TitleTAG: Good course!
See you next time!!!
UserIdTAG: 48745
UserNameTAG: viktar
CreateTimeTAG: 2013-04-01T09:32:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 86
TitleTAG: New amazing course
Hey guys!
If you want to become a true statistics jedi, don't miss a new coursera course [Underwater Bascketweaving][1] starting today.
I'm so excited to participate in it!
By the way, students who successfully complete this course will receive a Statement of Accomplishment signed by the instructor and a 1500-watt professional hair dryer.
[1]: https://www.coursera.org/course/basketweave
UserIdTAG: 1296275
UserNameTAG: YaroslavD
CreateTimeTAG: 2013-04-01T08:34:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: This might be an "April the Fool" course!
FirstChildUserIdTAG: 18529
FirstChildUserNameTAG: Bedilu
FirstChildCreateTimeTAG: 2013-04-01T09:28:12Z
FirstChildVoteTAG: 3
SecondChildTAG: Yes, of course it is, but it's funny :)
SecondChildUserIdTAG: 1071309
SecondChildUserNameTAG: _Helena_
SecondChildCreateTimeTAG: 2013-04-01T12:23:51Z
SecondChildVoteTAG: 0
SecondChildTAG: You revealed this "secret" too soon, I was hoping someone would fall for it :)). Nice joke from Coursera, I was laughing a lot.
Also check out new Google Nose service - http://www.google.com/landing/nose/index.html
SecondChildUserIdTAG: 1296275
SecondChildUserNameTAG: YaroslavD
SecondChildCreateTimeTAG: 2013-04-01T13:28:04Z
SecondChildVoteTAG: 0
FirstChildTAG: I have enrolled myself, great and wet course! ;-)
FirstChildUserIdTAG: 63180
FirstChildUserNameTAG: ianton
FirstChildCreateTimeTAG: 2013-04-01T13:23:19Z
FirstChildVoteTAG: 1
IndexTAG: 87
TitleTAG: Thanks Dr.A
Dr.A
Thank you so much for coming up with this intro course to statistics. We all appreciate your efforts you've put in to make this course a grand success.
Looking forward to Stat 2.2!!!!!!!!!!!!
UserIdTAG: 1118635
UserNameTAG: imati
CreateTimeTAG: 2013-04-01T08:32:20Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thank u Dr. for this class
FirstChildUserIdTAG: 1515331
FirstChildUserNameTAG: Elryah
FirstChildCreateTimeTAG: 2013-04-01T08:59:26Z
FirstChildVoteTAG: 0
IndexTAG: 88
TitleTAG: about cerificate of passing
Dear Sir/madam
when we will receive the Passing certificate.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-04-01T07:37:39Z
VoteTAG: 15
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is not a passing certificate it is a completion certificate, they will be available "from 1st April", you will see it on your dashboard for downloading
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-04-02T06:30:02Z
FirstChildVoteTAG: 0
IndexTAG: 89
TitleTAG: Thanks!
Thank you, Prof A and the entire team for making the course so interesting and SIMPLE. It has been years since I have done a course and it was worth it. Looking forward to 2.2X
UserIdTAG: 998199
UserNameTAG: kolyn
CreateTimeTAG: 2013-04-01T07:26:38Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 90
TitleTAG: Stat 2.1X
Thank you Prof A and all the faculty and staff of Stat 2.1 X for taking so much time to help me out with statistics. I am very grateful
UserIdTAG: 1258579
UserNameTAG: shalinicn
CreateTimeTAG: 2013-04-01T05:47:05Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 91
TitleTAG: I just found this lecture will they open it again in the near future? Or other basic statistics course?
I just found this lecture will they open it again in the near future? Or other basic statistics course?
UserIdTAG: 777512
UserNameTAG: juanmahaganti
CreateTimeTAG: 2013-04-01T05:14:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 92
TitleTAG: Thanks To Prof A and The Edx Staff
Many thanks to Prof A and The Edx staff. Stat 2.1x was such a great experience to me and i learn so many things.. Thank you...
UserIdTAG: 1193006
UserNameTAG: makmursp
CreateTimeTAG: 2013-04-01T03:12:30Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 93
TitleTAG: Thank you Prof. A!! From the Philippines
I am currently a science teacher at our school and have started our research program, and with that I want to train my students already on basic statistics skills in the field of research in science. This course helped me a lot, though I may not have anymore have time for stat2.2x due to our upcoming classes, will still try my best always. Thank you again and I will always keep myself posted.
UserIdTAG: 1235301
UserNameTAG: Marts
CreateTimeTAG: 2013-04-01T02:28:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 94
TitleTAG: Greetings and thanks to miss A from Bolivia
I really enjoyed this course. I think everybody noticed how well made the videos and slides were, and the fluency from every topic was excellent. Congrats! Miss A. and everybody who putted so much effort for bringing us this course.
I cannot wait for 2.2x
UserIdTAG: 1316542
UserNameTAG: Dodavor
CreateTimeTAG: 2013-04-01T01:36:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 95
TitleTAG: Stat professors have other lives ...
Professor Ani Adhikari has shared with us some aspects of her private life: "Just in case people think Stat professors have no other lives ..."
It's so cute!
Please, do not miss it.([http://www.stat2x.blogspot.com.es/][1])
An advice: read it while listening the song [https://www.youtube.com/watch?v=P3oTUdlvYzs][2]
[1]: http://www.stat2x.blogspot.com.es/2013/03/on-turquoise-cloud.html
[2]: https://www.youtube.com/watch?v=P3oTUdlvYzs
UserIdTAG: 918956
UserNameTAG: a-per
CreateTimeTAG: 2013-03-31T22:56:22Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 96
TitleTAG: Many Many Thanks to Prof. A
I have taken this course. Though I was always playing catchup with the video lectures and assignments. But in the whole process I learned a lot. I was able to finish up many assignments on time but could'n get to mid-term and final on time.
Looking forward to 2.2x.
UserIdTAG: 974077
UserNameTAG: ransanjeev
CreateTimeTAG: 2013-03-31T20:27:09Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I'm really looking forward to 2.2X... I study economics at the university of Piraeus,in Greece,so...statistics is a very important field for me.Congrats for all your efforts!!! :D
FirstChildUserIdTAG: 1241690
FirstChildUserNameTAG: KravvaritisChristos
FirstChildCreateTimeTAG: 2013-03-31T21:51:33Z
FirstChildVoteTAG: 1
SecondChildTAG: What can we say_ THANK YOU and looking forward for more statistics!
SecondChildUserIdTAG: 911813
SecondChildUserNameTAG: vukasinbvasic
SecondChildCreateTimeTAG: 2013-03-31T22:23:51Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks to Prof. A, you are a great instructor
FirstChildUserIdTAG: 1104740
FirstChildUserNameTAG: dramrali
FirstChildCreateTimeTAG: 2013-03-31T23:49:58Z
FirstChildVoteTAG: 2
IndexTAG: 97
TitleTAG: Greetings from Ghana to Prof. A
We those from Ghana send our hearty appreciation to prof A and all the Stat 2.1x staff, we are still waiting to sign-up to stat2.2x.
LONG LIVE EdX!, Long live MOOCs !!
UserIdTAG: 820147
UserNameTAG: frimpongmaxwellkwadwo
CreateTimeTAG: 2013-03-31T16:38:01Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I missed my homeland. Hope everything is good in GH for real. Long live Ghana.
FirstChildUserIdTAG: 751214
FirstChildUserNameTAG: weltyscotus
FirstChildCreateTimeTAG: 2013-04-01T09:48:37Z
FirstChildVoteTAG: 1
IndexTAG: 98
TitleTAG: with thanx
I wish I could express my gratitude in th same way as so many of these posts, but in truth I can't. Even though I passed alright I found this course very difficult and complex; in short, I was never good at word problems and this course was a fine reminder of that. Just th same I'd like to thank those at Cal-Berkeley and edX for an illuminating experience and as for me, I'm headed back to th liberal arts world where I hope I can get some of my ego back. thanx again.
UserIdTAG: 950367
UserNameTAG: catt9
CreateTimeTAG: 2013-03-31T16:16:28Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: this post is NOT about Ex. set 1
FirstChildUserIdTAG: 950367
FirstChildUserNameTAG: catt9
FirstChildCreateTimeTAG: 2013-04-01T00:55:22Z
FirstChildVoteTAG: 0
IndexTAG: 99
TitleTAG: Where is my Certificate? Calling from Somalia
What a trip? it was fun and it helped me like statistics even more, I always liked it but this course made me even like it more.. to make it short.. I got 81% where is my certificate?
Congrats to all who passed and good luck to all in general, what is next prof? and where is my certificate?
UserIdTAG: 929984
UserNameTAG: Moti01
CreateTimeTAG: 2013-03-31T15:57:13Z
VoteTAG: 1
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 1
FirstChildTAG: Hi!
Information about certificates is given on the Edx website:
[https://www.edx.org/help#certificates_and_credits_faq][1]
[1]: https://www.edx.org/help#certificates_and_credits_faq
I hope it helps.
FirstChildUserIdTAG: 918956
FirstChildUserNameTAG: a-per
FirstChildCreateTimeTAG: 2013-03-31T22:11:18Z
FirstChildVoteTAG: 3
SecondChildTAG: thanks..
SecondChildUserIdTAG: 929984
SecondChildUserNameTAG: Moti01
SecondChildCreateTimeTAG: 2013-04-01T08:30:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi Moti....ummm "Moti" means "gem" in India (at least in Bengali, one of the many languages spoken in India). What does it mean in Somalian? Hope you don't mind...just curious
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-04-01T12:21:33Z
SecondChildVoteTAG: 0
IndexTAG: 100
TitleTAG: 20% took the midterm
I was expecting more but considering regression to the mean probably only 10% by MOOC standards completed the course
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-31T15:38:36Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: One thing though is of all the excuses that I saw on the forum not to complete the assignments no one said that the dog ate the homework !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-31T15:51:55Z
FirstChildVoteTAG: 6
SecondChildTAG: I would have said that but my dog has passed away days before I started the course..:(
SecondChildUserIdTAG: 929984
SecondChildUserNameTAG: Moti01
SecondChildCreateTimeTAG: 2013-03-31T16:08:13Z
SecondChildVoteTAG: 0
SecondChildTAG: You're not serious? Are you? My condolences then...used to have a dog myself...
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-04-01T03:16:52Z
SecondChildVoteTAG: 0
SecondChildTAG: If it is true I am very sorry about it.I try to help injured animals(mainly cats) who come to my house when injured(don't know why they do so but they do and I am a human Doctor and mot a vet !!- I have admitted some to an ICU for as long as a month !! Feel really sorry for you.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-04-01T16:44:45Z
SecondChildVoteTAG: 0
FirstChildTAG: Only 20%! :(((
Quality online education offered by edx are golden gifts without strings.
Why or why does people pass it up? :(((
FirstChildUserIdTAG: 584390
FirstChildUserNameTAG: pluribus
FirstChildCreateTimeTAG: 2013-03-31T19:36:48Z
FirstChildVoteTAG: 1
SecondChildTAG: Well, I think that some of us are enrolling for many courses (It's my way of being on Coursera) just to see what will be going on, to judge, how many times do we need, how interesting it will be and also how difficult. I would love to participate in many moocs, but there is a live outside. I got my job, my phd and my master thesis in ( both in progress), family and friends.
BUT I really loved Stat2.1. It was joga to my brain :)
SecondChildUserIdTAG: 1338976
SecondChildUserNameTAG: karusia
SecondChildCreateTimeTAG: 2013-03-31T19:50:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Pluribus, I'm not quite sure people ignored it completely. Have you considered that those who have busy lives and already had > 35%, may have decided not to do it, or do it after the hard deadline? (not my case, I assure you!) Still, 20% :-/ ... perhaps it's a good benchmark for the future?
SecondChildUserIdTAG: 632581
SecondChildUserNameTAG: GMendes
SecondChildCreateTimeTAG: 2013-03-31T20:39:14Z
SecondChildVoteTAG: 0
FirstChildTAG: That's why people should not complain about the 35% pass mark, the fact that one reached the end and did the **FINAL EXAM** is an achievement by itself. It shows initiative, self-discipline, determination, committment, good organizational skills and a focussed mind on oneself. Which serious employer wouldn't want this traits on a potential employee? So even if my certificate doesnt count for anything, in my next job interview I'll make sure I drive this point home.
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-03-31T20:44:21Z
FirstChildVoteTAG: 7
SecondChildTAG: Seconded! :)
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-03-31T22:47:06Z
SecondChildVoteTAG: 0
SecondChildTAG: I mentioned that I was taking this course in one of my PhD interviews (I'm getting a degree in a non-science based program where students are terrified of statistics!) and the professors were really impressed. So use it! It works!
SecondChildUserIdTAG: 1017108
SecondChildUserNameTAG: LoriJG
SecondChildCreateTimeTAG: 2013-04-01T11:23:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks LOriJG, good to know it works
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-04-02T15:34:29Z
SecondChildVoteTAG: 0
FirstChildTAG: > Which serious employer wouldn't want this traits on a potential employee?
True. And an employer, who is aware of the pitfalls of online learning, will sit you down with a dataset and a computer. Then ask you to demonstrate your new knowledge.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-31T22:53:10Z
FirstChildVoteTAG: 3
SecondChildTAG: Which is perfectly acceptable to do- that is why you have taken the course.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-04-01T02:38:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Judging from the Mid-term performance, it can be implied that most of the 20% who took the exam have statistical competencies hence able to demonstrate the new knowledge to employers if need arises.
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-04-01T10:34:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Implied competence? I don't think so. Some of what I've seen here does not instill a lot of confidence.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-04-04T05:33:41Z
SecondChildVoteTAG: 0
IndexTAG: 101
TitleTAG: RMS Errors in a Football scatter diagram
I am catching up on the last lectures only now. Apologies for that. But I have a question
In a foot ball shaped scatter diagram both the axis are individually normal shaped. So:
a.) 68% of y will be covered in Average +- one SD
b.)Now since we are using regression we know that the rms error is less than using the average as is.Example is there in the slide 2 of lecture 8.2 where SD was 0.4gm and rms error is 0.32bm
So let say after combining a and b together, should not the rms error in a football shaped scatter diagram be better than a niormal curve. i.e should not +- 1 RMS error cover more than 68% of the points in the scatter diagram??
UserIdTAG: 87424
UserNameTAG: Sknair
CreateTimeTAG: 2013-03-31T14:40:24Z
VoteTAG: 2
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 1
FirstChildTAG: Within each vertical stripe, values of b will follow the normal curve and mean will lie on the regression line. Because values follow the normal curve, 68% values will lie in the 1sd. sd for regression is rms which will always be lesser than the typical value of b i.e.32gm in this case.
For your question, +-RMS should cover more than 68%, Normal curve is in **standard units**, so doesn't matter, what's the value of b, +- 1 sd will always 68%.
FirstChildUserIdTAG: 974077
FirstChildUserNameTAG: ransanjeev
FirstChildCreateTimeTAG: 2013-03-31T20:17:52Z
FirstChildVoteTAG: 2
IndexTAG: 102
TitleTAG: Edx MOOC: Why 35% and not one bit more or less?
There are *two associated variables* that give rise to the 35% *average*. And it is the wrong notion of average as a pass/fail that will be discussed here, and why the right notion has a 35% context for a MOOC course. And of course we all know that we are talking about *average* and not the 35th percentile but to reassure us all, Edx, as far as I know, has no policy of wanting only 65% of participants to pass.
But before we continue let us take look at *35% in context* using the continuum of ... data to information to knowledge to understanding for an *Edx MOOC* course. (I know some of us are impatient but we will come to the two variables in a couple of minutes!)
**Edx MOOC** represents a very thoughtful approach to organize a substantial and targeted portion of the information available on the internet for effective and efficient use by anyone.
For instance, in terms of more education or continuing professional development (not further education) on a specific topic, one could likely look at an Edx course and do it out of the offer period in a couple weeks of intensive effort. The rigor and certainty of the Edx course would certainly replace googling. And while the certificate would most certainly be welcome, it is the access to organised information that is of immediate value to working people. I make the point that Edx courses should be available at all times to meet the notion of accessibility and not be restricted to start-end periods.
Arrgh! One teenage daughter is now demanding lunch so I will continue this post later.
UserIdTAG: 344400
UserNameTAG: carlallen
CreateTimeTAG: 2013-03-31T14:09:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Life always gets in the way at the most inopportune moments - sigh! :)
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-03-31T22:48:57Z
FirstChildVoteTAG: 0
IndexTAG: 103
TitleTAG: Stat from Pr A 'About the midterm: about 20% of the students enrolled at that time took the exam...'
Wow, I would have thought more actually...
I will definitely read Prof A's blog to get more information on us.
I am particularly interested in knowing more about numbers of people. If I remember well we were about 47000 students registered at least the 1st week?...
Z
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-31T13:48:25Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I think 20% is quite high considering these courses are fairly new and many people are just experimenting. ָAnyway, I have learnt a fair bit and am very grateful to all those who have put effort into making this available. Thanks so much. Looking forward to Stat2.2X!
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-31T20:02:48Z
FirstChildVoteTAG: 3
IndexTAG: 104
TitleTAG: Edx: More education and not just higher education.
Edx MOOC represents a very thoughtful approach to organize a substantial and targeted
portion of the information available on the internet for effective and efficient use by anyone.
For instance, in terms of more education or continuing professional
development (not further education) on a specific topic, I would likely look at
an Edx course and do it out of the offer period in a couple weeks of
intensive effort. The rigor and certainty of the Edx course would certainly replace
googling. And while the certificate would most certainly be welcome, it is
the access to organised information that is of immediate value to working
people. I make the point that Edx courses should be available at all times
to meet the notion of accessibility and not be restricted to start-end
periods.
The above said, many thanks to all concerned including community participants and I look forward to Stat 2.2x continuing in the vein ... data to information to knowledge to understanding.
UserIdTAG: 344400
UserNameTAG: carlallen
CreateTimeTAG: 2013-03-31T13:04:58Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 105
TitleTAG: Congratulations and many thanks from Tokyo
Dear Professor A and staff
Congratulations on and many thanks for your great teaching. You successfully taught us not only the subject substance, but also the joy of STATS-learning. We really look forward to taking Stats 2.2 X.
Cheers
UserIdTAG: 899455
UserNameTAG: amizumot
CreateTimeTAG: 2013-03-31T12:31:54Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 106
TitleTAG: hi
some vedios can be not opend
UserIdTAG: 905755
UserNameTAG: alamri1
CreateTimeTAG: 2013-03-31T12:31:43Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I noticed that too ... but I discovered that if you click the "YouTube" button at the bottom those videos usually turned up ... in fact you got to watch the whole series of them in one sitting rather than having them broken up into a series of shorter shows ... ... at least this worked for Professor Stark's video's in the text material ...
FirstChildUserIdTAG: 1287965
FirstChildUserNameTAG: ReadeDavis
FirstChildCreateTimeTAG: 2013-03-31T19:16:23Z
FirstChildVoteTAG: 0
IndexTAG: 107
TitleTAG: Help with further explanation for 6E in the final
Dear staff and peers learning on this course,
I know that this course is over. I really appreciate this learning experience, which really gives me a good opportunity to learn from this course and you.
After see the explanation, i am still not quite clear about 6E.
Why SD is 0.15? i cannot figure out.
Thanks a lot.
UserIdTAG: 547145
UserNameTAG: Pronectar
CreateTimeTAG: 2013-03-31T12:11:29Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Let me try to help. I'm considering you got 6D right. Here, you have to use the information given on the length of the petals. It has a normal distribution (since the scatterplot is football shaped), with average 3.1 cm and SD 0.25 cm. So finding the 45th percentile is easy.
For question 6E, you have to consider a regression line on the scatterplot. Of all the data in the scatterplot, we're only interested in the petals that are 1.8 cm wide. These petals, do they have a normal distribution? Yes, because the scatterplot is football shaped. Do they have a SD? Obviously. Is it the same as in the previous question? No, because of the shape of the scatterplot, you can imagine that the length of the petals that are 1.8 cm wide is much more concentrated around its average than the length of **all** petals. Maybe this petal-unrelated graph ![graph][1] I've found online helps (unfortunately, it lacks a scatterplot, but you can see all the normal curves explaining the distribution of each "petal width"). Notice how the normal curves have an average (equal to the regression estimate of each "petal width") and all have the same SD (since the scatterplot is football shaped - *homoscedasticity*). That SD is the r.m.s. of the regression line. You are to find a 45th percentile much like you did in 6D, but the average is the regression estimate of 1.8 (which is 3.1) and the SD is the r.m.s.: √(1-0.8^2)*0.25 = 0.15.
[1]: http://www.psychstat.missouristate.edu/introbook/sbgraph/regress9.gif
FirstChildUserIdTAG: 632581
FirstChildUserNameTAG: GMendes
FirstChildCreateTimeTAG: 2013-03-31T14:03:58Z
FirstChildVoteTAG: 2
SecondChildTAG: thanks a lot. I just do not understand why SD is the r.m.s of the regression line
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-04-01T13:33:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Since you mention the explanation provided, may be point of average is not clear. So I am adopting general approach & showing minor steps. Length & breadth of petals are linearly related with a football shaped scatter-plot. Breadth is independent variable on x-axis. length is dependent variable on y-axis. y-coordinate of a point on regression line gives the average or regression estimate of length of petal of a given breadth (corresponding to x-coordinate) . Concentrate on verticlal strip of petals that are 1.8 cm wide . Regression estimate of length of,1.8 cm wide petals = 3.1 cm ( both respective means & therefore both are 0 in Standard Units . ) **SD of a football shaped( & therefore homoscadastic) scatter plot is rms error 'e'; e = [sqrt(1 - r^2)]*SD ; SD is SD of length of petals=.25cm; solving it gives e=.15cm** Now 45th percentile is -0.125 i.e. 0.125 SDs below average ; hence 45th percentile of the petal lengths (in cm)= -0.125*0.15 + 3.1 Hope it helps! If not please tell specific difficulty or the step you want explanation about.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-31T14:38:49Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks a lot. I just do not understand why SD is the r.m.s of the regression line
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-04-01T13:33:47Z
SecondChildVoteTAG: 0
SecondChildTAG: The rms of error is the equivalent of SD in a bivariate normal scatterplot.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-04-01T16:46:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Y-coordinate of each point on Regression Line gives estimate of average value of unknown variable( here length ); if the known variable( here width ) is equal to X-coordinate of that point. In this context that is the only purpose of regression line . To estimate average length of petal for a given value of width of petal . Here that estimate (average length of 1.8cm wide petals) turns out to be 3.1 cm . But that's just average value. If we consider all the petals, that are 1.8 cm wide, 'their lengths' are spread above and below this 3.1 cm average point on the vertical strip & this distribution is normal . SD of this distribution of 'limited set of only 1.8 cm wide petals' is less than SD of distribution of lengths of 'whole set of petals of all possible widths'. The later is given to be .25 cm. And SD of only 1.8 cm petals is rms error = .15cm (calculated above).(In fact rms error is SD of all vertical strips in this football shaped scatter plot & not just that of vertical strip of 1.8 cm wide petals) You can also see video Lecture 8.2 or refer to chapter 11 of our online textbook. You may ask here further if need be. Hope its helpful!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-04-01T18:38:00Z
SecondChildVoteTAG: 0
FirstChildTAG: > Why SD is 0.15? i cannot figure out.
Because you are looking at the error around the regression line, not the error of the individual variables.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-31T21:37:18Z
FirstChildVoteTAG: 0
IndexTAG: 108
TitleTAG: Great course
Professor A -
I really enjoyed taking Stat2.1 and plan to take 2.2, if I can figure out how to sign up for it! Is there any way to send a message directly to you (or others) aside from the public discussion? Just wondered.
Thank you for giving us this opportunity.
UserIdTAG: 16539
UserNameTAG: islandbirder
CreateTimeTAG: 2013-03-31T11:57:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 109
TitleTAG: STAT2.2X
Dear Professor A,
It has been a privilege attending your lectures. I learnt so much; even though I did not score good marks. After all, I am getting old. However, at 44, I find good use of what I learnt which I could not have found earlier in my career.
I am eagerly looking forward to STAT2.2X and STAT2.3X. I understand that STAT2.2X will start from 12Apr13. However, I do not find this course in my course list. How do I enroll? Request your kind advice as I am no mood to miss this program.
Thanks and Regards,
Partha Majumdar
PS: You have a great blog. Maybe, you would also spare some time to go through my blog at http://www.parthamajumdar.org.
UserIdTAG: 359166
UserNameTAG: PARTHA6369
CreateTimeTAG: 2013-03-31T11:49:29Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: At 59 years old it took me a while to get adjusted but I did.
FirstChildUserIdTAG: 344400
FirstChildUserNameTAG: carlallen
FirstChildCreateTimeTAG: 2013-03-31T12:50:16Z
FirstChildVoteTAG: 1
IndexTAG: 110
TitleTAG: Diolch yn fawr from Bulgaria
That is thankyou from an ancient Welshman in Bulgaria for an excellent course excellently presented. All my objectives achieved including the unexpected one of discovering that histogram is not just a posh way of saying barchart!
UserIdTAG: 7854
UserNameTAG: pejic
CreateTimeTAG: 2013-03-31T08:49:48Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 111
TitleTAG: Downloadable textbook
Is there an easy way to download the text materials so that I have them for future reference?
UserIdTAG: 1085170
UserNameTAG: LionelHutz
CreateTimeTAG: 2013-03-31T04:34:32Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is an online text, designed to be used interactively and online. So, no.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-31T07:51:12Z
FirstChildVoteTAG: 0
IndexTAG: 112
TitleTAG: Easter wishes...
Hearty thanks to the team of stat2.1. The course was well structured and made learning statistics interesting. Hopeful that Stat2.2 & 2.3 would be a great learning experience.
Congratulations to all those completed the course with a lot of gains in the subject and Happy Easter wishes to all, as well.
UserIdTAG: 1322988
UserNameTAG: tomwilson329
CreateTimeTAG: 2013-03-31T02:00:25Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 113
TitleTAG: Thank you for a wonderful Course
Thank you Professor. It was a very Good course & I learnt a lot!
Thanks for providing me an opportunity to learn & challenge myself!
UserIdTAG: 60584
UserNameTAG: gbellary
CreateTimeTAG: 2013-03-31T00:58:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: i congralation all teems- thank you professor - it was exclant course,sudan
FirstChildUserIdTAG: 926316
FirstChildUserNameTAG: alsadig310
FirstChildCreateTimeTAG: 2013-03-31T06:04:34Z
FirstChildVoteTAG: 0
IndexTAG: 114
TitleTAG: Thanks
To Dr. A and all of the Stat 2.1x staff (and my fellow students):
Thank you for the wonderful experience. You have inspired me to continue the Stat sequence and I look forward to seeing you in the coming weeks!
(And, Dr. A, I really enjoyed your sense of humor in the lectures!)
Thanks again!
UserIdTAG: 1071329
UserNameTAG: jpfred
CreateTimeTAG: 2013-03-31T00:58:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 115
TitleTAG: Wonderful it would take a calculus course ...
... in the second semester 2013 with Professor Ani, right?
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-03-30T23:16:47Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Sure! It would be an experience.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-31T00:15:17Z
FirstChildVoteTAG: 1
FirstChildTAG: Are You talking about some regular course on campus and not an online course?
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-04-02T06:16:08Z
FirstChildVoteTAG: 0
IndexTAG: 116
TitleTAG: Big Moroccan thanks...
Thank you very much for this course! Guess I finally got to really understand some statistics...
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-30T23:08:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 117
TitleTAG: Greetings from BELARUS!
Dear Professor Ani Adhikari,
I would like to say many thanks in address to You and Your Team! You did really useful and helpful thing (FOR FREE!). I hope that EDX becomes leading eLearning project in the world. You help for many students and young professionals (as I am) to recall and use on practice many topics! So thanks and God bless You all...
Best wishes,
Andrey GRISHKIN
Minsk, BELARUS
UserIdTAG: 787465
UserNameTAG: Andrey-Serge
CreateTimeTAG: 2013-03-30T22:35:30Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 118
TitleTAG: Thank you from South Africa
Thanks Prof, a brilliant course.
UserIdTAG: 1276165
UserNameTAG: Rael-Liss
CreateTimeTAG: 2013-03-30T22:20:03Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 119
TitleTAG: Thank Note
To Prof. A and to the Stat2.1x staff and to the co-students : Thanks a lot!!!
It was wonderful to be a part of this big 'classroom' (but not with its traditional connotation).
Best wishes.
-Dnyanesh
UserIdTAG: 1069242
UserNameTAG: kdnyanesh
CreateTimeTAG: 2013-03-30T19:21:50Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 120
TitleTAG: thank you from Uganda and Algeria
thank you very much for the great job. anxiously waiting for stat 2.2x
UserIdTAG: 439981
UserNameTAG: enom200
CreateTimeTAG: 2013-03-30T19:17:04Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hey Enom.
Where in abouts Uganda are you based? Im in Kampala, maybe we can meet for a coffe when stat 2.2 starts
FirstChildUserIdTAG: 1217071
FirstChildUserNameTAG: SifaP
FirstChildCreateTimeTAG: 2013-03-31T15:58:11Z
FirstChildVoteTAG: 1
IndexTAG: 121
TitleTAG: a handful of thanks
my thanks goes to the edx team. and all of you guys who constantly helped me and others through the discussion forum. keep the spirit up the spirit up for the next course
UserIdTAG: 439981
UserNameTAG: enom200
CreateTimeTAG: 2013-03-30T19:04:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 122
TitleTAG: Thank you from Cyprus
Great course, amazing teachers and fantastic colleagues!!! Such a positive experience for my first course with EdX. Thanks to all :-)
UserIdTAG: 1069830
UserNameTAG: TheodoraCh
CreateTimeTAG: 2013-03-30T18:45:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hope you are coping. Thoughts are with people of Cyprus.
FirstChildUserIdTAG: 584390
FirstChildUserNameTAG: pluribus
FirstChildCreateTimeTAG: 2013-03-30T22:46:06Z
FirstChildVoteTAG: 2
SecondChildTAG: We are trying ... My country is in a difficult situation right now, but we hope for better days to come. Thank you.
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-31T05:42:58Z
SecondChildVoteTAG: 0
SecondChildTAG: +1 @pluribus
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-31T09:08:08Z
SecondChildVoteTAG: 0
IndexTAG: 123
TitleTAG: Thanks from Poland
Thank you very much, I like this course.
UserIdTAG: 1256261
UserNameTAG: ilow
CreateTimeTAG: 2013-03-30T18:41:14Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 124
TitleTAG: Problems connecting to site day final was due
Hi edX team and stat2X professors. I took the final shortly before the time it was due...during that time several times i submitted answers my connection with the site was interrupted, got errors. I Had to refresh multiple times before conecting again. It was not the computer cause i tried 3 diferent devices including an ipad and a pc... So well it took longer than expected and could not finish couple of last problems. Just wanted to let you know so you take the due steps to fix any bugs for those procastinators among us that wait until the end to take tests. Brenda
UserIdTAG: 1161260
UserNameTAG: bsalerno
CreateTimeTAG: 2013-03-30T18:35:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I suspect that allowing a 3 day window for a 2 hour test is already "Due Steps"
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-31T08:38:51Z
FirstChildVoteTAG: 2
IndexTAG: 125
TitleTAG: Thanks from Argentina - about the grading
Hello,
I would like to sent my gratitude to all the staff behind Stat 2.1X. This was my first experience with online education and I found it amazing.
I've been reading comments about the grading. I'm not sure if the complaints about the 35% for passing the course as too low are because people are going to obtain credits from this online course.
But I just wanted to point out that I don't think that a low percentage will discourage interested students, considering that we're taking this course voluntarily.
I think that even if we know that we already got the 35% at the beginnig of the course, we'll try to get better and better every time.
Best regards,
Pato
UserIdTAG: 689072
UserNameTAG: pato54
CreateTimeTAG: 2013-03-30T18:16:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 126
TitleTAG: More exercises - Where can we get them?
Dr. Adhikari,
This course was great. We learned a lot of nuances of topics which we had some idea already. I had learned about histograms, averages, sd and regression, but during this course I learned a lot more. Tests provided a lot of opportunity to dig deeper than the surface and understand these concepts.
Is there a web site where we can get more exercises? I would love to explore the concept of bivariate normal a bit more. Although I was able to solve the problems from the tests I think some more exercises will help understand the concepts deeply.
Thanks.
Rahul V
UserIdTAG: 278932
UserNameTAG: Rahulsv
CreateTimeTAG: 2013-03-30T17:42:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Have you tried the "Additional Practice" exercises?
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/94d4b5a81e374ccc96496bd1f01e459d/1c1bedac270e464a85e7697d806a7dc0/
FirstChildUserIdTAG: 823860
FirstChildUserNameTAG: mike111
FirstChildCreateTimeTAG: 2013-03-31T00:50:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Mike. I hadn't tried that. Perhaps in the frenzy of finishing the exams I forgot to look at that.
Rahul
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-04-01T17:14:48Z
SecondChildVoteTAG: 0
IndexTAG: 127
TitleTAG: Thank You from Singapore
Had such great in doing this course. The study material was absolutely amazing.
Thanks to all the staff and special thanks to Prof Ani.
Regards
Soma
UserIdTAG: 1219615
UserNameTAG: Good2Go
CreateTimeTAG: 2013-03-30T16:28:11Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 128
TitleTAG: How To Register 2.2x?
Stat 2.2x will begin on 2nd April but I don't know how to register it. Is there anyone who can tell me? Thanks!
UserIdTAG: 1403029
UserNameTAG: dsghg
CreateTimeTAG: 2013-03-30T16:10:24Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Same question from my side. Let me know if anyone has cracked that question
FirstChildUserIdTAG: 1219615
FirstChildUserNameTAG: Good2Go
FirstChildCreateTimeTAG: 2013-03-30T16:25:26Z
FirstChildVoteTAG: 2
SecondChildTAG: The prof mailed (and i quote):
"... Stat 2.2X starts on April 12."
So you have some time left I'd say ;-)
SecondChildUserIdTAG: 342554
SecondChildUserNameTAG: tijldb
SecondChildCreateTimeTAG: 2013-03-30T17:00:30Z
SecondChildVoteTAG: 0
FirstChildTAG: I think it will show up on edx website.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-03-30T17:38:05Z
FirstChildVoteTAG: 0
SecondChildTAG: good
SecondChildUserIdTAG: 984291
SecondChildUserNameTAG: vishwas_s
SecondChildCreateTimeTAG: 2013-03-31T11:14:45Z
SecondChildVoteTAG: 0
FirstChildTAG: registration has started now.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-04-02T05:49:15Z
FirstChildVoteTAG: 0
IndexTAG: 129
TitleTAG: Changes expected in upcomming stat 2 x series
I would thank Prof. A for offering this great course , though i already finished my college maths but after listening to this classes it completely changed my understanding on statistics!!!...thank you for that.
**The changes which i expect are**--
1.There should be some relaxation on the dead lines for submitting assignment by introducing hard deadlines with some penalty.
2.I would feel that increasing pass percentage would enhance quality students who get the certificate, 35% is too low.
UserIdTAG: 693537
UserNameTAG: Malal
CreateTimeTAG: 2013-03-30T15:30:46Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Anyone care to calculate the probability of passing the whole course by just guessing all the multiple choice questions. The course material was excellent, but with a 35% pass mark, the exercise sets and exams should be more challenging.
FirstChildUserIdTAG: 23266
FirstChildUserNameTAG: dnc
FirstChildCreateTimeTAG: 2013-03-30T17:55:32Z
FirstChildVoteTAG: 2
FirstChildTAG: I agree with and second both points. I missed several deadlines due to work and travel and it would have been very helpful if the deadlines for the mid-term and final could have at least stretched into the weekend. Still, I passed - but only on account of the low pass rate, and so it does not really feel like an achievement.
Anyway, thanks for the good course, learned a lot. Looking forward to 2.2
FirstChildUserIdTAG: 791982
FirstChildUserNameTAG: 210eurosMike
FirstChildCreateTimeTAG: 2013-03-30T19:57:47Z
FirstChildVoteTAG: 1
FirstChildTAG: > The changes which i expect are
You expect?
> but with a 35% pass mark, the exercise sets and exams should be more challenging.
The Prof explained her reason for the low 35%. Don't expect it in the next courses.
And I can see from comments here and on other posts, that many complainers just don't read messages. If they did, they would know why the mark was set at 35%.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T21:11:21Z
FirstChildVoteTAG: 2
FirstChildTAG: I think that 35 % is low mark too, but there are many different students with different knowledge.
Low mark is not like achievement thats true. But you can get it bigger it's only your bussines what mark get satisfaction for you. You can take your goal for himself.
FirstChildUserIdTAG: 918758
FirstChildUserNameTAG: viksrelis
FirstChildCreateTimeTAG: 2013-03-30T22:10:44Z
FirstChildVoteTAG: 1
FirstChildTAG: I once asked my teacher why pass is set at 60%. I still remember the pause and the look before he/she asked me whether I could be proud of myself for knowing less than half of what I have been taught. I dare not ask about why the extra 10% from 50%. That was a few decades ago. For edx courses which I cannot achieve 60% in my attempt, I will keep re-enrolling until I do.
FirstChildUserIdTAG: 584390
FirstChildUserNameTAG: pluribus
FirstChildCreateTimeTAG: 2013-03-30T22:44:01Z
FirstChildVoteTAG: 4
IndexTAG: 130
TitleTAG: thank u from Greece!!
thank u from Greece!!
UserIdTAG: 1147076
UserNameTAG: giomicho
CreateTimeTAG: 2013-03-30T15:21:55Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 131
TitleTAG: thanks from germany
vielen dank... thank you very much for offering this statistics course and this great material. i really appreciate the work of two very very smart and charming teachers... this course was during my university vacation and it was really worth taking it
UserIdTAG: 1280120
UserNameTAG: Rabia93
CreateTimeTAG: 2013-03-30T14:42:48Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 132
TitleTAG: Great Job
Professors,
Thanks for the stats course, it exceeded my expectations. Text, applets, lecture videos, slides, & EDX platform easy and intuitive. Even better is the flexibility to pause and focus on parts of the material as fits our busy lives.
Hope you were prepared for the size of online enrollment, I guess it might grow with your online reputation.
Thanks again, I appreciate the chance to continue with the rest of your series when available.
Rob
UserIdTAG: 940447
UserNameTAG: rob4511
CreateTimeTAG: 2013-03-30T14:40:33Z
VoteTAG: 9
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 133
TitleTAG: Thank you from Kenya
Really enjoyed the course and the wonderful Professors.Looking forward to Stat2.2x
UserIdTAG: 422336
UserNameTAG: lilian2012
CreateTimeTAG: 2013-03-30T14:34:28Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 134
TitleTAG: Thank you from China
Thank you very much, I like this course.
UserIdTAG: 258697
UserNameTAG: 123qws
CreateTimeTAG: 2013-03-30T14:30:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 135
TitleTAG: Exercise Set 3 - Problem 1
**One person can not be 18.59 years old, the correct answer needed be 19 year.**
UserIdTAG: 1058400
UserNameTAG: Rayde
CreateTimeTAG: 2013-03-30T14:15:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: > One person can not be 18.59 years old
Yes they can. 18 years 6 months and a few days and hours. We can break our age down to seconds if we want to.
And you missed the point of continuous data.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T21:22:30Z
FirstChildVoteTAG: 0
IndexTAG: 136
TitleTAG: A HEARTY THANKS
TO OUR DEAR PROFESSORS ADHIKARI AND JON STARK FOR THIS WONDERFUL EXPERIENCE IN LEARNING . IT WAS ALWAYS A PLEASURE TO BE PART OF SUCH ILLUSTRIOUS COMPANY A NOTE OF GRATITUDE FOR MAKING IT MEMORABLE ..... WILL KEEP COMPANY FOR 2.2X ...WITH WARM REGARDS .
UserIdTAG: 1145257
UserNameTAG: klarioncall
CreateTimeTAG: 2013-03-30T14:09:18Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 137
TitleTAG: More mathematics
Great teaching and splendid organization of the course. Thoroghly enjoyed being a part of this and I am not able to wait for Stat2.2x. I request you to provide some of the more mathematical parts of the course in separate pdfs,etc so that people like me interested in math will find it useful.(I am sure there will be many undergrads like me wanting more math!)
UserIdTAG: 227254
UserNameTAG: ashwinkalyan
CreateTimeTAG: 2013-03-30T13:56:28Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: My support for this. Kindly someone some suggest site for calculus.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-30T15:00:05Z
FirstChildVoteTAG: 1
SecondChildTAG: There are some Coursera MOOCs on calculus (I don't take them). Search for calculus there.
Free and good materials are available in the web. This summer I found a very promising open textbook (work in progress). I read most of the differential calculus part (not enough time at the moment to read cover to cover). IMHO its approach is excellent. I even sent comments to the author (typo reports and the like). He is really involved in his book and I think it's a serious attempt to provide a modern and pedagogically well-designed open textbook:
http://faculty.gvsu.edu/boelkinm/Home/Open_Calculus.html
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-31T09:32:23Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you
SecondChildUserIdTAG: 1277571
SecondChildUserNameTAG: cnishaanntt
SecondChildCreateTimeTAG: 2013-04-01T12:40:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-04-02T06:07:21Z
SecondChildVoteTAG: 0
FirstChildTAG: Getting a firm grasp on concepts and understanding is a main virtue of this course. Math supplements, though, are fine. So +1 (I miss a second supplement).
On the other hand, there are dozens of good books (free and non-free) out there with the math stuff. Most of them require a very solid background on calculus, by the way. See this one, for example:
https://www.math.umass.edu/~lavine/Book/book.html
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-30T21:17:53Z
FirstChildVoteTAG: 0
FirstChildTAG: There are plenty of other moocs out there where you can learn more advanced stuff. There are books. But it is basically up to you.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T21:29:41Z
FirstChildVoteTAG: 0
IndexTAG: 138
TitleTAG: EX12-3A: Why I got it Correct?
I don't know why the grader give a tick mark for that question. Is it a bug?
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13646511971277307.png
UserIdTAG: 498723
UserNameTAG: YLTO
CreateTimeTAG: 2013-03-30T13:47:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 139
TitleTAG: appreciation!!!!
many thanks from Nepal!!!!!!!
UserIdTAG: 635032
UserNameTAG: maheshsarki
CreateTimeTAG: 2013-03-30T13:43:43Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 140
TitleTAG: Thank you from Canada
Thank you for this excellent course. I am looking forward to Stat2.2x.
UserIdTAG: 807428
UserNameTAG: Brigitte2012
CreateTimeTAG: 2013-03-30T13:12:26Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 141
TitleTAG: THANK YOU VERY MUCH...
Thanks very much professor Adhikari and edx team for such a nice experience of learning...understood the statistics as well as enjoyed it...thanks again..looking forward to stat 2.2..
UserIdTAG: 1100109
UserNameTAG: docchinu
CreateTimeTAG: 2013-03-30T13:09:05Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: "...understood the statistics as well as enjoyed it..."
Well said. Although I'd also add that I was challenged by it.
Thanks Prof A! I look forward to 2.2x.
FirstChildUserIdTAG: 208750
FirstChildUserNameTAG: dorien
FirstChildCreateTimeTAG: 2013-03-30T18:14:10Z
FirstChildVoteTAG: 0
SecondChildTAG: "...understood the statistics as well as enjoyed it..."
Well said.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-31T09:02:45Z
SecondChildVoteTAG: 0
IndexTAG: 142
TitleTAG: how MOOC grades can be relied upon?
Dear Rosewoodbay,
Hello!
I applaud you for your observation : **I will grant you that many people will be discouraged by the lack of a grade.** That was the idea that was central to the post : Percentage scored should be mentioned in the certificate. Avoiding percentage in the certificates is only going to discourage serious students and encourage mediocrity.
Also accept my thanks for your kind words : **I don't want to skip past the new questions you posed. Let me just say that those are great questions and certainly would deepen this discussion.**
Again, I strongly support your view that : **Grades mean something when they can be counted on as being an accurate portrayal of academic performance. It's hard to see how a mooc could provide grades that can be relied upon. That's not to say that at some point in the future that won't be the case.**
Now , I invite you and all others for comments on reply to a post by Mr. Harineem : **I was shocked to see exam questions posted by some individuals in online forums requesting answers . Frankly I don't see why this people are doing the course if the only goal is to score rather than understand the material.** This is deplorable and I don't
understand why anybody opposing it, not be welcome . After all it affects the forum negatively. May be the remedy suggested is the reason for some opposition. In my view also **decreasing exam. duration for MOOC exam is not a good idea . But arranging for optional proctored exam is the way out . This is not my idea. EdX itself practised it for another MOOC viz. PH207x just two months back .** I don't know why this option is not available this time. There might be some technical problem . Even now all the results are with edX & it can arrange proctored exam only for those who are willing , at some later suitable time .
That can also make way for grading option for those interested. I conclude this by another quote from Harineem: **Ultimately edX has to make the call.** Because grading is never decided by the students themselves but by the faculty.
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-30T12:53:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: > . Avoiding percentage in the certificates is only going to discourage serious students and encourage mediocrity.
How? If the only reason you are here is to get a bit of paper to put on your wall and for bragging rights, I suppose the mark will mean lots.
> This is not my idea. EdX itself practised it for another MOOC viz. PH207x just two months back
No, they did not. Another course, yes. But not PH207x.
> I don't know why this option is not available this time.
Because it is probably still in the trial phase. And this was a small part of a larger course. The material was basic in the extreme. Hardly worth the expense of a proctored certificate.
And not all countries currently have access to proctored centres. It might have changed, but there were a lot of upset Pakistani students (among others) at one point.
> Ultimately edX has to make the call.
And they have. No grades on certificates.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T21:18:58Z
FirstChildVoteTAG: 0
SecondChildTAG: 1. Do all academic fora giving marks do it for 'a bit of paper to put on their students wall and for their bragging rights ?' In fact it seems to be other way round. Marks or not, just manage 'a bit of paper to put on your wall and for bragging rights' by hook or crook. (I don't mean it generally, relevant only in this context.)
2.
Even if edX practiced it for another MOOC & not PH207x (for argument sake), it's enough to say that it's not my idea . But as a matter of fact edx did publicize it widely on landing page for students taking up PH207x final exam and other courses just two months back.
3. My 'I don't know' practically means same as your 'It is probably'. Better we first check our facts before using the language ''to get a bit of paper to put on your wall and for bragging rights''
4. General good shouldn't be avoided for a few unfortunate cases.
5. True, ultimately edX has to make the call. But this last line didn't concern you . And you are not objective either because you also mentioned , that edx is giving it a trial .
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-31T02:57:04Z
SecondChildVoteTAG: 0
SecondChildTAG: >''to get a bit of paper to put on your wall and for bragging rights''
Because that is what it is all about. A mark is meaningless. Both here and for real courses.
You can lie and cheat your way to a PhD these days, so it is ability not marks that will decide.
You can photoshop a mark onto the certificate, print it off and you are set.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-31T07:50:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Despite all your delusions and understanding about the marks, academic curricula all over the world, including at Berkeley, continue to award percentage, grades or marks in one form or the other, to quantify variability in ability, performance etc.,so that estimation of curricula is good in general. MOOCs & online mode are relative new arrivals with certain limitations . The whole idea of the discussion is whether we can overcome these, & if yes how ? That is quite different from shameless advocacy of cheating & malpractices as exhibited in your latest post .
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-31T08:57:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I haven't understood "ability" in the @lalotsb comment as an advocacy of cheating ("ability to lie without being discovered"). I think (s)he means "ability to do certain task". Actual knowledge or skill is necessary for doing a task. One has to show proficiency in real world situations. Having a certificate is not enough, in and of itself, to show mastery. I think this is what (s)he's trying to convey.
Maybe I misunderstood. In either case this is my own reflection about the value of certificates. An indicator, at best, that must be confirmed by other means.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-31T10:24:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh! May be I misunderstood! Despite all this, academic curricula all over the world, including at Berkeley, continue to award percentage, grades or marks in one form or the other. Are edX courses & stat2.1x so much irrelevant to real world situations & out of tune with skills, abilities & proficiency required therein ?
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-31T12:07:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't know why edX decided not to put percentages in these certificates. It might have to do with what it is commented above. Not only with cheating but rather with the differences between exams taken on a physical place and online exams (different time margins, different materials available, etc.)
Honestly, I don't mind. I'm here only for learning and I respect the Honour Code with great care. For me the certificate has only a symbolic value, I take it as a sign of my accomplishment (I even prefer the progress page).
If I try to put myself in the place of someone that needs a certificate, the first question I ask me is what for. If it's needed for CEUs, the percentage does not matter (I guess). For a CV? Well, what is the usefulness of a CV? Maybe it depends on countries.
Scores are useful if one keeps studying in the same institution. If I know with certainty, as a professor of an institution, who is my colleague and that her students scored +90, I don't bother to test those students, I take for granted their level, at least at first. If students come from other institution, I have to check them via an entry test. Same, I think, in the job market. As an employer I have to test (by whatever means) the ability of the potentials, even if they are coming from MIT, unless (it's a hypothesis, I don't know if that's actually happens) the company has some contract with MIT to hire certain people specifically recommended by MIT, something similar to the situation of being part of the staff in the same educational institution.
My particular opinion, I know it's somewhat unrealistic: I absolutely don't mind what your credentials are, I don't mind where you studied, what it is your CV or if you are a self-learner coming from Mars. Show me your work! Tell about it. Show me whatever you are able to do and what you are willing to do, here and now! That's all.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-31T14:17:53Z
SecondChildVoteTAG: 0
FirstChildTAG: In a proctored exam cheating is much more difficult, but if someone wants eagerly to cheat, he'll cheat.
Maybe we have to change our minds. What is the real weight of a certificate after all? In the real world what mostly matters is the level of accomplishment, and even there it's not easy to assess.
The value of a certificate is zero if accomplishment is zero. Forget cheaters. They are digging their own graves.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-31T00:36:52Z
FirstChildVoteTAG: 1
FirstChildTAG: As a side comment to the interesting discussion about the value of certificates in general I want to point to the fact that in many circumstances we have to make initial choices based on "marks", so to say.
Why are we here? in edX, in this course? Obviously we have to make an initial decision. Berkeley is one of the top universities in world (a first mark). We've read excellent credentials of our Profs (second mark). But what mostly counts, what only counts in fact, is the course itself. Our initial decision, based on those indicators, has been largely confirmed. That's not always the case. I'm sure you have experienced many counterexamples. I think the same is true for certificates, and for a lot of things.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-31T10:59:00Z
FirstChildVoteTAG: 0
SecondChildTAG: > Why are we here?
Curiosity. Already have the knowledge and I'm just curious about moocs. It will also help for when/if my boss says we are going to do one. I will be the one running very fast in the opposite direction.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-04-02T06:01:04Z
SecondChildVoteTAG: 0
IndexTAG: 143
TitleTAG: A big Thank You
Very Many Thanks for the course.Looking forward to the next one.
Thanking you
Regards
Swarn Munshi
India
UserIdTAG: 133068
UserNameTAG: swarn99
CreateTimeTAG: 2013-03-30T12:47:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 144
TitleTAG: Thank you from Bosnia and Herzegovina
Prof. Adhikari and prof. Stark,
many thanks for this wonderful learning experience. I have heretofore completed several online courses, but Stat 2.1X was by far the best one.
I am very much looking forward to Stat 2.2X.
Best wishes,
J.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-30T11:57:35Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 145
TitleTAG: Thank you and a question about 2.2X
Love it so much, a wonderful experience. Many thanks.
Sure I would love to continue. But I am not sure what I am supposed to do to ensure I am going to be part of the 2.2X. Do I need to reregister or ?
UserIdTAG: 1029226
UserNameTAG: workayehuke
CreateTimeTAG: 2013-03-30T11:43:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's a different course, so you'll have to enroll in it once it's up on edX.
Since the course is supposed to start on the 12th, we should see it appear soon enough :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-30T12:03:59Z
FirstChildVoteTAG: 1
IndexTAG: 146
TitleTAG: Thanks Prof. Adhikari and Philip Stark
Thanks so much. This course was fantastic and looking forward to joining the next one.
UserIdTAG: 746139
UserNameTAG: megan2012
CreateTimeTAG: 2013-03-30T10:28:00Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Thanks to Prof Ani and Phillip Stark for this wonderful course! Waiting eagerly for Stat 2.2X.
Student from India
FirstChildUserIdTAG: 804111
FirstChildUserNameTAG: s131
FirstChildCreateTimeTAG: 2013-03-30T11:33:11Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you so much.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-30T11:43:16Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes dear MAM and SIR,
the stats course was very interesting and concise too. Nowhere I felt overloaded.
I have always feared stats, and in order overcome my fear I took the help of edx and I am feeling that I am succeeding.
Thanks a lot again to both of you for ur success!
Thanks and Regard
(From INDIA)
FirstChildUserIdTAG: 741211
FirstChildUserNameTAG: tabishjamil
FirstChildCreateTimeTAG: 2013-03-30T12:01:51Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Profs A and Stark
I too wish to join the thank you bandwagon. Thanks for the challenges, infuriation (not sure if that's a verb!) and opportunity.
Prof A, I think I have a girl crush on you, though thats not my motivation for looking forward to Stat 2. You just seem to be a truly excellent person and you explain complex subject matter in way that is charming and engaging.
Good luck to your son's band.
Greetings from Uganda.
FirstChildUserIdTAG: 1217071
FirstChildUserNameTAG: SifaP
FirstChildCreateTimeTAG: 2013-03-31T12:21:21Z
FirstChildVoteTAG: 0
IndexTAG: 147
TitleTAG: Thank you from the philippines
Thank you Prof Ani and Staff!
UserIdTAG: 1083507
UserNameTAG: mtzemd68
CreateTimeTAG: 2013-03-30T10:18:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 148
TitleTAG: Thanks from Kazakhstan
Hello everyone! Could you tell me how can I take my certificate?
UserIdTAG: 987671
UserNameTAG: Askar96
CreateTimeTAG: 2013-03-30T09:55:23Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
FirstChildUserIdTAG: 923445
FirstChildUserNameTAG: MLaszczewska
FirstChildCreateTimeTAG: 2013-03-30T10:02:05Z
FirstChildVoteTAG: 0
IndexTAG: 149
TitleTAG: Thank you so much!!! Wonderful experience!!!
Thanks very much professors for yours explanations and lessons. Learn with you was a pleasure. I hope be back very soon in next courses.
This was a fantastic experience!!!
UserIdTAG: 953802
UserNameTAG: isabelmms
CreateTimeTAG: 2013-03-30T09:53:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 150
TitleTAG: Thanks from UK
I am glad that I had a chance to be part of this course. Prof A., you are an EXCELLENT teacher. Million thanks to you and whole Stat2.1x staff.
UserIdTAG: 1053569
UserNameTAG: nicola2003
CreateTimeTAG: 2013-03-30T08:32:42Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Excellent course, well presented easy to follow and the weekly exercise sets consistently had a question that really made you think about the topic you were reviewing.
Many, many thanks from sunny Wales in the UK, or as the locals would say in Welsh 'Diolch yn fawr iawn'
FirstChildUserIdTAG: 16957
FirstChildUserNameTAG: DavidXRobinson
FirstChildCreateTimeTAG: 2013-03-30T09:17:58Z
FirstChildVoteTAG: 1
IndexTAG: 151
TitleTAG: [Stat 2.1 Staff]
I missed ES 07, ES 08 and Mid Term 01 Exams. This was due to the course ware not responding for two days and I missed the Exercises and Mid Term exams mentioned. This affected my performance greatly. This was not my own making. Can Stat 2.1 Staff please consider my case? I sent an Email to the above effect and I have never received any response. Only a 1% total bonus will do me very good.
Otherwise thank you very very much for the course I have increased now my professionalism, performance, creativity and team work in my work I am doing.
I will be very grateful for any kind consideration Stat 2.1x Staff will avail me.
Kind regards,
John
UserIdTAG: 360344
UserNameTAG: Wabuyi
CreateTimeTAG: 2013-03-30T07:49:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: OOps, I seemed to have missed my final exam as I did not notice the time limit. But i think the proportion of final exam score is not so heavy. Maybe i'll pass this course. Nevertheless, whether i may pass or not I already learned a lot in this course.
Thanks to Professor A and all the staff at this course.
By the way, do i have to pass Stat2.1x in order to register to Stat2.2X?
FirstChildUserIdTAG: 117228
FirstChildUserNameTAG: Kevin345
FirstChildCreateTimeTAG: 2013-03-30T10:40:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Final score counted for 30%. You "passed" the course if you got at least 35% total.
And, no, you don't need to pass 2.1x to enroll in 2.2x.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-30T12:05:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Its good that the proportion of the final is not so heavy,cause I missid it too .i had a problem with my net connection and when it did connect , the deadline had been crossed.
But I passed the course.
Thankyou for such a wonderful course.
SecondChildUserIdTAG: 1198994
SecondChildUserNameTAG: parthkelkar
SecondChildCreateTimeTAG: 2013-03-31T05:19:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Dammit! I missed the start of the Olympics. Do you think they will run them again for me?
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T21:12:42Z
FirstChildVoteTAG: 0
IndexTAG: 152
TitleTAG: Thank you very much for the excellent course - Athens, Greece
Thank you very much for the opportunity provided to all of us. Congratulations on your kind offer to all of us.
Athanasios
UserIdTAG: 905025
UserNameTAG: Athanasios961
CreateTimeTAG: 2013-03-30T07:42:39Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 153
TitleTAG: Passed Or Not
I am unable to understand how can i view my result ! Whether I passed or not ?
Please help me out !!!!!
UserIdTAG: 1148355
UserNameTAG: Sunnye01
CreateTimeTAG: 2013-03-30T06:15:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Click Progress. Is the right hand bar at 35% or higher? If so, yes you have passed. But given this was a course involving numbers ........
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T06:31:06Z
FirstChildVoteTAG: 0
SecondChildTAG: What do the shades of red, maroon and grey signify ?
SecondChildUserIdTAG: 1148355
SecondChildUserNameTAG: Sunnye01
SecondChildCreateTimeTAG: 2013-03-31T20:27:45Z
SecondChildVoteTAG: 0
IndexTAG: 154
TitleTAG: Stat2.1x Staff
Hi
This is my 2nd course through edx and 1st completed course in edx.
Before I start this Statistics Course, I am truly not familiar with what does statistics actually can do & cannot.
But after this stat2.1X I could able understand how to look into a data and drew conclusions.
Especially I started with low grades in Exercise set when the problem set is to drew conclusion, as on the go I could able to make better.
My Sincere thanks to everyone who made such a course meaningful and I happy to be a part of it.
Thanks
Saravanan
India
UserIdTAG: 1147750
UserNameTAG: SaravananMani
CreateTimeTAG: 2013-03-30T06:11:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 155
TitleTAG: Thanks from Kosovo!
Looking forward to 2.2!
UserIdTAG: 1247915
UserNameTAG: Iliri2013
CreateTimeTAG: 2013-03-30T06:04:24Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 156
TitleTAG: Thank you
Thank you Profs and looking forward to stat2.2X
UserIdTAG: 359736
UserNameTAG: Bishwa
CreateTimeTAG: 2013-03-30T05:57:07Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 157
TitleTAG: thank you
thank you Drs. Ani and stark
UserIdTAG: 898629
UserNameTAG: sureshag27
CreateTimeTAG: 2013-03-30T05:51:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 158
TitleTAG: Thanks
Hello,
Before : I am not good at statistics. A bit fear of the subject. I am good at math. My introduction to statics is very horrible by Dr. Dutta at Bhabha Atomic Research Centre.
Now : I am very comfortable with this subject. Most of the things are common sense.
Thanks 'ANI' mam. Your way of teaching is really good. The thing that i like most are
a) Your frequent pause in between to think.
b) Try to figure out the solution by only looking at it or using common sense.
c) Extending the concept to the edge.
d) Breaking the rules. "What if i draw a line according to me ?" in regression analysis.
Once more, and infinite times for rest of my life
"THANKS"
UserIdTAG: 556698
UserNameTAG: GGG
CreateTimeTAG: 2013-03-30T05:06:17Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 159
TitleTAG: Thanks from India
thanks a lot for this absolutly free online course..it was really a very good experience since last few weeks..and looking forward to furthur courses..but i also request to please send the percentile rank of the student so they can evaluate where they stand for their motivation..
UserIdTAG: 1293847
UserNameTAG: shailesh1984
CreateTimeTAG: 2013-03-30T04:51:21Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I support this view.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-30T07:35:38Z
FirstChildVoteTAG: 0
IndexTAG: 160
TitleTAG: How can I join the directory of the students?
Well it seems quite late,but I came to know about the student's directory right now.It was really difficult for me to just STEAL the time for this course from the hectic routine.I came to know about the discussion forum during 3rd week of the course.Now I have seen there is a student directory in the WIKI link.How can I join the directory?
UserIdTAG: 1293941
UserNameTAG: CHHAVIMEHROTRA
CreateTimeTAG: 2013-03-30T03:42:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Just edit the wiki page with your name ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-30T12:51:04Z
FirstChildVoteTAG: 0
SecondChildTAG: Many thanks Klionheart!
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-04-02T00:29:09Z
SecondChildVoteTAG: 0
IndexTAG: 161
TitleTAG: how to know when a scatter plot is a well consider "football shaped"
does anyone know that? any website which explain that? thanks in advance
UserIdTAG: 817175
UserNameTAG: yoshioks
CreateTimeTAG: 2013-03-30T03:41:33Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Prof Ani explained it in her Lecture 6.1 and also our text mentions it. You can use table of contents to search text . You may also see see the discussion related to scatter plot, linear scatter plots, & chapter 10 regression diagnostics . In a football-shaped scatterplot, most of the points lie within a tilted oval, shaped more-or-less like a football. A football-shaped scatterplot is one in which the data are homoscedastically scattered about a straight line .
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-30T07:56:49Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks!!!!
SecondChildUserIdTAG: 817175
SecondChildUserNameTAG: yoshioks
SecondChildCreateTimeTAG: 2013-03-30T21:36:40Z
SecondChildVoteTAG: 0
SecondChildTAG: welcome! glad that it served your purpose.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-31T04:13:03Z
SecondChildVoteTAG: 0
FirstChildTAG: This is the sentence from the on-line book (see Chapter 5): "If a scatterplot shows linear association (or no association), homoscedasticity, and no outliers, it is said to be football-shaped."
FirstChildUserIdTAG: 961016
FirstChildUserNameTAG: Pois
FirstChildCreateTimeTAG: 2013-03-30T10:53:41Z
FirstChildVoteTAG: 0
SecondChildTAG: ... the last sentence of the chapter.
SecondChildUserIdTAG: 961016
SecondChildUserNameTAG: Pois
SecondChildCreateTimeTAG: 2013-03-30T10:54:15Z
SecondChildVoteTAG: 0
SecondChildTAG: yhh!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T15:04:37Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks!!!!
SecondChildUserIdTAG: 817175
SecondChildUserNameTAG: yoshioks
SecondChildCreateTimeTAG: 2013-03-30T21:36:48Z
SecondChildVoteTAG: 0
IndexTAG: 162
TitleTAG: Thanks from Puerto Rico!
My most sincere thanks for the course. Prof. A., Prof. S. and all the staff at EdX, you are amazing!
Jo González (Puerto Rico)
UserIdTAG: 1238533
UserNameTAG: JoGonzalez
CreateTimeTAG: 2013-03-30T03:33:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 163
TitleTAG: Thanks for the course
I think this course was great and very ejoyable.
Thank you/ EDX, BerkeleyX Prof Adhikari and Prof Stark.
UserIdTAG: 1180593
UserNameTAG: CARLOSJAV
CreateTimeTAG: 2013-03-30T02:44:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 164
TitleTAG: Thanks a lot for the excellent course on Statistics from Peru
Dear Stat 2.1x team,
I enjoy very much the course, in special the excellent lectures of Mr. Ani Adhikari, who has made from some complex and abstracts topics so simple to teach, that anyone can learn. I appreciate very much your lectures.
I have to mention also the course material by Dr. Philip B. Stark, the famous SticiGui, that help us so much to solve the proposed problems.
Thanks a lot again to the excellent team.
Best regards,
Julio Porcel.
UserIdTAG: 1262270
UserNameTAG: JPorcel
CreateTimeTAG: 2013-03-30T02:39:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 165
TitleTAG: Getting ready to also be a molecular gastronomist
Joining this course too as I am interested in the science of cooking (and dabble with it) anyone cares to join with me (Of course along with Stat2.2X.MOOC seems to be addictive.
https://www.edx.org/courses/HarvardX/SPU27x/2013_Oct/about
If stat2X gets completed I hope there can be a Stat 3X - Greedy me but I do hope we could go up the ladder further in our understanding .
Professor Adhikari - you have to give the supplements for the post midterm exercises !! Looking forward to it.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-30T02:27:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 166
TitleTAG: More, I need more!
Just how much more maths courses can I expect from Edx now that I am thinking of continuing this for several years?
UserIdTAG: 344400
UserNameTAG: carlallen
CreateTimeTAG: 2013-03-30T02:07:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 167
TitleTAG: The best stat software or Texas Instrument calculator
I take these courses (the three STAT courses) to prepare for a PhD in Education. Thanks for this fantastic learning experience. I would like to know if you could recommend a software or a calculator to complement these STAT courses. Thanks. Jack
UserIdTAG: 1277709
UserNameTAG: meibushengshou
CreateTimeTAG: 2013-03-30T01:59:39Z
VoteTAG: 0
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 3
FirstChildTAG: I don't know about a physical calculator.
For "software" for this 2.1 MOOC, I just used the google search. A random functionality of a google search, is that if you put a calculation like " 100 / 7 " , the returned search will be an answer, on a calculator "applet" on the returned page. from there you can do other calculations, either by using the mouse to "press the applet buttons" or via typing. This was "good enough" for the arithmetic-type calculations I needed for 2.1 MOOC.
A spreadsheet (example - the free http://www.libreoffice.org 's Calc , or Google Drive's online spreadsheet) can do calculations.
Also the free R statistics software can be used as a calculator
http://www.r-project.org/
Hope that helps
FirstChildUserIdTAG: 538198
FirstChildUserNameTAG: A_P
FirstChildCreateTimeTAG: 2013-03-30T12:37:03Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1277709
SecondChildUserNameTAG: meibushengshou
SecondChildCreateTimeTAG: 2013-04-01T01:48:41Z
SecondChildVoteTAG: 0
FirstChildTAG: There is also a free, (very user friendly, with tutorials and sample data), software called EpiInfo available from the CDC. Though designed for epidemiology, it can be used for all kinds of statistical anlysis. The latest version of the program can also be installed on a USB thumb drive and is quite amazing.
http://wwwn.cdc.gov/epiinfo/
FirstChildUserIdTAG: 1231212
FirstChildUserNameTAG: wsk
FirstChildCreateTimeTAG: 2013-03-30T17:27:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes,I have used it for years and it is a good software
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-31T02:20:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1277709
SecondChildUserNameTAG: meibushengshou
SecondChildCreateTimeTAG: 2013-04-01T01:48:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Gretl is also good for some parts of statistics.
FirstChildUserIdTAG: 884187
FirstChildUserNameTAG: Madelenka
FirstChildCreateTimeTAG: 2013-04-01T16:00:29Z
FirstChildVoteTAG: 0
IndexTAG: 168
TitleTAG: Thanks from Morocco !
Thank you prof A. for this amazing course that i've really enjoyed ! and i am so excited now for the next Stat2.2X !
Greetings from Morocco !
UserIdTAG: 816905
UserNameTAG: Benzino
CreateTimeTAG: 2013-03-30T01:01:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 169
TitleTAG: See you guys!!!
I did enjoy this course and I want to sincerely thank both the instructor and all the staff.
Thank you all !!!!
UserIdTAG: 206086
UserNameTAG: pedrocas1972
CreateTimeTAG: 2013-03-30T00:58:06Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Aren't you going to be around for Stat 2.2X?
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-30T03:20:41Z
FirstChildVoteTAG: 0
FirstChildTAG: Sure, of course!!!
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-03-30T12:26:43Z
FirstChildVoteTAG: 0
IndexTAG: 170
TitleTAG: Thanks Prof. A!
Thank you, Prof. A for an engaging Stats course. Having you teach the course is especially excellent because it proves ladies need not worry about Math and Stats! :-D
(Although I could have done better... I joined very late though. I'll ace the next two parts, fer sure.)
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-30T00:57:32Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It was a great course!! I enjoyed every bit of it, though I do have a stats background. Thanks to Edx team, Berkeley Univ, Prof. A.
FirstChildUserIdTAG: 1056571
FirstChildUserNameTAG: JayashreeGopalakrishnan
FirstChildCreateTimeTAG: 2013-03-30T04:37:19Z
FirstChildVoteTAG: 0
IndexTAG: 171
TitleTAG: Thanks from Colombia!
Dear Prof Adhikari:
I just want to thank you, all Stat2.1x staff, Prof Stark and edX team for making this course so enjoyable! Different from other biostatistic courses in which many different topics are covered in a rush, Stat2X takes a reasonable pace for this difficult topics.
I surely have great expectations from the rest of Stat2X courses.
The only suggestion that I have about the course is that I did not see about how to identify a normal distribution, apart from the graphical approach and comparing means to medians. I have heard about some parameters that can state normality, but I do not know how to use them. If they were not included in the next Stat 2X courses, I would like very much, at least, to know if they are completely necessary for what we have learned.
Once again, thanks for your effort (I have read your blog)!
Sincerely,
Andres Acevedo
UserIdTAG: 743246
UserNameTAG: andresace
CreateTimeTAG: 2013-03-30T00:21:33Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 172
TitleTAG: Prof. Adhikari Appreciation Thread
Thanks you to Prof. Adhikari for providing this MOOC.
I've heard it said that (in the USA at least, not sure about other nations), college Professors are job-evaluated almost exclusively by research metrics, such as number of journal articles, or even just sales skills/"rainmakering" in the number of grant/research money they are able to obtain. Actual teaching skills are an afterthought.
I've also heard it said that research & teaching skills are not related. In Stat 2.1x lingo, they would have little or no association. The correlation coefficient would likely be near 0 (assuming it's even linear, homoscedastic, & without outliers, ha). A prof could be great at both, neither, or only 1 of these 2 areas, etc.
From the 4 MOOCs I've taken, & have to say that Prof. Adhikari is easily the best TEACHER I've seen of these courses. Adhikari is excellent at explaining the concepts in the video lectures, pdf notes, & post-deadline answer explanations on the exercise sets & exam assignments. For example, the "Additional Practice for the Final" quizzes imho were a great review/preparation for the Final.
I also appreciate that Adhikari designed the MOOC competently, in the sense that it was possible to do the particular exercise set or exam given the preceding work (Vid Lectures/ES/exams) done at that time. In other MOOCs, at times I have seen a big gap on a homework assignment, that was very challenging to complete successfully given the material that had been covered up to that time. My opinion is that the purpose of MOOCs is to learn, not to be some "challenge" of being able to somehow learn extra material from other internet sources to complete an unreasonably inappropriate assignment. Perhaps those MOOCs should at least had optional Video Lectures or non-course url links to resources that would enable the student a better chance of completing the assignment.
A 1st suggestion I have for this excellent MOOC, would be to provide optional (do not count for pts towards the grade, so students can skip if uninterested) links/R code/Video Lectures on the R language, to illustrate the examples from the existing Video Lectures. From what I've read the OpenIntro statistics book takes this approach. R, being both FOSS (free & open source software) and having world-class functionality for statistics/data manipulation/data graphing, empowers any person to use the statistics concepts taught in your MOOC in a "real-world" environment (work/school/etc).
A 2nd suggestion is related to the "Practice for Exercise Sets" that reference a link to the Prof. Stark online text. I presume that a relevant Info Tech./Computer Science guru (perhaps call the Berkeley IT Dept or a CS Berkeley Prof ?) could suggest an easy/quick/cheap way, for the Stark text link to include ONLY the text that is relevant that you assign us to read. This way you could eliminate the "So start with estimating using the Regression Line:" "read to the end of the paragraph that ends with bivariate distrubution" type of wording. It would be more obvious for the student: click the link, which has ONLY the relevant material you wish us to read/study.
Thanks again Prof. Adhikari. IMHO in terms of innovation & contribution to society, you are a world-class level leader for providing this MOOC to 100K+ people globally.
Best regards from this grateful student,
AP
--
PS - a joke for fellow hip hop listeners
Jay-Z once said of Talib Kweli "if skills sold truth be told, I'd probably be, lyrically Talib Kweli".
could adapt it to be:
"if professor skills sold truth be told, a professor should strive to be, professorially, Dr. Ani Adhikari" :0
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FirstChildTAG: Very true . She is the best . One practical advise by her that helped me a lot is: It's clearly better to do smaller amounts of work more frequently, from the point of view of absorbing material and being able to think about it in your own way; that is why the video segments have been kept very short so that one or two can be viewed even after a day at work. This technique of her in my view one of basic difference in her style of teaching . One that bears max fruit though less talked about . This happens when you have so many positives in one person .
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TitleTAG: Thanks again for a good course Stat2.1x_Berkely_EDX_
Dear Prof. Adhikari, Prof. Philip Stark, Course Assistants Paul Matsiras and Gordon Heaton, EDX... Team and to all my colleagues in Stat2.1x_BerkelyX, Spring, 2013.
We all in stat2.1x thank You and appreciate dearly for offering this course Stat2.1x. I have personally learned new things and enjoyed the course Stat2.1x the whole five weeks. I Will look forward to the next courses Sat2.2X...2.3x and promise god willing more prepared and better equipped, since we are pressed for time but I have got a good foundation now and I will manage to spend more time in discussions section which has been really my weak area in stat2.1x, agreed the place to perfect ourselves as new students of statistics 2.1x....Series.
This has been an exceptionally well thought by Prof. Adhikari,Prof. Philip Stark, course assistants and presented with perfection. Stat2.1x has been very exciting and challenging mentally at times and I look forward to the future courses with keen interest in learning while enjoying more challenges and perfecting the skills of "Descriptive Statistics" studies through EDX..... one to one by the Professor Adhikari,Prof. Philip Stark, and course assistants, students at discussion fourum and The great team behind at EDX. Berkeley, California my favorite State I am a Californian too leaving outside USA last 16 years in East Africa -Horn-Africa region now in Kampala, Uganda last 2.5 years!
Thank You again for sharing the exiting knowledge of Stat2.1x, Your time, and Your personal effort making the best opportunity to take this course for the first time stat2.1x... through the availed powerful medium EDX... virtual world 24-7-365 and thousands of miles away with big time difference between Berkeley, California USA and Kampala, Uganda East Africa.
Best regards to all,
H.M.F.
HFWELI2012
March 30, 2013
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FirstChildTAG: I really enjoyed my course and learnt more form it than what I "thought" I knew.It was a very refreshing look at statistics and looking forward to 2.2X
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TitleTAG: So very different from other statistics courses...
Every other statistics class I've taken has started with a long discussion of combinatorics, probability, and long memorization of distributions (and their means, SDs, PDFs, and CDFs).
I could always reproduce Markov's and Chebychev's inequalities (and use them), as well as OLS regression. But taking this course was the first time I really appreciated the full meaning of them (rather than simply reproducing the equations, or using OLS to estimate coefficients).
Thank you Dr. Adhikari and Dr. Stark
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TitleTAG: Adding my vote to all the thanks
I haven't actively participated in the forums, but did want to give a huge vote of thanks to Prof A who brought what could have been a dry subject to life for me in a very practical way.
I've been aware for a while that stats is big gap for me that I need to get to grips with in order to achieve a number of different goals, and this course was a really reassuring introduction. I struggled at the end due to lack of time to complete the lectures and exercises properly, but I've archived the material so that I can go through it properly before 2.2x - and I'm really looking forward to that next step!
Thanks so much Prof A for an excellent learning experience. Very much appreciated.
Regards
Chris
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TitleTAG: Thanks from Egypt
Thank you soooo much. I now have have a better understanding of concepts I never even presumed to grasp. Thank you for making statistics sound sooo easy.
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FirstChildTAG: thanks from alexandria,egypt.
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TitleTAG: Thanks!
This has been really useful! Breaking up the videos/exercises into small parts also works well with busy schedules. Anyway thank you all for setting it up. Looking forward to the next series!
Loren
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TitleTAG: Thanks
Wish to add my thanks to the various ones so far. I wish the course team will add both an entry and exit survey for students and also wish to see something in the nature of tutorials being added to the course. Thanks for a job well done. Looking forward to Stats 2.2, though i expect it to be tougher and less enjoyable than Stats 2.1 and 2.3.
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TitleTAG: Thanks from Trinidad
Thank you very much. I have a greater understanding of the topics taught. Professor Adikhari explained things in ways I never got whilst I was doing my BSc Mathematics. I hated statistics, but now I am looking forward to 2.2 and 2.3.
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CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
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TitleTAG: Thank you
Dear Prof. Adhikari, thank you for offering this course. I have learned new things and enjoyed the course. Will look forward to the next course. Thank you again for your time and effort.
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TitleTAG: Will the courseware continue to be available?
There are some key concepts i would like to revise again , will the courseware and lectures continue to be available for access now that the course is finished? And for how long?
If anyone can clarify this , Thank you !
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IMHO the safe assumption would be that access will end at some time.
IMHO it is worth your time to download the pdf lecture notes, & video lectures.
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FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
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FirstChildTAG: Thanks Guys!
Yeah i was wondering what the extent "Archived material for reference in stat 2.2" will be.
I will download the videos , just to be safe.
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TitleTAG: Thanks from Dubai!
Thank you, Prof. A! Looking forward to 2.2x!
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FirstChildTAG: Hi brooo from morocco
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SecondChildTAG: i am from Morocco too !
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TitleTAG: Regression estimate of X based on Y and vise versa are identical. Why?
Dear All,
I am confused as why the regression estimate of X based on Y and Y based on X are both the same when X and Y are in standard form.
X = r * Y
and
Y = r * X
where r is the correlation factor. This means that the regression estimate of X for Y = 3 is X = 3 * 0.5 = 1.5 assuming r = 0.5. However, the regression estimate of Y for X = 1.5 is Y = 1.5 * 0.5 = 0.75.
Either I did not get something here or there is something seriously wrong. I expect if the regression estimate of X based on Y is X = r * Y, then the regression estimate of Y based on X to be Y = (1/r) * X. I appreciate if any of you can help me understand the regression a bit more.
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FirstChildTAG: Without considering the math, the regression line is what it is i.e. an "estimate" not a formula to derive the exact value. So, if you know X why are you estimating its value again based on another estimated value?
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SecondChildTAG: agreed . This is practically correct.
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FirstChildTAG: I suggest you go to Lecture 6.2 and start the video around 9:20. There is a fairly extended explanation of this phenomenon. But I will add my thoughts, with the caveat that I am just another student engaging in speculation.
We think of correlation as the slope of a line, but it is **not** simply a function of one variable in terms of another. It is instead a measure of the degree to which a positive shift in one variable leads to a positive shift in the other variable.
To try to draw this out, we all know that for a given rate of exchange, the price of pounds in dollars is the inverse of the price of dollars in pounds. (By the way, this particular exchange rate is called the "cable," because early transatlantic cables were used to trade dollars and pounds.) The exchange rate is a function that connects the dollar to the pound in a linear way. It is **not** like correlation. That is why we would expect that one of these numbers would be greater than 1. (Today, that would be the price of pounds in dollars: $1.52 as I write this.)
So then you have to realize that *correlation is not like the exchange rate between dollars and pounds*. Correlation is a measure of the extent to which two variables move together. Imagine that Parliament (or Congress or whatever) holds 100 votes, and each member votes yea or nay on each vote. Think of correlation as the extent to which any two legislators voted the same in those votes. You can see that for any pair of legislators, the number is going to be the same. The media might report, "Politician A voted the same as Politician B 68% of the time." We don't then have to ask how often Politician B voted the same as Politician A. By definition, it's 68%. (In my example, both politicians cast a vote every time - otherwise I suppose the numbers could be different.)
So you can think of correlation as being more like the legislative example than like the exchange rate example. You don't multiply x by r to get y. Rather, r tells you the degree to which you can expect x and y to *correlate* - for movements in one to coincide with movements in the other. As with the legislators, this is just a flat number, not a function of one in terms of the other. So just as you could switch the legislators, you can switch x and y without affecting r.
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SecondChildTAG: Good examples & I agree except for some portions of last para. However , to be precise , even in exchange rate example price of dollar & price of pound is a special case of correlation with r=1 .
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FirstChildTAG: Pre-Code, **r** measures degree of clustering around a straight line, not a slope. **r** times σy/σx is the one that represents the slope of a regression line, and gives us that "measure of the degree to which a positive shift in one variable leads to a positive shift in the other variable".
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SecondChildTAG: GMendes, if you go to about 4:35 in Lecture 7.2, you will find that r is the slope of the regression line when the variables are expressed in standard units.
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FirstChildTAG: We all are students. Let me speak my mind. Continuing with example you quoted, X & Y are two variables in standard form with r = 0.5 . It implies knowing one we can estimate other & degree of linearity between X & Y is 0.5 . Coming to regression estimates , X = 0.5*3 = 1.5 means X & Y covary . Had r been 1 , X would also be 3 for Y =3 . But when correlation is weak ( only 0.5 ) then regression estimate of X i.e. co-variation of X is going to follow variation in Y but not quite & tend to follow Y value i.e. 3 & mean i.e. 0 and precise regression estimate of X = 0.5*3 = 1.5 . This is a mean estimate of all possible values of X on horizontal strip , corresponding to Y = 3 . In similar fashion Y co-varies with X with r= 0.5 & Y = r*X i.e. ditto all the things said above for X = r*Y but replacing X for Y and also Y for X . For X = 3 regression estimate of Y is 0.5*3 = 1.5 i.e. Y is going to vary to different values on vertical strip on scatter plot & mean regression estimate of these all values on vertical strip is 1.5 . Similarly we can calculate regression estimate for unknown or dependent variable based on any other value of known or independent variable be it 3 or 1.5 or something else . This is how regression & regression estimates should be understood and it's wrong to conclude that " if the regression estimate of X based on Y is X = r * Y, then the regression estimate of Y based on X to be Y = (1/r) * X ".
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FirstChildTAG: The two equations are not the same. In standard units:
a) Estimate of y = r * actual x
b) Estimate of x = r * actual y
There are four variables in those equations, not two.
Eqn (a) gives the center of the vertical strip at x. Eqn (b) gives the center of the horizontal strip at y.
Best,
Prof. A.
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SecondChildTAG: Excellent answer, as it was to be expected from prof. Adhikari :)
BTW, this question is a recurrent one. I won't add it to the Wiki FAQs since they are about course policy, not content. I could add it to Lecture 7.2 summary, since it's relevant to that lecture, even though it wasn't discussed during the actual lecture. What do others think?
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SecondChildTAG: Thinking about vertical strips and horizontal strips was, for me, the best way to understand why there are two different regression lines.
Illustrating this with one of your wonderful hand-drawn graphs (no irony here) and actually showing the two lines could definitively help people understand.
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SecondChildTAG: Very simple & very precise! thanks Prof ! But it doesn't seem to be critical of my answer or is it? Please tell ( just for clarity ).
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TitleTAG: Over-arching Certification?
Some weeks ago I suggested the possibility of adding an over-arching certificate for those students who completed all three of the Stat2X courses. At the time Prof. A said that she had considered this and was putting it to edX. Is there any news on that front yet (I appreciate that, although we seem to have been here forever, in fact it's only a matter of weeks)?
I would add my vote of thanks to the many already posted. This has been an exceptionally well-structured and presented course and I look forward to the future courses with keen interest.
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FirstChildTAG: Strongly support it with a suggestion that it be optional for those willing.
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TitleTAG: Now I get it! thanks
Thank you Prof for the Stat course.
I have taken Stat before (part of a course or a standalone course) but I never quite got it. Now I understand Normal distribution, Standard deviation and regression and their relation to one another (Demystified!)
Thank you for modularizing the course into three parts. Will definitely be taking Stat2.2x and Stat2.3x.
See you then!
br
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FirstChildTAG: I agree entirely. It's probably 40 years since my first exposure to statistics but there are some aspects which have never really sunk in (despite, I'm embarrassed to say, actually teaching Maths occasionally in high school). After all these years I've finally got an intuitive grasp of SD rather than just seeing it in the abstract as a value to be computed and used to satisfy examination questions.
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SecondChildTAG: I also agree with this view. I did undergrad stats 30 years ago (and passed) but only really understand this now.
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SecondChildUserNameTAG: Stewart
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SecondChildTAG: I completed undergrad stats in 1986 and was fortunate to have an excellent teacher. However, in the last almost 30 years most of what I learned has atrophied.
This course was an excellent refresher! I'll return for Stat2.2x!
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SecondChildUserNameTAG: BrianDeering
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TitleTAG: Certificate
This course will provide us one certificate? If yes, how many points do I need to get it and when it will be available?
Thanks!
Bárbara
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FirstChildTAG: If you have achieved over 35% overall then you will get the certificate. Latest indications are that they will become available **from** 1st April.
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FirstChildUserNameTAG: PaulJM
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SecondChildTAG: Thanks!
SecondChildUserIdTAG: 803020
SecondChildUserNameTAG: Barbaralbtorres
SecondChildCreateTimeTAG: 2013-04-02T01:43:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you For a very good course
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FirstChildUserNameTAG: benali
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FirstChildTAG: Just how much more maths courses can I expect from Edx now that I am thinking of continuing this for several years?
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TitleTAG: Greatly Appreciated!
Dear Prof. Adhikara and Prof. Stark,
Many thanks to you both and your support staff for an incredibly enriching experience. As you must know by now, the "black box" is alive and well with many appreciative students. This course exceeded all expectations!
Judy in Portland, Oregon, USA
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TitleTAG: Thanks from Pakistan
Dear Professors and Staff,
Being a law major not having been exposed to statistics, I was quite scared as to what really statistics was? Even more daunting was regression which I had not listened, let alone solved. Ingenuously speaking, as I progressed through the course, I found it fun to master the concepts of Mean, SD, R. and r.m.s. error to say the least. By the end of final exam, I had scored 92% marks. Incredible! And it is owing to a wonderful way of teaching and availability of free book online.
I am really grateful to Professors A. Adhikari, Phillip B. Stark, the staff and the Edx team for opening up the course and sharing fruits of education to all and sundry across the globe. I anxiously look forward to signing up for 2.2x.
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TitleTAG: Extremely well-designed course.
Dear Prof A,
Thank you for your enlightening lectures. You are the best. The way you had designed the course and taught it generated a lot of interest in the subject. Glad to be part of the humongous global classroom too. I would also like to thank Edx for the wonderful opportunity to learn at leisure, with pleasure, without pressure and from the Guru in the subject. All the best to this initiative.
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TitleTAG: I just found out about this course. Is it too late to join?
(Just kidding.)
Thanks to the professor and staff for an amazing course. And thanks to edx for such a great platform.
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FirstChildTAG: And there I had, ready for you, the Ultimate Sarcastic Post$^2$, Diamond Edition.
But then you say you are just kidding. I'm a sad panda now.
xD
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SecondChildTAG: Keep the Diamond Edition ready! I'm guessing there will be an opportunity to use it in Stat2.2x. See you in April?
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SecondChildTAG: Of course :)
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TitleTAG: Thanks from Greece!!!
Very good course...and very good way to learn more on this wonderful field of statistics...
Giorgos from Greece
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TitleTAG: Can you please clear this out for me?
I understand the formula for the score but I can't seem to understand why the correlation is 1.
Thank you.
![Problem 2b][1]
[1]: https://edxuploads.s3.amazonaws.com/13645849321343693.jpg
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FirstChildTAG: Mike,
A correlation of 1 means a perfect linear association between two variables. It cannot get better than that! In other words, **you can never have -1 > r > 1**.
Plot out the points for *score* vs. *number right* and perhaps you will find it easier to understand.
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FirstChildUserNameTAG: WH
FirstChildCreateTimeTAG: 2013-03-29T19:46:21Z
FirstChildVoteTAG: 1
FirstChildTAG: The correlation coefficient is **not** the slope of the score formula. And it can **never** be more than 1(or less than -1).
If this is not clear for you, I *strongly* encourage you to review Lecture 6.2.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-29T20:02:36Z
FirstChildVoteTAG: 1
FirstChildTAG: Weight & height , monthly income & spending on education, blood sugar level & coronary heart disease , smoking & life span etc are examples of different pairs of variables . In each pair two variables co-vary . Value of one can be predicted/estimated from the other but not quite . The estimate is actually a mean along with a spread with SD equal to rms error & graphically the estimate is a vertical strip on scatter plot. Special case of correlation & co-variation is where there is no spread or uncertainty associated with the estimate because relation between pair of variables is perfectly linear and graphically there is no spread, rms error = 0, vertical strip & spread reduce to a point and scatter plot reduces to a simple straight line . In such cases r=1 for positive correlation. Example is weight in pounds & weight in kilograms, speed of the train you travel in & the distance it covers in given time span. Hope it helps.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-30T04:09:27Z
FirstChildVoteTAG: 1
FirstChildTAG: Plot the data.
![enter image description here][1]
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13646234238474448.png
[2]: https://edxuploads.s3.amazonaws.com/13646234011343662.jpg
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T06:04:28Z
FirstChildVoteTAG: 2
IndexTAG: 193
TitleTAG: Thank you Prof A and Prof Stark and Stat2.1x team for giving me a better understanding of statistics
I found Prof A's lectures very understandable but had some trouble with the math for applying the concepts since I had not used much mathematical thinking since graduating from High School in 1963.
If Prof A could go into more detail in her lectures it would certainly help me, because she is very clear in her explanations.
Thanks again for a good course
UserIdTAG: 1101945
UserNameTAG: johanelbers
CreateTimeTAG: 2013-03-29T19:19:46Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 194
TitleTAG: Thank you for a very good course
To prof Ani and all the supporting staff
Thank you for a very intresting and well explained material.
Will be waiting for more from this good came from.
Although i have learned statistics 30 years ago i have never felt such deep understanding as i got from your lecture and examples.
Moshiko, Israel
UserIdTAG: 1240022
UserNameTAG: Moshiko
CreateTimeTAG: 2013-03-29T18:42:11Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 195
TitleTAG: How to register for Stat2.2x
How to register for Stat2.2x? I cant find any courses in edX.
UserIdTAG: 1011172
UserNameTAG: BChoudhary
CreateTimeTAG: 2013-03-29T18:13:40Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: How and when? I cannot find it too. Does anyone know it?
FirstChildUserIdTAG: 918956
FirstChildUserNameTAG: a-per
FirstChildCreateTimeTAG: 2013-03-29T19:12:16Z
FirstChildVoteTAG: 0
FirstChildTAG: how do you register for 2.2statx?
FirstChildUserIdTAG: 950329
FirstChildUserNameTAG: cbiglow
FirstChildCreateTimeTAG: 2013-03-29T19:16:52Z
FirstChildVoteTAG: 0
FirstChildTAG: You register in the same way as you registered for this course - once it becomes available.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-29T20:12:55Z
FirstChildVoteTAG: 0
IndexTAG: 196
TitleTAG: NNOOOOO!!!!!
I thought it was due today!! darn. :(
UserIdTAG: 316261
UserNameTAG: Brady1997
CreateTimeTAG: 2013-03-29T18:12:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 197
TitleTAG: Prof A's latest Course Info post
Can anyone explain to me how it is that Prof A's writing her blog sitting in/near Berkeley yet her blog ends with .in for me (I'm in India: I know that .in stands for India but how come its not the generic .com)?
I know this has nothing to do with Stat 2.1X but I'm interested in these things...Does anyone know?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-29T17:59:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I think you are referring to the domain redirection recently implemented in blogger:
http://support.google.com/blogger/bin/answer.py?hl=en&answer=2402711
To access the blog without being redirected try this:
http://stat2x.blogspot.com/ncr
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-29T18:47:36Z
FirstChildVoteTAG: 2
FirstChildTAG: Putting it very simply, the platform that hosts the blog([Blogger][1]), saves the blog into different servers around the world.
When one attempt to connect to the blog, the website redirects him/her to the closest server, which in your case is of course in India. If you were to connect from Germany, it would redirect your the the .de server, and so on :)
[1]: http://en.wikipedia.org/wiki/Blogger_%28service%29
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-29T18:52:33Z
FirstChildVoteTAG: 1
SecondChildTAG: Nice explaination! Thanx!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T04:15:54Z
SecondChildVoteTAG: 0
FirstChildTAG: Use the/ncr at end of the blogpost URL to see the nonlocal server edition
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-30T02:11:14Z
FirstChildVoteTAG: 0
IndexTAG: 198
TitleTAG: Thanks PROF ANI K and Team; i can now face my BOSS
i have learn t so much in a short time and you and your team have expanded my horizon laterally and now can face my "difficult" (lol) boss with confidence when ever i sent her a report, why we need a new staff, a new equipment, and why she needn't be afraid of a new competitor. My OPD Morbidity(Bio-statistics) got even better. This course has given me more insight and confidence to face him outright and even prove to him beyond reasonable doubt through what you and your team have taught me. thanks and can't wait for the next lecture.
i like your voice,sarcasm and the abc...way of presenting the same thing that baffles us, in an easy to comprehend way. thanks soooooooo much.
UserIdTAG: 799816
UserNameTAG: JAMINx
CreateTimeTAG: 2013-03-29T17:32:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Don't try to explain too much, he might use the f-word!
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-29T17:53:21Z
FirstChildVoteTAG: 0
IndexTAG: 199
TitleTAG: Exam needs to have shorter duration to prevent cheating
While some of us slogged for hours to finish the exam, I was shocked to see exam questions posted by some individuals in online forums requesting answers.Frankly I dont see why this people are doing the course if the only goal is to score rather than understand the material.
Suggest in Stats 2.2 the exam duration is shortened. Give only a day or some fixed hours on a Saturday or Sunday. This will at least make it impossible for people to get responses when they post the questions.
Also weekdays for exam really is exhausting after a work day.
Overall I have never understood Stats as well as this course has taught me. A BIG THANKS to EDX,BERKELEY and PROF. ADHIKARI.
UserIdTAG: 403216
UserNameTAG: harineem
CreateTimeTAG: 2013-03-29T17:21:53Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 7
FirstChildTAG: You're applying your values to others. The reasons to attend a MOOC are as varied as the people who take them. Your reason is no better or worse than mine.
I'm here to understand. The certificate is of inconsequential value. That one of us scores higher than another is of no consequence. You and I are not competing. That I did the work and others did not does not in any way minimize or trivialize my accomplishment.
Some of us work weekdays. Some of us work weekends. Some of us work evenings. Some of us work nights. Opening the exams for short time puts people who do not work traditional schedules and who are not in or near the time zone of record at a disadvantage.
I don't think any changes should be made to the way in which exams are handled.
FirstChildUserIdTAG: 876324
FirstChildUserNameTAG: BrianDeering
FirstChildCreateTimeTAG: 2013-03-29T17:43:25Z
FirstChildVoteTAG: 14
SecondChildTAG: Ok I understand your point on the duration. But there is a certificate attached to the course and it loses value if more and more people use loop holes to beat the system.My suggestion was only to curb the same.Ultimately edX has to make the call.
But at least have one weekend day for the exam time.I have done the Stanford online ones and it was easier to manage there because of the weekend day.
SecondChildUserIdTAG: 403216
SecondChildUserNameTAG: harineem
SecondChildCreateTimeTAG: 2013-03-29T18:35:52Z
SecondChildVoteTAG: 0
FirstChildTAG: You put too much stock in the certificate. In its current form, it's probably worth no more than the ink on the paper. Many of us took the class to learn, to enrich ourselves. I myself would be very happy if my final score is in the same quartile as Susan's. ;-)
FirstChildUserIdTAG: 608203
FirstChildUserNameTAG: chauct
FirstChildCreateTimeTAG: 2013-03-29T18:44:51Z
FirstChildVoteTAG: 5
SecondChildTAG: Why criticize certificate here, where issue raised is cheating? At how many posts clamouring for certificate have you registered your criticism of certificates?
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T17:59:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Dear Professor, EdX Staff and forum user;
I deeply appreciate your contribution in empower others whom less fortunate than you are. Final exam period was on my 63rd birthday and I just have a grandson on March 17th; I work full time and take care 2 dogs run back and forth to hospital. Your grace period and your kindness allow me to complete the course with the rest whom younger and more talent than me. My life does not need a lot including certificate. I am only need to feel how smart people learn. I do not care who cheat, it is none of my business. I only know I sign honor code and I stick by.
Thank you very much have a happy Easter,
Pitak
FirstChildUserIdTAG: 666107
FirstChildUserNameTAG: Pitak
FirstChildCreateTimeTAG: 2013-03-29T19:45:37Z
FirstChildVoteTAG: 10
FirstChildTAG: The only way that certificates from courses such as this will have real value is if we take the exams in a formally supervised environment.
I think some of the MIT courses look at doing that but if you're here to learn then cheating serves no purpose.
FirstChildUserIdTAG: 1735
FirstChildUserNameTAG: Stewart
FirstChildCreateTimeTAG: 2013-03-29T22:57:48Z
FirstChildVoteTAG: 1
SecondChildTAG: ok
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T15:24:55Z
SecondChildVoteTAG: 0
FirstChildTAG: You won't stop the cheating. It happens in f2f courses, formal online courses, and it will happen here - where the certificate really means nothing. And the cheaters don't realise that one reason the certificate means zip is because of their actions.
The certificate means everything to some. I've lurked on lots of courses, and one thing is consistent. The certificate takes priority for some. They want it. Badly. They want their grade on it. They want it mailed to them in hard copy. They want it recognized by other institutions. They want, want, want.
What they *don't* want, is to actually have to work for the certificate.
Their behaviour really p-s me off. Because there are those who really appreciate what edX and others are doing. Providing access to quality education for those who would otherwise not have it.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-29T23:29:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Why criticize certificate here, where issue raised is cheating? At how many posts clamouring for certificate have you registered your criticism?
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T15:34:27Z
SecondChildVoteTAG: 0
FirstChildTAG: I work full time but my hours are way more varied than the 9-5 mill, I also have a number of other commitments - similar I suspect to many taking online learning - since the flexibility of timing is one of the big advantages for me, otherwise I might never get a chance to finish anything.
I'm truly appreciative of the opportunity to participate in the course for many reasons: the nature of the content, the quality of the instruction, the freedom of access and of course the fact that it's free is particularly helpful, since I doubt I could afford it if it wasn't.
The certificate is a very small incentive, though I don't expect any employer would rate it as equivalent to a traditional qualification of any kind, but it proves that I'm interested and willing to learn, and eager enough to pursue learning on my own time. It also gives me a personal sense of satisfaction and completion. If I cheated, I'd only be cheating myself.
I certainly hope they don't change the timings around either the exercises or the exams, even though the only time I could actually fit them in was around 2am, it was worth it because I thoroughly enjoyed them.
Thanks again Prof A for a challenging and worthwhile course, much appreciated :)
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-03-30T01:46:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Harineem posted: **I was shocked to see exam questions posted by some individuals in online forums requesting answers . Frankly I don't see why this people are doing the course if the only goal is to score rather than understand the material.** This is deplorable and I don't understand why anybody opposing it, not be welcome . After all it affects the forum negatively. May be the remedy suggested is the reason for some opposition . In my view also decreasing exam. duration for MOOC exam is not a good idea . **But arranging for optional proctored exam is the way out . This is not my idea. EdX itself practised it for another MOOC viz. PH207x just two months back .** I don't know why this option is not available this time. There might be some technical problem . Even now all the results are with edX & it can arrange proctored exam sometime later when it suits edX only for those who are willing . That can also make way for grading option for those interested.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-30T10:26:14Z
FirstChildVoteTAG: 0
SecondChildTAG: There was no proctored exam in PH207x.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-30T11:08:11Z
SecondChildVoteTAG: 0
SecondChildTAG: But it was widely publicized on edX fora and on PH207x site.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T11:22:03Z
SecondChildVoteTAG: 0
IndexTAG: 200
TitleTAG: Certification
Thanks everyone for their direct or indirect support.
I have successfully completed stat2.1x .
But i would like to know that when will be the certificates awarded.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T17:17:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Look under Course Info ... Prof A's post may not have been up when you last checked.
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-29T17:46:59Z
FirstChildVoteTAG: 1
IndexTAG: 201
TitleTAG: Thanks from Tunisia
Greetings from Tunisia
Thank you very much for the course !!! it was really interresting. Many thanks to all staff, you did really great job.
UserIdTAG: 1246720
UserNameTAG: lilia1979
CreateTimeTAG: 2013-03-29T17:12:43Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 202
TitleTAG: Thanks very much Professor Adhikari !
Thanks very much Professor Adhikari for your lessons, very interesting and clear.
It was a pleasure to learn with you. I look forward to meet you again in Stat2.2x.
Best regards
R.M.M
UserIdTAG: 1163701
UserNameTAG: canbo
CreateTimeTAG: 2013-03-29T16:48:43Z
VoteTAG: 7
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 0
IndexTAG: 203
TitleTAG: Thanks for all
Thanks for all
UserIdTAG: 1194493
UserNameTAG: mbenmour
CreateTimeTAG: 2013-03-29T16:46:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 204
TitleTAG: thanks from Slovakia
I would love to say Thank you, to all assistants, profesors and every one included in creating of this course, for teaching and sharing this course. It was nice experience. Hope to meet some of you, fellow "students" in Stat 2.2X.
Had more fun and understood more during this online course than in similar regular class.
Best Wishes,
Tomas from Slovakia
UserIdTAG: 1208016
UserNameTAG: TomFerech
CreateTimeTAG: 2013-03-29T16:34:39Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 205
TitleTAG: To all of you!
I am delighted that so many people from different countries joined by pure desire to learn. It's a wonderful experience to feel part of the community. Pakistan, India, Costa Rica, Indonesia, Artgentyna, New Zealand, Portugal, Serbia, Germany, the United States ...
Thank you all, because I feel proud to participate in such excitig international project. Greetings from Poland.
Margaret
UserIdTAG: 923445
UserNameTAG: MLaszczewska
CreateTimeTAG: 2013-03-29T16:32:15Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 8
FirstChildTAG: +Slovakia, +Tunisia, +Israel :-) So we are from all continents!!!
FirstChildUserIdTAG: 923445
FirstChildUserNameTAG: MLaszczewska
FirstChildCreateTimeTAG: 2013-03-29T18:53:37Z
FirstChildVoteTAG: 1
SecondChildTAG: +Spain, some Spanish people were working here too ;)
SecondChildUserIdTAG: 918956
SecondChildUserNameTAG: a-per
SecondChildCreateTimeTAG: 2013-03-29T19:10:05Z
SecondChildVoteTAG: 0
SecondChildTAG: That's great I Love Spain:) thanks for that comment. I looked through comments but I did't find you.
SecondChildUserIdTAG: 923445
SecondChildUserNameTAG: MLaszczewska
SecondChildCreateTimeTAG: 2013-03-29T19:19:12Z
SecondChildVoteTAG: 0
SecondChildTAG: OOh I just wish someone on a Base in the Antarctic joins in - then we will have people from all over the globe(I actually did a study with someone form a Base in the Antarctic some years abck abnd so you never know - it can be possible via the net!!)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-30T02:16:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-03-30T03:26:36Z
SecondChildVoteTAG: 0
FirstChildTAG: +Spain, +Australia, +Brasil, +Belgium, +Canada, +Italy +Greece !!! Who else?
FirstChildUserIdTAG: 923445
FirstChildUserNameTAG: MLaszczewska
FirstChildCreateTimeTAG: 2013-03-29T19:21:21Z
FirstChildVoteTAG: 1
SecondChildTAG: United Kingdom
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-29T20:13:48Z
SecondChildVoteTAG: 0
SecondChildTAG: And Canada :)
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-03-30T01:48:34Z
SecondChildVoteTAG: 0
SecondChildTAG: +India
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-30T02:16:26Z
SecondChildVoteTAG: 0
FirstChildTAG: +United Kingdom, +Dubai, +Uganda, +Algeria
FirstChildUserIdTAG: 923445
FirstChildUserNameTAG: MLaszczewska
FirstChildCreateTimeTAG: 2013-03-29T20:45:33Z
FirstChildVoteTAG: 1
FirstChildTAG: +Trinidad +Egypt!!!
FirstChildUserIdTAG: 923445
FirstChildUserNameTAG: MLaszczewska
FirstChildCreateTimeTAG: 2013-03-29T21:06:46Z
FirstChildVoteTAG: 1
FirstChildTAG: +Peru, +Puerto Rico, +Kossovo, +Morocco, +Colombia, +Kazakhstan, Philippines, +Bosnia and Herzegovina, +Cyprus, Belarus:)
FirstChildUserIdTAG: 923445
FirstChildUserNameTAG: MLaszczewska
FirstChildCreateTimeTAG: 2013-03-30T09:39:48Z
FirstChildVoteTAG: 1
FirstChildTAG: Great!
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-30T18:03:15Z
FirstChildVoteTAG: 1
FirstChildTAG: +Singapore, +Kenya, +Cyprus, +China, +Nepal !!!!!
FirstChildUserIdTAG: 923445
FirstChildUserNameTAG: MLaszczewska
FirstChildCreateTimeTAG: 2013-03-30T19:04:49Z
FirstChildVoteTAG: 1
FirstChildTAG: Serbia :)
FirstChildUserIdTAG: 302329
FirstChildUserNameTAG: markomarkovic
FirstChildCreateTimeTAG: 2013-04-01T09:09:49Z
FirstChildVoteTAG: 1
IndexTAG: 206
TitleTAG: Thanks from Serbia
Thank you for wonderful course. Hope to see you soon in Stat 2.2x.
UserIdTAG: 302329
UserNameTAG: markomarkovic
CreateTimeTAG: 2013-03-29T16:24:54Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: extra je bilo, odakle si?
FirstChildUserIdTAG: 990423
FirstChildUserNameTAG: George95
FirstChildCreateTimeTAG: 2013-03-29T16:27:55Z
FirstChildVoteTAG: 1
SecondChildTAG: Iz Beograda. Stvarno sjajan kurs. Profesorka je sjajna, odlično objašnjava i duhovita je.
SecondChildUserIdTAG: 302329
SecondChildUserNameTAG: markomarkovic
SecondChildCreateTimeTAG: 2013-04-01T09:08:05Z
SecondChildVoteTAG: 0
FirstChildTAG: Super je bilo))
Studirao sam statistiku i ekonometriku na fakultetu ali ovde sam dobio stvarno duboko razumevanje.
Ja sam iz Crne Gore))
FirstChildUserIdTAG: 197621
FirstChildUserNameTAG: quilombolo
FirstChildCreateTimeTAG: 2013-03-29T18:54:28Z
FirstChildVoteTAG: 1
FirstChildTAG: He, ja mislila nema ovde Srba. :)
I meni se dopalo. Zna li neko kad ce biti nastavak? Ovo je samo deskriptivna statistika a meni treba multivatijantna.
FirstChildUserIdTAG: 1170582
FirstChildUserNameTAG: nakili
FirstChildCreateTimeTAG: 2013-03-29T22:31:46Z
FirstChildVoteTAG: 1
SecondChildTAG: Negde je bilo tu na forumu - pisala je Prof. Adhikari - da nastavak ce da pocne 12 Aprila. Ali treba njima vreme za pripremu, mozda ce da odloze kao i ovaj kurs.
P.S. Ja sam Rus)))
SecondChildUserIdTAG: 197621
SecondChildUserNameTAG: quilombolo
SecondChildCreateTimeTAG: 2013-03-29T22:59:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Pa to je isto... vi ste nama braca..hehehehe
SecondChildUserIdTAG: 1170582
SecondChildUserNameTAG: nakili
SecondChildCreateTimeTAG: 2013-03-30T00:34:38Z
SecondChildVoteTAG: 0
SecondChildTAG: P.S. Hvala na informaciji za nastavak kursa
SecondChildUserIdTAG: 1170582
SecondChildUserNameTAG: nakili
SecondChildCreateTimeTAG: 2013-03-30T01:37:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Ima nas, ima nas :) Vidimo se na Stat 2.2x uskoro.
SecondChildUserIdTAG: 302329
SecondChildUserNameTAG: markomarkovic
SecondChildCreateTimeTAG: 2013-04-01T09:09:13Z
SecondChildVoteTAG: 0
IndexTAG: 207
TitleTAG: Prof Ani's additional practice problem sets
Prof Ani,
Thank-you for the additional practice sets on the regression topics, it clarified and solidified points that did not sink in the first time around.
Also, I liked your hand drawn sketches in many of your lectures, these greatly help me understand the topics.
If similar min sketche were to be supplied with the answer keys, it would be great.
Thanks again, looking forward to the next session.
UserIdTAG: 940447
UserNameTAG: rob4511
CreateTimeTAG: 2013-03-29T16:20:09Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I really liked the hand drawn sketches too - a very warmly human ingredient to mix with the technology, and far less intimidating than a perfectly generated graphic :)
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-03-30T01:50:57Z
FirstChildVoteTAG: 0
IndexTAG: 208
TitleTAG: Few Suggestions
Thanks Ani Adhikari for a wonderful course.
I am suggesting few things which I felt needs to be taken care of
1. Please keep the exams on the weekends, as many taking these course are working it will be easy to read and take the exams in the weekends.
2. Please increase the number of submissions for the exercises atleast 10 chances for the problems, if we don't understand the problem at the first time then two chances are over and we need to wait for the results to come, if more than two chances atleast we can try and understand the problems
3. Please explain more type of problems in the class videos and more problems are required in the assignment.
Once again thanks for the wonderful course, waiting for Stats2.2x.
UserIdTAG: 451012
UserNameTAG: swamydkv
CreateTimeTAG: 2013-03-29T16:19:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 209
TitleTAG: Thank you very much from Costa Rica
It was really fun taking this course these five weeks, I learnt a lot. Hope to stay up for Stat 2.2x.
Thanks Prof. A and Staff
UserIdTAG: 1203461
UserNameTAG: Andrey18
CreateTimeTAG: 2013-03-29T16:14:20Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 210
TitleTAG: Thanks from Kerala, India
Thanks to Prof.Ani and the whole team behind Stat2.1x - you did a wonderful job!
Anxiously waiting for Stat2.2x to begin!!
UserIdTAG: 99863
UserNameTAG: pramode_ce
CreateTimeTAG: 2013-03-29T16:00:18Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: agreed
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T17:06:59Z
FirstChildVoteTAG: 0
IndexTAG: 211
TitleTAG: Thank you Prof. A. and EdX staff!
This class has been great and such a valuable opportunity! I look forward to Stat 2.2 becoming an option on EdX. Thank you again!
UserIdTAG: 338209
UserNameTAG: mikemichael
CreateTimeTAG: 2013-03-29T15:42:23Z
VoteTAG: 9
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thank to Prof. A and her team.
I expect to additional course on Stat.
FirstChildUserIdTAG: 1189075
FirstChildUserNameTAG: Tejadhikari
FirstChildCreateTimeTAG: 2013-03-29T18:51:01Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks to all participants and their discussion from Nepal
SecondChildUserIdTAG: 1189075
SecondChildUserNameTAG: Tejadhikari
SecondChildCreateTimeTAG: 2013-03-29T18:51:51Z
SecondChildVoteTAG: 0
IndexTAG: 212
TitleTAG: Thanks EdX team!
I would like to thank Prof. Ani Adhikari, Prof. Philip Stark, and all
EdX team for this great opportunity: to learn statistics with
some of the best professors of the USA. For me, Stats 2.1X was an
opportunity not only to learn Statistics but also to study English
language, and
it has been an amazing experience.
I am anxiously waiting for Stats 2.2X.
Thank all you so much.
Marivaldo Aragão
Brazil
UserIdTAG: 1031814
UserNameTAG: Marivaldo
CreateTimeTAG: 2013-03-29T15:30:23Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's great to see so many international students. Your English looks great to me!
FirstChildUserIdTAG: 1153828
FirstChildUserNameTAG: Matt2edX
FirstChildCreateTimeTAG: 2013-03-29T15:44:05Z
FirstChildVoteTAG: 0
IndexTAG: 213
TitleTAG: Prof. A., do you have a Twitter feed?
You would become an instant sensation!
Your praises on this discussion forum are well-deserved. Thanks very much for the course and see you in Stat2.2x!
UserIdTAG: 914245
UserNameTAG: dbaPlanB
CreateTimeTAG: 2013-03-29T15:26:34Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Should I? I don't use Twitter, Facebook, etc, but I think I'm the only person in the world who doesn't. Do students want me on Twitter? I can't help thinking they get more than they want of me in the lectures.
I'll learn to use Twitter if students want, but really, I inflict myself on them quite enough as it is ...
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-29T16:58:46Z
FirstChildVoteTAG: 2
SecondChildTAG: I just wanted to say that you are one of TWO people in the world that do not use social media ;) Actually, that is not correct; I wanted to say something more, too...
First, thank you so very much! Secondly, I think Twitter would indeed be a very effective way for you to reach a wide audience. Just think, in a 140 characters or less, you could direct your followers to your blog - or anywhere else - where you could share with them your insights, knowledge, advice or (something I truly appreciate) your subtle humor.
SecondChildUserIdTAG: 23003
SecondChildUserNameTAG: WH
SecondChildCreateTimeTAG: 2013-03-29T17:27:22Z
SecondChildVoteTAG: 0
SecondChildTAG: There's 3 of us :D
Although were I to choose one, Twitter would probably be much better than Facebook, that den of horribly noisy strangers, acquaintances, and the occasional real friend, who constantly expect you to post as you go to work, or on holiday, or clubbing with friends, or, heck, even when you go to the bathroom. And they want photos too!
And if you don't play along...well then, *they* will post those photos for you, tag you, or send 3 millions emails every day asking to water their crops in Farmville. No, thanks.
Twitter at least, it's just about sharing some news or opinions when you feel like it :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-29T19:08:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't use Twitter and Facebook and any like this neither:P But I agree with you;the Twitter really could be useful sometimes.Maybe few people would notice there easier the deadlines and these kind of things:)
SecondChildUserIdTAG: 1232601
SecondChildUserNameTAG: Firefly-2009
SecondChildCreateTimeTAG: 2013-03-29T20:59:07Z
SecondChildVoteTAG: 0
SecondChildTAG: I have no time for Facebook but find Twitter quite useful, I'd certainly read your tweets Prof A :)
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-03-30T01:54:48Z
SecondChildVoteTAG: 0
FirstChildTAG: Even I don't use twitter,facebook and don't know much about these ,may be due to lack of interest and time. Your blog posts are superb.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T17:40:19Z
FirstChildVoteTAG: 0
FirstChildTAG: I think Twitter would be a great medium for you. As WH and Klionheart said, it's a way to direct people to your blog (congratulations on your day off, although . . .), and for you to share random thoughts (no pun intended), or spread the word about statistics.
It's not an imposition on students at all, since only those who want to follow you will get your tweets, and the manner of receiving tweets is very customizable. Which means responses to your tweets needn't be a big imposition on you, either.
Here's an exercise from student to teacher: Go to https://twitter.com/search-home and type in "stat2.1x"
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-29T20:38:26Z
FirstChildVoteTAG: 1
SecondChildTAG: Wow - who knew there was so much chatter about 2.1x on Twitter already! :)
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-03-30T01:57:31Z
SecondChildVoteTAG: 0
IndexTAG: 214
TitleTAG: Many Thanks from Portugal
Thank you very much for the course, it was really great. Looking forward to see you here again in April. Many thanks to all staff, you did really great job. Greetings from Portugal.
UserIdTAG: 1264473
UserNameTAG: Alex_from_Sintra
CreateTimeTAG: 2013-03-29T15:08:02Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 215
TitleTAG: Thanks from Germany
Thank you very much for wonderful course. I got 87% for the total. Waiting for the next course.
UserIdTAG: 7980
UserNameTAG: Nazri
CreateTimeTAG: 2013-03-29T15:05:17Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 216
TitleTAG: Thanks
Thank you to all of you for making this possible - a class with an enrolment in the tens of thousands is mind-boggling to me, but I think it all went very well considering the scale. The course itself definitely stretched me, but I enjoyed the challenge and am looking forward to 2.2x.
Thanks!
UserIdTAG: 971321
UserNameTAG: peteben
CreateTimeTAG: 2013-03-29T15:02:17Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 217
TitleTAG: Midterm Problem 4B
The solution to the above problem seemed somewhat qualitative to me. I've tried a more rigorous proof.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13645663824494937.png
The bottom three lines in the graph show the section averages ± 2SD and the top line shows the combined average along with the minimum and maximum from the lines below.
----------
For Section 3 (µ = 60), the number of students with marks below 42 can be no more than 1/4 of the total number of students (32), viz., 8 as per Chebychev's inequality. In other words, the number of students with marks below 42 can be only up to 8.
----------
Similarly, for Section 2 (µ = 75), the number of students with marks above 93 can be no more than 1/4 of the total number of students (25), viz., 6. In other words, the number of students with marks above 93 can be only up to 6.
----------
For the combined scores, let us assume the SD is equal to the section SDs, viz., 9. Then, the point 42 is 2.8 SD away from the average (67). Hence, the number of students with marks below 42 can be no more than 1/2.8^2 of the total number of students (77), viz., 10. In other words, the number of students with marks below 42 can be up to 10. However, this violates the earlier assumption that the number of students with marks below 42 can be only up to 8.
----------
Similarly, the point 93 is 2.9 SD away from the average. Hence, the number of students with marks above 93 can be no more than 1/2.9^2 of the total number of students, viz., 9. In other words, the number of students with marks above 93 can be up to 9. However, this violates the earlier assumption that the number of students with marks above 93 can be only up to 6.
----------
Ergo, the SD of the combined scores must be greater than 9 to satisfy the earlier assumptions.
----------
I would welcome any comments/criticisms/fallacies in the above proof.
UserIdTAG: 346428
UserNameTAG: aranic
CreateTimeTAG: 2013-03-29T14:51:14Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 0
IndexTAG: 218
TitleTAG: Thank you very much!
Thank you so much for sharing your knowledge ma'am! Helped me a lot.When you come from a place with below average teachers, the online courses are a boon!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T14:47:12Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 219
TitleTAG: Please post the distribution of the class scores
Please post the distribution of the class scores. I am interested to see how an online course this large turns out (for scores that is) as well as to know how I fared.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T14:46:41Z
VoteTAG: 13
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: ... and how many completed the course compared with the total initial registration?
FirstChildUserIdTAG: 1153828
FirstChildUserNameTAG: Matt2edX
FirstChildCreateTimeTAG: 2013-03-29T15:46:47Z
FirstChildVoteTAG: 6
FirstChildTAG: Please post the distribution along with stem and leafs plot of top 100 scorers' scores.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T17:28:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Really? Why not a stem/leaf plot of everyone, that would be a fun task! Lol :)
*Tongue firmly in cheek
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-03-30T02:01:42Z
SecondChildVoteTAG: 0
SecondChildTAG: That be better left for you! Lol :)
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T18:06:23Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't understand the obsession with marks. The top 100 will no doubt have scored 100.
Thousands enrolled, and as the content wasn't exactly rocket science, I'm sure many who were here from the start did okay.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-29T21:41:02Z
FirstChildVoteTAG: 0
SecondChildTAG: I don't understand the obsessive aversion to marks. If distribution of figures so upsets anybody, why join stat2.1x ? By the way, did you notice your marks ?
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T18:19:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Sometimes obsessive compulsion & mindless opposition blinds you . Even you two are contradicting each other, one finds it inconceivable & laughable to draw the plot , the other finds it simple enough not to merit drawing a plot ! Perfect example of opposing in a discussion , without being sure of your of own point of view ! At the same time, crowding at 100 % ( w.r.t final exam problem 4a/4b ) happens to be a hot topic of discussion at half a dozen posts !
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-31T00:29:16Z
SecondChildVoteTAG: 0
FirstChildTAG: It would be interesting to see the statistics for all students, with the ES AVG, Midterm, Final, and Total Scores.
Think of the scatter plots we could make and the correlations we could analyze for fun! :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-29T22:57:17Z
FirstChildVoteTAG: 1
SecondChildTAG: Interesting indeed!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-30T18:21:18Z
SecondChildVoteTAG: 0
IndexTAG: 220
TitleTAG: Prof A, you have such a sweet voice. - From Hyderabad, India.
Hi Prof A,
Until I completed my schooling, the majority of the teachers I had were females. May be I got associated with it that I used to find it easy to connect to the lesson being taught if it was a female instructor.
Your sweet voice reminded me of school days and of course, taught me the descriptive statistics. Thanks for your time. It really meant a lot.
Lots of love,
Avinash Raju D.V,
Hyderabad, India.
UserIdTAG: 1014053
UserNameTAG: Avinash101
CreateTimeTAG: 2013-03-29T14:39:48Z
VoteTAG: 2
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 3
FirstChildTAG: Hmm. I enjoyed the course tremendously, but I kept imagining Prof. Adhikari on my PhD committee, eviscerating me in the qualifying exam with deceptively simple questions, and then finishing me off with a grace note of expertly timed sarcasm.
Hopefully she uses her powers for good.
FirstChildUserIdTAG: 174848
FirstChildUserNameTAG: jberg
FirstChildCreateTimeTAG: 2013-03-29T16:29:52Z
FirstChildVoteTAG: 0
SecondChildTAG: jberg, you are very perceptive. I try not to eviscerate. And the sarcasm has toned down over the years. But it's definitely there. Students who take my classes often come back for more, so either they're masochists or they still have some viscera left. Or I'm getting soft in my old age. But your description did remind me of myself on my grouchy days.
Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-29T16:48:58Z
SecondChildVoteTAG: 0
FirstChildTAG: jberg - I wish you had not brought up that side of Prof A;) I had hopes of retaining
the image and thought of the good Prof A. In any case, Prof A has captured
my statistical heart and I will follow her to Stats 2, 3, 4, 5 ...
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-03-29T22:02:48Z
FirstChildVoteTAG: 1
FirstChildTAG: cobradav, Dr. Bruce Banner is a great guy. He teaches a wonderful edX MOOC on the biophysics of gamma radiation. But as nice as he is, it's a good idea not to aggravate him. Maybe we should think of Prof. Adhikari the same way.
FirstChildUserIdTAG: 174848
FirstChildUserNameTAG: jberg
FirstChildCreateTimeTAG: 2013-04-01T04:56:31Z
FirstChildVoteTAG: 0
IndexTAG: 221
TitleTAG: certificate
i coudnt face to the final exam.but having marks above the passing grade. am i eligible for certificate and next stat 2.2. thanks for the knowledge given by stat 2.1 every staff.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T14:17:43Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 222
TitleTAG: Sincere thanks from Indonesia
Dear Prof Ani, Prof Stark,and all the edx 2.1x stat staffs,
thank you very much for enabling this extraordinary measure of disseminating a knowledge. It is of an immense and sincere gratitude from me to be a part of this class which I have never thought or even dare to dream of-a world class for free.
May your sincerity be granted with much more rejoice and goodness in life:)
I am looking forward to joining in the next 2.2x:)
Best regards from Indonesia:)
UserIdTAG: 1274748
UserNameTAG: kusumawati
CreateTimeTAG: 2013-03-29T14:15:50Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 223
TitleTAG: Very grateful for sharing knowledge
Teacher Ani clear in his explanations, I thought the final exam was until today at 6:30 Ecuador, not end final exam, I also lost E3. I will organize myself better to spend more time studying, I want to continue in statistics, google translator helps me and my interest in learning.
UserIdTAG: 1024935
UserNameTAG: N3
CreateTimeTAG: 2013-03-29T13:55:34Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 224
TitleTAG: Thanks from New Zealand!
As this chapter comes to a close & we wait on the next, i would like to thank Ani Adhikari & Philip Stark for first of all giving us the opportunity to learn from you both.
It has been a challenging ride, Ani Adhikari learning from you was an eye opener, at times, having had me wracking my brains out only to think..."Oh! that's it!. Phillip with your lectures, for me it felt like actually being in the classroom, very, very good learning experience with you. while new to me, with the content available, being able to follow is very manageable & yes i read/watched everything. As i am very new to stat, with the better part of my background studying/working with Microsoft, which is very different & a welcome change.
With the knowledge gained & my achievements exceeding expectations by far i'm certain that i'm beginning to like stat, i feel i may continue!
For those interested
Graded average; 98%
Midterm; 90%
Final; 100%
Total; 97%
Thanks again for all whom put the time in as it is solid education & free at that.
Your time is very much appreciated.
Regards,
John
UserIdTAG: 1253130
UserNameTAG: Eternalight
CreateTimeTAG: 2013-03-29T13:41:25Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 225
TitleTAG: Thank you
Dear Professor Ani and Professor Stark.
Many thanks for all.
I always use statistics in my work, and you clarified a lot of things!
I'm waiting for april the 12th.
Best regards.
Luigi
UserIdTAG: 1008980
UserNameTAG: ginopra
CreateTimeTAG: 2013-03-29T13:40:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 226
TitleTAG: What happens?
I missed the final exam, completely. I wont get the certificate? Even I did well in the other exams?
Thanks
UserIdTAG: 1222835
UserNameTAG: CatonElMenor
CreateTimeTAG: 2013-03-29T13:39:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you have at least 35% overall the you will get the certificate. No part is compulsory, it would be perfectly possible to pass the course without taking either exam.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-29T14:22:16Z
FirstChildVoteTAG: 0
IndexTAG: 227
TitleTAG: Thanks from Argentina
Thank a lot proffesor and staff for this wonderfull course. The classes were very clear and precise and I learned a lot watching and reading them.
Thanks
UserIdTAG: 1222835
UserNameTAG: CatonElMenor
CreateTimeTAG: 2013-03-29T13:38:04Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 228
TitleTAG: Final exam 4a not clear for me
Hi, maybe it?s because of my English, but If we say: The final exam is “graded on a curve,” with the top 20% of the students on the final receiving an A grade on the exam, we can mean that they will recieve an A because they are among the best 20% or that they recieved the A because they reached a certain score and, by chance, 20% reached that score. In the latter case the correlation wouldn't be 1, much more A grades would be awarded, there is even a possibility that all students recieved A.
UserIdTAG: 1341242
UserNameTAG: alesbadura
CreateTimeTAG: 2013-03-29T13:12:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I think the wording implies that grades are matched to a normal distribution so the same proportion achieve each grade regardless of the actual mark.
We don't use the term 'graded on the curve' in education here in the UK although we do sometimes refer to 'normalising scores' which seems to mean the same thing - the assumption that each cohort will perform to the same standard and variations in marking from year to year are down to the examination rather than the students.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-29T14:28:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Yeah I learn that "curve" term when I moved to the states. What this question asked in "simpler" term was, are the "TOP 20%" grades from the previous list the same as the "TOP 20%" of the new list?
Keep in mind that the new list is the old list plus a constant to each exam result. So in escense ... the new list 20% == the old list 20% .
Hope this helped,
Gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-03-29T16:25:44Z
FirstChildVoteTAG: 0
IndexTAG: 229
TitleTAG: MY AUTOEVALUATION
to begin with, my pros
----------
* I learnt a lot with the video lectures, and Y used the book as a guide and to do the exercises proposed.
* I have to thanks to all staff by specially to Ani Adikhari for being so clear in her explanations
* I liked and enjoyed the rithm of lessons and exercises
----------
My cons:
* Threads of discussions were a mess in my opinion, I think that a lot of us should read the discussion threads before post another opinion
* I didn´t like those who posted answers
----------
PD: sorry for my English level but I am learning it. I would like to have a statistic-summary of the course: note-average, median, percentiles of midtearm an final exam...
----------
I´ll see all you in Stat 2x2
See all you soon and kisses from Basque Country
----------
Maite
UserIdTAG: 1002821
UserNameTAG: Urimare
CreateTimeTAG: 2013-03-29T13:06:27Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I agree with your assessments. The good news is that MOOCs are a new paradigm. It will take awhile for the systems to develop and for the instructors and professors to feel comfortable with the developments. I think Dr. Ani did a terrific job. I’m impressed and will return. And, although I’ve not met Dr. Ani, I feel strangely connected to the instructor - much as I did when I took classes at brick and mortar schools with direct student/teacher interaction.
I think the discussion areas were a mess. I was frustrated when someone posted something like “Problem with question 3b!” I had no way of knowing to which exercise set they were referring. And while I might have had something to offer, and would have been happy to do so, I didn’t have the time to sift through.
I attended another MOOC where the first segment of the first week covered “How to Ask Questions.” The lecture derived in part from [How to Ask Questions][1] and other resources. I think this is a good beginning for every MOOC.
Perhaps the discussion areas could be pre-organized so that each exercise set had a folder and each question a sub-folder beneath that. I was about to complain about the absence of a discussion area search feature but I just now saw the little magnifying glass. Now I feel like a dunce.
Some of those responding to questions seemed a little sarcastic but remember that text messages are flat; they do not have tone and they do not have visual clues (body language). The only tone a text message has is that which the recipient imparts. Perhaps what you experienced were cultural differences. (I’ll go with that.) That said, some of the responses were less than helpful.
I find it frustrating when I pose a question and someone posts, “watch the video.” I've watched the video. If I understood the video I wouldn't be asking. If I didn't understand the video the first time it’s unlikely I’ll understand it the second time and by the fifth time I’ll just be frustrated.
Best wishes to everyone and I look forward to ‘seeing’ everyone is Stat2.2x.
[1]: http://www.catb.org/~esr/faqs/smart-questions.html
FirstChildUserIdTAG: 876324
FirstChildUserNameTAG: BrianDeering
FirstChildCreateTimeTAG: 2013-03-29T17:33:07Z
FirstChildVoteTAG: 3
SecondChildTAG: BrianDeering - thanks for posting that link about asking questions. I personally wish I had read it before jumping into the forum. I showed some bad behavior and I feel awful about it. But this makes me want to try harder, so it is much appreciated.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-29T19:18:33Z
SecondChildVoteTAG: 0
IndexTAG: 230
TitleTAG: Tough but Thanks!
Wow, That was tough! But very rewarding and I learned a lot over the past few weeks. I don't know how well others did, I scraped by with about 60%. Considering I had virtually no background in maths before taking this course I am happy with that. I faired reasonably well until we got to linear regression, then my head started to explode.
I probably would have got a better result if I had more time to dedicate to learning the material each week, but I have to balance this course with jobs and other things.
Thanks so much for a wonderful course. I look forward to getting my certificate.
Very best wishes
George
UserIdTAG: 1265802
UserNameTAG: GMORRIS010
CreateTimeTAG: 2013-03-29T12:51:20Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: This describes me totally!
FirstChildUserIdTAG: 4612
FirstChildUserNameTAG: Susnaj
FirstChildCreateTimeTAG: 2013-03-29T15:10:34Z
FirstChildVoteTAG: 0
FirstChildTAG: Agree totally George - and you did great! I struggled at the end due to lack of time as like you I was squeezing in the course between work and other commitments, but so glad I did and wouldn't have missed it for the world.
Keeping my fingers crossed that 'stuff' won't get in the way of study next time :)
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-03-30T02:12:48Z
FirstChildVoteTAG: 0
IndexTAG: 231
TitleTAG: Thank you Prof. A
Thank you Prof. A for teaching this course. I learned a lot of statistics from Frequency Histogram to Regression. I will enroll stat2.2x and stat2.3x to learn and to understand more about the statistics. :)
UserIdTAG: 211916
UserNameTAG: dwrdchoi
CreateTimeTAG: 2013-03-29T12:39:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 232
TitleTAG: Final Exam - STAFF
Tried to log in last night and problems have all my answers and now i missed out on doing the exam and this is wrong.
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-03-29T12:29:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Dear staff members,
There was an error in my connection last day. So please be kind enough to provide me another chance please.
Randika
FirstChildUserIdTAG: 679558
FirstChildUserNameTAG: Randika
FirstChildCreateTimeTAG: 2013-03-29T12:40:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too..couldnt write final exam..:(
FirstChildUserIdTAG: 1050926
FirstChildUserNameTAG: Retrolyte
FirstChildCreateTimeTAG: 2013-03-29T12:46:48Z
FirstChildVoteTAG: 0
FirstChildTAG: I was unable to take the final exam. I marked my calendar for Friday the 29th, and now I see it was due at 5:00 a.m.
FirstChildUserIdTAG: 1160056
FirstChildUserNameTAG: Beneviolence
FirstChildCreateTimeTAG: 2013-03-29T14:02:21Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks from Colombia:
Wonderful course, Thanks to all staff members for their patiente and understanding. I am very happy with my own results but what a pity that I have confounded the date and hour of the final examination. I have traveled to another Colombian city to meet with my mother and I don't know what has happened. If it is any possibility to do it, please help giving me another chance. I want to be with you on April 12 at the beginning of a new 2.2 x course.
FirstChildUserIdTAG: 1240706
FirstChildUserNameTAG: remipole
FirstChildCreateTimeTAG: 2013-03-29T15:21:30Z
FirstChildVoteTAG: 0
FirstChildTAG: No, it is not wrong. It's the rules.
I couldn't do the test for grading because of illness. But I don't expect special treatment. This is a massive course, read the rules and follow them.
Do the test anyway for your own benefit, not for a certificate - which you probably have anyway, if you were here from the start.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-29T21:15:05Z
FirstChildVoteTAG: 0
IndexTAG: 233
TitleTAG: Is one of the ES not graded?
Is one of the ES not graded? I completely missed ES 12 (forgot that it was due on tuesday). But overall progress remains at 98%.
UserIdTAG: 389476
UserNameTAG: Wuddel
CreateTimeTAG: 2013-03-29T11:53:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: This is explained in the course policy.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-29T11:59:37Z
FirstChildVoteTAG: 0
FirstChildTAG: Lowest 2 scores are dropped (as marked by the x's on the progress chart).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-29T14:13:09Z
FirstChildVoteTAG: 0
FirstChildTAG: This policy really saved my grade as well, since I missed an entire week due to confusion over the time zone. I think many of us wanted the best result possible, even though the pass mark (35%) is so low. I look forward to seeing what the certificate looks like. When does registration begin for Stat 2.2x?
FirstChildUserIdTAG: 1153828
FirstChildUserNameTAG: Matt2edX
FirstChildCreateTimeTAG: 2013-03-29T15:30:49Z
FirstChildVoteTAG: 0
IndexTAG: 234
TitleTAG: Stat2.2X Eligibility
Hi,
I signed up late for Stat2.1X apparently I signed up just before the finals and didn't clear the final exam and others as well. So, will I still be eligible for Stat2.2X ?
Thanks
UserIdTAG: 1487361
UserNameTAG: AmanAkash
CreateTimeTAG: 2013-03-29T11:26:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Yes
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-29T11:40:50Z
FirstChildVoteTAG: 0
FirstChildTAG: yhhh, there seems to be no relation. Do Double check , you can see edX FAQs probably.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T11:41:01Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, Stat2.1x is not enforced as a prerequisite for the following courses.
You still need to know its concepts if you hope to accomplish something in 2.2x though. So forget about the grade and/or certificate and get working ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-29T12:33:29Z
FirstChildVoteTAG: 2
SecondChildTAG: This course was no joke. Although I passed, I feel that I will need to review all material over the next two weeks before the next class begins; so that i won't start behind.
SecondChildUserIdTAG: 4612
SecondChildUserNameTAG: Susnaj
SecondChildCreateTimeTAG: 2013-03-29T15:12:02Z
SecondChildVoteTAG: 0
IndexTAG: 235
TitleTAG: To the instructor: Final exam question 4B. Come on! The correlation may not be equal to 1 in this case...
Let say that the maximum score of the exam is 100/100.
If you give everybody 15 more points, what happen to those who had an old final score of 85/100 or more??
Their score would be... same 100/100.
So if you plot old final scores x new final scores, yes it is a straight line sloping up .. until old scores of 85 or more, then the line is flat.
So the correlation would be very close to one sure but not equal to 1 !!
So the correct answer to this final exam question is ... 'impossible to determine based on the info/rmation given. ' Why? because we dont know if or how many people of this 'large class' got an old score of 85/100 or more...
I know the Stat2.1x is over now, but I would appreciate to have your opinion on that.
Thx
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T11:24:50Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 8
FirstChildTAG: >So the correct answer to this final exam question is ... 'impossible to determine based on the info/rmation given. ' Why? because we dont know if or how many people of this 'large class' got an old score of 85/100 or more...
So, you learnt nothing from the course? Read the question again. Seriously, read it again and think about the info given. And there is no mention of "large" for this question.
>So the correct answer to this final exam question is
1
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-29T11:42:23Z
FirstChildVoteTAG: 1
SecondChildTAG: I had the same thought, answering this question. But keep two things in mind:
- No reason the maximum score must be capped at 100, it may well go above.
- As we learned, the number of students out at or above StDev 3.5 in a normal distribution is tiny, just 0.02% of the population.
Given this, and your own good judgement about what the question is trying to measure, you should come to the correct answer, correlation = 1.
SecondChildUserIdTAG: 1244133
SecondChildUserNameTAG: SQL-man
SecondChildCreateTimeTAG: 2013-03-29T12:28:46Z
SecondChildVoteTAG: 0
SecondChildTAG: You don't disprove anonymous with your comments.
And the comment about his understanding gained from this course is, I believe, at least irrelevant. You are not in a position, nor you have the "info required" to reach such conclusions.
SecondChildUserIdTAG: 902212
SecondChildUserNameTAG: trigeor
SecondChildCreateTimeTAG: 2013-03-29T12:44:48Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with anonymous above. Correlation coef equal to 1 means something very specific, which cannot be deduced from the data given. You need the max score of the old test to be able to Calculate the asked corrcoef.
As for the max scores being above 100 idea...in another planet maybe...
The scores can saturate, given any size of class, with increasing probability, as the population grows.
My opinion is that the correct answer in 2 questions of the final is at least questionable given the choices provided.
FirstChildUserIdTAG: 902212
FirstChildUserNameTAG: trigeor
FirstChildCreateTimeTAG: 2013-03-29T12:40:09Z
FirstChildVoteTAG: 2
FirstChildTAG: I had a similar problem with 4A:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/51553daafdcb722a06000048
Once I answered 4A I understood what was the logic behind the problem and I answered 4B and 4C accordingly to that logic.
However, I'd like to know from prof. Ani what the logic behind problem 4 is like. :-D
FirstChildUserIdTAG: 1263500
FirstChildUserNameTAG: DaveFromItaly
FirstChildCreateTimeTAG: 2013-03-29T13:25:45Z
FirstChildVoteTAG: 0
FirstChildTAG: SusanAust answer was useless.
Agree with anonymous. One cannot be sure that the correlation is exactly equal to one .
Number of people having a previous score above 85 points or even people having less than 15 points would not fit the equation.
I personally made the approximation and choose the r = 1 answer. Lucky.
However, we have been taught that if there is any spread from the line .....?
I hope we can have the opinion from Professor Ani.
FirstChildUserIdTAG: 1416028
FirstChildUserNameTAG: Trocadero
FirstChildCreateTimeTAG: 2013-03-29T14:09:06Z
FirstChildVoteTAG: 1
FirstChildTAG: It seemed to me to be a question about a simple transformation. The context (ie exam scores) was irrelevant. I see no reason to assume there should be a cap on scores (at 100 or elsewhere).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-29T14:11:35Z
FirstChildVoteTAG: 1
SecondChildTAG: indeed. lesson 6-2, at 12.31 - adding a constant to one of the lists just slides the scatter diagram, r stays the same.
the wording is "each student gets +15 points", that would include those who had max points. why assume a cap? (and frankly a cap would actually be unfair to those who scored really high)
the top 20% still remain the top 20%. you don't need any approximation.
SecondChildUserIdTAG: 1230458
SecondChildUserNameTAG: Tyrea
SecondChildCreateTimeTAG: 2013-03-29T14:30:50Z
SecondChildVoteTAG: 0
SecondChildTAG: We could assume a cap just because the possibility is not explicitly negated. Anyway, that's probably just me overthinking the problem. :)
SecondChildUserIdTAG: 1263500
SecondChildUserNameTAG: DaveFromItaly
SecondChildCreateTimeTAG: 2013-03-29T14:54:39Z
SecondChildVoteTAG: 0
FirstChildTAG: I had to keep this simple for myself.
1) I remembered Prof A's calm reasoning voice "Take what you are given." So ... are we given what the top score in terms of points is? No, so I threw that kind of thinking out first. We are given that the top 20% get As.
2) What else are we given? That 15 points in the new scoring scheme is given to everyone. This made me remember Lec. 4.4 about adding a constant to a list, ie whatever line there is will be shifted by +15 points.
3) Then I remembered Prof A's advice to draw things out. So I kept it simple. I created a basic list of 5 scores before and after the 15+ point addition. It became clear to me right away.
"Let say that the maximum score of the exam is 100/100. If you give everybody 15 more points, what happen to those who had an old final score of 85/100 or more??"
I, too, started down that road, but because of my above "keep it simple" reminder (plus, "make no assumptions" which I keep having to remind myself about ...), you MUST add 15 points to all scores. So, in your sentence here, you MUST add 15 to what you were assuming is the top score. So 100/100 becomes 115/115 and 85/100 becomes 100/115. Hopefully this will make you consider that whatever the top score limit is (100, 115, 999.6) quickly becomes unimportant.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-29T14:35:56Z
FirstChildVoteTAG: 0
FirstChildTAG: I was always told to ignore anonymous communications.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-29T17:09:10Z
FirstChildVoteTAG: 0
SecondChildTAG: I assume most of the messages on the forum are anonymous, since most people do not use their full names or even parts of their names.
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-29T17:54:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Come on indeed!
Mean of 50, SD of 10. Work it out! The course gave you the knowledge. Use it.
Probability of the original being $\ge85$ is 0.0002. So if this university class had $5000$ students, $1$ of them might have had more than 85.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-29T21:13:44Z
FirstChildVoteTAG: 0
IndexTAG: 236
TitleTAG: Stat2.2x
Will Stat2.2x be offered through edX? It doesn't appear as one of the classes yet.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T11:13:59Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: 12 April.
FirstChildUserIdTAG: 584390
FirstChildUserNameTAG: pluribus
FirstChildCreateTimeTAG: 2013-03-29T11:18:13Z
FirstChildVoteTAG: 0
FirstChildTAG: How/when can we enrol on Stat 2.2?
Also,I am away soon until 13th April, can I enrol then. one day after course start date?
FirstChildUserIdTAG: 169991
FirstChildUserNameTAG: birkenhead
FirstChildCreateTimeTAG: 2013-03-29T11:56:03Z
FirstChildVoteTAG: 0
SecondChildTAG: You can enroll at any time after the course's up on EdX. Even just before the final exam, as some apparently did here in 2.1x :D
So, yeah, one day isn't a problem at all.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-29T12:35:13Z
SecondChildVoteTAG: 0
FirstChildTAG: If I'm not mistaken it's going to be released in April 12.
FirstChildUserIdTAG: 1274748
FirstChildUserNameTAG: kusumawati
FirstChildCreateTimeTAG: 2013-03-29T14:01:28Z
FirstChildVoteTAG: 0
IndexTAG: 237
TitleTAG: A big thank you!
i am saying Thanks to Prof.A Adhikari and staff of EDX.
You guys are really wonderful for this groundbreaking background for me in statistics.
Many thanks.
UserIdTAG: 1173873
UserNameTAG: rasheedsalaudeen
CreateTimeTAG: 2013-03-29T11:10:44Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 238
TitleTAG: certificate
now this course is done............so when we got the certificate??
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T11:09:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hmmm, maybe you should read edX's faqs. Or one of the many other posts about this.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-29T11:10:50Z
FirstChildVoteTAG: 1
FirstChildTAG: This is from the EdX FAQs:
EdX certificates are delivered online through edx.org. So be sure to check your email in the weeks following the final grading – you will be able to download and print your certificate.
FirstChildUserIdTAG: 1289355
FirstChildUserNameTAG: DaRitz
FirstChildCreateTimeTAG: 2013-03-29T11:24:45Z
FirstChildVoteTAG: 6
IndexTAG: 239
TitleTAG: Thank you Prof A. from South America.
:))) !!
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-03-29T11:08:06Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: thank u professors, for starting such a good course which is easily understood by everyone... thank you very much..
waiting for the stat2.2x
FirstChildUserIdTAG: 1311995
FirstChildUserNameTAG: podilashree
FirstChildCreateTimeTAG: 2013-03-29T12:01:17Z
FirstChildVoteTAG: 2
IndexTAG: 240
TitleTAG: Thank you and Humbled by this opportunity
Dearest Prof. A and Philip Stark, It has been such a pleasure to go through this course. The teaching styles of both of you are wow. I loved every bit of it.
Thanks to staff as well for putting it all together and keeping it going, with such a large number of students it could have been anything but not easy.
My thanks and salutations again, Looking forward to Stat 2.2x.
Regards
Nasir
UserIdTAG: 1216795
UserNameTAG: NasirK
CreateTimeTAG: 2013-03-29T10:46:19Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Pray, what is the teaching style of Prof. Stark?
FirstChildUserIdTAG: 346428
FirstChildUserNameTAG: aranic
FirstChildCreateTimeTAG: 2013-03-29T13:08:40Z
FirstChildVoteTAG: 0
SecondChildTAG: Look at the video lectures linked in the online textbook and make your own judgement.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-29T14:20:39Z
SecondChildVoteTAG: 0
FirstChildTAG: agreed!
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T17:18:05Z
FirstChildVoteTAG: 0
IndexTAG: 241
TitleTAG: Lecture notes
All data from slides plus problem sets in one file: https://docs.google.com/folder/d/0BxxdPC5rUpI-QzZGeExXNWgxNzg/edit?pli=1
Also I can archive and load all videos on Google Drive and make them available for a week or two to make students life a little bit easier. If there are students who haven't downloaded the videos yet, let me know.
Thank you very much Professor Adhikari, this is an amazing course!
UserIdTAG: 1296275
UserNameTAG: YaroslavD
CreateTimeTAG: 2013-03-29T10:39:57Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Thanks a lot, that's great !
FirstChildUserIdTAG: 1069830
FirstChildUserNameTAG: TheodoraCh
FirstChildCreateTimeTAG: 2013-03-29T10:42:29Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks Yaroslav, I don´t downloaded videos yet.
Maite
FirstChildUserIdTAG: 1002821
FirstChildUserNameTAG: Urimare
FirstChildCreateTimeTAG: 2013-03-29T13:20:24Z
FirstChildVoteTAG: 1
SecondChildTAG: Hi, Urimare! Here you go: https://docs.google.com/folder/d/0BxxdPC5rUpI-eWZpUmRTSTVQVVE/edit?usp=sharing
SecondChildUserIdTAG: 1296275
SecondChildUserNameTAG: YaroslavD
SecondChildCreateTimeTAG: 2013-03-29T13:54:34Z
SecondChildVoteTAG: 0
FirstChildTAG: I cannot download the slides and problem files (docx and pdf) I get an error each time i try :-(
Does anybody else have the same problem or may be i'm doing something wrong ?
Thanks
FirstChildUserIdTAG: 1069830
FirstChildUserNameTAG: TheodoraCh
FirstChildCreateTimeTAG: 2013-03-29T20:03:22Z
FirstChildVoteTAG: 0
SecondChildTAG: strange, sorry about that,
please, try this link: https://dl.dropbox.com/u/55246206/2.1x%20Descriptive%20Statistics.zip
SecondChildUserIdTAG: 1296275
SecondChildUserNameTAG: YaroslavD
SecondChildCreateTimeTAG: 2013-03-30T07:00:43Z
SecondChildVoteTAG: 0
SecondChildTAG: It was my fault, sorry YaloslavD. Your link works perfectly.
Thanks again, it was very nice of you as you saved all of us much time :-)
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-30T12:12:07Z
SecondChildVoteTAG: 0
SecondChildTAG: :) my pleasure, I'm happy to see that you finally manage to download it.
SecondChildUserIdTAG: 1296275
SecondChildUserNameTAG: YaroslavD
SecondChildCreateTimeTAG: 2013-03-30T13:11:45Z
SecondChildVoteTAG: 0
IndexTAG: 242
TitleTAG: Best book for statistics??
Which is the best book for statistics?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-29T10:37:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 243
TitleTAG: Agradecimientos
Quisiera agradecer a todo el equipo que ha hecho posible este maravilloso curso.
Gracias.
UserIdTAG: 89776
UserNameTAG: PacoBenarque
CreateTimeTAG: 2013-03-29T10:30:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 244
TitleTAG: request - pls!
I missed the deadline! I thought the deadline will be 5.00 **P.M.**
May a have several ours for finishing test?
I was upset. I am sorry...
UserIdTAG: 1107133
UserNameTAG: Shumanova
CreateTimeTAG: 2013-03-29T10:26:51Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I had the same challenge!!! Wow an opportunity to finish it will be appreciated. But unfortunately, the answers have been released.
FirstChildUserIdTAG: 1114838
FirstChildUserNameTAG: abass01
FirstChildCreateTimeTAG: 2013-03-29T10:46:59Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes, I realized that after my posting...howsoever - another questions maybe..By the way if I have more than 35% total is that means I will get a certificate?
SecondChildUserIdTAG: 1107133
SecondChildUserNameTAG: Shumanova
SecondChildCreateTimeTAG: 2013-03-29T11:23:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Yep.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-29T12:35:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Wow! It will be great!I will be motivated for next levels maybe!Thanks a lot, abass01!!!
SecondChildUserIdTAG: 1107133
SecondChildUserNameTAG: Shumanova
SecondChildCreateTimeTAG: 2013-03-29T13:26:02Z
SecondChildVoteTAG: 0
SecondChildTAG: pardon - thanks to Klionheart too! :)
SecondChildUserIdTAG: 1107133
SecondChildUserNameTAG: Shumanova
SecondChildCreateTimeTAG: 2013-03-29T13:27:16Z
SecondChildVoteTAG: 0
FirstChildTAG: me too missed some questions, thinking its 5 pm...
FirstChildUserIdTAG: 1311995
FirstChildUserNameTAG: podilashree
FirstChildCreateTimeTAG: 2013-03-29T12:02:52Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too :( I only realised when I punched in my answer as well. Oh well it was right so at least I have a moral victory. Still I am pretty pleased I got this far. Passed with about 60%
FirstChildUserIdTAG: 1265802
FirstChildUserNameTAG: GMORRIS010
FirstChildCreateTimeTAG: 2013-03-29T12:45:36Z
FirstChildVoteTAG: 0
IndexTAG: 245
TitleTAG: Online education rocks!
It has been a very intresting course, concept were explained in a very easy way and the whole organization has been outstanding! Thanks, thanks a lot to all the staff...Online education rocks!
UserIdTAG: 1325246
UserNameTAG: Marco1979
CreateTimeTAG: 2013-03-29T10:18:43Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 246
TitleTAG: Thank You :)
Dear Professor Ani and Professor Stark,
It was really a great pleasure to participate in Stat2.1x ! During my 8-years adventure with science I've attended few courses in statistics, in different countries, however it was always presented as a bunch of equations and excel-based analysis of the data.
I often use statistics to interpret the results and to draw conclusions from experiments. Before, I didn't fully understand statistics which I've applied to the data. And here, right now, finally I feel the data !!! And that is great :)
I would like to thank you very much for this course, for great Java applets (especially the normal curve applet!) and all your kindness toward students. I cannot wait to continue this adventure in Stat2.2x !
Best regards.
UserIdTAG: 833055
UserNameTAG: AgnieszkaNiedzwiecka
CreateTimeTAG: 2013-03-29T10:11:04Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I so so so agree with "feel the data" part. This course was great because of the instructors
FirstChildUserIdTAG: 1216795
FirstChildUserNameTAG: NasirK
FirstChildCreateTimeTAG: 2013-03-29T10:57:48Z
FirstChildVoteTAG: 2
FirstChildTAG: Absolutely and utterly agree :)
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-03-30T02:22:51Z
FirstChildVoteTAG: 0
IndexTAG: 247
TitleTAG: my humble thanks
i would like to say thanks for such a marvelous and knowledgeable course , i got allot and i will remember it
UserIdTAG: 172435
UserNameTAG: husnainabbass
CreateTimeTAG: 2013-03-29T09:58:34Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 248
TitleTAG: Regression: error in the differences of the dependent variable
Hi,
I know the course is closing, but let's see if I manage to get an answer to this question before that :)
I estimate the values of Y based on X as (Y_est -Y_mean)/SD_Y = r*(X -X_mean)/SD_X : the rms error is e=sqrt(1-r^2)*SD_Y. And if the joint distribution is bivariate normal, i.e., the scatter plot is football-shaped, I know also that, for a given X, 68% of Y values fall into [Y_est - e,Y_est + e].
Now, if Y is the result of a measurement, e won't be smaller than the precision of the measurement instrument. However, if I consider two different values of X, X_1 and X_2, and I compute the respective Y_est_1 and Y_est_2, what is the error estimate for Y_est_2-Y_est_1? I don't think it can be e, because, as X_2-X_1 goes to 0, I expect the "real" Y_2-Y_1 (that given by Tyche's line, so to speak) to go to zero too. For sure, the estimated Y__est_2-Y_est_1 goes to 0 as X_2-X_1 does.
So the error between the estimated difference in the dependent variable and the real difference in the dependent variable should go to 0, no matter what is e, or the precision of my measurement error. Is this correct? What is an estimate for this error in the difference? Would it be (X_2-X_1)*e?
UserIdTAG: 407687
UserNameTAG: AndreaPi
CreateTimeTAG: 2013-03-29T09:47:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 249
TitleTAG: Big Thanks
Big Thanks to the staff, Prof A and others and all the students, especially those who asked the questions I had in the forums, saving me the trouble of typing them in and waiting for explanations!
Waiting for Stat 2.2X!
PS - why isn't Stat 2.2X on the "Find Courses" page yet? Will we all be automatically enrolled for Stat 2.2X?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-29T08:53:42Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 250
TitleTAG: Missed deadline for the final exam
I missed the deadline for the final exam. I was without internet access and I had thought the deadline was 23.30 as with the assignments. I logged on this morning at about 8.00 GMT only to realise that I had missed the deadline by 3 hours. I feel very bad about it but what can I do.
However, I want to thank Prof Ani for the course. I had known some statistics prior to this course but I have learnt a great deal in this course. I have also reinforced the knowledge I had in some areas. Thank you once more and I look forward to Stat 2.2x.
PS: I doubt if anything can be done about the deadline I missed!
UserIdTAG: 673376
UserNameTAG: Ojaiks
CreateTimeTAG: 2013-03-29T08:52:01Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 7
FirstChildTAG: Well, I started the course 7 problem sets too late, so you aren't alone....You do get the cert if you have scored >35% without the final exam...All the Best
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-29T08:55:31Z
FirstChildVoteTAG: 0
FirstChildTAG: The same happened to me
I'm really down for that. It's frustrating after a period of commitment missing the exam for just some hours. I was excelling until now...
wouldn't it be possible to extend the deadline for some hours more?
When will stat 2.1x be offered again, in order to take the final?
Thanks
FirstChildUserIdTAG: 104367
FirstChildUserNameTAG: the_eraser
FirstChildCreateTimeTAG: 2013-03-29T09:02:34Z
FirstChildVoteTAG: 0
FirstChildTAG: There are probably many more with this problem and not everybody will post. So I hope the staff will answer by taking into account that many might be concerned.
As you say, it's frustrating after having done all those exercises and having kept the schedule just until now...
But it was still a great experience to do this course, so thanks a lot!
FirstChildUserIdTAG: 1269427
FirstChildUserNameTAG: jessicadehler
FirstChildCreateTimeTAG: 2013-03-29T10:32:46Z
FirstChildVoteTAG: 0
FirstChildTAG: Same with me. Me also missed the dead lines of final exam, because we done our assignments with a same time but the final exam ending time was not same to assignments ending time. So, it is my request to department to do some thing if possible.
Thanks in advance
Regards,
Shafaqat Mehmood
FirstChildUserIdTAG: 1236951
FirstChildUserNameTAG: shafaqatphd
FirstChildCreateTimeTAG: 2013-03-29T12:00:37Z
FirstChildVoteTAG: 0
FirstChildTAG: Same for me. I thought the Deadline was 23:30... Now, I'm trying to do the exam but it doesn't work... At least, I get more than 60 per cent (without the final exam) I hope to get the certificate...
Thank you very much to everybody and specially to the professors. See you in the next course.
FirstChildUserIdTAG: 1022822
FirstChildUserNameTAG: JorgeValenciaUniversity
FirstChildCreateTimeTAG: 2013-03-29T12:27:08Z
FirstChildVoteTAG: 0
FirstChildTAG: There was a 3 day window, I was stuck because I was scheduled for surgery on the second day, so worried that the exam would be delayed like the previous week stuff, but it wasn't and I got the exam finished the first day - I might have got a few more ticks if I had the extra 2 days free to work out the answers but passed anyway.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-29T17:32:51Z
FirstChildVoteTAG: 0
FirstChildTAG: Sorry, but seriously? If you cannot follow the rules, and read the course instructions, you have no one to blame but yourself.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-29T21:20:38Z
FirstChildVoteTAG: 0
IndexTAG: 251
TitleTAG: Feedback on stat2.1X
Namastey Everyone,
I am Manish Balodi from India.I have successfully cleared the stat2.1X with 95% marks,and eagerly looking forward to stat2.2X.I would like to express sincere thanks to Professor Ani Adhikari for her wonderful explanation of descriptive stats.I am feeling more confident and enthusiastic now,and would definitely apply the concepts learned in stat2.1X to reason questions pertaining to description and interpretation of real world data from various sources.
Thanks to all !!!
UserIdTAG: 1050175
UserNameTAG: Mdbi
CreateTimeTAG: 2013-03-29T08:47:21Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 252
TitleTAG: Will you keep this site alive?
Hi, many thanks to everybody for this course, I'm looking forward to the next part. I'd just like to know if Stat 2.1 will remain online for a while. I want to go back without any deadline, analyse some exercises once more and be really perfectly prepared for 2.2. My aim was not only to get 'passed' and then forget everything I've learned. My best regards.
UserIdTAG: 1341242
UserNameTAG: alesbadura
CreateTimeTAG: 2013-03-29T08:44:15Z
VoteTAG: 14
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes, I'm hoping too that the site will be kept alive...need 2-3 days to consult the text a few times and go through the rather extensive exercise set by Prof A before the exam finale
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-29T08:47:15Z
FirstChildVoteTAG: 1
IndexTAG: 253
TitleTAG: Certificate Issue
I have successfully cleared the stat2.1X with 95% marks.I would like to know,when and how the certificates will be issued,and is there any fee which will be charged to get the certificate.
UserIdTAG: 1050175
UserNameTAG: Mdbi
CreateTimeTAG: 2013-03-29T08:41:11Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No fees. You will see a certificate download link on your Dashboard when the certificates are ready. Our professor says it may be ready by April 1st.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-29T09:30:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Can your respective institution send us hard copy certificate with original stamp and signature? (On demand of concern person.)
SecondChildUserIdTAG: 1236951
SecondChildUserNameTAG: shafaqatphd
SecondChildCreateTimeTAG: 2013-03-29T12:48:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Arti, how about a frieze on Prof. A?
SecondChildUserIdTAG: 346428
SecondChildUserNameTAG: aranic
SecondChildCreateTimeTAG: 2013-03-29T13:14:41Z
SecondChildVoteTAG: 0
IndexTAG: 254
TitleTAG: Special Thanks
thanks to Prof.A and All staffs being so kind and extremely patient.
it was my first course in EDX but very effective i learned many thing beside Statistics. once again i would like to thank you all.
Ahmad Zia
UserIdTAG: 1078818
UserNameTAG: Jamili
CreateTimeTAG: 2013-03-29T08:34:07Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: many thanks for this course.
Regards,
Pietro
FirstChildUserIdTAG: 7870
FirstChildUserNameTAG: ppizzine
FirstChildCreateTimeTAG: 2013-03-29T08:43:49Z
FirstChildVoteTAG: 0
FirstChildTAG: Completely agree. A course to be highly recommended !
FirstChildUserIdTAG: 1137018
FirstChildUserNameTAG: Guseri
FirstChildCreateTimeTAG: 2013-03-29T09:50:11Z
FirstChildVoteTAG: 1
IndexTAG: 255
TitleTAG: A big thanks
Wonderful course!
$y = \alpha x + \phi, (r = 1)$
Looking forward to Τύχη.
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UserNameTAG: atopos
CreateTimeTAG: 2013-03-29T08:33:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Indeed! Hope to see you in the next class!
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-29T09:30:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes let's see what we will learn about Tyche-τύχη :-)
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-29T10:07:26Z
SecondChildVoteTAG: 0
IndexTAG: 256
TitleTAG: Question to the Professor Question 6C final exam clarification
If we do not assume mean length as 2.8 (as per the previous question)and do calculations we get mu = 2.82
2.75 in standard units is (2.75-3.1)/0.25=-1.4.
-1.4 x r(0.8)=-1.12
So mu of strip =-1.12 x 0.25 + 3.1= 2.82
So in standard units is (2.75-2.82)/0.15=-0.46667 and AUC for<-0.4667 is 32.02 The grader marks this as wrong. What is wrong in using this method.
Professor, can you please clarify this as the grader marks this wrong.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-29T08:32:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The average of the vertical strip that are width 1.5 - is as calculated in previous question 2.8cm. You are looking for the percentage that are less than 2.75cm. ie you are looking for the percentage that are .05 below the mean.
First off transfer to standard units - which you have done but I think you have used the wrong mean and SD - but you must use the mean of the vertical strip (ie all the petals with width 1.5) - this mean is the answer to previous question 2.8cm from the regression estimate. You also need to know the SD of the vertical strip - this is the RMS of residual error [sqrt(1-r^2)SDofLength]. you now have the desired variation from the mean of the vertical strip.
you then plug this deviation below the mean (as the top bound) into the normal curve calculator (with -5 as the bottom) and read off what percentage is below
hope that is right and my explanation helps.
FirstChildUserIdTAG: 1383747
FirstChildUserNameTAG: imatfaal
FirstChildCreateTimeTAG: 2013-03-29T09:36:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually the mean as calculated is for the 1.5 cm strip isn't it ? The rms of error has been used for determining how many SD's away too.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-29T12:01:42Z
SecondChildVoteTAG: 0
FirstChildTAG: You seem to have calculated how far 2.75 is from the mean for the whole "petal lengths" dataset, instead of just the dataset for "petal lengths for petals 1.5 cm wide" as was asked.
The rest of the procedure is correct(although you kept using the original SD instead of the RMS in some places), but the wrong z ruins the whole Problem :(
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-29T10:09:02Z
FirstChildVoteTAG: 0
FirstChildTAG: You did main mistake at the step: ' 2.75 in standard units is (2.75-3.1)/0.25=-1.4 ' which is a calculation for z for all the petals of the flower less than 2.75 cm and NOT JUST those that are 1.5 cm wide as asked. For these concentrate & calculate for the verticle strip ( on the scatterplot ) of petals measuring 1.5 cm wide . For this special case mean is the regression estimate for the petals 1.5 cm wide ( not a matter of assumption but caculations only and turns out to be 2.8 as calculated in 6b ), SD is rms error of regression estimate = [sqrt( 1 - r^2 )]* SD of petal length = sqrt(1 – 0.8^2)*0.25 = 0.15 cm . Therefore So z = (2.75 – 2.8)/0.15 = -0.333 . So finally the area under the normal curve to the left of -0.333 is 36.96%.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T12:24:58Z
FirstChildVoteTAG: 0
IndexTAG: 257
TitleTAG: Many thanks
This course was so much fun! I really loved it.
Thank you very much Professor A and thanks to all staff that made this all happening!
The fact that you can study such an interesting topic just from home (or anywhere else) at a time that is most suitable for you is fantastic.
I even watched some lectures and did some homework in hospital right before I had my ear drum operation!
I was more nervous to get my homework finished on time than I was nervous for the operation :-)
And I really love the captions! When my hearing aid broke down I was still able to (silently) watch the video lectures thanks to the captions!
Being hard of hearing I even more appreciate all the MOOC as this makes it much easier for me to learn new things.
Keep up the good work!
Kind Regards,
Sandy Van den Borne
Belgium
UserIdTAG: 1151221
UserNameTAG: svandenborne
CreateTimeTAG: 2013-03-29T08:00:47Z
VoteTAG: 2
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 0
IndexTAG: 258
TitleTAG: Thank You!
Thank you Professor A! I have finally learned stats properly!
UserIdTAG: 216107
UserNameTAG: Tanushree
CreateTimeTAG: 2013-03-29T07:45:54Z
VoteTAG: 1
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 0
IndexTAG: 259
TitleTAG: Thank you, professor!
I just want to thank Prof Adhikari for the class. I learned a great deal of things and I realize that is not easy to teach a course like this.
UserIdTAG: 1221034
UserNameTAG: GermanNegron
CreateTimeTAG: 2013-03-29T07:15:26Z
VoteTAG: 7
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 0
IndexTAG: 260
TitleTAG: Final: Problem 4
I knew the correct answer to question 4A was the second one but I had one little doubt that could have a subtle impact to the answers for questions 4B and 4C.
The Problem 4 statement doesn't talk about an upper limit in score value, but scores are usually capped at 100 points.
If we consider 100 as the upper boundary in the final exam we have the "natural" scores ranging from 0 to 100 (50 +-5SDs). Adding 15 to each vote makes that range slightly different: 15-100, with 65 +-5SDs.
Therefore, if we assume that the exam score is capped at 100, we lose 1.5SDs worth of results that could be sort of "downgraded" to 100. I know this has a very small chance to happen (the Normal Curve applet says it's just 0.02% of the results) but since we did not know how many students were in the class it could just be possible. Improbable, but possible.
Furthermore: since there's a 0.02% chance that the results could be changed at the top end and since we assume that scores are a quantitative discrete variable, isn't there also a chance that someone at the lower end of the "20% best" would gain (or lose) an A by some kind of "tie" (or tie-breaker) effect?
By the way: I don't care about my actual answer to problem 4, I had a blast studying with prof. Ani and I'm quite satisfied with what I gained from this whole experience.
Thanks to everyone for the course, I'll hopefully see you again in Stat2.2x! :)
UserIdTAG: 1263500
UserNameTAG: DaveFromItaly
CreateTimeTAG: 2013-03-29T07:07:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: As the answer says, adding 15 to everyone's mark doesn't change the ranking. The top 20% will still be the same top 20%.
If you were grading by mark (say, 85+ is an A), then you could well have a different group of students getting an "A" after the regrading.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-29T07:25:17Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks, that was my general reasoning as well for the answer to problem 4A.
Saying "top 20% of the students" should be the same as saying "top 20% of scores" since every student has one (and only one) score.
But if you consider the 20% as a score level, you have to associate it to a precise score (say 85), since scores are a discrete variable.
So, where am I failing?
SecondChildUserIdTAG: 1263500
SecondChildUserNameTAG: DaveFromItaly
SecondChildCreateTimeTAG: 2013-03-29T08:04:37Z
SecondChildVoteTAG: 0
SecondChildTAG: In this case there is no set score. The question says that the top 20% get an A.
Adding 15, or any number, to *every* final score just raises everyone's mark. The top 20% will still be the same top 20% afterwards.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-29T08:15:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Susan, sorry, please re-read my initial post. All my reasoning is based on the assumption there is an upper boundary to scores equal to 100. I know the answer to problem 4A was "No", I'm just exploring different conditions. :)
SecondChildUserIdTAG: 1263500
SecondChildUserNameTAG: DaveFromItaly
SecondChildCreateTimeTAG: 2013-03-29T08:30:42Z
SecondChildVoteTAG: 0
SecondChildTAG: The final exam is “graded on a curve”, so your reasoning doesn't apply at all.
SecondChildUserIdTAG: 407687
SecondChildUserNameTAG: AndreaPi
SecondChildCreateTimeTAG: 2013-03-29T09:18:12Z
SecondChildVoteTAG: 0
SecondChildTAG: I see your problem Dave - and those answering by merely stating that the grades are assessed on a curve are correct but not giving a complete answer.
For those who say that as it is graded on a curve - or that adding 15 points cannot change anything - consider a scenario in which 21% of the students scored at least 85 points. Adding 15 points to these scores would end with 21% of the students having a maximum score of 100 points (assuming the points are capped as Dave mentions in his query - I am also European and don't know how US exams are structured). If 21% of the class have precisely the same score - ie are tied at 100 points how exactly do you determine the top 20%?
But!! and it is a big but; Can 21% of the class have such a high mark? You said you looked at the normal distribution Dave - but I would just use Chebychev. Chebychev applied mathematically to all distributions - it doesnt rely on likelihood. Thus 85 points is 35 from mean - ie 3.5 SD from mean. Chebychev would say that, at maximum, the number of students who can be 3.5SD away from mean would be 1/[(3.5)^2]. In this case that works out as around 8%. So there is no way that 21% can be in the range that your scenario would require to be a real problem. hope that is right and that I have helped
SecondChildUserIdTAG: 1383747
SecondChildUserNameTAG: imatfaal
SecondChildCreateTimeTAG: 2013-03-29T10:27:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Hey imatfaal, thanks for your answer! :)
I also thought about chebychev's inequality by the way; my doubt is not about the theorically maximum-graded students. If I look at the lower end of the "20% best" I could have the very same situation of some students that, thanks to the +15 points, reach the minimum possible score value.
This could mean that, given a large enough classroom, there's a small chance that the two groups are different. I calculated 0.02% with the normal curve by decreasing the SD max value from +5 to +3.5, but I'm not sure about the results.
What I'm looking for is some kind of formal demonstration of why this could (or could not) be the case. :)
SecondChildUserIdTAG: 1263500
SecondChildUserNameTAG: DaveFromItaly
SecondChildCreateTimeTAG: 2013-03-29T13:00:47Z
SecondChildVoteTAG: 0
SecondChildTAG: ' consider a scenario in which 21% of the students scored at least 85 points. ' This is not possible because it's a case of football shaped curve and therefore normal distribution. You can also see my detailed reply on this problem in separate post 15 min. back .
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-29T13:39:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Reasoning for correct answer should be based on the question itself and not the answer provided ( 'SusanAust :
As the answer says, adding 15 to everyone's mark doesn't change the ranking. The top 20% will still be the same top 20%.' ) . Here it's given that distribution is football shaped . Therefore **1. 80th percentile is at .842 Standard units = 50 + .842*10 = 58.42 marks ( as per normal curve applet provided ) & **2. the max data in the right upper tail is 2.28% . And to take into account DaveFromItaly's apprehension , even if all 2.28% scored 100% (just for argument sake), then even after adding extra 15 marks given by the instructor and '100% cap' , those achieving 100% can not be more than 20% . And therefore from this now we can conclude that ' adding 15 to everyone's mark doesn't change the ranking and that the top 20% will still be the same top 20%. It's also wrong to say: 'If you were grading by mark (say, 85+ is an A), then you could well have a different group of students getting an "A" after the regrading.' because it's cearly given: ' 4A : 2.0 POINTS
The final exam is “graded on a curve,” with the top 20% of the students on the final receiving an A grade on the exam. '
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T13:22:33Z
FirstChildVoteTAG: 0
SecondChildTAG: Uhm...so what you're saying is: the professor doesn't care if someone with the same result gets an A or another grade. Just 20% of the students (at max) gets an A.
This is semantically correct, but still doesn't sound right to me (ethically speaking ;-) ).
SecondChildUserIdTAG: 1263500
SecondChildUserNameTAG: DaveFromItaly
SecondChildCreateTimeTAG: 2013-03-29T13:30:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Lower bound of the scores the students getting A grade as resolved in original grading of finals is going to translate into corresponding lower bound after regrading . And since it's given that even after regrading we have distinct set of of 20% getting A grade , and the question concerns only if they are the same or different from the original ones , presumed crowding at 100% point if out of place.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-29T14:58:16Z
SecondChildVoteTAG: 0
FirstChildTAG: > It's also wrong to say: 'If you were grading by mark (say, 85+ is an A), then you could well have a different group of students getting an "A" after the regrading.
No it's not. If that was the scheme (which it wasn't) then you could have more over 85. She was giving an example of how the ranks could change, not saying that is what was happening.
You are adding a constant to everyone. Of course the top 20% remain the same top 20%. Especially as the question tells you that the probability of anyone initially having 85+ is miniscule (1 in 5000).
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-29T21:27:19Z
FirstChildVoteTAG: 0
FirstChildTAG: I believe the main confusion arises from equating "points" with "percents". They are not the same. There's nothing stopping the maximum possible points from being larger or smaller than 100 points as long as it doesn't violate other assumptions in the problem. In earlier examples you've seen SAT scores of several hundreds of points; the Stat 2.1X midterm had a max possible of 20 points; the final exam in the question being discussed might have had a max possible of 90 points, or 150, etc.
"... the instructor gives each student 15 more points on the final" means exactly that. New score = old score + 15 points. There is no restriction; and you can't add points to any other unit of measurement.
If you want to convert to percents you have to also convert the denominator (the max possible) by adding 15 to it. But Ex 4 isn't about percents. It's about points.
If the scores had been in percents to start with, adding 15 percent to all of them would indeed imply that some people might end up with more than 100 percent; there's nothing stopping that either. At our local schools it's called "extra credit." But that's not the situation here.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-31T19:42:42Z
FirstChildVoteTAG: 0
SecondChildTAG: Professor, you have my gratitude. Well, you already had it; this is just icing on the cake. :-)
Take care and see you for Stat2.2x!
SecondChildUserIdTAG: 1263500
SecondChildUserNameTAG: DaveFromItaly
SecondChildCreateTimeTAG: 2013-04-02T21:18:41Z
SecondChildVoteTAG: 0
IndexTAG: 261
TitleTAG: Unable to know the result
I am unable to find my result ! How can I know whether I passed or not ? What do those shades of maroon, red and grey signify ? Please help me out
UserIdTAG: 1148355
UserNameTAG: Sunnye01
CreateTimeTAG: 2013-03-29T07:00:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hold your cursor over the bars, and you will see what they signify.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-29T07:07:57Z
FirstChildVoteTAG: 1
SecondChildTAG: You did do a course in Descriptive Statistics, you know!
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-03-29T08:56:58Z
SecondChildVoteTAG: 0
FirstChildTAG: You did do a course in Descriptive Statistics, you know!
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-29T08:57:17Z
FirstChildVoteTAG: 2
SecondChildTAG: hurrrah!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-29T11:43:52Z
SecondChildVoteTAG: 0
IndexTAG: 262
TitleTAG: For stat 2.2 please more examples
I want to thank all the staff. it was a wonderful course.
somethings to add:
it will be useful for the next time to use examples that keeps us interested in other areas as well. like statistics and graphs in variety of themes that not only teach us to analyze the data but also keeps us informed about interesting things in current studies in areas like Biology, Medicine, Science, Art, social behavior, etc.
Also please make something with the format of deadlines. that GMT doesn't work well when you are 5 hours behind.
yes. i know that we have to adjust our schedule and be responsible. but i have to say that i´m in another 2 courses in EDX and they have deadlines with an hour of difference. and it´s hard to make some space at 2am in the morning. ( i miss half of the questions of the Final because of that, i got confused even with the clocks on desktop adjusted to -1 -5 -3, but i tend to accomplish more those deadlines who are similar to my time zone, maybe it´s psychological i don´t know. but it will be nice to see if there is a relation between time zone and fulfillment of problem set)
An immense Thanks to Professor Ani Adhikari and to the people who share the knowledge.
i almost withdraw at the beginning because i though mathematics stuff it will be hard but Prof A it´s an amazing teacher :D
:)
PD: forgive the english please.
UserIdTAG: 933119
UserNameTAG: wsaw
CreateTimeTAG: 2013-03-29T06:36:21Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: *somethings to add: it will be useful or he next time to use examples that keeps us interested in other areas as well. like statistics and graphs in variety of themes that not only teach us to analyze the data but also keeps us informed about interested things on current studies in areas like Biology, Medicine, Science, Art, social behavior, etc.*
I agree. One thing I would really like to see in the future would be a large group of examples aside from the psets that we can work on ourselves if we've completed the homework. I really enjoyed the course but one of the things I found was that I would complete each week's work over the course of two or three days and then three or four days later, when I came back to the next set of lectures, I felt a little lost for the first part of the next lecture set as I had to recall everything we had previously gone over.
I'm one of those people who if they don't use it they lose it. I would have really enjoyed a bunch of statistical data samplings relative to what I was learning to tinker with in those "gaps" between lectures. It wouldn't need to be graded but it would give me something to work with if, for example, I wanted to merge what I'm learning with real world practical applications.
Simply put, if I could just have access to large numbers of datasets I could use them to calculate averages, SD's, and regressions. I could play with those datasets in Excel and set up my own Excel "laboratory". For me, I think it would have provided several more "A-ha!" moments and I'll take as many as them as I can get!
All in all, though, I really liked the course and am looking forward to the sequels! :-D
FirstChildUserIdTAG: 87103
FirstChildUserNameTAG: fjbasile
FirstChildCreateTimeTAG: 2013-03-29T07:41:14Z
FirstChildVoteTAG: 1
FirstChildTAG: I agree about the call for more examples(I'm all about examples in my learning).
But...
> Also please make something with the format of deadlines. that GMT doesn't work well when you are 5 hours behind. [...]
This is incredibly self-centered.
The professors have to set the deadlines' timezone with the whole world in mind, not just you.
GMT is the central, "average" timezone, and as we *should* have learned in this course, this means GMT it's the best "guess" for the students' timezone.
Think what would happen if we used CDT, as you seem to suggest. *You* would be comfortable at +0 local time, but someone in Australia would have to deal with a -12 shift!(at best). And if we used WST instead, because the australian requests it, the situation would be reversed(+12 for you, +0 for the australian).
Meanwhile, using GMT, you'd get +5 and the australian a -8. Looks like a compromise for everyone involved, doesn't it? And life is all about compromises.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-29T10:01:40Z
FirstChildVoteTAG: 6
SecondChildTAG: It is what it is. I'm 7 hours behind so I understand the time issue, but the fact that the course is online and can be accessed 24 hours a day is what makes it possible for me to take it at all.
If the exams & scores are important to you, you'll make sure you're organized enough to hit the deadlines, if it's just the learning that's important, then deadlines don't matter. I'm just really grateful for the opportunity to learn :)
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-03-30T02:51:04Z
SecondChildVoteTAG: 0
FirstChildTAG: But the windows are about 9 times wider than the work requires, there is no need to wait until the last minute (or even the last day) to get the work done.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-29T17:44:20Z
FirstChildVoteTAG: 0
FirstChildTAG: > Simply put, if I could just have access to large numbers of datasets I could use them to calculate averages, SD's, and regressions.
There are data sets all over the web and you can just google. For instance
http://www.hhs.gov/open/datasets/
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-29T21:33:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Great link - thanks! :)
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-03-30T02:45:40Z
SecondChildVoteTAG: 0
IndexTAG: 263
TitleTAG: When shall we get our certificate?
Hello everyone! I've passed the course and wanna know when I'll be provided with the certificate and further information on it.
Thanks beforehand.
Best regards,
Nodira
UserIdTAG: 1088451
UserNameTAG: dira
CreateTimeTAG: 2013-03-29T06:24:08Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: When edX has generated the certificates there will be a link on your dashboard. When? Depends on lots of factors.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-29T06:36:31Z
FirstChildVoteTAG: 7
SecondChildTAG: By Monday April 1, I hope. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-29T06:51:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks alot..!!!
SecondChildUserIdTAG: 1023900
SecondChildUserNameTAG: LA75
SecondChildCreateTimeTAG: 2013-03-29T07:00:51Z
SecondChildVoteTAG: 0
SecondChildTAG: **thanks**
SecondChildUserIdTAG: 1316999
SecondChildUserNameTAG: aminebounouar
SecondChildCreateTimeTAG: 2013-03-29T08:01:00Z
SecondChildVoteTAG: 0
SecondChildTAG: THANKS
SecondChildUserIdTAG: 1198994
SecondChildUserNameTAG: parthkelkar
SecondChildCreateTimeTAG: 2013-03-29T08:05:17Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks dear Ani
SecondChildUserIdTAG: 1078818
SecondChildUserNameTAG: Jamili
SecondChildCreateTimeTAG: 2013-03-29T08:17:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot Prof.Ani for teaching us so excellently and making all concepts crystal clear.
Thanks to all the Staff members at Edx.
warm regards,
Sanjana
SecondChildUserIdTAG: 1094606
SecondChildUserNameTAG: sanjana66
SecondChildCreateTimeTAG: 2013-03-29T09:52:28Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks, I learned a lot.
see you in the next course
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-03-29T10:11:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanx Prof. Ani, thanx edX for this course..
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-29T10:31:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot!!!!!!
SecondChildUserIdTAG: 1088451
SecondChildUserNameTAG: dira
SecondChildCreateTimeTAG: 2013-03-29T18:03:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks a lot to all the staff members involved.
And, of course, thanks to Prof. Ani Adhikari and Prof. Philip B. Stark for such a brilliant lectures and exercises!
All the best to everyone!
FirstChildUserIdTAG: 1056369
FirstChildUserNameTAG: YelenaYermilova
FirstChildCreateTimeTAG: 2013-04-01T08:43:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you Prof. Adhikari for your excellent effort.
Why did you choose to issue our certificates dated April 1?
FirstChildUserIdTAG: 1043948
FirstChildUserNameTAG: someshbose
FirstChildCreateTimeTAG: 2013-04-03T04:02:40Z
FirstChildVoteTAG: 0
IndexTAG: 264
TitleTAG: Thanks to the staff
Hi Dr. Adhikari and the course staff
I want to thank you all for this wonderful offering. I am a 23 year old software engineer, and this course has helped me realise that I want to go back to school for masters. Statistics was never so much fun.
Looking forward to 2.2 :D
Regards
Aman Gupta
UserIdTAG: 956579
UserNameTAG: aman2304
CreateTimeTAG: 2013-03-29T06:07:24Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Thanks a lot for the course it was great!!!
FirstChildUserIdTAG: 1227415
FirstChildUserNameTAG: Pantelia
FirstChildCreateTimeTAG: 2013-03-29T06:20:11Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks a lot Dr. Adhikari and to all the staff. We've learned a lot. Although I missed the final exam. I printed the questions and answered it while I'm not connected to the internet thinking that the deadline is 5:00pm. When I entered my answer I was confused because it automatically showed the answer. Well, I learned my lesson now... I'm looking forward for the next course in Statistics. See you all!
FirstChildUserIdTAG: 512705
FirstChildUserNameTAG: Rizadel
FirstChildCreateTimeTAG: 2013-03-29T09:06:21Z
FirstChildVoteTAG: 0
IndexTAG: 265
TitleTAG: Deadlines of homework and exams
I blew this one. I totally missed the deadlines for Exercise set 12 and the final exam. For Exercise set 12, I assumed the deadline was going to be on Wednesday at 23:30 GMT and didn't take a hard look at the published schedule. For the final I assumed the deadline would be at 23:30 like with the other deadlines, therefore I started the exam 2 hours before the deadline. Yes, I should have been able to finish in 2 hours, but since there was plenty of time to complete the exam,I figured I would have time to consult the homework and lectures to help with the exam, and therefore didn't study like I should have.
Anyway, I learned my lesson and next time I'll pay attention to the deadlines. For the last class I took, the homework and labs were always due on the same day at the same time, and it made me complacent.
Dr. A, this class was excellent, thank you. I look forward to the next class.
UserIdTAG: 132828
UserNameTAG: rharris
CreateTimeTAG: 2013-03-29T05:58:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 266
TitleTAG: Thanks Prof A. & Thanks to everyone at the Discussion Board
Thanks Prof A. I always loved calculus and never paid any attention to Statistics until recently when I decided I wanted to be a Data Analyst. I am already more than 6 years into working and my job involves lot of Microsoft Excel work. Your Course has made my foundations Strong. Things I thought I knew strongly, didn't seemed that way in the middle of the course. Especially, the format of Questions; I loved them. They stirred thought more than tedious calculations. "*I achieved 77% thats a Fair Start, I suppose.*"
Thanks Once again, Thanks to everyone on the Discussion Board; It was Fun! I hope to meet everyone in the next class of **Stat 2.2X**.
**"I wouldn't miss it for the world"**
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-03-29T05:56:11Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 267
TitleTAG: Ann3067
Dear staff, I am a 74 yr old female student from Australia and I live in a small country town with no statistic help from anyone but your instructions and I am delighted to have achieved somewhere above 70%. I found the going tough at times but feel a sense of achievement. Thank you for your wonderful instructions. I will be enrolling in the next course.
UserIdTAG: 1209211
UserNameTAG: Ann3067
CreateTimeTAG: 2013-03-29T05:50:11Z
VoteTAG: 17
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I'm delighted. Half my family is from Tassie, by the way. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-29T06:50:00Z
FirstChildVoteTAG: 4
FirstChildTAG: Congrats!!!
I am a 24 year old engineering grad and I am stuck at a measly 63% :(
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-29T08:50:48Z
FirstChildVoteTAG: 3
FirstChildTAG: Congrats Ann!!! I'm showing this to my hubby who is 62 and claiming to be too old to bother learning to use a computer, not to mention taking online courses in Stats - you're an inspiration :)
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-03-30T02:56:21Z
FirstChildVoteTAG: 0
IndexTAG: 268
TitleTAG: Congratulations to the all the Students who Passed the Course!
I achieved 87 percent Hurrah, and even better I learned a ton in this course. Hope that Dr. Ani will keep on teaching in the next stat episodes. I had really great time studying Stats, this will go a long way in making me a better researcher. Congratulations to all who passed the course!Sincerely
Yours
Ammar
UserIdTAG: 151750
UserNameTAG: Rajputana
CreateTimeTAG: 2013-03-29T05:35:32Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: 98%. (just because a fatfinger error in the final exam). Congratulations to all students and Prof A.
FirstChildUserIdTAG: 1210009
FirstChildUserNameTAG: GIAN66
FirstChildCreateTimeTAG: 2013-03-29T06:50:14Z
FirstChildVoteTAG: 1
FirstChildTAG: YEAH. was a wonderful course and enjoyed working with Prof.Ani.Hope she continues teaching more STATISTICS IN 2.2 AND 2.3.
PASSED THE COURSE WITH FLYING COLOURS.
CONGRATS TO EVERYBODY WHO PASSED THE COURSE.
FirstChildUserIdTAG: 1198994
FirstChildUserNameTAG: parthkelkar
FirstChildCreateTimeTAG: 2013-03-29T08:08:12Z
FirstChildVoteTAG: 0
IndexTAG: 269
TitleTAG: unavoidable thanks to Ani Adhikari
Dearest professor,
I am very glad that i had opportunity to study from you.It was great pleasure. Thank you for it!
UserIdTAG: 337198
UserNameTAG: harvard1
CreateTimeTAG: 2013-03-26T04:41:43Z
VoteTAG: 272
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 17
FirstChildTAG: Thank you Professor Ani Adhikari it was a very interesting course, but also challenging and fun. Thank you to all in your team.
I was wondering if you guys would send some info on the certificates. Thanks again.
Demetrio Hernandez.
FirstChildUserIdTAG: 1200226
FirstChildUserNameTAG: dxltx01
FirstChildCreateTimeTAG: 2013-03-29T06:35:38Z
FirstChildVoteTAG: 1
FirstChildTAG: Although I have studied statistics at the engineering school in the past I am very glad I took the course.
Not only did I remember concepts I had forgotten but also fully understood concepts I have never really did.
So many thanks, congratulations and see you in Stat 2.2x
FirstChildUserIdTAG: 38852
FirstChildUserNameTAG: fsanchez
FirstChildCreateTimeTAG: 2013-03-29T06:41:23Z
FirstChildVoteTAG: 2
FirstChildTAG: Thanks Professor.Looking forward for Stat 2.2x :)
FirstChildUserIdTAG: 5765
FirstChildUserNameTAG: vijay2221989
FirstChildCreateTimeTAG: 2013-03-29T06:41:45Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks alot madam.....was a wonderful experience.Will continue in coming sections.
Best Regards
Liaquat Ali
India
+91-8467850007
FirstChildUserIdTAG: 1023900
FirstChildUserNameTAG: LA75
FirstChildCreateTimeTAG: 2013-03-29T07:03:53Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks to Prof.A Adhikari and staff of EDX......I have scored 80% in final and 67% overall exam.
Thanks to all members of team
FirstChildUserIdTAG: 360347
FirstChildUserNameTAG: PRASADKVV
FirstChildCreateTimeTAG: 2013-03-29T07:36:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks a lot to Prof.A Adhikari and the whole staff of EdX for providing such a platform for online education ... It was a good experience for me towards the first online course of my academic career... Love you Stat2.1X ...Thanks a lot once again !!!
FirstChildUserIdTAG: 1341340
FirstChildUserNameTAG: Ihsan475
FirstChildCreateTimeTAG: 2013-03-30T04:43:35Z
FirstChildVoteTAG: 1
FirstChildTAG: Thank you, professor,
Looking for 2.2x
FirstChildUserIdTAG: 897023
FirstChildUserNameTAG: Lotvuthy
FirstChildCreateTimeTAG: 2013-03-30T06:04:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks, Professor, waiting for 2.2x.
SecondChildUserIdTAG: 570075
SecondChildUserNameTAG: NikiSadovski
SecondChildCreateTimeTAG: 2013-04-01T12:48:27Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks to Prof.A Adhikari and all staff of EDX involved in this course!! It was a great experience and I'm looking forward for Stat2.2X!
FirstChildUserIdTAG: 1109476
FirstChildUserNameTAG: LamprosK
FirstChildCreateTimeTAG: 2013-03-30T07:01:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Professor Ani, Thank you from the bottom of my heart for your enlightening lectures! Such grace, such simplicity, and above all, such nobility!
Till Stat2.2x I remain,
Your protege
FirstChildUserIdTAG: 795052
FirstChildUserNameTAG: BillVutz
FirstChildCreateTimeTAG: 2013-03-30T09:52:23Z
FirstChildVoteTAG: 1
FirstChildTAG: Thank you professor Ani, it was a great experience and i learn't a lot from you. Looking forward to Sta2.2X .
Kind Regards
FirstChildUserIdTAG: 1085077
FirstChildUserNameTAG: maveshsila
FirstChildCreateTimeTAG: 2013-03-31T11:02:52Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Prof. A,
I'm quite excited to get a chance to learn from you. Data analysis for informed business decision is something that always thrills me. Your teaching enlightened me so much towards it. Eagerly waiting for Stat 2.2x. Never felt so much joy for attending statistics class in my life earlier !!! Thank you.
It is my honour to get a chance to learn from you.
Kind Regards,
FirstChildUserIdTAG: 1047591
FirstChildUserNameTAG: priyodip
FirstChildCreateTimeTAG: 2013-03-31T23:53:00Z
FirstChildVoteTAG: 1
FirstChildTAG: thank you mam ...for all your guidance and support
FirstChildUserIdTAG: 907864
FirstChildUserNameTAG: TANVI11
FirstChildCreateTimeTAG: 2013-04-01T16:04:50Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks Prof Adhikari, the course surpassed my expectations. There are two pints of creamy stout waiting for you and Prof Stark in Kerry, Ireland!
FirstChildUserIdTAG: 1204342
FirstChildUserNameTAG: MelodyMay
FirstChildCreateTimeTAG: 2013-04-01T17:44:25Z
FirstChildVoteTAG: 0
FirstChildTAG: ... and 2 bottles of wine waiting for you over here in Slovenia, for making statistics such fun :-)
FirstChildUserIdTAG: 1188102
FirstChildUserNameTAG: Mojca
FirstChildCreateTimeTAG: 2013-04-01T18:25:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks to Prof. and staff. Great effort. It was wonderfull!!!
FirstChildUserIdTAG: 23811
FirstChildUserNameTAG: mitiwana
FirstChildCreateTimeTAG: 2013-04-02T10:12:58Z
FirstChildVoteTAG: 0
FirstChildTAG: As a learner that took his last college course more than 15 years ago, this has been a treat. I realized I missed the thrill of facing the unknown on a weekly basis. Thanks Prof Adhikari for making this seemingly impersonal venue a very familiar one with your expertise, candor and sense of humor. You give MOOCs a good name.
FirstChildUserIdTAG: 1152094
FirstChildUserNameTAG: CristianOpazo
FirstChildCreateTimeTAG: 2013-04-03T13:02:54Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks a lot Prof. A. Adhikari and all Staff and team members for making this online course possible. Great Effort in upgrading and propagating of knowledge.
Good Luck to this WONDERFUL TEAM. Waiting for Stat2.2x
FirstChildUserIdTAG: 1324978
FirstChildUserNameTAG: mmasalam
FirstChildCreateTimeTAG: 2013-04-03T21:04:37Z
FirstChildVoteTAG: 0
IndexTAG: 270
TitleTAG: Many thanks for Stat2.1x ! See you in Stat2.2x from April12th...
Thanks very much Professor A for your kind words.
The pleasure to learn with you was ours.
Personally, I really had 'hated' to study 'biostatistics' during my early years of medical cursus... without having any fundamental clues to understand what I was doing.
So glad to here that you ll be back for Stat2.2x very soon.
Looking forward to it!
By the way, just a quick question. I think with such a system as Edx (i.e grading, progress visualization etc..), did you record and will you use this profusion amount of data (grading, passing) and make some stats on us for your own work?
You know you just taught to a class of nearly 50000 people!!
Sincerely,
Z.
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-26T04:17:14Z
VoteTAG: 165
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Can we sign up for stat 2.2 yet? I didn't see it on the course list.
FirstChildUserIdTAG: 950537
FirstChildUserNameTAG: cjc71
FirstChildCreateTimeTAG: 2013-03-29T05:56:09Z
FirstChildVoteTAG: 3
FirstChildTAG: Dear staff of 2.1X and professor A. adhikari
Thanks for an excellent course. I can appreciate the trouble taken to design the problem sets with all their intricacies, all of which had a common goal to increase the understanding of the topic.
By the way i did not regress to mediocrity my finals i scored more than the midterm!!
It would be interesting to have the scatter plots of everyone who took the course, to see if it is football shaped. Especially the residual plot!!!
How did Galton's fallacy stand up
were the scores normally distributed?
What were the median scores?
hahah look eagerly to stat 2.2x
FirstChildUserIdTAG: 341206
FirstChildUserNameTAG: laxmishac
FirstChildCreateTimeTAG: 2013-03-29T10:40:38Z
FirstChildVoteTAG: 1
FirstChildTAG: The course was amazing, special thanks to both Proffesor Ani and Profesor Stark (amazing text book), and of course to all the team at Stat2.1X (EdX too).
As Zacharie, I would also like to see the data and...you know... some statistics about it, I think it would be kind of a nice review.
I'm looking forward for Stat 2.2X, my best to all
Vera
FirstChildUserIdTAG: 1199074
FirstChildUserNameTAG: VeraA
FirstChildCreateTimeTAG: 2013-03-29T23:59:38Z
FirstChildVoteTAG: 1
FirstChildTAG: Great course. At the beginning I thought I could go trough without doing anything as I relied on my Quality training (ASQ etc) and on my statistics stuff from University some years ago. Later it became evident that I indeed could learn a great deal here... and I did as I see it. Furthermore the course is accompanied by a quite well written e-book accompanied with video lecture and online exercises. I like the way in which Prof. A. presents the material and found it effective and very efficient. She is always after the crucial points of the presented subject, which is quite beneficial if you don't have that much time to spend. I felt also quite comfortable with the impression that she actually knows her stuff so well that she doesn't have to talk around something -she's always to the point. And I like that. Anyway: Great course and congratulations to all its producers. When I got time I'll (probably) take a look to the educational Baldrige criteria and try to rate it upon them. I'm sure the result will be quite good. Anyways...thanks for the course.
FirstChildUserIdTAG: 720154
FirstChildUserNameTAG: LUCALOTTO2012
FirstChildCreateTimeTAG: 2013-03-30T15:57:44Z
FirstChildVoteTAG: 0
IndexTAG: 271
TitleTAG: 3b. Correctness
I'm sorry! Are you kidding?
rms = sqrt(1-0.55^2)*0.5 !!!
0.5/rms = 1.19 r.m.s. errors ????? Why not 1.197368....?
Maybe round(0.5/rms, 2) == 1.2 ???
I entered the right answer twice and in the end I thought I couldn't understand the question correctly. So I entered the wrong number at all...
UserIdTAG: 759395
UserNameTAG: Gen_Art
CreateTimeTAG: 2013-03-26T04:12:51Z
VoteTAG: 3
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: The rounding requirements are certainly a lottery. Despite the instructions.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-26T04:35:43Z
FirstChildVoteTAG: 3
IndexTAG: 272
TitleTAG: Dhanyawad(Gracias) for Stat 2.1 X!
Dear Dr. Adhikari,
We all appreciate your efforts and most of all the heart to teach us this particular module. I was a student in an Engg. school in Eastern India, in the 90's, stat wasn't comprehensible; I got kicked out from college for failing this paper then. However, you've been a source of motivation and made this subject a very interesting one.
UserIdTAG: 117419
UserNameTAG: mcpyngrope
CreateTimeTAG: 2013-03-26T04:12:20Z
VoteTAG: 18
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 273
TitleTAG: Prof Adhikari :Recommended further reading recommendation
If we want to read further which books do you recommend.(I have already got Freedman's book) Basically I would like a reference book which is simple in style but can build over the knowledge base that has been constructed for us so far.In particular I would like to read more on regression modeling etc (especially nonlinear methods)
(ps for some reason the "general" tab seems to be removed so it is getting posted in Ex1 Set1
I would make another request for more problem exercises (In the regression chapter we suddenly had a lower number of problem exercises and I think they are important because we can test wethere we really understood concepts before going for the assessment part.In fact I think I understood some concepts better after doing the additional problems in the regression portion and actually the nonEdx format was perfectly OK. Even if the course gets over could you post additional optional exercises so that we can solve them at our leisure in between 2.1 and 2.2 X ?
I also would be grateful if you would post the proofs of the last portions of the lectures like you had done for the first part in the supplemental section.
Thanks for a great course and looking forward to the 2.2X course.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-26T03:17:10Z
VoteTAG: 21
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 274
TitleTAG: Problem marking ex set 12?
After answering 2B, 2C, 2D, 2E, "0 of 1 submissions used" remains even after "check answer" is selected. No "final" choice is given. Are the marked answers being accepted?
UserIdTAG: 398274
UserNameTAG: aremh
CreateTimeTAG: 2013-03-26T02:52:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Maybe I had better learn how to regress my time zone on GMT. A very costly lesson was learned.
FirstChildUserIdTAG: 398274
FirstChildUserNameTAG: aremh
FirstChildCreateTimeTAG: 2013-03-26T02:57:08Z
FirstChildVoteTAG: 2
SecondChildTAG: Same here.
SecondChildUserIdTAG: 1178106
SecondChildUserNameTAG: pyt
SecondChildCreateTimeTAG: 2013-03-26T03:09:27Z
SecondChildVoteTAG: 0
IndexTAG: 275
TitleTAG: what happened?
answers 1a thru 2e were marked correct in exercise set 12, yet I received no credit for any of th problems; th problems under 3 gave me no response at all after an answer.
UserIdTAG: 950367
UserNameTAG: catt9
CreateTimeTAG: 2013-03-26T02:37:24Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: If you are doing this now, it is because submissions closed a couple of hours ago.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-26T02:44:23Z
FirstChildVoteTAG: 2
IndexTAG: 276
TitleTAG: Why was submission date changed??
The submission day for exercise 12 was not Wednesday as usual!! In February this statement was posted: ALL EXERCISE SET DUE DATES ARE BEING CHANGED TO WEDNESDAYS.
Apparently not all due dates .....
UserIdTAG: 900351
UserNameTAG: JoeFalconer
CreateTimeTAG: 2013-03-26T01:58:47Z
VoteTAG: 15
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: >Solutions to Exercise Set 12 will be visible once you have submitted your answers. That is the only Exercise Set in Week 5. Please note that the due date for Exercise Set 12 is Monday March 25, the day before the final.
Only one set of exercises,and due date quite clearly specified.
And also stated in the Course Schedule.
>Exercise Set 12, due Mon Mar 25
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-26T02:09:39Z
FirstChildVoteTAG: 6
SecondChildTAG: I missed it too, my own fault I was busy doing the midterm on another course and just had it in my head that I had until Wednesday. It is worth remembering that your two worst exercise scores are not included when working out your grade. In my case this is definitely one of them...
John
SecondChildUserIdTAG: 57955
SecondChildUserNameTAG: JohnnyP
SecondChildCreateTimeTAG: 2013-03-26T03:02:53Z
SecondChildVoteTAG: 0
IndexTAG: 277
TitleTAG: Some of the students have to work and take care of our families
Dear professor: Some of the students have to work at a job and in our houses with shores, hence we study and do homeworks at night after a hard work day.
Therefore, I have to ask you if is possible to adjust the time hour to a local time, in that situation, we would have the opportunity to finish our job at night and get best grades, despite our family commitments.
Today I lost the exercise set 12 (the same as the exercises 5 and 6) thanks to the end time. At least a 7.0 grade I could have at 18:33 p.m. and that is a very sad situation.
Best regards.
UserIdTAG: 910307
UserNameTAG: MarciaLizeth
CreateTimeTAG: 2013-03-26T01:28:07Z
VoteTAG: 4
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 5
FirstChildTAG: We had almost a week to do the exercises. You can't blame the professor if you can't plan ahead.
I work full time and raise two small children. I get really upset when I read posts like yours, because you make us working parents look bad. Take responsibility for your own time management. Don't ask the professor to shape the course around your needs.
As you probably read, the professor is receiving zero monetary compensation for her efforts. Maybe you could show a little gratitude.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-26T02:36:44Z
FirstChildVoteTAG: 21
FirstChildTAG: I was conducting a workshop in another city 2500 Km away with spotty access and was in transit during a lot of this time in airports etc but did manage to finish the exercises.I think a bit of preplanning is necessary. You can keep reminders etc using Google calendar(an ical file for google calendar was graciously provided by one of the costudents here)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-26T02:43:31Z
FirstChildVoteTAG: 1
FirstChildTAG: And I started the course 7 sets too late and eked out a 63% final tally...It's not difficult...I too have a job...My solution was to stop hanging out with friends and rush home after closing time and sit up 2-3 nights...Its manageable if you plan it out
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-29T09:01:53Z
FirstChildVoteTAG: 1
FirstChildTAG: If your life is too busy for this course, then maybe you should reassess your priorities.
>adjust the time hour to a local time
Seriously? And what local time would you suggest? Yours? But then it's not my local time. Or someone else's.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T00:39:00Z
FirstChildVoteTAG: 0
FirstChildTAG: I think we all have a diverse range of commitments and competing priorities, and in a class this large, this diverse and so globally spread it's just not possible to have times that would suit everyone.
If it's the learning that's important then deadlines don't matter - because thankfully the materials are available 24 hours a day. If the scores are important to you, then you make a commitment to yourself to check the due dates/times, set reminders and meet the deadlines. That's all there is to it :)
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-03-30T03:05:41Z
FirstChildVoteTAG: 0
IndexTAG: 278
TitleTAG: Problem 3A(Exercise set 12) - To Staff (Reposting cos I did not get a response earlier)
Shouldn't the answer be double the answer that you have shown when you consider both sides(positive and negative) of the 50% from the applet.
Thanks
UserIdTAG: 1181314
UserNameTAG: SolomonT
CreateTimeTAG: 2013-03-26T01:10:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: I am not staff but ...
This problem requires identifying the area WITHIN two standard unit endpoints, so what is in the tails is not applicable.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-26T02:32:33Z
FirstChildVoteTAG: 0
IndexTAG: 279
TitleTAG: Greetings from India!
I am sending the colorful greetings on the festival of colors .All good things come to an end.So is this course.Thank you so much to staff of EDX team,and our class mates for the help they had provided throughout the course.Wish we will meet again for Stat2.2 on the same platform.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-26T00:58:17Z
VoteTAG: 13
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Wishing you the same!
FirstChildUserIdTAG: 1416809
FirstChildUserNameTAG: mehrotravinit
FirstChildCreateTimeTAG: 2013-03-26T01:27:54Z
FirstChildVoteTAG: 3
FirstChildTAG: happy holi!
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-26T01:43:28Z
FirstChildVoteTAG: 3
FirstChildTAG: Wishing all a very happy Holi.
FirstChildUserIdTAG: 1293941
FirstChildUserNameTAG: CHHAVIMEHROTRA
FirstChildCreateTimeTAG: 2013-03-26T04:55:57Z
FirstChildVoteTAG: 3
IndexTAG: 280
TitleTAG: Dear Dr. Ani:
If you see my answer of exercise 3a is correct, but I wrote the interval (13.73-14.28) instead of +-0.28, there is a possibility that it will be correct?
In 3b I wrote 11.57, but it wasn´t save it, finally my answer was wrong.
Thank you very much for all.
UserIdTAG: 328875
UserNameTAG: mggh2005
CreateTimeTAG: 2013-03-26T00:58:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 281
TitleTAG: To Staff
I'm a 59 - year old male in Toronto. I've been out of school for 40 years. I found this course to be very well presented and I've enjoyed it very much. I found it to be "not easy - not hard". Because I've a family, job and so on, I couldn't give it the attention or time I should have. If I had, I believe I could have aced it. It's a very informative course and so, Thank You.
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-03-26T00:30:35Z
VoteTAG: 33
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 282
TitleTAG: Unfinished
I answered this exercise yesterday but did not finish it. I intended to finish it today. It's 5:10pm PST, and the deadline is not until 23:50 EST, right? How come I can no longer submit my answers to the remaining numbers I did not finish? This is bad, it appears that I flank this exercise by "default". I didn't like it that I did not even get to try to submit my answers.
UserIdTAG: 434563
UserNameTAG: jer_nano
CreateTimeTAG: 2013-03-26T00:12:40Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Please refer to Course Info dated Feb. 27, which was emailed to all participants ~
"Information about due dates and times has been posted since the first day: Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT)."
Additionally, most exercise sets including Exercise Sets 9, 10, and 11 had Greenwich Mean Time (GMT) listed in bold letters at the top. While Exercise Set 12 did not have a bold-face reminder, it can be assumed to be GMT as stated in the Course Info, not EST.
FirstChildUserIdTAG: 582353
FirstChildUserNameTAG: Slaggie
FirstChildCreateTimeTAG: 2013-03-26T00:37:59Z
FirstChildVoteTAG: 1
FirstChildTAG: The windows are big enough that you do not need to wait until the last minute or even the last day before doing the work.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-29T17:56:17Z
FirstChildVoteTAG: 0
IndexTAG: 283
TitleTAG: A nice guide to interpret Regresion plots
http://www.youtube.com/watch?v=_NkWG1M69CI
UserIdTAG: 933119
UserNameTAG: wsaw
CreateTimeTAG: 2013-03-25T23:51:16Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thanks!
FirstChildUserIdTAG: 582353
FirstChildUserNameTAG: Slaggie
FirstChildCreateTimeTAG: 2013-03-26T00:28:48Z
FirstChildVoteTAG: 0
IndexTAG: 284
TitleTAG: DEAR STAFF…
In question number 3B I did the right procedure… I found and AUC in the applet displayed after enter values -1.2 and 1.2 which were 76.99%... then I rounded this number to 77% as my answer. I am almost certain is right, the procedure was exactly as suggested in your ANSWER, which in the applet give us 76.6%.
I am confused because sometimes you suggest to round numbers. I did this and got a wrong answer.
Could you please assist me in this matter ?
The course and concepts´s been very favorable to my understanding, comprehension and delightful by the way. CONGRATS TO ALL OF YOU !!!
UserIdTAG: 1172070
UserNameTAG: alpisteasea
CreateTimeTAG: 2013-03-25T23:49:48Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Sorry, anyway I double checked… I had to look JUST the AUC left to the LEFT tail. My mistake. ups...
FirstChildUserIdTAG: 1172070
FirstChildUserNameTAG: alpisteasea
FirstChildCreateTimeTAG: 2013-03-25T23:53:17Z
FirstChildVoteTAG: 0
FirstChildTAG: And if I remember aright answers are to be to 2 decimal places unles otherwise requested.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-29T17:58:04Z
FirstChildVoteTAG: 0
IndexTAG: 285
TitleTAG: A General Thank You
I would like to thank Professor Adhikari for presenting us with clear and instructive lectures.
I would also like to thank the many participants on the discussion boards who took the time to aid their fellow students.
UserIdTAG: 441203
UserNameTAG: etstowell
CreateTimeTAG: 2013-03-25T23:47:48Z
VoteTAG: 31
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 286
TitleTAG: Thankyou Course Staff
Thankyou for producing this excellent course.
UserIdTAG: 169991
UserNameTAG: birkenhead
CreateTimeTAG: 2013-03-25T23:42:27Z
VoteTAG: 59
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Thanx alot...was an exceelent experience..!!
FirstChildUserIdTAG: 1023900
FirstChildUserNameTAG: LA75
FirstChildCreateTimeTAG: 2013-03-29T06:46:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank to all team members who worked hard to deliver this great course to world students.
FirstChildUserIdTAG: 897023
FirstChildUserNameTAG: Lotvuthy
FirstChildCreateTimeTAG: 2013-03-30T06:06:04Z
FirstChildVoteTAG: 0
IndexTAG: 287
TitleTAG: About the end of this first course
Hello fellow students and staff,
What a surprise for me when i just saw roughly 3 hours ago, that this problem set was due today...
Was a bit difficult for me to see lectures, and make this problem in this amount of time, especially because of the content which was a clearly more difficult this week than previous weeks. And also, because normally, i spend far more time on lectures to write some things etc...
I made several mistakes, especially on the residual plots.
I understand the frustration of some of the students, because some problems were a bit tricky... Though, not so important for me, since i have already max score for problem sets.
But clearly, one thing to notice is that the textbook, which i am not used to read every week, i admit, contains many clues to answer these questions properly. I noticed a bit too late.
I also noticed, that the final exam will also come this week. I found this a little prematured, especially because the stuff to learn this week clearly needS more time to be well mastered.
Would have been nice to put it next week... :/
UserIdTAG: 957952
UserNameTAG: Jjclof
CreateTimeTAG: 2013-03-25T23:34:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: The Course Schedule has been available since the beginning of the course:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Course_Schedule.pdf
I don't understand why you were surprised by the due date and final exam date?
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-25T23:38:48Z
FirstChildVoteTAG: 1
SecondChildTAG: It appears that some just don't bother reading the various policies and announcements.
There would be very little to complain about, and no-one to blame, if instructions were read.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-25T23:47:42Z
SecondChildVoteTAG: 0
SecondChildTAG: There is nothing about complaining here. I just said i was "surprised", and i also said that the course material was more difficult this week. That's why i was a bit "short" for the problems.
U may also understand that some people take more than one course on EDX at the same time. And so probably, they have specific days allocated to some specific courses. That's what i do...
Maybe, that would be something to improve on the Edx websitE, for instance to have a personal agenda in the user's profile...
Anyway, and to conclude, i have also read the course schedule, for once, at the beginning. But maybe, i had forgotten that, for the last week, the due date had not been set on wednesday as usual but on Monday. I am happy to notice that u had not...
SecondChildUserIdTAG: 957952
SecondChildUserNameTAG: Jjclof
SecondChildCreateTimeTAG: 2013-03-26T00:45:19Z
SecondChildVoteTAG: 0
IndexTAG: 288
TitleTAG: Optional Quiz #2, Question 1(c)
Optional Quiz #2, Question 1(c). "A child who is 41.5 inches tall is estimated to weigh __ lbs, ..." How do you calculate the estimated weight of the child? This is embarrassing. I seem to be forgetting everything today! I've got the rms error so know the second part of the question ("give or take __ lbs").
Thanks!
UserIdTAG: 1252523
UserNameTAG: Willabe
CreateTimeTAG: 2013-03-25T23:20:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Go back to your notes or textbook and look for estimated Y = slope * x + some intercept
Plug in the values for this formula
FirstChildUserIdTAG: 1059783
FirstChildUserNameTAG: aguirrem
FirstChildCreateTimeTAG: 2013-03-25T23:53:20Z
FirstChildVoteTAG: 0
SecondChildTAG: So it's just the regression estimate equation? Thanks. I think I tried that but maybe I just need to check my calculations.
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-25T23:57:44Z
SecondChildVoteTAG: 0
IndexTAG: 289
TitleTAG: Thanks
Thanks, to Prof Ani & edx staff for organizing such a wonderful course, it was a wonderful experience taking an online course, I find this mode of learning more feasible for a working person like myself. I would appreciate if the course Material like text book and lecture videos are available for a while.
UserIdTAG: 558560
UserNameTAG: wasimpak
CreateTimeTAG: 2013-03-25T23:16:10Z
VoteTAG: 12
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 290
TitleTAG: problem with 3C
I rounded everything to the third decimal and my result was valued as wrong...It's a pitty because I have all the steps correctly done... :(
UserIdTAG: 805246
UserNameTAG: Ioanna_
CreateTimeTAG: 2013-03-25T23:08:14Z
VoteTAG: 3
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 291
TitleTAG: Has my name been registered correctly?
My name doesn't appear in your student directory...is that a problem with my registration and will be a problem with my certificate?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-25T22:53:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you click on your username in the top right corner, it will show the course "title" page. Look at the left for your full name and email address. If your name isn't there, or is incorrect, you can edit it. Hope this makes sense!
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-25T23:05:51Z
FirstChildVoteTAG: 3
IndexTAG: 292
TitleTAG: A big thank you!
Prof Ani - I would like to thank you and the people that helped you in preparing this great course. It was a really fun and stimulating way to spend a few hours every week. Look forward to seeing you again in stat 2.2x.
UserIdTAG: 24910
UserNameTAG: havelp
CreateTimeTAG: 2013-03-25T22:37:56Z
VoteTAG: 13
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 0
IndexTAG: 293
TitleTAG: [staff] Thank you Professor and Staff
I appreciate this class and your responsiveness to concerns. To Professor, thank you for forcing me to think through the questions in a methodical way.
For reference, I usually watch the lectures on HD, 1.50x speed, with captions, and tended towards procrastination except for last weeks homework. I did use the discussion for certain questions, posted rarely, and usually skimmed the text.
Having written this, perhaps it would be of interest to edX to offer some surveys to participants about how they attend this course (discussion usage, speed watched, download or stream, captions or not, etc.), and get some stats on that sort of thing. Just a thought.
And I love edX.
UserIdTAG: 78038
UserNameTAG: subz
CreateTimeTAG: 2013-03-25T21:49:33Z
VoteTAG: 15
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Excellent bravo!!!!
FirstChildUserIdTAG: 611869
FirstChildUserNameTAG: bostonpatriot
FirstChildCreateTimeTAG: 2013-03-25T23:10:13Z
FirstChildVoteTAG: 0
SecondChildTAG: awsome..!
SecondChildUserIdTAG: 1023900
SecondChildUserNameTAG: LA75
SecondChildCreateTimeTAG: 2013-03-29T06:49:46Z
SecondChildVoteTAG: 0
IndexTAG: 294
TitleTAG: Residual Plot "Trend" vs. "Pattern"
I think I've been using these terms interchangeably and perhaps shouldn't be. How is the word "trend" defined in relation to residual plots? Does it only refer to linearity? Whereas "pattern" could be any kind of apparent relationship?
Thanks!
UserIdTAG: 1252523
UserNameTAG: Willabe
CreateTimeTAG: 2013-03-25T21:16:46Z
VoteTAG: 0
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 0
IndexTAG: 295
TitleTAG: I made a stupid mistake
ok! Now i understand why i got all answers wrong...i just forgot the square root when computing the rms. hahaha. Ok i won't be caught at it again :)
UserIdTAG: 134165
UserNameTAG: sthierry
CreateTimeTAG: 2013-03-25T21:09:29Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Missing a step is something I have to be wary of. In the preample to the first optional practice quiz, Prof A. cautions against hasty answers and gives some basic advice worth remembering for the final exam: "Think things through, check your reasoning, and check your arithmetic."
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-25T21:22:56Z
FirstChildVoteTAG: 2
SecondChildTAG: Learning this the hard way.
SecondChildUserIdTAG: 252779
SecondChildUserNameTAG: msushi
SecondChildCreateTimeTAG: 2013-03-26T00:06:16Z
SecondChildVoteTAG: 0
FirstChildTAG: I have been a complete ass during this course. If I had followed Professor A's admonitions, I'd be doing better. No one to blame but me and not checking GMT versus local time. I am a dope but loved the course.
FirstChildUserIdTAG: 611869
FirstChildUserNameTAG: bostonpatriot
FirstChildCreateTimeTAG: 2013-03-25T23:09:43Z
FirstChildVoteTAG: 1
SecondChildTAG: LOL
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-25T23:31:38Z
SecondChildVoteTAG: 0
IndexTAG: 296
TitleTAG: For Staff: 2.2x Course Title
Will the title for 2.2x also be "Introduction to Statistics: Descriptive Statistics"? Please point me in the right direction if this question has already been answered.
Thanks for a great course; looking forward to 2.2x on April 12th!
UserIdTAG: 1059543
UserNameTAG: ajconti
CreateTimeTAG: 2013-03-25T20:55:21Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I bet it'll be called "Introduction to Statistics: Probability", or something very similar.
But, it's just my guess, we'll likely have more details later ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T20:58:10Z
FirstChildVoteTAG: 0
FirstChildTAG: It could be called 2SD :)
FirstChildUserIdTAG: 584390
FirstChildUserNameTAG: pluribus
FirstChildCreateTimeTAG: 2013-03-25T23:42:44Z
FirstChildVoteTAG: 0
IndexTAG: 297
TitleTAG: For Staff: Access to materials after final
For those of us planning to take 2.2x. Will we still have access to the materials in 2.1x after the course is completed? In case we need to refer to previous concepts/videos. Should we make our own archives?
UserIdTAG: 695174
UserNameTAG: nerico
CreateTimeTAG: 2013-03-25T20:22:18Z
VoteTAG: 18
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 1
FirstChildTAG: i hope they keep videos online and the problem sets (so useful!).
you can´t access it trough youtube because they are private (only by link access)
FirstChildUserIdTAG: 933119
FirstChildUserNameTAG: wsaw
FirstChildCreateTimeTAG: 2013-03-25T23:36:11Z
FirstChildVoteTAG: 1
IndexTAG: 298
TitleTAG: Quiz 1 Question 9
Reference: Additional Practice for Final - Quiz 1.
Q9 : The 20th percentile of the distribution is ________________ years.
Given A9 : 19.55 [15 + (20/44)*10]
I dont understand how this calculation is done. Because 20% lies **within** the first interval namely 15-25 which is already 44%. So I though the calculation would be
[15 + (5/44)*10] = 16.13 years.
Can somebody please explain how this is done. Thanks
UserIdTAG: 600543
UserNameTAG: Pradha
CreateTimeTAG: 2013-03-25T20:17:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 20% does lie in the first interval, yes.
But, the first interval starts at 0%(there are **no** values below 15), and not at 15% as your formula seems to suggest. It's "width" of course is 10(25-15).
So starting at 0%(15) you need to move 20% out of the 44% the interval represents. Thus, $15+(\frac{20\%}{44\%}*10)$.
Hope this helps!
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T20:29:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you so much for your reply and explanation.
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-25T20:57:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Guess I got confused with the age and %
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-25T21:10:51Z
SecondChildVoteTAG: 0
IndexTAG: 299
TitleTAG: a question concerning SDs and regression
If you have a single quantity such as IQ is the SD the same for a subgroup far from the mean as it is for the overall mean population? In other words do people 3 SDs from the norm have the same 15 point SD as the overall population. And if not, how does one calculate this narrowing of deviation?
UserIdTAG: 27119
UserNameTAG: cah
CreateTimeTAG: 2013-03-25T19:50:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Mmm...I don't think that you can tell much about "people 3 SDs from the average", except for the usual Normal approximation which allows you to say that they are about 0.13% of the total.
To know more you'd have to actually compile the data as a new subset and then calculate the Average and SD for them.
At least, this is what I think. I welcome any corrections ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T20:25:16Z
FirstChildVoteTAG: 0
IndexTAG: 300
TitleTAG: Could someone please help me with Q 3B
I really don't understand how to go about this question. Any help will be much appreciated!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-25T19:20:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: If you got 3a correct, then you know how to calculate the SD or the RMS of error. You also know how to calculate for Z using the RMS of error.
The question is very similar to 3a. 3a gives you the percentile and your job is to find the Z and then convert it to the normal unit. This question asks for the percentile. And make sure that you read the question carefully to really understand which portion of the standard normal curve it is looking for.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-25T20:09:00Z
FirstChildVoteTAG: 3
SecondChildTAG: Thank you for your help :)
SecondChildUserIdTAG: 951385
SecondChildUserNameTAG: Jsmb
SecondChildCreateTimeTAG: 2013-03-25T22:07:58Z
SecondChildVoteTAG: 0
IndexTAG: 301
TitleTAG: Please if no answer disable check click function.
I clicked by mistake check with no Answer cause I was doing the test from an iPad.
I won't claim another chance or start protesting that I knew the answer bla bla ...but please if possible disable the option Check if no answer ..it's a pity cause I really worked carefully on those patterns. Certainly I don't want to think that this may happen on final.
Thank you in advance
UserIdTAG: 1239975
UserNameTAG: Xenofon
CreateTimeTAG: 2013-03-25T19:14:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: In the same vein, it would be nice if Check did not use up a submission if the answer was the same as a previous submission.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-29T18:12:50Z
FirstChildVoteTAG: 0
IndexTAG: 302
TitleTAG: some help for 3C?
I have never asked before - pls , some hint?
UserIdTAG: 1107133
UserNameTAG: Shumanova
CreateTimeTAG: 2013-03-25T18:38:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: It's a straight-up SU transformation +regression + consulting the Normal Curve applet.
You might have problems if you don't approximate the intermediate results. Make sure to only use 2 decimal values for all calculations in this exercise.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T18:51:00Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you very much! I tend to overdo it and round off at three or four decimal values, which gave me quite different results (that weren't accepted), so I am very thankful for this hint :)
SecondChildUserIdTAG: 1240329
SecondChildUserNameTAG: KStroem
SecondChildCreateTimeTAG: 2013-03-25T21:49:09Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you!
FirstChildUserIdTAG: 1107133
FirstChildUserNameTAG: Shumanova
FirstChildCreateTimeTAG: 2013-03-25T21:34:40Z
FirstChildVoteTAG: 0
IndexTAG: 303
TitleTAG: Applet
How do I use the applet correctly? Is there something I have missed? I lost my marks in exercise 11 because I couldn't use the applet correctly.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-25T17:29:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: You use the applet to either:
- Find an interval of *z* that contains a certain fraction of the area under the Standard Normal curve.
For example, if you want to know the 25% percentile, start at -5 and move right until you have 25% of the area under your interval. Or, if you need to know how far you can go from the Average before you hit a certain area, start from 0, and move left or right until you get to **half** that area(the curve is symmetric)
- Find the fraction of the area under a certain interval of z.
For example, you might want to know what area is within 1.5SU of the Average. Start from 0, and go right(left) to 1.5(-1.5). Double the percentage and you have your area.
Of course, you always need to work in Standard Units with the applet. But you should know how to convert any values in an (approximately) normal curve to Standard Units if you followed the course ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T18:32:31Z
FirstChildVoteTAG: 0
IndexTAG: 304
TitleTAG: About the Greenwich Mean Time...is this British time?
"The final exam for Stat 2.1X will start at 05:00 A.M. Greenwich Mean Time (GMT) on Tuesday, March 26 and end at 05:00 A.M. GMT on Friday, March 29. That's 72 hours."
I am a little confused, you mentioned 5 AM, GMT, so that will be mid-night for EST, right? I just wonder why you guys use GMT, isn't Berkeley located in CA?
UserIdTAG: 60773
UserNameTAG: billchenxi
CreateTimeTAG: 2013-03-25T16:48:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: Gosh- this thing has been beaten up so many times.It is Greenwich mean time which is not exactly London time(which can have daylight saving time etc).It is used because this is an international course and GMT is the reference time for the whole world.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-25T16:55:04Z
FirstChildVoteTAG: 1
FirstChildTAG: oh my actual god
This may help [Whats GMT][1]
[1]: http://bit.ly/YAaMwN
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-03-25T17:03:39Z
FirstChildVoteTAG: 0
FirstChildTAG: "you mentioned 5 AM, GMT, so that will be mid-night for EST, right? "
No ... I believe it would be 1 am for EST. EST is currently 4 hours behind GMT.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-25T18:29:48Z
FirstChildVoteTAG: 0
FirstChildTAG: There is one website I love: http://www.worldclock.com/ Among other things, it allows you to convert any time/date between timezones ;)
> just wonder why you guys use GMT, isn't Berkeley located in CA?
Because edX and BerkeleyX are *not* Berkeley, and are not in California. They are online, international institutions with students registered from all around the world. Therefore, it's nice to use a "Central" reference timezone like GMT instead of a local timezone ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T18:39:37Z
FirstChildVoteTAG: 2
SecondChildTAG: Perhaps a whole lecture should be devoted to "How to tell the time, regardless of where you live".
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-26T02:01:14Z
SecondChildVoteTAG: 0
FirstChildTAG: I think edX can consider putting a countdown timer next to each submission ....like "24 hours left for this submission" ...tick tock tick tock...."24 min left for submission" --- pressure on!
No one can complain of missing a deadline then!
FirstChildUserIdTAG: 600543
FirstChildUserNameTAG: Pradha
FirstChildCreateTimeTAG: 2013-03-25T19:58:17Z
FirstChildVoteTAG: 2
SecondChildTAG: Check out the "Suggestions for Improvements" in the Wiki!
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-25T19:59:21Z
SecondChildVoteTAG: 0
FirstChildTAG: A good reference for GMT is the date and time on your computer, usually in the lower right corner of the screen. It actually uses UTC (Coordinated Universal Time), which was adopted over GMT due to highly accurate time pieces available today. See here [GMT vs. UTC][1] for an explanation. UTC+0:00 is GMT.
Click on the time or date (actually they are together), select "Change date and time settings", select "Change time zone", then select the "Time zone:" drop down menu. There you see many large cities, which give the amount of time either before or after UTC+0:00. From these numbers you can calculate what time you are at based on where you live. Just make sure you cancel out of the clock/time settings so you don't change your time zone, etc.
Or, you can type GMT into Google and probably find the differences in time much faster.
[1]: http://geography.about.com/od/timeandtimezones/a/gmtutc.htm
FirstChildUserIdTAG: 132828
FirstChildUserNameTAG: rharris
FirstChildCreateTimeTAG: 2013-03-29T06:32:32Z
FirstChildVoteTAG: 0
IndexTAG: 305
TitleTAG: Exercise Set 12, problem 3C
I want my points for this problem back!
I calculated everything right, except the fact that I was trying to be more precise and I calculated everything with four digits after the dot. So in the end I got an answer that is slightly different from the given answer. But that's only due to precision.
I think that's not fair :(
UserIdTAG: 1111798
UserNameTAG: kammolch
CreateTimeTAG: 2013-03-25T16:47:46Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 306
TitleTAG: Tyche's Prediction
The next 2.2x course will be most difficult than 2.1x. In this last one, at the end, my progress' bars are lowering as on a downhill. Eggs, ages, heights, weights, SATs, and wages haven´t to allow to obtain a better success. May be the problem is connected with the understanding of a very well wrotten by teachers English. Tyche will help to all us I think. So allow me to be with you in 2.2x.
UserIdTAG: 1240706
UserNameTAG: remipole
CreateTimeTAG: 2013-03-25T16:33:58Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: I hope I am going to like Tyche ...
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-25T18:26:22Z
FirstChildVoteTAG: 0
SecondChildTAG: MyOwnCamera, I certainly hope you like Tyche. We're about to enter her territory: she rules the world of Stat 2.2X. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-25T18:40:10Z
SecondChildVoteTAG: 0
SecondChildTAG: the problem may be __associated__ with the level of Eng. This is how it's correct to say after having taken this course.
no, my level of En is not advanced. the main question here is to have a good understanding of the basic conceptions of stats.
SecondChildUserIdTAG: 18187
SecondChildUserNameTAG: alinsoar
SecondChildCreateTimeTAG: 2013-03-25T21:48:20Z
SecondChildVoteTAG: 0
IndexTAG: 307
TitleTAG: QUESTION ABOUT WEEK1
If the interval includes both the left and right endpoint, does the length of the interval change e.g the interval 10-15 width=6if both endpoints are included,width=5 if one endpoint is included
UserIdTAG: 694631
UserNameTAG: wafaztaha
CreateTimeTAG: 2013-03-25T15:07:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: I think the convention is to include either the left endpoint or the right endpoint but never both.
FirstChildUserIdTAG: 119039
FirstChildUserNameTAG: Alan56
FirstChildCreateTimeTAG: 2013-03-25T16:12:54Z
FirstChildVoteTAG: 0
FirstChildTAG: One of the end intervals (either the first one or the last one) often includes both. No, the length does not change. The width of the 10-15 interval is 5 regardless of which endpoints are included; there is no discreteness in calculating the width. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-25T18:38:14Z
FirstChildVoteTAG: 1
FirstChildTAG: Another thing to consider is that including both left *and* right endpoints into an interval has a problem: some values would be counted twice.
For example if you have the intervals [0,5] and [5,10], what do you do with values that are exactly 5? You'd have to put them in both intervals, and that's usually not a good idea :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T18:47:40Z
FirstChildVoteTAG: 0
IndexTAG: 308
TitleTAG: certificate
I missed the first week of this class and am at about 50% right now, which is enough to pass this class. I'm really busy for the next few days, and don't have much time for the last exercise set and the final. If I skip those for now and go back to them at a later time just for practice, will I have the same certificate as people who got 100% in this class, or does the certificate specify your grade?
UserIdTAG: 1326696
UserNameTAG: Maxkim
CreateTimeTAG: 2013-03-25T15:06:25Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: It's right . The same is also discussed in the post titled: certificate of completion will be awarded to those who score 35% or higher . I would also like to see what Lanlau & Rosewood or anybody else thinks honestly in view of this fresh post and the discussion there .
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-25T15:28:28Z
FirstChildVoteTAG: 0
FirstChildTAG: I read somewhere that the certificate is the same don´t matter the score you get. It says that you finish the course successfully but not the score you got in it.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-03-25T15:54:54Z
FirstChildVoteTAG: 2
FirstChildTAG: edX has their policies on the faq page. It tells you there that the certificates do not contain grades.
>Will my grade be shown on my certificate?
>No. Grades are not displayed on either honor code or proctored certificates.
https://www.edx.org/help#certificates_and_credits_faq
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-25T21:25:46Z
FirstChildVoteTAG: 1
IndexTAG: 309
TitleTAG: Practice for the Final
Thank you for this. These exercises were helpful and clarified several important points on regression.
UserIdTAG: 1305333
UserNameTAG: bellerin
CreateTimeTAG: 2013-03-25T14:55:34Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I agree - These exercises really helped me understand the details a little bit better - it was worth going through these on paper and then checking the answers. I feel much more ready for the final!
Thank you!
FirstChildUserIdTAG: 455504
FirstChildUserNameTAG: kamay
FirstChildCreateTimeTAG: 2013-03-25T19:11:34Z
FirstChildVoteTAG: 0
IndexTAG: 310
TitleTAG: Next Stat course
Do someboby know when Stat2.2 will start?
UserIdTAG: 336649
UserNameTAG: Roksolana
CreateTimeTAG: 2013-03-25T13:05:41Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 12th of April :)
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/514e1f751785850e00000041
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T13:26:06Z
FirstChildVoteTAG: 1
IndexTAG: 311
TitleTAG: THANKS,Prof.A
We will miss u,Prof.A.Thank u for all the effort and pain u have taken in imparting the course.God bless.
UserIdTAG: 1182251
UserNameTAG: ChaitaliPattanayak
CreateTimeTAG: 2013-03-25T12:49:04Z
VoteTAG: 17
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You will see Prof. A. again if you enroll for Stat 2.2x, which starts on April 12th, as mentioned on the Updates page.
FirstChildUserIdTAG: 823860
FirstChildUserNameTAG: mike111
FirstChildCreateTimeTAG: 2013-03-25T20:42:49Z
FirstChildVoteTAG: 1
IndexTAG: 312
TitleTAG: to the staff, problem with score count
i have submitted the exersise but when i look in the progress tab i see there were 15 questions so my score is lower. even though in reality there are 10 questions.
is it a computer error, or have i missed some questions?
Ori
UserIdTAG: 1028095
UserNameTAG: orihorvitz
CreateTimeTAG: 2013-03-25T11:53:59Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: There are 15 **points**, not questions. If you look in the Exercise Set, it says how many points each question is worth, and that's what you should compare with the Progress tab ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T13:03:24Z
FirstChildVoteTAG: 1
IndexTAG: 313
TitleTAG: [staff] some statistics about the course
Hallo from Italy.
It would be nice to know
- How many are we now (e.g. how many did the midterm)
- Where are we from
- How old are we
Thank you very much for your work!
UserIdTAG: 1096469
UserNameTAG: sergio_chiodo
CreateTimeTAG: 2013-03-25T11:02:39Z
VoteTAG: 15
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Hi Sergio.
I agree: statistics about the class are welcome.
(from Italy me too).
FirstChildUserIdTAG: 1210009
FirstChildUserNameTAG: GIAN66
FirstChildCreateTimeTAG: 2013-03-25T17:43:35Z
FirstChildVoteTAG: 2
FirstChildTAG: I read somewhere number 47 000, but I don't know where.
To the second point, it could be useful https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/students-directory/_dir/
- some people wrote there their name
FirstChildUserIdTAG: 884187
FirstChildUserNameTAG: Madelenka
FirstChildCreateTimeTAG: 2013-03-25T18:21:50Z
FirstChildVoteTAG: 3
FirstChildTAG: I'd love to know where my overall score falls in comparison with others. I seem to recall Prof. A. saying she doesn't using averages for her regular classes ... percentile I think (oh goodness, now I'm forgetting the easy stuff!)
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-25T20:36:18Z
FirstChildVoteTAG: 3
IndexTAG: 314
TitleTAG: Everybody invited to participate in the next 12 hours(group study for the final)
(This discussion will only serves as valuable resource for the final by the contribution us hopefully we will be able to answer all question before the forum close)
Will I awake this morning to find an additional practice for the final that apparently wasn’t there when I did ex set 12, unfortunately I have to go to work but to start this discussion let's say I assume that the answer of the first question in additional practice for the final is the outcome of the division of the (percentage for interval 15-25/(25-15))which will equal=?? Or else so what is your response .
UserIdTAG: 810363
UserNameTAG: anht
CreateTimeTAG: 2013-03-25T10:43:06Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: so what you try to say is that (44%/10 years)==4.4 % per years
FirstChildUserIdTAG: 1019661
FirstChildUserNameTAG: wnu
FirstChildCreateTimeTAG: 2013-03-25T10:55:57Z
FirstChildVoteTAG: 2
SecondChildTAG: please give an additional explanation of additional practice problem set-2/ problem 4(B) and 4(C). basis of the estimated of percentiles.
Thanks
Abhinaya
SecondChildUserIdTAG: 1195486
SecondChildUserNameTAG: Abhipuri
SecondChildCreateTimeTAG: 2013-03-25T11:18:14Z
SecondChildVoteTAG: 0
SecondChildTAG: sorry I meant 4(A) and 4(C)
SecondChildUserIdTAG: 1195486
SecondChildUserNameTAG: Abhipuri
SecondChildCreateTimeTAG: 2013-03-25T11:20:13Z
SecondChildVoteTAG: 0
SecondChildTAG: you should know that 4(a) need alittle caculation to pick the right answer,the calculation is similar to that of the previous qestion with the only diferent that r is apostive range (r1=0,r2=.99)less than 1 ,z of the 70th percentile=.52, i think thats more than enough to get your answer. asimilar tech also work for 4c
SecondChildUserIdTAG: 1019661
SecondChildUserNameTAG: wnu
SecondChildCreateTimeTAG: 2013-03-25T12:43:30Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks!!
SecondChildUserIdTAG: 1195486
SecondChildUserNameTAG: Abhipuri
SecondChildCreateTimeTAG: 2013-03-25T17:10:33Z
SecondChildVoteTAG: 0
IndexTAG: 315
TitleTAG: Dear Prof A.
Hi Prof, I really am getting a lot out of the the optional practice at the end of section 8. I have a learning disability that is helped by repetitiveness so I can go over and over this practice set to confirm my learning. This is much better than the practice sets at the end of each lecture as there is more to do i think?
Any way so my point is, for 2.2 and 2.3 I would personally think more practice sets would help others as well
Just a thought, love the learning
UserIdTAG: 7545
UserNameTAG: jasontimothyjones
CreateTimeTAG: 2013-03-25T09:42:11Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: OK, thanks for the feedback. If students aren't bothered by problems not in the EdX "click a button" format, then in the next course I'll be happy to upload any practice problems I have from campus courses. They are a bit repetitive, as you point out, but that was in some ways the purpose - "exercise," literally. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-25T15:01:05Z
FirstChildVoteTAG: 8
SecondChildTAG: not bothered about the format at all, actually it sort of stops me from checking the answers as I go, just get on and check the answers at the end
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-03-25T15:40:49Z
SecondChildVoteTAG: 0
SecondChildTAG: They are indeed usful.In fact reptitive prolems often drive homw a point.I remember slogging with Hall and Knight Algebra to prove humungous equations are = zero ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-25T16:57:25Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree that the extra practice is helpful. I don't mind at all that it's not in the EdX format. This class has been excellent. I'm looking forward to 2.2X
SecondChildUserIdTAG: 1143871
SecondChildUserNameTAG: CarolPeterman
SecondChildCreateTimeTAG: 2013-03-25T21:15:04Z
SecondChildVoteTAG: 0
IndexTAG: 316
TitleTAG: To the staff
I submitted Exercise set 12 but I can not see any progress ...
Is this a system error?
UserIdTAG: 1098889
UserNameTAG: charmy
CreateTimeTAG: 2013-03-25T09:32:58Z
VoteTAG: 4
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: The Exercise set 12 scores might be lower then your other Exercise set scores submitted till now therefore the scores for this set are deducted. Check the "x" mark at the bottom of your two lowest graded exercises, this might be one of them!
FirstChildUserIdTAG: 1247915
FirstChildUserNameTAG: Iliri2013
FirstChildCreateTimeTAG: 2013-03-25T10:18:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you ,but it wasn't my two lowest scores.
I don't know what to do.
SecondChildUserIdTAG: 1098889
SecondChildUserNameTAG: charmy
SecondChildCreateTimeTAG: 2013-03-25T11:09:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Did the bar for ES12 go up?
In the ES12 page, do you have green ticks and/or red Xs next to each answer?
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-25T13:16:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Like others, my progress is also not registering.
SecondChildUserIdTAG: 730654
SecondChildUserNameTAG: N0ra
SecondChildCreateTimeTAG: 2013-03-26T00:31:32Z
SecondChildVoteTAG: 0
IndexTAG: 317
TitleTAG: Late enrollent
Just enrolled in this course and just realize that the final dead line is tomorrow, should I wait for next edition or may I fulfill due assignments?
UserIdTAG: 1476046
UserNameTAG: miguelnovais
CreateTimeTAG: 2013-03-25T09:14:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You technically have the chance. ES12 adds as much as 5% to the total grade, and the final tomorrows adds as much as 30%. So if you ace both, you get the certificate.
For learning purposes, however, rushing is never good, so it's probably a better idea to wait for the next edition. (Though nobody stops you from having an head start by going through the current material, ignoring the grades)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T13:10:24Z
FirstChildVoteTAG: 1
IndexTAG: 318
TitleTAG: regression relation
if r1 and r2 are two regression coefficient then sign of r1 and r2 depends on ..?
UserIdTAG: 85421
UserNameTAG: nitesh101285
CreateTimeTAG: 2013-03-25T08:41:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: On whether the association between the data is positive or negative.
In other words, if you take an *x* below/above average, and you look at the *y*, if *y* is also below/above average, then *r* is positive. Otherwise *r* is negative.
Problem 2 of ES9 is a good example of this.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T13:14:40Z
FirstChildVoteTAG: 0
IndexTAG: 319
TitleTAG: stat2.2x and stat2.3x
Stat2.2X ^ Stat2.3X - I like this idea!!!!! hopefully we can start soon :)
UserIdTAG: 1347095
UserNameTAG: Lukasz87
CreateTimeTAG: 2013-03-25T08:20:38Z
VoteTAG: 2
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 0
IndexTAG: 320
TitleTAG: Any hints on how to solve 3A please???!!!
I have looked upon the explanations on the threads below, in order to find some hints on how to solve 3A. I have used the applet and found the **z** for 50% of the area under the normal distribution. I have also found the r.m.s that can be used as an SD in the calculation. Then, I tooked the **z** values and converted them into inches, but still got the wrong answer. Any ideas on how to solve this??? Don´t give answers, just guide through the correct path. I have one submission left.
Thanks in advance!!!
Ale
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-25T06:26:08Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Look about 19 minutes into Lec 8.2. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-25T07:01:58Z
FirstChildVoteTAG: 1
FirstChildTAG: > I have used the applet and found the z for 50% of the area under the normal distribution.
Make sure you've got this part right. You're **not** looking for a percentile here.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-25T13:19:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Klionheart
SecondChildUserIdTAG: 441203
SecondChildUserNameTAG: etstowell
SecondChildCreateTimeTAG: 2013-03-25T16:27:06Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you klionheart
SecondChildUserIdTAG: 1036551
SecondChildUserNameTAG: Geetagrg
SecondChildCreateTimeTAG: 2013-03-25T19:13:47Z
SecondChildVoteTAG: 0
IndexTAG: 321
TitleTAG: ES 12 - scores
ES 12 - scores have not been posted to progress, any fix?
UserIdTAG: 935061
UserNameTAG: _Martha
CreateTimeTAG: 2013-03-25T05:32:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Thank you Prof. A. and/or staff for sorting out the phantom extra exercise set - my score looks better now.
Kit.
FirstChildUserIdTAG: 20821
FirstChildUserNameTAG: KitR
FirstChildCreateTimeTAG: 2013-03-25T08:42:59Z
FirstChildVoteTAG: 0
IndexTAG: 322
TitleTAG: Lec 8.2 Residuals slide confusion
In the residual slide where you showed the error as the distance between the actual point and the regression line, shouldn't the line representing the distance be perpendicular to the *regression line* rather than go straight down below?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-25T01:31:32Z
VoteTAG: 0
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 2
FirstChildTAG: The error of estmate is inY so it will be vertical.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-25T02:30:41Z
FirstChildVoteTAG: 0
FirstChildTAG: > shouldn't the line representing the distance be perpendicular to the regression line rather than go straight down below?
In OLS (ordinary least squares) you take the vertical distance to the regression line.
You can take the perpendicular distance too. This is Orthogonal Regression (Total least squares) where you assume that there is an error in X and Y. It is related to Principle Components.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-25T03:14:37Z
FirstChildVoteTAG: 0
IndexTAG: 323
TitleTAG: Accuracy for Q 3B
Pls work with rounded numbers in this exercise
otherwise your answer will not be correct
UserIdTAG: 349683
UserNameTAG: rsar33
CreateTimeTAG: 2013-03-25T01:25:55Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: I was wondering if that's why I got it wrong. Rounded to the nearest what though? And do you mean for the calculations as well or only for the results?
FirstChildUserIdTAG: 67837
FirstChildUserNameTAG: Friederike
FirstChildCreateTimeTAG: 2013-03-25T10:41:37Z
FirstChildVoteTAG: 1
SecondChildTAG: Use 2 decimals everywhere, and you should be fine :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-25T13:21:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Is there a policy for how many places to round to for the intermediate calculations? I have been working with 5 decimal places until the final answer, at which point I would round to 2 or 3, but this caused some trouble with E-12 P3C.
SecondChildUserIdTAG: 252779
SecondChildUserNameTAG: msushi
SecondChildCreateTimeTAG: 2013-03-26T00:10:49Z
SecondChildVoteTAG: 0
SecondChildTAG: I used upto four decimals and my answer was marked wrong :-(
SecondChildUserIdTAG: 1049248
SecondChildUserNameTAG: Rnandy
SecondChildCreateTimeTAG: 2013-03-26T02:07:11Z
SecondChildVoteTAG: 0
IndexTAG: 324
TitleTAG: All my Math was right but not the use of the App
The use of the App was so bad, all my math correct but the use of it all wrong this is frustrating
UserIdTAG: 903197
UserNameTAG: Ruthgarciacorrales
CreateTimeTAG: 2013-03-25T01:23:09Z
VoteTAG: 3
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 325
TitleTAG: Percentage In The Certificates
The overall percentage should be mentioned in the certificates. Avoiding percentage in the certificates is going to discourage serious students and encourage mediocrity in long run.
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-25T01:05:00Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Then you should present a well reasoned argument regarding this to the edX people. This is their policy for the entire edX platform, including proctored certificates.
They generate and issue the certificates, not the course staff.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-25T02:16:00Z
FirstChildVoteTAG: 2
FirstChildTAG: Is it possible that the intent of the low pass mark (35%) and 'not mentioning overall percentage' is because the completion certificate is not meant to demonstrate a student's competency? Perhaps it is only meant to demonstrate a student's motivation towards self advancement, through self-study. The courses are 100% free and, in my opinion, the quality of instruction for Stat2.1x has been exceptional! Perhaps the value offering is free knowledge at a quality that may be compared to what you may find at tuition-costing universities. What is not being offered is free recognition at a level that may be compared to what you may find at tuition-costing universities. Perhaps the constraints inherent to the paradigm under which these course offerings operate (e.g., 100% free), is such that the degree of recognition that students stand to gain is already reasonable?
FirstChildUserIdTAG: 1049690
FirstChildUserNameTAG: ianlau
FirstChildCreateTimeTAG: 2013-03-25T03:54:38Z
FirstChildVoteTAG: 6
SecondChildTAG: > What is not being offered is free recognition at a level that may be compared to what you may find at tuition-costing universities.
But that is what some want the certificate to mean. My uni degrees don't have grades on them, and I don't expect a mooc certificate to have them either.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-25T04:26:25Z
SecondChildVoteTAG: 0
SecondChildTAG: "..the completion certificate is not meant to demonstrate a student's competency? Perhaps it is only meant to demonstrate a student's motivation towards self advancement, through self-study.." How does certificate without a mention of percentage conveys student's motivation towards self advancement more effectively than one that mentions it . And also how does certificate , even without percentage , doesn't demonstrate student's competence and does not offer free recognition! This whole argument is fallacious and it seems real intention of the opposition here is something else than genuine concern for self advancement through self study or relative aloofness from recognition. Proctored exams are always welcome but Prof. Ani has already told that that option is not available this time . Well that is a constraint . One can compensate for that by mentioning it along with percentage or as a subscript. So that brings us back to the original point I raised in this post . Let me reword my argument in the form of two questions: Is drive for scoring higher percentage deplorable ? If not then should forum like edX ignore it ?
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-25T08:18:41Z
SecondChildVoteTAG: 0
SecondChildTAG: " My uni degrees don't have grades on them, and I don't expect a mooc certificate to have them either." The two are not comparable atleast as far as their not mentioning the percentage is concerned . In the case of University degree, percent is provided separately by the institute concerned with the course. That's why I raised this issue here. One thing more I can add here is that percentage of those below certain threshold need not be mentioned. And now I am not going to take it any further because I didn't post it for any personal motive. If there is any truth in my submission it will see the light sometime!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-25T08:50:30Z
SecondChildVoteTAG: 0
FirstChildTAG: **Adding course % to a certificate would bring about comparisons with traditional university level classes**. That comparison would be unfair.
In a traditional university class, including an on-line course, (ones that I pay for) I would expect and receive the one-on-one attention of either an instructor or a teaching assistant when I sought that kind of attention. I could receive additional explanation and clarification of points I wasn't sure of.
None of that is possible in a MOOC. Therefore, comparison with traditional university classes is unfair.
That said, I feel the value of what I've received from this course exceeds by several orders of magnitude what I paid for it (that's supposed to be funny) and I'm better for the experience.
I'll be back for 2.2x!
FirstChildUserIdTAG: 876324
FirstChildUserNameTAG: BrianDeering
FirstChildCreateTimeTAG: 2013-03-25T17:50:07Z
FirstChildVoteTAG: 0
SecondChildTAG: My motivation for the suggestion is not comparison . The two systems are actually complementary and not supplementary. For more on this I am qouting below my reply to another similar post, in slightly different context (titled : certificates will be awarded to those who score 35%...) ... ...("I'm not sure why there needs to be a grade on the certificate in order to learn the material, which is what I presume a serious student has as the main motivation.") Well, seems to be right . But then I don't understand why there needs to be a certificate at all, in order to learn the material, which though correctly presumed what a serious student has as the main motivation. ( " A serious student is likely to be seeking a degree or some sort of measured badge of achievement enabling the furthering of the student's goals.." ) So you seem to be arguing that if anybody is serious then uni degree/course is all that counts and edX course are ' well some sort of learning or at the best supplementary learning that is available free of cost ( "There must be another reason for serious students to take the class. I argue that serious students wishing to learn statistics can do so essentially without cost." ) . And it is precisely the thinking like that , what has made me write this post . In present times online education , institutions and MOOCs have changed all these dogmas and have come to acquire their own place . And then MOOCs by forum of such a standing as edX's ! This is not to underplay the importance of mainstream education and should be read in proper context only. But if MOOCs have limititions so do have mainstream education curricula . Otherwise there would have been no need of MOOCs in the first place . Let's try to answer a few questions before we go further in arguments . Why percentage/grading is done anywhere in educational curricula ? Is drive for higher percentage something deplorable, one that ought to be discouraged by edX ? Is that full justice to the vision and efforts of dedicated team working for edX and talent of luminary staff ? All these questions become even more pertinent when we consider these in relation to courses like stat2.1x , courses that have a connect to wide gaps in the needs of society for research in human health, livelihood etc.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-25T19:15:28Z
SecondChildVoteTAG: 0
FirstChildTAG: I don´t think a certificate with grade percentage is important in a MOOC.
However it would be interesting to have the data for all the students. Then we can calculate the averages, medians, quartiles, SD, etc, etc....
FirstChildUserIdTAG: 908105
FirstChildUserNameTAG: LuizAraripe
FirstChildCreateTimeTAG: 2013-03-25T19:08:16Z
FirstChildVoteTAG: 1
IndexTAG: 326
TitleTAG: Problem 3C
Regarding 3B guys,make sure your rms is really really accurate and you should hit the mark .
UserIdTAG: 1181029
UserNameTAG: Ilya19
CreateTimeTAG: 2013-03-25T01:00:34Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 327
TitleTAG: How to find best fit line or curve for a scatter and some general doubts!
Dear Prof. Adhikari,
Let us say I have a scatter plot for two variable, as a result of some observation. Now what is the best way to find the association between the two variables? I understand that by looking at it I should get an idea whether it is linear or not, but other than linear what are the types of associations and are we going to discuss them?
Also, we did not discuss the significance of r^2 (r squared) in this course. As far as I know, and please correct me if I am wrong, higher the value of r squared, higher is the liner association (probably just because, for example, r squared 0.99 is a better correlation than r equal to 0.99).
Also in stat 2.2 or in 2.3 are we going to study tests of significance?
Thank you for such a wonderful course!
UserIdTAG: 1149334
UserNameTAG: NitinJindal
CreateTimeTAG: 2013-03-25T00:44:05Z
VoteTAG: 0
CoursewareTAG: Section 6: Relation between two variables / Lec 6.1 Scatter Diagrams
NumberOfReplyTAG: 1
FirstChildTAG: I'll take your last question first:
In 2.3X we'll cover several tests of significance.
To fit a non-linear curve you're going to need multiple regression which is outside the scope of Stat 2X. E.g. to fit a quadratic, you'd try to estimate y by the best linear combination of both x and x^2.
However, based on what you know in Stat 2.1X, you know enough to get a sense of what the r^2 of multiple regression is all about. If you accept that people have worked out how to get the least squares estimates even when there are several independent variables, then some things you know now turn out to still be true:
a) residual = actual y - estimate of y
b) average of residuals = 0; r.m.s. of residuals = fraction*SDy
A fraction can always be written as sqrt(1-w), so just define r^2 = w and your formula for the r.m.s. of the residuals is sqrt(1-r^2)*SDy.
That's pretty much the definition of what's called the "multiple r^2".
Everything we said about the r.m.s error still holds: the bigger the r^2, the smaller the rough size of the r.m.s. error, and so in that sense the prediction is better with a bigger r^2. However, there are many subtleties with understanding and using this, and it's prone to misuse; not easy to talk about at the Stat 2X level. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-25T04:38:56Z
FirstChildVoteTAG: 3
IndexTAG: 328
TitleTAG: Don't miss the second post in stat2x blog
Unfortunately comments are not open in Stat2X blog. So I comment briefly here.
Don't miss that blog! Don't miss this:
http://stat2x.blogspot.com.es/2013/03/why-do-this-press-asked-philip-if-hes.html
I cannot find better and more noble motivations than your two motivations, prof. Ani. When I read these things, whose spirit I absolutely share, I feel not only gratitude but also admiration and a deep sense of confirmation. Confirmation of a thought that I've always had, even when I was a child (only a wordless emotion in that time): teaching is a vocation, the vocation to give others a precious gift, as a few (our great professors) gave us in a timeless and unforgettable moment of our life. Thanks Prof!
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-25T00:28:02Z
VoteTAG: 10
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Thanks for the link. It was a good read.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-25T01:20:11Z
FirstChildVoteTAG: 1
FirstChildTAG: Very noble thoughts indeed . Money means a lot . But money is not everything . Fragrance of flower is priceless . We are lucky that such an enlightened soul is our mentor and that we have got the opportunity to come in contact ( 'sanidhay' ) with her , at least in some sense !
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-25T02:41:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you atopos fo such in insight! :)
This is really motivating and encouraging, such people as Prof. Adhicari.
Thank you very much Prof.!
FirstChildUserIdTAG: 1148146
FirstChildUserNameTAG: Prostova
FirstChildCreateTimeTAG: 2013-03-25T08:47:06Z
FirstChildVoteTAG: 0
FirstChildTAG: After reading your second post, I only have three simples words for both of you (and for the rest of the staff) THANKS A LOT
FirstChildUserIdTAG: 1002821
FirstChildUserNameTAG: Urimare
FirstChildCreateTimeTAG: 2013-03-25T16:03:41Z
FirstChildVoteTAG: 0
IndexTAG: 329
TitleTAG: Question 1B
What can we say about the scatterplot given the data? Can we know whether it is football shaped?
I check the correlation. It is .45. It leads me to suspect that the scatter is football shaped. Can I be sure? I, for one, am not.
My queries:
Is it right to check the correlation coefficient to guess the shape of the scatterplot? Does a high positive or high negative correlation imply a football shape? Is t necessary to know the significance of the correlation coefficient?
Thanks for your help..
UserIdTAG: 1139936
UserNameTAG: SundarV
CreateTimeTAG: 2013-03-24T23:54:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Try calculating income in the multiples of its SD.you will reach to answer
FirstChildUserIdTAG: 1416809
FirstChildUserNameTAG: mehrotravinit
FirstChildCreateTimeTAG: 2013-03-25T00:23:49Z
FirstChildVoteTAG: 0
FirstChildTAG: The correlation is not the thing to look at. Is that what you are suggesting? Can there be a football shaped scatter if r=0?
FirstChildUserIdTAG: 1139936
FirstChildUserNameTAG: SundarV
FirstChildCreateTimeTAG: 2013-03-25T03:46:34Z
FirstChildVoteTAG: 0
IndexTAG: 330
TitleTAG: Frustrating
Worked on this for hours, I had the correct answers I just put on number not the problem to get to it, now I remember the example in the lectures!!! How sad.
UserIdTAG: 1115165
UserNameTAG: Abbyjohnson
CreateTimeTAG: 2013-03-24T23:08:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 331
TitleTAG: hi
hi,i would like to ask about the applet for the normal curve,i find the answer on question 3c but i don't knwo what percentage is the result because i don't have the table..can someone help me?
UserIdTAG: 1420568
UserNameTAG: mikelpishtari
CreateTimeTAG: 2013-03-24T22:37:10Z
VoteTAG: 0
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 0
IndexTAG: 332
TitleTAG: For the staff : Problem with my score in 2A
Dear Staff,
I got the answer wrong in 2A but I had a check and the point in 2a. I completely flunk it this exercise so any correction won't change my overall result.
Thanks to correct it or explain me why I got the point.
UserIdTAG: 1044317
UserNameTAG: Mlaknin
CreateTimeTAG: 2013-03-24T21:26:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 333
TitleTAG: Is anyone having problems with SticiGUI applets?
I have tried every imaginable browser, Chrome, Firefox, and IE9, and I can't get some of the SticiGui applets to work. The two I know don't work off the top of my head are the Confidence Intervals one, and the Normal Curve one - this is a problem because I've already had issues where one of these was on a test and I couldn't answer some questions. Does anyone else have this problem? Has anyone solved it? Is it possible the applets themselves are just broken and need to be fixed?
UserIdTAG: 1359572
UserNameTAG: gabe0727
CreateTimeTAG: 2013-03-24T20:56:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Have you read this?
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/browser-setting-appletsif-they-do-not-work/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-24T21:47:40Z
FirstChildVoteTAG: 0
IndexTAG: 334
TitleTAG: Applet Link
Here is the applet link: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
UserIdTAG: 1292508
UserNameTAG: gaberen
CreateTimeTAG: 2013-03-24T20:53:36Z
VoteTAG: 10
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 335
TitleTAG: help for 3b
icant solve
UserIdTAG: 578995
UserNameTAG: Gehan_Basiony
CreateTimeTAG: 2013-03-24T20:08:35Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: similar to practice problem 1D.
FirstChildUserIdTAG: 278857
FirstChildUserNameTAG: suzyQ2012
FirstChildCreateTimeTAG: 2013-03-25T04:53:37Z
FirstChildVoteTAG: 0
SecondChildTAG: No, it is not the same. The calculation is like in lecture 8.2 on p.6, but when you use applet you should take only one tail. I made a good calculation, but my answer was wrong, I think because I don't really understand all the English terms like "over", "within", "below" etc. Or maybe it is easy to say my English isn't good than think more ;)
SecondChildUserIdTAG: 1071309
SecondChildUserNameTAG: _Helena_
SecondChildCreateTimeTAG: 2013-03-25T18:47:29Z
SecondChildVoteTAG: 0
IndexTAG: 336
TitleTAG: Time This is Due?
I know exercise 12 is due on Monday but what is the actual closing time of the homework assignment? Is it 23:59 GMT Sunday night or 23:59 GMT Monday night? I've had some family issues to tend to the past few days and I will only now be able to get to Ex. Set 12 tonight. I've already passed the course but I still want to do as well as possible.
UserIdTAG: 87103
UserNameTAG: fjbasile
CreateTimeTAG: 2013-03-24T20:06:26Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: > graded exercises due March 25 23:30
The 25th is Monday, isn't it?
So, 23.30 GMT Monday Night. You still have 1 day :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T20:11:04Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks!
SecondChildUserIdTAG: 87103
SecondChildUserNameTAG: fjbasile
SecondChildCreateTimeTAG: 2013-03-24T20:16:47Z
SecondChildVoteTAG: 0
IndexTAG: 337
TitleTAG: I have problem
I'm on a trip and exactly from Tuesday I can't access internet, what can I do?
UserIdTAG: 1235821
UserNameTAG: psychzd
CreateTimeTAG: 2013-03-24T19:38:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you are unavailable for the entire duration of the final, you won't be able to do it. If you already have $35\%$ you will get the certificate.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-24T21:45:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks...
SecondChildUserIdTAG: 1235821
SecondChildUserNameTAG: psychzd
SecondChildCreateTimeTAG: 2013-03-25T07:17:10Z
SecondChildVoteTAG: 0
IndexTAG: 338
TitleTAG: Certificates of completion will be awarded to those who score 35% or higher overall
Hi Everyone!!! As final exam is closing up, I'm so very interested about question "How exactly I'll get certificate of completion" Hope U interested too, and maybe know the answer!!!
UserIdTAG: 1103272
UserNameTAG: Soroka1
CreateTimeTAG: 2013-03-24T19:10:23Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Your title includes the answer :D
See the "Total" bar in the "Progress" Bar? That's the overall. If you have 35% or more there, you'll get the certificate. The final can add as much as 30% to that.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T19:52:41Z
FirstChildVoteTAG: 0
SecondChildTAG: It's understood!!! The question - will it be paper sent by post, or email and i'll have to print it or something else!
SecondChildUserIdTAG: 1103272
SecondChildUserNameTAG: Soroka1
SecondChildCreateTimeTAG: 2013-03-24T20:26:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh! Sorry for the confusion.
A merhutchin says, it's a Printable PDF Download, and yes, it should include your full name as entered into EdX ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-24T20:36:49Z
SecondChildVoteTAG: 0
SecondChildTAG: А к чему это подмигивание?)
SecondChildUserIdTAG: 1103272
SecondChildUserNameTAG: Soroka1
SecondChildCreateTimeTAG: 2013-03-25T18:29:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Почему нет?
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-26T00:58:20Z
SecondChildVoteTAG: 0
SecondChildTAG: tanks dear friends
SecondChildUserIdTAG: 1078818
SecondChildUserNameTAG: Jamili
SecondChildCreateTimeTAG: 2013-03-29T08:08:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Your certificate will be available to download as a pdf. When you log in to edx, you'll see a link that says "Download certificate" (or something like that) underneath the Stat2.1x heading.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-24T20:10:03Z
FirstChildVoteTAG: 0
SecondChildTAG: oh, cool. will be there my name and surname in it?
SecondChildUserIdTAG: 1103272
SecondChildUserNameTAG: Soroka1
SecondChildCreateTimeTAG: 2013-03-24T20:27:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-24T22:45:14Z
SecondChildVoteTAG: 0
FirstChildTAG: edX has a page of FAQs that explain all this. Certificates are pdf, and no grades are listed. A link will appear on your dashboard.
Make sure you have your correct name listed on your dashboard, as that is the name that will be put on the certificate. And unless there is a stuff up on their end, the certificate will not be reissued because you suddenly realise your name was wrong or spelt incorrectly.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-24T21:43:59Z
FirstChildVoteTAG: 0
FirstChildTAG: Percentage scored should be mentioned in the certificate. Avoiding percentage in the certificates is only going to discourage serious students and encourage mediocrity.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-25T01:14:04Z
FirstChildVoteTAG: 0
SecondChildTAG: There will certainly be people that are discouraged because of that, but I'm not sure it is well founded discouragement. In general, (I know there are people saying otherwise, I'm only arguing the general case), the edx certificate does not count for college credit. A serious student is likely to be seeking a degree or some sort of measured badge of achievement enabling the furthering of the student's goals. An edx course that does not result in college credit doesn't help the student earn credits towards a degree merely by publishing a grade on the certificate.
There must be another reason for serious students to take the class. I argue that serious students wishing to learn statistics can do so essentially without cost. Perhaps they may be able to skip an introductory course in statistics by passing some test. Maybe it's possible to earn a credit that way. I'm not sure why there needs to be a grade on the certificate in order to learn the material, which is what I presume a serious student has as the main motivation.
While I don't think your conclusion is sound, I am in favor of having the grade on the certificate.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-25T02:49:33Z
SecondChildVoteTAG: 0
SecondChildTAG: ("I'm not sure why there needs to be a grade on the certificate in order to learn the material, which is what I presume a serious student has as the main motivation.") Well, seems to be right . But then I don't understand why there needs to be a certificate at all, in order to learn the material, which though correctly presumed what a serious student has as the main motivation. ( " A serious student is likely to be seeking a degree or some sort of measured badge of achievement enabling the furthering of the student's goals.." ) So you seem to be arguing that if anybody is serious then uni degree/course is all that counts and edX course are ' well some sort of learning or at the best supplementary learning that is available free of cost ( "There must be another reason for serious students to take the class. I argue that serious students wishing to learn statistics can do so essentially without cost." ) . And it is precisely the thinking like that , what has made me write this post . In present times online education , institutions and MOOCs have changed all these dogmas and have come to acquire their own place . And then MOOCs by forum of such a standing as edX's . This is not to underplay the importance of mainstream education and should be read in proper context only. But if MOOCs have limititions so do have mainstream education curricula . Otherwise there would have been no need of MOOCs in the first place . Let's try to answer a few questions before we go further in arguments . Why percentage/grading is done anywhere in educational curricula ? Is drive for higher percentage something deplorable, one that ought to be discouraged by edX ? Is that full justice to the vision and efforts of dedicated team working for edX and talent of luminary staff ? All these questions become even more pertinent when we consider these in relation to courses like stat2.1x , courses that have a connect to wide gaps in the needs of society for research in human health, livelihood etc.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-25T12:59:29Z
SecondChildVoteTAG: 0
SecondChildTAG: > But then I don't understand why there needs to be a certificate at all
Indeed, there does not need to be one, but still, game theory suggests that powerful motivation lies in giving people a badge to display.
> So you seem to be arguing that if anybody is serious then uni degree/course is all that counts
I did mention a degree, but added this: a measured badge of achievement enabling the furthering of the student's goals.
I left the statement wide open so as to allow the first portion of that particular statement to provide an example, and the second part to give the general case. The case being that a serious student has goals, and time spent in this course should help the student to achieve those goals. But, I have serious doubts that a grade posted on the certificate does anything more than the certificate itself does.
Going back to your original post, you said "Avoiding percentage in the certificates is only going to discourage...". The use of "only" there is what I think is the weakest part of your statement. I will grant you that many people will be discouraged by the lack of a grade.
I don't want to skip past the new questions you posed. Let me just say that those are great questions and certainly would deepen this discussion, but let me just touch on grading, since it goes to the heart of my point. Grades mean something when they can be counted on as being an accurate portrayal of academic performance. It's hard to see how a mooc could provide grades that can be relied upon. That's not to say that at some point in the future that won't be the case.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-26T00:22:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Is it possible that the intent of the low pass mark (35%) and 'not mentioning percentage in the certificate' is because the completion certificate is not meant to demonstrate a student's competency? Perhaps it is only meant to demonstrate a student's motivation towards self advancement, through self-study. The courses are 100% free and, in my opinion, the quality of instruction for Stat2.1x has been exceptional! Perhaps the value offering is free knowledge at a quality that may be compared to what you may find at tuition-costing universities. What is not being offered is free recognition at a level that may be compared to what you may find at tuition-costing universities. Perhaps the constraints inherent to the paradigm under which these course offerings operate (e.g., 100% free), is such that the degree of recognition that students stand to gain is already reasonable?
FirstChildUserIdTAG: 1049690
FirstChildUserNameTAG: ianlau
FirstChildCreateTimeTAG: 2013-03-25T03:59:55Z
FirstChildVoteTAG: 3
SecondChildTAG: ("..the completion certificate is not meant to demonstrate a student's competency? Perhaps it is only meant to demonstrate a student's motivation towards self advancement, through self-study..") How does certificate without a mention of percentage conveys student's motivation towards self advancement more effectively than one that mentions it . And also how does certificate , even without percentage , doesn't demonstrate student's competence and does not offer free recognition! This whole argument is fallacious . Although I can't comment on intent of edX but perhaps real intention of the opposition here is something else than a genuine concern for self advancement through self study or relative aloofness from recognition. But still, one thing more I can add here is that percentage of those below certain threshold may not be mentioned. Proctored exams are always welcome but Prof. Ani has already told that that option is not available this time . Well that is a constraint . One can compensate for that by mentioning it along with percentage or as a subscript. So that brings us back to the original point I raised in this post . So let me reword my argument in the form of the same two questions again: Is drive for scoring higher percentage deplorable ? If not then should forum like edX ignore it ?
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-25T13:24:43Z
SecondChildVoteTAG: 0
IndexTAG: 339
TitleTAG: Exercise 13 ????
Where is exercise 13? Maybe someone from the Staff could explain that?
UserIdTAG: 1256261
UserNameTAG: ilow
CreateTimeTAG: 2013-03-24T18:45:25Z
VoteTAG: 0
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 2
FirstChildTAG: I have the same problem. I don't understand what is going on.
FirstChildUserIdTAG: 1256305
FirstChildUserNameTAG: rozanska
FirstChildCreateTimeTAG: 2013-03-24T18:48:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Was an error. Has been removed :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T19:53:26Z
FirstChildVoteTAG: 0
SecondChildTAG: I hear an echo.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-24T21:41:44Z
SecondChildVoteTAG: 0
IndexTAG: 340
TitleTAG: exercise 13
Hello I've entered the Progress section and can see an exercise 13?
The program considers this one as one of my lower scores so my average is being slipped down a bit, does this happen to anyone? can someone else check and see on progress if an exercise 13 appears? Thanks a lot
UserIdTAG: 896461
UserNameTAG: cecimatho
CreateTimeTAG: 2013-03-24T18:10:51Z
VoteTAG: 0
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 1
FirstChildTAG: Was an error. Has been removed :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T19:53:19Z
FirstChildVoteTAG: 0
IndexTAG: 341
TitleTAG: How to read documentation in R
By reading comments in the forum and from my own experience I get the impression that one of the major difficulties encountered by R users is its very technical documentation.
I've written a wiki page with an example of how I try to approach to the R documentation, at least for relatively simple functions:
https://www.edx.org/wiki/Stat2.1x/R/scaleDoc
Hope it'll be useful.
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-24T17:52:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 342
TitleTAG: Tyche's line
I do not understand the purpose of Tyche's line. How does Tyche calculate it? What is the instructor trying to prove by stating Tyche's line?
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-24T17:49:55Z
VoteTAG: 1
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 2
FirstChildTAG: Tyche's line is in our imaginations. Formally, it is part of what people call "the regression model." The model is a set of assumptions, one of which is that the scatter diagram that we see is generated by errors added on to points an unknown line. That unknown and invisible line is what I'm calling Tyche's line. A standard inference problem is to try and estimate it by the regression line.
In Stat 2.1X, that's not what we're doing. We're simply finding the best (i.e. least squares) line to put through a scatter diagram. We're not making any assumptions about how the scatter diagram was generated. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-24T18:57:38Z
FirstChildVoteTAG: 6
FirstChildTAG: Tyche is from a greek word (Τύχη) and means fate, luck!
Angelos
FirstChildUserIdTAG: 838366
FirstChildUserNameTAG: aapapado
FirstChildCreateTimeTAG: 2013-03-24T21:17:18Z
FirstChildVoteTAG: 1
SecondChildTAG: Which is absolutely synonymous with the term "Fortune", stemming from the Latin "Fortuna", the Roman equivalent of the Goddess Τύχη. Plus, I have the suspicion that the English pronunciation is closer to the original ancient "υ" that the flat "ee" sound used in modern Greek.
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-25T20:42:34Z
SecondChildVoteTAG: 0
IndexTAG: 343
TitleTAG: Problem 1D. Slope in standard units but intercept not??
Looking at the explanation for 1D, would someone please explain why SAT score is first put in standard units to get the slope? Then the rest of the regression estimate equation uses non-standard units. Or am I totally missing something?
Thanks!
UserIdTAG: 1252523
UserNameTAG: Willabe
CreateTimeTAG: 2013-03-24T17:49:23Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 2
FirstChildTAG: We're not using the regression line there. Just the regression estimate using Standard Units and its transformation equations.
First the score of 500(the **x** value) is converted into SU. Then the result is regressed to find **y** in SU, and *that* is converted back to the original units for the GPA, to find the actual estimated **y**.
This y is the average of a sub-dataset of GPAs including only those students with a SAT Score of 500. This dataset uses the RMS for its SD, instead of the original SD of 0.35.
Now that you have this information, you can find what percent of the sub-dataset has values <2.9 with the usual procedures we learned in the earlier lectures (I.E converting the deviation into SU, and using the applet to find the appropriate area).
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T18:58:18Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks so much for taking the time to explain this. Clearly I was way off track. Think I'll take another look at the last lectures, with caffeine this time!
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-24T22:12:16Z
SecondChildVoteTAG: 0
SecondChildTAG: That found that very hard, thank you for the additional explanation.
SecondChildUserIdTAG: 901925
SecondChildUserNameTAG: RaymondLowe
SecondChildCreateTimeTAG: 2013-03-25T03:08:32Z
SecondChildVoteTAG: 0
FirstChildTAG:
This post refers to Practice Question 1D for Week 5.
The explanation provided in the Show Answer says:
> Note that if the question had asked what percent of all students have
> GPAs below 2.9, the answer would have been 50%.
I do not understand how 50% is derived. Can someone please explain the steps?
FirstChildUserIdTAG: 865969
FirstChildUserNameTAG: Shanatova
FirstChildCreateTimeTAG: 2013-03-25T11:54:20Z
FirstChildVoteTAG: 0
SecondChildTAG: Good question ... I'm taking a guess. Since 2.9 is the average of GPAs, in standard units that would be 0. On the normal curve 0 is the balance point: 50% above and 50% below.
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-25T17:25:42Z
SecondChildVoteTAG: 0
IndexTAG: 344
TitleTAG: Answer for question 3A and 3B
HELP please, I don't understand how I must did question 3A and 3B, all times I had wrong answer...So can you write me please solution for me, because I really don't understand
UserIdTAG: 1172999
UserNameTAG: Anastasiya145
CreateTimeTAG: 2013-03-24T17:31:24Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: No giving solutions before the due date.
But, to help you figure it out, I can give you a couple hints:
In 3A, you need the value **x**, so that if you estimate **y** as the head circumference based on weight, 50% of the "real" values are between $y-x$ and $y+x$. You'll need to understand clearly what the error of the regression is and what it can be used for, and also remember the usual techniques for finding values and areas on the normal curve.
3B is very similar, you still have an estimate **y**, but here you need to calculate what percentage of the "real" values are $FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T20:07:02Z
FirstChildVoteTAG: 3
SecondChildTAG: Thank you very much,it helped me since I overlooked that word ''overestimate'' ,silly me.
SecondChildUserIdTAG: 1181029
SecondChildUserNameTAG: Ilya19
SecondChildCreateTimeTAG: 2013-03-25T00:58:06Z
SecondChildVoteTAG: 0
SecondChildTAG: 50% is 0 as r. i´m so confused. because then you will don´t need regression line.
SecondChildUserIdTAG: 933119
SecondChildUserNameTAG: wsaw
SecondChildCreateTimeTAG: 2013-03-25T21:14:15Z
SecondChildVoteTAG: 0
IndexTAG: 345
TitleTAG: Where is exercise set 13?
When i checked my progress bar page i saw that there is exercise set 13 but i do not see that in the courseware page. Did this happen to anyone else? Please help
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-24T15:22:32Z
VoteTAG: 7
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 5
FirstChildTAG: I'm also wondering about this.
FirstChildUserIdTAG: 1116038
FirstChildUserNameTAG: UrosKovac
FirstChildCreateTimeTAG: 2013-03-24T15:45:07Z
FirstChildVoteTAG: 1
FirstChildTAG: Me too - I've just about staggered through Exercise 12
with one revision day to spare before the final exam -
and now (possibly) discovered there is another exercise set somewhere
which (i don't think) existed this morning - what gives, please???
FirstChildUserIdTAG: 20821
FirstChildUserNameTAG: KitR
FirstChildCreateTimeTAG: 2013-03-24T16:02:46Z
FirstChildVoteTAG: 0
FirstChildTAG: we will know soon wt does es 13 mean :)
FirstChildUserIdTAG: 1048539
FirstChildUserNameTAG: Reham1989
FirstChildCreateTimeTAG: 2013-03-24T16:20:47Z
FirstChildVoteTAG: 0
FirstChildTAG: I also think it'll be an error. There's no exercise set 13 and I think won't be exercise set 13 because the course has ended now just only the final exam left.
FirstChildUserIdTAG: 1232601
FirstChildUserNameTAG: Firefly-2009
FirstChildCreateTimeTAG: 2013-03-24T16:27:17Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section8a_Lec_8_2/threads/514ef11661b6350e0000011a
FirstChildUserIdTAG: 975121
FirstChildUserNameTAG: SvetlanaZer
FirstChildCreateTimeTAG: 2013-03-24T19:21:55Z
FirstChildVoteTAG: 0
IndexTAG: 346
TitleTAG: When will Stat 2.2 and 2.3 be offered online?
I would like to continue the Statistics course, onto Stat 2.2 and 2.3. Do you know when will they be offered online through EdX?
Thanks, Noreen
UserIdTAG: 1130547
UserNameTAG: nluetteke
CreateTimeTAG: 2013-03-24T14:58:15Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I would also like to know if EdX is going to offer Stat2.2 and Stat2.3 anytime soon.
Does anyone have a clue?
FirstChildUserIdTAG: 151933
FirstChildUserNameTAG: WildW1ill
FirstChildCreateTimeTAG: 2013-03-24T15:16:06Z
FirstChildVoteTAG: 1
SecondChildTAG: Question has been asked many, many times. The 'official' answer is that the others courses will follow on shortly after this finishes - some weeks later. As edX seem to advertise courses at least a month before they start I'd guess Late April or May but who knows? The intention certainly seem to be to offer the three courses which make up the Stats2 course on campus.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-24T15:20:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Seems I'm out of date as I now see that the Prof. has quoted a date of 12 April. This is, of course, in line with her earlier posts and welcomed by me as I'm ready to go ahead as soon as possible. It is a surprisingly short lead time for an edX course which is why I made my earlier estimate above.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-24T16:24:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Here's the answer what we know at this time.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/514e1f751785850e00000041
FirstChildUserIdTAG: 1232601
FirstChildUserNameTAG: Firefly-2009
FirstChildCreateTimeTAG: 2013-03-24T16:13:39Z
FirstChildVoteTAG: 2
FirstChildTAG: Percentage should be shown in the certificates. Avoiding percentage scores is going to discourage the serious students and encourage mediocrity.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-25T00:58:19Z
FirstChildVoteTAG: 0
IndexTAG: 347
TitleTAG: Answer for question 3C
Dear prof A,
I have calculated the thing as below
=(8-7)/1.2 = 0.833,
0.833*0.55= 0.458,
0.458*0.5+14=14.22,
14.22/0.418= 1.866
In applet it is 96.9
Area right to 96.9= 3.1
Could you please consider this as it is due to the number of decimal points I used.
Thank you,
Randika
UserIdTAG: 679558
UserNameTAG: Randika
CreateTimeTAG: 2013-03-24T14:06:12Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: I got the same answer. Wrong.
the point is in the very accurate rounding of the numbers. and I got right at the end.
FirstChildUserIdTAG: 1148146
FirstChildUserNameTAG: Prostova
FirstChildCreateTimeTAG: 2013-03-24T14:27:49Z
FirstChildVoteTAG: 0
SecondChildTAG: There is a problem with this approach. I used 0.413 for my rms error--worked fine with problem 3b; however, in 3C, using .413 (more accurate) rather than .42 (used by prof) yields 1.8644 as the rms error. Plugging that into applet gives @ 96.86% under 15", so 3.14% above. I tinkered with rounding choices at various places in my computations and used up my 3 submissions giving estimates ranging from 3.12 to 3.3. "Correct" answer was 3.5, but this was based on a decision to round rms error immediately to 2 places, rather than using more accurated value.
SecondChildUserIdTAG: 252779
SecondChildUserNameTAG: msushi
SecondChildCreateTimeTAG: 2013-03-25T19:54:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Just saw my error and it's a stupid one. I used 4.13 for my rms error because I copied my own handwriting of 4.18 incorrectly. Gheesh! But at least it made me review my logic several times so I now really understand it, even though I got 3C wrong. Please ignore my post above.
SecondChildUserIdTAG: 252779
SecondChildUserNameTAG: msushi
SecondChildCreateTimeTAG: 2013-03-25T20:08:51Z
SecondChildVoteTAG: 0
FirstChildTAG: Yeah, you really shouldn't get marked wrong there. If you still have submissions available, do your calculations with only 2 decimals.
But Randika, could you edit your post and delete the numbers? It's a bad violation of the honor code.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T14:48:28Z
FirstChildVoteTAG: 2
IndexTAG: 348
TitleTAG: In progress section, what is ES 13
As per curriculum, there were supposed to be 12 graded exercises. Why is the progress section showing ES 13 and where is this exercise in the courseware section?
UserIdTAG: 1085799
UserNameTAG: ramanmakkar
CreateTimeTAG: 2013-03-24T12:27:02Z
VoteTAG: 12
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 7
FirstChildTAG: With this additional ES13, my Exercise set average has suddenly fallen :)
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-24T12:30:46Z
FirstChildVoteTAG: 5
SecondChildTAG: yes, the same with me!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-24T13:19:14Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, what is it?!
FirstChildUserIdTAG: 975121
FirstChildUserNameTAG: SvetlanaZer
FirstChildCreateTimeTAG: 2013-03-24T12:34:01Z
FirstChildVoteTAG: 0
FirstChildTAG: *Someone* has been playing with the EdX software it seems :P
It can only be a technical error, I'm sure it'll be removed soon.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T12:57:13Z
FirstChildVoteTAG: 3
SecondChildTAG: Bless you for such positive thoughts:)
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-24T12:59:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Hope you are correct!
SecondChildUserIdTAG: 975121
SecondChildUserNameTAG: SvetlanaZer
SecondChildCreateTimeTAG: 2013-03-24T13:06:29Z
SecondChildVoteTAG: 0
FirstChildTAG: I have just went into panic mode - ES 13 was not there last night. This has been stressful enough without adding this to the equation :-) . I really do hope someone is not having a laugh at our expense.
FirstChildUserIdTAG: 965242
FirstChildUserNameTAG: Bev1969
FirstChildCreateTimeTAG: 2013-03-24T13:49:59Z
FirstChildVoteTAG: 0
FirstChildTAG: Agreed... the only extra work that shows is the "Additional practice for the final" but appears to be optional...in which case if E13 refers to this, then is not optional !...
FirstChildUserIdTAG: 1003677
FirstChildUserNameTAG: CValladaress
FirstChildCreateTimeTAG: 2013-03-24T14:47:02Z
FirstChildVoteTAG: 0
FirstChildTAG: I'd guess that when setting up the additional practice questions the wrong button was clicked and an additional (non-existent) graded exercise set added to the Progress calculation.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-24T15:59:04Z
FirstChildVoteTAG: 0
FirstChildTAG: There is no ES 13. We'll look into how it popped up. Sometimes the platform has mysteries too deep to fathom. The additional practice is optional, and not even do-able in the EdX way. ES 12 is the last graded exercise set. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-24T18:52:39Z
FirstChildVoteTAG: 4
SecondChildTAG: Thank you very much Prof. A.
SecondChildUserIdTAG: 1256305
SecondChildUserNameTAG: rozanska
SecondChildCreateTimeTAG: 2013-03-24T18:55:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank You very much
SecondChildUserIdTAG: 1256261
SecondChildUserNameTAG: ilow
SecondChildCreateTimeTAG: 2013-03-24T18:55:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Course staff is amazing. Thanks a lot.
LOL
SecondChildUserIdTAG: 1263723
SecondChildUserNameTAG: Chamikad
SecondChildCreateTimeTAG: 2013-03-24T20:04:45Z
SecondChildVoteTAG: 0
SecondChildTAG: As expected :)
Thanks for confirming it Prof!
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-24T20:08:59Z
SecondChildVoteTAG: 0
IndexTAG: 349
TitleTAG: Problems based on US Education System
So many problems are based on the US Education system. Many of us are not familiar at all with US Education system. Words like Freshman and all only add to the confusion. Understanding the problem statement based on EDUCATION domain is in itself a challenge more than the statistics concept being discussed.
Would really appreciate if the questions are based on something more generic than a US Education system, as we are all still in the learning phase and would like to focus more on statistics concept rather than also trying to understand the Domain. I am sure you will agree that it is not possible to appreciate/solve the problem without understanding what it means, unless we just catch few words like 'average', SD, etc in the problem statement and mechanically plug in values and get the answer. It is not enjoyable.
This is just a request, not a complain. Also, I am not sure I am alone in this or others too face this challenge.
UserIdTAG: 300213
UserNameTAG: Artimehta
CreateTimeTAG: 2013-03-24T12:07:15Z
VoteTAG: 10
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 1
FirstChildTAG: I fail to see know how exactly the US Education system words bring confusion to this problem.
You have two datasets, with stated Average and SD, and a correlation coefficient between them. The datasets are referred by names("MSAT scores of freshmen" and "GPAs of freshmen"), but these names could have been anything.
They could have been "Ages of Atlantians" and "Minutes it took them to drown", which also takes a specific knowledge(the myth of Atlantis) to put into context.
But the names and their contexts don't really change what you have to take in about the exercise(the numbers), nor the procedures you need to follow ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T13:12:39Z
FirstChildVoteTAG: 4
SecondChildTAG: I agree procedure doesn't change, but when words don't make sense, it is no fun solving a problem.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-24T13:17:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh, I agree with that :)
But, we are in a global world nowadays. A [tiny][1] [bit][2] of [research][3] will answer all your doubts very quickly, and it can also be fun to learn new things and terminologies ;)
[1]: http://en.wikipedia.org/wiki/SAT
[2]: http://en.wikipedia.org/wiki/Freshman
[3]: http://en.wikipedia.org/wiki/Grade_Point_Average#United_States
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-24T13:35:20Z
SecondChildVoteTAG: 0
SecondChildTAG: No fun when we are hard pressed for time. Otherwise, yes agree.
SecondChildUserIdTAG: 865969
SecondChildUserNameTAG: Shanatova
SecondChildCreateTimeTAG: 2013-03-24T14:45:26Z
SecondChildVoteTAG: 0
SecondChildTAG: The naming is inconsistent, though. We're given “SAT scores” here, yet asked about “MSAT scores”. Are they the same or not? It generates unnecessary confusion.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-03-24T17:08:44Z
SecondChildVoteTAG: 0
SecondChildTAG: **Yes**, that's a typo in the first sentence. It should have been MSAT there too, given the context and the average of 600 that would be ridiculously low for the full SAT.
I agree, it might generate confusion...although it *is* the only data you have other than the GPAs, so you don't really have much choice there :D
Luckily, it is only a Practice problem.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-24T20:22:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I suppose it's the same as going to school abroad - there's some culture gap you have to cross, and it's all part of the experience.
SecondChildUserIdTAG: 1002202
SecondChildUserNameTAG: ury949
SecondChildCreateTimeTAG: 2013-03-25T00:42:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Can any one tel me about the course on project management
Thanks,
SecondChildUserIdTAG: 1017884
SecondChildUserNameTAG: Bilew
SecondChildCreateTimeTAG: 2013-03-25T11:31:38Z
SecondChildVoteTAG: 0
IndexTAG: 350
TitleTAG: Solution for Problem no 2
When i used the method of simultaneous equation, the answers i got were 33 for A and 1.7 for B. That is using the two entries where both the value and standard units were given((54,2.8 and 42,0.4); using these two sets, i believe the mean and SD of the data could be obtained from whence the two unknowns could be derived.
Kindly confirm if i was correct? and if so, correct the answer to also accept 33 for A and 1.7 for B. Thanks
M.K Yakubu
UserIdTAG: 1257308
UserNameTAG: mkyakubu
CreateTimeTAG: 2013-03-24T11:08:42Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 0
IndexTAG: 351
TitleTAG: Problem 3A - To the staff
Shouldn't the answer be double the answer that you have shown when you consider both sides(positive and negative) of the 50% from the applet.
Thanks
UserIdTAG: 1181314
UserNameTAG: SolomonT
CreateTimeTAG: 2013-03-24T09:49:42Z
VoteTAG: 3
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 352
TitleTAG: positive association and linear
will a positive association among two variables always mean that the two variables are linear.
With a positive association the scatter diagram will be roughly going up and we will be probably able to draw a straight line thru it as well, right?
UserIdTAG: 87424
UserNameTAG: Sknair
CreateTimeTAG: 2013-03-24T09:07:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Not necessarily. Think of a scatter diagram that patterns this curve: ![enter image description here][1]
It's still a positive association. When x increases, y also increases. So *r* will likely be a positive number here. But nobody would dare tell me that this is a straight line by any approximation, so the two variables are definitely **not** linear ;)
[1]: https://dl.dropbox.com/u/6636701/curve.jpg
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T11:16:53Z
FirstChildVoteTAG: 0
SecondChildTAG: You might be able to **approximate** that curve to a straight line but it wouldn't be the **best** approximation.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-24T16:26:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Unless you are only interested in some parts of that curve, it would be a **very bad** approximation in most cases, and should you attempt it in a professional environment, don't be surprised if you get fired quickly :P
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-24T20:33:38Z
SecondChildVoteTAG: 0
IndexTAG: 353
TitleTAG: Science Project Dataset
to Prof. Ani, I hope you can help me analyze the following dataset of my son's science project on effect of pH on Aspirin Solubility.
series of ph Solution (N=35)
-0.8
-0.8
-0.8
-0.8
-0.8
0
0
0
0
0
1
1
1
1
1
7
7
7
7
7
13
13
13
13
13
14
14
14
14
14
14.8
14.8
14.8
14.8
14.8
corresponding time to dissolve Aspirin (N=35)
1128.0
2092.5
3466.5
3674.7
3855.3
67.3
59.3
140.0
75.1
43.9
92.6
59.1
71.4
50.4
109.7
93.69
55.0
88.5
69.5
65.1
72.4
64.1
114.6
53.1
80.5
246.1
256.9
124.4
144.5
203.6
2279.8
1982.1
4920.0
5049.0
4500.0
The scatter graph we plotted looks like a U-shape. Can you help me mak sense of it, since it does not agree with what is written in the book that Aspirin is more soluble in basic solution than water or acids.
UserIdTAG: 408651
UserNameTAG: Drdanilofuna
CreateTimeTAG: 2013-03-24T06:03:29Z
VoteTAG: 0
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 2
FirstChildTAG: Separate into three regions: acidic (pH<7), basic (pH>7) and neutral (pH=7). Check what's happening in each one. This will help you discern if there's anything wrong (there has to be something, as aspirin is acidic itself).
Taking a quick look at your series, there's obviously something wrong: pH goes from 0 to 14, 0 to 7 being acidic, 7 to 14 being basic. You have negative values (!?!) and over-14 values (!?). These don't even have a physical meaning....
FirstChildUserIdTAG: 687022
FirstChildUserNameTAG: ThanosT
FirstChildCreateTimeTAG: 2013-03-25T20:48:46Z
FirstChildVoteTAG: 0
SecondChildTAG: In other words, try to redo your original acidic/basic solutions (before dissolving the aspirin), as they're clearly off. Try to set a gradual scale to your pH: start with pH=1 (which is extremely acidic by the way, what are you using???) and work your way to a more basic solution. The ideal would be, to make a series of solutions ranging from pH~4 all the way to ~11.
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-25T20:54:08Z
SecondChildVoteTAG: 0
SecondChildTAG: The -pH is base on calculated H+. pH= -log(moles of H+) and yes it can be negative values such as in this case because we used 6 N solution of HCl. The slightly acidic and basic solution did not have any statistical difference with neutral solution but both highly acidic and basic solution makes the chewable aspirin very unsoluble. Ths is contrary to what book says that adding a basic solution will actually makes Aspirin more soluble. Thank you Thanos for your critique, I really appreciate it.
SecondChildUserIdTAG: 408651
SecondChildUserNameTAG: Drdanilofuna
SecondChildCreateTimeTAG: 2013-03-31T04:38:01Z
SecondChildVoteTAG: 0
FirstChildTAG: I was also wondering how does on get a pH as a negative value.pH should be between a positive number till 14.(Being the negative logarithm of the Hydrogen ion concentration)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-26T02:50:30Z
FirstChildVoteTAG: 0
SecondChildTAG: I just discovered this my self but I read it on science tutorial and you can use this on-line calculator -http://easycalculation.com/chemistry/ph-poh-calculator.php
SecondChildUserIdTAG: 408651
SecondChildUserNameTAG: Drdanilofuna
SecondChildCreateTimeTAG: 2013-03-31T04:44:31Z
SecondChildVoteTAG: 0
IndexTAG: 354
TitleTAG: Residual Plot
After listening lecture 8.2 twice, I came to following conclusions
1. If a residual plot is random with respect to mean of residual, regression is good
2. Patterned(Cyclic, quadratic, polynomial and so on ) residual plot indicates non-linearity between 2 variables.
3. Beside(1 & 2) represents a computational error and examples will be non-zero mean, linear association between residual and x(or y)
Comments and criticisms are welcome!!
UserIdTAG: 1181586
UserNameTAG: eumannu
CreateTimeTAG: 2013-03-24T04:15:09Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: For this topic Listen last 5-6 min of 39 min video carefully and go through very good discussion in the online text, chapter 10. This helped me. Hope you will benefit.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-24T12:23:26Z
FirstChildVoteTAG: 0
IndexTAG: 355
TitleTAG: Is the answer to problem 1B of ES 10 correct?
The answer says:
> 22.5 mm in standard units = -1.11; 0.75*(-1.11) = -0.83; -0.83 standard units = 5.63 grams.
But this doesn't seem to make sense. 0.83 standard units is about 0.415 grams, so the weight should be something like 6 - 0.415 = 5.585 right?
UserIdTAG: 529507
UserNameTAG: Lasker
CreateTimeTAG: 2013-03-24T04:03:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: I didn't check the Prof's sums, so thought it was just a rounding thing. But maybe not. $5.585$ is what it should be. I got $5.583$ by not rounding so much.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-24T04:15:19Z
FirstChildVoteTAG: 0
SecondChildTAG: I feel we can say with ome confidence that it was a typo.
I'm only just now getting around to doing ES 9-12, but I assume the grader itself must have been correct or there would already be an outcry in the forums.
SecondChildUserIdTAG: 529507
SecondChildUserNameTAG: Lasker
SecondChildCreateTimeTAG: 2013-03-24T04:29:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes. There was some discussion about the discrepancy. I think there was at least one poster who, if 5.63 was the official answer, maybe should have been given correct. But s/he wasn't. So that makes me think the answer in the system is correct.
Can't find the posts now, I'm having awful trouble just getting the discussion page to load. Can't see the posts I am Following, or a list of my own posts.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-24T04:42:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Seems to be fixed now as **5.59**
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-24T09:32:05Z
SecondChildVoteTAG: 0
IndexTAG: 356
TitleTAG: Sound is out 3-23-2013
Sound is out
UserIdTAG: 226651
UserNameTAG: flloyd
CreateTimeTAG: 2013-03-24T02:01:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Sound is on
FirstChildUserIdTAG: 226651
FirstChildUserNameTAG: flloyd
FirstChildCreateTimeTAG: 2013-03-24T02:10:30Z
FirstChildVoteTAG: 0
IndexTAG: 357
TitleTAG: incorrect answer to Problem 2A
Sure others have already noted but while I'm looking at it, the correlation should be 0.75 and not 0.65
UserIdTAG: 1215650
UserNameTAG: pdenitz
CreateTimeTAG: 2013-03-24T01:07:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: I think it's typo....because answer confirms 0.75 not .65
FirstChildUserIdTAG: 1181586
FirstChildUserNameTAG: eumannu
FirstChildCreateTimeTAG: 2013-03-24T04:32:08Z
FirstChildVoteTAG: 0
IndexTAG: 358
TitleTAG: Incorrect unit of measure in problem 3?
Should the circumference of a newborn's head be in cm, not inches? We are talking about human newborns, right?
UserIdTAG: 1183782
UserNameTAG: Tessamessa
CreateTimeTAG: 2013-03-24T01:06:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: The question is using imperial measurement, not metric. So 14" is okay for an average newborn, 14cm is not.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-24T01:34:21Z
FirstChildVoteTAG: 0
IndexTAG: 359
TitleTAG: Question on Problem 3A. Exercise set 12.
Sorry if this one is too silly but I don't get the exact meaning of "is correct to" within the question....
UserIdTAG: 1003677
UserNameTAG: CValladaress
CreateTimeTAG: 2013-03-24T00:44:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's asking for the deviation from a central point(the regression estimate).
For example, if 5 inches is the length I estimate, the estimate is "correct to within **0.5 inches**" for all values between 4.5 and 5.5.
Hope this helps ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T14:02:56Z
FirstChildVoteTAG: 0
IndexTAG: 360
TitleTAG: Regression towards the mean - unclear
Dear All,
These questions are troubling me for several days. I am trying here to summarize the sentences which are making a mess in my head right now. What is not clear to me is:
1. In the Practice for Ex.Set 10, Problem 1B, from the given answer, we learned that:
"Regression says that the estimate should be a bit below where we started", which can be easily seen on the plot, given that the scatter diagram is football shaped, with positive association. But then the following occurs:
2. In Lecture 7.3, it is said that:
a) "Those who have high values of one variable tend not to be quite that high on the other.", which is due to, I guess, slope !=1, or I am wrong?
b) Definition of Regress. towards the mean:
"If you start out low on one variable, then your estimate will be somehow higher on the other". AND
"If you start out high on one variable, then your estimate will be somehow lower on the other".
Here I do not understand what is low/high and what is very low/very high?
Can I see this on a plot? Can I see the both situations ("starting very low" and "starting very high") at the same time on one plot? Is this in contradictory with what's written under #1?
3. Regression towards the mean. Why is it called like this?
I would appreciate any help.
Thank you!
Best,
Mitzi
UserIdTAG: 1185598
UserNameTAG: Mitzi
CreateTimeTAG: 2013-03-24T00:39:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 2a) is due to 0 < r < 1 and the football shape.
2b) "low": below average
"high": above average
3. Every regression estimate is closer to the mean (that is, standard units closer to 0) than the value of the given variable that was used as the basis for estimation; the exception is if you start out with the given variable equal to its mean, in which case the regression estimate will be the mean of the other variable.
So e.g. assuming that r is positive but not 1, and the scatter is football shaped:
- If the value of the given variable is at the 60th percentile, then the regression estimate of the other variable will be between the 50th percentile and the 60th.
- If the value of the given variable is at the 40th percentile, then the regression estimate of the other variable will be between the 40th percentile and 50th.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-24T01:03:09Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you!
Best,
Mitzi
SecondChildUserIdTAG: 1185598
SecondChildUserNameTAG: Mitzi
SecondChildCreateTimeTAG: 2013-03-25T00:17:35Z
SecondChildVoteTAG: 0
IndexTAG: 361
TitleTAG: From Prof. A: My Stat2X blog
Hello everyone,
Students and others have been asking me what it's like to teach a MOOC. Now that it seems clear that students and staff are going to come through Stat 2.1X relatively unscathed, and that some (including me) have enjoyed the experience, I've started to jot down some thoughts about it. You'll find the first entry at
http://stat2x.blogspot.com.
Read if you wish; I'll update as I have time. Just to be clear, the entries will be my thoughts about MOOCs in general, and about teaching this one in particular, but will not cover material in the course. **The blog will contain nothing that you will need to solve the exercises and exams in Stat 2X.**
So reading it is entirely optional. Blogs are often self-indulgence on the part of the author, anyway. However, we are all learning in a new medium, and some of you might be interested in the experience of an instructor, especially one whom you know mostly as a disembodied voice.
Best,
Prof. A.
UserIdTAG: 1019686
UserNameTAG: AniAdhikari
CreateTimeTAG: 2013-03-23T23:41:31Z
VoteTAG: 19
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: I, for one, have enjoyed this experience immensely! I am an 'older' person long removed from academia and thought I would take this class as a challenge to myself. I have actually learned many useful techniques and ideas for my data crunching that I do, out of curiosity, in my career.
Thank you for taking the time to share your expertise. You are an EXCELLENT teacher and look forward to your next installations.
FirstChildUserIdTAG: 1346686
FirstChildUserNameTAG: kimbalips
FirstChildCreateTimeTAG: 2013-03-24T00:04:44Z
FirstChildVoteTAG: 2
FirstChildTAG: As an instructor myself I'm very interested in your experience. An exciting one, I guess. Thanks for sharing.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-24T01:21:55Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks for this opportunity to have some insight on the "insider" world of MOOC! I expect it will be very interesting :)
Also, that guy Rosenthal on the NYT sounds like he's missing the point about MOOC courses. They shouldn't ever be intended as replacement for "traditional" courses, and it's not surprising that most people who take a course with no interest whatsoever in the topic, just because it's required by their curriculum, do better when they have to deal with more "tangible" lectures and professors in the "real world". They feel more pressure.
MOOCs are for people interested in a topic they couldn't explore during their college days, or for people who just couldn't take the course otherwise because of time and/or location constraints. These people wouldn't have had access to this education *at all* in the "traditional" world, and therein lies the great innovation and advantage of Online Courses.
IMHO ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T09:51:19Z
FirstChildVoteTAG: 3
FirstChildTAG: Dear Prof. Adhikari,
Great idea! I already subscribed your feeds. What about enabling comments? They may spur the blog's popularity.
About the article on The Times, I do disagree. If we're talking about motivation, I'd say that face-to-face courses of top ranked universities require far more motivation and competitiveness. After all, it's because I'm not that motivated to give up my full time job :) that I didn't relocate to US to follow some courses in a top University. My limited experience with Ph.D. students and PostDocs at Stanford, when I was there as a visiting researcher, pretty much confirms that.
Of course MOOC require a good amount of motivation and self-discipline too, but if somebody can't muster that much, I highly doubt he would fare much better in MIT-hard, Berkeley-hard or Stanford-hard standard courses. So I think it's the MOOC that have more hopes to deliver state-of-the-art education to a larger audience of people. For example, people such as Klionheart was talking about - people who once took a graduate degree, and now need to learn some other stuff, but are not willing or don't need to take another degree.
I have the impression that criticists of MOOC sometimes confound them with online videos of class lectures, such as the OpenCourseware initiative of MIT. Clearly, that is in no way comparable to a real MOOC, which offers a real course schedule, short lectures specifically tailored for online audience which more often than not doesn't have the time to follow 1 or 2h lectures, real examinations, and forums to discuss with other students from all the rest of the world. And I do like the small rewards given by those small green marks :)
See also here:
http://tech.mit.edu/V133/N2/mooc.html
PS I believe that the short lecture format also helps overcome the issue of the shorter attention span younger students seem to show when studying on Internet.
FirstChildUserIdTAG: 407687
FirstChildUserNameTAG: AndreaPi
FirstChildCreateTimeTAG: 2013-03-24T12:38:19Z
FirstChildVoteTAG: 2
FirstChildTAG: I did not read the NYT article but I did read your blog posting. It seems like on-line education (MOOC) is going to be the wave of the future. I think edX is evolving and it is likely to become a more robust delivery platform. It has been a wonderful experience listening to your Stat 2.1x lectures. It also seems like the lectures delivered at Berkeley (as evident from StatGui) may be more rigorous than the lectures delivered on the edX platform? Thanks.
FirstChildUserIdTAG: 413463
FirstChildUserNameTAG: Venkataramani
FirstChildCreateTimeTAG: 2013-03-24T16:15:09Z
FirstChildVoteTAG: 1
SecondChildTAG: Philip Stark's lectures were in Stat 21, not Stat 2. Stat 21 has a calculus prerequisite. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-24T19:08:46Z
SecondChildVoteTAG: 0
FirstChildTAG: I read your posts. Very noble thoughts indeed. Money means a lot. But money is not everything . The fragrance of a flower is priceless . We are lucky that such an enlightened soul as yourself is our mentor and that we have got an opportunity to come in contact ( 'sanidhay' ) with you , at least in some sense ! Thanx a lot!
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-25T06:42:42Z
FirstChildVoteTAG: 1
IndexTAG: 362
TitleTAG: 2E Explanation requests
When the time comes—not now, but after the exercises due date passes—I would appreciate a more, detailed, nuanced explanation of 2E. Thank you in advance.
UserIdTAG: 984607
UserNameTAG: jbhm
CreateTimeTAG: 2013-03-23T23:38:59Z
VoteTAG: 6
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Joining the request.
FirstChildUserIdTAG: 955096
FirstChildUserNameTAG: yoav_v
FirstChildCreateTimeTAG: 2013-03-24T10:55:28Z
FirstChildVoteTAG: 1
FirstChildTAG: If you look at that diagram, you'll see that the whole data is kind of shifted above the regression line so the bulk of them is situated in the positive area. Adding all of those residuals up wouldn't give you a zero, that is, r.m.s. error for that "regression" line is not minimal. Hope it'll give you a clue without spoilering to much to the others :3
It was simple, but I rushed to answer, too :c
FirstChildUserIdTAG: 907272
FirstChildUserNameTAG: Fedor_Igntakin
FirstChildCreateTimeTAG: 2013-03-25T19:34:54Z
FirstChildVoteTAG: 0
IndexTAG: 363
TitleTAG: lect 8.1
the rest lec.8.1 should be posted soon.
UserIdTAG: 950329
UserNameTAG: cbiglow
CreateTimeTAG: 2013-03-23T21:34:36Z
VoteTAG: 0
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.1: Least squares: why the regression line and no other
NumberOfReplyTAG: 0
IndexTAG: 364
TitleTAG: From Prof. A: Week 4 answers
We are mystified as to why these have not appeared, but are working on it. Sorry about the glitch. Best,
Prof. A.
UserIdTAG: 1019686
UserNameTAG: AniAdhikari
CreateTimeTAG: 2013-03-23T21:33:37Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 365
TitleTAG: From Prof. A.: 2.2X
Hi all,
Stat 2.2X will start on Fri April 12. A few details are still to be ironed out; I'll post when things are clear. For the schedule, I'm taking into account some of your requests e.g. having exams over weekends.
Hang on for a bit till I have all the details. Thanks,
Prof. A.
UserIdTAG: 1019686
UserNameTAG: AniAdhikari
CreateTimeTAG: 2013-03-23T21:32:37Z
VoteTAG: 71
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 23
FirstChildTAG: Thank you professor.I really wait for the new course.
The stat2.1 was the best math based course where I participated and it was really a fantastic experience.I really enjoyed it so much and I'll be there on the stat2.2 as well:)
FirstChildUserIdTAG: 1232601
FirstChildUserNameTAG: Firefly-2009
FirstChildCreateTimeTAG: 2013-03-23T21:48:05Z
FirstChildVoteTAG: 12
SecondChildTAG: agreed
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-24T01:33:57Z
SecondChildVoteTAG: 0
SecondChildTAG: agreed too :-)
SecondChildUserIdTAG: 385816
SecondChildUserNameTAG: dinoRB
SecondChildCreateTimeTAG: 2013-03-25T00:25:10Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm very grateful for this wonderful course, thank you for hearing our requests about exam dates. Thanks a lot!
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-23T22:26:17Z
FirstChildVoteTAG: 2
FirstChildTAG: Good!
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-23T23:27:35Z
FirstChildVoteTAG: 3
FirstChildTAG: Thank you so much! This course has been wonderful. I'm definitely in for the long haul. For my friends who haven't yet taken Stat 2.1X, will you be offering it again? If so, when?
FirstChildUserIdTAG: 975044
FirstChildUserNameTAG: ChantalA
FirstChildCreateTimeTAG: 2013-03-24T04:19:15Z
FirstChildVoteTAG: 0
FirstChildTAG: That's wonderful news! Thanks a lot to Prof.Ani and all others who made this possible!
FirstChildUserIdTAG: 99863
FirstChildUserNameTAG: pramode_ce
FirstChildCreateTimeTAG: 2013-03-24T06:15:20Z
FirstChildVoteTAG: 2
FirstChildTAG: Thank you for the heads-up! I'll certainly be there :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-24T09:23:44Z
FirstChildVoteTAG: 5
SecondChildTAG: thanks very much for the videos! Would 2.1x videos stay on the web for a long time?
SecondChildUserIdTAG: 817175
SecondChildUserNameTAG: yoshioks
SecondChildCreateTimeTAG: 2013-03-26T03:30:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you indeed for this very well-taught course. I am looking forward to the next one.
FirstChildUserIdTAG: 539593
FirstChildUserNameTAG: RomanLajciak
FirstChildCreateTimeTAG: 2013-03-24T10:51:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Prof. A
I was assured by the edX team that Stat2.2x would not be offered in April and I therefore confirmed a vacation at the end of April for 3 weeks (no internet access). Can you please advise when you think Stat2.2x will be offered again?
I have really enjoyed Stat2.1x and I am very disappointed that I am unable to participate in Stat2.2x this time.
Best regards
Bev1969
FirstChildUserIdTAG: 965242
FirstChildUserNameTAG: Bev1969
FirstChildCreateTimeTAG: 2013-03-24T14:20:44Z
FirstChildVoteTAG: 1
SecondChildTAG: > I was assured by the edX team that Stat2.2x would not be offered in April
It surprises me too as I've never seen a course offered on edX without at least a month's advertising before course start.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-24T16:20:30Z
SecondChildVoteTAG: 0
SecondChildTAG: It's hard for me to understand how/why that would be said to you, but I'll check with EdX. It has been known all along that Stat 2X is one course with three parts, and that the parts would follow each other as closely as we could manage. Hope to see you back in 2.3X. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-24T18:48:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you Prof. A. I logged my inquiry via email and a ticket #5921 was logged. The response I received was "Thank you for your question, we appreciate your interest in edX. At this time it has not yet been confirmed as to whether we will be offering these courses. I can assure you that they won't be offered in April".
Will I be at a disadvantage if I do Stat2.3x without doing Stat2.2x and do you know when Stat2.2x will be offered again?
Many thanks for making Stats easier to understand.
SecondChildUserIdTAG: 965242
SecondChildUserNameTAG: Bev1969
SecondChildCreateTimeTAG: 2013-03-24T19:27:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Hmmm, for what a single person opinion may count, I'd really prefer to keep having exams during the working week! I already work with a pc all the week, so I can cram in some late nights to do the exams. But I wouldn't mind some pc-free time during the weekend :)
FirstChildUserIdTAG: 407687
FirstChildUserNameTAG: AndreaPi
FirstChildCreateTimeTAG: 2013-03-25T08:39:35Z
FirstChildVoteTAG: 5
SecondChildTAG: Im for exam as they were too. I have no weekends when Im with my child at home ...
SecondChildUserIdTAG: 1289210
SecondChildUserNameTAG: ZHYRUNCHIK1
SecondChildCreateTimeTAG: 2013-03-30T05:12:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Great news, looking forward to the next two classes. Despite having to work 12/7 I have been able to follow the class and submit the exercises on time! Edx and Berkeley together with other Institutions involved in this journey are doing a fantastic job. Hopefully in the near future this initiative develops into a form of a recognized (credit courses) education that will give a chance to thousands of people around the globe to get qualitative education which otherwise would have never been possible.
Thank you Prof. A.
Ilir
FirstChildUserIdTAG: 1247915
FirstChildUserNameTAG: Iliri2013
FirstChildCreateTimeTAG: 2013-03-25T10:55:05Z
FirstChildVoteTAG: 1
FirstChildTAG: Fewer quizzes, equally graded ones, quizzes interspersed with two short mid terms and a final at the end. A slight change in course pedagogy shall be exciting. May be even a case assignment on descriptive statistics! Question banks with lots of practice questions just before the mid terms and the final and most definitely - Professor AA - please speak a little louder at the microphone! - Thanks - Eagerly awaiting Stat 2.2x! We are on our way to becoming Master's in Descriptive Statistics - Thanks to Professor AA.
FirstChildUserIdTAG: 413463
FirstChildUserNameTAG: Venkataramani
FirstChildCreateTimeTAG: 2013-03-25T11:51:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Great~~ Looking forward~
FirstChildUserIdTAG: 1239689
FirstChildUserNameTAG: Jamie425
FirstChildCreateTimeTAG: 2013-03-25T16:11:57Z
FirstChildVoteTAG: 0
FirstChildTAG: waiting 4 it
FirstChildUserIdTAG: 994886
FirstChildUserNameTAG: ARUN86
FirstChildCreateTimeTAG: 2013-03-25T17:25:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Excellent! I am not a person who is super good at working with mathematical concepts. I need to be able to work with statistical data more efficiently in my career, which is why I'm taking the course. I have enjoyed the way you explain things, Prof. A, and the repetition of material has helped me to get a better grasp on the subject. I look forward to Stat2.2 and continued learning!
Thank you to Prof. A and staff for making the course so accessible.
Best regards...
FirstChildUserIdTAG: 1394646
FirstChildUserNameTAG: DevorahKat
FirstChildCreateTimeTAG: 2013-03-25T19:48:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too. I like this course so much, easy to follow. Hope for the next course.
FirstChildUserIdTAG: 7980
FirstChildUserNameTAG: Nazri
FirstChildCreateTimeTAG: 2013-03-25T20:57:45Z
FirstChildVoteTAG: 0
FirstChildTAG: We're grateful for your kind efforts and thoughts, you've been a source of inspiration and motivation for us all.
Dhanyawad!
FirstChildUserIdTAG: 117419
FirstChildUserNameTAG: mcpyngrope
FirstChildCreateTimeTAG: 2013-03-26T04:15:22Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear prof A:
why can we not see Stat 2.2X in the EdX website for registration yet?
I got similar response from EdX team about not knowing when course will be offered.
Thank you very much
FirstChildUserIdTAG: 1161260
FirstChildUserNameTAG: bsalerno
FirstChildCreateTimeTAG: 2013-03-29T06:29:02Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks for all of the obvious hard work and consideration that you and the staff have put into this series.
FirstChildUserIdTAG: 990035
FirstChildUserNameTAG: RSeverson
FirstChildCreateTimeTAG: 2013-03-29T22:13:49Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you for this course!
Just a question: How can we assign for 2.2? I can't see this course on the main page. Will we get any invitation?
FirstChildUserIdTAG: 903120
FirstChildUserNameTAG: Rapunzelia
FirstChildCreateTimeTAG: 2013-03-30T17:25:51Z
FirstChildVoteTAG: 0
FirstChildTAG: eagerly waiting...meet you then prof!
FirstChildUserIdTAG: 1085077
FirstChildUserNameTAG: maveshsila
FirstChildCreateTimeTAG: 2013-03-31T11:10:10Z
FirstChildVoteTAG: 0
FirstChildTAG: It was a wonderful learning experience.......eagerly waiting for 2.2X
FirstChildUserIdTAG: 841351
FirstChildUserNameTAG: EpidemiologistPk
FirstChildCreateTimeTAG: 2013-04-01T11:56:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks a lot Prof Ani. Your lectures are concise , laden with information & well-structured , well-presented and well-modulated to keep the attention focussed. I guess I have got rid of Statistic Phobia :-). This is my first course in edx and enjoyed it and thank you once again for the wonderful class. Suresh- TN,IN.
FirstChildUserIdTAG: 101714
FirstChildUserNameTAG: sureshv
FirstChildCreateTimeTAG: 2013-04-02T07:03:21Z
FirstChildVoteTAG: 0
FirstChildTAG: I am in!! Thanks a lot Prof Ani.Such a wonderful learning experience in last 5 weeks. I was super busy at work,however, I could not stop surfing on edx for stat2.1x everyday. Thanks a lot edx as well, which really opens a window for those who eager to learn knowledge but do not know where/how to start. Zhenyu, Sydney
FirstChildUserIdTAG: 1246961
FirstChildUserNameTAG: guzhenyu
FirstChildCreateTimeTAG: 2013-04-02T09:22:21Z
FirstChildVoteTAG: 0
IndexTAG: 366
TitleTAG: New Course Openings
Hi,
My name is Lashundra, and I just signed up with edx. I am interesting in taking this course, but since it has already started, I know I want be able to learn anything in the short period of time. When will the course be offered again?
Sincerely,
LashundraK
UserIdTAG: 1469738
UserNameTAG: LashundraK
CreateTimeTAG: 2013-03-23T20:17:09Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 367
TitleTAG: point of average in regression line
So regression line passes through point of average which is origin (0,0) in standard units. can we say average of Y that falled in the verticl strip that corresponds to average X is ALSO the average of Y overall? in other words, average Y for individuals that had value of average X is the same as average of overall Y?
UserIdTAG: 1249880
UserNameTAG: xuy1
CreateTimeTAG: 2013-03-23T19:45:48Z
VoteTAG: 1
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 1
FirstChildTAG: Yes, to a close approximation. The regression line passes through the point of averages, and is a smoothed version of the graph of averages on a football shaped scatter. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-23T21:27:26Z
FirstChildVoteTAG: 1
IndexTAG: 368
TitleTAG: Hello World..!
Hi Everybody!
I really hope that the entire Stat2.1x course was a joyride for everyone, as it was for me!
Now since most of us have probably 'earned' a certificate, I would love to encourage all of you to work towards completing the course on a high note by successfully acing your final exam.
All the best to everyone for the same!
Hope to see you all in other exciting courses as well.
Special thanks to Prof. Ani for being extremely sweet, patient, lovable and above all, for being an excellent teacher!
Thanks to the Stat2.1x course staff and Prof. Philip Stark for an excellent GUI Book (SticiGUI).
Love you all! ;-)
UserIdTAG: 916575
UserNameTAG: Vipul94
CreateTimeTAG: 2013-03-23T18:30:26Z
VoteTAG: 8
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 1
FirstChildTAG: Agreed . Thanx Prof. Ani & Prof. Philip Stark.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-29T13:42:50Z
FirstChildVoteTAG: 0
IndexTAG: 369
TitleTAG: Hello World...!
Hi Everybody!
I really hope that the entire Stat2.1x course was a joyride for everyone, as it was for me!
Now since most of us have probably 'earned' a certificate, I would love to encourage all of you to work towards completing the course on a high note by successfully acing your final exam.
All the best to everyone for the same!
Hope to see you all in other exciting courses as well.
Special thanks to Prof. Ani for being extremely sweet, patient, lovable and above all, for being an excellent teacher!
Thanks to the Stat2.1x course staff and Prof. Philip Stark for an excellent GUI Book (SticiGUI).
Love you all! ;-)
UserIdTAG: 916575
UserNameTAG: Vipul94
CreateTimeTAG: 2013-03-23T18:24:32Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 370
TitleTAG: ES12 - Problem 2 is anything but scientific ! It's a shame.
How can you affirm without doubt that there is a trend in figure X ? I find very funny that in the video refered to as practice for ES12" reading residual plots" at 1:09:20 looking at a similar plot the teacher says, I quote, "That doesn't really look like a trend to me"
And to affirm that on X the average of the points is not zero it's also quite borderline.
I hope that the final will be more serious ...
UserIdTAG: 31693
UserNameTAG: sjfeg
CreateTimeTAG: 2013-03-23T18:07:01Z
VoteTAG: 3
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: I too had trouble with E-12 Problem 2, but I don't think it's fair to call it "unscientific." In fact, scientists need to make judgements like these all the time. I think the problem is that we have too little experience at this point to make solid judgements about whether a scatter plot is showing a trend or is linear. In fact, I'm not sure if these are the same things? Is it appropriate to use a regression line to estimate even when no trend is apparent from the scatter plot (provided that a curve would not be a better fit)?
FirstChildUserIdTAG: 252779
FirstChildUserNameTAG: msushi
FirstChildCreateTimeTAG: 2013-03-23T18:35:15Z
FirstChildVoteTAG: 2
FirstChildTAG: I've also failed one of the plots. Shame of me! Having familiarity with equations and, maybe, less exposure to graphics analysis is not a reason to judge this kind of problems "unscientific". At the contrary graphics are everywhere in modern science (at different stages of the scientific work) and we have to gain skill in qualitative analysis. Getting wrong (or right only by chance) is our fault.
After reading the answers I think every plot in this set has only one possible and right interpretation. In other cases the answer might really be unachievable without a quantitative analysis, but in my opinion there is no ambiguity here.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-23T20:01:14Z
FirstChildVoteTAG: 0
IndexTAG: 371
TitleTAG: 1C, where's my error?
After "showing answer", I understand how to do it in "the short way". I tried "the long way", treating all the vertical of SAT=500 as a data set, which is probably redundant, but should still yield the same result.
What I did was to find the Z value of the GPA of those who had SAT=500 on the regression line (using Zsat*r). I got **-0.533**
Then I calculated the RMS, which is the root of 1-r^2, multiplied by SD of SAT. I got **0.3207**.
if 0.3207 is 1 "SD", so 0.5 is **1.5587** "SD" (I say "SD", since its actually the RMS which I treat as SD).
Based on these numbers, I find that the % I'm looking for is the area right of -0.533+1.5587=**1.025**, and left of -0.533-1.5587=-**2.0917**, which is **not 12%** (the actual answer).
Can anybody please tell me why?
By the way, I also tried the actual SD of GPA instead of the RMS which based on it - and it also didn't work for me.
UserIdTAG: 955096
UserNameTAG: yoav_v
CreateTimeTAG: 2013-03-23T18:06:05Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 3
FirstChildTAG: ![just for illustration...][1]
[1]: https://edxuploads.s3.amazonaws.com/13640628478474419.bmp
FirstChildUserIdTAG: 955096
FirstChildUserNameTAG: yoav_v
FirstChildCreateTimeTAG: 2013-03-23T18:21:20Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Yoav_v, I also solved this problem the same "long way" as you did . However, when I have got 1.56 r.m.s. errors away from the regression line, I cdid heck again the area under the standard normal curve. Like in problem 1 b , the area between -1.56 and 1.56 is about 88%; so, more than 0.5 away from the regression estimate will be 12% - correct answer.
FirstChildUserIdTAG: 290615
FirstChildUserNameTAG: Elena_63
FirstChildCreateTimeTAG: 2013-03-23T22:23:21Z
FirstChildVoteTAG: 0
SecondChildTAG: So you are saying that I should check the area of +/- 1.56 around 0 (in standard units) and not around -0.533?
How come? We check for the specific series of people whose SAT is 500 (which isn't the average - the average is 600).
Thanks for the reply. I'm still confused though :(
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-03-24T04:35:03Z
SecondChildVoteTAG: 0
SecondChildTAG: > about what percent have GPAs that are more than 0.5 away from the regression estimate of GPA based on their MSAT score
The question specifically requests the percentage around the regression line based on the SAT score
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-03-24T04:37:56Z
SecondChildVoteTAG: 0
FirstChildTAG: yoav_v, I believe the problem you are having is due to using two different SDs as units of measurement:
a) Your regression estimate is -0.533 standard units of GPA, that is -0.533 GPA SDs above 2.9.
b) The "plus or minus" number you are using is 1.5587 r.m.s. errors of regression. The r.m.s. error is the SD of the GPAs of those who got 500 on the SAT, but it is not the same as the SD of all GPAs, which is the unit in a).
So when you add -0.533 and 1.5587, you're in effect adding apples to oranges, and that notoriously leads to trouble.
You can continue in the "long way", by finding the GPA corresponding to -0.533 standard units (about 2.71), then adding and subtracting 0.5 from it, and so on, at which point you'll get the solution that Elena_63 has suggested.
I hope this clears up the mystery. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-24T05:59:28Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you for clearing it up, I can see my mistake now!
Yoav
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-03-24T10:09:30Z
SecondChildVoteTAG: 0
IndexTAG: 372
TitleTAG: Downloading All Materials from One Location
Is there a way to download all materials from one location (in one file or multiple files)? As this part of the course is now ending, I would like to archive it on my hard disk for future reference and am wondering about whether there is one location with all the video/lecture note/other files like they have for Coursera and Udacity courses. Thanks!
UserIdTAG: 539593
UserNameTAG: RomanLajciak
CreateTimeTAG: 2013-03-23T16:39:43Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 373
TitleTAG: Intro to Multivariate Statistics
This three-part course is a useful statistics refresher for me and I would like to thank the professor, Berkeley and EdX for offering it. I would be really interested in taking this further and delving into multivariate statistics. Is Berkeley/EdX going to offer something like that in the near future? As far as I know, there are no online introductions to multivariate statistics here or on Coursera or on Udacity, so it would be a useful niche to cover from EdX perspective too.
UserIdTAG: 539593
UserNameTAG: RomanLajciak
CreateTimeTAG: 2013-03-23T16:35:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Isn't what you propose a bit too deep and focused for the usual purposes of a MOOC? We would be slowly edging towards a masters in statistics if such a course does take place...I would be delighted as well...but for free? I doubted
FirstChildUserIdTAG: 902212
FirstChildUserNameTAG: trigeor
FirstChildCreateTimeTAG: 2013-03-23T18:34:30Z
FirstChildVoteTAG: 0
SecondChildTAG: Well, there are plenty of free courses on other advanced subjects being offered online. I think you need much more than a multivariate statistics course to obtain a degree in statistics.
SecondChildUserIdTAG: 539593
SecondChildUserNameTAG: RomanLajciak
SecondChildCreateTimeTAG: 2013-03-24T10:49:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Multivariate (bivariate) statistics has been introduced in the last part of the course. Regression is done over two variables, so multivariate statistics is already here, a bit of it.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-23T20:15:44Z
FirstChildVoteTAG: 0
SecondChildTAG: Although you are technically correct that two variables already are 'multiple' i.e. more than one, multivariate statistics generally refers to statistics of more than two variables.
SecondChildUserIdTAG: 539593
SecondChildUserNameTAG: RomanLajciak
SecondChildCreateTimeTAG: 2013-03-24T10:45:57Z
SecondChildVoteTAG: 0
IndexTAG: 374
TitleTAG: A little doubt about residual plot 2D !
I have a little doubt about residual plot 2D, for the first look it looks like a formless blob around the horizontal axis...mmm but I think their is a little trend I don't know if anyone else like me has seen it, it's confusing !
UserIdTAG: 773907
UserNameTAG: Redouanekh
CreateTimeTAG: 2013-03-23T15:41:32Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: I'm also finding detecting a trend difficult - I know what to look for but have little success in identifying it!
FirstChildUserIdTAG: 1026491
FirstChildUserNameTAG: Rob_M
FirstChildCreateTimeTAG: 2013-03-23T15:44:48Z
FirstChildVoteTAG: 0
SecondChildTAG: You said that you know what to look for, can you tell me what is it ?
SecondChildUserIdTAG: 773907
SecondChildUserNameTAG: Redouanekh
SecondChildCreateTimeTAG: 2013-03-23T16:32:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry, I wasn't clear - I meant I know what to look for "in theory". I know what a trend is, but have difficulty applying it to the examples given in Exercise 10-1. If it's any consolation, I think the answers in question 2 are easier than Exercise 10-1. In question 2 I don't think the staff are trying to provide ambiguous examples - they are exaggerated examples. So I think you will be able to clearly identify a trend/non-zero mean of residuals when you see one.
SecondChildUserIdTAG: 1026491
SecondChildUserNameTAG: Rob_M
SecondChildCreateTimeTAG: 2013-03-23T19:38:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Finally I answered this question and it was correct ! Yipeee
SecondChildUserIdTAG: 773907
SecondChildUserNameTAG: Redouanekh
SecondChildCreateTimeTAG: 2013-03-23T20:01:59Z
SecondChildVoteTAG: 0
IndexTAG: 375
TitleTAG: Difficulty in determining whether the mean of the residuals is non-zero?
I have been looking at the examples and exercise at http://statistics.berkeley.edu/~stark/SticiGui/Text/regressionDiagnostics.htm#residual_plot , and have been struggling to understand when the mean of the residuals is non-zero. Could anyone shed some light on what I'm missing (without giving the answer away to the questions above!). I have consistently got Exercise 10-1 wrong, so am clearly missing something. Or is it just my eyesight?
Thanks!
UserIdTAG: 1026491
UserNameTAG: Rob_M
CreateTimeTAG: 2013-03-23T15:10:15Z
VoteTAG: 8
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 5
FirstChildTAG: Is it something about the white points of data in the residual plot?
FirstChildUserIdTAG: 1026491
FirstChildUserNameTAG: Rob_M
FirstChildCreateTimeTAG: 2013-03-23T15:43:12Z
FirstChildVoteTAG: 0
FirstChildTAG: I have the same problem. To me, Fig.10-4 and 10-5 are just the same. I don't really see why the mean of the residuals is not zero.
FirstChildUserIdTAG: 894138
FirstChildUserNameTAG: erodola
FirstChildCreateTimeTAG: 2013-03-23T19:36:36Z
FirstChildVoteTAG: 0
FirstChildTAG: In exercise 10-1, I look at the coordinates of the red point (point of averages), but it is not easy to see if the y-coordinate is 0 or not because of the scale. Is there another method?
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-23T21:33:22Z
FirstChildVoteTAG: 0
SecondChildTAG: If you hover your mouse over the point of averages, it's coordinates will appear at the bottom of the chart. Also, if you hit the "regression line" button, it will show the regression line. This line should be equal to y=0; horizontal and crossing the y-axis at 0. If it's slanting, the mean is non-zero and the residuals show a trend. If it's not at y=0, the y-intercept of the regression line was calculated wrong.
SecondChildUserIdTAG: 1002202
SecondChildUserNameTAG: ury949
SecondChildCreateTimeTAG: 2013-03-25T04:51:48Z
SecondChildVoteTAG: 0
SecondChildTAG: The coordinates are often non-zero (because of the scale) when the answer tells us that the residuals do have zero mean.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-25T09:32:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Leaving aside non-zero mean , correlation between residuals and x-axis independent variable is another basis for determining incorrect calculation. I was also not clear about regression diagnostics. reading chapter 10 of online text and listening to last 5-6 min. of 39 min. video lecture 8.2 by Prof. A helped me.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-24T12:59:52Z
FirstChildVoteTAG: 0
FirstChildTAG: The mean of the residual plot is not zero when the line of regression is not the line y=0; horizontal and crossing the y-axis at zero. If the line (which is the mean of the residuals) is horizontal through a different y-intercept (not zero), the mean is non-zero. If the line is slanting, the residuals show a trend.
FirstChildUserIdTAG: 1002202
FirstChildUserNameTAG: ury949
FirstChildCreateTimeTAG: 2013-03-25T04:56:54Z
FirstChildVoteTAG: 0
SecondChildTAG: I saw examples in exercise 10-1 where the line of regression is not y=0 en the answer says that the residuals have zero mean.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-25T09:33:52Z
SecondChildVoteTAG: 0
IndexTAG: 376
TitleTAG: Frustrated and annoyed
I got 3B & 3C wrong despite understanding the calculations. Take care with rounding as this is what tripped me up on 3C. I went back to answer 3B after getting 3C wrong and I don't know if there is a technical problem but I entered the correct answer on my third attempt and it returned a big red X. When I went back to study where I went wrong, it showed me a different calculation but gave me another shot at it. Believing my last answer was wrong, I entered another answer which was wrong and then the explanation showed me that my third answer was in fact correct despite marking it wrong (I still had the applet open so I knew my answer was right).
Sorry for the rambling post but I am really annoyed and frustrated about this and a word of caution to anyone who is still working through the problems - take care when entering your answers.
UserIdTAG: 965242
UserNameTAG: Bev1969
CreateTimeTAG: 2013-03-23T14:56:27Z
VoteTAG: 3
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Hello,
I regret your situation. I also got X ... but unlike you I had not idea how to solve the problems. Neither I understand explanations
Maybe If you explain me. You feel better, because your knowledge will be valuable for me.
Thanks =)
PD: my english is not very good.
FirstChildUserIdTAG: 1280316
FirstChildUserNameTAG: JameRebolledo
FirstChildCreateTimeTAG: 2013-03-23T15:44:06Z
FirstChildVoteTAG: 2
SecondChildTAG: Hi JameRebolledo, I wish I could help you, however, I would be breaking the honor code. If you watch the lectures again, the answers are there.
p.s - your English is very good.
SecondChildUserIdTAG: 965242
SecondChildUserNameTAG: Bev1969
SecondChildCreateTimeTAG: 2013-03-23T22:40:46Z
SecondChildVoteTAG: 0
IndexTAG: 377
TitleTAG: [STAFF] Inquiry
Hello dear staff and co-students,
I dwelt in anonymity to attract curiosity and mystery. :)
It has dawned on me how extremely damaging to one's performance the misunderstanding and/or misconception of how the second-to-the-last three exercises will be released, altogether with the midterm exam.
I comprehend that no one but us, probable online delinquents or online access-constrained students, are at fault for not always checking out what could be happening online especially in EDX - a convergent portal offering free access to quality education.
I just have a simple question, in behalf of everyone of those who failed to answer either or all of the three exercises last week, whether or not they were able to finish the midterms.
Would it be possible for our beloved staff, and with approval of our classmates, that even just one special assignment (applicable for all, yet not compulsory) be given to at least get back on track for the triple major credit loss, perhaps enhance everyone's performance, and save those who are almost at the brink of failing?
I know that there's still a final exam to lift us up, but as a competitive learner, I feel bad that I won't be able to raise my grade, to a level that I wish I could have reached, had I been able to update 2.1x after finishing the midterm.
While this reasoning seems to have piled up from a mix of misfortune and short-sighted responsibility, it may be noted that there are students here who are virtually-incapacitated, while others are squeezed off their time as they balance work, real-time conventional schooling, online learning, and the other facets of everyday living.
It's a bit saddening, especially for those who do not have easy access to the online platform, that all three exercises and the midterm were all released in just one week.
Must I clarify that this is, by no means and not at all, a demand but just a simple inquiry.
Thank you for taking time to read this note. And thank you for bringing BerkeleyX closer to everyone's reach. Apologies for my poor use of words.
*I did this because I know there's nothing to lose if I simply ask.*
For me, it's not just about the grades nor the certificate. It's about the sense of accomplishment - the wish-I-could-have's.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-23T14:18:40Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: no need to worry about grades.the certificate will only say you passed the programme-your final grade wont be seen.if you have over 35% you are just fine.
FirstChildUserIdTAG: 1110226
FirstChildUserNameTAG: pittnik
FirstChildCreateTimeTAG: 2013-03-23T14:46:34Z
FirstChildVoteTAG: 4
SecondChildTAG: His/her concern is not about grades, but about a sense of accomplishment.
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-23T19:38:34Z
SecondChildVoteTAG: 0
FirstChildTAG: I fell behind as well, and that's something I have to accept. What about completing the assignments on your own after the class is over? (Print out the answers in case we can't access them at a later date.) That would take even more self-discipline and should give you a sense of accomplishment.
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-23T19:47:26Z
FirstChildVoteTAG: 2
IndexTAG: 378
TitleTAG: problem 3C
Please help me I don't know were I make a mistake
r.m.s = 0.42
(8-7)/1.2=0.83
0.83*0.55= 0.457
0.457*0.5+14= 14.2
z = (15-14.2)/0.42 =1.90
And when I used the applet the answer was 2.9
where is mistake?
UserIdTAG: 336649
UserNameTAG: Roksolana
CreateTimeTAG: 2013-03-23T12:40:24Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: your rounding in the end was wrong - use higher precision
FirstChildUserIdTAG: 525070
FirstChildUserNameTAG: YL_
FirstChildCreateTimeTAG: 2013-03-23T14:55:56Z
FirstChildVoteTAG: 0
SecondChildTAG: It got me too.
SecondChildUserIdTAG: 344400
SecondChildUserNameTAG: carlallen
SecondChildCreateTimeTAG: 2013-03-23T21:44:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I tried but it still wrong =(
SecondChildUserIdTAG: 336649
SecondChildUserNameTAG: Roksolana
SecondChildCreateTimeTAG: 2013-03-23T22:10:24Z
SecondChildVoteTAG: 0
SecondChildTAG: First, you round-off easily.
Secondly, you are using the applet wrongly...
SecondChildUserIdTAG: 1174140
SecondChildUserNameTAG: dipotepede
SecondChildCreateTimeTAG: 2013-03-24T11:58:17Z
SecondChildVoteTAG: 0
SecondChildTAG: please,help me. I had,that z =1.8353 and I used the applet the answer was 2.9 too. So I have mistake...Write me please, right answer after using applet, because I tried 2,9 ,but it wrong...please help me, because I need to understand, where I have a mistake when using applet
SecondChildUserIdTAG: 1172999
SecondChildUserNameTAG: Anastasiya145
SecondChildCreateTimeTAG: 2013-03-24T16:45:35Z
SecondChildVoteTAG: 0
SecondChildTAG: i also found this incrediby frustrating because of the rounding. if you just do the whole thing on your calculator, without rounding at all, then you'll get the answer
SecondChildUserIdTAG: 1307321
SecondChildUserNameTAG: lvasta
SecondChildCreateTimeTAG: 2013-03-24T21:05:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Check your rounding...I have used 4 decimals to get the correct answer... hope it help.
SecondChildUserIdTAG: 1238533
SecondChildUserNameTAG: JoGonzalez
SecondChildCreateTimeTAG: 2013-03-25T02:20:48Z
SecondChildVoteTAG: 0
SecondChildTAG: use all decimals places in any calculations you have to do.
SecondChildUserIdTAG: 1250949
SecondChildUserNameTAG: barcay
SecondChildCreateTimeTAG: 2013-03-25T03:07:45Z
SecondChildVoteTAG: 0
IndexTAG: 379
TitleTAG: Answers for Week 4
Respected Prof,
Answers for week 4 of exercises have not been uploaded as yet.Please upload the same at the earliest
Dr.Harish
UserIdTAG: 1175422
UserNameTAG: harish09
CreateTimeTAG: 2013-03-23T12:32:47Z
VoteTAG: 4
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: I feel the delay in the answers appearing will affect a lot of people's preparation for the final exam.
FirstChildUserIdTAG: 119039
FirstChildUserNameTAG: Alan56
FirstChildCreateTimeTAG: 2013-03-23T16:36:34Z
FirstChildVoteTAG: 1
IndexTAG: 380
TitleTAG: answer to 3C
i did exactly how it was done and got answer as 3.17. but twice it showed wrong for just a decimal mistake.
and later wrongly entered the value by multiplying with 2.
Any help
UserIdTAG: 1010579
UserNameTAG: maheshboss1984
CreateTimeTAG: 2013-03-23T12:30:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 0
IndexTAG: 381
TitleTAG: MSAT
What is a MSAT in this problem?
Problem 1 : 0.0 points
SAT scores of freshmen at a large university have an average of 600 and an SD of 75. The GPAs of the freshmen have an average of 2.9 and an SD of 0.35. The correlation between the two variables is 0.4 and the scatter diagram is football shaped.
Scores are typically stated without units, so just to be clear: in what follows, a description like “the GPAs that are more than 0.2 away from 3” means all the GPAs below 2.8 as well as all the GPAs above 3.2.
1A. About what percent of the freshmen have GPAs that are more than 0.5 away from 2.9?
unanswered
1B. About what percent of the freshmen have GPAs that are more than 0.5 away from the regression estimate of GPA based on their MSAT score?
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-23T12:24:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: There is a typo in the problem. For this problem SAT=MSAT
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-23T12:49:46Z
FirstChildVoteTAG: 0
IndexTAG: 382
TitleTAG: A question about courses...
Will 2.2X be on edX? Can I get the course on edX?
UserIdTAG: 1168549
UserNameTAG: dave1011
CreateTimeTAG: 2013-03-23T10:08:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It has been asked many times.
2.2x will be on EdX "shortly". I don't think we have a certain date yet, but it should be a matter of weeks ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-23T10:53:22Z
FirstChildVoteTAG: 0
IndexTAG: 383
TitleTAG: qtn 3c help...
somebody please tell me where am going wrong with 3c..i got the ave head circumferene estimate.used that average to get how far 15 inches is from it. divided by sd which is rms error..got % of that from appelet then got difference..where am i going wrong
UserIdTAG: 815453
UserNameTAG: warinda
CreateTimeTAG: 2013-03-23T09:47:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: the question says:
>what percent have head circumferences **larger** than 15 inches?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-23T10:15:56Z
FirstChildVoteTAG: 0
FirstChildTAG: This sucks :( just because i took 3 decimal places in instead of 2 and didnt round off my answer is wrong by 0.5% ! C'mmon!
Calculations are perfectly right.
FirstChildUserIdTAG: 254949
FirstChildUserNameTAG: stormshadow
FirstChildCreateTimeTAG: 2013-03-23T13:07:59Z
FirstChildVoteTAG: 1
SecondChildTAG: A multibillion dollar company that makes rounding errors potential wipes out millions of dollars! This is an important aspect of the class, and as such the calculations did have an error.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-23T14:01:50Z
SecondChildVoteTAG: 0
SecondChildTAG: yeah but in the lecture it was always rounded to the nearest percent so i did the same, still would have gotten it wrong if i used my more exact numbers as i kept more decimal places in my calculations, i had 3.2% if i did that.
SecondChildUserIdTAG: 977255
SecondChildUserNameTAG: Jonhern
SecondChildCreateTimeTAG: 2013-03-25T01:35:57Z
SecondChildVoteTAG: 0
IndexTAG: 384
TitleTAG: exc. set 12
this was my worst performance in all the excercise sets.
Dear Ani/forum members,even now I am not clear about regression plots, how to identify them if average is not given in the scatter plot, whether calculation is wrong. kindly clarify my doubt.
UserIdTAG: 1311995
UserNameTAG: podilashree
CreateTimeTAG: 2013-03-23T09:34:01Z
VoteTAG: 4
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Go though chapter 10 of online text and last 5-6 min of Prof. Ani's 39 min. video lecture 8.2 .
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-24T13:03:49Z
FirstChildVoteTAG: 0
FirstChildTAG: I never figured out how to choose more than one answer in the online text book exercise at the end of the chapter. Like many, somewhat miffed on how to determine nonlinearity, non-zero about the regression line and finding a trend. The online lecture was excellent, but simply incomplete on this.
FirstChildUserIdTAG: 975799
FirstChildUserNameTAG: lmacareo
FirstChildCreateTimeTAG: 2013-03-24T22:52:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Holding ctrl while clicking will let you select multiple answers on the exercise 10-1.
SecondChildUserIdTAG: 1002202
SecondChildUserNameTAG: ury949
SecondChildCreateTimeTAG: 2013-03-25T05:15:58Z
SecondChildVoteTAG: 0
IndexTAG: 385
TitleTAG: Solutions to Exercises
Professor,
It appears that the solutions to exercises 9, 10 and 11 are not available. Could you please make these available as they will be helpful in the preparation for the finals?
Thanks
UserIdTAG: 65480
UserNameTAG: Ansh04
CreateTimeTAG: 2013-03-23T07:15:15Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 386
TitleTAG: Why use Standard Units?
Could someone give some understanding what the geometrical significance is of the scaling by the SD's? That is, I get that we want the average point at (0,0) but that is done by a simple shift of either variable by their means. What do we gain by scaling them further by the SD's (as is done in Standard Units)?
Does this (the slope of the line of averages being = "r") have anything to do with the fact that 1 unit along either axis represents 1 SD of that variable?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-23T06:55:01Z
VoteTAG: 1
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 0
IndexTAG: 387
TitleTAG: India Help in Spreading
Help in promoting this page :
http://www.facebook.com/pages/Being-Engineer/175303765955875
Thanks.
UserIdTAG: 303485
UserNameTAG: iparitosh
CreateTimeTAG: 2013-03-23T06:32:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 388
TitleTAG: 2E. Two answers right!, be carefull , you have to select well
Come on! Please someone have to review the questions. Of course the mean is not zero, but the shape is...non-linear. When the answers are so obvious... and right!. Don't play with us. The question is also incorrect! Two in five. Please review the questions.
UserIdTAG: 176020
UserNameTAG: JMER
CreateTimeTAG: 2013-03-23T06:08:15Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: The problem asks for "the best available" answer, suggesting that some times, there might be more than one. I thought that the posted solution(*"Show Answer"*) for 2E explains fairly well why one of them is "worse" than the other.
But as we shouldn't discuss answers before the due date for the Exercises, we can't go into more detail than this.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-23T11:00:42Z
FirstChildVoteTAG: 1
FirstChildTAG: > The question is also incorrect! Two in five. Please review the questions.
Actually, no. None in five.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-23T11:12:06Z
FirstChildVoteTAG: 0
SecondChildTAG: a little harsh Susan - but no surprise there given how you posted in ph207x
SecondChildUserIdTAG: 636154
SecondChildUserNameTAG: jcmcdonn
SecondChildCreateTimeTAG: 2013-03-23T14:53:50Z
SecondChildVoteTAG: 0
SecondChildTAG: wow .. can't we all just get along here? You, Sir ..
SecondChildUserIdTAG: 951821
SecondChildUserNameTAG: JohnMcd
SecondChildCreateTimeTAG: 2013-03-23T19:45:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Harsh? No. Factual. Harsh are those who think they know more than the professional staff, and come on the board screaming in outrage. And in the vast majority of cases, they are wrong.
You should have seen what I didn't post.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-23T23:13:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I felt a little bit same with jcmcdonn, but Susan helped me a lot. You can say it as I like strong woman. Susan Ganbare!
SecondChildUserIdTAG: 200548
SecondChildUserNameTAG: kame
SecondChildCreateTimeTAG: 2013-03-24T02:35:59Z
SecondChildVoteTAG: 0
IndexTAG: 389
TitleTAG: 1B. Tell me how you can decide wether the scatter plot is football shape or not
I do not know the shape of the catter plot if i can't see it. It is a mistake in this question. The answer is not right. Please correct it!
UserIdTAG: 176020
UserNameTAG: JMER
CreateTimeTAG: 2013-03-23T06:00:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: > It is a mistake in this question. The answer is not right. Please correct it!
No, it is not a mistake. The Show Answer explains why.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-23T06:07:38Z
FirstChildVoteTAG: 0
SecondChildTAG: i don't understand, my answer is 'Maybe, or maybe not; there is not enough information to decide'...why is not right?
SecondChildUserIdTAG: 1172999
SecondChildUserNameTAG: Anastasiya145
SecondChildCreateTimeTAG: 2013-03-24T16:56:46Z
SecondChildVoteTAG: 0
SecondChildTAG: Read this link: http://statistics.berkeley.edu/~stark/SticiGui/Text/correlation.htm where says: Football-shaped scatterplots can be summarized rather well by five numbers:
SecondChildUserIdTAG: 515654
SecondChildUserNameTAG: esmaylinfrancini
SecondChildCreateTimeTAG: 2013-03-25T17:49:03Z
SecondChildVoteTAG: 0
FirstChildTAG: It looks like I have misunderstanding here.
Football shaped plot means both values are normally distributed which in turn means that we can use correlation (r) here. If a variable is not normally distributed, how can we use regression estimate (e.g. RMS error of regression, correlation (r), etc.)?
FirstChildUserIdTAG: 255838
FirstChildUserNameTAG: EngineerHrenov
FirstChildCreateTimeTAG: 2013-03-24T11:35:07Z
FirstChildVoteTAG: 0
SecondChildTAG: Correlation doesn't depend on scatter diagrams being football shaped, though with football shaped diagrams it's most easy to see how correlation behaves. The regression estimates are the "least squares" estimates no matter what the shape of the scatter. The formula for the r.m.s. error is also correct regardless of the shape of the scatter. What you cannot do if the scatter is not football shaped is use any normal approximation; that might be a really bad idea. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-24T19:03:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you!
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-24T20:11:20Z
SecondChildVoteTAG: 0
FirstChildTAG: Since post is in relation to a exercise set still due, I can only reassure that question 1b is correct and has all relavent information.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-24T13:09:10Z
FirstChildVoteTAG: 0
IndexTAG: 390
TitleTAG: Link to the normal distribution applet?
This is the humble request to the staff to provide the link of normal distribution applet to all the exercises which require its use.
UserIdTAG: 1416809
UserNameTAG: mehrotravinit
CreateTimeTAG: 2013-03-23T05:09:40Z
VoteTAG: 5
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: Try looking at past exercise sets, there should be the link somewhere. Also, you could use z-score tables available all over the internet. Have a nice day!
FirstChildUserIdTAG: 1267887
FirstChildUserNameTAG: VLtr
FirstChildCreateTimeTAG: 2013-03-24T15:13:01Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes, while I agree with the above poster that the applet link should be pasted everywhere it is likely to be used, I too have found that a z-score chart is generally easier to use.
SecondChildUserIdTAG: 529507
SecondChildUserNameTAG: Lasker
SecondChildCreateTimeTAG: 2013-03-24T20:42:22Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with the first poster. The link to the applet should be posted constantly and everywhere. I ended up saving the link as a bookmark. That finally relieved my stress of constantly trying to figure out where it was linked to last.
FirstChildUserIdTAG: 975799
FirstChildUserNameTAG: lmacareo
FirstChildCreateTimeTAG: 2013-03-24T22:56:05Z
FirstChildVoteTAG: 1
FirstChildTAG: I've made a lot of mistakes because of this "missed" link.
FirstChildUserIdTAG: 1222674
FirstChildUserNameTAG: r2s2
FirstChildCreateTimeTAG: 2013-03-25T01:18:24Z
FirstChildVoteTAG: 0
IndexTAG: 391
TitleTAG: median definition given?
"At least half the data are equal to or smaller than the median, and at least half the data are equal to or greater than the median." if the median is one of the dataset then how can this be?
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-03-23T05:02:50Z
VoteTAG: 0
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.2: The average: calculation and basic properties
NumberOfReplyTAG: 2
FirstChildTAG: It's kinda like this: if some variable called x is greater than some value a, and less than some value b, then x is contained in the set containing all values from a to b. Similarly, the median is larger than the smallest datum, and smaller than the largest datum. Therefore, it must be a value between the smallest and the largest. Well, perhaps the middle value is between two datum, then you just pick the larger one. In that way, the median is always in the data set.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-23T05:11:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks rosewoodbay, reading this whilst listening to Hound Dog Taylor & the Houserockers, so ....
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-24T10:30:40Z
SecondChildVoteTAG: 0
FirstChildTAG: A quick example can make this clearer, perhaps?
Suppose you have the dataset [1,3,4,10,15,80]. What's the median? Well, the median, as you wrote, is that value for which ""At least half the data are equal to or smaller than the median, and at least half the data are equal to or greater than the median.".
Now, in this example, both 4 and 10 match the criteria:
- 1,3,4 are equal to or smaller than 4, 3 out of 6 values, so that's exactly half of the data.
4,10,15,80 are equal to or greater than 4, 4 out of 6 values, definitely at least half of the data.
- 1,3,4,10 are equal to or smaller than 10, 4 out of 6 values, again, at least half of the data.
10,15,80 are equal to or greater than 10, exactly half of the data.
So you could theoretically pick either of them. But by convention, we take the smallest number, so here, the median is **4**.
See Lecture 2.5 for a review of this.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-23T11:21:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks K, perfect explanation, simple, it's locked in for eternity, where's those questions .....
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-24T10:32:53Z
SecondChildVoteTAG: 0
SecondChildTAG: And it works for a odd numbered dataset as well, amazing ....
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-24T10:35:39Z
SecondChildVoteTAG: 0
SecondChildTAG: And I think your explanation is a tad easier to comprehend than 2.5, just went back and reread it, mark
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-24T10:55:31Z
SecondChildVoteTAG: 0
IndexTAG: 392
TitleTAG: Why
Why didn't I see this out (Exercise 8-10) when the Midterm Exam was released? :( I missed all three (3)! :( I was very complacent thinking that on Midterm Week, the exercises won't be released since only the Midterm Exam showed up first - only to realize just now that 3 exercise sets are overdue.
UserIdTAG: 16973
UserNameTAG: TerrEpic_Dude
CreateTimeTAG: 2013-03-23T03:59:30Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: > Why didn't I see this out (Exercise 8-10) when the Midterm Exam was released?
Because they were posted after the test. This was explained on the post regarding the midterm on the Course Info page.
![enter image description here][1].
And the Course Schedule has the due dates for all the exercise sets.
[1]: https://edxuploads.s3.amazonaws.com/13640114791343616.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-23T06:01:25Z
FirstChildVoteTAG: 0
IndexTAG: 393
TitleTAG: Problems
I'm sorry I can not finish the week 11th, I had been problems with the system! I got the solution
But my score will be down!! :((
UserIdTAG: 672958
UserNameTAG: Patbustamante
CreateTimeTAG: 2013-03-23T01:24:04Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 0
IndexTAG: 394
TitleTAG: What about Mode as an estimate?
Wouldn't the mode, seeing that it is the one that appears most frequently, be a better first estimate than the average?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-23T00:41:10Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 1
FirstChildTAG: The mode is very unstable. It's far to easy to drastically change the mode. Besides, the calculus tells us that when we want to minimize the distance from some central location to any datum, the regression line is the best choice.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-23T05:16:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-03-23T05:43:31Z
SecondChildVoteTAG: 0
IndexTAG: 395
TitleTAG: Residual plots!!!!!
Differentiating between calculations done incorrectly and non linearity in residual plots is really mind boggling. I seem not to get the hang of it
UserIdTAG: 422336
UserNameTAG: lilian2012
CreateTimeTAG: 2013-03-22T23:17:53Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Did you look at the examples in the online textbook (Sticigui)? It makes more sense to me and I got a lot out of it.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-23T03:03:24Z
FirstChildVoteTAG: 0
SecondChildTAG: I did but I guess I just need enough time to go over it slowly
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-23T10:02:00Z
SecondChildVoteTAG: 0
IndexTAG: 396
TitleTAG: Why does r represent linear association?
Prof A, could you please supplement your supplements with the algebraic explanation of why is it that "r" measures linear association?
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-22T22:35:48Z
VoteTAG: 3
CoursewareTAG: Section 6: Relation between two variables / Lec 6.2: The correlation coefficient: calculation and properties
NumberOfReplyTAG: 0
IndexTAG: 397
TitleTAG: additional practice for the final
I am not able to see this. I am using Chrome browser and have not had any trouble before seeing the exercises.
UserIdTAG: 4612
UserNameTAG: Susnaj
CreateTimeTAG: 2013-03-22T22:09:16Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No, looks like there might be a little problem. Not there in Chrome or Firefox.
Edit: link is gone now.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T22:38:01Z
FirstChildVoteTAG: 0
SecondChildTAG: I saw the link just fine yesterday, but it's gone today.
SecondChildUserIdTAG: 1289355
SecondChildUserNameTAG: DaRitz
SecondChildCreateTimeTAG: 2013-03-23T12:46:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Same problem: there yesterday and gone today.
SecondChildUserIdTAG: 1343670
SecondChildUserNameTAG: rleonetti
SecondChildCreateTimeTAG: 2013-03-23T20:28:18Z
SecondChildVoteTAG: 0
IndexTAG: 398
TitleTAG: Answers to exercise sets 9, 10, and11
Please post answers to these exercise sets with solutions. Needed to study for final exam
UserIdTAG: 274577
UserNameTAG: scanning
CreateTimeTAG: 2013-03-22T21:45:51Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 399
TitleTAG: Regressing X on Y
In the text book (Chapter 9, below exercise 9.3) it is said that the slope of the correlation line for regressing X on Y is: SDy/rSDx, is that correct?
Wouldn't it be SDx/rSDy? Or am I wrong?
Thank you
UserIdTAG: 918956
UserNameTAG: a-per
CreateTimeTAG: 2013-03-22T20:02:46Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 2
FirstChildTAG: It doesn't make a difference which axis you use.
FirstChildUserIdTAG: 164614
FirstChildUserNameTAG: LuketheEngineer
FirstChildCreateTimeTAG: 2013-03-23T20:14:07Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm not quite picturing it myself, but since he said that the residuals are horizontal instead of vertical, then X and Y do not switch axes, so rise over run is the same: SDy over SDx. Regarding why r goes to the demoninator, here's my guess: You're taking the graph of averages of slices of Y instead of slices of X, so your residuals are horizontal instead of vertical. Since r goes to the denominator, then the slope, SDy/r*SDx, would be steeper for regressing X on Y than for regressing Y on X. A confirmation from the faculty would be helpful!
FirstChildUserIdTAG: 945111
FirstChildUserNameTAG: judithpdx
FirstChildCreateTimeTAG: 2013-03-25T19:56:14Z
FirstChildVoteTAG: 0
IndexTAG: 400
TitleTAG: query
can anyone advice me some other course related to management which i can do it now?
UserIdTAG: 1463746
UserNameTAG: harshpal27
CreateTimeTAG: 2013-03-22T19:33:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You need to go to the edX home page and look at the courses on offer. There are also courses on Coursera.
You could also ask on the edX facebook page. I know I have read a few requests for management courses. They say they take all requests into consideration. But I suppose they have to find an institution prepared to take on the teaching. And that is a BIG ask.
http://www.facebook.com/EdxOnline
https://www.coursera.org/courses
Haven't had a good look at this site, but it says it has a listing of all available moocs. I've linked to the management page:
http://www.mooc-list.com/categories/business-management
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T21:44:56Z
FirstChildVoteTAG: 0
IndexTAG: 401
TitleTAG: Response originally shown correct, vanished subsequently, and reset- software issue?
I had completed 2A with the correct response and progress showed this as complete (ie I got 12/15) - overall completion on exercises at 94%. Then suddenly when I reloaded the sheet, this showed a blank, and i hit a check, because I thought something had gone wrong. It has marked it wrong, and has scored me down by 2points. Is there a software issue?
UserIdTAG: 953642
UserNameTAG: Anand1963
CreateTimeTAG: 2013-03-22T19:04:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Sorry 3A, not 2A
FirstChildUserIdTAG: 953642
FirstChildUserNameTAG: Anand1963
FirstChildCreateTimeTAG: 2013-03-22T19:04:56Z
FirstChildVoteTAG: 0
IndexTAG: 402
TitleTAG: Answers
please provide with the answers so that we can make our corrections
UserIdTAG: 461939
UserNameTAG: 66
CreateTimeTAG: 2013-03-22T18:49:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section6_Lec_6_3/threads/514bec3908fa521600000173
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-22T19:18:53Z
FirstChildVoteTAG: 0
IndexTAG: 403
TitleTAG: I love your sense of humor and clarity professor.
Thank you. It definitely makes the lectures much more engaging.
UserIdTAG: 291189
UserNameTAG: zenjen
CreateTimeTAG: 2013-03-22T18:35:28Z
VoteTAG: 16
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 1
FirstChildTAG: True
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-03-22T19:36:06Z
FirstChildVoteTAG: 0
IndexTAG: 404
TitleTAG: Possible an Error
Hello there
I was thinking that there might be an error in first numerical example of third video at 20:00 minutes.
The question is to find the percent of weight within 40 pounds based on height.
Then you calculate 40/17.32=2.31. So by saying the estimate of percent is between -2.31 and +2.31 means, that the percentance you are looking for is between +40 and -40 pounds (total of 80 pounds) whitch is wrong according to the question whitch asking for +20 -20 between regrasion line.
UserIdTAG: 1090983
UserNameTAG: AchilleasP
CreateTimeTAG: 2013-03-22T17:43:31Z
VoteTAG: 2
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 2
FirstChildTAG: You want to find the percent of weight within 40 pounds based on height. If someone is +39.99 pounds, this is within 40 pounds. If someone is -39.99 pounds, this is within 40 pounds.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-22T19:24:08Z
FirstChildVoteTAG: 0
FirstChildTAG: It is okay the way it is. Within 40 pounds mean you can be within the range of 40 pounds lighter or 40 pounds heavier from the average.
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-03-22T19:26:57Z
FirstChildVoteTAG: 0
IndexTAG: 405
TitleTAG: See you soon, Prof. A.
I'm really glad and proud of being part of this "first generation" of the Stat2.1x.
I guess I've done it pretty well (so far...), and I have learned and understood a lot of things.
Congratulations to you, Prof. A., and the staff. You are such a great teacher!
I can hardly wait for the start of Stat2.2x!
UserIdTAG: 797704
UserNameTAG: Hersan13
CreateTimeTAG: 2013-03-22T17:27:32Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 406
TitleTAG: [STAFF] Answers to study for final
Some of the students have families and cannot study on the weekends. We need the answers for Exercises 9, 10, and 11 ASAP.
UserIdTAG: 64151
UserNameTAG: guba11ro
CreateTimeTAG: 2013-03-22T16:36:49Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section6_Lec_6_3/threads/514bec3908fa521600000173
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-22T19:19:19Z
FirstChildVoteTAG: 0
IndexTAG: 407
TitleTAG: [Staff] Question on the text, The Regression Line section
In the text it says:
*Minimizing the square root of the sum of the squares of the residuals (the rms of the residuals) is equivalent to minimizing the sum of the squares of the residuals. For this reason the regression line is sometimes called the least squares line.*
Since the text refers to rms, shouldn't this read as follows?
*Minimizing the square root **of the mean** of the sum of the squares of the residuals (the rms of the residuals) is equivalent to minimizing **the mean of** the sum of the squares of the residuals. For this reason the regression line is sometimes called the least squares line.*
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-03-22T16:36:02Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Not "the mean of the sum of squares". As a starting point, it's "the mean of the squares," but minimizing "the mean of the squares" is the same as minimizing "the sum of the squares" as the mean is the sum divided by a constant. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-23T21:20:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, makes sense - thanks!
SecondChildUserIdTAG: 433872
SecondChildUserNameTAG: dfburke
SecondChildCreateTimeTAG: 2013-03-24T22:46:49Z
SecondChildVoteTAG: 0
IndexTAG: 408
TitleTAG: Disconnect Between Questions and Lectures
The last practice exercise set demonstrates the complete severance in content between the freestanding video lectures, which are nearly devoid of content, and the online text, which is full of content but short on connecting the information to practical applications and requires acrobatic manipulations to access the normal curve applet and then fills every page with an unneeded glossary that occupied a quarter of the already limited space on the monitor. This course is a terrible disappointment. Poor presentation of material, lack of connection between questions and problems presented in the lectures, and a generally dyspeptic and antisocial teaching assistant who cannot field answers without insulting students. There are better courses elsewhere on edX and Coursera. This one was a waste of time.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-22T15:57:18Z
VoteTAG: 2
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 4
FirstChildTAG: I can't agree. I have found the course well structured with clear examples and a close linkage between lectures and exercises. There was, in my opinion as an educator, a clear progression with no surprises and no hidden traps to trip learners. I'm not familiar with this material but had no problems following the course and the few points dropped on exercises were due to carelessness on my part. Pretty much every problem in the graded exercises and midterm exactly reflected a worked example from the lectures.
I would agree that it would have been helpful to have an easily accessible link for the normal curve applet - but there was always the opportunity to bookmark it.
I think your comments in regard to "a generally dyspeptic and antisocial teaching assistant who cannot field answers without insulting students" are misguided as the person to whom I suspect you are referring is not a staff member but a fellow student doing her best to answer the terribly repetitive questions - most answered in the published course information or already addressed multiple times on the discussion boards. It is a thankless task to tell the twentieth person demanding to know why they can't submit there exercise that it is long past the GMT deadline and it is understandable that the answers sometimes get a little short.
A think that if I were making personal attacks on other posters (unlikely as that seems) it would be common courtesy to post under my own ID rather than anonymously.
There are other courses but the only one paralleling this to any degree is on Coursera and my experience of that one is that it is far less well structured and supported than this.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-22T17:02:59Z
FirstChildVoteTAG: 13
SecondChildTAG: I totally agree with PaulJM.
Thanks to teachers and assistans.
I learnt a lot with the video lectures and explanations of the teacher
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-03-22T18:16:44Z
SecondChildVoteTAG: 0
FirstChildTAG: > freestanding video lectures, which are nearly devoid of content,
Did you even watch the same lectures we did?
> the online text, which is full of content but short on connecting the information to practical applications,
Ok, fair enough. The textbook is a bit dry. That's why we have the lectures from Prof A., much better in my opinion.
> and requires acrobatic manipulations to access the normal curve applet
I never realized switching between tabs on my browser was doing "acrobatic manipulations". I am an acrobat! Yay!
> and then fills every page with an unneeded glossary that occupied a quarter of the already limited space on the monitor.
unless you follow the links in the practice problems, which actually send you on the chapter page without glossary, or open the chapters from the textbook homepage(again, bookmarks and tabs. It's not quantum physics).
> lack of connection between questions and problems presented in the lectures
Again, are you even watching the same lectures we did? I found nothing in the ES that wasn't explained in the lectures, except perhaps part of Problem 2 from this last ES12. Which was explained in the textbook.
> a generally dyspeptic and antisocial teaching assistant who cannot field answers without insulting students.
If someone comes on the forum writing the equivalent of *"WAA! WAA! I'm not having every single thing served on a silver plate like in 1st grade! WAA! Why don't you do everything as I like? WAA!"*, the *best* s/he can expect is some sort of ironic answer. This happened for at least 75% of the posts here. It's bound to make people who actually want to participate in a useful way a bit grumpy.
> There are better courses elsewhere on edX and Coursera. This one was a waste of time.
Goodbye. Close the door behind you, please.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-22T19:02:35Z
FirstChildVoteTAG: 7
FirstChildTAG: Maybe me? Memories, I have a friendly stalker from another course and maybe they have followed me. But I make no apology for losing patience.
A course this size needs order. The forums are a total dog's breakfast at times because of the post repetition. Students need to actually read the course info. In most cases every question about the course has been answered. Multiple times on the forum and usually in the course info. You just have to look for it.
Unfortunately, not all are prepared to spend *their* time looking. Some are even honest about it, saying they don't have the time to look so could someone just tell them? But if you personally don't have the time, why should you expect someone else to spend *their* time doing it for you?
This isn't school. It is independent learning. You need to be proactive and look for info yourself. Not rely on someone else to do all the legwork for you.
This week was more challenging than others. So if this week twisted you in knots, consider what is to follow. The basics are covered. Now is the time to get a bit meaty.
Though I am being very good, and ignoring the dozens of posts asking for last week's answers.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T21:41:28Z
FirstChildVoteTAG: 2
SecondChildTAG: Hi, this is spot-on. This stat course is very good, well structured and convincing. The near ?50,000 students are from all over the globe and not all of have their 1st language as English, further more sort of American English, Australian English or English English may confuse sometimes. I live in Australia but English is not my 1st language.
SecondChildUserIdTAG: 1082215
SecondChildUserNameTAG: Ayee
SecondChildCreateTimeTAG: 2013-03-25T02:25:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Come on, you're being unfair and you know it. I also had a few problems, a couple of disagreements and a genuine hate towards most of the graph questions that failed to stimulate my optical nerve. I've also had Stats at a university level before - and there's the reason I've taken this course: it ended up clearing many misconceptions on various topics. For this, I'm thankful.
FirstChildUserIdTAG: 687022
FirstChildUserNameTAG: ThanosT
FirstChildCreateTimeTAG: 2013-03-25T20:37:57Z
FirstChildVoteTAG: 0
IndexTAG: 409
TitleTAG: QUERY
hi..i have registered for the course on march 22...can i go ahead with all study and pass the exams now or it's late registration?
UserIdTAG: 1463746
UserNameTAG: harshpal27
CreateTimeTAG: 2013-03-22T15:47:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is, just, possible to pass the course - there is only one graded exercise set still within deadline for assessment and the final exam is next week. You would need to achieve 100% on both these remaining elements to get a bare 35% overall mark (the pass).
To be realistic, how much will you be able to learn in the few days remaining? In my opinion you would be better to wait until the course is presented again (no published date but I'd guess September).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-22T17:06:26Z
FirstChildVoteTAG: 0
SecondChildTAG: I think that's the best thing...wait for course to commence again...can u advice me some other alternative course related to management which i can do it now?
SecondChildUserIdTAG: 1463746
SecondChildUserNameTAG: harshpal27
SecondChildCreateTimeTAG: 2013-03-22T17:31:33Z
SecondChildVoteTAG: 0
IndexTAG: 410
TitleTAG: Prof. Ani please explain
While discussing correlation coef. at 4.36 min. at speed 1.25x we are told "..as to why this produces something that measures linearity is something hard to explain in algebraic terms.." but I want to try to learn precisely this in bit detail. The similar gap we notice in discussion of regression line that the line for which residual errors are minimum is regression line with r as the slope. Respected Prof ,in your characteristic simple style ,and fellow students, please tell a little more on this, although it may be beyond the scope of stat2.1x . I am embarrassed but I want to come out of this confusion.
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-22T15:19:45Z
VoteTAG: 1
CoursewareTAG: Section 6: Relation between two variables / Lec 6.2: The correlation coefficient: calculation and properties
NumberOfReplyTAG: 1
FirstChildTAG: Hear hear!
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-22T22:36:31Z
FirstChildVoteTAG: 0
IndexTAG: 411
TitleTAG: Will be posible show the answers of the exercises
Good morning,
I couldn't make the exercise but I need to see the correct answers for the final test.
It's possible show the answers of the excercise?
Thank's
UserIdTAG: 251482
UserNameTAG: rigof80
CreateTimeTAG: 2013-03-22T14:55:28Z
VoteTAG: 2
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section6_Lec_6_3/threads/514bec3908fa521600000173
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-22T19:19:46Z
FirstChildVoteTAG: 0
IndexTAG: 412
TitleTAG: Midterm Q2c
This is a question just to seek understanding, not to grapple for extra marks :)
The right answer to question 2c in the midterm exam was: "The average is bigger than the median." But when I take a look at the histogram obtained from the data (histogram shown below), all my instincts tell me the average should be located closer to the left of the graph, and hence less than the median. Could someone help me out here please...
![histogram for midterm Q2c][1]
[1]: https://edxuploads.s3.amazonaws.com/1363962053203120.jpg
UserIdTAG: 22301
UserNameTAG: Joel_OA
CreateTimeTAG: 2013-03-22T14:22:21Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Remember the definitions.
The median is the value x for which 50% of the values are $\le x$, and 50% are $\ge x$. Due to the big amount of low values, the median is dragged down(or to the left, if you prefer). A quick look at your graph tells us intuitively that the median will be around 6. (5.76, in fact)
The average is a little more complicated to see, but remember that it's heavily influenced by very big values even if there are only a few of them, and this is exactly what happens here. We have several values around 20 or more, which is much higher than 6, and that drags the average up(to the right). In fact, if you actually calculate it(summing all possible values from 0 to 27, multiplied by their relative weight), you get an Average of 6.56.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-22T15:27:02Z
FirstChildVoteTAG: 1
FirstChildTAG: The graphic you have provided is not a histogram. Look at the horizontal axis. 20-28 is occupying the same horizontal distance as 0-4. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-23T21:16:53Z
FirstChildVoteTAG: 0
FirstChildTAG: ![enter image description here][1]
Histogram showing the unequal bins.
[1]: https://edxuploads.s3.amazonaws.com/13640958571343601.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-24T03:32:42Z
FirstChildVoteTAG: 0
IndexTAG: 413
TitleTAG: Accessibility after the course
Will the course materials (including the SticiGui texts) be available/accessible to us after the course ends? This has been one of the best courses I've taken so far and retaining accessibility to the course materials after the course ends would be really helpful.
UserIdTAG: 933932
UserNameTAG: Shadybog
CreateTimeTAG: 2013-03-22T14:02:51Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 414
TitleTAG: EQUATION OF REGRESSION OF MULTIPLE VARIABLE
IF i want to put ( calculate ) equation of regression for multiple variable how r could be calculated based on data & what is equation ( i want to see effect of variable like age( categorial data) , sex ,education ( binary outcome )on patient compliance what to do ( please help ) im not student of statistics
UserIdTAG: 578995
UserNameTAG: Gehan_Basiony
CreateTimeTAG: 2013-03-22T13:42:16Z
VoteTAG: 0
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 1
FirstChildTAG: You don't do this by hand. You will need a statistical program, and $r$ will be included on the output. It is calculated essentially the same way, but involves matrix calculations as you have more than one $x$.
How is patient compliance measured?
> im not student of statistics
Then you really need to talk to someone who does know statistics and get some guidance. The computer will spit out a regression table for you, but you then have to decide whether your results are valid. Then you have to interpret your results. It's not as straightforward as simple regression.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T21:20:53Z
FirstChildVoteTAG: 0
SecondChildTAG: Either you can wait for the continuations of the stat2.1x!!!!!
SecondChildUserIdTAG: 1263723
SecondChildUserNameTAG: Chamikad
SecondChildCreateTimeTAG: 2013-03-24T18:24:43Z
SecondChildVoteTAG: 0
IndexTAG: 415
TitleTAG: 3A - how to find z
I have 3A correct, but I had to guess a bit.
I have found r.m.s. as we can read in explanation, then I have used the applet to find the area of 50% and then I have got z. The last step is clear for me.
My question is how to find z. I have only tried to find correct area via the applet, but I had a luck that I have found it.
Is any way to get z more precisely?
UserIdTAG: 884187
UserNameTAG: Madelenka
CreateTimeTAG: 2013-03-22T13:30:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: I can't think of any easy way of doing it that doesn't involve the applet, but it's pretty easy to do.
Remember that the Standard curve is symmetric, so once you find 25% on one side, you know how far to go to the other side too ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-22T20:33:48Z
FirstChildVoteTAG: 0
FirstChildTAG: To find $z$ given the probability, you need tables of some sort. That could involve using one of the many online applets, actual tables, or one of the many statistical computer programs available.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T21:09:18Z
FirstChildVoteTAG: 0
FirstChildTAG: you dont need to find z.use the formula to find just the RMS error
FirstChildUserIdTAG: 1198994
FirstChildUserNameTAG: parthkelkar
FirstChildCreateTimeTAG: 2013-03-23T11:10:45Z
FirstChildVoteTAG: 0
IndexTAG: 416
TitleTAG: 3c: intermediate calculations rounding
In the solution all values of intermediate calculations are rounded to two decimal places. I calulate problems in Excel, and there no rounding. Thats for I got the answer larger for 0.34 than "right answer". More over, when I get last quantity of SD (on which 15 inches more than mean at 8 pounds, and SD there is r.m.s) and enter that number in normal curve calculation script I got another answer, that is 0.46 larger than "right answer".
I think there two errors in calculations in 3c "right answer".
P.S. sorry for my English
UserIdTAG: 82864
UserNameTAG: AndreyGranenkin
CreateTimeTAG: 2013-03-22T12:55:08Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: The calculations are correct. They have rounded at several places (which I confess really surprises me). I didn't round until the end, and my answer was 0.26 less than the official answer. I was marked correct.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T13:02:42Z
FirstChildVoteTAG: 1
SecondChildTAG: My answer isn't right because I used another applet at
http://statistics.berkeley.edu/~stark/SticiGui/Text/zTest.htm and it allways worked, but here, in forum I found another applet
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
and it shows a right answer for my calculations.
SecondChildUserIdTAG: 82864
SecondChildUserNameTAG: AndreyGranenkin
SecondChildCreateTimeTAG: 2013-03-25T07:00:15Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm also about 0.36 off the right answer. Strange though that this answer is not correct, especially as the standard unit difference is only 0.01. If I look at the rounding rules it's not very obvious for me why this time I got the answer marked as incorrect.
FirstChildUserIdTAG: 492112
FirstChildUserNameTAG: TamasBocsi
FirstChildCreateTimeTAG: 2013-03-22T19:35:27Z
FirstChildVoteTAG: 0
FirstChildTAG: I also was 0.36 off the right answer in my first try and got it wrong, until I'd rounded everything up to 2 decimal places and got it 0.14 off got it correct
FirstChildUserIdTAG: 1098346
FirstChildUserNameTAG: caeduft
FirstChildCreateTimeTAG: 2013-03-23T07:58:23Z
FirstChildVoteTAG: 0
IndexTAG: 417
TitleTAG: Problem set 12 was a disaster for me!
But in this class, I seem to learn the most from my wrong answers!
UserIdTAG: 811172
UserNameTAG: MarianB
CreateTimeTAG: 2013-03-22T12:45:46Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Even it was disasters for me, I just passed.
FirstChildUserIdTAG: 889766
FirstChildUserNameTAG: AvinashKG
FirstChildCreateTimeTAG: 2013-03-24T06:38:38Z
FirstChildVoteTAG: 0
IndexTAG: 418
TitleTAG: Problem 2E
To decipher what the diagram shows you really need a superb vision. The comment (after pressing 'Show Answers') is the following:
> Take a good look at where the horizontal axis is.
Well, to notice that miniature shift of couple of pixels on a hand-held device (on which I have worked out the exercise) is simply impossible. I would really suggest to the staff to make differences more significant. I have lost one point just because I was not able to see that shift (I have picked option c, suggesting non-linearity in the data).
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-22T12:33:38Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: It is not the x-axis that has shifted. The residuals should be symmetric around 0. These are not.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13639560142897876.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T12:41:44Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Susan for this additional info. Nevertheless, when the picture is nicely zoomed like you did it here then there are no problems. However, if you look it on a small hand-held device then it is easy to miss that "shift" (that the line is not quite passing in the middle of points). A more significant difference would have been welcome, though.
SecondChildUserIdTAG: 411014
SecondChildUserNameTAG: evarga
SecondChildCreateTimeTAG: 2013-03-22T13:07:33Z
SecondChildVoteTAG: 0
SecondChildTAG: That image is not zoomed, it's cropped, if you see the difference here you should've been able to see it in the Problem too ;)
However, I have not attempted the exam on my 2 Android devices, so I can't really judge how hard the asymmetry is to spot. It's a lot more than a couple of pixels, though...
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-22T19:10:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, not zoomed. Just snipped from the page.
I know nothing about mobile devices, don't have them and never used them. But given the screen size (and my ancient eyesight) I think I would be lucky to see anything at all on them.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-22T21:03:04Z
SecondChildVoteTAG: 0
SecondChildTAG: @Klionheart
It is zoomed for me, since I am now reading this on my laptop! :-)
SecondChildUserIdTAG: 411014
SecondChildUserNameTAG: evarga
SecondChildCreateTimeTAG: 2013-03-22T21:45:53Z
SecondChildVoteTAG: 0
IndexTAG: 419
TitleTAG: solutions for exercise set 9, 10 and 11
This post is directed to the professors. Could you provide the solutions for exercise 9, 10 and 11 for week 4 as an aid for preparing for the final exams. All the other sets have solutions. I am just wondering if it was an oversight. Thank you
UserIdTAG: 1058906
UserNameTAG: Debbi
CreateTimeTAG: 2013-03-22T11:49:36Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section6_Lec_6_3/threads/514bec3908fa521600000173
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-22T19:20:24Z
FirstChildVoteTAG: 0
IndexTAG: 420
TitleTAG: So looking forward to Stat2.2!!
This course is great! I just want to thank the professors and the whole Stat2.1 staff for making up this course. I need statistics in my future work, and when I started this course I knew absolutely nothing about it. Plus, I haven't done any real math since high school, which was 8 years ago, and I wasn't even good at it back then! This course, however, is so well thought out that I really enjoyed learning from scratch, understanding the concepts, and solving problems all over again. Brilliant, just brilliant... Thank you!
Okay, that is all, I wanted to get that out of my system :)
UserIdTAG: 1116038
UserNameTAG: UrosKovac
CreateTimeTAG: 2013-03-22T11:16:15Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes I agree of what you have said .. a great course, so thanks to the professor and the staff of the course ... I am really looking forward to Stat2.2, do you know when it will start?
FirstChildUserIdTAG: 1231676
FirstChildUserNameTAG: morsi43
FirstChildCreateTimeTAG: 2013-03-22T13:57:33Z
FirstChildVoteTAG: 3
SecondChildTAG: April 12th!
SecondChildUserIdTAG: 1116038
SecondChildUserNameTAG: UrosKovac
SecondChildCreateTimeTAG: 2013-03-23T23:34:53Z
SecondChildVoteTAG: 0
IndexTAG: 421
TitleTAG: Reading Residual Plots
http://statistics.berkeley.edu/~stark/SticiGui/Text/regressionDiagnostics.htm#residual_plot
Hi all,
Can somenone explain to me how we can understand from Figure 10-5 (and 10-6) that the mean of the residuals is not zero?
Besides, I don't see any trend in 10-6. Where is the trend? Is it increasing or decreasing??
Thanks,
Antonis
UserIdTAG: 1207733
UserNameTAG: AntoniusBlock
CreateTimeTAG: 2013-03-22T11:13:37Z
VoteTAG: 1
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 4
FirstChildTAG: It's pretty hard. Possibly the hardest part of this course for me.
For the mean, you need to look at the symmetry of the problem, and at very high, or very low, values of y, and "guesstimate" the mean. It's extremely hard in many cases in the textbook, but thankfully easier in the Exercises on EdX.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-22T19:14:54Z
FirstChildVoteTAG: 0
FirstChildTAG: It's impossible for me to understand this type of plots. I am obviously missing something because you are saying that the exercise sets are easy but I got 4/5 wrong and even the explanations didn't really help me. It's the first time in this course I'm feeling I have to seek for another source of the same information cause I'm feeling it's not explained to me adequately. It's probably my understanding which is stuck for a reason here, not somebody's fault obviously. Anyway, thanks for the reply.
Antonis
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-22T20:54:50Z
FirstChildVoteTAG: 0
FirstChildTAG: I do not see a trend at all in Figure 10-6 of the text.
Also, is a trend something that goes in only one direction, or does a trend include a pattern, such as a sine or cosine wave?
These Residual questions for Exercise Set 12 are driving me crazy!
FirstChildUserIdTAG: 1231552
FirstChildUserNameTAG: Albertson
FirstChildCreateTimeTAG: 2013-03-23T14:19:35Z
FirstChildVoteTAG: 0
FirstChildTAG: To determine if there is a trend or not, I looked at the value for the correlation coefficient. If the correlation coefficient is not equal to 0, then there is still a linear relationship between the residuals and the x-variable.
However, I think that the r-value given is that of the original data, because it does not change when you click 'Plot Residuals'.
For the mean, I thought I had to look at the y-coordinate of the red point, but it is not easy to see if it is 0 or not because of the scale.
Also, it is not clear to me if the Residual Plots give the data and the residuals (when you click 'plot residuals') or if they give the residuals and the residuals of the residuals after clicking 'plot residuals'.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-23T21:51:40Z
FirstChildVoteTAG: 0
IndexTAG: 422
TitleTAG: YOUR ADVICE
HELLO PEOPLE ,
I JUST JOINED THE COURSE, IS THERE POSSIBILITY TO PASS THE MINIMUM SCORES IN ORDER TO GET A CERTIFICATE.
IT SEEMS THAT I STILL ONLY HAVE EXERCISE 12 AND FINAL .
WHAT IS YOUR ADVICES.
THANKS
UserIdTAG: 1463980
UserNameTAG: mohammed5111
CreateTimeTAG: 2013-03-22T11:12:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: There is still a possibility but you will have to do well on the exam and the last remaining exercise. Read the document "Course Policies and Requirement" for more information (under the tab "Course Info") or this thread:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/514bb600108ca4160000014c
As far as I know, you don't need the 2.1 certificate ("just" the knowledge) in order to participate in the upcoming course Stat 2.2, so good luck for 2.1 and good spirits for the upcoming 2.2 course!
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-22T11:25:08Z
FirstChildVoteTAG: 1
IndexTAG: 423
TitleTAG: Answers
Hi, this time answers are shown even before the deadline. Still, answers for E11 are missing.
UserIdTAG: 288327
UserNameTAG: IsabellaVel
CreateTimeTAG: 2013-03-22T11:07:43Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: I don't know why answers for E11 are still missing but for E12, it was announced on the Course Update Page: "Solutions to Exercise Set 12 will be visible once you have submitted your answers."
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-22T11:28:09Z
FirstChildVoteTAG: 0
FirstChildTAG: Check this:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section6_Lec_6_3/threads/514bec3908fa521600000173
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-22T13:34:31Z
FirstChildVoteTAG: 0
IndexTAG: 424
TitleTAG: TO STAFF PROGRESS BAR
I have answered the questions but observed that my progress bar remains at the percentage it was before I answered them. Is this due to technical problem or this week homework doesn't add up to the total percentage?
UserIdTAG: 417195
UserNameTAG: Oriafo
CreateTimeTAG: 2013-03-22T10:34:33Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: In the Course Info, it says: "Your two lowest Exercise Set scores will not be used in the calculation of your overall grade." Might this be a possible explanation?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-22T10:46:35Z
FirstChildVoteTAG: 0
SecondChildTAG: then whats the total percent of the homework and mid team exam if the two lowest exercise is dropped
SecondChildUserIdTAG: 417195
SecondChildUserNameTAG: Oriafo
SecondChildCreateTimeTAG: 2013-03-22T20:00:50Z
SecondChildVoteTAG: 0
SecondChildTAG: The 'Total' has, surprisingly enough, from Day 1 shown the total (there's a clue in the name!).
When you had fewer than ten completed exercises each new one increased your total score (by a maximum of 5%). When you completed the Midterm this also increased the total (by a maximum of 20%). Once you reach the eleventh exercise set, the software decides which is the lowest score and drops that from the total - so the total score can increase or stay the same. When you get the result for the Final exam that will be added (up to a maximum of 30%) to give a final score.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-22T20:34:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for explaining the score system:). I wasn`t sure about all of these percentages;).
SecondChildUserIdTAG: 1141835
SecondChildUserNameTAG: TrissMerigold
SecondChildCreateTimeTAG: 2013-03-23T01:22:30Z
SecondChildVoteTAG: 0
IndexTAG: 425
TitleTAG: staff! difference between incorrect calculation and non-linear relationship between x,y variables
While two are distinct things,the two are discussed together in regression diagnostics and residual plots without telling the difference between the two in regression diagnostics and residual plots. Kindly explain the difference between the two in context of residual plots and regression diagnostics in bit detail. This is for the staff and the students. Of course direct reference to any problem and exercise sets be avoided and honor code must be observed.
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-22T06:18:03Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Basically, if there is linear relationship (ie the line slopes up or down) then there is an error because it is impossible to have a slope. If there is a pattern to the points then this indicates a non-linear relationship.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-22T17:16:31Z
FirstChildVoteTAG: 0
IndexTAG: 426
TitleTAG: Here are Week 4 Exercise 9, 10, 11 Answers
As Show Answer is not showing and many want to know the answers, I am sharing my Green Tick marks with you:
**Exercise Set 9:**
Problem 1A:
-----------
non-linear, and shows negative association
Problem 1B:
-----------
- The students who took the test in Illinois did better, on average, than those who took the test in Maine.
- A higher percentage of students took the test in Maine than in Illinois.
- In general, states with high participation rates tended to have low scores.
- The higher scoring states tended to be those that had lower participation rates, in general.
Problem 2A:
-----------
-1
Problem 2B:
-----------
1
Problem 3:
----------
The association is positive as older couples consist of older wives and older husbands.
**Exercise Set 10:**
Problem 1A:
-----------
6.833
Problem 1B:
-----------
5.583
Problem 1C:
-----------
c. fewer than 50%
Problem 2A:
-----------
79.76
Problem 2B:
-----------
43.49
**Exercise Set 11:**
Problem 1:
----------
is above the 35th percentile of lengths.
Problem 2A:
-----------
0.833 grams per mm
Problem 2B:
-----------
-13.159
Problem 2C:
-----------
0.417
Problem 3:
----------
I survived midterm week.
This class is almost over.
UserIdTAG: 300213
UserNameTAG: Artimehta
CreateTimeTAG: 2013-03-22T05:29:29Z
VoteTAG: 7
CoursewareTAG: Section 6: Relation between two variables / Lec 6.3: Using r: with caution!
NumberOfReplyTAG: 3
FirstChildTAG: Some graphs explaining 2A and 2B (Set 9):
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/514a56baa386aa1600000151
And for Problem 1A (Set 9)
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_9/threads/514a1529a386aa0a00000084
Question 2C (Set 11)
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_11/threads/514bb6518740eb0e000000e0
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T05:33:58Z
FirstChildVoteTAG: 2
SecondChildTAG: thnks
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-22T08:48:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Very helpful! Thanks SusanAust!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-22T13:24:37Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks Artimehta. I really appreciate this. Would it be possible to know the calculations for Exercise Set 10, Questions 2A and 2B? I'm not sure how to get to those answers.
FirstChildUserIdTAG: 1049690
FirstChildUserNameTAG: ianlau
FirstChildCreateTimeTAG: 2013-03-22T12:22:08Z
FirstChildVoteTAG: 1
SecondChildTAG: Hi 0ianlau - Here is the workout:
Exercise Set 10 - Problem 2A
----------------------------
- The scatter diagram of SAT verbal and math scores in a state is **roughly football shaped**. This gives us the hint that we can assume normal distribution and hence can use Standard Normal Applet to look up Z valuue
- So when we try to get 90th percentile using standard applet, we get the z value of 1.282. (You can verify this by entering Lower endpoint = -5 and Upper Endpoint = 1.282. It will give you 90.01% which can be taken as 90th percentile).
![enter image description here][1]
- Next, use the formula = y = rx where y is the regression estimate of this student’s percentile rank in math that we are trying to estimate, r is the regression coefficient (provided in problem statement and is = 0.65, x is the z value of student's verbal math score at 90th percentile).
> y = r * x
> y = 0.65 * 1.282
> y = 0.883. This is the value of student's math score in standard units when verbal math score is 90th percentile.
- Now to find the math score in percentile, enter this value in Upper Endpoint in the standard Applet as shown below:
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13639577935221595.jpg
[2]: https://edxuploads.s3.amazonaws.com/1363958163230864.jpg
- **And there you have your answer in percentile - 79.76%.**
Exercise Set 10 - Problem 2B
----------------------------
I am sure you have already figured out how to solve this problem by now - ditto same approach as above!!!
Hope this helped!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-22T13:18:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Please correct my typos in above post while reading.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-22T13:19:21Z
SecondChildVoteTAG: 0
FirstChildTAG: Exercise Set 10, Question 2A, I rounded to 80 and it was marked as wrong answer... :(
FirstChildUserIdTAG: 1003753
FirstChildUserNameTAG: danatudorica
FirstChildCreateTimeTAG: 2013-03-22T12:33:23Z
FirstChildVoteTAG: 2
SecondChildTAG: Oh...when you round it to 80th percentile, the z value changes to 0.842 from .8333. I guess we should refrain from rounding unless we are rounding off more than 5 decimal places to 2 or 3 decimal value. The instructions also state the same.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-22T13:22:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you, Artimehta. You are right about rounding, in general.
Actually it was the first time when i rounded something. And that because in Lecture 7.2, minute 12.43, 66.31% from the applet was rounded at 66th percentile.
What i still don't understand is that on Question 2B, i also rounded 43.49 to 43th percentile and ... i got a green tick mark.
SecondChildUserIdTAG: 1003753
SecondChildUserNameTAG: danatudorica
SecondChildCreateTimeTAG: 2013-03-22T13:42:52Z
SecondChildVoteTAG: 0
SecondChildTAG: I have learnt to stay away from rounding!!!! It has always helped! Also, as we are still learning, I assume that may be I do not know when it is ok to get away with rounding and when precision is required. So I opt not to round most of the time.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-22T14:00:10Z
SecondChildVoteTAG: 0
IndexTAG: 427
TitleTAG: answer provided to problem 3c,excercise set 12 is approximate
Although my answer is marked correct but it's bit different from that provided,which appears to be quite approximate. Please correct me if I am wrong. Thanx in advance.
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-22T05:18:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: My answer was different too, as I didn't round as often as the solution did.
Had a 0.26 difference. Was marked correct.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T05:38:47Z
FirstChildVoteTAG: 1
SecondChildTAG: I was also marked correct with a 0.24 difference. The result in the solution, when used to find the percentage, is also 0.14 off compared what what the applet says.
I guess they accept a fairly big range as valid, because with these values the amount of rounding weights heavily.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-22T09:45:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanx SusanAust & Klionheart . Reassuning. I too had a difference of 0.26 .
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-22T10:46:06Z
SecondChildVoteTAG: 0
IndexTAG: 428
TitleTAG: solutions to exercise sets 9, 10 & 11 not provided as yet
Show answer option is not available as yet . I just wanted to see 1b in exercise set 9, the one about ecological correlation. Staff please notice it.
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-22T04:55:11Z
VoteTAG: 4
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 429
TitleTAG: "SD" vs. "RMS Error" Terminology in Lec. 8.2
I swear these lecture videos keep changing between each viewing.
I thought I understood the difference between SD and RMS Error, that they were distinct (and the latter is "better" than the former). But at position 26:42 of Lec. 8.2, Prof A refers to the rms error AS the sd.
What subtlety (or basic concept) am I missing here? Are they the same, or are they different?
UserIdTAG: 1235638
UserNameTAG: MyOwnCamera
CreateTimeTAG: 2013-03-22T03:49:36Z
VoteTAG: 1
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 1
FirstChildTAG: The RMS *can* be used as the SD for a dataset consisting of a "strip" taken from the scatter diagram.
For example, if you have a plot of heights VS weights, you might want to look at only the list of heights for those people who weigh X lbs. For *that* dataset, **if the graph is football-shaped**, you can use the RMS of the scatter plot as its SD.
Otherwise, the two are distinct entities.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-22T09:48:58Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you. I need to be more aware of the context.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-22T13:23:05Z
SecondChildVoteTAG: 0
IndexTAG: 430
TitleTAG: Answers to week 4
Hi Staff, could you please put up the answers
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-03-22T03:40:58Z
VoteTAG: 10
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: I am not staff, but you may visit this thread:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section6_Lec_6_3/threads/514bec3908fa521600000173
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-22T13:31:15Z
FirstChildVoteTAG: 0
IndexTAG: 431
TitleTAG: "Show Answer" for Week 4 Exercise Sets
1-2 people (Stat2.1x staff?) have stated on the Discussion board that the "Show Answers" function for the Week 4 Exercise Sets will "soon" be available. That was more than 24 hours ago.
When is "soon"?
UserIdTAG: 11318
UserNameTAG: JMcGlynn
CreateTimeTAG: 2013-03-22T03:32:03Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They are usually available by now. May be a tech problem, or an oversight??
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T03:39:57Z
FirstChildVoteTAG: 1
SecondChildTAG: I can't see them... What's the problem??
SecondChildUserIdTAG: 815940
SecondChildUserNameTAG: elzadomingues
SecondChildCreateTimeTAG: 2013-03-22T10:17:57Z
SecondChildVoteTAG: 0
IndexTAG: 432
TitleTAG: Answers from Week 4, please. Would help to prepare for the final
Hi -
Before I try to build on my knowledge (or lack thereof) in anticipation of the final, could we please have the solutions to week 4 questions? As soon as possible would help. I want to know where I went wrong, etc. before trying to add another layer of info.
Thanks so much. I am really enjoying this course.
UserIdTAG: 16539
UserNameTAG: islandbirder
CreateTimeTAG: 2013-03-22T01:39:29Z
VoteTAG: 6
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: You can find answer at below link:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section6_Lec_6_3/threads/514bec3908fa521600000173
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-22T13:31:50Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you for the answers. I was hoping to see the thinking behind the answer for 2c in exercise 11. I am not able to get to the answer that was provided, and would like to know what I am missing before I move on to this week. Thank you in advance for your help.
SecondChildUserIdTAG: 16539
SecondChildUserNameTAG: islandbirder
SecondChildCreateTimeTAG: 2013-03-22T16:17:10Z
SecondChildVoteTAG: 0
FirstChildTAG: > I was hoping to see the thinking behind the answer for 2c in exercise 11
the question:
>The diameter of one of the eggs is 0.5 mm wider than that of another. According to the regression method, the chick that hatches from the bigger egg is estimated to be ____________ grams heavier.
The answer: $0.4165$
The slope ($\beta$) of the regression line is saying that for every unit increase in $X$, $Y$ will increase by $\beta$.
So if your slope is $\beta = 0.8333$ and your units are in $mm$, it means that for a $1mm$ increase in diameter the egg weight (yes, mass) increases by $0.8333g$
So a $\frac{1}{2}mm$ increase in diameter, on average, has a $\frac{0.8333}{2}=0.4165g$ increase in egg weight.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-23T01:59:06Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you so much! I can now move on to this week's info without losing any more sleep.
SecondChildUserIdTAG: 16539
SecondChildUserNameTAG: islandbirder
SecondChildCreateTimeTAG: 2013-03-23T02:27:40Z
SecondChildVoteTAG: 0
IndexTAG: 433
TitleTAG: Maybe a stupid question?
Respected Admins/Fellow Students,
I got to know about this course just a few minutes back and immediately wanted to take it up. However, I realized that the final exams begin in a few days. I am confident that I can spend the next few days studying and be able to pass the final exam (I work in the field of Analytics but wanted to brush up on my basic concepts).
However, I am **unsure if I can still get the certification if I pass the exam, without having submitted the exercises and mid-term by their due dates?** (If that helps, I can try completing all assignments and/or mid-term?). If yes - this may sound selfish but I am just being brutally honest in admitting that I will be incentivized to complete 5 weeks of coursework in 5 days and then take the final exam.
This is my 1st post here, so please go soft on me.
Thanks,
NJ
UserIdTAG: 1463230
UserNameTAG: NipunJ
CreateTimeTAG: 2013-03-22T01:38:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The grading requirements are listed in the course policy (link on Course Info tab).
For this course, the requirement for the certificate is only $35\%$. To achieve that at this stage you would need to do the Week 5 assessment and get it all correct. Then you would need to do the final exam, and get 100%.
Assessments are $5\%$ each. Final exam is worth $30\%$.
So, yes you could achieve the certificate. But just one mistake and you are history.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T01:43:14Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks, Susan! That was super helpful info. I appreciate it!
It seems like a challenge lies ahead of me! Reminds me of days from my Bachelors degree. Nice! :)
SecondChildUserIdTAG: 1463230
SecondChildUserNameTAG: NipunJ
SecondChildCreateTimeTAG: 2013-03-22T02:00:51Z
SecondChildVoteTAG: 0
FirstChildTAG: Haha you are not alone! I also need to speed up all the materials as I got really behind with my other work! I think this weekend will be my intensive stat study time! :) Good luck with studying!
FirstChildUserIdTAG: 120643
FirstChildUserNameTAG: Julesyu
FirstChildCreateTimeTAG: 2013-03-22T11:30:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks and good luck!
SecondChildUserIdTAG: 1463230
SecondChildUserNameTAG: NipunJ
SecondChildCreateTimeTAG: 2013-03-26T00:38:18Z
SecondChildVoteTAG: 0
FirstChildTAG: Good luck for y'all...
FirstChildUserIdTAG: 1213285
FirstChildUserNameTAG: JUSTANDY
FirstChildCreateTimeTAG: 2013-03-22T17:06:28Z
FirstChildVoteTAG: 0
IndexTAG: 434
TitleTAG: Script (subtitle) for Introduction of Session 8a
if it is possible, can we have the script in Introduction video.
This is not because of that what Professor's explanation. Due to the limited internet access, I just copy and save the script and read. I understand that it is very effective if I can watch only lecture video as much as I can. If i have the hard copy, i do not need to worry that the videos are not available due to the limited connection.
Thanks. Apology for so much demanding in very details.
By the way Professor A, the patterned top and vest is very match with you. ;-)
Thanks and regards,
Lai lai
UserIdTAG: 254503
UserNameTAG: LaiLai
CreateTimeTAG: 2013-03-22T00:13:45Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 1
FirstChildTAG: I also print the script - it helps with reviewing material; I can read faster than re-watching the video.
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-25T14:10:44Z
FirstChildVoteTAG: 0
IndexTAG: 435
TitleTAG: "And in fact, the parabola will be better but cubic is better still."
In the end of the third video of this section 8a, I am not very clear on whether Prof A. is referring this to the residual plot or the scatter diagram... The scatter looks more like an angled sinusoid and the residual looks nothing like a cubic graph. Thank you!
UserIdTAG: 824173
UserNameTAG: pinepike
CreateTimeTAG: 2013-03-21T21:56:44Z
VoteTAG: 0
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 1
FirstChildTAG: If any curious souls want to play with the data - it is in the R datasets.
>women {datasets}
>This data set gives the average heights and weights for American women aged 30–39.
A cubic fit to the scatter plot:
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13639046408474428.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T22:15:00Z
FirstChildVoteTAG: 1
IndexTAG: 436
TitleTAG: Are we being fair here?
It seems to me that the when a question has a multiple choice answer with only 3 choices, one of which is obviously wrong, that all you need to do is wait around until someone blurts out an over specific clue on the forum which makes the answer obvious. We should remember why we are doing this course, it's not to get a silly certificate but to understand. You only understand if you think things through for yourself. The forum is useful when you're at a loss and need a steer in the right direction but it actually makes the learning experience worse when the answer is pretty well laid out on a plate for you. In my view, the course should increase the weighting of the exams and decrease the weighting of the exercises. It's only when you get an answer on your own with no help that you know you're not fooling yourself that you understand.
UserIdTAG: 18229
UserNameTAG: TonyRBH
CreateTimeTAG: 2013-03-21T20:55:28Z
VoteTAG: 9
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: There will always be those who get others to do the work for them. Even the midterm test appeared on a homework help site. The final test will too. Because the certificate is important to some - more important than actually learning the content.
People use the certificate for all sorts of reason. Proof of continuing education, avoid paying for a f2f class, bragging rights (hey! I've got a certificate from xxxxx!). And some just don't care how they get the certificate. You can pay for someone to write your PhD, so academic cheating is an industry. moocs won't be any different.
It would be nice if answers weren't discussed. But there are those who are just so outraged - because they know they were right and the prof is wrong! - that they have to shout to the world. Others are just befuddled as to why they were wrong.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T21:23:44Z
FirstChildVoteTAG: 5
SecondChildTAG: people are just people... some try to learn something... others may be here just to get cert without considering how... but we should also remember that even those that are not interested in learning have to know something to actually filter through all sorts of clues and answers... so they learn LOL
SecondChildUserIdTAG: 905926
SecondChildUserNameTAG: MarcinJ77
SecondChildCreateTimeTAG: 2013-03-21T22:28:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Attempt the exercises 'on your own', care for 'your own certificate' and please 'do not bother about how others are getting their certificates'. This will help you realize the importance of regular studies and hence greater weightage of exercise sets. Berkeley profs and edX are not novices!
SecondChildUserIdTAG: 916575
SecondChildUserNameTAG: Vipul94
SecondChildCreateTimeTAG: 2013-03-22T19:32:58Z
SecondChildVoteTAG: 0
SecondChildTAG: I can say that I have not posted anything related to a problem, nor would I, but I can clearly understand the frustration that causes people to lay out their troubles when they have honestly worked through something and are confused. If the point is -learning-, then understanding should come first and not so much worrying about what someone has blurted out. It seems those who freak out when they so too much information being shared are more concerned about their certificate status than the poor folks that are seeking understanding.
SecondChildUserIdTAG: 975799
SecondChildUserNameTAG: lmacareo
SecondChildCreateTimeTAG: 2013-03-24T23:07:20Z
SecondChildVoteTAG: 0
SecondChildTAG: *"see" too much information.
SecondChildUserIdTAG: 975799
SecondChildUserNameTAG: lmacareo
SecondChildCreateTimeTAG: 2013-03-24T23:08:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I have to agree with MarcinJ77, because I've used the forum discussion a lot and I've learned how to understand the questions, not only "what is the answer". Before that understanding, I felt myself much more confident to answer all the other questions.
SecondChildUserIdTAG: 1222674
SecondChildUserNameTAG: r2s2
SecondChildCreateTimeTAG: 2013-03-25T02:00:28Z
SecondChildVoteTAG: 0
SecondChildTAG: go to Havard and get ur degree then, we try to help each others study, the point is that everyone gets the knowledge.
SecondChildUserIdTAG: 1314120
SecondChildUserNameTAG: ThyNguyen
SecondChildCreateTimeTAG: 2013-03-25T20:06:06Z
SecondChildVoteTAG: 0
FirstChildTAG: I concur with TonyRBH that weighting of exam should be more and that of exercise sets less.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-22T05:10:30Z
FirstChildVoteTAG: 0
FirstChildTAG: There is an educationally (and psychologically) valid reason for the weighting towards graded exercises. The weighting is intended (I assume) to encourage students to complete all the exercises and practices. As this course has shown, if you work through the material in a methodical manner, completing the exercises then you will understand the course and find few surprises in the exams. As a teacher myself, I can see the benefits and as a student only too aware of my own tendency to procrastinate I can certainly appreciate the encouragement to stick to the straight and narrow.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-22T20:40:15Z
FirstChildVoteTAG: 3
IndexTAG: 437
TitleTAG: "If the scatter diagram happens to be linear..."
It seems like the second lecture was cut off at the end -- it ends with the unfinished sentence "if the scatter diagram happens to be linear..."
Are we missing anything substantive here?
UserIdTAG: 118792
UserNameTAG: tonyrobots
CreateTimeTAG: 2013-03-21T18:59:30Z
VoteTAG: 0
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 1
FirstChildTAG: "...then the regression line is actually really useful".
The downloaded video is ok, and I only watched that until now so I didn't notice it, but it's true, Lecture 8.1 in the web player is missing the last second of video.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-21T19:08:53Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks!
SecondChildUserIdTAG: 118792
SecondChildUserNameTAG: tonyrobots
SecondChildCreateTimeTAG: 2013-03-21T22:13:26Z
SecondChildVoteTAG: 0
IndexTAG: 438
TitleTAG: Residual Plot
It's not entirely clear to me how to infer about residuals mean from looking at residual plots. For example, in the plot in figure 10-6 mean of residuals is not zero, and we are supposed to know this just by looking at it. But it's not obvious to me; about half of points are positive, half are negative, and positive and negative look about symmetrical around 0. So, as far as I can tell mean of residuals could be 0, just as well.
Any comments? Am I doing this wrong?
UserIdTAG: 162039
UserNameTAG: ghromis
CreateTimeTAG: 2013-03-21T18:53:39Z
VoteTAG: 6
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 3
FirstChildTAG: The negative half of y goes down to -15, while the positive half goes only up to +10, so the negative values actually go much lower and drag the Average to a negative.
But I agree that estimating the mean just by looking at the graph can be very tricky in some situations :|
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-21T19:11:29Z
FirstChildVoteTAG: 0
SecondChildTAG: yeah, but if you have few more negative points, it can cancel the difference in outliers. you can't tell just but looking at max and min.
SecondChildUserIdTAG: 162039
SecondChildUserNameTAG: ghromis
SecondChildCreateTimeTAG: 2013-03-21T20:43:08Z
SecondChildVoteTAG: 0
FirstChildTAG: I have the same problem. It's not helping that figure 10-4 and 10-5 (the latter of which is supposed to be showing an "impossible" residual graph) seem to be exactly the same.
FirstChildUserIdTAG: 118792
FirstChildUserNameTAG: tonyrobots
FirstChildCreateTimeTAG: 2013-03-21T22:09:19Z
FirstChildVoteTAG: 4
SecondChildTAG: Also the text states that one can tell the mean of the residuals is not zero if the point of averages of the residual plot is not on the x axis, yet in all the examples of supposedly non-zero means (10-5, 10-6 and exercise 10-1), the point of averages is at zero, sitting right there on the x axis.
I'm beginning to think it's an applet issue.
SecondChildUserIdTAG: 118792
SecondChildUserNameTAG: tonyrobots
SecondChildCreateTimeTAG: 2013-03-21T22:15:37Z
SecondChildVoteTAG: 0
SecondChildTAG: It might very well be that something's wrong with the applet. Hoping for feedback from the professors on this.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-21T23:22:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Has anyone had any feedback from professors?
SecondChildUserIdTAG: 846820
SecondChildUserNameTAG: BetseyShay
SecondChildCreateTimeTAG: 2013-03-22T14:39:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I think that this indeed might be a problem with the applet. But, regardless, this does not help with the exercises given that the point of averages is not displayed at all.
SecondChildUserIdTAG: 1026491
SecondChildUserNameTAG: Rob_M
SecondChildCreateTimeTAG: 2013-03-23T16:18:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Determining a trend is also difficult. It would help if the r-value given was the correlation coefficient of the residuals and the x-variable.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-23T21:56:37Z
FirstChildVoteTAG: 0
IndexTAG: 439
TitleTAG: 3a
Just a heads up to the admin:
I did problem 3a totally wrong but my answer was within the acceptable range so it counted it as correct.
I got my answer by looking at the area under the normal curve for 50% of the data and then multiplying the SD of the height. This gave me an answer of which is not right but was accepted.
UserIdTAG: 840238
UserNameTAG: bchilders
CreateTimeTAG: 2013-03-21T18:27:58Z
VoteTAG: 5
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: I did the same thing and was also marked right even though my method was wrong.
FirstChildUserIdTAG: 119039
FirstChildUserNameTAG: Alan56
FirstChildCreateTimeTAG: 2013-03-22T12:02:56Z
FirstChildVoteTAG: 0
FirstChildTAG: Which "height" are you talking about?
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-22T12:03:25Z
FirstChildVoteTAG: 1
FirstChildTAG: The same happened to me. I used a normal curve and forgot about the rms error of regression. I guess we won't be the only one with this answer
FirstChildUserIdTAG: 693583
FirstChildUserNameTAG: Remmi
FirstChildCreateTimeTAG: 2013-03-22T20:03:56Z
FirstChildVoteTAG: 0
IndexTAG: 440
TitleTAG: Exercise 12, Problem 3B
Is the answer to Exercise 12, problem 3B, incorrect? I think it should be twice the amount given in the answer because it asked for head circumference by more than 0.5 inches (to the left and right of the curve). The answer appears to show just the left tail. Thanks.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-21T18:27:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: If a value is x, and your guess overestimates it by 0.5'', it means the guess is x+0.5.
Or, in other terms: if your guess is x, and it overestimates the actual value by 0.5'', then the value is x-0.5.
Make of this what you want, but stop discussing the details of a Problem's solution before due date, please.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-21T19:02:36Z
FirstChildVoteTAG: 4
FirstChildTAG: The answer is correct . Honour code should be respected while using discussion forum.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-22T05:27:56Z
FirstChildVoteTAG: 0
SecondChildTAG: Kindly look for the keywords in the question, this problem set was especially challenging in terms of the 'attention' required to attempt the questions correctly!
SecondChildUserIdTAG: 916575
SecondChildUserNameTAG: Vipul94
SecondChildCreateTimeTAG: 2013-03-22T19:25:01Z
SecondChildVoteTAG: 0
FirstChildTAG: HELLO PEOPLE ,
I JUST JOINED THE COURSE, IS THERE POSSIBILITY TO PASS THE MINIMUM SCORES IN ORDER TO GET A CERTIFICATE.
IT SEEMS THAT I STILL ONLY HAVE EXERCISE 12 AND FINAL .
WHAT IS YOUR ADVICES.
THANKS
FirstChildUserIdTAG: 1463980
FirstChildUserNameTAG: mohammed5111
FirstChildCreateTimeTAG: 2013-03-22T11:11:05Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi,
I think it is better for you to wait for the Stat 2.2x.
Best wishes,
Elena
SecondChildUserIdTAG: 1007312
SecondChildUserNameTAG: Elena_Sh
SecondChildCreateTimeTAG: 2013-03-22T18:44:42Z
SecondChildVoteTAG: 0
IndexTAG: 441
TitleTAG: Volume low on video
Has anyone else found the volume on the week 5 videos to be too low as to be barely audible ? This hasn't been the case on previous videos.
UserIdTAG: 119039
UserNameTAG: Alan56
CreateTimeTAG: 2013-03-21T18:24:07Z
VoteTAG: 6
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.1: Least squares: why the regression line and no other
NumberOfReplyTAG: 2
FirstChildTAG: yes, I am having the same issue
FirstChildUserIdTAG: 348290
FirstChildUserNameTAG: joshb
FirstChildCreateTimeTAG: 2013-03-21T18:25:51Z
FirstChildVoteTAG: 1
FirstChildTAG: I have also noticed that the introduction videos where the professor is in frame are much louder than the videos with the slides and talking in the background. This has been consistent week after week.
FirstChildUserIdTAG: 1061881
FirstChildUserNameTAG: kristen1trigen
FirstChildCreateTimeTAG: 2013-03-21T21:00:25Z
FirstChildVoteTAG: 6
IndexTAG: 442
TitleTAG: Exercise set 12, problem 3B
Hi all,
I'm having troubles with this seemingly easy problem. Maybe I'm not going in the right direction?
My steps:
- First, we find r.m.s error of regression;
- Then, calculate how many r.m.s. errors our 0.5" is far from the regression line;
- And finally, find (1 - area of the curve between those amounts).
My answer (2X.X3) is marked as incorrect, so I have no clue where am I wrong. Any ideas?
UserIdTAG: 193779
UserNameTAG: skywill
CreateTimeTAG: 2013-03-21T17:33:51Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: I'm also getting same answer as yours. Can't find where I'm going wrong.
FirstChildUserIdTAG: 159507
FirstChildUserNameTAG: manirana
FirstChildCreateTimeTAG: 2013-03-21T18:04:35Z
FirstChildVoteTAG: 1
SecondChildTAG: I'm working on that one right now, and I'm pretty sure the right direction is by noticing the specific wording of the question:
**over**estimate head circumference by more than 0.5 inches?
SecondChildUserIdTAG: 261974
SecondChildUserNameTAG: ereiner
SecondChildCreateTimeTAG: 2013-03-24T22:53:30Z
SecondChildVoteTAG: 0
FirstChildTAG: I think you have a problem with your third step. The problem asks:
> what percent of the newborns does the regression line overestimate head circumference by more than 0.5 inches?
So think about which area of the curve you are actually interested in...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-21T18:06:31Z
FirstChildVoteTAG: 0
SecondChildTAG: i tried both, but both were wrong :(
SecondChildUserIdTAG: 1053569
SecondChildUserNameTAG: nicola2003
SecondChildCreateTimeTAG: 2013-03-21T18:08:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Does this means that only one end of tail needs to calculated ?
SecondChildUserIdTAG: 159507
SecondChildUserNameTAG: manirana
SecondChildCreateTimeTAG: 2013-03-21T18:10:01Z
SecondChildVoteTAG: 0
SecondChildTAG: I try to guess the length of a wall, and I say it's 100 meters high. If I "overestimate" it by 30 meters, it means that the wall is actually 70 meters long, or 30 meter less than my guess.
Apply the concept from this example to the Problem, and you'll understand the area that you want. I really can't say more without giving away a part of the solution...
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-21T18:26:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Go through the second example given by Prof. A
SecondChildUserIdTAG: 1416809
SecondChildUserNameTAG: mehrotravinit
SecondChildCreateTimeTAG: 2013-03-22T05:18:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you!
I thought of an overestimation as a general "non directional" term, not in the context of under- and overestimation...
Now it is correct.
SecondChildUserIdTAG: 193779
SecondChildUserNameTAG: skywill
SecondChildCreateTimeTAG: 2013-03-22T06:42:28Z
SecondChildVoteTAG: 0
IndexTAG: 443
TitleTAG: Descriptive Statistics vs. Inferential Statistics
The course has been a great experience thus far. However, I do have a question. This course is descriptive statistics, and I understand estimation to be included in the other branch of statistics, called inferential statistics. Request clarification on the branch under which estimation lies in the fabulous world of statistics! Thank you!
UserIdTAG: 1186269
UserNameTAG: jhsmith
CreateTimeTAG: 2013-03-21T17:10:00Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 2
FirstChildTAG: As far as I understand inference is about going from sample statistics (ideally randomly selected samples) to the estimation of parameters of the population from which those samples were selected. Staff can answer more appropriately
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-21T18:03:26Z
FirstChildVoteTAG: 0
FirstChildTAG: In other for us to draw a conclusion or make decisions from the data we have to learn descriptive statistics. In this class we learn how to compute and read the data either from the graph, the table, equations or all of them. We have to know how to compute, read, analyze the data and understand them. This is what descriptive stats is. From our understanding of the data, we can make inferences or hypothesis.
In the real world, most of the data we gather are incomplete. We only gather a sample out of the population. For example, in the Presidential Polls, there is no way the pollsters can ask all 300 million plus people in the US to find out who they would vote for. They only ask at most a couple thousand people - this is what a random sample means. And from this Random Sample, we do the computations and analyze the data and draw conclusion from them. Inferential Statistics teaches us how to draw conclusion from random samples. We can't do inferential statistics or draw conclusion if we don't understand the data.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-21T19:50:45Z
FirstChildVoteTAG: 1
IndexTAG: 444
TitleTAG: Exercise 10-1 in the text
What are the things I should be looking for in the residual plot that show a) the residuals have a non-zero mean and b) the regression went wrong? The point of averages (red dot) is on the x-axis, so that means the residuals *do* have a zero mean? Is that right? And in terms of the regression going wrong, r is not equal to zero, and the residuals appear to have a trend. Again, am I looking at the right thing?
UserIdTAG: 846820
UserNameTAG: BetseyShay
CreateTimeTAG: 2013-03-21T16:55:08Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 1
FirstChildTAG: The regression went wrong if *a* and/or *b* are true.
As for the mean...I'm terribly confused myself about it. Sometimes you can sort of "eyeball" where the average lies by looking at the graph symmetry...but it's often misleading. And the red dot seems to stay on (0,0) regardless of what the mean is, so it doesn't help.
I'll have to practice a lot more with this exercise before I attempt Problem 2 of the ES12 :o
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-21T17:54:57Z
FirstChildVoteTAG: 2
IndexTAG: 445
TitleTAG: Applet link
In case you are looking for this ... http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
UserIdTAG: 495068
UserNameTAG: quake
CreateTimeTAG: 2013-03-21T16:15:29Z
VoteTAG: 23
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 1
FirstChildTAG: THANKS SO MUCH!
FirstChildUserIdTAG: 1193628
FirstChildUserNameTAG: FLupia
FirstChildCreateTimeTAG: 2013-03-22T08:14:27Z
FirstChildVoteTAG: 2
SecondChildTAG: thank u very much, I hav been searching for this graph since long time... thank u...
SecondChildUserIdTAG: 1311995
SecondChildUserNameTAG: podilashree
SecondChildCreateTimeTAG: 2013-03-22T16:18:57Z
SecondChildVoteTAG: 0
IndexTAG: 446
TitleTAG: progress x's
there's a few bold x's over th ES10 and ES12 slots on my progress page. what do they mean? I seem to know less and less as this course progresses.
UserIdTAG: 950367
UserNameTAG: catt9
CreateTimeTAG: 2013-03-21T16:00:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They are your lowest ES results and as such are dropped from your overall grade.
FirstChildUserIdTAG: 283474
FirstChildUserNameTAG: Methuselah
FirstChildCreateTimeTAG: 2013-03-21T16:03:22Z
FirstChildVoteTAG: 0
SecondChildTAG: thank you
SecondChildUserIdTAG: 950367
SecondChildUserNameTAG: catt9
SecondChildCreateTimeTAG: 2013-03-21T18:49:30Z
SecondChildVoteTAG: 0
IndexTAG: 447
TitleTAG: 2B
i thought that residuals must be around zero. i cant understand why 2B is saying:no linear relation between variables? we are plotting x against residual.
is it must to be blob pattern?
UserIdTAG: 782631
UserNameTAG: basem_enany
CreateTimeTAG: 2013-03-21T15:36:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: Think about a function where y is related to x by the equation ax + bx^2. This looks like a line for small values of x and like a parabola for large values of x.
If x can take on positive and negative values, and there is some random measurement error (or natural variance) in y, I think the plot of residuals will look something like 2B.
FirstChildUserIdTAG: 174100
FirstChildUserNameTAG: markpolak
FirstChildCreateTimeTAG: 2013-03-21T16:54:29Z
FirstChildVoteTAG: 1
FirstChildTAG: You should not see any pattern, trend etc in the residuals. They should just be a blob, scattered around a mean of 0.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T20:54:49Z
FirstChildVoteTAG: 0
IndexTAG: 448
TitleTAG: [staff] The video seems to be incomplete.
The video gets cut off while the professor is speaking.
Comparing the slide and the video,I guess she was finishing her last sentence? But if there is more explanation that we should listen to, please upload the full version.
Thank you.
UserIdTAG: 1142810
UserNameTAG: miji
CreateTimeTAG: 2013-03-21T15:24:48Z
VoteTAG: 9
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.1: Least squares: why the regression line and no other
NumberOfReplyTAG: 2
FirstChildTAG: Were you watching the video greater than 1.0x speed? I find the video sometimes cuts of a bit early when watched at higher speeds. Slow it down to hear the last bit.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-03-21T18:14:33Z
FirstChildVoteTAG: 2
SecondChildTAG: Slow it down and it's still cut off mid-sentence
SecondChildUserIdTAG: 1031610
SecondChildUserNameTAG: AmgadMoussa89
SecondChildCreateTimeTAG: 2013-03-21T21:15:52Z
SecondChildVoteTAG: 0
FirstChildTAG: Some comment here
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section8a_Lec_8_2/threads/514b589260bc930e0000001c
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T21:25:15Z
FirstChildVoteTAG: 2
IndexTAG: 449
TitleTAG: For the STAFF : Next level of statistics
Is there going to be a next course of statistics? I enjoyed very much this course and I would like to continue. It will be very-very helpful. Thank you!
UserIdTAG: 1124742
UserNameTAG: corneliav
CreateTimeTAG: 2013-03-21T15:19:24Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Stat 2.2x and Stat 2.3x have been discussed many times. Suggest a search through past discussions?
FirstChildUserIdTAG: 901827
FirstChildUserNameTAG: clv101
FirstChildCreateTimeTAG: 2013-03-21T16:36:50Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you. I found the answer: it's going to start two weeks after the end of 2.1X. Great news! :-)
SecondChildUserIdTAG: 1124742
SecondChildUserNameTAG: corneliav
SecondChildCreateTimeTAG: 2013-03-21T18:37:00Z
SecondChildVoteTAG: 0
IndexTAG: 450
TitleTAG: feel bad
This section tests how deep I understand regression. I hope I can do better in the final exam.
UserIdTAG: 1027696
UserNameTAG: bhamgm
CreateTimeTAG: 2013-03-21T15:00:51Z
VoteTAG: 2
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: I got all the calculations right, and messed up the simple stuff, like interpreting the diagrams, smh
FirstChildUserIdTAG: 844365
FirstChildUserNameTAG: jeremyliver
FirstChildCreateTimeTAG: 2013-03-21T15:56:48Z
FirstChildVoteTAG: 2
IndexTAG: 451
TitleTAG: (@Staff) Missing data for Exercise 11-1 of the textbook.
Exercise 11-1 refers you to Figure **11-1**, but unless I'm missing something, that graph doesn't have any information about the required correlation coefficient in it.
I suspect you wanted to refer to Figure **10-1**, which does include all necessary data ;)
UserIdTAG: 604636
UserNameTAG: Klionheart
CreateTimeTAG: 2013-03-21T14:40:31Z
VoteTAG: 15
CoursewareTAG: Practice for Exercise set 12 / Reading and Practice for Exercise set 12
NumberOfReplyTAG: 1
FirstChildTAG: Thank you Klionheart! I thought I was going crazy when I couldn't figure out what r was.
FirstChildUserIdTAG: 1117832
FirstChildUserNameTAG: Kindree
FirstChildCreateTimeTAG: 2013-03-24T20:32:24Z
FirstChildVoteTAG: 1
SecondChildTAG: I second that Kindree! Thank you, Klionheart!
SecondChildUserIdTAG: 1394646
SecondChildUserNameTAG: DevorahKat
SecondChildCreateTimeTAG: 2013-03-25T01:11:44Z
SecondChildVoteTAG: 0
SecondChildTAG: I third that! Thanks for finding the right picture. I broke my brains trying to figure out how they got r! :)
SecondChildUserIdTAG: 181578
SecondChildUserNameTAG: AnaMack
SecondChildCreateTimeTAG: 2013-03-25T08:41:27Z
SecondChildVoteTAG: 0
IndexTAG: 452
TitleTAG: To Staff
I would like to know if I can defer taking this course to another time. I cannot seem to meet up.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-21T14:26:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The course will likely be offered again in the future, yes. Wouldn't hold my breath until June or so, though.
If you are interested in the topic, I suggest you take it easy, don't worry too much about the grade, and go through the course anyway as a learning experience. Then when it's offered again, you'll ace it easily :D
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-21T17:33:35Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks for this advice. Quite helpful
SecondChildUserIdTAG: 1228303
SecondChildUserNameTAG: Shirlee
SecondChildCreateTimeTAG: 2013-03-22T12:14:40Z
SecondChildVoteTAG: 0
IndexTAG: 453
TitleTAG: ES12
what is the weight of problem set 12?
UserIdTAG: 1157619
UserNameTAG: princetongirl
CreateTimeTAG: 2013-03-21T14:19:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: Each problem set is worth 5% or 0% of your grade. Your lowest two problem sets are thrown out, and the remaining problem sets are worth 5% each.
FirstChildUserIdTAG: 174100
FirstChildUserNameTAG: markpolak
FirstChildCreateTimeTAG: 2013-03-21T16:11:18Z
FirstChildVoteTAG: 0
IndexTAG: 454
TitleTAG: Confusion in text of q1
When the text states "The decimal point is 1 digit to the right of the |”" it would seem that this ids erroneous as there is no decimal part of these whole number figures. This lead me to confusion and would be best dropped in the future IMO :)
UserIdTAG: 176770
UserNameTAG: GreginKenya
CreateTimeTAG: 2013-03-21T13:27:16Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 455
TitleTAG: RL situation: your thoughts?
If both the mean and median are affected by small sample size, is there something else that can be used to summarise the data? Don't say increase the sample size! The thing is done, there's no way to do that...we have five scores and I think neither the mean nor the mediam are acceptable. Any thoughtful suggestions would be appreciated. Thanks!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-21T13:15:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I'm afraid that I would say that a sample of 5 is too small to be statistically significant in most cases. The most I'd want to say is that the samples lie within a range x to y - but what further could be said is problematic. For such a small data set mean and median or pretty arbitrary indicators; a single 'bad' data point is going to have a significant effect (and you have no real way of knowing which, if any, are the 'bad' points.
The only context in which I could see where such a data set might be useful would be where the data related to an individual, perhaps in a longitudinal study where a trend might have significance but this outside the scope of this course and not relevant to your needs, given that you are talking of mean or median values.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-21T18:50:40Z
FirstChildVoteTAG: 0
FirstChildTAG: If the sample is that small, could you explain why you'd want to summarize it? I can see how you'd want to use it to make inferences about the population from which it was drawn, and we'll get to that in 2.3X, but if I just had a list of 5 numbers I'd simply list the 5 numbers.
Most likely I haven't understood your question. If so, please give me a bit more detail. Thanks,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-21T19:25:10Z
FirstChildVoteTAG: 0
IndexTAG: 456
TitleTAG: COMIC! ES 11!
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13638694917034932.png
UserIdTAG: 316261
UserNameTAG: Brady1997
CreateTimeTAG: 2013-03-21T12:38:15Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Lol. I got the same.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-03-21T13:20:35Z
FirstChildVoteTAG: 0
FirstChildTAG: exactly what happened to me! LOL thanks for the share :)
FirstChildUserIdTAG: 1278232
FirstChildUserNameTAG: eirras
FirstChildCreateTimeTAG: 2013-03-22T14:16:32Z
FirstChildVoteTAG: 0
IndexTAG: 457
TitleTAG: Results for ex set 9, 10 and 11
Why there is no "show answer" option. Deadline was more than 10 hours ago????
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-21T12:02:34Z
VoteTAG: 9
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Same request
FirstChildUserIdTAG: 274577
FirstChildUserNameTAG: scanning
FirstChildCreateTimeTAG: 2013-03-21T14:22:43Z
FirstChildVoteTAG: 1
SecondChildTAG: Me too
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-21T18:07:44Z
SecondChildVoteTAG: 0
IndexTAG: 458
TitleTAG: STAT2.2/3x?
When do the following courses start?
UserIdTAG: 1163915
UserNameTAG: ClemensW
CreateTimeTAG: 2013-03-21T11:41:20Z
VoteTAG: 24
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 3
FirstChildTAG: Yes this one has been fun. Thanks to Prof. A and all the team!!!
FirstChildUserIdTAG: 962810
FirstChildUserNameTAG: victordoors
FirstChildCreateTimeTAG: 2013-03-21T12:56:55Z
FirstChildVoteTAG: 11
SecondChildTAG: Yep, its been great, really supplemented what im learning in college. Eagerly waiting for the following courses.
Thanks to all the Staff and Prof. A
SecondChildUserIdTAG: 1106062
SecondChildUserNameTAG: Saurabh_Maurya
SecondChildCreateTimeTAG: 2013-03-21T13:08:16Z
SecondChildVoteTAG: 0
SecondChildTAG: The best course I've taken so far.
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-03-22T14:06:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Something on the course info page would be a good idea - otherwise I think this question will be asked again and again.
FirstChildUserIdTAG: 881870
FirstChildUserNameTAG: tomboyoung
FirstChildCreateTimeTAG: 2013-03-22T03:45:36Z
FirstChildVoteTAG: 4
FirstChildTAG: Apr 12 for 2.2x.
FirstChildUserIdTAG: 1145404
FirstChildUserNameTAG: KimHill
FirstChildCreateTimeTAG: 2013-03-24T01:05:01Z
FirstChildVoteTAG: 0
SecondChildTAG: Dear and Lovely Staff people
Although it will be very difficult for me I want to be with you in 2.2x. Thanks for promoting andragogy, in higher educational institutions, and not pedagogy, around the world. The fashion mode in education now is Andragogy. Wonderful course
SecondChildUserIdTAG: 1240706
SecondChildUserNameTAG: remipole
SecondChildCreateTimeTAG: 2013-03-25T16:19:53Z
SecondChildVoteTAG: 0
IndexTAG: 459
TitleTAG: Coursware tab: Was "Week 4" added later and above "Midterm"?
Listing the "Midterm Exam" link below the "Weeks 4" related links in the Coursesware Tab, although the deadlines were actually in a reverse deadline, disoriented me (my fault at all but a true fact in a busy world) and led me to loose the dead line for the completion of Exercises 9-11. If this is a fact for others following this course too, I would kindly request you to examine the possibility of providing the opportunity to take this tests in a short specific time frame before the final exam. Thank you for your time.
UserIdTAG: 905025
UserNameTAG: Athanasios961
CreateTimeTAG: 2013-03-21T11:40:35Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The same thing happened to me. I finished the midterm before the Week 4 Problem Sets and lectures were posted, so I thought there wouldn't be any new material until Week 5 lectures and Problem Sets came out yesterday. When I checked for Week 5, I was pretty surprised to see three Week 4 Problem Sets that were due about two hours before I saw them.
I would love to have an extension too, but at the end of it I think this one is on us for not reading the syllabus and exam announcement more closely.
FirstChildUserIdTAG: 1059543
FirstChildUserNameTAG: ajconti
FirstChildCreateTimeTAG: 2013-03-21T12:30:34Z
FirstChildVoteTAG: 1
SecondChildTAG: As I said, its not an excuse, but on the other hand when you are in rush its very easy to miss something. For me the courseware tab was (unfortunately) my guide to were I stand with regards to course advance.
SecondChildUserIdTAG: 905025
SecondChildUserNameTAG: Athanasios961
SecondChildCreateTimeTAG: 2013-03-21T12:45:37Z
SecondChildVoteTAG: 0
SecondChildTAG: me to... missed it!
SecondChildUserIdTAG: 470068
SecondChildUserNameTAG: Delirious
SecondChildCreateTimeTAG: 2013-03-21T13:11:20Z
SecondChildVoteTAG: 0
SecondChildTAG: I missed it too...
So frustrating :(
SecondChildUserIdTAG: 1076491
SecondChildUserNameTAG: natashitza
SecondChildCreateTimeTAG: 2013-03-25T18:33:15Z
SecondChildVoteTAG: 0
FirstChildTAG: > , but at the end of it I think this one is on us for not reading the syllabus and exam announcement more closely.
Yes. It clearly said that Week 4 was being released on March 14
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13638699138474428.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T12:45:39Z
FirstChildVoteTAG: 1
SecondChildTAG: read the fine print!
SecondChildUserIdTAG: 470068
SecondChildUserNameTAG: Delirious
SecondChildCreateTimeTAG: 2013-03-21T13:11:58Z
SecondChildVoteTAG: 0
SecondChildTAG: With all due respect. I agree once more but, in my humble opinion, what was clearly said does not affect the true fact I have mentioned.
SecondChildUserIdTAG: 905025
SecondChildUserNameTAG: Athanasios961
SecondChildCreateTimeTAG: 2013-03-21T13:30:05Z
SecondChildVoteTAG: 0
FirstChildTAG: I am sorry that you missed the deadline, but I hope you take advantage of the provided exercises as an aid to learning the material. That is their most important function. Fortunately your lowest two problem sets are thrown out. You still have plenty of material with which to pass the class.
I think you have to look at this from the instructor's point of view. Because this class is large, there will be people with issues like yours throughout the class. Most of these people will be sincere (I have no question about your sincerity), some will be from people trying to game the system. The only way to effectively administer a MOOC is to be brutal and ignore requests like yours. Otherwise, the instructors will be doing nothing else, and there may not even be hooks in the software to easily accommodate such exceptions.
Ultimately, everyone has to take responsibility for meeting deadlines that have been posted well in advance. I wish you success with the remainder of the class, and I hope this class helps you achieve "statistics literacy" which should be your real goal as it will help you navigate modern life.
FirstChildUserIdTAG: 174100
FirstChildUserNameTAG: markpolak
FirstChildCreateTimeTAG: 2013-03-21T16:26:17Z
FirstChildVoteTAG: 0
IndexTAG: 460
TitleTAG: R code for ES 9 - 11
I've just put code for those exercises in the wiki.
Please, if you understand what I've tried to do in ES10 Problem 1C:
https://www.edx.org/wiki/Stat2.1x/R/ES_10_Solutions/
give me feedback. Particularly about the last optional lines of the code for this problem. Does that make statistical sense at all?
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-21T10:52:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I'm following your codes, for me very good.
But ES10 1C is not understandable for the moment.
I will look it again after the final exam.
Your code is an excellent source of learning, please, follow publishing it.
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-23T20:53:56Z
FirstChildVoteTAG: 0
SecondChildTAG: I appreciate! Don't forget that I've to code very quickly and that my knowledge of the R language is rudimentary as well as of statistics. So, please, don't take the code as reference, only as a way to see how to use R even at a rudimentary level (as a student - of R and statistics).
Regarding ES10 1C new ideas can be gained from the last lecture.
I'm trying to find out R facilities (I mean, built-in functions or functions provided by well-known packages) as suitable as possible to the material, that's the case of the `MASS` library in a previous set. I'm afraid, though, that solutions to ES12 have to wait for a better coder ;-), unless one would resort to self-made functions (I'm currently refraining from do that). The library `mvtnorm` seems promising for this set, but the documentation is very technical.
In the meantime, take a look at the `lm()` function. It's the R king for linear regression. I didn't have time to write some demonstration code, but it's relatively easy to use at a basic level.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-23T23:01:39Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.coursera.org/course/stats1
This is a course where you can be interested in.
Statistics using "R".
There, the Teacher use lm() a lot.
The use of R is from highest level (built in) functions.
The good thing about your code is that you use low level code to
solve problems.
And it let us a better understanding of how statistics details can
be coded.
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-24T13:09:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the information. I'll be there if I can.
The better way to go to the low-level is in R base code itself, but many basic functions (that `.Internal` that you get sometimes if you investigate the code with the interpreter) are written in C for improving performance. I've taken a look at the C source code, but it requires much more time to understand.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-24T18:01:35Z
SecondChildVoteTAG: 0
IndexTAG: 461
TitleTAG: How do these questions relate to the lecture?
I've bombed out here, I thought I had followed and understood the lecture, but I failed to see how the questions related to the content.
UserIdTAG: 7854
UserNameTAG: pejic
CreateTimeTAG: 2013-03-21T10:50:35Z
VoteTAG: 1
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 1
FirstChildTAG: The last question directly relates to the lecture on RMS Error of Regression. And the residual plots also relate to the last section of that lecture.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T11:10:08Z
FirstChildVoteTAG: 3
IndexTAG: 462
TitleTAG: Excellent explaination
The qualitative explaination of the formula for the rms error is excellent - the formula makes so much sense now, that it's impossible to forget it :)
UserIdTAG: 407687
UserNameTAG: AndreaPi
CreateTimeTAG: 2013-03-21T10:48:40Z
VoteTAG: 2
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 0
IndexTAG: 463
TitleTAG: Week 4: Math in lecture a little different from math in text
The textbook discussion of the Regression Effect (Ch.11 ) mentions k*SDY. The value "k" also comes up in an earlier chapter(s). I cannot find a discussion of it, since the text is not searchable, nor by searching key words at the end of the textbook chapters.
What is it and how is it connected to the professor's discussion of r and relevant to regressions equations? Thank you.
UserIdTAG: 11318
UserNameTAG: JMcGlynn
CreateTimeTAG: 2013-03-21T07:06:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: $k$ was used when we did Chebychev and Markov inequalities.
>If the mean of a list of numbers is M and the standard deviation of the list is SD, then for every positive number k,
>[the fraction of numbers in the list that are k×SD or further from M] ≤ $\frac{1}{k^2}$.
So, in the text:
> the average value of Y for individuals whose values of X are about kSDX above the mean(X) is less than kSDY above the mean(Y)
You have $k=2$, say, so values are $2sd$ from the mean.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T01:09:05Z
FirstChildVoteTAG: 0
IndexTAG: 464
TitleTAG: ex set 12, 1B
I can hardly infer from the information given that the scatter diagram of annual income and age is football-shaped. Can we say that "It's indeed a football-shaped diagram just because it's reasonable"?
Hope someone could help me.
Thanks in advance.
UserIdTAG: 724149
UserNameTAG: BillZhao
CreateTimeTAG: 2013-03-21T07:06:34Z
VoteTAG: 7
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 5
FirstChildTAG: Agree! The problem 1 is absolutely similar to the problem 3, but in the last one we have direct instruction, that *the scatter diagram is football shaped*.
FirstChildUserIdTAG: 827410
FirstChildUserNameTAG: nickme
FirstChildCreateTimeTAG: 2013-03-21T07:23:51Z
FirstChildVoteTAG: 0
SecondChildTAG: Tick show answer and you could take the explanation
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-03-21T19:33:40Z
SecondChildVoteTAG: 0
FirstChildTAG: We may ask if "It's indeed a football-shaped diagram just because it's reasonable" does it mean "yes" or "maybe".
FirstChildUserIdTAG: 1210009
FirstChildUserNameTAG: GIAN66
FirstChildCreateTimeTAG: 2013-03-21T11:41:54Z
FirstChildVoteTAG: 0
FirstChildTAG: I have failed this question.
The only approach I see is to figure out whether or not each of the two distributions are normal.
FirstChildUserIdTAG: 495702
FirstChildUserNameTAG: donpepe
FirstChildCreateTimeTAG: 2013-03-21T13:54:51Z
FirstChildVoteTAG: 1
SecondChildTAG: "show answer".
SecondChildUserIdTAG: 1210009
SecondChildUserNameTAG: GIAN66
SecondChildCreateTimeTAG: 2013-03-21T15:03:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Maybe we can make conclusion based on the r.m.s error of regression. because in footbal shaped the r.m.s is about equal to the SD alone just for one variable" The SD is a measure of their spread, and in the case of football-shaped scatterplots, is about the same as the rms error of regression" so maybe we can use this!!! the only thing is that I'm not sure how much those two sould be same.
FirstChildUserIdTAG: 152907
FirstChildUserNameTAG: visperad
FirstChildCreateTimeTAG: 2013-03-22T12:44:48Z
FirstChildVoteTAG: 3
FirstChildTAG: Think about the question this way:
Instead of asking whether or not the data is football shaped, think about it using the more proper term: bivariate normal. Meaning that to be football shaped both data sets have to be normal.
FirstChildUserIdTAG: 840238
FirstChildUserNameTAG: bchilders
FirstChildCreateTimeTAG: 2013-03-23T17:02:31Z
FirstChildVoteTAG: 3
IndexTAG: 465
TitleTAG: Download Video link not visible for Lecture 5.4
Download Video link not visible for Lecture 5.4 (NOT ALL HISTOGRAMS ARE BELL SHAPED; CHEBYCHEV REVISITED)
Please I don't want to lose the video after the course ends.
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-03-21T06:45:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 0
IndexTAG: 466
TitleTAG: [STAFF] PROBLEM WITH FINAL EXAM DATES
Hi Staff,
First of all I´d like to congratulate you for this great course.
Secondly, I have a problem with respect to the final exam. The problem is I will not be available during the final exam period and most probably I will not be able to do it.
In this case, will I get the certificate? My overall grade is already 56%. I understand that the answer might be YES, provided that my overall mark is above 35%, but need confirmation.
I wait for a response so as to be able to organize myself.
Thanks in advanced
UserIdTAG: 675535
UserNameTAG: asori
CreateTimeTAG: 2013-03-21T06:30:54Z
VoteTAG: 0
CoursewareTAG: Section 8b: Error in the regression estimate (Lec 8.3) / Lec 8.3: How regression is commonly used; estimating an unknown true line
NumberOfReplyTAG: 0
IndexTAG: 467
TitleTAG: [STAFF] PROBLEM WITH FINAL EXAM DATES
Hi Staff,
First of all I´d like to congratulate you for this great course.
Secondly, I have a problem with respect to the final exam. The problem is I will not be available during the final exam period and most probably I will not be able to do it.
In this case, will I get the certificate? My overall grade is already 56%. I understand that the answer might be YES, provided that my overall mark is above 35%, but need confirmation.
I wait for a response so as to be able to organize myself.
Thanks in advanced
UserIdTAG: 675535
UserNameTAG: asori
CreateTimeTAG: 2013-03-21T06:28:13Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I'm not staff, but the question has been asked many times, and I'm pretty confident about the answer.
The answer *is* yes. As long as your total grade is at least 35%, you'll get the certificate.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-21T11:16:54Z
FirstChildVoteTAG: 1
FirstChildTAG: As it says in the course policy, 35% *overall*.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T12:16:31Z
FirstChildVoteTAG: 1
IndexTAG: 468
TitleTAG: Exercise Set 11 - answers not visible
Dear,
I do not have access to the "show answer" button for Exercise Set 11.
Will they be available?
Thanks
Renauld
UserIdTAG: 99916
UserNameTAG: Renauld
CreateTimeTAG: 2013-03-21T06:26:48Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I want to know the answers too. Where can i see them?
FirstChildUserIdTAG: 815940
FirstChildUserNameTAG: elzadomingues
FirstChildCreateTimeTAG: 2013-03-21T10:49:36Z
FirstChildVoteTAG: 2
IndexTAG: 469
TitleTAG: No submit button
I tried to do this test since yesterday but there is no 'check'' or 'grade' or any button appear. how can I do this test?
UserIdTAG: 419787
UserNameTAG: Duangta
CreateTimeTAG: 2013-03-21T05:37:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 4
FirstChildTAG: You can't. There are deadlines. This one expired about 5 hours ago. You can only do Week 5 work for grading.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T05:38:39Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Duangta, I'm in the same situation. I don't care about the grade, I'd just like to check my answers. Here they are:
1A: non-linear, and shows negative association
1B: options 2 thru 5
2A: -1
2B: 1
3: option 3
Do these match yours?
FirstChildUserIdTAG: 495943
FirstChildUserNameTAG: Akosiwa
FirstChildCreateTimeTAG: 2013-03-21T05:43:50Z
FirstChildVoteTAG: 0
SecondChildTAG: They are correct. The Show Answer button should be activated soonish.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-21T05:50:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Susan :)
SecondChildUserIdTAG: 495943
SecondChildUserNameTAG: Akosiwa
SecondChildCreateTimeTAG: 2013-03-21T06:51:48Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you
FirstChildUserIdTAG: 419787
FirstChildUserNameTAG: Duangta
FirstChildCreateTimeTAG: 2013-03-21T07:23:14Z
FirstChildVoteTAG: 0
FirstChildTAG: good to know the answers :) thanks
FirstChildUserIdTAG: 899355
FirstChildUserNameTAG: nelolo
FirstChildCreateTimeTAG: 2013-03-22T03:04:34Z
FirstChildVoteTAG: 0
IndexTAG: 470
TitleTAG: I just got started.
I just noticed about this magnificent course, and i would like to know if as i move forward in the course, will i have the opportunity to get the certificate? I really don't care too much, but before keeping on i would like to know that. I'm from Chile, and spending time learning something useful for free is amazing, thanks for the work you are delivering.
I hope you can answer me.
Atte. Cristóbal Ojeda Pinto
ca.ojedapinto@gmail.com
UserIdTAG: 1459018
UserNameTAG: caojedap
CreateTimeTAG: 2013-03-21T05:21:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > I hope you can answer me
Did you read the course policy on grading? Get 100% for the rest of the course (one problem set and the exam) and you will get the certificate.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T05:24:47Z
FirstChildVoteTAG: 1
SecondChildTAG: hi susan, i am in a similar quandary.. posted this as well..(How do i earn a certificate now- late starters)
Looks like even if i take just the final exam, would need a 100% to get this certificate..correct?
Any alternatives? maybe a repeat of stat2.1 x in the near future?
SecondChildUserIdTAG: 974217
SecondChildUserNameTAG: kmfaraaz
SecondChildCreateTimeTAG: 2013-03-21T06:22:38Z
SecondChildVoteTAG: 0
SecondChildTAG: The course will probably be repeated. That is the general idea with edX - courses are developed and offered again.
But of course, that depends on the Berkeley staff being prepared to go through this all again. And again.
>would need a 100% to get this certificate..correct?
Correct. The final exam is worth 30% and the problem set for week 12 is 5%. So you would need to get them both 100% correct.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-21T06:47:24Z
SecondChildVoteTAG: 0
IndexTAG: 471
TitleTAG: How do I earn a certificate now. - late startes (Staff and Prof - please read ! )
Prof Ani and team ,let me start by first thanking you for the great course that you have been conducting. I don't think i have ever enjoyed stats so thoroughly before.
My concern is regarding earning of a certificate as i was able to start taking the course only in week 3. Before I come across as a whiner, please bear in mind that i work a 60 hr work week and have been facing some issues on the home front which have been keeping me away from this course.
I currently work for an Analytics firm and Statisticss is something which i need to arm myself with nonetheless,irrespective of whether if i can earn this certificate or not.
So what i ask for is this:
-if i cant earn a certificate, can i directly move on to 2.2x . Will i be eligible to take that up? Will the material for 2.1 x still be available post the exam date since i am keen learning everything here.
-Would the team at edx be courteous enough to give folks like me an alternative chance at earning this certificate. Like a delayed exam or a supplementary - the way we have it here in India. Just a thought!
A big thanks to you guys (@ edx) for the work you'll are doing. God bless!
Faraaz
UserIdTAG: 974217
UserNameTAG: kmfaraaz
CreateTimeTAG: 2013-03-21T05:15:21Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For "pass" (= the certificate) your end result needs to be at least 35%.
The final exam will be worth 30% and the problems of weeks 3 and 4 can get you 20% of the end result. So you could potentially score 50% by cracking the exam and exercises from weeks 3 and 4. So it depends on you.
You will be able to move directly to Stat2.2x!
Besides, the course Stat2.1x will be offered again in the future as well as almost all of the courses on edx.org.
FirstChildUserIdTAG: 267427
FirstChildUserNameTAG: Davorin
FirstChildCreateTimeTAG: 2013-03-21T14:17:17Z
FirstChildVoteTAG: 1
SecondChildTAG: hi davorin, i get what you mean, and i am correct on most of my answers, just wish i had found the time to do this before.. when you say, you will be able to move directly.Do you mean- my pass certificate on this course will have no effect on me wanting to take up stats 2.2x?
SecondChildUserIdTAG: 974217
SecondChildUserNameTAG: kmfaraaz
SecondChildCreateTimeTAG: 2013-03-21T16:29:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Edx courses are traditionally open. You probably should have mastered the 2.1x material before starting 2.2x, but that doesn't mean you need to have passed or even enrolled in 2.1x.
In other words, you get to decide whether or not you are ready for Stat 2.2x.
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-03-21T16:43:04Z
SecondChildVoteTAG: 0
IndexTAG: 472
TitleTAG: Seriously?
39 minutes!! omg!
UserIdTAG: 120241
UserNameTAG: RomanoLaura
CreateTimeTAG: 2013-03-21T04:58:35Z
VoteTAG: 12
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 2
FirstChildTAG: I gather you have never had to sit through a 3 hour mathematics lecture? In a crowded room, no pause button.
39 minutes is nothing! Run it at 1.50x and it's a mere 26 minutes.
We really have become a society that wants instant everything.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T05:07:12Z
FirstChildVoteTAG: 6
SecondChildTAG: I think it's more the surprise considering all the previous videos have been quite a bit shorter.
SecondChildUserIdTAG: 1145404
SecondChildUserNameTAG: KimHill
SecondChildCreateTimeTAG: 2013-03-21T05:35:50Z
SecondChildVoteTAG: 0
SecondChildTAG: I've found through experience that during a 3+ hour lecture of *almost* any kind, if the lecturer doesn't schedule a pause, you *do* create a pause button by yourself...by quietly running off and getting a cup of coffee.
You miss about 5 minutes of lecture, unfortunately, but failure to do so often results in worse, and sometimes embarrassing, consequences, like loud snoring during a moment of silence, and a complete failure at taking in anything that's been said after the 2nd hour or so.
But, yeah, seriously, 39 minutes is nothing :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-21T14:44:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Darling, I said it because my internet is slow, and the larger the video, the more I have to wait for it to charge. So sorry if I offended your faith in humanity, not everyone has a fast internet connection.
SecondChildUserIdTAG: 120241
SecondChildUserNameTAG: RomanoLaura
SecondChildCreateTimeTAG: 2013-03-21T17:07:02Z
SecondChildVoteTAG: 0
SecondChildTAG: In this case you're probably be better off downloading the video .mp4 file(there's a link just below the lecture).
You can go do something else while it downloads, if anything happens to the connection you can just resume the download, and once it's completed you'll have the file on your computer in case you need to re-watch the lecture later.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-21T17:18:41Z
SecondChildVoteTAG: 0
SecondChildTAG: > Darling, I said it because my internet is slow,
That's okay, sweetheart.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-21T20:59:49Z
SecondChildVoteTAG: 0
SecondChildTAG: No, I don't want instant *coffee*!! :)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-21T21:50:25Z
SecondChildVoteTAG: 0
SecondChildTAG: the problem is while many of the other segments had relatively little content, a lot of important content is concentrated in this one which makes this part of the lecture take less care than the others...the content is somehow not equally distributed along all the course
SecondChildUserIdTAG: 902568
SecondChildUserNameTAG: khassi
SecondChildCreateTimeTAG: 2013-03-23T20:45:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Residual plot segment could have been a separate video. But no big issue.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-21T09:08:46Z
FirstChildVoteTAG: 0
IndexTAG: 473
TitleTAG: Pilot Landing Segment in "Regression Effect" Video
If one were trying to think about the pilot-landing example from the "Regression Effect" video in graphical terms, what variables would be plotted on the X & Y axes? Would it be "quality of 1st [or nth] landing" vs. "quality of 2nd [or (n+1)th] landing?"
UserIdTAG: 93947
UserNameTAG: TM1001
CreateTimeTAG: 2013-03-21T03:50:03Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 11 / Reading and Practice for Exercise set 11
NumberOfReplyTAG: 1
FirstChildTAG: I think one individual is the pilot, so probably (x - first landing, y - second landing) would be the axes. But maybe one could collect more than one double take-off/landing sessions per pilot.
FirstChildUserIdTAG: 197621
FirstChildUserNameTAG: quilombolo
FirstChildCreateTimeTAG: 2013-03-22T00:28:14Z
FirstChildVoteTAG: 0
IndexTAG: 474
TitleTAG: coud'nt do some of the excercises 9,10,11 in time
I could not submit some of the excercises in 9,10 and 11 in time since my internet connection was not working properly.Can I get one more mercy chance to submit the excercises 9,10,11 ?
UserIdTAG: 991318
UserNameTAG: Rejani
CreateTimeTAG: 2013-03-21T03:30:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: same problem
FirstChildUserIdTAG: 947092
FirstChildUserNameTAG: PKNeupane
FirstChildCreateTimeTAG: 2013-03-21T04:27:17Z
FirstChildVoteTAG: 0
IndexTAG: 475
TitleTAG: Help! I can't submit my work on chrome
I am having problems with submitting my answers to the homework.
UserIdTAG: 185348
UserNameTAG: prophet7X
CreateTimeTAG: 2013-03-21T03:27:36Z
VoteTAG: 2
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: I realize my time is up but I also don't see the check button on the chrome.
FirstChildUserIdTAG: 1206081
FirstChildUserNameTAG: anusimw
FirstChildCreateTimeTAG: 2013-03-21T03:31:19Z
FirstChildVoteTAG: 0
FirstChildTAG: > I realize my time is up but I also don't see the check button on the chrome.
And that is why you don't see a Check button. Once the deadline has gone, you can't submit for grading.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T04:19:20Z
FirstChildVoteTAG: 0
IndexTAG: 476
TitleTAG: Exercise 2e
I think there's no linear relationship between variables according to the error plot
UserIdTAG: 1219337
UserNameTAG: luisfrivera
CreateTimeTAG: 2013-03-21T03:07:31Z
VoteTAG: 3
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: I suppose there are two correct options (first and last) and we should check the *best* one, but I can't understand why first option is *better* than last option...
FirstChildUserIdTAG: 827410
FirstChildUserNameTAG: nickme
FirstChildCreateTimeTAG: 2013-03-21T07:13:20Z
FirstChildVoteTAG: 1
SecondChildTAG: Last option is not correct.... Don't know why!
SecondChildUserIdTAG: 1219337
SecondChildUserNameTAG: luisfrivera
SecondChildCreateTimeTAG: 2013-03-21T13:32:33Z
SecondChildVoteTAG: 0
SecondChildTAG: I have not submitted the answer but look out for things which is not obvious at first look. Try to find answer qualitatively
1. What will be average mean of Residuals?
2. Is there any trend?
Based on above answer, decide best option. Thanks!
SecondChildUserIdTAG: 1181586
SecondChildUserNameTAG: eumannu
SecondChildCreateTimeTAG: 2013-03-23T23:57:05Z
SecondChildVoteTAG: 0
FirstChildTAG: I thought so, too, but the "show solution" text explains pretty well why this residual plot has a symptom indicating that it cannot be trusted enough to draw any conclusions, even about a possible nonlinearity.
FirstChildUserIdTAG: 76774
FirstChildUserNameTAG: spatrick
FirstChildCreateTimeTAG: 2013-03-24T02:11:56Z
FirstChildVoteTAG: 0
IndexTAG: 477
TitleTAG: week 4 excercise solutions
Can someone kindly tell me when the answers to the excercises 9, 10,& 11 of week 4 be posted?
UserIdTAG: 876760
UserNameTAG: devirajmohan
CreateTimeTAG: 2013-03-21T03:04:26Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I'm waiting for the answers as well...
FirstChildUserIdTAG: 1293941
FirstChildUserNameTAG: CHHAVIMEHROTRA
FirstChildCreateTimeTAG: 2013-03-21T03:27:14Z
FirstChildVoteTAG: 1
FirstChildTAG: Please post the answers, as I didn't do this segment well
FirstChildUserIdTAG: 569767
FirstChildUserNameTAG: SanjayS72
FirstChildCreateTimeTAG: 2013-03-21T05:23:07Z
FirstChildVoteTAG: 1
IndexTAG: 478
TitleTAG: I am not allowed to complete Exercise 11, at it is not time yet.
It is just 9.56 pm Central Time on March 20 in the midwest (Kansas), and I can no longer answer questions in exercise 11, isn't it suppose to close at 23:30 on March 20.
Prof. A, what do I do?
UserIdTAG: 1021357
UserNameTAG: bodeade
CreateTimeTAG: 2013-03-21T02:58:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30pm GMT. That translates to (I think) 6:30pm Central Time.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-21T03:10:31Z
FirstChildVoteTAG: 0
IndexTAG: 479
TitleTAG: CHECKER NOT WORKING
Who can help me with this , I sill have at least 1 hr and 30 secs to deadline but the checker is not working. Can I just email my answer to the instructors
UserIdTAG: 408651
UserNameTAG: Drdanilofuna
CreateTimeTAG: 2013-03-21T02:41:47Z
VoteTAG: 1
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: Time was up a few hours ago. It uses GMT
FirstChildUserIdTAG: 150589
FirstChildUserNameTAG: TriciaC
FirstChildCreateTimeTAG: 2013-03-21T02:47:20Z
FirstChildVoteTAG: 0
SecondChildTAG: me too no check answer button
SecondChildUserIdTAG: 1102287
SecondChildUserNameTAG: Loubar
SecondChildCreateTimeTAG: 2013-03-21T03:16:36Z
SecondChildVoteTAG: 0
FirstChildTAG: The current time is Thursday 2:57am GMT .
The deadline was Wednesday 11:30pm GMT.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T02:57:50Z
FirstChildVoteTAG: 0
IndexTAG: 480
TitleTAG: ES12
I can't understand last exercises of ES12, Could anyone help me please?
UserIdTAG: 906560
UserNameTAG: ivanm02
CreateTimeTAG: 2013-03-21T02:35:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 2
FirstChildTAG: ES12 has not been posted as yet. Atleast I cannot see it
FirstChildUserIdTAG: 1049940
FirstChildUserNameTAG: skarora1
FirstChildCreateTimeTAG: 2013-03-21T04:17:22Z
FirstChildVoteTAG: 0
SecondChildTAG: It has. Look for Week 5
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-21T04:18:37Z
SecondChildVoteTAG: 0
SecondChildTAG: watch section 8a again. Your answer resides in there.
SecondChildUserIdTAG: 724149
SecondChildUserNameTAG: BillZhao
SecondChildCreateTimeTAG: 2013-03-21T07:28:50Z
SecondChildVoteTAG: 0
FirstChildTAG: You need to watch the 2nd video carefully (The RMS error of regression).
At 1.50X speed, about 12 minutes in there is a worked example "For what percent of the people, roughly, is the regression estimate of weight based on height correct to within 40 pounds?"
This will help with the first two parts. For the 3rd you need to follow the next example on estimating weight on height.
You need to manipulate the formula a bit, you are not working out exactly what the example demonstrates.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T04:17:41Z
FirstChildVoteTAG: 1
IndexTAG: 481
TitleTAG: [Staff] No submition buttons in this excersice...
I'm at 23:05 and the submitions buttons are missing...
UserIdTAG: 323166
UserNameTAG: PabloT
CreateTimeTAG: 2013-03-21T02:06:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: No, it is after 2am GMT. Deadline gone.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T02:10:30Z
FirstChildVoteTAG: 0
SecondChildTAG: i'm -4 gmt
SecondChildUserIdTAG: 323166
SecondChildUserNameTAG: PabloT
SecondChildCreateTimeTAG: 2013-03-21T02:17:33Z
SecondChildVoteTAG: 0
SecondChildTAG: It doesn't matter where *you* are. The time is GMT. Here in Australia it is 1.26pm, whereas it is 2.26am GMT.
http://wwp.greenwichmeantime.com/info/current-time.htm
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-21T02:26:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Too bad, and thnx Susan, i'm still working with the Harvard course times, i do the same mistake a couple of times already. Thanks for your time and explanation.
SecondChildUserIdTAG: 323166
SecondChildUserNameTAG: PabloT
SecondChildCreateTimeTAG: 2013-03-21T02:30:36Z
SecondChildVoteTAG: 0
IndexTAG: 482
TitleTAG: R code for population versus sample: a very quick and dirty hack
Here is a very quick and dirty hack to wrap 'fixed' built-in R functions for population statistics when we don't want the default R behaviour based on samples (it takes into account only typical problematic functions):
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/R/popFix/
I put it in the forum expecting comments, refutations or critics as a coding exercise if there is someone interested. The code is incomplete.
BEWARE!! DON'T USE IN EXERCISES!! I've only tested it for one test-case :O with few functions.
Typical use case:
`popFix(sd, x)`
instead of, for example, `sd(x)`
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-21T01:54:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 483
TitleTAG: Thank edX and Professor Ani
Dear Prof. Ani,
In just a week time our statistics course will be finished. I did not take this course seriously when I was in college. But I realized how important statistics now in my medical career. I am a practicing anesthesiologist and I know how important this course can be applied not only academically but also clinically. Medicine is now gearing more towards research especially in my field wherein there is fast turnover of new technology and knowledge. A basic knowledge of this course is necessary and I would like to thank edX for giving me a chance to review again for free and giving us a very good teacher, Professor Ani.
Am looking forward to join again the stat 2.2 and 2.3 courses with Professor Ani.
Thank you very much Professor Ani!
Dr. Tess Estrellas
UserIdTAG: 1083507
UserNameTAG: mtzemd68
CreateTimeTAG: 2013-03-21T01:51:37Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thank you Professor Ani !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
The number of exclamations is statistically significant.
FirstChildUserIdTAG: 1106649
FirstChildUserNameTAG: skoules
FirstChildCreateTimeTAG: 2013-03-21T21:43:24Z
FirstChildVoteTAG: 1
IndexTAG: 484
TitleTAG: final exam
Could someone please tell me where the info for the final is? I'm reading posts about having 3 days, starting Tuesday, etc. Where is this posted? How do I access it?
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-03-21T01:48:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You should have received an email. The Course Info section is broken at the moment, but it will be posted there as soon as possible. Meanwhile, the email:
Dear Students,
The final exam for Stat 2.1X will start at 05:00 A.M. Greenwich Mean Time (GMT) on Tuesday, March 26 and end at 05:00 A.M. GMT on Friday, March 29. That's 72 hours.
Solutions to Exercise Set 12 will be visible once you have submitted your answers. That is the only Exercise Set in Week 5. Please note that the due date for Exercise Set 12 is Monday March 25, the day before the final.
The discussion forum will be closed during the three days of the final exam, but staff will be able to post to the forum and you will be provided with an email address to which you can email bugs or errors.
You will have the entire 72 hour period to take the exam. You don't have to do it all in one sitting.
The final will be about 1.5 to 2 times the length of the midterm. If you do it at one sitting I expect it will take you 90 minutes to 2 hours, possibly less depending on how well you know your stuff. The Exercise Sets, Practice Problems sets, and the midterm are good indications of what to expect on the final.
I will post additional practice problems by the end of this week.
Best,
Prof. A.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T01:57:50Z
FirstChildVoteTAG: 0
FirstChildTAG: Information about the final exam timing is not on the course website yet. Check your email to see if you received an email about the final exam.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-21T01:58:16Z
FirstChildVoteTAG: 0
IndexTAG: 485
TitleTAG: CANNOT SUBMIT
There is no submit button on the exercises that are due today!
Is this just happening on mine or is this a problem for everyone?
UserIdTAG: 344472
UserNameTAG: ss54357
CreateTimeTAG: 2013-03-21T00:48:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: They were due yesterday. GMT. It is now 1am Thursday.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T00:59:18Z
FirstChildVoteTAG: 0
FirstChildTAG: We couldn't access Section 6 (Exercise Set 9 till Set Exercise 11). Just noticed this morning but its already due. I had opened last Monday (18 March 2013) but there was no any updates on Section 6. I wonder Section 6 is not covered in midterm but how it can be placed before midterm. Kindly clarify. Thank you.
Regards from Malaysia,
Aizura
FirstChildUserIdTAG: 1283749
FirstChildUserNameTAG: aizura
FirstChildCreateTimeTAG: 2013-03-21T02:47:53Z
FirstChildVoteTAG: 0
IndexTAG: 486
TitleTAG: Stat 2.2x course
Will a Stat 2.2x or an appropriate follow up course to the current Stat 2.1x be offered following completion?
UserIdTAG: 798251
UserNameTAG: asmani
CreateTimeTAG: 2013-03-21T00:42:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Search the forum. There are dozens of posts. Yes. Time unknown.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T00:59:46Z
FirstChildVoteTAG: 1
SecondChildTAG: Hola, mi nombre es Laura y soy peruana, me da gusto participar en este foro.
SecondChildUserIdTAG: 443466
SecondChildUserNameTAG: lauragoicochea
SecondChildCreateTimeTAG: 2013-03-21T01:02:19Z
SecondChildVoteTAG: 0
IndexTAG: 487
TitleTAG: Excercise set 9
can anyone please explain problems 2&3, now that the deadline is over.
UserIdTAG: 570669
UserNameTAG: Nion
CreateTimeTAG: 2013-03-21T00:39:22Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Set 9: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/61842796b3b14c94823269e6fa001439/1072491ab42a4679863f6b5bb5e223ba/
>2A: The correlation between the number of right answers and the number of wrong answers is
![enter image description here][1]
With a correlation of $r=-1$. The graph wasn't necessary, but it helps to visualise. No calculation required, you have a perfect negative relationship.
[1]: https://edxuploads.s3.amazonaws.com/13638278981343653.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T01:05:40Z
FirstChildVoteTAG: 2
SecondChildTAG: Sorry, How did you get -1?
SecondChildUserIdTAG: 569767
SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-03-23T08:23:27Z
SecondChildVoteTAG: 0
FirstChildTAG: >2B. The correlation between the score on the test and the number of right answers is
So you have $Marks=(right \times 5) - wrong$, as each right answer gets 5 points, and 1 point is taken off for each wrong answer.
![enter image description here][1]
Correlation $r=1$
The data, obtained from the question description - 10 questions that are marked either right or wrong:
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13638283091343601.png
[2]: https://edxuploads.s3.amazonaws.com/13638286261343601.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T01:12:52Z
FirstChildVoteTAG: 2
FirstChildTAG: >Q3. Consider all the married couples in the world. Which of the following do you think is true regarding the association between wife’s age and husband’s age? Pick the best option.
Solution
>The association is positive as older couples consist of older wives and older husbands.
Here, we were just interested in the direction of the relationship. I made up a bit of data, with husband generally older than wife, but sometimes not:
![enter image description here][1]
So there is a positive relationship.
To get a negative relationship you would need the young women to marry much older men, and young men to marry much older women.
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/1363917503134361.png
[2]: https://edxuploads.s3.amazonaws.com/1363917805847440.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-22T02:26:38Z
FirstChildVoteTAG: 0
IndexTAG: 488
TitleTAG: Answer of 2B
Now the deadline is over can any one tell me what was the ans of 2B (0.3277) ?My answers for 1A and 1C were correct.
UserIdTAG: 1293941
UserNameTAG: CHHAVIMEHROTRA
CreateTimeTAG: 2013-03-21T00:33:05Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: -13.17
FirstChildUserIdTAG: 99916
FirstChildUserNameTAG: Renauld
FirstChildCreateTimeTAG: 2013-03-21T06:38:18Z
FirstChildVoteTAG: 0
FirstChildTAG: $Intercept=\mu_y - slope \times \mu_x = 6 - 0.8333 \times 23 = -13.1659$
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T07:18:36Z
FirstChildVoteTAG: 0
IndexTAG: 489
TitleTAG: General question regarding the course
I would like to make a question.
Since the courses are not live. Why each participant cannot enter in the course when he/she wants and follow and complete the course in specific time period that he can manage? With a maximum period directed by you ie the course 2 months and max period of completion 3 months. By this method we can be a little more relaxed....also in case of a failure or something happens and the participation is interrupted the participant will have to wait till the completion to reapply
I have difficulty in completing each time the exercises mainly because of the time needed to solve them in a daily basis. Work doesn't leave me with a lot of time gaps and usually if there are any they are irregular in their duration and schedule.
thanks
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-21T00:27:50Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I have a very similar question, because I do not understand the strict deadlines. Especially this week, I am really busy with work and do not have time to master correlation and regression. I will have time this weekend and next week, but then I won't be able to submit the exercises.
Is it possible to relax the due dates for the end of the class? Maybe have the rest of the assignments for 2.1x, including the final, due on the final day of the class term?
Thank you.
FirstChildUserIdTAG: 1244339
FirstChildUserNameTAG: Tuck3r
FirstChildCreateTimeTAG: 2013-03-21T01:04:10Z
FirstChildVoteTAG: 1
SecondChildTAG: My guess for the narrow window of time for the course is to minimize the administrative load on the professors and staff. If the course is open for 2 months or something like that, then the professors have to be available to answer questions and the staff have to run upkeep on the course for that long.
Additionally, running tests would be quite hard to do with a flexible time range. Part of the test is to complete it in a certain amount of time. Also it becomes incredibly hard to get students feedback about the test results because you can't release the answers until everyone is done.
I also wish the course moved at a slightly slower pace, but I can understand why the course schedule can't be quite as flexible.
SecondChildUserIdTAG: 1117422
SecondChildUserNameTAG: edutainment
SecondChildCreateTimeTAG: 2013-03-21T15:50:09Z
SecondChildVoteTAG: 0
FirstChildTAG: You might also find that the structure of the course is defined by edX. It is their platform, and they might make the format rules. So if they are trying to be comparable to a f2f class, then the courses will be structured as such.
edX is also offering proctored exams for some courses, with maybe more to follow. So you have to have set starting and finishing times.
With assessments, it is hard enough maintaining academic integrity now.
The bottom line really is that you have enrolled in an online course with an entity that wants to be a player in the online education market. So there will be rigidity in the requirements.
The university staff have their real time jobs too. And lives. I just hope they are getting some compensation for this, and that it hasn't been foisted on them by their Head as part of their teaching contract. Knowing how universities work...
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T21:44:59Z
FirstChildVoteTAG: 0
SecondChildTAG: I too hope they're compensated!
If not, where can I send some flowers and candy?
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-21T21:54:04Z
SecondChildVoteTAG: 0
IndexTAG: 490
TitleTAG: How do we find r to use in Exercise 11-1 from the text?
(*Just to clarify, this request is about a practice question - not about a question from Exercise Set 12*)
In the "Practice for Exercise Set 12", we are asked to try Exercise 11-1 from the text. You need the value of *r* to complete the calculations, but I don't see where to obtain *r*. Could someone smarter than me (which is probably a population of n > 20,000, out of the total number doing this course) point me in the right direction? Thank you!
UserIdTAG: 23003
UserNameTAG: WH
CreateTimeTAG: 2013-03-21T00:21:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 12 / Exercise Set 12
NumberOfReplyTAG: 3
FirstChildTAG: You can usually eyeball it and guess based on the graph, but if you want to calculate the it, I believe the formula for R is:
r = [(Exy) - (Ex)(Ey)] / sqrt{ [nE(x^2) - (Ex)^2][nE(y^2) - (Ey)^2] }
*E means "sum of"
FirstChildUserIdTAG: 1244339
FirstChildUserNameTAG: Tuck3r
FirstChildCreateTimeTAG: 2013-03-21T01:39:52Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks, Tuck3r - I was aware of the formula for *r*, it's just that there is apparently an error in the text (see SusanAust's post, above).
SecondChildUserIdTAG: 23003
SecondChildUserNameTAG: WH
SecondChildCreateTimeTAG: 2013-03-21T02:38:17Z
SecondChildVoteTAG: 0
FirstChildTAG: The question tells you to use Figure 11-1. It should be **Figure 10-1.**
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T02:02:07Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you!
SecondChildUserIdTAG: 23003
SecondChildUserNameTAG: WH
SecondChildCreateTimeTAG: 2013-03-21T02:35:25Z
SecondChildVoteTAG: 0
FirstChildTAG: This exercise set is very difficult, i guess that very few people will get 15/15
FirstChildUserIdTAG: 1104740
FirstChildUserNameTAG: dramrali
FirstChildCreateTimeTAG: 2013-03-23T01:10:42Z
FirstChildVoteTAG: 0
IndexTAG: 491
TitleTAG: STAFF - don't see submit button -- it's not 23:30 GMT
STAFF - don't see submit button -- it's not 23:30 GMT
Thank you.
UserIdTAG: 278857
UserNameTAG: suzyQ2012
CreateTimeTAG: 2013-03-21T00:15:10Z
VoteTAG: 4
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: > it's not 23:30 GMT
Now 00:20 GMT
FirstChildUserIdTAG: 339255
FirstChildUserNameTAG: RostFizhuk
FirstChildCreateTimeTAG: 2013-03-21T00:21:54Z
FirstChildVoteTAG: 1
FirstChildTAG: suzyQ2012 - sorry; edX says you posted 7 minutes ago. As I post this it's 12:22am GMT on Thursday, so it's almost an hour after 23:30 GMT. Sorry you couldn't submit!
(I'm not staff, btw - just another student)
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-21T00:22:26Z
FirstChildVoteTAG: 1
SecondChildTAG: Oh, thanks. Guess I need to finish my work earlier next time. :)
SecondChildUserIdTAG: 278857
SecondChildUserNameTAG: suzyQ2012
SecondChildCreateTimeTAG: 2013-03-21T01:30:51Z
SecondChildVoteTAG: 0
SecondChildTAG: You're not the only one! I was watching the clock scrambling to finish my own! :) Especially this week - lots of reading, and new topics for me.
SusanAust posted how to have a second clock in the Windows taskbar; have one for local time, one for GMT. That helped me a *lot*! Here's her post: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section3a_Lec_3_3/threads/5133be92f0ef281f0000002c
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-21T17:57:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Alan. Just make sure you used UTC time, I forgot about daylight saving in England. A commenter (patey) provided the timezone you should use. It's "Coordinated Universal Time" in the options.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-21T21:51:36Z
SecondChildVoteTAG: 0
IndexTAG: 492
TitleTAG: Check my answer after deadline, please
For 1a I posted 6.325 twice - and it is wrong [ :( ]. After that I rechecked and got 6.83.
Is this a right answer?
UserIdTAG: 339255
UserNameTAG: RostFizhuk
CreateTimeTAG: 2013-03-21T00:08:58Z
VoteTAG: 1
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: I agree with you... The answer (for me) is 6.83 grams
FirstChildUserIdTAG: 730908
FirstChildUserNameTAG: GabiNet
FirstChildCreateTimeTAG: 2013-03-21T01:06:11Z
FirstChildVoteTAG: 0
FirstChildTAG: A Show Answer option should appear soon. But yes, 6.83 is correct.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T01:21:10Z
FirstChildVoteTAG: 1
IndexTAG: 493
TitleTAG: What is the difference between Regression Coefficient and Correlation Coefficient???
Can anyone please explain this to me in detail that what is the difference between Regression Coefficient and Correlation Coefficient???
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T23:46:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: i just know the correlation coefficient is how tightly the points are clusted about a straight line.
FirstChildUserIdTAG: 1031881
FirstChildUserNameTAG: 19850524
FirstChildCreateTimeTAG: 2013-03-22T03:25:54Z
FirstChildVoteTAG: 0
IndexTAG: 494
TitleTAG: Prob 3 is quite good
Prob 3 is actually quite good, for it drives home the point that when faced with such problems, you should take care to note that
1.For there to be any positive/negative association you should be able to intuitively identify a mathematical relationship between the variables. One being in general less/more than the other is not enough to establish an association - you need to intuitively establish that one is the other plus something or multiplied by something, that something remaining similar for all the entries
2.Very often there is extraneous information in the different estimates (the options) which are strictly unavailable in the scatter plot which invalidates those estimates right away. For example option d is invalid straightaway since based on a cross section of wife's age vs husband's age we cannot estimate anything related to when they were married.
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-20T23:37:32Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 0
IndexTAG: 495
TitleTAG: ANOTHER DAY MORE
PLEASE I JUST REALICE THAT I CANT DO ALL THESE FOR TODAY..PLEASE ONE DAY MORE !!. I DONT WANNA FAIL THIS MODULE =(
UserIdTAG: 1062477
UserNameTAG: alejandra-hd
CreateTimeTAG: 2013-03-20T23:33:19Z
VoteTAG: 5
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 0
IndexTAG: 496
TitleTAG: Problem 1
So...obviously I got it wrong...but there is no "show answer"...and I swear I read everything I think I was supposed to read and watched the videos (and actually understood everything--or so I thought!) yet I still am not sure what the answer is...so I am hoping to get an explanation of this (after the deadline of course) so I can figure out where I went wrong.
UserIdTAG: 1280049
UserNameTAG: MissBehave
CreateTimeTAG: 2013-03-20T23:29:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: well, i just know it. i think 35% is -0.385 in the standard normal line. the r is less than 1. so another variable value is -0.385 times r, the value is larger than the -0.385. focus on the minus. the area in the standard normal line is larger.
hope to help you!
FirstChildUserIdTAG: 1031881
FirstChildUserNameTAG: 19850524
FirstChildCreateTimeTAG: 2013-03-22T03:32:49Z
FirstChildVoteTAG: 0
IndexTAG: 497
TitleTAG: PROBLEM 3
BRILLIANT!!!!
UserIdTAG: 798007
UserNameTAG: raji007
CreateTimeTAG: 2013-03-20T23:24:41Z
VoteTAG: 3
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: as i m :)
FirstChildUserIdTAG: 1158215
FirstChildUserNameTAG: umar07
FirstChildCreateTimeTAG: 2013-03-22T14:18:48Z
FirstChildVoteTAG: 0
IndexTAG: 498
TitleTAG: Problem 3
I love you Ani
UserIdTAG: 1260441
UserNameTAG: arachne
CreateTimeTAG: 2013-03-20T23:16:49Z
VoteTAG: 6
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: me to :)
FirstChildUserIdTAG: 1158215
FirstChildUserNameTAG: umar07
FirstChildCreateTimeTAG: 2013-03-22T14:19:04Z
FirstChildVoteTAG: 1
IndexTAG: 499
TitleTAG: [STAFF] : Question about the final exam
Hello. I´ve just read the email you have submitted to students about information on the final exam. I know it especifically stated that the forums will be closed during the exam period, except for technical issues we might encounter during the test. However, I was wondering if it is going to be possible to see previous posts, that is, the posts that already exist and that have been there for the previous weeks prior the final exam, just like they were available during the midterm.
Staff members, could you please inform students on this??
Thank you in advance and I have to say I have really enjoyed this course. Prof. Adhikari and Prof. Stark are great!!! Hope to join the following module for this Stats class!!
Best regards,
Ale
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T23:03:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The email does say that the forum will remain open read-only, so I'm pretty sure it'll just like during the midterm ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T23:09:41Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, you will be able to see the old posts. Just like during the midterm, as Klionheart has said. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-21T05:56:40Z
FirstChildVoteTAG: 0
IndexTAG: 500
TitleTAG: Final exam date
the final exam coincides with the jewish holiday called passover, or pesach. I am jewish, and therefore will not be able to access my computer because of jewish customs. is there anything that can be done about this?
UserIdTAG: 1326696
UserNameTAG: Maxkim
CreateTimeTAG: 2013-03-20T22:55:31Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Wait - aren't you just forbidden from eating leavened bread during that holiday? How are you prevented from accessing a computer?
(*note:* not judging anything here - I'm just curious)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T23:19:57Z
FirstChildVoteTAG: 1
FirstChildTAG: Dear Maxkim,
The date for the final exam has been posted since the beginning of the class. Did you take it into consideration when you registered?
Also, just out of curiosity - and, I admit, my ignorance - I was wondering whether the entire 72 hour period, during which the exam could be done, coincides with passover?
FirstChildUserIdTAG: 23003
FirstChildUserNameTAG: WH
FirstChildCreateTimeTAG: 2013-03-20T23:22:09Z
FirstChildVoteTAG: 1
FirstChildTAG: Maxkim - you can take the exam on the first day of Chol HaMoed.
[For those who are curious, Orthodox Jews do not use electrical devices on Saturday or on the first two days of many holidays, including Passover. That applies to Tuesday and Wednesday. Most Orthodox Jews will use a computer when necessary on the "Intermediate Days" of Passover, which start on Thursday - technically Wednesday night. These days are referred to in Hebrew as Chol HaMoed.]
FirstChildUserIdTAG: 1043
FirstChildUserNameTAG: jon31
FirstChildCreateTimeTAG: 2013-03-20T23:22:11Z
FirstChildVoteTAG: 2
SecondChildTAG: Like jon31 said, the first 2 days of the exam I am not permitted to use any electrical devices, and it's preferable to not use them the next day as well. And no, I hadn't thought about Passover being on the day of the final, I often tend to overlook things like that, unfortunately. I suppose I can take it on the last day if I must, but I was just wondering if due to this somewhat unique situation anything could be done. Thanks to everyone who answered!
SecondChildUserIdTAG: 1326696
SecondChildUserNameTAG: Maxkim
SecondChildCreateTimeTAG: 2013-03-20T23:55:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I see! Thanks for the info.
Well, the third day seems to be available, then. It should count as "necessary" to use the computer if you want to do the exam, especially if you need it to reach the 35% grade.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-21T18:15:21Z
SecondChildVoteTAG: 0
FirstChildTAG: Really loved the knowledge gained from this course, but the board should be moderated. The snide and inconsiderate, borderline hostile,comments made frequently here have no place amongst what I initially considered would be a group of life long sophisticated learners. The old adage that if you have nothing nice,or constructive and supportive (sic) to add, type NOTHING. But, my confidence in this project's long term objectives, alleviate this disappointment in said participants. Before long, the negativity, abject disrespect and silliness will dissipate as staff is added and techies put controls in place. Meanwhile, let's keep learning,succeeding and eagerly await part two! Happy Easter, and a Blessed Passover.
FirstChildUserIdTAG: 911527
FirstChildUserNameTAG: kbilic
FirstChildCreateTimeTAG: 2013-03-21T00:10:32Z
FirstChildVoteTAG: 0
SecondChildTAG: who was being snide and inconsiderate?
SecondChildUserIdTAG: 1326696
SecondChildUserNameTAG: Maxkim
SecondChildCreateTimeTAG: 2013-03-21T00:23:45Z
SecondChildVoteTAG: 0
FirstChildTAG: > who was being snide and inconsiderate?
No one. It's just one of the problems with internet communication. Some read hostility where there is none. Frankness is seen as rudeness. Any negative comment is bad.
Everything must be love, light, and joy - with a dash of unicorn sprinkles.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T00:29:06Z
FirstChildVoteTAG: 1
SecondChildTAG: > unicorn sprinkles
I want some! Can you put them on cup cakes?
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-21T00:38:47Z
SecondChildVoteTAG: 0
IndexTAG: 501
TitleTAG: Befuddled
Since the MidTerm Week I have been checking for the next lecture set - nothing
And today, for me at least it shows up...when it is due
Befuddled
UserIdTAG: 504031
UserNameTAG: Lindy7
CreateTimeTAG: 2013-03-20T22:52:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: It's due today
FirstChildUserIdTAG: 1288995
FirstChildUserNameTAG: olsolis
FirstChildCreateTimeTAG: 2013-03-20T23:16:38Z
FirstChildVoteTAG: 0
FirstChildTAG: You still have 30 minutes, technically.
I think you got confused because the Week4 Lecture Set was put together with the Midterm - and you missed that. I'm sorry to hear that, but I can assure you, those lectures *have* been up for a week.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T23:22:27Z
FirstChildVoteTAG: 0
SecondChildTAG: That was sort of confusing by the way... Many of us saw Midterm at the bottom of the screen and thought nothing had been posted after that.
I had to run to complete today's exercise sets.
A suggestion would be to continue posting the exercises/exams in chronological order; thinking about whether stuff is in the right order just adds unnecessary confusion...IMHO
SecondChildUserIdTAG: 1288995
SecondChildUserNameTAG: olsolis
SecondChildCreateTimeTAG: 2013-03-20T23:27:17Z
SecondChildVoteTAG: 0
IndexTAG: 502
TitleTAG: FINAL EXAMS
I think it will be a good idea to have the final exams over a weekend - saturday - sunday. It is difficult coming back from work after a hard days and job with just a few hours left to the timeline, to rush an exam. I am assuming more people will be free or have more time for themselves on those days. Any one doing the statistics on this assumption?
UserIdTAG: 909938
UserNameTAG: AOmokhua
CreateTimeTAG: 2013-03-20T22:45:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You can distribute the exam over all the 72-hour period. 30 minutes one day, 30 another, 30 again the 3rd...and you should've got enough time :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T23:00:23Z
FirstChildVoteTAG: 1
SecondChildTAG: Great Idea...
SecondChildUserIdTAG: 1302597
SecondChildUserNameTAG: neha_kaur
SecondChildCreateTimeTAG: 2013-03-20T23:01:07Z
SecondChildVoteTAG: 0
IndexTAG: 503
TitleTAG: Just joined
Dear Prof. A.
I've joined the class yesterday, will I be able to catch up with what you went over till the moment and take the exam. Thanks
UserIdTAG: 1453959
UserNameTAG: atheeralattar
CreateTimeTAG: 2013-03-20T22:45:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You are going to do four week's works in one week!? Superman. You must be an outlier :)
FirstChildUserIdTAG: 584390
FirstChildUserNameTAG: pluribus
FirstChildCreateTimeTAG: 2013-03-20T23:04:55Z
FirstChildVoteTAG: 1
FirstChildTAG: At this point, you still technically can, but you'll need to ace both ES12 and the Final to get to the minimum 35% passing grade. Although there's still about 50 minutes to do ES 9,10 and 11, so you could rush them :D
That said, you can still follow the course as a learning experience and don't worry too much about the grade. It will be immensely useful once Stat2.2x starts ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T23:07:38Z
FirstChildVoteTAG: 0
IndexTAG: 504
TitleTAG: Having some trouble grasping which of my non algebraic numbers is the intercept
I got the intercept question wrong but my calcs get the y estimates right. After the deadline tonight maybe we can have some clarification. I haven't practiced algebra in 30 years ... a little rusty simplifying formulas. Thanks
UserIdTAG: 945143
UserNameTAG: joddde
CreateTimeTAG: 2013-03-20T21:40:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Check this out:
[http://www.purplemath.com/modules/strtlneq.htm][1]
[1]: http://www.purplemath.com/modules/strtlneq.htm
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-20T22:12:07Z
FirstChildVoteTAG: 1
IndexTAG: 505
TitleTAG: [Week 5 lectures do not appear]
So, basically that´s it, Lectures from week 5 do not apper, all the course info is gone, the exercises for week 5 are not there either....
Or is it that Prof. A. is kind enough to give us a break before the exam....
Regards
UserIdTAG: 962810
UserNameTAG: victordoors
CreateTimeTAG: 2013-03-20T21:39:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The lectures and exercises are now available.
FirstChildUserIdTAG: 335630
FirstChildUserNameTAG: rjmarks
FirstChildCreateTimeTAG: 2013-03-20T22:12:50Z
FirstChildVoteTAG: 0
FirstChildTAG: The Prof has commented on the Course Info problem. It is a technical issue that edX is working on.
The week 5 lectures have been posted.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T22:14:33Z
FirstChildVoteTAG: 0
FirstChildTAG: Yeah, everything is hunky dory now, thanks
FirstChildUserIdTAG: 962810
FirstChildUserNameTAG: victordoors
FirstChildCreateTimeTAG: 2013-03-21T13:00:06Z
FirstChildVoteTAG: 0
IndexTAG: 506
TitleTAG: Problem 2A
Is the slope supposed to be 0.833 mm per gram? I had that first but none of the radio button showed that. The closest was 0.833 inches per gram (- is that the correct answer?) Because of that, I inverted the x with y, thinking that perhaps I got it wrong so that it'll be 0.675 gram per mm. It now doesn't allow me to re-select. :(
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T21:37:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: The calculation was write but you got the units wrong.
FirstChildUserIdTAG: 1044317
FirstChildUserNameTAG: Mlaknin
FirstChildCreateTimeTAG: 2013-03-20T22:09:02Z
FirstChildVoteTAG: 0
IndexTAG: 507
TitleTAG: Checky,
Learnt my lesson from Q2.0. Read carefully. Thanks for P3 :-)
UserIdTAG: 1071395
UserNameTAG: lewendon
CreateTimeTAG: 2013-03-20T21:23:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: ditto!
FirstChildUserIdTAG: 961272
FirstChildUserNameTAG: CuriousCatastrophe
FirstChildCreateTimeTAG: 2013-03-23T18:59:23Z
FirstChildVoteTAG: 0
IndexTAG: 508
TitleTAG: EDX Bug?: Allows blank answer submissions and counts as incorrect
Is this an EDX bug or a configuration option you have set in this course? If a bug, I will file it to bugs@edx.org (https://www.edx.org/contact). Thanks!
Scenario:
I accidentally clicked "submit" for answer 2c when I meant to click the "submit" button for 2b. However, I hadn't yet put an answer for 2c.
Steps to reproduce:
1) Leave an answer blank
2) Click submit
Expected Outcome:
Answer is not submitted, prompt appears letting you know that you forgot to fill in the answer.
Actual outcome:
Although the answer box is blank, it still submits. It then treated blank as an incorrect answer, and I lost one of my submission chances. (Would have been even worse if it had been a question with only 1 submission chance)
UserIdTAG: 162716
UserNameTAG: nathanleiby
CreateTimeTAG: 2013-03-20T21:21:35Z
VoteTAG: 1
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: > Actual outcome: Although the answer box is blank, it still submits. It then treated blank as an incorrect answer, and I lost one of my submission chances. (Would have been even worse if it had been a question with only 1 submission chance)
This is what many others have found (another course), so I assume it is how the system works.
A request to the tech people for a warning message if you haven't filled in a box might be in order. I know others have requested this feature.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T22:09:26Z
FirstChildVoteTAG: 0
SecondChildTAG: That would be good; I put NA as the answer in one of the earlier problems and it responded something like 'NA isn't a number'. Was nice because it didn't decrease my submit count, and I then got the correct answer. (although maybe it *should* have decreased the count; NA wasn't a correct answer... :)
But a blank answer should always be rejected without lowering the submit count.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T22:18:21Z
SecondChildVoteTAG: 0
IndexTAG: 509
TitleTAG: Diagrams do not show on my computer
Dear All,
I have a problem with the interactive diagrams in the textbook - they do not show on my komputer - all the page is visible. the box is visible but it is empty inside - for the normal distribution I got anly the sliders and numbers but for the scatters the box is empty. I have tried three browsers - Firefox, Internet Explorer 32 bit and 64 bit - all the same. I have reinstalled java and opened al the firewalls, ad blockers - no joy. Is anyone sharing the same problem? I was able to do the tests, but before the final I would like to be able to read do all the additional material....
I will be grateful for any suggestions how to get the diagrams running.
Anna from Poland
UserIdTAG: 993040
UserNameTAG: AnnaHarper
CreateTimeTAG: 2013-03-20T21:17:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I believe edX was developed to run optimally on Chrome / Chromium, so I would suggest trying one of those. I use Chromium (on Ubuntu) and have no problems.
FirstChildUserIdTAG: 1143958
FirstChildUserNameTAG: Syreh
FirstChildCreateTimeTAG: 2013-03-20T21:18:54Z
FirstChildVoteTAG: 0
SecondChildTAG: I have just tried Chrome - no joy! it is the same. I have to mention it is the same at my computer at work.
SecondChildUserIdTAG: 993040
SecondChildUserNameTAG: AnnaHarper
SecondChildCreateTimeTAG: 2013-03-20T21:24:24Z
SecondChildVoteTAG: 0
SecondChildTAG: And I do not want to change to Linux just for the sake of seeing the diagrams.
SecondChildUserIdTAG: 993040
SecondChildUserNameTAG: AnnaHarper
SecondChildCreateTimeTAG: 2013-03-20T21:25:46Z
SecondChildVoteTAG: 0
SecondChildTAG: That's strange. I'm not sure what else to suggest then.
SecondChildUserIdTAG: 1143958
SecondChildUserNameTAG: Syreh
SecondChildCreateTimeTAG: 2013-03-20T21:49:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Check [this][1] out. The last section in particular, will probably help you ;)
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/fixing-normal-curve-applet/
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-20T22:43:09Z
SecondChildVoteTAG: 0
IndexTAG: 510
TitleTAG: Confused on Problem 2: HELP!!!!!
I understand the data, and made a table, but now I am really lost.
>The correlation between the number of right answers and the number of wrong answers is _________________.
What does that mean? What type of answer do they want? a decimal? Of what? Please explain!
Same with problem B!
UserIdTAG: 484877
UserNameTAG: Andre97
CreateTimeTAG: 2013-03-20T20:48:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: Did you look at the discussion on the page with the problem...? I don't really know what the answer is, but I think some people there have a better idea...check it and see. I guessed the answer and got it wrong! :(
FirstChildUserIdTAG: 1280049
FirstChildUserNameTAG: MissBehave
FirstChildCreateTimeTAG: 2013-03-20T20:51:02Z
FirstChildVoteTAG: 0
SecondChildTAG: It's a number. An integer, even :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-20T20:58:02Z
SecondChildVoteTAG: 0
SecondChildTAG: While you CAN make a table to actually calculate the correlation, it can be guessed intuitively too. To give you a hint, think of the equation between the number of right answers and number of wrong answers. This equation would give you an idea of the relationship they share. Another hint is the part in the lecture where Prof. A mentions "The limits of +1 and -1 represent perfectly linear relationships between the variables".
SecondChildUserIdTAG: 21672
SecondChildUserNameTAG: rahsin
SecondChildCreateTimeTAG: 2013-03-20T21:15:59Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks rashin. you are good with words. if you know what i mean. :)
SecondChildUserIdTAG: 1117998
SecondChildUserNameTAG: ashutoshpathak
SecondChildCreateTimeTAG: 2013-03-20T23:31:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Maybe this dicussion will help? https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_9/threads/5149e12d1acaa6ef0000011e
FirstChildUserIdTAG: 1143958
FirstChildUserNameTAG: Syreh
FirstChildCreateTimeTAG: 2013-03-20T21:21:22Z
FirstChildVoteTAG: 0
IndexTAG: 511
TitleTAG: Could you imagine I failed Problem 3?
Hahahaha, just kidding. The best question so far. I wish we had questions like this for all exercise sets. In fact it is the only answer I got in this set
UserIdTAG: 585153
UserNameTAG: princelobga
CreateTimeTAG: 2013-03-20T20:44:38Z
VoteTAG: 4
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: me too! :/
FirstChildUserIdTAG: 923593
FirstChildUserNameTAG: SaraMB
FirstChildCreateTimeTAG: 2013-03-20T21:15:13Z
FirstChildVoteTAG: 0
SecondChildTAG: i failed the question in the exercise 11, the one they give you away as a gift ... because i didn´t read it well ..... jajajajajaja ... i couldn´t stop laughing
SecondChildUserIdTAG: 1166847
SecondChildUserNameTAG: Jriveraespejo
SecondChildCreateTimeTAG: 2013-03-20T22:27:58Z
SecondChildVoteTAG: 0
FirstChildTAG: I am taking a screen shot of this question to keep. I hope this does not violate the honor code.
Chris - Atlanta GA
FirstChildUserIdTAG: 144628
FirstChildUserNameTAG: ChrisKohanek
FirstChildCreateTimeTAG: 2013-03-20T23:13:34Z
FirstChildVoteTAG: 0
SecondChildTAG: As long as you don't post that screenshot here within the next 30 minutes, it doesn't :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-20T23:23:13Z
SecondChildVoteTAG: 0
IndexTAG: 512
TitleTAG: The two most needed points
Thanks for your polite two points. Without them I would lost the course.
UserIdTAG: 1240706
UserNameTAG: remipole
CreateTimeTAG: 2013-03-20T20:42:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 513
TitleTAG: To staff - I would appreciate supplement materials
For those who have the necessary mathematical tools to understand, please provide a proof for why "c is the one that makes the smallest error" (and other things that will need a proof in the future). I really appreciated the supplement material for sections 3 and 4 so please keep on doing that.
UserIdTAG: 104367
UserNameTAG: the_eraser
CreateTimeTAG: 2013-03-20T20:40:01Z
VoteTAG: 1
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 0
IndexTAG: 514
TitleTAG: Course info page
It appears empty, which was not the case a few days ago: no news visible. Please correct. Thanks.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T20:36:38Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 515
TitleTAG: Minor point
Grams are not a unit of weight, but a unit of mass. A 6 gram chick weighs .0588 Newtons.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T20:15:04Z
VoteTAG: 6
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: True, but I'm pretty sure we won't be launching chicks into space any time soon in this course, so I'm sure we can use the "common use" version of the gram xD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T21:00:58Z
FirstChildVoteTAG: 6
FirstChildTAG: Anonymous posts are always such a welcome light relief.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T23:20:00Z
FirstChildVoteTAG: 0
SecondChildTAG: They can't compete with Problem 3 :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-20T23:24:12Z
SecondChildVoteTAG: 0
IndexTAG: 516
TitleTAG: My 35%
finally i got my 35%. its really a heavy week for me but it paid up...
UserIdTAG: 1193006
UserNameTAG: makmursp
CreateTimeTAG: 2013-03-20T20:01:26Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Congrats :) I've got 54%
FirstChildUserIdTAG: 1053569
FirstChildUserNameTAG: nicola2003
FirstChildCreateTimeTAG: 2013-03-20T23:18:18Z
FirstChildVoteTAG: 0
SecondChildTAG: If we are above 35%, does that mean we have automatically passed even without the final exercise set and final exam score? In other words, is it 35% total to pass, or do we need to pass both the homework and the exams separately.
That's my understanding, but I haven't actually seen it stated explicitly.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-03-20T23:53:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh, and congrats to both.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-03-20T23:53:52Z
SecondChildVoteTAG: 0
FirstChildTAG: > In other words, is it 35% total to pass, or do we need to pass both the homework and the exams separately. That's my understanding, but I haven't actually seen it stated explicitly.
From the course policies:
>Certificates of completion will be awarded to those who score 35% or higher overall.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T02:28:38Z
FirstChildVoteTAG: 0
IndexTAG: 517
TitleTAG: 1A
please explain me how it is not linear?
it is more log than linear for me I see it clearly, and I sow it clearly while marking my answer but that does not change fact that it is linear, am I wrong?
I'm really annoyed by getting this answer wrong.
Could someone explain me that?
UserIdTAG: 1202138
UserNameTAG: szuetam
CreateTimeTAG: 2013-03-20T19:59:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: so is it a log or linear? you decide
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-20T20:18:37Z
FirstChildVoteTAG: 0
FirstChildTAG: We're not past due date, so we can't discuss it too openly yet. But I'd like to point out a couple things you said.
> it is more log than linear for me I see it clearly
Then why the heck would you say it is linear if you "see" that it's a log?
> I saw it clearly while marking my answer but that does not change fact that it is linear.
Yes it does! If you think it's a logarithmic *curve*, then it **can't** be linear! And if you think it's linear, then it can't be a log curve. The two *are* mutually exclusive.
Unless we are using different definitions for "linear". What's yours?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T20:21:06Z
FirstChildVoteTAG: 1
SecondChildTAG: I am really wondering what some think "linear" means.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-20T22:52:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Plotting the data, and trying to fit a line that runs through the centre.
![enter image description here][1]
As you noted, there is a curve. So try logging (as you suggested) and then putting a line through.
![enter image description here][2]
Much better. You didn't need to do this. Just eyeballing the graph should have told you that the plot was not linear. There was an obvious curve, so perhaps linear regression would not be appropriate. This week's lectures look at residual diagnostics.
However, if you *had* fitted a linear regression model (to the unlogged data) the residuals would look like this:
![enter image description here][3]
Not good.
The data I used might not be the exact same as the question, but it looks pretty close.
[1]: https://edxuploads.s3.amazonaws.com/13638292121343601.png
[2]: https://edxuploads.s3.amazonaws.com/13638292791343607.png
[3]: https://edxuploads.s3.amazonaws.com/13638298822550792.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-21T01:33:21Z
FirstChildVoteTAG: 1
IndexTAG: 518
TitleTAG: Great book on this phenomenon
In case any of you have the time and the interest, I highly recommend a book called Outliers (http://www.amazon.com/Outliers-Story-Success-Malcolm-Gladwell/dp/0316017930/ref=sr_1_1?ie=UTF8&qid=1363809403&sr=8-1&keywords=outliers). It gives great examples of regression to the mean and other statistical phenomena, taken from real life and written for the layman. No equations of any kind, as far as I can recall. It made an enjoyable read and I couldn't put it down and finished it in one day. Enjoy!!!!
UserIdTAG: 937396
UserNameTAG: m2foster
CreateTimeTAG: 2013-03-20T19:58:57Z
VoteTAG: 1
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.3: Regression effect, Galton, and the regression fallacy
NumberOfReplyTAG: 1
FirstChildTAG: Thank you for the hint!
I found an pdf copy in case anyone has the same problems with Amazon (their shipping to my country is pretty much expensive and takes a lot of time, thanks to our snail-mail)
http://247best.weebly.com/uploads/5/5/2/4/5524897/gladwell_malcolm_-_outliers_the_story_of_success.pdf
FirstChildUserIdTAG: 1111798
FirstChildUserNameTAG: kammolch
FirstChildCreateTimeTAG: 2013-03-20T20:08:21Z
FirstChildVoteTAG: 1
IndexTAG: 519
TitleTAG: "Intercept" not present in SticiGui Glossary of Statistical Terms
I was trying to work out these equations in my own language and wanted to check my understanding of the concept of the intercept in the glossary, but that term is not there, either as intercept, x-intercept, or y-intercept.
If I understand this correctly, in the conversion of degrees Centigrade to degrees Fahrenheit, 1.8 (or 9/5) is the slope and 32 degrees Fahrenheit is the intercept. Is that correct?
UserIdTAG: 914245
UserNameTAG: dbaPlanB
CreateTimeTAG: 2013-03-20T19:57:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Yes, it is.
In general, for an equation in the form $m*x+c$, *m* is the slope, and *c* is the intercept.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T20:24:10Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks! I think that the temperature conversion will help me remember the equation of the regression and vice-versa.
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-03-20T20:45:29Z
SecondChildVoteTAG: 0
IndexTAG: 520
TitleTAG: To Prof A
I know this is a stupid question, but still want to know.
If someone gets Zero(0)or did not attend in two tests, will that student get the accomplishment certificate if s/he gets more than 50% on average.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T19:57:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: You need 35%+ for you total average to get the certificate. That's the only requisite.
One could, in theory, start the course tomorrow, with 0 in ES1 to 11, and the midterm, then do perfectly in ES12 and the Final, and s/he would still get the certificate(30% from the final+5% from ES12).
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T20:28:12Z
FirstChildVoteTAG: 2
IndexTAG: 521
TitleTAG: A suggestion for the syllabus...next time
It would be nice, in the future, to have the assigned/suggested reading from the textbook linked on the syllabus with the appropriate lectures. That would give us a bit more flexibility in our studies.
I watch the lectures, go to the practice exercises which then sends me to the textbook, before proceeding to the exercise set. I understand not wanting to publish the exercise sets but at least allow us to move a bit more freely through the material.
Thanks for the excellent content in this course.
UserIdTAG: 1231585
UserNameTAG: JDBower
CreateTimeTAG: 2013-03-20T19:54:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 522
TitleTAG: To our Instructor(Prof A)
If someone gets Zero(0)or did not attend in two tests, will that student get the accomplishment certificate if s/he gets more than 50%.
UserIdTAG: 1111783
UserNameTAG: irfans011
CreateTimeTAG: 2013-03-20T19:53:24Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 11 / Reading and Practice for Exercise set 11
NumberOfReplyTAG: 0
IndexTAG: 523
TitleTAG: problem 3
after clicking both options, i got a green tick but no marks were given in progress
it isnt fair
Was I punished for being sincere,
i appreciate the course hugely but if u ask me if i am happy to sail thro midterm and happy that part 1 is getting over that is so true i would click yes otherwise also so why not given the points for it
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T19:41:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: If you got the green tick, then you should have gotten the points on the Progress page as well. Try refreshing the Progress page.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-20T19:43:09Z
FirstChildVoteTAG: 0
FirstChildTAG: Don't worry, sometimes it takes a while for your score to be reflected, even if you do refresh right away it might not show up for a few hours sometimes.
FirstChildUserIdTAG: 867437
FirstChildUserNameTAG: Ellyn
FirstChildCreateTimeTAG: 2013-03-20T21:30:47Z
FirstChildVoteTAG: 0
IndexTAG: 524
TitleTAG: What's X and what is Y?
Is anyone else having a problem where it feels like they're ending up with mean of *y* and mean of *x* switched in their formula by accident? *x* is the number you already have, and *y* is the number you are looking for. Which means mean of *y* should be the mean of whichever value you are hoping to find the estimate for. But whenever I feel like I am doing this correctly, the exercises keep telling me to switch it around. Is it just me, or is it unclear whether wives or husbands are on the *x* or *y* axis? When they list the data (x,y) is the first piece of data the husband's data? They called the chart wives vs husbands, so I thought wives would be on the *x* axis. If anyone else is having this kind of trouble, let me know! I'm pretty baffled, since it's the only place in the substitution where I'm getting caught at this point.
UserIdTAG: 1180501
UserNameTAG: apolubi
CreateTimeTAG: 2013-03-20T19:04:02Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 11 / Reading and Practice for Exercise set 11
NumberOfReplyTAG: 1
FirstChildTAG: You are not the only one having trouble with the text book exercises! In general, I prefer Prof. A's way of explaining things and find that the textbook explanations confuse me, even when I try to work through problems with the solutions showing. I think it's great that this teaching pair gives us a choice of presentations. I don't think I'd have gotten past week 1 were it not for Prof. A's lectures and explanations.
The class lectures give us everything we need to succeed in the quiz. In my opinion, of course.
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-20T20:26:55Z
FirstChildVoteTAG: 0
IndexTAG: 525
TitleTAG: [staff] Get 37% in TOTAL but missed the MIDTERM.
I get 36% in TOTAL but missed the MIDTERM... am i still get the certificate?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T18:59:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Yes.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T20:29:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, the is no problem
FirstChildUserIdTAG: 1180593
FirstChildUserNameTAG: CARLOSJAV
FirstChildCreateTimeTAG: 2013-03-20T20:58:41Z
FirstChildVoteTAG: 0
IndexTAG: 526
TitleTAG: Am I late to get the certificate (I´ll start on march 21)?
Hi, I would like to joint this tomorrow, but I realized that I am in late.
I already know that grades will be calculated as follow:
Exercise Sets: 50%
Midterm: 20%
Final exam: 30%
But can I catch the certificate if Exercise Sets and Exames are due at specified dates and times?
Thanks a lot,
Filippo
UserIdTAG: 1435893
UserNameTAG: filippoloverre
CreateTimeTAG: 2013-03-20T18:58:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hi Filippo,
technically you can still catch it.
If you ace the final (and get all 30%) plus the final set just about to be released (5% more), you get a passing grade. And if you manage to ace them both, that pretty much shows that you understood enough to have the certificate awarded :)
If you decide you want to give it a shot, you'll either need a good background in statistics, or spend a significant amount of time (like 30-50 hours) to go through everything.
One thing to consider: sets 9 to 11 are still open till 11.30pm GMT March 20th, so you might want to click through them to make some guesses and get some points in advance before you go for the finals. (e.g. last question in set 11 gives some easy points)
Good luck!
--
Gábor
FirstChildUserIdTAG: 485563
FirstChildUserNameTAG: gaborsomogyi
FirstChildCreateTimeTAG: 2013-03-20T19:33:08Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks for the reply.
"edx" is an excellent service.
I'll definitely try, although it would certainly be interesting to find a way to undo the courses by the time factor.
Concerning this I think that you may consider an on demand development/service.
Like the way we download movies with iTunes, we are not talking about cinema. :)
What do you think?
Sincerly,
Filippo
FirstChildUserIdTAG: 1435893
FirstChildUserNameTAG: filippoloverre
FirstChildCreateTimeTAG: 2013-03-20T20:38:02Z
FirstChildVoteTAG: 0
SecondChildTAG: you can watch the videos lectures on this site and do the exercises whenever you want, you just won't get anything for it. besides knowledge, of course.
SecondChildUserIdTAG: 1326696
SecondChildUserNameTAG: Maxkim
SecondChildCreateTimeTAG: 2013-03-20T22:57:43Z
SecondChildVoteTAG: 0
IndexTAG: 527
TitleTAG: Week 5
Has week 5 not been posted yet?
UserIdTAG: 1106649
UserNameTAG: skoules
CreateTimeTAG: 2013-03-20T18:50:02Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I can't see it either. Was hoping to get a portion done tonight as a procrastination activity for something more pressing ; )
FirstChildUserIdTAG: 1072347
FirstChildUserNameTAG: rizdin
FirstChildCreateTimeTAG: 2013-03-20T19:29:24Z
FirstChildVoteTAG: 1
FirstChildTAG: It is now 1925 GMT and I have nothing - and no-one on the staff seems to care enough to explain why it is over 12 hours late. Can we expect better service for the Finals? it is not a level playing field if some folks get (in effect) extra time.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-20T20:25:03Z
FirstChildVoteTAG: 0
IndexTAG: 528
TitleTAG: 1a, problem in question?
It says that **One of the students is on the 70th percentile of the final.** So, doesn't it mean that we actually need to look at the problem the other way around (axis wise) the invert of the slope?
Perhaps I'm wrong, and in that case, I'm confused.
UserIdTAG: 955096
UserNameTAG: yoav_v
CreateTimeTAG: 2013-03-20T18:42:17Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 3
FirstChildTAG: think back to the normal curve. this one confused me until i skipped back in my notes.
FirstChildUserIdTAG: 1277876
FirstChildUserNameTAG: AmandaMUK
FirstChildCreateTimeTAG: 2013-03-20T19:54:40Z
FirstChildVoteTAG: 0
FirstChildTAG: OK - Here's my initial response:
"I'm with yoav.
In fact, so is 1b.
Look at the listed "correct" answer for 1a. Compare that to the question in 1b.
The "correct" answers for both 1a and 1b cannot *both* be true.
If 1a were true, then 1b would have a different answer. If 1b were true, and the answer to 1a were true, then 1a would have to have a different starting point (final score)."
Upon further review, r is a correlation, which is to say a CO-relation. Each is related to the other in the same way.
Since we are estimating, we are guessing closer to the middle to reduce error. If a data point is above average (let alone high above), we're not assuming the same magnitude (unless r = 1 or -1) for our estimate, in order to leave better room for error on either side.
In the real world, the point of using r is to estimate an unknown variable from a known. Other than playing math games, we wouldn't actually continually do this process to estimate y for x and then x again from y and so on. If we were to do so, we would draw closer and closer to the actual average for the data set.
So, yes, 1a can be true and then 1b can be true. If there were a 1c, it would be closer still to 50%.
FirstChildUserIdTAG: 972465
FirstChildUserNameTAG: ToddCioffi
FirstChildCreateTimeTAG: 2013-03-20T21:42:54Z
FirstChildVoteTAG: 2
SecondChildTAG: Also, look at example 9-1. Note that it doesn't matter which is "x" (known) and which is "y" (unknown). The math is the same.
http://statistics.berkeley.edu/~stark/SticiGui/Text/regression.htm#estimation_by_regression_line
SecondChildUserIdTAG: 972465
SecondChildUserNameTAG: ToddCioffi
SecondChildCreateTimeTAG: 2013-03-20T22:27:24Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with yoav_v I think that we should look the problem conversely, to try to find out the percentile in the **midterm**!
FirstChildUserIdTAG: 1069196
FirstChildUserNameTAG: JohaR3
FirstChildCreateTimeTAG: 2013-03-20T21:52:15Z
FirstChildVoteTAG: 0
IndexTAG: 529
TitleTAG: Problem 1B- How many checks?
How many checks do I have to put in Problem 1B in order to get it correct?
UserIdTAG: 941991
UserNameTAG: oxoxo
CreateTimeTAG: 2013-03-20T18:40:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: As many as necessary!
(I'm sorry, I don't want to sound like a jerk, but answering your question *would* give away a good part of the solution.)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T20:33:22Z
FirstChildVoteTAG: 0
SecondChildTAG: I also had an issue with 1B, and got it correct on the second attempt by guessing that the objective 'low' really means 'relatively lower' - I hope I'm not giving too much away.
Note that the graph does not start (on the Y-axis) at zero, so without knowing something extra about what's considered 'low' in SAT terms, the idea of 'low' is mathematically ambiguous.
Hopefully this helps refine the question for the next group of students.
SecondChildUserIdTAG: 81246
SecondChildUserNameTAG: bigbro
SecondChildCreateTimeTAG: 2013-03-20T23:02:04Z
SecondChildVoteTAG: 0
IndexTAG: 530
TitleTAG: "Course Info" no longer displays news\messages
Has anyone else noticed that the "Course Info" section no longer includes any content? When I go to this tab, it's blank except for the "Course Updates & News" title. I used to see the messages that Prof. Adhikari sent out in the main part of the page. On the side there is still the box with the links labeled "Course Handouts".
I'm using Firefox, but I tested it in Chrome with the same results. I'm not sure if this is intentional, a glitch, or something else.
UserIdTAG: 1117422
UserNameTAG: edutainment
CreateTimeTAG: 2013-03-20T18:39:41Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Yes, the section is currently empty. Maybe they are updating it...
FirstChildUserIdTAG: 1237723
FirstChildUserNameTAG: alex326
FirstChildCreateTimeTAG: 2013-03-20T18:50:39Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks for the confirmation - glad it's not just me going crazy ;)
SecondChildUserIdTAG: 1117422
SecondChildUserNameTAG: edutainment
SecondChildCreateTimeTAG: 2013-03-20T19:39:16Z
SecondChildVoteTAG: 0
FirstChildTAG: This morning Prof A. spoke of some problems with the EdX software, so it's likely that the techs are working on that...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T19:01:50Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks for the additional info. Hopefully that's the case and the techs will resolve whatever is ailing the page.
SecondChildUserIdTAG: 1117422
SecondChildUserNameTAG: edutainment
SecondChildCreateTimeTAG: 2013-03-20T19:40:38Z
SecondChildVoteTAG: 0
FirstChildTAG: The Prof has commented on this. It is a technical issue that edX is working on.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T21:01:29Z
FirstChildVoteTAG: 0
IndexTAG: 531
TitleTAG: Availability of material and forum archive
Does anyone know if the course material and forum archive will be available after course is finished?
UserIdTAG: 197621
UserNameTAG: quilombolo
CreateTimeTAG: 2013-03-20T18:33:51Z
VoteTAG: 7
CoursewareTAG: Section 8a: Error in the regression estimate (Lec 8.1 - 8.2) / Lec 8.2: The r.m.s. error of regression; calculations assuming bivariate normal scatter
NumberOfReplyTAG: 1
FirstChildTAG: As far as I know, it will be available.
FirstChildUserIdTAG: 120241
FirstChildUserNameTAG: RomanoLaura
FirstChildCreateTimeTAG: 2013-03-21T05:22:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Are you sure? I mean maybe it's stated somewhere explicitly and I missed that?
SecondChildUserIdTAG: 197621
SecondChildUserNameTAG: quilombolo
SecondChildCreateTimeTAG: 2013-03-21T15:08:42Z
SecondChildVoteTAG: 0
IndexTAG: 532
TitleTAG: ex set 9
am totally blank in this ex. set 9 ...i don't know any of them...tried 3 of them and got all of them wrong and rest, i have no clue...so just leaving this set
UserIdTAG: 1036551
UserNameTAG: Geetagrg
CreateTimeTAG: 2013-03-20T18:15:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 0
IndexTAG: 533
TitleTAG: [staff] what about percentile score..
Progress bar is very good as an overview.
Can we have a percentile score also?
UserIdTAG: 867488
UserNameTAG: mkhaled
CreateTimeTAG: 2013-03-20T18:11:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: touche
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-20T20:25:55Z
FirstChildVoteTAG: 0
IndexTAG: 534
TitleTAG: When will Stat2.2x be opened?
Hello, TAs,
This course Stat2.1x is going to finish in next week.
This course is very interesting and got a lot of new statistics Knowledge. So I am looking forward to register Stat2.2x course, which launch on edX. May I know, when will stat2.2x be opened?
UserIdTAG: 1230887
UserNameTAG: tun2aung
CreateTimeTAG: 2013-03-20T18:10:17Z
VoteTAG: 16
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 535
TitleTAG: wife on X, husband on Y ? or wife on Y, husband on X ?
I drew a guessplot (scatterplot based on guessing data - my terminology; not a real term...) for question 3. plotted a few points of (guessed) married friends ages, relatives, etc.
Based on the wording of the question, which should be on the X axis, and which on Y?
> Which of the following do you think is true *regarding the association between wife’s age and husband*’s age?
Wife on X, husband on Y? Or wife on Y, husband on X?
UserIdTAG: 459910
UserNameTAG: AlanJayWeiner
CreateTimeTAG: 2013-03-20T18:00:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: Try both options out on paper. I found I understood the question better when I did so, and the answer became very clear.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-20T18:06:46Z
FirstChildVoteTAG: 1
SecondChildTAG: yup - should've realized that!
thanks!
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T19:33:12Z
SecondChildVoteTAG: 0
FirstChildTAG: Does a positive association ever become negative, or vice-versa, when you swap the axes of a guessplot?
FirstChildUserIdTAG: 1367426
FirstChildUserNameTAG: Ribreceptor
FirstChildCreateTimeTAG: 2013-03-20T18:09:12Z
FirstChildVoteTAG: 2
SecondChildTAG: oh, I hate it when the answer is obvious! :)
(banging head on keyboard...)
Thanks!
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T19:32:38Z
SecondChildVoteTAG: 0
IndexTAG: 536
TitleTAG: [STAFF] Why cant a football diagram have a regression line angle > 45 degrees?
Hello,
Can someone please help me understand this:
When a football diagram in plotted in normalized units, why cant the football major axis and consequently the regression line have a steep angle i.e. >> 45 but < 90?
Thanks in advance for your help.
Mario
UserIdTAG: 898917
UserNameTAG: MarioPinto
CreateTimeTAG: 2013-03-20T17:53:29Z
VoteTAG: 5
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 4
FirstChildTAG: I was wondering about the same thing. Looking forward to some answers...
FirstChildUserIdTAG: 1116038
FirstChildUserNameTAG: UrosKovac
FirstChildCreateTimeTAG: 2013-03-20T18:23:15Z
FirstChildVoteTAG: 1
FirstChildTAG: Because the slope of the regression line is $r$ when plotted in standard units, this is equivalent to asking why we cannot have $r > 1$. When she went through the computation of $r$ in lecture, Adhikari said "Trust me."
Intuitively, a perfect linear positive association earns $r = 1$, and there's no stronger correlation than a perfect line. Hence, no steeper than $45^\circ$.
A slightly deeper intuition is that estimates based on $0 < r < 1$ exhibit regression toward the mean, an effect of random variation. Estimates based on $r=1$ would not exhibit regression toward the mean, but there's no such thing as progression *from* the mean!
FirstChildUserIdTAG: 1367426
FirstChildUserNameTAG: Ribreceptor
FirstChildCreateTimeTAG: 2013-03-20T18:35:07Z
FirstChildVoteTAG: 4
SecondChildTAG: This leads to the second question. Why does r represent the slope? if this is proved then my question would be answered. I looking for a qualitative explanation if possible. Or maybe I just have to figure out the math.
SecondChildUserIdTAG: 898917
SecondChildUserNameTAG: MarioPinto
SecondChildCreateTimeTAG: 2013-03-21T02:00:47Z
SecondChildVoteTAG: 0
SecondChildTAG: btw Thanks for responding. :)
SecondChildUserIdTAG: 898917
SecondChildUserNameTAG: MarioPinto
SecondChildCreateTimeTAG: 2013-03-21T02:01:30Z
SecondChildVoteTAG: 0
FirstChildTAG: The slope of the regression line is in general $r \frac{\sigma_y}{\sigma_x}$ and this value can be bigger than 1. So, a regression line can be steeper than $45^{\rm o}$, but not when you are working in standard units.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-20T20:57:40Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks for your answer. I just want to intuitively "see" what you are stating. Let me try to figure out how one could get the slope of the regression line to be r * sigma_y / sigma_x.
SecondChildUserIdTAG: 898917
SecondChildUserNameTAG: MarioPinto
SecondChildCreateTimeTAG: 2013-03-21T02:04:07Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't think its possible to see the intuition since its quite difficult to see intuitively what the Standard Unit does. In particular what happens when we scale the shifted variable (x-mu) by the SD of the variable.
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-03-23T06:48:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Mario,
if you're looking for an algebraic proof that the equation of the regression line is
y_estimate = sigma_y/sigma_x*r*(x-mu_x)+mu_y
have a look at the link posted here:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section7_Lec_7_2/threads/5146d7079d8a021f00000132
FirstChildUserIdTAG: 407687
FirstChildUserNameTAG: AndreaPi
FirstChildCreateTimeTAG: 2013-03-21T10:55:47Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks a ton Andrea!
SecondChildUserIdTAG: 898917
SecondChildUserNameTAG: MarioPinto
SecondChildCreateTimeTAG: 2013-03-21T17:38:55Z
SecondChildVoteTAG: 0
IndexTAG: 537
TitleTAG: Problem 1B
Are we to use only the information given in the question to answer it or should we also look at the plot?
UserIdTAG: 1280049
UserNameTAG: MissBehave
CreateTimeTAG: 2013-03-20T17:45:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: You can look at the plot, and it will probably help you visualize the answer.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-20T19:19:15Z
FirstChildVoteTAG: 0
FirstChildTAG: > Are we to use only the information given in the question to answer it or should we also look at the plot?
You must look at the plot. And at the options. Which ones agree with the plot? Which ones are making claims that cannot be justified by the plot?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T21:03:10Z
FirstChildVoteTAG: 0
IndexTAG: 538
TitleTAG: Thanks....
Really great course, thanks for problem 3.
UserIdTAG: 1013229
UserNameTAG: LorenaNava
CreateTimeTAG: 2013-03-20T17:44:35Z
VoteTAG: 9
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: I also loved problem 3 :d. Great course indeed.
FirstChildUserIdTAG: 1156005
FirstChildUserNameTAG: ioanel
FirstChildCreateTimeTAG: 2013-03-20T19:27:25Z
FirstChildVoteTAG: 3
IndexTAG: 539
TitleTAG: The Voice
Professor Adhikari has a really great spoken voice, one could say she is the Sinatra (or Mel Torme, or Mario Del Monaco, if you want to go lyric) of spoken voices. Her explanations are also very clear, and this is making for a much useful and needed intro to statistics, better than the one I had in my university course. I only regret not having much time to dedicate, I hope I will be able at least to take the final exam.
Waiting eagerly for the next Stat courses !
Thanks a lot
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T17:29:23Z
VoteTAG: 11
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: About Prof. A's voice: I can read English very fluently, but I often find it difficult to understand English mothertongue people when they speak (of course this is not anyone's fault, it's one of my many limitations). But Prof. A. has a very clear pronounciation, and I understand nearly everything she says without looking at the transcrips.
FirstChildUserIdTAG: 1237723
FirstChildUserNameTAG: alex326
FirstChildCreateTimeTAG: 2013-03-20T18:57:04Z
FirstChildVoteTAG: 2
IndexTAG: 540
TitleTAG: Not understanding Problem 3, use of 'association'
So, I'm a little bit confused, because as far as I understand, a negative association would essentially be a negative slope on the graph. No? Then assuming that, drawing a graph where you're assuming that wives tend to be younger than husbands you'd have a positive slope. I suppose that answer could just be wrong. So I went with older than their wives, because that's just another way of saying it. Am I misunderstanding the meaning of 'association' in this context? Waiting for the explanations to come out...
UserIdTAG: 1040596
UserNameTAG: AnneD
CreateTimeTAG: 2013-03-20T17:24:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Try drawing a scatterplot - wife's age on the vertical (Y), husband's on the horizontal (X). Plot a few points based on guessing; approximate ages of a few married friends, relatives, etc. Exact ages won't matter. You should see the answer quickly.
(for what it's worth, I was going to pick the wrong answer initially, then my guess-plot showed me the correct answer)
*Hey! I just invented a new term! (or did I???) Put me down in history as the creator of **guessplot** - a scatterplot based on guessed (or estimated) data which shows useful real information!* I'm famous; I can quit now... :)
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-20T17:55:53Z
FirstChildVoteTAG: 3
IndexTAG: 541
TitleTAG: Just collected my 10 points
Hie everyone? How are you finding this so far? For the first time in this Course I've just collected all the points.
UserIdTAG: 1258683
UserNameTAG: Tshuxx
CreateTimeTAG: 2013-03-20T17:23:01Z
VoteTAG: 2
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: I'ts my 3d time so far that i am getting 100 %, hope to do the same with the last exercise :)
FirstChildUserIdTAG: 1247915
FirstChildUserNameTAG: Iliri2013
FirstChildCreateTimeTAG: 2013-03-20T18:15:13Z
FirstChildVoteTAG: 0
SecondChildTAG: can you tell me the 1c answer as detail, i am confused.thank you.
SecondChildUserIdTAG: 1031881
SecondChildUserNameTAG: 19850524
SecondChildCreateTimeTAG: 2013-03-22T02:55:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Same with me. I got 100% for this Ex Set 10. This is my first time too!
FirstChildUserIdTAG: 941991
FirstChildUserNameTAG: oxoxo
FirstChildCreateTimeTAG: 2013-03-20T19:36:29Z
FirstChildVoteTAG: 0
IndexTAG: 542
TitleTAG: Credit Hours for CPA's
Hello Professor Ann and Staff,
I am a CPA and enrolled this course to refresh my Statistics knowledge from college so that I can apply it at my current job field, which is in model validation. So far it has been interesting and has helped me go through a lot of subjects in an organized way. I would like to include this course as part of my CPA license renewal process and since I don't see Berkeley X registered as a NASBA sponsor, I would need you to provide an estimate of the hours that this course takes so that I can use them to register them with NASBA in my next renewal. I would also need that you could help me to sustain or determine whether all the scoring requirements before weighting to arrive at the 35% are at least 70%, since it will be something that I need to prove to NASBA. What I mean is since all the scores for the exercises are weighted at 50%, the midterm at 20% and the final at 30%, they should probably acquaint for the 70% required by NASBA, but I'm not quite sure how to prove that.
I will appreciate your answer.
Best Regards,
Danilisse.
UserIdTAG: 1067880
UserNameTAG: dpadilla
CreateTimeTAG: 2013-03-20T17:15:48Z
VoteTAG: 5
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.4: Equation of the regression line
NumberOfReplyTAG: 0
IndexTAG: 543
TitleTAG: Dropping the lowest Exercise Set.
I would like to have a vote for all those who are in favor of dropping the lowest exercise set. I know some of us had bad days, or forgot the GMT time due date and would like an opportunity to save grace. Please vote yes!!
UserIdTAG: 2625
UserNameTAG: Shalini
CreateTimeTAG: 2013-03-20T17:13:41Z
VoteTAG: 2
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: The 2 lowest exercise sets are automatically dropped. That's built into the grading system. If you look at your Progress page, you'll see a little 'x' beneath the 2 exercise sets that will not count towards your grade.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-20T17:15:48Z
FirstChildVoteTAG: 8
SecondChildTAG: I have one already dropped, check for the x!
SecondChildUserIdTAG: 1247915
SecondChildUserNameTAG: Iliri2013
SecondChildCreateTimeTAG: 2013-03-20T18:17:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Oh wow!!! I didn't notice that before because I did not finish the last exercise. Once I did, I saw the x beneath my lowest grade! This is great! Thanks for pointing it out.
FirstChildUserIdTAG: 2625
FirstChildUserNameTAG: Shalini
FirstChildCreateTimeTAG: 2013-03-20T21:25:14Z
FirstChildVoteTAG: 0
IndexTAG: 544
TitleTAG: Printable Version of Text Book?
Sorry if this is a repeat message. (And it's not just about ES1 but I can't figure out how to post generally rather than to one of the sections.)
I tried to print one of the first sections of the text book to .pdf and the histogram jumped to another place covering the text. So I haven't tried to print other sections. I have trouble sitting at the computer for long periods so I've been avoiding the text book except to try specific exercises.
Does anyone know if there is a printable version of the textbook available? With the final exam approaching, I think it's time (okay, long overdue) that I reviewed the selected readings.
Thanks!
UserIdTAG: 1252523
UserNameTAG: Willabe
CreateTimeTAG: 2013-03-20T17:04:16Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 545
TitleTAG: LOL
you got me on the last one ahahah
too tired after work and homework
P
UserIdTAG: 7870
UserNameTAG: ppizzine
CreateTimeTAG: 2013-03-20T16:51:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 546
TitleTAG: How to transform regression line equation in term of slope and intercept?
Could anyone please explain step by step the transformation in term of slope and intercept? I'm completely lost at the moment.
![enter image description here][1]
[1]: http://i.imgur.com/3fNwrlr.png
UserIdTAG: 498723
UserNameTAG: YLTO
CreateTimeTAG: 2013-03-20T16:33:12Z
VoteTAG: 2
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.4: Equation of the regression line
NumberOfReplyTAG: 2
FirstChildTAG: I'll try it.
That's because a line has the mathematics expression: y = mX + b.
When X=0, then y=b. That's the point: (0,b) which intercepts the vertical axis.
On the other hand, m is the slope of the line: how much you run up on the vertical axis when you run a step on the horizontal axis (to the right or to the left). You can imagine little triangles every time you move on the line. One step to the right or to the left (X) is a move up (y). So m is the tangent: (y/x)
Try to find explanations about lines. I think that would help you better.
Did it help?
FirstChildUserIdTAG: 918956
FirstChildUserNameTAG: a-per
FirstChildCreateTimeTAG: 2013-03-20T17:29:03Z
FirstChildVoteTAG: 2
SecondChildTAG: Nicely done!
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-03-20T20:35:08Z
SecondChildVoteTAG: 0
FirstChildTAG: In standard units,
$y_{std} = r\cdot x_{std}$
So $r$ is the slope and the intercept is $0$. That's when $x$ and $y$ are expressed in standard units. All the rest of the math on the slide is concerned with substituting the variables in their native units.
Since a value in standard units is defined as how many standard deviations it is above its mean, you can readily convert to and from meaningful physical units:
$x_{std} = \frac{x-\mu_x}{\sigma_x}$
$y_{std} = \frac{y-\mu_y}{\sigma_y}$
Because we would like to deal in physically meaningful units, let's use these definitions to replace $y_{std}$ and $x_{std}$, above.
$\frac{y-\mu_y}{\sigma_y} = r \cdot \frac{x-\mu_x}{\sigma_x}$
We would really like to see $y$ by itself on the left-hand side, so multiply both sides by $\sigma_y$ and then add $\mu_y$.
$y - \mu_y = r\cdot \frac{\sigma_y (x - \mu_x)}{\sigma_x}$
$~~~~~~~~~y = r\cdot \frac{\sigma_y (x - \mu_x)}{\sigma_x} + \mu_y$
The right-hand side is not in the slope-intercept form $y=m\cdot{}x+b$ so let's fix that by expanding and regrouping.
$~~~~~~~~~y = r\cdot (\frac{\sigma_y x}{\sigma_x} - \frac{\sigma_y \mu_x}{\sigma_x}) + \mu_y$
$~~~~~~~~~y = \frac{r \cdot \sigma_y}{\sigma_x} x - \frac{r \cdot \sigma_y \mu_x}{\sigma_x} + \mu_y$
$~~~~~~~~~y = \frac{r \cdot \sigma_y}{\sigma_x} x - \frac{r \cdot \sigma_y}{\sigma_x} \mu_x + \mu_y$
$~~~~~~~~~y = (\frac{r \cdot \sigma_y}{\sigma_x}) x + (\mu_y - \frac{r \cdot \sigma_y}{\sigma_x} \mu_x)$
At this point we can verify that we're in agreement with the slide, because $\mbox{slope} = \frac{r \cdot \sigma_y}{\sigma_x}~~$ and $~~~\mbox{intercept} = \mu_y - \mbox{slope} \cdot \mu_x$.
A final caution: our instructor is careful to write "estimate of $y$" instead of simply "$y$". I have been less careful, but it's important to remember that this linear equation relates *observed* values of the independent variable $x$ with our *estimate* of the associated variable $y$.
FirstChildUserIdTAG: 1367426
FirstChildUserNameTAG: Ribreceptor
FirstChildCreateTimeTAG: 2013-03-20T17:40:21Z
FirstChildVoteTAG: 6
SecondChildTAG: you could use $\hat{y}$ (\hat{y}) to indicate that it is an estimate
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-20T21:02:31Z
SecondChildVoteTAG: 0
SecondChildTAG: @Ribreceptor: Thanks
SecondChildUserIdTAG: 498723
SecondChildUserNameTAG: YLTO
SecondChildCreateTimeTAG: 2013-03-30T13:53:53Z
SecondChildVoteTAG: 0
IndexTAG: 547
TitleTAG: r: The correlation coefficient
What is the physical meaning when r=0? Could anyone explain in the lines like the ones for r=-1 and r=+1 were explained? (linear with negative slope and positive slope).
UserIdTAG: 106510
UserNameTAG: balavignesh
CreateTimeTAG: 2013-03-20T16:30:54Z
VoteTAG: 0
CoursewareTAG: Section 6: Relation between two variables / Lec 6.2: The correlation coefficient: calculation and properties
NumberOfReplyTAG: 2
FirstChildTAG: If r = 0, then then the value of y has no correlation with the value of x. Think of a scatterplot with the data points scattered randomly over the entire graph. There's no line that fits the data.
(Someone please correct me if I'm wrong.)
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-20T16:51:24Z
FirstChildVoteTAG: 1
FirstChildTAG: I think when r = 0, it means NO LINEAR relationship. The two variables may have a quadratic or some other form of relationship and r can still be zero.
Am I correct?
FirstChildUserIdTAG: 246991
FirstChildUserNameTAG: spatra
FirstChildCreateTimeTAG: 2013-03-20T18:19:07Z
FirstChildVoteTAG: 3
SecondChildTAG: Yes, I think you're correct.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-20T21:11:12Z
SecondChildVoteTAG: 0
SecondChildTAG: r=0 means you cannot draw a line that represents the general behavior of the data, ie there is no LINEAR relationship.
eg. take a few points (x,y) as y=sqrt(100-x^2) and compute r.
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-03-22T22:39:39Z
SecondChildVoteTAG: 0
IndexTAG: 548
TitleTAG: regression estimate
How did you find z=0.842 in video?
UserIdTAG: 1247534
UserNameTAG: Sunseer
CreateTimeTAG: 2013-03-20T16:20:20Z
VoteTAG: 1
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 1
FirstChildTAG: You have to use the applet for the normal curve:
[http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm][1]
[1]: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
The question mentions 80th percentile, so we know we are talking about 80% of the area under the normal curve. So, enter value of -5 for the lower endpoint (this is essentially the maximum lowest point). Now we have to tweak the upper endpoint until we get 80 percent of the area under the curve. (Try using left/right arrows on keyboard; I have just been fiddling with entering different numbers once I get as close as I can by using the slider.)
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-20T17:26:22Z
FirstChildVoteTAG: 1
IndexTAG: 549
TitleTAG: Problem 2 need clarification.
To TA or someone got the answer,
Since the number of submitting the answer is very less, I would like to clarify this question. Is this like 10 multiple question and we just assume to create a table let say I got 8 question right and and course 2 will be wrong, so we have 2 tables 8 for right and 2 must be wrong. And we have to create another tables, and how many tables?...
More to clarify is the question have 10 only?, How many people do I need to consider?
UserIdTAG: 7980
UserNameTAG: Nazri
CreateTimeTAG: 2013-03-20T16:17:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: It is not about the number of people. It is the correlation between the number of right answers and the number of wrong answers.
FirstChildUserIdTAG: 1252099
FirstChildUserNameTAG: BetulCoskun
FirstChildCreateTimeTAG: 2013-03-20T16:57:18Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you, I still dont get
SecondChildUserIdTAG: 7980
SecondChildUserNameTAG: Nazri
SecondChildCreateTimeTAG: 2013-03-20T17:02:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Is the point here that there is no relationship between correct and incorrect answers, but a direct relationship between correct answers and score?
SecondChildUserIdTAG: 1033476
SecondChildUserNameTAG: VeronicaCYCP
SecondChildCreateTimeTAG: 2013-03-20T17:09:52Z
SecondChildVoteTAG: 0
SecondChildTAG: That's it. Number of correct answers has a perfect positive linear relationship with the score. It's confusing because you tend to look at the slope, haven't been given an average. But if you converted each variable (score and #Qs correct) to standard units they'd be the same on each axis. The inverse is true for correct versus incorrect answers, I think. (Too late for me because I already entered the incorrect answers!)
SecondChildUserIdTAG: 1033476
SecondChildUserNameTAG: VeronicaCYCP
SecondChildCreateTimeTAG: 2013-03-20T17:26:14Z
SecondChildVoteTAG: 0
SecondChildTAG: So...we were supposed to create an imaginary data table and compute r...? Drat!
SecondChildUserIdTAG: 1280049
SecondChildUserNameTAG: MissBehave
SecondChildCreateTimeTAG: 2013-03-20T17:50:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I created a table of right answers and wrong answers. "if a person got X right answers, how many wrong answers" One column for right answers, one for wrong.
That helped me answer 2A. (it confirm my thinking)
Then I added another column; the score with that many right and wrong.
Then I drew a plot, and that gave me the answer for 2B. (just a rough plot on scrap paper; don't need to do it on graph paper or be exact with positions)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T18:05:10Z
SecondChildVoteTAG: 0
SecondChildTAG: The question boils down to point how to relate the variation in number of right answers, when u vary the number of wrong answers. How to put in a equation, give number of wrong anwers, how many right answers? What will the graph look like.
SecondChildUserIdTAG: 115240
SecondChildUserNameTAG: Sarathboss
SecondChildCreateTimeTAG: 2013-03-20T18:39:02Z
SecondChildVoteTAG: 0
FirstChildTAG: The right answer is expected to be in numeric format, but think of it in qualitative way.
FirstChildUserIdTAG: 885282
FirstChildUserNameTAG: DmytroYa
FirstChildCreateTimeTAG: 2013-03-20T17:31:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Can I refer this question (2a) something like lecture 6.2 or this question is not covered (I have to think differently)
SecondChildUserIdTAG: 7980
SecondChildUserNameTAG: Nazri
SecondChildCreateTimeTAG: 2013-03-20T20:00:29Z
SecondChildVoteTAG: 0
IndexTAG: 550
TitleTAG: Problems 2A and 2B
I think the answer must be NA, because there's no enough information to answer that.
But system don't let me it.
UserIdTAG: 435900
UserNameTAG: samuelvp
CreateTimeTAG: 2013-03-20T16:11:14Z
VoteTAG: 5
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: NA is not accepted and that is probably stating that there is a numerical answer. Think in numbers. You will get it.
FirstChildUserIdTAG: 786512
FirstChildUserNameTAG: shoaibkhanz
FirstChildCreateTimeTAG: 2013-03-20T16:27:41Z
FirstChildVoteTAG: 0
SecondChildTAG: I still don't get it :/
SecondChildUserIdTAG: 1033476
SecondChildUserNameTAG: VeronicaCYCP
SecondChildCreateTimeTAG: 2013-03-20T17:00:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I got B but not A. Can someone give me a clue for A?
SecondChildUserIdTAG: 911828
SecondChildUserNameTAG: 1Student
SecondChildCreateTimeTAG: 2013-03-20T17:19:35Z
SecondChildVoteTAG: 0
SecondChildTAG: what is the approach that u used for 2B and A is still a mystery
SecondChildUserIdTAG: 85797
SecondChildUserNameTAG: Nilayam
SecondChildCreateTimeTAG: 2013-03-20T17:26:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the 'think in numbers' - that helped me. (and made me bang my head on the keyboard - I should've know better! :)
I just posted the way I did 2A and 2B in "Problem 2 need clarification" but since it's short, I'll post it here too. (normally I'd avoid double-posting...)
I created a table of right answers and wrong answers. "if a person got X right answers, how many wrong answers" One column for right answers, one for wrong.
That helped me answer 2A. (it confirm my thinking)
Then I added another column; the score with that many right and wrong.
Then I drew a plot, and that gave me the answer for 2B. (just a rough plot on scrap paper; don't need to do it on graph paper or be exact with positions)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T18:09:36Z
SecondChildVoteTAG: 0
IndexTAG: 551
TitleTAG: Problem 3
This is the best Stats course ever. Sort of sad is almost half over.
UserIdTAG: 913981
UserNameTAG: DSamuel
CreateTimeTAG: 2013-03-20T16:04:01Z
VoteTAG: 10
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: I mistakenly checked only one box. What can I do now? :(
FirstChildUserIdTAG: 837071
FirstChildUserNameTAG: diabaobao
FirstChildCreateTimeTAG: 2013-03-20T20:34:46Z
FirstChildVoteTAG: 0
FirstChildTAG: I think it's part one of a 3 part series, actually.
If I'd had this course in college, I probably would have stuck with statistics instead of hating it and having it limit my options. Would love to see her teach a class on Bayesian stats!
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-03-20T21:14:22Z
FirstChildVoteTAG: 0
IndexTAG: 552
TitleTAG: Course stat2
This is my first course in statistics and I don't have overall understanding how big statistic can be.
I'm interested how much of material is covered in stat2 and will it be enough for practical use?
So far I enjoyed the course, it's not easy but the topic is interesting and presented very well.
UserIdTAG: 610203
UserNameTAG: Petar11
CreateTimeTAG: 2013-03-20T15:49:33Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 553
TitleTAG: the textbook was very helpful
with the slow network connection, I was unable to download the video lectures. I relied most often on the textbook to complete the exercices. Has anyone experienced the same thing?
UserIdTAG: 46420
UserNameTAG: passoret
CreateTimeTAG: 2013-03-20T15:45:42Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 554
TitleTAG: Problem 2
I am always confused on how to identify x and y. When the statement is that the correlation between the two variable is 0.75 could be diameter=0.75 x weights but also weights = 0.75 diameter
How can that be addressed?
UserIdTAG: 1210888
UserNameTAG: Marouzela
CreateTimeTAG: 2013-03-20T15:44:00Z
VoteTAG: 4
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Variable x is the variable that's known; variable y is the variable that you're trying to determine. The question states:
"The slope of the regression line for estimating chick weight based on egg diameter is...."
In this case you know the egg diameter, and you're estimating chick weight.
x = diameter
y= weight
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-20T15:50:59Z
FirstChildVoteTAG: 2
IndexTAG: 555
TitleTAG: what am I lacking ( question to teacher and staff)
I came late for the class.
On Exercise set 10 , I got perfect score but on Exercise set 11 I got only one right out of 5, What am I lacking?
Am I only good on calculation but not on critical thinking or lacking logical part?
UserIdTAG: 621690
UserNameTAG: sakar60
CreateTimeTAG: 2013-03-20T15:40:49Z
VoteTAG: 3
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: I scored 100 percent in the Home work 7, 8, 9 and also this one. But after spending many hours, I just managed to answer two questions wrong in HW 9 and I decided to complete it afterwards. I would request the instructor to try to resolve this issue, why such a large cohort of good students is finding it very hard.
FirstChildUserIdTAG: 151750
FirstChildUserNameTAG: Rajputana
FirstChildCreateTimeTAG: 2013-03-20T19:49:45Z
FirstChildVoteTAG: 0
IndexTAG: 556
TitleTAG: With out Applet
If you do not have an applet, how do you calculate the percentiles??
UserIdTAG: 1379448
UserNameTAG: Phindaseanhlubi
CreateTimeTAG: 2013-03-20T15:38:46Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 2
FirstChildTAG: Here is the link: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 927161
FirstChildUserNameTAG: DeathLenin
FirstChildCreateTimeTAG: 2013-03-20T16:12:02Z
FirstChildVoteTAG: 0
FirstChildTAG: I would also appreciate a hint how to work out the solutions without the use of the applet. I have tried to use the applets and they just don't not work - I can get the numbers, but the graphs are not shown. I have updated Mozilla to the required version, but still... nothing. I did not post a message so far because I could get by without it with simple computations, but it seems that is over now. Any suggestions will be appreciated.
FirstChildUserIdTAG: 1188102
FirstChildUserNameTAG: Mojca
FirstChildCreateTimeTAG: 2013-03-20T16:25:09Z
FirstChildVoteTAG: 1
SecondChildTAG: Google "normal curve table"
http://www.mathsisfun.com/data/standard-normal-distribution-table.html has a similar applet as well as a table. Note that their table is *from the mean* instead of including everything to the left of the mean.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T20:05:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Many thanks!
SecondChildUserIdTAG: 1188102
SecondChildUserNameTAG: Mojca
SecondChildCreateTimeTAG: 2013-03-20T20:21:44Z
SecondChildVoteTAG: 0
IndexTAG: 557
TitleTAG: Pay attention to the unit.
Staff, Thanks for testing us on alertness and not only on statistics, for it is also very important.
*(# bitter for not paying attention and getting the wrong answer)*
UserIdTAG: 955096
UserNameTAG: yoav_v
CreateTimeTAG: 2013-03-20T15:18:43Z
VoteTAG: 3
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: also, i'm stuck on Problem 3, any suggestions?
FirstChildUserIdTAG: 955096
FirstChildUserNameTAG: yoav_v
FirstChildCreateTimeTAG: 2013-03-20T15:27:41Z
FirstChildVoteTAG: 0
SecondChildTAG: The problem of Q3 there is ONLY one submission ;)
SecondChildUserIdTAG: 1288142
SecondChildUserNameTAG: aldawlah
SecondChildCreateTimeTAG: 2013-03-20T17:40:26Z
SecondChildVoteTAG: 0
IndexTAG: 558
TitleTAG: intersept calculation
I want to calculate the intersept. is it like this :
meanx - ( slope X meany). so after I get the answer of (slope X meany) then I subtracted from meanx?
UserIdTAG: 1048539
UserNameTAG: Reham1989
CreateTimeTAG: 2013-03-20T15:02:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Depends on how you use *x* and *y*.
With the convention used in the lectures(*x=known data, y=unknown*), it would be $mean_y-(slope*mean_x)$.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T15:20:49Z
FirstChildVoteTAG: 0
FirstChildTAG: The intercept is the value of y when x is equal to zero, i.e. the point at which the line intersects the y-axis. Plug x=0 in in the equation of the line and you will see what the intercept is.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-20T16:14:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Watch Lec. 7.1 & 7.2 to make sure you understand that. Write out & Calculate the problems with the Professor. Then go to 7.3 -7.4, do the same thing. You will understand.
FirstChildUserIdTAG: 4612
FirstChildUserNameTAG: Susnaj
FirstChildCreateTimeTAG: 2013-03-20T17:27:35Z
FirstChildVoteTAG: 0
IndexTAG: 559
TitleTAG: Thanks!!!
I think I needed that unexpected surprise and it just made my day!!! I highly appreciate your effort to cheer us up! It worked beautifully! Thanks!
UserIdTAG: 759060
UserNameTAG: RocioRosado
CreateTimeTAG: 2013-03-20T14:48:22Z
VoteTAG: 9
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: Ha, ha :)
FirstChildUserIdTAG: 584390
FirstChildUserNameTAG: pluribus
FirstChildCreateTimeTAG: 2013-03-20T15:26:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Yeah I agree! That was very thoughtful and sweet :)
FirstChildUserIdTAG: 1099148
FirstChildUserNameTAG: zemyrym
FirstChildCreateTimeTAG: 2013-03-20T16:31:11Z
FirstChildVoteTAG: 1
IndexTAG: 560
TitleTAG: Could we get the data fot plotting by ourselves?
Hi,
I'm trying to plot the data of the exercises on the lectures with R. Could we get the data (maybe in a csv format) so we could plot it by ourselves?
Thanks
UserIdTAG: 937399
UserNameTAG: fernandocalero
CreateTimeTAG: 2013-03-20T14:22:16Z
VoteTAG: 2
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: These look like the same data:
http://www.commonwealthfoundation.org/policyblog/detail/sat-scores-by-state-2011
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-20T14:49:47Z
FirstChildVoteTAG: 1
IndexTAG: 561
TitleTAG: STAFF Correlation based on averages
the last point made in the lecture that one should be careful about the use of averaged values and the interpretation of the r value. so it means that for the given example r = 0.97 would mean only that a positive correlation exist between average values of math s and reading sections of SAT across the states of USA. Anything else?
Also the prediction of scores in reading from scores in math would depend on r values for particular states and it would possibly be different for different states. is it that ways?
UserIdTAG: 879527
UserNameTAG: bhavinpattni
CreateTimeTAG: 2013-03-20T14:19:29Z
VoteTAG: 0
CoursewareTAG: Section 6: Relation between two variables / Lec 6.3: Using r: with caution!
NumberOfReplyTAG: 0
IndexTAG: 562
TitleTAG: Course Updates and News ... Is this page blank for anyone else but me?
I have tried two different devices so far. And I do not want to miss anything!
UserIdTAG: 1235638
UserNameTAG: MyOwnCamera
CreateTimeTAG: 2013-03-20T14:16:56Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Is blank for me too, there is a message from prof. A saying there is a problem with the site and as soon as they fix it will be posting news about final exam and Stat2.2X.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-03-20T14:19:27Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you much!
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-20T14:28:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Good to know. I was worried as well.
SecondChildUserIdTAG: 177806
SecondChildUserNameTAG: Judi
SecondChildCreateTimeTAG: 2013-03-20T14:50:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Blank for me too. Probably some update in progress...
FirstChildUserIdTAG: 898917
FirstChildUserNameTAG: MarioPinto
FirstChildCreateTimeTAG: 2013-03-20T15:20:59Z
FirstChildVoteTAG: 0
FirstChildTAG: I am also worried. I am on roaming and somehow only able to see the discussion page but not the courseware page
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-20T16:11:45Z
FirstChildVoteTAG: 0
FirstChildTAG: just got the following e-mail:
Dear Students,
The final exam for Stat 2.1X will start at 05:00 A.M. Greenwich Mean Time (GMT) on Tuesday, March 26 and end at 05:00 A.M. GMT on Friday, March 29. That's 72 hours.
Solutions to Exercise Set 12 will be visible once you have submitted your answers. That is the only Exercise Set in Week 5. Please note that the due date for Exercise Set 12 is Monday March 25, the day before the final.
The discussion forum will be closed during the three days of the final exam, but staff will be able to post to the forum and you will be provided with an email address to which you can email bugs or errors.
You will have the entire 72 hour period to take the exam. You don't have to do it all in one sitting.
The final will be about 1.5 to 2 times the length of the midterm. If you do it at one sitting I expect it will take you 90 minutes to 2 hours, possibly less depending on how well you know your stuff. The Exercise Sets, Practice Problems sets, and the midterm are good indications of what to expect on the final.
I will post additional practice problems by the end of this week.
Best,
Prof. A.
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-20T16:44:33Z
FirstChildVoteTAG: 2
SecondChildTAG: Awesome!! Thank you MarianW.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-20T17:10:17Z
SecondChildVoteTAG: 0
FirstChildTAG: If the due date for Exercise Set 12 is Monday March 25, the day before the final, shouldn't the lectures and corresponding exercises be already posted? Am I missing something?
thanks
FirstChildUserIdTAG: 1077370
FirstChildUserNameTAG: Paraty
FirstChildCreateTimeTAG: 2013-03-20T20:12:36Z
FirstChildVoteTAG: 0
IndexTAG: 563
TitleTAG: Midterm Exam
I missed midterm exam! Can I still get mark for attempting it?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T14:03:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: nope. you need to wait for the next session.
FirstChildUserIdTAG: 18187
FirstChildUserNameTAG: alinsoar
FirstChildCreateTimeTAG: 2013-03-20T14:46:47Z
FirstChildVoteTAG: 0
SecondChildTAG: which section? next Stat2.1x course? sorry, i did not find this info on site. im in the same situation, i have registered last week on Stat2.1x, and lost all exercises and midterm... what would i do now? Could i do the exercises now or i must get out of this course and start another one ?
SecondChildUserIdTAG: 1446070
SecondChildUserNameTAG: maramd
SecondChildCreateTimeTAG: 2013-03-20T19:01:55Z
SecondChildVoteTAG: 0
IndexTAG: 564
TitleTAG: Joules
The problem 3 was the best so far in Stat 2.1x! More of these on the way. Thank you!
UserIdTAG: 1268329
UserNameTAG: Joulece
CreateTimeTAG: 2013-03-20T14:00:31Z
VoteTAG: 4
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 565
TitleTAG: Xcellent course ..Thanxxx
It has been a great journey till now understanding statistics. I am enjoying it.
Many thanks dear Prof A, Prof Stark and all the team behind this venture for your valuable time and effort to help us learn statistics....
UserIdTAG: 994886
UserNameTAG: ARUN86
CreateTimeTAG: 2013-03-20T13:28:34Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Agreed. I am so thankful to Prof A & Prof Stark for continuously deepening my understanding on statistics through providing this excellent course :)
FirstChildUserIdTAG: 1147529
FirstChildUserNameTAG: GRHernanda
FirstChildCreateTimeTAG: 2013-03-20T13:43:16Z
FirstChildVoteTAG: 2
FirstChildTAG: As Albert Einsten once said: "everything should be made as simple as possible, but not simpler". I believe Prof A & Prof St. have made this statistics course an enjoyable journey through simplified concept to make everybody understand statistics. I have studied descriptive statistics in highschool and university, but I find this one unique in the way the lectures were presented. I think it shows the power of Berkeley University for providing simple concept to complex problems.
FirstChildUserIdTAG: 46420
FirstChildUserNameTAG: passoret
FirstChildCreateTimeTAG: 2013-03-20T15:55:02Z
FirstChildVoteTAG: 1
IndexTAG: 566
TitleTAG: Percentile rounding !
Since we are dealing with two **discrete** variables which roughly normal distributed the rough estimation of any portion above 66% percentile should rather belong to the 67% percentile and not to the 66%?
UserIdTAG: 1239975
UserNameTAG: Xenofon
CreateTimeTAG: 2013-03-20T13:25:52Z
VoteTAG: 2
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 0
IndexTAG: 567
TitleTAG: Textbook download is it possible?
I would like to download the textbook so that I can read it offline. It is not convenient for me to be online 24 hours everyday. How can I download the textbook?
UserIdTAG: 941991
UserNameTAG: oxoxo
CreateTimeTAG: 2013-03-20T13:14:21Z
VoteTAG: 2
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: I don't know, whether it is a solution, but i've printed all the chapters of textbook in PDF. This is not so cool, actually, though it's readable and suits me right now.
I would love to get source TeX files for the book if they exist, so we could compile it and get a better offline version. I hope i didn't break any licences by making an offline copies?
FirstChildUserIdTAG: 1038359
FirstChildUserNameTAG: nonagenarian
FirstChildCreateTimeTAG: 2013-03-20T13:25:23Z
FirstChildVoteTAG: 1
SecondChildTAG: with offline explorer you can have the whole text at least i mean the text without videos
SecondChildUserIdTAG: 1078818
SecondChildUserNameTAG: Jamili
SecondChildCreateTimeTAG: 2013-03-20T16:23:57Z
SecondChildVoteTAG: 0
SecondChildTAG: i prefer PDF, so i can read them on my tablet as well. I have videos downloaded separately, so this is not a problem
SecondChildUserIdTAG: 1038359
SecondChildUserNameTAG: nonagenarian
SecondChildCreateTimeTAG: 2013-03-20T16:29:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Did your pdfs come out okay? I tried one and the histogram moved and obscured the text.
How do you do it offline (using Safari, or Firefox, or Chrome)?
Thanks.
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-20T19:59:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Another thought, if your pdfs came out okay, is is possible to post them to the Wiki page, please oh please...
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-20T20:02:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks a lot for your response, nonagenarian. With the pdf, how would you check your answers? Remember the online textbook provides the submitted answers.
Hi Jamili! I know I am being lazy about this but can you please give the link to offline explorer that you use?
FirstChildUserIdTAG: 941991
FirstChildUserNameTAG: oxoxo
FirstChildCreateTimeTAG: 2013-03-20T19:34:09Z
FirstChildVoteTAG: 0
IndexTAG: 568
TitleTAG: Midterm.last question
There is no any indication of mean or SD sizes for the problem,
There is no ground for usage of chebyshem in-qty
The problem not well posed, should be removed from the test
UserIdTAG: 1393717
UserNameTAG: gena123
CreateTimeTAG: 2013-03-20T13:05:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The list of numbers given in the problem is in standard units, so you don't need to know the mean or SD of the original list to see that 7 of the numbers are greater than +4 or less than -4.
FirstChildUserIdTAG: 464008
FirstChildUserNameTAG: pmccli
FirstChildCreateTimeTAG: 2013-03-20T13:29:52Z
FirstChildVoteTAG: 0
FirstChildTAG: There is *plenty* of ground for usage of Chebychev's inequality. The *k* in $\frac{1}{k^2}$ is effectively the value in Standard Units for the element of a list.
You **have** values in Standard Units in the Problem. So you have all the *k* values you need to make your evaluations.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T13:31:42Z
FirstChildVoteTAG: 1
FirstChildTAG: Sorry you have not understood the question doesn't imply the question is bad or wrong!! Please read the question again. The computer converts the data to standard units and Chebyshev applies. Indeed applies to any list!!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-20T16:14:52Z
FirstChildVoteTAG: 0
IndexTAG: 569
TitleTAG: Is it tiredness or brain fatigue?
):forgot to add the correct sign to my answer to P2B, i.e. the Intercept.
Please consider regrading this mistake as due to inattention. I was socked when the page returned with a red cross and then I saw my mistake!
Can someone please tell me why the regression fallacy does not apply here?
UserIdTAG: 941991
UserNameTAG: oxoxo
CreateTimeTAG: 2013-03-20T12:49:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: You had 2 available checks there. Was it inattention both times?
As for the regression fallacy...I guess you mean the regression effect? It does apply. If you take a 25mm egg(about 4.5 SDs more than the Average) using the equation you'll get an estimated chick weight of about 7.7g(3.4 SDs more than the Average). So there is still regression toward the Average.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T13:26:21Z
FirstChildVoteTAG: 1
SecondChildTAG: @Klionheart: your explanation here made the whole thing click for me! Thank you!
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-03-20T19:30:16Z
SecondChildVoteTAG: 0
IndexTAG: 570
TitleTAG: problem 3!
I wish all the problems could be solved as easily as the third one!:)
UserIdTAG: 903120
UserNameTAG: Rapunzelia
CreateTimeTAG: 2013-03-20T12:34:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 571
TitleTAG: Exercise 9.5
How can you read the r from the scatter plot? Please help
UserIdTAG: 1210888
UserNameTAG: Marouzela
CreateTimeTAG: 2013-03-20T12:20:07Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 1
FirstChildTAG: You can not, i suppose. Try to answer this questions first:
1. What does scatter plot display and what is it used for?
2. What is r coefficient and what does it mean?
After that i think you'll find the answer to your initial question.
P.S. By "read the r" you mean to get the exact value of r or to estimate it?
FirstChildUserIdTAG: 1038359
FirstChildUserNameTAG: nonagenarian
FirstChildCreateTimeTAG: 2013-03-20T13:38:47Z
FirstChildVoteTAG: 0
SecondChildTAG: Based on the answer provided for the a.m. exercise, part of the solution involves that you should read the r from the scatter plot, the one in Fig 5.2 which is not clear to me how that can be achieved, Thx anyway
SecondChildUserIdTAG: 1210888
SecondChildUserNameTAG: Marouzela
SecondChildCreateTimeTAG: 2013-03-20T14:17:00Z
SecondChildVoteTAG: 0
SecondChildTAG: the more "clustered" together the data is around the (imaginary) line on the graph, the closer r is to $\pm1$.
That should help estimating r roughly.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-20T15:13:30Z
SecondChildVoteTAG: 0
SecondChildTAG: it makes sense, thx
SecondChildUserIdTAG: 1210888
SecondChildUserNameTAG: Marouzela
SecondChildCreateTimeTAG: 2013-03-20T15:41:34Z
SecondChildVoteTAG: 0
IndexTAG: 572
TitleTAG: 1b
Disappointing question. Didn't felt like it was testing me on the material taught.
UserIdTAG: 955096
UserNameTAG: yoav_v
CreateTimeTAG: 2013-03-20T12:12:52Z
VoteTAG: 2
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: As I see it, it was testing whether we understand the concepts behind the numbers, which is a very important part of statistics.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T13:40:54Z
FirstChildVoteTAG: 1
IndexTAG: 573
TitleTAG: Simplest Exercises - Worst score =)
intentionally didn't take P3 points =)
and absolutely inattentive for trivial P1 and P2A =)
worst score in this course! LOL!
UserIdTAG: 255838
UserNameTAG: EngineerHrenov
CreateTimeTAG: 2013-03-20T12:09:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 574
TitleTAG: stop refering us to the text book is confusing
navigating through the text book is quite confusing and long winding. i turn to focus on the video lectures and grasp what is taught there only to be referred to the text book to look for the normal curve only God knows where it is. by the time i begin navigating into it, i have forgotten what i learn t and i have to be moving back and forth. From practice for exercise set 10, a link was provided but browser was showing a 404 error and the therefore could not access the resource. i believe if every referrals is provided in the question / test block, it will enhance focus and speed. i hope you agree with me?
UserIdTAG: 799816
UserNameTAG: JAMINx
CreateTimeTAG: 2013-03-20T11:51:16Z
VoteTAG: 8
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 1
FirstChildTAG: Personally I have received no benefit from the text book, the verbal references to start and stop points, seems mildly archaic in the days of dynamic links
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-20T13:50:04Z
FirstChildVoteTAG: 0
IndexTAG: 575
TitleTAG: Most unclear
I didn't know what and where to find practice material for exercise 9.
I don't understand these questions. What is asked here precisely? Numerical values? Correlation could also be could negative and positive, couldn't it?
It's a little bit of a shame. Course was reasonably clear until about now. I think it's not wise to offer fundamental course material ("course textbook"), outside of the EDx.org platform and form factor. Really makes things confusing, unclear and frustrating.
UserIdTAG: 67948
UserNameTAG: DeRaaf
CreateTimeTAG: 2013-03-20T10:16:36Z
VoteTAG: 3
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: True.. didnt clearly understood, homoskedasticity and heteroskedasticity
and this is just the beginning !
FirstChildUserIdTAG: 977503
FirstChildUserNameTAG: ratanK
FirstChildCreateTimeTAG: 2013-03-20T11:42:41Z
FirstChildVoteTAG: 0
SecondChildTAG: I think you have to suppliment the text book with additional materials. I found a great stats book at the library. Sometimes the ' dummy ' collection of books is good too, just to get your head around some of the concepts. Helped me :)
SecondChildUserIdTAG: 1322718
SecondChildUserNameTAG: Jovanovic
SecondChildCreateTimeTAG: 2013-03-20T13:33:58Z
SecondChildVoteTAG: 0
FirstChildTAG: This is the second time I have taken an intro class in Stats. The first time I took it I felt lost and confused too! To be successful in Stats you have to understand the concept more than the "formula". Ask yourself what data am I looking at, what am I looking for, and what is a reasonable answer. Stats is not just "math" it is ideas.
The best help is to go back and review the materials ... each time you do you will begin to understand the bigger picture of what Stats are and what they represent!
I think the way they are doing this course is superior to the freshman stats I took at university because here they spend time explaining the concepts over the formulas. Anyway this is just my experience and opinion.
FirstChildUserIdTAG: 980531
FirstChildUserNameTAG: tesmaili
FirstChildCreateTimeTAG: 2013-03-20T11:45:17Z
FirstChildVoteTAG: 2
IndexTAG: 576
TitleTAG: Also called...
beginner's luck. Now I get some things...
UserIdTAG: 921807
UserNameTAG: hdzmiriam
CreateTimeTAG: 2013-03-20T09:59:56Z
VoteTAG: 1
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.3: Regression effect, Galton, and the regression fallacy
NumberOfReplyTAG: 1
FirstChildTAG: Indeed, that is what I thought about too...
FirstChildUserIdTAG: 134165
FirstChildUserNameTAG: sthierry
FirstChildCreateTimeTAG: 2013-03-20T13:32:54Z
FirstChildVoteTAG: 0
IndexTAG: 577
TitleTAG: Mouse slipped and Clicked the wrong radio button!
:(
Just clicked the wrong radio button. I knew the right answer to Prb1!!. Wanted to click Check and instead clicked the wrong radio button and then Checked!
Very angry at myself...
UserIdTAG: 190804
UserNameTAG: rito
CreateTimeTAG: 2013-03-20T09:49:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: This has been problem with the mouse selecting a button if hovered over the white area.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-20T09:55:10Z
FirstChildVoteTAG: 1
SecondChildTAG: Very angry at myself...this thing happens to me twice during the course.LOL at me.
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-20T11:07:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeah, I just did this, too. :( Ah well...
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-03-20T19:41:34Z
SecondChildVoteTAG: 0
FirstChildTAG: happened to me too at problem 2A :'( I knew the answer just clicked incorrectly, noticed moments after clicking the button
FirstChildUserIdTAG: 533740
FirstChildUserNameTAG: Amadeus86
FirstChildCreateTimeTAG: 2013-03-20T20:58:58Z
FirstChildVoteTAG: 0
IndexTAG: 578
TitleTAG: week 5
has the week 5 exercise started yet? i dont seem to be able to see the exercise.
many thanks,
nicole
UserIdTAG: 946512
UserNameTAG: nicoleha
CreateTimeTAG: 2013-03-20T09:36:15Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Nor me - at 0841 GMT
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-20T09:38:51Z
FirstChildVoteTAG: 2
FirstChildTAG: Consider this - 9.00GMT is 3AM in California - I doubt anyone's up to open week 5.
Be patient for a few more hours.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T09:49:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Well now it is 13:55 GMT (so query 07:55 in California) I hope you will urge patience on the tutors when the deadlines for submission are missed!
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-20T13:55:24Z
FirstChildVoteTAG: 2
FirstChildTAG: now 1552 GMT and nothing showing, I hope this problem is resolved for the final
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-20T16:50:38Z
FirstChildVoteTAG: 1
IndexTAG: 579
TitleTAG: Thanks for this course.
I'm a master student in Aerospace Engineering, I've studied statistics a lot of time, inside other courses (failure rate of airplane, Reynolds tensor for tourboulence etc) but they skypped always the basics, so I've to say thank you for your help in clearing the fog in some topics.
UserIdTAG: 1080570
UserNameTAG: MirkoPonzanelli
CreateTimeTAG: 2013-03-20T09:25:35Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 580
TitleTAG: Mid Term Last Question
Since we do not know the average of 100 number, I am not able to understand the logic behind violating Chebycheb's Inequality. Or by standard units, it is meant to produce Normal(0,1) distribution.
UserIdTAG: 324509
UserNameTAG: halfliver
CreateTimeTAG: 2013-03-20T07:26:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Since the program converts the numbers to standard units; the mean of the output will be 0. A correct program would output value of 1=> 1 unit of sd(z), 2=>2 units of sd, 3z, 4z and so on...
By Chebychev's inequality we can have only 1/(4*4) portion of 100 numbers with values > 4z. i.e. of the 100 sd equivalents that the program will output, only about 6 numbers can have values > 4.
However in the first sample of 10 that the program provided we see around 7 nos > 4sd.
So the conclusion is that the program is not converting the numbers to standard units correctly
FirstChildUserIdTAG: 1243120
FirstChildUserNameTAG: NKum
FirstChildCreateTimeTAG: 2013-03-20T08:21:10Z
FirstChildVoteTAG: 1
FirstChildTAG: Another way is that the sum of the squares of the standard units should be the number of observations. If we just summed up the the squares of the 10 results it far exceeds 100.
FirstChildUserIdTAG: 1061625
FirstChildUserNameTAG: Agnostic
FirstChildCreateTimeTAG: 2013-03-20T11:16:05Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you very much for sharing this insight.
Because I did not understand your statement intuitively, I worked it out mathematically. Maybe other people prefer it this way as well.
The standard deviation, $\sigma_x$, is computed based on the list of $100$ points:
$\sigma_x = \sqrt{\frac{1}{100}\sum_{i=1}^{100}(x_i-\mu_x)^2}$, where $\mu_x = \sum_{i=1}^{100} x_i$ is the mean of the $100$ points. The data points in standard units are $x_{i}^{(s)} = \frac{x_i-\mu_x}{\sigma_x}$.
The sum of the squares of all data points in standard units is
$\sum_{i=1}^{100}x_{i}^{(s)^2} = \sum_{i=1}^{100}\frac{(x_i-\mu_x)^2}{\sigma_x^2} = \frac{1}{\sigma_x^2}\sum_{i=1}^{100}(x_i-\mu_x)^2$.
Since $\sigma_x^2 = \frac{1}{100}\sum_{i=1}^{100}(x_i-\mu_x)^2$, it follows that
$\sum_{i=1}^{100}x_i^{(s)^2} = \frac{1}{\sigma_x^2}100\cdot \sigma_x^2 = 100$.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-21T10:33:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi Agnostic,
"sum of the squares of the standard units should be the number of observations". This is true when applied for the full set of observations and (my understanding is) it may not always hold true for a subset of observations. i.e. as in this example a partial of the full (10 of 100)
SecondChildUserIdTAG: 1243120
SecondChildUserNameTAG: NKum
SecondChildCreateTimeTAG: 2013-03-24T00:20:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi Agnostic,
My bad missed the second half "If we just summed up the the squares of the 10 results it far exceeds 100"
I agree with the reasoning
SecondChildUserIdTAG: 1243120
SecondChildUserNameTAG: NKum
SecondChildCreateTimeTAG: 2013-03-24T00:22:20Z
SecondChildVoteTAG: 0
IndexTAG: 581
TitleTAG: What about the second and third part of the course?
Hello, first of all, thank you for the wonderful course you're offering. As reported in https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/about the 2.1x is the first of three courses. Will the other two courses be taught , at the end of this one? I'd like it very much. If so, will the lesson be available on this platform, as the 2.1x?
Thank you very much for your great job. Best regards
UserIdTAG: 1385216
UserNameTAG: silviasinigardi
CreateTimeTAG: 2013-03-20T07:19:10Z
VoteTAG: 14
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 4
FirstChildTAG: This has been commented on multiple times by the prof.
There is a problem with the Course Info page at the moment, but she says that when that is resolved info regarding the exam and the other courses will be posted.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5149387bc1dc69600b000102
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T07:26:56Z
FirstChildVoteTAG: 4
SecondChildTAG: Thank you very much.
I'll follow the updates
SecondChildUserIdTAG: 1385216
SecondChildUserNameTAG: silviasinigardi
SecondChildCreateTimeTAG: 2013-03-20T07:53:59Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you very much Prof. Andi. Your way of teaching is very good. Your language is very clear I like your way of teaching.
FirstChildUserIdTAG: 405944
FirstChildUserNameTAG: shumailazia
FirstChildCreateTimeTAG: 2013-03-20T08:02:53Z
FirstChildVoteTAG: 4
SecondChildTAG: I agree, your form of explaining in detail each new problem makes this much easier to learn! Not easy, but easy to learn if you work at it. Thank you!
SecondChildUserIdTAG: 1115165
SecondChildUserNameTAG: Abbyjohnson
SecondChildCreateTimeTAG: 2013-03-20T15:58:57Z
SecondChildVoteTAG: 0
FirstChildTAG: thanks prof for this wonderful course.....
FirstChildUserIdTAG: 1216316
FirstChildUserNameTAG: Ashwanik
FirstChildCreateTimeTAG: 2013-03-20T13:57:15Z
FirstChildVoteTAG: 0
FirstChildTAG: hi everyone, the course is really good and very useful. It will be helpful if the other two courses were done in continuation of this...
FirstChildUserIdTAG: 1311995
FirstChildUserNameTAG: podilashree
FirstChildCreateTimeTAG: 2013-03-20T17:50:33Z
FirstChildVoteTAG: 0
IndexTAG: 582
TitleTAG: nonretracability on regression line
![enter image description here][1]![see that mid point of intersect of ellipse on X and y are different][2]
[1]: http://
[2]: http://
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-20T06:35:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Can't seem to upload the picture!!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-20T06:38:30Z
FirstChildVoteTAG: 0
IndexTAG: 583
TitleTAG: please help with intercept
the intercept as calculated in the video 67 - 0.09 = 52.6 inches where does that 52.6 come from? my calculator is giving me a different value.
UserIdTAG: 617692
UserNameTAG: Inoukapo
CreateTimeTAG: 2013-03-20T06:34:29Z
VoteTAG: 0
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.4: Equation of the regression line
NumberOfReplyTAG: 1
FirstChildTAG: On the slide it says: intercept = 67 − 0.09 × 160 = 52.6 inches. Of course it's important to keep in mind that if no parenthesis are used, multiplication and division are calculated before addition and subtraction.
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-20T06:48:38Z
FirstChildVoteTAG: 2
IndexTAG: 584
TitleTAG: problem3
v happy to see problem n0 3 n my answer to this question is absolutely correct !!! Hurray ;)))
UserIdTAG: 1036551
UserNameTAG: Geetagrg
CreateTimeTAG: 2013-03-20T06:03:17Z
VoteTAG: 1
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 585
TitleTAG: Technical Issues concerning Week 5
Hello everyone,
I logged in today as usually, in order to get to familiarize myself with the contents of the final week, as well as complete the exercise set12 and the final exam. However, there is no reference to week 5 when I click the courseware , neither is there any reference to the material of it in the discussion tab. Has anyone else experienced similar problems??? What do I get to do to fix this issue??? I would appreciate the help.
Thanks in advance,
G.P
UserIdTAG: 1333124
UserNameTAG: GregPa
CreateTimeTAG: 2013-03-20T05:51:39Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I guess we will just have to wait for week 5 materials to be put online. Even though deadlines are in GMT new material upload might not be.
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-20T06:12:15Z
FirstChildVoteTAG: 0
FirstChildTAG: I think Week 5 is not yet available.
FirstChildUserIdTAG: 681879
FirstChildUserNameTAG: oued1967
FirstChildCreateTimeTAG: 2013-03-20T08:36:55Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm sure the deadlines will be extended as well!
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-20T09:39:53Z
FirstChildVoteTAG: 0
IndexTAG: 586
TitleTAG: [STAFF] I am unregistering from this course
Sorry Stat2.1x professors and staff,
The formatting of this course is way too frustrating. It is too difficult to follow the connections between two lecturers and how they are related, and then how that is all related to the problem sets. Consequently, I spend too much time trying to match content and then to figure out what I'm supposed to do with the problems sets.
Simple juxtaposition of content in the same window, using Headers to group content, and the very sophisticated technology of using LINKS are not practiced where they should be. If you don't have the time to spend an extra minute formatting, to save me 30 minutes or more trying to understand your instructional flow, then I have no choice but to drop this course.
I am very interested in the topic of statistics, and there have been some things that I've learned thus far, but I have too many other things going on in RL to waste time decrypting the format of this course. It's not at all enjoyable.
I would also like to add that there should be more moderation by staff to make deletions of posts that show sarcasm, meanness, and which solely create a demoralizing atmosphere on the discussion boards. I came here for a positive experience, but there is too much noise to sift through overall to make this course presently worth my while.
I will wait a few more iterations and then in the future I'll check back to see if things have improved in your instructional design.
Sincerely and with the best intentions, until then...
LB
UserIdTAG: 963897
UserNameTAG: lightbulb
CreateTimeTAG: 2013-03-20T05:30:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: > The formatting of this course is way too frustrating. It is too difficult to follow the connections between two lecturers and how they are related, and then how that is all related to the problem sets. Consequently, I spend too much time trying to match content and then to figure out what I'm supposed to do with the problems sets.
I don't have problems with this. Dividing lectures in short chunks to make them easier to digest has this counterpart: students have to recombine things and put them in its natural hierarchical order. But, IMO, at this level of education (higher education) it's something to be taken for granted. I've made myself an all-in-one pdf consisting of all the lectures and a little table of contents that allows me to see the big picture and go to the right place in my review of the material.
> I would also like to add that there should be more moderation by staff to make deletions of posts that show sarcasm, meanness, and which solely create a demoralizing atmosphere on the discussion boards
Fortunately they are an absolute minority and the best way to 'delete' this behaviour is refraining from responding. Trolls exist because they receive feedback, even angry feedback. Whenever I see a troll I go away. Complete silence makes them disappear.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-20T09:38:29Z
FirstChildVoteTAG: 1
FirstChildTAG: Lightbulb, your comments constitute your own subjective view.
Here is mine. I strongly disagree with you, I find the course very well designed and the course material superb.
There is nothing similar available around, coming close to being as good as what is freely provided in this course.
You overly exaggerate time supposedly wasted to grasp the flow of the lectures, and link to the other course material.
I find your comments in all false and surely ill intended.
My own experience is 100 percent positive, and I have 8 years experience in university level education.
Best,
GT
FirstChildUserIdTAG: 902212
FirstChildUserNameTAG: trigeor
FirstChildCreateTimeTAG: 2013-03-20T11:53:36Z
FirstChildVoteTAG: 6
SecondChildTAG: I would second that.
SecondChildUserIdTAG: 1015352
SecondChildUserNameTAG: weizkn
SecondChildCreateTimeTAG: 2013-03-20T12:17:36Z
SecondChildVoteTAG: 0
FirstChildTAG: > the very sophisticated technology of using LINKS are not practiced where they should be
>
> If you don't have the time to spend an extra minute formatting, to save me 30 minutes
> but I have too many other things going on in RL to waste time decrypting the format of this course. It's not at all enjoyable.
>I will wait a few more iterations and then in the future I'll check back to see if things have improved in your instructional design.
Ouch!
> I would also like to add that there should be more moderation by staff to make deletions of posts that show sarcasm, meanness
Hmmm
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T12:29:27Z
FirstChildVoteTAG: 2
SecondChildTAG: Lol!
SecondChildUserIdTAG: 4612
SecondChildUserNameTAG: Susnaj
SecondChildCreateTimeTAG: 2013-03-20T14:10:11Z
SecondChildVoteTAG: 0
SecondChildTAG: i understand your frustration but remember, if deletion of posts that show sarcasm, meanness etc was possible your post wouldn't have survived either. I have frustrations too at time but due to the fact that what i learn here is important i kept my head up.
SecondChildUserIdTAG: 617692
SecondChildUserNameTAG: Inoukapo
SecondChildCreateTimeTAG: 2013-03-20T20:42:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Goodbye, Lightbulb!
I might not think very highly of some of your arguments, but I am absolutely dazzled by your chutzpah: you complain about **your** time being wasted, while you attend a free course being delivered (wonderfully well, IMHO) by one of the preeminent educational institutions in the world.
Keep up the good fight...!
FirstChildUserIdTAG: 23003
FirstChildUserNameTAG: WH
FirstChildCreateTimeTAG: 2013-03-20T17:16:12Z
FirstChildVoteTAG: 4
IndexTAG: 587
TitleTAG: Problem 3
Uugghh - I quickly(from brain exhaustion) missed the second tick box for Problem 3, and hit check/save. Does this one really count - or can I redo it as not a real problem!! ?
UserIdTAG: 1146194
UserNameTAG: McClatchy
CreateTimeTAG: 2013-03-20T05:05:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: I'd guess it counts - it checks reading comprehension of English which is a Prerequisite of the course.
The lesson is - don't do these Problems if you're tired or distracted :o
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-20T10:12:51Z
FirstChildVoteTAG: 1
IndexTAG: 588
TitleTAG: Stat2.2x
To the staff:
I'm really enjoying this course, even though hasn't been easy at all. This is my first time with an EdX course and so far it's been great.
Is there any information about Stat2.2x schedule? Or better, Will we have Stat2.2x?
Thanks in advance
UserIdTAG: 689072
UserNameTAG: pato54
CreateTimeTAG: 2013-03-20T04:58:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: We should get the info today. I am not sure what time the upload occurs but it is already 5.09 GMT. I usually get to see them much later but(as I am at work at that time) but am free as I am in a transit lounge at an airport and was hoping to download the lectures to hear on the flight :)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-20T05:13:40Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks, enjoy your flight, by the way!
SecondChildUserIdTAG: 689072
SecondChildUserNameTAG: pato54
SecondChildCreateTimeTAG: 2013-03-20T11:00:02Z
SecondChildVoteTAG: 0
IndexTAG: 589
TitleTAG: jajajaja!
jajajaj they totally own me in the last one! Don't do this if you are tired!
UserIdTAG: 1081681
UserNameTAG: Gabv105
CreateTimeTAG: 2013-03-20T04:54:28Z
VoteTAG: 1
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: My opinion is that such a joke shouldn't be a part of an exercise, especially if awarded with points. If I should pass 35% required thanks these 2 points, what is it worth for me? What worth is the final certificate then? Can I put it to my CV and present it to somebody who by chance knows this course and how can some points be awarded? By the way, 35 %? it was possible to achieve 35% long time before midterm so anybody who stopped studying after that (and before the really serious studying began) will get the same certificate as those who did well all the time (Im dedicating a lot of time). I accepted the contidions so I will carry on but I ask if universities get funds depending on the number of certificates issued. There will be many participants with the certificate but still lacking any knowledge. I know, it's for free. But there could be still more quality here with the same effort by the staff.
FirstChildUserIdTAG: 1341242
FirstChildUserNameTAG: alesbadura
FirstChildCreateTimeTAG: 2013-03-20T11:28:02Z
FirstChildVoteTAG: 0
SecondChildTAG: But you can still use the knowledge in the future over the certificate. And I suppose whole of these knowledge'll be useful if you want to participate on the Stat2.2 and Stat2.3 as well.
SecondChildUserIdTAG: 1232601
SecondChildUserNameTAG: Firefly-2009
SecondChildCreateTimeTAG: 2013-03-20T12:12:18Z
SecondChildVoteTAG: 0
SecondChildTAG: The point is not about the certification.If you would mention it in your CV that i have done such and such a course, it just shows interests. This is not a degree certificate by which you can say , hey i a rubber stamp of Berkeley on my CV. If you are expecting something on those line, i would suggest that you take up courses that are administered in a controlled environments. Its all about gaining knowledge and edx staff are is doing a great job in that direction.In My Opinion Certifications are just small perks to sweeten the process of learning. Just enjoy the class and dont cry over two/marks or people passing without understanding, and all the unwanted stuff.
SecondChildUserIdTAG: 115240
SecondChildUserNameTAG: Sarathboss
SecondChildCreateTimeTAG: 2013-03-20T20:37:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Have you considered that they might not have asked the question as a joke? May be it is relevant to the course teachers to understand how well students are able to understand and follow simple english instructions? Just food for thought...
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-20T21:15:56Z
SecondChildVoteTAG: 0
FirstChildTAG: No objections.
FirstChildUserIdTAG: 1341242
FirstChildUserNameTAG: alesbadura
FirstChildCreateTimeTAG: 2013-03-20T12:29:11Z
FirstChildVoteTAG: 0
IndexTAG: 590
TitleTAG: 95% of People or 95% of the time?
The video for Lecture 7.1 at 2.39 minutes says
> so for 95% of the people your estimate is going to be correct to within 6
inches, but that's if the distribution is normal.
Should it be
> for 95% of the time your estimate is going to fall within 2 SD from the average?
UserIdTAG: 865969
UserNameTAG: Shanatova
CreateTimeTAG: 2013-03-20T04:52:40Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 1
FirstChildTAG: 3" = 1sd: so 6" = 2sd
FirstChildUserIdTAG: 1273210
FirstChildUserNameTAG: wwp
FirstChildCreateTimeTAG: 2013-03-20T05:15:35Z
FirstChildVoteTAG: 0
SecondChildTAG: I understand it as: say there are 100 people and we are to estimate for all of the 100 people in the distribution our estimates would fall in +/- 6 inches of the correct value for 95 of them.
(It can also be seen as: to do the above we will need to estimate a 100 times and 95 times we would fall in the 6" or 2sd range)
SecondChildUserIdTAG: 1243120
SecondChildUserNameTAG: NKum
SecondChildCreateTimeTAG: 2013-03-20T08:06:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeah, I think in this case, "people" is the same as "times", since every "Time" you check your estimate you're comparing it to one "person" :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-20T09:58:53Z
SecondChildVoteTAG: 0
IndexTAG: 591
TitleTAG: 1a
Attempting to guess a chick's weight - dangerous territory.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T04:50:53Z
VoteTAG: 11
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 4
FirstChildTAG: lol!
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-20T05:09:00Z
FirstChildVoteTAG: 0
FirstChildTAG: Ya know, that's not the only thing that needs to be treated with caution in this course. There was some example about wives being horizontal and husbands being vertical...and I just steered well clear of that one.
FirstChildUserIdTAG: 23003
FirstChildUserNameTAG: WH
FirstChildCreateTimeTAG: 2013-03-20T05:15:05Z
FirstChildVoteTAG: 3
FirstChildTAG: I did err on the safe side...
FirstChildUserIdTAG: 608203
FirstChildUserNameTAG: chauct
FirstChildCreateTimeTAG: 2013-03-20T06:21:27Z
FirstChildVoteTAG: 0
FirstChildTAG: And for babies weights (next ES) the P1 is the best: careless common sense $\not=$ statistical common sense ;-)
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-20T10:20:20Z
FirstChildVoteTAG: 1
IndexTAG: 592
TitleTAG: Good course - Thanks!
Just want to say thanks for doing such a good job on this course. Have the flu this week and feel awful, but was still able to understand the videos easily. Nicely done.
UserIdTAG: 1133176
UserNameTAG: sc2014
CreateTimeTAG: 2013-03-20T04:37:51Z
VoteTAG: 6
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Thank you Professors for this course. Have found it to be very helpful. The visual and numerical explanations help in understanding the concepts.
FirstChildUserIdTAG: 1243120
FirstChildUserNameTAG: NKum
FirstChildCreateTimeTAG: 2013-03-20T08:24:19Z
FirstChildVoteTAG: 4
SecondChildTAG: I feel the same, thank you professors! You have presented difficult statistics in a simple and straight forward way. I feel so happy that I understand the point of regression now. Previously, I studied some statistical books by myself, but I always stopped at SD, not able to move on. Now I feel confident to keep on studying.
SecondChildUserIdTAG: 1027696
SecondChildUserNameTAG: bhamgm
SecondChildCreateTimeTAG: 2013-03-20T09:44:35Z
SecondChildVoteTAG: 0
IndexTAG: 593
TitleTAG: hi so the passing score of 35% for this section is separate from the passing score of like 60% for the next 2 sections 2.2x and 2.3x right?
or if we get like 70% on this section, then is it somehow going to affect the other 2 scores cumulatively or something thereby making the full 3part course easier to pass? i would think not but i just want to make sure. i made a couple really dumb mistakes on the homework this week and on the midterm too so ya.
UserIdTAG: 985560
UserNameTAG: zoe3456
CreateTimeTAG: 2013-03-20T04:18:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: and when does stat 2.2x start?
FirstChildUserIdTAG: 985560
FirstChildUserNameTAG: zoe3456
FirstChildCreateTimeTAG: 2013-03-20T04:26:26Z
FirstChildVoteTAG: 0
FirstChildTAG: No, because we are not going to require that students have taken 2.1X to take 2.2X. They'll have to know the material, but it's fine if they've taken it elsewhere. The grading for each of 2.1X, 2.2X, and 2.3X will be self-contained.
There seems to be some problem with the Updates on the Landing Page at this moment, but once it is resolved there will be messages about the final and about 2.2X.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-20T07:00:29Z
FirstChildVoteTAG: 8
SecondChildTAG: ok thanks so much for clarifying this. it was just something i wondered whenever i checked my progress page.
SecondChildUserIdTAG: 985560
SecondChildUserNameTAG: zoe3456
SecondChildCreateTimeTAG: 2013-03-21T04:23:18Z
SecondChildVoteTAG: 0
IndexTAG: 594
TitleTAG: Problem 3, exercise 11
I wanted to mark the two alternatives but when I make the first click on the first alternative, appeared the X of wrong answer. I do not understand the sense of this question
UserIdTAG: 1270203
UserNameTAG: rollinroldan
CreateTimeTAG: 2013-03-20T03:38:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Just follow the instructions.
FirstChildUserIdTAG: 1293941
FirstChildUserNameTAG: CHHAVIMEHROTRA
FirstChildCreateTimeTAG: 2013-03-20T03:41:20Z
FirstChildVoteTAG: 0
IndexTAG: 595
TitleTAG: On 2A
I got a negative correlation of 0.99 based on my table calculations. I put -0.99 as the answer, and I got a wrong answer. Is r an absolute (|r|) value?
Or is my calculation of the correlation value wrong, in the first place?
UserIdTAG: 1288543
UserNameTAG: KFVillaprudente
CreateTimeTAG: 2013-03-20T03:21:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Think about what your answer almost is.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T03:24:22Z
FirstChildVoteTAG: 0
SecondChildTAG: Arg. 1.0 :(
SecondChildUserIdTAG: 1288543
SecondChildUserNameTAG: KFVillaprudente
SecondChildCreateTimeTAG: 2013-03-20T03:27:37Z
SecondChildVoteTAG: 0
SecondChildTAG: you don't have to do calculations.just plot a graph (hint for the next question)
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-20T03:37:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks. With 2B, I just did it with logic.
SecondChildUserIdTAG: 1288543
SecondChildUserNameTAG: KFVillaprudente
SecondChildCreateTimeTAG: 2013-03-20T10:36:12Z
SecondChildVoteTAG: 0
SecondChildTAG: the results should be the same with plot and with calculation
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-03-20T18:17:04Z
SecondChildVoteTAG: 0
SecondChildTAG: has anybody find the answer by calculate?
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-03-20T18:18:03Z
SecondChildVoteTAG: 0
IndexTAG: 596
TitleTAG: Make a certificate you can put on your CV
Hi all,
If anyone is interested in putting the course on their CV, I created a way to build your own certificates for online courses as you progress through them, but which are **credible enough to put on your CV/resume**, by embedding all the work that went into the course onto the certificate itself. I thought I'd mention it here in case anyone is interested.
Check it out at [www.accredible.com][1] for examples - it's all free! **I'd love to hear your thoughts as it's still a work in progress!**
[1]: https://www.accredible.com
UserIdTAG: 1452386
UserNameTAG: dking
CreateTimeTAG: 2013-03-20T02:45:34Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 597
TitleTAG: lec5.4 video has no download button
There is no download button below the video of Prof. A.
UserIdTAG: 1027696
UserNameTAG: bhamgm
CreateTimeTAG: 2013-03-20T02:30:44Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 598
TitleTAG: Missing something with 1a and 1b
Can someone please help me, I followed the same process for both problems:
I converted the height into standard units:
24-22 / .45 = ~4.4444444444
-
I estimated the weight
4.4444444444 * .75 = 3.33333333333
-
I converted back
3.33333333333 * .5 + 6 = ~ 7.66
-
But the system marked this incorrect.
For 1b I ended up with 5.8125
UserIdTAG: 912950
UserNameTAG: mikegfried
CreateTimeTAG: 2013-03-20T02:18:10Z
VoteTAG: 1
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 4
FirstChildTAG: Apart from the giving answers issue, just double check the value you are using for the mean.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T02:30:25Z
FirstChildVoteTAG: 0
FirstChildTAG: Check your steps again, and make sure you put in the right values
FirstChildUserIdTAG: 951385
FirstChildUserNameTAG: Jsmb
FirstChildCreateTimeTAG: 2013-03-20T02:43:02Z
FirstChildVoteTAG: 1
FirstChildTAG: Thank you for the responses! This is what happens when you try to do stats late at night. No credit but at least it wasn't an error in approach!
FirstChildUserIdTAG: 912950
FirstChildUserNameTAG: mikegfried
FirstChildCreateTimeTAG: 2013-03-20T03:08:03Z
FirstChildVoteTAG: 0
FirstChildTAG: You have to change 24 for 23
FirstChildUserIdTAG: 1041097
FirstChildUserNameTAG: JUANADORIS2013
FirstChildCreateTimeTAG: 2013-03-20T05:06:28Z
FirstChildVoteTAG: 0
SecondChildTAG: and 22 to 22.5
SecondChildUserIdTAG: 865969
SecondChildUserNameTAG: Shanatova
SecondChildCreateTimeTAG: 2013-03-20T12:58:32Z
SecondChildVoteTAG: 0
IndexTAG: 599
TitleTAG: data set plotting
can someone help with plotting data set on on the graph eg. that of es 9 problem (2) thanks.
either way 0-10 on y-axis and what to what on the x-axis????
UserIdTAG: 799816
UserNameTAG: JAMINx
CreateTimeTAG: 2013-03-20T01:44:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > A quiz consists of 10 multiple choice questions. Each question is marked either “right” or “wrong.”
So if you get 10 correct, 0 wrong.
9 correct, 1 wrong.
Plot, where X = correct, Y = wrong.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T02:09:56Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks susan
SecondChildUserIdTAG: 799816
SecondChildUserNameTAG: JAMINx
SecondChildCreateTimeTAG: 2013-03-20T23:38:24Z
SecondChildVoteTAG: 0
IndexTAG: 600
TitleTAG: This test has issues and is theory
I have said nothing about any of the test in the past, but this one has issues.
#1 problem 2 A & B does not allow for input of NA.
#2 problem 3 changed my answer upon submission.
UserIdTAG: 1273210
UserNameTAG: wwp
CreateTimeTAG: 2013-03-20T01:17:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: You only said it three times. If you said it four times, you would have convinced me.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-20T01:34:51Z
FirstChildVoteTAG: 2
SecondChildTAG: Again, a computer issue: This was entered into the subject line only. "If you said it four times, you would have convinced me." Stick to math grammar is not your strong suit.
SecondChildUserIdTAG: 1273210
SecondChildUserNameTAG: wwp
SecondChildCreateTimeTAG: 2013-03-20T02:01:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Pot? Kettle is calling!
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-20T13:05:19Z
SecondChildVoteTAG: 0
FirstChildTAG: > Stick to math grammar is not your strong suit.
You have made my day.
> ... but this one has issues.
Only if you didn't understand the concepts.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T02:12:06Z
FirstChildVoteTAG: 2
SecondChildTAG: troll
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-03-20T05:03:58Z
SecondChildVoteTAG: 0
IndexTAG: 601
TitleTAG: Why do we estimate lower?
on the second video of section 7A, we have data that says if you scored in the 80th percentile on the midterm, you're predicted to score in the 66th percentile on the final. I see why that's right according to the formula, but logically why would he be expected to score lower? it's like expecting an all 90's student to suddenly get a 70 on his next test?
UserIdTAG: 1326696
UserNameTAG: Maxkim
CreateTimeTAG: 2013-03-20T01:03:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: We have a bias that when we see a test score of 80%, that we think the student that produced that score is an all 80% scoring student. That one score is just a statistic sitting on a normal density curve, and as such, is subject to the: average, the sd, and the regression. Suppose the average is 70%, and we see a score of 60%, we might have a bias the other way, and assume that the student had a bad day, and must have scored higher on the final.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-20T02:05:42Z
FirstChildVoteTAG: 0
FirstChildTAG: The way I think about this is that each persons's score has two components: a sort of "core" component, and then some randomness thrown in. So for instance, maybe I am generally a B student, but sometimes I get a B+ because I'm having a good day, or a B- because I'm having a bad one.
So among students who are high-scoring, there will be a disproportionate number who are having an unusually good day. The "random" component of these scores is disproportionately high. You would expect, then, that when the dice are rolled again, a lot of these students will "revert to mean" and score lower. Not all of them, of course, but more than 50%.
This would not be true if there were no random element to the process. But then, with no randomness, we wouldn't need to estimate, we would expect perfect replication from observation to observation.
FirstChildUserIdTAG: 1258756
FirstChildUserNameTAG: Pre-Code
FirstChildCreateTimeTAG: 2013-03-20T03:06:58Z
FirstChildVoteTAG: 0
FirstChildTAG: If you take all the students on the 80th percentile of one exam, their average score on the other exam is around the 66th percentile (for the value of r in that particular problem). Not all of them will be at the 66th. Some will be above; some will even be above 80th. But overall, their average score will be at the 66th.
This is perhaps most easily understood by looking at those who did exceptionally well, say high 90's in percentile rank, on one test. On the second, they have almost nowhere to go but down.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-20T03:29:33Z
FirstChildVoteTAG: 0
IndexTAG: 602
TitleTAG: Help with 1B (graphical)
Would appreciate help understanding the "below 58%" answer graphically.
I can get the answer (53%) mathematically. Can also see how the answer will be below 70% graphically. However, after drawing several footballs, I am still unable to see graphically/intuitively how the answer has to be below 58%.
If someone could explain this with a graph/figure, it would be very helpful!
Thanks in advance.
UserIdTAG: 93947
UserNameTAG: TM1001
CreateTimeTAG: 2013-03-20T01:01:29Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 4
FirstChildTAG: Draw one football (not several). Put midterm on the horizontal and final on the vertical. Mark the vertical strip corresponding to the 70th percentile. Its center is at 58th. Now consider somebody at that final score. That person is on the horizontal strip at that level. Locate the center of that strip. That's your 53. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-20T03:26:10Z
FirstChildVoteTAG: 0
SecondChildTAG: The path taken should also be reversible. In the above problem, it is not. Answers to 1A and 1B should fall on the same line because of the very nature of a one-to-one linear relation.
SecondChildUserIdTAG: 155585
SecondChildUserNameTAG: rapra
SecondChildCreateTimeTAG: 2013-03-20T03:40:41Z
SecondChildVoteTAG: 0
SecondChildTAG: It is unforunately not reversible in the sense the mid point of a strip of X is not the mid point of a strip of Y as it is an oval and not the center of a circle.in fact it is an eccentric portion of an ellipse so they will not be the same traverse except at the midpoint of both (intersection of both mean values) it is like the projection of a light on a wall and floor from two separate light sources at an angle to each other will not be the same. The average of all people of a particular height is not the same as average the people of a particular weight
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-20T04:49:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Prof. A.,
Thank you very much for your response.
Following your directions (which I had tried independently several times before posting my question), it is very clear that the center of the horizontal strip at the 58th percentile final-score level is less than 70th percentile on the mid-term scale. However, it is still unclear to me how one can deduce graphically that it is less than 58th percentile on the mid-term scale.
SecondChildUserIdTAG: 93947
SecondChildUserNameTAG: TM1001
SecondChildCreateTimeTAG: 2013-03-21T03:39:05Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm having trouble visualising strips and centres. One problem is that I am not used to using standardised values in regression. I looked at it by switching the plotting variables (mid vs final and final vs mid).
> One of the students is on the 70th percentile of the final. Estimate this student’s percentile rank on the midterm.
We are using standardised values, $y=rx$, where $r$ is the correlation coefficient.
I've simulated some data with $r=0.4$. The red line is the 70th percentile for the final scores ($x=0.524$). The estimate midterm percentile is where the red line crosses the regression line (black line).
![enter image description here][1]
This is at $y=0.21$. ($y=rx=0.4 \times 0.524=0.21$)You use the applet, or similar, to find that this corresponds to 58%.
![enter image description here][2]
>A student is on the 58th percentile of midterm scores. This student’s final score is estimated to be:
Now we want to estimate the final from the midterm result. So plot again with midterm on the X axis. The red line is the 58th percentile ($x=0.21$). This crosses the regression line at $y=rx=0.4 \times 0.21=0.08$, which is the 53rd percentile (blue line).
![enter image description here][4]
![enter image description here][3]
[1]: https://edxuploads.s3.amazonaws.com/13637539069557855.png
[2]: https://edxuploads.s3.amazonaws.com/13637542631343601.png
[3]: https://edxuploads.s3.amazonaws.com/13637553881343625.png
[4]: https://edxuploads.s3.amazonaws.com/13637552611343647.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T05:35:49Z
FirstChildVoteTAG: 1
FirstChildTAG: The path is not reversible. There are two regression lines:
In standard units:
estimate of y = r.(actual x)
estimate of x = r.(actual y)
There are four variables in those equations, not two.
Draw a football; draw any off-center vertical strip on the football; mark the center of that vertical strip; draw the horizontal strip at the level of the center that you marked. Now look for the center of that horizontal strip. It's not where the vertical and horizontal strips intersect.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-20T07:09:04Z
FirstChildVoteTAG: 1
FirstChildTAG: can i get appletate for calculation of propbability with estimate
FirstChildUserIdTAG: 249360
FirstChildUserNameTAG: LalithaK
FirstChildCreateTimeTAG: 2013-03-20T07:25:43Z
FirstChildVoteTAG: 0
IndexTAG: 603
TitleTAG: 2B
I don't get why the estimate in 2B is a greater percentile than the given percentile of 40%. Shouldn't it be smaller?
UserIdTAG: 1002202
UserNameTAG: ury949
CreateTimeTAG: 2013-03-20T00:44:18Z
VoteTAG: 1
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: Regression towards the mean ...
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-20T00:50:35Z
FirstChildVoteTAG: 4
SecondChildTAG: This confused me too. I hope we'll get some explanation of this phenomenon in later lectures. Thanks for a great intro to Stats so far, Prof A!
SecondChildUserIdTAG: 1254854
SecondChildUserNameTAG: Iv0
SecondChildCreateTimeTAG: 2013-03-20T14:05:51Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL! In the very next lecture ... :)
SecondChildUserIdTAG: 1254854
SecondChildUserNameTAG: Iv0
SecondChildCreateTimeTAG: 2013-03-20T14:12:23Z
SecondChildVoteTAG: 0
IndexTAG: 604
TitleTAG: Answer of the problema 2
Answer of the problem 2 is easy. It is just to be relaxed and thinking about it. There were some examples about it on the text book and on the video class.
UserIdTAG: 1031814
UserNameTAG: Marivaldo
CreateTimeTAG: 2013-03-20T00:37:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 0
IndexTAG: 605
TitleTAG: Why not put a link to the textbook up in the top navigation bar?
http://statistics.berkeley.edu/~stark/SticiGui/Text/
Why not put a link to the textbook up in the top navigation bar?
UserIdTAG: 450628
UserNameTAG: ctr
CreateTimeTAG: 2013-03-20T00:36:31Z
VoteTAG: 2
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.4: Equation of the regression line
NumberOfReplyTAG: 3
FirstChildTAG: They could do that. Or we could bookmark it.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T00:54:25Z
FirstChildVoteTAG: 0
SecondChildTAG: Susan, I do think constructive criticism is actually welcome. I appreciate your many helpful comments to fellow students but couldn't help noticing you're quick to brush off criticism of the course materials.
I've been designing online course materials myself and welcomed any comment that could help me improve it. True, not every criticism is justified. And one certainly could argue that lack of convenience from a student's perspective is much less of an issue than actual mistakes in the materials.
Then again, this particular suggestion is extremely easy to implement; not easier than bookmarking a page, maybe, but considering the number of students on the course I think it would be worth the trouble.
SecondChildUserIdTAG: 387767
SecondChildUserNameTAG: JanDE
SecondChildCreateTimeTAG: 2013-03-20T13:00:44Z
SecondChildVoteTAG: 0
FirstChildTAG: This is probably because, Prof A's lectures and the Chapters on online text dont match up one to one. She points to the corresponding reading material (chapters or section there off) after each lecture sequence as part of the practice exercise.
I would think this is a better way to do it, for it makes things easier for us.
FirstChildUserIdTAG: 600543
FirstChildUserNameTAG: Pradha
FirstChildCreateTimeTAG: 2013-03-20T04:30:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Most likely, the edX software doesn't support doing that (yet...)
All the courses use the same framework (I think that's true); this discussion board, the arrangement of the week-to-week lectures, tests, wiki, etc. It may be that the web design simply doesn't have a place to put such a reference.
I expect the whole edX experience to improve over time. We're only in the second semester since it's started. (since public release; not counting beta testing)
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-20T21:37:31Z
FirstChildVoteTAG: 0
IndexTAG: 606
TitleTAG: Question re 1A
Can someone help explain why in 1A, I cannot assume that X is the midterm score, and Y is the final score and Y = 0.4 * X. I believe in the lecture, I was supposed to assume known variable as X, then solving for Y. But if the equation is Midterm Score = 0.4 * Final Score, wouldn't that conflict the answer of 1B, which assumes the reverse? Thank you for your help.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-20T00:20:29Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 1
FirstChildTAG: I too agree with you. It makes no sense. Once we establish a linear relation,
we should be able to travel back and forth on the same line. If it does not happen, then there is no use finding a correlation.
FirstChildUserIdTAG: 155585
FirstChildUserNameTAG: rapra
FirstChildCreateTimeTAG: 2013-03-20T03:33:30Z
FirstChildVoteTAG: 1
IndexTAG: 607
TitleTAG: Zeros?
Do we get questions wrong if we write .55 instead of 0.55.? I just submitted twice for each question just to get them wrong and I knew I got the right answer but I never plugged in the zeros. Lol
UserIdTAG: 990423
UserNameTAG: George95
CreateTimeTAG: 2013-03-20T00:09:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: >I just submitted twice for each question just to get them wrong and I knew I got the right answer
So why didn't you enter the right answer? I'm confused. And how did you know your answer was correct?
For 2A and 2B? Regardless of whether you put $0.55$ or $.55$, you would be wrong. Because that is not the correct answer.
I don't put the $0$ in when the answer is, for example, $.123$. Haven't been marked wrong yet.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T00:19:47Z
FirstChildVoteTAG: 0
IndexTAG: 608
TitleTAG: dear staff
I entered in 2c 1.66 and 0.41 (0.4165) but I got wrong. Would be pleased to check vs the right one to understand what I´ve missed.
Thanks
And very nice "gesture"… about the bonus, it encourage us to smile and follow. Not really about the points.
UserIdTAG: 1172070
UserNameTAG: alpisteasea
CreateTimeTAG: 2013-03-19T23:43:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Apart from talking answers before the deadline, check your rounding as what you did is not correct.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-19T23:54:16Z
FirstChildVoteTAG: 0
IndexTAG: 609
TitleTAG: Question about Midterm - Perhaps for a Staff Person
I have been pondering Question 2B since last week, and am very confused about how to calculate to find a percentile. In this question we had to find the 80th percentile. The solution shows 12 + (4/12) * (20-12). I cannot find anything in my notes that describes a formula for calculating to find a percentile. Can a staff person explain this to me?
UserIdTAG: 868031
UserNameTAG: CaliforniaViv
CreateTimeTAG: 2013-03-19T22:30:02Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: Go back to Lecture 2.4. It's well-explained there.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T22:42:24Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you for such a quick reply. I will go there and review the information.
SecondChildUserIdTAG: 868031
SecondChildUserNameTAG: CaliforniaViv
SecondChildCreateTimeTAG: 2013-03-19T23:40:03Z
SecondChildVoteTAG: 0
IndexTAG: 610
TitleTAG: Midterm exercise 1.b. How to solve it ?
During the exam, I used the R programming language to solve the 1.b. I did so:
> sd (c(33, 38, 40, 41, 38, 45, 42))
[1] 3.779645
>
So, I said, the closest was to 3.8.
Despite my expectations, the answer was wrong .
Please tell me how I was wrong, and how it should have been.
Thank you .
UserIdTAG: 18187
UserNameTAG: alinsoar
CreateTimeTAG: 2013-03-19T22:24:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: R uses $n-1$ in the denominator for the calculation (sample variance), we were told to use $n$ (population variance). So that is why you were wrong.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-19T22:37:48Z
FirstChildVoteTAG: 2
SecondChildTAG: thank you ! I did not know about the difference between sample and population !
SecondChildUserIdTAG: 18187
SecondChildUserNameTAG: alinsoar
SecondChildCreateTimeTAG: 2013-03-19T23:07:54Z
SecondChildVoteTAG: 0
SecondChildTAG: You can check in R by typing ?var or ?sd. This tells you (eventually) that R uses n-1.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-19T23:32:39Z
SecondChildVoteTAG: 0
IndexTAG: 611
TitleTAG: 7.1 one variable estimation - clarification needed
"Chebychev: For at least 75% of the people, the estimate will be correct to within 6 inches.
If the distribution of heights is roughly normal, then for about 95% of the people, the estimate will be correct to within 6 inches."
If in a normal distribution 95% are within 2 SD of the mean, then the mean will be correct to within a range of 12 inches, i.e +/- 6 inches from the mean. The wording on the slide could be interpreted to mean that 95% lie within 1 SD either side of the mean, a total of 6 inches.
UserIdTAG: 495068
UserNameTAG: quake
CreateTimeTAG: 2013-03-19T22:12:19Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 1
FirstChildTAG: Um, no?
If you choose the Average(ok, the mean, if you prefer) as your estimate, then the maximum error you can make is 2SD, or 6 inches. You are picking the middle value of that 12 inches range ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T22:35:29Z
FirstChildVoteTAG: 0
IndexTAG: 612
TitleTAG: book's practice exercise 9.6 (which carries to 9.10)
for rotated question with the data listd below, I read it to mean the wife was on the x axis which would make the husband's iq for the 1st question __3__ SDs from the mean. How should I have read the question or is the solution incorrect? The mean data use seems reversed from what it should be. Questions following it suffer from similar consequence. 9.10 seems to disassemble in logic as a result.
The point of averages of these data is (111.05, 103.2), the SD of the husbands' IQs is 7.84, and the SD of the wives' IQs is 7.82. The correlation coefficient of the IQs of husbands and wives is r = 0.41. The value of wife's IQ of the regression line (for regressing the IQs of wives against the IQs of their husbands) at husband's IQ= 126.73 is ...
UserIdTAG: 1232482
UserNameTAG: bhunji
CreateTimeTAG: 2013-03-19T22:10:17Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 3
FirstChildTAG: No, the **husbands'** IQs are on the x axis, and their average is 111.05.
Remember, x is the known data, y the unknown.
Then $z_x=\frac{126.73-111.05}{7.84}=2$. I'm sure you can take over from here ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T22:38:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Agreed, but that is not how the table is labeled, it is labeled wives vs. husbands. And if you check the data points, the wives are on the x axis. the questions is backwards.
SecondChildUserIdTAG: 1307321
SecondChildUserNameTAG: lvasta
SecondChildCreateTimeTAG: 2013-03-20T03:16:56Z
SecondChildVoteTAG: 0
FirstChildTAG: > the wives are on the x axis.
Not on the graph I was given. Wives were on the Y. Wives vs husbands. Y vs X.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T03:32:18Z
FirstChildVoteTAG: 0
FirstChildTAG: I think the figures are different every time you re-load the question - In my graph the men were puching way above their weight, intellectually - the average IQ for the men was about 80
FirstChildUserIdTAG: 42051
FirstChildUserNameTAG: cjscott
FirstChildCreateTimeTAG: 2013-03-20T13:44:03Z
FirstChildVoteTAG: 0
IndexTAG: 613
TitleTAG: certificate
can i pass the course just by taking the final exam?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-19T21:53:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: This is how the grades are distributed:
Grades will be calculated using the following weights:
Exercise Sets: 50%
Midterm: 20%
Final exam: 30%
You need 35% to pass the course. Taking only the final exam, you would not complete all the requirements, but you still have time to finish exercises 9-11 and there will be exercise 12 next week. As they are going to remove the two lowest grades to compute the exercise sets grade, you will have 4/10 exercises, which can give to you up to 20% of the final grade. Thus, you have 20% from exercises and 30% from the final exam, you can pass if you do well on them.
FirstChildUserIdTAG: 1024776
FirstChildUserNameTAG: guil
FirstChildCreateTimeTAG: 2013-03-19T22:16:03Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks dude:)
SecondChildUserIdTAG: 1157619
SecondChildUserNameTAG: princetongirl
SecondChildCreateTimeTAG: 2013-03-19T22:56:10Z
SecondChildVoteTAG: 0
FirstChildTAG: I finished mid term exams 5 hrs after deadline of 13th march - will i get certificate? please guide
FirstChildUserIdTAG: 1267420
FirstChildUserNameTAG: axay_shah
FirstChildCreateTimeTAG: 2013-03-19T23:07:02Z
FirstChildVoteTAG: 0
SecondChildTAG: As guil said above, you get the certificate if you obtain $\ge 35\%$ over all.
I didn't do the midterm, due to other commitments, but I will get the certificate as I have the required 35% from just doing the problem sets.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-19T23:34:45Z
SecondChildVoteTAG: 0
SecondChildTAG: You could also make your own certificate at [www.accredible.com][1] (the idea is you prove the credibility of your learning by uploading proof of your work & expertise).
[1]: http://www.accredible.com
SecondChildUserIdTAG: 1452386
SecondChildUserNameTAG: dking
SecondChildCreateTimeTAG: 2013-03-20T02:41:42Z
SecondChildVoteTAG: 0
IndexTAG: 614
TitleTAG: Problem 2
i cant make out what the question is asking. Have been thinking about it for hours. What it seems to ask (as per my understanding) is whether the r is positive or negative. Cant make out how to calculate r for this. If someone can help me on this then i will be really grateful
UserIdTAG: 1216795
UserNameTAG: NasirK
CreateTimeTAG: 2013-03-19T21:37:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: There are plenty of posts about this. Plot your data. No need for any calculation. Look at the line of points, and enter the number that you think describes the correlation.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-19T21:46:48Z
FirstChildVoteTAG: 3
FirstChildTAG: @NasirK, a useful insight could be to consider the question in the direction of the previously solved problem sets last week. You will see a similar question providing a clue on how the mathematical expression to solve this problem will look like. Hope this suggestion helps!
FirstChildUserIdTAG: 1114838
FirstChildUserNameTAG: abass01
FirstChildCreateTimeTAG: 2013-03-20T15:33:46Z
FirstChildVoteTAG: 0
IndexTAG: 615
TitleTAG: Please clarify your references
It would make life a bit easier if you could make your references clearer. I thought that Text Ch5-8 meant section 8 in chapter 5, in the same way that 5-5 is an exercise and 5-4 is a figure, but what I think you actually mean is chapters 5 to 8. Could you also provide links to the textbook when you talk about it - it took me a while to find it buried at the bottom of the Wiki. Thanks
UserIdTAG: 164614
UserNameTAG: LuketheEngineer
CreateTimeTAG: 2013-03-19T21:32:46Z
VoteTAG: 6
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: Hi Luke,
I feel the same way! :/
Here is are the links to the online textbook by Professor Stark below. Unfortunately, there is no way to link to the exercises directly except to scroll to them by hand.
Chapter 5 - Scatterplots
------------------------
http://statistics.berkeley.edu/~stark/SticiGui/Text/scatterplots.htm
(Review Exercises 5-5 and 5-6)
Chapter 6 - Association
-----------------------
http://statistics.berkeley.edu/~stark/SticiGui/Text/association.htm
(Review Exercise 6-4)
Chapter 7 - Correlation and Association
---------------------------------------
http://statistics.berkeley.edu/~stark/SticiGui/Text/correlation.htm
(Review Exercises 7-2, 7-3, 7-4, and 7-5)
Chapter 8 - Computing the Correlation Coefficient
-------------------------------------------------
http://statistics.berkeley.edu/~stark/SticiGui/Text/computeR.htm
(No exercises to review)
Hope this is helpful to you all...
FirstChildUserIdTAG: 963897
FirstChildUserNameTAG: lightbulb
FirstChildCreateTimeTAG: 2013-03-20T01:09:35Z
FirstChildVoteTAG: 8
SecondChildTAG: Lightbulb, thanks!! you save me a lot of time,
Pato
SecondChildUserIdTAG: 689072
SecondChildUserNameTAG: pato54
SecondChildCreateTimeTAG: 2013-03-20T03:13:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here - thanks!
SecondChildUserIdTAG: 387767
SecondChildUserNameTAG: JanDE
SecondChildCreateTimeTAG: 2013-03-20T10:33:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Really helpful, thank you! I was about to recommend the same idea. direct links make a ton of sense.
SecondChildUserIdTAG: 162716
SecondChildUserNameTAG: nathanleiby
SecondChildCreateTimeTAG: 2013-03-20T19:46:19Z
SecondChildVoteTAG: 0
IndexTAG: 616
TitleTAG: How to calculate the SD?
Hey Guys!
Sorry to bother you, but I can't remember how to calculate the SD of a list. In the example used in lecture 6.2 the x and y values are to be transformed in standard units. For this one needs the Average as well as the SD of each of those 'lists' but I just can't remember how to calculate the SD.
Anyone able to help me out?
Highly appreciated!
Thank you!
UserIdTAG: 1275617
UserNameTAG: SarahLie
CreateTimeTAG: 2013-03-19T20:59:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: FIRST FIND MEAN, THEN DEVIATE EVERY SINGLE DATA FROM THE MEAN, THEN SQUARE EACH OF THE RESULT THEN AGAIN FIND THE MEAN OF YOUR RESULTS AND AT THE END JUST TAKE SQUARE ROOT.
FirstChildUserIdTAG: 1250042
FirstChildUserNameTAG: DrAnwar
FirstChildCreateTimeTAG: 2013-03-19T21:56:46Z
FirstChildVoteTAG: 0
SecondChildTAG: thank you :)
SecondChildUserIdTAG: 1275617
SecondChildUserNameTAG: SarahLie
SecondChildCreateTimeTAG: 2013-03-19T22:03:48Z
SecondChildVoteTAG: 0
SecondChildTAG: whoa, careful with those caps Dr :|
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-19T22:31:28Z
SecondChildVoteTAG: 0
SecondChildTAG: If you forget something like that, take the time to look it up - that'll help cement in into your brain. (at least it does to mine...)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T18:12:26Z
SecondChildVoteTAG: 0
FirstChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/Text/gloss.htm#sd
FirstChildUserIdTAG: 18187
FirstChildUserNameTAG: alinsoar
FirstChildCreateTimeTAG: 2013-03-19T22:16:50Z
FirstChildVoteTAG: 0
IndexTAG: 617
TitleTAG: Exercise Set 11...done !
I got a score of 100%,just follow carefully the videos and read the textbook and you will succeed like me, good luck to everyone !
UserIdTAG: 773907
UserNameTAG: Redouanekh
CreateTimeTAG: 2013-03-19T20:16:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Good job ! i got a perfect score too. you're right you just have to watch the videos and do the exercice set carefully and take the time to answer.
FirstChildUserIdTAG: 816905
FirstChildUserNameTAG: Benzino
FirstChildCreateTimeTAG: 2013-03-19T22:53:45Z
FirstChildVoteTAG: 0
IndexTAG: 618
TitleTAG: Trouble with applet
hello, I have trouble with my applet - nothing is see there - no nombers, no graphs, no z scale - co i can´t do exercises ... could you help me?
UserIdTAG: 1137412
UserNameTAG: Lukes89
CreateTimeTAG: 2013-03-19T19:43:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: couple of options - there may be an issue with your internet browser. Try restarting it. Alternatively, try a different internet browser (I use chrome and it works fine, though I'm sure IE will also work with the applet).
FirstChildUserIdTAG: 941165
FirstChildUserNameTAG: bp84
FirstChildCreateTimeTAG: 2013-03-19T20:44:19Z
FirstChildVoteTAG: 0
SecondChildTAG: I used reinstal Java, 3 types of browsers and nothing work ...
SecondChildUserIdTAG: 1137412
SecondChildUserNameTAG: Lukes89
SecondChildCreateTimeTAG: 2013-03-19T20:48:25Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/browser-setting-appletsif-they-do-not-work/
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-19T21:01:02Z
SecondChildVoteTAG: 0
IndexTAG: 619
TitleTAG: problem 2b
i apply same method for 2A and 2B, but for 2B, I received a wrong answer from the system.
what is the problem?
UserIdTAG: 1140440
UserNameTAG: ocantea
CreateTimeTAG: 2013-03-19T19:01:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 3
FirstChildTAG: Just keep trying. Maybe deriving the formula for yourself will help with clarity.
FirstChildUserIdTAG: 1270753
FirstChildUserNameTAG: RobLL
FirstChildCreateTimeTAG: 2013-03-19T19:39:08Z
FirstChildVoteTAG: 0
FirstChildTAG: can someone know if we get from the applet
0.654
we need to enter 0.654 or 65.4 as the rank
FirstChildUserIdTAG: 1047522
FirstChildUserNameTAG: daveBen
FirstChildCreateTimeTAG: 2013-03-19T19:46:36Z
FirstChildVoteTAG: 0
SecondChildTAG: the answer should be 65.4
i wasted all my tries to get it
probably 4 points due to my bad english :-)
SecondChildUserIdTAG: 1047522
SecondChildUserNameTAG: daveBen
SecondChildCreateTimeTAG: 2013-03-19T20:01:11Z
SecondChildVoteTAG: 0
FirstChildTAG: If you really used the same correct method, then the results should both be correct. Don't ignore the signs.
Note that the result of 2B might be a little unexpected if you've not watched the Lectures for Section 7b yet, but it *is* correct.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T22:28:46Z
FirstChildVoteTAG: 0
IndexTAG: 620
TitleTAG: I cant find the Graph to answer question 2 and 3
I cant find the Graph to answer question 2 and 3 , could someone help me out please
UserIdTAG: 823986
UserNameTAG: Nicholasborsotto
CreateTimeTAG: 2013-03-19T18:39:35Z
VoteTAG: 2
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: There is none for 2 and 3. Perhaps re-read the questions?
FirstChildUserIdTAG: 1059783
FirstChildUserNameTAG: aguirrem
FirstChildCreateTimeTAG: 2013-03-19T18:53:54Z
FirstChildVoteTAG: 0
SecondChildTAG: I need help too for exercice 2, what we need to do?
SecondChildUserIdTAG: 1243226
SecondChildUserNameTAG: ericvidal94
SecondChildCreateTimeTAG: 2013-03-19T19:09:48Z
SecondChildVoteTAG: 0
SecondChildTAG: You don't need a graph, everything is in the question
SecondChildUserIdTAG: 164614
SecondChildUserNameTAG: LuketheEngineer
SecondChildCreateTimeTAG: 2013-03-19T21:16:46Z
SecondChildVoteTAG: 0
SecondChildTAG: i cant make out what the question 2 is asking. Have been thinking about it for hours. What it seems to ask (as per my understanding) is whether the r is positive or negative. Cant make out how to calculate r for this. If someone can help me on this then i will be really grateful
SecondChildUserIdTAG: 1216795
SecondChildUserNameTAG: NasirK
SecondChildCreateTimeTAG: 2013-03-19T21:36:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Draw the graphs yourself if you need to. You can do it easily, the pair of values are related as y=f(x) (see ES7).
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T22:25:22Z
FirstChildVoteTAG: 0
IndexTAG: 621
TitleTAG: This is where all the intuition broke down!
This video makes me feel very uneasy. Up to this point, the correlation coefficient was the measure of how tightly distributed the data is. Now, it's the slope of the line of averages. I'm guessing this has to do with the conversion to standard units, but it's not clear why. I know Prof A will be posting an algebraic derivation soon, but I'm more interested in the intuition. Why is it that the slope of the line of averages in standard units is always less than 1? Why is the slope of this line representative of how closely related the data is?
UserIdTAG: 106436
UserNameTAG: aliqasim
CreateTimeTAG: 2013-03-19T18:39:02Z
VoteTAG: 4
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 2
FirstChildTAG: The intuition comes from the example that she gave when you have only one variable, the "best" choice/estimate would be the average and she showed the error would be the smallest.
As the regression coefficient allows you to "plot" a line on the path of averages between the two variables, you would be able to estimate the "best" option for any given x.
It is interesting to note that if you keep doing this several times, estimating one time, then get the result and estimate for the other variable and do it again and again, you may, eventually, get to the point of averages.
FirstChildUserIdTAG: 1024776
FirstChildUserNameTAG: guil
FirstChildCreateTimeTAG: 2013-03-19T21:20:25Z
FirstChildVoteTAG: 1
FirstChildTAG: Don't loose the intuition cause if you convert both variables to standard units then both averages will be 0 correct? Also the slope of the line will be r correct? Now what is the correlation coefficient measure again? The spread of what? And what is the regression line again? Do you think that the regression line has a direct relationship with the pairs of data on x & y axis? Do you think that units or scales or even what is on x and y axis matters?
Of course not cause regression line is nothing more than **regression to mediocrity** it does what r does for the standard units. Read and listen carefully to what professor has analyzed so remarkably that you won't be able to find in any book in the world. Now find your intuition to try to understand why not above 1 or less than -1. Unless you can understand the Cauchy Swartz inequality do some Cartesian geometry magic box if you want. Draw a box with the Cartesian axes and draw the lines that pass from each one of the corners. That's a 45 degrees line to the Cartesian axes. Now you have created lines with slope -1 or +1. Try to create clouds of points that the regression lines is at first are the lines that you have drawn and after to other lines.calculate r.if r =1 or -1 then all points are on one of the lines you have drawn. Else? What is happening in any other case? Can you tell? Draw regression lines from one side of the rectangle to the other. Try to find the equations of the lines a*x + b .calculate r. Was it helpfull?
FirstChildUserIdTAG: 1239975
FirstChildUserNameTAG: Xenofon
FirstChildCreateTimeTAG: 2013-03-20T20:36:19Z
FirstChildVoteTAG: 0
IndexTAG: 622
TitleTAG: Post pone the due date please!!!!!!!
Dr. AA,
Please post this week's assingment for another week!!!! there's too much to understand at a time!!!!!!
UserIdTAG: 1118635
UserNameTAG: imati
CreateTimeTAG: 2013-03-19T18:02:33Z
VoteTAG: 8
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: forreal. um read 4 chapters this week n do the exercises? its like we had 3 weeks just to read n grasp the last 3 chapters sheesh.
FirstChildUserIdTAG: 985560
FirstChildUserNameTAG: zoe3456
FirstChildCreateTimeTAG: 2013-03-19T21:23:38Z
FirstChildVoteTAG: 3
SecondChildTAG: Glad I had a snow day from work today. I spent nearly the whole day learning this material. We're definitely doing stuff I've never done before now.
SecondChildUserIdTAG: 1153828
SecondChildUserNameTAG: Matt2edX
SecondChildCreateTimeTAG: 2013-03-20T00:05:36Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too, but I blame my own time management...
Uh, that came off as harsh; I don't mean it that way. Just an observation that **I** need to work on homework sooner after it's posted. I didn't mean it as a comment about other people.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T18:16:43Z
SecondChildVoteTAG: 0
SecondChildTAG: I just wish to have another day to finish it!
SecondChildUserIdTAG: 1224485
SecondChildUserNameTAG: sithinhdf
SecondChildCreateTimeTAG: 2013-03-20T23:26:20Z
SecondChildVoteTAG: 0
FirstChildTAG: ANOTHER DAY MORE PLEASE !!
FirstChildUserIdTAG: 1062477
FirstChildUserNameTAG: alejandra-hd
FirstChildCreateTimeTAG: 2013-03-20T23:31:44Z
FirstChildVoteTAG: 0
IndexTAG: 623
TitleTAG: whats the matter
"Problem 2
A quiz consists of 10 multiple choice questions. Each question is marked either “right” or “wrong.” Each right answer gets 5 points, and 1 point is taken off for each wrong answer.
In what follows, fill in the blank; if you think there is not enough information to answer the question, enter NA."
But:
"Invalid input: could not interpret 'NA.' as a number"
My answer have been saved but not graded.
UserIdTAG: 834676
UserNameTAG: vmvedad
CreateTimeTAG: 2013-03-19T17:50:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 4
FirstChildTAG: A quick check on the board would have got you the answer.
Yes, it's a "bug", but one that helps you. Now you know that the right answer is a number, and you didn't have to spend a check to learn it ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T18:09:03Z
FirstChildVoteTAG: 0
SecondChildTAG: it happened the same with me. Can´t get my answers graded.
SecondChildUserIdTAG: 1172070
SecondChildUserNameTAG: alpisteasea
SecondChildCreateTimeTAG: 2013-03-19T20:40:16Z
SecondChildVoteTAG: 0
FirstChildTAG: right ans could be +/- some value of correlation and for sure "NA". You have to work on excell: column -A Vs Colum -B fill values 10 right (5*10) Vs 0 wrong (1*0) than all the way upto 1 right or 0 right. Use function =CORREL hope that will give you some # or idea.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-19T18:39:00Z
FirstChildVoteTAG: 3
SecondChildTAG: An excellent formula in excel. thanks navgir
SecondChildUserIdTAG: 417448
SecondChildUserNameTAG: Oldzigi
SecondChildCreateTimeTAG: 2013-03-20T20:07:04Z
SecondChildVoteTAG: 0
FirstChildTAG: remember that the relation b/w the two variables are linear b/c if you see the change in the result is somewhat constant.
result is clear if you have seen the 3th video
FirstChildUserIdTAG: 1250042
FirstChildUserNameTAG: DrAnwar
FirstChildCreateTimeTAG: 2013-03-19T19:44:10Z
FirstChildVoteTAG: 0
SecondChildTAG: i cant make out what the question is asking. Have been thinking about it for hours. What it seems to ask (as per my understanding) is whether the r is positive or negative. Cant make out how to calculate r for this. If someone can help me on this then i will be really grateful
SecondChildUserIdTAG: 1216795
SecondChildUserNameTAG: NasirK
SecondChildCreateTimeTAG: 2013-03-19T21:34:56Z
SecondChildVoteTAG: 0
SecondChildTAG: For both 2a and 2b:
The problem asks for *r* as a number. It *can* be either positive or negative.
If you are still stuck, write down the values for the two variables in a table, and a graph. It's easy, there's only 10 pairs and they are related with a simple formula(see ES7).
If you still can't tell *r* from the graph, then calculate it as explained in the lectures.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-19T22:19:13Z
SecondChildVoteTAG: 0
FirstChildTAG: think slope up or down
FirstChildUserIdTAG: 1113869
FirstChildUserNameTAG: djr270
FirstChildCreateTimeTAG: 2013-03-19T22:12:14Z
FirstChildVoteTAG: 0
IndexTAG: 624
TitleTAG: Problem 1
That was tricky :)
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-19T17:24:48Z
VoteTAG: 3
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: I was too spontaneous and got it wrong. A frequent problem for me on answering questions. I don't let myself think through the problem!
FirstChildUserIdTAG: 1061881
FirstChildUserNameTAG: kristen1trigen
FirstChildCreateTimeTAG: 2013-03-19T17:44:32Z
FirstChildVoteTAG: 5
SecondChildTAG: You are not alone with that. I am learning to really just stop and analyze even if it takes additional time and reasoning. Once I do that, I get the answer right. I just answer what I think I know, I get it wrong.
SecondChildUserIdTAG: 4612
SecondChildUserNameTAG: Susnaj
SecondChildCreateTimeTAG: 2013-03-19T19:58:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here. We probably need more practice exercises that force us to think twice about what we think we know
SecondChildUserIdTAG: 338910
SecondChildUserNameTAG: emiliobr
SecondChildCreateTimeTAG: 2013-03-20T09:37:14Z
SecondChildVoteTAG: 0
SecondChildTAG: me too. I've taken to printing the exercises, answering on paper, going away for a bit & then coming back.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-20T11:39:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeap..... another one here
SecondChildUserIdTAG: 257327
SecondChildUserNameTAG: sebastian_sagv
SecondChildCreateTimeTAG: 2013-03-20T17:17:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I took a while to think about it, and still got it wrong. Another 1/2 hour and the test deadline is over and we can discuss it in detail...
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-20T23:04:32Z
SecondChildVoteTAG: 0
IndexTAG: 625
TitleTAG: Thanks!
Thanks Prof! I have a new appreciation for scatter plot.
UserIdTAG: 246991
UserNameTAG: spatra
CreateTimeTAG: 2013-03-19T17:23:05Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 626
TitleTAG: MIdterm Average/Median
I'm curious about the class average and median on the midterm. If the staff could post it, I would really appreciate it.
UserIdTAG: 1327840
UserNameTAG: Sapphire38
CreateTimeTAG: 2013-03-19T17:08:51Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Maybe we'll get to see those data in the Final? :D
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T17:39:21Z
FirstChildVoteTAG: 1
FirstChildTAG: Creating histogram based on our data results would be nice too;)
FirstChildUserIdTAG: 1263818
FirstChildUserNameTAG: Ruteq
FirstChildCreateTimeTAG: 2013-03-19T21:15:28Z
FirstChildVoteTAG: 0
IndexTAG: 627
TitleTAG: Answers
Please, could you show the answers, as I could not figure them out for some questions?
Thank you!
UserIdTAG: 288327
UserNameTAG: IsabellaVel
CreateTimeTAG: 2013-03-19T16:47:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: They will be there after the due date.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T17:11:12Z
FirstChildVoteTAG: 0
IndexTAG: 628
TitleTAG: Can we have reminders on our personal emails/SMS's for the exams?
Hi Team (edx),
We are glad to be a part of this valuable course but somehow we may miss several important lectures/tests/exams. Can we have a mechanism where we will get alerts from management about important updates. This will be a great help to us.
Regards,
Misba
UserIdTAG: 1274394
UserNameTAG: misba_masood
CreateTimeTAG: 2013-03-19T15:33:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Really? This request doesn't embarrass you? They already posted a schedule. This is a college course, and you should be responsible for you own due dates. Why don't you set up reminders on a calendar program, or if that is unavailable to you, make your own hard-copy of a calendar?
FirstChildUserIdTAG: 374593
FirstChildUserNameTAG: lf2223
FirstChildCreateTimeTAG: 2013-03-19T16:48:47Z
FirstChildVoteTAG: 5
SecondChildTAG: The person may ask but it is up to the faculty and organizers to accede or not regard the request.So please do not make personal comments about another person.That breaks one of the forums discussion rules
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-19T17:33:50Z
SecondChildVoteTAG: 0
FirstChildTAG: Use Google calender and set alerts by email, reminder or something in schedule.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-19T17:08:49Z
FirstChildVoteTAG: 4
IndexTAG: 629
TitleTAG: Area under the curve between two points
Is there any method to find the area under the curve between two points **without** using the applet? As the closed form of the integral of the function is not defined, out of curiosity, i would like to know what algorithm might the applet be using? Is it feasible to use such algorithm manually (by hand) and do the calculations?
UserIdTAG: 106510
UserNameTAG: balavignesh
CreateTimeTAG: 2013-03-19T15:24:08Z
VoteTAG: 1
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 3
FirstChildTAG: There actually is a definite integral for that, and I assume the applet makes use of it.
You could calculate it by "hand" if you're into calculus...it's just that it's an awful mess: Prasannasimha attempted it [here][1], and you could also Google for it. Good luck! :D
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/proof-area-standard-normal-curve-1/
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T15:49:44Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you :)
SecondChildUserIdTAG: 106510
SecondChildUserNameTAG: balavignesh
SecondChildCreateTimeTAG: 2013-03-19T16:12:14Z
SecondChildVoteTAG: 0
SecondChildTAG: There are approximations that can be used to generate the normal curve values and that is how it is done.It cannot be expressed as a "standard series" in the classical manner
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-19T16:14:40Z
SecondChildVoteTAG: 0
FirstChildTAG: You can avoid the applet by using a "Normal Table."
e.g. http://www.sjsu.edu/faculty/gerstman/EpiInfo/z-table.htm
FirstChildUserIdTAG: 904020
FirstChildUserNameTAG: KC8ZKF
FirstChildCreateTimeTAG: 2013-03-19T16:04:17Z
FirstChildVoteTAG: 1
FirstChildTAG: > Is there any method to find the area under the curve between two points without using the applet?
Several ways. As said, solve the integral as best you can. Or use Normal Tables. Or use one of the many statistical/mathematical programs (e.g. R, Matlab, Minitab, JMP, SPSS, SAS, S+, etc etc). Even Excel.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-19T20:38:14Z
FirstChildVoteTAG: 0
IndexTAG: 630
TitleTAG: After the test, unable to submit it
Hay All,
Has anyone any idea how to submit this test coz its still showing pending state. I have completed this test long back.
UserIdTAG: 1274394
UserNameTAG: misba_masood
CreateTimeTAG: 2013-03-19T15:22:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi Misba,
If you did not submit your results before the deadline, you cannot submit it any more at all.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-19T15:37:47Z
FirstChildVoteTAG: 0
IndexTAG: 631
TitleTAG: Suggested improvements to course (Week 4)
In this most recent week (Week 4), I found the differences between Professor Adhikari's lectures and the text to be much greater, and that consuming both was unnecessary. The lectures were very focused and clear. The text is broader, the mathematical representation very poor, and the concept explanation is generally more confusing.
My frustration with the normal curve "applet" gave me cause to go and find the [Standard Normal Table][1], which is a much better tool for the calculation tasks. I understand the desire for visualization and interactivity, but the function is bad. The sliders need to be made larger, so that they can be placed accurately.
[1]: http://en.wikipedia.org/wiki/Standard_normal_table "Standard Normal Table"
UserIdTAG: 1285276
UserNameTAG: prausch
CreateTimeTAG: 2013-03-19T15:21:52Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: You can adjust the sliders using the keyboard. It becomes very easy to use the applet if you do.
Then again, you can use the Table and be perfectly happy. To each his own :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T15:51:22Z
FirstChildVoteTAG: 1
FirstChildTAG: Use the right and left arrow key.One of the members on this list told me about it and it made my life from pain to pleasure as I was wringing my hands everytime I tried to "fix the slider"
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-19T16:18:19Z
FirstChildVoteTAG: 1
IndexTAG: 632
TitleTAG: about of the question 2
tried many times the answer, but didn't get right... someone could help me understand!!please
UserIdTAG: 1212544
UserNameTAG: tiagocomeon
CreateTimeTAG: 2013-03-19T14:50:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: What does r represents? It shows how closely related your x and y are. In problem 2, y is a function of x. What does this mean for r?
Also, if you are stuck, plot the values into a quick graph. There are only 10 pairs of values for each problem, so it's not too long or hard to do.
If you are *really* stuck using intuition, you can calculate r with the method explained in lecture 6.2. You'll likely have to round 2a unless you calculate with many significant digits.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T16:02:29Z
FirstChildVoteTAG: 0
IndexTAG: 633
TitleTAG: One Last Chance to score 100%
Has anyone here not getting a score of 100% on one of their exercises? I have not managed a single perfect score.
UserIdTAG: 861599
UserNameTAG: Nam2point0
CreateTimeTAG: 2013-03-19T14:23:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: I scored 100% on ES3 and ES9, but exercises have been pretty hard and have had a couple of 60´s too... So I guess at the end been consistent is what really matters.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-03-19T14:47:49Z
FirstChildVoteTAG: 0
FirstChildTAG: I dropped two marks on one ES, which was badly designed. I also dropped two marks on another, because I was tired at the time. All the others were 100%.
FirstChildUserIdTAG: 270738
FirstChildUserNameTAG: sheardp
FirstChildCreateTimeTAG: 2013-03-19T14:53:39Z
FirstChildVoteTAG: 0
FirstChildTAG: 100% in all exercises except two (one already dropped). 100% in MidTerm. Total score 70% (50%+20%).
FirstChildUserIdTAG: 1210009
FirstChildUserNameTAG: GIAN66
FirstChildCreateTimeTAG: 2013-03-19T15:53:47Z
FirstChildVoteTAG: 0
SecondChildTAG: Same here,but week 4 (yet to submit) will change it if submission deadline is not extended. Although week 4 is most comprehensive & lengthy and has the most core parts of stat2.1x , but given the midterm , the least time has been provided to submit it. Not all students are with maths background & learning is a time consuming process. So deadline to submit should be extended. Prof A. kindly help.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-19T17:33:46Z
SecondChildVoteTAG: 0
SecondChildTAG: You could have done ES9 in the time it took to write that message :P
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-19T17:36:14Z
SecondChildVoteTAG: 0
FirstChildTAG: I got wrong a problem back in ES2, but that doesn't count anymore. The real problem is that I messed up in the midterm with Problem 4B, so the best score I can currently hope for now is 98%.
I don't mind all that much though. Learning is what's important here :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T16:06:23Z
FirstChildVoteTAG: 3
SecondChildTAG: Same here ... but as you said, the score does not really matter, what we are after is the learning!
SecondChildUserIdTAG: 99863
SecondChildUserNameTAG: pramode_ce
SecondChildCreateTimeTAG: 2013-03-19T16:11:51Z
SecondChildVoteTAG: 0
FirstChildTAG: I scored 100 on the exercises of pure computation, not on that ones that required some feeling of the subject.
The course is pretty difficult, even if it is conceived for very beginners.
I love the course.
FirstChildUserIdTAG: 18187
FirstChildUserNameTAG: alinsoar
FirstChildCreateTimeTAG: 2013-03-19T22:29:50Z
FirstChildVoteTAG: 0
FirstChildTAG: The best that I can hope for is probably between 96% - 98%. In the early exercises, I messed up with some simple questions since I was just warming up to the course pedagogy and expectations. Have secured 100% in 5 ES and also the midterm.
All we are going to get is a nice certificate of completion. Does it really matter whether the score is 100% or 96% or 90% or 80%?
How can we better leverage this on-line distance education MIT exposure is the obvious question? Does anybody have any thoughts on the same?
FirstChildUserIdTAG: 413463
FirstChildUserNameTAG: Venkataramani
FirstChildCreateTimeTAG: 2013-03-20T03:43:42Z
FirstChildVoteTAG: 0
IndexTAG: 634
TitleTAG: 1B - wording
the last option is a relative statement (i.e. **lower**) which can easily be checked from the graph, but option 4 is an absolute statement -
option 4 states: "In general, states with high participation rates tended to have **low scores**."
the data in the graph shows total SAT scores in the range: 1500-1600.
are these scores considered low??
UserIdTAG: 28231
UserNameTAG: hanan
CreateTimeTAG: 2013-03-19T14:13:11Z
VoteTAG: 2
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 5
FirstChildTAG: I am interested in the answer too. Let's wait til after the deadline, see the explanation and discuss it then.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-19T15:30:52Z
FirstChildVoteTAG: 0
FirstChildTAG: Mmm.
As I see it, these values *are* absolute. They are a snapshot of how the *entirety* of the test-takers have done in 2011.
And the graph range actually goes from 1400 to 1800, roughly. I think it's safe to assume that 1400-1500 is a fairly low average score for 2011...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T16:22:07Z
FirstChildVoteTAG: 0
FirstChildTAG: > but option 4 is an absolute statement - option 4 states: "In general, states with high participation rates tended to have low scores."
Absolute? To me it is airy fairy. In general, tended to have.
So do the states with participation rates on the right of the graph have high or low scores, compared to the left side of the graph? Look at the spread of points for both groups. There will be overlap, but in *general* is there a *tendency* to lower scores?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T03:02:34Z
FirstChildVoteTAG: 0
FirstChildTAG: So, somewhat tongue-in-cheek, regarding the wording in this problem set, which appears to have stumped a lot of people, including myself, I refer everyone to the home page of our textbook (http://statistics.berkeley.edu/~stark/SticiGui/index.htm) where it says "Statistics means never having to say you're certain" and argue against multiple choice and single specific answers which ask for a certain level of certainty as to the correctness of the choice.
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-03-20T17:18:39Z
FirstChildVoteTAG: 1
FirstChildTAG: I agree that the wording of this answer ("In general, states with high participation rates tended to have low scores.) is odd. A score of 1500 does not appear low to me, a score of 100 would. 1500 is, at best, a lower score, but a low score?!
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-22T22:06:23Z
FirstChildVoteTAG: 0
IndexTAG: 635
TitleTAG: Solutions should be (as they were) available after final check on exercises
I know that there was a posting that after the mid-term, answers would be available after the deadline (as normal), however, this is not "as normal." Prior to this week, solutions were available immediately after you entered your final check. This is an invaluable service that can only be done in an online class and makes either an immediate revision to your understanding or an immediate confirmation. This is the hallmark of adult education, immediate application, revision and understanding.
Being provided explanations immediately after answering also helps confirm -how- one achieved a correct answer. Sometimes I get the correct answer, but I am not sure if I did the problem correctly or efficiently. Please bring back the availability of solutions after answering the questions. Thank you.
UserIdTAG: 975799
UserNameTAG: lmacareo
CreateTimeTAG: 2013-03-19T14:07:01Z
VoteTAG: 5
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: Only in the week prior to the midterm were solutions available after the final check in order to be able to prepare for the exam.
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-20T06:41:22Z
FirstChildVoteTAG: 1
FirstChildTAG: Only in PRACTICE exercises (and with the exception of the Graded Exercises just before Midterm, as senta pointed out) have solutions been immediately available after submitting your answers. The faculty want to hold posting answers to GRADED Exercises until just after the posting period ends to make the Graded Exercises function as graded quizzes.
FirstChildUserIdTAG: 1326845
FirstChildUserNameTAG: firefrorefiddle
FirstChildCreateTimeTAG: 2013-03-20T11:28:27Z
FirstChildVoteTAG: 1
IndexTAG: 636
TitleTAG: Problem 1B
My mistake was that I have not pick all options that are correct. I selected only one right. Do not make my mistake!
UserIdTAG: 570075
UserNameTAG: NikiSadovski
CreateTimeTAG: 2013-03-19T13:29:32Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Tell me about it:) I made this kind of mistakes all the time. I am sure many others as well. There are different reasons why people make mistakes. I think the reasons I made these kinds of mistakes arises from the fact that
1) I tend to be careless at time and not thinking hard enough - something I would like to correct.
2) I tend to not pay close attention to details especially the smallest ones - I also would like to correct this.
3) This reason relates to the other two and that is I still haven't truly master the concepts. If I master the concepts like Professor A. or (at the moment) at least as well as I should, it would be unlikely for me to make those mistakes.
My conclusion is I still have a long way to go. Professor A. had done an amazing job at simplifying Descriptive Statistics and still retain a lot of depth to help us understand something that is quite confusing. I can't wait for Stats 2.2x
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-19T15:28:40Z
FirstChildVoteTAG: 0
IndexTAG: 637
TitleTAG: What if slope is bigger than 45 degrees?
Okay, this is all great, but what if we have an oval-shaped scatterplot that has a line with a slope bigger than 45 degrees? I.e. bigger than 1? Then the "r" value doesn't work, because it is always between -1 and 1?
UserIdTAG: 1116038
UserNameTAG: UrosKovac
CreateTimeTAG: 2013-03-19T13:26:07Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 1
FirstChildTAG: Only for variables in standard units is the correlation coefficient equal to the slope of the regression line.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-19T13:59:18Z
FirstChildVoteTAG: 2
IndexTAG: 638
TitleTAG: Exercise 9, 1A and 1B
I have doubts on the correctness of the answers there. For this exercise on SAT scores vs participation rate, there is ¨some sort of¨ linear relationship and that in general states with lower participation have higher scores and the reversed. see ¨Mathematics for Elementary School Teachers¨ISBN-10: 0840054637 pg.411
So in my view the correct answer would have been ¨linear and shows negative association¨ . I also have doubt on the answers for 1B .
Any views on this?
UserIdTAG: 900106
UserNameTAG: Cory65
CreateTimeTAG: 2013-03-19T13:09:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: In general, as the people at BerkeleyX are the teachers of this course and I am their student, I assume their answers have a higher possibility to be correct than mine. So if they say that your answer is not correct, it probably is not. Other than that, I am not sure about your question, esp. the referral to the book(?). If you look through the discussion forum on Exercise 9 (before posting your question in the forum on Exercise Set 1), you will find several threads on Question 1A, e.g. this one: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_9/threads/5146a9ca5829e323000000f8 May be they can help you find the information you are looking for?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-19T13:45:28Z
FirstChildVoteTAG: 1
FirstChildTAG: Got 1A wrong but think I can see why. Got 1B right so am obviously convinced it is fair question with correct answers :) Happy to debate at length & in detail once the exercise is closed.....
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-19T13:49:23Z
FirstChildVoteTAG: 0
FirstChildTAG: Review your material on this matter, because if you got it wrong, then it is truly wrong.
FirstChildUserIdTAG: 4612
FirstChildUserNameTAG: Susnaj
FirstChildCreateTimeTAG: 2013-03-19T15:36:10Z
FirstChildVoteTAG: 0
FirstChildTAG: Put your cursor on Illinois. Now try and trace out a *straight* line running through the centre of the points - you want the same number of points above and below the line. No bend, no curve - a straight line.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-20T12:21:24Z
FirstChildVoteTAG: 0
IndexTAG: 639
TitleTAG: How to find the z value?
Approximately what is the 99th percentile of the lengths? Give your answer in mm but please do not enter the units.
incorrect
34.79
Explanation
The 99th percentile of the standard normal curve is z=2.325.
2.325*1.2 + 32 = 34.79
Here I cant understand how z gets 2.325, I went through SticiGui, but it shows different? Can u please explain?
UserIdTAG: 1087607
UserNameTAG: rinasmohamed
CreateTimeTAG: 2013-03-19T12:50:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: if i knew which exercise you are referring to i would try to help you but i did not find this task. are you sure that this is in exercise set 1?
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-19T14:16:10Z
FirstChildVoteTAG: 0
FirstChildTAG: When using this app http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm, put: Lower Endpoint: -5 and experiment with the Upper Endpoint until you achieve 99%. This is the z-value for the 99th percentile.
It usually helps to check the discussion forum on the exercises (which is where this question would belong, too).
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-19T15:35:44Z
FirstChildVoteTAG: 0
FirstChildTAG: You go into the Bell curve, you set the left side of the interval very to left , and you use divide-and-conqueror divisions of the right side until you find a good approximation of z (the value of the right side of the interval in this case, for percentile).
Next, you go back to your curve and multiply with SD, because the bell curve is obtained by lineariaztion with afine tranformation SD*z.
FirstChildUserIdTAG: 18187
FirstChildUserNameTAG: alinsoar
FirstChildCreateTimeTAG: 2013-03-19T22:34:35Z
FirstChildVoteTAG: 0
IndexTAG: 640
TitleTAG: check and final check options
hello everybody
what is the logic behind check and final check. Does it have any ralation with the marks or not?
if we just check and our answer is right then if we do not use final check option what will happen will it effect our marks or not?
UserIdTAG: 1182082
UserNameTAG: NisarAhmedAfghan
CreateTimeTAG: 2013-03-19T11:04:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Final Check just means you had more than one chance. So, if you are correct on your first attempt you have finished. No need for Final Check.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-19T11:07:26Z
FirstChildVoteTAG: 0
SecondChildTAG: i didn't know but although used the button because i thought it isn't graded when i don't hit the button. but it does not change anything in the marks if you had more than two chances.
SecondChildUserIdTAG: 1280120
SecondChildUserNameTAG: Rabia93
SecondChildCreateTimeTAG: 2013-03-19T14:06:23Z
SecondChildVoteTAG: 0
IndexTAG: 641
TitleTAG: Best points!
I think this is the best exercise I've ever answered.
UserIdTAG: 1167094
UserNameTAG: ATTAHENRY1
CreateTimeTAG: 2013-03-19T11:01:44Z
VoteTAG: 3
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: i agree with you, i did well too in this exercise
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-19T14:07:37Z
FirstChildVoteTAG: 0
SecondChildTAG: best of luck
SecondChildUserIdTAG: 1078818
SecondChildUserNameTAG: Jamili
SecondChildCreateTimeTAG: 2013-03-20T16:25:00Z
SecondChildVoteTAG: 0
IndexTAG: 642
TitleTAG: next course date
when will the next course start ? I just joined and want to take it from start.
UserIdTAG: 1448254
UserNameTAG: hdharmadarshi
CreateTimeTAG: 2013-03-19T10:36:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For Stat2.1x? I wouldn't keep my breath until it is June or so.
There will be a Stat2.2x course "shortly after" the end of this one though, and presumably a Stat2.3x later too.
So it's still a good idea to take this now, without worrying too much about the grades, if you plan to take the "sequels" :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T17:34:16Z
FirstChildVoteTAG: 0
IndexTAG: 643
TitleTAG: EXERCISE 9, PROBLEM 2A AND 2B
REQUIRE SOME HINTS FOR SOLVING PROBLEM 2A AND 2B FROM EXERCISE 9
UserIdTAG: 720707
UserNameTAG: zuberm
CreateTimeTAG: 2013-03-19T10:26:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Go and look in the forum for this question (link at bottom of question page). Lots of posts.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-19T10:28:24Z
FirstChildVoteTAG: 0
IndexTAG: 644
TitleTAG: Midterm
Dear Professor,
I could not participate in midterm because the midterm section disappeared from my window. Is there a way to retake it?
UserIdTAG: 846761
UserNameTAG: emarbell
CreateTimeTAG: 2013-03-19T09:47:26Z
VoteTAG: 1
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.3: Regression effect, Galton, and the regression fallacy
NumberOfReplyTAG: 3
FirstChildTAG: I could not take up the mid term as well, because I get confuse with the new homework and mid term dates. I regret I was very busy with work all week and never got a chance until today to come back and work on my exercises and exam. Am I still eligible to pass the course if I get more than 35% even after missing the mid term?
FirstChildUserIdTAG: 157588
FirstChildUserNameTAG: Chopra
FirstChildCreateTimeTAG: 2013-03-19T12:51:06Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-19T13:46:39Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't think so, as the deadline is over and the answers are available for everyone to see.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-19T13:47:14Z
FirstChildVoteTAG: 0
FirstChildTAG: There was time duration mentioned for this exam.
FirstChildUserIdTAG: 1274394
FirstChildUserNameTAG: misba_masood
FirstChildCreateTimeTAG: 2013-03-19T15:30:05Z
FirstChildVoteTAG: 0
IndexTAG: 645
TitleTAG: bug in my browser?
histograms don't show up in chapter 5 and 6 and onwards. I'm using google chrome, don't know why...
UserIdTAG: 1027696
UserNameTAG: bhamgm
CreateTimeTAG: 2013-03-19T09:40:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Try the steps [here][1], the last one most likely applies to you. The page is about the Normal Curve Applet, but it should apply to most other graphs in the textbook too.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/fixing-normal-curve-applet/
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-19T09:44:44Z
FirstChildVoteTAG: 0
SecondChildTAG: it works! thanks a lot!
SecondChildUserIdTAG: 1027696
SecondChildUserNameTAG: bhamgm
SecondChildCreateTimeTAG: 2013-03-19T09:53:36Z
SecondChildVoteTAG: 0
IndexTAG: 646
TitleTAG: Applet Use...
Hi! I have joined this course just before the mid term so I dont know how to use applet,Can you guys please help me with this
UserIdTAG: 1422371
UserNameTAG: Neha_me
CreateTimeTAG: 2013-03-19T08:44:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You can view the applet here - http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1276376
FirstChildUserNameTAG: binukeloth
FirstChildCreateTimeTAG: 2013-03-19T09:31:51Z
FirstChildVoteTAG: 0
FirstChildTAG: yes i can c..please explain how to use this
FirstChildUserIdTAG: 1422371
FirstChildUserNameTAG: Neha_me
FirstChildCreateTimeTAG: 2013-03-20T10:25:32Z
FirstChildVoteTAG: 0
IndexTAG: 647
TitleTAG: Final Exam?
When is the final exam?
UserIdTAG: 1075168
UserNameTAG: Ashish_Mamgain
CreateTimeTAG: 2013-03-19T05:43:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Course_Schedule.pdf
FirstChildUserIdTAG: 1222050
FirstChildUserNameTAG: SteveFitzjohn
FirstChildCreateTimeTAG: 2013-03-19T08:47:38Z
FirstChildVoteTAG: 0
IndexTAG: 648
TitleTAG: Confused: Multiplying doesn't change SD?
I was sure that if we multiply all the data by some constant, SD would also be multiplied by that constant. Either that or I'm totally confused this with something else. Any help?
Thanks.
UserIdTAG: 955096
UserNameTAG: yoav_v
CreateTimeTAG: 2013-03-19T05:14:41Z
VoteTAG: 1
CoursewareTAG: Section 6: Relation between two variables / Lec 6.2: The correlation coefficient: calculation and properties
NumberOfReplyTAG: 1
FirstChildTAG: That is correct. Multiplication scales SD. Addition does not.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-19T11:28:30Z
FirstChildVoteTAG: 0
SecondChildTAG: the constant cancels out: k(x - x bar)/k STD = SU (new) = SU (old)
SecondChildUserIdTAG: 720154
SecondChildUserNameTAG: LUCALOTTO2012
SecondChildCreateTimeTAG: 2013-03-19T11:47:03Z
SecondChildVoteTAG: 0
SecondChildTAG: SD is multiplied by the "absolute value" of the multiplier, not the multiplier in all its positive or negative glory.
Lucal you confused Standard Units with Standard Deviation.
SecondChildUserIdTAG: 38912
SecondChildUserNameTAG: AG20390
SecondChildCreateTimeTAG: 2013-03-22T22:33:25Z
SecondChildVoteTAG: 0
IndexTAG: 649
TitleTAG: Q 2 B not knowing what to do.
My calculations for making decision about "SLOPE" is correct.But not getting the right answer for "INTERCEPT" .Where I am wrong.Please help .
Intercept= MuY- slope * MuX.
Here MuX=23 and MuY=6.Or there is some confusion?
UserIdTAG: 1293941
UserNameTAG: CHHAVIMEHROTRA
CreateTimeTAG: 2013-03-19T04:51:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: Buddy, this question took me 12 hours before arriving at the final answer:: listen carefully to the lecture section 7.4 between time interval of 04:51-05:08
just assume the given value is **DIAMETER** of egg--->x
the value to be found is **WEIGHT**--------->y
class mate, listen to the above given lecture section and the hint to find yourself a help.....gud luck
FirstChildUserIdTAG: 820147
FirstChildUserNameTAG: frimpongmaxwellkwadwo
FirstChildCreateTimeTAG: 2013-03-19T08:30:46Z
FirstChildVoteTAG: 2
SecondChildTAG: If you get Q2A right, then you will know which variable is dependent (Y) and which one is independent (X). Since the slope's units of measure are in direct relation to them (Y/X). One could have allocated them in any axes, but here they did it in a particular way and Q2A holds the answer.
SecondChildUserIdTAG: 902345
SecondChildUserNameTAG: phidesigner
SecondChildCreateTimeTAG: 2013-03-19T11:18:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you friends,but I still don't understand where and why I'm wrong.I have gone through the lecture twice.According to my perception Diameter is taken as "X" and Weight is taken as "Y".
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-19T15:46:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I calculated b = r*(SDy/SDx) to g/mm value. then for intercept, I used eq. y = My - b*Mx and result is way higher than avg egg wt +/- SD. What I am doing wrong.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-19T16:09:21Z
SecondChildVoteTAG: 0
SecondChildTAG: in lecture it seems to me a case of fallacy
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-19T16:13:26Z
SecondChildVoteTAG: 0
SecondChildTAG: result can possibly be higher than the avg wt, if you see it clearly is just an intercept of the line
SecondChildUserIdTAG: 991656
SecondChildUserNameTAG: charansai
SecondChildCreateTimeTAG: 2013-03-19T16:48:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanx @charansai, after all I feed in the value that I calculated, though higher, and it's right.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-19T17:22:44Z
SecondChildVoteTAG: 0
SecondChildTAG: the intercept required is the y intercept, that is, the y value when x = 0
SecondChildUserIdTAG: 958344
SecondChildUserNameTAG: 314
SecondChildCreateTimeTAG: 2013-03-20T02:40:28Z
SecondChildVoteTAG: 0
SecondChildTAG: i found myself with a negative value :/
SecondChildUserIdTAG: 933119
SecondChildUserNameTAG: wsaw
SecondChildCreateTimeTAG: 2013-03-20T22:19:41Z
SecondChildVoteTAG: 0
IndexTAG: 650
TitleTAG: Show Answer
I scored 0 on this exercise. Why doesn't Show Answer button display?
UserIdTAG: 865969
UserNameTAG: Shanatova
CreateTimeTAG: 2013-03-19T04:51:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Because answers are released after the deadline.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-19T05:33:23Z
FirstChildVoteTAG: 2
SecondChildTAG: It wasn't always like that. May be the rule changed and I missed it.
SecondChildUserIdTAG: 865969
SecondChildUserNameTAG: Shanatova
SecondChildCreateTimeTAG: 2013-03-20T04:15:29Z
SecondChildVoteTAG: 0
IndexTAG: 651
TitleTAG: One more ES and one more Exam!
Dear Professor,
Some of the ES were short (10 marks) and a few of them were elaborate (15 marks or 20 marks). I hope you would give the appropriate weights to each ES and then arrive at the gross marks after eliminating say a few bad ES? It does not really matter but then I was just a little curious! Lessons learned - do the ES diligently and the exams shall become smooth sailing.
Professor AA - Very eagerly awaiting the second part of your statistics course.
Students - Please do not hesitate to listen to some of the StatGui lectures that are an integral part of the e-book, they are informative and illustrative too! All the best for the final exam.
UserIdTAG: 413463
UserNameTAG: Venkataramani
CreateTimeTAG: 2013-03-19T04:33:20Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: All graded exercises are equally weighted with the lowest two scores being dropped. This is clearly explained in the course description.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-20T02:30:41Z
FirstChildVoteTAG: 0
IndexTAG: 652
TitleTAG: Week 4 - Submission Deadline
This week was released post Midterm i.e. 15th March, still its submission deadline is 20th. Shouldn't more time be given?
UserIdTAG: 865969
UserNameTAG: Shanatova
CreateTimeTAG: 2013-03-19T04:32:05Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: No. Thank you.
FirstChildUserIdTAG: 23003
FirstChildUserNameTAG: WH
FirstChildCreateTimeTAG: 2013-03-19T04:34:12Z
FirstChildVoteTAG: 4
FirstChildTAG: Prof. A. Study material,no. of text chapters and conceptually week 4 is by far most comprehensive,but time provided is less . Submission deadline should be extended by 2-3 days for both week 4 and week 5, or else progress of otherwise good achievers is sure to fall unfairly. The fact that **number of students are from non-mathematics background, that many have other compelling commitments too and that learning is a time taking *** makes it even more necessary in the interest of fair play. Please do the needful Prof. A. Thanx.
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-19T07:42:04Z
FirstChildVoteTAG: 2
SecondChildTAG: yes, it's bit difficult to understand chapter 6-8 (week 4). It seems big steps from previous lectures.
SecondChildUserIdTAG: 1027696
SecondChildUserNameTAG: bhamgm
SecondChildCreateTimeTAG: 2013-03-19T09:44:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree, more time should be given, at least one more day to compensate the day when we took the midterm.
Thanks
SecondChildUserIdTAG: 826276
SecondChildUserNameTAG: acamacho5
SecondChildCreateTimeTAG: 2013-03-19T23:01:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Those who feel proper one week which is otherwise allotted to every week's topic is not required - This is a self centred thinking - most people who complete the exercises 'before they are even released', find everything easy, never have problems understanding any topic are the ones who are already knowing statistics and are here just for certificate (few exceptions to the rule acknowledged). That's OK. To each his own. But please, don't be so self centred to not spare thoughts for others.
FirstChildUserIdTAG: 865969
FirstChildUserNameTAG: Shanatova
FirstChildCreateTimeTAG: 2013-03-20T04:13:37Z
FirstChildVoteTAG: 0
IndexTAG: 653
TitleTAG: Correlation coefficient calculation
Hi
I do not have access to the videos in the text book.
Can some one tell me how to calculate the index R of correlation coefficient.
UserIdTAG: 152907
UserNameTAG: visperad
CreateTimeTAG: 2013-03-19T04:02:02Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: hi,
if you want to calculate r you have to do the following:
1. transformation of the x and y lists to standard units
2. calculating the products of one value x and the according y;
in standard units of course
3.compute the mean of the products
4. what you got in step 3 is already r
hope this was helpful
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-19T14:25:47Z
FirstChildVoteTAG: 0
IndexTAG: 654
TitleTAG: The soft only accepts one decimal point
It seems the software only accepts one decimal point, true?
UserIdTAG: 1105154
UserNameTAG: Bogdan2
CreateTimeTAG: 2013-03-19T03:48:56Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you are talking about Set 1, then yes there were dp issues back then. But only for the first week. After that you enter 2 - 5 places, if required.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-19T03:55:05Z
FirstChildVoteTAG: 0
IndexTAG: 655
TitleTAG: Ques 2C
Can somebody give me a clue on how to solve this?
Problem 2C : 2.0 points
The diameter of one of the eggs is 0.5 mm wider than that of another. According to the regression method, the chick that hatches from the bigger egg is estimated to be ____________ grams heavier.
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-19T03:38:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You have a couple of options. Solve the regression equation you just defined - for two values 0.5mm apart. Or, use the definition of the slope to answer with only a bit of mental arithmetic.
Why didn't you put this question in the correct forum? Makes life easier for those who want to help you.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-19T03:51:40Z
FirstChildVoteTAG: 0
FirstChildTAG: Please teach me how to put it in the correct forum.
FirstChildUserIdTAG: 277481
FirstChildUserNameTAG: scott520
FirstChildCreateTimeTAG: 2013-03-21T02:18:46Z
FirstChildVoteTAG: 0
IndexTAG: 656
TitleTAG: Problem 1
if r = 1, then it could be letter A, other than that the estimated values would tend to go to point of averages.
IMHO, it should be D
;/
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-19T03:33:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 5
FirstChildTAG: is it about set 11 problem 1? in my opinion the Question should have mentioned what is the value of r as the answer will depend on it accordingly.
FirstChildUserIdTAG: 1083257
FirstChildUserNameTAG: lalichat
FirstChildCreateTimeTAG: 2013-03-19T06:46:54Z
FirstChildVoteTAG: 0
SecondChildTAG: No, the answer doesn't depend on the specific value of r. You (should)know what the valid range for r is, and within that range, the answer doesn't change no matter what r is.
Except for the special case of r=1, true...but it has been stated in the lectures, multiple times, that r=1 is an ideal value and just **doesn't happen** with natural data. "*Birthweights and lengths of newborns at a hospital"* is definitely natural data, so you should already rule out that possibility.
In my opinion, of course ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-19T09:35:26Z
SecondChildVoteTAG: 0
FirstChildTAG: > if r = 1, then it could be letter A, other than that the estimated values would tend to go to point of averages.
IMHO, it should be D
r is irrelevant. This question relates to the regression effect and doesn't depend on r.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-19T07:03:48Z
FirstChildVoteTAG: 0
FirstChildTAG: I got this wrong too, but I don't think r can be one as it's a "football shaped scatter diagram", i.e. the newborns lengths and weights are normally distributed.
If the question was "The birthweights and lengths of newborns at a hospital have an upward sloping scatter diagram. For a baby on the 35th percentile of birthweights, the regression estimate of length"
then I think the answer should be d. Unfortunately for us, that's not the question!
FirstChildUserIdTAG: 84802
FirstChildUserNameTAG: adsadn
FirstChildCreateTimeTAG: 2013-03-19T13:06:02Z
FirstChildVoteTAG: 0
FirstChildTAG: I got this wrong too, I think we have to follow regression effect slide to get it right.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-19T17:26:00Z
FirstChildVoteTAG: 0
FirstChildTAG: The fact that the scatterplot is "football shaped" is the clue here. Even if r=1, the data does not fit perfectly on the regression line -- it is scattered around it. Because of this, you cannot assume that the data will fall exactly on the regression line. You have to figure out where the data will tend to fall.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-19T19:48:31Z
FirstChildVoteTAG: 0
IndexTAG: 657
TitleTAG: Problem with the figures in text
I am using the recommended Chrome browser, but I cannot see and use Figures 5-1 and 6-2. We don't actually need them, but it would be nice to play with them too.
UserIdTAG: 1330238
UserNameTAG: xeniosm
CreateTimeTAG: 2013-03-19T02:37:52Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: Do you have javascript enabled? Disabling js makes those figures disappear for me.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-19T11:33:51Z
FirstChildVoteTAG: 0
IndexTAG: 658
TitleTAG: Difficult set of Exercises
I have not fared really well in this set
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-03-19T02:35:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 0
IndexTAG: 659
TitleTAG: set 11 problem 1 clarification
is the upward slope indicative of a perfect linear positive correlation( r=1 ) or is it r=> 0.1<1 ) ?
based on the value of :r" the answer will depend as to whether it is on the 35th percentile line or above it?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-19T02:02:53Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I agree. I thought that r would be 1. ;/
FirstChildUserIdTAG: 1024776
FirstChildUserNameTAG: guil
FirstChildCreateTimeTAG: 2013-03-19T03:48:16Z
FirstChildVoteTAG: 0
SecondChildTAG: *r* is never exactly $\pm1$ with real data, unless there's actually a mathematical formula relating the two datasets.
This is not the case.
Upward slope restricts the value of *r*, but not to r=1...and besides, you'd get the same answer even without that restriction ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-19T09:41:54Z
SecondChildVoteTAG: 0
IndexTAG: 660
TitleTAG: Lecture Slides
Professor kindly share lecture slides and update lecture notes on Wiki.
Regards
UserIdTAG: 197348
UserNameTAG: pr07809
CreateTimeTAG: 2013-03-19T01:37:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 661
TitleTAG: Problem 1 B
I don't understand the question .any one plz help,though it is already wrong.I just want to know logic behind.Many thanks
UserIdTAG: 1293941
UserNameTAG: CHHAVIMEHROTRA
CreateTimeTAG: 2013-03-19T01:28:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: ![enter image description here][1]
The circled points have been identified in the question description. Illinois, Minnesota and Iowa in the top left, Maine and D.C. in the bottom right.
You have to decide which of the given statements are correct. You can select as many as you think are correct.
>The state of Illinois did a better job preparing its students for the SAT than the state of Maine did.
>The students who took the test in Illinois did better, on average, than those who took the test in Maine.
>A higher percentage of students took the test in Maine than in Illinois.
>In general, states with high participation rates tended to have low scores.
>The higher scoring states tended to be those that had lower participation rates, in general.
You need to look at the graph - noting the axis labels, position of points. Then read the answers carefully. Are the statements accurate? Or are some not reasonable to make, given the information from the graph?
[1]: https://edxuploads.s3.amazonaws.com/13636569548474411.png
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-19T01:41:29Z
FirstChildVoteTAG: 1
SecondChildTAG: ChristineStv thank you so much.now I understand.
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-19T04:59:45Z
SecondChildVoteTAG: 0
SecondChildTAG: i feel all statements are true as explaining same thing...its weird...
SecondChildUserIdTAG: 1239112
SecondChildUserNameTAG: Zawara
SecondChildCreateTimeTAG: 2013-03-19T07:06:18Z
SecondChildVoteTAG: 0
SecondChildTAG: No Zawara ,If you look at the statements with scrutinizing eyes you can find the contradictions.
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-19T08:39:29Z
SecondChildVoteTAG: 0
SecondChildTAG: How does a graph help us in explaining the situation particularly the first option or for that matter all the options?
SecondChildUserIdTAG: 169509
SecondChildUserNameTAG: rajeevbasapathy
SecondChildCreateTimeTAG: 2013-03-19T13:42:30Z
SecondChildVoteTAG: 0
SecondChildTAG: I think you nailed the problem,actually.
Does the graph help you evaluate those statements or not? Answer that, and you'll know what to check and what to not check.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-19T17:42:55Z
SecondChildVoteTAG: 0
FirstChildTAG: The test is over now. If anyone is still reading this discussion, can you please refer me to the answer. I misread the question and got it wrong. I understand that some interpretation of "low" is required to get the correct answer. Knowing the answer may help me to interpret the questions on the final better.
Here's what I think: if you letter the answers a - e, then (b), (c), and (e) are the answers that I would check.
For (b), you can say that the students in Illinois did better on average than students in Maine, but for (a), can you say with certainty that the state did a better job of preparing them? Maybe they did a better job of discouraging lousy test-takers from taking the test? That would also help explain the low participation rate. I guess I'm less certain about (d). In this case we're not talking about the two lowest score states, but low scores in general. My inclination is to say that in general, those states with a participation rate greater than 50% had the lowest average scores, and not try to decide what constitutes a low score. Thanks.
FirstChildUserIdTAG: 1342025
FirstChildUserNameTAG: mbunch25
FirstChildCreateTimeTAG: 2013-03-22T02:26:19Z
FirstChildVoteTAG: 0
IndexTAG: 662
TitleTAG: Had a great time!
I love the lectures and have learned a lot from this class so far. However, family issues and time constraints prevent me from properly finishing this class. My thanks to the people at edX for making all this possible.
UserIdTAG: 478427
UserNameTAG: galaxym100
CreateTimeTAG: 2013-03-19T00:53:12Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 663
TitleTAG: Sharing My Experience So Far (Some tips needed for a small project)
Hello All,
I would like to share the fact that this course has been a major turning point. Finally, I can understand some statistics, I had a few classes during my first undergraduate course, but I hardly recall understanding anything. I didn't feel comfortable with numbers for some time. It has all changed now, I was willing to take the challenge and I strongly believed I would understand, and enjoy statistics. Thank you Prof. Ani, the way you lecture is simply fantabulous.
I'm enjoying statistics so far. I would actually want to do some practical work using what I've learned till now. I'm currently associated with a language institute that offers 7 courses. I would like to collect several samples of scores from each course/level. I thought of computing the mean/median/SD of the scores for each level.
How many samples should I take for each level? 5 Maybe? A level is usually 2 months, so 6 samples would account for the scores of the entire year.
After I get some data out, could it be analyzed as follows:
In case we improved the learning material within the past year and the average score tended to increase afterwards, would this indicate that the new materials were beneficial?
Maybe letting the students know that they fall within the 50th percentile or more could also be more informative for them.
What other things could I get after computing the averages of scores for the different levels? Or maybe what else could I compute from such Data?
I feel quite excited when I use numbers, and I'm really looking forward to it. Please chip in your ideas, I consider myself an amateur in the field of statistics.
Thank you in advance
UserIdTAG: 909648
UserNameTAG: Ozziee
CreateTimeTAG: 2013-03-19T00:40:06Z
VoteTAG: 3
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.4: Equation of the regression line
NumberOfReplyTAG: 1
FirstChildTAG: You must use inferential statistics to draw conclusions.That is in Stat 2,3
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-19T01:46:45Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you Prasannasimha, I'm looking forward to learn about inferential Statistics then.
For now I'll stick to descriptive statistic, I'll try to utilize what I learned here.
SecondChildUserIdTAG: 909648
SecondChildUserNameTAG: Ozziee
SecondChildCreateTimeTAG: 2013-03-19T11:47:32Z
SecondChildVoteTAG: 0
IndexTAG: 664
TitleTAG: After Stat2.1x
Is there another course we can take after Stat2.1x?
UserIdTAG: 1310862
UserNameTAG: payalkela
CreateTimeTAG: 2013-03-19T00:39:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Will be announced soon by the Priofessor
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-19T01:47:05Z
FirstChildVoteTAG: 0
FirstChildTAG: I am very interested about Stat2.2x and Stat2.3x
When they will be ?
I love how this course is presented, comparing to other similar courses from Coursaira.
FirstChildUserIdTAG: 18187
FirstChildUserNameTAG: alinsoar
FirstChildCreateTimeTAG: 2013-03-19T22:37:58Z
FirstChildVoteTAG: 0
IndexTAG: 665
TitleTAG: Due date exercise set 12?
Hi all,
Has anyone seen a post from staff about the due date for exercise set 12? The course schedule states its due in on Monday 25 March. In a staff post on the landing page (on 21 February) it was announced though that the deadlines for all exercise sets had changed to Wednesdays (as has indeed been the case for each of the sets).
I am aware that the final exam will be posted on Tuesday 26 March, and this may very well be the reason that the due date for the exercise set is Monday 25 March. Just would like to get confirmation from staff that this is indeed the case.
Thanks!
UserIdTAG: 1143082
UserNameTAG: C71
CreateTimeTAG: 2013-03-18T23:34:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: what exercise? i have not seen anything since the exam.... is it just me? i have been checking ever since.
FirstChildUserIdTAG: 1235093
FirstChildUserNameTAG: Ifeg
FirstChildCreateTimeTAG: 2013-03-18T23:57:31Z
FirstChildVoteTAG: 0
SecondChildTAG: oh. i just realised it was there. the last on the list is the midterm which was done before so i thought those assignments above it were the ones past as well. why did they just leave the midterm in chronological order with the rest of the assignments?
SecondChildUserIdTAG: 1235093
SecondChildUserNameTAG: Ifeg
SecondChildCreateTimeTAG: 2013-03-19T00:46:05Z
SecondChildVoteTAG: 0
SecondChildTAG: could it be the reason as to why some guys missed the midterm exam??,
i suggest the staff should clarify this issue before the final exam is posted;
SecondChildUserIdTAG: 439981
SecondChildUserNameTAG: enom200
SecondChildCreateTimeTAG: 2013-03-19T01:04:41Z
SecondChildVoteTAG: 0
FirstChildTAG: > could it be the reason as to why some guys missed the midterm exam??
No. At the time of the midterm, it was the only option available. Add to that all the written information on the Info page and syllabus regarding the test. People missed the midterm because they did not read the information correctly.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-19T01:12:08Z
FirstChildVoteTAG: 0
FirstChildTAG: where is this exercise set 12 you mentioned, i can just see up till exercise set 11
FirstChildUserIdTAG: 192591
FirstChildUserNameTAG: prateekdk
FirstChildCreateTimeTAG: 2013-03-19T03:11:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Exercise set 12 has not been opened yet. I guess it will be at some point after the deadline for this week's exercise sets.
SecondChildUserIdTAG: 1143082
SecondChildUserNameTAG: C71
SecondChildCreateTimeTAG: 2013-03-19T20:32:02Z
SecondChildVoteTAG: 0
IndexTAG: 666
TitleTAG: My new favorite word...
Respectical. I'm serious! I really will be saying that all the time. I really love Ani Adhikari. She is the best teacher and a repectic her greatly.
UserIdTAG: 316261
UserNameTAG: Brady1997
CreateTimeTAG: 2013-03-18T22:51:57Z
VoteTAG: 4
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 1
FirstChildTAG: She is a fantastic lecturer. Even with that small error, she barely missed a beat. I have a lot to learn from her speaking style: so clear, even when she's thinking and she rarely stumbles and never uses "like" or "ummmmm" :)
FirstChildUserIdTAG: 1157957
FirstChildUserNameTAG: meganbh
FirstChildCreateTimeTAG: 2013-03-19T17:08:27Z
FirstChildVoteTAG: 1
SecondChildTAG: I totally agree. And am sorry if i sounded irreverent or disrespectful.
SecondChildUserIdTAG: 316261
SecondChildUserNameTAG: Brady1997
SecondChildCreateTimeTAG: 2013-03-21T16:54:42Z
SecondChildVoteTAG: 0
IndexTAG: 667
TitleTAG: Terrible performance: regression appears to be my nemesis
I just scraped through exercise set 10. I don't know why some answers were right and others were wrong, as I was using the same method throughout.
Tonight, I did exercise set 11. I thought I understood what to do. The practice exercises went OK. I got all of the questions wrong (except the 2 points at the end). I've no idea what I was doing wrong.
All of the previous exercises I've done really well on, and I just don't know how I'm going wrong.
Is anyone else struggling with regression?
UserIdTAG: 1256079
UserNameTAG: AimeeGrant
CreateTimeTAG: 2013-03-18T22:42:58Z
VoteTAG: 2
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 7
FirstChildTAG: me too. I thought regression was something different.
FirstChildUserIdTAG: 1180593
FirstChildUserNameTAG: CARLOSJAV
FirstChildCreateTimeTAG: 2013-03-18T22:50:10Z
FirstChildVoteTAG: 0
FirstChildTAG: me too, i messed it up, all.
i don't really know where i was wrong...!!!:(
FirstChildUserIdTAG: 192591
FirstChildUserNameTAG: prateekdk
FirstChildCreateTimeTAG: 2013-03-19T03:15:11Z
FirstChildVoteTAG: 0
FirstChildTAG: for me too, but i know where my mistakes are: if you used the right formula like i did and then plugging in the wrong SD or the wrong mean becauese you have to read the task sentences very very careful...but do not worry, the two worst exercises do not count
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-19T14:39:33Z
FirstChildVoteTAG: 0
FirstChildTAG: It was ... **humbling.**
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-19T15:26:28Z
FirstChildVoteTAG: 0
FirstChildTAG: You are not alone, if you miss the 2nd one, the rest will be wrong. I missed them all.... At least we get 2 exemptions :) I just wish I knew how to do it correctly, I don't want to move on untill I master this.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-03-19T18:17:13Z
FirstChildVoteTAG: 1
FirstChildTAG: Me too, I didn't manage to get 1 question right although all the other times I usually score 80%....
FirstChildUserIdTAG: 1277718
FirstChildUserNameTAG: SanneJ
FirstChildCreateTimeTAG: 2013-03-19T19:10:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Dears at least mention the questions there r some students who can help you
FirstChildUserIdTAG: 1078818
FirstChildUserNameTAG: Jamili
FirstChildCreateTimeTAG: 2013-03-20T16:34:39Z
FirstChildVoteTAG: 0
IndexTAG: 668
TitleTAG: 40 % in my total progress
Excuse me, but that means that I have passed the course?
UserIdTAG: 1180593
UserNameTAG: CARLOSJAV
CreateTimeTAG: 2013-03-18T22:36:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Yes!
FirstChildUserIdTAG: 1080570
FirstChildUserNameTAG: MirkoPonzanelli
FirstChildCreateTimeTAG: 2013-03-19T00:32:01Z
FirstChildVoteTAG: 0
FirstChildTAG: I wish I know how is this course comparing to the similar course inside the Berkeley campus.
FirstChildUserIdTAG: 18187
FirstChildUserNameTAG: alinsoar
FirstChildCreateTimeTAG: 2013-03-19T22:39:31Z
FirstChildVoteTAG: 0
IndexTAG: 669
TitleTAG: Problem 3
Sorry for capitals, but LOL!!!!
UserIdTAG: 961016
UserNameTAG: Pois
CreateTimeTAG: 2013-03-18T22:11:31Z
VoteTAG: 7
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 3
FirstChildTAG: As a tutor can I 'borrow' this idea?
I still have not stopped laughing ...
Kit.
FirstChildUserIdTAG: 20821
FirstChildUserNameTAG: KitR
FirstChildCreateTimeTAG: 2013-03-19T06:56:27Z
FirstChildVoteTAG: 4
SecondChildTAG: I'm really struggling with this problem :(
Help please.
SecondChildUserIdTAG: 254949
SecondChildUserNameTAG: stormshadow
SecondChildCreateTimeTAG: 2013-03-19T13:05:20Z
SecondChildVoteTAG: 0
SecondChildTAG: :D
SecondChildUserIdTAG: 1142696
SecondChildUserNameTAG: ParulG
SecondChildCreateTimeTAG: 2013-03-19T15:01:54Z
SecondChildVoteTAG: 0
SecondChildTAG: This is so funny :D
SecondChildUserIdTAG: 1009052
SecondChildUserNameTAG: AgataK
SecondChildCreateTimeTAG: 2013-03-19T16:36:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Hahaha the first fun problem! Good one :)))
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-19T17:03:00Z
SecondChildVoteTAG: 0
FirstChildTAG: it would've been an easy 2 points if i had read the second part of the question.... lesson learned
FirstChildUserIdTAG: 1278232
FirstChildUserNameTAG: eirras
FirstChildCreateTimeTAG: 2013-03-19T15:27:46Z
FirstChildVoteTAG: 1
SecondChildTAG: Same here. lol
SecondChildUserIdTAG: 206086
SecondChildUserNameTAG: pedrocas1972
SecondChildCreateTimeTAG: 2013-03-19T19:15:17Z
SecondChildVoteTAG: 0
FirstChildTAG: It stated check both, lol...lol...
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-19T18:49:36Z
FirstChildVoteTAG: 0
IndexTAG: 670
TitleTAG: About Stat2.1x
Ok, maybe it's a bit too early since the course is still going on, but I wanted to post my impression of it anyway. Basically, I loved it! At first, I was a bit worried that the lack of a calculus prerequisite would impact the rigour of the course, but that proved not to be the case at all. Prof. Adhikari made an excellent job of explaining the physical meaning of the definitions and the methods used in Descriptive Statistics, instead than concentrating on the mathematical details. Of course, equations were necessary for the proofs in the algebra supplement, but I appreciated a lot the fact that the course developed a sense of intuition which, for many exercises, allowed me to get the answer right before doing calculations. By the way, I loved the exercises (in particular Midterm 4a and 5 were really great), and I also enjoyed the casual life anectodes during the video lectures - like the one on the (American) football-shaped scatter plot :)
If I have to find a small nag, it's that maybe some of the initial stuff could have been covered faster, in order to get to Stat2.2x sooner. On the other hand, that may be just me being worried about finding enough time to follow all three courses :P
I congratulate Prof. Adhikari for the great course, and all the edX staff for making this course available to so many people around the globe.
UserIdTAG: 407687
UserNameTAG: AndreaPi
CreateTimeTAG: 2013-03-18T21:40:41Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 671
TitleTAG: I just joined without realising that the course is in its last week.
Dear Professor,
I just joined without realizing that you are in the last week of the course. Please, could I be registered for the next 5 weeks course?
Looking forward to hearing from you. Cristina
UserIdTAG: 1446142
UserNameTAG: cristinapm
CreateTimeTAG: 2013-03-18T21:21:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Stat 2.2X does not require 2.1X to be a prerequisite but you will have been assumed to know all that was taught in 2.1X
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-19T01:49:55Z
FirstChildVoteTAG: 0
IndexTAG: 672
TitleTAG: Mid-term Question 2--a question
I need some help here. I arbitrarily said there were a 100 data points to make life easy. Than means the hours in the range (evenly distributed?) people:
0-28 are 56 (0 to 4 so average is 2),
28-64 are 216,
36-76 are 120,
76-88 are 192,
88-100 are 288,
Total hours then are 872 and 80% is 698.
That many hours occurs between 20 and 28 in the last 12%. The answer put it in the middle 12%. Where did I go wrong?
UserIdTAG: 1343670
UserNameTAG: rleonetti
CreateTimeTAG: 2013-03-18T20:44:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Are you talking about Question 2a or 2b?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-19T11:59:29Z
FirstChildVoteTAG: 0
SecondChildTAG: I can't find the mid-term again but it had to do with estimating the 80% point on the distribution.
SecondChildUserIdTAG: 1343670
SecondChildUserNameTAG: rleonetti
SecondChildCreateTimeTAG: 2013-03-19T18:03:31Z
SecondChildVoteTAG: 0
SecondChildTAG: You can find the midterm among the course material for week 4. Your approach seems way complicated. Click "Show Answer" and have a look at the solution. Does this help?
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-19T18:12:59Z
SecondChildVoteTAG: 0
IndexTAG: 673
TitleTAG: What does correlation mean in problem 2?
In problem 2, the question is about "The correlation between...". Does it mean correlation coefficient (r), a numerical relationship (ratio) between variables, or something else?
UserIdTAG: 1090102
UserNameTAG: Adonis79
CreateTimeTAG: 2013-03-18T20:13:16Z
VoteTAG: 10
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: just think easy. since the numbers dont allow much calculation it must e a simple answere related to the limits.
FirstChildUserIdTAG: 929681
FirstChildUserNameTAG: pratyushc
FirstChildCreateTimeTAG: 2013-03-19T02:47:20Z
FirstChildVoteTAG: 1
IndexTAG: 674
TitleTAG: Many thanks for problem 3 from tired mind :)
It is really cheers up!
UserIdTAG: 1148146
UserNameTAG: Prostova
CreateTimeTAG: 2013-03-18T19:51:29Z
VoteTAG: 25
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 0
IndexTAG: 675
TitleTAG: Standard Units
Is standard units the z score?
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-18T19:06:31Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 1
FirstChildTAG: Yes Z is the numerical value of the standard unit
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-19T01:50:34Z
FirstChildVoteTAG: 0
SecondChildTAG: (x-mean)/(sd) c:
SecondChildUserIdTAG: 80100
SecondChildUserNameTAG: CarlosGardella
SecondChildCreateTimeTAG: 2013-03-20T03:10:35Z
SecondChildVoteTAG: 0
IndexTAG: 676
TitleTAG: Line has no intercept?
In this video, Regression line: intuition; the equation in standard units; regression estimates, the instructor claims that the line passed through the origin but has no intercept. I do not understand what she means by no intercept. It does intercept the x and y axis at 0,0 so she is incorrect.
Why did she draw the 45 degree line in the video? What is its purpose?
Why is the green line R?
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-18T19:03:10Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 1
FirstChildTAG: I think technically what was meant by "no intercept" is the fact that the intercept is (0,0). So that graph shows **no non-zero** intercept. If you were to write this out in the form of the equation of a line, you would see +0 as the intercept, and it would drop out of the equation.
The 45-degree line signifies perfect correlation of +1. It is used as a reference here. It signifies "equal standard units on either side", that is, equidistant from both x and y axes. It marks the points where the averages of both x and y variables are equal. It is also called the "SD line".
The R line was drawn in a different color to represent one case of R being less than +1. It was just used as an example to hi-light that its slope is less than +1.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-18T19:16:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Important to note that the regression line has no non-zero intercept **only when it is expressed in standard units**. In the most recent lectures, we learned how to express the intercept as a function of the standard deviations, the correlation coefficient, and the mean value of x.
SecondChildUserIdTAG: 1258756
SecondChildUserNameTAG: Pre-Code
SecondChildCreateTimeTAG: 2013-03-18T19:25:48Z
SecondChildVoteTAG: 0
IndexTAG: 677
TitleTAG: Correlation coefficient clarification
In the video Sir Galton was given credit for correlation coefficient or "r" and then as part of another course I'm taking regarding reliability the text referred to "r" as the Pearson product-moment correlation coefficient which had the same value possibilities as "r" did in Stat2.1. My question is what's the difference if any in these "r" values? or concepts? Who is Pearson? Thanks for shedding any light on this. Paul
UserIdTAG: 1067669
UserNameTAG: psanders
CreateTimeTAG: 2013-03-18T18:28:29Z
VoteTAG: 1
CoursewareTAG: Section 6: Relation between two variables / Lec 6.2: The correlation coefficient: calculation and properties
NumberOfReplyTAG: 1
FirstChildTAG: http://en.wikipedia.org/wiki/Karl_Pearson
He was Galton's Protege
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-19T02:13:14Z
FirstChildVoteTAG: 0
IndexTAG: 678
TitleTAG: Question 1a 1b
I did the following to calculate both problems but my answers are marked wrong IE 0.629 and 0.637.
I done the following fomula example say it was y= r0.85 sy 0.10/0.50-0.85/0.5+ ybar.
any body help me or guide me on this.
UserIdTAG: 334968
UserNameTAG: MCGEEC147
CreateTimeTAG: 2013-03-18T18:03:27Z
VoteTAG: 1
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 2
FirstChildTAG: ok got it I know where I went wrong
FirstChildUserIdTAG: 334968
FirstChildUserNameTAG: MCGEEC147
FirstChildCreateTimeTAG: 2013-03-18T18:10:54Z
FirstChildVoteTAG: 0
SecondChildTAG: Can somebody help me understand what I do wrong? I am getting frustrated. I followed the step:
1)given x- mean/SD
2) Then I multiply this value by the r. This should given me the regression estimate, but it is wrong. What am I missing? I did not do step 3 as the exercise ask for the regression estimate (in standard units). Do i need to convert in weight? Thanks.
SecondChildUserIdTAG: 197730
SecondChildUserNameTAG: Claudia2505
SecondChildCreateTimeTAG: 2013-03-18T23:08:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I got it now...
SecondChildUserIdTAG: 197730
SecondChildUserNameTAG: Claudia2505
SecondChildCreateTimeTAG: 2013-03-18T23:30:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes claudia, convert it to weight
standard units to normal.
SecondChildUserIdTAG: 1140936
SecondChildUserNameTAG: molner
SecondChildCreateTimeTAG: 2013-03-19T10:50:07Z
SecondChildVoteTAG: 0
FirstChildTAG: 1 A
I have marked as correct but in progression I have 0/2, what happened. Other questions are marked correct too, I should have 10/10 or not?
Thanks
FirstChildUserIdTAG: 1158693
FirstChildUserNameTAG: dabad
FirstChildCreateTimeTAG: 2013-03-18T21:47:16Z
FirstChildVoteTAG: 0
IndexTAG: 679
TitleTAG: EVALUATION BUGS IN PROBLEM 2A and 2B
when posting the answer for problem 2A I posted the answer correct upto five decimal places and the rules above the exercise allow me to do so, however the grading system evaluated the answer as incorrect.
While posting the answer for problem 2B I rounded off the answer to zero decimal places and the grading system evaluated the answer as correct.
The answer I submitted for 2A was correct but I did not round it off - What inference should I draw???
UserIdTAG: 1312839
UserNameTAG: udakelkar
CreateTimeTAG: 2013-03-18T17:51:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: You did make sure you got the correct sign, didn't you?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T17:57:30Z
FirstChildVoteTAG: 1
SecondChildTAG: dont think too much. Think simple. there isnt much to calculate at all.
SecondChildUserIdTAG: 929681
SecondChildUserNameTAG: pratyushc
SecondChildCreateTimeTAG: 2013-03-19T02:48:28Z
SecondChildVoteTAG: 0
FirstChildTAG: The fact that you had to enter five decimal places suggests you got completely the wrong answer.
In 2B, the higher your score, the more right answers you got, so there is a positive association and the correlation is 1.
In 2A, the more right answers you got, the fewer wrong answers you got, so there is a negative association and the correlation is...?
FirstChildUserIdTAG: 224280
FirstChildUserNameTAG: Ryusui
FirstChildCreateTimeTAG: 2013-03-19T03:45:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Ryusui,
That is right. Conceptually as well as graphically 2B should be 1. However, when I use excel to calculate the 'r' using the multiplication of std units method, I get something like .90901. Have you tried this method? Did you get a different answer?
SecondChildUserIdTAG: 272952
SecondChildUserNameTAG: IamSid
SecondChildCreateTimeTAG: 2013-03-19T10:53:50Z
SecondChildVoteTAG: 0
FirstChildTAG: Ryusui,
Even you have calculated in excel right, you need to round it to nearest integer. However is does not need much of calculation.
FirstChildUserIdTAG: 684743
FirstChildUserNameTAG: subhashisa
FirstChildCreateTimeTAG: 2013-03-20T08:32:16Z
FirstChildVoteTAG: 0
IndexTAG: 680
TitleTAG: A filter to find all discussions with posts from staff
Hi,
as per title, would it be possible to add a filter to the discussion forum, which helps finding the discussions where staff members participated? Thanks
UserIdTAG: 407687
UserNameTAG: AndreaPi
CreateTimeTAG: 2013-03-18T17:10:09Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Try this link. At the moment it tracks posts only by prof. Adhikari. Everybody is free to add any other staff member:
[https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/posts-staff/][1]
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/posts-staff/
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-18T17:40:50Z
FirstChildVoteTAG: 3
SecondChildTAG: Excellent, thanks! I will look for some other staff member and try to add it to the page.
SecondChildUserIdTAG: 407687
SecondChildUserNameTAG: AndreaPi
SecondChildCreateTimeTAG: 2013-03-18T20:47:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I tried looking for other staff members' posts, without luck. Well, if I happen to find one, I'll add it.
SecondChildUserIdTAG: 407687
SecondChildUserNameTAG: AndreaPi
SecondChildCreateTimeTAG: 2013-03-18T21:08:21Z
SecondChildVoteTAG: 0
FirstChildTAG: Brilliant. I've added Philip B. Stark.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-18T23:56:29Z
FirstChildVoteTAG: 0
IndexTAG: 681
TitleTAG: problem 1 sos
Any hint for problem 1 ,
Will for the first time in this magnificent course I am one click away from the score of 100% ;so I'm a little bit hesitant at the moment not to through it away , any algebraic explanation would be appreciated .thanks
UserIdTAG: 810363
UserNameTAG: anht
CreateTimeTAG: 2013-03-18T16:48:05Z
VoteTAG: 2
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 4
FirstChildTAG: Try calculating it. Use any random valid value of r to find the estimate percentile for the length.
Or review ES10, where we did something similar.
For a formal algebraic proof however, you'll have to wait a bit more. I'm not the right person for it xD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T16:59:50Z
FirstChildVoteTAG: 1
FirstChildTAG: just a concept of question. U don't need to calculate it ! Please review Ch11-The regression effect carefully and then you will find the answer easily.!
FirstChildUserIdTAG: 1098016
FirstChildUserNameTAG: AlexSun88
FirstChildCreateTimeTAG: 2013-03-19T05:59:32Z
FirstChildVoteTAG: 0
FirstChildTAG: if you're a perfect scorer, i don't think you really need help. the concept on which this problem is based has been used in the previous excercise set, but, yeah, in disguise. numerically. don't just do calculations and get right answers, have some time to really play with and think over those numbers. have some observations done and you'll be done!!
btw, i hope that you understand that upward sloping means -----
best
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-03-19T07:19:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Yah it is defiantly upward sloping
FirstChildUserIdTAG: 810363
FirstChildUserNameTAG: anht
FirstChildCreateTimeTAG: 2013-03-19T09:40:49Z
FirstChildVoteTAG: 0
IndexTAG: 682
TitleTAG: mistake in chapter 6
in the text book chapter 6 the section of Association of Pairs of Variables, there is a mistake in line "The typical deviation of the y coordinate of a point from the mean of the y coordinates is SDX"
it seems to be SDY instead of SDX.
UserIdTAG: 152907
UserNameTAG: visperad
CreateTimeTAG: 2013-03-18T16:47:52Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: Yeah, it should be SD_Y.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T16:55:22Z
FirstChildVoteTAG: 1
IndexTAG: 683
TitleTAG: difficulty in answerin question 2 exercise 9
Please let me know answering format for exercise9 question 2a and 2 b as i m getting error message " invalid input".
I 'm not asking the answers but need to know whether to put numerical value or any thing else.
Thanks,
abhinaya
UserIdTAG: 1195486
UserNameTAG: Abhipuri
CreateTimeTAG: 2013-03-18T16:28:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Numerical value ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T16:41:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks!!!
SecondChildUserIdTAG: 1195486
SecondChildUserNameTAG: Abhipuri
SecondChildCreateTimeTAG: 2013-03-18T17:56:22Z
SecondChildVoteTAG: 0
IndexTAG: 684
TitleTAG: grades
i joined the classes on march so i couldn't do the first 6 exercises. I've already done all of them but in the progress page they don´t came up.
Can i retrieve those marks. my marks are quite good but without the first six i'm afraid that i won't be able to reach the 35%
UserIdTAG: 1391574
UserNameTAG: aonatibia
CreateTimeTAG: 2013-03-18T16:26:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The final alone is worth 30%. The Exercise Sets you can be graded for add as much as 20%.
So you can still get the passing grade fairly easily.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T16:40:49Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks!
SecondChildUserIdTAG: 1391574
SecondChildUserNameTAG: aonatibia
SecondChildCreateTimeTAG: 2013-03-18T16:43:46Z
SecondChildVoteTAG: 0
SecondChildTAG: actually, if you *were* graded on ES 7 and 8, add as much as 10% more :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T16:51:16Z
SecondChildVoteTAG: 0
IndexTAG: 685
TitleTAG: is it too late to join.?
how can l join the course as l registered for now ,lt seems that l 'm too late ?
is there any advanced courses ,or shall i try to catch you here?
too confuesed , i need your help , please
UserIdTAG: 1438620
UserNameTAG: drfatma1987
CreateTimeTAG: 2013-03-18T16:15:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You can still get up to a 50% grade, so you could still catch up :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T16:38:20Z
FirstChildVoteTAG: 0
SecondChildTAG: ok,thanx alot ,it needs alot of hard work .
SecondChildUserIdTAG: 1438620
SecondChildUserNameTAG: drfatma1987
SecondChildCreateTimeTAG: 2013-03-19T09:46:12Z
SecondChildVoteTAG: 0
IndexTAG: 686
TitleTAG: Understanding of the questions
Hello everyone, my english is quite bad and I don't get the difference between :
- "The association is positive as older couples consist of older wives and older husbands."
And - "The association is positive as husbands tend to be older than their wives."
I don't see what is different between the two options. In my mind it looks the same association. Thanks.
UserIdTAG: 1151142
UserNameTAG: Mohamed-Salmane
CreateTimeTAG: 2013-03-18T15:57:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Older men have older wives and that is relation to one another and in pairs older couples consist of older men and women.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-18T16:09:11Z
FirstChildVoteTAG: 2
SecondChildTAG: Ok so if I understand well :
"The association is positive as older couples consist of older wives and older husbands." mean older men and women but not necessarely a man older than his wife.
- "The association is positive as husbands tend to be older than their wives." means the man is older than his wife.
SecondChildUserIdTAG: 1151142
SecondChildUserNameTAG: Mohamed-Salmane
SecondChildCreateTimeTAG: 2013-03-18T16:17:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Exactly :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T16:36:51Z
SecondChildVoteTAG: 0
SecondChildTAG: @Mohamed-Salmane - I think your English writing is quite good! Please give yourself a lot of credit for that.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-18T17:34:04Z
SecondChildVoteTAG: 0
IndexTAG: 687
TitleTAG: Problem 3 of Exercise set 11 is the most Difficult one!!!
Problem 3 of Exercise set 11 is the most Difficult one!
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-03-18T15:09:50Z
VoteTAG: 7
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 1
FirstChildTAG: We should better thank professor Ani for this question. For a moment I hesitated, but then I decided to do it. :)
FirstChildUserIdTAG: 911813
FirstChildUserNameTAG: vukasinbvasic
FirstChildCreateTimeTAG: 2013-03-18T15:34:59Z
FirstChildVoteTAG: 7
SecondChildTAG: Same here
SecondChildUserIdTAG: 967531
SecondChildUserNameTAG: manjusinghal
SecondChildCreateTimeTAG: 2013-03-18T16:01:58Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm afraid now, not at ex 11 yet...
SecondChildUserIdTAG: 1061881
SecondChildUserNameTAG: kristen1trigen
SecondChildCreateTimeTAG: 2013-03-18T16:56:57Z
SecondChildVoteTAG: 0
SecondChildTAG: you'll be in for a treat :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T17:01:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Don't be afraid, but DO be very careful!
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-18T17:34:51Z
SecondChildVoteTAG: 0
SecondChildTAG: On the instructions of Problem 3 is the answer. It's been an exciting travels the statistics of the hand with an excellent teacher. Thank you!
SecondChildUserIdTAG: 1024935
SecondChildUserNameTAG: N3
SecondChildCreateTimeTAG: 2013-03-18T19:43:50Z
SecondChildVoteTAG: 0
SecondChildTAG: hahahah
SecondChildUserIdTAG: 1142696
SecondChildUserNameTAG: ParulG
SecondChildCreateTimeTAG: 2013-03-19T15:02:14Z
SecondChildVoteTAG: 0
IndexTAG: 688
TitleTAG: cannot see the lecture link
I cannot see the links for the lecture!
UserIdTAG: 373089
UserNameTAG: DocPuneet
CreateTimeTAG: 2013-03-18T14:13:04Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: You can't see the links, or the lectures themselves? At the moment, I can't see any lecture using Chrome either.
But everything works nicely in Firefox. You might want to try that.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T15:07:23Z
FirstChildVoteTAG: 1
SecondChildTAG: I'm using Firefox and can't see any links to lectures or text, just some plain headings at the top of the page:
Lec 6.1-6.3
Text Ch 5-8
SecondChildUserIdTAG: 495943
SecondChildUserNameTAG: Akosiwa
SecondChildCreateTimeTAG: 2013-03-18T23:56:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Akosiwa, the lectures aren't linked on the practice question page. They are in the menu to the left, where you have found all the previous lectures. The link above the link to the practice page (Section 6 Relation between two variables).
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-19T01:07:15Z
SecondChildVoteTAG: 0
IndexTAG: 689
TitleTAG: exercise 11 Problem 2A and 2B
2A. Slope= 0.75*0.45/0.5= 0.675
intercept= 23- 0.675*6 = 18.95 Where did I go wrong? please help
2B. 0.675*0.5= 0.3375 Where is my mistake need clarity.
UserIdTAG: 521763
UserNameTAG: taakondjo
CreateTimeTAG: 2013-03-18T14:06:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The problem is weight vs diameter... see????
FirstChildUserIdTAG: 400844
FirstChildUserNameTAG: Mario007
FirstChildCreateTimeTAG: 2013-03-18T15:02:30Z
FirstChildVoteTAG: 0
FirstChildTAG: The egg diameter is the given data. The chick weight is the unknown.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T15:11:21Z
FirstChildVoteTAG: 0
IndexTAG: 690
TitleTAG: [Midterm Q2C] Used Alternative Method, Cannot figure why I didn't get the right answer
The solution posted is drawing out the diagram to determine the mean and median. However, I used a different method and my result was wrong, could someone explain to me why this method is incorrect?
Here is what I did
to find mean, I calculated the sum of each percentage multiplied by each interval points, ie. 28%*4+36%*4+...12%*8 = 4.96
To find median, which is 50% of the data. I know interval 0-4hr contains 28%, thus 50% of the data or the median will lie within 4-8hr interval
- to calculate the exact number, I find what is percentage located within the 4-8hr interval, ie. 50-28=22
- each percentage point is 9%/point
- I find the exact point where the median is located 4 + 22/9 = 6.44
*mean = 4.96 and median = 6.44*
Therefore, for this distribution, Median > Average
However, the **solution** stated that
> The average is bigger than the median.
UserIdTAG: 1278232
UserNameTAG: eirras
CreateTimeTAG: 2013-03-18T13:47:07Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Your median is correct, but your average isn't.
For the (estimated) average of the values, you can do it in a couple ways. Following the same idea you used, and since we assume an uniform distribution, you'd need to find the weight of every single value (F.I 0 to 3 hours is 7% each, 4 to 7 is 9% each, 20 to 27 is 1.5% each, ecc...), then sum together each value times its respective weight.
You'd then find a value for the Mean>6.44.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T15:03:05Z
FirstChildVoteTAG: 1
SecondChildTAG: Can't you use the midpoints of each bin (assuming uniform distribution) and calculate weighted average using those 5 midpoints. At any rate the posted answer relying on "intuition" seems......I don't know what.
SecondChildUserIdTAG: 1259984
SecondChildUserNameTAG: mcc
SecondChildCreateTimeTAG: 2013-03-18T16:55:59Z
SecondChildVoteTAG: 0
SecondChildTAG: not rigorous?
SecondChildUserIdTAG: 1259984
SecondChildUserNameTAG: mcc
SecondChildCreateTimeTAG: 2013-03-18T17:02:42Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm sure there's a formal mathematical proof for why it doesn't work, but I try to stay away from those as much as I can :O
Intuitively, I think you would be greatly overstating the weight of the lower values with your method, and that ruins the calculation. Maybe if every range had the same size it would work, but the higher values are a lot more "scattered".
This also tells you why the median has to be lower than the average, intuitively. A lot of low values drag the median value down, while the few very high values don't. **But** they do have a significant influence on the average, dragging it up.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T17:12:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Midpoint was bad terminology on my part. I weighted the bin AVERAGES--5 in total--to get the average. I re-computed the average by your suggested method i. e. weighting each datum, and got the same answer. Either way gets average from histogram (previous assumptions applicable).
Considering the earlier "senior citizen" problem definition lets call it even.
SecondChildUserIdTAG: 1259984
SecondChildUserNameTAG: mcc
SecondChildCreateTimeTAG: 2013-03-18T20:52:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Klionheart! hm... I am still confuse how to mathematically calculate the average from the method you showed.
I found the weight of each point, the sum is 22%/point. What does the following do? I am stuck here
> then sum together each value times its respective weight.
Do you mind explain it further? Thank you again!
SecondChildUserIdTAG: 1278232
SecondChildUserNameTAG: eirras
SecondChildCreateTimeTAG: 2013-03-19T18:38:26Z
SecondChildVoteTAG: 0
IndexTAG: 691
TitleTAG: grading
hello stat 2.1x, i would like to know if i get for example 35% total in the exercise sets, midterm and final, is it that they are still going to reduce the take of the percentage for the worst two done exercise sets???
UserIdTAG: 439981
UserNameTAG: enom200
CreateTimeTAG: 2013-03-18T13:47:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The grade you see on the progress tab can only go up, not down. The two worst ES Results are already taken out in the ES Average(you have two small black x over some ES columns - those are the ignored results).
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T14:49:28Z
FirstChildVoteTAG: 2
IndexTAG: 692
TitleTAG: NA
in exercise set 9 it's impossible to fill in NA...i am very confused
UserIdTAG: 1280120
UserNameTAG: Rabia93
CreateTimeTAG: 2013-03-18T12:44:31Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: yeah, it's a bug.
But, you might want to take it as a hint ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T13:23:52Z
FirstChildVoteTAG: 0
FirstChildTAG: Maybe it's because you have to fill a number...
Cheers
FirstChildUserIdTAG: 6050
FirstChildUserNameTAG: xavutrecht
FirstChildCreateTimeTAG: 2013-03-18T13:24:10Z
FirstChildVoteTAG: 0
FirstChildTAG: The solution is a number guys......
FirstChildUserIdTAG: 400844
FirstChildUserNameTAG: Mario007
FirstChildCreateTimeTAG: 2013-03-18T15:03:16Z
FirstChildVoteTAG: 0
IndexTAG: 693
TitleTAG: questions???
I don´t understand this questions...it's me?
UserIdTAG: 1203825
UserNameTAG: alvescosta
CreateTimeTAG: 2013-03-18T12:03:27Z
VoteTAG: 3
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: None of them? Or is there one Problem in particular that you don't understand?
We might be able to help if you give a bit more details ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T12:25:12Z
FirstChildVoteTAG: 2
IndexTAG: 694
TitleTAG: STAFF
Is standard unit and probability is the same concept.
As both varies between 0 to 1.
UserIdTAG: 39476
UserNameTAG: abhyuday
CreateTimeTAG: 2013-03-18T11:38:59Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 3
FirstChildTAG: Related. SU is area under a curve.
The probability of datum falling anywhere under the curve is 100% (or 1)
So, the probability of a datum falling into a certain range under the curve is derived using SU.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-18T14:17:46Z
FirstChildVoteTAG: 0
FirstChildTAG: Sorry, both of you, but I have to fix what you've said:
Standard units are not between 0 and 1. If an entry in a list is 3.18 SDs below average, its value in standard units is -3.18.
Standard units aren't areas either. On a histogram, they're points on the horizontal axis.
So, not probabilities at all. As ArthurBarabash was trying to say, you can use standard units to find probabilities (or proportions) under the normal curve.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-19T06:04:10Z
FirstChildVoteTAG: 1
FirstChildTAG: ![enter image description here][1]
It helps to draw the curve for the standard normal. The horizontal values are the Z scores, and they are symmetric around 0.
The area under the curve is the probability of (in this case) being less than Z. (Some tables will give you the probability of being greater than Z, so you need to check what is being given.)
[1]: https://edxuploads.s3.amazonaws.com/13637320894954466.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-19T22:31:57Z
FirstChildVoteTAG: 0
IndexTAG: 695
TitleTAG: the use of the term 'association'
Hi,
I have one question: I have always encountered the term 'association' in the context of categorical data (for instance, having a specific mutation vs. disease status) and the term 'correlation' in the context of numerical data.
Now I see that association actually encompasses all kinds of data and roughly implies a relation between the data.
Could someone elaborate a bit more on this observation?
Thank you.
UserIdTAG: 872238
UserNameTAG: athanasiadis
CreateTimeTAG: 2013-03-18T10:49:09Z
VoteTAG: 1
CoursewareTAG: Section 6: Relation between two variables / Lec 6.1 Scatter Diagrams
NumberOfReplyTAG: 1
FirstChildTAG: Correlation means linear relation. Association means any kind of relation. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-19T05:59:26Z
FirstChildVoteTAG: 3
IndexTAG: 696
TitleTAG: Exercise 9
How do I get graded for the fill in part of the exercise?
UserIdTAG: 1375281
UserNameTAG: kknyame
CreateTimeTAG: 2013-03-18T10:48:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Like for most other parts: you put in the numerical answer and press Check.
Although there is a bug that prevents your from putting in "NA" as the answer, this doesn't stop you from answering correctly. (*big hint*)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T11:20:17Z
FirstChildVoteTAG: 0
IndexTAG: 697
TitleTAG: Exercise 9-4 and 9-5 textbook: figure 9-4 (and not 5.2-1)
Hi everyone,
I think that in exercise 9-4 and 9-5 where it says "Use Figure 5.2-1 to find the solution" is a mistake and the right figure is 9-4 (because in 5.2-1 you cannot find r)
UserIdTAG: 950696
UserNameTAG: benava48
CreateTimeTAG: 2013-03-18T10:31:55Z
VoteTAG: 10
CoursewareTAG: Practice for Exercise set 11 / Reading and Practice for Exercise set 11
NumberOfReplyTAG: 1
FirstChildTAG: i am also confused about how to get value of r. The applet doesn't show clearly.
Does anyone have idea about how to find r in exercise 9-4 and 9-5?
FirstChildUserIdTAG: 688695
FirstChildUserNameTAG: Xunzi
FirstChildCreateTimeTAG: 2013-03-18T22:23:33Z
FirstChildVoteTAG: 2
SecondChildTAG: Go back up to Figure 9.4. Use the dropdown boxes to plot the appropriate variables. r is given at the bottom of the plot. Click on Univariate Stats for means and sds.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-18T23:35:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for advice. I was just trying to look where to look for r in Figure 5.2-1 ... no idea.
SecondChildUserIdTAG: 437379
SecondChildUserNameTAG: MaisaSM
SecondChildCreateTimeTAG: 2013-03-19T11:37:54Z
SecondChildVoteTAG: 0
IndexTAG: 698
TitleTAG: An excessive request.
Dear diligent and laborious professor & all staff, I really love this course and learn a lot in it. And I'm just wondering whether one of staff could include the previous exercises and solutions into a pdf, coz I found that it's really inconvenient to click the questions I erred to see the solutions. And I think a pdf is helpful for us to review the pertinent knowledge.
Once again, gratitude to prof&staff.
UserIdTAG: 902440
UserNameTAG: Leo19920816
CreateTimeTAG: 2013-03-18T09:56:02Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I think it is a good idea to have it in PDF
FirstChildUserIdTAG: 569767
FirstChildUserNameTAG: SanjayS72
FirstChildCreateTimeTAG: 2013-03-18T10:31:26Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree. In a previous edx course I took, the answers and solutions were provided in a pdf which made studying much easier.
FirstChildUserIdTAG: 617920
FirstChildUserNameTAG: CMR
FirstChildCreateTimeTAG: 2013-03-18T11:52:19Z
FirstChildVoteTAG: 0
FirstChildTAG: That would help TREMENDOUSLY. Please!!
FirstChildUserIdTAG: 1292868
FirstChildUserNameTAG: SandyL
FirstChildCreateTimeTAG: 2013-03-18T17:51:31Z
FirstChildVoteTAG: 0
IndexTAG: 699
TitleTAG: Derivation of formula for correlation coefficient
Could someone from the staff please put the derivation of the formula for r in the supplements section? Thanks.
UserIdTAG: 1024625
UserNameTAG: jos_gubbels
CreateTimeTAG: 2013-03-18T09:20:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 700
TitleTAG: Next Course--When?
Dear Prof. Ani Adhikari,
Thank you very much for your efforts. I really enjoyed the course. That is why I am asking when will be the next course?
Many thanks
UserIdTAG: 446822
UserNameTAG: HAwad
CreateTimeTAG: 2013-03-18T09:08:25Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 701
TitleTAG: Why is correlation the "right" slope?
I understood that we needed a slope b/w 0 and 1 and correlation is an ideal variable considering it is b/w that and relates them, but why is it ALGEBRAICALLY the right slope?
UserIdTAG: 1106062
UserNameTAG: Saurabh_Maurya
CreateTimeTAG: 2013-03-18T08:57:43Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 2
FirstChildTAG: My understanding is that correlation coefficient is not the slope, but a measure of the variability of the points around a straight line. Any straight line sloping up can be +1 and any straight line sloping down can be -1.
FirstChildUserIdTAG: 382959
FirstChildUserNameTAG: RajdeepSingh
FirstChildCreateTimeTAG: 2013-03-18T16:43:49Z
FirstChildVoteTAG: 0
FirstChildTAG: In a few days I'll post the algebraic derivation of the regression line. That should answer your question. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-19T05:57:26Z
FirstChildVoteTAG: 0
SecondChildTAG: Dear Prof. Adhikari,
Since this seems to be a recurring question on the forum, I hope you won't mind if in the meantime I post the link to the derivation in the Online Textbook:
http://statistics.berkeley.edu/~stark/SticiGui/Text/regression.htm
scroll down to the sentence "Recall from Chapter 4, Measures of Location and Spread, that the mean is the number for which the rms of the deviations is smallest [..]", and click on the plus button. A simple and complete derivation will be shown.
SecondChildUserIdTAG: 407687
SecondChildUserNameTAG: AndreaPi
SecondChildCreateTimeTAG: 2013-03-20T09:26:01Z
SecondChildVoteTAG: 0
IndexTAG: 702
TitleTAG: STAFF-DUE DATE FOR MIDTERM
I would like to express my disappointment concerning midterm. You had communicated that the due date for midterm would be on 19th March, 2013. why is it that you have suddenly changed it back to 15th March, 2013. I intended to complete the exam on 19th March as I was committed with other things
please i seek you quick reversal of the decision.
UserIdTAG: 510759
UserNameTAG: SELEMANI
CreateTimeTAG: 2013-03-18T07:02:53Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: > I would like to express my disappointment concerning midterm. You had communicated that the due date for midterm would be on 19th March, 2013.
Where did you see this? I'm only relatively new, but **everything** I have seen said the 13th (completing on the 15th). The course policy, the exam itself in big bold writing, the Course Info note.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-18T07:06:11Z
FirstChildVoteTAG: 3
SecondChildTAG: Exactly.
Plus, while the midterm was on, it was the **only** link under Week4. The lectures and ESs appeared later, so you couldn't have mixed the dates up even if you wanted.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T09:53:16Z
SecondChildVoteTAG: 0
FirstChildTAG: Is this March 19th business the new GMT argument?
It boggles the mind how some enroll in the course and dont ever bother to log in and check the friggin' landing page!
When will people ever stop whining and start taking responsibility for their own actions?
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-18T14:13:55Z
FirstChildVoteTAG: 3
FirstChildTAG: I have copied and pasted the **original** course schedule at
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Course_Schedule.pdf
**MIDTERM, WED MAR 13: Describing one variable (Sections 1-5)**
So where was March 19th please ?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-18T15:26:55Z
FirstChildVoteTAG: 1
FirstChildTAG: >When will people ever stop whining and start taking responsibility for their own actions?
Never. They will whine, and call *you* mean and nasty if you tell them to grow up. The level of whining, and blaming of others for your own mistakes, is just astounding.
This is supposed to be a university level stats course - yet you have people who are unable to follow basic instructions, who can't tell the time, who can't figure out the grading scheme, who can't post in the correct forum, and who can't use a search function.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-18T21:46:35Z
FirstChildVoteTAG: 0
SecondChildTAG: I think the question asked is wrong and I think we should not dwell on these things either and ignore them after placing the facts.I don't think it is the prerogative of any of the students to tell another co-student to grow up so shall we not engage in negative discussions here.Let us stick to statistics and not continue flame wars.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-19T02:19:43Z
SecondChildVoteTAG: 0
SecondChildTAG: > Never. They will whine,
As I have noticed. Whine. Grovel. Toady. A real eye opener.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-19T05:37:56Z
SecondChildVoteTAG: 0
IndexTAG: 703
TitleTAG: 1B
The questions of 1a and 1b are the same, but in 1a i got right, but in the 1b something is wrong...how to understand?
UserIdTAG: 1334866
UserNameTAG: Geochem
CreateTimeTAG: 2013-03-18T05:50:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 3
FirstChildTAG: Maybe you didn't account for the sign? It's the only difference that comes to mind...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T09:54:04Z
FirstChildVoteTAG: 0
SecondChildTAG: I recalculate and find what I did wrong!
SecondChildUserIdTAG: 1334866
SecondChildUserNameTAG: Geochem
SecondChildCreateTimeTAG: 2013-03-19T08:02:32Z
SecondChildVoteTAG: 0
SecondChildTAG: It happen also to me, 1A ok 1B wrong and I had care of the negative.
SecondChildUserIdTAG: 1140936
SecondChildUserNameTAG: molner
SecondChildCreateTimeTAG: 2013-03-19T10:53:06Z
SecondChildVoteTAG: 0
SecondChildTAG: 1b is negative the standard unit
SecondChildUserIdTAG: 1041097
SecondChildUserNameTAG: JUANADORIS2013
SecondChildCreateTimeTAG: 2013-03-20T05:12:58Z
SecondChildVoteTAG: 0
SecondChildTAG: 1b is positive
SecondChildUserIdTAG: 1078818
SecondChildUserNameTAG: Jamili
SecondChildCreateTimeTAG: 2013-03-20T16:11:34Z
SecondChildVoteTAG: 0
SecondChildTAG: i have solved the Q 1b and it is positive and result is correct
SecondChildUserIdTAG: 1078818
SecondChildUserNameTAG: Jamili
SecondChildCreateTimeTAG: 2013-03-20T16:12:15Z
SecondChildVoteTAG: 0
FirstChildTAG: Review your calculation, some swapped number or something like that. If you got 1a you should have done well in 1b.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-18T09:56:29Z
FirstChildVoteTAG: 0
FirstChildTAG: It's better to use the commands and functions in spreadsheet to link your solutions so that the next calculations will still be the same.
FirstChildUserIdTAG: 1311779
FirstChildUserNameTAG: maryannevilla
FirstChildCreateTimeTAG: 2013-03-18T14:45:56Z
FirstChildVoteTAG: 0
SecondChildTAG: For this course, it's better if you don't use a spreadsheet at all, and do your calculations manually, so you remain aware of what you're doing.
But then again, it's just my opinion. To each his(her) own.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T15:09:39Z
SecondChildVoteTAG: 0
IndexTAG: 704
TitleTAG: Question 1
How is the first graph not representative of a negative linear correlation? Looks pretty linear to me. And it has to be negative so the other options don't make sense.
UserIdTAG: 1271683
UserNameTAG: ericamills33
CreateTimeTAG: 2013-03-18T05:44:42Z
VoteTAG: 16
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 5
FirstChildTAG: See the whole graph, the full line. Why are you giving hint about the answer?
FirstChildUserIdTAG: 592716
FirstChildUserNameTAG: drsaswatinath
FirstChildCreateTimeTAG: 2013-03-18T07:13:04Z
FirstChildVoteTAG: 2
SecondChildTAG: Ugly drawings time!!
![enter image description here][1]
Which is a line? A or B?
Which looks more like the graph in Problem 1?
I'll stop here, since the ES is still graded.
[1]: https://dl.dropbox.com/u/6636701/line.jpg
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T10:00:38Z
SecondChildVoteTAG: 0
SecondChildTAG: I too voted for linear negative. hope Prof A with explain sometime in the lecture.
SecondChildUserIdTAG: 929681
SecondChildUserNameTAG: pratyushc
SecondChildCreateTimeTAG: 2013-03-19T02:52:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Well again here, I find the interpretations from these graphs to be subjective.
I thought the answer was linear negative.
SecondChildUserIdTAG: 169509
SecondChildUserNameTAG: rajeevbasapathy
SecondChildCreateTimeTAG: 2013-03-19T13:46:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed. Main focus of studies leading up to Exercise Set 9 was on LINEAR associations. The scatter diagram for Question 1A is ambiguous and though one could draw a curve through there, one could just as easily step back a bit further, squint, and imagine a straight line generally sliding through those points.
SecondChildUserIdTAG: 1326845
SecondChildUserNameTAG: firefrorefiddle
SecondChildCreateTimeTAG: 2013-03-20T11:13:32Z
SecondChildVoteTAG: 0
SecondChildTAG: I found this one a bit disappointing, given that i believed it to be exponential in appearance, but all of the examples in the lecture and textbook showed "nonlinear" as a clear sine curve or parabolic curve.
This problem might have been "linear" with a lower correlation coefficient.
I suppose I should have looked at the forum first, given that this post gives away the correct answer for free :)
SecondChildUserIdTAG: 162716
SecondChildUserNameTAG: nathanleiby
SecondChildCreateTimeTAG: 2013-03-20T20:06:23Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm with you, Erica, but I suppose it is a question of how linear is linear....
FirstChildUserIdTAG: 1082561
FirstChildUserNameTAG: Streams
FirstChildCreateTimeTAG: 2013-03-18T21:04:26Z
FirstChildVoteTAG: 0
FirstChildTAG: > How is the first graph not representative of a negative linear correlation?
Can you visually place a straight line (no bends or curves) through the points - so an equal number of points are above and below the line?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-18T23:25:36Z
FirstChildVoteTAG: 2
SecondChildTAG: That's an interesting perspective. Not one I had encountered in the lecture, but a good idea.
Thanks for sharing.
SecondChildUserIdTAG: 162716
SecondChildUserNameTAG: nathanleiby
SecondChildCreateTimeTAG: 2013-03-20T20:07:10Z
SecondChildVoteTAG: 0
FirstChildTAG: I think that saying it's a linear can be a stretch (I chose that too, unfortunately) but then if this is graded, it should have a clearer graphical choice, not one that be possibly be ambiguous.
FirstChildUserIdTAG: 990109
FirstChildUserNameTAG: sarabel
FirstChildCreateTimeTAG: 2013-03-19T05:53:43Z
FirstChildVoteTAG: 4
FirstChildTAG: I agree with the others that are complaining about Q1. The only examples in the videos were either:
(i) linear, or
(ii) non-linear "snake," or
(iii) non-linear heteroscedastic.
Of those three choices, linear is obviously the best.
And some of the linear examples in the video were pretty "fuzzy." In particular, look at Lecture 6.2 at around the 11:40 mark. There the professor is discussing the correlation between midterm and final exam scores. If you look at the side-by-side comparison of the midterm-to-final and the final-to-midterm graphs (where she flips the x an y axis), there is a fairly obvious curve. However, she discusses these as if they were linear.
FirstChildUserIdTAG: 950537
FirstChildUserNameTAG: cjc71
FirstChildCreateTimeTAG: 2013-03-19T19:42:38Z
FirstChildVoteTAG: 2
IndexTAG: 705
TitleTAG: Midterm missed by mistake
I thought that i saw the due date for midterm to be 19 march. So by mistake i missed it .Is there anyway i can give another exam for midterm or not?
UserIdTAG: 679933
UserNameTAG: rohan25
CreateTimeTAG: 2013-03-18T05:32:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: hie you did not miss it by mistake. even myself I saw that the deadline was on 19th March 2013
I wonder why they have suddenly changed it . I opened my computer today I find that they have changed the due date to 15th March 2013. we need to handle the cause professionally
FirstChildUserIdTAG: 510759
FirstChildUserNameTAG: SELEMANI
FirstChildCreateTimeTAG: 2013-03-18T06:59:43Z
FirstChildVoteTAG: 0
SecondChildTAG: No, they never changed the midterm due date. I've been here since the beginning, and it has always been known the midterm would start on the 13th.
On the 11th we got the news in Course Info that announced the timeframe, and it is clearly stated there that:
> The midterm will become available at 7:00 A.M. Greenwich Mean Time (GMT) on Wednesday March 13. It will be due in 48 hours, at 7:00 A.M. (GMT) on Friday March 15.
Look it up. It never changed.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T10:04:39Z
SecondChildVoteTAG: 0
SecondChildTAG: No problem what's done is done i cannot change it now . Now onwards i will check the site more often.
SecondChildUserIdTAG: 679933
SecondChildUserNameTAG: rohan25
SecondChildCreateTimeTAG: 2013-03-19T08:40:37Z
SecondChildVoteTAG: 0
IndexTAG: 706
TitleTAG: EXERCISE 8 NOT MARKED
Dear Dr Ani
On the 13 March, at 17h20 GMT i logged on to do my exercise 8 and to my disappointment i was not able to submit because the system was already showing answers. I understand we are using GMT. i know the course allow us to drop two low marks. Is there an explanation why the time was cut?
UserIdTAG: 617692
UserNameTAG: Inoukapo
CreateTimeTAG: 2013-03-18T04:53:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: Are you absolutely sure that it was 17.20 GMT? As in, -2 hours respective to your current local timezone(you're from Namibia, right?)?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T10:08:59Z
FirstChildVoteTAG: 1
SecondChildTAG: i am sure it was 02h20 Thursday morning Namibian time. What got me disappointment is that the exercise are available according to GMT (15 hours difference) and it seems the deadline has a different time zone. I think it was because the midterm test was released that time and they decided to close the exercise which i think it is not fair.
SecondChildUserIdTAG: 617692
SecondChildUserNameTAG: Inoukapo
SecondChildCreateTimeTAG: 2013-03-19T04:57:31Z
SecondChildVoteTAG: 0
IndexTAG: 707
TitleTAG: Regression Fallacy: What is Natural Variability?
"*Thinking that the regression e ffect is due to some particular
external cause, other than simply **natural variability***"
Hello guys, I need your assistance regarding the term. What is meant by **Natural Variablity** and What are the example of it?
UserIdTAG: 498723
UserNameTAG: YLTO
CreateTimeTAG: 2013-03-18T04:37:33Z
VoteTAG: 0
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.3: Regression effect, Galton, and the regression fallacy
NumberOfReplyTAG: 2
FirstChildTAG: The lecture refers to the fact that this variability occurs in nature, particularly among human beings. Examples are given in the lecture (heights of parents/children, ...).
It's an empirical fact, that's all, in spite of Galton's desire, another case of certain interpretations of the Nietzsche's work that provoked atrocious consequences, by the way.
It's ironic that Galton, by contributing to the foundations of statistics, the science of "mediocrity", undermined, fortunately for the posterity, his own 'hybris' (this arrogant and inhuman ideals about the 'Übermensch').
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-18T11:23:02Z
FirstChildVoteTAG: 1
SecondChildTAG: What i can understand is that regression tend to maintain the stability of systems, it means limiting the dispersion of members of a system, for example not limit in growing.
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-18T14:08:43Z
SecondChildVoteTAG: 0
FirstChildTAG: The explaination of the Regression Effect on the Online Textbook is extremely clear:
http://statistics.berkeley.edu/~stark/SticiGui/Text/regressionErrors.htm#regression_effect
In practice, when estimating the **average** value of a variable Y from the value of a variable X which is positively correlated with Y, a value of X above mu_x (mean of X) corresponds to an average value of Y above mu_y (because of positive correlation). However the **average** value of Y will not be as much larger than mu_y, as the value of X is than mu_x. The reason is that the above mean value of X is due in part to some special causes, which influence in the same way also Y (positive correlation) and in part to pure chance. Special causes influence also Y, and contribute to an average value of Y which is higher than mu_y. But it is rare (improbable) that the same good luck that helped get an high value of X, happens again, or better, it will happen sometimes and sometimes not. So, on average, Y in standard units will be higher than 0 but lower than X, as stated by the formula `y_estimated = r*x` (true for y and x in standard units).
Note that all this is true only of the **average** value of Y: a **single** student who did great on the midterm, may do as well as or even better on the final. But it's extremely unlikely that **most** students who did great on the midterm, will do as well on the final. They'll probably get a good vote because their good skills are still there, but not all of them will be as lucky as the first time, so the votes on average will be not as good as the first time.
PS the same reasoning can be made in the case of negative correlation.
FirstChildUserIdTAG: 407687
FirstChildUserNameTAG: AndreaPi
FirstChildCreateTimeTAG: 2013-03-21T12:05:35Z
FirstChildVoteTAG: 1
IndexTAG: 708
TitleTAG: Chebychev
Chebychev ??
UserIdTAG: 1033735
UserNameTAG: nelsiton
CreateTimeTAG: 2013-03-18T04:36:44Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: Chebychev.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T10:10:42Z
FirstChildVoteTAG: 1
FirstChildTAG: Tschebysheff
:-)
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-18T14:18:44Z
FirstChildVoteTAG: 0
FirstChildTAG: Is this a drinking game?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-18T21:48:32Z
FirstChildVoteTAG: 0
SecondChildTAG: Чебышев ;-)
SecondChildUserIdTAG: 1195044
SecondChildUserNameTAG: rometw
SecondChildCreateTimeTAG: 2013-03-18T22:23:14Z
SecondChildVoteTAG: 0
IndexTAG: 709
TitleTAG: Promedio
Markov??? aplicaciones
UserIdTAG: 1033735
UserNameTAG: nelsiton
CreateTimeTAG: 2013-03-18T04:33:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 0
IndexTAG: 710
TitleTAG: Markov
Necesito mas información sobre la desigualdad de Markov
UserIdTAG: 1033735
UserNameTAG: nelsiton
CreateTimeTAG: 2013-03-18T04:27:23Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Review Lecture 3.5, everything you need to know about Markov is there.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-18T10:15:26Z
FirstChildVoteTAG: 0
IndexTAG: 711
TitleTAG: Prof A
At the end of the course i want to thank u alot i like your way of teaching. I hope i will finish the whole course with ya
I want to ask you why there is black X in ex9 and ex12 in the progress page? Dose it mean their grade have to be included to the total grade?
UserIdTAG: 1288142
UserNameTAG: aldawlah
CreateTimeTAG: 2013-03-18T04:11:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The grading scheme tells you that your two lowest problem set marks are dropped. The x marks your two lowest.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-18T07:34:35Z
FirstChildVoteTAG: 0
SecondChildTAG: ex 12 is nt discvred by us so blck x mean what !
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-18T13:35:49Z
SecondChildVoteTAG: 0
SecondChildTAG: once you have completed all the assignments, the 2 lowest marks will be not included in your average. The "x" represents the lowest marks currently. Once all assignments are finished and time elapsed in the course those "x's" will move to your lowest marked homework.
SecondChildUserIdTAG: 617920
SecondChildUserNameTAG: CMR
SecondChildCreateTimeTAG: 2013-03-18T13:46:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks for explaining
But ex. 12 is being X while we didnt have it yet !!!!!!?
FirstChildUserIdTAG: 1288142
FirstChildUserNameTAG: aldawlah
FirstChildCreateTimeTAG: 2013-03-19T10:22:19Z
FirstChildVoteTAG: 0
IndexTAG: 712
TitleTAG: La aplicación de la Media
El uso de la media me permite analizar el comportamiento de los datos con respecto al centro de la información
UserIdTAG: 1033735
UserNameTAG: nelsiton
CreateTimeTAG: 2013-03-18T03:50:55Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 1
FirstChildTAG: Translate:
"The use of the media allows me to analyze the behavior of the data with respect to the information centre"
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-03-18T03:57:20Z
FirstChildVoteTAG: 0
IndexTAG: 713
TitleTAG: Professor Ani is great!!!
Hi Professor Ani,
i just want to say that i really love your style of teaching and your sense of humor.
It is such a pleasure of taking this class from you!!
I'm so excited to take all other classes you'll teach!!
UserIdTAG: 1087255
UserNameTAG: RPersaud
CreateTimeTAG: 2013-03-18T03:32:38Z
VoteTAG: 135
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 11
FirstChildTAG: Clarity is the name of the game; she is the real deal.
FirstChildUserIdTAG: 142494
FirstChildUserNameTAG: jaria101
FirstChildCreateTimeTAG: 2013-03-18T05:30:48Z
FirstChildVoteTAG: 16
SecondChildTAG: Simple Delivery times mean of Focus & Precision,in English =
- = Simple Delivery * ( Focus + Precision)/2, in maths
- = Prof. Ani's Style of Teaching
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-20T08:37:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Luv to do exercise sets, all due to Prof. A.'s passion for teaching. Can't we have additional optional teaching sets no. 13 & 14, total 3 in week 5 for improving grades, as happens in some other MOOC e.g. exercise set 12 in PH207x.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-20T15:33:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes she is!! I love the way she teaches!!
FirstChildUserIdTAG: 1094545
FirstChildUserNameTAG: Lacilia
FirstChildCreateTimeTAG: 2013-03-18T08:09:52Z
FirstChildVoteTAG: 10
SecondChildTAG: Yes, I agree with all of you and I love her teaching style and sense of humor.
SecondChildUserIdTAG: 967531
SecondChildUserNameTAG: manjusinghal
SecondChildCreateTimeTAG: 2013-03-18T16:01:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Wow Prof Ani....Thanks for last question......its midnight ....I can sleep with a smile now.....yuhoooo.....God bless!
SecondChildUserIdTAG: 1063817
SecondChildUserNameTAG: PriyankaChaman
SecondChildCreateTimeTAG: 2013-03-20T18:40:23Z
SecondChildVoteTAG: 0
FirstChildTAG: Should we expect Stat 2.2?
FirstChildUserIdTAG: 911813
FirstChildUserNameTAG: vukasinbvasic
FirstChildCreateTimeTAG: 2013-03-18T15:35:38Z
FirstChildVoteTAG: 33
SecondChildTAG: I really hope so!
SecondChildUserIdTAG: 885733
SecondChildUserNameTAG: Arie90435
SecondChildCreateTimeTAG: 2013-03-18T15:45:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too
SecondChildUserIdTAG: 1071309
SecondChildUserNameTAG: _Helena_
SecondChildCreateTimeTAG: 2013-03-20T10:33:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I hope they will decide to make 2.2 and 2.3 available online!
SecondChildUserIdTAG: 867437
SecondChildUserNameTAG: Ellyn
SecondChildCreateTimeTAG: 2013-03-20T21:39:01Z
SecondChildVoteTAG: 0
SecondChildTAG: eagerly waiting!!
SecondChildUserIdTAG: 1087255
SecondChildUserNameTAG: RPersaud
SecondChildCreateTimeTAG: 2013-03-25T03:40:06Z
SecondChildVoteTAG: 0
FirstChildTAG: She is best even newbies like me enjoying Stat. Never thought, one day I will pursue something that I hate most. I, indeed, enjoyed Stat 2.1X and fellow class mates who helped me to sail through. It was wonderful and pleasant experience. Thanks to all.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-18T21:50:48Z
FirstChildVoteTAG: 19
SecondChildTAG: I subscribe to the above. :)
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-19T17:05:34Z
SecondChildVoteTAG: 0
SecondChildTAG: "Stat=Greek"
That impression is history. Thanks a lot to all the people who took woes in making such an "idiot-proof" course.
SecondChildUserIdTAG: 1263723
SecondChildUserNameTAG: Chamikad
SecondChildCreateTimeTAG: 2013-03-19T17:55:23Z
SecondChildVoteTAG: 0
SecondChildTAG: I heartily agree. This has been a fantastic experience. I love the balance of Prof. A and Prof. Stark's text. Both are absolutely wonderful.
SecondChildUserIdTAG: 987070
SecondChildUserNameTAG: AStanford
SecondChildCreateTimeTAG: 2013-03-25T22:18:35Z
SecondChildVoteTAG: 0
FirstChildTAG: She is one of the greatest professors I have ever had!
FirstChildUserIdTAG: 1276362
FirstChildUserNameTAG: tanja_sp
FirstChildCreateTimeTAG: 2013-03-19T22:10:43Z
FirstChildVoteTAG: 11
SecondChildTAG: Thats so true!
I never thought such a wonderful logic was behind statistics.
SecondChildUserIdTAG: 1202828
SecondChildUserNameTAG: zam1991
SecondChildCreateTimeTAG: 2013-03-20T23:07:02Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree. She is a terrific teacher for beginners and the course as a whole is first rate.
FirstChildUserIdTAG: 252779
FirstChildUserNameTAG: msushi
FirstChildCreateTimeTAG: 2013-03-19T23:44:51Z
FirstChildVoteTAG: 8
FirstChildTAG: I agree 100% . Considering the fact this was a brand new subject for me , learnt via a brand new medium ( i never took any formal courses online) i am pleased and surprised at how much i have learnt since the course started. I am very grateful to the Prof for her time and consideration . This , i assume is a side gig for her besides her revered and heavy duty responsibilities at Berkeley , so it is really quite generous of her to commit to a project of perhaps unprecedented ambition and magnitude ..Thousands of students from all over the world attending a course with the insignia and cachet of an Institute like Berkeley and without any cost! It really is a commitment on the part of Prof Ani and all other Professors and tech logistics people involved , my mom is a teacher so i know just the full time job can be quite demanding !
If she is involved in any further courses i will definitely enrol and look forward to learning more with her customary flair , humor and clarity!
FirstChildUserIdTAG: 1015352
FirstChildUserNameTAG: weizkn
FirstChildCreateTimeTAG: 2013-03-20T14:26:06Z
FirstChildVoteTAG: 9
FirstChildTAG: Could not agree more. Great class and great teaching, at a great price!
FirstChildUserIdTAG: 867273
FirstChildUserNameTAG: astrochak
FirstChildCreateTimeTAG: 2013-03-20T22:00:27Z
FirstChildVoteTAG: 1
FirstChildTAG: Every now and then you'll find something by which to measure all the others.
I can't think of a better teacher - in anything I've taken - than Prof. Ani. (except maybe my 3rd grade teacher who taught multiplication in terms of candy bars; the days we used real candy were the best! :)
Rating teachers in percentage of Prof A's, (with a range from zero to Prof A.), calculate the SD and mean of your lifetime teachers...
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-20T23:18:43Z
FirstChildVoteTAG: 3
SecondChildTAG: haha.
nice one
SecondChildUserIdTAG: 1087255
SecondChildUserNameTAG: RPersaud
SecondChildCreateTimeTAG: 2013-03-25T03:34:27Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you Prof Ani. I'm very much eager to see you and learn again in stat 2.2x.
FirstChildUserIdTAG: 1176229
FirstChildUserNameTAG: Haimanot
FirstChildCreateTimeTAG: 2013-03-29T07:44:59Z
FirstChildVoteTAG: 0
FirstChildTAG: I am also very satisfied with the way the prof. Ani is holding lectures. They are not long, but include all the necessary info for the students to understand the concepts. Looking forward to enroll the next course.
FirstChildUserIdTAG: 1249078
FirstChildUserNameTAG: mares777
FirstChildCreateTimeTAG: 2013-03-30T23:05:21Z
FirstChildVoteTAG: 0
IndexTAG: 714
TitleTAG: PRACTICE FOR EXERCISE SET 9
Dear Prof Ani,
Could we have more practice excercises in set 9 rather than, to refer to the online text book.
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-03-18T03:19:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 715
TitleTAG: Midterm Problem 4B
Can someone explain to me how to approach this problem? I see how to find the overall class average in this example, but I don't see how you can say something about the overall Standard Deviation of the class based on just the SD of the sections without more information about how the scores are distributed. Thanks!
UserIdTAG: 1153828
UserNameTAG: Matt2edX
CreateTimeTAG: 2013-03-18T01:03:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Intuitively, you can see that if each exam had a SD of 9 then, since the exams had different averages, that the overall SD would need to be bigger. It actually turns out that you can compute the resulting SD.
In the lecture, it was mentioned that SD of a population could be found as:
SD = sqrt( sum(xi^2)/N - (sum(xi)/N)^2)
Mean = sum(xi)/N
Since we know of each section the value of N, mean, and SD, we can compute the value of sum(xi) and sum(xi^2)
The sum of these will be the sum for the entire class, and we can then compute the mean and SD for the whole class.
As I said at the beginning, for the question, you didn't need to do all the math, but just note that because of the varying mean, the SD for the full class had to be bigger than the SD for each section.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-03-18T02:43:24Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/wiki/Stat2.1x/find-sds-combined-group/,
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-18T10:31:34Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks. This seemed like a correct answer, but without seeing the math I wasn't sure whether it would always be true.
FirstChildUserIdTAG: 1153828
FirstChildUserNameTAG: Matt2edX
FirstChildCreateTimeTAG: 2013-03-19T14:56:22Z
FirstChildVoteTAG: 0
IndexTAG: 716
TitleTAG: lll
plz, sorry for asking abt something unrelated to the lectures and ex. but I really need how to assess a sample size if i'm planning for a survey, can any one help ????
UserIdTAG: 704053
UserNameTAG: jehadhassan
CreateTimeTAG: 2013-03-17T23:41:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: It depends on the alpha and beta error values that you have setand the expected difference between the two groups.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-18T01:35:57Z
FirstChildVoteTAG: 0
SecondChildTAG: thank you
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-18T06:07:53Z
SecondChildVoteTAG: 0
SecondChildTAG: this might help? http://www.surveysystem.com/sscalc.htm
SecondChildUserIdTAG: 1015153
SecondChildUserNameTAG: ruthiegyll
SecondChildCreateTimeTAG: 2013-03-19T07:59:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Or you could refer to the WHO document of determining the Sample size by Lwanga
SecondChildUserIdTAG: 169509
SecondChildUserNameTAG: rajeevbasapathy
SecondChildCreateTimeTAG: 2013-03-19T13:47:11Z
SecondChildVoteTAG: 0
FirstChildTAG: It depends on what sort of survey you are doing, and how you intend to obtain your sample - random, cluster, stratified, proportional, etc.
Maybe you should consult a statistician - one who has experience in study design.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-18T02:12:13Z
FirstChildVoteTAG: 0
SecondChildTAG: thank you
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-18T06:07:46Z
SecondChildVoteTAG: 0
IndexTAG: 717
TitleTAG: Answers of problems 2.a and 2.b in exercises 9
I had a lot of troubles in solving the problems 2.a and 2.b in section Exercises 9. And both my answers were incorrect. Somebody can help with the right answer and how to get to that?
In 2.b I did all the math and found r=0.84 but it seems I got it wrong.
UserIdTAG: 955090
UserNameTAG: Haack
CreateTimeTAG: 2013-03-17T23:41:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: The key is in the lecture about r, review it carefully. I didn't need to write down any calculation to solve these problems.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-17T23:59:24Z
FirstChildVoteTAG: 0
SecondChildTAG: I will try. Thank you.
SecondChildUserIdTAG: 955090
SecondChildUserNameTAG: Haack
SecondChildCreateTimeTAG: 2013-03-18T01:15:43Z
SecondChildVoteTAG: 0
SecondChildTAG: I have revised my math and I think I have discovered my mistake. I believe the result is a number and it is possible and not hard to calculate. The only problem is that I have already tried 2 answers so know I will have to wait to see if in this last review I got it right. Thank you all for your help.
SecondChildUserIdTAG: 955090
SecondChildUserNameTAG: Haack
SecondChildCreateTimeTAG: 2013-03-18T01:55:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Please explain these questions. I'm not able to follow.
SecondChildUserIdTAG: 169509
SecondChildUserNameTAG: rajeevbasapathy
SecondChildCreateTimeTAG: 2013-03-19T13:48:05Z
SecondChildVoteTAG: 0
SecondChildTAG: I have to say I think both of these questions were poorly written. The wording was sparse. For instance, it asked for "the correlation" instead of "the correlation coefficient" or "r," which where the terms used in the video lecture. Further more, problem 2a was insufficiently precise when describing the test. It wasn't immediate clear whether you were talking about right/wrong answers per question, or per the entire test. Throwing in the possibility of filling in "NA," when it didn't even work, just further obscured the problems.
SecondChildUserIdTAG: 1270190
SecondChildUserNameTAG: hilango
SecondChildCreateTimeTAG: 2013-03-19T20:36:10Z
SecondChildVoteTAG: 0
IndexTAG: 718
TitleTAG: Applet Link
Here is the link to the applet: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
UserIdTAG: 1292508
UserNameTAG: gaberen
CreateTimeTAG: 2013-03-17T23:10:35Z
VoteTAG: 12
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: spent close to 45 min searching for this when i have so little time left to finish the last exercise . if we use this shortcut so often there should be a shortcut for it
FirstChildUserIdTAG: 783898
FirstChildUserNameTAG: Rashmikumari
FirstChildCreateTimeTAG: 2013-03-20T18:42:13Z
FirstChildVoteTAG: 0
IndexTAG: 719
TitleTAG: Applet Link
Here is the link for the applet: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
UserIdTAG: 1292508
UserNameTAG: gaberen
CreateTimeTAG: 2013-03-17T23:08:20Z
VoteTAG: 23
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 1
FirstChildTAG: Is there a link to something other than a Java applet. Java plugin for Mac's isn't the easiest to deal with anymore.
FirstChildUserIdTAG: 67948
FirstChildUserNameTAG: DeRaaf
FirstChildCreateTimeTAG: 2013-03-20T12:02:20Z
FirstChildVoteTAG: 0
IndexTAG: 720
TitleTAG: I am unable to see lectures??? What should I do??
I cant see the link to lectures. How do I reach them???
UserIdTAG: 1252686
UserNameTAG: Kanika79
CreateTimeTAG: 2013-03-17T21:53:20Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 2
FirstChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm that's the link
FirstChildUserIdTAG: 704053
FirstChildUserNameTAG: jehadhassan
FirstChildCreateTimeTAG: 2013-03-17T22:21:36Z
FirstChildVoteTAG: 0
FirstChildTAG: > I cant see the link to lectures
Section 6: Relation between two variables. The link above the one you used.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/61842796b3b14c94823269e6fa001439/3011a429e940413e846a7190cd964a0e/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-17T22:29:08Z
FirstChildVoteTAG: 0
IndexTAG: 721
TitleTAG: problem 2A and 2B
I do not know which answers they want: right or wrong? yes or no?, positive or negative?
UserIdTAG: 1096180
UserNameTAG: Seattle
CreateTimeTAG: 2013-03-17T21:42:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: The answer is the value of the correlation coefficient, so it's a number.
FirstChildUserIdTAG: 130405
FirstChildUserNameTAG: nollhun
FirstChildCreateTimeTAG: 2013-03-17T22:23:34Z
FirstChildVoteTAG: 0
FirstChildTAG: And there are lots of posts about this, so looking at the forum will help.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-17T22:29:37Z
FirstChildVoteTAG: 0
FirstChildTAG: try graphing the two variables. you can see the relationship from a quick graph.
FirstChildUserIdTAG: 1015153
FirstChildUserNameTAG: ruthiegyll
FirstChildCreateTimeTAG: 2013-03-19T08:00:00Z
FirstChildVoteTAG: 0
IndexTAG: 722
TitleTAG: calculating 'r'
Hi
if both x and y axis have the same unit (cm, degree,....), do I have to convert them into z-score in order to calculate 'r'??
Thanks ..
UserIdTAG: 1048539
UserNameTAG: Reham1989
CreateTimeTAG: 2013-03-17T21:31:11Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: I did a quick test in my "r spreadsheet" and the answer is yes. And it makes sense because even though the units are the same, the numbers are not in the right scale. For instance, pick numbers from 10 to 20, and then pick another set of numbers from 10 to 20. Put them in a list side by side in any order you like. Without converting to sigmas, the formula for r would be multiply an entry in list one to an entry in list two. Sum those up and divided by the number of entries. Well, you have an average of the two lists multiplied together and there is absolutely no way that that number is going to be between -1 and 1. It appears that the conversion must be done.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-17T22:09:39Z
FirstChildVoteTAG: 0
SecondChildTAG: thank u so much..reasonable!!
SecondChildUserIdTAG: 1048539
SecondChildUserNameTAG: Reham1989
SecondChildCreateTimeTAG: 2013-03-18T20:07:35Z
SecondChildVoteTAG: 0
SecondChildTAG: You're welcome
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-18T23:57:47Z
SecondChildVoteTAG: 0
IndexTAG: 723
TitleTAG: Problem 2A and 2B
I found the number of right and wrong answer is there a I need to find the SD to find the r? which is basically the number between -1 and +1. Please help
UserIdTAG: 521763
UserNameTAG: taakondjo
CreateTimeTAG: 2013-03-17T21:25:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 724
TitleTAG: Exercises wanted.
Can anyone recommend me a book with exercises as close as possible to this course? And highly desirable to have answers with explanations to check myself.
Thank you!
UserIdTAG: 255838
UserNameTAG: EngineerHrenov
CreateTimeTAG: 2013-03-17T20:59:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: If by as close as possible, you mean a book containing the information provided by this course, without excluding the possibility that the book contains more information, then I can recommend a book.
I am currently going through Schaums Outline of Statistics, 4th edition. Chebychev and regression are late in the book, so I can't tell you if everything is covered the same way. I have found it a to be a valuable extension to the class. It covers topics in much more mathematical detail, and has tons of fully worked out problems + supplemental problems as well.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-17T22:21:48Z
FirstChildVoteTAG: 1
SecondChildTAG: Schaum's is the best, and cheap compared to most text. There is never a shortage of worked examples, explanations, and details.
SecondChildUserIdTAG: 937396
SecondChildUserNameTAG: m2foster
SecondChildCreateTimeTAG: 2013-03-20T21:19:49Z
SecondChildVoteTAG: 0
FirstChildTAG: *Statistics* (Fourth Edition) by Freedman, Pisani, and Purves. Published by Norton.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-18T01:17:39Z
FirstChildVoteTAG: 6
SecondChildTAG: Thanks Prof. A, that's what I need to pursue from this point onward.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-18T21:52:13Z
SecondChildVoteTAG: 0
IndexTAG: 725
TitleTAG: Midterm statistics
I've looked around a bit and can't find the statistics for the midterm. Have they been posted? If not, could they be? I'd like to know how many people actually took midterm, what the grade distribution looked like and what how we did on each of the questions. Unless of you're saving that data for use in the final. ;-)
UserIdTAG: 260168
UserNameTAG: Jeff2012
CreateTimeTAG: 2013-03-17T19:21:49Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For the final, I'd like to see us analyzing a scatter diagram that compares the ES Averages with the Midterm results :D
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T20:17:06Z
FirstChildVoteTAG: 3
SecondChildTAG: :)
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-17T20:58:01Z
SecondChildVoteTAG: 0
IndexTAG: 726
TitleTAG: I just stumbled upon this course
Hi,
I have just enrolled, I was wondering how the grading system would work in such cases ? I am really interested in finishing the course, but I think a little more than March26th would be required to catch up with the course material. I just took my first exercise test but I can't see any option where I can submit my answers, just a 'show answer' option.
Thanks.
UserIdTAG: 1406941
UserNameTAG: Abhinayaes
CreateTimeTAG: 2013-03-17T19:11:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Only week four exercises can be submitted at this point. Submit those, the week five exercises, and get a good grade on the final, and you might get the 35% total score required to pass.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-17T19:17:59Z
FirstChildVoteTAG: 1
FirstChildTAG: You missed the deadlines for the Exercise Sets 1 to 8, plus the Midterm, so you won't be able to submit any answer for those(but you can still do them for self-assessment)
You *can* get a maximum grade of 50% (20% from the remaining 4 Exercise Sets, + 30% from the final), and the passing grade for this course is 35%, so the certificate is still very possible to get if you are interested in it :)
Certificate or not, the course is a great learning experience.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T19:18:34Z
FirstChildVoteTAG: 2
IndexTAG: 727
TitleTAG: Preregistration for Stat 2.2X possible Professors ?
It would be wonderful if a preregistration for Stat 2.2X could be possible over the next week so that those who want to continue can preregister and either get an intimation of the course starting or else get enrolled so that when it starts we can directly start the course- Just a suggestion and if possible would be wonderful.I think many of us would indeed like to complete all the 3 parts(and more if offered !!)
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-17T17:48:13Z
VoteTAG: 17
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: Good post, captures my intentions exactly.
thanks for the posting.
FirstChildUserIdTAG: 940447
FirstChildUserNameTAG: rob4511
FirstChildCreateTimeTAG: 2013-03-17T22:21:14Z
FirstChildVoteTAG: 2
FirstChildTAG: Prasannasimha, you seem to be passing quite a lot of time in this forum so, in case you have noticed any relevant information regarding 2.2x and 2.3x, do you know how long after this 5-week course finishes the next one is starting? I mean, roughly, is it going to be next week, next month, next summer..?
thanks,
Antonis
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-17T22:50:31Z
FirstChildVoteTAG: 1
SecondChildTAG: See prof A.'s post above. We'll have more details on Wednesday :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T12:26:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Great Course. Thank you Professor Adhikari. I really enjoyed your lectures.
I would love to take the rest of the courses in this series. Will they be offered?
FirstChildUserIdTAG: 1106649
FirstChildUserNameTAG: skoules
FirstChildCreateTimeTAG: 2013-03-17T23:35:29Z
FirstChildVoteTAG: 2
FirstChildTAG: Yes, and I now realize that I don't know exactly when registration opens. I'll inquire. Info about Stat 2.2X will go up on Wed, along with materials for the final week of 2.1X. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-18T01:16:24Z
FirstChildVoteTAG: 14
IndexTAG: 728
TitleTAG: scatterplot
How do I calculate SD by looking at a scatterplot? Anyone? I'm thinking specifically of Exer.5.6
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-03-17T17:34:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You can't.
The SDs(there are several ones) for the different variables are also not required for exercise 5.6 at all.
But if you really want to know them, click "Univariate Stats" below the graph ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T18:55:06Z
FirstChildVoteTAG: 0
IndexTAG: 729
TitleTAG: 2c
i added the .5 to avg and substituted 23.5 as x in regression equation and from the answer i got i subtracted the average of the egg's weight but still got the wrong answer have i done anything wrong wrong my method? if yes where should i correct? i want to understand the prob though i got it wrong in my attempts. pls point out my mistake.the wrong answer i got is .4085
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-03-17T17:18:40Z
VoteTAG: 5
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 4
FirstChildTAG: Your steps are fine, im sure you got wrong during calculating
FirstChildUserIdTAG: 1288142
FirstChildUserNameTAG: aldawlah
FirstChildCreateTimeTAG: 2013-03-17T19:24:28Z
FirstChildVoteTAG: 0
FirstChildTAG: Trying viewing the problem as two Y = m * X + B linear equations and subtract one equation from the other one. The "Delta Y" is what you're looking for. m is the slope (which is the same for both equations, X is the difference in the diameters, which is 0.5 mm as stated in the problem, B is a constant (which you don't need to determine, as B minus B is zero), so the problem reduces to "Delta Y" = m * 0.5. Remember m = r * (mean of weight / mean of diameter). Hope this helps.
FirstChildUserIdTAG: 1080964
FirstChildUserNameTAG: Yellowjacket786
FirstChildCreateTimeTAG: 2013-03-17T21:52:50Z
FirstChildVoteTAG: 1
SecondChildTAG: You are wrong! M = r * (SD of weight / SD of diameter)
SecondChildUserIdTAG: 1131693
SecondChildUserNameTAG: Catica
SecondChildCreateTimeTAG: 2013-03-18T00:25:04Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks!
SecondChildUserIdTAG: 1242151
SecondChildUserNameTAG: lhasan
SecondChildCreateTimeTAG: 2013-03-18T14:44:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Lets not go posting step by step solutions to ES in progress please?
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-18T15:30:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you very much for this explanation. very much helpful
SecondChildUserIdTAG: 617692
SecondChildUserNameTAG: Inoukapo
SecondChildCreateTimeTAG: 2013-03-20T07:14:08Z
SecondChildVoteTAG: 0
FirstChildTAG: I tried your technique and got 0.406 gms which was marked incorrect. Then I tried calculus and found the derivative of weight wrt length. The answer I got from this technique was marked correct.
FirstChildUserIdTAG: 559760
FirstChildUserNameTAG: arnie_z
FirstChildCreateTimeTAG: 2013-03-19T19:45:19Z
FirstChildVoteTAG: 2
FirstChildTAG: The answer is in the 'Interpretation of Slope' section of lecture 7.4.
Absolutely no heavy calculation required.
FirstChildUserIdTAG: 1093310
FirstChildUserNameTAG: SeemaAbb
FirstChildCreateTimeTAG: 2013-03-20T06:23:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you! No heavy calculation, indeed!:)
SecondChildUserIdTAG: 1141835
SecondChildUserNameTAG: TrissMerigold
SecondChildCreateTimeTAG: 2013-03-20T13:14:26Z
SecondChildVoteTAG: 0
IndexTAG: 730
TitleTAG: Bug: Problem 1B allows only one submission, & what does "better" mean?
Problem 1B allows only one submission.
The bug aside, to use the word "better" is problematic. Is it better to train only very few students out of many students to take the test? No. Is is better to train students so that a lot of them have the guts to take the test? Yes. By these criteria, Maine does a better job, although Illinois students have the better score average.
UserIdTAG: 1213513
UserNameTAG: lkockel
CreateTimeTAG: 2013-03-17T16:42:27Z
VoteTAG: 4
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 4
FirstChildTAG: Think this way: which are the variables observed? There are **only two** variables. No desire to be obscure, but saying more would be revealing part of the answer.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-17T17:17:13Z
FirstChildVoteTAG: 2
FirstChildTAG: In my opinion the first option should not affect the grader on this problem: are we now supposed to pick the answers based on how punny its wording is? The plot only takes 2 vars and no of them estimates the goodness of the job made by either state in educational process.
FirstChildUserIdTAG: 338763
FirstChildUserNameTAG: middaymoon
FirstChildCreateTimeTAG: 2013-03-17T18:29:10Z
FirstChildVoteTAG: 0
FirstChildTAG: The word "better" could have many interpretations, true. But the question here is: by looking at the graph, can you evaluate the training methods of Illinois and Maine schools?
With your interpretation, can you say **from looking at the graph only** that in Maine, students are trained *"so that a lot of them have the guts to take the test?"*, or that in Illinois, they *"train only very few students out of many students to take the test"*?
Answer this and you'll know whether you need to check that line or not ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T18:45:54Z
FirstChildVoteTAG: 1
FirstChildTAG: I got this question wrong because of my habit of rushing. Again, I need to keep remind and train myself to pay close attention to details and think carefully before answering.
Anyway, look at all the statements or options and ask yourself which one is the outlier. This question is like one of those IQ questions where you have to identify patterns. You have to watch out for the one that doesn't fit that pattern and exclude it from your answer. In other words, look for the one that doesn't appear to relate to the others.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-18T02:06:18Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you very much! By looking not only at outliers but also to the whole scatterplot, this question can be answered
SecondChildUserIdTAG: 743246
SecondChildUserNameTAG: andresace
SecondChildCreateTimeTAG: 2013-03-20T03:22:30Z
SecondChildVoteTAG: 0
IndexTAG: 731
TitleTAG: Exercise set 9
These questions are really screwed up.
UserIdTAG: 274577
UserNameTAG: scanning
CreateTimeTAG: 2013-03-17T14:40:45Z
VoteTAG: 5
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: Why? They seem reasonable to me .
FirstChildUserIdTAG: 119039
FirstChildUserNameTAG: Alan56
FirstChildCreateTimeTAG: 2013-03-17T15:01:47Z
FirstChildVoteTAG: 0
FirstChildTAG: Could you be more specific? The questions seemed clear enough to me.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T19:37:05Z
FirstChildVoteTAG: 0
IndexTAG: 732
TitleTAG: about problem 2
how to enter answers.when i enter NA it shows that it is invalid data
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-17T12:06:24Z
VoteTAG: 15
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 5
FirstChildTAG: It takes "NA" neither in small or caps!
FirstChildUserIdTAG: 894810
FirstChildUserNameTAG: holani
FirstChildCreateTimeTAG: 2013-03-17T12:33:37Z
FirstChildVoteTAG: 1
FirstChildTAG: count yourself lucky that the software prevents you from entering in the incorrect answer!
FirstChildUserIdTAG: 941165
FirstChildUserNameTAG: bp84
FirstChildCreateTimeTAG: 2013-03-17T17:42:23Z
FirstChildVoteTAG: 4
FirstChildTAG: To be fair, NA *is* mentioned as a perfectly valid answer in the problem text, so it *should* be allowed, and graded.
So it is a bug.
How people can *complain* about the one bug in this course that actually *helps* them, is beyond me xD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T18:49:21Z
FirstChildVoteTAG: 1
SecondChildTAG: First they have to realise that it *is* helping them.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-17T21:51:31Z
SecondChildVoteTAG: 0
SecondChildTAG: The fact that the answer isn't accepted *should* be a big hint that they might want to review their evaluation of the problem, shouldn't it?
But of course, it's much easier to immediately blame the examiner(real or virtual), assume that their answer can only be right and refuse to consider that maybe, just maybe, there's a slight chance that they might be doing something wrong. I forgot to account for human(?) nature :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-18T12:33:36Z
SecondChildVoteTAG: 0
FirstChildTAG: Many others have completed this answer correctly. The question will not accept NA (or any other text) as an input, only numbers. What does this suggest about the correct answer?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T19:38:50Z
FirstChildVoteTAG: 2
FirstChildTAG: Wow, a lot of you are extremely rude.
FirstChildUserIdTAG: 1288745
FirstChildUserNameTAG: awolfie
FirstChildCreateTimeTAG: 2013-03-19T14:19:04Z
FirstChildVoteTAG: 1
IndexTAG: 733
TitleTAG: Bad questions in this set!
I think many will agree that Problem 1A and Problem 3 are inappropriate and irrelevant to the course. Problem 1A is based on a subjective perception of the plot and Problem 3 is bad worded - answer relates to pairs while question is about age vs. age.
Objection! =)
UserIdTAG: 255838
UserNameTAG: EngineerHrenov
CreateTimeTAG: 2013-03-17T08:28:00Z
VoteTAG: 22
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: No I don't think so.Part of the problem in statistics is to decide when not to use an approach and when to use it. A look at the scatter diagram gives you an idea what to use and more importantly what not to use.
As for the second it is logical though you feel it is not so.Remember that when you are doing bivariate analysis you are analyzing pairs, their relations and trends too.You are choosing to forget the last part and then saying that it is bad !!
Rather than blaming the questions why don't you look at it in a more positive manner and see what lessons you can learn from it rather than blaming the problem ?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-17T08:48:41Z
FirstChildVoteTAG: 8
SecondChildTAG: Q3: "Which of the following do you think is true regarding the association between wife’s age and husband’s age?" Does it say anything about trend or about pairs? No it does not. It clear says "association BETWEEN age and age". The problem's question was clear and straightforward. The solution does not correspond to the questions.
Q1: Again, linearity in terms of ROUGHLY-ness can not be objectively measured - it totally depends on previous experience or subjective perception. For example, using actual data and correlation I can now precisely calculate linearity but using only lecture 6.1 (without knowing anything else) it is not possible. From my point of view that plot is not linear it looks like a logarithmic curve (this is how do I see the data via my eyes) and I'm sure that this ROUGH estimation is more precise and correct then linear ROUGH estimation.
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-17T10:52:40Z
SecondChildVoteTAG: 0
SecondChildTAG: So it is not then linear to you.
Also take the imaginary data points and plot them and you can see the scatter gram staring at you.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-17T12:45:11Z
SecondChildVoteTAG: 0
SecondChildTAG: EngineerHrenov, just a suggestion about problem three. To answer this question you don't need to evaluate how valid is the part of each choice such as "wives tend to be younger than their husbands". Rather, you need to see if such a statement is correctly described by the other half part "the association is negative". You have 4 choices and only in one of them the one half is accurately described by the other half (regardless whether this "fact" is actually true or not).
I hope this helps
Antonis
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-17T18:49:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Q3 is about the definition of association - positive or negative as the Prof explained in the lecture.
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-18T04:22:20Z
SecondChildVoteTAG: 0
SecondChildTAG: positive association: above average values of one variable tend to go
with above average values of the other; the scatter slopes up
negative association: above average values of one variable tend to go
with below average values of the other; the scatter slopes down
If you draw the scatter with husband and wife age with all those statements you get the answer
SecondChildUserIdTAG: 569767
SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-03-18T13:03:37Z
SecondChildVoteTAG: 0
SecondChildTAG: @Antonis Thanks for the hint! You made me see the problem from the other side and I got the right answer. For others - forget about current "marriage" situation. Question asks about association between two variables-and there is only one appropriate answer that more or less clear shows this association.
SecondChildUserIdTAG: 1007312
SecondChildUserNameTAG: Elena_Sh
SecondChildCreateTimeTAG: 2013-03-20T17:04:05Z
SecondChildVoteTAG: 0
FirstChildTAG: The questions seemed perfectly reasonable to me.
Q1 asks for a visual judgement of a scatter plot. Is it linear or not and which way does it slope?
Q3 describes the population - all married couples (although the answer excludes partners in 'same-sex' marriages) and the answer asks about the relationship between the members. Each partner has an age. Is an old man more likely to have an old wife or a young one?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T08:53:50Z
FirstChildVoteTAG: 1
SecondChildTAG: PaulJM, thanx once again. I was confused two choices between individual Vs population though association was (...). I have to pick one of these. Your hint was good to analyse the problem better.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T16:19:52Z
SecondChildVoteTAG: 0
FirstChildTAG: To answer this question, think which option makes the most sense. Let's take the first option for example, does it make any sense to you that if the husband is old, the wive must be young? Then does it mean that if the husband is young the wive must be old? Does that statement make any sense to you?
The reason we fit a line on the graph is to figure out the trend. The line has a name and it is called a Trend Line. So if there is any relationship between the variables in this problem husband and wive ages. Then it doesn't make any sense that if the husband is old the wive must be young and vice versa. And remember, this problem asks us to compare it to the real world. So from what you know about the world, do you think it is true that if the husband is old the wive is young?
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-18T01:56:31Z
FirstChildVoteTAG: 0
SecondChildTAG: If you take the general global trend, OF COURSE husbands are older than their wives.
A more interesting question is:
Is there a positive association between people who did well in the problem set and their (positive) opinion about the questions? Is it possible to have students who did well in the problem set (high scores) who think the questions were (mildly speaking) ambiguous?
Frankly, and with no intention of sarcasm, this is what I've been thinking lately...
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-18T15:26:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Two points. First, I did OK in this set so obviously didn't find the wording ambiguous - but I can empathise with anyone, particularly non-native English speakers, who is struggling to work it out. Second, I think some of the irritation on the forum is a natural first inclination is to blame the question. Hopefully most of us get over that and then reflect on why we went wrong / what we can do to get it right next time.
For example, I'm finding I get the subjective ones wrong - eg qualitative vs quantitative, straight line vs curve - but I've managed to stay positive about them because I can see that I'm being too literal about definitions instead of taking a step back & asking which answer is more likely to lead to effective use of the data. I hope! But if I'd posted immediately after the nasty red cross appeared I would not have been as positive ;)
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-18T17:10:09Z
SecondChildVoteTAG: 0
IndexTAG: 734
TitleTAG: 2b
Hi all!For 2b i use: average chick weight - slope X average diameter but it doesnt work.am i missing sth here? Obviously yes!!Any advice?do i have to convert sth?
I keep looking the example from lecture but cant find sth different to do.Thank you in advance!!
UserIdTAG: 1107430
UserNameTAG: Pintor
CreateTimeTAG: 2013-03-17T07:03:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 5
FirstChildTAG: Did you calculate the slope correctly? If you rounded, did you do so properly? I used 4dp with my answer. If your line is negative, did you include the - sign?
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-17T07:50:52Z
FirstChildVoteTAG: 0
SecondChildTAG: yes the slope is correct from 2a.i just used the data provided by the exercise.Really angry with my self!!!It must be sth so easy!!
SecondChildUserIdTAG: 1107430
SecondChildUserNameTAG: Pintor
SecondChildCreateTimeTAG: 2013-03-17T09:13:26Z
SecondChildVoteTAG: 0
SecondChildTAG: @pintor It is easy .... I did it wrong the first time too! May be you did the calculations in wrong order? eg the subtraction before the multiplication ? That's what I did :-)
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-17T10:30:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi Theodora,maybe i didnt include the - sign,do you think that could be the reason to get a wrong answer?
SecondChildUserIdTAG: 1110226
SecondChildUserNameTAG: pittnik
SecondChildCreateTimeTAG: 2013-03-17T12:22:57Z
SecondChildVoteTAG: 0
SecondChildTAG: I did the same with pintor but think i forgot to put the - sign so thats maybe why got it wrong.too late now..what do you say?
SecondChildUserIdTAG: 1110226
SecondChildUserNameTAG: pittnik
SecondChildCreateTimeTAG: 2013-03-17T12:25:01Z
SecondChildVoteTAG: 0
SecondChildTAG: listen carefully to the lecture section 7.4 between time interval of 04:51-05:08 just assume the given value is diameter of egg--->x the value to be found is weight--------->y class mate, listen to the above given lecture section and the hint to find yourself a help.....gud luck
SecondChildUserIdTAG: 820147
SecondChildUserNameTAG: frimpongmaxwellkwadwo
SecondChildCreateTimeTAG: 2013-03-19T08:32:00Z
SecondChildVoteTAG: 0
SecondChildTAG: i gave the result to two dp and it was marked wrong.
SecondChildUserIdTAG: 342243
SecondChildUserNameTAG: drrahulbasu
SecondChildCreateTimeTAG: 2013-03-19T14:40:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you very much for this explanation: I did it wrong the first time too! May be you did the calculations in wrong order? eg the subtraction before the multiplication ? That's what I did :-). you saved me.
SecondChildUserIdTAG: 617692
SecondChildUserNameTAG: Inoukapo
SecondChildCreateTimeTAG: 2013-03-20T07:16:24Z
SecondChildVoteTAG: 0
FirstChildTAG: You did remember to work in standard units?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T08:56:10Z
FirstChildVoteTAG: 1
SecondChildTAG: I used the data provided: avg diameter 23mm, SD 0,45mm,
weight avg 6 grams, SD 0,5 grams and r=0,75.
SecondChildUserIdTAG: 1107430
SecondChildUserNameTAG: Pintor
SecondChildCreateTimeTAG: 2013-03-17T09:11:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you PaulJM!
SecondChildUserIdTAG: 380621
SecondChildUserNameTAG: VukaMiu
SecondChildCreateTimeTAG: 2013-03-18T16:20:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually, I still don't think I got it totally right. Std units get me a step further and then stuck again. Don't understand why it's not correct just by replacing mus and sigmas. Guess I'll have to wait few days for the key...
SecondChildUserIdTAG: 380621
SecondChildUserNameTAG: VukaMiu
SecondChildCreateTimeTAG: 2013-03-18T16:43:42Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't understand either - I followed correctly the formula to get the slope and the intercept. I even paid close attention to the - sign, but it still said "wrong answer"!!!
FirstChildUserIdTAG: 1178106
FirstChildUserNameTAG: pyt
FirstChildCreateTimeTAG: 2013-03-17T16:22:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Can intercept be a negative number? if yes, then what does it mean?
FirstChildUserIdTAG: 978965
FirstChildUserNameTAG: Shahoushyar
FirstChildCreateTimeTAG: 2013-03-17T23:13:12Z
FirstChildVoteTAG: 2
SecondChildTAG: Yes, it can. So, the regression only works in a narrow range of egg's diameters. In this particular type of eggs, you wouldn't expect to find eggs of 2 mm of diameter, nor of 1/2 meter. Most of the eggs (99.7%) would lay between 21.65 and 24.35 mm (average +- 3 SDs)
SecondChildUserIdTAG: 19503
SecondChildUserNameTAG: jaimefromspain
SecondChildCreateTimeTAG: 2013-03-18T18:49:24Z
SecondChildVoteTAG: 0
SecondChildTAG: jamiefromspain
Thanks for this, and very well explained
SecondChildUserIdTAG: 169991
SecondChildUserNameTAG: birkenhead
SecondChildCreateTimeTAG: 2013-03-18T21:28:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Do the multiplication b4 the subtraction.
FirstChildUserIdTAG: 715356
FirstChildUserNameTAG: Janefrances
FirstChildCreateTimeTAG: 2013-03-20T21:30:24Z
FirstChildVoteTAG: 0
IndexTAG: 735
TitleTAG: Thank you Prof. Adhikari
I wanted to express my gratitude for your efforts with Stat2.1x. It is a great privilege and pleasure to participate in this course. I am not naturally talented in this subject and yet your lectures are very clear. Even the kindness of your voice helps me relax when facing new material. I really do enjoy listening to your lectures! Thank you and I wish you good fortune.
UserIdTAG: 845389
UserNameTAG: jonellevillar
CreateTimeTAG: 2013-03-17T06:01:43Z
VoteTAG: 26
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Well said; the course is a delight!
FirstChildUserIdTAG: 611869
FirstChildUserNameTAG: bostonpatriot
FirstChildCreateTimeTAG: 2013-03-17T22:25:11Z
FirstChildVoteTAG: 1
FirstChildTAG: Brilliant! Thank you very much!
FirstChildUserIdTAG: 1106649
FirstChildUserNameTAG: skoules
FirstChildCreateTimeTAG: 2013-03-17T23:36:32Z
FirstChildVoteTAG: 1
IndexTAG: 736
TitleTAG: 90 percentile,z=?
can any one plz hlp
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-17T05:52:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: If you are working with bivariate normal distributions (I hope that's how you say it), i.e., football-shaped scatter diagrams, use the applet for area under the normal curve to get your percentiles:
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-17T05:57:04Z
FirstChildVoteTAG: 1
FirstChildTAG: For the percentiles I used this table:
[Z-score table][1]
and it is very helpful.
[1]: http://www.pindling.org/Math/Learning/Statistics/z_scores_table.htm
FirstChildUserIdTAG: 436845
FirstChildUserNameTAG: petru
FirstChildCreateTimeTAG: 2013-03-17T12:38:17Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks for sharing this.
SecondChildUserIdTAG: 4612
SecondChildUserNameTAG: Susnaj
SecondChildCreateTimeTAG: 2013-03-17T20:26:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, thank you.
SecondChildUserIdTAG: 260168
SecondChildUserNameTAG: Jeff2012
SecondChildCreateTimeTAG: 2013-03-18T02:29:42Z
SecondChildVoteTAG: 0
FirstChildTAG: I use excel :D. Try NORM.S.DIST and GOAL SEEKER.
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-17T15:45:58Z
FirstChildVoteTAG: 0
IndexTAG: 737
TitleTAG: Please help !
I dont have posted the exercises of the section 6... Why? Anybody help me?
UserIdTAG: 428013
UserNameTAG: TinoSilva
CreateTimeTAG: 2013-03-17T05:32:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you mean Exercise Set 6, this was due to be submitted by 23:30 GMT on 6 March. Did you submit before that time?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T08:59:37Z
FirstChildVoteTAG: 0
IndexTAG: 738
TitleTAG: NA is NA
I feel as though the answers for those two questions(2A and 2B) are NA. I don't have enough data, to have data.
I have furiously tried many times to enter NA, yet over and over, up pops *Invalid input: could not interpret 'NA' as a number*. The instructions clearly say, if you think there is not enough information to answer the question, enter NA. Well Mr. Instructions, I can't. I was told I can put NA, yet I obviously cannot.
I am sure many agree with me that this question involving NA... is NA
> NA IS NA
NA IS NA
NA IS NA
NA IS NA
NA IS NA
NA IS NA
NA IS NA
NA IS NA
NA IS NA
UserIdTAG: 1304644
UserNameTAG: phillzRchamps
CreateTimeTAG: 2013-03-17T05:11:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: If others have completed the exercise correctly but it only accepts numbers, what does that suggest about answer?
Remember what 'r' describes. It is a measure of the amount of variation about the line (how scattered the points are). Now think about this example. Say a student has 6 correct answers, how many wrong answers do they have? How certain are you of this value? Might it be a bit more or fewer sometimes? Now think what this means for r.
If all else fails, plot the possible results on a chart (there are only ten possible answers so it's not a long job) and make a visual estimate of r - how close do the points fall to a perfect line...
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T08:44:59Z
FirstChildVoteTAG: 5
SecondChildTAG: perhaps NA isn´t the correct answer
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-03-17T16:20:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, I tried to complicate things by working it our with the scores, instead of the number of right vs. no. of wrong!! Your explanation helped.
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-18T04:00:59Z
SecondChildVoteTAG: 0
SecondChildTAG: NA is the correct answer, besides the instructions allow us to use it as a correct answer....
SecondChildUserIdTAG: 1207265
SecondChildUserNameTAG: CesarCataldi
SecondChildCreateTimeTAG: 2013-03-19T07:43:58Z
SecondChildVoteTAG: 0
FirstChildTAG: > I am sure many agree with me that this question involving NA... is NA
Maybe they do. That doesn't make them correct.
The system should accept NA. Be pleased it doesn't, otherwise you might have used up all your chances.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-17T21:33:29Z
FirstChildVoteTAG: 0
FirstChildTAG: I'll give you a hint: the answer is *not* NA. But it *is* ridiculously simple in both cases.
If you had a set of test results and you arranged them in a scatter plot where X is the number of right answers and Y is the number of wrong answers, you would get a *perfectly straight* line sloping downward.
If you took those same results and arranged them in a plot where X is the test score and Y is the number of right answers, you would get a *perfectly straight* line sloping upward.
One last hint (which pretty much gives it away): remember what the instructor said the correlation would *never* be? In this case, it *is.*
FirstChildUserIdTAG: 224280
FirstChildUserNameTAG: Ryusui
FirstChildCreateTimeTAG: 2013-03-19T03:50:32Z
FirstChildVoteTAG: 0
IndexTAG: 739
TitleTAG: Location of Applet
Hi Professor and Fellow Students,how do i get to the applet used in this course?
UserIdTAG: 1264305
UserNameTAG: dolittleklaz
CreateTimeTAG: 2013-03-17T05:03:27Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 2
FirstChildTAG: Applet for area under the (normal) curve:
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-17T05:47:40Z
FirstChildVoteTAG: 1
SecondChildTAG: Or maybe you meant an earlier applet. Generally, you'll find the appropriate links in the "Practice Set" sections for each lecture block.
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-03-17T05:54:51Z
SecondChildVoteTAG: 0
FirstChildTAG: All applets are in the online textbook [here][1].
If the one you're looking for isn't directly linked somewhere in the edx course(often in the Practice and/or Exercise Sets, as dba suggests), just look for the topic it's associated with in the textbook, scroll a little, and you'll find it.
[1]: http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T15:22:24Z
FirstChildVoteTAG: 1
IndexTAG: 740
TitleTAG: Answers
Dear Professor;
I think if we could have the answers to the problems and the tests after the closing date It would be great for us. We would be able to know about those which we couldn't solve.
I shall be thankful for the consideration.
UserIdTAG: 1119819
UserNameTAG: Hamraz
CreateTimeTAG: 2013-03-17T04:52:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: > I think if we could have the answers to the problems and the tests after the closing date It would be great for us.
Yes. The answers are available after the deadline.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-17T05:28:12Z
FirstChildVoteTAG: 0
FirstChildTAG: Answers are available with explanations. Just go to the Exercise page and click on 'show answer'.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T09:00:46Z
FirstChildVoteTAG: 1
IndexTAG: 741
TitleTAG: Considering Problem 2
Maybe, the questions should be rather asked like this:
"The correlation **Coefficient** between ... blabla"
The answers are really simple.
UserIdTAG: 957952
UserNameTAG: Jjclof
CreateTimeTAG: 2013-03-17T04:47:58Z
VoteTAG: 2
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: I think the phrase 'correlation between' and the context (ie what we are studying) makes it clear that the coefficient 'r ' is required but maybe it is less clear for students who do not have English as a first language.
The difficulties most people seem to have (who posted here) was not in understanding what was required but in getting to the answer!
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T09:04:35Z
FirstChildVoteTAG: 2
IndexTAG: 742
TitleTAG: About R
Do we at Stat2.1x required to understand R? Is that hard? Have anyone of you taken R?
UserIdTAG: 795482
UserNameTAG: VIVEK_88
CreateTimeTAG: 2013-03-17T04:11:11Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Steep learning Curve. Find a good tutorial to help you, it is not intuitive or menu driven
FirstChildUserIdTAG: 237509
FirstChildUserNameTAG: Mundi
FirstChildCreateTimeTAG: 2013-03-17T06:08:52Z
FirstChildVoteTAG: 0
FirstChildTAG: There is no requirement to understand or use the programming language R during this course (there is, after all, only a couple more lectures and one Exercise Set to go so it would be a little late).
Students should, of course, understand 'r' - the correlation coefficient - by the end of the course!
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T09:32:35Z
FirstChildVoteTAG: 1
FirstChildTAG: R is a programming language widely used for statistics and by statisticians and in fields involving data analysis and processing (machine learning, etc).
R is free software and it is delivered as any other free software. The main distribution consists of a core of packages providing basic functionalities that it's extensible by contributed packages installable on demand if you need them.
You can use this core set of functions without programming at all. In that case R is an environment for statistical work as any other application suitable for statistics. Although the primary interface of this environment is the command line, there is a graphic interface available: [Rcmdr][2], that can be combined with [RStudio][1] or used over the default R command-line interface.
You don't have to learn R for this course. You don't need to use R/program in R or in any other programming language. In general no statistical software is required.
Be careful (PaulJM points to that) - "R", the programming language or environment, is not "r", the correlation coefficient.
[1]: http://www.rstudio.com/
[2]: http://www.rcommander.com/
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-17T10:11:45Z
FirstChildVoteTAG: 0
FirstChildTAG: I use R to check my understanding of the solutions.
R is an incredibly powerful, incredibly non-intuitive application. For processing large or complex data sets it can't be outdone.
I agree - a ***very*** steep learning curve.
Coursera has a [Data Analysis][1] course that is largely a course in using R. I started the course and quit at about week 4. From my viewpoint, the course is less about teaching data analysis and more about teaching how to use R.
If you know statistics and want to learn R, then I recommend this course. If you want to use R, then the Coursera class is excellent.
[1]: https://www.coursera.org/course/dataanalysis "Data Analysis"
FirstChildUserIdTAG: 876324
FirstChildUserNameTAG: BrianDeering
FirstChildCreateTimeTAG: 2013-03-17T13:41:11Z
FirstChildVoteTAG: 0
SecondChildTAG: IMO the best things of R are the difficult things: everything in R is vectorized, higher-order procedures (functions as arguments to functions) are everywhere; there are a lot of generic functions capable of taking as input different data structures and producing transparently different suitable outputs.
All of these things are very convenient in order to handle large chunks of diverse data that are ultimately based on vectors, but at a cost: the language is very different from the typical procedural languages.
An example:
In 'generic' Python (i.e using Python in a non-pythonic way ---see last note), or C, or whatever, if you want to process a list, say, to create an slice of the list consisting of the elements greater than `n` and then multiply the result by a number `m`, you could do:
new_list = []
for e in a_list:
if e > n:
new_list.append(e * m)
A typical R implementation would look like this:
new_list <- a_list[a_list > n] * m
Concise and beautiful, but under the hoods, something weird (weird from the point of view of other languages) is happening:
`a_list > n` produces a vector of boolean values, that is used in a non-familiar way to indexing over the list and slicing it, then the multiplication, a vectorized operation as almost everything in R, is applied to the entire resulting vector without loops.
So R seems cryptic and the learning curve is consequently steeper for someone with some exposure to other languages.
In spite of this, I agree with you: it's a very powerful and flexible tool for data analysis and I recommend everyone to give it a try.
** Note for angry Pythonists (my classmates in 6.00x): pythonic Python shares somewhat this style, for example, via list comprehension (but you know, list comprehension is always a nightmare for a beginner ;-) ). A more pythonic way to implement the previous example would be:
new_list = [e * m for e in a_list if x > n]
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-17T16:35:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Do we at Stat2.1x required to understand R? - not R, just r!
Is that hard? - depends on your background. If you have any pre-windows programming experience, the syntax is a doddle. Undoubtedly less straight forward for the point & click generation. Understanding exactly what it is actually doing (7 different options to calculate percentiles....) is why I'm doing this course.
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-17T20:57:21Z
FirstChildVoteTAG: 1
SecondChildTAG: Even more than 7 ;-) Actually, if you are referring to that, there are 9 types of algorithms for the quantile() function (I said wrongly 10 types in an old post), and the documentation about each type is as terse as overwhelming, at least for me ;-)
What about the correlation coefficient function, cor()? 3 types (btw, we are using "Pearson", as far as I can understand) ... So, a lot of flexibility, but a lot of stuff. I think this complexity has to do more with statistics than with the language itself. Statisticians are largely involved in the creation, maintenance and extension (via packages) of R. So it's not surprising that heavy statistic is omnipresent. R is their tool.
Best wishes, Marian!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-17T23:47:56Z
SecondChildVoteTAG: 0
SecondChildTAG: > **the documentation about each type is as terse as overwhelming, at least for me ;-)**
too true!
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-18T12:12:30Z
SecondChildVoteTAG: 0
IndexTAG: 743
TitleTAG: Final Exam Request to Faculty
Since the Final Exam seems to be held a day earlier (On Tuesday and hopefully with a 48 hour window like the Midterm) can we get the teaching materials also a bit earlier so that we can pace ourselves for both the study and revision ? We can finish our due exercises etc earlier depending on individual requirements so that we can formulate the combined and comprehensive knowledge gained from all the lessons together.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-17T03:58:40Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Materials will be up on Wed. I designed Week 5 with only one main idea in it and only one Exercise Set so that you'll have plenty of time to go over the course in time for the final. I'll post some additional practice problems as well. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-17T08:40:21Z
FirstChildVoteTAG: 9
SecondChildTAG: Thanks.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-17T08:50:08Z
SecondChildVoteTAG: 0
SecondChildTAG: That's great, thanks!
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-17T09:08:17Z
SecondChildVoteTAG: 0
SecondChildTAG: See, the Professor does love us!
Thanks to all the team. Overall it seems to have been a well-paced course and, as someone who has taught Maths in high school (although it's not my specialist subject) I would think that those who were motivated enough to keep going and work through the examples should have no problems completing the course.
I'll be very interested to see what proportion of those registering get through to the end (assuming that information is ever published) and particularly the retention rate through each assessment point.
Feedback I've seen from other similar courses suggest a massive drop out at or before the first assessment - reflecting those who register without a serious intention of studying, those who decide the subject or level is not suitable and those who do not participate in assessments because they are not working towards certification. One course quoted 90% drop out at the first problem set.
Following that initial fall the retention rate seems likely to be related to the style of teaching and the pace. Too sudden an increase in complexity or difficulty will see relatively more drop out at the nest assessment point than a well-structured and supported progression. This course has been a fine example of structure with no 'surprises' other than in the overall progress made when one looks back. A beautifully painless introduction and I look forward to the later courses.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-17T09:29:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you Professor.
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-17T19:24:35Z
SecondChildVoteTAG: 0
SecondChildTAG: What PaulJM said. *thumbs up*
SecondChildUserIdTAG: 230828
SecondChildUserNameTAG: alanis
SecondChildCreateTimeTAG: 2013-03-17T19:40:24Z
SecondChildVoteTAG: 0
SecondChildTAG: I like the pace of the course. I also like the teaching. It is very informative and deep. Professor A. makes statistics very easy to learn. Eventhough it is simple, but it has a lot of depth. And I too would like to say Thank You to Professor A., the University of Berkeley, the Staffs, and Edx. Thank You.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-03-17T20:27:33Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanx for a wonderful course. Study material, number of chapters of text book and concepts wise, by all criteria week 4 is more comprehensive but time provided is less. Due to unique structure of the course number of students are from non-mathematics background , many have other compelling commitments and deadlines to meet. Besides learning is a time taking process. Therefore Prof. A. , kindly extend the submission deadline for 2-3 days for week 4. Otherwise progress of some of otherwise good achievers is sure to fall unfairly. Meanwhile week 5 can be offered as per the schedule. sincerely Dr. Arvind
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-19T08:19:26Z
FirstChildVoteTAG: 0
IndexTAG: 744
TitleTAG: Help...!!!
Menu of the online book provided has a column named Assignments do we need to register and submit for it also? It asks for Student ID, which I don't know, is that my user name? My name also don't have a last name, will it accept it without my last name? What should I do?
UserIdTAG: 795482
UserNameTAG: VIVEK_88
CreateTimeTAG: 2013-03-17T03:55:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: No we don't !1 That is for the actual Berkeley course-not the online one !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-17T04:00:11Z
FirstChildVoteTAG: 0
SecondChildTAG: But that one asks for the course you are enrolled in, and there's an option for Stat2.2x.
SecondChildUserIdTAG: 795482
SecondChildUserNameTAG: VIVEK_88
SecondChildCreateTimeTAG: 2013-03-17T04:04:20Z
SecondChildVoteTAG: 0
SecondChildTAG: But that one asks for the course you are enrolled in, and there's an option for Stat2.1x.
SecondChildUserIdTAG: 795482
SecondChildUserNameTAG: VIVEK_88
SecondChildCreateTimeTAG: 2013-03-17T04:05:48Z
SecondChildVoteTAG: 0
SecondChildTAG: No Stat 2.1 is the onsite course.2.1 X is the MOOC Edx course !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-17T07:10:09Z
SecondChildVoteTAG: 0
FirstChildTAG: How do you come to be asking this a week before the course ends?
The online textbook was not prepared especially for Stat2.1X (the online edX course) but is an existing resource used by on-campus Statistics courses at Berkeley. As such, registering to submit assignments is not relevant.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T09:38:10Z
FirstChildVoteTAG: 0
IndexTAG: 745
TitleTAG: Stat2.2x - when is it beginning?
Dear Staff,
Would you know if and when the Stat2.2x course will be offered? Will this course or any other future course involve programming?
Thanks
UserIdTAG: 1181314
UserNameTAG: SolomonT
CreateTimeTAG: 2013-03-17T03:55:18Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The notification for it hasn't come yet. Probably it would start when this one ends.
FirstChildUserIdTAG: 795482
FirstChildUserNameTAG: VIVEK_88
FirstChildCreateTimeTAG: 2013-03-17T03:59:20Z
FirstChildVoteTAG: 0
FirstChildTAG: The best information offered so far (as highlighted in at least twenty posts that I've seen so far - does nobody ever search the board?) is that the later courses will follow on shortly after the current course - 'within a few weeks'. When it is available it will appear on the edX 'Find Courses' page.
Since courses are normally advertised some months ahead of the start date I'd be surprised to see Stat2.2X offered before May but I'd be happy for the team to confound me.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T09:42:38Z
FirstChildVoteTAG: 1
SecondChildTAG: > does nobody ever search the board?
That would be a "nope".
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-17T10:09:27Z
SecondChildVoteTAG: 0
IndexTAG: 746
TitleTAG: Wouldn't the Median be a better choice?
Given that the median is the number closest to the rest of the numbers so that the sum of the absolute values of the differences between each number and the median is the smallest value, then wouldn't it be better if we chose the median as the best guess? It would be closer to any random subject than any other value. This is in the one-variable question of the most approximate estimation. Please explain, I don't get why the average is the best choice in this scenario. Thank you.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-17T02:45:23Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.1: Estimation, bivariate normal (football shaped) scatter diagrams
NumberOfReplyTAG: 1
FirstChildTAG: Median doesnt allow itself to much calculation.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-17T03:31:49Z
FirstChildVoteTAG: 1
SecondChildTAG: Median is just a measure of location. It is the midway point of the data but not the center of the value of all the data. It doesn't say anything about the spread. Mean is the best value since it summarize many details about the spread(considering the values of data) of a variable.
SecondChildUserIdTAG: 1263723
SecondChildUserNameTAG: Chamikad
SecondChildCreateTimeTAG: 2013-03-18T16:59:16Z
SecondChildVoteTAG: 0
IndexTAG: 747
TitleTAG: ES9: Problem 1B
It seems to be more options right. Pls help
UserIdTAG: 898107
UserNameTAG: navgir
CreateTimeTAG: 2013-03-17T02:27:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: The instructions to that problem say "Pick all the options that are correct." So you can put a check mark next to all the answers you think are correct.
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-17T02:48:18Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes-
if you think all are right check all (most likely all aren't right). You may check all the boxes you believe are correct to the question.
SecondChildUserIdTAG: 1304644
SecondChildUserNameTAG: phillzRchamps
SecondChildCreateTimeTAG: 2013-03-17T04:01:17Z
SecondChildVoteTAG: 0
SecondChildTAG: thanx, for help.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T16:20:34Z
SecondChildVoteTAG: 0
IndexTAG: 748
TitleTAG: questions on Problem 5 in Midterm
Dear professor or anyone would like to explain that to me:
After I see the answer explanation in problem 5 in mid-term, I cannot still get this question>
For that question, mean =-0.795; SD =5.75 (By the way, Is this correct?)
I do not understand. mean +/- 4 SD
4 SDs =23
mean + 4SDs =22.205
OR mean - 4SDs=-23.795
However the whole list is -6.8, 2.3, 4.9, -11, -1.15, 4.9,-5.1,0.7,8.1, -4.8
Which 7 would be more than 4SDs away from the average?
Thank you for your explanation.
UserIdTAG: 547145
UserNameTAG: Pronectar
CreateTimeTAG: 2013-03-17T02:09:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Those are values in standard units - they are not to be recalculated as mean median and SD's again.They are the Z values.So the & greater than sau 4Sd's are -6.8,4.9 etc etc
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-17T03:34:20Z
FirstChildVoteTAG: 1
FirstChildTAG: Thank you for your explanation. But i'm still wondering how do I know it is in standard units and i do not have to calculate mean and SD.
2. In Chebychev's thoery, in any list, the proportion of entries that are k or more SDs away from the average is at most 1/k^2
K could be any positive number.
In this case how can i decide the k=4?
Thank you so much
FirstChildUserIdTAG: 547145
FirstChildUserNameTAG: Pronectar
FirstChildCreateTimeTAG: 2013-03-17T11:49:06Z
FirstChildVoteTAG: 0
SecondChildTAG: It is mentioned in the problem that the program converts the values to standard units.
How do we select 4- I did not I used 4.7 why because I knew that anything beyond 4 SD is very low and If you have a look at the values there are few within 3 Sd's and a lot above 4 SD's I took the value above 4 SD's which was highest but not included in the list and worked it out and it was sufficient to explain the result (I did not use -11 as there can be a statistical fluke with one value so I doubt that would be sufficient to "prove" what we are trying to say. You caould seriall try with other values too and once you get a value which succesfully proves Chebyshev you have got the answer.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-17T12:51:49Z
SecondChildVoteTAG: 0
FirstChildTAG: The list is supposed to contain values in standard units, so the numbers you see show how many SD a value is away from the average.
We know, from the early lectures on SD, that values in a dataset that are more than "a few" SDs away from the average are extremely rare. If we want to be a little more precise, we can use Chebychev's inequality, and say that values more than, say, 4SD from the average can be **at most** 6.25% of the total.
Just in the 10 values we see, there are *7* values above 4. That's **70%** of the 10 values that are more that 4SD away from the mean. This would be enough to stop and say that something is wrong, really.
But maybe you could say *"oh, but there are 90 more values in that list. Maybe the first 10 were just very different from the rest?"*. Well, even ignoring how improbable that is, 7 values is 7% of all 100 values, which is still more than your upper bound of 6.25%. Yeah, something is wrong.
The *k* you use for the test is not really important. You can do the same reasoning with any reasonable k(not too close to 1, and definitely not <1), and it will still be valid in principle.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T15:06:54Z
FirstChildVoteTAG: 0
IndexTAG: 749
TitleTAG: Linear or Non-Linear fit?
Rather than "look like" fitting, I'm just wondering if there exists any way to legitimately judge whether a given graph fits linear characteristics, or non-learn?
UserIdTAG: 695231
UserNameTAG: KarlKao
CreateTimeTAG: 2013-03-17T02:02:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Use esxcel or any other softwares for curve fitting....
FirstChildUserIdTAG: 725356
FirstChildUserNameTAG: sanjeeb1990
FirstChildCreateTimeTAG: 2013-03-17T10:47:51Z
FirstChildVoteTAG: 0
IndexTAG: 750
TitleTAG: and the answer to 6-4 is .....
I thought there was a non-linear, heteroscedastic strong association but no, so anyone what's the correct answer as it doesn't give it, thanks, mark
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-03-16T23:37:44Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: > non-linear, heteroscedastic strong association
For 6-4? That's what I put, and they were correct.
>what's the correct answer as it doesn't give it
Did for me.
>[-]Answer: b and d and f.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T23:47:37Z
FirstChildVoteTAG: 1
SecondChildTAG: That's good then, not me, just my software, again .. thanks lalotsb
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-17T01:46:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Maybe. The graph changes with each page refresh, so maybe some are missing solutions.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-17T01:53:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, I just did another one and the answer wasn't given.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-17T02:00:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Since more than one option could be correct, trying using the ctrl and/or shift to select multiple answers
SecondChildUserIdTAG: 961272
SecondChildUserNameTAG: CuriousCatastrophe
SecondChildCreateTimeTAG: 2013-03-17T03:29:13Z
SecondChildVoteTAG: 0
IndexTAG: 751
TitleTAG: Definition of corelation coeficient
Hi
I saw a definition for r that looks diferent than what we were thought :.The correlation coefficient, or Pearson product-moment correlation coefficient (PMCC
Can someone explain what are the diferences and how would one know what way r was calculated?
Regards
Moshiko
UserIdTAG: 1240022
UserNameTAG: Moshiko
CreateTimeTAG: 2013-03-16T21:55:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's exactly the same. You are right that it "looks different," but that's usually because the other formulas have to account for the fact that they used n-1 instead of n when calculating the SD. This is what is going in the Wikipedia article on the correlation coefficient, for example. Karl Pearson was the statistician who came up with the formal definition.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T22:13:52Z
FirstChildVoteTAG: 1
IndexTAG: 752
TitleTAG: Lecture 7.2
How do I get the percentile of 66.13% on the applet with the standard score of 0.421? How do I do it on the applet, I placed the 0.421 in the upper point and 0 in the lower point and can`t get the 66.33%. please help.
UserIdTAG: 521763
UserNameTAG: taakondjo
CreateTimeTAG: 2013-03-16T21:50:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You need to set the lower limit to -5. Or you add 50% to the value you got by leaving the lower limit as 0.
You need to look at the chart. You want **all** the area to the left.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T22:04:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you, if for example my answer is 69,76% do I have to around to get percentile of in this case is 70 is that accurate? or is it 69?
SecondChildUserIdTAG: 521763
SecondChildUserNameTAG: taakondjo
SecondChildCreateTimeTAG: 2013-03-16T22:41:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I've left my answers at 2dp, so 69.76
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-16T23:16:29Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you, for the 40th percentile both the 2dp and rounding failed to work. are you able to see the correct answer after 2 attempt of failure?
SecondChildUserIdTAG: 521763
SecondChildUserNameTAG: taakondjo
SecondChildCreateTimeTAG: 2013-03-17T00:11:10Z
SecondChildVoteTAG: 0
SecondChildTAG: You don't see the correct answer until after the deadline.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-17T00:39:10Z
SecondChildVoteTAG: 0
IndexTAG: 753
TitleTAG: Withdrawal
How can I withdraw from this course? I have already missed 2 weeks due to time constraints and the midterm. I am already aufait with the content of this course, I was only doing it for the certificate so I see no point in continuing.
UserIdTAG: 12117
UserNameTAG: Cloud
CreateTimeTAG: 2013-03-16T21:05:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: If you really want to withdraw, go back to the Dashboard (ie where you go when you log in from the edx.org homepage) and there is an 'unregister' link against each course for which you are currently registered. You could, alternatively, simply not continue - there is no real difference other than in the stats which edX compile.
I would point out, however, that the pass mark is only 35%. The two lowest graded exercises are discounted so those missed wouldn't make any difference and it would still be possible to pass with a mark of 80% despite having missed the Midterm. If, as you say, you are already au fait with the material then I'd take a shot at the remaining parts and see what happens.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T21:41:37Z
FirstChildVoteTAG: 1
FirstChildTAG: At least you are honest about it being just about the certificate. But what use is this certificate to you?
And if you have to be told how to withdraw from the course ... well your powers of observation haven't been improved. And stats is about observing. So maybe you should stick around.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T21:59:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Even if you have missed two weeks you have a decent chance to earn the certificate- it requires only 35%. You may manage some extra time to take up the old lectures. But better you don't quit.
FirstChildUserIdTAG: 795482
FirstChildUserNameTAG: VIVEK_88
FirstChildCreateTimeTAG: 2013-03-17T04:03:05Z
FirstChildVoteTAG: 0
IndexTAG: 754
TitleTAG: Midterm
Hello,
I don't understand the solution of problem 5
Could you please explain it in more detailed.
Thank you
UserIdTAG: 992597
UserNameTAG: Drhannaa
CreateTimeTAG: 2013-03-16T20:43:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I missed the midterm deadline. I thought it was said that it was due on the 18th. Oh my gosh! This is such a let down, especially after all of the work that I have already put in. I did not look for answers yet. I was not expecting any. Is there anyway that I can still take the mid-term, even with a penalty?
FirstChildUserIdTAG: 991819
FirstChildUserNameTAG: Queen9302
FirstChildCreateTimeTAG: 2013-03-16T21:51:31Z
FirstChildVoteTAG: 0
SecondChildTAG: > Is there anyway that I can still take the mid-term
Not unless you plan to wait until the next presentation of the course. It is clear that deadlines are strictly observed and with probably tens of thousands of students enrolled it would just not be practical to make exceptions.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T22:30:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok. I understand that. Just for your fyi and mine though, I received 12/20=0.6
I got 2b,3a, 3b, 4a wrong.
I know it won't count, but at least I did it anyway, closed book and no looking at answers so I will know how well I am doing.
My question now is do I still have a chance of passing this class although I missed the midterm? Otherwise, I will stop now and just wait until the next course if offered again.
SecondChildUserIdTAG: 991819
SecondChildUserNameTAG: Queen9302
SecondChildCreateTimeTAG: 2013-03-16T22:45:43Z
SecondChildVoteTAG: 0
SecondChildTAG: The midterm only accounts for 20% of the marks overall. The pass mark is 35% so it is certainly possible to pass without scoring on the midterm. As it stands now, my overall score if I take off the contribution from the Midterm (and without the Final) is 48.3% - a clear pass.
Whether you can pass depends on your score on the graded exercises and the Final exam. Take a look at the Progress chart, many students have already crossed the Pass line some time ago.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T23:16:40Z
SecondChildVoteTAG: 0
SecondChildTAG: The course policy says:
>Grading
>● Exercise Sets are due at specified dates and times. All times are in Greenwich Mean
Time (GMT).
>● Your two lowest Exercise Set scores will not be used in the calculation of your overall
grade.
>● Grades will be calculated using the following weights:
>Exercise Sets: 50%
>Midterm: 20%
>Final exam: 30%
>● Certificates of completion will be awarded to those who score 35% or
higher overall.
So just work out how many marks you can get with what assessment remains.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-16T23:20:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you!
SecondChildUserIdTAG: 991819
SecondChildUserNameTAG: Queen9302
SecondChildCreateTimeTAG: 2013-03-16T23:26:29Z
SecondChildVoteTAG: 0
FirstChildTAG: @Queen9302, why not continue with the course, then if you take it again for "credit," you will be that much further ahead of the game in terms of your understanding. The point is to understand the material, yes?
I have pretty much resigned myself to taking this course (or another introductory statistics course) annually until I really, really, really understand it!
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-17T02:25:18Z
FirstChildVoteTAG: 0
IndexTAG: 755
TitleTAG: Deadlines not clear
Its surprising how bad interface is for edX. It doesn't show a student on upcoming deadline. Midterm was having deadline before the weekly set and it was not highlighted clearly
Lectures and materials are good. My comment is mainly for edX staff to work on interface
UserIdTAG: 1008568
UserNameTAG: saxenashobhit
CreateTimeTAG: 2013-03-16T20:23:17Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You could put this suggestion in the Wiki under "Suggestions for Improvement".
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T20:46:08Z
FirstChildVoteTAG: 0
FirstChildTAG: I missed the midterm deadline. I thought it was said that it was due on the 18th. Oh my gosh! This is such a let down, especially after all of the work that I have already put in. I did not look for answers yet. I was not expecting any. Is there anyway that I can still take the mid-term, even with a penalty?
FirstChildUserIdTAG: 991819
FirstChildUserNameTAG: Queen9302
FirstChildCreateTimeTAG: 2013-03-16T21:51:23Z
FirstChildVoteTAG: 0
FirstChildTAG: Unclear? But it was clearly stated in several places.
> My comment is mainly for edX staff to work on interface
And my comment is for students - you need to read **all** the material on the course site.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-17T21:34:52Z
FirstChildVoteTAG: 0
IndexTAG: 756
TitleTAG: Quitting
Though I really enjoyed this course but the time restraints are just too much. I am taking another edx course in biology and I have work for school and this course is just not working out so I'll be taking the udacity course instead so i can go a bit slower. Best of luck to the rest of you.
UserIdTAG: 1222341
UserNameTAG: richardHk
CreateTimeTAG: 2013-03-16T20:21:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Thanks. Best of luck for your other courses
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-16T21:56:01Z
FirstChildVoteTAG: 0
FirstChildTAG: The Udacity course is not as good.
FirstChildUserIdTAG: 1055674
FirstChildUserNameTAG: SocProf
FirstChildCreateTimeTAG: 2013-03-16T22:51:34Z
FirstChildVoteTAG: 1
IndexTAG: 757
TitleTAG: I have the worst score
i do not know what was the problem, I got a bad score. Is this exercise is difficult or i who did not concentrate well !! I do not know!!
UserIdTAG: 601399
UserNameTAG: doaamouhammed
CreateTimeTAG: 2013-03-16T20:16:51Z
VoteTAG: 5
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 7
FirstChildTAG: same with me, averging 90 al the way, only 50 on this one
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-03-16T20:32:22Z
FirstChildVoteTAG: 0
FirstChildTAG: sorry for you but I had 80%
it is not so hard
FirstChildUserIdTAG: 633858
FirstChildUserNameTAG: balakh
FirstChildCreateTimeTAG: 2013-03-16T20:41:03Z
FirstChildVoteTAG: 0
SecondChildTAG: It is hard and confusing
SecondChildUserIdTAG: 1198994
SecondChildUserNameTAG: parthkelkar
SecondChildCreateTimeTAG: 2013-03-18T17:15:06Z
SecondChildVoteTAG: 0
FirstChildTAG: its not hard however support was not good at this point.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-16T21:21:14Z
FirstChildVoteTAG: 1
FirstChildTAG: Support with the video and the text book and excercises was quite enough. I got a good score.
FirstChildUserIdTAG: 1262270
FirstChildUserNameTAG: JPorcel
FirstChildCreateTimeTAG: 2013-03-16T23:26:07Z
FirstChildVoteTAG: 0
SecondChildTAG: +JPorcel, if you have background in Stat then no issue, however for beginners like me it is. If you ask chemistry (nano-medicine), I probably do not need to read and can give ans to your most un-logistic qus as well.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T02:32:32Z
SecondChildVoteTAG: 0
SecondChildTAG: i'm a beginner with nearly no experience and got 100%
just i depende on imagination of the plots :)
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-17T23:57:16Z
SecondChildVoteTAG: 0
FirstChildTAG: This is all because it is only **SEVEN** questions, worth only **TEN** points.
FirstChildUserIdTAG: 1304644
FirstChildUserNameTAG: phillzRchamps
FirstChildCreateTimeTAG: 2013-03-17T04:03:07Z
FirstChildVoteTAG: 1
FirstChildTAG: I got a little puzzled also, but afterall I noticed that I was too much concerned about the calculus while I forgot the main, what is in fact the correlation coefficient! I got 70 on this, when I did 2 answer wrong I read the slides again, more calm, so I noticed it´s easier than I thought in a first glance. So you have to pay attention mainly in the part about the perfect straight line sloping down and up! Read the slides again if it seems difficult to you.
FirstChildUserIdTAG: 708307
FirstChildUserNameTAG: Rodrigo-moura
FirstChildCreateTimeTAG: 2013-03-17T05:04:36Z
FirstChildVoteTAG: 1
FirstChildTAG: Now I am reading books "Statistic 4th edition" recommended by Prof. A. A. Thanks a lot dear classmates.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-20T21:30:54Z
FirstChildVoteTAG: 0
IndexTAG: 758
TitleTAG: REGARDING CERTIFICATE //IMPORTANT//
I am having more than 35% in my final progress bar does it mean my certificate is confirmed??
UserIdTAG: 959584
UserNameTAG: aadiltrikha
CreateTimeTAG: 2013-03-16T19:28:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: You can search the discussion forum and find lots'n'lots of threads on the exact same question, e.g.: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/513c84daa021232600000103
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-16T20:26:16Z
FirstChildVoteTAG: 1
FirstChildTAG: the prof says in the course policies and requirements:
>Certificates of completion will be awarded to those who score 35% or higher overall.
Seems pretty cut and dried. Get 35%, get the certificate. You won't have much knowledge, but you will have a certificate.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T21:08:50Z
FirstChildVoteTAG: 2
IndexTAG: 759
TitleTAG: how i can calculacte standerd units
how i can calculacte standerd units
UserIdTAG: 776071
UserNameTAG: phaliaa
CreateTimeTAG: 2013-03-16T19:14:00Z
VoteTAG: 1
CoursewareTAG: Section 6: Relation between two variables / Lec 6.2: The correlation coefficient: calculation and properties
NumberOfReplyTAG: 1
FirstChildTAG: If you have a list of entries for X and a list of entries for Y,
Step 1: Calculate the Average of X and the SD of X
Step 2: Calculate the Average of Y and the SD of Y
Step 3: To convert the X-values to Standard Unit or Z use this formula
Z = (X - Average of X)/ SD of X
Step 4: To convert the Y-values to Standard Unit or Z use the same formula but be sure you use Y-value and Average of Y and the SD of Y.
Z = (Y - average of Y)/ SD of Y
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-16T19:29:48Z
FirstChildVoteTAG: 7
SecondChildTAG: Thank you!
SecondChildUserIdTAG: 773223
SecondChildUserNameTAG: Andaponte
SecondChildCreateTimeTAG: 2013-03-19T03:11:39Z
SecondChildVoteTAG: 0
IndexTAG: 760
TitleTAG: Unable to open text book/ applet
Hi all,
I'm not sure if this is a problem only I am having, but when I click on any of the links to open the text book, I am getting a link to the 'Department of Statistics University of Berkeley' home page (http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm )
Earlier today this happened with some of the new links, but I was able to get in using older links. Now the older links also don't work.
So, two questions:
1. What can I use if I can't use the applet
2. Is anybody else unable to access the text book?
Thanks very much,
Aimee
UserIdTAG: 1256079
UserNameTAG: AimeeGrant
CreateTimeTAG: 2013-03-16T18:38:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: i had such problem and i tackled it by on line calculators
FirstChildUserIdTAG: 633858
FirstChildUserNameTAG: balakh
FirstChildCreateTimeTAG: 2013-03-16T20:46:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Open a second tab in your window. In the address bar of the second tab, type in the applet address (that whole http://statistics.berkeley.edu blah blah that they give you in the course requirements section) and press enter. The aplet should appear in your second tab window. This also allows you to switch back and forth from one tab to the other without messing up your flow.
FirstChildUserIdTAG: 797869
FirstChildUserNameTAG: edoz
FirstChildCreateTimeTAG: 2013-03-17T16:03:54Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi edoz, thanks for your answer. Unfortunately the link doesn't work regardless of the number of windows.
Thanks for trying,
Aimee
SecondChildUserIdTAG: 1256079
SecondChildUserNameTAG: AimeeGrant
SecondChildCreateTimeTAG: 2013-03-18T21:39:31Z
SecondChildVoteTAG: 0
FirstChildTAG: So by following that link you posted yourself ([http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm][1]), you find yourself on the homepage for the Department of Statistics?
[1]: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-17T19:01:24Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes - it's odd isn't it?! It only started happening a few days ago - the link had previously worked fine!
Thanks,
Aimee
SecondChildUserIdTAG: 1256079
SecondChildUserNameTAG: AimeeGrant
SecondChildCreateTimeTAG: 2013-03-18T21:38:49Z
SecondChildVoteTAG: 0
IndexTAG: 761
TitleTAG: not showing in proggress bar !
i answered a right ans but it doesn't effect on progress bar why.marked-2
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-16T18:31:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: What week's exercises are you working on?
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T18:36:09Z
FirstChildVoteTAG: 0
FirstChildTAG: you may did that after the time is over
FirstChildUserIdTAG: 633858
FirstChildUserNameTAG: balakh
FirstChildCreateTimeTAG: 2013-03-16T20:48:30Z
FirstChildVoteTAG: 0
FirstChildTAG: i was in ex 9 prob 4.that was not shown in progress bar !
FirstChildUserIdTAG: 1042429
FirstChildUserNameTAG: Rifayat
FirstChildCreateTimeTAG: 2013-03-17T04:37:34Z
FirstChildVoteTAG: 0
IndexTAG: 762
TitleTAG: Wikipedia article on correlation coefficient
I found the first two figures in the wikipedia article very useful:
http://en.wikipedia.org/wiki/Pearson_product-moment_correlation_coefficient
UserIdTAG: 99863
UserNameTAG: pramode_ce
CreateTimeTAG: 2013-03-16T17:56:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Very interesting AND useful. Maybe someday I will understand more of the technical math. We are getting a very good start with this course, and I like looking at what other people are finding on the web. It helps to review multiple sources of the same concepts, so thank you!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T18:14:32Z
FirstChildVoteTAG: 0
IndexTAG: 763
TitleTAG: Video in textbook, Chapter 6
The video on association in chapter 6 of the textbook is very frustrating to watch, or should I say listen to. The instructor many times says "throw out something over there", "looking at this slice here", "over there" etc., however you never see where he is pointing to or what he is referring to. It does no good to refer to some place on the screen without pointing to it.
For feedback in the future, please show the instructor in the video so we can see what and where he is pointing.
UserIdTAG: 132828
UserNameTAG: rharris
CreateTimeTAG: 2013-03-16T17:48:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You should consider putting such helpful comment(s) in the Wiki section under "Suggestions for Improvements". Otherwise, your ideas might just get lost here with all the other Discussion posts.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T18:44:19Z
FirstChildVoteTAG: 0
FirstChildTAG: It is also worth remembering that the videos in the textbook don't form part of the course but are merely supporting material. They also aren't produced for the Stat2x course but are part of an existing Berkeley resource.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T21:00:54Z
FirstChildVoteTAG: 0
FirstChildTAG: The video in the text is from the actual f2f Berkeley course. Not our mooc. So I really don't think complaining about the lecture style is going to do anything. Unless you enrol at Berkeley.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T21:06:18Z
FirstChildVoteTAG: 0
SecondChildTAG: The video in the online text is actually from Berkeley's Stat 21, which is an intro course with a calculus prerequisite.For Stat 2.1X, I've created video lecture segments geared specially for the course. These are the ones in Courseware.
Philip Stark was filmed (one camera, I think) one semester when he was teaching Stat 21. Those videos have become part of the online text.
Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-16T22:21:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Prof Stark does a great job, he's just a tad nervous ..
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T22:43:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the feedback.
I didn't intend to criticize Prof. Stark, I believe he is doing an excellent job and is very knowledgeable. The feedback was primarily based on the operation of the camera, which needs to show the instructor while he talks. I realize these video's weren't created specifically for this style of class and I'm sure they will get better as edX prefects it system.
And by the way, I believe this type of interactive textbook is a brilliant idea and an excellent way to teach online. Thank you Dr. A and staff for coming up with it.
SecondChildUserIdTAG: 132828
SecondChildUserNameTAG: rharris
SecondChildCreateTimeTAG: 2013-03-18T19:25:15Z
SecondChildVoteTAG: 0
IndexTAG: 764
TitleTAG: Problem 2B
Can you tell me please if points for a quiz could be negative? (-10)? If we regard the situation when a student has no correct answers his score would be 0 or -10? The correlation between the number of correst answers and the score of the student would be different because students that make less then 2 correct answers would get 0 and there will be more 0.
UserIdTAG: 903120
UserNameTAG: Rapunzelia
CreateTimeTAG: 2013-03-16T17:22:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 4
FirstChildTAG: you can use the function =CORREL on excel, its the simplest way of doing the exercise, imo
FirstChildUserIdTAG: 996436
FirstChildUserNameTAG: FredRodrigues
FirstChildCreateTimeTAG: 2013-03-16T17:44:18Z
FirstChildVoteTAG: 2
SecondChildTAG: how do you do that on excel? please give me an example.
SecondChildUserIdTAG: 521763
SecondChildUserNameTAG: taakondjo
SecondChildCreateTimeTAG: 2013-03-16T19:40:05Z
SecondChildVoteTAG: 0
SecondChildTAG: thanx +FredRodrigues, that helps, I know one was + other was - (but confused what to write r or value). Corrected both
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T02:01:31Z
SecondChildVoteTAG: 0
FirstChildTAG: You are told that you lose a mark for every incorrect answer. So if you got 10 wrong, you get -10.
Just plot out the possible answers.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T21:02:42Z
FirstChildVoteTAG: 0
SecondChildTAG: no 5*x-1*y (x = no. right, y = wrong)
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T02:02:35Z
SecondChildVoteTAG: 0
FirstChildTAG: Rapunzelia - The correlation is the same either way. Lalotsb is correct, plot the possible score combinations and calculate r at several points along the plot line. r is the same whether you allow negative scores or not.
FirstChildUserIdTAG: 876324
FirstChildUserNameTAG: BrianDeering
FirstChildCreateTimeTAG: 2013-03-17T13:23:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Agreed but are you saying that the answer would include a negative score?
FirstChildUserIdTAG: 344400
FirstChildUserNameTAG: carlallen
FirstChildCreateTimeTAG: 2013-03-17T15:40:03Z
FirstChildVoteTAG: 0
IndexTAG: 765
TitleTAG: In addition to exercise 7.3 & 7.4: Guessing Correlations
A handy website to get more practice estimating correlations: http://www.istics.net/Correlations/
UserIdTAG: 591304
UserNameTAG: KMV
CreateTimeTAG: 2013-03-16T17:21:11Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: Thanks for this link, I had a little fun.
FirstChildUserIdTAG: 1167094
FirstChildUserNameTAG: ATTAHENRY1
FirstChildCreateTimeTAG: 2013-03-17T14:50:50Z
FirstChildVoteTAG: 1
SecondChildTAG: Relating to exercies 7.3 and 7.4 i didn't understand how to find r. Is there somebody that can explain it?
Thank you!
SecondChildUserIdTAG: 1004145
SecondChildUserNameTAG: ElyC
SecondChildCreateTimeTAG: 2013-03-17T15:00:36Z
SecondChildVoteTAG: 0
SecondChildTAG: r=1 is a perfect line pointing 45° up.
r=0 is data scattered with no (linear) pattern at all.
r=-1 is a perfect line pointing 45° down.
If you have data that forms a linear pattern, its r value will be between these values. The more the data pattern resembles a line, the closer r will be to + or - 1.
This should be enough to make rough estimates. That link posted by KMV is perfect for practicing ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-17T19:11:59Z
SecondChildVoteTAG: 0
SecondChildTAG: actually, drop the references to the angles. I don't know exactly why I put those there :o
The important thing is, the more the data resembles a straight line, the closer you are to $r=\vert1\vert$. The sign depends on whether the line is sloped down, or up.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-17T20:37:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I just can't write today. Hate that I can't edit subanswers :|
For the little equation in bold, I meant of course $\vert r \vert=1$.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-17T20:40:07Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you for your help! I will exercise!
SecondChildUserIdTAG: 1004145
SecondChildUserNameTAG: ElyC
SecondChildCreateTimeTAG: 2013-03-18T20:41:38Z
SecondChildVoteTAG: 0
IndexTAG: 766
TitleTAG: NA as un answer
Problem 9.2 does not accept NA as the final answer...why?????
UserIdTAG: 400844
UserNameTAG: Mario007
CreateTimeTAG: 2013-03-16T17:01:46Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Same problem here. Tried capital and small letters but still receiving error message. I double check the language setting (set as english for no english OS users)
FirstChildUserIdTAG: 1090983
FirstChildUserNameTAG: AchilleasP
FirstChildCreateTimeTAG: 2013-03-16T17:11:35Z
FirstChildVoteTAG: 1
SecondChildTAG: may be alphabetic answers are not required by the question
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-17T00:42:28Z
SecondChildVoteTAG: 0
FirstChildTAG: SAME PROBLEM FACING.THAT'S A CRAB ....
FirstChildUserIdTAG: 1400928
FirstChildUserNameTAG: helalrahman
FirstChildCreateTimeTAG: 2013-03-16T18:02:24Z
FirstChildVoteTAG: 1
SecondChildTAG: > SAME PROBLEM FACING.THAT'S A CRAB ....
A crab? Sorry, A CRAB? Why?
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-16T21:01:08Z
SecondChildVoteTAG: 0
SecondChildTAG: ![enter image description here][1]
[1]: http://weknowmemes.com/wp-content/uploads/2011/10/classy-crab1.jpg
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-18T03:18:31Z
SecondChildVoteTAG: 0
FirstChildTAG: Same problem here.
FirstChildUserIdTAG: 1291556
FirstChildUserNameTAG: zaeemy
FirstChildCreateTimeTAG: 2013-03-16T18:12:41Z
FirstChildVoteTAG: 1
FirstChildTAG: The answer is not NA. The answer is a numerical value.
For this problem, you can easily draw out a diagram. Or you can conceive the diagram abstractly and see the relationship between the two. And you can switch the variables and the relationship would still be the same.
There are 10 questions. For every 1 more question you get right, you get 1 less question wrong.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-16T19:48:49Z
FirstChildVoteTAG: 2
SecondChildTAG: Ok i wasn' t thinking that way.. the answer is clear now... thanks for yor help :)
SecondChildUserIdTAG: 1090983
SecondChildUserNameTAG: AchilleasP
SecondChildCreateTimeTAG: 2013-03-16T22:46:27Z
SecondChildVoteTAG: 0
IndexTAG: 767
TitleTAG: MISSED THE MIDTERM EXAM
I MISSED THE MIDTERM EXAM..!! WHAT SHOULD I DO NOW?? PLEASE HELP ME!!
am i still have a permission to continue the lecture?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-16T17:00:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You don't need extra permission to continue. As long as you are registered, you can keep going. Just do the best you can, and prepare for the upcoming (soon) final exam. That exam counts for a lot, and if you do well you might still get your certificate.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T18:19:08Z
FirstChildVoteTAG: 1
SecondChildTAG: I am having more than 35% in my final progress bar does it mean my certificate is confirmed??
SecondChildUserIdTAG: 959584
SecondChildUserNameTAG: aadiltrikha
SecondChildCreateTimeTAG: 2013-03-16T19:26:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Some folks are saying yes, but I am not sure. If you were to stop doing anything else for the class in this first of three segments, then all those upcoming zeroes you get for the remaining two segments will count against your average. Sorry I can't be more helpful; hopefully someone will come along and clear up the confusion. I personally am going to see this through completely because it is making my brain feel alive again! That's surely worth more than a certificate for me.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-16T20:54:29Z
SecondChildVoteTAG: 0
SecondChildTAG: The total shown on the Progress chart already includes zero for all incomplete elements so can only go increase. If you have more than 35% then you have passed the course.
50% of the marks overall come from the graded exercises so if a student achieves an average of 70% on those there is no **need** to take either exam!
> If you were to stop doing anything else for the class in this first of three segments, then all those upcoming zeroes you get for the remaining two segments will count against your average
Each course is free-standing. Nothing you do in this course can affect the mark in later courses (except by improving your learning, of course!). Even if the team take up my suggestion to link the three courses with an over-arching certificate, only the Pass/Fail grade for each course would matter.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T21:19:15Z
SecondChildVoteTAG: 0
IndexTAG: 768
TitleTAG: dome
When I looking at the stars now I`m trying to set the appropriate units to that space scatter... ))
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-16T16:47:03Z
VoteTAG: 1
CoursewareTAG: Section 6: Relation between two variables / Lec 6.1 Scatter Diagrams
NumberOfReplyTAG: 1
FirstChildTAG: LOL and a little scary! And what have you discovered so far?
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T18:19:57Z
FirstChildVoteTAG: 0
SecondChildTAG: that the universe can't be a scatter plot as it has more than 2 dimensions...
SecondChildUserIdTAG: 720154
SecondChildUserNameTAG: LUCALOTTO2012
SecondChildCreateTimeTAG: 2013-03-19T11:20:59Z
SecondChildVoteTAG: 0
SecondChildTAG: and...that the correlation factor between receding speed of a "star" and its distance from Earth is close to one....
SecondChildUserIdTAG: 720154
SecondChildUserNameTAG: LUCALOTTO2012
SecondChildCreateTimeTAG: 2013-03-19T12:36:21Z
SecondChildVoteTAG: 0
IndexTAG: 769
TitleTAG: [Staff] Typo in Chapter 6 Association of Pairs of Variables
I think there are a couple of typos in this section:
*The SD is a measure of the scatter in a list. The typical deviation of the x coordinate of a point from the mean of the x coordinates is SDX. The typical deviation of the y coordinate of a point from the mean of the y coordinates is SDX. We know from Chebychev's inequality that, for example, the x coordinates of at least 75% of the points will be within ±SDX of the x coordinate of the point of averages,*
Should be:
The typical deviation of the y coordinate of a point from the mean of the y coordinates is **SDY**.
and
We know from Chebychev's inequality that, for example, the x coordinates of at least 75% of the points will be within **±2SDX** of the x coordinate of the point of averages,
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-03-16T16:15:22Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I was just going to post about this. Glad to see I'm not crazy! Thanks for the post.
FirstChildUserIdTAG: 969411
FirstChildUserNameTAG: McAlary
FirstChildCreateTimeTAG: 2013-03-17T04:26:57Z
FirstChildVoteTAG: 0
IndexTAG: 770
TitleTAG: Problem Explanation doesn't make sense
(1A. One of the students is on the 70th percentile of the final. Estimate this student’s percentile rank on the midterm.
Exaplanation:
The 70th percentile is z = 0.524. So the estimated midterm score is 0.4***0.675** = 0.21 standard units. Under the standard normal curve, roughly 58% of the area is to the left of 0.21.)
The Above question and Answer, I don't get it.
As I understand, The Final exams happen later than midterm. Therefore, shouldn't we divide 0.525/0.4 to get midterm exams percentile.
**and Above that what is this 0.675 that shows up in explanation; its an error.**
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-03-16T15:49:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 3
FirstChildTAG: It makes sense to divide in that, we can go backwards from where we came. But statistically and mathematically speaking, dividing by r takes us away from the mean. In this course, always multiply by r.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-16T16:28:24Z
FirstChildVoteTAG: 0
FirstChildTAG: It's a typo. That should be 0.4*0.524 = 0.21; the rest is fine. Thanks for catching that. I'll fix it.
But no, you don't divide. The first equation is (in standard units)
estimated final = r x midterm
The second is
estimated midterm = r x final
Those are not the same equations. There are four variables in them, not two.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T18:41:05Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks.
SecondChildUserIdTAG: 786512
SecondChildUserNameTAG: shoaibkhanz
SecondChildCreateTimeTAG: 2013-03-16T18:59:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Prof. this hint is enough to get to the root.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T16:33:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you so much.
FirstChildUserIdTAG: 1093310
FirstChildUserNameTAG: SeemaAbb
FirstChildCreateTimeTAG: 2013-03-18T15:44:51Z
FirstChildVoteTAG: 0
IndexTAG: 771
TitleTAG: Re: Section 6 - Relation between 2 variables & Practice for Ex. Set 9
Where are lectures 6.1 - 6.3 in the online text? Are they in Chapter 5 or 6? Where is chapter 5.8? There is no part in chapter 5 that's labeled "chapter 5.8" or even "5.8".
We're asked to do ex. 5.5, 5.6, 6.4, 7.2 - 7.5. What part of the text covers this work?
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-03-16T15:47:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Yes, it is confusing the way it is worded, isn't it? Links would have been helpful.
Lectures 6.1-6.3 are in Courseware, Week 4 (current week). These are Prof. A.'s videos.
The "chapters" refer to the Sticigui text and videos. These are Prof. Stark's lectures. It's helpful to bookmark the table of contents so you can just click on the chapter needed. We are being asked to review Chapters 5 thru 8, briefly. So, for example, you will find exercises 5.5 etc. within the text that surrounds the videos.
Bookmark this:
[http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm][1]
[1]: http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T18:33:25Z
FirstChildVoteTAG: 0
FirstChildTAG: It was meant to say "Chapters 5-8" meaning Chapters 5 through 8. I'll take another look. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T18:37:54Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks all!
FirstChildUserIdTAG: 797869
FirstChildUserNameTAG: edoz
FirstChildCreateTimeTAG: 2013-03-17T16:05:20Z
FirstChildVoteTAG: 0
IndexTAG: 772
TitleTAG: homoscedasticity
Professor Stark says:
*When the scatter in Y is about the same in different vertical slices through a scatterplot, the data (and the scatterplot) are said to be homoscedastic (equal scatter).*
Can we determine homoscedasticity by looking at the scatter in X and taking horizontal slices? I would think so because we could just switch the x and y axis.
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-03-16T15:12:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 773
TitleTAG: somewhat disappointed
Like so many here I've enjoyed this course, even though it's been a little tougher than I expected. I have a BA from a good school and although I've never taken a stats course before I was able to get through college algebra and basic calculas without too much of a problem. My primary motivation in taking this course, frankly, is th fact that personalities like Nate Silver and Billy Beane have been much in th news in th recent past. But, as far along as we are in th course I'm still not sure about th simplest of stats such as: if one were to buy a lottery ticket where th odds of winning is 1 million to 1, what are th odds if I were to buy 10 tickets? 1 million to 10? I'm simply not sure. Or, in american football th most significant stat to winning is, and has been, yardage per passing attempt; is it really that simple?
UserIdTAG: 950367
UserNameTAG: catt9
CreateTimeTAG: 2013-03-16T14:52:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: We have not yet talked about probability - that probably comes later in the course. Don't forget, this is a 3 part course. There is a lot of statistics to come!
FirstChildUserIdTAG: 433872
FirstChildUserNameTAG: dfburke
FirstChildCreateTimeTAG: 2013-03-16T15:08:40Z
FirstChildVoteTAG: 1
FirstChildTAG: We need to walk before we can run.The next part is going to be about probability and the third inferential statistics but with the amount of knowledge we have do not expect to become a Nate Silver - that requires more computational statistics and I doubt we can do that from this course.You would probably need to do your Masters or much more !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-16T15:13:14Z
FirstChildVoteTAG: 2
SecondChildTAG: I admire th Nate Silvers of th world, I certainly don't wish to be like them. (Frankly, I'd rather be more like Bill James.) And thank you, as well as th others, for your responses.
SecondChildUserIdTAG: 950367
SecondChildUserNameTAG: catt9
SecondChildCreateTimeTAG: 2013-03-17T16:30:09Z
SecondChildVoteTAG: 0
FirstChildTAG: I can recommend the book _What Are the Odds: Chance in Everyday Life_ by Mike Orkin. He spends a lot of time talking about lottery odds and casino games.
I found it at the library just as this course was beginning. What are the odds? ;v)
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-17T02:34:45Z
FirstChildVoteTAG: 0
SecondChildTAG: thanx
SecondChildUserIdTAG: 950367
SecondChildUserNameTAG: catt9
SecondChildCreateTimeTAG: 2013-03-17T16:31:45Z
SecondChildVoteTAG: 0
FirstChildTAG: Stat2.2x is going to be probability!
FirstChildUserIdTAG: 1157957
FirstChildUserNameTAG: meganbh
FirstChildCreateTimeTAG: 2013-03-17T03:18:03Z
FirstChildVoteTAG: 0
IndexTAG: 774
TitleTAG: Best Experience..............
I`m getting first time online classes and i really this
UserIdTAG: 1416883
UserNameTAG: shoaib145
CreateTimeTAG: 2013-03-16T14:48:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 775
TitleTAG: Do what the video told you!
Plz recall the definition of **r** and then watch the video again! XD
If you have tried entering "NA" into the response bar but doing so didn't work, then figure out other methods! XD
UserIdTAG: 1378421
UserNameTAG: Misaka
CreateTimeTAG: 2013-03-16T14:43:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: I'm confused too, don't know what to write. I know one of th ans is +r and other is -r, do we write one of these or some r = value + or - whatever.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-16T21:24:41Z
FirstChildVoteTAG: 0
FirstChildTAG: Remember what r measures - the degree of variation around the line.
Now think about the example. If a student has 6 correct answers then how many wrong answers would he have he have? How much scope is there for variation? If you plotted all possible results, what would you see?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T21:32:03Z
FirstChildVoteTAG: 1
SecondChildTAG: thanx PaulJM, it really helps.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T16:14:45Z
SecondChildVoteTAG: 0
FirstChildTAG: I want to know do I have to convert score variables into z-score?? x and y have the same unit!!
FirstChildUserIdTAG: 1048539
FirstChildUserNameTAG: Reham1989
FirstChildCreateTimeTAG: 2013-03-17T21:17:35Z
FirstChildVoteTAG: 0
IndexTAG: 776
TitleTAG: How to check SD of outlier in the scatterd plot graph???
Chapter 5 TEXT last question please explain ???
UserIdTAG: 959584
UserNameTAG: aadiltrikha
CreateTimeTAG: 2013-03-16T14:19:23Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: You can find the SD by clicking on the "Univariate Stats" button.
Once you've done that you can scroll down to Undergrad GPA, you'll find the following information there:
Undergrad. GPA: Cases,Mean,SD,Min,LQ,Median,UQ,Max.
I've removed the numbers to make you go look for them :).
I hope this helped.
FirstChildUserIdTAG: 372474
FirstChildUserNameTAG: JeroenPinoy
FirstChildCreateTimeTAG: 2013-03-16T15:18:13Z
FirstChildVoteTAG: 2
SecondChildTAG: The value of the undergraduate GPA for the outlier is That is SDs the mean undergraduate GPA
VALU of outlier i got Please elaborate how to predict its SD ?? thank you
SecondChildUserIdTAG: 959584
SecondChildUserNameTAG: aadiltrikha
SecondChildCreateTimeTAG: 2013-03-16T19:31:27Z
SecondChildVoteTAG: 0
SecondChildTAG: mean is at 3.24,3.04 & outlier is at 1.11,2.90 how to calculate SD
SecondChildUserIdTAG: 959584
SecondChildUserNameTAG: aadiltrikha
SecondChildCreateTimeTAG: 2013-03-16T19:34:49Z
SecondChildVoteTAG: 0
IndexTAG: 777
TitleTAG: Marked scores disappeared!
I checked this exercise (set 3) today and to my surprise, all my marked scores have completely vanished. Not a single one!
I could remember vividly, I deed submit all my answers before the deadline.
Please is there anything the course moderator can do about this?
Thanks.
UserIdTAG: 886442
UserNameTAG: ismail23us
CreateTimeTAG: 2013-03-16T13:48:11Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Do they still register on the progress tab? If so there's nothing to worry about.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-16T14:11:32Z
FirstChildVoteTAG: 0
IndexTAG: 778
TitleTAG: possibility of solutions
Is there any chance solutions could be offered for problem set following the deadline ?
UserIdTAG: 1290797
UserNameTAG: GrahamReynolds
CreateTimeTAG: 2013-03-16T12:35:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Solutions are always available for problems after the deadline. Just go back to the page and select 'Show Answer'.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T12:39:53Z
FirstChildVoteTAG: 1
IndexTAG: 779
TitleTAG: SuperMan :)
Dear Professor,
according to this Lecture:
...to be or not to be the SuperMan, this is an interesting and diabolique question,
best regards.
UserIdTAG: 426127
UserNameTAG: hurgadion
CreateTimeTAG: 2013-03-16T12:16:04Z
VoteTAG: 0
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.3: Regression effect, Galton, and the regression fallacy
NumberOfReplyTAG: 1
FirstChildTAG: Eugenics had a blossoming of interest in the late 19th century and early 20th with the ambition to extend the principles of scientific selective breeding programmes, common for millennia in animal husbandry, to the genetic pool of mankind. Various governments enacted policies in line with eugenic principles in the early decades of the 20th Century. Eugenics is commonly linked with the Nazi policies and the attempt to breed a pure 'Aryan' race.
The major issues with eugenics are the classification of 'desirable' traits and the compulsive element required to operate the policy. It might seem uncontentious to give individuals information about the risk of passing on a genetic condition. If that is followed up by compulsory sterilisation it suddenly seems rather less reasonable. If the 'genetic condition' is moral delinquency (women becoming pregnant outside marriage), poverty, sexual orientation or race (Jews and Roma - gypsies - were favoured targets in Europe) there are some obvious holes opening up in the policy...
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T12:36:58Z
FirstChildVoteTAG: 4
SecondChildTAG: I understand now... My joke was a little unsuitable...
SecondChildUserIdTAG: 426127
SecondChildUserNameTAG: hurgadion
SecondChildCreateTimeTAG: 2013-03-16T19:07:49Z
SecondChildVoteTAG: 0
SecondChildTAG: great explanation! thanks
SecondChildUserIdTAG: 969411
SecondChildUserNameTAG: McAlary
SecondChildCreateTimeTAG: 2013-03-18T12:32:16Z
SecondChildVoteTAG: 0
IndexTAG: 780
TitleTAG: Errors in Chapter 6 of Textbook?
The second paragraph of the Association of Pairs of Variables section of chapter 6 of the text book looks to have some typos.
http://statistics.berkeley.edu/~stark/SticiGui/Text/association.htm
Could a member of staff please confirm or deny this?
* "The typical deviation of the y coordinate of a point from the mean of the y coordinates is SDx"
** Shouldn't this be "is SDy"?
* The discussion on 75% of the points uses +- 1 SD for x and +- 2 SDs for y.
** Shouldn't they both be +- 2 SDs?
UserIdTAG: 1735
UserNameTAG: Stewart
CreateTimeTAG: 2013-03-16T12:04:03Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 0
IndexTAG: 781
TitleTAG: about PROBLEM 5
The list -6.8, 2.3, 4.9, -11, -1.15, 4.9, -5.1, 0.7, 8.1, -4.8, in standards units includes numbers that are very different from the numbers we used to use in the applet, so my answer was based on that fact and not on your answer you proposed, which is very interesting, and defines a limit to this types of tests. If you used numbers under the interval -5 to +5 it where more intriguing and forced us to use Tchebychev.
I didn't do the midterm, I didn't have time. Only in the weekend, but I collect very good information (I get a 16V, not bad). The most important is that I am learning. Thank you for your very very very good work. Best, António
UserIdTAG: 122004
UserNameTAG: fqantonio
CreateTimeTAG: 2013-03-16T11:33:23Z
VoteTAG: 0
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 1
FirstChildTAG: I agree. I realized that students might get the right answer for excellent intuitive reasons but not with a calculation; that is indeed a limit of this kind of assessment. I thought of making the numbers less dramatic but I felt that would have led to more students getting very worried about whether the numbers looked "off" but there wasn't enough information to decide. Based on the emails I got about the problem even in its current form, that judgment was correct.
However, I'm happy that students are developing their intuition. Good statistical intuition is sorely lacking in the world - that's one of the primary reasons for the rubbish that gets passed off as statistics all over the place, and for statistics being thought of as "lies."
The Stat 2.1X team is investigating what's possible with textual analysis of answers, but I worry that with so many students for whom English is not a native language, we will get into trouble with the machine trying to understand what students are trying to say.
One step at a time ... I'm glad you found the answer interesting. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T18:35:35Z
FirstChildVoteTAG: 2
IndexTAG: 782
TitleTAG: MIDTERM 4B possible solution done?
1. 20/77 = 0.25 * 9= 2.25
2. 25/77 = 0.67 * 9= 6.03
3. 32/77 = 0.41 *9 = 3.69
4. ADD 2.25+6.03+3.69= 11.97
IS 11.97 the new SD?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-16T11:20:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I think there are several mistakes in your derivation. Please take a look at https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/find-sds-combined-group/
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-16T12:03:46Z
FirstChildVoteTAG: 0
FirstChildTAG: will have another chance to do the midterm cause i didnt see it. did i loose this point definitely?
FirstChildUserIdTAG: 1130501
FirstChildUserNameTAG: Datho
FirstChildCreateTimeTAG: 2013-03-16T15:29:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, definitely.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-16T17:01:15Z
SecondChildVoteTAG: 0
IndexTAG: 783
TitleTAG: exercise to calculate r
I have tried to repeat this exercise, and I think that the numbers are incorrect.
Example:
last line 5 6 1,414213562 1,165543035 1,648326767
UserIdTAG: 1134470
UserNameTAG: cpaula
CreateTimeTAG: 2013-03-16T11:12:26Z
VoteTAG: 2
CoursewareTAG: Section 6: Relation between two variables / Lec 6.2: The correlation coefficient: calculation and properties
NumberOfReplyTAG: 2
FirstChildTAG: same happend to me
FirstChildUserIdTAG: 1050999
FirstChildUserNameTAG: Ecdsy
FirstChildCreateTimeTAG: 2013-03-17T22:24:47Z
FirstChildVoteTAG: 0
SecondChildTAG: me too
SecondChildUserIdTAG: 1042769
SecondChildUserNameTAG: sambi
SecondChildCreateTimeTAG: 2013-03-18T20:09:32Z
SecondChildVoteTAG: 0
FirstChildTAG: My standard deviations come out to 1.58 and 2.3 vs 1.41 and 2.06
FirstChildUserIdTAG: 945143
FirstChildUserNameTAG: joddde
FirstChildCreateTimeTAG: 2013-03-18T23:16:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Found that the google spreadsheet stdev function yields the numbers above. Done manually as instructed previously the numbers match the lecture. Uhoh :)
SecondChildUserIdTAG: 945143
SecondChildUserNameTAG: joddde
SecondChildCreateTimeTAG: 2013-03-18T23:20:12Z
SecondChildVoteTAG: 0
SecondChildTAG: OK got it. If using Google spreadsheets it is necessary to use the stdevp function so the calc uses the entire population to find SD. If you use stdev it will do some other kind of estimation without using the whole population of numbers.
SecondChildUserIdTAG: 945143
SecondChildUserNameTAG: joddde
SecondChildCreateTimeTAG: 2013-03-18T23:23:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Even so I still come out with r=.755 which I would round to .76
SecondChildUserIdTAG: 945143
SecondChildUserNameTAG: joddde
SecondChildCreateTimeTAG: 2013-03-18T23:27:53Z
SecondChildVoteTAG: 0
SecondChildTAG: takes n-1 in the denominator...has something to do with degrees of freedom but I don't know what exactly...
SecondChildUserIdTAG: 720154
SecondChildUserNameTAG: LUCALOTTO2012
SecondChildCreateTimeTAG: 2013-03-19T11:34:07Z
SecondChildVoteTAG: 0
SecondChildTAG: I know that you have to calculate the SD like in this course ( as if you had all the population), but in any case, the results are diferente. Only a few decimals, but they are different. Can staff explain me, please? how many decimals I have to anotate to get the correct results?
Thank you!!
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-03-20T15:38:29Z
SecondChildVoteTAG: 0
IndexTAG: 784
TitleTAG: Prof Adhikari - solution for Midterm 4B as per sum of squares
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/find-sds-combined-group/
Is this the correct solution
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-16T10:44:12Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I also made the derivation based on Prof. Adhikari's guidelines and got the same result.
I made some minor changes to your derivation at the link given above. Also, could you please look at the fourth line and change it if you agree with my comment?
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-16T11:43:29Z
FirstChildVoteTAG: 2
SecondChildTAG: Yes I agree with your changes.It was what I wanted to say and added the maths notation below for clarity.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-16T12:38:30Z
SecondChildVoteTAG: 0
SecondChildTAG: I was wondering how to make the bar of the sqrt sign go over all the elements.Thanks for correcting that too. I learnt how to do it seeing your Tex command)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-16T12:40:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, I got just over 11 too. "Mean of squares minus square of mean" is an easy way to work out the variance (square of the SD); we don't stress it so much in Stat 2 because we're trying to focus on the motivation behind the definition of the SD. But for computation, "mean of squares minus square of mean" can be very helpful. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T18:16:30Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-17T03:45:05Z
SecondChildVoteTAG: 0
IndexTAG: 785
TitleTAG: Will the course continue?
Does anybody know something about the starting date of the second part of the Stat2.1x course?
UserIdTAG: 137573
UserNameTAG: bognarl
CreateTimeTAG: 2013-03-16T10:40:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: "after a few weeks after this course" is what information we have.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-16T10:52:15Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks
SecondChildUserIdTAG: 137573
SecondChildUserNameTAG: bognarl
SecondChildCreateTimeTAG: 2013-03-21T05:37:08Z
SecondChildVoteTAG: 0
IndexTAG: 786
TitleTAG: Staff Help
1. If everyone in a class score below 99% (reducaed to to correlation factor)....who is going to score higher percentiles? So, with what accuracy these estimates are made?
2. If midterm score and final scores are related, final scores and midterm scores are related as well...In such case, can we interchange the axes? In which case 75%ile in midterm can score more than 75%ile in final and vice versa? Confusing!
UserIdTAG: 64992
UserNameTAG: srmkrish
CreateTimeTAG: 2013-03-16T10:19:59Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 2
FirstChildTAG: 1. Those getting higher scores on one variable **tend** to get lower scores on the other.
2. Yes - those getting higher midterms will **tend** to get lower scores on the Final.
Those getting higher scores on the Final will **tend** to get lower on the Midterm.
In both cases the same applies - those who score more (or less) than the average will **tend** to score closer to the average on the send variable - that's regression!
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T10:29:41Z
FirstChildVoteTAG: 1
SecondChildTAG: Now I understand why it calls regression!
SecondChildUserIdTAG: 1071309
SecondChildUserNameTAG: _Helena_
SecondChildCreateTimeTAG: 2013-03-19T18:59:58Z
SecondChildVoteTAG: 0
FirstChildTAG: need staff's assistance:
If the midterm score is 58th, the r is still 0.4, is the answer to be a little bit less than 70th for the final score instead of lower than 58th?
FirstChildUserIdTAG: 495031
FirstChildUserNameTAG: karenZ
FirstChildCreateTimeTAG: 2013-03-17T20:39:38Z
FirstChildVoteTAG: 0
SecondChildTAG: No. how could you get a bigger number by multiplying for 0.4 ? Draw a football shaped scatter plot, draw from 70th perccentile point of final score a line vertical to the finals sore axes, and from 58th percentile point of the midterm score a line vertixal to the midterm score axes, find the middle point of the segment filled with data points for both and it will be much clearer. basically, in english, the average midterm score for those who got 70 in the final is 58, while the average final score for those who got 58 in the midterm score is 53
SecondChildUserIdTAG: 1693
SecondChildUserNameTAG: Lo233
SecondChildCreateTimeTAG: 2013-03-18T15:20:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Lo233, your explanation (in english) helped me understand!
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-20T02:54:34Z
SecondChildVoteTAG: 0
IndexTAG: 787
TitleTAG: Different approaches to problems in this course
Wow! Challenging problems last days. See, for example, the problem 4B in the Midterm:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5142f2672af1052700000081
So far I've been following this problem solving strategy:
1. Intuition and conceptual thinking based on the facts presented by our Profs, plus a bit of arithmetic or very elementary algebra.
2. If step 1 fails, more complex algebra (see algebraic statements for the the problem 4B in the above linked post as an example of what kind of algebra I'm thinking of). This is not expected to use in the course.
3. If step 2 fails or the algebra becomes extremely complex or convoluted, computer simulation. Also, not expected to use in the course.
My assumption is that this course encourages **sticking** to the step 1, and I'm refraining from resorting to algebra, it goes without saying to computer simulations, before submitting my solutions.
What do you think about? Which strategy are you using?
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-16T10:10:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I am using the intiutive method first and then reconfirming it with mathematics .Frankly every time I have gone against the intuitive method -I have made a mistake due to a fault in some maths;)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-16T12:35:18Z
FirstChildVoteTAG: 0
IndexTAG: 788
TitleTAG: Next lectures
When will next lectures following midterm would be uploaded?
UserIdTAG: 965773
UserNameTAG: AnchalGupta
CreateTimeTAG: 2013-03-16T10:02:05Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They are already online (week 4)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T10:25:37Z
FirstChildVoteTAG: 0
IndexTAG: 789
TitleTAG: excercise set 2
please check it and send feed back to me. thank you.
UserIdTAG: 1265218
UserNameTAG: hkdshah
CreateTimeTAG: 2013-03-16T09:46:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Why?
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T09:59:41Z
FirstChildVoteTAG: 0
FirstChildTAG: The deadline for this Exercise set passed some time ago.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T10:32:21Z
FirstChildVoteTAG: 0
IndexTAG: 790
TitleTAG: Midterm exam
Hello. I missed deadline for midterm exam. I had some problem with internet and time..
what I should to do now?
UserIdTAG: 336649
UserNameTAG: Roksolana
CreateTimeTAG: 2013-03-16T09:29:08Z
VoteTAG: 0
CoursewareTAG: Section 7b: Regression (Lec 7.3 - 7.4) / Lec 7.4: Equation of the regression line
NumberOfReplyTAG: 1
FirstChildTAG: Forget about it and keep on going. The point is surely to learn statistics rather than just collect a 'completion' certificate?
The Midterm accounts for a maximum of 20% of the overall mark. The 'Pass' mark is only 35%. It isn't necessary to pass each element. It is quite possible to pass without taking either examination if you average over 70% on the Graded Exercises.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T09:37:45Z
FirstChildVoteTAG: 6
IndexTAG: 791
TitleTAG: Great problem
Dear professors,
You really make me laugh with the last problem in set 11 - it is so nice and human and I am really happy to be one of your students.
Thank you very much for all the efforts and for this course
Best regards from Serbia, Europe
UserIdTAG: 1263121
UserNameTAG: Hadzija
CreateTimeTAG: 2013-03-16T09:14:53Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I agree.
Thank you very much for all.
(from Italy).
FirstChildUserIdTAG: 1210009
FirstChildUserNameTAG: GIAN66
FirstChildCreateTimeTAG: 2013-03-16T09:47:14Z
FirstChildVoteTAG: 0
IndexTAG: 792
TitleTAG: 2
A nummer... Draw a graph and you figur it out
UserIdTAG: 1064023
UserNameTAG: Ronald68
CreateTimeTAG: 2013-03-16T08:52:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 0
IndexTAG: 793
TitleTAG: Q2A 23mm is 23inches,0.45mm is 0.45inches?
As 1inch is 2.54cm,I could not get the answer. Usually we,Japanese,never use inch, therefore measure by inch is terrible for me.
UserIdTAG: 200548
UserNameTAG: kame
CreateTimeTAG: 2013-03-16T08:15:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 3
FirstChildTAG: No conversions were needed. Just work in the units as they were given.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T08:50:05Z
FirstChildVoteTAG: 2
FirstChildTAG: It doesn't matter what the unit is - the question could have been expressed as mm, metres, yards or furlongs - the answer still works out the same and is expressed in the units given.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T09:53:30Z
FirstChildVoteTAG: 3
FirstChildTAG: I am stupid. I am learning correlation coefficient r in this week and professor Ani Adhikari explained about the units in which they were measured that multiplication does nothing to standard units. Thank you Ialotsb,PauIJM.
FirstChildUserIdTAG: 200548
FirstChildUserNameTAG: kame
FirstChildCreateTimeTAG: 2013-03-17T08:49:26Z
FirstChildVoteTAG: 0
SecondChildTAG: what about 2b?do we have to convert the units?
SecondChildUserIdTAG: 1107430
SecondChildUserNameTAG: Pintor
SecondChildCreateTimeTAG: 2013-03-17T09:02:01Z
SecondChildVoteTAG: 0
IndexTAG: 794
TitleTAG: stastistics 2.2.x
will be another course of statistics after this??
UserIdTAG: 1147076
UserNameTAG: giomicho
CreateTimeTAG: 2013-03-16T08:09:48Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The question has been asked many times and has been answered by the Professor. There will be two further courses, Stat2.2X and 2.3X each following on shortly after the end of the previous course.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T09:51:58Z
FirstChildVoteTAG: 0
IndexTAG: 795
TitleTAG: Please tell us what we have to write down in problem 2
Maybe negative/positive or sloped up/sloped down or maybe the r value.
Which one?
UserIdTAG: 176020
UserNameTAG: JMER
CreateTimeTAG: 2013-03-16T07:53:53Z
VoteTAG: 6
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: ok, finally I tried one option. The answer is r value.
FirstChildUserIdTAG: 176020
FirstChildUserNameTAG: JMER
FirstChildCreateTimeTAG: 2013-03-16T07:58:42Z
FirstChildVoteTAG: 6
SecondChildTAG: This question should be rephrased to make it clear what they're looking for.
SecondChildUserIdTAG: 1224506
SecondChildUserNameTAG: debradley
SecondChildCreateTimeTAG: 2013-03-16T14:03:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Does it mean a value between -1 and 1?
SecondChildUserIdTAG: 902345
SecondChildUserNameTAG: phidesigner
SecondChildCreateTimeTAG: 2013-03-16T15:02:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok, yes. As r can only have values **between** -1 and +1, what the question is asking for, is to **numerically** determine the strength of the correlation (if at all) and determine if the association is positive or negative. Hope this helps.
SecondChildUserIdTAG: 902345
SecondChildUserNameTAG: phidesigner
SecondChildCreateTimeTAG: 2013-03-16T15:21:33Z
SecondChildVoteTAG: 0
SecondChildTAG: The first time I answered this question, I enter the words positive or negative. Then the program told me that it doesn't accept word for number. Then I enter the value and it accepted. So it has to be a number.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-03-16T17:38:47Z
SecondChildVoteTAG: 0
SecondChildTAG: R is the correlation coefficient. They ask for the correlation. Not the same thing.
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-03-19T00:55:10Z
SecondChildVoteTAG: 0
FirstChildTAG: I am also not sure what to put here. It seems to be a number, though a number representing what, I am not sure. The lecture explains what "association" and "correlation coefficient" are, but not "correlation" (as different from "association").
I assumed they were using correlation as a synonym for association, but "negative" and "positive" are not accepted, and I don't believe you can describe association using a number.
The only thing I am sure of is that they are not asking for "r" -- if they wanted that, they would have said "correlation coefficient" or "r".
FirstChildUserIdTAG: 1055945
FirstChildUserNameTAG: rebecca417
FirstChildCreateTimeTAG: 2013-03-19T00:58:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Correlation was defined in the lectures as the "degree" of linear association/relation between the 2 variables. It's measured by the correlation coefficient r, which is a number between -1 and 1.
A correlation (coefficient) of -1 means the data plots as a perfectly straight line with a negative slope, +1 a perfectly straight line with a positive slope. Numbers in between mean the data does not plot as a perfect line, but gets close as r approaches +/-1.
Q2 is asking: what is r?
SecondChildUserIdTAG: 315634
SecondChildUserNameTAG: FranCie
SecondChildCreateTimeTAG: 2013-03-19T10:14:18Z
SecondChildVoteTAG: 0
IndexTAG: 796
TitleTAG: Could someone elaborate the explanation of answer's 1B
> The the students on the 70th percentile of final scores are on a
> vertical strip, the center of which is the 58th percentile of the
> midterms. The students with this score are a horizontal strip whose
> center is certainly not at the 70th percentile. It’s quite a bit less.
What are the vertical and horizontal strips?
UserIdTAG: 158656
UserNameTAG: chalupa
CreateTimeTAG: 2013-03-16T07:05:21Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 2
FirstChildTAG: "The students with this score are a horizontal strip whose center is *certainly not* at the 70th percentile. It’s quite a bit less."
Can someone prove the "certainly not" part? Thanks!
FirstChildUserIdTAG: 158656
FirstChildUserNameTAG: chalupa
FirstChildCreateTimeTAG: 2013-03-16T08:50:02Z
FirstChildVoteTAG: 0
SecondChildTAG: See the video 7.3 Galton demonstrates this. Linear regression tends towards the mean (Galton's rather less kind phrase was 'regression towards mediocrity').
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T09:56:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Paul
SecondChildUserIdTAG: 158656
SecondChildUserNameTAG: chalupa
SecondChildCreateTimeTAG: 2013-03-16T11:21:38Z
SecondChildVoteTAG: 0
FirstChildTAG: since the we assume normal distribution a student who is in the 58 percentile of the midterm is certain SD from the mean ( you can use the applet to find how much) than in order to find his percentile at the final you should multiply by the correlation coefficent. now you get how many SD from the mean he is estimated to achieve in the final . you need to find the percentile meaning the percentage of students who scored less than the value you got after multiplication, and by using the applet find the percentile.
since the correlation coeficient is less than one the percentage is lower than the precentage he scored in the midterm.
FirstChildUserIdTAG: 1240022
FirstChildUserNameTAG: Moshiko
FirstChildCreateTimeTAG: 2013-03-16T17:40:01Z
FirstChildVoteTAG: 0
IndexTAG: 797
TitleTAG: problem 3
positive association is when
x increase -> y increase
negative association is when
x increase -> y decrease
so please explain your answer to q3
as i believe that is not the "best" answer
unless i misunderstood it
UserIdTAG: 1047522
UserNameTAG: daveBen
CreateTimeTAG: 2013-03-16T06:54:37Z
VoteTAG: 6
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 4
FirstChildTAG: Neither did I understand it. Considering the fact individuals are of concern and not couples, well, this leaves only one possible answer which is reported wrong.
FirstChildUserIdTAG: 313892
FirstChildUserNameTAG: doronko4
FirstChildCreateTimeTAG: 2013-03-16T11:22:49Z
FirstChildVoteTAG: 2
FirstChildTAG: Check the trend- think of pairs and plot them and you will get an idea if you visualize the plot as you plot newly married versus older couples even when all wives are younger than their husbands.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-16T12:42:23Z
FirstChildVoteTAG: 6
SecondChildTAG: I still don't understand. Where did you get the information about the trend?
SecondChildUserIdTAG: 177806
SecondChildUserNameTAG: Judi
SecondChildCreateTimeTAG: 2013-03-16T23:50:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Prasannasimha and PauJM... you guys are extremely helpful..! Your explanations really help:) Keep up the good work.
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-17T17:57:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Your advice for plotting the problem was great. Thanks!
SecondChildUserIdTAG: 743246
SecondChildUserNameTAG: andresace
SecondChildCreateTimeTAG: 2013-03-20T03:39:28Z
SecondChildVoteTAG: 0
FirstChildTAG: The ques. is all the couples in the world. Relationship is Age of Husband Vs Age of Wife. How do you say trend as pair?
Relationship is husband get older wife is older too but little younger. I'm confused here.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-17T02:20:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Trend of the pairs not one of each- we are comparing pairs (the couples) not individual husband to individual wife.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-17T04:04:14Z
SecondChildVoteTAG: 0
SecondChildTAG: The questions is "Which of the following do you think is true regarding the association between wife’s age and husband’s age?" there is NOTHING about pairs and the trend! If you were looking for trend of pairs then you have ask about it and not about color of the sky. Return me my lost 2 points please.
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-17T08:21:16Z
SecondChildVoteTAG: 0
FirstChildTAG: The question is not asking about particular couple it basically asks 'if a man is old, is his wife likely to be old or young?'. Given a man's age (and no other information), what would you estimate his wife's age to be? **On average**, we would expect the wife to be within a few years of the husband in most cultures (remembering this is a worldwide survey).
Think about a couple of examples; if a man is twenty, on average how old is his wife likely to be? I'd guess the **average** is probably somewhere around the low twenties (the exact figure doesn't matter).
Now take another example; if a man is seventy, how old is his wife likely to be? At a guess, I'd think that the **average** is probably a little below seventy (again the exact figure isn't important).
Now, think of a chart with just those two points. Draw a line between them (we'll assume it's linear for the moment). Which way is it sloping?
Just to check, try a point somewhere in the middle. Say a man is 50 years old, how old do you think his wife is likely to be on **average**? Say, somewhere around 50? Plot that point. Is it close to the line?
Three points don't make a scatter plot (especially when you just make up the results) but it should give you the idea of where the question is going if you don't see it intuitively.
Of course, these **averages** don't stop individual couples having widely varying ages - my own wife is twelve years younger than me, and we have all seen extreme examples in the media; "So what first attracted you Miss X to this 90 year old billionaire?"
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T10:17:39Z
FirstChildVoteTAG: 6
SecondChildTAG: Thanks PaulJM.. Beautiful explanation.. And hey, just outta curiosity, if you were included in this chart, wouldn't your point be an outlier?? ;)
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-03-17T14:42:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Prasannasimha and PauJM... you guys are extremely helpful..! Your explanations really help:) Keep up the good work.
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-17T17:57:54Z
SecondChildVoteTAG: 0
SecondChildTAG: > if you were included in this chart, wouldn't your point be an outlier?
Better not let my wife hear you describe her as an outlier!
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-17T19:52:51Z
SecondChildVoteTAG: 0
SecondChildTAG: > "So what first attracted you Miss X to this 90 year old billionaire?"
I can assure it that it was "wuv, twoo wuv". Nothing to do with the money.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-17T21:43:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot, I just couldn't figure out why my answer was wrong. :)
SecondChildUserIdTAG: 1293753
SecondChildUserNameTAG: AideeLu
SecondChildCreateTimeTAG: 2013-03-17T23:48:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Don't think too much about it...I stopped thinking and got it right!
Just look around you and compare how much "old"/"young" couples to how much approx same age couples you get.
SecondChildUserIdTAG: 720154
SecondChildUserNameTAG: LUCALOTTO2012
SecondChildCreateTimeTAG: 2013-03-19T13:39:17Z
SecondChildVoteTAG: 0
SecondChildTAG: The sign of the association is obvious, and from reading this thread I think most people didn't have a problem with that part. My objection to this question (and also question 1a to a smaller degree) is because I believe there is ambiguous reasoning in the choice descriptions. You're essentially asked to pick 'the best answer' between two correct answers.
SecondChildUserIdTAG: 517007
SecondChildUserNameTAG: CezarSerban
SecondChildCreateTimeTAG: 2013-03-20T02:29:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot!
SecondChildUserIdTAG: 997677
SecondChildUserNameTAG: meneva
SecondChildCreateTimeTAG: 2013-03-20T06:35:16Z
SecondChildVoteTAG: 0
IndexTAG: 798
TitleTAG: Problem 2 a and 2 b section 6.1
There is no way to answer to these questions it shows an error when typing letters!
UserIdTAG: 1281597
UserNameTAG: Luisns10
CreateTimeTAG: 2013-03-16T05:07:46Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you can only enter a number but others have got the answer correct, does this not suggest something about the answer?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T10:08:01Z
FirstChildVoteTAG: 1
SecondChildTAG: Luisns10 ,it seems like typing LETTERS will not give you correct ans.
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-16T10:56:14Z
SecondChildVoteTAG: 0
IndexTAG: 799
TitleTAG: Problem 2
What should we fill in the blank?????
Should we write " positve or negative"
Or " slope up or slope down" ??
Or "> 0 or < 0"
I know the correct answer but i dont know which expression i have to write in the blank
UserIdTAG: 1288142
UserNameTAG: aldawlah
CreateTimeTAG: 2013-03-16T05:06:01Z
VoteTAG: 1
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: Fill in the "r"
FirstChildUserIdTAG: 183861
FirstChildUserNameTAG: Xelio
FirstChildCreateTimeTAG: 2013-03-16T05:10:45Z
FirstChildVoteTAG: 0
SecondChildTAG: what u mean feel in the r? above the line?
SecondChildUserIdTAG: 1281597
SecondChildUserNameTAG: Luisns10
SecondChildCreateTimeTAG: 2013-03-16T05:16:46Z
SecondChildVoteTAG: 0
SecondChildTAG: You can calculate the rbased on the data given
SecondChildUserIdTAG: 1240022
SecondChildUserNameTAG: Moshiko
SecondChildCreateTimeTAG: 2013-03-16T10:34:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Do you mean 'value of r'? Or '+r' or '-r'?
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-17T12:07:55Z
SecondChildVoteTAG: 0
SecondChildTAG: yes value of r
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-17T23:48:25Z
SecondChildVoteTAG: 0
FirstChildTAG: You mean i should calculate "r"
Okay should i predict how many right Qs and wrong Qs.
I tried like the following
10 right - 0 wrong
5 right - 5 wrong
3 right - 7 wrong
0 right - 10 wrong
I calculate the mean and SD and found r= -0.63
But the answer was wrong ?!!!!!!
FirstChildUserIdTAG: 1288142
FirstChildUserNameTAG: aldawlah
FirstChildCreateTimeTAG: 2013-03-16T05:24:15Z
FirstChildVoteTAG: 0
SecondChildTAG: don't calculate the "r" just try to draw a scattered diagram .Write (Right,Wrong) (10,0) way .
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-03-16T05:50:52Z
SecondChildVoteTAG: 0
SecondChildTAG: you should try every case >>
10 right - 0 wrong
9 right - 1 wrong
8 right - 2 wrong
7 right - 3 wrong
... and so on. You should get the correct answer.
Note that this is one of possible solutions.
SecondChildUserIdTAG: 1120616
SecondChildUserNameTAG: Theerawat
SecondChildCreateTimeTAG: 2013-03-16T07:42:10Z
SecondChildVoteTAG: 0
SecondChildTAG: i got r= -0.996 and it's wrong fro Problem 2A,what have I done wrong?
SecondChildUserIdTAG: 974621
SecondChildUserNameTAG: jack1990
SecondChildCreateTimeTAG: 2013-03-16T19:29:58Z
SecondChildVoteTAG: 0
SecondChildTAG: you cannot count r from your own numbers ... each of us can have diff.numbers, so diff. r
SecondChildUserIdTAG: 1137412
SecondChildUserNameTAG: Lukes89
SecondChildCreateTimeTAG: 2013-03-16T21:29:54Z
SecondChildVoteTAG: 0
SecondChildTAG: you can draw the plot and use ur imagination
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-17T23:49:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I got it wrong, :-(
SecondChildUserIdTAG: 569767
SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-03-19T02:33:04Z
SecondChildVoteTAG: 0
FirstChildTAG: If there are 4 right answers, how many wrong answers will there be? Is there any scope for variation?
Remember r is a measure of correlation - how closely you can estimate one variable based on another.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T10:10:43Z
FirstChildVoteTAG: 0
SecondChildTAG: Since there are 10 questions all together than for each case of right answers you can caculate how many are wrong
SecondChildUserIdTAG: 1240022
SecondChildUserNameTAG: Moshiko
SecondChildCreateTimeTAG: 2013-03-16T10:38:06Z
SecondChildVoteTAG: 0
IndexTAG: 800
TitleTAG: Problem 2A and 2B doesn't accept NA
Problem 2A and 2B says,
A quiz consists of 10 multiple choice questions. Each question is marked either “right” or “wrong.” Each right answer gets 5 points, and 1 point is taken off for each wrong answer.
In what follows, fill in the blank; **if you think there is not enough information to answer the question, enter NA.**
However, it doesn't accept NA
It says invalid , not recognized as a number
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-03-16T04:59:42Z
VoteTAG: 18
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 3
FirstChildTAG: I just experienced the same problem. There is no way to answer both questions because the website is designed to type numbers not letters. So how could we answer this questions?? They worth 6 points quite a bit important for the total grade.
FirstChildUserIdTAG: 1281597
FirstChildUserNameTAG: Luisns10
FirstChildCreateTimeTAG: 2013-03-16T05:06:32Z
FirstChildVoteTAG: 3
SecondChildTAG: Yes Indeed! Even Problem 3 is argumentative. I have feeling this exercise set will be my worst one.
SecondChildUserIdTAG: 786512
SecondChildUserNameTAG: shoaibkhanz
SecondChildCreateTimeTAG: 2013-03-16T05:21:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeah I tried to answer that one analyzing all possible situations but I didn't get the mark so I don't have no clue whats the correct answer for that one. Also without getting the points in problem 2 my grade is really low as well. I hope the staff can fix that or erase the questions if is not possible to fix
SecondChildUserIdTAG: 1281597
SecondChildUserNameTAG: Luisns10
SecondChildCreateTimeTAG: 2013-03-16T05:25:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't know what to do with "NA" problem too.
SecondChildUserIdTAG: 975121
SecondChildUserNameTAG: SvetlanaZer
SecondChildCreateTimeTAG: 2013-03-16T14:54:04Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't know what to do with "NA" problem too.
SecondChildUserIdTAG: 1041097
SecondChildUserNameTAG: JUANADORIS2013
SecondChildCreateTimeTAG: 2013-03-17T23:10:26Z
SecondChildVoteTAG: 0
SecondChildTAG: just try to find a valid answer aother than NA
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-17T23:38:30Z
SecondChildVoteTAG: 0
SecondChildTAG: It doesn't accept "positive" or "negative" either.
What does it want from us?!
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-03-19T00:53:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi, I was confused by this at first, as well, mainly because I was interpreting "correlation" to mean association. The first video in Chapter 7 'Correlation Coefficient' helped me with this question. Hopefully it helps you, too.
SecondChildUserIdTAG: 972760
SecondChildUserNameTAG: missyl
SecondChildCreateTimeTAG: 2013-03-19T15:50:53Z
SecondChildVoteTAG: 0
SecondChildTAG: It is possible to get the correct answer on these problems, I have done it. However I am not sure that these problems are very nice to understand the concept of correlation. There is more a logic to be careful to than a deep understanding of what correlation is and how it works. Just my opinion though.
SecondChildUserIdTAG: 1178410
SecondChildUserNameTAG: Pti_Lu
SecondChildCreateTimeTAG: 2013-03-19T16:08:23Z
SecondChildVoteTAG: 0
SecondChildTAG: answer is not NA friends so don't write NA
SecondChildUserIdTAG: 1078818
SecondChildUserNameTAG: Jamili
SecondChildCreateTimeTAG: 2013-03-20T16:04:12Z
SecondChildVoteTAG: 0
SecondChildTAG: It's simple. Think putting scores and right numbers together in the table. Plot them as a scatter plot. Look at it and the answer is clear enough. No calculations necessary
SecondChildUserIdTAG: 131073
SecondChildUserNameTAG: russell2030
SecondChildCreateTimeTAG: 2013-03-20T17:36:49Z
SecondChildVoteTAG: 0
FirstChildTAG: If the field only accepts a number, maybe this suggests that NA isn't the correct answer?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T07:06:30Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes
SecondChildUserIdTAG: 1120616
SecondChildUserNameTAG: Theerawat
SecondChildCreateTimeTAG: 2013-03-16T07:43:50Z
SecondChildVoteTAG: 0
SecondChildTAG: No, that's wrong way of interpreting. If NA is possible answer as the question suggests, there should be provision to enter NA and the answer box should accept it. And if NA is wrong, then it should mark as wrong.
SecondChildUserIdTAG: 267922
SecondChildUserNameTAG: Kamesh2023
SecondChildCreateTimeTAG: 2013-03-17T04:17:41Z
SecondChildVoteTAG: 0
SecondChildTAG: You have to think about positive or negative association first and then put +/- in the answer.
SecondChildUserIdTAG: 186443
SecondChildUserNameTAG: drmoesandar
SecondChildCreateTimeTAG: 2013-03-17T10:14:04Z
SecondChildVoteTAG: 0
SecondChildTAG: If i plot right answers on the x-axis, for every correct answer(5 units) to a particular question, the y-axis(wrong) is zero and for every wrong(1 unit on the y-axis) the corresponding x-axis is zero. It's difficult to establish a relation! :)
SecondChildUserIdTAG: 117419
SecondChildUserNameTAG: mcpyngrope
SecondChildCreateTimeTAG: 2013-03-19T09:26:13Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with Kamesh2013. If they suggest using NA for an answer, then the field should be designed to allow input such as NA. This is so badly organized...
SecondChildUserIdTAG: 1264964
SecondChildUserNameTAG: ChaosCreator
SecondChildCreateTimeTAG: 2013-03-20T17:49:37Z
SecondChildVoteTAG: 0
FirstChildTAG: The point is you can have 2 different values for r depending on whether you accept negative scores or not (The values for r are pretty close to eachother but still.).
I don't like ambiguity.
FirstChildUserIdTAG: 372474
FirstChildUserNameTAG: JeroenPinoy
FirstChildCreateTimeTAG: 2013-03-16T13:38:24Z
FirstChildVoteTAG: 3
SecondChildTAG: The scoring scheme is exactly as described. So for example if the student gets all the questions wrong, his/her score will be negative. There is nothing that indicates otherwise. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-16T18:44:45Z
SecondChildVoteTAG: 0
SecondChildTAG: > you can have 2 different values for r depending on whether you accept negative scores or not
No you can't...
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T22:36:22Z
SecondChildVoteTAG: 0
SecondChildTAG: You have 10 questions. You get X correct, and 10 - X wrong. So your possible answers range from 10 correct, to 10 wrong.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-16T23:56:24Z
SecondChildVoteTAG: 0
SecondChildTAG: what if the question is unanswered?
SecondChildUserIdTAG: 1002689
SecondChildUserNameTAG: Lapogadnan
SecondChildCreateTimeTAG: 2013-03-17T12:49:45Z
SecondChildVoteTAG: 0
SecondChildTAG: > what if the question is unanswered?
As the case is not mentioned in the question then it is reasonable to ignore it, besides which the question says:
> A quiz consists of 10 multiple choice questions. Each question is marked either “right” or “wrong.”
So it can't be 'unanswered' - it's either right or wrong!
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-17T19:59:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Easier than you think
SecondChildUserIdTAG: 131073
SecondChildUserNameTAG: russell2030
SecondChildCreateTimeTAG: 2013-03-20T17:34:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Negative points for wrong answers only make sense if you can leave the question unanswered. They are meant to ensure that the students won't pick a random answer if they have no idea which one is correct, as the risk of getting negative points is too high.
SecondChildUserIdTAG: 517550
SecondChildUserNameTAG: Ewa_G
SecondChildCreateTimeTAG: 2013-03-20T22:08:18Z
SecondChildVoteTAG: 0
IndexTAG: 801
TitleTAG: Requirement of link to applet
Since the applet is required in many calculations there should be a link to it available on all pages.
UserIdTAG: 107587
UserNameTAG: akardeepak
CreateTimeTAG: 2013-03-16T04:57:21Z
VoteTAG: 9
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 5
FirstChildTAG: check the "wiki" on your dashboard ans scroll down to the last item(link)
FirstChildUserIdTAG: 799816
FirstChildUserNameTAG: JAMINx
FirstChildCreateTimeTAG: 2013-03-16T13:17:37Z
FirstChildVoteTAG: 0
SecondChildTAG: .
SecondChildUserIdTAG: 974077
SecondChildUserNameTAG: ransanjeev
SecondChildCreateTimeTAG: 2013-03-17T05:35:58Z
SecondChildVoteTAG: 0
SecondChildTAG: .
SecondChildUserIdTAG: 974077
SecondChildUserNameTAG: ransanjeev
SecondChildCreateTimeTAG: 2013-03-17T05:36:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Noticing that it's required frequently, you may wish to bookmark it.
SecondChildUserIdTAG: 1224506
SecondChildUserNameTAG: debradley
SecondChildCreateTimeTAG: 2013-03-17T19:12:20Z
SecondChildVoteTAG: 0
FirstChildTAG: Maybe you should put the link into your browser bookmarks.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T23:56:59Z
FirstChildVoteTAG: 3
FirstChildTAG: The applet
http://www.mathsisfun.com/data/standard-normal-distribution-table.html
FirstChildUserIdTAG: 200548
FirstChildUserNameTAG: kame
FirstChildCreateTimeTAG: 2013-03-17T08:22:42Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks a million for this link kame,I've failed most of the ex requiring applet bc i wasn't able to upload it using the 'java'link. Thanks to your link,i can do my applet requiring ex now.
SecondChildUserIdTAG: 715356
SecondChildUserNameTAG: Janefrances
SecondChildCreateTimeTAG: 2013-03-20T01:26:54Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, we know all these tricks. But why dont give a link?? Consider the hints about rounding numbers: THey are repeated many many times, so the url of the applet could be repeated for convenience, too.
FirstChildUserIdTAG: 1174304
FirstChildUserNameTAG: ThomasHGMann
FirstChildCreateTimeTAG: 2013-03-17T18:12:02Z
FirstChildVoteTAG: 2
FirstChildTAG: I can't agree more, it took me quite some time to find the link, now I bookmarked it for future use.
It would be very helpful to add in somewhere the students can access it easier every time.
FirstChildUserIdTAG: 495031
FirstChildUserNameTAG: karenZ
FirstChildCreateTimeTAG: 2013-03-17T20:33:26Z
FirstChildVoteTAG: 1
IndexTAG: 802
TitleTAG: video 6.1-6.3 ...
we're talking "Statistics 21 - Lecture 6" right?
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-03-16T04:08:15Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 4
FirstChildTAG: No, lectures 6.1 - 6.3 in the Courseware section.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T04:12:24Z
FirstChildVoteTAG: 1
FirstChildTAG: Not sure what you are asking? There are 4 videos in Section 6 (1 intro plus 3 lectures)
Wait, now I see what you mean. "Lecture" refers to Courseware videos. "Chapter" refers to the Sticigui textbook. So Prof A is suggesting we review one before the other (or something else - this confused me; I just went thru both completely to cover all bases).
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T04:12:29Z
FirstChildVoteTAG: 1
SecondChildTAG: Where do you access these videos, as with the earlier sections they gave the links to sections of video-ed lectures whereas I can't see any links in this new section, and thanks for trying to explain, mark
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T04:20:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeah, the instructions for that practice section for exercise 9 are written very confusingly. Someone earlier today posted a convenient link for the online text (which has Prof. Stark's videos embedded within it). I will try to find it for you. I then bookmarked it, and you can easily navigate to the chapters/videos/exercises that are referenced in the confusing instructions.
Back in a minute ...
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-16T04:28:11Z
SecondChildVoteTAG: 0
SecondChildTAG: You have me very confused Mark. From my understanding of the course, I'm new so can go only on what I've read and explored, the lectures are in the Courseware section. So 6.1-6.3 are on the page:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/61842796b3b14c94823269e6fa001439/3011a429e940413e846a7190cd964a0e/
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-16T04:29:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks MOC
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T04:29:33Z
SecondChildVoteTAG: 0
SecondChildTAG: My problem is, are the video lecture segments 6-1 to 6-3 found in Ch 6?
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T04:31:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, the first # refers to the Chapter, so 6-1 will go with Ch. 6.
I am having trouble linking stuff so do this: click on the magnifying glass next to "show all discussions". Enter search string "Text Book". The post with the link is about the 3rd post from the top.
Ok, I will try to link here:
[http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm][1]
[1]: http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-16T04:38:59Z
SecondChildVoteTAG: 0
SecondChildTAG: @ lalotsb - Welcome! I'm not all that new, yet still confused anyway, and have a gift for adding to the confusion. You are correct about 6.1-6.3 being in Courseware, and *not* in the SticiGui. As mjc shared more here about what they were after, it sounded like mjc also needed the online text, which is referenced in the practice set 9. (Sorry mjc to be talking about you in the third person like this ...)
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-16T04:46:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks MOC very good of you and I don't mind who(m?) talks about me, too old to worry. That link https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/61842796b3b14c94823269e6fa001439/3011a429e940413e846a7190cd964a0e/
that's Dr A talking for 4'28" and nothing else, right?
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T04:57:38Z
SecondChildVoteTAG: 0
SecondChildTAG: It's confusing to me, at least, its 'video 6-1 to 6-3' but it's from lecture 4 and found in chapter 5, isn't that confusing to others?
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T05:10:45Z
SecondChildVoteTAG: 0
SecondChildTAG: > that's Dr A talking for 4'28" and nothing else, right?
No. There are 3 lectures and the intro. Look at the film strip across the top of the video. It's just like all the other lectures from previous weeks.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-16T05:40:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks lalotsb, that's it, didn't realise they were there. I wish Prof Stark would share whatever he's on to Prof A. Thanks again, I'll go back and watch all those I've missed sofar, Mark
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T08:27:34Z
SecondChildVoteTAG: 0
FirstChildTAG: And all three chapters starting with "Chapter 5, Multivariate Data and Scatterplots."?
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
FirstChildCreateTimeTAG: 2013-03-16T04:21:53Z
FirstChildVoteTAG: 0
SecondChildTAG:
[http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm][1]
[1]: http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm
Then click on the chapter you need. Bookmark this, because we go there a lot. The video lectures with Prof. Stark, along with the text, give a different and more technical view of what we learn from Prof. A in Courseware.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-16T04:48:09Z
SecondChildVoteTAG: 0
FirstChildTAG: What the comments are trying to make clear is that the lectures here don't map exactly to the sequence the same information is presented in the textbook.
It suggests that there are two ways to approach this, either watch the lectures here then skim through the parts of the textbook mentioned and do the listed exercises (remember, this is supposed to be about Practice Exercises) - this is the way that most people will probably approach the work. The alternative (particularly if you haven't been following the lectures - as some don't) is to read the indicated parts of the textbook, then skim through the video lectures and then tackle the exercises in the book.
Whenever 'lectures' are mentioned they **always** refer to the videos here on the edX site, **never** to the video sequences in the book. The book provides supporting material but nothing there is *required* (other than to access some of the applets).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T10:05:32Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T11:16:58Z
SecondChildVoteTAG: 0
IndexTAG: 803
TitleTAG: STAFF Part of midterm not saved
I completed the midterm in two parts. I completed up to question 4A and then went back and completed the remainder of the exam. I'm not sure why but my remaining answers didn't save on the last three questions. I have never had this issue in any prior exercise sets, but I also never walked away and came back to them either. I had one correct answer and two wrong answers. Is there any way to correct this? If not, I understand, luckily I still passed with these questions unanswered.
UserIdTAG: 1061881
UserNameTAG: kristen1trigen
CreateTimeTAG: 2013-03-16T02:27:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Some addtional info: I completed the beginning of the test on a laptop and completed the last 3 questions on an iPad. A glitch there maybe?
FirstChildUserIdTAG: 1061881
FirstChildUserNameTAG: kristen1trigen
FirstChildCreateTimeTAG: 2013-03-16T02:30:18Z
FirstChildVoteTAG: 0
FirstChildTAG: I entered an answer for 3B which, when I checked gave me the Green check mark. But exam now says I did not answer that question. I thought at first it was because I used four decimal places but I see six are allowed. I had .8094. That should have been correct. That irritates me when I do that work and either I or the software mess up.
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-03-16T02:44:13Z
FirstChildVoteTAG: 0
IndexTAG: 804
TitleTAG: Midterm Question 2b
I don't get in 2b how to assign percentages to each number in the intervals. Shouldn't the problem be thought of in this way:
7% watched 0 hours of TV, 14% watched 1 or fewer hours, 21% watched 2 or fewer hours, 28% watched 3 or fewer hours. Now here's where I'm not sure - when you go from 3 hours to 4 hours. Do you add 9% to get 37% watched 4 or fewer hours? If you keep doing it in this way, you eventually get to 77.5% watch 12 or fewer hours, 79% watch 13 or fewer hours, and 80.5% watch 14 or fewer hours. So the answer should be between 13 and 14 hours, not the 14.67 hours.
UserIdTAG: 1231552
UserNameTAG: Albertson
CreateTimeTAG: 2013-03-16T02:23:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I may be misunderstanding your initial logic, so I will just say how I figured the cumulative percentages.
0-4 hours has 28% so the cumulative is 28%
4-8 hours has 36% so the cumulative is 64%
8-12 hours has 12% so the cumulative is 76%
12-20 hours has 12% so the cumulative is 88%
20-28 hours has 12% so the cumulative is 100%
We are looking for the 80th percentile, so we know it is in the 4th bin.
We need another 4% of that bin, since we have 76% from the 3rd bin.
So 12 + ( (80-76)/12) * (20 - 12)) = 14.67
Your initial logic is a off because there is no "zero interval" as you seem to be thinking. The zero hours are binned with the whole 0-4 hour interval, as pictured in 2a.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-16T03:51:41Z
FirstChildVoteTAG: 1
SecondChildTAG: I guess I assumed hours watching tv were in whole numbers, so some people had 0 hours of tv, some had 1 hour, etc.
Maybe I'm not understanding the difference between discreet and continuous values or something. Thanks.
SecondChildUserIdTAG: 1231552
SecondChildUserNameTAG: Albertson
SecondChildCreateTimeTAG: 2013-03-16T13:48:53Z
SecondChildVoteTAG: 0
SecondChildTAG: The key is the assumption of uniformity within intervals, stated in the problem. That means the data can be treated as continuous for the purposes of estimation. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-16T19:27:50Z
SecondChildVoteTAG: 0
IndexTAG: 805
TitleTAG: Estimate midterm from final (66.31% to x??)
Reversing the process, 66.31% is 0.420938 in standard units. Multiplying by r, 0.5, I get 0.210469 standard units. That converts into a percentage of 58.33%.
I must have miss understood. What I thought was that we multiply by r when estimating from x to y, and vice versa. Of course when I multiply by the inverse of 0.5 I do arrive at the correct 80% figure for the midterm. Any thoughts on this?
UserIdTAG: 878440
UserNameTAG: rosewoodbay
CreateTimeTAG: 2013-03-16T02:15:22Z
VoteTAG: 1
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 2
FirstChildTAG: The problem is that the property of the oblique ellipse is such that when you project your values from one angle and the other the mdipoints are different.It is like the shadow of the sun is not the same at different points of time because the sun is incident on your head despite the same head.The projected area of your shadow is different ant different times and the midpoint of your shadow(equivalent to your point of average) will be different.Better still think of the projection of your body on a slanted wall and floor from above and the side by a torch - the two shadows are not the same and their midpoints are not the same.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-16T03:35:32Z
FirstChildVoteTAG: 2
SecondChildTAG: It seems reasonable then to conclude that we can multiply or divide by r and choose the one that best suits the situation.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-16T14:14:57Z
SecondChildVoteTAG: 0
SecondChildTAG: After doing exercise 1b on practice set 10, it is clear that dividing by r is not the way to go. It seems that regression tends towards the boundary of the range of 1 standard unit since we are always multiplying by a number from -1 to 1. Any sd above 1 gets smaller, and an sd from 0 to 1 gets larger. Dividing by r would take us away from this 1 sd boundary.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-16T14:50:59Z
SecondChildVoteTAG: 0
SecondChildTAG: The given is usually taken in the x axis and the unknown in the y axis. So the slope would be different if you switch midterm and final scores.Is that right?
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-18T05:58:28Z
SecondChildVoteTAG: 0
SecondChildTAG: From the online text - "There are really two regression lines: one for regressing Y on X, and one for regressing X on Y. The regression line for regressing X on Y also passes through the point of averages, but its slope is SDY/(r×SDX). This line minimizes the sum of the squared horizontal residuals, instead of the sum of squared vertical residuals. It is steeper than the SD line unless r is 1 or −1. Often, the variable that is regressed upon is called the independent variable, and the variable that is being regressed is called the dependent variable. Usually, the variable plotted on the horizontal (x) axis is the independent variable and the variable plotted on the vertical (y) axis is the dependent one. In this book, the independent variable of the regression line is always plotted on the horizontal axis and the dependent variable is always plotted on the vertical axis. "
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-23T03:03:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, and if a student was in the 80th percentile on the final, we predict the 66th percentile on the midterm. Go figure!
FirstChildUserIdTAG: 124536
FirstChildUserNameTAG: DavidHolmgren
FirstChildCreateTimeTAG: 2013-03-22T14:03:16Z
FirstChildVoteTAG: 0
IndexTAG: 806
TitleTAG: problem 2
doesn't accept NA
please help
UserIdTAG: 896461
UserNameTAG: cecimatho
CreateTimeTAG: 2013-03-16T00:50:28Z
VoteTAG: 2
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: May be NA is not a correct answer then
FirstChildUserIdTAG: 1120616
FirstChildUserNameTAG: Theerawat
FirstChildCreateTimeTAG: 2013-03-16T07:45:04Z
FirstChildVoteTAG: 0
IndexTAG: 807
TitleTAG: [Staff] Middle Term examn
Again problems with the set Time, when i come to complete the middle term, the time was expired. Please, try do something about it is very frustrating can't complete the test becose some clock stick are not propper coordinated. Is the seconf time i complete loose by the same reason.
Thnx
UserIdTAG: 323166
UserNameTAG: PabloT
CreateTimeTAG: 2013-03-16T00:19:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Pablo, what was the problem? I joined late, but did the test. The instructions clearly said GMT.
> Is the seconf time i complete loose by the same reason.
Maybe after the first time you should have taken the time to co-ordinate your time and GMT. There is another test soon. So now would be a good time to get it sorted.
http://wwp.greenwichmeantime.com/info/current-time/
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T01:29:42Z
FirstChildVoteTAG: 2
SecondChildTAG: Or perhaps try to complete the exam earlier? There are 48 hours allowed and it should take less than an hour to complete. It is rarely a good idea to leave a submission to the closing minutes.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T06:35:02Z
SecondChildVoteTAG: 0
IndexTAG: 808
TitleTAG: To Prof A. and Prof. Stark
I must comment, and I never do. This is to Prof A. and Prof Stark. I am horrible in Math (always have been) and I knew this course would be a challenge for me, and it certainly has been. But, I did it for me, and every time I wanted to quit, I dug in harder. When I didn't understand what Prof. A was saying, I had Prof. Stark on You Tube. I have learned MORE in this course, than I ever thought I would or could. I missed 4 or the mid-term, and I don't care what that means. It doesn't matter to me. What matters most for me, is for the first time in my long academic career, I can honestly say, I have thus far learned what statistics is, and how I can apply it to so many things. I even hear word problems in normal conversation with people talking. I'm not sure folks have had the opportunity to listen to Prof. Stark via You Tube, he's awesome as well. I look forward to this course and appreciate this opportunity to learn under you too. Thank You. I feel smarter.
UserIdTAG: 1200616
UserNameTAG: lawtec
CreateTimeTAG: 2013-03-15T23:54:52Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: That's awesome, lawtec! I've taken several courses through EdX so far and they all seem to have that same genuine ability to make you learn amazing things while enjoying the process and allowing you to become fascinated with the topics at hand. With this course and many others I've found myself lost in captive thought and intrigue by what I'm learning. I also agree that both professors are incredible.
Good luck with the rest of the course!
FirstChildUserIdTAG: 87103
FirstChildUserNameTAG: fjbasile
FirstChildCreateTimeTAG: 2013-03-16T00:08:23Z
FirstChildVoteTAG: 1
FirstChildTAG: Actually, I have watched the whole videos of STAT 21 performed by Prof. Ibser on Youtube, and he is very good!
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-16T01:21:08Z
FirstChildVoteTAG: 0
IndexTAG: 809
TitleTAG: Problem 1A
Explanation 6.1 is not enough to make the correct decision in regard to the Problem 1A. Precisely following to 6.1 video I have chosen wrong answer. But it is obviously such a simple problem!
P.S.: does anyone see there a straight line? I don't, I do see a curve... obviously, right? What I see is either hyperbolic or natural logarithm curve. ROUGHLY.
P.P.S.: and I've chosen the right answer in Problem 1B which means that I correctly analysed that diagram.
IMHO Problem 1A is not fair.
UserIdTAG: 255838
UserNameTAG: EngineerHrenov
CreateTimeTAG: 2013-03-15T23:54:36Z
VoteTAG: 9
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 6
FirstChildTAG: > IMHO Problem 1A is not fair
Are you serious? Not fair? You were just asked whether the relationship was linear or not, based on a scatterplot. Look at the picture. Can you fit a straight line? What's not fair about that?
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T01:25:55Z
FirstChildVoteTAG: 0
SecondChildTAG: did you read my comment above or just IMHO at the end?
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-16T07:24:43Z
SecondChildVoteTAG: 0
SecondChildTAG: repeating myself - no, there is NO straight line, it is OBVIOUSLY a curve. 100%
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-16T07:26:30Z
SecondChildVoteTAG: 0
SecondChildTAG: But, why isn't it "fair"?
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-16T07:46:55Z
SecondChildVoteTAG: 0
SecondChildTAG: because 'linearity' in that Problem 1A is subjective. this means that your answer 'linear' and my answer 'non-linear' are both correct in terms of ROUGHLY-ness.
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-16T09:28:08Z
SecondChildVoteTAG: 0
SecondChildTAG: That is not the point - you want to filt all the lines in one visual line - is that straight or curved.Is that going up or down in general ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-16T12:44:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Hello,
I didn't read the comments before answering to this first question.
My answer was wrong. And it makes me a little bit angry...
I have perfectly understood the concept from the lecture, and to answer this question, I have just compared this diagram with the examples shown in lecture.
Remember that in lecture, the first example used as a linear scatter diagram is (bird weight ; egg size) association.
Considering this, it appears quite clearly to me, that this diagram has a shape which is a bit like a straight line.
But it seems to be NOT according to the grader...
This question is just a big joke, seriously... i Obviously do not consider the positive/negative association aspect, which is trivial...
This diagram can both be seen as a straight line or as a curve. It is just a subjective point of view to say that this one is in fact non-linear since no mathematical criterium has been set to define linearity.
SecondChildUserIdTAG: 957952
SecondChildUserNameTAG: Jjclof
SecondChildCreateTimeTAG: 2013-03-17T03:49:37Z
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SecondChildTAG: Hi,
I too found it bit difficult to interpret with the help of the content of the 6.1 videos along. But there is a good point which can be used in such situations at the online text book, which says "Nonlinearity. The pattern in the relationship between the variables is not a straight line—it is curved. The data are scattered more-or-less evenly around a curve: The scatter in the values of Y is about the same for different values of X, that is, in different vertical slices through the scatterplot." I think that's why Reading and Practice for Exercise Set 9 strongly recommend to refer the text book(even it is bit boring)
SecondChildUserIdTAG: 1263723
SecondChildUserNameTAG: Chamikad
SecondChildCreateTimeTAG: 2013-03-17T17:56:29Z
SecondChildVoteTAG: 0
FirstChildTAG: The deadline is not over so please do not discuss actual answers due to the honor code.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-16T09:00:36Z
FirstChildVoteTAG: 0
SecondChildTAG: and we are not.
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-16T09:28:40Z
SecondChildVoteTAG: 0
SecondChildTAG: based on assumption its linear otherwise non-linear. So its very difficult to decide how to say which one. Association, no doubt, is negative.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-16T17:34:03Z
SecondChildVoteTAG: 0
FirstChildTAG: Why, why, why, did I read this discussion thread before answering the question?
Makes mental note to herself that trying to be extra-clever (aka cheat) is simply a stupid idea. Now someone console me with a cookie please.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-16T17:49:22Z
FirstChildVoteTAG: 0
FirstChildTAG: > based on assumption its linear otherwise non-linear. So its very difficult to decide how to say which one.
Look at the plot. Can you fit a straight line through the center of the points - you want the line of best fit, so you are trying to balance the number of points above and below the line.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-17T00:01:39Z
FirstChildVoteTAG: 0
SecondChildTAG: +lalostb based on my visual understanding from video and plot that were shown, I made me decisions. I marked to ans. on my book one was linear other was non-linear, however relationship was -ve. So I chooses the obvious one and it was wrong. Such assumption based qus depends on perception than logic. Hope this help. "I know you are good at Stat (an adv.) but I'm beginner.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-17T02:11:41Z
SecondChildVoteTAG: 0
FirstChildTAG: The data for the scatter diagram seems to be taken from [here][1].
As to whether the association is linear or not, bear in mind that the origin of the y-axis starts at 1400 rather than zero, which has the effect of 'amplifying' the relative differences between the scores.
[1]: http://nces.ed.gov/programs/digest/d11/tables/dt11_156.asp
FirstChildUserIdTAG: 366083
FirstChildUserNameTAG: smath
FirstChildCreateTimeTAG: 2013-03-17T14:16:59Z
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FirstChildTAG: I actually got this wrong so I can sympathise to a degree with earlier posters although I'd find it difficult to get 'angry' over a question that amounts to 0.5% of the overall score on a course with a 35% pass mark.
Although I called it wrong (and it's clearly true that there is some degree of judgement involved - otherwise I would have got it right) I can see that the correct answer is probably a better fit although the scale somewhat distorts the picture. Not unfair but not as easy as many seem to have assumed. I think I had too many years as an engineer squeezing the numbers to get a line of best fit and not enough time as a mathematician!
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-17T20:07:52Z
FirstChildVoteTAG: 1
SecondChildTAG: It's a bit like the earlier question about income being discrete / continuous - there's an element of judgement in both. And I got them both wrong :( but it made me think harder about why & when it might matter...
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-17T21:28:52Z
SecondChildVoteTAG: 0
IndexTAG: 810
TitleTAG: Missed the midterm. Will the total grade be shown on the certificate?
I comleteley missed the midterm, too. I was only able to watch the lectures and do the exercises on monday through wednesday due to my work, so the usual week due dates was perfect to me, but I couldn't even get to see the midterm exam itself until now and it is over already. Feel frustrated since I had no problems with solving the exercises and lost midterm only because of timing.
I've passed minimal grade required to earn the certificate, so does it matter for me to worry about it? I mean, will the grade be shown on the certificate? I still wish to perform at maximum — for myself at first, — and will do the exercises as well, but if so, I would like to complete the midterm anyway, if it possible somehow.
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UserNameTAG: Fedor_Igntakin
CreateTimeTAG: 2013-03-15T23:18:25Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: The certificate does not show your score in the course.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-15T23:29:09Z
FirstChildVoteTAG: 1
FirstChildTAG: The edX policies state that grades are not shown.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T01:22:49Z
FirstChildVoteTAG: 1
FirstChildTAG: I also missed the midterm. When I checked last week the deadline was March 19. Then I check it today, it was already closed due the deadline is March 15 already. Does the deadline moved or it just that I overlooked the deadline? Is there a possible way for me to take the midterm?
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FirstChildUserNameTAG: lucky1206
FirstChildCreateTimeTAG: 2013-03-16T04:12:03Z
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SecondChildTAG: I have the same problem. I more then sure that deadline must be March 19 but not 15 march... So I miss it.
What I need to do now?
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SecondChildUserNameTAG: Roksolana
SecondChildCreateTimeTAG: 2013-03-16T09:20:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Nothing. Just move on.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T10:33:19Z
SecondChildVoteTAG: 0
FirstChildTAG: > When I checked last week the deadline was March 19
Where did you see that? The Course Info page says:
>The midterm will become available at 7:00 A.M. Greenwich Mean Time (GMT) on Wednesday March 13. It will be due in 48 hours, at 7:00 A.M. (GMT) on Friday March 15.
Nothing about the 19th. The Schedule also lists March 13th as the date.
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FirstChildUserNameTAG: lalotsb
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SecondChildTAG: it was true that the course info page indicated 15th March as deadline. however on the course ware the deadline was 19th March. we thought that the deadline has been shifted to 19th March
they need not to change the dates anyhow. they confuse
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SecondChildUserNameTAG: SELEMANI
SecondChildCreateTimeTAG: 2013-03-18T07:16:40Z
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IndexTAG: 811
TitleTAG: Excellent Course, a general comment..
I'm sure it's been posted previously but just to add my own praise and appreciation. This is an excellent course! The lecturing style is second to none. Prof A. would even give Mr. Salman Khan a run for his 'money' (if this all wasn't free that is :). High praise indeed! So a sincere thank you from one student who is very much looking forward to the next installment in the course.
UserIdTAG: 9115
UserNameTAG: esc1
CreateTimeTAG: 2013-03-15T23:09:59Z
VoteTAG: 18
CoursewareTAG: Exercise Set 1 / Exercise Set 1
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FirstChildTAG: Prof A. & edx are great. Lots of thanx.
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FirstChildUserNameTAG: arvindsingla
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IndexTAG: 812
TitleTAG: Midterm problem 5
I don't understand the explanation for problem #5 - "Of the 10 results shown, 7 are more than 4 SDs away from average." How do we know what the average would have been for the entire set of 100 results?
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UserNameTAG: MShank
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
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FirstChildTAG: Question is, do we *need* to know the average? All those transformed numbers you see are distances from the average (whatever that might be) measured in standard deviations, because the numbers have been standardized by the computer. According to Chebychev, only so many results can lie n standard deviations away from the average.
Note that those 10 numbers *could* obey Chebychev's inequality for some values, like 5 [standard deviations away from the average]. But not 4 or 6. You can't really be sure for 2 and 3.
FirstChildUserIdTAG: 632581
FirstChildUserNameTAG: GMendes
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FirstChildTAG: MShank, all the data have been converted into standard units. In standard units, the average is always 0 and the SD is always 1. An observation like -11 is 11 SDs away from the average, and that, according to Chebychev's bound, is impossible. According to Chebychev's bound, the maximum percentage of entries that can be greater than 11 SDs is 1/121 = 0.008. 1 entry out of a 100 is 0.01 percent of the total entries, and 0.01 is greater than 0.008. Thus, this violates Chebchev's inequality and so the programme is malfunctioning for sure.
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FirstChildUserNameTAG: PrernaDewan
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SecondChildTAG: Again I am not sure if we should draw an answer from a single number -11 as it can be an outlier but take 4.7 and you should be not having more than 4.5 % and here we are having 7 % which is a more convincing argument. One swallow will not make a summer so judgement I think should not be made on just one sample value.Suspicious - yes but not proof since the sample size is small .
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
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SecondChildVoteTAG: 0
SecondChildTAG: Yes I was just giving an example with -11, the same can be seen for other observations in the sample too.
SecondChildUserIdTAG: 47031
SecondChildUserNameTAG: PrernaDewan
SecondChildCreateTimeTAG: 2013-03-16T11:37:51Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks. I forgot that simple point about average = 0 in standard units.
FirstChildUserIdTAG: 1095515
FirstChildUserNameTAG: MShank
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FirstChildTAG: ehh, same problem, didn't think that question clearly says - standard units :/ so easy to make stupid mistake without thinking through question properly.
But that is a good lesson for final exam :-)
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FirstChildUserNameTAG: apbyte
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IndexTAG: 813
TitleTAG: 1C
I'm not completely sure what this question is asking. Since the previous question used eggs at 22.5mm in diameter, is it wanting us to refer to the answer we got for 2b? or using exactly 6 grams as it asks in 1c?
Also is the relevant concept we're looking at here have to do with the graph of averages as in exercise 9-1 in the text?
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UserNameTAG: FareedHameed1
CreateTimeTAG: 2013-03-15T23:03:24Z
VoteTAG: 1
CoursewareTAG: Exercise Set 10 / Exercise Set 10
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FirstChildTAG: Actually, we don't have to calculate anything in this question. Just use the intuition.
You can see that two variables have positive r, so that if one variable is below the average, another variable also tends to be below the average.
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FirstChildUserNameTAG: Theerawat
FirstChildCreateTimeTAG: 2013-03-16T08:17:44Z
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SecondChildTAG: > if one variable is below the average, another variable also tends to be below the average.
I'm not sure that is expressed quite correctly. It is better to say that values tend towards the mean (ie regress) so if *x* values are above average, associated *y* values will be lower (ie closer to the mean). If *x* values are low, the *y* values will be higher (again, closer to the mean). 'High' and 'low' relate to the mean.
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SecondChildUserNameTAG: PaulJM
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SecondChildTAG: I think what you explained applies to negative correlation.while positive correlation = if one variable above the mean the other variable will be. And vice versa
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SecondChildUserNameTAG: aldawlah
SecondChildCreateTimeTAG: 2013-03-16T20:43:48Z
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SecondChildTAG: Dear PauijM
I think what you explained applies to negative correlation.while positive correlation = if one variable above the mean the other variable will be. And vice versa
SecondChildUserIdTAG: 1288142
SecondChildUserNameTAG: aldawlah
SecondChildCreateTimeTAG: 2013-03-16T20:45:04Z
SecondChildVoteTAG: 0
SecondChildTAG: > think what you explained applies to negative correlation.while positive correlation = if one variable above the mean the other variable will be. And vice versa
Negative or positive makes no difference. The result will always be closer to the mean
For example, assuming a positive correlation, mean = 50%, midterm = 90% predicted final would be between 50 and 90% (tending **downwards** towards the mean)... or... mean = 50%, midterm = 10%, predicted final would be between 10 and 50% (tending **upwards** towards the mean)
If the correlation were negative the directions would be reversed but the tendency would still be towards the mean.
I think some of the confusion arises because most examples seen deal with values which are high - in line with Galton's original observations (which only considered unusually tall parents). If he had looked at parents well below the mean he would have found their children tended to be taller - which point was mentioned by Prof. A in her lecture.
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SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-16T23:08:56Z
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SecondChildTAG: A 22.5mm diameter egg produces 5.58grams chick -in average- taking in account a normal distribution; so, >=5.58grams chicks are upper 50% of that distribution.
The question is what percentage of that distribution weights >=6grams.
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SecondChildUserNameTAG: jcquintero
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SecondChildTAG: I think it's easier to visualise if you think of the vertical strip on the scatter plot that will line up for the diameter we are looking for. Remember the value you obtained in the previous question for 22.5mm is an estimate, i.e. it is the average for the values that are in that strip. Now think about where 6g will be on that strip.
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SecondChildUserNameTAG: NuwanRD
SecondChildCreateTimeTAG: 2013-03-20T15:44:51Z
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FirstChildTAG: Please, could someone explain me what 1C means? I am thinking about the slope of the regression line that lies below the Sdsxy line on the left of the average point but how it does reflect the average of the strip=22.5 mm of diameter on the weight?
FirstChildUserIdTAG: 941908
FirstChildUserNameTAG: katecat
FirstChildCreateTimeTAG: 2013-03-19T13:25:48Z
FirstChildVoteTAG: 1
SecondChildTAG: ...above, not below, I wrote incorretly. The question is the same.
SecondChildUserIdTAG: 941908
SecondChildUserNameTAG: katecat
SecondChildCreateTimeTAG: 2013-03-19T13:33:57Z
SecondChildVoteTAG: 0
SecondChildTAG: ..above on the left, I wrote incorretly
SecondChildUserIdTAG: 941908
SecondChildUserNameTAG: katecat
SecondChildCreateTimeTAG: 2013-03-19T15:37:53Z
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SecondChildTAG: The problem can be solved by visual inspection of a normal distribution (draw it!).
A football shaped scatter plot is considered normally distributed on any vertical (or horizontal) strip.
Hence, there is a normally distributed strip of weights at diameter=22.5mm. This strip has an average=(answer to part 1B).
The relative position of the 6 grams to the average will tell you the portion of the graph you need.
SecondChildUserIdTAG: 514871
SecondChildUserNameTAG: ali_lateef
SecondChildCreateTimeTAG: 2013-03-19T15:54:23Z
SecondChildVoteTAG: 0
SecondChildTAG: I still cannot figure this one out and any additional hint would be appreciated. I understand the direction towards mean concept but unable to understand how to calculate %
SecondChildUserIdTAG: 1138594
SecondChildUserNameTAG: nathyash
SecondChildCreateTimeTAG: 2013-03-19T22:56:25Z
SecondChildVoteTAG: 0
SecondChildTAG: @ nathyash -
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13637469401343623.tiff
SecondChildUserIdTAG: 514871
SecondChildUserNameTAG: ali_lateef
SecondChildCreateTimeTAG: 2013-03-20T02:36:32Z
SecondChildVoteTAG: 0
SecondChildTAG: ![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13637478051343659.jpg
SecondChildUserIdTAG: 514871
SecondChildUserNameTAG: ali_lateef
SecondChildCreateTimeTAG: 2013-03-20T02:50:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks ali_lateef , the diagram helped. I was so far not able to visualize the stirp, now it is clear
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SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-20T05:35:56Z
SecondChildVoteTAG: 0
IndexTAG: 814
TitleTAG: Hint for Problem 2a, 2b: Carefully review the slides from Lec 6.2!!!
*Wink, wink*!
UserIdTAG: 267644
UserNameTAG: gojun077
CreateTimeTAG: 2013-03-15T22:12:22Z
VoteTAG: 4
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: :)
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-15T22:55:23Z
FirstChildVoteTAG: 0
SecondChildTAG: Pls can you throw more light on how to crack 2a and 2b. I completely missed it.
SecondChildUserIdTAG: 1173471
SecondChildUserNameTAG: jides
SecondChildCreateTimeTAG: 2013-03-16T01:32:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Draw a diagaram
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SecondChildUserNameTAG: Prasannasimha
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SecondChildVoteTAG: 0
SecondChildTAG: Think about the **properties** of the correlation coefficient as they are explained in the referred lecture (the last part of the lecture).
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-16T22:14:06Z
SecondChildVoteTAG: 0
SecondChildTAG: I am still unable to figure out the correlation, I marked an answer with approp sign and it is still wrong for 2A
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SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-03-19T01:41:54Z
SecondChildVoteTAG: 0
FirstChildTAG: I think **r** actually measures how plots may seen as a straight line... So if connected points form a uniform slope, then the coefficient will be...
FirstChildUserIdTAG: 1378421
FirstChildUserNameTAG: Misaka
FirstChildCreateTimeTAG: 2013-03-16T14:39:21Z
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IndexTAG: 815
TitleTAG: Question 1A
1A, I interpreted as we have been given Y (the final) so use it to get X the midterm. In my estimate the student's midterm percentile was about 90th. My assumption is we generally use midterm to estimate final so Y= r.X in this case we have Y and r so we are to find X. Why is this method wrong?
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UserNameTAG: lilian2012
CreateTimeTAG: 2013-03-15T21:58:27Z
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CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
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FirstChildTAG: **Estimated** Y = r.X
If you are given Y then:
**Estimated** X = r.Y
You couldn't just rearrange for example:
Y = r.X
X = Y/r <- WRONG!
because the one of the values is actual and one estimated. If you want to work from this formula then it is better always to think of the known value as X.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T23:28:10Z
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SecondChildTAG: Thats where the confusion is coming in; Taking Y=rX to be equal to X= rY, why not X= Y/r?
Assuming I have the SD line of Y=rX. Does this mean I cannot use the same line to estimate Y and X for questions 1A and 1B?. Given that the standard units for finals are on the Y-axis and standard units for midterm on the X-axis?
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-17T14:35:10Z
SecondChildVoteTAG: 0
SecondChildTAG: this does't make any sense to me -- it can't work the same both ways, but alas, r must be between -1 and +1.
Perhaps the right answer is to take 1-r for the reverse, but still that doesn't resolve properly for this question. I think this question is wrong and accidentally applies the same r both directions.
Anyway else more sure about this???
SecondChildUserIdTAG: 1168822
SecondChildUserNameTAG: davmarc
SecondChildCreateTimeTAG: 2013-03-19T13:56:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I called the midterm score = X and the final score = Y.
My answer for 1A was 1.31 (standard units) which converts to 90.5%.
I don't understand why if Y = r*X then X ≠ Y/r?
This gave me the correct answer for 1B (.081su or 53.23%) but the wrong answer for 1A.
In plain English, these answers mean
1) being the 70th percentile on the final predicts a 58th precentile on the midterm
2) but the opposite is not true! Being a 58th percentile on the midterm does NOT predict a 70th percentile on the final, but rather a LOWER score.
This does not make visual sense to me.
SecondChildUserIdTAG: 1153828
SecondChildUserNameTAG: Matt2edX
SecondChildCreateTimeTAG: 2013-03-19T20:40:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Okay, the next section beautifully explains my question. Maybe I'll view all the videos before beginning the graded exercises next time.
SecondChildUserIdTAG: 1153828
SecondChildUserNameTAG: Matt2edX
SecondChildCreateTimeTAG: 2013-03-20T00:12:39Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, its confusing. The problem is the counter-intuitive wording:
> Midterm and final scores have a correlation on 0.4
That means for me: midterm -> 0.4 * final; but what is used here: final -> 0.4 * midterm, which in my understanding is in English: "Final and midterm scores have a correlation **of** 0.4."
FirstChildUserIdTAG: 1174304
FirstChildUserNameTAG: ThomasHGMann
FirstChildCreateTimeTAG: 2013-03-17T18:19:05Z
FirstChildVoteTAG: 2
SecondChildTAG: I agree - it is very confusing - it can't be that you multiply by 0.4 in both cases, when relating the final scores to the midterm (as in problem a) and when relating midterm scores to the final (as in b).
SecondChildUserIdTAG: 885733
SecondChildUserNameTAG: Arie90435
SecondChildCreateTimeTAG: 2013-03-17T23:44:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, you DO multiply by .4 for estimating in both direction, the key is that regression is NOT a "reversible" process, i.e, given a Mid-term score, you can estimate the Final score, but if you use that same final score to estimate a mid term score you won't get the original Mid-term score, but something close to the mean. Look at the "Football" of the distribution, in normal units, the "center" line of the football will be the y=x line (or y=-x for negative correlation), but because the football has width, the y=x line is too high to be the "best" estimate, your estimates regress back to the mean. Only in the case of r=+/-1 does reversing the regression get you back to the original value.
SecondChildUserIdTAG: 1222946
SecondChildUserNameTAG: RichardDamon
SecondChildCreateTimeTAG: 2013-03-18T01:57:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Ah. Hence the *regression*.
That wouldn't have been so hard to cover during the slides. She wouldn't have to cover all the math just yet, but the concept that you covered right there clarifies it enough.
Basically, since the *average* is always a best guess (because you're splitting the difference on error, if you are starting above average) you will always regress back down to the average, but if you are below average, you will regress back *up* to the average.
It's unidirectional, not reciprocal (except for the +-1 or 0 special cases).
Thanks.
SecondChildUserIdTAG: 972465
SecondChildUserNameTAG: ToddCioffi
SecondChildCreateTimeTAG: 2013-03-20T22:04:56Z
SecondChildVoteTAG: 0
IndexTAG: 816
TitleTAG: Is there any way to make up my missed grades?
Unfortunately I couldn't make my midterm exam since I was on vacation. Would you please let me know is it still possible that I can achieve the passing grade? Since now my grade is 17% :(
UserIdTAG: 439644
UserNameTAG: Samane
CreateTimeTAG: 2013-03-15T21:38:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Have you read the grading requirements? I'm new, but I've read them and know that even starting this late it is possible to get the "certificate".
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-15T21:41:38Z
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SecondChildTAG: I am also late for my March 6-12 exercise and the mid term as I was away on work trip. Is it possible for me to submit my exercise 7 and 8
SecondChildUserIdTAG: 972972
SecondChildUserNameTAG: 0123
SecondChildCreateTimeTAG: 2013-03-15T22:00:39Z
SecondChildVoteTAG: 0
SecondChildTAG: deadline is over.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-16T03:40:39Z
SecondChildVoteTAG: 0
FirstChildTAG: It would be possible to meet the 35% Pass mark using only the scores from the remaining Exercise sets and Final exam. You would need to be getting high scores on all the remaining elements.
You say that you are currently on 17%. If you have submitted all the previous exercises on time that suggests you have averaged somewhere near 50%. Keep on at the same rate and get a score of about 50% on the Final and you should get an overall pass - just.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T06:41:39Z
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IndexTAG: 817
TitleTAG: Midterm 4B - (Request) - Can we prove this thru line equation?
Hello ,
The explanation provided in the exercise doesn't look adequate to prove the logic. Can someone please provide a detail explanation through a linear equation or (some other logic) to prove why SD will be larger.
Mistakenly (not sure) I was looking the whole point from linear equation perspective thinking that SD were remaining same for each section because a constant addition/substraction of marks are happening as compared to section1 . And then was trying to see it from that angle which seems was not a good idea.
Please provide little help. Thanks in advance.
Lipin
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UserNameTAG: Lipin
CreateTimeTAG: 2013-03-15T21:18:11Z
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: http://www.emathzone.com/tutorials/basic-statistics/combined-variance.html
Just extend for 3 groups. But the info given is enough.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-15T21:34:36Z
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FirstChildTAG: Look at it this way: If the three data sets had had the SAME mean, the SD of the combined total *still* would have been nine! The fact that they had DIFFERENT averages means that the total data would be MORE spread out and therefore the SD would be GREATER than nine.
FirstChildUserIdTAG: 1289355
FirstChildUserNameTAG: DaRitz
FirstChildCreateTimeTAG: 2013-03-15T21:50:36Z
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SecondChildTAG: That doesn't explain the problem to me. If the groups had different averages, that can mean that many samples from these groups fell CLOSER to the common mean, lowering common SD.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-03-15T22:10:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, it made logical sense to me. I then verified it with hard numbers.
SecondChildUserIdTAG: 1421305
SecondChildUserNameTAG: lalotsb
SecondChildCreateTimeTAG: 2013-03-15T22:17:07Z
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SecondChildTAG: to quote KarienJ - full text 6 posts down:
> From the on-line textbook, Chapter 4: "the sum of the squares of the differences between the data and the mean is smaller than the sum of squares of the differences between the data and any other number. (Equivalently, the rms or root mean square of the differences from the mean is smaller than the rms of the list of differences from any other number.)"
which feels right - that's what the mean is all about - you've calculated a number that minimises the average deviation of the data. Now you're combining data with pretty disimilar means - so the contribution to the sd from each subset of the data will increase, and the sd for the combined data will be higher that 9. I know what you mean about some combination of numbers that will be closer to the new mean - tried and failed to come up with an example.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-15T22:21:13Z
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SecondChildTAG: Although ''constant addition/subtraction are happening within each section'',yet SD of whole class is to be calculated from final class average 66.95 vs marks of whole class,including from upper extreme marks ( 75 + 1/2/3..*9 ) of section 2 and from lower extreme marks ( 60 - 1/2/3..*9 ) of section 3. And dear aiS2ru,many samples from different groups do bring final common mean 66.95 CLOSER to individual group means 60,68 & 75 but leaves final data of marks of whole class much more spread out and with larger SD.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-16T07:04:57Z
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FirstChildTAG: One way is to look at the algebra supplement, in which I showed you how the SD is the square root of: "mean of squares minus square of mean". This implies that whenever you have the mean and the SD of a list of numbers, you can calculate the mean of the squares and hence the sum of the squares.
So: use this idea to calculate:
a) the sum of squares in each of the three sections
b) the sum of squares of the whole class
You already computed the mean of the whole class in a previous problem, so now you can figure out the SD of the whole class as the square root of "mean of squares minus square of mean."
In the exam I didn't ask you for the value of the SD, and it's not necessary to do the calculation to see that the SD will be bigger, but I agree that the calculation is reassuring. Try it, and let me know if you need help getting it finished. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T04:50:41Z
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SecondChildTAG: Thank you, Prof A. You have a way of simplifying things (even though my brain exploded the first time I read that - too many "square ofs"...).
Now I need to sit down now with pen and paper and work this out to be sure I really understand it.
I had printed out your paper on Derivations, but it got buried on my desk and I never did read it.
Like many others, I'm thoroughly enjoying this course. Thank you for all your efforts.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-16T09:13:14Z
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FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/514390134adb116b18000045
So
$\Sigma x_1^2=(\sigma_1^2+ \mu_1^2).n_1 $ ie $(9^2 +68^2).20=94100$
$\Sigma x_2^2=(\sigma_2^2+ \mu_2^2).n_2 $ ie $(9^2 +75^2).25=142650$
$\Sigma x_3^2=(\sigma_3^2+ \mu_3^2).n_3 $ ie $(9^2 +60^2).32=117792$
Let subscript "c" refer to the combined group
$\Sigma x_c^2 = \Sigma x_1^2 + \Sigma x_2^2 + \Sigma x_3^2= 354542$
$n_c=n_1+n_2+n_3 =77$
$\mu_c = 66.95$
So
$\sigma_c^2= \displaystyle\frac{1}{n_c}\Sigma x_c^2 -\mu_c^2 $
So
=$\displaystyle\frac{354542}{77}-(66.95)^2$
=$122.1391$
So
$\sigma_c=\displaystyle\sqrt122.1391$
$\sigma_c=11.05$
So the combined standard deviation is higher than the SD's of the individual groups.
Prof Adhikari, is this the correct solution
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-16T10:35:31Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes, correct; sorry, I answered this in the wrong thread.
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-16T19:31:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank You
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-17T03:39:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank You Prof A. Explanation really helped . Lucky to be part of this class & looking forward to attend more of your classes.
Thanks everyone for providing valuable inputs.
SecondChildUserIdTAG: 1214737
SecondChildUserNameTAG: Lipin
SecondChildCreateTimeTAG: 2013-03-20T04:30:58Z
SecondChildVoteTAG: 0
IndexTAG: 818
TitleTAG: Next Course...
When will Stat2.2x start?
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UserNameTAG: ghromis
CreateTimeTAG: 2013-03-15T21:17:45Z
VoteTAG: 14
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Asked and answered a number of times - 'shortly after the end of 2.1X'.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-16T10:36:37Z
FirstChildVoteTAG: 0
IndexTAG: 819
TitleTAG: Only a little over a week until Final Exam...
My goodness, hasn't this course flown by? Yet at the same time it seems long ago that we took our first steps here. Looking forward to the new challenges of Stat2.2X.
Not worrying about the Final exam. I don't need the marks to pass and, assuming it will be similar to the Midterm, not an insurmountable obstacle if you have done the Practice and Graded Exercise Sets.
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UserNameTAG: PaulJM
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FirstChildTAG: My view is that our Midterm is similar to one of those mini quiz at Berkeley. And our Final Exam for this course is like the first Midterm at Berkeley. I am too looking forward to Stats 2.2x.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-16T02:01:29Z
FirstChildVoteTAG: 1
FirstChildTAG: Jeez Paul you and 1,000 others .....
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
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FirstChildVoteTAG: 0
IndexTAG: 820
TitleTAG: 'Midterm Avg' Progress bar?
Does anyone know what the bar Midterm Avg represents in the Course Progress?
UserIdTAG: 1159651
UserNameTAG: KatrienJ
CreateTimeTAG: 2013-03-15T20:52:19Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It represents the average of all of *your* midterm scores. Since there is one midterm, the average should equal the score on your midterm. This should be true for everyone.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-15T23:18:13Z
FirstChildVoteTAG: 1
IndexTAG: 821
TitleTAG: Midterm Problem 2B
The problem required to estimate the 80th percentile of the distribution of times, in hours. And I understood that the answer is to be given in FULL (complete or maybe there is another word, which describes it more precisely i.e. when incomplete hours should be omitted) hours. My answer was 14 and it was wrong (the right one was 14.67). If there were not a specification "in hours", most probably I would add decimals, as it is required in the introductory part. This remark about hours was really misleading...
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UserNameTAG: Pois
CreateTimeTAG: 2013-03-15T20:50:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The question stated it in hours. It didn't say anything about rounding.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-16T02:02:22Z
FirstChildVoteTAG: 2
FirstChildTAG: And the general instructions were for 2dp or no more than 5dp.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-16T02:07:07Z
FirstChildVoteTAG: 1
FirstChildTAG: Prof. A comes through with the knowledge in [this post][1].
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5143d7b41910c71f00000007
FirstChildUserIdTAG: 969411
FirstChildUserNameTAG: McAlary
FirstChildCreateTimeTAG: 2013-03-16T21:07:36Z
FirstChildVoteTAG: 0
IndexTAG: 822
TitleTAG: The minimum required score
I think Dr Ani said we needed a really low score to pass, something like 23.1 and I think I my grades are above that. I am happy because I had missed a couple of assignments and could not make up for them.
UserIdTAG: 580652
UserNameTAG: nivanmorgan
CreateTimeTAG: 2013-03-15T20:44:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: I am getting a certificate from BERKLEY.........
FirstChildUserIdTAG: 580652
FirstChildUserNameTAG: nivanmorgan
FirstChildCreateTimeTAG: 2013-03-15T20:46:51Z
FirstChildVoteTAG: 0
SecondChildTAG: The 'Pass' mark is 35% - as shown on the Progress tab above and in the course inof.
The certificate is technically from BerkeleyX via edX.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-15T20:50:44Z
SecondChildVoteTAG: 0
IndexTAG: 823
TitleTAG: MIDTERM PROBLEM 4B
To the Staff Stat2.1x
The answer/explanation Prob 4B seams not that convincing to me.In the problem text it's not said the distributions(all class sections) were symmetrical, Normal or the likes.These shapes are crucial, I think, to derive the spread of the compound distribution.
Therefore the item (d) "cannot be placed... based on the information given" should be correct.
VOLNEY
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UserNameTAG: Volney
CreateTimeTAG: 2013-03-15T20:22:38Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 7
FirstChildTAG: I can prove that the SD should be larger than 9.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-15T20:28:18Z
FirstChildVoteTAG: 0
SecondChildTAG: OK. Please, go ahead!
VOLNEY
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SecondChildUserNameTAG: Volney
SecondChildCreateTimeTAG: 2013-03-15T21:00:36Z
SecondChildVoteTAG: 0
FirstChildTAG: Whoooah, I hoped to understand statistics by doing this course. For that I'm going to need a explanation how the answer was derived. How do you get from the 'answer' to the answer??? Any idiot could guess the variation would be bigger because the averages are different but what's the statistical logic for it. I've waited 3 days for this, I want to understand statistics not after the 'piece of paper', please elaborate, thanks, mark
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
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FirstChildTAG: There's a lot of discussion about 4B in a discussion titled 'midterm problem 4B':
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5142f2672af1052700000081
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-15T21:12:18Z
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FirstChildTAG: I used the fact that the mean minimizes the Euclidean distance to the data points. From the on-line textbook, Chapter 4: "the sum of the squares of the differences between the data and the mean is smaller than the sum of squares of the differences between the data and any other number. (Equivalently, the rms or root mean square of the differences from the mean is smaller than the rms of the list of differences from any other number.)"
The SDs of the three class sections are
$SD_1 = \sqrt{\frac{1}{20} \sum_{i=1}^{20}(s_i - M_1)^2} = 9$
$SD_2 = \sqrt{\frac{1}{25} \sum_{i=21}^{45}(s_i-M_2)^2} = 9$
$SD_3 = \sqrt{\frac{1}{32} \sum_{i=46}^{77}(s_i-M_3)^2} = 9$,
where $M_1 = 68$, $M_2 = 75$ and $M_3 = 60$ and $s_i (i=1,\ldots,77)$ are the students' scores.
For the three class sections, the respective means make the rms minimal.
Let $M$ be the mean for the whole class, which is $66.95$, as computed in 4A. Then,
$\sum_{i=1}^{20}(s_i - M)^2 > \sum_{i=1}^{20}(s_i - M_1)^2 = 20 \cdot 81$ (it cannot be equal because $M \not = M_1$ and the function is convex.) Similarly
$\sum_{i=21}^{45}(s_i - M)^2 > \sum_{i=21}^{45}(s_i - M_2)^2 = 25 \cdot 81$
and
$\sum_{i=46}^{77}(s_i - M)^2 > \sum_{i=46}^{77}(s_i - M_3)^2 = 32 \cdot 81$
Summing the three expressions gives us
$\sum_{i=1}^{77} (s_i - M)^2 > 77\cdot 81 $
So that
$\sqrt{\frac{1}{77}\sum_{i=1}^{20}(s_i - M)^2} > 9$
and the left hand side of this expression is the SD of the whole class.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-15T21:41:53Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you, that explains it well.
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SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-03-15T22:13:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Nice, Katrien! I see what I did wrong now. Great explanation!
SecondChildUserIdTAG: 87103
SecondChildUserNameTAG: fjbasile
SecondChildCreateTimeTAG: 2013-03-16T00:12:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Katrien
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SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T01:52:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Wowsers! That looks ... fun. Easier to use this (just add another group) as we have all the values required:
http://www.emathzone.com/tutorials/basic-statistics/combined-variance.html
Or just use a bit of logic.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-15T22:11:29Z
FirstChildVoteTAG: 0
SecondChildTAG: And that logic would be ....
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T01:52:27Z
SecondChildVoteTAG: 0
FirstChildTAG: "The penny drops" ...
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
FirstChildCreateTimeTAG: 2013-03-16T08:45:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Also take a look at another post about problem 4B, where Prof. A. explains a way to prove it.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-16T08:57:52Z
FirstChildVoteTAG: 0
IndexTAG: 824
TitleTAG: Practice for Exercise Set 10
Question about Problem 1:
Why is the midterm percentile less than the final percentile when the correlation coefficient is less than 1.0? Was the question stated incorrectly?
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UserNameTAG: guba11ro
CreateTimeTAG: 2013-03-15T19:36:12Z
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
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IndexTAG: 825
TitleTAG: [STAFF] MID TERM PROBLEM 1B & 4A
Problem 1A I got answer as 39.5714 and 4A as 66.9481 and marked wrong.
It is clearly stated that:
**Format of numerical answers**
Please provide all numerical answers correct to two decimal places or more, but please don't use more than five decimal places. No answer in this course will involve that degree of accuracy.
Please Professor can you advice me.
Thank you.
UserIdTAG: 360344
UserNameTAG: Wabuyi
CreateTimeTAG: 2013-03-15T19:30:51Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I think you mean problem 1A. Problem 1B asks about which number the SD is closest to.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-03-15T20:14:26Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you Rahulsv exactly that is what I meant. It was the thinking that was beyond my control, but the idea about the subject matter is got.
SecondChildUserIdTAG: 360344
SecondChildUserNameTAG: Wabuyi
SecondChildCreateTimeTAG: 2013-03-15T21:06:48Z
SecondChildVoteTAG: 0
IndexTAG: 826
TitleTAG: Problem 2
What we are supposed to write in the blanks ?? NA is also not accepting... and message "Invalid Input" pops up...What to do?
UserIdTAG: 1240091
UserNameTAG: Visheshta
CreateTimeTAG: 2013-03-15T19:18:54Z
VoteTAG: 5
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 2
FirstChildTAG: Are we expected to write negative or positive in the blanks ?
FirstChildUserIdTAG: 1069830
FirstChildUserNameTAG: TheodoraCh
FirstChildCreateTimeTAG: 2013-03-15T19:35:48Z
FirstChildVoteTAG: 0
SecondChildTAG: No, negative, positive wont work as well.......i have tried that !
So better just apply common sense.....u will get the answer !!
As i did !
SecondChildUserIdTAG: 1240091
SecondChildUserNameTAG: Visheshta
SecondChildCreateTimeTAG: 2013-03-15T19:41:00Z
SecondChildVoteTAG: 0
SecondChildTAG: I think you should write down correlation coefficient.
SecondChildUserIdTAG: 1249880
SecondChildUserNameTAG: xuy1
SecondChildCreateTimeTAG: 2013-03-15T19:42:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I think it's looking for the slope of the line; a positive or negative integer.
Slope = change in Y / change in X (http://www.mathwarehouse.com/algebra/linear_equation/slope-of-a-line.php)
That's what I used for 2A and the answer was correct. I used the same formula for 2B but the answer was marked incorrect.
SecondChildUserIdTAG: 876324
SecondChildUserNameTAG: BrianDeering
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SecondChildVoteTAG: 0
SecondChildTAG: try using some imaginary data to create a scatter diagram for each case. I did that and helped me a lot to find the correct answers :-)
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-15T20:47:39Z
SecondChildVoteTAG: 0
SecondChildTAG: **I correct myself.** It has NOTHING to do with the **numeric** slope of the line.
Everything is explained in Lecture 6.2 slides, starting at 3:08.
Plot the data according to what's described in the problem set. For instance, in Problem 2A, the possible paired values are:
> correct answers - 10 = incorrect answers
If there are 10 correct answers then there must be 0 incorrect answers!
If there are 5 correct answers then there must be 5 incorrect answers!
If there are 3 correct answers then there must be 7 incorrect answers!
If there are 0 correct answers then there must be 10 incorrect answers!
Follow the examples in the slides (6.2 starting at 3:08) and create a series of paired data points.
They should look like:
1. 10,0 (10 correct, 0 incorrect)
2. 5,5 (5 correct, 5 incorrect)
3. and so on.
Then do the math.
Very exciting really when it finally comes to you!
SecondChildUserIdTAG: 876324
SecondChildUserNameTAG: BrianDeering
SecondChildCreateTimeTAG: 2013-03-15T21:15:44Z
SecondChildVoteTAG: 0
SecondChildTAG: I did this, still got a wrong answer
SecondChildUserIdTAG: 569767
SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-03-19T02:36:19Z
SecondChildVoteTAG: 0
FirstChildTAG: You should answer the "r"
FirstChildUserIdTAG: 183861
FirstChildUserNameTAG: Xelio
FirstChildCreateTimeTAG: 2013-03-16T05:12:34Z
FirstChildVoteTAG: 0
IndexTAG: 827
TitleTAG: Love this course.
Actually I believe some of us already passed the passing mark. Thank you for the good course. This is also make me no stress to continue this course. Anybody out there also has passed this course?
UserIdTAG: 7980
UserNameTAG: Nazri
CreateTimeTAG: 2013-03-15T18:59:54Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hi!
I have passed the course as well , although i had missed one exercise set. I concur about the course , the professor is great and the people who are responsible for the tech logistics are very helpful too.
Edx will surely be a staple in my future efforts to learn more. I will also definitely enroll if Professor Ani/ Berkeley x offer a follow up to this course.
Very grateful for this!
FirstChildUserIdTAG: 1015352
FirstChildUserNameTAG: weizkn
FirstChildCreateTimeTAG: 2013-03-15T19:08:06Z
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FirstChildTAG: i love the way of learning of this course..i didn't thought of statistics in that way.. i love the philosophy of the professor Ani and her passion about the statistics..
FirstChildUserIdTAG: 1147076
FirstChildUserNameTAG: giomicho
FirstChildCreateTimeTAG: 2013-03-15T20:16:31Z
FirstChildVoteTAG: 3
IndexTAG: 828
TitleTAG: ...Considering this is a Stat course...
Dear Professors and TAs,
Would you be able to share the data on mean and median mid-term scores from the test we just took? I know we're a pretty large class but some way to get a perspective on our scores would be much appreciated! :)
Thanks very much for all you do!
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UserNameTAG: VeenaChatti
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
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FirstChildTAG: And by now we know enough about stem & leaf diagrams not to ask for one of those diagrams! ;)
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-15T18:51:54Z
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FirstChildTAG: Well done, MyOwnCamera: I want all the data but even I didn't ask for a stem and leaf plot.
I have to tell you that I don't have these data. I've been told that the platform is being upgraded to provide the instructor with this kind of information at a glance, and you can be sure that Philip Stark and I will have a lot to say about exactly what information is provided ...
But EdX is great about getting instructors the info they need, so I will ask for performance summaries. I'll keep you posted. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T04:54:20Z
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IndexTAG: 829
TitleTAG: Midterm 3B
Applying Tchebycheff does not solve the problem?:
0.5=1-1/k2
0.5-1=-1/k2
-0.5+1=1/k2
0.5=1/k2
0.5*k2=1
k2=1/0.5
k2=2
k=square root(2)
k=1.41
1.41*1.2=1.69
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UserNameTAG: JorgeSeifert
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FirstChildTAG: Click on "Show Answer" underneath the question on the midterm page, and you'll seen an explanation of the answer. Basically, you shouldn't use Chebychev's Inequality.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-15T18:44:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Why not?
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-15T18:50:14Z
SecondChildVoteTAG: 0
SecondChildTAG: "No matter what the list, a proportion of at least 1 - 1/k2 of the entries will be in the range average +/- k*SD!
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-15T18:53:59Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm sorry character ! should be " to close the text
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-15T18:55:23Z
SecondChildVoteTAG: 0
FirstChildTAG: You are not being asked the estimate of a bound.You know the distribution is normal so we can get a sharper bound than Chebychev (not more than +/-2.34 mm)- in fact since we know the distribution is near normal we get a better in fact accurate estimate.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
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SecondChildTAG: But the text is "a proportion of at least 1 - 1/k2".
I calculated +/- 1.69 using Chebychev that is less than +/-2.34
Why +/- 2.34 from where is this value?
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-15T19:17:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Replacing your value of K gives 2.34 mm (sinbce what is wanted is not in Z values (ie in so many times SD which is what you got as 1.69- multiply it with what one SD is)but in actual mm.Youare though missing the point, we already know that the curve/distribution is a normal curve and so we already have a better sense of distribution than what Chebychev tells us so why use a less accurate method when you have a better measure and why use an approximation of a bound when we can ge actual estimates using a measure of spread and thus can get an accurate estimation of location ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T20:16:25Z
SecondChildVoteTAG: 0
IndexTAG: 830
TitleTAG: ex-9-10 solutn is nt appearing.why?
when will be the solutn availbl?
UserIdTAG: 1400928
UserNameTAG: helalrahman
CreateTimeTAG: 2013-03-15T17:40:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 1
FirstChildTAG: Once the deadline is over.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-15T17:42:20Z
FirstChildVoteTAG: 0
SecondChildTAG: but it does not happened in previous so why now !we will not gonna learn what was the problem?
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-15T18:07:14Z
SecondChildVoteTAG: 0
SecondChildTAG: As per March 6th message in the Course Info Section:
> To give you the opportunity to look at solutions before the midterm, we are making the solutions to Week 3 exercise sets visible to you as soon as you have turned in your answers. <...> **In Week 4 we will return to the usual “solutions posted after due date” system.**
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-15T18:16:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Notwithstanding what you quote Mzvd, this represents a change. Solutions have always been available immediately after you choose answer in the regular weekly questions and it has been very helpful.
SecondChildUserIdTAG: 975799
SecondChildUserNameTAG: lmacareo
SecondChildCreateTimeTAG: 2013-03-16T17:49:19Z
SecondChildVoteTAG: 0
SecondChildTAG: lmacareo, your info is correct for the first week but not the second.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-16T17:58:10Z
SecondChildVoteTAG: 0
IndexTAG: 831
TitleTAG: Exercise set 6
I fail to find any discussion of SD in Courseware, Wiki, etc other than in the 'on line text', but not in the lectures by Dr. A.
UserIdTAG: 1359572
UserNameTAG: gabe0727
CreateTimeTAG: 2013-03-15T17:26:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Did you watch the lectures from week 2, section 4?
There are several videos/lectures in every section, which you can access either by clicking on the little video tape signs (on top of the video) or through the arrows on the bottom.
Also: you posted your question in the discussion forum on Exercise Set 1; by posting in the correct discussion forum, you increase your chances of getting an answer.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-15T17:41:31Z
FirstChildVoteTAG: 0
IndexTAG: 832
TitleTAG: Exercise 5-6
I do not understand how this exercise works :-(. can anybody explain where we can find the SD, please ?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-15T17:12:15Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 3
FirstChildTAG: I could not understand either, how the SD of the multi-variable plot was calculated? Ir was not explain any where.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-15T17:22:57Z
FirstChildVoteTAG: 0
SecondChildTAG: Subtract 1.10 from mean and divide by SD.
3.23-1.10=2.13 and then 2.13/0.40=5.325
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-15T19:23:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Where did 0.40 come from?
SecondChildUserIdTAG: 1224506
SecondChildUserNameTAG: debradley
SecondChildCreateTimeTAG: 2013-03-16T13:52:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Click the button "Univariate Stats" below the scatterplot, and search the SD in "Undergrad. GPA"
SecondChildUserIdTAG: 1081098
SecondChildUserNameTAG: BrilloBox
SecondChildCreateTimeTAG: 2013-03-18T19:01:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Use the SD applet at
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T18:32:08Z
FirstChildVoteTAG: 0
SecondChildTAG: I think thats a bad idea, because the GPA histogram is pretty skewed. But, in fact, all SD's are given in the app of Exercise 5.6. Just click on the 'Univariate Stats' button.
SecondChildUserIdTAG: 365465
SecondChildUserNameTAG: Vzzzz
SecondChildCreateTimeTAG: 2013-03-15T18:47:32Z
SecondChildVoteTAG: 0
FirstChildTAG: My problem is to get the x-co-ordinate of the mean one has to place the mouse over it. i did it 4 times and got 4 different answers and only one of them subsequently gave the correct answer (range). The x,y co-ordinates of the mean should be given otherwise very iffy, mark
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
FirstChildCreateTimeTAG: 2013-03-16T23:27:46Z
FirstChildVoteTAG: 0
SecondChildTAG: My mouse is doing the same thing!
SecondChildUserIdTAG: 1292868
SecondChildUserNameTAG: SandyL
SecondChildCreateTimeTAG: 2013-03-20T21:49:42Z
SecondChildVoteTAG: 0
IndexTAG: 833
TitleTAG: Exercise 8 Problem 1c
PROBLEM 1C : 2.0 POINTS
Approximately what percent of the adults are 70 inches tall, to the nearest inch? Please don't enter the percent sign.
incorrect 4.5
EXPLANATION
Adults that are 70 inches tall to the nearest inch have heights ranging from 69.5 to 70.5. In standard units,(69.5 - 66)/2.5 = 1.4; (70.5 - 66)2.5 = 1.8. Enter these z-values into the lower and upper endpoints respectively to find that the area is equal to 4.48%.
After seeing the explanation, I still don't understand why it has to be 69.5 and 70.5? Why can't it be 69.6 or 70.4? Can someone tell me why?
UserIdTAG: 861599
UserNameTAG: Nam2point0
CreateTimeTAG: 2013-03-15T17:02:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The range 69.6-70.4 includes some, but not all of the hights that will be rounded to 70. The complete intervall of hights ranges from 69.5 to 70.499999: this invervall includes ALL numbers that will be rounded to 70.
If you look in the discussion forum on Exercise Set 8, there are plenty of threads on the question, e.g. this one:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_8/threads/513ca3e4e8c8242700000186
If you post in the forum on Exercise Set 8, other students who have the same question (or an answer to your question) are more likely to find it.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-15T17:13:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-03-15T17:21:19Z
SecondChildVoteTAG: 0
SecondChildTAG: It's just a matter of rounding. What is the smallest number which would round up to 70? 69.5. What is the largest which will round down? 70.5 (let's not get involved in the arguments about which way 0.5s round, it doesn't make any difference in this data set).
I'm not sure why so many people are having difficulty with this question wording, perhaps it's just down to language.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-15T21:01:10Z
SecondChildVoteTAG: 0
SecondChildTAG: For me the wording was definitely difficult (English is not my mother tongue), but I was happy to learn its meaning.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-16T00:01:13Z
SecondChildVoteTAG: 0
IndexTAG: 834
TitleTAG: Problem 1
I did not understand it. I got the answer wrong. Any pointers to which video or lecture I should read to understand the problem.
UserIdTAG: 172382
UserNameTAG: Padmini
CreateTimeTAG: 2013-03-15T16:22:39Z
VoteTAG: 4
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 2
FirstChildTAG: Lecture 7.3 is covering it.
FirstChildUserIdTAG: 1284250
FirstChildUserNameTAG: kurig
FirstChildCreateTimeTAG: 2013-03-15T22:46:41Z
FirstChildVoteTAG: 5
FirstChildTAG: A bit of algebra over the regression equation combined with reasoning about percentiles can confirm the right intuition for this kind of problem.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-17T01:06:39Z
FirstChildVoteTAG: 1
IndexTAG: 835
TitleTAG: Help me please
what is the z-score for 99th percentile?
UserIdTAG: 1172999
UserNameTAG: Anastasiya145
CreateTimeTAG: 2013-03-15T15:58:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-15T15:59:29Z
FirstChildVoteTAG: 0
SecondChildTAG: i don't undestand, how it works, can you help me please or write what is the z-score for 99th percentile
SecondChildUserIdTAG: 1172999
SecondChildUserNameTAG: Anastasiya145
SecondChildCreateTimeTAG: 2013-03-15T16:52:35Z
SecondChildVoteTAG: 0
SecondChildTAG: > or write what is the z-score for 99th percentile
What would be the point of simply giving you an answer?
To get the number for any percentile just drag the left slider all the way to the low end. Drag the right slider until the area under the curve shows 90%. Read off z.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-15T21:04:11Z
SecondChildVoteTAG: 0
SecondChildTAG: So if you noticed so far we have been taught only to compute percentiles using histograms. It is because it is easier to compute percentiles when you make the assumptions that simplify computation/understanding. Histograms assume that within each class interval the distribution of data is uniform.
I am guessing that you would have to use Calculus Integration to compute the percentiles inside normal curves.
This is why this class gives you that UI posted by MarianW above to help you compute the percentiles.
Hope I haven't added more to your confusion :-). All the best.
SecondChildUserIdTAG: 305272
SecondChildUserNameTAG: shekharshan
SecondChildCreateTimeTAG: 2013-03-15T21:04:43Z
SecondChildVoteTAG: 0
IndexTAG: 836
TitleTAG: 5-6
Why is it 5.3-5.4 SD-s below? With 1 as value for outlier I got 5.75. With 1.2 as value for outlier I got 5.075.
UserIdTAG: 1081293
UserNameTAG: GorGrigoryan
CreateTimeTAG: 2013-03-15T15:39:57Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 3
FirstChildTAG: how did you calculate, anyway. I was unable to find out. Please help me.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-15T17:42:26Z
FirstChildVoteTAG: 1
SecondChildTAG: Subtract 1.10 from mean and divide by SD. 3.23-1.10=2.13 and then 2.13/0.40=5.325
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-15T19:25:43Z
SecondChildVoteTAG: 0
SecondChildTAG: thanx TheodoraCh
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-16T16:54:32Z
SecondChildVoteTAG: 0
SecondChildTAG: How did u know that SD is .4???
SecondChildUserIdTAG: 1048539
SecondChildUserNameTAG: Reham1989
SecondChildCreateTimeTAG: 2013-03-18T19:07:52Z
SecondChildVoteTAG: 0
SecondChildTAG: ahaaa I got it .. thanks
SecondChildUserIdTAG: 1048539
SecondChildUserNameTAG: Reham1989
SecondChildCreateTimeTAG: 2013-03-18T19:09:17Z
SecondChildVoteTAG: 0
FirstChildTAG: The scatterplot, which I see, begins at 1.1 =)
With this one you get roughly 5.325
FirstChildUserIdTAG: 365465
FirstChildUserNameTAG: Vzzzz
FirstChildCreateTimeTAG: 2013-03-15T18:51:14Z
FirstChildVoteTAG: 0
SecondChildTAG: There's no scale at the minimum end of the x-axis, it looks like 1.00 and since the outlier is on the limit I certainly did and theodore i assume assumed the value was 1.0 which gave an incorrect calculation, SOMETHING TO WATCH IN FUTURE, mark
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-16T23:34:25Z
SecondChildVoteTAG: 0
FirstChildTAG: I see. Thanks.
FirstChildUserIdTAG: 1081293
FirstChildUserNameTAG: GorGrigoryan
FirstChildCreateTimeTAG: 2013-03-16T04:16:22Z
FirstChildVoteTAG: 0
IndexTAG: 837
TitleTAG: Where are the solutions to the Midterm?
Midterm Solutions.
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-15T15:13:37Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: There's a "Show Answer" button beneath each question in the midterm. Click on "Show Answer," and you'll see the solution and a brief explanation.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-15T16:53:45Z
FirstChildVoteTAG: 1
IndexTAG: 838
TitleTAG: Problem 3
You are right, it have been hard.
But I loved reading problem 3! ;-)
UserIdTAG: 1323430
UserNameTAG: apons
CreateTimeTAG: 2013-03-15T15:10:26Z
VoteTAG: 30
CoursewareTAG: Exercise Set 11 / Exercise Set 11
NumberOfReplyTAG: 5
FirstChildTAG: The best question so far!
FirstChildUserIdTAG: 886442
FirstChildUserNameTAG: ismail23us
FirstChildCreateTimeTAG: 2013-03-16T14:25:14Z
FirstChildVoteTAG: 2
SecondChildTAG: ahhhhhhhhhh
this is the worst. I do not understand the english term
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-03-16T15:38:07Z
SecondChildVoteTAG: 0
SecondChildTAG: I wonder what will happen if we tick only one. Couldn't try since we had only one submission!!!!!!
SecondChildUserIdTAG: 1263723
SecondChildUserNameTAG: Chamikad
SecondChildCreateTimeTAG: 2013-03-19T17:50:19Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks alot prof for this Q ;)
FirstChildUserIdTAG: 1288142
FirstChildUserNameTAG: aldawlah
FirstChildCreateTimeTAG: 2013-03-17T04:44:47Z
FirstChildVoteTAG: 1
FirstChildTAG: But did anyone get Problem 3 wrong?
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-17T11:25:15Z
FirstChildVoteTAG: 1
SecondChildTAG: yes
SecondChildUserIdTAG: 694631
SecondChildUserNameTAG: wafaztaha
SecondChildCreateTimeTAG: 2013-03-17T13:03:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Got it wrong :/
SecondChildUserIdTAG: 609882
SecondChildUserNameTAG: ivojulca
SecondChildCreateTimeTAG: 2013-03-18T19:05:40Z
SecondChildVoteTAG: 0
SecondChildTAG: yeah, some of us did :)
SecondChildUserIdTAG: 1247551
SecondChildUserNameTAG: Yanichka
SecondChildCreateTimeTAG: 2013-03-19T11:32:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes I got it wrong :(
SecondChildUserIdTAG: 1227082
SecondChildUserNameTAG: LauraPinillos
SecondChildCreateTimeTAG: 2013-03-19T13:20:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Those who did it wrong are genius :) not because you did not answer correctly, but because you tried differently.
SecondChildUserIdTAG: 1111783
SecondChildUserNameTAG: irfans011
SecondChildCreateTimeTAG: 2013-03-20T12:58:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Perhaps 0.4% of us are likely to get it wrong. Well just kidding. But thanks for this bonus question.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-03-17T18:14:32Z
FirstChildVoteTAG: 3
SecondChildTAG: it stated check both, so no means to tick only one!
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-19T18:50:53Z
SecondChildVoteTAG: 0
FirstChildTAG: This really was wonderful. You're all tense, scrolling down to see what's next, and then you see Problem 3. :) A lovely touch, and a great way to finish off this week, thank you so much!
FirstChildUserIdTAG: 230828
FirstChildUserNameTAG: alanis
FirstChildCreateTimeTAG: 2013-03-17T22:37:36Z
FirstChildVoteTAG: 5
IndexTAG: 839
TitleTAG: Course data
Is there any data about the participation on this course?
I'd be interested to know:
How many people registered, how many completed the first week's assignment, all the assignments so far, the midterm etc.
I imagine lots of people registered but progressively fewer and fewer pass these milestones.
Is this data published?
UserIdTAG: 901827
UserNameTAG: clv101
CreateTimeTAG: 2013-03-15T14:55:05Z
VoteTAG: 15
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I don't know exactly, but this information is sometimes given after the finish of the course.
FirstChildUserIdTAG: 1309661
FirstChildUserNameTAG: Grammer
FirstChildCreateTimeTAG: 2013-03-15T16:40:48Z
FirstChildVoteTAG: 0
FirstChildTAG: While Midterm Average is OK, I'd also like to know the SD, and/or the mean and quartiles. ;-)
FirstChildUserIdTAG: 1231805
FirstChildUserNameTAG: kimbro
FirstChildCreateTimeTAG: 2013-03-18T04:17:08Z
FirstChildVoteTAG: 0
IndexTAG: 840
TitleTAG: Where is the applet???
Can anybody paste a link to the "Applet" to address Problem 2A and 2B?
UserIdTAG: 1149486
UserNameTAG: lhenriquez
CreateTimeTAG: 2013-03-15T14:31:54Z
VoteTAG: 3
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 1
FirstChildTAG: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1149486
FirstChildUserNameTAG: lhenriquez
FirstChildCreateTimeTAG: 2013-03-15T14:41:51Z
FirstChildVoteTAG: 4
SecondChildTAG: Thanks to me!!!
SecondChildUserIdTAG: 1149486
SecondChildUserNameTAG: lhenriquez
SecondChildCreateTimeTAG: 2013-03-15T14:42:02Z
SecondChildVoteTAG: 0
SecondChildTAG: You could also always retrieved it from the "book's" webpage, under menu/tools and demos/normal probabilities (Top left corner).
SecondChildUserIdTAG: 902345
SecondChildUserNameTAG: phidesigner
SecondChildCreateTimeTAG: 2013-03-18T11:05:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I find the following calculator much easier to use than the textbook tools - you select z value or percentile from the drop-down menu:
[http://www.computerpsych.com/Research_Software/NormDist/Online/Normal_Curve][1]
[1]: http://www.computerpsych.com/Research_Software/NormDist/Online/Normal_Curve
SecondChildUserIdTAG: 958344
SecondChildUserNameTAG: 314
SecondChildCreateTimeTAG: 2013-03-20T01:47:45Z
SecondChildVoteTAG: 0
IndexTAG: 841
TitleTAG: Slides please!
this pdf is not loading.
UserIdTAG: 541148
UserNameTAG: Kattimani
CreateTimeTAG: 2013-03-15T14:22:01Z
VoteTAG: 0
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 0
IndexTAG: 842
TitleTAG: Staff; A little confused
In this lecture you have said association is not causation, which I agree to some extent because I think it depends on the variable in question. For example looking at the two variables used in lecture 6.2 Height and weight and I want to examine the relationship between the two which I believe one causes the other. I put height on x-axis and weight on y-axis, the positive correlation will imply as the height increases it leads to an increase in weight and vice versa. That is height affects weight. However when I switch the variables so that weight (x-axis) and height (y-axis. how do you interprete the positive correlation? Increase in weight leads to increase in height?
UserIdTAG: 422336
UserNameTAG: lilian2012
CreateTimeTAG: 2013-03-15T14:15:21Z
VoteTAG: 1
CoursewareTAG: Section 6: Relation between two variables / Lec 6.3: Using r: with caution!
NumberOfReplyTAG: 1
FirstChildTAG: If you are heavy, you are *more likely* to be tall. That's positive correlation. You might be short & fat, you might be avearge height & chubby but on the whole, depending on the strength of the correlation, you'll be taller than someone lighter.
(And, as you say, to make the jump from that to "you are tall because you are heavy" is to assume causation from correlation - and that you can't do. It's not that the height leads to an increas and vice versa, it's that you are observing taller people tend to be heavier.)
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-15T14:24:49Z
FirstChildVoteTAG: 1
SecondChildTAG: I somehow feel there is some degree of *causation* between this two variables, but that term causation has always been fuzzy to me.
I got confused when Professor said variables can be interchanged. How do we interprete? For example, measuring the heights and
weights of a child/en over a period of time say 3 years. With height (x-axis) and weight (y-axis). The **general** trend will be as the heights of the children increase over a period of time so will their weights, my argument is the increase in height leads to increase in weight or increase in height influences increase in weight . **But not** increase in weight leads to increase in height when the variables are interchanged.
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-15T15:35:55Z
SecondChildVoteTAG: 0
SecondChildTAG: mmmm... what we're doing at the moment is descriptive stats - so for example looking at a set of weights and heights for 100 children aged 5. and if we plot that on a scatter plot we might be able to see a straight line relationship, and we can calculate r to see how strong that correlation is. For that purpose you can plot height against weight, or weight against height. r is the same, and from the data alone you know nothing about causation.
What you're talking about - measuring two variables over time and looking for correlation / causation there - I *think* is getting into analysis of time-series. But I might be talking nonsense so I'll shut up now.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-15T15:58:24Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem is that neither variable is independent. Will taller people be heavier - oh, course, assuming similar build. Will heavier people be taller - again, of course, given the same build, a heavier person must be taller. Is there as causal link? Far more difficult to answer and not necessarily amenable solely to statistical analysis. If you have an hypothesis to explain a causal link then you can explore the data and see if you can isolate the relationship. Incidentally, heavier children do tend to be taller - both are actually cause by change in diet (comparing now with 50 years ago, children are both more heavily built and taller).
It is far easier if you have an independent variable. If you considered, say, boys and girls of the same age and build and found that girls were heavier then you could certainly say that gender influenced weight as the link could not be in the opposite direction - weight doesn't determine gender
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-15T16:28:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I deliberately avoided the use of dependent and independent variables, but actually thats what I had in mind when talking about the X and Y axis. Thanks MarianW and PaulJM, for your helpfull insights
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-15T22:28:47Z
SecondChildVoteTAG: 0
IndexTAG: 843
TitleTAG: Missed the Mid-term
Hi,
I missed the mid-term due to an unfortunately timed meeting and travel arrangements. Is there any point continuing with the course? Can anyone give some helpful direction?
Thanks,
SH
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-15T14:12:28Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Read the course info. You only need 35% to pass. If you do the exercise assignments, you can probably still make it. Good luck and have fun!
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-15T14:15:40Z
FirstChildVoteTAG: 2
FirstChildTAG: Of course it's worth continuing, you're still going to learn the material irrespective of passing the exam. I would recommend doing the midterm off-line for the practice and to see how you're doing.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-03-15T14:22:33Z
FirstChildVoteTAG: 6
FirstChildTAG: there is still hope cuz the final is a chunky 30%.
FirstChildUserIdTAG: 1264070
FirstChildUserNameTAG: XenDavid
FirstChildCreateTimeTAG: 2013-03-15T15:22:05Z
FirstChildVoteTAG: 1
FirstChildTAG: Hi,
Can't believe it too. I also missed the mid term. Does this disqualify me from the course?
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-03-15T20:00:02Z
FirstChildVoteTAG: 0
FirstChildTAG: A big value of this course is gaining the knowledge and learning from the experience of Prof and her assistants. Therefore it is worth continuing. And as someone else said above, one can pass by doing well on other exams.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-03-15T20:16:28Z
FirstChildVoteTAG: 2
IndexTAG: 844
TitleTAG: Midterm problem 1b
I have calculated again and again. The Sd=3.779. Then why is 3.8 being marked wrong. Can someone please help me understand?
UserIdTAG: 1149334
UserNameTAG: NitinJindal
CreateTimeTAG: 2013-03-15T14:03:15Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: You must have taken n-1 in the formula...that's why you went wrong.
FirstChildUserIdTAG: 1057432
FirstChildUserNameTAG: achalrm
FirstChildCreateTimeTAG: 2013-03-15T14:04:53Z
FirstChildVoteTAG: 1
SecondChildTAG: But during the course wasn't it stressed again and again the for Sd the formula being followed is with n and not n-1? Am I missing something?
SecondChildUserIdTAG: 1149334
SecondChildUserNameTAG: NitinJindal
SecondChildCreateTimeTAG: 2013-03-15T14:07:05Z
SecondChildVoteTAG: 0
SecondChildTAG: During one of the lectures Prof. A. made it clear "don't use n-1" . Which one you used?
SecondChildUserIdTAG: 1247915
SecondChildUserNameTAG: Iliri2013
SecondChildCreateTimeTAG: 2013-03-15T14:09:55Z
SecondChildVoteTAG: 0
SecondChildTAG: We use n-1 when we are having a sample of the entire population. For example, the presidential polls. The pollsters only ask a couple thousand people (Sample) to represent the whole population of 300 million people. They would use n-1.
In this course, everything we do involve an entire population so we don't use n-1.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-03-15T17:14:29Z
SecondChildVoteTAG: 0
FirstChildTAG: There's no confidence that we shouldn't consider the list of numbers as population.
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-15T14:14:26Z
FirstChildVoteTAG: 0
FirstChildTAG: I selected 3.8 as well. I did the calculations by hand and arrived at 3.499 something. The I verified my results with Excel (stdev) and R (sd) and came up with 3.779. Two out of three so I went with 3.8.
I forgot the population v. sample. In Excel (stdevp) produces 3.499. R does have ab organic sd for population.
FirstChildUserIdTAG: 876324
FirstChildUserNameTAG: BrianDeering
FirstChildCreateTimeTAG: 2013-03-15T15:19:00Z
FirstChildVoteTAG: 0
SecondChildTAG: That's why it is better to stick with hand calculation if you are not 100% sure that you understand how the tools you are using work. It was the work of a couple of minutes to calculate the SD from first principles using pen, paper and calculator. Since the answer I got matched one of the options that was good enough for me.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-15T16:30:39Z
SecondChildVoteTAG: 0
SecondChildTAG: For me I use Octave (an open-source version of MATLAB) and I wrote my own function SD(data) that finds the standard deviation with n instead of n-1, but I made the mistake of first using the built in function of std(data) instead.
If I had stuck with my homemade function I would have gotten the correct answer.
The built in function sdt(data) gave me 3.7796, and my homemade function SD(data) gave me 3.4993.
I guess I really should stick to writing my own functions more. (at least for when I understand the algorithm for the function I am writing)
SecondChildUserIdTAG: 151933
SecondChildUserNameTAG: WildW1ill
SecondChildCreateTimeTAG: 2013-03-16T19:36:04Z
SecondChildVoteTAG: 0
FirstChildTAG: when should I use n and n-1 in SD calculations? which is the difference?
FirstChildUserIdTAG: 1134470
FirstChildUserNameTAG: cpaula
FirstChildCreateTimeTAG: 2013-03-15T20:27:12Z
FirstChildVoteTAG: 0
SecondChildTAG: If the data is complete (population) then you use n. But when your data is just a sample of the complete data then you use n-1.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-15T21:16:18Z
SecondChildVoteTAG: 0
FirstChildTAG: I wish I had not lost 2 points on this but the lesson that I learned is worth much more than 2 points. When the Prof said the problem was behaving as it should I knew that I must be wrong somewhere.
And I was.
Trusted the tool too much without knowing the nuances. Due to this problem now I know that R and Excel use (n-1) for calculating SD.
Tools are good but while using them it is always better to know what they are doing.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-03-15T21:34:48Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-03-15T21:37:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed, lesson learned with some irritation.
SecondChildUserIdTAG: 78038
SecondChildUserNameTAG: subz
SecondChildCreateTimeTAG: 2013-03-16T17:36:33Z
SecondChildVoteTAG: 0
FirstChildTAG:
$$data=[d_1,d_2,d_3,d_4,d_5]=[33, 38, 40, 41, 38, 45, 42]$$
$$\mu = \frac{d_1+d_2+d_3+d_4+d_5}{n} = 39.571$$
$$\sigma=\sqrt{\frac{(\mu-d_1)+(\mu-d_1)+(\mu-d_1)+(\mu-d_1)+(\mu-d_1)}{n}}=3.4993$$
I made the mistake of using $n-1$ in finding $\sigma$ instead of using $n$ Too bad we didn't get two tries to this problem.
FirstChildUserIdTAG: 151933
FirstChildUserNameTAG: WildW1ill
FirstChildCreateTimeTAG: 2013-03-16T19:10:06Z
FirstChildVoteTAG: 0
IndexTAG: 845
TitleTAG: Questions on Exam - 2B, 3B and 4B
I got the following incorrect: 2B, 3B, 4B. Can somebody show me how to solve them correctly?
Problem 2B : 2.0 points
Estimate the 80th percentile of the distribution of times, in hours; give the best estimate you can, based on the information in the problem. Please do not enter units of measurement.
incorrect .23
Problem 3B : 2.0 points
Approximately 50% of the eggs have lengths in the range 32 mm plus or minus ____________ mm. .56
incorrect .56
Problem 4B : 2.0 points
The SD of scores of all the students in the class
a) is equal to 9. b) is less than 9. c) is greater than 9. d) cannot be placed relative to 9 based on the information given.
Pick the best option. incorrect D
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-15T13:52:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I also got 4b incorrect because I assumed the sd would be the same, forgetting that its the difference from the combined average that we're calculating. Since the deviations will be larger from a common mean I'm assuming that would drive the SD up and it would be greater than 9.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-03-15T14:18:12Z
FirstChildVoteTAG: 1
SecondChildTAG: calculate you will get around 11.xxx
Answer is GREATER THAN 9
SecondChildUserIdTAG: 273912
SecondChildUserNameTAG: raj2691
SecondChildCreateTimeTAG: 2013-03-15T14:24:18Z
SecondChildVoteTAG: 0
SecondChildTAG: How do we calculate the SD from a common mean when combining data? I don't remember this being covered. I pretty much guessed the right answer using the same reasoning as Jeff2012s rethink.
SecondChildUserIdTAG: 23266
SecondChildUserNameTAG: dnc
SecondChildCreateTimeTAG: 2013-03-15T21:11:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Question 2B: 14.67
Question 3B: 0.81
FirstChildUserIdTAG: 343755
FirstChildUserNameTAG: Covadonga
FirstChildCreateTimeTAG: 2013-03-15T14:34:35Z
FirstChildVoteTAG: 0
SecondChildTAG: How did you get 14.67 and 0.81?
SecondChildUserIdTAG: 277481
SecondChildUserNameTAG: scott520
SecondChildCreateTimeTAG: 2013-03-15T15:12:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Using the information that 0 SD = 50 percent. To me it seems you are stating that 50% of the eggs would have a length equal to the mean itself (no standard deviation). Using the applet only reinforces this concept. What calculation did you use to get 0.81? Thanks in advance.
SecondChildUserIdTAG: 1071900
SecondChildUserNameTAG: aortiz
SecondChildCreateTimeTAG: 2013-03-15T15:21:00Z
SecondChildVoteTAG: 0
SecondChildTAG: This is how I solved 3B. With the applet, since the mean was 32 and they wanted 50% around the mean, I measured 50.03%. The upperbound was .675 and the lowerbound was -0.675. This is the Z score. I took 0.675 * 1.2 (SD)= 0.81. Somehow I calculated it wrong. I had the correct logic but the incorrect answer.
SecondChildUserIdTAG: 277481
SecondChildUserNameTAG: scott520
SecondChildCreateTimeTAG: 2013-03-15T15:29:08Z
SecondChildVoteTAG: 0
SecondChildTAG: With 2B, the range was from 0-28. So I took .80 * 28 which is 22.4. How did you get 14.67?
SecondChildUserIdTAG: 277481
SecondChildUserNameTAG: scott520
SecondChildCreateTimeTAG: 2013-03-15T15:32:12Z
SecondChildVoteTAG: 0
FirstChildTAG: I got problem 4b wrong also. This only means that I still haven't fully conceptualize the SD yet. Need to rewatch the lecture videos on the SD.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-15T17:10:45Z
FirstChildVoteTAG: 0
IndexTAG: 846
TitleTAG: please i want an advice
i have just joined recently and i will try my best to be ready for the final exam with the rest of students, but i didn't do the midterm, how can i get a certificate?
can be there other exam for people who are late?
UserIdTAG: 1359374
UserNameTAG: maenassali
CreateTimeTAG: 2013-03-15T13:49:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: If you are good/lucky enough, you will get 50%*(4*100%)/(10*100%) from ES 9 to ES 12, in addition with 30%*100%*1 from the final.
Just try whatever you can do to make that happen.
Good luck and have fun!
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-15T13:59:57Z
FirstChildVoteTAG: 2
FirstChildTAG: And what does the certificate really mean anyway? We're really here to learn statistics aren't we? You can take midterm off-line for practice and to see how you're doing.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-03-15T14:25:19Z
FirstChildVoteTAG: 3
IndexTAG: 847
TitleTAG: Mid term exam solutions
Will the solutions to the Mid term exam be posted? I'd like to see the logic behind the answer to question 5. Many Thanks!
UserIdTAG: 1329223
UserNameTAG: green_geoff
CreateTimeTAG: 2013-03-15T13:24:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: I'd like to see the explanation to the last 2 questions!
FirstChildUserIdTAG: 895825
FirstChildUserNameTAG: JGonzalezGUS
FirstChildCreateTimeTAG: 2013-03-15T13:30:27Z
FirstChildVoteTAG: 0
FirstChildTAG: There's a good thread (title "midterm problem 5") that has a good explanation of question 5 part way down. Basically the distribution violates Chebyshev's principle. For example, there can't even be one entry in a list of 100 with z=11.
FirstChildUserIdTAG: 174100
FirstChildUserNameTAG: markpolak
FirstChildCreateTimeTAG: 2013-03-15T13:39:38Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks for that Mark.
FirstChildUserIdTAG: 1329223
FirstChildUserNameTAG: green_geoff
FirstChildCreateTimeTAG: 2013-03-15T13:42:51Z
FirstChildVoteTAG: 0
FirstChildTAG: You can see midterm solutions by clicking on the "Show Answer" button underneath each question on the midterm.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-15T16:57:00Z
FirstChildVoteTAG: 1
IndexTAG: 848
TitleTAG: Is ES10 2a being graded correctly ? - RESOLVED
I have checked and rechecked my answer for problem 2a, and I can't see what I did wrong. I use four decimal places in my answer, perhaps I would get it right if I rounded up to the nearest integer, but I dare not waste my second try.
I had no problem with 2b, so I know how to do this type of problem.
There is clearly an error in a similar problem in the practice exercises, and a discussion thread is already open.
How are others doing?
RESOLUTION- Based on Duggi's comments below I resubmitted my original answer and got a green check mark. The problem appears to be fixed.
UserIdTAG: 174100
UserNameTAG: markpolak
CreateTimeTAG: 2013-03-15T13:17:30Z
VoteTAG: 8
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 3
FirstChildTAG: Even I have the same problem.
FirstChildUserIdTAG: 889766
FirstChildUserNameTAG: AvinashKG
FirstChildCreateTimeTAG: 2013-03-15T14:42:21Z
FirstChildVoteTAG: 0
FirstChildTAG: I had no problem, I got it right the first time
FirstChildUserIdTAG: 1218819
FirstChildUserNameTAG: duggi
FirstChildCreateTimeTAG: 2013-03-15T14:46:49Z
FirstChildVoteTAG: 0
SecondChildTAG: In this post https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/51430863250bed27000000cd
the calculation is described. He is solving the problem the same way I did. Is there something we're doing wrong?
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-03-15T15:01:05Z
SecondChildVoteTAG: 0
SecondChildTAG: you have to convert 0.8328 into percitile using the applet
SecondChildUserIdTAG: 1218819
SecondChildUserNameTAG: duggi
SecondChildCreateTimeTAG: 2013-03-15T16:29:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Duggi,
I did do the conversion, but your comments have given me the courage to retry. I just hit final check without changing my original answer, and got a green check mark. I think there was a problem, and it has been fixed silently by the staff.
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-03-15T16:46:50Z
SecondChildVoteTAG: 0
SecondChildTAG: please tell me how to convert 0.8328 into percentile
SecondChildUserIdTAG: 319801
SecondChildUserNameTAG: catch_minie
SecondChildCreateTimeTAG: 2013-03-20T10:35:54Z
SecondChildVoteTAG: 0
FirstChildTAG: I have this problem too.. I have used both my attempts.. i have been marked wrong for the solution for 2A. I have followed the same method for 2B and got the right answer. Surely there is a bug there that needs to be fixed. I hope the Admin looks into it :/
FirstChildUserIdTAG: 1081147
FirstChildUserNameTAG: SruthiS
FirstChildCreateTimeTAG: 2013-03-18T11:14:26Z
FirstChildVoteTAG: 0
SecondChildTAG: I have the same problem at 2A... Is it a bug or something we missed?
SecondChildUserIdTAG: 1003753
SecondChildUserNameTAG: danatudorica
SecondChildCreateTimeTAG: 2013-03-18T12:50:10Z
SecondChildVoteTAG: 0
IndexTAG: 849
TitleTAG: Exercise Set 9
Problem 2 on Exercise Set 9, has says "In what follows, fill in the blank; if you think there is not enough information to answer the question, enter NA." However, if I put NA and submit, it says that this is an "invalid input." Is anyone else having this problem? And is there a solution?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-15T13:04:11Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: Having the same problem here
FirstChildUserIdTAG: 1256931
FirstChildUserNameTAG: Jhoara
FirstChildCreateTimeTAG: 2013-03-15T13:15:55Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too, there is no info to calculate it
FirstChildUserIdTAG: 1386867
FirstChildUserNameTAG: Carlos12
FirstChildCreateTimeTAG: 2013-03-15T13:29:05Z
FirstChildVoteTAG: 0
FirstChildTAG: I just list all the numbers and did the math, and seems both answer to problem 2 are not NA.
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-15T13:39:29Z
FirstChildVoteTAG: 1
FirstChildTAG: Don't overthink it.The answer is not so mathematical as commonsense
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T16:32:47Z
FirstChildVoteTAG: 0
FirstChildTAG: Draw a picture, first, to see what's really going on. As soon as I did that, the answers became quite clear. If you can draw it, you are more than halfway to solving it.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-15T18:46:57Z
FirstChildVoteTAG: 0
FirstChildTAG: Chapter 7 may help
http://statistics.berkeley.edu/~stark/SticiGui/Text/correlation.htm
FirstChildUserIdTAG: 99916
FirstChildUserNameTAG: Renauld
FirstChildCreateTimeTAG: 2013-03-16T06:54:46Z
FirstChildVoteTAG: 0
IndexTAG: 850
TitleTAG: Exercise 9
Hello all,
How can we answer problem 2A and 2B to find the correlation without data given in the problem??????????
UserIdTAG: 992597
UserNameTAG: Drhannaa
CreateTimeTAG: 2013-03-15T13:02:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: It's one of those problems that require thought and understanding rather than calculation.
FirstChildUserIdTAG: 1289355
FirstChildUserNameTAG: DaRitz
FirstChildCreateTimeTAG: 2013-03-15T16:28:02Z
FirstChildVoteTAG: 0
FirstChildTAG: Chapter 7 may help
http://statistics.berkeley.edu/~stark/SticiGui/Text/correlation.htm
FirstChildUserIdTAG: 99916
FirstChildUserNameTAG: Renauld
FirstChildCreateTimeTAG: 2013-03-16T06:53:51Z
FirstChildVoteTAG: 0
IndexTAG: 851
TitleTAG: Problem 2A and 2B
Can I calculate the 90th and the 40th percentile in problem 2A and 2B without knowing r? I'm not sure.
Please, could you tell me if it's an error?. Maybe I didn't undertand well this section. In any case, please let me know.
UserIdTAG: 1323430
UserNameTAG: apons
CreateTimeTAG: 2013-03-15T12:46:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 10 / Exercise Set 10
NumberOfReplyTAG: 4
FirstChildTAG: The lecture shows how to do it. Use the javascript tool to convert percentile to standard units (or you can use an on-line calculator like this one: http://stattrek.com/online-calculator/normal.aspx).
Once you have x in standard units, you can get y in standard units by using the correlation coefficient. Go back to the java app or the calculator and get y in percentile units.
FirstChildUserIdTAG: 174100
FirstChildUserNameTAG: markpolak
FirstChildCreateTimeTAG: 2013-03-15T13:05:24Z
FirstChildVoteTAG: 2
SecondChildTAG: Watch out though, a few of us think there is a grader issue with problem 2a. Try problem 2b first to see if you have the hang of it.
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-03-15T13:25:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok. I'll try it. Thanks
SecondChildUserIdTAG: 1323430
SecondChildUserNameTAG: apons
SecondChildCreateTimeTAG: 2013-03-15T15:13:41Z
SecondChildVoteTAG: 0
SecondChildTAG: NIce calculator ,thanks
SecondChildUserIdTAG: 1264710
SecondChildUserNameTAG: treemantan
SecondChildCreateTimeTAG: 2013-03-17T07:01:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, very useful calculator.
SecondChildUserIdTAG: 1024935
SecondChildUserNameTAG: N3
SecondChildCreateTimeTAG: 2013-03-18T03:28:26Z
SecondChildVoteTAG: 0
FirstChildTAG: r = 0.65!!!
FirstChildUserIdTAG: 1149486
FirstChildUserNameTAG: lhenriquez
FirstChildCreateTimeTAG: 2013-03-15T14:23:07Z
FirstChildVoteTAG: 1
FirstChildTAG: Am unsure how I ought to use the applet.
FirstChildUserIdTAG: 1256932
FirstChildUserNameTAG: SandeepNarang
FirstChildCreateTimeTAG: 2013-03-16T15:14:55Z
FirstChildVoteTAG: 0
SecondChildTAG: you need to find the standard unit that will have the area to it's left to equal 90% , so you set the left (lower endpoint) to its minimum (-5) and start increasing or decreasing the upper endpoint value until you get that the area selected is as close as you can to 90% than you have the upper endpoint value which represent the standard unit for the 90 percentile.
SecondChildUserIdTAG: 1240022
SecondChildUserNameTAG: Moshiko
SecondChildCreateTimeTAG: 2013-03-16T18:17:41Z
SecondChildVoteTAG: 0
SecondChildTAG: If you use this calculator, http://stattrek.com/online-calculator/normal.aspx, you can avoid the playing around you need to do with the applet, and simply translate z to percentile and back again.
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-03-16T20:35:36Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes as long as vwe know that it's roughly football shaped that's all we need for this...
FirstChildUserIdTAG: 1258683
FirstChildUserNameTAG: Tshuxx
FirstChildCreateTimeTAG: 2013-03-20T17:20:55Z
FirstChildVoteTAG: 0
IndexTAG: 852
TitleTAG: showing ans
where is prac exrcise ques? and the ans? even in exercise i didn't found the righr ans of which is red marking ,why?
UserIdTAG: 1400928
UserNameTAG: helalrahman
CreateTimeTAG: 2013-03-15T12:16:07Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 0
IndexTAG: 853
TitleTAG: slope and correlation
There is something that is quite unclear to me. If we have a football shape distribution, then we take y=r.x everything in standard units, and we say that it is our approximation. But we have learned earlier that if we switch x and y, then r remains the same. Now, our approximation is x=r.y, or y=x/r. If the first one is a good approximation, then the second one has to be as good?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-15T11:53:47Z
VoteTAG: 2
CoursewareTAG: Section 7a: Regression (Lec 7.1 - 7.2) / Lec 7.2: Regression line: intuition; the equation in standard units; regression estimates
NumberOfReplyTAG: 2
FirstChildTAG: I think (just paraphrasing what I have understood),
X and Y are designations to identify that there are two variables and they can be plotted as scatter plot their axis can be interchanged which doesnot affect their association. If the relatioship/association is known between them and this relationship (r) follows normal distribution, then one variable can be found from the other variable using the equation,
one variable in standard units=Correlation coefficient **x** second variable in standard units.
As per this argument, your formula's are valid.
FirstChildUserIdTAG: 541148
FirstChildUserNameTAG: Kattimani
FirstChildCreateTimeTAG: 2013-03-15T14:21:11Z
FirstChildVoteTAG: 0
FirstChildTAG: The problem is that you are using "y" to mean two different things.
The regression equation, with everything in standard units, is:
estimate of y = r*x
The other equation is
estimate of x = r*y
The two are not the same. In the first one, you are using the actual values of x to get the estimates of y. In the second, you are using the actual values of y to get the estimates of x. So there are four variables in play, not just two. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-16T04:58:18Z
FirstChildVoteTAG: 3
SecondChildTAG: Like Anonymous, I made the obvious assumption that the regression line was the same when looking at X to estimate Y or vice-versa. Prof. A's explanation makes it clear that there are actually 4 variables, hence two different lines.
However, I like visualizing these kind of concepts on a graph, so I thought about it some more and I think I finally grasped why there are two different regression lines.
Fig. 9-4 of [http://statistics.berkeley.edu/~stark/SticiGui/Text/regression.htm#regression_line][1] shows the regression line in green, and what the textbook calls the "graph of averages", in yellow dots.
These dots are the averages of the Y-values in each vertical slice of the scatterplot: the average Y for a given X. The regression line that helps us estimate Y for a given X passes close to these points.
If you think about the average X-value for a given Y, though, you get different points: the regression line that helps us estimate X for a given Y passes close to those points.
It's not exactly a coincidence that the slopes of these lines are the same in standard units, but it's still a pretty amazing property.
[1]: http://statistics.berkeley.edu/~stark/SticiGui/Text/regression.htm#regression_line
SecondChildUserIdTAG: 1057358
SecondChildUserNameTAG: s_zambelli
SecondChildCreateTimeTAG: 2013-03-19T06:51:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Now that I think about it some more... The "american football shaped" scatterplot is actually a sort of ellipse, with SDx and SDy the horizontal and vertical pseudo-radii.
Does this mean that that "american football shape" becomes a round "rest of the world football" in Standard Units?
SecondChildUserIdTAG: 1057358
SecondChildUserNameTAG: s_zambelli
SecondChildCreateTimeTAG: 2013-03-19T07:09:53Z
SecondChildVoteTAG: 0
IndexTAG: 854
TitleTAG: The Midterm VS. My 1.5 year old boy :-)
So yesterday I decided to take a peek at the exam before going to work. Silly me.. I left the page open. My 1.5 year old decided that he is qualified enough to answer the questions.
He answered two. One he got right, one he got wrong!
He still insists that the one he got wrong is an error on the Prof's end :-)
Way to go Adam! Stats for kids under 2!
UserIdTAG: 919822
UserNameTAG: ArthurBarabash
CreateTimeTAG: 2013-03-15T11:48:46Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Well my Son who is in preuniversity got a go at the paper after I had answered it and he did it in a few minutes !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T12:23:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Now you have to decide if you're going to be upset because he could do it so quickly - or *proud* because he could do it so quickly!
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T12:35:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Well he better to do it more quickly than me ;)A Son has to do better than a Father or else its an insult to the Father :)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T12:45:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Dunno about an insult, but I tell my kids how happy I am they're smarter than I am. :)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T19:25:12Z
SecondChildVoteTAG: 0
SecondChildTAG: "Insult" was used as a jocular play of the father being upset or proud.:)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T20:18:42Z
SecondChildVoteTAG: 0
FirstChildTAG: ArthurBarabash, that could mean two things a)the midterm was too easy, and/or b) your boy is a genious
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-03-15T13:57:01Z
FirstChildVoteTAG: 0
FirstChildTAG: My boy should apply to be a Berkley TA.
He gets paid in Teddy Puffs cereal and toy cars.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-15T14:00:03Z
FirstChildVoteTAG: 0
FirstChildTAG: That's some sophisticated snark there!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-15T18:49:00Z
FirstChildVoteTAG: 1
SecondChildTAG: ?Snark - where - I thought all of the discussion ws in jest - the child must do better than the father though taking the regression to the mean we are probably seeing a myth but opportunities for children are generally more than that for the parents. (Probably also explains why the old adage easy wealth does not stay for more than 3 generations !!)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T20:20:33Z
SecondChildVoteTAG: 0
IndexTAG: 855
TitleTAG: ES 10 2A - done
90th ----> SU(verble) = 1.2812 ----multiply by 0.65----> SU(math) = 0.8328 ----> ?
I typed in my best answer, but the red cross appeared.
Maybe the answer to this question in the system is not right.
----------
I am sorry that I chose a wrong category, but I can't find any place to make a modification now.
----------
The problem has been corrected and I have seen the green check mark.
UserIdTAG: 1409496
UserNameTAG: qhfu
CreateTimeTAG: 2013-03-15T11:39:15Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Sorry, I'm new here and rather confused. I followed your link, but don't see how your 2A relates to the question on the page????????
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-15T11:41:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Updated! sorry for the inconvenience.
SecondChildUserIdTAG: 1409496
SecondChildUserNameTAG: qhfu
SecondChildCreateTimeTAG: 2013-03-15T11:47:03Z
SecondChildVoteTAG: 0
FirstChildTAG: I just started a thread on this topic on the correct page. I get the same solution as you do (although I did not post as many details). Did you try rounding up to the nearest integer?
Also, note that there was an error in the practice exercise for the same type of problem.
FirstChildUserIdTAG: 174100
FirstChildUserNameTAG: markpolak
FirstChildCreateTimeTAG: 2013-03-15T13:24:20Z
FirstChildVoteTAG: 0
SecondChildTAG: Yup, my answer is the nearest integer, and the system gave me a red cross.
As to the other error, the answer of 1A, practice for ES 10, has been corected.
SecondChildUserIdTAG: 1409496
SecondChildUserNameTAG: qhfu
SecondChildCreateTimeTAG: 2013-03-15T13:35:26Z
SecondChildVoteTAG: 0
IndexTAG: 856
TitleTAG: Newly joined
hello guys I joined this course yesterday only ..Can you please tell me how to use applet for finding z-scores?
UserIdTAG: 1422371
UserNameTAG: Neha_me
CreateTimeTAG: 2013-03-15T11:25:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Click on this applet link:
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
Enter the z-score you're looking for, and the graph automatically tells you what area of the curve that z-score includes. Set the upper and lower z values as per the requirement of the problem.
Or else, if you have a % area in mind, slide the bars along to see which z-score that corresponds to.
FirstChildUserIdTAG: 1347279
FirstChildUserNameTAG: VeenaChatti
FirstChildCreateTimeTAG: 2013-03-15T18:30:40Z
FirstChildVoteTAG: 1
IndexTAG: 857
TitleTAG: Exam Results..
When we can see solutions
UserIdTAG: 319801
UserNameTAG: catch_minie
CreateTimeTAG: 2013-03-15T11:03:08Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 858
TitleTAG: midterm Problem 5
So what is the correct answer here? I picked c ("It looks as though something might be wrong with the program, but it’s not possible to be certain based on just 10 out of the 100 results.") which is wrong. Guess b was correct?
However, I think this is highly debatable. Shouldn't be most of the values lie within 3 SDs. A considerable number out of these 10 did not, raising some doubt.
UserIdTAG: 389476
UserNameTAG: Wuddel
CreateTimeTAG: 2013-03-15T10:34:08Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 4
FirstChildTAG: I thought along similar lines; since 68% are within 1 SD, 95% within 2 SD, and 99% within 3 SD, when I saw numbers like -6.8, -11, and 8.1 it just seemed too way off. True, 68%/95%/99% are for a normal distribution, but still... -11 SD ? That's pretty wacky.
So I chose "a) something is definitely wrong with the program"
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-15T11:17:32Z
FirstChildVoteTAG: 1
SecondChildTAG: Yep, I used the same argument too
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-15T11:57:53Z
SecondChildVoteTAG: 0
SecondChildTAG: By random chance a single -11 SD is technically not impossible but very very very less likely (could be an extreme outlier) so a single value point like that could not be used as "evidence" for sure (could have been some single error) but the improbability was based on Chebychev's inequality which shows the mathematical impossibility and not due to "chance"
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T12:28:43Z
SecondChildVoteTAG: 0
SecondChildTAG: yes; if that had been the only outlier it might have been real, but with the others, it seemed almost certain the program wasn't working right.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T12:33:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed but the thing is to be "Sure" not based just on perception and all the more with an incomplete data set.If the other 90 were within 2 SD's apart from this(or worse still within one SD - you would not have been so sure unless you thought of Chebycheff.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T12:48:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Data shows skewdness so normal distribution does not apply.
SecondChildUserIdTAG: 344400
SecondChildUserNameTAG: carlallen
SecondChildCreateTimeTAG: 2013-03-15T12:53:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Chebycheff does not need to have a normal distribution.It applies to **all lists**
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T13:07:10Z
SecondChildVoteTAG: 0
FirstChildTAG: Since the midterms are over and the lock out period is over too- think about it this way -
Chebychev's inequality says that **no more than 1/k^2 of the values can lie K SD away**.
So if you set K at 4.7 SD it would be- around 4.5% cannot have values >=+/-4.7
There are 7 entries in 10 ie at least 7 entries in 100 (ie 7%)more than +/-4.7 SD
so it cannot happen as any list could not have greater than 4.5%
So the program has to be wrong.
It is indeed a nifty question to test knowledge of Chebychev's inequality and I can see potential for its use in forensic application in statistics - someone fudging data could be caught with this !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T11:19:20Z
FirstChildVoteTAG: 5
SecondChildTAG: hello guys I joined this course yesterday only ..Can you please tell me how to use applet for finding z-scores?
SecondChildUserIdTAG: 1422371
SecondChildUserNameTAG: Neha_me
SecondChildCreateTimeTAG: 2013-03-15T11:23:19Z
SecondChildVoteTAG: 0
SecondChildTAG: I simply used the normal curve, the fact that 7 values (70%) were outside ±3 SD's was a red flag something was definately wrong with the programme
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-15T12:07:19Z
SecondChildVoteTAG: 0
SecondChildTAG: You have no idea that it indeed is normal or not.It can be highly skewed.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T13:07:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I approached it a little differently using Chebychev. I focused on the -11 and figured that at most 1/121 of the values could be in this range. That would mean we'd need at least 121 entries in the list. Since we only had 100, there would not be enough to place one that far out and therefore there must have been something wrong with the program.
SecondChildUserIdTAG: 773223
SecondChildUserNameTAG: Andaponte
SecondChildCreateTimeTAG: 2013-03-15T13:41:37Z
SecondChildVoteTAG: 0
SecondChildTAG: One value could be an outlier so I don't think we should totally rely one value.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-15T16:27:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, Prasannasimha! That's a great explanation for how the program **must** be wrong - *proving* it must be wrong, instead of just "pretty darn likely" educated guessing. (at least semi-educated... :)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T21:17:19Z
SecondChildVoteTAG: 0
FirstChildTAG: That question threw me for a loop!.
It's a great question to test understanding of distributions.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-15T11:42:22Z
FirstChildVoteTAG: 0
FirstChildTAG: Y'all are making it harder than it really is. No math was necessary. Consider this statement from the last bullet point on the last slide of the lecture in Week 2, Section 4, "Standard Units":
"The vast majority (at least 8/9) of any list in standard units will be in the range -3 to 3."
When only 3 of 9 of the computed values fall between -3 and 3, you know something is definitely wrong with the program. She even gave us a list of 9!
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-03-15T19:52:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually how was that data obtained - again from Chebychev !! The solution is being done just with the hard points being given to us.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-16T12:56:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Also 3 of 9 given to us is only for 10 it does not mean that the remaining 90 cannot all fall within 3 SD so in essence now 93 of the values can still within 3 SD's so then ?
You have to show the values lying out of the bounds is impossible as the values in the bound are still possible to be 8/9ths given that we have only partial data (7 greater than 4.7 is a fact but wether the remaining 93 are within 3 SD or not is speculation)
There is a subtle difference
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-16T12:59:43Z
SecondChildVoteTAG: 0
IndexTAG: 859
TitleTAG: midterm problem 4B
Did we cover how to determine the SD when combining a group like this? It wasn't familiar at all to me; I looked back and didn't see anything.
I guessed wrong (*stupidly* wrong - after thinking a bit more, I could see how it almost surely *couldn't* still be 9... oh, well...)
According to Wikipedia, the standard deviation of the aggregate of non-overlapping data sets is:
New mean:
![][1]
New standard deviation:
![enter image description here][2]
Yeah, that looks nasty...
But it's not so bad if you take it one step at a time.
If I calculated correctly, the new SD is 10.9915.
So the correct answer for 4B *should be* "C: greater than 9"
But I don't see how we could have known that. Did I miss something during the lectures or the workbook?
[1]: https://edxuploads.s3.amazonaws.com/13633413261343644.png
[2]: https://edxuploads.s3.amazonaws.com/1363341418134369.png
UserIdTAG: 459910
UserNameTAG: AlanJayWeiner
CreateTimeTAG: 2013-03-15T10:05:27Z
VoteTAG: 9
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 7
FirstChildTAG: carefull - the mid term is still open - in practice if not in theory! -
but I agree this was the most testing question - my first instinct was the same as yours, but when you think hard about it it can't be. We haven't covered the maths of how to derive the actual answer, but I think we're encouraged to have a "feel" for how different transformations / combinations will work.
I resorted to playing with numbers in excel to convince myself :)
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-15T10:17:40Z
FirstChildVoteTAG: 0
SecondChildTAG: Wasn't it suppossed to finish 3'29" ago?
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-15T10:29:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Do you really think the midterm is still open? Because then I have to remove my post.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-15T10:32:40Z
SecondChildVoteTAG: 0
SecondChildTAG: I didn't use all of my submissions - when I go back to it to see if the "show answer" buttons have appeared, the check and save buttons are still live.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-15T10:37:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Of course submissions might be blocked later in the system? not about to change a correct answer to find out 'tho!
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-15T10:40:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Midterm *should* be closed - I posted it about 10am GMT; midterm was scheduled to close at 7am GMT on Friday 3/15 (today).
I just looked too - I still see 'Final Check' buttons; I didn't try any just in case it would mess anything up. Pity 4B only allowed one try! :)
I used Excel to calculate the answer, following the formula I posted from Wikipedia. Took a few wrong turns, but I think I finally got it right.
Maybe I can get extra credit for figuring it all out - offset getting 4B wrong... :)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T10:47:54Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm sure you can't assume that the data are non-overlapping.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-15T10:51:26Z
SecondChildVoteTAG: 0
SecondChildTAG: yes, careful ... midterm is still open. I tested by "final checking" my correct answers and the system accepted them again.
SecondChildUserIdTAG: 1091958
SecondChildUserNameTAG: DEnoch
SecondChildCreateTimeTAG: 2013-03-15T11:01:45Z
SecondChildVoteTAG: 0
SecondChildTAG: KatrienJ - If there were, we couldn't calculate the average without knowing the overlap, so we couldn't answer the problem at all.
This could be described as "77 students, section 1 is the first 20, section 2 is the next 25, section 3 is the last 32" - no overlap.
It would be a different case if we said something like "section 1 is the first 20 students, section 2 is the first 25 students, and section three is 32 students starting with the 15th student"
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T11:30:10Z
SecondChildVoteTAG: 0
SecondChildTAG: What do you both (and wikipedia!) mean by overlapping? One interpretation is "no student in more than one data set", another is "no score in more than one data set".
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-15T11:34:17Z
SecondChildVoteTAG: 0
SecondChildTAG: I interpreted non-overlapping wrongly. Thank you for pointing it out, AlanJayWeiner and MarianW. I checked the wikipedia article and non-overlapping refers to the populations, so "no student in more than one data set." This is indeed the case, as explained by AlanJayWeiner.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-15T12:14:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Is it correct to assume that the data is not overlapping?
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-15T10:17:49Z
FirstChildVoteTAG: 0
SecondChildTAG: I also think its not a good assumption, when using the normal curve to identify where most of the values lie, there is high possibility of overlapping. The question was the most challenging though
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-15T10:39:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed. I did not feel very confident when I clicked "Check". Fortunately, I got the right answer and now I am waiting for the answers to see whether the right reasoning lead to the right answer, or wrong reasoning turned out to suggest the right answer :)
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-15T10:49:01Z
SecondChildVoteTAG: 0
SecondChildTAG: (I just answered longer above) If the data did overlap, we couldn't calculate the average without knowing the overlap, so we couldn't even do problem 4A.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T11:32:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, you are right. At first I misunderstood what you are referring to: population or scores.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-15T12:56:55Z
SecondChildVoteTAG: 0
FirstChildTAG: I used the fact that the mean minimizes the Euclidean distance to the data points.
From the on-line textbook, Chapter 4:
"the sum of the squares of the differences between the data and the mean is smaller than the sum of squares of the differences between the data and any other number. (Equivalently, the rms or root mean square of the differences from the mean is smaller than the rms of the list of differences from any other number.)"
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-15T10:29:09Z
FirstChildVoteTAG: 0
SecondChildTAG: so for the hour I spent trying to produce a counter example I was trying to disprove Euclid!
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-15T10:47:04Z
SecondChildVoteTAG: 0
SecondChildTAG: This, plus the fact that the mean of a list is always greater or equal than the minimum of the list. This way, for section 1, section 2 and section 3 separately, the sums of squared deviations from the total mean, S1, S2 and S3, are each separately larger than 9^2 (since the mean minimizes the sum of squared deviations, as cited by you). The mean MU of this list {S1,S2,S3} is larger than the minimum of the list, thus larger than 9^2 => the square root of MU, which equals the standard deviation of the total population, is larger than 9. QED
SecondChildUserIdTAG: 407687
SecondChildUserNameTAG: AndreaPi
SecondChildCreateTimeTAG: 2013-03-18T13:54:04Z
SecondChildVoteTAG: 0
FirstChildTAG: I did think visually of the students like 3 heaps of oranges(the bell curves).Add them all together and make them into one big mound of oranges and you have a bigger heap with a higher center(higher mean - we knew that anyway and well I could squish them down if i wanted and make the base automatically still wider and we knew the mean was not that high ie not that high piled up) and wider base(wider distribution) so the SD has to be larger. I did try to find a mathematical solution and one way to add SD's was to sum the variances (SD^2)and find its square root (since variances can be added).There were other methods also described and so I wasn't very sure which one to apply (sum of SD's, pooled variance etc etc) and since there was a need only for an intuitive answer I clicked greater though with square root of sum of variances it comes to 9sqrt3 which would be approximately 15.8. I got another value with the big formula in wikipedia so anyway I just took the intuitive route as all of them are bigger than 9 anyway.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T12:35:07Z
FirstChildVoteTAG: 3
SecondChildTAG: I used essentially the same process. I used the average from 4A and imagined the problem as a balance beam with the average as the fulcrum, each data point as a weight and, correctly or not, assumed a normal distribution.
The combined effects of the mixing of the section scores had to stretch the range of values therefore, the SD had to increase.
SecondChildUserIdTAG: 876324
SecondChildUserNameTAG: BrianDeering
SecondChildCreateTimeTAG: 2013-03-15T12:40:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Is there a way to write a linear transformation for this problem, as was done for Exercise 6 Problem 3 (the right and wrong answer one)? I tried the formula but couldnt work it out. Then I used an online applet and still got it wrong!
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-15T13:41:03Z
SecondChildVoteTAG: 0
FirstChildTAG: I used a visual method as well. Just plotted the new total average and the 3 class averages and made dotted lines to show where 1SD would fall for each of those three. The visual effect showed that the SDs would "spread out" overall, even though I didn't know how to find the exact numbers. Maybe we'll learn that later.
FirstChildUserIdTAG: 773223
FirstChildUserNameTAG: Andaponte
FirstChildCreateTimeTAG: 2013-03-15T13:47:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Think I can prove that yucky looking formula, but only if it's not (n-1)'s but n's - which would make sense if wikipedia was talking about samples.
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-15T22:46:42Z
FirstChildVoteTAG: 0
FirstChildTAG: I was unable to "feel" the solution, and I also used algebra, but I absurdly miscalculated something (maybe a noisy restaurant is not the best place to do algebra or, more probably, my math competence is really awful ;-) . After returning home from job I caught the error and tried some R simulations. Computers point in the right direction extremely well and quickly. But I had decided not to use computer simulations in the exam, following my own advice ;-)
I really admire all of you who feel the answer. I guess this is one of the main objectives of this course. But, for me, this problem is, even now, hard to grasp by mere intuition.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-16T01:10:45Z
FirstChildVoteTAG: 1
SecondChildTAG: Same issue, knew it had to be solved by understanding the concept, but couldnt figure it out. Wish the Porf would explain it in detail in a video for us to understand.
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-18T02:50:59Z
SecondChildVoteTAG: 0
IndexTAG: 860
TitleTAG: Problem 3 has a more correct answer and a typo in explanation
What if list A consists of 25 100s? In that case SDs are equal. Also in explanation instead of second "List B" should be "List A".
UserIdTAG: 1081293
UserNameTAG: GorGrigoryan
CreateTimeTAG: 2013-03-15T09:40:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: List A has 25 different entries
FirstChildUserIdTAG: 1134470
FirstChildUserNameTAG: cpaula
FirstChildCreateTimeTAG: 2013-03-15T09:44:56Z
FirstChildVoteTAG: 0
SecondChildTAG: How do I can get Applet results? Is there any one who can help me for 3A and 3B
SecondChildUserIdTAG: 1017884
SecondChildUserNameTAG: Bilew
SecondChildCreateTimeTAG: 2013-03-15T11:19:35Z
SecondChildVoteTAG: 0
FirstChildTAG: Well, you are modifying the problem :)
Look at the original one once more:
> List A has 25 **different entries**, and its average is 100
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-15T09:45:00Z
FirstChildVoteTAG: 0
FirstChildTAG: Sorry for inattention.
FirstChildUserIdTAG: 1081293
FirstChildUserNameTAG: GorGrigoryan
FirstChildCreateTimeTAG: 2013-03-15T11:33:22Z
FirstChildVoteTAG: 0
IndexTAG: 861
TitleTAG: problem 2a
I believe that there are 2 submissions for problem 2a. i submitted once. however, it said ive used ' 2 out of 2 submissions.' please assist.
many thanks.
UserIdTAG: 946512
UserNameTAG: nicoleha
CreateTimeTAG: 2013-03-15T09:39:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 9 / Exercise Set 9
NumberOfReplyTAG: 5
FirstChildTAG: It neither takes NA as an answer
FirstChildUserIdTAG: 855928
FirstChildUserNameTAG: pbeverat
FirstChildCreateTimeTAG: 2013-03-15T13:03:56Z
FirstChildVoteTAG: 1
FirstChildTAG: you probably pressed the 'check' button twice.
FirstChildUserIdTAG: 1218819
FirstChildUserNameTAG: duggi
FirstChildCreateTimeTAG: 2013-03-15T13:30:30Z
FirstChildVoteTAG: 0
SecondChildTAG: I pressed more than twice...and the aswer is always "could not interpret 'NA' as a number"
SecondChildUserIdTAG: 788389
SecondChildUserNameTAG: SIDICE
SecondChildCreateTimeTAG: 2013-03-15T13:58:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Yup, maybe your mouse or touchpad need a replacement.
SecondChildUserIdTAG: 1409496
SecondChildUserNameTAG: qhfu
SecondChildCreateTimeTAG: 2013-03-15T14:02:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I actually have the same problem. NA is not accepted as an answer for 2a
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-03-15T14:12:03Z
SecondChildVoteTAG: 0
SecondChildTAG: It would be nice if there was an option to edit/delete posts
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-03-15T14:32:37Z
SecondChildVoteTAG: 0
FirstChildTAG: NA is not accepted because its the wrong answer
FirstChildUserIdTAG: 1218819
FirstChildUserNameTAG: duggi
FirstChildCreateTimeTAG: 2013-03-15T14:31:00Z
FirstChildVoteTAG: 0
FirstChildTAG: I have the same problem.NA is not accepted as an answer.Any idea?
FirstChildUserIdTAG: 1029226
FirstChildUserNameTAG: workayehuke
FirstChildCreateTimeTAG: 2013-03-15T15:05:06Z
FirstChildVoteTAG: 2
FirstChildTAG: Respect Honour Code, please. As usual, this is the kind of problem that requires a deeper understanding. I even think it's a problem for which any hint, whatever the hint, reveals more than it should.
That said, the problem statement allows two possible kind of answers: a numerical value or NA. if NA is not accepted, the grader has obviously a bug.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-15T21:09:12Z
FirstChildVoteTAG: 1
IndexTAG: 862
TitleTAG: Problem 6 explanation has a typo
It should be 1/2.5=40%
UserIdTAG: 1081293
UserNameTAG: GorGrigoryan
CreateTimeTAG: 2013-03-15T09:32:59Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 0
IndexTAG: 863
TitleTAG: No Practice Exercises?
Is it just me or does this section have no practice exercises? My computer is certainly showing none.
UserIdTAG: 47031
UserNameTAG: PrernaDewan
CreateTimeTAG: 2013-03-15T09:25:49Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 5
FirstChildTAG: It should be your browser or something, because I can see the practice exercises, one for each section as always
FirstChildUserIdTAG: 1108368
FirstChildUserNameTAG: BlancaR
FirstChildCreateTimeTAG: 2013-03-15T09:32:20Z
FirstChildVoteTAG: 0
SecondChildTAG: I cannot see link for opening Chapter 5 to 8
SecondChildUserIdTAG: 925661
SecondChildUserNameTAG: VandanaLaheri
SecondChildCreateTimeTAG: 2013-03-15T09:56:14Z
SecondChildVoteTAG: 0
SecondChildTAG: No link just go to http://statistics.berkeley.edu/~stark/SticiGui/Text/scatterplots.htm
and scroll to bottom to move chapters.
Practice questions are on chapter 5 of the above link.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-15T17:32:16Z
SecondChildVoteTAG: 0
FirstChildTAG: We are asked to do some exercises from the text book. There are no more exercises other than that this time ...
FirstChildUserIdTAG: 1069830
FirstChildUserNameTAG: TheodoraCh
FirstChildCreateTimeTAG: 2013-03-15T09:33:01Z
FirstChildVoteTAG: 1
FirstChildTAG: Does this thread help you? https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Practice_For_Exercise_Set_9/threads/5142e84d2af1052300000088
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-15T10:22:44Z
FirstChildVoteTAG: 0
FirstChildTAG: Look above lecture video. You will see there are several framed segments. Touch the second one and you will see the scatter video and practice exercises etc...and so on.
FirstChildUserIdTAG: 1220195
FirstChildUserNameTAG: Emuna309
FirstChildCreateTimeTAG: 2013-03-15T16:57:11Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you all. I suppose there are practice exercises only in the textbook, not separate ones in the courseware.
FirstChildUserIdTAG: 47031
FirstChildUserNameTAG: PrernaDewan
FirstChildCreateTimeTAG: 2013-03-15T23:58:05Z
FirstChildVoteTAG: 2
IndexTAG: 864
TitleTAG: Text Book for Practice Exercise Set 9
For anyone looking for the textbook exercises for Practice Set 9, here is a link to the textbook (table of content):
http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm
UserIdTAG: 591304
UserNameTAG: KMV
CreateTimeTAG: 2013-03-15T09:22:21Z
VoteTAG: 19
CoursewareTAG: Practice for Exercise set 9 / Reading and Practice for Exercise set 9
NumberOfReplyTAG: 1
FirstChildTAG: Thanks, that's really useful
FirstChildUserIdTAG: 1069830
FirstChildUserNameTAG: TheodoraCh
FirstChildCreateTimeTAG: 2013-03-15T15:33:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks, that is really useful. However, i can't see the histogram alluded to in Figure 5.1. Is there something wrong with my laptop or is there something I am supposed to do to make the histogram show?
SecondChildUserIdTAG: 1242644
SecondChildUserNameTAG: Danje
SecondChildCreateTimeTAG: 2013-03-15T15:39:00Z
SecondChildVoteTAG: 0
SecondChildTAG: This is a screenshot of what I see. May be try a different browser? ![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13633650941343676.png
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-15T16:32:27Z
SecondChildVoteTAG: 0
IndexTAG: 865
TitleTAG: PROBLEM 4 has another pair of right choices?
Just wondering. What if statistician picked to multiply all the weights by -0.4 and add 162.4? Didn't she get what she wants?
UserIdTAG: 1081293
UserNameTAG: GorGrigoryan
CreateTimeTAG: 2013-03-15T09:18:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 0
IndexTAG: 866
TitleTAG: Practice for ES 10
1A. Since the 75th percentile, not 70th, is z = 0.675, there may be some typing mistake.
1B. In the 3rd option, what does "below the 61st percentile" supposed to mean?
UserIdTAG: 1409496
UserNameTAG: qhfu
CreateTimeTAG: 2013-03-15T08:29:55Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise set 10 / Reading and Practice for Exercise set 10
NumberOfReplyTAG: 1
FirstChildTAG: 1A. The 70th percentile is z=0.52. So Show Answer is incorrect.
1B. 3rd option means just little number than 61.
58 is my mistake. 58 of under section is 54.4. Though I wrote 54.4 before I vanished it and I mistook the number as 58 this time. I just wanted to clarify that regress towards the mean by number and I thought how does the regression rely on intuition as Markpolak said. Therefore qhfu,markpolak's comment is very important not only me but also for everybody. Unfortunatery, staff vanished Z=0.675 and 61 as typo. So nobody think of this seriously.
Why I say about of this typo because I learned a lot of things from my mistakes by myself till now in this course. I wanted to ask some question so many times as professor Ani Adhikari gave kind answer. But as my English is so poor,Japanese,it is so difficult to express the number without violate honor code or vice versa I wanted to answer often but I'm afraid I did not understand what's the meaning of question sometimes. So I admire classmates who write their quetions and answers. Thank you professor Ani and everybody.
FirstChildUserIdTAG: 200548
FirstChildUserNameTAG: kame
FirstChildCreateTimeTAG: 2013-03-15T08:51:19Z
FirstChildVoteTAG: 0
SecondChildTAG: 1B. The answers are given the way they are so you don't have to do any calculation - you can just rely on intuition. As long as correlation is < 1, given a value of x, y will regress towards the mean. That's all you need to know to answer the question.
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-03-15T13:11:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you markpolak. You are right. Regression towards to the mean,so as answer is 58, I wanted to say 61 was mistake.
SecondChildUserIdTAG: 200548
SecondChildUserNameTAG: kame
SecondChildCreateTimeTAG: 2013-03-20T07:08:59Z
SecondChildVoteTAG: 0
IndexTAG: 867
TitleTAG: midterm solutions
we ll see the midterm solutions?
UserIdTAG: 1147076
UserNameTAG: giomicho
CreateTimeTAG: 2013-03-15T08:25:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
Friday 8 00AM GMT
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T08:36:41Z
FirstChildVoteTAG: 0
SecondChildTAG: it´s 08:50 am gtm
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-03-15T08:49:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Friday 8:00 am GMT is already over, we will just have to wait...
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-15T08:42:53Z
FirstChildVoteTAG: 1
IndexTAG: 868
TitleTAG: 2nd a 3rd part of the course
I'd like to know if Stat2.2x and Stat 2.3x will follow in a short time or with some break (the sooner the better). I also don't know if it's only for those who succesfuly pass Stat2.1x. The final certificate will be issued for each part or only for the three parts together? This is not clear from the course description.
UserIdTAG: 1341242
UserNameTAG: alesbadura
CreateTimeTAG: 2013-03-15T08:22:30Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I believe there will be a few weeks break. I think we have to wait for the announcements.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T08:38:07Z
FirstChildVoteTAG: 0
SecondChildTAG: I think we will get a different certificate for each course.
I am not sure though if only those who have passed stat2.1x will be allowed to take the following courses. I doubt that this will be the case .... Can the course team kindly inform us about that please? Thanks.
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-15T09:39:32Z
SecondChildVoteTAG: 0
SecondChildTAG: This shouldn't be here :-) I've copied it below. I am not allowed to delete or edit comments as we can do for posts ... Is it only me ?
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-15T09:43:08Z
SecondChildVoteTAG: 0
FirstChildTAG: I think we will get a different certificate for each course. I am not sure though if only those who have passed stat2.1x will be allowed to take the following courses. I doubt that this will be the case .... Can the course team kindly inform us about that please? Thanks.
FirstChildUserIdTAG: 1069830
FirstChildUserNameTAG: TheodoraCh
FirstChildCreateTimeTAG: 2013-03-15T09:40:12Z
FirstChildVoteTAG: 0
FirstChildTAG: Prof has said that the other courses will follow on 'shortly after' each other.
I wouldn't expect that 2.1x would be a prerequisite for the later courses, that isn't in the spirit of open access courses.
I have suggested in another thread that an overarching certificate for those completing the three courses would be attractive and the Prof. was kind enough to reply that she would be discussing up this possibility with edX.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-15T16:03:18Z
FirstChildVoteTAG: 1
IndexTAG: 869
TitleTAG: Empty boxes in text
When I try to study the new material (ch 5 - exec 9), in the text I see only absolutly empty boxes instead of graphics - no scatterplots. No points, numbers, lines inside. My software is up to date. I had the same problem earlier but somebody just recommended me to update Firefox. It's updated but of no help.
UserIdTAG: 1341242
UserNameTAG: alesbadura
CreateTimeTAG: 2013-03-15T08:13:32Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: try with chrome.
FirstChildUserIdTAG: 1134470
FirstChildUserNameTAG: cpaula
FirstChildCreateTimeTAG: 2013-03-15T08:22:15Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/browser-setting-appletsif-they-do-not-work/
PLease perform all settings wrt encoding.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-15T08:39:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Well, I've tried everything. Still only empty boxes, no scatterplots. I will find a similar material somewhere else but I remind you I never ever had such a problem on my comp. I just can't see any graphs in the text. Video is running well, the applet (normal curve) is calculating allright (but still no histograms).
FirstChildUserIdTAG: 1341242
FirstChildUserNameTAG: alesbadura
FirstChildCreateTimeTAG: 2013-03-15T12:48:58Z
FirstChildVoteTAG: 0
IndexTAG: 870
TitleTAG: median definition
It's stated that the median has at 50% of the data less or equal to it and also that 50% of the data is more or equal to it. If 50% of the data is 'less' than it then how can 50 % (the greater data) be more or equal to it? eg data -4,-2,0,1,3,5 then median according to the def "smallest number that is equal or more than 50% (lesser data)" makes '0' the median, yet if the "50 % of data greater or equal to it then wouldn't '1' be the median?, thanks, confused
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-03-15T07:39:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 0
IndexTAG: 871
TitleTAG: No bug in 1b
There's no bug in midterm problem 1b. Really. It's doing exactly what it's supposed to do. Best,
Prof. A.
UserIdTAG: 1019686
UserNameTAG: AniAdhikari
CreateTimeTAG: 2013-03-13T08:06:07Z
VoteTAG: 57
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: On a technical note: The default discussion forum is apparently set on Exercise Set 1. May be this could be changed, as many posts that have nothing to do with Exercise Set 1 get sorted into this discussion forum?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-15T16:42:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks Prof. I was lazy, played a hunch without being methodical and paid the price. This will sting appropriately for the Final.
FirstChildUserIdTAG: 78038
FirstChildUserNameTAG: subz
FirstChildCreateTimeTAG: 2013-03-16T04:29:58Z
FirstChildVoteTAG: 0
FirstChildTAG: oh my god i lost my midterm what shall i do?
FirstChildUserIdTAG: 548650
FirstChildUserNameTAG: bonenasir
FirstChildCreateTimeTAG: 2013-03-16T06:37:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Is this "bug" relates to sample/population SD?
FirstChildUserIdTAG: 193779
FirstChildUserNameTAG: skywill
FirstChildCreateTimeTAG: 2013-03-16T10:01:19Z
FirstChildVoteTAG: 0
FirstChildTAG: I did it wrong because I calculated the SD using excel, however this is not a problem. Then I calculated it by hand, using the formula reported in the lesson, and I found the right answer. Prof A, could you please explain to me why such a difference in the SD? Can I rely on the SD calculated by a statistical program?
Thank you in advance.
FirstChildUserIdTAG: 276631
FirstChildUserNameTAG: nico8
FirstChildCreateTimeTAG: 2013-03-18T20:54:10Z
FirstChildVoteTAG: 1
SecondChildTAG: Hi Nico8. Be careful with Excel Stdev function as it returns the population SD based on a random sample (divides by N-1). You should use the function stdevp (or stdev.p for newer versions of Excel)
SecondChildUserIdTAG: 1248519
SecondChildUserNameTAG: MarioPC
SecondChildCreateTimeTAG: 2013-03-19T12:21:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you so much MarioPC! Just a curiosity: is it the same with SPSS or STATA?
SecondChildUserIdTAG: 276631
SecondChildUserNameTAG: nico8
SecondChildCreateTimeTAG: 2013-03-19T12:28:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I am not sure Nico8, but probably yes it is the same. Stat programs are often used for estimations of populations based on samples.
I use quite often the Minitab for capability studies and it is using the same stdev formula (divided by N-1, so NOT the one to be used in this course)
SecondChildUserIdTAG: 1248519
SecondChildUserNameTAG: MarioPC
SecondChildCreateTimeTAG: 2013-03-20T13:31:27Z
SecondChildVoteTAG: 0
FirstChildTAG: I should say I did it with the good old pencil and paper, sailed through, and till now have NO clue what the bug is!
Got tricked in the last problem (didn't take the hint that the first 10 are meant to be a random sample of the entire population) though!
Nice one Prof A!
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-19T15:16:05Z
FirstChildVoteTAG: 1
IndexTAG: 872
TitleTAG: 20th percentile for problem 1E
can anyone tell me what is the z-score for 20th percentile? pls as SticiGui suddenly stopped working in my comp.
Thanx!
UserIdTAG: 319801
UserNameTAG: catch_minie
CreateTimeTAG: 2013-03-13T06:01:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: -0.84
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-13T06:35:08Z
FirstChildVoteTAG: 0
IndexTAG: 873
TitleTAG: A query regarding course progress
Hi there ,
This is not of capital importance but i will be grateful if someone can clarify what "ES avg" Bar on the progress page denotes. Is it the average of all of one's prior ES scores? Mine does not seem to tally with my scores. One misgiving i have is regarding practice exercises , some of which i chose to skip. Are they being graded and bringing down my score?
Thanks to anyone that can enlighten me on this!
UserIdTAG: 1015352
UserNameTAG: weizkn
CreateTimeTAG: 2013-03-13T05:58:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hi,
Practise exercise is not graded and certainly does not count towards your grade.
ES avg is (sum of the percentage of prior ES that have been done)/(10). So it will keep increasing as you finish more problem set. It is divided by 10 since out of 12 problem sets, only highest 10 will be taken to be graded. Hope it helps :)
FirstChildUserIdTAG: 380986
FirstChildUserNameTAG: Yandi_lay
FirstChildCreateTimeTAG: 2013-03-13T06:48:14Z
FirstChildVoteTAG: 4
FirstChildTAG: Thank you!
That makes perfect sense = )
FirstChildUserIdTAG: 1015352
FirstChildUserNameTAG: weizkn
FirstChildCreateTimeTAG: 2013-03-15T18:59:42Z
FirstChildVoteTAG: 0
IndexTAG: 874
TitleTAG: Problem 1.b
Hi, i don´t understand the problem. For wich of he following questions are they asking?
area > 66?
or 65< area< 67
or area< 66
I would be grateful if you could confirm me the correct option.
Thanks and regards
UserIdTAG: 405568
UserNameTAG: hugoanf
CreateTimeTAG: 2013-03-13T05:52:26Z
VoteTAG: 3
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: "within 1 inch of the average" means 65 < area < 67.
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-13T06:39:36Z
FirstChildVoteTAG: 4
IndexTAG: 875
TitleTAG: Where to find the page for the Mid-term Program
I am unable to find the link which takes me to the online midterm program
Help me.
UserIdTAG: 1341076
UserNameTAG: sandoc2005
CreateTimeTAG: 2013-03-13T05:23:39Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 7am. GMT. You still have over an hour to wait. The link will be with all the other Courseware links.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-13T05:41:25Z
FirstChildVoteTAG: 0
SecondChildTAG: i am in bangladesh how much time lef for me??
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-13T06:03:05Z
SecondChildVoteTAG: 0
SecondChildTAG: You can go to google search page and type time in GMT. It will show current time in GMT. When the time is 7 AM over there, after that the link should appear. It may be a few minute late. It is 11 PM here, so give some slack to the staff who are working in the late hour.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-13T06:09:02Z
SecondChildVoteTAG: 0
IndexTAG: 876
TitleTAG: Please follow the honor code
Please follow the honor code https://www.edx.org/honor Please do not publish or distribute the solutions in any form.
edX Honor Code Pledge
By enrolling in an edX course, I agree that I will:
... ... ...
Not engage in any activity that would dishonestly improve my results, or improve or hurt the results of others.
Not post answers to problems that are being used to assess student performance.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-13T05:12:11Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Dream on. I give it 30 minutes between the "test" being posted, and questions appearing on a homework site.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-13T05:16:22Z
FirstChildVoteTAG: 0
SecondChildTAG: I will dream on. There are people that uphold academic integrity.
SecondChildUserIdTAG: 1157957
SecondChildUserNameTAG: meganbh
SecondChildCreateTimeTAG: 2013-03-13T06:07:20Z
SecondChildVoteTAG: 0
SecondChildTAG: There are. But sadly, not everyone thinks that way.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-13T06:26:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Being pessimistic isn't going to change that but talking about it (like anonymous above) might.
SecondChildUserIdTAG: 1157957
SecondChildUserNameTAG: meganbh
SecondChildCreateTimeTAG: 2013-03-17T03:19:59Z
SecondChildVoteTAG: 0
IndexTAG: 877
TitleTAG: Passing grade is 35% or 60% ?
I thought all edX classes where only considered a "Pass" grade if the student receives a 60% for all assignments, but in the information for this course it says only 35% is required?
Please advise.
UserIdTAG: 1280636
UserNameTAG: jonnybravo9
CreateTimeTAG: 2013-03-13T05:02:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: >the information for this course it says only 35%
you have answered your own question.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-13T05:10:39Z
FirstChildVoteTAG: 17
SecondChildTAG: I don't like your approach to discussions happening here. If you think you are the smartest in here, then you should be able to understand that people here come from different backgrounds,and also some might not be able to spend 24 h to read everything to the smallest details, so if you don't want to help then just don't say anything. I wonder if you work for Edx and your role is to humiliate everyone in here, or it's just you! Why are you involved in every discussion anyway...
SecondChildUserIdTAG: 1247915
SecondChildUserNameTAG: Iliri2013
SecondChildCreateTimeTAG: 2013-03-13T06:56:08Z
SecondChildVoteTAG: 0
IndexTAG: 878
TitleTAG: You Tube Videos are erroring out.
Hello, it is about 10PM PST and the lecture videos are not available in this section.
I could download the video of the prior lesson (BERSTAT2SP13-G050300_100.mp4) but not this one. It seems many people below are having the same issue.
Please quality control that all links are available?
It is worrisome not to have the material available right before homework is due and right before the midterm.
UserIdTAG: 963897
UserNameTAG: lightbulb
CreateTimeTAG: 2013-03-13T04:54:09Z
VoteTAG: 7
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 0
IndexTAG: 879
TitleTAG: Hint for problem 7
In order to find the answer, you need two values: the mean and the standard deviation. Look at the first part of the problem: you may have two unknown (and needed) variables and two equations :).
UserIdTAG: 257327
UserNameTAG: sebastian_sagv
CreateTimeTAG: 2013-03-13T04:20:18Z
VoteTAG: 6
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 0
IndexTAG: 880
TitleTAG: where is the applet
Midterm direction says, "You will need the normal curve applet you have used in Section 5. Please ensure that you know how to make it work on your browser....."
I am sorry but I wonder where is the applet that the professor and others are using for calculating stuffs.
anyone, will highly appreciate your direction.
UserIdTAG: 867488
UserNameTAG: mkhaled
CreateTimeTAG: 2013-03-13T03:54:51Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Did you do the last lot of exercises? If so, you should have seen a link to the applet at the top of the page.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-13T03:55:57Z
FirstChildVoteTAG: 0
SecondChildTAG: i admit, i am skipping some of the things, specially the book SticiGui pages and exercises. could you please give the exact link of the page that has the aplet.
SecondChildUserIdTAG: 867488
SecondChildUserNameTAG: mkhaled
SecondChildCreateTimeTAG: 2013-03-13T04:03:22Z
SecondChildVoteTAG: 0
SecondChildTAG: No. Go to the exercise set and click on the link. It says it is the applet link, it's not exactly hidden.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-13T05:13:58Z
SecondChildVoteTAG: 0
FirstChildTAG: I admit, I am skipping some of the things, specially the book SticiGui pages and exercises. could you please give the exact link of the page that has the applet.
FirstChildUserIdTAG: 867488
FirstChildUserNameTAG: mkhaled
FirstChildCreateTimeTAG: 2013-03-13T04:11:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Here it is,
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1115908
FirstChildUserNameTAG: rochak_khandelwal
FirstChildCreateTimeTAG: 2013-03-13T04:15:44Z
FirstChildVoteTAG: 3
IndexTAG: 881
TitleTAG: Problem 1A
The question should have been stated as "what percent of the adults are 6 feet tall and over" for the answer to be correct. Interpreted "over 6 feet tall" as 6ft .5 inches, (just over 6 ft) the first answer I put in turned out to be .35 percent low. Reworked the problem with the 6 ft measurement and rounded it up .18 percent and had that one marked wrong as well!! So much for rounding to the "Approximately what percent" live and learn...
UserIdTAG: 575791
UserNameTAG: George_C
CreateTimeTAG: 2013-03-13T03:37:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: I think somewhere earlier on she made the point that "greater than" and "greater than or equal to" can be treated as virtually the same thing. Maybe someone else can corroborate this. I did the problem assuming "greater than or equal to" and it worked.
FirstChildUserIdTAG: 773223
FirstChildUserNameTAG: Andaponte
FirstChildCreateTimeTAG: 2013-03-13T03:58:39Z
FirstChildVoteTAG: 0
SecondChildTAG: coincided to z = 2.4, but then I thought it was to search the table this value 0.9918 and place right this value, gave 33.94%.
2.4 I put right on the applet and it yielded 0.82%, as obtained this%??
SecondChildUserIdTAG: 1024935
SecondChildUserNameTAG: N3
SecondChildCreateTimeTAG: 2013-03-13T05:30:54Z
SecondChildVoteTAG: 0
FirstChildTAG: 6 feet tall and over means greater than or equal to.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T04:47:47Z
FirstChildVoteTAG: 0
IndexTAG: 882
TitleTAG: problem 7
this problem 7 is making me crazy... i got the z value of 90% ... now what should i do? how to find sd and mean ??? anybody!!! help
UserIdTAG: 1036551
UserNameTAG: Geetagrg
CreateTimeTAG: 2013-03-13T03:26:01Z
VoteTAG: 3
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: mean+[sd*(z-value of 60th percentile)] = 110
mean+[sd*(z-value of 70th percentile)] = 120
You can get the mean and sd from above equations. In addition with the z-value of 90th percentile, you will get the answer.
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-13T05:00:32Z
FirstChildVoteTAG: 0
IndexTAG: 883
TitleTAG: Problem 3A
I have not understood the transformation on 3A problem. How do you skip from " 5*(number right) - (10 - number right)" to " 6*(number right) - 10" ?
UserIdTAG: 1031814
UserNameTAG: Marivaldo
CreateTimeTAG: 2013-03-13T03:25:21Z
VoteTAG: 1
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Let number right be =r
5*(r) -(10-r) =5r-10+r (removing brackets)
=6r-10
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T03:46:48Z
FirstChildVoteTAG: 1
IndexTAG: 884
TitleTAG: midterm exam
Still i did not found any link for midterm exam, it is 8.15 am in India so at what time the exam start at India.
UserIdTAG: 393580
UserNameTAG: Aditiak
CreateTimeTAG: 2013-03-13T02:48:24Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: It will be posted at 7 am GMT (Wednesday). Not sure what time zone you are in, so whatever that translates to in your time zone.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-13T03:04:18Z
FirstChildVoteTAG: 0
FirstChildTAG: Please look at the GMT time.Install qclock on you desktop and you will have gadget.Install GMT as the time.The exam will be posted at 7.00 AM GMT which is 7+5.30=12.30 PM IST
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T03:04:29Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks all, All the best for exam.
SecondChildUserIdTAG: 393580
SecondChildUserNameTAG: Aditiak
SecondChildCreateTimeTAG: 2013-03-13T05:00:30Z
SecondChildVoteTAG: 0
FirstChildTAG: Should be any time now.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-03-13T06:03:46Z
FirstChildVoteTAG: 0
IndexTAG: 885
TitleTAG: Practice For Exercise Set 8
Hi! I´ve done the practice for exercise set 8, but it wasn´t saved in the "progress" window. Similar thing happened in week 1 and 2. It will affect may grades? Thank you!
UserIdTAG: 803020
UserNameTAG: Barbaralbtorres
CreateTimeTAG: 2013-03-13T02:21:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Practice exercises do not count towards your grade. No, it will not affect your grade
FirstChildUserIdTAG: 142494
FirstChildUserNameTAG: jaria101
FirstChildCreateTimeTAG: 2013-03-13T02:29:20Z
FirstChildVoteTAG: 2
IndexTAG: 886
TitleTAG: Additional Time for Exercise
With no time left after my job, I'm finding it hard to solve the exercises within the time limits. I would request that we may be given some extra time to solve the exercises and the deadlines to be extended, if possible. I liked the course and have scored good in my previous exercises but I didn't get ample to even study the course material.
UserIdTAG: 1147139
UserNameTAG: AnaAggarwal
CreateTimeTAG: 2013-03-13T02:13:55Z
VoteTAG: 2
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: One quick way to go through the material is to use the PDF's rather than the videos - you can cover a lot within the same period.That may help. You say you have done well in the exercises so far so don't worry - it seems more about being in panic facing a deadline and just relaxing and taking a time out may help.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T02:41:00Z
FirstChildVoteTAG: 4
SecondChildTAG: Also, set 8 is pretty short. I confess that the practice for set 7 had me a little worried but I got through everything faster than I thought I would.
SecondChildUserIdTAG: 905318
SecondChildUserNameTAG: kamili
SecondChildCreateTimeTAG: 2013-03-13T02:54:21Z
SecondChildVoteTAG: 0
FirstChildTAG: Another way is to jump directly to exercise sets rather than attending practice sets. If you are from Maths background, it would not be big deal for you to do so.
FirstChildUserIdTAG: 1115908
FirstChildUserNameTAG: rochak_khandelwal
FirstChildCreateTimeTAG: 2013-03-13T04:19:59Z
FirstChildVoteTAG: 0
IndexTAG: 887
TitleTAG: Midterm Comments, Questions and Encouragements
Post your Midterm related "things" (for lack of a better term) here instead of making 3,908,509,128,039,095,872,392,093,810,902,930,958,928,271,984,984,395,091,283,849,239 other posts. Here's mine:
![enter image description here][1]
[1]: http://cdn.memegenerator.net/instances/400x/24507509.jpg
UserIdTAG: 316261
UserNameTAG: Brady1997
CreateTimeTAG: 2013-03-13T01:59:46Z
VoteTAG: 39
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Brady, I'm so into the Stats "thing" (for lack of a better term) that the first thing I wanted to do upon looking at your message was to calculate the mean, median and mode of the numbers above. Geez! Am I addicted or what? LOL. BTW, I like your post.
FirstChildUserIdTAG: 1325060
FirstChildUserNameTAG: Kuarup
FirstChildCreateTimeTAG: 2013-03-15T20:39:57Z
FirstChildVoteTAG: 0
SecondChildTAG: Kuarup, it's just one big number ;)
SecondChildUserIdTAG: 193779
SecondChildUserNameTAG: skywill
SecondChildCreateTimeTAG: 2013-03-16T09:52:24Z
SecondChildVoteTAG: 0
SecondChildTAG: I know, skywill. I was just being sarcastic.
SecondChildUserIdTAG: 1325060
SecondChildUserNameTAG: Kuarup
SecondChildCreateTimeTAG: 2013-03-20T18:11:58Z
SecondChildVoteTAG: 0
IndexTAG: 888
TitleTAG: Midterm
I got the email about the midterm. So during the midterm exam, are we allowed to use notes or not? Is it open book or closed book exam?
UserIdTAG: 77471
UserNameTAG: Jalib
CreateTimeTAG: 2013-03-13T01:44:00Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Open book
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T02:12:34Z
FirstChildVoteTAG: 1
IndexTAG: 889
TitleTAG: Question
I am confused that in case of 2 submissions if my first answer is wright then is it necessary to use 2 of 2 submissions?
UserIdTAG: 1025953
UserNameTAG: Rubaya
CreateTimeTAG: 2013-03-13T01:29:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No it is not necessary.Once you have checked the correct answerr(no save) it has been submitted
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T01:43:49Z
FirstChildVoteTAG: 1
IndexTAG: 890
TitleTAG: Excel functions for calculating percentile, area under normal curve, etc.
For those who can't use the applet for whatever reason (or simply to double-check your answers), the following Excel functions can help.
1. **NORMSDIST** Use to calculate area to the _left_ of a value of the normal distribution (mean = 0, sd = 1). You can use **NORMDIST** (note no S) when you have mean $\ne$ 0 and sd $\ne$ 1.
2. **NORMSINV** Use to calculate a given percentile of the normal distribution. Again, you can use a version with no S, **NORMINV** when mean $\ne$ 0 and sd $\ne$ 1.
Examples for the normal dist (mean = 0, sd = 1):
1. area to the left of mean: `NORMSDIST(0)` = 0.5 or 50%
2. area to the right of 1: `1 - NORMSDIST(1)` = 0.1587 or 15.87%
3. area between mean and 1 sd: `NORMSDIST(1) - NORMSDIST(0)` = 0.3413 or 34.13%
4. 5th percentile: `NORMSINV(0.05)` = -1.645 or 5% of values are less than -1.645 (or 95% are less than 1.645 due to symmetry)
Examples for normally distributed data (e.g. mean = 50, sd = 10):
1. area to the left of mean: `NORMDIST(50, 50, 10, TRUE)` = 0.5 or 50%
2. area to the right of 60: `1 - NORMDIST(60, 50, 10, TRUE)` = 0.1587 or 15.87%
3. area between 50 and 60: `NORMDIST(60, 50, 10, TRUE) - NORMDIST(50, 50, 10, TRUE)` = 0.3413 or 34.13%
4. 5th percentile: `NORMINV(0.05, 50, 10)` = 33.55 (Notice this is -1.645 * 10 + 50)
UserIdTAG: 502508
UserNameTAG: amaher
CreateTimeTAG: 2013-03-13T00:59:07Z
VoteTAG: 19
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: I happen to be a frequent MS Excel user and think there should be dot(s) in the formula, like "NORM.DIST" and "NORM.S.DIST".
In addition, Goal Seeker is very helpful when you want to find the x-value or z-value, given the area of percentile.
FirstChildUserIdTAG: 1409496
FirstChildUserNameTAG: qhfu
FirstChildCreateTimeTAG: 2013-03-13T03:46:57Z
FirstChildVoteTAG: 4
SecondChildTAG: I believe both NORM.DIST and NORMDIST work starting with Excel 2010 (there are some technical differences in implementation), but NORM.DIST and other dot versions _do not_ work with earlier versions of Excel, in particular 2007, which I'm currently using. If you've got newer versions of Excel, then certainly dot versions are better since they've been re-written to provide closer approximations.
SecondChildUserIdTAG: 502508
SecondChildUserNameTAG: amaher
SecondChildCreateTimeTAG: 2013-03-16T04:34:46Z
SecondChildVoteTAG: 0
IndexTAG: 891
TitleTAG: exercise 7 problem4
need to find out how this problem is interpreted. what is required?
UserIdTAG: 521763
UserNameTAG: taakondjo
CreateTimeTAG: 2013-03-13T00:32:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: first,transform the SD of weights by 25/10 = 2.5 (change unit to multiply value (0.4)
then,calculate the transform mean (156 to 100)= 156/2.5 = xxx and multiply by transform SD
FirstChildUserIdTAG: 676917
FirstChildUserNameTAG: sangtu
FirstChildCreateTimeTAG: 2013-03-13T04:29:07Z
FirstChildVoteTAG: 0
IndexTAG: 892
TitleTAG: Problem 1C
Problem 1C was misleading without more specific guidance. The answer changes significantly depending on the convention and decimal place you use to round up or down to 70 inches. The solution says the boundaries should be 69.5 to 70.5 inches, but if you follow typical convention of rounding up tenth decimal to whole number at 0.5, and rounding down at less than 0.5, then shouldn't the boundaries be 69.5 to 70.4, or 69.50 to 70.45 (as 70.50 would be rounded up to 71)?
UserIdTAG: 1130547
UserNameTAG: nluetteke
CreateTimeTAG: 2013-03-13T00:31:52Z
VoteTAG: 10
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: I've used one of your alternatives, and worked out just fine.
FirstChildUserIdTAG: 632581
FirstChildUserNameTAG: GMendes
FirstChildCreateTimeTAG: 2013-03-13T01:56:21Z
FirstChildVoteTAG: 0
IndexTAG: 893
TitleTAG: where do percentiles come from?
they say the 60% percentile for example is z= some number. Where do they get that number???
UserIdTAG: 990423
UserNameTAG: George95
CreateTimeTAG: 2013-03-13T00:26:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: You use the applet.
FirstChildUserIdTAG: 1157957
FirstChildUserNameTAG: meganbh
FirstChildCreateTimeTAG: 2013-03-13T01:16:15Z
FirstChildVoteTAG: 0
IndexTAG: 894
TitleTAG: Bell curve for grades
General question: Why do teachers and professors use the curve for grading? Doesn't this just compare students within a class? Doesn't this mean that your marks aren't "standard" later on when applying for higher education? And is this why universities ask for SAT and later the GRE?
Just loose thoughts, obviously I never understood the concept of grading on a curve when I was in high school.
UserIdTAG: 845389
UserNameTAG: jonellevillar
CreateTimeTAG: 2013-03-13T00:11:00Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: There is an expectation of a certain class average in a university course. In general, here in Canada it's a C+ (and Im pretty sure it's along the same lines in the US).
A higher class average tells the university (rightly or wrongly) that the course is too easy. A lower tells them the Prof is making it too difficult.
So instead of adjusting the material which needs to be covered due to accreditation and other issues, they "bell curve" the grades.
So it will become a normal distribution, with a numerical mean equivalent to a C+..
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-13T02:57:43Z
FirstChildVoteTAG: 1
SecondChildTAG: They adjust the student grades to make it a mean of C+ ? I have seen percentile grading being done too.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-13T03:09:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, that's my understanding. Funny enough, I've never heard of it being pushed down, only up :-)
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-13T03:22:24Z
SecondChildVoteTAG: 0
SecondChildTAG: In a way normalizing to the mean of scores rather than absolute scores can be problematic. It may account for difficulty levels of exams but unfortunately poor performance does not imply that the course is bad but the students indeed did badly.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-13T04:53:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Here the UK the public examinations at age 16 (then called 'O' Levels - for Ordinary as compared to Advanced) were normalised. The assumption was that each cohort had broadly similar ability and any variation due to differences in examination.
When the examination system was changed in the 1980s (to the GCSE - General Certificate of Secondary Education) the use of normalisation was dropped. What has followed is three decades of steadily rising results. Such was the rate of grade 'inflation' (or improvement?) that it became necessary to add an A* grade as too many candidates were achieving A grades so making it impossible to distinguish performance.
Despite the unlikelihood of students' ability and performance increasing year on year for three decades each round of results is greeted by politicians as proof of improving standards. A little statistical understanding would go a long way...
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-15T21:43:29Z
SecondChildVoteTAG: 0
IndexTAG: 895
TitleTAG: exercise 7 3b
I was able to solve yesterday 3a but now I am confuse with 3b and 4 please help.Is the last question in the unit similar to the practice example? need some clarity
UserIdTAG: 521763
UserNameTAG: taakondjo
CreateTimeTAG: 2013-03-12T23:46:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 896
TitleTAG: excercise 1
How to submit my exercise?
UserIdTAG: 1265218
UserNameTAG: hkdshah
CreateTimeTAG: 2013-03-12T23:44:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline for Exercise Set 1 is over, you cannot submit it anymore.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-15T10:28:50Z
FirstChildVoteTAG: 0
IndexTAG: 897
TitleTAG: Michael T
Have to agree with all those re: "to the nearest inch". Imprecise and subject to multiple interpretations.
UserIdTAG: 90148
UserNameTAG: MichaelT81
CreateTimeTAG: 2013-03-12T23:18:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 3
FirstChildTAG: Seems exact and clear to me.
If a question had asked for an answer to be given 'to the nearest whole number' would that be *imprecise and subject to multiple interpretations*? 'To the nearest inch' is exactly the same requirement simply expressed with a unit, inches.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-12T23:59:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Think the range of the numbers which CAN usually get approximated to 70 . Just ask these questions to ourself
1. whether 69.2 gets approximated to 69 or 70 ?
2. What about other numbers such 69.3, 69.4, 69.5 & so on till ___?
Answer to these questions will help you to identify the range & the path towards the answer
FirstChildUserIdTAG: 1214737
FirstChildUserNameTAG: Lipin
FirstChildCreateTimeTAG: 2013-03-13T00:36:57Z
FirstChildVoteTAG: 0
FirstChildTAG: If you learned how to average a number, like we all did in high school, it shouldn't be a problem. It's tricky, but so is application of statistical concepts in the real world.
FirstChildUserIdTAG: 1340247
FirstChildUserNameTAG: echurch
FirstChildCreateTimeTAG: 2013-03-13T04:58:12Z
FirstChildVoteTAG: 0
IndexTAG: 898
TitleTAG: The applet she talks about
Where is the applet Ani talks about? I am a remote student and do not have a text book. Help! Thanks.
UserIdTAG: 942920
UserNameTAG: utahsifu
CreateTimeTAG: 2013-03-12T22:43:55Z
VoteTAG: 0
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.1: Bell shaped curves; the standard normal curve
NumberOfReplyTAG: 3
FirstChildTAG: This one: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
Also, the "textbook" referred would be this: http://statistics.berkeley.edu/~stark/SticiGui/Text/index.htm
It's an online textbook, intended for us "remote students" ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T23:03:11Z
FirstChildVoteTAG: 2
FirstChildTAG: There's a link in the Reading and Practice for Exercise Set 7.
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-12T23:04:29Z
FirstChildVoteTAG: 0
FirstChildTAG: just beware that when you go to use th applet, whatever answers you may have submitted, won't be there when you return. you'd better write them down. and good luck with th applet; mine was tough to read because another page was double-exposed over it.
FirstChildUserIdTAG: 950367
FirstChildUserNameTAG: catt9
FirstChildCreateTimeTAG: 2013-03-13T00:42:46Z
FirstChildVoteTAG: 0
IndexTAG: 899
TitleTAG: exercise 8 , 1a, 1b, 1c help
1a. 6*12+72 inches
72-66/2.5 = 2.4 percentage 49.18 where did I went wrong?
1b. 1-66/2.5 = -26 Where am I wrong?
1c. 70-66/2.5 = 1.6 percentage 44.52 where did I miss?
UserIdTAG: 521763
UserNameTAG: taakondjo
CreateTimeTAG: 2013-03-12T21:32:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: 1a) how do you get 49.18? Did you use the Applet?
1b) the question is asking for the area between 5 feet 5 and 5 feet 7 inches. Because both of those heights are within 1 inch of the average. Again you have to use the Applet.
1c) I got this question wrong so I can't help you. I didn't understand the question. But after looking at the explanation all I can tell you that it is the same as 1b. Just to be sure when I said "the same" I don't mean the same answer. The questions are similar and the answers are different. Again, you have to know what you need to do and then use the Applet to get the area.
Look at 1a and ask yourself why do you do the calculation to get 2.4. If you know why you have to do that calculation, then you can answer 1b and 1c.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-12T23:21:53Z
FirstChildVoteTAG: 0
FirstChildTAG: You can get explanations for the answers by clicking the "show answer" button:
1a. (72-66)/2.5 = 2.4. Now use the applet to get the area to the right of 2.4. Approximately 0.82% of adults are over 6 feet tall.
1b. 1/2.5 = 0.4. Enter z=-0.4 into the lower endpoint and z=0.4 into the upper endpoint on the SticiGui applet to find 31.08%.
1c. Adults that are 70 inches tall to the nearest inch have heights ranging from 69.5 to 70.5. In standard units,(69.5 - 66)/2.5 = 1.4; (70.5 - 66)2.5 = 1.8. Enter these z-values into the lower and upper endpoints respectively to find that the area is equal to 4.48%.
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-12T23:24:32Z
FirstChildVoteTAG: 0
SecondChildTAG: thank you for your explanation.
SecondChildUserIdTAG: 521763
SecondChildUserNameTAG: taakondjo
SecondChildCreateTimeTAG: 2013-03-12T23:39:37Z
SecondChildVoteTAG: 0
SecondChildTAG: **You are NOT supposed to post the answers before the Exercise due date!!!!**
SecondChildUserIdTAG: 501313
SecondChildUserNameTAG: jimmir
SecondChildCreateTimeTAG: 2013-03-13T00:26:51Z
SecondChildVoteTAG: 0
IndexTAG: 900
TitleTAG: Sound volume
Hey Prof. A.
Could I please make a request that you talk closer to the microphone or in other ways increase the volume on the lectures.
Its not a big deal, but I am unable to hear loud and clear when I use my laptop speakers even with the volume at max, I have to use headphones. It would be very convenient to watch lecture at times when I do not have my headphones at hand.
UserIdTAG: 626637
UserNameTAG: 1051
CreateTimeTAG: 2013-03-12T21:27:27Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Same thing here. The volume of the non-lectures videos (2 min ones) is good but the volume of the lectures is low. Is it possible to increase it to the level of the non-lecture videos?
Thank you very much.
FirstChildUserIdTAG: 1144890
FirstChildUserNameTAG: ltavares
FirstChildCreateTimeTAG: 2013-03-13T02:32:37Z
FirstChildVoteTAG: 2
IndexTAG: 901
TitleTAG: APPLET NOT WORKING
I cant resolve problems 3-6 because applet is not working on my computer. I try to actualisation of Firefox and Java but it doesn't help at all. Like this I can't pass this course even if I want to try very much.
UserIdTAG: 734057
UserNameTAG: cieursz
CreateTimeTAG: 2013-03-12T21:21:00Z
VoteTAG: 2
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: go to right top corner click setting, click tools-->click encoding-->click unicode (UTF-8). You are get set go. This is for chrome
Edit
Delete
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/513ce10974c9d92b000001a0
–posted about 23 hours ago by navgir
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-12T21:44:24Z
FirstChildVoteTAG: 0
FirstChildTAG: Have a look [here][1] and see if you can't fix the problem.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/fixing-normal-curve-applet/
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T23:04:25Z
FirstChildVoteTAG: 0
FirstChildTAG: I've listed some Excel functions that can do the calculation (without the applet) in the following thread. If you don't have Excel, try WolframAlpha website. It's pretty neat as you can actually search for something like "5% percentile of normal" and it gives you the answer as z-score.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_8/threads/513fcf5b8a586f2300000092
FirstChildUserIdTAG: 502508
FirstChildUserNameTAG: amaher
FirstChildCreateTimeTAG: 2013-03-13T01:07:56Z
FirstChildVoteTAG: 0
IndexTAG: 902
TitleTAG: Applet issue
The applet isn't laid out properly for me, I can't quite make out the figures as they are behind the Stici logo. Do I need some updated software?
UserIdTAG: 927476
UserNameTAG: leomas
CreateTimeTAG: 2013-03-12T21:19:55Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: What browser are you using? Are you using a computer or a tablet?
FirstChildUserIdTAG: 1157957
FirstChildUserNameTAG: meganbh
FirstChildCreateTimeTAG: 2013-03-12T21:29:47Z
FirstChildVoteTAG: 0
FirstChildTAG: go to right top corner click setting, click tools-->click encoding-->click unicode (UTF-8). You are get set go. This is for chrome
Edit
Delete
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/513ce10974c9d92b000001a0
–posted about 23 hours ago by navgir
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-12T21:44:50Z
FirstChildVoteTAG: 0
IndexTAG: 903
TitleTAG: Problem with Java and the applet
Hi There,
I am here totally frustrated.Java is having some trouble with my Mac.and I could not get in to the applet.which means I am not going to do well at the test this week and probably the mid term.......by the way I have tried all the suggestion forwarded at the forum on how to solve problem with Java however my problem still persist.
I think in this course there should be a consideration need to be made that a software handling challenge should not be allowed to be translated in to a poor performance in the course.I will do all my best to figure out hoe to handle those question that need the applet...
UserIdTAG: 1029226
UserNameTAG: workayehuke
CreateTimeTAG: 2013-03-12T20:56:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: I'm having same problem with you too.I must have to get the other questions that don't need the applet right to make up for the deficiency.
FirstChildUserIdTAG: 715356
FirstChildUserNameTAG: Janefrances
FirstChildCreateTimeTAG: 2013-03-12T21:25:32Z
FirstChildVoteTAG: 0
FirstChildTAG: You can still use other software, there should be plenty around on the internet. Even the good old tables can work too.
FirstChildUserIdTAG: 1152666
FirstChildUserNameTAG: brentsen
FirstChildCreateTimeTAG: 2013-03-12T23:05:53Z
FirstChildVoteTAG: 0
FirstChildTAG: I've listed some Excel functions that can do the calculation in the following thread. If you don't have Excel, try WolframAlpha website. It's pretty neat as you can actually search for something like "5% percentile of normal" and it gives you the answer as z-score.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_8/threads/513fcf5b8a586f2300000092
FirstChildUserIdTAG: 502508
FirstChildUserNameTAG: amaher
FirstChildCreateTimeTAG: 2013-03-13T01:07:05Z
FirstChildVoteTAG: 1
IndexTAG: 904
TitleTAG: Problem 1C - two decimal places is too many
For this exercise, I assumed that "to the nearest inch" meant "between the lowest and highest two-decimal values that could be rounded to 70".
Don't make the same mistake. The exercise wants you to use a one-decimal value that actually rounds to 71. I guess it sort of makes sense that the entire range is one inch, but this is a rather counterintuitive (for me anyway) way of approaching it.
UserIdTAG: 1055945
UserNameTAG: rebecca417
CreateTimeTAG: 2013-03-12T19:57:09Z
VoteTAG: 6
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 3
FirstChildTAG: I had similar struggles - could be an international thing, perhaps... wasn't 100% sure what was meant by 'to the nearest inch'. Without breaking the honour code, I think you've given enough of a hint to be helpful.
FirstChildUserIdTAG: 1261574
FirstChildUserNameTAG: Bravus
FirstChildCreateTimeTAG: 2013-03-12T20:32:38Z
FirstChildVoteTAG: 5
FirstChildTAG: I'm not sure I follow. The range that rounds to x is the same whether you use one decimal value, two decimal values, or 10000 decimal values ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T20:33:41Z
FirstChildVoteTAG: 2
SecondChildTAG: "to the nearest inch" i think the next time this ideea should be developped or given in a simplier way. i failed my exercise because of that((((
SecondChildUserIdTAG: 1401721
SecondChildUserNameTAG: VictoriaGalbur
SecondChildCreateTimeTAG: 2013-03-12T20:59:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Totally agree, the question was open to any interpretation about what suposse to meant "the nearest inch"
SecondChildUserIdTAG: 1069196
SecondChildUserNameTAG: JohaR3
SecondChildCreateTimeTAG: 2013-03-12T21:35:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Rebecca, your point saved me!
SecondChildUserIdTAG: 1070406
SecondChildUserNameTAG: barretrp
SecondChildCreateTimeTAG: 2013-03-12T21:37:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Agree, there are a range of values that could be considered "to the nearest inch."
SecondChildUserIdTAG: 1219328
SecondChildUserNameTAG: cmburch
SecondChildCreateTimeTAG: 2013-03-12T23:02:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks! I was so confused!
SecondChildUserIdTAG: 484877
SecondChildUserNameTAG: Andre97
SecondChildCreateTimeTAG: 2013-03-13T00:08:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, this is too fuzzy, specially if your native language is not english. I so interpretative that "to the nearest inch". I actually fail my first try... i still and dunno what the question likes by answer
SecondChildUserIdTAG: 323166
SecondChildUserNameTAG: PabloT
SecondChildCreateTimeTAG: 2013-03-13T06:58:54Z
SecondChildVoteTAG: 0
FirstChildTAG: I burnt my first try and still don't know what's meant by the nearest inch. Unfortunately the question's too fuzzy....
FirstChildUserIdTAG: 186276
FirstChildUserNameTAG: OliverMun
FirstChildCreateTimeTAG: 2013-03-12T20:41:48Z
FirstChildVoteTAG: 0
SecondChildTAG: jUST THE NEAREST WHOLE NUMBER,I THINK
SecondChildUserIdTAG: 37490
SecondChildUserNameTAG: yemmymoore
SecondChildCreateTimeTAG: 2013-03-12T22:08:45Z
SecondChildVoteTAG: 0
IndexTAG: 905
TitleTAG: Download second presentation
Hello,
In this section I can't download as a video the second presentation. Con you allow to download it?
Thanks,
Cristian
UserIdTAG: 599243
UserNameTAG: crojasvilla
CreateTimeTAG: 2013-03-12T19:05:00Z
VoteTAG: 3
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 0
IndexTAG: 906
TitleTAG: Where have you gone, SusanAust??
No snide remarks, no exquisite snark, nothing which showcases your superiority and general wonderfulness for a few hours now :(
At this stage, learning a little bit about statistics is a secondary reason to do this course; the primary one HAS to be to read SusanAust's comments to her fellow students.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-12T18:53:02Z
VoteTAG: 10
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Anonymous' prose is always a winner too.
FirstChildUserIdTAG: 1057358
FirstChildUserNameTAG: s_zambelli
FirstChildCreateTimeTAG: 2013-03-12T20:45:11Z
FirstChildVoteTAG: 5
SecondChildTAG: What's wrong of posting anon?
SecondChildUserIdTAG: 608203
SecondChildUserNameTAG: chauct
SecondChildCreateTimeTAG: 2013-03-13T00:57:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Nothing is wrong with posting anon - we are all anon courtesy of our username.
But anonymous posts attacking others, are just begging to be smacked down. For some reason Skyhooks is playing in my mind.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-13T01:11:37Z
SecondChildVoteTAG: 0
SecondChildTAG: $\sigma \nu $
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-13T04:01:20Z
SecondChildVoteTAG: 0
FirstChildTAG: Maybe, unlike you, she ummmmm has a life? Family? Job? And unlike so many here, she doesn't whinge and whine about the injustice of voluntarily signing up for a free online course that then conflicts with real life commitments.
Or maybe she has finally lost all hope for commonsense, humanity, intelligence,etc - and called it a day?
I don't blame her if she has. As a researcher in a certain nameless field, I am more than stunned by the attitudes here and on other moocs.
>no exquisite snark
Something that is really needed here. Some snark to break up the constant "it's all about ME ME ME ME ME and more ME".
And I do love anonymous posters. Particularly those who really do believe their post is anonymous. No, it's not. Not to those who matter.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-13T01:01:55Z
FirstChildVoteTAG: 0
SecondChildTAG: I think that this is feeding trolling.I request everyone stop.It serves no purpose.The whole discussion should be held out of this forum if people want to pursue it.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-13T01:51:41Z
SecondChildVoteTAG: 0
FirstChildTAG: As per discussion forum guidelines-no negative commentary or flaming.Please stop this thread. It doesn't help anyone as far as statistics is concerned.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T01:13:39Z
FirstChildVoteTAG: 2
SecondChildTAG: You should be a Community TA, if this course had one. :)
SecondChildUserIdTAG: 1157957
SecondChildUserNameTAG: meganbh
SecondChildCreateTimeTAG: 2013-03-13T01:18:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't know what a TA is exactly but nothing is gained by playing out animosity or being rude or negative -it just detracts from the main point of this course - learning statistics.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-13T01:46:12Z
SecondChildVoteTAG: 0
SecondChildTAG: TA = Teaching Assistant (someone who knows about the topic and is active and productive in the forums). My other edX course (MIT14.73x) has Community TAs.
SecondChildUserIdTAG: 1157957
SecondChildUserNameTAG: meganbh
SecondChildCreateTimeTAG: 2013-03-13T05:56:01Z
SecondChildVoteTAG: 0
FirstChildTAG: (Totally OT)
Some good sayings to get out of negativity.
Life is short - fill it up with sweetness rather than bitterness and acrimony and negativity and imposing o each other.
http://www.petapixel.com/2013/03/08/time-lapse-15-months-of-a-forests-life-in-3-minutes/
"We should all keep an open mind - but not so open as our brains leak out our ears."
There are no need for a Kaycee Nicoles. We are all anonymous here but that should not be an excuse for use or abuse. Do not post anything here that you would not in real life is a good guide to civil exchange.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-13T01:57:03Z
FirstChildVoteTAG: 2
FirstChildTAG: LOL. Read old posts, and you find some hidden gems. Snark. Yes, we need some more of it at the moment.The sanctimonious tripe being posted is enough to curdle milk.
FirstChildUserIdTAG: 1421305
FirstChildUserNameTAG: lalotsb
FirstChildCreateTimeTAG: 2013-03-30T07:18:43Z
FirstChildVoteTAG: 1
IndexTAG: 907
TitleTAG: importance of not loosing focus
Hi All
Just want to share something... I decided to do this course to learn something completely new, completely not connected to anything I did so far... And it was pretty good idea so far... and surprisingly pretty enjoyable. The lectures are really good (thanks for that!) and I did score pretty well so far...
And this is where the problem occurs! Doing pretty well on the assignments (not dropping below 70%) I lost focus of what's important. Watched some videos without paying attention... and suddenly when it came to exercise set 7 I found myself completely stupefied! I did pretty well but alarming bells were ringing. Right after submitting exercise I went back to videos... and got the perfect score with next exercise submitted :D
The bottom line is... folks, we are half way through... so pay attention! :D
UserIdTAG: 905926
UserNameTAG: MarcinJ77
CreateTimeTAG: 2013-03-12T18:43:03Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Well said, the course shouldn't be hastily done away with, on the pretext that it's too easy.
One can dive deep into it, the way Prasannasimha has done..!
FirstChildUserIdTAG: 916575
FirstChildUserNameTAG: Vipul94
FirstChildCreateTimeTAG: 2013-03-12T19:05:16Z
FirstChildVoteTAG: 3
SecondChildTAG: I did the same - mentally wandered off during a lecture. A cup of coffee and re-watching it helped...
Prof A is wonderful; I love her side comments!
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-12T21:19:46Z
SecondChildVoteTAG: 0
FirstChildTAG: Thumbs up for what you said, completely agree. And actually thumbs up for professors for giving exercise set after every 20-40 minutes of lectures, this allows us to realise that we have lost attention before it is out of control.
FirstChildUserIdTAG: 127421
FirstChildUserNameTAG: apbyte
FirstChildCreateTimeTAG: 2013-03-12T20:20:31Z
FirstChildVoteTAG: 5
IndexTAG: 908
TitleTAG: Captions in Full screen mode- Bottom of the video is hidden in fill the browser mode
Why can't i see the captions when i'm using the full screen instead of fill the browser mode? And why can't i still not see the bottom of the video in the fill the browser mode?It is so frustrating!I've tried everything mentioned in other posts but nothing has worked so far :(
UserIdTAG: 1259481
UserNameTAG: MrsFounta
CreateTimeTAG: 2013-03-12T18:43:00Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Try hitting F11 to resize your window when in full screen.
FirstChildUserIdTAG: 142313
FirstChildUserNameTAG: jjave
FirstChildCreateTimeTAG: 2013-03-12T20:25:40Z
FirstChildVoteTAG: 1
SecondChildTAG: It worked!!!!Thanx a lot :)
SecondChildUserIdTAG: 1259481
SecondChildUserNameTAG: MrsFounta
SecondChildCreateTimeTAG: 2013-03-12T22:01:37Z
SecondChildVoteTAG: 0
IndexTAG: 909
TitleTAG: Problem 1C
I did this rounding to 69 and 71 first, then to 69.9 and 70.1. Both results - and the way they were calculated - should have been correct. Turns out the rounding should have been to 69.5 and 70.5, so my answers were wrong. Did I misread the question? If not, can you amend my score? thanks
UserIdTAG: 970345
UserNameTAG: Leviathano79
CreateTimeTAG: 2013-03-12T18:33:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: i agree...either (and most probably) question was open to many interpretation or we misread it.....i too got wrong answer in this....request to ADMIN team to look in to this.....thanks
FirstChildUserIdTAG: 1267420
FirstChildUserNameTAG: axay_shah
FirstChildCreateTimeTAG: 2013-03-12T19:23:52Z
FirstChildVoteTAG: 0
FirstChildTAG: The question asks for 70 inches, to the nearest inch. When you round numbers to the nearest whole number, you end up with an interval 0.5 units on both sides of each whole number. So 69.4 would round to 69, while 69.5 would round to 70.
To give another example 69.499999999999999999999999.... would round to 69 since it is (only just) the closest whole number. So the cut-off values are +/-0.5 inches of each whole inch.
Is that any clearer?
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-03-12T20:01:42Z
FirstChildVoteTAG: 4
SecondChildTAG: yes Thank you so much :)
SecondChildUserIdTAG: 1097005
SecondChildUserNameTAG: carmenrojas
SecondChildCreateTimeTAG: 2013-03-12T23:12:23Z
SecondChildVoteTAG: 0
IndexTAG: 910
TitleTAG: midterm exam
during the midterm exam will be available the video-lectures(section) or the exercizes set ?
UserIdTAG: 1147076
UserNameTAG: giomicho
CreateTimeTAG: 2013-03-12T18:26:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: All resources will still be available except the discussion boards (for obvious reasons!) which will be in 'read-only' mode for the duration.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-12T21:30:08Z
FirstChildVoteTAG: 0
SecondChildTAG: ok thank u!!
SecondChildUserIdTAG: 1147076
SecondChildUserNameTAG: giomicho
SecondChildCreateTimeTAG: 2013-03-12T22:21:11Z
SecondChildVoteTAG: 0
FirstChildTAG: What questions I have to review in order to get a better grade in the midterm ?
Please give me some examples.
Thank you very much !
Cheer up
Bill
FirstChildUserIdTAG: 967906
FirstChildUserNameTAG: Billchau2013
FirstChildCreateTimeTAG: 2013-03-13T00:42:03Z
FirstChildVoteTAG: 0
IndexTAG: 911
TitleTAG: Feet, inches...
Come on folks, there is a reason the rest of the world adopted the metric system!
:)
UserIdTAG: 387767
UserNameTAG: JanDE
CreateTimeTAG: 2013-03-12T17:44:10Z
VoteTAG: 7
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 5
FirstChildTAG: hahahaha... yes... to mess with other measure systems LOL
FirstChildUserIdTAG: 905926
FirstChildUserNameTAG: MarcinJ77
FirstChildCreateTimeTAG: 2013-03-12T18:33:06Z
FirstChildVoteTAG: 0
FirstChildTAG: This is to test us, if you can easily work with and switch between both then you have prooved to be Chuck Norris and statistics will be easy thing for you :D
I am from rest of the world by the way.
FirstChildUserIdTAG: 127421
FirstChildUserNameTAG: apbyte
FirstChildCreateTimeTAG: 2013-03-12T20:23:51Z
FirstChildVoteTAG: 1
FirstChildTAG: I grew up with feet and inches (and pounds and ounces, pints and gallons etc etc) here in the UK where it is/was known as the Imperial System but saw them gradually replaced from the late sixties, first in science then later in general use (largely driven by membership of the EEC/EU). Although I still find imperial measures more intuitive and 'person sized', SI (Système international) 'metric' units are an awful lot easier in calculation.
Although saying a person is 6 feet tall allows me to visualise their height where 182cm doesn't, that may well be due to my early indoctrination. A pint still seems like a decent measure for a drink of beer though and is one of the few remaining items where the use of non-SI measures are allowed in UK law. Furlongs are still used in horse racing (eight furlongs to the mile, 220 yards to the furlong, 3 feet to the yard, 12 inches to the foot) and miles are still used in road signage - but that's it so far as I can recall in general use now.
Just to confuse things even further for the enjoyment of our fellow-students worldwide, the UK 'Imperial' system is not entirely compatible with the US system. Although pounds and ounces are the same (but our american cousins don't use stones (= 14 lbs (lbs = pounds!)) look, nested parentheses!) gallons and fluid ounces aren't.
I have to admit that after more than 40 years of using metric units I still, mentally, think 'kilogram - about two pounds' when I'm buying fruit and still estimate sizes in inches and convert (about 2.5cm to the inch). Luckily enough, the last section of my little finger is exactly 1" (" = inch) in length (assuming I keep my nails trimmed!) which means I always have a *handy* measure available...
Isn't it nice having this free time to chat before the exam?
Paul
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-12T21:50:42Z
FirstChildVoteTAG: 1
SecondChildTAG: ditto
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-13T01:27:50Z
SecondChildVoteTAG: 0
FirstChildTAG: *Way* back in 7th grade (uh, mid-1960's...), my science teacher insisted that the US would go metric within 10 years.
When I'm King things'll be different...
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-12T23:41:32Z
FirstChildVoteTAG: 0
FirstChildTAG: I was never, ever taught metric in the US.
FirstChildUserIdTAG: 1157957
FirstChildUserNameTAG: meganbh
FirstChildCreateTimeTAG: 2013-03-13T05:56:49Z
FirstChildVoteTAG: 0
IndexTAG: 912
TitleTAG: STAFF--sticky applet
When I try to enter bounds on the normal curve applet, sometimes the applet changes the number I have entered, so it's impossible for me to get the exact bounds that I am trying to achieve. It's almost like the applet has a mind of it's own and gets fixated on certain bounds and won't allow others to be entered (like it's catching on numbers). Without the ability to get the right percentile, I can't accurately answer questions that require use of the applet. What am I to do?
UserIdTAG: 406503
UserNameTAG: Wind
CreateTimeTAG: 2013-03-12T17:42:42Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: I do it in the following way to obtain the upto 3 decimal places accuracy for the Z value:
1. High-lighted the slide bar with you mouse.
2. Use the Arrow keys on key board to increase or decrease the Z value.
3. Fine tune the third decimal place digit to get the closest approximation that aiming for.
Hope this help you to get the closest approximation. It works for me.
FirstChildUserIdTAG: 155350
FirstChildUserNameTAG: ingenieur
FirstChildCreateTimeTAG: 2013-03-12T17:51:44Z
FirstChildVoteTAG: 2
SecondChildTAG: This is exactly what works for me, too, using Chrome and Firefox. Thanks for posting.
SecondChildUserIdTAG: 1231212
SecondChildUserNameTAG: wsk
SecondChildCreateTimeTAG: 2013-03-12T19:48:42Z
SecondChildVoteTAG: 0
IndexTAG: 913
TitleTAG: william's view
indeed the introduction to statistic is well explained. it is imperative for me to mention here that the content in this course is helping immensely in adding value to the work am doing.
UserIdTAG: 1187956
UserNameTAG: omojowo
CreateTimeTAG: 2013-03-12T17:41:12Z
VoteTAG: 0
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 0
IndexTAG: 914
TitleTAG: what is the applet
what is the apllet
UserIdTAG: 776071
UserNameTAG: phaliaa
CreateTimeTAG: 2013-03-12T17:24:23Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 8 / Reading and Practice For Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: Applet is JAVA Application/Application build on JAVA
FirstChildUserIdTAG: 498723
FirstChildUserNameTAG: YLTO
FirstChildCreateTimeTAG: 2013-03-12T18:13:06Z
FirstChildVoteTAG: 0
SecondChildTAG: i can't download that....
SecondChildUserIdTAG: 1302054
SecondChildUserNameTAG: tayyabarawjani25
SecondChildCreateTimeTAG: 2013-03-12T19:37:27Z
SecondChildVoteTAG: 0
SecondChildTAG: not this one, no. You just use it in your web browser.
You don't actually need java installed to use it, since it is written in javascript (which is unrelated to java). Any up-to-date web browser should work.
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-12T20:07:40Z
SecondChildVoteTAG: 0
FirstChildTAG: Question, would like to take a quick look at prior solution sets and, well, can't seem to locate them......any suggestions as to where I should be looking? Thanks!
FirstChildUserIdTAG: 1167726
FirstChildUserNameTAG: Jephill
FirstChildCreateTimeTAG: 2013-03-12T20:10:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Just go back to the Week you want, click on the Exercise Set and you're there. For answers to particular questions, click the "show answer" button.
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-03-12T23:09:42Z
SecondChildVoteTAG: 0
IndexTAG: 915
TitleTAG: query
Hi,
I would be grateful if someone could please tell me if solutions to the first two weeks assignments are available?
Thanks
Sohini
UserIdTAG: 592961
UserNameTAG: Sohini
CreateTimeTAG: 2013-03-12T17:03:04Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: i guess NO....its not available
FirstChildUserIdTAG: 1267420
FirstChildUserNameTAG: axay_shah
FirstChildCreateTimeTAG: 2013-03-12T19:25:54Z
FirstChildVoteTAG: 0
SecondChildTAG: They *are* available.
Go to the Courseware. On the left you have:
- General Course Information
- Week 1: Feb 20 - Feb 26
- Week 2: Feb 27 - Mar 5
- Week 3: Wed Mar 6 - Tue Mar 12
Click on the week you're interested in, open the Exercise Sets and click the "Show Answer" button below every problem.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T20:42:06Z
SecondChildVoteTAG: 0
IndexTAG: 916
TitleTAG: Missing income data
Dear teaching staff,
The income data referred to in the above questions is not found anywhere in the resource materials. Please attach it.
Thanks,
UserIdTAG: 910465
UserNameTAG: kbelachew
CreateTimeTAG: 2013-03-12T16:54:36Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: As stated in the question the data are in lecture 2.4, starting from minute 2:55 or you can find them on slides 9-23 of the lecture: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec2.4.pdf
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-12T18:45:23Z
FirstChildVoteTAG: 0
IndexTAG: 917
TitleTAG: Metric
From exercise set 8:
[For those of you who are used to the metric system: one foot is 12 inches.]
How Americans ever manage to do any science or engineering is beyond me. :)
UserIdTAG: 901827
UserNameTAG: clv101
CreateTimeTAG: 2013-03-12T15:57:45Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Simple: their scientists and engineers *do* use the metric system :)
Last time they forgot to do that, [disaster ensued][1] xD
[1]: http://en.wikipedia.org/wiki/Mars_Climate_Orbiter
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T16:17:38Z
FirstChildVoteTAG: 1
FirstChildTAG: I am an American born in Europe and we do just fine with both systems.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-03-12T16:19:41Z
FirstChildVoteTAG: 0
FirstChildTAG: Really depends on what you are use too. If I'm told a weight of 50kg I have no idea if I should bring a plastic bag or a truck. 110lbs I have a immediate idea of what it takes to handle that.
But I have to agree doing science and engineering calculations is much easier in SI units. If you mix the two you tend to smack into planets.
So lets compromise. US (Burma and Liberia too) will go to metric if the rest of the world will write their numbers with proper separators like 1,000,000.00 , drive on the right side of the road, and everyone write dates in day, month, year format.
FirstChildUserIdTAG: 972298
FirstChildUserNameTAG: dorght
FirstChildCreateTimeTAG: 2013-03-12T16:28:28Z
FirstChildVoteTAG: 3
SecondChildTAG: I can understand that it's very difficult to get a whole country to change a weights and measures system they have been using for centuries, but who could possibly think it was a good idea to swap the month and day in a date format?
It throws me every time I see it. It seems to me as logical as writing the time in the format MM:SS:HH
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-12T20:18:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Isn't US the one that writes dates in wrong format? I mean month/day/year ?
rest of the world I think writes them in normal ordered way as you said - day, month, year
SecondChildUserIdTAG: 127421
SecondChildUserNameTAG: apbyte
SecondChildCreateTimeTAG: 2013-03-12T20:28:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Year-month-day would be the way to go:
[http://www.xkcd.com/1179/][1]
Regarding unit systems, using the same convention everywhere would help immensely, but it doesn't necessarily have to be the metric system. Metric sounds nice because we have 10 fingers, but we are also used to systems in base 12... or even in base 2, nowadays.
[1]: http://www.xkcd.com/1179/
SecondChildUserIdTAG: 1057358
SecondChildUserNameTAG: s_zambelli
SecondChildCreateTimeTAG: 2013-03-12T20:53:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Metric is a lot easier to do sums in your head. I don't think it is just because we have 10 fingers, but because we represent numbers with a base-10 system (ie. the 10 digits 0-9), even in imperial units (which uses multiples of 12, 14, 16 depending on what it is)
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-12T21:40:56Z
SecondChildVoteTAG: 0
SecondChildTAG: We normally work in base 10 (ie decimal) and that may well be because we have ten fingers but the origin is largely irrelevant. It's how it is and, frankly, it isn't going to change even if someone could provide a convincing argument for another base - after all, hexadecimal (base 16) has not really exerted any influence outside the world of computing despite 50-odd years of use there.
Much as I love our traditional Imperial System herein teh UK, it is not even a case of using, say, base 12 instead of case decimal. We have 16 ounces to the pound, 112 pounds to the hundredweight (which is 8 stone, stone is 14 pounds) or 100 pounds to the hundredweight in US. The ton is defined in both UK and US as 20cwt (hundredweight) but as the cwt is different UK tons weight 2,240 pounds while the US ones weigh 2,000. By happy chance the UK ton is far closer to the metric tonne (100kg approx 2,204 pounds) than the US version.
A last blast of joy, the British currency pre-1971 'decimalisation' used 12 pennies to the shilling, 20 shillings to the pound (so 240 pence to the pound). A price might be expressed £4 10s 3½d meaning 4 pounds, 10 shillings and three and a half pence (normally said as "four pounds, ten and thrupence ha'penny").
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-12T22:17:50Z
SecondChildVoteTAG: 0
SecondChildTAG: I remember half a pound of tupenny rice half a pound of treacle ,mix it up and make them nice -pop goes the weasel- the tupenny was two penny !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-13T02:28:03Z
SecondChildVoteTAG: 0
FirstChildTAG: The Imperial System is just as logical to us as the metric system is to non-Americans (or non-Burmese or non-Liberians). And some Americans know both.
FirstChildUserIdTAG: 1157957
FirstChildUserNameTAG: meganbh
FirstChildCreateTimeTAG: 2013-03-13T06:10:35Z
FirstChildVoteTAG: 0
IndexTAG: 918
TitleTAG: HELP!!!
Guys! I have scored not less than 60% in any of the ES.. Rather I have scored 100%.. two 60% and rest above 75%
Then why does my average total say 30% ???
Does this mean I don't get the cerificate?
How was the thing calculated? :(
UserIdTAG: 1211883
UserNameTAG: Santastic
CreateTimeTAG: 2013-03-12T15:17:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 3
FirstChildTAG: I believe that that is your score >> So Far << It is not the final score. You have more ES and Midterm and Final marks to add to that number
Greg
FirstChildUserIdTAG: 297742
FirstChildUserNameTAG: GregDC
FirstChildCreateTimeTAG: 2013-03-12T15:22:57Z
FirstChildVoteTAG: 1
SecondChildTAG: Oh okay.. Thanks
(*fingers crossed*)
SecondChildUserIdTAG: 1211883
SecondChildUserNameTAG: Santastic
SecondChildCreateTimeTAG: 2013-03-12T15:24:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, the course is not over yet :D
Plus, the The Exercise Sets only counts as 50% for the total grade, so if you currently have 60% ES Average, the total is correct at 30%.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T15:26:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Some statistics would help you realize that the 30 % you see is out of total 100 % , you got a midterm comingplus two more weeks and the final. By the time you're done with the midterm you will eventually reach the 35 % and pass!
FirstChildUserIdTAG: 1247915
FirstChildUserNameTAG: Iliri2013
FirstChildCreateTimeTAG: 2013-03-12T17:32:56Z
FirstChildVoteTAG: 0
FirstChildTAG: If you hover your mouse on top of the progress bars it will show you some information.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-03-12T19:57:40Z
FirstChildVoteTAG: 0
IndexTAG: 919
TitleTAG: 1 c
Did not follow the explanation. What do u mean by the term "nearest inch" ? Did not follow why we subtract 0.5 from both sides of the mean. Please explain.
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UserNameTAG: Santastic
CreateTimeTAG: 2013-03-12T15:10:08Z
VoteTAG: 1
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: It's basically about rounding.
If I want 10 "to the nearest integer", and I get 9.6, then the result is correct, because 9.6 rounded to an integer is 10. The same for 10.499999.
10.5 *would* technically be wrong since it commonly rounds to 11, but we still have to take it as the upper bound for our *continuous* range, or we'd miss some values.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T15:32:49Z
FirstChildVoteTAG: 0
IndexTAG: 920
TitleTAG: Lecture summery
Hi,,,
Could you please post the missing lectures(3.3, 3.4,( all lecture 4&5)
Thank you for your support
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UserNameTAG: Drhannaa
CreateTimeTAG: 2013-03-12T14:47:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 921
TitleTAG: Browser settings to make the applets work
If your applets in the exercises or online textbook do not work use the following methods
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/browser-setting-appletsif-they-do-not-work/
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-12T14:31:31Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Or, check this page, which expands a little on it :)
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/fixing-normal-curve-applet/
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T15:01:14Z
FirstChildVoteTAG: 1
SecondChildTAG: You can delete mine
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T15:16:08Z
SecondChildVoteTAG: 0
IndexTAG: 922
TitleTAG: Problem 3B
I have a doubt about the approach for 3B.
When we say 5 marks for correct and -1 for incorrect answer, why cant we look at the problem this way:
New Average = 5 x 6.2 - 10 x 3.8 = 27.2
Therefore the SD of the transformed data should be 5*SD of original data?
I read in forum that the way to look at it is 5x (Num Correct) - (10 - Num Correct), which is 6 X Num correct - 10, therefore giving us the SD of transformed data as 6 X SD of original.
Can any one explain why is the first approach wrong?
UserIdTAG: 1011172
UserNameTAG: BChoudhary
CreateTimeTAG: 2013-03-12T14:18:34Z
VoteTAG: 7
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 4
FirstChildTAG: Because to transform the Average and SD, you need a formula in the $m*x+a$ format, m being the multiplicative constant, and a the additive constant.
Until you get to that format, you can't apply the transformation rules to find the transformed Average and SD.
Also, mind the honor code. Due date has not come yet and yet you are posting solutions(right or wrong, it doesn't matter). Please edit your post.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T15:08:31Z
FirstChildVoteTAG: 2
SecondChildTAG: Hello,
Its not like that we have to have a formula of linear transformation as you have given, but instead we hadn't dealt with the tools to solve the problem based on the lines, the other person is thinking.
SecondChildUserIdTAG: 1004532
SecondChildUserNameTAG: goelamit05
SecondChildCreateTimeTAG: 2013-03-12T15:16:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok, yes, you could also do the research for yourself and find other methods.
But, for the purposes of the current lectures and exercises, you need to get to that format.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T15:22:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot for your compliments. I had already done a research and found other methods for myself and if you need the inferences then i will be very happy to share them with you. But i think that we are not a bookworms here. And sticking to one particular format and restricting our mind to a particular format is not a good idea.
SecondChildUserIdTAG: 1004532
SecondChildUserNameTAG: goelamit05
SecondChildCreateTimeTAG: 2013-03-12T15:32:15Z
SecondChildVoteTAG: 0
FirstChildTAG: Hello,
First approach is not wrong. Its right that we can write the new average as you have written but you are going wrong in SD. it can be just straight 5 SD as we have SD for wrong answers too. so you have to think in terms of SD(ax - by) and with this, the terms like co-variance and co-relations comes in picture which we have not deal in this course till now.
FirstChildUserIdTAG: 1004532
FirstChildUserNameTAG: goelamit05
FirstChildCreateTimeTAG: 2013-03-12T15:08:49Z
FirstChildVoteTAG: 2
SecondChildTAG: I agree that we have not covered how to deal with multiple effects on the SD yet
SecondChildUserIdTAG: 406503
SecondChildUserNameTAG: Wind
SecondChildCreateTimeTAG: 2013-03-12T18:16:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm still not clear on this - I also calculated the incorrect way, getting the correct average, but incorrect SD.
I'm not sure what you mean by "SD(ax-by)". Is the 'a' and 'b' the same as from the transformation ( (Ax-avg)/SD )? What's 'x' and 'y'. I've got too many numbers and places to put 'em... :)
I see that we get the correct average both ways. But I don't understand why we have to do it the stated way to get the SD correctly.
Can you explain further, please? I'm trying to understand *why* rather than just memorize *what* to do.
(I'd put actual numbers down here, but there are still a few hours before the homework's due)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-12T19:02:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Without using specific numbers here, I'll say only that we have to think about the TWO parts of the score calculation. You are multiplying the right answers, which have a standard deviation, by ____ and you are also multiplying the wrong answers, which have a standard deviation, by ___. Think about the factors by which you would be multiplying EACH standard deviation. Both have to be included in the answer. Hope this is helpful.
SecondChildUserIdTAG: 773223
SecondChildUserNameTAG: Andaponte
SecondChildCreateTimeTAG: 2013-03-12T23:28:24Z
SecondChildVoteTAG: 0
SecondChildTAG: @all,
if we will use SD(ax - by) then we need to have co-variance and co-relation. and we have a result for
SD(ax-by) = sqroot( a^2 * var(x) + b^2 * var(y) - 2ab cov(x,y) )
where cov(x,y) = var(x)* var(y)* co-relation(x,y)
here x, y are random variable and a,b are constants.
SecondChildUserIdTAG: 1004532
SecondChildUserNameTAG: goelamit05
SecondChildCreateTimeTAG: 2013-03-13T03:01:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you, yes, it's definitely helpful. I *think* I get it, but I'm not completely sure. After the homework deadline, I'll post what I think you're saying to confirm I've understood correctly.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-13T03:15:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Andaponte - can we continue this again, now that the homework deadline is past?
If I do the SD transformation using the *calculated* number of wrong answers (3.8)
> 5*6.2 - 3.8
> (so transforming SD by multiplying by 5)
Then I'm not including the wrong answers in the calulation. But really, the multiplier for the wrong answers is 1:
> 5*6.2 - 1*3.8
or:
> 5*6.2 + (-1)*3.8
But now I get confused again - maybe... We've got multipliers of 5 and -1. I started wondering why the SD transformation wouldn't be to multiply by (5-1) or four.
Then I remembered we use the absolute value of the multiplier, so it would indeed be 6:
> (5 + |-1| ) = 6
That's not quite as clean as expressing the number of wrong answers in terms of the (total - number right) but am I correct in my thinking?
I'll remember to use a (total - number right) type of equation; it simplifies easier. But if my explanation is correct, now I understand why I got the wrong answer.
Thanks for working with me on this!
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T10:27:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Goelamit, the reason the equation
5*6.2 - 10*3.8 is wrong because
a) 5 = 5 points for every question right
b) 6.2 = Average numbers of question right
c) 10 = total number of questions on the test
d) 3.8 = Average numbers of question wrong
How can you get 10 times 3.8? It doesn't make any sense.
And when you do the math 5 times 6.2, minus 10 times 3.8, they don't equal 27.2.
5*6.2 = 31
10* 3.8 = 38
31 - 38 = -7.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-12T23:31:11Z
FirstChildVoteTAG: 0
SecondChildTAG: there is a typo error there while writing the equation. its 1 not 10. it's 5*6.2 - 1*3.8.
SecondChildUserIdTAG: 1004532
SecondChildUserNameTAG: goelamit05
SecondChildCreateTimeTAG: 2013-03-13T02:55:52Z
SecondChildVoteTAG: 0
FirstChildTAG: It was confusing for me at 1st too, make sure are accounting for how the scores change (pos and negative effect) based on the change in change from the avg by adding an SD. Hope tho isn't giving too much info
FirstChildUserIdTAG: 348290
FirstChildUserNameTAG: joshb
FirstChildCreateTimeTAG: 2013-03-13T01:40:51Z
FirstChildVoteTAG: 0
IndexTAG: 923
TitleTAG: problem 3B
I think problem 3B solution is wrong (wont tell anything else because of the honor code). I would ask the staff to verify it.
Regards,
-Mario
UserIdTAG: 507259
UserNameTAG: mruz
CreateTimeTAG: 2013-03-12T14:02:45Z
VoteTAG: 1
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: I don't think it's wrong. Looking at the solutions for both 3A and 3B should explain why the result is correct.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T15:03:04Z
FirstChildVoteTAG: 1
IndexTAG: 924
TitleTAG: Prob 7 Help.
Can I get some directions on how to start on this exercise?
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UserNameTAG: Anamile71
CreateTimeTAG: 2013-03-12T13:40:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: There are several posts outlining the algebra involved in answering this question, no sense to repeat those explanations here - just browse the discussion for them (you should already know to do this - it's in the forum guidelines). Also, there is a "shortcut" that you will learn when you click "show answer" after you've used your two submissions. You will then proceed to laugh at yourself for doing all that algebra. Good luck!
FirstChildUserIdTAG: 969411
FirstChildUserNameTAG: McAlary
FirstChildCreateTimeTAG: 2013-03-12T14:00:50Z
FirstChildVoteTAG: 0
FirstChildTAG: I am repeating my post for this question elsewhere as probably it is buried under other post.
Here is the step by step guide:
- Using standard applet, find out 60th percentile. Lets call this **z1**.
- From the problem statement we know, the 60th percentile = 110. Lets call this **µ1**.
- We do not know the SD (**σ**) and average (**µ**) yet.
- Let us plug these values in the following equation:
> z1 = (µ1- µ)/σ
> µ1 - µ = z1 * σ
> **µ = µ1 - (z1 * σ)**
- Again, using standard applet, find out 70th percentile. Call this **z2**.
- Also, the problem statement tells us that 70th percentile is 120. Lets call it **µ2**.
- Time to again use the same formula we used above for 60th percentile. And we get the following equation:
> **µ = µ2 - (z2 * σ)**
- Now note the two highlighted formulae. Using simple mathematical principal, we get the following:
> **µ1 - (z1 * σ) = µ2 - (z2 * σ)**
- Resolve this equation to find **σ**
- Next, plug in the value of σ in either of the above two formulae to get the **µ**.
> z1 = (µ1 - µ )/ σ. *(Hint: We already know values of z1, µ1, and σ by now!)*
- Ditto, find out 90th percentile and call it **z3.**
- By now, we already have **z3, µ** and **σ** and have to find **µ3**.
> Hint: use the Same old formula z3 = (**µ3** - µ )/ σ.
Hope this explains.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-12T17:38:36Z
FirstChildVoteTAG: 9
SecondChildTAG: This helps a lot! Thank you for posting it - I found walking through it helps me to better understand.
This would be worth putting in the wiki.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-12T19:48:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-12T19:49:42Z
SecondChildVoteTAG: 0
SecondChildTAG: How come **µ1 - µ = z1 * σ** be **µ = µ1 - (z1 * σ)** ? shouldn't it be **-µ = z1 * σ - µ1**
SecondChildUserIdTAG: 498723
SecondChildUserNameTAG: YLTO
SecondChildCreateTimeTAG: 2013-03-13T02:23:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I check with the result of this formula and give me error. I think that Z is a percentil and it is not valid as a standar unit. Is it posible?
SecondChildUserIdTAG: 405568
SecondChildUserNameTAG: hugoanf
SecondChildCreateTimeTAG: 2013-03-13T04:15:39Z
SecondChildVoteTAG: 0
SecondChildTAG: @YLTO: I had the same reaction at first...
starting with:
> **z1 = (µ1 - µ)/σ**
multiply each side by **σ** to get:
> **z1 * σ = µ1 - µ**
add **µ** to each side:
> **(z1 * σ) + µ = µ1**
subtract **(z1 * σ)** from each side:
> **µ = µ1 - (z1 * σ)**
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-13T04:37:11Z
SecondChildVoteTAG: 0
IndexTAG: 925
TitleTAG: problem 5
Can someone pleaseeeeeeeeee explain to me why the answer at problem 5 is 0.87? We already know that 50% of the area under the normal curve is between -5 and 0 I really don't understand.. /feeling stupid/
UserIdTAG: 1281760
UserNameTAG: Eucrates
CreateTimeTAG: 2013-03-12T12:53:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: The area in question starts at -0.5, not -5.0...
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-12T12:55:21Z
FirstChildVoteTAG: 1
SecondChildTAG: /facepalm/ I am stupid indeed.. thank you very much.. I need to change glasses ^^
SecondChildUserIdTAG: 1281760
SecondChildUserNameTAG: Eucrates
SecondChildCreateTimeTAG: 2013-03-12T12:59:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Please don't post the answers in the discussions section.
SecondChildUserIdTAG: 1164331
SecondChildUserNameTAG: Oberyn
SecondChildCreateTimeTAG: 2013-03-12T15:27:56Z
SecondChildVoteTAG: 0
IndexTAG: 926
TitleTAG: Problem 2
I don´t get it. The answer says:
"(...) That means 42 in the original units is 0.4*5 = 2 units above average, which means the average is 40."
?? Help please
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UserNameTAG: patymut
CreateTimeTAG: 2013-03-12T12:46:57Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
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FirstChildTAG: The Standard Normal Curve graph measures its z values as the distances from the Average, expressed in multiples of the SD.
You know that 42 is 0.4 on the standard graph, which means 42 is 0.4*SD away from the average. You've found that the SD is 5.
Do I need to say more?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T13:24:29Z
FirstChildVoteTAG: 1
FirstChildTAG: That means 42 is 2 SD of the mean, the mean is therefore 40.
FirstChildUserIdTAG: 1278200
FirstChildUserNameTAG: Grosado
FirstChildCreateTimeTAG: 2013-03-12T13:37:52Z
FirstChildVoteTAG: 0
SecondChildTAG: This is wrong, it's 2 units above average, 0.4 SD away from the mean.
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-12T15:21:48Z
SecondChildVoteTAG: 0
IndexTAG: 927
TitleTAG: doubt in Q6
To Professor,
In the 6th question,it has been said to find the percent of entries that are more than 6 SDs above average.In my opinion,this implies that we are not supposed to take the left tail into account which is at a distance of (SD -k) because it is given clearly in the question....6SDs above average.Therefore,we must calculate the percent of entries that are lying within right tail and for finding it,Chebychev's formula doesn't hold for 1 tail
UserIdTAG: 1033884
UserNameTAG: vaishalivashisht
CreateTimeTAG: 2013-03-12T12:43:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: It does indeed hold, since it's a bound and you don't know anything about the symmetry of your dataset.
For all you now, the left tail could be empty and exactly $(\frac{1}{k^2}*100)\%$ entries could be on the right tail.
Even if that's not true, and some values are on the left tail, and/or the total percentage of values is lower, $\frac{1}{k^2}$ is still an upper bound and remains valid.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T13:29:46Z
FirstChildVoteTAG: 1
SecondChildTAG: Indeed that is the concept of a bound.I have 2 teaspoons of sugar in my closed (two) hands made into a fist .If you are asked how much is there at the most in a hand (one tail) all you can say is not more than two spoons and that is the truth even if there are zero spoons in one hand or up to two spoons in the same hand or if both spoons have any combination including equal to one spoon in each hand !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T13:40:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Thnx to both of you. I got it now.
SecondChildUserIdTAG: 1033884
SecondChildUserNameTAG: vaishalivashisht
SecondChildCreateTimeTAG: 2013-03-12T14:56:03Z
SecondChildVoteTAG: 0
IndexTAG: 928
TitleTAG: Histogram not working
I try all advice and histogram is not working.
UserIdTAG: 734057
UserNameTAG: cieursz
CreateTimeTAG: 2013-03-12T12:05:20Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 1
FirstChildTAG: Have you ensured your browser's default encoding is right, **and** cleaned your cache *afterwards*?
Most times, if the browser failed in loading the applet the first time, it doesn't even bother trying again until you clean the cache.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T13:33:19Z
FirstChildVoteTAG: 0
SecondChildTAG: Llionheart - you could post the steps in the wiki so that people can refer to it (or can be directed to it)when they face this recurrent problem.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T13:42:00Z
SecondChildVoteTAG: 0
SecondChildTAG: That's a good idea! For some reason I keep forgetting that there's the wiki :D
I'll get to it right now.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T13:51:37Z
SecondChildVoteTAG: 0
SecondChildTAG:
i have pasted the basics so you can elaborate it..I cannot ccreate alink on the main wiki page foe some reason.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T14:57:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Finally finished it! I've put the link inside the FAQ, or it is available directly from [here][1].
I wonder how many will actually see it without being directed from here xD
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/fixing-normal-curve-applet/
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T14:59:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Well every time a question comes up you can just say "look here" !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T15:18:07Z
SecondChildVoteTAG: 0
IndexTAG: 929
TitleTAG: are yu guys using Excel-ish softwares ?
I have a very big "issue": I really actually used excel (the open office version) once, 8 years ago and it was to add all the numbers in one vertical gentle A and to show the result in the last A rectangle....
So since the beggining, I m only using windows basic calculator, and my notebook and pensil...and It's quite hard to not be wrong, especially when you re-read yourself and see a 7 where you wrote a 1 and so on....
Am I an exception or are some of you also going all "pen paper" style?
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-03-12T12:01:36Z
VoteTAG: 1
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 4
FirstChildTAG: I am doing most of the calculations with a calculator or pen and pencil.I find the hand held calculator is a bit better for me to do it than the one in the computer - but that's me !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-12T12:14:02Z
FirstChildVoteTAG: 1
SecondChildTAG: I've gone technophile in the sense that I use my Nexus 7 Tablet as a scientific calculator, with a proper app.
Apart from that, it's pen-and-paper.
Excel(or equivalents) is bad because you end up doing things without understanding them, which is bad when you are learning, or trying to.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T13:37:11Z
SecondChildVoteTAG: 0
SecondChildTAG: I think spreadsheet software is fine for learning, IF you use it as a sophisticated calculator. I use it for adding, multiplying, finding the square root, etc. The only statistics function I have used so far is "average". I've typed the z formula: z = (x - mean)/SD so many times now doing exercises that I have it pretty well engraved in my memory.
SecondChildUserIdTAG: 1342025
SecondChildUserNameTAG: mbunch25
SecondChildCreateTimeTAG: 2013-03-13T02:27:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Here? Paper and pen work fine. The datasets are sufficiently small to allow double checking of numbers.
Otherwise, I'm a heavy excel user for stat applications as I have to run regressions on huge chunks of data.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-12T14:01:09Z
FirstChildVoteTAG: 1
FirstChildTAG: I'm using pen-and-paper, writing out what the calculation is, then using the Windows calculator and the applet. (and thinking about writing an Android app... :)
I'll use tools to confirm I have the correct answer, but I want to work it out myself so I understand what I'm doing. (hence, writing the calculation out each time even though I know what it is)
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-12T23:45:19Z
FirstChildVoteTAG: 0
FirstChildTAG: I am using pencil, paper and a calculator mostly so I have something to refer to later and to find and correct mistakes. I confess that I did use the SD feature on my calculator. Calculating SD more than once or twice is a waste if you understand the concept, I think.
FirstChildUserIdTAG: 905318
FirstChildUserNameTAG: kamili
FirstChildCreateTimeTAG: 2013-03-13T02:51:43Z
FirstChildVoteTAG: 0
IndexTAG: 930
TitleTAG: Open Book or Closed Book?
I have been completing the Exercise Sets closed book till date. But just reading the honour code now in preparation for the midterm exam seems to indicate that only the midterm is closed book.
Can someone please clarify whether or not:
1) The Exercise Sets
2) The Exams
are open or closed-book?
Thanks.
UserIdTAG: 902746
UserNameTAG: mjraji2000
CreateTimeTAG: 2013-03-12T11:24:48Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It is not.The Professor has clarified it in one of the posts.Because the training did not involve closed book exams the exam itself is open book.Be warned though as a paper setter for various university exams in the past (albeit not in statistics or even maths) that an open book exam is actually more difficult at times than a closed book one ;)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-12T12:12:37Z
FirstChildVoteTAG: 1
SecondChildTAG: As a former consumer of several paper exams, both open book and closed book(or, if you prefer, a former student who took many of those exams), I agree with Prasannasimha completely :)
Open-book tests check your *understanding* of the problems much more thoroughly.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T13:16:34Z
SecondChildVoteTAG: 0
IndexTAG: 931
TitleTAG: 1C
To be honest I had a look at the different variables here, and possible over thought it. The phrase to the nearest inch led me to a whole number where slightly different wording my have convinced me to go another way.
Such is life I guess
UserIdTAG: 7545
UserNameTAG: jasontimothyjones
CreateTimeTAG: 2013-03-12T11:05:56Z
VoteTAG: 3
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 3
FirstChildTAG: I have the same problem .... it refers to 70 to 71 inches or what ? I have entered the result for this computation and is not right :(
FirstChildUserIdTAG: 115080
FirstChildUserNameTAG: Adelin
FirstChildCreateTimeTAG: 2013-03-12T12:04:41Z
FirstChildVoteTAG: 0
SecondChildTAG: I googled and I found that [...If it is supposed to be 94.2 inches then the nearest whole inch is 94. Classic rounding off rules would have you round down if the last number is 5 or <5 and round up if the last number is >5. In this case, the number you are looking at to guide your rounding off process is 2. That is < 5 so you round off to 94....]
Good Luck
SecondChildUserIdTAG: 945953
SecondChildUserNameTAG: Turca
SecondChildCreateTimeTAG: 2013-03-12T13:06:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Tricky wording of the question is 'nearest to inch'... but now get it... it is from 69.5 to 70.5....
FirstChildUserIdTAG: 890751
FirstChildUserNameTAG: AkshayKale93
FirstChildCreateTimeTAG: 2013-03-12T14:36:09Z
FirstChildVoteTAG: 0
SecondChildTAG: got it too late :'(
SecondChildUserIdTAG: 1246720
SecondChildUserNameTAG: lilia1979
SecondChildCreateTimeTAG: 2013-03-12T15:01:09Z
SecondChildVoteTAG: 0
FirstChildTAG: I did it wrong first and went 'huh?' when I saw the red 'x'.
After a bit of thinking, it dawned on me what "to the nearest inch" meant.
Annoying though some of the wordings are, we'll see such things in real life...
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-12T23:48:01Z
FirstChildVoteTAG: 0
IndexTAG: 932
TitleTAG: Please realise Week 4 materials on Thursday March 13 or prolong due date
I'll be on the trip on 03.15-03.20. If material will be realised on 03.14 and due date will be 03.20, it will be impossible to me to do exercises. Please realise Week4 materials on dates indicated in syllabus (03.13).
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-12T10:51:07Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: LOL! Talk about the ME ME ME generation. Alive and thriving on moocs.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-12T11:02:03Z
FirstChildVoteTAG: 2
SecondChildTAG: SusanAust, please keep all the snide comments to yourself. I don't appreciate you constantly deriding people who you've never met. Have some empathy: don't presume to understand his situation. He isn't the only one who struggles to get these assignments done on time between work, family, and other circumstances.
If you don't have something to contribute, please don't comment.
SecondChildUserIdTAG: 879900
SecondChildUserNameTAG: IanCJohnson
SecondChildCreateTimeTAG: 2013-03-12T16:59:39Z
SecondChildVoteTAG: 0
SecondChildTAG: The point is not one of empathy (and anyway, since, as you say, we can't *presume to understand his situation*, how much empathy could we have) but of practicality. I would assume there are somewhere between 20,000 and 100,000 students registered on this course (based on figures for other courses). There is no way that the course teams have the capacity to consider individual appeals to vary the rules. The decision to change the release date was taken in the interests of the majority of students, as was the decision to lighten the workload this week before the midterm.
The team have shown themselves willing to modify the scheduling where there are seen to be widespread issues, as in the decision to allow all Exercises to be submitted by the weekly cut-off date rather than needing to be submitted three times per week.
I think you were a little sharp with Susan who has chosen to give a lot of time in replying to often repetitive queries.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-13T00:17:26Z
SecondChildVoteTAG: 0
IndexTAG: 933
TitleTAG: No Download Link for 2nd video of section 5b
Hi cant see the download link that should be at the bottom of the video.
UserIdTAG: 466179
UserNameTAG: RudyOcampo
CreateTimeTAG: 2013-03-12T10:39:00Z
VoteTAG: 5
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 0
IndexTAG: 934
TitleTAG: need help with Exercise 8
I watch the lecture several times but can not get the concept.Please help
UserIdTAG: 521763
UserNameTAG: taakondjo
CreateTimeTAG: 2013-03-12T10:29:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: What did you not understand ? if you give specifics we may be able to help.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-12T11:49:09Z
FirstChildVoteTAG: 0
SecondChildTAG: nothing in this exercise just approx. problems are somewhat tricky and lecture is confusing....
SecondChildUserIdTAG: 890751
SecondChildUserNameTAG: AkshayKale93
SecondChildCreateTimeTAG: 2013-03-12T14:36:41Z
SecondChildVoteTAG: 0
IndexTAG: 935
TitleTAG: Late Comers allowed?
Dear Sir,
I could not join the course on Feb 20, is there any possibility that I may join now and have previous lectures and assignments with new deadlines for submission?
UserIdTAG: 1210443
UserNameTAG: Waseempk
CreateTimeTAG: 2013-03-12T10:06:17Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: No new deadlines for submitting assignments whose due date have passed. However, the exams are worth 50% of the final score. If you do well in exams, you will get the certificate.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-12T11:33:38Z
FirstChildVoteTAG: 1
FirstChildTAG: You can potentially pass the course by joining at any time before the final week. One Exercise Set(**5%**) plus a perfect Final Exam(**30%**) would be enough.
Of course, joining earlier gives you more margin for error.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T13:44:16Z
FirstChildVoteTAG: 2
IndexTAG: 936
TitleTAG: Missing link for video download
Please give the link to download the 5.4 lecture.
UserIdTAG: 1056610
UserNameTAG: SowmyaD
CreateTimeTAG: 2013-03-12T09:51:42Z
VoteTAG: 4
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 0
IndexTAG: 937
TitleTAG: Problem 1 b, HELP
Could anyone explain me how to find the SD of a transformed list in linear transformation?
I tried solving th first part and got the mean wrong. Please help me with this question.
Thanks in advance!
UserIdTAG: 1242151
UserNameTAG: lhasan
CreateTimeTAG: 2013-03-12T08:41:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Remember adding and subtracting doesn't change SD
FirstChildUserIdTAG: 569767
FirstChildUserNameTAG: SanjayS72
FirstChildCreateTimeTAG: 2013-03-12T13:00:41Z
FirstChildVoteTAG: 0
SecondChildTAG: So if you do not change the SD, then why did I get that answer wrong?
|a|*(SD of old list) only applies to multiplication of a constant, and so if I kept the original SD since its an addition of a constant, it should have been right, right?
I still have one attempt left for this problem. Can someone please help clarify my understanding? Perhaps I am overlooking something
SecondChildUserIdTAG: 997742
SecondChildUserNameTAG: phamv
SecondChildCreateTimeTAG: 2013-03-12T18:12:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Reread the description of the transformation.
> and so if I kept the original SD since its an addition of a constant, it should have been right, right?
*If the transformation were only the addition of a constant* you'd be correct. (hint-hint... reread the description of the transformation...)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-12T19:55:17Z
SecondChildVoteTAG: 0
IndexTAG: 938
TitleTAG: Will Stat 2.1 Lecture Videos be removed after the course is complete?
Will Stat 2.1 Lecture Videos be removed after the course is complete?
What if I don't download the videos now and wish to view them and download them later, will it be possible to do so?
*Similar question for pdf presentation as well!
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-03-12T08:32:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I have downloaded everything so far for good measure.There was a conversation on this list and I believe the course material for another course was removed from the servers after a month of completion of the course so it may be wise to download everything.
Indeed I would have liked it to be in the clud as a ready reference but it may not be logistically possible.The you tube videos may be there.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-12T11:41:57Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks! I will download...
SecondChildUserIdTAG: 786512
SecondChildUserNameTAG: shoaibkhanz
SecondChildCreateTimeTAG: 2013-03-13T03:57:07Z
SecondChildVoteTAG: 0
IndexTAG: 939
TitleTAG: Raise the bar
Imagine this:
1/ pass levels raised to C: 55-65, B: 66-80, A: 81-100
2/ as for midterm: 1 day window, 2 hours to complete once you start the test
This is the way to really earn the certificate.
After all, it's THE Berkeley...
UserIdTAG: 408421
UserNameTAG: maelcum
CreateTimeTAG: 2013-03-12T08:14:08Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: I fully expect it to be this way for the following Stat2 courses(2.3x and 2.3x).
As this is only an introduction course, I understand why they want to make it easier...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-12T09:32:52Z
FirstChildVoteTAG: 1
SecondChildTAG: I do hope so...
SecondChildUserIdTAG: 408421
SecondChildUserNameTAG: maelcum
SecondChildCreateTimeTAG: 2013-03-12T10:57:40Z
SecondChildVoteTAG: 0
SecondChildTAG: I see the future solution for this being something like this: The course is free and can be taken by anyone. In order to get credit for the course, whether a certificate or actual course credits, you have to pay a fee and take a proctored exam at one of these testing centers. That's where I see this going. That way, a rigorous, well-delivered course can satisfy the philomatheans as well as the credential seekers.
SecondChildUserIdTAG: 937396
SecondChildUserNameTAG: m2foster
SecondChildCreateTimeTAG: 2013-03-12T21:10:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Unless the exam were proctored a generous time frame is unavoidable for technical reasons. Think about these scenarios: 1) the user's network connection suffers a malfunction during the exam not attributable to her misuse but to her Internet Provider. 2) the cloud server that handles the edX web infrastructure has a major glitch for hours.
These scenarios are not science-fiction. Actually, I suffered both in 6.00x course. The latter (the cloud server breakdown in the middle of the final) forced the staff to extend unexpectedly the time frame while the exam was running.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-12T10:28:53Z
FirstChildVoteTAG: 1
SecondChildTAG: I also took the 6.00x.
I agree that there can be technical issues but I believe that they should be no excuse for lowering the bar.
SecondChildUserIdTAG: 408421
SecondChildUserNameTAG: maelcum
SecondChildCreateTimeTAG: 2013-03-12T10:53:03Z
SecondChildVoteTAG: 0
SecondChildTAG: lose -> lost
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-12T11:23:25Z
SecondChildVoteTAG: 0
SecondChildTAG: [My incomprehensible last comment is a typo correction in a previous comment devoured by the server (a glitch!). I reproduce it.]
IMO, if this is the crucial consideration, the only viable option is a proctored exam regarding time frames. (I'm not speaking about the pass level percent).
Maybe the server breakdown during the 6.00x Final didn't catch you. I can tell that it was very frustrating. I battled for hours (emailing staff in between) to submit my code without success. I went to bed with no hope. Next morning I saw the unexpected extension. Students who didn't read the staff email lost their points.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-12T11:43:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, I was lucky, and yes, it was a battle for me too, even without any technical issues. :-)
SecondChildUserIdTAG: 408421
SecondChildUserNameTAG: maelcum
SecondChildCreateTimeTAG: 2013-03-12T12:17:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Unforgettable 6.00x :-)
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-12T13:19:01Z
SecondChildVoteTAG: 0
FirstChildTAG: > pass levels raised to C: 55-65, B: 66-80, A: 81-100
Then you should not be doing an edX course. My understanding is that they give a certificate with no mention of grade - as explained in their Help files. Coursera does give "with distinction".
>as for midterm: 1 day window, 2 hours to complete once you start the test
You have to allow for technical issues.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-12T10:38:28Z
FirstChildVoteTAG: 0
FirstChildTAG: I believe the test is mean to test what we learn and know. It also to tests how we think. It shouldn't be only a memory test. So I like the idea of having 48 hours to finish the midterm. This gives us plenty of time to think and reflect on the questions and apply the materials to answer them. Because we don't have to submit on the same day, we have more time to think about the questions that we are a little unsure with our answers; and that gives us a much better insight about our thinking process and how and why we come up with the answers; whether the answers are incorrect or under the wrong assumptions or calculation. We learn more this way than we do just by memorizing the materials. I believe we will memorize the materials if we understand and know the mechanics and concepts. And know more about our thinking process and how we conceptualize it.
So if you want to challenge yourself and try to finish the exam in two hours, then go ahead. The 48 hours time only there to give us more flexibility. Also not all of us can take the exam on that exact same day and hour.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-12T12:32:49Z
FirstChildVoteTAG: 2
SecondChildTAG: My memory is at least 3 SDs below the average :-)
SecondChildUserIdTAG: 408421
SecondChildUserNameTAG: maelcum
SecondChildCreateTimeTAG: 2013-03-12T12:43:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I for one am glad of the extended time and format. With kids at home, the doorbell ringing unexpectedly, and everything else that goes on at my house, there's rarely a chunk of uninterrupted time greater than 15 minutes, never mind 2 hours.
SecondChildUserIdTAG: 937396
SecondChildUserNameTAG: m2foster
SecondChildCreateTimeTAG: 2013-03-12T20:29:32Z
SecondChildVoteTAG: 0
FirstChildTAG: @maelcum, I respectfully disagree with your proposal; both parts. In my opinion edX is different from attending "The Berkeley". If you wanted the rigid Berkeley experience and a certificate that demonstrated different levels of achievement then you should pursue that option, but edX is free and I don't think the goal of edX is to make their certificates lofty. The goal is to provide an educational opportunity to a vast audience. For me its just a great statistics review opportunity. I recently took a stats class for my PhD program and we had zero interaction with our professors it was me and my book vs. the computer exam/instructor. I am so happy to have access to top notch videos that actually explain the concepts and a discussion board capability to interact with peers like you and Prof A. This is a great opportunity for me and others; I don't think making it more rigid/tough is the answer. Just judge your performance against the answer key and make your conditions as difficult on yourself as you want, but leave the rest of us out of your plan. Thanks. Paul
FirstChildUserIdTAG: 1067669
FirstChildUserNameTAG: psanders
FirstChildCreateTimeTAG: 2013-03-12T12:43:15Z
FirstChildVoteTAG: 3
SecondChildTAG: Hi Paul, no hassle here, I am also glad edX is free and I certainly could not afford the rigid Berkeley experience. So the idea was a free educational opportunity to a vast audience but with a worthy certificate (if you care to try).
SecondChildUserIdTAG: 408421
SecondChildUserNameTAG: maelcum
SecondChildCreateTimeTAG: 2013-03-12T12:50:15Z
SecondChildVoteTAG: 0
SecondChildTAG: The more the certificate is "worth" the greater the incentive to cheat. And then you have to put measures in place to stop / police cheating and the whole experience changes. I think a 35% flat "completion percentage" is absolutely in line with the philosophy for this particular course, and I think it encourages us all to use the materials in a way that suits our individual circumstances.
For example, the mid-term. My usually rock solid internet connection has gone flaky this last week. So the plan is - log in at 7.00am GMT and keep my fingers crossed. If I'm in luck, I'll print the test off and save it for a convenient time. I'll attempt it under closed book conditions - purely for my own benefit, to see how much I have retained in my (below average) memory. Depending on how that goes, and the state of my broadband, I'll revisit lectures / exercises and come up with a revised set of answers to enter online - hopefully before the deadline.
And the only pressure will be my own desire to "get it right" - the completion certificate is in the bag, so if technical problems / life in general prevent me from submitting on time, it makes not an iota of difference. And that is an "environment" that enables me to learn effectively.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-12T13:50:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Murphy's law is always right !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T14:06:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi Marian, you are absolutely right about cheating and also about your individual approach. However, isn't there something strange about the "completion certificate" being in the bag even before completing the mid term, not to mention the two remaining exercise sets and the final? Regards, Erik.
SecondChildUserIdTAG: 408421
SecondChildUserNameTAG: maelcum
SecondChildCreateTimeTAG: 2013-03-12T14:09:22Z
SecondChildVoteTAG: 0
SecondChildTAG: People like rewards. They like to be able to feel good about themselves. If they think or know that they would do something well, they will more likely than not do it. They will be eager and happy. When you are happy, everything will be better including learning.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-03-12T15:45:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Main goal of edx is to understand the subject...
it is not for gaining marks or grades...
as maelcum's thinking its for a community or university exams where the main aim is to gain degree...
FirstChildUserIdTAG: 890751
FirstChildUserNameTAG: AkshayKale93
FirstChildCreateTimeTAG: 2013-03-12T14:48:51Z
FirstChildVoteTAG: 1
SecondChildTAG: Nothing wrong with a low pass mark of 35, if and only if, there is also recognition for better marks. How about awarding merit for 60% and distinction for 80%? It costs nothing for EdX to issue three different types of certificate and would be a motivator for many to try and hit the higher targets.
SecondChildUserIdTAG: 901827
SecondChildUserNameTAG: clv101
SecondChildCreateTimeTAG: 2013-03-12T16:07:08Z
SecondChildVoteTAG: 0
SecondChildTAG: quote clv101: perfectly reasonable.
SecondChildUserIdTAG: 1210009
SecondChildUserNameTAG: GIAN66
SecondChildCreateTimeTAG: 2013-03-19T13:40:52Z
SecondChildVoteTAG: 0
IndexTAG: 940
TitleTAG: (Addressed to staff) Link to download 5.2 Video
Kindly make the download link available for the lecture sequence "**Not all histograms are bell shaped; Chebychev revisited**". Every since 2.1x began, I have not been able to watch any 2.1x video online since the edx videos are hosted on youtube and in my country Pakistan, youtube is banned. Many thanks
UserIdTAG: 31529
UserNameTAG: abbass
CreateTimeTAG: 2013-03-12T08:10:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 941
TitleTAG: Earnest Request - To Prof A to include Saturday weekend for the Mid-Term Exam
Hi,
Considering that many of the students in this course are Professionals working Mon-Friday, I would earnestly request Prof A to consider opening the Mid-Term exam 1 day later and close it 1 day late on Saturday instead of Friday. This will help us to give the Mid-term exam properly.
Please please take note and check if thats feasible.
Thanks,
Soma
UserIdTAG: 1219615
UserNameTAG: Good2Go
CreateTimeTAG: 2013-03-12T06:58:35Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: ya i agree with this... please look at the feasibility.
FirstChildUserIdTAG: 898629
FirstChildUserNameTAG: sureshag27
FirstChildCreateTimeTAG: 2013-03-12T07:13:35Z
FirstChildVoteTAG: 2
FirstChildTAG: I second this request. Or at least give us a Friday night to work. Thanks!
FirstChildUserIdTAG: 608203
FirstChildUserNameTAG: chauct
FirstChildCreateTimeTAG: 2013-03-12T07:25:08Z
FirstChildVoteTAG: 3
FirstChildTAG: You have 48 hours to do something that should take you less than an hour.
There are shift workers, who work nights and/or weekends. Single mums/dads who basically work 24/7. People working two jobs, or more. They deal with it. So should you.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-12T07:25:09Z
FirstChildVoteTAG: 1
SecondChildTAG: We deal with it as much as we can. You know my opinion: the schedule is already fixed from the very beginning and we shouldn't expect modifications (the 48h time-frame is welcomed and, probably, technically necessary to minimize the possibility of a cloud server collapse).
I think, however, that a large time frame (say 4 days -weekend included- as in 6.00x) with a tighter limit of hours to do the exam in one-sitting (say, 4-6h in order to cope with unexpected technical glitches) would be beneficial for everybody and equally fair.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-12T10:43:08Z
SecondChildVoteTAG: 0
SecondChildTAG: The "deal with it" statement has crossed a line- you are not a Teacher/Faculty here- Remember you are a student too.This is out of your ambit.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T11:27:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi susanaust
Pls pause before making comments. Am also full time working with school going kids managing everything alone.
SecondChildUserIdTAG: 1219615
SecondChildUserNameTAG: Good2Go
SecondChildCreateTimeTAG: 2013-03-12T14:31:12Z
SecondChildVoteTAG: 0
SecondChildTAG: +1 for atopos suggestion for a larger time frame, yet with a tighter limit once you start. Otherwise, it is just another exercise set.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-12T23:39:35Z
SecondChildVoteTAG: 0
FirstChildTAG: Most MOOC's have completion rates of less than 10%(*)
http://edlab.tc.columbia.edu/index.php?q=node/8990
FirstChildUserIdTAG: 608203
FirstChildUserNameTAG: chauct
FirstChildCreateTimeTAG: 2013-03-12T09:32:00Z
FirstChildVoteTAG: 3
FirstChildTAG: I think it is not an unreasonable request to ask for a week end exam(especially for the finals).Whether that can be done or not is up to the course coordinators and the Professors and I think no student in this course has a right to remonstrate or flame other members on this course to "deal with it".People do have a right to voice their opinions and requests.Many such requests indeed have been acceded to by the staff and Professors - for eg conversion to a weekly instead of a triweekly submission, larger cursor for the lectures, 48 hours window for the mid term exam and I don't think the Professors told us to "deal with it" and made appropriate changes on hearing rational requests which they determined.They have never said brusquely "deal with it".
Since people like to bring up various forum rules and guidelines, I would also like to bring to notice this following rule that has been mentioned in the guidelines which some forget while quoting the rule book ever so often -
"It’s fine to make suggestions, but avoid negative
commentary and please do not “flame” anyone."
http://en.wikipedia.org/wiki/Flaming_(Internet)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-12T11:13:34Z
FirstChildVoteTAG: 4
SecondChildTAG: LOL!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-12T11:23:49Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL! too
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T13:44:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Please remember that unlike a real classroom with less than 500 students, MOOC was designed to be taken by ten's of thousand of students, who all have jobs and other activities to do.
There is no way that the staff can please everyone of those ten's of thousand students. Asking for an exam date change would potentially upset other students who might have already rearranged their personal schedules to accommodate the exam date.
In short, please consider the other students who don't want to change due to their own schedules/reasons too. If the course schedules made by staff is really interfering with one' schedule, then perhaps one should assess their priorities in life and maybe take the next offering of the course when they are less hectic.
Finally, with a low passing grade, missing out on a midterm exam should not effect your chances of passing the course. If learning is your primary objective, then you should not worry as the exam questions will be available long after the due date has elapsed.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-03-12T19:50:31Z
FirstChildVoteTAG: 0
IndexTAG: 942
TitleTAG: Should we 'check' second time even if got correct in the first attempt?
If I check the answer and it is correct, the page shows that I have used 1 of 2 answers. I am not sure if the answer is saved at that point. If I don't click the 'Check' second time will my answer be still saved?
To be cautious I have been clicking on the 'Check' button second time. The page shows that I have used 2 of 2. But I was correct in the first attempt!
Not a big deal. I am sure the answer is somewhere in the course guidelines. But if you remember from your experience let me know.
UserIdTAG: 278932
UserNameTAG: Rahulsv
CreateTimeTAG: 2013-03-12T06:58:25Z
VoteTAG: 1
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: If you have the green tick, then there is no need to check again.
There have been posts where people have, for some strange reason, changed their correct answer and rechecked. And got it wrong.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-12T07:19:33Z
FirstChildVoteTAG: 3
SecondChildTAG: But need to save it? so we have to recheck?
SecondChildUserIdTAG: 945953
SecondChildUserNameTAG: Turca
SecondChildCreateTimeTAG: 2013-03-12T12:37:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Checking the answer also saves it automatically ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T13:47:18Z
SecondChildVoteTAG: 0
IndexTAG: 943
TitleTAG: graph the bell curve
make the bell chart helps visualize better
UserIdTAG: 1024935
UserNameTAG: N3
CreateTimeTAG: 2013-03-12T05:39:46Z
VoteTAG: 1
CoursewareTAG: Practice For Exercise Set 8 / Reading and Practice For Exercise Set 8
NumberOfReplyTAG: 0
IndexTAG: 944
TitleTAG: Auto-grader not accurate enough
So I accidently used 65 as my average instead of 66, yet the grader still marked my answers (1D & 1E) as correct. I was confused later when I kept getting 1C wrong, until I realized my mistake. I think I'd have caught it earlier if the grader had marked me as wrong for these other two questions as well. Thanks though for the class.
UserIdTAG: 1160480
UserNameTAG: ZaneStevens
CreateTimeTAG: 2013-03-12T03:00:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 0
IndexTAG: 945
TitleTAG: Midterm
Hi everyone,
Enjoying the course but concerned that the midterm is scheduled to be completed during a work week. For myself with a demanding job and family this will be a problem. Am I along wit this concern ?
UserIdTAG: 1081952
UserNameTAG: serogers
CreateTimeTAG: 2013-03-12T02:51:29Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: This was brought up and so they have given a 48 hour time and we are allowed to sit through it in parts(ie we can choose to do part of the exam and continue ie it is not timed.It would have been ideal to have it over a weekend but then this seems to be a doable compromise.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-12T03:02:31Z
FirstChildVoteTAG: 4
FirstChildTAG: > For myself with a demanding job and family this will be a problem. Am I along wit this concern ?
I took this into account when I joined up. This is an online course with thousands from around the world enrolled. Can't please everyone. Some things might not fit in with my schedule, but that is something I have to deal with.
I am a shift worker. My "weekend" is not Saturday or Sunday.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-12T03:04:58Z
FirstChildVoteTAG: 5
FirstChildTAG: I am a full time working single mom. I dont have weekends. Welcome to the club! :)
FirstChildUserIdTAG: 1289210
FirstChildUserNameTAG: ZHYRUNCHIK1
FirstChildCreateTimeTAG: 2013-03-12T03:20:47Z
FirstChildVoteTAG: 2
FirstChildTAG: I have recently started a full time job and have been fully absorbed in it, just when the courses started. This weekend (Sat-Sunday) I was hoping to study few chapters and do assignments when I figured out, there is a 48-hr limit scheduled on wednesday (working day) and that I have missed out many graded assignments. What do I do now?
FirstChildUserIdTAG: 1062848
FirstChildUserNameTAG: Meanita
FirstChildCreateTimeTAG: 2013-03-12T06:14:54Z
FirstChildVoteTAG: 0
FirstChildTAG: If you are unable to finish everything you intended to, due to a new commitment or something else, then you may have to opt out of something, such as this course. It is not a right to be able to complete a course no matter what (I realize that may sound rude but it is absolutely not my intention!).
Quite likely this course will be offered again in the future and if not other courses in statistics will be (there are at least two in Coursera, one by University of Toronto starting April 1 and another by Princeton University starting September 1).
FirstChildUserIdTAG: 1241616
FirstChildUserNameTAG: Larsfl
FirstChildCreateTimeTAG: 2013-03-12T07:24:29Z
FirstChildVoteTAG: 2
FirstChildTAG: LOL. And they are having conferences to debate whether moocs are a threat to universities. As if!
If you can't find one hour in a 48 hour window, then maybe you should be rethinking your priorities and motivations.
There are thousands here from all over the planet. By changing to suit you, others will take your place in being upset about the timing. It is impossible to cater to every individual.
And it's not as if this was a surprise - the date has been set at March 13th since the beginning of the course.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-12T07:35:28Z
FirstChildVoteTAG: 2
SecondChildTAG:
From the Discussion guidelines - please follow
It’s fine to make suggestions, but avoid negative
commentary and please do not “flame” anyone
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T11:45:25Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't see any flaming here, unlike in the other thread. What Susan says is absolutely correct.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-03-12T19:37:51Z
SecondChildVoteTAG: 0
SecondChildTAG: A request is a request.Ideally should be placed in one place (which is wrong).It is for the Course coordinators to determine what is a reasonable and unreasonable request (not for a fellow student).Of course if all the requests are in one place it would be ideal.Wish they had the ability to have a polling button to avoid multiple posts.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-13T02:37:36Z
SecondChildVoteTAG: 0
IndexTAG: 946
TitleTAG: I thought a percentile was a range of scores, ..
for example, the 95th percentile are those data where 95 % of the data are less and 4 % are more, mark
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-03-12T02:49:28Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: In fact, the 95th percentile is the smallest value such that 95% of the population are less than or equal to that score. So, for example, if everyone scored 5, 5 would be the 95th percentile with 100% less than or equal to that score and 0% greater than that score.
FirstChildUserIdTAG: 217043
FirstChildUserNameTAG: jacksonk
FirstChildCreateTimeTAG: 2013-03-12T07:21:01Z
FirstChildVoteTAG: 1
IndexTAG: 947
TitleTAG: 7:03...why is the area important if we just want the percentages in each interval?
The problem I have is the following:
At 7:03 Prof A says that the area under the bar should be compatible with the no of (or percentage of) people in that interval. Then she refers to the interval widths and give us a formula for adjusting the area of the bars.
But why should the interval width have any effect on the number of people in that interval in this case? What I'm saying is, suppose (just for brevity) we have intervals 0-50, 50-500, 500-1000 with percentages as 50%, 35% and 15%. Then if we leave the horizontal widths equal (say "x") and draw bars scaled by 10, we would have rectangles with area 5x, 3.5x and 1.5x, which would roughly be interpreted as such by our eyes so that the ratio 10:7:3 is roughly apparent.
UserIdTAG: 38912
UserNameTAG: AG20390
CreateTimeTAG: 2013-03-12T02:29:27Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 2
FirstChildTAG: OK got it. Sorry!
FirstChildUserIdTAG: 38912
FirstChildUserNameTAG: AG20390
FirstChildCreateTimeTAG: 2013-03-12T02:45:41Z
FirstChildVoteTAG: 0
FirstChildTAG: I observed same thing. Thanks all
FirstChildUserIdTAG: 1277373
FirstChildUserNameTAG: imoize1982
FirstChildCreateTimeTAG: 2013-03-12T08:54:52Z
FirstChildVoteTAG: 0
IndexTAG: 948
TitleTAG: should I sign up for the course?
I was wondering if I should sign up for the course, do you think it's too late to sign up or should I wait for another time to sign up for the course since it's the middle up the semester?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-12T02:26:51Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 2
FirstChildTAG: If you are posting in this forum, you are already signed up for the course! Also, you have posted this comment under Section 2b, which means you have also taken lectures.
So why this question now near midterm as anonymous?
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-12T04:38:57Z
FirstChildVoteTAG: 0
FirstChildTAG: > I was wondering if I should sign up for the course
As already said, you have signed up.
Did you read the course outline and grading requirements? You should be able to decide for yourself whether you can catch up or not. We can't make that decision for you.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-12T07:59:18Z
FirstChildVoteTAG: 0
IndexTAG: 949
TitleTAG: Professor Adhikari - "If this were an exam at Berkeley..."
...it would be a closed-book test...
Are you asking this of us?
Truthfully it is what I had expected; and I would hope that you would challenge us as you would any student there.
Thanks
UserIdTAG: 504031
UserNameTAG: Lindy7
CreateTimeTAG: 2013-03-12T02:01:00Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section5b_Lec_5_4/threads/513e52302b7b422700000220
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-12T02:29:52Z
FirstChildVoteTAG: 0
FirstChildTAG: Stat 2.1X students are welcome to work as they have worked on the Exercise Sets, with their course materials available for reference.
In Berkeley's Stat 2, students get plenty of practice taking closed-book quizzes before they take a closed-book exam. I don't like putting exams in a format that students aren't used to in the course.
So, to be consistent with that, the Stat 2.1X midterm will be just as the exercise sets are.
I described what happens in my Berkeley class to explain the experience based on which I think 50 minutes will be enough for the upcoming test: if you know your material without having to look it up, that's the time you'll need. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-12T06:08:40Z
FirstChildVoteTAG: 5
IndexTAG: 950
TitleTAG: Problem 7: I forget how to algebra.
I'm having some trouble with the algebra for Problem 7.
Using the applet from the text, I can get the value for the 60th, 70th, and 90th percentile in standard units. But I am not sure how to get the average and SD necessary to convert the value back to the original units.
(z score for 60th percentile)=(110-x)/y
(z score for 70th percentile)=(120-x)/y
But how to find x and y!
I know that this resembles one of the practise exercises for this set, but I had a lot of trouble with that one, too. I read the explanation but I couldn't understand why they did the calculations they did.
> On the standard units scale, distances are measured in SDs. So the
> distance of 54-42=12 in the original units is equal to 2.8-0.4 = 2.4
> SDs. So the SD is 12/2.4 = 5. That means 42 in the original units is
> 0.4*5 = 2 units above average, which means the average is 40. So A= -1.2*5 + 40 = 34.
Why does dividing the difference of two original values by the difference of the two standard units give us the SD?
UserIdTAG: 1055945
UserNameTAG: rebecca417
CreateTimeTAG: 2013-03-12T01:46:46Z
VoteTAG: 4
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 5
FirstChildTAG: I got the correct answers by plugging the correct values for Problem 7 into the alternate algebraic formula described in the practise exercises by user Shadybog. I don't know why this formula works though, so if anyone could explain it a little, that would be swell!
(Specifically, I don't know how to turn my two equations above with two unknowns each into a single equation with one unknown like the one below).
> **Problem 2 - Alternate method. (by Shadybog)**
>
Problem 2 can be also solved using simple algebra. We know z=(x-avg)/SD. Hence
> SD=(x-avg)/z. The table in Prob 2 has x (original unit) on the left
> hand side and z (standard unit) on the right hand side. We now have to
> find the avg and the SD, both of which are non-variables, i.e they
> have a constant value. Thus, SD=(54-avg)/2.8 . Now since the SD is the
> same for all values given above, we can equate this as follows:
> (54-avg)/2.8 = (42-avg)/0.4 or 0.4(54-avg)=2.8(42-avg). Solve this
> equation and u get the average. Now use the average to find the SD
> (eg. (54-avg)/2.8). That gives us everything required to solve the
> problem. :)
FirstChildUserIdTAG: 1055945
FirstChildUserNameTAG: rebecca417
FirstChildCreateTimeTAG: 2013-03-12T02:12:38Z
FirstChildVoteTAG: 1
SecondChildTAG: I'm having the same difficulty, Rebecca. It's hard to remember algebra from 30 plus years ago (I studied linguistics and theater at university.) My most recent difficulty was forgetting how to simplify an expression by distributing the negative sign. Good thing I have a teenager in the house who is currently in a calculus class! Role reversal--he helps me with my homework!
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-12T11:20:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Haha, a teenager does sound very helpful! I keep thinking, "I'm sure I did equations much harder than this when I was 15!" Perhaps next time I should text my high school aged cousin.
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-03-12T17:42:32Z
SecondChildVoteTAG: 0
SecondChildTAG: A good place to review algebra (and other math and topics) is Khan Academy.
http://www.khanacademy.org
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-12T19:58:29Z
SecondChildVoteTAG: 0
FirstChildTAG: If you have two equations where the X and Y are the same unknown values, you can use the first equation to express Y in terms of X (or vice versa), then sub it into the second one.
So for example we have these two equations:
x + 4y = 12
4x + 2y = 13
So we take the first equation, and move the 4y to the other side of the equation (changing the sign, as it's moving across), giving us
x = 12-4y
We slot this into the second equation, which transforms into:
4(12-4y) + 2y = 13
48 - 16y + 2y = 13
48 - 14y = 13
48 - 13 = 14y
35 = 14y
2.5 = y
Please note that this is for parallel equations in general, I do not advocate their use in the exam, but if you do use them, be very very careful with the rounding.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-12T02:22:04Z
FirstChildVoteTAG: 4
SecondChildTAG: Thanks, this is definitely helpful!
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-03-12T17:40:25Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks!!!
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-03-13T00:26:41Z
SecondChildVoteTAG: 0
FirstChildTAG: If you are still trying to figure out the algebra, you can find your answer in the below thread:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_7/threads/513c3e63e8c82427000000e9
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-12T04:41:13Z
FirstChildVoteTAG: 1
FirstChildTAG: Hi Rebecca and all,
Rebecca said "...Using the applet from the text, I can get the value for the 60th, 70th, and 90th percentile in standard units..."
Please how did you get the 'z' value ? I don't seem to know the applet you are talking about?
FirstChildUserIdTAG: 1157488
FirstChildUserNameTAG: Maxims
FirstChildCreateTimeTAG: 2013-03-12T16:26:46Z
FirstChildVoteTAG: 0
SecondChildTAG: This is the applet referred to several times in the lectures, practise exercises, and exercises, the one in the text (Prof. Stark's "SticiGUI"). It allows you to find the area under any selected portion of a normal distribution. Here's the link to the stand-alone applet: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-03-12T17:38:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks Rebecca!
How do I use the applet to generate the standard unit value for the 60th, 70th and 90th percentiles as requested please?
FirstChildUserIdTAG: 1157488
FirstChildUserNameTAG: Maxims
FirstChildCreateTimeTAG: 2013-03-20T14:12:58Z
FirstChildVoteTAG: 0
IndexTAG: 951
TitleTAG: A+ on this'un
![enter image description here][1]
[1]: http://3.bp.blogspot.com/-mIAAkX_JTvE/T3B6SGpo96I/AAAAAAAAA6g/iQ0lk8-TZYg/s1600/like-a-boss-meme-shirt.jpg
UserIdTAG: 316261
UserNameTAG: Brady1997
CreateTimeTAG: 2013-03-12T01:37:45Z
VoteTAG: 13
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: ![enter image description here][1]
[1]: http://memecrunch.com/meme/BJ4U/good-for-you/image.png
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-12T02:58:26Z
FirstChildVoteTAG: 2
FirstChildTAG: ![enter image description here][1]
[1]: http://troll.me/images/victory-baby/good-job-you-win-this-round.jpg
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-12T03:02:04Z
FirstChildVoteTAG: 1
IndexTAG: 952
TitleTAG: Exam - Access to Courseware
Will we have access to Courseware during the exam and will be able to look at the videos and exercies?
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-12T01:23:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section5b_Lec_5_4/threads/513e52302b7b422700000220
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-12T01:24:50Z
FirstChildVoteTAG: 0
IndexTAG: 953
TitleTAG: answers in problem 1 are not accurate
I answered problem 1, when I checked, the answer was correct, then I look at the explanation, It did not make sense at all, but I had to leave. I came back online later and answer the same question giving the same answer, but now the answer is incorrect, giving the same explanation It had before.
I'm having serious doubts about the system, I'm also afraid you will have the same problems during the MIDTERM and final exam.
UserIdTAG: 1085886
UserNameTAG: AndyHdz
CreateTimeTAG: 2013-03-12T00:52:28Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 0
IndexTAG: 954
TitleTAG: WEEK 3
I got a 40% exercise 7 and I failed Exercise 8 and got a zero cause messed up on question 1 when i had it correct but now i know the solutions and can understand.
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-03-12T00:42:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 955
TitleTAG: 2B grading issue
On 2B, after I clicked, 'check answer', it said the answer was incorrect, but when I clicked show answer, it said the answer was the same as what I had listed in the blank. (even though its grading it as incorrect).
Did anyone else run into this issue?
UserIdTAG: 970558
UserNameTAG: nk0321
CreateTimeTAG: 2013-03-12T00:41:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: nevermind, it looks like somehow my first answer, which was incorrect, somehow saved even though I don't think I clicked "check answer" before changing it
FirstChildUserIdTAG: 970558
FirstChildUserNameTAG: nk0321
FirstChildCreateTimeTAG: 2013-03-12T00:48:31Z
FirstChildVoteTAG: 0
IndexTAG: 956
TitleTAG: Finding Z with the applet
Hi everyone,
I finally can see and use the applet.
However, I am not sure exactly how z is obtained. For example, in the exercise, I do not get z=1.036 or 1.037 for Problem 6. Is it lower endpoint or upper endpoint.
Thanks for the help!
P.
UserIdTAG: 1178106
UserNameTAG: pyt
CreateTimeTAG: 2013-03-12T00:32:22Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Glad you can see the applet now! Do you know what changed (or what you did) so you can see it? If you do, please post that in case others have the same problem. I'd suggest posting it both in the original thread and perhaps in a new thread all its own; the title of the new thread might be easier to find for anyone with the same problem.
As to finding z:
If you think about it, you know the 0 point is the mean. The mean is the 50th percentile, because the standard bell curve is symmetrical.
So if you wanted the 50th percentile, which is the place where 50% of the curve is covered, you slide the left slider all the way left, and put 0 in the box for the right slider. (That's easier than fiddling with the right slider to find 0)
You'll see the left half (50%!) is yellow, and the applet says the selected area is 50%.
Now let's say you want the 75th percentile. Left one stays all the way left (it reads -5 in the box). Fiddle with the right slider until the applet says 75% is selected. What I do is get close with the slider, then manually change numbers to fine-tune it.
Let's say I get to 73.92% with the slider; the value is 0.641. We need to move more to the right (higher numbers) to get from 73.92% to 75%, so change the value to 0.65. Then click in the left box (don't change its value) so the applet changes the selected area. It says 74.22% is selected. We need just a bit higher, so try 0.655 in the right box. (again click in the left so the applet recalculates) Now we're at 74.38%. Try 0.66; that's 74.54%. Try 0.67; 74.86%. Try 0.68; ah! 75.17%. A bit over, so try 0.675; 75.02% Still a bit over; try 0.674. That's 74.98%. You can try 0.6745, but the app truncates it back to 0.674 (rather than rounding up to 0.675). Either 0.674 or 0.675 is good; it's as close as the app gets us.
Then do the calculation to get from z back to x (back to units), and that's the answer.
It works the same way for lower percentiles; it's just that the right number will be negative. That can make fiddling with the number to tune it in a bit odd; remember to go to a lower percentage you want a more-negative number, which is a higher (absolute) value. I.e., changing the right box from -1.1 to -1.2 will select *less* of the area (-1.2 is further negative than -1.1).
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-12T02:30:00Z
FirstChildVoteTAG: 1
SecondChildTAG: It worked, thanks
SecondChildUserIdTAG: 712542
SecondChildUserNameTAG: Doyinmola
SecondChildCreateTimeTAG: 2013-03-13T04:25:24Z
SecondChildVoteTAG: 0
IndexTAG: 957
TitleTAG: STAFF or CLASSMATES - HELP ASAP WEEK 3
Can someone please email me so that i can provide my phone number to them cause i am in extreme need for help with this weeks homework and understanding everything. I think I have the basis down but not it completely and NEED HELP. Please email to aimstermill51@aol.com
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-03-11T23:56:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 958
TitleTAG: all correct
all correct
UserIdTAG: 1107978
UserNameTAG: betoagto
CreateTimeTAG: 2013-03-11T23:41:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: How can I use the applet?
FirstChildUserIdTAG: 1370679
FirstChildUserNameTAG: voyager18
FirstChildCreateTimeTAG: 2013-03-12T05:24:53Z
FirstChildVoteTAG: 0
IndexTAG: 959
TitleTAG: Another "applet" for the normal distribution
Try this link. Hope that will do:
http://www.mathsisfun.com/data/standard-normal-distribution-table.html
UserIdTAG: 636013
UserNameTAG: ABARIGOU
CreateTimeTAG: 2013-03-11T23:26:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 960
TitleTAG: Very important
It's very important to distinguish quantitative and qualitative datas.
UserIdTAG: 1096843
UserNameTAG: Szydam
CreateTimeTAG: 2013-03-11T23:18:54Z
VoteTAG: 0
CoursewareTAG: Section 1: Introduction / Lec 1.2. Variables: terminology
NumberOfReplyTAG: 1
FirstChildTAG: Thanx, that's where I was lagging.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-11T23:20:25Z
FirstChildVoteTAG: 0
IndexTAG: 961
TitleTAG: Very good beginnings
Calm and clear voice encourages me to further lessons.
UserIdTAG: 1096843
UserNameTAG: Szydam
CreateTimeTAG: 2013-03-11T22:58:29Z
VoteTAG: 6
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 1
FirstChildTAG: agreed .... may i add..... assuring .....
FirstChildUserIdTAG: 1145257
FirstChildUserNameTAG: klarioncall
FirstChildCreateTimeTAG: 2013-03-11T23:10:19Z
FirstChildVoteTAG: 1
IndexTAG: 962
TitleTAG: When will the midterm be posted(PST)?
At what time abd date will the midterm be posted . DO we need to complete it in one shot or can complete in multiple shots before the due date/time
UserIdTAG: 923827
UserNameTAG: vinit2901
CreateTimeTAG: 2013-03-11T22:06:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Midterm information was just posted to the "Course Info" page.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-11T22:39:21Z
FirstChildVoteTAG: 0
FirstChildTAG: Gotta say, the overall format of the midterm is far more generous than I was anticipating.
The express distinction between this midterm and the nature of an equivalent exam in actual Berkeley is a bit disheartening. Seems to make it more likely that they will also ensure to distinguish the cert from direct Berkeley association.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T22:48:02Z
FirstChildVoteTAG: 1
SecondChildTAG: The professor is really in a position where she's "damned if I do, damned if I don't." Hundreds of people complain that a 24-hour time limit on the midterm isn't enough. So she expands it to 48-hours, and then people complain that it's too much time and takes away from the value of the certificate. I'm not saying that you're wrong. I just think we should appreciate the situation the professor is in.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-11T22:52:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Overall, it's not about certificate. It's to deliver knowledge and get access to high quality education materials, in my opinion.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-11T22:59:38Z
SecondChildVoteTAG: 0
SecondChildTAG: That varies for different students: everyone has their own reasons for taking the course instead of just reading the googleable information on statistics.
In the ideal world I completely agree with you, it would be just about the knowledge, but sadly contemporary HR and recruiters look for certs more than knowledge evaluation, so those can be important for some.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-12T01:55:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Well the certificate indeed will be called Stat2.1X and is not Stat 2.1 !! The important thing is have grasped the concepts.As far as HR etc even if you do get a job can you deliver without the knowledge and thus keep your job intact.That is something to think about.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-12T02:20:29Z
SecondChildVoteTAG: 0
FirstChildTAG: thanks to professor and the way she explained, my mind now understands statistics i think that's more important after all. i've had passed good many subjects from big name universities...& ummm...... but u are never able to use wat u learned by rot ..all that's more necessary with name of good university is best understanding ...my regards for all
FirstChildUserIdTAG: 1145257
FirstChildUserNameTAG: klarioncall
FirstChildCreateTimeTAG: 2013-03-11T23:08:29Z
FirstChildVoteTAG: 2
FirstChildTAG: Overall, it's not about certificate. It's to deliver knowledge and get access to high quality education materials, in my opinion.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-11T23:13:55Z
FirstChildVoteTAG: 0
IndexTAG: 963
TitleTAG: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
When I access
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm, the resulting page shows as follows:
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/1363039276134360.jpg
This is the applet for Exercise Set 7. It was accessed using Chrome. Any advice on pulling up a version that displays correctly? Thanks.
(I think the course is great. Thanks.)
UserIdTAG: 1228199
UserNameTAG: BBabski
CreateTimeTAG: 2013-03-11T22:04:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: go to right top corner click setting, click tools-->click encoding-->click unicode (UTF-8). You are get set go.
This is for chrome
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-11T22:12:08Z
FirstChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/513ce10974c9d92b000001a0
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-11T23:04:00Z
SecondChildVoteTAG: 0
FirstChildTAG: I have the same problem. But I have Mozilla. What can I do?
Thanks
FirstChildUserIdTAG: 1014550
FirstChildUserNameTAG: RafaelUP
FirstChildCreateTimeTAG: 2013-03-12T01:43:39Z
FirstChildVoteTAG: 0
IndexTAG: 964
TitleTAG: Mid Term
What format does this take?
Is there a set start/finish time?
Not seen any info on this.
UserIdTAG: 1109540
UserNameTAG: NegusNegast
CreateTimeTAG: 2013-03-11T21:52:48Z
VoteTAG: 2
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 2
FirstChildTAG: Midterm information was just posted to the "Course Info" page.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-11T22:40:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Follow up question: what resources will we be able to use? It was mentioned that the 'live' midterm is closed book. Should we treat it the same way with the exception of the applet? Or, can we use notes, lecture slides etc? I assume searching the internet is out of bounds (what's the point of taking a class if you're just going to ask someone else to do your work for you?).
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-03-11T23:53:47Z
FirstChildVoteTAG: 1
SecondChildTAG: While at Berkeley this would be an in-class closed-book exam,for Stat 2.1X it's just like one of the exercise sets, except that you have 48 hours instead of a week. You are free to use any materials and assistance that don't violate the honor code. Everything under Courseware can and should be used; go through the old discussion forum posts if they help; use the applet and any other portion of the text. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-12T01:07:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the clarification.
SecondChildUserIdTAG: 260168
SecondChildUserNameTAG: Jeff2012
SecondChildCreateTimeTAG: 2013-03-12T19:19:37Z
SecondChildVoteTAG: 0
IndexTAG: 965
TitleTAG: no submit button
there is no place or button for submitting the answers. please help
UserIdTAG: 1396296
UserNameTAG: Nehamehta
CreateTimeTAG: 2013-03-11T21:38:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline for Exercise Set 1 is over. You cannot submit the answers anymore.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-11T21:58:00Z
FirstChildVoteTAG: 0
IndexTAG: 966
TitleTAG: Frustration
That I simply got disappointment on test scores because I could not fathom how to make the applet work for me. I have gone back again to work it out and can now see how it works but this was more a test in learning the applet rather than stats themselves. It also felt like a huge jump forward in terms of difficulty. Tough week.
UserIdTAG: 1064433
UserNameTAG: Jerryfb
CreateTimeTAG: 2013-03-11T21:13:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: yep Jerryfb
Tough week. Not that easy that I was hoping.
I guess we have to repeat time after time that material.
Good luck to all of us.
FirstChildUserIdTAG: 900267
FirstChildUserNameTAG: kamil_sielicki
FirstChildCreateTimeTAG: 2013-03-11T21:22:30Z
FirstChildVoteTAG: 0
SecondChildTAG: may be this link can be helpful (z score)
http://www.regentsprep.org/Regents/math/algtrig/ATS7/ZChart.htm
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-11T21:26:52Z
SecondChildVoteTAG: 0
FirstChildTAG: There has been a number of alternatives to the applet posted on these very forums, including the =NORMINV function in Excel, or just plain googling a normal curve table:
http://lmgtfy.com/?q=normal+curve+table
The applet itself is not a unique invention, just a reference shortcut, so there is other mechanisms for getting the results. In part that's the beauty of the online courses, where fortune truly favours the resourceful.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T21:34:41Z
FirstChildVoteTAG: 1
IndexTAG: 967
TitleTAG: Joules
Sorry, but i don´t find the link to access to midterm examination. Can you help me? Thank you. Best regards
UserIdTAG: 1268329
UserNameTAG: Joulece
CreateTimeTAG: 2013-03-11T21:01:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's not the 13th yet.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-11T21:34:01Z
FirstChildVoteTAG: 0
IndexTAG: 968
TitleTAG: Only just able to start course
Hi There
Due to unforeseen circumstances, I'm only just able to start the course. Will I still be graded if I submit responses and try to catch up? Thanks, Kim
UserIdTAG: 1007580
UserNameTAG: KWilliamson7
CreateTimeTAG: 2013-03-11T20:55:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You will have the same deadlines as anyone else, so as of this moment, you are still eligible to submit Exercise Sets 7-12, the midterm and the final, but you can also do the other exercise sets regardless to see for yourself as to whether you understood the materials.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T21:16:38Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi, that is my case too. Does it means that I cannot get a final certificate?
Thanks
FirstChildUserIdTAG: 1379938
FirstChildUserNameTAG: felope
FirstChildCreateTimeTAG: 2013-03-11T21:22:31Z
FirstChildVoteTAG: 0
SecondChildTAG: You will get the certificate if you achieve an average grade of 35%, which is still very much doable, despite the 6 exercises counted at 0%, especially as the two lowest ES results are dropped from the final grade.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-11T21:31:23Z
SecondChildVoteTAG: 0
FirstChildTAG: You should read the course documents - syllabus, policies. All the grading requirements are explained. So you should be able to decide whether you can complete the course.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-11T21:35:15Z
FirstChildVoteTAG: 0
IndexTAG: 969
TitleTAG: got 1,2,4&5 just fine...but
I 'm having a hard time to focus, and I'm trying ridiculous "solutions" to get the answers.
It's obvious that I'm just getting further and further from the real thing. It is all linked.
Can somebody please help me to go back on the right tracks? I 'm having a break,in order to not putting more crazy theories in my brain^^
In advance, thank you for your help!
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-03-11T20:26:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: and 6 ok too....
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-03-11T20:55:24Z
FirstChildVoteTAG: 0
SecondChildTAG: and 3A
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-03-11T21:28:39Z
SecondChildVoteTAG: 0
FirstChildTAG: I know what you mean about ridiculous solutions. I ended up taking a scenic route through quadratic equations for one of the questions, eventually got the answer, opened up the Show Answer, to have a very Homer Simpson moment.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T21:14:01Z
FirstChildVoteTAG: 2
SecondChildTAG: Hahaha me too, thats the problem of overthinking when the solution is just straight forward
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-11T22:08:57Z
SecondChildVoteTAG: 0
FirstChildTAG: So, it's problem 3B. There are zillions of problems about that problem ;-)
Review the oldest posts on this (on this Ex. Set 3, in general). Focus on Prof. Ani's words. She has repeated a mantra:
> Try to write everything in terms of the number right; including the number wrong
It's the key. The important question is: "why has she pointed in that direction?" If you can answer this question, you'll connect things, I hope. It's all about transformations and, if a transformation is possible, what it requires, what makes it feasible and correct, mathematically speaking, so to say. I don't want to be cryptic, but I think it's the best way to provoke the connection.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-12T00:17:40Z
FirstChildVoteTAG: 0
IndexTAG: 970
TitleTAG: Problem 1A
I used Chebychev's Inequality for lists...gives you a slightly different, but wrong, answer of 8.68.
UserIdTAG: 1343670
UserNameTAG: rleonetti
CreateTimeTAG: 2013-03-11T20:25:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: But Chebychev's doesn't give an approximation, it gives a bound. It merely establishes that the number can't be, rather than evaluating what it might be.
It's like taking the time it takes to score a touchdown, the length of a game, the number of games in a season, and saying that the number of touchdown passes Drew Brees can throw in a regular season cannot exceed 500. But if one were to estimate how many he will throw, it will be quite different, so in reality it was just happy almost-coincidence that the number you got was only slightly different, as per the Prof's 3 heads example.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T21:24:29Z
FirstChildVoteTAG: 0
IndexTAG: 971
TitleTAG: Problem 3B explanation comment
I think that explanation on Problem 3B was a bit off. The explanation on how we reach 6*(number right) - 10 should be available as well. I did solve it, but it still seems too short. :)
UserIdTAG: 278637
UserNameTAG: TotalOblivion
CreateTimeTAG: 2013-03-11T20:22:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 4
FirstChildTAG: It's a mathematical writing if you put X instead of right it's maybe a little easier to understand and using the mathematical law of writing, you should be able to arrive at 6X-10. starting with how much is a right answer worth and how much a wrong answer cost.
FirstChildUserIdTAG: 1044317
FirstChildUserNameTAG: Mlaknin
FirstChildCreateTimeTAG: 2013-03-11T20:48:23Z
FirstChildVoteTAG: 0
FirstChildTAG: It is available. the equation is given, just follow it through.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-11T21:23:20Z
FirstChildVoteTAG: 0
FirstChildTAG: Look at the answer to 3A. I think you'll find what you're looking for. 3B is a continuation. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-11T22:05:37Z
FirstChildVoteTAG: 1
SecondChildTAG: Not at all. you don't got that from 3a
SecondChildUserIdTAG: 789101
SecondChildUserNameTAG: Posoneto
SecondChildCreateTimeTAG: 2013-03-12T02:52:05Z
SecondChildVoteTAG: 0
SecondChildTAG: That deduction has nothing to do with descriptive statistic
SecondChildUserIdTAG: 789101
SecondChildUserNameTAG: Posoneto
SecondChildCreateTimeTAG: 2013-03-12T03:01:30Z
SecondChildVoteTAG: 0
SecondChildTAG: of course it is. you will find a linear relation between "score" and "numbers right" like y = mx + c, find m to find out new SD from SD of old variable (ie. x). have a look on lecture 4.4 to learn how to convert.
SecondChildUserIdTAG: 99047
SecondChildUserNameTAG: taminur
SecondChildCreateTimeTAG: 2013-03-12T10:29:10Z
SecondChildVoteTAG: 0
FirstChildTAG: Refer to the below thread for details on how we reach 6*(number right) - 10
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_7/threads/513c3e63e8c82427000000e9
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-12T04:35:30Z
FirstChildVoteTAG: 3
IndexTAG: 972
TitleTAG: Confused...
Can someone help me on Problem 2?
>A quiz consists of 10 questions. Each question is marked either “right” or “wrong.” For each student in the class, the instructor keeps a record of the number of right answers the student got. In the class, the average number of right answers is 6.2 and the SD of the number of right answers is 1.4.
Okay, that makes sense.
>Find the average number of wrong answers.
Wait, what? So the average number of right answers is 6.2, meaning that 6.2 out of every 10 questions were answered correctly, right? I guess the number of wrong answers is 3.8, then. But that just seems to obvious!
>Find the SD of the number of wrong answers.
Same here. so the SD of right answers is 1.4, meaning most people were between 4.8 and 7.6, right? But how do you find it for wrong answers? don't you need Value - average to find deviations? Well, this has no value. I am totally lost.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-11T20:14:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: You're over complicating this question. Sometimes the obvious is right.
FirstChildUserIdTAG: 1109540
FirstChildUserNameTAG: NegusNegast
FirstChildCreateTimeTAG: 2013-03-11T21:45:17Z
FirstChildVoteTAG: 0
SecondChildTAG: Help! I also need clarifications in 2a and 2b. Weird, but I solved 3a and 3b correctly. Now I think I'm over analyzing. :( Please help. To get the average of the wrong numbers, I know that I need to multiply a constant (a) and add a constant (b). But I don't know how to get (a) in 2a. :(
SecondChildUserIdTAG: 1188300
SecondChildUserNameTAG: cqprivado
SecondChildCreateTimeTAG: 2013-03-11T22:39:56Z
SecondChildVoteTAG: 0
IndexTAG: 973
TitleTAG: problem 2b
OK, I've got an average number of wrong answers. Let it be NW, and num of right - NR. So I have a*NR + b = NW. And all I need is to calculate a, and put it into a*rSD = wSD.
But I didn't get how to calculate "b" param. Please, tell me, what did I miss?
UserIdTAG: 693583
UserNameTAG: Remmi
CreateTimeTAG: 2013-03-11T19:55:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 5
FirstChildTAG: I think that "b" is not necessary to calculate SD. SD is changing when you multiplying or dividing. When you add or subtracting it doesn't influence on SD.
FirstChildUserIdTAG: 1256305
FirstChildUserNameTAG: rozanska
FirstChildCreateTimeTAG: 2013-03-11T20:02:09Z
FirstChildVoteTAG: 0
SecondChildTAG: But I need a "b" to calculate "a". Or...?
SecondChildUserIdTAG: 693583
SecondChildUserNameTAG: Remmi
SecondChildCreateTimeTAG: 2013-03-11T20:05:31Z
SecondChildVoteTAG: 0
FirstChildTAG: The Number of Wrong and Number of Right are part of the same problem. They are two parts of One-whole part. So if you know the SD of one, you should know the SD of the other.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-11T20:02:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Ok, I found that a = (NW-b)/NR , so that's why I need "b" param. Did I miss something and there's another way to calculate "a"?
FirstChildUserIdTAG: 693583
FirstChildUserNameTAG: Remmi
FirstChildCreateTimeTAG: 2013-03-11T20:11:06Z
FirstChildVoteTAG: 0
FirstChildTAG: I think that in this task you have to only subtract - you don't have to multiplying. Only multiplying or dividing caused that SD changed.
FirstChildUserIdTAG: 1256305
FirstChildUserNameTAG: rozanska
FirstChildCreateTimeTAG: 2013-03-11T20:23:57Z
FirstChildVoteTAG: 3
SecondChildTAG: Oh, that's really make a sense. This is the most useful hint I've ever seen :)
SecondChildUserIdTAG: 693583
SecondChildUserNameTAG: Remmi
SecondChildCreateTimeTAG: 2013-03-11T21:07:57Z
SecondChildVoteTAG: 0
SecondChildTAG: According to that, I easily made problem 3a and 3b. What a stupid I had been :)
SecondChildUserIdTAG: 693583
SecondChildUserNameTAG: Remmi
SecondChildCreateTimeTAG: 2013-03-11T21:27:52Z
SecondChildVoteTAG: 0
FirstChildTAG: STILL NEED HELP
FirstChildUserIdTAG: 1326753
FirstChildUserNameTAG: Khlarah
FirstChildCreateTimeTAG: 2013-03-11T23:24:38Z
FirstChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_7/threads/513c3e63e8c82427000000e9
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-12T04:45:40Z
SecondChildVoteTAG: 0
IndexTAG: 974
TitleTAG: Problem 1C
This task is not formulated clearly enough. I chose the 70-71 range and it was also wrong. Does anyone have any idea?
UserIdTAG: 1256305
UserNameTAG: rozanska
CreateTimeTAG: 2013-03-11T19:48:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The post is about Excercise Set 8.
FirstChildUserIdTAG: 1256305
FirstChildUserNameTAG: rozanska
FirstChildCreateTimeTAG: 2013-03-11T20:07:21Z
FirstChildVoteTAG: 0
SecondChildTAG: The length is 1 inch, and 70 is in the middle.
SecondChildUserIdTAG: 693583
SecondChildUserNameTAG: Remmi
SecondChildCreateTimeTAG: 2013-03-11T20:09:12Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes here is one idea...
70.0 to the nearest 0.1 inch is 69.95 to 70.05.
70.00 to the nearest 0.01 inch is 69.995 to 70.005.
70 to the nearest 1 inch (which is what the problem asks for) is 69.5 to 70.5.
Try it.
FirstChildUserIdTAG: 902212
FirstChildUserNameTAG: trigeor
FirstChildCreateTimeTAG: 2013-03-11T20:09:49Z
FirstChildVoteTAG: 0
IndexTAG: 975
TitleTAG: Format and timing of midterm exam
What is the format of the midterm exam? Will it be time bound?
UserIdTAG: 1111917
UserNameTAG: rajeswariv
CreateTimeTAG: 2013-03-11T19:30:09Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: >Will it be time bound?
Of course!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-11T21:24:43Z
FirstChildVoteTAG: 0
IndexTAG: 976
TitleTAG: Lecture summary
These lectures are not posted in the lecture summary
3.3, 3.4, 4.1, 4.2, 4.3 and all week 3 lecture (5.1-5.4)
Thank you
UserIdTAG: 992597
UserNameTAG: Drhannaa
CreateTimeTAG: 2013-03-11T18:59:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 977
TitleTAG: midterm exam
what it will hapened if i will not pass the exam?
UserIdTAG: 1147076
UserNameTAG: giomicho
CreateTimeTAG: 2013-03-11T18:45:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Judging by the thread it will make you slightly disappointed with yourself, but according to the course policies there is no requirement to pass each individual element of the course, merely achieve an overall grade of 35% of the total available marks, of which the midterm represents 1/5th.
You can find the full information here:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
So you're good, and have no need to worry. Do your best, and if you run into trouble, you can catch up through the assignments and/or the final.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T18:49:38Z
FirstChildVoteTAG: 2
SecondChildTAG: thank u !!you were very helpful and kind. u have right i will dissapoint my self..but i am afraid of the word "exam"...
SecondChildUserIdTAG: 1147076
SecondChildUserNameTAG: giomicho
SecondChildCreateTimeTAG: 2013-03-11T19:15:44Z
SecondChildVoteTAG: 0
IndexTAG: 978
TitleTAG: Applet Visual Problem
For a wierd reason I can' t see any of the appelet' s visual. I' ve disable adblock and enable java at startup but still have the problem. Any suggestion?
UserIdTAG: 1090983
UserNameTAG: AchilleasP
CreateTimeTAG: 2013-03-11T18:34:55Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Try a different browser?
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T18:44:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Won't help. It's a bug on the webpage itself, that manifests only on web browsers configured to work with specific non-English languages.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-03-11T20:47:43Z
SecondChildVoteTAG: 0
FirstChildTAG: I can not see any applet either. Where to access it?
FirstChildUserIdTAG: 1178106
FirstChildUserNameTAG: pyt
FirstChildCreateTimeTAG: 2013-03-11T19:36:31Z
FirstChildVoteTAG: 0
SecondChildTAG: All up in here: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
Update your Java, try a different browser if that doesn't work by itself, and there is a thread around here where some super-smart person tracked down a problem with the applet not displaying for people using funny fonts.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-11T19:55:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Won't help. It's a bug on the webpage itself, that manifests only on web browsers configured to work with specific non-English languages.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-03-11T20:47:51Z
SecondChildVoteTAG: 0
FirstChildTAG: go to right top corner click setting, click tools-->click encoding-->click unicode (UTF-8). You are get set go. This is for chrome
You don't need java since it is java script, all you need a right encoding from your browser (use firefox or chrome).
If you have any issue pls copy page and paste here. I can help you.
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-11T22:19:17Z
FirstChildVoteTAG: 0
IndexTAG: 979
TitleTAG: z from applet
Hello all,how to get z from applet for certain percentile to calculate the value.
Like the Q1 of practice to exercise 8
A distribution of test scores is approximately normal with mean 65 and SD 10.
what 75th percentile of the score ?
I hope you can help me !!! I cannot understand it
Thank you
UserIdTAG: 992597
UserNameTAG: Drhannaa
CreateTimeTAG: 2013-03-11T18:29:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You should give the values in applet and define what score is corresponding to 75%.
Watch the lecture and use the formula for computing the z score to get the right answer!
FirstChildUserIdTAG: 1334866
FirstChildUserNameTAG: Geochem
FirstChildCreateTimeTAG: 2013-03-11T20:50:32Z
FirstChildVoteTAG: 0
IndexTAG: 980
TitleTAG: Problem 1a and 1b. Find Average and SD of transformed list
Some help needed for problem 1a and 1b.
A list of numbers has an average of 48 and an SD of 12. The list is transformed by subtracting 3 from each entry and then dividing the result by 5. To find the Average of the transformed list, do I need to subtract 3, then divide it by 5?
I am confused as the equation to find Average and SD of transformed list talks about adding and/or multiplying a constant not subtracting and dividing.
UserIdTAG: 1203339
UserNameTAG: Anamile71
CreateTimeTAG: 2013-03-11T18:11:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: Dividing is identical to multiplying by a fraction. Subtracting is the same as adding a negative number.
4 divided by 2 is the same as 4 multiplied by 1/2. Does that make it any easier to conceptualise?
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T18:35:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks BBF. My mistake was that I divide first, then I substract. Therefore, my Av was wrong.
SecondChildUserIdTAG: 1203339
SecondChildUserNameTAG: Anamile71
SecondChildCreateTimeTAG: 2013-03-12T11:27:04Z
SecondChildVoteTAG: 0
FirstChildTAG: This problem is helpful because it is wording in a way that tells us exactly what to do. We have to first subtract. Then we divide.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-11T18:35:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks. My mistake was that I divide first, then I substract. Therefore, my Av was wrong.
SecondChildUserIdTAG: 1203339
SecondChildUserNameTAG: Anamile71
SecondChildCreateTimeTAG: 2013-03-12T11:28:04Z
SecondChildVoteTAG: 0
IndexTAG: 981
TitleTAG: Staff
I do not understand the z values given for the percentiles in the answer. E,g You give a value for 60th percentile as 0.25 (2dp). How? I have 0.84.I got the answer right.
UserIdTAG: 722050
UserNameTAG: aswanifj
CreateTimeTAG: 2013-03-11T17:41:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Ignore plse. Sorry and thnks
FirstChildUserIdTAG: 722050
FirstChildUserNameTAG: aswanifj
FirstChildCreateTimeTAG: 2013-03-11T18:14:14Z
FirstChildVoteTAG: 0
IndexTAG: 982
TitleTAG: More Reading...
This class has been very helpful in terms of learning the basics. However, I would like more reading/practice to help solidify the material we've been learning (i.e. practical/real world application of statistics in action). Can anyone suggest some books?
Thanks in advance!
UserIdTAG: 984610
UserNameTAG: relznedk
CreateTimeTAG: 2013-03-11T17:13:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 983
TitleTAG: PROBLEM 1A
i have probably problem with the applet, i use the same number with the solution but i found wrong percent.i dont know what i m doing wrong....please help...
i had the same problems with the latest exercise set..
UserIdTAG: 1147076
UserNameTAG: giomicho
CreateTimeTAG: 2013-03-11T17:12:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: revisit to the videos of lectures 5.1 and 5.2, prof has demonstrated the use of applet in those videos. Try to follow the professor, i guess that would help you.
FirstChildUserIdTAG: 1007920
FirstChildUserNameTAG: PrakashGupta
FirstChildCreateTimeTAG: 2013-03-11T17:16:14Z
FirstChildVoteTAG: 0
SecondChildTAG: thank u!i cant find the % of number 2.4.do you??
SecondChildUserIdTAG: 1147076
SecondChildUserNameTAG: giomicho
SecondChildCreateTimeTAG: 2013-03-11T17:44:22Z
SecondChildVoteTAG: 0
SecondChildTAG: ok now i understand ..
SecondChildUserIdTAG: 1147076
SecondChildUserNameTAG: giomicho
SecondChildCreateTimeTAG: 2013-03-11T18:04:17Z
SecondChildVoteTAG: 0
FirstChildTAG: google a z-score percentile table, that way you don't have to keep moving the mark to get your percentile.
FirstChildUserIdTAG: 1261130
FirstChildUserNameTAG: sue970828
FirstChildCreateTimeTAG: 2013-03-11T17:34:44Z
FirstChildVoteTAG: 1
IndexTAG: 984
TitleTAG: More Reading...
This class has been very helpful in terms of learning the basics. However, I feel I need some extra practice/materials to really solidify what we've been learning (i.e. more practical/real world examples of statistics in action). Can anyone suggest some books?
Thanks in advance!
UserIdTAG: 984610
UserNameTAG: relznedk
CreateTimeTAG: 2013-03-11T17:09:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 985
TitleTAG: Problem 4 - Second part
Hi Everyone
I am having problem solving second part of Problem 4. Can somebody guide me please.
I have got the answer for first part. Thanks in advance
UserIdTAG: 967531
UserNameTAG: manjusinghal
CreateTimeTAG: 2013-03-11T16:55:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: What is the problem?
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-11T18:04:01Z
FirstChildVoteTAG: 0
FirstChildTAG: You just need to watch again Affine Transformations and you will find the right answer...It's easy!
FirstChildUserIdTAG: 1334866
FirstChildUserNameTAG: Geochem
FirstChildCreateTimeTAG: 2013-03-11T20:36:19Z
FirstChildVoteTAG: 0
IndexTAG: 986
TitleTAG: Practice Exercise 7 Problem 2
I am totally confused by this question even when I viewed the answer. I admit my math skills are rather rusty. I was following along in the answer until I got to " That means 42 in the original units is 0.4*5 = 2 units above average, which means the average is 40". Huh? Can someone please explain? I am thinking it's OK to talk about the answer here since I am speaking of the practice set, not the actual exercise set for this series.
UserIdTAG: 1061881
UserNameTAG: kristen1trigen
CreateTimeTAG: 2013-03-11T16:11:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Kristen, my suggestion for you is to draw out a diagram. This problem gives us the Standard Unit (Z) and the Original Unit in the table. We know that if we convert the Original Unit to Standard Unit, the Average will turn into 0 or Z = 0. And one standard deviation from the Average is 1 or Z = 1.
However, for this problem, we don't know the average. We also don't know what the SD is. But what we do know is the original unit and the standard unit. So we pick 2 points in the table that have both the Original Unit and the Standard Unit.
For example, in the first row of the table, the Original Unit is 54. This 54 equals the 2.8 if we convert it to the Standard Unit.
Likewise, 42 is the original value and it is equals 0.4 if we convert it to the standard unit.
So draw a horizontal line with 2 points. One point for 42 and one point for 54. Beneath 54 we put 2.8 and 0.4 under 42. This to symbolize that 2.8 in standard unit is the same as 54 in the original unit.
We want to find the standard deviation. We want to know how many SDs are there per 1 unit of Z. Think of the 54 and 42 in terms of meters and 2.8 and 0.4 in terms of miles. You want to know how many meters are there per 1 mile.
So if we go from 54 to 42, there are 12 meters. And if we go from 2.8 to 0.4 there are 2.4 miles. If we divided 12/2.4 = 5. This 5 tells us that there are 5 meters per mile.
Likewise, in terms of SD, it says that there are 5 SDs per Z-unit.
Now that we have the SD, we can plug this into the formula
Z = (X - average)/SD
Pick any point in the table that has both the X value or the original value and the Z-score. In the Explanation, they pick 42 and 0.4 to solve for the Average.
You just need to substitute 0.4 for Z; 42 for X; and 5 for SD;
Z = (X - average)/SD
0.4 = (42 - average)/5
0.4 * 5 = 42 - average
2 = 42 - average
2 + average = 42
average = 42 - 2
Average = 40
Now that you have the Average, SD, you can solve for Point A and B just by plugging in the numbers for that formula.
I suggest you head over to Udacity and take Visualizing Algebra if your command of Algebra is not as strong as you would like. It helps me a great deal because I forgot many things about Algebra. I couldn't even comprehend Intermediate Algebra on Coursera. So I go to Udacity to learn Algebra from the basics. And after only 2 units I have a much better command of the basics. I still have a long way to go. Anyway, I suggest you give it a try. It is really fun and cool.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-11T16:53:29Z
FirstChildVoteTAG: 1
FirstChildTAG: Thank you so much! This really helped me. It's been a long time since I've done "real" math that the course you recommended sounds great.
FirstChildUserIdTAG: 1061881
FirstChildUserNameTAG: kristen1trigen
FirstChildCreateTimeTAG: 2013-03-12T03:19:10Z
FirstChildVoteTAG: 0
IndexTAG: 987
TitleTAG: midterm exam
I would appreciate to know if for the exam of the 13th. march we will have all the day to solve it, or an interval of time will be given.
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-03-11T15:59:43Z
VoteTAG: 12
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Details will be released 'soon'. The Prof. has said that there will be at lest a day to complete the exam - although whether that refers to the submission window or the time allowed once started (if that is different) has yet to be revealed.
Presumably the information will be available today or tomorrow...
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-11T16:14:07Z
FirstChildVoteTAG: 5
FirstChildTAG: that is really important info. how are we supposed to plan our week and work schedule if they want us to be available 24 hrs on wednesday due to time change...
FirstChildUserIdTAG: 1207892
FirstChildUserNameTAG: triplebee
FirstChildCreateTimeTAG: 2013-03-11T19:26:44Z
FirstChildVoteTAG: 0
IndexTAG: 988
TitleTAG: Passing Grade
Hello all of you,
I have received 38% in total so far and the passing grade is 35%. So does it mean that I have passed the exam already ??
Let me know..:)
Thanks & Regards
UserIdTAG: 357124
UserNameTAG: vnirwan
CreateTimeTAG: 2013-03-11T15:34:00Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: If you have 38% you have now passed stats 2.1x.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T15:53:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Yeah, it means you have passed the course and will get a certificate. I'm in a similar situation, but want to take it all the way and score as highly as I can on the course. And, more importantly, learn as much as I can!
FirstChildUserIdTAG: 1261574
FirstChildUserNameTAG: Bravus
FirstChildCreateTimeTAG: 2013-03-11T18:56:27Z
FirstChildVoteTAG: 0
SecondChildTAG: yes That's right! I'm too intersted to get as much ahead as I can..just thot to ask abt it...:)
Thanks
SecondChildUserIdTAG: 357124
SecondChildUserNameTAG: vnirwan
SecondChildCreateTimeTAG: 2013-03-12T09:30:49Z
SecondChildVoteTAG: 0
IndexTAG: 989
TitleTAG: Problem 1C - not explicit
It is not explicitly enough stated what "the nearest inch" means. I chose a bigger interval and was wrong. Could have thought of a smaller one and still be wrong. Please attach an explication note on exactly what that means, so other people won't be confused. Thank you.
UserIdTAG: 1216723
UserNameTAG: Darkennoia
CreateTimeTAG: 2013-03-11T14:40:48Z
VoteTAG: 23
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 6
FirstChildTAG: You need to think back to the beginning of the course. when the prof was talking about the width of the bars. you have to think about it as an bar, from which number till which upper limit are included in this bar and use those in the applet. I hope this is clear enough.
FirstChildUserIdTAG: 804886
FirstChildUserNameTAG: marlasinger1470
FirstChildCreateTimeTAG: 2013-03-11T15:55:31Z
FirstChildVoteTAG: 2
SecondChildTAG: I am not talking about endpoint convention, but the width of the interval;"the nearest inch" is vague and can comprise a variety of widths, all at my discretion. I pointed out a interpretable part of the problem, which should be cleared; I understand what the problem is asking, and my posting isn't about that.
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-11T17:03:43Z
SecondChildVoteTAG: 0
SecondChildTAG: You are of the opinion that the interval "the nearest inch" can comprise a distance of more than an inch?
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-11T17:19:30Z
SecondChildVoteTAG: 0
SecondChildTAG: It's very odd how you are so deranged by my assumption? It's not about your lost points. As for higher mathematics analysis, this is not the place. It can comprise a smaller interval, as I wrote to the next post.:)
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-11T18:16:00Z
SecondChildVoteTAG: 0
SecondChildTAG: I am not contradicting your point of view, this post it's specifically to the staff, and not to prove that this I am right or wrong. Better not turn this into a soap opera and stay friends. Let's put this on my bad English skills. I didn't understand that it meant **1 inch distance** in that interval. I am used to other measures. Assuming that others have the same problem, I asked for a not that should clarify the problem and say: from 0.5 to 0.5. We are not all native english speakers.
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-11T18:23:16Z
SecondChildVoteTAG: 0
SecondChildTAG: It really really can't. The normal curve shows all the values. So you are trying to work out which of all the values are X inches to the nearest inch. If one goes with your assumption that it includes only the .9 to .1 where do the rest of the numbers go? There is only one logical interval, using rounding conventions, that allows us to review the numbers to the nearest inch.
This really isn't higher mathematics, you would be further confusing yourself to think it's much more than rounding, the principles of which were explained to us pretty much from the first histogram.
And yeah, you are correct, that your insistence that you not getting something is the test's fault is making me quite mad: it makes it harder to appreciate my fellow man, so I am going to leave this thread before it makes me sad.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-11T18:30:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Darkennoia, if you have trouble understanding the problem because of your unfamiliarity with the meaning of "to the nearest inch", then you should ask others to help you understand it in the forums, NOT ask the staff to change the test(if you don't know what "to the nearest inch" means, you should learn it, not try to get staff to give you a way to get around not knowing it).
SecondChildUserIdTAG: 969411
SecondChildUserNameTAG: McAlary
SecondChildCreateTimeTAG: 2013-03-12T14:40:16Z
SecondChildVoteTAG: 0
FirstChildTAG: Part of any mathematical problem is to translate the question into equations to find the answer, it's also a big part of the "descriptive" element of the descriptive statistics. Choosing a bigger interval is both illogical and inconsistent with the way we calculate and round answers for any question in this course.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T15:57:16Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes, but this exercise isn't asking integrals and functions. It's plain simply mathematics. As for bigger and smaller intervals, that is very arguable. I couldn't guess it's .that answer and the logic isn't very transparent in this case. To the nearest inch could mean .90 and .10.
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-11T17:10:07Z
SecondChildVoteTAG: 0
SecondChildTAG: Personally I get to the nearest number by rounding. In some cases these numbers could include decimal places, in this one it does not, as the exact number has been given as part of the question.
Where you round from and to is a very firm mathematical convention, which requires no guesswork. You can argue against it, but that is a journey you will have to make alone.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-11T17:30:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Is 4.51 (any unit you want to use) closer to 4 units or closer to 5 units ?
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-13T01:31:52Z
SecondChildVoteTAG: 0
FirstChildTAG: 70 inches tall, to the nearest inch...
That means 69.5 to 70.5....can it BE more explicit?
Surely 69.49 and 70.51 are not 70 to the nearest 1 inch...
FirstChildUserIdTAG: 902212
FirstChildUserNameTAG: trigeor
FirstChildCreateTimeTAG: 2013-03-11T18:07:08Z
FirstChildVoteTAG: 0
SecondChildTAG: How about 69.99 and 70.01?
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-11T18:14:09Z
SecondChildVoteTAG: 0
SecondChildTAG: " Approximately what percent of the adults are 70 inches tall, to the nearest inch?"
Sure from 69.99 to 70.01 they are 70 inches tall to the nearest inch, but this is only a subset of those who meet the criterion which are from approximately 69.5 to approximately 70.5 inches tall, to the degree of accuracy used in all problems. This is clear surely ...no?
SecondChildUserIdTAG: 902212
SecondChildUserNameTAG: trigeor
SecondChildCreateTimeTAG: 2013-03-11T19:45:01Z
SecondChildVoteTAG: 0
SecondChildTAG: I took the expression "to the nearest inch" in a somewhat odd sense, and calculated +1 inch, -1 inch from 70. It is frustrating that i am accused of discussing the properties of the normal curve and other technical stuff, witch **is not** what this is about. I know that 0.5 to the next 0.5 makes 1. I was pointing out that not all people have an excellent fluency in english and might have the same problem. I am sorry for the futile "quarrel" witch was not the point. I asked to be more explicit not for my sake, as I am done with the exercise, but for others. Anyway, thanks for help. All the best.
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-11T20:08:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually, 70.5 rounds up to 71. 70.49 is more correct. That is the number I used.
SecondChildUserIdTAG: 1327840
SecondChildUserNameTAG: Sapphire38
SecondChildCreateTimeTAG: 2013-03-11T21:22:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Look at it as an interval where one end point is inclusive and the other not, that way the confusion is minimized
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-11T22:22:11Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks Darkennola, i live in California and it wasn't clear to me either!
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-03-13T03:48:22Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm a native English speaker, and I wasn't entirely sure what was meant by this question either. As close to 70 inches as possible? Within one inch if you round the numbers (meaning 69.5 - 70.4)? Within one inch above or one inch below? Using rounding as a guide, I'd guess between 69.5 - 70.4 is the best one to use. I haven't submitted my answer yet, so I don't know this for certain yet.
FirstChildUserIdTAG: 673325
FirstChildUserNameTAG: coutlay
FirstChildCreateTimeTAG: 2013-03-11T19:24:47Z
FirstChildVoteTAG: 4
SecondChildTAG: Submit 69.5 to 70.5. It is about the 1 inch from 69.5 to 70.5, not the endpoint convention.
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-11T20:09:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Remember (69.5,70.5). This interval means that you could be as close as you want to 69.5 and 70.5 but you don´t get to them...so, you HAVE to use this interval to solve it, because normal function is a CONTINOUS FUNCTION. If some one use 69.5-70.4 is wrong beuse 70.41 is rounded to 70 as well and 70.43 and 70.44 and 70.49999999 but not 70.5. Hope it helps
SecondChildUserIdTAG: 731428
SecondChildUserNameTAG: mjgarciam
SecondChildCreateTimeTAG: 2013-03-11T20:28:15Z
SecondChildVoteTAG: 0
FirstChildTAG: Precaución not native English >>
The question asks what percentage of adults are in one unit (inch) centered on the value 70.
FirstChildUserIdTAG: 1183170
FirstChildUserNameTAG: kungan
FirstChildCreateTimeTAG: 2013-03-11T20:00:03Z
FirstChildVoteTAG: 4
FirstChildTAG: There is a response from staff that explains [measurements to the nearest][1] [fill in the units] which may be helpful. I wish I had checked this out myself before submitting. Hope this helps.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/513a117a1f558227000001e4
FirstChildUserIdTAG: 327437
FirstChildUserNameTAG: guanaco
FirstChildCreateTimeTAG: 2013-03-12T02:15:56Z
FirstChildVoteTAG: 3
IndexTAG: 990
TitleTAG: Help!. Prob 3, exercise 3 (to the left of 0.4)
Why answer is 65.54 instead of 34.46?
UserIdTAG: 1203339
UserNameTAG: Anamile71
CreateTimeTAG: 2013-03-11T14:03:03Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: - Problem 3, Part 2: to the right of 0.4 (from 0.4 to right endpoint
5.0 -> 4.6 standard units).
- Problem 3, Part 3: to the left of 0.4 (from left endpoint -5.0 to 0.4 -> 5.4 standard units).
The sum of the two must be 100%
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-11T14:23:50Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks Senta
SecondChildUserIdTAG: 1203339
SecondChildUserNameTAG: Anamile71
SecondChildCreateTimeTAG: 2013-03-11T16:10:31Z
SecondChildVoteTAG: 0
FirstChildTAG: Why would it be 34.46?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-11T14:27:42Z
FirstChildVoteTAG: 0
SecondChildTAG: -0.4 to right (5) check what u get and hence ask qus why would it be 34.46 (as klionheart mentioned above)
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-11T14:37:53Z
SecondChildVoteTAG: 0
SecondChildTAG: or check 0.4 to -5 either way
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-11T14:39:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Kilonheart and Navgir
SecondChildUserIdTAG: 1203339
SecondChildUserNameTAG: Anamile71
SecondChildCreateTimeTAG: 2013-03-11T16:10:58Z
SecondChildVoteTAG: 0
IndexTAG: 991
TitleTAG: Exercise Set Solution/ Midterm
Where are the exercise set solutions?
How is the Midterm taking place? Is it like exercise set where we get X amount of time to finish it? And what's the format like?
UserIdTAG: 1198576
UserNameTAG: MChiu
CreateTimeTAG: 2013-03-11T13:58:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You can get the solutions with an explanation by clicking on **Show Answer** after you submit your final answer.
One of the students is also writing the R code solutions for the exercise sets, which can be found here: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/R/
I don't think the definite info on the Midterm is out yet, but it's likely to appear at the following link once it's available: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T14:04:29Z
FirstChildVoteTAG: 1
IndexTAG: 992
TitleTAG: Problem 6 & 7
Got the wrong answers, looked through the solution, and still din't quite catch it. HELP!
UserIdTAG: 1211883
UserNameTAG: Santastic
CreateTimeTAG: 2013-03-11T13:23:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: The explanations are pretty brief for those.
If you wanna run through them, send me a mail at *redacted after a set time period*
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T13:48:21Z
FirstChildVoteTAG: 0
SecondChildTAG: Calculate the z for xth percentile from the normal curve and use formula zSD + A to get the ditribution. Hope this helps.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-11T14:10:30Z
SecondChildVoteTAG: 0
FirstChildTAG: Got It! Thank You :)
FirstChildUserIdTAG: 1211883
FirstChildUserNameTAG: Santastic
FirstChildCreateTimeTAG: 2013-03-12T05:05:12Z
FirstChildVoteTAG: 0
IndexTAG: 993
TitleTAG: Prob 1A confusion
I am confused about how to post the answer in percentage. Suppose I got .1234 as the answer, do I type in the same or should I do some alterations to it like move the decimal places?
UserIdTAG: 933932
UserNameTAG: Shadybog
CreateTimeTAG: 2013-03-11T13:19:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: e.g. 0.1234 = 12.34%, report in the box as 12.34
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-11T13:42:32Z
FirstChildVoteTAG: 0
SecondChildTAG: Doing that got me 1 wrong attempt :(
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-03-11T14:40:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Perhaps the answer itself was wrong?
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-03-11T19:25:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Wait, I don't think you need to calculate percentages. I used the applet to find percentages. If the applet gives you 49.2%, you should enter 49.2
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-03-11T19:26:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Looking at the question and the range of possible answers I would go with 0.xx.
Did you use the applet to get your solution? The answer should be quite clear if you did...
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-11T13:50:14Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes I did.. Got the solution also.. only confused about how to post it
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-03-11T14:35:22Z
SecondChildVoteTAG: 0
SecondChildTAG: That also didn't work :(
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-03-11T14:42:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I didn't use the applet but used Chebychev's to get the answer.. That's where I went wrong.
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-03-11T14:47:28Z
SecondChildVoteTAG: 0
SecondChildTAG: The question reads as 'The distribution of heights of a population of adults **is approximately normal** with mean 66 inches and SD 2.5 inches'. So when the distribution is to be assumed as approximately Normal, you do not have to use Chebbychev's. USe the same formula that you use for normal distribution.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-11T18:10:36Z
SecondChildVoteTAG: 0
IndexTAG: 994
TitleTAG: the video volume is too low
the volume is so low...i could barely lisiten...
UserIdTAG: 845414
UserNameTAG: Jinal0407
CreateTimeTAG: 2013-03-11T12:08:34Z
VoteTAG: 3
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 0
IndexTAG: 995
TitleTAG: cross mark in progress report
hey i m getting cross mark in progress report in exercise 11 and 12....what does it mean???????
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-11T10:52:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: your worst 2 exercise sets will be crossed out - and will not influence the average exercise grade.
So by now - while you have still 0% of Exercise 11 and 12 - both will be crossed out. When you achive better scores in 11 or 12 then the other Exercises the crosses will jump over.
FirstChildUserIdTAG: 1264246
FirstChildUserNameTAG: Puhgee
FirstChildCreateTimeTAG: 2013-03-11T11:03:53Z
FirstChildVoteTAG: 0
FirstChildTAG: Cool, thanks, I'd wondered about that too, and it makes a lot of sense.
FirstChildUserIdTAG: 1261574
FirstChildUserNameTAG: Bravus
FirstChildCreateTimeTAG: 2013-03-11T18:57:49Z
FirstChildVoteTAG: 0
IndexTAG: 996
TitleTAG: To Professor Adhikari, a request.....
Madam, I hope you are reading the discussions done by students here. I love to attend your lectures and love the simplicity in your explanations of the concepts.
Although this problem set was challenging in comparison to the other sets. It took a huge time to solve this problem set but in the end i was able to solve it. Please don't set any time limit (if you are planning for it) because students like me who belongs to the field of social sciences wish to learn statistics because it is helpful for doing our research better by incorporating tools of statistics in it but our cognition will take some more time to adapt with mathematical curriculum. Students like 'me' will struggle in Mid-sem if time limitations are posed in the test.
Kindly accept a small request from my side.
UserIdTAG: 1007920
UserNameTAG: PrakashGupta
CreateTimeTAG: 2013-03-11T10:22:58Z
VoteTAG: 8
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 4
FirstChildTAG: So what are you asking for? No time limits on tests?
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-11T11:43:10Z
FirstChildVoteTAG: 0
FirstChildTAG: I think to a certain level time limits on tests are valuable because they help move towards an evaluation of one's understanding of the material, rather than the ability to research the answer.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T12:56:57Z
FirstChildVoteTAG: 2
FirstChildTAG: I agree about time limits. True that we all are busy. But we should be able to find time for this course if this is important to us. It is all a matter of priorities.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-03-11T17:35:28Z
FirstChildVoteTAG: 0
FirstChildTAG: Busy people need to rethink their priorities. This could isn't about the individual. We (collective) sign up to an online course, knowing that it follows the rigor of a f2f course. Expect time limits.
Oh, and good edit! It helps to get the Prof's name correct.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-11T21:32:08Z
FirstChildVoteTAG: 0
SecondChildTAG: A collective is a pack of wolves and a sheep deciding what's for dinner! We didn't sign up as a collective, but as individuals.
SecondChildUserIdTAG: 937396
SecondChildUserNameTAG: m2foster
SecondChildCreateTimeTAG: 2013-03-12T19:53:43Z
SecondChildVoteTAG: 0
IndexTAG: 997
TitleTAG: practice exrcise 5,6,8
in progress those exercise showing 0 number of mine.but i have clered 100 percent.so dont it showing my number?
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-11T07:06:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Practice problems don't count for the grade, and will always show as 0/0 on the Progress page. Nothing to worry about.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-11T14:52:01Z
FirstChildVoteTAG: 0
IndexTAG: 998
TitleTAG: How do you find the z part of the equation?
I am lost. On one of the problems for 7 it gives you something like the z=.0882 How do I find this number?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-11T06:49:41Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hi there!
To turn original units (x) into standard units (z) you should use the following formulae:
**x = z*SD+Avg**
If you know the other players you can isolate z and its value with some maths.
Good luck!
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-11T09:21:21Z
FirstChildVoteTAG: 0
FirstChildTAG: z is the "x" coordinate on the Standard Normal Curve graph.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-11T14:30:53Z
FirstChildVoteTAG: 1
IndexTAG: 999
TitleTAG: can't submit results
Hi!
I have the new Surface RT tablet with the >>Internet Explorer 10<< Browser.
I can't change the browser because there is no way to install a Chrome or Firefox in the RT-tablet and this week I'm on vacation (sunny Egypt) so I can't change the computer either.
How can I submit the test-results (in time, i.e. till wednesday)?
Otherwise THX 4 the great platform.
Eliane
UserIdTAG: 1240020
UserNameTAG: Elibee
CreateTimeTAG: 2013-03-11T06:29:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi!
All I can say is try to get a PC the firefox browser from a friend or go to a internet café... Chrome has given me problems at visualizing some compoments as well.
Good luck!
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-11T09:18:11Z
FirstChildVoteTAG: 0
IndexTAG: 1000
TitleTAG: sticking with it
With just math basics, things are starting to get intimidating. But Professor A has been presenting material in a math-phobic friendly way that even I can catch up. the course is so interesting, I want to stick with it.
UserIdTAG: 1229212
UserNameTAG: mobmarshall
CreateTimeTAG: 2013-03-11T05:34:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: yes, you can do it. Totally. Go self!
FirstChildUserIdTAG: 1229212
FirstChildUserNameTAG: mobmarshall
FirstChildCreateTimeTAG: 2013-03-11T05:45:51Z
FirstChildVoteTAG: 1
SecondChildTAG: go mobmar!
SecondChildUserIdTAG: 433872
SecondChildUserNameTAG: dfburke
SecondChildCreateTimeTAG: 2013-03-11T13:52:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Just a little tip, if you really struggle with the math, maybe you can try khanacademy.org There are lots of video's and exercises there to help you. It helped me get over my "numberphobia"
SecondChildUserIdTAG: 804886
SecondChildUserNameTAG: marlasinger1470
SecondChildCreateTimeTAG: 2013-03-11T18:01:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks!
SecondChildUserIdTAG: 1229212
SecondChildUserNameTAG: mobmarshall
SecondChildCreateTimeTAG: 2013-03-12T02:20:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Glad to hear mobmar shall stick with the course.
I think a lot of people are using a very subjective evaluation of whether they are doing well in the course. It's 35% to pass, which is possible to pick up from the midterm and final alone, even getting 0% in all the assignments. So if you are getting 35% or more of each assignment's marks, you are on target, and regardless of marks it's worth sticking with the course. Worst case scenario you don't get the cert, but still know more about statistics, the interest in which brought us all here, no?
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T18:43:45Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes.Thanks.
SecondChildUserIdTAG: 1229212
SecondChildUserNameTAG: mobmarshall
SecondChildCreateTimeTAG: 2013-03-12T02:20:38Z
SecondChildVoteTAG: 0
IndexTAG: 1001
TitleTAG: Problem 2
I dont quite understand how this problem is solved. I tried to apply the same methodology on each of the values (54 and 42) alone and I got different results
Why didn't it work?
UserIdTAG: 1213517
UserNameTAG: CarolinaOcampo
CreateTimeTAG: 2013-03-11T05:33:17Z
VoteTAG: 1
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: What would this "methodology" be? Did you find the Average and the SD?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-11T14:50:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Same problem here. I solved it using a two equation system, getting SD and average from the two given points. My SD is 4.4 and average is 41.8. No far from the solution, the disparity has to do with decimals during the calculations, but still i got it wrong.
SecondChildUserIdTAG: 1041137
SecondChildUserNameTAG: SimaoCastro
SecondChildCreateTimeTAG: 2013-03-11T16:41:49Z
SecondChildVoteTAG: 0
IndexTAG: 1002
TitleTAG: help needed how to find answers to exercises already marked
hi please i need help in locating answers to previous exercises already. i dont know where to find it on platform.
UserIdTAG: 1105307
UserNameTAG: takut
CreateTimeTAG: 2013-03-11T05:32:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Click **Show Answer**, located under the question.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-11T05:51:41Z
FirstChildVoteTAG: 0
IndexTAG: 1003
TitleTAG: I registered this course today.
Hi,
I registered this course today. Is it possible to follow up the course and can write the exam?
I am very much interested to learn statistics . Please share your views.
UserIdTAG: 1400440
UserNameTAG: astolunar
CreateTimeTAG: 2013-03-11T04:50:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Welcome. Please go ahead and do the Week 3 Exercise. While deadline for Week 1 and 2 are over, there is plenty of scope to meet up with minimum passing requirements through future assignments and exams.
So just go thru' all the videos from day 1 and you should be good! If you sit at a stretch, a day is enough to cover the syllabus till date.
Best Wishes.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-11T10:39:18Z
FirstChildVoteTAG: 1
SecondChildTAG: i am very happy to register your website
SecondChildUserIdTAG: 1402539
SecondChildUserNameTAG: destaw
SecondChildCreateTimeTAG: 2013-03-11T13:49:54Z
SecondChildVoteTAG: 0
SecondChildTAG: it is very wonderful cooperation practice i appreciate your free education .
SecondChildUserIdTAG: 1402539
SecondChildUserNameTAG: destaw
SecondChildCreateTimeTAG: 2013-03-11T13:54:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you very much for your care and concern.
SecondChildUserIdTAG: 1400440
SecondChildUserNameTAG: astolunar
SecondChildCreateTimeTAG: 2013-03-11T14:09:22Z
SecondChildVoteTAG: 0
IndexTAG: 1004
TitleTAG: Histogram v barchart
Oh, I did not know that there is so much behind Histogram. Thanks Professor!!
UserIdTAG: 1400423
UserNameTAG: shaik134
CreateTimeTAG: 2013-03-11T04:35:20Z
VoteTAG: 1
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 0
IndexTAG: 1005
TitleTAG: midterm exam
Dear Profs,
I am not clear about the procedure when to sit the exam, time frame? Do we have to sit live or during a window of period? Do we have to answer in one sit or come and go during a time frame?
I would be so grateful if kindly explain so I can plan the time for the exams.
regards
UserIdTAG: 1082215
UserNameTAG: Ayee
CreateTimeTAG: 2013-03-11T03:20:20Z
VoteTAG: 16
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: From what we have been told so far, there will be a 24hr window on the wednesdayish to do the exam. Now whether within that it will be further restricted, such as having X minutes from the time the first answer is submitted... I don't think they have answered that yet.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T03:36:39Z
FirstChildVoteTAG: 1
FirstChildTAG: Hope it is within the 24hr window. Otherwise, people with schedule restrictions (like me, on a business trip that day) will be facing a hard time !....
FirstChildUserIdTAG: 1003677
FirstChildUserNameTAG: CValladaress
FirstChildCreateTimeTAG: 2013-03-11T11:41:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Prof. has already said that there will be 'at least' a day.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-11T16:18:33Z
SecondChildVoteTAG: 0
IndexTAG: 1006
TitleTAG: Exercise set 7 problem 3B
in the exercise it says that every correct answer is multiply by 5 points, I did that but the answer was wrong and it corrected me that it was multiply by 6. I think there is a discordance between both, or I didn´t understand it right.
UserIdTAG: 818670
UserNameTAG: mgainza
CreateTimeTAG: 2013-03-11T03:13:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Look at the Show Answer solution for 3A. And the honour code.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-11T03:20:44Z
FirstChildVoteTAG: 0
IndexTAG: 1007
TitleTAG: Pace of information
While I appreciate the in-depth coverage of certain topics, I find its becoming difficult to maintain interest when we cover a single example for such a long period. I feel like I get the "meat" in the first 5 minutes (at 1.5x) of a lecture, and want to skip the rest. Its a discipline issue on my part, but I felt like it should be said.
I also think that LARGER homework assignments would be helpful, even if its just more problems of the same type.
Great course, just wanted to provide feedback. :)
UserIdTAG: 40598
UserNameTAG: jstarkey
CreateTimeTAG: 2013-03-11T02:55:18Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I think there is a balance to be had between the pace of the course and the drastically divergent mathematical aptitudes of the students.
The information they make available to us isn't just in the taped lectures, but also the online textbook, which goes into massive depth on the subject of statistics and has a solid number of example questions for anyone looking to put in more work.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T02:58:03Z
FirstChildVoteTAG: 0
FirstChildTAG: If you want more, maybe the Coursera courses that start soon?
https://www.coursera.org/courses?orderby=upcoming&cats=stats
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-11T03:18:40Z
FirstChildVoteTAG: 0
FirstChildTAG: And bear in mind this is only the first of three introductory Stats courses.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-11T16:20:21Z
FirstChildVoteTAG: 0
IndexTAG: 1008
TitleTAG: Sorry but could use help
I only figured out 1B.
I don't even understand 1A. The mean is 66in, and over 6ft is over 72in but how do we know the range? How do you determine the low and high height approximations?
Also for 1D, I thought 90th percentile has a z value of -1.28
Do you not take the z-value times SD plus the mean (same as practice problem 1)? What am I missing here?
Thanks
UserIdTAG: 1298867
UserNameTAG: cuppycakerz
CreateTimeTAG: 2013-03-11T02:35:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: https://www.edx.org/honor
It would be rude to post an explanation on the forums before the deadline of the course. Best thing to do in these cases is to see if you can organise some kind of study group, so if you wish to discuss the results earlier, you can email/skype/whatevs your crew to team up on the questions without diluting the educational value of the course for the other students.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T03:00:24Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm not going to give you the answer but I will help you along. Remember from the previous lectures that the mean in standard units is 0. Or, if you want to think of it visually, the mean is where the red line is in the picture below.
![Normal][1]
So, problem 1A is asking what percent of the adults are over 6 feet tall. Well, let's take what we do know. We know that the information given to us in the question tells us that the median (where the red line is drawn) is at 66 inches. It also tells us that 2.5 inches is one SD (standard deviation) away.
Next, let's ask how tall, in feet, a 66-inch person is. As is also given to us, 12 inches is equal to 1 foot. So, 66 / 12 = 5.5. Be careful to note that this is read as "five and a half feet" **NOT** "five feet, five inches." In other words, the red line is drawn at the five foot, six inch mark.
Since we know, based on the information given to us in the problem, that 1 standard deviation is 2.5 inches, we know that the mark at z = 1 is 2.5 inches greater than the median. So, if we slide over to the orange line in the below picture, we know that the heights between 0 and 1 comprise a range of between 66 inches and 66 + 2.5 inches (68.5 inches).
![Normal + 1 SD][2]
So, with this in mind, we know that + 2 SD's is going to be 66 + (2.5 * 2) and 3 SD's is going to be 66 + (2.5 * 3) and so on and so forth.
So, how many SD's is 6 feet? Perhaps I should rephrase and ask how many inches comprise a 6 foot individual? Then, since the question asks what percent of people are above six feet, we know that we can "shade in" the entire area to the right of the 6 foot mark. And, since we have [access to that handy, dandy applet,][3] all we have to do is shade in the area to the right of the "6 foot mark" and it'll auto-magically give us the percentage.
And, then, you're done.
Good luck!
[1]: https://edxuploads.s3.amazonaws.com/13629746421343646.gif
[2]: https://edxuploads.s3.amazonaws.com/13629749931343671.gif
[3]: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 87103
FirstChildUserNameTAG: fjbasile
FirstChildCreateTimeTAG: 2013-03-11T04:23:18Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you for the fantastic explanation!! bravo.
SecondChildUserIdTAG: 982787
SecondChildUserNameTAG: annettedonnelly
SecondChildCreateTimeTAG: 2013-03-11T17:00:19Z
SecondChildVoteTAG: 0
IndexTAG: 1009
TitleTAG: Difficulty finding percentile with applet - need step-by-step instructions for how to adjust lower and upper limits before Midterm
Hi,
I can not figure out how to find the percentile using the applet because I am not sure what to put for the upper and lower limits. Sometimes it is obvious that I will choose -5 or +5, but for other questions, I have no idea where to set the limits.
Can you please point to specific section in notes (I could not find details in lecture - the only example I found shows the applet, but not how to set the upper and lower limits). I have gotten almost all of these percentile questions wrong on the exercise sets and would really appreciate more detailed examples to study before the Midterm.
Thanks!
UserIdTAG: 1059091
UserNameTAG: KJMcKinley
CreateTimeTAG: 2013-03-11T01:10:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I use my taiji habits to go by feel. You get the slider as close as you can manually, then you already know which direction you are supposed to adjust it towards, so just "walk it" some decimal places until you get as close as you can. so lets say I am going for the 12th percentile. I set the lower endpoint at -5 (all the way down), then the closest i was able to get by sliding was 11.95%, which was at -1.177, I then walked up to -1.176, which didn't quite get me there, then at -1.175 BOOM goes the dynamite.
Oddly satisfying.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T01:51:21Z
FirstChildVoteTAG: 1
FirstChildTAG: An alternative for people with graphing calculators, (at a minimum I can say this applies to the TI Inspire CX CAS), there are functions that will do calculations based on the normal curve.
invNorm(area, mu=0, sigma=1)
Type in a decimal percentage for the area under the curve and get the sigma value in return. For instance, area=.5, sigma will =0, since 0 is where the 50% mark is.
normCdf(lowBound, highBound, mu=0, sigma=1)
Type in lowBound and highBound in units of sigma and find out the area of the curve contained by these bounds. For instance, lowBound=-1, highBound=1, area=0.682689.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-11T02:51:40Z
FirstChildVoteTAG: 0
SecondChildTAG: In R you write: qnorm(0.85, mean=170,sd=16) and is very quickly! or you calculate P(X<=A)=0.85 then from calculus. P(Z<=(A-170)/16)=0.85 an then is only calculate the equation (A-170)/16= the value you got with the applet.
SecondChildUserIdTAG: 945953
SecondChildUserNameTAG: Turca
SecondChildCreateTimeTAG: 2013-03-11T14:24:09Z
SecondChildVoteTAG: 0
IndexTAG: 1010
TitleTAG: About the course!
This is a very smart class, I have to do a lot of studying to keep up with you guys.
Good luck!
UserIdTAG: 886662
UserNameTAG: Darrell193
CreateTimeTAG: 2013-03-11T00:59:16Z
VoteTAG: 0
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 1
FirstChildTAG: That's an interesting assumption, and there is certainly people still at 100%, but have we had any information of what the distribution of scores are like.
If you are doing a lot of studying it's quite likely you are ahead of the curve (if you can excuse me using that in its linguistic rather than statistical sense).
Stay strong, friend.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T02:18:42Z
FirstChildVoteTAG: 1
IndexTAG: 1011
TitleTAG: Problem 1 is wrongly stated
There is no linear transformation, which would change the SD but leave the MEAN intact. The book nicely explains the difference between a linear and an affine transformation. The transformation referred to in Problem 1 is actually an affine transformation, though.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-11T00:52:59Z
VoteTAG: 1
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: The text on affine transformations (as well as the professor's lecture) actually states "Some books call this a linear transformation, because it has the equation of a straight line." What book are you using that explains the difference between two things that are apparently the same?
I suppose technically the linear transformation does not leave the mean "intact" as you state it or "unchanged" as stated in the question. The mean is transformed - back into the same number as before....
FirstChildUserIdTAG: 1082561
FirstChildUserNameTAG: Streams
FirstChildCreateTimeTAG: 2013-03-11T15:49:52Z
FirstChildVoteTAG: 1
SecondChildTAG: If you go to SticGui's glossary, *affine* refers you to *transformation* (at http://statistics.berkeley.edu/~stark/SticiGui/Text/gloss.htm#transformation)
which says:
> This is an example of an affine transformation: multiply by something and add something (y = ax + b is the general affine transformation of x; it's the familiar equation of a straight line). **In a linear transformation, you only multiply by something (y = ax)**
*However*, the text (at Affine Transformations) says:
> (Some books call this a linear transformation, because it has the equation of a straight line.)
There's a [+] at that point to open up an explanation of the difference; an affine transformation is linear only if b = 0. (the affine transformation is a * x + b)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-12T02:40:51Z
SecondChildVoteTAG: 0
IndexTAG: 1012
TitleTAG: How to easily find the z values for any percentile of the standard normal distribution
The easiest way is to use an Excel function, the =NORMSINV(0.x) where x is the percentile we are looking for.
For example, for the 70th percentile, we shall write:
=NORMSINV(0.7)
For 15th percentile, we shall write:
=NORMSINV(0.15)
UserIdTAG: 206823
UserNameTAG: Dimitra
CreateTimeTAG: 2013-03-10T23:53:09Z
VoteTAG: 9
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 6
FirstChildTAG: That's a pretty sweet way to be sneaky with the use of obscure Excel functions.
![enter image description here][1]
[1]: http://leanneellington.com/wp-content/uploads/2012/03/youre-awesome.jpg
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T02:10:07Z
FirstChildVoteTAG: 3
SecondChildTAG: :)
SecondChildUserIdTAG: 206823
SecondChildUserNameTAG: Dimitra
SecondChildCreateTimeTAG: 2013-03-11T08:40:18Z
SecondChildVoteTAG: 0
FirstChildTAG: I just posted in another thread about using a graphing calc to do the same thing. Here it is for convenience.
An alternative for people with graphing calculators, (at a minimum I can say this applies to the TI Inspire CX CAS), there are functions that will do calculations based on the normal curve.
invNorm(area, mu=0, sigma=1) Type in a decimal percentage for the area under the curve and get the sigma value in return. For instance, area=.5, sigma will =0, since 0 is where the 50% mark is.
normCdf(lowBound, highBound, mu=0, sigma=1) Type in lowBound and highBound in units of sigma and find out the area of the curve contained by these bounds. For instance, lowBound=-1, highBound=1, area=0.682689.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-11T02:54:00Z
FirstChildVoteTAG: 0
FirstChildTAG: Woah... Now that is awesome!
I'll make a feeble attempt at adding that to the Wiki if it isn't already done. Nice work!
FirstChildUserIdTAG: 87103
FirstChildUserNameTAG: fjbasile
FirstChildCreateTimeTAG: 2013-03-11T04:40:46Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks!
FirstChildUserIdTAG: 160934
FirstChildUserNameTAG: DonnaC
FirstChildCreateTimeTAG: 2013-03-11T11:35:04Z
FirstChildVoteTAG: 0
FirstChildTAG: You can also use a [normal distribution table][1]. For example to find the 63rd percentile, find the closet value in the table (0.6331), read the row to find the first two digits (0.3), read the column to find the last digit (0.04) and combine them to get the Z value (0.3 + 0.04 = 0.34).
[1]: http://www.math.unb.ca/~knight/utility/NormTble.htm
FirstChildUserIdTAG: 1116003
FirstChildUserNameTAG: umeditor
FirstChildCreateTimeTAG: 2013-03-12T15:42:40Z
FirstChildVoteTAG: 1
FirstChildTAG: The problem with using Excel or a calculator that does all the work for you is you may not understand what it is actually *doing.*
I've met people who write beautiful C++ code, but it performs horribly because they didn't know what happened when it was compiled.
Learn what goes on underneath! Use Excel etc to verify your answers, but do it yourself first! (Here in class, I mean - out in the real world, sure; use the tools, but *really understand* what they are doing.)
Just my less-than-humble opinion...
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-13T00:25:37Z
FirstChildVoteTAG: 1
SecondChildTAG: "Use Excel etc to verify your answers" or the calculator!
Exactly my thoughts. Calculate by hand, even if by hand means manually typing in a formula into the spreadsheet, and not using a built in function.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-16T03:27:40Z
SecondChildVoteTAG: 0
IndexTAG: 1013
TitleTAG: I cant see this video
Please put the lectures as slides and video as was done for week one and two on the we wiki part
UserIdTAG: 916875
UserNameTAG: nilufa
CreateTimeTAG: 2013-03-10T23:18:46Z
VoteTAG: 0
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 0
IndexTAG: 1014
TitleTAG: Error Clarification
Hello, I think there's an error in 1:19 of video.
Isn't when cm is converted to inches, it's
cm = 0.393700787 x inches?
or when inches is converted to cm, it's
inches = 2.54 x cm?
Thank you for the clarification.
UserIdTAG: 16973
UserNameTAG: TerrEpic_Dude
CreateTimeTAG: 2013-03-10T23:18:37Z
VoteTAG: 1
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 1
FirstChildTAG: yes that's just wat i noticed
FirstChildUserIdTAG: 704053
FirstChildUserNameTAG: jehadhassan
FirstChildCreateTimeTAG: 2013-03-10T23:38:54Z
FirstChildVoteTAG: 0
IndexTAG: 1015
TitleTAG: HELP can't download lectures for week 4
I use to download from the wiki part....now I can't see YouTube or download video it does not play. Please do what was done for the first few weeks
UserIdTAG: 916875
UserNameTAG: nilufa
CreateTimeTAG: 2013-03-10T23:11:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I meant week 3
FirstChildUserIdTAG: 916875
FirstChildUserNameTAG: nilufa
FirstChildCreateTimeTAG: 2013-03-10T23:15:18Z
FirstChildVoteTAG: 0
IndexTAG: 1016
TitleTAG: i think, that in Quiz6 , problem5 the task isn't correct,
we have -7, -7, -7, 7 7 7 7 7, according to the answer we must have -7 -7 -7 -7 7 7 7 7
UserIdTAG: 1211329
UserNameTAG: Gaini
CreateTimeTAG: 2013-03-10T22:33:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: You are squaring, so sign doesn't matter.
Did you read the Show Answer explanation?:
>Since sign doesn’t matter, the entries all have size 7; no calculation is
needed. If you want to go through the procedure, you’ll get a list of 8 squared
entries, all of which are 49; their average is 49, and its square root is 7.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-10T22:36:39Z
FirstChildVoteTAG: 0
IndexTAG: 1017
TitleTAG: Mid Term - how do we access mid term
I see references to a mid term, but cannot find any information on how and when to access it and how long we will have to complete the mid term. Any additional information on the mid term would be greatly appreciated.
UserIdTAG: 1373530
UserNameTAG: Bmxoldman
CreateTimeTAG: 2013-03-10T21:33:37Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: just to avoid opening another same post,
prof. Adhikari wrote on 6th March that she would "post the midterm syllabus, format, etc shortly". Is it somewhere and I can't find it or is it not available yet?
Thanks,
Antonis
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-10T22:15:21Z
FirstChildVoteTAG: 0
FirstChildTAG: I am reasonably certain that it will be posted here when the decisions become finalized: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
So I check there at regular intervals (though I suspect that if I don't see anything by tomorrow, it will become my homepage to ensure I don't miss it).
Meantime:
http://www.youtube.com/watch?v=ErvgV4P6Fzc
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T02:07:46Z
FirstChildVoteTAG: 1
IndexTAG: 1018
TitleTAG: mid-term
There have been a lot of comments on how the mid-term should be run. But none from the staff. Enough already.
Tell us how long we have, when does it start, how do we access it.
Please.
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-03-10T20:45:05Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You should search the forum. Comments have been made. And it says, Tuesday.
I can see that this is the new drinking game. Cheers!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-10T21:27:12Z
FirstChildVoteTAG: 0
IndexTAG: 1019
TitleTAG: Creating the Curve- Applet to find the percentile when you have Mean & SD
Please advise I know to figure out the percentile when it is 0 from the lecture but confused on how to adjust the mean and sd. Can someone please email me aimstermill51@aol.com
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-03-10T20:32:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you know the average and SD of any dataset approximating a normal curve, you can convert any "z" value on the Standard Normal curve to the corresponding "x" value for your dataset.
If you don't remember how, Lecture 5.2 might refresh your memory ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-10T20:59:06Z
FirstChildVoteTAG: 0
IndexTAG: 1020
TitleTAG: exercise set 8, problem 3
The question asks "what percent of adults are 70 inches tall, to the nearest inch?"
To me, this means from 69 inches to 71 inches. And so I figureed it out to be 9.23%.
Apparently "to the nearest inch" means from 69.5 to 70.5.
I believe this is wrong. "To the nearest inch" means within one inch of the stated value i.e.70. Therefore the computation should be from 69 - 71. Am I wrong? From 69.5 - 70.5 is to the nearest half-inch!
Someone (preferably the prof) please comment.
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-03-10T20:04:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Same problem with my answer.
FirstChildUserIdTAG: 938252
FirstChildUserNameTAG: shashankJain1310
FirstChildCreateTimeTAG: 2013-03-10T20:14:22Z
FirstChildVoteTAG: 1
FirstChildTAG: Prof Philip has already commented about this. Search for the "staff" label in this post:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_8/threads/513a117a1f558227000001e4
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-10T20:15:02Z
FirstChildVoteTAG: 0
FirstChildTAG: I read the prof's comments. I still think he's wrong. Bah!
FirstChildUserIdTAG: 797869
FirstChildUserNameTAG: edoz
FirstChildCreateTimeTAG: 2013-03-10T20:35:25Z
FirstChildVoteTAG: 0
SecondChildTAG: Of course he is wrong! What would the Prof know about statistics?
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-10T21:27:46Z
SecondChildVoteTAG: 0
FirstChildTAG: As an example, the inch nearest to 69.2 inches is 69 inches, not 70. The correct range is the open interval (69.5, 70.5). As we are using a continuous curve as an approximation, you can throw in the endpoints too, which is why you convert 69.5 and 70.5 to standard units.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-10T21:38:16Z
FirstChildVoteTAG: 1
IndexTAG: 1021
TitleTAG: problem uploading
I have completed exercise 7 but cannot upload them. Has anyone got any ideas about what I am doing wrong?I have had no trouble with previous sets.
Ann
UserIdTAG: 1209211
UserNameTAG: Ann3067
CreateTimeTAG: 2013-03-10T19:43:08Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Does the "Save" button work? Maybe the edX server or the network connection has some temporary glitch. Try again later. If it does not work, save your answers (write down in a paper), restart your browser and try again.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-10T20:05:36Z
FirstChildVoteTAG: 0
SecondChildTAG: I'll try that - I don't know if the 'save' button is working. I do know that I cannot alter my answers. Thank you
Ann
SecondChildUserIdTAG: 1209211
SecondChildUserNameTAG: Ann3067
SecondChildCreateTimeTAG: 2013-03-10T21:41:31Z
SecondChildVoteTAG: 0
IndexTAG: 1022
TitleTAG: so mad at myself... always always double check your work
I figured out what the answer to 3b was but had an error when I punched it into my calculator and got the question wrong on my second attempt :-( let this serve as a reminder to always double check your work.
UserIdTAG: 70894
UserNameTAG: dantegl36
CreateTimeTAG: 2013-03-10T19:42:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: Same here
FirstChildUserIdTAG: 898107
FirstChildUserNameTAG: navgir
FirstChildCreateTimeTAG: 2013-03-10T22:22:36Z
FirstChildVoteTAG: 0
FirstChildTAG: I feel really bad about the way I answered 3B because it betrays me as being a better researcher than a mathematician. I worked out the answer for 3A correctly, but my initial hypothesis for 3B was incorrect. So in reviewing what element of my methodology brought about the error, I examined all the information available to me, including the Show Answer for 3A, which gave away the answer for 3B :-/
Am I a bad person?
but yeah, lots of pitfalls. I started the course by having disposable documents where I jotted down my calculations. I am starting to save them now, both to allow to double check, and to review for future exercises.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T01:40:31Z
FirstChildVoteTAG: 0
FirstChildTAG: You know, I found that I learn more from mistakes then from getting things right all the time.
Dont worry about it, just internalize the "lessons learned" part.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-11T15:20:35Z
FirstChildVoteTAG: 1
IndexTAG: 1023
TitleTAG: Bug in the normal curve applet page
Hello,
I finally found why the applet page does not work. Please tell people responsible for the applet website to follow these directions [1], otherwise the applet simply does not work properly [2].
D3, a Javascript library used for the applets, requires a unicode-capable webpage for its source code to be parsed correctly. The applet webpage does not state any encoding (probably assuming that English means “I don't care about encodings”), therefore the browser can perform a fallback to any local encoding. Apparently D3 authors were of a different opinion…
[1] http://stackoverflow.com/questions/14080401/uncaught-syntaxerror-unexpected-token
[2] https://dl.dropbox.com/u/52886258/bug-screenshot.png
UserIdTAG: 1097026
UserNameTAG: aiS2ru
CreateTimeTAG: 2013-03-10T19:37:45Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I see! So that's why it only happens with a few people then. Localized browsers and their encodings...
While we wait for Prof Stark(or whoever updates the textbook site) to fix the problem, note that if you have problems with the applet, you can "fix" it on your own.
- On Chrome, go to Setting and press *"Show advanced settings..."*. Scroll down to "Web content" and click *"Customize fonts..."*.
The very last option in the dialogue that opens is "Encoding". Change the setting there to "Unicode (UTF-8)" or "Western (ISO-8859-1)".
Click "Done", close the Settings tab, and refresh the applet page. If it still doesn't work, clean your cache.
- On Firefox, go to Options, then the "Content" Tab. Press the *"Advanced"* button in the "Fonts & Colors" section, then, at the bottom of the dialogue is "Fallback Character Encoding". Again, change the setting there to "Unicode (UTF-8)" or "Western (ISO-8859-1)"
Click "OK" twice, then refresh the applet page, cleaning your cache if necessary.
Now the applet should work! You might have problems on other sites written in your local language though - so I'd suggest reverting back to your "Normal" encoding for normal navigation.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-10T20:55:06Z
FirstChildVoteTAG: 7
SecondChildTAG: Also, to run applet you need java (Latest ver.), however, for javascript which is alltogether a different language, you do not require java. For javascript to work properly, you need to use proper encoding ver. It's already been explained above by @klionheart
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T21:49:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank You Klionheart! It finally works on my browser. Thanks once again :)
SecondChildUserIdTAG: 943583
SecondChildUserNameTAG: Dorota23
SecondChildCreateTimeTAG: 2013-03-12T09:38:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I also would like to thank you Klionheart as the applet now works on my Chrome browser!
SecondChildUserIdTAG: 658358
SecondChildUserNameTAG: Philrk
SecondChildCreateTimeTAG: 2013-03-12T09:43:48Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks to aiS2ru too for figuring out what the problem is!
I never would have thought of checking for that :o
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-12T13:11:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Excellent! I followed the hints above and finally the normal curve suddenly appeared! Many-many thanks!
SecondChildUserIdTAG: 1310163
SecondChildUserNameTAG: kaliczp
SecondChildCreateTimeTAG: 2013-03-12T21:04:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanx!you are great!
SecondChildUserIdTAG: 1259481
SecondChildUserNameTAG: MrsFounta
SecondChildCreateTimeTAG: 2013-03-12T22:17:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Where is the applet? Can not find it.
FirstChildUserIdTAG: 942920
FirstChildUserNameTAG: utahsifu
FirstChildCreateTimeTAG: 2013-03-12T23:15:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Here is the link for the applet.
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
SecondChildUserIdTAG: 1192559
SecondChildUserNameTAG: Diegoisc
SecondChildCreateTimeTAG: 2013-03-13T03:52:17Z
SecondChildVoteTAG: 0
FirstChildTAG: oh man!
kudos to both of you guys, aiS2ru and Klionheart
I had given up until I finally saw this post by aiS2ru and the intsructions by Klionheart (do you remember the other post I had opened?)
At last, the problem is fixed for me and it is very important because this week's scatter diagrams also had the same problem.
A big thank you again
Antonis
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-15T17:15:32Z
FirstChildVoteTAG: 0
IndexTAG: 1024
TitleTAG: I already pass this course.
I just got 35% so I pass the course (all my answers so far were correct on first try!)
UserIdTAG: 272376
UserNameTAG: massys
CreateTimeTAG: 2013-03-10T18:37:12Z
VoteTAG: 1
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: good for you
FirstChildUserIdTAG: 70894
FirstChildUserNameTAG: dantegl36
FirstChildCreateTimeTAG: 2013-03-10T19:03:18Z
FirstChildVoteTAG: 0
SecondChildTAG: massys, i would be grateful if you could explain the whole things to me. I messed up completely. Thanks. You can mail me on anousha@1950studio.com. My worst performance so far..
SecondChildUserIdTAG: 1246659
SecondChildUserNameTAG: AnoushaJunggee
SecondChildCreateTimeTAG: 2013-03-10T19:11:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi,
You should tell me what points you don't understand and I'll try to help.
SecondChildUserIdTAG: 272376
SecondChildUserNameTAG: massys
SecondChildCreateTimeTAG: 2013-03-10T20:00:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Congrats
SecondChildUserIdTAG: 413854
SecondChildUserNameTAG: markq
SecondChildCreateTimeTAG: 2013-03-12T22:44:15Z
SecondChildVoteTAG: 0
FirstChildTAG: Good for you! I'm almost there! If only I hadn't gotten 0 on ES 3... I didn't know we were on GMT.
FirstChildUserIdTAG: 484877
FirstChildUserNameTAG: Andre97
FirstChildCreateTimeTAG: 2013-03-13T01:19:21Z
FirstChildVoteTAG: 0
IndexTAG: 1025
TitleTAG: The interquartile range
the answer shows fractions being used in the calculation: 71.75 - 58.25 = 13.5
Wouldn't you want to find the 25th and 75the percentiles first (72 and 59) first and then subtract? Or are we assuming that scores are not limited to integers?
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-03-10T18:20:36Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 8 / Reading and Practice For Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: You need to find out the Z values for getting the percentile and work it out so you may not get integers.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T18:29:17Z
FirstChildVoteTAG: 3
SecondChildTAG: You need to find z score from the curve for 75% and 25% and you set to go. You have mean and SD. Hope this helps ;)
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T21:45:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Please explain how to find the z while calculating percentiles. I'm not able to follow.
SecondChildUserIdTAG: 169509
SecondChildUserNameTAG: rajeevbasapathy
SecondChildCreateTimeTAG: 2013-03-12T13:49:12Z
SecondChildVoteTAG: 0
IndexTAG: 1026
TitleTAG: R code for Exercise Set 4
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/R/ES_4_Solutions/
As always, PLEASE, take this code as tentative and don't resort to it before understanding the subject matter entirely and before completing every exercise by reasoning and thinking, in the splendid spirit of this course.
Still I have a weird feeling that showing code is, in some sense, dangerous, not in itself (there are people, as me, that are eager for practising R and for integrating in their toolbox), but on blind hands and in lazy minds.
So no problem at all from my part if the staff consider that it's better to remove my wiki entries.
[This is the last post on this matter I submit to the forum. See the corresponding wiki page for addenda, if I keep writing]
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-10T18:11:14Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1027
TitleTAG: ES1 P3
b) There are: 270 magenta/green plants, 90 magenta/red plants, 90 red/green plants, 30 red/red plants, and 20 green/green plants. Therefore, 380 out of the 500 plants contain green; this corresponds with graph B.
I think graph D is wright, another anomaly here.
UserIdTAG: 898107
UserNameTAG: navgir
CreateTimeTAG: 2013-03-10T17:47:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You're right. The correct answer is Graph D. But for some reason, when you look at the explanation under the "Show Answers" button, it says that Graph B is correct. I also think this is an error on the website.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-10T19:14:22Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, this is an error in the solution text.
The right graph is Graph D, and if you selected D you were graded correct.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-10T20:28:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I, fortunately, selected the "D" which was right. Thanks
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T21:39:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Sort of. I am not sure if it's actually a mistake, or if both the question and the explanation of the answer are designed to highlight the core lesson from the question.
Graphs B and D are identical except for the label on the Y axis, but because we are classifying the information rather than attempting to infer probabilities from it, D is correct as per the wording of the question.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-11T01:45:07Z
FirstChildVoteTAG: 0
IndexTAG: 1028
TitleTAG: ES1 P2 my all answer were right then why it graded wrong?
Hi Prof. A.A.
I check the solution my all ans were correct then why did graded wrong?
Please look into this matter.
Thnaks a lot for your time
UserIdTAG: 898107
UserNameTAG: navgir
CreateTimeTAG: 2013-03-10T17:44:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You have crossed the deadline for submission (more than a week back) so you will not be graded for these tests(Week one and two) so you will get grades only for week 3 onward if you submit them by 2330 GMT Wednesday(So look for the equivalent time in your place)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T18:00:15Z
FirstChildVoteTAG: 1
SecondChildTAG: I submitted the results on time, Today, I was reviewing my exercise and found that my attempted qus were right.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T18:47:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Do you have green ticks or red Xs next to your answers in the Set?
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-10T20:29:45Z
SecondChildVoteTAG: 0
SecondChildTAG: red Xs
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T21:36:17Z
SecondChildVoteTAG: 0
IndexTAG: 1029
TitleTAG: Point of inflection?
I understand that the professor is saying that we can approximate how big is the SD just by looking at the bell curve: we just find the point of inflection, and there it is. My question is: how can we find the point of inflection just by looking at the curve? I'm not even sure if I understand what is a point of inflection.
BTW, I wanna add that I'm really enjoying this course, which is surprising since I haven't done any serious math since high school :) Cheers, and thanks in advance.
UserIdTAG: 1116038
UserNameTAG: UrosKovac
CreateTimeTAG: 2013-03-10T17:43:30Z
VoteTAG: 1
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 3
FirstChildTAG: If you start at the top of the curve and follow it down one side you will see that the slope increases as you start down the slope, but then stops changing (becoming almost linear)for a bit and then the slope begins to decrease as you head towards the bottom. That short almost linear section where you change from increasing slope to decreasing slope is the point of inflection. It might help to print it out and put a straight edge on it. Hope that helps.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-03-10T17:50:36Z
FirstChildVoteTAG: 3
SecondChildTAG: Thanks for the explanation!
SecondChildUserIdTAG: 99863
SecondChildUserNameTAG: pramode_ce
SecondChildCreateTimeTAG: 2013-03-10T18:25:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Hey, you're right, using a straight edge really helps! Thanks a bunch!
SecondChildUserIdTAG: 1116038
SecondChildUserNameTAG: UrosKovac
SecondChildCreateTimeTAG: 2013-03-10T23:46:53Z
SecondChildVoteTAG: 0
SecondChildTAG: I thought it was always Mu +or- sigma. In other words mean +or- the SD? And this point -1 or +1 was always in the downwardor upward slope area?
SecondChildUserIdTAG: 1115165
SecondChildUserNameTAG: Abbyjohnson
SecondChildCreateTimeTAG: 2013-03-12T18:22:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Think of driving on an S shaped curved road.The point where you would not feel a drag and then thedirection of drag would reverse while going through the turns on the road would be the point of inflection
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T18:13:15Z
FirstChildVoteTAG: 4
FirstChildTAG: To put it a little more technically the point of inflection is where the rate of change moves from positive to negative (or vice versa).
Look at this simple sine wave:
![A simple sinusoid][1]
Going from the peak, as the line moves towards the horizontal axis the slope gets steeper and steeper. As it crosses the axis it starts to get more and more shallow eventually levelling out at the lower peak. The point of inflection is as it crosses the horizontal axis. Although it may not be very clear to the eye, as the shape is symmetrical you can guess that it will be half way.
To make it a little clearer, here's the same curve with some approximate slopes added (just drawn by eye):
![sinusoid with marked tangents][2]
And doing the same for a bell curve:
![Bell curve illustrating point of inflection][3]
The arrow marks roughly the point of inflection.
[1]: https://edxuploads.s3.amazonaws.com/13629441651343673.jpg
[2]: https://edxuploads.s3.amazonaws.com/13629449901343619.jpg
[3]: https://edxuploads.s3.amazonaws.com/13629452911343648.jpg
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-10T19:56:13Z
FirstChildVoteTAG: 2
IndexTAG: 1030
TitleTAG: I think, I should drop by now
Unable to devote some time due to my shift work (12h, 7/7 D/N cycle)and also projection is that I'll only make 28%. However, it is a good learning experience. this whole credit goes to Professor Ani Adhikari and Professor P. Stark. I will say thank you very much. I'll keep going with course however will not attempt any exam online but do so on my notebook.
Cheers and Good Luck to fellow students.
UserIdTAG: 898107
UserNameTAG: navgir
CreateTimeTAG: 2013-03-10T17:23:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: I feel you. It's a tough course if you are starting from scratch with stats AND having to hold down a job, family etc...good luck next time :)
Blessings
FirstChildUserIdTAG: 1265802
FirstChildUserNameTAG: GMORRIS010
FirstChildCreateTimeTAG: 2013-03-10T19:09:48Z
FirstChildVoteTAG: 0
FirstChildTAG: If by 'projection' you mean the number on the progress chart, that's not a projection but an actual record of your current position. If you are showing 28% now then it only requires a further 7% from all the remaining exercises and exams to reach the pass mark.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-10T19:59:19Z
FirstChildVoteTAG: 3
SecondChildTAG: so you mean, I need another 7% from rest of the course.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T21:35:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Correct.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-10T22:33:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for clarification, then I should take a chance, even 30 to 45 mins can get me through which is not a bad deal.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T22:46:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, if you can get even a little time for the class. If nothing else, it'll make next time easier.
Who cares if you pass or not? Sure, it's better, and I've got my 6.00x certificate on the wall, but you're only out the time you give it. If you were paying money for the class I'd say differently, but here? Do what you can, learn what you will, and take the class again. No worries!
(and if I only squeaked by and passed, I'd consider taking the class again and learning what I missed the first time)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-13T00:30:24Z
SecondChildVoteTAG: 0
IndexTAG: 1031
TitleTAG: Ghada Radwan
Dear Instructors,
in the problem 2 b: it says in the queations ..% above 65 years not not equal to or above 65. so I calculated the number of years as 9 instead of 10 so 9* 0.83= 7.47 ..this plus 6% in the subsequent interval gives 13.5 that I used as an answer.
would you please calify if my answer is considered right or not??
thanks
UserIdTAG: 749490
UserNameTAG: ghadanasr
CreateTimeTAG: 2013-03-10T17:00:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Click in the "Show Answer" button for that question and you'll get the instructor's explanation.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-10T20:23:51Z
FirstChildVoteTAG: 0
SecondChildTAG: I did but I am still have the issue of concern I mentioned above?? would you please clarify?
Thanks,
SecondChildUserIdTAG: 749490
SecondChildUserNameTAG: ghadanasr
SecondChildCreateTimeTAG: 2013-03-11T17:54:05Z
SecondChildVoteTAG: 0
SecondChildTAG: I did this too and would also like an explanation :)
SecondChildUserIdTAG: 833174
SecondChildUserNameTAG: MES93
SecondChildCreateTimeTAG: 2013-03-12T03:11:13Z
SecondChildVoteTAG: 0
SecondChildTAG: For instance the age 65 years and 1 day is between 65- 66. The interval should start from 65-75 to give you 10 not 9
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-13T00:24:28Z
SecondChildVoteTAG: 0
IndexTAG: 1032
TitleTAG: Help Problem 1B
Hello everyone,
I'm a little confused about the meaning of the question "what percent of the adults have heights that are within 1 inch of the average ?". Is that mean the percent within mean + 1 and mean -1 ?
UserIdTAG: 773907
UserNameTAG: Redouanekh
CreateTimeTAG: 2013-03-10T16:17:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: Kind of, yes. Watch out for another part to this.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-10T16:39:15Z
FirstChildVoteTAG: 0
SecondChildTAG: thats right. I solved it right and after listening to other I attempted wrong.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T17:18:44Z
SecondChildVoteTAG: 0
SecondChildTAG: within i inch of average means mean+1 and mean-1 which is from -.4 to .4 in standard units
SecondChildUserIdTAG: 755737
SecondChildUserNameTAG: mtaimoor
SecondChildCreateTimeTAG: 2013-03-11T04:30:26Z
SecondChildVoteTAG: 0
SecondChildTAG: @mtaimoor - close. Logically it would be from -.5 to +.4. If you are rounding to one decimal, -.5 to +.5 (the asymptote would lie at +.499999999999999)
Using +.4 or .5 both result in correct answers FYI.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-11T15:24:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I am sorry to argue with everyone here, but within 1 inch of the average means you have half an inch up and half an inch down. If you want to go for an inch both sides, you should have said for two inches.
SecondChildUserIdTAG: 1245724
SecondChildUserNameTAG: Useralgarcia
SecondChildCreateTimeTAG: 2013-03-13T03:56:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, convert the divergence from the mean to standard units and enter into the applet
FirstChildUserIdTAG: 433872
FirstChildUserNameTAG: dfburke
FirstChildCreateTimeTAG: 2013-03-10T18:47:39Z
FirstChildVoteTAG: 1
SecondChildTAG: Problem solved, thank you all !
SecondChildUserIdTAG: 773907
SecondChildUserNameTAG: Redouanekh
SecondChildCreateTimeTAG: 2013-03-10T20:07:44Z
SecondChildVoteTAG: 0
SecondChildTAG: I found this Ex. 8 to be the easiest. Quite a break from Ex. 7. Thanks Staff.
SecondChildUserIdTAG: 722050
SecondChildUserNameTAG: aswanifj
SecondChildCreateTimeTAG: 2013-03-11T18:48:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Where can I use the applet? Thanks for the help.
SecondChildUserIdTAG: 1370679
SecondChildUserNameTAG: voyager18
SecondChildCreateTimeTAG: 2013-03-12T05:21:51Z
SecondChildVoteTAG: 0
SecondChildTAG: I found Exercise Set 8 easier, also - except for 1B which I initially did wrong (like many others...)
And now I'm at 37% so I can skip everything else and go play video games...
(I'm kidding, I'm *kidding*!!)
(I'm having a great time here - I must be nuts 'cause this stuff is *fun*! I'm getting things wrong sometimes, but as long as afterwards I understand what I did wrong and how to do it right, I'm fine with making mistakes.)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-13T00:37:06Z
SecondChildVoteTAG: 0
IndexTAG: 1033
TitleTAG: Error in solution set for exercise set 6?
Going through Exercise set 6 (was on a business trip last week and forgot), have a question about problem 3. Shouldn't the answer be:
"The SD of List A might be equal to, or greater than, or less than the SD of List B; there is not enough information to decide."
Because if List A has all 25 #'s equal to 100, then the SD of List A = 0 and the SD of List B = 0 as well?
Granted then answer isn't perfect, because well, SD(List A) >= SD(List B) (in the non-pathological case SD(List A) > SD(List B)), but that option isn't given.
UserIdTAG: 981569
UserNameTAG: hubertchao
CreateTimeTAG: 2013-03-10T16:06:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The key is there are "different" terms as per the definitions of the list A
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T16:09:43Z
FirstChildVoteTAG: 0
FirstChildTAG: > Because if List A has all 25 #'s equal to 100,
But that is not what the question allows. You need to read questions carefully.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-10T20:19:28Z
FirstChildVoteTAG: 0
IndexTAG: 1034
TitleTAG: Problem 4 - correct answer marked wrong
Hi. I've posted this on another "Problem 4" thread. I submitted the right answer (the % of the mothers above avg was greater 50%) and I got the red cross. Can someone from the staff please check and correct this so I can get my 2 points?
Thanks alot :)
UserIdTAG: 1216723
UserNameTAG: Darkennoia
CreateTimeTAG: 2013-03-10T16:01:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Which exercise are you referring to.You have posted this in Exercise 1 Exercise set1
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T16:08:54Z
FirstChildVoteTAG: 0
FirstChildTAG: He means Exercise 5. Don't know why people have so much trouble posting in the correct forum.
>I submitted the right answer (the % of the mothers above avg was greater 50%) and I got the red cross.
What makes you think that was the correct answer?
Show Answer tells you:
>50% of the ages are greater than 26, so less than 50% are greater than 27.23. The assumption of uniformity is important because it ensures that the percent in the range 26 to 27.23 is not 0.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-10T21:37:11Z
FirstChildVoteTAG: 0
IndexTAG: 1035
TitleTAG: mistake in the answer of question 8
actually ,it is coming to be 3133.33 instead of 3133.34
UserIdTAG: 1033884
UserNameTAG: vaishalivashisht
CreateTimeTAG: 2013-03-10T15:39:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: No, it's .34 (if you read the instructions, that is).
That ES is already closed for submission, btw.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-10T16:41:50Z
FirstChildVoteTAG: 0
SecondChildTAG: Doing the calculation that's in the solution, it *is* actually .33 and not .34 ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-10T21:03:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Doesn't matter. When the answer is in the thousands, we don't fuss about the second decimal place. We gave students quite a bit of wiggle room on this one. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-10T21:33:52Z
SecondChildVoteTAG: 0
IndexTAG: 1036
TitleTAG: Problem 1C
What does it mean 'to the nearest inch'? Is it a mean value?
Thanks
UserIdTAG: 759395
UserNameTAG: Gen_Art
CreateTimeTAG: 2013-03-10T15:16:52Z
VoteTAG: 14
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: i had the same problem. I computed percent of the value between 69 and 70. I might have guessed that it should be value between 69.5 and 70.5 but it was more difficult for me. maybe my english isn't so good.
FirstChildUserIdTAG: 539890
FirstChildUserNameTAG: Tolek
FirstChildCreateTimeTAG: 2013-03-10T15:53:09Z
FirstChildVoteTAG: 0
SecondChildTAG: The same I thought the value should be beetween 69 and 71 but it's not that so I'm waiting someone too :)
SecondChildUserIdTAG: 1151142
SecondChildUserNameTAG: Mohamed-Salmane
SecondChildCreateTimeTAG: 2013-03-11T02:07:48Z
SecondChildVoteTAG: 0
SecondChildTAG: You were right Tolek thank you very much.
SecondChildUserIdTAG: 1151142
SecondChildUserNameTAG: Mohamed-Salmane
SecondChildCreateTimeTAG: 2013-03-11T02:11:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Nearest inch means that it is at 70 and with a width of one inch(rounding is such that if less than 69.5 it will go to 69 and above 70.5 will go to 71 so it will be between 69.5 and 70.5
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T16:11:06Z
FirstChildVoteTAG: 4
SecondChildTAG: Actually, more technically correct would be 70.4
70.5 is rounded up ;-)
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-10T16:43:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes it should be 70.4
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T17:07:43Z
SecondChildVoteTAG: 0
SecondChildTAG: 70.5 is rounded up but everything infinitesimal below 70.5 (say 70.49999 inches ) is rounded down, and the area(70.5 < height <= 70.5)= 0.0 so i would say the 70.5 of Prasannasimha are ok.
SecondChildUserIdTAG: 1243466
SecondChildUserNameTAG: anoetos
SecondChildCreateTimeTAG: 2013-03-10T17:07:53Z
SecondChildVoteTAG: 0
SecondChildTAG: I stuck to one decimal place !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T17:20:43Z
SecondChildVoteTAG: 0
SecondChildTAG: It will not affect your result either you take 70.47 or 70.5 both yield same results. Hope this help.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-10T17:25:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, both are close enough.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-11T00:54:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you very much!
I'll remember what it means =)
SecondChildUserIdTAG: 759395
SecondChildUserNameTAG: Gen_Art
SecondChildCreateTimeTAG: 2013-03-11T07:13:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks guys, I didn't understand the meaning of "to the nearest inch" my first try was 69 and 71, but thanks to your comments I knew that my guess was wrong and, most important, how to do it.
SecondChildUserIdTAG: 950696
SecondChildUserNameTAG: benava48
SecondChildCreateTimeTAG: 2013-03-11T11:03:34Z
SecondChildVoteTAG: 0
SecondChildTAG: This should be 69 and 71 if for the nearest inch. A bit confusing for the question. I guess I should read first this conversation....
SecondChildUserIdTAG: 1370679
SecondChildUserNameTAG: voyager18
SecondChildCreateTimeTAG: 2013-03-12T05:55:50Z
SecondChildVoteTAG: 0
IndexTAG: 1037
TitleTAG: Please, formal definition of tie breaking on rounding
Hi,
There are multiple ways of rounding from a decimal number to an integer where the fractional part is .5.
- Up, e.g. 23.5 goes to 24, 24.5 goes to 25
- To Even, e.g. 23.5 goes to 24, 24.5 goes to 24
- To Odd
- To zero
etc...
Which one a person uses most often can be culturally biased. My UK undergrad maths (30 years ago) defaulted to rounding to Even.
For avoidance of doubt could the required method please be stated in future?
UserIdTAG: 1735
UserNameTAG: Stewart
CreateTimeTAG: 2013-03-10T15:13:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: Most often one rounds with a schema of rounding 05 to the next integer 9same for the fractional decimals) and <0.5 to the lower(preceding) integer.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T15:18:49Z
FirstChildVoteTAG: 0
SecondChildTAG: It doesn't matter what one does most often. It's what is expected by those who set the questions that matters!
SecondChildUserIdTAG: 1735
SecondChildUserNameTAG: Stewart
SecondChildCreateTimeTAG: 2013-03-11T21:10:13Z
SecondChildVoteTAG: 0
FirstChildTAG: i' ve also learned that .5 goes up and .4 goes down...but normally here in edx you are allowed to write up to 4 decimalplaces
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-10T16:22:48Z
FirstChildVoteTAG: 0
SecondChildTAG: > but normally here in edx you are allowed to write up to 4 decimalplaces
But irrespective of the number of decimal places the question still arises of rounding where the last digit is a five. I'm not sure there is a formal definition but the convention I was learnt (and taught) was that rounding of 5 is always up.
For example:
2.34565 (5 decimal places), would round to 2.3457 (four decimal places, using the 'round up' convention)
2.345674 which would round down to 2.3456
however, I'm aware that there is an alternative convention to round to the even number (this avoids the statistical bias of always rounding up when to be 'fair' you should round up half the time and down half the time). This rule works like this example:
2.34565 would round down to 2.3456 (because the last remaining digit is even)
2.34575 would round up to 2.3458 (to make the last digit even)
The disadvantage of this convention, although more statistically sound, is that it is more difficult to apply. I have to say that I've never seen it used or taught in the UK (but I've little background in stats).
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-10T18:53:16Z
SecondChildVoteTAG: 0
IndexTAG: 1038
TitleTAG: practice for exercise set 7 problem 2
hello,
i am stuck on the mentioned exercise because there is no SD and no mean given. can anybody tell me how i can calculate them from the table or is there maybe another way to solve the problem without them?
i don't want any solutions, just a way to solve this problem on my own.
thanks a lot
UserIdTAG: 1280120
UserNameTAG: Rabia93
CreateTimeTAG: 2013-03-10T14:55:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: use the applet
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1277876
FirstChildUserNameTAG: AmandaMUK
FirstChildCreateTimeTAG: 2013-03-10T14:57:50Z
FirstChildVoteTAG: 0
SecondChildTAG: i'm sorry but i just took a look at that and it still doesnot help me. how can i work without neither SD nor average?
SecondChildUserIdTAG: 1280120
SecondChildUserNameTAG: Rabia93
SecondChildCreateTimeTAG: 2013-03-10T15:08:05Z
SecondChildVoteTAG: 0
FirstChildTAG: I have a pretty good algebra background, so I wrote two equations from the information given in the chart, which formed a system. I then solved the system to get the average and the SD.
(54 - AVG)/SD = 2.8
(42 - AVG)/SD = 0.4
FirstChildUserIdTAG: 144162
FirstChildUserNameTAG: Rena2012
FirstChildCreateTimeTAG: 2013-03-10T15:16:30Z
FirstChildVoteTAG: 0
SecondChildTAG: i tried the same as you did but it did not come to a solution, but as i see that you succeed in it i will try again. maybe there is a calculation mistake in mine.
thanks for your post :D
SecondChildUserIdTAG: 1280120
SecondChildUserNameTAG: Rabia93
SecondChildCreateTimeTAG: 2013-03-10T15:40:08Z
SecondChildVoteTAG: 0
IndexTAG: 1039
TitleTAG: Problem 2 & 3
Gotta agree, these 2 problems were the most difficult. And I could not follow very much the logic, but followed what every body else did. So, overall, i'm feeling quite behind this stuff. Look forward to statistics -1.0 :(
UserIdTAG: 921807
UserNameTAG: hdzmiriam
CreateTimeTAG: 2013-03-10T14:28:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 0
IndexTAG: 1040
TitleTAG: Prof. how to calculate z?
In problem 6, it reads "The 85th percentile is of the standard normal curve is z=1.036 (you can also use 1.037)". The point is i do not understand how to calculate z? thanks
UserIdTAG: 547145
UserNameTAG: Pronectar
CreateTimeTAG: 2013-03-10T14:27:44Z
VoteTAG: 2
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: hello pronectar,
i'm not a prof but maybe i can help you. i don't know which exercise you are exactly referring to but there is the applet we shall use for some exercises and this makes life much easier.
you chose -5 as the lower endpoint and for the other you enter the values that you mention in the post, then the area you have marked is nearly 85 percent..........
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-10T16:29:11Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks.
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-03-11T11:33:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Hello, You can use the applet given in the below link
http://statistics.berkeley.edu/~stark/SticiGui/Text/clt.htm#normal_curve .
You can refer back to the video again where Professor A is showing the usage of the applet multiple times.
FirstChildUserIdTAG: 1214737
FirstChildUserNameTAG: Lipin
FirstChildCreateTimeTAG: 2013-03-10T22:02:44Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks. very helpful
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-03-11T11:34:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Z=(x-M)/sd
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-11T15:25:17Z
FirstChildVoteTAG: 0
IndexTAG: 1041
TitleTAG: Standard normal curve bell shaped
Is the standard normal curve always bell shaped?
UserIdTAG: 1094545
UserNameTAG: Lacilia
CreateTimeTAG: 2013-03-10T13:59:58Z
VoteTAG: 3
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.1: Bell shaped curves; the standard normal curve
NumberOfReplyTAG: 3
FirstChildTAG: Yes !! It is the ideal curve and the equation used describes it.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T14:05:42Z
FirstChildVoteTAG: 0
FirstChildTAG: But doesn't the distribution of the data have to follow the normal curve?
FirstChildUserIdTAG: 1094545
FirstChildUserNameTAG: Lacilia
FirstChildCreateTimeTAG: 2013-03-10T14:47:42Z
FirstChildVoteTAG: 0
SecondChildTAG: It is an ideal curve it is "the curve" and whether other sets of data are normal is a different thing altogether.This "is" normal in distibution by definition.Other datasets may or may not be "normal". It is like all weights are not one KG and the International metric Kg is stored in Paris.All other weights may not be a Kg(quarter Kg or half and so on and so forth but there will be some one Kg weights.But the reference Kg is the "reference" Kg.Same for the "Standard Normal curve". It is the "ideal" curve.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T14:59:23Z
SecondChildVoteTAG: 0
SecondChildTAG: I see..I think understand now!
But let's say we have a distribution that does not follow the normal curve. Then, when we convert our units to standard units, then the curve we'll get for the standard units won't be bell shaped, right?
Thank you very much for your replies!
SecondChildUserIdTAG: 1094545
SecondChildUserNameTAG: Lacilia
SecondChildCreateTimeTAG: 2013-03-10T15:22:55Z
SecondChildVoteTAG: 0
SecondChildTAG: You should not be using a normal approximation for such a curve if it does not do so.There are tests for normality etc etc but I think we will not be dealing with those here.
If youa re interested you can see
http://en.wikipedia.org/wiki/Normality_test
Note that one of the commonest intuitive methods is to draw a histogram and inspect it !!
Hope it helps.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T15:30:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Please also note that the Professor has also given a"back of the envelope" method of testing if it is not normal(though it could still be not normal) ie we can exclude normality if the data is skewed for eg if the 1SD value is zero and there can be no non-negative numbers (for eg price of a house or income cannot be negative and if one SD falls at -200 etc- this distribution is obviously skewed and so cannot be normal.
You actually raised an important point as the normality assumption is a powerful thing and as the Professor told us a lot of distributions are not normal so applying the normality assumption can lead to very wrong answers.This is a situation we very often see in biomedical research and one of the things we do in a pilot study (mini study before a major study) is to check whether our data is following a normal distribution or not so the entire design,selection of tests etc change considerably and this is something a lot of people do not pay attention to. Very often people collect data and then attempt to analyze it and run into problems subsequently.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T15:34:02Z
FirstChildVoteTAG: 3
SecondChildTAG: Thank you very much for your help!!
SecondChildUserIdTAG: 1094545
SecondChildUserNameTAG: Lacilia
SecondChildCreateTimeTAG: 2013-03-11T17:33:16Z
SecondChildVoteTAG: 0
IndexTAG: 1042
TitleTAG: Where I can find the applet?
I dont find the applet, Can you help me?
UserIdTAG: 1197388
UserNameTAG: lbouzas5
CreateTimeTAG: 2013-03-10T13:42:18Z
VoteTAG: 1
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 1
FirstChildTAG: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1277876
FirstChildUserNameTAG: AmandaMUK
FirstChildCreateTimeTAG: 2013-03-10T14:49:51Z
FirstChildVoteTAG: 3
IndexTAG: 1043
TitleTAG: 35% cutoff cleared
I have cleared the 35% cutoff.
So, Do I need to do more exercises and appear in tests.
Will the certificate be different for different scores ?
UserIdTAG: 1259026
UserNameTAG: sahilratra
CreateTimeTAG: 2013-03-10T13:04:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: If you are only thinking of the certificate, you don't need to do anything more, but I'm sure you are willing to learn the whole stuff. In such case, practising and doing the next exercise sets is a must-have.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-10T13:32:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Cool:) no worries
SecondChildUserIdTAG: 1168549
SecondChildUserNameTAG: dave1011
SecondChildCreateTimeTAG: 2013-03-10T14:12:24Z
SecondChildVoteTAG: 0
FirstChildTAG: In a previous edX class I took there was no mention of grade, it was just pass/fail. So congratulations, you've passed! You can relax and enjoy the rest of the class now.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-03-10T17:54:16Z
FirstChildVoteTAG: 0
FirstChildTAG: I suppose it depends why you are taking the course.
If you are just collecting certificates then I suppose you can relax, you've met your target.
If you are intending to make any use of the course contents though, either in education or work then it would surely be wise to keep going, safe in the knowledge that you can complete the graded exercises and exams free of stress. If you are planning to go on to complete Stat2.2x and 2.3x I'd suggest it would probably be unwise to take a break at this point in the course!
Finally, if you are studying just for the enjoyment then the question hardly arises.
Bear in mind that any perceived value in the certificate to employers or educators will from the knowledge you can display rather than the possession of a certificate alone
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-10T19:12:45Z
FirstChildVoteTAG: 1
IndexTAG: 1044
TitleTAG: Which Questions do I have to answer, the Exercice Sets or the Questions in SticiGui Webpages?
Which Questions do I have to answer, the Exercice Sets or the Questions in SticiGui Wewbpages?
After entering the choices in the Exercice Sets, how do I send you the answers ?
Where do I have to click?
Lec 1.1,2.1 and 2.4 cannot be opened when downloaded. Is it due to partial download or they are not yet available?
Please mention the size of the Lecs so that we can tell if they have fully downloaded.
Thanks a lot for helping.
UserIdTAG: 941991
UserNameTAG: oxoxo
CreateTimeTAG: 2013-03-10T13:03:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You do the Stic Gui pages just for additional learning and you are graded wrt the exercises in the courseware.Practice xercises are not included in the grading for your score calculation.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T13:05:29Z
FirstChildVoteTAG: 0
IndexTAG: 1045
TitleTAG: 2B
I got the result right, but I don't think why. I don't understand why the solution said multiply by -1 and the addition of 10 does not affect it. Does anyone understand this explanation? I just assume that lineal transformation was not affected by subtractions.
UserIdTAG: 921807
UserNameTAG: hdzmiriam
CreateTimeTAG: 2013-03-10T13:02:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Concrete discussion can break the HC. The problem 2B can be solved without any arithmetic, only by logic. But a bit of calculation is needed for the 3B (the hardest problem of this Ex. Set) and you need to understand what is the suitable transformation to attack 3B. Think carefully about the Prof. Ani's comments included in other posts about 2B/3B, focus only on them: she repeats the same thing over an over, and the key is right there.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-10T13:45:58Z
FirstChildVoteTAG: 0
IndexTAG: 1046
TitleTAG: I cannot enter any answer to exercise 7 ... ?
I cannot enter any answer to exercise 7 ... ?
UserIdTAG: 176070
UserNameTAG: ahetland
CreateTimeTAG: 2013-03-10T12:33:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1047
TitleTAG: Get Ready!
Friends ,a hectic week is coming.as we have to submit midterm test as well as 3 exercises from 13th March to 20th March.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-10T11:13:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Well, at least that is a different complaint! All other posts about the Midterm seem to be complaining about not having a wide enough window during which to submit (even though timings and details haven't yet been released).
Look on the bright side, if, as seems likely, the exam has a submission window of only one day then you will have the other six days available to focus on the other work. I'm pretty sure that I read somewhere that the exam shouldn't take more than an hour anyway if taken in a single sitting.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-10T19:29:41Z
FirstChildVoteTAG: 0
SecondChildTAG: exam shouldn't take more than an hour anyway
Yes, 45 minutes I believe.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-10T20:18:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I thought I had seen that figure somewhere but couldn't find it amid the mass of identical postings.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-10T22:43:22Z
SecondChildVoteTAG: 0
SecondChildTAG: If only people would realise that mass posting of the same question just makes the answer impossible to find. I saw the Prof's response, but can't find it now. Hidden in the clutter.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-11T00:36:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Found.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/512b014e1f682c2200000146
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-11T01:43:15Z
SecondChildVoteTAG: 0
IndexTAG: 1048
TitleTAG: Midterm exam
for how long would the midterm exam be available ?
UserIdTAG: 1114589
UserNameTAG: Dibaa
CreateTimeTAG: 2013-03-10T08:43:13Z
VoteTAG: 17
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1049
TitleTAG: Problem 3b
Can anybody explain why to multiply by 6 in this problem when each right answer is 5 points?
Thanks
UserIdTAG: 358034
UserNameTAG: Luis57
CreateTimeTAG: 2013-03-10T08:03:47Z
VoteTAG: 11
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 8
FirstChildTAG: I don't know where 6 came from either.
FirstChildUserIdTAG: 1087384
FirstChildUserNameTAG: dadaulili
FirstChildCreateTimeTAG: 2013-03-10T10:34:16Z
FirstChildVoteTAG: 1
FirstChildTAG: It's explained in the answer for Problem 3a
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-10T10:46:22Z
FirstChildVoteTAG: 0
FirstChildTAG: **@Luis57:** Lets go thru the steps:
- Total questions = 10
- Numbers right = 6.2
- 5 points assigned to each right answer. So.
> Total score for right answers = 5 * Numbers Right
- (-1) point awarded for each wrong answer. So,
> Total score for Wrong answers = (-1) * Numbers Wrong
- This can be rewritten as follows (as we do not know Numbers wrong):
> Total score for Wrong answers = (-1)*(Total Questions - Numbers Right)
> Total score for Wrong answers = -Total Questions + Numbers Right
- Now, **Total Score = Total Right Answers + Total Wrong Answers**
- Substituting Values for Total Rights and Wrong, we get the following:
> Total Score = 5 * Numbers Right + (-Total Questions + Numbers Right)
> Total Score = 5 * Numbers Right - Total Questions + 1 * Numbers Right
> Total Score = 6 * Numbers Right - Total Questions
This is over simplification, but if you are faced with MATH challenge, this will help for all future work.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-10T10:58:48Z
FirstChildVoteTAG: 17
SecondChildTAG: genius...
SecondChildUserIdTAG: 1256897
SecondChildUserNameTAG: saketrathi
SecondChildCreateTimeTAG: 2013-03-10T18:13:19Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you for your kindness
SecondChildUserIdTAG: 174
SecondChildUserNameTAG: Sarapong
SecondChildCreateTimeTAG: 2013-03-11T17:44:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Welcome!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-11T18:01:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I did not consider de -1 because I saw it as a substraction and not as a multiplication.
SecondChildUserIdTAG: 1116101
SecondChildUserNameTAG: MEAB
SecondChildCreateTimeTAG: 2013-03-11T21:36:55Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you, math is not my strong suit, yet you make it sound logical as it should be.
G
SecondChildUserIdTAG: 1109502
SecondChildUserNameTAG: GVEF
SecondChildCreateTimeTAG: 2013-03-12T00:20:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Artimehta, you simplified this whole stuff and made it interesting. I was mad at myself after going through your explanation and still got it wrong. Perhaps it will be useful to note that the total score is same as av score. That was where i got it mixed up. All the same thanks for helping.
SecondChildUserIdTAG: 800765
SecondChildUserNameTAG: isaacabah
SecondChildCreateTimeTAG: 2013-03-12T13:44:16Z
SecondChildVoteTAG: 0
SecondChildTAG: U are good in this Artimehta
SecondChildUserIdTAG: 915660
SecondChildUserNameTAG: decomrador
SecondChildCreateTimeTAG: 2013-03-12T14:15:22Z
SecondChildVoteTAG: 0
SecondChildTAG: What? huh?
> ...(as we do not know Numbers wrong) ...
But we can calculate the Numbers wrong; it's 10-6.2 so it's 3.8. I know this is wrong because I end up with
> Total Score = 5 * Numbers Right + (-3.8)
> Total Score = 5 * Numbers Right -3.8
So I get
> SD = 5 * Numbers Right
which is incorrect. But *why* is it wrong?
(I also know I'm asking this in several threads - I'm just *really* confused.. :)
And thank you for your explanations!
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-12T20:15:38Z
SecondChildVoteTAG: 0
FirstChildTAG: This is just how the equation calculates.
Score = 5*(number right) - (10 - number right) = 5 number right -10+ number right= 6 number right - 10.
The explanation just omits one step.
FirstChildUserIdTAG: 547145
FirstChildUserNameTAG: Pronectar
FirstChildCreateTimeTAG: 2013-03-10T12:51:58Z
FirstChildVoteTAG: 3
SecondChildTAG: If you want to work out problem 3b, you need to follow the equation. the constant a is 6 in 3a
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-03-10T12:58:22Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm trying to review for the midterm, but I'm having a problem with a question that I got wrong on Exercise 3. It was concerning calculating percentiles from a graph. I used the formula to compute the lower, middle, and upper percentiles with my calculator and on my computer and I got the same answers. The answers, however, were not the same solutions that the problems gave. Please answer. Also, on Exercise 7, the question about percentiles in a normal distribution there is a problem with the formula. Where did you get the average 100.66 to put into that formula?
FirstChildUserIdTAG: 1207381
FirstChildUserNameTAG: Choco777
FirstChildCreateTimeTAG: 2013-03-10T13:00:22Z
FirstChildVoteTAG: 2
SecondChildTAG: **@Choco777**: Here is the step by step workout for later half of your query.
- Using standard applet, find out 60th percentile. Lets call this **z1**.
- From the problem statement we know, the 60th percentile = 110. Lets call this **µ1.**
- We do not know the SD (**σ**) and average (**µ**)
- Let us plug these values in the following equation:
> z1 = (µ1- µ)/σ
> µ1 - µ = z1 * σ
> **µ = µ1 - (z1 * σ)**
- Again, using standard applet, find out 70th percentile. Call this **z2.**
- Also, the problem statement tells us that 70th percentile is 120. Lets call it **µ2**.
- Time to again use the same formula we used above for 60th percentile. And we get the following equation:
> **µ = µ2 - (z2 * σ)**
- Now note the two highlighted formulae. Using simple mathematical principal, we get the following:
> **µ1 - (z1 * σ) = µ12 - (z2 * σ)**
- Resolve this equation to find σ
- Next, plug in the value of σ in either of the above two formulae to get the µ. You will get the value of 100.66.
> **z1** = (**µ1** - µ )/ **σ**. (Hint: We already know values of z1, µ1, and σ by now!)
- Ditto, find out 90th percentile and call it z3.
- We already have µ and σ and have to find µ3.
- Hint: use the Same old formula z3 = (**µ3** - µ )/ σ.
Hope this explains.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-11T10:29:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Please, remember Honour Code. This Set is key to test a lot of things. The benefit of thinking deeply about the problems, though failing to get the right answer, is watered if excessive hints are given.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-10T14:03:01Z
FirstChildVoteTAG: 2
FirstChildTAG: I solved this problem differently, without too much arithmetic (although on third try, which means no points for me).
For the SD of scores (3b) the procedure is the same as for the average score (3a), you just have to remember to use the ABSOLUTE value when you multiply. The sign is not an issue for SD, you are just looking at distances. Remember from the lecture: SD of new list = |a| * (SD of old list).
I hope this is not too revealing.
FirstChildUserIdTAG: 1116038
FirstChildUserNameTAG: UrosKovac
FirstChildCreateTimeTAG: 2013-03-11T01:07:06Z
FirstChildVoteTAG: 5
FirstChildTAG: I thought we're being evaluated in statistics but not in algebra
FirstChildUserIdTAG: 789101
FirstChildUserNameTAG: Posoneto
FirstChildCreateTimeTAG: 2013-03-12T04:11:30Z
FirstChildVoteTAG: 0
SecondChildTAG: The concept and logic comes from statistics. Algebra is just a tool used to solve the statistical problem. Change the perspective of looking at it and things would appear OK.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-12T04:24:13Z
SecondChildVoteTAG: 0
IndexTAG: 1050
TitleTAG: Lecture 5.1 Practice Normal Curve Applet
Hi, I have finished the lecture material for 5.1 & 5.2 and then tried to do the suggested practical exercises. When I click on the links for the normal curve applet, both do not show the image depicted in the lecture video. I am running on Chrome. Anyone else having this issue? What is a solution?
UserIdTAG: 1295447
UserNameTAG: JESKE1953
CreateTimeTAG: 2013-03-10T07:08:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Clear the cache.Enable Javascript(Not Java)If it doesn't work try Firefox
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T09:32:08Z
FirstChildVoteTAG: 0
SecondChildTAG: I had the same problem. I cannot run any of the applets
SecondChildUserIdTAG: 900106
SecondChildUserNameTAG: Cory65
SecondChildCreateTimeTAG: 2013-03-10T10:42:48Z
SecondChildVoteTAG: 0
IndexTAG: 1051
TitleTAG: Chebychev's vs Markhov's
At the end of the lecture, the prof mentioned that the Chebychev's bound is a lot sharper then the Markhov's bound. This is not always the case
Lets say, we have 4 numbers in our data
{0 0 0 80}
AVG = 20
STD = 34.64(approx)
80 from 20 is about mean + 1.73 Std Dev.
According to Chebychev's bound, the bound says it is no more than 33%, while Markov said its no more than 25%.
Therefore, the teacher didn't always win, the size of the standard deviation plays a role here too.
Is my understanding correct?
UserIdTAG: 1187573
UserNameTAG: irongreatwall
CreateTimeTAG: 2013-03-10T06:41:36Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: With your example, I found SD = 18.16.
This means that 80 is mean + 3.3 STD, which leads to Chebychev's bound being 9.1%.
FirstChildUserIdTAG: 1057358
FirstChildUserNameTAG: s_zambelli
FirstChildCreateTimeTAG: 2013-03-10T13:54:21Z
FirstChildVoteTAG: 0
SecondChildTAG: I think you have made a mistake
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T18:33:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Hm... Interesting
Let me show you my work
The distance away from the average is
80-20=60
0-20=-20
0-20=-20
0-20=-20
Square them you get
3600
400
400
400
The average of the square is
(3600+400+400+400)/4 = 1200
Square root of the mean of the square is Sqr(1200) which is 34.64102, which is the std dev
Can you please show me your work?
thanks and regards
SecondChildUserIdTAG: 1187573
SecondChildUserNameTAG: irongreatwall
SecondChildCreateTimeTAG: 2013-03-10T23:22:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I did make a mistake, I didn't count the deviations of the "zero" entries. I keep making this kind of small mistake, but I learn from them. Thanks for taking the time to go through the calculation step by step!
Even though I thought your counter-example gave a different result, I did agree that examples could be found where Chebychev's bound is bigger that Markov's. You would just need a small enough mean and a big enough SD.
SecondChildUserIdTAG: 1057358
SecondChildUserNameTAG: s_zambelli
SecondChildCreateTimeTAG: 2013-03-11T07:25:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Chebychev is more accurate than Markov on this example.
If we didnt had the dataset, Chevychev is telling us that the chance of having a number greater than 80 is no more than 33% against Markov saing that it's 25%.
Iron, the calculation you did is correct. mine is the same as yours.
FirstChildUserIdTAG: 1153259
FirstChildUserNameTAG: Thiago_NascimentoBR
FirstChildCreateTimeTAG: 2013-03-11T00:27:46Z
FirstChildVoteTAG: 0
IndexTAG: 1052
TitleTAG: interquartile range
How do introduce the intercuartile range? The limits of the range are two number...
how introduce two number in one only answers?
or the question is other?
i need some help :)
UserIdTAG: 1250949
UserNameTAG: barcay
CreateTimeTAG: 2013-03-10T05:12:34Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 8 / Reading and Practice For Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: The range is the difference and not the two numbers.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T06:06:50Z
FirstChildVoteTAG: 0
SecondChildTAG: yes
was a mental lapse
thanks
SecondChildUserIdTAG: 1250949
SecondChildUserNameTAG: barcay
SecondChildCreateTimeTAG: 2013-03-10T14:20:36Z
SecondChildVoteTAG: 0
IndexTAG: 1053
TitleTAG: prob 2b
could someone please help me with this question. i am completely at a loss. i have no idea how to solve this one.
UserIdTAG: 1299545
UserNameTAG: Rohankhalid95
CreateTimeTAG: 2013-03-10T03:57:48Z
VoteTAG: 15
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: indeed. i have tried everything and its like is 7.6/2=3.8 so is 2 the new sd??
i have watched the section 4 continued lecture this week which is 20 minutes long 3 times and took notes and i watched the rest of all the lectures and i read the online textbook and no i still do not understand how to solve it. i wont even mention 3b. the lectures this week were very badly organized compared to all the previous lectures and we did not get nearly enough examples even in the online textbook for the type of totally random questions like 2b and 3b asked this week in the homework i think. an example in addition to the extremely generic degree conversion example in the lecture itself would have been helpful.
FirstChildUserIdTAG: 985560
FirstChildUserNameTAG: zoe3456
FirstChildCreateTimeTAG: 2013-03-10T08:49:30Z
FirstChildVoteTAG: 0
SecondChildTAG: Remembers the types of affine transformations and how it affects MU and SD
SecondChildUserIdTAG: 598623
SecondChildUserNameTAG: dkv
SecondChildCreateTimeTAG: 2013-03-10T11:46:17Z
SecondChildVoteTAG: 0
SecondChildTAG: remember these points and follow them strictly:
1.SD cannot be negative,
2.even if the average changes as long as the histogram is an exact opposite of what is given then sprea might not vary
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-03-10T13:52:31Z
SecondChildVoteTAG: 0
FirstChildTAG: Think this way:
1. Total number of Questions are 10
2. Average right answers = 6.2
3. So average wrong answers = ?
4. If you had to get this average wrong answers using Linear transformation, what would you multiply 6.2 with (a)? And then what would you add to it (b)?
> (Hint: Average Wrong Answers = (a)*6.2 + (b)
5. Similarly, if you have to derive SD for wrong answers, given the SD for right answers, we use another Linear Transformation rule for SD that says
> SD for Wrong answers = |a|* SD of Right Answers.
There you have your answer.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-10T10:16:01Z
FirstChildVoteTAG: 8
SecondChildTAG: Hi, Arti, glad to see you here! I owe you an email :) but I'm waiting for having time. 'Busy' is a light word to describe my actual circumstances. What about the AI course?
This Stat2x is great!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T13:58:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi atopos! The feeling is mutual...am so glad to find you here!
You know what, while we all did great in 207x, this course explained some basic asthmatics, which if known earlier would have made life so much easier, as I had no stats or math background. Am very happy that I joined this course.
I did not join AI course as I am not skilled enough to go for it.
I am still awaiting your mail!!!!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-11T09:40:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Please read asthamatics = arithmetic :):):)
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-11T10:48:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Impossible! Without at least a good "aptitude for mathematics" you never could have gotten the 6.00x certificate ;-)
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-11T23:30:31Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree I have a good aptitude and I am also a fast learner, but I am not so good at math (in fact I have forgotten it)!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-12T04:26:33Z
SecondChildVoteTAG: 0
IndexTAG: 1054
TitleTAG: Week 3
Up until Week 2, there was a clear connection between the lectures, the textbook, and the exercises. That is completely gone this week. There is no rhyme or reason to anything. One lecture tells you to apply a constant before adding on a b for an affine transformation; another takes the sequence of steps into account. We deal with pi and e one moment and then disregard them the next. I am thoroughly disgusted with this course. The teaching is horrible.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-10T03:26:46Z
VoteTAG: 3
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: > I am thoroughly disgusted with this course. The teaching is horrible.
Maybe it is not the teaching, but the receiver that is the problem?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-10T03:42:16Z
FirstChildVoteTAG: 1
SecondChildTAG: Broken antenna?
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-10T16:29:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Huh ? whee are you taking pi and e and then disregardiing them.Specific examples please instead of wild accusations.Also affine transformations have some rules and reasons. I think you are jumbling up things instead of trying to learn the process and landing into grief and taking it on the course !!
If you do not understand ask in the discussion forum instead of having outbursts.With that - at least there is an opportunity to learn or else you will be the loser !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T06:14:25Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm not at disgust, but i'm losing the flow at times
FirstChildUserIdTAG: 169509
FirstChildUserNameTAG: rajeevbasapathy
FirstChildCreateTimeTAG: 2013-03-11T14:34:48Z
FirstChildVoteTAG: 1
IndexTAG: 1055
TitleTAG: Can't find Lectures 1.1, 1.2, and 1.3
I have joined late and realize I won't get graded for the first 2 weeks of homework. However, I am trying to catch up in time for week 3 and the midterm and am unable to locate the video links for lectures 1.1, 1.2, and 1.3 in the Courseware section. Am I missing something? Thank you.
UserIdTAG: 1394646
UserNameTAG: DevorahKat
CreateTimeTAG: 2013-03-10T03:24:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Same here, but I don't care about the grade. Since I'm never going to do anything ontime. I'm using this to supplement a course I'm currently taking. Unfortunately for me, I need 2.2 and 2.3x too.
FirstChildUserIdTAG: 1394759
FirstChildUserNameTAG: TonyStarkPE
FirstChildCreateTimeTAG: 2013-03-10T03:29:45Z
FirstChildVoteTAG: 0
FirstChildTAG: Oh my, I should have explored how to use the site in a little more detail before making my post. However, I'm glad to know there are other students who couldn't initially find the lecture links.
To TonyStarkPE...after viewing the Introduction video for Week 1, at the bottom of the page are unlabeled 'back' and 'next' arrow buttons. Click on the 'next' button to get to the next lecture. Best of luck with the course!
FirstChildUserIdTAG: 1394646
FirstChildUserNameTAG: DevorahKat
FirstChildCreateTimeTAG: 2013-03-10T03:37:38Z
FirstChildVoteTAG: 0
FirstChildTAG: This may help as all of the inital lectures are at one site.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/lecture-summary/
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T06:15:39Z
FirstChildVoteTAG: 0
IndexTAG: 1056
TitleTAG: Can we get the midterm asap please
Is is possible to get the midterm questions please. It seems like many have completed the exercises and awaiting for same. It will also give a longer time to complete it.
Thank you
UserIdTAG: 1181314
UserNameTAG: SolomonT
CreateTimeTAG: 2013-03-10T01:47:32Z
VoteTAG: 8
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: Dear Madam Professor Doctor,
As I need travelling to Dubai for business, it will be very useful if the mid term could be made available by tomorrow. I am tense as to whether I would miss out on attempting the mid term exam.
Thanks and Regards,
Partha
FirstChildUserIdTAG: 359166
FirstChildUserNameTAG: PARTHA6369
FirstChildCreateTimeTAG: 2013-03-10T03:52:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Dear Prof A,
I would also appreciate knowing more about the dates the midterm will be available to work on.
Many thanks,
Aimee
SecondChildUserIdTAG: 1256079
SecondChildUserNameTAG: AimeeGrant
SecondChildCreateTimeTAG: 2013-03-10T10:39:11Z
SecondChildVoteTAG: 0
SecondChildTAG: ........................................
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-10T11:15:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Susan.. you are a sucker for punishment aren't you? first ph207x.. now 2.1.. what IS next? ; ))
SecondChildUserIdTAG: 617920
SecondChildUserNameTAG: CMR
SecondChildCreateTimeTAG: 2013-03-10T15:07:07Z
SecondChildVoteTAG: 0
FirstChildTAG: > Is is possible to get the midterm questions please. It seems like many have completed the exercises and awaiting for same.
I'm sure you will get them. On the 13th.
>It will also give a longer time to complete it.
This isn't a random, open amount of time here! You will only get the time the Prof decides. No more.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-10T21:40:09Z
FirstChildVoteTAG: 1
IndexTAG: 1057
TitleTAG: GRADING PRACTICE EXCERSICES
I WAS WONDERING IF THERE IS A PROBLEM WITH THE SISTEM BECAUSE THE PRACTICE EXERCISE OF WEEK 2 THE SYSTEM DID NOT SAVE MY GRADES EVEN THOUGH I DO SAVE THEM AND DID THE FINAL CHECK. IN WEEK 3 THE PRACTICE EXERCISE PROBLEM 8 HAVE THE SAME PROBLEM....DO I HAVE TO WORRY? OR IT DOES NOT MATTER IF THE PRACTICE EXERCISE DOES NOT HAVE SCORE?
UserIdTAG: 1013229
UserNameTAG: LorenaNava
CreateTimeTAG: 2013-03-10T01:43:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Please do not use all caps.Its netiquette implication is that you are shouting at us.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T02:02:02Z
FirstChildVoteTAG: 2
SecondChildTAG: It's not if she's from a Spanish-speaking country...
SecondChildUserIdTAG: 1157957
SecondChildUserNameTAG: meganbh
SecondChildCreateTimeTAG: 2013-03-10T04:39:32Z
SecondChildVoteTAG: 0
SecondChildTAG: No - this is an English list !! Also I looked it up even in Spanish countirex it is not considered acceptable in formal email comnversations.It is used in the place of specia characters.
I am including an extract from an article
"So why do so many Mexicans write emails to English speakers in ALL CAPS? Well, to start Spanish is a language that uses accents and other special characters (specifically: á, é, Ã, ó, ñ, ú, ü, ¿double question marks? and ¡double exclamation points!). But there are times when people writing in Spanish can’t or don’t wish to use all those special characters and accents, so it is acceptable in casual situations to write in Spanish using ALL CAPS and to skip the accents.
I understand that this practice of writing in ALL CAPS in Spanish is not acceptable in formal situations, as it is not proper Spanish. And not using accents can lead to confusion about meaning. But in casual emails it is common for many Mexicans to write emails in ALL CAPS and skip the special characters."
The point still remains that these emails are not in Spanish so can lead to misinterpretation.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T06:23:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Please see the discussion forum guidelines in the policy document
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T06:28:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Nobody has answered her qn yet. We're ALL being rude.
SecondChildUserIdTAG: 474123
SecondChildUserNameTAG: uniquestar7
SecondChildCreateTimeTAG: 2013-03-10T10:26:54Z
SecondChildVoteTAG: 0
SecondChildTAG: No this is not being rude.I am pointing out that the whole thing in All caps is not readable so one would not read it.Incidentally it has been pointed out that practice scores are not going to be graded.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T11:22:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Please note in the document
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
use of all caps is deprecated.
Those are the rules and we have to stick to it wherever we are from.
Here is an extract of the same
• Use “netiquette,” or common writing practices for online
communication. For example:
o **Avoid TYPING IN ALL CAPS.** Some people read this as
shouting, even if that is not what you mean to convey.
o Avoid unnecessary symbols, abbreviated words, texting
shorthand, and replacing words with numbers (e.g. Pls don’t
rplce wrds w/#s).
o Avoid repeating letters or characters like this:
reeepeeaattingggg chaaracterrrss
o Avoid excessive punctuation if possible (e.g. !!!!!!!!
or ??????)
o It’s fine to make suggestions, but avoid negative
commentary and please do not “flame” anyone
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T06:30:16Z
FirstChildVoteTAG: 0
FirstChildTAG: Practice exercises do not contribute to the final score. They're just for practice before you answer the actual exercise set that is graded. :)
FirstChildUserIdTAG: 474123
FirstChildUserNameTAG: uniquestar7
FirstChildCreateTimeTAG: 2013-03-10T10:28:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks ....
SecondChildUserIdTAG: 1013229
SecondChildUserNameTAG: LorenaNava
SecondChildCreateTimeTAG: 2013-03-11T00:09:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Practice is just that...practice. It doesn't get graded.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-10T16:27:47Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1013229
SecondChildUserNameTAG: LorenaNava
SecondChildCreateTimeTAG: 2013-03-11T00:10:25Z
SecondChildVoteTAG: 0
IndexTAG: 1058
TitleTAG: Reading and Practice for Exercise 2- Stem and Leaf plot Question 1
> 1. Here is a stem and leaf plot of the heights (in centimeters) of a group of men. Computer programs that generate such plots have to
> explain where they chose to place the vertical bar; the one I used
> says, **“The decimal point is 1 digit to the right of the |”**
>
>
> 16 | 56778; 17 | 0012234444; 17 | 55666788889; 18 | 0111234; 18 | 56
What exactly does that mean? For example 18|56 could mean 185.6? Instead of 185, 186. Is this normally how stem and leaf plots are worded? How would you represent decimal data, for example, 3.981, 26.1, -0.25?
UserIdTAG: 838733
UserNameTAG: Ronnicus
CreateTimeTAG: 2013-03-10T00:53:28Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The standard format of stem and leaf plots as given to us before the line is the digits constant to all numbers on the line, and after it is a string of digits, each one individually completes the number. Thus 18|56 is 185, 186
For your example, it isn't really formatted right for a stem and leaf chart, as all numbers need to have the same number of digits after the decimal point, so for 3.981, 26.100, -0.250 you would list it as:
-0.25|0
3.98|1
26.10|0
Doesn't really save you space, stem and leaf plots are really best for data where data spacing is close to the precision of the numbers.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-03-10T04:24:03Z
FirstChildVoteTAG: 1
IndexTAG: 1059
TitleTAG: Let's make friends here
Hey all those who are interested in making new friends along with studying together, can comment here...:-) such great knowledge and friends too...
UserIdTAG: 818577
UserNameTAG: rajarjit
CreateTimeTAG: 2013-03-10T00:29:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I'm in! having a hard time with exercise 7 :(
FirstChildUserIdTAG: 1188300
FirstChildUserNameTAG: cqprivado
FirstChildCreateTimeTAG: 2013-03-11T21:14:00Z
FirstChildVoteTAG: 0
IndexTAG: 1060
TitleTAG: so hard this exercises
I struggled this week my brain. I hope some of the exercises would be clearer next time.
UserIdTAG: 1021459
UserNameTAG: ManolitoWyns
CreateTimeTAG: 2013-03-09T23:59:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: The course will more than likely get tougher as we progress through the material. Future assignments will build on fundamentals learned in the past. If your brain struggled this week then there is a good chance you learned something and will continue it forward. Most true problems in the world are not easy to understand and solve. That basic understanding is translated here as well. Just keep at it and will gain true rewards in the end :-)
FirstChildUserIdTAG: 70894
FirstChildUserNameTAG: dantegl36
FirstChildCreateTimeTAG: 2013-03-10T19:14:41Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too ManolitoWyns... It was a hard week, the hardest once so far. I reviewed the lectures a 2nd time around and things became a bit easier as I understood better. I am so glad I spent extra time to understand, so I learned many new things!
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-03-11T03:16:01Z
FirstChildVoteTAG: 0
IndexTAG: 1061
TitleTAG: Downloading video lectures from earlier weeks
Hi:
I was wondering if anyone had difficulty in downloading videos
from earlier lectures (say the introduction etc.). As of today (3/9/2013)
the link just loads up in my browser as opposed to asking whether to
play it or save it.
Is the downloading time-sensitive?
I am able to download this week's video lectures.
Thanks
-sms
UserIdTAG: 1094947
UserNameTAG: ssharma123
CreateTimeTAG: 2013-03-09T22:31:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No I downloaded allthe lectures yesterday.If notuse a downloader like orbit downloader
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T02:04:51Z
FirstChildVoteTAG: 0
IndexTAG: 1062
TitleTAG: problem 6 part b
I understood my mistake
UserIdTAG: 1235463
UserNameTAG: marychiri
CreateTimeTAG: 2013-03-09T21:53:36Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: @marychiri
> I understood my mistake
- Great. But How does this post help others unless you share what mistake you made such that others also benefit from your learning?
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-10T10:21:06Z
FirstChildVoteTAG: 0
IndexTAG: 1063
TitleTAG: Problem 1C
Approximately what percent of the adults are 70 inches tall, to the nearest inch? Please don't enter the percent sign.
Do not understand the question, does it mean, what percentage are taller than 70 inches?
UserIdTAG: 241217
UserNameTAG: joseperez
CreateTimeTAG: 2013-03-09T21:49:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/525a7e5b2b9d41ccb41b3dd7260dc319/66f372cc235341e1ae7f9779450f1cba/
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-09T23:07:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Nearest inch means that the value would round to 70. 69.6 inches would be 70 to the nearest inch as would 70.2
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-03-10T04:26:42Z
FirstChildVoteTAG: 0
IndexTAG: 1064
TitleTAG: Notation
Hi guys,
in these lectures of distributions, are we talking about the population or the sample (or both) distributions? I assume it is the population because of the notation used (the symbols used for the mean and sd), but I wanted to be sure about it.
Thanks!!
UserIdTAG: 162825
UserNameTAG: Brunak
CreateTimeTAG: 2013-03-09T21:11:54Z
VoteTAG: 0
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 1
FirstChildTAG: We are talking about the standard deviation of the entire population. That is what has been, and will be used for this course. Don't use n-1!
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-09T21:36:39Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you!! That explains a lot!! =)
SecondChildUserIdTAG: 162825
SecondChildUserNameTAG: Brunak
SecondChildCreateTimeTAG: 2013-03-09T21:40:03Z
SecondChildVoteTAG: 0
SecondChildTAG: It was specifically mentioned in the lectures that we will not be using sample standard deviations for this discussion
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T02:06:08Z
SecondChildVoteTAG: 0
IndexTAG: 1065
TitleTAG: problem 6 part b
I think the correct is 157.12 because the valor is -0,805 not -0,524 for 30th percentile
UserIdTAG: 1235463
UserNameTAG: marychiri
CreateTimeTAG: 2013-03-09T20:45:55Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: It's -0.524 on the applet [here][1]. Where did you get -0.805?
[1]: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-09T20:56:10Z
FirstChildVoteTAG: 0
SecondChildTAG: -0.524 only 19.99%?
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-03-10T14:30:19Z
SecondChildVoteTAG: 0
SecondChildTAG: we need to see from the lowest value. Assuming the lower interval at SD -5 will cover the lower data point, now look till what SD you would get 30%. Which means -5 as the lower point till -.524.
Note: don't put level from 0 but from the extreme end.
SecondChildUserIdTAG: 358255
SecondChildUserNameTAG: drnidhi27
SecondChildCreateTimeTAG: 2013-03-13T00:13:21Z
SecondChildVoteTAG: 0
IndexTAG: 1066
TitleTAG: Great course!
I am grateful to Berkeley and other universities for offering these free, graded courses over the internet. They are a real gift. I am not finding this course to be difficult but that is because I am somewhat familiar with the material. I find Prof. A.'s lectures are very clear and well constructed. Anyone who complains that this course is too easy may want to join me in the MIT Physics 8.02x course. You may find it keeps you busy and that Stat 2.1x becomes a cherished chance to relax and enjoy math.
UserIdTAG: 1270753
UserNameTAG: RobLL
CreateTimeTAG: 2013-03-09T20:37:48Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Agreed. Great course, great Prof. And all that for free.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-09T21:55:00Z
FirstChildVoteTAG: 1
FirstChildTAG: No calculus needed, practically no algebra, only thinking and "seeing". Read the Prof. Ani's comment in this thread:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/525a7e5b2b9d41ccb41b3dd7260dc319/820046be290b47a681d544a9a5a200ca/1?discussion_page=2:
> Equations are great; I use them all the time ... :) But I'm a firm
> believer in the Berkeley approach to elementary statistics: you should
> be able to "see it in a picture" if at all possible.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-09T23:53:00Z
FirstChildVoteTAG: 0
FirstChildTAG: AGREED!! I am really enjoying this course! Who would have thought I would be enjoying a statistics course. Not me.
I enjoy how Prof. Ani presents the material.
Looking forward to the next courses, 2.2x and 2.3x!!
FirstChildUserIdTAG: 1346686
FirstChildUserNameTAG: kimbalips
FirstChildCreateTimeTAG: 2013-03-10T22:52:11Z
FirstChildVoteTAG: 1
IndexTAG: 1067
TitleTAG: Do we have to take the mid-term exam on only that day?(Staffs please read)
On the course info the professor implied that the midterm date is 13th. But for me the weekend is the most convenient. Well if it the exam is short it will be possible for me to access the site for the test. So I want to ask:
1.Do we have to take the exam on exactly that day?
2.How many questions does it consist of?
UserIdTAG: 1168549
UserNameTAG: dave1011
CreateTimeTAG: 2013-03-09T17:57:07Z
VoteTAG: 12
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: I have the same question, thanks dave
FirstChildUserIdTAG: 1304893
FirstChildUserNameTAG: MichelleOrozcoBrenesTEC
FirstChildCreateTimeTAG: 2013-03-09T18:54:49Z
FirstChildVoteTAG: 2
SecondChildTAG: same question
SecondChildUserIdTAG: 177042
SecondChildUserNameTAG: CofCof
SecondChildCreateTimeTAG: 2013-03-09T19:09:45Z
SecondChildVoteTAG: 0
FirstChildTAG: And as is written on the Course Info page, more details soon. Multiple posts won't make it happen faster.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T21:51:10Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you SusanAust. Now, we all know your opinion; we all know you are better than most of us in reading course descriptions. However the dude dates for the exercises were changed. I don't see why the midterm date cannot be changed.
SecondChildUserIdTAG: 127549
SecondChildUserNameTAG: ochavoya
SecondChildCreateTimeTAG: 2013-03-09T22:40:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Well you will just have to wait and see! Dude. The Prof has commented on this (try searching the forum) several times, and it's not as if the date is a surprise. It's been listed since Day 1.
Maybe it will change. But the constant whining, poor me posts don't help. 47000+ people. Of course some are going to be disadvantaged.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-09T22:48:00Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem is that some of us are workers and have little or no time to take the exam if it's scheduled on a working day. SusanAus, if "whining" does not work, what would you suggest these people should do? :)
SecondChildUserIdTAG: 1145082
SecondChildUserNameTAG: Arabert
SecondChildCreateTimeTAG: 2013-03-10T10:30:06Z
SecondChildVoteTAG: 0
SecondChildTAG: > The problem is that some of us are workers and have little or no time to take the exam if it's scheduled on a working day.
*You* have chosen to do an online course. Deal with it. If times don't work for you, then accept it. With 47,000 people, individual circumstances can't be catered to. For this course you need a whole *35%* to get the coveted certificate. As grades aren't on the certificate, egos should cope.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-10T12:17:01Z
SecondChildVoteTAG: 0
SecondChildTAG: It's not a matter of ego but one of willing to do things properly. FYI, online courses were conceived of to be MORE flexible than regular ones. I'm sure speaking one's mind (which unfortunately you interpret as "whinging") will help improve EdX courses in the future.
SecondChildUserIdTAG: 1145082
SecondChildUserNameTAG: Arabert
SecondChildCreateTimeTAG: 2013-03-10T12:46:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Susan, I have to agree with dave and arabert here. Searching the forum, but a link to the posts you mentioned the instructor posted would be nice. On that point at least, I agree with wholeheartedly - multiple posts on the same topic are annoying, and a waste of time!
SecondChildUserIdTAG: 229679
SecondChildUserNameTAG: Ahsen
SecondChildCreateTimeTAG: 2013-03-10T18:12:36Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm afraid that's the case: one working day for the exam (the Midterm and the Final). It's in the Course Info page from the very beginning.
My personal opinion is that exams should be scheduled at weekend (as in other edX courses). But the staff has decided in other direction and changing dates while the course is running can alter the whole schedule and provoke complications.
We knew this and we could have taken (and still we can take) whatever decision. For what I'm concerned, if I can take the exams I'll take them. But I'm realistic, probably I cannot, and, honestly, I don't want to do the exam in my sleeping hours after a long and exhausting working day. So I rely on the Exercise Sets. Consider that the 35% for the certificate is already here (one thing for the other) and that we can do the exam, for the sake of learning, whenever we want after the due date.
Well. I understand you'd like to see a +90% in your sandbox (me too!), but this is ultimately no more than a childish desire. If you learn the material and you get the certificate everything is fine. Not so fine for the course statistics, but surely our expert Profs. are thinking of possible ways to correct outliers ;-)
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-09T22:33:58Z
FirstChildVoteTAG: 2
FirstChildTAG: Reach 35% is a piece of cake, you don't need mid and exam at all.
FirstChildUserIdTAG: 1080570
FirstChildUserNameTAG: MirkoPonzanelli
FirstChildCreateTimeTAG: 2013-03-09T23:23:14Z
FirstChildVoteTAG: 0
SecondChildTAG: I think this is right. I didn't see anything about a minimum passing score on the mid-term or final exams, just a 35% overall for the course.
If anyone knows different, please post a response.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-03-10T06:51:12Z
SecondChildVoteTAG: 0
SecondChildTAG: My progression total bar is over 35% so I thinnk that I've already passed the course. Even if I have made some miskates due to Enghlish misunderstanding.
SecondChildUserIdTAG: 1080570
SecondChildUserNameTAG: MirkoPonzanelli
SecondChildCreateTimeTAG: 2013-03-10T09:37:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Seeing the requests probably we should have a poll button ability for such issues if nothing but to draw attention to a significant problem that could (if possible) be redressed by the teachers and support staff. For eg the multiple requests made the organizers change the exercise submissions from thrice a week to once a week.So if the requests seem reasonable there should be an avenue to express it with the Teachers obviously having a final say. It would also reduce the load on the discussion forum too (of similar posts)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T16:21:22Z
FirstChildVoteTAG: 1
IndexTAG: 1068
TitleTAG: Error in example?
I was doing the last example by Professor using the applet, and found z=-1.285 for the 40th percentile and not -0.253. Did anyone else get the same answer? Please let me know,I could be wrong. Thank you
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-09T17:54:54Z
VoteTAG: 0
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 1
FirstChildTAG: It is -0.253.Did you check what you're getting as shaded ?I just checked it right now
![Normal curve applet][1]
[1]: https://edxuploads.s3.amazonaws.com/13628531701343606.jpg
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T18:20:20Z
FirstChildVoteTAG: 2
SecondChildTAG: Please try using an upper endpoint of 0(corresponding to mean of 67) and lower endpoint of -1.285 and see what you are getting. Thats what I used
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-09T19:23:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok I know understand where my problem is, thanks a lot Prasannasimha
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-09T19:37:31Z
SecondChildVoteTAG: 0
IndexTAG: 1069
TitleTAG: PROBLEM 1
I dont get this exercise.
If you multiply 10x3 and then you sustract 100, then SD=-70, not 30.
UserIdTAG: 1235646
UserNameTAG: CristinaMorillas
CreateTimeTAG: 2013-03-09T17:48:35Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: sd is never ever negative
FirstChildUserIdTAG: 985560
FirstChildUserNameTAG: zoe3456
FirstChildCreateTimeTAG: 2013-03-09T18:32:40Z
FirstChildVoteTAG: 1
FirstChildTAG: You shouldn't substract 100 from SD...
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-09T18:53:11Z
FirstChildVoteTAG: 0
SecondChildTAG: Use the two transform equations:
new SD = a times old SD, and a*old avg + b= new avg
30=a*10, and
a*50+b=new avg, but a =3 so 3*50 + b = 50 and b=100
SecondChildUserIdTAG: 1059809
SecondChildUserNameTAG: pegean
SecondChildCreateTimeTAG: 2013-03-10T02:00:04Z
SecondChildVoteTAG: 0
SecondChildTAG: opps b = -100
SecondChildUserIdTAG: 1059809
SecondChildUserNameTAG: pegean
SecondChildCreateTimeTAG: 2013-03-10T05:53:40Z
SecondChildVoteTAG: 0
FirstChildTAG: And why would you subtract 100? Did you watch the lectures?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-09T20:58:41Z
FirstChildVoteTAG: 0
IndexTAG: 1070
TitleTAG: YouTube videos on Android Tablet Devices (Link Missing)
I have usually required the download link as the Youtube player will not work in my native Android broswer or in Chrome. It will play however using Firefox for Android browser, hope this helps some people.
UserIdTAG: 1106695
UserNameTAG: robchrispower
CreateTimeTAG: 2013-03-09T17:12:28Z
VoteTAG: 2
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 2
FirstChildTAG: Good to know.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-09T23:58:32Z
FirstChildVoteTAG: 0
FirstChildTAG: You actually can play the videos on native android using youtube player.(They do not play flash videos in Jelly Bean Android but HTML5 videos play fine)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T02:12:27Z
FirstChildVoteTAG: 0
IndexTAG: 1071
TitleTAG: captions over the slide content
Please could you please live a space in blanck in the bottom of the video screen in order for the captions to not overcame the content? Since we can't remove the captions, sometimes its impossible to understand what his under. Thanks.
PS: you are an amazing teacher, explaining the crucial details about the concepts for us to understand. Don't bother with same comments. I'm learning a lot!
UserIdTAG: 122004
UserNameTAG: fqantonio
CreateTimeTAG: 2013-03-09T17:02:51Z
VoteTAG: 0
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 1
FirstChildTAG: If by 'captions' you are referring to the control buttons, the workaround I use is to decrease font size (hold Ctrl and turn the mouse wheel towards yourself) - this results in a really slim strip at the bottom of the video.
FirstChildUserIdTAG: 387767
FirstChildUserNameTAG: JanDE
FirstChildCreateTimeTAG: 2013-03-11T22:11:38Z
FirstChildVoteTAG: 0
IndexTAG: 1072
TitleTAG: Udacity Students ?
So just a quick question ,how does this course ,content wise ,not instructor teaching style format etc ,just the content between them both ,how does it stack up to udacitys into to stats https://www.udacity.com/course/st101 ,I took a look at the sylabus and then at the general outline our prof gave and well from what she said it was
STAT 2.1X: Descriptive Statistics
STAT 2.2X: PROBABILITY
Understanding and quantifying randomness
STAT 2.3X: INFERENCE
Making conclusions based on data from random samples
So im not asking whos better ,I dont want to know or care to start some petty fight ,just do they cover roughly the same content ?
UserIdTAG: 20186
UserNameTAG: vikashx1
CreateTimeTAG: 2013-03-09T16:25:52Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I am also taking Intro to Stats at Udacity. I can say that at Udacity, they choose to teach probability first. I am at the Bayes' Theorem as of right now. And here we learn Descriptive Statistics first. I believe they do. It is just that each instructor has a different way of teaching. This is why I tend to take the same courses with multiple instructors if they are available because I would like to learn the same subject from multiple angles and point of view. I think it would help improve my creativity if that is possible, to be able to see the same thing from many directions.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-09T19:07:54Z
FirstChildVoteTAG: 0
SecondChildTAG: Whoa thats a pretty smart thing to do ,and yeah I think it would definitely help ,its just I have a ton of math and I dont know ,I cant keep up with this classes timetable (why I like udacity is the whole self paced method because some weeks you have no time and others you have all the time in the world )so I dont know if ill stay on for sure here .I really ,I just ,I cant say how awesome edx on the whole is ,so im taking a couple other courses from them ,but those I cant get anywhere else so I think I might keep math on the whole as a self paced subject .And thanks ,thats what I thought too ,I was just hoping that I was right ,thanks again ,Good luck on both courses
SecondChildUserIdTAG: 20186
SecondChildUserNameTAG: vikashx1
SecondChildCreateTimeTAG: 2013-03-10T00:28:36Z
SecondChildVoteTAG: 0
IndexTAG: 1073
TitleTAG: "to" the right of 0.4
I'm confused about the word "to" indicated here. Supposedly, it means from minus infinite to the point of 0.4. However, telling from the answer, it turns to be starting from 0.4 to positive infinite. Why use the word "to" here to interpret the latter case?
UserIdTAG: 695231
UserNameTAG: KarlKao
CreateTimeTAG: 2013-03-09T15:03:57Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: "to the right of #" means "on the right-hand side of"
"to the left .." means "on the left-hand side of"
in this case "to" does not mean "up to" or "up until" as I think you are thinking.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-09T15:12:15Z
FirstChildVoteTAG: 2
FirstChildTAG: To the right means just that, to the right of the number.
$-\infty$ is to the left of 0.4.
So you want the area from: $0.4 \rightarrow \infty$
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T21:58:10Z
FirstChildVoteTAG: 2
IndexTAG: 1074
TitleTAG: my applet
My applet in figure 23-1 of chapter 23 of SticiGui is blank in the box. Can someone help me? eanes@fortalnet.com.br
UserIdTAG: 1007702
UserNameTAG: delgado58
CreateTimeTAG: 2013-03-09T14:21:43Z
VoteTAG: 3
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: 1. If you are using Internet Explorer, **don't**. Switch to either [Google Chrome][1] or [Mozilla Firefox][2].
2. Make sure Javascript is enabled.
- For Chrome, go to Settings-->Contents Settings-->Make sure that "Allow all sites to run JavaScript (recommended)" is checked.
- For Firefox, it's Options-->Content-->Enable Javascript
3. Clean your browser cache.
- On Chrome, History-->Clear all browsing data
- On Firefox, History-->Clear Recent History
[1]: https://www.google.com/intl/en/chrome/browser/
[2]: http://www.getfirefox.com
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-09T14:36:40Z
FirstChildVoteTAG: 2
SecondChildTAG: My applet still doesn't work....therefore can't answer the questions
SecondChildUserIdTAG: 1109472
SecondChildUserNameTAG: SushilKeswani
SecondChildCreateTimeTAG: 2013-03-09T19:05:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I have exactly the same problem. Using Firefox, last version, Javascript is enabled, recent history has been cleaned. Still not working.
SecondChildUserIdTAG: 697078
SecondChildUserNameTAG: mousekrup
SecondChildCreateTimeTAG: 2013-03-09T19:41:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Same problem here.
SecondChildUserIdTAG: 1092175
SecondChildUserNameTAG: Hillmer
SecondChildCreateTimeTAG: 2013-03-10T03:24:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Yep, checked the "Allow all sites.." and now the box has shrunk to a narrow section at the top of the page, and definitely can't read anything, any further advice would be appreciated, yes i'm in GoogleChrome, mark
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-10T05:07:01Z
SecondChildVoteTAG: 0
IndexTAG: 1075
TitleTAG: Transcripts
Is it possible to have transcripts of the video lectures for download. Thank you.
UserIdTAG: 807428
UserNameTAG: Brigitte2012
CreateTimeTAG: 2013-03-09T14:19:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For now, subtitle files are available on the [wiki][1] for Week 1 and 2, thanks to scriba :)
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/subtitle-files/
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-09T14:39:56Z
FirstChildVoteTAG: 0
IndexTAG: 1076
TitleTAG: I feel like I totally missed it this week
This was a tough assignment .... I'll try to do better next time
UserIdTAG: 1202785
UserNameTAG: sjmadden
CreateTimeTAG: 2013-03-09T14:19:02Z
VoteTAG: 4
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 4
FirstChildTAG: Yes, it was tough. I had thoughts of dropping the course, but.... I'm sticking with it!
FirstChildUserIdTAG: 895825
FirstChildUserNameTAG: JGonzalezGUS
FirstChildCreateTimeTAG: 2013-03-09T18:42:53Z
FirstChildVoteTAG: 0
SecondChildTAG: The practice exercise sets were definitely a must this week, as you say it's tough but stick with it!!
SecondChildUserIdTAG: 16957
SecondChildUserNameTAG: DavidXRobinson
SecondChildCreateTimeTAG: 2013-03-09T22:06:07Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree. Looking at Exercises 5 and 6--It is like I am in total mental breakdown. All the terms are coming at me at once. That awful snow storm in Louisa, Virginia knocked out our power (no lights, heat or internet) on March 6 and apparently what is left of my mind! I missed the March 6 submission date, but I will keep at it until the end.
FirstChildUserIdTAG: 1220195
FirstChildUserNameTAG: Emuna309
FirstChildCreateTimeTAG: 2013-03-09T22:16:23Z
FirstChildVoteTAG: 2
FirstChildTAG: Oops, I meant Exercises 7 and 8! See what I mean...I'm losing my focus rapidly.
FirstChildUserIdTAG: 1220195
FirstChildUserNameTAG: Emuna309
FirstChildCreateTimeTAG: 2013-03-09T22:19:30Z
FirstChildVoteTAG: 0
SecondChildTAG: The first thing to do is take a time out.Relax or take rest for some time.It helps when dealing with "unsurmountable problems" and is a valid technique to use in such situations.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T02:16:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks for the advice...definitely needed a break! Will start fresh tomorrow.
FirstChildUserIdTAG: 1220195
FirstChildUserNameTAG: Emuna309
FirstChildCreateTimeTAG: 2013-03-11T02:31:19Z
FirstChildVoteTAG: 0
IndexTAG: 1077
TitleTAG: problem 6
I missed it. I am not quite understanding the solution to this problem.could someone guide me to where this is in the text or post it after the deadline.Thanks
UserIdTAG: 1202785
UserNameTAG: sjmadden
CreateTimeTAG: 2013-03-09T14:05:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: Go to 6:40 at https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/525a7e5b2b9d41ccb41b3dd7260dc319/0820ac4590f042a8a5462cd2fe574c59/ for instructions on using the applet.
FirstChildUserIdTAG: 164614
FirstChildUserNameTAG: LuketheEngineer
FirstChildCreateTimeTAG: 2013-03-09T14:31:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Luke except the video only goes for 3'01", and no instructions in that first 3 minutes and 1 second, any ideas where the rest of the video is, appreciated, mark c
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-10T05:32:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Do you mean any part or everything?
I cannot say if it is explained or not in the text because I didn't read it completely, but I solved it considering the data as 2 different curves with 2 different transformations which are combined at the end.
Cannot say more...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T14:38:39Z
FirstChildVoteTAG: 0
FirstChildTAG: I too had difficulty with Problem 6. I finally figured out that I was not using the applet correctly. As suggested by LuketheEngineer I viewed the video again. I was then able to go on and solve Problem 7.
FirstChildUserIdTAG: 626017
FirstChildUserNameTAG: JE-Golf
FirstChildCreateTimeTAG: 2013-03-09T22:11:39Z
FirstChildVoteTAG: 0
IndexTAG: 1078
TitleTAG: Lecture 5.4 video: is not possible to download
Please, can you make this lecture downloadble?
Thank you
UserIdTAG: 937105
UserNameTAG: Peppone1965
CreateTimeTAG: 2013-03-09T12:34:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: "Ditto"
FirstChildUserIdTAG: 1106649
FirstChildUserNameTAG: skoules
FirstChildCreateTimeTAG: 2013-03-09T16:05:38Z
FirstChildVoteTAG: 0
IndexTAG: 1079
TitleTAG: Problem 4
Can any one please let me know how to solve the problem 4 using the aplet
UserIdTAG: 481115
UserNameTAG: Nagendranagu
CreateTimeTAG: 2013-03-09T11:58:27Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: you select the percent of area required and you get the value...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T14:24:46Z
FirstChildVoteTAG: 1
SecondChildTAG: perhaps more helpfully: for the 15th percentile place the left slider to the lowest data value (-5) and the right slider to some value where the percent then shows as around 15%. Similarly for the 70th percentile.
SecondChildUserIdTAG: 895825
SecondChildUserNameTAG: JGonzalezGUS
SecondChildCreateTimeTAG: 2013-03-09T17:38:09Z
SecondChildVoteTAG: 0
FirstChildTAG: Review carefully the lectures. Everything about the applet is explained and exemplified there.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-10T00:20:15Z
FirstChildVoteTAG: 0
IndexTAG: 1080
TitleTAG: Problem 4 and 6: Applet use help
Can someone please explain to me how to calculate the answers in the applet for problem 4 and 6.
So if it is asking me for 15percentile and 50percentile, what should I be entering as lower and upper endpoints. Please help.
UserIdTAG: 1237295
UserNameTAG: tanushree31
CreateTimeTAG: 2013-03-09T11:50:48Z
VoteTAG: 1
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: Guys...please help...
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-03-09T12:43:01Z
FirstChildVoteTAG: 0
SecondChildTAG: You ahve to scroll in the applet to get the percentile. An actual problem was solved in the lectures.Also note that when you set the Z value to greater than -5 or -6 you are practically having a very very low value on that side(1 in a million and so setting it at -5 is actually setting it virtually at zero.Beyond that - I cannot answer as it is now in the realm of the honor code.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T12:48:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks prasannasimha. Technically no violation of honour code s I am trying to understand practice exercise. The 85 percentile, so should I start by b assuming since between -2 and 2, 95% of the observation lie. So should I start by setting the lower endpoint to -2 and change the right endpoint until it shows 85...I guess what I need help with is understanding the endpoints? Please guide..
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-09T16:09:34Z
SecondChildVoteTAG: 0
SecondChildTAG: You need to remember what a percentile is to make sense of the problem. I suggest reviewing Lecture 2.4.
Once you've got that clear, the starting point will be obvious.
To find the endpoint, all you need to do is start moving it until you get to the percentile you are interested in, and write down the number you get.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T16:25:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the clue. This is no violation of the honors code
SecondChildUserIdTAG: 800765
SecondChildUserNameTAG: isaacabah
SecondChildCreateTimeTAG: 2013-03-10T18:12:50Z
SecondChildVoteTAG: 0
FirstChildTAG: Sorry but... have you watched the videos at all? It's been demonstrated there...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T14:26:32Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes I have watched the video and I seem to be getting the wring answer...
I am doing exactly what the video demonstrated... Do I set the lower endpoint to -5?
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-09T16:03:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes because a percentile is the cumulative area of the histogram or curve or "area under curve" in this case.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T16:57:45Z
SecondChildVoteTAG: 0
IndexTAG: 1081
TitleTAG: Move it along!
Is anyone struggling with the idea that one below zero is -1? If not can we spend a little less time going over this fact and other such trivialities. I'm taking to pausing the video and reading the script because it's much faster.
UserIdTAG: 164614
UserNameTAG: LuketheEngineer
CreateTimeTAG: 2013-03-09T10:52:44Z
VoteTAG: 1
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 3
FirstChildTAG: You could just up the speed of the video.
> If not can we spend a little less time going over this fact and other such trivialities.
As this is a basic course, it is going as fast as it needs to. There are plenty here who are struggling.
So maybe the course is too basic for you?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T11:01:43Z
FirstChildVoteTAG: 4
SecondChildTAG: I agree Susan! I enjoy they way Prof A. explains thing clearly and specifically, for those of us who have never taken a stats class before. That is what makes her a great teacher. And don't forget, she is a "numbers" person. She is going to be very detailed in her explanations. It is a blessing!! :)
SecondChildUserIdTAG: 1024913
SecondChildUserNameTAG: akaren65
SecondChildCreateTimeTAG: 2013-03-11T03:22:58Z
SecondChildVoteTAG: 0
FirstChildTAG: My favourite line so far was "you may have come across this term before, the middle".
I would simply like to spend less time on the bits like "one below zero is minus one, and two above zero is two".
Yes those parts are too basic for me.
FirstChildUserIdTAG: 164614
FirstChildUserNameTAG: LuketheEngineer
FirstChildCreateTimeTAG: 2013-03-09T11:19:35Z
FirstChildVoteTAG: 1
SecondChildTAG: C’mon. She’s not assuming that there is some who don’t know these things. Those are just side effects, if you like, of the style with the aim to be very clear without too much mathematical formulas. So adapt! And, for that matter, it seems that you have found perfect solution for you “problem”.
SecondChildUserIdTAG: 963407
SecondChildUserNameTAG: JRuth
SecondChildCreateTimeTAG: 2013-03-09T12:03:10Z
SecondChildVoteTAG: 0
SecondChildTAG: May be an Engineer should not be taking the course !! This is a basic course, the explanations are done without using algebra and calculus and so on and so forth so you can choose to skip the parts you do not want.Remember that there are people struggling even now to grasp these concepts even as we speak. There are things in the supplements and wiki if you want to read the esoteric ;)Also I actually do not mind going through those things.I have always found it more difficult to teach the younger the class.I can very easily teach post docs(but they present a new problem as they are very "set" in their ways and I have even found them blundering when confronted with their basics.One of the reasons why I did want to go through this course is it builds right from the fundamentals and simple things and I always wanted to do a formal statistics course like this.In medial statistics I click things on a computer and boot strap blah blah blah but really did not knwo the nuts and bolts that goes behind these statistics though we did do all of this in medical statistics in graduate school(and most of these have indeed been covered for my Son in his high school itself)but the joy of learning formally from basics is just that - a joy of knowing why a thing is being done as it is.I make it challenging for myself by specifically trying to find out the things which the Professors say are being assumed as it helps build a better foundation.Maybe you should be doing it too.I am trying to learn R on the side too and dabbling with Latex too - tough when you are working and teaching but then it does make the course more fulfilling. I always say Heaven or Hell is in your mind - you can choose what you want it to be !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T12:59:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Dear Prasannasimha, you mentioned R. Do you know any course online about it?
SecondChildUserIdTAG: 122004
SecondChildUserNameTAG: fqantonio
SecondChildCreateTimeTAG: 2013-03-09T23:55:46Z
SecondChildVoteTAG: 0
SecondChildTAG: @fqantonio, you might find interesting this warming up:
http://www.codeschool.com/courses/try-r
In Coursera there was a course:
https://www.coursera.org/course/compdata
Maybe someone here attended it and can give more info.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T00:33:13Z
SecondChildVoteTAG: 0
SecondChildTAG: fqantoniio, as atopos suggested - http://tryr.codeschool.com
Basic, but enough to give me an idea. I'll be looking at more advanced courses.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-10T16:23:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Not that I am very succesful but I am trying to go through this online teaching module
http://www.youtube.com/playlist?list=PLFf3DKi9pkFQceRv27Wm_EtNx6QOiCpOY
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-10T02:18:46Z
FirstChildVoteTAG: 0
IndexTAG: 1082
TitleTAG: great practice quiz!
Love the applet..waaaay better than normal tables :)
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-09T09:54:36Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: yes, i love tech as well
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T14:27:12Z
FirstChildVoteTAG: 0
IndexTAG: 1083
TitleTAG: Stats learning with special effects!
The augmented reality at the beginning of Lecture 5 Introduction just blew my mind! Nice touch!
UserIdTAG: 35091
UserNameTAG: Danzig1788
CreateTimeTAG: 2013-03-09T09:43:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: My only problem is the finicky slider control.I can never et it ti set it where I want it.I wish the slider bars were made larger than what it is and less hypersensitive.it changes even when I try to release my mouse from my hand !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T16:59:16Z
FirstChildVoteTAG: 1
SecondChildTAG: Drag it close to where you want it, then use your arrow keys to give the finishing touches ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T17:03:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes= it works . Thank you.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T17:22:51Z
SecondChildVoteTAG: 0
IndexTAG: 1084
TitleTAG: my feed back on the lectures
My knowledge of maths is low. Basically i am a doctor having to teach statistics to my students , so entered the course to understand statistics. but after listening to the lectures i am unable to answer questions . maybe because i am not equipped for the course, but i just wanted to know whether others have experienced similar feeling.
UserIdTAG: 711460
UserNameTAG: neelu1965
CreateTimeTAG: 2013-03-09T08:17:20Z
VoteTAG: 17
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 13
FirstChildTAG: > Basically i am a doctor having to teach statistics to my students , so entered the course to understand statistics.
Sorry, but why are you teaching something you don't know? Surely your university has statisticians?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T08:44:23Z
FirstChildVoteTAG: 6
SecondChildTAG: The reality is in many places getting a statistician in. developing countries is difficult and many of us double up to do it. I have also taught basic statistics for paramedical students.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T10:55:13Z
SecondChildVoteTAG: 0
SecondChildTAG: thanku for the prompt reply. i am an MD community Medicine graduate and biostatistics is a part of our curriculum. I am teaching in a government set up, where a post for statisticians have not been created in our department, so seeing the pathetic state of students having to learn from an old debilitated notebook, i started to teach the basic things i knew. Anyway i just put up the post to see if there are others in my same boat. Now i see that there are seven .
Susan - i really appreciate your concern for others and the patients to respond to all queries.
SecondChildUserIdTAG: 711460
SecondChildUserNameTAG: neelu1965
SecondChildCreateTimeTAG: 2013-03-11T15:56:01Z
SecondChildVoteTAG: 0
SecondChildTAG: I've always found Schaum's Outlines to be very instructive, if you have the time. There are lots of worked problems with every step shown in detail. If I had to teach something I wasn't all that familiar with, I'd start there.
SecondChildUserIdTAG: 937396
SecondChildUserNameTAG: m2foster
SecondChildCreateTimeTAG: 2013-03-12T19:56:41Z
SecondChildVoteTAG: 0
SecondChildTAG: @SusanAust - The purpose of these forums is to support, not deride, classmates - I don't think comments like the one you've made above are helpful.
@neelu1965 - My advice would be to go back and look at the material again, discuss the areas you don't understand in the forums, and search the net for things that you are finding it hard to get your head around. That's what I do when I get stuck, and it always helps. But, if this style of teaching just isn't working for you, there are some more statistics courses coming up on Coursera that you might like to try too :)
SecondChildUserIdTAG: 1032160
SecondChildUserNameTAG: sokkusuchan
SecondChildCreateTimeTAG: 2013-03-16T17:07:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Dear Neelu,
I am also a MD community medicine and fortunately we have a statistician to teach statistics. I really appreciate your efforts to teach something which we are not tough in a very systematic way like the one tough by Prof. Ani and Prof. Philip. I also had similar difficulties.
these are some of the tips to help you answer your test properly.
1. listen to the lecture carefully by focusing on the lectures, you care reduce the pace of lecture to 0.75 speed.
2. print the lecture slides before listening to lectures and you will understand lecture better. It will also help you locate the concept while answering the test if need be.
3. after answering the practice session, copy the problem and answers in the word form and print that will help you to learn the calculations and understand have to answer the final tests.
4. similarly copy the test problems and answers in word and print then you will know your mistakes better.
I would encourage you not to get disheartened by the difficulties and continue course even if you don't perform like others. You are unique dont compare yourself to any one.
All the best
Nitin
SecondChildUserIdTAG: 571249
SecondChildUserNameTAG: nydhupdale
SecondChildCreateTimeTAG: 2013-03-18T07:09:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Have you listened to all the lectures? A friend of mine did not know that one has to scroll to the right for the next video and he was only viewing the first lecture for each section! He was still able to pass though with difficulty.
If you're viewing all the lectures and still cannot answer the questions, then I guess you've already provided the explanation in your first sentence- "My knowledge of maths is low". One of the stated per-requisites for this course is good knowledge of high school algebra.
SecondChildUserIdTAG: 1076285
SecondChildUserNameTAG: francais
SecondChildCreateTimeTAG: 2013-03-19T08:04:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Neelu, prasana & nitin... I am a student of SRCC, one of the elite colleges in our country(presuming we are from the same)...what is funny is even in my college we don't have good teachers.i had a good teacher for stats but we are never given practical examples!. I am thankfully to EDX. As I can now take some of my learnings and share it with my peers.
SecondChildUserIdTAG: 1043835
SecondChildUserNameTAG: anubhav_maini
SecondChildCreateTimeTAG: 2013-03-29T06:57:07Z
SecondChildVoteTAG: 0
SecondChildTAG: *although I had a god teacher
SecondChildUserIdTAG: 1043835
SecondChildUserNameTAG: anubhav_maini
SecondChildCreateTimeTAG: 2013-03-29T07:04:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, might be better your students enroll here by themselves.
SecondChildUserIdTAG: 720154
SecondChildUserNameTAG: LUCALOTTO2012
SecondChildCreateTimeTAG: 2013-03-30T15:18:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Dear sister
I am a prof teaching statistics at college level. I found that prof A was clear and lucid in her expressions. One more thing which is really commendable that she barely used any formula and possibly kept away from technical jargon. Since we can play videos again and again, it therefore becomes easy to understand the concept. We may be required to have some extra patience sometimes.
All the best for Stat 2.2X
AKS
SecondChildUserIdTAG: 974461
SecondChildUserNameTAG: ncscaks
SecondChildCreateTimeTAG: 2013-04-01T10:32:44Z
SecondChildVoteTAG: 0
FirstChildTAG: I am also a doctor and do teach very basic statistics to paramedical students. It is doable if you choose to do it. Go through the basics. Factually all of this was indeed taught Tue is in social and preventive medicine -check out Park and Park
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T10:40:51Z
FirstChildVoteTAG: 1
FirstChildTAG: Great! I'll put myself down to teach brain surgery. Suddenly my faith in medicine hits a rock bottom low.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T10:59:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Well if you are in a disadvantaged region a general physician may even have to do brain surgery !! That is the bitter reality indeed in many places in the world where things are less fortunate(actually more than 3/5th of the world,(So what you see or perceive as reality is actually not so ,Having said that actually in the medical graduate course a significant amount of statistics is taught and indeed is needed but many people tend to gloss over it and then struggle later.(They are actually expected to know what is covered in the PH20X course.)
There are indeed many fine Doctors (whatever your opinion may be) but some do not know their statistics well.I have seen glaring errors in papers due to this.Indeed one of the reasons I am goiung through this course is to allow me to have formal training to better understand the process even though all of this was "taught" to us a long time ago.Helps brush up concepts and more importantly the teachers teach it in a very enjoyable manner too.At least the person hee admitted to being deficientand should not be mowed down.There are others who are so knowledgable about multiple GMT times and berate the Professors.I at least admire that she is upfront and being hones.He who knows that he does not know - He is Ignorant - Teach him indeed is a very wise adage- better than He who does not knwo and thinks he knows - who is a fool- shun him and well He who knows and knows that he knows is wise - Respect him.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T13:07:50Z
SecondChildVoteTAG: 0
SecondChildTAG: [Off-topic]
Socrates said that in its Apology, Prasannasimha.
Not knowing that we don't know is the worst ignorance, squared ignorance, ignorance of the ignorance. But Socrates goes further: nobody knows in the strong sense of the word. We can have this or that specialized "techné" (it's the Socrates term), but we can't have "sophia" (wisdom), we haven't the real knowledge, we can't. And knowing this bound, our human bound, is the most profound human wisdom. I'm very fond of this idea.
Sorry for the philosophical excursion, your last reflections have triggered it.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T00:59:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Indeed Atopos, thanks for the rest of the statements regarding techne and sophia .Indeed three is a difference between knowledge and wisdom .I think I ahd knowledge before wrt to contents of this course(I knew most of what has been taught) but I hopefully have become a bit wiser as the teaching is giving me a fresh perspective about some of the concepts I had.Also I think as one becomes wiser it is associated and tempered with more humility.
Just see the persons with the most humility while correcting us are the most knowledgeable ones - the Professors.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T02:29:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Susan Aust is among the nastiest of all MOOC instructors I have come across. You have little faith in medicine? You should have still less faith in yourself as a teacher.
SecondChildUserIdTAG: 1305333
SecondChildUserNameTAG: bellerin
SecondChildCreateTimeTAG: 2013-03-10T03:28:47Z
SecondChildVoteTAG: 0
SecondChildTAG: She is not an instructor.She is a student on this course.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T09:33:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Please, @bellerin, moderate your words.
Susan Aust is not an instructor in this course, she is not in the staff, she's participating as a student as us and she's dedicating endless hours to the forum trying to give hints whenever possible without violating the Honour Code and answering patiently the same questions over and over again.
Regarding the issue raised by the post I understand her concerns, as I understand Prasannasimha response. It's very sad that in some circumstances and countries someone has to teach or do something without a firm grasp and knowledge of the subject matter. It shouldn't happen, but it happens. Hence worldwide improvement of education is essential, ethically speaking, for the humanity. And so edX and MOOCs..
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T10:06:52Z
SecondChildVoteTAG: 0
SecondChildTAG: @Prasannashimha, agreed. Humility is the most prominent sign of wisdom. That's also my experience: the wiser, the humbler.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T10:15:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Bellerin, I have no problems if a person corrects peoples inattention to course material etc but personal attacks is something that is not tolerable-in fact that itself breaks one of the rules of the forum so I think it should not be done here in this thread.That is why I am taking a strong stance against it.We are no one to judge another professionally as we don't know their qualifications , their exact field of expertise etc etc.They can at the most be judged by their group of peers and we are not as far as this group is concerned their peers as a professional group.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T11:34:16Z
SecondChildVoteTAG: 0
SecondChildTAG: > Great! I'll put myself down to teach brain surgery
Better yet, put yourself down to teach statistics to neelu1965's medical students!
SecondChildUserIdTAG: 1057358
SecondChildUserNameTAG: s_zambelli
SecondChildCreateTimeTAG: 2013-03-10T12:24:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Please, let us move away from this issue. I haven't enough English skill to assess the connotations of certain wordings, but it's better for all of us being as polite and friendly as possible. Let us go to the course itself, guys :) , and good luck for the Midterm.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T13:24:56Z
SecondChildVoteTAG: 0
SecondChildTAG: We should I am done with it but one thing I will not tolerate is people making fun of the people who are down and out for whatever reason.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T15:02:36Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed. We shouldn't tolerate.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T15:26:13Z
SecondChildVoteTAG: 0
SecondChildTAG: All I wanna say is you know the most number of doctors come from the 'disadvantaged region' we are talking about......maybe you can't figure out the country but I can....from the names of the people posting..I would appreciate if you could be more supportive in helping us(being from the same region) gain knowledge from such portals.
Best of luck .
SecondChildUserIdTAG: 1043835
SecondChildUserNameTAG: anubhav_maini
SecondChildCreateTimeTAG: 2013-03-29T07:03:31Z
SecondChildVoteTAG: 0
FirstChildTAG: God! If you can't answer these questions then how possibly can u teach????
FirstChildUserIdTAG: 1075168
FirstChildUserNameTAG: Ashish_Mamgain
FirstChildCreateTimeTAG: 2013-03-09T11:39:30Z
FirstChildVoteTAG: 2
SecondChildTAG: I think wanting to teach is different from being able to teach
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T13:08:32Z
SecondChildVoteTAG: 0
SecondChildTAG: It is not his fault, no options. But I agree...
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-09T14:43:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Many a time we get dumped into such situations - like it or not and then we have to swim or sink.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T02:30:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Agree! This just blows my mind. These questions are basic maths. How are some of the Drs here calculating drug doses? Scary!
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-11T00:53:52Z
SecondChildVoteTAG: 0
SecondChildTAG: sorry basic maths is not required for teaching drug doses. Besides there are a whole lot of statistics teachers i have met who can do problems well but haven't understood the concepts.
SecondChildUserIdTAG: 711460
SecondChildUserNameTAG: neelu1965
SecondChildCreateTimeTAG: 2013-03-11T16:09:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Turning back to the original query...
I am just a pharmacist, but so far I could answer everything. Some questions required a good amount of thought anyway and I hope this is not getting much complicated...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T14:46:22Z
FirstChildVoteTAG: 0
SecondChildTAG: I don't think it makes much of a difference for this course whether you are a doctor, a pharmacist, or the head physician for your hospital.
The skill set for everything we've seen until now is grade school level Algebra, and it's not too surprising that those who, after graduation, went on to professions not involving much math, might be a bit rusty at it.
To neelu1965 I say: don't lose hope. Keep trying the exercises and review the solutions so you can see where you went wrong: eventually you'll get the hang of it :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T16:33:55Z
SecondChildVoteTAG: 0
SecondChildTAG: It's good to read some encouraging/positive feedback! Thanks, Klionheart.
SecondChildUserIdTAG: 144162
SecondChildUserNameTAG: Rena2012
SecondChildCreateTimeTAG: 2013-03-09T18:08:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you , I have no plans to give up.
SecondChildUserIdTAG: 711460
SecondChildUserNameTAG: neelu1965
SecondChildCreateTimeTAG: 2013-03-11T16:11:06Z
SecondChildVoteTAG: 0
FirstChildTAG: A Dr. with no knowledge of math and statistics? How do you evaluate efficacy of treatment? Goodness, how do you determine dosage based on weight? You need some basic math skills for that too.
How can the bar be set so low for such a mission critical profession?
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-09T16:47:57Z
FirstChildVoteTAG: 0
SecondChildTAG: "Basic math skills" are addition, multiplication, and their inverses. I suspect "dosage based on weight" doesn't require much more that that.
Equations, percentages, and linear transformations are quite some steps above that, and important parts of this course.
I don't know how crucial they are for the medical profession, though. I can't go into that.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T17:11:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Getting into medical school in Canada requires an undergrad GPA of 4.75/5 in recent years. I shudder at the thought of foreign trained physicians practicing medicine here. That's all I'll say on the issue.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-09T17:27:50Z
SecondChildVoteTAG: 0
SecondChildTAG: It is indeed surprising as I ahve seen people making goof ups when they are rusty.I could probably make people dance around in circles wrt cardiac anatomy which may be obvious to biology students and make maths students jittery and vice versa.I find going back to calculus difficult and that too after a gap of 30 odd years.Having said that let it be clear that actually in medicine graduation course we have to do quite a bit of statistics(and need it a lot in academic work) but people who do not deal with it probably forget all that they have learnt.Also statistics was one of those things which were glossed over by many in medical school (though I liked it) and then they get a statistician to help them when required.In fact this can cause major problems in conception and conducting many research studies.It doesnt help that often the statistics teacher often is one of the most boring teachers in medical school - not like our Prof here !! I used to rememebr with a shudder the boring monotous description of chi squared test etc.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T17:29:31Z
SecondChildVoteTAG: 0
SecondChildTAG: I can relate..my undergrad stats prof was a guy who would come in to the lecture hall, turned to the blackboard and stand there mumbling to himself for 3 hours at a time.
It didn't change the fact that I needed 90+ to get in to the grad program I wanted and get an internship. So I studied on my own.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-09T18:08:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I think besides college and career advancement, its also important for everyone to have some knowledge of statistics, given that we are constantly bombarded with statistical analysis from multitudes of researches being carried out some which are very questionable. It enables one separate the wheat from the chaff or critique the research analysis employed.
I must also add that even though I generally consider myself good with numbers, I have also experienced challenges and made some careless mistakes in this course, which I believe is very normal. Those having difficulties just share your problems on the discussion board, there are some very helpful and kind students here.
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-09T22:38:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Yup.. I've made a few careless mistakes here too. Lost a few marks here and there.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-09T22:49:15Z
SecondChildVoteTAG: 0
SecondChildTAG: That was exactly what used to happen in our stats class too(teacher with the nback to the class !!) Anyway I did do extremely well then but did it make me wiser -not so much except for what I learnt by myself and not because of sitting in the class.Many chose to just glosss over it (as we had a heck of a lot of other things to do in social and preventive medicine and statsitics was just one portion - clinical epidemiology and things like that was a huge part apart from things like water purification and toilet design !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T02:34:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually Arthur and Susan, most of those who indeed get into medicine have actually got extremely good scores in the premedical years(You don't have to shudder about foreign medical graduates - those who take the entrance exams typically get very high scores and are usually above the 90th percentile !!) but what happens is many over the years just don't deal with statistics if they are not in academics etc and in clinical practice not much of these are required and so they may become rusty or faded. wrt to that but manage very well in their clinical practice.Just like you as a financial expert would be laughing stock in a medical biochemistry class if you were to suddenly take it.So, I would not pronounce judgments so liberally !)Or else you should not have made any mistakes at all in these even if careless.Let the one who is perfect caste the first stone ;)One thing that irked me was the holier than though pronouncements of people when a person comes out with her/his problems and inability to comprehend.At least some compassion must be there rather than making fun.Ask what is the problem being faced and try to help.One thin that seems lacking is compassion by those who made such comments.I was surprised by that and let me tell you some of us are good in our subject(including statistics right here) but we don't make fun of others and yes Susan you can't do brain surgery or cardiac surgery. Ooops I can - you can't and my Euroscore adjusted mortality is 50 % of the predicted if you care , I have international publications using sophisticated statistical analysis (including multivariate analysis,propensity scoring, boot strapping etc etc) but I don't make fun of others or crow over them especially when they make a cry out for help.I do not want to brag but thinking others are dunces here is very very very wrong. Don't also forget your Professor on this list indeed is a Foreign born and is instructing you today !! Parochialism is not in order here. Arrogance is not in the order here .The free spirit of learning and exchange is.Maybe Doctor's seeing suffering daily may become immune to it but I though the lay people should be the last to lose that quality of empathy to a fellow human being.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T09:52:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Prasannasimha, my comments went right over your head apparently. Nowhere in my posting I have bragged or put down others.
I have (as I have a right to) questioned the wisdom of allowing foreign trained physicians to practice in Canada without having the basic abilities required for certain aspects of their job. I have no issues with FTP's practicing here as long as they can prove that they are on par with local trained physicians.
Despite everything you said in your post, I still don't see how someone who has not been trained in basic statistics can assess treatment efficacy, or do basic research. Forget contributing to the general body of knowledge via publications.
I'm not sure what you are hinting at when you say that the Prof here is foreign trained.It doesn't matter where the specialist has been trained, as long as the specialist is at least on par with locally trained specialists in the field. It's obvious that Prof. A is top notch, and is above and beyond most Profs.
I'll have the same opinion and attitude toward any foreign trained physician if they can prove that they are on par with locally trained physicians.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-10T16:18:07Z
SecondChildVoteTAG: 0
SecondChildTAG: There is nothing specific to a foreign trained graduate or a locally trained graduate relevant to competence in relation to geography.It is related to the persons competence and tey can be equally incompetent people originating from both the native country and the foreign graduates.have a look at any medical register and see the people who have been censures or struck off the list.You will see both.Question competence - Yes but don't give it a geographical color.next what other category could one choose to fit our bias ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T16:49:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Is there any way one can edit a post which is nested within a major post ?There is no edit button and you cannot correct any errors once you post in a "nested" manner.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T16:52:24Z
SecondChildVoteTAG: 0
SecondChildTAG: tey should be "there"have should be Have,censures should be censured and next should be Next.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T16:53:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Pranishma, stop reading into what I write, and read it as it is.
1: Getting into Canadian / US medical school is extremely difficult (93% average in undergrad)
2: Even if you take an arts major, statistics are thought. And remember, the grade has to be extremely high
3: Taking the previous two points into account, North American med school grads are comfortable (at least) with stats.
So far, so good? Nothing about geography, or geographical "color" as you so subtly put it.
Now, lets continue
4: Comments made here (and some of my own experience) lead ME to believe that SOME of the foreign trained professionals are NOT up to par with North American trained ones.
5: As long as foreign trained medical professionals can prove they are up to par with North American trained ones, I have no problem. Otherwise, they should not be allowed to practice IMHO.
Now, still not much talk of geography or geographical "color" is there?
Your "bias" comment.. im not going to even dignify that with an answer.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-10T17:09:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Guess how many American medical graduates got this question right(and I am not quoting impressions or thoughts but from an (actual study)A bat and ball costs $1.10.The bat costs 1 dollar more than the ball. What is the cost of the ball? Guess what 84% got it wrong.Believe it or not- they are the same people who got wonderful GPA grades and if you think that that was a "trick question you should see the simpler ones on the test.
So before drawing conclusions about such issues you really need to think.Ask the same medical graduates 10 years down the line and let us see how they fumble within elementary statistics.I have seen it first hand with my own eyes.You are mistaking cognitive reflection and dissonance and making an issue out of it. Most medical graduates have been selected with very good scores in their premedical entrance (usually in the 90+ range in very competitive examinations.Unfortunately what happens is most do get trained in statistics and over a period of time their maths skills do deteriorate as they do not use it.They however hone themselves on diagnostic skills, can make sense of what investigations mean intuitively but fumble when faced with actual mathematics unless they are in touch with it.So even if you think that NA graduates are comfortable with stats when they pass medical school they are not after a few years (which is very likely the people who are here in this course) So you did not have the facts but chose to label FMG's with a single brush and of course yes I would equally be uncomfortable with any medical graduate who is not trained medically. Mathematiccs depending on what he/she has to deal with.if dealing with public health - yes but a person can be a very skilled clinician and diagnostician without remembering the esoterics of stats and yes I pretty well am sure they know intuitively what a mean is etc but give them a paper and pencil and calculate - I have seen such people fumble.So I indeed have a peer reviewed article to quote whereas you are quoting a point bias. So there is bias and I added no "color" just geographical color- you did that = go look again indeed was your statement.I said geography indeed should not color ones perception (as color as in jaundice) and not the way you chose to do so.(Frankly I don't even know what the color of the person who I am referring to is or care).I used bias again in a statistical manner and you choose to use it otherwise.I havd enough of this conversation and will not bother to continue it further but you need to reflect on what you said a bit slowly.If you cannot see that it was offensive to others(May or may nnot have even have not been intentional ) but those comments had no business to be here in a statistics course and those opinions where uncalled for even if you claim that you have the right to freedom of speech but it should not impinge on the feelings of others. I am done with this .
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-10T17:54:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Reread point 5. Carefully. Then tell me I'm painting everyone with the same brush.
Anyway, enjoy the rest of this great course. I have neither the time nor the will to engage in this meaningless debate with you. I'm sure you're a wonderful Doctor BTW.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-10T19:04:33Z
SecondChildVoteTAG: 0
SecondChildTAG: If you remove the "geographical color" (Canadian / US, North American, foreign,...) from your 5 points, here it how they read:
>1: Getting into medical school is extremely difficult (93% average in undergrad)
>2: Even if you take an arts major, statistics are thought. And remember, the grade has to be extremely high
>3: Taking the previous two points into account, med school grads are comfortable (at least) with stats.
>4: Comments made here (and some of my own experience) lead ME to believe that SOME of the trained professionals are NOT up to par.
>5: As long as trained medical professionals can prove they are up to par, I have no problem. Otherwise, they should not be allowed to practice IMHO.
This is exactly what Prasannasimha agreed with.
The danger is adding a "color", whether it is geographical, ethnical, gender-based or even based on whether the doctor uses glasses or not. Adding these tinges distracts from the real message, which is that it is all based on individual competences.
SecondChildUserIdTAG: 1057358
SecondChildUserNameTAG: s_zambelli
SecondChildCreateTimeTAG: 2013-03-11T07:52:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry for all the commotion caused by my lack of mathematical skills, anyway i am just going to keep on trying till i understand.
SecondChildUserIdTAG: 711460
SecondChildUserNameTAG: neelu1965
SecondChildCreateTimeTAG: 2013-03-11T16:20:02Z
SecondChildVoteTAG: 0
FirstChildTAG: > maybe because i am not equipped for the course
As an engineer, my training involved a lot of exercises where the problem was stated in plain language and needed to be translated into into mathematical terms before being solved. I know what you are feeling very well.
I know many students at all levels can feel overwhelmed by mathematics, just like they would be by a foreign language. I find that, generally, it's simply a problem of formalism or vocabulary: they easily understand the underlying concepts, but they are put off by the apparent complexity that is needed to express it.
I bet that you *are* equipped for the course. Try to break down the question into small, manageable, "generic" bits. If we take the example of Exercice 3, everything hinges on transforming the number of right answers X of a student into the corresponding score Y. If you can manage to express that relationship correctly in mathematical terms, the rest will follow.
FirstChildUserIdTAG: 1057358
FirstChildUserNameTAG: s_zambelli
FirstChildCreateTimeTAG: 2013-03-10T13:07:53Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you. I think i just got frustrated too fast.
SecondChildUserIdTAG: 711460
SecondChildUserNameTAG: neelu1965
SecondChildCreateTimeTAG: 2013-03-11T16:21:49Z
SecondChildVoteTAG: 0
FirstChildTAG: Going way back to the start of this long discussion, I have to admit that I was surprised that someone teaching statistics to undergraduates was struggling with this introductory material. Having then read the background I can certainly understand how it has come about. There is a shortage of mathematicians in education at all levels pretty much worldwide. I suspect this is because there are so many other opportunities open.
My wife is a doctor and trained 'overseas' (relative to my country of residence, the UK) and in order to practice here she needed to pass quite stringent exams here both theoretical and practical tests of medical knowledge and a test of her language ability (as English is not her first language). Statistics don't, however, form a part of that test - for the simple reason that they also don't form part of the day to day practice of a doctor. From what I know of the system in Canada and the US, similar rules apply.
Practising physicians do not need to use statistics although it is obviously important to those involved in research. I know from my wife's experience that although she had conducted medical research some years ago (in Chernobyl if you're interested) which involved a lot of large scale statistical analysis, she found her current work (in the final stages of a Psychology Masters) extremely taxing as she had forgotten much she once knew (but never subsequently used).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-10T21:02:27Z
FirstChildVoteTAG: 1
FirstChildTAG: I am a retired psychiatrist, and I also have a PhD in maths. Colleagues always assumed that I knew about statistics, but they were wrong. Whenever I wrote down an equation, they treated it like a divine revelation. They were wrong there, too.
FirstChildUserIdTAG: 270738
FirstChildUserNameTAG: sheardp
FirstChildCreateTimeTAG: 2013-03-19T15:12:45Z
FirstChildVoteTAG: 0
FirstChildTAG: i can not get anything correct. does it mean i know nothing?
FirstChildUserIdTAG: 1241440
FirstChildUserNameTAG: Bertinah
FirstChildCreateTimeTAG: 2013-03-19T22:24:08Z
FirstChildVoteTAG: 1
FirstChildTAG: While this post originally did not start out as being about the state of American education specifically, I think it's relevant to note the unintended consequences of a failing system. One of those consequences is that people who were dead certain when they were in the K-12 public education system, that they would never need or want math find themselves needing to learn advanced concepts like the equation of a line, or the math for a stats class. As kids we say "We have calculators! There's an app for that!" Then we realize we should have paid more attention and been held to a higher standard. This is a video about the root cause of math illiteracy that everyone should see (especially those of you who are parents of a child in K-12):
http://youtu.be/Tr1qee-bTZI
Enjoy!.
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-03-25T19:45:03Z
FirstChildVoteTAG: 0
FirstChildTAG: hello,
am a MD community too. i thought this course need not any statistic background and complicated math skill. I completed this course by understanding lecture, reading discussion board, using textbook online. thats enough to pass the course. am sure if you have statistic background, this course will be easier. but thats not the point.
Statistic knowledge for me is very helpful to understand and interpret many research article. and also to conduct my original research.
keep looking, dont settle !
FirstChildUserIdTAG: 646706
FirstChildUserNameTAG: donnyputra
FirstChildCreateTimeTAG: 2013-03-29T07:03:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you Prof Ani Adhikari and Philip Stark! The lectures were amazing! It was a real pleasure to be part of such a good experience.
Thank you and all the best!
FirstChildUserIdTAG: 1141835
FirstChildUserNameTAG: TrissMerigold
FirstChildCreateTimeTAG: 2013-03-30T21:58:17Z
FirstChildVoteTAG: 0
IndexTAG: 1085
TitleTAG: Ex 7/ Q 3 Confiusing
A list of numbers has an average of 48 and an SD of 12. The list is transformed by subtracting 3 from each entry and then dividing the result by 5
the subtracting com before dividing an i think that
(48-3)/5 and 48/5-3 are totally differ
so plz check it and help me to understand
UserIdTAG: 633858
UserNameTAG: balakh
CreateTimeTAG: 2013-03-09T07:45:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Follow the sequence as asked.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T10:37:52Z
FirstChildVoteTAG: 1
FirstChildTAG: I have the same doubt.
FirstChildUserIdTAG: 1270186
FirstChildUserNameTAG: anar0sa
FirstChildCreateTimeTAG: 2013-03-09T17:03:18Z
FirstChildVoteTAG: 0
FirstChildTAG: Consider, what would be the situation if you had no wrong answers? This should help you see the sequence of the transformation.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-09T17:22:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Your first expression with the parentheses is correct since you are to divide the "results" by 5.
FirstChildUserIdTAG: 144162
FirstChildUserNameTAG: Rena2012
FirstChildCreateTimeTAG: 2013-03-09T18:01:05Z
FirstChildVoteTAG: 0
IndexTAG: 1086
TitleTAG: THe applet !
THe applet is necessary to get the Z value, especially Q6 & Q7.in this week 3,
I recommend website.
http://www.mathsisfun.com/data/standard-normal-distribution-table.html
Mathis Fun.com Just open and try!
UserIdTAG: 200548
UserNameTAG: kame
CreateTimeTAG: 2013-03-09T06:22:07Z
VoteTAG: 2
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Thanks kame, that worked unlike the guici applet, mark
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
FirstChildCreateTimeTAG: 2013-03-10T05:34:42Z
FirstChildVoteTAG: 0
IndexTAG: 1087
TitleTAG: Problem 1A
Reads: Approximately what percent of the adults are over 6 feet tall? Please don't enter the percent sign.
Does that mean what percentage of adults are over 72 inches compared to the 66 inches?
UserIdTAG: 1150329
UserNameTAG: cbratsis
CreateTimeTAG: 2013-03-09T03:05:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: Yes - those above 72 inches.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T03:13:12Z
FirstChildVoteTAG: 0
SecondChildTAG: 6 feet is 72 inches, isn't it? There's even a note reminding us of the conversion factor "for those used to the metric system" :)
(which is, by the way, *far* superior to this feet-inch-stone silliness IMHO. But, to each his own...I suppose Romans were very proud of their numerals too.)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T14:46:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Q 1A.
Please. Someone can say me which is the lower endpoint in this case, I wrote 0 and upper (72-66)/2.5 = 2.4, but my result is wrong.
Thanks in advance
SecondChildUserIdTAG: 1158693
SecondChildUserNameTAG: dabad
SecondChildCreateTimeTAG: 2013-03-12T22:47:28Z
SecondChildVoteTAG: 0
FirstChildTAG: "Does that mean what percentage of adults are over 72 inches compared to the 66 inches?"
I don't know... it means exactly what percent of adults are over 72 inches tall
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T22:20:04Z
FirstChildVoteTAG: 0
IndexTAG: 1088
TitleTAG: R function
Will anyone plz tell me how to get the R function and where to use it...???
UserIdTAG: 795482
UserNameTAG: VIVEK_88
CreateTimeTAG: 2013-03-09T02:15:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: R is a free open source statistical program. So "R function" is a very very broad concept.
http://www.r-project.org/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T02:36:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Look at here:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/R/
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-09T11:03:22Z
FirstChildVoteTAG: 0
IndexTAG: 1089
TitleTAG: What am I doing wrong!!!
PROB 1B Approximately what percent of the adults have heights that are within 1 inch of the average?
average is 65 inchs. So within one inch of the averege is averege minus 1 an +1.. Then find z value using z formula and then find percentage usin applet???
And thats not it. So what is it??
UserIdTAG: 1202387
UserNameTAG: Danny1412
CreateTimeTAG: 2013-03-09T01:10:08Z
VoteTAG: 4
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 6
FirstChildTAG: The average is 66, not 65.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T01:33:01Z
FirstChildVoteTAG: 0
SecondChildTAG: that is ok.. I know. But the point is """is it right procedure""" I lost my confident during last Ex
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-09T01:51:23Z
SecondChildVoteTAG: 0
FirstChildTAG: My last 2 weeks exercises was almost perfect..This last two were sooo bad...It is like i become stupid over night.
FirstChildUserIdTAG: 1202387
FirstChildUserNameTAG: Danny1412
FirstChildCreateTimeTAG: 2013-03-09T01:36:32Z
FirstChildVoteTAG: 0
SecondChildTAG: Same with me ! Must admit that I feel better now that I know I'm not alone :-)
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-09T09:03:31Z
SecondChildVoteTAG: 0
FirstChildTAG: I am also at a lost with the topics on standard deviation and normal curve.
FirstChildUserIdTAG: 1083507
FirstChildUserNameTAG: mtzemd68
FirstChildCreateTimeTAG: 2013-03-09T03:14:43Z
FirstChildVoteTAG: 0
SecondChildTAG: I thought, I was the only one. Now good to know most of us on same boat.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-09T20:34:26Z
SecondChildVoteTAG: 0
FirstChildTAG: You seem off to a good start in that you know you need to deal with endpoints. I am finding it helpful to draw out what the problem is asking, and identifying the correct endpoints is crucial. (And that's all I can say about these particular endpoints.)
I want to help, but I don't know what you mean by "And thats not it."
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-09T03:50:10Z
FirstChildVoteTAG: 1
SecondChildTAG: OK, so please help than.
"thats not it" means I try it that way and got wrong answer. So my endpoinds are mean +1 and mean -1/SD..than i find interval betwen z values of mean +1 and -1 and i get wrong answer. It seems so simple, and thats why I cant find out what am I missing.
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-09T12:21:08Z
SecondChildVoteTAG: 0
FirstChildTAG: "OK, so please help than."
I was NOT being snarky.
Back up.
It seems your endpoints are possibly questionable. In inches, what exactly are the endpoints in question? (Please do not post you answer as that is the most critical part of the problem.) What does it mean to, say for example, select only boards that are within 1 inch of 66 inches? Which boards would we eliminate because they are not "within 1 inch"? How far away from "within 1 inch" can you get before the boards are no longer close enough to 66 inches to be included? What range does that leave us with?
Think about this while looking at the 3rd video in the Lec 5.1 - 5.2 series at and just beyond point 5:19.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-09T13:18:16Z
FirstChildVoteTAG: 0
SecondChildTAG: I know you were not snarky. Thanks for help :)
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-09T14:00:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks. Remember heights are continuous. If I ask you to what nearest inch is 1.37 inches, the answer would be _ ? What about 2.4 inches? Or 2.7 inches? These are basic examples, and maybe the exercise question is also basic, to test that we can get the proper intervals identified before using the applet. And intervals imply ranges, and with ranges we need to take into account both the average and the SD, THEN use the applet. Hope this weekend brings us all a bit of better understanding, myself included!
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-09T15:03:49Z
SecondChildVoteTAG: 0
SecondChildTAG: What applet have I missed something do we have course software.
SecondChildUserIdTAG: 334968
SecondChildUserNameTAG: MCGEEC147
SecondChildCreateTimeTAG: 2013-03-10T19:38:39Z
SecondChildVoteTAG: 0
FirstChildTAG: I think the problem here is the meaning of "within one inch of the average". For those of us who are not native English speakers that may be a confusing sentence....
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T22:25:40Z
FirstChildVoteTAG: 1
IndexTAG: 1090
TitleTAG: How are you planning to prepare for the midterm exam?
Suggestions?
Here are my plans, so far:
* Go through the entire Lecture/Exercise series, start to finish, all of it
* Utilize all the re-generating problems in SticiGui
* Load my shopping cart with Double-Chocolate Milanos; stock freezer with same
* Load my shopping carts on Amazon and Zappos; empty carts; buy more Milanos
UserIdTAG: 1235638
UserNameTAG: MyOwnCamera
CreateTimeTAG: 2013-03-09T00:52:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I think I need to reflect on a few things to make sure that I understand the concepts holistically. The exercises prove to me that I still far from comprehending the concepts as deeply as I would like. I understand enough to do fine on the exercises but still having some difficulty. Therefor what I understand is not enough. And I also overlook a few things. Like you, I will review the video lectures. But this time instead of just watching and taking notes, I will try to reflect along the way. I will redo the exercises while watching the videos. And I will experiment with different methods of solving the problems and also trying to prove that my methods are correct. I didn't do this before because of time constraint. But in order to master something, I guess I have to experiment with it. Watching video lectures, taking notes, and then do the exercises are not enough - at least that is what I find out for me. I really want to master Statistics and I now I know that I have to get down and dirty. In the past I was very reluctant to force myself to go the extra mile.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-09T02:31:19Z
FirstChildVoteTAG: 0
FirstChildTAG: I am at work daily from 8.00 am to 5.00 pm. In the house around 5.15 pm... tired and tired again. So, I can not even plan, just hope for the best really !!! The best that I can do, in these circumstances..
FirstChildUserIdTAG: 1128864
FirstChildUserNameTAG: mihaelagandy
FirstChildCreateTimeTAG: 2013-03-09T05:41:08Z
FirstChildVoteTAG: 0
IndexTAG: 1091
TitleTAG: where are the solutions
hi im from Ghana,where do I get the solutions to the exercises
UserIdTAG: 1266869
UserNameTAG: josaline
CreateTimeTAG: 2013-03-09T00:50:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Click on Show Answer for each question
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-09T00:58:17Z
FirstChildVoteTAG: 0
IndexTAG: 1092
TitleTAG: Midterm submission deadline
I was wondering how long we will have to submit the midterm questions. Do we have to finish it by the end of Wednesday?
UserIdTAG: 1330238
UserNameTAG: xeniosm
CreateTimeTAG: 2013-03-09T00:27:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: A final answer has not yet been given by the course team. The Prof. has said, on one of the many posts asking the same question, that we will certainly have at least a day.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-09T00:44:41Z
FirstChildVoteTAG: 1
SecondChildTAG: we have 48 hours. its due friday
SecondChildUserIdTAG: 970558
SecondChildUserNameTAG: nk0321
SecondChildCreateTimeTAG: 2013-03-12T01:46:34Z
SecondChildVoteTAG: 0
IndexTAG: 1093
TitleTAG: Practice for Exercise Set 7, Problem 6 - How to calculate z score?
How exactly does one determine that the "85th percentile is of the standard normal curve is z=1.036"?
UserIdTAG: 1259274
UserNameTAG: maylor
CreateTimeTAG: 2013-03-08T23:43:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I use the applet. Set the lower endpoint to -5, then drag the upper endpoint till the yellow area "all the way to the left" is 85%. I find that as I get close to the area I want, I have to start entering the digits by hand, as I'm not good enough at dragging. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-09T07:31:20Z
FirstChildVoteTAG: 1
SecondChildTAG: You can also move the endpoints with your arrow keys instead(or in addition to) dragging. Click once on the marker, then press the keys as needed.
*Very* convenient :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T14:49:46Z
SecondChildVoteTAG: 0
IndexTAG: 1094
TitleTAG: Slight differences between the applet and certain R functions [SOLVED]
I've been comparing the numbers given by the applet and some numbers that I obtain from R functions on standard normal distributions. There are slight differences. They might have something to do with the algorithm to compute areas. I'm curious to know the actual reason. I refrain from putting anything before the due date, assuming we are encouraged to use the applet.
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-08T23:25:39Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: any examples?
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T00:49:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Which R functions? pnorm reproduces the applet for everything I've thrown at it.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-09T15:03:41Z
SecondChildVoteTAG: 0
SecondChildTAG: I've been using pnorm and it works as you said, if I remember well.
I observed differences trying to produce simulations with rnorm and quantifying percentiles, but I need to reproduce my experiments. Sadly I didn't take note of the differences.
Either case differences are expected (I've thought after sending my post) due to the sd versus sigma issue (you know that all R functions rely on the sample sd instead of sigma).
I've had no time to come back to this, and errors from my part should not been discarded. I'll try to post something about the issue tomorrow (GMT time).
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-09T21:31:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Typo. I mean: "errors from my part should not be discarded ..."
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-09T21:45:31Z
SecondChildVoteTAG: 0
SecondChildTAG: I've reproduced my computations and this is what I've found.
Short answer: for what is needed in the exercises **there are not sensible differences**.
Long answer: `pnorm()` / `qnorm()` work as expected for standard and non-standard normal and match applet results. Differences raise when I try to produce samples with `rnorm()` and apply `quantile()` (or my own percentile function) instead of simply using `qnorm()`. It's expected due to the random nature of the generating process. Increasing the number of observations in the random sample reduces drastically the difference, as it also should be reduced by averaging multiple samples (not tested).
So far so good :)
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-10T11:51:21Z
SecondChildVoteTAG: 0
IndexTAG: 1095
TitleTAG: Problem 2 - Alternate 2
Another way of solving problem 2 is to determine the equation of the line:
y = mx + c
m = (y2 - y1) / (x2 - x1) = (2.8 - 0.4)/(54 - 42) = 0.2
y = 0.2x + c
To find c, plug in the 42 & 0.4 values:
0.4 = 0.2 . 42 + c , c = -8
y = 0.2x - 8
But the "proper" way is much simpler!
UserIdTAG: 1735
UserNameTAG: Stewart
CreateTimeTAG: 2013-03-08T22:54:18Z
VoteTAG: 3
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: I prefer this one in fact...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T00:54:06Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you!!!
SecondChildUserIdTAG: 759060
SecondChildUserNameTAG: RocioRosado
SecondChildCreateTimeTAG: 2013-03-10T15:28:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Stewart, you mix up the X and Y.
M = slope. And the slope is Rise over Run.
The Y should be the value 54 and 42.
The Z score should be on the X axis. And if you remember on the Histogram or Standard Normal Curve Z is on the X-axis.
So it should be
Y = ((54-42)/(2.8 - 0.4))* X + C
Y = (12/2.4)* X + C
Y = 5*X + C
To calculate for C
We pick any known Y and X. So we pick Y = 54 and X = 2.8
Y = 5X + C
54 = 5 * 2.8 + C
54 = 14 + C
54 - 14 = C
40 = C = the Average = Z = 0. C in this formula is the Average. And when we convert that to Z score it turns into 0.
So the finish formula is
Y = 5X + 40.
Thanks for Reminding me about this method. I completely forgot about this Linear Equation. And because of it I overlook the formula in the lecture
New List = A * (Old List) + B
This formula is the same as the
Y = M*X + C
Now that I try to prove this method of computation is also the right way to solve for this problem, I realize that or incorrectly believe 54 and 42 are on the Y-axis. They are not. 54 is the normal unit for this problem and the 2.8 is the standard Z-unit. 54 is also the value on the X-axis. If we convert 54 to the Z-value, it is 2.8 for this example. And 40 is the Average in normal unit. And if we convert it to the Z unit it would be 0. And the reason we make (54-42) as the Y and divided by (2.8 - 0.4) as the X in the calculation for M because we want to know how many normal unit are there per Z unit. So we divided it by Z.
Anyway, thank you for posting this thread because when I try to answer your question, I forced myself to reflect deeper and I realized I had overlook a few things because I got the right answer. I should keep this in mind going forward. Thank You.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-09T01:38:43Z
FirstChildVoteTAG: 0
SecondChildTAG: It's immaterial which axis you plot the normal units on, you'll still get the right answer. As we've both shown.
I'm not aware of any axis convention around plotting normal units verses standard units, so, unless someone can point us to a definition, neither of us has mixed up the x and y.
SecondChildUserIdTAG: 1735
SecondChildUserNameTAG: Stewart
SecondChildCreateTimeTAG: 2013-03-09T15:53:12Z
SecondChildVoteTAG: 0
SecondChildTAG: When I calculated A and B in the equation (Old List)=A*(New List)+B I tried to comprobate that the mean and sd are the corrects values to standarize (calculated the mean an sd of the Old List), but I am in doubt because these values are incorrect why?
SecondChildUserIdTAG: 945953
SecondChildUserNameTAG: Turca
SecondChildCreateTimeTAG: 2013-03-11T13:08:23Z
SecondChildVoteTAG: 0
IndexTAG: 1096
TitleTAG: Please Help - Problem accessing Practice Test - 7
I am having issues accessing Practice Set #7 and get below error.
Error: We're sorry, this module is temporarily unavailable. Our staff is working to fix it as soon as possible. Please email us at technical@edx.org to report any problems or downtime
Prof A/Tech Staff, please confirm if there is an issue and what is the ETA to resolve it. Can the practice questions be loaded somewhere else (wiki) in case the technical issue is not resolved?
I have tried multiple browsers and machines but issue persists. I also sent email to tech staff but no response yet.
Appreciate your help.
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UserNameTAG: nathyash
CreateTimeTAG: 2013-03-08T21:32:32Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 4
FirstChildTAG: I am in the same boat!
FirstChildUserIdTAG: 1181586
FirstChildUserNameTAG: eumannu
FirstChildCreateTimeTAG: 2013-03-08T21:47:27Z
FirstChildVoteTAG: 0
FirstChildTAG: I can access it. Windows 8, Chrome.
Sometimes I need to refresh pages multiple times before they load.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:50:24Z
FirstChildVoteTAG: 0
FirstChildTAG: Reading and Practice for Exercise Set 7
Week 3 lectures will cover the normal approximation for data histograms, which is not covered in the text. However, the main ingredients in the approximation are covered in the text in other contexts. The reading below takes you directly to those sections of the text; if you watch the video lecture segments then you will be able to follow the sections of the text recommended below, without needing to read the sections in between.
Lecture 4.4
Text Chapter 4
Affine Transformations: http://statistics.berkeley.edu/~stark/SticiGui/Text/location.htm#affine
We will focus on the mean and the SD, but transformations of other measures of location and spread are easy to follow and are described in the section. Try Exercise 4-9. You have already read the section on Markov and Chebychev; stop when you get there.
Text Chapter 8
Standard units
http://statistics.berkeley.edu/~stark/SticiGui/Text/computeR.htm#standard_units
Straightforward discussion; try Exercise 8-1. Every time you load the page, you get a different value to try. Stop when you get to Computing r.
Lec 5.1
Text Chapter 23
The normal curve
http://statistics.berkeley.edu/~stark/SticiGui/Text/clt.htm#normal_curve
The text uses the normal curve only in the context of probability distributions, which is why it appears much later that it does in Stat 2.1X. What it calls “the normal curve” is the standard normal curve. We will be using the applet that calculates areas under the standard normal curve; it appears in this section as well as a stand-alone program: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm.
If you need to use a “normal table” provided in a statistics textbook, the section explains how to do so. Stop when you get to The Normal Approximation to Probability Histograms.
Lec 5.2
Not covered in the text in a form that will be easy for you to follow at this stage. However, I expect that you will find the material straightforward once you have watched the video lecture segment. Some of the exercises below will help you practice the moves.
Here are some practice problems based on the material of Lectures 4.4, 5.1, and 5.2. For numerical answers, please follow the same guidelines as last week:
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:51:47Z
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FirstChildTAG: 5 of the 6 problems, though of course you can't see the answers.
A list of numbers has an average of 50 and an SD of 10. Is there a linear transformation that can be applied to the list to convert the SD to 30 but leave the average unchanged? [Yes, No, Not enough info]
Find the following areas under the standard normal curve, in percents. Please don't enter the percent sign.
1. between -1.2 and 0.5
2. to the right of 0.4
3. to the left of 0.4
Find the following percentiles of the standard normal curve.
1. 15th percentile
2. 70th percentile
Find the following areas under the normal curve with mean 170 and SD 16. Please provide the numerical answers in percents, but don't enter the percent sign.
1. between 154 and 186
2. to the right of 150
3. between 150 and 160
Find the following percentiles of the normal curve with mean 170 and SD 16.
1. 85th percentile
2. 30th percentile
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:59:34Z
FirstChildVoteTAG: 0
SecondChildTAG: can you please post the answers also?
SecondChildUserIdTAG: 1138594
SecondChildUserNameTAG: nathyash
SecondChildCreateTimeTAG: 2013-03-08T22:44:52Z
SecondChildVoteTAG: 0
IndexTAG: 1097
TitleTAG: Done?
As I've completed all 7 exercise sets with 0 errors, I've completed 7 out of 10 sets to be graded = 70%. As that counts for 50% of the total, I've reached the overall 35% minimum already. So I could stop now and still get a positive result... Just kidding, I'm just getting warmed up :-) Nice lectures! Although it's until now a little too easy for me, I'm enjoying it and I'm definitely taking some notions with me!
UserIdTAG: 900261
UserNameTAG: JRoest
CreateTimeTAG: 2013-03-08T20:30:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Be sure you really take those notions with you, I get the feeling we're going to need them for the upcoming Stat2.2x and Stat2.3x ;)
PS: There's also an Exercise Set 8 up :D
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T21:10:13Z
FirstChildVoteTAG: 2
IndexTAG: 1098
TitleTAG: Problem 7.
I took these steps yet my answer seems to be incorrect
1.Find the difference in percentiles
2. Find the difference in units.
3. Divide one by the other. This is your SD.
4. For the 60th percentile multiply 110 X the SD. Subtract this figure from 60 to get your mean. Repeat for 70th percentile and the mean numbers should match.
5. Use the formula (90-Mean)/SD. This gives you the 90th Percentile value.
Where am I going wrong? Thanks
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UserNameTAG: Davidgriffin10
CreateTimeTAG: 2013-03-08T20:17:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: David,
for
1)step 1 you need to use the Applet to find the Z or the Standard Unit for each percentile. Then you subtract the two Zs to get the difference. You subtract the Zs not the percentile.
2)then for step 2, you want to calculate calculate the difference between 110 and 120 at the 60th and 70th percentiles respectively = 10. This 10 is in the normal unit. But the Z is in a Standard Unit so you need to convert the Z to the normal SD unit.
3) This is why in step 3 you divide 10 by the Z. 10/z = SD
You are going in the right direction for the first 3 steps. However, you make mistakes at Steps 4 and 5.
4) For step 4 all you need to do is plug in the number for the known variables into the formula Z = (x - mean)/SD.
5) Do the same for step 5. Just make sure what are the known variables and what is the variable that you need to solve for each step.
Hope this helps.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-08T21:06:43Z
FirstChildVoteTAG: 0
SecondChildTAG: How many decimals in the "standard units"? And how many decimals in intermediate calculus?
SecondChildUserIdTAG: 1210009
SecondChildUserNameTAG: GIAN66
SecondChildCreateTimeTAG: 2013-03-09T10:16:31Z
SecondChildVoteTAG: 0
SecondChildTAG: That's no making great difference, but I took 3 and it was ok
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-09T14:52:39Z
SecondChildVoteTAG: 0
SecondChildTAG: 2 or 3 decimals are enough with all steps.
Personally, I use 2 almost always, except in cases like 1.2963 that would round to 1.30, since I hate doing that. However, that's just me :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T14:54:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Dear all, many thanks.
SecondChildUserIdTAG: 1210009
SecondChildUserNameTAG: GIAN66
SecondChildCreateTimeTAG: 2013-03-09T17:25:12Z
SecondChildVoteTAG: 0
IndexTAG: 1099
TitleTAG: Alternative way of solution of Exercise set 7, Problem 7? I had the right answer!
I had a different way of finding the answer, without reckoning the SD and the average first.
I looked up: 60th percentile: z=0.253, the 70th percentile: z=0.524, 90th percentile: z=1.282. Difference between 70th and 60th percentile: 0.524 - 0.253 = 0.271, that is also the difference 120-110=10.
Now I took an alternative way of reckoning:
Difference between 90th and 70th percentile: 1.282 - 0.524 = 0.758. 0.758 is X times 0.271, so I divided: 0.758:0.271=2.797. 2.797 means the multiplication factor of 0.271 (0.271 was the difference between 70th and 60th percentile, in other terms:120-110=10). So I multiplicated: 2.797*10=27.97. So the difference between the 70th and 90th percentile is 27.97. From the 70th to the 90th percentile: 120+27.97=147.97. This answer was correct. I don't know if this is a clumsy way of finding the answer. I would appreciate ver y much if the prof would give a critical commentary on this alternative way: is it good or does it show that I cannot apply the SD and the average like I'm supposed to do?
UserIdTAG: 1144814
UserNameTAG: Krooswijk
CreateTimeTAG: 2013-03-08T20:13:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: Perhaps we should wait until the due date is past before discussing these procedures in detail?
I know the forum is likely going to be overwhelmed by questions about the midterm on the 14, but, ES 7 and 8 are still open, so please don't reveal solutions(valid or not) until then.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T21:05:27Z
FirstChildVoteTAG: 0
FirstChildTAG: Your method is fine. It uses proportionality rather than the parameters of the distribution, and I don't think it's any more or less clumsy than any other method. But I agree with Klionheart: many students are still working on these problems so please find a way to ask questions in greater generality. Thanks,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-08T21:20:10Z
FirstChildVoteTAG: 0
SecondChildTAG: I used the same method, and my 2nd decimal wasn't the same, but still, got the right answer.... the problem is: I feel like it is a very nasty way to get to the solution. I had 60th 70th and 90th zs, but my calculator isn't good enough to manage such a formula...
I have to say that, except for the average, I have no clue on how to use excel types software,thus:pen and paper. But it really has its limits!!!
I submitted every set 7 response the max time, so if I could get an explanation on that (1/squroot(2pi))square 1/....even typing it is a mess ^^;;;;
In advance,thank you Prof A.!!!!
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-03-11T23:08:52Z
SecondChildVoteTAG: 0
FirstChildTAG: You are very clever making calculations but a bit silly giving the answers to problems people is still working on...
You should be reprimanded in my opinion.
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-09T14:58:21Z
FirstChildVoteTAG: 1
SecondChildTAG: tar and feathers?
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-09T16:50:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Make him(her?) walk the plank! xD
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T17:14:14Z
SecondChildVoteTAG: 0
IndexTAG: 1100
TitleTAG: applet usage help
The arrow keys on my laptop, Macbook Pro, move the SticiGui applet slider buttons in .02-.03 increments. This much easier than trying to drag the slider buttons. Of course, you want to get close by dragging first.
UserIdTAG: 1259984
UserNameTAG: mcc
CreateTimeTAG: 2013-03-08T19:49:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1101
TitleTAG: Midterm
First time using Edx and I'm wondering if someone could give me some insight on how it works. I understand that it is next wednesday, is it just like another assignment that needs to be done some day? How much time do we have to complete it?
Thank you ahead of time!
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UserNameTAG: Ingrid90
CreateTimeTAG: 2013-03-08T19:35:18Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: My previous experience with Edx is that midterms and finals usually have a relatively short window of time in which they can be started, generally a few days(but less than a week).
In addition, a shorter personal timer(24 hours is the maximum I've seen) starts once you *begin* the test.
As for **this** test, we are still waiting for the details, and don't know much beyond the starting date. Earlier comments suggest we'll only have a day in total, but, we'll see.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T19:55:53Z
FirstChildVoteTAG: 3
SecondChildTAG: you mean that it may be as the same as exercises in their style, but with shorter available time??
SecondChildUserIdTAG: 1065475
SecondChildUserNameTAG: Alshymaa
SecondChildCreateTimeTAG: 2013-03-08T20:57:46Z
SecondChildVoteTAG: 0
SecondChildTAG: Basically, yes.
And hopefully with a more strict enforcement of the honor code in the forums...
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T21:07:33Z
SecondChildVoteTAG: 0
SecondChildTAG: The forum should be shut to posting during the exam. That's how other courses have worked.
I think on Coursera they keep them open, but people are told that any exam post results in instant expulsion from the course.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-08T21:19:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Does anyone know how long it takes to know our result on the exam ? Will it take a week for us we see our grade ? or is it posted as soon as we finish ?
SecondChildUserIdTAG: 1133230
SecondChildUserNameTAG: KarinaVids
SecondChildCreateTimeTAG: 2013-03-09T04:18:47Z
SecondChildVoteTAG: 0
SecondChildTAG: SusanAust & Klionheart - You guys are very active in the discussion forum and the whole course in general !! Really helps.. Keep it up !! I've a really packed schedule right now so it's a bit tough to be participative here.
Would be great to know more about each other :)
Ping me on Facebook - https://www.facebook.com/Nitish.Raole
SecondChildUserIdTAG: 379141
SecondChildUserNameTAG: NitishRaole
SecondChildCreateTimeTAG: 2013-03-09T13:22:36Z
SecondChildVoteTAG: 0
IndexTAG: 1102
TitleTAG: Please improve your production values.
It appears that the course is merely composed of recorded class room lectures. The lectures for exercise 7 include a snapshot of pages from the text. However, there are also inaudible questions being asked and audible answers are given. Hearing the questions would enhance the purpose of the question. If the question and its answer are unimportant, please edit them out. Also, from the sounds heard, one surmises that there is some scratching going on at the blackboard, but we are not able to see what is being done. Perhaps the camera could have shown what was being put on the blackboard.
Please - improve the production values of the lectures to match the importance of that which is taught. I think the subject is worthy of the effort.
UserIdTAG: 769852
UserNameTAG: MRArthurDent
CreateTimeTAG: 2013-03-08T19:12:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Please look under Courseware. The class consists of a sequence of lecture segments recorded specifically for Stat 2.1X. The online text and the video lectures that are part of the text are supplements. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-08T21:15:40Z
FirstChildVoteTAG: 4
IndexTAG: 1103
TitleTAG: Is 35% a passing score at Berkeley?
If it is not, then why have such dramatically lower expectations for the online students?
Many other EdX courses (such as 8.02x, for example) have tried to make the experience equivalent to the corresponding university course to the extent possible. I'm a bit puzzled about Stat 2.1x's approach - the passing grade almost seems like a typo.
UserIdTAG: 1043
UserNameTAG: jon31
CreateTimeTAG: 2013-03-08T18:54:13Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 7
FirstChildTAG: I think is about how many students they can retain. In other edX classes more than 90% of the people that opened the first PS (not the ones that originally signed for the class, that number is 5 times bigger) were "lost" on the way to the end. My guess is that such a low passing grade is trying to minimize this percentage.
In a conventional class, after you have paid $40.000, nobody is going to quit if a 70% is required (or 90%).
I don't agree with such a low number, or at least not without the possibility of other grades (60%, 80%,...), but I feel that is how they are thinking.
FirstChildUserIdTAG: 1024715
FirstChildUserNameTAG: iparrajorge
FirstChildCreateTimeTAG: 2013-03-08T19:35:19Z
FirstChildVoteTAG: 1
SecondChildTAG: and i agree with you. if they want high percentage of students that have passed then the limit should be zero and we all should get certificates upfront. btw, i have already earned certificate and there wasnt even midterm yet. isnt that silly? all other thing in the coulse are pefect. with such low limit of 35% they think bad about themselves. they are not sure if they are theaching right. what i can say is: "yes guys, you are doing that very well, you shouldnt underestimate yourselves". cheers
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T20:22:03Z
SecondChildVoteTAG: 0
FirstChildTAG: The problem is that it devalues the certificate. By extension, it devalues all EdX certificates.
FirstChildUserIdTAG: 1043
FirstChildUserNameTAG: jon31
FirstChildCreateTimeTAG: 2013-03-08T19:57:37Z
FirstChildVoteTAG: 3
SecondChildTAG: I agree completely
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T20:14:48Z
SecondChildVoteTAG: 0
SecondChildTAG: agreed..
SecondChildUserIdTAG: 303485
SecondChildUserNameTAG: iparitosh
SecondChildCreateTimeTAG: 2013-03-09T04:13:07Z
SecondChildVoteTAG: 0
SecondChildTAG: That is seriously stretching of the courses. it would for me be a big issue if I was getting credit for this class but we are not.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-09T07:28:03Z
SecondChildVoteTAG: 0
FirstChildTAG: As has been commented many times, the Prof explained this. From memory, she set the bar low for *this* course so as to encourage those new to stats and edX - there are those here who are total novices and are already struggling. Don't expect the same for the next two courses.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:08:35Z
FirstChildVoteTAG: 2
FirstChildTAG: Stat2.1x is lasting one month which is on average one 3rd of the other courses.
However we know now from Prof A that Stat2.2x and Stat2.3x may follow.
At Berkeley, it is likely that all three count as one for the final grade.
Please just enjoy Stat2.1x and its certificate for now and I wish good luck to all of you who might continue with Stat2.2x and 2.3x.
Z.
FirstChildUserIdTAG: 830835
FirstChildUserNameTAG: Zacharie
FirstChildCreateTimeTAG: 2013-03-08T23:31:58Z
FirstChildVoteTAG: 3
FirstChildTAG: One question that occurs to me and which I haven't seen addressed is whether the suite of courses (Stat2.1-3x) might be considered for overall certification. That is to say, by passing all three courses a certificate be awarded for Stat2x (or whatever the naming convention). This would reflect the modular approach taken by many courses and better match the on campus version. It might also address some of the concerns expressed about the difficulty level of Stat2.1x.
There would then be 4 certificates available, Stat2.1x, Stat2.2x and Stat2.3x representing the current (and planned) five week courses with an overarching Stat2x certificate for the full semester course. Students could continue to choose to complete only one or two of the modules if this suited their needs.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-09T00:30:10Z
FirstChildVoteTAG: 3
SecondChildTAG: This is an interesting suggestion, and one that I've considered but not raised with EdX. Stat 2 at Berkeley consists of all three pieces, so it would make sense to acknowledge students who have taken all three modules online. I'm not sure whether this is possible but I'll look into it. Thanks, PaulJM. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-09T07:38:39Z
SecondChildVoteTAG: 0
SecondChildTAG: As a scholar, I really like this suggestion. I hope that it will be possible for those who continue on with Stat 2.2 and 2.3 to obtain an overall certification for completing the entire course.
SecondChildUserIdTAG: 1394646
SecondChildUserNameTAG: DevorahKat
SecondChildCreateTimeTAG: 2013-03-10T03:32:26Z
SecondChildVoteTAG: 0
SecondChildTAG: PaulJM has a terrific idea. And thanks to Prof. A. for agreeing to look into it.
Incidentally, can Prof. A. share any data about the academic success rate of those (such as scores on a mid-term or mini review test in combination with problem sets) at Berkeley who complete whatever the course modular equivalent is to edX Stat2.1x? If it's anything close to the Stat2.1edX 35% then there's less reason to grumble about the 35% pass mark.
SecondChildUserIdTAG: 11318
SecondChildUserNameTAG: JMcGlynn
SecondChildCreateTimeTAG: 2013-03-22T03:21:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Very good suggestion...!
SecondChildUserIdTAG: 1023900
SecondChildUserNameTAG: LA75
SecondChildCreateTimeTAG: 2013-03-29T07:17:14Z
SecondChildVoteTAG: 0
FirstChildTAG: this course did not provide any materials that can be printed easily, everything is available online, so 35% is an acceptable passing score for those who never learned stats.
Every week I attempted the marked exercise first, and mostly I got more than 35%, using my previous stats knowledge & without any printed materials, I am struggling to continue this course...
FirstChildUserIdTAG: 199205
FirstChildUserNameTAG: ririana
FirstChildCreateTimeTAG: 2013-03-09T04:47:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Nothing wrong with a low pass mark of 35, if and only if, there is also recognition for better marks. How about awarding merit for 60% and distinction for 80%? It costs nothing for EdX to issue three different types of certificate and would be a motivator for many to try and hit the higher targets.
FirstChildUserIdTAG: 901827
FirstChildUserNameTAG: clv101
FirstChildCreateTimeTAG: 2013-03-12T16:08:50Z
FirstChildVoteTAG: 1
IndexTAG: 1104
TitleTAG: 3a y 3b
y=5x-1 ????
UserIdTAG: 1107978
UserNameTAG: betoagto
CreateTimeTAG: 2013-03-08T18:31:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: What does that even mean?
FirstChildUserIdTAG: 92101
FirstChildUserNameTAG: DarylHickey
FirstChildCreateTimeTAG: 2013-03-08T19:09:04Z
FirstChildVoteTAG: 0
FirstChildTAG: There must be a second equitation to form a linear system;
FirstChildUserIdTAG: 1024621
FirstChildUserNameTAG: pronko
FirstChildCreateTimeTAG: 2013-03-08T19:22:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Close, but no.
Something's missing...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T19:58:40Z
FirstChildVoteTAG: 0
IndexTAG: 1105
TitleTAG: week 3 exercise 7
i really did not understand this week 3. my worst performance.
UserIdTAG: 222188
UserNameTAG: DrArya2012
CreateTimeTAG: 2013-03-08T18:12:49Z
VoteTAG: 3
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: Dr, this was my toughest week for the exercises. I think I've got the info during the lectures, but when I get to really test my knowledge on the problems, it is not so clear. That is why I like this course - it makes me feel like the effort is worthwhile, and maybe, just maybe, I am learning a thing or two.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-08T19:09:19Z
FirstChildVoteTAG: 3
SecondChildTAG: me too
SecondChildUserIdTAG: 1065475
SecondChildUserNameTAG: Alshymaa
SecondChildCreateTimeTAG: 2013-03-08T21:00:25Z
SecondChildVoteTAG: 0
SecondChildTAG: joinig to the club..I am frustrated. I hope upcoming exercises wont ask us to do linear tranformations...My alegbra is poooor
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-08T22:51:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Agreed, this was tough. I spent a lot of time working with pen and paper, writing out all my assumptions in longhand (and sometimes discovering my own mistakes when I did so), and double-checking my math. I found it helped to spend some time playing with the normal curve applet at http://statistics.berkeley.edu/~stark/SticiGui/Text/clt.htm#normal_curve just to understand the concepts better.
FirstChildUserIdTAG: 1154356
FirstChildUserNameTAG: TomFaber
FirstChildCreateTimeTAG: 2013-03-08T20:09:40Z
FirstChildVoteTAG: 2
SecondChildTAG: it's really a good question to solve. Wasn't tough, just a few toilsome.
SecondChildUserIdTAG: 1276711
SecondChildUserNameTAG: Buarque
SecondChildCreateTimeTAG: 2013-03-13T04:55:19Z
SecondChildVoteTAG: 0
FirstChildTAG: I sure learned one thing right away - draw it! If you can understand the problem well enough to draw it out, that is a very good start. It also catches some thinking errors.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-08T22:23:57Z
FirstChildVoteTAG: 0
IndexTAG: 1106
TitleTAG: the 80th percentile calculation
I thought if the 80th percentile of the 6 entries is 4.8,then it lies within 4&7 not 7&7 like its being demonstrated,Can anyone clarify on this issue.Its getting me confused.
UserIdTAG: 596280
UserNameTAG: Rousseus
CreateTimeTAG: 2013-03-08T17:04:58Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 1
FirstChildTAG: First, 4.8 is not the 80th percentile. 7 is the 80th percentile.
It helps to remember that the percentile process always returns an actual member of the list. 4.8 is not a member of the list.
Look at the part of the lecture that goes over this; the answer is actually given on one of the slides.
Let me know if you need more help.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-08T19:30:24Z
FirstChildVoteTAG: 0
IndexTAG: 1107
TitleTAG: Practice for Exercise Set 7
Help!! I cannot access practice for Exercise SET#7. Sent e-mail to technical staff but still unavailable. Message i seen is as follows
There has been an error on the edX servers
We're sorry, this module is temporarily unavailable. Our staff is working to fix it as soon as possible. Please email us at technical@edx.org to report any problems or downtime.
UserIdTAG: 1181586
UserNameTAG: eumannu
CreateTimeTAG: 2013-03-08T17:00:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: reload it now.I can see it.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-08T17:07:54Z
FirstChildVoteTAG: 0
SecondChildTAG: Works for me too. Try cleaning your browser cache if it's still refusing to work for you.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T17:51:49Z
SecondChildVoteTAG: 0
IndexTAG: 1108
TitleTAG: Exercise 7 problem 5
Are we allowed to use the Normal Curve applet for this question?
UserIdTAG: 1259026
UserNameTAG: sahilratra
CreateTimeTAG: 2013-03-08T17:00:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I hope so!!!
FirstChildUserIdTAG: 92101
FirstChildUserNameTAG: DarylHickey
FirstChildCreateTimeTAG: 2013-03-08T19:10:50Z
FirstChildVoteTAG: 0
FirstChildTAG: You have posted in the wrong subforum.
How to use the forums properly (scroll to bottom):
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/51320ee24bebda2b000000c4
>Are we allowed to use the Normal Curve applet for this question?
Given they link to the applet, one would assume so. But you could just as easily do it with a set of tables.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:16:40Z
FirstChildVoteTAG: 0
SecondChildTAG: Sorry for the format !!
SecondChildUserIdTAG: 1259026
SecondChildUserNameTAG: sahilratra
SecondChildCreateTimeTAG: 2013-03-10T13:01:03Z
SecondChildVoteTAG: 0
IndexTAG: 1109
TitleTAG: When will this course be offered again?
As I have just found out about edx yesterday, I am two weeks behind this course and is concerned about not being able to receive a passing grade.
Can someone please advise when this course will be taught again, so I can decide if I should play catch-up or wait until the new course begins?
Thanks!
UserIdTAG: 1387949
UserNameTAG: xilef0610
CreateTimeTAG: 2013-03-08T16:39:46Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It should still be fairly easy to receive a passing grade, with the 35% threshold.
The best you can still get is an 80% grade, so there's quite a lot of margin for error too :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T17:05:31Z
FirstChildVoteTAG: 0
IndexTAG: 1110
TitleTAG: Statistical Understanding: To the nearest inch.
> or < or = or ~
Any one of the above or any mix.
UserIdTAG: 344400
UserNameTAG: carlallen
CreateTimeTAG: 2013-03-08T16:27:38Z
VoteTAG: 6
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 3
FirstChildTAG: In these terms...
$x-0.5 \le x \le x+0.5$
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T16:50:54Z
FirstChildVoteTAG: 3
SecondChildTAG: Not quite sure what you're getting at. It is always true that x-.5 < x, and that x < x+.5; that has nothing to do with "the nearest inch." I think that you are using x to represent two different things.
In measurements made to-the-nearest-something, there's some "true" value y and some measured value x. If x is supposed to be the value of y measured to the nearest inch, then
x−0.5" ≤ y ≤ x+0.5"
Cheers,
Philip
SecondChildUserIdTAG: 990671
SecondChildUserNameTAG: pstark
SecondChildCreateTimeTAG: 2013-03-08T17:13:07Z
SecondChildVoteTAG: 0
SecondChildTAG: I meant *"x is between x-0.5 and x+0.5, extremes included"*, x being a valid value for the range we are considering. Just like in $1 \le x \le 2$.
That said, yours is the more precise statement, mathematically speaking. Mine was a rough statement intended for ES8, Problem 1B, which is what I'm assuming carlallen was wondering about ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T17:50:04Z
SecondChildVoteTAG: 0
SecondChildTAG: ...rereading, I realize I'm just sprouting nonsense.
Yes, I mixed up x as a valid value for the range, with x as the central value for the range.
$ x−0.5" \le y \le x+0.5" $ is the correct one. x is the central value, y the valid value.
Sorry for the confusion :|
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T17:58:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Glad to see you here, Prof. Philip! Awesome course and great SticiGui textbook!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-09T21:19:11Z
SecondChildVoteTAG: 0
SecondChildTAG: @pstark: Thanks for clarification
SecondChildUserIdTAG: 99047
SecondChildUserNameTAG: taminur
SecondChildCreateTimeTAG: 2013-03-12T13:05:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Klionheart is correct. Problem should have stated to the nearest half inch, not inch. With two decimal places, one would assume from the question that it would be calculated from 69.99 inches to 70.01 inches, but you know what they say about assuming ...
FirstChildUserIdTAG: 1278827
FirstChildUserNameTAG: kb1334
FirstChildCreateTimeTAG: 2013-03-08T17:09:04Z
FirstChildVoteTAG: 1
SecondChildTAG: Klionheart didn't say that "to the nearest inch" wasn't correct, just that the limits are half a unit either side. It's simple number rounding. If you take something to the nearest whole number then e.g. 8.49 would be nearest to 8, while 8.50 would round up to 9.
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-08T22:21:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Patey ... i did a half on each side initially forgetting about the rounding. When rounding anything below a .5 rounds down. Thank you
SecondChildUserIdTAG: 1202785
SecondChildUserNameTAG: sjmadden
SecondChildCreateTimeTAG: 2013-03-10T13:38:03Z
SecondChildVoteTAG: 0
FirstChildTAG: All the question is implying is rounding. Heights are measured on a continuous scale. I could be 71.2635478 inches tall, for example. The question wants only to deal in inches. So what is my height 'to the nearest inch'? Hopefully you would see that by normal rounding it would be 71 inches.
So, now we have decided what the question means, you just have to decide what range of heights would round to the target value. If the target were 71 inches then (using the example figure I gave earlier) I would be included in that range. If my friend's height were 71.6 inches he would be outside the range (as that would round to 72 inches).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-09T00:38:45Z
FirstChildVoteTAG: 1
SecondChildTAG: definitely, my English isn't good enough....
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-09T22:40:50Z
SecondChildVoteTAG: 0
SecondChildTAG: I was frustrated that 69.5 (the lowest one-decimal value that could be rounded to 70) to 70.4 (the highest one-decimal value that could be rounded to 70) was incorrect.
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-03-12T19:50:10Z
SecondChildVoteTAG: 0
IndexTAG: 1111
TitleTAG: Staff: Problem 3 Solution of Exercise Set 6!
Dear Prof,
Please, can you throw more light on Problem 3 solution? Its quite confusing. Is it a typo-graphical error or what else could it be! Please, I need more clarification.
Thanks
UserIdTAG: 1114838
UserNameTAG: abass01
CreateTimeTAG: 2013-03-08T15:27:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: There is no error of any kind. It's well-explained in the solution.
What's the part that doesn't convince you?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T15:33:10Z
FirstChildVoteTAG: 0
SecondChildTAG: One of the statement made in the solution: "So List B has the same average as List B" that is one and the other one is "So the root mean square of its deviations will be smaller than that of List B." The ans says "The SD of List A is greater than the SD of List B." Hope you understand my point now?
SecondChildUserIdTAG: 1114838
SecondChildUserNameTAG: abass01
SecondChildCreateTimeTAG: 2013-03-09T10:55:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Woops. I do. My bad! I focused so much on the explanation for the method that I overlooked those two typos.
But, that's all they are. Two fairly obvious typos. "So List B has the same average as List **A**" and "So the root mean square of its deviations will be smaller than that of List **A**".
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T16:43:39Z
SecondChildVoteTAG: 0
FirstChildTAG: This may be a bit of cheating, but if you work it out by hand or in a spreadsheet, the answer should be clear. Just make up a few numbers for List A, say 5 or so, and then go through the SD process for Lists A and B.
FirstChildUserIdTAG: 945111
FirstChildUserNameTAG: judithpdx
FirstChildCreateTimeTAG: 2013-03-08T16:37:32Z
FirstChildVoteTAG: 0
IndexTAG: 1112
TitleTAG: 3a & 3b
I apologize if it is annoying for you but hi I'm Still struggling with 3a ,I try to( multiply the avrg right in 5) and then subtract (the avrg wrong in 1)and divide the overall results by 5 the result is 5.44 and of course it is wrong ,
I can't even think how to deal with 3b yet.
Any help will be appreciated
UserIdTAG: 1019661
UserNameTAG: wnu
CreateTimeTAG: 2013-03-08T15:18:01Z
VoteTAG: 5
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 5
FirstChildTAG: You said you took three steps:
1) multiply the avrg right with 5
2) subtract the avrg wrong*1
3) divide the overall results by 5.
Think about each step, why you do it (if it is necessary).
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-08T15:26:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Trying not to give too much away: you are transforming an average, not a total.
3b requires you to write down the transformation as a formula involving a multiplicative constant, and an additive constant. Something like $y=m*x+c$ (with m and c as constants, of course).
And then remembering how the SD is affected by transformations.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T15:30:21Z
FirstChildVoteTAG: 0
FirstChildTAG: You are quite close, but not quite applying the right transformation.
The way I approached this was to write down an equation that enables the score to be calculated using the number of correct answers only. With this you will see clearly the linear transformation that relates the number of correct answers to the score awarded. 3a and 3b should then be easy to calculate as was demonstrated in the lectures.
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-03-08T15:31:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you guys , I may try it again tomorrow but what really buzzing me at the moment is that I didn’t digest the question . for me and I say in hypothetical situation ,where the average of class is 5 right answer out of 10 and when apply the rule of 5 point for each right one and -1 for each wrong one the average point is 20 and in term of right answer it is20/5=4,so now the average right answer is 4 instead of 5.it look like should start fresh because I'm obviously now missing a key point .
FirstChildUserIdTAG: 1019661
FirstChildUserNameTAG: wnu
FirstChildCreateTimeTAG: 2013-03-09T10:31:05Z
FirstChildVoteTAG: 0
SecondChildTAG: I solved it considering the data as 2 different curves with 2 different transformations which are combined at the end. Cannot say more, hope it helps.
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-09T15:09:06Z
SecondChildVoteTAG: 0
SecondChildTAG: What is "20/5=4"? Looks like an attempt at an inverse formula, but it's missing something.
Think in terms of x=number of right answers, as the problem text suggests. Figure out the equation to go from "No. of Right Answers" to "Score" for any x.
The rest should come on its own.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T16:51:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Well I'm looking at the answers right now but Is it me or the wording of problem 3 is inconsistent with the answer provided for it.
Here is the problem :-
*In the quiz in Exercises 1 and 2, the grading scheme is as follows: each right answer is awarded 5 points, and 1 point is taken off for each wrong answer. Recall that the quiz consists of 10 questions, and that in the class, the average number of right answers is 6.2 and the SD of the number of right answers is 1.4. In what follows, it will help to express a student’s score in terms of the number of right answers the student got.
*The question ask for :- student’s score in terms of the number of right answers the student got.**
And since each right answer is awarded 5 points, aren’t we suppose to divide whatever result we got (as long as it is in term of points )over 5 which is what each right answer is worth in this situation.
FirstChildUserIdTAG: 1019661
FirstChildUserNameTAG: wnu
FirstChildCreateTimeTAG: 2013-03-10T15:08:42Z
FirstChildVoteTAG: 1
IndexTAG: 1113
TitleTAG: Midterm Exam
Will the exam be solved with the same style of exercises? or will be at certain limited time?
UserIdTAG: 1065475
UserNameTAG: Alshymaa
CreateTimeTAG: 2013-03-08T15:04:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: And when will it be available for us to do it? On March the 13th? Or that date is the due date only???
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-08T18:28:44Z
FirstChildVoteTAG: 0
SecondChildTAG: its most probably both available and due on the 13th. i just really wana know already how much time we have to complete it from the time we open the file or like how that part is gona work.
SecondChildUserIdTAG: 985560
SecondChildUserNameTAG: zoe3456
SecondChildCreateTimeTAG: 2013-03-08T23:21:51Z
SecondChildVoteTAG: 0
FirstChildTAG: Why not use one of the dozens of posts already created about this? Or wait for the official announcement. Until then everyone is second guessing.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:13:39Z
FirstChildVoteTAG: 1
SecondChildTAG: i wish they would tell us already.. its like are they gona let us know ON the actual day of the midterm itself that we only have an hour to complete it from the time we view the questions or something sheesh. i wish they would give us some advance notice but it doesnt seem like they will n i hope we have at least 2 hours to complete it. how was it in your last edx class?
SecondChildUserIdTAG: 985560
SecondChildUserNameTAG: zoe3456
SecondChildCreateTimeTAG: 2013-03-08T23:20:04Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm afraid about that.Most of us aren't full-time students & Wednesday will not be a weekend; the matter will be hard in this way. I think this matter is well-known for the staff and they will take it into consideration.
SecondChildUserIdTAG: 1065475
SecondChildUserNameTAG: Alshymaa
SecondChildCreateTimeTAG: 2013-03-09T16:27:34Z
SecondChildVoteTAG: 0
IndexTAG: 1114
TitleTAG: Staff: Technical Suggestion
In the videos to introduce the lectures, where the Professor appears in front of the camera, the volume is ok, however, in the lectures themselves the volume is lower, poor.
For an English native speaker this may be irrelevant, but I guess that for the rest of us it isn’t, because we need to listen as clear as possible to improve our understanding.
So, could you do something to solve this in the further lectures? I mean, making the Professor’s voice louder.
Thank you.
UserIdTAG: 797704
UserNameTAG: Hersan13
CreateTimeTAG: 2013-03-08T14:58:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I agree, the lecture's volume seems lower. And I have external speakers connected to my laptop and it still doesnt help much...
FirstChildUserIdTAG: 1288995
FirstChildUserNameTAG: olsolis
FirstChildCreateTimeTAG: 2013-03-08T15:04:56Z
FirstChildVoteTAG: 0
SecondChildTAG: I usually download the video and listen to it using VLC at 150% volume, so it's fine xD
But, I had to watch Lecture 5.4 on the page since there's no download link, and yes, it is a bit low. Wouldn't be a bad idea to fix it :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T15:12:30Z
SecondChildVoteTAG: 0
SecondChildTAG: use earphones
SecondChildUserIdTAG: 1259026
SecondChildUserNameTAG: sahilratra
SecondChildCreateTimeTAG: 2013-03-08T17:03:49Z
SecondChildVoteTAG: 0
SecondChildTAG: I use earphones. The volume is low.
SecondChildUserIdTAG: 797704
SecondChildUserNameTAG: Hersan13
SecondChildCreateTimeTAG: 2013-03-08T18:45:12Z
SecondChildVoteTAG: 0
SecondChildTAG: volume is low even with head phones
SecondChildUserIdTAG: 1144890
SecondChildUserNameTAG: ltavares
SecondChildCreateTimeTAG: 2013-03-13T02:34:48Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree. The lectures' volume seems lower. I have external speakers connected to my laptop computer and it still doesnt help...
FirstChildUserIdTAG: 1288995
FirstChildUserNameTAG: olsolis
FirstChildCreateTimeTAG: 2013-03-08T15:06:18Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks for the heads-up. I'll tell the video production staff. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-08T21:16:49Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks. I virtually have to hold the smartphone to the ear or on the desktop ramp up the volume full blast to just hear it in some videos !! One thing though is that it makes you really pay attention ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T03:16:44Z
SecondChildVoteTAG: 0
IndexTAG: 1115
TitleTAG: midterm exam timing
Hi, I just want to ask about midterm exam, is it on the same day of posting the exam or i can submit the answers of the exam to be marked by the weekend as i am a doctor and i am oncall on the week of the midterm exam and i do not want to miss it. looking forwrad to hear from you. thansk.monaBlue
UserIdTAG: 1182746
UserNameTAG: monaBlue
CreateTimeTAG: 2013-03-08T14:52:50Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: We are still waiting for the details, but it's likely going to be *at most* a 48-hour window to do the midterm, possibly even 24-hour. Don't count on having a week.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T14:56:29Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi there,
When will the midterm exam be posted and open to us? On March the 13th??
Thanks!
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-08T18:33:42Z
FirstChildVoteTAG: 0
SecondChildTAG: That's what the info page says.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-11T02:21:29Z
SecondChildVoteTAG: 0
FirstChildTAG: As the Prof said on the Course Info page, details soon.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:12:42Z
FirstChildVoteTAG: 0
IndexTAG: 1116
TitleTAG: The SD for the Berkeley temp into Fahrenheit
When Professor was converting the SD to Fahrenheit, the calculation was F = (9/5) x5
Am i wrong in thinking that it should be F = (9/5) x5 +32?
UserIdTAG: 263420
UserNameTAG: mmccue
CreateTimeTAG: 2013-03-08T14:50:40Z
VoteTAG: 0
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 1
FirstChildTAG: Yes. Remember that the SD isn't affected by the shift. (the constant you add or subtract in a trasformation).
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T14:53:27Z
FirstChildVoteTAG: 7
IndexTAG: 1117
TitleTAG: Late for the course
What should I do I have just joined the class and I have just found out that I am so behind with the syllabus, what should I do?? Help
UserIdTAG: 1379448
UserNameTAG: Phindaseanhlubi
CreateTimeTAG: 2013-03-08T14:30:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You should sit over the week end and go through all the videos and practice the exercises.It is not as tough as it seems.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-08T14:41:10Z
FirstChildVoteTAG: 0
FirstChildTAG: First of all, read the Course Info, cause there is basically all the information you need for your next steps.
There is an mid term exam coming up on March 13. The current exercises are due next week. For week 1 and 2, the deadline is over. You can still get enough points for the certificate, but it's probably gonna be a busy week. Have fun!
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-08T14:43:06Z
FirstChildVoteTAG: 0
FirstChildTAG: You should get stuck into the work.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T21:09:05Z
FirstChildVoteTAG: 0
IndexTAG: 1118
TitleTAG: Problem 2 - Alternate method.
Problem 2 can be also solved using simple algebra.
We know z=(x-avg)/SD. Hence SD=(x-avg)/z. The table in Prob 2 has x (original unit) on the left hand side and z (standard unit) on the right hand side. We now have to find the avg and the SD, both of which are non-variables, i.e they have a constant value.
Thus, SD=(54-avg)/2.8 . Now since the SD is the same for all values given above, we can equate this as follows: (54-avg)/2.8 = (42-avg)/0.4 or 0.4(54-avg)=2.8(42-avg). Solve this equation and u get the average. Now use the average to find the SD (eg. (54-avg)/2.8). That gives us everything required to solve the problem. :)
UserIdTAG: 933932
UserNameTAG: Shadybog
CreateTimeTAG: 2013-03-08T14:08:11Z
VoteTAG: 2
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Yeah, that's almost how I did it at first, too. Except I ended up calculating the SD first, then the average.
Then I looked at the solution, and kicked myself for over-complicating things xD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T14:25:41Z
FirstChildVoteTAG: 1
SecondChildTAG: Me too Klionheart me too !
SecondChildUserIdTAG: 773907
SecondChildUserNameTAG: Redouanekh
SecondChildCreateTimeTAG: 2013-03-08T18:44:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too! I've used algebra. I don't think is overcomplicated. Algebra is there for something (= for everything ;-) ) Though the provided solution is in some sense closer to the essence of the matter.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-08T23:36:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for this post. It was very useful in arriving at the answer
SecondChildUserIdTAG: 800765
SecondChildUserNameTAG: isaacabah
SecondChildCreateTimeTAG: 2013-03-10T18:09:15Z
SecondChildVoteTAG: 0
IndexTAG: 1119
TitleTAG: Question 1C heights 70 in
I could set it to the nearest inch (?)
I argue an environment of an inch to set the calculation (69, 71) and the result of percentile interval associated with the area is incorrect
Should be in the range (69, 70) (?)
I have only one last chance to respond ...
thanks
UserIdTAG: 369263
UserNameTAG: Ernest1971
CreateTimeTAG: 2013-03-08T13:49:14Z
VoteTAG: 1
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: Is a half inch in both side
FirstChildUserIdTAG: 369263
FirstChildUserNameTAG: Ernest1971
FirstChildCreateTimeTAG: 2013-03-08T13:52:54Z
FirstChildVoteTAG: 1
SecondChildTAG: I agree with Ernest find the percentage values for the range 69.5 - 70.5 inches
SecondChildUserIdTAG: 92101
SecondChildUserNameTAG: DarylHickey
SecondChildCreateTimeTAG: 2013-03-08T14:41:04Z
SecondChildVoteTAG: 0
SecondChildTAG: maybe a bit late, but there is a post from replied by staff "Statistical Understanding: to the nearest inch" in which it is explained how to get the range, but it is the same Ernest1971 and DarylHickey have said.
SecondChildUserIdTAG: 251116
SecondChildUserNameTAG: Almu79
SecondChildCreateTimeTAG: 2013-03-10T01:46:27Z
SecondChildVoteTAG: 0
FirstChildTAG: You need the range between the lowest and biggest values that still round off as 70.
*Hint:* 1.5 rounds off as 2.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T13:58:37Z
FirstChildVoteTAG: 2
IndexTAG: 1120
TitleTAG: Nearest inch or HALF INCH?????
Problem 1C is badly worded. The question says NEAREST INCH and NOT HALF INCH. If there was a concept or rule to interpret the question, it should have been introduced at some point in the class...
UserIdTAG: 1123115
UserNameTAG: pbarr
CreateTimeTAG: 2013-03-08T13:44:15Z
VoteTAG: 3
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: The class interval for one inch is a 1/2 an inch on either side.You are using a smooth curve to estimate an area of the histogram.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-08T13:47:46Z
FirstChildVoteTAG: 4
SecondChildTAG: Thanks
SecondChildUserIdTAG: 369263
SecondChildUserNameTAG: Ernest1971
SecondChildCreateTimeTAG: 2013-03-08T13:49:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Because it *is* "nearest inch" and not "half inch".
"Half Inch" would include 70.5, which is **not correct**. You care about the values that round off as 70 only.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T13:55:23Z
FirstChildVoteTAG: 0
SecondChildTAG: Mmm, actually, I stand corrected. In my calculations I stopped at 70.49, but rereading the solution, I see that 70.5 was indeed included. I suppose because of the continuous nature of the data.
Disregard my previous post.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T16:47:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Because the % value at exactly 7.5 is essentially zero, using 70.5 is correct (using 70.49 would disregard values between 70.49 and 70.5). The area remains the same regardless of whether you use a closed bound or an open one; if you drew it out on the graph, there would be a closed boundary at 69.5, and an open one at 70.5.
SecondChildUserIdTAG: 458728
SecondChildUserNameTAG: seleneyue
SecondChildCreateTimeTAG: 2013-03-08T19:22:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeah, there's not enough % difference in this case to really matter...if you deal with data that has an higher degree of precision, though, things change.
It's good to have learned my lesson here :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T20:05:33Z
SecondChildVoteTAG: 0
IndexTAG: 1121
TitleTAG: Prof A suggestion for introductory Stats text book??
A long time ago in a galaxy far, far away.... before the second great GMT debate.... I'm sure she replied to someone who asked about this. Tried searching the forum but failed.
(This course has reminded me how much I enjoy playing with numbers, how out of date my statistical practice is and how hard I find it to study from an online text book!)
UserIdTAG: 1193788
UserNameTAG: MarianW
CreateTimeTAG: 2013-03-08T13:29:50Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: This is the link to the text book discussion but the link inside to the eller is only for the low cost edition in India.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/513352f1dd04c01f0000008d
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-08T13:46:27Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks a lot - but ouch it's expensive on Amazon in the UK - time to search around for an importer I think.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-08T14:04:46Z
SecondChildVoteTAG: 0
IndexTAG: 1122
TitleTAG: Geometric and Harmonic mean
What is the use of the geometric and harmonic mean ?
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-08T13:06:31Z
VoteTAG: 2
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.2: The average: calculation and basic properties
NumberOfReplyTAG: 2
FirstChildTAG: Harmonic mean is considered in many ways the truest average in physics (or at least certain areas). It is also used in computer science to evaluate algorithms. I'm sure there are many other uses.
Geometric mean is right up my professional alley (Finance IT). It is used in computing the compound annual growth rate of return in finance.
It has many other uses too..perhaps the Prof. will elaborate further.
Cheers.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-08T15:23:09Z
FirstChildVoteTAG: 3
FirstChildTAG: Substitute each entry by 100.
Get sums of (100+2+3+4), (1+100+3+4) etc. .
The related averages are **27.25, 27, 26.75, 26.5** .
The new average can't be 27.5.
What's wrong with my calculation/understanding? Any ideas?
FirstChildUserIdTAG: 720154
FirstChildUserNameTAG: LUCALOTTO2012
FirstChildCreateTimeTAG: 2013-03-10T13:53:31Z
FirstChildVoteTAG: 0
IndexTAG: 1123
TitleTAG: Task 3A and 3B
I'm sorry to ask, regarding the posts a lot of people already figured it out. The question states that for every right answer you get 5 points and for every wrong answer you substract 1 point.
So my question is, do you substract that one point of the five points rewarded for the right answer so to say 4 OR are you substracting the one point of the generell score one student has?
Just to be precise... I guess multiple answering is not possible?
I hope some of the people who solved the task could help me please
best regards
UserIdTAG: 421982
UserNameTAG: Zonky
CreateTimeTAG: 2013-03-08T12:16:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Each student writes 10 answers. Any right answer adds 5 points to his score, any wrong answer subtracts 1.
Can you write an equation for the total score that follows those rules? As the problem suggests, use the number of right answers as the x.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T12:27:41Z
FirstChildVoteTAG: 0
SecondChildTAG: okay thanks, I got the right answer! And thanks a lot for the rather fast answer!
SecondChildUserIdTAG: 421982
SecondChildUserNameTAG: Zonky
SecondChildCreateTimeTAG: 2013-03-08T12:33:09Z
SecondChildVoteTAG: 0
SecondChildTAG: what about if you dont have , wrong answers, what would the equation be ?? cual seria la ecuacion??
SecondChildUserIdTAG: 1107978
SecondChildUserNameTAG: betoagto
SecondChildCreateTimeTAG: 2013-03-08T18:13:54Z
SecondChildVoteTAG: 0
SecondChildTAG: The same one. The correct equation is valid for any possible case.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T18:41:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Yo consideré 2 curvas diferentes para negativas y positivas, así se ve más clara la transformación. Calculé la desviación de cada una y luego consideré que esas curvas se fusionan.
Translating from a previous answer...
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-09T15:15:00Z
SecondChildVoteTAG: 0
IndexTAG: 1124
TitleTAG: Link for video
Where´s the link to lecture 5.4?
UserIdTAG: 893643
UserNameTAG: andersonbs
CreateTimeTAG: 2013-03-08T11:44:13Z
VoteTAG: 10
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 2
FirstChildTAG: There are several post on the topic already. Hopefully they'll put it up soon.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T11:55:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Still no link.
SecondChildUserIdTAG: 1253130
SecondChildUserNameTAG: Eternalight
SecondChildCreateTimeTAG: 2013-03-11T04:01:57Z
SecondChildVoteTAG: 0
FirstChildTAG: same here!! ... and i´m going crazy .. because i can´t see it
FirstChildUserIdTAG: 1166847
FirstChildUserNameTAG: Jriveraespejo
FirstChildCreateTimeTAG: 2013-03-12T01:14:04Z
FirstChildVoteTAG: 0
IndexTAG: 1125
TitleTAG: STAFF technical problems with java and histograms
This is really frustrating. The problem is already reported by me and others in the past. I still haven't managed to solve it. I had to rely on the video lectures until now to see what was going on in the figures but the normal curve text is pretty much based on the figure which is again not available. I am stuck, not able to move on with the theory and the exercises and I don't feel this is my fault. So, essentially, if you are unlucky enough to not be able to see the contents with your browsers (and not a pc expert to solve the problem) you can't move on.
And please, the last thing that I need is answers by smartasses who will tell me that it's easy to grasp anyway -there are people in here who are trying to learn from scratch, without any background at all- or people who don't have the same problem.
Antonis
ps. I know an alternative link is posted below but this is not helping me. I can't relate the explanation of the figure to the other link
UserIdTAG: 1207733
UserNameTAG: AntoniusBlock
CreateTimeTAG: 2013-03-08T11:35:42Z
VoteTAG: 8
CoursewareTAG: undefined
NumberOfReplyTAG: 11
FirstChildTAG: >And please, the last thing that I need is answers by smartasses
Trying not to.
Have you tested whether Java is working on your computer?
http://www.java.com/en/download/testjava.jsp
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T11:41:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Not relevant, as the applet uses Javascript, not Java ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T11:54:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Bummer! Shows how much I know.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-08T21:09:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Click on either of the two links for lecture 5.1
These links work.
Why other links work I do not know.
SecondChildUserIdTAG: 344400
SecondChildUserNameTAG: carlallen
SecondChildCreateTimeTAG: 2013-03-15T21:00:04Z
SecondChildVoteTAG: 0
FirstChildTAG: You don't need to be a computer expert to change browser if the current one doesn't work.
Until last week, I would have suggested Google Chrome, but I'm having problems with it recently, and I don't seem to be the only one.
So I strongly suggest you use [Mozilla Firefox][1]. It's very straightforward to install. Just ensure you have **Javascript**(not Java) enabled(Options->Content) and you should be ok.
[1]: http://www.getfirefox.com/
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T11:50:46Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks for your answer.
I wish this was the solution.
I have already tried with Chrome, Mozilla and explorer, and the problem persists
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-08T12:12:37Z
SecondChildVoteTAG: 0
SecondChildTAG: And Javascript is enabled, yes?
What do you get instead of the applet [here][1]? A white gap? Just the movable bars on the bottom? Just a line of text?
[1]: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T12:22:44Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you for trying to help. just the movable bars for the lower and upper endpoint
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-08T12:35:58Z
SecondChildVoteTAG: 0
SecondChildTAG: I see. Then Javascript is working.
Does this page opens with no errors? Should be just a bunch of text.
http://d3js.org/d3.v3.min.js
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T12:59:14Z
SecondChildVoteTAG: 0
SecondChildTAG: this is what I see when opening this page:
d3=function(){function t(t){return t.target}function n(t){return t.source}function e(t,n){try{for(var e in n)Object.defineProperty(t.prototype,e,{value:n[e],enumerable:!1})}catch(r){t.prototype=n}}function r(t){for(va .....
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-08T13:13:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Can you see this site
http://www.java.com/en/download/testjava.jsp
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:29:55Z
SecondChildVoteTAG: 0
SecondChildTAG: That's correct. I would've bet your problem was in accessing that page, since it contains the code used to show the graphs.
But if it works...I'm stumped, sorry :(
Unless...do you use any Antivirus or Firewall program with some form of AD-Blocking capabilities included? Norton, McAfee, Kaspersky...the likes of that. If you do, try temporarily disabling them.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T13:32:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Just tried this. Still nothing. I'm officially depressed. Thank you very much for trying to help.
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-08T13:56:56Z
SecondChildVoteTAG: 0
SecondChildTAG: All right. Time to move on to dirty tricks then.
Go [here][1]. Put in this in the text bar:
> Integrate (1/sqrt(2pi))*e^(-1/2*x^2) from -1 to 1
You'll notice that the result is the fraction of the Normal Curve between -1 and 1, as you see in the lectures or the textbook table. The percent is, of course, just the result*100.
This is, presumably, the method used by the nonworking applet to calculate its results.
Change the limit points accordingly to get the rest of the values you need for the Exercises. You can use "-infinite" and "infinite" for open ranges ;)
[1]: http://www.wolframalpha.com/
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T14:15:59Z
SecondChildVoteTAG: 0
SecondChildTAG: After accessing the material from a pc at work and seeing what exactly the applet does, I realised that it's the graphic representation that is only missing. The calculations can be done even in this erroneous version of the applet. So now that I know the idea I will just use it for the calculations. I hope this course does not involve many histograms in the future :0
Thank you very much.
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-09T09:14:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Ah, I see what you mean. The percentage comes up even without the graph showing, that's nice :D
But it's so strange that you still can't see those applets :S
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T16:56:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi,
I am having the same problem. I will try to follow your suggestions. It is important because our midterm exam requires applets.
Thank you guys:)
SecondChildUserIdTAG: 1141835
SecondChildUserNameTAG: TrissMerigold
SecondChildCreateTimeTAG: 2013-03-12T20:56:30Z
SecondChildVoteTAG: 0
FirstChildTAG: Use chrome or Firefox, enable Java plugins and download Java- this is required for a platform independent ability to see the applets as people will be using different operating systems.Like it or not one of the requirements is a compatible browser which was mentioned in the course requirements and I also ha some problems as I was trying to read most of these on my Galaxy Note 2 which has essentially replaced my laptop and I ahve now managed to work around some deficiencies for eg Dolphin browser will not render pages correctly whereas Chrome and Firefox do a better (if not perfect) job.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-08T11:56:43Z
FirstChildVoteTAG: 0
FirstChildTAG: I hava java installed on all my browsers and javascript enabled and still cant see the histogram
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-08T12:15:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Could you see the test page on the Java site ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:02:42Z
SecondChildVoteTAG: 0
SecondChildTAG: What is your operating system and Browser?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:04:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Windows 7. I am not sure what is the test page you are refering to but I always update to the latest version of Java and I never had a similar problem in any website with java or javascript :/
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-08T13:15:33Z
SecondChildVoteTAG: 0
SecondChildTAG: I need to make one thing clear, because otherwise we risk a lot of confusion. The applets in the textbooks use *Javascript*, which is integrated into the browsers themselves.
Java has nothing to do with it: http://kb.mozillazine.org/JavaScript_is_not_Java
So having Java installed or not isn't going to make any difference ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T13:15:51Z
SecondChildVoteTAG: 0
SecondChildTAG: my main browser is chrome but I ve tried with all of them
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-08T13:16:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Since it is an applet isn't it running Java ? In fact it asked me if it wanted to run it as a warning.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:31:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Some applets might be Java, but not the one for the Normal Curve. I have the Java Plugins all disabled on my Browsers, and I can see the applet normally. Plus, I stop seeing it as soon as I disable JavaScript.
Sounds like conclusive evidence, even without looking at the HTML code ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T13:38:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Could consider installing SWware iron - which is a version of chrome and seeing if it works on that.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:45:01Z
SecondChildVoteTAG: 0
SecondChildTAG: I can now see the applet and I did a few things - OR - something got changed in the software. Before I take more of your time, have you tried just RELOADing the page with the applet from Chrome?
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-08T16:37:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Sometimes the simplest solution is also the best :o
Yeah, try this too, AntoniusBlock.
Or cleaning your browser cache, which is another basic thing to do which I overlooked for some reason :|
Either using CCleaner, as Prasannasimha suggests below, or doing it from the browser. For Chrome, it's History-->Clear all browsing data. For Firefox, History-->Clear Recent History.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T16:59:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Klionheart, don't forget that Myowncamera could see the figure elsewhere, so it was probably an error loading the page. I will try ccleaner and the trick you suggested above
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-09T09:11:44Z
SecondChildVoteTAG: 0
FirstChildTAG: Like you, I cannot use the applet, no matter what I try.
So in desperation, I have been using the online text Figure 23-1 "The Normal Curve", right under the video (linked to in the Practice, right before the link for the applet).
Not perfect, but much better than the link to the applet itself. At least I am able to do the Exercises now.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-08T13:01:40Z
FirstChildVoteTAG: 0
SecondChildTAG: mate, I wish I could do that. I haven't been able to properly see any interactive figure involving histograms since the beginning of the course
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-08T13:20:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Have you tried clearing your cache wih C Cleaner.I had some issues and it helped.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T16:48:43Z
SecondChildVoteTAG: 0
SecondChildTAG: I can see it now, but not sure why. I did not use C Cleaner yet. I have another response for Antonius above (earlier response thread)
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-08T16:56:06Z
SecondChildVoteTAG: 0
FirstChildTAG: The figures do not use Java, only JavaScript. (It's been a massive undertaking to re-write all the Java as JavaScript before the class gets to the material.)
The figures rely on three javascript libraries that are not part of the course materials themselves: jQuery, jQuery-ui, and d3.
The figures have been tested in Firefox, Chrome, and Safari. Internet Explorer is not recommended.
If the figures do not display correctly for you, first make sure you have the latest version of your browser. If so, then clear the browser's cache, and re-start the browser.
Sorry this is causing grief.
Cheers,
Philip
FirstChildUserIdTAG: 990671
FirstChildUserNameTAG: pstark
FirstChildCreateTimeTAG: 2013-03-08T17:35:56Z
FirstChildVoteTAG: 3
SecondChildTAG: Thanks Prof. Philip. It did work.
Cheers
SecondChildUserIdTAG: 1291556
SecondChildUserNameTAG: zaeemy
SecondChildCreateTimeTAG: 2013-03-08T17:47:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm guessing the cache was the key?
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T17:53:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you very much for your reply. At least I have now realised that even without the graphs, the calculations are done correctly by the applet. I will try cleaning my cache -I have already tried it from the browsers settings, I will now try using the programme suggested, ccleaner- and if this does not work again, so be it. I will manage without it.
Antonis
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-09T09:21:05Z
SecondChildVoteTAG: 0
SecondChildTAG: What happened?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T10:57:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi Philip,
the figures have been posing problems for me too from the start (no histograms, but the sliders). Now I took a step into another direction. Please review your code according to the W3C standards, because the W3C validator finds a lot of problems with the code.
If you'd take a look at this: http://goo.gl/UH0yZ probably you could figure out what causes this type of problem.
My understanding from the output of the validator is that there are many errors in the code and the browsers behave differently due to the errors.
George
SecondChildUserIdTAG: 151942
SecondChildUserNameTAG: GyuriK
SecondChildCreateTimeTAG: 2013-03-12T09:31:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks AntoniusBlock for posting this issue. I had exactly same trouble with Chrome and followed recomendations above (with Java, Java Script, etc but no one gave me a good result). The one that allowed me to finally view the Normal Curve graphic was cleaning the cache. Hope this helps to others :) MaisaSM
SecondChildUserIdTAG: 437379
SecondChildUserNameTAG: MaisaSM
SecondChildCreateTimeTAG: 2013-03-12T12:03:00Z
SecondChildVoteTAG: 0
FirstChildTAG: I had the same problem; someone suggested that I should use Opera and it worked. You should try it.
FirstChildUserIdTAG: 1266083
FirstChildUserNameTAG: Asimina
FirstChildCreateTimeTAG: 2013-03-11T22:52:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Using Safari, just changed my encoding language to UTF-8. It works! Thanks Prof.!
FirstChildUserIdTAG: 913981
FirstChildUserNameTAG: DSamuel
FirstChildCreateTimeTAG: 2013-03-12T10:26:39Z
FirstChildVoteTAG: 0
SecondChildTAG: After trying latest versions of chrome and firefox without positive results I decided to use Safari. LOL!! It really works! It is so nice to see everything:). Thaank you!
SecondChildUserIdTAG: 1141835
SecondChildUserNameTAG: TrissMerigold
SecondChildCreateTimeTAG: 2013-03-18T14:31:11Z
SecondChildVoteTAG: 0
FirstChildTAG: im ready to do my work but the page is not opening.
FirstChildUserIdTAG: 1241440
FirstChildUserNameTAG: Bertinah
FirstChildCreateTimeTAG: 2013-03-19T22:21:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Your antivirus software might be blocking Java, I was using Kaspersky and I had to change settings to 'Do not scan network traffic' for Java to get Java applets to work.
If you are just after the Standard Normal Distribution there are lots of tables online.
There's a flash version here
http://www.mathsisfun.com/data/standard-normal-distribution-table.html
FirstChildUserIdTAG: 1083047
FirstChildUserNameTAG: NuwanRD
FirstChildCreateTimeTAG: 2013-03-20T16:55:11Z
FirstChildVoteTAG: 0
FirstChildTAG: I cant find the reading material though I found the syllabus. Is it that I will source my own reading stuff or modules. Please respond I need to start my course right away
F Bure
prbure@gmail.com
FirstChildUserIdTAG: 1466419
FirstChildUserNameTAG: prbure
FirstChildCreateTimeTAG: 2013-03-24T20:30:41Z
FirstChildVoteTAG: 1
IndexTAG: 1126
TitleTAG: playing catch up
I joined the class late - last week or so and have been playing catchup should be there this week
UserIdTAG: 1359884
UserNameTAG: Kdean127
CreateTimeTAG: 2013-03-08T11:26:06Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 0
IndexTAG: 1127
TitleTAG: Standard normal curve -proof of area =1 and gaussian Integral=\sqrt \pi
I think I have completed the proof for the standard normal curve being equal to one and included the proof of the Gaussian integral (which tested the limits of my calculus which is 30 years old and never looked into thereafter ;) )I have written it in a form that I could understand and hope it is a correct method of derivation. Prof Adhikari, could you please check if it is correct ? It is at the wiki page
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/proof-area-standard-normal-curve-1/
I apologize for the aesthetically shabby integral signs but I am not good at Latex which I started learning recently and cannot seem to write those beautiful large integral signs that look better. everything looks clunky and cluttered.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-08T11:23:58Z
VoteTAG: 3
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.1: Bell shaped curves; the standard normal curve
NumberOfReplyTAG: 2
FirstChildTAG: Like this? $\displaystyle\int$ instead of $\int$?
Put \displaystyle before the \int
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T11:33:43Z
FirstChildVoteTAG: 2
SecondChildTAG: Yes.Thanks.I will try. Those stubby \int"s look positively ugly.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T11:55:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Now is there an easy way to add it all or else I will have to copy and paste it to all integrals ? :( (It took me a stuttering long time as it is to get this out !)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T11:58:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Copy the text into notepad, use the "Replace" tool, copy it back into the wiki ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T12:24:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Managed to do the changes and also the brackets[] need a \bigg command to look big enough !
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T12:49:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Now I know it looks nice but I hope it is correct ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:32:57Z
SecondChildVoteTAG: 0
SecondChildTAG: As I already said somewhere in the forum, I really suck with this kind of things, so I'm just going to trust you, and say that I admire you :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T13:49:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I also suck at it but am forcing myself to do it.I have written a maths paper (actually work done in my teens but preserved by Mother for decades !! and of course I think it is worth the maths equivalent of the Nobel prize :)) but it was rejected by the London mathematical society journal so I have to rework it so laboriously going through Latex which is like Greek and Latin for a cardiac surgeon !! Can't even get it into Arxiv as I don't know any mathematicians who can endorse the paper :( It is on number/Group theory and deals with singularities.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:57:28Z
SecondChildVoteTAG: 0
SecondChildTAG: I have posted the set- can the students who are interested also go through it and point out if they see any errors ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T13:10:20Z
SecondChildVoteTAG: 0
FirstChildTAG: Can the Professors correct the Wiki if there are any errors?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T13:09:17Z
FirstChildVoteTAG: 1
IndexTAG: 1128
TitleTAG: Subtitles for Lec 4.4
Am I right that there is no subtitles available for this video?
UserIdTAG: 197621
UserNameTAG: quilombolo
CreateTimeTAG: 2013-03-08T10:59:03Z
VoteTAG: 0
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 1
FirstChildTAG: You mean the captions in the side bar? I can see them
FirstChildUserIdTAG: 517550
FirstChildUserNameTAG: Ewa_G
FirstChildCreateTimeTAG: 2013-03-08T12:14:44Z
FirstChildVoteTAG: 0
SecondChildTAG: No, I mean subtitles inside video.
SecondChildUserIdTAG: 197621
SecondChildUserNameTAG: quilombolo
SecondChildCreateTimeTAG: 2013-03-08T14:01:18Z
SecondChildVoteTAG: 0
SecondChildTAG: yup, none
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-10T23:54:09Z
SecondChildVoteTAG: 0
IndexTAG: 1129
TitleTAG: mid trm
syllabus 4 mid trm will be 1-8 lctr right? pls let us know about the score in ths xm.
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-08T09:14:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: As it says on the Course Info page:
> I will post the midterm syllabus, format, etc shortly. The exercise sets are good indicators of the sorts of problems that you will see on the exam.
And on the course policy:
> MIDTERM, WED MAR 13: Describing one variable (Sections 1-5)
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T11:03:35Z
FirstChildVoteTAG: 0
IndexTAG: 1130
TitleTAG: need help
need help for z value (applet)
stuck with problem 7.
UserIdTAG: 393580
UserNameTAG: Aditiak
CreateTimeTAG: 2013-03-08T07:35:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: Do you have problem using the java applet?
If you do, here's an applet made in flash: http://www.mathsisfun.com/data/standard-normal-distribution-table.html
And also, for your reference, the java applet's link is http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
FirstChildUserIdTAG: 1378421
FirstChildUserNameTAG: Misaka
FirstChildCreateTimeTAG: 2013-03-08T07:41:01Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you so much
SecondChildUserIdTAG: 393580
SecondChildUserNameTAG: Aditiak
SecondChildCreateTimeTAG: 2013-03-08T08:59:06Z
SecondChildVoteTAG: 0
SecondChildTAG: can not get write answer for problem 7 i am confused how should i get mean and SD from this data?
SecondChildUserIdTAG: 393580
SecondChildUserNameTAG: Aditiak
SecondChildCreateTimeTAG: 2013-03-08T09:19:48Z
SecondChildVoteTAG: 0
SecondChildTAG: You can find the z value for any percentile.
Then review Problem 2 of the Practice Set and you'll get an idea of how to proceed ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T10:58:35Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks Klionheart,
i follow the steps and got correct answer.
SecondChildUserIdTAG: 393580
SecondChildUserNameTAG: Aditiak
SecondChildCreateTimeTAG: 2013-03-09T03:33:41Z
SecondChildVoteTAG: 0
FirstChildTAG: I can't even get the z score...where did it come from?
FirstChildUserIdTAG: 925684
FirstChildUserNameTAG: KamLoong
FirstChildCreateTimeTAG: 2013-03-10T12:28:07Z
FirstChildVoteTAG: 0
SecondChildTAG: Go to the applet. On the left box type -5 because for percentile you want to include all the values to the left. Then play around with the right box until the area is shown equal to what you want. That is your Z score.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-11T06:42:31Z
SecondChildVoteTAG: 0
IndexTAG: 1131
TitleTAG: For those of you who are used to the metric system...
1inch = 2.54cm
Anecdote: In the past, people were using inches and feet units to measure any distances.
Where did that come from? Actually it was refering to the exact lenght of an inch and a foot of the king/queen in place. It means that each time the king or the queen changed, a new measured unit had to be used refering to the new king/queen's finger and foot...
Thanks the French for establishing a constant unit on earth, the 'metre' in 1790 (equal to the lenght of a pendulum with a half-period of one second), one year after the start of the Revolution.
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-08T07:12:20Z
VoteTAG: 7
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 3
FirstChildTAG: The changing with each sovereign had changed a long time before the french experiment. You can see the standards set in the wall at the back of Trafalgar square next time you are in London.
Foot, inch, yard and mile have the advantage of being human scales, with a long history and therefore instinctive. The measuring system together with the old pounds shillings and pence monetary system and the ounce, pound stone weight system, probably contributed to the mental flexibility which resulted in so much innovation from the British Empire and its rebels!
I looked up your comment because I was amused by the lecture note "for those of you used to the metric system, 12 inches = 1 foot" thinking it similar to the snooker commentator who said "For those of you with black and white televisions (remember them?), the brown is next to the yellow."
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-08T08:56:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Amusante answer.
And now in the modern world, we need acuracy and things far from human scale like a bacteria diameter (around 1 micro meter) nanomachines dimensions (nano meter range) or moon-earth distance (about 384000 kilo meters, acceleration due to gravity, speed of light, etc, etc...)to be measured, calculated and understood by all of us on this planet.
In the future, if we manage to construct cities on Mars, I just hope that people would drive on the 'right' side of the road and not on the 'wrong' side. ;)
Take it easy.
Z.
FirstChildUserIdTAG: 830835
FirstChildUserNameTAG: Zacharie
FirstChildCreateTimeTAG: 2013-03-08T10:19:30Z
FirstChildVoteTAG: 1
SecondChildTAG: I'd be careful! You might open up a whole can of worms. According to wikipedia 33.9% of the world lives in a left-hand traffic countries and they might not see it as "wrong" :P
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-08T22:12:01Z
SecondChildVoteTAG: 0
SecondChildTAG: 33.9% < 50%.
So the majority drives on the right. This can only mean that the "Right" side is the right side :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-09T16:59:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I know this course is all about drawing conclusions from data, but I think you might be over-interpreting this one!
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-09T19:59:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Not so sure about the over interpretation actually.
Most of the 33.9% did not have the choice... Apart from Japan whom yet nobody understand this choice (I ve asked them many times how, why. Nobody could answer ;)).
To say the leasr.
SecondChildUserIdTAG: 830835
SecondChildUserNameTAG: Zacharie
SecondChildCreateTimeTAG: 2013-03-10T02:02:36Z
SecondChildVoteTAG: 0
FirstChildTAG: Interestingly, the only countries in the world where the SI system is not the official system of weights and measures are Burma, Liberia, and the United States.
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-03-08T22:15:45Z
FirstChildVoteTAG: 1
IndexTAG: 1132
TitleTAG: Frustrated at exercise set 7
PROBLEM 3
In the quiz in Exercises 1 and 2, the grading scheme is as follows: each right answer is awarded 10 points, and 1 point is taken off for each wrong answer. Recall that the quiz consists of 1 questions, and that in the class, the average number of right answers is 7.2 and the SD of the number of right answers is 1.4. In what follows, it will help to express a student’s score in terms of the number of right answers the student got.
PROBLEM 3A : 2.0 POINTS
I am really frustrated. If one more person tells me to go look something up I am going to use my great biological knowledge....well you get the idea. I am having trouble applying the lectures to the problem and feeling like the discussions are an abosolute waste of time becasue people cant get their acts togther.
Find the average score of the class.
My question is that in order to find class average do you take the the 7.2 ave for right6 answers subtract it from the total number of questions to get the ave for wrong answers?
There are 15 total problems on the quiz. i then have 15 x(15-7.2/1.4) but I am not sure where to go or if I am right.
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-08T05:54:51Z
VoteTAG: 5
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 6
FirstChildTAG: think old score as a result of 1 for right and 0 for wrong, new score as 5 for right and -1 for wrong. both average and SD will be changed.
FirstChildUserIdTAG: 538792
FirstChildUserNameTAG: HtayOung
FirstChildCreateTimeTAG: 2013-03-08T06:15:05Z
FirstChildVoteTAG: 0
FirstChildTAG: The average number of correct answers is 6.2, not 7.2. Make sure that doesn't throw off your calculations.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-08T06:19:48Z
FirstChildVoteTAG: 0
SecondChildTAG: I cant post the actual problem because I dont want to violate the honor code
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-08T06:46:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Try to figure out what the average score is, starting from the average number of right answers. Then look at the formula you used to do it. Check if it applies to a random amount of right answers.
I'm sure you can continue by yourself from there.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-08T10:47:42Z
FirstChildVoteTAG: 0
FirstChildTAG: The right answers bear some relation to the wrong ones. Try to think about that. In addition, You can work out an example with your own data and see what happens with the avg and the sd and take your own conclusions. It helped me a lot!
I hope that'll help you as well.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-08T11:40:59Z
FirstChildVoteTAG: 0
FirstChildTAG: Sorry everyone for posting the solutions. Next time I should only give hints rather than giving the solutions. The reason I do this this week because we get the answers with the explanation right after we post our solutions. So I thought that it is appropriate to post the method in a logical way as best as I can for those who are still confused even after getting the answer.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-09T01:50:39Z
FirstChildVoteTAG: 0
FirstChildTAG: this is what I could come up with in the original problemthat to find the new average
6x7.2=27.2 math wont work but looking at th e format for solving.
My question is how does the way we do transformations apply? I know when we do transformation on lists -2,-1,0,1,2 we can multiply or add constants but how do you do that when your statement is |a|x(old average)+b?
also when your looking at the statement where do you find the a and b constants?
I am also having trouble with SD.
(SD of Transformed list)=|a|x(SD of original)
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-09T04:41:31Z
FirstChildVoteTAG: 1
IndexTAG: 1133
TitleTAG: Are MOOCs here to stay (Australia and India related)
Could be interesting, if you live in the vicinity of Sydney. edX President is the keynote speaker.
https://www.eiseverywhere.com/ehome/futureofhighereducation/106619/
UserIdTAG: 629320
UserNameTAG: SusanAust
CreateTimeTAG: 2013-03-08T05:02:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Indeed would be interesting to know what they think. Seeing this course I think the main issue will be primarily exam certification for wide spread use as can be seen on this and other lists where people try to cheat by using online forums. Probably the applet type of questions wihch change the question (values) for each person automatically on logging in will prevent ad verbatim copying to a large extent but I do not know how that will be implemented or implementable.
At the postdoctoral level I had once conducted an open book exam where I allowed my students to go to the library and access all the material, computer resources etc there and they told me that indeed it was harder to write that exam despite more resources being available.One thing is that in such exams there will obviously elimination of things that need to be memorized (which students often think is learning) and more emphasis on **application of concepts**. That indeed seems more difficult but more vital. At the end of the day people should understand that learning is to gain knowledge and not just a certificate.
One thing though is that these courses are indeed fantastic methods of learning.The only way they can replace traditional degrees is if other universities will accept these grades and professional bodies and employers will accept them
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T03:31:21Z
FirstChildVoteTAG: 0
IndexTAG: 1134
TitleTAG: How to get correct answer to Problem 7
Having trouble with understanding how to get the 90th percentile? All you have to do is look at **Practice Set Exercise 7 Number 2**. Reverse engineer the problem and you're set.
UserIdTAG: 587109
UserNameTAG: TigranA
CreateTimeTAG: 2013-03-08T04:25:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: Try to find z values for 60th and 70th percentile, then recall the formula, this might help.
FirstChildUserIdTAG: 1378421
FirstChildUserNameTAG: Misaka
FirstChildCreateTimeTAG: 2013-03-08T07:33:36Z
FirstChildVoteTAG: 0
FirstChildTAG: I think you need to use the applet, or something similar.
FirstChildUserIdTAG: 433872
FirstChildUserNameTAG: dfburke
FirstChildCreateTimeTAG: 2013-03-08T19:13:38Z
FirstChildVoteTAG: 0
SecondChildTAG: The applet helps to find the z values. The rest of the work is up to us :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T20:06:37Z
SecondChildVoteTAG: 0
FirstChildTAG: Where's the applet found? thanks
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
FirstChildCreateTimeTAG: 2013-03-08T21:10:35Z
FirstChildVoteTAG: 0
SecondChildTAG: TRIED BUT STILL STUCK CANT SOLVE MY TWO UNKNOWNS. HELP PLS
SecondChildUserIdTAG: 1105307
SecondChildUserNameTAG: takut
SecondChildCreateTimeTAG: 2013-03-11T04:48:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks. That worked!
SecondChildUserIdTAG: 1223260
SecondChildUserNameTAG: aditis
SecondChildCreateTimeTAG: 2013-03-12T07:11:06Z
SecondChildVoteTAG: 0
IndexTAG: 1135
TitleTAG: In the quiz in Exercises 1 and 2, the grading scheme is as follows
what is this talking about? Exercises 1 and 2? This doesn't make any sense. Can you make the question more straight-forward. Is there one quiz or two?
UserIdTAG: 60773
UserNameTAG: billchenxi
CreateTimeTAG: 2013-03-08T03:41:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: >In the quiz in Exercises 1 and 2, the grading scheme is as follows: each right answer is awarded 5 points, and 1 point is taken off for each wrong answer. Recall that the quiz consists of 10 questions, and that in the class, the average number of right answers is 6.2 and the SD of the number of right answers is 1.4. In what follows, it will help to express a student’s score in terms of the number of right answers the student got.
As the question then goes on to give you all the information you need, it doesn't matter how many quizzes there are.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T03:50:32Z
FirstChildVoteTAG: 0
SecondChildTAG: This time that reference to Exercises 1 and 2 *is* wrong, though. Should be just Exercise 2. Probably a leftover of an Exercise Set's precious form.
Oh, well. It doesn't matter anyway, since any useful information is repeated here anyway :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T10:40:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes. Too many getting caught up in minor points and missing the big picture.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-08T10:48:49Z
SecondChildVoteTAG: 0
IndexTAG: 1136
TitleTAG: Will be there a continuation of the course?
Will be there a continuation of the course? This is only an introduction to statistics. Something like Stat2.2x or Stat 2.3x? Please. This is just too easy
UserIdTAG: 1258339
UserNameTAG: Dondic
CreateTimeTAG: 2013-03-08T03:32:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Do you know what else is easy? Searching the discussion forum. Give it a try, and you'll discover that this question has already been asked and answered several times.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-08T03:43:46Z
FirstChildVoteTAG: 1
SecondChildTAG: LOL. Beat me to it.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-08T03:51:29Z
SecondChildVoteTAG: 0
SecondChildTAG: obviously, exercises are much more easier than find it. i´ve alredy searched for this topic
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T12:47:38Z
SecondChildVoteTAG: 0
SecondChildTAG: found it. it really was zillion similar questions, but also zillion-1 similar answers: "profesor has already told it!!!". only one question has had the normal answer. i really can´t get why is so hard to answer those normal questions, and so easy to answer 1000 times to question which could be very easy googled like "what is GMT?" or "why course time isnt set on california time so that it will be easier for all people?"
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T14:01:55Z
SecondChildVoteTAG: 0
FirstChildTAG: > Something like Stat2.2x or Stat 2.3x?
And these are just intro courses too. One intro course split into three sections.
> This is just too easy
As this is an introductory course, some will find it easy. Others won't.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T03:51:58Z
FirstChildVoteTAG: 1
SecondChildTAG: ok, will be there then stat3.1x or stat3.2? :)
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T14:03:13Z
SecondChildVoteTAG: 0
FirstChildTAG: It may be easy for you but not everyone is from statistics background or studied this at school level.
FirstChildUserIdTAG: 895245
FirstChildUserNameTAG: Ezegoing
FirstChildCreateTimeTAG: 2013-03-08T07:36:48Z
FirstChildVoteTAG: 2
SecondChildTAG: and wouldn´t be great if everybody could find something apropriate
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T12:45:23Z
SecondChildVoteTAG: 0
IndexTAG: 1137
TitleTAG: Question to staff
At what EXACT time of the day (in GMT) on Wed 13th will the exercises of the mid term exam be available in the net?
UserIdTAG: 1231201
UserNameTAG: wolkoe
CreateTimeTAG: 2013-03-08T02:51:01Z
VoteTAG: 4
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 1
FirstChildTAG: The email announced 7:00 AM GMT on Wed March 13
FirstChildUserIdTAG: 963897
FirstChildUserNameTAG: lightbulb
FirstChildCreateTimeTAG: 2013-03-13T04:49:27Z
FirstChildVoteTAG: 0
IndexTAG: 1138
TitleTAG: +1 if you liked the fx on the "LECTURE 5 INTRODUCTION"
It's over there. You here it calling. Go on, push it! =========>
UserIdTAG: 316261
UserNameTAG: Brady1997
CreateTimeTAG: 2013-03-08T02:20:28Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1139
TitleTAG: Could you help on an English language understanding problem?
What do you mean by 'to the nearest inch'?
Let s say for example that I am measured at 50.4 inches. Will I be in the 50 inch-people category or in the 51 inch-people category?
Same question if I am measured 50.5 inches?
Thanks.
Z.
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-08T02:16:52Z
VoteTAG: 6
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 4
FirstChildTAG: $\lt50.5=50$
$\ge50.5=51$
So 50.4 goes to 50, 50.5 to 51
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T02:21:52Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks. It is very clear for me now.
SecondChildUserIdTAG: 830835
SecondChildUserNameTAG: Zacharie
SecondChildCreateTimeTAG: 2013-03-08T04:45:34Z
SecondChildVoteTAG: 0
SecondChildTAG: I hope I had read your post befor submitting!! The nearest inch got me too (the metric sytem change). :)
SecondChildUserIdTAG: 923593
SecondChildUserNameTAG: SaraMB
SecondChildCreateTimeTAG: 2013-03-11T12:55:24Z
SecondChildVoteTAG: 0
FirstChildTAG: I think he want you to use interval. I am confusing too, since normal is continuous distribution so it is weird to ask point value...
FirstChildUserIdTAG: 60773
FirstChildUserNameTAG: billchenxi
FirstChildCreateTimeTAG: 2013-03-08T04:28:50Z
FirstChildVoteTAG: 0
FirstChildTAG: > since normal is continuous distribution so it is weird to ask point value...
Yes, that stumped me at first. But you look at the wording - to the nearest inch. So you have an interval.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T04:43:15Z
FirstChildVoteTAG: 0
SecondChildTAG: I considered using a "Histogram" of one inch intervals and the normal curve is the smooth "approximation"
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T10:01:20Z
SecondChildVoteTAG: 0
SecondChildTAG: I was in a bit of a hurry when I did this problem, and I took it to read "what percent are *over* 70 inches". I quickly realized that I was horribly wrong when I saw the red X! Take it as a cautionary tale against not taking your time when you read a problem :D
Thankfully I had a second chance to figure it out. It's a tricky little question, but easy once you realize that we want the interval that rounds off as 70 inches.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T11:42:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Hurry burry spoils the curry and that is how I ended with the big red X in another question which unfortunately had only one submission :(
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T12:40:12Z
SecondChildVoteTAG: 0
SecondChildTAG: I think I'm actually getting sloppy because of the 2-submissions-everywhere thing.
I used to be a lot more careful in the earlier ES when we only had one chance...
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T13:03:30Z
SecondChildVoteTAG: 0
FirstChildTAG: in the problem 1C shall we use an intervel or a single value nearest to 70? confused??? need help.
FirstChildUserIdTAG: 393580
FirstChildUserNameTAG: Aditiak
FirstChildCreateTimeTAG: 2013-03-08T07:02:54Z
FirstChildVoteTAG: 0
SecondChildTAG: It says to the nearest inch. As the data is continuous, this gives you an interval. Also, I think you will realize something is wrong if you try to use a single value.
SecondChildUserIdTAG: 1241616
SecondChildUserNameTAG: Larsfl
SecondChildCreateTimeTAG: 2013-03-08T08:53:51Z
SecondChildVoteTAG: 0
SecondChildTAG: I was about to comment on this, because as non-native English speaker this was confusing for me as well. I would suggest to add something like "when rounded to the nearest inch".
SecondChildUserIdTAG: 900261
SecondChildUserNameTAG: JRoest
SecondChildCreateTimeTAG: 2013-03-10T20:20:10Z
SecondChildVoteTAG: 0
IndexTAG: 1140
TitleTAG: Where is the Stici Gui applet and normal curve applet?
Couldn't do questions 5,6, and 7 as didn't know where to look. For future reference I need to know, thanks, mark
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-03-08T01:44:09Z
VoteTAG: 2
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm You'll find the applet using this link, but I don't know that it'll do you any good. I find the bold text SticiGui directly on the % area figure that yields our answers. It is very difficult to read each entry.
FirstChildUserIdTAG: 1110149
FirstChildUserNameTAG: MonstaCody
FirstChildCreateTimeTAG: 2013-03-08T01:49:14Z
FirstChildVoteTAG: 0
SecondChildTAG: If you "select" the answer by dragging the cursor over it you will find that the answer is easy to read. I do not suppose it is a design feature (I thought I was the only one with this problem).
SecondChildUserIdTAG: 7854
SecondChildUserNameTAG: pejic
SecondChildCreateTimeTAG: 2013-03-08T08:42:20Z
SecondChildVoteTAG: 0
FirstChildTAG: just use the applet in figure 23-1 of chapter 23 of SticiGui.
FirstChildUserIdTAG: 1231201
FirstChildUserNameTAG: wolkoe
FirstChildCreateTimeTAG: 2013-03-08T01:52:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks wolkoe, how do i access this chapter? mark.
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-08T21:19:59Z
SecondChildVoteTAG: 0
FirstChildTAG: It is linked at the top of each question page!
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T01:59:03Z
FirstChildVoteTAG: 0
SecondChildTAG: That link doesn't work, it's blank in the box!!!
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-08T21:13:32Z
SecondChildVoteTAG: 0
SecondChildTAG: My applet in figure 23-1 of chapter 23 of SticiGui is blank in the box. Can someone help me?
eanes@fortalnet.com.br
SecondChildUserIdTAG: 1007702
SecondChildUserNameTAG: delgado58
SecondChildCreateTimeTAG: 2013-03-09T14:14:35Z
SecondChildVoteTAG: 0
IndexTAG: 1141
TitleTAG: How to approach question 2B?
I'm sure this question has a pretty simple solution, but I don't even know where to begin. I got the answer to part A correct, but I'm really at a loss with regards to part B. Could someone point me in the right direction? I'm assuming I'm supposed to use the SD of the number of right answers in some fashion, but I'm not sure how to apply it. Thanks.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-08T01:40:27Z
VoteTAG: 7
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 4
FirstChildTAG: I am stuck on this as well. I have gotten everything else, but this... I know it will be extremely simple, I just can't figure it out.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-03-08T03:13:23Z
FirstChildVoteTAG: 0
FirstChildTAG: Think about how you transformed the number of correct answers to the number of wrong answers. (Hint: it involves multiplying by a number and adding by a number.) That's a linear transformation. The lectures explained how to find the SD of the new distribution based on the linear transformation.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-08T04:55:01Z
FirstChildVoteTAG: 0
FirstChildTAG: Trying to be cryptic in my question here, so as not to give anything away...
Even after seeing the real answer I still don't get this (I'm having similar problems for 3B). Can anyone explain why the transformation is completely different for 2A and 2B in the explanation? I thought the only difference was supposed to be lack of adding/subtracting for the SD.
FirstChildUserIdTAG: 1226786
FirstChildUserNameTAG: goodhen
FirstChildCreateTimeTAG: 2013-03-08T14:46:38Z
FirstChildVoteTAG: 0
SecondChildTAG: The transformation is the same, you're just expressing it in different terms.
Try using the transformation in 2B to find the average - you'll notice the result is the same of the one in 2A ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T15:16:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Ah, thanks, I think I've got it now. So the equation needs to be rearranged to be in the order as specified (i.e. not simply 10-6.2 but one that involves adding and multiplying to reach the same figure). Now to think again about 3B!
SecondChildUserIdTAG: 1226786
SecondChildUserNameTAG: goodhen
SecondChildCreateTimeTAG: 2013-03-08T16:15:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Exactly :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-08T17:54:21Z
SecondChildVoteTAG: 0
FirstChildTAG: plz i dont understand the q3a and 3b
FirstChildUserIdTAG: 776071
FirstChildUserNameTAG: phaliaa
FirstChildCreateTimeTAG: 2013-03-09T17:41:18Z
FirstChildVoteTAG: 0
SecondChildTAG: plz i dont anderstand the q3a and 3b
SecondChildUserIdTAG: 776071
SecondChildUserNameTAG: phaliaa
SecondChildCreateTimeTAG: 2013-03-09T17:56:39Z
SecondChildVoteTAG: 0
IndexTAG: 1142
TitleTAG: HELP! Locked out...
Hi, I just came to know about this great course and joined it TODAY!
I did the first exercises and got 100% right on the first submission.
But it is not saving my scores, or is it? The alarm clock is showing, so I am assuming that is a categorical indicator that my data was rejected! Please help me to catch up with this course so I can complete it. I am from SF Bay Area and visiting India and doing the course from Delhi. So ask the professor to do some chamatkar and I will give her a namaskar! :)
Thanks. Please confirm if I should continue or drop this course.
UserIdTAG: 1377257
UserNameTAG: GlobalWellBeing
CreateTimeTAG: 2013-03-08T01:13:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > Hi, I just came to know about this great course and joined it TODAY!
So, did you read the Course Info page and all the links to the right? If so, you would see that there are deadlines. Week 1 and 2 are gone. You can do the work, but it will not be graded. The answers are already available (click Show Answer)
You can only do Week 3 for grading.
The alarm clocks indicate exercises that are graded.
You only require 35% to get the certificate in this initial course, so joining now is not a problem.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T01:16:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks.
SecondChildUserIdTAG: 1377257
SecondChildUserNameTAG: GlobalWellBeing
SecondChildCreateTimeTAG: 2013-03-08T13:48:58Z
SecondChildVoteTAG: 0
IndexTAG: 1143
TitleTAG: Withdrawing from class
Hello - I need to withdraw from the class for personal reasons. What do I need to do?
Thank you very much for holding the class; I regret not being able to participate at this time.
UserIdTAG: 890985
UserNameTAG: KATAK
CreateTimeTAG: 2013-03-08T00:58:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: After logging in, there is a list of the course you have registered for. At the right there is "unregister" You just have to click on that. Sad to see you go.
FirstChildUserIdTAG: 157670
FirstChildUserNameTAG: _Nelson_
FirstChildCreateTimeTAG: 2013-03-08T01:13:57Z
FirstChildVoteTAG: 0
IndexTAG: 1144
TitleTAG: PROBLEMS WITH Z VALUE
Hello everyone!
How can I know "Z" value, for the percentile exercises?
UserIdTAG: 906560
UserNameTAG: ivanm02
CreateTimeTAG: 2013-03-08T00:34:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Where do i find the Stick Gui applet and normal curve applet???????? Can't answer questions without knowing how to access, thanks, mark
FirstChildUserIdTAG: 1284323
FirstChildUserNameTAG: markjohnconley
FirstChildCreateTimeTAG: 2013-03-08T01:40:39Z
FirstChildVoteTAG: 0
SecondChildTAG: You click on the link on the question page.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-08T01:52:12Z
SecondChildVoteTAG: 0
IndexTAG: 1145
TitleTAG: "Z" Value
How can I know "Z" value, for the percentile exercises?
UserIdTAG: 906560
UserNameTAG: ivanm02
CreateTimeTAG: 2013-03-08T00:32:06Z
VoteTAG: 1
CoursewareTAG: Practice For Exercise Set 8 / Reading and Practice For Exercise Set 8
NumberOfReplyTAG: 2
FirstChildTAG: Watch the lectures or familiarize yourself with Z score tables
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-08T00:34:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Ok thanks!
But I can't understand, how to use Z score tables to get percentiles.
SecondChildUserIdTAG: 906560
SecondChildUserNameTAG: ivanm02
SecondChildCreateTimeTAG: 2013-03-08T00:38:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, watch the lecture!
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-08T00:39:54Z
SecondChildVoteTAG: 0
SecondChildTAG: You can find the "Z" value for the 75th percentile using "The normal curve" app (see the link).
SecondChildUserIdTAG: 775707
SecondChildUserNameTAG: ElFilatova
SecondChildCreateTimeTAG: 2013-03-08T12:25:42Z
SecondChildVoteTAG: 0
SecondChildTAG: applet?
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-09T12:17:15Z
SecondChildVoteTAG: 0
SecondChildTAG: http://www.mathsisfun.com/data/standard-normal-distribution-table.html
this can be of help
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-11T20:35:29Z
SecondChildVoteTAG: 0
FirstChildTAG: You can find the "Z" value for the 75th percentile using "The normal curve" app (see the link).
FirstChildUserIdTAG: 775707
FirstChildUserNameTAG: ElFilatova
FirstChildCreateTimeTAG: 2013-03-08T12:26:07Z
FirstChildVoteTAG: 0
IndexTAG: 1146
TitleTAG: Problem 3 solution
This solution does not make sense to me at all. if anyone got it right kindly post his / her logic they used to answer it. Faculty can also provide further explanation. Thanks.
UserIdTAG: 330935
UserNameTAG: des0abbey
CreateTimeTAG: 2013-03-08T00:28:24Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Is that the 6 Sigma question?
Using Chebyshev's inequality -->
1/6^2 = 1/36 = 2.78%
Therefore at 6 Sigma level, there will be at most 2.78% (or rounded up to 3% which is the closest answer)
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-08T00:33:20Z
FirstChildVoteTAG: 0
FirstChildTAG: Also we need to add that 3% is an appropriate bound as it is not more than 3% (as 2.78) and is the closest in the appropriate direction as far as the inequality is concerned.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-08T02:44:39Z
FirstChildVoteTAG: 0
IndexTAG: 1147
TitleTAG: My assignment
I don't know if my assignments being submitted
UserIdTAG: 1223445
UserNameTAG: nandacadd555
CreateTimeTAG: 2013-03-08T00:25:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Well, if is for Week 1 or Week 2, it won't be submitted as the deadlines have gone.
You need to click the Check button to grade the answer. Then look on the Progress page, you marks are tallied there.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T01:07:51Z
FirstChildVoteTAG: 0
IndexTAG: 1148
TitleTAG: Succesfull
my five last exercises ended 100% succesfully, i'm very proud of me hhhhhh
UserIdTAG: 919422
UserNameTAG: tarwateanas
CreateTimeTAG: 2013-03-08T00:22:06Z
VoteTAG: 4
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: hhhhhh diangezan【
FirstChildUserIdTAG: 1378421
FirstChildUserNameTAG: Misaka
FirstChildCreateTimeTAG: 2013-03-08T00:56:21Z
FirstChildVoteTAG: 0
SecondChildTAG: congratulations ...
SecondChildUserIdTAG: 731839
SecondChildUserNameTAG: mebiostatistician
SecondChildCreateTimeTAG: 2013-03-08T06:24:07Z
SecondChildVoteTAG: 0
IndexTAG: 1149
TitleTAG: I´m very glad!!
I did everything well!!!
Good luck to all !!
UserIdTAG: 945953
UserNameTAG: Turca
CreateTimeTAG: 2013-03-08T00:12:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: Congratulations ...
FirstChildUserIdTAG: 731839
FirstChildUserNameTAG: mebiostatistician
FirstChildCreateTimeTAG: 2013-03-08T06:24:28Z
FirstChildVoteTAG: 0
FirstChildTAG: smart any tips
FirstChildUserIdTAG: 386558
FirstChildUserNameTAG: yogeshdave
FirstChildCreateTimeTAG: 2013-03-09T19:25:55Z
FirstChildVoteTAG: 0
IndexTAG: 1150
TitleTAG: Exercise set 1- problem 3a) clarification
I don't really understand the answer for problem 3a)
> Adding 20 green/green plants does not affect the numbers of the other kinds of plants, **though it does affect the proportions.**
How does adding 20 green/green plants affect the proportions? Relative to each other, the magenta/green, magenta/red etc. would still be in the same ratios (because the numbers don't change). I thought that the only reason the graph was incorrect was because green/green wasn't on it.
UserIdTAG: 838733
UserNameTAG: Ronnicus
CreateTimeTAG: 2013-03-07T23:26:30Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Because your total has increased by 20, so all the proportions will change. So the magenta/green were $\dfrac{270}{480}$ and now they are $\dfrac{270}{500}$.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-08T01:10:23Z
FirstChildVoteTAG: 1
SecondChildTAG: Ahh i see what you mean- i guess I was kinda confused because the bar graph displayed number of plants, not percentages
SecondChildUserIdTAG: 838733
SecondChildUserNameTAG: Ronnicus
SecondChildCreateTimeTAG: 2013-03-09T23:04:16Z
SecondChildVoteTAG: 0
IndexTAG: 1151
TitleTAG: Lecture 4.2
Professor,
First of all, THANKS so much for the effort put into this project. I am sure most of us are enjoying it immensely although there will always be outliers who complain just about everything they can. Statistics in real life…
In lecture 4.2, almost at the end, you explain how on certain lists, it is easy to figure out the SD without doing the actual calculations. You provide an example of a simple list:
0, 1
For which, surely enough, the average is 0.5 and the SD is 0.5
BUT, I think this approach could be dangerous in certain cases. For example, let’s take this list:
0, 0.5, 1
If one looks at this not carefully enough, one could think along this line: the average is 0.5. The deviations, without regard to sign of the extreme values to the mean look to be 0.5 and -0.5. So one could mistakenly think the SD is 0.5… Wrong! One has to consider that the mean’s deviation to itself is zero, so the correct value for SD, applying the formula is actually 0.408
My point is that one has to be very careful when not applying a formula. Maybe this mistake just happened to me, but when I thought of this example at first, my first guess for SD was 0.5
My 2 cents…
UserIdTAG: 1288995
UserNameTAG: olsolis
CreateTimeTAG: 2013-03-07T23:04:43Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.2: Deviations from average; the standard deviation (SD)
NumberOfReplyTAG: 0
IndexTAG: 1152
TitleTAG: Email Notification for Due Dates
I wonder if a system can be implemented where students have the option of getting email notification regarding due dates 24 hours before the due date and time. I understand the GMT time but for some, taking many classes online, a reminder system will be nice to have. Was just thinking.
UserIdTAG: 523705
UserNameTAG: IITian
CreateTimeTAG: 2013-03-07T21:43:14Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Why not set a reminder on your phone or something? Outlook has calendar functionality, so does gmail..
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T21:47:20Z
FirstChildVoteTAG: 0
SecondChildTAG: If there was an app that could crawl Edx's course sites and find their due dates, convert them to local times, and then set a reminder for phone or email, that would be nice.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T21:57:02Z
SecondChildVoteTAG: 0
SecondChildTAG: There is. It's called iBrain, and it's on sale currently at the Body Store, together with the special controllers for it, a pair of iHands and another of iEyes.
You have to be quick though! The sale ends at 23.00 **GMT** today! xD
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T22:13:35Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL! I want one!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T22:17:32Z
SecondChildVoteTAG: 0
SecondChildTAG: wicked
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-07T22:19:20Z
SecondChildVoteTAG: 0
SecondChildTAG: I have been laughing at the whole GMT issue, but lets not ignore the fact that it is bringing a few valid points (thanks for that **IITian**).
The first one was a clock to signal the time left for a given assignment, that is very intuitive and easy to implement.
The second one, the e-mails, it is already implemented in other courses here at edX (6.00x for example). You get a weekly update. In one I got:
"Problem Set 3 is due today! Please remember the due date is 10:00 PM (22:00) EST - the time zone for Boston, MA. Be sure you know what time this is in your local time zone by using a converter such as the one here: http://www.timeanddate.com/worldclock/converter.html."
I think that is very helpful and easy for the staff to do.
I know the border between spoon-feed and being helpful is thin. In this case, I think they would be valuable improvements.
SecondChildUserIdTAG: 1024715
SecondChildUserNameTAG: iparrajorge
SecondChildCreateTimeTAG: 2013-03-07T22:31:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Emails are useful. But if I had a dollar for every post I read where people complained about missing something - even though there were email reminders - I'd not be rich, but my wine cabinet would be fuller.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-08T01:13:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree. Staff could personally call everybody (!) 24 h before the assignment is due, and some would complain that there was no call 12 h before BUT that doesn't mean that no attempts to facilitate communication should be made.
SecondChildUserIdTAG: 1024715
SecondChildUserNameTAG: iparrajorge
SecondChildCreateTimeTAG: 2013-03-08T15:33:56Z
SecondChildVoteTAG: 0
FirstChildTAG: This is not an advanced course. I guess many of the students are novices - perhaps taking their first or second online course. They are excited and have studied hard for the assignments. Now suddenly they find that they have been blocked from taking the test because the times were in GMT. It's going to kill their enthusiasm.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-03-07T22:51:51Z
FirstChildVoteTAG: 0
SecondChildTAG: No it will not. It will however teach them a lesson. That lesson will probably be as valuable, if not more, then anything stats related they will learn here.
I bet the next time submission time comes along, they will read instructions and plan ahead.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T23:51:43Z
SecondChildVoteTAG: 0
SecondChildTAG: @Arthur: I agree completely. That lesson IS worth more than the course itself, particularly if they plan to attend more courses (in different platforms, different countries,...).
Plus, with a (almost ridiculously) low passing grade (35%!!!!) you get the lesson for free, since you can pass this class regardless.
SecondChildUserIdTAG: 1024715
SecondChildUserNameTAG: iparrajorge
SecondChildCreateTimeTAG: 2013-03-08T15:37:36Z
SecondChildVoteTAG: 0
FirstChildTAG: I was checking the assignment due times and they mentioned time only without the 'GMT' term added. It could have misled many. One simple way is to display all times in GMT - including the assignment page.
One analogy of people missing the GMT time is - say some town in the USA decided to follow metric system and posted speed limits of 45 kms per hour and while drivers are able to see the notice that the town follows metric system when they enter the town, I guess many will be misled by the 45 km speed limit and will get speeding tickets. Good for the town though.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-03-08T22:36:39Z
FirstChildVoteTAG: 0
IndexTAG: 1153
TitleTAG: ES7 P3A: Was it by chance, Professor?
Professor:
I used the average number of wrong answers as, let’s say, the constant b to solve the Problem 3A, and I was right. But when I went on Problem 3B and tried to solve it following the same reasoning, I was wrong. Then, reading the explanation for 3A, I figured out what I had to do.
The question is, did I get the right answer in 3A by chance? Otherwise, if my reasoning was right, why didn’t it work for 3B?
I thank you in advance, Professor.
UserIdTAG: 797704
UserNameTAG: Hersan13
CreateTimeTAG: 2013-03-07T21:27:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: No, I'm guessing not by chance. Since I don't know (and please don't tell me, since others are still working on this) exactly what transformation you used, here's a suggestion about how to examine your answers further:
Take an arbitrary number of right answers, say 3 right, and work out the corresponding score. Now see whether the transformation you used in 3A gives you the same score. As I don't know exactly what you used, I can't say with certainty, but I have a pretty good guess that your transformation will give you the right average score if you plug in the average numbers of right and wrong answers, but it will break if you take other values.
Try it and let me know. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-07T21:52:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Interestingly enough, the correct answer to this question is intuitive. You just have to think it through.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T23:53:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Professor:
Since I can´t be as explicit as I wanted, because of there are classmates still working on the problem, I guess I´ll rather wait until the right time to continue this discussion.
Till then.
SecondChildUserIdTAG: 797704
SecondChildUserNameTAG: Hersan13
SecondChildCreateTimeTAG: 2013-03-08T01:51:24Z
SecondChildVoteTAG: 0
IndexTAG: 1154
TitleTAG: exercise 7 problem 3
i dont understand exercise 3 , help me please ????
whats the difference between ex 2 and ex 3
UserIdTAG: 1107978
UserNameTAG: betoagto
CreateTimeTAG: 2013-03-07T21:14:53Z
VoteTAG: 3
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: write an algebraic equation for the scoring. example if we say my score was x, how would you score that? once you write this equation out, simplify it and you have your clues. how do the numbers multiplying to x or adding/subtracting it effect the SD and mean? use that to solve.
FirstChildUserIdTAG: 1270408
FirstChildUserNameTAG: armencho
FirstChildCreateTimeTAG: 2013-03-07T21:24:23Z
FirstChildVoteTAG: 2
SecondChildTAG: Despite the promise of no algebra only arithmetic for this class, this problem is most easily solved using some algebra the way armencho says. Fortunately, the algebra is pretty simple.
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-03-07T22:00:11Z
SecondChildVoteTAG: 0
SecondChildTAG: But it does say some basic algebra will make some things go faster.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T22:06:32Z
SecondChildVoteTAG: 0
IndexTAG: 1155
TitleTAG: How Many Will Pass?
Our class average according to the Progress chart is 80. We need 35 to pass. Let’s assume that the distribution is bell shaped (probably not a good assumption.) It would be reasonable to assume that less than 2% of the students will have a score of more than 98. Looking at the right side of the curve, that should be contained within 2 SD’s of the mean and since 98 is 18 more than the mean then 9 seems like a reasonable value for the SD.
Okay. Mean = 80 SD = 9 Number of students = 40,000
What is the number of students that will score less than 35?
UserIdTAG: 1284382
UserNameTAG: kite420
CreateTimeTAG: 2013-03-07T21:03:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: Is there a class average on the progress tab? I thought it's your own average..
Seems like 50% of the students here cant figure out GMT, so I'm betting on a significant number failing just based on that fact alone.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T21:23:18Z
FirstChildVoteTAG: 1
SecondChildTAG: LOL. Add to that those who are having difficulty accepting that they are the ones who are wrong, not the Prof.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T21:34:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Arthur - it may not be class average but it sure isn't my average as I've only missed one question for all 8 sets. It may mean nothing at all. The column "Total" makes no sense. Put the cursor over it. Mine says "graded exercises = 40% of a possible 50%." Huh?
SecondChildUserIdTAG: 1284382
SecondChildUserNameTAG: kite420
SecondChildCreateTimeTAG: 2013-03-07T22:28:43Z
SecondChildVoteTAG: 0
SecondChildTAG: I think the "40% of a possible 50%" means that the graded exercises can contribute a maximum of 50% towards your composite grade. You've gotten 40% of the exercises right. (This includes the exercise sets that haven't been released yet, minus the 2 lowest scores.)
At least I think that's what it means.
BTW congrats on the awesome score!
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T23:04:35Z
SecondChildVoteTAG: 0
SecondChildTAG: @KITE420: What MERHUTCHIN said...!
Congratulations on being a very accomplished solver of statistics exercises. Now, if you could just work on being a better detective... ;)
SecondChildUserIdTAG: 23003
SecondChildUserNameTAG: WH
SecondChildCreateTimeTAG: 2013-03-07T23:09:51Z
SecondChildVoteTAG: 0
SecondChildTAG: The average for Exercise Sets includes zero for all unattempted sets (and drops the two lowest scores). If you had 100% on each of the first 8 sets then your average would be 80% (8 out of twelve but two sets discounted so 8 from 10 = 80%).
The 'Total' includes 50% weighting from the Exercise Sets with the balance coming from the two exams. As with the ES average, elements not yet completed are graded as zero. Taking the above example, your current total would be 40% and if you hovered it would say 40% from a possible 50%. That is your 80% current ES average from the 50% maximum which can earned by ES grades.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T23:10:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the explanation Paul
SecondChildUserIdTAG: 1284382
SecondChildUserNameTAG: kite420
SecondChildCreateTimeTAG: 2013-03-08T05:12:53Z
SecondChildVoteTAG: 0
IndexTAG: 1156
TitleTAG: Exercise 4 - Prob.8
Dear Prof
With all due respect, I think the given answer is wrong.
If all 32 house were sold at $819,000, then the average was -$15,000 as I’ve answered first.
If first house was sold at $834,000 and the others at $819,000, the answer will be:
(1 x $834,000 + 31 x $819,00)/32 = -$14,531
Pls comment…
Best Regards
Mario S. Pereira
UserIdTAG: 400844
UserNameTAG: Mario007
CreateTimeTAG: 2013-03-07T21:02:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > Dear Prof With all due respect, I think the given answer is wrong.
No. It is correct. Did you read the comment in Show Answer?
> If all 32 house were sold at 819,000
They weren't
>If first house was sold at 834,000 and the others at 819,000,
They weren't.
As the question said. The price was given for only one house. The others are irrelevant to the question.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T21:33:39Z
FirstChildVoteTAG: 0
IndexTAG: 1157
TitleTAG: applet
A distribution of heights follows the normal curve with mean 67 inches and SD 3 inches. What percent of the heights are between 63 inches and 67 inches? (63 67)=3 = 1:33 standard units; 67 inches = 0 standard units. So the question becomes: Under the standard normal curve, what percent of the area is between 1:33 and 0? The applet says the area is 40.82%. Answer: 40.82%.
which applet is this referring to?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-07T20:30:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: there is a technical glitch. Ipost this under exercise 7 and it shows up in exercise 1/exercise set 1
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-07T20:31:24Z
FirstChildVoteTAG: 0
FirstChildTAG: This one: http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm
A suggestion: do Practice Set 7.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T21:01:07Z
FirstChildVoteTAG: 0
SecondChildTAG: I did find it
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-08T04:25:04Z
SecondChildVoteTAG: 0
SecondChildTAG: and I did the practice set. I always do it the practice set first.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-09T04:42:56Z
SecondChildVoteTAG: 0
IndexTAG: 1158
TitleTAG: the area under the curve applet
This is a great tool (especially now I am using Firefox!!)
There are one or two trifling matters which would be nice to clear up, though:
1. "SticGui" appears on top of the answer to selected area, I have been unable to move anything around and have to select the answer with a dragged cursor to see what it is
2. Is it not supposed to take 4 decimal places?
3. Sometimes it seems to add a digit to the end of what I have entered
UserIdTAG: 7854
UserNameTAG: pejic
CreateTimeTAG: 2013-03-07T20:06:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1159
TitleTAG: Why x/M in the answer?
What is this answer? I thought Markov's inequality was = M/x which, in this case, means 6.2/15.5 and equals the 40% mentioned above as being the % => x (x is 15.5).
Why do x/M?
UserIdTAG: 1074797
UserNameTAG: ElizabethDelbreil
CreateTimeTAG: 2013-03-07T19:56:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: In the words of SusanAust - did you click on Show Answer?
After the submission date you can see the correct answer and an explanation of how you arrive to it.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-08T02:27:43Z
FirstChildVoteTAG: 0
IndexTAG: 1160
TitleTAG: Very important for me.
Would you please prolong the due time for exercise 6 for half an hour. the 2ed week I have a condensed course on my job that makes me loss time to follow. this the 1st time to face this problem.
UserIdTAG: 536841
UserNameTAG: Manalhassan
CreateTimeTAG: 2013-03-07T19:53:21Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Exercise Set 6's due date was yesterday. They are not going to reopen it.
It's not the end of the world. Do the Problems anyway, learn from them even though they won't be graded, then move on to Week 3.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T19:58:44Z
FirstChildVoteTAG: 0
SecondChildTAG: That is OK, i am already do that. Thank you very much
SecondChildUserIdTAG: 536841
SecondChildUserNameTAG: Manalhassan
SecondChildCreateTimeTAG: 2013-03-07T20:42:06Z
SecondChildVoteTAG: 0
IndexTAG: 1161
TitleTAG: Problem 1A (exercise set 8)
The solution in this exercise is wrong. Since z = 2.4 and when typing this into the SticiGui tablet (upper point) shows to be 49.18% I don't understand why the answer shows to be 0.82%
Thanks
Luis Nieto
UserIdTAG: 1281597
UserNameTAG: Luisns10
CreateTimeTAG: 2013-03-07T19:50:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: >The solution in this exercise is wrong
Really? If you say so. Others would disagree.
You should post in the correct forum. Posting this under Exercise 1 hides it. Which is good, seeing as you have decided to ignore the Prof's comment on the Honor Code.
Do you understand what the $z$ means? And what the total area under the curve is? If you had understood the Normal process you would have seen instantly that you were wrong. You need to look at the shaded curve, as well as the answer. Does it look right?
How to post in correct forum (scroll down):
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/51320ee24bebda2b000000c4
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T21:23:51Z
FirstChildVoteTAG: 0
IndexTAG: 1162
TitleTAG: How can I be added to the student directory?
Hello.
I´m not in the student directory list. How can I be added to the student directory?
UserIdTAG: 1279047
UserNameTAG: loriase
CreateTimeTAG: 2013-03-07T19:38:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You have to add it yourself in the wiki page
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T19:40:23Z
FirstChildVoteTAG: 0
SecondChildTAG: It's not mandatory or required, but if you wish to let others know you a little better, you can put yourself on it and link your facebook or blog sites.
SecondChildUserIdTAG: 683854
SecondChildUserNameTAG: Flighthawk
SecondChildCreateTimeTAG: 2013-03-07T22:46:37Z
SecondChildVoteTAG: 0
SecondChildTAG: ok thanks!
SecondChildUserIdTAG: 1279047
SecondChildUserNameTAG: loriase
SecondChildCreateTimeTAG: 2013-03-09T17:11:41Z
SecondChildVoteTAG: 0
IndexTAG: 1163
TitleTAG: Problem 2a
I don't even know where to begin with this. Do I need to make the avg 0 and sd 1, or is it as simple as just subtracting to find the average? Maybe I should watch the lectures again...
UserIdTAG: 1018852
UserNameTAG: sansquamtch
CreateTimeTAG: 2013-03-07T19:20:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Average and SD don't have anything to do with Exercise Set 1, but that's the section where you posted this.
We can't help if we don't know what you are talking about.
Although re-watching the lectures is never a bad idea ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T20:01:12Z
FirstChildVoteTAG: 1
IndexTAG: 1164
TitleTAG: Learning vs Weekly Deadlines
I missed the deadline to do Week 2 exercises due to computer and internet problems yesterday. Full credit matters to me as, I am applying to a master's program, and even if the credit doesn't transfer officially, the graduate adviser may have the discretion to wave the prerequisite in consideration of taking a course such as this. I will now go to Udacity's statistics courses which let us go at our own pace without and artificial penalty based on something that has nothing to do with whether we've learned the material, nor with any relation to real-world success.
So, the question is, Is there some point to weekly hard deadlines? Is the point to just weed people out people who, like me, are not fortunate enough have home Internet connections and spare computers? Yes, if I had anticipated problems, I would have done it earlier in the week, but life if busy and one schedules.
UserIdTAG: 537121
UserNameTAG: kelceywilson
CreateTimeTAG: 2013-03-07T18:57:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: I am surprised the graduate adviser may wave a pre-req because you can easily get the answers.
Discipline for these deadlines. In life, most procrastinate and need deadlines.
I do not recommend a Masters program without home internet connection or a space computer. If you cant afford these, how will you afford the Masters program?
FirstChildUserIdTAG: 277481
FirstChildUserNameTAG: scott520
FirstChildCreateTimeTAG: 2013-03-07T19:01:09Z
FirstChildVoteTAG: 0
FirstChildTAG: I teach at the post doctoral level and also undergraduates and am a student here .I can tell you that if you cannot stick to deadlines then it will be a problem in your later coursework for your Masters and it does help to learn to stick to these (let alone in real life where all work comes with deadlines !!)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T19:20:11Z
FirstChildVoteTAG: 0
FirstChildTAG: > , I am applying to a master's program, and even if the credit doesn't transfer officially, the graduate adviser may have the discretion to wave the prerequisite in consideration of taking a course such as this.
Seriously? I hope the advisor comes and looks at the material, and then sits you down with an equivalent exam and gets you to do it.
>So, the question is, Is there some point to weekly hard deadlines?
Well, good luck with your Masters if you don't like deadlines.
>but life if busy and one schedules.
And priorities matter.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T21:17:06Z
FirstChildVoteTAG: 0
FirstChildTAG: I would understand your comments if the passing grade was higher, say 85%, where every point counts. The way it is now for this course, you can skip more than one (and two, and three,...) of the PS and still get it done. Come on! It is 35%!!! They are making your life as easy as possible.
An interesting discussion would be: Self vs fixed pace for Online platforms (Coursera, edX, Udacity,...) and that has many factors: How do you change PS or exams that has been there for too long, honor code in both systems,...
...but none of this really applies to your problem.
FirstChildUserIdTAG: 1024715
FirstChildUserNameTAG: iparrajorge
FirstChildCreateTimeTAG: 2013-03-07T21:19:36Z
FirstChildVoteTAG: 0
FirstChildTAG: I've been studying by distance means (first by post then online) at undergraduate and postgraduate level for over twenty years but I still value the framework offered by deadlines. However strong one's own self-discipline, there are always things happeing in 'real life' that offer the excuse to just put off that work for a few days... and that can be a slippery slope.
I completed a bachelors degree over a six year period during which virtually all my studying was done in hotel bedrooms as I was working across Europe as a radio engineer designing and installing systems. Without the regular monthly assignments I would probably still be working on it now, twenty years later!
As a project manager, business owner and latterly as a teacher, I would always stress the value of time management which includes the ability to work to deadlines.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T22:22:29Z
FirstChildVoteTAG: 0
IndexTAG: 1165
TitleTAG: The area of a standard normal curve =1
I have put it in the wiki at
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/proof-area-standard-normal-curve-1/
Professors may correct me please if there are any errors.I do not know Latex well so there may be formatting errors.
$\phi(x)=\frac{1}{\sqrt2\pi}.e^ {-\frac{1}{2}x^2}dx$
$\int\phi(x)=\frac{1}{\sqrt2\pi}\int e^ {-\frac{1}{2}x^2}dx$
= $\int\phi(x)=\frac{1}{\sqrt2\pi}\int e^ {-\left(\frac{x}{\sqrt2}\right)^2}dx$
= $\int\phi(x)=\frac{1}{\sqrt2\pi}\int e^ {-\left(\frac{x}{\sqrt2}\right)^2}\frac{dx}{\sqrt2}.\sqrt2$
= $\int\phi(x)=\frac{1}{\pi}\int e^ {-\left(\frac{x}{\sqrt2}\right)^2}\frac{dx}{\sqrt2}.\sqrt2$
= $\int\phi(x)=\frac{1}{\sqrt2\pi}\int e^ {-\left(\frac{x}{\sqrt2}\right)^2}\frac{dx}{\sqrt2}.\sqrt2$
= $\int\phi(x)=\frac{1}{\sqrt2\pi}.\sqrt2\int e^ {-\left(\frac{x}{\sqrt2}\right)^2}\frac{dx}{\sqrt2}$
= $\int\phi(x)=\frac{1}{\sqrt\pi}.\int e^ {-\left(\frac{x}{\sqrt2}\right)^2}\frac{dx}{\sqrt2}$
but $\int e^ {-\left(\frac{x}{\sqrt2}\right)^2}\frac{dx}{\sqrt2} = \pi$ as it is a Gaussian integral of the form $\int e^{-x^2}=\sqrt\pi$
So,
$\int\phi(x)=\frac{\sqrt\pi}{\sqrt\pi}=1$
$QED$
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-07T18:49:13Z
VoteTAG: 1
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.1: Bell shaped curves; the standard normal curve
NumberOfReplyTAG: 2
FirstChildTAG: Not sure why the thing did not come out here correctly despite the $ signs whereas in the wiki it does !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T19:06:11Z
FirstChildVoteTAG: 0
FirstChildTAG: Prasannasimha, thanks for this. I believe what you've done is assumed the answer to the "Gaussian integral" and then shown that our introduction of scale factors of 1/2 etc make everything work out. That's in fact true, but it's the straightforward part. The heart of the question is, "Why is the Gaussian integral equal to the square root of pi?" That takes more work. Look up Gaussian integral on Wikipedia. You'll find more than one derivation there. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-07T19:59:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you.I assumed the value of the Gaussian integral as a "standard derivation" which I will correct.
Out of curiosity was the Gaussian integral derived for the sake of the standard normal curve historically ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T02:36:18Z
SecondChildVoteTAG: 0
IndexTAG: 1166
TitleTAG: Feedback advanced
Usually we are asked for feedback at the end of these courses. You may take this message as an advance.
What do you have against a clock?
The amount of problems that the time reference has generated should make somebody come to the brilliant conclusion that something should be done about it.
In every important activity establishing standards is normal and in these kind of courses it is a standard that the student usually finds recorded somewhere what date and time the institution is using. For example, when a student take a test, the answers come together with the record of the date and time the test was taken.
Some institutions place in a visible part of the web page the remaining time before an event (in red when is running out). We do not claim such delicacy on your part but no reference to the date and time anywhere is completely abnormal.
Now we're accused of not reading and following simple instructions ignoring that, full of interest and excitement, many of us can barely take a few hours of our sleep to study the material that has been delivered, for then to take the exams in the short time that we have.
You give us a great opportunity to gain important knowledge for free. Eventually the idea should not be just reminding the student what their defects are.
It is the first time in my life that I have to refer to GMT time to participate in a course of this type. The standard is the time of the institution offering the course (eg Boston for MITx). Naturally, you can use the rules that please you but you also should take into account the consequences of completely unusual practices.
A lot of people who had a genuine interest in taking the tests were unable to do so. Yes, it was their fault, that is a fact, but if you really want to do something important, place somewhere the date and time you are working with. That is what is usually done and, in the future, it will reduce the size of problems such as the one just presented.
UserIdTAG: 450068
UserNameTAG: RafaelAntonio
CreateTimeTAG: 2013-03-07T18:48:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 9
FirstChildTAG: [Policies and Requirements][1]
This is on the main page for the course, and that should suggest that it's a fairly important link. It's one(1) page, so it doesn't take much to read it. It clearly states that:
> Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
I don't know what more you could want...
[1]: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T18:54:12Z
FirstChildVoteTAG: 0
FirstChildTAG: The date and time have been clearly mentioned as referring to GMT in the courseware policies and requirements
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
The actual extract is
Grading
● Exercise Sets are due at specified dates and times. All times are in Greenwich Mean
Time (GMT)
which was clearly mentioned and placed **before the start of the course**
Also I think it was clarified a zillion times when the last test was announced that it will be GMT too.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T18:58:57Z
FirstChildVoteTAG: 0
FirstChildTAG: > The amount of problems that the time reference has generated should make somebody come to the brilliant conclusion that something should be done about it.
Only for people who can not or will not for whatever reason read and follow instructions.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T19:28:25Z
FirstChildVoteTAG: 0
FirstChildTAG: > What do you have against a clock?
What do students have against taking responsibility for their own time management?
>The amount of problems that the time reference has generated should make somebody come to the brilliant conclusion that something should be done about it.
How about the student doing something? The staff are not our parents. We should be able to figure out the time ourselves. It's not difficult.
>Now we're accused of not reading and following simple instructions ignoring that, full of interest and excitement, many of us can barely take a few hours of our sleep to study the material that has been delivered
If you are not prepared to read the Course Policies, then you have no-one to blame but yourself. The Policy has been there since Day 1. If you have such serious time issues, then maybe you need to reconsider the course.
>It is the first time in my life that I have to refer to GMT time to participate in a course of this type
And I have done courses in different zones, while living a totally different zone. It can be done.
>Naturally, you can use the rules that please you but you also should take into account the consequences of completely unusual practices
Define "completely unusual practices". Given the different languages and cultures here, everything would fall under that heading for someone somewhere.
>A lot of people who had a genuine interest in taking the tests were unable to do so. Yes, it was their fault, that is a fact, but if you really want to do something important, place somewhere the date and time you are working with.
Yes, 100% their own fault. They had a full week. And the time is now very clearly displayed. Will it help? Probably not. There are always those who will blame others for their own failings.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T21:10:57Z
FirstChildVoteTAG: 0
FirstChildTAG: I really don't get the problems with GMT. It was the original standard after all!!!
The idea of using the time at the University offering the course looks fine in principle BUT what happens when more than one school is involved? (Not happening yet in edX but it is in Coursera)
Wouldn't it be wonderful if all the courses in all the platforms referred to exactly the same time? Why not use GMT then?
I agree with you that a clock running down the time left to finish a given PS would be a good addition, but that is it, an addition, an improvement, not something to get all angry about because somebody didn't read the rules.
FirstChildUserIdTAG: 1024715
FirstChildUserNameTAG: iparrajorge
FirstChildCreateTimeTAG: 2013-03-07T22:19:48Z
FirstChildVoteTAG: 0
FirstChildTAG: > Some institutions place in a visible part of the web page the remaining time before an event (in red when is running out).
I like this. Cool. :)
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-03-07T22:37:11Z
FirstChildVoteTAG: 0
FirstChildTAG: I think it would be very interesting to see what percentage of the students in the class actually failed to submit the exercises on time, and perhaps try to infer from that how many find themselves powerless against the great mysteries of GMT.
It *seems* like an overwhelming issue from reading the forums, where the only thread missing is from the Doctor stating that he just got out of the TARDIS, and couldn't submit it before, and it's not even March 6th, and he shouldn't be punished for being an alien.... But in my experience with forums, the participants are usually a vocal majority.
Would be some context to the alleged issue. Still wouldn't necessarily make it a problem, but get some data on whether they may want to change the structure of the pages a bit.
The way I see it though is: they are generously offering us the opportunity to learn. They don't owe us a certificate and it's our responsibility to put in the effort to follow the course rules and give them reasons to pass us, unburdened by expectations of this free course, outside of what the staff have committed to with the policies.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-08T02:11:36Z
FirstChildVoteTAG: 0
SecondChildTAG: We have discussed TARDIS yesterday.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-08T02:23:49Z
SecondChildVoteTAG: 0
SecondChildTAG: I am so out of touch with the zeitgeist...
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-08T02:29:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Patiently waiting for the new Dr Who episodes...
It is quite amazing, to me, the expectations of some. I've seen posts (not here) where students were very militant in their demands. They basically expected the academic staff to cater to their every whim - immediatley. Made me very pleased that they weren't students in any of my classes!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-08T03:10:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I am pretty sure taunting other students with your patience is against the forum guidelines :-P
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-08T03:31:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Klionheart, it would be a great thing if you make an effort for "understanding" what you are "reading".
Look, genius, I'm talking about a normal practice in any institution of this type.
These are common examples:
University of Illinois at Urbana-Champaign
You submitted this quiz on Sun 3 Mar 2013 8:22 PM PST. You got a score of 14.00 out of 14.00.
Berklee College of Music
Lesson 1 Assignment
Submission due on Mon 11 Mar 6:00 am (2 days, 21 hours)
Lesson 2 Assignment
Submission due on Mon 18 Mar 6:00 am (1 week, 3 days)
It is common practice putting date and time in a visible place in this type of learning institutions. If this institution does not want to and you have to take courses in those conditions is a special case.
FirstChildUserIdTAG: 450068
FirstChildUserNameTAG: RafaelAntonio
FirstChildCreateTimeTAG: 2013-03-12T17:15:47Z
FirstChildVoteTAG: 0
FirstChildTAG: SusanAust, you are the type of people that do not sell an umbrella amid a downpour.
Everyone strives to provide a better service and that's exactly what I'm talking about: giving a better service giving a service that everyone gives, but that's something I really do not pretend you to understand.
This platform needs to be updated and there is nothing wrong if someone reminds it to them.
FirstChildUserIdTAG: 450068
FirstChildUserNameTAG: RafaelAntonio
FirstChildCreateTimeTAG: 2013-03-12T17:32:18Z
FirstChildVoteTAG: 0
SecondChildTAG: > SusanAust, you are the type of people that do not sell an umbrella amid a downpour
I'd give you the umbrella or better yet, invite you inside.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-20T00:51:20Z
SecondChildVoteTAG: 0
IndexTAG: 1167
TitleTAG: Shortcut procedure
i think this term is little bit hard
..so i need help if anyone provides me shortcut procedure to find the correct value ...........
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-07T18:30:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: There is no shortcut procedure, and the question is not really a difficult one.
You can solve for mean and SD with the data you are given.
Remember that in general Z=(x-m)/sd
That is everything you need to solve the question really. You will end up with two equations and two variables. Once you found m and SD, finding the 90th percentile is very easy.
Good luck.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T18:46:33Z
FirstChildVoteTAG: 0
FirstChildTAG: Or you could look at the practice problem where you have to fill in a couple of entries in a table of standard units. The explanation uses a method that doesn't require simultaneous equations. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-07T20:00:34Z
FirstChildVoteTAG: 0
SecondChildTAG: ^^
True. I must be the only one who likes solving equations instead of using available technology :-)
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T21:15:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Equations are great; I use them all the time ... :) But I'm a firm believer in the Berkeley approach to elementary statistics: you should be able to "see it in a picture" if at all possible. But if you're at ease with solving equations, then solve away. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-07T22:11:41Z
SecondChildVoteTAG: 0
SecondChildTAG: I wish my undergrad stats Prof was using visualization as opposed to mumbling to himself for 3 hours straight..
Prof. A, your teaching style reminds me so much of my grad game theory prof @ Kellogg (NorthWestern), which is great. He made me understand and love mathematical concepts. Without him, I would have never been able to slug thorough my MBA finance courses. Thanks again for doing this Prof. A.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T23:58:55Z
SecondChildVoteTAG: 0
IndexTAG: 1168
TitleTAG: download link
Missing Download Link for Lecture 5.4 video. Kindly add the Link.
UserIdTAG: 558560
UserNameTAG: wasimpak
CreateTimeTAG: 2013-03-07T17:24:36Z
VoteTAG: 15
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 0
IndexTAG: 1169
TitleTAG: LECTURE 5.4
Why isn't this lecture available to download like the rest of the lectures?
UserIdTAG: 900452
UserNameTAG: PBOD
CreateTimeTAG: 2013-03-07T16:49:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They introduce the other lectures. They dont seem to have actual information in them.
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-07T20:32:11Z
FirstChildVoteTAG: 0
IndexTAG: 1170
TitleTAG: Practice Problems?
Does anyone know of a good source for more practice problems on this topic? The more practice, the more comfortable I become.
UserIdTAG: 1218219
UserNameTAG: dlegg
CreateTimeTAG: 2013-03-07T16:17:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Have you exited and then gone back into the online text (Sticigui)? Some of the problem sets will change each time you re-enter.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-07T16:26:52Z
FirstChildVoteTAG: 0
IndexTAG: 1171
TitleTAG: problem with video
i'm unable to watch the video after 16:02..it is staring again from first..can any one help me with this??
UserIdTAG: 795263
UserNameTAG: esh
CreateTimeTAG: 2013-03-07T15:50:12Z
VoteTAG: 0
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 1
FirstChildTAG: maybe you can download the video.
FirstChildUserIdTAG: 157670
FirstChildUserNameTAG: _Nelson_
FirstChildCreateTimeTAG: 2013-03-08T00:17:07Z
FirstChildVoteTAG: 0
SecondChildTAG: try watching on youtube
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-10T23:54:42Z
SecondChildVoteTAG: 0
IndexTAG: 1172
TitleTAG: Posted R code for Exercise Set 3 in wiki
I've posted R code for Exercise Set 3. Code for Exercise Set 2 does not make sense due to the nature of problems in that set (easy hand calculations or graph interpretation).
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/R/ES_3_Solutions/
This code implements R functions for percentiles. The second one is only given for the sake of completeness (R already provides the `quantile()` built-in function to compute percentiles from a list of values).
Although I use R as a tool, I've hardly experience with R programming. You know, using a function is not the same as coding functions in a specific programming language. So my solutions might be overcomplicated or against the "R" style of coding. Be free to make enhancements if you want.
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-07T15:35:12Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Atopos:
Perhaps you like this course:
https://www.coursera.org/course/pdstatistics
It start March 25th.
It is about statistics using SAS
I'd like to have you as fellow
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-08T14:08:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks for your kind words, jorge.
I'm afraid I cannot enrol in that course.
First reason: lack of time. The Stat2.1x schedule (exams) is actually very tight for me. I don't know if I'll be able to take the Midterm (maybe I'll try it). Regarding the Final, not sleeping that night is my only chance (that day my job is already scheduled from 8 A.M to 24 P.M (travelling, meetings, classes, and so on). So I have to rely completely on the Exercise Sets. Otherwise, because I have to choose only one course at a time, I'd like, if I can, to follow Stat2.2/3. Lectures are fantastic. I recommend you not leaving this awesome opportunity from edX.
The second reason is that I haven't got a Windows machine (required for SAS). I'm a Linux guy and a free/open software advocate for ages. Hence I prefer to keep working with R. I like R and I'm beginning to appreciate its power and flexibility, and, as you probably know, R is released under the GPL licence: two gifts in one.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-08T21:50:32Z
FirstChildVoteTAG: 0
IndexTAG: 1173
TitleTAG: Where are the solutions
How can I access the solutions to assignments after the due date? Thanks
UserIdTAG: 1303909
UserNameTAG: Sharmar
CreateTimeTAG: 2013-03-07T15:27:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Go to the Exercise Sets again. Click "Show Answer" below every Problem ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T16:00:20Z
FirstChildVoteTAG: 1
IndexTAG: 1174
TitleTAG: Midterm exam release time (GMT)
Hi,
Can you please publish the mid-term exam release time (GMT) on the 13th?
Thanks!
UserIdTAG: 1163738
UserNameTAG: ronitadiv
CreateTimeTAG: 2013-03-07T14:39:00Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: How can I access solutions to problems after turning in assignments? Thanks
FirstChildUserIdTAG: 1303909
FirstChildUserNameTAG: Sharmar
FirstChildCreateTimeTAG: 2013-03-07T15:17:11Z
FirstChildVoteTAG: 0
FirstChildTAG: I am wondering the same thing. Also, do we have to complete this exam on Wednesday or do we have a whole week? I was under the impression that we never had to do assignments on a specific day, but the wording on the main page seems to indicate the contrary.
FirstChildUserIdTAG: 1109996
FirstChildUserNameTAG: ARober
FirstChildCreateTimeTAG: 2013-03-07T19:00:32Z
FirstChildVoteTAG: 2
FirstChildTAG: So far as I am aware, the exams must be taken on the day issued. I'm sure I've seen a discussion to that effect with the course team but can't put my finger on it at the moment.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T19:45:00Z
FirstChildVoteTAG: 0
FirstChildTAG: do you mean that we only have a day to complete the midterm? please clarify !!
FirstChildUserIdTAG: 1040395
FirstChildUserNameTAG: Bcandelario
FirstChildCreateTimeTAG: 2013-03-07T19:57:54Z
FirstChildVoteTAG: 1
SecondChildTAG: The Professor confirmed in answer to the question "how long will we have to complete the Exam?":
> Any time that day [13th]. I'll post the exact period, but you'll certainly
> have a day.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T23:15:45Z
SecondChildVoteTAG: 0
IndexTAG: 1175
TitleTAG: progress bars
I'm un-certain as to what th bars ES Avg. and Total represents... anyone?
UserIdTAG: 950367
UserNameTAG: catt9
CreateTimeTAG: 2013-03-07T14:19:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: ES Avg. is your average for the Exercise Sets(ESs) only.
Total is your average for everything put together (ESs + Midterm + Final).
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T14:34:23Z
FirstChildVoteTAG: 1
SecondChildTAG: I'm still confused. th ES avg. bar is shorter than ALL th other bars excepting th Total bar; and th Practice Exercises don't count towards anything, do they?
SecondChildUserIdTAG: 950367
SecondChildUserNameTAG: catt9
SecondChildCreateTimeTAG: 2013-03-07T14:54:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, because it counts ES 9 and 10 as 0%, since we haven't had the chance to do them yet. ES 11 and 12 are excluded as the two lowest: see the black X? If you have a 100% grade on ES 1 to 8, the ES Average would then be $\frac{100*8}{10}= 80\%$. You know, just like any other average we study in the course ;)
Total is a bit different, as it only counts the ES Average for 50%, the Midterm for 20%, and the Final for 30%, and adds the results. The max you can have there for now is 40% ($80*0.5+0*0.2+0*0.3$)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T15:52:46Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you.
SecondChildUserIdTAG: 950367
SecondChildUserNameTAG: catt9
SecondChildCreateTimeTAG: 2013-03-07T16:23:35Z
SecondChildVoteTAG: 0
FirstChildTAG: Es average is the average result of the assignments you have done but drops the lowest two scores. At the moment that will be dropping zeroes from 2 of the incomplete assignments. total is the percentage of the final grade you have already achieved and factors in Es with your results from the midterm and the final both of which will currently be zero.
The goal for total is the pass grade of 35% so you can see how close you are to gaining the certificate by the horizontal line.
FirstChildUserIdTAG: 1030056
FirstChildUserNameTAG: RBartram
FirstChildCreateTimeTAG: 2013-03-07T14:35:20Z
FirstChildVoteTAG: 0
IndexTAG: 1176
TitleTAG: Standard Normal Curve
Thank you so much Prof A. Adhikari for this wonderful course. I was very much excited when I was going through your lectures on Standard Normal Curve and this curve indeed generates a lot of curiosity in my mind. Following are few questions I have on this topic. Can you please answer them at your convenience? I will be delighted and grateful to hear your response on them -
1) From where, we got this difficult equation, f(z)= (2pi)1^2 * e^(-z^2) - I may not be able to write this correctly here, but I think you have understood which equation, I am referring to. Also, can we have its derivation as well in the supplements?
2) By intuition, I can understand the areas under a normal curve is 1 as all the sample has to be under it, but can you please provide the proof using integral calculus in the supplements?
3) When z was replaced with (x-u)/s, we saw that the equation has got an additional sigma under the (2pi). How did it come? Can you also provide the derivation when the curve changes from z to x in the supplements?
4) When working on proportion of sample in between a & b under the curve, so the range a,b is indeed [a,b), correct? like histograms notation. Please correct me if I am wrong here
5) As a thumb rule, how many percentage points difference between normal curve approximations and actual histograms should be enough to assume normal curve approximations to that sample?
UserIdTAG: 1091284
UserNameTAG: rabi221080
CreateTimeTAG: 2013-03-07T14:09:17Z
VoteTAG: 7
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.2: Normal curves: relation to the standard normal
NumberOfReplyTAG: 2
FirstChildTAG: I also wanted to ask about question 3) where this additional Sigma comes from? and BTW it is not under the square root, it should be written as: Sigma * sqrt(2*pi)
The x-based formula is correct, what about z-based normal distribution?
FirstChildUserIdTAG: 255838
FirstChildUserNameTAG: EngineerHrenov
FirstChildCreateTimeTAG: 2013-03-10T11:45:09Z
FirstChildVoteTAG: 0
FirstChildTAG: I have posted the derivation in the wiki at
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/proof-area-standard-normal-curve-1/
Be warned that the second part (proving the Gaussian Integral has to be still verified by the Professors.)
As for the new sigma coming in when you integrate you are substituting $x$ as $z=\frac{(x-\mu)}{\sigma}$ so you will have to reintegrate your substitution and include it (Integration by substitution)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-11T02:41:02Z
FirstChildVoteTAG: 0
IndexTAG: 1177
TitleTAG: Set 7 Problem 4 Wrong Description
Dear Stuff,
I just finished working on the problem 4 set 7 and i found out the correct answers. However, there is a note which says:
Note: the first blank corresponds to the higher entry box; the second blank corresponds to the lower entry box.
As i understand this the higher value should be placed in the first entry box and the lower in the second one. Am i right? Unfortunately i did this and my question was marked wrong. The higher value is placed in the second box and the lower in the first one. How can this be fixed? i believe it is not my fault or did i do something wrong?
Thanks
UserIdTAG: 1256931
UserNameTAG: Jhoara
CreateTimeTAG: 2013-03-07T13:52:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Your understanding is not correct. There are two entry box above one another, one is over the other. There is thus one "higher box" at the top, and another "lower box" at the bottom. Nothing about the hight of the values can be assumed.
By the way, your entry is in the wrong discussion forum. By filing it in the "Exercise Set 1" Forum, you risk that many students who could be interested in your question miss it.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-07T14:18:28Z
FirstChildVoteTAG: 0
SecondChildTAG: I got it now. So bad i understood it wrong cuz i got the right answers. Thanks for your answer.
BTW i didnt notice i posted this in Exercise Set 1. I thought it was posted in Exercise set 7.
Cheers
SecondChildUserIdTAG: 1256931
SecondChildUserNameTAG: Jhoara
SecondChildCreateTimeTAG: 2013-03-07T15:06:32Z
SecondChildVoteTAG: 0
IndexTAG: 1178
TitleTAG: Why "n-1" for a sample?
ok, here goes what mighty be a silly question...
To calculate Variance or SD for a population, in some point it’s necessary to do a division by “n”.
So, why on Earth for a sample is it necessary to do a division by “n-1”?
UserIdTAG: 1091568
UserNameTAG: Yughues
CreateTimeTAG: 2013-03-07T13:17:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Sorry,
Are you referring to the n-1 that does not work in descriptive analysis?
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-03-07T13:35:54Z
FirstChildVoteTAG: 0
SecondChildTAG: Well, I'm not sure if "n-1" does or does not work in descriptive analysis (for what I've read we could spend some time discussing that), but as it is mentioned in the SticiGui, I got curious and dissatisfied with the explanation offered on the on line book.
So, could you help me?
SecondChildUserIdTAG: 1091568
SecondChildUserNameTAG: Yughues
SecondChildCreateTimeTAG: 2013-03-07T14:50:14Z
SecondChildVoteTAG: 0
FirstChildTAG: Very simply put, using n-1 is a better approximation when you are working with a sample of data and not the entirety of it.
For a more detailed explanation, that's beyond what we are covering in this course, have a look [here][1].
[1]: http://en.wikipedia.org/wiki/Bessel%27s_correction
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T13:55:11Z
FirstChildVoteTAG: 0
SecondChildTAG: That's it. Bessel's correction filled my hunger for knowledge.
Thank you Klionheart for the appropriate answer.
SecondChildUserIdTAG: 1091568
SecondChildUserNameTAG: Yughues
SecondChildCreateTimeTAG: 2013-03-07T16:05:04Z
SecondChildVoteTAG: 0
IndexTAG: 1179
TitleTAG: exercise set 8 - problem 1c
Hi, I don't want to get result, I only want to know how I should understand the problem - what percent of adults are 70 inches tall, to the nearest inch. I thought it means 70 to 70.9999... inches, it would be 3.2 per cent then. But I'm obviously wrong. Somebody who found the right answer could explain, what I should be actually looking for. No the result, I want to calculate it myself.
UserIdTAG: 1341242
UserNameTAG: alesbadura
CreateTimeTAG: 2013-03-07T13:09:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Or is it between 69.5 to 70.499?
FirstChildUserIdTAG: 1341242
FirstChildUserNameTAG: alesbadura
FirstChildCreateTimeTAG: 2013-03-07T13:12:30Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes. that is right.
SecondChildUserIdTAG: 1341242
SecondChildUserNameTAG: alesbadura
SecondChildCreateTimeTAG: 2013-03-07T13:16:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Did you guys manage to find out? i have the same problem now.
SecondChildUserIdTAG: 1256931
SecondChildUserNameTAG: Jhoara
SecondChildCreateTimeTAG: 2013-03-07T16:44:29Z
SecondChildVoteTAG: 0
IndexTAG: 1180
TitleTAG: Little bit too easy
This exercise set is a little bit too easy compared to the previous one.
UserIdTAG: 148610
UserNameTAG: schwanke
CreateTimeTAG: 2013-03-07T12:26:10Z
VoteTAG: 5
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 4
FirstChildTAG: what !!!!!!!!!!!!!!!!!!!
FirstChildUserIdTAG: 1042429
FirstChildUserNameTAG: Rifayat
FirstChildCreateTimeTAG: 2013-03-07T13:02:44Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, but it got us thinking about what questions to ask the applet
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-07T19:43:36Z
FirstChildVoteTAG: 1
SecondChildTAG: ok, I agree
SecondChildUserIdTAG: 148610
SecondChildUserNameTAG: schwanke
SecondChildCreateTimeTAG: 2013-03-08T05:59:49Z
SecondChildVoteTAG: 0
FirstChildTAG: It's intentional, because his material is going to be on the midterm which is directly after the exercises are due. I explained this in the course update. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-07T20:07:13Z
FirstChildVoteTAG: 2
SecondChildTAG: dear prof
the scoring system seems not functioning , all my answers were correct in exc 8 bu the progress did not showed the bar accordingly!!!!!!1
SecondChildUserIdTAG: 689363
SecondChildUserNameTAG: sehamballa
SecondChildCreateTimeTAG: 2013-03-10T19:35:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks, Prof. A nice restful ES that took about 5 minutes to complete but gave an opportunity to practice transforming a stated problem to fit the available tools.
Bonus is that ES 8 pushes me over the 35% line (now at 39%) so doubly pleased.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T23:43:29Z
FirstChildVoteTAG: 0
IndexTAG: 1181
TitleTAG: Problem 3B
Either the question is incorrectly asked or the explanation is wrong. The number given in the explanation for the score multiplication does not match the number in the question. Please advise.
UserIdTAG: 895423
UserNameTAG: joshea68
CreateTimeTAG: 2013-03-07T11:49:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 3
FirstChildTAG: try reading the explanation for problem 3A first
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-07T12:01:29Z
FirstChildVoteTAG: 3
FirstChildTAG: The truth is that after reading the explanations it seems much easier
FirstChildUserIdTAG: 961907
FirstChildUserNameTAG: ngarin
FirstChildCreateTimeTAG: 2013-03-07T14:12:10Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree with the original post . . . even after reading the answer, I have NO idea how they got that answer!!
FirstChildUserIdTAG: 919673
FirstChildUserNameTAG: ldh
FirstChildCreateTimeTAG: 2013-03-08T18:26:52Z
FirstChildVoteTAG: 0
SecondChildTAG: Refer to the below thread:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_7/threads/513c3e63e8c82427000000e9
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-10T11:11:31Z
SecondChildVoteTAG: 0
IndexTAG: 1182
TitleTAG: Usefulness of Forum
Although multiple posts about the same issue or the same sorts of issues do clog up the forum and make it more difficult to find germane and useful information about the content of the course, multiple posts *about the people* who make such posts, don't read policies/instructions, or complain, also clog up the forum. These posts seem to serve no purpose except to force people who are looking for good information to read through the snark--which is unpleasant. There doesn't seem to be a way to block individual posts or posters? Am I missing a feature in the forum? Being able to block people from view who contribute offensively would be a great addition to the platform. I assume the course staff cannot make changes to the platform but perhaps, the edX developers?
UserIdTAG: 986983
UserNameTAG: Dianebefd
CreateTimeTAG: 2013-03-07T11:29:24Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: A way around this would be a subforum for complaints / issues and other posts not directly related to the course as well as ones for just general discussion and more as they seem crop up. Mods could then move any post going 'GMT BAAAAAAH!' for example to these subforums.In fact they could even make sub sub forums for common topics like GMT BAAAAAAH! and for decimal places.
FirstChildUserIdTAG: 954932
FirstChildUserNameTAG: hellothomasjohnson
FirstChildCreateTimeTAG: 2013-03-07T11:48:33Z
FirstChildVoteTAG: 1
IndexTAG: 1183
TitleTAG: prob 4
which rule i should use .i am confused.
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-07T11:26:41Z
VoteTAG: 6
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Start with adjusting the SD by a multiplication factor, then sees what that same multiplication factor does to the average1 to produce average-temp, then work out what constant has to be added to adjust the average-temp to the average required in the question.
FirstChildUserIdTAG: 895423
FirstChildUserNameTAG: joshea68
FirstChildCreateTimeTAG: 2013-03-07T11:53:11Z
FirstChildVoteTAG: 0
SecondChildTAG: prevs sd is 25 and i hv 2 make it 10 by multification !!!is ths pssible !!!
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-07T11:56:16Z
SecondChildVoteTAG: 0
SecondChildTAG: can there be 3 submishns?it will help us more 4 undrstand the probs
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-07T11:58:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Rifayat, instead of dividing something you can also multiply it by its inverse/reciprocal. Look at this explanation, may be it helps: http://www.mathsisfun.com/fractions_division.html
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-07T12:18:24Z
SecondChildVoteTAG: 0
SecondChildTAG: i am sorry bt in the prolem there is no fractn.so it didnt help me !!!
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-07T12:47:34Z
SecondChildVoteTAG: 0
SecondChildTAG: *Hint:* a fraction can also be written as a decimal number.
For example, $\frac{1}{10}$ can also be written as $0.1$.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T13:46:08Z
SecondChildVoteTAG: 0
SecondChildTAG: How do you transform 25 to 10?
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-07T14:14:05Z
SecondChildVoteTAG: 0
SecondChildTAG: (@ Rifayat)
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-07T14:14:23Z
SecondChildVoteTAG: 0
SecondChildTAG: hey i got the values of multiplication factor and the constant factor. i plug in to the equation and it fits perfectly fine. but i am getting my answer as wrong ..how . both my multiplication factor and the constant factor to add are decimal to one place. what am i missing
SecondChildUserIdTAG: 1253175
SecondChildUserNameTAG: yn9876
SecondChildCreateTimeTAG: 2013-03-08T22:05:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, help me a lot !
SecondChildUserIdTAG: 280481
SecondChildUserNameTAG: vitorpiro
SecondChildCreateTimeTAG: 2013-03-09T23:53:03Z
SecondChildVoteTAG: 0
IndexTAG: 1184
TitleTAG: Prob #7
can somebody please give me a hint on how to answer this one? been stuck here. thanks
UserIdTAG: 892025
UserNameTAG: gerickABM
CreateTimeTAG: 2013-03-07T10:38:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 4
FirstChildTAG: Try to find the SD and the average of the normal distribution first using the information given in the question (hint: you should get two equations with two unknowns, corresponding to the SD and average respectively).
FirstChildUserIdTAG: 1243304
FirstChildUserNameTAG: gordonheaton
FirstChildCreateTimeTAG: 2013-03-07T10:53:34Z
FirstChildVoteTAG: 5
SecondChildTAG: Thanks!
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-07T12:44:44Z
SecondChildVoteTAG: 0
FirstChildTAG: If you don't want to solve the equations that gordonheaton mentions, you can also follow the same approach as in "PROBLEM 2 Practice for Execise Set 7" This way it's even easier to solve this problem.
FirstChildUserIdTAG: 1146787
FirstChildUserNameTAG: picoto
FirstChildCreateTimeTAG: 2013-03-07T11:05:35Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks picoto, your explanation really helped me answer that question
SecondChildUserIdTAG: 844365
SecondChildUserNameTAG: jeremyliver
SecondChildCreateTimeTAG: 2013-03-07T14:59:50Z
SecondChildVoteTAG: 0
SecondChildTAG: How many decimals in the "standard units"? And how many decimals in intermediate calculus?
SecondChildUserIdTAG: 1210009
SecondChildUserNameTAG: GIAN66
SecondChildCreateTimeTAG: 2013-03-07T15:09:36Z
SecondChildVoteTAG: 0
FirstChildTAG: u complt 6,4 how !! can u plz hlp me.
FirstChildUserIdTAG: 1042429
FirstChildUserNameTAG: Rifayat
FirstChildCreateTimeTAG: 2013-03-07T11:12:16Z
FirstChildVoteTAG: 0
FirstChildTAG: I think you need to use the applet, or something similar.
FirstChildUserIdTAG: 433872
FirstChildUserNameTAG: dfburke
FirstChildCreateTimeTAG: 2013-03-08T19:16:49Z
FirstChildVoteTAG: 0
IndexTAG: 1185
TitleTAG: Proof of Chebyshev Inequality
I think we really need the proof of those fundamental theorems (Markov and Chebyshev inequalities) just to be 100% percents convinced in the validity and conditions...
UserIdTAG: 415375
UserNameTAG: ZWX
CreateTimeTAG: 2013-03-07T10:22:26Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: look in the "supplements" - next to progress button - it's all there.
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-07T10:24:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Is it just me or what, however much i go through these two, i don't grasp anything.What is the easiest way i can understand it?
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-03-07T12:54:18Z
FirstChildVoteTAG: 0
SecondChildTAG: I think schematically. Find a histogram and try to see what each one tells you specifically for this data set. Just a suggestion..
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-07T13:53:35Z
SecondChildVoteTAG: 0
SecondChildTAG: This is just my humble opinion on how to go about understanding this. There's two ways. One is to find a lecture or someone willing to give you a lecture explaining it. Two is to spend time developing your mathematical maturity. When that maturity develops to a certain level, you will begin to be able to break that thing apart and understand it.
SecondChildUserIdTAG: 878440
SecondChildUserNameTAG: rosewoodbay
SecondChildCreateTimeTAG: 2013-03-07T14:46:37Z
SecondChildVoteTAG: 0
IndexTAG: 1186
TitleTAG: What materials and techniques of learning have you been using?
So personally what I have been doing with this course is going through the lecture videos quite slowly (pausing a lot) and writing a ton of notes. I've already done over 40 pages of notes. I haven't really bothered with the online textbook because I find it a bit at odds with the rest of the material.
What about you?
UserIdTAG: 954932
UserNameTAG: hellothomasjohnson
CreateTimeTAG: 2013-03-07T09:54:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: I've never been much of a note writer, and this course is no exception for me.
I jot down the major formulas but not much beyond it, and I have a grand total of *one* page of proper notes written as of now.
I did read the online textbook extensively, though, and I make up several examples of my own for applying the concepts we learn. Most of my paper writings consist of these "self-made" exercises :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T10:15:06Z
FirstChildVoteTAG: 0
SecondChildTAG: Different than how I do things. This is why it is an interesting question for me to ask.
Personally I find it really useful being able to pause the lecture. If something goes a bit over my head initially I can think about it and look it up. The note taking helps drill it into me a bit more because it forces you to actively engage with the lecture rather than passively letting it wash over you.
But each yo their own.
Not sure how well I am long term retaining all the info though. I reckon I will start doing something similar to you for revision for the mid term and final
SecondChildUserIdTAG: 954932
SecondChildUserNameTAG: hellothomasjohnson
SecondChildCreateTimeTAG: 2013-03-07T11:44:52Z
SecondChildVoteTAG: 0
SecondChildTAG: You drill it into your mind by taking notes, I do it by applying what I just heard to an example or three :)
Too much theory goes over my head quickly, so I put thinks into practice often to understand it.
I suppose that's why I royally suck at advanced calculus: too much theory and mental trips, too few readily available practical applications xD
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T14:02:45Z
SecondChildVoteTAG: 0
SecondChildTAG: thinks = things, of course.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T14:05:10Z
SecondChildVoteTAG: 0
FirstChildTAG: Personally i take very short notes, i have like 8 pages so far.
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-03-07T12:56:29Z
FirstChildVoteTAG: 0
FirstChildTAG: I usually power through each video to get a feel for the overall concept presented in it. Then I get some big mass of numbers and run a few simulations to see the technique in practice.
Something like the quarterback rating is great for that: http://espn.go.com/nfl/qbr
I usually start the test and the additional reading materials together, so I can go back and forth referencing them as I do the questions.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T13:18:04Z
FirstChildVoteTAG: 0
FirstChildTAG: I have been searching online for other sources, which provide different examples or a different way of saying the same thing. This helps me test my comprehension.
I also watch the Courseware lectures twice; the first time, no notes, then the second time I write just the essentials.
Also, I find that if I do choose to try to answer someone's question on the Discussion forum, that makes me do a little more research and tests my own understanding.
And I use my hand-held calculator. For some reason, it has always been like a good-luck charm to me, perhaps because I am comfortable with it. Still can't always balance my check-book, but that is a different class ...
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-07T16:13:03Z
FirstChildVoteTAG: 0
FirstChildTAG: I have to admit that I've not taken any notes yet. I generally run through the lectures at 1.25 or 1.5x speed. Although the Professor is emminently clear in her exposition I find her vocal delivery a little slow for my taste so the higher speeds work out nicely. If I don't catch something the first time I'd rather run that section again than pause and read notes.
I find the lectures great at getting the ideas rolling but it is the practice exercises which really embed the learning and I repeat each exercise until I have 100% green ticks - even if I sometimes have to read the answer first!
I find the pace of the course quite manageable but I have done some of this before so I'm not coming in totally cold. It is, though, about 20 years since my last undergraduate maths course and I've never done a straight stats course at all. One of the reasons I'm taking this course is that my wife is currently in the final stages of a Psychology Masters and I'm finding my reputation as infallible oracle in matters mathematical is coming apart a bit under the strain of the large scale and heavy duty analysis she is attempting.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T22:05:34Z
FirstChildVoteTAG: 0
SecondChildTAG: PaulJM, you've just made my day. "Talks too fast" is a standard comment that I get in teaching evals at Berkeley. I can't tell you how thrilled I am that someone thinks it's slow. Yesssss!!!!
No, really. I love it. I've deliberately tried to slow my words down, mindful of the many students who are not fluent in English.
Now, if I could only have all my Stat 2.1X students watch me at a blackboard ... they see me clicking through slides one slow sentence at a time, but, "Writes faster than any human," is one of my more memorable Berkeley evaluations.
Cheers,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-07T22:22:57Z
SecondChildVoteTAG: 0
SecondChildTAG: I had the same issues myself, both in business presentations and later in teaching when I changed career. I overcame my 'need for speed' after taking a public speaking course offered in the university where I sat my post-grad teaching qualification. Seeing myself on the big screen in full flow brought home just how quickly I was speaking. I had to consciously throttle back and even some years later it still takes an effort to speak at what seems an unnaturally slow pace.
In the past I prided myself in how much material I could cram into a lesson/lecture/training session. Now I pride myself in being able to hit the timings almost to the second (even when extemporising from note cards) and taking all my students along with me. I recently had occasion to make a sales presentation, the first in many years, and was pleased to find the lessons learnt in the classroom carried across most successfully. Maybe if I'd learnt sooner I would have stayed focused on business and not moved to education!
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T23:58:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes indeed it is difficult to tlak slowly especially when you ahve a diverse gfgroup.I was giving a lecture in some foerighn countires and one of the problems indeed is that with different levels of fluency and comprehension it is easy to go fast and this indeed is a problem. I was rolling over in laughter when Prof PStark says in one videos (with something related to geometric probability in relation to a coin toss) - Am I the only one understanding whats going on here and there was abject silence !! I have seen that often when there is a quite class room the class is usually quite because they do not understand anything and don't ask and so I usually end up sopping at that time to ask questions regarding the issue at hand and need to work through the issue step by step.I teach perfusion and cardiac surgery and I love to break down these mathematically s there is a lot of basic physics needed in these though they are biological sciences which comes as a rude shock to most trainee surgeons and perfusionists !!.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-08T13:01:25Z
SecondChildVoteTAG: 0
SecondChildTAG: It is possible to change the rate of speech! I taught English language to immigrant teenagers for years. I learned quickly to speak more slowly--otherwise no one learned anything! I wish I had had a 1.25x and .5 buttons to automatically change my rate. ;)
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-11T13:18:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes indeed .I do wish I had that ability too.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-11T13:32:05Z
SecondChildVoteTAG: 0
IndexTAG: 1187
TitleTAG: MIDTERM TIMEFRAME?
Dear Stat 2.1x Team,
Please inform about the time frame we will have for the MidTerm Exam, for example how many hours we will have, starting for instance (March 13) at 14:00 GMT and ending at 19:00 GMT.
On the other hand, let us know at what time the exam will be released. On other edX courses, the exams are released, but time begins to count only when a student clicks the second page on the exam. In the first page (or landing page) normally, there is useful information with a motivational message, so people have the opportunity to go back a study some more before clicking page 2.
Thanks in advance for the information, and of course, for this class, specially to Professor Adhikari, for her simple, lucid and sharp teaching and knowledge, everything is really great,
Oscar.
UserIdTAG: 609816
UserNameTAG: Oscar7000
CreateTimeTAG: 2013-03-07T09:18:44Z
VoteTAG: 18
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: One problem is that since most people here are working, the "Usable " time will not be 24hours round the world despite everyone getting a 24 hour window and most would come back from work to take their exam as it is a week day. So it would be better to give a 36 or 48 hour window so that everyone gets an equal amount of possible useful "nonwork- nonsleep time" to make it truly equitable for everyone and to allow selection of a undivided free time to answer the exam.
It is indeed different for an assignment since there is indeed sufficient time and a deadline whereas for an exam we are forced to sit in a narrow window of "Usable time"(for want of a better word) and while for a full time student it can be as much as 18 hours for people working it can be as less as 4-6 hours and any offset more than that wrt GMT essentially puts a lot of us in "trouble" especially for those who have jobs/schedules which are nonadjustable by their very nature of their jobs (for eg I ahve given patient appointment schedules over 6 months before for surgery and if I have to cancel one to make for my exam there will be a song and dance and while I have personally no problem sitting in the wee hours of the morning taking the exam it indeed would be a disadvantage not taking it "fresh" and I personally would be praying that I do not get calls from the hospital at that time as it is a working day and we have operated cases in the mroning and they will be in the ICU intensively managed t throughout the night (Though that would indeed be a personal problem that I will ahve to manage but just quoting it as an example) So the "Useful window" would indeed be severely truncated for most people who are at an unfavorable offset for sitting for the exam even though all get a 24 hour window.
I am also not sure whether the lectures and exercises are indeed posted at 00.00 GMT but with a week to a deadline there is nothing to quibble but for an exam it could "matter" as people have to make prearrangements.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T12:49:19Z
FirstChildVoteTAG: 4
FirstChildTAG: Let's wait and see what they have planned for the midterm. I think that until now they have done very well and have been very understanding, so let's give them a vote of confidence. I'm sure they are trying to find a way that's good and fair for everyone.
FirstChildUserIdTAG: 1108368
FirstChildUserNameTAG: BlancaR
FirstChildCreateTimeTAG: 2013-03-07T13:32:44Z
FirstChildVoteTAG: 3
FirstChildTAG: Good afternoon.
I'm also concerned with the timeframe of the Midterm and the Final.
Working on this course around my work schedule is always a struggle and usually means some amount of lack of sleep.
With the Midterm and the Final being only one day I doubt I'll be able to attend them.
I hope a larger timeframe will be given to attend them.
Thank you,
Luisa
FirstChildUserIdTAG: 1156003
FirstChildUserNameTAG: MariaLuisaLeite
FirstChildCreateTimeTAG: 2013-03-07T14:33:33Z
FirstChildVoteTAG: 2
FirstChildTAG: If you assume that one sleeps for 6 hours(can debate that it can be reduced by "burning the midnight oil" !!) and 8 hours of work(many of us actually do around 12 then that adds to 14 ("useless hours wrt exam) (upto 18 hours if one works 12 hours) hours.For a person whose useful hours is unfortunately overlapped by useless hours due to time zone variation that essentially ends up with 4 hours worth of time zones - people (ie overlapping 4 one hour time zones) who are unable to take the exam due to unfavorable schedule of a working person and if we take 12 hours it ends up with 8 time zones .So people working in these unfavorable time zones will get a raw deal as they would either be working or sleeping during the "favorable" exam period in their time zone !! That is why I asked if the net period can be extended so that every one around the globe gets a fair chance to answer the exams.
As an example the exercise set deadline ends somewhere around when I am sleeping so is pretty useless to me as a deadline so I jolly well have to submit my work well in advance.It is perfectly OK for exercise set as we have a weeks time here (even for a 48 hour window it is OK) but when you are talking for a one day turnover with working people this sort of anomaly will occur.Of course for full time students it should not matter as their work is their studies so they have 18 useful hours and any overlap of 12 hours could still give them 6 hours of appropriate exam writing time- a thing that is used to advantage when conducting exams like the USMLE around different time zones around the world !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T17:37:41Z
FirstChildVoteTAG: 1
FirstChildTAG: On Wednesdays I go to work and in the afternoon I go to graduate school, it is impossible for me to solve the midterm that day: i leave home at 8am and come back at 10 pm...
FirstChildUserIdTAG: 259928
FirstChildUserNameTAG: nadiasb
FirstChildCreateTimeTAG: 2013-03-10T21:33:18Z
FirstChildVoteTAG: 0
FirstChildTAG: I don't see the problem. You have enough time in a day to make a 45 minute exam (the professer says in a post somewere that that will be the cause)
And GMT also does not make it any harder.
I do hope that they post a timeline soon so you know when it starts so you can plan a hour.
FirstChildUserIdTAG: 1195844
FirstChildUserNameTAG: irenelok82
FirstChildCreateTimeTAG: 2013-03-11T06:59:06Z
FirstChildVoteTAG: 0
IndexTAG: 1188
TitleTAG: help
Why is there no link to download the video?
UserIdTAG: 1248686
UserNameTAG: HL21
CreateTimeTAG: 2013-03-07T07:45:05Z
VoteTAG: 11
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 0
IndexTAG: 1189
TitleTAG: DEADLINE OVER NOW?! 23:14... ATTENTION TECHNICAL STAFF!
What the....?! how come it's showing answers instead of checking my answers? it's not time yet, it's 23:14 MARCH 6,2013.
UserIdTAG: 166635
UserNameTAG: bonalkid
CreateTimeTAG: 2013-03-07T07:14:46Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: ATTENTION STUDENT
Read the course policy, the Course Info page and note from the Prof, and go Google GMT. Oh, and read the forum too. You are not the only one who failed to follow instructions.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T07:21:45Z
FirstChildVoteTAG: 2
SecondChildTAG: SusanAust, you are a treasure! I can imagine how irritating it can be to a explain the same thing again, and again, and again! :)
SecondChildUserIdTAG: 963407
SecondChildUserNameTAG: JRuth
SecondChildCreateTimeTAG: 2013-03-07T08:23:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Haha yeah! I think SusanAust has replied to every single one of them
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-03-07T08:32:50Z
SecondChildVoteTAG: 0
SecondChildTAG: That "ATTENTION STUDENT" is pure class! :)
SecondChildUserIdTAG: 963407
SecondChildUserNameTAG: JRuth
SecondChildCreateTimeTAG: 2013-03-07T09:53:21Z
SecondChildVoteTAG: 0
SecondChildTAG: You are too patient, Susan. We should ignore there people for once, let them figure it out on their own.
Would be good for their brains, I think xD
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T10:02:36Z
SecondChildVoteTAG: 0
SecondChildTAG: True. It's a distraction from some serious work I should be doing. I'm done now. I shall concentrate on a literature review that must be started. Yesterday.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T10:15:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Bad Karma!
SecondChildUserIdTAG: 929633
SecondChildUserNameTAG: BorjaMG
SecondChildCreateTimeTAG: 2013-03-07T13:15:41Z
SecondChildVoteTAG: 0
IndexTAG: 1190
TitleTAG: submissions ended already??
I can't submit any answers, it just has "Show Answer." The assignment says due March 6 23:30, but it's only March 6 23:06 right now!
UserIdTAG: 466283
UserNameTAG: optobeagle
CreateTimeTAG: 2013-03-07T07:06:25Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: No, it is Thursday March 7th 7.22am, GMT. You need to read the materials.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T07:22:27Z
FirstChildVoteTAG: 2
FirstChildTAG: Oh my good! I can't believe that we are passing through the same thing again... Groundhog day!
FirstChildUserIdTAG: 1108368
FirstChildUserNameTAG: BlancaR
FirstChildCreateTimeTAG: 2013-03-07T09:08:29Z
FirstChildVoteTAG: 3
SecondChildTAG: Yeah! And a new thread have to be opened every single time, because we are so sure that we are right and we have unique problem!! SusanAust is my hero!
SecondChildUserIdTAG: 963407
SecondChildUserNameTAG: JRuth
SecondChildCreateTimeTAG: 2013-03-07T09:17:12Z
SecondChildVoteTAG: 0
SecondChildTAG: yeah! mine too! She should be given a prize for her patience!!She replies EVERY single comment about the same issue again again and again...SusanAust you are the best!
SecondChildUserIdTAG: 1108368
SecondChildUserNameTAG: BlancaR
SecondChildCreateTimeTAG: 2013-03-07T09:35:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Lots of bad karma!
SecondChildUserIdTAG: 929633
SecondChildUserNameTAG: BorjaMG
SecondChildCreateTimeTAG: 2013-03-07T13:52:01Z
SecondChildVoteTAG: 0
IndexTAG: 1191
TitleTAG: 0
the cost given is of one house=834000
the reduced cost is also of one house =819000
cost of 32 houses = 834000 * 32
reduced cost of 32 houses = 819000 * 32
therefore avg cost reduction = ((819000 *32)-(834000 * 32))/32 =-15000
why is this reasoning not right?
UserIdTAG: 409724
UserNameTAG: geet-gec
CreateTimeTAG: 2013-03-07T06:43:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: Because only one house's value has changed, you seem to have over complicated the formula.
It's just the total value change of the one house divided by the number of houses.
(834000-819000)/32 = 468.75 and because its a reduction in total value it's -468.75
FirstChildUserIdTAG: 1030056
FirstChildUserNameTAG: RBartram
FirstChildCreateTimeTAG: 2013-03-07T10:24:58Z
FirstChildVoteTAG: 0
FirstChildTAG: The cost of all 32 houses is **not** 834000*32 - I think that's where you got confused. 834000 is the price of a single, specific house - not the average price.
You don't need to know the total price of all 32 houses, however, nor the average price - all you are asked is to determine by how much the average price goes down if one price goes down.
You know that the 834000 house is now priced at 819000...that's 15000 less. The 15000 directly affects the total price of all 32 houses, and in the average, is distributed between them. The average thus goes down by 15000/32 = 468.75.
So how much has the average changed? It's now -468.75 than what is was before.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T10:42:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks guys,this is much clear now.
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-03-07T13:07:56Z
FirstChildVoteTAG: 0
IndexTAG: 1192
TitleTAG: Unable to submit answers before cutoff time???
Unable to submit answers? only 10:30pm
UserIdTAG: 88470
UserNameTAG: samkwong
CreateTimeTAG: 2013-03-07T06:38:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: No. The deadline has passed. Is GMT hour. Read the Course Info page and note from the Prof
FirstChildUserIdTAG: 1108368
FirstChildUserNameTAG: BlancaR
FirstChildCreateTimeTAG: 2013-03-07T09:13:23Z
FirstChildVoteTAG: 0
IndexTAG: 1193
TitleTAG: What time is GMT in Chicago?
It seems that I never read through all the details of this course. At firs glance I see where the deadline for exercises are 23:30 GMT. I never bothered to note the GMT. As such I think I am late with submitting exercises.
Needed the grades too....my first two were horrible.
UserIdTAG: 792084
UserNameTAG: ssfranciscan
CreateTimeTAG: 2013-03-07T06:18:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: It seems that I never read through all the details of this course. At firs glance I see where the deadline for exercises are 23:30 GMT. I never bothered to note the GMT. As such I think I am late with submitting exercises.
Needed the grades too....my first two were horrible
FirstChildUserIdTAG: 792084
FirstChildUserNameTAG: ssfranciscan
FirstChildCreateTimeTAG: 2013-03-07T06:18:37Z
FirstChildVoteTAG: 0
FirstChildTAG: In the time it took you to post your question, you could have googled it and had your answer by now.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T06:20:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Dude, its not that serious....relax.
SecondChildUserIdTAG: 792084
SecondChildUserNameTAG: ssfranciscan
SecondChildCreateTimeTAG: 2013-03-07T21:19:39Z
SecondChildVoteTAG: 0
FirstChildTAG: http://www.timeanddate.com/worldclock/
Enjoy.
Or, even better: http://www.timeanddate.com/worldclock/converter.html
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T10:03:20Z
FirstChildVoteTAG: 0
FirstChildTAG: This should cover it for you
http://bit.ly/YC7Xdw
FirstChildUserIdTAG: 954932
FirstChildUserNameTAG: hellothomasjohnson
FirstChildCreateTimeTAG: 2013-03-07T11:39:56Z
FirstChildVoteTAG: 2
SecondChildTAG: that was funny... ;)
SecondChildUserIdTAG: 792084
SecondChildUserNameTAG: ssfranciscan
SecondChildCreateTimeTAG: 2013-03-07T21:20:16Z
SecondChildVoteTAG: 0
FirstChildTAG: I have a world clock in my iPad and I have not the option "GMT time". I am using the City of London time, which is the same.
FirstChildUserIdTAG: 450068
FirstChildUserNameTAG: RafaelAntonio
FirstChildCreateTimeTAG: 2013-03-07T18:59:20Z
FirstChildVoteTAG: 0
SecondChildTAG: Only until Summer Time kicks on the 31th, though. Then London will run GMT+1...keep that in mind (might be important for Stat2.2x)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T20:09:44Z
SecondChildVoteTAG: 0
IndexTAG: 1194
TitleTAG: I think GMT is confusing - California time will be better.
I live in Oakland, next to Berkeley, and of course I can relate to California time.
Moreover, most people are aware of California time and it comes later than most places, so it is doubly safe and people are less likely to miss deadlines.
UserIdTAG: 523705
UserNameTAG: IITian
CreateTimeTAG: 2013-03-07T05:46:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 10
FirstChildTAG: > Moreover, most people are aware of California time
Really? I'm not. And most outside the timezone wouldn't be aware of it.
>comes later than most places, so it is doubly safe
Why would that make a difference? 24 hours is 24 hours regardless of where in the world you live.
We are doing a course that involves manipulating numbers. If people can't even work out how to tell the time .......
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T05:50:42Z
FirstChildVoteTAG: 8
SecondChildTAG: I think natural tendency is to see who is offering the course and be aware of their local times.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T05:55:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, and even more natural is to read the course requirements and policies.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T05:57:22Z
SecondChildVoteTAG: 0
SecondChildTAG: I think GMT is like Latin and Sanskrit, respected but hardly followed. California is the centre of universe.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T06:04:30Z
SecondChildVoteTAG: 0
SecondChildTAG: But the course is offered by BerkeleyX, an online offshoot of the uni. Would that mean we have to use Swatch Internet Time?
I have my doubts that the submission time being at @979 would make it clearer for anyone.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T11:51:22Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm soo loving SusanAust- hammering sense into Stat 2.1X participants since 2013 :-)
SecondChildUserIdTAG: 1076285
SecondChildUserNameTAG: francais
SecondChildCreateTimeTAG: 2013-03-19T08:13:37Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm sorry , but most students come from places outside the US. GMT seems fair for all !.
SecondChildUserIdTAG: 715680
SecondChildUserNameTAG: Cairodoc
SecondChildCreateTimeTAG: 2013-03-31T08:27:52Z
SecondChildVoteTAG: 0
FirstChildTAG: hahaha... guys... I like the part "most people are aware of California time"! LOL Really good :D
But to be more serious... first, all was clearly stated and recently announced on the board... second... people who signed for the course live also outside the USA... strange, but yes... there is a life out there! And as for someone living in the USA California time may be obvious... for others not so... :D
FirstChildUserIdTAG: 905926
FirstChildUserNameTAG: MarcinJ77
FirstChildCreateTimeTAG: 2013-03-07T08:04:40Z
FirstChildVoteTAG: 11
SecondChildTAG: California time! Some one there saying ' most people are aware of California time'???! If I may ask..according to which study? The standard time is GMT and we can easily make the conversion to our local time...else why not Tokyo time!
SecondChildUserIdTAG: 673786
SecondChildUserNameTAG: Konqu3ror
SecondChildCreateTimeTAG: 2013-03-15T16:27:49Z
SecondChildVoteTAG: 0
FirstChildTAG: From the Wikipedia page for GMT:
http://en.wikipedia.org/wiki/Greenwich_Mean_Time
"Greenwich Mean Time (GMT) is a time system originally referring to mean solar time at the Royal Observatory in Greenwich, London, which later became adopted as a global time standard."
GMT is a commonly used global time standard. California time is just local time to California. Why not use Timbuktu time ect.
FirstChildUserIdTAG: 954932
FirstChildUserNameTAG: hellothomasjohnson
FirstChildCreateTimeTAG: 2013-03-07T09:43:40Z
FirstChildVoteTAG: 6
SecondChildTAG: I go for Star Trek time!! :)
SecondChildUserIdTAG: 963407
SecondChildUserNameTAG: JRuth
SecondChildCreateTimeTAG: 2013-03-07T09:49:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Stardate calculation is a bit funky before 23rd century, though :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T14:08:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Are you *really* so self-centered in California?
This is an international course - it involves the whole world. Since GMT is the central timezone in the world(the "Average" timezone, if you want), it seems logical to use it for the course.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T09:55:45Z
FirstChildVoteTAG: 5
SecondChildTAG: Worst part is see his moniker "IITian" which should mean he has forgotten his roots !
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-07T12:36:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Huh. That makes it even weirder :o
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T14:12:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Prasannasimha, I was in Bombay (well... Mumbai) recently to meet my classmates and enjoyed my time there and all flights and train timings were in IST and not GMT. GMT times are good no doubt and human mind works well with some location-specific time better. Just my view.:)
There is a Big Data course offered by Indian institute on Coursera and if they follow IST, it will be perhaps nice.
As an analogy, if someone in NY asks me to call him at 2 PM, my default assumption is that the time is NY time, and not California or India time. Same with courses offered by universities.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T17:42:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Huh apples and oranges- your meeting and trains was in India (**local meet**) and the **flight time convention** on all flights is local time of take off and landing of the flight neither the origin or destination is the default timing there so that is indeed not a valid argument as anyone taking an international flight should know.Here we are talking of one deadline over the World and it makes sense to have one noncontroversial times and that was clearly fixed and that was GMT.I do receive and set calls from people round the world and indeed if I were to tell them to phone me at a particular time I would add the qualifier and not just call me at 2 PM !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T13:27:31Z
SecondChildVoteTAG: 0
FirstChildTAG: I physically am ROFL (Rolling on the floor laughing)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T10:10:12Z
FirstChildVoteTAG: 7
FirstChildTAG: I would suggest against thinking of it as GMT but rather as UTC all other time zones are defined by that,
GMT is UTC +0
British Summer Time is UTC +1
EST is UTC -5
Eastern Daylight Time is UTC -4
It saves the error of just thinking GMT is the time in London, an assumption only true for half the year.
FirstChildUserIdTAG: 1030056
FirstChildUserNameTAG: RBartram
FirstChildCreateTimeTAG: 2013-03-07T10:57:43Z
FirstChildVoteTAG: 1
FirstChildTAG: Regarding self-centered in California, let's face it. The course is offered by UC, Berkeley, which is located in Berkeley which is in California. Given the teaching staff is in California it will make it easier for them.
Regarding this being an 'international' class and so on, Super Bowl is also 'international' and so is World Cup Series - except most of the viewers in the USA and the times stated for them are in their local times and not in GMT.
As things stand now, almost everyone is confused. Imagine international flights using GMT times instead of local times! Will cause total confusion.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-03-07T17:36:09Z
FirstChildVoteTAG: 0
SecondChildTAG: "Given the teaching staff is in California it will make it easier for them."
I'd like to give the teaching staff a little more credit than that. Converting time from GMT is not rocket science.
"Super Bowl is also 'international' and so is World Cup Series "
World Cup, yes. Super Bowl, no.
"As things stand now, almost everyone is confused."
The only people who are confused are the ones who didn't take the time to read the Course Policies and understand them. Take some personal responsibility, and please don't presume to speak for 'almost everyone.'
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T17:42:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Of course if you are in a specific place, then you expect dates and time to be specified in that place's local timezone.
When I go to my local airport, of course the flight times are specified in CET(or CEST during Summer Time). I am in Italy.
If I were to travel to Berkeley and enroll at the university there, of course dates and times are given in PST or PDT. I would be in California.
But here we are online. We are not based in any specific place, no matter where the edx servers might be. There is not
It was a sensible decision, in my opinion, to choose a "neutral" timezone that everyone in the world can relate to, because, you know, it's a reference timezone and not a local timezone.
Finally, it doesn't really matter what timezone you, or me, or anyone expects the times to be given in. This information was clearly stated by the course managers, and it's not up to individual opinion.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T19:09:38Z
SecondChildVoteTAG: 0
SecondChildTAG: "Super Bowl is also 'international' and so is World Cup Series "
Could you find worse examples?!?!? :-D
Super Bowl, almost completely a national issue.
World Cup Series, if you mean the World Series, no Cup (very humble name for what is basically a US baseball tournament) it has a wider audience internationally, but with everybody (almost) in the same time zone. If you meant the World Cup, no series (of any major sport: basketball, soccer,...). Yes, you have to be very careful about what the time of the games will be in your local time, as you should have been with the class.
SecondChildUserIdTAG: 1024715
SecondChildUserNameTAG: iparrajorge
SecondChildCreateTimeTAG: 2013-03-07T21:40:51Z
SecondChildVoteTAG: 0
SecondChildTAG: iparrajorge, I meant the World Series - thanks for the correction.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T21:44:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I thought you did. The problem is that the US has no real international "show" that happens in vastly different time zones. It makes itself very self-centered (and I live in the US!). The Olympics in London would be a perfect example of the need to adapt, and that was as close as it gets to the GMT!
The funny thing is that the whole GMT was the first attempt to a standardized time, the same way a meter makes sense, not because the distance is particularly beautiful but because it sets a standard.
I know that other courses use different rules, but complain about the GMT for not being a rational decision is hilarious! It is the "original" time zone!
SecondChildUserIdTAG: 1024715
SecondChildUserNameTAG: iparrajorge
SecondChildCreateTimeTAG: 2013-03-07T22:04:57Z
SecondChildVoteTAG: 0
SecondChildTAG: You know what could have been really fun? If they had decided to write the dates the US way (month/day) with numbers instead of letters as they do now: Feb 29, Mar 4,... with 2-29, 3-4 (!) instead.
Watching people coming from the 95% of the world that don't use this format trying to guess when a PS is due, would have made the whole GMT "rage" a child's play.
SecondChildUserIdTAG: 1024715
SecondChildUserNameTAG: iparrajorge
SecondChildCreateTimeTAG: 2013-03-07T22:12:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Let's face it, most students of current MOOCs are from the USA, followed by Europe, and then lagging far behind them are students from remaining countries. (I base this on statistics on Scala programming offered on Coursera.) It is absurd to change all times to GMT for the sake of single student from say Jamaica, when tens of thousands of students from the USA and Europe will rather deal with perhaps California time. Football (soccer) a case though where GMT can make more sense.
A better idea might be for Edx to personalize the web pages for each student, showing due times in their local times, based on a menu selection by the student. This is an old concept.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-08T00:20:25Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree about personalization, it just makes sense and it is not difficult to implement, like the clock showing how long you have left.
I disagree with the USA-Europe-centric view. Either this experiences try to be truly global, or they will lose their real value. It doesn't matter if 95% of the audience is from USA-Europe, the most important students are the ones that start post like: "My country has YouTube banned. Help!". This will only be revolutionary if it affects the world has a whole, particularly in countries with poor college education systems.
By the way, you didn't answer, what is the time to be used if more than one School is involved in the organization of the class?
SecondChildUserIdTAG: 1024715
SecondChildUserNameTAG: iparrajorge
SecondChildCreateTimeTAG: 2013-03-08T16:06:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Ha the "World series" with 2-3 countries ? Superbowl being international ? really? really ?????
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T13:28:25Z
SecondChildVoteTAG: 0
FirstChildTAG: iparrajorge,
GMT is useful only if it is implemented properly. For example, the submission times listed are just plain times with no terms like **GMT** or **PST** etc. and people tend to associate times with either their local or the institution's local time. The hypothetical case of more than one school is very unlikely - and then too one will be the lead school. In extremely unlikely case of that happening they can agree to GMT time.
If Edx learns how to implement GMT times properly (show all times in GMT - have GMT times on top of every submission if not all pages, etc.) and then nobody will complain. People missing on assignment submissions is not a sign of their laziness but improper implementation by Edx. I have taken many Coursera classes but it is rare to read comments about this issue means they are doing something right.
I would like GMT to become standard, just like I want metric system to become standard, but am aware that forcing people to change without laying the groundwork is futile.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-03-09T00:17:39Z
FirstChildVoteTAG: 2
SecondChildTAG: The courseware policy page clearly tells all times are GMT .If a clock is added or a clock is added or better still a count down timer is added it may be better but that does not absolve the responsibility of checking your time for a submission deadline in a clearly international course.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T13:30:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Submission times should have GMT added. That will reduce the confusion. Coursera too is international but most times are not GMT.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-10T03:16:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Asking that GMT be appended to the time mentioned is acceptable but the rest of the logic that Berkeley is the center of the universe so it must be is not :)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-11T13:40:45Z
SecondChildVoteTAG: 0
FirstChildTAG: Start thinking globally :-) Here are few answers to people who think that US is world and California is biggest country in it.
"most people are aware of California time"
A: less than 1% of world populations knows what it is and less than 0.5% knows what time is there now
"against thinking of it as GMT but rather as UTC all other time zones are defined by that"
A: UTC is term mainly used in US, rest of world primarly uses GMT. US is 4.5% of world population, so 95.5% are fine with GMT
"Super Bowl is also 'international' and so is World Cup Series"
A: not even close to true, they are local to US.
Olympics is international
"Imagine international flights using GMT times instead of local times!"
A: Imagine international flights using California time :D It would be strange to appear at airport 10 hours before my flight, because time on my ticket is in GMT and times in my airport are GMT
Just reminding and solving whole problem with math and statistics: US is only 4.5% of popultion, and US is only 12-16th place by average internet speed. So believing that everyone here knows California time is at least ...
FirstChildUserIdTAG: 127421
FirstChildUserNameTAG: apbyte
FirstChildCreateTimeTAG: 2013-03-18T23:30:07Z
FirstChildVoteTAG: 0
SecondChildTAG: US is 4.5% of population but my guess is that about 40-50% of the students for this course come from the USA. Perhaps another 40% come from Europe and they all know California quite well.
I don't want to discount the sole student from say Uganda, still the majority of the students know California, and even that sole person from Uganda.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-25T23:53:22Z
SecondChildVoteTAG: 0
FirstChildTAG: It is PST. The guy does not even know which time zone he is in. Is this a wind up?
FirstChildUserIdTAG: 270738
FirstChildUserNameTAG: sheardp
FirstChildCreateTimeTAG: 2013-03-24T08:50:21Z
FirstChildVoteTAG: 0
IndexTAG: 1195
TitleTAG: Mid-term organisation
I'm writing because I would like to know how the mid-term will be organised, in order to organised myself to work on it.
When it will be posted? How long will we be allowed to work on it?
Thank you in advance_
UserIdTAG: 900078
UserNameTAG: Ele_B
CreateTimeTAG: 2013-03-07T05:45:53Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: My issue is that I will be up a mountain on the 13th of March with no access to network or IT until the 17th of March. What will be the time requirements of the test? Will it be possible to take it when I get back at the weekend?
Thanks in advance.
FirstChildUserIdTAG: 15436
FirstChildUserNameTAG: peterprinciple
FirstChildCreateTimeTAG: 2013-03-07T08:58:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Details about the midterm schedule will be posted shortly according to Prof A.
But I think that, at best, it will be available from the 13th through the 14th, so no luck if you are off the grid until the 17th I'm afraid :(
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T10:00:42Z
SecondChildVoteTAG: 0
IndexTAG: 1196
TitleTAG: No download link....
The download link is missing here...
Please update....
UserIdTAG: 169571
UserNameTAG: Rymz
CreateTimeTAG: 2013-03-07T05:37:26Z
VoteTAG: 20
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 1
FirstChildTAG: Yup. More specifically, middle video of section 5b, heading: NOT ALL HISTOGRAMS ARE BELL SHAPED; CHEBYCHEV REVISITED
FirstChildUserIdTAG: 99047
FirstChildUserNameTAG: taminur
FirstChildCreateTimeTAG: 2013-03-07T06:00:30Z
FirstChildVoteTAG: 2
IndexTAG: 1197
TitleTAG: Deadline!
I Couldn't submit the answers!
UserIdTAG: 1130399
UserNameTAG: RafaelHMM
CreateTimeTAG: 2013-03-07T05:36:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: That's correct. You cannot submit answers after the deadline.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T05:42:42Z
FirstChildVoteTAG: 0
IndexTAG: 1198
TitleTAG: Soon will be a proud owner of a UC, Berkeley certificate.
Already above 35%. Oh yeah. I guess it's time to grab a beer. (Please drink responsibly, and don't drive, and please be above legal drinking age, if you want to imitate me. Thanks.)
UserIdTAG: 523705
UserNameTAG: IITian
CreateTimeTAG: 2013-03-07T05:28:10Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hate to be a buzzkill, but you'll be a proud owner of an edx certificate, not a UC Berkeley certificate.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T05:33:23Z
FirstChildVoteTAG: 1
SecondChildTAG: Won't UC Berkeley be mentioned somewhere on that certificate :( I guess I need more beer.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T05:37:38Z
SecondChildVoteTAG: 0
SecondChildTAG: congrats...may b we will soon cathc ur avrg.good wishes with u...
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-07T05:44:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Oops, I might be wrong. Your certificate will probably say "BerkeleyX" and "edX" but not "U.C. Berkeley."
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T05:45:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok, I hope X is silent in BerkeleyX. If not, I will make it so.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T05:52:35Z
SecondChildVoteTAG: 0
SecondChildTAG: It should say BerkeleyX, but one I got recently said Harvard and included the Harvard logo. Which, according to edX faqs, was not supposed to happen.
They are supposed to be issued under BerkeleyX, but obviously there have been problems in the past. So it could say anything.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T05:53:54Z
SecondChildVoteTAG: 0
SecondChildTAG: The certificates are generated by edX techs, and are apparently generating them is not as easy as it sounds.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T05:56:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Just now I checked my certificate from a previous course and it clearly states "a course of study offered by MITx, an online learning initiative of The **Massachusetts Institute of Technology** through edX.for..."
Time to get them framed and hang on the wall, I guess.
SecondChildUserIdTAG: 523705
SecondChildUserNameTAG: IITian
SecondChildCreateTimeTAG: 2013-03-07T06:00:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Wow, congratulations!
SecondChildUserIdTAG: 1379115
SecondChildUserNameTAG: Fisherhh
SecondChildCreateTimeTAG: 2013-03-07T06:11:00Z
SecondChildVoteTAG: 0
SecondChildTAG: I too am celebrating being over the required 35% We all did well to survive
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-07T09:20:31Z
SecondChildVoteTAG: 0
SecondChildTAG: To me whether certificate with an X or none, it is a bomb!
SecondChildUserIdTAG: 1209905
SecondChildUserNameTAG: Josmal
SecondChildCreateTimeTAG: 2013-03-07T13:26:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Same almost. Made one or two stupid mistakes when settling into the format but had a 100% streak since. I should be up to 35% this next set of assignments.
FirstChildUserIdTAG: 954932
FirstChildUserNameTAG: hellothomasjohnson
FirstChildCreateTimeTAG: 2013-03-07T09:18:53Z
FirstChildVoteTAG: 0
IndexTAG: 1199
TitleTAG: Submission time
Hello
I waited on Exercise 6 until today and it is 9:30P PST and am unable to submit... Request to keep submission open until 11:30 local time zone.
Thanks
Raju
UserIdTAG: 106654
UserNameTAG: rajuchellappa
CreateTimeTAG: 2013-03-07T05:22:58Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: The deadline is 23.30 **GMT** (over 5 and a half hours ago)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T05:25:01Z
FirstChildVoteTAG: 0
FirstChildTAG: > Request to keep submission open until 11:30 local time zone.
And which local time should we use? Yours? Mine? Paul's?
We have all had exactly the same amount of time to do this work. Something that some appear to have great difficulty believing.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T05:29:37Z
FirstChildVoteTAG: 1
IndexTAG: 1200
TitleTAG: Why you can post your answers - Ha! We should read ALL instructions on EdX courseware
See the Courseware landing page "Week 3 exercise sets are due on Wednesday March 13, the same day as the midterm. To give you the opportunity to look at solutions before the midterm, we are making the solutions to Week 3 exercise sets visible to you as soon as you have turned in your answers."
UserIdTAG: 1292868
UserNameTAG: SandyL
CreateTimeTAG: 2013-03-07T05:18:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 0
IndexTAG: 1201
TitleTAG: Understanding Question #6's Solution Explanation
I understand how to do question #6. I answered it correctly. However, I do not understand Professor Adhikari's explanation about why option f is false. She wrote, "Option f) is false, as the first example in Lec 4.1 shows." What example is Professor Adhikari referring to? Chebychev’s bound is taught in Lec 4.3, not in Lec 4.1.
Please clarify. Thank you in advance.
UserIdTAG: 1327840
UserNameTAG: Sapphire38
CreateTimeTAG: 2013-03-07T05:01:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Bounds in general are explained in 4.1. A bound is a bound no matter if it comes from Chebychev or Markov's rules.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T10:09:24Z
FirstChildVoteTAG: 0
IndexTAG: 1202
TitleTAG: CAN'T SUBMIT ANSWERS
The show answer button is activated so I couldn't submit the answers
UserIdTAG: 1130399
UserNameTAG: RafaelHMM
CreateTimeTAG: 2013-03-07T04:54:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: Deadline was 23:30 GMT.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T05:09:12Z
FirstChildVoteTAG: 0
FirstChildTAG: im unable to get access to the edx course within deadline period of exercises can i start from first again
FirstChildUserIdTAG: 1111671
FirstChildUserNameTAG: kanduri
FirstChildCreateTimeTAG: 2013-03-12T04:25:13Z
FirstChildVoteTAG: 0
IndexTAG: 1203
TitleTAG: Submitting exercises
I cannot submit my answers. It is only 8:50 pm.
UserIdTAG: 173512
UserNameTAG: jeanlim
CreateTimeTAG: 2013-03-07T04:51:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 23:30 GMT.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T05:09:01Z
FirstChildVoteTAG: 0
SecondChildTAG: And the time now is 05.10 GMT (on 7 March).
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T05:10:51Z
SecondChildVoteTAG: 0
SecondChildTAG: cannot submit my answers too, how can we submit it on time? i tried it several days already
SecondChildUserIdTAG: 1077280
SecondChildUserNameTAG: Mayoliza
SecondChildCreateTimeTAG: 2013-03-08T02:28:19Z
SecondChildVoteTAG: 0
IndexTAG: 1204
TitleTAG: Applet
A distribution of heights follows the normal curve with mean 67 inches and
SD 3 inches. What percent of the heights are between 63 inches and
67 inches?
(63 67)=3 = 1:33 standard units; 67 inches = 0 standard units.
So the question becomes:
Under the standard normal curve, what percent of the area is
between 1:33 and 0?
The applet says the area is 40.82%.
Answer: 40.82%.
which applet is this referring to?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-07T04:49:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You posted this question in the wrong forum.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-07T09:19:47Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks for letting me know
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-07T20:16:53Z
SecondChildVoteTAG: 0
IndexTAG: 1205
TitleTAG: why i can´t enter my answers?
is 22:41 but i can´t enter my answers :( why????
UserIdTAG: 427080
UserNameTAG: Drkmarvin
CreateTimeTAG: 2013-03-07T04:41:56Z
VoteTAG: 3
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: Because the GMT deadline was almost 5 hours ago.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-07T04:45:26Z
FirstChildVoteTAG: 0
SecondChildTAG: It's a conspiracy. Someone is messing with the timelines. Chronoguards?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T04:59:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Ha ha ha....
SecondChildUserIdTAG: 1209905
SecondChildUserNameTAG: Josmal
SecondChildCreateTimeTAG: 2013-03-07T13:46:02Z
SecondChildVoteTAG: 0
FirstChildTAG: No. The GMT deadline is still 100 minutes away
FirstChildUserIdTAG: 31529
FirstChildUserNameTAG: abbass
FirstChildCreateTimeTAG: 2013-03-07T04:49:59Z
FirstChildVoteTAG: 0
SecondChildTAG: I think you are mistaken.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T05:09:55Z
SecondChildVoteTAG: 0
FirstChildTAG: There's certainly a mistake by 2.1x staff
FirstChildUserIdTAG: 31529
FirstChildUserNameTAG: abbass
FirstChildCreateTimeTAG: 2013-03-07T04:50:26Z
FirstChildVoteTAG: 0
SecondChildTAG: No.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T10:06:04Z
SecondChildVoteTAG: 0
FirstChildTAG: > There's certainly a mistake by 2.1x staff
Isn't everything a mistake by the Prof? Never a student's mistake.
It is currently Thursday 4.57am GMT. Well beyond the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:58:49Z
FirstChildVoteTAG: 0
IndexTAG: 1206
TitleTAG: A binomial approach for Ex2
For each question there's equal possibility for it to be marked "right" or "wrong". Given the average and SD, the distribution of questions fits the binomial distribution R~B(6.2,1.4). Thus, W~B(average,SD) can be deducted.
P.S.: I am not quite sure whether it is suitable to post either answers or deduction processes.
UserIdTAG: 1378421
UserNameTAG: Misaka
CreateTimeTAG: 2013-03-07T04:41:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 1
FirstChildTAG: Sorry, I'm not following you. In the setting of the problem, no probabilities are involved. Nothing is happening due to chance, and there is no assumption that "right" and "wrong" are equally likely; indeed, one would hope they are not, if the students have done any studying.
Where are you seeing a binomial? Clearly not with n=10 and p=0.5. It's not n=10 and p=0.62 either. I'm curious about where you have seen the binomial parametrized by its mean and SD; that's not standard, though there's nothing inherently wrong with it.
I'm guessing that you have over-complicated the problem. There's a simple deterministic relation between the two variables; once you write that down, the methods of Sec 4.4 will give you the average and the SD. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-07T08:25:48Z
FirstChildVoteTAG: 7
SecondChildTAG: Madam, may I complete the exercises that have passed their due date? I registered for this after the course has begun. Is there any regulation to my situation?
SecondChildUserIdTAG: 1378421
SecondChildUserNameTAG: Misaka
SecondChildCreateTimeTAG: 2013-03-08T07:48:37Z
SecondChildVoteTAG: 0
IndexTAG: 1207
TitleTAG: When will the next courses Stat 2.2x and 2.3x become live on edx?
Once this course ends on 26th March ,
When will the next courses Stat 2.2x and 2.3x become live on edx?
Any Date estimate?
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-03-07T04:39:37Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: This has been asked and answered a few times by the course team. There are no dates yet set but it is expected that the other courses will follow on from 2.1x 'within weeks' of the course ending.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T05:13:50Z
FirstChildVoteTAG: 4
SecondChildTAG: Thanks for your Reply
SecondChildUserIdTAG: 786512
SecondChildUserNameTAG: shoaibkhanz
SecondChildCreateTimeTAG: 2013-03-07T10:37:42Z
SecondChildVoteTAG: 0
FirstChildTAG: I really hope we will continue the following courses right after this one as we will remember what we just learned.
FirstChildUserIdTAG: 989706
FirstChildUserNameTAG: kli
FirstChildCreateTimeTAG: 2013-03-13T02:39:50Z
FirstChildVoteTAG: 0
IndexTAG: 1208
TitleTAG: Again, a tad broken...
I won't spill the beans this time.
UserIdTAG: 994938
UserNameTAG: keithlhatfield
CreateTimeTAG: 2013-03-07T04:38:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Again, not broken at all.
But feel free to elaborate on what you *think* it's broken. Due date is past, answers are out, no reason to keep it inside this time ;)
Assuming of course that you are actually referring to ES6.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-07T14:21:35Z
FirstChildVoteTAG: 0
IndexTAG: 1209
TitleTAG: Me too!!!
Please!!! we are all confused!! was GMT California?
UserIdTAG: 945953
UserNameTAG: Turca
CreateTimeTAG: 2013-03-07T04:37:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: GMT = Greenwich Mean Time, the time based on the meridien passing through Greenwich in London, UK
As I write this the time is 05.00 GMT (on 7 March), some and a half hours past the deadline.
If you can't use Google to find the information there is, helpfully, a whole section addressing this point on the course wiki (linked above).
To see the current time click here:
http://wwp.greenwichmeantime.com/time/scripts/clock-8/runner.php
GMT should properly be referred to as UTC (Universal Coordinated Time) which is the term officially used by international communications (including the internet) and the scientific community.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T05:09:31Z
FirstChildVoteTAG: 0
IndexTAG: 1210
TitleTAG: STAFF
Where time is it?
Here are just 9:30 pm
I could not finish Exercise 6
UserIdTAG: 162722
UserNameTAG: FDA2
CreateTimeTAG: 2013-03-07T04:37:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You were here last week, so surely you read all the drama and the Prof's message?
GMT. So deadline has expired. Died. Gone. Move on to Week 3
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:39:33Z
FirstChildVoteTAG: 0
SecondChildTAG: What was the dram? Pray tell me.. This is most unfair.. I've seen the lectures with all attention and when moved to pset.. I see the deadline has expired
SecondChildUserIdTAG: 31529
SecondChildUserNameTAG: abbass
SecondChildCreateTimeTAG: 2013-03-07T04:52:29Z
SecondChildVoteTAG: 0
IndexTAG: 1211
TitleTAG: Certificate Earned!
After taking this exercise, I found that my progress percentage went up to 37%, which meant that I have passed the 35% line and earned the certificate!
Anyone else at the same stage?
Just to be cautious, and a question for the staff: the current shown progress report is indeed part of my final grade, right?
UserIdTAG: 1058318
UserNameTAG: MelodyLi
CreateTimeTAG: 2013-03-07T04:36:41Z
VoteTAG: 19
CoursewareTAG: Exercise Set 8 / Exercise Set 8
NumberOfReplyTAG: 29
FirstChildTAG: Yes. All you need is 35%, as shown in the bar on the far right.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:38:04Z
FirstChildVoteTAG: 1
SecondChildTAG: well done, MelodyLi!
I've never taken a class in which one would get a passing grade without taking the mid-term and final. But who am I to complain? :)
SecondChildUserIdTAG: 608203
SecondChildUserNameTAG: chauct
SecondChildCreateTimeTAG: 2013-03-07T04:48:27Z
SecondChildVoteTAG: 0
FirstChildTAG: 37% is the mark to beat this week. Copy.
Also: congrats.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T04:51:16Z
FirstChildVoteTAG: 1
SecondChildTAG: congrats.party time.ha...!!
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-07T05:46:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Mission accomplished.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-11T02:13:08Z
SecondChildVoteTAG: 0
FirstChildTAG: @ MelodyLi : Hey I too got 37%... (37.1% to be exact)...congo...A great work form both of us...:-)
FirstChildUserIdTAG: 818577
FirstChildUserNameTAG: rajarjit
FirstChildCreateTimeTAG: 2013-03-07T06:27:36Z
FirstChildVoteTAG: 0
FirstChildTAG: congrats to you. but may i be curious and ask you how many percents you got in the exercises?always 100?
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-07T09:56:19Z
FirstChildVoteTAG: 1
SecondChildTAG: Grades will be calculated using the following weights:
Exercise Sets: 50%
Midterm: 20%
Final exam: 30%
● Certificates of completion will be awarded to those who score 35% or higher overall.
SecondChildUserIdTAG: 731839
SecondChildUserNameTAG: mebiostatistician
SecondChildCreateTimeTAG: 2013-03-08T09:03:32Z
SecondChildVoteTAG: 0
FirstChildTAG: I think that apart from getting 35% the certificate is given for completion.
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-03-07T13:41:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Did you see that written in the Course Policies, or did you just make it up?
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T17:32:51Z
SecondChildVoteTAG: 0
FirstChildTAG: I dont think you have passed the course.. remember that if you do poorly in future exercises or exams those scores would put down your avarage ... so keeo it up doing great!
FirstChildUserIdTAG: 1256931
FirstChildUserNameTAG: Jhoara
FirstChildCreateTimeTAG: 2013-03-07T16:49:58Z
FirstChildVoteTAG: 1
SecondChildTAG: No, it won't. The percentage given in the Progress tab assumes that all other exercises have been graded as '0'. Therefore, you can only go up.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-03-07T17:14:19Z
SecondChildVoteTAG: 0
FirstChildTAG: 40% - I've only had one wrong so far and all on first attempt. I have an advantage - I listen to all the videos, read all the texts and do all the practice problems. Try it - it works!
FirstChildUserIdTAG: 1284382
FirstChildUserNameTAG: kite420
FirstChildCreateTimeTAG: 2013-03-07T19:40:32Z
FirstChildVoteTAG: 2
SecondChildTAG: Well done, which one did you get wrong? I like to look at the questions first before looking at the videos, most problems in life are like that, first comes the problem, then you need to research how to solve it.
SecondChildUserIdTAG: 895423
SecondChildUserNameTAG: joshea68
SecondChildCreateTimeTAG: 2013-03-07T21:55:44Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't think so. The ES scores are only a part of the final score, sorry.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-07T19:42:18Z
FirstChildVoteTAG: 1
SecondChildTAG: Yeah, they count for 50% of the final score. Which means, that an average of at least 70% for the ES gives you the passing grade.
You can currently reach as high as 80% ES Average, so it's quite possible to be in the clear already ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T20:17:05Z
SecondChildVoteTAG: 0
FirstChildTAG: I just squeaked by with 35.8%. Can't complain though. Still going to try for 100%'s on the rest of the course!
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-08T01:11:36Z
FirstChildVoteTAG: 0
SecondChildTAG: I squeaked in by 35%. Not bad, mate! Still a long way to go! *smiles* and Congrats!
SecondChildUserIdTAG: 1243349
SecondChildUserNameTAG: vix
SecondChildCreateTimeTAG: 2013-03-10T15:41:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Same here.
I feel like a different person now ;).
I really had "hated" my Biostatistics courses in the past.
Next target, the 95%.
FirstChildUserIdTAG: 830835
FirstChildUserNameTAG: Zacharie
FirstChildCreateTimeTAG: 2013-03-08T01:30:38Z
FirstChildVoteTAG: 2
FirstChildTAG: I got 39%.
I made one mistake in Ex set1 and one in Ex set3 (one is that I put 0.... instead of a percent number, etc).
But I think maybe the 2 lowest scores are already removed automatically from the calculation?
FirstChildUserIdTAG: 830835
FirstChildUserNameTAG: Zacharie
FirstChildCreateTimeTAG: 2013-03-08T04:57:17Z
FirstChildVoteTAG: 1
FirstChildTAG: Congrats! However I registered this course just before the mid-term... It will take me some time before I beat 35%...
FirstChildUserIdTAG: 1378421
FirstChildUserNameTAG: Misaka
FirstChildCreateTimeTAG: 2013-03-08T07:38:02Z
FirstChildVoteTAG: 0
FirstChildTAG: I do not think so, you did not passed it,
as it is written in course policy that final grading will be done using the following system
---
Grades will be calculated using the following weights:
Exercise Sets: 50%
Midterm: 20%
Final exam: 30%
● Certificates of completion will be awarded to those who score 35% or higher overall.
So you still have to putt your time and efforts to attempt mid and final term exam.
good luck
FirstChildUserIdTAG: 731839
FirstChildUserNameTAG: mebiostatistician
FirstChildCreateTimeTAG: 2013-03-08T09:02:42Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm more than happy with my progress so far, sitting on 38.2%. I'm still going to take a big hit in the marks though because it still looks like I'm going to miss the mid-term as I'll be in transit for over 24hours travelling overseas on the day without any access to internet :(
FirstChildUserIdTAG: 946554
FirstChildUserNameTAG: DavidH-Aus
FirstChildCreateTimeTAG: 2013-03-08T10:26:39Z
FirstChildVoteTAG: 0
SecondChildTAG: same here...I have already misses the mid-term:(
SecondChildUserIdTAG: 1141835
SecondChildUserNameTAG: TrissMerigold
SecondChildCreateTimeTAG: 2013-03-15T15:03:31Z
SecondChildVoteTAG: 0
FirstChildTAG: Me too, I'm on 38%. I was just let down by Exercise set 7 where I still don't get 2B and 3B, despite seeing the answers! I'm going back over the lectures to see what I missed, as I *really* want to understand this stuff. It's been brilliant so far!
FirstChildUserIdTAG: 1226786
FirstChildUserNameTAG: goodhen
FirstChildCreateTimeTAG: 2013-03-08T15:59:22Z
FirstChildVoteTAG: 1
FirstChildTAG: I got 37% ,but I think it is not enough to earn the certificate.
I think we need to get 35% in mid term and final
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-08T19:55:07Z
FirstChildVoteTAG: 0
FirstChildTAG: I got 40% so far; just lost 1 point on the first set on the very first exercise. But I believe knowledge is more important than a grade (too cliche? haha). So I will continue participating in this course
FirstChildUserIdTAG: 1330238
FirstChildUserNameTAG: xeniosm
FirstChildCreateTimeTAG: 2013-03-09T11:22:38Z
FirstChildVoteTAG: 0
FirstChildTAG: 35% seems like a low bar to pass, but I missed the deadline for an entire set of exercises because of the GMT time zone. For such a short class, I have to do well on everything else now.
FirstChildUserIdTAG: 1153828
FirstChildUserNameTAG: Matt2edX
FirstChildCreateTimeTAG: 2013-03-10T17:42:02Z
FirstChildVoteTAG: 0
FirstChildTAG: Progress 40% and zero errors yet :D
FirstChildUserIdTAG: 900261
FirstChildUserNameTAG: JRoest
FirstChildCreateTimeTAG: 2013-03-10T20:24:27Z
FirstChildVoteTAG: 1
FirstChildTAG: Hi,
congratulations.
I have 40% and zero mistakes for the moment.
I think it's important to pay a lot of attention to avoid silly mistakes in calculations.
FirstChildUserIdTAG: 272376
FirstChildUserNameTAG: massys
FirstChildCreateTimeTAG: 2013-03-10T21:16:18Z
FirstChildVoteTAG: 2
FirstChildTAG: Got 36% ! So happy :)
FirstChildUserIdTAG: 766247
FirstChildUserNameTAG: ndayiwilly
FirstChildCreateTimeTAG: 2013-03-12T21:25:44Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm at 37% also.
As I calculate it, that *is* enough to pass (which I think is really, really low!)
Exercise sets are 50% of grade, 20% for midterm, 30% for final. So the calculation is:
> (0.5 * ES grade) + (0.2 * grade on mid-term) + (0.3 * grade on final)
Look at the 'ES Avg' bar on the progress page; hover over it for the value. Mine says 75% (damn! I wanted to do better than that!)
If we assume I do nothing from now on, my ES average stays at 75% (it's already counting my scores for ES 9 and 10 as 0; ES 11 and 12 don't seem to count. Ah! that's why my ES average is 75%). My mid-term and final tests would be 0, so we get:
> (0.5 * 75) + (0.2 * 0) + (0.3 * 0)
which is the 37% shown as a total grade. (My ES average is actually 74.8%; round up to show ES average as 75%, then 0.5 * 74.8 = 37.4 which rounds down to show 37% for my total.)
But don't stop now! All you can do is *improve* your grade! And learn more, of course!
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-13T00:57:19Z
FirstChildVoteTAG: 1
SecondChildTAG: ES 11 and ES 12 are currently your two lowest scores I believe.
SecondChildUserIdTAG: 1174310
SecondChildUserNameTAG: Catprog
SecondChildCreateTimeTAG: 2013-03-13T06:03:21Z
SecondChildVoteTAG: 0
SecondChildTAG: that makes sense - good thinking!
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-15T10:30:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Why have u multiplied the final and mid term scores by .2 & .3 resp. We don't need to.....congrats....
SecondChildUserIdTAG: 1043835
SecondChildUserNameTAG: anubhav_maini
SecondChildCreateTimeTAG: 2013-03-29T06:49:32Z
SecondChildVoteTAG: 0
FirstChildTAG: 37.2% for me.
Exercise 1,2,5 are where I did not get 100%
FirstChildUserIdTAG: 1174310
FirstChildUserNameTAG: Catprog
FirstChildCreateTimeTAG: 2013-03-13T06:04:23Z
FirstChildVoteTAG: 0
FirstChildTAG: i have 56%, before the exercise 12 and the final ... i think it´s a good work ... :)
FirstChildUserIdTAG: 1166847
FirstChildUserNameTAG: Jriveraespejo
FirstChildCreateTimeTAG: 2013-03-20T22:23:37Z
FirstChildVoteTAG: 0
FirstChildTAG: Exercise 11 and Exercise 12 were make a mark "The lowest 2 graded exercise scores are dropped", is it right?
I didn't do Exercise 8 and I see this mark in my score ES08. This means I can't get Certificate from this course?
FirstChildUserIdTAG: 491117
FirstChildUserNameTAG: HaiBaTu
FirstChildCreateTimeTAG: 2013-03-22T03:22:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks Prof. Ani .It Has been real learning. With your Blessing & Grace of God, I achieved 98.5 % in exercise sets (100% in all later weeks), 100% in midterm & 100% in final . That means more than 99% overall . More than 17 years after my M.B.B.S. learning new field at this age. has been very different experience . Very many thanks to you ,all edX team, all fellow students on discussion boards . Looking forward to stat2.2x . (98.5% in exercise sets means only 2 deductions for ###1. problem 1a in exercise set 2 , which is error & ###2. problem 1a in exercise set 1 i.e. income as continuous variable/continuous discrete variable )
FirstChildUserIdTAG: 485682
FirstChildUserNameTAG: arvindsingla
FirstChildCreateTimeTAG: 2013-03-31T10:30:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Where is my certificate? :) congrats all, it was a fun class..great professor .. and good course
FirstChildUserIdTAG: 929984
FirstChildUserNameTAG: Moti01
FirstChildCreateTimeTAG: 2013-03-31T15:52:59Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi guys,
Congratulations to all who have done the course successfully!
I have a questions! When are we going to receive the certificate?
All the best,
Ines
P.S. - See you on Stat2.2X :D
FirstChildUserIdTAG: 847088
FirstChildUserNameTAG: InesHenriques
FirstChildCreateTimeTAG: 2013-04-01T19:09:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you very much for this excellent course . I am so excited for the next one.
FirstChildUserIdTAG: 1290965
FirstChildUserNameTAG: mohagab2006
FirstChildCreateTimeTAG: 2013-04-02T18:35:50Z
FirstChildVoteTAG: 0
IndexTAG: 1212
TitleTAG: How can I post my answers??
I was doing the exercises, but I didn´t saw that I could not post them, why? I´m in time now...
UserIdTAG: 945953
UserNameTAG: Turca
CreateTimeTAG: 2013-03-07T04:29:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: I'm having same problem - for past 30 min!
FirstChildUserIdTAG: 1292868
FirstChildUserNameTAG: SandyL
FirstChildCreateTimeTAG: 2013-03-07T04:34:07Z
FirstChildVoteTAG: 0
FirstChildTAG: In time? Only for Week 3.
So, you didn't do as the Prof asked last week?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:36:01Z
FirstChildVoteTAG: 0
IndexTAG: 1213
TitleTAG: Trouble with submission of my work
I am having trouble submitting my assignments. Has anyone else experienced this problem,
Sonia
UserIdTAG: 1189866
UserNameTAG: SoniaSuri
CreateTimeTAG: 2013-03-07T04:27:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Maybe you should look at the forum before asking if anyone else has the problem. Sadly, lots. Sadly because we have been through this before. Yet, here we are again.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:35:34Z
FirstChildVoteTAG: 0
IndexTAG: 1214
TitleTAG: Now it is Wednesday, 6 March 2013 at 11:21:44 PM EST
To whom it may concern
I have been very busy this week and I wanted to submit the answers for the assignment at the final minutes but I think there is a problem in the system because it is now Wednesday, 6 March 2013 at 11:21:44 PM EST and the deadline is 11:30 PM but I can't submit my answers.
Regards
Hassan
UserIdTAG: 418831
UserNameTAG: haliloo
CreateTimeTAG: 2013-03-07T04:23:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: It happened the same thing with me. Tried to put in my answer of exercise 6 at 11:20, but it did not work. It is so sad!!
FirstChildUserIdTAG: 695135
FirstChildUserNameTAG: HudsonSantos
FirstChildCreateTimeTAG: 2013-03-07T04:29:56Z
FirstChildVoteTAG: 0
SecondChildTAG: hello same with me..was busy last week so what if the deadline are over?????
SecondChildUserIdTAG: 1105633
SecondChildUserNameTAG: avadhi
SecondChildCreateTimeTAG: 2013-03-17T10:28:51Z
SecondChildVoteTAG: 0
FirstChildTAG: What is sad is that even after last week's meltdown people are still not reading the Course Info!
GMT - has written in the policy that we all read. Didn't we?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:34:44Z
FirstChildVoteTAG: 1
SecondChildTAG: Why is a class taught out of California using the time zone of the United Kingdom?! Seems nuts to me.
SecondChildUserIdTAG: 1153828
SecondChildUserNameTAG: Matt2edX
SecondChildCreateTimeTAG: 2013-03-08T03:15:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Because most of the students are not in California !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-09T13:35:16Z
SecondChildVoteTAG: 0
IndexTAG: 1215
TitleTAG: GMT deadline?
Seriously? Dang.
UserIdTAG: 154551
UserNameTAG: Nano85
CreateTimeTAG: 2013-03-07T04:23:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: I guess students should be allowed to submit the exercise with some penalty for one or two days after the deadline. It is very sad to see all the answers right and getting 0 for that exercise. :(
FirstChildUserIdTAG: 1170465
FirstChildUserNameTAG: SachindraDahal
FirstChildCreateTimeTAG: 2013-03-07T04:41:59Z
FirstChildVoteTAG: 0
SecondChildTAG: You had one week to submit those exercises. It's not like you *had* to do it at the last minute :|
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-07T14:25:49Z
SecondChildVoteTAG: 0
IndexTAG: 1216
TitleTAG: Can't submit answers
Hi, is anyone else experiencing issues submitting the answers? Anyone know what to do?
UserIdTAG: 1015778
UserNameTAG: PhilippaLysaght
CreateTimeTAG: 2013-03-07T04:22:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Read the Course Info page. And accept that you missed the GMT deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:29:14Z
FirstChildVoteTAG: 2
SecondChildTAG: me too. I realized lately that the time to send the answers is over. Is there any other option to send?
SecondChildUserIdTAG: 949829
SecondChildUserNameTAG: tesfayereta
SecondChildCreateTimeTAG: 2013-03-07T04:51:25Z
SecondChildVoteTAG: 0
SecondChildTAG: The deadline passed over 5 hours ago and the 'Show Answer' button is available. It's not likely that submissions would be accepted at this point.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T05:12:28Z
SecondChildVoteTAG: 0
IndexTAG: 1217
TitleTAG: no submission?!
I've checked the time, so it isn't over, why there is no submission button?
UserIdTAG: 892435
UserNameTAG: anni2b
CreateTimeTAG: 2013-03-07T04:21:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: I'm having the same problem. Just did all the exercises for this week, but don't see my scores recorded in the progress tab.
FirstChildUserIdTAG: 1153828
FirstChildUserNameTAG: Matt2edX
FirstChildCreateTimeTAG: 2013-03-07T04:23:14Z
FirstChildVoteTAG: 0
FirstChildTAG: I am going to have to submit to all these submission queries: there is no stopping them.
Answer can be found on the following, arguably important, page:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
Please spread the word.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T04:27:16Z
FirstChildVoteTAG: 0
SecondChildTAG: LOL, spread the word. I thought the Prof did that last week. You know, with the message requesting everyone to read the course documents.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T04:31:23Z
SecondChildVoteTAG: 0
IndexTAG: 1218
TitleTAG: My apologies
I did not realize that GMT was the accepted time and that it is far earlier than my time zone. I suppose my last post can be disregarded.
UserIdTAG: 1150302
UserNameTAG: Drussell1
CreateTimeTAG: 2013-03-07T04:16:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 0
IndexTAG: 1219
TitleTAG: For the whole faculty, apologies
I am very sorry for not corresponding with the time frame of gmt, I was in an allusion that we never used a time frame. It won't happen again, I do love statistical mathematics and it pains me for forgetting that we have a specific time frame for due dates.
UserIdTAG: 990423
UserNameTAG: George95
CreateTimeTAG: 2013-03-07T04:13:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1220
TitleTAG: Can't Submit answers to graded quiz !?!
I have not been able to submit any of my answers today for either problem set 5 or 6. If possible to accept in this format, my answers are as follows for problem set 6 : 1.)60 2.)3.46 3.)SD of List A is greater than the SD of List B 4.)Distribution B 5.)7 6.)C(at most 3%). I have seen that other people have had this similar problem tonight, hopefully these will be acceptable or have the graded deadline extended for 24 hours?
UserIdTAG: 1150302
UserNameTAG: Drussell1
CreateTimeTAG: 2013-03-07T04:08:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Madam Ani Adhikari we (many of us)unable to submit our assignment today please help in this regard. Thanks
FirstChildUserIdTAG: 147852
FirstChildUserNameTAG: irtazakhalid
FirstChildCreateTimeTAG: 2013-03-07T04:14:31Z
FirstChildVoteTAG: 0
IndexTAG: 1221
TitleTAG: Time Deadline also
Just wanted it on record for the Professors and TAs. It is 10:03 Central time and I have completed the exercise. I think someone set the timer incorrectly.
Following message added later:
I read the notes about Week 3 & 4 exercises, but missed the one about GMT. I went back and reread when I read other student's comments after writing this post. Will missing the assignment result in our being removed from the class?
UserIdTAG: 1138487
UserNameTAG: gperry
CreateTimeTAG: 2013-03-07T04:07:41Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Time is 11:00 but i am unable to submit my assignment. why?
FirstChildUserIdTAG: 147852
FirstChildUserNameTAG: irtazakhalid
FirstChildCreateTimeTAG: 2013-03-07T04:09:04Z
FirstChildVoteTAG: 0
SecondChildTAG: Because it is 4:00am GMT and the answer submittal has been turned off since before 12:00am GMT. The time we need to use is GMT.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-07T04:22:00Z
SecondChildVoteTAG: 0
IndexTAG: 1222
TitleTAG: NO!!!!!
I forgot the time zone, and I really looked forward to solving the problems due to more complex analysis and equations that follow. No!! This ruined my day utterly.
UserIdTAG: 990423
UserNameTAG: George95
CreateTimeTAG: 2013-03-07T04:06:47Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: You can still solve the problems and the exercise will help you with subsequent exercises. Yay!
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-07T09:23:28Z
FirstChildVoteTAG: 0
FirstChildTAG: It's been the same time zone (GMT) since the course started...
FirstChildUserIdTAG: 1281619
FirstChildUserNameTAG: sfc17
FirstChildCreateTimeTAG: 2013-03-07T14:16:48Z
FirstChildVoteTAG: 0
IndexTAG: 1223
TitleTAG: Can't submit answers!?!
Can not submit answers to the graded quiz! If possible to accept in this format, my answers are as follows: Problem Set 5 - 1.)54 2.)1.5 3.)right-skewed 4.)less than 50 5.)True 6.)All choices are correct answer
UserIdTAG: 1150302
UserNameTAG: Drussell1
CreateTimeTAG: 2013-03-07T04:04:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: me too!!! I´m in Argentina and have a difference hour of 5 hours, I am in time!!
FirstChildUserIdTAG: 945953
FirstChildUserNameTAG: Turca
FirstChildCreateTimeTAG: 2013-03-07T04:25:53Z
FirstChildVoteTAG: 0
FirstChildTAG: > I am in time!!
Not for Week 1 or Week 2.
Yes, for Week 3
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:36:37Z
FirstChildVoteTAG: 1
IndexTAG: 1224
TitleTAG: Submission closed before time.
Why submission is closed already? It is not 23:30 Eastern nor Pacific time. Please fix that asap. Everything is spoiled already, so it should count as completed or taken away from overall grade for those people who are affected by this.
UserIdTAG: 1274808
UserNameTAG: iCeMaKeR
CreateTimeTAG: 2013-03-07T04:04:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: I filled only first exercise set 4 before March 6 23:30. They thought, that I have filled all of them, so exercise sets 5 and 6 are counted as wrong, although I didn't fill them and there is still time left.
This is a huge bug in the system.
FirstChildUserIdTAG: 1274808
FirstChildUserNameTAG: iCeMaKeR
FirstChildCreateTimeTAG: 2013-03-07T04:11:56Z
FirstChildVoteTAG: 0
SecondChildTAG: Sorry, never mind apparently it is GMT. My bad
SecondChildUserIdTAG: 1274808
SecondChildUserNameTAG: iCeMaKeR
SecondChildCreateTimeTAG: 2013-03-07T04:14:02Z
SecondChildVoteTAG: 0
IndexTAG: 1225
TitleTAG: No time is fulfilled ...
Still not satisfied the time in my country and I could not take the test. No let me qualify!
UserIdTAG: 725713
UserNameTAG: DenMar
CreateTimeTAG: 2013-03-07T03:58:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 23:30 GMT. You missed the deadline.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T05:15:47Z
FirstChildVoteTAG: 0
IndexTAG: 1226
TitleTAG: yup- cant submit answers ..done all the excercises..
cant submit answers ..done all the exercises..not sure what to do now??
UserIdTAG: 614768
UserNameTAG: Priya70
CreateTimeTAG: 2013-03-07T03:53:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: No worries, someone will be coming along soon to settle your woes. My guess is either: SusanAust, ArthurBarabash,or BBF. My money is on SusanAust...
FirstChildUserIdTAG: 309823
FirstChildUserNameTAG: prion
FirstChildCreateTimeTAG: 2013-03-07T03:58:08Z
FirstChildVoteTAG: 1
FirstChildTAG: Sing it loud ...I've been everywhere man! But always in GMT.
I see nothing has changed over the week. Groundhogs out in force.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-07T04:02:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Sadly the deadline is passed for submission, as the cut-off is based on GMT as per the course materials.
So now in the words of the Colts safety Antoine Bethea: "This week, this time, we have to prepare."
This could really be a tough week, with the Midterm flying towards us, so could be worthwhile to try and structure your study plan to submit the exercises early.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T04:05:34Z
FirstChildVoteTAG: 1
FirstChildTAG: Blast! BBF got in before me.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:37:06Z
FirstChildVoteTAG: 0
IndexTAG: 1227
TitleTAG: Wonky Text Chapter 23 diagram layout (Java?)
When I bring up Chapter 23 in the text as instructed in this week's practice, it is all messed up and impossible to read.
I AM using Chrome (Windows 8)
I DO have Java enabled
Any suggestions would be most appreciated. Thank you!
UserIdTAG: 1235638
UserNameTAG: MyOwnCamera
CreateTimeTAG: 2013-03-07T03:43:36Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I'm not having problems - Chrome, Win8.
I am getting a security window asking permission to run, which is new but not causing any trouble.
I think Java updated recently, so that might be an issue?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:49:21Z
FirstChildVoteTAG: 0
SecondChildTAG: I just downloaded and enabled the newest version. Is there something else I need to be doing? I can't really proceed with the exercises for normal curves. Also I do not get any permission window such as you mention.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-07T03:52:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Can try to make sure that you are running Chrome as an Admin:
http://www.howtogeek.com/115977/beginner-how-to-run-an-application-as-administrator-in-windows-8/
Can also try a different broswer?
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T03:54:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Don't know. If you have everything up-to-date, and enabled, I would have thought it would run.
I get a "Do you want to run this application" message. Maybe a Firewall issue?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:58:08Z
SecondChildVoteTAG: 0
SecondChildTAG: BBF, yes I am running as Admin. And I have tried every browser and so far Chrome is the only one on my laptop I can get to run edX.
Firewall? Not sure how I would even look into that...
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-07T04:03:10Z
SecondChildVoteTAG: 0
SecondChildTAG: That would depend whether you have some wonky setting in the Windows Firewall, or have a third party firewall installed (a lot of antivirus programs have them as part of the package).
You can find details on disabling the Windows one here:
http://windows.microsoft.com/en-us/windows7/turn-windows-firewall-on-or-off
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T04:09:15Z
SecondChildVoteTAG: 0
SecondChildTAG: FWIW I am using Kaspersky, and I really do not want to be turning my firewall off, do I? Sounds so ... fatal.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-07T04:15:46Z
SecondChildVoteTAG: 0
SecondChildTAG: Depends on what you are running at the time you turn it off. Despite what the News sometimes try and have us belief, there isn't a host of hackers picnicking outside each firewall, waiting for it to come down.
Kaspersky can be very particular about what it allows through, so that could have something to do with it. You can use this guide to ensure that edX is a trusted URL in your Kaspersky settings if you choose:
http://support.kaspersky.com/8052
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T04:21:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Mmmmm ... "picnic". I think I need to go to bed now and I will look at that support link. Maybe send an email to tech support also.
Thanks so much for trying to help. I was doing fine up until Java. Darn.
Good night all.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-07T04:25:06Z
SecondChildVoteTAG: 0
IndexTAG: 1228
TitleTAG: Solution set
Is there any link for solution sets which I am not able to find anywhere? Much appreciated if anyone can provide me that link. Thanks!
UserIdTAG: 1181586
UserNameTAG: eumannu
CreateTimeTAG: 2013-03-07T03:33:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Click on **Show Answer** next to each question.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:42:45Z
FirstChildVoteTAG: 0
IndexTAG: 1229
TitleTAG: The time for posting is 23:30 GMT
It will help everyone that the GMT is displayed on time deadline. I was assuming the time was California time...
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-07T03:29:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 5
FirstChildTAG: Me too. :(
FirstChildUserIdTAG: 1059787
FirstChildUserNameTAG: quetien
FirstChildCreateTimeTAG: 2013-03-07T03:55:20Z
FirstChildVoteTAG: 0
FirstChildTAG: Completely agree. Somewhere on the screen supposed to be how much time is left till due date based on where student is. Didn't even have a chance to do the last set. That's not good at all.
FirstChildUserIdTAG: 1284143
FirstChildUserNameTAG: TatiG
FirstChildCreateTimeTAG: 2013-03-07T03:56:24Z
FirstChildVoteTAG: 0
FirstChildTAG: > Somewhere on the screen supposed to be how much time is left till due date based on where student is.
You should not need to be told the time. Sometimes you have to take a bit of responsibility for your own actions. You have a computer, you can watch the time.
Funny how computers seem to have made us less able to be independent thinkers and doers.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T04:08:18Z
FirstChildVoteTAG: 0
FirstChildTAG: I can only assume the deadline is set to 23:30 in order to give us a complete last day to finish the exercises. For those of us in the USA, the vast majority I assume, 23:30 GMT will be much earlier. I work a regular job during the day, so an early Wednesday deadline does me no good. We would do much better with a clear deadline that gives us a full day.
FirstChildUserIdTAG: 1153828
FirstChildUserNameTAG: Matt2edX
FirstChildCreateTimeTAG: 2013-03-07T04:33:47Z
FirstChildVoteTAG: 0
FirstChildTAG: > . We would do much better with a clear deadline that gives us a full day.
Day? you've had a full week! Timezone doesn't matter. We all had exactly the same amount of time to do the work.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T05:02:23Z
FirstChildVoteTAG: 0
IndexTAG: 1230
TitleTAG: What is wrong with the Time
I'm trying to complete work and it isn't 1130 yet I'm not getting credit???
UserIdTAG: 641661
UserNameTAG: ChemStem
CreateTimeTAG: 2013-03-07T03:24:36Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: "What is wrong with the time"
Is this a philosophical question? Or are you saying you didnt bother reading course instructions?
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T03:31:02Z
FirstChildVoteTAG: 2
SecondChildTAG: Minor Oversight
SecondChildUserIdTAG: 641661
SecondChildUserNameTAG: ChemStem
SecondChildCreateTimeTAG: 2013-03-07T03:42:45Z
SecondChildVoteTAG: 0
FirstChildTAG: > Or are you saying you didnt bother reading course instructions?
Surely not? That is the first thing we all did. Read the Course Policies and Syllabus. And check the Course Info page for updates from the Prof. We are all doing that! Aren't we?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:32:14Z
FirstChildVoteTAG: 0
FirstChildTAG: GMT.....Man I have to be more careful....my fault
FirstChildUserIdTAG: 641661
FirstChildUserNameTAG: ChemStem
FirstChildCreateTimeTAG: 2013-03-07T03:39:48Z
FirstChildVoteTAG: 0
IndexTAG: 1231
TitleTAG: Java applets are considered unsafe by Apple, and the Java plug-in has been inactivated
Please note to Stat2.1x tech staff and professors: Apple in their most recent security update for Java they have inactivated the Java plug-in for all browsers, including Firefox and Chrome. There are zero-day vulnerabilities with the most recent version of Java, that allow malware to be downloaded using Java applets, and the only thing that might hold them at bay is the Java sandbox, which Apple has considered unacceptable. As a result, all java applets used for illustrations and problems are unavailable for use. Please consider to using web apps using Javascript and HTML5, which are available to all users.
Do you really think I would drop my security standards for even a known site, given the volatility of this issue?
UserIdTAG: 1175066
UserNameTAG: cloudman
CreateTimeTAG: 2013-03-07T03:23:12Z
VoteTAG: 4
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 5
FirstChildTAG: see the following Apple support notes about Java:
http://support.apple.com/kb/dl1572
http://support.apple.com/kb/HT5675
http://support.apple.com/kb/HT1222
FirstChildUserIdTAG: 1175066
FirstChildUserNameTAG: cloudman
FirstChildCreateTimeTAG: 2013-03-07T03:28:34Z
FirstChildVoteTAG: 1
FirstChildTAG: Im running a mac and have no issues.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T03:29:05Z
FirstChildVoteTAG: 0
SecondChildTAG: I have a PC, and I'm having the same problem. I think if your Java is up-to-date it blocks it, and if it's not up-to-date it doesn't.
SecondChildUserIdTAG: 141717
SecondChildUserNameTAG: eralon
SecondChildCreateTimeTAG: 2013-03-12T00:20:23Z
SecondChildVoteTAG: 0
SecondChildTAG: I meant if your security is up-to-date. (Not Java.)
SecondChildUserIdTAG: 141717
SecondChildUserNameTAG: eralon
SecondChildCreateTimeTAG: 2013-03-12T00:21:15Z
SecondChildVoteTAG: 0
FirstChildTAG: The last two updates from Apple have disabled the Java plug-in for all web browsers. Please note there is general advisory from CERT from March 5, 2013 recommending that Java Plug-ins for all web browsers be disabled.
More Alerts
Alert (TA13-064A)
Oracle Java Contains Multiple Vulnerabilities
http://www.us-cert.gov/ncas/alerts/TA13-064A
All versions of Java 7 through update 15, Java 6 through update 41, and Java 5.0 through update 40 are affected. Web browsers using the Java 5, 6 or 7 plug-in are at high risk.
Overview
Oracle Java 7 update 15, Java 6 update 41, Java 5.0 update 40, and earlier versions of Java contain a vulnerability that can allow a remote, unauthenticated attacker to execute arbitrary code on a vulnerable system.
Description
An arbitrary memory read and write vulnerability in the Java JVM process could allow an attacker to execute arbitrary code. An attacker could use social engineering techniques to entice a user to visit a link to a website hosting a malicious Java applet. An attacker could also compromise a legitimate website and upload a malicious Java applet (a "drive-by download" attack).
Any web browser using the Java 5, 6, or 7 plug-in is affected. The Java Deployment Toolkit plug-in and Java Web Start can also be used as attack vectors.
Reports indicate this vulnerability is being actively exploited, and exploit code is publicly available.
Further technical details are available in Vulnerability Note VU#688246.
Impact
By convincing a user to load a malicious Java applet or Java Network Launching Protocol (JNLP) file, an attacker could execute arbitrary code on a vulnerable system with the privileges of the Java plug-in process. Note that applications that use the Internet Explorer web-content-rendering components, such as Microsoft Office or Windows Desktop Search, may also be used as an attack vector for these vulnerabilities.
Solution
Update Java
Oracle Security Alert for CVE-2013-1493 states that Java 7 Update 17 (7u17) and and Java 6 Update 43 address this vulnerability (CVE-2013-1493) and a different but equally severe vulnerability (CVE-2013-0809).
Java 7 Update 17 sets the default Java security settings to "High" so that users will be prompted before running unsigned or self-signed Java applets.
Disable Java in Web Browsers
This and previous Java vulnerabilities have been widely targeted by attackers, and new Java vulnerabilities are likely to be discovered. To defend against these vulnerabilities, consider disabling Java in web browsers until adequate updates are available. As with any software, unnecessary features should be disabled or removed as appropriate for your environment.
Starting with Java 7 Update 10, it is possible to disable Java content in web browsers through the Java control panel applet. According to Setting the Security Level of the Java Client,
For installations where the highest level of security is required, it is possible to entirely prevent any Java apps (signed or unsigned) from running in a browser by de-selecting Enable Java content in the browser in the Java Control Panel under the Security tab.
If you are unable to update to Java 7 Update 10, see the solution section of Vulnerability Note VU#636312 for instructions on how to disable Java on a per-browser basis.
FirstChildUserIdTAG: 1175066
FirstChildUserNameTAG: cloudman
FirstChildCreateTimeTAG: 2013-03-07T07:02:10Z
FirstChildVoteTAG: 1
SecondChildTAG: I did activate the Java plug-in briefly in Firefox using Java 1.7.0_17, and will deactivate it in between uses. This Java vulnerability appears to be ongoing despite numerous updates of Java by Oracle. This vulnerability is cross-platform and applies also to Windows and Linux platforms, not just Mac OS X. I would be surprise if the IT tech at U Cal Berkley or edX were not aware of it.
SecondChildUserIdTAG: 1175066
SecondChildUserNameTAG: cloudman
SecondChildCreateTimeTAG: 2013-03-07T07:05:49Z
SecondChildVoteTAG: 0
SecondChildTAG: I did activate the Java plug-in briefly in Firefox using Java 1.7.0_17, and will deactivate it in between uses. This Java vulnerability appears to be ongoing despite numerous updates of Java by Oracle. This vulnerability is cross-platform and applies also to Windows and Linux platforms, not just Mac OS X. I would be surprise if the IT tech at U Cal Berkley or edX were not aware of it. In doing the last few problem sets regarding the normal distribution, it is very difficult to complete them without access to the normal distribution applet. So far no problems, but I am very leary of java malware, given the US-CERT advisories. Why not use a javascript web app instead or a risky Java applet?
SecondChildUserIdTAG: 1175066
SecondChildUserNameTAG: cloudman
SecondChildCreateTimeTAG: 2013-03-07T07:07:37Z
SecondChildVoteTAG: 0
SecondChildTAG: you can die crossing a street everyday.... just turn it on and off.
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-09T00:57:16Z
SecondChildVoteTAG: 0
FirstChildTAG: You may google for "normal distribution table", applet made in flash and images of distribution table can help.
FirstChildUserIdTAG: 1378421
FirstChildUserNameTAG: Misaka
FirstChildCreateTimeTAG: 2013-03-08T00:55:33Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you for the information. I don't normally use flash, but I will look for similar Normal distribution tables in javascript and jquery. If I find anything worthy of mention, I will post it here for your review. Take Care!
BTW you might find the following link useful for information about internet and mobile device malware: http://www.f-secure.com/en/web/labs_global/
The H2 2012 Threat report and Q4 2012 Mobile Threat Report make interesting reading.
SecondChildUserIdTAG: 1175066
SecondChildUserNameTAG: cloudman
SecondChildCreateTimeTAG: 2013-03-08T05:18:31Z
SecondChildVoteTAG: 0
FirstChildTAG: It is Java script applet and not Java which are not the same.They are different
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T13:37:58Z
FirstChildVoteTAG: 3
IndexTAG: 1232
TitleTAG: unable to submit exercise set 6
I was on business training for 3 days and back home this evening. couldn't submit answers for exercise set 6 as it passed deadline in GMT time. so sad.
UserIdTAG: 1249880
UserNameTAG: xuy1
CreateTimeTAG: 2013-03-07T03:22:31Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: So sad indeed.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:31:14Z
FirstChildVoteTAG: 0
FirstChildTAG: Im also saddened by the inability of xuy to submit the answers.
Now, xuy, be frank here - Russian?
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T03:34:59Z
FirstChildVoteTAG: 0
SecondChildTAG: Implausible. It's thursday morning in Russia. They're from the future.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T03:36:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Im only asking because my Russian friend is sitting here and giggling at the user name of the OP.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T03:39:19Z
SecondChildVoteTAG: 0
SecondChildTAG: The Y and the U would need to be in reverse order to make it giggle-worthy to a real Russian.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T03:41:34Z
SecondChildVoteTAG: 0
SecondChildTAG: What if he doesn't want to be Frank?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:43:59Z
SecondChildVoteTAG: 0
SecondChildTAG: @ BBF - Yeah maybe. This particular Russian giggles for no reason.
@ Susan - OP can be Steve if he doesnt want to be Frank.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T03:48:22Z
SecondChildVoteTAG: 0
SecondChildTAG: I didn't notice the "xuy" until you commented on it. Shame on you.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T05:19:31Z
SecondChildVoteTAG: 0
IndexTAG: 1233
TitleTAG: Why did`t I have option to finish my exercise? My country have same time that USA
Hello!
I tried to arrive very soon of my job. I needed finish my excersise but I didn´t have option. My country have the same time. What happen? the limit time is at 11:30, Thanks
UserIdTAG: 1161612
UserNameTAG: anmuc
CreateTimeTAG: 2013-03-07T03:20:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 6
FirstChildTAG: This happen to me last weeks set...what is going on
FirstChildUserIdTAG: 641661
FirstChildUserNameTAG: ChemStem
FirstChildCreateTimeTAG: 2013-03-07T03:25:46Z
FirstChildVoteTAG: 0
FirstChildTAG: > My country have the same time. What happen? the limit time is at 11:30, Thanks
You need to read the course info. You need to read the Prof's message. GMT.
And there are several US timezones, so your country having the same time as the US is a pretty broad frame.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:26:15Z
FirstChildVoteTAG: 1
FirstChildTAG: same problem with me. I still have 1 hour to submit exercise but its not allowing me to do so. Some problem with the timing or software. Moderators please respond....
FirstChildUserIdTAG: 1145140
FirstChildUserNameTAG: Masoodulhaq
FirstChildCreateTimeTAG: 2013-03-07T03:27:31Z
FirstChildVoteTAG: 0
FirstChildTAG: The Prof appears to be delightfully old-school from when the world was not believed to revolve around the USA (even though they are home to The West Wing and CityZen restaurant). The deadlines are set in GMT to allow consistency for all students all around the world, as detailed in the course policy and announcements.
Reference:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
and
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T03:30:04Z
FirstChildVoteTAG: 0
SecondChildTAG: But if it did revolve around the US, in which timezone would it be? East? West? Mountain? Central?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:40:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, the mode of the population as divided by time zones would be Eastern. The geographical median would likely land it somewhere in Central.
Averaging the abbreviations of the time zones looked easy by assigning numerical values to the letters until Alaska and Hawaii broadsided me with the 4-letter abbreviations.
So I am going to jettison myself out of this discussion by distracting you with a song:
http://www.youtube.com/watch?v=NKKTez5Djtc
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T03:49:39Z
SecondChildVoteTAG: 0
FirstChildTAG: > This happen to me last weeks set...what is going on
What is going on? A small subset of students are refusing to read the course information. Refusing to read the forum. Refusing to basically follow instructions. Simple really.
> Moderators please respond...
Why should they? You obviously aren't reading the information that has been provided since Day 1.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:30:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Not sure it is a small subset.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T03:37:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I was being generous.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:39:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Imagine getting the opportunity to review such anonymous data. Would it not be fascinating?
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T03:39:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh yes. The edX people must have some mind boggling data. Oh, to be a fly on the wall!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:46:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Susan,
neglecting ≠ REFUSING
SNARKINESS ≠ intelligence
SecondChildUserIdTAG: 142313
SecondChildUserNameTAG: jjave
SecondChildCreateTimeTAG: 2013-03-07T03:53:06Z
SecondChildVoteTAG: 0
SecondChildTAG: WOOT!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:54:26Z
SecondChildVoteTAG: 0
FirstChildTAG: Am I too late for the drinking game?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-07T03:59:55Z
FirstChildVoteTAG: 3
SecondChildTAG: Where have you been, Christine?! I hate drinking by myself.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T05:21:47Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm busy working (blast the people who decided we need money to survive and feed our kids in a capitalist world). Unlike some I don't whine and complain about it, or expect special treatment. I just suck it up and work on this course when I can.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-10T21:42:38Z
SecondChildVoteTAG: 0
IndexTAG: 1234
TitleTAG: Time Problem...
I still have 3 hours of time to di the test and the test is closed. Please fix the time zome properly for the test, is very unfair loose one entire test by time bugs...
UserIdTAG: 323166
UserNameTAG: PabloT
CreateTimeTAG: 2013-03-07T03:13:49Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: > I still have 3 hours of time to di the test and the test is closed. Please fix the time zome properly for the test, is very unfair loose one entire test by time bugs...
No bugs. Just an inability to read all the course documents properly. GMT
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:17:26Z
FirstChildVoteTAG: 0
IndexTAG: 1235
TitleTAG: We can handle the truth.
So I have been fascinated with the mass of data we have from like nine legions of students being signed up for the course.
I wonder if there is any plans to use this data in examples or even questions. Seems we are all submitting a lot of data which would be awesome from a watching the watchers viewpoint.
Plus it could be good motivation to stay on the numbers, like when the Saints were still playing for that slim chance for an 0 and 3 team to make it to the playoffs, to like try and see how long we can stay even with Susan on her 100% and such.
UserIdTAG: 1019741
UserNameTAG: BBF
CreateTimeTAG: 2013-03-07T03:13:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: ![enter image description here][1]
[1]: http://fistfuloftalent.com/wp-content/uploads/2010/10/truth_exit_sign-460x250.jpg
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T03:21:00Z
FirstChildVoteTAG: 2
IndexTAG: 1236
TitleTAG: Unable to submit answers at 22:10
Unable to submit my answers, even though it is not 11:30pm.
UserIdTAG: 262089
UserNameTAG: anmicard
CreateTimeTAG: 2013-03-07T03:10:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: Unable to read simple instructions.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T03:15:30Z
FirstChildVoteTAG: 0
FirstChildTAG: > even though it is not 11:30pm.
True. It is 3.15am thursday GMT. Well beyond the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:15:35Z
FirstChildVoteTAG: 1
FirstChildTAG: May grade is going to be ugly....
FirstChildUserIdTAG: 641661
FirstChildUserNameTAG: ChemStem
FirstChildCreateTimeTAG: 2013-03-07T03:40:29Z
FirstChildVoteTAG: 0
IndexTAG: 1237
TitleTAG: Unable to submit
Unable to submit
UserIdTAG: 1191602
UserNameTAG: Lvcole
CreateTimeTAG: 2013-03-07T03:04:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: Unable to submit
FirstChildUserIdTAG: 1260474
FirstChildUserNameTAG: Shikha1980
FirstChildCreateTimeTAG: 2013-03-07T03:10:40Z
FirstChildVoteTAG: 0
FirstChildTAG: unable to follow simple instructions.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T03:14:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Unable to use the forum properly
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:15:54Z
FirstChildVoteTAG: 0
SecondChildTAG: LOL!!! You and Arthur are killing me!
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T05:24:02Z
SecondChildVoteTAG: 0
IndexTAG: 1238
TitleTAG: MIDTERM TIMEFRAME?
Dear Stat 2.1x Team,
Please inform about the time frame we will have for the MidTerm Exam, for example how many hours we will have, starting for instance (March 13) at 14:00 GMT and ending at 19:00 GMT.
On the other hand, let us know at what time the exam will be released. On other edX courses, the exams are released, but time begins to count only when a student clicks the second page on the exam. In the first page (or landing page) normally, there is useful information with a motivational message, so people have the opportunity to go back a study some more before clicking page 2.
Thanks in advance for the information, and of course, for this class, specially to Professor Adhikari, for her simple, lucid and sharp teaching and knowledge, everything is really great,
Oscar.
UserIdTAG: 609816
UserNameTAG: Oscar7000
CreateTimeTAG: 2013-03-07T03:02:29Z
VoteTAG: 9
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Agreed. If we only have a 24 hour window to take the Midterm, I'd like warning to adjust my schedule.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-03-07T03:57:44Z
FirstChildVoteTAG: 3
FirstChildTAG: Prof has said that the exam can be submitted:
*Any time that day. I'll post the exact period, but you'll certainly have a day.*
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T23:22:39Z
FirstChildVoteTAG: 0
IndexTAG: 1239
TitleTAG: Couldn't submit
Only "Show Answer"
UserIdTAG: 967979
UserNameTAG: snoowball
CreateTimeTAG: 2013-03-07T02:55:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: Time was out before deadline. Trying to submit Ex 4, 5 and 6 but did not work.
FirstChildUserIdTAG: 1248875
FirstChildUserNameTAG: Ryanraj
FirstChildCreateTimeTAG: 2013-03-07T02:56:33Z
FirstChildVoteTAG: 0
SecondChildTAG: same issue...seems like system issue
SecondChildUserIdTAG: 311053
SecondChildUserNameTAG: ejcacciatore
SecondChildCreateTimeTAG: 2013-03-07T03:00:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Ya. The system is out to get you.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T03:17:40Z
SecondChildVoteTAG: 0
FirstChildTAG: > same issue...seems like system issue
No. It is the same issue as last week. Students not reading the Course Info, or the Prof's message.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:01:59Z
FirstChildVoteTAG: 0
IndexTAG: 1240
TitleTAG: The quiz wasn't functioning on Chrome version 25.0.1364.152 m. My answers follow...
PROBLEM 1 : 54
PROBLEM 2 : 1.5
PROBLEM 3 : right-skewed
PROBLEM 4 : less than 50
PROBLEM 5 : True
PROBLEM 6 : more than 25, 35, and 45
UserIdTAG: 994938
UserNameTAG: keithlhatfield
CreateTimeTAG: 2013-03-07T02:51:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Are you sure it was the quiz that was not functioning?
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T02:59:52Z
FirstChildVoteTAG: 1
SecondChildTAG: Careful, you might be joining the Mean Persons table.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:02:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Well... it is pretty blatant! Honor code, yes?
SecondChildUserIdTAG: 162716
SecondChildUserNameTAG: nathanleiby
SecondChildCreateTimeTAG: 2013-03-07T03:04:38Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree, no solutions are meant to be posted here on or before the due date/time.
SecondChildUserIdTAG: 609816
SecondChildUserNameTAG: Oscar7000
SecondChildCreateTimeTAG: 2013-03-07T03:06:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, has this exercise set closed over 3 hours ago, I don't see a problem.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:11:02Z
SecondChildVoteTAG: 0
SecondChildTAG: as not has
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:11:17Z
SecondChildVoteTAG: 0
IndexTAG: 1241
TitleTAG: Please configure time in local hour
I suggest you to configure the end time for graded the exercises at local time, another courses take in account the local time in similar cases, for example, here in El Salvador, the elapsed time finished now march 6th at 6:30 p.m. and this situation does not permit the participation this day.
Today i have finished my exercises on paper, but I don't have time to summit on time because I was in a field trip, so I am so sad because I have checked my answers and all of them were correct.
Please try to permit the same opportunities for everybody.
UserIdTAG: 910307
UserNameTAG: MarciaLizeth
CreateTimeTAG: 2013-03-07T02:51:21Z
VoteTAG: 3
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: Even if the time had been set to your local time, it is gone. There is only one GMT - it is up to us to know what that corresponds to with our own local time.
> Please try to permit the same opportunities for everybody.
Everyone had exactly the same amount of time to do the exercises. 7 days.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:57:40Z
FirstChildVoteTAG: 4
FirstChildTAG: Time was out before deadline.... so sad.
FirstChildUserIdTAG: 1248875
FirstChildUserNameTAG: Ryanraj
FirstChildCreateTimeTAG: 2013-03-07T02:58:24Z
FirstChildVoteTAG: 0
IndexTAG: 1242
TitleTAG: Ex7 Problem 3B, how to approach SD given different weighings for "score"?
I'm a bit stuck on how to approach the question: "Find the SD of *scores* of the class." I know that multiplying the scores suggests that one should multiply the mean, but there are two factors (5 and -1) which seem to weigh differently. Can you give any other suggestion of a similar problem or how to approach this issue?
Thanks!
Note: SOLVED. I made up a dataset in R which ~matched the question's parameters, updated it accordingly based on "right" to "score" mapping, and then used this to experimentally determine the Mean and SD. I'm still not sure what linear transform is happening which causes the SD to move as it does (though the multiplier makes sense). If others are stuck on this it might need a response, but otherwise I can read the answers next week.
UserIdTAG: 162716
UserNameTAG: nathanleiby
CreateTimeTAG: 2013-03-07T02:50:57Z
VoteTAG: 2
CoursewareTAG: Exercise Set 7 / Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: Try to write everything in terms of the number right; including the number wrong. That should do the job. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-07T03:04:40Z
FirstChildVoteTAG: 1
SecondChildTAG: I am sorry but i don't understand what you mean by this. Can you give an example?
SecondChildUserIdTAG: 1223424
SecondChildUserNameTAG: BrendaS
SecondChildCreateTimeTAG: 2013-03-07T08:20:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Refer to the below thread:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_7/threads/513c3e63e8c82427000000e9
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-10T11:14:31Z
SecondChildVoteTAG: 0
FirstChildTAG: I still need help on this I see why you need to multiply by 5, but why do you factor in the -1? On the Celsius example:
Avg = 20 SD= 5
New avg = Degrees F = (9/5) x 20 + 32 = 68
New SD = Degrees F = (9/5) x 5 = 9
My notes may be wrong, but in that example you left out the +32 when figuring the New SD. Is it the same way on 3B when figuring out the class SD?
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-03-07T23:20:05Z
FirstChildVoteTAG: 0
SecondChildTAG: You have to factor in the -1 in this case because it is multiplied by a variable (the number of wrong answers). In the Celsius/Fahrenheit example, the 32 is a constant--the same for every conversion. Here the number of wrong answers is multiplied by -1, so the result is a variable.
SecondChildUserIdTAG: 538232
SecondChildUserNameTAG: ANNECBH
SecondChildCreateTimeTAG: 2013-03-09T02:28:35Z
SecondChildVoteTAG: 0
IndexTAG: 1243
TitleTAG: submission
I have just a button show answers, so my ones are correct, but I could't submit 'em!
UserIdTAG: 892435
UserNameTAG: anni2b
CreateTimeTAG: 2013-03-07T02:47:05Z
VoteTAG: 2
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: Same thing happened to me too. I was busy all day and tried to submit this evening but did not work. It was couple of hours before deadline given in the exercise tab.
FirstChildUserIdTAG: 1248875
FirstChildUserNameTAG: Ryanraj
FirstChildCreateTimeTAG: 2013-03-07T03:01:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Same here.
SecondChildUserIdTAG: 1092175
SecondChildUserNameTAG: Hillmer
SecondChildCreateTimeTAG: 2013-03-07T03:19:13Z
SecondChildVoteTAG: 0
SecondChildTAG: how can i submit my answer?
SecondChildUserIdTAG: 1077280
SecondChildUserNameTAG: Mayoliza
SecondChildCreateTimeTAG: 2013-03-08T02:26:23Z
SecondChildVoteTAG: 0
FirstChildTAG: > It was couple of hours before deadline given in the exercise tab.
That would depend on whether you were using the correct timezone. GMT. As explained in the official documents.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T03:04:54Z
FirstChildVoteTAG: 0
SecondChildTAG: But last time I've paid attention to time there were EST!!!!!!
So I was sure I have time to complete tasks.
It's a pity that I missed change of conditions...
SecondChildUserIdTAG: 892435
SecondChildUserNameTAG: anni2b
SecondChildCreateTimeTAG: 2013-03-07T04:49:30Z
SecondChildVoteTAG: 0
SecondChildTAG: There was no change in conditions. The deadline has always been expressed in GMT, since day 1.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T05:27:33Z
SecondChildVoteTAG: 0
SecondChildTAG: I am answering it several days ago but i cant post my answer please help!
SecondChildUserIdTAG: 1077280
SecondChildUserNameTAG: Mayoliza
SecondChildCreateTimeTAG: 2013-03-08T02:25:40Z
SecondChildVoteTAG: 0
IndexTAG: 1244
TitleTAG: Unable to submit answers
I'm trying to submit answers but they will not save. Have tried multiple times on two
UserIdTAG: 951634
UserNameTAG: jlowder
CreateTimeTAG: 2013-03-07T02:36:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: > Not sure what to do.
Read the Course Info. Accept that you missed the deadline, and move on to Week 3. And make note of when GMT is, compared to your own time zone.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:38:46Z
FirstChildVoteTAG: 0
SecondChildTAG: *This has (typo)
SecondChildUserIdTAG: 641661
SecondChildUserNameTAG: ChemStem
SecondChildCreateTimeTAG: 2013-03-07T03:44:41Z
SecondChildVoteTAG: 0
SecondChildTAG: GMT never occurred to me so thanks for the tip. Also just noticed the note about week 3 and saw that the answers were going to be shown. Thanks again.
SecondChildUserIdTAG: 951634
SecondChildUserNameTAG: jlowder
SecondChildCreateTimeTAG: 2013-03-07T04:10:06Z
SecondChildVoteTAG: 0
IndexTAG: 1245
TitleTAG: Deadline mistake
Obviously it shows that deadline for this exercise is supposed to be 11:30pm today, but it's only 9:23pm...What am I supposed to do?
UserIdTAG: 902737
UserNameTAG: LiangYou
CreateTimeTAG: 2013-03-07T02:22:32Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: May I suggest reading about the various timezones of the world? And finding out which one is applicable?
Perhaps once you go through this emotional journey, you will discover that you missed the deadline.
Or...perhaps you will be posting here again next week about the same issue.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T02:27:45Z
FirstChildVoteTAG: 0
FirstChildTAG: And you could also try reading the Prof's message on the Course Info page, and do as she asked us to do last week. Read the course policy.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:31:49Z
FirstChildVoteTAG: 0
IndexTAG: 1246
TitleTAG: Time Deadline inaccurate
Dear Sirs,
I have attempted to submit my answers by the posted deadline allowing for CST, but I have not been able to submit the answers. I was able to do so during the last problem sets, using the deadline as indicated. Is there a server problem or have you changed time zones. Please display the time zone for the time deadline accurately.
UserIdTAG: 1175066
UserNameTAG: cloudman
CreateTimeTAG: 2013-03-07T02:11:09Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: The deadline was 23:30 GMT, over 2 hours ago.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T02:12:20Z
FirstChildVoteTAG: 1
FirstChildTAG: This is clearly detailed in the course policy, and in comments by the Prof on the course info page.
> I was able to do so during the last problem sets, using the deadline as indicated.
No, you weren't. The deadline last week was extended (as you would have read on the Course info page) because of the inability of some to follow basic instructions.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:16:31Z
FirstChildVoteTAG: 0
IndexTAG: 1247
TitleTAG: cannot submit assignment for today.
cannot submit assignment for today.
UserIdTAG: 1084726
UserNameTAG: mjparra
CreateTimeTAG: 2013-03-07T02:07:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: That's correct. The deadline was 23:30 GMT, over 2 hours ago.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T02:10:36Z
FirstChildVoteTAG: 0
FirstChildTAG: This seems like a fantastic opportunity to examine the concept of correlation: as time progresses through the day, the number of people unable to submit the exam increases.
http://xkcd.com/552/
Now I apologise for this coming off as somewhat mean, but surely the endless parade of threads that already have a similar title and have answers could have been used to gather the relevant data?
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T02:11:06Z
FirstChildVoteTAG: 0
SecondChildTAG: LOL!
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T02:13:17Z
SecondChildVoteTAG: 0
FirstChildTAG: The deadline for Weeks 1 and 2 is gone, you can only submit Week 3. Please, please, please, read the Course Info page.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:11:16Z
FirstChildVoteTAG: 0
FirstChildTAG: > Now I apologise for this coming off as somewhat mean, but surely the endless parade of threads that already have a similar title and have answers could have been used to gather the relevant data?
You are the meanest meanie!
Maybe the first assessment item on courses should involve reading the course documentation and answering questions about it. Then if anyone posts these sort of "oh noes!!!!!" posts, they can be docked the marks.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:18:58Z
FirstChildVoteTAG: 0
SecondChildTAG: *sigh* not I have been pronounced mean by the Queen of the Forums, and there is no going back on it. Can I at least also be judged to be entertaining?
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T02:23:16Z
SecondChildVoteTAG: 0
SecondChildTAG: You post xkcd, so you are indeed entertaining.
And fear not, I have it on good authority that they don't come any meaner than yours truly.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T02:25:59Z
SecondChildVoteTAG: 0
IndexTAG: 1248
TitleTAG: I don´t undertand Problem 2, Parts a) and b)
Why in the to parts of the exercise they multiply by 10?
in a) 1.32⋅10=13.2%
in b) (12.5/15)⋅10=8.33%
UserIdTAG: 1208522
UserNameTAG: nicifuentes
CreateTimeTAG: 2013-03-07T02:05:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: We got the percent per year by dividing the total number of percent in the 30-45 category by the number of years in it, which is 15. However of those 15 only 10 are thirties, so we multiply the result by the decade of thirties getting the answer.
In the senior citizen question, likewise 60-75 only contains 10 years of people 65+
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T02:17:23Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you click on **Show Answer** to read the explanation?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:23:59Z
FirstChildVoteTAG: 0
IndexTAG: 1249
TitleTAG: Time Problem!!!
IN Argentina is exactly 23:04! and I can finish the excercises. I heard that the time shown is adapted to local time. Am I wrong?
I WILL ADD A SONG TO MY POST: SOOoo un PERDEDOR, IM a LOOSER BABY, SO WHY DONT YOU KILL ME.....
I finally understand Greenwinch MEAN !!! TIME.
UserIdTAG: 1222835
UserNameTAG: CatonElMenor
CreateTimeTAG: 2013-03-07T02:05:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: "One point to note: there's only one Greenwich Mean Time. There isn't a GMT in every country, in spite of what some of you have been telling me."
I am afraid whoever told you that lied to you, my friend.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T02:07:18Z
FirstChildVoteTAG: 0
FirstChildTAG: Time problem is a relative concept.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T02:13:52Z
FirstChildVoteTAG: 0
FirstChildTAG: > SO WHY DONT YOU KILL ME
I think that is over-reacting somewhat. You only need 35% to pass this first installment. Just live and learn.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:23:04Z
FirstChildVoteTAG: 0
SecondChildTAG: Sheesh.. and you called yourself mean. You're a softie.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T02:30:39Z
SecondChildVoteTAG: 0
IndexTAG: 1250
TitleTAG: Cannot submit Assignment
I cannot submit my assignment for this task.
UserIdTAG: 935153
UserNameTAG: Danogee
CreateTimeTAG: 2013-03-07T02:00:25Z
VoteTAG: 2
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: Correct. You have missed the deadline. Have you read the Course Info?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T02:01:17Z
FirstChildVoteTAG: 0
IndexTAG: 1251
TitleTAG: Mid term Date problems..!!!
Greetings Sir/Madam
The course has been going very well. It has been informed that the Mid-term wil be on 13th March.
We are all students from various parts of the world and Mid term exams on one single day might be extremely difficult for all of us to comprehend our duties on a single day.
It would have been nice, if you had kept the Midterm window for 3 or atlest 2 days thereby giving us an option to free ourselves on either of one of the day if we have very important works of our own on one day.
Would like you to consider this..
With Regards
Murali Karthikeyan
UserIdTAG: 513978
UserNameTAG: Murali_Karthikeyan
CreateTimeTAG: 2013-03-07T01:57:13Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1252
TitleTAG: How to graph three variables in a histogram, if possible
Does anyone know how I can graph three variable in a histogram. Here is the example:
Contributions: $0-25, $50-$100, $100-$500, $500+
Frequency in each bin: 15, 5, 7,10
Total Revenue: $105, $285, $1750, $7500
I want convey the relationship between low dollar donors and high dollar donors vs. the total revenue.
UserIdTAG: 1299221
UserNameTAG: coxen00
CreateTimeTAG: 2013-03-07T01:54:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Where is the third variable ? You only ahve contributions and their frquency.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T13:40:04Z
FirstChildVoteTAG: 0
IndexTAG: 1253
TitleTAG: enable to submit
i can not submit any answers...... i'm running out of time.please help
UserIdTAG: 977559
UserNameTAG: MarieYolande
CreateTimeTAG: 2013-03-07T01:51:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: The deadline was 22:30 GMT, around 2 hours ago.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T01:52:23Z
FirstChildVoteTAG: 0
FirstChildTAG: > i'm running out of time.please help
you have run out of time.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:58:54Z
FirstChildVoteTAG: 0
SecondChildTAG: You make it sound so final...
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T02:00:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Only because my hope for the future of mankind is approaching zero.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T02:03:20Z
SecondChildVoteTAG: 0
SecondChildTAG: It's like Groundhog Day.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T02:08:53Z
SecondChildVoteTAG: 0
FirstChildTAG: I cannot submit any answers. I dont understand why It is not 12:00 yet. I would like to have the opportunity to submit my answers. Can I have an email on that. Tx
FirstChildUserIdTAG: 514962
FirstChildUserNameTAG: rphilippe
FirstChildCreateTimeTAG: 2013-03-07T03:08:52Z
FirstChildVoteTAG: 0
SecondChildTAG: > Can I have an email on that.
How about the Course Info page, where the Prof requests that everyone go read the course policy?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:19:55Z
SecondChildVoteTAG: 0
SecondChildTAG: The guy didn't even bother reading the comments above before posting his question. Do you really expect him to read the Course Info page?
I am willing to bet he doesn't read your response or even this message. Most likely just waiting on his email app for a response from whoever about it "not 12:00 yet" (Moreover, the deadline is 11:30 so that is a double fail right there)
SecondChildUserIdTAG: 309823
SecondChildUserNameTAG: prion
SecondChildCreateTimeTAG: 2013-03-07T03:51:26Z
SecondChildVoteTAG: 0
IndexTAG: 1254
TitleTAG: SD
I like the way Prof. Ani Adhikari explained about SD! ^^
UserIdTAG: 491117
UserNameTAG: HaiBaTu
CreateTimeTAG: 2013-03-07T01:51:26Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.2: Deviations from average; the standard deviation (SD)
NumberOfReplyTAG: 0
IndexTAG: 1255
TitleTAG: aplet issues
http://statistics.berkeley.edu/~stark/Java/Html/NormHiLite.htm.
Even after downloading the updated java - I am still having problems with the aplet working. Is there a workaround? Is anyone else having issues with it?
UserIdTAG: 1150329
UserNameTAG: cbratsis
CreateTimeTAG: 2013-03-07T01:45:05Z
VoteTAG: 0
CoursewareTAG: Practice For Exercise Set 7 / Reading and Practice For Exercise Set 7
NumberOfReplyTAG: 2
FirstChildTAG: Try a different browser - Chrome or Firefox (depending on what you have already tried)
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:46:27Z
FirstChildVoteTAG: 0
SecondChildTAG: It did not work on Chrome, I changed the analogue monitor and its fine now.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-07T15:23:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Try to download browser plug-in for both x86 and x64 browser, java.com indicates that:
> If you use 32-bit and 64-bit browsers interchangeably, you will need to install both 32-bit and 64-bit Java in order to have the Java plug-in for both browsers.
Here's the link for you: http://java.com/en/download/manual.jsp
FirstChildUserIdTAG: 1378421
FirstChildUserNameTAG: Misaka
FirstChildCreateTimeTAG: 2013-03-08T01:03:16Z
FirstChildVoteTAG: 0
IndexTAG: 1256
TitleTAG: Problem 6
If the answer is 6.2/15.5=0.4, then any of the answer "more than 25" and "more of 35 applies". why picking just one is incorrect?
UserIdTAG: 1284510
UserNameTAG: AnaFlores7
CreateTimeTAG: 2013-03-07T01:43:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: "Select all that are correct."
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T01:48:36Z
FirstChildVoteTAG: 0
IndexTAG: 1257
TitleTAG: Glitch
There is a technical glitch in this exercise set. Only show answer option is displaying instead of submit answer. Please scrap this exercise and replace with another one so that everyone gets a proper shot. Thanks
UserIdTAG: 393719
UserNameTAG: nirmalpaudel
CreateTimeTAG: 2013-03-07T01:39:51Z
VoteTAG: 3
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: That is because the deadline 23.30 GMT is over.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-07T01:43:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Oh my god, i thought i had plenty of time to do this
SecondChildUserIdTAG: 1222341
SecondChildUserNameTAG: richardHk
SecondChildCreateTimeTAG: 2013-03-07T01:54:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I red somewhere that the time shown in the deadline is adapted to your time zone. Am I right?
SecondChildUserIdTAG: 1222835
SecondChildUserNameTAG: CatonElMenor
SecondChildCreateTimeTAG: 2013-03-07T02:10:36Z
SecondChildVoteTAG: 0
SecondChildTAG: Nowhere on this site does it say that the time is adapted to your time zone.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T02:11:37Z
SecondChildVoteTAG: 0
FirstChildTAG: > There is a technical glitch in this exercise set.
The glitch isn't with the exercise
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:44:43Z
FirstChildVoteTAG: 0
SecondChildTAG: Ouch.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T01:53:11Z
SecondChildVoteTAG: 0
IndexTAG: 1258
TitleTAG: CLOSING TIME
LEONARD COHEN
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-07T01:39:28Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 0
IndexTAG: 1259
TitleTAG: If you want to know the time...
Ask someone else, I'm going to bed.
Time here now in the UK is 01.25 GMT - that's nearly 2 hours after the submission deadline if you're wondering why you can't finish you exercises.
If you missed the deadline, don't worry, the two lowest marks are dropped from the average anyway and you only need 35% overall to pass.
I would suggest you keep track of the time next week though...
Why did this post (like so many others) end up in Ex 1 - I definitely selected ex 6...
Oh well, at least I've submitted Ex7 now and can rest content that I need only 1% more to pass. (smug)
UserIdTAG: 952145
UserNameTAG: PaulJM
CreateTimeTAG: 2013-03-07T01:25:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1260
TitleTAG: Please I study this section very good so I can improve my average!
I want to answer the problem in this section it is only 19:23 central time!
UserIdTAG: 1260415
UserNameTAG: JESUSJCARBAJAL
CreateTimeTAG: 2013-03-07T01:23:58Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Too late.
What time is the deadline?
23.30 **GMT**
What time is it now?
01.28 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T01:27:55Z
FirstChildVoteTAG: 1
FirstChildTAG: If you are not going to read the replies to your other post, why should we bother?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:28:48Z
FirstChildVoteTAG: 0
IndexTAG: 1261
TitleTAG: WROOOONGGGGG TIME!!!!!!!!!
GOD, I was confused with EAST TIME is already is already GMT Thursday March 7 at 1:20 am, PACIFIC TIME IS ONLY 5:20 pm Wednesday , March 6 .
This is very sad, I wish, we could have another chance to submit our work......
UserIdTAG: 759233
UserNameTAG: ARIIDO
CreateTimeTAG: 2013-03-07T01:23:39Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: If you did the Week 1 work, then you should have known about the time.
And if you had read the course documents and Prof's message, you would have known.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:27:06Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes you are right, getting experience and trust me...It wont be happening to me again...I promise myself !
SecondChildUserIdTAG: 759233
SecondChildUserNameTAG: ARIIDO
SecondChildCreateTimeTAG: 2013-03-07T01:39:15Z
SecondChildVoteTAG: 0
FirstChildTAG: You can use this link to reference GMT compared to wherever you are, as Bon Jovi would put it:
http://wwp.greenwichmeantime.com/
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T01:50:10Z
FirstChildVoteTAG: 0
IndexTAG: 1262
TitleTAG: Can't seem to submit Exercise 6
I don't have a Final Check or Submit button for Exercise 6, but have a Show Answer button instead. Looks like I scored 0/15 in Progress. Can this be reset?
UserIdTAG: 1205399
UserNameTAG: kmilhauser
CreateTimeTAG: 2013-03-07T01:22:24Z
VoteTAG: 3
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: > Can this be reset?
Nope. You missed the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:25:33Z
FirstChildVoteTAG: 0
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
01.26 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T01:26:38Z
FirstChildVoteTAG: 0
IndexTAG: 1263
TitleTAG: Inaudible
Wasn't it 'Chebyshev'?
UserIdTAG: 1338976
UserNameTAG: karusia
CreateTimeTAG: 2013-03-07T01:17:59Z
VoteTAG: 5
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.1: Bell shaped curves; the standard normal curve
NumberOfReplyTAG: 2
FirstChildTAG: Wasn't what?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:21:36Z
FirstChildVoteTAG: 0
SecondChildTAG: "Was it not...?"
And yes, Chebyshev (or Chebychev).
SecondChildUserIdTAG: 1158056
SecondChildUserNameTAG: CanuckistaniPhilosopher
SecondChildCreateTimeTAG: 2013-03-07T19:37:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Agreed. That line with an "[inaudible] Should be: "Remember, Chebyshev had told us that it has to be at least 75%."
FirstChildUserIdTAG: 949545
FirstChildUserNameTAG: bwgriffiths
FirstChildCreateTimeTAG: 2013-03-07T16:43:30Z
FirstChildVoteTAG: 2
SecondChildTAG: LOL, not a name I would expect to find in the dictionary. The subtitles must be computer generated.
SecondChildUserIdTAG: 1153828
SecondChildUserNameTAG: Matt2edX
SecondChildCreateTimeTAG: 2013-03-08T18:40:16Z
SecondChildVoteTAG: 0
IndexTAG: 1264
TitleTAG: Numbers in the video
Dear Prof Ani,
Could I request you to enlarge the size of the fonts in your slides in your video presentation.They are too small to decipher.
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-03-07T01:13:12Z
VoteTAG: 8
CoursewareTAG: Section 4, continued / Lec 4.4 Changing units of measurement; standard units
NumberOfReplyTAG: 4
FirstChildTAG: View the video on full screen.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:21:21Z
FirstChildVoteTAG: 0
SecondChildTAG: You could see everything better in the slides rather than the video presentations.
SecondChildUserIdTAG: 886662
SecondChildUserNameTAG: Darrell193
SecondChildCreateTimeTAG: 2013-03-09T03:06:10Z
SecondChildVoteTAG: 0
SecondChildTAG: It is blurred on full screen
SecondChildUserIdTAG: 569767
SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-03-18T06:25:14Z
SecondChildVoteTAG: 0
FirstChildTAG: When I try to view in full screen it's very blurry. Larger fonts for the formulae would help.
FirstChildUserIdTAG: 1013930
FirstChildUserNameTAG: Allyssandra
FirstChildCreateTimeTAG: 2013-03-07T04:39:34Z
FirstChildVoteTAG: 3
SecondChildTAG: Check the slides out!
SecondChildUserIdTAG: 886662
SecondChildUserNameTAG: Darrell193
SecondChildCreateTimeTAG: 2013-03-09T03:07:07Z
SecondChildVoteTAG: 0
FirstChildTAG: You could download the slides of lec. 4.4 for a better use of the formulae
FirstChildUserIdTAG: 941908
FirstChildUserNameTAG: katecat
FirstChildCreateTimeTAG: 2013-03-07T10:29:08Z
FirstChildVoteTAG: 2
FirstChildTAG: Did You try to watch it in HD? It becomes way better))
FirstChildUserIdTAG: 197621
FirstChildUserNameTAG: quilombolo
FirstChildCreateTimeTAG: 2013-03-08T10:57:21Z
FirstChildVoteTAG: 1
IndexTAG: 1265
TitleTAG: Check Answer Option Disabled
In attempting to complete the assignments [Set Nos. 4-6]-of which is due 3/6/13 at twenty-three hundred hours, and thirty minutes post meridian time-at approximately nineteen hundred hours-that is, approximately four hundred hours of the earlier-the courseware system automatically disabled the check answer option, thus perpetuating, and further estopping a timely completion of assignments.
UserIdTAG: 7286
UserNameTAG: ptfrizz
CreateTimeTAG: 2013-03-07T01:10:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
01.18 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T01:18:06Z
FirstChildVoteTAG: 0
IndexTAG: 1266
TitleTAG: Decimals again
My answers were wrong because I rounded the figure and ommitted the decimals... 11% and 22%, totaling 33% against the 66% of the other two groups... of course 1% would be amiss... silly me....
UserIdTAG: 1104340
UserNameTAG: carloszfonseca
CreateTimeTAG: 2013-03-07T01:06:02Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1267
TitleTAG: I was still working and it closed :( It is only 22:05 here in Brazil...
I was going to get 100% I was studying hard for this section that is why I did not finish yesterday :((
UserIdTAG: 1051932
UserNameTAG: LARISSAMROCHA2013
CreateTimeTAG: 2013-03-07T01:05:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 5
FirstChildTAG: GMT!!!!!!!!!!!!!!!!!
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T01:06:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Because we are not on Brazil time. As clearly written in policies and Prof messages.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:07:08Z
FirstChildVoteTAG: 0
FirstChildTAG: Oww so it is pattern 23:30 GMT!! I thought it adapted acording to each country... it was my fault then...
FirstChildUserIdTAG: 1051932
FirstChildUserNameTAG: LARISSAMROCHA2013
FirstChildCreateTimeTAG: 2013-03-07T01:07:22Z
FirstChildVoteTAG: 0
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
01.17 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T01:17:06Z
FirstChildVoteTAG: 0
FirstChildTAG: Same here! So frustrating
FirstChildUserIdTAG: 1316751
FirstChildUserNameTAG: nataliagrdm
FirstChildCreateTimeTAG: 2013-03-07T03:06:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Not nearly as frustrating as seeing the forum fill up with posts from people who just don't get it.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T03:20:33Z
SecondChildVoteTAG: 0
IndexTAG: 1268
TitleTAG: exercises closed? why?
**I still have time until 23:30 ! I need to answer this problems, help me out**!!
UserIdTAG: 1260415
UserNameTAG: JESUSJCARBAJAL
CreateTimeTAG: 2013-03-07T01:05:52Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 4
FirstChildTAG: GMT!!!!!!!!!!!!!!!!
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T01:06:47Z
FirstChildVoteTAG: 1
SecondChildTAG: LOL. Something to look forward to every week.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T01:07:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Well for me it is 19:14 central time!
SecondChildUserIdTAG: 1260415
SecondChildUserNameTAG: JESUSJCARBAJAL
SecondChildCreateTimeTAG: 2013-03-07T01:15:09Z
SecondChildVoteTAG: 0
SecondChildTAG: > Well for me it is 19:14 central time!
So? That's not the time the course runs on. As you would have known if you had read the policy and the Prof's message.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T01:20:13Z
SecondChildVoteTAG: 0
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
01.16 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T01:16:31Z
FirstChildVoteTAG: 0
FirstChildTAG: ![enter image description here][1]
[1]: http://media.comicvine.com/uploads/11/110934/2891002-triple_facepalm_by_spottedheart98464-d3kuyp3.png
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T01:17:53Z
FirstChildVoteTAG: 2
FirstChildTAG: Haha, I didn't even think to check what GMT was, I figured being on EST it was some time a couple hours BEHIND me, turns out I was an idiot and it's very far AHEAD, sucks having a job and can only find time to do this stuff at night. Looks like I'll need to use a freebie for Problem Set 6.
FirstChildUserIdTAG: 408965
FirstChildUserNameTAG: stayrusty
FirstChildCreateTimeTAG: 2013-03-07T01:27:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Could I suggest you do it a day earlier then you can still work at night?
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T01:32:00Z
SecondChildVoteTAG: 0
IndexTAG: 1269
TitleTAG: Unable to submit
Hi. I did not get the option to submit my answers. Please advise.
UserIdTAG: 1001073
UserNameTAG: lrodz
CreateTimeTAG: 2013-03-07T01:05:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: My advice: Read the forum and the Course Info tab.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:06:17Z
FirstChildVoteTAG: 0
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
01.16 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T01:15:50Z
FirstChildVoteTAG: 0
FirstChildTAG: ![enter image description here][1]
[1]: http://upload.wikimedia.org/wikipedia/commons/thumb/3/3b/Paris_Tuileries_Garden_Facepalm_statue.jpg/300px-Paris_Tuileries_Garden_Facepalm_statue.jpg
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T01:19:09Z
FirstChildVoteTAG: 2
IndexTAG: 1270
TitleTAG: What I like about Stat2.1x...
I just thought I'd start a thread about the good things about this class. Aside from being able to access good education from almost anywhere (an overall hat's off to Edx.org there), I really like the way Dr. A explains things. I'm one that tends to glaze over when the Greek Alphabet letters start showing up! I really appreciate her way of demystifying the mathematics. Thanks!
UserIdTAG: 262065
UserNameTAG: rjb_ak
CreateTimeTAG: 2013-03-07T00:59:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I rather like the way exercise sets scale. The first set every week gets me over-confident, then by the time I am digging into the third one, it's 03:00, and I am completely caught up in the wonderful world of numbers, feverishly searching for that answer, like Drew Brees trying to find a hole in the defence.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T01:54:32Z
FirstChildVoteTAG: 0
IndexTAG: 1271
TitleTAG: Certificate
I didnt submit any problem from Pset3. So the score for it is 0.
Is there a chance to get a certificate?(other scores are fine 80-100)
UserIdTAG: 673683
UserNameTAG: klukva
CreateTimeTAG: 2013-03-07T00:54:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I'm sounding like a broken record. Have you read the Course Policy document? The grading and certificate criteria are clearly spelt out. You need 35%. So you can get the certificate for these section without too much difficulty.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:55:32Z
FirstChildVoteTAG: 0
SecondChildTAG: Thx a lot. I ve read about the grading system but two lowest scores are above zero(not exactly zero) and that scared me
SecondChildUserIdTAG: 673683
SecondChildUserNameTAG: klukva
SecondChildCreateTimeTAG: 2013-03-07T00:59:12Z
SecondChildVoteTAG: 0
FirstChildTAG: The minimum average mark to pass is 35%. The two lowest scores are dropped from the average. This is a Stats course - can you work it out?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T00:55:44Z
FirstChildVoteTAG: 0
SecondChildTAG: two lowest scores are a little above from zero.
SecondChildUserIdTAG: 673683
SecondChildUserNameTAG: klukva
SecondChildCreateTimeTAG: 2013-03-07T00:57:11Z
SecondChildVoteTAG: 0
SecondChildTAG: There are no lowest scores shown - the 'x' merely identifies which score will be dropped. By default the last two scores are selected until actual scores are filled in. Don't know why, it's just the way the software is set up.
It would make no sense whatosever to allow the lowest scores to be dropped but then set a minimum. One of the main reasons such a rule is in place is to help those who, for whatever reason, have missed an assignment. Such systems are common in many universities and even more so with distance learning courses as students will tend to have lives that sometimes take priority over studying.
Be grateful that the system is not as complex as the OU (Open University here in UK) which uses a system of substitutions rather than simply dropping scores. In that system you work out a first average (of coursework marks). Then, depending on the course rules, you substitute that average for the one or two lowest marks and calculate a new average.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T01:10:07Z
SecondChildVoteTAG: 0
IndexTAG: 1272
TitleTAG: exercices closed?
whats time?
23:55 where?
UserIdTAG: 569006
UserNameTAG: drhgdiaz
CreateTimeTAG: 2013-03-07T00:46:39Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
00.51 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T00:51:17Z
FirstChildVoteTAG: 0
FirstChildTAG: ![enter image description here][1]
[1]: http://images1.wikia.nocookie.net/__cb20120906010622/dragonball/images/9/90/Annoyed-facepalm-picard-l.png
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T01:20:55Z
FirstChildVoteTAG: 0
IndexTAG: 1273
TitleTAG: Problems submitting answers
I put in the answers, but it won't let me submit... and the time hasn't run out yet. I know my answers are correct!
UserIdTAG: 1078968
UserNameTAG: MissTori
CreateTimeTAG: 2013-03-07T00:46:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
00.50 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T00:50:46Z
FirstChildVoteTAG: 0
FirstChildTAG: > and the time hasn't run out yet.
It has. Do yourself a favour, read the Course Info.
> I know my answers are correct!
Maybe they are. But you should have submitted them on time.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:50:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Do us a favor and try not to be a jerk online. It doesn't do much to help promote the spirit of a free online course.
At least this person has shown passion for the material/course and is reaching out for help.
It's a pretty simple mistake to make, considering the menu which lists the exercises show a time when it's due without listing the timezone on the main page. One of the many logical assumptions would be that the time zone for submission is the one from which the course is being taught, Berkeley.
One thing that isn't an assumption, is that the passive-aggressiveness and condescending tone of your post will not help to foster intelligent conversation, but limits it in the future.
I hope you got your jollies off by implying the stupidity of multiple people online. You are definitely smarter than us.
SecondChildUserIdTAG: 1160419
SecondChildUserNameTAG: nicholasgalano
SecondChildCreateTimeTAG: 2013-03-07T02:40:32Z
SecondChildVoteTAG: 0
SecondChildTAG: > It's a pretty simple mistake to make
No, it's not. Part of doing any course is reading the relevant material. If you are not going to read the course policies, then don't complain.
>I hope you got your jollies off by implying the stupidity of multiple people online.
I imply nothing.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T07:59:12Z
SecondChildVoteTAG: 0
IndexTAG: 1274
TitleTAG: Problem with the
On problem 6, even though it´s still not the due time, it didn`t allow me to enter the answer. And it only shows: show answer. I had answered the other questions in the morning.
Thanks.
Evelyne Rodriguez
UserIdTAG: 1039433
UserNameTAG: Evelyne2013
CreateTimeTAG: 2013-03-07T00:46:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: Same thing happened with me. I was taken out and unable to complete the questions I was working on.
FirstChildUserIdTAG: 1322718
FirstChildUserNameTAG: Jovanovic
FirstChildCreateTimeTAG: 2013-03-07T00:47:04Z
FirstChildVoteTAG: 0
FirstChildTAG: What time is the deadline?
23.30 **GMT**
What time is it now?
00.49 **GMT** (on 7 March)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T00:49:38Z
FirstChildVoteTAG: 0
FirstChildTAG: And you have all read the messages from the Prof on the Course Info tab?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:50:32Z
FirstChildVoteTAG: 0
IndexTAG: 1275
TitleTAG: ok so here is 7.37pm eastern time ( USA)
What will be the GMT TIME.
UserIdTAG: 1181954
UserNameTAG: mywhitebear
CreateTimeTAG: 2013-03-07T00:38:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Google it.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T00:41:02Z
FirstChildVoteTAG: 0
FirstChildTAG: According to my clock here in the UK it is now 00.47 on the 7th.
To put it another way, an hour or so too late to submit the last problems.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T00:48:00Z
FirstChildVoteTAG: 0
IndexTAG: 1276
TitleTAG: Sorry about this general complain on the new policy but...
I have just read the new policy which starts from week 3. From now, each person have the possibility to see the correct answer ('show answer') just after having submitted and not anymore after the deadline of all graded exercises.
This may kill the certificate system of Edx, assuming that since we are in this course more than 47'000 students, not all of us are following strictly the Honor code. I am not even mentioning what we could have read on the forum sometimes that support this idea. I am not even mentioning people that are working in groups (which is probably a good thing though). Therefore this new policy does not support those who are really following the instructions. Honestly, can't people wait for one single week after deadline to see the correct answers?
This way of educating people in this course has become way too generous. I was and I am currently studying other courses on Edx where the passing grade and the graded exercises system level are uncomparable to the Stat2.1x course. Each Edx module is supposed to reflect not only what is taught to these prestigious universities but also a taste of the conditions under which students from there are performing their exams.
What does Prof A think about that?
Anyway sorry for this post, and good luck to all of us!
Z.
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-07T00:35:48Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: > I have just read the new policy which starts from week 3. From now, each person have the possibility to see the correct answer ('show answer') just after having submitted and not anymore after the deadline of all graded exercises.
Then you need to read it again. That's not exactly what it says.
This is only for Week 3, to assist in exam preparation. As it also says
>In Week 4 we will return to the usual “solutions posted after due date” system.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:40:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Zacharie,
Right now, the Edx platform is very good at teaching people who want to learn. As far as I'm concerned, that's enough.
The Edx platform is not very good at certification. There are numerous ways for users to game the system and to cheat (e.g. multiple accounts). You know what you are getting out of this course, and that should be enough.
The show answer button allows people to see what they have done wrong, and should improve learning and mastery in preparation for the exam. I actually think it would be a good (but far from necessary) idea to continue this policy for the remainder of the course, so students could understand what they got wrong before proceeding further. In short, improving the learning experience for the worthy (which includes most of us) is much more important than worrying about cheating opportunities for the unworthy.
FirstChildUserIdTAG: 174100
FirstChildUserNameTAG: markpolak
FirstChildCreateTimeTAG: 2013-03-07T01:00:10Z
FirstChildVoteTAG: 0
SecondChildTAG: Sorry I do not have time to develop my counter argument to your post Markpolak.
But just for your information, after the end PH module I participated to a survey conducted by EDx.
Some questions were about motivations to take a course. Of course we could check multiple answers,,, We will see the results of this in near future.
Honestly I really do not believe that 'most of us' are here for strictly only the desire to learn.
There could be desire to learn plus many other reasons. (Trust me I am on the Greek hero History course as well).
I am sorry but developing Edx as a system considering only for the desire to learn reason is not enough. Other systems already exist for that...
Improving the system considering All the factors will help EDx to show their seriousness and professionalism. It will attract more lecturer and more institutions and motivate them to spend a huge amount of time to prepare their courses.
I am looking forward to seeing more courses in the future. EDx is becoming more and more popular... EPFl etc.
Anyway, I am glad to see that this showing answer immediately after submission system was just for week 3.
Thx
Z.
SecondChildUserIdTAG: 830835
SecondChildUserNameTAG: Zacharie
SecondChildCreateTimeTAG: 2013-03-07T05:11:59Z
SecondChildVoteTAG: 0
IndexTAG: 1277
TitleTAG: Sorry about this general complain about the new policy but...
I have just read the new policy which starts from week 3.
From now, each person have the possibility to see the correct answer ('show answer') just after having submitted and not anymore after the deadline of all graded exercises.
This may kill the certificate system of Edx, assuming that since we are in this course more than 47'000 students, not all of us are following strictly the Honor code. I am not even mentioning what we could have read on the forum sometimes that support this idea. I am not even mentioning people that are working in groups (which is probably a good thing though). Therefore this new policy does not support those who are really following the instructions. Honestly, can't people wait for one single week after deadline to see the correct answers?
This way of educating people in this course has become way too generous. I was and I am currently studying other courses on Edx where the passing grade and the graded exercises system level are uncomparable to the Stat2.1x course.
Each Edx module is supposed to reflect not only what is taught to these prestigious universities but also a taste of the conditions under which students from there are performing their exams.
What does Prof A think about that?
Anyway sorry for this post, and good luck to all of us!
Z.
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-07T00:34:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You only need to post once. And as I said on your other post, go read it again. It does not say what you think it says.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:41:50Z
FirstChildVoteTAG: 0
IndexTAG: 1278
TitleTAG: I dont like this
The time frame, should be different, not how it is.
UserIdTAG: 1181954
UserNameTAG: mywhitebear
CreateTimeTAG: 2013-03-07T00:31:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: Well there you go.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T00:33:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Well no excuses next time. Put in great **big letters** at the top of the question pages. Not that that will help.
> The time frame, should be different, not how it is
A time has to be decided. And it is GMT. No matter what the time, someone will complain and miss the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:36:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Crap, I thought it was California time.
SecondChildUserIdTAG: 1078968
SecondChildUserNameTAG: MissTori
SecondChildCreateTimeTAG: 2013-03-07T00:47:37Z
SecondChildVoteTAG: 0
FirstChildTAG: This is getting silly.
I would like to use SMT. You know, standard martian time..
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T00:57:02Z
FirstChildVoteTAG: 0
SecondChildTAG: What we need is a Tardis. That would take care of all these problems.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T01:04:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Right on! A fellow Dr. Who connoisseur :-)
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-07T01:11:05Z
SecondChildVoteTAG: 0
FirstChildTAG: I believe it was The Rolling Stones who had a song explaining that "Time Waits for No One".
Thing is, there isn't too much work in the course, so it's a matter of planning ahead of time. I don't get back from work until 22:35 GMT, so it's not possible for me to do exercises on the due date. So I plan out my week to get them done at some point during the week (normally the day before).
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T02:01:16Z
FirstChildVoteTAG: 0
IndexTAG: 1279
TitleTAG: A problem
I was not able to submit the answers, ansd will not have an opportunity to do it later today. What can I do?
UserIdTAG: 258130
UserNameTAG: TKiriazova
CreateTimeTAG: 2013-03-07T00:31:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: Move on to week 3.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T00:32:08Z
FirstChildVoteTAG: 0
SecondChildTAG: I also don't have the submit button.
I tried adding Firefox and it also is missing the submit buttons.
SecondChildUserIdTAG: 967371
SecondChildUserNameTAG: rtgear
SecondChildCreateTimeTAG: 2013-03-07T00:58:33Z
SecondChildVoteTAG: 0
FirstChildTAG: Move on. The required pass mark is 35% and the two lowest marks are dropped anyway.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T00:32:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, move on. But first - go to the Course Info tab and read the Prof's messages. And read the documents she tells you to read. The ones you should have read on Day 1.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T01:05:15Z
FirstChildVoteTAG: 0
IndexTAG: 1280
TitleTAG: problem is closed
I entered an answer to exercise set 6 problem 2 and tried to check it but nothing happened. I got the message "problem is closed." What does that mean?
UserIdTAG: 1110758
UserNameTAG: jcu
CreateTimeTAG: 2013-03-07T00:30:03Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: It means just that. The deadline has passed.
Did you read the course policy? Have you read any of the messages from the Prof?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:31:28Z
FirstChildVoteTAG: 0
IndexTAG: 1281
TitleTAG: submission option
Does anybody else have problems with submitting answers? Submit/Save buttons are not available on my screen. It is the first time I encounter this problem.
UserIdTAG: 1146604
UserNameTAG: yunakohls1
CreateTimeTAG: 2013-03-07T00:29:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: If you check the discussion forum, you'll notice that you're not the only person to have this problem, and that the deadline has past. That's why you can't submit your answers.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T00:33:01Z
FirstChildVoteTAG: 0
FirstChildTAG: I too have made the mistake. Oh well...now I know.
FirstChildUserIdTAG: 1257990
FirstChildUserNameTAG: Crisyana
FirstChildCreateTimeTAG: 2013-03-07T02:07:24Z
FirstChildVoteTAG: 0
IndexTAG: 1282
TitleTAG: the time
is the time GMT?
UserIdTAG: 701620
UserNameTAG: kittoe
CreateTimeTAG: 2013-03-07T00:27:11Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: The deadline is 23:30 GMT, correct.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T00:31:14Z
FirstChildVoteTAG: 0
FirstChildTAG: idea: can you guys put a javascript countdown timer on the site, esp when it's almost the deadline? I have seen other Moocs do this.
I just started the class today, a few hours before the deadline, so was oblivious to GMT. Assumed EST or PST out of laziness.
Thanks!
FirstChildUserIdTAG: 162716
FirstChildUserNameTAG: nathanleiby
FirstChildCreateTimeTAG: 2013-03-07T00:47:03Z
FirstChildVoteTAG: 0
SecondChildTAG: Additionally, you might also simply add "GMT" after all timestamps.
"graded exercises due March 06 23:30"
->
"graded exercises due March 06 23:30 GMT"
SecondChildUserIdTAG: 162716
SecondChildUserNameTAG: nathanleiby
SecondChildCreateTimeTAG: 2013-03-07T00:48:01Z
SecondChildVoteTAG: 0
SecondChildTAG: The time is now clearly stated on the question pages.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T00:53:32Z
SecondChildVoteTAG: 0
IndexTAG: 1283
TitleTAG: quiz not working
unable to submit this assignment as well
UserIdTAG: 1160058
UserNameTAG: mtere
CreateTimeTAG: 2013-03-07T00:26:11Z
VoteTAG: 3
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: I believe you submit after the due date.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-07T00:30:32Z
FirstChildVoteTAG: 0
IndexTAG: 1284
TitleTAG: unable to submit this assignment- Ass#6
unable to submit this assignment. The check/save/submit options are not there.
UserIdTAG: 1252998
UserNameTAG: Kris942
CreateTimeTAG: 2013-03-07T00:25:12Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: I suggest you look at past posts, and also read the course policy and the Prof's message from last week.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:26:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Same here, unable to submit. I guess the dateline is over :(
SecondChildUserIdTAG: 1203339
SecondChildUserNameTAG: Anamile71
SecondChildCreateTimeTAG: 2013-03-07T00:45:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Have you read the Course Info page? If so, your question should be answered.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T00:54:05Z
SecondChildVoteTAG: 0
IndexTAG: 1285
TitleTAG: Submission button missing!!!
i cant give my answers without it! :(
UserIdTAG: 1262618
UserNameTAG: MelanieMbg
CreateTimeTAG: 2013-03-07T00:22:46Z
VoteTAG: 2
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: Of course not. Just like you can't get on a plane once it has taken off (unless you are Arnie or Bruce), you can't submit answers after the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:23:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Deadline is today at 11.30 pm. We did not miss it.
SecondChildUserIdTAG: 1146604
SecondChildUserNameTAG: yunakohls1
SecondChildCreateTimeTAG: 2013-03-07T00:30:19Z
SecondChildVoteTAG: 0
SecondChildTAG: GMT time, that explains a lot!
SecondChildUserIdTAG: 1146604
SecondChildUserNameTAG: yunakohls1
SecondChildCreateTimeTAG: 2013-03-07T00:36:04Z
SecondChildVoteTAG: 0
FirstChildTAG: > Deadline is today at 11.30 pm. We did not miss it.
Does no one here read official announcements? Or the course policy - which has been available from Day 1?
You cannot blame others for you own mistakes. You need to read the material on the website.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:33:03Z
FirstChildVoteTAG: 0
IndexTAG: 1286
TitleTAG: The future of online lectures
The lecture 5 introduction was groundbreaking in that you had superimposed some graphs in there. The video and their transcripts, and their corresponding PDF's are just perfect. But the HTML-files - in the lectures - are a bit noisy. They're kinda mashed.
UserIdTAG: 864596
UserNameTAG: Rubenjtj
CreateTimeTAG: 2013-03-07T00:16:23Z
VoteTAG: 1
CoursewareTAG: Section 5a: The normal curve (Lec 5.1 - 5.2) / Lec 5.1: Bell shaped curves; the standard normal curve
NumberOfReplyTAG: 0
IndexTAG: 1287
TitleTAG: why it said the problem is close
why it said that the problem is been close
UserIdTAG: 1181954
UserNameTAG: mywhitebear
CreateTimeTAG: 2013-03-07T00:15:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: Because the deadline just passed. It's over. Now you move on to Week 3.
As clearly explained in course info policy and a **very pointed message from the Prof on the course info page.**
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:20:22Z
FirstChildVoteTAG: 0
SecondChildTAG: they should change the date instead of wed, they should use Tuesday. next time that mean that midturn is tuesday and not wed like the page said
SecondChildUserIdTAG: 1181954
SecondChildUserNameTAG: mywhitebear
SecondChildCreateTimeTAG: 2013-03-07T00:35:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm not sure I understand. Are you saying it's Tuesday where you live? It's Wednesday GMT. It's your responsibility to translate GMT into your own timezone.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T00:39:46Z
SecondChildVoteTAG: 0
IndexTAG: 1288
TitleTAG: Let's now go over the definition of Greenwhich Mean Time (GMT), shall we?
This is more for myself than anyone else, seeing as this is the second time I'm having issues with submissions. (First time, I thought we were working on either local or California time. (yes, I read the guidelines in the beginning. No, details in there didn't become important or relevant until after the fact.) Now I know we are working on GMT.
So, GMT is not always the same as London time, seeing as they have some kind of daylight savings, just as we do here in the US (or the Eastern US, anyway). But as someone in the UK is now telling me, the 2 times are currently in synch.
For current GMT time, just do yourself a favor (note to self) and keep referring to this website: http://wwp.greenwichmeantime.com, because it is, as of this writing, now Thursday, 7 March 0:13:46 a.m(GMT + 0:00).
(edited)
UserIdTAG: 450628
UserNameTAG: ctr
CreateTimeTAG: 2013-03-07T00:14:29Z
VoteTAG: 4
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: Hey! Maybe in a future lesson, you can work in time zones and GMT into a chart! Wouldn't that be good! (variance, standard deviation, and how far off we are, how much distance from the average center in our perception and interpretation of time. just a thought.)
FirstChildUserIdTAG: 450628
FirstChildUserNameTAG: ctr
FirstChildCreateTimeTAG: 2013-03-07T00:17:05Z
FirstChildVoteTAG: 0
SecondChildTAG: "You are at most GMT plus or minus 10 hours."
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-07T00:24:54Z
SecondChildVoteTAG: 0
SecondChildTAG: GMT? Isn't that just everyone's local time? Grafton Mean Time, Georgia Mean Time, etc.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T00:27:50Z
SecondChildVoteTAG: 0
FirstChildTAG: *So, GMT is NOT, I repeat, NOT currently the same as London time*
Well, actually, it is at the moment as we have not yet moved to daylight saving time (British Summer Time - BST starts on 31 March in 2013).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-07T00:37:24Z
FirstChildVoteTAG: 0
SecondChildTAG: whoops. Still can't get it together! This class is just as much a lesson in world time zones as it is in statistics!
SecondChildUserIdTAG: 450628
SecondChildUserNameTAG: ctr
SecondChildCreateTimeTAG: 2013-03-07T00:42:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Use Google and find out what is GMT in your time zone. I live in Boston, Ma so it is about 6:00 p.m when GMT is 23:00.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-07T00:37:40Z
FirstChildVoteTAG: 0
IndexTAG: 1289
TitleTAG: Where to check the correct answers for assignments - for the ones that I got incorrect
Where to check the correct answers for assignments - for the ones that I got incorrect
UserIdTAG: 1109472
UserNameTAG: SushilKeswani
CreateTimeTAG: 2013-03-07T00:14:02Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Click the "Show Answer" button underneath the exercise.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-07T00:16:39Z
FirstChildVoteTAG: 0
FirstChildTAG: I got one of the homework questions wrong and also would like to have the correct answer - **or, more properly, the method to arrive at the correct answer** - shown. But where? When?
FirstChildUserIdTAG: 1081022
FirstChildUserNameTAG: Paul02035
FirstChildCreateTimeTAG: 2013-03-07T01:42:05Z
FirstChildVoteTAG: 0
IndexTAG: 1290
TitleTAG: Why did the graded exercises grey out although I haven't submitted answer yet?
Is this a bug or this is timed exercise timed out?
UserIdTAG: 860670
UserNameTAG: DeeZee
CreateTimeTAG: 2013-03-07T00:12:57Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: A bug? No, just yet another demonstration of people not reading the Course Info policy and, more importantly, not reading messages from the Prof.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:21:34Z
FirstChildVoteTAG: 0
FirstChildTAG: It seems we are all a bit confused about the GMT and how it translates to our perspective time zones because you are not the only one that had that problem today. I for one know now that I will be submitting my assignments before Wednesday’s deadline or I will run the risk of not having my answers graded.
FirstChildUserIdTAG: 1268534
FirstChildUserNameTAG: amdesigns
FirstChildCreateTimeTAG: 2013-03-07T00:52:51Z
FirstChildVoteTAG: 0
IndexTAG: 1291
TitleTAG: submissions cut off half hour early?
Is it me? Or did the submission time cut off half hour earlier? All my saved work didn't get submitted!
UserIdTAG: 1235093
UserNameTAG: Ifeg
CreateTimeTAG: 2013-03-07T00:12:23Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: So you should have submitted it on time. Saving doesn't submit. Check submits.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:22:01Z
FirstChildVoteTAG: 0
FirstChildTAG: No, I had a problem too. I was in the midst of completing exercise 5 and I hit the check button to submit my answers. When I clicked on the button I did not get a response. I continued to answer the questions and since it was close to the deadline I hit the check button to ensure those answers would be recorded but I got no response. I then went to exercise 6 and the check button was no longer an option. So, it seems that if you are in the system close to the deadline your answers may not be recorded.
FirstChildUserIdTAG: 1268534
FirstChildUserNameTAG: amdesigns
FirstChildCreateTimeTAG: 2013-03-07T00:32:46Z
FirstChildVoteTAG: 0
FirstChildTAG: Actually, it cut out $\sim$half an hour after the scheduled time. Around 23.59, not 23.30. GMT
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:38:04Z
FirstChildVoteTAG: 0
IndexTAG: 1292
TitleTAG: no check icon
I do not have a check icon in this section to see if i am correct or not.
UserIdTAG: 564178
UserNameTAG: pompaii
CreateTimeTAG: 2013-03-07T00:12:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: Correct. You just missed the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:22:15Z
FirstChildVoteTAG: 0
SecondChildTAG: how. its 7:25 est
SecondChildUserIdTAG: 564178
SecondChildUserNameTAG: pompaii
SecondChildCreateTimeTAG: 2013-03-07T00:26:42Z
SecondChildVoteTAG: 0
SecondChildTAG: i guess i missed the deadline too
SecondChildUserIdTAG: 1277018
SecondChildUserNameTAG: Gporpino
SecondChildCreateTimeTAG: 2013-03-07T00:28:13Z
SecondChildVoteTAG: 0
SecondChildTAG: the side bar states that the assignments are due by 23:30
SecondChildUserIdTAG: 564178
SecondChildUserNameTAG: pompaii
SecondChildCreateTimeTAG: 2013-03-07T00:29:19Z
SecondChildVoteTAG: 0
SecondChildTAG: 13.30 **GMT**
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-07T00:38:37Z
SecondChildVoteTAG: 0
FirstChildTAG: > how. its 7:25 est
Demonstrating that you have not read the course policy. Nor any of the messages posted by the Prof on the course info tab. You should.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:29:33Z
FirstChildVoteTAG: 0
IndexTAG: 1293
TitleTAG: The exercises
The exercises er wonderfully cunning. Now is it possible to put in several more exercises in the exercise section, and not only in the graded exercise sections?
UserIdTAG: 864596
UserNameTAG: Rubenjtj
CreateTimeTAG: 2013-03-07T00:07:40Z
VoteTAG: 7
CoursewareTAG: Practice For Exercise Set 8 / Reading and Practice For Exercise Set 8
NumberOfReplyTAG: 1
FirstChildTAG: I would like that also. Lots of exercises help me to understand what we're doing and when to do what. Especially not to do stupid things like keeping the interquartile range in standard units. (duh! *obvious* once I saw what I did wrong...)
Let me make lots of mistakes with practice exercises so I won't (hopefully!) make them during exams.
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-12T23:05:54Z
FirstChildVoteTAG: 1
IndexTAG: 1294
TitleTAG: submission issue
I cant submit event though it is only 19:00 est!
help
UserIdTAG: 1271736
UserNameTAG: sushigupta
CreateTimeTAG: 2013-03-07T00:06:59Z
VoteTAG: 6
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 9
FirstChildTAG: i cant submit either :(
FirstChildUserIdTAG: 900416
FirstChildUserNameTAG: atlightspeed
FirstChildCreateTimeTAG: 2013-03-07T00:09:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Neither can I. Where to check the answers for the submissions. The ones that I got wrong - where can I check the correct answers
SecondChildUserIdTAG: 1109472
SecondChildUserNameTAG: SushilKeswani
SecondChildCreateTimeTAG: 2013-03-07T00:13:04Z
SecondChildVoteTAG: 0
SecondChildTAG: I cant submit too. i tried already but cannot submit my answer please help!
SecondChildUserIdTAG: 1077280
SecondChildUserNameTAG: Mayoliza
SecondChildCreateTimeTAG: 2013-03-08T02:41:35Z
SecondChildVoteTAG: 0
FirstChildTAG: Me too ,but what time zone am I shooting for ? Is it est because I just thought about something and well berkley is sort of a little behind me ,so did I just miscalculate time zones ,ouch ....
FirstChildUserIdTAG: 20186
FirstChildUserNameTAG: vikashx1
FirstChildCreateTimeTAG: 2013-03-07T00:09:14Z
FirstChildVoteTAG: 0
FirstChildTAG: I am having the same problem...
FirstChildUserIdTAG: 885733
FirstChildUserNameTAG: Arie90435
FirstChildCreateTimeTAG: 2013-03-07T00:09:31Z
FirstChildVoteTAG: 0
FirstChildTAG: I am unable to submit my answers too! Something wrong is happening. This is a technical issue.
FirstChildUserIdTAG: 637514
FirstChildUserNameTAG: alfonso3
FirstChildCreateTimeTAG: 2013-03-07T00:09:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Its our fault ,we shouldve read the instructions "Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT)." and its actually the 7th haha http://www.timeanddate.com/library/abbreviations/timezones/eu/gmt.html so yeah its not a problem with the site ,it just scored already ,I guess the only thing to do is keep up and use this problem set as the drop score later on .
FirstChildUserIdTAG: 20186
FirstChildUserNameTAG: vikashx1
FirstChildCreateTimeTAG: 2013-03-07T00:12:36Z
FirstChildVoteTAG: 1
SecondChildTAG: So you mean the deadline was just a few minutes ago?
SecondChildUserIdTAG: 637514
SecondChildUserNameTAG: alfonso3
SecondChildCreateTimeTAG: 2013-03-07T00:14:39Z
SecondChildVoteTAG: 0
SecondChildTAG: No I dont think so I think it mightve been a little bit late actually but we did get enough time ,I guess I just have to keep up now ,and try not to miss any more of them ,but im sort of glad ,can you imagine if I missed the midterm or final because I didnt know the time zone ,yeah id kick myself .
SecondChildUserIdTAG: 20186
SecondChildUserNameTAG: vikashx1
SecondChildCreateTimeTAG: 2013-03-07T01:08:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Same problem here... seems there is a tech issue...
FirstChildUserIdTAG: 169571
FirstChildUserNameTAG: Rymz
FirstChildCreateTimeTAG: 2013-03-07T00:12:44Z
FirstChildVoteTAG: 0
FirstChildTAG: I win! You all owe me a bottle of scotch.
I wonder what part of the Prof's message on the Course Info page people didn't read.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:17:06Z
FirstChildVoteTAG: 1
SecondChildTAG: The part that said all of these exercises are due on Friday, Wednesday and Monday of each week not a half hour before the Wednesday deadline.
SecondChildUserIdTAG: 1268534
SecondChildUserNameTAG: amdesigns
SecondChildCreateTimeTAG: 2013-03-07T00:40:54Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm running out of fail pictures...
![enter image description here][1]
[1]: http://killmydaynow.com/wp-content/uploads/2010/06/FunnyPicturesofFailBlogPart1_11893/FunnyPicturesofFailBlog_22.jpg
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-07T01:45:39Z
FirstChildVoteTAG: 1
FirstChildTAG: In my courseware it shows "graded exercise due March 06 23:30". It should be some mistake. I don't want to lose the chance to get scores.
FirstChildUserIdTAG: 1081293
FirstChildUserNameTAG: GorGrigoryan
FirstChildCreateTimeTAG: 2013-03-07T07:31:35Z
FirstChildVoteTAG: 0
SecondChildTAG: March 6 23:30 GMT. The GMT is the important part of that sentence.
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-03-07T17:00:15Z
SecondChildVoteTAG: 0
IndexTAG: 1295
TitleTAG: Stat 2.2 and 2.3
Dr Adhikari mentioned in the first lecture that we should be seeing stat 2.2 and 2.3 (also from Cal Berkeley) sometime soon.
I was expecting 2.2 and 2.3 to be back to back with 2.1 (without much gap). Any ideas about those other courses?
UserIdTAG: 305272
UserNameTAG: shekharshan
CreateTimeTAG: 2013-03-07T00:00:51Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The Prof has responded several times to this. Just search the forum.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-07T00:15:59Z
FirstChildVoteTAG: 0
FirstChildTAG: For me the interesting question would be whether 2.2 and 2.3 would have entry requirements.
Would be interesting to see something like a pass grade of 35% for 2.1, but a requirement of 65% to enlist for 2.2, with something like 80% for 2.3. With eight legions signed up for 2.1, you would still have a significant number of people complete the entirety of the course, and avoid having people just do the first 3 weeks of exercises to pass the course.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T02:56:43Z
FirstChildVoteTAG: 1
SecondChildTAG: > For me the interesting question would be whether 2.2 and 2.3 would have entry requirements.
The Prof has said that passing 2.1x is not a requirement, but you *are* assumed to have the knowledge of 2.1x.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T11:06:26Z
SecondChildVoteTAG: 0
IndexTAG: 1296
TitleTAG: Doing week1 exercises
I've started a week late because I had another final exam to deal with in real life :S so I watched the lectures of week one but skipped the exercises. still it's painful to look at the progress tab and see week one completely blank. do I get anything if I solve the problems or is it far gone now?
UserIdTAG: 533740
UserNameTAG: Amadeus86
CreateTimeTAG: 2013-03-06T23:53:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hi im new here and i dont know where to start., can anybody help me? what should i do first? thank you so much. :) it would be a big help for me.
FirstChildUserIdTAG: 1377174
FirstChildUserNameTAG: Cpadolina
FirstChildCreateTimeTAG: 2013-03-06T23:55:51Z
FirstChildVoteTAG: 0
FirstChildTAG: It's too late.
Since you're new to the class, it would be a good idea to learn how to search the discussion forum to see if your questions have already been asked and answered. Your question in particular has been asked many, many, many times already.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-06T23:56:19Z
FirstChildVoteTAG: 0
SecondChildTAG: so your saying that im late for anything in this course?
SecondChildUserIdTAG: 1377174
SecondChildUserNameTAG: Cpadolina
SecondChildCreateTimeTAG: 2013-03-06T23:58:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm sorry I didn't know that :) will search next time
Cpadolina you're not late but you'll have to work hard to catch up, and not miss any assignments from now on :)
SecondChildUserIdTAG: 533740
SecondChildUserNameTAG: Amadeus86
SecondChildCreateTimeTAG: 2013-03-07T00:01:33Z
SecondChildVoteTAG: 0
IndexTAG: 1297
TitleTAG: Number of Submissions per point
It looks like for each problem that is worth 2 points, there are two submissions, except for Problem 6, which was the most challenging on this bunch. Was it intentional? My entire score got affected because I typed the wrong number, although I solved all other problems correctly.
UserIdTAG: 870633
UserNameTAG: ekoustova
CreateTimeTAG: 2013-03-06T23:13:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 0
IndexTAG: 1298
TitleTAG: Unable to download video
Hi. I am unable to download Lecture 5.4. The download option seems to be missing. Is anybody else facing the same problem? Slides are not a problem, but the download option is missing.
UserIdTAG: 1321975
UserNameTAG: AdityaVerma
CreateTimeTAG: 2013-03-06T23:09:50Z
VoteTAG: 24
CoursewareTAG: Section 5b: The normal curve (Lec 5.3 - 5.4) / Lec 5.4: Not all histograms are bell shaped; Chebychev revisited
NumberOfReplyTAG: 3
FirstChildTAG: Yeah, there's no download link for that Lecture.
We'll just have to wait a bit until they add it I suppose. Or just watch on Youtube ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-06T23:30:38Z
FirstChildVoteTAG: 1
SecondChildTAG: No download link for lecture...please check!!!
SecondChildUserIdTAG: 1063817
SecondChildUserNameTAG: PriyankaChaman
SecondChildCreateTimeTAG: 2013-03-07T04:34:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Hello
I have a suggestion for the download links.
If the team provide us a table of download links in the course info page, we wont have problem to find the links and download videos.
Thank you for helping us enjoying statistic science,
FirstChildUserIdTAG: 420339
FirstChildUserNameTAG: AliJenabi
FirstChildCreateTimeTAG: 2013-03-07T10:48:09Z
FirstChildVoteTAG: 1
FirstChildTAG: Download link:
http://r6---sn-4pgnuhxqp5-jb3e.c.youtube.com/videoplayback?sparams=cp%2Cid%2Cip%2Cipbits%2Citag%2Cratebypass%2Csource%2Cupn%2Cexpire&source=youtube&expire=1363069208&ipbits=8&id=a663d8f171396fb1&mv=m&newshard=yes&upn=wLeDZmnHujM&cp=U0hVSFBRV19FUkNONV9IS0FDOk9PTWR1UlBoUmZr&key=yt1&ip=111.95.112.185&fexp=902543%2C920704%2C912806%2C902000%2C919512%2C929901%2C913605%2C925006%2C906938%2C931202%2C931401%2C908529%2C930803%2C920201%2C930101%2C930603%2C906834&ms=au&mt=1363043414&ratebypass=yes&itag=22&sver=3&signature=6AF1E8434951E938B1BFDF83ADC80A85B237D988.B2926736F4068F28F5CD6062399B945841C331A8&title=BERSTAT2SP13-G050400_100
FirstChildUserIdTAG: 985199
FirstChildUserNameTAG: dechchi
FirstChildCreateTimeTAG: 2013-03-11T23:52:41Z
FirstChildVoteTAG: 1
IndexTAG: 1299
TitleTAG: For those struggling with Set 6, problem 6
1. Watch lecture 4.3 from 4:45-8:40 where she describes how to determine this
2. Keep watching lecture 4.3 from 8:40-11:30 where she talks about one-tailed versus two-tailed
3. You must round your calculated answer before it will match one of the options given (at least I had to, assuming I did everything correctly)
I'm REALLY hoping this post will be considered helpful without giving too much away...
UserIdTAG: 673325
UserNameTAG: coutlay
CreateTimeTAG: 2013-03-06T22:51:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: I disagree with the "correct" answer: it corresponds to the percentage outside the range defined by the mean +/- 6 sigma. "Above" the mean is only half of that. The question was about "above" the mean not "outside the range"!
FirstChildUserIdTAG: 1165218
FirstChildUserNameTAG: mdynca
FirstChildCreateTimeTAG: 2013-03-06T23:28:11Z
FirstChildVoteTAG: 0
SecondChildTAG: In the lecture, Prof A. clearly states that you cannot assume that half of the value lies above the range and half the value lies below the range. This is because you cannot assume that the distribution is symmetrical. Therefore you can say that the value above the range is the value given by Ch. Inequality. That's as precise as you can get.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T23:35:40Z
SecondChildVoteTAG: 0
SecondChildTAG: But of course, what would the Prof know?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T23:44:25Z
SecondChildVoteTAG: 0
SecondChildTAG: You're so snarky :)
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T23:46:07Z
SecondChildVoteTAG: 0
SecondChildTAG: So I've been told. Once or twice.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-07T00:07:17Z
SecondChildVoteTAG: 0
SecondChildTAG: The official "at most" answer is a tiny bit above the calculated "at most answer." If you're at the "at most" mark, you cannot go further.
Doesn't that therefore make e) the only 100% safe answer? If not why not?
If I calculate a Ch. bound of, say, 1.76 and there are two answer choices of 1.75 and 1.8, which is most correct?
SecondChildUserIdTAG: 11318
SecondChildUserNameTAG: JMcGlynn
SecondChildCreateTimeTAG: 2013-03-12T04:24:22Z
SecondChildVoteTAG: 0
IndexTAG: 1300
TitleTAG: Problem 5
If you realice the problem 5 with 20 house, the excercise es false...
(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2500,2500,2500)/20=375.85
Is posible more than the 20%.
UserIdTAG: 1304942
UserNameTAG: MichaelZam
CreateTimeTAG: 2013-03-06T22:47:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: The problem states that the average monthly rent paid for apartments in a city is 500 dollars.
The average of your dataset is $375.85. Your dataset doesn't follow the guidelines of the problem.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-06T22:53:21Z
FirstChildVoteTAG: 0
IndexTAG: 1301
TitleTAG: Lecture 5.4 not downloadable
link missing...
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-03-06T22:44:32Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: https://www.youtube.com/watch?v=pmPY8XE5b7E&feature=player_embedded
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-06T23:11:55Z
FirstChildVoteTAG: 0
SecondChildTAG: This section can't be downloaded..
SecondChildUserIdTAG: 1274748
SecondChildUserNameTAG: kusumawati
SecondChildCreateTimeTAG: 2013-03-07T00:10:06Z
SecondChildVoteTAG: 0
SecondChildTAG: You can use programs to download Youtube videos. I think it may be in somewhat bad tone to specify any, but worth googling.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-07T03:01:02Z
SecondChildVoteTAG: 0
IndexTAG: 1302
TitleTAG: I'm three years old!
What a coincident!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-06T22:40:41Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 1
FirstChildTAG: Cool! :-)
FirstChildUserIdTAG: 992070
FirstChildUserNameTAG: MihaelaB
FirstChildCreateTimeTAG: 2013-03-06T23:08:20Z
FirstChildVoteTAG: 0
IndexTAG: 1303
TitleTAG: Off piste posting
The lower quartile of the weights is 90 pounds and the median is 120 pounds...
what are the advantages of the metric system, as opposed to the imperial?
UserIdTAG: 864596
UserNameTAG: Rubenjtj
CreateTimeTAG: 2013-03-06T22:39:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: imperial is a historical rudiment, use metric for your own calculations.
FirstChildUserIdTAG: 255838
FirstChildUserNameTAG: EngineerHrenov
FirstChildCreateTimeTAG: 2013-03-06T22:49:30Z
FirstChildVoteTAG: 0
FirstChildTAG: on the other hand, an advantage of non-metric systems is that they embed the concept of a non decimal base from an early age :)
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-07T09:20:17Z
FirstChildVoteTAG: 0
IndexTAG: 1304
TitleTAG: Problem 3 - Explanation wanted
Now as this week is over can anybody explain to me why my answer "The SD of List A is less than the SD of List B. " is incorrect?
UserIdTAG: 255838
UserNameTAG: EngineerHrenov
CreateTimeTAG: 2013-03-06T22:35:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Hope my answer will help you.
What is important is that the 5 numbers that are added in list B are equal to the average: 100.
So what happens from here to calculate the SD.
1) To get the deviation you substract the average from value.. 100 - 100 : 0
2) In the next step you would square the deviations. 0^2 : 0
3) Now imagine the lists of squared deviations for A & B next to each other. Picture the last 5 squared deviations being 0. Both lists will add up to the same amount. But B will be divided by a greater number of entries.
4) In this step you would root the mean square of deviations from average. But this step wasn't necessary to answer the question.
FirstChildUserIdTAG: 1240204
FirstChildUserNameTAG: jpnijman
FirstChildCreateTimeTAG: 2013-03-06T23:05:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks! That was easy =) could solve it myself...
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-06T23:27:19Z
SecondChildVoteTAG: 0
SecondChildTAG: > 1) To get the deviation you **subtract the average** from value.. 100 - 100
But when you add five more entries to list A, shouldn't list B average would also increased giving a different value compares to list A average?
This new average or list B thus would have different deviations from the average of entries from list A's although the first 25 entries were the same.
SecondChildUserIdTAG: 1208879
SecondChildUserNameTAG: deqalb
SecondChildCreateTimeTAG: 2013-03-07T07:34:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Maybe you misread the question. List A & B are the same in the first 25 values, so those first 25 values have an average of 100. Adding 5 values to list B of 100 won't change that average. The 2 lists will have the same deviations for the first 25 values, except list B will have 5 deviations of 0 because 100 - 100 = 0. If you have trouble seeing this in writing try it with two short lists.
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-03-07T08:06:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Ah, yes. Silly me. From the information give, the sum of List A would be 2500 and the sum of list B would be 2500 + 5(100)= 3000 but with 30 entries, List B average = 3000/30 = 100, still the same! and so the SD would still be the same for the first list A entries and 0 for the new 5 entries. I had see it now, thanks!
SecondChildUserIdTAG: 1208879
SecondChildUserNameTAG: deqalb
SecondChildCreateTimeTAG: 2013-03-08T22:47:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Week 2 Problems are open for 12 more minutes at the time of my post. The week isn't over yet.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-06T23:18:42Z
FirstChildVoteTAG: 0
SecondChildTAG: sorry about that...
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-06T23:27:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Week 2 problems are open for 5.5 more hours since the due time is March 6th 23:30 (11:30 pm EST).
SecondChildUserIdTAG: 305272
SecondChildUserNameTAG: shekharshan
SecondChildCreateTimeTAG: 2013-03-06T23:58:40Z
SecondChildVoteTAG: 0
SecondChildTAG: actually I mis-spoke. It is 11:30 pm GMT. I didn't realize that.
SecondChildUserIdTAG: 305272
SecondChildUserNameTAG: shekharshan
SecondChildCreateTimeTAG: 2013-03-07T00:04:35Z
SecondChildVoteTAG: 0
IndexTAG: 1305
TitleTAG: Interesting questions
I found the questions to be interesting, made you analyze the material and go back to the lessons sometimes. I believe they were all phrased properly. I could not read the course material until 2 days ago due to personal matters and it has been an uphill battle getting the answers on time. Congratulations to the professors for doing a very good job, and thank you.
UserIdTAG: 902684
UserNameTAG: DonCigarro
CreateTimeTAG: 2013-03-06T22:33:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 0
IndexTAG: 1306
TitleTAG: Waiting for the next course of statistics
dear professor
I m really thankful of you, because of this perfect course and how you are teaching us. I m following the lessons and waiting for the next courses of statistics enthusiastically.
UserIdTAG: 1259656
UserNameTAG: tarannomkhak
CreateTimeTAG: 2013-03-06T22:28:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1307
TitleTAG: Problème 2
I ve tried several Time, but i cant grade thé final Check. Why
UserIdTAG: 788840
UserNameTAG: Venica
CreateTimeTAG: 2013-03-06T22:02:45Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Could be a browser error.
Please first try clearing your browser cache and cookies:
http://www.wikihow.com/Clear-Your-Browser's-Cache
Turning off any browser addons is also recommended.
If using Internet Explorer, set your security level to default:
http://windows.microsoft.com/en-us/windows-vista/Change-Internet-Explorer-Privacy-settings
If using Firefox, try using Firefox (Safe Mode). You can find this option on your Windows start menu, go to All Programs, then Mozilla Firefox and load Firefox (Safe Mode) from there.
Should the problems persist, please consider attempting to access the website using an alternative (free) browser:
http://www.firefox.com
http://www.google.com/chrome
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-06T22:13:35Z
FirstChildVoteTAG: 0
FirstChildTAG: Might be too close to the start of Week 3, which is already up in Courseware. The shutout for homework exercises seems to happen a bit sooner than the new week's session.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-06T22:38:34Z
FirstChildVoteTAG: 0
IndexTAG: 1308
TitleTAG: stat 2.1x
I'm having fun!!!
UserIdTAG: 812256
UserNameTAG: banwo
CreateTimeTAG: 2013-03-06T21:31:43Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1309
TitleTAG: Week 3
Where are week 3 lectures and Exercise Sets?
UserIdTAG: 989925
UserNameTAG: CassandraB
CreateTimeTAG: 2013-03-06T21:28:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Sigh. So it appears every week we will have multiple posts asking this.
They will be where every other lecture is. If they are not there, they haven't been released yet.
Two hours until GMT deadline. Oh joy.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:36:53Z
FirstChildVoteTAG: 0
SecondChildTAG: oh and can i have the answers before the cut off so i can see what i did wrong :)
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-03-06T21:47:15Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL :-) First video and problem in the next section should be about Gmt :-)
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-06T22:03:48Z
SecondChildVoteTAG: 0
FirstChildTAG: Week 3 material was just released.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-06T22:05:40Z
FirstChildVoteTAG: 1
SecondChildTAG: Why didn't you start a new post to announce this? Falling down on the job merhutchin!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T22:09:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Oops, sorry. I should have posted this in the Week 1/Exercise 1 section, like everyone else does :)
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T22:10:30Z
SecondChildVoteTAG: 0
SecondChildTAG: We could both post a new thread. Maybe one in every forum?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T22:10:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Brilliant! Be sure to blame the professor for not making it more obvious to us.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T22:20:20Z
SecondChildVoteTAG: 0
IndexTAG: 1310
TitleTAG: I need to tell everyone I know that they have at most 3 heads
I need to tell everyone I know that they have at most 3 heads.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-06T21:04:30Z
VoteTAG: 0
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3.5: Markov’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: Surely some people can have 0 heads ( properly working) , so the low bound is 0 heads, the dataset becoming 0,1,2,3. Median is then just the 1 head, which sounds about right.
FirstChildUserIdTAG: 902212
FirstChildUserNameTAG: trigeor
FirstChildCreateTimeTAG: 2013-03-06T21:27:30Z
FirstChildVoteTAG: 3
SecondChildTAG: But what's the mode?
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T22:05:58Z
SecondChildVoteTAG: 0
SecondChildTAG: It's a tetramodal distribution :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-06T23:20:23Z
SecondChildVoteTAG: 0
FirstChildTAG: The other one is to think of something 3 in Total Recall - that would also jog the brain but would still be true in Mars as per the movie
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-09T13:43:35Z
FirstChildVoteTAG: 0
IndexTAG: 1311
TitleTAG: Can you find your name in Students directory
I went through students directory and I could not find my name in my country. Is that ok, can you find your name in student directory.Answer pls.
Thanks.
UserIdTAG: 1202387
UserNameTAG: Danny1412
CreateTimeTAG: 2013-03-06T21:04:20Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 5
FirstChildTAG: Couldn't find mine either. :-(
FirstChildUserIdTAG: 989925
FirstChildUserNameTAG: CassandraB
FirstChildCreateTimeTAG: 2013-03-06T21:25:42Z
FirstChildVoteTAG: 0
SecondChildTAG: where can you find the students directory???
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-06T21:27:57Z
SecondChildVoteTAG: 0
SecondChildTAG: go to wiki section and scroll...
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-06T21:43:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Me neither, could it be that I didn't start the course the first week?
FirstChildUserIdTAG: 1328997
FirstChildUserNameTAG: BeatrizA
FirstChildCreateTimeTAG: 2013-03-06T21:31:33Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you put your name in the directory? It is up to you to do, it is not an automatic thing.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:35:16Z
FirstChildVoteTAG: 2
FirstChildTAG: I think that no one can`t find they name because of programe. Program does not show us our names. I thought it was just me..
SusanAust I think it is an automatic thing, but I`ll chek it anyway
FirstChildUserIdTAG: 1202387
FirstChildUserNameTAG: Danny1412
FirstChildCreateTimeTAG: 2013-03-06T21:41:53Z
FirstChildVoteTAG: 1
SecondChildTAG: No, Danny. You need to add yourself to the list.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T21:51:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, SusanAust you are right again :) as you were many times before..
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-06T21:55:58Z
SecondChildVoteTAG: 0
FirstChildTAG: I just found the list. The reason you cannot find your names is that you simply need to EDIT the list and add your names yourselves
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-06T21:48:45Z
FirstChildVoteTAG: 2
IndexTAG: 1312
TitleTAG: I'm lost. (Lecture 4.3)
I was following along pretty well through lecture 4.2, pulling an A-level grade in all of the exercises so far, but 5 minutes into lecture 4.3 I was completely lost. I've watched it three times now and have no idea what is going on.
On Exercise Set 6, I got the 0 on the first three questions, and perfect on the last three.
Was there a big leap there that I missed? Am I going to be able to keep going or if I am lost now will I just keep getting more lost?
UserIdTAG: 1281619
UserNameTAG: sfc17
CreateTimeTAG: 2013-03-06T21:03:02Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: When the exercise answers are provided, work through them.
If you got 47% (the last 3 questions being right), then that is keeping you above 35% for that exercise set. If the earlier ones were as good or better, then don't worry - just take your time and have learning sessions in small chunks (not 5 hours at a time but 1.5 hours at most is probably better).
The videos can be paused and "re-wound" a little if you want to go over a particular point, pausing to allow it to "sink in".
Problem 2 in Exercise Set is just a matter of systematically working through the steps of calculating the SD, less a matter of any flight of understanding.
Enjoy!
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-03-06T22:09:35Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks. The overall grade is still OK, it's the lack of understanding that concerns me. The point is not only to pass but to gain knowledge.
I have re-watched the lecture videos, pausing, taking notes, etc. but 4.3 might as well be in a language I don't speak/read.
Now that the exercise answers have been revealed I will definitely go back and work through them. (Exercise 2, which I thought I had done easily following along the steps that were shown and discussed multiple times, has finally revealed itself to me. I was missing a step which I have now corrected.) Frustrating!
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-03-07T17:08:04Z
SecondChildVoteTAG: 0
IndexTAG: 1313
TitleTAG: What is the worth of the certificate gained upon successful completion?
The certificate is not just a piece of meaningless paper. It is an affirmation of our efforts to understand a topic that few have bothered to master. Understanding statistics is vital for the appreciation of the worth of data. Whether we are any kind of scientist or anyone trying to make an intelligent decision, knowing the value of statistics allows us to appreciate the value of conclusions drawn from raw data. For example, the recent "demonstration" of the Higgs boson was really just an appreciation that phenomena were observed at a level that would be best statistically explained by its decay.
UserIdTAG: 769852
UserNameTAG: MRArthurDent
CreateTimeTAG: 2013-03-06T20:53:41Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: > It is an affirmation of our efforts
Yes, but to some it is far far more. Which is why cheating happens.
The certificate might not be as important as a towel, but it does have meaning. It just depends on the person.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:34:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Gosh, I am having fun just looking under my "Progress" tab. (Hope I am not jinxing myself...) The certificate will be the icing on the cake!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-06T22:40:24Z
FirstChildVoteTAG: 1
FirstChildTAG: You could also make your own certificate at [www.accredible.com][1] (the idea is you prove the credibility of your learning by uploading proof of your work & expertise).
[1]: http://www.accredible.com
FirstChildUserIdTAG: 1452386
FirstChildUserNameTAG: dking
FirstChildCreateTimeTAG: 2013-03-20T02:43:04Z
FirstChildVoteTAG: 0
IndexTAG: 1314
TitleTAG: satisfy
very interesting class this week,but there are things to study for me,hope we get the answers as soon as possible to see our mistakes.
UserIdTAG: 1093938
UserNameTAG: Douna
CreateTimeTAG: 2013-03-06T20:49:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: As it tells you in the course policy, answers are released after the deadline. Just click on the Show Answer button.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:32:31Z
FirstChildVoteTAG: 0
IndexTAG: 1315
TitleTAG: edx thanks muchos muchos
i am preparing for my masters for public health later in the year and will be studying biostatistics...pretty sure what i am learning hear will help me out....
UserIdTAG: 1033614
UserNameTAG: neo8701
CreateTimeTAG: 2013-03-06T20:47:02Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi Neo,
You might be aware of this but I saw there are one or more biostat courses coming up on coursera.org. Maybe something that matches your interest.
Cheers,
Joris
FirstChildUserIdTAG: 1240204
FirstChildUserNameTAG: jpnijman
FirstChildCreateTimeTAG: 2013-03-06T21:45:28Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks for that info joris...i will check it asap.need all the prep i can.i hope the experience you gaining here is invaluable..
SecondChildUserIdTAG: 1033614
SecondChildUserNameTAG: neo8701
SecondChildCreateTimeTAG: 2013-03-06T22:36:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Absolutely! I have a similar motivation as you do, on the one hand I'm following courses as preparation for a masters on the other hand I'm following courses pure out of interest. A healthy appetite to expand my knowledge ;) I really enjoy how these courses are set up.
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-03-06T22:42:29Z
SecondChildVoteTAG: 0
IndexTAG: 1316
TitleTAG: Short Shrift
Hi. Maybe it's just me, but on this subject of standard deviation and variance, I feel like this subject is getting short shrift here. It's not clear to me exactly how much to go over, and since my time is limited, what to skip on this page:
http://statistics.berkeley.edu/~stark/SticiGui/Text/location.htm
Maybe I've become accustomed to our professor's very clear, straightforward teaching. But when an entire subject is then given over to an online textbook and some lectures given from another class, given by another teacher with another style, in the past, apparently not originally intended for students of this course, well now you've lost me.
I've turned the videos on a few times and read some paragraph that I was supposed to read. ("only 1 paragraph!" Great! But which paragraph are you referring to? The graph consisting of one declarative sentence followed by 3 or more questions?)
I'm trying to zero in on what is being asked of ME, based on THIS CLASS. It's not like I want to cut corners by not reading. It's just that I have a family to pay attention to most times, so I want to be clear about getting in, consuming the information, doing what is required of me, and getting out. Nice, clear, and clean. So far, my time on this course has been great. Time well spent. But now we hit variance and THIS, in my uninformed opinion is CRUCIAL and KEY information. If I don't have the clear presentation by Madam Professor on the subject (sorry. your name isn't coming immediately to mind in the moment. You know who you are, however.), I feel that this key subject has been given short shrift. The burden of raising the level/bar of teaching to that which seems so normal and clear by both the teacher and the students is that you GREATLY MISS it, when it is taken away.
Also, it doesn't help that the other professor's lectures in the online textbook are being tuned out by the students. He asks his audience questions. They don't respond and leave him to answer his own questions. I feel the overwhelming urge to a) yell at the students and b) tell the professor to move on because **I** am trying to listen, understand, and respond. I understand that you are not responsible for my mental noise. But just try to consider all of this when putting lessons together. The use of silence/pause by Madam Professor for this course is GOLDEN. She is imagining us thinking and responding to her. And she is as close to right as can reasonably be when taking into account that there is 40k students listening in.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-06T20:39:46Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: The textbook lectures are not our lectures, they are the real lectures from a f2f course. So student behaviour there is the behaviour of just about any student sitting in front of a lecturer. They do perfect imitations of stunned mullets.
Watch them if you want to, but the lectures we worry about are the ones on this site.
>sorry. your name isn't coming immediately to mind in the moment.
LOL. You could have taken a few seconds to look it up. But as you don't know your own name, we can't expect too much.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:10:47Z
FirstChildVoteTAG: 2
SecondChildTAG: what helpful snark
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-03-06T22:29:34Z
SecondChildVoteTAG: 0
FirstChildTAG: I think this person is missing the fact that there are lectures on SD on here. Just pay attention to all the videos listed at the top, side by side, for any given lesson. I know I would forget to look back at the top too, at the end of the lecture. It's just a UX issue.
FirstChildUserIdTAG: 450628
FirstChildUserNameTAG: ctr
FirstChildCreateTimeTAG: 2013-03-06T21:40:13Z
FirstChildVoteTAG: 0
IndexTAG: 1317
TitleTAG: Week 3
When do the lectures get posted for each week?
UserIdTAG: 220333
UserNameTAG: jeya
CreateTimeTAG: 2013-03-06T20:10:01Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Well, I think today at night. =D
FirstChildUserIdTAG: 1137654
FirstChildUserNameTAG: Anita10
FirstChildCreateTimeTAG: 2013-03-06T20:19:34Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Jeya and Anita10
For India, GMT+5:30hours, is the time. So by our time, second week finishes on
7 March 2013, 5am.
So, any time after that schedule for week 3 would be posted.
FirstChildUserIdTAG: 1212171
FirstChildUserNameTAG: RAJAT86
FirstChildCreateTimeTAG: 2013-03-06T21:14:54Z
FirstChildVoteTAG: 0
IndexTAG: 1318
TitleTAG: The sound of the video is quite low
Maybe the sound of the video could be increased? Thanks!
UserIdTAG: 743321
UserNameTAG: Pa_CR
CreateTimeTAG: 2013-03-06T20:06:05Z
VoteTAG: 0
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.2: The average: calculation and basic properties
NumberOfReplyTAG: 3
FirstChildTAG: I agree. I have to wear headphones most times.
FirstChildUserIdTAG: 989925
FirstChildUserNameTAG: CassandraB
FirstChildCreateTimeTAG: 2013-03-06T21:32:18Z
FirstChildVoteTAG: 0
FirstChildTAG: What volume controls do you have on your computer?
I think you can also turn the volume up on the video itself - hold Ctrl key and the central wheel on your mouse to increase or reduce volume.
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-03-06T22:16:42Z
FirstChildVoteTAG: 0
FirstChildTAG: The videos can be relatively inconsistent in volume. This week I was trying to balance the sound on one monitor with the lecture with the Redskins game on another, and it just got so frustrating I had to make a decision.
For the record, Prof A. is 1-0 against the Redskins.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-07T03:18:56Z
FirstChildVoteTAG: 0
IndexTAG: 1319
TitleTAG: Don't understand Problem 7
>As part of a fund raising campaign, the 12 members of the governing board of an organization pledge to raise 100,000 dollars.
What does that mean? The company is working together to make 100,000 dollars, Or each individual pledges to raise 100,000 dollars?
> In the first month of the campaign, the average amount raised by the 12 board members is $5,200. How much more must they raise, on average, so that they can keep their pledge?
Does each individual need to raise on average 94,800, or do they combined need to raise that much?
UserIdTAG: 484877
UserNameTAG: Andre97
CreateTimeTAG: 2013-03-06T20:04:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: 12 members are working together to raise a total of $100,000
FirstChildUserIdTAG: 893938
FirstChildUserNameTAG: mdeebold
FirstChildCreateTimeTAG: 2013-03-06T20:39:36Z
FirstChildVoteTAG: 0
SecondChildTAG: I got that wrong and I couldn't believe it....
I understood that they were trying to raise a total of 100k but since the senerio didn't state a time frame that they were working with it made calculation difficult...
Further I took the 5200 / 12 got 433.33 which was the average of what they raised and I was still considered wrong... ahhh
SecondChildUserIdTAG: 1150175
SecondChildUserNameTAG: cassx
SecondChildCreateTimeTAG: 2013-03-06T22:57:11Z
SecondChildVoteTAG: 0
IndexTAG: 1320
TitleTAG: Mid Term will be released on March 12th 11:30 GMT.....?????(Help Faculty)
Since MidTerm is on 13th March as mentioned so will it be released on
March 12th 11:30 GMT
or
March 13th 11:30 GMT
or
Something Else...
Regards
UserIdTAG: 303485
UserNameTAG: iparitosh
CreateTimeTAG: 2013-03-06T20:03:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Search the forum for the Profs reply to various other posts about the test.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T20:45:32Z
FirstChildVoteTAG: 1
SecondChildTAG: can you please give me some links for that? I am not sure I can find what you are talking about.
thanks
Antonis
SecondChildUserIdTAG: 1207733
SecondChildUserNameTAG: AntoniusBlock
SecondChildCreateTimeTAG: 2013-03-06T21:55:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Antonis, click on "Discussion" in the upper tool bar. Then you should click on the magnifying glass icon next to the "Show All Discussion" heading. This lets you search the discussion forum. Search for "midterm" and you'll see *lots* of postings asking the same question.
Searching the discussion forum is a very useful skill. It's worth it to try it for yourself.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T22:13:37Z
SecondChildVoteTAG: 0
IndexTAG: 1321
TitleTAG: Exercise 5 Problem6
Its is confusing me?
UserIdTAG: 691586
UserNameTAG: twinoalbo
CreateTimeTAG: 2013-03-06T19:54:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Not long to wait now before the solution is given. Almost perfection.
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-03-06T22:18:23Z
FirstChildVoteTAG: 0
IndexTAG: 1322
TitleTAG: Confused by question
This question is confusing me. Can someone explain it in simple terms or paraphrase it?
UserIdTAG: 691586
UserNameTAG: twinoalbo
CreateTimeTAG: 2013-03-06T19:49:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: What does the last sentence say? Read it again and look at the choices.
FirstChildUserIdTAG: 132828
FirstChildUserNameTAG: rharris
FirstChildCreateTimeTAG: 2013-03-06T20:03:35Z
FirstChildVoteTAG: 0
IndexTAG: 1323
TitleTAG: :-)
I am really enjoying this course!
UserIdTAG: 144162
UserNameTAG: Rena2012
CreateTimeTAG: 2013-03-06T19:49:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1324
TitleTAG: Q6
Whoops, I just made a mistake on that one, and it was due to forgetting the last step that I need to perform to answer the question that was actually asked. Make sure you answer based on how many will commute LESS than 15.5 miles, not those who will commute 15.5 miles OR MORE.
UserIdTAG: 673325
UserNameTAG: coutlay
CreateTimeTAG: 2013-03-06T19:41:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: This is true, but if Markov's inequality gives the amount of employees who commute 15.5 miles or more, this means the remaining number of employees traveled less then 15.5. This is the thinking I used, but somewhere I went wrong.
FirstChildUserIdTAG: 132828
FirstChildUserNameTAG: rharris
FirstChildCreateTimeTAG: 2013-03-06T19:58:13Z
FirstChildVoteTAG: 0
SecondChildTAG: I looked at it again, and now I know where I went wrong. Read the question carefully!!
SecondChildUserIdTAG: 132828
SecondChildUserNameTAG: rharris
SecondChildCreateTimeTAG: 2013-03-06T20:01:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Yep, also select ALL that are correct LOL SMH
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-03-06T20:07:36Z
SecondChildVoteTAG: 0
IndexTAG: 1325
TitleTAG: Philantoo Sambava
Just Wonderful
UserIdTAG: 401080
UserNameTAG: Rakotondrajoa
CreateTimeTAG: 2013-03-06T19:37:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 0
IndexTAG: 1326
TitleTAG: Text book Exercise 4-8
List -5,5,1,-6,5
How do you find mean when negative numbers are included?
I first found (-4) just by adding (-5)+5+1+(-6)+(5)/5=-4
The answer in the book
is (-0.01 to 0.01)?
Can anyone help me understand how to get that answer?
UserIdTAG: 1115165
UserNameTAG: Abbyjohnson
CreateTimeTAG: 2013-03-06T19:22:33Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: You forgot a parenthesis:
You did: (-5)+5=0 1+(-6)+(5/5)=-4
You should have done: ((-5)+5=0 1+(-6)+5)/5=0
Just try adding up the numbers in your list, you'll notice the sum is zero.
I guess you calculated that with Excel or a similar programme. As a rule, such programmes start by calculating * and / before they calculate + and -. This is why using the right parenthesis is essential. For example 3*1+10=13 but 3*(1+10)=33.
Hope this helps.
FirstChildUserIdTAG: 1341583
FirstChildUserNameTAG: mnoschis
FirstChildCreateTimeTAG: 2013-03-06T19:50:46Z
FirstChildVoteTAG: 0
FirstChildTAG: The mean is (-5 +5 + 1 -6 +5 )/5 = 0/5 = 0
What you do in your expression is (-5)+5+1+(-6)+(5)/5= -5 + 5 + 1 -6 + 1 = -4
you only divide the last figure 5 by 5 which is 1, ending up at -4 as mean
:)
FirstChildUserIdTAG: 1127875
FirstChildUserNameTAG: Weerakappetipola
FirstChildCreateTimeTAG: 2013-03-06T19:59:00Z
FirstChildVoteTAG: 0
IndexTAG: 1327
TitleTAG: Amazing
Exercices 3 and 4 are amazing!. It is just thinking about and to apply the formula.
UserIdTAG: 1031814
UserNameTAG: Marivaldo
CreateTimeTAG: 2013-03-06T19:19:30Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 0
IndexTAG: 1328
TitleTAG: Next Session
Any one can tell me that when the next exercise and lecture will be available at account?
UserIdTAG: 1348562
UserNameTAG: manzarhayat
CreateTimeTAG: 2013-03-06T18:17:30Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: After March 6, 23.30 GMT
FirstChildUserIdTAG: 1258652
FirstChildUserNameTAG: gja
FirstChildCreateTimeTAG: 2013-03-06T18:22:16Z
FirstChildVoteTAG: 2
SecondChildTAG: Yep...and that's actually March 7 for many of us => 6 days only to do the work ;)
Would be nice to get the material available on the days specified at more reasonable GMT hours if at all possible..
SecondChildUserIdTAG: 902212
SecondChildUserNameTAG: trigeor
SecondChildCreateTimeTAG: 2013-03-06T19:52:42Z
SecondChildVoteTAG: 0
SecondChildTAG: **Thaxks A lot @gja**
SecondChildUserIdTAG: 303485
SecondChildUserNameTAG: iparitosh
SecondChildCreateTimeTAG: 2013-03-06T19:52:46Z
SecondChildVoteTAG: 0
IndexTAG: 1329
TitleTAG: hello
today is 6 th march 2013,I would like to know when materials for 3rd week will be provided?Since week 2 ends on march 5 th. So, please help me out.
UserIdTAG: 1177236
UserNameTAG: SOHAM1989
CreateTimeTAG: 2013-03-06T18:16:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: March 6 at 23:30 GMT
FirstChildUserIdTAG: 1127875
FirstChildUserNameTAG: Weerakappetipola
FirstChildCreateTimeTAG: 2013-03-06T18:50:26Z
FirstChildVoteTAG: 0
FirstChildTAG: > So, please help me out.
As we are not the ones who decide when the material is made available, that's a bit difficult.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T20:43:29Z
FirstChildVoteTAG: 0
IndexTAG: 1330
TitleTAG: Error (broken link) in SticiGui Text
While working the practice for ES6, we are instructed to try exercise 4-6 in the text. This exercise relies on the gravity data set, and there is a hotlink to bring us to the data.
That hotlink is broken in three places: First, in the exercise question itself, then both times it is used when I opened the solution.
This is FYI for staff.
Thank you.
UserIdTAG: 1165890
UserNameTAG: sandigarcia
CreateTimeTAG: 2013-03-06T18:03:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1331
TitleTAG: certificate
does anbody know if our marks will appear on the certificate or is it just general
UserIdTAG: 1280120
UserNameTAG: Rabia93
CreateTimeTAG: 2013-03-06T17:48:04Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: No
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T18:08:37Z
FirstChildVoteTAG: 0
SecondChildTAG: no the marks are not appeared on the certificate.
SecondChildUserIdTAG: 1348562
SecondChildUserNameTAG: manzarhayat
SecondChildCreateTimeTAG: 2013-03-06T18:13:30Z
SecondChildVoteTAG: 0
FirstChildTAG: does this cert really mean anything? it's just a piece of useless and meaningless paper...
FirstChildUserIdTAG: 255838
FirstChildUserNameTAG: EngineerHrenov
FirstChildCreateTimeTAG: 2013-03-06T20:31:15Z
FirstChildVoteTAG: 0
FirstChildTAG: > does this cert really mean anything? it's just a piece of useless and meaningless paper...
Depends. If you can convince someone of its worth, then it is worth something. But this particular certificate covers very basic beginning stats. If anything, you would need all 3 certificates from the 3 courses.
It has value to you, so I suppose that is the main thing to most people. Though there are those who use these certificates as proof of ongoing education efforts, or to try and get uni/college credit.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T20:42:46Z
FirstChildVoteTAG: 1
SecondChildTAG: I agree- I'm doing this for all 3 courses & for myself.
SecondChildUserIdTAG: 1267512
SecondChildUserNameTAG: MsPriya
SecondChildCreateTimeTAG: 2013-03-06T20:46:11Z
SecondChildVoteTAG: 0
SecondChildTAG: > Depends. If you can convince someone of its worth, then it is worth something.
Totally agree! You can actually use [www.accredible.com][1] to help convince someone of the worth of the courses you take online... might help! :)
[1]: http://www.accredible.com
SecondChildUserIdTAG: 1452386
SecondChildUserNameTAG: dking
SecondChildCreateTimeTAG: 2013-03-20T02:44:41Z
SecondChildVoteTAG: 0
FirstChildTAG: It has a great value, it will always add to your statistical knowledge, and added to your formal certifications & degrees, of course they will be well seen. Your professional performance will be by far the most important key indicator about what you may know and how skillfully you can put it into practice.
On the other hand, as far as I know, in other edX courses, you could take a proctorate exam, if you want to validate your studying and learning.
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-03-07T09:25:26Z
FirstChildVoteTAG: 0
FirstChildTAG: for me it has value ,too, because you can prove your basic understanding of statistics and in some institutions you need this to start e. g. a doctorate
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-07T09:38:56Z
FirstChildVoteTAG: 0
IndexTAG: 1332
TitleTAG: good article on SD just fyi
Here is a good article that may help some people with regard to SD. It nicely combines a few thoughts in one area.
[wiki link to SD][1]
[1]: http://en.wikipedia.org/wiki/Standard_deviation
UserIdTAG: 617920
UserNameTAG: CMR
CreateTimeTAG: 2013-03-06T17:35:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1333
TitleTAG: Question Six
Need to read the whole statement and look what kind of options we have.
UserIdTAG: 1145881
UserNameTAG: brunoa
CreateTimeTAG: 2013-03-06T17:03:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 0
IndexTAG: 1334
TitleTAG: What is meant by "1.96 sd covers 95% of population"
Well presented concepts, which is why I took this course. My thanks to Prof Ani Adhikary and her team.
I have come across the phrases "2 sd covers 95% of population" and "3 sd cover 99% of population" in the past. Are they talking about something else?
UserIdTAG: 382959
UserNameTAG: RajdeepSingh
CreateTimeTAG: 2013-03-06T17:01:40Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 5
FirstChildTAG: I believe these refer to datasets that have a normal distribution. The lectures so far have not assumed that the data has a normal distribution. This will probably be covered in later lectures.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-06T17:06:15Z
FirstChildVoteTAG: 0
FirstChildTAG: That is a normal distribution (Gaussian curve) where 1 Sd covers approximately 68 % and two SD's 95 % and 3 Sd's nearly 99.7 % and so on.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T17:21:10Z
FirstChildVoteTAG: 0
FirstChildTAG: What prasannasimha stated. Here is a "wikipedia" entry for it.
[Standard Normal Distribution - 1.96][1]
-Gabriel
[1]: http://en.wikipedia.org/wiki/1.96
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-03-06T19:52:45Z
FirstChildVoteTAG: 0
FirstChildTAG: You will learn that in this week's lectures. For any distribution you have Markov and Chebychev.
For the Normal you have the Empirical Rule, the values given in Prasannasimha's post.
Or you have the values obtained by using the normal formula. So $95\% = 1.96$ SD
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T20:34:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks!
FirstChildUserIdTAG: 382959
FirstChildUserNameTAG: RajdeepSingh
FirstChildCreateTimeTAG: 2013-03-09T18:19:42Z
FirstChildVoteTAG: 0
IndexTAG: 1335
TitleTAG: Staff: Midterm, urgent question
The midterm is set for 13th March
But when is it due for completion?
Thanks
UserIdTAG: 344400
UserNameTAG: carlallen
CreateTimeTAG: 2013-03-06T16:52:39Z
VoteTAG: 4
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: I would appreciate to know it as well because I need to organize my compromises for this day.
FirstChildUserIdTAG: 1270758
FirstChildUserNameTAG: leonardolamas
FirstChildCreateTimeTAG: 2013-03-06T17:01:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Dear all, search for 'midterm' in the forum and you will notice that the question has been answered.
SecondChildUserIdTAG: 1270758
SecondChildUserNameTAG: leonardolamas
SecondChildCreateTimeTAG: 2013-03-06T17:13:35Z
SecondChildVoteTAG: 0
FirstChildTAG: The Prof has answered several questions about this. As suggested, search the forum.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T20:39:46Z
FirstChildVoteTAG: 0
IndexTAG: 1336
TitleTAG: Problem 7 is unclear to me
I'm getting an answer like 1111.111111..., for the question number 7. How should I present it in the field? For how many decimals should it be rounded.
UserIdTAG: 1127875
UserNameTAG: Weerakappetipola
CreateTimeTAG: 2013-03-06T16:46:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: at the very top of the page it has the format/rounding notes
> Format of numerical answers
>
> This exercise set is worth 20 points. The paragraphs below discuss the
> format of numerical answers; please see the Course Announcement on the
> Landing Page for the reasons.
>
> Please provide all numerical answers correct to two decimal places or
> more, but please don't use more than five decimal places. No answer in
> this course will involve that degree of accuracy.
>
> For example, if your answer is 1/6, you can enter 0.17, or 0.167, or
> 0.1667, or 0.16667. Please don't enter 1/6 or 0.166666... or any expression that is not a number.
>
> If your answer is exactly -20.5, you can enter -20.5; you don't have
> to enter -20.50. If your answer is exactly 15, you can enter 15; you
> don't have to include a decimal point.
>
> Please do NOT enter any units of measurement; if they are needed, they
> will have been entered for you or will appear as part of multiple
> choice statements.
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-03-06T16:53:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Oh, Actually i didn't read it. i have been a bit busy so I skipped that part. My Mistake.
Thank you for your immediate response.
SecondChildUserIdTAG: 1127875
SecondChildUserNameTAG: Weerakappetipola
SecondChildCreateTimeTAG: 2013-03-06T16:57:02Z
SecondChildVoteTAG: 0
IndexTAG: 1337
TitleTAG: Supplements
Hello,
I was trying to access the supplements but after having some strange (incomplete) display (e.g. the sigmas cut in half), I have now a "bad gateway" message. Has anybody got the same problem? Is there another mean to get the documents?
Kind regards,
L
UserIdTAG: 1178410
UserNameTAG: Pti_Lu
CreateTimeTAG: 2013-03-06T16:36:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You need to post this question in the right discussion forum (not Exercise Set 1), otherwise you risk that many people (who might be able to give you an helpful answer) do not see it.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-06T16:44:00Z
FirstChildVoteTAG: 0
SecondChildTAG: oops sorry, thanks for pointing at it
SecondChildUserIdTAG: 1178410
SecondChildUserNameTAG: Pti_Lu
SecondChildCreateTimeTAG: 2013-03-06T16:58:38Z
SecondChildVoteTAG: 0
FirstChildTAG: It does load properly.I did it just now.Please ensure that your browser plug in for Adobe reader or foxit reader or PDF X change viewer is installed.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T17:19:25Z
FirstChildVoteTAG: 0
FirstChildTAG: Sometimes pages don't load. You just have to keep refreshing. I often have great problems loading the discussion page.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:28:35Z
FirstChildVoteTAG: 0
IndexTAG: 1338
TitleTAG: monaBlue
Hi I do not know how he get the answer for problem 3 in this exercise exercise set 6 can you please explain the answer as i got confused. thankks
UserIdTAG: 1182746
UserNameTAG: monaBlue
CreateTimeTAG: 2013-03-06T16:25:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: jot down the formula and check which values differ from one another and think which one is gonna produce the small value at the end...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-06T16:30:00Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Mona,
please consider two examples:
1°) x1=x2=...=x25=0. You'll SD25=0 and SD30=37.27 >>> In conclusion it gets bigger.
2° x1=1000, x2=x3=...=x25=0. You'll get SD25=195.96 and SD30=180.28 >>> in this case it gets smaller.
SD is getting bigger or smaller, depending on the series x1,...,x25 you've used. I cannot draw a mathematical conclusion that is valid for absolutely all possible unknown x1, x2,..., x25. In conclusion answer 4 or 5 would be correct.
Can anybody else help?
Kind Regards,
FirstChildUserIdTAG: 108063
FirstChildUserNameTAG: LiviuG
FirstChildCreateTimeTAG: 2013-03-06T17:03:09Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Mona,
in list A you have different values, so the SD > 0. To this list you add 5 values which are the same as the mean. So they do add 0 to the calculation of the sum of squared differences. But now you have to divide by 30 instead of 25. This makes the SD of list B smaller or the SD of list A greater.
FirstChildUserIdTAG: 1226081
FirstChildUserNameTAG: Birgid
FirstChildCreateTimeTAG: 2013-03-06T19:42:32Z
FirstChildVoteTAG: 0
IndexTAG: 1339
TitleTAG: Thank You for Providing 2 Submissions per Question
Providing at least 2 submissions per question turns the test/quiz/exercise into a learning experience instead of a degrading experience. I did not need those extra submission opportunities in this set, but in ES05, even though I clearly knew the answer to #6, I was so intent on solving the exercise, that by the time I obtained the answer and checked it, I forgot the statement in the exercise which told us to mark all possible correct answers, as opposed to the best answer. Unfortunately, in that exercise, there was only one submission allowed, so even though I clearly knew the information being taught, I scored an 80%. I am sure that it is very rare that answering a question such as that one will be a life and death situation, so I encourage you to continue to use these exercise sets in a positive manner by allowing multiple submissions per question (like you did in ES06). This will give your students an opportunity to carefully review their methods if they happen to experience a transient thought aberration in the midst of their learning process.
UserIdTAG: 909175
UserNameTAG: GeorgeJetson
CreateTimeTAG: 2013-03-06T16:05:01Z
VoteTAG: 11
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 0
IndexTAG: 1340
TitleTAG: I don´t understand Chebychev´s inequality
Could please someone explain me how to use the formula of Chebychev´s inequality. I am stuck in that. Thanks.
UserIdTAG: 526713
UserNameTAG: Miolan
CreateTimeTAG: 2013-03-06T15:39:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 6
FirstChildTAG: sorry but... what do you mean? can you be more precise? because you only need to use tha values accordingly...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-06T16:31:47Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, I don´t understand how get the bound with Chebychev´s inequality, using the SDs.
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-03-06T17:02:39Z
SecondChildVoteTAG: 0
SecondChildTAG: The lecture explains this just about as well as anyone could. I suggest you rewatch the lecture.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T17:07:34Z
SecondChildVoteTAG: 0
SecondChildTAG: My problem is english :( I cant understand very well becasue of that. If my understanding was perfect I wouldn´t ask that, but is my mistake to ask it in english, I will do in spanish again.
Si por favor, alguien que me pueda explicar en español este tema de Chebychev´s. Al menos la última parte relacionada con el SD.
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-03-06T18:34:05Z
SecondChildVoteTAG: 0
FirstChildTAG: Rewatch the elcture.If you really want to go through the proof it is there in the supplements and is a nice exercise in logic and maths !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T17:22:07Z
FirstChildVoteTAG: 0
SecondChildTAG: My problem is english :( I cant understand very well becasue of that. If my understanding was perfect I wouldn´t ask that, but is my mistake to ask it in english, I will do in spanish again.
Si por favor, alguien que me pueda explicar en español este tema de Chebychev. Al menos la última parte relacionada con el SD.
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-03-06T18:35:04Z
SecondChildVoteTAG: 0
FirstChildTAG: chebychev is an easy way to make some kind of educated guess of how much of the data is outside of the range of average plus or minus k times the SD; the formula tells you hat this is at most1/k squared, so you just need to replace the k
FirstChildUserIdTAG: 1280120
FirstChildUserNameTAG: Rabia93
FirstChildCreateTimeTAG: 2013-03-06T17:31:57Z
FirstChildVoteTAG: 0
SecondChildTAG: I was checking the slides and I don´t know where the 1/144 come from? is in the last slide.
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-03-06T18:37:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Miolan: In the example from last slides of the lecture:
average is 20 years, and SD is 5 years
We are looking for 80 years or more.
80 years old are 60 years form average. (80-20=60)
Those 60 years of distance form average are 12 SDs form the average, because SD is 5 years. (60/5 = 12)
12 SDs is the distance of 80 yars form average. Those 12 SDs are "k". Formula is 1/k-squared. k-squared is 12x12=144. So our formula is 1/44.
Was that helpful?
SecondChildUserIdTAG: 1278788
SecondChildUserNameTAG: KatarzynaRakowska
SecondChildCreateTimeTAG: 2013-03-06T19:05:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Katarzna explained correctly, but the last part has a typo:
correction: the formula is 1/**144**
Chebychev's inequality is 1/k^2
which is the same as 1/(k*k)
if k = 12, then the formula is 1/(12*12) which is 1/144
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-06T21:41:12Z
SecondChildVoteTAG: 0
FirstChildTAG: Goodness! So many helpful answers!
You people are just wonderful classmates....
If i felt like i could help, i would. Unfortunately, i am working hard to master this material, too, and so i can't offer up anything useful.
Thank god, however: i'm not some smug grade-hound cozying up to a free online grade....
FirstChildUserIdTAG: 911606
FirstChildUserNameTAG: ExpatKyle
FirstChildCreateTimeTAG: 2013-03-06T18:45:20Z
FirstChildVoteTAG: 1
FirstChildTAG: It is very very simple,
Suppose you have a distribution and the Standard deviation is SD. what chebychev's Inequality says is when you take K times SD range (K.SD <= Average <= K.SD) beside the average, the Values fall outside this range is Less than or equal to the fraction of 1/k^2 (one over K squared).
For an Example,
If the average is 50, and the SD = 5, the if you consider the data range of 2.SD (k=1) to the both sides of the average (40 - 60), The fraction of the data points fall outside this range is equal to 1/4 = 0.25 , and as a percentage 25%. 25% of the data points fall outside the range of 40 - 60.
Hope this helps!
FirstChildUserIdTAG: 1127875
FirstChildUserNameTAG: Weerakappetipola
FirstChildCreateTimeTAG: 2013-03-06T19:13:12Z
FirstChildVoteTAG: 1
SecondChildTAG: just to make sure: did you mean 2 SD (k=2) ?
SecondChildUserIdTAG: 1226081
SecondChildUserNameTAG: Birgid
SecondChildCreateTimeTAG: 2013-03-06T19:47:12Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi Miolan,
the bound (el limite) is the the distant value for which you want to know how high its probability is. So the further away from the mean (measured by SDs) the low the probability. To calculate this probability you use Chevychev (as you have the SD). Without the SD you take Markov. Inequalities mean that the result gives an "at most" proportion or fraction. So it could easily be a lower fraction but NEVER a greater.
I do not want to give you any advice, but I try to write down all formula in my language (and statistical syntax). For the problems I write down all data given in my language. This makes understanding and calculation easier for me.
FirstChildUserIdTAG: 1226081
FirstChildUserNameTAG: Birgid
FirstChildCreateTimeTAG: 2013-03-06T19:59:43Z
FirstChildVoteTAG: 0
IndexTAG: 1341
TitleTAG: what follows
Does anyone know if this course will be followed by one in inferrential statistics for those who succesfully finished the current one??
I like the pace, the amount of information and the assessment, everything seems to suit me so I would love to move on and do a higher course if this will be offered.
Cheers,
Antonis
UserIdTAG: 1207733
UserNameTAG: AntoniusBlock
CreateTimeTAG: 2013-03-06T15:28:34Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: 2.2X will probably by probability and 2.3X will be inferential statistics as per previous discussions.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T15:40:47Z
FirstChildVoteTAG: 0
FirstChildTAG: I read in a previous discussion that 2.2, on probability, will follow this course in a few weeks, and later 2.3, which i guess will be about inference.
FirstChildUserIdTAG: 929633
FirstChildUserNameTAG: BorjaMG
FirstChildCreateTimeTAG: 2013-03-06T15:43:49Z
FirstChildVoteTAG: 0
FirstChildTAG: That would be awesome. This is one of those precious courses that the professor can explain mathematical ideas from their roots in plain language.
I really appreciate the course and look forward to more.
FirstChildUserIdTAG: 1253143
FirstChildUserNameTAG: Jinjie
FirstChildCreateTimeTAG: 2013-03-06T16:03:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Do we have to keep track on that or will we be posted?
I would like to make a little bit more "official" my stats skills (I have been learning a bit only own through my little professional career but can't afford to go back to university).
So a big thank you for the opportunity to get a free course and the possibility to get a certificate.
FirstChildUserIdTAG: 1178410
FirstChildUserNameTAG: Pti_Lu
FirstChildCreateTimeTAG: 2013-03-06T16:40:43Z
FirstChildVoteTAG: 0
FirstChildTAG: These are really great news for me also.
Thanks for the answers.
Antonis
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-06T16:47:22Z
FirstChildVoteTAG: 0
IndexTAG: 1342
TitleTAG: exercise 4.12 from "text book"
*Exercise 4-12. A certain type of light bulb has an average lifetime of 10,000 hours. The SD of bulb lifetimes is 510 hours. What decimal fraction of bulbs could last more than 12,856 hours?
[-]Answer: 0.0309 to 0.0329.*
I computed the Chebychev's inequality which gives < / = 0,0318 which was taken as correct.
But giving it a second thought, doesn't this number (3,18%) represent the fraction of bulbs in total that can last either more than 12856 hrs or less than (10000-2856)=7144 hours??
Could you please answer if your are certain regarding what you are talking about as I would rather not be more confused.
Cheers
Antonis
UserIdTAG: 1207733
UserNameTAG: AntoniusBlock
CreateTimeTAG: 2013-03-06T15:02:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: It is more than **the sum of two tails** and therefore **more than the value of one tail** !! The key word here is **more than**
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T15:39:57Z
FirstChildVoteTAG: 0
FirstChildTAG: If you don't know the kind of distribution you're working with, you can't say both tails are equal. One tail could be zero. Thus the max for both tails, is also the max for one tail. Remember it is an inequality, towards a bound.
So you apply the max valid for both tails, also to one tail.
Hope this helps,
Kind Regards,
Eduard
PS Only if you have a symmetrical shaped distribution, you could say something more specific about the individual tails than about the combination of both tails. The video with the lecture explained this also, if I remember it OK.
FirstChildUserIdTAG: 989872
FirstChildUserNameTAG: EAK63
FirstChildCreateTimeTAG: 2013-03-06T15:52:01Z
FirstChildVoteTAG: 0
FirstChildTAG: yes, you are right, I had to give it some deeper thinkg to grasp the whole concept beyond the numbers and calculations
thanks,
Antonis
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-06T15:55:35Z
FirstChildVoteTAG: 0
FirstChildTAG: Chebychev's inequality gives the maximum fraction of data points that can fall outside the range that is being concerned. It is true that the percentage of light bulbs fall above the 12,856 hrs could be less than the fraction you have calculated. because Chebychev's inequality gives the collective fraction from the both ends. So it is obvious that the fraction related to one end is definitely less than the collective fraction unless one end consists of 0 data points.
so collective fraction is always Greater or equal to the fraction we get from one end.
Ex :- Chebychev's inequality = 25% , right hand side end consist of 17% (bulbs that have over 12 856 hrs life) and the other end consists of 8% (Bubls that have below 7144 hrs life). so when you answer the percentage of bulbs that have lifetimes over 12 856 hrs is less than 25% is is obvious because if its actually less than 17% it must be less than 25% as well!
:D
FirstChildUserIdTAG: 1127875
FirstChildUserNameTAG: Weerakappetipola
FirstChildCreateTimeTAG: 2013-03-06T19:44:26Z
FirstChildVoteTAG: 0
IndexTAG: 1343
TitleTAG: answers to exercise set
This posting is directed to the professors. It would extremely helpful if after we have completed the exercise sets and they have been graded, the answers are posted on the landing page or attach to what we have submitted. I would like to use the information as a learning tool to determine were I went wrong because some sets were more difficult than others.
UserIdTAG: 1058906
UserNameTAG: Debbi
CreateTimeTAG: 2013-03-06T14:55:44Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I agree. Now that the first 3 exercises due last week have all been graded. Where can we see explanations to the questions. Otherwise it's hard for us to learn from our mistakes. Thanks!
FirstChildUserIdTAG: 1178106
FirstChildUserNameTAG: pyt
FirstChildCreateTimeTAG: 2013-03-06T15:27:00Z
FirstChildVoteTAG: 0
SecondChildTAG: If you revisit the exercises after the weekly deadlines have passed, the correct answers with explanation will show for the questions you'd answered with a wrong answers.
Kind regards,
Eduard
SecondChildUserIdTAG: 989872
SecondChildUserNameTAG: EAK63
SecondChildCreateTimeTAG: 2013-03-06T15:55:43Z
SecondChildVoteTAG: 0
FirstChildTAG: If you go back to the 1st exercise sets the check/save buttons below each of the questions have been replaced by "show answer" buttons.
FirstChildUserIdTAG: 1034840
FirstChildUserNameTAG: StaceyD
FirstChildCreateTimeTAG: 2013-03-06T15:56:41Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree.
I think that should be very useful
FirstChildUserIdTAG: 1180593
FirstChildUserNameTAG: CARLOSJAV
FirstChildCreateTimeTAG: 2013-03-06T16:02:59Z
FirstChildVoteTAG: 0
IndexTAG: 1344
TitleTAG: I GUESS I AM TOO LATE FOR THE CLASS.
HELLO I AM NEW , HERE AND I WANTED TO JOIN THE COURSE.IS IT OK HERE ,
UserIdTAG: 1359420
UserNameTAG: coolaryan99
CreateTimeTAG: 2013-03-06T14:55:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: It is Ok here but it is not OK to use all caps as it is equivalent of shouting
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T15:07:53Z
FirstChildVoteTAG: 1
SecondChildTAG: What? All caps is the equivalent of genocide where I come from.
SecondChildUserIdTAG: 763150
SecondChildUserNameTAG: quasiscroto
SecondChildCreateTimeTAG: 2013-03-06T16:45:56Z
SecondChildVoteTAG: 0
SecondChildTAG: lol!
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T17:04:08Z
SecondChildVoteTAG: 0
FirstChildTAG: You're still in time to join. Just read the course info and do the problems from the beginning. You'll have some catching up to do but the material is not that difficult and grade for the certificate is only 35%. The course material will explain anything. Please read it before coming back to the forum to avoid unnecessary discussions.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-06T16:57:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Well, as you are here and posting you have obviously joined the class. As suggested above, read all the course documents.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:27:03Z
FirstChildVoteTAG: 0
IndexTAG: 1345
TitleTAG: Query for Prof. Adhikary
Hi,
As for the solution for median. The data is given as -4, 6, 6, 4, -10, 6. Once we sort the data we get -10, -4, 4, 6, 6, 6.
I had attended a stats course in India where we were told if there are even numbers, add the middle two numbers and divide it by 2. That would make the median 5 ([6+4]/2) where as the solution says that the median is 4. Looking forward to your comments
Thanks in advance
Sohini
UserIdTAG: 592961
UserNameTAG: Sohini
CreateTimeTAG: 2013-03-06T14:23:49Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: Have a look at this discussion we had
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/512cfdf7e9253d2500000008
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T14:35:28Z
FirstChildVoteTAG: 1
FirstChildTAG: And that was all covered in the lecture.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:26:17Z
FirstChildVoteTAG: 0
IndexTAG: 1346
TitleTAG: Answer validation is *BROKEN*
In the exercise you have to append the % symbol to get the right answer, but here if you append the % symbol you get a wrong answer. The last 2 questions I answered correctly and exactly the same as the correct answer, but the system did not mark them as correct. If an answer is 8.666 and I write 8.6, I get it wrong because the system thinks it is 8.67. I think you should fix your system, and mark an answer as correct if it differs for no more than 0.1. Specify if the symbol % needs to be specified or not, or remove it if necessary or give 4 choices and have the student pick the correct one.
It is very discouraging to get wwong answers when they are right but the system is broken.
UserIdTAG: 1062361
UserNameTAG: jkobeh
CreateTimeTAG: 2013-03-06T14:09:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: this is a course of statistics, maths. you need a precision answer.
If the answer is 8.66666, the correct answer (round) is 8.67, not 8.66. Your answer was wrong.
FirstChildUserIdTAG: 1134470
FirstChildUserNameTAG: cpaula
FirstChildCreateTimeTAG: 2013-03-06T15:44:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Additionally, if you are rounding to only one decimal place and your value is 8.6666666, it would be more correct to round to 8.7 anyway.
SecondChildUserIdTAG: 1117422
SecondChildUserNameTAG: edutainment
SecondChildCreateTimeTAG: 2013-03-06T18:20:47Z
SecondChildVoteTAG: 0
IndexTAG: 1347
TitleTAG: I nearly gave up!
I got all correct in this section! Am amazed as I was toying with the idea of dropping out after seeing the supplement with those sigma notations. RK77
UserIdTAG: 929545
UserNameTAG: RK77
CreateTimeTAG: 2013-03-06T14:08:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 0
IndexTAG: 1348
TitleTAG: Late registration
Hello,
I just found out about this edx and this amazing course and registered for it right now. I would like to ask, what will happen to my grades since the submission dates for the 1,2 and 3 excercises have passed? Can I do it and sumbit it at a later date?
Thanks
UserIdTAG: 1372692
UserNameTAG: Stexfano
CreateTimeTAG: 2013-03-06T13:39:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I don't think it would make that much of difference to you grades since the two lowest scores are dropped anyway and the certificate you get only states 'pass' or 'not passed'. So you should be okay.
It's a really great course, don't pass up on it just because you missed an assignment.
FirstChildUserIdTAG: 959823
FirstChildUserNameTAG: rasneer
FirstChildCreateTimeTAG: 2013-03-06T17:52:24Z
FirstChildVoteTAG: 0
FirstChildTAG: Will this course be offered again? If so, when? I'm enjoying the class but it looks like I need to unregister. I've injured myself and it looks like I need to go in for surgery. I will likely miss a couple of weeks of class, maybe more. I'm assuming you're going to go on with the next two parts. If we've had descriptive statistics before and this is review, may we take the next two parts without first taking this one? Thanks!
FirstChildUserIdTAG: 1312273
FirstChildUserNameTAG: bexn
FirstChildCreateTimeTAG: 2013-03-06T18:17:18Z
FirstChildVoteTAG: 0
FirstChildTAG: > Will this course be offered again?
Probably
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:13:25Z
FirstChildVoteTAG: 0
IndexTAG: 1349
TitleTAG: In problem 2
In problem 2 each child raise the same amount? If each of the childs could have raised $25 so....
??
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UserNameTAG: Turca
CreateTimeTAG: 2013-03-06T13:33:34Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: The *average* (or the *mean*) each child raised is **$5**; presumably some raised more and some raised less, but that's immaterial to the problem.
Use Markov's inequality to calculate how many children could have raised $25
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-06T14:12:19Z
FirstChildVoteTAG: 0
IndexTAG: 1350
TitleTAG: Q3..I have gone though different post. what about..
what if the first 25 digits are also 100s? the question does not specify the first 25digits are different....can somebody expound on this?
What do I mean: if the other 25 digits are 100 each, then the SD will be the same!
UserIdTAG: 1281184
UserNameTAG: Otur
CreateTimeTAG: 2013-03-06T13:32:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: List A has 25 **different** entries, and its average is 100 if all number were 100 then it wouldn't have 25 different entries
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-03-06T13:39:53Z
FirstChildVoteTAG: 0
SecondChildTAG: by the addition of more entries equal to average, reduces standard deviation
SecondChildUserIdTAG: 1164630
SecondChildUserNameTAG: jehanalam
SecondChildCreateTimeTAG: 2013-03-06T16:01:02Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you for noting the importance of the word "different"!
SecondChildUserIdTAG: 773223
SecondChildUserNameTAG: Andaponte
SecondChildCreateTimeTAG: 2013-03-06T22:12:26Z
SecondChildVoteTAG: 0
FirstChildTAG: Otur, you can create any small list for yourself using excel. Let say you create a list of 5 entries. You find the average. Then create a second list with the same values for the first 5 entries. Then you just add one or 2 more entries with the average for the first list as values for these additional entries for list 2. Do the rest of the calculations and you will see conceptually why the answer is what it is. The key is to look at the deviations.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-06T15:14:22Z
FirstChildVoteTAG: 0
FirstChildTAG: What was handy for me to think about was that set A and set B have the same exact entries except for the additional 5 values in set B. So set B changes in two ways: it has more total entries, and those new entries have particular values (in this case they are all 100). From there I would suggest focusing on how averages and standard deviations are calculated.
FirstChildUserIdTAG: 1117422
FirstChildUserNameTAG: edutainment
FirstChildCreateTimeTAG: 2013-03-06T16:23:37Z
FirstChildVoteTAG: 0
SecondChildTAG: but they are supposed not to...
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-06T16:33:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Thats actually how I proved my answer, for some reason I didnt trust my gut, so 2 lists with average of 100 then the additional 5 lots of 100, mess around with the lists, let them stay the same and have an average of 100, and it will prove the answer
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-03-06T17:21:42Z
SecondChildVoteTAG: 0
IndexTAG: 1351
TitleTAG: Staff Please: This is a big problem that makes me wonder why I am trying so hard
Hi Staff, can you please do something about people posting answers both on this forum and others. Apart from the honor code, this really takes away from any prestige of doing this study. Some people are working quite hard at this, and others are either blatantly giving out answers, or doing it out of pure stupidity
Im at the point now where I cant rely on the forum for help now as I dont know If I am opening a post with the answer rather than a discussion on the problem.
I would suggest they are removed from edX completely, but I am not know for being Mr Nice Guy
UserIdTAG: 7545
UserNameTAG: jasontimothyjones
CreateTimeTAG: 2013-03-06T13:30:03Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Your point is a good one; it can certainly be frustrating to stumble across the full solution when you were only looking for a little help in getting back onto the right path.
However I think perhaps it's a little too punitive to remove anyone from edX simply because of an action that was doubtfully intended to cause distress or hamper others' ability to discover and learn the answer, as well as the method.
It is worth noting that sometimes people can find having the answer a useful tool in checking back through their calculation to discover where they strayed from the correct method, and perhaps at least some of those posting the answer may be trying to help in this way. This can be a useful way to learn a method and so I wouldn't necessarily wish to prevent people from using it.
But perhaps a solution to this concern could be requesting people post a spoiler alert e.g. ***ANSWER IS INCLUDED IN POST BELOW***, which would permit both ways of learning to exist on the forum.
In any case, I hope this isn't enough to put you off the course or continuing to use the forum. The very best of luck with your studies and I hope you enjoy the rest of the course!
FirstChildUserIdTAG: 1070406
FirstChildUserNameTAG: barretrp
FirstChildCreateTimeTAG: 2013-03-06T13:58:49Z
FirstChildVoteTAG: 2
FirstChildTAG: Hi.
It is true that some post contains solutions, but it is also true that there is some "bad karma" floating around this forum. The solution for the spoiler problem is not the exile from edx. I think this is better: one warning, then restricted acces to forums, this will prevent the harm and keep our "bad karma" under control.
FirstChildUserIdTAG: 929633
FirstChildUserNameTAG: BorjaMG
FirstChildCreateTimeTAG: 2013-03-06T13:59:07Z
FirstChildVoteTAG: 1
FirstChildTAG: Perhaps discussion could be a feature that is locked until the deadline expires? Then, students can come back to discuss the answer sets. I agree that having the answers readily available in the discussion section is not a good motivator for students who are putting a lot of hard work in, and it also means that obtaining the certificate does not necessarily mean that a student actually understood the material at all, if they could simply check the discussion section for the answers.
FirstChildUserIdTAG: 1025842
FirstChildUserNameTAG: mspijksma
FirstChildCreateTimeTAG: 2013-03-06T17:02:14Z
FirstChildVoteTAG: 0
FirstChildTAG: @jasontimothyjones,
I would recommend that you stop worrying about what other students are doing or not doing. Hopefully you are here to learn statistics and if trying hard to do that is a requirement for you so be it, but you can't be distracted by others posting answers. Just focus on "you" doing the right thing and it will make your life much more peaceful.
FirstChildUserIdTAG: 1067669
FirstChildUserNameTAG: psanders
FirstChildCreateTimeTAG: 2013-03-06T17:39:05Z
FirstChildVoteTAG: 0
SecondChildTAG: My problem is when I read a post looking for discussion and the answer is right there....But thanks for the recommendation
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-03-06T18:18:42Z
SecondChildVoteTAG: 0
FirstChildTAG: It doesn't matter what you do, answers will be posted. Locking the forum to people who haven't done the assessment is draconian in the extreme. For some people you are locking them out permanently, because they don't do assessments early. And what of those who want to ask questions? They don't matter?
The point is that we all agreed not to discuss assessed item solutions. Some just absolutely refuse to believe that they could be wrong. So they have to scream loud and long about the injustice of it all. That will never change.
And there are always people who think they are helping by giving an answer. Or who do it just to cause friction.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:24:00Z
FirstChildVoteTAG: 0
SecondChildTAG: You're right: close the forums is draconian. But even this seems better than remove someone from edx. I don´t want my proposal be carried out, it was just a way to protest against the bad karma.
SecondChildUserIdTAG: 929633
SecondChildUserNameTAG: BorjaMG
SecondChildCreateTimeTAG: 2013-03-07T13:50:11Z
SecondChildVoteTAG: 0
IndexTAG: 1352
TitleTAG: Problem 2
Yes, yes, yes. The answer to problem 2 is -4.01 (negative). The average goes down with the correction.
UserIdTAG: 450068
UserNameTAG: RafaelAntonio
CreateTimeTAG: 2013-03-06T13:08:28Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 2
FirstChildTAG: No, no, no.
The recorded distance was recorded as 165 INSTEAD OF 16.5. Therefore and because of that error, the average will increase.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-03-06T13:19:55Z
FirstChildVoteTAG: 0
FirstChildTAG: RafaelAntonio, you agreed to the Honor Code, this includes: Don't post solutions in the forum (or anywhere else) as long as the exercise deadline is not over.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-06T14:17:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Suggestion : A COUNT DOWN CLOCK on discussion & exercise pages ?
Would a count down clock, counting down to the nearest deadline, placed above the forum pages and exercise pages on the website be a workable solution ?
This would help people remind the remaining time to do the exercises, identical to the wait for exchanging discussion, calculations and answers re. the exercises.
Kind Regards,
Eduard
SecondChildUserIdTAG: 989872
SecondChildUserNameTAG: EAK63
SecondChildCreateTimeTAG: 2013-03-06T16:08:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Your suggestion is posted in the wrong thread.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-06T16:41:43Z
SecondChildVoteTAG: 0
IndexTAG: 1353
TitleTAG: Registered to the course at 2nd week
I have just made my registration, but as I see today ends the 2nd week, and also the assignment delivering. How can I repair the past weeks? Will the exercises be accepted since the course already started?
UserIdTAG: 1372603
UserNameTAG: Peppe
CreateTimeTAG: 2013-03-06T12:59:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > How can I repair the past weeks? Will the exercises be accepted since the course already started?
No. Deadlines are set in stone. Miss them, and you can't make them up. So Week 1 is gone, Week 2 is about to finish.
Read the Course Info Policy document for grading details.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T21:19:56Z
FirstChildVoteTAG: 0
IndexTAG: 1354
TitleTAG: Can I do the exercises after the deadline?
I just want to know that. Are the exercises closed after that?
UserIdTAG: 526713
UserNameTAG: Miolan
CreateTimeTAG: 2013-03-06T12:53:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The exercises are still available to work through, but the answers you provide are no longer counted towards a final grade.
FirstChildUserIdTAG: 1070406
FirstChildUserNameTAG: barretrp
FirstChildCreateTimeTAG: 2013-03-06T14:18:44Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-03-06T15:09:20Z
SecondChildVoteTAG: 0
IndexTAG: 1355
TitleTAG: Meaning of "persons over 65"
Hi Prof. A,
I'd like to ask if there is a convention regarding such phrases as "persons over 65." I understand this phrase to mean "people aged 66 and above," but Problem 2b of Exercise Set 2 seems to interpret it as "people aged 65 and above." I hope you could help us regarding this. Thank you!
UserIdTAG: 893512
UserNameTAG: jeremiad
CreateTimeTAG: 2013-03-06T12:52:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: I believe you're right... aged 65 and above
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-03-06T13:18:55Z
FirstChildVoteTAG: 0
FirstChildTAG: The question allows you to assume that ages are uniformly distributed within intervals. That assumption implies that age is being worked with as a continuous variable, not "age in completed years" which is what I think you are imagining.
Once you assume uniformity within intervals, "over 65" means any number greater than 65, no matter how close to 65 it might be.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-06T18:38:24Z
FirstChildVoteTAG: 0
SecondChildTAG: Oh, I did regard age as a discrete variable. There's the rub. :D
Thanks, Prof. A!
SecondChildUserIdTAG: 893512
SecondChildUserNameTAG: jeremiad
SecondChildCreateTimeTAG: 2013-03-07T13:38:57Z
SecondChildVoteTAG: 0
IndexTAG: 1356
TitleTAG: problem 6
I find problem 6 odd....I did not get the answer right...please check for me
UserIdTAG: 916875
UserNameTAG: nilufa
CreateTimeTAG: 2013-03-06T12:35:06Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: i got answer right
FirstChildUserIdTAG: 525070
FirstChildUserNameTAG: YL_
FirstChildCreateTimeTAG: 2013-03-06T12:45:03Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes me too.It is a tricky one though,i got it with the second.
SecondChildUserIdTAG: 1036302
SecondChildUserNameTAG: vaggelas
SecondChildCreateTimeTAG: 2013-03-06T14:22:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi,
please consider two examples:
1°) x1=x2=...=x25=0. You'll SD25=0 and SD30=37.27 >>> In conclusion it gets bigger.
2° x1=1000, x2=x3=...=x25=0. You'll get SD25=195.96 and SD30=180.28 >>> in this case it gets smaller.
SD is getting bigger or smaller, depending on the series x1,...,x25 you've used. I cannot draw a mathematical conclusion that is valid for absolutely all possible unknown x1, x2,..., x25. In conclusion answer 4 or 5 would be correct.
Can anybody else help?
Kind Regards,
SecondChildUserIdTAG: 108063
SecondChildUserNameTAG: LiviuG
SecondChildCreateTimeTAG: 2013-03-06T17:04:32Z
SecondChildVoteTAG: 0
FirstChildTAG: You got an average and populations size. You, probably, can assume something out of these two figures.
FirstChildUserIdTAG: 313892
FirstChildUserNameTAG: doronko4
FirstChildCreateTimeTAG: 2013-03-06T14:22:14Z
FirstChildVoteTAG: 0
IndexTAG: 1357
TitleTAG: the policy of rounding numbers
Why there is still no unification in the policy of rounding numbers?) For example, 4 in the problem 2 is the right answer (the answer could be written as 4.01), however in the problem 3 69 is the wrong answer? Please, don't get it wrong way, but this is really easy to fix :)
UserIdTAG: 181632
UserNameTAG: illashenko
CreateTimeTAG: 2013-03-06T12:15:56Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 2
FirstChildTAG: If you look at the given answers, they are given to 2 dp (ie 4.01 and 68.71). It seems that the grader has a little bit of tolerance in it and so 4.00 is deemed close enough to the correct answer. 68.71 and 69.00 are much further apart.
In both cases if you round to 2 dp as specified then it's marked correct.
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-03-06T12:39:03Z
FirstChildVoteTAG: 0
FirstChildTAG: It says in the main "Course Info" page and at the beginning of the Week 2 Exercise sets that answers between 2 dp and 5dp (inclusive) will be accepted.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-03-06T13:18:26Z
FirstChildVoteTAG: 0
IndexTAG: 1358
TitleTAG: BUG
THE ANSWER IS -4.01 AND NOT 4.01
UserIdTAG: 556698
UserNameTAG: GGG
CreateTimeTAG: 2013-03-06T11:30:49Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 3
FirstChildTAG: No, it isn't. Read the question again, as I don't think you understand exactly what is being asked.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-03-06T11:33:52Z
FirstChildVoteTAG: 0
FirstChildTAG: Before declaring the answer is wrong and there's a bug, have you really checked how you reached your conclusions?
The recorded distance was recorded as 165 INSTEAD OF 16.5. Naturally, the average will be increased because of that...
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-03-06T11:35:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Of course it's wrong! And the moon landings were faked too.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T11:52:48Z
FirstChildVoteTAG: 1
IndexTAG: 1359
TitleTAG: do I get the concept SD properly (answered to set 6 question 3 ok)?
I answered what I answered because:
what we learn in the pb lead me to think,: ok so average is x, we have y times that x entry in list W. so the average of list W will get closer to x. Can't write anything more.
Yes, I took the proportion in count (lec.4.2)
Just want to know if I my logic is ok^^
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-03-06T11:27:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi,
please consider two examples:
1°) x1=x2=...=x25=0. You'll SD25=0 and SD30=37.27 >>> In conclusion it gets bigger.
2° x1=1000, x2=x3=...=x25=0. You'll get SD25=195.96 and SD30=180.28 >>> in this case it gets smaller.
SD is getting bigger or smaller, depending on the series x1,...,x25 you've used. I cannot draw a mathematical conclusion that is valid for absolutely all possible unknown x1, x2,..., x25. In conclusion answer 4 or 5 would be correct.
Can anybody else help?
Kind Regards,
FirstChildUserIdTAG: 108063
FirstChildUserNameTAG: LiviuG
FirstChildCreateTimeTAG: 2013-03-06T17:05:30Z
FirstChildVoteTAG: 0
IndexTAG: 1360
TitleTAG: Problem 4
I don´t understand problem 4, can somebody explain it to me? Thanks
UserIdTAG: 504132
UserNameTAG: BenjaminY
CreateTimeTAG: 2013-03-06T11:04:46Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Think about the difference between the median and the mean (average).
What is the median?
What is the mean?
If you have trouble with the concepts, it is worth rewatching the lectures or reading additional material, as they really are important basic concepts.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-06T11:11:41Z
FirstChildVoteTAG: 1
SecondChildTAG: rewatch lecture 3.4 It is a VERY important concept!! I will be happy to explain it to you once due date has passed
SecondChildUserIdTAG: 1051932
SecondChildUserNameTAG: LARISSAMROCHA2013
SecondChildCreateTimeTAG: 2013-03-06T13:03:36Z
SecondChildVoteTAG: 0
SecondChildTAG: BenjaminY, we have been told that with the median we get two equal areas and that with the mean (average) we get the center of gravity (and it can be over the median, to the right or to the left) —in this case it is to the right—. You do not need to know anything else.
SecondChildUserIdTAG: 450068
SecondChildUserNameTAG: RafaelAntonio
SecondChildCreateTimeTAG: 2013-03-06T18:23:42Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm not getting this question neither... I actually thought that the correct answer is NOT to tick any LOL
SecondChildUserIdTAG: 905926
SecondChildUserNameTAG: MarcinJ77
SecondChildCreateTimeTAG: 2013-03-06T18:49:12Z
SecondChildVoteTAG: 0
SecondChildTAG: see avg> median....so if ur value is avg, its greater than that of 50% of the population....hence 50% ppl have lower value than the average value.
SecondChildUserIdTAG: 432151
SecondChildUserNameTAG: rgdixit
SecondChildCreateTimeTAG: 2013-03-06T18:58:12Z
SecondChildVoteTAG: 0
SecondChildTAG: just read the question again... for some reason I thought that there was how many people have to travel MORE than 15.5... silly mistake on my side... again :D
SecondChildUserIdTAG: 905926
SecondChildUserNameTAG: MarcinJ77
SecondChildCreateTimeTAG: 2013-03-07T00:12:49Z
SecondChildVoteTAG: 0
IndexTAG: 1361
TitleTAG: I made a mistake
Hello:
I understood that the answer was -10 due to a misunderstanding of the phrase " If you think the median goes down by 10 miles, enter -10" so the answer for this question was less than 10.... !!
Thanks
UserIdTAG: 945953
UserNameTAG: Turca
CreateTimeTAG: 2013-03-06T10:43:41Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 1
FirstChildTAG: It is unfair to post answers whether right or wrong
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T13:55:24Z
FirstChildVoteTAG: 3
SecondChildTAG: Where are the solutions of Exercise Set 4-6?
SecondChildUserIdTAG: 1360058
SecondChildUserNameTAG: manas_zafar
SecondChildCreateTimeTAG: 2013-03-06T15:15:46Z
SecondChildVoteTAG: 0
SecondChildTAG: They will be released after the deadline which is today 23.30 GMT
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-06T17:25:42Z
SecondChildVoteTAG: 0
IndexTAG: 1362
TitleTAG: Assignment/Student ID
Hi
How can i get Course ID to login for assignment.
I have just completed the second week exercise, so do i have any assignment to be completed?
Thanks
Asif
UserIdTAG: 936171
UserNameTAG: Asif99
CreateTimeTAG: 2013-03-06T10:35:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You should not use the online textbook bit only the course ware tests which have a blue clock on them
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T13:56:41Z
FirstChildVoteTAG: 0
IndexTAG: 1363
TitleTAG: Passing for ES3
I want to knows if it is possible to make passing for me about ES3. On Feb 28 last week, didn't have possibility to finish ES3 because of the Internet connection failure.
UserIdTAG: 681879
UserNameTAG: oued1967
CreateTimeTAG: 2013-03-06T10:26:56Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1364
TitleTAG: Don't skip any lectures by accident or "how to navigate the site"
I missed some lectures by prof A. because I did not continue after the first video. Sometimes there is more than one lecture, as indicated in the title, for example Lec 3.1 - 3.3. After watching the introduction, you can go to lecture 3.1 by clicking on the right black arrow (triangle) at the bottom of the page (or at the top of the page where you see an overview of the videos). After lecture 3.1 you continue with lecture 3.2 and then 3.3. I'm sure I'm not the only one who made this mistake.
UserIdTAG: 1159651
UserNameTAG: KatrienJ
CreateTimeTAG: 2013-03-06T10:17:26Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1365
TitleTAG: Problem 6
15.5/6.2= 2.5
1/2.5 = 0.4
UserIdTAG: 39476
UserNameTAG: abhyuday
CreateTimeTAG: 2013-03-06T10:09:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: SERIOUSLY?
NO ANSWERS ON THE FORUM DICUSSION.....!
HINTS, BUT THAT....
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-03-06T11:38:16Z
FirstChildVoteTAG: 0
SecondChildTAG: 15.5/6.2 = 2.5,so as per markov's inequality the percent of commuters who travels more than 15.5 miles is at the most 1/2.5=0.4,which is 40%,which means commuters who travels less than 15.5 miles are atleast 60%.So all options are correct
SecondChildUserIdTAG: 1050175
SecondChildUserNameTAG: Mdbi
SecondChildCreateTimeTAG: 2013-03-06T11:51:53Z
SecondChildVoteTAG: 0
SecondChildTAG: And Mdbi shows that s/he doesn't agree with honour either.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T11:54:21Z
SecondChildVoteTAG: 0
SecondChildTAG: 15.5/6.2 = 2.5,so as per markov's inequality the percent of commuters who travels more than 15.5 miles is at the most 1/2.5=0.4,which is 40%,which means commuters who travels less than 15.5 miles are atleast 60%.60% of 82 = 49.2 ~ 49.So all options aply
SecondChildUserIdTAG: 1050175
SecondChildUserNameTAG: Mdbi
SecondChildCreateTimeTAG: 2013-03-06T11:56:58Z
SecondChildVoteTAG: 0
SecondChildTAG: So you repeat it? LOL. Must be a full moon.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T11:58:58Z
SecondChildVoteTAG: 0
SecondChildTAG: @SusanAust haha, love you without even knowing you...
SecondChildUserIdTAG: 997742
SecondChildUserNameTAG: phamv
SecondChildCreateTimeTAG: 2013-03-06T20:33:27Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi Abhyuday, by joining this course, you agreed to EdX's honor code as well as to reading the Course Info and the Forum Guidelines. Seeing how you violated all of them by posting these crude numbers without any context or question, I am puzzled how to "answer" to your post. Edit it!
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-06T11:47:14Z
FirstChildVoteTAG: 4
IndexTAG: 1366
TitleTAG: Problem 8
Question is not clear to me.
UserIdTAG: 39476
UserNameTAG: abhyuday
CreateTimeTAG: 2013-03-06T10:03:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: I don't know how much can i tell without giving the answer,but if you watch the last video of the lecture(it has something similar) and follow the hint at the bottom of the question i think you will get the answer.
Just think will the average get bigger or smaller?if something gets bigger is positive,if something get smaller is negative.
And how bigger or smaller will the average be?What was the change of the value and what is the number of the sample.
FirstChildUserIdTAG: 1036302
FirstChildUserNameTAG: vaggelas
FirstChildCreateTimeTAG: 2013-03-06T14:26:43Z
FirstChildVoteTAG: 0
SecondChildTAG: Question could have been phrased more appropriately.
SecondChildUserIdTAG: 1129606
SecondChildUserNameTAG: navneetshrivastava
SecondChildCreateTimeTAG: 2013-03-06T17:51:21Z
SecondChildVoteTAG: 0
SecondChildTAG: The question is worded exactly the same as the comparable practice exercises. That should help. I think they've gone above and beyond to try to make sure we understand what the question is asking, but it only helps if you do the practice first
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-03-06T19:30:22Z
SecondChildVoteTAG: 0
IndexTAG: 1367
TitleTAG: just commenting!
wow, this section was a little bit harder... getting scared for the next sections... well, good luck to all!
UserIdTAG: 921807
UserNameTAG: hdzmiriam
CreateTimeTAG: 2013-03-06T09:55:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Your kidding - hard for a 6th grader maybe. I can't believe that this is considered a college level course.
FirstChildUserIdTAG: 1284382
FirstChildUserNameTAG: kite420
FirstChildCreateTimeTAG: 2013-03-06T13:34:28Z
FirstChildVoteTAG: 0
SecondChildTAG: If it's so easy perhaps you shouldn't be taking it. Consider a grammar or spelling course instead!
[You're = you are / Your = belonging to you]
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-03-06T20:49:08Z
SecondChildVoteTAG: 0
IndexTAG: 1368
TitleTAG: wrong answer/explanation provided for people in their thirties(exercise set 2,problem2a)
Explanation provided is wrong because left bound & hence those aged 30 are not included in class interval 30-45 but in interval 20-30. Therefore people in their thirties = (13.8/10)*1 + (19.8/15)*9 =1.38 + 11.88 =13.26
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-06T09:41:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: >Intervals include the left endpoint but not the right;
The answer as given is correct.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T09:52:47Z
FirstChildVoteTAG: 0
FirstChildTAG: The Teacher is always wrong :) Wouldn't it be better to clarify a doubt rather than assume one is correct. Of course there may be errors but it would be better to ask and in fact if there were any they would have been spotted by now
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T10:23:22Z
FirstChildVoteTAG: 0
SecondChildTAG: > Wouldn't it be better to clarify a doubt rather than assume one is correct.
Where's the fun in that?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T10:58:53Z
SecondChildVoteTAG: 0
IndexTAG: 1369
TitleTAG: Help.. Indian Time Schedule for the Course?
Hey hi,
Can anyone help me the **MIDTERM** date and **time as per the Indian Time Zone**.
I am from Rajasthan and having problems with time schedule.. for ex. today is 6th and Week 3 should have been uploaded but it's not yet...
Thanks and Regards
Paritosh
UserIdTAG: 303485
UserNameTAG: iparitosh
CreateTimeTAG: 2013-03-06T09:16:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: it is **GMT** time check on google india and **GMT** time
For instance, I live in France, and France is GMT +2 from October to April, and GMT +1 from April to October( yeah, it sux)
Good luck!!!
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-03-06T09:52:37Z
FirstChildVoteTAG: 0
SecondChildTAG: thx:)
SecondChildUserIdTAG: 303485
SecondChildUserNameTAG: iparitosh
SecondChildCreateTimeTAG: 2013-03-06T10:21:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Try this site for time zone conversions: http://www.timeanddate.com/worldclock/converter.html
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-03-06T10:11:59Z
FirstChildVoteTAG: 0
SecondChildTAG: thx:)
SecondChildUserIdTAG: 303485
SecondChildUserNameTAG: iparitosh
SecondChildCreateTimeTAG: 2013-03-06T10:20:51Z
SecondChildVoteTAG: 0
FirstChildTAG: We are ahead of GMT but 5 hours 30 minutes. So it is 3.44 PM in India and 10.14 AM in UK. There are a lot of online resources to. Invert GMT to IST and vice versa and you can use Qclock which will install a gadget on your desktop screen and you can have London time Berkeley time and so on and so forth.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T10:18:14Z
FirstChildVoteTAG: 0
SecondChildTAG: thx :)
SecondChildUserIdTAG: 303485
SecondChildUserNameTAG: iparitosh
SecondChildCreateTimeTAG: 2013-03-06T10:20:43Z
SecondChildVoteTAG: 0
IndexTAG: 1370
TitleTAG: problem 2
i picked the number 14, since 13.6 is closer to 14.
why did it turn out to be 13?
besides if we choose 14, we would be defenitly sure that no more than 14 children could have made $25. while if we choose 13 we might stil have a small possibility (because of the 0.6 left), that we have not chosen the largest possible number.
i'm really confused, please help me out.
UserIdTAG: 1202828
UserNameTAG: zam1991
CreateTimeTAG: 2013-03-06T08:51:48Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Did you read the explanation given when clicking the "Show Answer" button?
It says: "...the proportion is "no more than 1/5" (...) we have to pick 13 (not 14, as that is greater than 13.6)."
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-06T09:56:54Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks.
SecondChildUserIdTAG: 1202828
SecondChildUserNameTAG: zam1991
SecondChildCreateTimeTAG: 2013-03-06T18:44:41Z
SecondChildVoteTAG: 0
IndexTAG: 1371
TitleTAG: Courseware - Week 1 & 2
I went through and solved all the exercises and found them very interesting and concept building. The way of presentation of the statistical concepts and the way of linking them to gather information in most efficient way is simply marvelous.
Dr A K Singh, Bharuch, Gujarat, India
UserIdTAG: 974461
UserNameTAG: ncscaks
CreateTimeTAG: 2013-03-06T08:39:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1372
TitleTAG: Post answers??????
I do not find the answers to my post.
I have had asked a lot of questions since the course had begun but never found the answer to my post or do not know where to look for those post.
I could only see a list of post how to identify which one is mine.
Please help me out.
Thanks in advance.
Dhanashree V.
UserIdTAG: 948983
UserNameTAG: DhanashreeV
CreateTimeTAG: 2013-03-06T08:13:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You can follow them by clicking on the star in the top right corner of the post (which then turns blue). You can then find your posts by going to the Discussion tab. In the top left corner (right under Courseware, Course Info), you see "Show all Discussions". Click on the arrow next to it and choose "Following". Voilà!
If you want to find old posts you participated in, click on your user name (blue) at the top of this page (right under your question title). It will show you all posts you wrote.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-06T08:17:50Z
FirstChildVoteTAG: 1
IndexTAG: 1373
TitleTAG: paxho
Please explain question 3
UserIdTAG: 1214065
UserNameTAG: fjluquem
CreateTimeTAG: 2013-03-06T07:46:27Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Look through past posts. This has been covered too many times already.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T07:51:33Z
FirstChildVoteTAG: 0
IndexTAG: 1374
TitleTAG: Arrrrg!!!!!!!!
my cat just jmped on my laps: laptop is there to = she typed an answer in set6 ex1 and checked it at least twice (I don't know how.....but cats will rule the world eventually):
How to lose 2 points: own a cat!(I have 2)
FGS.......2 points
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-03-06T07:43:33Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: ![proof by picture][1]
soooo easy to work like that!!!
[1]: https://edxuploads.s3.amazonaws.com/13625561641343636.jpg
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-03-06T07:50:34Z
FirstChildVoteTAG: 2
SecondChildTAG: It's ok, she is is cute, you will forgive her eventually :)
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-06T10:58:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Sweet!
SecondChildUserIdTAG: 387767
SecondChildUserNameTAG: JanDE
SecondChildCreateTimeTAG: 2013-03-06T11:07:50Z
SecondChildVoteTAG: 0
FirstChildTAG: You can teach statistics to your cats ;-)
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-06T10:09:16Z
FirstChildVoteTAG: 2
SecondChildTAG: well, she got the answer wrong by 10...she might be learning statistics already!
I love her, she wants to be cuddled and hugged all the time and I m ok with that.
The thing is: she is to silent to see/hear her coming! I would have check where the cursor point to, and moved it far away from "check" ^^;
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-03-06T11:58:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Sounds like a great opportunity to work out a bound for cat-related points loss.
Will be even more interesting later in the course when we work on probabilities.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-06T11:46:34Z
FirstChildVoteTAG: 1
SecondChildTAG: in this case: 2 points!
100% of my lost points are cat-related!
still managed to have the remaining points like that:
![enter image description here][1]
![enter image description here][2]
pen and paper style!!!!
[1]: https://edxuploads.s3.amazonaws.com/13625740661343633.jpg
[2]: https://edxuploads.s3.amazonaws.com/13625740901343619.jpg
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-03-06T12:48:50Z
SecondChildVoteTAG: 0
IndexTAG: 1375
TitleTAG: I was working on first assignment but it shows me a timer off msg at 22:17 on Feb 28 rather it's time of closing was Feb 28 at 23:30
waiting for reply of my query.....
UserIdTAG: 624573
UserNameTAG: Wakade
CreateTimeTAG: 2013-03-06T07:37:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: you can't take last week sets... deadline was feb 28 at 23:30 GMT....
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-03-06T08:02:43Z
FirstChildVoteTAG: 0
IndexTAG: 1376
TitleTAG: great exercise
nice exercise............:)
UserIdTAG: 1370775
UserNameTAG: Ghishing
CreateTimeTAG: 2013-03-06T07:28:03Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1377
TitleTAG: Answers?
Once i submit my answers, will I be able to find out what the answers are to the questions that I got wrong. We will never be able to learn from our mistakes if we don't know what our mistakes were.
UserIdTAG: 1304644
UserNameTAG: phillzRchamps
CreateTimeTAG: 2013-03-06T07:09:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: The answers to Homeworks are posted after the deadline has passed. You can access them by clicking the "Show Answer' button under the question. See Week 1 Homework for examples.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-03-06T07:11:59Z
FirstChildVoteTAG: 0
FirstChildTAG: > We will never be able to learn from our mistakes if we don't know what our mistakes were.
Well one mistake you made is not reading the course info, where you are told that answers are made available after the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T07:14:00Z
FirstChildVoteTAG: 2
SecondChildTAG: lol
SecondChildUserIdTAG: 902684
SecondChildUserNameTAG: DonCigarro
SecondChildCreateTimeTAG: 2013-03-06T22:29:13Z
SecondChildVoteTAG: 0
IndexTAG: 1378
TitleTAG: 3rd week will be started 4m when w8ing.....
nxt wk is a busy sdl.pls hurry up....
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-06T06:58:45Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Pardon? You can write in proper English here, it's not a text limited forum.
> nxt wk is a busy sdl.pls hurry up....
I think this says you want the Prof to get a move on, because you are busy (or your saddle is busy, or something is). That is not the Prof's problem. It's yours.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T07:04:42Z
FirstChildVoteTAG: 3
SecondChildTAG: I think it says: "Now extra work, I am bussing sidelines. People! Have you really written yet? Universal Peace...............
(though you might be right about the saddle)
SecondChildUserIdTAG: 392090
SecondChildUserNameTAG: aramin
SecondChildCreateTimeTAG: 2013-03-06T08:12:32Z
SecondChildVoteTAG: 0
SecondChildTAG: I weep for the human race
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-03-06T08:56:03Z
SecondChildVoteTAG: 0
SecondChildTAG: All good things comes to those who wait
SecondChildUserIdTAG: 1000472
SecondChildUserNameTAG: john79
SecondChildCreateTimeTAG: 2013-03-06T10:27:54Z
SecondChildVoteTAG: 0
SecondChildTAG: bt they said tht 6 feb is the dy so...why u guy reacting like tht. !!!!
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-06T11:53:10Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL, why indeed. Humanity is toast.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T11:55:24Z
SecondChildVoteTAG: 0
SecondChildTAG: If you want to make a statement, at least write it so everyone can understand it. Poor English is one thing I can cope with, and will do my best to understand. Absolute butchery of the language, I can't and won't attempt to understand.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T11:57:54Z
SecondChildVoteTAG: 0
FirstChildTAG: I am still not sure what sdl is - suddenly ? schedule ?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T14:39:07Z
FirstChildVoteTAG: 0
SecondChildTAG: it means Saddle I think he has been waiting 4 minutes for his saddle
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-03-06T17:22:39Z
SecondChildVoteTAG: 0
FirstChildTAG: Rifayat, is your keyboard broken?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-06T16:00:42Z
FirstChildVoteTAG: 0
IndexTAG: 1379
TitleTAG: My work is not being submitted
Prof under progress i see no work being completed on my behalf. is my answers not being submitted? is there an indication when work was submitted properly. Okay this time it submitted only two problems, but not the rest. For week one it saved 0. i want to be able to get credit. help please
UserIdTAG: 402800
UserNameTAG: chrisp339
CreateTimeTAG: 2013-03-06T06:52:54Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Are you submitting them by clicking the **Check** button?
You can only submit Week 2 exercises, Week 1 deadline has passed. The practice exercises do not count to your grade, so won't show on the progress bars.
**Edit**, as you have altered your post. As I wrote, Week1 has gone. You can't get credit for Week 1. Only Week 2. And time is running out. It's 7am in London, you have until 11.30pm - about $16\frac{1}{2}hrs$. Then Week 2 will be closed for submission.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T06:58:35Z
FirstChildVoteTAG: 0
IndexTAG: 1380
TitleTAG: Calculating SD- help!
Still confused when calculating the SD. I got the problem set right by thinking about it logically, but I want to be sure I can calculate it mathematically going forward. I understand how it was reached on the slides using the dollar example (where the deviation from the average squared was calculated for each number, then added up and divided to find the mean, and then the square root of that number was the SD). But do you have to calculate the deviation squared for each number in the set? I thought the equation was saying to find the mean of the biggest deviation above and below and then take the square root... but I seem to be doing something wrong. Help please!!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-06T06:32:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > But do you have to calculate the deviation squared for each number in the set?
Yes. For every number:
$SD=\sqrt{\dfrac{\sum(x_i - \bar x)^2}{n}}$
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T06:42:07Z
FirstChildVoteTAG: 0
IndexTAG: 1381
TitleTAG: Income (excercise set 1,problem 1a)
The same question in the text has two correct answers describing income as both continuous and continuous discrete variable, but in exercise 1, 1 mark has been deduced rejecting continuous discrete option. Avoidable dip in otherwise near 100 % score line.
UserIdTAG: 485682
UserNameTAG: arvindsingla
CreateTimeTAG: 2013-03-06T05:42:54Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1382
TitleTAG: Dr RK Saxena
I could not comprehend Problem No 3. Pl Explain.
UserIdTAG: 930448
UserNameTAG: drrajivsaxena
CreateTimeTAG: 2013-03-06T05:28:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Third problem deals with standard deviation. You have to compare both A and B series. Upto 25 datas both were same. The SD also the same. But when the remaining 5 score in data b is 100, it will reduce the standard deviation of set B. I believe from this explanation you may answer the question appropriately.
FirstChildUserIdTAG: 947298
FirstChildUserNameTAG: senthilkumaran
FirstChildCreateTimeTAG: 2013-03-06T05:56:07Z
FirstChildVoteTAG: 0
FirstChildTAG: > But when the remaining 5 score in data b is 100, it will **EDIT**. I believe from this explanation you may answer the question appropriately.
Giving the answer doesn't exactly help in understanding the concepts.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T06:20:00Z
FirstChildVoteTAG: 0
SecondChildTAG: you can take any hypothetical series with some edition according to the questions,
Then find their S.D, so have the nice sol.
hope for the best..
good luck :)
SecondChildUserIdTAG: 731839
SecondChildUserNameTAG: mebiostatistician
SecondChildCreateTimeTAG: 2013-03-06T07:08:33Z
SecondChildVoteTAG: 0
SecondChildTAG: To answer this question, one must understand what SD is. SD measures the spread of data -- the larger the spread, the larger the SD. Now let that sink in for a moment. It's huge, I know. :)
SecondChildUserIdTAG: 608203
SecondChildUserNameTAG: chauct
SecondChildCreateTimeTAG: 2013-03-06T09:29:12Z
SecondChildVoteTAG: 0
SecondChildTAG: >, one must understand what SD is
Yes, they must.
> Now let that sink in for a moment. It's huge, I know. :)
Like some egos here.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T09:54:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks all, my query is: what if the first 25 numbers are also 100s? the question does not specify the first 25numbers are different....can somebody expound on this?
SecondChildUserIdTAG: 1281184
SecondChildUserNameTAG: Otur
SecondChildCreateTimeTAG: 2013-03-06T13:30:15Z
SecondChildVoteTAG: 0
SecondChildTAG: > the question does not specify the first 25 numbers are different...
Then we must be reading a different question.
> what if the first 25 numbers are also 100s?
Then the answer will be different.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T21:15:53Z
SecondChildVoteTAG: 0
IndexTAG: 1383
TitleTAG: Technical Problem
I clicked twice on Check button in problem 6 and the save button disappeared. Is my answer saved? What do I do to save it? thanks
UserIdTAG: 1049940
UserNameTAG: skarora1
CreateTimeTAG: 2013-03-06T05:00:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: You don't have to save it. Because of the fact you clicked twice on Check button while you had just two possibles submissions. You can't change your answer anymore and it's saved :)
FirstChildUserIdTAG: 1151142
FirstChildUserNameTAG: Mohamed-Salmane
FirstChildCreateTimeTAG: 2013-03-06T05:03:16Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks very much
SecondChildUserIdTAG: 1049940
SecondChildUserNameTAG: skarora1
SecondChildCreateTimeTAG: 2013-03-06T05:04:44Z
SecondChildVoteTAG: 0
IndexTAG: 1384
TitleTAG: Progress: Graded Exercices ??
Hello everyone, When you click on ***Progress*** the last bar is ***Graded Exercices: X% of a possible 50%***. What does it means?
Because I had the feeling that I wasn't really bad in thi course but when I saw my low score, I'm a little disappointed but maybe I should not.
Have a good night or day depending on your location :)
UserIdTAG: 1151142
UserNameTAG: Mohamed-Salmane
CreateTimeTAG: 2013-03-06T05:00:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The graded exercises are worth $50\%$ of the total mark, with the remaining $50\%$ coming from the mid-term and final exams.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T05:05:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Ohh OK I get it thank you very much Susan Aust
SecondChildUserIdTAG: 1151142
SecondChildUserNameTAG: Mohamed-Salmane
SecondChildCreateTimeTAG: 2013-03-06T05:12:11Z
SecondChildVoteTAG: 0
IndexTAG: 1385
TitleTAG: Significance of Markhov's inequality ?
Considering the existence of Chebychev's Inequality, what is the significance of Markhov's inequality rule? Is there any area in mathematics were we have to depend on Markhov's rule & cannot use Chebychev's ? Thanks in advance for your response.
UserIdTAG: 1214737
UserNameTAG: Lipin
CreateTimeTAG: 2013-03-06T04:58:33Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: Chebychev's Inequality can only be used if you know the SD *and* the mean of a dataset. If all you know is the mean, then Markov's Inequality will at least give you an approximation, while Chebychev's won't be useable.
FirstChildUserIdTAG: 906684
FirstChildUserNameTAG: 2pter
FirstChildCreateTimeTAG: 2013-03-06T05:09:26Z
FirstChildVoteTAG: 1
SecondChildTAG: But if you have the list then we can always get the SD right ? In real case scenario , don't we always need the list to get the Mean (excluding the question paper/assignment questions)
SecondChildUserIdTAG: 1214737
SecondChildUserNameTAG: Lipin
SecondChildCreateTimeTAG: 2013-03-06T05:18:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh I see, you're talking about practical applications of Markov. You're right, most real-life situations would allow the SD to be calculated. I guess maybe the most important use of Markov's inequality was to prove Chebychev's inequality :).
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-06T05:36:23Z
SecondChildVoteTAG: 0
SecondChildTAG: If you have all the data, you don't need any bounds. You can say exactly what percent is in each intervals. The inequalities help you say things about data that have already been summarized. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-06T09:23:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Everyone . Just to make my understanding clear, Can you please provide a real world scenario where Markhov's inequality have to be used instead of Chebychev's ? Or is it as 2pter suggested the main use of Markhov's inequality is use to prove Chebychev's inequality.
Thanks
Lipin
SecondChildUserIdTAG: 1214737
SecondChildUserNameTAG: Lipin
SecondChildCreateTimeTAG: 2013-03-06T16:28:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Just to add a reason for my question . Professor, as you have mentioned in the lecture video the Chebychev's inequality is giving me a much accurate range as compared to Markhov's. Hence I was curious about a real world scenario where I would have to use Markhov's instead of Chebychev's.
SecondChildUserIdTAG: 1214737
SecondChildUserNameTAG: Lipin
SecondChildCreateTimeTAG: 2013-03-06T16:31:53Z
SecondChildVoteTAG: 0
FirstChildTAG: At times you may not have complete data and need to extrapolate. For eg if you want to do some statistical forensic work with incomplete information these could help. Many a time we may only have partial information for eg when analysing a paper where we will not actually have the complete data.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T07:44:55Z
FirstChildVoteTAG: 1
SecondChildTAG: Hello Prasanna... Highly appreciate your response. Just to make sure I understand the point correctly . In this example are you saying that only Mean can be calculated & not SD.
SecondChildUserIdTAG: 1214737
SecondChildUserNameTAG: Lipin
SecondChildCreateTimeTAG: 2013-03-06T16:35:09Z
SecondChildVoteTAG: 0
IndexTAG: 1386
TitleTAG: QUE 3
please explain question 3
UserIdTAG: 1271269
UserNameTAG: Wallabis
CreateTimeTAG: 2013-03-06T04:49:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 0
IndexTAG: 1387
TitleTAG: Course not started yet
Respected Sir
I, Swati Keshari, due to some unavoidable reasons could not be able to start my course. I wanted to start it from today. I wanted to know I can access the previous lectures and exercises which I have not completed to learn the course. If not, what is needed to be done.
Hope for your valuable concern and thanking you for the same.
UserIdTAG: 1298349
UserNameTAG: SwatiKeshari
CreateTimeTAG: 2013-03-06T04:47:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I am not the staff - but this might help to get you started.
**Lecture videos** are accessible to all registered students through out the course duration.
While you can still do **Exercise 1 and 2**, you will not be able to have your exercises graded as the deadlines have passed. However, the course offers two exercises that will be dropped from your final grade calculation, so in reality you haven't missed anything as you can do all remaining exercises without fail.
Also, go through the **Course Info** page before starting and also from time to time for important announcement.
Link to **on-line Textbook** references are provided as appropriate for the lecture. So start reading them after watching the videos. It has plenty of Example exercises too!
Refer to **Course Wiki** page for shared knowledge and resources.
Refer to **Discussion Forum** for wealth of information and rich learning experience.
All the best.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-06T05:24:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Not to discourage anyone but just hoping to clarify...
> Blockquote
However, the course offers two exercises that will be dropped from your final grade calculation, so in reality you haven't missed anything as you can do all remaining exercises without fail.
> Blockquote
>
> But week1 had 3 submissions, so since week1 deadline is past, one has already missed 3 submission out of 12.
Pl correct me if I am wrong.
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-06T06:56:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Correct Pradha. Missing all of week 1 means that you will have missed 3 exercises, of which only 1 will count as the other 2 are dropped.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-06T07:00:16Z
SecondChildVoteTAG: 0
IndexTAG: 1388
TitleTAG: Solution to Ex 4.11 in Textbook...
An addition to the explanation to Ex 4.11 in the textbook is:
It should be that a 4 or higher is 4/2.7 so a 4 or higher would be 1.48 times the mean. Therefore, 1/k = 1/1.48 = 0.675... = 0.68.
UserIdTAG: 1015153
UserNameTAG: ruthiegyll
CreateTimeTAG: 2013-03-06T04:19:41Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: The page gives you:
$\dfrac{2.7}{4}=0.675$
And you have:
$\dfrac{1}{k}=\dfrac{1}{\frac{4}{2.7}}=\dfrac{2.7}{4}=0.675$
BTW the question changes each time you refresh the page, so not everyone will see this exact question. I haven't seen it, just similar ones.
(and this comment is a bit out of context now that you changed your original comment)
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T04:39:10Z
FirstChildVoteTAG: 0
IndexTAG: 1389
TitleTAG: More exercise questions please!
These questions are great. Even when I think I know the answers I still get caught out.
UserIdTAG: 963896
UserNameTAG: melanie63
CreateTimeTAG: 2013-03-06T03:44:10Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Ooh in a high school class you would be thulped by the other students :) seriously, you can also Google problems in (whatever type of problem set tour want and there are oodles of problems. In fact I practice with some of these before I go to the actual exercises
and it does help
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T04:06:56Z
FirstChildVoteTAG: 0
IndexTAG: 1390
TitleTAG: Problem 2
Where can I find information about this problem in the Lectures, I got the above question correct, so I understand the process, but the negative numbers are throwing me off. I am not exactly sure If I understand clearly what a distribution is, although I understood how to find it in problem 1.
UserIdTAG: 1115165
UserNameTAG: Abbyjohnson
CreateTimeTAG: 2013-03-06T03:12:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Lecture 3.3.
I am not sure I can give an exact link without effectively giving away the answer.
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-06T03:20:45Z
FirstChildVoteTAG: 0
IndexTAG: 1391
TitleTAG: Explanation for Qs 3 & 6
Could you please provide explanation for questions 3 & 6?
Thank you
UserIdTAG: 1261388
UserNameTAG: PadmaUpp
CreateTimeTAG: 2013-03-06T02:26:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: A and B are the same series except for the additional 5 data points each of which is a 100. Since the mean of A series is 100, the difference between mean and each of the 5 extra observations in the B series must be zero. From here, think about the average of squared differences...
FirstChildUserIdTAG: 1139936
FirstChildUserNameTAG: SundarV
FirstChildCreateTimeTAG: 2013-03-06T14:56:08Z
FirstChildVoteTAG: 0
SecondChildTAG: Please consider 2 examples that contradict you:
1°) x1=x2=...=x25=0. You'll SD25=0 and SD30=37.27 >>> In conclusion it gets bigger.
2° x1=1000, x2=x3=...=x25=0. You'll get SD25=195.96 and SD30=180.28 >>> in this case it gets smaller.
SD is getting bigger or smaller, depending on the series x1,...,x25 you've used. I cannot draw a mathematical conclusion that is valid for absolutely all possible unknown x1, x2,..., x25. In conclusion answer 4 or 5 would be correct.
Can anybody else help?
SecondChildUserIdTAG: 108063
SecondChildUserNameTAG: LiviuG
SecondChildCreateTimeTAG: 2013-03-06T17:07:31Z
SecondChildVoteTAG: 0
IndexTAG: 1392
TitleTAG: Silly mistakes...
The down side of taking the test late at night...silly mistakes..
UserIdTAG: 1317628
UserNameTAG: sampatankar
CreateTimeTAG: 2013-03-06T02:23:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: you actually stole my line for summering my whole life!!!!!!!!!!!!!!!!
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-03-06T06:16:55Z
FirstChildVoteTAG: 1
IndexTAG: 1393
TitleTAG: extremely confusing
I am completely lost as to how the anser of 8.8 was found in the last problem, problem 7.
UserIdTAG: 987373
UserNameTAG: CarinaPereiraMPA
CreateTimeTAG: 2013-03-06T01:52:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: The histograms are based on density, showing percent per whatever.
So the 0-4 hour category contained 4*2.5 = 10% of the group
4-10 contained 6*6 = 36% of the group
15-25 contained 10*1 = 10% of the group
So the known part of the group is 10+36+10 = 56%, meaning that the "unknown" part is 44%
Since we know that the "unknown" is all in the 10-15 section, and that section contains 5 units, the height representing the density of that bar is going to be 44/5 =8.8
FirstChildUserIdTAG: 1019741
FirstChildUserNameTAG: BBF
FirstChildCreateTimeTAG: 2013-03-06T02:05:50Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you follow the explanation given when you clicked on Show Answer?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T03:12:33Z
FirstChildVoteTAG: 1
SecondChildTAG: This is a much more empowering answer. Was not aware of that functionality, and it's a really cool feature.
Now I know if I get a question wrong, I won't be stranded trying to figure out why. Really digging the structure of these tests.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-06T03:26:16Z
SecondChildVoteTAG: 0
IndexTAG: 1394
TitleTAG: Markov Inequality
I started watching the Markov Inequality video posted on the link to Practice for Exercise set 5.
http://statistics.berkeley.edu/~stark/SticiGui/Text/location.htm#markovChebychev
This lecture seems to be coming out of nowhere and I am wondering whether this link was given by accident or are we expected to learn that material in order to work on Excercise 5.
Right below that link it also says to stop once we get to 'Markov and ChebyChev's inequality'. I am a little confused.
UserIdTAG: 305272
UserNameTAG: shekharshan
CreateTimeTAG: 2013-03-06T01:51:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You need to learn Markov's and Chebychev's and stop at affine transformations
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T03:10:34Z
FirstChildVoteTAG: 1
IndexTAG: 1395
TitleTAG: Problem 7 - conceptual misunderstanding
I don't understand this "fund rising" stuff. Never messed with this before and have no idea how it works. Can anyone check my understanding of the problem in the following abstract example: me and my friend have pledged to rise $100, for the first month we raised $45 on average. Does this mean that we have to rise $55 more to keep our pledge?
10x!
UserIdTAG: 255838
UserNameTAG: EngineerHrenov
CreateTimeTAG: 2013-03-06T01:35:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: It means you raised an average of $ \$45 $. So how much did you raise in total? Look at the formula for the average.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T01:38:59Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you. Spent few minutes accurately translating "on average", "in average", "average of" and understanding the difference and meanings.
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-06T02:10:34Z
SecondChildVoteTAG: 0
IndexTAG: 1396
TitleTAG: Question Six is Worded Strangely
I'm not going to give the correct answer, but I feel like this question is written in such a way that generates an incorrect response even if the student understands the concept.
I don't have a problem with the question, but answers provided are redundant.
UserIdTAG: 1299221
UserNameTAG: coxen00
CreateTimeTAG: 2013-03-06T01:33:44Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: No it is not - there is a reason for such questions .
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T03:09:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Ay yi yi. The reason is to teach people like me to read the question directions more carefully. My bad.
SecondChildUserIdTAG: 1360369
SecondChildUserNameTAG: suechamp
SecondChildCreateTimeTAG: 2013-03-06T03:25:43Z
SecondChildVoteTAG: 0
FirstChildTAG: It's the kind of question that's designed to discourage the mechanical application of formulas without taking the time to understand the question. I love it!
FirstChildUserIdTAG: 387767
FirstChildUserNameTAG: JanDE
FirstChildCreateTimeTAG: 2013-03-06T10:22:44Z
FirstChildVoteTAG: 1
SecondChildTAG: Agree...
SecondChildUserIdTAG: 1050175
SecondChildUserNameTAG: Mdbi
SecondChildCreateTimeTAG: 2013-03-06T11:53:47Z
SecondChildVoteTAG: 0
SecondChildTAG: me too! But I have to admit, my first reaction was less happy.... :)
Clue to figure it out: think about what you *can* determine, and then think about how that helps answer the question.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-06T15:05:06Z
SecondChildVoteTAG: 0
SecondChildTAG: I like everything about the question until we reach the "select all that are correct" portion. I am unsure what relevance any potential "less correct" answer(s) would have.
SecondChildUserIdTAG: 10241
SecondChildUserNameTAG: bobok
SecondChildCreateTimeTAG: 2013-03-06T16:39:09Z
SecondChildVoteTAG: 0
IndexTAG: 1397
TitleTAG: q 6
yes 6.2/15.5= 40% commute equal or more than 15.5 therefore 60% of 82 =49 commute less than 15.5 miles, then given the other options will allso be true. Question is very nicely framed but I wonder about the options as all options are true.Why did I get 45 wrong?
UserIdTAG: 802995
UserNameTAG: sanjaydixit
CreateTimeTAG: 2013-03-06T01:18:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: There is an Honor Code and you must not post answers here whether they are right or wrong till the submission time is over.It would be advisable to delete this post and also see similar questions that have been posted about it.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T03:08:19Z
FirstChildVoteTAG: 5
FirstChildTAG: Prasannasimha, you very correct. We should follow up with the honor code. Though I got it wrong myself, I am very interested in seeing the solution after the date of submission expires! Wish you all the best!
FirstChildUserIdTAG: 1114838
FirstChildUserNameTAG: abass01
FirstChildCreateTimeTAG: 2013-03-06T11:32:21Z
FirstChildVoteTAG: 0
IndexTAG: 1398
TitleTAG: The last question...
Isn't the last question another Markovs? 60% of 82 is Bout 50...so why the wrong answer?
UserIdTAG: 1317628
UserNameTAG: sampatankar
CreateTimeTAG: 2013-03-06T00:59:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Because you are wrong. The misunderstanding of the concept has been the focus of **countless posts**. Have a look through some and see if it helps.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T01:05:51Z
FirstChildVoteTAG: 1
IndexTAG: 1399
TitleTAG: I love this course
Thanks to this course i discovered my inner love for Statistics. I'm studying Mechanical Engineering and i see so much potential in statistics in fatigue failure prevention criteria.
UserIdTAG: 1132721
UserNameTAG: Daniel_Vergara
CreateTimeTAG: 2013-03-06T00:54:08Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1400
TitleTAG: The pace is too slow
Please make practice sets and lectures available earlier. The course is moving a bit too slow in my eyes...
UserIdTAG: 1291617
UserNameTAG: Hultman21
CreateTimeTAG: 2013-03-06T00:48:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: This is a new course, with new material. The target audience is the novice, so time is allowed for understanding of the basic concepts. And the staff have their Berkeley responsibilities too.
If you have time on your hands, you could look back over forum posts to where the Prof addressed this issue.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T01:03:12Z
FirstChildVoteTAG: 3
SecondChildTAG: thats what I do and I am slowly improving the number of questions I am able to get correct
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-06T01:10:46Z
SecondChildVoteTAG: 0
FirstChildTAG: There are people struggling to meet the requirements.Since all 5 fingers are not the same it will be a difficult juggle. would recommend that if you find the pace too slow to do a bit of extra reading for fun !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-06T03:05:56Z
FirstChildVoteTAG: 0
IndexTAG: 1401
TitleTAG: Im Happy
I finished muy first week, and im very interesting by the learning that I have
UserIdTAG: 1318143
UserNameTAG: Rosaisabel
CreateTimeTAG: 2013-03-06T00:18:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi Rosaisabel! I am also learning so much! I love this class!
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-03-06T03:19:06Z
FirstChildVoteTAG: 0
IndexTAG: 1402
TitleTAG: Whe is week 3 commencing
Have finished my exercises on week 2, so enthusiastic when is week3 lecture commencing?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-05T23:44:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: When it is posted.
Are we really going to go through this every week? It is 4pm Tuesday in Berkeley.
Come back at 5pm Berkeley time tomorrow. Maybe then.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T23:51:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually it seems the uploading of new sets is not at 0.00 GMT .I wonder what time does the actual upload occur(Could pose a problem wrt the exam)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-06T03:04:31Z
SecondChildVoteTAG: 0
SecondChildTAG: That's exactly why everyone is getting so confussed with the times, the due dates are in gmt but the rest is not. I would very much like to know at what time the new week does start so that I don't have to keep checking. It would be great if we would know an approximate time, gmt or berkeley time, I don't care, I just would like to know, in some parts of the world the day is almost over by the time the new week gets released, so that can be a lot of checking the site later, If we would know around what time it is getting released it would be a lot clearer to al of us and we won't get all these posts about it.
SecondChildUserIdTAG: 804886
SecondChildUserNameTAG: marlasinger1470
SecondChildCreateTimeTAG: 2013-03-06T09:35:10Z
SecondChildVoteTAG: 0
IndexTAG: 1403
TitleTAG: DEAR STAFF
Question 4 is not clear. it says: "The line 10 | 358 should be read as 103, 105, 108. Select the option that is closest to the average of **these** weights."
where these could be interpreted as these three (i.e. 103, 105, 108) or the whole leaf and steam plot. Consequently the results would be different: 105.3 in the former and 143 in the latter.
Hence the right answer would be the first option (105) or the third one (140), respectively.
Please make it clear as, I have chosen 105 and is marked wrong. Could you please, help me in this matter ?
Thanks a lot…
UserIdTAG: 1172070
UserNameTAG: alpisteasea
CreateTimeTAG: 2013-03-05T23:05:46Z
VoteTAG: 3
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: There have been many posts about this already. Please read the discussion forum.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-05T23:37:05Z
FirstChildVoteTAG: 0
SecondChildTAG: I had the same problem. I understood from the reading that it referred to the line 103 105 108
SecondChildUserIdTAG: 1039433
SecondChildUserNameTAG: Evelyne2013
SecondChildCreateTimeTAG: 2013-03-06T04:16:40Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree! I had the same problem... :(
SecondChildUserIdTAG: 718288
SecondChildUserNameTAG: aerodriguez
SecondChildCreateTimeTAG: 2013-03-06T08:04:53Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree, this question is tricky.
SecondChildUserIdTAG: 51544
SecondChildUserNameTAG: oscarosero
SecondChildCreateTimeTAG: 2013-03-06T20:17:37Z
SecondChildVoteTAG: 0
SecondChildTAG: I made the same mistake!
SecondChildUserIdTAG: 1002932
SecondChildUserNameTAG: MarianOsman
SecondChildCreateTimeTAG: 2013-03-06T20:39:43Z
SecondChildVoteTAG: 0
SecondChildTAG: The question itself isn't tricky-- the wording is just a bit misleading. Could the staff reconsider the marking of this?
SecondChildUserIdTAG: 1002932
SecondChildUserNameTAG: MarianOsman
SecondChildCreateTimeTAG: 2013-03-06T21:05:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Misinterpretation usually happens when the command of the question is ambiguous; i got the same problem; i choose the 1st option (103, 105 and 108) for the interpretation; the use of expression **these** refers to the closest numbers not all in the whole leaf and steam plot, for that you should use **those**.
FirstChildUserIdTAG: 652456
FirstChildUserNameTAG: NMCFilho
FirstChildCreateTimeTAG: 2013-03-06T00:23:03Z
FirstChildVoteTAG: 1
SecondChildTAG: +1
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-06T01:31:07Z
SecondChildVoteTAG: 0
SecondChildTAG: If you are given instruction on how to "read" the stem and leaf plot why should you use that (thw instructions) when it is clearly mentioned further that you can use a computer etc etc and given the entire stem and leaf plot .
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-06T03:02:33Z
SecondChildVoteTAG: 0
IndexTAG: 1404
TitleTAG: Interesting...
These were simple, but congrats on some interesting questions!
S.
UserIdTAG: 1317628
UserNameTAG: sampatankar
CreateTimeTAG: 2013-03-05T22:41:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 0
IndexTAG: 1405
TitleTAG: i can't comprehend PROBLEM 1
my mind just don`t work. if the lover quartile is, for example hm..30 is it then upper quarile 90..and why do we need median in this prolblem. I can`t see point.
this ex set is hard one.
UserIdTAG: 1202387
UserNameTAG: Danny1412
CreateTimeTAG: 2013-03-05T22:07:11Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: The question gives you 3 bits of information. Symmetric around median, the lower quartile and the median. You need all these to calculate the IQR.
You are not given the upper quartile, you have to deduce what it is from the provided information.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T22:10:15Z
FirstChildVoteTAG: 1
SecondChildTAG: first you need to find the other quartile with this data: "symmetric " and then calculate the interquartile range with the formula q1-q3 ..and that all...
SecondChildUserIdTAG: 1062477
SecondChildUserNameTAG: alejandra-hd
SecondChildCreateTimeTAG: 2013-03-06T00:53:40Z
SecondChildVoteTAG: 0
SecondChildTAG: yea, great. I got correct answer, and keyword is, as you mentioned "symmetric" :) Thanks a lot SusanAust and alejandra-hd
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-06T01:10:25Z
SecondChildVoteTAG: 0
FirstChildTAG: please elaborate more for this question. I can get it too
FirstChildUserIdTAG: 521763
FirstChildUserNameTAG: taakondjo
FirstChildCreateTimeTAG: 2013-03-05T23:23:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Ok, I finally got it. The point is in the symmetric distribution. Google on topic what is happening with quariles whan data are normal distributed.
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-06T00:48:00Z
SecondChildVoteTAG: 0
SecondChildTAG: sorry for tipos
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-06T00:48:31Z
SecondChildVoteTAG: 0
FirstChildTAG: > Google on topic what is happening with quariles whan data are normal distributed.
Note though, that this has nothing to do with normality. Symmetric distributions don't have to be normal.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-06T01:08:12Z
FirstChildVoteTAG: 0
SecondChildTAG: ups.. that was lapsus. I meant " when data are symmericly distributed..my bad...Normal distribution is yet to come.
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-06T01:33:42Z
SecondChildVoteTAG: 0
SecondChildTAG: "A distribution of weights is symmetric about its median"
everything is in this sentence...
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-06T02:08:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Look up the video where Prof A talks about box plots. That will help a lot.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-06T08:19:53Z
SecondChildVoteTAG: 0
SecondChildTAG: look at the box plots for one and also plot the histogram to show you exactly how symmetrical the values should be on the graph, will you to expolate upper quartile
SecondChildUserIdTAG: 922541
SecondChildUserNameTAG: Onyenuobi
SecondChildCreateTimeTAG: 2013-03-06T14:56:35Z
SecondChildVoteTAG: 0
IndexTAG: 1406
TitleTAG: 3,4&6 problem i need exceplanation!
in problem 3 am little confused ..how can i knw if the enteries of the list A have bigger value than list B or not or even if is equal?? i choose the last one igot it wronge...(can someone help me)please!!
in problem 4 am also confused .. how can imeasure the averege from the distribution ?? please i need alittle hint !
in problem 6 : ok i thought about (average+6xSD)then i got confused ! little help please..thanks..
UserIdTAG: 920087
UserNameTAG: Areejo33
CreateTimeTAG: 2013-03-05T21:52:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: **Problem 3:**
You don't need to know the entries of list A. The average, and the knowledge that the entries are all different(and so can't for example, be all 100), are enough. Think: what changes, and what does not, between List A and List B? How do you calculate the SD in general? If you can answer these two questions then you can do the problem.
**Problem 4:**
You can see from inspection....the average in particular is easy, because both distributions are symmetric. From there, think about what the SD represents, and the answer should be obvious.
**Problem 6:**
You know about average+6*SD, good. Now what do you do with this information? Review lecture 4.3.
Hope this helps!
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T23:11:31Z
FirstChildVoteTAG: 2
SecondChildTAG: thanQ so much ! igot it correct!!
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-03-06T18:09:19Z
SecondChildVoteTAG: 0
FirstChildTAG: it is clearly stated that list A and B are the same except for the 100s... you have to read.
In P4, just keep in mind the calculation for SD and imagine which one it's gonna go higher, it is quite evident after a little thought.
In P6; just recall chevy. You have the formula, what was it said is left outside?
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-06T16:50:22Z
FirstChildVoteTAG: 0
SecondChildTAG: thanQ ! igot it correct!!
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-03-06T18:10:07Z
SecondChildVoteTAG: 0
IndexTAG: 1407
TitleTAG: Solved Exercise Sets
I have just posted solved Exercise Set 1 on wiki. Will post more as and when time permits. All are welcome to add/append.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/solutions-exercise-sets/
UserIdTAG: 300213
UserNameTAG: Artimehta
CreateTimeTAG: 2013-03-05T21:34:22Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1408
TitleTAG: Box plot?
Please help me to show how you calculate the values on the box plot? For this example.
UserIdTAG: 544247
UserNameTAG: akite
CreateTimeTAG: 2013-03-05T21:13:03Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 1
FirstChildTAG: http://www.brainingcamp.com/resources/math/box-plots/lesson.php
this link is helpful in understanding box plot.
FirstChildUserIdTAG: 1293941
FirstChildUserNameTAG: CHHAVIMEHROTRA
FirstChildCreateTimeTAG: 2013-03-06T00:58:02Z
FirstChildVoteTAG: 1
IndexTAG: 1409
TitleTAG: Solutions - online stat book
Hi, I'm not able to open solutions in the online stat book. I'm using Mozilla Firefox and when I click on the solutions link, it just takes me back to the top of the page. Is there anyway to fix this to view solutions? Thanks so much for the help.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-05T21:09:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Try using Chrome.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T21:17:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Yup. Chrome, Explorer both work with no issues.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-06T00:22:22Z
SecondChildVoteTAG: 0
IndexTAG: 1410
TitleTAG: I liked this:
The homework was actually very interesting. I did get 2 wrong answers, but that's because I did not read the question properly.
Carina P.
UserIdTAG: 987373
UserNameTAG: CarinaPereiraMPA
CreateTimeTAG: 2013-03-05T21:02:33Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1411
TitleTAG: Concept of Question 5: Please help
Can anyone please explain question 5 to me i.e...does it involve any calculation or can it be solved by concept alone?
I have submitted my answers already. I know you cannot take my word for it. If some one can just please explain if its a conceptual problem or calculation? I have an inkling that it is conceptual problem. Can someone please give a little nudge...?Its very frustrating ...I am obviously missing something basic. Thanks
UserIdTAG: 1237295
UserNameTAG: tanushree31
CreateTimeTAG: 2013-03-05T20:40:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 4
FirstChildTAG: without giving it away, its a bit of both, you can calculate it, but if you stick with Markovs Inequality youll get the answer by observation
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-03-05T20:50:18Z
FirstChildVoteTAG: 0
SecondChildTAG: Markov's Inequality. M/x
SecondChildUserIdTAG: 1198170
SecondChildUserNameTAG: KAG7
SecondChildCreateTimeTAG: 2013-03-05T22:51:01Z
SecondChildVoteTAG: 0
SecondChildTAG: M/x or 1/k?
SecondChildUserIdTAG: 997742
SecondChildUserNameTAG: phamv
SecondChildCreateTimeTAG: 2013-03-06T20:39:24Z
SecondChildVoteTAG: 0
FirstChildTAG: "Refer again to the distribution in Exercise 3. You can assume that the ages are uniformly distributed within each bar. The median age was 26 years and the average was 27.23 years. Fill in the blank with the appropriate option: The percent of mothers who are above the average age is"
I don't know if this is the question you are referring to. I got this question wrong simplify because I was being careless and not pay close attention to the details of the question. The answer to this question is in knowing the difference between the Mean and the Median. You can review Lecture 3.4.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-05T21:09:50Z
FirstChildVoteTAG: 0
SecondChildTAG: > I don't know if this is the question you are referring to. I got this **post** wrong simplify because I was being careless and not pay close attention to the details of the **post**.
Might want to up that concentration level! ;P
SecondChildUserIdTAG: 969411
SecondChildUserNameTAG: McAlary
SecondChildCreateTimeTAG: 2013-03-05T21:36:15Z
SecondChildVoteTAG: 0
FirstChildTAG: I got a little bit confused about the word 'Exercise'in the first sentence of Problem 4 question,"Refer again to the distribution in Exercise 3".I think it should be 'Problem 3' instead of 'Exercise 3' for better Clarity.
FirstChildUserIdTAG: 715356
FirstChildUserNameTAG: Janefrances
FirstChildCreateTimeTAG: 2013-03-06T11:47:20Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree; I had the same momentary confusion.
I think even better would be to position the histogram before problem 3, and label it something like "use this histogram for problems 3 and 4" (or "use this distribution..." if the word 'distribution' is intended to be part of the problem; i.e., understanding the meaning of the word)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-06T15:13:49Z
SecondChildVoteTAG: 0
FirstChildTAG: Hey guys..Thanks for your responses... I think I was thinking exactly as you guys suggested, but made some foolish mistake.
Can you please tell me how exactly you answered the question, please?
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-03-09T08:11:05Z
FirstChildVoteTAG: 0
IndexTAG: 1412
TitleTAG: My first statisitcs experience:
It's the first time I get to study Statistics, and the profs and the staff manage to make pretty much everything look like really easy! Even though it's obviously an impression, it's so great to learn something in a way that does not disgust you from studying!!!!!
thank you so much!!!! Passing would be an awesome bonus, it would pump up my zero self-confidence (I answered a few times wrong thinking that I couldn't be right! I 'll keep on not trusting myself, but perhaps less than before :-)
Thank you guys!!!!!*from France*
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-03-05T20:25:29Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1413
TitleTAG: supplements
I read the supplements but don't have the math to follow them. Do we need them for the tests or exams?
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-03-05T19:54:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: no, we don't.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-05T20:15:20Z
FirstChildVoteTAG: 0
FirstChildTAG: No. This is for people who wanted to see some theory.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T21:09:35Z
FirstChildVoteTAG: 0
IndexTAG: 1414
TitleTAG: Certificate Awarded
how many scores(in % ) will i have to score for achieving a certificate
...........don't take it otherwise i posted this post just for my curiosity
and enjoying the course
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-05T19:17:11Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: According to the Progress section, it looks like passing is 35% - which seems wrong as HW along is worth 50% of your grade.
My gut would say go with the estimate of 65-70% for a passing grade.
FirstChildUserIdTAG: 117377
FirstChildUserNameTAG: KPEdwards
FirstChildCreateTimeTAG: 2013-03-05T20:08:44Z
FirstChildVoteTAG: 0
SecondChildTAG: HW... that would be?
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-03-05T20:17:25Z
SecondChildVoteTAG: 0
SecondChildTAG: HW = homework.
In the United States, passing is usually around 70%, or about a C, so I agree with KPEdwards in aiming towards the higher end of the spectrum. 35% just seems too low...
SecondChildUserIdTAG: 997742
SecondChildUserNameTAG: phamv
SecondChildCreateTimeTAG: 2013-03-05T20:58:35Z
SecondChildVoteTAG: 0
FirstChildTAG: > My gut would say go with the estimate of 65-70% for a passing grade.
Gut has nothing to do with it. As it says in the course info policy (which we all read, of course): 35%
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T21:05:52Z
FirstChildVoteTAG: 3
SecondChildTAG: One question: 35% in each exercise or in general mean?
SecondChildUserIdTAG: 515654
SecondChildUserNameTAG: esmaylinfrancini
SecondChildCreateTimeTAG: 2013-03-07T00:20:48Z
SecondChildVoteTAG: 0
FirstChildTAG: The passing grade in most countries is 33%. I guess that might be the reasoning for this.
FirstChildUserIdTAG: 1075168
FirstChildUserNameTAG: Ashish_Mamgain
FirstChildCreateTimeTAG: 2013-03-06T11:50:48Z
FirstChildVoteTAG: 0
SecondChildTAG: we have to keep 70% up to achieve a certificate
is that ??
SecondChildUserIdTAG: 1047894
SecondChildUserNameTAG: Iftikarbd
SecondChildCreateTimeTAG: 2013-03-06T21:30:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Certificate will be awarded if you score 35%.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T22:26:26Z
SecondChildVoteTAG: 0
FirstChildTAG: we have to keep 70% up to achieve a certificate
is that ??
FirstChildUserIdTAG: 1047894
FirstChildUserNameTAG: Iftikarbd
FirstChildCreateTimeTAG: 2013-03-06T21:30:30Z
FirstChildVoteTAG: 0
SecondChildTAG: Certificate will be awarded if you score 35%.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-06T22:26:30Z
SecondChildVoteTAG: 0
IndexTAG: 1415
TitleTAG: Thank you!
Though the course is far from over. I just want to say kudos to Prof. A and all of her staff for this wonderful course. I already took a Statistics subject a few years ago and I didn't understood the use and the importance of SD, average and other statistics terms which I now know thanks to this course!
This course made me experience what it feels like to study on Berkeley. Some might argue that it is very different from the normal classroom setting but the way the course was taught was frankly, easy but when I'm answering the exercise this is where I apply what I learned from the lectures and for me this is a very good avenue for self learners!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-05T18:40:09Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I was always upset during my statistic course in MBA. I do not understand why these are come out (i.e X1 , why square root to find SD, bound,etc. ). But I really need to understand statistic which is essential for my research. I still struggle with statistic. I took the Harvard course for health study last time but it remind me that I need more statistic knowledge. So I unregristered that course. Then I got to know about this course. It is very basic.
But it is very supportive because of your kind and hamble explanation in very details and your very wide knowledge. Your examples( i.e three heads, 3 years )make me clear understanding of the things you explained. You explained us even how it invented by whom which make me more interesting with thorough understanding. Although for you is very easy to explain that, for us if we have to find out these things, it will become more than 10 year. ;-P
Thank you very much. Please accept my apology that I cant get the full marks in the exercise due to my carelessness in English and not enough self-learning.
Thanks and regards,
Lai Lai
FirstChildUserIdTAG: 254503
FirstChildUserNameTAG: LaiLai
FirstChildCreateTimeTAG: 2013-03-06T01:54:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you Prof. Adhikari, it is a pleasure to study Statistics from you. I love the way you explain concepts simply and clearly, and in a logical stepwise fashion.
FirstChildUserIdTAG: 807428
FirstChildUserNameTAG: Brigitte2012
FirstChildCreateTimeTAG: 2013-03-08T14:13:42Z
FirstChildVoteTAG: 0
IndexTAG: 1416
TitleTAG: Love the teaching
I am just blown away by the style of teaching.Statistics has never been easy for me, wish I had a teacher like this at school.
Thanks edX
UserIdTAG: 403216
UserNameTAG: harineem
CreateTimeTAG: 2013-03-05T18:10:35Z
VoteTAG: 16
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3.5: Markov’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: I agree the teaching is very informative. Eventhough Professor A. also teaches us the calculations, the main focus here is to teach us to pay close attention to the minute details of the data. This is the data analysis course, it is very important that we know how to scrutinize the data closely. I must keep that in mind and train my brains to pay close attention to small details. Much like I have to train myself to think again after not having use my brains or think for a quite a while:) These courses are great because they force me to think. Train me how to think. And help me think. This ability to me is much more important than being able to do the calculation and answer the questions. I think this is what sets Elite Schools from average schools. Elite Schools teach us a way of thinking. Thank You so so much.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-05T20:30:22Z
FirstChildVoteTAG: 1
IndexTAG: 1417
TitleTAG: Supplements section - derivations posted
There is a new supplement button and the Prof has uploaded the derivations there.
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/algebra_mean_SD.pdf
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-05T17:43:34Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: how it can help me
FirstChildUserIdTAG: 1047894
FirstChildUserNameTAG: Iftikarbd
FirstChildCreateTimeTAG: 2013-03-05T19:17:52Z
FirstChildVoteTAG: 0
SecondChildTAG: If you want to study a bit more why we are using the formulae (derivations) that we are using in this program.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-06T17:40:33Z
SecondChildVoteTAG: 0
FirstChildTAG: Fantastic!
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-06T00:41:43Z
FirstChildVoteTAG: 0
IndexTAG: 1418
TitleTAG: late in joining course
Hi,
I'm late in joining the course. How can I get on track with it? If I solve the exercises now, will they still be valid?
UserIdTAG: 1157868
UserNameTAG: shreya2208
CreateTimeTAG: 2013-03-05T17:30:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: I have the same question therefore a prompr answer would be greatly appreciated. Thank you
FirstChildUserIdTAG: 1366559
FirstChildUserNameTAG: IrisB
FirstChildCreateTimeTAG: 2013-03-05T17:36:22Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, it is valid. 2 least scores are dropped. So if you try to get good grades in the rest of the exercises, you can easily get through. Good Luck!
FirstChildUserIdTAG: 100418
FirstChildUserNameTAG: balashyamala
FirstChildCreateTimeTAG: 2013-03-05T17:37:10Z
FirstChildVoteTAG: 0
FirstChildTAG: You can still catch up by viewing the earlier videos and still answering the exercise, though the first batch of exercises were due and I doubt you'll be given a score. Don't worry 2 of your lowest scores will be dropped!
FirstChildUserIdTAG: 892025
FirstChildUserNameTAG: gerickABM
FirstChildCreateTimeTAG: 2013-03-05T18:23:21Z
FirstChildVoteTAG: 0
FirstChildTAG: You cannot submit Week 1, as the deadline has passed. There are no extensions on exercises.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T21:03:41Z
FirstChildVoteTAG: 0
IndexTAG: 1419
TitleTAG: Do we have two chances to get the right answer??
I was wondering that if the check in button doesn`t disappear after giving an answer , does it mean that I have another chance to give the correct answer???
UserIdTAG: 1252686
UserNameTAG: Kanika79
CreateTimeTAG: 2013-03-05T17:16:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: Yes, there will be 0 of 2 submissions, 0 of 3 submissions, which will have a check button. It will say it right below the check button. But there are some that you just have one try and it will say final submission.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-03-05T18:49:01Z
FirstChildVoteTAG: 0
SecondChildTAG: i dont have a check button at all. I have reloaded the page 3 times
SecondChildUserIdTAG: 564178
SecondChildUserNameTAG: pompaii
SecondChildCreateTimeTAG: 2013-03-07T00:23:32Z
SecondChildVoteTAG: 0
FirstChildTAG: This post might help explain
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5132e6f49788382a0000003a
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T21:02:57Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks! This was helpful! It suddenly occurred to me that perhaps I needed to click "final check" on every question to submit my answer, regardless of whether I got it right the first time (and I haven't been doing that!). What a relief :)
SecondChildUserIdTAG: 1181793
SecondChildUserNameTAG: nabraham1
SecondChildCreateTimeTAG: 2013-03-09T01:08:53Z
SecondChildVoteTAG: 0
IndexTAG: 1420
TitleTAG: problem 7: found a round result
did I screw up because they ask cents, so even if I found xxxx$ in average I have to write xxxx.x?
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-03-05T17:05:39Z
VoteTAG: 2
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: If you find exactly xxxx.00 as your answer, then you can write xxxx.
If you find xxxx.x0, you have to write it at least as xxxx.x and round.
Any more decimals than that, you need to write at least xxxx.xx and round.
In the case of this particular problem, I can tell you that you'll need xxxx.xx.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T17:11:40Z
FirstChildVoteTAG: 1
SecondChildTAG: Absolutely correct. Correct answer is not a whole number I now nailed it. Note is how much each member has to raise on average to the additional $5200 already pledged
SecondChildUserIdTAG: 722050
SecondChildUserNameTAG: aswanifj
SecondChildCreateTimeTAG: 2013-03-05T17:23:01Z
SecondChildVoteTAG: 0
SecondChildTAG: 12 members raised $5200. 12 members have to raise what's left to raise. Taht's how I understood the pb, and my calculator gave me a round number... cause X.333333333333..... minus Y.33333333333333 returns a round number. So my logic is wrong...
Also checked with the other way ((x - y)/n) ==>gave me a round number....
I'm probably the most stupid person on earth
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-03-05T17:36:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I am struggling with this problem as well. Just to double check, there is not period of time that is indicated. Does this make a difference?
SecondChildUserIdTAG: 1268646
SecondChildUserNameTAG: sburris
SecondChildCreateTimeTAG: 2013-03-05T23:26:25Z
SecondChildVoteTAG: 0
SecondChildTAG: **FaizaHarbi** - nah, we're all stupid at times, and in different ways... I've mis-read problems and gotten the wrong answer, mis-typed, etc, etc. Just learn from it so you won't make the same mistake again. (I keep thinking I'll run out of ways to make a mistake, but I seem to just come up with new creative mistakes... :)
**sburns** - no; the time is immaterial. you're just calculating the average amount each person needs to raise so the final amount raised is $100000.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-06T06:33:59Z
SecondChildVoteTAG: 0
IndexTAG: 1421
TitleTAG: Will the Probability course follow after the completion of this course?
Hi friends, I have a question
Will Probability course follow as soon as we complete of this course (OR) do we have to wait for sometime again?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-05T16:46:54Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I have just now finished the second week's assignment and I have found this course to be a *very* interesting experience! The professors and everyone else involved have done a wonderful job, thank you very much! It will be great to have the remaining two parts of the course available on the EdX platform!
FirstChildUserIdTAG: 99863
FirstChildUserNameTAG: pramode_ce
FirstChildCreateTimeTAG: 2013-03-05T17:00:16Z
FirstChildVoteTAG: 1
FirstChildTAG: According to previous comments, 2.2 will follow within a few weeks after 2.1 is done. 2.3 to follow 2.2
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-05T19:55:45Z
FirstChildVoteTAG: 1
IndexTAG: 1422
TitleTAG: Request to Berkley team from Dropping out student
Hi All,
I want to say that I learned this class very entusiastically to learn stats that too from prestigious Berkley. But, I am dropping out rather unwillingly and without any other opetions. Because, I am having a low bandwidth Right now, but each section of the class video costs 400 MB to download(2 week section 3). This avaerages about atleast 3-4 GB per month. My request for berkley is to design videos so that perople having low bandwidth can also use it. Like coursera, provides all the videos of a week within 110-120 MB. Please consider this.
Thanks,
Santhosh
UserIdTAG: 985263
UserNameTAG: santhosh_chn
CreateTimeTAG: 2013-03-05T16:41:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: I wonder why it takes 400Mb ... the video is mostly text and it should be possible to get very good compression for that! As you said, the coursera videos (of similar duration) are considerably smaller in size.
FirstChildUserIdTAG: 99863
FirstChildUserNameTAG: pramode_ce
FirstChildCreateTimeTAG: 2013-03-05T17:03:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Yeah I tried to download it from YouTube by following the link given in courseware.
SecondChildUserIdTAG: 985263
SecondChildUserNameTAG: santhosh_chn
SecondChildCreateTimeTAG: 2013-03-06T13:56:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Santosh there is an option to go to YouTube and download at a lower rate.Another option fr you is to use Android and download at low resolution with tubemate app.Incidentally I downloaded all the classes so far and it is around 60-100 MB per lecture at HD resolution(and you can download lower than that).
You can use some cheaper options and if you tell me where you are 9if in India ) I can make some suggestions)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T17:27:34Z
FirstChildVoteTAG: 1
SecondChildTAG: Yeah I tried to download it from YouTube by following the link given in courseware.
SecondChildUserIdTAG: 985263
SecondChildUserNameTAG: santhosh_chn
SecondChildCreateTimeTAG: 2013-03-06T13:56:16Z
SecondChildVoteTAG: 0
FirstChildTAG: I think you need to talk to edX about this. And it is a problem with every course.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T21:01:28Z
FirstChildVoteTAG: 1
SecondChildTAG: Yeah this problem exists. Previously I had the same problem with CS161.x also
SecondChildUserIdTAG: 985263
SecondChildUserNameTAG: santhosh_chn
SecondChildCreateTimeTAG: 2013-03-06T13:56:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Dear all,
As of week 3 in Stat2, and as of now for all of our other new courses, our videos have been undergoing a newer compression schema that is a better compromise between legibility and file size. (We do realize that many of you are not as blessed with bandwidth as we are here in Cambridge!) You should find these files much more easily downloadable.
We are working to go back and compress the file size of some of our older content, so please stay tuned. We are hoping to have all of the old content retranscoded to the new schema by the end of this week.
Our apologies for the delay in addressing this.
Sincerely,
the edX media team
FirstChildUserIdTAG: 469111
FirstChildUserNameTAG: romyr
FirstChildCreateTimeTAG: 2013-03-08T13:17:07Z
FirstChildVoteTAG: 0
IndexTAG: 1423
TitleTAG: Study Materials
Hi,
I am confused with videos I have seen in this week, 2nd Week. We have only 18 minutes of video overall and Prof. A says we will see about deviations and avaergaes in the video (2 and 3). But I don't find any other videos for that. Do we need to go through any other study materials?
Thanks,
Santhosh
UserIdTAG: 985263
UserNameTAG: santhosh_chn
CreateTimeTAG: 2013-03-05T16:29:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Did you see this
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/d4ff35dabfe64ed5b1f1807eb0292c73/435205e2089545c58823b5928809a1af/
There are two videos in this section and 4 in these
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/d4ff35dabfe64ed5b1f1807eb0292c73/33a93d61935a4fae93a7078ae1338dcf/
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T17:29:47Z
FirstChildVoteTAG: 0
FirstChildTAG: I also missed some lectures by prof A. Sometimes there is more than one lecture, as indicated in the title, for example Lec 3.1 - 3.3. After watching the introduction, you can go to lecture 3.1 by clicking on the right black arrow (triangle) at the bottom of the page (or at the top of the page where you see an overview of the videos). After lecture 3.1 you continue with lecture 3.2 and then 3.3.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-06T10:03:38Z
FirstChildVoteTAG: 0
IndexTAG: 1424
TitleTAG: Answers to exercises
Hi,
please could anyone point out where the answers to exercises are to be found after the submission date has expired.
thanks.
UserIdTAG: 1105307
UserNameTAG: takut
CreateTimeTAG: 2013-03-05T15:59:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Click on the show answer buttons
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T17:30:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Please note, the **Show Answer** button displays **YOUR OWN LAST SUBMITTED ANSWER**, not the answer to the exercise from eDX (unless you are in the Practice Exercise Set).
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-05T19:56:53Z
FirstChildVoteTAG: 0
SecondChildTAG: Why do you keep saying that? When I click on the "Show Answer" button, it shows my answer as well as the correct answer.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-05T20:27:42Z
SecondChildVoteTAG: 0
SecondChildTAG: I said this based on Past eDX course experience. If you have verified what you are saying then I should remove my post. I haven't had the chance to verify any wrong answer so far as all my answers have been correct for week 1. In week 2 Exercise, I do have wrong answer, but I will have to wait to verify if it shows the correct answer after the deadline is passed.
So, for now I will trust you if you are sure. Please disregard my post.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T20:38:12Z
SecondChildVoteTAG: 0
SecondChildTAG: I am assuming that you could get the correct answer for your wrong answer by using Show Answer button.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T20:39:53Z
SecondChildVoteTAG: 0
SecondChildTAG: When you click the "Show Answer" button you see the correct answer along with your answer. This holds true if you submit the correct answer, and it holds true if you submit the incorrect answer.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-05T20:51:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Many thanks for this update, merhutchin!
I request all to disregard my posts on Show Button.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T21:17:15Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks everyone, i thought we ought to get a more detailed explanation as to the answers so we know where we went wrong.
SecondChildUserIdTAG: 1105307
SecondChildUserNameTAG: takut
SecondChildCreateTimeTAG: 2013-03-11T05:35:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Artimehta is reliving the horror of the Show Answer button on PH207x. In that course, the Show Answer button was visible (if you got the question wrong) while the assessment was still in progress. When clicked, it would show the answer you just submitted, but greyed out. I think this was only for multiple choice questions.
The board would go into meltdown *every* week. "I was robbed!" type posts. Over and over. Just like the time drama here. But every single week. This is how it would appear - Left is submitted answer, Right is what Show Answer would show.
![enter image description here][1]
With this course Show Answer, after the deadline shows the solution and answer.
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13625170591343696.jpg
[2]: https://edxuploads.s3.amazonaws.com/13625171381343619.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T20:59:35Z
FirstChildVoteTAG: 0
SecondChildTAG: You are right Susan! But with this course I stand corrected (thanks merhutchin) and GLADLY withdraw my post!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T21:20:36Z
SecondChildVoteTAG: 0
IndexTAG: 1425
TitleTAG: can we see basic statistics of the course?
I just wanted to share a though. Maybe, it would be interesting to see some basic statistics of the course in different graphical format. For example, number of students taking this course- nationality, age, gender, percentile of the marks etc. If professor and the team do not think so, please ignore this message.
UserIdTAG: 867488
UserNameTAG: mkhaled
CreateTimeTAG: 2013-03-05T15:24:30Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I have also wondered if we students could know what aspects of our learning process are being studied via the MOOC.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-05T16:01:22Z
FirstChildVoteTAG: 0
SecondChildTAG: In one of the coursera classes I had taken (Prof.Martin Odersky's Functional Programming with Scala course), the detailed statistics were released after the class - there was even an interesting assignment were we were asked to analyze the data using some Scala code!
http://docs.scala-lang.org/news/functional-programming-principles-in-scala-impressions-and-statistics.html
It will be fun to have something similar for this course also!
SecondChildUserIdTAG: 99863
SecondChildUserNameTAG: pramode_ce
SecondChildCreateTimeTAG: 2013-03-05T16:55:59Z
SecondChildVoteTAG: 0
IndexTAG: 1426
TitleTAG: Mark Needed to Pass?
On the course info page, it states that the pass mark would be posted in the second week.
On the progress page, it says we pass if we have 35%.
Do we get a certificate if we have 35% like it says on the progress tab?
Thanks.
UserIdTAG: 683854
UserNameTAG: Flighthawk
CreateTimeTAG: 2013-03-05T15:01:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Yes
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T15:28:21Z
FirstChildVoteTAG: 1
FirstChildTAG: Will there be any recognition for getting higher than 35% or is it just a one-size-fits-all cert. for everyone over 35%? Any pass, merit, distinction etc?
FirstChildUserIdTAG: 901827
FirstChildUserNameTAG: clv101
FirstChildCreateTimeTAG: 2013-03-05T16:05:43Z
FirstChildVoteTAG: 2
SecondChildTAG: It's a one-size-fits-all certificate.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-05T16:32:52Z
SecondChildVoteTAG: 0
IndexTAG: 1427
TitleTAG: Answer keys for exercise sets 1, 2, 3?
Will the answer keys be posted for already-graded problem sets?
UserIdTAG: 1207247
UserNameTAG: ChristinaParadis
CreateTimeTAG: 2013-03-05T14:37:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You can find the answers by clicking the Show Answer button right beneath each question where the Submit button used to be before the deadline.
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-05T14:43:25Z
FirstChildVoteTAG: 1
SecondChildTAG: Please note, the **Show Answer** button **displays YOUR OWN LAST SUBMITTED ANSWER**, not the answer to the exercise from eDX (unless you are in the Practice Exercise Set).
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T19:59:03Z
SecondChildVoteTAG: 0
SecondChildTAG: My statement above is incorrect and I apologise for the same. I said it based on past Statistics course on eDX but obviously it does not seem to be true for this course.
My apologies to all once again.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T21:24:15Z
SecondChildVoteTAG: 0
FirstChildTAG: > Please note, the Show Answer button displays YOUR OWN LAST SUBMITTED ANSWER, not the answer to the exercise from eDX (unless you are in the Practice Exercise Set).
I don't know what happens if you get a question wrong. Does the Show Answer button appear? In which case, yes it will show your last answer not the correct answer. As we haven't been flooded with "Show Answer showed MY answer! I was robbed!!" posts, I assumed it wasn't activated.
The Show Answer button will show the answer and working, *after* the deadline. For example:
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13625167411343686.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T20:53:08Z
FirstChildVoteTAG: 0
IndexTAG: 1428
TitleTAG: Found lectures for 2.2 and 2.3. Other Edx course navigation help for Newbies.
Sad to say I've lost some ground not knowing what I didn't know. Here are a few tips to help new Edx users.
- Policies are not just 12 pages of legal speak as they usually would be on the internet. They put the course rules in there. The most important of which is that this isn't a go at your own speed course for people who are working. There are strict work completion dates and times.
- GMT is in England :)Work submission times are all stated in GMT. Logical but frustrating if you made assumptions.
- When you click on a lecture series in courseware there are very lightly colored pictures of filmstrips at the top of the screen. You have to click on these to get to additional lectures you need to watch before trying the practice sets. I have been frustrated wondering what I missed in the lectures I did find.
- Sticigui = Textbook. The link in the Policys document is the textbook
- WIKI = Place to find course answers. Particularly in the FAQ. The "errata" link in the WIKI might help if your convinced you have the right answer but the software doesn't agree. There have been a few bugs.
UserIdTAG: 945143
UserNameTAG: joddde
CreateTimeTAG: 2013-03-05T14:27:01Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Maybe we should create a new button for "School of Hard Knocks" information. But sadly, the people who don't read the information already provided would not read that either!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-05T15:49:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Very true.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-05T20:30:11Z
SecondChildVoteTAG: 0
IndexTAG: 1429
TitleTAG: How to find the section size?
I understood how to find the average , but how do i find the section size @ 6:39 ? Could someone help me out in it please....
UserIdTAG: 1052716
UserNameTAG: maithri28
CreateTimeTAG: 2013-03-05T14:15:55Z
VoteTAG: 0
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.3: Comparing and combining averages
NumberOfReplyTAG: 1
FirstChildTAG: We did not know the section size until it was given to us. It can't be calculated. The example at 6:39 is to show how some answers (in this case, the average of the 2 sections) cannot be known without being given extra information (in this case, the 2 section sizes).
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-05T15:47:37Z
FirstChildVoteTAG: 2
IndexTAG: 1430
TitleTAG: Lecture Slides 3.3 & 3.4 Can Not Print
Please advise me on this trying to print. if someone can then can you email them to aimstermill51@aol.com
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-03-05T13:56:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: what's the problem? Can't you download the pdf files from
[https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Lec3.3.pdf][1] (Lecture 3.3)
and
[https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Lec3.4.pdf][2] (Lecture 3.4)
?
[1]: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Lec3.3.pdf
[2]: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Lec3.4.pdf
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T14:22:25Z
FirstChildVoteTAG: 0
SecondChildTAG: I am also having the same problem accessing both. When I click on the link the screen displays a blank white page.
Can someone from the teaching/admin team assist. Or if one of the students would be so gracious as to upload/send these to us? My email is m8rcus@gmail.com if that is possible. Thanks!
SecondChildUserIdTAG: 1354658
SecondChildUserNameTAG: m8rcus
SecondChildCreateTimeTAG: 2013-03-05T18:53:09Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem seems to have been resolved now. I hope it works for you Klionheart.
SecondChildUserIdTAG: 1354658
SecondChildUserNameTAG: m8rcus
SecondChildCreateTimeTAG: 2013-03-05T18:55:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Always worked for me :)
I hope it works for aimster ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T19:07:20Z
SecondChildVoteTAG: 0
FirstChildTAG: > When I click on the link the screen displays a blank white page.
Try right clicking and either saving or open in a new tab.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T20:28:49Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually the same happened for me in exactly these two pdf's and I finally opened them in firefox and could download them today(Wasn't working in both Chrome and Firefox yesterday) Not sure why because the other slides were downloading but the funny thing was the videos stopped working on Chrome for these tow questions and an error message was getting posted !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-06T03:13:08Z
SecondChildVoteTAG: 0
IndexTAG: 1431
TitleTAG: Exercise 4 Problem 8
Hi Ani,
the question statement is appear to be confusing , whether all 32 house individual cost 834000 , and all house cost decreasing to 819000 ????
if only one house cost 834000 , am wondering how can we calculate average??
UserIdTAG: 1084077
UserNameTAG: Dharam17
CreateTimeTAG: 2013-03-05T13:26:03Z
VoteTAG: 5
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 5
FirstChildTAG: Refer Lecture 3.2. You will get your answer.
FirstChildUserIdTAG: 273912
FirstChildUserNameTAG: raj2691
FirstChildCreateTimeTAG: 2013-03-05T13:35:53Z
FirstChildVoteTAG: 1
SecondChildTAG: #8 - Question could have been phrased more appropriately.
SecondChildUserIdTAG: 1129606
SecondChildUserNameTAG: navneetshrivastava
SecondChildCreateTimeTAG: 2013-03-06T17:52:12Z
SecondChildVoteTAG: 0
FirstChildTAG: You don´t have to calculate the average, only how the average changes when the price of the house is lower. The lecture explains that quite well.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-03-05T14:15:19Z
FirstChildVoteTAG: 0
FirstChildTAG: You only know the price of 1(one) house. That price was 834000, but then is lowered to 819000.
You don't know how much the other 31 houses cost, nor do you care. You have the average.
Just remember how the average is calculated.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T14:24:49Z
FirstChildVoteTAG: 0
SecondChildTAG: But where in the question is the average given?
SecondChildUserIdTAG: 1081741
SecondChildUserNameTAG: ptstucky
SecondChildCreateTimeTAG: 2013-03-06T18:53:48Z
SecondChildVoteTAG: 0
FirstChildTAG: From the original data the total price for all 32 homes is the average x 32.
if one house is priced differently from the original average then the average for all becomes (original total - cost of one house) / number of houses. If you wanted the average of the remaining 31 after one house is sold it is ((32 x original average)-the price house 1 was sold for) / 31.
FirstChildUserIdTAG: 895423
FirstChildUserNameTAG: joshea68
FirstChildCreateTimeTAG: 2013-03-05T14:47:50Z
FirstChildVoteTAG: 0
SecondChildTAG: Quite an easy question. Do not forget the negative sign.
SecondChildUserIdTAG: 722050
SecondChildUserNameTAG: aswanifj
SecondChildCreateTimeTAG: 2013-03-05T17:45:03Z
SecondChildVoteTAG: 0
FirstChildTAG: So many having issues with this question, yet practically an entire lecture is devoted to this sort of problem.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T20:28:04Z
FirstChildVoteTAG: 0
IndexTAG: 1432
TitleTAG: having so many issues with problems
i am confused with the problems. trying to do them but the wording is hard.
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-03-05T13:25:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1433
TitleTAG: Thank you very much for the supplements!!!
Thank you very much for the supplements, they are very useful to deepen into theoretical aspects.
UserIdTAG: 1219337
UserNameTAG: luisfrivera
CreateTimeTAG: 2013-03-05T13:24:25Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1434
TitleTAG: Practive problems
why are we not getting posts for practice problems or is it just me and we are?
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-03-05T13:16:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Probably because the answers are available right away, so people read them, understand their mistakes, and so can't go around accusing the Professor of getting the problem wrong as many they do with the Exercise Sets :D
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T14:16:59Z
FirstChildVoteTAG: 0
SecondChildTAG: Or because so very few people are actually doing them, perhaps? (Cynical, I know ...)
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-05T16:02:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Also possible.
My guess is little more optimistic, though. Pick the one you like more xD
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T17:20:54Z
SecondChildVoteTAG: 0
IndexTAG: 1435
TitleTAG: K=1
The instructor stated that if one is k steps beyond the average than the tails have maximum area, 1/(k^2). This makes sense if k is 2, 1/4, or k is 3, 1/9, etc.
However what if k is 1, 1/(1^2) = 1? This does not make sense.
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-05T13:05:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's the same thing as the example in the lectures with Markov and a k=2.
It's still logically sound(you are going to have at most 100% of the data inside any subset, that's obvious), but not very useful in practice :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T14:13:23Z
FirstChildVoteTAG: 0
IndexTAG: 1436
TitleTAG: The teacher is awesome!!!!!!!!!!!!!
I just want to say that Mam, you are awesome!!! It is a great experience to be your student and you are doing an excellent job by giving us an opportunity to be taught by you.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-05T13:04:57Z
VoteTAG: 17
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: May I also add that you are the coolest math related professor I've ever had the opportunity of.... well, can't say I've met you, but still, you're very cool!!!!!!
FirstChildUserIdTAG: 606994
FirstChildUserNameTAG: Makiblue
FirstChildCreateTimeTAG: 2013-03-05T14:56:04Z
FirstChildVoteTAG: 4
IndexTAG: 1437
TitleTAG: PROBLEM 3
I wonder is the option you gave us as correct:
The SD of List A is greater than the SD of List B.
really correct. I can think of the case when both lists A and and B have only elements: 100.
Then both of the SDs are 0, so the correct answer should have been
The SD of List A is **equal or greater** than the SD of List B. ?
Is it not so?
Thanks!
Sanja
UserIdTAG: 1254776
UserNameTAG: sanja7s
CreateTimeTAG: 2013-03-05T12:47:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: > List A has 25 **different** entries <...>
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-05T13:01:57Z
FirstChildVoteTAG: 0
FirstChildTAG: Read the Problem text again. List A has 25 **different entries**.
They can't all be 100 ;)
Also, **don't post answers to Exercises that are still graded!**
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T13:03:34Z
FirstChildVoteTAG: 1
SecondChildTAG: It is so simple . You need to know what happened to the denominator. I fthe denominator increases what happens to the value!!
SecondChildUserIdTAG: 341206
SecondChildUserNameTAG: laxmishac
SecondChildCreateTimeTAG: 2013-03-05T14:45:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Except in one very specific case, which is apparently the only one some people can think of when they answer wrong and try to grasp at straws to convince the world that *the Professor* got it wrong.
Except that case is covered and excluded by the text.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T17:24:04Z
SecondChildVoteTAG: 0
SecondChildTAG: It was initially wrong, but was discovered and fixed early in the piece.
Maybe some are just trying to show how clever they are at finding that one special case.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-05T20:26:18Z
SecondChildVoteTAG: 0
SecondChildTAG: I think her question was legit, I also thought about that case because it was one possibility. What I mean is I don't think anybody is just trying to prove they are clever or attacking the Professor.
SecondChildUserIdTAG: 1112364
SecondChildUserNameTAG: LeticiaA
SecondChildCreateTimeTAG: 2013-03-05T21:43:52Z
SecondChildVoteTAG: 0
SecondChildTAG: It was a general comment. It might not be the case here, but there are cases where this is happening (here and other courses). People will knowledge join up, and seem to take great pleasure in trying to show up the staff - and in many cases they (the know-it-all-students) are just wrong.
And sometimes they are correct, but they are correct because they are applying more advanced knowledge to a problem. They forget that beginners start with the basics. Which is why having the knowledge doesn't mean you will make a good lecturer - if you can't talk/think at a beginner level then you shouldn't teach 1st year courses.
And mistakes do happen.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-05T22:35:19Z
SecondChildVoteTAG: 0
SecondChildTAG: the thing is, if you believe you found that very special unique case... go and read again and look for anything on the text discarding it before claiming you found the exception to all...
I think we all thought about that case at first...
SecondChildUserIdTAG: 875061
SecondChildUserNameTAG: sabarda
SecondChildCreateTimeTAG: 2013-03-06T02:22:09Z
SecondChildVoteTAG: 0
IndexTAG: 1438
TitleTAG: Need help for Example 4-5: Applying Chebychev's inequality
From the text book given
> The mean weight of students in a certain class of students is 140 lbs., and the SD of their weights is 30 lbs. What fraction weighs between 90 lbs. and 190 lbs.?
>Solution. We cannot get an exact answer, but we can get a lower bound using Chebychev's inequality. The range from 90 lbs. to 190 lbs. is the mean, **plus or minus 50 lbs**. 50 lbs. is 1 2/3 times the SD of the weights, so according to Chebychev's inequality, the fraction of students who weigh less than 90 lbs. or more than 190 lbs. is at most
>1/(1 2/3)2 = 1/(1.6667)2 = 0.36 = 36%.
>Thus the fraction who weigh between 90 lbs. and 190 lbs. is at least 100% − 36% = 64%.
What got me in a bind is why the need to deduct the upper (190 lbs) and lower (90 lbs) range from them mean?
90 lbs is 3 sigma of SD, which gives a percentage of <= 1/3^2. 190 lbs is 6 1/3 sigma so the given percentage 1/(6 1/3)^2. So, to get the fraction of weight of 90-190 lbs, I'd assume one would just 100% - (1/3^2+1/(6 1/3)^2).
UserIdTAG: 1208879
UserNameTAG: deqalb
CreateTimeTAG: 2013-03-05T12:34:55Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: You need to figure how many SDs you are away **from the mean**.
90 lbs is *not* 3 SDs away from the mean. It's $\frac{140-90}{30}=1.67$ SDs away.
190 lbs is *not* 6.33 SDs from the mean. It's $\frac{190-140}{30}=1.67$ SDs away.
So your k is 1.67, and you can calculate that 36% of the weights is 1.67*SD=50 lbs away from the Average of 140. So, lighter than 90 lbs or heavier than 190.
You want to know how many are *between* 90 and 190, so take the total(100%) and subtract those outside your range(36% at most). The result is "at least 64%"
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T13:01:33Z
FirstChildVoteTAG: 3
SecondChildTAG: Thanks for the explanation. That made so much sense.
Guess I had Markov's and Chebychev's inequalities mixed up.
SecondChildUserIdTAG: 1208879
SecondChildUserNameTAG: deqalb
SecondChildCreateTimeTAG: 2013-03-06T15:09:18Z
SecondChildVoteTAG: 0
IndexTAG: 1439
TitleTAG: I failed my Excrise 6 so disadpointed..... :(
I failed my Excrise 6 so disadpointed..... :(
UserIdTAG: 802316
UserNameTAG: WeiPing
CreateTimeTAG: 2013-03-05T12:33:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Dont worry man.. better luck next time :)
FirstChildUserIdTAG: 1033651
FirstChildUserNameTAG: sarveshbhatt
FirstChildCreateTimeTAG: 2013-03-05T13:20:26Z
FirstChildVoteTAG: 1
SecondChildTAG: I learned something from it, so it was not a failure.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-05T13:29:31Z
SecondChildVoteTAG: 0
SecondChildTAG: (even though I did not get the points for my progress bar)
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-05T13:29:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Cheby's Inequality :)
SecondChildUserIdTAG: 1175129
SecondChildUserNameTAG: jarrodz
SecondChildCreateTimeTAG: 2013-03-06T02:00:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too
SecondChildUserIdTAG: 903383
SecondChildUserNameTAG: bchaihuaque
SecondChildCreateTimeTAG: 2013-03-06T13:01:25Z
SecondChildVoteTAG: 0
IndexTAG: 1440
TitleTAG: Timeline
I couldn't meet the timeline. Its not too difficult. Need to read the course in the link given, its very helpful.
UserIdTAG: 439794
UserNameTAG: alljohn
CreateTimeTAG: 2013-03-05T12:03:11Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 1441
TitleTAG: Chebychev's Inequality (CI)
Doesnt' specify 'above the average' it states 'away from the average' so doesn't that include both 'above the average' and 'below the average'? , so shouldn't the answer to Problem 6 be 1/2 of the value calculated using CI?, thanks, mark
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-03-05T11:39:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: The lectures address this.
Long story short: you don't know how the values are distributed, and cannot assume they are symmetrical. It's very possible that the left tail is completely empty of values, and so the full $\frac{1}{k^2}$ might lie beyond the right tail. Or vice-versa. Or anything in between.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T11:56:41Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks, yep I assumed normal distribution, Mark
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-03-05T20:21:18Z
SecondChildVoteTAG: 0
IndexTAG: 1442
TitleTAG: Lec 1.3
my ans was also wrong when i expressed with two decimal points 11.11
UserIdTAG: 1155509
UserNameTAG: Virgialberdi
CreateTimeTAG: 2013-03-05T11:21:39Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1443
TitleTAG: problem 1
how to solve the problem 1?
UserIdTAG: 1151619
UserNameTAG: rathina
CreateTimeTAG: 2013-03-05T10:58:31Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: How can we give the answer.as it is still under submission.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T12:08:27Z
FirstChildVoteTAG: 0
SecondChildTAG: thanx for the hint. Its easier to solve,if you follow Prof. Ani's method of compute. :)
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-05T18:16:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Watch lecture 3.4.
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-03-06T18:14:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Think of the values of the table as sub-averages.
There are, of course, 100% entries in total.
30% of the entries have average 5.
20% have average 8.
50% have average 15.
Now think about how the average is calculated.
If you still can't figure it out, you really need to review the lectures.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T12:19:15Z
FirstChildVoteTAG: 1
SecondChildTAG: I would like to think of the percentage of entries as the frequency of the values. So with 5 having a frequency of 30, making it a total of 150. Use the same calculations for the other values and you would get the total number of values for 100% of entries.
SecondChildUserIdTAG: 1196786
SecondChildUserNameTAG: Onome
SecondChildCreateTimeTAG: 2013-03-06T01:37:32Z
SecondChildVoteTAG: 0
SecondChildTAG: got it, thank you
SecondChildUserIdTAG: 1151619
SecondChildUserNameTAG: rathina
SecondChildCreateTimeTAG: 2013-03-06T02:23:50Z
SecondChildVoteTAG: 0
IndexTAG: 1444
TitleTAG: perfect score :)
read the slides carefully to get the answers
UserIdTAG: 1140772
UserNameTAG: pavelgupta
CreateTimeTAG: 2013-03-05T10:53:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 0
IndexTAG: 1445
TitleTAG: technical (?) problem with histograms
Hi all,
I have a problem seeing any interactive histogram table in the online "text book" pages.
I can see the "area from" and "to" boxes and the bars next to them but I cannot see the bins. I've tried with all the browsers I have. Does anyone have the same problem, or, even better, had it and sorted it out?
cheers,
Antonis
UserIdTAG: 1207733
UserNameTAG: AntoniusBlock
CreateTimeTAG: 2013-03-05T10:42:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi. Yes, I have the same, absolutly the same problem, posted here by me as Applets not functioning. No bins, just an empty box with two small boxes and bars in the lower part. I'm using actualised Firefox
FirstChildUserIdTAG: 1341242
FirstChildUserNameTAG: alesbadura
FirstChildCreateTimeTAG: 2013-03-05T11:15:43Z
FirstChildVoteTAG: 0
SecondChildTAG: Very strange.
You could try and clear you cache (Firefox Menu-->History-->Clear Recent History), sometime it helps with these kind of issues.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T12:04:05Z
SecondChildVoteTAG: 0
IndexTAG: 1446
TitleTAG: Hello from Pakistan
Hello Teachers & my fellow coursemates,
I have been a bit late in registering for this course. But like they say, its better late than never. Is there someone here who can walk me through quickly through the Week1 classes? And can someone also tell me what to do about my assignment submission, since I have missed the Week1 assignment deadline. Im glad I can submit my assignment tomorrow.
Thanks for all the help in advance,
Yousuf
UserIdTAG: 1360914
UserNameTAG: Ymarvi
CreateTimeTAG: 2013-03-05T10:38:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You are stuck at 0% grade for week 1 since it's past the deadline, but don't worry too much. The 2 lowest graded Exercise Set are dropped from your grade calculation, so that's only 1 of those that count. Just try and do well for the rest of the course and you'll be just fine :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T11:46:56Z
FirstChildVoteTAG: 0
FirstChildTAG: > Is there someone here who can walk me through quickly through the Week1 classes?
That's what the lectures are for. You need to watch them. If you have problems, read the forum to see if your question has already been asked and answered. If you still have a problem, ask.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T21:11:43Z
FirstChildVoteTAG: 0
IndexTAG: 1447
TitleTAG: Submissions past due-date?
I joined the course late, and was trying to complete the submissions for week 1 now. However, although I answered the exercises correctly, I cannot seem to submit them, and they do not occur in my progress tab.
Is this because the due-date has been exceeded?
Louise
UserIdTAG: 1359664
UserNameTAG: Llindbaek
CreateTimeTAG: 2013-03-05T10:25:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T11:05:57Z
FirstChildVoteTAG: 0
SecondChildTAG: I goofed up the first set of exercises. Didn't understand some of the problems and the inconsistency of % and rounding off that was required in some problems. So what should I do to understand those and catch up with the rest of the class. Am I allowed to continue with the second set of exercises despite the first phase fiasco? RK77
SecondChildUserIdTAG: 929545
SecondChildUserNameTAG: RK77
SecondChildCreateTimeTAG: 2013-03-05T14:30:57Z
SecondChildVoteTAG: 0
SecondChildTAG: You can and hurry up. The last time for submission is tonight (22.30 GMT)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T14:40:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually it's 23:30 GMT on March 6, so you still have more than 32 hours!
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-05T14:50:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Oops
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T15:47:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Please note. GMT. That's Greenwich Mean Time. Based in Greenwich, UK, as the name suggest, and often used as a reference for timezones around the world.
Washington time, for example, is GMT -5, or 5 hours earlier than GMT.
New Delhi time, as another example, is GMT +5:30, or 5 hours and 30 minutes later than GMT.
Sometimes GMT is confused with UTC, but that might lead to mistakes when DST(Summer time) in in effect, as GMT is *not* influenced by DST, while UTC is. Keep this in mind if you enter DST on the 10th, as many countries do.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T17:35:39Z
SecondChildVoteTAG: 0
IndexTAG: 1448
TitleTAG: Having a hard time to "visualize" the entire def of the mean:
No pb for the first part (how to calculate the average to put it that way), but if somebody could give me a good exemple of "the mean has the smallest sum of squared differences from members of the list" please?
Thxs
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-03-05T10:03:13Z
VoteTAG: 0
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.3: Comparing and combining averages
NumberOfReplyTAG: 1
FirstChildTAG: [0,1,2,3]. The average is 1.5.
What are the squared differences of the average from each member of the list?
$[(1.5-0)^2,(1.5-1)^2,(1.5-2)^2,(1.5-3)^2]$
or [2.25,0.25,0.25,2.25]. Sum these, you get *5*.
If you took another number, for example the median, 1.
What are the squared differences?
$[(1-0)^2,(1-1)^2,(1-2)^2,(1-3)^2]$
or [1,0,1,4]. Sum these, you get *6*. 6>5!
You can try any other number, you'll see that this "sum of squared differences from members of the list" is always bigger than what you get using the average of 1.5.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T11:43:10Z
FirstChildVoteTAG: 0
IndexTAG: 1449
TitleTAG: applets not functioning
Figure 3-2: Histogram of deviations of g measured at Piñon Flat Observatory - this (and all similar) applet is not showing anything when I enter data, only two bars down and the rest is empty. I'm using Firefox (actualised). Do I need some plug-in?
UserIdTAG: 1341242
UserNameTAG: alesbadura
CreateTimeTAG: 2013-03-05T09:59:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Strange, it works correctly for me with Firefox Nightly. Do you have Javascript enabled?
Also, you don't happen to use the NoScript plugin, do you? You'll have to allow the scripts from jquery.com if that's the case.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T11:33:09Z
FirstChildVoteTAG: 0
FirstChildTAG: No such a plugin but thanks anyway. There is another one with the same problem - posted as technical problem with histograms.
FirstChildUserIdTAG: 1341242
FirstChildUserNameTAG: alesbadura
FirstChildCreateTimeTAG: 2013-03-05T11:58:54Z
FirstChildVoteTAG: 0
SecondChildTAG: Try with Chrome.You need to allow Java
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T12:07:11Z
SecondChildVoteTAG: 0
IndexTAG: 1450
TitleTAG: problem 4
i solved it mathematically using the formula for SD,but apparently my answer is incorrect.can u check if there has been an error made from your side?
thanks.
UserIdTAG: 1344658
UserNameTAG: sreedharmenon
CreateTimeTAG: 2013-03-05T09:56:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: There is no error.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T11:26:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Correct. No error that I see. My answers matched...
SecondChildUserIdTAG: 895825
SecondChildUserNameTAG: JGonzalezGUS
SecondChildCreateTimeTAG: 2013-03-05T14:47:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Thats because probably you used excel to calculate the SD which uses (n-1) in calculating the variance.
SecondChildUserIdTAG: 1282346
SecondChildUserNameTAG: divyasaini
SecondChildCreateTimeTAG: 2013-03-05T22:47:50Z
SecondChildVoteTAG: 0
FirstChildTAG: There's no need to calculate, just think what is different from one to another and you'll see the answer is so evident. It just take a little time thinking, just be patient...
FirstChildUserIdTAG: 875061
FirstChildUserNameTAG: sabarda
FirstChildCreateTimeTAG: 2013-03-06T02:13:58Z
FirstChildVoteTAG: 1
FirstChildTAG: Read the textbook at a relaxed rate and make notes. There was indeed no need for calculation as Sabarda says.
FirstChildUserIdTAG: 344400
FirstChildUserNameTAG: carlallen
FirstChildCreateTimeTAG: 2013-03-06T16:43:05Z
FirstChildVoteTAG: 0
IndexTAG: 1451
TitleTAG: PROBLEM 2
I'M CONFUSED PLEASE HELP! WHAT IS A MODE AND THEN WHICH IS THE ANSWER?
UserIdTAG: 1258683
UserNameTAG: Tshuxx
CreateTimeTAG: 2013-03-05T09:24:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: What do you want to know. We can't read your mind !!:)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T09:26:05Z
FirstChildVoteTAG: 0
SecondChildTAG: What is a mode, then which is the answer?
SecondChildUserIdTAG: 1258683
SecondChildUserNameTAG: Tshuxx
SecondChildCreateTimeTAG: 2013-03-05T09:38:14Z
SecondChildVoteTAG: 0
SecondChildTAG: It's explained in [Lecture 3.1][1]
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/d4ff35dabfe64ed5b1f1807eb0292c73/bd343b7dcb2c4817bd1992b0cef66ff4/
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-05T09:41:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Mode is the number that has the highest frequency of occuring. For instance: 1,2,3,3,3,4,5,6,8,10.
Then the mode will be 3 (unimodal >> 1 mode).
Another example :
1,2,3,3,4,4,5,6,10.
The mode will be 3 and 4 (bimodal >> 2 modes)
Hope it helps :)
SecondChildUserIdTAG: 380986
SecondChildUserNameTAG: Yandi_lay
SecondChildCreateTimeTAG: 2013-03-05T10:13:09Z
SecondChildVoteTAG: 0
IndexTAG: 1452
TitleTAG: clarification on grade
Is there any grade difference when people use 1 submission instead of 2
UserIdTAG: 1247279
UserNameTAG: Masasa
CreateTimeTAG: 2013-03-05T09:10:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: No
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T09:25:06Z
FirstChildVoteTAG: 0
IndexTAG: 1453
TitleTAG: Question six needs explanation after the deadline
At this time I think the question six is incorrect. But I am just a student so I could be wrong. I don't want to give too much here because of honor code. But I do request the staff to explain this question a bit more after the deadline has passed.
UserIdTAG: 278932
UserNameTAG: Rahulsv
CreateTimeTAG: 2013-03-05T08:06:50Z
VoteTAG: 18
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: The logical answers seem to be.. wrongfully wrong! The educators should certainly explain afterwards.
FirstChildUserIdTAG: 759907
FirstChildUserNameTAG: ivassilis
FirstChildCreateTimeTAG: 2013-03-05T17:19:52Z
FirstChildVoteTAG: 1
SecondChildTAG: Oh, they will explain.
I expect it will involve basic logic, and the meaning of an AND statement when defining conditions. Start from there if you want to understand it earlier on your own ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T17:38:00Z
SecondChildVoteTAG: 0
IndexTAG: 1454
TitleTAG: ohhhhhhhhhhh
only one point is true. i got frustrated, may be am getting older and have old brain
i felt unhappy.
UserIdTAG: 689363
UserNameTAG: sehamballa
CreateTimeTAG: 2013-03-05T07:22:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: I believe the two exercises that scored the lowest would be excluded from the final grade. There's still hope.
FirstChildUserIdTAG: 1208879
FirstChildUserNameTAG: deqalb
FirstChildCreateTimeTAG: 2013-03-05T10:20:29Z
FirstChildVoteTAG: 0
IndexTAG: 1455
TitleTAG: A perfect score - question 6 is worth the try
Easily doable, just follow lectures
UserIdTAG: 1140772
UserNameTAG: pavelgupta
CreateTimeTAG: 2013-03-05T07:07:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 0
IndexTAG: 1456
TitleTAG: Normal Distribution
Hi guys!
I just wanted to check. Doesn't Markov's and Chebyshev's Inequalities only apply to normal distributions?
Thanks!!
UserIdTAG: 162825
UserNameTAG: Brunak
CreateTimeTAG: 2013-03-05T07:01:57Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: No. Can be any distribution. As the lecture said "in any list".
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T07:10:04Z
FirstChildVoteTAG: 0
FirstChildTAG: The beauty of Markov's and Chebychev is that it does apply to any list !! The normality assumption need not apply.Thatis why for eg assymetric tails can still be analyzed and symmetry of tails should not be assumed also.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T09:06:06Z
FirstChildVoteTAG: 1
IndexTAG: 1457
TitleTAG: How can I access the assignments?
Hi my teachers and my friends,
Could you please show me how to access the assignments? I want to know the requirements and the due date.
Thanks a lot!
Regard
UserIdTAG: 1224485
UserNameTAG: sithinhdf
CreateTimeTAG: 2013-03-05T06:50:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The blue alarm clocks on the Courseware page identify assessment items.
This link might help. Scroll down for instructions:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5129096f872f381f00000093
And then you need to go to the Course Info page and read the policies.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T07:01:13Z
FirstChildVoteTAG: 0
IndexTAG: 1458
TitleTAG: Suggestion to edX team...
Why not program the page such that the discussion board can be viewed only after completion of the given assignment. This way we can discuss the questions being correct or wrong in a more open manner and the so called **HONOR CODE** can be done away with. If this is possible then it will be more of ones skill in solving the question given, rather than scrolling down the discussion board for clue to the correct answer.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-05T06:47:37Z
VoteTAG: 6
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: LOL, I give you an A for persistence. The discussion board is for more than the assessments. If you have issues with a lecture, or practice exercise, you come and ask.
What you don't do is post answers. Quite simple really.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T06:53:32Z
FirstChildVoteTAG: 2
SecondChildTAG: Dear Susan, what you are saying is true to some extent. But what I am actually talking about is the discussion board related to the exercise sets (where students sort of argue over the answers, thus giving out clues in actually soling the questions)and not the one for lecture videos or practice exercises ( where students do ask questions related to the lectures). Does seem simple but is quite complex.
SecondChildUserIdTAG: 340510
SecondChildUserNameTAG: shngain
SecondChildCreateTimeTAG: 2013-03-05T08:46:26Z
SecondChildVoteTAG: 0
SecondChildTAG: I see this forum as a study group, like you have at any grade of school.
People get together to study and **do their homework** together, sometimes some of them get the answer before the others, and then they might help the others figure it out. I've never seen a professor even try to ban study groups for Homework, and they shouldn't. This kind of cooperative learning helps both the one who give the hints(explaining something to someone helps you remember it a lot better than just listening from a teacher, or studying yourself), and the ones who receive them, for obvious reasons.
Of course, like in a study group, there might be some lazy people who convince others to just do the homework for them, and don't put any effort it in. It's an unfortunate reality...but in the end, it's their loss, since they don't really *learn* anything.
I would probably be favorable to a partial lock-down of the board while the Midterm and Final are active, however. You don't do study group during a classroom exam, after all.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T10:11:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the A, but it was not me posting as anonymous. Other people have similar views of the situation.
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-05T12:10:12Z
SecondChildVoteTAG: 0
FirstChildTAG: The new age paradigm for the touchy feely age-
Teachers are wrong - Students are always right.If you get an answer wrong - its the Teacher's fault or the question is always wrong and/or not enough attempts were allowed ;)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T09:08:59Z
FirstChildVoteTAG: 2
SecondChildTAG: Oh, couldn't agree more.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-05T09:59:16Z
SecondChildVoteTAG: 0
SecondChildTAG: But of course! Mistakes do happen, but we all know that rank beginners know far more than any lecturer!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-05T10:00:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Note I used simple statements for the teachers and absolute for the students ;) That is a "Bound" ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T12:10:12Z
SecondChildVoteTAG: 0
FirstChildTAG: Learning is each ones responsibility. No matter if the complete answers were posted by anyone, each one should solve honestly the home work by themselves. This is the only way to learn.
FirstChildUserIdTAG: 1262270
FirstChildUserNameTAG: JPorcel
FirstChildCreateTimeTAG: 2013-03-05T23:14:30Z
FirstChildVoteTAG: 3
IndexTAG: 1459
TitleTAG: Case when SD is larger than Mean
In Last example If we face case where the SD is Much larger than the mean.then ,Morkov's bound will better bound than the Chebychev's bound .As in Case on Age spread if SD is 50 and average is still 20 then Markov's bound holds more no of data set for K=2 on range of 20 to 40.
Please justify if SD can't be that much big.
UserIdTAG: 739769
UserNameTAG: Abishek_raj
CreateTimeTAG: 2013-03-05T04:23:55Z
VoteTAG: 2
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 4
FirstChildTAG: Markov's Inequality does not use SD.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-05T05:08:38Z
FirstChildVoteTAG: 0
FirstChildTAG: Your instinct that the SD can't actually be that big is correct. I'm sure there's an elegant way to write this as an algebraic proof, but I'll try to do it in words:
When dealing with non-negative datasets, the SD can never be greater than the average. To illustrate this, consider a simple dataset of {0,0,100,100}. In this case, the average is 50, and so is the SD. Is it possible to move the datapoints to increase the SD while keeping the average the same? No. Why? Because to increase SD, the datapoints must move farther away from the average. The "0" datapoints can't move any farther from the average because it has to be a non-negative dataset. The "100" datapoints could increase and move further from 50, but doing so would necessarily increase the average.
So in your example, given an average of 20, the SD could never be greater than 20.
Now, who wants to summarize that in a few lines of math instead of a whole paragraph :)?
FirstChildUserIdTAG: 906684
FirstChildUserNameTAG: 2pter
FirstChildCreateTimeTAG: 2013-03-05T05:10:13Z
FirstChildVoteTAG: 0
SecondChildTAG: After thinking about it a bit more, I realized that my statement is wrong. It is possible for a non-negative dataset to have an SD greater than its mean. In my above example, the dataset could be changed to {0,0,0,200}, which would preserve the mean at 50 while increasing the SD to about 86.6. I'll have to think about your scenario a little more...
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-05T05:29:46Z
SecondChildVoteTAG: 0
FirstChildTAG: > When dealing with non-negative datasets, the SD can never be greater than the average.
It can.
4,4,6,10,15,75
Mean 19, SD 25.34
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T05:25:21Z
FirstChildVoteTAG: 1
FirstChildTAG: Nowhere is said that Chebychev's bound is *always* better than Markov's. It just was the case for the examples *we* saw.
And you found the instance where the situation is reversed. Good job!
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T10:16:06Z
FirstChildVoteTAG: 0
IndexTAG: 1460
TitleTAG: found this thought it might help. It worked for me
What Sigma Means
Sigma is a mathematical term used interchangeably with the phrase "standard deviation." The word "sigma" comes from the Greek symbol used by mathematicians to represent the standard deviation. The standard deviation of a sample is a measure of the average variability between the mean, or average, of a sample or population, and the individual data points that make up the total sample. The standard deviation of a sample has a numeric value.
For instance, if the mean of a process is 100, the standard deviation might be 25. Any values falling between 75 and 125 would be said to fall within plus or minus one standard deviation, or one sigma.
Calculating The Standard Deviation
The standard deviation of a sample can be calculated as follows: First, calculate the mean of the sample. The mean is calculated by adding all the numbers in a set -- for this example we will use 1, 2, 3, 4, and 5 as our sample points -- and dividing the total by the number of samples. So 1+2+3+4+5 = 15. Divide 15 by the 5 data points and you get a mean of 3.
Next, calculate the variance: This is done by subtracting each sample point from the mean, squaring that number, then taking the average of those squared numbers. So 1-3 = minus-2, which when squared becomes 4, 2-3 = minus-1, which squared becomes 1, and so on. The sum of squares of this sample is 4+1+1+1+1 = 8, and the average, or variance, is 1.6.
Finally, take the square root of the variance to get the standard deviation. The square root of 1.6 is 1.26. So the standard deviation of a sample containing the numbers 1, 2, 3, 4, and 5 is 1.26.
A sample size of at least 30 is recommended for most statistical analyses. The previous example includes only five observations for simplicity's sake.
Read more: The Difference Between 3 Sigma & 6 Sigma | eHow.com http://www.ehow.com/info_8211579_difference-3-sigma-6-sigma.html#ixzz2MdTSpbxq
The Difference Between Three Sigma and Six Sigma
The difference between three and six sigma is what percentage of the observations that make up the total sample or population will fall between the sigma level and the mean. The rule of "68-95-97" states that approximately 68 percent of the observations in a normally distributed sample fall within plus or minus one standard deviation from the mean, while 95 percent fall within two standard deviations, and just over 97 percent fall within three standard deviations.
In a sample, if the mean is 50 and the standard deviation is 5, minus three sigma would be 35 and plus three sigma would be 65. So if you are controlling your process to within three sigma of the mean, 97.44 percent of the observations in your sample will have values between 35 and 65.
If your process operate at a six sigma level, however, the percentage of points falling between your upper and lower limits increases to 99.99966 percent, meaning that only 3.4 out of every 1,000,000 observations would be outside the expected limits. In the previous example, minus six sigma would be 20 and plus sigma would be 80, increasing the spread between the upper and lower control limits from 30 to 100.
Tips and Warnings
When a given sigma level is talked about, whether it is one, three, or six sigma, the expression refers to plus or minus the given sigma level. So a sigma level of three would have a spread of six sigma total and a sigma level of six would have a spread of 12 sigma total.
The six sigma curve assumes a normally distributed sample population. In order to be able to assume normal distribution, your sample size must be 30 or more. Just because the variability in a process falls within six sigma does not mean that the process is tightly controlled. If a process has a small standard deviation, six sigma might represent only 10 percent variance from the mean, but if the standard deviation is large, six sigma might represent a control limit 80 percent higher or lower than the mean.
It's very cumbersome to calculate variance and standard deviation by hand. See the Resources section for easier calculation tools.
Read more: The Difference Between 3 Sigma & 6 Sigma | eHow.com http://www.ehow.com/info_8211579_difference-3-sigma-6-sigma.html#ixzz2MdTbNVCn
I hope this helps and doesnt violate the honor code in any way
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-05T04:19:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: i forgot to note the source so here it is http://www.ehow.com/info_8211579_difference-3-sigma-6-sigma.html
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-05T04:20:11Z
FirstChildVoteTAG: 0
IndexTAG: 1461
TitleTAG: How would I start to solve a problem like thisList A has 20 different entries, and its average is 75. List B has 20 entries, 25 of which
are exactly the same as List A; the remaining 5 are all equal to 75. Thus List
B looks like:
List A, 75, 75, 75, 75, 75
Pick the correct option:
The SD of List A is equal to the SD of List B.
The SD of List A is greater than the SD of List B.
The SD of List A is less than the SD of List B.
The SD of List A is not equal to the SD of List B, but there is not enough information to decide which of the two SDs is greater.
The SD of List A might be equal to, or greater than, or less than the SD of List B; there is not enough information to decide.
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-05T03:55:54Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: How is the SD calculated? Review that, and you'll have your answer ;)
It might help to throw some data for the first 20 entries and see what happens, if you can't visualize it theoretically. Just remember that they are 20 **different** entries.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T10:19:23Z
FirstChildVoteTAG: 0
IndexTAG: 1462
TitleTAG: Why is it ok to say over 80 is at most 25%?
It seems to me that:
1. 80 / 20 = 4
2. 1 / 4 = 25%
3. Proportion 80 or older is at most 25%
----------
1. 81 / 20 = 4.05
2. 1 / 4.05 = 24.69%
3. Proportion over 80 is at most 24.69% <- this seems more meaningful
If it is okay to say the proportion over 80 is at most 25%, is it okay to say 26% or 30% or even 100%? If so, shouldn't we still try to give the smallest percentage possible?
UserIdTAG: 1155072
UserNameTAG: babbler
CreateTimeTAG: 2013-03-05T03:18:11Z
VoteTAG: 1
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3.5: Markov’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: There are still infinite numbers between 80 and 81, so that's why we are giving the most accurate proportion.
FirstChildUserIdTAG: 1056095
FirstChildUserNameTAG: Guinto90
FirstChildCreateTimeTAG: 2013-03-05T03:40:35Z
FirstChildVoteTAG: 2
SecondChildTAG: Ahh... so saying 100%, for example, would be permissible and we choose to say 25% because the actual number would be 24.99999...%?
SecondChildUserIdTAG: 1155072
SecondChildUserNameTAG: babbler
SecondChildCreateTimeTAG: 2013-03-05T04:03:17Z
SecondChildVoteTAG: 0
SecondChildTAG: **babbler**, I agree with you that "at most 25%" is an inaccurate statement. The phrase "at most 25%" implies that it is inclusive of exactly 25%, and is the same as saying "less than or equal to 25%". I think it should be stated simply as "less than 25%", which saves us from having to use irrational numbers like 24.9999...%.
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-05T04:35:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Even an irrational number can also be "at most" 25% - It is not wrong.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T09:10:36Z
SecondChildVoteTAG: 0
SecondChildTAG: Oops missent - Even an irrational number obeys the "at most" or "no more than" 25 %
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T09:11:27Z
SecondChildVoteTAG: 0
SecondChildTAG: @2pter: and why couldn't it be exactly 25%? All it takes is a distribution where there are exactly **0 entries** for 80.
Unless you know for sure that it's not the case, then you have to include "exactly 25%" as a possible value.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T10:23:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Please bear with me while I illustrate my point:
Suppose the dataset we're discussing contains 100 people. Now let's put exactly 25% of the people (25 people) at exactly 80 years. How old must the other 75 people be for the average to remain at 20? The other 75 people must all be exactly 0 years old.
Now consider if you moved just one of those 25 people *just barely* over 80 years old. What happens to the average? It *just barely* goes up. But we could "counterbalance" the increase in age of one datapoint with a decrease in age at another datapoint. Can we decrease one of the "0" points? No, because the set has to be non-negative. Instead, we'd have to decrease one of the "80" points. But doing this reduces the number of people that are at or above 80 to 24 people, or 24%.
You might be thinking, hey, 24% isn't the 24.9999% you were talking about either! True, but let's look at more examples to clear that up.
Suppose instead the dataset was 1000 people. We could then put 250 people at 80 years, everyone else again at 0 years, and achieve the average age of 20 years. Again, we could move one of the 250 people above 80 years, but then another one of them would have to drop slightly to counterbalance, and we end up with only 249 out of 1000 people at or above 80, or 24.9%
Suppose the dataset is 10,000 people. Then the limit becomes 24.99%. Suppose 100,000 people. Limit is 24.999%. And so on and so forth...
So in other words, as the population size approaches infinity, the number of datapoints that can be above 80 approaches 25%, but never quite reaches it. That can be expressed as either 24.999999...%, or more simply, less than 25%.
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-05T15:44:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes. But no one ever said that all the other values are 0! You can have an average of 20 with a lot of possible distributions.
Some of those distributions might not have any value >=80 at all, others have a few =80 but none >80, others yet only values >80 but none =80. The rest of the values can be anything between 0 and 79, in a whole lot of possible combinations. And they will all have an average of 20 and a SD of 5 due to what the rest of the values are. You don't know, and you can't eliminate any of these possibilities.
Your reasoning is only valid in your particular case. In any other case, you will indeed be able to decrease one or more of the other values to reduce the average back to it's original value.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T17:56:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Then please give an example that satisfies all those conditions.
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-05T21:35:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Guinto I think that the concept of having many 0 (ceros) in a dataset is not valid from the math point of view and also the logical, you cant be 0 years old. From the math point of view I dont quite understad what a cero does to the distribution. It only adds 1 to the numerator of the fraction. The effect on the meen is exponential. Am I right?
SecondChildUserIdTAG: 1222835
SecondChildUserNameTAG: CatonElMenor
SecondChildCreateTimeTAG: 2013-03-06T01:34:38Z
SecondChildVoteTAG: 0
SecondChildTAG: There is such thing as being 0 years old. They're called newborns. Also, if age happens to be treated as a discrete variable (as it often is), all individuals up to but not including 1 year (so 4 month olds, 8 month olds, etc.) are swept into the "0 year old" category, just as anyone who is in between their 24th and 25th birthdays is called a 24 year old.
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-06T03:47:03Z
SecondChildVoteTAG: 0
IndexTAG: 1463
TitleTAG: Hint for solving Problem 6 Ex5
Problem 6
A firm has 82 employees. The average commute distance (that is, the travel distance from home to work) of the employees is 6.2 miles. How many employees have a commute distance of less than 15.5 miles? Select all that are correct.
What kind of formula should I look into?
UserIdTAG: 802316
UserNameTAG: WeiPing
CreateTimeTAG: 2013-03-05T03:15:01Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 4
FirstChildTAG: This is related to the Markov's inequality video at 3.5. You are asked to find the proportion of employees whose commute is LESS than 15.5 miles . You could find first the proportion of employees whose commute distance is more than that and deduce the answer from that.
FirstChildUserIdTAG: 897233
FirstChildUserNameTAG: makmanos
FirstChildCreateTimeTAG: 2013-03-05T04:36:12Z
FirstChildVoteTAG: 4
SecondChildTAG: See, firstly, find proportion of employees who have AT LEAST 15.5 miles commute dist. Then find no. of employees. But these are employees on the right side of 15.5 and we're asked those on the left side. So, remaining have to be on the left. Since their sum is constant (which constant?), at most 'k' to the right give at least 'constant-k' to the left. This play of at least and at most is simple if you understand how inequalities (especially, their signs) change with the algebraic operations like multiplication.
I hope that this helps.
SecondChildUserIdTAG: 1069242
SecondChildUserNameTAG: kdnyanesh
SecondChildCreateTimeTAG: 2013-03-05T14:56:35Z
SecondChildVoteTAG: 0
SecondChildTAG: what is the value of k? since avergae is 6.2 and we are starting at 15.5mi?
SecondChildUserIdTAG: 1203339
SecondChildUserNameTAG: Anamile71
SecondChildCreateTimeTAG: 2013-03-06T10:11:58Z
SecondChildVoteTAG: 0
SecondChildTAG: you can go through markov's inequality from the online text
SecondChildUserIdTAG: 611684
SecondChildUserNameTAG: reneeralte
SecondChildCreateTimeTAG: 2013-03-06T18:36:39Z
SecondChildVoteTAG: 0
FirstChildTAG: I think it's just a logic question. Think about what the average commute distance tells you or exactly how would you compute the average commute distance for 82 employees. Then try thinking of some of the cases that could yield such results. Of course, all 82 employees could have a commute distance hovering somewhere around the 6.2 miles, but what happens in other cases? What conclusion can you draw?
FirstChildUserIdTAG: 374593
FirstChildUserNameTAG: lf2223
FirstChildCreateTimeTAG: 2013-03-05T05:46:52Z
FirstChildVoteTAG: 1
FirstChildTAG: I have some doubt about the wording of this question. Suppose I have found (with markov inequality) at most 40 employees can have a commute distance of 15.5 miles or more. That means the boundary of employee count for less than 15.5 miles can only be between 82 and 42 (=82-40), right? Then, considering given options, is it meaningful to select "more than 25"? I think no. Take for example 26. It is not in the boundary (40,82), so I think we cannot select this option. Am I right or missing something somewhere?
FirstChildUserIdTAG: 872312
FirstChildUserNameTAG: oblomovian
FirstChildCreateTimeTAG: 2013-03-05T13:26:50Z
FirstChildVoteTAG: 1
SecondChildTAG: If as in your example at most 40 employees can have a distance of 15.5 miles or more than *ALL the others* must have a distance of less than 15.5 miles. I think your "boundary" is logically incorrect...
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-05T13:45:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Why is it not meaningful? isn't it the case that the sentence "if X is between 42 and 82 then X is more than 25" is true?
SecondChildUserIdTAG: 897233
SecondChildUserNameTAG: makmanos
SecondChildCreateTimeTAG: 2013-03-05T14:44:04Z
SecondChildVoteTAG: 0
SecondChildTAG: See, firstly, find proportion of employees who have AT LEAST 15.5 miles commute dist. Then find no. of employees. But these are employees on the right side of 15.5 and we're asked those on the left side. So, remaining have to be on the left. Since their sum is constant (which constant?), at most 'k' to the right give at least 'constant-k' to the left. This play of at least and at most is simple if you understand how inequalities (especially, their signs) change with the algebraic operations like multiplication.
So, there's nothing wrong with the wording, provided you understand the meaning of inequalities. It's not hard at all, just deliberate over it for a minute or two.
I hope that this helps.
SecondChildUserIdTAG: 1069242
SecondChildUserNameTAG: kdnyanesh
SecondChildCreateTimeTAG: 2013-03-05T15:00:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry, I obviously did not understand your question... Of course very number between 42 and 82 would be "more than 25" but that does not mean that every number bigger than 25 (say 26) **must** be between 42 and 82...
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-05T15:03:52Z
SecondChildVoteTAG: 0
SecondChildTAG: @senta Yes I agree with you. I was responding to the original poster (oblomovian) . I think the so called 'boundary' he/she calculates does not create any logical problems or contradictions. He/she can still chose answer(s) from the available ones based on this information.
SecondChildUserIdTAG: 897233
SecondChildUserNameTAG: makmanos
SecondChildCreateTimeTAG: 2013-03-05T15:10:59Z
SecondChildVoteTAG: 0
SecondChildTAG: @makmanos: I was also answering to oblomovians post just not writing fast enough. My answer wasn't referring to your comment...
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-05T15:19:42Z
SecondChildVoteTAG: 0
SecondChildTAG: After some thinking it is now clear, as it is simple logic. Thanks to everybody for clarification with comments.
SecondChildUserIdTAG: 872312
SecondChildUserNameTAG: oblomovian
SecondChildCreateTimeTAG: 2013-03-06T20:40:37Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't have this problem in my exercise but I think I can help. Let draw out the histogram and you start from (0 to 6.2). (6.2 to 12.4). (12.4 to 15.5). 15.5 - 12.4 = 3.1. 3.1 is exactly half that of 6.2. So if you go from 0 to 15.5 at an increment or the average of 6.2, you take 2.5 steps. Or K=2.5. This is all the hint I can give you for this problem because I can't give you the answer.
I just check the exercise again and realize that I miss this question. When I apply my method, I got the wrong answer. So ignore my advice.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-05T21:02:26Z
FirstChildVoteTAG: 0
IndexTAG: 1464
TitleTAG: only 35%?
do you really only need to get a 35 in this class to pass?
UserIdTAG: 1326696
UserNameTAG: Maxkim
CreateTimeTAG: 2013-03-05T02:41:42Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: That's what the course policy says.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T02:48:26Z
FirstChildVoteTAG: 0
FirstChildTAG: It's an introductory course. I'm pretty sure its follow-ups, Stat 2.2x and Stat 2.3x will have more realistic thresholds :)
I still encourage you to strive for as high a grade as you can, it'll mean better understanding of the concepts and an easier time in the next courses.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T10:26:26Z
FirstChildVoteTAG: 1
FirstChildTAG: 35% as a passing limit - it is a point indeed, but is that a problem or what? In fact, I thought that is encouraging for many to continue. Would you please share your views?
FirstChildUserIdTAG: 867488
FirstChildUserNameTAG: mkhaled
FirstChildCreateTimeTAG: 2013-03-05T15:28:27Z
FirstChildVoteTAG: 0
SecondChildTAG: 35% to pass is okay. But it would also be nice to recognise higher grades, award a merit for 60%, a distinction for 80% for example.
SecondChildUserIdTAG: 901827
SecondChildUserNameTAG: clv101
SecondChildCreateTimeTAG: 2013-03-05T22:34:11Z
SecondChildVoteTAG: 0
IndexTAG: 1465
TitleTAG: Problem 6
There must be some kind of problem in question 6. The average does not have to be a logical value, so the first option is incorrect (There must be an error....). The average is the typical value of the sample, so option 2 is correct. The total number of people living in the households are, in fact, 3480 (2.9 x 1200), so option 3 is correct. With the given information, there is no means to tell that the median is 2.9, so option 4 is incorrect. The problem is, I've marked the 2 and 3 options ant the test gave me incorrect for both. What am I missing here?
UserIdTAG: 931999
UserNameTAG: RenatoPassos
CreateTimeTAG: 2013-03-05T02:15:41Z
VoteTAG: 2
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: You're missing the honor code, apparently. And you're missing the discussion forum guidelines which ask you not to post answers before the due date, even incorrect ones. And you're also missing the previous posts where this question has already been discussed.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-05T02:21:58Z
FirstChildVoteTAG: 7
SecondChildTAG: Haha..
SecondChildUserIdTAG: 31529
SecondChildUserNameTAG: abbass
SecondChildCreateTimeTAG: 2013-03-05T16:52:58Z
SecondChildVoteTAG: 0
IndexTAG: 1466
TitleTAG: Question 8 Problem.
In question 8, the correct thing to do isn't just divide the price by the number of the houses, to get the averages of 834 and 819 and after subtract one average from other?
I mean: (834/32)-(819/32)?
Or what is the correct way of doing it?
UserIdTAG: 1148904
UserNameTAG: vspiger
CreateTimeTAG: 2013-03-05T01:28:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: Did you watch lecture 3.2? There was a segment on "Change an entry, change the average"
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T02:05:53Z
FirstChildVoteTAG: 0
SecondChildTAG: firstly, calculate the difference in the price....
(834000-819000)=15000
as the cost has been decreased, it will be -15000
hence we should find the average after the decrease of price
-15000 would be equally distributed to 32
(-15000)/32=-468.75
hence, therefore the average would be decreased by 468.75
good....luck
SecondChildUserIdTAG: 833878
SecondChildUserNameTAG: dineshthumati
SecondChildCreateTimeTAG: 2013-03-06T12:25:50Z
SecondChildVoteTAG: 0
IndexTAG: 1467
TitleTAG: Graph B or D
Just a clarification. The answer says Graph B is the answer. The green check mark is in Graph D. My answer is graph B, but there is a red X mark. therefore is my answer right or wrong. Thank you to whatever assistance you could render.
UserIdTAG: 1174861
UserNameTAG: Roddy
CreateTimeTAG: 2013-03-05T00:30:34Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I think you caught a mistake in the reported solution.
The correct answer is definitely graph D, due to the Y axis
(graph B has "probability", which doesn't make sense with the data we have)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T00:57:36Z
FirstChildVoteTAG: 0
FirstChildTAG: This is reference to which problem?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T01:55:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Problem 3b
SecondChildUserIdTAG: 886662
SecondChildUserNameTAG: Darrell193
SecondChildCreateTimeTAG: 2013-03-05T02:06:51Z
SecondChildVoteTAG: 0
SecondChildTAG: I think this is reference to the very first problem set, Exercise Set 1, problem 3, since I definitely had a question about that too and never had time to look on the forums to figure it out... until now, lol.
SecondChildUserIdTAG: 997742
SecondChildUserNameTAG: phamv
SecondChildCreateTimeTAG: 2013-03-21T01:41:26Z
SecondChildVoteTAG: 0
IndexTAG: 1468
TitleTAG: Solutions from last week exercise.
I have been looking for the solution of the last week exercises, but I couldn't find it. I had read that Staff will post them after the due date. Please let us know where are the exercise solutions post to see the correct answers and be aware of our mistakes.
Thank you!
UserIdTAG: 716638
UserNameTAG: quinteropaula
CreateTimeTAG: 2013-03-05T00:10:58Z
VoteTAG: 6
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Go to the Exercises' pages.
You'll notice that below every problem, there's now a "Show Answer" button. Try clicking it ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T00:12:47Z
FirstChildVoteTAG: 2
SecondChildTAG: @Klionheart - Just wanted to update that the **Show Answer** button does not display 'CORRECT ANSWER", it just display's your own LAST ENTERED ANSWER.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T03:56:51Z
SecondChildVoteTAG: 0
SecondChildTAG: So, please do not be misled by it - everyone!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T03:57:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Show Answer gives an explanation of how the problem was solved, as well as displaying the answer.
Show Answer works as it should here, unlike in PH207x.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-05T04:02:19Z
SecondChildVoteTAG: 0
SecondChildTAG: the show answer showed only on the question when i was attempting to answer
I believe she said she would upload the answers but dotn quote me on that.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-05T04:24:01Z
SecondChildVoteTAG: 0
SecondChildTAG: i am getting really tired of the technical glitches. The show answer button is only showing up on one of my assignments and they werent there 5 hours ago. grrr. will have to wait to see about the others tomorrow
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-05T04:52:34Z
SecondChildVoteTAG: 0
SecondChildTAG: @Artimehta: mmm, no? Show Answers show the correct solution and, in most cases, an explanation for it.
@SherryJo: I suppose there could have been some sort of glitch, but I did check for it 10 hours ago before answering, and I checked again just now: Show Answers works correctly for me on the first 3 Exercise Sets.
Which browser are you using? Maybe that's the problem. Avoid Internet Explo(de)rer.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T10:02:19Z
SecondChildVoteTAG: 0
IndexTAG: 1469
TitleTAG: Question 8 trouble
Question 8 looks like the same thing as in practise problem 2, but using the same method does not provide the correct answer.
PP 2 asks about the commute distance error: If one datum is recorded as 165 miles rather than 16.5 miles, how does this affect the average of the 37 commute distances?
(165-16.5)/37 = 4.01
(original value minus "correct/new" value) divided by number of data = answer
The above calculation is the one given in the explanation.
Q. 8 asks how the price change of a house affects the average price of the houses.
(834,000-819,000)/32 = incorrect answer for problem
(original house price minus "new" house price) divided by number of data = wrong answer??
Could someone shed some light onto how these two problems are different?
UserIdTAG: 1055945
UserNameTAG: rebecca417
CreateTimeTAG: 2013-03-04T23:44:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: All I can say is, read the text of the exercise carefully. Especially the part that's inside the square brackets.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-05T00:04:02Z
FirstChildVoteTAG: 0
SecondChildTAG: The same problem, as i have; what is the ans
SecondChildUserIdTAG: 936171
SecondChildUserNameTAG: Asif99
SecondChildCreateTimeTAG: 2013-03-05T10:05:00Z
SecondChildVoteTAG: 0
FirstChildTAG: I figured it out. The above formula is correct. It was the format of my answer -- I simply put in the difference, forgetting to specify that the average is DECREASING by that amount. Make sure you read and understand the instructions in the brackets!
FirstChildUserIdTAG: 1055945
FirstChildUserNameTAG: rebecca417
FirstChildCreateTimeTAG: 2013-03-05T00:04:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Please, mind the [honor code][1]...
Hints are one thing, all-but straight up answers are quite another.
[1]: https://www.edx.org/honor
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T00:07:14Z
SecondChildVoteTAG: 0
IndexTAG: 1470
TitleTAG: Solutions & Hints in the Discussion
I'm sorry if I upset anyone, but I have to ask this:
What is the point of having a limited number of submissions per exercise (one or two), when one can simply scroll down to the discussion and find hints, solutions and even results (if needed, hints etc would be provided in the wording of the exercise itself)?
I'm posting this because I get to feel like an absolute idiot every time I'm missing a question (it happens), only to scroll down to the discussion to find out that the goods are already sold out in the market (sic).
Suggestion: either disallow the discussion forum (which is not a liberal solution, of course) or allow for unlimited attempts, like in some other edX classes.
And, what is the point of using software (e.g SPSS) to calculate simple stats of 10-entries lists? Are you sure you have learnt how SD is calculated before skipping to the easy machine? I mean, come on, it's getting ridiculous...
UserIdTAG: 687022
UserNameTAG: ThanosT
CreateTimeTAG: 2013-03-04T23:41:32Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 4
FirstChildTAG: A limited amount of submission still make it less likely that one could "guess" the right solution by simply throwing a bunch of answers in until they hit the correct one.
Hopefully the hints on the board won't be too explicit, and so you still need to figure out *something* for yourself.
Think of it as meeting with classmates to do your home assignments. Cooperative learning is immensely useful. If you're lazy you might decide to cheat and persuade one of your friends to do the work for you...but then you're probably not learning much, and will be into trouble later. It will be your loss in the end...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T23:54:22Z
FirstChildVoteTAG: 2
SecondChildTAG: Then you can adopt unlimited submissions only for arithmetic questions. I think that cooperative learning is extremely valuable and functional when it comes to ungraded problem sets (practice sets etc) or when the problem requites arithmetic methods complicated enough that a little help is always welcome. Like I've written above, I am comparing with the policies from other edX classes and Coursera classes: problems that require complicated mathematical manipulation do benefit from a cooperative approach, in the way that one can get unstuck from a difficult position; the rest is up to the student. However, this is not the case in Stat2.1x: the mathematical manipulation is much shorter, but the key element (the one the whole exercise focuses on) is usually something that has to be unveiled by the practicing student. What's the point of providing this in the discussion page?
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-05T11:54:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Sometimes, you get stuck on a very stupid thing, maybe because the wording of the problem has got you confused, or perhaps just because you overlooked something. A nudge in the right direction can do wonders in these kind of cases, and seems perfectly legitimate to me, at least for home assignments.
Abuse of the tools you have unfortunately happens everywhere. Again, it's going to be your loss in the long run if you just get the solutions without learning anything.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T12:26:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Indeed. Of course I realize that I might be focusing on the trivial right now, but do understand that I only voiced what seemed to me unfair and problematic.
I also know that this is not a "customer's service department". If the course designers want to do something about the issue (if they consider it an issue), it's up to them. It's all part of the democratic process - even the "wisdom of crowds" theorem addresses the importance of varied opinions on a subject. So, please refrain from considering this as typical nagging - it isn't; it's merely an opinion, with the importance (if any) of one opinion out of the whole. Thanks.
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-05T12:46:09Z
SecondChildVoteTAG: 0
FirstChildTAG: ThanosT, your comments about this getting ridiculous seem to be based on observations that have been made quite some time ago. Consider that the certificate awarded will not mean very much to a potential employer, nor will it count for college credit because there is no way to verify if the person with their name on the certificate is the person that took the course and provided answers. I don't mean to belittle the course, or EDX, which I have profound appreciation and gratitude for.
In my humble opinion, the largest benefit for a person to take a free online course is to learn the material. To that end, the extent to which a person resorts to cheating, or peeking as it were, to fill in blanks on problem sets only cheats themselves. ThanosT, it seems to me that either you are here to learn, in which case you shouldn't have the concern that you do, or you are here to simply get a certificate which you presumably value more than actually learning the material.
To conclude, just focus on learning the material. All else is non-consequential. Cheers and good luck in the course!
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-05T00:24:40Z
FirstChildVoteTAG: 4
SecondChildTAG: I couldn't agree more. Why anyone would bother to sign up for the course and then cheat to finish it is beyond my comprehension. I, too, am most grateful for this opportunity. The fact that so many professors are generously sharing their knowledge and course material for no cost is enough to make me want to do my part and learn as much as I can. Whether or not an employer recognizes a certificate is immaterial to me. I will have gained knowledge and that itself will be my real take-away.
SecondChildUserIdTAG: 374593
SecondChildUserNameTAG: lf2223
SecondChildCreateTimeTAG: 2013-03-05T00:41:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I beg to differ. Maybe in your case (and mine), the certificate does not offer much in the way of employment and we are here to learn - I am using this course as a helpful review for my research. But I've come across too many people from certain parts of the world, where this kind of certificate targets 100% employability and is meant to enjoy prominent placement in their CVs (as a title from Berkeley or MIT, it can be enough to impress an employer).
But you have drifted from my point: I was not trying to impose a more rigid protestant morality over here. And it's very nice that some people have the character to do their own part etc (as you are saying). If you read through the discussion forum, though, this is not the case (statistically speaking)...
Other than that, please excuse the rather strong language in the original comment (i.e. ridiculous, idiot), but this is the way it makes me feel.
Cheers and good luck.
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-05T12:04:57Z
SecondChildVoteTAG: 0
FirstChildTAG: > Why anyone would bother to sign up for the course and then cheat to finish it is beyond my comprehension.
One of life's mysteries. But it happens. Probably quite a lot. The PH207x exam was posted, in its entirety, to a couple of homework help sites. And obligingly answered by a proud university graduate (though not proud enough to use his real name). Other courses have had the same experience.
In some areas the certificate is worth more than the knowledge obtained. Getting that certificate is "vital" to someone. Just the certificate, nothing else matters.
The proctored certificate might be a bit better policed, but even that will have issues. But I am astounded that students are claiming that their university is going to give them credit based on a mooc certificate - not a proctored certificate. Just a certificate.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T01:57:07Z
FirstChildVoteTAG: 1
SecondChildTAG: I am in an unique position of needing the certificate and the knowledge but it is so beyond my wildest imagining to cheat.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-05T04:45:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you. My point exactly.
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-05T12:05:54Z
SecondChildVoteTAG: 0
SecondChildTAG: I think the course is about the experience and joy of learning.If that is not there then only GOd can help you.
SecondChildUserIdTAG: 341206
SecondChildUserNameTAG: laxmishac
SecondChildCreateTimeTAG: 2013-03-05T14:51:12Z
SecondChildVoteTAG: 0
FirstChildTAG: These are open book tests and you need more than one attempt to answer them? Get real!
FirstChildUserIdTAG: 1284382
FirstChildUserNameTAG: kite420
FirstChildCreateTimeTAG: 2013-03-05T08:57:11Z
FirstChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/MITx/8.02x/2013_Spring/about
Here is one. Get polite.
SecondChildUserIdTAG: 687022
SecondChildUserNameTAG: ThanosT
SecondChildCreateTimeTAG: 2013-03-05T12:06:47Z
SecondChildVoteTAG: 0
IndexTAG: 1471
TitleTAG: trying to keep up
awww suddenly i have so much to do( got posted out to a new station) ...hope i can
UserIdTAG: 1033614
UserNameTAG: neo8701
CreateTimeTAG: 2013-03-04T23:24:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1472
TitleTAG: Bounds and Inequalities
I'm confused about how terms of inequality are used for this dataset. Isn't it inaccurate to say **at most** 0.7% (or 0.694444...% to be precise) are more than 80 years old? To me, that statement implies the possibility that **exactly** 0.7% are **more than** 80 years old. The upper bound should be the scenario where **exactly** 0.7% are **exactly** 80 years old. Any increase above this bound (i.e. more than 80 years old) would increase the SD and/or the average.
UserIdTAG: 906684
UserNameTAG: 2pter
CreateTimeTAG: 2013-03-04T22:28:27Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: You don't know that. The distribution of data could be such as there are **exactly 0** people who are 80, and so there *is* the possibility that exactly 0.7% are more than 80 years old ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T22:56:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Sure, but in that case the SD and/or average would be higher than what's specified.
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-04T23:12:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Why? Neither the average nor the SD give you any information about how many people are of a specific age, from what I understand.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T23:44:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Neither the average nor the SD *on their own* can tell you about the number of datapoints at a given value, but when used *in combination* in Chebychev's Inequality, they can tell you that certain values are impossible and others are not. Try working out a scenario in which the SD is 5, the average is 20, and exactly 0.694444...% of datapoints are greater than 80. I'm saying that it's not possible.
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-05T01:08:22Z
SecondChildVoteTAG: 0
SecondChildTAG: It doesn't matter. We are talking about bounds here.
The Average and SD are calculated based on a distribution of values that we don't have access to. It could be anything. It could have thousands of values exactly 80 and none above it, or none exactly 80, and thousands above it. Those thousand values combined with the others <80 have an average of 20 and an SD of 5, because that's what we are told *Ex Cathedra*, and we trust it.
In the second case, it doesn't make any difference for the bound if we consider values >=80, or values strictly >80, and since we don't know that this is **not** the case, we have to include the rightmost limit of the bound in both calculations.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T11:01:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Again, I ask whether you can come up with *even one* scenario where all those conditions are met. If none exist, it is inaccurate to include the bound by saying "at most".
SecondChildUserIdTAG: 906684
SecondChildUserNameTAG: 2pter
SecondChildCreateTimeTAG: 2013-03-05T21:38:21Z
SecondChildVoteTAG: 0
SecondChildTAG: The possibility of getting a data sample reduce drastically with increasing K (multiple of MEAN /SD in different inequality discussed) .Use of bound will clear your doubt about interpretation of inequality.
One of the purpose of bound is to restrict the range of data set to make it manageable without losing any significant no. samples.
As in case when you have millions of data (lets suppose age collected by govt for welfare planning in a country) the final compilation from such large data set presented to planner of the country contains the value in terms of SD and Mean of all data (if he would be fed with all data collected he would have fall in limbo). Now with This value of SD and Mean.Now he uses bound and found that his population above 80 year is very miniscule (max upto bound limit id 0.7% or even less). Now while planning welfare he can roughly estimate his population spread and plan since his population more than 80 is minute he can ignore them.Even them even depending on data set no people actually more than 80 will differ .there may be cases that there is no person at all above 80.
Hope I am able to present it clearly
SecondChildUserIdTAG: 739769
SecondChildUserNameTAG: Abishek_raj
SecondChildCreateTimeTAG: 2013-03-08T12:56:46Z
SecondChildVoteTAG: 0
IndexTAG: 1473
TitleTAG: SD
You may have indicated what "SD" meant in the videos but it is not in the slides that I Printed however, I assumed it meant "spread" but, if that were the case, then, I wouldn't have gotten problem 2 incorrect. In the future, when using an abbreviation in a graded exercise, can you please spell out for what the acronym stands? thanks.
UserIdTAG: 983629
UserNameTAG: Jamiebjohn
CreateTimeTAG: 2013-03-04T22:08:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Ignoring the fact that the video lectures are an important, if not crucial, part of the course...
The downloadable slides for Lecture 4.2 *clearly* state that SD=Standard Deviation, in multiple places. All through slides 3 and 4, for example.
So when you get to the Exercise Set 6, you should know what SD stands for without any need for it to be spelled out. It's part of the material that you should have reviewed.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T22:50:16Z
FirstChildVoteTAG: 0
SecondChildTAG: just because people have reviewed the material, it does not mean they master it. it is very arrogant to make the statement you did above. Everyone learns differently
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-05T04:46:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Everyone learn differently, true. But evidently there are cases when someone does *not* learn. You don't need to "master" that material to know what the SD is. It's been spelled for you several times.
It's like doing a math test on additions in 1st grade, and in the middle of it getting up and asking the teacher. *"Sorry ma'am, I don't understand what this "cross" symbol is on the paper, next to the numbers. Why do you not tell us in the test?"*
The "cross" symbol would be a +. If you go to your math test without knowing what the addition symbol is, then you're obviously unprepared for it, and won't get a very good grade. Maybe you'll actually pay some attention in class next time?
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T11:12:47Z
SecondChildVoteTAG: 0
FirstChildTAG: > You may have indicated what "SD" meant in the videos but it is not in the slides that I Printed however
Which ones did you print?
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13624596051343614.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T05:00:34Z
FirstChildVoteTAG: 2
IndexTAG: 1474
TitleTAG: Question 6 : looks great but not really!
Here is my opinion: if more than 45 is correct, more than 25 or more than 35 is correct! Yes they are correct but what if the number is between 25 and 45? That number is not correct because it's definitely lower than 45.
Technically the question 6 has no problem but also not a great question!
UserIdTAG: 1106581
UserNameTAG: Beann
CreateTimeTAG: 2013-03-04T21:44:05Z
VoteTAG: 2
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: First: reread the [Honor Code][1]. What did you do that you shouldn't have?
...yes, you're giving out answers. If they are right, you are improving the chances of others. If they are wrong, you are hurting those chances. Either way you're violating the code, so try not to do it again. Now that's out of the way...
If your answer has multiple options checked, you are saying that a solution is valid for you if, and only if, it meets all your conditions. So if you checked all 3 options, you are saying that a valid solution has to be higher that 25,35, and 45 at the same time. 40(a number between 25 and 45) meets only 2 out of 3 conditions, so it's not a valid solution for you. 30 meets only 1 condition, and is also not a valid solution for you. 50 meets all 3 conditions, so it's a valid solution for you. So is 80. 1000 isn't, because while it does meet your 3 conditions, of course, it fails to meet the 4th, implicit condition imposed by the text, the fact that there are only 82 employees in total.
Are 50 and 80 correct solutions for the problem? I can't say that, but you are saying that they are. You are also saying that 30 and 40 are not. What's the problem?
[1]: https://www.edx.org/honor
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T22:41:54Z
FirstChildVoteTAG: 5
SecondChildTAG: I draw I fine little wanky diagram, and everything was fine.....And managed to read oncoreectly my own diagram...And in case you're asking yourself how did she miss that:
When you can't sleep for a few days in a raw due to health issues, it's really getting harder and harder to focus...
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-03-05T19:11:41Z
SecondChildVoteTAG: 0
FirstChildTAG: So, after all, what's your point?
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-03-05T15:03:46Z
FirstChildVoteTAG: 0
FirstChildTAG: The lecture videos do not load easy. The quality of visuals in videos is poor and they jump from one topic to multiple windows on their own. The questions are worded in a poor manner leaving scope for different interpretations. I suggest the male instructor should undergo training in English language speaking and practice more so that he does not stammer and is able to communicate better.
The lady is good, able to communicate effectively but the links to the lessons and exercises have much scope for improvement. Just my POV.
FirstChildUserIdTAG: 929545
FirstChildUserNameTAG: RK77
FirstChildCreateTimeTAG: 2013-03-06T16:56:44Z
FirstChildVoteTAG: 0
IndexTAG: 1475
TitleTAG: To Ani Adhikari
From Pa3cr@aol.com, K. Page
Please email to let me know I have bee withdrawn from the course. I wrote you last week to inform you I have a Family emergency.
UserIdTAG: 900614
UserNameTAG: pa3cr
CreateTimeTAG: 2013-03-04T21:40:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Interesting. EDX provides a facility for students to remove themselves from a class without requiring the direct intervention of the professor already carrying the burden of overseeing a class of tens of thousands of individuals, if not hundreds of thousands.
Here is a link just for you: https://www.edx.org/dashboard#unenroll-modal
Please click with care.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-03-04T22:50:34Z
FirstChildVoteTAG: 3
IndexTAG: 1476
TitleTAG: Rhymes with Orange comic strip of 3/4/2013
Stat2.1Xers may like today's "Rhymes with Orange" comic strip - "Storm Watch". In the first panel, the TV announcer says "3 to 30 inches expected by nightfall...". The viewer's response is "Well, that's helpful. I'm going to start saying I'm between 5 and 50 years old." Here's a link, if you'd like to see the pictures: http://rhymeswithorange.com/
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-04T21:13:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1477
TitleTAG: Loved the joke about Californians
Prof. Adhikari does have a sense of *humour*: "Californians will tell you that it's the growth hormones in the milk that is making our young people get taller." Indeed!
UserIdTAG: 1152094
UserNameTAG: CristianOpazo
CreateTimeTAG: 2013-03-04T21:05:27Z
VoteTAG: 1
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.3: Comparing and combining averages
NumberOfReplyTAG: 2
FirstChildTAG: That said, it actually is not unusual at all for someone to lose two inches in height from when they are in their 30s to when they are in their 70s. We have a lot of vertebrae, with a lot of discs to compress.
Among populations where there has been significant progress in nutrition the difference in heights between different age cohorts changes much more than two inches.
FirstChildUserIdTAG: 677079
FirstChildUserNameTAG: rjzmml
FirstChildCreateTimeTAG: 2013-03-05T07:18:39Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree that is true and struck me as soon as I saw it but the point made isthat with a heterogenous population ie crossectional study that cannot be concluded.ie the statement is true but the reasoning or method of analysis is false.In fact we are shorter in the evening compared to the morning and also due to variations in the hydration of the nucleus pulposus of the interverterbal disk !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T09:14:53Z
SecondChildVoteTAG: 0
FirstChildTAG: The data shows that short people live longer. Survival of the shortest.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-05T14:33:13Z
FirstChildVoteTAG: 1
IndexTAG: 1478
TitleTAG: Problem 6 - read it carefully
'Wait, what??!! oh yeah...damn' was my thought process after getting this question wrong. :D
UserIdTAG: 1265802
UserNameTAG: GMORRIS010
CreateTimeTAG: 2013-03-04T20:38:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: nice one :)
FirstChildUserIdTAG: 1121196
FirstChildUserNameTAG: zabily
FirstChildCreateTimeTAG: 2013-03-04T21:24:23Z
FirstChildVoteTAG: 0
IndexTAG: 1479
TitleTAG: When can i see the answers to these questions??
Is there anyway after the deadline is over, we can review our wrong answers to see where exactly we went wrong???
UserIdTAG: 902908
UserNameTAG: sagarsahay
CreateTimeTAG: 2013-03-04T20:10:44Z
VoteTAG: 4
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: after dead line we can post our answer
so post right answer
so every body will get idea
i hope there is no objection in puting input after dead line
if any pl do tell me .
i have posted both assignment
ist was little in haze so silly error
2nd with ease with only 2 mistakes
so do home work before answering it twice
and recheck before saving and puting check command it will have better score
26//50 first then 41/45 ...it could be 45/45 if proper care taken
FirstChildUserIdTAG: 386558
FirstChildUserNameTAG: yogeshdave
FirstChildCreateTimeTAG: 2013-03-04T20:43:33Z
FirstChildVoteTAG: 0
SecondChildTAG: After the deadline the answers will be available on the Exercise pages themselves. The "Check" button will become "Show answer" ;)
And we'll also be able to discuss it in the board, sure.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T20:47:12Z
SecondChildVoteTAG: 0
SecondChildTAG: no they wont become show answer because the deadline has passed and no show answer buttons.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-05T04:48:08Z
SecondChildVoteTAG: 0
SecondChildTAG: The deadline has not passed for Week 2. The "Show answers" button is indeed available for the Week 1 Sets.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T11:15:54Z
SecondChildVoteTAG: 0
IndexTAG: 1480
TitleTAG: Congratulations
Dear professors,
Unfortunately, the last days of the first week, I have been sick, so, I could not fulfill all the tests.
In the second week I could do everything, and now, I am back on the schedule of the course.
I congratulate to all who have organized the course, which I took to update my knowledge in statistics after almost 40 years, and really the course is amazing, the methodology is quite stimulating, the lectures are so clear, that anyone can understand. And I could see, that it is a new whole world for me. Thanks to Mrs. Ani Adhikari for her nice lectures.
Best regards,
Julio Porcel.
UserIdTAG: 1262270
UserNameTAG: JPorcel
CreateTimeTAG: 2013-03-04T19:53:18Z
VoteTAG: 21
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Yes I agree that the lectures are explained very simply. What I personally wanted to thank the staff is about encouraging us to understand the concept more than the understanding of the calculation.
Thanks
FirstChildUserIdTAG: 946880
FirstChildUserNameTAG: VandanaVarma
FirstChildCreateTimeTAG: 2013-03-06T15:36:27Z
FirstChildVoteTAG: 4
IndexTAG: 1481
TitleTAG: Exams
I know this is a copy of others' posts but could we please have a 2-3 day window to complete the test (preferably starting before the 26th) because:
1) It's Passover;
2) It's a Tuesday (which isn't a day we're all able to do coursework on);
3) I'm having my left ankle reconstructed on the 26th and would really very much like the opportunity to sit the final before the general anaesthetic kicks in.
Thanks!
Fiona
UserIdTAG: 1243154
UserNameTAG: fimckenzie
CreateTimeTAG: 2013-03-04T19:34:05Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I support this as I am due a spine reconstruction operation on 26th
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-07T19:57:59Z
FirstChildVoteTAG: 0
IndexTAG: 1482
TitleTAG: Syllabus for Stat2.2 and Stat2.3
Hello,
Is there a syllabus available for the second and third part of this course (Stat2.2 and Stat2.3)? I tried looking for a syllabus of a standard Berkeley Stat2 course (which probably should be somewhere at http://www.stat.berkeley.edu/), which the EDX courses are based on, but I couldn't find them.
Thank you,
UserIdTAG: 1097026
UserNameTAG: aiS2ru
CreateTimeTAG: 2013-03-04T19:28:17Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1483
TitleTAG: Thanks
I'm sorry for those who are lost.
I just had so much FUN doing this exercise!! took me back to my high school years, prof A. explains things slowly but is not boring, and the practice site were you can reload the exercises is just an example of great application of ITs to education.
Waiting was worth it
Thanks
s
UserIdTAG: 923593
UserNameTAG: SaraMB
CreateTimeTAG: 2013-03-04T19:22:13Z
VoteTAG: 3
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 0
IndexTAG: 1484
TitleTAG: Next Week
Is there a guideline on the text we should be reading for the next week? I want to read ahead, but I also don't want to get in to things that we won't be covering in the lectures.
UserIdTAG: 1018852
UserNameTAG: sansquamtch
CreateTimeTAG: 2013-03-04T19:09:19Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Check the syllabus that is posted. Sometimes you can tell the subjects that relate to the online text.
In Courseware/General Information/Schedule
(sorry, having hyperlink finger problems)
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-04T19:54:19Z
FirstChildVoteTAG: 0
IndexTAG: 1485
TitleTAG: problem 6,7&8 help!
please help me !or give me a hint ! am little confused...
UserIdTAG: 920087
UserNameTAG: Areejo33
CreateTimeTAG: 2013-03-04T18:58:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: What answers did you give, or how did you calculate them? I can help out from there.
FirstChildUserIdTAG: 945111
FirstChildUserNameTAG: judithpdx
FirstChildCreateTimeTAG: 2013-03-04T19:17:20Z
FirstChildVoteTAG: 0
SecondChildTAG: it is very simple
just try to read all pdf file
and see video clip
there is no sense if i post you hint and answer
i understand to give answer is prohibited
one hint i can give when average is more than sd than...
graph will be....symetrical/skew ...which way
it is written in slides
so if you read properly you will learn other wise just answering you will not help you in long run
SecondChildUserIdTAG: 386558
SecondChildUserNameTAG: yogeshdave
SecondChildCreateTimeTAG: 2013-03-04T20:33:34Z
SecondChildVoteTAG: 0
SecondChildTAG: be careful they have asked no of mode not which mode
my answer posted wrongly
SecondChildUserIdTAG: 386558
SecondChildUserNameTAG: yogeshdave
SecondChildCreateTimeTAG: 2013-03-04T20:34:33Z
SecondChildVoteTAG: 0
SecondChildTAG: simple arithmetic
have difference of average
after reduction in price
and find remaining amount
and have average
so your answer
is
dont forget to put sign...whether it is reduce or increase in average....so you have to take of instruction given herewith
SecondChildUserIdTAG: 386558
SecondChildUserNameTAG: yogeshdave
SecondChildCreateTimeTAG: 2013-03-04T20:36:23Z
SecondChildVoteTAG: 0
SecondChildTAG: ok! can u at least direct me to the right lecture please!!
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-03-04T20:40:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Sure!
Lectures 3.2 and 3.3 would be a good start ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T20:49:29Z
SecondChildVoteTAG: 0
SecondChildTAG: All answers are there in the lectures itself, take little time when solving with a cool head and you will have the answers
SecondChildUserIdTAG: 1140772
SecondChildUserNameTAG: pavelgupta
SecondChildCreateTimeTAG: 2013-03-05T06:09:58Z
SecondChildVoteTAG: 0
SecondChildTAG: thanQ so much! i got them correct..
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-03-06T18:24:22Z
SecondChildVoteTAG: 0
FirstChildTAG: If you could be more specific about which problems you have problems with, we can probably drop some suggestions.
Keep in mind the restrictions of the honor code, though...so don't be too detailed.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T20:12:15Z
FirstChildVoteTAG: 0
SecondChildTAG: in problem 8 :(old cost-new cost)/the total number of the house but iget my answer wrong ! so am little confused..
in problem 6:really i need someone 2 give me an exceplanation!!
in problem 7:(the total cost-the amount raised in one month)/the number of the member ! also i get it wrong .. so am little confused.. please need your help!
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-03-04T20:53:41Z
SecondChildVoteTAG: 0
SecondChildTAG: - Problem 6 *is* a little tricky, I admit. The key is remembering what the average is, and what it **isn't**. Also, look out the meaning of "Typical".
- Problem 7...is hard to tell you much without giving answers away...you probably want to review the numbers you have. Let me also point out how $5200 is the **average** raised by the 12 board members.
- Problem 8. The two prices you have are prices for **one** house, not for the total. And you are asked to calculate by how much the average of all 32 prices changes when you change the price of a single house.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T21:07:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Also, make sure you follow the correct format of numerical answers. 2 decimal places, no units of measurement...and for problem 8, read what's between the square brackets.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T21:10:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Problem 8: Agreed! I read those square brackets, thought I knew what I was talking about, and had the same problem. Think of your answer in those terms. Is the average increasing or decreasing?
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-03-05T00:10:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Please tell us at some point what definition you use for **typical**.
SecondChildUserIdTAG: 902725
SecondChildUserNameTAG: Brichardson
SecondChildCreateTimeTAG: 2013-03-05T18:15:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Here, 'typical' means 'the most common' or 'the most frequent'. As in "the typical customer orders two burgers, fries, and a drink" or "the typical person has no idea of how to properly brew tea."
So the problem could be reworded as "there were many households with 2.9 people living in them."
Just occurred to me that using that definition, 'typical' is the 'mode'.
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-06T06:51:36Z
SecondChildVoteTAG: 0
SecondChildTAG: thanQ so much ! i got them right..
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-03-06T18:23:49Z
SecondChildVoteTAG: 0
IndexTAG: 1486
TitleTAG: Problem 8
After 2 failed attempts i think i know what the question asks ;)
I dont know what shall i say:
It's a poorly written question
or
i dont understand the language well
Any way rest all answered perfectly.
UserIdTAG: 1033651
UserNameTAG: sarveshbhatt
CreateTimeTAG: 2013-03-04T18:30:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: Please do not hesitate to ask questions about the English wording. If you can be specific (by mentioning the exact word or phrase) I think you will find both native and non-native English-speakers happy to help. I did not appreciate how difficult it must be for you until I saw a few posts from a few days ago, in which the poster typed out the exact words they were having trouble with. That really helps both sides!
And how wonderful that you did so well anyway!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-04T19:52:50Z
FirstChildVoteTAG: 0
SecondChildTAG: there is no poor english
you need to focus on slides and video
it is simple
and take care to have properly read instruction
and answer only when you had done calculation twice
and answer what is required
SecondChildUserIdTAG: 386558
SecondChildUserNameTAG: yogeshdave
SecondChildCreateTimeTAG: 2013-03-04T20:38:12Z
SecondChildVoteTAG: 0
SecondChildTAG: the method to solve this problem was almost exactly what was given in lecture
SecondChildUserIdTAG: 348290
SecondChildUserNameTAG: joshb
SecondChildCreateTimeTAG: 2013-03-04T20:49:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too... I had the same problem.. but still I did 7 good answers!!!
I shall try to interact with you more often!!
Thanks
SecondChildUserIdTAG: 945953
SecondChildUserNameTAG: Turca
SecondChildCreateTimeTAG: 2013-03-06T11:48:44Z
SecondChildVoteTAG: 0
FirstChildTAG: So here is my question:
"One of the houses costs $834,000, but in order to attract more buyers, the price is dropped to $819,000."
So: so should I understand that just price of this one particular house was 834k$ or every single house as one or two or any number of houses could cost sth. and after that price dropped to 819k$ but just for this particular one house, or all of them, and does it mean that just there is discount for one house? it is non intuitive for me to drop price of just one...
Ok It is clear for me now after reading couple of times that you mean:
There is 32 houses.
One of them changed from 934 to 819 k$ so how this itself affected average?
FirstChildUserIdTAG: 1202138
FirstChildUserNameTAG: szuetam
FirstChildCreateTimeTAG: 2013-03-05T00:37:43Z
FirstChildVoteTAG: 0
IndexTAG: 1487
TitleTAG: Teacher is great!
I really like the teacher's style of presenting and her conversational tone. And her accent is great too.
UserIdTAG: 1231552
UserNameTAG: Albertson
CreateTimeTAG: 2013-03-04T18:25:43Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Agreed!! She is a fantastic communicator and has one of the most beautiful speaking voices I've ever heard.
FirstChildUserIdTAG: 1252523
FirstChildUserNameTAG: Willabe
FirstChildCreateTimeTAG: 2013-03-04T19:19:21Z
FirstChildVoteTAG: 0
SecondChildTAG: Agreed.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-16T23:24:54Z
SecondChildVoteTAG: 0
FirstChildTAG: She always sounds like a chipmunk to me... but that's because I watch the lecture videos at 1.5x speed!
But I agree, I have found the lectures so far really engaging and really pleased I signed up for the course.
FirstChildUserIdTAG: 5547
FirstChildUserNameTAG: HoorayForLuke
FirstChildCreateTimeTAG: 2013-03-04T20:48:51Z
FirstChildVoteTAG: 1
FirstChildTAG: I think she is great, it is as though she is talking just to me, and her knowledge of the subject makes it a joy to listen - thank you.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-03-07T19:59:50Z
FirstChildVoteTAG: 0
SecondChildTAG: Agreed. Apt comment.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-16T23:23:43Z
SecondChildVoteTAG: 0
IndexTAG: 1488
TitleTAG: Request to Faculty
Please Faculty Do something about **EXAM DATE**.. it would be great if we can get a **2 DAY WINDOW** for exam if possible. Thanks.
UserIdTAG: 303485
UserNameTAG: iparitosh
CreateTimeTAG: 2013-03-04T17:01:29Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Yes especially since the time that it is "put up" could be unfavorable to some subset around the globe -All may get 24 hours but some may have started a day and others ending it so the net "usable" time may vary as it is a week day and many would be working and would have to come back from work and then write their exam !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T17:29:57Z
FirstChildVoteTAG: 3
SecondChildTAG: A very good point, and I agree with the request :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T17:42:43Z
SecondChildVoteTAG: 0
FirstChildTAG: exam date?? wen is it? Did i miss some announcement?
FirstChildUserIdTAG: 1226050
FirstChildUserNameTAG: DrShwetaa
FirstChildCreateTimeTAG: 2013-03-04T18:28:36Z
FirstChildVoteTAG: 0
SecondChildTAG: 13th and 26th.See the course schedule at
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/9565a679e4d44bee9f3aeb2a787f0b80/
and also at
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Course_Schedule.pdf
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-04T18:31:26Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks!! :)
SecondChildUserIdTAG: 1226050
SecondChildUserNameTAG: DrShwetaa
SecondChildCreateTimeTAG: 2013-03-04T21:33:52Z
SecondChildVoteTAG: 0
FirstChildTAG: It would certainly be helpful if we have a time slot early.
I am traveling abroad so this requires some scheduling ahead.
FirstChildUserIdTAG: 1286585
FirstChildUserNameTAG: Rakuda
FirstChildCreateTimeTAG: 2013-03-05T19:26:14Z
FirstChildVoteTAG: 0
IndexTAG: 1489
TitleTAG: answers to graded problems
Please, it would be very useful to hava the answers to graded problems, once the due date is over.
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-03-04T16:30:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You do have them. Go back to those Exercise Sets, you'll notice that the old "Check" button had been replaced with a "Show Answers" button ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T16:47:06Z
FirstChildVoteTAG: 4
SecondChildTAG: Nice!
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-03-04T17:58:06Z
SecondChildVoteTAG: 0
SecondChildTAG: the graded assignments do not have that option. At least mine dotn
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-05T03:57:12Z
SecondChildVoteTAG: 0
IndexTAG: 1490
TitleTAG: How do i register to do my assignments?
I really want to register to do my assignments at this link but i don't have ID as the form requests me to do. Can the Instructor (Mr. Philip) kindly help me do this? http://statistics.berkeley.edu/~stark/SticiGui/Problems/assign-21-s13.htm#instructions
Thanks so much in advance for this alleviation.
UserIdTAG: 824988
UserNameTAG: KongorJ
CreateTimeTAG: 2013-03-04T16:26:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: That is not for us.We only have to do the courseware
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T16:32:55Z
FirstChildVoteTAG: 1
SecondChildTAG: More specifically.
That link is for actual students at Berkeley university. To get a student ID, travel to Berkeley, California, fork up the enrollment money, and enjoy life as a freshman in an US college.
Most likely, you don't *want* to do that. So, don't worry about it and just do the Exercise Set in the courseware ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T16:41:31Z
SecondChildVoteTAG: 0
FirstChildTAG: How do I submit my answers to the exercises? I haven't been able to yet.
FirstChildUserIdTAG: 748089
FirstChildUserNameTAG: meganisaacs
FirstChildCreateTimeTAG: 2013-03-04T19:43:41Z
FirstChildVoteTAG: 0
SecondChildTAG: If you mean for the Exercise Sets 1,2, and 3, you can't anymore. The deadline for those was the end of February. However, you can(and should) still attempt the problems and check your answers(via the "Show Answer" button).
Exercise Sets 4,5, and 6, on the other hand, are still open until March 06, 23.30 GMT, and you can submit your answers by pressing the "Check" button that's below every problem. Your attempts are limited, so think before you answer.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T20:19:28Z
SecondChildVoteTAG: 0
IndexTAG: 1491
TitleTAG: It's 11.11 & NOT 11.1 Oppps!
I also made the mistake of putting 11.1 instead of the 11.11. But I know this is only the beginning and that this course will get significantly harder.
UserIdTAG: 987373
UserNameTAG: CarinaPereiraMPA
CreateTimeTAG: 2013-03-04T16:14:35Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Actually, it's 11.1 and *not* 11.11 that registers correct ;)
But, yeah, whatever. It was just a "youthful error" from the test maker(s) and it doesn't even affect your grade.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T16:19:19Z
FirstChildVoteTAG: 0
IndexTAG: 1492
TitleTAG: Problem 4
Is it possible problem 4 to solve by "inspection" or needs calculation?
I did "Inspection" and got it wrong and had to compute to get the correct answer
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-03-04T15:48:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: It's very possible to do it by inspection.
You just need to think about what the SD represents. What does it mean for a distribution to have a bigger SD than another? (don't answer here :D)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T16:13:06Z
FirstChildVoteTAG: 2
SecondChildTAG: Inspection should work. 40% of entries in dist A are closer to the mean. That gives a big clue on which SD is bigger.
SecondChildUserIdTAG: 1192110
SecondChildUserNameTAG: RupamRaja
SecondChildCreateTimeTAG: 2013-03-05T04:03:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Look at the Octoplets mother example that I gave - it may give you an idea (If you can search for it)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T09:16:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Simple inspection
Ask a few questions: What is the average. What is the spread like
Hope this helps
SecondChildUserIdTAG: 341206
SecondChildUserNameTAG: laxmishac
SecondChildCreateTimeTAG: 2013-03-05T14:56:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Just inspection. recollect the relationship between average and standard deviation.
SecondChildUserIdTAG: 1253175
SecondChildUserNameTAG: yn9876
SecondChildCreateTimeTAG: 2013-03-06T06:53:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi,
You can do that by inspection. Try to think about average and distribution of values.
FirstChildUserIdTAG: 370415
FirstChildUserNameTAG: kziz
FirstChildCreateTimeTAG: 2013-03-04T22:56:05Z
FirstChildVoteTAG: 0
IndexTAG: 1493
TitleTAG: Practice questions and Quizzes
Dear Instructor,
Thank you for an interesting course, I am enjoying this course to the max, even though sometimes I get a bit lost,
Sometimes I do not answer the practice questions will that effect my overall scores? and my total score up to now after 6 exercises is 21%, and passing grade is 35% is that including the midterm and final results? Not that I am aiming just to get 35%, but it gives me some relief ..
Once I again thank you for a very interesting course and the beautiful step by step video sessions.
UserIdTAG: 929984
UserNameTAG: Moti01
CreateTimeTAG: 2013-03-04T15:43:09Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: Practice exercises have no influence on your scores, and, yes, the total score includes the midterm and final. You can get up to 50% with the Exercise Sets alone ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T16:09:57Z
FirstChildVoteTAG: 2
SecondChildTAG: Nice, that is encouraging but I am aiming high.. thanks a million
SecondChildUserIdTAG: 929984
SecondChildUserNameTAG: Moti01
SecondChildCreateTimeTAG: 2013-03-06T19:38:26Z
SecondChildVoteTAG: 0
IndexTAG: 1494
TitleTAG: Mean + 1xSD & Chebychev's Bound
In case of Mean + 1xSD, Chebychev's bound is not giving plausible answer (1/sq.k = 1/ sq.1=1=100%). Can it be explained? I couldn't understand.
UserIdTAG: 1063763
UserNameTAG: Chinmoy4
CreateTimeTAG: 2013-03-04T15:41:50Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: See the example in the lecture about Markov's inequality where we had an x of 0.5 and a bound of 200%.
You still get a logically correct bound: there are at most 100% of the values beyond 1 SD from the average? Sure! It's obvious that there can't be more than 100% of the values in any interval.
It's just not a very *useful* bound -_-
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T15:50:14Z
FirstChildVoteTAG: 1
IndexTAG: 1495
TitleTAG: Suggestion for discussions of quizzes
If possible, I think it would be helpful to disable the discussion option for students that have NOT completed the quiz. While not full-proof, it might make it easier for students and staff to discuss the quiz without giving anything away to those that haven't completed the quiz. It would also be more convenient for those that tend to take the quiz early because they won't have to wait to post comments until after the deadline. Most of us, I think, would find it extra work to have to come back and do this several days later. Just a thought.
UserIdTAG: 937396
UserNameTAG: m2foster
CreateTimeTAG: 2013-03-04T15:33:26Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Excellent idea.
FirstChildUserIdTAG: 1305333
FirstChildUserNameTAG: bellerin
FirstChildCreateTimeTAG: 2013-03-04T15:51:22Z
FirstChildVoteTAG: 0
FirstChildTAG: First, not all discussion are about specific exercises, so you can't just disable the forum for people who might have other legitimate questions(about a lecture, for example).
Second, there *are* discussions about specific exercises that even people who haven't completed them can legitimately be part of. As long as they don't ask for straight answers or procedures, they have the right to discuss the problem and get rid of doubts they might have.
It would be nice to be able to immediately discuss the details of problems, especially if we got them wrong and want to know why...but it won't kill anyone to wait until after the deadline, and sometimes, trying to figure out our mistakes by ourselves might actually be instructive ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T16:03:50Z
FirstChildVoteTAG: 2
SecondChildTAG: I was under the impression that there was a separate forum for the practice exercises and lectures. As for legitimate questions about specific exercises in a quiz, I'm not sure that getting hints (rather than outright answers) is honoring the "Honor Code". Participating in a discussion about quiz questions before a quiz is probably not legit either, IMNSHO, anyway.
SecondChildUserIdTAG: 937396
SecondChildUserNameTAG: m2foster
SecondChildCreateTimeTAG: 2013-03-12T21:01:21Z
SecondChildVoteTAG: 0
IndexTAG: 1496
TitleTAG: Lecture of 4.3 Problem how you get 12 SDs. I dont understand that part?
Lecture of 4.3 Problem how you get 12 SDs. I dont understand that part.
UserIdTAG: 802316
UserNameTAG: WeiPing
CreateTimeTAG: 2013-03-04T15:08:01Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: You're looking for the percent of people who are more than 80 years old. You know that the average is 20 years, and the SD is 5 years.
To use Chebychev's rule you need to know by what multiple of the SD your "limit" value differs from the average, so you start by figuring out what the difference is in years: $80-20=60$ years. Now just divide by the SD: $\frac{60}{5}=12$.
So at 80 years, you are 12 SDs away from the average of 20 and you can use k=12 to find your percent.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T15:16:52Z
FirstChildVoteTAG: 5
SecondChildTAG: Thank you for that!
SecondChildUserIdTAG: 886662
SecondChildUserNameTAG: Darrell193
SecondChildCreateTimeTAG: 2013-03-06T22:32:22Z
SecondChildVoteTAG: 0
FirstChildTAG: I was having that same problem, but now I understand.
FirstChildUserIdTAG: 886662
FirstChildUserNameTAG: Darrell193
FirstChildCreateTimeTAG: 2013-03-06T22:31:58Z
FirstChildVoteTAG: 0
IndexTAG: 1497
TitleTAG: Video NOT working
All the other videos worked well except this one. Lecture 4.3. I used Windows 7, Firefox 19.0 and IE 9.
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-04T14:33:35Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: I'm having the same problem.
FirstChildUserIdTAG: 217892
FirstChildUserNameTAG: anavianna
FirstChildCreateTimeTAG: 2013-03-04T19:18:50Z
FirstChildVoteTAG: 0
IndexTAG: 1498
TitleTAG: A perfect 20 :)
Just follow the lectures properly and you would see these problems through.
UserIdTAG: 1140772
UserNameTAG: pavelgupta
CreateTimeTAG: 2013-03-04T14:14:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: indeed? what about problem 4? =)
FirstChildUserIdTAG: 255838
FirstChildUserNameTAG: EngineerHrenov
FirstChildCreateTimeTAG: 2013-03-05T20:54:30Z
FirstChildVoteTAG: 0
IndexTAG: 1499
TitleTAG: Problems 4 & 6, exercise set 5
Why problems 4 and 6 from the exercise set 5 have only one submission posibility?
UserIdTAG: 63180
UserNameTAG: ianton
CreateTimeTAG: 2013-03-04T13:49:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: That is the rule of the game !! Now with 2 submissions out of 3 possibilities you have a 66% chance of getting it right by fluke isn't it and with 3 submissions a 100 % ;)
Seriously - the parameters in any exam or evaluation is set by the teachers isn't it !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T13:54:53Z
FirstChildVoteTAG: 0
FirstChildTAG: Because they test your understanding only. They don't require "complex" calculations where you might do something wrong, but only that you are aware of what we're talking about.
Plus, there are only a limited amount of answers available, and if you give too many chances you'll just end up with people randomly trying all the possible combinations and then checking their answers xD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T13:55:23Z
FirstChildVoteTAG: 1
IndexTAG: 1500
TitleTAG: SD vs SD
Dears when I calculated a standard deviation of some data by using excel or SPSS programs the result was differ from the result which I calculate it manually by a pen and a papper.
UserIdTAG: 1270021
UserNameTAG: Akhali
CreateTimeTAG: 2013-03-04T13:31:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 8
FirstChildTAG: That is because they may be giving sample SD or SD+ which is indeed a problem !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T13:36:13Z
FirstChildVoteTAG: 0
FirstChildTAG: This is probably because the program you're using calculates SD as:
$\sqrt{\frac{1}{n-1}*\sum_{i=1}^{n}(x_i-\bar{x})^2}$
Instead of the way we do it in the course, which is:
$\sqrt{\frac{1}{n}*\sum_{i=1}^{n}(x_i-\bar{x})^2}$
The difference is explained in the lectures ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T13:42:01Z
FirstChildVoteTAG: 1
FirstChildTAG: I was always told you should never use Excel for statistics. Use SPSS instead, if that's what you've got.
Excel can give incorrect answers for even simple tests. See this link for some examples:
[why you shouldn't use MS Excel][1]
[1]: http://pages.stern.nyu.edu/~jsimonof/classes/1305/pdf/excelreg.pdf
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-03-04T14:24:47Z
FirstChildVoteTAG: 4
SecondChildTAG: Thank you!
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-03-04T15:00:10Z
SecondChildVoteTAG: 0
SecondChildTAG: that link is talking about *Excel 2002*. I'm not a great fan of Microsoft, but still, I'm sure that even them, in 11 years, would have figured what the problem is and fixed it.
In fact, somewhere later in the article, the writer himself admits that *Excel 2003* already fixed most of the problems. We are now at *Excel 2013*, with most people probably using the 2010 or, at worst, 2007 version.
So...no, it's not Excel that's incorrect. The program is just using a different method than the one **we** use. See ArthurBarabash's post below.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T15:28:18Z
SecondChildVoteTAG: 0
SecondChildTAG: As recently as version 2007 it still had some serious errors in its algorithms. There are peer reviewed publications on its shortcomings. (e.g. [Computational Statistics & Data Analysis 52, pp. 4570-4578][1]).
As you say, it may have improved in the most recent versions, I don't know. And I'm not saying people should never use Excel. It's very handy for quick calculations on small datasets. I'm sure it's fine too for calculating a standard deviation. But I would double check the results if I wanted to use it for any more complicated calculations.
[1]: http://dx.doi.org/10.1016/j.csda.2008.03.004
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-07T11:17:37Z
SecondChildVoteTAG: 0
FirstChildTAG: >I was always told you should never use Excel for statistics. Use SPSS instead, if that's what you've got.
Excel can give incorrect answers for even simple tests. See this link for some examples:
why you shouldn't use MS Excel
Blatantly incorrect. Excel is used everywhere. From banking to government offices to calculate statistical information. Excel will do whatever you want it to do, but you need to know what it is that you want first. If you jump into using the built in Excel functionality without paying attention to what it does, you will get it wrong.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-04T15:16:43Z
FirstChildVoteTAG: 3
FirstChildTAG: In Excel use the function DEV.ST.POP and not DEV.ST. Also for variance you need to use VAR.POP and not VAR. Results will be equal to the manually calculated.
FirstChildUserIdTAG: 1210009
FirstChildUserNameTAG: GIAN66
FirstChildCreateTimeTAG: 2013-03-04T15:23:03Z
FirstChildVoteTAG: 2
SecondChildTAG: absolutely right.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-04T16:53:59Z
SecondChildVoteTAG: 0
FirstChildTAG: More precisely use =stdevp() instead of =stdev()
FirstChildUserIdTAG: 63180
FirstChildUserNameTAG: ianton
FirstChildCreateTimeTAG: 2013-03-04T15:48:20Z
FirstChildVoteTAG: 2
FirstChildTAG: It's better to do the calculation rather than use formulas. Otherwise you won't be testing whether you really understand the concepts!
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-04T16:15:06Z
FirstChildVoteTAG: 1
FirstChildTAG: Well if I am correct you got the same problem in excel and/ or spss. I can't understand why you are using the Ferrari (spss) to go for a walk in the park, or try to give the taxi driver (excel) to understand why you need not to walk till the next corner (result of calculations).
Anyway this is not your problem from my understanding neither is the right function of the excel.you can read the help or tutorial of the microsoft "experts in statistics"!!
Try to see if your intervals are all included and if you give the correct variables for calculation with the correct weighted factors or criteria . N-1 is a usual mistake I agree as this programs and functions have been made to work with large data sets rather than 5- 10 numbers.
I hope that will help you.
FirstChildUserIdTAG: 1239975
FirstChildUserNameTAG: Xenofon
FirstChildCreateTimeTAG: 2013-03-05T01:35:46Z
FirstChildVoteTAG: 0
IndexTAG: 1501
TitleTAG: about Problem 6 : of Exercise Set 6
Hi,
I am not understanding what is it meant by "the percent of entries that are more than 6 SDs above average" in problem 6. Can anyone help me understand the meaning of the sentence?
UserIdTAG: 916034
UserNameTAG: makcool
CreateTimeTAG: 2013-03-04T12:59:24Z
VoteTAG: 5
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 5
FirstChildTAG: It can also be read as "the percent of entries that are more than **Average+6*SD** in value"
Does this help? If not, you'll need to review the lectures in Section 4.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T13:24:13Z
FirstChildVoteTAG: 3
SecondChildTAG: Thanks a lot Klionheart. Your response is really helpful.
SecondChildUserIdTAG: 916034
SecondChildUserNameTAG: makcool
SecondChildCreateTimeTAG: 2013-03-05T05:13:30Z
SecondChildVoteTAG: 0
FirstChildTAG: Imagine walking 6 steps from a point(the mean) (one step-= ones SD )- now anything more is more than 6 SD's)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T13:37:20Z
FirstChildVoteTAG: 2
SecondChildTAG: but it it is 6 SD above mean. notice to that
SecondChildUserIdTAG: 152907
SecondChildUserNameTAG: visperad
SecondChildCreateTimeTAG: 2013-03-06T22:09:50Z
SecondChildVoteTAG: 0
FirstChildTAG: The problem is: which is correct result obtained by Chebyshev or by his student?
1/6 gives 17% and 1/36 gives 2.7% . These were my two possibilites and I lost.
FirstChildUserIdTAG: 1240706
FirstChildUserNameTAG: remipole
FirstChildCreateTimeTAG: 2013-03-04T19:52:26Z
FirstChildVoteTAG: 1
SecondChildTAG: Don't post answers(not even tentative ones) before the deadline, please.
If you think about what those numbers *mean*, you should be able to figure out the answer, though. Think about it a little, and if you really can't figure it out, in just a couple more days you can check the solution anyway ;)
But trust me, it will help a lot if you try to understand on your own.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T20:28:59Z
SecondChildVoteTAG: 0
FirstChildTAG: FYI - Markov's Inequality uses Average (Mean), whereas Chebyshev's uses Average (mean) and Standard Deviation. Just remember this simple rule. Now your call how you approach the problem.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-03-05T04:07:41Z
FirstChildVoteTAG: 1
FirstChildTAG: i got the cross. why? when and where we can check the answers?
FirstChildUserIdTAG: 152907
FirstChildUserNameTAG: visperad
FirstChildCreateTimeTAG: 2013-03-06T22:11:12Z
FirstChildVoteTAG: 1
IndexTAG: 1502
TitleTAG: Q. No 6 is excellent
We should always remember that it is difficult to make question than answer it. Q. No. 6 is excellently framed. We should thanks the staff for framing the questions like this. Because this type of questions help in getting the concept to its depth.
UserIdTAG: 655684
UserNameTAG: Rajesh04
CreateTimeTAG: 2013-03-04T12:55:10Z
VoteTAG: 14
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: I got it wrong, but think I thought process was sound. would it not be 2.5 times the mean in this case?
FirstChildUserIdTAG: 348290
FirstChildUserNameTAG: joshb
FirstChildCreateTimeTAG: 2013-03-04T23:37:32Z
FirstChildVoteTAG: 2
SecondChildTAG: Be sure you understand what the problem is asking.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-05T00:10:42Z
SecondChildVoteTAG: 0
SecondChildTAG: oh, less than 15.5. that makes sense. just a little to quick on trigger. but the question was straight forward
SecondChildUserIdTAG: 348290
SecondChildUserNameTAG: joshb
SecondChildCreateTimeTAG: 2013-03-05T21:53:21Z
SecondChildVoteTAG: 0
IndexTAG: 1503
TitleTAG: wrong answer
my ans was also wrong when i expressed with two decimal points... wats the difference btw 11.1 and 11.11 anyways i was been thought to express decimal points with two points aafter the decimal is that wrong... Please explain the reason
UserIdTAG: 1162240
UserNameTAG: Sudhadhayalan
CreateTimeTAG: 2013-03-04T12:20:56Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The post on the Course Info page came after this Practice Exercise was released. It applies to all exercises after the first week.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-03-04T13:21:59Z
FirstChildVoteTAG: 1
IndexTAG: 1504
TitleTAG: Practice exercise
Is it compulsory to submit and score the practice exercise? i practice it but do not get any score. Please suggest.
UserIdTAG: 947092
UserNameTAG: PKNeupane
CreateTimeTAG: 2013-03-04T10:55:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The practice exercises are, as the name suggests, practice.
They are not graded and not mandatory...but, I suggest you do them anyway. They usually help a lot with understanding the "real" Exercises :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T10:59:08Z
FirstChildVoteTAG: 0
IndexTAG: 1505
TitleTAG: Late join- exercise set grade?!
Hi,
If I have joined late (about a week late), that automatically gives me 3 zero exercise set grades (two of which are dropped, but still have one zero grade)...
can there be an exception for students who joined the course late?
Thanks
UserIdTAG: 1172351
UserNameTAG: Edmania
CreateTimeTAG: 2013-03-04T10:52:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No.
You only need a 35% grade to pass, anyway. One missed Set won't ruin your chances at all ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T10:57:54Z
FirstChildVoteTAG: 0
IndexTAG: 1506
TitleTAG: Lecture Presentation Style
I really enjoying the wonderful lecture style, simply great, for statistics beginners like myself.
UserIdTAG: 558560
UserNameTAG: wasimpak
CreateTimeTAG: 2013-03-04T09:53:18Z
VoteTAG: 21
CoursewareTAG: Section 4: Measures of spread / Lec 4.2: Deviations from average; the standard deviation (SD)
NumberOfReplyTAG: 1
FirstChildTAG: I agree with you, it's great!
FirstChildUserIdTAG: 1221482
FirstChildUserNameTAG: Kimmy2013
FirstChildCreateTimeTAG: 2013-03-04T18:50:44Z
FirstChildVoteTAG: 0
SecondChildTAG: I paused the lecture to express exactly the same sentiment.
SecondChildUserIdTAG: 304419
SecondChildUserNameTAG: oliverru
SecondChildCreateTimeTAG: 2013-03-06T02:44:14Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL, me too! I was just coming here to express how well she explains mathematical notation in the formulas, as well as other concepts.
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-03-06T22:09:51Z
SecondChildVoteTAG: 0
IndexTAG: 1507
TitleTAG: Need help
I don't understand the line on Problem 4 in Exercise set 5.
> Refer again to the distribution in Exercise 3
Please help me.
UserIdTAG: 1047641
UserNameTAG: rezowankabir
CreateTimeTAG: 2013-03-04T08:13:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: It should say "Refer again to the distribution in Problem 3".
FirstChildUserIdTAG: 797704
FirstChildUserNameTAG: Hersan13
FirstChildCreateTimeTAG: 2013-03-04T15:09:32Z
FirstChildVoteTAG: 0
FirstChildTAG: You should refer to the histogram in the problem 3: the one regarding the maternal ages...
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-03-05T15:05:35Z
FirstChildVoteTAG: 0
IndexTAG: 1508
TitleTAG: When will correct answers be uploaded?
Dear Prof,
When will correct answers be uploaded to the weekly exercises?How do I access them?
Harish
UserIdTAG: 1175422
UserNameTAG: harish09
CreateTimeTAG: 2013-03-04T07:57:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Click on Show Answer
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T08:05:10Z
FirstChildVoteTAG: 0
FirstChildTAG: where is this supposed to be found. I go back to the exercises and cant find them
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-05T04:20:55Z
FirstChildVoteTAG: 0
IndexTAG: 1509
TitleTAG: Dears,
Please tell us the reference book for this course.
Thak you,
UserIdTAG: 910465
UserNameTAG: kbelachew
CreateTimeTAG: 2013-03-04T06:56:36Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: This has been linked in various exercises, as well as in the course policy.
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T07:03:32Z
FirstChildVoteTAG: 0
FirstChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/
Is there in the wiki section and is the official online textbook. There is a book (search in the discussion forum for Freedman, Pisani and Purves and you can Check that book out.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T07:04:38Z
FirstChildVoteTAG: 0
IndexTAG: 1510
TitleTAG: Q6 is poorly worded.
Q6 is poorly worded.
UserIdTAG: 821917
UserNameTAG: dlacymss
CreateTimeTAG: 2013-03-04T06:35:36Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: I don't think so. Perfectly clear. Just checking that you understand concepts, as talked about in the many other posts about this question.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T06:50:39Z
FirstChildVoteTAG: 1
SecondChildTAG: It indeed is not poorly worded. It is formulated to test the understanding of bounds.Not understanding the question and not getting the answer does not make the question "worded poorly "
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-04T06:55:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Of course it doesn't. But this question is poorly worded, none-the-less and merits revision.
SecondChildUserIdTAG: 821917
SecondChildUserNameTAG: dlacymss
SecondChildCreateTimeTAG: 2013-03-05T06:42:02Z
SecondChildVoteTAG: 0
SecondChildTAG: And why do you say it is poorly worded - specifics please since you are "never the less" repeating such a claim ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-05T09:17:58Z
SecondChildVoteTAG: 0
SecondChildTAG: It isn't.
SecondChildUserIdTAG: 604234
SecondChildUserNameTAG: maurobruno
SecondChildCreateTimeTAG: 2013-03-05T19:07:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Frankly, Prasannasimha, I have not engaged in detail because I am really directing the comment to the setters of the questions for their consideration. Perhaps that is you. However I do find both the tone of your reply to me and your assumption that I got the question wrong rather off putting. Something for you to consider. However, you asked for my reasoning, and here it is for what it is worth: Greater than 40% is inclusive of the other two responses, which I know you do understand. And the question required me to click all three responses, which now you know that I understand. So, it all comes down to whether to click on all three options or just the third. In other words, we are debating the semantics of the question, not the math. When the discussion ends up focusing on the semantics and not the subject being studied, it is an indication that the phrasing should be reconsidered. That's all. Regards, dlacymss.
SecondChildUserIdTAG: 821917
SecondChildUserNameTAG: dlacymss
SecondChildCreateTimeTAG: 2013-03-06T04:40:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I would argue that in applied statistics, math without semantics is rather pointless.
SecondChildUserIdTAG: 387767
SecondChildUserNameTAG: JanDE
SecondChildCreateTimeTAG: 2013-03-06T10:28:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi janDE. I believe we are in agreement about semantics. Really. Because good semantics is very important. That's why I feel this question needs improvement. The math is fine. The phrasing needs work. My opinion. Cheers. dlacymss
SecondChildUserIdTAG: 821917
SecondChildUserNameTAG: dlacymss
SecondChildCreateTimeTAG: 2013-03-07T03:09:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Not at all! Just a game between 'at most' and 'at least' (i.e. less than or equal to and more than or equal to)...make sure you understand the meaning of inequalities and how inequalities (especially, their signs) change with the algebraic operations like multiplication....
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-03-05T15:08:50Z
FirstChildVoteTAG: 0
IndexTAG: 1511
TitleTAG: 'these weights' in question 4
I interpreted 'these weights' in sentence 3, to refer to the last sentence's three numbers, ie: these weights, therefore I answered incorrectly? Was the question referring to all the weights listed below's average? If so, I found the question unclear. If not, is there a glitch in the answer?
UserIdTAG: 291189
UserNameTAG: zenjen
CreateTimeTAG: 2013-03-04T06:32:58Z
VoteTAG: 5
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: Yes, the question is badly worded. And yes, there are many other posts discussing this.
You want the mean of the entire stem and leaf. Just giving the mean of one leaf is pointless.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T06:40:57Z
FirstChildVoteTAG: 1
SecondChildTAG: I did the same mistake. I could not understand the question.
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-04T21:38:38Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree its worded badly, but there is not intent in the wording either as to the need to compute (giving the mean of one leaf is pointless), therefore what's pointless is not relative here, it's a matter of answering the question as asked. Having to assume the writers intent is not part of this course..LOL
SecondChildUserIdTAG: 1026839
SecondChildUserNameTAG: MiltV
SecondChildCreateTimeTAG: 2013-03-05T00:27:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I did the same mistake! it's unfair!!!
SecondChildUserIdTAG: 610868
SecondChildUserNameTAG: Beatriz_Falva
SecondChildCreateTimeTAG: 2013-03-05T21:58:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I don´t think is our mistake… but the question must be completely CLEAR. with no chances to errors. By this I mean, it should have the both possibilities marked as right or be completely CLEAR about what "THESE" means or is referring to.
SecondChildUserIdTAG: 1172070
SecondChildUserNameTAG: alpisteasea
SecondChildCreateTimeTAG: 2013-03-05T23:18:52Z
SecondChildVoteTAG: 0
SecondChildTAG: The mess in the question 4 is the word **THESE**. It is not fair!!!
SecondChildUserIdTAG: 652456
SecondChildUserNameTAG: NMCFilho
SecondChildCreateTimeTAG: 2013-03-06T00:26:59Z
SecondChildVoteTAG: 0
FirstChildTAG: I had the same problem, they should then write the questions in a manner in which we can all clearly understand the question. That´s a mean question I must say.
FirstChildUserIdTAG: 1085886
FirstChildUserNameTAG: AndyHdz
FirstChildCreateTimeTAG: 2013-03-04T18:12:54Z
FirstChildVoteTAG: 0
SecondChildTAG: agreed. I calculate the all the leaf and stem avg. then avg of all. But reply the avg of 103+105+108, as asked in ques (based on my interpretation of the question)
SecondChildUserIdTAG: 898107
SecondChildUserNameTAG: navgir
SecondChildCreateTimeTAG: 2013-03-04T21:40:38Z
SecondChildVoteTAG: 0
SecondChildTAG: same problem.
"The line 10 | 358 should be read as 103, 105, 108. Select the option that is closest to the average of these weights."
SecondChildUserIdTAG: 255838
SecondChildUserNameTAG: EngineerHrenov
SecondChildCreateTimeTAG: 2013-03-05T20:47:50Z
SecondChildVoteTAG: 0
SecondChildTAG: ME TOO… is not clear !!
SecondChildUserIdTAG: 1172070
SecondChildUserNameTAG: alpisteasea
SecondChildCreateTimeTAG: 2013-03-05T23:19:09Z
SecondChildVoteTAG: 0
IndexTAG: 1512
TitleTAG: staff
Dear staff,
When we suppose to get answer for wk 1 exercise? If you give us answer or method of solving the exercise it will help us to to improv our knowledge.
UserIdTAG: 393580
UserNameTAG: Aditiak
CreateTimeTAG: 2013-03-04T06:28:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Press show answer it is there.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T06:36:42Z
FirstChildVoteTAG: 1
SecondChildTAG: is there any printed version of the solution?
SecondChildUserIdTAG: 199205
SecondChildUserNameTAG: ririana
SecondChildCreateTimeTAG: 2013-03-04T07:46:20Z
SecondChildVoteTAG: 0
IndexTAG: 1513
TitleTAG: need help on problem 6
can we say or apply Chebychev's bound as a sharpest bond for this problem ie. 1/k^2 but it gives different answers. if we choice closer options to our answer then which we apply at least or at most.
UserIdTAG: 393580
UserNameTAG: Aditiak
CreateTimeTAG: 2013-03-04T06:20:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Please, read some of the many other posts about this.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T06:38:43Z
FirstChildVoteTAG: 0
SecondChildTAG: Read the definition of Chebychev's bound to get you specific answer.
SecondChildUserIdTAG: 254949
SecondChildUserNameTAG: stormshadow
SecondChildCreateTimeTAG: 2013-03-05T16:20:23Z
SecondChildVoteTAG: 0
FirstChildTAG: > if we choice closer options to our answer then which we apply at least or at most.
The answer to this requires comprehension of Chebychev's bound, and so it's an integral part of the exercise. You should be able to answer yourself if you review the subject.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T11:33:38Z
FirstChildVoteTAG: 0
IndexTAG: 1514
TitleTAG: Pre-Posting of Exercises
Is there anyway you can post the next weeks exercises a bit earlier? I do travel on business a lot, I would like to have more flexibility with my schedule. Especially with the midterm approaching.
Thanks in advance.
UserIdTAG: 1169965
UserNameTAG: craigfarrel
CreateTimeTAG: 2013-03-04T06:07:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1515
TitleTAG: to course staff: suggestion for exercise page
before suggestion, a compliment.
it is very helpful and enjoying to see the progress bar as I proceed. (but does the overall bar at the end count the unattended exercises sets also which are understandably future and have zero values.
suggestion for the exercise/problem pages:
what if we can see the answer after each question is finally checked and submitted. that increases understanding and learning for the next questions. And yes, that increases the probability of getting next questions 'right'. But, if learning is the goal, then that may not be a disliked by the instructor/grader team.
All said, I am extremely happy and enjoying the course. Thanks to professors and all of the course team.
UserIdTAG: 867488
UserNameTAG: mkhaled
CreateTimeTAG: 2013-03-04T05:58:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: Answers being revealed can surely help for learning.
But all of us should wait until the submission s deadline has passed, otherwise there is no point for the Edx certificate system.
What you are suggesting is already the case of the practice set of exercises.
Moreover, I think that most of graded exercises are pretty independent to each other, and that most of all answers can be fouond in the lectures.
Good luck to you.
FirstChildUserIdTAG: 830835
FirstChildUserNameTAG: Zacharie
FirstChildCreateTimeTAG: 2013-03-04T10:02:34Z
FirstChildVoteTAG: 0
IndexTAG: 1516
TitleTAG: Problem 8 : 3.0 points
Is the price of all the 32 houses is $834,000?
If the price is reduced, whether it is reduced for one house or for all the 32 houses?
UserIdTAG: 1130499
UserNameTAG: Nivethan
CreateTimeTAG: 2013-03-04T05:52:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: $834,000 is the price for only one of the 32 houses. That same house will now cost $819,000
FirstChildUserIdTAG: 1098346
FirstChildUserNameTAG: caeduft
FirstChildCreateTimeTAG: 2013-03-04T06:05:16Z
FirstChildVoteTAG: 0
FirstChildTAG: You know the old price and new price for a house. You know the total number of houses. So you can work out the change in the average price.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T06:34:16Z
FirstChildVoteTAG: 0
SecondChildTAG: For one house only.
SecondChildUserIdTAG: 1274748
SecondChildUserNameTAG: kusumawati
SecondChildCreateTimeTAG: 2013-03-04T06:57:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Whether or not the other 31 houses are pricing at $834,000 is irreverent here. The only thing you need to **remember** is that ONE house got the price drop, other 31 houses' prices remains unchanged.
SecondChildUserIdTAG: 177886
SecondChildUserNameTAG: leaonfm
SecondChildCreateTimeTAG: 2013-03-04T10:36:11Z
SecondChildVoteTAG: 0
SecondChildTAG: this was not clear
SecondChildUserIdTAG: 1121196
SecondChildUserNameTAG: zabily
SecondChildCreateTimeTAG: 2013-03-04T20:48:17Z
SecondChildVoteTAG: 0
SecondChildTAG: That was not made clear at all, the question was phrased to make it sound like all prices were dropped
SecondChildUserIdTAG: 901850
SecondChildUserNameTAG: hshamma
SecondChildCreateTimeTAG: 2013-03-04T20:50:54Z
SecondChildVoteTAG: 0
SecondChildTAG: I understand in that way too and I get wrong. I'm such an idiot
SecondChildUserIdTAG: 1151142
SecondChildUserNameTAG: Mohamed-Salmane
SecondChildCreateTimeTAG: 2013-03-05T04:13:44Z
SecondChildVoteTAG: 0
FirstChildTAG: @Nivethan, if you read the question very carefully; it says "*ONE* of the houses costs $834,000". "***the* price** is reduced" implies a single house to me. Hope this helps you.
FirstChildUserIdTAG: 1067669
FirstChildUserNameTAG: psanders
FirstChildCreateTimeTAG: 2013-03-04T18:42:07Z
FirstChildVoteTAG: 0
IndexTAG: 1517
TitleTAG: Problem 6 - Am i going in right direction?
I am stuck with this question. My thinking is portrait as below. ![Ex5-P6][1]
Can anyone tell me whether i am going right or wrong direction? if it is right, then this will be a hints to me and others as well? Please also let me know whether it violates honor code.
[1]: https://edxuploads.s3.amazonaws.com/13623743741343661.jpg
UserIdTAG: 99047
UserNameTAG: taminur
CreateTimeTAG: 2013-03-04T05:12:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: Have you read through any of the other posts about this?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T05:41:24Z
FirstChildVoteTAG: 0
FirstChildTAG: There is a problem with your limitation of the bound. See in the discussions Lakshman Rekha and you may get an idea how a bound can be moved without altering the truth.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T08:24:54Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks for your response. Unfortunately, I have not found discussions of Lakshman Rekha. Could you please give me a link?
SecondChildUserIdTAG: 99047
SecondChildUserNameTAG: taminur
SecondChildCreateTimeTAG: 2013-03-04T09:45:46Z
SecondChildVoteTAG: 0
SecondChildTAG: I got u. https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5131a8c04bebda2b0000006e
. nice story.
SecondChildUserIdTAG: 99047
SecondChildUserNameTAG: taminur
SecondChildCreateTimeTAG: 2013-03-04T10:10:29Z
SecondChildVoteTAG: 0
FirstChildTAG: No need to move that blue line...thoroughly understand Markov's inequality....AT MOST 'x' are in red region, so AT LEAST remaining are in yellow region...
Got it?
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-03-05T15:13:43Z
FirstChildVoteTAG: 0
IndexTAG: 1518
TitleTAG: Set 6 prob 6
Set 6 prob 6 asks: "6 SDs above average is (pick the sharpest correct bound from among the following options):" I'm unsure what "sharpest correct bound" means when 6SD is found between 2 of the likely provided answers. In one case, 6SD is closer to one of the answers, but the answer would indicate poorer performance for the example firm. On the other hand the provided smaller answer is at a flatter part of the tail, thus "sharper"?
UserIdTAG: 940447
UserNameTAG: rob4511
CreateTimeTAG: 2013-03-04T05:01:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: The best possible bound without sacrificing the truth!! Look at the discussion where I have given an example of Laxman rekha.Ravana could be miles away, feet away or inches away from the line/boundary. Between miles and feet away, feet away is a better or is a sharper bound compared to miles away even though inches away is a still sharper bound.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T06:33:11Z
FirstChildVoteTAG: 1
FirstChildTAG: Problem 6 is the easiest! There is one clear answer. NO ambiguity there!
FirstChildUserIdTAG: 254949
FirstChildUserNameTAG: stormshadow
FirstChildCreateTimeTAG: 2013-03-05T14:32:32Z
FirstChildVoteTAG: 1
SecondChildTAG: I didn't get problem 6... and still now i don't know the answer and how to get it.
SecondChildUserIdTAG: 929134
SecondChildUserNameTAG: louiewashere
SecondChildCreateTimeTAG: 2013-03-05T23:27:48Z
SecondChildVoteTAG: 0
IndexTAG: 1519
TitleTAG: Problem 8
one of the houses costs $834,000 what about the rest of the houses without knowing this how can we calculate the change in average
UserIdTAG: 1105885
UserNameTAG: AJITHABK
CreateTimeTAG: 2013-03-04T04:18:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: Look through the lecture. We do not need to know individual values apart from the one that changed.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T05:03:14Z
FirstChildVoteTAG: 0
FirstChildTAG: average = total/32
What has changed since the original average was calculated?
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-04T12:54:49Z
FirstChildVoteTAG: 0
IndexTAG: 1520
TitleTAG: After this course will second and third parts promptly follow
Hi,
I need to have a full review of stat before my Summer Classes. Will the second and third parts of this Intro stat course immediately follow Stat 2.1x? Will we cover the complete online textbook?
Thank You!
Kym
UserIdTAG: 985667
UserNameTAG: KymberlyKline
CreateTimeTAG: 2013-03-04T04:08:05Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Not answering all your queries, but Prof comment:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/51303b710aa32f2a00000072
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T04:14:05Z
FirstChildVoteTAG: 0
IndexTAG: 1521
TitleTAG: the answer of problem 6 is correct?
i think the correct answer of Problem 6 is wrong, i selected " more than 45" ,i think it is right
UserIdTAG: 1191891
UserNameTAG: elsie0612
CreateTimeTAG: 2013-03-04T04:00:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: > i think the correct answer of Problem 6 is wrong,
It's not. Just read some of the many posts about this question.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T04:08:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Just read the last sentence "**select all that are correct**". I failed to read that one,too.
SecondChildUserIdTAG: 1262183
SecondChildUserNameTAG: hsinling
SecondChildCreateTimeTAG: 2013-03-04T05:27:43Z
SecondChildVoteTAG: 0
SecondChildTAG: He he I'm among the victims too, it's tricky yet good for practising carefulness, I didn't read the less than part :(
SecondChildUserIdTAG: 1274748
SecondChildUserNameTAG: kusumawati
SecondChildCreateTimeTAG: 2013-03-04T08:02:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I was about to post the same (answer is not correct) and then realized that it was asking for all correct answers...
SecondChildUserIdTAG: 1248519
SecondChildUserNameTAG: MarioPC
SecondChildCreateTimeTAG: 2013-03-04T08:27:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Arrrgh! Me too... Let's take this as a lesson in itself!
SecondChildUserIdTAG: 1242147
SecondChildUserNameTAG: VickyUK
SecondChildCreateTimeTAG: 2013-03-04T08:51:36Z
SecondChildVoteTAG: 0
SecondChildTAG: 'Wait, what??!! oh yeah...damn' was my thought process after getting this question wrong. :D
SecondChildUserIdTAG: 1265802
SecondChildUserNameTAG: GMORRIS010
SecondChildCreateTimeTAG: 2013-03-04T20:38:18Z
SecondChildVoteTAG: 0
IndexTAG: 1522
TitleTAG: SD and indicators
Can we base our insertion that list b is bigger by the fact that it has two more entries then list A?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-04T03:08:33Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Adding the entries 0 and 100 will not change the average, but, since the numbers are spread over a larger range, the SD will be higher. Is this also a correct assumption?
FirstChildUserIdTAG: 1250862
FirstChildUserNameTAG: KarlaGeo
FirstChildCreateTimeTAG: 2013-03-04T03:12:42Z
FirstChildVoteTAG: 2
SecondChildTAG: even i think so..coz SD simply is d deviation from the mean. so jus by looking at the large difference b/w 0 and 100 we can make out that the SD wil increase in LIST B.
SecondChildUserIdTAG: 403054
SecondChildUserNameTAG: PrachiP
SecondChildCreateTimeTAG: 2013-03-05T12:05:01Z
SecondChildVoteTAG: 0
SecondChildTAG: The SD measure the spread form the mean. Puting the list in order you find to extra values 0 and 100. Calculating it I get SD_A = 6.16 and SD_B = 21.17.
SecondChildUserIdTAG: 122004
SecondChildUserNameTAG: fqantonio
SecondChildCreateTimeTAG: 2013-03-05T16:41:54Z
SecondChildVoteTAG: 0
FirstChildTAG: The mean of B is also important, and the sum of squared differences. So if $\sum{(x_i - \bar x)^2}$ is the same for both, then the sample size will be the deciding factor.
The answer to the question explains how to comprehend this without calculating.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T03:13:19Z
FirstChildVoteTAG: 1
IndexTAG: 1523
TitleTAG: Question 7 needs clarification
In Question 7 the time (e.g number of months remaining) within which the board is required to reach its goal is not stated. One should not be left to assume that the rest of the money needs to be raised within one month.
UserIdTAG: 1293667
UserNameTAG: research4life
CreateTimeTAG: 2013-03-04T02:56:35Z
VoteTAG: 5
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: Time is irrelevant. You know how much has been raised. How much, on average, remains for the 12 to raise?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T03:02:58Z
FirstChildVoteTAG: 3
SecondChildTAG: interesting. I tried to both to wait the time remaining as 11/12ths in the calendar year. also tried a more simplified version by just taking the mean of the remaining and this too was incorrect. I am sure the solution is probably straightforward, but I am not seeing it.
SecondChildUserIdTAG: 348290
SecondChildUserNameTAG: joshb
SecondChildCreateTimeTAG: 2013-03-04T20:54:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeah, you're over-thinking it.
Time has absolutely nothing to do with the problem. Only the total, the averages, and the number of people are involved.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T23:01:45Z
SecondChildVoteTAG: 0
IndexTAG: 1524
TitleTAG: Week 1 Execrise 2: More Detail Explanation? Problem 2 a to professor
$1.32\cdot10=13.2\%$ Why 1.32 x 10. I dont understand.
UserIdTAG: 802316
UserNameTAG: WeiPing
CreateTimeTAG: 2013-03-04T02:51:45Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: You have 10 years of being in your 30s. The density of the interval is $1.32 \% $ per year
Assuming equal distribution in the category, the $\%$ in their 30s is $1.32 \times 10=13.2\%$
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T03:08:30Z
FirstChildVoteTAG: 1
SecondChildTAG: I cant understand the explanation.
Why in the part b), they multiply by 10?
12.5/15 x 10 = 8.33%
Why again 10?
SecondChildUserIdTAG: 1208522
SecondChildUserNameTAG: nicifuentes
SecondChildCreateTimeTAG: 2013-03-07T00:18:30Z
SecondChildVoteTAG: 0
FirstChildTAG: We must multiply by 10 because there are 10 years in the range of ages 30 (inclusive) to 40 (exclusive). So multiply 1 year for age 30 by 1.32, then multiply 1 more year for age 31, etc. (repeat 10 times)
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-04T03:09:10Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi Susan, we answered at (almost) the same time.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-04T03:11:04Z
SecondChildVoteTAG: 0
IndexTAG: 1525
TitleTAG: Problem 6 is very silly despite protestations from the question setter(s).
In almost all examinations that I have taken (including American Board of Internal Medicine and others), the student is expected to mark the single best answer. Here, you have turned that concept on its head. I am sure you wanted to analyze the students' understanding of Markov's bound and NOT his/her understanding of your (the question setter's) thought process. **I urge the teaching staff to withdraw this question (Problem 6) grade the answers on remaining questions only**.
UserIdTAG: 877817
UserNameTAG: sreedhara
CreateTimeTAG: 2013-03-04T02:30:38Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: Huh,I have also taken such exams and let it be clear apart from choose the best answer there are choose all the answers that are appropriate.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T02:34:22Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, there are questions where multiple answers are correct (for example, causes for anemia) but not like the one given in Problem 6. What was the intention of the question? To test one's understanding of Markov's bound or to read the question setter's mind?
SecondChildUserIdTAG: 877817
SecondChildUserNameTAG: sreedhara
SecondChildCreateTimeTAG: 2013-03-04T02:56:25Z
SecondChildVoteTAG: 0
SecondChildTAG: No , it is to test the concept of a mathematical boundary.
It seems you did not understand the question so I would recommend that you reread the question, go through the course material and if required do a bit of outside reading before you make comments that it is silly. The question indeed is testing a specific concept and that you did not get the concept and did not understand it and then apply it doesn't make it silly.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-04T03:18:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Sreedhara, while you are correct that some exams ask to take the best answer, not all the exams have to be like that. Moreover last sentence in the question asks us to select all that are correct. It is tricky, but I think the intention was to make us think and go through the concept deeply.
Prasanna, you may be right but I am afraid calling others silly is a slippery slope even if others seem to be unreasonable.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-06T05:53:44Z
SecondChildVoteTAG: 0
FirstChildTAG: The instructions are clear. If you follow the instructions and get your (very basic) math right, you will also mark the right answer(s).
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-04T02:56:22Z
FirstChildVoteTAG: 1
FirstChildTAG: I presume from your name that you know the story but see the story I told in perspective of bounds.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5131a8c04bebda2b0000006e
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T04:05:23Z
FirstChildVoteTAG: 0
IndexTAG: 1526
TitleTAG: Problem 3: Answer Is Incorrect
All we know is that B's members match A's members and, beyond those, have 5 additional members with values that equal the mean of 100. If ANY of the values of A differ from 100, then the SD of distribution A will have a value > 0, and the additional 5 members of B, which necessarily have a squared difference from the mean equal to 0, which will be taken account of before the sum of the squares is divided by the number of members in the distribution (30 for B rather than 25 for A), should have a smaller SD than found in A. But if ALL the members of A have a value of 100 (and we are given no information that this is not the case), then the standard deviation of A will be 0, as will the standard deviation of B (since its additional five members equal the mean). So there is no way, on the basis of the information given, to determine whether the SD of B is less than or equal to the SD of A.
UserIdTAG: 1305333
UserNameTAG: bellerin
CreateTimeTAG: 2013-03-04T01:41:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 6
FirstChildTAG: > Answer Is Incorrect
No, it is not.
>But if ALL the members of A have a value of 100 (and we are given no information that this is not the case),
I suggest you read the question again. And also read the Honour Code you agreed to again.
Reading past posts would help too.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T01:49:53Z
FirstChildVoteTAG: 1
SecondChildTAG: Don't forget phrasing of question itself:- List A has 25 different entries........this does not imply or safe to assume all numbers are equal to 100.
SecondChildUserIdTAG: 1181586
SecondChildUserNameTAG: eumannu
SecondChildCreateTimeTAG: 2013-03-04T03:52:59Z
SecondChildVoteTAG: 0
SecondChildTAG: I made the same mistake by overlooking that important phrasing of '25 _different_ entries'. Would have got it correct if I had :)
SecondChildUserIdTAG: 1165841
SecondChildUserNameTAG: moralloki
SecondChildCreateTimeTAG: 2013-03-04T22:35:44Z
SecondChildVoteTAG: 0
FirstChildTAG: I would suggest that you read it again. And the online text, as well.
As for the Honor Code, students are on their honor not to rely on the answers of others. If they have not yet completed a certain exercise or quiz, then they should not be reading the forums for that specific exercise. But for those who have already completed an exercise in question, the purpose of the discussion forums is to raise issues with, among other things, the correctness or not of the questions. And this is not the first question that has had a questionable answer. Bringing this to the attention of the designers of the course is for the benefit of everyone.
FirstChildUserIdTAG: 1305333
FirstChildUserNameTAG: bellerin
FirstChildCreateTimeTAG: 2013-03-04T04:25:17Z
FirstChildVoteTAG: 1
FirstChildTAG: > But for those who have already completed an exercise in question, the purpose of the discussion forums is to raise issues with, among other things, the correctness or not of the questions.
Yes, discussion is fine. And I would certainly expect beginner stats students to know more than the Prof. As shown by all the "the answer's wrong!" posts.
But the forum guidelines explicitly tell you not to discuss solutions to problems.
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
>As for the Honor Code, students are on their honor not to rely on the answers of others.
Yes, and they are also not supposed to give answers to assessment items on the forums.
>Not post answers to problems that are being used to assess student performance.
https://www.edx.org/honor
>And this is not the first question that has had a questionable answer.
There is nothing questionable here. The issue was fixed. And many other "questionable" ones are students not understanding the question and/or concept.
>Bringing this to the attention of the designers of the course is for the benefit of everyone.
Yes, and there are ways to do it without screaming from the rooftops as some have done.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T04:42:21Z
FirstChildVoteTAG: 0
FirstChildTAG: The imperious attitude is out of place in a course like this. If you consider discussion and every criticism to constitute a personal attack, then you will discourage use of the forums, which perhaps is your objective. I am thankful that Drs. Stark and Adhikari have provided this excellent course online. It is a shame that it has been left under the draconian surveillance of a Cerberean guardian. But so be it. I will continue to make note of answers that raise questions.
FirstChildUserIdTAG: 1305333
FirstChildUserNameTAG: bellerin
FirstChildCreateTimeTAG: 2013-03-04T15:50:08Z
FirstChildVoteTAG: 2
SecondChildTAG: You are certainly entitled to discuss your doubts about the Problem.
**After** the deadline is past and the discussion won't have any chance of influencing the answers, and therefore the grades, of people taking the course.
Right now, however, I can't and I won't. From the honor code:
> By enrolling in an edX course, I agree that I will: [...]
>- Not engage in any activity that would dishonestly improve my results, or improve or hurt the results of others.
>- Not post answers to problems that are being used to assess student performance.
You gave an answer to Problem 3, violating one clause. If the answer is correct, you potentially improved the results of others. If it's wrong, you potentially hurt the results of others. Either way, you violated the other clause.
I will gladly discuss with you whether I think your analysis of the problem is correct or not, and why. **After** March 06 23.30 GMT.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T17:39:52Z
SecondChildVoteTAG: 0
FirstChildTAG: > The imperious attitude is out of place in a course like this.
It's funny that it is usually those who choose not to follow the rules who get upset when someone is called on it.
This course is trying to maintain some academic integrity. Not all moocs care about such niceties, but they don't give out certificates. edX wants to be a player in world education, so integrity of results is important.
So students have to show a bit of integrity too.
> If you consider discussion and every criticism to constitute a personal attack,
Huh?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-05T01:28:09Z
FirstChildVoteTAG: 0
FirstChildTAG: Bellerin for starters- read the question again - it mentions clearly there are 25 **different** entries .
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-05T09:21:50Z
FirstChildVoteTAG: 0
IndexTAG: 1527
TitleTAG: In case you didn't join yet.
I would like you to join the EdX community on facebook!
http://www.facebook.com/groups/edXcommunity/
It would be great to have everybody taking these online courses in a single group and maybe finding people in the same city. (:
UserIdTAG: 66457
UserNameTAG: Agu10
CreateTimeTAG: 2013-03-04T01:15:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1528
TitleTAG: Posting answers to check our work
Could we eventually have the answers to these exercises posted?
When I get them wrong I usually have no idea why! or how I was supposed to work out the answer (ie. Problem 1 of Exercise Set 6.). It would be very helpful to see what the correct procedure is especially since the work is cumulative.
UserIdTAG: 1059425
UserNameTAG: RachelDay
CreateTimeTAG: 2013-03-04T00:35:33Z
VoteTAG: 3
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: > Could we eventually have the answers to these exercises posted?
Yes, as is explained in the Course Info documents. After the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T00:36:27Z
FirstChildVoteTAG: 0
SecondChildTAG: It is now the third. The prof extended the deadline for the first assignment by one day. I realize she is busy but it has me wondering if everything is ok.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-04T01:22:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Are you sure you are looking at the right deadline Sherryjo? The deadline for Week 2 exercises is 6 March @ 23:30 GMT - a little over 2.5 days from now.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-03-04T07:40:44Z
SecondChildVoteTAG: 0
SecondChildTAG: The answers for week 1 are available since February 28. Look into the exercise sets and click "Show answer".
The answers for week 2 will be available in the same way **after** the due date of March 6, 23.30 GMT.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T12:01:31Z
SecondChildVoteTAG: 0
IndexTAG: 1529
TitleTAG: I've joined in late - Need some help!
Hi I've joined in late and it looks like I have already missed out on 3 exercises.
Where in the website can i find the materials for the first 3 course sections? Any chance of catching up with the first 3 exercises?
Thanks in advance
Sylvain
UserIdTAG: 640408
UserNameTAG: sbagnack
CreateTimeTAG: 2013-03-04T00:32:32Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: You need to explore the course pages. All the lectures and exercises are under the Courseware tab. Also look at Course Info and read all the course documentation.
This post might help, if you are confused with the layout.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5129096f872f381f00000093
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T00:37:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Susan,
thanks for that.
Sylvain
FirstChildUserIdTAG: 640408
FirstChildUserNameTAG: sbagnack
FirstChildCreateTimeTAG: 2013-03-04T00:41:06Z
FirstChildVoteTAG: 0
IndexTAG: 1530
TitleTAG: Markov vs Chebychev: not a fair comparison the way it was presented
I think it was not fair to compare Markov's bound to Chebychev's bound, the way the problem was presented the first time round. We were not given the SD at the time. So, with the data we were given, we could not do any better than the Markov's bound. And, exactly as 4learning suggests in the problem set discussion, the imprecision of Markov's bound compared to Chebyshev's bound will depend on SD. Yes, Chebychev's bound can be more precise, but it requires more data.
UserIdTAG: 634217
UserNameTAG: taprokh
CreateTimeTAG: 2013-03-04T00:14:04Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: They are two methods.As you get more information the bound becomes more precise.What is wrong with that. it is like having a intertial navigation system and a GPS -civilan and military. each has its own level of precision but can complement each other.The civilan GPS though can never be more accurate than the military one but whn combined with the inertial navigation system gives better information for the missile and the circular propability of error(CEP) of the missile hitting a target decreases with more information.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T02:23:55Z
FirstChildVoteTAG: 2
FirstChildTAG: I agree with taprokh. It wasn't fair because we lost generality when we said the SD=5.
What if our sample looked like this: 0,0,0,0,100. Then the average is still 20.
The SD = sqrt((4*20^2+80^2)/5) = 40. Now 60 = 1.5*SD so Chebyshev says that the percent of people older or equal to 80 years old cannot be higher than 100/1.5^2 = 44.44%. While Markov says that it cannot be higher than 25%. So now Markov's bound is better.
Edit: I did some calculations wrong but i fixed the numbers ... i hope :D
old: SD = sqrt((4*20^2+100^2)/5)
new: SD = sqrt((4*20^2+80^2)/5)
FirstChildUserIdTAG: 46554
FirstChildUserNameTAG: Szenko
FirstChildCreateTimeTAG: 2013-03-06T11:34:36Z
FirstChildVoteTAG: 2
IndexTAG: 1531
TitleTAG: I can't submit the answer
I did the exercise 1 but i can't submit the answer! How can i do that...
UserIdTAG: 1261728
UserNameTAG: Djalma123
CreateTimeTAG: 2013-03-03T23:50:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You can't. Week 1 is over. You can only submit week 2.
To be able to submit, you need a Check button. Look at this post, it has some explanation about the process:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5132e6f49788382a0000003a
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T00:01:12Z
FirstChildVoteTAG: 0
IndexTAG: 1532
TitleTAG: STAFF - Prof. Stark / Adhikari - Textbook Homework Schedule
RE: Course: Statistics 2.1x, Spring 2013, UC Berkeley: Profs P.B. Stark and A. Adhikari
The dates for textbook homework seem to be based on the start date initially intended and not our actual class start date, therefore the textbook assignments are closing prior to our actual schedule?
Thanks
UserIdTAG: 504031
UserNameTAG: Lindy7
CreateTimeTAG: 2013-03-03T22:57:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > The dates for textbook homework
These are **not** our homework exercises. The only exercises that we are graded on are those in the Coursework section, marked with the blue alarm clock icon.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T23:06:10Z
FirstChildVoteTAG: 0
IndexTAG: 1533
TitleTAG: Problem 6: incorrect solutions
The question has no correct answers to choose from. "More than 25" can mean 81 which is wrong. And the same goes for the rest of the options.
Yes, I do understand what the question is asking and I do know the answer and the reason why that answer is such. But the answers provided are ALL wrong due to simple logic.
UserIdTAG: 1036236
UserNameTAG: H4ckJack
CreateTimeTAG: 2013-03-03T22:57:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 4
FirstChildTAG: If you apply the logic taught in the lectures, then I think you will find that you might change your mind...
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-03T23:13:23Z
FirstChildVoteTAG: 0
SecondChildTAG: H4ckJack would you say, then, that it's not true that "More than 25". :)
SecondChildUserIdTAG: 963407
SecondChildUserNameTAG: JRuth
SecondChildCreateTimeTAG: 2013-03-04T16:26:55Z
SecondChildVoteTAG: 0
FirstChildTAG: > Yes, I do understand what the question is asking and I do know the answer and the reason why that answer is such. But the answers provided are ALL wrong due to simple logic.
Well... that is quite a statement! I'm sure you are right, because you said so :-)
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-03T23:16:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, so many who are so sure they are "right". Sometimes they are (mistakes happen), most often they are not.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-03T23:21:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, that is the OP speaking Ex Cathedra :-)
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-03T23:31:25Z
SecondChildVoteTAG: 0
FirstChildTAG: So, 81 is less than 25 now? Well, it seems I have to reconsider everything I knew about numbers :o
Jokes aside: review the lectures. Think. Think again. You can figure it out.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T12:05:57Z
FirstChildVoteTAG: 0
SecondChildTAG: No, I said 81 is MORE than 25.
8127489745197817248023 is more than 25 (and is an incorrect answer).
I hope you guys understand basic math and stop white knighting. This is a Berkeley lecture.
SecondChildUserIdTAG: 1036236
SecondChildUserNameTAG: H4ckJack
SecondChildCreateTimeTAG: 2013-03-04T20:05:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, I know what you said. I was being a bit ironic. Again, jokes aside:
There is no error in the exercise. It has a solution. You need to understand what the numbers represent, and if you think there's no valid solution, then clearly you don't understand it. Yet. But I'm sure that if you stop assuming that the professors are wrong and start thinking, you'll figure it out.
More than this I can't say before the deadline, but if you still want to discuss it better after that, I'll be here.
Oh, and 8127489745197817248023 is certainly wrong, but not because of the bound :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T20:42:43Z
SecondChildVoteTAG: 0
FirstChildTAG: More than 21 means more than 21. This can be either true or false. More than 21 doesn't mean 81 it doesn't mean 10023 or any other specific value. I find both the wording and the answers perfectly fine without any logical contradictions.
FirstChildUserIdTAG: 897233
FirstChildUserNameTAG: makmanos
FirstChildCreateTimeTAG: 2013-03-06T13:35:43Z
FirstChildVoteTAG: 0
IndexTAG: 1534
TitleTAG: Ex cathedra
What does ex cathedra mean in the 3.4 video? Is it a term used in England?
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-03T22:29:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: From Google.
ex cathedra: With the authority derived from one's office or position.
And (in a religious sense) if the Prof was to be the next Pope, she has already made an infallible pronouncement.
How to post in the correct forum (scroll down):
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/51320ee24bebda2b000000c4
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T22:43:25Z
FirstChildVoteTAG: 0
FirstChildTAG: Ex cathesdra is the pope/cardinal delivering from the pulpit ie in virtue of his official position and not as an ordinary human. (Literally from the chair0
http://en.wikipedia.org/wiki/Papal_infallibility
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T02:27:39Z
FirstChildVoteTAG: 0
FirstChildTAG: Susan and Prasannasimha gave the literal explanation. Hope you won't mind if I chime in in layman's terms :)
Ex cathedra is a figure of speech, derived from the latin expression. It basically means than you should take what is said as the truth.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-04T12:11:34Z
FirstChildVoteTAG: 0
IndexTAG: 1535
TitleTAG: I'd problems with the date
Dear professor:
I was in a mistake about the date of the excersice, because in my computer the first week I could watch only the first ejercice. So I am trying to make but i can`t. So I wanna know if i can continue with this course or not. In the positive way, i wanna know to continue with the excersice of the second week. I waiting your answer, i hope i won`t problems...
UserIdTAG: 1219973
UserNameTAG: micaelacerezoli
CreateTimeTAG: 2013-03-03T22:07:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Of course you can continue. You just can't submit week 1 assessment work. But can certainly do week 2. Read the Course Info documents for grading details.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T22:10:57Z
FirstChildVoteTAG: 1
IndexTAG: 1536
TitleTAG: GMT clock posting
May I suggest to the course administrators an aid for all students worldwide to eliminate the weekly deadline confusion: Post one of the easily available GMT date and time clocks on the landing page for the course for easy, constant and current reference by all. Probably (no statistical pun intended) most students have adjusted to the deadline by now but with DST coming up shortly and at different dates in different countries the confusion may become compounded. Adding to the possibility of confusion, London time may go to DST but GMT will not be affected.
Respectfully
UserIdTAG: 398274
UserNameTAG: aremh
CreateTimeTAG: 2013-03-03T21:20:18Z
VoteTAG: 3
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.3: Comparing and combining averages
NumberOfReplyTAG: 3
FirstChildTAG: I believe we all can type "gmt time" on google or do the hw one day earlier, though.
FirstChildUserIdTAG: 334059
FirstChildUserNameTAG: RafaelNeumann
FirstChildCreateTimeTAG: 2013-03-03T21:28:45Z
FirstChildVoteTAG: 1
FirstChildTAG: All they need to do is add a GMT display to their internet clock. **Edit to add: For Windows Vista onwards.** Doesn't work in XP. Link in comments to a tech site that has a workaround for XP.
Click on the time display in the system tray and the clock will display.:
![enter image description here][1]
![enter image description here][2]
My clock shows Sydney, London, and Boston time. **Please read patey's comment below regarding daylight saving - you need to use "Coordinated Universal Time" option**
You can add a clock by going into the Change date and time settings:
![enter image description here][3]
Just find the timezone you require, and tick "Show this clock". Of course, this is for Windows. Macs and Linux, I am clueless.
[1]: https://edxuploads.s3.amazonaws.com/13623470851343659.png
[2]: https://edxuploads.s3.amazonaws.com/13623468231343678.png
[3]: https://edxuploads.s3.amazonaws.com/13623468941343605.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:46:06Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you, Susan!
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-03T23:50:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Nice Tip, SusanAust!
One small thing. After 31 March, London, Dublin, Lisbon etc will be one hour ahead of GMT. For those who don't want to submit their homework an hour sooner than is absolutely necessary, they can choose the next timezone up in the list - called "Coordinated Universal Time".
That should stay on GMT.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/1362355906134360.png
SecondChildUserIdTAG: 434869
SecondChildUserNameTAG: patey
SecondChildCreateTimeTAG: 2013-03-04T00:16:07Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks patey.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-04T00:19:56Z
SecondChildVoteTAG: 0
SecondChildTAG: One thing though - it doesn't work on XP computers!!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-04T02:29:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry. Did a search, and this was a feature introduced in Vista onwards. Found this post, that might help
http://techie-buzz.com/softwares/display-multiple-time-zones-in-the-xp-system-tray.html
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-04T02:38:00Z
SecondChildVoteTAG: 0
SecondChildTAG: There is a software called qclock which puts small gadgets on your screen and is useful
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-04T03:20:07Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, Susan! I expected I'd learn some new statistics information (and already have!) but great to also learn something so convenient about Windows. That's a great tip - and now I have both local and GMT time zones displayed.
And I'm behind GMT, so I've gotta get cranking and finish the lectures and homework! :)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-06T03:56:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Or you could try finishing the exercises a day before the deadline (gasp!).
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-04T03:16:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Takes all the fun and adrenaline rush out of procrastinating while concentrating on the minute hand (or digits)of the clock!
SecondChildUserIdTAG: 398274
SecondChildUserNameTAG: aremh
SecondChildCreateTimeTAG: 2013-03-04T21:29:49Z
SecondChildVoteTAG: 0
SecondChildTAG: What!? And have nothing to complain about when you miss the deadline?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-05T01:29:02Z
SecondChildVoteTAG: 0
IndexTAG: 1537
TitleTAG: Interval average
In the lecture Professor A used the term 'interval average'. I was a little confused because i thought she was actually referring to the average of the whole list and not the average of a particular interval. What did she mean by 'interval average'?
Thanks,
dfburke
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-03-03T21:13:37Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.2: Deviations from average; the standard deviation (SD)
NumberOfReplyTAG: 3
FirstChildTAG: When you look at the table that compares the averages of different intervals or groups, just know that each groups or interval is different from the other groups or intervals. They are not the same group. For example, in that Table, it is showing the average heights of each age group. The age group 20-30 is not the same as the age group 75+ because they are two different groups of people.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-03-03T22:12:55Z
FirstChildVoteTAG: 0
FirstChildTAG: hi!im not really good in statistics/math so please bare with me :)
my question is how come the interval **average** + or - **SD** is roughly 2.75 to 5.75
whereas the lecture said that
> You start at the average, and you walk an SD on either side.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/1362515907134366.jpg
an explanation would be greatly appreciated!thanks!
FirstChildUserIdTAG: 951663
FirstChildUserNameTAG: aprilumali12
FirstChildCreateTimeTAG: 2013-03-05T20:46:40Z
FirstChildVoteTAG: 0
FirstChildTAG: When she used the term "interval average" she was referring to the interval that was one SD away from average in both directions. (mean - SD, mean + SD)
Not sure if that helps.
FirstChildUserIdTAG: 969411
FirstChildUserNameTAG: McAlary
FirstChildCreateTimeTAG: 2013-03-05T22:28:57Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, thanks.
SecondChildUserIdTAG: 433872
SecondChildUserNameTAG: dfburke
SecondChildCreateTimeTAG: 2013-03-11T13:56:53Z
SecondChildVoteTAG: 0
IndexTAG: 1538
TitleTAG: problem 4 ! help !
can someone help me !or give a hint! about what is going on on these problem ?? please!!!
UserIdTAG: 920087
UserNameTAG: Areejo33
CreateTimeTAG: 2013-03-03T21:13:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: IF the median is 26, meaning that 50% of the values are to the left and the other 50% are to the right of 26 ... What does it mean to be above the median?
If the average is > median then what % of the data is to the right of the average? What happens to the amount of data available as you go farther to the right (increase)?
-Gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-03-03T21:20:07Z
FirstChildVoteTAG: 0
IndexTAG: 1539
TitleTAG: Why not absolute value?
It seems that Professor A. skipped over why squaring the deviations is preferred to taking the absolute value, or did I miss something? Using absolute value would be simpler and (I think) provide the same value for the SD as squaring. Can someone explain why absolute value is not used in the SD calculation?
Thanks,
dfburke
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-03-03T21:11:05Z
VoteTAG: 3
CoursewareTAG: Section 4: Measures of spread / Lec 4.2: Deviations from average; the standard deviation (SD)
NumberOfReplyTAG: 3
FirstChildTAG: You missed. Maybe you should re-watch the lecture.
$a^2$ is different from $|a|$, especially if you sum its difference from the mean.
FirstChildUserIdTAG: 334059
FirstChildUserNameTAG: RafaelNeumann
FirstChildCreateTimeTAG: 2013-03-03T21:38:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, Rafael, but on the slide 'a powerful little list' she uses absolute values to estimate the SD. She validates that using squares produces the same SD.
SecondChildUserIdTAG: 433872
SecondChildUserNameTAG: dfburke
SecondChildCreateTimeTAG: 2013-03-04T01:13:08Z
SecondChildVoteTAG: 0
FirstChildTAG: >It seems that Professor A. skipped over why squaring the deviations is preferred to taking the absolute value, or did I miss something?
She also said earlier in the lecture:
>Some of you will know that the absolute value doesn't have great
mathematical properties.
Then of the variance:
>The way this happens to be useful is even though physically it is hard to
interpret, it has nice mathematical properties.
The standard deviation, which is $\sqrt {variance}$, is in the same units as the data.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-04T01:35:15Z
FirstChildVoteTAG: 0
FirstChildTAG: I came across to [this][1] while searching the question on Google. In short we use squared differences, because it just easier to deal with squares instead of absolute values. But you can still use [absolute deviation][2] as a measure of spread.
[1]: http://stats.stackexchange.com/questions/118/why-square-the-difference-instead-of-taking-the-absolute-value-in-standard-devia
[2]: http://en.wikipedia.org/wiki/Absolute_deviation
FirstChildUserIdTAG: 502219
FirstChildUserNameTAG: nistro
FirstChildCreateTimeTAG: 2013-03-05T18:57:48Z
FirstChildVoteTAG: 1
IndexTAG: 1540
TitleTAG: question 7
Im not sure whether we needed a time scale that they were collecting over?
UserIdTAG: 1221836
UserNameTAG: ramanjeet111
CreateTimeTAG: 2013-03-03T20:37:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: No, you don't need to worry about any times ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T20:43:27Z
FirstChildVoteTAG: 0
IndexTAG: 1541
TitleTAG: R code for Exercise Set 1
I've just added a wiki page with tentative solutions in R code to the Problem Set 1 by following the suggestion of this post:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/51332e639788381f00000087
I was hesitating whether providing code would be beneficial for students. Read the warning message at the very beginning of the section 'Solutions to Exercises':
https://www.edx.org/wiki/Stat2.1x/R/
If the staff considers that this code is not useful for the learning process, please point it out to me and I'll delete the corresponding page.
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-03T20:29:08Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: > If the staff considers that this code is not useful for the learning process, please point it out to me and I'll delete the corresponding page.
I hope they don't! I am taking this course to try to understand the assumptions and defaults underlying "R" so am also playing around with code & will enjoy comparing notes. Thank you.
(prompted by the discovery that not only did Excel & R disagree about percentiles by default, but that decoding R's help page to work out why made my brain hurt)
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-03T20:40:24Z
FirstChildVoteTAG: 0
FirstChildTAG: Excellent!!!!
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-03T22:31:30Z
FirstChildVoteTAG: 0
IndexTAG: 1542
TitleTAG: 404 Not Found - trying to access Forum Guidelines from Wiki
Tech glitch?
UserIdTAG: 1235638
UserNameTAG: MyOwnCamera
CreateTimeTAG: 2013-03-03T20:09:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The link was wrong. Good catch.
Should be fixed now ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T20:13:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Yay! Thanks so much.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-03-03T20:19:26Z
SecondChildVoteTAG: 0
IndexTAG: 1543
TitleTAG: Auditing the Course
Plan to Audit the course.
UserIdTAG: 353792
UserNameTAG: wxdude225
CreateTimeTAG: 2013-03-03T19:57:55Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: What is the purpose of this post? I don't understand.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-04T16:53:26Z
FirstChildVoteTAG: 0
IndexTAG: 1544
TitleTAG: Certificate
I want to know that when we get our certificate, we will get our number about the total course .
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-03T19:04:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You mean, the grade? No.
It's a pass/fail course, so you either pass(>35%), or fail. Nothing else will be registered in the certificate.
If you mean something else, please specify ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T20:04:49Z
FirstChildVoteTAG: 0
FirstChildTAG: These sort of questions are answered on the edX Help page.
https://www.edx.org/help#certificates_and_credits_faq
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T20:47:42Z
FirstChildVoteTAG: 0
IndexTAG: 1545
TitleTAG: time for mid-term
what will be the time(how much) to solve mid-term exam?
at what time(GMT) will it start on 13th March?
UserIdTAG: 949459
UserNameTAG: roshan_920
CreateTimeTAG: 2013-03-03T19:00:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Prof comment
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/512fb17794db642300000010
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T22:14:32Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm really disappointed that the mid-term seems to be such a fixed timeslot on the one day. Unfortunately I will be out of the country and unable to get near a computer until March 15th.
IMO, it would have been much more user-friendly given how complicated our lives are, to have a period during which the mid-term could be submitted. I was planning on catching up with the subsequent week's work and to complete the mid-term on my return, but I guess I will just have to miss the exam. This is a great pity as I'm really enjoying the challenge of this course.
FirstChildUserIdTAG: 896043
FirstChildUserNameTAG: Mike503
FirstChildCreateTimeTAG: 2013-03-03T23:25:59Z
FirstChildVoteTAG: 1
SecondChildTAG: I'm in the same boat - I am in transit for pretty much all of 13 March (the joy of international travel). Thankfully with a pass mark of 35%, it's not really all that much of an issue if you miss a midterm, or all of the exams, provided you keep up with the problem sets.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-03-04T07:49:00Z
SecondChildVoteTAG: 0
IndexTAG: 1546
TitleTAG: Prof. A - IQR and "Skewness" of data
Could we safely assume that looking at the IQR "whiskers" "0% --> 25%" and "75% --> 100%" can tell us if it has a right tail/left tail? If I put the IQR on its side "where Y becomes X" then I can see the tails ("whiskers").
Also the range of the IQR seems to tell me how Steep the graph is going to be.
How incorrect am I?
-Gabriel
UserIdTAG: 203329
UserNameTAG: gabieee
CreateTimeTAG: 2013-03-03T17:55:49Z
VoteTAG: 3
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 3
FirstChildTAG: I'm guessing that you are quite correct.
Of course, I'm not the professor, but I can only agree with your assessment ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T18:03:42Z
FirstChildVoteTAG: 1
FirstChildTAG: The longer the whisker 9compared to the other)- the longer the tail.Also the position of the Median within the box will add to the information too.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T18:08:51Z
FirstChildVoteTAG: 5
FirstChildTAG: each part of the box plot represents 25% of the data. the size of each section could give you an idea of the proportions in that section. for example a long upper whisker means that 25% of your data distributes in a long range (from the upper quartile to the max value) and therefore the proportions of the data in it will be low and you could possibly have a right skewed distribution. the same for the lower whisker, except it will be a left skewed.
FirstChildUserIdTAG: 1262310
FirstChildUserNameTAG: biofelup
FirstChildCreateTimeTAG: 2013-03-06T07:08:52Z
FirstChildVoteTAG: 0
IndexTAG: 1547
TitleTAG: Passing mark
What is the statistical significance of 35% as a passing mark? Does it represent the 25% quartile? Will it be the mean or median? Is it a mode although I doubt it will be the only one? Usually 50% is considered a pass although years ago I wrote some British exams where the passing mark was 40 and 60% had you in the 75% percentile...meaning the exams were damn hard. Is that the case here? lol
UserIdTAG: 419542
UserNameTAG: ccwinkler
CreateTimeTAG: 2013-03-03T17:51:44Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Could be o_O
There's nothing particularly difficult for now, I think, but we're less than halfway through, so who knows?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T18:01:40Z
FirstChildVoteTAG: 0
FirstChildTAG: It's impossible to know what 35% will represent in statistical terms (quartiles, mean, etc.) of our grading data set because the data set is not yet complete, we haven't completed the course :) So I think we can safely assume it has nothing to do with that.
My guess is it's more of an arbitrary cutoff picked by the professor or the course organizer, and a low cutoff (35%) was chosen because of the "Intro" nature of this course. All of the MOOCs I have taken so far have had different passing cutoffs (50% in CS169x, 70% in MITx6.00, 80% in Gamification which was offered out of UPenn) that did not necessarily align with their difficulty levels. So I think it's largely a personal decision on the part of the professor or course staff.
Personally, I think 35% is really low and cheapens the value of the certificate a bit, but at least it allows for more people to feel that they can attain it. And since this is an Intro course I guess that is the most important thing.
FirstChildUserIdTAG: 222873
FirstChildUserNameTAG: theusual
FirstChildCreateTimeTAG: 2013-03-03T19:39:54Z
FirstChildVoteTAG: 0
SecondChildTAG: Maybe Stat 2.2x will have this course as a prerequisite.
It would make a lot of sense and justify the low pass threshold, if this were part of a proper "series" of related courses.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T19:48:50Z
SecondChildVoteTAG: 0
FirstChildTAG: > Maybe Stat 2.2x will have this course as a prerequisite.
No, pretty sure I read earlier a post from the Prof where she said it wasn't going to be a prerequisite. That's not something they can really enforce, and it goes against the whole mooc philosophy.
I know the Copyright course had a selection process with a 500 intake limit. But that was unique. In general, if you want to do a course you can. If you don't meet the assumed knowledge requirements then it is up to you to catch up.
So I would assume that this course will be "assumed knowledge". But that won't prevent people with zero prior knowledge from joining, and asking the forum to help them catch up.
Edit
Found Prof comment. So passing this course isn't a prereq, but the knowledge is. Hidden deep in page:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13623493751343636.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:30:11Z
FirstChildVoteTAG: 0
SecondChildTAG: Yeah, I figured as much. I suppose it was a sort of wishful thinking on my part. It really would make a lot of sense IMO.
Hopefully those future "zero-knowledge" people won't be too upset if all they 2.1x-related questions are answered with a link to this course's page xD
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T21:45:24Z
SecondChildVoteTAG: 0
FirstChildTAG: > Personally, I think 35% is really low and cheapens the value of the certificate a bit,
The Prof explained this too. Must try and find the post. She said (from memory) that it was more for those new to stats and edX, so they wouldn't feel totally discouraged. The next two courses will probably have a more realistic passing grade.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:31:54Z
FirstChildVoteTAG: 0
SecondChildTAG: but it's not a passing grade is it? It's a "certificate of completion" - and 35% is fine to demonstrate that you stuck with it, did your best etc etc. For a "passing grade" - signifying something about competence?? - we'd need more than the honour system for course work - yet to see what the forum is like in exam season!
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-03T22:01:45Z
SecondChildVoteTAG: 0
SecondChildTAG: > yet to see what the forum is like in exam season!
The forum will probably be closed to posting during the exam period. Still open to view, but not to post.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-03T22:09:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Nothing wrong with a 35% pass mark, if and only if, there is also recognition for better marks. How about awarding merit for 60% and distinction for 80%?
FirstChildUserIdTAG: 901827
FirstChildUserNameTAG: clv101
FirstChildCreateTimeTAG: 2013-03-12T16:04:42Z
FirstChildVoteTAG: 0
IndexTAG: 1548
TitleTAG: I'm learning a lot!
THANK YOU!
UserIdTAG: 122004
UserNameTAG: fqantonio
CreateTimeTAG: 2013-03-03T17:31:30Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 0
IndexTAG: 1549
TitleTAG: Median
Median should be in the middle of data. 26 is not in the middle between 15 and 45. Could you explain me why it is 26?
UserIdTAG: 734057
UserNameTAG: cieursz
CreateTimeTAG: 2013-03-03T17:18:52Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 2
FirstChildTAG: Did you watch the lectures in section 3a?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-03T17:51:49Z
FirstChildVoteTAG: 1
SecondChildTAG: Dear Cieursz,
Median is not in the middle of data. But it means the point at which half the values less than the median (Point). And half the values more than the median.
SecondChildUserIdTAG: 938252
SecondChildUserNameTAG: shashankJain1310
SecondChildCreateTimeTAG: 2013-03-03T21:09:55Z
SecondChildVoteTAG: 0
FirstChildTAG: I suggest you review Lecture 3.1, but, as a summary: The median is the 50th percentile, or the value for which 50% of the data is smaller or equal than it, and 50% of the data is larger or equal.
"In the middle" is not correct, in general, as it depends by how the data is distributed. If the distribution is perfectly symmetrical, then yes, the median would be the value "in the middle"(and it would also equal the average), but in this case, the distribution is clearly *not* simmetrical.
With the distribution of data that we have in that lecture, that value is 26. You can sort of estimate it from the histogram, as the prof does, but to really verify it better you'd need the data table, or at least the range percentiles, and we don't have those. You'll have to trust the slides in this case :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T17:56:20Z
FirstChildVoteTAG: 1
IndexTAG: 1550
TitleTAG: PROBLEM: 5
NOT UNDERSTANDING THIS QUESTION?
UserIdTAG: 1307911
UserNameTAG: madhu123
CreateTimeTAG: 2013-03-03T17:10:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: How about reading the Discussion Forum Guidelines?
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-03T17:47:40Z
FirstChildVoteTAG: 0
FirstChildTAG: The lectures have an example that is almost the same as that problem. Reviewing them might be helpful.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T17:58:13Z
FirstChildVoteTAG: 0
FirstChildTAG: If you have a specific problem, then you should say what it is. You should include this in your title so others searching the forum can find it.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:24:24Z
FirstChildVoteTAG: 0
IndexTAG: 1551
TitleTAG: Progress issue
Hello , Iam taking Stat2.1xIntroducion to statistics course and i was shocked when i checked the progress! there are exercise named " practice for exercise" which means preparing for the actual exercise but actually they were included in the final evaluation which is not mentioned from the first place . Now my scores are good but because of this they became so low!
UserIdTAG: 475264
UserNameTAG: chrisi
CreateTimeTAG: 2013-03-03T16:12:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Practice exercises **do not count** to the scores.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T16:19:00Z
FirstChildVoteTAG: 0
FirstChildTAG: > but actually they were included in the final evaluation which is not mentioned from the first place
They are not, and never have been, counted towards your final mark. Practice exercises are just that. Practice. You will note on the question that they marks awarded are: 0.0 points.
They are given marks on the Progress page, but they are not marks that count towards anything. It is just to show you that you have completed them.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:23:23Z
FirstChildVoteTAG: 0
IndexTAG: 1552
TitleTAG: practice exercises
Hi guys,
I just want to confirm that the practice exercises that preceede each exercise set do not affect our course progress. I sometimes don't bother doing them but I just realised from having a look in my "Progress" tab that they are also monitored -not on the actual table but in the detailed list below. Can someone who is sure about that please confirm that it's not obligatory to have the practice exercises done before each week's deadline.
Thank you very much,
Antonis
UserIdTAG: 1207733
UserNameTAG: AntoniusBlock
CreateTimeTAG: 2013-03-03T15:51:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: They do not count but why would one not do a practice exercise.Very often there is some point introduced in it which can help with the actual graded exercise.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T16:19:56Z
FirstChildVoteTAG: 1
FirstChildTAG: thank you for your repsonse. just for the record, the fact that another person posted the same question exactly after me was totally random. and she is probably also Greek like me. we, Greeks.. :P
FirstChildUserIdTAG: 1207733
FirstChildUserNameTAG: AntoniusBlock
FirstChildCreateTimeTAG: 2013-03-03T16:33:49Z
FirstChildVoteTAG: 0
SecondChildTAG: We're in a statistics course, so you'd better start defining that "random"!
...just kidding, of course ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T16:41:42Z
SecondChildVoteTAG: 0
IndexTAG: 1553
TitleTAG: Week 2 / Exercise Set 5 / problem 6
Hello! Could anybody help me find the correct answer in Problem 6 Exercise Set 5? Probably, I should have applied Markov's inequality but I cannot figure out what exactly have to compute so as to find the solution..Please, provide me with some tips.. I have already taken the test and my answer at that problem is wrong but I wouldn't like to have any misunderstandings about the theory before proceeding to the next lecture.
Thanks in advance.
Andronikos
UserIdTAG: 961824
UserNameTAG: Andronikos
CreateTimeTAG: 2013-03-03T15:04:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Adronikos, to get visibility, please, post your question in the right place (Exercise Set 5 Problem 6) and delete this post (there is a button to do that). You have posted it inadvertently in the wrong place (ex 1 set 1).
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-03T15:19:03Z
FirstChildVoteTAG: 0
FirstChildTAG: The only tip that I can give you under honor code is...read the Problem text. Carefully. Now read it again.
What is it asking for?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T15:28:42Z
FirstChildVoteTAG: 0
FirstChildTAG: How to post in the correct forum (scroll down)
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/51320ee24bebda2b000000c4
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:19:52Z
FirstChildVoteTAG: 0
IndexTAG: 1554
TitleTAG: Latecomer to the course
I have registered for the course just today at 3:00pm GMT on 3 March 2013. Will I be able to continue with the course? If yes, can I complete the tests of earlier dates i.e. from the first week at a later date , for example with the courses in the 3rd week. I understand the course is already towards the end of 2nd week. Please advise.
UserIdTAG: 1346462
UserNameTAG: drmonwar
CreateTimeTAG: 2013-03-03T15:04:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You will not get points for the previous week but do well from this week.Lowest two scores will be dropped and pass is 35% so if you do well from now there is a good chance of completing the course and getting the pass grade.(Scores will be not given in the certificate)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T15:21:06Z
FirstChildVoteTAG: 0
FirstChildTAG: Tough Prof. A, and seemingly quite rude as well, just by reading one of her (his) welcoming note to the coursants and I felt that the person is pointing out useless clarifications on GMT in a way that presume the students are not reliable.
In case she (he) did not found out yet, some people do not know what GMT is and they are making "sincere" mistakes, no need to be rude as a Proffesor here. The public image and large number of (adult) learners should teach you something, too. And, yes, I felt that you need it from someone to tell you that, in the happy case right one read this.
FirstChildUserIdTAG: 1004163
FirstChildUserNameTAG: lumierre
FirstChildCreateTimeTAG: 2013-03-03T18:16:43Z
FirstChildVoteTAG: 0
SecondChildTAG: lumierre,If you even had a remote idea what people told then you would not be making these comments.I think that by calling your Professor as rude, you are yourself being rude and personally feel that you should withdraw this comment.GMT is a standard terminology , people were asked to abide by it and they did not despite it being mentioned in the courseware clearly.Unreasonable requests were being made too. Clearly you are going overboard and I don't think you gain much by antagonizing with your teachers.A person can ask what is GMT and people would tell him/her but to neither ask and to justify that there are many GMT values is a joke and that is what people did.Be innocent, be ignorant but to be so and claim superiority is naivety or arrogance and one can choose !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-03T18:50:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, if someone actually tried to argue the idiocy of multiple GMTs, then they are **not** reliable.
At all.
As Prasannasimha said: it's one thing to not know what GMT is(perfectly understandable, not everyone had a reason to deal with time zones in his/her life), another to argue an idiocy that's obvious if you do 5 seconds of research on any search engine.
So those people are either trolls spreading misinformation...or really, really stupid persons. Either way, not reliable.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T20:01:53Z
SecondChildVoteTAG: 0
FirstChildTAG: lumierre said:
> Tough Prof. A, and seemingly quite rude as well, just by reading one of her (his) welcoming note to the coursants and I felt that the person is pointing out useless clarifications on GMT in a way that presume the students are not reliable. In case she (he) did not found out yet, some people do not know what GMT is and they are making "sincere" mistakes, no need to be rude as a Proffesor here. The public image and large number of (adult) learners should teach you something, too. And, yes, I felt that you need it from someone to tell you that, in the happy case right one read this.
Thanks for that **lumierre**. It needs to be preserved. The only rude one here would be you. This course has over 47000 people enrolled, and if they can't follow basic instructions then they won't/shouldn't be pandered too.
People are using the internet. If they haven't discovered search engines, then they need to.
Another thing that some here need to learn is to think and ask questions before jumping onto the forum and posting in anger. If you don't understand, ask.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:17:35Z
FirstChildVoteTAG: 0
IndexTAG: 1555
TitleTAG: Stat 2.2x &2.3x
Will the second and third components of the course be offered through edX? If so, do you know when?
UserIdTAG: 1278827
UserNameTAG: kb1334
CreateTimeTAG: 2013-03-03T15:00:51Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Prof Adhikari alluded to this in one of her posts and will potentially be there after a few weeks of completion of this course.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T15:19:53Z
FirstChildVoteTAG: 0
FirstChildTAG: Prof comment
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/512a89f9a4474f1f0000005e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:10:31Z
FirstChildVoteTAG: 0
IndexTAG: 1556
TitleTAG: Distinquished Teaching Awards
http://teaching.berkeley.edu/dta-recipient/ani-adhikari
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-03-03T14:35:25Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Certainly worthy then in 2006 and even more so now in 2013. Prof. A' enthusiasm shows all the time as well as her wit and humor. I will take all the 2.x series in hopes that she is our professor/lecturer.
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-03-03T14:52:44Z
FirstChildVoteTAG: 0
FirstChildTAG: Prof. A is awesome!!
FirstChildUserIdTAG: 664881
FirstChildUserNameTAG: OKSue
FirstChildCreateTimeTAG: 2013-03-03T22:53:41Z
FirstChildVoteTAG: 0
FirstChildTAG: > Prof. A is awesome!!
Yes, she is. Im taking this course as a refresher on basics - Ive done undergrad stats at York University (Toronto) many years ago..Profs. were awful. Ive taken graduate stats for finance courses for my MBA (Kellogg - Northwestern U.) and the profs were great, but not as great as Prof. A!!
Looking forward to the other two courses, and hoping Prof. A. teaches them as well!
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-03T23:27:11Z
FirstChildVoteTAG: 0
IndexTAG: 1557
TitleTAG: DataGenetics blog - some interesting reading
Some interesting articles using statistics and probability to read with your coffee (or tea!) this morning. There are a few word games sprinkled in, too.
http://www.datagenetics.com/blog.html
Here is one that analyzes Chutes and Ladders (a game for young children).
http://www.datagenetics.com/blog/november12011/index.html
UserIdTAG: 1302407
UserNameTAG: HelenES
CreateTimeTAG: 2013-03-03T14:28:58Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Amazing, thanks
FirstChildUserIdTAG: 1002821
FirstChildUserNameTAG: Urimare
FirstChildCreateTimeTAG: 2013-03-03T20:12:59Z
FirstChildVoteTAG: 0
IndexTAG: 1558
TitleTAG: Freedman Pisani and Purves Textbook in India
Prof Adhikari had recommended a book called "Statistics " by Freedman, Purves and Pisani and it is supposed to be expensive.I had posted this in the original discussion but thought I could post it again as a "searchable" one with the heading.
It is available in the Indian subcontinent (Not sure if it means only India or the SAARC countries and specifically mentions on the cover page -"This edition is for sale in the Indian subcontinent only. Not for export elsewhere) ) as a low price Indian paperback edition For INR 495 at
https://sapnaonline.com/statistics-119082
Note - I have no financial incentive and I noted it was available at the physical store when I went to see it (and found the official cheaper paperback edition !!) and thought that those who can order it could and also, probably cheaper local editions in developing countries may be available compared to the original hardback with glossy pages)
Hope this information helps someone.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-03T13:41:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I think this is the book being referred to.The link is for the lowcost Indian edition only.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/513352f1dd04c01f0000008d
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-08T13:43:16Z
FirstChildVoteTAG: 0
IndexTAG: 1559
TitleTAG: A positive outlook
What is the justification for ignoring the negative answer of the square root in standard deviation? Ex. If SD=root 4 why is the answer 2 instead of plus 2 and minus 2?
UserIdTAG: 283474
UserNameTAG: Methuselah
CreateTimeTAG: 2013-03-03T13:17:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I don't think you ignore it. On a number line, the positive 2 would represent one standard deviation to the right, and -2 would represent one standard deviation to the left.
I think it is written as a positive number just as a shorthand. Writing +/-2 all the time could get time consuming, and be confusing in longer calculations.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-03-03T13:26:38Z
FirstChildVoteTAG: 0
FirstChildTAG: Because the SD represents a rough value for how "far" the values in a dataset tend to be from its average.
If you have this list [1,2,3], its average value is 2. The list of its values' deviation from this average is [-1,0,1], so by intuition, you can tell that the values tend to be at a "distance" of 1 unit from the average. Whether that is a positive or negative 1 doesn't really concern you.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T13:34:08Z
FirstChildVoteTAG: 1
IndexTAG: 1560
TitleTAG: I need down Subtitle of vedio, please
my level of english is low
UserIdTAG: 1061541
UserNameTAG: print
CreateTimeTAG: 2013-03-03T13:11:47Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 3
FirstChildTAG: Press the button on the bottom right of the video player, the one with "CC" written on it. It'll open the text transcript on the right :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T13:44:40Z
FirstChildVoteTAG: 0
FirstChildTAG: I need to get rid of subtitle, my level of english if good...
FirstChildUserIdTAG: 1004163
FirstChildUserNameTAG: lumierre
FirstChildCreateTimeTAG: 2013-03-03T18:46:45Z
FirstChildVoteTAG: 1
FirstChildTAG: And, **as it says on the Course Info page**, the subtitles for Lecture 4.x are delayed. They will upload them when they can.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:09:11Z
FirstChildVoteTAG: 0
IndexTAG: 1561
TitleTAG: rounding off values of answers
Please specify the number of decimal places to be used in the computations. I got a wrong answer only because i have written two decimal places instead of one.
Thanks
UserIdTAG: 803419
UserNameTAG: coneneng1978
CreateTimeTAG: 2013-03-03T13:07:16Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: In week 1 there was some confusion with this. I think most questions worked with just one decimal place except for one question that I can't remember. The instructions are now at the top of each exercise set for Week 2 so you won't have the same problem again.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-03T13:12:02Z
FirstChildVoteTAG: 0
IndexTAG: 1562
TitleTAG: Error in Textbook - Exercise 4.8
From what we are taught, SD = RMS (Lecture 4.2, Slide 5/7)
**The dataset given for Text book Exercise 4.8 is**
> `-10 3 5 -10 -7`
This evaluates to mean = -3.8 and **RMS=SD = 6.493**.
The solution provided gives ***RMS = 7.513 to 7.533*** and SD = ***6.483 to 6.503***.
This is error, isnt it Professor Adhikari?
UserIdTAG: 300213
UserNameTAG: Artimehta
CreateTimeTAG: 2013-03-03T12:39:35Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: SD isn't the same thing as RMS.
RMS takes the mean(average) of the squares of a certain dataset, then the root of the previous result.
SD is the RMS of a dataset's deviations from its average ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T13:24:14Z
FirstChildVoteTAG: 1
SecondChildTAG: Many thanks Klionheart. Could you please help me further with the calculation of RMS for above dataset as I am having challenge understanding it? Thanks in advance for your help.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-03T13:30:54Z
SecondChildVoteTAG: 0
SecondChildTAG: is it sqrt(((-10)sqrd + (-10)sqrd +(-7)sqrd+ (3)sqrd+ (5)sqrd )/5)? If so, I do get the value of 7.443 which tallies with the textbook answer.
Await your confirmation and thanks again. It was very helpful.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-03T13:36:23Z
SecondChildVoteTAG: 0
SecondChildTAG: It would help to know what's the part that you don't understand ;)
But anyway, from the textbook:
> The rms (root mean square) of a list measures the average size of its entries.
So by doing the rms, you don't really care about the actual values in your datasets, but only about the "size" of the numbers who represent them.
As an analogy, think of vectors. There are times when you might not care about the direction of a vector, but only about its "strength", or magnitude. This is similar.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T13:42:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh, you meant about the actual calculation, sorry!
Yes, your formula is correct, even though your result is a bit off...maybe because of too much approximation?
Let's split it up for clarity:
1. Square all the values in your list. Write down these values in another list. [100,9,25,100,49]
2. Take the average of this new list: 56.6
3. Take the root of the value you found: **7.52**
There we go :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T13:52:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you, Klionheart!!!! You helped me with my query! My challenges are 'English' and 'Math' in that order, but once simplified by experts like you, I take no time to understand it!!!
I have been reading your various posts...keep up the good work of simplifying complex things some of us face!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-03T14:00:36Z
SecondChildVoteTAG: 0
SecondChildTAG: You are welcome!
I am by no means an expert, but I'm glad that I helped you understand :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T15:32:17Z
SecondChildVoteTAG: 0
IndexTAG: 1563
TitleTAG: Practice for Exercise Set 4
I did the exercise several times but the progress is not recorded in my progress. Did this happen to anyone?
Also, for Exercise 4-2."Homes in a certain area have a mean price of $400,000, but a median price of "only" $250,000. How might you explain this best?" I picked "b" several times but the "correct" mark did not appear. Could it be due to this?
Many thanks.
UserIdTAG: 897162
UserNameTAG: kymwkl
CreateTimeTAG: 2013-03-03T12:37:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You posted in the discussion forum on Exercise Set 1 but your title says that your question is about Exercise Set 4. Looking at Exercise 4-2, I cannot see a connection with your question.
Progress for exercises is only recorded if you submit the correct answer within the max. number of submission. Progress for practice exercises is not recorded.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-03T13:01:44Z
FirstChildVoteTAG: 0
FirstChildTAG: I assume you mean exercise 4-2 of the online textbook? I've noticed that too, the answer doesn't seem to register. But, it doesn't have any influence on edx, don't worry :)
As KMV said, progress for practice exercises is not recorded.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T13:20:08Z
FirstChildVoteTAG: 0
IndexTAG: 1564
TitleTAG: problem 1 (set 3)
Hello, thsnk you for your fine job.
I have a problem with the answers:
my answer is 18.6, and your correct answer is 18.59
my answer is 37, and your correct answer is 36.97
my answer is 55.4, and your correct answer is 55.3
two questions:
We round always to the decimal in every calculation?
We round it always to the decimal? But you have only onw correct answer to the decimal!
Thanks. António
UserIdTAG: 122004
UserNameTAG: fqantonio
CreateTimeTAG: 2013-03-03T12:36:35Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Read the Course Info. The second entry for *February 27, 2013* should answer your questions ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T13:15:53Z
FirstChildVoteTAG: 0
IndexTAG: 1565
TitleTAG: Beware of executing statistical apps blindly!
Statistical tools are obviously useful and can help us to make tedious calculations. But we should not rely on them blindly.
An example of a lurking danger around who doesn't know exactly what her tools are doing: the `sd()` R function to calculate the standard deviation. In R this function is implemented with the sample standard deviation in mind (with that $\frac{1}{n - 1}$ factor explained in the lecture).
So be careful and read the documentation of your programs before using the functions they provide.
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-03T11:43:16Z
VoteTAG: 3
CoursewareTAG: Section 4: Measures of spread / Lec 4.2: Deviations from average; the standard deviation (SD)
NumberOfReplyTAG: 2
FirstChildTAG: Good to know it.
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-03-03T12:10:51Z
FirstChildVoteTAG: 0
FirstChildTAG: As a matter of fact I'm hardly using programs so far. Most of the exercises are doable without calculations or with very short calculations, even when the problem appears to be a number crunching one: for example the list of 7's, it can be done in head only by reasoning.
IMO the best approach to problems (it's my approach so far) is trying to reason about them without doing calculations. Hand calculations or programs may be later used to test our reasoning.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-03T12:19:04Z
FirstChildVoteTAG: 2
IndexTAG: 1566
TitleTAG: "R" solutions after deadline
Perhaps, those students that know it statistical language , can post "R" solutions for exercises.
It could be a useful extra learning for this course.
(http://www.r-project.org/)
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-03-03T11:05:07Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: What do you mean with 'R' solutions? I don't understand. If we need to get the sd of a list, for example, the solution is the same whatever the way to do the calculation.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-03T11:46:24Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, you are right.
The idea is not to get a better calculation.
The idea is learn to use "R".
May be, on the beginning of the course it seems simple, but when
the course become complex the use of "R" could become most
interesting.
I think, particularly when we started Probability and Inferential Statistic.
You can look the R solutions posted by Andrey_K to have an idea about.
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-03T12:04:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Where are the Andrey_K answers?
What you say about probability and statistical inference makes more sense, but afaik it's material of Stat2.2x and Stat2.3x respectively.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-03T12:15:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Look for:
Solution of practice 2.1 b in RStudio
Bargraph in RStudio
Materials of the lecture in RStudio
Stem-and-Leaf Plot in RStudio
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-03T12:23:40Z
SecondChildVoteTAG: 0
SecondChildTAG: jorge, I'm not able to find andrew_k's materials within the RStudio site.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-03T12:41:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Andrey is an student of this course, look into the discussions.
Use what I posted to look for.
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-03T12:48:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Look the comment of Prof Ani in Bargraph in RStudio.
Interesting, right? I'd like that Prof Ani promotes the use of R inside this cours.
Look also the answer of Andrey.
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-03T13:02:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Found it! I could also post R solutions. In fact I've posted a little program some days ago, but in Python.
It's hardly surprising that Ani uses R. R is the mainstream programming language among statisticians. I'm beginning to use R as well. For what I've seen so far it's an ideal language for statistics. See my comment here about R (it's buried in a sub thread as a response to a @jimbangun's comment):
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_Exercise_Set_3/threads/5128ff6d829739220000002c
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-03T13:32:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Excellent! Python is excellent also to use.
Coursera has a few courses about statistics and data analysis using R. I recently got an introductory course about R there.
Also there is a new about Bioinformatics using Python.
I wanted to have a course like this about statistics to depth on that.
But what if the course include (in the future) some about R use?
I mean, keeping the main focus on learning statistics
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-03T13:51:48Z
SecondChildVoteTAG: 0
SecondChildTAG: What I'm trying to mean in the first line of my previous comment:
R (or Python, or whatever) solutions are fine and your comment encourages me to think again about this, but I have one concern (maybe I'm wrong): this course is for reasoning about concepts and posting computer procedures might refrain us from thinking.
As I've said before I'm trying to refrain myself from using programs and I'm currently use them only to test my reasoning. I spite of this I can post tentative solutions, if I have time, to some problems.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-03T14:02:59Z
SecondChildVoteTAG: 0
SecondChildTAG: As you point out in a previous comment using R would be very appropriate when we enter in complex matters. In fact all modern statistical analysis is done with the aid of programs. Hence, it would be reasonable to learn the fundamentals of the R language here, at least as a personal homework. That's precisely what both of us are currently doing ;-)
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-03T14:12:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Yep, I think we have (more or less) the same point of view (including the concern about to use or not computer helping)
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-03T15:16:08Z
SecondChildVoteTAG: 0
IndexTAG: 1567
TitleTAG: small issue with problem 3
I believe there is a small issue with problem #3. (I got the answer the question was looking for, but that's all I'll say before the assignment is done in the forum.)
Jake
UserIdTAG: 1284156
UserNameTAG: Dispader
CreateTimeTAG: 2013-03-03T10:07:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 3
FirstChildTAG: I...don't think so? It looks ok to me.
But we'll really have to wait until we can discuss it openly.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T10:28:52Z
FirstChildVoteTAG: 2
SecondChildTAG: yes; i think the same, maybe there is a probleme in #3.
SecondChildUserIdTAG: 959988
SecondChildUserNameTAG: boulid
SecondChildCreateTimeTAG: 2013-03-03T16:21:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree that there is an issue with problem 3.
SecondChildUserIdTAG: 730654
SecondChildUserNameTAG: N0ra
SecondChildCreateTimeTAG: 2013-03-04T22:17:15Z
SecondChildVoteTAG: 0
FirstChildTAG: I don´t think so, in my opinion the problem matchs with the teory given.
FirstChildUserIdTAG: 1002821
FirstChildUserNameTAG: Urimare
FirstChildCreateTimeTAG: 2013-03-03T19:48:22Z
FirstChildVoteTAG: 0
FirstChildTAG: No problem with this question. Look at the formulas for mean and sd. Reason out what the mean of B will be.
Or make up some data and see what happens.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T21:04:39Z
FirstChildVoteTAG: 1
IndexTAG: 1568
TitleTAG: No student can have a negative amount of money in his or her pocket
JUST PURE HUMOR
It's called Credit Cards ... ;-)
> Example 4-4: Applying Markov's inequality.
>There are 200 students in a class. The average amount of money in their pockets is $15.
>How many could have 75 or more in their pockets?
>***Solution. No student can have a negative amount of money in his or her pocket,*** so Markov's inequality applies. Markov's inequality guarantees that
>[fraction of students with at least $75 in their pockets] ≤ $15/$75 = 0.2 = 20%.
>Thus at most 20% of the students (40 students) could have $75 or more in their pockets.
-Gabriel
UserIdTAG: 203329
UserNameTAG: gabieee
CreateTimeTAG: 2013-03-03T09:26:13Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: Good point :D
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T10:27:44Z
FirstChildVoteTAG: 0
FirstChildTAG: What about if the percentage obtained when applied to the number of students gives us a fraction?
Suppose you have 133 students. What would be the answer?
0.2*133=26.6 Would it be 26 students?
FirstChildUserIdTAG: 918956
FirstChildUserNameTAG: a-per
FirstChildCreateTimeTAG: 2013-03-03T12:25:09Z
FirstChildVoteTAG: 0
SecondChildTAG: It's still "at most 20% of the students", so, "At most 26.6 students".
Of course, you cannot cut a student into pieces and then take a sixth of it, and 27 students would already be over the bound, so 26 is the maximum number of students you can get in practice. But only because we're dealing with discrete variables.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T13:12:16Z
SecondChildVoteTAG: 0
IndexTAG: 1569
TitleTAG: Exercise Set 5- P1 and 2
I have tried everything but in vain.
What i did:
The percentage of each corresponding value was multiplied with the value in terms of % (20% as 0.2) and then added together. The sum was then divided by 5 for 5 entries.
This shows incorrect.
Any help would be appreciated.
plz help
regards
UserIdTAG: 722572
UserNameTAG: rheajose
CreateTimeTAG: 2013-03-03T08:50:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The only thing I can suggest without breaking honor code, is:
Check your results at each stage. Think of what you are trying to find and how the numbers you have relate to it.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T10:31:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Two questions that might help:
1) If there are 5 entries, why are you talking about percentages and not about entries?
2) Why did you post your question in the discussion forum on Exercise Set 1?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-03T12:13:57Z
FirstChildVoteTAG: 0
IndexTAG: 1570
TitleTAG: What is "over the age of 65"
Your answer to problem 2b seems to assume that "over the age of 65" means the same as 'at least 65' because you included 65-year-olds in the answer. Isn't another reasonable assumption 'at least 66' which would give a different answer? It seems either is reasonable so the question could be more precise.
UserIdTAG: 989729
UserNameTAG: randyps
CreateTimeTAG: 2013-03-03T08:44:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Over the age of 65 is using the last Birthday convention which is common all over the world.ie your age is your last Birthday so the moment you are 65 years on your Birthday you are over 65 9or 65 and over)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T08:59:19Z
FirstChildVoteTAG: 0
IndexTAG: 1571
TitleTAG: Exercise 4.12
This is the lightbulb exercise in the text referenced above. I can't put the numbers because they change every time. Doesn't Chebychev's inequality refer to both tails? But the question asks how many lightbulbs can last more than x hours? So it seems the answer should be half of the fraction given by Chebychev's inequality (i.e. if the question asks about how many lightbulbs will last more than 3 SD from the mean, shouldn't the answer be 5.5% rather than 11.1%)? But that answer isn't what's programmed.
UserIdTAG: 989729
UserNameTAG: randyps
CreateTimeTAG: 2013-03-03T08:17:38Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: There is a subtle thing that has to be noted . If something is greater than a thing , it is also greater than 1/2 a thing. Now , if we have a symmetric distribution ie it looks the same on both sides of the mean and median then it may be justifiable to divide by half but we do not know that for sure so it is better not to assume the symmetry of the distribution.So one tail may be small and the other tail may be big but one tihng we know for sure is that the total value of both the tails cannot me more than a certain amount $1/k^2$.Telling that it is $1/2$ is the "truth' for only a symmetric distribution but is "Untrue" for all the rest ie "False" , so when applying Chebychev's inequality we can only say that the bound is as per Chebychev ie less than or equal to $1/k^2$for the two tails and so also for one tail (as we have no knowledge of symmetry)
Try to see my Ravana Lakshman Rekha example from Mythology.
See the story that I described to get an idea of bounds Hope it helps.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5131a8c04bebda2b0000006e
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T08:49:10Z
FirstChildVoteTAG: 0
SecondChildTAG: It's addressed in one of the lectures ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T10:32:12Z
SecondChildVoteTAG: 0
SecondChildTAG: can u show the workings of the light bulb problem ( ex 4-12). Any data is fine.
SecondChildUserIdTAG: 1111701
SecondChildUserNameTAG: VJ42
SecondChildCreateTimeTAG: 2013-03-04T14:06:48Z
SecondChildVoteTAG: 0
SecondChildTAG: I will do the exercise as it appears to me on my latest refresh.
> A certain type of light bulb has an average lifetime of 10,000 hours. The SD of bulb lifetimes is 480 hours. What decimal fraction of bulbs could last more than 11,200 hours?
Ok, so the dataset represents a time in hours. The average is 10000, the SD is 480, and I want to know what percentage of the bulbs is beyond the value of 11200. I have the SD, and a lifetime can't be negative, so I know that I can use both Markov and Chebychev. Let's do that.
**Markov's inequality**
The rule states that:
> If the average of a list of numbers is M, and the list contains no negative numbers, then the fraction of numbers in the list that are greater than or equal to x ≤ M/x.
or, as we saw it in Prof A.'s lectures:
> If a list has only non-negative entries, then the proportion of entries that are at least as large as k times the average is at most 1/k.
They mean the same thing. I'll be using Prof A.'s method, but you can do it either way. We know that there are no negative values, so we can do it. 11200 is $\frac{11200}{10000}=1.12$ times as large as the average. So the proportion of entries that are at least as large as 1.12 times the average is at most $\frac{1}{1.12}=89\%$, or 0.89. Ugh, that's an horrible bound! Hopefully Chebychev's rule will give more useful information...
**Chebychev's inequality**
The rule states that:
> If the mean of a list of numbers is M and the standard deviation of the list is SD, then for every positive number k, the fraction of numbers in the list that are k×SD or further from M ≤ 1/k^2.
or, as we saw it in Prof A.'s lectures:
> In any list, the proportion of entries that are k or more SDs away from the average is at most 1/k^2.
Again, the two mean the same thing. Now, I can easily calculate that 11200 is 11200-10000=1200 hours away from the average. What is 1200 is terms of SD? Well, the SD is 480, so 1200 is $\frac{1200}{480}=2.5*SD$ away from the average. This means that the proportion of entries that are 2.5 or more SDs away from the average is at most $\frac{1}{2.5^2}=16\%$, or 0.16. This is much better!
Chebychev's result is much more accurate, so I'm going to imput 0.16 into the answer's box and...yes, a green tick! Awesome!
This is it. The same reasoning can be used for any combination of numbers. Hope that the example was useful ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T23:38:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Very useful example, Klionheart!
SecondChildUserIdTAG: 1015153
SecondChildUserNameTAG: ruthiegyll
SecondChildCreateTimeTAG: 2013-03-06T04:32:56Z
SecondChildVoteTAG: 0
SecondChildTAG: very useful indeed. Thanks
SecondChildUserIdTAG: 79318
SecondChildUserNameTAG: guruvyasa
SecondChildCreateTimeTAG: 2013-03-08T14:36:22Z
SecondChildVoteTAG: 0
IndexTAG: 1572
TitleTAG: [STAFF]ES04 Problem 7
Might want to reword the problem to say:
> As part of a fund raising campaign, the 12 members of the governing board of an organization pledge to raise 100,000 **in total**.
I wasn't sure if the pledge was to raise 100,000 each or in total.
UserIdTAG: 1143906
UserNameTAG: Robert_Veres
CreateTimeTAG: 2013-03-03T08:13:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 1
FirstChildTAG: The board as a whole pledges to raise 100.000. I've no problems to understand this.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-03T10:46:50Z
FirstChildVoteTAG: 2
IndexTAG: 1573
TitleTAG: ES4 Problem 6
There is an error in this question. The two correct conclusions are:
b) The typical household in the sample consisted of 2.9 people.
c) There were 3480 people living in the sampled households.
UserIdTAG: 1077641
UserNameTAG: bongeri
CreateTimeTAG: 2013-03-03T08:09:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: Not necessarily. Read them again, taking note of definitions.
And remember that pesky little honour code.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T08:20:04Z
FirstChildVoteTAG: 8
FirstChildTAG: "typical" is not the same thing as "average"
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-03T14:34:57Z
FirstChildVoteTAG: 0
FirstChildTAG: I think it doesn't make sense playing with words.
FirstChildUserIdTAG: 491424
FirstChildUserNameTAG: GORGUI
FirstChildCreateTimeTAG: 2013-03-03T15:47:30Z
FirstChildVoteTAG: 2
SecondChildTAG: In my opinion, one of the objectives of the course is to make us better consumers of statists. Therefore if we hear a news source say "the typical household has xx children" we know what that means, and what it doesn't mean. We can reject things that don't make sense. Therefore it does make sense to "play with words" so that we learn these important lessons.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-03T20:10:29Z
SecondChildVoteTAG: 0
SecondChildTAG: > I think it doesn't make sense playing with words.
They are not playing with words.
Statistics is also about words, and understanding what numbers mean. If you make a statement, it has to be statistically correct in numbers and words.
Just like a lawyer has to use his words in the correct context and meaning, so do statisticians.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-03T21:01:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Pardon me if I'm mistaken,since I'm not a native, I try to grasp the meaning of "typical" being used here is not to convey the meaning of average rather it merely states "most of or majority", as in typical south east asian has brown skin...is it? CMIW
SecondChildUserIdTAG: 1274748
SecondChildUserNameTAG: kusumawati
SecondChildCreateTimeTAG: 2013-03-04T07:14:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Conclusion (b), that the typical household contains 2.9 people, MAY be true but we can't know that from the data given.
If 10 households were surveyed, and 9 of them contained 3 people but 1 contained 2 people, then the average would still be 2.9. However, it is inaccurate to say that the "typical" household contains 2.9 people since not one single house contains that many!
To put it another way, if half the houses on your street are painted all red and half are painted all blue, you cannot say that the typical house is painted half red and half blue.
FirstChildUserIdTAG: 1055945
FirstChildUserNameTAG: rebecca417
FirstChildCreateTimeTAG: 2013-03-04T23:34:04Z
FirstChildVoteTAG: 0
IndexTAG: 1574
TitleTAG: help in box and plot lesson
http://www.brainingcamp.com/resources/math/box-plots/lesson.php
UserIdTAG: 1293941
UserNameTAG: CHHAVIMEHROTRA
CreateTimeTAG: 2013-03-03T07:45:39Z
VoteTAG: 3
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 0
IndexTAG: 1575
TitleTAG: timing problem
I just started the course and it seems i'm joining towards the end of the second week. How do i go about submitting the assignments?
UserIdTAG: 1344658
UserNameTAG: sreedharmenon
CreateTimeTAG: 2013-03-03T07:39:07Z
VoteTAG: 1
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 2
FirstChildTAG: For week 1, you don't. Deadline passed. Read the Course Info page for further course details.
Read this thread for how to submit:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5132e6f49788382a0000003a
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T07:45:21Z
FirstChildVoteTAG: 0
SecondChildTAG: same here. I joined the course today, 4th march! what should I do? Do i need to start reading from week 1?
SecondChildUserIdTAG: 1359407
SecondChildUserNameTAG: Indushah
SecondChildCreateTimeTAG: 2013-03-04T19:04:25Z
SecondChildVoteTAG: 0
SecondChildTAG: sir same problem i have joined on 7th march, 2013...how to go about the assignments and what to be done further....will i get certificate even after entering late for this course...
SecondChildUserIdTAG: 1372491
SecondChildUserNameTAG: SHIKHAJUYAL
SecondChildCreateTimeTAG: 2013-03-08T14:25:41Z
SecondChildVoteTAG: 0
FirstChildTAG: same problem here. I want to cry.
FirstChildUserIdTAG: 924021
FirstChildUserNameTAG: ElishaVale
FirstChildCreateTimeTAG: 2013-03-04T15:12:46Z
FirstChildVoteTAG: 0
SecondChildTAG: me too just started.
SecondChildUserIdTAG: 898741
SecondChildUserNameTAG: BrahmaPrakash
SecondChildCreateTimeTAG: 2013-03-05T15:50:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Let's cry togeeher :p because i have same problem too
SecondChildUserIdTAG: 1380557
SecondChildUserNameTAG: Zohaib028
SecondChildCreateTimeTAG: 2013-03-09T16:50:20Z
SecondChildVoteTAG: 0
IndexTAG: 1576
TitleTAG: Are the course material available to us after the course?
Once the course is over are all the course material and exercises available for us if we want to refresh our knowledge or clarify something ?
It is a useful resource which I would like to be able to log in and see if I need it anytime .
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-03T06:36:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Will depend. Some courses leave their material available for a time, others don't. The only other course I did here was leaving material up for about a month. It was up to you to get what you wanted before it disappeared.
Might depend on the server arrangement edX has, keeping all material available forever might not be feasible.
And the lectures might stay on YouTube, so all you need to do is keep copies of the other files.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T06:40:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks.That was the reason I wanted to ask because I was wondering if I should back up all the videos and slides etc though living more and more "on the cloud" Iwas wondering if I should store them now itself.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-03T07:00:22Z
SecondChildVoteTAG: 0
IndexTAG: 1577
TitleTAG: Markov Vs Chebychev
This was good lecture!!
UserIdTAG: 541148
UserNameTAG: Kattimani
CreateTimeTAG: 2013-03-03T06:04:53Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: Better understanding after going through the online book.
FirstChildUserIdTAG: 947092
FirstChildUserNameTAG: PKNeupane
FirstChildCreateTimeTAG: 2013-03-03T11:01:46Z
FirstChildVoteTAG: 0
SecondChildTAG: which book?
SecondChildUserIdTAG: 403216
SecondChildUserNameTAG: harineem
SecondChildCreateTimeTAG: 2013-03-06T17:12:45Z
SecondChildVoteTAG: 0
FirstChildTAG: I thought it a little bit lengthy, and it didn't touch the case of k = 1, when you consider the tails outside 1 SD away from average.
FirstChildUserIdTAG: 1174304
FirstChildUserNameTAG: ThomasHGMann
FirstChildCreateTimeTAG: 2013-03-03T14:32:00Z
FirstChildVoteTAG: 0
SecondChildTAG: It's the same thing as the case with Markov's and a k<1.
As it is a bound, the formula is still valid. Isn't it true that if you move 1 SD away from the average, you'll find at most $ \frac{1}{1^2}=100\% $ of the values on the tails? It's just...not very useful :)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T15:43:27Z
SecondChildVoteTAG: 0
IndexTAG: 1578
TitleTAG: Submission
how exactly do I submit my answers?
UserIdTAG: 1342581
UserNameTAG: Cherry6162
CreateTimeTAG: 2013-03-03T06:00:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: For week 1, you don't. Deadline has passed. So you can only submit Week 2. You click "Check" to get the question graded.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T06:03:40Z
FirstChildVoteTAG: 0
SecondChildTAG: but I can't find the 'check' button!
SecondChildUserIdTAG: 1342581
SecondChildUserNameTAG: Cherry6162
SecondChildCreateTimeTAG: 2013-03-03T06:14:15Z
SecondChildVoteTAG: 0
FirstChildTAG: > but I can't find the 'check' button!
For the first week of questions (Sets 1 - 3), there will be no Check button. You will see a Show Answer button instead.
![enter image description here][1]
For active exercises, you will see a Check and a Save button. Check submits for marking. Save just saves your answer without marking. So you can go away and think about it before submitting.
![enter image description here][2]
If you are allowed more than one submission, this is indicated next to the buttons. So if you get marked wrong, you can try again if you haven't used all your submissions.
The examples above show this. The first image there was only 1 submission allowed, the second had 3 submissions.
[1]: https://edxuploads.s3.amazonaws.com/13622920381343633.png
[2]: https://edxuploads.s3.amazonaws.com/13622921261343622.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T06:29:04Z
FirstChildVoteTAG: 1
SecondChildTAG: oh. ok. thank you.
SecondChildUserIdTAG: 1342581
SecondChildUserNameTAG: Cherry6162
SecondChildCreateTimeTAG: 2013-03-03T06:36:46Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the info. So I think that means that if you have multiple submissions but you get it correct on the first attempt, then there is no need to click "Final Check" since it has been marked. Is that right?
SecondChildUserIdTAG: 899047
SecondChildUserNameTAG: ash-v-g
SecondChildCreateTimeTAG: 2013-03-03T07:32:55Z
SecondChildVoteTAG: 0
SecondChildTAG: > t you get it correct on the first attempt, then there is no need to click "Final Check" since it has been marked. Is that right?
Yes. If you have a green tick, then there is no need to make more submissions. For instance, the one above showing "1 of 3 submissions" was correct. So I just leave it as is, no more submissions as they are not needed.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-03T07:42:30Z
SecondChildVoteTAG: 0
IndexTAG: 1579
TitleTAG: Average commute distance
I am not getting any good knowledge for this particular topic. can you explain more.
UserIdTAG: 222188
UserNameTAG: DrArya2012
CreateTimeTAG: 2013-03-03T05:18:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: Can't be explicit since I plan to respect the honor code.
But, as an hint: review Markov and/or Chebychev. Understand what their rules mean(don't just apply them mechanically). Then the problem should make sense ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-03T10:38:51Z
FirstChildVoteTAG: 0
IndexTAG: 1580
TitleTAG: Slide #6
I did go get a cup of tea, and watched the slide #6. Found it very interesting :)
UserIdTAG: 931587
UserNameTAG: annaikeda
CreateTimeTAG: 2013-03-03T03:26:32Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.2: Deviations from average; the standard deviation (SD)
NumberOfReplyTAG: 1
FirstChildTAG: What kind of tea? (Some of us could use a nice cup ...)
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-03T04:35:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Earl Grey, Hot.
What else? :D
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T10:39:46Z
SecondChildVoteTAG: 0
SecondChildTAG: *brofists klionheart*
SecondChildUserIdTAG: 316261
SecondChildUserNameTAG: Brady1997
SecondChildCreateTimeTAG: 2013-03-06T03:54:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Ha ha ha, instead of going to get tea, I went online and made a quick purchase. :-)
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-03-06T22:12:38Z
SecondChildVoteTAG: 0
IndexTAG: 1581
TitleTAG: Answers to the Exercise Sets
Hi guys and professors!!
I'm enjoying this course a lot, but I think it'd be better if we had access to the answers to the exercise sets after the submission date has passed. I would like to know the answers to the questions I didn't get right in order to figure out what my mistake was.
Hope the professors read my suggestion! :)
UserIdTAG: 162825
UserNameTAG: Brunak
CreateTimeTAG: 2013-03-03T03:00:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: But that is already the case. You even get an explanation too.
FirstChildUserIdTAG: 1152666
FirstChildUserNameTAG: brentsen
FirstChildCreateTimeTAG: 2013-03-03T03:30:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Not sure if this system allows private messages. If it does, and you still don't have the answers for sets 1/2/3, drop me a line, I can send them to you.
SecondChildUserIdTAG: 1019741
SecondChildUserNameTAG: BBF
SecondChildCreateTimeTAG: 2013-03-03T03:41:21Z
SecondChildVoteTAG: 0
FirstChildTAG: You just have to wait until after the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T03:41:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks!! I didn't notice the answers are available for the exercise sets as well. I thought I could only see the answers to the practice sets!
FirstChildUserIdTAG: 162825
FirstChildUserNameTAG: Brunak
FirstChildCreateTimeTAG: 2013-03-03T03:59:34Z
FirstChildVoteTAG: 0
IndexTAG: 1582
TitleTAG: Please stop complaining or being frustrated on wrong answers. Relax and think about this...
The minimum required to pass the Stat2.1x module is 35%.
And I think it is mentionned that the 2 lowest exercise scores will be removed from the total calculation.
And It is clearly written that the certificate you would receive is not graded and is the same for all students that pass.
Beleive it or not but all problems' statements were crystal clear. You may have to read them slowly or several times to avoid zapping key words and getting into the wrong answer.
There was only one little problem in the 'list A having 25 entries average 100 and list B indentical to list A +5 new entries all of them being 100 ' story, which was corrected by the Pr very rapidly. Even that, you could have the correct answer because like in many problems here, we could have 2 submissions.
Please use them with parcimony and strategy if you still get confuse with some problem statement.
Good luck to all of you.
Z.
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-03T02:47:01Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1583
TitleTAG: Skewed distributions (to professor)
I want to discuss the problem that we asked to confirm from the probability density histogram the distribution of the ages of the women that give birth at a certain hospital.
Rule of thumbs mode < median < mean also a many times displayed shape etc etc...
but ...
In this case if I am correct one of the two criteria of the significant non normal distribution ,the kurtosis, failed. It falls in [+- 2SD error of kurtosis] while the skeweness criteria bearly pass.
Also the rule of thumb about the mean and the median it seams that this generally fails frequently in terms of defining the kind of skewness ..."Mean-Median and skew.Correcting a textbook rule" Paul .T. Von Hippel Journal of statistics education volume 13 November 2, 2005.
And finally is it true?that the density calculation induces skewness due to multiplication?
My point is do you think that for a small range or variance of a small population all these could affect the definition of a significant non normal distribution?
Thanks in advance for your time.
UserIdTAG: 1239975
UserNameTAG: Xenofon
CreateTimeTAG: 2013-03-03T02:32:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1584
TitleTAG: Teeter-totter
![][1]
[1]: https://edxuploads.s3.amazonaws.com/13622745581343664.jpg
*Data in the tails of the distribution have a lot of leverage on the mean, just as a light person can balance a much heavier one on a teeter-totter if she sits much farther from the fulcrum than the heavier person does.*
UserIdTAG: 250161
UserNameTAG: gaurwraith
CreateTimeTAG: 2013-03-03T01:37:19Z
VoteTAG: 28
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 7
FirstChildTAG: Excellent
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-03T02:24:40Z
FirstChildVoteTAG: 0
FirstChildTAG: I hope the Professor sees this. It's great.
FirstChildUserIdTAG: 1055674
FirstChildUserNameTAG: SocProf
FirstChildCreateTimeTAG: 2013-03-03T03:02:59Z
FirstChildVoteTAG: 0
FirstChildTAG: Cool!
FirstChildUserIdTAG: 99863
FirstChildUserNameTAG: pramode_ce
FirstChildCreateTimeTAG: 2013-03-03T08:34:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Nice
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T09:18:10Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks the visual aids understanding much more x
SecondChildUserIdTAG: 916875
SecondChildUserNameTAG: nilufa
SecondChildCreateTimeTAG: 2013-03-06T09:29:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Great! A picture is worth a thousand words.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-03T11:03:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Teeter-totter = seesaw (British English)
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-03T14:27:06Z
FirstChildVoteTAG: 3
SecondChildTAG: Thanks,
SecondChildUserIdTAG: 1082215
SecondChildUserNameTAG: Ayee
SecondChildCreateTimeTAG: 2013-03-05T14:21:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Class is so much fun ^_^
FirstChildUserIdTAG: 1243910
FirstChildUserNameTAG: Diddi
FirstChildCreateTimeTAG: 2013-03-05T22:23:17Z
FirstChildVoteTAG: 0
SecondChildTAG: Very beautiful
SecondChildUserIdTAG: 945953
SecondChildUserNameTAG: Turca
SecondChildCreateTimeTAG: 2013-03-06T10:44:58Z
SecondChildVoteTAG: 0
IndexTAG: 1585
TitleTAG: Unimodal distribution.
Hello! I'm a bit confused about how a distribution is unimodal, bimodal... etc. Prof. Adhikari said that the distribution in the last example in this part is unimaodal because it has one peak, but actually the number of peaks depends on the width of the interval. If we consider the interval width to be 10 points, i.e. 40 to 50, 50 to 60.. etc. yes we'll have one peak which is at the interval 80 to 90. However, if we consider the interval width to be just 1 point, i.e. 48,49,50,51,..., 100 we will have 3 peaks, namely at 63, 70 and 95. So is this distribution unimodal ot trimodal?!
What I understand is that: what determines if the distribution is unimodal, bimodal... etc. is the number of entities with the same highest frequency, or is it depend on the interval width we consider?
Thank You!
UserIdTAG: 528804
UserNameTAG: AdhamM
CreateTimeTAG: 2013-03-03T01:09:50Z
VoteTAG: 4
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.1: The median and the mode
NumberOfReplyTAG: 4
FirstChildTAG: Wow, this is a good "thinking" question! I had to draw it all out myself before I could even think of answering your question. So here is my best humble shot:
In that lecture, think about what is happening when the graph goes from being "sticky" to a nice curvy histogram. Then look back at the grade data. See where the most grades occur? There are more grades in the 80s than anywhere else. THAT is the "uni" part. Yes, the 3 modes are still captured in that histogram, but in the case of the mode of grade value 63, it happens to occur in a lower area of the histogram. Why? Because there were only 3 scores in the 60s yet there were 8 scores in the 80s. Hence the highest peak occurs in the interval from 80-89.
I went over that lecture 3 times after reading your question, and it certainly does force us to think. A lot!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-03T02:00:43Z
FirstChildVoteTAG: 2
SecondChildTAG: Well, there are more scores in the interval 80-89 than 60-70 because I chose to have my intervals that way 40-50, 50-60, 60-70, 70-80,..etc. but What if I chose them to be 40-45,...,60-65, 65-70, 70-75,...etc.? look at the Histogram with an interval span of 5, how does it look? and how is it classified in terms of x-modal?
SecondChildUserIdTAG: 528804
SecondChildUserNameTAG: AdhamM
SecondChildCreateTimeTAG: 2013-03-06T18:29:49Z
SecondChildVoteTAG: 0
FirstChildTAG: I believe the unimodal or bimodal characteristic is based upon the values you wish to assign to each bin. This way the 'sticky' histogram should be considered as being trimodal. It has 3 modes because there are 3 values that are the most repeated ones. And then, when you move to the other histogram, yo have a unimodal distribution because there was only ONE value which was the most repeated, which was 80-90. So you consider that interval as being one value, because that is how you are dividing your histogram. Remember that when you make a graph like that on your data, you lose a lot of information. In this case, we lost every individual value among those ranges, so that's the best approximation we can do. I hope this helped you out.
FirstChildUserIdTAG: 1056095
FirstChildUserNameTAG: Guinto90
FirstChildCreateTimeTAG: 2013-03-03T08:36:03Z
FirstChildVoteTAG: 0
FirstChildTAG: The modal distribution is done when the histogram is converted into a smooth curve.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T09:18:50Z
FirstChildVoteTAG: 0
FirstChildTAG: I think I've found the answer of the question "does it depend on the interval width?" in the textbook:
http://statistics.berkeley.edu/~stark/SticiGui/Text/location.htm#location
"The mean, median, and mode can be related (approximately) to the histogram: loosely speaking, the mode is the highest bump, the median is where half the area is to the right and half is to the left, and the mean is where the histogram would balance, were it a solid object cut out of a uniform block of metal. (All these heuristics are approximate, and **depend on the class intervals**.)"
It's stated here that it depends on the class interval. However, the question is: how to choose the "*best*" or "*most representative*" class interval?
I do not mean the most representative mesure of location, I mean the most representative class interval (span of the intervals) that gives the most illustrated or represtative histogram.
FirstChildUserIdTAG: 528804
FirstChildUserNameTAG: AdhamM
FirstChildCreateTimeTAG: 2013-03-06T20:19:06Z
FirstChildVoteTAG: 1
IndexTAG: 1586
TitleTAG: Staff: selections for problem 6, exercise 5 not registered correctly
Dear staff,
I wish to request to give me another chance to answer problem 6 in exercise 5.
I was using the Chrome web browser on android 4.2. The answers submitted weren't the ones entered. I clicked on my answer options and then hit "Final Check". On doing so it unchecked one of the options marked and hence I was marked incorrectly. I am concerned that the answers submitted may not represent what has been entered. I am not trying to get my incorrect answers changed, but rather am drawing to your attention the fact that there is some spurious behaviour with mobile devices. I humbly request the course staff to, if possible, reset my question for this one and thus allow me to make my intended submission. I totally understand if that's not possible.
I look forward to your reply. Thanks
UserIdTAG: 1237295
UserNameTAG: tanushree31
CreateTimeTAG: 2013-03-03T00:52:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Advice from a fellow student: Please keep in mind that the cutoff for passing the class is at 35%. This is a pretty low bar. I understand that it's frustrating to be marked incorrectly when it feels like it wasn't your fault. But look at the big picture -- this one problem in one exercise won't affect your ability to pass the class that much. And it would take a significant amount of effort for the professor to allow one out of 45,000+ students to get one more chance on one problem out of one exercise. The cost of fulfilling your request greatly outmeasures any benefit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-03T01:34:32Z
FirstChildVoteTAG: 1
SecondChildTAG: youre right!
SecondChildUserIdTAG: 385816
SecondChildUserNameTAG: dinoRB
SecondChildCreateTimeTAG: 2013-03-03T02:25:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I do see your point. However just wanted to bring this to light as it is frustrating and rather disappointing...!!
Thanks .
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-03T11:46:41Z
SecondChildVoteTAG: 0
FirstChildTAG: One piece of advice always hit the save button first - recheck and then click the Final check button !1 I swore I had hit an AB and luckily there were 2 submissions for that question so it was OK but if there was one I would have lost some points !! One advantage of the Save button is it locks an answer unless you change it and doesnt select an answer just because you hover over it.FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T02:46:41Z
FirstChildVoteTAG: 0
FirstChildTAG: It's a problem that I've also suffered, scrolling with the track pad and inadvertently tapping (you know, the sensitivity of the track pad is a hell) and checking without seeing that my previous selection had changed. @Prasannasimha trick is a good one. My current strategy is trying to scroll only when the pointer is placed as far away as possible from the "white" canvas of the webpage. Be careful!
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-03T11:18:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Atopos and Prasannasimha! Its so frustrating...!!! and I did press the save the button and then changed my answer, thats when it got me.......!!!!!!!...
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-03T11:45:35Z
SecondChildVoteTAG: 0
SecondChildTAG: I noticed it when I was doing an exercise and clicked one answer and had my pointer hovering over another and then to my horror I clicked a submit/check I saw the wrong one selected and then I luckily had a second submission and corrected it !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-03T13:43:41Z
SecondChildVoteTAG: 0
IndexTAG: 1587
TitleTAG: Videos truncated?
The tail end of both videos in section 3B is getting cut off for me, by roughly 5-7 seconds. That's not a problem for my comprehension, but I wanted to note it as a technical or content glitch you may want to look at.
UserIdTAG: 1224506
UserNameTAG: debradley
CreateTimeTAG: 2013-03-03T00:48:00Z
VoteTAG: 2
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3.5: Markov’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: I noticed the same thing.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-03T01:35:16Z
FirstChildVoteTAG: 0
IndexTAG: 1588
TitleTAG: Confusing wording on Problem 4 of Exercise set 4
The question reads:
"PROBLEM 4 : 2.0 POINTS
The stem and leaf plot below shows the distribution of weights (in ounces) of newborns at a hospital. The line 10 | 358 should be read as 103, 105, 108. Select the option that is closest to the average of these weights. Yes, you can enter the list into your calculator and compute the average. But it will be a lot faster to do this exercise by inspection."
It is not clear from the way the question is worded if the student is being asked to take the average of the *entire* stem and leaf plot, or only of the line that includes the values 103, 105, and 108.
The lines in question read:
"The line 10 | 358 should be read as 103, 105, 108. Select the option that is closest to the average of these weights."
"These weights" seems to refer to the weights of line 10, that have just been mentioned in the previous sentence.
This is not the first time I have been confused by the wording of these homework problems. It is a very frustrating thing to get a problem wrong simply because the problem is not stated clearly.
UserIdTAG: 911606
UserNameTAG: ExpatKyle
CreateTimeTAG: 2013-03-02T14:38:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: Yes, ok, it's not **explicit**, perhaps. But come on, use a bit of common sense.
Why would they give you the entire plot and then ask you to consider only 3 values? Especially when 3 of the 4 answers clearly have nothing to do with those 3 values!
Also, half the text of the problem is about how sometimes inspection allows you to avoid lots of calculations and do things "a lot faster". That point would be lost if the question was about the average of 3 values.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T16:08:56Z
FirstChildVoteTAG: 0
SecondChildTAG: I did use common sense:
I read what was written, and that clearly indicated that we were supposed to take the average of "these [three just-mentioned] values".
Unfortunately, the answer which the professor wanted returned was not the answer she asked for.
Long story short: i did not get this question wrong because i didn't know how to take an average, failed at the math, or had misunderstood the principles involved.
I got this question wrong because A) i had a single chance to answer it, but B) there were two possible ways of interpreting what was asked, and the choice most clearly indicated according to the rules of standard written English happened to be the wrong one.
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-03T04:49:02Z
SecondChildVoteTAG: 0
SecondChildTAG: No. If you used common sense, you would immediately realize what was being asked there.
You used technicalities about the "rules of standard written English" to justify an interpretation of the question that makes no sense, given the circumstances.
It's just like those guys did [here][1]. They posted a news article to talk about a mix up that, while technically true, has nothing whatsoever to do about the topic of the original speech. It would be amusing, except you actually seem to take it seriously.
[1]: http://www.washingtonpost.com/blogs/in-the-loop/post/obamas-jedi-mind-meld-mixes-sci-fi-worlds/2013/03/01/749ca984-8291-11e2-a350-49866afab584_blog.html
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T11:56:53Z
SecondChildVoteTAG: 0
FirstChildTAG: There is no stem and leaf plot on the page you have posted this comment.
Also, the issue has been raised (as I am sure you are aware as you have commented multiple times). Please refrain from multiple postings as it makes the discussion boards much more difficult to navigate.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-03-02T19:08:54Z
FirstChildVoteTAG: 0
FirstChildTAG: And please, **use the forum that was created for this set of questions**. Putting your question in the wrong forum means that others who are also confused, will probably not see it.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T21:17:08Z
FirstChildVoteTAG: 0
FirstChildTAG: I offer up these suggestions as much in a spirit of helpfulness as of frustration:
A) It's my first time to post anything to this forum repository. Telling me to "post it in the [right] one" does absolutely nothing to help me understand where i should be posting this. There appears to be, from what i can tell, five different discussions (at least) dealing with this one issue. Which one am i supposed to post to? How many discussion am i supposed to review before i have satisfactorily determined that i've found the "right" one?
B) The forum interface is clunky and extremely difficult to navigate. It is not arranged according to weekly content, and it only displays 10 different discussions at a time. Frankly, i just didn't realize that i would be expected to review a list of 50 or 60 or 100 different topics that load *extremely* slowly simply to indicate a problem with the homework. And again: how am i supposed to know which question is "the one" i am supposed to be posting on?
C) There *is* a course wiki. Oddly, however, the course staff has so far failed to add anything that might actually help the students out with this sort of problem, over there. It stands to reason that should be the place where administrative questions about and difficulties with the problem sets and content would best be posted, rather than a long, ever-changing list of random topics on a clunky "discussion board" that offers absolutely no possibility of ordering information in a meaningful or effective manner.
FirstChildUserIdTAG: 911606
FirstChildUserNameTAG: ExpatKyle
FirstChildCreateTimeTAG: 2013-03-03T05:03:08Z
FirstChildVoteTAG: 0
FirstChildTAG: > And again: how am i supposed to know which question is "the one" i am supposed to be posting on?
You posted in the subforum for Exercise set 1.You could have done that one of two ways.
From the Discussion tab, click on New Post. Then you have to decide what forum to post in. The drop down box on the left has a list of all forums. You select the appropriate one. Your post will be placed in whatever forum you select.
![enter image description here][1]
Or you go to the Question page, scroll to the bottom where you will find a discussion link. Every lecture page and question page has a forum link. It might take a day or two to be activated at the start of a new week, but it will eventually appear.
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13622899431343682.png
[2]: https://edxuploads.s3.amazonaws.com/13622900631343678.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-03T05:55:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Susan! Maybe this could be in the course Wiki...
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-03T13:23:44Z
SecondChildVoteTAG: 0
FirstChildTAG: Ex Post Facto, i'm sure everything seems super clear.
FirstChildUserIdTAG: 911606
FirstChildUserNameTAG: ExpatKyle
FirstChildCreateTimeTAG: 2013-03-03T16:34:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Just curiously, SusanAust:
Are you a student, or staff?
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-03T16:35:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Staff posts have a blue bar across the top of the post, with the word staff.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-03T22:28:25Z
SecondChildVoteTAG: 0
IndexTAG: 1589
TitleTAG: Faster if do the problem 4 with "inspection"
Hi,
Well, I only came up with calculate its average. What is the "inspection"? Can I find it in the lecture somewhere?
UserIdTAG: 1133472
UserNameTAG: hirogotanda
CreateTimeTAG: 2013-03-02T14:23:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: In maths terms, "inspection" is looking closely at the data and finding or approximating the answer that way. There are lots of example in the lectures of looking at histograms etc and estimating values. So it might not give you an exact answer but it might allow you to work out which of a set of possible answers "looks" right. Hope that makes sense / helps!
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-02T14:32:39Z
FirstChildVoteTAG: 0
SecondChildTAG: it might help to see how the numbers are "weighted", and to compare with the choices. the choices show some extreme figures, which would show they are not close to the middle or average.
SecondChildUserIdTAG: 1264070
SecondChildUserNameTAG: XenDavid
SecondChildCreateTimeTAG: 2013-03-03T04:11:33Z
SecondChildVoteTAG: 0
SecondChildTAG: As professor stressed so many times on videos that consider stem and leaf plot as distribution(density of data set) and average will be around middle of it and that is what simple visualization provides.
SecondChildUserIdTAG: 1181586
SecondChildUserNameTAG: eumannu
SecondChildCreateTimeTAG: 2013-03-04T02:30:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Took me a bit to figure out "by inspection". Include looking at the answers as part of your inspection...
SecondChildUserIdTAG: 945111
SecondChildUserNameTAG: judithpdx
SecondChildCreateTimeTAG: 2013-03-04T19:37:22Z
SecondChildVoteTAG: 0
SecondChildTAG: it was easier for me to plug in the answers and work backwards to "inspect if they made sense"
SecondChildUserIdTAG: 348290
SecondChildUserNameTAG: joshb
SecondChildCreateTimeTAG: 2013-03-04T20:57:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I think that the average cannot, in this case, be calculated only by inspection, but only the mode.
SecondChildUserIdTAG: 128193
SecondChildUserNameTAG: Marianne
SecondChildCreateTimeTAG: 2013-03-04T23:13:42Z
SecondChildVoteTAG: 0
FirstChildTAG: No, you won't have it in the lectures, but you might have done something similar in your life when you didn't have a calculator or the time to calculate the average. It's a multiple choice question, so look at the possible answers: are any of them too big? Too small? Compare the offered values to the list of data you have.
FirstChildUserIdTAG: 1262732
FirstChildUserNameTAG: Gahuga
FirstChildCreateTimeTAG: 2013-03-02T14:45:36Z
FirstChildVoteTAG: 1
SecondChildTAG: Problem 4, the way it's worded, describing points 103,105,108, and having one of the answers being 105, and saying use 'inspection' I figured the answer was 105 since the average of all the points is 123.53 (which is close to 125 though.) My bad.
SecondChildUserIdTAG: 25489
SecondChildUserNameTAG: TerryatMit
SecondChildCreateTimeTAG: 2013-03-02T19:19:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Same. I was thrown off by the example of the three points (103,105,108)followed by the request to find the average of "these weights". Assumed then, that the "inspection" was to do a quick mental estimate and compare to the available answers. That one of the answers actually fit this ruse, I consider to be devious.
FirstChildUserIdTAG: 441413
FirstChildUserNameTAG: coyotecoach
FirstChildCreateTimeTAG: 2013-03-03T20:50:17Z
FirstChildVoteTAG: 0
IndexTAG: 1590
TitleTAG: Am I going right ???
Hello friends..
I have completed all the graded exercises till now (till 2nd week).
So am I going on right path or I need to do anything extra apart from this all ?
Please reply as soon as possible.
All the best for all your exercises as well.
Thanks & Regards
UserIdTAG: 1039552
UserNameTAG: sutikshan4nmims
CreateTimeTAG: 2013-03-02T14:07:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You should be ok, and I don't think you *need* to do anything else if you've done good in the problems.
But, if you still have lingering doubts, you might want to explore the [online textbook][1] in detail and/or let us know in the forum so we can discuss them.
Or, if you're feeling adventurous, you could also play a little with Google and some key terms :)
[1]: http://statistics.berkeley.edu/~stark/SticiGui/index.htm
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T15:52:52Z
FirstChildVoteTAG: 0
IndexTAG: 1591
TitleTAG: Problem 2 answer
Why is -4.01 the wrong answer and +4.01 is correct? Surely the average goes down and not up.
UserIdTAG: 130184
UserNameTAG: Tapparo
CreateTimeTAG: 2013-03-02T13:34:03Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 3
FirstChildTAG: Calculate the average of the following three numbers: 1, 5, 9.
Then change the third number to 20 so you have 1, 5 and 20. What did just happen to the average?
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-02T14:05:35Z
FirstChildVoteTAG: 0
SecondChildTAG: we have to take a bigger number(165) instead of a smaller number(16.5) so the average will go up
SecondChildUserIdTAG: 1127915
SecondChildUserNameTAG: HelloFriend
SecondChildCreateTimeTAG: 2013-03-04T16:51:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree. The average will really go up since 165 is larger than 16.5. :)
SecondChildUserIdTAG: 969517
SecondChildUserNameTAG: iamlala
SecondChildCreateTimeTAG: 2013-03-04T18:46:19Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree! the average will go down, certainly! since 165 was the wrong observation (165 is mistakenly recorded instead of 16.5) and 16.5 is the correct observation, the change will be (16.5-165)/37. This leads to a negative change in the average. Hence average goes down.
STAFF, please look into the problem!
SecondChildUserIdTAG: 47031
SecondChildUserNameTAG: PrernaDewan
SecondChildCreateTimeTAG: 2013-03-05T15:57:30Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree, average should go down. 165 was the incorrect mileage
SecondChildUserIdTAG: 462806
SecondChildUserNameTAG: hayesmi1
SecondChildCreateTimeTAG: 2013-03-05T21:25:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Im agree !! it should go down !!
SecondChildUserIdTAG: 1249299
SecondChildUserNameTAG: PaolaVargasV
SecondChildCreateTimeTAG: 2013-03-06T02:29:54Z
SecondChildVoteTAG: 0
FirstChildTAG: Why would the average would go down when you insert a data that is much higher than the others? :S
I'm guessing that you are reading the question wrong.
What's asked is, how does the average change when you compute it by using the wrong value, compared to when you compute it using the correct value?
Example:
If your list is [0,1,1,2], the average is 1. If, by mistake, you read the list as [10,1,1,2], the average becomes 7/2. By how much has this mistake changed the average? The wrong average is 5/2 *higher* than the right one. Same thing is happening in Problem 2 ;)
EDIT: thanks to Hartti for pointing out that my first average in the example was wrong. I've fixed the mistake ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T14:06:32Z
FirstChildVoteTAG: 2
SecondChildTAG: To be correct the average of the data set 0, 1, 1 and 2 should be 1.
0 + 1 + 1 + 2 = 4
4 : 4 = 1
Because there are four entries not three as the example in the lecture showed.
SecondChildUserIdTAG: 974720
SecondChildUserNameTAG: Hartti
SecondChildCreateTimeTAG: 2013-03-03T12:48:16Z
SecondChildVoteTAG: 0
SecondChildTAG: You are perfectly right. I...uh, don't know what happened there, but yes, the average is 1, not 3/4.
Thankfully the point I was trying to make in my post is still valid :P
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T16:33:01Z
SecondChildVoteTAG: 0
FirstChildTAG: If you mistakenly insert a very high number for one of the values instead of a comparatively low number, then what will happen to the average of the list? The question is asking what happened to the average when they used 165 in the list instead of the correct number (which was much much smaller).
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-02T16:34:38Z
FirstChildVoteTAG: 4
IndexTAG: 1592
TitleTAG: PROBLEM7
please i need help for problem 7.i really don't understand it
UserIdTAG: 935205
UserNameTAG: memekeng
CreateTimeTAG: 2013-03-02T10:56:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: > As part of a fund raising campaign, the 12 members of the governing board of an organization pledge to raise \$100,000. In the first month of the campaign, the average amount raised by the 12 board members is \$5,200. How much more must they raise, on average, so that they can keep their pledge?
12 people are trying to raise \$100,000 between them. They have raised an average $5200. You should be able to work out the total raised, then how much, on average, remains.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T11:24:22Z
FirstChildVoteTAG: 0
SecondChildTAG: How long is the campaign ? is it 12 months ? the question is not clear . how much more time do we have . Should we assume 12 months ?
If we divide the remaining amount(100000-5200) by 12 members the answer is incorrect , so its not what each member more .
SecondChildUserIdTAG: 984232
SecondChildUserNameTAG: Selwyn1977
SecondChildCreateTimeTAG: 2013-03-02T12:45:41Z
SecondChildVoteTAG: 0
SecondChildTAG: If each one of the member raise5200 when we collect all they raised they will not be 100.000 because 2500*12=62400 so those 12 member should raised 833.3 each and of them to complete100.000 and to keep their pledge so the first average whish is5.200 should raise to8.333 ie.increase by 3.133 am I right?
SecondChildUserIdTAG: 1039467
SecondChildUserNameTAG: omnia3
SecondChildCreateTimeTAG: 2013-03-02T12:45:48Z
SecondChildVoteTAG: 0
SecondChildTAG: There is no time element to this question its just number of members and amount .
SecondChildUserIdTAG: 984232
SecondChildUserNameTAG: Selwyn1977
SecondChildCreateTimeTAG: 2013-03-02T12:52:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Each of the member has on average raised 5200, so 12 members have raised an X number. There is still a deficit. That deficit must be raised by shared by all members, which gives the number which a individual member should raise
SecondChildUserIdTAG: 569767
SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-03-02T14:23:50Z
SecondChildVoteTAG: 0
SecondChildTAG: @Selwyn1977 you cant deduct 5200 from 100,000 cause 5200 is the average raised per member. 100,000 is the target total amount to be raised by all all 12 members.
SecondChildUserIdTAG: 254949
SecondChildUserNameTAG: stormshadow
SecondChildCreateTimeTAG: 2013-03-02T16:11:08Z
SecondChildVoteTAG: 0
SecondChildTAG: So much for the honour code.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-02T21:20:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Omnia3 ;)
SecondChildUserIdTAG: 1288142
SecondChildUserNameTAG: aldawlah
SecondChildCreateTimeTAG: 2013-03-03T03:54:31Z
SecondChildVoteTAG: 0
SecondChildTAG: To answer the problem u should differentiate between 100000= total amount of money they should arise
"X" = is the average of the moneye they pledge to achieve
5200 = is part of the average they did in the 1st month
The answer is to find how much of AVERAGE should be add to 5200 to achieve "X"
Good luck
SecondChildUserIdTAG: 1288142
SecondChildUserNameTAG: aldawlah
SecondChildCreateTimeTAG: 2013-03-03T04:00:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi there!
It is a lot easier if you have a look to the slides provided by the stuff of the course. There, you'll find an almost identic example of this exercise. I really recomend you to carefully check the materials before doing nothing. It's being a very useful strategy for me.
Good luck!
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-02T21:14:44Z
FirstChildVoteTAG: 0
IndexTAG: 1593
TitleTAG: late comer
all questions were right but did not count unfortunately.
UserIdTAG: 421428
UserNameTAG: mshahid007
CreateTimeTAG: 2013-03-02T10:47:56Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Not unfortunate at all! You **learned** the material and did very well, thus you are keeping up (so far) in **THAT** sense. Which puts you in a great position to continue onward and do just as well in the current Week 2 and later. (Not all of us can say we are doing as well as you, even though some students did get their first set of scores to "count".) Point is, **all** learning counts.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-03-02T15:21:24Z
FirstChildVoteTAG: 3
SecondChildTAG: Wonderful way of looking at it! :)
SecondChildUserIdTAG: 1024913
SecondChildUserNameTAG: akaren65
SecondChildCreateTimeTAG: 2013-03-02T16:27:52Z
SecondChildVoteTAG: 0
IndexTAG: 1594
TitleTAG: Poorly worded problem 6 and suggestion to STAFF
The question for problem 6 is quite confusing and misleading. Moreover, wouldn't it be more convenient to add some more option in the answer (If more than one option need to be marked) for eg.
1. more than 25
2. more than 35
3. more than 45
4. 1 and 2
5. 1 and 3
6. 2 and 3
7. all of the above
Furthermore, owing to the number of option in the answer the number of submission should be given accordingly (taking into account from the previous problems)
So, i kindly request the staff to look into the matter.
UserIdTAG: 340510
UserNameTAG: shngain
CreateTimeTAG: 2013-03-02T09:09:48Z
VoteTAG: 8
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 8
FirstChildTAG: Maybe...but if so, I'm pretty sure it was intentional. To test that we really understand what we're talking about here ;)
Also, there's no reason to have options 4 to 7 when you can already check multiple answers.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T11:38:32Z
FirstChildVoteTAG: 3
SecondChildTAG: yeah, it really is misleading.. At least write in the problem that more than 1 option is possible, I got it wrong because of that =/
SecondChildUserIdTAG: 198235
SecondChildUserNameTAG: Bezmolwie
SecondChildCreateTimeTAG: 2013-03-02T12:49:26Z
SecondChildVoteTAG: 0
SecondChildTAG: > A firm has 82 employees. The average commute distance (that is, the
> travel distance from home to work) of the employees is 6.2 miles. How
> many employees have a commute distance of less than 15.5 miles? **Select
> all that are correct.**
See the part in bold. It *does* say that more than 1 option is possible ;)
That said, yes, it is slightly misleading unless you carefully read the text, and understand what is asked.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-02T13:23:26Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem asks "how many have a commute distance of LESS than 15.5 miles?" The practice problems all ask "how many can be MORE or equal than ..." Therefore, calculate as More, then subtract to get how many are LESS.
SecondChildUserIdTAG: 797869
SecondChildUserNameTAG: edoz
SecondChildCreateTimeTAG: 2013-03-02T19:42:35Z
SecondChildVoteTAG: 0
SecondChildTAG: An important part of these problems is reading the problem carefully. Reading carefully and making sure you understand is essential. Several times in the lectures the professor has encouraged us to look carefully, read carefully, understand before proceeding. That is one of the most important things we can learn from this course. (I just got this problem wrong because I did not read it carefully. I did the calculation correctly, understood the solution, but was careless reading the instructions, so I got it wrong.)
SecondChildUserIdTAG: 433872
SecondChildUserNameTAG: dfburke
SecondChildCreateTimeTAG: 2013-03-03T01:33:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I got this one wrong and at first couldn't figure out why but then when I read the question again I noticed the "select all that are correct" and realised that was why I was wrong. **Entirely my own fault** for not reading the question carefully. People need to stop blaming the staff for not reading problems properly.
SecondChildUserIdTAG: 1015358
SecondChildUserNameTAG: clarence30
SecondChildCreateTimeTAG: 2013-03-03T02:10:11Z
SecondChildVoteTAG: 0
SecondChildTAG: I liked this problem so much.
SecondChildUserIdTAG: 1288142
SecondChildUserNameTAG: aldawlah
SecondChildCreateTimeTAG: 2013-03-03T05:55:33Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with Clarence30. The question is clear **if** you read it
SecondChildUserIdTAG: 164614
SecondChildUserNameTAG: LuketheEngineer
SecondChildCreateTimeTAG: 2013-03-03T11:04:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I, too, am a fan of the question.
SecondChildUserIdTAG: 1314968
SecondChildUserNameTAG: thenson9200
SecondChildCreateTimeTAG: 2013-03-03T12:22:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I too failed to read the last sentence in this question. The issue is that it **is** the last sentence. This is bad design. We live in a world of sound bites and short attention spans.
SecondChildUserIdTAG: 270738
SecondChildUserNameTAG: sheardp
SecondChildCreateTimeTAG: 2013-03-03T17:27:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Doesn't mind that we should encourage such a world.
Especially not in an academic course, official or not.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T18:15:12Z
SecondChildVoteTAG: 0
SecondChildTAG: It would help if the last sentence was in bold or stated first.
SecondChildUserIdTAG: 1260533
SecondChildUserNameTAG: kijones
SecondChildCreateTimeTAG: 2013-03-05T21:30:42Z
SecondChildVoteTAG: 0
SecondChildTAG: yeah it is not optimally phrased. it should say check all that apply.I don't see a reason to make sentences complex or dubious.in any case..learning or advancement does not mean making things complex...but make it simple..
SecondChildUserIdTAG: 358255
SecondChildUserNameTAG: drnidhi27
SecondChildCreateTimeTAG: 2013-03-06T03:38:59Z
SecondChildVoteTAG: 0
SecondChildTAG: This is rich.
I wonder how many of y'all were telling those of us who so carefully read Problem 4 on the last series to "Use common sense!" and "Obviously, the way the problem was set up, the Professor INTENDED for...."
Now, all of a sudden, it's "Read the problem carefully!" and "Be sure to follow the directions as stated!"
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T16:57:07Z
SecondChildVoteTAG: 0
SecondChildTAG: Klionheart, i *know* you were one.....
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T16:57:42Z
SecondChildVoteTAG: 0
FirstChildTAG: You are giving away too much information prior to submission due date.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-03-02T18:16:02Z
FirstChildVoteTAG: 1
SecondChildTAG: I post the question looking into the account of the honor code. I came to learned about so called mistake from previous post.
SecondChildUserIdTAG: 340510
SecondChildUserNameTAG: shngain
SecondChildCreateTimeTAG: 2013-03-04T09:23:40Z
SecondChildVoteTAG: 0
FirstChildTAG: It is not poorly worded- there is a reason for it and it relates to "Bounds or boundary conditions.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-02T18:31:26Z
FirstChildVoteTAG: 4
FirstChildTAG: Hi!
We should be asking about doubts but I think it is not a good idea to explain how to do a graded exercise almost step by step. Please, read the slides and see the videolectures before going to the graded exercises. I use this sensible strategy and it's working very well to me.
Good luck!
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-02T21:25:09Z
FirstChildVoteTAG: 3
FirstChildTAG: I didn't have any problems doing it! You need to pay attention to the way the question is asked, that is all!
FirstChildUserIdTAG: 99863
FirstChildUserNameTAG: pramode_ce
FirstChildCreateTimeTAG: 2013-03-03T08:14:05Z
FirstChildVoteTAG: 4
FirstChildTAG: I agree, the wording could be improved. Even better, the correct answer can be given as an option.
FirstChildUserIdTAG: 382959
FirstChildUserNameTAG: RajdeepSingh
FirstChildCreateTimeTAG: 2013-03-03T11:43:50Z
FirstChildVoteTAG: 1
FirstChildTAG: I understood why they designed the question this way but this question went too far. There have been many tricky questions here, which I doubt they can help me understand statics better. I wish to see less number of tricky questions in future lectures. Little disappointed.
FirstChildUserIdTAG: 1106581
FirstChildUserNameTAG: Beann
FirstChildCreateTimeTAG: 2013-03-03T22:01:50Z
FirstChildVoteTAG: 0
SecondChildTAG: But isn't life tricky and if you agree, isn't this a good preparation for life?
SecondChildUserIdTAG: 277481
SecondChildUserNameTAG: scott520
SecondChildCreateTimeTAG: 2013-03-03T22:39:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Got Question no. 6 wrong but that was due to my mistake of not understanding the concept better. But now I do. I think it wasn't difficult to understand the phrasing of the question and we should be ready for slight twists and turns..
FirstChildUserIdTAG: 229740
FirstChildUserNameTAG: Poojanshr
FirstChildCreateTimeTAG: 2013-03-06T07:50:22Z
FirstChildVoteTAG: 0
IndexTAG: 1595
TitleTAG: - unifrom distribution - problem 4 c
could you please clarify the uniformity of distribution. throughout we have been assuming that the distribution of values is equal- hence the flatness of the bars of the histogram. please explain why this is being negated in problem 4 c.
thanks
UserIdTAG: 914795
UserNameTAG: ayeshar
CreateTimeTAG: 2013-03-02T08:44:40Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Think about this problem like this:
If you assumed that the distribution was uniform, how many pupils attended school only for one year? only two years? etc.? And would it make sense?
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-02T10:36:43Z
FirstChildVoteTAG: 1
FirstChildTAG: I quite agree with ayeshar's comment and have the same question. I don't quite understand the point Mzvd is trying to make.
FirstChildUserIdTAG: 970558
FirstChildUserNameTAG: nk0321
FirstChildCreateTimeTAG: 2013-03-03T20:52:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, we assume that the data is uniformly distributed because otherwise, with the instruments currently at our disposal, we wouldn't be able to handle the example data.
Question c doesn't negate that. It only asks if the assumption we are making is reasonable or not in that specific case.
Now think of what we are talking about. Do real children(in the USA) commonly start school and then abruptly stop after a couple of years?
No. In the bast majority of cases, once they start a certain school "layer" (elementary, middle, high, college), they usually complete that "layer", so you're going to have very few actual people in the middle of those wider ranges.
For example, take the 0-9 range. Most of the people in that range are going to be clumped at 0, as they represent children who never entered any school. Once a children *starts* school, s/he going to go all the way through elementary and middle school in most cases, and it'll be *very* rare that they drop off in 4th or 5th grade. In numbers: if there are, say, 100 children in that 0-9 range, it's a safe guess that at least 95 of them will be in the 0-1 sub-range. Definitely not *uniformly* distributed.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T21:30:08Z
SecondChildVoteTAG: 0
IndexTAG: 1596
TitleTAG: progress
my answers aren't graded on my progress why?
UserIdTAG: 704225
UserNameTAG: mohamedaboouf
CreateTimeTAG: 2013-03-02T08:34:15Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: bad luck :p
FirstChildUserIdTAG: 817087
FirstChildUserNameTAG: turnonb
FirstChildCreateTimeTAG: 2013-03-02T13:04:55Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you check your answers?
Did they get a green check, or red cross next to them?
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T14:09:42Z
FirstChildVoteTAG: 0
IndexTAG: 1597
TitleTAG: Section 3b is not loading with me,,
Section 3b: Measures of Location (Lec 3.4 - 3.5), is not loading with me the whole day yesterday & today also. Am I the only one, or the issue is related to the site ?
Many thanks :)
UserIdTAG: 1232249
UserNameTAG: FatmaSam
CreateTimeTAG: 2013-03-02T07:52:18Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I have the same problem , but I suspect it had to do with Google Chrome. Using that browser I also have problems with YouTube in general, and also other Google services like Docs, and the search on the address bar.
I switched to Firefox at the moment and everything is working normally, so I suggest you try the same if you are using Chrome.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T13:27:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Many thanks Klionheart :))
it has resolved thanks God :)
SecondChildUserIdTAG: 1232249
SecondChildUserNameTAG: FatmaSam
SecondChildCreateTimeTAG: 2013-03-02T16:14:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi!
Yes, I also have problems with google chrome. Instead, when I use Mozilla everything works. My recomendation... try the mozilla firefox browser.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-03-02T21:31:55Z
FirstChildVoteTAG: 0
IndexTAG: 1598
TitleTAG: Understanding the "mode"
No matter how many times I read, I have no idea what following explanation means. "However, the mean, the median, and the mode are "as close as possible" to all the data: For each of these three measures of location, the sum of the distances between each datum and the measure of location is as small as it can be. The differences among the three measures of location are in how "distance" is defined."
Could somebody please help me!
UserIdTAG: 1133472
UserNameTAG: hirogotanda
CreateTimeTAG: 2013-03-02T07:36:14Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 3
FirstChildTAG: Distance refers to how far between two points. The way we measure can be different for EF I can use inches or centimeters or worse still make it more complex and say my unit of measurement is my foot but every time I go 5 steps forward I have to go 1/2 step back or whatever. So for median it is actual difference whereas for mean it is the square of the dierence and so on.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-02T08:33:03Z
FirstChildVoteTAG: 0
FirstChildTAG: I think you get a good answer for your question in lecture 3.4: the average is the center of gravity of the histogram and the median the center of the area. Both are centers and therefore have the least distance from the data. The mode is just the most common value, and hence has the least distance if you define distance as "different" (e.g. 0 if the same and 1 if different). The course handbook also deals with this in the beginning of Chapter 4, "However, the mean, the median, and the mode are "as close as possible" to all the data"... I hope this helps!
FirstChildUserIdTAG: 1262732
FirstChildUserNameTAG: Gahuga
FirstChildCreateTimeTAG: 2013-03-02T14:55:59Z
FirstChildVoteTAG: 2
FirstChildTAG: what you are aiming for, when you find any one of mean,median,or mode, is to find one *single number* that will tell you something about your data as a whole - what any datum is 'typically' like. But a hypothetical 'typical' element of the data might not necessarily actually correspond to any of the elements - like, if you are a sewer, you will known that nobody has the measurements of the pattern-maker's 'average' woman!
Everyone is different, and there are lots of ways to describe the extent of difference between a real woman and the hypothetical 'typical' woman the pattern-makers use. But some ways of describing the difference are more relevant and useful than others, depending on what aspect of the difference you want to understand.
In the same way, you can describe the difference between any particular real element and the 'typical' representation of an element of that particular set of data, in different ways. But whatever way you want to look at it, if a hypothetical element is to *be* typical of the set, it must necessarily be "as close as possible" to all the elements, or it doesn't do a good job of 'typifying' them. (The clothing pattern-makers do a pretty good job with their 'typical' woman - their patterns fit no-one, but aren't too bad a fit for anyone.)
The question is, what do you mean by 'not too bad' or 'close'? You can choose an appropriate measure for 'close', depending on what you want to know about the data.
For example, if you want find a 'typical' element such that half of the data set are less than it, and half are more than it, that is the 'median'. The median is "as close as possible to all the data" because it's in the middle - the data is spread evenly around it.
Another way of looking for a 'typifying number' that is "as close as possible" to every number in the data set, is to look for a number 'm' that minimises the the sum of the squared differences(x - m). That is, an 'm' that will make this function: f(m) = sum of the 'distance' between m and x, squared, for every x in the data set,
be minimal. If you used calculus to solve this, you would end up with the definition for what is called 'the mean': sum of total data/number of data
It's a *different* notion of 'closeness' - or 'distance' to that offered by the median.
The mode is simply the most commonly occurring element in the data. In that sense, mode also 'typifies' the data set into one single piece of information about it.
FirstChildUserIdTAG: 958344
FirstChildUserNameTAG: 314
FirstChildCreateTimeTAG: 2013-03-06T01:46:26Z
FirstChildVoteTAG: 2
IndexTAG: 1599
TitleTAG: please help me out problems in exercise 6
in exercise 6,problem 3 and 4 i got wrong,so can you please explain me,and in problem 3 I have a question.
In problem 3 we know that the average is same,but since for calculating SD,we measure deviation,so for last 5 values deviation is 0.And also since total number here is 30,so it increases and though we know SD wont be equal,but we say whether SD from List A & list B that since the deviations of those same 25 values are not known to us,so we can't say whether summing up of those deviations are greater than 1 or not.Since if the deviations sump up to >1 then if we divide by 25 and 30 and then sqrt,then for 25 values SD will be more,and if deviations <1,then if we divide by 25 and 30,then sqrt,then for 30 values SD will be higher,since when we divide a fraction it gets even more smaller,and then sqrt of a fraction makes the number much more bigger so here in this case sqrt of 30 values will be higher.
So what is wrong in this concept?Please help me out,I do think my problem 3 in exercise 6 is correct,please help me out,and problem 4 i couldn't solve help me out please...
UserIdTAG: 1177236
UserNameTAG: SOHAM1989
CreateTimeTAG: 2013-03-02T07:22:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: > in exercise 6,problem 3 and 4 i got wrong,so can you please explain me
This is an assessment. So explaining it to you is telling everyone else the answer. Remember that you agreed to an honour code. So no giving of answers.
I tried to follow you rather long post, but got lost in detail. You need to sit down, with the formulas, and look at what is happening. Make up some data, and find the mean and sd.
>Please help me out,I do think my problem 3 in exercise 6 is correct,
If you were marked wrong, you were wrong. Trying to puzzle out what you wrote, and you seem to have a few issues. Play around with denominators, and see what makes the answer bigger or smaller.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T07:30:51Z
FirstChildVoteTAG: 0
SecondChildTAG: As Susan says, you have a week to try and work out where you went wrong. Then next week when the results are posted and everyone has been graded we can discuss it all on the forum. You just have to wait a week.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-02T14:40:58Z
SecondChildVoteTAG: 0
SecondChildTAG: SOHAM - you are misunderstanding roots. Although the root of a decimal is bigger than the original, it is not bigger than the root of a larger decimal.
SecondChildUserIdTAG: 1003361
SecondChildUserNameTAG: steve_cooke
SecondChildCreateTimeTAG: 2013-03-02T21:43:53Z
SecondChildVoteTAG: 0
FirstChildTAG: The key to all these question is the concept of the "Bound" and we want the sharpest 'Bound" .
In the Ramayana , Laxmana draws a line as a perimeter around the house where Sita is living. and tells Sita if anyone crosses these lines other than her Husband(Rama) himself(Lakshmana who is Ram's brother) or Sita herself the person will be divinely singed (burnt).Only those 3 can enter the perimeter/boundary and be alive.Ravana comes to abduct her.He would be burnt if he crossed the line ie he can **go no more closer a distance than the line/boundary** to stay alive .Similarly Sita is safe **as long as the distance is no more than the boundary** So the chances of Ravana being burnt is no more than the distance from his home to the divine boundary .This can be miles away or a millimeter away but he stays alive as long as the distance is not less than the boundary (in relation to his home). Similarly the distance that determines Sita being abducted is not less than the boundary (ie she has to cross the boundary to be abducted- which she does and thus gets abducted and then the saga of the story starts !!)
This could give you an idea about how bounds work- the tail or tails should not be bigger than the bound !!(just as Ravana's distance from home cannot be more than his boundary and similarly Sita to remain free can never walk a distance more than the boundary)
Hope this helps or at least gives you an amusing respite on Sunday and an introduction to Indian Mythology ;)
http://en.wikipedia.org/wiki/Lakshmana_rekha
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-02T18:03:03Z
FirstChildVoteTAG: 2
SecondChildTAG: What a wonderful istory. Thanks
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-03-03T19:54:49Z
SecondChildVoteTAG: 0
SecondChildTAG: such an awesome example, thank you! i recall the times i used to read and re-read the book with indian myths.
SecondChildUserIdTAG: 1038359
SecondChildUserNameTAG: nonagenarian
SecondChildCreateTimeTAG: 2013-03-04T08:46:45Z
SecondChildVoteTAG: 0
SecondChildTAG: good analogy
SecondChildUserIdTAG: 1069242
SecondChildUserNameTAG: kdnyanesh
SecondChildCreateTimeTAG: 2013-03-05T15:18:54Z
SecondChildVoteTAG: 0
SecondChildTAG: now I want some chicken vindaloo...
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-03-06T15:25:34Z
SecondChildVoteTAG: 0
IndexTAG: 1600
TitleTAG: Recent subscription
Me and my statistics group have just suscribe to the course, Could we have dead line date extension?
UserIdTAG: 1339724
UserNameTAG: egzahoul
CreateTimeTAG: 2013-03-02T05:41:21Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: > Me and my statistics group have just suscribe to the course, Could we have dead line date extension?
No. Deadlines are just that, deadlines. And the answers have been posted for week 1. With many thousand enrolled in the course, individual circumstances cannot be catered to.
These sorts of general questions are answered in the general edX help files.
https://www.edx.org/help
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T05:44:27Z
FirstChildVoteTAG: 0
FirstChildTAG: No, for the reasons stated above. It is worth noting though that the two lowest Exercise Sets are dropped from the overall calculation so it would still be possible to score 100% for the course (assuming you get perfect marks later). The system will simply treat ES1 as 0% and count this as one of the lowest scores to be excluded. Bear in mind that the pass mark is only 35% so you have a fair bit of headroom - particularly if you have the advantage of an existing study group.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-02T20:21:15Z
FirstChildVoteTAG: 0
IndexTAG: 1601
TitleTAG: Just Register With edX, And Found Out This Course.
As above, can i join in this course since it started on 20 Feb 2013. How about the missed lessons and assignments for week 1, will i be able to take the tests? If yes, can i get extensions together for week 2 that ends on March 5 2013.
UserIdTAG: 1339369
UserNameTAG: rtph
CreateTimeTAG: 2013-03-02T05:29:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: >As above, can i join in this course since it started on 20 Feb 2013
Yes
> How about the missed lessons and assignments for week 1, will i be able to take the tests?
No.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T05:42:17Z
FirstChildVoteTAG: 0
SecondChildTAG: How much will the missed test for week 1 affect my completion of the course in terms of result?
SecondChildUserIdTAG: 1339369
SecondChildUserNameTAG: rtph
SecondChildCreateTimeTAG: 2013-03-02T10:55:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Check che ["Policies and requirements" page][1].
Among other interesting things, you'll also see this in the "Grading" section:
> Your two lowest Exercise Set scores will not be used in the calculation of your overall grade.
So, the missed test for week 1 won't affect your result **at all**, as long if you do well in the others ;)
[1]: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-02T13:35:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks :)
SecondChildUserIdTAG: 1339369
SecondChildUserNameTAG: rtph
SecondChildCreateTimeTAG: 2013-03-02T14:04:55Z
SecondChildVoteTAG: 0
IndexTAG: 1602
TitleTAG: Find the average of the distribution
Find the average of the distribution given below.
value percent of entries
42 20
55 10
58 40
59 10
69 20
to solve this problem the notes and stuff say the format for solving this problem should be as follows:
42*20+55*10+58*40+59*10+69*20=
At what point should I worry about the percents. Should I from the start have them converted to decimals or are they already in a format and I should just multiply and add them out? Is there more steps to figuring out this problem.
I have changed some of the numbers so it would not be a copy of the homework but maintain the same format.
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-02T04:53:09Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: How to find the mean: probability distribution or binomial distribution
binomial distribution, mean mode median 13 Comments
Finding the mean of a probability distribution is easy in probability and statistics. This how to will guide you through a few simple steps necessary to find the mean. You’ll often find these types of questions in textbook chapters on binomial probability distribution. The binomial distribution is just a simple trial where there are two outcomes: success or failure.
Sample question: “A grocery store has determined that in crates of tomatoes, 95% carry no rotten tomatoes, 2% carry one rotten tomato, 2% carry two rotten tomatoes, and 1% carry three rotten tomatoes. Find the mean number of rotten tomatoes the crates.”
Step 1: Convert all the percentages to decimal probabilities. For example:
95% = .95
2% = .02
2% = .02
1% = .01
Step 2: Construct a probability distribution table. (If you don’t know how to do this, see this article on constructing a probability distribution).)
Step 3: Multiply the values in each column. (In other words, multiply each value of X by each probability P(X).)
Referring to our probability distribution table:
0 × .95 = 0
1 × .02 = .02
2 × .02 = .04
3 × .01 = .03
Step 4: Add the results from step 3 together.
0 + .02 + .04 + .03 = .09 is the mean.
You’re done finding the mean for a probability distribution!
source:http://www.statisticshowto.com/articles/how-to-find-the-meanprobability-distribution-or-binomial-distribution/
gonna give it a try and see if it helps
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-02T04:58:08Z
FirstChildVoteTAG: 0
IndexTAG: 1603
TitleTAG: Attention to details
Most of my incorrect answers are the result of my lack of attention to details. We need to get use to use our brains more frequently. I enjoy the course so far ,thancs to all staff and teachers! :)
UserIdTAG: 1289210
UserNameTAG: ZHYRUNCHIK1
CreateTimeTAG: 2013-03-02T03:09:05Z
VoteTAG: 19
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: full agreement here, thanks a lot to the staff and the teachers, you are awesome =)!
FirstChildUserIdTAG: 1243466
FirstChildUserNameTAG: anoetos
FirstChildCreateTimeTAG: 2013-03-02T12:22:46Z
FirstChildVoteTAG: 1
FirstChildTAG: I am enjoying the course a lot. Thanks to the staff.
FirstChildUserIdTAG: 1177608
FirstChildUserNameTAG: Gayatris
FirstChildCreateTimeTAG: 2013-03-03T04:10:39Z
FirstChildVoteTAG: 0
FirstChildTAG: Hello everybody!!
I am also enjoying this course and the best part about it is the question framing.
They need full attention, otherwise misinterpreting them and leading to wrong answers. Here are some advices for my e-classmates hoping they'll prove useful.
1) Till now, we have not started the real course. It's only about few topics and concepts.
So far, it's the game of language, if you understand it means you have nailed the problem.
2) As discussed by other mates, we really need to focus on problem and blindly follow the instructions, believe me, if you go in this way it'll be damn easy to crack the questions.
Thanks to all.
FirstChildUserIdTAG: 961465
FirstChildUserNameTAG: gokulhada
FirstChildCreateTimeTAG: 2013-03-03T11:47:36Z
FirstChildVoteTAG: 3
FirstChildTAG: With no exaggeration is an awesome educational experience. I feel lucky I have the chance to live it even in my middle age.
Also I believe this is the start but also the core of the thing, and the foundations of statistics. Without this even if you know how to use the tools and the theory you will always miss the point.And the point is "why am I doing it, is this the right thing to do, what is really the dataset I am dealing with? No matter how fluently one will learn to do calculations and apply tests the target should be one ... to be a scientist not a calculator.
FirstChildUserIdTAG: 1239975
FirstChildUserNameTAG: Xenofon
FirstChildCreateTimeTAG: 2013-03-05T19:41:22Z
FirstChildVoteTAG: 0
IndexTAG: 1604
TitleTAG: PROBLEM 7 : 3.0 POINTS
I do not understand
UserIdTAG: 1268580
UserNameTAG: sharmi2005
CreateTimeTAG: 2013-03-02T02:06:52Z
VoteTAG: 2
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: be more precise please, what do you not understand?;)
FirstChildUserIdTAG: 1207892
FirstChildUserNameTAG: triplebee
FirstChildCreateTimeTAG: 2013-03-02T02:13:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Are they saying that each of the 12 members raised ~5,000 so that there is really a total of 60k? I'm assuming this must be the case.
Is there a time limit to this pledge or are they saying they pledged to raise 100k each and every month?
The same ambiguity suffers in Q8 as well. Are the other houses 100k or 5 million?
SecondChildUserIdTAG: 627857
SecondChildUserNameTAG: dt1
SecondChildCreateTimeTAG: 2013-03-02T02:37:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Forget it. I thought about it more and tricked my ownself on 7.
SecondChildUserIdTAG: 627857
SecondChildUserNameTAG: dt1
SecondChildCreateTimeTAG: 2013-03-02T02:42:41Z
SecondChildVoteTAG: 0
FirstChildTAG: You need to understand what the average *is*. Review the lectures until that's clear, then Problems 7 and 8 will be trivial.
Also, for problem 7, time is not relevant. You only care about the totals, and averages, and the number of people.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T14:18:06Z
FirstChildVoteTAG: 1
IndexTAG: 1605
TitleTAG: Median for the Histogram
So, the median will smeared out a bit because of the class interval, and if more of the boundary range of class intervals than 9(example of his class), say 1,000, the median will also be getting closer to the acculate 50%?
UserIdTAG: 1133472
UserNameTAG: hirogotanda
CreateTimeTAG: 2013-03-02T01:57:06Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 0
IndexTAG: 1606
TitleTAG: PROBLEM 6 : 3.0 POINTS
I do not understand this point, someone can explain
UserIdTAG: 1268580
UserNameTAG: sharmi2005
CreateTimeTAG: 2013-03-02T01:56:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 4
FirstChildTAG: You'll find that if you ask a specific question, people will be glad to help. If you ask a vague question, you likely won't get an answer.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-02T02:21:36Z
FirstChildVoteTAG: 0
SecondChildTAG: the relevant formula is the main topic of lecture 4.3.
SecondChildUserIdTAG: 1234879
SecondChildUserNameTAG: RyanMichael
SecondChildCreateTimeTAG: 2013-03-06T17:00:17Z
SecondChildVoteTAG: 0
FirstChildTAG: What do you mean by "point". The question? The fact that it is worth "3 points"?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T03:13:48Z
FirstChildVoteTAG: 0
FirstChildTAG: *Hint:* the first half of the Problem text doesn't really have much to do with the problem itself. It's just fluff(Google it if necessary).
Focus on what's important.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T16:14:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Check the course slides (or vide) for lecture 4.3 , the answer will jump right out
[4.3 Slides][1]
[1]: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec4.3.pdf
-Gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-03-03T20:41:25Z
FirstChildVoteTAG: 1
IndexTAG: 1607
TitleTAG: (staff) Balancing Work, Life and Classes in Tight Deadline Situations
Is there any way to request a small extension at hectic times, when a person's second part time job, apart from their 7 day a week job, comes up with a sudden tight deadline, that requires a few all-nighters to meet, and suddenly the time for working on one's online class has been eaten up?
Very excited for this course, and most pleased for the small extensions that have already been offered. It's a great class and I have learned so much already. I will be continuing on regardless of my mark going forward, as what's truly important is the learning opportunities.
UserIdTAG: 946980
UserNameTAG: ColleenR
CreateTimeTAG: 2013-03-02T00:40:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: You only need 35% to pass, so missing a few marks here and there is not going to make a huge difference.
>Is there any way to request a small extension at hectic times
There are over 47000 people doing this course. It is up to all of us to manage our time effectively, and accept that sometimes we might not make it.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T00:44:17Z
FirstChildVoteTAG: 2
FirstChildTAG: Can I submit late work?
FirstChildUserIdTAG: 1160985
FirstChildUserNameTAG: ggalisanao
FirstChildCreateTimeTAG: 2013-03-02T01:15:01Z
FirstChildVoteTAG: 0
SecondChildTAG: No
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-02T01:23:23Z
SecondChildVoteTAG: 0
FirstChildTAG: Your two lowest exercise scores are dropped when calculating your final score in the course. Therefore the flexibility you're asking for has already been built into the scoring scheme for the course.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-02T02:13:30Z
FirstChildVoteTAG: 1
IndexTAG: 1608
TitleTAG: You can help without revealing the answers
I've been randomly reading some posts and comments on specific exercises and I've found that, while some posters are really respectful to the Honour Code, others, in their eagerness to help their classmates, are revealing more than they should.
I know, helping others without telling the whole story is not an easy task in this course. But, in my opinion, revealing answers, or giving concrete procedures to produce almost automatically the answer, doesn't help. It precludes others (me included) from thinking deeply in order to solve our doubts or misunderstanding.
Take as a model the Prof. Ani's comments. She is kindly responding, giving hints that are really useful in the sense that they point to the right direction and force us to think about the matter in question thoroughly. I think this is the best and most helpful way to enhance our learning process.
UserIdTAG: 461686
UserNameTAG: atopos
CreateTimeTAG: 2013-03-02T00:28:18Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It is tricky. I'm sure most of us who have tried to help have given the game away more than once. I was a Community TA on pH207x and had a hell of a time trying to help without actually answering.
The issue here would be helped if students didn't immediately hit the forums demanding to know why they were wrong. Or accusing the staff of misleading them, because they know they were right!
Instead they should go over the lecture material again and try to figure out what the problem was. The answers will be revealed at the end of the week, so it's not as if they are never going to know what the problem was.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T00:41:36Z
FirstChildVoteTAG: 0
SecondChildTAG: I mostly agree. I refrain myself from giving advise if I'm not sure I can guide without revealing, or even, without misguiding anyone due to that hell, as you say, of keeping safe the secret and being at once helpful. You've seen, though, how appropriate Prof. Ani's comments are. So, there is a way, not easy to find, indeed.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-02T01:12:09Z
SecondChildVoteTAG: 0
SecondChildTAG: BTW, your comments are also a good model :)
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-02T01:17:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I am working on having the lectures memorized but I am fast losing my mind.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-02T04:44:32Z
SecondChildVoteTAG: 0
IndexTAG: 1609
TitleTAG: Problem 4.4 is a swindle
In this problem, the pronoun "these" has two possible referents (all the values in the chart, or just the three previously mentioned). It's usual in English in such cases that the referent is the most recent possibility, e.g., 103, 105, 108. Suggest exams be pre-screened by native English speaker for clarity.
UserIdTAG: 1284385
UserNameTAG: EdMeasure
CreateTimeTAG: 2013-03-01T23:24:11Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: Yes, you could read the question that way. But why give you a stem and leaf, then ask for the average of only 3 values?
A swindle? Hardly. Given only 35% is required to get through this course, dropping a mark or two is hardly a swindle. Let them sort out the problems in part 1 of the course, so the next two will run smoothly. That's if some of the participants manage to sort out GMT by then.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-01T23:30:13Z
FirstChildVoteTAG: 2
FirstChildTAG: I agree with Susan. Why would they present a whole stem and leaf plot and then just ask for an average of a single line? It doesn't make sense in the context. I think they were just trying to give you extra help by reminding you how the stem and leaf plot is set up. I don't think anyone is intentionally trying to trick you. In fact, I think so many people suggesting that the organizers are intentionally trying to "swindle" us or trick us is a bit of a lack of respect. Clearly a lot of people are putting a lot of time and effort into making this work (and for free). There's always room for improvement. Just suggesting that the wording was a bit confusing for you would have been enough, and a help to others who may be interpreting the question the same way you did (but without offending anyone's honesty).
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T23:38:57Z
FirstChildVoteTAG: 3
SecondChildTAG: I would bet that the part "The line 10 | 358 should be read as 103, 105, 108." was only added to help make it clear how a stem and leaf should be interpreted as a helpful reminder - likely in response to the many complaints in the week 1 assignment about ambiguity. Unfortunately it resulted in this, but it's rude to call it swindling, when all they're doing is trying to accommodate the diverse student audience taking this course. Apparently they can do no right...
SecondChildUserIdTAG: 1250448
SecondChildUserNameTAG: BHeaton
SecondChildCreateTimeTAG: 2013-03-02T18:16:27Z
SecondChildVoteTAG: 0
FirstChildTAG: Just to add to the chorus of people defending the question, if you read the question carefully it says:
"Yes, you can enter the list into your calculator and compute the average. But it will be a lot faster to do this exercise by inspection."
Why would the question ask you to visually inspect the average of one line of the plot? That's not really plausible. The prof wants you to visually interpret the entire plot to estimate the average score.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-02T02:38:55Z
FirstChildVoteTAG: 1
SecondChildTAG: Its said so because obviously there is some sense to estimate the average by inspection. Give it a try by inspection and still check it on the calculator.
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-02T13:39:11Z
SecondChildVoteTAG: 0
FirstChildTAG: It does not matter why or why not extra data might or might not be included. We are not being asked to second-guess the Professor's intent. The problem as currently worded is ambiguous, and many of us have gotten it wrong *not* because we didn't know what to do, or were unable to perform the math, but simply because we made the wrong guess as to what the Professor intended to say.
The lines in question read:
"The line 10 | 358 should be read as 103, 105, 108. Select the option that is closest to the average of these weights."
According to the norms of standard written English, "these weights" refers to the weights that have just been mentioned in the previous sentence.
Add to that the comment that is added by the professor at the end, that calculating the average "will be a lot faster to do this exercise by inspection," and the misperception is strongly reinforced.
FirstChildUserIdTAG: 911606
FirstChildUserNameTAG: ExpatKyle
FirstChildCreateTimeTAG: 2013-03-02T14:47:01Z
FirstChildVoteTAG: 0
SecondChildTAG: People really need to start using their common sense.
The "norms of standard written English" are completely irrelevant to comprehension of this problem, and any ambiguity in the text can be easily dismissed as long as you spend half a second thinking, instead of blindly throwing answers around.
Unless you're a complete moron. But I'd never accuse anyone I don't know of that, and I prefer to think that it's just a case of people shutting their brain off on the Internet for some reason.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-02T18:57:43Z
SecondChildVoteTAG: 0
IndexTAG: 1610
TitleTAG: Using Excel to help with Calculation
Find the SD of the list 30, 35, 25, 30, 32, 32, 36, 37, 35, 30.
You can use several formulas in Excel (or an equivalent spreadsheet program) to calculate the standard deviation.
To find the average of a group of numbers, you go to a new cell and type "=AVERAGE(range of cells with numbers you want to average)"
To find the difference between the average and the numbers, you can type "=(cell with number in it)-(cell with average)"
To copy it down so you don't have to type it over and over, you can copy and paste, or click on the little square that shows up in the bottom right corner of the cell when it is highlighted and drag that down the column to copy the formula. You need to use dollar signs in front of the letter and the number of the cell if you want to always use the same cell even when you copy it down the column. so A11 becomes dollar signAdollarsign11 (sorry it does a strange formatting thing when I just type it normally...).
To square a number, you go to a new cell and type "=(cell you want to square)^2"
This can also be copied down the column.
You'll need to use the AVERAGE function again, and then to find the square root, you type "=sqrt(cell with number you want the square root of)"
You can also use the functions STDEV (simple standard deviation, dividing by the total number of values minus 1) or STDEVP (the standard deviation as described in the textbook, dividing by the total number of values). BUT don't do this until after you've done the actual calculation all the way through! You can use it to check that you've done it correctly.
Hopefully that's helpful! Feel free to comment if you need more clarification.
UserIdTAG: 890941
UserNameTAG: sansom
CreateTimeTAG: 2013-03-01T23:10:33Z
VoteTAG: 12
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 5
FirstChildTAG: Hi
I haven't bothered to use Excel to help but a note of caution; I do seem to recall from work that Excel doesn't generate mode values properly and only ever returns the first value found in the list if there are multiple modes to a data set.
Do you think it's worth using excel for doing this though? The whole purpose of this course is to learn and using Excel as a short cut (except may be to check your answers before submission) seems like you might end up shortchanging yourself?
FirstChildUserIdTAG: 993192
FirstChildUserNameTAG: mitorious
FirstChildCreateTimeTAG: 2013-03-02T12:11:23Z
FirstChildVoteTAG: 1
SecondChildTAG: Excel can show multiple modes, but you must use the =MODE.MULT() formula and make it an array. It will not populate the other modes beyond the first within just one cell. This is using Excel 2012.
To your other point, I personally use Excel to do all my calculations in this course, but I don't use the pre-made formulas (i.e. SD) to do all the work in one step other than to assist in validation. For the mode example, a simple COUNTIF() formula for each unique value coupled with something like IF(value=MAX(range),"MAX","") would lead you to the same outcome - just in a lot of steps.
Whatever works best for you, Excel can be both a shortcut and a way of meticulously going over each step. I personally like that it can do both.
SecondChildUserIdTAG: 1250448
SecondChildUserNameTAG: BHeaton
SecondChildCreateTimeTAG: 2013-03-02T21:59:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Fair point, and thanks for the tip on generating multiple modes.
I quite agree that using Excel as a calculator is totally valid, it's probably a lot easier than using their, never sufficiently damned, windows calculator. Just worried people might short change themselves by using it's inbuilt methods!
Thanks again
SecondChildUserIdTAG: 993192
SecondChildUserNameTAG: mitorious
SecondChildCreateTimeTAG: 2013-03-03T12:37:51Z
SecondChildVoteTAG: 0
SecondChildTAG: It is also worthwhile to practice writing formulae in Excel. It is possibly easier for most people to make mistakes in Excel than by doing the work by hand.
As I mentioned in a different post, I'm doing these by hand for class in order to make sure I understand the method, but at some point I will be using Excel to examine datasets for my employer. Being able to run the calculations using step-by-step (multiple formula) and single formula methods in Excel may be important for some classmates' professional development.
SecondChildUserIdTAG: 1082561
SecondChildUserNameTAG: Streams
SecondChildCreateTimeTAG: 2013-03-05T21:32:44Z
SecondChildVoteTAG: 0
FirstChildTAG: I am not very good at arithmetic so I use excel to help with that.
I suppose I could try to be better at arithmetic but does not seem to be a skill I would use.
I agree using excel formulas does seem to be shortchanging my learning
FirstChildUserIdTAG: 471645
FirstChildUserNameTAG: FredFriedman
FirstChildCreateTimeTAG: 2013-03-02T16:53:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Understandable, but really, isn't Excel a bit overkill in this case?. Any standard calculator(physical or otherwise) will do the work, and keeps you practiced at doing averages and other simple intermediate calculations ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-02T19:01:44Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you. Just used Excel for a lot of the calculations and it helps to avoid the silly mistakes I make in my head.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-02T18:39:13Z
FirstChildVoteTAG: 1
SecondChildTAG: Same here. I think of it as a kind of scratch pad that helps me avoid silly manual calculation errors that I would likely make. But mentioned earlier, it's really most helpful if you use Excel to do the steps of the formula in order to learn the formula, rather than just relying on the built-in formulas.
SecondChildUserIdTAG: 1117422
SecondChildUserNameTAG: edutainment
SecondChildCreateTimeTAG: 2013-03-06T16:39:23Z
SecondChildVoteTAG: 0
FirstChildTAG: I think using Excel or some other program is fine (though I would never use Excel for anything seriously statistical)- after you have either done it by hand or reasoned the answer.
Just using the Excel inbuilt functions is not showing you how everything works. And it really helps to understand the process if you work through examples by hand.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T23:04:25Z
FirstChildVoteTAG: 1
SecondChildTAG: Totally agree. I just used Excel for the calculations but using my own workings and logic. I didn't use their automatic formulas. It wouldn't have helped me comprehend the exercise at all.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-03T01:04:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Ditto Susan
SecondChildUserIdTAG: 203329
SecondChildUserNameTAG: gabieee
SecondChildCreateTimeTAG: 2013-03-03T20:47:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Sansom, thank you so much for this tip with dollar sign! I use Excel a lot every day and always had problem when propagating a formula if I needed one cell to be fixed. Your method will help me a lot!
FirstChildUserIdTAG: 517550
FirstChildUserNameTAG: Ewa_G
FirstChildCreateTimeTAG: 2013-03-06T20:10:45Z
FirstChildVoteTAG: 0
IndexTAG: 1611
TitleTAG: Transcript Errata, chuckle
I had a bit of a laugh at the following in the transcript (6:22), "And the next step is to take that total pot of $10 and spit it evenly".
I like your humour professor ;).
UserIdTAG: 910962
UserNameTAG: SpirosP
CreateTimeTAG: 2013-03-01T22:29:16Z
VoteTAG: 2
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.2: The average: calculation and basic properties
NumberOfReplyTAG: 3
FirstChildTAG: I also was looking at it and laughed imagining a good dose of bright red tobacco juice being directed in an aiming contest in front of 4 pots ;)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-02T02:30:17Z
FirstChildVoteTAG: 1
FirstChildTAG: Ah, I should start reading those transcripts. Who knows how many other gems are hidden in there? :D
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T19:06:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Please submit all transcript errata that you find in the course wiki, here: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/Transcript-errata/
We appreciate your keen eyes and will fix errors as they get reported!
Thanks, Staff
SecondChildUserIdTAG: 469111
SecondChildUserNameTAG: romyr
SecondChildCreateTimeTAG: 2013-03-04T14:56:51Z
SecondChildVoteTAG: 0
FirstChildTAG: Please submit all transcript errata that you find in the course wiki, here: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/Transcript-errata/ We appreciate your keen eyes and will fix errors as they get reported!
Thanks, Staff
FirstChildUserIdTAG: 469111
FirstChildUserNameTAG: romyr
FirstChildCreateTimeTAG: 2013-03-04T14:57:46Z
FirstChildVoteTAG: 0
IndexTAG: 1612
TitleTAG: so?
so I know im not getting any points, no problem. But how do I get the arrow to take me to the next section?
UserIdTAG: 831928
UserNameTAG: WhosYourDaddy
CreateTimeTAG: 2013-03-01T21:54:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Look at the left-hand menu bar. Click on the next section. Voila.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-01T21:57:35Z
FirstChildVoteTAG: 0
IndexTAG: 1613
TitleTAG: Problem 1 clarification
In this problem we are told that "By mistake, the largest commute distance is recorded as 165 miles instead of 16.5 miles." but not that this value of 16.5 remains the largest commute distance, which is assumed to produce the correct answer. Without seeing the actual data, or specifying that 16.5 remains the largest commute distance after the correction, there's no way to conclude that "Increasing the largest entry in the list does not change the median because it does not affect the lower half of the dataset."
UserIdTAG: 937396
UserNameTAG: m2foster
CreateTimeTAG: 2013-03-01T21:13:03Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 5
FirstChildTAG: > A company records the commute distances (distance traveled from home to work) of all of its 37 employees. By mistake, the largest commute distance is recorded as 165 miles instead of 16.5 miles. By how many miles does this mistake change the median of the commute distances?
You are told the largest value is 165, when it should have been 16.5. Does this affect the median?
> specifying that 16.5 remains the largest commute distance after the correction
Where does it say there was a correction?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-01T22:00:42Z
FirstChildVoteTAG: 0
SecondChildTAG: the median remains same ...
SecondChildUserIdTAG: 65259
SecondChildUserNameTAG: MujeebQuli
SecondChildCreateTimeTAG: 2013-03-05T07:59:51Z
SecondChildVoteTAG: 0
FirstChildTAG: > "By mistake, the largest commute distance is recorded as 165 miles
> instead of 16.5 miles."
To me this means that when they were recording the largest value, they mistakenly recorded it as 165 instead of 16.5. It was always the largest value. They just made a mistake when they recorded it.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T23:13:49Z
FirstChildVoteTAG: 5
SecondChildTAG: This is how I read it as well.
SecondChildUserIdTAG: 868031
SecondChildUserNameTAG: CaliforniaViv
SecondChildCreateTimeTAG: 2013-03-02T00:34:57Z
SecondChildVoteTAG: 0
FirstChildTAG: the median is the value at least as large as at least half the data points.
so if the largest value changes from 16.5 miles to 165 miles ( or 1.65 billion miles for that matter) it does not affect the median that only counts to the 19th data point ( 37 * 0.5 rounded to upper = 19 ) and notes this value.
FirstChildUserIdTAG: 1243466
FirstChildUserNameTAG: anoetos
FirstChildCreateTimeTAG: 2013-03-02T11:49:59Z
FirstChildVoteTAG: 0
FirstChildTAG: Actually this problem is explained later, in video LECTURE 3.4 (between 3:00 and 4:00).
FirstChildUserIdTAG: 1141933
FirstChildUserNameTAG: zsombor_laszlo
FirstChildCreateTimeTAG: 2013-03-03T15:20:39Z
FirstChildVoteTAG: 0
FirstChildTAG: There is not enough information to answer problem 1 because we don't know if 16.5 is below, at, or above the median.
FirstChildUserIdTAG: 341539
FirstChildUserNameTAG: Eliah
FirstChildCreateTimeTAG: 2013-03-04T08:00:15Z
FirstChildVoteTAG: 0
IndexTAG: 1614
TitleTAG: P4 is a MISTAKE
If the line 10 should be read as 103, 105, 108,
the average is approximately 105 (option a)
But if the line 10 is seen as 358,
the average is about 120 (option b)
The question is ambiguous!
I demand is enabled a second option for cheq!!!
UserIdTAG: 314985
UserNameTAG: Ivonnep_g
CreateTimeTAG: 2013-03-01T21:01:37Z
VoteTAG: 4
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 6
FirstChildTAG: How can line ten be seen as 358? This is a leaf and stem diagram and can only be seen as 103, 105, and 108. IF read correctly, then the average is NOT 105 as you indicated, unless you're just looking at the line "10" and picking the value in the middle. I refer you to http://en.wikipedia.org/wiki/Stem_and_leaf_diagram for an explanation of how to construct, read, and use a stem and leaf diagram.
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-03-01T21:37:53Z
FirstChildVoteTAG: 1
SecondChildTAG: The question asks for the average of all of the weights in the stem and leaf plot. It does *not* ask for the average of only the weights listed in line 10. I think that's your misunderstanding.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-01T21:47:10Z
SecondChildVoteTAG: 0
SecondChildTAG: (Sorry, I should have posted that as a reply to the original question.)
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-01T21:49:16Z
SecondChildVoteTAG: 0
SecondChildTAG: ... line 10 means 103, 105, 108 alright... the question can be interpreted in two ways: 1) in its immediate context (due to the statement/explanation about line 10), one can interpret the question as asking for the average of the 3 observations 103, 105, 108 then the average is 105; and 2) the other is that one can take the whole stem-and-leaf plot and the closest average would be 125... i took the first point of view (the statement about line 10 made me interpret the question to get the average of 103, 105 and 108 and answered 105 - and, had my answer marked X. That statement about line 10 created the confusion - if one deletes that statement it could be READILY INTERPRETED as requiring the average of the whole data set indicated in the stem-and-leaf plot.... many of us are not native-born english speakers or may be just plain misunderstanding of the question. A statement stating or asking for the average of the whole data set in the stem-and-leaf plot could have eliminated any other interpretation). Can we make the questions a lot clearer or straight forward next time?
SecondChildUserIdTAG: 1056161
SecondChildUserNameTAG: aseanmaverick
SecondChildCreateTimeTAG: 2013-03-02T04:56:13Z
SecondChildVoteTAG: 0
SecondChildTAG: ... can we request the staff to reconsider and allow 2 submissions for Problem 4?
SecondChildUserIdTAG: 1056161
SecondChildUserNameTAG: aseanmaverick
SecondChildCreateTimeTAG: 2013-03-02T05:06:38Z
SecondChildVoteTAG: 0
SecondChildTAG: i do agree with the ambiguity of this question...It has nothing to do with not being a non-native born english speaker.Anyone could have misread the question. i've misinterpreted the question as asking for the average of line 10 ONLY!!!
SecondChildUserIdTAG: 611684
SecondChildUserNameTAG: reneeralte
SecondChildCreateTimeTAG: 2013-03-02T11:51:36Z
SecondChildVoteTAG: 0
SecondChildTAG: >>>The question asks for the average of all of the weights in the stem and leaf plot. It does not ask for the average of only the weights listed in line 10. I think that's your misunderstanding.
Nonsense.
The question asks for the average of "these weights," and in standard English "these weights" refers to whatever was just mentioned.
The question is ambiguous. Suggesting that it isn't just shows you don't understand English very well. I'm a professional technical writer and a native English speaker: if i allowed mistakes like this to get past me, i'd get fired. So no: this has nothing to do with whether or not someone is a native speaker of English.
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-02T14:50:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Common. Sense.
Don't leave bed without it.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-02T19:10:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I think it was clear. Very clever in fact. Made you think about how the averages are influenced by individual values.
SecondChildUserIdTAG: 341206
SecondChildUserNameTAG: laxmishac
SecondChildCreateTimeTAG: 2013-03-03T05:57:31Z
SecondChildVoteTAG: 0
SecondChildTAG: "Common sense always speaks too late. Common sense is the guy who tells you you ought to have had your brakes relined last week before you smashed a front end this week. Common sense is the Monday morning quarterback who could have won the ball game if he had been on the team. But he never is. He's high up in the stands with a flask on his hip. Common sense is the little man in a grey suit who never makes a mistake in addition. But it's always somebody else's money he's adding up."
Philip Marlowe
Marlowe was thinking of you, Klionheart.
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T13:47:54Z
SecondChildVoteTAG: 0
SecondChildTAG: "There is nothing more uncommon than common sense."
Thomas Chalmers, (att'd)
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T13:48:30Z
SecondChildVoteTAG: 0
SecondChildTAG: "Common sense is nothing more than a deposit of prejudices laid down by the mind before you reach eighteen."
Albert Einstein (att'd)
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T13:48:56Z
SecondChildVoteTAG: 0
SecondChildTAG: "There are people who are so full of common sense that they haven't the slightest cranny left for their own sense."
Miguel de Unamuno
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T13:49:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I rest my case....
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T13:49:45Z
SecondChildVoteTAG: 0
FirstChildTAG: The question asks for the average of all of the weights in the stem and leaf plot. It does not ask for the average of only the weights listed in line 10. I think that's your misunderstanding.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-01T21:50:19Z
FirstChildVoteTAG: 7
SecondChildTAG: ... the explanation about how to read line 10 was not necessary... it only confuses people (again, some may interpret the question in the immediate context following that statement on line 10).
SecondChildUserIdTAG: 1056161
SecondChildUserNameTAG: aseanmaverick
SecondChildCreateTimeTAG: 2013-03-02T05:48:31Z
SecondChildVoteTAG: 0
SecondChildTAG: I totally second that! I was almost going to put 105 down myself. That sentence really confused me!
SecondChildUserIdTAG: 1265802
SecondChildUserNameTAG: GMORRIS010
SecondChildCreateTimeTAG: 2013-03-03T20:57:04Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with them, the explanation only makes confusion, it is not fare.
SecondChildUserIdTAG: 654914
SecondChildUserNameTAG: Fenixhc
SecondChildCreateTimeTAG: 2013-03-04T06:26:17Z
SecondChildVoteTAG: 0
SecondChildTAG: I just gambled.
I knew it was asking for one of the two, and happened to get the wrong one. It is poorly worded IMO.
Anyway, shouldn't really give away the answers in this part. Could still raise the issue without giving the answer away.
SecondChildUserIdTAG: 1027030
SecondChildUserNameTAG: thesandman
SecondChildCreateTimeTAG: 2013-03-05T03:24:20Z
SecondChildVoteTAG: 0
FirstChildTAG: > I demand is enabled a second option for cheq!!!
Perhaps if you approached this with a more reasoned manner you might be taken seriously. Currently you sound like an angry 4-year-old.
Why would you be given a stem and leaf plot, then only asked about one line?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T05:53:54Z
FirstChildVoteTAG: 4
SecondChildTAG: It's not our job to second-guess what the professor means, Susan. The question is poorly worded. If you can't see that, then you need to either stop criticizing those of us who are frustrated by the poor wording, or go start studying English rather than Statistics.
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-02T14:51:50Z
SecondChildVoteTAG: 0
SecondChildTAG: But you could have always asked for clarification before submitting, noting that you understand that there is ambiguity in the wording. Frustration averted. Consider using this as a learning experience for how to deal with ambiguity in the future - it will not go away.
SecondChildUserIdTAG: 1250448
SecondChildUserNameTAG: BHeaton
SecondChildCreateTimeTAG: 2013-03-02T17:50:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Totally agree with BHeaton. (Although sometimes people read things one way and it doesn't even occur to them that another way exists until someone else points it out.)
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-02T18:35:33Z
SecondChildVoteTAG: 0
SecondChildTAG: A) We are not tasked with second-guessing what the professor means. I answered the question according to *what* *was* *asked.* I should not be penalized because what the Professor asked for was different from the answer the Professor wanted to elicit.
B) It's a very simple thing to make a question like this unambiguous, and in fact THAT IS THE JOB OF THE STAFF AND THE PROFESSOR. I know because i've been a language teacher for 20 years, and i have been a technical writer, as well, for 10. In *both* of those jobs, i would be rightfully criticized for allowing sloppy work like this to get past me. As a teacher, i would be contrite that i caused my students confusion; as a writer, i would be contrite that i had not done my job properly. All of these "use common sense" answers are simply meaningless posts by immature students looking to curry favor at the expense of their fellow students - and frankly, if any of y'all had come out making such noisome defenses of a mistake i made in my class, i'd pointedly humiliate each one of you for speaking so presumptuously on my behalf.
At the very least, the question should be struck from the grade-sheet. When all is said and done, with 40,000 students it is doubtless that hundreds - or, more probably, thousands - were marked wrong on this question *not* because they didn't understand the mathematical concepts, *not* because they did the math wrong, *not* because they did not understand what was being asked, but rather because they gave the answer to the question that was asked rather than firing up their mind-reading skills to suss out the alternative answer that the professor actually intended.
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-03T05:18:43Z
SecondChildVoteTAG: 0
FirstChildTAG: An angry 4 year old??? What does this mean? How can this be the opposite of someone with reasoned manner? What about angry adults? Do they act in a better manner when angry? We should all treat children with a bit more respect, starting from the way we talk about them.
FirstChildUserIdTAG: 197730
FirstChildUserNameTAG: Claudia2505
FirstChildCreateTimeTAG: 2013-03-02T21:54:04Z
FirstChildVoteTAG: 3
FirstChildTAG: Everyone should be able to read a stem and leaf plot by now. But if it isn't stated how to read it, people would complain about that (even with the explanation some people are complaining!!!!). It should never cross one's mind that they would care to plot over 30 data for us to use only three!
FirstChildUserIdTAG: 1250862
FirstChildUserNameTAG: KarlaGeo
FirstChildCreateTimeTAG: 2013-03-03T23:15:21Z
FirstChildVoteTAG: 0
SecondChildTAG: It did cross my mind.
Perhaps it's because i read English better than you do?
Perhaps it's because i have mis-read other questions (which, incidentally, were ALSO ambiguously written) and felt like it was very important to follow the teacher's instructions EXACTLY as they are written?
Why should it "never" cross one's mind that we are given more data than is used to arrive at the answer? Are you aware that this is a statistics course, and we are given questions which ignore MOST of the presented data ALL the time?
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-03-06T13:46:01Z
SecondChildVoteTAG: 0
FirstChildTAG: The concern is NOT how to read a stem and leaf plot. It is NOT how to calculate the correct answer. The problem is the incorrect use of the English language. The pronoun "these" refers to the noun directly proceeding it.
As far as using common sense, my understanding was that we were to read the questions carefully and answer accordingly.
I'm disappointed that it caused me to miss a perfect score, but I don't think in the big scheme of things it's worth all this aggravation.
FirstChildUserIdTAG: 1308402
FirstChildUserNameTAG: Jolane
FirstChildCreateTimeTAG: 2013-03-05T19:24:10Z
FirstChildVoteTAG: 1
IndexTAG: 1615
TitleTAG: Answer formatting on Problem 6
The format of that question is silly. If the correct answer is "more than 35" or "more than 45" obviously "more than 25" is also correct. But why punish people for getting the right answer, but not checking an extra unnecessary box?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-01T20:57:11Z
VoteTAG: 13
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 5
FirstChildTAG: This question has already been asked on the forum. Please avoid posting duplicate questions.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-01T21:52:29Z
FirstChildVoteTAG: 7
FirstChildTAG: Because maybe they are seeing if you understand what all those options mean.
> The format of that question is silly
The usual comment from some who make mistakes. Always someone else's fault.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-01T22:02:48Z
FirstChildVoteTAG: 6
SecondChildTAG: It wasnt asked for the best answer! ;)
SecondChildUserIdTAG: 631206
SecondChildUserNameTAG: Rysy58
SecondChildCreateTimeTAG: 2013-03-03T12:16:46Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh, SusanAust, welcome back.
I see that you love your statistics courses.
SecondChildUserIdTAG: 418267
SecondChildUserNameTAG: Stefanus
SecondChildCreateTimeTAG: 2013-03-04T22:20:29Z
SecondChildVoteTAG: 0
FirstChildTAG: It's the same thing for many of the questions. You have to read carefully what is exactly asked.
FirstChildUserIdTAG: 1152666
FirstChildUserNameTAG: brentsen
FirstChildCreateTimeTAG: 2013-03-01T22:18:07Z
FirstChildVoteTAG: 4
FirstChildTAG: I think this question is related to concepts that were specifically stressed in the lectures. (See Lecture 3.5, from minute 7:54 onward) So they must be asking it to check whether we have comprehended it correctly. It probably has some very good reason that we will see in future lectures.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T23:29:19Z
FirstChildVoteTAG: 2
FirstChildTAG: It is not silly- please note that the central concept in Markov's inequality is -**It is a bound** .
One of the important thing in learning (and trust me I have been a Teacher for over 25 years in various capacities and am a student here) is that it is very important to consider the fact that when we are marked wrong - then there is an overwhelming possibility that we are indeed wrong (except if there is a glitch) and it is better to consider and clarify with the teacher why you are marked wrong rather than being dismissive of the question. Of course there is always Markov and Chebychev to consider and I used the term overwhelming and not a absolute because there is a small chance but note that it is many standard deviations away ;) Those are often 'glitches" and rarely systematic.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-02T02:27:05Z
FirstChildVoteTAG: 8
IndexTAG: 1616
TitleTAG: To Prasannaimha
I like your posts. Always positive and helpful. Thank you.
UserIdTAG: 310963
UserNameTAG: TwinOtter
CreateTimeTAG: 2013-03-01T20:52:57Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Your welcome.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-02T02:21:15Z
FirstChildVoteTAG: 1
FirstChildTAG: I second Twin Otter's comment. Really appreciate Prasannasimha's input.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-02T18:38:10Z
FirstChildVoteTAG: 1
SecondChildTAG: I do hope it helps someone.The best gem for a Teacher is when his/her students can spread knowledge around.With a great Teacher around teaching us, we should interact to make our group achieve the highest possible score within the limits of the Honor code.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T19:12:50Z
SecondChildVoteTAG: 0
IndexTAG: 1617
TitleTAG: Miss the date
Hi,
is there any possibility for getting some points from this test if I miss the date?
Thanks.
UserIdTAG: 522387
UserNameTAG: GP_Tomas
CreateTimeTAG: 2013-03-01T20:29:06Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Nope
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-01T20:43:06Z
FirstChildVoteTAG: 1
IndexTAG: 1618
TitleTAG: Mistake in the video
Just at 5:30, she says "qualitative ordinal". The captions read "quantitative ordinal".
To clarify, the speech is correct: it is qualitative ordinal.
UserIdTAG: 150317
UserNameTAG: Franciozzy
CreateTimeTAG: 2013-03-01T20:10:30Z
VoteTAG: 2
CoursewareTAG: Section 1: Introduction / Lec 1.2. Variables: terminology
NumberOfReplyTAG: 1
FirstChildTAG: Please submit all transcript errata that you find in the course wiki, here: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/Transcript-errata/
We appreciate your keen eyes and will fix errors as they get reported.
Thanks,
Staff
FirstChildUserIdTAG: 469111
FirstChildUserNameTAG: romyr
FirstChildCreateTimeTAG: 2013-03-04T14:55:21Z
FirstChildVoteTAG: 0
IndexTAG: 1619
TitleTAG: Exr set 2 problem 6 - histogram charts
Hi
The explanation is that B is not a histogram, since it has percent on the vertical axis, as opposed to density.
I saw that the statistical software package called STATA under their Histogram do accept several representations **of histogram charts**, such that the Y axis can be either: Density, Fraction, Frequency or Percent.
http://www.youtube.com/watch?v=nPqNZVToGx8&feature=plcp
is this wrong? and those are not histograms?
UserIdTAG: 1240022
UserNameTAG: Moshiko
CreateTimeTAG: 2013-03-01T20:07:38Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: You can have percentages. But the histogram is not drawn correctly (nor is the correct one).
The *area* of the bar should equal the percentage, not the height. The height should be percent per x-unit.
This histogram has combined the 0-9 and 9-12 groups into one group of 0-9, and all other groups have dropped into the next lowest category. Strange.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-01T21:46:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Susan
If the area has to be the total percentage (100%) than the height is indeed percentage per unit, or density. But my question is addressing the fact that it is costumed to use the height as Percentage and still be called an Histogram as i saw in STATA or other tools such as excel.
As i understand, the definition of this course is different than all other tools that present histograms.
In the question the chart might be wrong but it was explained that the reason for option B not to be correct is only due to the fact that it used percentage and not density (percentage per unit)
Best
Moshiko
SecondChildUserIdTAG: 1240022
SecondChildUserNameTAG: Moshiko
SecondChildCreateTimeTAG: 2013-03-04T09:20:21Z
SecondChildVoteTAG: 0
IndexTAG: 1620
TitleTAG: Markov's Inequality
What does the term "inequality" mean in the context of statistics (as in Markov's Inequality)? Just curious because the term seems to be commonly used, but I don't think it was defined in the lecture. Many thanks in advance.
UserIdTAG: 919673
UserNameTAG: ldh
CreateTimeTAG: 2013-03-01T19:54:11Z
VoteTAG: 1
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3.5: Markov’s inequality
NumberOfReplyTAG: 3
FirstChildTAG: The distrubution you use it on is inequal, because you start at 0 and the than there is a peak, and a long tail. the distrubution is nog evenly devided around the avarage and so it is inequal. I hope it helps.
FirstChildUserIdTAG: 804886
FirstChildUserNameTAG: marlasinger1470
FirstChildCreateTimeTAG: 2013-03-01T20:29:02Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-01T23:40:39Z
SecondChildVoteTAG: 0
FirstChildTAG: I think inequality means its a bound, it represents a range of values, it has no exact value as compared to equal which has an exact value. For instance if you say X> 3 (> is an inequality sign meaning 'greater than') means the values of x can be 4, 5, 6 and so on. But X= 3 means the value of X is exactly 3. I believe thats what the Professor meant in Markov's inequality. The inequality represented a region that is at most 1/k that is a region that is no more than 1/k.
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-03-01T20:59:08Z
FirstChildVoteTAG: 4
SecondChildTAG: This would be the correct response to the question.
SecondChildUserIdTAG: 840238
SecondChildUserNameTAG: bchilders
SecondChildCreateTimeTAG: 2013-03-02T23:13:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Inequlities refers to a relation between two equations which have different solutions(ie they give different answers.For eg <,> and not equal to
This may help
http://en.wikipedia.org/wiki/Inequality_%28mathematics%29
Think of a see saw -
When balanced horizontally the state is an "equal' but when not at the horizontal they are all inequalities.The lowest a see saw can go to is a "bound" so a person can go no lower than (or higher than at the other end) the bound set up by a see saw is set during its construction(or else people would be catapulted over !!) by the very design of the see saw.ie you define the boundary conditions for your see saw which has an inequality
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T02:26:03Z
FirstChildVoteTAG: 1
IndexTAG: 1621
TitleTAG: Attn Professor - Corrigendum for Problem 4 (Exercise Set 5)?
The Problem 4 is written as "Refer again to the distribution in Exercise 3". It should read as "Refer again to the distribution in Problem 3 (Exercise Set 5). Many people are searching for the problem in Exercise Set 3. Please confirm if this interpretation is correct.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-01T19:16:39Z
VoteTAG: 6
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 2
FirstChildTAG: It really shouldn't be such a drama, as the question again talks about mothers.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-01T21:51:17Z
FirstChildVoteTAG: 1
SecondChildTAG: I think that you are missing the point.It may be very obvious to some but there are obviously a lot of people who are confused (and whether one likes it or not the referred distribution is indeed **not** Exercise 3 !! .It is better to have a correction compared to a 1000 enquiries of the same type! (And at the end of the day it is indeed an error)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T02:19:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Look, the *point* is that we are supposed to be people with an IQ over 10. No matter what the text says, you, as a human being who's supposed to be more intelligent than a pasturing cow, should easily realize that if a problem is part of an *exercise set*, then it is an **exercise**.
Thus, when you see a reference to **Exercise 3** within *Exercise set 5*, your first thought *should* be to the third exercise of the fifth set, and not to a completely unrelated(it's even a different week, FFS) exercise set.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-02T11:47:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Ad hominem attacks are not acceptable--even when they are implied. I suggest we ignore comments we think are redundant or illegitimate.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-02T18:21:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Klionheart- I think you are going overboard- the discussion group is to help people without revealing answers.If there are people having confusion- help if you can but being arrogant does not cut it and shows you in a poor light. There are people who have different comprehension levels especially when English is not their first language and when they read English with a different set of mannerisms that are not the same in other countries so Ad hominem attacks etc are not really beneficial.I will not discuss this more but remember a bit of compassion to other learners does no one harm and bullying others doesn't help either.You may have not noticed but in the previous set of exercises attention to graphs and drawing not in the same exercise set (for eg in other exercises or the text book etc etc) has been done) so people can get confused.I really think that you should retract your statements.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T18:40:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Even if it's confusing, no mention of "mothers" is made in Exercise Set 3. So of the two possibilities, that the reference is in Exercise Set 3, or in #3 of this set, the answer is easily identified with a few seconds of effort. Why ask others to solve such a simple problem for you? It's good to think for oneself, it builds critical thinking skills. So really, this 'challenge' is just another learning experience, to make us all better people. And the staff can be clearer next time too, so they have also learned. Yay for learning!
SecondChildUserIdTAG: 1250448
SecondChildUserNameTAG: BHeaton
SecondChildCreateTimeTAG: 2013-03-02T19:04:20Z
SecondChildVoteTAG: 0
SecondChildTAG: One thing is that if there is no ambiguity people will not get misdirected and keep asking questions on the discussion board.Another thing is that for some people videos are not loading etc etc so some people have actually thought they have missed out portions or are not able to see some parts of the site.So that element of doubt remains and so they post repeatedly. That is why I mentioned it is better to have a clarification or a corrigendum before multiple posts are made.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T19:17:19Z
SecondChildVoteTAG: 0
SecondChildTAG: fair enough. I suppose I do get a bit riled up when I see people who fail to use common sense when in doubt.
Just to clarify, I'm not "attacking" anyone, and I don't get how my post comes along as "bullying", but it's true that there are different mannerisms in the world, so I apologize if you got that impression.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T12:21:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Klionheart, I am regularly accused of being mean and nasty. All it takes with some, is disagreeing. With anything. Or telling someone to go read the Course Info. Or eventually losing patience with the 100th post about something.
But, as you say there are different mannerisms. Some posts that are put through a translator first are often very rude because of the translation. Then there those of the opinion that "if you have nothing nice to say, say nothing".
Having enjoyed the language of Paul Keating's Prime Ministership, interesting turns of phrase are water off a duck's back to me.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-03T20:55:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes indeed Susan but it also doesn't hurt to be civil ;) (And klion has clarified so it should be left at that) - correct people if you want, remind them about the courseware and to follow it and not post the same post a zillion times , remonstrate if they break the honor code- but would it be appropriate to call people as having the mental ability of a pasturing cow ? In what language is it civil- even a cow would get offended and would you like it if I said the same to you for not understanding that !! :) There is a line and it was crossed and yes indeed there was a factual error. Minor may be, traceable may be but still had led to confusion and already the tide of questions were pouring in and if a request for that to be corrected was considered offensive then God and the pasturing cows save us.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-04T02:58:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Mmm, I just realized - I may have picked the wrong animal for my figure of speech - cows being important parts of many cultures. But again, it *was* a figure of speech - I wasn't *accusing* anyone of being dumb, especially not Prasannasimha.
I'm still convinced, though, that if you are doing an *Exercise* Set, it should easily follow that the "Problems" inside it can also be referred as "Exercises", just as in a Data set, its values can be referred as "Data".
It's part of the "good comprehension of English" that is a prerequisite for the course, and so I fail to see how the text in problem 4 can be read wrong. Maybe it's just me xD
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-04T11:28:05Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks for the correction.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-02T18:40:26Z
FirstChildVoteTAG: 0
IndexTAG: 1622
TitleTAG: Please follow the same answer guidelines as in Exercise 1.
Hello,
I Solved the 2 problem correctly but information "Please follow the same answer guidelines as in Exercise 1" enter me in error.
UserIdTAG: 734057
UserNameTAG: cieursz
CreateTimeTAG: 2013-03-01T18:36:49Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 1
FirstChildTAG: The guidelines in Exercise 1 refer to how to enter your answer - the way you enter the number, and not putting measurement words into the answer (i.e. do not enter miles after the number).
FirstChildUserIdTAG: 868031
FirstChildUserNameTAG: CaliforniaViv
FirstChildCreateTimeTAG: 2013-03-02T00:37:38Z
FirstChildVoteTAG: 1
SecondChildTAG: Even if one does not enter the word 'miles' but simply inserts a minus sign implying that there is a reduction, it shows it as the wrong answer, until one removes the minus sign!
So ATTENTION course -staff. The answer ought to be in the negative as per the instructions given.
SecondChildUserIdTAG: 813459
SecondChildUserNameTAG: DrPuja
SecondChildCreateTimeTAG: 2013-03-02T09:32:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry, my bad! I just re-read the question. The answer is CORRECT.
SecondChildUserIdTAG: 813459
SecondChildUserNameTAG: DrPuja
SecondChildCreateTimeTAG: 2013-03-02T09:37:19Z
SecondChildVoteTAG: 0
IndexTAG: 1623
TitleTAG: Despite of easy topic I am finding these classes a bit tough
I have very less time to go through due to a busy schedule, and in one go I find it difficult to grasp the whole of it. its really good and I am learning a lot, but due I still find this tough ... how to cope up.
UserIdTAG: 336475
UserNameTAG: ShivaniPurnima
CreateTimeTAG: 2013-03-01T18:17:33Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 1
FirstChildTAG: Download the lectures on to your smartphone and hear it during travel etc.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-01T18:43:06Z
FirstChildVoteTAG: 0
IndexTAG: 1624
TitleTAG: Prof A. Awesome Set...advice for anyone strugling
This really tested me, i really did need to take the time and map everything out.For anyone having problems, you have to watch all the vids, and read the text.
That being said, it was tough, and I love a challenge...100% BOOM
UserIdTAG: 7545
UserNameTAG: jasontimothyjones
CreateTimeTAG: 2013-03-01T18:14:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I made the mistake in the first two sets in week one of not noticing there were more than one video. Gads! Good thing the lowest two are dropped! Yes, I concur, very challenging!
FirstChildUserIdTAG: 1218219
FirstChildUserNameTAG: dlegg
FirstChildCreateTimeTAG: 2013-03-01T18:27:59Z
FirstChildVoteTAG: 0
SecondChildTAG: I made that mistake too.
SecondChildUserIdTAG: 510141
SecondChildUserNameTAG: rsec2012
SecondChildCreateTimeTAG: 2013-03-01T20:42:10Z
SecondChildVoteTAG: 0
IndexTAG: 1625
TitleTAG: Exercise 6: PROBLEM 1
A distribution of weights is symmetric about its median. The lower quartile of the weights is 90 pounds and the median is 120 pounds. Find the interquartile range of the distribution.
**Question:** Is there a bug? I aint getting the correct answer. It says symmetrical, so I get the answer, but does not work.
UserIdTAG: 415366
UserNameTAG: Malik12
CreateTimeTAG: 2013-03-01T17:03:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: Consider the question, what is the distance between the median and the third quartile? If you answer this question and apply the definition of the IR, you inmediately get the answer and will discover the right answer
FirstChildUserIdTAG: 40403
FirstChildUserNameTAG: CHALE
FirstChildCreateTimeTAG: 2013-03-01T17:24:45Z
FirstChildVoteTAG: 1
SecondChildTAG: I spread my hands out equally.Look Ma this hand is here(my right) so well - where is your left ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T03:39:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Revisit the box plot diagram in Lecture 4.1, it will be of help in solving the question.
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-03-01T19:14:49Z
FirstChildVoteTAG: 1
IndexTAG: 1626
TitleTAG: any help on problem 2, am lost
any help on problem 2, am lost!
UserIdTAG: 820147
UserNameTAG: frimpongmaxwellkwadwo
CreateTimeTAG: 2013-03-01T16:52:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: Calculate the average the same way you would with a positive number. That is, multiply each value by its percent in decimal form (i.e. -16*.10, etc) and add your answers together.
FirstChildUserIdTAG: 1254077
FirstChildUserNameTAG: alexsfein
FirstChildCreateTimeTAG: 2013-03-01T19:06:47Z
FirstChildVoteTAG: 9
FirstChildTAG: I did but still no success... Why it has to be no decimal point?
FirstChildUserIdTAG: 1133472
FirstChildUserNameTAG: hirogotanda
FirstChildCreateTimeTAG: 2013-03-05T13:20:42Z
FirstChildVoteTAG: 0
FirstChildTAG: I tried the two possible ways of solving this problem, but I got not the right answer. And both ways give the same result...
FirstChildUserIdTAG: 128193
FirstChildUserNameTAG: Marianne
FirstChildCreateTimeTAG: 2013-03-05T18:42:46Z
FirstChildVoteTAG: 0
IndexTAG: 1627
TitleTAG: Ranges.. ?
In video 2.3, at 8:05, in the first interval why are we choosing the range between $5000 to $6000 with about 2% of incomes, why should it start with the range of $0 to $1000.. with 2% of income.. ?
Similarly in the second interval why are we saying the range of $14000 to $15000 with an income about 1.87%, why should this be $10000 to $11000.. ?
Pls can some one help me understand, many thanks..
UserIdTAG: 833175
UserNameTAG: shahfasi92
CreateTimeTAG: 2013-03-01T16:35:56Z
VoteTAG: 1
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 0
IndexTAG: 1628
TitleTAG: if in some exercise i gt below 35% will i gt a crtificate
plzz tell
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-01T16:34:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: As long as your average over all the grades taken is over 35%, you will get a certificate. Plus, your bottom two exercise scores will not be counted.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T16:44:40Z
FirstChildVoteTAG: 4
IndexTAG: 1629
TitleTAG: ex6-prob 5
i really dont understant what the ques says.which rules i should follow.plzz hlp.i dnt find anything about tht in lctr
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-03-01T16:31:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: you need to read the text also
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-03-01T18:10:53Z
FirstChildVoteTAG: 0
SecondChildTAG: which txt
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-03-02T06:23:33Z
SecondChildVoteTAG: 0
FirstChildTAG: > The "root mean square" (or r.m.s.) is a procedure that can be applied to any list of numbers, to get a sense of how big the numbers are without regard to sign. The procedure is: square the entries, then take the mean of the squares, then take the square root. Find the r.m.s. of the list -7, -7, -7, 7, 7, 7, 7, 7.
This one? It is just asking for the root mean square of these numbers.
>The procedure is: square the entries,
So square every number
>then take the mean of the squares
You have squared all the numbers. Now find the mean of the squared numbers.
$\bar{x}=\dfrac{\sum x_i}{n}$
>then take the square root
Take the square root of your answer. This is the r.m.s.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T06:32:34Z
FirstChildVoteTAG: 0
FirstChildTAG: Rifayat. **This was not in the lectures. You have to read the text and do the exercises in it.** At the top of this exercise set there are links to text that you are required to read. I was a bit lazy this week and just skimmed over everything without doing the practice exercises in the text and ended up getting things wrong because of my sillyness. I have learned my lesson for next week!
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-02T19:15:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually, all you need to do in this case is read the text of the Problem, since the procedure to do the rms is also explained there :)
But yes, in general, do try to read at least the suggested portions of the textbook ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T12:57:58Z
SecondChildVoteTAG: 0
IndexTAG: 1630
TitleTAG: Problem 6 ES 4. Help!
I am not able to solve problem 6 of ES 4... like (b) has to be wrong as there cant be 2.9 people in a household. And also I dont think that a could be correct as there could possibly be no mistake in the calculation. Can someone please give me a close hint if the answer is a, c or d without breaking the honor code?
Thanks in advance.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-01T16:21:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: Hi, I also failed to find the answers for problem 6 es 4, but i think the answer may not be only in the text, i think You have to go through all of the videos to figure that out. A lot of it could be in the way we are supposed to interprate statistic data more then use of logic thinking. Haven't really given you the answer,but maybe you should pay more atention to videos and those non-graded exercise sets.
FirstChildUserIdTAG: 1307317
FirstChildUserNameTAG: bojanamarkovic
FirstChildCreateTimeTAG: 2013-03-01T16:31:44Z
FirstChildVoteTAG: 0
SecondChildTAG: You can find the answer in the text alone, following carefully the lectures will make it very easy for you to find the solution. I suggest you better spend some time with the lectures provided, as opposed to trying to guess!
SecondChildUserIdTAG: 1247915
SecondChildUserNameTAG: Iliri2013
SecondChildCreateTimeTAG: 2013-03-01T16:55:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes please go through the question one more time you will get the answer and also I would say go through this text/video
http://statistics.berkeley.edu/~stark/SticiGui/Text/location.htm#location
SecondChildUserIdTAG: 976798
SecondChildUserNameTAG: Vassri
SecondChildCreateTimeTAG: 2013-03-01T19:35:00Z
SecondChildVoteTAG: 0
SecondChildTAG: I went thorugh them and actualy got the correct answer and in this section had all my answers corrrect !! :)
SecondChildUserIdTAG: 1242151
SecondChildUserNameTAG: lhasan
SecondChildCreateTimeTAG: 2013-03-02T16:36:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Through the first attempt, I got two wrong, putting the other two, wrong as well. Obviously there can't be 4 wrong in this problem!!
Strange.
SecondChildUserIdTAG: 1178410
SecondChildUserNameTAG: Pti_Lu
SecondChildCreateTimeTAG: 2013-03-02T22:38:40Z
SecondChildVoteTAG: 0
SecondChildTAG: > Through the first attempt, I got two wrong, putting the other two, wrong as well. Obviously there can't be 4 wrong in this problem!! Strange.
You are assuming that two answers were required, maybe not.
And just because your first two were wrong, doesn't mean the other two are correct. Maybe one of your first two was correct, and maybe even one of the 2nd two. Maybe you needed 3 answers, or 1, or 4.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-02T23:19:53Z
SecondChildVoteTAG: 0
SecondChildTAG: After giving my answers I am of the opinion that question six is incorrectly worded or not all the options are given. After the deadline, please provide explanation for the correct answer and also for an answer that was marked incorrect.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-05T08:15:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Review the definitions of each measure of location--especially what they show and what they DON'T show.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-03-01T17:51:09Z
FirstChildVoteTAG: 0
FirstChildTAG: this one is about semantics, the study of meaning
got it wrong in 2 attempts. keep walking.
FirstChildUserIdTAG: 916555
FirstChildUserNameTAG: josecanica
FirstChildCreateTimeTAG: 2013-03-02T21:44:29Z
FirstChildVoteTAG: 0
IndexTAG: 1631
TitleTAG: Late in Exercise !!
Hello...
I haven't finished the exercises for the last 2 week!
1. Can I still do them now?
2. Will this effect on my grades and my final mark?
Thank you
UserIdTAG: 1212585
UserNameTAG: Lina88
CreateTimeTAG: 2013-03-01T15:55:42Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Please read the Course Info pages. They should answer your questions.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T16:43:26Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi ... where can I find about the "better late than never" principle?
HELP
SecondChildUserIdTAG: 1212585
SecondChildUserNameTAG: Lina88
SecondChildCreateTimeTAG: 2013-03-01T21:24:59Z
SecondChildVoteTAG: 0
SecondChildTAG: > "better late than never" principle?
This just means that it is better to do something late than never. In this case it is reading the course info documents. Something that everyone should have done on Day 1 but, as the time drama demonstrated, many did not. So go read them now.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-01T22:06:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Better late than never probably means that you should do the exercises anyway so then you will learn the concepts even if it's too late for your grade to be reported. You have missed week 1 but still have a few days for week 2. So, read the course info and do the work from the beginning. Submit your answers in time for the rest of the course and you should be OK.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-02T19:18:03Z
SecondChildVoteTAG: 0
IndexTAG: 1632
TitleTAG: SD++ and mod of chebyshev inequality
After going through the heuristic proof of Chebyshev's inequality in the online textbook, i was wondering:
A 4th power of the deviations will also get rid of the - signs. And if we make a new measure of spread:
nSD=4thRoot(mean(deviation)^4)
Then using the same process of proof as in the text, we'll get a much more tighter bound based on the nSD, where fraction of population outside k nSDs will be at most 1/k^4
So, wouldnt it be better to use nSD instead of SD as a measure of spread? In which case, where do we stop? the 100th power? the 1000th power?
I think [this][1] question by 4learning is somehow related to the usefulness of the upperbound obtained. But i'm unable to make a formal connection between the power used and the actual tightness of the bound.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_6/threads/51302a6994db64260000008f "this"
UserIdTAG: 133193
UserNameTAG: SudhirP
CreateTimeTAG: 2013-03-01T15:52:58Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 6 / Reading and Practice for Exercise Set 6
NumberOfReplyTAG: 1
FirstChildTAG: As far as I know, such things are actually used, but rarely. People don't need them much in day-to-day statistics, but I've seen the fourth power used to prove some complex math statements about algorithms in computer science papers.
It's similar to computing with decimals in engineering. When writing a number, you can write any number of digits after a decimal point, but usually it's enough to write 2-3 significant digits. More than that doesn't give you much more information — on the contrary, it increases information load, and so makes information harder to comprehend.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-03-02T20:22:14Z
FirstChildVoteTAG: 2
IndexTAG: 1633
TitleTAG: ADMIN Please help
I joined the course a little late. As many other students I am not able to submit the answers. What should we do now?
UserIdTAG: 1317242
UserNameTAG: ArjunSood
CreateTimeTAG: 2013-03-01T15:48:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Do the Week 1 problems on your paper, check with the answers, move on to Week 2
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-01T15:55:56Z
FirstChildVoteTAG: 0
IndexTAG: 1634
TitleTAG: about certificate
If I pass the exam and receive more than necessary points, will I receive a certificate?
UserIdTAG: 987671
UserNameTAG: Askar96
CreateTimeTAG: 2013-03-01T15:44:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: yes ofcrs
FirstChildUserIdTAG: 1042429
FirstChildUserNameTAG: Rifayat
FirstChildCreateTimeTAG: 2013-03-01T16:32:45Z
FirstChildVoteTAG: 1
IndexTAG: 1635
TitleTAG: problem 2
the average drops because of the mistake in recordings (165 instead 16.5) so the change cant be a positive value, is that correct?
UserIdTAG: 1210888
UserNameTAG: Marouzela
CreateTimeTAG: 2013-03-01T15:41:11Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 3
FirstChildTAG: Agreed, shouldn't the answer be -4.01?
FirstChildUserIdTAG: 935558
FirstChildUserNameTAG: NancyLew
FirstChildCreateTimeTAG: 2013-03-01T16:12:16Z
FirstChildVoteTAG: 1
SecondChildTAG: you should read the question, it is said median not average. I did the same mistake
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-03-01T17:47:04Z
SecondChildVoteTAG: 0
SecondChildTAG: I also think it should be a negative value.
SecondChildUserIdTAG: 1252009
SecondChildUserNameTAG: Emilyjch
SecondChildCreateTimeTAG: 2013-03-01T23:18:38Z
SecondChildVoteTAG: 0
SecondChildTAG: median is not mean... ;)
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-03-02T00:57:17Z
SecondChildVoteTAG: 0
SecondChildTAG: the question asked in problem 2 is: "By how many miles does the mistake in Exercise 1 change the average..."
the mistake has highered our real average by 4.01 units. so it will be +4.01 (i think).
SecondChildUserIdTAG: 1202828
SecondChildUserNameTAG: zam1991
SecondChildCreateTimeTAG: 2013-03-02T13:03:41Z
SecondChildVoteTAG: 0
FirstChildTAG: So you think that using 165 instead of 16.5 will *decrease* the average?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-01T21:13:11Z
FirstChildVoteTAG: 0
FirstChildTAG: For example:
2.1, 3.2, 5.7, 14.3, 19.5: Average = 8.96 Median = 5.7
2.1, 3.2, 5.7, 14.3, 195: Average = 44.06 Median = 5.7
Difference: $\dfrac{195-19.5}{5}=35.1$
$35.1+8.96=44.06$
So average has increased by 35.1.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T00:02:06Z
FirstChildVoteTAG: 1
SecondChildTAG: are you a programmer? or how do you manage to have equations display like this on here? this is amazing!
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-03-02T00:59:40Z
SecondChildVoteTAG: 0
SecondChildTAG: You use the mathjax ability of the forums. There is a bit of a tutorial on the wiki:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/mathjax-tutorial-write-formula-forum-wiki/
A comprehensive list of usage:
http://www.onemathematicalcat.org/MathJaxDocumentation/TeXSyntax.htm
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-02T01:09:02Z
SecondChildVoteTAG: 0
SecondChildTAG: If you right click on the formula in my post, select Show Math As > TeX Commands. This will show a pop-up window with the command used to create the forumla. You just need to start and stop with a $ sign to render the formula.
\dfrac{165-16.5}{5}=29.7
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-02T01:15:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Haha! Very amused by [triplebees][1] comments. I am also impressed with [SusanAust][2]'s formatting. I was too lazy to read the TeX info.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/users/1207892
[2]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/users/629320
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-02T19:21:06Z
SecondChildVoteTAG: 0
IndexTAG: 1636
TitleTAG: GMT/Daylight Saving Time
An explanation of GMT and the change to relative time in many countries during this course, due to the beginning of daylight saving time, is now on the **Course Wiki.**
UserIdTAG: 986983
UserNameTAG: Dianebefd
CreateTimeTAG: 2013-03-01T14:43:25Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Daylight saving time will start in march not end...?!
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-01T14:46:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Oh my goodness, you're right.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T14:54:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Fixed it!
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T14:57:20Z
SecondChildVoteTAG: 0
FirstChildTAG: The World Clock Time Converter is your best friend - make use of it!
http://www.timeanddate.com/worldclock/converter.html
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-03-02T19:26:00Z
FirstChildVoteTAG: 0
IndexTAG: 1637
TitleTAG: Late of submission
Thanks for this educative course.
I have tried to answer the questions given in set 1 but i can't submit, does that mean that time has caught up with me?
UserIdTAG: 453450
UserNameTAG: fmwambua
CreateTimeTAG: 2013-03-01T14:37:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Yes, week 1 is over. However since your lowest two scores are dropped, you will have no problem if you can turn in the others.
FirstChildUserIdTAG: 1152666
FirstChildUserNameTAG: brentsen
FirstChildCreateTimeTAG: 2013-03-01T15:28:12Z
FirstChildVoteTAG: 0
IndexTAG: 1638
TitleTAG: Set 6 Problem 6
Neither option solves the problem from my point of view. To solve this problem seems to be simple applying Chebychev's inequality.
What I don't understand:
*The English expression "sharpest correct"?
*Chebychev's inequality?
*Other?
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-03-01T13:55:27Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 5
FirstChildTAG: yes, you need to use formula 1/k2
FirstChildUserIdTAG: 1053569
FirstChildUserNameTAG: nicola2003
FirstChildCreateTimeTAG: 2013-03-01T14:05:00Z
FirstChildVoteTAG: 0
SecondChildTAG: OK, using it, I can't see what option I should to choose to answer it
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T14:23:48Z
SecondChildVoteTAG: 0
SecondChildTAG: You want the answer that provides the best bound that is correct. Remember the example that the 25% Markov bound was still correct, even when we later learned we could bound to 0.7%
SecondChildUserIdTAG: 1222946
SecondChildUserNameTAG: RichardDamon
SecondChildCreateTimeTAG: 2013-03-03T02:48:09Z
SecondChildVoteTAG: 0
FirstChildTAG: The video lessons didn't teach that formula yet, I was assuming you had to use Markov's; but I probably would have gotten it wrong anyway.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-03-01T14:14:06Z
FirstChildVoteTAG: 0
SecondChildTAG: You have just SD to fix it, then you need Chebychev's inequality
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T14:21:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Chebychev's inequality's formula is indeed taught in the lectures for section 4.
You really want to watch all lectures of the section, plus read the sections of the textbook suggested in the Practice Problems, before attempting the Exercise sets ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-03-03T13:01:37Z
SecondChildVoteTAG: 0
FirstChildTAG: Chebychev's Theorems states that at least (1-1/k^2)Of the data values must be within k standard deviations Of the mean,where k is any positive real number greater than 1. The point is to determine the value of k. Try it and you will get the right answer!
FirstChildUserIdTAG: 40403
FirstChildUserNameTAG: CHALE
FirstChildCreateTimeTAG: 2013-03-01T17:05:34Z
FirstChildVoteTAG: 0
SecondChildTAG: K is the only data you have, for me, the point is to have 1/k^2.
But this value is not in the option.
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T17:44:15Z
SecondChildVoteTAG: 0
SecondChildTAG: You have here what you get:
Table 4-5: Bounds implied by Chebychev's inequality
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T18:33:33Z
SecondChildVoteTAG: 0
SecondChildTAG: the exact value might not be a choice, but which of the choices is most correct based on your number? That's what I used.
SecondChildUserIdTAG: 1067669
SecondChildUserNameTAG: psanders
SecondChildCreateTimeTAG: 2013-03-01T20:05:33Z
SecondChildVoteTAG: 0
SecondChildTAG: It make sense
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T20:07:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Chebychev's Theorem for SD = 6.0 gives 0.9722 inside the distribution and 0.0278 in the remainder. So outside either tail there is 0.0278 of the distribution, but in Six-Sigma we are only interested in being better than 6.0 SDs. Therefore it should be only the upper part or half of 0.0278 = 0.0139 =~ 1.4%. I believe this answer to be correct but it was flagged as incorrect. Any thoughts?
FirstChildUserIdTAG: 983708
FirstChildUserNameTAG: LouisDB
FirstChildCreateTimeTAG: 2013-03-01T20:13:45Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, I think it should say mor than 6 sigma appart from the average value or something like that. I answered it under this assumption and found the answer in the choices ( the closest to my results which are similar to yours ).
SecondChildUserIdTAG: 40403
SecondChildUserNameTAG: CHALE
SecondChildCreateTimeTAG: 2013-03-01T20:38:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Below what P. Ani said in lect 4.3
it means, you shouldn't have the half.
"But you cannot say that the proportion in one tail is at most half of
1=k2, unless you know that the two tails are equal."
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T20:59:41Z
SecondChildVoteTAG: 0
SecondChildTAG: correction half of 1/k2
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T21:01:01Z
SecondChildVoteTAG: 0
SecondChildTAG: I think, the answer is the most promising way that "six sigma" can make its customers based on the calculation considering "the percent of entries that are more than 6 SDs above average"
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-01T21:52:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Done!
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-03-02T13:48:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Honor code, people!!! Honor code! Don't post what answer is correct, and don't post what answer is incorrect.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-02T23:57:35Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with you. The answer does not correspond to the wording of the question. The question asks for "the percent of entries that are more than 6 SDs above average." This clearly indicates the upper tail, not the lower. So the answer should be half of the portion of the distribution that lies outside six standard deviations, i.e., the portion superior to the +6SD mark. The answers given do not even provide that as an option.
SecondChildUserIdTAG: 1305333
SecondChildUserNameTAG: bellerin
SecondChildCreateTimeTAG: 2013-03-04T01:33:34Z
SecondChildVoteTAG: 0
SecondChildTAG: No, ballerin! The prof mentions in the lecture that you *cannot* assume that one tail contains half of the number provided by Chebychev's inequality.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-04T03:20:49Z
SecondChildVoteTAG: 0
SecondChildTAG: This is analogous to what Dr. A taught us using Markov's inequality for small K values. So we really have multiple correct answers shown, but one is the "best" or "closest", while still being inclusive, to the real value.
SecondChildUserIdTAG: 1071329
SecondChildUserNameTAG: jpfred
SecondChildCreateTimeTAG: 2013-03-06T03:02:30Z
SecondChildVoteTAG: 0
FirstChildTAG: Got it (in my second try)! Hey! A simple problem in disguise, but, again, a problem to test if we really understand what's the meaning of a bound. Thinking about what a 'six sigma' process implies (what it 'promises', as jorge has pointed) has helped me. So the example is illuminating.
Awesome exercises. Most of them don't require calculations, but conceptual comprehension. Good work, profs!
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-02T20:48:59Z
FirstChildVoteTAG: 2
SecondChildTAG: I agree with you about the conceptional understanding. I am enjoying the way she makes us think. . and I got through this question, but it is not the best example of the Prof's checking on a subtle teaching point because her choice of words is suboptimal at best in this question. I am dying to say more, but will wait until answers are posted.
SecondChildUserIdTAG: 975799
SecondChildUserNameTAG: lmacareo
SecondChildCreateTimeTAG: 2013-03-03T02:43:54Z
SecondChildVoteTAG: 0
SecondChildTAG: I've no problem with the wording here. The key thing is that the exact quantity is not given and that's the pedagogical feature, because it's necessary to understand precisely what the inequality bound means and implies (in the example, what implies for a 'six sigma' process) in order to select the right answer.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-03T09:49:56Z
SecondChildVoteTAG: 0
IndexTAG: 1639
TitleTAG: answers to graded problems
When and where will appear the correct answers for the set of problems due february 28?
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-03-01T13:51:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: they are already available. Look for a Show Answer button below the exercises
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-01T13:59:26Z
FirstChildVoteTAG: 0
IndexTAG: 1640
TitleTAG: Where my answers!!!!???
Where my answers!!!!??? I've lost the asnwers to problems 1 and 2
UserIdTAG: 183605
UserNameTAG: jjpachon
CreateTimeTAG: 2013-03-01T13:49:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No need for a double post.
Double check your progress bars ("Progess" on the top of this page). What do they say?
If they show 0% completion, did you save or submit your answers? You always need to submit them.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T13:59:41Z
FirstChildVoteTAG: 0
IndexTAG: 1641
TitleTAG: Answers for Exercise Set 1 missing
I did the exercise set 1 before the second deadline (27feb), all the questions!! But today i was checking the exercise set again and the problems 1 and 2 don't have the answers, so i got no points!!!!
UserIdTAG: 183605
UserNameTAG: jjpachon
CreateTimeTAG: 2013-03-01T13:42:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Double check your progress bars ("Progess" on the top of this page). What do they say?
If they show 0% completion, did you save or submit your answers?
You always need to submit them.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T13:48:54Z
FirstChildVoteTAG: 0
IndexTAG: 1642
TitleTAG: Is there an error with problem 6?
I can see that all answers can be considered as correct. If I choose "more than 45" this also includes the two previous ones. I cannot see the reason for those options in the specific problem. Am I missing something ???
UserIdTAG: 1069830
UserNameTAG: TheodoraCh
CreateTimeTAG: 2013-03-01T12:57:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: Its a tough one that I really had to think about, but think about the question, it says
> A firm has 82 employees. The average commute distance (that is, the
> travel distance from home to work) of the employees is 6.2 miles. How
> many employees have a commute distance of less than 15.5 miles? Select
> all that are correct.
so if your answer is between 26 and 35, you will tick one box, if your answer is more than 35 and less than 45, you need to ask how many correct answers there are, its more than 25 and more than 35 so this means there is more than 1 correct statement... etcetera for more than 45
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-03-01T13:39:13Z
FirstChildVoteTAG: 0
SecondChildTAG: @jasontimothyjones What if i find that it is "more than 45". Doesn't that also include the two previous ones ? Must I choose them too ? This is what confuses me ....
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-01T13:58:42Z
SecondChildVoteTAG: 0
SecondChildTAG: It says all that are correct, so we have to mark all that we consider right... I made the same mistake in my case because I didn't read carefully.
SecondChildUserIdTAG: 26776
SecondChildUserNameTAG: aleguillen
SecondChildCreateTimeTAG: 2013-03-01T14:02:02Z
SecondChildVoteTAG: 0
SecondChildTAG: The answer says you should check all that are correct. Remember the example in the lecture regarding number of hands or regarding 200%. If more than one is true then select ALL that are true, even if the answers seem to be redundant.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-01T14:02:10Z
SecondChildVoteTAG: 0
SecondChildTAG: I think you are right, we must select all the answers that are true. I guess the examiner wants to stress the fact that what we get from using the specific formula is a boundary and NOT a specific value.
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-01T18:49:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Imagine 3 heads (or if anyone has seen Total Recall - something else with 3)
Now you should be able to go "Bounding off" to get the answer ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T03:06:15Z
SecondChildVoteTAG: 0
SecondChildTAG: More than 48 of employees have a commute distance of less than 15.5 miles, that is every answer is correct.
SecondChildUserIdTAG: 933199
SecondChildUserNameTAG: Andreii
SecondChildCreateTimeTAG: 2013-03-02T20:43:44Z
SecondChildVoteTAG: 0
FirstChildTAG: It's not justified at all. Because since 'more than 45' is in the list, 'more than 25' and 'more than 35' options obviously not correct. I can't see any point to select all. 'More than 45' is the best possible answer.I would select all only if it would have been asked for 'select which can be true? among the option?'. Requesting to restate the question. Thanks
FirstChildUserIdTAG: 936512
FirstChildUserNameTAG: Roqib
FirstChildCreateTimeTAG: 2013-03-01T14:52:06Z
FirstChildVoteTAG: 4
SecondChildTAG: Here's how I think of it. Let's say we had a multiple choice question, and we're told to select all the answers that are true. Here are the choices:
a) 100>25
b) 100>35
c) 100>45
Which answers are correct? All of the answers are correct. If we need to select all of the answers that are true, then we would select a and b and c.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-01T17:02:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks and I agree that theoretically you are right.....but I don't understand, what has tried to be assessed by this question. If it is to assess the students' understanding over a question-then its fine. But if to assess understanding on what has been taught by previous lecture, then I am sorry but the question failed to do so. We are not kindergarten going kids here who won't understand which number is bigger (that @merhutchin replied). We understand, if a number is bigger than 45 then it must have to be bigger than any other numbers lower than 45. I am sorry but its just my feeling. I am not caring about my scores in this course, I have never been after the scores. I want to learn and I think i figured out the right answer. Thanks a bunch!
SecondChildUserIdTAG: 936512
SecondChildUserNameTAG: Roqib
SecondChildCreateTimeTAG: 2013-03-02T07:20:56Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with Roqib. If correct answer is not only one, who can understand how of us with mistakes and by only one submission?
SecondChildUserIdTAG: 200548
SecondChildUserNameTAG: kame
SecondChildCreateTimeTAG: 2013-03-02T15:17:58Z
SecondChildVoteTAG: 0
SecondChildTAG: You are giving away too much information prior to submission due date.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-02T18:17:26Z
SecondChildVoteTAG: 0
SecondChildTAG: I think the fundamental error is you are missing the whole point of the exercise and the question - it is related to identification of bounds.-What is the bound and what is its relation to elements on either side of the bound.In essence this is in relation to the inequality and the interpretation of a bound set up by that inequality.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T19:44:58Z
SecondChildVoteTAG: 0
FirstChildTAG: If the goal of the question is to see if I learned about Markovs Inequality then I showed I knew it by proving that "more than 45" is correct...which obviously logically implies that the other two answers are correct.
Bad question format by the instructor because it seems to be trying to assess additional comprehension beyond knowing the correct answer to a straightforward Markov Inequality question. Hard to figure why the instructor used this approach.
Anybody that picked "more than 45" should get credit for the points.
FirstChildUserIdTAG: 1186397
FirstChildUserNameTAG: larryweidman
FirstChildCreateTimeTAG: 2013-03-02T21:07:53Z
FirstChildVoteTAG: 2
SecondChildTAG: > Bad question format by the instructor because it seems to be trying to
> assess additional comprehension beyond knowing the correct answer to a
> straightforward Markov Inequality question.
The Prof. specifically went over these sorts of questions with some seemingly ridiculous examples in the lectures. There is a reason for it even if we don't know exactly what it is.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-03T01:10:50Z
SecondChildVoteTAG: 0
IndexTAG: 1643
TitleTAG: Crashing when using Latex commands
Has anyone noted if the chrome tab crashes with an "Aw" when you use latex commands in the discussion group ?I have to hurry and type a few words (Latex commands) and save it every time I insert the Latex commands.I try to follow what Google says wrt this but it doesnt seem to help(Check for Malware, firewall,plugins etc etc).What plug in does the Edx site use for inserting Latex commands ? I can type any other gobbledygook with no problem !!
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-03-01T12:57:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I use Google chrome and have not had any problem with it, but I have no idea what latex commands are...
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-03-01T14:37:18Z
FirstChildVoteTAG: 0
SecondChildTAG: I am using Chrome on a wonsows XP PC. I can manage for some time but then it crashes
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-01T14:56:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Latex -pronounced lateck is a markup language to wrie maths in documents.
http://en.wikipedia.org/wiki/LaTeX
Type two dollar signs around these and see what happens to the ouput:
/n.\sigma_{n=1}^n n!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-03T14:58:15Z
SecondChildVoteTAG: 0
SecondChildTAG: you should get this
$/n.\sigma_{n=1}^n n!$
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-03T14:58:57Z
SecondChildVoteTAG: 0
FirstChildTAG: $\mu = \frac{1}{n} \sum_{i=1}^n x_i$
It works for me (chrome on Linux).
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-01T14:49:22Z
FirstChildVoteTAG: 0
SecondChildTAG: I can manage some time(fore g I could type some equations but after a bit of time it crashes !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-01T14:57:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Hmm. Can you be more specific. What is a "a bit of time" in minutes? Maybe the problem has nothing to do with time, but with the quantity (or, even, the complexity) of your LaTeX commands, or it's a certain command that triggers some interpreter malfunction..
I'll try to test with more time of latexing during the weekend. I'll tell you.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-01T21:04:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Excuse me my grammar errors in the last comment. I'm writing while travelling.
You might try the same sequence of commands to test what I've said in the previous comment.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-01T21:09:48Z
SecondChildVoteTAG: 0
SecondChildTAG: It usually is not more than one or two minutes and the equation was not unduly complex (just showing the average of the sum of absolute values) and I had to continuously save every couple of entries!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T04:28:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Testing from chrome on android (previous was chrome on Win XP)
$/sum $
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T04:32:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Chrome on android seems to refuse to accept mathsjax! $Sigma $ $/sum will retru with desktop
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T08:49:33Z
SecondChildVoteTAG: 0
SecondChildTAG: I can test chrome on android later when I've access to my tablet.
Is it something like this?
$MAD = \frac{1}{n}\sum_{i=1}^n |x_i - \tilde{x}|$
Again, it works fine for me.
Note that you have written a '/' (slash) in your example, instead of a backslash, '\', to start the LaTeX commands.
Hey! Now that I'm writing this post, I notice, while typing, a delay between keystrokes and character displaying. If I remove the formula my typing is seamless again. Maybe when a formula is present the interpreter suffers some extra burden.
I paste the formula in the corresponding place right now. So try this: type you normal text, and after that, put the formula in the corresponding place just before submitting.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-02T10:11:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Trying with android..
$\frac{1}{n}\sum_{i=1}^n |x_i-median(x)|$
It seems to work
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-02T11:29:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Dont know why but I get the aw snap crash of the tab still and this is the google report suggestions
https://support.google.com/chrome/bin/answer.py?hl=en&answer=95669&p=e_awsnap
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T18:46:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Atopos I tried again and it doesn't still seem to work (crashing) I think I need to enter everything as you say and hurriedly put the $ signs (and yes I did make a mistake wrt \ !! I removed all extensions, scanned for Malware etc still no luck. I jsut crashed a set of lines that I wrote :(
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-02T18:58:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Maybe if has something to do with Windows. I'm on Linux, as I've said before. I can't try on Windows. Have you tried with Firefox? I'm going to try on Firefox right now and I'll tell you.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-02T20:57:13Z
SecondChildVoteTAG: 0
SecondChildTAG: I've just tried with Firefox (on Linux, no Windows machine at hand), mixing normal test with formulas and it works fine. Give a try to Firefox and tell me.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-02T21:12:33Z
SecondChildVoteTAG: 0
SecondChildTAG: testing on Firefox
$\sum_{i=1}^{\infty}\frac{1}{i}$
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-03T02:35:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Testing on Firefox
$\sum_{i=1}^{\infty}\frac{1}{i}$
$\sum\limits_{i=1}^n\frac{n}{n+1} + n! $
Seems to work on Firefox so far without crashing !! Only problem is that Firefox is such a resource hog over time compared to Chrome :( Anyway if I have to use latex commands I think I will ahve to do it in Firefox.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T02:42:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Glad to know that!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-03T09:41:17Z
SecondChildVoteTAG: 0
IndexTAG: 1644
TitleTAG: Problem 2
if there are 4 (6s), 5 (3s), 4 (1s), 4 (5s), 4 (2s) and 3 (4s), how come the number of modes in the list is not four??????
UserIdTAG: 467778
UserNameTAG: kimera
CreateTimeTAG: 2013-03-01T12:14:12Z
VoteTAG: 2
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: Because there is only one mode (i.e., most frequent number) - which is 3 (which occurred 5 times)
FirstChildUserIdTAG: 1069628
FirstChildUserNameTAG: aioreill
FirstChildCreateTimeTAG: 2013-03-01T12:28:53Z
FirstChildVoteTAG: 2
FirstChildTAG: The number 3 showed up five times ... that is the only one and it has the most times in the list. The other numbers like 6, 1, 5, and 2 only showed up four times each.
IF the number 3 only showed up four times then you would have had five modes.
IF the number 6 showed up five times then you would have two modes.
The mode is the data point that shows up the most times in a list of data. You find it by counting and the one that shows up the MOST will be the Mode. Some data lists will not have any and some data sets will have more than one Mode.
FirstChildUserIdTAG: 980531
FirstChildUserNameTAG: tesmaili
FirstChildCreateTimeTAG: 2013-03-01T12:35:08Z
FirstChildVoteTAG: 1
SecondChildTAG: Please stick to the honor code and edit your responses so that they dont give away the answer.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-01T12:52:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Because they are not asking for the mode, the are asking for how many modes do that problem have. Read carefully.
SecondChildUserIdTAG: 1131693
SecondChildUserNameTAG: Catica
SecondChildCreateTimeTAG: 2013-03-01T16:28:51Z
SecondChildVoteTAG: 0
SecondChildTAG: I am wondering why there will not have any? It is quite clear to understand some data sets will have more than one mode, as some data would have the same frequency. COuld you give me an example? thanks
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-03-02T02:41:09Z
SecondChildVoteTAG: 0
IndexTAG: 1645
TitleTAG: How to enter the answer of problem 5 in ES 4? Help!
I got the answer of problem 5 in ES4 but I don't know how to enter it...like in the answer I got 4 decimal places. So how many decimal places should I enter? Or should I round it off?
Due to this reason I am not able to answer the question. Please help me anyone.
Thanks in advance.
UserIdTAG: 1242151
UserNameTAG: lhasan
CreateTimeTAG: 2013-03-01T11:49:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: I've used 2 decimal places in all the exercises in Week 2 without a problem.
You can use from 2 to 5 if I am not mistaken, but do not forget rounding the number in the end.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-03-01T11:57:35Z
FirstChildVoteTAG: 2
SecondChildTAG: thanks
SecondChildUserIdTAG: 1242151
SecondChildUserNameTAG: lhasan
SecondChildCreateTimeTAG: 2013-03-01T16:24:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Read the paragraph before the problems begin. The directions tell you how to enter the numbers.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T17:54:50Z
SecondChildVoteTAG: 0
SecondChildTAG: from 2 till 4 decimel places but not 5
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-01T19:54:17Z
SecondChildVoteTAG: 0
SecondChildTAG: xxx.xx
SecondChildUserIdTAG: 160934
SecondChildUserNameTAG: DonnaC
SecondChildCreateTimeTAG: 2013-03-01T20:00:06Z
SecondChildVoteTAG: 0
FirstChildTAG: This following information is at the top of the exercise set:
Format of numerical answers
This exercise set is worth 10 points. The paragraphs below discuss the format of numerical answers; please see the Course Announcement on the Landing Page for the reasons.
Please provide all numerical answers correct to two decimal places or more, but please don't use more than five decimal places. No answer in this course will involve that degree of accuracy.
For example, if your answer is 1/6, you can enter 0.17, or 0.167, or 0.1667, or 0.16667. Please don't enter 1/6 or 0.166666... or any expression that is not a number.
If your answer is exactly -20.5, you can enter -20.5; you don't have to enter -20.50. If your answer is exactly 15, you can enter 15; you don't have to include a decimal point.
Please do NOT enter any units of measurement; if they are needed, they will have been entered for you or will appear as part of multiple choice statements.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T16:45:31Z
FirstChildVoteTAG: 0
IndexTAG: 1646
TitleTAG: Answer shown for problem 4c
Hello, first of all thank you very much for the opportunity of this course, i've been enjoying very much the lectures and the exercises, and all of you have been very patient with the discussions.
I don't understand the answer on problem 4c, which i've had incorrect. Although i understand years 12 and 16 are milestones, as the intervals include the left endpoint but not the right one, both groups, those with 12 and those with 16, are alone in the interval. Shouldn't this make the intervals distribution uniform?
UserIdTAG: 1030867
UserNameTAG: vodonnell
CreateTimeTAG: 2013-03-01T11:45:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: If you assume that the distribution is uniform it would follow that there is the same number pupils who spent only one year in school, only two years, etc. Now ask yourself whether it is a logical assumption? Or rather, in general, (majority of) pupils tend to stay whole 12 years.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-01T14:06:32Z
FirstChildVoteTAG: 1
SecondChildTAG: But the uniform distribution is supposed to be inside each interval not relative to the other intervals. I'm still having problems understanding this problem but thank you for answering.
SecondChildUserIdTAG: 1030867
SecondChildUserNameTAG: vodonnell
SecondChildCreateTimeTAG: 2013-03-02T12:52:25Z
SecondChildVoteTAG: 0
SecondChildTAG: that is what I am talking about: take the first interval which is [0;9].If you assume the uniform distribution within this interval it would follow that there is an equal number of pupils who received one year of schooling, two years of schooling and so on. However, in real life, pupils do not drop out from school at the same rate each year. They, rather, drop out after achieving some educational milestone (or continue further, of course).
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-02T13:59:27Z
SecondChildVoteTAG: 0
IndexTAG: 1647
TitleTAG: TEST 1 - Problem 6
Hi there,
Just for clarification purposes:
In Problem 6, it states "the average amount raised by the 12 board members is $5,200".
**Question** - is this the sum of all 12 board members or individual amount (on average), raised by EACH of the 12 board members?
Thank you,
Pedro
UserIdTAG: 206086
UserNameTAG: pedrocas1972
CreateTimeTAG: 2013-03-01T11:32:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The total sum cannot be an average.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T11:38:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, I understand that.
The assumption is that EACH of the 12 members collected an average of 5,200 correct?
SecondChildUserIdTAG: 206086
SecondChildUserNameTAG: pedrocas1972
SecondChildCreateTimeTAG: 2013-03-01T14:42:06Z
SecondChildVoteTAG: 0
SecondChildTAG: It means that on average, each member collected 5.200.
By the way, your questions has an incorrect/confusing title and is not in the right discussion category (Discussion on Exercise Set 3). If you edit it accordingly, other students are more likely to find it and give you their opinion on the matter.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-01T14:54:39Z
SecondChildVoteTAG: 0
IndexTAG: 1648
TitleTAG: pls i need more info.
My name is EKOE JOHN PETER, a registered student from Nigeria, i need more information about the course in terms of lecture time, time for exercise and the course manual, i will be glad if this can be sent to my e-mail. thanks.
UserIdTAG: 1012378
UserNameTAG: bongarcon
CreateTimeTAG: 2013-03-01T11:28:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Course Info: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T11:30:21Z
FirstChildVoteTAG: 1
IndexTAG: 1649
TitleTAG: I am unable to submit pset2
unable to submit problem 2. Does it have to do with deadline?
UserIdTAG: 900106
UserNameTAG: Cory65
CreateTimeTAG: 2013-03-01T09:50:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Yes
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-03-01T10:07:26Z
FirstChildVoteTAG: 0
FirstChildTAG: ya , we need to do within timeline...
i too could n't submit it
FirstChildUserIdTAG: 1311995
FirstChildUserNameTAG: podilashree
FirstChildCreateTimeTAG: 2013-03-01T10:13:29Z
FirstChildVoteTAG: 0
FirstChildTAG: Aggh...so i suppose it'd same for the other one...pity
FirstChildUserIdTAG: 900106
FirstChildUserNameTAG: Cory65
FirstChildCreateTimeTAG: 2013-03-01T10:24:05Z
FirstChildVoteTAG: 0
IndexTAG: 1650
TitleTAG: hello
hello, i would like to ask if i could follow the course and pass it and obtain a crtificate because unfotunately i dropped out the first week, many thanks.
UserIdTAG: 613284
UserNameTAG: emy2012
CreateTimeTAG: 2013-03-01T09:33:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Read the Course Info and esp. the document: Course Policies and Requirements to decide for yourself. Short answer: Yes.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T09:42:11Z
FirstChildVoteTAG: 0
FirstChildTAG: Just register again.
FirstChildUserIdTAG: 310963
FirstChildUserNameTAG: TwinOtter
FirstChildCreateTimeTAG: 2013-03-01T16:33:38Z
FirstChildVoteTAG: 0
IndexTAG: 1651
TitleTAG: Why is probe wrong?
(-16) + (-3) + 5 + 8 = -6 / 4 = -1.5
UserIdTAG: 1163039
UserNameTAG: CassandraPW
CreateTimeTAG: 2013-03-01T08:43:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: think about the second column in the table....
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-03-01T08:57:03Z
FirstChildVoteTAG: 1
FirstChildTAG: And just remember the honour code.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T08:58:00Z
FirstChildVoteTAG: 1
FirstChildTAG: As Marian suggested the second column is the percentage of the distribution. ie. 10 % of the whole distribution are made up of 16s... I find it easier to think that there are 100 items in the distribution...
You will then find it is the absolute answer. :)
FirstChildUserIdTAG: 1181263
FirstChildUserNameTAG: drush
FirstChildCreateTimeTAG: 2013-03-01T09:54:12Z
FirstChildVoteTAG: 0
SecondChildTAG: so can u give me just a hint as to how the two columns are manipulated? am so confused
SecondChildUserIdTAG: 820147
SecondChildUserNameTAG: frimpongmaxwellkwadwo
SecondChildCreateTimeTAG: 2013-03-01T17:22:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Best to relook at the lectures- they have given a similar example.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-01T19:00:56Z
SecondChildVoteTAG: 0
SecondChildTAG: The values are weighted. you have to use all the information in the table - meaning both columns. I agree that you should review the lectures.
SecondChildUserIdTAG: 868031
SecondChildUserNameTAG: CaliforniaViv
SecondChildCreateTimeTAG: 2013-03-03T19:42:39Z
SecondChildVoteTAG: 0
IndexTAG: 1652
TitleTAG: Unable to view the material for Week 2
Could someone help me I am unable to download the week 2 material.
UserIdTAG: 948983
UserNameTAG: DhanashreeV
CreateTimeTAG: 2013-03-01T08:19:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1653
TitleTAG: Ex. set 2
Please anyone tell me what was the answer of problem 5 of Exercise set 2 -
"In a histogram of lengths measured in millimeters, the height of the 20-40 bar is 1 percent per millimeter. If I measure all the lengths in centimeters instead, then the corresponding bar would be labeled 2-4".
Time is over, so it will not break the honor code.
UserIdTAG: 592716
UserNameTAG: drsaswatinath
CreateTimeTAG: 2013-03-01T08:15:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: EXPLANATION
The bar has 1% of people in each millimeter. A centimeter is 10 millimeters. So there are 10% of people in each centimeter.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-03-01T08:23:44Z
FirstChildVoteTAG: 0
SecondChildTAG: Another explanation is:
the area remains unchanged: 20%.
However, using centimeter, the interval changed. It is now 4-2=2cm and not anymore 40-20=20 mmm.
So now you can calculate the new height of the bar, which is expressed in % per cm.
In the course we have learned that the area= class interval x height of the bar. 20% = 2cm x new height in % per cm.
The answer is therefore 10% per cm.
SecondChildUserIdTAG: 830835
SecondChildUserNameTAG: Zacharie
SecondChildCreateTimeTAG: 2013-03-01T10:00:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks a lot Mzvd.
FirstChildUserIdTAG: 592716
FirstChildUserNameTAG: drsaswatinath
FirstChildCreateTimeTAG: 2013-03-02T01:23:06Z
FirstChildVoteTAG: 0
FirstChildTAG: The original display showed $\displaystyle\frac{\%}{mm}$.
The new display bar is in$\ cm $ instead of$\ mm$, and we have to maintain the relationship between the parts, so:
$\displaystyle\frac{1\%}{1mm}$ = $\displaystyle\frac{\color{#008800}x\%}{\color{#0000FF}1cm}$ We know that $\color{#0000FF}1cm = \color{#0000FF}1\color{#0000FF}0mm.$ Therefore:
$\displaystyle\frac{1\%}{1mm}$ = $\displaystyle\frac{\color{#008800}x\%}{\color{#0000FF}1\color{#0000FF}0mm}$ We can thus conclude that: $\color{#008800}x = \color{#008800}1\color{#008800}0$
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-03T01:50:25Z
FirstChildVoteTAG: 0
IndexTAG: 1654
TitleTAG: Unable to submit
Please add me to the list.
UserIdTAG: 574844
UserNameTAG: shush120
CreateTimeTAG: 2013-03-01T07:41:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: What list?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T07:48:14Z
FirstChildVoteTAG: 0
SecondChildTAG: The list of people who didn't understand the deadline, even though it was explained clearly on the landing page.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-01T17:05:58Z
SecondChildVoteTAG: 0
IndexTAG: 1655
TitleTAG: Progress on practice for exercise sets
Hello,
this week the progress on these practice for exercise sets are not shown for some reason, for the exercise sets themselves it seems okay. Any idea where this comes from?
UserIdTAG: 1024625
UserNameTAG: jos_gubbels
CreateTimeTAG: 2013-03-01T07:08:35Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 5
FirstChildTAG: Same here
FirstChildUserIdTAG: 1133963
FirstChildUserNameTAG: yolandaOliver
FirstChildCreateTimeTAG: 2013-03-01T07:17:03Z
FirstChildVoteTAG: 0
FirstChildTAG: I may be wrong here, but practice for exercise sets are just that: practice.
They don't count for progress/grade or at least for me they never did.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-03-01T09:31:20Z
FirstChildVoteTAG: 0
FirstChildTAG: Point is in week 1 the progress was shown, however not for week 2..........I know it is a minor flaw.
FirstChildUserIdTAG: 1024625
FirstChildUserNameTAG: jos_gubbels
FirstChildCreateTimeTAG: 2013-03-01T11:55:02Z
FirstChildVoteTAG: 0
FirstChildTAG: I think it's because they are listed as 0 points. Even when you get them right, they add 0 towards the practice points total.
FirstChildUserIdTAG: 83185
FirstChildUserNameTAG: oysteingrondahl
FirstChildCreateTimeTAG: 2013-03-01T12:00:51Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes, it seems you're right. Thanks.
SecondChildUserIdTAG: 1024625
SecondChildUserNameTAG: jos_gubbels
SecondChildCreateTimeTAG: 2013-03-01T15:35:48Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, I had the same problem
FirstChildUserIdTAG: 40403
FirstChildUserNameTAG: CHALE
FirstChildCreateTimeTAG: 2013-03-01T16:41:04Z
FirstChildVoteTAG: 0
IndexTAG: 1656
TitleTAG: need help for problem 2 and 6
should i use -16 or only 16 for calculation confused?
tried both the ways and get wrong answers. can any one help me to solve this.
I am also confused for problem 6, please help.
UserIdTAG: 393580
UserNameTAG: Aditiak
CreateTimeTAG: 2013-03-01T06:47:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: > should i use -16 or only 16 for calculation confused?
Use the value in the table. So if it a negative value, it is negative. Then be careful with your calculations - don't lose signs.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T07:11:41Z
FirstChildVoteTAG: 1
IndexTAG: 1657
TitleTAG: How to calculate the squared deviations
I want clarification on how to calculate sum of squared differences and sum of absolute differences.
UserIdTAG: 807230
UserNameTAG: SUMA2612
CreateTimeTAG: 2013-03-01T06:43:07Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 4
FirstChildTAG: Do you want to find out the mean, the median or something else? I am not sure...
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-03-01T11:35:33Z
FirstChildVoteTAG: 0
FirstChildTAG: Calculating the plain old **sum** of the differences is pointless as the sum will always be zero. This is shown and stated in Lecture 4.2, first two minutes of the lecture approximately.
(Regarding **absolute** differences, I don't know how relevant that is at this point in the course. What applications does the sum of absolute differences have? I don't think we've seen that yet...)
Anyway, you first need to calculate the deviation of each score (difference of **each** single score from the average) in order to then calculate the sum of the **squared** differences. This is necessary for finding the standard deviation of a list which **is** a significant indicator.
Let me know if the slide below is of any help. Note that I have illustrated over the professor's original slide in different colours and none of this information has been condoned or checked by staff so there could be errors in it. I am just a student!:
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13621626581343687.jpg
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T11:56:23Z
FirstChildVoteTAG: 3
SecondChildTAG: Now it is clear to me
SecondChildUserIdTAG: 807230
SecondChildUserNameTAG: SUMA2612
SecondChildCreateTimeTAG: 2013-03-01T15:37:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Super. Drawing the chart helped me to understand standard deviation more clearly too!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-01T17:03:51Z
SecondChildVoteTAG: 0
SecondChildTAG: I just updated an amended chart. The previous one had errors in the list of green deviations that were being squared. The logic was OK. There were just typos in the numbers that could have been very confusing...
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-01T18:33:13Z
SecondChildVoteTAG: 0
SecondChildTAG: The absolute differences are relevant for measures of the median. Each of the three Measures of Location we've had have a nice corresponding Metric which are useful for minimizing distance from a location.
mode: Boolean (0 for no distance, 1 for some distance)
median: absolute value (raw distance in units, like a "ruler" on the x scale)
average (mean): the square of the absolute values of those distances (which is the same as the square of the distances, since we lose the meaningless - signs when we square)
![a little chart, if it helps][1]
If you add all the absolute value distances from each point to the median (in, say, the little spreadsheet above, Column E) you get a total distance of 21. Also, if you add the absolute values distances from each point to an arbitrarily chosen "2" as a location, you get the same distance.
In fact, it seems like no matter what value you choose between -1.0 and 2.0, the sums of the absolute value distances is the same. They're all, in some sense, the "median." However, we choose the smallest value that's in our set (-1), as the median in this class.
On to the *squares* of the distances: that's interesting to me, because it accentuates values which are very far away from the average by making the distances larger as a nonlinear function. So... is the minimization of the sums of the *cubes* of the distances, for example, and equally valid (though more complicated) metric to use in calculating the average?
[1]: https://edxuploads.s3.amazonaws.com/13622666291343658.png
SecondChildUserIdTAG: 1284156
SecondChildUserNameTAG: Dispader
SecondChildCreateTimeTAG: 2013-03-02T23:31:03Z
SecondChildVoteTAG: 0
FirstChildTAG: VickyO , the sum of the absolute differences is not zero.The absolute difference is given by $|x-y|$ ie difference disregarding signs.So the sum of the average of the absolute differences is given by $\frac{\sum\limits_{i=1}^n|x_n -\mu|}{n} $
This will be a non zero number unless all the numbers are equal.
ps this is my first real attempt to use Latex commands as I always used to do it indirectly using Lyx !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-01T12:37:50Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, you're right. I will amend.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-01T13:52:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Guys, that's a very interesting discussion, but WHY below Practice for Excercise Set 4?!
FirstChildUserIdTAG: 517550
FirstChildUserNameTAG: Ewa_G
FirstChildCreateTimeTAG: 2013-03-03T10:17:10Z
FirstChildVoteTAG: 2
IndexTAG: 1658
TitleTAG: Chebychev
Chebychev says that the proportion outside the range average kSD is
at most 1=k2.
This is an upper bound on the total proportion in the two tails:
average kSD average +kSD
left tail right tail
So it is also an upper bound on each of the two tails separately:
The proportion in the left tail is at most 1=k2.
The proportion in the right tail is at most 1=k2.
But you cannot say that the proportion in one tail is at most half of
1=k2, unless you know that the two tails are equal.
1. does the bound have to be able to work on both sides of the tail in order for it to be applied?
2. If the bound is being placed upon one tail, is it dependant on the two tails being equal to work?
3. Does this also have to involve itself with non-negative numbers or does it take into consideration negative numbers?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-01T06:18:46Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Chebychev's bound: 80 years is 60 years above average. That's 12 SDs
above average.
Chebychev's inequality, applied to the right tail:
the proportion average +12SD is at most 1/144 = 0.7%, roughly,
and so
Chebychev: at most 0.7% are more than 80 years old.
More Questions.
4. average +12SD is at most 1/144 = 0.7%, i see that 12 comes frome the fact that they said that 80 is 12 sd above average but how did they come up with 1/144 or more specifically the 144?
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-01T06:45:46Z
FirstChildVoteTAG: 1
FirstChildTAG: > how did they come up with 1/144 or more specifically the 144?
$k=12$
From text:
>[the fraction of numbers in the list that are k×SD or further from M] ≤ $\frac{1}{k^2}$.
So $\dfrac{1}{k^2}= \dfrac{1}{12^2} = \dfrac{1}{144}$
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T07:08:02Z
FirstChildVoteTAG: 0
IndexTAG: 1659
TitleTAG: 6.4. incorrect as well - not sure I understand.
I first draw the histogram and thought they will have the same AVG and therefore same SD - didn't work. So I created my respective A and B lists by multiplying the % of entries per each value and proceeded to calculate SD for each list but when seemingly correct answer was selected I got the X again. Any insight? I just want to understand what did I do wrong.
UserIdTAG: 1130342
UserNameTAG: Sany-t
CreateTimeTAG: 2013-03-01T05:52:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 5
FirstChildTAG: I also did the second option that you've mentioned and got the correct answer. Try recomputing your values and it will give you the right answer.Compare your manual computation by using a calculator or excel to see possible errors during the process.Hope it helps!=)
FirstChildUserIdTAG: 466761
FirstChildUserNameTAG: Yuwee0730
FirstChildCreateTimeTAG: 2013-03-01T08:31:22Z
FirstChildVoteTAG: 2
SecondChildTAG: You dont really need to calculate anything, just look at the lists carefully and you can work it out
SecondChildUserIdTAG: 844365
SecondChildUserNameTAG: jeremyliver
SecondChildCreateTimeTAG: 2013-03-01T23:54:20Z
SecondChildVoteTAG: 0
FirstChildTAG: You really cannot say that ''they have the same avg and therfore same SD''.
which rule is saying that...
FirstChildUserIdTAG: 830835
FirstChildUserNameTAG: Zacharie
FirstChildCreateTimeTAG: 2013-03-02T06:38:54Z
FirstChildVoteTAG: 1
FirstChildTAG: > I first draw the histogram and thought they will have the same AVG and therefore same SD - didn't work.
It wouldn't. Having the same mean does not say they have the same SD.
$\bar x = \dfrac{\sum x_i}{n}$
$SD=\sqrt{\dfrac{\sum(x_i- \bar x)^2}{n}}$
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-03-02T06:50:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Think about the fact that most values aggregate within a few standard deviations around the mean. Ie it is like a mother spreading her arms in to catch all her babies crawling away from her (Think of Octoplets).She has to not spread her arms wide if they are all close to her and she has to spread her arms more to grab them all if she has them all running away -One poor tired hassled Mom indeed if you can imagine it ;)
Of course you can painstakingly calculate the values too !
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-02T18:12:10Z
FirstChildVoteTAG: 2
SecondChildTAG: Very helpful analogy.
SecondChildUserIdTAG: 360217
SecondChildUserNameTAG: cchapman
SecondChildCreateTimeTAG: 2013-03-04T10:09:29Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with Prasannashimha. If you understand the concept of SD, you don't need to do any calculations.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-03T00:01:12Z
FirstChildVoteTAG: 2
IndexTAG: 1660
TitleTAG: Unable to Submit assignment 1 on time
Hello Course team/ Professor
Yesterday my University has notified me about this course and I have registered immediately but I did not get enough time between registering last night and 4:30 pm California time to complete my first assignment. My concern is that how this will impact my grades and should I continue or drop and take it next time around? your eraly response is appreciated.
UserIdTAG: 1327140
UserNameTAG: AMunad
CreateTimeTAG: 2013-03-01T05:32:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Read the Course Info and it will tell you that there is no problem. You need 35% to "pass".
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T06:25:33Z
FirstChildVoteTAG: 0
SecondChildTAG: Hello I too have missed out the Assignment will it effect my grades.
I was a bit muddled up , Are the exercises below the lessons of the particular week as assignment???
Please Answer me..
Thanks in advance.
Dhanashree V.
SecondChildUserIdTAG: 948983
SecondChildUserNameTAG: DhanashreeV
SecondChildCreateTimeTAG: 2013-03-01T08:23:23Z
SecondChildVoteTAG: 0
FirstChildTAG: > Are the exercises below the lessons of the particular week as assignment???
Yes. They are indicated by the little blue alarm clock icon.
There are also practice exercises, clearly labelled as such. These are not graded, just for practice.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T08:28:27Z
FirstChildVoteTAG: 0
IndexTAG: 1661
TitleTAG: Margin of errors in polling data
Does the standard devieation account for the margin of error in polling data often reported during elections?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-01T05:30:41Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes, in a very particular way which you will see in Stat 2.2X if you continue in the sequence. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T05:56:20Z
FirstChildVoteTAG: 1
SecondChildTAG: I wondered about this as well. Polling data relies on random samples. I wondered if the standard deviation is calculated differently when the list is complete in and of itself but is, itself, a representative list.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-06T20:47:53Z
SecondChildVoteTAG: 0
IndexTAG: 1662
TitleTAG: To the lecturer et al of this course...
First, thanks for this great opportunity to learn properly something that I had 'hated' to study years ago.
I am a molecular neuroscientist but I also conduct some clinical research through collaborations in the field of infectious diseases.
I took this course to have a better understanding of the tools I am using to exploit the data...
Here is my questions. The Stat2.1x is going to last one month. I was wondering if you have any plans to pursue with Stat2.2x, 2.3x afterward on EdX? Just for curiosity, is there any Stat2.4x? Was there any Stat1.x?
Thanks again for your time and efforts for doing that generously!
Z.
UserIdTAG: 830835
UserNameTAG: Zacharie
CreateTimeTAG: 2013-03-01T05:24:01Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No Stat1.x, because the Berkeley intro course is numbered Stat 2, not Stat 1, for reasons I'm not sure about.
No Stat 2.4X, because we took Stat 2 which is a 15 week course and broke it into three five-week segments.
Yes, there will be a Stat 2.2X, at the moment expected to begin a couple of weeks after Stat 2.1X ends. Stat 2.3X will start a couple of weeks after 2.2X ends, I hope, but I don't have firm dates yet.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T05:55:31Z
FirstChildVoteTAG: 12
SecondChildTAG: Will these courses 2.1 through 2.3 cover the whole online textbook?
SecondChildUserIdTAG: 985667
SecondChildUserNameTAG: KymberlyKline
SecondChildCreateTimeTAG: 2013-03-04T06:09:11Z
SecondChildVoteTAG: 0
SecondChildTAG: That's excellent news :)
SecondChildUserIdTAG: 584390
SecondChildUserNameTAG: pluribus
SecondChildCreateTimeTAG: 2013-03-04T10:54:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Great news!! I'm sure we'd all appreciate even smaller breaks between the courses.
Will there be a Stat3.*x though? There are some pretty nice stat and probability courses over at Carnegie Mellon's OLI, but the edX format is much nicer, and though I have to play the video at 2x normal speed to keep focused, the lectures are really really well organized, and do a great job of making the concepts very very simple and easy to follow. Stuff I agonized over for hours during university is explained with brilliant simplicity here. Thank you for the great work! And back to the original question, will there be a Stat3.*x?
SecondChildUserIdTAG: 229679
SecondChildUserNameTAG: Ahsen
SecondChildCreateTimeTAG: 2013-03-10T18:08:59Z
SecondChildVoteTAG: 0
IndexTAG: 1663
TitleTAG: Unable to submit answers
The only option available is "show answer". I need to know what to do. It is very frustrating when this isn't working and you are trying to complete your assignments on time.
UserIdTAG: 1058288
UserNameTAG: Sharonchi
CreateTimeTAG: 2013-03-01T05:16:12Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: On time you say? The deadline was 27 February 23.30GMT and it was postponed to 28 Feb 23.30 GMT. You've missed two deadlines.
FirstChildUserIdTAG: 1314589
FirstChildUserNameTAG: Sebaall
FirstChildCreateTimeTAG: 2013-03-01T06:10:54Z
FirstChildVoteTAG: 2
IndexTAG: 1664
TitleTAG: can not submit my answers
Ive been trying for hours to submit my answers in several questions for quizzes 2 and 3.. but it just shows the "show/ hide answer" buttom...
UserIdTAG: 1281919
UserNameTAG: JorgeCar
CreateTimeTAG: 2013-03-01T05:00:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes, because the deadline has passed. Move on to week 2. And read the Course Info page.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T06:23:52Z
FirstChildVoteTAG: 0
IndexTAG: 1665
TitleTAG: Clarification
This is not a problem. Markov is not wrong.
**Every proportion in the world is at most 200%, since proportions are at
most 100%.**
When k is a fraction, Markov's bound is still correct as a bound.
Please explain what you mean by the bolded statement?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-03-01T04:55:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: "At most" is the same thing as "no more than." Every proportion is between 0 and 1, so it's between 0% and 100%, so it's no more than 100%, so it's no more than 200%. It's like asking a little kid his age and getting the answer, "I'm at most 100 years old." That statement is true. It's silly, but logically true. That's all I meant. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T05:41:49Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks for the reply. I thought I was reading it wrong.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-01T05:51:31Z
SecondChildVoteTAG: 0
FirstChildTAG: 100% is less than 200%. Therefore any proportion of the population is less than 200%.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-03-01T05:42:22Z
FirstChildVoteTAG: 0
IndexTAG: 1666
TitleTAG: UNABLE TO SUBMIT MY ANSWERS
I TRYED TO MANY TIMES AND IT DIDNT LET ME SUMBMIT THE ANSWERS, WHAT CAN I DO?
UserIdTAG: 893372
UserNameTAG: carolinacp
CreateTimeTAG: 2013-03-01T04:54:18Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Read the Course Info and the Discussion Forum Guide Lines.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T09:01:51Z
FirstChildVoteTAG: 2
IndexTAG: 1667
TitleTAG: Having challenges viewing Week 2 lectures
I am having challenges viewing week 2 lectures ie lecture 3.1 and 3.3, it tells me an error occured, please try later. I have done that several times with no response
I have opened in both Firefox and Google chrome.
Any help please.
Thanks
UserIdTAG: 417448
UserNameTAG: Oldzigi
CreateTimeTAG: 2013-03-01T04:27:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You should post in the relevant forum to make it easier for everyone.
I've been having trouble too. Some videos are just freezing and refusing to play. I've been watching on Youtube instead of the course page. Yesterday they weren't playing on Youtube either, today they are.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T04:35:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks and ChritineStv which is the relevant forum please?
FirstChildUserIdTAG: 417448
FirstChildUserNameTAG: Oldzigi
FirstChildCreateTimeTAG: 2013-03-01T04:47:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Every lecture and question page has its own forum. You used the forum for Exercise 1. Just go the bottom of the page you are on for the link.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-01T05:36:43Z
SecondChildVoteTAG: 0
IndexTAG: 1668
TitleTAG: Can't submit
add me to the list of people who can't submit answers.
UserIdTAG: 914146
UserNameTAG: RobertJS
CreateTimeTAG: 2013-03-01T04:26:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: But the deadline was hours ago. That's why you can't submit.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T04:34:42Z
FirstChildVoteTAG: 0
FirstChildTAG: > add me to the list of people who can't submit answers
And to those who didn't read the Prof's message on the Course Info page.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T04:37:21Z
FirstChildVoteTAG: 2
IndexTAG: 1669
TitleTAG: PROBLEM 6 They did not ask for percentage\???
Very clear they asked this> What percent of students spent fewer than 4 hours in preparation?
SO I put 10% and the system told me WRONG.. because they expected me to put 10 only without the sign of % .. that is unfair... and that is why I got the answer wrong!
:(
UserIdTAG: 705507
UserNameTAG: EdmundoIZ
CreateTimeTAG: 2013-03-01T04:22:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Read the Course Info, follow Course Updates and search the forum for similar problems and life won't seem to unfair anymore.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T09:04:52Z
FirstChildVoteTAG: 0
IndexTAG: 1670
TitleTAG: solutions to week 1
Hi,
i couldnt find the solutions to the exercises for week 1. please kindly assist.
many thanks,
nicole
UserIdTAG: 946512
UserNameTAG: nicoleha
CreateTimeTAG: 2013-03-01T04:20:15Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Ditto! I looked back on the exercises and there were no solutions, nor are they specifically listed under courseware.
katie
FirstChildUserIdTAG: 1027958
FirstChildUserNameTAG: ktmccusk
FirstChildCreateTimeTAG: 2013-03-01T06:55:26Z
FirstChildVoteTAG: 0
FirstChildTAG: she gave us an extra day. they will be out tomorrow
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-03-01T06:59:09Z
FirstChildVoteTAG: 0
SecondChildTAG: I know they are not out yet but give the prof a chance.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-01T22:16:16Z
SecondChildVoteTAG: 0
IndexTAG: 1671
TitleTAG: Exams
Hi!
I saw the dates for mid term and final exams. However, i was just told by my management that i am required to attend conference and course respectively on those two days.
Can i do the midterm on the 16th march and final exam on 22nd march instead please?
many thanks,
nicole
UserIdTAG: 946512
UserNameTAG: nicoleha
CreateTimeTAG: 2013-03-01T04:18:31Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: i have same problem for the midterm. Can some one help us? is there specific time during those days or we can do it any time on those days?
FirstChildUserIdTAG: 152907
FirstChildUserNameTAG: visperad
FirstChildCreateTimeTAG: 2013-03-01T08:39:21Z
FirstChildVoteTAG: 0
FirstChildTAG: I can't write the final because it's on Passover, my religious holiday. I'm very sad because I'm actually passing the course, to my surprise. But I'm not doing well enough to pass without taking the final.
FirstChildUserIdTAG: 310963
FirstChildUserNameTAG: TwinOtter
FirstChildCreateTimeTAG: 2013-03-01T16:38:33Z
FirstChildVoteTAG: 0
FirstChildTAG: The exams form 50% of the overall mark. If you miss both then you need to average 70% on the Exercise Sets in order to reach the 35% pass mark (and remember that the two lowest scoring sets are dropped from the average). After completing ES6 I am on 29% overall and would expect the reach the pass mark by the time I've done the next two ESs.
While I'd aim to get the best possible overall score, there is no real need to do any more than reach 35%. The exams assess learning but are not formative (ie they do not improve or embed learning) and in a course of this nature I find the Exercise Sets and associated Practices far more valuable. I certainly plan to take the exams but won't worry if I can't fit them in. If I were struggling to maintain a 70% average on the Exercises I'd be a little worried about at this point, regardless of exams.
Is it confirmed that the exams have to be taken in the single day indicated on the Course Schedule? Other courses allow a few days between release and submission, realising that most of us have real lives away from here.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-03-03T14:20:10Z
FirstChildVoteTAG: 2
SecondChildTAG: >Is it confirmed that the exams have to be taken in the single day indicated on the Course Schedule? Other courses allow a few days between release and submission, realising that most of us have real lives away from here.>
This is what I want to ask too. We will be allowed a whole day (or even two) for taking the exams or we will have specific times ? I think that a period or 2-3 days would work best for such a big and diverse group.
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-03T16:21:50Z
SecondChildVoteTAG: 0
IndexTAG: 1672
TitleTAG: Dreke
It will not let me submit my answers.
UserIdTAG: 830342
UserNameTAG: dreke89
CreateTimeTAG: 2013-03-01T04:16:35Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1673
TitleTAG: Dreke
It will not let me submit my answers.
UserIdTAG: 830342
UserNameTAG: dreke89
CreateTimeTAG: 2013-03-01T04:15:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The extended deadline ended Feb 28, 23:30 (GMT).
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-03-01T09:06:55Z
FirstChildVoteTAG: 0
IndexTAG: 1674
TitleTAG: Unable to submit answers for Excercise Set #3
Have tried several times and there is no button for submission evident. The only operative button present is "Hide Answer/Show Answer". It is now 23:14...
Thanks for making this course interesting. I am learning and enjoying the material.
UserIdTAG: 611869
UserNameTAG: bostonpatriot
CreateTimeTAG: 2013-03-01T04:15:05Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: You are past the deadline. Timezone is GMT, not EST (assuming you are in Boston because of your username).
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T04:37:14Z
FirstChildVoteTAG: 0
FirstChildTAG: And we went through this yesterday. The Prof even has an announcement explaining, and telling everyone to go *read the course policy*.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T04:40:50Z
FirstChildVoteTAG: 0
IndexTAG: 1675
TitleTAG: can't submit either
XS
UserIdTAG: 1326874
UserNameTAG: clast83
CreateTimeTAG: 2013-03-01T04:12:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was hours ago.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T04:37:28Z
FirstChildVoteTAG: 0
IndexTAG: 1676
TitleTAG: Fun question that comes to mind from lecture
In the dataset in which we had a mean age of 20, by Markov's inequality, at most 1/4 of the list were at or over 80. When we assumed an SD of 5, at most 1/144 were over 80 by Chebyshev's inequality.
Having an SD gives us much more information about how the data is bunched.
But I think it's also fun to consider the extremes. In a data set with three new borns and one 80 year old, the mean would be 20, exactly 1/4 would be 80 or over.
Without calculating, we know that our SD would be at least 30. That's b/c 80 is 2 SDs away from our mean, 20, and Chebyshev says no more than 1/4 can be two SDs away.
A quick calculation shows the SD in this extreme little dataset is 34.64. In this case, Markov actually gave us the tighter bound. Thought this was just a fun extreme to consider.
UserIdTAG: 1118146
UserNameTAG: 4learning
CreateTimeTAG: 2013-03-01T04:11:21Z
VoteTAG: 3
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 2
FirstChildTAG: With these calculations, Chebychef's result is that at most 33.33% of the values are 80 or over. Markov's is that at most 25% of the values are over 80. As we only have 4 values in our very extreme list, we always know that at most 1 of the values can be 80 or over. So they are **both** right. Right???
What a great question you posed, [4learning][1].
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/users/1118146
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-02T16:25:34Z
FirstChildVoteTAG: 0
SecondChildTAG: I believe you were right in the first part, as 80 is 4 times average, and in case of Markov's inequality we're looking at the threshold (80), no a difference between a threshold and mean (60).
SecondChildUserIdTAG: 517550
SecondChildUserNameTAG: Ewa_G
SecondChildCreateTimeTAG: 2013-03-06T13:46:40Z
SecondChildVoteTAG: 0
SecondChildTAG: You're right Ewa_G. I confused Chebychef and Markov and just messed everything up. For Markov: the proportion of entries that are at least as large as k times the average is at most 1/k so it should be 25%. I'll remove my incorrect amendment. And thank you for the feedback!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-06T17:03:10Z
SecondChildVoteTAG: 0
FirstChildTAG: I also thought it was not fair to compare Markov's bound to Chebychev's bound, the way the problem was presented the first time round. We were not given the SD at the time. So, with the data we were given, we could not do any better than the Markov's bound. And, exactly as 4learning suggests, the imprecision of Markov's bound compared to Chebychev's bound will depend on SD. Will post this too on the lecture discussion :)
FirstChildUserIdTAG: 634217
FirstChildUserNameTAG: taprokh
FirstChildCreateTimeTAG: 2013-03-04T00:14:58Z
FirstChildVoteTAG: 0
SecondChildTAG: I don't understand why you would say it is not fair?
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-04T16:12:02Z
SecondChildVoteTAG: 0
IndexTAG: 1677
TitleTAG: score declined
Though i have deposited the answers in exercise set 3,all were correct but today it appears like box graph set was not saved, so no marks allotted.What to do now?
UserIdTAG: 413576
UserNameTAG: drrakesh75
CreateTimeTAG: 2013-03-01T04:05:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1678
TitleTAG: Markov's Inequality Problem 6
I have seen a few posts where people do 1-1/5, I just need to know why they are subtracting one. The textbook shows:
Example 4-4: Applying Markov's inequality.
There are 200 students in a class. The average amount of money in their pockets is 15. How many could have 75 or more in their pockets?
Solution. No student can have a negative amount of money in his or her pocket, so Markov's inequality applies. Markov's inequality guarantees that
[fraction of students with at least $75 in their pockets] ≤ 15/75 = 0.2 = 20%.
Thus at most 20% of the students (40 students) could have $75 or more in their pockets.
I just don't see where the 1 is. I already got the question wrong, I just want to know why. Thanks!
UserIdTAG: 1018852
UserNameTAG: sansquamtch
CreateTimeTAG: 2013-03-01T04:00:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If I'm interpreting correctly, your question is different to the one posed. You ask how many have 75 or more in their pockets. But the question we actually had to deal with was how many had LESS than 75 in their pockets. Does that help?
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T04:33:09Z
FirstChildVoteTAG: 1
IndexTAG: 1679
TitleTAG: Histogram marked correct for 3b clearly wrong
On can quickly see that there are 6 groups but only 5 bars in the "correct" histogram.
One can quickly see from a) that the density of the 3rd group is 8.67; the density on the "correct" histogram for this group is ~0.25.
I posted about a similar issue in the first set of exercises. There have also been examples from the text book which mark correct answers incorrectly. What's up with all these errors???
UserIdTAG: 1119025
UserNameTAG: Dooie
CreateTimeTAG: 2013-03-01T03:56:09Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: Remember that depending on the units used, the actual numbers on the vertical axis could change. You have to look at the overall shape to see whether the histogram is plausible or not. That is, how do the areas of the bars relate to each other? Is this in line with the distribution of scores in your list or table? Also, the final bin in the drawing of the correct histogram actually includes two ranges of scores. So it is still correct. How you bin is technically up to you when you create a histogram.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T04:00:20Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes. I understand you could combine two ranges into one bin. I tried to see if that was how it became five bins instead of six. However, the height, and area, of the combined bin does not seem right. The data show a bimodal distribution--at least when in six bins. If you are right and this is the explanation, it brings up the interesting question of what would be ethical in this case. If people assume uniform distribution when looking at a histogram, is it ethical to 'hide' a peak in the data?
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T15:16:09Z
SecondChildVoteTAG: 0
SecondChildTAG: @Dooie, Perhaps edit the title of this thread to indicate that we don't understand the explanation of the correct answer? I'm thinking that this title might get lost in the volume of posts. Maybe something like==Explanation of 3b answer leaves more questions? It would be nice if post was noticed by Prof A.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T15:31:01Z
SecondChildVoteTAG: 0
SecondChildTAG: When I said bimodal--I guess I didn't precisely mean that because there is one mode in the data, but there is second relatively high frequency in one of the other ranges, a peak that is important to the interpretation of the data. The reader needs to know that there are peaks at the ages one graduates high school and college respectively.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T15:46:04Z
SecondChildVoteTAG: 0
FirstChildTAG: >One can quickly see from a) that the density of the 3rd group is 8.67
density $0.0867$, 4th group
![enter image description here][1]
I think this is what it should look like (above). Last bar is influenced by the upper limit (assumed to be 22)
![enter image description here][2]
What it was presented as.
[1]: https://edxuploads.s3.amazonaws.com/13621123061343624.png
[2]: https://edxuploads.s3.amazonaws.com/13621118261343635.png
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T04:27:19Z
FirstChildVoteTAG: 2
FirstChildTAG: I, too, am confused by this question and its explanation. I see that c is the only histogram because it is labeled correctly on the y axis. However, the math I did to get the heights of each bin indicate a histogram with two significant peaks. Also, I see six bins, as there are six intervals.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-03-01T15:10:19Z
FirstChildVoteTAG: 2
FirstChildTAG: Same concerns--would love to hear more explanation. Glad to see your responses above--I was doubting my math!
FirstChildUserIdTAG: 833174
FirstChildUserNameTAG: MES93
FirstChildCreateTimeTAG: 2013-03-12T03:19:02Z
FirstChildVoteTAG: 0
IndexTAG: 1680
TitleTAG: I'm unable to save and post my answers
even though it is due at 11:30 tonight. Please help!
UserIdTAG: 1164635
UserNameTAG: Ptorchia
CreateTimeTAG: 2013-03-01T03:51:48Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: 11:30 GMT is the deadline. I don't know your timezone but it is already 3:55am GMT on March 1.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T03:56:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Current time: Fri 1st March 3.50am GMT
So you missed the deadline. Please read the Course info page. this is all explained there.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T03:56:53Z
FirstChildVoteTAG: 0
IndexTAG: 1681
TitleTAG: Trying to Submit?
Hello - I am trying to submit but there is no submit button - what do I need to do?
UserIdTAG: 1179944
UserNameTAG: jackiecipolletta
CreateTimeTAG: 2013-03-01T03:43:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Me too!
FirstChildUserIdTAG: 611869
FirstChildUserNameTAG: bostonpatriot
FirstChildCreateTimeTAG: 2013-03-01T03:46:50Z
FirstChildVoteTAG: 0
FirstChildTAG: You need to go to the Course Info page and read what is there. And note where the Prof says:
>One point to note: there's only one Greenwich Mean Time. There isn't a GMT in every country, in spite of what some of you have been telling me.
Current time: Fri 1st March 3.50am GMT
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T03:48:50Z
FirstChildVoteTAG: 0
IndexTAG: 1682
TitleTAG: Number of submissions
On all problems, the number of submissions should be 2. Sometimes, we just type something incorrect and get a wrong answer even though we know how to solve the problem.
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-01T03:28:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1683
TitleTAG: Lectures videos
Hello:
Well, I´m not sure whether this has been said already, but...
1-Why don´t you make some forums so as there wouldn´t be maaany posts, some about more or less the same topic (as mine lol).
2- The structure of the course as displayed in courseware sometimes confound me. For example, in the second video of prof A, she said that the income table has been used a lot...really? i never saw it before,not with her. Am I losing something or is she refering to the lectures with her assistant?
Thx.
UserIdTAG: 1262090
UserNameTAG: Danonino
CreateTimeTAG: 2013-03-01T03:26:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: > she said that the income table has been used a lot...really? i never saw it before,
So you didn't watch the first week's lectures?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T03:27:36Z
FirstChildVoteTAG: 0
SecondChildTAG: I also missed some lectures by prof A. Sometimes there is more than one lecture, as indicated in the title, for example Lec 3.1 - 3.3. After watching the introduction, you can go to lecture 3.1 by clicking on the right black arrow (triangle) at the bottom of the page (or at the top of the page where you see an overview of the videos). After lecture 3.1 you continue with lecture 3.2 and then 3.3.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-06T09:58:22Z
SecondChildVoteTAG: 0
FirstChildTAG: I also missed some lectures by prof A. Sometimes there is more than one lecture, as indicated in the title, for example Lec 3.1 - 3.3. After watching the introduction, you can go to lecture 3.1 by clicking on the right black arrow (triangle) at the bottom of the page (or at the top of the page where you see an overview of the videos). After lecture 3.1 you continue with lecture 3.2 and then 3.3.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-06T09:59:18Z
FirstChildVoteTAG: 0
IndexTAG: 1684
TitleTAG: exercise set 3
I could not save and post the answers.It is due by 28 at 23:30
UserIdTAG: 920059
UserNameTAG: Yeshitila46
CreateTimeTAG: 2013-03-01T03:24:37Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: And it is currently: Fri 1st March 3.28am GMT. Well beyond 23.30.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T03:28:40Z
FirstChildVoteTAG: 1
IndexTAG: 1685
TitleTAG: Broken link - Lec4.3 Slides?
I am unable to download the Lecture 4.3 Slides. The pdf is not opening/damaged. Are you having similar problems? Is the link broken? Any ideas?
Thanks in advance.
UserIdTAG: 190804
UserNameTAG: rito
CreateTimeTAG: 2013-03-01T03:23:22Z
VoteTAG: 0
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 1
FirstChildTAG: Downloads for me. Chrome. Win8
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T03:29:40Z
FirstChildVoteTAG: 0
IndexTAG: 1686
TitleTAG: Need help for problem 8
can any body help me for calculating average of 32 houses cost.
Should i consider $834000 as average cost of house?
Thanks in advance.
UserIdTAG: 393580
UserNameTAG: Aditiak
CreateTimeTAG: 2013-03-01T03:14:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 8
FirstChildTAG: 834,000 is the cost of 1 house, than that one house drops to 819,000. You just have to answer how much that would effect the total average.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-03-01T03:21:32Z
FirstChildVoteTAG: 2
SecondChildTAG: so the difference should multiplied by 32 then would be changes in average. But still had wrong answer.. please
explain.
SecondChildUserIdTAG: 688322
SecondChildUserNameTAG: kiranpiparva
SecondChildCreateTimeTAG: 2013-03-01T11:08:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually, you divide the difference because only one house drops the price, not every house and this way the mean is reduced in a 1/32 of the difference. If every house droped tha amount, the mean would drop that same amount.
SecondChildUserIdTAG: 945542
SecondChildUserNameTAG: Fingusmingus
SecondChildCreateTimeTAG: 2013-03-01T11:40:59Z
SecondChildVoteTAG: 0
SecondChildTAG: So, would it be like this: Substract new (reduced) price from old price and than divide that difference with 31..I am going to have an interesting day thinking just about this. Help pleaseeeeeee
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-01T14:26:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Not 31, the house has not been removed from the list...
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-01T14:40:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot. Now i have to press submit.Moment.......
I have done it. It is correct answer:)) . Oh, i thougt it is something soooo complicated, but it is quit easy when you focus.
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-03-01T14:52:18Z
SecondChildVoteTAG: 0
SecondChildTAG: is the total average 834,000$ ?? am little confused..!
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-03-01T17:34:31Z
SecondChildVoteTAG: 0
SecondChildTAG: There are two averages:
Average 1 (if the house remained at its price)
Average 2 (as the price of the house changes)
Av1= (31 houses of a given price x + 834000) / 32
Av1= (31x+834000)/32
Av2= (31 houses of a given price x + 819000) / 32
Av2= (31x+819000)/32
> By how much does this change the average price of the 32 houses?
What is the difference between Av2 and Av1.
Av2-Av1=((31x+819000)-(31x+834000))/32
I Hope I helped
SecondChildUserIdTAG: 404119
SecondChildUserNameTAG: tkboing
SecondChildCreateTimeTAG: 2013-03-01T17:57:09Z
SecondChildVoteTAG: 0
SecondChildTAG: You must check your answer, they said: "One of the house", all the others should have the same prize
SecondChildUserIdTAG: 654914
SecondChildUserNameTAG: Fenixhc
SecondChildCreateTimeTAG: 2013-03-04T06:44:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Questions are worded badly so their meaning is ambiguous. Could be much improved by use of the word 'each'
FirstChildUserIdTAG: 6563
FirstChildUserNameTAG: mvdh
FirstChildCreateTimeTAG: 2013-03-01T09:51:04Z
FirstChildVoteTAG: 2
SecondChildTAG: I found it to be quite clear. The price is for one of the houses not for each but that doesn't matter anyway.
SecondChildUserIdTAG: 389451
SecondChildUserNameTAG: senta
SecondChildCreateTimeTAG: 2013-03-01T10:40:14Z
SecondChildVoteTAG: 0
SecondChildTAG: 834000 AND 819000 ARE BOTH AVERAGES;YOU JUST HAVE TO DO THE DIFFERENCE TO FOUND OUT THE AMOUNT FROM WHICH THE PRICE OF HOUSES DECREASE AND DIVIDE THIS DIFFERENCE BY 32. sorry for my poor english, am a french speaker
SecondChildUserIdTAG: 935205
SecondChildUserNameTAG: memekeng
SecondChildCreateTimeTAG: 2013-03-02T11:04:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Did just that and still got wrong!
SecondChildUserIdTAG: 865969
SecondChildUserNameTAG: Shanatova
SecondChildCreateTimeTAG: 2013-03-02T11:17:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I am unable to understand the question, because, what i have understood from the question is find the difference of two nos. 834000 and 819000 and that is the answer, but it is marking incorrect, don't understand, why
SecondChildUserIdTAG: 547024
SecondChildUserNameTAG: gauravanand
SecondChildCreateTimeTAG: 2013-03-02T14:48:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Re memekeng's post, $834K and $819K are not averages, they are the individual price of one house (which changes) among the total number of 32 houses. You want to think about how that change in price of one house will be "distributed" among the others to get a new overall average. Hope this is helpful.
SecondChildUserIdTAG: 773223
SecondChildUserNameTAG: Andaponte
SecondChildCreateTimeTAG: 2013-03-03T04:58:51Z
SecondChildVoteTAG: 0
SecondChildTAG: no .. actually you should find the difference in AVERAGE so we need to find difference then average of this difference i guess :)
SecondChildUserIdTAG: 475264
SecondChildUserNameTAG: chrisi
SecondChildCreateTimeTAG: 2013-03-03T16:00:52Z
SecondChildVoteTAG: 0
SecondChildTAG: find the correct difference and then think of average.
check for sign.
SecondChildUserIdTAG: 344764
SecondChildUserNameTAG: abhijitpawar
SecondChildCreateTimeTAG: 2013-03-03T16:09:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Remember there is a drop in price !!!!
SecondChildUserIdTAG: 684743
SecondChildUserNameTAG: subhashisa
SecondChildCreateTimeTAG: 2013-03-04T11:28:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Just assume you know the average. Name it Y1 and Y2. Make a calucation with X (sum of other houses) and the price of that one house. This is the longest way but you will realize what this is all about. All needed numbers are given in this question. :)
SecondChildUserIdTAG: 1009052
SecondChildUserNameTAG: AgataK
SecondChildCreateTimeTAG: 2013-03-04T22:52:08Z
SecondChildVoteTAG: 0
FirstChildTAG: First calculate how much the final cost of the total amount is reduced by, due to the fall in price of the house. Then spread this amount over the total number of houses.
FirstChildUserIdTAG: 92101
FirstChildUserNameTAG: DarylHickey
FirstChildCreateTimeTAG: 2013-03-01T10:17:15Z
FirstChildVoteTAG: 5
FirstChildTAG: One of the sample problems was almost identical to this one.
FirstChildUserIdTAG: 70894
FirstChildUserNameTAG: dantegl36
FirstChildCreateTimeTAG: 2013-03-01T23:58:25Z
FirstChildVoteTAG: 0
FirstChildTAG: First consider how much the price dropped because of the change. This reflects for that one house. This can be 1/32 of the average. Consider the sign when submitting the answer
FirstChildUserIdTAG: 569767
FirstChildUserNameTAG: SanjayS72
FirstChildCreateTimeTAG: 2013-03-02T15:24:26Z
FirstChildVoteTAG: 1
FirstChildTAG: You maybe getting the right answer but you may not be entering it the right way!
> Please be careful how you enter your answer. Here’s the model to
> follow: if you think the average goes up by $5, enter 5; if you think
> the average stays the same, enter 0; if you think the average goes
> down by $5, enter -5.
FirstChildUserIdTAG: 254949
FirstChildUserNameTAG: stormshadow
FirstChildCreateTimeTAG: 2013-03-02T15:35:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Problem 8 is definitly not formulated in a unique way. It should say, that only the price for ONE house is dropped.
FirstChildUserIdTAG: 949358
FirstChildUserNameTAG: nfa019
FirstChildCreateTimeTAG: 2013-03-02T15:36:00Z
FirstChildVoteTAG: 0
SecondChildTAG: All that information is provided in one sentence. The "one of the houses" at the beginning of the sentence will naturally refer to all aspects contained in it. Hope that helps...
SecondChildUserIdTAG: 1250448
SecondChildUserNameTAG: BHeaton
SecondChildCreateTimeTAG: 2013-03-02T18:08:44Z
SecondChildVoteTAG: 0
FirstChildTAG: i entered -468.75 ((819000-834000))/32 in the first submission, and it got wrong but dont know the reason...
FirstChildUserIdTAG: 1284639
FirstChildUserNameTAG: aquaankit
FirstChildCreateTimeTAG: 2013-03-07T14:14:14Z
FirstChildVoteTAG: 0
IndexTAG: 1687
TitleTAG: to Staff
Dear Staff,
it is possible to have pdf file that can be printed without any repetition in the text. I tried to print lecture 1.1 but in total there are 28 slides, each slide contains only one additional sentences. Is this because of copyright that there is no printed material available? I also tried to print sticiqui but the printed result is not good enough for me to learn.
This is probably my last post in complaining about lack of materials to study in this course ( i have written two separate posts about this). I have done Ph207x course by Harvard Edx, and I really appreciated the resources they have provided in that course. I would expect the same standard for other edx course, but I am quite disappointed with this one.
UserIdTAG: 199205
UserNameTAG: ririana
CreateTimeTAG: 2013-03-01T03:13:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you go to course wiki and click on lecture notes, you will then be able to print PDF slide by slide. You do so by clicking each page until all the dialogue for that page appears. Then, print away. Did it today in fact.
FirstChildUserIdTAG: 611869
FirstChildUserNameTAG: bostonpatriot
FirstChildCreateTimeTAG: 2013-03-01T03:50:05Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks bostonpatriot, i have downloaded the pdf file, yeah I might have to select which page I want to print one by one
SecondChildUserIdTAG: 199205
SecondChildUserNameTAG: ririana
SecondChildCreateTimeTAG: 2013-03-01T03:58:18Z
SecondChildVoteTAG: 0
IndexTAG: 1688
TitleTAG: Intervals included with endpoints
With the data, I noticed it states intervals include the left end point but not the right end point.
Lets say the data was 20-30, 30-40, 40-50, etc.
Wouldn't it be easier to state, 20-29, 30-39 and 40-49 and one would not have to worry about what endpoint are included in the data?
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-03-01T02:52:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: What about 29.5?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T03:23:19Z
FirstChildVoteTAG: 0
SecondChildTAG: You have a valid point.
SecondChildUserIdTAG: 277481
SecondChildUserNameTAG: scott520
SecondChildCreateTimeTAG: 2013-03-01T03:30:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Scott520, you raise an understandable question in the case where the data are genuinely discrete, as is often the situation with exam scores, say. The reason for writing the intervals in the way we do is that eventually we're going to want to approximate them with smooth curves, and then we really don't want to have gaps between bars. You'll start seeing such approximations in Week 3. Stay tuned ...
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T05:52:33Z
FirstChildVoteTAG: 0
IndexTAG: 1689
TitleTAG: Problem in submitting set 3
Prof.Adhikari,
Thank you for such an interesting course and for extending the deadline by one more day. I tried to make good use of this opportunity and submitted set 1 and 2. I accessed the exercise set 3 at around 20:00 GMT. However my answers could not be submitted.I had internet connectivity at that time but the edx.org site did not operate. I kept on trying for a long time however the site did not operate. Is it possible to submit another exercise on part 3?
Regards,
UserIdTAG: 1286164
UserNameTAG: SmitaNair
CreateTimeTAG: 2013-03-01T02:42:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Hi there!
Well i have the same problem...thus this happens since 17:00 hrs SmitaNair, now i made a mistake.. i click on 'show answers' after writing my own ones and now it looks like i haven't submitted anything!!!... no scores =(. and i have this problem with set 2 and 3...
We really need help about time.
FirstChildUserIdTAG: 1288656
FirstChildUserNameTAG: Damaritos
FirstChildCreateTimeTAG: 2013-03-01T03:05:00Z
FirstChildVoteTAG: 0
FirstChildTAG: > We really need help about time.
This was done to death yesterday. Did you read the Course Policy as asked? The timezone is GMT.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T03:25:08Z
FirstChildVoteTAG: 0
IndexTAG: 1690
TitleTAG: Question 2b)
The median is (80+81)/2,here and everywhere, not just the 14th value.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-01T02:40:10Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Did you watch lecture? There are many definitions. This course uses the one in the lecture. If you object to the definition, fine. Just don't expect to be give a green tick.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T02:44:09Z
FirstChildVoteTAG: 0
IndexTAG: 1691
TitleTAG: Submissions
Yup, 8:27 in Mexico and I can´t submit my homework...
UserIdTAG: 1262090
UserNameTAG: Danonino
CreateTimeTAG: 2013-03-01T02:27:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 1692
TitleTAG: Problem 7
How many months does the campaign last? Or is that number somehow irrelevant?
UserIdTAG: 249940
UserNameTAG: damcevski
CreateTimeTAG: 2013-03-01T02:16:11Z
VoteTAG: 8
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: It's not relevant - the question just asks how much more they have to raise.
FirstChildUserIdTAG: 1133176
FirstChildUserNameTAG: sc2014
FirstChildCreateTimeTAG: 2013-03-01T02:41:10Z
FirstChildVoteTAG: 1
SecondChildTAG: Is the average per member (likely) or is the average per month (less likely)? If it is average per month, the question "how many months does a campaign last?" is definitely relevant.
What is 5200? Is it the average of the amount raised by 12 members? Likely...
SecondChildUserIdTAG: 1139936
SecondChildUserNameTAG: SundarV
SecondChildCreateTimeTAG: 2013-03-01T15:45:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, no. I don't know, but I assumed that the rest is following 11 months, and that campaign is for a year. And i failed at that.
The total amount of money that is needed is also not an answer.
SecondChildUserIdTAG: 404119
SecondChildUserNameTAG: tkboing
SecondChildCreateTimeTAG: 2013-03-01T17:47:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Remember that the mean times the number of occurrences is the total number.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T17:58:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Forget months. Nothing is said in the problem statement about months or the duration of the fund raising campaign. What matters is the number of members.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-01T23:24:32Z
FirstChildVoteTAG: 2
IndexTAG: 1693
TitleTAG: Negative numbers and Markov
If you have an average and the lowest negative number in the distribution can you still use Markov's inequality by adding the absolute value of the lowest number to the average and the number you are trying to find out?
It does work for 4 x -5 and 1x75. (average 11. trying to find 75.)
16average - 80find. 80/16=5 . 1/5 is 20% and is equal to the number of 75s in the distribution.
I just don't know how it works in the general case.
UserIdTAG: 1174310
UserNameTAG: Catprog
CreateTimeTAG: 2013-03-01T02:03:26Z
VoteTAG: 1
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3.5: Markov’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: First time I am hearing and learning about. Finding it to understand very difficult.
FirstChildUserIdTAG: 1236052
FirstChildUserNameTAG: neelam25
FirstChildCreateTimeTAG: 2013-03-02T16:58:02Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Catprog.
That would be a nice way to go around the "non-negative distribution" constraint. However, one should not forget that computing averages of negative numbers is very different from their positive conterparts, e.g. average of -2 and 4: ((-2)+4)/2=1
And this is very different from average of 2 and 4 which is 3.
But I am pretty sure Prof. A has a handful of alternative solutions for calculating proportions in negative distributions, don't you Professor Ani Adhikari?
Cheers,
Tiago.
FirstChildUserIdTAG: 1157163
FirstChildUserNameTAG: sousaveloso
FirstChildCreateTimeTAG: 2013-03-03T09:42:28Z
FirstChildVoteTAG: 0
IndexTAG: 1694
TitleTAG: Full size window
Does anybody know why if I want to use a full size window, I can´t see the bottom of the video?? For example at the begining of this video, if I use the full size window, I can´t see all that it is above the x axis of the histogram
UserIdTAG: 557505
UserNameTAG: dmenendezv
CreateTimeTAG: 2013-03-01T01:58:37Z
VoteTAG: 2
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.1: The median and the mode
NumberOfReplyTAG: 3
FirstChildTAG: I am using Internet Explorer (IE) and have the same problem, as it is recommended to use Chrome or Firfox, using the recommnded browsers you probably will not get that problem.
I increase the IE zoom to 200% in tools which helps.
If you are using the recommended browsers and still having the problem, sorry cannot help you.
FirstChildUserIdTAG: 910962
FirstChildUserNameTAG: SpirosP
FirstChildCreateTimeTAG: 2013-03-01T06:26:03Z
FirstChildVoteTAG: 0
SecondChildTAG: Same problem on firefox newest version
SecondChildUserIdTAG: 127421
SecondChildUserNameTAG: apbyte
SecondChildCreateTimeTAG: 2013-03-01T10:59:49Z
SecondChildVoteTAG: 0
SecondChildTAG: I am using Chrome, so I don´t think that´s the problem..
SecondChildUserIdTAG: 557505
SecondChildUserNameTAG: dmenendezv
SecondChildCreateTimeTAG: 2013-03-01T17:53:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Same problem, but somehow you can almost fix it if you go to the full screen mode (at least in firefox) with the browser.
SecondChildUserIdTAG: 507259
SecondChildUserNameTAG: mruz
SecondChildCreateTimeTAG: 2013-03-01T17:54:02Z
SecondChildVoteTAG: 0
SecondChildTAG: It happens with all the videos, not only this one.Does the staff read this discussions?
SecondChildUserIdTAG: 557505
SecondChildUserNameTAG: dmenendezv
SecondChildCreateTimeTAG: 2013-03-01T22:59:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Hit F11 to make your browser window full-screen, then you will see the bottom.
FirstChildUserIdTAG: 990430
FirstChildUserNameTAG: gsullivan
FirstChildCreateTimeTAG: 2013-03-02T18:35:55Z
FirstChildVoteTAG: 0
FirstChildTAG: Use the fill browser(double rectangle icon below the video) and then enlarge the browser to the maximum and this will prevent the problem (rather than the full screen method)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T15:07:10Z
FirstChildVoteTAG: 0
IndexTAG: 1695
TitleTAG: Graded Exercises Score
First of all, a big THANKS for the extremely useful course arranged free online with so much efforts.
It is a sincere request to kindly allow one more score to be dropped from scoring as done in earlier courses. It can be done by adding one more optional exercise set again as per earlier courses.
As noticed and highly appreciated, the staff has already made the deadlines flexible and extended the first deadline to Thursday in the interest of the students.
I think one more optional exercise set will help out those students who registered late or who still faced some issues during the first week.
Please consider the request.
Also, request for fellow colleagues to please vote for this post if you feel that it is correct.
Thanks
UserIdTAG: 647027
UserNameTAG: crstudent
CreateTimeTAG: 2013-03-01T01:58:08Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I second this request.
FirstChildUserIdTAG: 1327140
FirstChildUserNameTAG: AMunad
FirstChildCreateTimeTAG: 2013-03-01T05:45:28Z
FirstChildVoteTAG: 0
FirstChildTAG: You only need 35% to pass this course. So you could miss *every* weekly assessment and still pass.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T06:30:28Z
FirstChildVoteTAG: 0
IndexTAG: 1696
TitleTAG: Problem 6
I do not understand why my answer in problem 6 is wrong.
6.2/15.5 =0.4
since we want to know how many employees commute distance less than 15.5 miles so 1-0.4=0.6
82 employees *0,6 = 49.2
Doing by other method, 15.5 -6.2 = 9.3
9.3/6.2 = 1.5 SD
1/2.25 = 0.444
since we want to know how many employees commute a distance of 15.5 or less and no the number of employees that commute a distance more than 15.5 so we do the following:
(1-0.444)*-1 =0.556
82 employees * 0,556= 45.6
so the answer of problem 6 is "more than 45"
Prof. A please help me with this.
Sincerelly
Marcela G.
UserIdTAG: 1054170
UserNameTAG: Chela29
CreateTimeTAG: 2013-03-01T01:53:52Z
VoteTAG: 7
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 5
FirstChildTAG: You have to select ALL the answers that you think correct.
FirstChildUserIdTAG: 653718
FirstChildUserNameTAG: Ranchu
FirstChildCreateTimeTAG: 2013-03-01T01:57:41Z
FirstChildVoteTAG: 2
SecondChildTAG: You're right. But more than 45 means also more than 25 and 35. But it's my fault I didn't read the question good enough too.
SecondChildUserIdTAG: 982348
SecondChildUserNameTAG: joschr
SecondChildCreateTimeTAG: 2013-03-01T11:46:43Z
SecondChildVoteTAG: 0
SecondChildTAG: It's not justified at all. Because since 'more than 45' is in the list, 'more than 25' and 'more than 35' options obviously not correct. I can't see any point to select all. 'More than 45' is the best possible answer.I would select all only if it would have been asked for 'select which can be true? among the option?'. Requesting to restate the question. Thanks
SecondChildUserIdTAG: 936512
SecondChildUserNameTAG: Roqib
SecondChildCreateTimeTAG: 2013-03-01T14:51:33Z
SecondChildVoteTAG: 0
SecondChildTAG: You have less than 3 heads. You have less than 2 heads. Both statements are correct.
SecondChildUserIdTAG: 901248
SecondChildUserNameTAG: mercury9
SecondChildCreateTimeTAG: 2013-03-01T19:38:52Z
SecondChildVoteTAG: 0
SecondChildTAG: I thought it was reasonably clear but could we also not make it as blindingly obvious what the correct answer is in the discussion please?
SecondChildUserIdTAG: 993192
SecondChildUserNameTAG: mitorious
SecondChildCreateTimeTAG: 2013-03-02T12:58:07Z
SecondChildVoteTAG: 0
SecondChildTAG: You are giving away too much information prior to submission due date.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-02T18:18:08Z
SecondChildVoteTAG: 0
SecondChildTAG: @mercury9 - Less than three heads can be 0,1,2 BUT less than 2 heads can be 0 ,1. So how can both be same?
SecondChildUserIdTAG: 865969
SecondChildUserNameTAG: Shanatova
SecondChildCreateTimeTAG: 2013-03-02T19:24:35Z
SecondChildVoteTAG: 0
SecondChildTAG: How did you arrive at 1.5 SD? I dont think you can just divide 9.3 by 6.2 and say SD is 1.5. There is not enough data to calculate SD. Therefore, you can only use the Markov Inequality formula.
SecondChildUserIdTAG: 877817
SecondChildUserNameTAG: sreedhara
SecondChildCreateTimeTAG: 2013-03-04T02:35:38Z
SecondChildVoteTAG: 0
SecondChildTAG: I was also wondering about the giving away of the answer before the submission date. That being said, I think we are over analyzing the answer. We are required to tick ALL that we think are correct so if you calculate your answer to be 38 for example, then tick more than 25 and more than 35. Go with your gut instincts, check back at the text and the videos and confidently submit your answer.
SecondChildUserIdTAG: 1278020
SecondChildUserNameTAG: DaleSteph29
SecondChildCreateTimeTAG: 2013-03-04T10:59:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Agree with Shanatova, that when the word "less" is used rather than "more", it has the additional restriction that "less than 3" includes 0, 1, and 2 so it's not the same as "less than 2" which can only be 0 and 1. I think this problem was needlessly complicated when it tried to combine two concepts by switching the wording and using "at least 15.5 miles" instead of "more than 15.5 miles" AND then threw in an additional concept. For me, it was hard to figure out which of two concepts were being tested. It turned out to be both, a realization that I didn't make until after I submitted the answer. Not sure if it really measures what I actually understand.
SecondChildUserIdTAG: 937396
SecondChildUserNameTAG: m2foster
SecondChildCreateTimeTAG: 2013-03-04T13:10:48Z
SecondChildVoteTAG: 0
FirstChildTAG: Why did you do 1 - 0.4
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-03-01T03:48:14Z
FirstChildVoteTAG: 0
SecondChildTAG: Because the question was "How many employees have a commute distance of **less** than 15.5 miles?". The fraction of emplyers with distance **more** then 15.5 miles is 6.2/15.5=0.4, so the fraction with less then 15.5 is 1-0.4.
SecondChildUserIdTAG: 1148146
SecondChildUserNameTAG: Prostova
SecondChildCreateTimeTAG: 2013-03-01T10:02:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Prostova,
Thank you for the explanation. Can you say what underlying concept should be used to come to that conclusion. I'm having a very hard time moving between the **less** than/**greater** than assignment and how it converts to a ration and 1-ratio. I always seem to get it backwards and really require additional practice in this area.
SecondChildUserIdTAG: 1186269
SecondChildUserNameTAG: jhsmith
SecondChildCreateTimeTAG: 2013-03-02T00:32:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Here we can use Markovs inequality witch can show us the **fraction** of data in the list that is **greater or equal** to particular value. Let us see - we have some list of values and know only its average and nothing else about it. Actually Markov inequality shows maximum possible part (or fraction - let us call it P) of values in the list that are equal or larger then given value (or threshold - let us call it X) knowing only average. How it works? It is heuristic, means not exact and used to weigh roughly, as Prof.A said in lecture 4.3. Totally, summ of fractions of all values is 100%. This 100% contain fraction of values less then X + fraction of values equal and more then X. Markov observed that (fraction of values in the list that are equal or more then X) can not be greater then average (let ua call it M) divided with value X (peculiarly, isnt it). So we have Markov inequality P<(or equal)to M/X. In terms of Problem 6, we can find what could be the maximum fraction of employers that have 15.5 and more miles from home. But the question was to find **the number** of employers that have less then 15.5 miles from home. We can find **the fraction** of these happy employers. As we known this fraction will be 100% (all employers) minus fraction of employers that have 15.5 miles and more from home. Knowing total number of employers we can find number of guys knowing their fraction from total 100%.
I hope this helps!
Wish you Good Luck and having pleasure of making things out!
SecondChildUserIdTAG: 1148146
SecondChildUserNameTAG: Prostova
SecondChildCreateTimeTAG: 2013-03-04T15:46:37Z
SecondChildVoteTAG: 0
FirstChildTAG: People, I have a feeling that this thread is not respecting the honour code. Aren't you discussing the results of exercises that are still available for submission? I made the mistake yesterday of answering someone's question on the same exercise because I thought they were asking about week 1 exercises and I was scolded accordingly. (I promptly removed my post). If I'm being too strict, I'd like to know. Thanks.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T17:38:25Z
FirstChildVoteTAG: 1
SecondChildTAG: Indeed it is violating the honor code and the answer should be removed from the discussion.Luckily since the perosns ae having doubts the exact answer is not technically released !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-01T19:08:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Is it possible to remove post? I thought about the same. I posted it with aim to help and after posting realised that it was against honor code.
SecondChildUserIdTAG: 1148146
SecondChildUserNameTAG: Prostova
SecondChildCreateTimeTAG: 2013-03-03T18:41:33Z
SecondChildVoteTAG: 0
FirstChildTAG: I think the correct answer is "more than 45".
FirstChildUserIdTAG: 996971
FirstChildUserNameTAG: ntanhhong
FirstChildCreateTimeTAG: 2013-03-03T15:37:27Z
FirstChildVoteTAG: 0
SecondChildTAG: You should not post direct "answers " as it violates the honor code and worse still can mislead others especially if you are wrong!!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-04T08:37:19Z
SecondChildVoteTAG: 0
FirstChildTAG: The answer cannot be posted till the week is over but think of boundaries and the bound conditions. Also remember if 2>4 it is also>3. I think if I tell any thing more it will break the honor code :)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-04T08:35:28Z
FirstChildVoteTAG: 0
IndexTAG: 1697
TitleTAG: I don´t understand
Why the system keep saying "you have used 0 of 1 submissions?, What should I do to submit the answers?
UserIdTAG: 1325045
UserNameTAG: Sheny
CreateTimeTAG: 2013-03-01T01:47:01Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For week 1, nothing. As the deadline has passed. For week 2, click Check to submit.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T01:58:27Z
FirstChildVoteTAG: 0
IndexTAG: 1698
TitleTAG: Video script please.
It is very supportive for our understanding by watching video. But here has the high constraint on telecommunication infrastructure. I cant watch the video continuously. I have to repeated “play”mode while I was watching. Although I tried at mid night, it is not better connection.
Therefore I have to rely on the video scripts and lecture slides although it is hard for me to understanding 100%.
Therefore let me have the video script for this section, please.
Thanks and regards,
Lai Lai
UserIdTAG: 254503
UserNameTAG: LaiLai
CreateTimeTAG: 2013-03-01T01:44:55Z
VoteTAG: 1
CoursewareTAG: Section 4: Measures of spread / Lec 4.3: Properties of the SD; Chebychev’s inequality
NumberOfReplyTAG: 2
FirstChildTAG: As it says on the Course Info page:
>Please note also that Lec 4.1-4.3 have been uploaded without transcripts. Transcripts will be uploaded in the next day or so, at a conservative estimate.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T01:57:19Z
FirstChildVoteTAG: 0
SecondChildTAG: Also, LaiLai, stop duplicating your posts. It is not necessary.
SecondChildUserIdTAG: 1253130
SecondChildUserNameTAG: Eternalight
SecondChildCreateTimeTAG: 2013-03-01T02:10:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Eternal, its because the connection i think.
SecondChildUserIdTAG: 1193006
SecondChildUserNameTAG: makmursp
SecondChildCreateTimeTAG: 2013-03-01T03:52:40Z
SecondChildVoteTAG: 0
SecondChildTAG: true. Because of our poor connection.
SecondChildUserIdTAG: 254503
SecondChildUserNameTAG: LaiLai
SecondChildCreateTimeTAG: 2013-03-05T08:44:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you very much for the script. Sorry for duplicate post if happened. I just posted in the sections when the script is not available. Apology !
FirstChildUserIdTAG: 254503
FirstChildUserNameTAG: LaiLai
FirstChildCreateTimeTAG: 2013-03-05T08:44:09Z
FirstChildVoteTAG: 0
IndexTAG: 1699
TitleTAG: Video script please.
It is very supportive for our understanding by watching video. But here has the high constraint on telecommunication infrastructure. I cant watch the video continuously. I have to repeated “play”mode while I was watching. Although I tried at mid night, it is not better connection.
Therefore I have to rely on the video scripts and lecture slides although it is hard for me to understanding 100%.
Therefore let me have the video script for this section, please.
Thanks and regards,
Lai Lai
UserIdTAG: 254503
UserNameTAG: LaiLai
CreateTimeTAG: 2013-03-01T01:44:20Z
VoteTAG: 2
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 2
FirstChildTAG: I agree, having the subtitle files to download would be nice.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-03-02T12:16:27Z
FirstChildVoteTAG: 0
SecondChildTAG: For me, Downloading is very time consuming. I just copy the video script and paste in the word which can finish within 2-3 mins.
SecondChildUserIdTAG: 254503
SecondChildUserNameTAG: LaiLai
SecondChildCreateTimeTAG: 2013-03-05T08:47:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Sorry for double post. I loaded from phone and did not notice about it. Please accept my apology. Thank you for the script.
FirstChildUserIdTAG: 254503
FirstChildUserNameTAG: LaiLai
FirstChildCreateTimeTAG: 2013-03-05T08:46:36Z
FirstChildVoteTAG: 0
IndexTAG: 1700
TitleTAG: Video script please
It is very supportive for our understanding by watching video. But here has the high constraint on telecommunication infrastructure. I cant watch the video continuously. I have to repeated “play”mode while I was watching. Although I tried at mid night, it is not better connection.
Therefore I have to rely on the video scripts and lecture slides although it is hard for me to understanding 100%.
Therefore let me have the video script for this section, please.
Thanks and regards,
Lai Lai
UserIdTAG: 254503
UserNameTAG: LaiLai
CreateTimeTAG: 2013-03-01T01:43:50Z
VoteTAG: 2
CoursewareTAG: Section 4: Measures of spread / Lec 4.1: Range and interquartile range
NumberOfReplyTAG: 0
IndexTAG: 1701
TitleTAG: Problem 4
Problem 4
Refer to the box plots in Problem 3.
: 4.0 POINTS
Compare experiments 4 and 5. When drawn on the same scale, the histogram for one of them has a noticeably higher peak the histogram for the other. From the box plots alone, can you tell which one has the higher peak?
Experiment 4
Experiment 5
I have a right answer (Experiment 5) but I missed the the GMT again. I loss 4 points !!
If you don't believe me you can check my post on Feb. 27, 2013
Cheer up
Bill
UserIdTAG: 967906
UserNameTAG: Billchau2013
CreateTimeTAG: 2013-03-01T01:17:14Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1702
TitleTAG: Extending time
Last night many had missed the GMT; including myself. I was a little frustrated (with myself) and I understand that it was my responsibility and I accepted that last night.
Tonight I was frustrated. It seems that there was an extension given after the reactions. Which is OK, but may I say that since this class is global it does not necessarily help even though the move was well-intentioned.
Speaking for myself my timeline opens post 23:30 GMT. So I feel excluded from the opportunity today. I still accept it but am frustrated tonight nonetheless. There are many reasons people engage in this format. It is a great opportunity and we do this all while juggling work, caring for family, domestic duties, community service and so on. Extending a deadline that people missed on day one will most likely be missed 24 hours later for the same scheduling issues. They will have missed the posted opportunity while fulfilling other duties only to find it past again when they return. Those of us in this category will need to complete twenty four hours earlier in order to make deadline. And that is okay too. Perhaps the best thing was to leave well enough alone.
UserIdTAG: 504031
UserNameTAG: Lindy7
CreateTimeTAG: 2013-03-01T01:14:08Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: I totally agree with you I am just coming in from work and it 9:01 pm where I am and I feel that deadlines on the weekend would be better. I also feel that the deadlines should be at least 2-3 weeks long.
Anyway we just have to make do this is free after all and it is a useful course. However, I suspect even if it were a paid course it would still have the same level of rigidity.
FirstChildUserIdTAG: 1221482
FirstChildUserNameTAG: Kimmy2013
FirstChildCreateTimeTAG: 2013-03-01T02:04:00Z
FirstChildVoteTAG: 0
FirstChildTAG: 47K students in this course. There is no way that everyone's wishes can be accommodated. Arbitrary timelines have been set, and it's the responsibility of students to get the assignments in on time.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-01T02:31:18Z
FirstChildVoteTAG: 1
FirstChildTAG: > They will have missed the posted opportunity while fulfilling other duties only to find it past again when they return.
I read this quite a bit. Students saying that they can't possibly get work in on time due to their "busy" schedules. Perhaps a time management course is required.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T02:40:25Z
FirstChildVoteTAG: 0
FirstChildTAG: Deadline is a deadline, plan ahead
FirstChildUserIdTAG: 73809
FirstChildUserNameTAG: rhyssouth
FirstChildCreateTimeTAG: 2013-03-01T02:41:09Z
FirstChildVoteTAG: 2
IndexTAG: 1703
TitleTAG: Have not submit my answers for Set 3
I only see the 'show answer' bottom. What can I do to submit my answers? Thanks!
UserIdTAG: 981305
UserNameTAG: suadelburai
CreateTimeTAG: 2013-03-01T01:10:52Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: You can't. The deadline has, again, passed. Move on to Week 2
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T01:13:54Z
FirstChildVoteTAG: 0
FirstChildTAG: The point is, how is this submission to be done? Or the same thing will happen in week 2...
FirstChildUserIdTAG: 748089
FirstChildUserNameTAG: meganisaacs
FirstChildCreateTimeTAG: 2013-03-04T19:49:51Z
FirstChildVoteTAG: 0
IndexTAG: 1704
TitleTAG: Unfair
For some of us, the best time to complete the assignment is right now....and this page is not allowing us to submit our answers. This is unfair because we were told the deadline is 23:30 GMT
UserIdTAG: 495350
UserNameTAG: christychristop
CreateTimeTAG: 2013-03-01T01:03:50Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: >This is unfair because we were told the deadline is 23:30 GMT
The deadline was already extended for Week 1 by a day! And it is now well past 23.30 GMT 28 Feb
>For some of us, the best time to complete the assignment is right now
You had a whole week.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T01:09:10Z
FirstChildVoteTAG: 2
FirstChildTAG: It's well past that now. As I write (about 6 minutes after your post), it's about 1:10 GMT on Friday March 1. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T01:10:03Z
FirstChildVoteTAG: 0
FirstChildTAG: I think the bottom line is the learning experience. Passing grade is so ridiculously low that not submitting the one week shouldn't matter.
Don't worry about it too much.
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-01T02:28:44Z
FirstChildVoteTAG: 1
FirstChildTAG: Where I am from all this deadline complaining would be called "looking a gift horse in the mouth". You are getting a free class from a top notch professor. Learning is the goal. As a teacher I deal with this constant whining about deadlines. There is always an excuse.
FirstChildUserIdTAG: 73809
FirstChildUserNameTAG: rhyssouth
FirstChildCreateTimeTAG: 2013-03-01T02:46:27Z
FirstChildVoteTAG: 4
IndexTAG: 1705
TitleTAG: question
how are test graded. how are they submitted? does it do it automatically
?
UserIdTAG: 402800
UserNameTAG: chrisp339
CreateTimeTAG: 2013-03-01T01:01:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1706
TitleTAG: P(X>u+6 SD)=0?
P(X>u+6 SD)=0??
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-01T00:57:21Z
VoteTAG: 2
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 6
FirstChildTAG: Not in general.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T01:05:39Z
FirstChildVoteTAG: 1
FirstChildTAG: Did you watch the lecture?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T01:06:24Z
FirstChildVoteTAG: 0
FirstChildTAG: Even the probability of mean + 10SD is not 0. Just ask the hedge fund traders.. (or at least you should have asked them in 2008. They probably forgot all about it by now)
FirstChildUserIdTAG: 919822
FirstChildUserNameTAG: ArthurBarabash
FirstChildCreateTimeTAG: 2013-03-01T02:48:14Z
FirstChildVoteTAG: 0
FirstChildTAG: Well, it is part of the lecture. but when you answer read carefully what is asked and don't rush as I did.
FirstChildUserIdTAG: 1240022
FirstChildUserNameTAG: Moshiko
FirstChildCreateTimeTAG: 2013-03-01T19:22:13Z
FirstChildVoteTAG: 0
FirstChildTAG: From the Lecture (4.3):
1/(k^2) means what?
;-)
-Gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-03-03T20:43:06Z
FirstChildVoteTAG: 0
FirstChildTAG: I have failed this one.
When the question ask for: "the percent of entries that are more than 6 SDs **above** average ...", does it mean that only value that are more than the average +6SD to be included (as in a one sided skewed histogram) or should we also take into account values that are less than the mean minus 6SD (such as in a bell shaped histogram) ?
As i understand 6 sigma in real life we do not care if it is below or above the boundary both such values are far way from the desired outcome, but we get a different result that depends on the understanding of the word **above**
Best
Moshiko
FirstChildUserIdTAG: 1240022
FirstChildUserNameTAG: Moshiko
FirstChildCreateTimeTAG: 2013-03-04T09:35:21Z
FirstChildVoteTAG: 1
SecondChildTAG: Same here. "Above", indicate a one tail distribution.
SecondChildUserIdTAG: 705689
SecondChildUserNameTAG: BR864
SecondChildCreateTimeTAG: 2013-03-05T00:31:22Z
SecondChildVoteTAG: 0
SecondChildTAG: My mistake... "Above" indicate a right tail of the distribution.
SecondChildUserIdTAG: 705689
SecondChildUserNameTAG: BR864
SecondChildCreateTimeTAG: 2013-03-05T01:01:02Z
SecondChildVoteTAG: 0
IndexTAG: 1707
TitleTAG: Thanks
Hello, I have to admit some degree of misunderstanding in the interpretation of texts. That was during the first week, so today I start week 2 with more strength to learn. I commend the teacher for such clear and simple presentations. It is very gratifying to learn that way.
Thank you!
UserIdTAG: 945953
UserNameTAG: Turca
CreateTimeTAG: 2013-03-01T00:52:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1708
TitleTAG: Help!
I cannot send my answers!!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-03-01T00:48:00Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Deadline has passed.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T01:18:14Z
FirstChildVoteTAG: 0
FirstChildTAG: time is over
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-03-01T03:56:46Z
FirstChildVoteTAG: 0
IndexTAG: 1709
TitleTAG: histogram construction?
Doubt 1: How do we construct uni-modal distributions? i didn't understand from the lecture can some one elaborate please?
Doubt 2: how do we construct a histogram with a discrete set of data. for ex: in the above lecture professor has taken the frequency of a value as the height and the data as the midpoint of its corresponding histogram 1.5-2.5 for 2 and 3.5 to 3.5 for 3&so on is it correct?
Doubt 3: why are these histograms non uniform in distribution? please elaborate
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-03-01T00:44:11Z
VoteTAG: 4
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3. 4: The average and the histogram; the average and the median
NumberOfReplyTAG: 3
FirstChildTAG: 1. Unimodal distributions: the lecture just says essentially that distributions with one peak are called unimodal.If you want to construct one, write any list of numbers in which one value occurs more often than any of the others. That will be the unique mode, and the distribution will be unimodal.
2. For histograms where the values of the variables are integers: since the width of each interval is 1, the density is numerically equal to the percent, which is proportional to the frequency. So yes, it's correct.
3. In the 1.5-2.5 bar, the only entries are exactly at 2. There are no entries of 1.75, or 1.9, or 2.15, etc. They're all at 2. So the distribution in the interval is seriously non-uniform; in fact, it's all concentrated on the single value 2.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T01:04:43Z
FirstChildVoteTAG: 4
SecondChildTAG: thank you mam
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-03-03T01:58:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Doubt1:
Unimodal distributions has only one peak. In multimodal distributions there are more than one peak, and, loosely speaking, these peaks don't need to have the same height. So, some distributions can be multimodal, and this fact may be the symptom of something interesting in our data. Probably we'll learn things like that in this course. See this wikipedia page for more info:
http://en.wikipedia.org/wiki/Unimodality
Doubt2:
Quantitative discrete? Why not?
Doubt3:
There are many kinds of distributions: uniform distributions, normal (gaussian) distributions, and so on. It depends on the collected data. Take a look at this wikipedia page:
http://en.wikipedia.org/wiki/Discrete_probability_distribution#Common_probability_distributions
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-03-01T01:07:43Z
FirstChildVoteTAG: 0
FirstChildTAG: I'll take a stab at your doubts. That doesn't mean my answers are right so feedback is very welcome!
Doubt 1: I think at this level of a statistics course, you just create the histogram and then observe whether the distribution is uni-modal (ie - it will have one peak) or bi-modal or whatever. According to how you group your data, however, this can change. There was an example in the lessons (Lecture 3.1) where a histogram was created with individual scores and it had so many peaks that it was very difficult to draw any useful conclusions from it. By grouping the scores into ranges, the distribution of the histogram then showed it was uni-modal. That result is dependent on what the values were and how they were grouped. The result probably would have been different if the values were different. (An more advanced statistician can probably group data to actually create a unimodal distribution in many cases, but this is not necessarily useful information. It may actually be misleading).
Doubt 2: For all intents and purposes pretend the bar is just a line. The width is always the same in this case because you are not representing a **range** of values. You are representing a **single** value. Either 2, or 3 or 4. Each *line* is presented as a bar centered on the actual value it represents. Each bar is drawn 0.5 units wider to the left and right of the value it represents for purposes that will become clear in future lectures.
Doubt 3: The values are not uniformly distributed because they are not actually distributed at all. For example for the bar centered on 3, which has a frequency of 2, the 2 scores both have a value of exactly 3. There are no scores with a value of 3.2 or 2.7. The score 3 has a frequency of 2. That's it. The answer to doubt 2 also explains this idea.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T01:16:55Z
FirstChildVoteTAG: 0
IndexTAG: 1710
TitleTAG: No submission option
I cannot find the "check" or "save" button on this page. I'm afraid this will prevent me from completing the assignment. Please correct this technical error.
UserIdTAG: 495350
UserNameTAG: christychristop
CreateTimeTAG: 2013-03-01T00:42:46Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You're past the deadline. Too late. It's not a technical error.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T00:47:53Z
FirstChildVoteTAG: 0
SecondChildTAG: You said deadline has passed, but pasted on what timezone? I would assume EST, since you know Harvard and MIT started this... Meh...
SecondChildUserIdTAG: 1228963
SecondChildUserNameTAG: hungpham35
SecondChildCreateTimeTAG: 2013-03-01T03:15:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Really..it's pasted all over the place - GMT is the timezone.
Assume away, but at your own risk.
SecondChildUserIdTAG: 919822
SecondChildUserNameTAG: ArthurBarabash
SecondChildCreateTimeTAG: 2013-03-01T03:19:58Z
SecondChildVoteTAG: 0
SecondChildTAG: I gather some have not been reading the course info, the course updates, or the forums. Be it on their own heads.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-01T03:42:34Z
SecondChildVoteTAG: 0
IndexTAG: 1711
TitleTAG: Submissions
Hey, guys, I cannot submit my answers. The problems show "show answer" button instead of "check/save".
UserIdTAG: 989097
UserNameTAG: Goodeasy
CreateTimeTAG: 2013-03-01T00:26:25Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Unfortunately you're too late.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T00:47:21Z
FirstChildVoteTAG: 0
SecondChildTAG: Ok. :(
SecondChildUserIdTAG: 989097
SecondChildUserNameTAG: Goodeasy
SecondChildCreateTimeTAG: 2013-03-01T01:06:15Z
SecondChildVoteTAG: 0
SecondChildTAG: But you can do the exercises on paper and then click "Show answer" to see if you were right or not. Don't worry. Your worst two results will be dropped so just be clear on the deadline next time and do the work with more space before it's actually due. The important thing is to check whether you understood the concepts. And you don't need a perfect score in your progress bar to do that! As long as you get over 35% you will receive a certificate of completion.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-01T01:22:55Z
SecondChildVoteTAG: 0
SecondChildTAG: This is really sad as the due date was Today at 23:30 which has not expired as yet.
SecondChildUserIdTAG: 1189320
SecondChildUserNameTAG: LCastillo66
SecondChildCreateTimeTAG: 2013-03-01T02:23:33Z
SecondChildVoteTAG: 0
SecondChildTAG: It expired around 3 hours ago.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-01T02:25:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Haven't we been through this before? Groundhog Day.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-03-01T03:43:53Z
SecondChildVoteTAG: 0
IndexTAG: 1712
TitleTAG: Couldn't submit answers
I couldn't submit my answers to exercise 3
UserIdTAG: 1332541
UserNameTAG: larry3194
CreateTimeTAG: 2013-03-01T00:22:29Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: What time is it?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-03-01T00:30:53Z
FirstChildVoteTAG: 0
FirstChildTAG: larry3194, time is over mate.. next time we have to see the deadline. (what tims is it? <-- everyone can see the time but this is such a rude word). :(
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-03-01T04:04:52Z
FirstChildVoteTAG: 0
SecondChildTAG: There are also hundreds and hundreds of these unfortunate posts.
SecondChildUserIdTAG: 1157957
SecondChildUserNameTAG: meganbh
SecondChildCreateTimeTAG: 2013-03-01T20:29:45Z
SecondChildVoteTAG: 0
IndexTAG: 1713
TitleTAG: Clarification of Exercise Set marks - Graded only, not Practice, right?
Just want to ensure my understanding ... in the final grade for the course the percent rating for each of: Exercise Sets, Midterm and Final are noted. I am assuming the Exercise Sets consists of ONLY the Graded Exercise Set marks and not the Practice Exercise Sets. Of course, the reason I'm asking is because I didn't do all the Practice Sets and so I already have some o's that show up on my Progress screen, which made me think I better double check my understanding. Thanks!
UserIdTAG: 1059091
UserNameTAG: KJMcKinley
CreateTimeTAG: 2013-03-01T00:05:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Only the exercise set. Practice is not graded.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-03-01T00:45:01Z
FirstChildVoteTAG: 0
FirstChildTAG: Practice Sets aren't counted in your overall grade. You've understood correctly. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-03-01T00:45:12Z
FirstChildVoteTAG: 2
IndexTAG: 1714
TitleTAG: Interested in Markov's inequality proof
I'm very much interested in the Markov's inequality proof? When will the pdf be available? Thanks in advance.
UserIdTAG: 157670
UserNameTAG: _Nelson_
CreateTimeTAG: 2013-02-28T23:44:44Z
VoteTAG: 11
CoursewareTAG: Section 3b: Measures of Location (Lec 3.4 - 3.5) / Lec 3.5: Markov’s inequality
NumberOfReplyTAG: 4
FirstChildTAG: This weekend. I have to attend to Week 3 first. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T23:51:45Z
FirstChildVoteTAG: 3
SecondChildTAG: thrice i did listen but still not cleared want to lear more with more applications. are we going to learn more?
SecondChildUserIdTAG: 1236052
SecondChildUserNameTAG: neelam25
SecondChildCreateTimeTAG: 2013-03-02T16:55:30Z
SecondChildVoteTAG: 0
SecondChildTAG: **I'm very much looking forward to that Professor A! Thank you!**
SecondChildUserIdTAG: 933606
SecondChildUserNameTAG: charlesfactor77
SecondChildCreateTimeTAG: 2013-03-03T04:22:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I've found this information. Does it work?
[http://people.stat.sfu.ca/~pritamr/stat801_05/ineq2.pdf][1]
[1]: http://people.stat.sfu.ca/~pritamr/stat801_05/ineq2.pdf
SecondChildUserIdTAG: 918956
SecondChildUserNameTAG: a-per
SecondChildCreateTimeTAG: 2013-03-03T10:25:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Markov's formal proof must certainly be very "mathematic", but I thought it this way:
1) Lets says we have 100 people.
2) Then the worst-case (the case in which you have the most people at 80 or more) is having all the young at 0 and all the old at k times the average.
4) Lets say we have X young and Y old.
5) Then in order to have an histogram that balance at the average you need X - (k-1) x Y = O (otherwise it would tip over).
6) You also know that X + Y = 100.
7) By solving this system of 2 equation for Y, you get Y = 25.
8) Since it is the worst-case, it means Y <= 25.
Since you had 100 people, you can easily convert in %.
What do you think?
SecondChildUserIdTAG: 809365
SecondChildUserNameTAG: mathmonde
SecondChildCreateTimeTAG: 2013-03-06T01:42:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Great! I´m also looking forward to see the proof of Markov's inequality :-)
thanks!
FirstChildUserIdTAG: 740800
FirstChildUserNameTAG: Jakubicek
FirstChildCreateTimeTAG: 2013-03-01T11:32:12Z
FirstChildVoteTAG: 2
FirstChildTAG: Looking forward to it. thank you
FirstChildUserIdTAG: 994886
FirstChildUserNameTAG: ARUN86
FirstChildCreateTimeTAG: 2013-03-03T16:50:10Z
FirstChildVoteTAG: 0
FirstChildTAG: We know the average is:
> sum of all the values / number of values
We also know that if we have the average and the number of values:
> number of values * average = sum of all the values
----------
Using k as the multiple, Markov's inequality says
> the proportion of entries >= (average * k) is at most 1/k
It works out that:
> (number of entries / k) * (average * k) = sum of all the values
divide by k then multiply by k; k cancels out so it's back to
> number of entries * average
which we already know = sum of all the values
----------
I stumbled onto it while I was playing with Excel - I wanted to calculate the amount of money billionaires might collectively have.
(roughly 250 million people in U.S., per-capita earnings in 2011 was 41,560 -- much less in some states, more in others...)
Total income: (250,000,000 * 41,560) = 10,390,000,000,000
(**10,390** billion dollars)
**millionaires...**
25 times the average is 1,039,000 dollars. Markov's inequality says at most 1/25 of the entries (people) can be this or above. 1/25 is 4%, by the way
> 250,000,000 people / 25 = 10,000,000
> $1,039,000 * 10,000,000 = **10,390** billion dollars
**100-millionaires...**
2500 times the average is 103,900,000 dollars.
> 250,000,000 / 2500 = 100,000
> 103,900,000 * 100,000 = **10,390** billion dollars
**billionaires**
25000 times the average is 1,039,000,000 dollars.
> 250,000,000 / 25000 = 10,000
> 1,039,000,000 * 10,000 = **10,390** billion dollars
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-03-06T09:33:37Z
FirstChildVoteTAG: 0
IndexTAG: 1715
TitleTAG: Good staff!
http://www.timeanddate.com/time/map/.
UserIdTAG: 48745
UserNameTAG: viktar
CreateTimeTAG: 2013-02-28T23:34:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Interesting and useful map. Probably will get the same treatment as the course instructions, no one will read it! I have been so long in the space business I live with GMT (or Zulu, or UTC if you prefer) and with data collectors (sensors) spread out all over the world I have many places burned into my brain as offsets to GMT. For several years I also managed employees on board ships all over the world's oceans so I could be wakened at any time of day or night with some crisis or other that occurred in their "normal" day.
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-03-01T00:48:30Z
FirstChildVoteTAG: 1
IndexTAG: 1716
TitleTAG: exhausted!
I have registered to this course about 5-6 hours ago and have just completed all exercise sets of 1st week! Is there a way to find out if my last one has been completed prior the deadline of 23:30? I think it's just on time.
Thank you.
UserIdTAG: 1330238
UserNameTAG: xeniosm
CreateTimeTAG: 2013-02-28T23:33:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: If you look at the Progress page (link is on the top menu bar) then you'll see if you got a score for the exercises. Hope that helps.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T23:50:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Hmmm how did I missed that? That was helpful. Thanks.
SecondChildUserIdTAG: 1330238
SecondChildUserNameTAG: xeniosm
SecondChildCreateTimeTAG: 2013-03-01T00:16:40Z
SecondChildVoteTAG: 0
FirstChildTAG: If you were able to submit it, it's in. Now get some rest. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T23:51:12Z
FirstChildVoteTAG: 0
SecondChildTAG: That's great, thank you Prof. I thoroughly enjoy your lessons.
SecondChildUserIdTAG: 1330238
SecondChildUserNameTAG: xeniosm
SecondChildCreateTimeTAG: 2013-03-01T00:17:34Z
SecondChildVoteTAG: 0
IndexTAG: 1717
TitleTAG: Problems with Problem 1.c
I have made the same maths for the 1.a and 1.b, but in 1.c the page indicates wrong answer, don't understand:
45+((6.5/20.9)*(60-45))=49.7
UserIdTAG: 977137
UserNameTAG: vfarru
CreateTimeTAG: 2013-02-28T23:09:32Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Wrong , not 6.5
FirstChildUserIdTAG: 812561
FirstChildUserNameTAG: fahiye-asfar
FirstChildCreateTimeTAG: 2013-02-28T23:52:51Z
FirstChildVoteTAG: 0
SecondChildTAG: 45+(14.4/20.9)*15 years=55.3
SecondChildUserIdTAG: 611869
SecondChildUserNameTAG: bostonpatriot
SecondChildCreateTimeTAG: 2013-03-01T03:39:35Z
SecondChildVoteTAG: 0
IndexTAG: 1718
TitleTAG: Lecture 3.2 - Smoothing Operation (average? or sum?)
At the beginning of the slide on Smoothing Operation, I believe the instructor misspeaks and refers to the list (1, 2, 3, 4) as having an average of 10 dollars. I believe she should have said a sum of $10. (Not difficult to make the mental translation, but might want to fix in the future.)
UserIdTAG: 1308402
UserNameTAG: Jolane
CreateTimeTAG: 2013-02-28T23:07:05Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You're right. I should have said the average was $2.50, which was staring at me on the slide. I talked to the engineer about it earlier today and will talk to the video people. Thanks for listening carefully. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T23:16:51Z
FirstChildVoteTAG: 0
IndexTAG: 1719
TitleTAG: Almost 100% on 1st submission.
I almost got 100% on my 1st submission.
I just forgot something in question 8 which I corrected for the 2nd and final submission.
UserIdTAG: 1174310
UserNameTAG: Catprog
CreateTimeTAG: 2013-02-28T23:06:28Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: good for you.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-03-01T00:27:02Z
FirstChildVoteTAG: 0
SecondChildTAG: you forgot "-" on Prob 8! :P
SecondChildUserIdTAG: 1016286
SecondChildUserNameTAG: curio
SecondChildCreateTimeTAG: 2013-03-01T04:54:58Z
SecondChildVoteTAG: 0
SecondChildTAG: yep.
SecondChildUserIdTAG: 1174310
SecondChildUserNameTAG: Catprog
SecondChildCreateTimeTAG: 2013-03-01T07:51:18Z
SecondChildVoteTAG: 0
SecondChildTAG: i don't get prob. 7, should i assume the number of months?
SecondChildUserIdTAG: 434563
SecondChildUserNameTAG: jer_nano
SecondChildCreateTimeTAG: 2013-03-02T05:45:33Z
SecondChildVoteTAG: 0
FirstChildTAG: a wow for you..
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-03-01T04:08:03Z
FirstChildVoteTAG: 0
FirstChildTAG: congrats
FirstChildUserIdTAG: 704053
FirstChildUserNameTAG: jehadhassan
FirstChildCreateTimeTAG: 2013-03-01T20:04:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Just wondering - If you get it right on the first check and you get a 'Final Check' button, do you still have to click that or is the answer already submitted with the first check?
FirstChildUserIdTAG: 899047
FirstChildUserNameTAG: ash-v-g
FirstChildCreateTimeTAG: 2013-03-02T04:55:53Z
FirstChildVoteTAG: 0
IndexTAG: 1720
TitleTAG: Amusing contrast
In one of the lectures Prof. Adhikari mentions that she never reports test averages to her students, only medians or stem and leaf plots and yet looking at the progress section I see that there is a listing for midterm and final averages. Perhaps with 47,000 students a stem and leaf plot might be a bit much!
UserIdTAG: 260168
UserNameTAG: Jeff2012
CreateTimeTAG: 2013-02-28T22:35:04Z
VoteTAG: 0
CoursewareTAG: Section 3a: Measures of Location (Lec 3.1 - 3.3) / Lec 3.2: The average: calculation and basic properties
NumberOfReplyTAG: 2
FirstChildTAG: If Prof. Adhikari had written EdX, they wouldn't be reporting averages. But then EdX wouldn't exist, as Prof. Adhikari isn't a programmer. You're right that with tens of thousands we wouldn't want a stemleaf, but I'd love to get a histogram ... let me see how easy it is to get the data. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T22:51:17Z
FirstChildVoteTAG: 12
SecondChildTAG: Professor,
I have a somewhat related question. Looking at the "Progress" tab, it shows a graded exercises average of below 35% because it is averages all of the zero scores for exercises not yet attempted. Would it possible to have the admins adjust the ESAvg bar so it only shows the average of assignments that have been submitted (or are past due if I missed a deadline)?
Thanks.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-03-03T02:32:17Z
SecondChildVoteTAG: 0
FirstChildTAG: In fact, the average mentioned on the Progress page is the mean of YOUR scores.
Still it would be really appreciated if we could see a histogram of the results of entire group (at least for final exam). So yes, Professor, please be so kind and try to organise it if you can!
FirstChildUserIdTAG: 517550
FirstChildUserNameTAG: Ewa_G
FirstChildCreateTimeTAG: 2013-03-02T13:33:27Z
FirstChildVoteTAG: 1
SecondChildTAG: **ES Avg** is the mean of our scores, but what about **Midterm Av** and **Final Av**? Those must be class averages. Otherwise it all doesn't make much sense... Although according to Prof A it still doesn't make much sense ;-)
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-03T02:04:04Z
SecondChildVoteTAG: 0
SecondChildTAG: As I understand it, the Midterm Av and Final Average are for the individual student. In the case of this course it is meaningless as the average = result (since there is only one Final and one Midterm). Other courses might have more than one exam so the edX system allows for an average to be calculated.
Ironically, one of the other courses for which I'm currently registered (6.0x) has two Mid-terms so would be an ideal candidate to check whether this reasoning is correct - unfortunately, it doesn't display averages at all...
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-03-06T18:47:46Z
SecondChildVoteTAG: 0
IndexTAG: 1721
TitleTAG: i got big problem..all exercites i did wrong
it did wrong all most
UserIdTAG: 1284506
UserNameTAG: QuanNguyen
CreateTimeTAG: 2013-02-28T22:24:02Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Please post your incorrect answers, since any small misunderstanding could cause this. Someone on the board might be able to help.
FirstChildUserIdTAG: 680933
FirstChildUserNameTAG: MyFriendsCallMePaul
FirstChildCreateTimeTAG: 2013-03-01T00:01:36Z
FirstChildVoteTAG: 0
IndexTAG: 1722
TitleTAG: Is the average mode a mean median?
This you tube clip is a fun way to learn what the mean, median & mode are http://www.youtube.com/watch?v=uydzT_WiRz4
UserIdTAG: 895423
UserNameTAG: joshea68
CreateTimeTAG: 2013-02-28T22:22:32Z
VoteTAG: 3
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: cute link
FirstChildUserIdTAG: 257938
FirstChildUserNameTAG: vasudhaanil
FirstChildCreateTimeTAG: 2013-03-01T07:22:09Z
FirstChildVoteTAG: 0
FirstChildTAG: It's funny!
FirstChildUserIdTAG: 1071309
FirstChildUserNameTAG: _Helena_
FirstChildCreateTimeTAG: 2013-03-01T14:00:58Z
FirstChildVoteTAG: 0
SecondChildTAG: too nica
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-01T19:56:12Z
SecondChildVoteTAG: 0
IndexTAG: 1723
TitleTAG: Just for fun
Just for fun I wrote a quick python program to test the result in problem 4-5 from the text (it wasn't intuitively obvious to me). I had it roll 10,000 dice for a series of guesses and this is what I found:
guess = 6 payout = 0.7433;
guess = 5.5 payout = 3.044175;
guess = 5.0 payout = 4.7893;
guess = 4.5 payout = 6.110775;
guess = 4.0 payout = 6.8422;
guess = 3.5 payout = 7.072375;
guess = 3.0 payout = 6.8681;
guess = 2.5 payout = 6.134975;
guess = 2.0 payout = 4.8369;
guess = 1.5 payout = 2.955775;
guess = 1.0 payout = 0.9003;
guess = 0.5 payout = -1.892225.
So 3.5 does seem to have the best payout.
UserIdTAG: 260168
UserNameTAG: Jeff2012
CreateTimeTAG: 2013-02-28T22:16:06Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 5 / Reading and Practice for Exercise Set 5
NumberOfReplyTAG: 3
FirstChildTAG: That is very cool!!!!
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-03-02T19:36:23Z
FirstChildVoteTAG: 1
FirstChildTAG: Can someone please explain Practice question 1 to me. I do not understand why the total wasn't divided by 3?
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-03-02T19:41:04Z
FirstChildVoteTAG: 1
SecondChildTAG: I think it is because you have 100 entries.
SecondChildUserIdTAG: 197730
SecondChildUserNameTAG: Claudia2505
SecondChildCreateTimeTAG: 2013-03-02T22:12:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Remember that you need to do a weighted average of the numbers by the proportion of the sample they represent.
SecondChildUserIdTAG: 1222946
SecondChildUserNameTAG: RichardDamon
SecondChildCreateTimeTAG: 2013-03-03T00:47:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Aha...got it..weighted average...!!! Thanks Richard and Claudia
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-03-03T01:06:49Z
SecondChildVoteTAG: 0
FirstChildTAG: I model It in Excel, was really helpfull.
FirstChildUserIdTAG: 544348
FirstChildUserNameTAG: jpbaudoin
FirstChildCreateTimeTAG: 2013-03-04T04:02:14Z
FirstChildVoteTAG: 0
IndexTAG: 1724
TitleTAG: How many students are left? (Dr. Adhikari)
Along with enhancing my knowledge of statistics I am also interested in the management challenges associated with managing an online course with 47,000 learners. Can you share any of those with me and how many students are left after week one? I was curious about the attrition rate as well. Thanks. Paul
UserIdTAG: 1067669
UserNameTAG: psanders
CreateTimeTAG: 2013-02-28T22:02:03Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Actually, I don't know how to define the number who are "left", in the sense that I don't know how many students are genuinely active. Every time I look at the enrollment, it's higher than it was before, but I've been advised not to discuss exact numbers.
As for challenges, in fact the number of students has turned out not to be a major issue. I had expected the forum to be much harder to manage, for a variety of reasons, but there are not many genuinely different questions being raised, and the people posting are by and large a thoroughly nice group. Even those who get quite agitated and use dramatic language are trying to get across some reasonable points.
The challenges are with a new course trying to negotiate a developing platform. Those challenges are considerable, and students have noticed some of them, but everyone is learning, and I'm sure Week 2 will be smoother for students than Week 1.
I appreciate the good humor, patience, and genuine interest in the subject matter being shown by the majority of forum discussants.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T22:23:35Z
FirstChildVoteTAG: 7
SecondChildTAG: Thank you so much for the time and patience. I am really enjoying the course. The lectures are so clear and a pleasure to listen to. In an ideal utopia I would really love to have lots more practice exercises :). Is there a statistics text that you could recommend? Online is fabulous but a printed book to complement and then refer back to would really add to the learning experience too.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T22:53:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Statistics (Fourth Edition) by Freedman, Pisani, and Purves, published by W.W. Norton. Expensive, but easily the best intro statistics text ever, and very likely one of the best intro texts in any quantitative discipline.
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T23:15:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T23:28:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Prof. A.,
Thank you for responding to my inquiry. Maybe if at the end of the course you could provide some ball park figure for those graduating that will suffice and satisfy my curiosity. I am deriving great comfort from the many posts that fall into the category of "student failed to read the instructions" which is also the most common occurrence in the course I facilitate. Thanks again. Paul
SecondChildUserIdTAG: 1067669
SecondChildUserNameTAG: psanders
SecondChildCreateTimeTAG: 2013-03-01T18:05:08Z
SecondChildVoteTAG: 0
IndexTAG: 1725
TitleTAG: 14/20
not as good as I wanted :( still need to work on quartiles!
UserIdTAG: 1223452
UserNameTAG: tflavien101
CreateTimeTAG: 2013-02-28T21:54:22Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1726
TitleTAG: choosing median from an even number of data
I am confused about how to choose the median from an even number of values.
I thought that the median is the same as the 50th percentile.
Say we have the list [1 2 3 4 5 6], do we take 3 or 4 to be the median?
Please Clarify.
UserIdTAG: 151933
UserNameTAG: WildW1ill
CreateTimeTAG: 2013-02-28T21:47:47Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise set 4 / Reading and Practice for Exercise set 4
NumberOfReplyTAG: 3
FirstChildTAG: 3.5
FirstChildUserIdTAG: 1326432
FirstChildUserNameTAG: stephenbeaumont
FirstChildCreateTimeTAG: 2013-02-28T22:03:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually, it's 3 according to the lecture - because 3 is the smallest number that is at least as large as half of the number of the entries, which is half of 6 which is 3. So 3 is at least as large as 3.
SecondChildUserIdTAG: 1002202
SecondChildUserNameTAG: ury949
SecondChildCreateTimeTAG: 2013-02-28T22:26:01Z
SecondChildVoteTAG: 0
FirstChildTAG: According to the method of taught in this course, the median would be 3. ury949 is right. I think most of us learned the stephenbeaumont way in school but that is clearly NOT the method applied in this course.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T22:45:26Z
FirstChildVoteTAG: 2
FirstChildTAG: The true median would be 3.5 which would place 1,2,3 to the left and 4,5,6 to the right.
FirstChildUserIdTAG: 868031
FirstChildUserNameTAG: CaliforniaViv
FirstChildCreateTimeTAG: 2013-03-02T03:48:19Z
FirstChildVoteTAG: 1
SecondChildTAG: Doesn't the same argument hold for any number between 3 and 4? (3.1, 3.2, ...)
All these numbers cut the data in half.
Also, all these numbers have the property that they're minimally distant with respect to our little "absolute value" metric.
If you take any of them (3.5, 3.0), and add up the absolute value distances between that and each of the points in the data, you get the same answer.
In this class, we just seem to be choosing a value that's in the data (making our choice either 3 or 4), and further just take the smaller of the two.
SecondChildUserIdTAG: 1284156
SecondChildUserNameTAG: Dispader
SecondChildCreateTimeTAG: 2013-03-02T23:39:51Z
SecondChildVoteTAG: 0
IndexTAG: 1727
TitleTAG: Decimal confusion
It's pretty frustrating and disquieting that the Professor has told us in the Course Info Post on 2/27/13 to report decimal answers to TWO places, which I just did on the practice exam, only to have my answers marked as INCORRECT because I didn't stop at ONE decimal!! What am I expected to do on the GRADED exam? ONE decimal or TWO? I have absolutely NO idea based on this experience. Not happy.
UserIdTAG: 1326845
UserNameTAG: firefrorefiddle
CreateTimeTAG: 2013-02-28T21:45:32Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You have posted to the first set of exercises, so I assume that is the question you are talking about.
If so, different set of requirements. The announcement is for week 2 onwards. The issue with week 1 is well known and there are dozens of posts about it.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T21:50:05Z
FirstChildVoteTAG: 0
IndexTAG: 1728
TitleTAG: E5P4 - Mothers? [Solved]
Where do the mothers get in the picture? As far as I can see from the data, it's age data for the entire population of the US at some point. Are we supposed to do some guessing about how many of the women who are mothers are older than 27.23?
Mothers are a subset of the data, and we don't have the information to make these decisions, unless we're supposed to guess, based on knowledge of the real world.
Edit: The problem was that the text refers to exercise 3 (which was last week), and not problem 3 within exercise 5. The questions within each exercise is clearly named "problems", and the sets of problems are named "exercises".
The reason I didn't think about the problem I just did was that I didn't just do it, I took a break after problem 3 :p
UserIdTAG: 83185
UserNameTAG: oysteingrondahl
CreateTimeTAG: 2013-02-28T21:35:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 4
FirstChildTAG: The problem 3 says:
> The histogram below shows the distribution of ages of mothers who gave birth at a local hospital.
Nothing about the entire population, just mothers.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T21:43:57Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi, the question is incorrectly worded as it refers to "Exercise 3" which as oysteingrondahl says refers to US general population data from Week 1 exercise 3. It should refer to the "Problem 3" data! That's where you will find those mothers!!!
SecondChildUserIdTAG: 895423
SecondChildUserNameTAG: joshea68
SecondChildCreateTimeTAG: 2013-02-28T23:17:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you joshea68, that was just my problem. I wish the text for all the problems were correct, but of course an error might creep in once in a while.
SecondChildUserIdTAG: 83185
SecondChildUserNameTAG: oysteingrondahl
SecondChildCreateTimeTAG: 2013-03-01T06:09:28Z
SecondChildVoteTAG: 0
FirstChildTAG: You don´t have to guess, go back to the lectures and you´ll understand what they are asking for. It´s pretty easy actually.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-28T22:05:10Z
FirstChildVoteTAG: 0
SecondChildTAG: You did not understand my question. See joshea68's reply to ChristineStv's reply to me for what I was actually asking about.
SecondChildUserIdTAG: 83185
SecondChildUserNameTAG: oysteingrondahl
SecondChildCreateTimeTAG: 2013-03-01T06:06:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi!
The right answer to problem 4 : The percent of mothers who are above the average age is..etc was marked wrong. The median age is 26 years, and the average is 27.23 , therefore the percent of mothers above average is greater than 50%. I got the red cross, although the answer is correct. Can someone from staff repair the script so I can get my 2 points? :)
Thanks
FirstChildUserIdTAG: 1216723
FirstChildUserNameTAG: Darkennoia
FirstChildCreateTimeTAG: 2013-03-01T17:39:04Z
FirstChildVoteTAG: 2
FirstChildTAG: Can anyone please explain question 5 to me i.e...does it involve any calculation or can it be solved by concept alone?
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-03-03T22:05:29Z
FirstChildVoteTAG: 0
IndexTAG: 1729
TitleTAG: No correct answer to problem 6-3?
This problem does not seem to have a correct answer, because of the case when List A is just 100 listed 25 times.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T21:29:52Z
VoteTAG: 9
CoursewareTAG: Exercise Set 6 / Exercise Set 6
NumberOfReplyTAG: 5
FirstChildTAG: It would be nice if we could keep the discussion in one post:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/512f2e27263a78240000011d
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T21:47:56Z
FirstChildVoteTAG: 0
SecondChildTAG: There's no reason for the unpleasant attitude. I clicked to view the discussion below the homework set and no posts appeared. Why is this thread not associated with the actual homework set it references?
SecondChildUserIdTAG: 3946
SecondChildUserNameTAG: Elliot
SecondChildCreateTimeTAG: 2013-02-28T21:56:07Z
SecondChildVoteTAG: 0
SecondChildTAG: oUnpleasant. Good grief. It wasn't associated tbecause the subforums have only been recently activated. I put the link sso the original thread could be foundb.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T21:59:49Z
SecondChildVoteTAG: 0
SecondChildTAG: And I don't waste too many pleasantries when someone posts anonymously.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T22:00:48Z
SecondChildVoteTAG: 0
SecondChildTAG: "While it's not linked here since the subforums have only been recently activated, we have been discussing this issue at *link*." -- How pleasant that sounds!
SecondChildUserIdTAG: 3946
SecondChildUserNameTAG: Elliot
SecondChildCreateTimeTAG: 2013-02-28T22:10:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Actually, anonymous has picked up a very good point; I will add another option as correct; anonymous knows which one.
Anonymous: did you get the big red cross?
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T22:32:07Z
FirstChildVoteTAG: 2
SecondChildTAG: The problem clearly says that list A has 25 *different* values. Thus, it cannot be the case of 25 "100" in a row. That is, only one answer is accurate.
SecondChildUserIdTAG: 19503
SecondChildUserNameTAG: jaimefromspain
SecondChildCreateTimeTAG: 2013-02-28T23:38:54Z
SecondChildVoteTAG: 0
SecondChildTAG: That was my update, in response to the issue raised by anonymous and a few others on the forum. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T23:52:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Got that problem and 6-4 wrong, guess I´m not understanding the theory behind lectures properly. Got the big red cross in both submissions. Any advice?
SecondChildUserIdTAG: 26776
SecondChildUserNameTAG: aleguillen
SecondChildCreateTimeTAG: 2013-02-28T23:56:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Could you explain to me the reasoning you used? Maybe start a new thread. Thanks,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-01T00:48:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually the problem only states that the list consists of 25 different entries, it doesn't say these entries have different values, as a non-statistician I don't know if this is quibbling...but I constructed both of my best guess wrong answers on the possibility that that List A could be comprised of 25 100 values.
SecondChildUserIdTAG: 1027280
SecondChildUserNameTAG: afterthought11
SecondChildCreateTimeTAG: 2013-03-02T23:55:17Z
SecondChildVoteTAG: 0
SecondChildTAG: If we assume the possibility that all values on list A are 100, then there is no difference in standard deviation between list A and list B.
Since we do not know that this is not the case the correct answer must include the possibility of List A and List B having an equal standard deviation.
List B has the potential of having a lower standard deviation from list A in so far as List B is constituted as being list A plus 5 values which do not deviate.
Therefore shouldn't the answer be: List B has a standard deviation value lower than or equal to the standard deviation for list A?
SecondChildUserIdTAG: 1027280
SecondChildUserNameTAG: afterthought11
SecondChildCreateTimeTAG: 2013-03-02T23:57:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Easy, if you think about the effect ,on the sum of square deviations from the mean, of adding whatever number of values equal to the mean. In addition, what happens to the size of the list? Consider these two facts and you wil soon get the right answer.
FirstChildUserIdTAG: 40403
FirstChildUserNameTAG: CHALE
FirstChildCreateTimeTAG: 2013-03-01T17:15:55Z
FirstChildVoteTAG: 2
SecondChildTAG: I overthought this question and ended up getting it wrong on the two submissions. I'm beginning to see how straight forward it was, lol
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-03-01T19:26:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Lilian2012, I have to agree with you. I too was 'over thinking' the question which resulted in an incorrect submission. :(
Well, I will certainly learn from THAT mistake!
SecondChildUserIdTAG: 1346686
SecondChildUserNameTAG: kimbalips
SecondChildCreateTimeTAG: 2013-03-06T03:50:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Chale, I was about to post exactly what you said, at least without math is what I figured that answer was and got it right. So Tushe
So people, think of the SD/Variance the new numbers (list B additions) are bringing in to the SD/Variance of list A ... now what happens when you spread that across a larger data set?
-Gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-03-03T20:46:57Z
FirstChildVoteTAG: 0
FirstChildTAG: I joined late, but have caught up and have been able to get this latest set of problems complete. I am thoroughly enjoying this class! I love the way you present the information.
Thank you!
FirstChildUserIdTAG: 1346686
FirstChildUserNameTAG: kimbalips
FirstChildCreateTimeTAG: 2013-03-06T03:51:29Z
FirstChildVoteTAG: 0
IndexTAG: 1730
TitleTAG: Problem 7
Hi Ani
Could you please direct me to the write lecture for problem 7?
Thanks
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T21:00:10Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: I'd say, Lecture 3.2.
FirstChildUserIdTAG: 1174304
FirstChildUserNameTAG: ThomasHGMann
FirstChildCreateTimeTAG: 2013-02-28T21:26:33Z
FirstChildVoteTAG: 2
SecondChildTAG: 3.2 smoothing of the average
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-03-01T19:58:04Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks, ThomasHGMann. 3.2 it is. Think about spreading the pain of fund raising evenly across the Board members. How much pain is left, and how much of that burden will each member have if they share the pain equally?
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T22:26:21Z
FirstChildVoteTAG: 4
SecondChildTAG: Thanks Ani
I got the answer correct. could you please also direct me to right direction for problem 5.
Thanks
SecondChildUserIdTAG: 967531
SecondChildUserNameTAG: manjusinghal
SecondChildCreateTimeTAG: 2013-03-01T16:25:36Z
SecondChildVoteTAG: 0
SecondChildTAG: HI Ani
Dont worry about answering for problem 2 for me as I have got it right.
Thanks
SecondChildUserIdTAG: 967531
SecondChildUserNameTAG: manjusinghal
SecondChildCreateTimeTAG: 2013-03-01T16:35:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Me too, I don't understand Q#7 correctly for the first time. But after, I have got a correct answer! So, there are 12 people who want to have 100 000 dollars (total sum). Each of them has paid already 5 200 dollars. How much more each of them should pay to reach together total sum.
FirstChildUserIdTAG: 1071309
FirstChildUserNameTAG: _Helena_
FirstChildCreateTimeTAG: 2013-03-01T14:37:24Z
FirstChildVoteTAG: 3
SecondChildTAG: so the average would be how much more per person?
SecondChildUserIdTAG: 891709
SecondChildUserNameTAG: dhsegura
SecondChildCreateTimeTAG: 2013-03-01T15:48:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you Helena.. Earlier I got wrong answer but after reading your explanation got the answer right.
SecondChildUserIdTAG: 976798
SecondChildUserNameTAG: Vassri
SecondChildCreateTimeTAG: 2013-03-01T20:21:38Z
SecondChildVoteTAG: 0
SecondChildTAG: The way the sentence is worded " In the first month of the campaign, the average amount raised by the 12 board members is $5,200", got me confused too. I think it would be easier if it read as "In the first month of the campaign, the average amount raised by EACH board member is $5,200"
SecondChildUserIdTAG: 600543
SecondChildUserNameTAG: Pradha
SecondChildCreateTimeTAG: 2013-03-01T23:35:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Helena your explanation helped me a lot.
SecondChildUserIdTAG: 985699
SecondChildUserNameTAG: Wywechka
SecondChildCreateTimeTAG: 2013-03-05T04:02:41Z
SecondChildVoteTAG: 0
IndexTAG: 1731
TitleTAG: Can I answer the exams of each sections after its deadline , please??
Can I answer the exams of each sections after its deadline , please??
UserIdTAG: 1222817
UserNameTAG: mohamed_Abdelhady
CreateTimeTAG: 2013-02-28T20:56:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: We were asked to read the course policy. If you had done this you should have read that the answers are released the day after submission closes.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T21:05:25Z
FirstChildVoteTAG: 0
IndexTAG: 1732
TitleTAG: Response to definition question , Staff please
Hi to staff
Few days ago i have raised questions regarding the definition of precentile and also regarding histograms, see links:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section2b_Lec_2_5/threads/512c81b867cc5f1f00000137
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/51272d2be327772200000107
I think those questions have a value for the course and would ask your response
And , yes, i understand it is almost imposible to adress so many questions comming from so many students
With appreciation
Moshiko
UserIdTAG: 1240022
UserNameTAG: Moshiko
CreateTimeTAG: 2013-02-28T20:34:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1733
TitleTAG: My excercise
I did this exercise and it was rights
UserIdTAG: 1024459
UserNameTAG: Archiwal
CreateTimeTAG: 2013-02-28T20:23:15Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: good for you
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-03-01T04:15:33Z
FirstChildVoteTAG: 0
IndexTAG: 1734
TitleTAG: To the Staff
THANK YOU FOR GIVING US ANOTHER OPPORTUNITY TO DO ESs!!!
IT'S A PLEASURE TO PARTICIPATE IN THIS COURSE! :)
UserIdTAG: 594132
UserNameTAG: DiraeMada
CreateTimeTAG: 2013-02-28T20:12:19Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I agree.
FirstChildUserIdTAG: 1189168
FirstChildUserNameTAG: esai23
FirstChildCreateTimeTAG: 2013-02-28T22:28:25Z
FirstChildVoteTAG: 0
IndexTAG: 1735
TitleTAG: Question for STAFF regarding score for practice exercise 1
When I was checking my progress I noticed that for "Practice for exercise set 2 and 3" I got scores (%). Although I solve the problems in "Practice for exercise set 1" I can't see any score for this section in the progress report. Is it ok?
Thank you
UserIdTAG: 1277862
UserNameTAG: Jcwyk
CreateTimeTAG: 2013-02-28T20:05:06Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Yes, it is OK.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T20:22:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you
SecondChildUserIdTAG: 1277862
SecondChildUserNameTAG: Jcwyk
SecondChildCreateTimeTAG: 2013-03-01T00:06:59Z
SecondChildVoteTAG: 0
FirstChildTAG: Practice sets don't count towards your grade. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T20:33:53Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you for the answer
SecondChildUserIdTAG: 1277862
SecondChildUserNameTAG: Jcwyk
SecondChildCreateTimeTAG: 2013-03-01T00:07:45Z
SecondChildVoteTAG: 0
IndexTAG: 1736
TitleTAG: submission
If one submits two times, the first time with a wrong answer and the second right which one will be considered?
UserIdTAG: 1090680
UserNameTAG: Ailin
CreateTimeTAG: 2013-02-28T19:51:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The second. When you are allowed 2 submissions, we are giving you the chance to rethink if you get the wrong answer the first time. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T20:05:03Z
FirstChildVoteTAG: 2
SecondChildTAG: Good evening everyone. Pls how do i go about it? I've been unable to view the problem sets and notes.
SecondChildUserIdTAG: 597865
SecondChildUserNameTAG: Sogo_dammy
SecondChildCreateTimeTAG: 2013-02-28T22:01:11Z
SecondChildVoteTAG: 0
IndexTAG: 1737
TitleTAG: Problem 6
If Markov inequality says "fraction of numbers in the list that are greater than or equal to x" then less than x should be 1-1/k, I selected that but still get the answer wrong?????
UserIdTAG: 290968
UserNameTAG: mkhkheder
CreateTimeTAG: 2013-02-28T19:48:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 5 / Exercise Set 5
NumberOfReplyTAG: 1
FirstChildTAG: How many choices did you mark? You must select ALL that are correct.
FirstChildUserIdTAG: 19503
FirstChildUserNameTAG: jaimefromspain
FirstChildCreateTimeTAG: 2013-02-28T20:00:55Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, didn't read carefully.... got it wrong for been careless... that makes me angry.... :(
SecondChildUserIdTAG: 26776
SecondChildUserNameTAG: aleguillen
SecondChildCreateTimeTAG: 2013-02-28T20:49:11Z
SecondChildVoteTAG: 0
SecondChildTAG: I marked all 3 and still got it wrong. How come?
SecondChildUserIdTAG: 1187096
SecondChildUserNameTAG: Chinonso411
SecondChildCreateTimeTAG: 2013-03-01T06:04:39Z
SecondChildVoteTAG: 0
SecondChildTAG: That is what I was thinking to do too ... I think I better wait though for a clarification from the course team... I have all the previous as correct ...it's a pity to lose the last one :-)
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-03-01T13:01:02Z
SecondChildVoteTAG: 0
SecondChildTAG: option a is correct i think so
6.2/15.5 =.4 * 82 =32.8
more then 25
less then 35
so a
SecondChildUserIdTAG: 1158215
SecondChildUserNameTAG: umar07
SecondChildCreateTimeTAG: 2013-03-02T05:58:13Z
SecondChildVoteTAG: 0
SecondChildTAG: i think that only a is the correct answer(for the same reason) but it is graded as wrong!
SecondChildUserIdTAG: 1083376
SecondChildUserNameTAG: patchmd
SecondChildCreateTimeTAG: 2013-03-02T10:12:42Z
SecondChildVoteTAG: 0
SecondChildTAG: i thought so too @patchmd!cant wait for the clarification!
SecondChildUserIdTAG: 951663
SecondChildUserNameTAG: aprilumali12
SecondChildCreateTimeTAG: 2013-03-05T16:43:23Z
SecondChildVoteTAG: 0
SecondChildTAG: More than one option correct? That is weird...
SecondChildUserIdTAG: 128193
SecondChildUserNameTAG: Marianne
SecondChildCreateTimeTAG: 2013-03-05T18:37:57Z
SecondChildVoteTAG: 0
SecondChildTAG: I thought I did select ALL answers that I thought were applicable, only to realise one of my selected option had got unchecked (dunno how) when I saw RED CROSS!!!! This has happened with me in another eDX course in the past, but there I was lucky as there were multiple submission options. Neways, some days are just bad! Look forward to next Exercise set.... :)
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-03-05T20:33:40Z
SecondChildVoteTAG: 0
IndexTAG: 1738
TitleTAG: Poblem 8
HOW DO I SOLVE PROBLEM 8?
UserIdTAG: 1130399
UserNameTAG: RafaelHMM
CreateTimeTAG: 2013-02-28T19:37:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 2
FirstChildTAG: I got the rest correct so I wouldn't have to worry about it. Unsure how to calculate this without knowing the original average. Hoping the answer sheet released next week will help me figure it out for future reference.
FirstChildUserIdTAG: 1317658
FirstChildUserNameTAG: WilliamK99
FirstChildCreateTimeTAG: 2013-02-28T19:44:23Z
FirstChildVoteTAG: 1
SecondChildTAG: You don't need to know original average.
SecondChildUserIdTAG: 149923
SecondChildUserNameTAG: Odessa
SecondChildCreateTimeTAG: 2013-02-28T20:06:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Also please read the last line of the question carefully re entering your answer.
I learned this from my initial mistake in entering my answer.
SecondChildUserIdTAG: 313672
SecondChildUserNameTAG: blinxnot
SecondChildCreateTimeTAG: 2013-02-28T20:44:31Z
SecondChildVoteTAG: 0
SecondChildTAG: enter your answer in negative or positive; read the last sentence
SecondChildUserIdTAG: 915660
SecondChildUserNameTAG: decomrador
SecondChildCreateTimeTAG: 2013-02-28T23:57:56Z
SecondChildVoteTAG: 0
SecondChildTAG: ... review the principle on how to re-compute the average in the lecture for this week (focus on the topic changing multiple entries, change the average...)
SecondChildUserIdTAG: 1056161
SecondChildUserNameTAG: aseanmaverick
SecondChildCreateTimeTAG: 2013-03-02T05:58:27Z
SecondChildVoteTAG: 0
SecondChildTAG: READ THE LAST LINE IF YOU THINK YOU KNOW HOW TO DO THIS PROBLEM AND YOU ARE GETTING IT WRONG. The negative sign is what hung it up for me.
SecondChildUserIdTAG: 501764
SecondChildUserNameTAG: dasMetzger
SecondChildCreateTimeTAG: 2013-03-04T15:30:44Z
SecondChildVoteTAG: 0
FirstChildTAG: You don't need the original average. Watch Lec 3.2 starting at about 8:25, or try the practice set for Exercise Set 4. In general, if you get stuck it's a great idea to go back and look at videos and practice. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T20:32:44Z
FirstChildVoteTAG: 4
IndexTAG: 1739
TitleTAG: Midterm 01
We gonna have the midterm exam on 13th March, but in the same date I have another exam from 9 to 14 GMT. how is the midterm? will it start at specific time or we can do it at any time on 13th March?
UserIdTAG: 152907
UserNameTAG: visperad
CreateTimeTAG: 2013-02-28T19:35:19Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Any time that day. I'll post the exact period, but you'll certainly have a day.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T19:47:25Z
FirstChildVoteTAG: 5
SecondChildTAG: I had hoped that the mid-term would be timed but that we did not have to take it on a specific day. My work commitments might prevent me from being able to do an exam on a wednesday. I am also thinking of others whose access to the internet might be less secure.
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-28T20:08:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Will Section 5: Exercise Sets 7&8 also be due on the 13th as stated on the Course Schedule?
The Course Policies state that "Exercise Sets are due on Friday, Monday, and Wednesday of each week, except on the day of the Midterm", March 13.
SecondChildUserIdTAG: 1155153
SecondChildUserNameTAG: KristinH
SecondChildCreateTimeTAG: 2013-02-28T21:58:32Z
SecondChildVoteTAG: 0
SecondChildTAG: I noticed the problem when we changed the due dates per student request. We'll keep the due date Wed Mar 13, and I will account for the timing by selecting the syllabus for the midterm suitably. Stay tuned for a set of announcements about the midterm. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T22:48:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you professor, In my very specific case by the time I leave work (5:30 - 6:00pm EST) the midterm submittal time would have already passed.
I guess it can be said that I can wake up at 5am , start exam at 5:30am (when it opens up) before I start getting ready to work at 6:30am.
Will stay tuned to the announcements!
-Gabriel
SecondChildUserIdTAG: 203329
SecondChildUserNameTAG: gabieee
SecondChildCreateTimeTAG: 2013-03-03T21:29:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Dearest Prof. A,
May I suggest the system that was used for MIT 6.00x: Each midterm was allowed to be taken over the period of 3 days (roughly). Once the exam was started, the student had a set time in which to finish the exam (12hrs for MIT 6.00x; that might be too lenient). Thus, one could set similar guidelines for tests in this course. For example: have tests on Thurs - Sat with a 1hr limit on the test once it is started. Also, the staff of MIT 6.00x used to completely shut down the forums / discussions during these 3 days (something I completely agree with).
Well those are my 2 cents (+/- 1cent).
-Prion
SecondChildUserIdTAG: 309823
SecondChildUserNameTAG: prion
SecondChildCreateTimeTAG: 2013-03-06T18:29:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Prof Adhikari,
13th is a wednesday and its mid-week. A lot of the students taking this course are working professional and may not be able to access web at a stretch of 24-48 hours due to work commitments. If possible, please increase the time span to atleast 3-4 days. I am personally, myself wont be able to take the exam as I am travelling on work from 12-14 and wont have access to the web. You can set a 24 hour clock timer but availability for just 1 day is a little too constricted time.
Its a sincere request.
Regards,
Neha Sanwalka
SecondChildUserIdTAG: 632886
SecondChildUserNameTAG: nehasanwalka
SecondChildCreateTimeTAG: 2013-03-10T08:55:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Much appreciated if MID-TERM can be scheduled on weekends considering working professionals have difficulty working on week-day. Thanks!
FirstChildUserIdTAG: 1181586
FirstChildUserNameTAG: eumannu
FirstChildCreateTimeTAG: 2013-03-07T16:25:47Z
FirstChildVoteTAG: 1
IndexTAG: 1740
TitleTAG: Problem 8 ES4
I do not think that problem 8 has all the values needed for computing the result, or , it is not formulated well.
"One of the houses costs" that means one does, we dont know how much the others cost, the cost may vary. And I believe that without knowing the value of all of the houses we can not compute the avarage price of them (therefore the change of it as well).
Will be glad if you correct me.
UserIdTAG: 205188
UserNameTAG: prediivo
CreateTimeTAG: 2013-02-28T19:25:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 4
FirstChildTAG: The question has all the information you need in order to be able to answer it. Perhaps it would be a good idea to watch lecture 3.2 again
FirstChildUserIdTAG: 1242147
FirstChildUserNameTAG: VickyUK
FirstChildCreateTimeTAG: 2013-02-28T19:30:26Z
FirstChildVoteTAG: 1
SecondChildTAG: It is not very well formulated. As it is you might think that all the houses originally went for 834,000, and then all but one were asking for 819,000. If you read it differently, assuming all the houses have different prices and it is the one which is sold which has the reduction the answer is relatively simple
SecondChildUserIdTAG: 7854
SecondChildUserNameTAG: pejic
SecondChildCreateTimeTAG: 2013-02-28T20:13:42Z
SecondChildVoteTAG: 0
SecondChildTAG: But it doesn't matter what the other houses went for as you don't need to calculate the average - just the change in the average that is caused by the price of the one house in question being dropped.
SecondChildUserIdTAG: 1242147
SecondChildUserNameTAG: VickyUK
SecondChildCreateTimeTAG: 2013-02-28T20:29:44Z
SecondChildVoteTAG: 0
SecondChildTAG: i agree. It is about the average of difference i guess.
SecondChildUserIdTAG: 475264
SecondChildUserNameTAG: chrisi
SecondChildCreateTimeTAG: 2013-03-03T16:02:52Z
SecondChildVoteTAG: 0
FirstChildTAG: Hello, no you do not need to know the prices of the individual houses (as indicated in the lecture). You only need to know the number of houses and the amount of money that was either added or subtracted from the total.
FirstChildUserIdTAG: 144162
FirstChildUserNameTAG: Rena2012
FirstChildCreateTimeTAG: 2013-02-28T19:33:22Z
FirstChildVoteTAG: 0
FirstChildTAG: just you have to subtract the two averages and divide them by 32 to get the difference
that was explained in lec 3.2
FirstChildUserIdTAG: 704053
FirstChildUserNameTAG: jehadhassan
FirstChildCreateTimeTAG: 2013-03-01T20:07:01Z
FirstChildVoteTAG: 0
FirstChildTAG: i liked that question... took quite a while to figure out "one of the houses" and not all the houses cost $834k.. :)
FirstChildUserIdTAG: 893456
FirstChildUserNameTAG: phate07
FirstChildCreateTimeTAG: 2013-03-03T14:54:26Z
FirstChildVoteTAG: 0
IndexTAG: 1741
TitleTAG: Video control bar covering lower 1/5 of screen in full screen mode?
Hi everyone,
When I display the videos in full screen mode I find that the video control bar covers approximately the lower 1/5 or so of the video playback area. This is unfortunate as it usually covers the x-axis of any displayed charts. When I display the video in the smaller mode, the text is too small to see clearly.
I'm using Chrome.
Anyone else have this issue? Is there a really simple way of minimizing the video control bar in full screen mode that I'm perhaps missing?
Thank you!
Terry
UserIdTAG: 1271361
UserNameTAG: TerryBot
CreateTimeTAG: 2013-02-28T19:19:11Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Did you try clicking on the HD button?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-02-28T22:13:58Z
FirstChildVoteTAG: 0
SecondChildTAG: I did, the video was sharper, but the same area was still hidden. Thank you for the thought, though.
SecondChildUserIdTAG: 1271361
SecondChildUserNameTAG: TerryBot
SecondChildCreateTimeTAG: 2013-03-02T04:38:57Z
SecondChildVoteTAG: 0
SecondChildTAG: For me, the video is then sharp enough so I can read everything even with the small screen.
There was another thread on the exact same problem and someone recommended a different browser, I believe it was Firefox. Hope that helps...
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-03-02T11:19:39Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks KVM, I had tried Firefox as well but no luck. The good news is that this now seems resolved in the latest lectures. Hooray....
FirstChildUserIdTAG: 1271361
FirstChildUserNameTAG: TerryBot
FirstChildCreateTimeTAG: 2013-03-07T00:28:50Z
FirstChildVoteTAG: 0
IndexTAG: 1742
TitleTAG: I don't understand!!!!!
It's too difficult understand the questions in this section.
UserIdTAG: 1192028
UserNameTAG: jmh_qf
CreateTimeTAG: 2013-02-28T19:18:44Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: You're going to have to be a little more specific if you'd like some help. Tell us which problem you're having difficulty with and what you've tried already.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-02-28T21:17:47Z
FirstChildVoteTAG: 4
IndexTAG: 1743
TitleTAG: Question on the ebook
From the ebook:
*Example 4-2 makes it clear that the mean of the squares of the elements of a list is not generally equal to the square of the mean of the elements of the list: the square of the mean is 0, but the mean of the squares is not.*
My question: Other than trivial examples are there cases when we would find the mean of the squares of the elements of a list is equal to the square of the mean of the elements of the list? Would that have some meaning regarding the characteristics of the list?
dfburke
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-02-28T19:02:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The statement is equivalent to "SD = 0." That is, all entries equal. The proof is algebraic; interested in seeing it?
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T19:38:01Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, thanks.
SecondChildUserIdTAG: 433872
SecondChildUserNameTAG: dfburke
SecondChildCreateTimeTAG: 2013-02-28T21:47:00Z
SecondChildVoteTAG: 0
IndexTAG: 1744
TitleTAG: Professor and Staff
I want to discuss something related to the Problem 6 of ES 4, but I don't think that is correct to do it here because of I would be talking about the answers. Is there another way to communicate with you? Otherwise, do you authorize me to post the issue here?
UserIdTAG: 797704
UserNameTAG: Hersan13
CreateTimeTAG: 2013-02-28T19:01:31Z
VoteTAG: 1
CoursewareTAG: Exercise Set 4 / Exercise Set 4
NumberOfReplyTAG: 3
FirstChildTAG: me also (problem 6), question as for average not for media, so d can be?
FirstChildUserIdTAG: 758560
FirstChildUserNameTAG: estre
FirstChildCreateTimeTAG: 2013-02-28T19:26:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Problem 6 - I completely disagree (100% disagree), but I don't want to give the answers. What to do, Prof. A?
SecondChildUserIdTAG: 990430
SecondChildUserNameTAG: gsullivan
SecondChildCreateTimeTAG: 2013-03-02T21:39:28Z
SecondChildVoteTAG: 0
SecondChildTAG: After the deadline, the staff should explain why our answers were wrong. If they are able to explain then it will only add to our knowledge. But if they are unable to explain then it is only fair to give three points back.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-03-05T08:24:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Don't you think that doing so would give you an unfair advantage over the students who do not have free access to the instuctors or TAs? I do. Here is why: you probably have not submitted your answers yet. If you submit them AFTER conversing with Prof. A or TAs, there is a direct correlation between your answers and whatever info you are seeking to find. That is not fair to the other 46,999 students who have already submitted their answers. You would have a statistical advantage that might put you in the tail of the curve, so to speak.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-28T19:53:24Z
FirstChildVoteTAG: 1
SecondChildTAG: That's why I refered to Professor and Staff, as they can see that I ALREADY answered the excercises.
SecondChildUserIdTAG: 797704
SecondChildUserNameTAG: Hersan13
SecondChildCreateTimeTAG: 2013-02-28T21:27:33Z
SecondChildVoteTAG: 0
SecondChildTAG: I think that the discussion board is here so anyone of the students can ask a question before they submit their answers - seems fair to me.
SecondChildUserIdTAG: 1002202
SecondChildUserNameTAG: ury949
SecondChildCreateTimeTAG: 2013-02-28T22:48:35Z
SecondChildVoteTAG: 0
FirstChildTAG: It's fine to post a general question about the problem. I will probably point you to the right lecture segment to view. Thank you for asking; I appreciate that you are trying to do the right thing. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T20:08:57Z
FirstChildVoteTAG: 5
SecondChildTAG: Yes please point me to the right part of the lectures. I have a bad feeling that it has to do with how a word is defined.
SecondChildUserIdTAG: 913981
SecondChildUserNameTAG: DSamuel
SecondChildCreateTimeTAG: 2013-02-28T20:42:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok, Professor, thanks for answering, and here's the point:
Exercise Set 4, Problem 6.
You ask to select (and you specify "all that are correct")
which of the conclusions can be drawn from the information
given.
a) is impossible because of you told us in the
preceding Lecture that we MUST NOT round off the averages. Ok.
d) is obviously wrong, it would be right if we were talking
about the median, which is not the case. I guess it doesn't
need more explanations. Ok.
So, b) is certainly right.
I have doubts about c). For me, it would be certainly right if
you had written "there were roughly 3480..." or "there were
approximately 3480...".
Anyway, as you said "Select all that are correct", I took it
like a hint of that there were more than one correct, so I
chose b) and c). They evaluated it wrong. As my second
submission I chose just b), and they evaluated wrong again!
So, the question is, which is/are the correct option/s?????
I mean, I guess I was right.
I'll wait for your comments. Thanks a lot.
SecondChildUserIdTAG: 797704
SecondChildUserNameTAG: Hersan13
SecondChildCreateTimeTAG: 2013-02-28T21:35:53Z
SecondChildVoteTAG: 0
SecondChildTAG: How can there be 2.9 people living in a house, even if it's a typical house?
SecondChildUserIdTAG: 1002202
SecondChildUserNameTAG: ury949
SecondChildCreateTimeTAG: 2013-02-28T22:47:04Z
SecondChildVoteTAG: 0
SecondChildTAG: The average is 2.9, not approximately 2.9. That should remove one of your doubts. ury949 asks an excellent rhetorical question; and now all your doubts should be removed. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T22:57:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Hersan13, quoting your (a,b,c,d) set doesn't make any sense, since the answers are randomly rotated. Try instead a nice educational experiment with me. Take paper and pencil. Write down 10 numbers (any numbers you feel affinity with). Now sum them all. Write down the sum. Now calculate the average, well, taking the sum and dividing it by the number of the numbers you chose, i.e. 10. Now that you've got the average, try multiplying it by the number of the numbers, won't you get again the sum? Fantastic. Now don't think of numbers, think of households. You know how many households there are (your numbers) and you know the average of people living in a household, so don't you think that there's nothing approximative? As for as the 2.9 people living in a house, well, I suggest you to think in terms of Trilussa's chicken, one of first statistical aphorisms that I have ever heard of ( http://margaret.healthblogs.org/2007/11/24/statistics-according-to-a-roman-poet-eating-two-chickens/ ). An average is an average.
SecondChildUserIdTAG: 526184
SecondChildUserNameTAG: lmassaron
SecondChildCreateTimeTAG: 2013-02-28T23:25:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Professor:
One would obviously think that there can’t be 2.9 people by home, but here’s what you told us in the Lecture:
"I know you're all shouting at the screen going, you can't
have 7 and 1/2 monkeys.
I completely agree.
You're right.
So what you're learning is the average is not a number of monkeys.
It's not a possible number of monkeys.
And you must not round it off.
The average is 7.5."
So, I see the things and I agree with ury949 and his/her rhetorical question, but I tried to apply what you have just said.
Could you make this point clear for me, please? In these cases of common sense, one must or must not round off an average.
Thank you very much for your attention and patience.
SecondChildUserIdTAG: 797704
SecondChildUserNameTAG: Hersan13
SecondChildCreateTimeTAG: 2013-03-01T02:13:14Z
SecondChildVoteTAG: 0
SecondChildTAG: The word "typical" doesn't mean the same as the word "average." If a household had 2.9 people, it would be extremely atypical, not typical.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-03-01T04:11:06Z
SecondChildVoteTAG: 0
SecondChildTAG: The average is 2.9; it shouldn't be rounded. At the "monkeys" stage of the lectures, what you have learned is that the average need not be a possible value of the variable, so there should be no surprise that the average household size isn't a household size at all. That's what several people have been trying to say, in different ways. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-01T05:48:56Z
SecondChildVoteTAG: 0
SecondChildTAG: I figured this problem out by going to the online textbook (Stark) and using "find" for the word typical, and re-reading all the uses of the word.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T18:12:01Z
SecondChildVoteTAG: 0
SecondChildTAG: you are right Dianebefd, we must be careful about what the word "typical" really means and if the average 2.9 in the case of problem 6 reflect what is typical ? I suggest everyone to read carefully the text book !
SecondChildUserIdTAG: 773907
SecondChildUserNameTAG: Redouanekh
SecondChildCreateTimeTAG: 2013-03-02T10:07:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Just a quick note to everyone regarding your 2nd attempt at these questions.
your answer may be marked incorrect, even if it is correct if you have also marked an incorrect answer. the only way to get a green check mark is by putting in the right combination of answers. Therefore you could have ad a red X appear next to you answer on 1st attempt even if is was correct. This was enlightening for me and I hope it helps the rest of you.
SecondChildUserIdTAG: 348290
SecondChildUserNameTAG: joshb
SecondChildCreateTimeTAG: 2013-03-04T21:09:52Z
SecondChildVoteTAG: 0
IndexTAG: 1745
TitleTAG: The Range, IQR and SD
Hi, In lecture 4 of the ebook Professor Stark writes:
*In computing the rms, we divide by the number of entries before taking the square-root. What difference does it make to square the entries? Squaring them makes every term in the sum positive, so positive and negative entries do not cancel. **If we ignored the square and the square root, we would just have the mean of the list**, which could be zero, even if all the numbers were large in magnitude, because positive and negative entries could cancel. Squaring the entries before averaging them prevents cancellations.*
I think the way this is written is a little misleading.
It sounds like he is saying the rms and the mean are the same, except for positive and negative numbers cancelling each other in the calculation of the mean. But even in the case of all positive numbers the rms and the mean are not the same:
Data: 1,2,3
mean = 1 + 2 + 3 / 3 = 6/3 = 2
rms = square_root( (1*1 + 2 * 2 + 3 * 3 )/3 ) = sq_root( 14/3) = 2.16
I'd like to know in words - to understand intuitively - the difference in what the two measures describe. That the mean = 2 I certainly understand. The average is 2. But what is does it 'mean' that the rms is 2.16?
dfburke
UserIdTAG: 433872
UserNameTAG: dfburke
CreateTimeTAG: 2013-02-28T18:49:16Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1746
TitleTAG: new to the course
Hi My name is Tanefer I just found out about this course today, Im not sure how to access assignments and I see they are due today. Can I turn in assignments for this first week later while I figure out what Im supposed to do?
UserIdTAG: 1331615
UserNameTAG: Tanefer
CreateTimeTAG: 2013-02-28T18:45:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Read the course info and you will understand. Use the menu at the top to navigate to "course info" and read it all (there is a vertical menu with links to several documents) before starting the course and also before using the discussion forum. It will save you time and heartache and also answer the questions regarding turning in assignments, etc.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T19:32:59Z
FirstChildVoteTAG: 0
IndexTAG: 1747
TitleTAG: PROBLEM WITH SLIDES
Hi Guys! Probably there some problem with slides of and after lec. 3.5....Could anybody help......????
UserIdTAG: 795482
UserNameTAG: VIVEK_88
CreateTimeTAG: 2013-02-28T18:44:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1748
TitleTAG: PROBLEM WITH SLIDES
Hi Guys! Probably there some problem with slides of and after lec 3.5....Could anybody help...???
UserIdTAG: 795482
UserNameTAG: VIVEK_88
CreateTimeTAG: 2013-02-28T18:41:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thanks for reporting this.
Is it a problem with downloading the slides, or a problem with the content of the downloaded material?
FirstChildUserIdTAG: 392626
FirstChildUserNameTAG: robertjmarks
FirstChildCreateTimeTAG: 2013-02-28T18:56:48Z
FirstChildVoteTAG: 0
IndexTAG: 1749
TitleTAG: Possible misprint in question
I could not find any 'income date' in lecture 3 or lecture 2.
a) For the income data in Lec 2.4, find the 40th percentile in thousands of dollars. Please enter only your numerical answer, and please round to one decimal place.
UserIdTAG: 901943
UserNameTAG: nbabra01
CreateTimeTAG: 2013-02-28T18:20:21Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: The income data is referred to in the video by the instructor, not the video by the guy that's accessed with the online e-textbook.
It is referred to at the beginning of her lecture, as if she is continuing a previous problem.
FirstChildUserIdTAG: 797869
FirstChildUserNameTAG: edoz
FirstChildCreateTimeTAG: 2013-02-28T19:11:13Z
FirstChildVoteTAG: 0
SecondChildTAG: There should be a direct link to the data. I could not find it too.
SecondChildUserIdTAG: 621690
SecondChildUserNameTAG: sakar60
SecondChildCreateTimeTAG: 2013-03-12T00:03:07Z
SecondChildVoteTAG: 0
FirstChildTAG: The income data is the only data set that the professor really worked with in Lecture 2.4. Click the lecture slides for 2.4, the 9th slide has all the income data.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T19:13:23Z
FirstChildVoteTAG: 3
IndexTAG: 1750
TitleTAG: Using iPad ok?
I'm using an iPad to view the course and answer all questions. There aren't submit buttons on the exercise pages but final check buttons instead. It appears everything is behaving properly for submissions, does anyone know if this is indeed the case?
UserIdTAG: 1061881
UserNameTAG: kristen1trigen
CreateTimeTAG: 2013-02-28T18:07:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I am also using an iPad. I don't think it's a problem at all. U can check the progress icon to see how u r doing.
FirstChildUserIdTAG: 1187096
FirstChildUserNameTAG: Chinonso411
FirstChildCreateTimeTAG: 2013-02-28T18:14:44Z
FirstChildVoteTAG: 0
FirstChildTAG: same here use ipad with no issues
FirstChildUserIdTAG: 895245
FirstChildUserNameTAG: Ezegoing
FirstChildCreateTimeTAG: 2013-02-28T19:39:52Z
FirstChildVoteTAG: 0
IndexTAG: 1751
TitleTAG: Exercise 5 pblm 4
Please can someone explain how to find the percent of mothers above the average age.
UserIdTAG: 1187096
UserNameTAG: Chinonso411
CreateTimeTAG: 2013-02-28T17:28:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Just remember the definitions of median and average... :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-28T17:42:29Z
FirstChildVoteTAG: 0
IndexTAG: 1752
TitleTAG: Professor
Good morning, I just joineds the class today, there is no way I can have the first assignment in today.
UserIdTAG: 1331082
UserNameTAG: sdmonette
CreateTimeTAG: 2013-02-28T17:08:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: On Course Info, it says:
As this is Week 1 and people are yet to get into a rhythm with the course, the staff and I have extended the deadline for Exercise Sets 1, 2, and 3 till Thursday February 28, 23:30 GMT.
So, you can still do the first week assignments if you have time :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-28T17:45:15Z
FirstChildVoteTAG: 1
SecondChildTAG: thank you
SecondChildUserIdTAG: 1036551
SecondChildUserNameTAG: Geetagrg
SecondChildCreateTimeTAG: 2013-02-28T19:10:22Z
SecondChildVoteTAG: 0
IndexTAG: 1753
TitleTAG: Late submissions
What happens if we try to submit late?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T17:07:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The "submit" button will disappear once the deadline has past. You will be prevented from submitting late. You'll get a score of 0 on that exercise.
NB that you can drop your 2 lowest exercise scores from your course score. And a passing grade is considered to be anything over 35%. So you'll still have avery good chance of passing the course.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T18:44:21Z
FirstChildVoteTAG: 1
IndexTAG: 1754
TitleTAG: I can´t download the lectures slides 3.3 and 3.4
Hello everyone
I can´t download the slides 3.3 and 3.4 it seems to be in blank after I click the slides link.
UserIdTAG: 1279047
UserNameTAG: loriase
CreateTimeTAG: 2013-02-28T16:49:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I'm sorry to hear that. Could you copy the link address into the forums, this will help us to diagnose and fix any issues. Also if you could indicate which web browser you were using that would be helpful as well.
FirstChildUserIdTAG: 335630
FirstChildUserNameTAG: rjmarks
FirstChildCreateTimeTAG: 2013-02-28T18:59:22Z
FirstChildVoteTAG: 0
SecondChildTAG: I´m using mozilla firefox browser. I will copy the links
SecondChildUserIdTAG: 1279047
SecondChildUserNameTAG: loriase
SecondChildCreateTimeTAG: 2013-03-01T15:25:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Hello, here are the links addresses:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec3.3.pdf
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec3.4.pdf
Also Iwoul like to report that the volume of the videos is too low and I have trouble trying to hear what the professor says.
Thanks for your response.
SecondChildUserIdTAG: 1279047
SecondChildUserNameTAG: loriase
SecondChildCreateTimeTAG: 2013-03-01T15:28:34Z
SecondChildVoteTAG: 0
IndexTAG: 1755
TitleTAG: Assignments
Hi,
I'm having a process of consciousness here... the assignments from this page http://statistics.berkeley.edu/~stark/SticiGui/Problems/assign-2x-s13.htm are also for the online students or not?...I don't have a Student ID, so I guess not. I still have a few hours left until the new deadline and I thought I could try.... :)
UserIdTAG: 1230945
UserNameTAG: Nikole
CreateTimeTAG: 2013-02-28T16:42:55Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Nikole those sticigui exercises are not required. (But parts of the reading ARE and we get linked to the relevant area.) We in Stat2.1x should do the exercises under Courseware. There is no Student ID for Stat2.1x. Hope this helps.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-28T18:54:20Z
FirstChildVoteTAG: 0
IndexTAG: 1756
TitleTAG: I can´t download the videos
Miss
I can´t download the videos from the week 2 section 4 - "spread", because there´s no link to do it.
where can i find it
Regards
UserIdTAG: 1166847
UserNameTAG: Jriveraespejo
CreateTimeTAG: 2013-02-28T16:28:12Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Same here!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-28T19:17:09Z
FirstChildVoteTAG: 0
FirstChildTAG: same here!!
FirstChildUserIdTAG: 1214920
FirstChildUserNameTAG: Sebastian_Beto
FirstChildCreateTimeTAG: 2013-02-28T22:14:06Z
FirstChildVoteTAG: 0
IndexTAG: 1757
TitleTAG: Is there a pdf or some other offline version of the SticiGui text?
My online connections are time limited and unstable. As a result I spend most of my studying time off line. When I try to save the web page of the SticiGui text I keep getting double images which are difficult to read through.
Please, if there is a offline version of the text I would certainly be overjoyed to get a copy of it.
Are there any suggestions out there?
UserIdTAG: 151933
UserNameTAG: WildW1ill
CreateTimeTAG: 2013-02-28T16:25:59Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I just open a browser in my smartphone and I don't close the tab so the whole chapter stays in the cache!! 8
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-28T19:05:09Z
FirstChildVoteTAG: 1
SecondChildTAG: I use my smartphone for this class and it stays there. I just can't download the lectures and have to use up my mobile data plan on watching the UTube videos. I wish I could downlowd them on my phone and watch them.
SecondChildUserIdTAG: 4612
SecondChildUserNameTAG: Susnaj
SecondChildCreateTimeTAG: 2013-02-28T19:19:11Z
SecondChildVoteTAG: 0
IndexTAG: 1758
TitleTAG: answers of the exercises of week 1
Can someone tell me where the answers of exercises of week 1 are posted? I would like to view the correct answers since the deadline is over so that i can comprehend the material much more properly.
UserIdTAG: 876760
UserNameTAG: devirajmohan
CreateTimeTAG: 2013-02-28T15:52:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The deadline has been postponed to February 28, 23:30 (GMT).
FirstChildUserIdTAG: 859593
FirstChildUserNameTAG: AlvFdezFdez
FirstChildCreateTimeTAG: 2013-02-28T16:00:18Z
FirstChildVoteTAG: 1
FirstChildTAG: Oh! I was not aware of that. But thanks for informing me.
FirstChildUserIdTAG: 876760
FirstChildUserNameTAG: devirajmohan
FirstChildCreateTimeTAG: 2013-02-28T16:03:27Z
FirstChildVoteTAG: 0
IndexTAG: 1759
TitleTAG: can't watch the videos!!!
During all the week i was trying to look at the videos of this part... i couldn't!!!.. Does anybody else knows any solution?
UserIdTAG: 1288656
UserNameTAG: Damaritos
CreateTimeTAG: 2013-02-28T15:50:36Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 1
FirstChildTAG: What seems to be the problem? Do you have Flash?
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-28T16:51:56Z
FirstChildVoteTAG: 0
IndexTAG: 1760
TitleTAG: ex 3.9
in the book in ex 3.9 the answers of 50th,59th and 75th percentiles are not given correctly.
UserIdTAG: 974461
UserNameTAG: ncscaks
CreateTimeTAG: 2013-02-28T15:27:11Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 0
IndexTAG: 1761
TitleTAG: Exercise set 4 Problem 6
I' m a bit confused with this one. It seems to me that only one answer is correct ... However the question somehow "implies" more than one answers. I have chosen two (even though for the second one I had my doubts) and the result is incorrect. Any ideas ??? I have only one submission left and do not want to make a mistake in the problem that seems the easiest of all :-)
UserIdTAG: 1069830
UserNameTAG: TheodoraCh
CreateTimeTAG: 2013-02-28T15:24:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: The idea would be to go with your initial answer without trying to read between the lines. Just think which choices are incorrect 100% and given the information you have from your first submission make a final selection.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T15:40:33Z
FirstChildVoteTAG: 0
SecondChildTAG: mmmm... - chosing the "least wrong" answer again? I suspect you're right, but it offends my sense logic.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-28T16:17:43Z
SecondChildVoteTAG: 0
SecondChildTAG: I hope that by now you already found whether your choice was "least wrong" or "just correct" :)
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T20:21:05Z
SecondChildVoteTAG: 0
SecondChildTAG: yes thanks - I'm fine with this one - it's set 6 problem 3 I'm stressing over!
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-28T20:28:48Z
SecondChildVoteTAG: 0
SecondChildTAG: MarianW: take another look at 6-3. I might have managed to reduce your stress.
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T23:18:49Z
SecondChildVoteTAG: 0
FirstChildTAG: I missed that one =(
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-28T16:06:28Z
FirstChildVoteTAG: 0
FirstChildTAG: Is there only one right answer one though ? It appears to me that the question is implying that there are more than one correct answers to be chosen .... What do you think about that ?
FirstChildUserIdTAG: 1069830
FirstChildUserNameTAG: TheodoraCh
FirstChildCreateTimeTAG: 2013-02-28T16:48:39Z
FirstChildVoteTAG: 0
SecondChildTAG: woops sorry I'm talking about a different question - OK. Yes, the wording (and the type of check box) allow you to pick as many of the answers as you like. But none of that stops you just selecting just one answer if you think the other three are incorrect.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-28T16:56:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-02-28T17:35:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Dont forget you get 2 attempts at that one
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-28T16:53:33Z
FirstChildVoteTAG: 0
FirstChildTAG: It could require just one answer!
FirstChildUserIdTAG: 1187096
FirstChildUserNameTAG: Chinonso411
FirstChildCreateTimeTAG: 2013-02-28T17:10:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-02-28T17:35:27Z
SecondChildVoteTAG: 0
FirstChildTAG: This is the easiest problem up to now, and of course, I did wrong. When I got my red cross I got stunned, then I realized that the answer was so obvious that I could not see it although it was in front of my eyes. Just a tip, you can mark as many choices as you want. Btw, it is the typical question that may require at least two, but no more than two opportunities.
FirstChildUserIdTAG: 19503
FirstChildUserNameTAG: jaimefromspain
FirstChildCreateTimeTAG: 2013-02-28T17:36:56Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks a lot!
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-02-28T17:38:59Z
SecondChildVoteTAG: 0
IndexTAG: 1762
TitleTAG: Lies, damned lies, and statistics...
Hello,
Part of the reason I want to understand statistics better is to counter all the bad info we get on TV.
It's very easy to mislead people by misusing statistics.
One thing I do, is to look at who did the study. For example, if I hear about a study that says "second-hand smoke is ok" I first look at who paid for the research. If its a tobacco company, then I am suspicious.
That quote above is from Mark Twain. I think he says that because we give statistics extra credence, because it's math. Unscrupulous people will present valid data in misleading ways, but you're tempted to believe it, well, because math.
What are some ways you've seen statistics misused?
UserIdTAG: 471020
UserNameTAG: WaitWhat
CreateTimeTAG: 2013-02-28T15:20:27Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: That's funny as this is why I am taking this course. The media loves to spin numbers and I feel if I am able to translate my own polls than I would be better informed.
FirstChildUserIdTAG: 1317658
FirstChildUserNameTAG: WilliamK99
FirstChildCreateTimeTAG: 2013-02-28T17:45:40Z
FirstChildVoteTAG: 0
SecondChildTAG: So it is only me who wants to learn how to manipulate people? Oh…
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T18:46:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Twain was the master of irony. Therefore, either Statistics is the only "truth" or it is even more devious that "lies". Gotta love irony!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-28T18:56:24Z
FirstChildVoteTAG: 0
FirstChildTAG: 82.315 % of Statistics Quoted are made up :)
FirstChildUserIdTAG: 1181263
FirstChildUserNameTAG: drush
FirstChildCreateTimeTAG: 2013-03-01T10:02:05Z
FirstChildVoteTAG: 0
IndexTAG: 1763
TitleTAG: Same mistake!
Hey, i think we all are in the same boat.
UserIdTAG: 1033884
UserNameTAG: vaishalivashisht
CreateTimeTAG: 2013-02-28T15:14:39Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1764
TitleTAG: Assignments from the online text book?
Hi
I am still getting use to the navigation. I came across. Do we need to do those or just the ex. Sets?
UserIdTAG: 916875
UserNameTAG: nilufa
CreateTimeTAG: 2013-02-28T15:09:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I found the suggested problems from the online textbook to be helpful, and advise you to do them.
FirstChildUserIdTAG: 83185
FirstChildUserNameTAG: oysteingrondahl
FirstChildCreateTimeTAG: 2013-02-28T15:38:24Z
FirstChildVoteTAG: 0
FirstChildTAG: The suggested problems from the text are not part of the course grade. They are for you to practice, if you wish. As oysteingrondahl says, students find them useful. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T19:51:33Z
FirstChildVoteTAG: 0
IndexTAG: 1765
TitleTAG: Careful reading, statistics and late night crying.
What strikes me is the very careful reading required of the material and the exercises.
There is no hurrying when doing the reading, making notes after you read and the reread.
Now the above does not mean one will not cry at all, but the tears are more likely to be of joy from using a steady and sensible approach to learning a difficult and sometimes tortuously precise subject.
And by way of note, here in England, school children of 11 years are doing some topics of this course are doing as part of the curriculum.
UserIdTAG: 344400
UserNameTAG: carlallen
CreateTimeTAG: 2013-02-28T14:54:25Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Yeah. If the course was in my native language, I would suggest it to my younger sister (she's in high school now, doesn't speak English well enough yet). The lecturer makes everything very clear and understandable.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T18:48:41Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks, carlallen, for picking up a key ingredient in any decent statistical analysis: a careful formulation of the problem and an equally careful choice of methods. Let's hope the hankies only come out because you are overwhelmed with delight. Cheers,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T23:26:20Z
FirstChildVoteTAG: 0
IndexTAG: 1766
TitleTAG: Unable to do 2nd Submission for Problem 1
I coudn't submit values for 2nd submission !
But yes it is Fun !!
UserIdTAG: 1129606
UserNameTAG: navneetshrivastava
CreateTimeTAG: 2013-02-28T14:43:01Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1767
TitleTAG: GMT 23.30
This timing is not great for people who are studying or working in the Western Hemisphere, 9.00 to 5.00
UserIdTAG: 1308941
UserNameTAG: FrankF
CreateTimeTAG: 2013-02-28T14:18:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: It is a deadline. You have a whole week to do it. You can work on weekends and in your own free hours. Just don't leave it until the last minute and you'll be fine.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T14:24:28Z
FirstChildVoteTAG: 6
FirstChildTAG: > This timing is not great for people who are studying or working in the Western Hemisphere, 9.00 to 5.00
You get *exactly* the same amount of time as a person on the other side of the planet. And you have an entire week.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T20:19:23Z
FirstChildVoteTAG: 1
IndexTAG: 1768
TitleTAG: Doubt about Week2:Exercise Set4: Problem7
Hello Prof. Adhikari and Staff
First, thank you very much for this course. It is amazing. :>
Second: I am having problems understanding Week2: Exercise Set4: Problem7.
I think, the total duration of the fundraising campaign is needed.
We only have the average raised by the 12 members in the first month. How many months the campaign will last?.
BTW: If I am going in the wrong direction :>, please let me know.
UserIdTAG: 236109
UserNameTAG: RubenOnlineLearning
CreateTimeTAG: 2013-02-28T14:13:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The time is not an issue at all. You know that they have pledged to raise a total of 100000. So far they have raised an average of 5200 (I think, I'm quoting from memory) per person. So you just have to calculate how much is left for them to raise on average per member. Whether they raise it in a week or a year has no bearing on the result. Hope that helps.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T14:28:33Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks a lot for the explanation. I had the same question and your answer was very useful !!!
SecondChildUserIdTAG: 1069830
SecondChildUserNameTAG: TheodoraCh
SecondChildCreateTimeTAG: 2013-02-28T15:36:02Z
SecondChildVoteTAG: 0
SecondChildTAG: acc. to your explanation and approach the answer will not be correct. I've already tried that method.
SecondChildUserIdTAG: 18215
SecondChildUserNameTAG: mhr201
SecondChildCreateTimeTAG: 2013-02-28T15:45:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Check again, it worked for me
SecondChildUserIdTAG: 1240022
SecondChildUserNameTAG: Moshiko
SecondChildCreateTimeTAG: 2013-03-01T12:38:11Z
SecondChildVoteTAG: 0
IndexTAG: 1769
TitleTAG: to Indonesian students, please read this post :)
Dear all,
please let me introduce my self first, I am Inayati and this is my second course in EDX after having PH207x in previous months :). Since this post is particularly written for Indonesian students in this Stat2.1x course, please let me further write in Indonesian language :).
Teman teman, adakah yang mengetahui informasi adanya group diskusi course Stat2.1x yang sudah dibentuk? Senang sekali bila ada yang dapat menginformasikan keberadaan grup tersebut mengingat pengalaman saya sebelumnya, adanya grup diskusi PH207x di Facebook amat membantu saya untuk memahami materi lebih lanjut karena masing masing dari kami dapat saling membantu mencerahkan bila ada materi yang tidak jelas ataupun tugas yang membingungkan :). Terimakasih sebelumnya atas informasinya :).
Warmly
Inayati
di GMT +1
UserIdTAG: 190011
UserNameTAG: inayati
CreateTimeTAG: 2013-02-28T13:47:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Kamu bisa coba di facebook untuk
edx indonesia.. tapi kita masih mengikuti "Honor Code"... jadi hanya sebatas pertanyaan penjelasan yang mungkin kita bisa bantu.
Semoga bisa bersama-sama salaing belajar.
FirstChildUserIdTAG: 1213285
FirstChildUserNameTAG: JUSTANDY
FirstChildCreateTimeTAG: 2013-02-28T16:35:08Z
FirstChildVoteTAG: 0
SecondChildTAG: iya, tadi saya sudah menengok sebentar grup nya, sayangnya tidak spesifik ya sehingga ruang lingkup diskusinya di postingannya masih terlalu luas :(.
SecondChildUserIdTAG: 190011
SecondChildUserNameTAG: inayati
SecondChildCreateTimeTAG: 2013-03-01T09:44:50Z
SecondChildVoteTAG: 0
FirstChildTAG: hadir.. hehehe
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-02-28T17:19:16Z
FirstChildVoteTAG: 0
SecondChildTAG: sudah dicatat mas :)
SecondChildUserIdTAG: 190011
SecondChildUserNameTAG: inayati
SecondChildCreateTimeTAG: 2013-03-01T09:40:12Z
SecondChildVoteTAG: 0
FirstChildTAG: I am not Indonesian,but curiosity is getting the better of me. What are you guys talking about?
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-02-28T18:39:30Z
FirstChildVoteTAG: 0
SecondChildTAG: well, actually I asked in my previous post whether anyone among Indonesian students know already with regard to the discussion group of this course which is specifically solely for Indonesian. That's all :).
SecondChildUserIdTAG: 190011
SecondChildUserNameTAG: inayati
SecondChildCreateTimeTAG: 2013-03-01T09:43:52Z
SecondChildVoteTAG: 0
IndexTAG: 1770
TitleTAG: Exercise set three
I have read and re- read for the lecture on percentiles and histograms. I thought I finally understood it but when I started on exercise set three, I got them all wrong.How did you guys calculate the median, lower quartile and upper quartile? I have a formular that I used in school. like median would be (n+1)/2 and for the sake of the exercise I followed the lecturers instructions but I still got them wrong. Help
UserIdTAG: 1246920
UserNameTAG: dzame
CreateTimeTAG: 2013-02-28T13:24:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1771
TitleTAG: 3b)
I don't understand this part.
"the area between 0 and 50 is 75%; therefore, the 75th percentile is 50 thousand dollars". Well, 75th percentile is -8.8 according to the histogram, isn't it?
UserIdTAG: 1133472
UserNameTAG: hirogotanda
CreateTimeTAG: 2013-02-28T13:15:46Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: Where are you getting 8.8?
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-28T16:21:03Z
FirstChildVoteTAG: 0
SecondChildTAG: You already have the 75th being 50,000, now just find out how much the 25th is and than subtract the two.
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-28T16:23:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Behind the game here a bit (in a remote location in developing country)-- but wouldn't the 75th percentile be 49 thousand dollars--- since the bin is exclusive of the right boundary?
FirstChildUserIdTAG: 1215198
FirstChildUserNameTAG: megsut
FirstChildCreateTimeTAG: 2013-03-06T22:02:37Z
FirstChildVoteTAG: 0
IndexTAG: 1772
TitleTAG: awesome course
This course is an exciting one.Thank you professor for launching this course as i have a great interest in statistics
UserIdTAG: 1033884
UserNameTAG: vaishalivashisht
CreateTimeTAG: 2013-02-28T13:11:21Z
VoteTAG: 5
CoursewareTAG: Section 1: Introduction / Lec 1.2. Variables: terminology
NumberOfReplyTAG: 0
IndexTAG: 1773
TitleTAG: Suggestion for forum guidelines
I think it might be helpful if, either in the guidelines document or in a separate course document, directions on how to use the discussion forum were posted. It occurred to me that perhaps some of the repetitive posts and/or posting in the wrong sub-forum might be because the student does not fully understand how the forum works. I know, for myself, a native English speaker but unfamiliar with fora, it was not all intuitive. I would think ESL issues might compound newness difficulty. *Perhaps assuming that all students know how to search for a topic, or select a sub-forum is contributing to the problem?* Just my humble two cents.
UserIdTAG: 986983
UserNameTAG: Dianebefd
CreateTimeTAG: 2013-02-28T13:06:42Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Hi,
from the day one of the course the following document is available:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
in short, that did not help at all
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T13:36:42Z
FirstChildVoteTAG: 0
SecondChildTAG: I know the guidelines are there. I read them before I posted my suggestion. My suggestion concerns more practical "how" information. Some people are new to online discussions (due to age or unavailability) and don't know how to post in a forum or sub-form, how to upvote, how to find posts by a specific person. If you did not think my suggestion helpful, simply ignore it, and this response, there is no reason to be unkind.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T14:49:24Z
SecondChildVoteTAG: 0
FirstChildTAG: I think it is also a function of the way the software works. I find this interface a bit cumbersome. In most forum interfaces, it is easy to see the number of replies to each topic. It is also sometimes possible to see the replies nested below the topics. That kind of interfaces makes it more likely that people will reply to a post in a "me too" sort of way rather than duplicate the topic. IN the forums in this course we only see the op post title and, on the exercise page, can't even tell if the post has any replies unless we expand it. Not very user friendly.
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T16:22:16Z
FirstChildVoteTAG: 0
FirstChildTAG: People couldn't read the course policies. Of course they won't read the forum guidelines! Most just don't care. Those who do, have read them. Look at all the repeat posts. Regardless of what others say, pleas to read the guidelines, etc - ignored.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T20:25:38Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree. Except, it took me a considerable length of time to figure out how the forum works because I've never participated in one. Having "how to" information in the guidelines would have helped me--I read them.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-01T14:51:21Z
SecondChildVoteTAG: 0
IndexTAG: 1774
TitleTAG: week 2
why r the discussion forums not open to week 2 course lectures and exercises yet?
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-02-28T12:37:44Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: i have got quite a few doubts in lecture 3.2-3.4 and would be glad if i can post my doubts undr the lecture itself
FirstChildUserIdTAG: 1028247
FirstChildUserNameTAG: thekid
FirstChildCreateTimeTAG: 2013-02-28T13:05:30Z
FirstChildVoteTAG: 0
SecondChildTAG: I have no problem with those lectures.
SecondChildUserIdTAG: 1312938
SecondChildUserNameTAG: Edmond14
SecondChildCreateTimeTAG: 2013-02-28T13:15:03Z
SecondChildVoteTAG: 0
SecondChildTAG: the exercise for week 2 are open. I've just finished answering problem 4 and
SecondChildUserIdTAG: 1312938
SecondChildUserNameTAG: Edmond14
SecondChildCreateTimeTAG: 2013-02-28T13:16:02Z
SecondChildVoteTAG: 0
FirstChildTAG: I noticed that Video Lectures 4.0 Intro, 4.1, 4.2, 4.3 do NOT have a direct download "Download Video here" link. Will the Course staff be providing these "Download Video here" links soon, say by Saturday Mar 2?
FirstChildUserIdTAG: 538198
FirstChildUserNameTAG: A_P
FirstChildCreateTimeTAG: 2013-02-28T16:20:05Z
FirstChildVoteTAG: 0
IndexTAG: 1775
TitleTAG: Stat 2
do we will have other parts of stat 2(stat 2.2 and state 2.3) also being offered?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T12:32:00Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes. I expect Stat 2.2X to start two weeks after Stat 2.1 X is complete. I don't have a firm date for Stat 2.3X but it should be shortly after 2.2X ends. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T20:40:30Z
FirstChildVoteTAG: 1
SecondChildTAG: thank you so much
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T13:50:19Z
SecondChildVoteTAG: 0
IndexTAG: 1776
TitleTAG: Regarding some variable
What Is The Meaning of ethinicity?
UserIdTAG: 933545
UserNameTAG: Prashant850
CreateTimeTAG: 2013-02-28T12:02:28Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Somwhere between culture, nationality, heritage and race - the subject of many a Human Geography dissertation! Here in the UK we have categories like "White British" and "Black Caribbean" - and lots of arguments about why we don't have "Black British" etc.
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-28T12:19:47Z
FirstChildVoteTAG: 1
SecondChildTAG: ok
SecondChildUserIdTAG: 1017150
SecondChildUserNameTAG: siva1969
SecondChildCreateTimeTAG: 2013-02-28T12:24:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Certainly have "Black British" on a number of forms I see. It's a sub-category under Black, like White British is under White.
SecondChildUserIdTAG: 41340
SecondChildUserNameTAG: FPike
SecondChildCreateTimeTAG: 2013-02-28T13:11:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Fair comment - it wasn't an option on the forms I used to have to request from parents, which I think were based on census classifications. It's an example of where a statistical "need" is in conflict with how individuals identify themselves. We needed to monitor differences in educational outcomes between - say - "Black African" girls and "White Eastern European" boys - and do something about any issues identified; the parents were understandably more interested in their children as individuals. You used to be able to "enhance" a school's relative performance by "encouraging" the use of categories with lower estimated outcomes. Not sure how significant the effect was - maybe I will look at it again after this course!
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-28T13:29:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Ethnicity is the noun form of the word ethnic which means of a particular group with a common national or cultural identity. Examples:
In the Ukraine, there are more than three million ethnic Russians. --This means that they are citizens of the Ukraine but are of Russian descent.
If English is not your first language, I suggest "Dave's ESL cafe" website for resources.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-02-28T12:23:06Z
FirstChildVoteTAG: 0
SecondChildTAG: non local residents of the area
SecondChildUserIdTAG: 1017150
SecondChildUserNameTAG: siva1969
SecondChildCreateTimeTAG: 2013-02-28T12:25:54Z
SecondChildVoteTAG: 0
FirstChildTAG: good information relating to the specific situation
FirstChildUserIdTAG: 1017150
FirstChildUserNameTAG: siva1969
FirstChildCreateTimeTAG: 2013-02-28T12:26:14Z
FirstChildVoteTAG: 0
IndexTAG: 1777
TitleTAG: Homework Exercise 3 problem #2
I had a lot of trouble with homework exercise 3 problem #2: the stem and leaf chart.
I counted the total number of data. I got 28. I used a fraction to determine the percentage of data in each range (ie. intervals from 40-49, 50-59, etc).
I then proceeded to calculate percentiles using the method from the lecture:
1) find the interval in which the percentile you are seeking to estimate
2) use the fraction of the percent needed to reach the target percentile and multiply that by the interval (in other words the width of the bar)
3) I took that value and added it to the left most number in that interval
I thought that would easily give me the percentile but all my answers were wrong. Can anyone share how they solved this problem?
UserIdTAG: 768544
UserNameTAG: percyhegemony
CreateTimeTAG: 2013-02-28T11:38:18Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Use the method in Lecture 2.5.
FirstChildUserIdTAG: 875495
FirstChildUserNameTAG: tldegray
FirstChildCreateTimeTAG: 2013-02-28T13:13:00Z
FirstChildVoteTAG: 0
SecondChildTAG: I mistakenly have put the decimal sign in the numbers....So I burnt both submissions :-(
SecondChildUserIdTAG: 620062
SecondChildUserNameTAG: nmilevska
SecondChildCreateTimeTAG: 2013-02-28T18:55:32Z
SecondChildVoteTAG: 0
IndexTAG: 1778
TitleTAG: submission
Hi,
I joined the course only today. Is it possible to get couple of days extension for the submission of the assignments please?
UserIdTAG: 1328714
UserNameTAG: InternetJockey
CreateTimeTAG: 2013-02-28T11:33:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: No, it is not possible.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T11:36:47Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi, I joined the course only today. Is it possible to get couple of days (up to Sunday) extension for the submission of the assignments please? I need your reply ASAP.
SecondChildUserIdTAG: 953708
SecondChildUserNameTAG: Muluaderie
SecondChildCreateTimeTAG: 2013-02-28T14:51:18Z
SecondChildVoteTAG: 0
SecondChildTAG: Did you read the reply that you posted to?
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T20:23:35Z
SecondChildVoteTAG: 0
FirstChildTAG: Yeah because they already extended deadlines two times .But still try to solve as much problems/exercises as you can and then otherwise focus on next exercises .I feel you still have chances to get the certificate (if you are targeting that )so don't loose hope .Good luck :)
FirstChildUserIdTAG: 92822
FirstChildUserNameTAG: ShashiBhagendra
FirstChildCreateTimeTAG: 2013-02-28T14:46:36Z
FirstChildVoteTAG: 0
IndexTAG: 1779
TitleTAG: about the exam
i am new in this online course. so please tell me the criteria for passing it. i have done the exercise sets from week one and i have done good so far. but i have not done the practice test.
UserIdTAG: 239910
UserNameTAG: bikalpa
CreateTimeTAG: 2013-02-28T11:17:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Go to the tab "Course Info" on the top of this page https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info and click the link on the right hand side "Course Policies and Requirements" https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf. You will find the information there.
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-02-28T11:33:29Z
FirstChildVoteTAG: 0
FirstChildTAG: Do you mean you have submitted the Exercise Sets but not the Practice exercises which are listed above? If not, get a move on with submitting the three Exercise Sets - you have until 23.30 GMT today. Depending on where in the world you are, you could have earlier or later local time.
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-02-28T13:13:46Z
FirstChildVoteTAG: 0
IndexTAG: 1780
TitleTAG: Excercise 5 problem 2
My answer is -1.5 & its wrong?? i dont get it???
UserIdTAG: 879928
UserNameTAG: yasirihsan
CreateTimeTAG: 2013-02-28T11:10:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Do the calculations again. Watch your signs.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T11:15:49Z
FirstChildVoteTAG: 0
SecondChildTAG: -16 -3 5 8 .....-19 +13 = -6 & by dividing it on 4 i got -1.5 as mean
SecondChildUserIdTAG: 879928
SecondChildUserNameTAG: yasirihsan
SecondChildCreateTimeTAG: 2013-02-28T11:23:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Recalculate the average and check all your + and -.
(Also, please note that this question does not belong in the discussion forum on exercise set 1.)
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-02-28T11:19:20Z
FirstChildVoteTAG: 0
SecondChildTAG: -19 +13 = -6 & by dividing it on 4 i got -1.5 as mean
SecondChildUserIdTAG: 879928
SecondChildUserNameTAG: yasirihsan
SecondChildCreateTimeTAG: 2013-02-28T11:23:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Did you get the Practice for Exercise Set 5 correct?
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-02-28T11:28:10Z
SecondChildVoteTAG: 0
SecondChildTAG: And did you watch the lectures in section 3? Re-watch 3a carefully, Prof A explains in detail how to calculate the average in this case...
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-02-28T11:31:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Ohh okay..thanks alot :)
SecondChildUserIdTAG: 879928
SecondChildUserNameTAG: yasirihsan
SecondChildCreateTimeTAG: 2013-02-28T11:37:04Z
SecondChildVoteTAG: 0
IndexTAG: 1781
TitleTAG: exrsise4 prob 5,6 ans plzzzz sm1 hlp me with the ans
how 2 calculate them
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-02-28T10:47:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: This might help you to follow the guidelines of this forum and ask questions that do not breach the honor code: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
If you need help, post specific questions on the problems you encountered. That way, other students might be able to guide you in the right direction. We are all aiming to expand our knowledge, not only get a certificate, aren't we?
Did you watch the lectures?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-02-28T11:08:13Z
FirstChildVoteTAG: 1
SecondChildTAG: prob 6 my ans is a is wrong but why? i dnt undrstnd?explain it
SecondChildUserIdTAG: 1042429
SecondChildUserNameTAG: Rifayat
SecondChildCreateTimeTAG: 2013-02-28T11:27:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I am not clairvoyant and thus cannot know how you got to that answer so I cannot tell you what is wrong with your train of thought. You have to explain yourself better if you want people to help you. Did you watch the lecture in section 3b and read the text book?
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-02-28T11:40:14Z
SecondChildVoteTAG: 0
IndexTAG: 1782
TitleTAG: week 2 exercise set 4 problem 8
Can any one help me how to calculate average cost of 32 house?
UserIdTAG: 393580
UserNameTAG: Aditiak
CreateTimeTAG: 2013-02-28T10:15:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You don't need to know the average to find out the **change** in average
FirstChildUserIdTAG: 42051
FirstChildUserNameTAG: cjscott
FirstChildCreateTimeTAG: 2013-02-28T10:28:12Z
FirstChildVoteTAG: 0
IndexTAG: 1783
TitleTAG: Exercise Set 6 Q3
I think Exercise Set 6 Q3 is incorrect. Without giving too much away List A could be 25 values of 100 with an average of 100 and standard deviation of zero.
UserIdTAG: 1099155
UserNameTAG: RichardMoore
CreateTimeTAG: 2013-02-28T10:15:03Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 8
FirstChildTAG: I *think* I agree, and *believe* that I can refute all the options - but having "answered the wrong question" a couple of times in week 1 I'm mulling it over for a bit longer!
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-28T11:00:09Z
FirstChildVoteTAG: 2
FirstChildTAG: I totally agree and hence answered what I thought was most correct... i.e. allowed for both criteria but others also. Luckily they give two submissions...
FirstChildUserIdTAG: 1181263
FirstChildUserNameTAG: drush
FirstChildCreateTimeTAG: 2013-02-28T13:10:43Z
FirstChildVoteTAG: 0
FirstChildTAG: If you check carefully the options are not fully right. Though I found the right answer as-per the key but not fully satisfied with the options available.
**May be the instructors can have a look at it. If we find all the possibilities for list A then the options needs to be slightly corrected.**
FirstChildUserIdTAG: 1312166
FirstChildUserNameTAG: Sudeep_Macha
FirstChildCreateTimeTAG: 2013-02-28T14:45:45Z
FirstChildVoteTAG: 1
FirstChildTAG: If I add the average value to a list, this can not enlarge the standard deviation, right?
FirstChildUserIdTAG: 148610
FirstChildUserNameTAG: schwanke
FirstChildCreateTimeTAG: 2013-02-28T19:00:04Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree with the OP, I think the question should have stated lists cannot be entirely made of 100s, otherwise we could have a different answer
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-28T20:24:59Z
FirstChildVoteTAG: 1
FirstChildTAG: Yep - stopped stressing, assumed list A was not all 100's and got the magic tick. Still think it was the "least wrong option" though.
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-28T20:33:53Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks, everyone. Take a look at the question again; I believe I've addressed your concern. Please let me know if you got the big red cross. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T23:00:24Z
FirstChildVoteTAG: 3
SecondChildTAG: I got the red cross.
SecondChildUserIdTAG: 523951
SecondChildUserNameTAG: VelizarHr
SecondChildCreateTimeTAG: 2013-03-01T00:06:24Z
SecondChildVoteTAG: 0
SecondChildTAG: OK, I'll let the engineers know. They'll be able to see which entry you chose.
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-03-01T00:50:50Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks a lot
SecondChildUserIdTAG: 148610
SecondChildUserNameTAG: schwanke
SecondChildCreateTimeTAG: 2013-03-01T05:21:41Z
SecondChildVoteTAG: 0
SecondChildTAG: and i got red cross, and don't why
SecondChildUserIdTAG: 1258247
SecondChildUserNameTAG: Kolbas
SecondChildCreateTimeTAG: 2013-03-03T11:13:09Z
SecondChildVoteTAG: 0
SecondChildTAG: oh, sorry, my problem with exersize 6 Q 6
SecondChildUserIdTAG: 1258247
SecondChildUserNameTAG: Kolbas
SecondChildCreateTimeTAG: 2013-03-03T18:12:33Z
SecondChildVoteTAG: 0
SecondChildTAG: I got the red cross as well.
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-03-04T11:45:56Z
SecondChildVoteTAG: 0
SecondChildTAG: I got the red cross
SecondChildUserIdTAG: 1053411
SecondChildUserNameTAG: Lodeca
SecondChildCreateTimeTAG: 2013-03-06T11:13:06Z
SecondChildVoteTAG: 0
SecondChildTAG: i got the red cross
SecondChildUserIdTAG: 1267785
SecondChildUserNameTAG: toibigi
SecondChildCreateTimeTAG: 2013-03-06T17:14:34Z
SecondChildVoteTAG: 0
SecondChildTAG: i got the red cross too
SecondChildUserIdTAG: 951663
SecondChildUserNameTAG: aprilumali12
SecondChildCreateTimeTAG: 2013-03-06T21:03:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I also got the red cross.
SecondChildUserIdTAG: 913981
SecondChildUserNameTAG: DSamuel
SecondChildCreateTimeTAG: 2013-03-06T23:26:08Z
SecondChildVoteTAG: 0
FirstChildTAG: I also got the big red cross, due to the assumption I made in my reasoning. Perhaps if the staff decide this question is ambiguous (as others above have commented), the 3 points for this question could be removed from the overall assessment mark for Set 6.
FirstChildUserIdTAG: 946554
FirstChildUserNameTAG: DavidH-Aus
FirstChildCreateTimeTAG: 2013-03-03T00:44:16Z
FirstChildVoteTAG: 0
SecondChildTAG: but it was amended 4 days ago to remove the ambiguity...
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-03-04T19:27:36Z
SecondChildVoteTAG: 0
IndexTAG: 1784
TitleTAG: Set 4 - problem 4
Does anyone else think this question was too ambiguous?
UserIdTAG: 42051
UserNameTAG: cjscott
CreateTimeTAG: 2013-02-28T10:01:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: To be honest, I think it was pretty straightforward and you could also use the calculator if you wanted to be completely sure :/
FirstChildUserIdTAG: 1313846
FirstChildUserNameTAG: efreixas
FirstChildCreateTimeTAG: 2013-02-28T10:11:02Z
FirstChildVoteTAG: 2
SecondChildTAG: I agree with efreixas.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T11:39:09Z
SecondChildVoteTAG: 0
FirstChildTAG: I also thought it was ambiguous. I thought they were looking for the average of 103, 105 and 108 since they had just described those numbers. Oh well, live and learn.
FirstChildUserIdTAG: 260168
FirstChildUserNameTAG: Jeff2012
FirstChildCreateTimeTAG: 2013-02-28T21:28:58Z
FirstChildVoteTAG: 0
IndexTAG: 1785
TitleTAG: Solutions for First week exercises
Kindly provide the solutions for all exercises in the First week...........I am unable to see the final solutions.
Many thanks
Dr.Harish
UserIdTAG: 1175422
UserNameTAG: harish09
CreateTimeTAG: 2013-02-28T09:53:34Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Submission deadline has been extended, so please be patient!
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-02-28T10:00:05Z
FirstChildVoteTAG: 0
FirstChildTAG: If you look at at the course information page [here][1] then you will see that the deadline for submission of the first week exercises has been extended to 23.30GMT today. Inevitably this will delay publication of the solutions.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-28T10:04:31Z
FirstChildVoteTAG: 0
IndexTAG: 1786
TitleTAG: Stop blaming the staff
I don't understand why are you complaining so much. From the very beginning of the course the dates and the timezone of the exercises were clearly specified. When you enroll into a course, it's you responsability to read the information the staff provides you, so please stop complaining and blaming the staff, because all the information needed was clearly posted. As I said, if you enroll into a course and you don't read the course info, what do you expect? Please, be serious and assume your own responsabilities.
UserIdTAG: 1108368
UserNameTAG: BlancaR
CreateTimeTAG: 2013-02-28T09:44:22Z
VoteTAG: 17
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Blanca, we are coming from around the globe. the diversity is the point. and it makes different point of view in seeing things. some maybe dont understand, some maybe too busy to read the information. but yeah you are rite, we have to be serious and responsible. since many of us are new in this online course, students dont know what to do at the first. and maybe some of us is not using english as our daily conversation make us read every text detailly to understand the meaning of the text. hope you understand what i mean. for my english is really bad. :)
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-02-28T11:09:52Z
FirstChildVoteTAG: 0
SecondChildTAG: PREVIEWI didn't want to be rude with my coment, so sorry if i was. Of course I understand you (although English is not my daily language too), but in my opnion if you dont understand something you should ask (not complain), and if you are too busy to read the information, then dont blame others. As if you said, if you dont know what to do at the first, the best thing you can do is read the information of the course, for sure. I only wanted to mean that I'm sure that many of us understood the timezone used since the beginning of the course (probably because we read the information posted) and from my point of view it's unfair to blame the staff for our own faults. But as said before sorry if I sound rude, I didn't mean to. ;o)
SecondChildUserIdTAG: 1108368
SecondChildUserNameTAG: BlancaR
SecondChildCreateTimeTAG: 2013-02-28T11:57:02Z
SecondChildVoteTAG: 0
FirstChildTAG: While there are always people who genuinely have to confront exceptional circumstances with respect to their other responsibilities in life, I wholeheartedly agree with you.
Beyond my own pride and desire to improve myself, I feel an extra motivation to do well in this course because I am grateful for the efforts of the professor, her colleagues and EDX. This means I want to do my part to demonstrate that they are not involved in a futile effort. The same holds true for all of the other wonderful mass learning initiatives. Out of selfishness, I want more opportunities to learn new, useful and interesting things. At the same time, I truly believe these programs can be a general force for good in the world.
As a result of my views, I felt embarrassed when I crashed and burned on the second section test for the first week. I felt I let myself down, and by extension, let the program down. Assessing my efforts honestly, I quickly realized I'd not given the material my undivided attention. I remedied this for the third section, and surprise, did just fine on the test.
Like anything, one gets what they put in. While this course isn't perfect, since ANYTHING can be improved, I've seen no flaws that should prevent any participant who puts in the time and effort from doing well.
FirstChildUserIdTAG: 905578
FirstChildUserNameTAG: ironyisoverrated
FirstChildCreateTimeTAG: 2013-02-28T16:12:48Z
FirstChildVoteTAG: 2
FirstChildTAG: It's easier to blame someone else than take responsibility yourself. The blame game is how society seems to work these days.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T20:21:16Z
FirstChildVoteTAG: 0
SecondChildTAG: I believe the staff is doing great work. Thanks
SecondChildUserIdTAG: 826276
SecondChildUserNameTAG: acamacho5
SecondChildCreateTimeTAG: 2013-02-28T20:51:43Z
SecondChildVoteTAG: 0
IndexTAG: 1787
TitleTAG: Set 4 problem 7
I would appreciate if someone could tell me what do they refer to when they ask 'how much money must they raise, on average, to keep the pledge'. I mean, money in total? Each member? Within a time in concrete?
I've taken the difference between the aim and the current raised money and divided it by 12 and obviously is not that, but I had to try.
Thanks
UserIdTAG: 1313846
UserNameTAG: efreixas
CreateTimeTAG: 2013-02-28T09:35:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It sounds like your method is correct. I think the problem is not worded too clearly. They all pledge a **total** of $100,000. (The problem didn't say that so I had some confusion regarding whether the pledge was for each director or just for one). Hope this helps.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T09:44:58Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes,it helped! What I was doing wrong is that I counted that they had raised $5200 in total but it was each one of them so, of course, they had actually raised more money than that ;)
Thank you!!
SecondChildUserIdTAG: 1313846
SecondChildUserNameTAG: efreixas
SecondChildCreateTimeTAG: 2013-02-28T10:09:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Great!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T13:29:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks very much! I was also confused about that question and you helped making it clear! For others who had the same doubts:
Pledged total: $100 000
Raised so far (on average, not total): $5 200
The question asks how much needs to be raised still **on average**.
SecondChildUserIdTAG: 703576
SecondChildUserNameTAG: cmonteiro
SecondChildCreateTimeTAG: 2013-02-28T14:56:23Z
SecondChildVoteTAG: 0
SecondChildTAG: (Sorry for the repeat, but the formatting got messed up above.)
Thanks very much! I was also confused about that question and you helped making it clear! For others who had the same doubts:
- Pledged total: 100 000 dollars;
- Raised so far (on average, not total): 5 200 dollars;
- The question asks how much needs to be raised still **on average**.
SecondChildUserIdTAG: 703576
SecondChildUserNameTAG: cmonteiro
SecondChildCreateTimeTAG: 2013-02-28T14:58:33Z
SecondChildVoteTAG: 0
IndexTAG: 1788
TitleTAG: Excercise Set 2 Problem 2..
i have no idea how to do it. is there any clue to answer the problem. thanks
UserIdTAG: 1193006
UserNameTAG: makmursp
CreateTimeTAG: 2013-02-28T09:28:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: for 2a, what we need to do is to calculate the sum percents of the people with age 30, 31, 32, 33, 34, 35, 36, 37, 38, and 39 (by finding first the value of the percent per age and do pay attention to the interval of the group in order to find this value).
how to find the solution for 2b is pretty similar with previous one. We just need to calculate the the total percents of people with age above 65, namely 66, 67, 68, 69, 70, 71, 72, 73, 74, 75 and 75-100 (which is 6%).
hope it helps a little bit :).
FirstChildUserIdTAG: 190011
FirstChildUserNameTAG: inayati
FirstChildCreateTimeTAG: 2013-02-28T13:31:33Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks!!
SecondChildUserIdTAG: 826276
SecondChildUserNameTAG: acamacho5
SecondChildCreateTimeTAG: 2013-02-28T21:13:21Z
SecondChildVoteTAG: 0
SecondChildTAG: my pleasure :)
SecondChildUserIdTAG: 190011
SecondChildUserNameTAG: inayati
SecondChildCreateTimeTAG: 2013-03-01T09:47:56Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't get where I've made a mistake. I've calculated like this (12.5/15)*9 + 6 = 13.5 Does anyone have a clue?
FirstChildUserIdTAG: 302329
FirstChildUserNameTAG: markomarkovic
FirstChildCreateTimeTAG: 2013-02-28T22:15:44Z
FirstChildVoteTAG: 0
SecondChildTAG: are you sure it was "9"? :)
SecondChildUserIdTAG: 190011
SecondChildUserNameTAG: inayati
SecondChildCreateTimeTAG: 2013-03-01T09:47:43Z
SecondChildVoteTAG: 0
IndexTAG: 1789
TitleTAG: Set 2
Clearly the course, but assessments are not clear, not even define how to enter the response :(
UserIdTAG: 1061358
UserNameTAG: aline_mou
CreateTimeTAG: 2013-02-28T08:07:06Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 1790
TitleTAG: Simple explanation of where Chebychev's inequality comes from
This isn't quite a proof, but here is how I convinced myself of Chebychev's inequality. This is slightly advanced compared to how the course is being taught, but doesn't use any mathematical concepts that go beyond those used in the class.
We can intuitively picture that the way to get the most number of points at the **mean +/- n***$\sigma$, is to place almost all of the points at the mean (call this fraction **1-x**), and a small fraction of the points (**x**) at exactly **+/- n***$\sigma$ (fraction **x/2** at **mean + n***$\sigma$ and fraction **x/2** at **mean - n***$\sigma$).
Now we need to take the sum of the squares of the deviations. The square of the deviation for most of the terms (those at the mean) is 0, and the weighted sum of the squares will be $xn^2$$\sigma^2$.
The standard deviation, $\sigma$, is simply equal to the square root of the sum of the squares (I don't have to divide by anything because I've already used x to fractionally weight the data, much as was done in lecture for the computation of the mean).
Therefore,
$\sigma = \sqrt{x}n\sigma$
and we can rearrange this to eliminate $\sigma$ and obtain
$x = \dfrac{1}{n^2}$
Since my intuition tells me that this is the way to get the most measurements at **mean +/- n***$\sigma$, we can surmise that Chebychev's inequality
$x <= \dfrac{1}{n^2}$
is true for all distributions. This falls short of a proof because I haven't proven the initial intuitive statement about the distribution.
UserIdTAG: 174100
UserNameTAG: markpolak
CreateTimeTAG: 2013-02-28T07:35:37Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: You can prove it this way:
1. Prove Markov (not hard; write the sum for the average and break it into two pieces: one for the tail, and one for everything that goes before)
2. Apply Markov to the list of squared deviations.
I've been thinking about posting the algebra connected with the results in Sections 3 and 4. Interested?
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T08:52:38Z
FirstChildVoteTAG: 1
SecondChildTAG: Very interested!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T09:25:12Z
SecondChildVoteTAG: 0
SecondChildTAG: +1
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T09:30:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes please.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-28T09:33:30Z
SecondChildVoteTAG: 0
SecondChildTAG: much so
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-01T22:11:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes please, I'm anxious to remind myself how much high school algebra I've actually forgotten! Thank you so much for a great class.
SecondChildUserIdTAG: 1271361
SecondChildUserNameTAG: TerryBot
SecondChildCreateTimeTAG: 2013-03-02T04:42:32Z
SecondChildVoteTAG: 0
FirstChildTAG: I can "intuit" the lecture example by going back to Prof A's sharing analogy for the mean :-
If you have n people with an average age of 20 then there are 20 * n years of age in total.
If you want to know how many could possibly be over 80 then you have to share (divide) those years by 80 and so get a maximum of 20 / 80 * n or n / 4 (which implies everyone else is 0 - throw in negatives & it goes to pot as per Markov)
.... going away to think about turning that into algebra speak!
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-28T19:13:17Z
FirstChildVoteTAG: 1
SecondChildTAG: Interesting...
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-03-02T19:30:37Z
SecondChildVoteTAG: 0
FirstChildTAG: Ok, give me until the weekend. I'll post all the algebra associated with Sections 3 and 4. That will give MarianW time to convert to algebra his/her correct intuition about why Markov's inequality is true. And it will give me time to ensure that Week 3 is in the bag. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T20:16:07Z
FirstChildVoteTAG: 0
IndexTAG: 1791
TitleTAG: Adopt Timezone Standard for all EDX Courses
The beauty of the EDX model is its flexibility of time and place. The fact that students from all over the world can participate is incredible. Some things are not as easily negotiated. A deadline, for example. Because teachers and students want to meet deadlines, it is important and practical for EDX to adopt a standard timezone designation.
With a standard timezone for the whole of the EDX community, all users will always know which timezone is being used. The time should be stamped on the EDX page layout template. This is a valuable learning lesson for a workforce increasingly collaborating across timezones.
UserIdTAG: 769137
UserNameTAG: RedFern
CreateTimeTAG: 2013-02-28T07:33:35Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: So maybe you should be talking to edX about this.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T07:43:06Z
FirstChildVoteTAG: 0
FirstChildTAG: i couldnt be more agree with you Redfern,, yeah EDX has to think about it to help student understand the timezone. For some of us get confused about the time zone
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-02-28T08:37:34Z
FirstChildVoteTAG: 0
SecondChildTAG: totally agree. an indication right next to the hour/deadline which is in the upper left menu would be a good starting point
Most webinar providers (and Coursera) use the their local time as indication (e.g. EST), which makes the GMT usage here a bit confusing
SecondChildUserIdTAG: 1270740
SecondChildUserNameTAG: martinov
SecondChildCreateTimeTAG: 2013-02-28T08:55:20Z
SecondChildVoteTAG: 0
FirstChildTAG: The EdX default is GMT, I'm told, though faculty have the option to choose their timezone. EdX is an evolving platform, so this might not always have been the case. I agree that uniformity across courses will be helpful to those taking multiple EdX courses. But I can also see that my colleagues might want to decide on their own. It's not an easy problem, but I'll bring your suggestion to the attention of EdX.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T08:56:46Z
FirstChildVoteTAG: 3
SecondChildTAG: If you can suggest an improvement—the obvious, easiest for users would be to allow students to define their own timezone and let the system calculate time. It's what online forums do for, like 10 years now, so definitely doable.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T18:56:25Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem in this situation would be the timing of the release of answers, though I expect students could wait a day. I very much want the time zone to appear next to the time, everywhere a time appears. That seems like an easier matter to attend to, but I will bring all of this discussion's suggestions to the appropriate people. EdX is receptive to student input. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T23:05:12Z
SecondChildVoteTAG: 0
FirstChildTAG: When you do any sort of course, the teacher has a lot of discretion and, pretty much as long as things are not terribly unreasonable (not necessarily fair!), students adapt. It is absolutely reasonable and normal for a teacher to set his/her own due dates. A lot of international students would be aware that times and timezones are important for due dates, even more so when we are not physically present and not sharing the same time zones. If they aren't, it's never too late to learn! To all those who are complaining because they actually didn't read the course information, which was quite clear on this, I think a bit of humility and reflection might be in order. Your timezone is not necessarily the center of the universe. It is not mean or unfair just because you didn't read it correctly. Remember, this is meant to be a college level course!!! I think my teachers were less tolerant in high school.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T09:36:58Z
FirstChildVoteTAG: 0
FirstChildTAG: I suppose a uniform standard across courses might be less confusing. It seems a small matter though.
Although it is not difficult to get used to GMT, a running clock on the site might be helpful. However, it is easy to find a widget to add to your desktop, that will run on whatever timezone you set it to. My smart phone has that feature as well.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-02-28T12:30:05Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi Dianebefd, a widget is exactly what I use as well. I have one for each city whose time I need to track. They are very useful.
SecondChildUserIdTAG: 769137
SecondChildUserNameTAG: RedFern
SecondChildCreateTimeTAG: 2013-03-01T06:16:12Z
SecondChildVoteTAG: 0
IndexTAG: 1792
TitleTAG: Answers
It will be great if you send as the answers for exercise set 3. So that we can cross check our answers and correct answers
UserIdTAG: 1106167
UserNameTAG: Parthasarathi
CreateTimeTAG: 2013-02-28T07:21:26Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I second this idea
FirstChildUserIdTAG: 768544
FirstChildUserNameTAG: percyhegemony
FirstChildCreateTimeTAG: 2013-02-28T11:23:29Z
FirstChildVoteTAG: 0
FirstChildTAG: Will become visible shortly after the due date/time. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T23:05:53Z
FirstChildVoteTAG: 0
IndexTAG: 1793
TitleTAG: how to follow the course and submittal dates in case of absence?
I will be travelling 14th to 25th of March with too little time to follow the course; is there a possibility to stay in the course?
UserIdTAG: 1231201
UserNameTAG: wolkoe
CreateTimeTAG: 2013-02-28T07:07:35Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Think you will find the material will remain available for you to access beyond the prescribed weeks.
The passmark is only 35%. How much have you achieved now, after one week?
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-02-28T09:54:06Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks, I was not aware of the 35% passmark; no issue to miss the points of one weeks exercises. Wish you a good day
SecondChildUserIdTAG: 1231201
SecondChildUserNameTAG: wolkoe
SecondChildCreateTimeTAG: 2013-03-01T04:11:04Z
SecondChildVoteTAG: 0
IndexTAG: 1794
TitleTAG: [edX Staff]-PDF Lecture slide 3.3 and 3.4 not downloadable
please kindly check on the PDF lecture slides 3.3 and 3.4 as they are not downloadable.
Thanks.
UserIdTAG: 820147
UserNameTAG: frimpongmaxwellkwadwo
CreateTimeTAG: 2013-02-28T06:53:53Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They downloaded for me. (Chrome, Win8)
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T07:00:46Z
FirstChildVoteTAG: 1
IndexTAG: 1795
TitleTAG: Two submissions!
I have a doubt: If my first answer is correct but I have 2 submissions available... do I have to click final check??? or my answer is already checked and saved?
UserIdTAG: 1262618
UserNameTAG: MelanieMbg
CreateTimeTAG: 2013-02-28T06:53:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: If you have a green tick, then your answer is correct. So you do not need to try again.
If you have a red cross, you are wrong. If you have another submission then you can try again.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T06:58:07Z
FirstChildVoteTAG: 0
IndexTAG: 1796
TitleTAG: [Staff] Missing Download Option for Lecture -4
Dear Staff,
Download Option missed for Lecture - 4.
Requested to solve.
UserIdTAG: 99047
UserNameTAG: taminur
CreateTimeTAG: 2013-02-28T06:38:48Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Yup, to be exact is: Week 2, Section 4: Measures of spread
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-02-28T13:02:12Z
FirstChildVoteTAG: 2
FirstChildTAG: Yes, I have the same problem too.
FirstChildUserIdTAG: 892981
FirstChildUserNameTAG: YuanjiSun
FirstChildCreateTimeTAG: 2013-02-28T15:19:21Z
FirstChildVoteTAG: 1
IndexTAG: 1797
TitleTAG: Scores for Exercise 2
This put me in the 50th percentile. I hope at least that much.
UserIdTAG: 991819
UserNameTAG: Queen9302
CreateTimeTAG: 2013-02-28T06:26:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 1798
TitleTAG: Score on Exercise 3
I did not do too great. :(
UserIdTAG: 991819
UserNameTAG: Queen9302
CreateTimeTAG: 2013-02-28T06:24:56Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: There is always a next time! And your two lowest scores get dropped.
FirstChildUserIdTAG: 1189168
FirstChildUserNameTAG: esai23
FirstChildCreateTimeTAG: 2013-02-28T22:29:22Z
FirstChildVoteTAG: 0
IndexTAG: 1799
TitleTAG: 'Practice for Exercise Sets' and 'Exercise Sets' need to use consistent answer formatting!
I know that this will be addressed for future problem sets, but it is annoying to lose points for formatting issues such as adding a '%' symbol. In [Practice for Exercise Set 2][1], the fifth and sixth questions ask,
a) Height of -10 to 20 bar = ____________ % per unit
b) Height of 20 to 50 bar = ____________ % per unit
I initially entered these answers without '%', and the autograder marked them wrong. I therefore assumed that for [Exercise Set 2][2], Problem 2, we had to add '%' symbol as well.
a) About what percent of the people were in their thirties? Round your answer to one decimal place.
b) A common (though not universal) definition of "senior citizen" is "person over the age of 65". About what percent of the population were senior citizens? Round your answer to one decimal place.
My numerical answers were correct, but since I had added '%' symbol, my answers were marked wrong (sob). Having learned my lesson, on the first question of Problem 6 in [PS2][3], I avoided adding a '%' and got the question right.
What percent of students spent fewer than 4 hours in preparation?
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/36bcbc2a9dbd4f4b8546f13c035b2759/ca2db05b6d7a4e1b9ffd57e5b8b5c740/
[2]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/36bcbc2a9dbd4f4b8546f13c035b2759/941d9d6e8a3545f29b2a703b2412db88/
[3]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/36bcbc2a9dbd4f4b8546f13c035b2759/941d9d6e8a3545f29b2a703b2412db88/
UserIdTAG: 267644
UserNameTAG: gojun077
CreateTimeTAG: 2013-02-28T06:09:58Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I am having a hard time figuring out a and b. Any clue? I am not asking for the solution, just which way to go. Thanks
FirstChildUserIdTAG: 826276
FirstChildUserNameTAG: acamacho5
FirstChildCreateTimeTAG: 2013-02-28T07:11:32Z
FirstChildVoteTAG: 0
SecondChildTAG: @acamacho5:
1. Take a deep breath. Let us try to understand the scenario, and then the given problem.
2. The scenario contains two columns. Left column contains 'age intervals'. The Right column contains PERCENTAGE of people within each interval. Higher the percent, more the ABSOLUTE number of people within the interval.
3. Now read question (a) - Which interval contained more people: 5-15 or 15-20?. If you understand above point (2), the answer should be immediately obvious.
4. Now read question - (b) - Which interval was more crowded: 5-15 or 15-20. The question is not asking about absolute number of people. Let me take an example here. Age interval 5-15 contains Age 5,6,7,8,9,10,11,12,13,and 14 (i.e. the range is 10). So in all there are TEN ages which TOGETHER represent 13.3%. So if you distribute this 13.3% equally amongst each of the ten ages, each year would represent how many %? (Use the formula %/range).
![enter image description here][1]
5. Similarly, examine Age interval 15-20. What is the Range? What is the total percentage in Right column against it? Given this two values, what should be % per age?
6. Compare the values you get in Step 5 and 6 above. Find out which one is bigger. More the % PER AGE, more the crowding..
If you must take analogue, assume 5 people standing over 5 ft length on one hand (thus each getting to stand over a feet) and on the other hand assume 2 people trying to stand over 1 foot length, each getting just 1/2 ft, making it crowded even though first scenario has more people (5), compared to second one (2). This is what the DENSITY FUNCTION lecture was about.
Hope this explains.
[1]: https://edxuploads.s3.amazonaws.com/13620438611343682.jpg
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-28T09:32:18Z
SecondChildVoteTAG: 0
IndexTAG: 1800
TitleTAG: First Week Assignment
Thank you for allowing me to attempt the third part of the assignment after the first deadline had passed. I did so much better on section 3 than on section 2.
UserIdTAG: 868031
UserNameTAG: CaliforniaViv
CreateTimeTAG: 2013-02-28T06:00:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Excellent. Great to see you more encouraged than you seemed yesterday. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T07:01:30Z
FirstChildVoteTAG: 0
SecondChildTAG: Exercise set 3 was good
SecondChildUserIdTAG: 1106167
SecondChildUserNameTAG: Parthasarathi
SecondChildCreateTimeTAG: 2013-02-28T07:22:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Enjoyed the exercise set 3
FirstChildUserIdTAG: 1106167
FirstChildUserNameTAG: Parthasarathi
FirstChildCreateTimeTAG: 2013-02-28T07:24:26Z
FirstChildVoteTAG: 0
IndexTAG: 1801
TitleTAG: Quick way to check GMT (Greenwich Mean Time)
I confess I was also ignorant of 2.1x using GMT as the time convention. I assumed it was using U.S. Eastern Standard Time (the convention for MITx classes). To check GMT, go to the Google search page and type: [time in greenwich, uk][1] and it will show you time in GMT. For those of you to the west of Greenwich, London, you must *subtract* from GMT, while those to the east must *add* to GMT. United States EST is **GMT - 5**, while the West Coast of the US is **GMT - 8**. Here in Seoul, Korea, local time is **GMT + 9**. There's a nice GMT chart for cities around the world [here][2].
[1]: https://www.google.com/webhp?hl=en&tab=mw#hl=en&sclient=psy-ab&q=time%20in%20greenwich,%20uk&oq=time%20in%20greenwich,%20uk&gs_l=hp.3..0j0i5i30.16172.17073.2.17360.4.4.0.0.0.0.114.423.1j3.4.0.les;..0.0...1c.1.5.psy-ab.clXBQB5W5DI&pbx=1&bav=on.2,or.r_gc.r_pw.r_cp.r_qf.&bvm=bv.43148975,d.dGI&fp=4175446c85fca0c3&biw=1440&bih=784
[2]: http://wwp.greenwichmeantime.com/info/timezone.htm
UserIdTAG: 267644
UserNameTAG: gojun077
CreateTimeTAG: 2013-02-28T05:57:42Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Thanks gojun077, you could publish this info in the Wiki. It would be very helpful.
Best.
FirstChildUserIdTAG: 491947
FirstChildUserNameTAG: Lamiak
FirstChildCreateTimeTAG: 2013-02-28T06:30:58Z
FirstChildVoteTAG: 1
SecondChildTAG: Good idea-- over the weekend I'll add a page to the wiki!
SecondChildUserIdTAG: 267644
SecondChildUserNameTAG: gojun077
SecondChildCreateTimeTAG: 2013-02-28T17:53:38Z
SecondChildVoteTAG: 0
FirstChildTAG: i hope this helps
http://www.timeanddate.com/worldclock/converter.html
FirstChildUserIdTAG: 1162306
FirstChildUserNameTAG: Matrix07
FirstChildCreateTimeTAG: 2013-02-28T13:06:33Z
FirstChildVoteTAG: 0
FirstChildTAG: An article explaining GMT and daylight saving time (which ends in many countries during varied dates in the spring) is now on the course Wiki.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-03-01T14:36:39Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks for adding info about Daylight Savings Time in the U.S.! It's interesting to note that U.S. Eastern time zone will become **GMT - 4** from GMT -5 after Mar. 10-- so confusing. Here in Korea we don't use DST at all (but then again, we're a tiny country that exists in a single time zone).
SecondChildUserIdTAG: 267644
SecondChildUserNameTAG: gojun077
SecondChildCreateTimeTAG: 2013-03-03T14:29:15Z
SecondChildVoteTAG: 0
IndexTAG: 1802
TitleTAG: bad grades, any tinng wrong with the machine?
did anyone notice that even you use the right formulas gaved in the lecture the results are incorrects?
UserIdTAG: 977559
UserNameTAG: MarieYolande
CreateTimeTAG: 2013-02-28T05:48:30Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Not really.
FirstChildUserIdTAG: 982840
FirstChildUserNameTAG: AhadAlex
FirstChildCreateTimeTAG: 2013-02-28T06:21:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi there.
Be careful when using the formula for calculating percentiles using histogram.
Formula is
Start point + percentage of the next bar needed multiplied by bar width of the bar being used.
The notes don't make it clear (although they are superb notes), that you need to do the multiplication bit first then add the start point to this result. The notes assume you know the hierarchy.
Must do the multiplication bit first and then add the start point otherwise you get two different answers.
Hope this helps.
FirstChildUserIdTAG: 940205
FirstChildUserNameTAG: PJButler
FirstChildCreateTimeTAG: 2013-02-28T07:31:11Z
FirstChildVoteTAG: 1
SecondChildTAG: BODMAS
SecondChildUserIdTAG: 41340
SecondChildUserNameTAG: FPike
SecondChildCreateTimeTAG: 2013-02-28T10:10:18Z
SecondChildVoteTAG: 0
IndexTAG: 1803
TitleTAG: Finally got a100% with no syste, issues.
I am enjoying this experience. Ive signed up for 2 more classes. I love to learn.
UserIdTAG: 742199
UserNameTAG: Timbo359
CreateTimeTAG: 2013-02-28T05:24:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1804
TitleTAG: Extension
To the instructors. Thank you for the extension and I will not miss the 23:30 GMT deadline again.
UserIdTAG: 1324450
UserNameTAG: Busathe
CreateTimeTAG: 2013-02-28T05:03:48Z
VoteTAG: 9
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes, thank you. GMT time from now on.
FirstChildUserIdTAG: 348290
FirstChildUserNameTAG: joshb
FirstChildCreateTimeTAG: 2013-02-28T05:34:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Same here. Thank you.
SecondChildUserIdTAG: 1189168
SecondChildUserNameTAG: esai23
SecondChildCreateTimeTAG: 2013-02-28T22:29:42Z
SecondChildVoteTAG: 0
IndexTAG: 1805
TitleTAG: I'm a new student
Hello Prof. A and Everybody here.
I just started today (27/02) in this class and I see the deadline to upload the excercises is 28/02. I don't know what to do because there's no much time left to me!
I don't want to miss this class and this weight of my score.
Could you help me or advise me about what I should do.
Thank you in advance.
Hingler Guardado.
UserIdTAG: 1327580
UserNameTAG: Hingler
CreateTimeTAG: 2013-02-28T05:00:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Passing grade is 35%. Attempt the assignments without studying much - it's not difficult.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-02-28T05:51:35Z
FirstChildVoteTAG: 0
FirstChildTAG: I would suggest go the sections in sequential order. As soon as you complete seeing video for a given section, immediately attempt the exercise. That way you are sure to score in a given exercise set rather than taking a blind shot, unless you are familiar with statistics.
Also, sequential navigation would help in forming a complete picture rather than viewing lectures in haphazard manner since there are cross references made to the lectures and concepts are built sequentially.
Time is enough to complete all videos (you would need about 2 hrs max for week 1 videos and equal amount of time for exercises). So, you can still make it well before the deadline! Also, there is plenty of help and hints scattered all over the forum. Make use of it.
Take advantage of the extended deadline! You are really fortunate to be getting one! And do not worry about grades. Certificates do not display grades, if that is a bother!
Best Wishes.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-28T09:01:25Z
FirstChildVoteTAG: 0
FirstChildTAG: You'll be fine. The best and ONLY place to start is the Course Info. Read it ALL. When you've finished reading it, you'll realize that the question that you just asked will be answered and you will avoid a lot of problems in the future. A lot of people are having problems because they did not read all this information carefully.
Then go ahead with the course from the beginning. Deadlines for the first exercises have been extended so you're in real luck. But get cracking right now! Good luck with the rest of the course!
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T09:40:35Z
FirstChildVoteTAG: 0
IndexTAG: 1806
TitleTAG: Submit buttons are back
People, I am on EST time, in Washington Dc. I submitted my answers around 11:30 local time, but my last click on the submission button was more like 11:33 or 11:34. It worked for me. I suspect that Allah himself has interceded and shown us some mercy in his or her benevolent wisdom. Do yourself a favor and take advantage of it! You probably have a few hours left! namaste.
UserIdTAG: 450628
UserNameTAG: ctr
CreateTimeTAG: 2013-02-28T04:51:08Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: What I want to know now is what time zone are we using in this class, from this day forward, and where are the "house rules" about things like this posted? I ask the question, but now I will go look for the answer. But you know, I'm not very good at finding things on websites. I am in the web developer trade, and therefore have no patience with actually reading website content.
FirstChildUserIdTAG: 450628
FirstChildUserNameTAG: ctr
FirstChildCreateTimeTAG: 2013-02-28T04:54:35Z
FirstChildVoteTAG: 0
SecondChildTAG: By the way, I love the Professor's voice. Very pleasant to listen to. Not like those MIT professors. Yikes!
SecondChildUserIdTAG: 450628
SecondChildUserNameTAG: ctr
SecondChildCreateTimeTAG: 2013-02-28T04:55:27Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
The instructor posted a comment. The time zone will be **GMT**. She extended the deadline.
SecondChildUserIdTAG: 1152215
SecondChildUserNameTAG: Mantou
SecondChildCreateTimeTAG: 2013-02-28T06:26:50Z
SecondChildVoteTAG: 0
FirstChildTAG: > where are the "house rules" about things like this posted
In the General Course Information.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T05:01:11Z
FirstChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
SecondChildUserIdTAG: 1152215
SecondChildUserNameTAG: Mantou
SecondChildCreateTimeTAG: 2013-02-28T06:27:23Z
SecondChildVoteTAG: 0
FirstChildTAG: February 27, 2013
Hello everyone,
Gotta read the course policies. Really. Course Policies and Requirements, on the landing page; the first page you get when you log on. Information about due dates and times has been posted since the first day: "Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT)."
On the "better late than never" principle, please read it now, and please note how GMT translates to your time.
FirstChildUserIdTAG: 450628
FirstChildUserNameTAG: ctr
FirstChildCreateTimeTAG: 2013-02-28T05:04:23Z
FirstChildVoteTAG: 0
SecondChildTAG: As this is Week 1 and people are yet to get into a rhythm with the course, the staff and I have extended the deadline for Exercise Sets 1, 2, and 3 till Thursday February 28, 23:30 GMT. All subsequent exercise set deadlines will remain as they are on the schedule.
One point to note: there's only one Greenwich Mean Time. There isn't a GMT in every country, in spite of what some of you have been telling me.
To the many students who did read the policies and followed them, thanks from all the staff.
Best,
Prof. A.
SecondChildUserIdTAG: 450628
SecondChildUserNameTAG: ctr
SecondChildCreateTimeTAG: 2013-02-28T05:05:57Z
SecondChildVoteTAG: 0
IndexTAG: 1807
TitleTAG: Grade for Certificate of completion
I would like to know way the grading standard to get a certificate of completion is so low? THIRTY-FIVE PERCENT!!!!
Can it at least be changed to 60%. I would prefer 70% because that would encourage me and maybe others to try a bit harder and give a greater sense of accomplishment.
Prof. A., I commend you on your lectures, you are doing a far better job of presenting the class than I had with my first statistics class in college.
Thank you for extending the deadline as I was assuming ET not GMT.
Anyone else in favor of a higher required grade for a certificate?
UserIdTAG: 887436
UserNameTAG: KAP-Leo
CreateTimeTAG: 2013-02-28T04:47:43Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Well, you and I would have lost 12.5% already, since we don't understand clocks. Encouraged?
FirstChildUserIdTAG: 466057
FirstChildUserNameTAG: mateorod
FirstChildCreateTimeTAG: 2013-02-28T04:58:02Z
FirstChildVoteTAG: 5
SecondChildTAG: That was great xD
SecondChildUserIdTAG: 859593
SecondChildUserNameTAG: AlvFdezFdez
SecondChildCreateTimeTAG: 2013-02-28T09:00:24Z
SecondChildVoteTAG: 0
FirstChildTAG: The Prof has already explained this. She is allowing for those who take time to settle in to the course. Those who, for example, have trouble reading the course policies.
Maybe she will raise the bar for the two subsequent courses.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T05:00:14Z
FirstChildVoteTAG: 0
FirstChildTAG: um no i think u might change ur tune when u get past the second midterm if u have read ahead not to mention the midterms n finals themselves.. 35percent passing is what is giving me hope in a math class and actually making me try harder cuz if it was 65percent to pass i think i would drop before the second midterm n so would like half of every1 else haha. u should aim 4 the highest scores on the exercises before the second midterm in case u fail the third n last midterm n final. just try to get the best possible score 4 urself n not just so u pass! so far my average is like 90 hehe. good luck though!
FirstChildUserIdTAG: 985560
FirstChildUserNameTAG: zoe3456
FirstChildCreateTimeTAG: 2013-02-28T05:01:42Z
FirstChildVoteTAG: 1
IndexTAG: 1808
TitleTAG: Problem 3
I personally think that any of the graphics we have there represents the data shown in the chart. Because in the chart we have six intervals, and the last two graphics, just have five in each one. And the first one is rejected immediately by the width of each bar in the horizontal axis.
UserIdTAG: 435900
UserNameTAG: samuelvp
CreateTimeTAG: 2013-02-28T04:44:56Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I didn't even catch that. I too was hung up by this problem because the bars on either side of 30/1 are reversed.
FirstChildUserIdTAG: 1082322
FirstChildUserNameTAG: CharlesHall
FirstChildCreateTimeTAG: 2013-02-28T07:11:47Z
FirstChildVoteTAG: 0
SecondChildTAG: I found it out when I tried to compare my manually computed histogram to the ones from the exercise… somehow the number of rectangles didn't match up (-:
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-03-01T00:41:19Z
SecondChildVoteTAG: 0
IndexTAG: 1809
TitleTAG: RE: Online textbook
Hi
I am a bit late to the course, but I am sure I saw some mention of an online textbook in one of the lectures. Where do I find this online textbook?
Steve
UserIdTAG: 792084
UserNameTAG: ssfranciscan
CreateTimeTAG: 2013-02-28T04:43:27Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/
FirstChildUserIdTAG: 1298180
FirstChildUserNameTAG: TRBA
FirstChildCreateTimeTAG: 2013-02-28T04:54:20Z
FirstChildVoteTAG: 0
SecondChildTAG: was that a joke steve haha
SecondChildUserIdTAG: 985560
SecondChildUserNameTAG: zoe3456
SecondChildCreateTimeTAG: 2013-02-28T05:05:43Z
SecondChildVoteTAG: 0
IndexTAG: 1810
TitleTAG: Income is not discrete?
Aren't you measuring the amount of pennies they make, so the measurement should be discrete?
UserIdTAG: 171233
UserNameTAG: choxandrew
CreateTimeTAG: 2013-02-28T04:35:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Not really. You don't measure income to the penny. That would be like measuring height to the nanometer. So you will not have a predictable even spacing between values.
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T05:34:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually it won't be like that.
Income is discrete, since there is a minimum value unit (cent in the US). Length is NOT discrete, since you could have any fraction of a nanometer (if you really need to pick one of the many units of length), it's just not measurable.
You can't say income is not measurable below cents, because income doesn't exist below cents. It's not a matter of "cents is the minimum measurement value", it's a matter of "cents is THE minimum value". Since there is a minimum value, all other values can be written as n*cents, with even spacing between the values, and it is therefore discrete.
SecondChildUserIdTAG: 83185
SecondChildUserNameTAG: oysteingrondahl
SecondChildCreateTimeTAG: 2013-02-28T07:21:05Z
SecondChildVoteTAG: 0
SecondChildTAG: You can have any fraction of income - just introduce new sub-unit and you have it. Conceptually, there is nothing wrong with it. As an another example, in 2011 Zimbabwe issued 100 trillion dollars bill which was worth 5 american dollars. If get 1000 dollars (Zimbabwe), what is my income in American dollars? Zero cause it is less than 1 cent? Would not be far from truth, but I still had some income.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T10:01:53Z
SecondChildVoteTAG: 0
SecondChildTAG: I've never heard of someone having an income that includes fractions of pennies. As to that last point, having wildly smaller units still doesn't make it continuous. I'm sure someone in Zimbabwe would scoff just as quickly at being paid in tiny fractions of Zimbabwe pennies (or the equivalent currency units). At some point there is a minimum spacing below which income cannot be divided. For sheer practicality, income must be in payable and spendable quantities.
SecondChildUserIdTAG: 1312416
SecondChildUserNameTAG: flaerebear
SecondChildCreateTimeTAG: 2013-02-28T22:33:04Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm sorry I did not make my point clear. What I was trying to point out is that going all the way to the penny was too high a level of accuracy when looking at income. I was not making a comment about the ability to break down pennies into fractions or not. At the scale of income (as opposed to comparing prices on loaves of bread, the measure in dollars can be looked at as continuous. Nobody's paycheck gets rounded up to the nearest hundred or thousand dollars. You make anything in between.
SecondChildUserIdTAG: 695174
SecondChildUserNameTAG: nerico
SecondChildCreateTimeTAG: 2013-02-28T23:57:05Z
SecondChildVoteTAG: 0
FirstChildTAG: Cents are a fraction of a dollar. 1/100th of a dollar per cent.
Number of humans in a household, 5 ... You can't have 5.33 humans, being a newborn or extremely short does not mean a third human ;-) . So that measure is discrete.
You can however have 1 and a half (1.5) dollars (1 dollar and 50 cents/half dollar).
NOW ... you can be devil's advocate and say that in certain countries this is not true because the currency does not support having a fraction of the currency (in the case of the USA cents are our fraction of our currency, the dollar.) Hence, it could be that income is discrete in that country. Do not know if there is such currency.
-Gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-02-28T07:58:47Z
FirstChildVoteTAG: 0
IndexTAG: 1811
TitleTAG: GMT Time - Donna Becerril
http://wwp.greenwichmeantime.com/to/cst/index.htm
This website will allow you to calculate the GMT time in your time zone. For those who are in the US, be careful. It is 10:30 here in CST. Houston, TX but it is already 2/28/13 in GMT time. All assignments have to be in by 5:30 in CST, 6:30 EST, 4:30 MT, and 3:30 Pacific time.
UserIdTAG: 1071300
UserNameTAG: dbstetson27
CreateTimeTAG: 2013-02-28T04:33:02Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Good! that's the website I found to convert the GMT hour to my GMT (-6)
Regards!
FirstChildUserIdTAG: 1327580
FirstChildUserNameTAG: Hingler
FirstChildCreateTimeTAG: 2013-02-28T05:09:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Very useful.. thanks!
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T05:50:07Z
FirstChildVoteTAG: 0
FirstChildTAG: It's fine! Because I get +9GMT in Japan that mean assignment will be allowed till at half past eight in the next morning of the due date. It takes long time to read this discussion board for me, poor English ability, but I am getting encouragemant from complainer or low scored sigh. I want to do my best. Gannbare!
FirstChildUserIdTAG: 200548
FirstChildUserNameTAG: kame
FirstChildCreateTimeTAG: 2013-02-28T08:48:22Z
FirstChildVoteTAG: 0
IndexTAG: 1812
TitleTAG: STAFF - WEEK 1 assignments due
Thanks for the increase in time deadline. If we can not submit everything by 23.30 can we post as much as we can and post the rest a little after. Sorry just getting up my computer cause of problems and still slow plus don't know how much i can get done with work by 23.30 GMT. Can it be pushed to midnight in the USA? Can someone please contact me personally and directly. My email address is aimstermill51@aol.com and i can provide phone number once emailed to discuss please
thanks
Amy
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-02-28T04:22:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Many thanks for all the staff of edx for considering a one day extension - Cris
FirstChildUserIdTAG: 1119580
FirstChildUserNameTAG: CrisLares
FirstChildCreateTimeTAG: 2013-02-28T04:28:33Z
FirstChildVoteTAG: 2
SecondChildTAG: Amy , here you can convert the GMT hout to your GMT hour.
http://wwp.greenwichmeantime.com/gmt-converter/
Regards!
SecondChildUserIdTAG: 1327580
SecondChildUserNameTAG: Hingler
SecondChildCreateTimeTAG: 2013-02-28T05:11:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Bummer,
As I lost two points due to inattentiveness and the rush to complete before the previous deadline
But good luck to others!
FirstChildUserIdTAG: 1299515
FirstChildUserNameTAG: jamilaelgizuli
FirstChildCreateTimeTAG: 2013-02-28T04:50:36Z
FirstChildVoteTAG: 0
IndexTAG: 1813
TitleTAG: I just found out about this class today from CSU Eastbay.
I was wondering can you extend the due date for the homework otherwise I will need to drop this class.
UserIdTAG: 1327481
UserNameTAG: DevikaSingh11
CreateTimeTAG: 2013-02-28T04:16:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For reasons unconnected with your starting date, you and all the other students have until Thurs Feb 28 23:30 GMT to turn in Exercise Sets 1, 2, and 3. Please read the Course Policies and Guidelines page, as well as the Course Schedule, for related information. Both of these are found on the Landing page, which is the fist page you see when you log in. Read the announcement on there too.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T04:18:51Z
FirstChildVoteTAG: 0
IndexTAG: 1814
TitleTAG: Exercise Set 2, problem 3b
When I look at the histograms, none of them matches that heights that I calculate for the data. What am I doing wrong? I don't want to describe the problem precisely for fear of giving away too much information.
UserIdTAG: 1082322
UserNameTAG: CharlesHall
CreateTimeTAG: 2013-02-28T03:59:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: If its the one I remember, be sure to check the label of the y axis - then pick the one that makes the most sense.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-28T04:15:15Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks, it really seems like the bars don't represent the data.
SecondChildUserIdTAG: 1082322
SecondChildUserNameTAG: CharlesHall
SecondChildCreateTimeTAG: 2013-02-28T04:16:18Z
SecondChildVoteTAG: 0
FirstChildTAG: Remember that it the relative size between the bars that matters most. 6 is two thirds of 9 and 2 is two thirds of 3. So one bar at 6 and a two bars at 2 and 1 at 2/3. (although the last bar looks more like 1/3 than 2/3) convey the same info as 9:3:3:1. I think she want us to realize that neither the vertical axis nor bar order matter as long as the proportions are correct.
At least I hope that's it.
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T04:55:46Z
FirstChildVoteTAG: 0
FirstChildTAG: @CharlesHall - Please post your question in the right place to get it answered in a timely manner. You have posted this query on Exercise 2 under Exercise 1. Just drawing your attention assuming you are new to the forum use. If not, please disregard the suggestion.
Regarding your question:
1. First graph is a BAR graph, not a histogram
2. The second graph plots 'percent' along Y axis, not per unit measurement with respect to X axis
3. The third graph is representation of density function (Y axis plotting PER UNIT MEASUREMENT with respect to X axis.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-28T05:15:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks! My mistake. I simply clicked "new post" on the discussion page, and I clearly missed something.
Agreed, first graph does not scale the properly on the x axis, second graph is indeed labeled "percent", and the third graph represents density on the Y axis.
My problem is with the actual bars, it seems like 7/3 should be smaller than 26/3 and yet the height of the bars is reversed in the histogram.
SecondChildUserIdTAG: 1082322
SecondChildUserNameTAG: CharlesHall
SecondChildCreateTimeTAG: 2013-02-28T06:59:36Z
SecondChildVoteTAG: 0
SecondChildTAG: Agree.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-28T08:49:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks @artimetha. I missed that, I though he was asking about the bars on this homework.
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T05:52:31Z
FirstChildVoteTAG: 0
IndexTAG: 1815
TitleTAG: Timing: It's still 2/27 and can't post
it's 22.55 EST and I can't post answers. What's going on.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T03:56:48Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: If you have hit the discussion panel you no longer can submit answers because the answers may be in the discussion panel
FirstChildUserIdTAG: 1326703
FirstChildUserNameTAG: Orthodoc71
FirstChildCreateTimeTAG: 2013-02-28T04:00:21Z
FirstChildVoteTAG: 0
FirstChildTAG: refresh your page. then read the forum posts.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T04:02:09Z
FirstChildVoteTAG: 0
IndexTAG: 1816
TitleTAG: No submission
I cannot submit either
UserIdTAG: 1219423
UserNameTAG: Carocu
CreateTimeTAG: 2013-02-28T03:48:52Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Please try reloading/refreshing your page.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T03:52:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Refresh your page.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:52:50Z
FirstChildVoteTAG: 0
IndexTAG: 1817
TitleTAG: iS THIS THE WAY COLLEGE STUDENTS TODAY LEARN TODAY?
THIS IS BUSY WORK....WHAT IS PURPOSE OF ALL THIS MULTIPLICATION, DIVISION, BLAH BLAH...I AM 50 YEARS OLD...ANXIOUS TO ACTUALLY LEARN STATS...NOT SPEND HOURS I DONT HAVE DOING ARITHMETIC
UserIdTAG: 938670
UserNameTAG: JeffVirginia
CreateTimeTAG: 2013-02-28T03:47:23Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 8
FirstChildTAG: This is a class on basics, in the second week. What do you expect?
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-28T03:49:10Z
FirstChildVoteTAG: 5
FirstChildTAG: Is there any need to shout?
You have me confused. Stats is about numbers that you multiply/divide/substract/etc to come up with a statistic.
Here you are learning where these numbers come from. Anyone can call a number a "mean", here you learn how it is calculated. That's stats.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:52:27Z
FirstChildVoteTAG: 4
FirstChildTAG: Yes, this class is a "college" class, but as the course said, it's Stat2.1x, and it's only a portion of the actual things college students learn from what I can discern. Keep in mind that this course is geared towards a general audience.
Actually, I personally think that this is much easier than the math course I'm taking right now, and to be honest, I'm not in high school yet. Math isn't the most interesting subject to look at, but I think Stat is quite interesting sometimes :)
Besides, the arithmetic is a huge part of the course.
FirstChildUserIdTAG: 1253403
FirstChildUserNameTAG: dniu21
FirstChildCreateTimeTAG: 2013-02-28T04:00:41Z
FirstChildVoteTAG: 1
FirstChildTAG: Why do you act like they owe you something? You don't have to do the assignments if you don't want to. The entitlement here is unbelievable.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-28T04:03:13Z
FirstChildVoteTAG: 7
FirstChildTAG: This class is absolute basics. It is supposed to introduce Stats to someone who has never seen stats.
This is first of three parts of one semester class in intro to stats at UCBerkeley. I don't know what your expectations and knowledge level are, but even for someone who has taken AP Stats in high school, this class is below level. So if you have taken such courses or already know it, then please don't enroll here. This is very basics class and you may not benefit in such case.
Now if you haven't really taken any stats before but had different notion about stats, I can't really help you. This +/-/X are foundation of any maths course and certainly would be taught here. Later in weeks we can expect to go to so called real stats.
FirstChildUserIdTAG: 982840
FirstChildUserNameTAG: AhadAlex
FirstChildCreateTimeTAG: 2013-02-28T04:22:33Z
FirstChildVoteTAG: 0
FirstChildTAG: Actually this IS the way to learn. You are building the foundation to understand more complicated concepts later on. Nothing better to truly understand numbers and graphs that to work them out for yourself. It really makes the concepts sink in. Just being able to "follow" the lecture is not enough. More often than not concepts that seem obvious when you are following the lecture "get" quite complicated when you are stuck working out the problems on your own.Better to start with a solid grounding.
The problems seem simple because the professor purposely uses numbers that will require simple math to work out (for example 30:10:10 in the first video instead of 32095:269059:94932). She wants to stress the concepts, not your ability to handle complicated numbers. But simple math in these problems does not mean simple concepts.
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T05:42:51Z
FirstChildVoteTAG: 0
FirstChildTAG: As far as I understand, statistics involves a LOT of math. If you are not prepared to do arithmetic, then perhaps statistics itself is not for you! Without the math, how would they test that you understand the concepts?
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T09:50:12Z
FirstChildVoteTAG: 0
FirstChildTAG: I think this poster is really an 18 year old hoping to provoke responses, making a bit of fun of students who really are older than 18.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-28T20:06:02Z
FirstChildVoteTAG: 0
IndexTAG: 1818
TitleTAG: Regarding Video Audio
Subsampled audio sounds fantastic! Many thanks!
UserIdTAG: 40598
UserNameTAG: jstarkey
CreateTimeTAG: 2013-02-28T03:40:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1819
TitleTAG: Thank You Prof. A
we still have a little time to finish the excersises guys.. cmon .. cmon...
UserIdTAG: 1193006
UserNameTAG: makmursp
CreateTimeTAG: 2013-02-28T03:40:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1820
TitleTAG: Exercise 4 Problem 8
I think I calculated this incorrectly by typing 34 instead of 32. (DOH) Can anyone verify if these FAKE numbers would be correct?
22 houses
One was changed from 970,000 to 930,000.
970,000 - 930,000 = 40,000
Total Change in Set -40,000
-40,000 / 22 = -1818.18
Average change would be -1818.18. Correct?
Also on a side note - the \$ is apparently a formatting operator on the forums?
$well how-(about) that^2 $
UserIdTAG: 40598
UserNameTAG: jstarkey
CreateTimeTAG: 2013-02-28T03:39:53Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: > Also on a side note - the \$ is apparently a formatting operator on the forums?
It is. You can write fancy maths with it.
$\frac{-40000}{22}= -1818.18$
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/mathjax-tutorial-write-formula-forum-wiki/
> Average change would be -1818.18. Correct?
Sounds right
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:44:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks! Just wanted to make sure I didn't miss a concept. I mean... its just averages. This'd really SUCK to get lost now. :P
SecondChildUserIdTAG: 40598
SecondChildUserNameTAG: jstarkey
SecondChildCreateTimeTAG: 2013-02-28T03:46:25Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm mad at myself for missing problem 6...
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-28T03:48:29Z
FirstChildVoteTAG: 0
FirstChildTAG: Ummmmm .... I have to object here. You can call examples "fake" numbers, but if your "fake" example resembles the "real" homework exercise, isn't that just a "fake" way of breaking the honor code? If I am wrong, please someone explain.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-28T03:48:50Z
FirstChildVoteTAG: 1
SecondChildTAG: When its a math oriented class - how else do you do it? If this were a class on the quadratic equation, how else would I purpose a "test" problem to make sure my math and logic were sound?
SecondChildUserIdTAG: 40598
SecondChildUserNameTAG: jstarkey
SecondChildCreateTimeTAG: 2013-02-28T04:16:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Besides - the staff can verify I already flubbed the question. I assumed my mistake was not typing the decimals and was very obviously wrong.
SecondChildUserIdTAG: 40598
SecondChildUserNameTAG: jstarkey
SecondChildCreateTimeTAG: 2013-02-28T04:17:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't think this violates the honour code. To me it is a different example of a similar problem. But I would be interested in what the staff think? Maybe it shouldn't have had the label of exactly which problem it referred to so that it would have been more vague? Don't know.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T09:53:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Nope, I think it is too close to the actual exercise. Same object, same process, same flow, just "fake" numbers. Perilously close enough to fall right off the cliff. But that is just IMO, and I am not trying to be a hard a** about it, although perhaps I have come, er, perilously close to doing so.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-28T19:03:02Z
SecondChildVoteTAG: 0
SecondChildTAG: MyOwnCamera. Your opinion is totally fair but I'm not sure whether you addressed the second part of my comment and I am interested in your view. What if you didn't associate the question with a particular problem and just asked a "fake question"? Would that violate the honour code? I would really appreciate staff input on the matter, as I was just about to help someone with a question and then stopped when I remembered this thread!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T20:28:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Had solve the question this way but got it wrong. Pls did anyone get it right?
FirstChildUserIdTAG: 1187096
FirstChildUserNameTAG: Chinonso411
FirstChildCreateTimeTAG: 2013-02-28T05:40:20Z
FirstChildVoteTAG: 0
FirstChildTAG: @ jstarkey
Yes, that's it :)
FirstChildUserIdTAG: 703576
FirstChildUserNameTAG: cmonteiro
FirstChildCreateTimeTAG: 2013-02-28T15:06:42Z
FirstChildVoteTAG: 0
IndexTAG: 1821
TitleTAG: The Plants
Full scale for data graphic is an obligation, otherwise data displayed is not complete.
UserIdTAG: 76861
UserNameTAG: peruvianmiguel
CreateTimeTAG: 2013-02-28T03:38:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1822
TitleTAG: We still Have Next Week Guys...
i missed the excercise set 2 and 3..:( . learning from this week, most of us missed the assignment for the confusion of the time. next week we have to finish it in time...
UserIdTAG: 1193006
UserNameTAG: makmursp
CreateTimeTAG: 2013-02-28T03:35:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Read my post, please; a couple of posts below yours. I've given you another day.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T03:36:19Z
FirstChildVoteTAG: 1
IndexTAG: 1823
TitleTAG: Thank you!
Many thanks for allowing me to finish this exercise as I also assumed that the time was based on EST time.
Thank you!!!!
UserIdTAG: 1049439
UserNameTAG: C_Olson
CreateTimeTAG: 2013-02-28T03:32:59Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I also assumed the class was based on EST per other EdX courses....many thanks again to the staff for the extension.
FirstChildUserIdTAG: 996807
FirstChildUserNameTAG: Joshua29
FirstChildCreateTimeTAG: 2013-02-28T04:35:13Z
FirstChildVoteTAG: 0
IndexTAG: 1824
TitleTAG: From Prof. A, on submission deadline: just this once ...
Gotta read the course policies. Really. "Course Policies and Requirements," on the landing page; the first page you get when you log on. Information about due dates and times has been posted since the first day: "Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT)."
On the "better late than never" principle, please read it now, and please note how GMT translates to your time.
As this is Week 1 and people are yet to get into a rhythm with the course, the staff and I have extended the deadline for Exercise Sets 1, 2, and 3 till Thursday February 28, 23:30 GMT. All subsequent exercise set deadlines will remain as they are on the schedule.
One point to note: there's only one Greenwich Mean Time. There isn't a GMT in every country, in spite of what some of you have been telling me.
I will add this as an announcement to the landing page. To the many students who did read the policies and followed them, thanks from all the staff.
Best,
Prof. A.
UserIdTAG: 1019686
UserNameTAG: AniAdhikari
CreateTimeTAG: 2013-02-28T03:29:09Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 9
FirstChildTAG: THATS FIND EXCEPT IT WONT LET US SUBMIT...AND THE GMT ASSUMPTION WAS ABSURD
FirstChildUserIdTAG: 938670
FirstChildUserNameTAG: JeffVirginia
FirstChildCreateTimeTAG: 2013-02-28T03:31:30Z
FirstChildVoteTAG: 0
SecondChildTAG: Stop shouting, and refresh the page. Nothing was absurd. There has to be guidelines. It's up to you to read them and to follow them.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T03:34:18Z
SecondChildVoteTAG: 0
SecondChildTAG: You are being persistently rude.GMT is a universal standard of reference around the world. There has to be one time of reference when doing a class around the world.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-28T04:56:45Z
SecondChildVoteTAG: 0
FirstChildTAG: Sorry you guys have to go through this, what a mess. I hope it doesn't discourage you from future classes because I am really loving this!
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-28T03:31:38Z
FirstChildVoteTAG: 1
FirstChildTAG: Could the subforums for week 2 be activated? The forums are a dog's breakfast at the moment.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:33:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, we're on it. Thanks, ChristineStv. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T03:34:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks. But now to stop the hundreds of "thanks" posts that are about to arrive.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T03:35:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Ha, this is hilarious, one GMT per country... Prof, you are being way too nice :) But it adds to the experience - I must have matured a lot since college because I made it before the proper deadline, unlike back in those days, when many an assignment was submitted by me via fax just on the deadline
Btw, thanks a lot for doing this, not the extension, but the whole course. I hope it's just as much fun and just as much of an experience for you as it is for us.
Marton
FirstChildUserIdTAG: 953527
FirstChildUserNameTAG: Marton
FirstChildCreateTimeTAG: 2013-02-28T03:40:06Z
FirstChildVoteTAG: 3
SecondChildTAG: I agree. If you are worried about getting your assignments don, turn them in one day before the deadline. That is what I did.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-28T04:01:37Z
SecondChildVoteTAG: 0
FirstChildTAG: Professor - thank you for acknowledging and addressing the problem - and finding a workable solution.
Can you also ask the TAs to stop acting like 14 year-olds? I understand that they're frustrated, as are many of us, but they represent your course and they are constantly belittling the people posting to the discussion forum.
They are not sitting at the cool kids' lunch table, dishing about other kids outside their clique behind their backs. We can read what they are posting, even if it is not directed at us.
They are here to be helpful, not disparaging.
I can practically hear their eyes rolling while reading their posts. If they can't grow up, they should at least post like they have.
FirstChildUserIdTAG: 972465
FirstChildUserNameTAG: ToddCioffi
FirstChildCreateTimeTAG: 2013-02-28T03:44:15Z
FirstChildVoteTAG: 1
SecondChildTAG: They're not TAs. They are your fellow students.
Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-28T03:48:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I stand corrected.
SecondChildUserIdTAG: 972465
SecondChildUserNameTAG: ToddCioffi
SecondChildCreateTimeTAG: 2013-02-28T03:49:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you for your response, BTW - and for staying on top of the meltdown.
SecondChildUserIdTAG: 972465
SecondChildUserNameTAG: ToddCioffi
SecondChildCreateTimeTAG: 2013-02-28T03:50:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm not a TA. That made me chuckle. You asked that the TAs be named to the students. Did you know that each staff member has already been introduced to you? Check out the link below. Imagine all the information you can find if you explore the course website. I encourage you to try it.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/about
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T04:03:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Most people are asking people to check discussions and read the notices before posting. Is that really too much to ask?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-28T04:58:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Apparently.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T09:26:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Todd, I hope the people to whom you were referring as TAs take your point. I find the persistent, thinly-veiled, snide comments off-putting as well. It is frustrating to have the discussion forum clogged up with many repetitive posts, but it takes time for people to learn new things. Many people may not have participated in forums before. I know it took me several days to figure out how to search for staff postings by clicking on her blue name. Perhaps just ignoring the repetitive posts is the best approach?
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-28T12:52:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you so much! I just joined the class yesterday, and am happy for the opportunity to catch up!
FirstChildUserIdTAG: 955872
FirstChildUserNameTAG: celp77
FirstChildCreateTimeTAG: 2013-02-28T03:57:40Z
FirstChildVoteTAG: 2
SecondChildTAG: Welcome and good luck!
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-28T04:07:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks! I love it so far!
SecondChildUserIdTAG: 955872
SecondChildUserNameTAG: celp77
SecondChildCreateTimeTAG: 2013-02-28T04:13:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you Prof A!!!! From the bottom of my heart and the hearts of those of us who have very little time to spare but want to take advantage of your wonderful course.
I am also taking another online course for regular credit for a bachelor's degree. It is the first time I'm taking an online course but I wanted to share some perspective. In my day job, I coordinate a second year medical school course so I am not unsympathetic to the instructor's POV.
I was hesitant at first to take an online course because one of my co-workers had a very bad experience with a very disorganized instructor. Thankfully, my instructor has organized his course quite well. But one thing I have noticed my instructor does is repeat certain vey important requirements information points throughout his site. I have a feeling that it is something he has learned from teaching the course many times. I know it's not an even comparison, he has a minuscule number of students compared to you. And your course is certainly also *very well organized* (congratulations!). But I think he has learned not to fight human nature and instead anticipate the likely sources of miscommunications and find a way to minimize them. Some of us will always wait till the last minute and/or skip some reading either because we procrastinate or because we are beyond busy. I don't think it's productive to judge thousand of strangers as just somehow defective (not that you have, please don't think I'm implying that, but sadly other fellow students have felt the need to do so) Next time you teach the class you may want to make sure the deadline is posted at the top of the page in bold and red. Or maybe send an email a day before the first homework. Or find some other way of making the information very prominent on the site. You will never reach 100% of the late folks. But those of us who honestly want to make a go of this effort with love you for the extra help.
On a side note, my aunt is a therapist and she tells me that she is encountering a lot of patients undergoing a huge amount of stress because of online courses. She sounded quite concerned. I was quite surprised since my personal impression was that online would be so much easier. It will be interesting to see what research will find about the effect of online learning as the practice increases and is further studied.
Sorry for the long note. I hope you find it useful.
Thanks again! I'm looking forward to the rest of the course and hope to see parts 2 and 3 offered as well.
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T05:23:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Prof.A, Sir, i've miss some lectures due to timing and i'll really need you to help me out with the course handout to my e-mail. thank u sir.
FirstChildUserIdTAG: 1012378
FirstChildUserNameTAG: bongarcon
FirstChildCreateTimeTAG: 2013-03-01T11:34:00Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you Prof. A. I need to apologies for long delay in doing the practice sets. I just now start completed the exercise 1 and 2. From this point I will complete the course within the due dates given and I also would like to ask where I have check my performance and percentage marking etc.
FirstChildUserIdTAG: 1162240
FirstChildUserNameTAG: Sudhadhayalan
FirstChildCreateTimeTAG: 2013-03-06T11:08:54Z
FirstChildVoteTAG: 0
IndexTAG: 1825
TitleTAG: Now you can send your answers!!!
TIME LIMIT CHANGE!!!
UserIdTAG: 1041097
UserNameTAG: JUANADORIS2013
CreateTimeTAG: 2013-02-28T03:28:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1826
TitleTAG: i changed the hour
hi, if refresh is not working. I changed the time in my clock and was able to post the answers. Instructions say that GMT is the schedule to follow, so... since it's 7.19pm, you're still on time, but may not be able because of the clock on your computer.
UserIdTAG: 921807
UserNameTAG: hdzmiriam
CreateTimeTAG: 2013-02-28T03:20:30Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: hilarious
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T10:08:45Z
FirstChildVoteTAG: 1
IndexTAG: 1827
TitleTAG: SOLUTION!
Got it.
It says Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
I changed the date in my computer to wednesday 27 and i have the FINAL CHECK AND SAVE to post my answers. Check it out, it's 7.15 in GMT.
good luck!
UserIdTAG: 921807
UserNameTAG: hdzmiriam
CreateTimeTAG: 2013-02-28T03:16:17Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Yes. You can set multiple times on your computer clock. I have local, Boston, and GMT clocks.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:19:40Z
FirstChildVoteTAG: 0
FirstChildTAG: This is a great idea! Thank you!
FirstChildUserIdTAG: 1268646
FirstChildUserNameTAG: sburris
FirstChildCreateTimeTAG: 2013-02-28T03:29:03Z
FirstChildVoteTAG: 0
FirstChildTAG: But posting has nothing to do with you changing your clock.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:30:36Z
FirstChildVoteTAG: 0
IndexTAG: 1828
TitleTAG: on submitting exercise answers
Hi there,
How would I submit the answers to the exercises, anyone?
UserIdTAG: 1304293
UserNameTAG: VPeter
CreateTimeTAG: 2013-02-28T03:15:14Z
VoteTAG: 1
CoursewareTAG: Section 1: Introduction / Lec 1.2. Variables: terminology
NumberOfReplyTAG: 1
FirstChildTAG: You move on to Week 2.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:22:13Z
FirstChildVoteTAG: 0
SecondChildTAG: oh wow. that simple? greatly appreciate it, Christine! :)
SecondChildUserIdTAG: 1304293
SecondChildUserNameTAG: VPeter
SecondChildCreateTimeTAG: 2013-02-28T12:16:32Z
SecondChildVoteTAG: 0
IndexTAG: 1829
TitleTAG: I cant Submit The answers
Did anyone know how to submit the response?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T03:14:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I don't know
FirstChildUserIdTAG: 1041097
FirstChildUserNameTAG: JUANADORIS2013
FirstChildCreateTimeTAG: 2013-02-28T03:15:42Z
FirstChildVoteTAG: 0
SecondChildTAG: Please..someone can help ?
SecondChildUserIdTAG: 1041097
SecondChildUserNameTAG: JUANADORIS2013
SecondChildCreateTimeTAG: 2013-02-28T03:19:59Z
SecondChildVoteTAG: 0
SecondChildTAG: The deadline has passed and you can no longer submit. Please up vote my post so that we can get an extension due to the confusion of time zones.
SecondChildUserIdTAG: 261921
SecondChildUserNameTAG: IsaacGolberg
SecondChildCreateTimeTAG: 2013-02-28T03:21:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, I see another student that he said that the time were based on GMT time, so its not based on the time were we live?.
SecondChildUserIdTAG: 1181954
SecondChildUserNameTAG: mywhitebear
SecondChildCreateTimeTAG: 2013-02-28T03:22:11Z
SecondChildVoteTAG: 0
IndexTAG: 1830
TitleTAG: I cannot use the online text to perform the exercise
Prof A:
When I am trying to use the online text to do Historgrams, it doesn't even show up. Is this becasue of my browser? Is anyone else having this problem?
UserIdTAG: 1200616
UserNameTAG: lawtec
CreateTimeTAG: 2013-02-28T03:14:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1831
TitleTAG: Submissions
If you check the Course Policies and Requirements, and look at the Grading section, it states that all times are in Greenwich Mean Time (GMT).
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T03:12:42Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Bummer we all missed this. The rest of the course is still to come!
FirstChildUserIdTAG: 1268646
FirstChildUserNameTAG: sburris
FirstChildCreateTimeTAG: 2013-02-28T03:17:35Z
FirstChildVoteTAG: 0
IndexTAG: 1832
TitleTAG: Can't submit and willing to know the answers
I would like to know whether my answer is correct or not, although the deadline was passed.
How can I know the answers??
UserIdTAG: 326240
UserNameTAG: Yoshi0829
CreateTimeTAG: 2013-02-28T03:11:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Read the policy
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T03:20:01Z
FirstChildVoteTAG: 0
IndexTAG: 1833
TitleTAG: Homework [staff]
Did I miss the deadline for the Homework. I cannot submit it. \
Donna Becerril - Houston, TX
UserIdTAG: 1071300
UserNameTAG: dbstetson27
CreateTimeTAG: 2013-02-28T03:11:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: yes, the deadline has passed but I have posted a question/request asking them to extend the deadline due to confusion, please up vote it so that they can see it!
FirstChildUserIdTAG: 261921
FirstChildUserNameTAG: IsaacGolberg
FirstChildCreateTimeTAG: 2013-02-28T03:16:09Z
FirstChildVoteTAG: 3
FirstChildTAG: No you still have few hours as again the deadline is extended .now it's 28 Feb 11.30 pm GMT .check the course Info page .
FirstChildUserIdTAG: 92822
FirstChildUserNameTAG: ShashiBhagendra
FirstChildCreateTimeTAG: 2013-02-28T15:02:52Z
FirstChildVoteTAG: 0
IndexTAG: 1834
TitleTAG: no scores or answers
use refresh and it will work
UserIdTAG: 1095998
UserNameTAG: tonyi
CreateTimeTAG: 2013-02-28T03:09:40Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1835
TitleTAG: Can't submit
Can't submit
UserIdTAG: 912104
UserNameTAG: GarryiBG
CreateTimeTAG: 2013-02-28T03:09:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: refresh your page :) it'll come right back up.
FirstChildUserIdTAG: 495350
FirstChildUserNameTAG: christychristop
FirstChildCreateTimeTAG: 2013-02-28T03:17:52Z
FirstChildVoteTAG: 0
IndexTAG: 1836
TitleTAG: Problem with Deadline
Hi, I reserve this day to make the exercise set 3. I am from México and here is 27/02/2013 and its 9:07 PM, is CENTRAL TIME but i can not check my answers of excerices set 3. I think I am cool with the deadline that is (27/02/2013, 23:30)
Help Please
UserIdTAG: 1074208
UserNameTAG: RubencitoP
CreateTimeTAG: 2013-02-28T03:09:09Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1837
TitleTAG: Cannot post the answer to last two questions.
Why can't I submit my last two questions?
Even based on east coast, I should have time.
UserIdTAG: 978965
UserNameTAG: Shahoushyar
CreateTimeTAG: 2013-02-28T03:07:46Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1838
TitleTAG: It also happened to me - timeframe -
Now I understand why I can't save my answers. Timeframe. Now it's 9:00 pm in México City :-(
UserIdTAG: 1272120
UserNameTAG: Val_75
CreateTimeTAG: 2013-02-28T03:03:48Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1839
TitleTAG: Completed the assignment, but no submit option available
I see from the many post that I am not alone. It is current 22:02 here on the East Coast, and many more hours before we hit 23:30 in Berkeley.
UserIdTAG: 969813
UserNameTAG: amvedaa
CreateTimeTAG: 2013-02-28T03:03:43Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Please read the discussion forum. There are hundreds of posts about this. In general ou'll find your answers more quickly if you read the forum *before* posting a question.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T03:07:10Z
FirstChildVoteTAG: 0
IndexTAG: 1840
TitleTAG: can't post answers to question 4
Is anyone having same prob from Europe NL?
UserIdTAG: 1226732
UserNameTAG: Mastonefi2013
CreateTimeTAG: 2013-02-28T03:01:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: No, no one else has experienced this problem. sigh.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T03:07:29Z
FirstChildVoteTAG: 0
IndexTAG: 1841
TitleTAG: Extension on Week 1
Due to the confusion of time zones (Berkeley is located in California which is Pacific Standard Time not GWT) I ask all of the students enrolled in this course to vote up this post so the faculty can see our joint expression of misunderstanding (to those of you who still have not realized, you are not able to post because the deadline has already passed). Please everyone vote because I understand that many of us misunderstood and hopefully the staff will understand the issue and extend the due date.
To the faculty, personally I suggest connecting the deadline to change based on a person's IP address according to his/her geo-location to avoid future confusion in this course and the entire edX program.
Thank you.
UserIdTAG: 261921
UserNameTAG: IsaacGolberg
CreateTimeTAG: 2013-02-28T03:01:32Z
VoteTAG: 14
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Yes please extend.I totally agree.
FirstChildUserIdTAG: 1260474
FirstChildUserNameTAG: Shikha1980
FirstChildCreateTimeTAG: 2013-02-28T03:03:06Z
FirstChildVoteTAG: 3
SecondChildTAG: Please like my post so that more people can see it.
SecondChildUserIdTAG: 261921
SecondChildUserNameTAG: IsaacGolberg
SecondChildCreateTimeTAG: 2013-02-28T03:04:52Z
SecondChildVoteTAG: 0
FirstChildTAG: I totally agree with you or what they should do is set a 11:30 pm or 11:00 pm deadline across all time zones. Like you I do not find this course to be flexible. It is as if it is expected that this is the only course you are doing or you are a full time student. A lot of material and reading was in the first week and then you have the quizzes which are lengthy and many times require thought.
I am about to pursue a DBA and I shudder to think what regular people with little or no background at all in statistics and a full time are going through. I am glad to be learning a lot though. So I guess I will just continue learning but probably won't take any of the tests. I also find it questionable to have due dates for quizzes in the week day? What about working folks? Wouldn't weekends be better? I am up in the dead of night catching up with this course and at the end of it all I cannot submit my answers. I do not think this is fair to me regardless of any stated timezone deadlines because I am not in an area with that time zone. I also liked your post
FirstChildUserIdTAG: 1221482
FirstChildUserNameTAG: Kimmy2013
FirstChildCreateTimeTAG: 2013-02-28T03:11:48Z
FirstChildVoteTAG: 2
SecondChildTAG: I agree, I am actually only a student in high school who is in algebra 2 honors and I'm only taking statistics in my school next year.
SecondChildUserIdTAG: 261921
SecondChildUserNameTAG: IsaacGolberg
SecondChildCreateTimeTAG: 2013-02-28T03:15:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I too am a working folk. I agree the due date and time should be set to a time more manageable for a busy parent or full-time, salary employee.
I recognize that students are very busy, but the luxury I don't have now that I am not a full-time student is a 30 minute break in the middle of each day to do work for my online classes.
In any case, if the course admin do not change this, I will just plan to submit by the end of each Tuesday to be safe. As advice to the workers/parents/busybodies/busy students- act as though the due time is over the weekend and plan accordingly the same as you would for another class with deadlines set for the weekends. We will learn more if we spend the time to sit down and apply our thoughts to the processes that are required for this material.
SecondChildUserIdTAG: 1268646
SecondChildUserNameTAG: sburris
SecondChildCreateTimeTAG: 2013-02-28T03:27:23Z
SecondChildVoteTAG: 0
SecondChildTAG: > A lot of material and reading was in the first week and then you have the quizzes which are lengthy and **many times require thought**.
I am really happy this course requires active participation from us. If I am trying to learn statistics, I expect to excercise my thinking abilities. There are many other online courses that fail miserably simply because they don't make you think, so you don't learn. We have all the information about deadlines, number of hours of work per week and so on. So... I guess it is just reasonable to expect that all will read the information and follow the rules.
SecondChildUserIdTAG: 743321
SecondChildUserNameTAG: Pa_CR
SecondChildCreateTimeTAG: 2013-02-28T03:28:56Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree. Setting deadlines across time zones using our IP's would make things easier for everyone.
FirstChildUserIdTAG: 743321
FirstChildUserNameTAG: Pa_CR
FirstChildCreateTimeTAG: 2013-02-28T03:18:49Z
FirstChildVoteTAG: 1
FirstChildTAG: Yeah, I'm usually polite, but this is one of those times I'm not going to be as polite.
This is total crap.
The mildly snarky responses from those that are trying to be helpful are only adding to the bad taste. Especially if folks like ChristineStv and/or mercutchin are TAs. This is not a class of 19-year-old college students where metaphorical eye rolls and patronizing attitude from a 23-year old grad student is passable. The TAs should be professional in attitude or they shouldn't be in those roles.
(I don't recall if the TAs have been named to the students, but it would be helpful if they were. That way we can tell if we're getting an official response, or if someone is misrepresenting the course.)
Answers like "you get to drop one..." or "it's too late..." "Move on..." are all the wrong answer. They may be true, but are the wrong answer.
The right answer is to admit that the staff majorly screwed up. Obviously, the note about GMT is in way too obscure a location, otherwise hundreds of people smart enough to be taking a college-level statistics course wouldn't have had a problem finding it.
Blaming all of these people for not finding the needle in the haystack is "deflecting", as psychologists would call it. What's more likely? Hundreds of independent people that have little else in common but this course all managed to make the same mistake, or the single decision on how to tell everyone about the time zone was flawed?
The courseware, the Wiki page, the FAQ, the Course Schedule, the course book, none of them say anything about GMT. You know, the places where people spend any of their time.
The first (and therefore last) couple of times I happened by the Course Info page, it came up blank, so I stopped going there.
Now, it turns out, that's the only place that links to the Course Policies page (that notes the GMT deadline) - which is, I now see, different than the Policies section of the Wiki?
What's the point of having a Policies section of the Wiki if it doesn't actually contain your Policies?
So, instead, buried three levels down off an obscure page (Course Info, Course Polices, bottom of the page) that no one really needs to go to, or spend any time on, there is a tiny note about GMT? If that was so important (kinda is, don't you think?), shouldn't that be linkable from places like, oh, where people are submitting on deadline (the Courseware page) or at least elsewhere on the Wiki?
Why would you suppose that we would even *think* to look for that as opposed to:
A) the fact that the whole world had to wait until Pacific time for the course to launch (remember all day long on Launch Day how everyone was saying "it's only x:xx am in California"?).
B) There is a Policies section in the Wiki, which is much more obvious to find, that says nothing about GMT.
C) There is no time zone noted on any deadlines on the Courseware page (how hard would it be to add GMT or PST or whatever Zone you wanted to the deadline time?)
D) Other BerkeleyX (even just other EdX in general) courses have used Pacific (or local) time because that's where they are, and all the students can figure that out.
This is a total fail from the admin.
I'm kind of torn because I really like the material, but between all the logistic issues, I'm losing the passion for going through the course.
Clearly, the instructors are not new. These are not technology issues. You have run classes before. You are bright people.
How do you not know that you have to be crystal clear with instructions about when things are due and the format of expected answers? People shouldn't have to hunt for those.
It also makes the rest of the discussion forum almost useless because a sizable chunk of the 47,000 students flood the forum with the same thing so that you can't find the things that are unique and helpful. There's no way to filter out the noise of issues that have been covered, so the only way to make it workable is to not create silly mistakes that cause the flood to begin with.
How about proofing the answers before posting them, for example? That would have saved how many dozens of posts if someone had just double checked that -20 - 10 was 30, right?
I'm trying to do my part by not adding yet another thread to the flood, but if I don't get a response, I'm going to have to post this in its own thread (and keep posting this) until I do. This is already the second thread where I have posted it, with the observations about those that appear to be TAs added.
On behalf of all of the students, we deserve a response.
FirstChildUserIdTAG: 972465
FirstChildUserNameTAG: ToddCioffi
FirstChildCreateTimeTAG: 2013-02-28T03:35:16Z
FirstChildVoteTAG: 1
SecondChildTAG: ...and now we have one.
Thank you.
SecondChildUserIdTAG: 972465
SecondChildUserNameTAG: ToddCioffi
SecondChildCreateTimeTAG: 2013-02-28T03:48:32Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm not a TA. That made me chuckle. You asked that the TAs be named to the students. Did you know that each staff member has already been introduced to you? Check out the link below. Imagine all the information you can find if you explore the course website. I encourage you to try it.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/about
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T04:01:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Todd, what I find really strange that people who made mistakes on their own part (let it be ignoring Official course policies, or problems with understanding concepts such as income) come to the forums to seek reaffirmation from others who made similar mistakes. Except accepting their mistakes, they rather to prefer endlessly deny them. You spend your time to post an answer. Yet, somehow, they still choose to ignore it and continue their previous behavior. What does it mean? That people don't want to hear answers which they don't like.
And regarding "otherwise hundreds of people smart enough to be taking a college-level statistics course wouldn't have had a problem finding it", how smart you have to be to click Enroll button on the front page of edx?
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T10:24:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Everyone please get as many people to up vote because 13 isn't enough for the admins to notice it!!
FirstChildUserIdTAG: 261921
FirstChildUserNameTAG: IsaacGolberg
FirstChildCreateTimeTAG: 2013-02-28T04:09:50Z
FirstChildVoteTAG: 0
IndexTAG: 1842
TitleTAG: Maria Eugenia
I can not submit my answers, is there any problem?
UserIdTAG: 1208968
UserNameTAG: MaEugenia
CreateTimeTAG: 2013-02-28T03:01:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1843
TitleTAG: Berkeley humor
I did the work, but assumed a timezone. Laugh is on me.
UserIdTAG: 1115045
UserNameTAG: MisterBenz69
CreateTimeTAG: 2013-02-28T03:00:38Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: We have next week :)
FirstChildUserIdTAG: 1268646
FirstChildUserNameTAG: sburris
FirstChildCreateTimeTAG: 2013-02-28T03:28:14Z
FirstChildVoteTAG: 0
IndexTAG: 1844
TitleTAG: I guess I'm conditioned to automatically ignore anything that says "policys" :).
I'll submit my test earlier next time.
UserIdTAG: 945143
UserNameTAG: joddde
CreateTimeTAG: 2013-02-28T02:59:07Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: ;) i miss the assignment. :(
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-02-28T03:30:41Z
FirstChildVoteTAG: 0
IndexTAG: 1845
TitleTAG: I cannot submit my answers..
I cannot...
UserIdTAG: 1237648
UserNameTAG: shurave
CreateTimeTAG: 2013-02-28T02:58:45Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: That's correct.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T03:01:36Z
FirstChildVoteTAG: 0
IndexTAG: 1846
TitleTAG: unable to submit
I'm unable to submit my answers... whats going on?
UserIdTAG: 742822
UserNameTAG: delapazr
CreateTimeTAG: 2013-02-28T02:58:07Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Please read the posts already on the forum before posting.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T03:00:15Z
FirstChildVoteTAG: 0
IndexTAG: 1847
TitleTAG: Deadlines for exercises should be very clear.
This exercise deadline was not clear at all. I am doctoral student in "educational Media and Technology" in Boston and trying to follow a " MOOC" to see how it works while I am refreshing my "Statistics." There are so many design , content,and assessment concerns with this particular MOOC. "Open" and online means that "flexibility" should be the main purpose. Hard deadlines can only work if all the students are in the same time zone. If you prefer to have a hard deadline, then add a "time counter" for each exercise and deadline.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T02:56:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: "Open" and online means that "flexibility" should be the main purpose.
You have a lot to learn about MOOCs. It's near impossible to be flexible with 40,000+ students.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:58:22Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes. Some moocs are entirely flexible. Join when you want, submit when you want. But no certificate. No lecturer input. You are totally on your own.
Moocs are a big experiment, and we are the subjects. It is not a "free" university credit and the staff owe us nothing.
I'm just amazed at the number of those who *claim* higher degrees (I have my doubts). Why are they doing a basic stats course? And why haven't they learnt to read policies during their many years at university?
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T03:13:16Z
SecondChildVoteTAG: 0
FirstChildTAG: I totally agree with you or what they should do is set a 11:30 pm or 11:00 pm deadline across all time zones. Like you I do not find this course to be flexible. It is as if it is expected that this is the only course you are doing or you are a full time student. A lot of material and reading was in the first week and then you have the quizzes which are lengthy and many times require thought.
I am about to pursue a DBA and I shudder to think what regular people with little or no background at all in statistics and a full time are going through. I am glad to be learning a lot though. So I guess I will just continue learning but probably won't take any of the tests. I also find it questionable to have due dates for quizzes in the week day? What about working folks? Wouldn't weekends be better? I am up in the dead of night catching up with this course and at the end of it all I cannot submit my answers. I do not think this is fair to me regardless of any stated timezone deadlines because I am not in an area with that time zone.
FirstChildUserIdTAG: 1221482
FirstChildUserNameTAG: Kimmy2013
FirstChildCreateTimeTAG: 2013-02-28T03:02:36Z
FirstChildVoteTAG: 0
SecondChildTAG: @merhutchin that's crap I have no other issues with other courses. I am doing the global poverty course as well on EDX and these issues are not present. In fact most other MOOCs do not have such strict deadlines as are present in this course. It is possible to be flexible set a time zone across all timezones. Ask students to indicate their country and the time zones will be adjusted as such. Flexibility can occur with 400,000 if lecturers realize this is not simply an online portion of a berkeley course where all the students are in the same state and thus in the same time zone.
SecondChildUserIdTAG: 1221482
SecondChildUserNameTAG: Kimmy2013
SecondChildCreateTimeTAG: 2013-02-28T03:05:52Z
SecondChildVoteTAG: 0
SecondChildTAG: so n=1 is a good-sized sample?
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T03:08:38Z
SecondChildVoteTAG: 0
IndexTAG: 1848
TitleTAG: Can't meet the due time/date
Buttons not working and I have been trying for a few hours.
UserIdTAG: 1279151
UserNameTAG: dgsilva
CreateTimeTAG: 2013-02-28T02:55:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: that's because the time has elapsed. The homework due time is 11:30 pm GMT
FirstChildUserIdTAG: 617920
FirstChildUserNameTAG: CMR
FirstChildCreateTimeTAG: 2013-02-28T02:56:15Z
FirstChildVoteTAG: 0
IndexTAG: 1849
TitleTAG: "check"
i dont see the "check" on my page
UserIdTAG: 1297694
UserNameTAG: capoorva
CreateTimeTAG: 2013-02-28T02:53:11Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Im too drunk to type
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:54:18Z
FirstChildVoteTAG: 0
SecondChildTAG: There's an excuse we haven't heard on the posts!
SecondChildUserIdTAG: 310963
SecondChildUserNameTAG: TwinOtter
SecondChildCreateTimeTAG: 2013-02-28T03:28:40Z
SecondChildVoteTAG: 0
IndexTAG: 1850
TitleTAG: about problem 4 in exercise set 4 mistake!
when you say this line should be read as 103 105 108 which is already obvious, it makes it sound as if you want us to compute the average of those 3 numbers and i did which gave me exactly 105 so obviously the closest number to 105 is 105. i think this problem should be reiterated because i only got it wrong since the question was not clear. please consider this.
UserIdTAG: 985560
UserNameTAG: zoe3456
CreateTimeTAG: 2013-02-28T02:49:46Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: maybe its cuz i currently have a bad cold and an ear infection. but i found the way this question was asked to be really quite unclear. i bet a bunch of people will answer 105 just because of the weird way the question was asked so ya.
FirstChildUserIdTAG: 985560
FirstChildUserNameTAG: zoe3456
FirstChildCreateTimeTAG: 2013-02-28T03:59:44Z
FirstChildVoteTAG: 0
IndexTAG: 1851
TitleTAG: Submitting answers and deadlines
Perhaps I'll need to chalk this up to 'lessons learned', but I too was unable to submit my answers to Exercise 3. I assumed that I had until the end of the evening of the 27th to complete but have since discovered the times posted next to the Exercise units are in GMT. (This is stated under Course Info - Course Policies and Requirements - under the 'Grading' heading.)
I have actually completed the exercise though. Despite my timezone issues, I am nevertheless interested in submitting my answers, if for no other reason than to see if I am right. I am reluctant to post all of my answers here in this forum though. I would love it if this exercise deadline was extended but understand if it isn't - however, is there some way we can enter our answers to see if and how we've made mistakes (other than our inability to convert our local time to GMT)
UserIdTAG: 971542
UserNameTAG: Jim_Bond
CreateTimeTAG: 2013-02-28T02:47:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: Copying an answer from Stephanie M, who has been kind enough to answer a few similar inquiries already:
The answers will be posted: "Solutions for each Exercise Set will become available the day after the Set is due, and will remain available through the course."
See this page, "Course Policies and Requirements":
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-02-28T02:53:00Z
FirstChildVoteTAG: 0
FirstChildTAG: If you read the policy document then you no doubt also read the entry that said the answers are released the day after submission closes.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:53:20Z
FirstChildVoteTAG: 0
IndexTAG: 1852
TitleTAG: Correct Answers?
Like many others, I overlooked that the deadline is 23.30 GMT and wrongly assumed the deadline was 23.30 PT (since UC Berkley is in PT). Yes, this is my fault, and I accept that I can't get credit for completing the exercise.
However, because I can't check my answers, I have no idea if mine were right or wrong. This means I have no idea if I'm on track or not -- especially with the box and whiskers plot which wasn't covered in the lecture or the corresponding section of the online textbook. Even if I don't get a "grade", I would like to know if my answers are correct or not.
UserIdTAG: 895319
UserNameTAG: katedahl
CreateTimeTAG: 2013-02-28T02:46:55Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The answers will be posted:
"Solutions for each Exercise Set will become available the day after the Set is due, and will remain available through the course. "
So you could answer the questions (not receive credit for them) and check with the answers posted tomorrow to see if you are on track.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:49:02Z
FirstChildVoteTAG: 2
SecondChildTAG: You beat me to it again! :vD
(I was trying to make up for causing more confusion.)
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-02-28T02:50:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, Stephanie! I did write down my answers, so I will be able to compare them. I wish they were already up because I'm in that frame of mind and really like immediate feedback. (Plus, since they are using GMT to determine when it's due, it is already the day after the set is due in GMT.)
SecondChildUserIdTAG: 895319
SecondChildUserNameTAG: katedahl
SecondChildCreateTimeTAG: 2013-02-28T02:54:16Z
SecondChildVoteTAG: 0
SecondChildTAG: ahh..I too thought its PST. I came back from office early, to do chores and get set on this. My bad!
SecondChildUserIdTAG: 774017
SecondChildUserNameTAG: AdityaGupta
SecondChildCreateTimeTAG: 2013-02-28T02:56:46Z
SecondChildVoteTAG: 0
IndexTAG: 1853
TitleTAG: Submission time is GMT
I missed it too.
UserIdTAG: 913981
UserNameTAG: DSamuel
CreateTimeTAG: 2013-02-28T02:44:11Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: So bad, I was answering the exercises but I assume that was Berkeley's time (California, not GMT. Where was that info?
Thanks,
Jose
FirstChildUserIdTAG: 1020704
FirstChildUserNameTAG: JoseAC
FirstChildCreateTimeTAG: 2013-02-28T02:46:20Z
FirstChildVoteTAG: 0
SecondChildTAG: I was enjoying working the exercises but missed submitting the assignments. By the way it's about 22:15 EST
SecondChildUserIdTAG: 117419
SecondChildUserNameTAG: mcpyngrope
SecondChildCreateTimeTAG: 2013-02-28T03:20:18Z
SecondChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
FirstChildUserIdTAG: 617920
FirstChildUserNameTAG: CMR
FirstChildCreateTimeTAG: 2013-02-28T02:58:53Z
FirstChildVoteTAG: 0
IndexTAG: 1854
TitleTAG: Exercuse set 2:
I don't see how to submit my answers.It is 21.41 East Time(MONTREAL,CANADA)
UserIdTAG: 1101917
UserNameTAG: tnduwimana
CreateTimeTAG: 2013-02-28T02:42:09Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:45:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Please read the other posts. The deadline was based on the GMT time zone. It was stated in the course policies document.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:45:47Z
FirstChildVoteTAG: 0
IndexTAG: 1855
TitleTAG: HELP!
I cannot submit my answers .It is only 8:40 p.m. here in El Salvador
UserIdTAG: 1131546
UserNameTAG: luismiguel_lopez
CreateTimeTAG: 2013-02-28T02:42:07Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:45:25Z
FirstChildVoteTAG: 0
IndexTAG: 1856
TitleTAG: 11:30 ???????
Sooo upset.
UserIdTAG: 771488
UserNameTAG: baconusa
CreateTimeTAG: 2013-02-28T02:41:39Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1857
TitleTAG: Request that exercise set answers be posted once the submission deadline has passed.
Will the answers to exercise sets be posted at some point? I am still working my way through Week 1 material and quizzes (as I see many others are), and even though I'm too late for my scores to count, I would very much like to check my work against the correct answers.
I plan to continue, so I would like to make sure I understand the material before I move on to Week 2. I assume I'm not the only one.
Thank you!
UserIdTAG: 914245
UserNameTAG: dbaPlanB
CreateTimeTAG: 2013-02-28T02:41:37Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: They will be posted as stated in the Course Policies document:
Solutions for each Exercise Set will become available the day after the Set is due, and will remain available through the course.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:43:21Z
FirstChildVoteTAG: 1
FirstChildTAG: Hi, Stephanie,
Thank you very much. Perhaps it was your post I saw in another thread pointing to this information in the course policy document:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
I came back here to answer my own question, but you beat me to it!
Thanks again. Who thought I would ever be so anxious to see my answers on a statistics quiz! ;v)
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-02-28T02:47:36Z
FirstChildVoteTAG: 0
SecondChildTAG: No problem! I am always anxious to quickly see answers to tests I take so I don't forget how I answered them in the first place, so I understand :)
SecondChildUserIdTAG: 1055794
SecondChildUserNameTAG: Stephanie_M
SecondChildCreateTimeTAG: 2013-02-28T03:04:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Stephanie, what I am doing is copy-pasting the exam questions into a Word document, and recording my calculations in that document. Then I transfer the answers to the online quiz and check. That way I can backtrack to see what I got wrong, then try again. Plus, this is sort of like taking notes, because I see the Prof. likes to spring new material on us in the quizzes. (And what a thrill it is to be able to figure it out!)
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-02-28T16:56:58Z
SecondChildVoteTAG: 0
FirstChildTAG: > Will the answers to exercise sets be posted at some point?
sigh. Two points about the GMT policy
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:52:06Z
FirstChildVoteTAG: 0
IndexTAG: 1858
TitleTAG: cant finish in chicago
I also am unable to submit my answers and its only 840 in Chicago.
Could the submission timeframe be stated more obviously?
First time on here and did not even think about the time zones for the submission, if my mistake I apologize and will take it into account next time.
UserIdTAG: 1186081
UserNameTAG: asbischo
CreateTimeTAG: 2013-02-28T02:40:16Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1859
TitleTAG: Time zone wasn't specified, but...
...Berkeley is in the Pacific Time Zone, so I assumed the deadline would correspond.
UserIdTAG: 1086254
UserNameTAG: eunverdi
CreateTimeTAG: 2013-02-28T02:39:31Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: It was. GMT.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:41:49Z
FirstChildVoteTAG: 0
SecondChildTAG: What does 11:53 mean? 11:53 pm or something else for excesize due date?
SecondChildUserIdTAG: 991819
SecondChildUserNameTAG: Queen9302
SecondChildCreateTimeTAG: 2013-02-28T02:43:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Just found that course policy link. Bummer for me too.
SecondChildUserIdTAG: 945143
SecondChildUserNameTAG: joddde
SecondChildCreateTimeTAG: 2013-02-28T02:53:57Z
SecondChildVoteTAG: 0
IndexTAG: 1860
TitleTAG: Button issue
Me too!!!! Glad I am not the only one. I thought I had to be careful because I am two hours behind the east coast... actually I am 7 hours behind GMT.
UserIdTAG: 956641
UserNameTAG: Brit4tany
CreateTimeTAG: 2013-02-28T02:38:41Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Just wish you had posted this as a reply to an existing post.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:43:10Z
FirstChildVoteTAG: 0
SecondChildTAG: And I wish ChristineStv would stop her childish replies to EVERY post. It's more annoying than the so called annoying posts she keeps complaining about.
SecondChildUserIdTAG: 894150
SecondChildUserNameTAG: Anna618
SecondChildCreateTimeTAG: 2013-02-28T02:44:13Z
SecondChildVoteTAG: 0
SecondChildTAG: [enter link description here][1]
[1]: http://en.wikipedia.org/wiki/Catfight
SecondChildUserIdTAG: 309823
SecondChildUserNameTAG: prion
SecondChildCreateTimeTAG: 2013-02-28T02:50:23Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL!
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T02:55:23Z
SecondChildVoteTAG: 0
IndexTAG: 1861
TitleTAG: Due at 23:30
This is very unfortunate to have this time zone problem.
I also had problems with connexion and lost time. Now that I can finally get this going and find out I don't have the opportunity to finish is very demotivating.
UserIdTAG: 1202020
UserNameTAG: SylvieB
CreateTimeTAG: 2013-02-28T02:37:41Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I agree.
FirstChildUserIdTAG: 894150
FirstChildUserNameTAG: Anna618
FirstChildCreateTimeTAG: 2013-02-28T02:44:36Z
FirstChildVoteTAG: 0
IndexTAG: 1862
TitleTAG: finally the energy come back and i can't submit the test
i'm from Colombia and finally the energy come back and i can't submit the test :(
UserIdTAG: 1212588
UserNameTAG: hvargasb
CreateTimeTAG: 2013-02-28T02:37:22Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Which is why you should not be leaving things to the last minute.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:43:33Z
FirstChildVoteTAG: 0
IndexTAG: 1863
TitleTAG: cannot submit answers
glad i am not the only one not seeing the "final check" button. waiting.....
UserIdTAG: 1231834
UserNameTAG: RajH
CreateTimeTAG: 2013-02-28T02:35:57Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: So why a new post? What is wrong with using an existing post?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:43:57Z
FirstChildVoteTAG: 1
IndexTAG: 1864
TitleTAG: submit?
same as others... the button is not there...
UserIdTAG: 1283493
UserNameTAG: MAC67
CreateTimeTAG: 2013-02-28T02:35:43Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The funeral for my liver is tomorrow. All welcome.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:44:16Z
FirstChildVoteTAG: 1
IndexTAG: 1865
TitleTAG: No submit botton
I cannot submit my answers... what do we have to do now?
UserIdTAG: 1034614
UserNameTAG: MariamOsorio
CreateTimeTAG: 2013-02-28T02:35:07Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Good manners prevents me from answering that.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:44:36Z
FirstChildVoteTAG: 2
IndexTAG: 1866
TitleTAG: Couldn´t submit answers. I was in time!
I Couldn´t submit my answers neither. I´m In Chile. it´s 27 feb. 23.33 hrs.
UserIdTAG: 956495
UserNameTAG: cneirai
CreateTimeTAG: 2013-02-28T02:34:54Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:47:05Z
FirstChildVoteTAG: 0
IndexTAG: 1867
TitleTAG: Cannot finish the exercise 3????
The submission deadline was Feb 27, 2013 11:30 pm and at East coast time (Boston, it is still is 9:33 pm. I was trying to finish the exercise 3 and suddenly the submission tabs for the last questions are not there anymore. Please, what is going on?
UserIdTAG: 1223568
UserNameTAG: zzali
CreateTimeTAG: 2013-02-28T02:34:26Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Neither can I!
FirstChildUserIdTAG: 759060
FirstChildUserNameTAG: RocioRosado
FirstChildCreateTimeTAG: 2013-02-28T02:35:31Z
FirstChildVoteTAG: 1
FirstChildTAG: For the love of my liver, just go read the forum before you post!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:39:11Z
FirstChildVoteTAG: 0
FirstChildTAG: nope, time zone is GMT
FirstChildUserIdTAG: 617920
FirstChildUserNameTAG: CMR
FirstChildCreateTimeTAG: 2013-02-28T02:57:18Z
FirstChildVoteTAG: 0
IndexTAG: 1868
TitleTAG: Sound of lectures very low - hard to hear even at the max
Lectures for week 2 I noticed the sound is very low even at the maximum level. There is nothing wrong with my pc - it is new. Please do something to increase the sound level.
Thanks
UserIdTAG: 1181314
UserNameTAG: SolomonT
CreateTimeTAG: 2013-02-28T02:34:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: yeah I have to increase the vol in my PC to the max!
FirstChildUserIdTAG: 199205
FirstChildUserNameTAG: ririana
FirstChildCreateTimeTAG: 2013-02-28T02:44:27Z
FirstChildVoteTAG: 0
IndexTAG: 1869
TitleTAG: PLEASE calm down. The deadline is past.
Please stop posting the same thing hundreds of times. Deadlines are based on GMT time. Two lowest homework scores are dropped. No need to panic. We are just adding to the confusion by creating hundreds of separate posts.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T02:34:13Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Unfortunately I think your plea will fall on deaf ears. The people who keep posting the same question over and over again obviously don't ready the discussion forum, so they won't see your post.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:48:00Z
FirstChildVoteTAG: 0
IndexTAG: 1870
TitleTAG: distracting
I thought the discussion forum was for discussing homework not technical glitches etc. It is really irritating me givent the current status of forum
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-28T02:33:29Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: people really need to read all course materials thoroughly before posting. it really gets annoying not to mention frustrating searching for the post you posted with a question on a lecture point
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-28T02:38:47Z
FirstChildVoteTAG: 1
SecondChildTAG: It won't change SherryJo. It's why universities do not have to worry about moocs. Nice idea, but doomed to fail.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T02:58:06Z
SecondChildVoteTAG: 0
FirstChildTAG: It won't fail. It will evolve, but we, the first students, will go extinct.
FirstChildUserIdTAG: 310963
FirstChildUserNameTAG: TwinOtter
FirstChildCreateTimeTAG: 2013-02-28T03:23:42Z
FirstChildVoteTAG: 0
SecondChildTAG: lol I am now imagining myself as a great ape learning to use tools for the first time
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-01T22:51:41Z
SecondChildVoteTAG: 0
IndexTAG: 1871
TitleTAG: Time Zone should have been clear
I cannot submit my answers either.It is only 8:30 here
UserIdTAG: 1092528
UserNameTAG: SGomer
CreateTimeTAG: 2013-02-28T02:33:26Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I am facing the same issue I just completed my quiz and now I am seeing where I cannot submit the answers. The time here is 9:34 pm.
After spending so much time on the quiz I am disappointed.
FirstChildUserIdTAG: 1221482
FirstChildUserNameTAG: Kimmy2013
FirstChildCreateTimeTAG: 2013-02-28T02:35:14Z
FirstChildVoteTAG: 0
SecondChildTAG: it said the time zone in the syllabus as the following: Grading
● Exercise Sets are due at specified dates and times. All times are in Greenwich Mean
Time (GMT).
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-28T02:37:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Really? Where's the link to the Syllabus from within the course? I don't see it.
SecondChildUserIdTAG: 972465
SecondChildUserNameTAG: ToddCioffi
SecondChildCreateTimeTAG: 2013-02-28T03:05:43Z
SecondChildVoteTAG: 0
IndexTAG: 1872
TitleTAG: yeah I got locked out before the deadline
please help. I was working on EST. I got lock out about 2.5 hours too early.
UserIdTAG: 1299221
UserNameTAG: coxen00
CreateTimeTAG: 2013-02-28T02:31:30Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: me too in nj!
FirstChildUserIdTAG: 933984
FirstChildUserNameTAG: KatieRxPen
FirstChildCreateTimeTAG: 2013-02-28T02:33:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:33:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Was it? Who knew! Oh, those who read the policies.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T02:35:30Z
SecondChildVoteTAG: 0
IndexTAG: 1873
TitleTAG: Agree with everyone else on the time zone thing
that's a drag
UserIdTAG: 949202
UserNameTAG: Sindlinger
CreateTimeTAG: 2013-02-28T02:29:58Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yeah, how dare they! Set a policy that no one reads. Give forum guidelines that no one reads. Damn hide!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:36:18Z
FirstChildVoteTAG: 2
IndexTAG: 1874
TitleTAG: Time Zone?
I really wonder which time zone did you set , I am in Montreal UTC-5 see http://www.worldtimezone.com/ , at 9 p.m , can't submit answers ? !!!
UserIdTAG: 416313
UserNameTAG: Dti33
CreateTimeTAG: 2013-02-28T02:29:54Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:33:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Oh no I was working on the Panamanian time and thought I was in position to hand in.
Yeah lesson learnt.
SecondChildUserIdTAG: 979865
SecondChildUserNameTAG: Chrisgk
SecondChildCreateTimeTAG: 2013-02-28T03:11:50Z
SecondChildVoteTAG: 0
FirstChildTAG: Take a look at the Course Policies doc. Amazing read.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:36:48Z
FirstChildVoteTAG: 0
IndexTAG: 1875
TitleTAG: Unable to submit answers
I could not submit my answers
UserIdTAG: 1223700
UserNameTAG: Daminoo
CreateTimeTAG: 2013-02-28T02:29:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:33:54Z
FirstChildVoteTAG: 0
IndexTAG: 1876
TitleTAG: Extension of time for HW 1
Please let us have the extension of time for HW 1 as in previous course we used to submit till 12 noon next day according to our time zone hence the confusion
UserIdTAG: 530630
UserNameTAG: surekhatayade
CreateTimeTAG: 2013-02-28T02:29:22Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I certainly hope they don't. If you can't read the course policy and follow guidelines, then learn from your mistake and move on.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:37:37Z
FirstChildVoteTAG: 0
SecondChildTAG: That was a bit of a harsh response considering almost everyone taking this class is having the same issue. It's nice to know we are soo perfect that we can't even sympathize with someone else.
SecondChildUserIdTAG: 894150
SecondChildUserNameTAG: Anna618
SecondChildCreateTimeTAG: 2013-02-28T02:41:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Anna618, not everyone had the same problem. Apparently, the students who didn't read the deadline policy also didn't read the discussion forum guidelines. To me that shows a lack of respect towards the course and its staff.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T02:51:34Z
SecondChildVoteTAG: 0
IndexTAG: 1877
TitleTAG: 11:30 pm
Estoy realizando mi tarea y no puedo subir mis respuestas.
UserIdTAG: 638652
UserNameTAG: lauradelgado
CreateTimeTAG: 2013-02-28T02:28:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: La hora limite ya paso. Esta basada en el tiempo medio de Greenwich. GMT en ingles
FirstChildUserIdTAG: 695174
FirstChildUserNameTAG: nerico
FirstChildCreateTimeTAG: 2013-02-28T02:41:54Z
FirstChildVoteTAG: 0
IndexTAG: 1878
TitleTAG: Answers
I cannot submit my answers neither. Thanks!
UserIdTAG: 981305
UserNameTAG: suadelburai
CreateTimeTAG: 2013-02-28T02:28:13Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:34:17Z
FirstChildVoteTAG: 0
SecondChildTAG: But in California is 18:35 now... we have time
SecondChildUserIdTAG: 1034614
SecondChildUserNameTAG: MariamOsorio
SecondChildCreateTimeTAG: 2013-02-28T02:36:13Z
SecondChildVoteTAG: 0
SecondChildTAG: GMT GMT
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-28T02:37:26Z
SecondChildVoteTAG: 0
SecondChildTAG: LOL. Moving on to the tequila I think.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T02:38:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Just give me grain alcohol.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T02:52:10Z
SecondChildVoteTAG: 0
IndexTAG: 1879
TitleTAG: Too late
And me thinking that i had another 5 hours because berkeley is in california, too bad.. hahha, i was taking this really seriously.
UserIdTAG: 1316542
UserNameTAG: Dodavor
CreateTimeTAG: 2013-02-28T02:27:00Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: But not seriously enough to read the course policies?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:30:49Z
FirstChildVoteTAG: 0
SecondChildTAG: You are right, i just added this course yesterday i was hurry, i know it was my fault, im not saying that im against the policies of the course.
SecondChildUserIdTAG: 1316542
SecondChildUserNameTAG: Dodavor
SecondChildCreateTimeTAG: 2013-02-28T15:20:45Z
SecondChildVoteTAG: 0
IndexTAG: 1880
TitleTAG: Define the precise time zone please!!!
Time zone should be strictly defined for the next time!!! 23.30!!????
UserIdTAG: 1151475
UserNameTAG: Vicky87
CreateTimeTAG: 2013-02-28T02:26:59Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: The time zone was defined the in course policies document:
Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:30:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a shared responsibility, for us to read, and for you to inform with greater power.**
I hope you could take a positive action toward this problem,
Oscar7000
SecondChildUserIdTAG: 609816
SecondChildUserNameTAG: Oscar7000
SecondChildCreateTimeTAG: 2013-02-28T02:32:29Z
SecondChildVoteTAG: 0
SecondChildTAG: In a mooc course, what is imperative is that the 47000+ people read and follow instructions. The course policy was quite clear. Forum use guidelines are quite clear. Both of which are not optional reading, even though dozens treat them as such.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T02:41:16Z
SecondChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:30:43Z
FirstChildVoteTAG: 0
FirstChildTAG: From the courseware policy document
Grading
Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
Your two lowest Exercise Set scores will not be used in the calculation of your overall grade.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-28T02:38:51Z
FirstChildVoteTAG: 0
SecondChildTAG: ABSOLUTELY ABSURD
SecondChildUserIdTAG: 938670
SecondChildUserNameTAG: JeffVirginia
SecondChildCreateTimeTAG: 2013-02-28T03:29:27Z
SecondChildVoteTAG: 0
IndexTAG: 1881
TitleTAG: Don't start the exercises if you cannot finish!
Did the first problem - had to run out of the office for a minute and came back to a restarted computer and now I cannot submit the rest of the assignment! :(
UserIdTAG: 470006
UserNameTAG: DGull
CreateTimeTAG: 2013-02-28T02:25:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: time to submit answers was over appartently
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-28T02:32:08Z
FirstChildVoteTAG: 0
IndexTAG: 1882
TitleTAG: I cannot submit my answers, time zone should be precisely defined!!!!!!!!!!!!!!
I am trying to submit my answers and apparently this is not possible. Should be some misunderstanding with the time zone mentioned in the course description.
Please define the correct one, or re-open even for a few hours!
UserIdTAG: 1151475
UserNameTAG: Vicky87
CreateTimeTAG: 2013-02-28T02:25:08Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It was precisely defined in the Course Policies and Requirements Section:
Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
We really need to stop posting the same issue.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:29:40Z
FirstChildVoteTAG: 0
SecondChildTAG: Wow what a curt answer. So far I am not enjoying the experience of the course. I think that the timelines are too rigidly defined especially given the nature of the subject matter. We have to absorb a lot in a week and then complete lengthy quizzes in the same week. Then we have come online to find that we missed a deadline because of differences in time zones. The deadline should be across timezones i.e. 11:00 pm cutoff date for all time zones.
SecondChildUserIdTAG: 1221482
SecondChildUserNameTAG: Kimmy2013
SecondChildCreateTimeTAG: 2013-02-28T02:38:23Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem is there is one universal time zone and it was clearly mentioned in the courseware.It would be wiser to look through the whole thing once again.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-28T02:40:11Z
SecondChildVoteTAG: 0
IndexTAG: 1883
TitleTAG: No submit button
I can not submit my answers.
UserIdTAG: 894150
UserNameTAG: Anna618
CreateTimeTAG: 2013-02-28T02:23:39Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:24:16Z
FirstChildVoteTAG: 0
SecondChildTAG: mh… I never thought it was GMT (LONDON TIME)… has no sense whereas the courses are done in USA Universities. FUNNY though…
SecondChildUserIdTAG: 1172070
SecondChildUserNameTAG: alpisteasea
SecondChildCreateTimeTAG: 2013-02-28T02:27:25Z
SecondChildVoteTAG: 0
SecondChildTAG: What the heck?!?! Why didn't somebody bother to mention this? Other classes I'm taking at least have the time local to the college or even go so far to have an applet that puts it in my local time.
SecondChildUserIdTAG: 1282255
SecondChildUserNameTAG: caroljean52
SecondChildCreateTimeTAG: 2013-02-28T02:28:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Exactly this is the only Edx class that I am having this issue with & it's not like I am the only one. It's very disappointing apparently for everyone.
SecondChildUserIdTAG: 894150
SecondChildUserNameTAG: Anna618
SecondChildCreateTimeTAG: 2013-02-28T02:32:57Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm not disappointed. I read the Course Policy page and understood that the deadline was in GMT.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T02:35:42Z
SecondChildVoteTAG: 0
IndexTAG: 1884
TitleTAG: No submit button
Can not submit either
UserIdTAG: 894150
UserNameTAG: Anna618
CreateTimeTAG: 2013-02-28T02:22:31Z
VoteTAG: 10
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:24:23Z
FirstChildVoteTAG: 0
SecondChildTAG: Where was that specified? I searched, but couldn't find it.
SecondChildUserIdTAG: 1086254
SecondChildUserNameTAG: eunverdi
SecondChildCreateTimeTAG: 2013-02-28T02:41:26Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
"Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT)."
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T02:53:39Z
SecondChildVoteTAG: 0
IndexTAG: 1885
TitleTAG: Also, cannot submit!
No submit button.
UserIdTAG: 1282183
UserNameTAG: Lehman
CreateTimeTAG: 2013-02-28T02:21:23Z
VoteTAG: 8
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:24:29Z
FirstChildVoteTAG: 0
IndexTAG: 1886
TitleTAG: No Submit button
I can't submit my answers too..Feb 27 Time is 9:21pm (US EST)
UserIdTAG: 496630
UserNameTAG: mswaminathan
CreateTimeTAG: 2013-02-28T02:21:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:24:34Z
FirstChildVoteTAG: 0
IndexTAG: 1887
TitleTAG: I think the time zone for submission was not very clear, no???????
I know that in other Edx courses the time zone is always the one of the University. Nothing different was mentioned here. Please, deal with it somehow.
Thanx
UserIdTAG: 1149607
UserNameTAG: MSpyros
CreateTimeTAG: 2013-02-28T02:20:46Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: From the Course Policies page:
Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:25:23Z
FirstChildVoteTAG: 0
SecondChildTAG: I do Agree is stated. Nevertheless is kind of ridiculous instead of having a local time. Londoners (and people around) would be pleased… and probably they would complain or ask to change it if you´re stated another time.
Anyway you are right (Edx). Is our obligation to read the terms and work in advance. A thing it wasn´t possible for me this week though.
SecondChildUserIdTAG: 1172070
SecondChildUserNameTAG: alpisteasea
SecondChildCreateTimeTAG: 2013-02-28T02:30:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Yeah, all due respect to the helpful answer posted by merhutchin above (and to the help intended), that's total crap.
The courseware, the Wiki page, the FAQ, the Course Schedule, the course book, none of them say anything about GMT. You know, the places where people spend any of their time.
The last couple of times I happened by the Course Info page, it came up blank, so I stopped going there. Turns out, that's the only place that links to the Course Policies page noted above - which is, I now see, *different* than the Policies section of the Wiki?
What's the point of having a Policies section of the Wiki if it doesn't actually contain your Policies?
So, buried three levels down off an obscure page (Course Info, Course Polices, bottom of the page) there is a tiny note about GMT?
We are supposed to even think to look for that as opposed to:
A) the fact that the whole world had to wait until Pacific time for the course to launch (remember all day long on Launch Day how everyone was saying "it's only x:xx am in California"?).
B) There is a Policies section in the Wiki, which is much more obvious to find, that says nothing about GMT.
C) There is no time zone noted on any deadlines on the Courseware page (how hard would it be to add GMT or PST or whatever Zone you wanted?)
D) Other BerkeleyX (even just other EdX in general) courses have used Pacific (or local) time because that's where they are, and all the students can figure that out.
This is a total fail from the admin.
I'm kind of torn because I really like the material, but between all the logistic issues, I'm losing the passion for going through the course.
Clearly, the instructors are not new. These are not technology issues. You have run classes before. You are bright people.
How do you not know that you have to be crystal clear with instructions about when things are due and the format of expected answers? People shouldn't have to hunt for those.
It also makes the rest of the discussion forum almost useless because a good chunk of the 47,000 students flood the forum with the same thing so that you can't find the things that are unique and helpful (there's no way to filter out the noise of issues that have been covered, so the only way to make it workable is to not create silly mistakes that cause the flood to begin with.)
How about proofing the answers before posting, for example?
I'm trying to do my part by not adding yet another thread to the flood, but if I don't get a response, I'm going to have to post this in its own thread (and keep posting this) until I do.
On behalf of all of the students, we deserve a response.
FirstChildUserIdTAG: 972465
FirstChildUserNameTAG: ToddCioffi
FirstChildCreateTimeTAG: 2013-02-28T03:00:03Z
FirstChildVoteTAG: 1
SecondChildTAG: ... and now we have one.
SecondChildUserIdTAG: 972465
SecondChildUserNameTAG: ToddCioffi
SecondChildCreateTimeTAG: 2013-02-28T03:52:22Z
SecondChildVoteTAG: 0
IndexTAG: 1888
TitleTAG: cannot submit answers
It's 21:18 in my country and cannot submit the answers...
UserIdTAG: 35445
UserNameTAG: JavierB
CreateTimeTAG: 2013-02-28T02:20:44Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:25:40Z
FirstChildVoteTAG: 0
IndexTAG: 1889
TitleTAG: Time issue
I cannot submit my answers. It is only 9:20 in MA.
UserIdTAG: 199203
UserNameTAG: Portia685
CreateTimeTAG: 2013-02-28T02:20:30Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:25:49Z
FirstChildVoteTAG: 0
IndexTAG: 1890
TitleTAG: excuse for not completion course
Very good night teachers, due to situations beyond my control I find it impossible to continue with the course, I hope for a next can retake it. I appreciate very much the support and opportunity given on this occasion.
Kind regards
Mary Elena Hernandez Galvan
UserIdTAG: 1262461
UserNameTAG: MaryElenaHernandezGalvan
CreateTimeTAG: 2013-02-28T02:20:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1891
TitleTAG: Weird Timeline of Test Submissions. Why GMT?
It is pretty obvious that most of the users are from the United States. As the course is from US Berkeley, why would we have a timeline for UK(GMT)? I know this is not an excuse to miss the test deadline but I think the test prepares definitely missed a trick here. I believe a lot of genuine students missed an easy score and will have to play catch up in the remaining of the course. The least i would expect from a STAT course is to do a distribution analysis of the students and then keep a deadline based on the timeline where most students reside. Nonetheless, a really good course and it's free learning. SO no complains :)
UserIdTAG: 972294
UserNameTAG: ShadaabBirwadker
CreateTimeTAG: 2013-02-28T02:20:10Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Huh indeed GMT is used because it is the UTC for the world
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-28T03:09:35Z
FirstChildVoteTAG: 1
SecondChildTAG: When Amazon.com gives me a deadline, I can intuitively understand it within my timezone. In other words, rather than pick a timezone, Amazon works with mine. I think that will have to be the standard for global education. Make it intutitive. Please don't take that as a snide comment - I just think it fits digital expectations.
Thanks for the course!
SecondChildUserIdTAG: 1282933
SecondChildUserNameTAG: JohnMarkGrubb
SecondChildCreateTimeTAG: 2013-02-28T23:16:39Z
SecondChildVoteTAG: 0
FirstChildTAG: GMT is universal for military, air traffic, navigation, satellites, financial systems, etc. It also doesn't change seasonally, as with Daylight Savings Time in the US. It's also easier to convert between GMT and your own time zone since it's one calculation. Here's a link that might help: http://wwp.greenwichmeantime.com/gmt-converter/
FYI, I'm also taking some Coursera classes, where they use their local time, and it's caused a great deal of confusion. Using GMT is much easier.
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-03-04T18:28:38Z
FirstChildVoteTAG: 0
IndexTAG: 1892
TitleTAG: I Definitely shouldn't have waited till the last minute.
I guess the March 27 th 2330 due date was set to GMT time zone. I'll be aware of that for the next assignment. Still a good course. Learning more than stats in this course. Thanks to the instructors.
Joe
UserIdTAG: 1204895
UserNameTAG: JOSEPHLMCGINNIS
CreateTimeTAG: 2013-02-28T02:19:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > I Definitely shouldn't have waited till the last minute.
As the Prof suggested.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:32:50Z
FirstChildVoteTAG: 0
IndexTAG: 1893
TitleTAG: dont admit answer problem 4
I think you close 13 minuntes early
UserIdTAG: 1235463
UserNameTAG: marychiri
CreateTimeTAG: 2013-02-28T02:18:27Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:26:20Z
FirstChildVoteTAG: 0
IndexTAG: 1894
TitleTAG: Unable to submit my answers
The same here, can you please remind me the time zone for the deadlines?
UserIdTAG: 1059217
UserNameTAG: donda
CreateTimeTAG: 2013-02-28T02:18:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It's GMT, I just remembered reading it.
FirstChildUserIdTAG: 1059217
FirstChildUserNameTAG: donda
FirstChildCreateTimeTAG: 2013-02-28T02:19:58Z
FirstChildVoteTAG: 0
SecondChildTAG: It might not be GMT because I am in Philippines which is GMT+8. When I tried to complete the assignment on 27th February 12:30 PM (Local Time), I was not able to complete my assignments. Even I am pretty confused. It would be helpful if the time zone is clarified.
SecondChildUserIdTAG: 933093
SecondChildUserNameTAG: Adithirv
SecondChildCreateTimeTAG: 2013-02-28T07:01:34Z
SecondChildVoteTAG: 0
IndexTAG: 1895
TitleTAG: Define the appropriate time zone, please
I join the complaints and questions of the rest of the students. I follow another course in Edx and the submission time is always the time of the University. Here, it wasn t mentioned anything in particular.
UserIdTAG: 1149607
UserNameTAG: MSpyros
CreateTimeTAG: 2013-02-28T02:18:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: It is GMT, Greenwich Mean Time.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:20:07Z
FirstChildVoteTAG: 1
FirstChildTAG: There is a course policy. I gather you didn't read it?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:32:21Z
FirstChildVoteTAG: 0
FirstChildTAG: it says Grading
● Exercise Sets are due at specified dates and times. All times are in Greenwich Mean
Time (GMT).
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-28T02:39:40Z
FirstChildVoteTAG: 0
IndexTAG: 1896
TitleTAG: software not allowing me to submit answer for exercise 3 - problem 2
There was no check answers button for problem 2 of exercise 3. Text below part c of question said "you have used 0 of 2 submissions".
Can you please explain? The answers are in the text boxes, but i was not able to check and get green check mark or red X.
UserIdTAG: 1117100
UserNameTAG: rob05439
CreateTimeTAG: 2013-02-28T02:16:23Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: i have a screenshot available of the error but this post forum does not support such images.
FirstChildUserIdTAG: 1117100
FirstChildUserNameTAG: rob05439
FirstChildCreateTimeTAG: 2013-02-28T02:18:30Z
FirstChildVoteTAG: 0
FirstChildTAG: For me there isn´t any check buttom on the exercise of set 3, Do you Know what is hapenning? Here is 23:20 yet...
FirstChildUserIdTAG: 803020
FirstChildUserNameTAG: Barbaralbtorres
FirstChildCreateTimeTAG: 2013-02-28T02:21:08Z
FirstChildVoteTAG: 0
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:26:43Z
FirstChildVoteTAG: 0
IndexTAG: 1897
TitleTAG: would like feedback regardless - what happens when you post on time?
I understand that many of us have missed the deadline but I would like to work through the problems anyway. Specially to find out whether I'm answering the question correctly or not.
To those of you who completed the homework before the deadline. Do we find out if we answered correctly as with the example exercise?
UserIdTAG: 695174
UserNameTAG: nerico
CreateTimeTAG: 2013-02-28T02:16:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1898
TitleTAG: Can't Submit Excercise Set 3
A problem for astute students:
If the instructors say "23:30" without stating the time zone, are they not making the same unforgivable error of "neglecting units" mentioned in one of the lectures?
Or did some sysadmin forget to set the timezone properly?
23:30 GMT = 18:30 EST
I request a re-test day next week! I set aside Wed night to do the graded exercise!
UserIdTAG: 1164712
UserNameTAG: jamesfischer
CreateTimeTAG: 2013-02-28T02:15:37Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The course uses GMT for its deadlines. This is clearly stated on the Course Policies page. Be courteous to the staff and your fellow students and read the Course Policies page *before* you begin the course.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:37:16Z
FirstChildVoteTAG: 0
IndexTAG: 1899
TitleTAG: How to submit the exercise??
Please tell me how to submit the exercise...
UserIdTAG: 1125926
UserNameTAG: dchoi90
CreateTimeTAG: 2013-02-28T02:14:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Interesting.. why they used GMT for due date..
FirstChildUserIdTAG: 1125926
FirstChildUserNameTAG: dchoi90
FirstChildCreateTimeTAG: 2013-02-28T02:26:39Z
FirstChildVoteTAG: 0
IndexTAG: 1900
TitleTAG: Very sad!
For me too. In my country is 11 pm and the submission button is gone.
UserIdTAG: 731366
UserNameTAG: PauloRV
CreateTimeTAG: 2013-02-28T02:14:37Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Same for me!!!
FirstChildUserIdTAG: 803020
FirstChildUserNameTAG: Barbaralbtorres
FirstChildCreateTimeTAG: 2013-02-28T02:21:47Z
FirstChildVoteTAG: 0
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:37:31Z
FirstChildVoteTAG: 0
IndexTAG: 1901
TitleTAG: 23:10 in brazil
unable to submit answers :(
UserIdTAG: 998617
UserNameTAG: Pedro1987
CreateTimeTAG: 2013-02-28T02:13:36Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Of course not. GMT, as explained in the policy.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:14:11Z
FirstChildVoteTAG: 0
IndexTAG: 1902
TitleTAG: Cannot submit any work
Help please
UserIdTAG: 253564
UserNameTAG: JasonCantow
CreateTimeTAG: 2013-02-28T02:12:10Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Me too
FirstChildUserIdTAG: 1203709
FirstChildUserNameTAG: breadwater
FirstChildCreateTimeTAG: 2013-02-28T02:14:45Z
FirstChildVoteTAG: 0
FirstChildTAG: Week 1 is finished. Move on to Week 2. And this time go read the course policy on when submissions close. GMT. And read the forum use guidelines too.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:20:46Z
FirstChildVoteTAG: 0
IndexTAG: 1903
TitleTAG: Help!
Help! I can not qualify or save the answers. No submit button! In my country still 21:10 hours
UserIdTAG: 725713
UserNameTAG: DenMar
CreateTimeTAG: 2013-02-28T02:11:01Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:11:45Z
FirstChildVoteTAG: 0
IndexTAG: 1904
TitleTAG: Numerical summaries
It is indeed important how to read, analyze and understand data and translate into operational applications. Very well explained.
UserIdTAG: 1326492
UserNameTAG: elcarlo7
CreateTimeTAG: 2013-02-28T02:10:44Z
VoteTAG: 0
CoursewareTAG: Section 1: Introduction / Lec 1.3. Bar graphs: describing categorical data
NumberOfReplyTAG: 0
IndexTAG: 1905
TitleTAG: California counts
so sad -- for us Californians...
UserIdTAG: 1115362
UserNameTAG: KarmaDrama
CreateTimeTAG: 2013-02-28T02:10:30Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Sad for a lot of people, it looks like. I figured a Berkeley class would use a Berkeley timezone. Next data set we can study is how many people could not finish their homework due to bad assumptions.
FirstChildUserIdTAG: 815116
FirstChildUserNameTAG: markgmn
FirstChildCreateTimeTAG: 2013-02-28T02:22:39Z
FirstChildVoteTAG: 1
SecondChildTAG: Us Nyers apparently didn't make the deadline either.
SecondChildUserIdTAG: 894150
SecondChildUserNameTAG: Anna618
SecondChildCreateTimeTAG: 2013-02-28T02:27:13Z
SecondChildVoteTAG: 0
FirstChildTAG: In Brasil is happening the same, and here is 23:20 right now...
FirstChildUserIdTAG: 803020
FirstChildUserNameTAG: Barbaralbtorres
FirstChildCreateTimeTAG: 2013-02-28T02:22:53Z
FirstChildVoteTAG: 0
IndexTAG: 1906
TitleTAG: Cannot submit as well.
No submit button
UserIdTAG: 253564
UserNameTAG: JasonCantow
CreateTimeTAG: 2013-02-28T02:10:11Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Apparently time's up.
FirstChildUserIdTAG: 1189168
FirstChildUserNameTAG: esai23
FirstChildCreateTimeTAG: 2013-02-28T02:10:32Z
FirstChildVoteTAG: 0
SecondChildTAG: I did the exercises and had the same problem of not seeing the submit button. There are three still three hours and `14 minutes from Medwest time to Eastern time. Any idea what is going on?
SecondChildUserIdTAG: 987158
SecondChildUserNameTAG: vijaysharma1122
SecondChildCreateTimeTAG: 2013-02-28T02:17:43Z
SecondChildVoteTAG: 0
FirstChildTAG: As well? So why did you start another post? Why not just add your "I didn't read the course policy either" to an existing post.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:17:25Z
FirstChildVoteTAG: 0
IndexTAG: 1907
TitleTAG: Homework deadline in GMT
I was working on my homework and the submit button stopped working after 17:30 CST i.e. 23:30 GMT. Very confusing as other courses use PST or EST.
UserIdTAG: 1007841
UserNameTAG: swarupdoshi
CreateTimeTAG: 2013-02-28T02:09:44Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: This one uses GMT.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:18:19Z
FirstChildVoteTAG: 1
SecondChildTAG: would have been nice to see the deadline timezone mentioned..
SecondChildUserIdTAG: 940447
SecondChildUserNameTAG: rob4511
SecondChildCreateTimeTAG: 2013-02-28T02:21:23Z
SecondChildVoteTAG: 0
SecondChildTAG: It would have been nice if your read the Course Policies page, where it clearly states that deadlines are in GMT.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T02:38:39Z
SecondChildVoteTAG: 0
IndexTAG: 1908
TitleTAG: Buttons are not there!
Is there any other way to submit answers? It is frustrating.
UserIdTAG: 662184
UserNameTAG: VCampa
CreateTimeTAG: 2013-02-28T02:09:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:12:23Z
FirstChildVoteTAG: 0
IndexTAG: 1909
TitleTAG: Not able to submit - 21:10 EST
-- Just thought I'd add to the already obvious issue ;-)
-Gabriel
UserIdTAG: 203329
UserNameTAG: gabieee
CreateTimeTAG: 2013-02-28T02:09:37Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:12:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Does not say GMT on the course info, schedule, email or on the due date assigned to the homework entry (points to the top left).
So if someone says 23:30 then it's 23:30 for everyone regardless of timezone. If it had specified EST / GMT / PST or some sort of timezone then we can calculate worldwide what is our specific due date. It is still 4pm in hawaii.
My previous course here had "EST" at the end of the due date/time *points to the top left*
;-)
-Gabriel
SecondChildUserIdTAG: 203329
SecondChildUserNameTAG: gabieee
SecondChildCreateTimeTAG: 2013-02-28T02:19:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Under the Grading section of the Course Policies and Requirements Documents, it says,
"Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT)."
I will admit, I did not see this early enough.
SecondChildUserIdTAG: 1055794
SecondChildUserNameTAG: Stephanie_M
SecondChildCreateTimeTAG: 2013-02-28T02:25:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Yup Found it just now. Oh well will calculate the time going forward manually. All other courses I am taking have the Timezone specified in the due-date for the homework. It would help to have it here. Oh well.
SecondChildUserIdTAG: 203329
SecondChildUserNameTAG: gabieee
SecondChildCreateTimeTAG: 2013-02-28T02:29:27Z
SecondChildVoteTAG: 0
FirstChildTAG: I think it might be best to stop posting the very same complaint over and over. The huge number of repetitious posts will hide any other issues that come up and need addressed. The staff will surely see the great number of posts already created.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:13:44Z
FirstChildVoteTAG: 1
FirstChildTAG: Thank you for that. Your inability to read the course policy and forum use guidelines just adds to the clutter. Never mind that real problems are being hidden in the deluge of "poor me, I didn't follow the rules" posts.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:19:54Z
FirstChildVoteTAG: 0
SecondChildTAG: No need for personal attacks. You just added to the clutter and just took a personal shot at me. But thanks for your input anyways.
Have a wonderful day Christine,
-Gabriel
SecondChildUserIdTAG: 203329
SecondChildUserNameTAG: gabieee
SecondChildCreateTimeTAG: 2013-02-28T02:32:10Z
SecondChildVoteTAG: 0
IndexTAG: 1910
TitleTAG: Help!
Help! I can not qualify or save the answers. No submit button!
UserIdTAG: 725713
UserNameTAG: DenMar
CreateTimeTAG: 2013-02-28T02:08:45Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:12:34Z
FirstChildVoteTAG: 0
IndexTAG: 1911
TitleTAG: Unable to submit homework
I am sure the deadline posted for 11:30pm has not past. Yet I cannot submit my homework! Please Help!!!!!!!!!!
UserIdTAG: 1187176
UserNameTAG: Schemell
CreateTimeTAG: 2013-02-28T02:08:10Z
VoteTAG: 10
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: That's what I was thinking too.
FirstChildUserIdTAG: 1189168
FirstChildUserNameTAG: esai23
FirstChildCreateTimeTAG: 2013-02-28T02:09:23Z
FirstChildVoteTAG: 1
SecondChildTAG: GMT 11:30, now , it has been 02/28 2am
SecondChildUserIdTAG: 1191891
SecondChildUserNameTAG: elsie0612
SecondChildCreateTimeTAG: 2013-02-28T02:13:00Z
SecondChildVoteTAG: 0
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:12:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Normally the time zone is PST or EST. So thought there is still some time left!! Please Help!!!
FirstChildUserIdTAG: 229763
FirstChildUserNameTAG: MedhaPhatak
FirstChildCreateTimeTAG: 2013-02-28T02:15:59Z
FirstChildVoteTAG: 1
IndexTAG: 1912
TitleTAG: Submission time request
Is it possible to keep it 11:30pm Pacific time? That would be a big convenience for working people in this part of the world.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T02:07:34Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:12:49Z
FirstChildVoteTAG: 0
SecondChildTAG: 9pm here :/
SecondChildUserIdTAG: 933119
SecondChildUserNameTAG: wsaw
SecondChildCreateTimeTAG: 2013-02-28T02:16:11Z
SecondChildVoteTAG: 0
IndexTAG: 1913
TitleTAG: Was not able to submit answers
I also am not able to submit answers. My check and save buttons have disappeared. According to the assignments, the deadline is 23:30. The time near the assignments did not list a time zone.
UserIdTAG: 1319247
UserNameTAG: Mary7x
CreateTimeTAG: 2013-02-28T02:07:06Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: this is also what i waswondering, re the time zone thing.
FirstChildUserIdTAG: 1235093
FirstChildUserNameTAG: Ifeg
FirstChildCreateTimeTAG: 2013-02-28T02:07:54Z
FirstChildVoteTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:13:01Z
FirstChildVoteTAG: 0
IndexTAG: 1914
TitleTAG: Unable to submit homework
Again it is 9:06pm EST and I cannot submit homework!
UserIdTAG: 1187176
UserNameTAG: Schemell
CreateTimeTAG: 2013-02-28T02:06:38Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Same issue here...
FirstChildUserIdTAG: 1104132
FirstChildUserNameTAG: alison_
FirstChildCreateTimeTAG: 2013-02-28T02:09:10Z
FirstChildVoteTAG: 0
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:13:11Z
FirstChildVoteTAG: 0
IndexTAG: 1915
TitleTAG: Not Able to Submit
Hello,
I am not able to submit my answers as there is no option to grade them. It is 9:05 EST time for me.
UserIdTAG: 1311400
UserNameTAG: Nirad
CreateTimeTAG: 2013-02-28T02:06:05Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:13:15Z
FirstChildVoteTAG: 0
IndexTAG: 1916
TitleTAG: Time posting
In Guatemala it's 8:00pm and I can't summit my answers. Can you explain us the limit time to do it?
UserIdTAG: 1012988
UserNameTAG: Jherreran
CreateTimeTAG: 2013-02-28T02:05:20Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: This was explained in the course policy document. GMT. As also mentioned in many of the dozens of posts about this.
It appears that those who didn't read the course policy also didn't read the forum use guidelines. Very telling.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:12:10Z
FirstChildVoteTAG: 0
IndexTAG: 1917
TitleTAG: Time for graded assignment
Hi, Could someone from the staff please respond to this question? The time for submitting the first assignment was Wednesday 27th February 23:30 hours. Does that correspond to Berkeley, California local time or the local time for any student residing in any part of the world? I am from India and my clock shows that I have a few hours left but I am unable to submit any of my answers. Please help
UserIdTAG: 592961
UserNameTAG: Sohini
CreateTimeTAG: 2013-02-28T02:04:53Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: GMT.It was clearly mentioned in the courseware
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-28T02:06:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, the courseware course policy document that dozens appear to have not read.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:12:31Z
FirstChildVoteTAG: 0
IndexTAG: 1918
TitleTAG: Submit Button
I am unable to submit my homework. It is 9:04pm EST! Help
UserIdTAG: 1187176
UserNameTAG: Schemell
CreateTimeTAG: 2013-02-28T02:04:49Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:13:37Z
FirstChildVoteTAG: 0
IndexTAG: 1919
TitleTAG: Please, no more "Unable to submit" posts.
It is very clear that several people cannot submit answers for week 1's exercises. I also missed the deadline, as I was unaware of the time zone used. There are now a ton of posts explaining the same problem. I'm sure the staff will see the posts and answer our questions, but the repetition is not helping. Let's try to condense our questions and comments to a few posts addressing a single issue.
Everyone should keep in mind that the time zone used for this class is GMT and that the 2 lowest exercise scores will not be counted toward your final grade.
-Stephanie_M
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T02:04:25Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I agree. Thank God for that "two exercise drop" rule.
FirstChildUserIdTAG: 1189168
FirstChildUserNameTAG: esai23
FirstChildCreateTimeTAG: 2013-02-28T02:12:14Z
FirstChildVoteTAG: 1
FirstChildTAG: My main concern is finding out what the answers are. Regardless of credit, I'd like to know the correct answers. I assume the correct answers will be posted. At least I hope so. I guess I needn't worry about the getting the quiz for lecture 3 done in time, either.
I copied my answers to paper. I haven't found an efficient way to save them in the computer.
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-02-28T02:13:03Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes, and as it says in the course policy that seems to be unread by most, the answers will be released the day after submission closes.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T02:16:23Z
SecondChildVoteTAG: 0
SecondChildTAG: That's my main concern too. I think it's most important to understand why a question is incorrect, while your reasoning behind your answer is still fresh in your mind. Hopefully there will be an answer key.
SecondChildUserIdTAG: 1055794
SecondChildUserNameTAG: Stephanie_M
SecondChildCreateTimeTAG: 2013-02-28T02:16:31Z
SecondChildVoteTAG: 0
FirstChildTAG: If I were a lecturer of an online course such as this I think I would require students to read all course information and take a quiz on their understanding before allowing access to the rest of the material. People are posting about additional issues and I think their legitimate questions are getting buried.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T02:58:30Z
FirstChildVoteTAG: 1
IndexTAG: 1920
TitleTAG: Can't Submit Exercise Set 2
No submit button. Time here in NYC is 9:04pm EST on Wed.
UserIdTAG: 1164712
UserNameTAG: jamesfischer
CreateTimeTAG: 2013-02-28T02:04:20Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Hate to break it to you buddy, but there isn't going to be a submit for any of the exercises now.
FirstChildUserIdTAG: 1189168
FirstChildUserNameTAG: esai23
FirstChildCreateTimeTAG: 2013-02-28T02:12:47Z
FirstChildVoteTAG: 0
IndexTAG: 1921
TitleTAG: not able to submit.
i´m not being able to submit my answers, it´s not 23:30 in brazil yet! maybe clock diference causes this. please clarify me.
UserIdTAG: 1277369
UserNameTAG: Ascensor
CreateTimeTAG: 2013-02-28T02:03:49Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:16:17Z
FirstChildVoteTAG: 0
IndexTAG: 1922
TitleTAG: Unable to submit answers to Exercise Set 3 - CST 20:00
Joining the rest of the group in saying unable to do submission.
UserIdTAG: 867008
UserNameTAG: Joleen
CreateTimeTAG: 2013-02-28T02:02:53Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:04:45Z
FirstChildVoteTAG: 0
IndexTAG: 1923
TitleTAG: Wasn't able to submit all answers
I started exercise set 3 on Tuesday evening, but did not have time to complete it. I submitted what I had completed with the expectation of being able to complete the rest of the problems Wednesday evening. Like others in the class, I no longer have a button available to submit my answers. I did not realize the deadline was not based on local time.
UserIdTAG: 1203606
UserNameTAG: CarieK
CreateTimeTAG: 2013-02-28T02:02:30Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1924
TitleTAG: HELP!
help! I can not qualify or save the answers
UserIdTAG: 725713
UserNameTAG: DenMar
CreateTimeTAG: 2013-02-28T02:01:53Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:04:59Z
FirstChildVoteTAG: 0
IndexTAG: 1925
TitleTAG: Submit option unavailable
Hi the option to submit the answers in Exercise set 3 in not available. Please check and let me know as it is due today. I am running out of time.
UserIdTAG: 994630
UserNameTAG: Priyanka02
CreateTimeTAG: 2013-02-28T02:01:12Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:05:04Z
FirstChildVoteTAG: 0
IndexTAG: 1926
TitleTAG: Can't submit
It's only 9pm here. What time was the deadline?
UserIdTAG: 1102861
UserNameTAG: avid_learner
CreateTimeTAG: 2013-02-28T01:59:35Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I just read that the times are GMT. We're screwed.
FirstChildUserIdTAG: 1299121
FirstChildUserNameTAG: Limpy
FirstChildCreateTimeTAG: 2013-02-28T02:04:57Z
FirstChildVoteTAG: 1
IndexTAG: 1927
TitleTAG: How do I submit?
Where is the submit button? I've tried doing these quizzes in Firefox, Explorer and Chrome- none of them have a button to submit my answers. Anyone any ideas? Thank you.
UserIdTAG: 1299121
UserNameTAG: Limpy
CreateTimeTAG: 2013-02-28T01:59:18Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 1928
TitleTAG: please set up discussion topics for this weeks lectures and exercises
the subject line says it all
UserIdTAG: 174100
UserNameTAG: markpolak
CreateTimeTAG: 2013-02-28T01:58:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: We're on it. Thanks, markpolak. We looked into doing it before the materials went up, but there was some technical reason for doing it afterwards. We appreciate the importance of keeping the discussions organized.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T02:05:38Z
FirstChildVoteTAG: 0
IndexTAG: 1929
TitleTAG: No Submit Button for HW week 1
There's no submit button for HW 1 and deadline hasn't passed.
UserIdTAG: 1153506
UserNameTAG: raciel23
CreateTimeTAG: 2013-02-28T01:58:21Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: It's after 23:30 GMT. I blew it also. I'm on the east coast of the US so, GMT is 5 hours ahead of my time. Won't get caught like that again!
FirstChildUserIdTAG: 1122976
FirstChildUserNameTAG: GayleB4305
FirstChildCreateTimeTAG: 2013-02-28T02:00:55Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes it has. 11:30pm GMT.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T02:01:13Z
FirstChildVoteTAG: 0
IndexTAG: 1930
TitleTAG: cant submit exercise 3
I am trying to submit exercise 3 but it wont let me submit it. It is 2/27/13 at 6:57pm anyone know whats going on?
UserIdTAG: 1108954
UserNameTAG: RachTeno
CreateTimeTAG: 2013-02-28T01:57:50Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The timings were supposedly in GMT instead of traditional EST. So a lot of us missed the third assignment.
FirstChildUserIdTAG: 982840
FirstChildUserNameTAG: AhadAlex
FirstChildCreateTimeTAG: 2013-02-28T02:00:01Z
FirstChildVoteTAG: 1
IndexTAG: 1931
TitleTAG: Submit button disappeared
Submit button disappeared before deadline! Please help.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T01:57:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's after 23:30 GMT. I blew it also. I'm on the east coast of the US so, GMT is 5 hours ahead of my time. Won't get caught like that again!
FirstChildUserIdTAG: 1122976
FirstChildUserNameTAG: GayleB4305
FirstChildCreateTimeTAG: 2013-02-28T01:59:57Z
FirstChildVoteTAG: 0
IndexTAG: 1932
TitleTAG: Can a TA post a video demonstrating how to complete the homework?
It is currently 8:57PM Eastern.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T01:57:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Week 1 has closed. Move on to week 2. And this time note that it is GMT and don't leave it to the last minute.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:00:02Z
FirstChildVoteTAG: 0
SecondChildTAG: As you can see by the discussion thread, many had the same issue. Speaking for myself, I did not leave materials till the last minute - all other than Exercise 3 were submitted before today. I used my available time today to review all of the course materials again before final submission of the last exercise. I am having some difficulty myself with the teaching style & delivery and using the course reference materials. No need to assume folks are procrastinating.
SecondChildUserIdTAG: 867008
SecondChildUserNameTAG: Joleen
SecondChildCreateTimeTAG: 2013-02-28T02:08:22Z
SecondChildVoteTAG: 0
IndexTAG: 1933
TitleTAG: Time's Up
Ridiculous that time says until 11:30 but it had to be converted first. And oh yeah, that' not mentioned anywhere.
UserIdTAG: 587109
UserNameTAG: TigranA
CreateTimeTAG: 2013-02-28T01:57:33Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: > And oh yeah, that' not mentioned anywhere.
Really? Another one who decided not to read the course policies document.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T02:00:42Z
FirstChildVoteTAG: 0
IndexTAG: 1934
TitleTAG: The answers can be sent
No submit buttom available.
UserIdTAG: 595589
UserNameTAG: kijesus01
CreateTimeTAG: 2013-02-28T01:57:21Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:04:32Z
FirstChildVoteTAG: 0
IndexTAG: 1935
TitleTAG: Deadline !!
Define if is GMT, please reopen submit button. Thanks.
UserIdTAG: 920670
UserNameTAG: andersuescun
CreateTimeTAG: 2013-02-28T01:56:33Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was over 2 hours ago.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:57:42Z
FirstChildVoteTAG: 0
IndexTAG: 1936
TitleTAG: No submit buttons
No buttons in Chile at 10:30...
UserIdTAG: 323166
UserNameTAG: PabloT
CreateTimeTAG: 2013-02-28T01:56:09Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:58:04Z
FirstChildVoteTAG: 0
IndexTAG: 1937
TitleTAG: Cannot submit excercise 3 but deadline hasnt passed
HI no button to submit as if the deadline has passed, but I think I should have until 11:30 tonight. any thoughts?
UserIdTAG: 348290
UserNameTAG: joshb
CreateTimeTAG: 2013-02-28T01:55:09Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Deadline was 11:30 GMT.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:58:14Z
FirstChildVoteTAG: 0
SecondChildTAG: I have lost the will to live.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T02:05:35Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm having the same problem.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T02:17:58Z
SecondChildVoteTAG: 0
FirstChildTAG: having same problem
FirstChildUserIdTAG: 1108954
FirstChildUserNameTAG: RachTeno
FirstChildCreateTimeTAG: 2013-02-28T01:58:16Z
FirstChildVoteTAG: 1
FirstChildTAG: Looks like I found the answer to my question in the syllabus. I will definitely be more vigilant about this moving forward.
Grading
● Exercise Sets are due at specified dates and times. All times are in Greenwich Mean
Time (GMT).
FirstChildUserIdTAG: 348290
FirstChildUserNameTAG: joshb
FirstChildCreateTimeTAG: 2013-02-28T02:00:58Z
FirstChildVoteTAG: 0
IndexTAG: 1938
TitleTAG: Where's the submission button?
Where's the submit button?
UserIdTAG: 896318
UserNameTAG: joschka-joseph
CreateTimeTAG: 2013-02-28T01:54:52Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:58:27Z
FirstChildVoteTAG: 0
IndexTAG: 1939
TitleTAG: Can't submit.
I put in answers but there is no submit button.
UserIdTAG: 1185375
UserNameTAG: Scribs
CreateTimeTAG: 2013-02-28T01:54:23Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:58:42Z
FirstChildVoteTAG: 0
IndexTAG: 1940
TitleTAG: No button to submit answers. colombia 8:52pm
No button to submit answers. colombia 8:52pm
UserIdTAG: 1116131
UserNameTAG: saidur4
CreateTimeTAG: 2013-02-28T01:52:50Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:58:53Z
FirstChildVoteTAG: 0
IndexTAG: 1941
TitleTAG: No button to submit homework
There is no 'submit' button for the homework.
UserIdTAG: 224213
UserNameTAG: Prudence
CreateTimeTAG: 2013-02-28T01:52:18Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:59:04Z
FirstChildVoteTAG: 0
SecondChildTAG: ARE YOU SERIOUS....THEY SAY WEDN EVENING AND THE COURSE IS OUT OF CALIFORNIA AND THEY USE gmT TIME....ABSURD
SecondChildUserIdTAG: 938670
SecondChildUserNameTAG: JeffVirginia
SecondChildCreateTimeTAG: 2013-02-28T03:27:56Z
SecondChildVoteTAG: 0
IndexTAG: 1942
TitleTAG: No submit button
Sorry, there is no submit button. Can't submit the exercises set3
UserIdTAG: 179505
UserNameTAG: JMauro
CreateTimeTAG: 2013-02-28T01:49:29Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T01:59:22Z
FirstChildVoteTAG: 0
IndexTAG: 1943
TitleTAG: The time expired before Due time
The time expired before due time which was set for 23:30 and it expired 22:30 in Brazil, but with the time diference from california I should have at least 3 more hours.
My exercises were already done but I was revewing to make sure before submitting.
UserIdTAG: 35528
UserNameTAG: gabrielpradera
CreateTimeTAG: 2013-02-28T01:48:40Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Gabriel, o horário do curso é GMT. Nosso GMT (Brasília) é -3:00. Então, 23:30 - 3h= 20:30 é nosso limite.
Também so entendí após perder último teste.
FirstChildUserIdTAG: 1031814
FirstChildUserNameTAG: Marivaldo
FirstChildCreateTimeTAG: 2013-02-28T01:58:01Z
FirstChildVoteTAG: 0
FirstChildTAG: Translate
"Gabriel, the travel time is GMT. Our GMT (Brasilia) is-03:00. So 23:30-3:0 = 20:30 is our limit. Also so understand after losing the last test."
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-28T02:33:24Z
FirstChildVoteTAG: 0
IndexTAG: 1944
TitleTAG: Exercise Set 2
Last night I partially did exercise 2 and when I went back into it today to finish the exercise I entered my answers but there is no Check and Save buttons. I can't save anything.
Colleen
UserIdTAG: 1032399
UserNameTAG: colleenswain
CreateTimeTAG: 2013-02-28T01:47:47Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:06:20Z
FirstChildVoteTAG: 0
IndexTAG: 1945
TitleTAG: Error in page exercise set 2
I couldn't submit the exercises. The submit button is missing
UserIdTAG: 179505
UserNameTAG: JMauro
CreateTimeTAG: 2013-02-28T01:47:33Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: I cannot submit the answers at all how do we go about it
FirstChildUserIdTAG: 1193499
FirstChildUserNameTAG: AshwaniChawla3
FirstChildCreateTimeTAG: 2013-02-28T01:50:48Z
FirstChildVoteTAG: 0
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:06:29Z
FirstChildVoteTAG: 0
IndexTAG: 1946
TitleTAG: Can't submit homework!!!!!
I thought that I was still within time for the deadline.
UserIdTAG: 1191161
UserNameTAG: bassidarboe
CreateTimeTAG: 2013-02-28T01:44:15Z
VoteTAG: 14
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: It's not.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:48:56Z
FirstChildVoteTAG: 0
SecondChildTAG: I have difficulty submitting home work for Exercise 3, could it be the time difference, because here in Canada is only 9:00 I am still in the timeline for 23:30. Look like the assignment for the week has been closed early than dateline.I need clarity on the time difference and because of this technical difficulty can this assignment timeline be extended.
SecondChildUserIdTAG: 521763
SecondChildUserNameTAG: taakondjo
SecondChildCreateTimeTAG: 2013-02-28T02:14:40Z
SecondChildVoteTAG: 0
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:06:45Z
FirstChildVoteTAG: 0
IndexTAG: 1947
TitleTAG: Not getting to submit home work
On the first occasion the save cells and check tabs were static ...so I reloaded the page and retried, now I don't see the save and check buttons after redoing the Ex. set and it is now 21:40 here
UserIdTAG: 418570
UserNameTAG: frey79
CreateTimeTAG: 2013-02-28T01:43:16Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1948
TitleTAG: deadline extension request
Dear Staff, I join the rest of the student body in our claim that the deadline has not been made very clear. Given my time zone, I should still have time to submit although the submit button is already disabled. Looking forward to hearing from you soon concerning the matter.
UserIdTAG: 445842
UserNameTAG: Umrbek
CreateTimeTAG: 2013-02-28T01:42:51Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was made very clear in the Course Policies.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:09:28Z
FirstChildVoteTAG: 0
IndexTAG: 1949
TitleTAG: No submission allowed
7.48pm Mexico city and not allowed to submit the last two answers.
UserIdTAG: 970190
UserNameTAG: Thomasdf
CreateTimeTAG: 2013-02-28T01:42:11Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:09:33Z
FirstChildVoteTAG: 0
IndexTAG: 1950
TitleTAG: Submit
Has no button to submit.
UserIdTAG: 143588
UserNameTAG: Cleitoon
CreateTimeTAG: 2013-02-28T01:41:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:09:39Z
FirstChildVoteTAG: 0
IndexTAG: 1951
TitleTAG: No Submit Button
It is currently 8:40pm ET and I don't see any submit buttons for the answers. Please fix.
UserIdTAG: 152890
UserNameTAG: jeanmarc
CreateTimeTAG: 2013-02-28T01:41:03Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: GMT, not EST was the deadline timezone
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:44:16Z
FirstChildVoteTAG: 0
FirstChildTAG: Unfortunately, this course uses Greenwich mean time so it's actually 1:40AM Thursday, which is past the due date. I made this mistake also and missed the deadline.
The good news is that your lowest 2 exercise scores will not be counted for your final grade calculation.
FirstChildUserIdTAG: 1055794
FirstChildUserNameTAG: Stephanie_M
FirstChildCreateTimeTAG: 2013-02-28T01:45:09Z
FirstChildVoteTAG: 0
IndexTAG: 1952
TitleTAG: Can't submit
No button to submit answers. 8:37pm EST.
UserIdTAG: 1261408
UserNameTAG: MaggieMcD
CreateTimeTAG: 2013-02-28T01:37:58Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a shared responsibility, for us to read, and for you to inform with greater power.**
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:39:50Z
FirstChildVoteTAG: 2
SecondChildTAG: The deadline was explained clearly in the Course Info section of the website. It's your responsibility to read this and ask questions *before the deadline* if it's not clear. Show some respect for the staff and your fellow classmates.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T02:11:07Z
SecondChildVoteTAG: 0
IndexTAG: 1953
TitleTAG: Problem 3 and 4
Here in Atlanta USA is 8.32 pm on 2/27/2013 and we supposed the dead line is 11.59 pm.
But we do not have the chance to submit the answers due to the buttons disappeared.
What is wrong?
Please help .
Pachonusa
UserIdTAG: 568940
UserNameTAG: ernestusa
CreateTimeTAG: 2013-02-28T01:37:40Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a shared responsibility, for us to read, and for you to inform with greater power.**
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:39:40Z
FirstChildVoteTAG: 2
FirstChildTAG: I must say I am dismayed with the poor instructions on the time schedule as there is no information on the fact that the deadline is of GMT time. The courseware and course description does not mention this information at all.
FirstChildUserIdTAG: 167010
FirstChildUserNameTAG: djsicotte
FirstChildCreateTimeTAG: 2013-02-28T03:03:09Z
FirstChildVoteTAG: 0
IndexTAG: 1954
TitleTAG: keep calm...Important post!!!Read point 2
quote from Requirements and policies:
Grading
Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
**Your two lowest Exercise Set scores will not be used in the calculation of your overall grade.**
Grades will be calculated using the following weights:
Exercise Sets: 50%
Midterm: 20%
Final exam: 30%
I'm trying to find comfort anywher I can!
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-02-28T01:37:21Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1955
TitleTAG: Thought it was US time!! missed it
I saved all the answers but did not click the grade button.. Thought would review before submitting and suddenly the check in buttons were gone. This is bad!! Dont even know the solutions now..Isn`t there something that can be done??? I am in TX.
UserIdTAG: 1252686
UserNameTAG: Kanika79
CreateTimeTAG: 2013-02-28T01:37:03Z
VoteTAG: 9
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a shared responsibility, for us to read, and for you to inform with greater power.**
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:40:00Z
FirstChildVoteTAG: 3
IndexTAG: 1956
TitleTAG: I can't submit my answers
It is 7:30 in Mexico, and i can't submit my answers
UserIdTAG: 979279
UserNameTAG: Ceci0401
CreateTimeTAG: 2013-02-28T01:36:37Z
VoteTAG: 10
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a shared responsibility, for us to read, and for you to inform with greater power.**
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:39:08Z
FirstChildVoteTAG: 2
SecondChildTAG: Support
SecondChildUserIdTAG: 1074160
SecondChildUserNameTAG: CheungA
SecondChildCreateTimeTAG: 2013-02-28T02:03:41Z
SecondChildVoteTAG: 0
IndexTAG: 1957
TitleTAG: 2.1X introduction
Soothing voice for learning. Key words simply explain. Understand the need to established relationship between variables for graphic description and establishing numerical summaries.
UserIdTAG: 1326492
UserNameTAG: elcarlo7
CreateTimeTAG: 2013-02-28T01:34:18Z
VoteTAG: 0
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 0
IndexTAG: 1958
TitleTAG: What happen? The submission button is not appearing.
I can not submit my answers, the button dissapeared about 7 pm. I'm in Mexico City.
UserIdTAG: 328875
UserNameTAG: mggh2005
CreateTimeTAG: 2013-02-28T01:31:38Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a shared responsibility, for us to read, and for you to inform with greater power.**
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:39:02Z
FirstChildVoteTAG: 1
IndexTAG: 1959
TitleTAG: Submission time is GMT
Did read the course policy but missed this one.
UserIdTAG: 913981
UserNameTAG: DSamuel
CreateTimeTAG: 2013-02-28T01:28:59Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Did you also miss the information on how to use the Discussion Forum? If you're new to how these things work, then keep in mind that you should try not to create a new discussion when there are hundreds that already address the same subject. You yourself have already created a discussion on this subject so this is at least your second. Use the little magnifying glass next to "Show all discussions" to look for "submission" or "GMT" and write your comments into an existing discussion (unless your question is genuinely original - then go ahead and create your own). Thanks.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:36:19Z
FirstChildVoteTAG: 0
IndexTAG: 1960
TitleTAG: I don't finde the button to submit my answers????
Somebody could inform what happens, I'm Boston, and now is 8:27!
UserIdTAG: 1206610
UserNameTAG: NelsonMatias
CreateTimeTAG: 2013-02-28T01:28:52Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Timezone is GMT, not EST
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:31:13Z
FirstChildVoteTAG: 0
IndexTAG: 1961
TitleTAG: Time's up
Unexpected. Did the work. Can't submit.
UserIdTAG: 57146
UserNameTAG: Secret
CreateTimeTAG: 2013-02-28T01:26:43Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a shared responsibility, for us to read, and for you to inform with greater power.**
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:38:58Z
FirstChildVoteTAG: 1
IndexTAG: 1962
TitleTAG: GTM-Due date/time communication strategy has a flaw
Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem. In this MOOC courses human factors are imperative to be hopefully, fully considered.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
UserIdTAG: 609816
UserNameTAG: Oscar7000
CreateTimeTAG: 2013-02-28T01:26:29Z
VoteTAG: 8
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1963
TitleTAG: Cannot Submit
Same problem. It is 20:30 on the 27. Any ideas?
UserIdTAG: 913981
UserNameTAG: DSamuel
CreateTimeTAG: 2013-02-28T01:26:05Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: GMT timezone. Which was two hours ago. What is your timezone? Also, please read the existing discussions. There are hundreds already that say the same thing...
Anyway, your bottom two scores will be dropped so you're in luck. Answers will be posted tomorrow.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:30:24Z
FirstChildVoteTAG: 0
SecondChildTAG: I doesn't give a time zone in the course info so I thought it would be safe to assume pst since it is Berkley.
SecondChildUserIdTAG: 1013457
SecondChildUserNameTAG: asabahi
SecondChildCreateTimeTAG: 2013-02-28T01:37:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Some of us work and have families and have difficulty submitting answers for questions when GMT is five or more hours ahead of our local time. I was still at work at 2030 GMT and therefore lose an entire day for homework submissions. Since the class is based in Berkley it only makes sense that the timezone for the class is PST. I formally request that the submission time be changed to PST.
SecondChildUserIdTAG: 105209
SecondChildUserNameTAG: bridavis
SecondChildCreateTimeTAG: 2013-02-28T02:01:57Z
SecondChildVoteTAG: 0
IndexTAG: 1964
TitleTAG: No submission button
Same issue here.
UserIdTAG: 1318378
UserNameTAG: LuisQuiros
CreateTimeTAG: 2013-02-28T01:25:31Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:19:32Z
FirstChildVoteTAG: 0
IndexTAG: 1965
TitleTAG: deadline timings
staff, please note that on conversion of EST or PST to my time Zone ,i still haVE time to submit those assignments.it is unfair that this is in GMT, as all other courses run acc. to either of the above mentioned.please inform if you have some other policy , well in advance and through proper channels.
thanks.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T01:24:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. This is explained clearly in the Course Policies. Did you read it?
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:20:02Z
FirstChildVoteTAG: 0
IndexTAG: 1966
TitleTAG: Can submit either??
Same here. it's only 20h EST
UserIdTAG: 1301493
UserNameTAG: MattyA
CreateTimeTAG: 2013-02-28T01:23:52Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:20:08Z
FirstChildVoteTAG: 0
IndexTAG: 1967
TitleTAG: STAFF - Time Extension
There was some confusion on the time zone. Can we get an extension on the submission date for 1st week. Enjoying the course and don't...
UserIdTAG: 1325347
UserNameTAG: FToronto
CreateTimeTAG: 2013-02-28T01:23:14Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1968
TitleTAG: Couldn't complete any assignments in week 1 - Technical problems and math issues
please someone contact me. I'm having trouble since i couldn't turn in week 1 and now cause of stressing messing up on problems. need assistance please.
Amy
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-02-28T01:22:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Just breathe, do the problems on a piece of paper and check the solutions to last week's graded exercises when they are posted tomorrow. If everybody asked to be contacted, staff would have to attend to 47000 people personally. This is not a paid course so you have to do more stuff on your own. Use the practice exercises and the text (which has more practice questions) and remember that your two lowest scores will be dropped! So you're in luck.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:27:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi aimster,
I'm always happy to help students. First, please don't stress about this week's assignments. We drop the lowest two scores anyway. Could you give me some sense of what kinds of "math issues" you faced while trying to do the problems?
You may find the discussion forums very helpful when you have questions about a specific topic. Often, others have had that same question, and you'll find plenty of discussion even before you ask the question. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T01:31:59Z
FirstChildVoteTAG: 0
FirstChildTAG: edx fails its first test. Would it have been too difficult for you to write "graded exercises due February 27 23:30 GMT"? The answer is no. Do better next time by writing software that's obvious and easy-to-use.
FirstChildUserIdTAG: 1291953
FirstChildUserNameTAG: bio52
FirstChildCreateTimeTAG: 2013-02-28T02:27:59Z
FirstChildVoteTAG: 0
IndexTAG: 1969
TitleTAG: Time Extension
STAFF - There was some confusion on the time zone. Can we get an extension on the submission date for 1st week. Enjoying the course and don't want to drop it.
UserIdTAG: 1325347
UserNameTAG: FToronto
CreateTimeTAG: 2013-02-28T01:22:26Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Same here. Please I thought it was the GMT
FirstChildUserIdTAG: 296976
FirstChildUserNameTAG: PriyaS
FirstChildCreateTimeTAG: 2013-02-28T01:24:52Z
FirstChildVoteTAG: 0
IndexTAG: 1970
TitleTAG: [Staff] Confusing Times.
Most of edx courses are timed in EST and I'm taking another course by Berkeley - it is timed by Pacific Standard Time. It would be better to have uniform time across all of edx courses. Keep times in US, preferably EST, as even international students expect that kind of convention.
Thanks.
UserIdTAG: 982840
UserNameTAG: AhadAlex
CreateTimeTAG: 2013-02-28T01:22:13Z
VoteTAG: 8
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: > as even international students expect that kind of convention.
Actually, they don't. Just read the various posts where students are outraged because their *local* time was not 23.30 27th Feb when submissions closed.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:44:53Z
FirstChildVoteTAG: 0
SecondChildTAG: Well maybe they are new to MOOCs. Because usually all the MOOCs provided through a US based website have deadlines in EST.
SecondChildUserIdTAG: 982840
SecondChildUserNameTAG: AhadAlex
SecondChildCreateTimeTAG: 2013-02-28T02:02:09Z
SecondChildVoteTAG: 0
FirstChildTAG: They should use a countdown, that would be universal!
FirstChildUserIdTAG: 265899
FirstChildUserNameTAG: killmess
FirstChildCreateTimeTAG: 2013-03-04T02:19:32Z
FirstChildVoteTAG: 1
IndexTAG: 1971
TitleTAG: Had no idea they were utilizing GMT
Unfortunately, I could not submit the assignments on time. I did not know that this would be the time standard used when setting deadlines for assignments. I'm sure it is posted somewhere on the site, but I went with the assumption that the time shown for the deadline was in EST. My mistake.
UserIdTAG: 1040754
UserNameTAG: FabyanEstrada
CreateTimeTAG: 2013-02-28T01:21:06Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I am wondering why they would use GMT. I do not understand the logic behind this.
FirstChildUserIdTAG: 453550
FirstChildUserNameTAG: DebbieSmith
FirstChildCreateTimeTAG: 2013-02-28T01:25:13Z
FirstChildVoteTAG: 1
IndexTAG: 1972
TitleTAG: Unable to submit the answers to the excercise
Same issue, Mexico UTC -06:00, 07:19 PM. Unable to submit my answers, tried on Chrome and IE.
UserIdTAG: 1318378
UserNameTAG: LuisQuiros
CreateTimeTAG: 2013-02-28T01:20:18Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I think you were almost two hours late with your attempt to submit answers. The timezone is GMT.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:41:50Z
FirstChildVoteTAG: 0
IndexTAG: 1973
TitleTAG: Submissions buttons
The submission button is not appearing in the exams!!!!!
UserIdTAG: 981650
UserNameTAG: IsabelBeatriz
CreateTimeTAG: 2013-02-28T01:18:34Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You are past the submission time which is 11:30 GMT.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:42:08Z
FirstChildVoteTAG: 0
IndexTAG: 1974
TitleTAG: UNABLE TO SUBMIT
I can't check or submit! let me guess, we are using GMT Time?
UserIdTAG: 952989
UserNameTAG: suo3
CreateTimeTAG: 2013-02-28T01:18:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1975
TitleTAG: I am not able to submit solutions. Is deadline over?
I have ticked answers but could not find submit button. Can somebody help me please?
UserIdTAG: 1151403
UserNameTAG: Anki11
CreateTimeTAG: 2013-02-28T01:16:13Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:16:38Z
FirstChildVoteTAG: 1
SecondChildTAG: Well said,
Flloyd
SecondChildUserIdTAG: 226651
SecondChildUserNameTAG: flloyd
SecondChildCreateTimeTAG: 2013-02-28T01:24:46Z
SecondChildVoteTAG: 0
FirstChildTAG: same here....
FirstChildUserIdTAG: 466873
FirstChildUserNameTAG: pipicuit
FirstChildCreateTimeTAG: 2013-02-28T01:18:31Z
FirstChildVoteTAG: 1
SecondChildTAG: I also am experiencing the same issue.
SecondChildUserIdTAG: 1319699
SecondChildUserNameTAG: MattBr
SecondChildCreateTimeTAG: 2013-02-28T01:40:56Z
SecondChildVoteTAG: 0
SecondChildTAG: now, what we should to do?
SecondChildUserIdTAG: 920670
SecondChildUserNameTAG: andersuescun
SecondChildCreateTimeTAG: 2013-02-28T01:48:23Z
SecondChildVoteTAG: 0
FirstChildTAG: I would heartily appreciate if course staff can avoid including marks from this exercise. As many student were not aware that this time 23.30 was not boston time but GMT, many of us were not able to submit assignments. Please consider apologies for not submitting assignment for week 1.
FirstChildUserIdTAG: 1151403
FirstChildUserNameTAG: Anki11
FirstChildCreateTimeTAG: 2013-02-28T01:23:21Z
FirstChildVoteTAG: 0
IndexTAG: 1976
TitleTAG: Due date/time GMT based not sufficiently informed
Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
UserIdTAG: 609816
UserNameTAG: Oscar7000
CreateTimeTAG: 2013-02-28T01:15:57Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You could find the due date under the general course informations, click it and read the policies and requirements and you can eventually read the standard time in grading section, hope it might be helpful..
FirstChildUserIdTAG: 1274748
FirstChildUserNameTAG: kusumawati
FirstChildCreateTimeTAG: 2013-02-28T01:39:29Z
FirstChildVoteTAG: 2
IndexTAG: 1977
TitleTAG: can not submit
I am in ny. And the time is 20:14 now, why i can not submit the homework?
UserIdTAG: 1111358
UserNameTAG: gfbbq
CreateTimeTAG: 2013-02-28T01:15:19Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:17:09Z
FirstChildVoteTAG: 0
IndexTAG: 1978
TitleTAG: Can't submit my work from the Netherlands
It is still CET not USA time so I still have time but submit button is missing. What do I do now?
UserIdTAG: 1226732
UserNameTAG: Mastonefi2013
CreateTimeTAG: 2013-02-28T01:14:12Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:17:02Z
FirstChildVoteTAG: 0
IndexTAG: 1979
TitleTAG: Once again, I can't submit
i
It's 2.12 a.m. Spain Time (GMT+1) so we're 8-9 hours ahead of U.S.West Coast Time, have you closed submissions so early?
UserIdTAG: 279971
UserNameTAG: nostramo
CreateTimeTAG: 2013-02-28T01:14:04Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Is the time line GMT or East Coast or West Coast ?
Time is over for GMT but not for EST or PST.
FirstChildUserIdTAG: 982840
FirstChildUserNameTAG: AhadAlex
FirstChildCreateTimeTAG: 2013-02-28T01:16:51Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:17:21Z
FirstChildVoteTAG: 1
IndexTAG: 1980
TitleTAG: Cut off time
Got caught by the "GMT" ending time. You've got my address, your system should be able to calculate when it is 23:30 in my time zone.
UserIdTAG: 1324450
UserNameTAG: Busathe
CreateTimeTAG: 2013-02-28T01:13:21Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Is deadline given in GMT or Pacific Standard Time ?
FirstChildUserIdTAG: 982840
FirstChildUserNameTAG: AhadAlex
FirstChildCreateTimeTAG: 2013-02-28T01:17:22Z
FirstChildVoteTAG: 0
SecondChildTAG: GMT
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-28T01:21:18Z
SecondChildVoteTAG: 0
IndexTAG: 1981
TitleTAG: My biggest takeaway from week one?
Precision - accuracy and check things out. GMT - guessed it and was a couple hours off
UserIdTAG: 504031
UserNameTAG: Lindy7
CreateTimeTAG: 2013-02-28T01:12:47Z
VoteTAG: 7
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Me Too, I wasn't done submitting Exercise 3!
FirstChildUserIdTAG: 4612
FirstChildUserNameTAG: Susnaj
FirstChildCreateTimeTAG: 2013-02-28T01:35:52Z
FirstChildVoteTAG: 0
IndexTAG: 1982
TitleTAG: Can't submit answers
Hi there is 3 of us working on this course, it is 20:12 in Colombia , South America, and we cannot submit our answers!!!
So sad we stayed after work just to do this, and now we can't! :'(
UserIdTAG: 745313
UserNameTAG: catalecacheux
CreateTimeTAG: 2013-02-28T01:12:30Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: It is 20:14pm EST, and I do not know how to submit exercise set 2 and 3. I had no problems with set 1, but now there is no active button to submit
FirstChildUserIdTAG: 207743
FirstChildUserNameTAG: Evoyan
FirstChildCreateTimeTAG: 2013-02-28T01:15:12Z
FirstChildVoteTAG: 0
FirstChildTAG: The deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:23:48Z
FirstChildVoteTAG: 0
IndexTAG: 1983
TitleTAG: lecture vs book
are we tested on material not in lecture?
it looks like we are. I think that should have been spelled out beforehand.
UserIdTAG: 471645
UserNameTAG: FredFriedman
CreateTimeTAG: 2013-02-28T01:12:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1984
TitleTAG: Submit the exercise
Cant submit! And know?
UserIdTAG: 1292588
UserNameTAG: Alexrlopes
CreateTimeTAG: 2013-02-28T01:12:07Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: We are all having the same problem.
FirstChildUserIdTAG: 453550
FirstChildUserNameTAG: DebbieSmith
FirstChildCreateTimeTAG: 2013-02-28T01:21:38Z
FirstChildVoteTAG: 0
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:42:00Z
FirstChildVoteTAG: 0
IndexTAG: 1985
TitleTAG: Mistake in submission process exercise 1
By mistake I understood that I had to submit each exercise partially, now I finished the exercise and I cannot post the rest of my answers. Waht can I do to correct that? Thanks in advance.
Jose
UserIdTAG: 1020704
UserNameTAG: JoseAC
CreateTimeTAG: 2013-02-28T01:11:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 1986
TitleTAG: I can not submit my answer
The submit button is missing
UserIdTAG: 895085
UserNameTAG: GreiceLeite
CreateTimeTAG: 2013-02-28T01:10:18Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was 11:30 GMT. Too late to submit.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T02:42:12Z
FirstChildVoteTAG: 0
IndexTAG: 1987
TitleTAG: I can´t submitemy answers
Buttons desappears...I´m in Brazil (Belém)and here it´s 22:00h. What can I do????
UserIdTAG: 957832
UserNameTAG: isaac121
CreateTimeTAG: 2013-02-28T01:09:03Z
VoteTAG: 7
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: olá Isaac, tudo bom?
este site tem os fusos horários
http://www.horadomundo.com/
FirstChildUserIdTAG: 1050962
FirstChildUserNameTAG: raquelpestana
FirstChildCreateTimeTAG: 2013-02-28T01:11:26Z
FirstChildVoteTAG: 0
SecondChildTAG: me too...
SecondChildUserIdTAG: 1277371
SecondChildUserNameTAG: nataliasxcosta
SecondChildCreateTimeTAG: 2013-02-28T01:13:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Hello, I'm having the same problem with Homework #2. I can't submit more than 50% of my answers!! I'm in the US and I lost my internet connection. Please, can we get help!! They're going to be done pretty soon. I haven't got to the third section but I'll try that now
FirstChildUserIdTAG: 1008454
FirstChildUserNameTAG: clau_lima
FirstChildCreateTimeTAG: 2013-02-28T01:13:42Z
FirstChildVoteTAG: 0
IndexTAG: 1988
TitleTAG: GMT
Pra quem é brasileiro: o horário oficial do curso é GMT. O GMT de Brasília é - 3:00, ou seja, 23:30 - 3h = 20:30, horário ofinal para respostas. Infelizmente aprendi tarde.
UserIdTAG: 1031814
UserNameTAG: Marivaldo
CreateTimeTAG: 2013-02-28T01:08:43Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 1989
TitleTAG: Also unable to submit
Have also spent a lot of time especially on the third set. Did them out long hand only to find no submit button. Assumed 23:00 local time Berkeley. HELP
UserIdTAG: 940205
UserNameTAG: PJButler
CreateTimeTAG: 2013-02-28T01:07:56Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: It's only 17:12 local time in Berkeley.
FirstChildUserIdTAG: 1311471
FirstChildUserNameTAG: kdeppe
FirstChildCreateTimeTAG: 2013-02-28T01:13:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Also? So you have read other posts. So why start another one?
The course policies, which we all read didn't we?, tells you GMT.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:14:07Z
FirstChildVoteTAG: 0
IndexTAG: 1990
TitleTAG: I can not submit my answers, please help.
The check answer and submit buttons that are usually there, are missing.
UserIdTAG: 662184
UserNameTAG: VCampa
CreateTimeTAG: 2013-02-28T01:07:36Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Mexico UTC -06:00, 07:26 PM
Is there any other way we could submit answers?
FirstChildUserIdTAG: 662184
FirstChildUserNameTAG: VCampa
FirstChildCreateTimeTAG: 2013-02-28T01:27:49Z
FirstChildVoteTAG: 1
IndexTAG: 1991
TitleTAG: I can't enter answers
Hi!
I can enter the answers as response boxes have disappeared and it's only about 8pm EST!!!
Please help!
UserIdTAG: 1118856
UserNameTAG: ABhardwaj
CreateTimeTAG: 2013-02-28T01:06:47Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Read the forum.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:13:08Z
FirstChildVoteTAG: 0
IndexTAG: 1992
TitleTAG: I can´t believe it
I can´t submit my answers and it´s not time yet! what happens?
UserIdTAG: 924068
UserNameTAG: begodr
CreateTimeTAG: 2013-02-28T01:03:47Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: same here!
FirstChildUserIdTAG: 952989
FirstChildUserNameTAG: suo3
FirstChildCreateTimeTAG: 2013-02-28T01:07:27Z
FirstChildVoteTAG: 0
FirstChildTAG: I repeat. Did you read the course policy document. The one that told you the timezone was GMT?
I gather not. And given the dozens of repeat posts I can safely assume none of you have read the How To Use the Forums document either.
University admission requirements. they are a very good thing. hic
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:09:27Z
FirstChildVoteTAG: 0
IndexTAG: 1993
TitleTAG: unable to submit.confused :/
I went through all of the homework thinking there was a submit button at the end. However, no submit button. I am in the USA and thought expiration time was before 11:30 ET USA. Please allow submission and clarify the due dates/times.
UserIdTAG: 1202785
UserNameTAG: sjmadden
CreateTimeTAG: 2013-02-28T01:01:57Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I'm with you.
FirstChildUserIdTAG: 1194221
FirstChildUserNameTAG: Frank032061
FirstChildCreateTimeTAG: 2013-02-28T01:04:11Z
FirstChildVoteTAG: 0
FirstChildTAG: Did anyone think to read the course policy?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:05:53Z
FirstChildVoteTAG: 0
SecondChildTAG: I did. I forgot about GMT and just assumed that time were changed for the person looking at it. Silly, I know. My computer manages to do it somehow. However, I don't think it's too much to ask for GMT to be after the time just as a reminder. That is a simple fix that would satisfy most everyone. I actually finished the problems and was just looking over them and so could have submitted them had I realized it. Oh well.
SecondChildUserIdTAG: 905318
SecondChildUserNameTAG: kamili
SecondChildCreateTimeTAG: 2013-02-28T01:11:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Seriously, your right. But it's too much of an important matter to be put in a sub sub sub topic named Gradings!!! I thought was about how grading works,like grades and stuff. I didn't look enough properly to see that within the grading stuff there was a little GMT matter.
Plus I'm taking another MITx course and it's sepcified rather clearly and in Bold that due time is Boston time....
I agree with you, but an important matter has to be exposed as an important matter and not drawn in the middle of other informations
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-02-28T01:13:21Z
SecondChildVoteTAG: 0
IndexTAG: 1994
TitleTAG: Done
I can not publish the answers! How do I?
UserIdTAG: 1283250
UserNameTAG: anneduarte
CreateTimeTAG: 2013-02-28T01:01:56Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: you don't...
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-28T01:06:39Z
FirstChildVoteTAG: 1
IndexTAG: 1995
TitleTAG: Submit button deactivated too early
I think the exercise buttons were deactivated too soon. The check and save buttons failed to work and were then removed from the website.
Will the course administrators extend the deadline?
Thanks.
UserIdTAG: 952263
UserNameTAG: ClarissaK
CreateTimeTAG: 2013-02-28T01:01:52Z
VoteTAG: 8
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: seriously !! this is not what i expected.
i was working on the sums !
FirstChildUserIdTAG: 977503
FirstChildUserNameTAG: ratanK
FirstChildCreateTimeTAG: 2013-02-28T01:04:54Z
FirstChildVoteTAG: 0
IndexTAG: 1996
TitleTAG: Problem SET 3 expering before deadline!
February 27, 2013 - 20:54 pm
Dear Stat2.1x team,
I just came back from work to finish my problems sets, but it happened that the submissions were closed. My time zone is "Atlantic Time Zone" -now 20:54 pm-. On the other hand California´s time zone is "Pacific Standard Time" -now 16:54 pm-. The expiring time was set at 23:30 pm. I suppose you are using your local time.
We never had this problem while taking MITx courses. Due dates and times where set according to Boston time. Nonetheless, time zone was never specified as I now recall.
Please address this issue, cause is having a detrimental effect on my grade, not reflecting my true learning. I hope this is not happening to anyone else.
Looking forward to hear about a positive and affirmative action,
Best, Oscar7000
UserIdTAG: 609816
UserNameTAG: Oscar7000
CreateTimeTAG: 2013-02-28T01:01:02Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: oh boy! happening to loads of students...... due time is GMT time I live in Montpellier/France and it's 2:45 a.m here...
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-28T01:06:03Z
FirstChildVoteTAG: 1
SecondChildTAG: Hello from Colombia! I have a very similar situation. I´ve completed my exercise (there hours before the deadline in my time) but I cannot find the submission option. It´s my first time in this type of course and I didn´t even consider that time difference would be an issue, honestly!! So, what would happen with us?
Thanks and sorry for this convenient.
SecondChildUserIdTAG: 1214502
SecondChildUserNameTAG: monicagieyes
SecondChildCreateTimeTAG: 2013-02-28T01:25:21Z
SecondChildVoteTAG: 0
SecondChildTAG: ups!!! I meant three hours before...
SecondChildUserIdTAG: 1214502
SecondChildUserNameTAG: monicagieyes
SecondChildCreateTimeTAG: 2013-02-28T01:25:58Z
SecondChildVoteTAG: 0
FirstChildTAG: > oh boy! happening to loads of students
Only to those who didn't bother reading the documents
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:10:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
SecondChildUserIdTAG: 609816
SecondChildUserNameTAG: Oscar7000
SecondChildCreateTimeTAG: 2013-02-28T01:18:42Z
SecondChildVoteTAG: 0
IndexTAG: 1997
TitleTAG: feed back for Quizz
it is now 8:49 pm where I am .I have just completed set 1 and decided to submit but it seems like the check buttons are static... I am not sure if I missed the deadline
UserIdTAG: 418570
UserNameTAG: frey79
CreateTimeTAG: 2013-02-28T00:59:55Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes you've missed, because the deadline time is in GMT. In my opinion, it's big edX fault. It should be clearly written that it's in GMT - when there's no info about timezone, people assume that time is in their timezone (it's easy to check which timezone user is in)
FirstChildUserIdTAG: 1314589
FirstChildUserNameTAG: Sebaall
FirstChildCreateTimeTAG: 2013-02-28T01:16:59Z
FirstChildVoteTAG: 0
IndexTAG: 1998
TitleTAG: Submission time
Hello everyone, i reside in the US State of Virginia which uses Eastern Time. It is now 07:58 PM so i am trying to finish the home work but i do not see the save and submission button. Is there a problem or has the time passed?
Regards,
Noel Watson
UserIdTAG: 174302
UserNameTAG: noelsfwatson
CreateTimeTAG: 2013-02-28T00:59:36Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: i can see the save and submission button .. but its not working !
FirstChildUserIdTAG: 977503
FirstChildUserNameTAG: ratanK
FirstChildCreateTimeTAG: 2013-02-28T01:02:07Z
FirstChildVoteTAG: 1
FirstChildTAG: just like me....Sorry guys, due time is GMT time.....So we are screwed
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-28T01:03:14Z
FirstChildVoteTAG: 1
SecondChildTAG: Same here in Atlanta
SecondChildUserIdTAG: 1194221
SecondChildUserNameTAG: Frank032061
SecondChildCreateTimeTAG: 2013-02-28T01:09:21Z
SecondChildVoteTAG: 0
FirstChildTAG: Sigh. I fear for the future of the planet.
GMT people. As you would have read in the course policy document.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:15:06Z
FirstChildVoteTAG: 0
SecondChildTAG: Well maybe they should LIST GMT on this page too. Ridiculous.
SecondChildUserIdTAG: 1299121
SecondChildUserNameTAG: Limpy
SecondChildCreateTimeTAG: 2013-02-28T02:02:07Z
SecondChildVoteTAG: 0
IndexTAG: 1999
TitleTAG: Problems with assignment
I cant make the assignment. Something does not allowed me to submit and save?
UserIdTAG: 342283
UserNameTAG: Nacho7777
CreateTimeTAG: 2013-02-28T00:59:27Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I have the same I problem with exercise set 2. Now I've lost my answers
FirstChildUserIdTAG: 246767
FirstChildUserNameTAG: stormtrooper76
FirstChildCreateTimeTAG: 2013-02-28T01:01:23Z
FirstChildVoteTAG: 1
SecondChildTAG: Hi, I still have 6 hour according to my are but I can't find the save and submit button, what's wrong?
SecondChildUserIdTAG: 833176
SecondChildUserNameTAG: kholoudsamir
SecondChildCreateTimeTAG: 2013-02-28T02:08:32Z
SecondChildVoteTAG: 0
FirstChildTAG: I have the same problem also
FirstChildUserIdTAG: 930837
FirstChildUserNameTAG: kamieaa
FirstChildCreateTimeTAG: 2013-02-28T01:06:06Z
FirstChildVoteTAG: 1
IndexTAG: 2000
TitleTAG: Really!!
It NEVER said GMT you have to be kidding!!!!
UserIdTAG: 1271736
UserNameTAG: sushigupta
CreateTimeTAG: 2013-02-28T00:57:58Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Oh yes it did.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:10:49Z
FirstChildVoteTAG: 0
IndexTAG: 2001
TitleTAG: Should have checked GMT - wow
Well going through them anyway. Sad.
UserIdTAG: 504031
UserNameTAG: Lindy7
CreateTimeTAG: 2013-02-28T00:57:40Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Guess I'll be finishing a day earlier from now on
FirstChildUserIdTAG: 504031
FirstChildUserNameTAG: Lindy7
FirstChildCreateTimeTAG: 2013-02-28T01:06:22Z
FirstChildVoteTAG: 0
IndexTAG: 2002
TitleTAG: Problem help
Please let us do a re-do or extend the time!!!! Come on!
UserIdTAG: 1271736
UserNameTAG: sushigupta
CreateTimeTAG: 2013-02-28T00:56:58Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I would very much appreciate that too.
FirstChildUserIdTAG: 1194221
FirstChildUserNameTAG: Frank032061
FirstChildCreateTimeTAG: 2013-02-28T01:04:52Z
FirstChildVoteTAG: 1
IndexTAG: 2003
TitleTAG: REALLY UPSET AT THE LACK OF CLARIFICATION
Considering how many people sign up for these course, it would probably be a really good idea for the due date and time to be REITERATED and clarified more purposefully. I'm pissed that my grade in this class is now affected by the fact that they write GMT so I am thinking its based on American Mountain time! I mean this is an American school based course. Berkley is American! I'm pissed that this little clock states Feb 27 23:30 but there is NO indication that is based on LONDON GMT time! Seriously GUYS COME ON! EdX you have got to be smarter than this. With 40K students signing up from all over the world you don't think maybe you need to be crystal clear on time! I glanced through the schedule and pre-req's and I saw GMT, and I mean think about it, if Berkley is offering this course, I would expect it at the very least to be on PST? My other class is on EST! I would NEVER have guessed this was on GMT for LONDON! And NOT ONCE at any point did the practice set or the lectures state at the top of them, "hey remember this is due on LONDON GMT time NOT AMERICAN TIME!" Seriously! Especially when this is offered by an AMERICAN school I would expect it to be graded on american time, and if not for the teachers to make it crystal clear, and drill it in that it's not American GMT time! I now have missed out on submitted an entire week's worth of HW that would have taken me literally 5 minutes to complete. Really disappointing Berkley!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T00:56:06Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I thought the due time was set for East Coast Standard time.
FirstChildUserIdTAG: 512209
FirstChildUserNameTAG: somethingfiesty
FirstChildCreateTimeTAG: 2013-02-28T01:13:52Z
FirstChildVoteTAG: 1
SecondChildTAG: GTM my friend, and not sufficiently informed.
SecondChildUserIdTAG: 609816
SecondChildUserNameTAG: Oscar7000
SecondChildCreateTimeTAG: 2013-02-28T01:21:57Z
SecondChildVoteTAG: 0
SecondChildTAG: I thought the same thing East Coast so i was trying to get done by 12:00 wednesday
SecondChildUserIdTAG: 411228
SecondChildUserNameTAG: aimster
SecondChildCreateTimeTAG: 2013-02-28T04:29:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precedent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:20:40Z
FirstChildVoteTAG: 1
SecondChildTAG: It was clearly mentioned GMT in the courseware.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-28T02:11:21Z
SecondChildVoteTAG: 0
IndexTAG: 2004
TitleTAG: Website Problems
They need to improve this site. There are too many issues, it is worse when we need to submit work and we can't!
UserIdTAG: 1223452
UserNameTAG: tflavien101
CreateTimeTAG: 2013-02-28T00:55:58Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2005
TitleTAG: What is going on?
It is 9pm in Brasília (Brazil) and I can not check my answers. What time it have finished? .
UserIdTAG: 1031814
UserNameTAG: Marivaldo
CreateTimeTAG: 2013-02-28T00:54:59Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Exactly. What is going on? Why haven't people read the course policies?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:07:36Z
FirstChildVoteTAG: 0
IndexTAG: 2006
TitleTAG: TIME
I Can't submit but it's only 19:50 EST!!!! It said 23:30! What does it mean???
UserIdTAG: 1271736
UserNameTAG: sushigupta
CreateTimeTAG: 2013-02-28T00:54:06Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It means that like most students-including me- you didn't see the little thing in coursware:requirements and policies:Gradings:
GMT not CST nor EST as most courses....
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-28T00:58:05Z
FirstChildVoteTAG: 2
IndexTAG: 2007
TitleTAG: Unable to Submit Answers With Time Still Available
Okay, I am at a loss. Today is February 27 at 7:51 p.m. I still have time to submit my answers for the last two sets of questions, but I cannot. Why? What needs to be done to complete the exams and submit timely?
UserIdTAG: 1196
UserNameTAG: tebooker21
CreateTimeTAG: 2013-02-28T00:54:02Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: go to Deadline, or GMT post by searching,though I gave you the griggin awful answer.....
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-28T01:00:18Z
FirstChildVoteTAG: 0
FirstChildTAG: I am having the same issue, i do not see the save and submission button. I reside in the US State of Virginia which uses Eastern Time. It is now 08:00 PM.
FirstChildUserIdTAG: 174302
FirstChildUserNameTAG: noelsfwatson
FirstChildCreateTimeTAG: 2013-02-28T01:00:55Z
FirstChildVoteTAG: 2
FirstChildTAG: unable to submit my answers also
FirstChildUserIdTAG: 983113
FirstChildUserNameTAG: miknik40
FirstChildCreateTimeTAG: 2013-02-28T01:10:54Z
FirstChildVoteTAG: 1
IndexTAG: 2008
TitleTAG: WHY????
Why does UC Berkley run to GMT????
Previous EdX courses have run to local time deadlines!
This now nullifies the point of doing the rest of the course as without an entire weeks scores makes it more difficult to achieve passing grade
UserIdTAG: 484057
UserNameTAG: zchoudhury
CreateTimeTAG: 2013-02-28T00:53:47Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: which is 35 per cent and on top of that two assignments with the lowest grade are excluded from calculating your final score. You for sure were aware of it, weren't you?
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T01:05:18Z
FirstChildVoteTAG: 0
FirstChildTAG: > This now nullifies the point of doing the rest of the course
So the only reason to be here is to get a certificate? Not to learn? And as Mzvd said, 35%.
If you think missing these 3 submissions (only 1 of which will count if you do all the others) will not allow you to achieve 35% then maybe you should throw it in.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T01:12:52Z
FirstChildVoteTAG: 0
IndexTAG: 2009
TitleTAG: Deadline confusion
I could only do exercise set 1. Now the save and check buttons are gone. I thought we still have time. Please specify clearly the time zone we should follow. I was following the California time. I wish to submit my answers because I really worked hard for it. :(
Thanks
UserIdTAG: 1164674
UserNameTAG: nidajafri
CreateTimeTAG: 2013-02-28T00:52:50Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I also assumed that the deadline was PST. Tried to submit my answers @ 7:30 EST but was unable to.
FirstChildUserIdTAG: 893938
FirstChildUserNameTAG: mdeebold
FirstChildCreateTimeTAG: 2013-02-28T00:57:16Z
FirstChildVoteTAG: 1
SecondChildTAG: Due to course documents the deadline was GMT. I forgot about it and I was sure about PST. Now I have only 1st ES. But two (the worse) of ESs will be dropped in the end so I have nothing to worry about.
To my mind, they should write GMT next to the due date. But that is only my opinion.
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T01:06:21Z
SecondChildVoteTAG: 0
FirstChildTAG: I've done the problem 1 but the buttom to check the answers weren't there. I supposed if it was California time regarding my zone we had a lot of time to complete the tests.
FirstChildUserIdTAG: 84713
FirstChildUserNameTAG: boldrini
FirstChildCreateTimeTAG: 2013-02-28T00:58:21Z
FirstChildVoteTAG: 0
IndexTAG: 2010
TitleTAG: Deadline
I dont get why I can't check my answers since the deadline hasn't be reached yet.
UserIdTAG: 1144890
UserNameTAG: ltavares
CreateTimeTAG: 2013-02-28T00:52:26Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2011
TitleTAG: Missing Button
It was noted that the assignments were due at 11:30,yet the buttons for submission disappeared at approximately 7pm.
UserIdTAG: 485000
UserNameTAG: EmiliaP
CreateTimeTAG: 2013-02-28T00:52:02Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Keyword: GMT
FirstChildUserIdTAG: 1314589
FirstChildUserNameTAG: Sebaall
FirstChildCreateTimeTAG: 2013-02-28T00:55:54Z
FirstChildVoteTAG: 0
SecondChildTAG: its only 8 pm here...what is wrong??? i am unable to submit my ex. set 3 ...
SecondChildUserIdTAG: 1036551
SecondChildUserNameTAG: Geetagrg
SecondChildCreateTimeTAG: 2013-02-28T01:04:37Z
SecondChildVoteTAG: 0
SecondChildTAG: but in Greenwich is about 1am. I'm lucky, because in Poland is GMT+1, so my 23.30 was one hour before GMT and I've done all Exercises before the deadline
SecondChildUserIdTAG: 1314589
SecondChildUserNameTAG: Sebaall
SecondChildCreateTimeTAG: 2013-02-28T01:10:51Z
SecondChildVoteTAG: 0
IndexTAG: 2012
TitleTAG: GMT?!
Is this true?!
Are you shitting me?!
UserIdTAG: 1186397
UserNameTAG: larryweidman
CreateTimeTAG: 2013-02-28T00:51:32Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: What is wrong with it?
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T00:53:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Stat2.1x Team,
Due date/times expiring according to GTM, but precent edX courses had expired using local times. MITx courses emphasized all the time that they were using Boston Time for the problem sets deadlines.
I know we are responsible for reading the material and course information exhaustively, but actually primacy effects in perception are a trap (a measurement error derived from a problem of content design and presentation), so I'm now reading that apart from me, some of my classmates are having the same problem.
I really hope you could understand that is a **shared responsibility, for us to read, and for you to inform with greater power.****
I hope you could take a positive action toward this problem,
Oscar7000
FirstChildUserIdTAG: 609816
FirstChildUserNameTAG: Oscar7000
FirstChildCreateTimeTAG: 2013-02-28T01:19:04Z
FirstChildVoteTAG: 0
IndexTAG: 2013
TitleTAG: TO STAFF about the time
It seems that many people haven't realized that times are in GMT, although it is stated in the course policy. Is it possible that just for this first assignment deadline is prolonged for 24 hours? It would be a boost in the moral for the people as everyone likes to start any kind of work in a nice way. In the students defense I can only say that many other EDX courses have California time as official time for due dates.
Thanks in advance.
Marko
UserIdTAG: 302329
UserNameTAG: markomarkovic
CreateTimeTAG: 2013-02-28T00:51:25Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2014
TitleTAG: Can't Submit either and it's only 19:50 EST on 2/27/2013
Can we get a do-over here?
UserIdTAG: 423206
UserNameTAG: yperil
CreateTimeTAG: 2013-02-28T00:51:19Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes; tried to come back and use a second submission for question 1 and there was no submit button available.
FirstChildUserIdTAG: 16539
FirstChildUserNameTAG: islandbirder
FirstChildCreateTimeTAG: 2013-02-28T01:26:50Z
FirstChildVoteTAG: 0
IndexTAG: 2015
TitleTAG: mariaeugenia
Hi
Today I have learn about my mistakes
UserIdTAG: 1208968
UserNameTAG: MaEugenia
CreateTimeTAG: 2013-02-28T00:50:44Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2016
TitleTAG: Assignment Deadlines
TO: STAFF
I was confused about deadline 23:30 GMT, and thought I had until 11:30 tonight to submit my answers. I was at a conference and could not work on the problems until Tuesday. Today I went to review the lecture material and try to work assignment 3 problems, but now I understand I have missed the deadline. So I now have -20 points. In section 2 I only scored 8 correct out of 20. Being so far behind already, should I drop out? I know there is no way now that you will accept any answers to section 3, so I don't even have a chance to try to get a decent score. I wish you had clearly explained the deadline times instead of just stating 23:30 GMT. I think I am not the only one who did not know exactly what that meant.
UserIdTAG: 868031
UserNameTAG: CaliforniaViv
CreateTimeTAG: 2013-02-28T00:50:14Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: If you have read the course information you would know "our two lowest Exercise Set scores will not be used in the calculation of your overall grade. "
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T00:56:07Z
FirstChildVoteTAG: 0
IndexTAG: 2017
TitleTAG: Unable to post
I too am unable to submit my answers!
UserIdTAG: 893938
UserNameTAG: mdeebold
CreateTimeTAG: 2013-02-28T00:50:03Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I cannot submit my answer. The Final check box and save box are not under my questions.
FirstChildUserIdTAG: 1223452
FirstChildUserNameTAG: tflavien101
FirstChildCreateTimeTAG: 2013-02-28T00:52:35Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too. The buttom to submit the asnwer is not appearing at the end of the tests. Can anybody confirm that? I am using the Chrome browser on this course. I don't know if someone using another browser is having the same trouble
FirstChildUserIdTAG: 84713
FirstChildUserNameTAG: boldrini
FirstChildCreateTimeTAG: 2013-02-28T00:54:13Z
FirstChildVoteTAG: 0
IndexTAG: 2018
TitleTAG: S.M
I can't submit my answer, what should i do??
UserIdTAG: 984277
UserNameTAG: saramemon45
CreateTimeTAG: 2013-02-28T00:49:13Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2019
TitleTAG: Deadline issue
Had same issue with deadline, assumed it was PST...would greatly appreciate it if the professors gave an extension for the first batch of assignments since there appears to be a lot of confusion on the discussion forum re time zones.
UserIdTAG: 251751
UserNameTAG: mtl278
CreateTimeTAG: 2013-02-28T00:48:41Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2020
TitleTAG: Can't save or submit
I'm having the same problem as several other people. No save or submit buttons for Ex 2 or 3.
UserIdTAG: 1206221
UserNameTAG: rchestnutt
CreateTimeTAG: 2013-02-28T00:47:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2021
TitleTAG: Did not submit exercise set 2 or 3
Dear Prof,
I was unable to submit my answers to set 2 and 3 as I made an error with time zone differences. What happens now? Am I able to re-submit or will I be penalised? Will I be able to pass the course? It seems like there are a few other people with similar queries, would it be possible to re-open the exercises for another day or two? Which time zone are you working in?
Regards,
Emma
UserIdTAG: 1299871
UserNameTAG: ELD
CreateTimeTAG: 2013-02-28T00:47:12Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I am in the same boat here, and I'm hopeful that we can get another chance to finish these problem sets.
FirstChildUserIdTAG: 905159
FirstChildUserNameTAG: StephenCWan
FirstChildCreateTimeTAG: 2013-02-28T00:49:13Z
FirstChildVoteTAG: 1
IndexTAG: 2022
TitleTAG: Same for me, can't submit...
It's still 1.44 Spain (GMT+1) European time, at least 8 to 9 hours before midnight west coast!
UserIdTAG: 279971
UserNameTAG: nostramo
CreateTimeTAG: 2013-02-28T00:46:14Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Yeah apparently the course deadlines are set for GMT. I guess it is my fault for not scanning the syllabus more closely, but I must say it is rather annoying that they didn't specify the time zone in the deadlines on the section tabs.
FirstChildUserIdTAG: 593553
FirstChildUserNameTAG: Ziewvater
FirstChildCreateTimeTAG: 2013-02-28T00:50:09Z
FirstChildVoteTAG: 1
SecondChildTAG: Even by scanning it properly, sorry to say that, but it's a main topic and therefore shouldn't be in a sub-sub-sub topic named Gradings...
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-02-28T00:54:12Z
SecondChildVoteTAG: 0
IndexTAG: 2023
TitleTAG: Can't save my answers
It's not fair!!! I'm in Brazil and now it's 21:41 here, Why I can't save my answers?
UserIdTAG: 1100005
UserNameTAG: tckasa
CreateTimeTAG: 2013-02-28T00:41:28Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: There is 3 of us from Colombia, trying to enter the answers to the plataform, but the submit button is missing, the deadline says 23:30, and its 19:40!!!
Help please! we've tryed in every account and we have the same problem!
:( :( :(
FirstChildUserIdTAG: 1314095
FirstChildUserNameTAG: yulieth
FirstChildCreateTimeTAG: 2013-02-28T00:43:19Z
FirstChildVoteTAG: 0
FirstChildTAG: Brazil too, it's 20:42 in my timezone and same problem. Also EdX is based in Cambridge, Massachusetts and the time there is 19:42
FirstChildUserIdTAG: 1266217
FirstChildUserNameTAG: ptargioni
FirstChildCreateTimeTAG: 2013-02-28T00:45:22Z
FirstChildVoteTAG: 1
SecondChildTAG: People from Brazil... Seguinte: the deadline is at 23h30 Greenwich time-zone. In Brazil and all South America - except for Chile, I guess - the timezone is "-3:00" from Greenwich. It means you must respond the question up to 20h30 (Brazilian hour or a perhaps a little more on Colombia) not after that.
Pay attention to this detail. Greetings.
SecondChildUserIdTAG: 1270885
SecondChildUserNameTAG: SimoneBR
SecondChildCreateTimeTAG: 2013-02-28T00:55:33Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm from Ecuador and I have the same problem. It's 7:49 pm and I can't send my answers.
Last year I took another course in EDX and we didn't have this kind of problems.
FirstChildUserIdTAG: 257327
FirstChildUserNameTAG: sebastian_sagv
FirstChildCreateTimeTAG: 2013-02-28T00:50:47Z
FirstChildVoteTAG: 1
IndexTAG: 2024
TitleTAG: Times are in GMT so we missed out on submitting exercise sets.
which is a letdown. hopefully this won't hurt our averages too badly (of those who were unable to submit in time) [GMT Clock][1] for those of us who need to be reminded of time zones, like me.
[1]: http://wwp.greenwichmeantime.com/ "GMT Clock"
edit: do you think you could add a GMT to the "graded exercises due by" time stamp just so everyone is reminded which schedule grading is on?
UserIdTAG: 983770
UserNameTAG: kaseyjakes
CreateTimeTAG: 2013-02-28T00:41:01Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You are joking! Why couldn't that be noted along with the posted due date and time? I came home from work with the intention of finishing by 2330 -
FirstChildUserIdTAG: 667241
FirstChildUserNameTAG: MarthaD
FirstChildCreateTimeTAG: 2013-02-28T00:43:35Z
FirstChildVoteTAG: 3
SecondChildTAG: i edited my post to ask just for that. my plan was also the same. as long as i finished by 11:30 Eastern i thought i was all set. apparently not. :(
SecondChildUserIdTAG: 983770
SecondChildUserNameTAG: kaseyjakes
SecondChildCreateTimeTAG: 2013-02-28T00:44:35Z
SecondChildVoteTAG: 0
SecondChildTAG: i assumed that the time indicated was for my local time zone.
SecondChildUserIdTAG: 983770
SecondChildUserNameTAG: kaseyjakes
SecondChildCreateTimeTAG: 2013-02-28T00:46:25Z
SecondChildVoteTAG: 0
SecondChildTAG: but EdX is based in Cambridge, Massachusetts not in London, so it would be their time...
SecondChildUserIdTAG: 1266217
SecondChildUserNameTAG: ptargioni
SecondChildCreateTimeTAG: 2013-02-28T00:46:56Z
SecondChildVoteTAG: 0
SecondChildTAG: That is soooo unfair!!! they didn't add the GMT next to the deadline, how could we have knonw!!!, people from EDX, you need to remember there is people from all over the world doing this course and if you don't specify, it is impossible for us to guess.
Colombia /South America 19:47!!!
SecondChildUserIdTAG: 1314095
SecondChildUserNameTAG: yulieth
SecondChildCreateTimeTAG: 2013-02-28T00:47:16Z
SecondChildVoteTAG: 0
SecondChildTAG: France/Europe 01:49!
Shouldn't have eaten my diner, I would have at least some points in EX 3...
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-02-28T00:50:55Z
SecondChildVoteTAG: 0
IndexTAG: 2025
TitleTAG: Cannot submit: was confused about the deadline
Sadly, like many others, I also did not realize that deadline is 23.30 'GMT' and not California time. I will keep it in mind for future exercises!
UserIdTAG: 1149334
UserNameTAG: NitinJindal
CreateTimeTAG: 2013-02-28T00:40:38Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2026
TitleTAG: buttons missing
The deadline was 23:30 of which timezone? buttons desappears...
UserIdTAG: 1266217
UserNameTAG: ptargioni
CreateTimeTAG: 2013-02-28T00:39:19Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: GMT. At least you have asked the right question… good for you!
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:40:34Z
FirstChildVoteTAG: 1
IndexTAG: 2027
TitleTAG: No save or submit
As per other threads, the save/final check buttons are missing.
UserIdTAG: 338209
UserNameTAG: mikemichael
CreateTimeTAG: 2013-02-28T00:38:04Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: yes I too can't find the save or submit button! It's not yet the deadline time!
FirstChildUserIdTAG: 1164674
FirstChildUserNameTAG: nidajafri
FirstChildCreateTimeTAG: 2013-02-28T00:39:26Z
FirstChildVoteTAG: 0
FirstChildTAG: And you had to create a new thread only to say that? You couldn't just leave message in one of the hundred other posts? You know, that's impolite.
Anyway, you have missed the deadline.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:40:06Z
FirstChildVoteTAG: 0
FirstChildTAG: I don't know what happened, I was working and everything locked us out.
FirstChildUserIdTAG: 485000
FirstChildUserNameTAG: EmiliaP
FirstChildCreateTimeTAG: 2013-02-28T00:40:20Z
FirstChildVoteTAG: 0
IndexTAG: 2028
TitleTAG: Not able to post my answers for the graded excercise part three.
I am unable to post my answers for exercise set three. I am within the time limit.
UserIdTAG: 1144049
UserNameTAG: Slr4527
CreateTimeTAG: 2013-02-28T00:37:59Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: If you're talking about first week's assignments, I'm sorry to disappoint you—you're not within the time limit anymore.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:39:00Z
FirstChildVoteTAG: 0
SecondChildTAG: For first week's assignments, i see this: February 27 23:30. So i think still can submit test. Sorry for my poor english
SecondChildUserIdTAG: 86787
SecondChildUserNameTAG: svtrooper
SecondChildCreateTimeTAG: 2013-02-28T00:46:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, 23:30 **GMT**. Take your timezone into account.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T00:48:30Z
SecondChildVoteTAG: 0
SecondChildTAG: So, you know, the world is round. Sun can shine at only one part of the planet at the time, so it can be day in one place, and night in another. Therefore people introduced time zones… now, please check which time zone has been picked by course administrators for the deadline dates: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T00:50:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, so i can, but clicking on save or final check buttons, do nothing
Please help me.
SecondChildUserIdTAG: 86787
SecondChildUserNameTAG: svtrooper
SecondChildCreateTimeTAG: 2013-02-28T00:51:29Z
SecondChildVoteTAG: 0
IndexTAG: 2029
TitleTAG: Missing submit buttons
I have no submit buttons so I can't submit this exercise test to be graded. I had no problem doing the second set like an hour ago. Please help whenever possible. Cheers.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T00:35:57Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: “Like an hour ago”… that sounds like “still before the deadline”. You apparently missed the deadline. Don't worry, many people did.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:38:15Z
FirstChildVoteTAG: 0
FirstChildTAG: apparently all the times listed are GMT. i wish i realized that earlier because now it is too late for any of us who thought we had until the end of tonight (in US at least) to turn in the assignment. bummer.
i assumed that the time indicated was for my local time zone.
FirstChildUserIdTAG: 983770
FirstChildUserNameTAG: kaseyjakes
FirstChildCreateTimeTAG: 2013-02-28T00:38:40Z
FirstChildVoteTAG: 0
IndexTAG: 2030
TitleTAG: i can't submit! the button disappeared!!!
I'VE BEEN HAVING CHALLENGES SUBMITTING MY ASSIGNMENT! THE BUTTON DISAPPEARED!
UserIdTAG: 1261070
UserNameTAG: ML2D
CreateTimeTAG: 2013-02-28T00:35:52Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Same thing!!
FirstChildUserIdTAG: 977137
FirstChildUserNameTAG: vfarru
FirstChildCreateTimeTAG: 2013-02-28T00:37:54Z
FirstChildVoteTAG: 0
SecondChildTAG: i don't have either...help
SecondChildUserIdTAG: 1036551
SecondChildUserNameTAG: Geetagrg
SecondChildCreateTimeTAG: 2013-02-28T00:48:48Z
SecondChildVoteTAG: 0
FirstChildTAG: The deadline was 11:30 GMT. The website prevents you from submitting answers after the deadline.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T00:38:56Z
FirstChildVoteTAG: 0
IndexTAG: 2031
TitleTAG: submit buttons?
I can't send the answers, the sumit bottons are missing in all the problems, what can i do ??
UserIdTAG: 1249299
UserNameTAG: PaolaVargasV
CreateTimeTAG: 2013-02-28T00:35:50Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Read the forum and learn that the deadline has already passed.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:37:02Z
FirstChildVoteTAG: 0
IndexTAG: 2032
TitleTAG: Problem 4 buttons missing too
Problems 3 and 4 answer submit buttons missing.
UserIdTAG: 1186397
UserNameTAG: larryweidman
CreateTimeTAG: 2013-02-28T00:31:38Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: You seem to not even check the forum before asking a question. That's not polite, you know…
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:36:43Z
FirstChildVoteTAG: 1
FirstChildTAG: Wonder if I can bill edX for my liver transplant?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:39:34Z
FirstChildVoteTAG: 1
SecondChildTAG: It's so cute, I actually cannot stop laughing. I'll need to do some data mining on the comments later, I'm so curious whether there will be more “button missing” or “hello, I'm from X” messages.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T00:45:10Z
SecondChildVoteTAG: 0
SecondChildTAG: don't forget to include posts about the "width of interval -20 to 10"
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T00:49:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok, enough for me. Hope you'll be still alive tomorrow! Good night, it is, you know, almost 2 AM here ^_^
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T00:52:15Z
SecondChildVoteTAG: 0
IndexTAG: 2033
TitleTAG: Problem with final exercise date
Hi!
For what time zone published final exercise date?
According to this http://en.wikipedia.org/wiki/University_of_California,_Berkeley - for California.
At 1:00 A.M. 02.28.2013 in +2:00 timezone (Kyiv, Ukraine) I was still able to send answers, but not at the 2:00 A.M. What is the problem?
As I understand at the same time we have 4.00 P.M. and 5.00 P.M. 02.27.2013 in California
P.S. Sorry for my bad English
UserIdTAG: 339255
UserNameTAG: RostFizhuk
CreateTimeTAG: 2013-02-28T00:29:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The base time zone is defined in the policy document (https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/). It is Greenwich Mean Time, not the one in California.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:32:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes it's my fault. І am already read that agreement
Accustomed to that MITx courses used time during MIT time zone :lamer:
SecondChildUserIdTAG: 339255
SecondChildUserNameTAG: RostFizhuk
SecondChildCreateTimeTAG: 2013-02-28T00:44:02Z
SecondChildVoteTAG: 0
IndexTAG: 2034
TitleTAG: deadline hit before 23:30
it's not even 19:30 yet
UserIdTAG: 159568
UserNameTAG: TomaszBrz
CreateTimeTAG: 2013-02-28T00:29:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: It is 28th February already.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:31:03Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:33:41Z
FirstChildVoteTAG: 0
IndexTAG: 2035
TitleTAG: STAFF - TECHNICAL PROBLEMS
Please advise if I can hand things in tomorrow. I apologize but just getting onto my computer at home cause technical problems and very slow. Please email me at aimstermill51@aol.com.
thanks
amy
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-02-28T00:28:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The website prevents you from submitting your answers after the deadline. The good news is that you get to drop your 2 lowest scores from your final course score.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-28T00:40:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Not really an advantage though. I appreciate the process of learning and checking my answers. With the submit buttons gone, and the check answer buttons gone, I really have no way to know if I am on the right track. I am far more interested in learning the material and gaining a better understanding.
SecondChildUserIdTAG: 667241
SecondChildUserNameTAG: MarthaD
SecondChildCreateTimeTAG: 2013-02-28T00:48:48Z
SecondChildVoteTAG: 0
SecondChildTAG: So do the exercise set on a piece of paper and check them with the results when they are posted.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T00:50:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Allow me to remind that the answers to the questions will be posted - as it was stated in the Course Policy document.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T00:51:19Z
SecondChildVoteTAG: 0
FirstChildTAG: so upset cause the time difference in not helpful for us. please need help just starting and cause of stressing having problems with the beginning exercises after first video. how do they get the answers. i tutored in stats but no just annoyed. thanks
amy
FirstChildUserIdTAG: 411228
FirstChildUserNameTAG: aimster
FirstChildCreateTimeTAG: 2013-02-28T01:11:16Z
FirstChildVoteTAG: 0
IndexTAG: 2036
TitleTAG: Problem 4 in Exercise Set 3
Problem 4
Refer to the box plots in Problem 3.
: 4.0 POINTS
Compare experiments 4 and 5. When drawn on the same scale, the histogram for one of them has a noticeably higher peak the histogram for the other. From the box plots alone, can you tell which one has the higher peak?
Experiment 4
Experiment 5
You have used 0 of 1 submissions
I checked Experiment 5 but it don't give me a grade 4.0 points. It still say :You have used 0 of 1 submissions. Why it don't give me a right or wrong answer ?
UserIdTAG: 967906
UserNameTAG: Billchau2013
CreateTimeTAG: 2013-02-28T00:27:56Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2037
TitleTAG: Deadline confusion
Just read the document that says that the deadlines times are GMT.
Assumed that it was California time like many others here. I had my second excercise completed and then realised there is no way to submit it.
Is there anyway, that an allowance can be made considering that it is the first time. I think everyone here is interested in continuing and doing well. We do not want to lose out because of a small misunderstanding.
Thank you,
UserIdTAG: 959733
UserNameTAG: AnupamaMenon
CreateTimeTAG: 2013-02-28T00:27:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: same problem for me, I just got home from work intending to finish the work and Found that instead of being 8 hours early I'm already late...
FirstChildUserIdTAG: 1312416
FirstChildUserNameTAG: flaerebear
FirstChildCreateTimeTAG: 2013-02-28T00:31:47Z
FirstChildVoteTAG: 0
SecondChildTAG: I did the same confusion. The bad it's I did every exercises in my rough draft. Now is so late. But we are here for learn.
Best wishes.
Daniela Farias
SecondChildUserIdTAG: 1163536
SecondChildUserNameTAG: dsfarias
SecondChildCreateTimeTAG: 2013-02-28T00:45:58Z
SecondChildVoteTAG: 0
IndexTAG: 2038
TitleTAG: Exercise Set 3 buttons are missing
have anyone any solution?
UserIdTAG: 1236951
UserNameTAG: shafaqatphd
CreateTimeTAG: 2013-02-28T00:26:46Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: They are gone forever. You have missed the deadline.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:29:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 1236951
SecondChildUserNameTAG: shafaqatphd
SecondChildCreateTimeTAG: 2013-02-28T00:40:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Same issue. Deadline is 11:30 right?
FirstChildUserIdTAG: 845013
FirstChildUserNameTAG: Vinn
FirstChildCreateTimeTAG: 2013-02-28T00:30:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Deadline was 11:30 GMT.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T00:38:16Z
SecondChildVoteTAG: 0
SecondChildTAG: yes 11:30 GMT
SecondChildUserIdTAG: 1236951
SecondChildUserNameTAG: shafaqatphd
SecondChildCreateTimeTAG: 2013-02-28T00:40:43Z
SecondChildVoteTAG: 0
IndexTAG: 2039
TitleTAG: lost submit button
Yes. It happened here too at 7:25 pm 2/27.
UserIdTAG: 171463
UserNameTAG: Nanc
CreateTimeTAG: 2013-02-28T00:24:58Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: If you want to answer an existing post, please leave it there. You have created a new post now, we don't know who do you reply to.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:27:16Z
FirstChildVoteTAG: 0
IndexTAG: 2040
TitleTAG: answer submit buttons disappeared from problem 3
The buttons were there. I left the page and returned and the buttons were gone. Showed I still have my submissions available.
UserIdTAG: 1186397
UserNameTAG: larryweidman
CreateTimeTAG: 2013-02-28T00:20:19Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: same with me, i tried chrome and firefox... same result.
FirstChildUserIdTAG: 982941
FirstChildUserNameTAG: eielk
FirstChildCreateTimeTAG: 2013-02-28T00:22:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Same here
SecondChildUserIdTAG: 956612
SecondChildUserNameTAG: ignation
SecondChildCreateTimeTAG: 2013-02-28T00:23:20Z
SecondChildVoteTAG: 0
SecondChildTAG: currently me also in same problem. can someone hep?
SecondChildUserIdTAG: 1236951
SecondChildUserNameTAG: shafaqatphd
SecondChildCreateTimeTAG: 2013-02-28T00:25:05Z
SecondChildVoteTAG: 0
SecondChildTAG: i guess the time limit is up. brutal. i work in software and this is crazy to pick some arbitrary time, it should be local to where you are. missed that one in the policies. brutal
SecondChildUserIdTAG: 982941
SecondChildUserNameTAG: eielk
SecondChildCreateTimeTAG: 2013-02-28T00:25:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Same to me. No buttons at all! So... this is it? What if we can complete the excercises? I don't remember...
SecondChildUserIdTAG: 689072
SecondChildUserNameTAG: pato54
SecondChildCreateTimeTAG: 2013-02-28T00:31:56Z
SecondChildVoteTAG: 0
SecondChildTAG: same problem. I'm using chrome
SecondChildUserIdTAG: 281150
SecondChildUserNameTAG: LDias
SecondChildCreateTimeTAG: 2013-02-28T00:34:06Z
SecondChildVoteTAG: 0
SecondChildTAG: same
SecondChildUserIdTAG: 1223452
SecondChildUserNameTAG: tflavien101
SecondChildCreateTimeTAG: 2013-02-28T00:53:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Hopefully, we get extra time.
SecondChildUserIdTAG: 1223452
SecondChildUserNameTAG: tflavien101
SecondChildCreateTimeTAG: 2013-02-28T00:53:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Drink drink drink
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:24:32Z
FirstChildVoteTAG: 0
IndexTAG: 2041
TitleTAG: deadline?
same problem here!
the deadline is 23:30 and at the moment seems that most people can't finish/do the test?
What's the reason for that?
thanks,
Martin
UserIdTAG: 1270740
UserNameTAG: martinov
CreateTimeTAG: 2013-02-28T00:20:18Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:24:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Time for another drink. Here's to your health!
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-28T00:44:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Greenwich Mean Time..Does not make much sense, but good to know (:
thanks
SecondChildUserIdTAG: 1270740
SecondChildUserNameTAG: martinov
SecondChildCreateTimeTAG: 2013-02-28T00:46:55Z
SecondChildVoteTAG: 0
SecondChildTAG: merhutchin, this is just frightening stuff. I am more than gobsmacked. And gin soaked. (not really, too early for that)
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T01:42:41Z
SecondChildVoteTAG: 0
IndexTAG: 2042
TitleTAG: time over????
It vanishes to me too.I guess we are out of time, but I thought we could respect the difference time we have with the USA. That's not fair
because I've planned to to it now. :(
UserIdTAG: 984215
UserNameTAG: franci2910
CreateTimeTAG: 2013-02-28T00:19:10Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It happened to me too. They follow greenwich time, I Believe that this is the explanation. So we actually should not rely on the '23:30' schedule.
FirstChildUserIdTAG: 792484
FirstChildUserNameTAG: tiagobcs
FirstChildCreateTimeTAG: 2013-02-28T00:21:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Why shouldn't we? It's 23:30, except in GMT.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T00:23:20Z
SecondChildVoteTAG: 0
SecondChildTAG: You CAN rely on the 23:30 **GMT** schedule. Just adjust for your timezone.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T00:52:40Z
SecondChildVoteTAG: 0
IndexTAG: 2043
TitleTAG: Time zone not clearly stated - extra day to answer please?
Hi there,
The time zone for the 23:30 deadline was not clearly stated on the courseware and I can't find where the time zone is actually confirmed except for in a discussion thread. I don't know if this is a case of me failing to RTM but can those of us who messed up on the time zone have an extra day to submit our answers please?
Thanks
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-28T00:18:42Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The time was clearly stated in the policy document. You are supposed to read all course materials.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:19:35Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-28T00:21:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Hahahaha... I read this document at the beginning and still... I was sure about PST. Oh well, my bad.
FirstChildUserIdTAG: 594132
FirstChildUserNameTAG: DiraeMada
FirstChildCreateTimeTAG: 2013-02-28T00:42:32Z
FirstChildVoteTAG: 0
IndexTAG: 2044
TitleTAG: Course information:Policies and Requirements (I 'm so screwed, and sadly not the only one...)
Grading
Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
Your two lowest Exercise Set scores will not be used in the calculation of your overall grade.
Grades will be calculated using the following weights:
Exercise Sets: 50%
Midterm: 20%
Final exam: 30%
Certificates of completion will be awarded to those who score 35% or higher overall.
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-02-28T00:18:38Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Correct. It really helps to read the course documents.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:19:54Z
FirstChildVoteTAG: 1
SecondChildTAG: Some prefer to learn the hard way. On the other hand, there is a small chance someone will take a look at the course documents
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T00:23:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry I missed the deadline - is there anything I can dot o still submit?
SecondChildUserIdTAG: 988353
SecondChildUserNameTAG: jenny12
SecondChildCreateTimeTAG: 2013-02-28T00:26:45Z
SecondChildVoteTAG: 0
IndexTAG: 2045
TitleTAG: Another must read document
For all those who are annoyed that they can no longer submit the Week 1 work. You really need to read the policy document.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
UserIdTAG: 845623
UserNameTAG: ChristineStv
CreateTimeTAG: 2013-02-28T00:18:09Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2046
TitleTAG: Time out????
I couldn't save my answers
UserIdTAG: 1246881
UserNameTAG: Math_student
CreateTimeTAG: 2013-02-28T00:16:56Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: yup, mine won't accept my answers to check..
FirstChildUserIdTAG: 617920
FirstChildUserNameTAG: CMR
FirstChildCreateTimeTAG: 2013-02-28T00:18:30Z
FirstChildVoteTAG: 0
SecondChildTAG: I'm having the same problem. I don't believe the submission time is over (?).
SecondChildUserIdTAG: 984610
SecondChildUserNameTAG: relznedk
SecondChildCreateTimeTAG: 2013-02-28T00:30:54Z
SecondChildVoteTAG: 0
SecondChildTAG: 23:30 GMT, people. Read the course material...
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T00:54:13Z
SecondChildVoteTAG: 0
IndexTAG: 2047
TitleTAG: The submit button disappeared.
I am trying to submit my answers to the grades exercises but the submit and save buttons disappeared. It's only Feb. 27, 7:14pm in the east coast of USA. So, how can I post my answers now ?
UserIdTAG: 1174861
UserNameTAG: Roddy
CreateTimeTAG: 2013-02-28T00:16:39Z
VoteTAG: 11
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Same thing happened to me! Not a single submit button anywhere... :(
FirstChildUserIdTAG: 653786
FirstChildUserNameTAG: alfiamyst
FirstChildCreateTimeTAG: 2013-02-28T00:18:35Z
FirstChildVoteTAG: 3
SecondChildTAG: Same with me :(
SecondChildUserIdTAG: 1181463
SecondChildUserNameTAG: gene14
SecondChildCreateTimeTAG: 2013-02-28T00:19:39Z
SecondChildVoteTAG: 0
SecondChildTAG: The date was due Feb.27th 23:30 BUT WHAT TIME ZONE?
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:20:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Its in Greenwich Time Zone. :(
SecondChildUserIdTAG: 1181463
SecondChildUserNameTAG: gene14
SecondChildCreateTimeTAG: 2013-02-28T00:22:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I was wondering the same...
SecondChildUserIdTAG: 721572
SecondChildUserNameTAG: Grimage
SecondChildCreateTimeTAG: 2013-02-28T00:22:12Z
SecondChildVoteTAG: 0
SecondChildTAG: that's not fair~!
SecondChildUserIdTAG: 727699
SecondChildUserNameTAG: kaylee_amberlee
SecondChildCreateTimeTAG: 2013-02-28T00:25:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Same thing with me
SecondChildUserIdTAG: 1151883
SecondChildUserNameTAG: Anesia19
SecondChildCreateTimeTAG: 2013-02-28T00:27:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here, I guess I failed to read that somewhere?
SecondChildUserIdTAG: 829988
SecondChildUserNameTAG: NRKumar177
SecondChildCreateTimeTAG: 2013-02-28T00:30:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Why would a class from Berkeley use GMT and not PST? At least why not use EST, where edx.org is based from?
SecondChildUserIdTAG: 253723
SecondChildUserNameTAG: chrisindallas
SecondChildCreateTimeTAG: 2013-02-28T00:33:19Z
SecondChildVoteTAG: 0
SecondChildTAG: chrisindallas, I absolutely agree with you!!!
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:50:29Z
SecondChildVoteTAG: 0
FirstChildTAG: > that's not fair~!
Actually, what's not fair is the number of students who are posting repeatedly about this. This was an assessment item, with a deadline. So why the confusion? If the submit button has gone, then it should be obvious that submission has finished.
If people had read the course documents, they would have known this.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:29:44Z
FirstChildVoteTAG: 0
SecondChildTAG: what's with the elitist attitude. it certainly looks like you are enjoying this by posting on every discussion thread.
GMT, albeit the policy, is ridiculous.
SecondChildUserIdTAG: 982941
SecondChildUserNameTAG: eielk
SecondChildCreateTimeTAG: 2013-02-28T00:37:11Z
SecondChildVoteTAG: 0
SecondChildTAG: ChristineStv for many this is the first online class ever. It is confusing. Some may not know what GMT is and English may not be their first language. You are not nice.
SecondChildUserIdTAG: 955343
SecondChildUserNameTAG: alhaider
SecondChildCreateTimeTAG: 2013-02-28T00:42:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Dear ChristineStv,
I had read the course documents and forgot about GMT (I was sure it was PST) :p and now I have only 1st ES done.
Dear friends, don't worry. Two of the ESs (the worse) will be dropped.
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:57:25Z
SecondChildVoteTAG: 0
SecondChildTAG: True!!
SecondChildUserIdTAG: 512364
SecondChildUserNameTAG: claudiampt
SecondChildCreateTimeTAG: 2013-02-28T01:41:42Z
SecondChildVoteTAG: 0
FirstChildTAG: How about we do a histogram on how many people missed the GMT deadline policy. doh, i know i did.
Is this the typical policy for all EDX courses. This can't be the first time this online course has run into this... i'm sure the staff won't enjoy seeing all of these discussion threads...
FirstChildUserIdTAG: 982941
FirstChildUserNameTAG: eielk
FirstChildCreateTimeTAG: 2013-02-28T00:56:08Z
FirstChildVoteTAG: 1
IndexTAG: 2048
TitleTAG: Exercise problem
I could not present the results of exercise 1.
UserIdTAG: 1261728
UserNameTAG: Djalma123
CreateTimeTAG: 2013-02-28T00:16:09Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2049
TitleTAG: Can't Submit Answers
For some reason there's no submission button to submit my answers. Any ideas?
UserIdTAG: 165737
UserNameTAG: Finbarr
CreateTimeTAG: 2013-02-28T00:15:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I couldn't either. Must be an issue with the courseware.
FirstChildUserIdTAG: 952081
FirstChildUserNameTAG: hapittman
FirstChildCreateTimeTAG: 2013-02-28T00:22:29Z
FirstChildVoteTAG: 0
SecondChildTAG: Oh, certainly it isn't. The system works as advertised.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T00:24:32Z
SecondChildVoteTAG: 0
SecondChildTAG: :)
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T00:30:03Z
SecondChildVoteTAG: 0
IndexTAG: 2050
TitleTAG: STAFF: Submit buttons disappeared...
...and I'm unable to finish the last tests of the 1st week. It's not 23.30 california time yet...and I see there are new posts for week 2...maybe someone disabled that by mistake?
UserIdTAG: 1102822
UserNameTAG: monikedalencar
CreateTimeTAG: 2013-02-28T00:15:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Who told you the deadline is 23:30 California time? It's 23:30 Greenwich time. Check the policy document: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:25:49Z
FirstChildVoteTAG: 0
IndexTAG: 2051
TitleTAG: Problems
Hi,
I had problem with question 4. The system didn´t save my answer. I put Experiment 4.
Could you check the problem?
Tks!
Guilherme Coelho
UserIdTAG: 1097071
UserNameTAG: Guilhereme
CreateTimeTAG: 2013-02-28T00:14:42Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2052
TitleTAG: Missing submission button for problem 1
Hi,
I don't have a submission button for Problem 1 anymore and still have my 2 submission. I tried logging out and back in without success.
Thanks,
JF
![Missing submission button][1]
[1]: https://edxuploads.s3.amazonaws.com/13620103541343668.png
UserIdTAG: 202619
UserNameTAG: jfcantin
CreateTimeTAG: 2013-02-28T00:13:28Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2053
TitleTAG: help
help ! i can't write my answers !!
UserIdTAG: 504246
UserNameTAG: argelita
CreateTimeTAG: 2013-02-28T00:13:01Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: same with me
FirstChildUserIdTAG: 1151883
FirstChildUserNameTAG: Anesia19
FirstChildCreateTimeTAG: 2013-02-28T00:28:21Z
FirstChildVoteTAG: 0
IndexTAG: 2054
TitleTAG: STAFF - I have a technical problem, too
I have submitted answers to a problem 3, the page re-loaded and now I see that my answers did not go through; it says "You have used 0 of 1 submissions" on the bottom of the page, but there is no submission button anymore. Please help...
UserIdTAG: 653786
UserNameTAG: alfiamyst
CreateTimeTAG: 2013-02-28T00:10:58Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I just had this same problem with Exercise set 3, Problems 3&4.
Noreen
FirstChildUserIdTAG: 1130547
FirstChildUserNameTAG: nluetteke
FirstChildCreateTimeTAG: 2013-02-28T00:13:20Z
FirstChildVoteTAG: 0
FirstChildTAG: I think I just figured it out - it's because the 23:30 deadline has passed, I think. I didn't realize it was 23:30 GMT, I didn't see where that was stated on our course materials, and only found out when I saw one of the discussion threads.
FirstChildUserIdTAG: 1215056
FirstChildUserNameTAG: beaker77
FirstChildCreateTimeTAG: 2013-02-28T00:13:29Z
FirstChildVoteTAG: 0
SecondChildTAG: oh shoot! had the same problem. i thought it was california time. bummer :(
SecondChildUserIdTAG: 1102822
SecondChildUserNameTAG: monikedalencar
SecondChildCreateTimeTAG: 2013-02-28T00:17:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here. I was sure they set PST...
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:18:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too! :-(
SecondChildUserIdTAG: 1280
SecondChildUserNameTAG: tomwright1964
SecondChildCreateTimeTAG: 2013-02-28T00:20:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I know! I thought I had time to submit also. For the life of me I can't find where the time zone was stated in the course material.
SecondChildUserIdTAG: 1215056
SecondChildUserNameTAG: beaker77
SecondChildCreateTimeTAG: 2013-02-28T00:21:42Z
SecondChildVoteTAG: 0
SecondChildTAG: The course polices document.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T00:30:25Z
SecondChildVoteTAG: 0
SecondChildTAG: It wasn't stated. On other course, like MITx the due dates and times are set according to Boston time. That's a precedent that models our interpretation of the coming courses. Yes I missed the time deadline because of this.
SecondChildUserIdTAG: 609816
SecondChildUserNameTAG: Oscar7000
SecondChildCreateTimeTAG: 2013-02-28T01:04:18Z
SecondChildVoteTAG: 0
IndexTAG: 2055
TitleTAG: Submission buttons disappearing
I complete the exercise set questions but am not able to submit some sections due to the fact that the submission button has disappeared. I will have to drop the course.
UserIdTAG: 1218161
UserNameTAG: rtibolla
CreateTimeTAG: 2013-02-28T00:10:53Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2056
TitleTAG: submission buttons vanished
not sure why submission buttons on ex set3 for last two problems suddenly vanished. I didn't answer and was about to click..... weird..
UserIdTAG: 330198
UserNameTAG: ssyed
CreateTimeTAG: 2013-02-28T00:07:48Z
VoteTAG: 16
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: That's just happened to me as well.
Also can someone clarify what the time zone the 23:30 deadline is in?
FirstChildUserIdTAG: 1215056
FirstChildUserNameTAG: beaker77
FirstChildCreateTimeTAG: 2013-02-28T00:08:56Z
FirstChildVoteTAG: 3
SecondChildTAG: I assumed it was 23:30 Pacific Standard Time. I'm in New York and the button disappeared, but I thought I had all night to complete the assignments.
SecondChildUserIdTAG: 575972
SecondChildUserNameTAG: MRobotham1
SecondChildCreateTimeTAG: 2013-02-28T00:09:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Same thing happened to me just when I figured out how to do the problem. Did we run out of time?
SecondChildUserIdTAG: 890817
SecondChildUserNameTAG: JacksonPope
SecondChildCreateTimeTAG: 2013-02-28T00:10:25Z
SecondChildVoteTAG: 0
SecondChildTAG: I am in eastern time zone and was thinking that 23:30 is actually considered as student time zone???? i know the answers and bad luck if it is not considered...
SecondChildUserIdTAG: 330198
SecondChildUserNameTAG: ssyed
SecondChildCreateTimeTAG: 2013-02-28T00:13:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I live in France and it's the same!!!!! Someone from the staff please, give us an answer asap
It's 1:14 a.m here
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-02-28T00:14:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, wouldn't 23:30 be 11:30 pm? Eastern time (where I am) is 3 hours ahead of Pacific time,right? So even if the deadline is 11:30 pm on Wed Pacific time, that would correspond to 2:30 AM Thursday Eastern time, right? I was not able to complete submission of my last two answers (Probs 3 & 4 in Exercise set 3) at 7 pm Wednesday 2/27, so something is amiss as that is well ahead of 23:30 deadline in either extreme time zone.
SecondChildUserIdTAG: 1130547
SecondChildUserNameTAG: nluetteke
SecondChildCreateTimeTAG: 2013-02-28T00:19:13Z
SecondChildVoteTAG: 0
SecondChildTAG: it's still 7 hours away from 1130 pacific time. Ugg! this course is so buggy.
SecondChildUserIdTAG: 1152215
SecondChildUserNameTAG: Mantou
SecondChildCreateTimeTAG: 2013-02-28T00:37:19Z
SecondChildVoteTAG: 0
SecondChildTAG: I too also have no submission buttons in any of my exercise set 3 questions. weird.
SecondChildUserIdTAG: 1101196
SecondChildUserNameTAG: jotey67890
SecondChildCreateTimeTAG: 2013-02-28T00:41:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Apparently this course use GMT, which is a time zone in England. This is filling me with rage!!!!!
SecondChildUserIdTAG: 1152215
SecondChildUserNameTAG: Mantou
SecondChildCreateTimeTAG: 2013-02-28T00:44:54Z
SecondChildVoteTAG: 0
FirstChildTAG: It happened to me as well. It might be because we were late in submitting the assignments.
FirstChildUserIdTAG: 1246000
FirstChildUserNameTAG: ramdasp
FirstChildCreateTimeTAG: 2013-02-28T00:11:24Z
FirstChildVoteTAG: 1
FirstChildTAG:
> Did we run out of time?
Yes, you ran out of time. As the course policy says,submissions close at 23.30 GMT
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:11:41Z
FirstChildVoteTAG: 0
SecondChildTAG: oh! f***....
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-02-28T00:14:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for letting me know. The computer I'm using wouldn't let me download the pdfs so I wasn't sure.
SecondChildUserIdTAG: 890817
SecondChildUserNameTAG: JacksonPope
SecondChildCreateTimeTAG: 2013-02-28T00:16:54Z
SecondChildVoteTAG: 0
SecondChildTAG: How come? ![We are on time...][1]
[1]: https://edxuploads.s3.amazonaws.com/13620108001343652.png
SecondChildUserIdTAG: 1116101
SecondChildUserNameTAG: MEAB
SecondChildCreateTimeTAG: 2013-02-28T00:20:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Ohhhh... 27 feb, hmmm... sorry.
SecondChildUserIdTAG: 1116101
SecondChildUserNameTAG: MEAB
SecondChildCreateTimeTAG: 2013-02-28T00:21:04Z
SecondChildVoteTAG: 0
SecondChildTAG: How come? 27 Feb, that's how come.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T00:21:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Instead of guessing the time wouldn't be easier to have a COUNTDOWN?!
SecondChildUserIdTAG: 265899
SecondChildUserNameTAG: killmess
SecondChildCreateTimeTAG: 2013-03-04T02:18:21Z
SecondChildVoteTAG: 0
FirstChildTAG: What happens if we didn't submit our answers?
FirstChildUserIdTAG: 955343
FirstChildUserNameTAG: alhaider
FirstChildCreateTimeTAG: 2013-02-28T00:16:56Z
FirstChildVoteTAG: 1
SecondChildTAG: If you didn't submit any at all, you get 0
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T00:22:19Z
SecondChildVoteTAG: 0
IndexTAG: 2057
TitleTAG: omg wtf wrong I live in France, I can't submit anything anymore
I understood that time was US central. Got it wrong?
UserIdTAG: 1013822
UserNameTAG: FaizaHarbi
CreateTimeTAG: 2013-02-28T00:07:36Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: this is what i had also understood.. :/
FirstChildUserIdTAG: 1178448
FirstChildUserNameTAG: zisopouloukaterina
FirstChildCreateTimeTAG: 2013-02-28T00:17:05Z
FirstChildVoteTAG: 0
FirstChildTAG: Maybe you needed to read the course policy document.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:23:08Z
FirstChildVoteTAG: 0
SecondChildTAG: I just did, mistook cmt and gmt,
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-02-28T00:25:25Z
SecondChildVoteTAG: 0
FirstChildTAG: To be Honest, I didn't expect due time to be found in the Grading section!
I feel so stupid and useless, mistaking est and gmt ,as I also take 6.00x course and it's in bold and on top headline that due time is est.Even in the Calendar it's so big you can't miss it...
0 for me, my mistake,wanted to do my best so badly, so disappointed that I'm crying. Seriously....
Had the flu, was late to begin this course for a starters, insomnia (brain is so slow it's stunning!), and that...
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-28T00:36:11Z
FirstChildVoteTAG: 0
IndexTAG: 2058
TitleTAG: I have problems with submissions
Something wrong happened while I was doing my test and the submissions buttons disappeared. What can i do?
UserIdTAG: 1029237
UserNameTAG: anatascon
CreateTimeTAG: 2013-02-28T00:06:01Z
VoteTAG: 11
CoursewareTAG: undefined
NumberOfReplyTAG: 7
FirstChildTAG: I'm waiting them to appear too...
FirstChildUserIdTAG: 331946
FirstChildUserNameTAG: Phonascus
FirstChildCreateTimeTAG: 2013-02-28T00:07:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Having the same issues. Submit buttons are gone.
SecondChildUserIdTAG: 1311471
SecondChildUserNameTAG: kdeppe
SecondChildCreateTimeTAG: 2013-02-28T00:07:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Same thing here! what is going on???
SecondChildUserIdTAG: 1262910
SecondChildUserNameTAG: dashacoop
SecondChildCreateTimeTAG: 2013-02-28T00:10:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Time´s up? I dont think so...
SecondChildUserIdTAG: 1029237
SecondChildUserNameTAG: anatascon
SecondChildCreateTimeTAG: 2013-02-28T00:14:03Z
SecondChildVoteTAG: 0
SecondChildTAG: THere says 23:30 ... asume is EST... 19:16 now
SecondChildUserIdTAG: 936850
SecondChildUserNameTAG: A1ejandroMX
SecondChildCreateTimeTAG: 2013-02-28T00:15:46Z
SecondChildVoteTAG: 0
SecondChildTAG: It happened the same to me :(
I was half way
SecondChildUserIdTAG: 928962
SecondChildUserNameTAG: DianaMarcela
SecondChildCreateTimeTAG: 2013-02-28T00:22:11Z
SecondChildVoteTAG: 0
SecondChildTAG: me too
SecondChildUserIdTAG: 1321795
SecondChildUserNameTAG: Sofita
SecondChildCreateTimeTAG: 2013-02-28T00:24:54Z
SecondChildVoteTAG: 0
SecondChildTAG: me too
SecondChildUserIdTAG: 287627
SecondChildUserNameTAG: RGK
SecondChildCreateTimeTAG: 2013-02-28T00:30:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too, I have the answers and don't know what to do now.
SecondChildUserIdTAG: 1271553
SecondChildUserNameTAG: Ryno762
SecondChildCreateTimeTAG: 2013-02-28T01:14:25Z
SecondChildVoteTAG: 0
SecondChildTAG: I thought we had until end of today, but there's no buttons to submit.
SecondChildUserIdTAG: 836300
SecondChildUserNameTAG: ryan16
SecondChildCreateTimeTAG: 2013-02-28T01:17:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here. I am on the east coast and it is 8:53 pm (20:53)on feb 27th on the east coast
SecondChildUserIdTAG: 1238655
SecondChildUserNameTAG: myrmidon1011
SecondChildCreateTimeTAG: 2013-02-28T01:54:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too
SecondChildUserIdTAG: 1203059
SecondChildUserNameTAG: Marilis
SecondChildCreateTimeTAG: 2013-02-28T02:14:46Z
SecondChildVoteTAG: 0
SecondChildTAG: same here I can't submit my answers
SecondChildUserIdTAG: 222137
SecondChildUserNameTAG: Kevin0630
SecondChildCreateTimeTAG: 2013-02-28T02:15:02Z
SecondChildVoteTAG: 0
SecondChildTAG: me tooo :(
SecondChildUserIdTAG: 1205564
SecondChildUserNameTAG: MariamK
SecondChildCreateTimeTAG: 2013-02-28T02:31:19Z
SecondChildVoteTAG: 0
SecondChildTAG: I think its because of the due dates! Check your timezones carefully I guess?
SecondChildUserIdTAG: 253581
SecondChildUserNameTAG: Beej
SecondChildCreateTimeTAG: 2013-02-28T02:41:12Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm in the east coast. I was under the impression we had until 10:30 EST? Unable to submit final work as well.
SecondChildUserIdTAG: 1153795
SecondChildUserNameTAG: AIJ
SecondChildCreateTimeTAG: 2013-02-28T02:54:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Bummer. Looks like I missed the deadline for submission of Exercise Set 3. I suggest providing a timezone next to the date/time due in the future.
SecondChildUserIdTAG: 1097040
SecondChildUserNameTAG: lpedroza
SecondChildCreateTimeTAG: 2013-02-28T02:55:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Same as Ipedroza, I would like to know what's the timezone you are based on to close submissions. Thanks.
SecondChildUserIdTAG: 434854
SecondChildUserNameTAG: aluchelo
SecondChildCreateTimeTAG: 2013-02-28T03:01:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Some of us blew the submission time on the East Coast. Well at least we learned something about details. Good night or morning all.
SecondChildUserIdTAG: 1220195
SecondChildUserNameTAG: Emuna309
SecondChildCreateTimeTAG: 2013-02-28T03:02:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too. I also have problem to submit answer
SecondChildUserIdTAG: 139622
SecondChildUserNameTAG: farasipe
SecondChildCreateTimeTAG: 2013-03-01T00:47:44Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm confused about the same thing, it's 20.14 and I cant submit my answers!
SecondChildUserIdTAG: 622914
SecondChildUserNameTAG: Slobodkina
SecondChildCreateTimeTAG: 2013-03-01T01:15:37Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm having problems with submission as well.
SecondChildUserIdTAG: 199368
SecondChildUserNameTAG: marvinford
SecondChildCreateTimeTAG: 2013-03-01T03:14:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too.
SecondChildUserIdTAG: 1310514
SecondChildUserNameTAG: SarahCorm
SecondChildCreateTimeTAG: 2013-03-01T04:34:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too
SecondChildUserIdTAG: 387004
SecondChildUserNameTAG: Arnulfo
SecondChildCreateTimeTAG: 2013-03-01T06:27:36Z
SecondChildVoteTAG: 0
SecondChildTAG: catung
Can anyone help me, I started answering the questions since February, I checked the student directory and my name is not on the list thoug I registered for the course. I am from Papua New Guinea just north of Australia. Also how can my subjects be graded. I have not seen any grading for my courses taken so far.
By cyril
SecondChildUserIdTAG: 972972
SecondChildUserNameTAG: 0123
SecondChildCreateTimeTAG: 2013-03-16T05:38:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Same thing just happened to me. I should have until 23:30 yet it's only 19:00.
FirstChildUserIdTAG: 1281549
FirstChildUserNameTAG: cearley
FirstChildCreateTimeTAG: 2013-02-28T00:07:55Z
FirstChildVoteTAG: 0
SecondChildTAG: me at face same problem
SecondChildUserIdTAG: 1236951
SecondChildUserNameTAG: shafaqatphd
SecondChildCreateTimeTAG: 2013-02-28T00:21:27Z
SecondChildVoteTAG: 0
FirstChildTAG: I just had the same problem while trying to save and grade my answers to problems 3 and 4 at around 7 pm Eastern time. I kept selecting Save and Final Check, but nothing happened. I logged out and logged back in, but now the Save and Check options are not even shown!
FirstChildUserIdTAG: 1130547
FirstChildUserNameTAG: nluetteke
FirstChildCreateTimeTAG: 2013-02-28T00:09:50Z
FirstChildVoteTAG: 0
FirstChildTAG: So apparently you have to 'convert' the due dates shown next to the problem sets yourself. http://www.wolframalpha.com/input/?i=27th+february%2C+23%3A30+GMT+in+Boston
That's surprising and pretty lame if you ask me. I wish that was made clear someplace.
FirstChildUserIdTAG: 1281549
FirstChildUserNameTAG: cearley
FirstChildCreateTimeTAG: 2013-02-28T00:13:28Z
FirstChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T00:25:31Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't see where it says anything about timing differences in the edx link.
SecondChildUserIdTAG: 587109
SecondChildUserNameTAG: TigranA
SecondChildCreateTimeTAG: 2013-02-28T01:56:09Z
SecondChildVoteTAG: 0
SecondChildTAG: @cearley, here is a link for a time zone converter. http://www.timeanddate.com/worldclock/converter.html
SecondChildUserIdTAG: 1067669
SecondChildUserNameTAG: psanders
SecondChildCreateTimeTAG: 2013-03-04T14:50:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Do any of you read the course documents?
> I wish that was made clear someplace.
It was.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-28T00:14:16Z
FirstChildVoteTAG: 7
SecondChildTAG: It's still lame.
SecondChildUserIdTAG: 1281549
SecondChildUserNameTAG: cearley
SecondChildCreateTimeTAG: 2013-02-28T00:15:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Lame is not reading the requirements of the course. It isn't structured around your inability to follow instructions.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T00:16:07Z
SecondChildVoteTAG: 0
SecondChildTAG: From my point of view, the only way I see it stated clearly is to show it together with each date. Each single one. People are too accustomed to refer to their timezones that it's really not enough to state it somewhere deep in course documentation only. That's a usability measure.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T00:17:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Lame are your disparaging remarks - do you have nothing better to do with your time?
SecondChildUserIdTAG: 1281549
SecondChildUserNameTAG: cearley
SecondChildCreateTimeTAG: 2013-02-28T00:17:59Z
SecondChildVoteTAG: 0
SecondChildTAG: @cearley, it's so funny to see 10 posts within a minute, every about the same problem ^_^
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-28T00:19:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Just enjoying the drinking game.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T00:24:06Z
SecondChildVoteTAG: 0
SecondChildTAG: cearley, i'm with you.
SecondChildUserIdTAG: 982941
SecondChildUserNameTAG: eielk
SecondChildCreateTimeTAG: 2013-02-28T00:46:37Z
SecondChildVoteTAG: 0
SecondChildTAG: @ChristineStv, I agree with your assessment (lame). This is a graduate level course and yet people can't figure out the timezone issue? Perhaps EdX needs to make that a prerequisite for the courses; knowing how to read the course instructions and converting GMT into your local time. :)
SecondChildUserIdTAG: 1067669
SecondChildUserNameTAG: psanders
SecondChildCreateTimeTAG: 2013-03-04T14:36:45Z
SecondChildVoteTAG: 0
FirstChildTAG: me too! Please, anybody can help us?
FirstChildUserIdTAG: 1060737
FirstChildUserNameTAG: lilysf21
FirstChildCreateTimeTAG: 2013-03-01T03:11:11Z
FirstChildVoteTAG: 0
FirstChildTAG: Iam not able to access the normal curve applet for solving the problems. Kinldy help me out.
FirstChildUserIdTAG: 1105712
FirstChildUserNameTAG: sumi1986
FirstChildCreateTimeTAG: 2013-03-12T03:21:26Z
FirstChildVoteTAG: 0
IndexTAG: 2059
TitleTAG: Checking
For some reason, I cannot post my answers to this Exercise.
UserIdTAG: 1181463
UserNameTAG: gene14
CreateTimeTAG: 2013-02-28T00:04:40Z
VoteTAG: 8
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Deadline was about half an hour ago, I think.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:06:17Z
FirstChildVoteTAG: 0
SecondChildTAG: same here, is the announced deadline wrong ?
SecondChildUserIdTAG: 73196
SecondChildUserNameTAG: mip12
SecondChildCreateTimeTAG: 2013-02-28T00:09:02Z
SecondChildVoteTAG: 0
SecondChildTAG: What's going on? What was the time set?
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:10:37Z
SecondChildVoteTAG: 0
SecondChildTAG: The Course info says 23:30 of Feb. 27
SecondChildUserIdTAG: 1181463
SecondChildUserNameTAG: gene14
SecondChildCreateTimeTAG: 2013-02-28T00:12:35Z
SecondChildVoteTAG: 0
SecondChildTAG: what time zone?
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:13:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I am in Eastern Time Zone
SecondChildUserIdTAG: 1181463
SecondChildUserNameTAG: gene14
SecondChildCreateTimeTAG: 2013-02-28T00:17:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Weren't they supposed to set PST?
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:23:39Z
SecondChildVoteTAG: 0
SecondChildTAG: My friends, if you read this post hit "+" for "Checking". I think that staff will read posts with a lot of "+"s. They will find out what is going on.
SecondChildUserIdTAG: 594132
SecondChildUserNameTAG: DiraeMada
SecondChildCreateTimeTAG: 2013-02-28T00:28:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here.
SecondChildUserIdTAG: 705689
SecondChildUserNameTAG: BR864
SecondChildCreateTimeTAG: 2013-02-28T00:51:49Z
SecondChildVoteTAG: 0
SecondChildTAG: So why am I not able to submit my answer? It's 9:55 Eastern. Aargh.
SecondChildUserIdTAG: 1020734
SecondChildUserNameTAG: godelstein
SecondChildCreateTimeTAG: 2013-02-28T02:55:49Z
SecondChildVoteTAG: 0
IndexTAG: 2060
TitleTAG: Answers need to be calculated to 1 decimal point
Hey Guys,
I didn't know either, I see a lot of people have made the same mistake as I have and rounded either to two decimal places or more, or a whole number. They should have stated beforehand that answers should be given to one decimal place. Luckily it's only a practice question and so doesn't count towards the final grade.
UserIdTAG: 413046
UserNameTAG: mintyoreo
CreateTimeTAG: 2013-02-27T23:58:32Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2061
TitleTAG: Problem 1
I probably did not understand the question at problem 1 since one of the answer is correct and not the others. It is sometimes difficult to guess what is the precision level which is expected in the answer. Anyway I could also be wrong :-)
JMB
UserIdTAG: 605027
UserNameTAG: bonninjm
CreateTimeTAG: 2013-02-27T23:57:28Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2062
TitleTAG: Box and Whiskers? Suggestion to the Prof and TA's regarding test material
To the professor and TA's:
Is it a good idea to introduce a new chart style (box and whiskers) in an exam that has not been covered in the coursework?
That's like trying a new recipe for Thanksgiving with 100 guests arriving. :)
Don't get me wrong, W&B charts are interesting, but it really does feel you are throwing a curve just for the fun of it at our expense. For people who have the concepts down, it's easy, but for those who don't have the concepts down, it appears to add more frustration. I'm not sure I understand the point of that, unless it is to make people drop.
This course seems to be more about tricking students during the test than testing our knowledge of concepts that we want to learn.
I hope you will consider this comment for future tests.
UserIdTAG: 963897
UserNameTAG: lightbulb
CreateTimeTAG: 2013-02-27T23:41:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: > This course seems to be more about tricking students
This is the new drinking game.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T23:44:35Z
FirstChildVoteTAG: 1
SecondChildTAG: In that case I need another cup of coffee. oh, wait... :)
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-02-28T00:00:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Hilarious. On the other hand, it is full moon today.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-28T00:13:03Z
SecondChildVoteTAG: 0
SecondChildTAG: What about this drinking game option? Sounds interesting...
SecondChildUserIdTAG: 689072
SecondChildUserNameTAG: pato54
SecondChildCreateTimeTAG: 2013-02-28T00:38:32Z
SecondChildVoteTAG: 0
SecondChildTAG: If we keep on reading post after post with the same discussion, we will all need a drink to get through the course!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T00:58:59Z
SecondChildVoteTAG: 0
FirstChildTAG: I think, adding something new in the test makes it interesting....
Also,the concept isn't very difficult.....didn't it actually introduce a new ,very handy data representing method in a matter of just 2-3 minutes?
It is actually helpful.
FirstChildUserIdTAG: 85710
FirstChildUserNameTAG: nileshpatil
FirstChildCreateTimeTAG: 2013-02-28T00:02:56Z
FirstChildVoteTAG: 0
FirstChildTAG: lightbulb: I think the box and whiskers concept was not that much of a stretch from the concepts that had already been presented in the course material but, having said that, not everyone is the same. If you see a new concept and you have trouble with the question, then you have the whole of the internet to look for information, read and practise up on different subjects. Just use Google and you'll find tons of info. I don't think you can accuse a teacher and a university who have invested time and money to give you a free course (where you only need a 35% passing grade). Just as a starter, have a look on Khanacademy.com where box and whisker plots are explained.
Learning is about being active and searching for information. It's not about sitting back and being spoonfed. I'm guessing you're frustrated because you got something wrong. But getting things wrong is an opportunity for more learning. Let's be a bit more thankful for all of this.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T01:10:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Well put, agree
SecondChildUserIdTAG: 1240022
SecondChildUserNameTAG: Moshiko
SecondChildCreateTimeTAG: 2013-03-01T12:56:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you, Oprah.
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-03-13T06:01:17Z
SecondChildVoteTAG: 0
IndexTAG: 2063
TitleTAG: 3.1 lecture ?
List: $1, $2, $3, $4 average = $2.50
Suppose one of the people gets another $100.
What happens to the average? It goes up.
By how much? By $100/4 = $25
The new average is the old average plus the change:
new average = $2.50 + $25 = $27.50
Observe:
You didn't need to know which person got richer
**is the reason we dont need to know who got richer because the number of people receiving the cash did not changs**
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-27T23:34:43Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: The average depends on the total amount of money everyone has, and the total number of people. As long as you know those two numbers, you can find the average. Exactly who has how much does not affect the total.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T01:02:02Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-28T02:42:37Z
SecondChildVoteTAG: 0
IndexTAG: 2064
TitleTAG: Assignment Deadline Time
To Staff: I need clarification. If the deadline for submitting assignments is 23:30 GMT, does that mean 11:30 at night in each individual time zone? Does it mean Boston's time zone? Please help allay my confusion.
UserIdTAG: 868031
UserNameTAG: CaliforniaViv
CreateTimeTAG: 2013-02-27T23:31:30Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: 23:30 GMT means exactly this—23:30 GMT. GMT is a time zone, so you need to adjust the time to your own time zone manually. I like to use Wolfram Alpha to calculate the time, for example for Boston: http://www.wolframalpha.com/input/?i=27th+february%2C+23%3A30+GMT+in+Boston — the “Time Difference” field will show you how much time is left too (hint: not much).
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-27T23:37:17Z
FirstChildVoteTAG: 0
IndexTAG: 2065
TitleTAG: How to view problem set key after submission.
Hi All,
I apologize if this question has already been asked and answered…my search for it in the forum was unsuccessful.
How can I view the correct answers for problem sets after final completion? There are a few questions I have yet to solve, and a key would be beneficial to my overall learning.
Thanks!
UserIdTAG: 931416
UserNameTAG: mlollier
CreateTimeTAG: 2013-02-27T23:13:09Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The answers are released the day after submission closes.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T23:16:44Z
FirstChildVoteTAG: 4
SecondChildTAG: Oh, thanks. Where is this information listed?
SecondChildUserIdTAG: 931416
SecondChildUserNameTAG: mlollier
SecondChildCreateTimeTAG: 2013-02-27T23:39:42Z
SecondChildVoteTAG: 0
SecondChildTAG: In the Course Policy document.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T23:40:57Z
SecondChildVoteTAG: 0
SecondChildTAG: ...well, I feel foolish. Thanks again.
SecondChildUserIdTAG: 931416
SecondChildUserNameTAG: mlollier
SecondChildCreateTimeTAG: 2013-02-28T22:52:05Z
SecondChildVoteTAG: 0
IndexTAG: 2066
TitleTAG: List my own comments
Is it possible to show all my comments (in the discussion interface)?
UserIdTAG: 1097026
UserNameTAG: aiS2ru
CreateTimeTAG: 2013-02-27T23:08:12Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You can see your most recent posts if you click on your name from within a post. This is yours:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/users/1097026
This is only your recent posts, once you make a few dozen the old ones will vanish off the list. If you want to keep track of them you will need to Follow them - click on the star in the top right of the opening post. Then ShowAllDiscussions > Following in the left menu.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T23:12:07Z
FirstChildVoteTAG: 1
SecondChildTAG: Oh, thank you, this feature is not very obvious…
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-27T23:24:14Z
SecondChildVoteTAG: 0
IndexTAG: 2067
TitleTAG: Not doing so well
I got almost every wrong....I hope I can still pass...I am wishing we have one extra just to learn percentiles better....but I know that won't happen.
UserIdTAG: 916875
UserNameTAG: nilufa
CreateTimeTAG: 2013-02-27T23:06:31Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes, you can. Your worst two excercises will not be added to ur overall score. Just study harder.
FirstChildUserIdTAG: 1187096
FirstChildUserNameTAG: Chinonso411
FirstChildCreateTimeTAG: 2013-02-27T23:21:42Z
FirstChildVoteTAG: 1
IndexTAG: 2068
TitleTAG: [STAFF] Built-in Calculator
Well, overall the calculation were easy. But I think it would be very convenient if we can do it inside the browser without have to resort to another calculator for doing the exercise, like other courses such as intro to solid state chem and physics electricity. Thanks.
UserIdTAG: 716386
UserNameTAG: farizan
CreateTimeTAG: 2013-02-27T23:02:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: If the web browser vendor you use is Google Chrome, you can open another browser tab, & do simple arithmetic in the url address bar (example: 15 * 14.4 / 20.9). The resulting "search" "page result" shows a "calculator" with the result (example: 10.3349). You can then proceed to make further calculations if desired.
Of course, a spreadsheet can be "used as a glorified calculator", another option is to use a web spreadsheet like Google Spreadsheet.
FirstChildUserIdTAG: 538198
FirstChildUserNameTAG: A_P
FirstChildCreateTimeTAG: 2013-02-27T23:25:13Z
FirstChildVoteTAG: 2
SecondChildTAG: That's pretty cool!
SecondChildUserIdTAG: 876324
SecondChildUserNameTAG: BrianDeering
SecondChildCreateTimeTAG: 2013-02-27T23:27:30Z
SecondChildVoteTAG: 0
FirstChildTAG: There is already a built-in calculator for this class. In the online textbook! If you go to the textbook, at the top left corner there is a drop down menu that lists a calculator. :)
FirstChildUserIdTAG: 1106293
FirstChildUserNameTAG: bifurcation
FirstChildCreateTimeTAG: 2013-02-28T00:37:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks, bifurcation. The Course Policies and Requirements page has an Equipment section that tells you how to find the calculator in the online text. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T01:23:03Z
FirstChildVoteTAG: 0
IndexTAG: 2069
TitleTAG: Width of subinterval?
Hi,
please anyone can explain me how can i find "Width of subinterval"?
Thanks for your answer :)
UserIdTAG: 1060737
UserNameTAG: lilysf21
CreateTimeTAG: 2013-02-27T22:49:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2070
TitleTAG: Not Happy
my answer to ex 3-6 B is correct except I didn't go to three decimal places.
UserIdTAG: 323928
UserNameTAG: Claudelle
CreateTimeTAG: 2013-02-27T22:47:18Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: same here.
FirstChildUserIdTAG: 913981
FirstChildUserNameTAG: DSamuel
FirstChildCreateTimeTAG: 2013-02-28T00:16:33Z
FirstChildVoteTAG: 0
IndexTAG: 2071
TitleTAG: Exercise Set 2, Problem 1
In Exercise Set 2, Problem 1, it reads that "Intervals include the **left endpoint** but not the right. If this is the case, then I thought the answer to Question (b) should have been "5-15" and that of Question(c) should have been "5-year old" but this were not the case since I failed both (b) and (c). Please can anyone help to explain what I did wrong to fail those? Thank you
UserIdTAG: 1111086
UserNameTAG: praisegate
CreateTimeTAG: 2013-02-27T22:40:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: "Crowd" refers to percent per year :
for 5-15 class : crowd = 13.3/10 = 1.33
for 15-20 class : crowd = 7.1/5 = 1.42
Hence, 15-20 class is more crowded.
Also, taking above result, we can conclude that in the 15-20 class no. % per year is more, which implies number of people per year is greater....and so more 15 year olds than 5 year olds.
Does that help in any way?
:)
FirstChildUserIdTAG: 85710
FirstChildUserNameTAG: nileshpatil
FirstChildCreateTimeTAG: 2013-02-27T23:37:53Z
FirstChildVoteTAG: 0
IndexTAG: 2072
TitleTAG: Please
please show how to solve the homework, I had some errors
UserIdTAG: 122393
UserNameTAG: danitoff
CreateTimeTAG: 2013-02-27T22:39:03Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Do you have problems with any specific part of the assignment?
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:09:12Z
FirstChildVoteTAG: 0
IndexTAG: 2073
TitleTAG: How do you check your work?
I got all the practise questions right, and then using the exact same methodology, got all the "real" questions wrong :(
Re-did all my calculations; got the same answers.
How do I figure out what I am doing wrong??
UserIdTAG: 1055945
UserNameTAG: rebecca417
CreateTimeTAG: 2013-02-27T22:35:35Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Probably by showing your calculations to other students and staff here. Someone will surely find and explain any mistakes there.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-28T00:10:06Z
FirstChildVoteTAG: 0
FirstChildTAG: I ask if my answer seems sensible.
For example, if we look at exercise set 3, problem 1, we have the data set and we need to estimate (calculate) the lower and upper quartiles and the median.
To do those, we'll be determining which bin our answer will fall within, and how far across that bin the answer lies. Given the starting and ending percentages that bin covers, does our answer "seem right"?
For a simple case, the first bin covers 6.6% of the people. If we're told to calculate the 5th percentile (5%) we should come up with an answer "most of the way across" that first bin. That makes sense; the bin covers 6.6% (of the total people), and 5% (also of the total people) is most of the way to 6.6.
If we came up with another bin, or only part-way across the first bin, the answer might be suspected to be wrong. (For example, maybe we did 5% of that bin - 5% of 6.6% - instead of 5% of the total.)
If we want the 20th percentile, we'll see that the first two bins cover 19.9% of the total (6.6 + 13.3). So we want just 0.1% more from the next bin. Our answer is going to be very close to the start of that third bin.
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-02-28T01:05:22Z
FirstChildVoteTAG: 0
IndexTAG: 2074
TitleTAG: Exaggerating
Don't exaggerate, people. The answers are congruent and follow a precise and clear logic.
Just pay more attention and stop asking for easier things. There were NO errors in ANY of the three exercise sets.
UserIdTAG: 1036236
UserNameTAG: H4ckJack
CreateTimeTAG: 2013-02-27T22:29:20Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2075
TitleTAG: Problem 4, Exercise 3 grammar
Can someone correct the grammar in this question?
UserIdTAG: 1207647
UserNameTAG: lsummary
CreateTimeTAG: 2013-02-27T22:18:18Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Yay! Another reason to drink.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T22:23:32Z
FirstChildVoteTAG: 2
SecondChildTAG: Week 2 material has been released. What will the drinking game be this week?
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T22:24:33Z
SecondChildVoteTAG: 0
SecondChildTAG:
Please note also that Lec 4.1-4.3 have been uploaded without transcripts. Transcripts will be uploaded in the next day or so, at a conservative estimate.
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-27T23:08:49Z
SecondChildVoteTAG: 0
SecondChildTAG: My thoughts exactly MarianW
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T23:12:51Z
SecondChildVoteTAG: 0
SecondChildTAG: closely followed by "why can't I submit week 1 work, it isn't 11.30pm here yet"?
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-27T23:24:50Z
SecondChildVoteTAG: 0
SecondChildTAG: And the prize goes to MarianW! The flood of "what happened to the submission button" posts have started.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-28T00:15:10Z
SecondChildVoteTAG: 0
FirstChildTAG: i cudnt get what they meant by same scale??
FirstChildUserIdTAG: 432151
FirstChildUserNameTAG: rgdixit
FirstChildCreateTimeTAG: 2013-02-27T22:35:49Z
FirstChildVoteTAG: 0
IndexTAG: 2076
TitleTAG: Estimating percentile from stem and leaf plot?
I got everything right in problem 1 (read: I can calculate percentiles from a table), yet everything wrong in problem 2, so I guess my problem is to transfer the stem and leaf plot to a table I can work with. It seems like it's simple percentage, but why are my calculations wrong then? Any ideas?
UserIdTAG: 1316315
UserNameTAG: Yvi05
CreateTimeTAG: 2013-02-27T22:12:23Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: hello there.. you just need to calculate 20th ,50th & 90th percentile of 28
FirstChildUserIdTAG: 1217519
FirstChildUserNameTAG: addy0506
FirstChildCreateTimeTAG: 2013-02-27T22:17:49Z
FirstChildVoteTAG: 0
SecondChildTAG: List the values if you want - they are in increasing order
calculate totalOfListedItemsIs28 * percentile / 100 = n
E.g. 28 * 20 / 100 = 5.6 => int(5.6) = 5
Take the n_th+1 value of the list as the percentile
SecondChildUserIdTAG: 389424
SecondChildUserNameTAG: jmlietaer
SecondChildCreateTimeTAG: 2013-02-27T22:47:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Does this only apply to stem and leaf diagrams? I had exactly the same issue (as ranted about somewhere below) whereby I took the median to be between the 14th and 15th values - in any other case and according to most stem and leaf guidance on the internet, this would have been correct. I applied the same logic to the 20th and 90th percentiles, arriving at decimal answers for both. Again, to my understanding these would have been correct in any other situation (plus I threw the data at Excel as a speedy option) but they were marked wrong. In fairness, I didn't actually watch any lectures...
SecondChildUserIdTAG: 900978
SecondChildUserNameTAG: MattedPlatypus
SecondChildCreateTimeTAG: 2013-02-27T23:06:50Z
SecondChildVoteTAG: 0
SecondChildTAG: > In fairness, I didn't actually watch any lectures...
You should have. You would have learnt a different method, and it is the method we use in this course.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T23:14:00Z
SecondChildVoteTAG: 0
SecondChildTAG: boo...
SecondChildUserIdTAG: 900978
SecondChildUserNameTAG: MattedPlatypus
SecondChildCreateTimeTAG: 2013-02-27T23:15:22Z
SecondChildVoteTAG: 0
SecondChildTAG: @MattedPlatypus - Thank you for your honesty. I'm not sure I would have admitted that I had not watched the lecture video before asking my fellow students to spoon feed me what I would have learned had I watched the video.
But then, I would have watched the video and tried to understand the material BEFORE asking for assistance. I, for one, am delighted to help people.
SecondChildUserIdTAG: 876324
SecondChildUserNameTAG: BrianDeering
SecondChildCreateTimeTAG: 2013-02-27T23:26:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks very much Brian, I'll be sure to come knocking on your door this time next week. (once I've submitted my work)
Had I banked on the calculation of the median of a data set being redefined, it might have warranted paying more attention. Glad to know you're there though:)
SecondChildUserIdTAG: 900978
SecondChildUserNameTAG: MattedPlatypus
SecondChildCreateTimeTAG: 2013-02-27T23:44:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Did you follow the lecture on this? There is no need to alter the data layout, the stem and leaf is all you need.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T22:18:47Z
FirstChildVoteTAG: 0
IndexTAG: 2077
TitleTAG: Will the second and third parts to this class follow the first?
Hi,
since this is part one of a three part class, I am wondering if the second and third parts will promptly follow the first part? I need to have a full review of stat before I take Summer classes so I need to know if I will need to sign up for another class some place else before Summer if this sequence will not be completed by then.
Thank You!
UserIdTAG: 985667
UserNameTAG: KymberlyKline
CreateTimeTAG: 2013-02-27T22:10:45Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: KymberlyKline, fyi this alternative resource may help in case you can't access the Stat MOOCs you require before your summer deadline.
http://www.openintro.org/stat/
This is an free pdf Intro to Stats textbook. I haven't had a chance to read it myself, but heard that it's a useful good resource.
That OpenIntro site also has optional (not required) free downloadable R code that corresponds to certain parts of the textbook, like homework exercises. R is a widely-used free open source software for statistics/data analysis.
Perhaps Dr. Adhikari or any other Stats experts here on this forum might be able to opine on this OpenIntro stat pdf book, or other alternatives for learning Intro Stats when one is time-constrained by BerkeleyX Stat2.1X sequence's availability.
FirstChildUserIdTAG: 538198
FirstChildUserNameTAG: A_P
FirstChildCreateTimeTAG: 2013-02-27T23:36:29Z
FirstChildVoteTAG: 1
IndexTAG: 2078
TitleTAG: I can't see the histogram picture in the text
I cant see the Histogram of exercise 3.11. Where can I search for it? Is there another media to get it?
UserIdTAG: 72923
UserNameTAG: Jdeleon
CreateTimeTAG: 2013-02-27T22:07:49Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: I can confirm, this is what I see: http://imgur.com/uKhrf8Q
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-27T22:56:05Z
FirstChildVoteTAG: 1
SecondChildTAG: Exactly the same here. Nothing works and I can't practice for the exam. Frustrating as hell. :(
SecondChildUserIdTAG: 1009052
SecondChildUserNameTAG: AgataK
SecondChildCreateTimeTAG: 2013-02-27T23:17:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Apparently it requires Java, and some browsers frequently disable it due to security concerns. So, if you're not worried about all those nasty things that can infect your computer and steal your data, it should be possible for you to enable it somehow…
Other idea is to use sites like https://spoon.net/browsers/ and run a properly configured web browser from there — they claim Java will work, and they claim they sandbox the application, so the nasty things shouldn't be so nasty anymore. I don't know, haven't tried it.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-27T23:32:31Z
SecondChildVoteTAG: 0
SecondChildTAG: same problem.please tell a solution.
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-12T08:24:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Atlast histogram is visible after wasting 1 & 1/2 day on browsers,spoonfed,java etc without any practice for midterm!
SecondChildUserIdTAG: 485682
SecondChildUserNameTAG: arvindsingla
SecondChildCreateTimeTAG: 2013-03-12T10:35:16Z
SecondChildVoteTAG: 0
IndexTAG: 2079
TitleTAG: I can't see histograms
Hi!
Is there someone with the same problem? I checked it on two computers (Windows 7 and Windows XP) with IE, FF and Chrome. Nothing works. I can't do exercises, because I can't see histograms. Can someone help me with it? Please! :)
UserIdTAG: 1009052
UserNameTAG: AgataK
CreateTimeTAG: 2013-02-27T21:58:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2080
TitleTAG: Not Capturing score for the excercise set 1
In the progress page it is not capturing my score for the excercise set 1 is the same thing happening with you also guys
UserIdTAG: 234269
UserNameTAG: Gauravarora
CreateTimeTAG: 2013-02-27T21:51:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Try refreshing the page.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:56:00Z
FirstChildVoteTAG: 0
IndexTAG: 2081
TitleTAG: dates
Hi! I am not sure at what time are the classes and exercises posted? I'd like to know! Thank you very much!
Best regards
UserIdTAG: 896461
UserNameTAG: cecimatho
CreateTimeTAG: 2013-02-27T21:47:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2082
TitleTAG: Week 2
Does anyone has access to week 2 material?
UserIdTAG: 1281597
UserNameTAG: Luisns10
CreateTimeTAG: 2013-02-27T21:42:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2083
TitleTAG: GOOD START
NICE TO HAVE A PRACTICE SECTION, WEEK 1 WAS A SMOOTHIE...I REALLY LOVED THE INTERATIVE BOOK EXERCISES, A NEW THING I SAW ON MOOCS.
CHEERS
UserIdTAG: 201599
UserNameTAG: DELTECH
CreateTimeTAG: 2013-02-27T21:37:56Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2084
TitleTAG: Lec 2.5 transcript
if you can't see transcript for Lec 2.5
download the video
and download subtitle from this link
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/subtitle-files/
UserIdTAG: 287057
UserNameTAG: MohamedZizo
CreateTimeTAG: 2013-02-27T21:37:19Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 0
IndexTAG: 2085
TitleTAG: Can we drop our lowest homework score ?
can we drop one of our lowest homework scores?
UserIdTAG: 247732
UserNameTAG: Snazzy2
CreateTimeTAG: 2013-02-27T21:34:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Seems that you could drop two, as per the x's in the progress page. At least that happened in course CS6.00x (that was from MITx though).
FirstChildUserIdTAG: 250161
FirstChildUserNameTAG: gaurwraith
FirstChildCreateTimeTAG: 2013-02-27T21:37:35Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, looks like there are 2 to drop.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:51:24Z
SecondChildVoteTAG: 0
FirstChildTAG: All this is explained in the course policy! Does no one read this?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:56:55Z
FirstChildVoteTAG: 2
SecondChildTAG: Hi Christine, please keep in mind that not everybody has the time to read everything, nor does everybody remember everything from what they read a week ago. Thus said, if I had that question I probably would search in the course documentation rather than asking in the forum, indeed.
I've been reading some random posts here and there and noticed you are getting (understandably) a bit upset by the careless posting. Try to take it easy, because there are more than 40 thousand people here.
Best regards, Gaur.
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-28T01:37:02Z
SecondChildVoteTAG: 0
IndexTAG: 2086
TitleTAG: Height?
In Problem Six, you don't really mean 'height' in the right column, do you?
UserIdTAG: 1136968
UserNameTAG: susanmack
CreateTimeTAG: 2013-02-27T21:31:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Height refers to the height of the bars in the histogram, which corresponds to percent per hours.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T21:47:50Z
FirstChildVoteTAG: 0
IndexTAG: 2087
TitleTAG: point a
hallo,
about width of class interval for the first exemple I think that the width equal 20 - (-10)= 30 so the bin = 14/30= 0.46
UserIdTAG: 772973
UserNameTAG: nadjou
CreateTimeTAG: 2013-02-27T21:28:18Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Just off to replenish the gin.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:42:59Z
FirstChildVoteTAG: 1
SecondChildTAG: Cheers to that!
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T21:54:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Took the same approach.
SecondChildUserIdTAG: 913981
SecondChildUserNameTAG: DSamuel
SecondChildCreateTimeTAG: 2013-02-28T00:18:10Z
SecondChildVoteTAG: 0
IndexTAG: 2088
TitleTAG: really need captions for each lecture
I'm seeing no captions for lecture 2.5. I am hearing impaired and depend on the captions to follow the lecture.
Can a staff member please fix this?
Thank you.
UserIdTAG: 1281619
UserNameTAG: sfc17
CreateTimeTAG: 2013-02-27T21:16:55Z
VoteTAG: 4
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 1
FirstChildTAG: Hi sfc17 -- There are captions for this lecture in YouTube. Currently, a technical difficulty is preventing the sidebar transcript, which the staff is working on, but if you have close captioning on, you should still have access to those.
FirstChildUserIdTAG: 1197233
FirstChildUserNameTAG: maari13
FirstChildCreateTimeTAG: 2013-02-27T21:58:55Z
FirstChildVoteTAG: 0
IndexTAG: 2089
TitleTAG: Problem 5 and all Problem
Please at least give more than 1 try. Strongly suggest than problem with calculation give more try rather than only 1 try.
I agree yes and no question , no point to give more than 1 point. Is that so do not ask this type of question, change a little bit like multiple choice question, or give question with some calculation only at least.
UserIdTAG: 7980
UserNameTAG: Nazri
CreateTimeTAG: 2013-02-27T21:15:34Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2090
TitleTAG: Please let us know how to answer.
It would be helpful if, for the percentage questions, the directions told us to round our answer to the nearest tenth.
UserIdTAG: 750543
UserNameTAG: JTausiani
CreateTimeTAG: 2013-02-27T21:05:49Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2091
TitleTAG: Can we have a calcultor ?
In the chemistry class I took last semester- there was a calculator. It was nice having that to click on during quizzes and homework. I keep looking down at the lower left corner hoping to see a calculator.
I may not stay in the class, but I know others will probably want this calculator also. Thanks, Snazzy.
UserIdTAG: 247732
UserNameTAG: Snazzy2
CreateTimeTAG: 2013-02-27T21:03:33Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: doesn't your operating system come with a built-in calculator?
But you are right that a couple of edX courses were supplied with a calculator.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-27T21:11:39Z
FirstChildVoteTAG: 0
SecondChildTAG: I'm guessing that anyone with the skills to sign up and take this course has access to a calculator alternative. However, the edx provided calculator appears to be a standard component of the edx interface and I find it to be extremely convenient.
SecondChildUserIdTAG: 174100
SecondChildUserNameTAG: markpolak
SecondChildCreateTimeTAG: 2013-02-27T22:02:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, I have one. It's easier with the calculator already on the webpage.
SecondChildUserIdTAG: 247732
SecondChildUserNameTAG: Snazzy2
SecondChildCreateTimeTAG: 2013-02-28T02:01:32Z
SecondChildVoteTAG: 0
FirstChildTAG: +1!
FirstChildUserIdTAG: 279867
FirstChildUserNameTAG: Lisenik
FirstChildCreateTimeTAG: 2013-02-28T10:56:27Z
FirstChildVoteTAG: 0
IndexTAG: 2092
TitleTAG: waiting for the correction of the answers
????????????????????
UserIdTAG: 1292897
UserNameTAG: DrMahmut
CreateTimeTAG: 2013-02-27T21:02:26Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The deadline is still more than 2 hours away. Can you wait a bit longer?
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T21:03:27Z
FirstChildVoteTAG: 2
SecondChildTAG: well, he has no choice ;)
SecondChildUserIdTAG: 1053569
SecondChildUserNameTAG: nicola2003
SecondChildCreateTimeTAG: 2013-02-27T21:11:24Z
SecondChildVoteTAG: 0
SecondChildTAG: What timezone is the deadline in?
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-27T22:57:36Z
SecondChildVoteTAG: 0
SecondChildTAG: deadline is in GMT
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T23:03:56Z
SecondChildVoteTAG: 0
IndexTAG: 2093
TitleTAG: Q 1b: ????
Can anyone please explain why categorical is incorrect for q1B ???
UserIdTAG: 508471
UserNameTAG: TreborR
CreateTimeTAG: 2013-02-27T20:59:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Because we can do arithmetic operation on the score (e.g. use Total Score of a whole test which is a sum of score of each answer).
FirstChildUserIdTAG: 610852
FirstChildUserNameTAG: maMykola
FirstChildCreateTimeTAG: 2013-02-27T21:12:19Z
FirstChildVoteTAG: 0
IndexTAG: 2094
TitleTAG: Error SticiGui Chapter 2
Example 2-6 It should be ad misericordiam not ad misericordium. Slight Latin advantage of a Catholic theologian :)
UserIdTAG: 355018
UserNameTAG: randiriel
CreateTimeTAG: 2013-02-27T20:50:32Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: One of many advantages! (Also very helpful doing crossword puzzles ...but rarely comes up in spoken casual conversation anymore ...)
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-27T21:56:02Z
FirstChildVoteTAG: 0
IndexTAG: 2095
TitleTAG: Problems 6 and 7
The answers to problems 6 and 7 cannot be determined because we are not told the total number of students involved.
UserIdTAG: 1251292
UserNameTAG: clementbewaji
CreateTimeTAG: 2013-02-27T20:50:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: In this problem you don't need to know the total number of students involved to answer the question. The height of the bars shows percent per hour. You use this to determine the percent of students who spent <4 hours.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T21:02:21Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, they can. You know the formula to calculate the height. Work backwards.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:24:58Z
FirstChildVoteTAG: 0
FirstChildTAG: To answer questions 6 and 7, you have to know how to calculate the Area and the height of the bar or interval.
Area = height * width
Area = height * (right endpoint - left endpoint)
Height = Area / width
Height = Area / (right endpoint - left endpoint)
You can find those formulas in the lecture videos. The key ingredient here is you have to understand what the questions are asking for. What is question 6 looking for? And question 7?
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-27T21:46:29Z
FirstChildVoteTAG: 0
IndexTAG: 2096
TitleTAG: STAFF/FINAL EXAM
To the Professors:
Thank you for a wonderful learning experience - in all aspects. The final exam is scheduled for Passover. Is there any chance it might be rescheduled, or be available over more than a single day? Thank you.
UserIdTAG: 310963
UserNameTAG: TwinOtter
CreateTimeTAG: 2013-02-27T20:45:46Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2097
TitleTAG: A bug
(: Hi,
the app allows you to submit the test without checking an answer..
It should alert you first (that you've missed a question)
As in the moment it counts the unanswered/empty questions as incorrect
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-27T20:42:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2098
TitleTAG: Practice for Exercise vs. exercise set?
I hope that only exercise set is graded, because I am more relaxed doing "practice" therefore I am scoring less points on it.
Is that 'ok?
PS: I am 46years old psychiatrist with PhD and I don't remember being so anxious doing homework :-)
UserIdTAG: 908509
UserNameTAG: Sjanovic
CreateTimeTAG: 2013-02-27T20:33:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Don't worry, practice exercises do not count towards your score in the course.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T20:35:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Thx
SecondChildUserIdTAG: 908509
SecondChildUserNameTAG: Sjanovic
SecondChildCreateTimeTAG: 2013-02-27T20:37:00Z
SecondChildVoteTAG: 0
IndexTAG: 2099
TitleTAG: WEEK 2
HOW CAN ACCEDE TO WEEK 2!?
UserIdTAG: 1130399
UserNameTAG: RafaelHMM
CreateTimeTAG: 2013-02-27T20:30:48Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: *facepalm*
FirstChildUserIdTAG: 319056
FirstChildUserNameTAG: cydrus88
FirstChildCreateTimeTAG: 2013-02-27T20:31:52Z
FirstChildVoteTAG: 1
FirstChildTAG: How to get access to Week 2:
Step 1. Wait until it's released...
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T20:31:58Z
FirstChildVoteTAG: 3
FirstChildTAG: LOL. I suppose we will go through this every week too.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:34:53Z
FirstChildVoteTAG: 1
SecondChildTAG: Well, to be fair to those asking about Week 2, the schedule does say that Week 2 begins on Feb 27, which is today.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T21:52:24Z
SecondChildVoteTAG: 0
FirstChildTAG: two hours to 28th.
Is there any problem with week 2?? I still can't access
FirstChildUserIdTAG: 961907
FirstChildUserNameTAG: ngarin
FirstChildCreateTimeTAG: 2013-02-27T20:59:42Z
FirstChildVoteTAG: 1
SecondChildTAG: We seem to be losing a day.
SecondChildUserIdTAG: 1296057
SecondChildUserNameTAG: Davidgriffin10
SecondChildCreateTimeTAG: 2013-02-27T21:18:29Z
SecondChildVoteTAG: 0
IndexTAG: 2100
TitleTAG: setback
Hi everyone
I am very happy to start taking the statistics class. I couldn't start because i had some setback. Is there a specific time to attend the online session and submit assignment? I am ready to start but i am waiting for a quick response to my concern.
UserIdTAG: 1237746
UserNameTAG: sineusda
CreateTimeTAG: 2013-02-27T20:29:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: No but the deadline for the exercises is today so I think that you need to hurry a little bit, I completed all of the exercises today.
FirstChildUserIdTAG: 319056
FirstChildUserNameTAG: cydrus88
FirstChildCreateTimeTAG: 2013-02-27T20:32:57Z
FirstChildVoteTAG: 0
FirstChildTAG: > I am ready to start
Then I hope you already started.
>but i am waiting for a quick response to my concern.
Read the course documents for instructions.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:18:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Passing grade is low anyway, so you should be OK even if you can't
complete all the first exercises.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-27T21:21:38Z
FirstChildVoteTAG: 0
IndexTAG: 2101
TitleTAG: exercise set 3
how can i get the lower quartile of exers 3
UserIdTAG: 442102
UserNameTAG: fridexcool
CreateTimeTAG: 2013-02-27T20:27:41Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2102
TitleTAG: A wrong graph to illustrate a point
Great lesson. I confess that this is the first time I realize that bin areas in histograms *must* represent a meaningful quantity (in this case, percents.)
To that end, here's a suggestion to make this lesson even better: before calculating the areas, simply plot the quantities given originally, and ask the audience to think what's wrong with the picture. Here's what I mean:
![Wrong and right histograms][1]
[1]: https://edxuploads.s3.amazonaws.com/13619967781343663.jpg
UserIdTAG: 1152094
UserNameTAG: CristianOpazo
CreateTimeTAG: 2013-02-27T20:26:55Z
VoteTAG: 2
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 1
FirstChildTAG: Wow nice, that's a good way of looking at it!
FirstChildUserIdTAG: 838733
FirstChildUserNameTAG: Ronnicus
FirstChildCreateTimeTAG: 2013-03-09T21:42:08Z
FirstChildVoteTAG: 0
IndexTAG: 2103
TitleTAG: No captions for lecture 2.5?
I'm seeing no captions for lecture 2.5. I am hearing impaired and depend on the captions to follow the lecture.
Can a staff member please fix this?
Thank you.
UserIdTAG: 1281619
UserNameTAG: sfc17
CreateTimeTAG: 2013-02-27T20:23:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2104
TitleTAG: How to accede to "Next Section"
The bar on the top allows to go backwards but not to continue to next section. Please help to manage in general how to move about lectures, sections, chapters, etc.
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-02-27T20:16:56Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 1
FirstChildTAG: There's a menu on the left-hand side of the screen. Click on "Section 2b." Hope that helps.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T20:24:24Z
FirstChildVoteTAG: 0
SecondChildTAG: The manu does't appears always. Not in this case
SecondChildUserIdTAG: 1291666
SecondChildUserNameTAG: norabram
SecondChildCreateTimeTAG: 2013-02-27T20:28:08Z
SecondChildVoteTAG: 0
IndexTAG: 2105
TitleTAG: Stop complaining
I do not understand why people complain so much about everything. The way i see it everything was clearly explained. (When we supposed to write one decimal or two) and even if i did not score the highest in all of them i did very good. I think the problem lies in knowing how to read and being a little bit resourceful.
Thanks for this great course and i hope many of you are enjoying it as much as i do.
Cheers
UserIdTAG: 1256931
UserNameTAG: Jhoara
CreateTimeTAG: 2013-02-27T20:08:11Z
VoteTAG: 14
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2106
TitleTAG: No. 3b complaint
No.3b must be well reviewed to be sincere. I think A is correct, considering the arrangement in the question.
UserIdTAG: 1322834
UserNameTAG: Professor-Imoren
CreateTimeTAG: 2013-02-27T20:05:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Why do you think so? a whole lot more includes 'green' than 'no green', so the first bar must be taller, no?
FirstChildUserIdTAG: 953527
FirstChildUserNameTAG: Marton
FirstChildCreateTimeTAG: 2013-02-27T20:07:31Z
FirstChildVoteTAG: 0
SecondChildTAG: There are a duplicate answer (2 ad 4, maybe should have an invertion of the x-axis at one of that alternatives.
SecondChildUserIdTAG: 1279942
SecondChildUserNameTAG: viniciusvgc
SecondChildCreateTimeTAG: 2013-02-27T20:21:01Z
SecondChildVoteTAG: 0
SecondChildTAG: 2 and 4 have very similar graph, but not exacly the same. Look at the y-axis. However, I still agree that the x-axis should be changed to find the correct answer...
SecondChildUserIdTAG: 1121606
SecondChildUserNameTAG: CarlaBrS
SecondChildCreateTimeTAG: 2013-02-27T20:45:12Z
SecondChildVoteTAG: 0
FirstChildTAG: Look at the label for the y-axis.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T20:37:23Z
FirstChildVoteTAG: 0
FirstChildTAG: ahh, my teachers always told me to look at all the possible answers before picking one. However, it would help of the text on all the graphs were larger and easier to read.
FirstChildUserIdTAG: 1020498
FirstChildUserNameTAG: cgorski
FirstChildCreateTimeTAG: 2013-02-27T21:04:35Z
FirstChildVoteTAG: 0
IndexTAG: 2107
TitleTAG: MUST READ !!! Guidelines for Stat2x Discussion Forum
Guidelines for Stat2x Discussion Forum
--------------------------------------
The discussion forum helps improve your ability to search and talk about many different topics throughout the course.
Here are some friendly guidelines to help you successfully navigate and interact on the forum:
1. On each page, there is a link at the bottom which says “show
discussion.” Clicking on this link will show all the discussion on
the forum associated with this particular video or problem.
2. Be very specific about where you need help. Are you stuck on a
particular part of the problem? Do you need help understanding a
particular concept? What have you tried doing so far?
3. Please do not post problem solutions. If you need help, post errors
you’re encountering, but not your answers.
4. Use a descriptive and specific title to your post. This will attract
the attention of other students having the same issue.
5. Actively upvote other posts, and other students will upvote yours!
The more upvotes your posts have, the more likely they are to be
seen.
6. Use the search button. Many of your course classmates are likely to
have the same questions. If you perform a search for the question
first, you may find the question and answer without needing to post
it yourself.
7. Use “netiquette,” or common writing practices for online
communication. For example:
- Avoid TYPING IN ALL CAPS. Some people read this as shouting, even if that is not what you mean to convey.
- Avoid unnecessary symbols, abbreviated words, texting shorthand, and replacing words with numbers (e.g. Pls don’t rplce wrds w/#s).
- Avoid repeating letters or characters like this: reeepeeaattingggg chaaracterrrss
- Avoid excessive punctuation if possible (e.g. !!!!!!!! or ??????)
- It’s fine to make suggestions, but avoid negative commentary and please do not “flame” anyone.
UserIdTAG: 610852
UserNameTAG: maMykola
CreateTimeTAG: 2013-02-27T19:58:04Z
VoteTAG: 11
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes, a must read. But as you have noticed those who *should* read it, haven't. And won't.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:14:40Z
FirstChildVoteTAG: 3
SecondChildTAG: Yes, it is much easier to ask the question "Why doesn't work" rather than trying to find the answer.
SecondChildUserIdTAG: 610852
SecondChildUserNameTAG: maMykola
SecondChildCreateTimeTAG: 2013-02-27T21:20:12Z
SecondChildVoteTAG: 0
SecondChildTAG: my experience so far with edX is that those students usually end up quitting the course before half of the syllabus is completed.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:24:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Haha. So right!
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-27T21:25:06Z
SecondChildVoteTAG: 0
IndexTAG: 2108
TitleTAG: problem 3a
Sorry, How many decimal numbers do we have to write?? Thank you!
UserIdTAG: 1252051
UserNameTAG: Stefymonte
CreateTimeTAG: 2013-02-27T19:44:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: a) About what percent of the people were in their thirties? **Round your answer to one decimal place.**
FirstChildUserIdTAG: 610852
FirstChildUserNameTAG: maMykola
FirstChildCreateTimeTAG: 2013-02-27T19:47:32Z
FirstChildVoteTAG: 0
IndexTAG: 2109
TitleTAG: Pie chart?
Can histogram plotted in this lecture better be shown in a pie chart?
UserIdTAG: 1136968
UserNameTAG: susanmack
CreateTimeTAG: 2013-02-27T19:42:24Z
VoteTAG: 1
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 2
FirstChildTAG: With a pie chart you miss out on the benefit of the two axis system.
FirstChildUserIdTAG: 1296057
FirstChildUserNameTAG: Davidgriffin10
FirstChildCreateTimeTAG: 2013-02-27T19:51:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Yea I dunno- I think that they would be about the same. The pie chart is no doubt simpler, but then you miss out of things like the density vertical axis.
FirstChildUserIdTAG: 838733
FirstChildUserNameTAG: Ronnicus
FirstChildCreateTimeTAG: 2013-03-09T21:45:28Z
FirstChildVoteTAG: 0
IndexTAG: 2110
TitleTAG: lec 2.2 2.3 section
In q. b) the width of the class interval between -10 to 20 is 30 units
UserIdTAG: 409724
UserNameTAG: geet-gec
CreateTimeTAG: 2013-02-27T19:42:06Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Yes!
20 - (- 10) = 30
(14/30)=0.466
FirstChildUserIdTAG: 1031994
FirstChildUserNameTAG: Andrea33
FirstChildCreateTimeTAG: 2013-02-27T19:52:09Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks Andrea, but I want to know how we acquired the value of Relative frequency as 14 or % as 14.
SecondChildUserIdTAG: 1152224
SecondChildUserNameTAG: ram_ji
SecondChildCreateTimeTAG: 2013-02-27T20:49:59Z
SecondChildVoteTAG: 0
SecondChildTAG: I am also confused about that value, ram_ji. Where does the 14 come from?
SecondChildUserIdTAG: 1212754
SecondChildUserNameTAG: Kmowmow
SecondChildCreateTimeTAG: 2013-02-27T23:58:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you! Now I get to have a drink with lunch.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T20:02:19Z
FirstChildVoteTAG: 2
SecondChildTAG: Breakfast time for me. My poor liver.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T21:11:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Hair of the dog...
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T22:04:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks Andrea, but I want to know how we acquired the value of Relative frequency as 14 or % as 14.
FirstChildUserIdTAG: 1152224
FirstChildUserNameTAG: ram_ji
FirstChildCreateTimeTAG: 2013-02-27T21:05:02Z
FirstChildVoteTAG: 0
IndexTAG: 2111
TitleTAG: AHM
Inconsistent exercises, wrong answers in practice exercises makes coherent learning more difficult. Need to improve on the quality of materials and examples.
UserIdTAG: 1242398
UserNameTAG: Mawadic
CreateTimeTAG: 2013-02-27T19:36:30Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2112
TitleTAG: Problem with x of y submissions
Problem 2 states that one has two submissions for an answer. The first answers I put in for the first two parts were incorrect. I quickly realized my mistake, clicked on a work e-mail that had popped up in Outlook, and when I came back to input the correct responses, the message changed to "You have used 2 of 2 submissions" and I was unable to correct my mistakes. I realize this may be a question for the tech folks at Edx, but I was wondering if there's any way to avoid this other than staying only on the page while in the middle of a question (and therefore not doing the problems while on lunch break at work). I had the same issue in the second set of questions, and I would love to avoid the problem going forward. Thank you!
UserIdTAG: 1124700
UserNameTAG: Hanlon
CreateTimeTAG: 2013-02-27T19:33:37Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2113
TitleTAG: Rah!
Have they redefined the median or something? In a data set of 28 values, would it not lie between the 14th and 15th values? i.e. 50% of data either side....
UserIdTAG: 900978
UserNameTAG: MattedPlatypus
CreateTimeTAG: 2013-02-27T19:30:14Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: Did you watch the videos at all? They are very clear about this.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T19:37:36Z
FirstChildVoteTAG: 3
SecondChildTAG: Well it's exactly for that reason that I didn't get this answer right either. I watched the videos and therefore thought the answer would be the 15th value yet the right answer is the 14th value. But in the slide it said: "The pth percentile of a list of numbers is the smallest number that is at least as large as p% of the list." Which I would say is the 15th value not the 14th... But please explain to me why I misunderstood this.
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-02-27T22:35:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Haha, I watched one of the videos after I'd got it wrong... which one was it out of interest?
SecondChildUserIdTAG: 900978
SecondChildUserNameTAG: MattedPlatypus
SecondChildCreateTimeTAG: 2013-02-27T22:36:08Z
SecondChildVoteTAG: 0
SecondChildTAG: It was the last Lecture
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-02-27T22:48:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually, if you took the 14th value to be the median, 100(13/28)% of the data would lie below it and 100(14/28)% above. It's not 50% either way, nor would it be if you took the 15th value to be the median. Surely the median, by definition, lies in the middle of the data set. If there's an even number of data points, it'll be between the two middle ones. Excel says so, Google says so... christ, school said so.
Seems like a case of dumbing down to me.
jpnijman - I feel your pain!
SecondChildUserIdTAG: 900978
SecondChildUserNameTAG: MattedPlatypus
SecondChildCreateTimeTAG: 2013-02-27T23:00:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Lol 100(14/28) is exactly 50%, I don't know why you say it isn't. The error came down to rounding down the numbers earlier in the exercise, which explains why I didn't get to 50% with the 14th value. Which, why at first I thought it would be 15, the 15th value would be at least as large as p%. Anyway problem solved.
SecondChildUserIdTAG: 1240204
SecondChildUserNameTAG: jpnijman
SecondChildCreateTimeTAG: 2013-02-27T23:22:11Z
SecondChildVoteTAG: 0
SecondChildTAG: 100(14/28) is 50%, but 100(13/28) isn't - if you take the 14th data point out of a set of 28 values, the number of values either side of it isn't equal. Therefore, it's not the true median. I say tomato, they say tomatoe
SecondChildUserIdTAG: 900978
SecondChildUserNameTAG: MattedPlatypus
SecondChildCreateTimeTAG: 2013-02-27T23:33:23Z
SecondChildVoteTAG: 0
SecondChildTAG: MattedPlatypus I learned it the same way as you in high school, but the definition is clear here throughout all the material and we are told in the video and that it makes sense to define it this way when more advanced mathematical calculations are required (for reasons that are not yet fully explained). So, I'm just going to do what the Professor says and I'm guessing that eventually we'll understand why it's like this. I'm guessing they know a fair bit more than us about statistics. It's definitely harder to unlearn previous concepts than learn new ones, especially when you don't have all the info. I'm with you there.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-28T02:00:00Z
SecondChildVoteTAG: 0
FirstChildTAG: Print out the slides. She goes through this in great detail.
FirstChildUserIdTAG: 1296057
FirstChildUserNameTAG: Davidgriffin10
FirstChildCreateTimeTAG: 2013-02-27T19:40:01Z
FirstChildVoteTAG: 0
SecondChildTAG: slides?
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-27T19:50:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Sansquamtch: slides are available for each lecture, there are links beneath each of the lecture videos :-)
SecondChildUserIdTAG: 1290327
SecondChildUserNameTAG: CorinneH
SecondChildCreateTimeTAG: 2013-02-27T21:00:52Z
SecondChildVoteTAG: 0
SecondChildTAG: cool, thanks =)
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-28T03:51:17Z
SecondChildVoteTAG: 0
FirstChildTAG: it isn't the 14th ?
the definition used to explain that is on the slides, i think it's when Ani said that we can read the definition but she would read it anyway, after that she gives an "re explanation on english" for better understanding.
FirstChildUserIdTAG: 1153259
FirstChildUserNameTAG: Thiago_NascimentoBR
FirstChildCreateTimeTAG: 2013-02-27T20:06:25Z
FirstChildVoteTAG: 0
FirstChildTAG: I really do believe that people are not watching the lectures.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:10:28Z
FirstChildVoteTAG: 0
SecondChildTAG: or searching and reading the already posted topics in this forum, or reading and obeying the discussion forum guidelines, or upholding the edX honor code.
Yes, I agree with you. :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:14:16Z
SecondChildVoteTAG: 0
IndexTAG: 2114
TitleTAG: Base seven?
If as stated in the lecture there might be a case of groups of sevens rather than tens for the stem and leaf plot, can graph be broken into base seven?
UserIdTAG: 1136968
UserNameTAG: susanmack
CreateTimeTAG: 2013-02-27T19:25:37Z
VoteTAG: 2
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.1. Describing one quantitative variable
NumberOfReplyTAG: 2
FirstChildTAG: I don't think so. Unless you created your own base seven number system for it (in which case I'm not sure it would be very intuitive to look at). I think the example was given to show when it wouldn't be useful to use a stem and leaf diagram.
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-02-27T19:39:24Z
FirstChildVoteTAG: 0
FirstChildTAG: If you're doing it manually, it will be easy for you to make a mistake and assign a value to the wrong row, people who'll try to read it will also need additional explanation—and stem and leaf plot was meant to be simple.
You might just want to plot a histogram with equal bin widths anyway.
FirstChildUserIdTAG: 1097026
FirstChildUserNameTAG: aiS2ru
FirstChildCreateTimeTAG: 2013-02-27T23:03:11Z
FirstChildVoteTAG: 1
IndexTAG: 2115
TitleTAG: important
I need help about this course;the percentile.thank you
UserIdTAG: 1093938
UserNameTAG: Douna
CreateTimeTAG: 2013-02-27T19:24:23Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/search?text=percentile
FirstChildUserIdTAG: 610852
FirstChildUserNameTAG: maMykola
FirstChildCreateTimeTAG: 2013-02-27T20:07:17Z
FirstChildVoteTAG: 0
SecondChildTAG: Don't forget to take into account the percentage each interval has when calculating. That was my mistake :P
SecondChildUserIdTAG: 1018933
SecondChildUserNameTAG: IsisN
SecondChildCreateTimeTAG: 2013-02-27T21:16:55Z
SecondChildVoteTAG: 0
IndexTAG: 2116
TitleTAG: Income isn't discrete?
still not clear on that first one, it seems like monetary units have limited divisibility, maybe I misread what "minimum distance" is...
I figure it's dollars, cents, and if you're being ripped off by a gas station, tenths of cents, but nobody i know gets paid in infinitely small portions of pennies. Money has discrete units, right?
any help?
UserIdTAG: 1312416
UserNameTAG: flaerebear
CreateTimeTAG: 2013-02-27T19:10:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: I struggled with all of those questions.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T19:21:07Z
FirstChildVoteTAG: 1
SecondChildTAG: in exercise set 1, "income" without further precision should be categorical in my opinion. It could be a distribution according to "high, low, middle" income as well as income expressed in USD or euros. If the "measurement" unit is not indicated, shouldn't it be considered categorical (categorical is considered not correct in the exercise)?
SecondChildUserIdTAG: 780211
SecondChildUserNameTAG: ruxandrabp
SecondChildCreateTimeTAG: 2013-02-27T19:45:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I guess you are right, except she uses the word "natural" a lot in the intro, and for me at least, the natural way to think of income is not the high middle low framing you mention (albeit correct) but the pure monetary stuff - number of euros, precise to the cent even... at least when it comes to what I get from my employer :)
SecondChildUserIdTAG: 953527
SecondChildUserNameTAG: Marton
SecondChildCreateTimeTAG: 2013-02-27T20:09:59Z
SecondChildVoteTAG: 0
FirstChildTAG: Its discrete. No one gets paid fractions of pennies. The numbers stop, they don't get more specific than .01.
FirstChildUserIdTAG: 1270408
FirstChildUserNameTAG: armencho
FirstChildCreateTimeTAG: 2013-02-27T19:44:27Z
FirstChildVoteTAG: 0
SecondChildTAG: for most people thats true, but there is indeed stuff in the world (low value bulk stuff) that may be priced at less then a cent/piece. plus, with lots of lower value currencies, a cent can always be divided into further 'pennies'
SecondChildUserIdTAG: 953527
SecondChildUserNameTAG: Marton
SecondChildCreateTimeTAG: 2013-02-27T20:11:40Z
SecondChildVoteTAG: 0
FirstChildTAG: Feel free to correct me, but I think you are technically right - money is discretized in units of $0.01. But for practical purposes here, income is continuous (there are 100,000 cents in a thousand dollars). If the data were very low prices, like the cost of a postage stamp then it might be more borderline. The lecturer did say that the distinction between discrete and continuous is not absolute.
I suppose that any measured data are going to have some degree of discretization (since it is not possible to measure anything to an infinite degree of precision). The issue, I think, is whether or not the precision of the measurement is much less than the quantity of interest.
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-02-27T19:53:30Z
FirstChildVoteTAG: 2
SecondChildTAG: yeah, but I want my point back on the exercise set :p
SecondChildUserIdTAG: 1312416
SecondChildUserNameTAG: flaerebear
SecondChildCreateTimeTAG: 2013-02-28T22:51:59Z
SecondChildVoteTAG: 0
FirstChildTAG: I found this embedded in the solution to Exercise 3-1 on variables (I have added bold and italics on the important bit):
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#variables
"The type of tree is a categorical variable without a natural order—it does not make sense to say that "Elm" is larger than "Oak." Per-capita incomes in different countries could be viewed as a discrete or continuous quantitative variable. Certainly, the number of people in a country is discrete (it is an integer), and if you view money as having a smallest unit (for example, a cent in the USA), then per-capita income is a rational number (a fraction). Because fractions are countable, per-capita income would be discrete. ***For all practical purposes, however, per-capita income could be treated as a continuous quantitative variable***. Weight, divided into ranges, is an ordinal variable: someone whose weight is in the range 100 lbs to 200 lbs. weighs more than someone whose weight is less than 100 lbs. Weight to the nearest pound is an integer, so that variable is discrete. There is a smallest unit of currency in every country, so bank account balances are discrete."
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T20:54:42Z
FirstChildVoteTAG: 2
FirstChildTAG: I remember that I did read about some group of guys getting rich by siphoning off fractions of cents from bank transactions so money could very well be seen as "continuous"
FirstChildUserIdTAG: 838733
FirstChildUserNameTAG: Ronnicus
FirstChildCreateTimeTAG: 2013-03-07T23:20:51Z
FirstChildVoteTAG: 0
IndexTAG: 2117
TitleTAG: TO Ani Adhikari
From Pa3cr@aol.com
I would like to withdraw from the course. I have an emergency in my Family. I will enroll at another time. Thank you
UserIdTAG: 900614
UserNameTAG: pa3cr
CreateTimeTAG: 2013-02-27T19:08:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2118
TitleTAG: Is a some kind of mistake
At exercise a) the 20-(-10)=30, not 10
UserIdTAG: 1263834
UserNameTAG: Vasylyna
CreateTimeTAG: 2013-02-27T19:00:53Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: Yes, it is a mistake =)
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T19:03:51Z
FirstChildVoteTAG: 0
FirstChildTAG: Okay, so I am not the only one... Felt rather stupid for a second.
FirstChildUserIdTAG: 389362
FirstChildUserNameTAG: suttyo
FirstChildCreateTimeTAG: 2013-02-27T19:12:51Z
FirstChildVoteTAG: 1
FirstChildTAG: this stuff is confusing enough; I'm glad I'm not alone here.
FirstChildUserIdTAG: 950367
FirstChildUserNameTAG: catt9
FirstChildCreateTimeTAG: 2013-02-27T20:24:10Z
FirstChildVoteTAG: 0
FirstChildTAG: Hic hic hic
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:09:36Z
FirstChildVoteTAG: 1
SecondChildTAG: Now I'm going to get in trouble for drinking at work :(
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T22:08:22Z
SecondChildVoteTAG: 0
IndexTAG: 2119
TitleTAG: Question 4 c
can anyone explain question 4 part c
UserIdTAG: 1078818
UserNameTAG: Jamili
CreateTimeTAG: 2013-02-27T18:55:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Google Uniform Distribution, than go from there. I had a hard time with this one as well, but there is a 50/50 chance of getting it right! =P
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T19:11:25Z
FirstChildVoteTAG: 0
SecondChildTAG: The example she gave was rolling a dice. You are just as likely to get a 6 as you are to get a one. This is uniform because all numbers could be rolled at an equal rate. Not sure if that helps any.
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-27T19:14:37Z
SecondChildVoteTAG: 0
SecondChildTAG: while ppl may drop out of school on the way towards completing it, it is much much less likely (according to my observations at least) than for people to stop going to school after a certain degree (high school, bachelor, etc) has just been achieved. hence, with these arbitrary looking years (not corresponding to real life academic levels) you would exect most people to fall at the year which corresponds to the completion of a degree, hence no uniform distribution. Well, at least thats how I rationalized it..
SecondChildUserIdTAG: 953527
SecondChildUserNameTAG: Marton
SecondChildCreateTimeTAG: 2013-02-27T21:47:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Part (a) says In the United States, high school diplomas are awarded **after 12 years of schooling.** Part (b) states Bachelor’s degrees are awarded to those who successfully complete **four years** of education at a college or university **after high school.** This means there is no uniform number of years to attain different education level. And therefore it can not be said that x% of students completed 12 years, the same number completed 13 years, 14 years and so on as many fail, drop out, pursue different degrees/diplomas.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T19:38:50Z
FirstChildVoteTAG: 0
SecondChildTAG: I don't think you are supposed to give the answer yet.
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-27T19:43:54Z
SecondChildVoteTAG: 0
FirstChildTAG: This is partly a question of looking at what is being tracked and asking whether or not the distribution would be smooth or lumpy. Given the nature of education, there will be clusters at milestones. For instance, knowing that HS graduates are all lumped at the beginning of the 12/13 group suggests more in the 12 year group than 13.
FirstChildUserIdTAG: 1268832
FirstChildUserNameTAG: johnpsheppard
FirstChildCreateTimeTAG: 2013-02-27T19:48:27Z
FirstChildVoteTAG: 1
IndexTAG: 2120
TitleTAG: Deadline change
I know the deadline for the exercises was changed to every Wednesday but is there a certain time all exercises should be completed by?
UserIdTAG: 1268534
UserNameTAG: amdesigns
CreateTimeTAG: 2013-02-27T18:54:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: 11:30PM I believe. I am not sure is that Pacific or Eastern though.
FirstChildUserIdTAG: 1296057
FirstChildUserNameTAG: Davidgriffin10
FirstChildCreateTimeTAG: 2013-02-27T18:58:57Z
FirstChildVoteTAG: 0
SecondChildTAG: GMT
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-27T19:06:44Z
SecondChildVoteTAG: 0
SecondChildTAG: On our Landing Page, click on "Course Policies and Requirements" (grey vertical bar on right hand side of page).
**Grading**
● Exercise Sets are due at specified dates and times. All times are in Greenwich Mean Time (GMT).
SecondChildUserIdTAG: 1310109
SecondChildUserNameTAG: COELHO50
SecondChildCreateTimeTAG: 2013-02-27T19:26:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Cheers
SecondChildUserIdTAG: 1296057
SecondChildUserNameTAG: Davidgriffin10
SecondChildCreateTimeTAG: 2013-02-27T19:53:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Yeah can anyone actually tell me 11.30 PM is according to which time zone?
FirstChildUserIdTAG: 927632
FirstChildUserNameTAG: mukulgupta
FirstChildCreateTimeTAG: 2013-02-27T19:24:53Z
FirstChildVoteTAG: 0
SecondChildTAG: GMT, your time zone might say something like +X GMT o -X GMT, mine is -6GMT, it means for me the time would be 5:30pm today.
SecondChildUserIdTAG: 26776
SecondChildUserNameTAG: aleguillen
SecondChildCreateTimeTAG: 2013-02-27T19:57:37Z
SecondChildVoteTAG: 0
FirstChildTAG: > Yeah can anyone actually tell me 11.30 PM is according to which time zone?
As I seem to be saying a lot - did you read the course policy documents. All this is in there.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:09:08Z
FirstChildVoteTAG: 0
FirstChildTAG: Wikipedia link/table, that related different world time zones to GMT.
http://en.wikipedia.org/wiki/Time_zone#List_of_UTC_offsets
FirstChildUserIdTAG: 538198
FirstChildUserNameTAG: A_P
FirstChildCreateTimeTAG: 2013-02-27T23:53:31Z
FirstChildVoteTAG: 0
IndexTAG: 2121
TitleTAG: how can i get the value of the last question any help
???????????????????/
UserIdTAG: 1292897
UserNameTAG: DrMahmut
CreateTimeTAG: 2013-02-27T18:54:00Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Hint: (Time X height) gives you the % area covered by that bar and sum of area covered by all the bars should be 100%
FirstChildUserIdTAG: 1291720
FirstChildUserNameTAG: SatyendraPawar
FirstChildCreateTimeTAG: 2013-02-27T19:24:36Z
FirstChildVoteTAG: 0
FirstChildTAG: 1. Did you get correct value for Q6?
2. If so, use the same formula to calculate percent of students for intervals (4-10) & (15-25).
3. Add the values of percent of students for Q6, and for intervals (4-10) & (15-25) you calculated in Step 2.
4. As the total percent of students is 100, subtract this value from 100.
5. This value will give you the percent of students who spent 10-15 hours in preparation
6. Plug in this value in formula used in Q6 which is *`(Right End Point - Left End Point) * ? = percent of students spent 10-15 hours in preparation`*
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T19:50:15Z
FirstChildVoteTAG: 0
IndexTAG: 2122
TitleTAG: WOW
i got 20\20
UserIdTAG: 625229
UserNameTAG: alshaimaahmed
CreateTimeTAG: 2013-02-27T18:47:45Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: same ;)
FirstChildUserIdTAG: 1053569
FirstChildUserNameTAG: nicola2003
FirstChildCreateTimeTAG: 2013-02-27T19:00:47Z
FirstChildVoteTAG: 1
SecondChildTAG: Nice! Congrats! The last question ruined me T.T
SecondChildUserIdTAG: 1018933
SecondChildUserNameTAG: IsisN
SecondChildCreateTimeTAG: 2013-02-27T21:17:25Z
SecondChildVoteTAG: 0
IndexTAG: 2123
TitleTAG: looking for correct answer
where can i find correct answer?
UserIdTAG: 1111358
UserNameTAG: gfbbq
CreateTimeTAG: 2013-02-27T18:43:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: If you are looking for solutions to the Exercise Sets (Solved Exercise Sets), may be they would make it available at a later date.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T19:52:16Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you read the course policy on this?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:08:14Z
FirstChildVoteTAG: 0
IndexTAG: 2124
TitleTAG: Please, let´s stop complaining
Don´t know the majority of you, but I´m pretty tired of reading the same once and then again...
Common people, let´s stop complaining instead of trying to help the staff to improve this course. Stop ruining the experience for those of us who does accept that not everything is perfect and that´s always room to make things better.
Yes, we all have found mistakes, yes everybody has talk about them already, but it´s the first time they run this course and I bet is a great effort that most of us will not consider to put the energy on. It´s a new learning experience and it´s worth it, so let´s take the advantages on that.
UserIdTAG: 26776
UserNameTAG: aleguillen
CreateTimeTAG: 2013-02-27T18:39:11Z
VoteTAG: 18
CoursewareTAG: undefined
NumberOfReplyTAG: 7
FirstChildTAG: !=11.11, !=11, but ==11.1 when precise answer is 11.(1) - is not "a mistake" - it's THE HUGE EPIC FAIL
:)
FirstChildUserIdTAG: 342603
FirstChildUserNameTAG: YakovO
FirstChildCreateTimeTAG: 2013-02-27T18:43:01Z
FirstChildVoteTAG: 0
SecondChildTAG: I'm sure they will address it when they have the time, wasn't that a practice question?
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-27T18:55:37Z
SecondChildVoteTAG: 0
SecondChildTAG: It was. For assignment questions it will be totally frustrating experience.
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T19:56:44Z
SecondChildVoteTAG: 0
FirstChildTAG: And it's *free*, too!
Students participating in online courses like this can either help develop this concept for future students by giving useful (but positively framed) feedback, or can complain so much that professors no longer want to offer their time and effort because it is so painful to deal with students complaining that their FREE, on-demand, at-home, from anywhere in the world at any time, college-level course is not perfect.
We are getting so much more than what we are paying for, folks.
FirstChildUserIdTAG: 1302407
FirstChildUserNameTAG: HelenES
FirstChildCreateTimeTAG: 2013-02-27T18:53:44Z
FirstChildVoteTAG: 8
SecondChildTAG: I agree 100%
SecondChildUserIdTAG: 142494
SecondChildUserNameTAG: jaria101
SecondChildCreateTimeTAG: 2013-02-27T18:59:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Nicely put. I am excited just learning the material from a place I would never have chance of getting in to.
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-27T19:02:12Z
SecondChildVoteTAG: 0
SecondChildTAG: omg, I'm so tired of this "and btw it's free" excuse. You know why Linux still not popular as a desktop OS? Yes, because when ppl point to problems it's always "it's free" excuse.
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T19:59:55Z
SecondChildVoteTAG: 0
SecondChildTAG: with many free courses offered by other providers with the same topic, it is a waste of time to do courses that are less perfect
SecondChildUserIdTAG: 199205
SecondChildUserNameTAG: ririana
SecondChildCreateTimeTAG: 2013-02-27T23:18:30Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree, it's a great course, and it's free. So we should appreciate the privilege.
FirstChildUserIdTAG: 1252009
FirstChildUserNameTAG: Emilyjch
FirstChildCreateTimeTAG: 2013-02-27T19:22:52Z
FirstChildVoteTAG: 2
FirstChildTAG: Let us not get into "FREE or NOT FREE" logic. Every course has some teething problems, especially when offered for the first time. It will go thru' its maturity curve over time.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T19:56:14Z
FirstChildVoteTAG: 1
SecondChildTAG: I don't know why this problem arise - I took electronics course with the same grader (I think) - there was no such problem... probably they broke something :(
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T20:10:11Z
SecondChildVoteTAG: 0
SecondChildTAG: YakovO, edX is still new and some first offerings of courses still have bugs to work out. 6.002x was lucky to be 'error free'. Courses like 6.00x, SaaS, AI all had some bugs in their first offerings.
We are all human, so mistakes are fine. We learn from them, improve and move on. Feedback is positive but complaints aren't.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T20:53:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually I always feedback these courses positively and always recommend it to others - it's really amazing and I like it. I'm ranting to make edX push quality higher ;)
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T21:18:42Z
SecondChildVoteTAG: 0
SecondChildTAG: @ jimbangun - great to see you here after CS course! Keep motivating everyone as you did in the past!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-28T04:55:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Whether it's free or not, it's a great effort by everyone who is working to make this happen.
Sure, we can point out mistakes, and we should in order to help the improvement process. But let's be constructive about it or else we become part of the problem, and we should be part of the SOLUTION instead
FirstChildUserIdTAG: 1288995
FirstChildUserNameTAG: olsolis
FirstChildCreateTimeTAG: 2013-02-27T20:19:38Z
FirstChildVoteTAG: 4
FirstChildTAG: They tell the grader what answer they want. If they specify 1dp, then it is 1dp.
This has been addressed by the Prof. If people would actually read the forums before complaining they might be surprised at what has already been discussed. The Prof has been told about the issues with decimal places.
This is a new course on a revamped platform. There are going to be problems. If you can't deal with that, then leave and come back when the course is run again. Maybe all the issues will be fixed by then. But, of course, new ones might arise.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T21:07:24Z
FirstChildVoteTAG: 2
SecondChildTAG: well said...thank you.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:16:09Z
SecondChildVoteTAG: 0
SecondChildTAG: >They tell the grader what answer they want. If they specify 1dp, then it is 1dp.
...and as I said before - it's not correct behavior :)
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T21:23:03Z
SecondChildVoteTAG: 0
SecondChildTAG: neither is yours.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:27:03Z
SecondChildVoteTAG: 0
SecondChildTAG: fortunately truth is not a question of opinion :P
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T21:45:27Z
SecondChildVoteTAG: 0
FirstChildTAG: Given that even the most thoughtfully designed product or service can be improved, my primary hope is that participants in this course would ask themselves how they like to be confronted with their own errors when they make them, whether it's at home, work or school.
I'd imagine most people would like constructive, specific criticism that suggests how they might improve. Most likely, they would not like all of their positive efforts to be disregarded due to a few small errors. They would not like to be roundly, harshly criticized for not anticipating any problem that could possibly arise.
I implore anyone who takes part in this, or any other mass education program, to be generous with your praise when the program works well, and to be thoughtful and measured when you find some element that doesn't work so well. Isn't that what you'd want for yourself?
FirstChildUserIdTAG: 905578
FirstChildUserNameTAG: ironyisoverrated
FirstChildCreateTimeTAG: 2013-02-28T16:30:30Z
FirstChildVoteTAG: 0
IndexTAG: 2125
TitleTAG: Lec 1.3
There is a bug within this exercise. If you write the result using 2 decimals it will be considered incorrect even it's more accurate than using one decimal (accepted as correct).
UserIdTAG: 126035
UserNameTAG: victorcernatescu
CreateTimeTAG: 2013-02-27T18:31:21Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Had the same problem. Thought it might be an application of significant digits principle, 270 has 3 digits thus 3 digits in answer. But I don't think that is a correct application of the principle. Since the data set,270, has no digits to the right of the decimal then significant digits principle says the answer should not have any digits to the right of the decimal. That said, it would appear the number of digits past the decimal used to determine the correct answer was established arbitrarily. Good thing we have this practice stage, now we know that one decimal point is the section norm. It will be interesting to see if that is maintained through out the course.
FirstChildUserIdTAG: 1324450
FirstChildUserNameTAG: Busathe
FirstChildCreateTimeTAG: 2013-02-27T19:04:16Z
FirstChildVoteTAG: 0
FirstChildTAG: From what I have learned, I only see 1 significant figure through out the problem. 270 is not equal in significant figures as to 270., notice the decimal place at the end, which would make the significant figure count to 2.
The proportions are equal 1 and that is the lowest, so I would normally assume that is the significant figure amount. I am not too sure how it works with statistics or if it is dependent on the programming of the grader.
FirstChildUserIdTAG: 1140158
FirstChildUserNameTAG: SendIt_MsgIt
FirstChildCreateTimeTAG: 2013-02-27T21:17:18Z
FirstChildVoteTAG: 0
IndexTAG: 2126
TitleTAG: Excellent, I got everything wrong. Looks like there is no point in continuing.
Very frustrating. We jump from one example to something completely different. Obviously getting frustrated only makes it more difficult to think. This really sucks.
UserIdTAG: 1175679
UserNameTAG: mkemp2010
CreateTimeTAG: 2013-02-27T18:22:11Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 8
FirstChildTAG: Are you following the lectures in sequence ? You may be missing out lectures.There is a bar on the top of the lecture pages from which you can move from lecture to lecture in sequence.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T18:27:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes, I had at least enough brains to figure that part out.
SecondChildUserIdTAG: 1175679
SecondChildUserNameTAG: mkemp2010
SecondChildCreateTimeTAG: 2013-02-27T18:45:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Watch your tone buddy. People are only trying to help. If you have such high standards, go to a university. They will assign you a personal tutor. But ofcourse that is going to cost you money(lots!), right? Oh wait..you don't have any! So at the very least, respect the favour Prof. Ani is doing you or walk away.
SecondChildUserIdTAG: 1117998
SecondChildUserNameTAG: ashutoshpathak
SecondChildCreateTimeTAG: 2013-02-27T20:50:32Z
SecondChildVoteTAG: 0
FirstChildTAG: If you have any problem, you can always come to this forum and ask for help. I'm sure you'll get helpful answers.
If there anything in particular that you found difficult?
FirstChildUserIdTAG: 1260768
FirstChildUserNameTAG: Arjunkh
FirstChildCreateTimeTAG: 2013-02-27T18:45:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, the whole percentile thing. We went from arranging entries in a straight line and then dividing to find the correct entry to looking at a box in problem 1 exercise 3. That made no sense to me whatsoever. AT this point, it's done and I failed every single problem except for the last one when I just gave up and selected the correct answer by guessing. Someone said in an earlier post, you get it or you don't. I don't.
SecondChildUserIdTAG: 1175679
SecondChildUserNameTAG: mkemp2010
SecondChildCreateTimeTAG: 2013-02-27T18:54:56Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree that it's frustrating to not be able to see the correct solution when you get something wrong but with just a bit of patience you will be able to see the solutions after tonight and surely then you will understand better. Remember that if you make mistakes, the worst two exercise sets don't count for your final score...
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-27T19:31:11Z
SecondChildVoteTAG: 0
FirstChildTAG: If you need more information, you can look at the manual it's explained differently and you can watch lectures as well...
FirstChildUserIdTAG: 952904
FirstChildUserNameTAG: relie
FirstChildCreateTimeTAG: 2013-02-27T19:27:44Z
FirstChildVoteTAG: 0
FirstChildTAG: don't give up... you might get next ones correct if you work hard.
FirstChildUserIdTAG: 1053569
FirstChildUserNameTAG: nicola2003
FirstChildCreateTimeTAG: 2013-02-27T19:31:59Z
FirstChildVoteTAG: 0
FirstChildTAG: At least wait until the answers are explained, maybe then you will pick it up and be fine the rest of the course.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T19:34:41Z
FirstChildVoteTAG: 0
FirstChildTAG: I took the course by Philip B. Stark's book and I understood. You'll find the chapter you need in Practice for Exercise: http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#variables . Watch the course on youtube he posted then practice a little bit on the exercises on that page.
FirstChildUserIdTAG: 1313029
FirstChildUserNameTAG: Ghenoiu
FirstChildCreateTimeTAG: 2013-02-27T20:20:26Z
FirstChildVoteTAG: 0
SecondChildTAG: Agree with Ghenoiu
SecondChildUserIdTAG: 1293981
SecondChildUserNameTAG: Hassan_1
SecondChildCreateTimeTAG: 2013-02-27T22:04:48Z
SecondChildVoteTAG: 0
FirstChildTAG: hey, I just completed the exercise and to be honest I didn't understand everything completely but still I got 18/20(although I made a mistake and wrote wrong number in the failed one). IF you just look at the lectures and follow the formulas and examples then you should pass this assignment without any problems.
FirstChildUserIdTAG: 319056
FirstChildUserNameTAG: cydrus88
FirstChildCreateTimeTAG: 2013-02-27T20:26:35Z
FirstChildVoteTAG: 0
FirstChildTAG: > I had at least enough brains to figure that part out. ~mkemp2010
Watch your tone buddy. People are only trying to help. If you have such high standards, go to a university. They will assign you a personal tutor. But ofcourse that is going to cost you money(lots!), right? Oh wait..you don't have any! So at the very least, respect the favour Prof. Ani is doing you or walk away.
FirstChildUserIdTAG: 1117998
FirstChildUserNameTAG: ashutoshpathak
FirstChildCreateTimeTAG: 2013-02-28T02:33:59Z
FirstChildVoteTAG: 0
IndexTAG: 2127
TitleTAG: Major problem in Exercise Set-2; Problem 2
Hello Fellows
Though I managed other problems, i found problem 2 in exercise 2 to be complicated. Can anyone explain the concept in lucid way please? Thanks in advance.
UserIdTAG: 841834
UserNameTAG: Kushal4698
CreateTimeTAG: 2013-02-27T18:17:59Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Key idea(assumption): uniform distribution of ages in a particular interval.
If 12% is distributed among the ages 1-4, then there are 4% of people aged 1, 4% aged 2 and 4% aged 3.
This should help you solve a and b.Also, 'over 65' refers to >= 65.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_2/threads/512deb4c215db422000000db
FirstChildUserIdTAG: 1617
FirstChildUserNameTAG: sid3930
FirstChildCreateTimeTAG: 2013-02-27T18:31:50Z
FirstChildVoteTAG: 2
FirstChildTAG: 1. Thirties include 30,31,32......., 39
2. So the question refers to the Age interval 30-45.
3. Calculate the % per year(age) for this interval ( percent / (Right End point - Left End Point) )
4. Now the given interval includes ages from 30 to 45. We are only interested in first 10 ages (from 30 to 39).
5. So multiply the % per year(age) you got in Step 3 with 10 (as ages are uniformly distributed within interval) to get the percent of the people were in their thirties
6. Use same logic for the other question keeping in mind that 'Over sixties' includes ages 65 and above (65 is inclusive)
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T18:55:36Z
FirstChildVoteTAG: 1
SecondChildTAG: This seems pretty clear. However, I've got the wrong answer.
I'm assuming that because of the end points, the age bracket 30-45 actually contains **fourteen** "age years" rather than the fifteen one would assume, because the 30-45 age bracket actually only includes people aged 30-44. Is this correct? If not, perhaps it's why I got the wrong answer.
SecondChildUserIdTAG: 1055945
SecondChildUserNameTAG: rebecca417
SecondChildCreateTimeTAG: 2013-02-27T20:09:27Z
SecondChildVoteTAG: 0
SecondChildTAG: The range is 15, not 14.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-28T04:49:01Z
SecondChildVoteTAG: 0
SecondChildTAG: count 30,31,32...44 ...its 15 list entries.
1. 30
2. 31
3. 32
4. 33
5. 34
6. 35
7. 36
8. 37
9. 38
10. 39
11. 40
12. 41
13. 42
14. 43
15. 44
Hope it is clear now.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-28T04:51:58Z
SecondChildVoteTAG: 0
IndexTAG: 2128
TitleTAG: it's ridiculous
11 is not correct? 11.11 is not correct? 11.1 is correct????? Are you kidding me? I'm canceling this course due to unreliability of grader.
UserIdTAG: 342603
UserNameTAG: YakovO
CreateTimeTAG: 2013-02-27T18:15:12Z
VoteTAG: 9
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Rounding off was to one decimal
If you leave the course it is your choice but if you want to get information it is there and worth it.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T18:22:38Z
FirstChildVoteTAG: 2
SecondChildTAG: I ran into this too. Is this the understood convention, then, that all our answers should be rounded to the tenths place?
SecondChildUserIdTAG: 1312416
SecondChildUserNameTAG: flaerebear
SecondChildCreateTimeTAG: 2013-02-27T18:30:07Z
SecondChildVoteTAG: 0
SecondChildTAG: It's very frustrating when you are limited on number of tries, often to single one, and grader such stupendously unreliable. Will wait next session - probably they'll fix it :)
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T18:33:38Z
SecondChildVoteTAG: 0
SecondChildTAG: flaerebear
For many questions they ask for specific precision. But I disappointed in grader quality - your grade will depend on it... It's frustrating. Grader should compare not symbols, but precise result with allowed small inaccuracy.
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T18:39:17Z
SecondChildVoteTAG: 0
SecondChildTAG: The number of significant digits is very deliberate here, since with quantitative analysis its important to understand how to they work.
SecondChildUserIdTAG: 941165
SecondChildUserNameTAG: bp84
SecondChildCreateTimeTAG: 2013-02-27T18:39:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Do not leave the course for grades because certificates anyways do not print grades. It just states you successfully completed the course. So, it may make sense not to wait for the next season. Because by that time you would be done with this course and ready to move on to the next. Most important is to learn. Everyone who gets the minimum required grades will get the certificate and trust me, all certificates are alike except for the NAME of the student :). They do not mention any grades!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-27T19:04:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Learnt by experience- I round my answers to 2 decimal places unless specifically stated otherwise. This convention holds true for all the 3 test.
SecondChildUserIdTAG: 1291720
SecondChildUserNameTAG: SatyendraPawar
SecondChildCreateTimeTAG: 2013-02-27T19:17:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Artimehta, I'm taking QM now, so I'm not wasting my time anyway :)
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T20:05:36Z
SecondChildVoteTAG: 0
SecondChildTAG: What's QM
SecondChildUserIdTAG: 1187096
SecondChildUserNameTAG: Chinonso411
SecondChildCreateTimeTAG: 2013-02-27T20:17:35Z
SecondChildVoteTAG: 0
SecondChildTAG: BerkeleyX: CS191x Quantum Mechanics and Quantum Computation
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T20:28:21Z
SecondChildVoteTAG: 0
SecondChildTAG: That sounds great, YakovO! Best Wishes.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-28T04:45:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Getting certificate is not always enough, don't always run after certificates !!
However these certificates earmark your attentive nature but what would you do if you don't learn anything or learn wrong?
By the way there are enormous things i get to know from every course albeit many of them seems mundane and don't make any sense but still something is being gained in 3-5 hours out of 168 hours (1 week)therefore it's conventional and i remain tenacious to it :)
SecondChildUserIdTAG: 450282
SecondChildUserNameTAG: Astute
SecondChildCreateTimeTAG: 2013-03-09T05:01:21Z
SecondChildVoteTAG: 0
FirstChildTAG: > Are you kidding me?
Nope. The grader has to be told what to expect. Live with it.
> I'm canceling this course due to unreliability of grader.
We are devastated. One less "me too" poster to worry about. The grader isn't unreliable.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:34:25Z
FirstChildVoteTAG: 0
SecondChildTAG: >Live with it.
thanks, no
>We are devastated.
I don't care :P
>The grader isn't unreliable.
It is - as a programmer I know what I'm talking about - it's a total bullshit.
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T20:38:11Z
SecondChildVoteTAG: 0
SecondChildTAG: The grader is told what to expect
>I don't care :P
Doubly devastated.
>It is - as a programmer I know what I'm talking about - it's a total bullshit.
Ah yes. Of course you do. You know that computers can think and decide the answer without any guidance.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T21:01:28Z
SecondChildVoteTAG: 0
SecondChildTAG: and as a programmer you never need a debugger because your code always compile and run correctly every single time, right? You never make mistakes because you cannot accept other people making mistakes. :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:04:35Z
SecondChildVoteTAG: 0
SecondChildTAG: also this error has already been discussed many times and even acknowledged by the staff/prof. Next time search the forum and read the posts. Also read the nettiquette section of the discussion forum guidelines.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:07:34Z
SecondChildVoteTAG: 0
SecondChildTAG: >The grader is told what to expect
the grader should expect specific precision OR BETTER, and minimal precision should be disclosed
>Doubly devastated.
Doubly don't care :PP
>Ah yes. Of course you do. You know that computers can think and decide the answer without any guidance.
It's your personal delirium, sorry :)
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T21:08:53Z
SecondChildVoteTAG: 0
SecondChildTAG: wow, so childish....lol
Why are you still here?
Didn't you say that you didn't want to waste your time?
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:19:12Z
SecondChildVoteTAG: 0
SecondChildTAG: >and as a programmer you never need a debugger because your code always compile and run correctly every single time, right?
First of all debugger has nothing to do with compiler. My programs most of the time doesn't compile at first try. My programs not always behave correctly - it's why I test it and DON'T put in production with ridiculously obvious bugs.
>You never make mistakes because you cannot accept other people making mistakes.
It's not "a mistake", as I said before. It's ridiculously obvious bug.
>also this error has already been discussed many times........
I'm expressing my frustration in order to push staff work harder to improve this amazing edX ;) Actually I really love it with all its bugs and problems :)
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T21:34:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Have you ever used Assembler or C? No need to lecture me on programming, I am one too as well as my brother who works for Microsoft, and plenty of my friends who work for major software companies.
As with all production software, bugs/mistakes happen and they don't always get fixed immediately. That's why you have patches and upgrades. You should know this.
People vent out frustrations, that is normal. However there are etiquette and norms to be followed. Using caps lock, multiple !!! or ???, using profanity (such as 'b*llsh*t), etc. are improper.
Also in order to make this forum effective, please read the already existing posts and answers from fellow students as well as staff before making a post on a subject that has already been discussed.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-27T21:47:46Z
SecondChildVoteTAG: 0
SecondChildTAG: C/C++ last 15 years. Very rarely x86 asm. Java sometimes. Perl scripting, shell scripting, batch scripting. Long long time ago Pascal, Clipper, something else don't remember already, longer time ago (at school) Basic. Enough? :)
>my brother ... and plenty of my friends ...
lol
that's funny :)
looks like it works as a passive smoking ;)
>they don't always get fixed immediately
do you know what QA is? my wife is a professional QA - want me to ask her about this specific bug and what they do with programmers who leave it for QA and what they do with QA who let it go to production? :) Oh no, don't ask - it's too cruel :)
>Using caps lock, multiple !!! or ???
but how else express emotions in plain text? :)
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T22:09:54Z
SecondChildVoteTAG: 0
IndexTAG: 2129
TitleTAG: WEEK TWO AVAILABILITY
Is week two available to everyone? As I am not able to view courses for week two.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-27T18:10:50Z
VoteTAG: 10
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 8
FirstChildTAG: I too am wondering the same thing. As of Wed 1:30 pm ET, I cannot access it.
FirstChildUserIdTAG: 153468
FirstChildUserNameTAG: dnv05
FirstChildCreateTimeTAG: 2013-02-27T18:31:19Z
FirstChildVoteTAG: 1
FirstChildTAG: Is the due date today, and the next section starts tomorrow? I don't know how it works yet.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T19:05:07Z
FirstChildVoteTAG: 0
FirstChildTAG: According to the Syllabus, the next section is on measures of location. While I also cannot yet view the lectures, I did click on Chapter 4 of the SticiGui materials to browse ahead.
FirstChildUserIdTAG: 769137
FirstChildUserNameTAG: RedFern
FirstChildCreateTimeTAG: 2013-02-27T19:18:06Z
FirstChildVoteTAG: 2
SecondChildTAG: Good idea!
SecondChildUserIdTAG: 1252523
SecondChildUserNameTAG: Willabe
SecondChildCreateTimeTAG: 2013-02-27T21:38:59Z
SecondChildVoteTAG: 0
FirstChildTAG: Yeah I think it's about mean, median, and mode, as well as Standard Deviation, which is a pain to me.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T19:38:28Z
FirstChildVoteTAG: 0
FirstChildTAG: No for me its not avaible yet. Would you mind letting me know when it becomes available for u. thanks
FirstChildUserIdTAG: 1281597
FirstChildUserNameTAG: Luisns10
FirstChildCreateTimeTAG: 2013-02-27T19:40:22Z
FirstChildVoteTAG: 0
FirstChildTAG: indeed. is this a delay or how its just gona be? as of noon pst the material still is not available yet..
FirstChildUserIdTAG: 985560
FirstChildUserNameTAG: zoe3456
FirstChildCreateTimeTAG: 2013-02-27T19:40:34Z
FirstChildVoteTAG: 0
FirstChildTAG: It was late starting, maybe this one will be late too. What time was the first week available?
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T19:42:07Z
FirstChildVoteTAG: 0
FirstChildTAG: Good night from Europe. I live in a country with +0 GMT and it is 21:33 of the 27th... BUT the second week is not available yet.
Why is that happening??
FirstChildUserIdTAG: 961907
FirstChildUserNameTAG: ngarin
FirstChildCreateTimeTAG: 2013-02-27T20:38:13Z
FirstChildVoteTAG: 0
IndexTAG: 2130
TitleTAG: Problem 3, part b)
Why??? Why error??? The bar graph #2 and #4 are the same bar graph!!!
380 green plants and 120 no green plants!!!
Why??? My answer is correct!!!
Total number of plants: 500.
Total green plants: 380.
Total no green plants: 120.
Why???
UserIdTAG: 1031994
UserNameTAG: Andrea33
CreateTimeTAG: 2013-02-27T18:09:47Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: y-axis label:)
FirstChildUserIdTAG: 1617
FirstChildUserNameTAG: sid3930
FirstChildCreateTimeTAG: 2013-02-27T18:18:31Z
FirstChildVoteTAG: 0
SecondChildTAG: but i think both 2 and 4 are wrong answer
SecondChildUserIdTAG: 329840
SecondChildUserNameTAG: eharry
SecondChildCreateTimeTAG: 2013-02-27T18:48:29Z
SecondChildVoteTAG: 0
SecondChildTAG: @eharry - and why do you say so?
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-27T19:06:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Yeah, this one almost got me, but I figured something had to be up when I thought they were both identical so I inspected more closely. The second graph shows Probability as the y-axis, so that data wouldn't fit. Only the fourth has the correct category for the y-axis (number of plants) and qualities for the x-axis (contains green / no green).
FirstChildUserIdTAG: 1312416
FirstChildUserNameTAG: flaerebear
FirstChildCreateTimeTAG: 2013-02-27T19:06:03Z
FirstChildVoteTAG: 1
FirstChildTAG: I should have continued with the line of reasoning that flaerebear used......I will watch more closely in the future
FirstChildUserIdTAG: 1194221
FirstChildUserNameTAG: Frank032061
FirstChildCreateTimeTAG: 2013-02-27T20:20:13Z
FirstChildVoteTAG: 0
FirstChildTAG: But it is written microscopic!!! As I was noticing this thing? Don't expect a thing!!! It seems that both put there on purpose to cheat you! Could write bigger!!
FirstChildUserIdTAG: 1031994
FirstChildUserNameTAG: Andrea33
FirstChildCreateTimeTAG: 2013-03-01T20:43:11Z
FirstChildVoteTAG: 1
IndexTAG: 2131
TitleTAG: Second Attempt!!
I was thinking that time is in IST but turns out it is in GMT. I tried attempting this test without reading the lectures given. Do I have a chance at attempting this test a second time?
UserIdTAG: 1300196
UserNameTAG: nimishasrivastava
CreateTimeTAG: 2013-02-27T18:09:12Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: yeap, i have just finished
FirstChildUserIdTAG: 520346
FirstChildUserNameTAG: zhuldizai
FirstChildCreateTimeTAG: 2013-02-27T18:21:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Nimisha, I'm also located in India and finished it just now. I guess you would have time till tomorrow morning taking into consideration that this course is not running on GMT but some USA time zone
SecondChildUserIdTAG: 1162288
SecondChildUserNameTAG: AbhiT
SecondChildCreateTimeTAG: 2013-02-27T18:38:01Z
SecondChildVoteTAG: 0
SecondChildTAG: I think all times are based Pacific time (i.e. GMT -8 hours), because Berkeley University is in California. Hope that helps :-)
SecondChildUserIdTAG: 1290327
SecondChildUserNameTAG: CorinneH
SecondChildCreateTimeTAG: 2013-02-27T19:36:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Double check because Berkeley is in California, but I believe EDX headquarters are in Boston/Cambridge, Massachusetts, a different time zone by 3 hours.
FirstChildUserIdTAG: 310963
FirstChildUserNameTAG: TwinOtter
FirstChildCreateTimeTAG: 2013-02-27T19:58:38Z
FirstChildVoteTAG: 0
SecondChildTAG: Before they changed the dates, they specified it was Pacific time... so we can safely assume it's still the same. After all, the evaluation is done in Berkley, not the EdX headquarters.
SecondChildUserIdTAG: 1060592
SecondChildUserNameTAG: Lucius513
SecondChildCreateTimeTAG: 2013-02-27T20:26:07Z
SecondChildVoteTAG: 0
FirstChildTAG: > I was thinking that time is in IST but turns out it is in GMT.
Did you read the Course policy document?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:57:58Z
FirstChildVoteTAG: 1
IndexTAG: 2132
TitleTAG: Registration confirmation
Sir, my name is not present in student dictionary. Kindly confirm this either my registration is confirmed or not. Thanks
UserIdTAG: 941373
UserNameTAG: jabirmumtaz
CreateTimeTAG: 2013-02-27T17:55:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: You need manually add your name to Student Dictionary.
FirstChildUserIdTAG: 610852
FirstChildUserNameTAG: maMykola
FirstChildCreateTimeTAG: 2013-02-27T18:10:33Z
FirstChildVoteTAG: 0
SecondChildTAG: I'm embarrassed to admit it, but I could not figure out how to do this. I have no experience with Wikis. I tried using the symbols that were in the shortcuts list but it didn't work. I'm sure there is something very basic that I'm not knowing how to do. Would you mind responding with a brief explanation? Or someone else?
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T22:01:23Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm guessing you figured out how to click "Edit" on the wiki page, but were unsure how to add your name to the list with the proper formatting? You can copy someone else's name and paste it where you want your name to go. The correct formatting is copied as well. Then you can just replace the old name with yours. Does that help?
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T22:19:06Z
SecondChildVoteTAG: 0
FirstChildTAG: If you're able to login to the course, then you're enrolled. If you want to be in the student directory, then add yourself.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T20:13:04Z
FirstChildVoteTAG: 0
IndexTAG: 2133
TitleTAG: rounding
Hello, I think that I must be rounding incorrectly because the amounts that I got were incorrect based off of using 2-character decimals compared to if I used the full decimal with a calculator.
UserIdTAG: 320444
UserNameTAG: Linda_Mullally
CreateTimeTAG: 2013-02-27T17:54:31Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I have similar issue, most of my answer is incorrect as I don't know what is expected in none round calcul... example 8.66666667 is 8.67... arghh what are we suppose to put, we get bad results even if we have understood and apply what we learn.
FirstChildUserIdTAG: 1177855
FirstChildUserNameTAG: benacello
FirstChildCreateTimeTAG: 2013-02-27T18:23:44Z
FirstChildVoteTAG: 0
IndexTAG: 2134
TitleTAG: cannot see the data set
Hi,
Please assist. I cannot locate the data set for exercise 3-6. Thanks
UserIdTAG: 592961
UserNameTAG: Sohini
CreateTimeTAG: 2013-02-27T17:44:45Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG:
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#frequency_tables
FirstChildUserIdTAG: 1281619
FirstChildUserNameTAG: sfc17
FirstChildCreateTimeTAG: 2013-02-27T18:07:24Z
FirstChildVoteTAG: 0
IndexTAG: 2135
TitleTAG: Mostly wrong in Exercise 3
Just finished exercise 3. Got most wrong. I dont understand. The questions make limited sense in the context of the YouTube lecture. The answers seem to have the same problem. I just don't get it!
UserIdTAG: 1192110
UserNameTAG: RupamRaja
CreateTimeTAG: 2013-02-27T17:44:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: People here can help you out if you are more specific:)
FirstChildUserIdTAG: 1617
FirstChildUserNameTAG: sid3930
FirstChildCreateTimeTAG: 2013-02-27T18:08:37Z
FirstChildVoteTAG: 0
FirstChildTAG: You have posted this comment under Exercise 1 but your subject title says Exercise 3. Where did you face the problems?
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T19:10:10Z
FirstChildVoteTAG: 0
SecondChildTAG: So many are doing this! So confusing. Why not post in the correct subforum?
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T20:57:23Z
SecondChildVoteTAG: 0
IndexTAG: 2136
TitleTAG: Question?
Kindly tell me about the reference time zone...
UserIdTAG: 941373
UserNameTAG: jabirmumtaz
CreateTimeTAG: 2013-02-27T17:44:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: http://www.timeanddate.com/worldclock/city.html?n=791
I guess
FirstChildUserIdTAG: 848506
FirstChildUserNameTAG: T_Valencia
FirstChildCreateTimeTAG: 2013-02-27T17:53:30Z
FirstChildVoteTAG: 0
SecondChildTAG: no. GMT
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-27T17:54:29Z
SecondChildVoteTAG: 0
FirstChildTAG: It tells in the course policy document.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:56:50Z
FirstChildVoteTAG: 0
IndexTAG: 2137
TitleTAG: Couldnt attend this weeks courses and test ..............what next
Really messed up with a big consultation at my work place coudlnt spend time for work sheets and week end test, would it be possible to continue still the course to next week, i can do the complete 1st week work by day after tomorrow , would it be allowed please let us know.
regards
Kishor
UserIdTAG: 927247
UserNameTAG: drmkishor
CreateTimeTAG: 2013-02-27T17:37:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You can't but two out of 12 tests are for the final evaluation
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T17:46:05Z
FirstChildVoteTAG: 0
IndexTAG: 2138
TitleTAG: STAFF: Pearons Proctored Exams
Does the Stat2.1x course offer Pearons proctored exams?
UserIdTAG: 1207788
UserNameTAG: NRHassan
CreateTimeTAG: 2013-02-27T17:35:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2139
TitleTAG: Week TWO
Hi everyone out there, just failed week one and now i cant see week two hope its going to bring me hope; oooh.
UserIdTAG: 1258683
UserNameTAG: Tshuxx
CreateTimeTAG: 2013-02-27T17:28:30Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: My suggestion for you is to rework on all the assignments and review the videos if need be to make sure that you have master the materials for this week. If you don't then it is only getting harder because week 2 and beyond are building upon what you learn this week.
Although I am doing okay but I still don't feel like I have truly master the materials yet. So I am going to do the same myself to make sure that I understand the materials the way that it is suppose to and be able to solve the problems without much struggle.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-27T17:56:03Z
FirstChildVoteTAG: 1
IndexTAG: 2140
TitleTAG: It should it as correct and I hit enter and the 2 answers were marked as wrong
For question 6 and 7 it showed I had the answer correct I hit enter and then they both were seen as marked wrong.. what happened? Can it be fixed?
UserIdTAG: 896245
UserNameTAG: Ingrid90
CreateTimeTAG: 2013-02-27T17:27:50Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: > I had the answer correct I hit enter and then they both were seen as marked wrong
Maybe because they were wrong?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:54:48Z
FirstChildVoteTAG: 0
IndexTAG: 2141
TitleTAG: Week Two
Hi just wondering when week two will be made available?
UserIdTAG: 1296563
UserNameTAG: Gsalley
CreateTimeTAG: 2013-02-27T17:16:42Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: waiting for week two
FirstChildUserIdTAG: 1123599
FirstChildUserNameTAG: sohag179ju
FirstChildCreateTimeTAG: 2013-02-27T17:27:34Z
FirstChildVoteTAG: 2
FirstChildTAG: Me too
FirstChildUserIdTAG: 961907
FirstChildUserNameTAG: ngarin
FirstChildCreateTimeTAG: 2013-02-27T20:02:16Z
FirstChildVoteTAG: 1
IndexTAG: 2142
TitleTAG: did it :)
did it at-last..
UserIdTAG: 731839
UserNameTAG: mebiostatistician
CreateTimeTAG: 2013-02-27T17:09:16Z
VoteTAG: 7
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2143
TitleTAG: Staff: Is there going to be tiered grading or a certificate with distinction for a set percentage?
It may be a little early to tell, but having got a 100% so far, I feel I can score at least in the 90's for this course. The difficulty level seems easy for the passing grade of 35%. I expect the difficulty to increase though.
I just want to gauge the difficulty level for others, so whoever got a 100% so far feel free to post.
Nice to see names from 6.00x around here, including atopos. I would not have been able to get a 100 without the valuable discussion and hints in the forums, so thanks to all of you.
UserIdTAG: 181676
UserNameTAG: dark_horse
CreateTimeTAG: 2013-02-27T16:58:23Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Certificate might be on the horizontal axis only.
It appears that 35% is what applies for the graded exercises only.
The tests are another matter.
How the graded and the test scores are combined is a further matter.
FirstChildUserIdTAG: 344400
FirstChildUserNameTAG: carlallen
FirstChildCreateTimeTAG: 2013-02-27T17:04:35Z
FirstChildVoteTAG: 0
FirstChildTAG: carlallen - one of the summary pages show how the relative weight of the homeworks, midterm, and final are.
and I could have sworn it was 35% for the entire course, but perhaps I'm wrong.
either way, I was also curious if there would be 'certificates of distinction' or something along those lines, since 35% seems to be a very low bar to hit for passing (unless the questions rapidly scale in difficulty).
FirstChildUserIdTAG: 941165
FirstChildUserNameTAG: bp84
FirstChildCreateTimeTAG: 2013-02-27T18:46:08Z
FirstChildVoteTAG: 1
FirstChildTAG: The Prof has already explained the 35%. It is to ease people in to the course, especially those who are new to higher learning.
Perhaps two subsequent courses will have a higher mark required, but for this course it is 35%.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:52:56Z
FirstChildVoteTAG: 0
FirstChildTAG: Hello, fellow 6.00x veteran!
As with the other edX courses (with the exception of the first offering of 6.002x), the certificates do not carry grades on them.
Maybe when they do proctored exams then those certificates will have grades and carry some credit on them.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-27T21:34:55Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks for all the replies. The professor's reason for the 35% is understandable and accommodating, though it would have been nice to have a certificate of distinction. Nevertheless, as jimbangun pointed out, the certificates do not carry grades on them, so this is mostly a matter of personal pride. For me the applications of what we learn in this course and Stat 2.2x and 2.3x - AI, Machine Learning, Cryptography - are important, so this course on its own is probably of less value personally. I wonder when Stat 2.2x is going to be offered, as probability is one of my weak areas.
FirstChildUserIdTAG: 181676
FirstChildUserNameTAG: dark_horse
FirstChildCreateTimeTAG: 2013-02-28T04:04:33Z
FirstChildVoteTAG: 0
IndexTAG: 2144
TitleTAG: no description
there is no description in 2.5 lecture, i cant understand all the the things unless i m reading behind the lecture..
UserIdTAG: 1147076
UserNameTAG: giomicho
CreateTimeTAG: 2013-02-27T16:51:21Z
VoteTAG: 2
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 0
IndexTAG: 2145
TitleTAG: Problem 3 question b
I think that all the 3 histograms are incorrect
but i got my answer wrong 2 times after 2 submissions on the 1st & 2nd choices.......so they put the histogram of density as the correct one but I think that it is also an incorrect histogram provided that density equals the percentage divided by the width of the bar which if applied on values on the distribution table, won't result in this density histogram......
Do any one has an answer about this, please??
UserIdTAG: 1152022
UserNameTAG: DrHazem
CreateTimeTAG: 2013-02-27T16:44:20Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Look at the histograms again and see the labels.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T16:45:23Z
FirstChildVoteTAG: 0
SecondChildTAG: Same thing here, but I still don't get it.
SecondChildUserIdTAG: 1060592
SecondChildUserNameTAG: Lucius513
SecondChildCreateTimeTAG: 2013-02-27T16:56:11Z
SecondChildVoteTAG: 0
SecondChildTAG: third is correct, as compare to first and second
SecondChildUserIdTAG: 731839
SecondChildUserNameTAG: mebiostatistician
SecondChildCreateTimeTAG: 2013-02-27T17:07:27Z
SecondChildVoteTAG: 0
SecondChildTAG: I looked again but i think that it still have something wrong.........if you try to divide each interval's percent by its bar width..........you will find that the histogram contains wrong values
SecondChildUserIdTAG: 1152022
SecondChildUserNameTAG: DrHazem
SecondChildCreateTimeTAG: 2013-02-27T17:22:56Z
SecondChildVoteTAG: 0
SecondChildTAG: There is the Honor code and we should not release answers before the final evaluation date and time of the exercise.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T18:17:31Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't think you're supposed to write the answers here, DrHazem.
FirstChildUserIdTAG: 1060592
FirstChildUserNameTAG: Lucius513
FirstChildCreateTimeTAG: 2013-02-27T16:59:22Z
FirstChildVoteTAG: 1
FirstChildTAG: I initially had the correct answer prior to submission, but changed it based on the title axis as it didn't seem to make sense. Lost out as a result.
FirstChildUserIdTAG: 1220073
FirstChildUserNameTAG: fconway
FirstChildCreateTimeTAG: 2013-02-27T17:22:28Z
FirstChildVoteTAG: 0
IndexTAG: 2146
TitleTAG: Homework Feedback
Hi, could you please give the rationale for the correct answers. Some answers are not as obvious as others. It would really help us reach the analytical level of learning for theses concepts quicker and some of us (i.e. me) might not make the same mistakes at the end (smile). Thanks again for this opportunity. (Don't remember how I got a "B" in Statistics years ago....)
UserIdTAG: 963273
UserNameTAG: Mydelight
CreateTimeTAG: 2013-02-27T16:33:01Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Please read the Course Policies page, available from the Course Info tab. It discusses how homework solutions will be released *after the due date.*
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T16:35:20Z
FirstChildVoteTAG: 0
SecondChildTAG: Good to know. There's so many information to start that we can get easily lost. Thanks!
SecondChildUserIdTAG: 689072
SecondChildUserNameTAG: pato54
SecondChildCreateTimeTAG: 2013-02-27T23:21:56Z
SecondChildVoteTAG: 0
IndexTAG: 2147
TitleTAG: Poor internet connectivity & lack of internet service at home.
I have poor internet connectivity at my office in the hinterland of my country,and even at home i have no access to internet to make research after working hours. This has caused me lots of difficulties to find my way out though i am dragging in the studies cause i don't want to be out. Bit by bit i believe i will gradually do better in my edx desired courses. can't give off and never.
UserIdTAG: 824988
UserNameTAG: KongorJ
CreateTimeTAG: 2013-02-27T16:32:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Use the sldies. They help. Dowmlaod the videos and then see them if possible.I can understand your problems.Any chance that you have a smartphone -you cna get cheap 2G connections and download the videos with them if that is possible in your area.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T16:38:44Z
FirstChildVoteTAG: 1
FirstChildTAG: I salute your attitude and perseverance, my friend.
Where do you live?
Is there anyone close to you who can download and put the videos in a CD and mail to you? How long does post mail usually take to arrive at your place?
I assume your internet is at least enough to do the exercises?
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-27T21:31:04Z
FirstChildVoteTAG: 0
IndexTAG: 2148
TitleTAG: ..
yey, done
UserIdTAG: 1233669
UserNameTAG: Cheers_agnes
CreateTimeTAG: 2013-02-27T16:30:12Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2149
TitleTAG: 2 submissions
This might sound a little bit trivial, but do we actually have to use both submissions for a questio, even if we scored all the right answers at first? Because I still have the possibility to perform a final check and I just want to make sure my answers are all "registered". And by the way, I'm glad we can discuss pretty much anything in this course but I think this is all getting too chaotic.
UserIdTAG: 1206659
UserNameTAG: MaximilianSchildt
CreateTimeTAG: 2013-02-27T16:20:21Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: If we check the discussion board before posting, we can avoid double postings. For your question: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/512dd56e51ad1c23000000c9
Does this answer your question?
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-02-27T16:24:47Z
FirstChildVoteTAG: 0
FirstChildTAG: Once you get all 'GREEN' tick marks (even in the first attempt), NO NEED TO SUBMIT again. You are done.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T19:17:38Z
FirstChildVoteTAG: 0
IndexTAG: 2150
TitleTAG: dificulties to move around
Please ,help!! The course is excellent butI have difficulties to move around. For example how to go from Lecture 2.3 to the next where the percentiles will be explained from the stem and leaf , how to find the probles for chapter 4, etc.
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-02-27T16:15:31Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Look at the top and there is a progress bar.You can click on it succesfully to see the next video.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T16:33:22Z
FirstChildVoteTAG: 0
IndexTAG: 2151
TitleTAG: Exercise set 1, problem 3 (b)
What is the difference between the second and fourth options? They look exactly the same to me.
UserIdTAG: 1260768
UserNameTAG: Arjunkh
CreateTimeTAG: 2013-02-27T16:14:11Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: actually, there is a nice hint at the end of set 1 practice exercises for reading and interpreting histograms.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-27T16:20:40Z
FirstChildVoteTAG: 1
FirstChildTAG: Problem 3, part b): the bar graph #2 and #4 are the same bar graph!
FirstChildUserIdTAG: 1031994
FirstChildUserNameTAG: Andrea33
FirstChildCreateTimeTAG: 2013-02-27T17:06:20Z
FirstChildVoteTAG: 1
SecondChildTAG: there is a difference in the vertical axe's name
SecondChildUserIdTAG: 931032
SecondChildUserNameTAG: guitar_angel
SecondChildCreateTimeTAG: 2013-02-27T17:45:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Why??? Why error??? The bar graph #2 and #4 are the same bar graph!!! 380 green plants and 120 no green plants!!! Why??? My answer is correct!!!
Total number of plants: 500.
Total green plants: 380.
Total no green plants: 120.
Why???
SecondChildUserIdTAG: 1031994
SecondChildUserNameTAG: Andrea33
SecondChildCreateTimeTAG: 2013-02-27T18:00:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Why??? Why error??? The bar graph #2 and #4 are the same bar graph!!! 380 green plants and 120 no green plants!!! Why??? My answer is correct!!!
Total number of plants: 500. Total green plants: 380. Total no green plants: 120.
Why???
FirstChildUserIdTAG: 1031994
FirstChildUserNameTAG: Andrea33
FirstChildCreateTimeTAG: 2013-02-27T18:01:02Z
FirstChildVoteTAG: 1
SecondChildTAG: bar graph #4 has the right variable at vertical axis not #2
SecondChildUserIdTAG: 1059727
SecondChildUserNameTAG: nofal
SecondChildCreateTimeTAG: 2013-02-27T18:08:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Why? Because you didn't read the paragraph on the practice page telling you how to read graphs.
>My answer is correct!!!
No, it is not.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T20:49:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I can read a graph!
I have a bit more trouble reading microscopic letters!!!
The problem was to read what was written on the y-axis, not knowing how to read a chart!
SecondChildUserIdTAG: 1031994
SecondChildUserNameTAG: Andrea33
SecondChildCreateTimeTAG: 2013-03-01T20:47:22Z
SecondChildVoteTAG: 0
FirstChildTAG: no. they are not the same , look at the vertical axis of both bar graphs, trick is there
FirstChildUserIdTAG: 1059727
FirstChildUserNameTAG: nofal
FirstChildCreateTimeTAG: 2013-02-27T18:06:59Z
FirstChildVoteTAG: 2
IndexTAG: 2152
TitleTAG: Exercise set 3b
Hi,
I don't understand why the answer for this question is calculated the way they explain it.
Why consider "10+(5/28)*(25-10)=12.68 thousand dollars" insted of 20+(5/28)*(25-10)= 27.32????
I got it wrong and I don't undestand what that "10" means... Because the percentage that are in the table is 20% !!
UserIdTAG: 1243742
UserNameTAG: AnaMenezes
CreateTimeTAG: 2013-02-27T16:07:27Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: 10 refers to the previous interval . 0-10 .
We are finding 25th percentile so it lies between 20and 48
we know 0-10 is 20th percentile now we need to fine 25th percentile
so now remaining 5% is included in the next interval that is 10-25 which is 28
5/28 (25-10)
We have to add the 20th percentile
which is 10+(5/28)(25-10)Hope this helped.
FirstChildUserIdTAG: 1177608
FirstChildUserNameTAG: Gayatris
FirstChildCreateTimeTAG: 2013-02-27T16:40:27Z
FirstChildVoteTAG: 2
SecondChildTAG: Yes, thanks! I didn't understand the formula at first.
I was wrong.
SecondChildUserIdTAG: 1243742
SecondChildUserNameTAG: AnaMenezes
SecondChildCreateTimeTAG: 2013-02-27T16:49:18Z
SecondChildVoteTAG: 0
FirstChildTAG: Ana, I am sure that you pretty much understand the materials. You just make one simple mistake.
The "10 + (5/28) (25-10)". This is the formula that you create to find the income of people at the 25th percentile.
Lets break down this formula and see what it actually calculate:
1) The 25-10 is the range. In the interval $10,000 to $25,000, the distance or range is $15,000. This is why we subtract 25-10.
2) The 5/28 is the fraction or the ratio. In the interval 10 to 25, there are 28 percent of the population fall into this interval. But we only want 5% of the 28%. This is why we divide 5/28. And the reason we only want 5% because in the first interval 0 to 10 (or $0 to $10,000) there is only 20% and we want to find the amount of income at the 25th percentile.
3) So when we do the calculation (5/28)* 15,000 = 2,678.57 dollars
4) And if we add this 2,678 to the 10,000 we get 12,678 or 12.68. This 12,678 is the amount people are making at 25th percentile.
So if you 20% + 2,678 = ? it doesn't make sense because how can we add percent with dollars.
Hope this helps.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-27T17:09:47Z
FirstChildVoteTAG: 1
IndexTAG: 2153
TitleTAG: Confusion
It seems there are a lot of people that got confused which formula/technique to use. I wonder if these people know that there are more than one video in a section of the courseware. The formula for calculating percentiles in a histogram was explained in Lecture 2.4, and Lecture 2.5, in the same section of the courseware, explained how to do it in a list. Some of the people who posted here insisted to apply the formula for histograms in the stem-and-leaf plot, which is obviously a list, and therefore got the wrong answers in Problem 2.
Anyway, congratulations to those who got 20/20! :) And yes, the box plot was a surprise, but I guess it was a good way to test whether we understood concepts in the lectures or just memorized formulas and skipped to the exercises.
UserIdTAG: 1148939
UserNameTAG: markasunread
CreateTimeTAG: 2013-02-27T16:05:53Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I agree, There is some confusion between the lectures and the class text. I'm still trying to figure out histograms and area/width/height of bins!
FirstChildUserIdTAG: 1246920
FirstChildUserNameTAG: dzame
FirstChildCreateTimeTAG: 2013-02-27T17:08:31Z
FirstChildVoteTAG: 0
IndexTAG: 2154
TitleTAG: Width of interval-20 to 10
Width is 30 because 10-(-20)=30 ,how it come width is 10
Please explain to me thanks
UserIdTAG: 691318
UserNameTAG: Feda94
CreateTimeTAG: 2013-02-27T15:50:50Z
VoteTAG: 11
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: I agree. The width should be 30, so it is in the second part.
FirstChildUserIdTAG: 257327
FirstChildUserNameTAG: sebastian_sagv
FirstChildCreateTimeTAG: 2013-02-27T16:09:54Z
FirstChildVoteTAG: 2
SecondChildTAG: It's a mistake. See earlier questions and answers. The correct width is 30.
SecondChildUserIdTAG: 773223
SecondChildUserNameTAG: Andaponte
SecondChildCreateTimeTAG: 2013-02-27T16:11:21Z
SecondChildVoteTAG: 0
SecondChildTAG: The drink a shot gamesters must be sozzled out to continue.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T16:34:26Z
SecondChildVoteTAG: 0
SecondChildTAG: I need to run to the liquor store to get more booze.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T16:37:02Z
SecondChildVoteTAG: 0
SecondChildTAG: merhutchin I thought everyone who were in the shot game are down and out by now ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T16:39:34Z
SecondChildVoteTAG: 0
SecondChildTAG: When the course is over we need to see if there's a correlation between someone's final score and their blood/alcohol level.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T16:50:35Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with the width being 30. I don't agree with the liquor jokes...!!!
SecondChildUserIdTAG: 310381
SecondChildUserNameTAG: kimefa
SecondChildCreateTimeTAG: 2013-02-27T17:09:18Z
SecondChildVoteTAG: 0
SecondChildTAG: HA!
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-02-27T17:45:37Z
SecondChildVoteTAG: 0
FirstChildTAG: because the question is width, you should ignore "minus".. from -10 to 20.. so the correct answer is 10 (20-10)..not (20-(-10)).. got it?
FirstChildUserIdTAG: 1213285
FirstChildUserNameTAG: JUSTANDY
FirstChildCreateTimeTAG: 2013-02-27T17:56:17Z
FirstChildVoteTAG: 1
SecondChildTAG: The correct width is 30. If you apply the formula, then width = Right endpoint - Left endpoint = 20 - (-10) = 30.
And if you just use common sense, then the width of the class interval is 30 units, not 10.
SecondChildUserIdTAG: 1260768
SecondChildUserNameTAG: Arjunkh
SecondChildCreateTimeTAG: 2013-02-27T18:18:34Z
SecondChildVoteTAG: 0
FirstChildTAG: I wonder why no-one has posted this before? It's been up for a week. Oh wait....hic
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:36:00Z
FirstChildVoteTAG: 2
IndexTAG: 2155
TitleTAG: Correct answers marked as wrong
(30*100)/270= 11.1111111111 and so on. I answered it as 11.11 and it was marked as wrong. When I checked the answer it said 11.1 . I don't understand, how can a more precise answer be marked as wrong?
UserIdTAG: 1183029
UserNameTAG: kajubadam
CreateTimeTAG: 2013-02-27T15:47:48Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: because the requirement was to round to first decimal number 11.1, or if the requirement was missing, the previous exercises had one, therefore you should know :P
FirstChildUserIdTAG: 1083985
FirstChildUserNameTAG: noneA
FirstChildCreateTimeTAG: 2013-02-27T16:25:51Z
FirstChildVoteTAG: 0
IndexTAG: 2156
TitleTAG: problem 5
All true except problem # 5 , Damn it is FIVE points
UserIdTAG: 1151146
UserNameTAG: wess339
CreateTimeTAG: 2013-02-27T15:47:12Z
VoteTAG: 9
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: It just looked so easy! If only I had noticed it was 5 points before I rashly answered. If anyone is reading this before answering that question, take your time. I won't go so far as to call it a trick question, but it's a tricky one.
FirstChildUserIdTAG: 1060592
FirstChildUserNameTAG: Lucius513
FirstChildCreateTimeTAG: 2013-02-27T20:39:13Z
FirstChildVoteTAG: 1
IndexTAG: 2157
TitleTAG: Week 2 lectures
It is 27th, but no lectures posted - when will they be posted?
UserIdTAG: 220333
UserNameTAG: jeya
CreateTimeTAG: 2013-02-27T15:33:43Z
VoteTAG: 15
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Agreed, but please search for "week 2" and up-vote the thread that says exactly the same thing... that's what I did before making my thread.
That way, the burning issues (like delays in getting the lectures out) are addressed!
If you click on my name above you can then click through to the relevant post to upvote it...
FirstChildUserIdTAG: 229679
FirstChildUserNameTAG: Ahsen
FirstChildCreateTimeTAG: 2013-02-27T15:41:57Z
FirstChildVoteTAG: 3
IndexTAG: 2158
TitleTAG: And a perfect 20
Nice exercise this one, expect the other following ones to be as interesting as this one :)
UserIdTAG: 1140772
UserNameTAG: pavelgupta
CreateTimeTAG: 2013-02-27T15:28:15Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: which percentile you think you're in?
FirstChildUserIdTAG: 955096
FirstChildUserNameTAG: yoav_v
FirstChildCreateTimeTAG: 2013-02-27T16:24:58Z
FirstChildVoteTAG: 0
IndexTAG: 2159
TitleTAG: pls,be concrete
Oh please be careful with the task. You ask about the percentage, so ask concrete: wheather to write 0.1 or 10. This is actually the same. but only in different manner. It's a pity to see that the right answer is not correct.
UserIdTAG: 1278715
UserNameTAG: tanygavrilova
CreateTimeTAG: 2013-02-27T15:25:27Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2160
TitleTAG: problem 2 missing for exercise set 1
problem 2 is missing. so i cant complete the task. has the problem being removed.
UserIdTAG: 1058906
UserNameTAG: Debbi
CreateTimeTAG: 2013-02-27T15:20:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Still there. Refresh or try a different browser
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:46:10Z
FirstChildVoteTAG: 0
IndexTAG: 2161
TitleTAG: Exercise set 2 Problem 5
I am sorry but I couldn't get very well problem 5. Could someone help me to understand it fully?
Thanks
UserIdTAG: 1121129
UserNameTAG: sarah_lupu
CreateTimeTAG: 2013-02-27T15:17:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2162
TitleTAG: practice exercise 2: calculation error
i believe the denominator for question 2 a) should be 30 instead of 10.
UserIdTAG: 1146660
UserNameTAG: Drsidrao
CreateTimeTAG: 2013-02-27T15:12:24Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 155350
FirstChildUserNameTAG: ingenieur
FirstChildCreateTimeTAG: 2013-02-27T15:19:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Please read the existing threads and course information before posting a new discussion.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T15:21:49Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you, I needed some vodka for breakfast.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T16:53:18Z
FirstChildVoteTAG: 0
FirstChildTAG: My liver does not like you.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:45:19Z
FirstChildVoteTAG: 0
IndexTAG: 2163
TitleTAG: download lectures
Hi, is there any way to download lectures with their relative text subtitles ? thanks
UserIdTAG: 1246720
UserNameTAG: lilia1979
CreateTimeTAG: 2013-02-27T15:10:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: thanks to edx staff for making the videos available for downloading. I couldnt have carry forward with the course otherwise :)
FirstChildUserIdTAG: 157588
FirstChildUserNameTAG: Chopra
FirstChildCreateTimeTAG: 2013-02-27T16:15:16Z
FirstChildVoteTAG: 2
IndexTAG: 2164
TitleTAG: The difference between check and submit
Well I've discovered that like the old adage says, the USA and Britain are two nations divided by a common language.
In Exercise Set 1 I "checked" Problem 1 to make sure I had clicked all the radio buttons. To my surprise I found I had submitted the problem. Subtle difference of meaning here.
Of course I then discovered that somehow I no longer had the radio buttons selected.
I guess when I hit the browser back button to "check up" on an answer in the notes I somehow deselected my answers.
Oh well. I'll know better the next time.
UserIdTAG: 1150437
UserNameTAG: jimnite
CreateTimeTAG: 2013-02-27T14:55:35Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2165
TitleTAG: Problem 7-I got it, but i do't exactly why it is so?
i have got the answer for problem 7. however, i am not confident that the reason behind my answer is correct. is it because exp 5 have highest maximum than exp 4 or i should analyze drawing a histogram of each problem?
UserIdTAG: 921985
UserNameTAG: heny
CreateTimeTAG: 2013-02-27T14:51:18Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: There is a relationship between the height of the bar, and the area of the bar (which is the % divided by the width). The summary slide of the histogram shows the formula for that (about minute 14:06 on video 2.2). If you work that out for any of the existing intervals, then you can use the result to work out the missing height. There is no obvious guess result. You have to do the calculation.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T15:15:31Z
FirstChildVoteTAG: 0
FirstChildTAG: In a histogram, the height of a particular bin is based on how "crowded" that bin is: how many variables are in the range for that bin. If you have a large number of variables in a small range, then you have a high peak. In a box plot, the distance between lines is inversely related to number of variables between those lines. If you have a large number of variables in a small range, then you have two lines very close to each other.
Thus, if you have two lines on your box plot very close together, you will have a very high peak on your histogram.
In Experiment 4, you can see that all of the lines are almost perfectly uniform, so no high peaks. But in Experiment 5, the 25% line and the median line are almost on top of each other. That means all of the measurements in the 25% to 50% range were nearly identical (very crowded), so the histogram will have a peak in this range.
Anyway, that's how I got my answer, hopefully it's right.
FirstChildUserIdTAG: 950537
FirstChildUserNameTAG: cjc71
FirstChildCreateTimeTAG: 2013-02-27T22:17:13Z
FirstChildVoteTAG: 0
IndexTAG: 2166
TitleTAG: Round your answer to one decimal place...
If I will answer 7.0 it equals 7? and vice versa.
Thanks
UserIdTAG: 759395
UserNameTAG: Gen_Art
CreateTimeTAG: 2013-02-27T14:44:45Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You should be OK with just 7, I believe, but I can't be 100% sure.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T14:58:25Z
FirstChildVoteTAG: 0
IndexTAG: 2167
TitleTAG: Sathian
I got 20/20
UserIdTAG: 367734
UserNameTAG: drsathian
CreateTimeTAG: 2013-02-27T14:44:31Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Great...
FirstChildUserIdTAG: 1236052
FirstChildUserNameTAG: neelam25
FirstChildCreateTimeTAG: 2013-02-28T09:34:20Z
FirstChildVoteTAG: 0
IndexTAG: 2168
TitleTAG: Exercise Set 1
Do I have another chance if I miss the deadline of 27 February. I am swamped up by too many tasks
UserIdTAG: 1084257
UserNameTAG: Matsika
CreateTimeTAG: 2013-02-27T14:31:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I don't think so !!
Anyway most of us are busy and for eg I had to sit at 2 AM to do my exercises after operating the whole day and receiving calls about patients (calls through the night and be up and about to operate next day !! It is all about choices and time management.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T14:34:19Z
FirstChildVoteTAG: 0
SecondChildTAG: There should no extensions-No exceptions. We are all busy with other stuff. Rules have to apply fairly to all.
SecondChildUserIdTAG: 722050
SecondChildUserNameTAG: aswanifj
SecondChildCreateTimeTAG: 2013-02-27T15:19:50Z
SecondChildVoteTAG: 0
FirstChildTAG: There seems to be an issue with people posting discussion without actually reading ANY of the material associated with the course or its policies.
You will find all the answers to your question here:
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
Also, please read the course info (there is a menu on the right):
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/info
Finally, search the discussion forum for your question before posting it and use the available threads.
Even if you're swamped, it doesn't take long to do these things. It may sound a bit intolerant, and I apologize for that, but there are 47000 people in this course, so let's keep the discussion forum for the more important LEARNING questions, or at least the original ones. It will be better for all of us, yourself included.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T14:54:51Z
FirstChildVoteTAG: 0
FirstChildTAG: > There seems to be an issue with people posting discussion without actually reading ANY of the material associated with the course or its policies.
Yes. And I think some are not even watching the lectures before attempting the problems.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:44:26Z
FirstChildVoteTAG: 0
IndexTAG: 2169
TitleTAG: Incorrect options for Exercise Set 2 Problem 3 (b)?
I'm just wondering if the histograms shown for this problem are incorrect. There should be up to six BINS in each with a variation in height and width reflecting the relative frequencies of each BIN.
The first is reflective of a bar chart with no change in width or height for the BINs.
The second and third have variations but only five bars.
Please help me if I'm misreading the question of to confirm that there maybe an error with the options. Thanks
UserIdTAG: 1220073
UserNameTAG: fconway
CreateTimeTAG: 2013-02-27T14:19:19Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The question is correct.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T14:22:58Z
FirstChildVoteTAG: 0
FirstChildTAG: The same thing happened to me when I first looked at the charts. But have a look at the bins and what ranges of scores they include. Don't necessarily assume that there will be 6 bins just because you see 6 ranges of scores... Also, look for shapes. I believe that as units are not specified, your calculations could be different to the numbers that you see on the vertical axes of the charts in the question. However, if you draw your own histogram based on your own calculations, then compare it to the charts, you will find one chart that is similar in shape and others that are quite obviously different.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T14:44:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks. I see it now. Too late for me. :(
FirstChildUserIdTAG: 1220073
FirstChildUserNameTAG: fconway
FirstChildCreateTimeTAG: 2013-02-27T14:49:14Z
FirstChildVoteTAG: 0
IndexTAG: 2170
TitleTAG: How to use Edx videos
There was an introductory video "How to use Edx" which used to be the first lecture.It gives an idea how to navigate the web site etc.That has been removed.Maybe it is wise to have it still as it would help people to navigate the site as there still seems to be a lot of confusion regarding it.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-27T14:17:14Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2171
TitleTAG: Should I watch the video in the Online Textbook?
Should I watch it? does it matter if I do not watch it?
UserIdTAG: 498723
UserNameTAG: YLTO
CreateTimeTAG: 2013-02-27T13:56:47Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I don't think it will change your life, but the link lasts just some minutes (it's not the whole 1 hour plus video, if that's what scaring you)
FirstChildUserIdTAG: 250161
FirstChildUserNameTAG: gaurwraith
FirstChildCreateTimeTAG: 2013-02-27T14:04:10Z
FirstChildVoteTAG: 0
SecondChildTAG: Sometimes I feel it is pointless to watch the edX lecture since edX Lecture is a subset of the Real Berkeley Lecture.
SecondChildUserIdTAG: 498723
SecondChildUserNameTAG: YLTO
SecondChildCreateTimeTAG: 2013-02-27T14:55:44Z
SecondChildVoteTAG: 0
FirstChildTAG: I think while learning it is best to get differnet sources of information even if repetitive.It helps
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T14:09:11Z
FirstChildVoteTAG: 0
IndexTAG: 2172
TitleTAG: Histograms
Dear Lecturers and fellow students
How do I know whether the data is uniformly distributed? I fail to understand how to know when given a set of values like in Exercise 2.
Kind Regards
L B Tsie
UserIdTAG: 1149526
UserNameTAG: LoneBTsie
CreateTimeTAG: 2013-02-27T13:54:57Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 3
FirstChildTAG: You assume uniformity of distribution based on the context.For eg if there is an impossible value in the distribution it will be ununiform so the uniformity assumption will not be correct. You will have to see the data or make an inelligent guess at times.Sometimes logical analysis will guide you.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T14:11:14Z
FirstChildVoteTAG: 0
SecondChildTAG: Prof. A , I do have the same doubt as mentioned above. Please help us out here.
SecondChildUserIdTAG: 379141
SecondChildUserNameTAG: NitishRaole
SecondChildCreateTimeTAG: 2013-02-27T18:28:32Z
SecondChildVoteTAG: 0
SecondChildTAG: You assume that the uniformity of the data is evenly distributed when there are flat tops on the histograms.
SecondChildUserIdTAG: 1181463
SecondChildUserNameTAG: gene14
SecondChildCreateTimeTAG: 2013-02-28T00:45:22Z
SecondChildVoteTAG: 0
SecondChildTAG: I guess one assume the data is uniformly distributed when you lack data, or when estimations don't affect very much the truth of the claims you will made from the data. Incomes might be not very important for public to know about precisely.
In other cases, like medicine you must have very precise data in order to make claims based on such data, so you can´t just assume certain uniformity.
SecondChildUserIdTAG: 1206104
SecondChildUserNameTAG: Lupita_amancio
SecondChildCreateTimeTAG: 2013-02-28T05:05:33Z
SecondChildVoteTAG: 0
FirstChildTAG: The only way to know if the data is uniformly distributed is to look at the actual data. What we are learning here is how to estimate without looking at and working with the actual data. So I think the professor keeps harping on the assumption part so that we always remember that these are just estimates -- sometimes they will be accurate, some times close enough, and sometimes way off.
FirstChildUserIdTAG: 950537
FirstChildUserNameTAG: cjc71
FirstChildCreateTimeTAG: 2013-02-27T20:28:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you watch and listen to the lectures? This concept was explained.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:42:35Z
FirstChildVoteTAG: 0
IndexTAG: 2173
TitleTAG: how to contact lecturer
In case we have certain doubts in lecture slides does anyone know how to contact Prof A? it would be convenient if there is a way
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-02-27T13:34:31Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Use the Discussion Board that belongs to the video for your questions. Other students might have helpful additions, or, if they have the same issues, can vote for your question (in the top right corner) so the post will catch more attention. This might help: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
FirstChildUserIdTAG: 591304
FirstChildUserNameTAG: KMV
FirstChildCreateTimeTAG: 2013-02-27T13:42:59Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks KMV
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-02-28T10:33:14Z
SecondChildVoteTAG: 0
IndexTAG: 2174
TitleTAG: Help
please i cant understand Question a) Height of -10 to 20 bar = ____________ % per unit, Help me please
UserIdTAG: 849174
UserNameTAG: Belhajji
CreateTimeTAG: 2013-02-27T13:16:23Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Please see courseware errata
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T13:25:48Z
FirstChildVoteTAG: 2
SecondChildTAG: nice answer prasanna, next time be more helpful please.
SecondChildUserIdTAG: 1316389
SecondChildUserNameTAG: camavego
SecondChildCreateTimeTAG: 2013-02-27T15:59:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Prasannasimha's answer *is* helpful because it's showing Belhajji how he can answer his own question in a matter of minutes rather than posting a duplicated question on the discussion forum and wasting his time waiting for an answer.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T16:56:03Z
SecondChildVoteTAG: 0
IndexTAG: 2175
TitleTAG: chapter 4
I don't know how to accede ( find, enter) to the set of problems for Chapter 4. Thank you
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-02-27T13:05:58Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The last set of exercises is
set3
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T13:25:24Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you.I have to wait!!
SecondChildUserIdTAG: 1291666
SecondChildUserNameTAG: norabram
SecondChildCreateTimeTAG: 2013-02-27T16:17:10Z
SecondChildVoteTAG: 0
IndexTAG: 2176
TitleTAG: Why we don't cover skewness?
I wonder why we don't cover skewness though in the textbook they cover it - chapter 3?
UserIdTAG: 498723
UserNameTAG: YLTO
CreateTimeTAG: 2013-02-27T12:58:51Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 2
FirstChildTAG: We have just started the course. I am hopeful, it will be covered going forward.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T13:35:02Z
FirstChildVoteTAG: 0
SecondChildTAG: But hey, they cover it in the textbook - chapter 3.
SecondChildUserIdTAG: 498723
SecondChildUserNameTAG: YLTO
SecondChildCreateTimeTAG: 2013-02-27T14:02:04Z
SecondChildVoteTAG: 0
SecondChildTAG: So, in that case let us assume that some concepts would be introduced thru self learning! Besides, the textbook may have wide range of topics, not everything would be included in the course.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-27T14:03:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok. Did you watch the video in the text book anyway?
SecondChildUserIdTAG: 498723
SecondChildUserNameTAG: YLTO
SecondChildCreateTimeTAG: 2013-02-27T14:20:40Z
SecondChildVoteTAG: 0
SecondChildTAG: in part, yes.
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-27T18:15:15Z
SecondChildVoteTAG: 0
FirstChildTAG: The topics in the text and the video lectures won't be exactly the same. For example, in Week 3 I'll do the normal approximation for data, but the text doesn't cover it. You should expect significant overlap between text and video lectures, but the videos won't be "following the text" or vice versa. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T01:54:35Z
FirstChildVoteTAG: 1
IndexTAG: 2177
TitleTAG: exercise set 3 problem 2
I assume one translates the leaf and stem to to a table and calculates the percentiles as before - yes?
UserIdTAG: 1110758
UserNameTAG: jcu
CreateTimeTAG: 2013-02-27T12:47:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Add (count) all the 'leaves'. That gives you length of the list. Once you have the length, calculate p% as shown in the video lecture. Also note that the list is automatically sorted. So locating the p% is easy.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T13:14:58Z
FirstChildVoteTAG: 0
FirstChildTAG: There are 28 leaves.. Do you mean add 48 +59 + 63 ...that total would make no sense.
So is the length 28? Are the bins 0-50, 50-60, 60-70,..?
would the chart look like this?
0-50 1 3.6 3.6
50-60 1 3.6 7.2
60-70 4 14.2 21.4 ...
so 20% would fall in the third line and the formula for the percentile would be 60 + 12.8/14.2 * 10?
FirstChildUserIdTAG: 1110758
FirstChildUserNameTAG: jcu
FirstChildCreateTimeTAG: 2013-02-27T15:30:43Z
FirstChildVoteTAG: 0
SecondChildTAG: length is 28. That's what I meant (count of leaves). Sorry if 'add' confused you.
Refer to the below thread for details.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/512dccfc4f48df22000000c6
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-27T18:19:04Z
SecondChildVoteTAG: 0
FirstChildTAG: I cannot give you the exact answers but if you remember the lecture 2.5 it is very similar to that. Its just you have to write the numbers down from the stem and leaf. Prof. used a bunch of random number its the same way you do this problem.
FirstChildUserIdTAG: 1177608
FirstChildUserNameTAG: Gayatris
FirstChildCreateTimeTAG: 2013-02-27T16:49:00Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you watch the relevant lecture? This was all explained.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:40:20Z
FirstChildVoteTAG: 0
IndexTAG: 2178
TitleTAG: Is doing the practice sets necessary ?
Hi,
I wanted to know if doing the practice sets necessary or if these are considered for evaluating the performance in the course. Can someone please let me know ?
Thanks,
Avinash.
UserIdTAG: 1014053
UserNameTAG: Avinash101
CreateTimeTAG: 2013-02-27T12:37:52Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: **@Avinash -** The practice scores do not count towards the final grade in this course. (Please refer to the progress page, the practice score is not shown in the bar graph).
About practice test being important, IT IS VERY IMPORTANT TOWARDS sound learning.
Please take your own call.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T13:17:20Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Avinash101,
I believe you're asking whether doing the practice sets will count towards your grade? No, not as points scored. They are there to help with comprehension, should you need it.
Thanks, Artimehta, for helping Avinash101. Since this is a "course administration" question, I'm just officially confirming what you said.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-28T01:52:19Z
FirstChildVoteTAG: 0
IndexTAG: 2179
TitleTAG: Of whining and complaining...
I can't seem to understand why so many people are airing complaints in the discussions. Are these people really studying or what? If you find it difficult to solve the exercises with the given references, then the internet is all yours for taking. The information posted in the world wide web is so huge that you'll get good materials to aid you in solving the exercises.
What makes it more funny is that for some creative questions, people are whining because it was not discussed and all those stuffs. Honestly, my niece who is a second grader, nailed the questions about the box plot. Got problems with that?
No pain, no gain. Study, study, study and you'll learn, learn, learn.
UserIdTAG: 1300259
UserNameTAG: princejune86
CreateTimeTAG: 2013-02-27T12:32:09Z
VoteTAG: 15
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: People are spending quality time in airing complaints instead of devoting that precious time for studies. The course is simple and straightforward and people should not have any problems getting through with the course material.
FirstChildUserIdTAG: 1256932
FirstChildUserNameTAG: SandeepNarang
FirstChildCreateTimeTAG: 2013-02-27T13:42:17Z
FirstChildVoteTAG: 4
FirstChildTAG: The thing with moocs is that anyone can join. Unfortunately not everyone is capable of doing the material. But they want to. Hence the problems.
And it does seem that some are trying to answer questions without watching the lecture. Or they slept through the lecture - because they are asking questions that the lecture should have answered for them.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:39:43Z
FirstChildVoteTAG: 1
IndexTAG: 2180
TitleTAG: *IMPORTANT* regarding practice set 2
We are a community of around 40,000 students from different places, timezones and schedules.
Having said, I think we should all strive to use some common sense when using the discussion forums. Seriously, how many times has the question regarding the 20-(-10) been asked? And it was only a practice set question, not one from the actual graded exercises.
If something similar is to happen in the upcoming exercises, we should all try to minimize the number of similar posts by:
1) Searching for the topic on the left....by word or exercise, not really that difficult.
2) Checking the errata on the Wiki page.
The discussion forums should support *STICKY* topics, but since there's no such thing available, here's my *IMPORTANT* tag to bring attention to this nuisance.
Thanks and good luck everybody.
UserIdTAG: 1068140
UserNameTAG: MrKeSh
CreateTimeTAG: 2013-02-27T12:26:49Z
VoteTAG: 10
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 155350
FirstChildUserNameTAG: ingenieur
FirstChildCreateTimeTAG: 2013-02-27T15:18:48Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks for posting the course errata link, ingenieur!
SecondChildUserIdTAG: 1152094
SecondChildUserNameTAG: CristianOpazo
SecondChildCreateTimeTAG: 2013-02-27T21:15:42Z
SecondChildVoteTAG: 0
IndexTAG: 2181
TitleTAG: Problem with question a of lecture 2.2-2.3 from practice for exercise set 2
The question asks the height of the -10 to 20 bar.
as height = Rf / width of class interval, it should me 0.46.
The Rf is 14 and the width is 30 (-10 to 20).
But the given answer is 1.46 and takes the width of interval as 10.
Please check it and resolve this confusion.
UserIdTAG: 919599
UserNameTAG: raviaudichya
CreateTimeTAG: 2013-02-27T12:24:27Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: yes,you are right.In future,please read the forum before starting a new topic:)
FirstChildUserIdTAG: 1617
FirstChildUserNameTAG: sid3930
FirstChildCreateTimeTAG: 2013-02-27T12:35:05Z
FirstChildVoteTAG: 0
FirstChildTAG: > Please check it and resolve this confusion.
The only confusion is with people who can't use the forums properly.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T20:38:03Z
FirstChildVoteTAG: 0
IndexTAG: 2182
TitleTAG: Hi from Côte d'Ivoire
This was a nice test!
UserIdTAG: 844176
UserNameTAG: MDJOBO
CreateTimeTAG: 2013-02-27T12:07:41Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: yeah I got it all correct
FirstChildUserIdTAG: 1051058
FirstChildUserNameTAG: reshmamathews
FirstChildCreateTimeTAG: 2013-02-27T12:34:10Z
FirstChildVoteTAG: 0
IndexTAG: 2183
TitleTAG: PRACTICE EXERCISE FOR SET 1 NOT GRADED
I completed the practice exercise for set 1 and it is not graded. Practice exercise for set 2 has been graded... Am I missing something?
UserIdTAG: 1207788
UserNameTAG: NRHassan
CreateTimeTAG: 2013-02-27T12:07:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Practice exercise sets are not graded...they are just there so that you get acquainted to the actual ones :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-27T12:16:58Z
FirstChildVoteTAG: 0
IndexTAG: 2184
TitleTAG: last minute
Hi all, a word of advice, always finish the assignment early enough...
UserIdTAG: 1281184
UserNameTAG: Otur
CreateTimeTAG: 2013-02-27T11:30:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: That's right.
FirstChildUserIdTAG: 1256932
FirstChildUserNameTAG: SandeepNarang
FirstChildCreateTimeTAG: 2013-02-27T11:57:50Z
FirstChildVoteTAG: 0
IndexTAG: 2185
TitleTAG: Course Test Book
please can any one show me where I can get the course textbook? Thank you.
UserIdTAG: 967511
UserNameTAG: BlanksonJC
CreateTimeTAG: 2013-02-27T11:30:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: There are links in the exercises and there is a link at the bottom of the Wiki page.
It's online, free, and includes videos and applets.
FirstChildUserIdTAG: 987070
FirstChildUserNameTAG: AStanford
FirstChildCreateTimeTAG: 2013-02-27T11:34:17Z
FirstChildVoteTAG: 0
IndexTAG: 2186
TitleTAG: Problem 2
a) About what percent of the people were in their thirties? Round your answer to one decimal place.
b) A common (though not universal) definition of "senior citizen" is "person over the age of 65". About what percent of the population were senior citizens? Round your answer to one decimal place.
Please please Help
UserIdTAG: 894282
UserNameTAG: Maheen91
CreateTimeTAG: 2013-02-27T11:17:32Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: a) This question asks you to find the percentage of people who's ages are in the range 30,31...39.Remember that "people are uniformly distributed".
i.e if 7.1% of people lie in the 15-20 range.This assumption means that, the same percent of people are of the age 15,16,17,18,19.(the 7.1% is uniformly distributed among these ages.)
b)I think the above hint should help you get this as well:)
(EDIT:Corrected a mistake thanks to Dianebefd)
FirstChildUserIdTAG: 1617
FirstChildUserNameTAG: sid3930
FirstChildCreateTimeTAG: 2013-02-27T12:10:18Z
FirstChildVoteTAG: 1
SecondChildTAG: 65 includes people age 65. The expression 'over 65' means '65 and over'.
People in their twenties, thirties, forties,etc. are of an age in that decade, 20-29, 30-39. 40-49.
You are smart to check the meanings if English is not your first language. Even those with a high degree of fluency get tripped up on these distinctions. (I am an English language teacher.) A good resource for English language students is "Dave's ESL cafe" on the web. There is a section for students that has idiom, slang, grammar, and more.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T12:29:15Z
SecondChildVoteTAG: 0
SecondChildTAG: noted:)thanks for the advice:)
SecondChildUserIdTAG: 1617
SecondChildUserNameTAG: sid3930
SecondChildCreateTimeTAG: 2013-02-27T12:37:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, I had the same question about 65 years
SecondChildUserIdTAG: 1250949
SecondChildUserNameTAG: barcay
SecondChildCreateTimeTAG: 2013-02-27T16:05:00Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks! I had the same question about the '65 and over'
SecondChildUserIdTAG: 1282359
SecondChildUserNameTAG: smoncaleano
SecondChildCreateTimeTAG: 2013-02-27T18:03:07Z
SecondChildVoteTAG: 0
IndexTAG: 2187
TitleTAG: About calculations
why,30 out of 270 = 11.11% is wrong ? The given correct answer is 11.1%
I did the calculation manually and got the answer 11.11. I cant understand whats the error in my answer ?
The same thing is about the next answer i.e. 22.22% where the correct answer is 22.2%
Please elaborate
UserIdTAG: 1319645
UserNameTAG: MuktaN
CreateTimeTAG: 2013-02-27T11:17:25Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The answer must be rounded to one digit although not specified in the question.
FirstChildUserIdTAG: 1274977
FirstChildUserNameTAG: RichardBekhazi
FirstChildCreateTimeTAG: 2013-02-27T11:30:02Z
FirstChildVoteTAG: 0
SecondChildTAG: 11.11 = 11.1 = 11.11111111
There's an infinitely repeating decimal.
It's a problem with the site, as it only recognises up to 1 decimal. Your answer is correct.
SecondChildUserIdTAG: 1260768
SecondChildUserNameTAG: Arjunkh
SecondChildCreateTimeTAG: 2013-02-27T15:57:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Please be extremely careful in reading the INSTRUCTIONS about DECIMAL POINT and ROUNDING as the evaluation is done by auto-grader and not manually. The auto-graders are programmed to check specific decimal points, so even if the answer is correct, it might still get evaluated as wrong. Those who are new to online courses, this is an important point to remember.
For e.g. if you get the value of **11.45** from your calculation, and the question is asking you to round the answer to ONE decimal place, entering **11.45** may be given wrong as grader may be expecting **11.5**. Just an example.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T13:26:37Z
FirstChildVoteTAG: 0
SecondChildTAG: hm... no, your point doesn't work - there is NO INSTRUCTIONS at all
SecondChildUserIdTAG: 342603
SecondChildUserNameTAG: YakovO
SecondChildCreateTimeTAG: 2013-02-27T18:13:12Z
SecondChildVoteTAG: 0
SecondChildTAG: If you added '%' sign, then also it would be marked wrong...
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-27T18:20:34Z
SecondChildVoteTAG: 0
IndexTAG: 2188
TitleTAG: Question a)
Shouldn't the answer for a) be 0.4666. The range for -10 to 20 is 30, not 10.
UserIdTAG: 1320712
UserNameTAG: richiemuleya
CreateTimeTAG: 2013-02-27T11:17:05Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Hic
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T11:49:21Z
FirstChildVoteTAG: 1
SecondChildTAG: i think soo.
SecondChildUserIdTAG: 662088
SecondChildUserNameTAG: memedu
SecondChildCreateTimeTAG: 2013-02-27T12:22:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, I needed an excuse to drink more.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T16:42:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Yeah... it should be.
FirstChildUserIdTAG: 919599
FirstChildUserNameTAG: raviaudichya
FirstChildCreateTimeTAG: 2013-02-27T12:25:02Z
FirstChildVoteTAG: 0
IndexTAG: 2189
TitleTAG: Box plots lesson
Hi there,
I can't seem to find the lesson on box plots. Which one is it???
Thanks,
A
UserIdTAG: 1145082
UserNameTAG: Arabert
CreateTimeTAG: 2013-02-27T11:13:29Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: The only demonstration of box and whisker plot is in the question itself. Read the relevant question in ES3 slowly and carefully and you can answer the question easily.
FirstChildUserIdTAG: 413463
FirstChildUserNameTAG: Venkataramani
FirstChildCreateTimeTAG: 2013-02-27T11:26:40Z
FirstChildVoteTAG: 2
FirstChildTAG: just google the experiment so that you have an idea about this box-plot and whisker..
FirstChildUserIdTAG: 1231135
FirstChildUserNameTAG: shie112709
FirstChildCreateTimeTAG: 2013-02-27T11:42:34Z
FirstChildVoteTAG: 1
IndexTAG: 2190
TitleTAG: Homework submission
The homework due date was changed to Feb 27 23:30. However, no time zone is listed anymore next to the problem sets or in Course Info. Does this mean they must be submitted at 23:30 of whatever time zone the student resides?
UserIdTAG: 1266723
UserNameTAG: jumbolaya
CreateTimeTAG: 2013-02-27T10:59:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: it says GMT - somewhwere, honest!
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-27T11:01:13Z
FirstChildVoteTAG: 0
FirstChildTAG: There are Course Policy documents. You really should read them.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T11:05:08Z
FirstChildVoteTAG: 1
IndexTAG: 2191
TitleTAG: Kudos to the professors
I really liked the touch of creativity in the problems 3 and 4. Hopefully this will continue in the next sessions. It is much more interesting when you have to tackle sth different yet familiar.
UserIdTAG: 931186
UserNameTAG: niksteff1
CreateTimeTAG: 2013-02-27T10:54:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The more variations are there the more we will get to learn. Am sure this would continue in the forthcoming lectures and would get interesting as the problem sets become more and more complicated.
FirstChildUserIdTAG: 1256932
FirstChildUserNameTAG: SandeepNarang
FirstChildCreateTimeTAG: 2013-02-27T12:00:04Z
FirstChildVoteTAG: 0
IndexTAG: 2192
TitleTAG: Confused! Exercise Set 2 Problem 1 (a) & (c)
I just don't get the answers to Exercise Set 2 Problem 1 (a) & (c)! The interval 5-15 makes up 13.3 percent of the whole population. Then how come the answer claims there are more people in 15-20 interval?!
UserIdTAG: 1042271
UserNameTAG: Saeed19
CreateTimeTAG: 2013-02-27T10:36:55Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Why didn't you post this in the exercise 2 forum? It would make life so much easier if people used these forums properly!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T10:58:00Z
FirstChildVoteTAG: 1
FirstChildTAG: > Then how come the answer claims there are more people in 15-20 interval?!
It doesn't. Read the question again.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T10:58:59Z
FirstChildVoteTAG: 0
FirstChildTAG: There are two concepts here.
One is the absolute number of people in a given interval and another one is NUMBER OF PEOPLE PER UNIT OF MEASUREMENT within the interval. This second one is called density.
So it is possible that a given interval has more number of people but the area of the interval being large, the people are scattered and hence the density is less.
Try to use this concept while evaluating options. It will help.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T13:33:51Z
FirstChildVoteTAG: 0
IndexTAG: 2193
TitleTAG: how to sort excel table horizontally
how to sort the numbers of a table horizontally in excel:
-1 2 -74 -44 -19 -60 -106 -83 -86 -79
-24 -12 14 -74 -50 41 14 72 -15 -107
-71 -128 -35 -120 18 -101 -19 -67 24 -27
-106 0 150 0 14 -132 -14 18 -14 51
-37 -34 -59 -113 29 -83 -38 -108 -61 -16
45 -69 -34 -4 -71 -132 -89 -55 -24 19
-99 155 1 -12 -67 14 -112 -12 -16 -60
-43 -62 -19 -80 -19 -122 -49 29 -101 -74
7 -18 -105 -121 -27 -16 -48 -29 -65 -48
-80 -152 -52 -26 -87 -107 -54 -54 -47 -106
to:
-152 -132 -132 -128 -122 -121 -120 -113 -112 -108
-107 -107 -106 -106 -106 -105 -101 -101 -99 -89
-87 -86 -83 -83 -80 -80 -79 -74 -74 -74
-71 -71 -69 -67 -67 -65 -62 -61 -60 -60
-59 -55 -54 -54 -52 -50 -49 -48 -48 -47
-44 -43 -38 -37 -35 -34 -34 -29 -27 -27
-26 -24 -24 -19 -19 -19 -19 -18 -16 -16
-16 -15 -14 -14 -12 -12 -12 -4 -1 0
0 1 2 7 14 14 14 14 18 18
19 24 29 29 41 45 51 72 150 155
UserIdTAG: 1276679
UserNameTAG: lanmat_p
CreateTimeTAG: 2013-02-27T10:35:29Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: copy your data & use the paste "transpose" option to get in a column for vertical sorting?
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-27T10:58:24Z
FirstChildVoteTAG: 2
FirstChildTAG: If you really wanted to keep your horizontal data intact you can sort horizontal (left to right within a row). It's in the detail sort section of DATA in Excel 2003, 2007, 2010. You can control many options in that dialog box. If you need more help there let me know. But if you just need a simple way MarlanW described a good option.
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-03-01T01:18:04Z
FirstChildVoteTAG: 0
IndexTAG: 2194
TitleTAG: Can't see week 2!! Please make it visible, it's been the 27th forever!
Please make week 2 videos and assignments available already!
UserIdTAG: 229679
UserNameTAG: Ahsen
CreateTimeTAG: 2013-02-27T10:25:42Z
VoteTAG: 7
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > it's been the 27th forever!
Depends on where you are in the world.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T10:55:06Z
FirstChildVoteTAG: 3
SecondChildTAG: That's true! I did not think about that before!
SecondChildUserIdTAG: 1040395
SecondChildUserNameTAG: Bcandelario
SecondChildCreateTimeTAG: 2013-02-27T11:55:52Z
SecondChildVoteTAG: 0
SecondChildTAG: True, but I think the largest difference between any place in the US and the UK is about 10 hours. I posted 5 hours ago, at 10:30 GMT, which would mean no matter where in the US Berkley or edX is located, it would have been the 27th for at least half an hour. (I think)
SecondChildUserIdTAG: 229679
SecondChildUserNameTAG: Ahsen
SecondChildCreateTimeTAG: 2013-02-27T15:21:47Z
SecondChildVoteTAG: 0
SecondChildTAG: And the first week was released at approx 5pm London time.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T20:36:58Z
SecondChildVoteTAG: 0
IndexTAG: 2195
TitleTAG: doubt about letter a of set 2 exercise - lecture 2.2/2.3
Why the width was considered 10 if 20 - (-10) = 30 ? It should be 30 not 10, shouldn't it?
I didn't understood why was considered 10, anybody could help me?
Thanks
UserIdTAG: 186546
UserNameTAG: CrisBogsan
CreateTimeTAG: 2013-02-27T10:16:02Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: At this rate my liver will be shot by morning.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T10:18:15Z
FirstChildVoteTAG: 2
SecondChildTAG: you need to study the links on Lectures 2.2 and 2.3 first:
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#frequency_tables
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#histograms
SecondChildUserIdTAG: 1042271
SecondChildUserNameTAG: Saeed19
SecondChildCreateTimeTAG: 2013-02-27T10:28:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Time for a drink!
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T16:44:21Z
SecondChildVoteTAG: 0
FirstChildTAG: It is 30 not 10
FirstChildUserIdTAG: 1274977
FirstChildUserNameTAG: RichardBekhazi
FirstChildCreateTimeTAG: 2013-02-27T11:33:04Z
FirstChildVoteTAG: 1
FirstChildTAG: Hi there ..
I think you are right .. the explanation on the video shows that the width is the upper endpoint minus the lower one .. it means 30 and not 10 ..
regards
FirstChildUserIdTAG: 1003275
FirstChildUserNameTAG: ourholm
FirstChildCreateTimeTAG: 2013-02-27T18:20:21Z
FirstChildVoteTAG: 0
IndexTAG: 2196
TitleTAG: Feedback and request re: number of submissions
Dear Profs,
You have introduced an entirely new concept of box plots and yet the answers are allowed only one submission. By contrast, the material covered in the lectures is tested with an allowance for two submissions.
I don't see the logic. Please consider allowing for two submissions on all questions, consistently in this course.
Thank you.
UserIdTAG: 1182448
UserNameTAG: dcwebster
CreateTimeTAG: 2013-02-27T10:03:08Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I think that exercise was intended to measure our ability to grasp concepts, and to do some figuring out on our own, our analytical and interpretative skills. So it is fair that the first submission is final. You get it by analyzing it or you don´t.
FirstChildUserIdTAG: 294031
FirstChildUserNameTAG: MarceHH
FirstChildCreateTimeTAG: 2013-02-27T10:54:38Z
FirstChildVoteTAG: 2
SecondChildTAG: Very correct MarceHH. Had read other references for the box plot topic. Then, looking back to the questions, I laughed at myself. Geez, first graders can nail that one. Ahahaha
SecondChildUserIdTAG: 1300259
SecondChildUserNameTAG: princejune86
SecondChildCreateTimeTAG: 2013-02-27T12:21:59Z
SecondChildVoteTAG: 0
SecondChildTAG: It makes sense to only allow one submission when the answer is between two answers, or if there is no calculation required.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T12:33:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, people, you may be right. But remember that there are some of us that have never seen this before, so we're gonna need a little time and may be insecure about the answer that we chose. I would appreciate more tries on topics we haven't studied in the lessons prior
SecondChildUserIdTAG: 1018933
SecondChildUserNameTAG: IsisN
SecondChildCreateTimeTAG: 2013-02-27T21:05:32Z
SecondChildVoteTAG: 0
FirstChildTAG: they dont give 2 submissions to questions of type where you choose from a pool of options. in such a case your chance of getting the right answers without understanding the questions gets high
FirstChildUserIdTAG: 1028247
FirstChildUserNameTAG: thekid
FirstChildCreateTimeTAG: 2013-02-27T12:06:03Z
FirstChildVoteTAG: 2
SecondChildTAG: Good point!
SecondChildUserIdTAG: 144162
SecondChildUserNameTAG: Rena2012
SecondChildCreateTimeTAG: 2013-02-27T12:20:28Z
SecondChildVoteTAG: 0
IndexTAG: 2197
TitleTAG: How do we withdraw from the course?
Hi, I'm behind ith the exercises & my maths isn't good enough to catch up quickly? What to we have to do to pull out?
UserIdTAG: 1234670
UserNameTAG: WendyENagel
CreateTimeTAG: 2013-02-27T09:57:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: I think you should not quit but pace yourself at leisure to enjoy the course.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T10:14:26Z
FirstChildVoteTAG: 3
FirstChildTAG: On your dashboard (click your name on the right upper corner of any page) where all your courses are listed you can find an "Unregister" link.
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-02-27T10:23:18Z
FirstChildVoteTAG: 0
FirstChildTAG: **@WendyENagel** - Do not be so worried. Its Ok if you are a little behind. Deadline still has few hours left. Do as many questions as you can. In the worst case scenario, take the BEST GUESS while selecting option based on your understanding from the lectures.
Also, if you are worried about 'Grades', the course drops two least scores amongst all the exercise scores while calculating the FINAL GRADE. So, you have absolutely no reason to worry. Even if you score less in this exercise, you have many more to go. So, do not bother much about SCORE, just focus on learning.
*Please do share your MATH related bottlenecks. Lets see, if through this forum you can get over it!* MATH is a personal challenge for me too. I always end up taking twice/thrice the amount of time compared to an average student, but I do get it almost all the time. So please do not give up.
Sincerely hoping that you will not discontinue. Best Wishes.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T12:52:27Z
FirstChildVoteTAG: 2
FirstChildTAG: @WendyENagel don't give up so easy.
somebody wrote this before no pain no gain.
FirstChildUserIdTAG: 900267
FirstChildUserNameTAG: kamil_sielicki
FirstChildCreateTimeTAG: 2013-02-27T13:20:51Z
FirstChildVoteTAG: 0
IndexTAG: 2198
TitleTAG: What GMT time will be posted the new lectures?
Local Time = GMT 0:00 (Standard Time)
Wednesday, 27 February
9:51:53 a.m
(GMT + 0:00)
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-27T09:52:03Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2199
TitleTAG: practice exercises
hello everyone
I have done the practice exercises but they are not reflecting in my progress. would someone kindly advise me on what to do. thanks in advance
UserIdTAG: 1266279
UserNameTAG: Nyabonyi
CreateTimeTAG: 2013-02-27T09:46:44Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: They are just for practicing, so no scores on those exercises and thus no progress shown on your progress page.
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-02-27T09:50:50Z
FirstChildVoteTAG: 0
FirstChildTAG: As senta mentioned - the scores from the practice test are not part of the progress in the bar graph, but if you scroll towards the bottom of the same page, you would be a summary of the entire module - lectures, practice test and the exercises. Hope this helps
FirstChildUserIdTAG: 998199
FirstChildUserNameTAG: kolyn
FirstChildCreateTimeTAG: 2013-02-27T09:56:49Z
FirstChildVoteTAG: 0
IndexTAG: 2200
TitleTAG: Should i check of final check my answers
When i "check" my answer system tells me weather my answer is right or wrong. Do i need to "final check" it or is "check" sufficient. Can i also change my answer after i check & before i "final check" my answers.
UserIdTAG: 1127915
UserNameTAG: HelloFriend
CreateTimeTAG: 2013-02-27T09:44:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: One check is enough. If it is wrong, you can change your answer and use the final check. Otherwise, it is enough (you can check that in progress).
Still, if you're already right, you can always check again :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-27T09:53:33Z
FirstChildVoteTAG: 0
FirstChildTAG: We are allowed one or more ATTEMPTS to submit our answers depending on the questions. The FINAL CHECK means this is YOUR LAST CHANCE at submitting the answers. No more attempts are left!!!!!
**If you get ALL correct in first ATTEMPT, YOU ARE DONE! No need to submit again.**
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T13:41:35Z
FirstChildVoteTAG: 0
IndexTAG: 2201
TitleTAG: New set of Courseware
Does anyone know at what time the new set of courseware will go online? (GMT/UTC or Berkeley time? ET)
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-27T09:36:31Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Berkeley time is not Eastern Time. East Coast US is GMT-5, West Coast (Berkeley)is GMT-8. The course is using GMT.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-02-27T12:41:52Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks for the Clarification .I think the submission time is GMT though I do not expect the course admins to upload it in the middle of the night or wee hours of the morning so I asked whether it will be uploaded at Berkeley time !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T14:20:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Will this class be offered again? I need to learn more of the math. I did not do well with this assignment at all.
FirstChildUserIdTAG: 247732
FirstChildUserNameTAG: Snazzy2
FirstChildCreateTimeTAG: 2013-02-27T16:32:57Z
FirstChildVoteTAG: 0
IndexTAG: 2202
TitleTAG: Problem 1A
Why is that not a quantitative discrete variable, and what is the right one?
UserIdTAG: 1155531
UserNameTAG: SamSchrevel
CreateTimeTAG: 2013-02-27T09:35:00Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is quantitative because you can get all values in the range (decimals). Quantitative discrete can not be all values in a range. It is often integers.
FirstChildUserIdTAG: 453550
FirstChildUserNameTAG: DebbieSmith
FirstChildCreateTimeTAG: 2013-02-27T10:52:44Z
FirstChildVoteTAG: 0
SecondChildTAG: Actually, I think it should be quantitative discrete, as you can only get values up to one penny, or cent, or paisa, or whatever. No income and no bank balance that I've ever seen has been in a fraction of a penny/cent/paisa!
SecondChildUserIdTAG: 229679
SecondChildUserNameTAG: Ahsen
SecondChildCreateTimeTAG: 2013-02-27T15:25:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Quantitative discrete is a subset of quantitative. Income can be viewed as discrete (no one is paid in multiples of pi). This is puzzling.
SecondChildUserIdTAG: 1260768
SecondChildUserNameTAG: Arjunkh
SecondChildCreateTimeTAG: 2013-02-27T16:11:44Z
SecondChildVoteTAG: 0
IndexTAG: 2203
TitleTAG: Right Answers But Wrong Grading Due to 000s Dollars Issue
The answer format is not at all clear. My answers were right for both questions - 20714.3 and 37321.4. Both in dollars and not 000s dollars. In the first question where 000s dollars is mentioned, I was graded wrong and in the second where 000s dollars is not mentioned, I was graded wrong again. This is an issue with the way the questions are framed and they are inconsistent. This needs to be rectified and the grades changed.
UserIdTAG: 1156368
UserNameTAG: Sudakshina
CreateTimeTAG: 2013-02-27T09:16:22Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: a) For the income data in Lec 2.4, find the 40th percentile in thousands of dollars.
Seems clear it is thousands of dollars. b) should follow a), therefore it is also thousands of dollars :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-27T09:51:47Z
FirstChildVoteTAG: 1
FirstChildTAG: Have they changed it since you did it? It now clearly says "Please enter only your numerical answer, and please round to one decimal place."
FirstChildUserIdTAG: 1281619
FirstChildUserNameTAG: sfc17
FirstChildCreateTimeTAG: 2013-02-27T20:48:37Z
FirstChildVoteTAG: 0
IndexTAG: 2204
TitleTAG: full score
I am very happy as I got full score for this exercise set 3
UserIdTAG: 1261388
UserNameTAG: PadmaUpp
CreateTimeTAG: 2013-02-27T09:10:04Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: ES3 was more straightforward (although the Box and Whisker Plot problem was a surprise) as compared to ES1 and ES2. Agreed.
FirstChildUserIdTAG: 413463
FirstChildUserNameTAG: Venkataramani
FirstChildCreateTimeTAG: 2013-02-27T11:29:05Z
FirstChildVoteTAG: 1
IndexTAG: 2205
TitleTAG: Question about exercise set 3, problem 2
Hello,
I would really appreciate if someone could clarify the following for me. In the problem 2 of set 3, I calculated the percentage of people who got the scores in the ranges below 50, 50-60, 60-70, and so on which comes to 3.7%, 3.7%, 14.8%, etc. given that there were total 28 people in the class. This is all based on the provided data. Therefore, for example, for the 20th percentile, I calculated the score to be 65.8 given that 7.4% of people received grades below 59 and we therefore need another 12.6% from the next range which gives us 59+(12.6%/14.8%)*(75-67). I also tried using the inclusive ranges (60+(12.6/14.8)*(70-60)). According to the answer check either of these answers is incorrect. My suspicion is that I am missing something in the definition of "scores" used in this problem.
Thank you.
UserIdTAG: 1103522
UserNameTAG: statisticsevi
CreateTimeTAG: 2013-02-27T09:08:12Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: > My suspicion is that I am missing something in the definition of "scores" used in this problem.
The lectures tell you the method to use for determining percentiles. You are not using it. Look again at the formal definition of percentiles. And the example that took all of lecture 2.5
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T09:12:04Z
FirstChildVoteTAG: 0
SecondChildTAG: @ChristineStv.
Please ignore my questions in the future. Thanks.
SecondChildUserIdTAG: 1103522
SecondChildUserNameTAG: statisticsevi
SecondChildCreateTimeTAG: 2013-02-27T18:55:54Z
SecondChildVoteTAG: 0
FirstChildTAG: Did you read the mechanics from Lec 2.5 "Applying the definition"?
1. put the list in increasing order: already done for you
2. identify the place that is p% of the bottom of the list
3. if that's a place on the list, take the number in that place; if not, take the next one up
It's just the same with stem and leaf plots. So the answer is always a number out of the list provided, no decimals or the like. Hope that helps?
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-02-27T09:13:22Z
FirstChildVoteTAG: 1
FirstChildTAG: Yes, don't put decimals, I assumed the numbers where marks over 10 so I put like 6.5 instead 65, for instance, I almost went crazy because I couldn't understand why it said it was wrong!
FirstChildUserIdTAG: 1313846
FirstChildUserNameTAG: efreixas
FirstChildCreateTimeTAG: 2013-02-27T11:12:26Z
FirstChildVoteTAG: 0
FirstChildTAG: **@statisticsevi:**
1. The stem/leaf evaluates to 48, 59, 66,63,63,63,67 .....etc.
2. As you rightly said there are 28 items in the list and the list is already sorted.
3. Next calculate, 20% of 28 items is how much.
4. Whatever value you get in point 3 above, check if that's a place on the list (count number of places from the left end of the list).
5. If yes, take the number in that place; if not, take the next one up
For e.g. if you get the value say 3. 3rd place from left end (48, 59, **66**,63,63,63,67) which is **66** here. So your answer would be 66.
However, if you get the value say **3.4** (More than 3 but less than 4), we do not have any place called **3.4**! We have 1,2,3,4,5...etc. So, take the value which is immediately after place 3, which is **63**.(48, 59, 66,**63**, ) So the answer would be **63** (this is just an example, not the actual answer)
Hope this helps.
FirstChildUserIdTAG: 300213
FirstChildUserNameTAG: Artimehta
FirstChildCreateTimeTAG: 2013-02-27T14:01:54Z
FirstChildVoteTAG: 1
SecondChildTAG: Dear Artimehta,
Thank you so much for the detailed explanation! I "over thought" the problem but thanks to you I get it know. I really appreciate this.
Best regards.
SecondChildUserIdTAG: 1103522
SecondChildUserNameTAG: statisticsevi
SecondChildCreateTimeTAG: 2013-02-27T18:39:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Welcome!
SecondChildUserIdTAG: 300213
SecondChildUserNameTAG: Artimehta
SecondChildCreateTimeTAG: 2013-02-27T19:19:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you.. We were making it much too hard.
SecondChildUserIdTAG: 1110758
SecondChildUserNameTAG: jcu
SecondChildCreateTimeTAG: 2013-02-27T21:16:42Z
SecondChildVoteTAG: 0
FirstChildTAG: @senta and @efreixas
Thank you for your answers! It is great to have team support!
FirstChildUserIdTAG: 1103522
FirstChildUserNameTAG: statisticsevi
FirstChildCreateTimeTAG: 2013-02-27T18:43:14Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi.
As I understood You, You are calculating percentiles by finding percents. However, this is not the way it works. You have to divide each number (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, .. 28) by 28 and which one gives you exactly or approximately 20%(0.2 something), You take the number at that count. for example, if 1/28 will be 3.5%, 2/28 will be 7.1%... the answer to that question will be 6th number, that is 67, because 5th number has less than 20s percentile and 7th got higher.
FirstChildUserIdTAG: 386497
FirstChildUserNameTAG: khsiddiq
FirstChildCreateTimeTAG: 2013-02-28T11:06:13Z
FirstChildVoteTAG: 0
IndexTAG: 2206
TitleTAG: Assignments
Please help me get the assignments. I cannot access them.
richellmsoma@yahoo.co.uk
UserIdTAG: 415613
UserNameTAG: richellmsoma
CreateTimeTAG: 2013-02-27T08:54:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They are on the Courseware page,indicated by the blue alarm clock icon. If you can't submit your answers you might need to change browsers. Chrome or Firefox.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T09:03:03Z
FirstChildVoteTAG: 0
IndexTAG: 2207
TitleTAG: oh, crap! damn decimal point...
I properly calculated the answer for question 5, then messed up the answer because I used the decimal calculation instead of the percentage!
banging head on keyboard...
UserIdTAG: 459910
UserNameTAG: AlanJayWeiner
CreateTimeTAG: 2013-02-27T08:24:47Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2208
TitleTAG: ERROR in practice for exercise set 2
In practice for exercise set 2 question (a) of Lectures 2.2 and 2.3 has wrong answer. In the explanation it is given that interval between -10 to 20 is of 10, whereas it should be 30. So the correct answer would be 14/30 and not 14/10.
UserIdTAG: 1127915
UserNameTAG: HelloFriend
CreateTimeTAG: 2013-02-27T08:00:30Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 5
FirstChildTAG: I agree with you.
FirstChildUserIdTAG: 844176
FirstChildUserNameTAG: MDJOBO
FirstChildCreateTimeTAG: 2013-02-27T08:05:28Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, you are right. 14/30= 0.466%. It is taking 10 as the width when it's actually 30
SecondChildUserIdTAG: 1078871
SecondChildUserNameTAG: CarlosMartin2013
SecondChildCreateTimeTAG: 2013-02-27T08:15:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Just cracking the 2nd gin bottle.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T08:23:53Z
FirstChildVoteTAG: 6
SecondChildTAG: But I don't drink and also in between 2 cardiac surgeries :)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T09:22:35Z
SecondChildVoteTAG: 0
SecondChildTAG: answer should be 0.47.
SecondChildUserIdTAG: 705463
SecondChildUserNameTAG: Eros
SecondChildCreateTimeTAG: 2013-02-27T09:55:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree
SecondChildUserIdTAG: 899410
SecondChildUserNameTAG: JodyS
SecondChildCreateTimeTAG: 2013-02-27T11:01:56Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree
FirstChildUserIdTAG: 106654
FirstChildUserNameTAG: rajuchellappa
FirstChildCreateTimeTAG: 2013-02-27T08:40:03Z
FirstChildVoteTAG: 0
SecondChildTAG: ya....i too agree
SecondChildUserIdTAG: 835165
SecondChildUserNameTAG: DrSmita
SecondChildCreateTimeTAG: 2013-02-27T16:48:03Z
SecondChildVoteTAG: 0
FirstChildTAG: ha had the same issue.
FirstChildUserIdTAG: 754963
FirstChildUserNameTAG: infaribued
FirstChildCreateTimeTAG: 2013-02-27T09:34:48Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree
FirstChildUserIdTAG: 899410
FirstChildUserNameTAG: JodyS
FirstChildCreateTimeTAG: 2013-02-27T11:02:17Z
FirstChildVoteTAG: 0
IndexTAG: 2209
TitleTAG: where can I find the Student Id? How can I do my assignments?
when I fill out this form to do the assignments,I don't know what is my Student ID,or where can I find it?How can I do my assignments? Thanks for your help!
UserIdTAG: 1032859
UserNameTAG: ymeixia
CreateTimeTAG: 2013-02-27T07:46:56Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You do not need an id. The assignments are on the **Courseware page** - marked with a blue alarm clock. They have *nothing to do with the online text*.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T07:53:08Z
FirstChildVoteTAG: 0
IndexTAG: 2210
TitleTAG: please give us solutions after submission of homework
it will help us study more thoroughly.
UserIdTAG: 1027696
UserNameTAG: bhamgm
CreateTimeTAG: 2013-02-27T07:43:25Z
VoteTAG: 10
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Yes, and as it tells you in the course info documents, the answers are released the day after the due date.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T07:53:46Z
FirstChildVoteTAG: 1
SecondChildTAG: Where do the answers are released. I also want a description of the answers.
SecondChildUserIdTAG: 1119819
SecondChildUserNameTAG: Hamraz
SecondChildCreateTimeTAG: 2013-02-27T09:21:08Z
SecondChildVoteTAG: 0
IndexTAG: 2211
TitleTAG: How do you make your Subtitles?
Just wondering what you use to create your subtitles. They look automated. Do you use 3Play Media?
UserIdTAG: 1080056
UserNameTAG: alexd457
CreateTimeTAG: 2013-02-27T07:21:56Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2212
TitleTAG: I know the right answer...
I was annoyed that 'a' had the wrong answer, and giving it the correct answer meant that my progress showed that problem as a failure.
So I gave it the wrong answer that it wanted, just to show my correct progress... :)
UserIdTAG: 459910
UserNameTAG: AlanJayWeiner
CreateTimeTAG: 2013-02-27T07:20:26Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: We all did this ;) i think :p
FirstChildUserIdTAG: 1274977
FirstChildUserNameTAG: RichardBekhazi
FirstChildCreateTimeTAG: 2013-02-27T11:36:16Z
FirstChildVoteTAG: 0
IndexTAG: 2213
TitleTAG: About the score of exercise and schedule of its submission date
I don’t understand it says no score after; I scored 8 out of 10. Is there any way of tour calculation or because of I didn’t submitted it before the end hour and date? Please make flexible your rule by adding little time and one day, because I have many activities which are make me busy to submit on time. At least one day is enough to me. Thank you for your cooperation in advance.
UserIdTAG: 802865
UserNameTAG: Habteyes
CreateTimeTAG: 2013-02-27T07:18:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: > or because of I didn’t submitted it before the end hour and date
If you submit late, then of course you would get 0. But have they closed yet? Refresh your page.
> Please make flexible your rule by adding little time and one day, because I have many activities which are make me busy to submit on time.
Then you need to budget your time. If you have too many activities, then maybe you need to drop one or two and concentrate on this course. We are all busy people.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T07:57:46Z
FirstChildVoteTAG: 0
FirstChildTAG: Don't forget to SAVE after you have checked your answers.
FirstChildUserIdTAG: 1247915
FirstChildUserNameTAG: Iliri2013
FirstChildCreateTimeTAG: 2013-02-27T11:00:52Z
FirstChildVoteTAG: 0
IndexTAG: 2214
TitleTAG: relative frequency in the class interval
Hello everyone!
I understand that there's a Courseware errata, but cannot get where "14" number comes from in a) exercise and "5" in b).
Could you kindly explain me that please.
Thank you.
UserIdTAG: 750933
UserNameTAG: Aselina
CreateTimeTAG: 2013-02-27T07:06:22Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Check the discussions; the answer in the exercise is incorrect. The width of the bin is 30; not 10. That makes the calculation: 14 / 30 = .4666
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-02-27T07:16:21Z
FirstChildVoteTAG: 0
SecondChildTAG: AlanJayWeiner, thnak you for the answer, but my question was actually about the meaning of "14" when we divide it by 30, where does it come from?
SecondChildUserIdTAG: 750933
SecondChildUserNameTAG: Aselina
SecondChildCreateTimeTAG: 2013-02-27T07:38:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Hellow everyone,
I have done exercise set 2 and some of the questions below which I have scored wrong. Can anyone assist providing explanations to the questions and why get it wrong?
About what percent of the people were in their thirties? Round your answer to one decimal place.
13.8
unanswered
b) A common (though not universal) definition of "senior citizen" is "person over the age of 65". About what percent of the population were senior citizens? Round your answer to one decimal place.
a) In the United States, high school diplomas are awarded after 12 years of schooling. Which interval contains the adults who had completed 12 years of school and did not proceed with higher education?
0-9 9-12 12-13 13-16 16-17 17+
b) Bachelor’s degrees are awarded to those who successfully complete four years of education at a college or university after high school. Which interval contains the adults who completed 16 years of schooling and did not proceed with further education?
0-9 9-12 12-13 13-16 16-17 17+
SecondChildUserIdTAG: 972972
SecondChildUserNameTAG: 0123
SecondChildCreateTimeTAG: 2013-02-27T07:48:30Z
SecondChildVoteTAG: 0
IndexTAG: 2215
TitleTAG: time of submission
which time to follow for submission of homework?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-27T07:00:13Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: GMT
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-27T09:08:36Z
FirstChildVoteTAG: 0
IndexTAG: 2216
TitleTAG: ES Average calculation?
In the progress section, does anyone know how is the "ES Average" calculated?
UserIdTAG: 998199
UserNameTAG: kolyn
CreateTimeTAG: 2013-02-27T06:53:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Well, this is a statistics course. So let's look at the numbers. 3 bars, with a total of 100% each if you got them all correct. 10 bars for assessment (+ 2 spare as lowest two are not counted).
ES Average = 30%, if you got 100% for all 3 bars. So this must mean each of the 10 bars is worth 10% for the ES average.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T07:06:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks, Christine.. the graph makes sense now!! :D
SecondChildUserIdTAG: 998199
SecondChildUserNameTAG: kolyn
SecondChildCreateTimeTAG: 2013-02-27T09:58:24Z
SecondChildVoteTAG: 0
IndexTAG: 2217
TitleTAG: what are the differences between quantitative discrete and quantitative?
and what are the differences between categorial and qualitative ordinal?
UserIdTAG: 1027696
UserNameTAG: bhamgm
CreateTimeTAG: 2013-02-27T06:33:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Qualitative ordinal is when qualitative variables are ranked (High, medium, low) etc etc
Categorial - there is no ranking or preferences.
FirstChildUserIdTAG: 998199
FirstChildUserNameTAG: kolyn
FirstChildCreateTimeTAG: 2013-02-27T06:51:46Z
FirstChildVoteTAG: 2
SecondChildTAG: I gave an example using beauty and millihelens. If tour search the forum you may get it
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T09:19:14Z
SecondChildVoteTAG: 0
SecondChildTAG: must take a look at it.. if i can find it among the mountain of comments..
SecondChildUserIdTAG: 998199
SecondChildUserNameTAG: kolyn
SecondChildCreateTimeTAG: 2013-02-27T09:50:15Z
SecondChildVoteTAG: 0
IndexTAG: 2218
TitleTAG: Problem 3 (b)
why not experiment 5?
what is the answer of that question then?
UserIdTAG: 1312359
UserNameTAG: sewak
CreateTimeTAG: 2013-02-27T06:29:07Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: The distance from 800 (Q1) to 840 (Q2 or Median) is equals to 840 (Q2 or Median) to 880 (Q3). That is 40-40. It is not justified in any of the experiment other than Experiment 2. :-)
FirstChildUserIdTAG: 1298494
FirstChildUserNameTAG: NarenderSingh
FirstChildCreateTimeTAG: 2013-02-27T07:17:26Z
FirstChildVoteTAG: 0
SecondChildTAG: I hate this:( I accidentally hit the wrong choice, it should be experiment 4, if the way I think isn't mistaken here is the logic-> the area in exp 4 is bigger than that of 5,if it's going to be drawn in histogram we need to find it's height,since the width of both are the same-drawn in the same scale- it means the height of exp 4 will be Higher than that of 5->Height= area:width
SecondChildUserIdTAG: 1274748
SecondChildUserNameTAG: kusumawati
SecondChildCreateTimeTAG: 2013-02-27T09:11:07Z
SecondChildVoteTAG: 0
SecondChildTAG: > here is the logic-
Box plots - upper line of box is 75% (Q3), bottom line is 25% (Q1), middle line is 50% (median Q2). So which box has the lowest median.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T09:17:37Z
SecondChildVoteTAG: 0
SecondChildTAG: I am confused now..what is the answer to 3(b)????
SecondChildUserIdTAG: 1286076
SecondChildUserNameTAG: riyarahiman
SecondChildCreateTimeTAG: 2013-02-27T12:27:39Z
SecondChildVoteTAG: 0
SecondChildTAG: look at the box plot carefully
SecondChildUserIdTAG: 157588
SecondChildUserNameTAG: Chopra
SecondChildCreateTimeTAG: 2013-02-27T16:24:46Z
SecondChildVoteTAG: 0
SecondChildTAG: for 3(b) answer is experiment 2. Use experiment 1 Q1(850) closer to 840 which median given. The median for experiment 5 is way lower than Q1 for experiment 1. Also if you look at experiment 5 Q1 and Q2 are closer to each other they cannot be 800 and 840 with such a smaller distance between them
SecondChildUserIdTAG: 600088
SecondChildUserNameTAG: tungadex
SecondChildCreateTimeTAG: 2013-02-27T19:38:06Z
SecondChildVoteTAG: 0
FirstChildTAG: http://www.conkerstatistics.co.uk/iase/papers/IASE2011PaperPoster6Lemetal.pdf
FirstChildUserIdTAG: 177112
FirstChildUserNameTAG: manikghosh
FirstChildCreateTimeTAG: 2013-02-27T09:44:43Z
FirstChildVoteTAG: 1
IndexTAG: 2219
TitleTAG: rounding?
I gave 11.11% the percentage of freshmen and it took it as wrong answer saying that the correct one is 11.1%. shouldn't it be the same? Should we consider that for the tests so not to get a WRONG ANSWER? Thanks
UserIdTAG: 1078871
UserNameTAG: CarlosMartin2013
CreateTimeTAG: 2013-02-27T06:28:28Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I had the same problem and totally agree. I would really appreciate if there was some hint as to how we shall round our results.
FirstChildUserIdTAG: 1206659
FirstChildUserNameTAG: MaximilianSchildt
FirstChildCreateTimeTAG: 2013-02-27T08:47:12Z
FirstChildVoteTAG: 0
IndexTAG: 2220
TitleTAG: Set 1, Problem 3b
I don´t think the anwer which was evaluated as correct in the 3b problem of Set 1 is right.
Am I missing something?
I noticed why there are not **two** right answers, but still don´t think I am wrong.
I have recalculated it three times...
UserIdTAG: 764275
UserNameTAG: PeterVe
CreateTimeTAG: 2013-02-27T06:20:06Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: It is correct.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T06:22:32Z
FirstChildVoteTAG: 0
SecondChildTAG: Strange. I got the righ answer, but in my browser, a tick sign appeared next to a wrong answer and yet, the evaluation calculated my aanwer as correct. weird.
anyway...never mind
SecondChildUserIdTAG: 764275
SecondChildUserNameTAG: PeterVe
SecondChildCreateTimeTAG: 2013-02-27T06:25:18Z
SecondChildVoteTAG: 0
FirstChildTAG: PeterVe, you are correct. The answer sheet shows the first bar graph to be the correct choice, but it cannot be correct because the magenta/green plants alone account for more than half of the plants. The first bar graph shows the proportion of green plants and those that have no green, to be equal. Clearly, that is not correct. The correct choice is the last bar graph, representing 380 green, and 120 no-green.
FirstChildUserIdTAG: 6594
FirstChildUserNameTAG: Honu
FirstChildCreateTimeTAG: 2013-02-27T08:59:46Z
FirstChildVoteTAG: 0
FirstChildTAG: The tick appears at the top of the question, but it is not saying the first choice is correct. It is saying the graph you *chose* is correct. Confusing, but correct.
If you look at all the other ticks, they appear at the top of a question. So for the mcq questions the tick is always alongside the first choice.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T09:05:45Z
FirstChildVoteTAG: 0
FirstChildTAG: Check the axis label as well.
FirstChildUserIdTAG: 936512
FirstChildUserNameTAG: Roqib
FirstChildCreateTimeTAG: 2013-02-27T09:28:38Z
FirstChildVoteTAG: 0
IndexTAG: 2221
TitleTAG: Off to a bad start
Ok- I'm discouraged already. I'm off to an awful start, just 8 out of 20 points. I guess it's true, you really can't teach an old dog new tricks. I am just too old to learn.
UserIdTAG: 868031
UserNameTAG: CaliforniaViv
CreateTimeTAG: 2013-02-27T06:18:49Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 5
FirstChildTAG: do not give up so easy CaliforniaViv, I am sure that in the end you will make just fine
FirstChildUserIdTAG: 900267
FirstChildUserNameTAG: kamil_sielicki
FirstChildCreateTimeTAG: 2013-02-27T06:26:05Z
FirstChildVoteTAG: 2
SecondChildTAG: I agree - from one old dog to another...
SecondChildUserIdTAG: 459910
SecondChildUserNameTAG: AlanJayWeiner
SecondChildCreateTimeTAG: 2013-02-27T08:10:48Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, I got just about everything wrong. I'm not remotely encouraged.
SecondChildUserIdTAG: 1175679
SecondChildUserNameTAG: mkemp2010
SecondChildCreateTimeTAG: 2013-02-27T17:23:02Z
SecondChildVoteTAG: 0
FirstChildTAG: You should definitely not be giving up. It takes a while to get used the way of thinking, that's all. I suggest using the forum; there's a lot of help out there, and I put in my 2 cents from time to time as you can see.
Incidentally, from a purely practical perspective, you're on track to get your Certificate of Completion. I made the passing grade 35% for several reasons, one of them being that it takes people a while to get started.
Hang in there,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-27T08:39:10Z
FirstChildVoteTAG: 1
SecondChildTAG: That's wonderful encouragement. I would add that there is no risk in continuing. If you don't succeed this five week period, you will still have learned part of the material and will be more prepared the next time you try a statistics class. There are only positive outcomes from trying!
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T12:48:57Z
SecondChildVoteTAG: 0
FirstChildTAG: I think that you should continue and learn for yourself using the course and enjoy the course. I am indeed getting a fresh outlook and challenging many presumptions that I had and I am also not exactly "young " so hang in there.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T09:15:28Z
FirstChildVoteTAG: 0
SecondChildTAG: And my Mom in her 70's started blogging around the age of 70 and she has blogs on sewing and tailoring which is actively followed by many around the world.She teaches people how to sew clothes etc etc.She did not have great computer knowledge prior to that.Her latest acquisition is a tablet and she mastered Android pretty quickly.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T15:57:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Californiaviv that's not true (You can't teach old dog new tricks). My mother's just like you, when she asked me to teach her something at first it was really really hard to the point that i want to give up, but with perseverance and hard work I'm sure you'll be fine.
FirstChildUserIdTAG: 892025
FirstChildUserNameTAG: gerickABM
FirstChildCreateTimeTAG: 2013-02-27T12:19:13Z
FirstChildVoteTAG: 0
FirstChildTAG: 8 out of 20, is not a bad start. I know you are going to gradually improve from this point onwards. All the best
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-02-27T15:16:09Z
FirstChildVoteTAG: 0
IndexTAG: 2222
TitleTAG: Incorrect evaluation of answers
I agree that the number of decimal places and the rounding of answers should have been mentioned or stated as part of the question. Also agree that it was rather a lengthy session that involved multiple issues
1. too much scrolling for the data grid
2. more data examples should have been used while calculating area of the bin, for example
3. the last histogram never refreshed to show -160 as the lower range. Felt like the page was faulty but i din't dare to refresh as I could not figure how to save the 98% work already done.
Hope the above is taken care of in the following sessions. Thx Sushma
UserIdTAG: 1001534
UserNameTAG: SushmaAk
CreateTimeTAG: 2013-02-27T06:00:50Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Can the data set be given in ms excel format and put on the site for us to download and use during practice and exercise. I am having problems accessing the data sets because it was banned from my empolyer website. If this can be in excel would be great for use all to download and use
FirstChildUserIdTAG: 972972
FirstChildUserNameTAG: 0123
FirstChildCreateTimeTAG: 2013-02-27T08:02:08Z
FirstChildVoteTAG: 0
IndexTAG: 2223
TitleTAG: Having Problems Signing In To Do Ex 2 and 3
I am having problems signing in to do my exercises Exercise 2 and 3, any help please
Thanks
UserIdTAG: 417448
UserNameTAG: Oldzigi
CreateTimeTAG: 2013-02-27T05:52:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: If you are posting, then you are logged in. If you can't do the exercises then it is probably a browser issue. Try Chrome or Firefox - whichever one you aren't currently using.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T05:58:23Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks ChristeneStv, it was a browser problem, shifted from firefox to chrome and it is working.
Thanks
FirstChildUserIdTAG: 417448
FirstChildUserNameTAG: Oldzigi
FirstChildCreateTimeTAG: 2013-02-27T06:03:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Good. It's very strange. Some are okay with Chrome, some are not. Same with Firefox.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T06:05:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I found it working on both Firefox and chrome. I think you need to have the latest versions. The one thing that really gave me problems is the Sticgui textbook. The histogram slider :s super sensitive when we drag and even micro movements on clicking the mouse changes the position which can be painful for some problems!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T09:11:40Z
SecondChildVoteTAG: 0
IndexTAG: 2224
TitleTAG: calculating height without relative frequency
I don't know how to get height if I have interval only and not having the frequency
UserIdTAG: 640369
UserNameTAG: mwana77
CreateTimeTAG: 2013-02-27T05:46:16Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 1
FirstChildTAG: The interval will only define the width. Check the formula: Height = % / Width.
FirstChildUserIdTAG: 52707
FirstChildUserNameTAG: oONIo
FirstChildCreateTimeTAG: 2013-02-27T07:43:53Z
FirstChildVoteTAG: 0
IndexTAG: 2225
TitleTAG: Sound
I dont have any sound, neither videos. Please help me.
UserIdTAG: 938565
UserNameTAG: Suany
CreateTimeTAG: 2013-02-27T05:45:14Z
VoteTAG: 0
CoursewareTAG: Section 1: Introduction / Lec 1.3. Bar graphs: describing categorical data
NumberOfReplyTAG: 1
FirstChildTAG: Maybe try opening it in youtube instead. (click lower right corner of video)
FirstChildUserIdTAG: 1031066
FirstChildUserNameTAG: sarahbergquist
FirstChildCreateTimeTAG: 2013-02-27T05:51:51Z
FirstChildVoteTAG: 0
IndexTAG: 2226
TitleTAG: Problem 1 Exercise set 3
Can we get the answers to these problems after the due date?
What is the lower percentile for problem 1 of Ex. set 3? I tried it twice and I'm sure I used the formula right, because it worked for the other two cases.
UserIdTAG: 1213517
UserNameTAG: CarolinaOcampo
CreateTimeTAG: 2013-02-27T05:44:09Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I also tried this two times but caught answer wrong.
FirstChildUserIdTAG: 972972
FirstChildUserNameTAG: 0123
FirstChildCreateTimeTAG: 2013-02-27T07:59:52Z
FirstChildVoteTAG: 1
SecondChildTAG: lower quartile is 18.6
SecondChildUserIdTAG: 1053569
SecondChildUserNameTAG: nicola2003
SecondChildCreateTimeTAG: 2013-02-27T11:50:24Z
SecondChildVoteTAG: 0
SecondChildTAG: How did you get this? Will you mind sharing the process you used? Thanks...
SecondChildUserIdTAG: 982787
SecondChildUserNameTAG: annettedonnelly
SecondChildCreateTimeTAG: 2013-02-27T16:53:45Z
SecondChildVoteTAG: 0
SecondChildTAG: the lower percentile is 18.6
u will need 5.1 to reach the 25%
to calculate it 15+(5.1/7.1*5)= 18.59
SecondChildUserIdTAG: 625229
SecondChildUserNameTAG: alshaimaahmed
SecondChildCreateTimeTAG: 2013-02-27T19:07:19Z
SecondChildVoteTAG: 0
SecondChildTAG: I also got this wrong, although I used similar calculations. I thought to get to the 25th percentile age, you would assume Age range 0-15 (actually years 0-14, since right endpoint isn't included) was 19.9%, and therefore you would need 5.1% additional. Taking the next age range 15-20 that comprised 7.1% and because they are evenly distributed: 7.1%/5 = 1.42% per year. So in order to reach at least 5.1% you would need at least 3.59 additional years (5.1%/1.42%=3.59). Counting 15 yrs old as 1 year, 16 as 2 years, 17 as 3 additional years, I thought the answer would be 17.59 years old, or 17.6 (not 18.6). Why is it 18.6? Can you please tell me where is my logic flawed??? Thanks.
SecondChildUserIdTAG: 1091958
SecondChildUserNameTAG: DEnoch
SecondChildCreateTimeTAG: 2013-02-27T20:20:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here. I got the answers as 17.59, 35.97 and 54.33. Even I added the fractional part to 14 because the problem clearly states that the left endpoint is to be considered.
SecondChildUserIdTAG: 1099022
SecondChildUserNameTAG: EktaaR
SecondChildCreateTimeTAG: 2013-02-27T20:37:03Z
SecondChildVoteTAG: 0
FirstChildTAG: ...the instructions keep talking about: Intervals include the left endpoint but not the right; when really, what's being considered as the correct answer keeps including the right.
FirstChildUserIdTAG: 7286
FirstChildUserNameTAG: ptfrizz
FirstChildCreateTimeTAG: 2013-02-27T14:19:13Z
FirstChildVoteTAG: 2
SecondChildTAG: Agree. The solution includes the right endpoint when the instructions clearly state that it is not part of the range.
SecondChildUserIdTAG: 105209
SecondChildUserNameTAG: bridavis
SecondChildCreateTimeTAG: 2013-03-01T02:36:34Z
SecondChildVoteTAG: 0
IndexTAG: 2227
TitleTAG: How to calculate the relative frequency for Exercise 3-6 in textbook?
The examples given in the table shows the relative frequencies for class intervals -160 to -110 and -110 to -90 are 9% and 10% respectively. This made me assume that the right answer for the class interval -90 to -70 is 14%(14 out of a 100). However the answer is expected in the range 0.1287 to 0.1313. How do I arrive at this answer?
UserIdTAG: 181676
UserNameTAG: dark_horse
CreateTimeTAG: 2013-02-27T05:43:18Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The online text had 13 varibles listed in the interval.
FirstChildUserIdTAG: 1289698
FirstChildUserNameTAG: smpauline
FirstChildCreateTimeTAG: 2013-02-27T06:04:19Z
FirstChildVoteTAG: 0
SecondChildTAG: You are right, I had miscounted. However, there are two areas which need to be clearer..1. The percentages are listed in the solved examples, not decimal numbers. 2. The values are discrete so there is no question of a range. The answer should be 0.13 or 13%. Hope this is rectified. The implications are not so severe since this is a practice exercise, however.
SecondChildUserIdTAG: 181676
SecondChildUserNameTAG: dark_horse
SecondChildCreateTimeTAG: 2013-02-27T06:59:15Z
SecondChildVoteTAG: 0
IndexTAG: 2228
TitleTAG: Appeal to Prof.A
Thanks for all inputs.
A request: Please check the settings for the quizzes. An example is of answers being marked incorrect because % is added at the end of the answer. What is being tested here?
I teach. I use several LMSs. A simple solution is to convert all questions to Multiple Choice type rather than have students type in the answer. With the latter, the settings can be difficult to get. The problems arising from incorrect settings or wrongly understood settings can be easy to fix in small classes but get really amplified in a MOOC.
Hope this is useful.
UserIdTAG: 1139936
UserNameTAG: SundarV
CreateTimeTAG: 2013-02-27T05:06:12Z
VoteTAG: 7
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Truly, this has been addressed and is being remedied.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T05:26:24Z
FirstChildVoteTAG: 0
SecondChildTAG: I think a simple solution will be, to provide an example for the format expected in each of the questions:)
SecondChildUserIdTAG: 1617
SecondChildUserNameTAG: sid3930
SecondChildCreateTimeTAG: 2013-02-27T05:51:39Z
SecondChildVoteTAG: 0
IndexTAG: 2229
TitleTAG: Exercise Due Dates
What if I missed the due date to submit my exercise, which would affect my final pass of this course? Thank you for the respones.
UserIdTAG: 209887
UserNameTAG: Guoming
CreateTimeTAG: 2013-02-27T04:25:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: If you miss a due date then you score 0 for that assessment item.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T04:27:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Oh...no...I miss 3 exercise at a time. Does it means that I won't pass this course even if I finish the rest coming up exercises?
SecondChildUserIdTAG: 209887
SecondChildUserNameTAG: Guoming
SecondChildCreateTimeTAG: 2013-02-27T05:33:54Z
SecondChildVoteTAG: 0
SecondChildTAG: You need to read the Course Info documents.The grading scheme is detailed there.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T05:39:32Z
SecondChildVoteTAG: 0
SecondChildTAG: I see, thank you anyway.
SecondChildUserIdTAG: 209887
SecondChildUserNameTAG: Guoming
SecondChildCreateTimeTAG: 2013-02-27T05:51:44Z
SecondChildVoteTAG: 0
FirstChildTAG: What time on Wednesdays are the questions due? I mean to say are they due before midnight (11:59pm in whatever time zone the student is in) or is there a set time? Thank you.
FirstChildUserIdTAG: 978307
FirstChildUserNameTAG: MathNewbie
FirstChildCreateTimeTAG: 2013-02-27T04:47:12Z
FirstChildVoteTAG: 0
SecondChildTAG: There are Course Information documents where all this is explained.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T05:26:51Z
SecondChildVoteTAG: 0
IndexTAG: 2230
TitleTAG: Exercise 1 set 3
Hello
Please I need a an additional explication in order to resolve this exercise.
Thanks
UserIdTAG: 1158693
UserNameTAG: dabad
CreateTimeTAG: 2013-02-27T04:16:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Which part specifically?
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T04:36:33Z
FirstChildVoteTAG: 0
IndexTAG: 2231
TitleTAG: Practice Problems a) and b) under Lectures 2.2 and 2.3
Am totally confused now; What is the number of units between -10 and 20? Please help!
UserIdTAG: 1258683
UserNameTAG: Tshuxx
CreateTimeTAG: 2013-02-27T04:00:28Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 6
FirstChildTAG: actually same here.
I expected it to be 3. But weirdly enough it takes it as 1.
In the discussion below, more people seem to have the same query
FirstChildUserIdTAG: 1133726
FirstChildUserNameTAG: Anand1871
FirstChildCreateTimeTAG: 2013-02-27T04:15:01Z
FirstChildVoteTAG: 0
SecondChildTAG: I guessed it'd be 30, and the counts in that range would be 82, I was getting 2.73 as the height of the bar, I got the second one right, I'm confused about the first one too
SecondChildUserIdTAG: 930781
SecondChildUserNameTAG: victorgarciagallegos
SecondChildCreateTimeTAG: 2013-02-27T04:44:46Z
SecondChildVoteTAG: 0
FirstChildTAG: I'm going to shoot myself in the head. This has got to stop.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T04:15:27Z
FirstChildVoteTAG: 1
SecondChildTAG: Join the queue.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T04:22:50Z
SecondChildVoteTAG: 0
SecondChildTAG: We should start a drinking game. Whenever anyone posts the same question about this same exercise, we drink a shot.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-27T04:34:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Then we can measure what percentage of students went to the ER with alcohol poisoning!
SecondChildUserIdTAG: 941597
SecondChildUserNameTAG: NSandar
SecondChildCreateTimeTAG: 2013-02-27T05:03:43Z
SecondChildVoteTAG: 0
FirstChildTAG:
This question has been posted and answered several times.
See below in the course errata
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 682727
FirstChildUserNameTAG: CediCed
FirstChildCreateTimeTAG: 2013-02-27T04:16:09Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you.
SecondChildUserIdTAG: 1055515
SecondChildUserNameTAG: Eracles
SecondChildCreateTimeTAG: 2013-02-27T05:11:55Z
SecondChildVoteTAG: 0
FirstChildTAG: > Am totally confused now; What is the number of units between -10 and 20? Please help!
You need to help yourself! There are forums. Read them!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T04:23:34Z
FirstChildVoteTAG: 1
FirstChildTAG: Just remember there are 40,000+ students taking this, not everyone will catch on right away.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T04:39:11Z
FirstChildVoteTAG: 0
FirstChildTAG: You have to make table of using varible from the online text, the calculate the percetage(area), width, and height(density)for each interval of data. The heigh/density is the value you are looking for.
FirstChildUserIdTAG: 1289698
FirstChildUserNameTAG: smpauline
FirstChildCreateTimeTAG: 2013-02-27T05:14:28Z
FirstChildVoteTAG: 0
IndexTAG: 2232
TitleTAG: Were there more 5-year-olds or 15-year-olds?
Hi everyone, I don't really get the meaning of the question of the exercise set 2 problem1. Is there someone who can explain what I'm supposed to do? Just an explanation would be ok I don't want the answer :)
UserIdTAG: 1151142
UserNameTAG: Mohamed-Salmane
CreateTimeTAG: 2013-02-27T03:54:06Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's just asking you to look at the graph and answer whether there are more 5 year olds, or 15 year olds.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T04:18:04Z
FirstChildVoteTAG: 0
IndexTAG: 2233
TitleTAG: Set 3 Problem #2
The median is 80.5. The answer and method is wrong. Use any graphing calculator or wolfram and the median is 80.5 not 81.
UserIdTAG: 1167478
UserNameTAG: KidOregon
CreateTimeTAG: 2013-02-27T03:50:15Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: The program does not recognize 81 as correct either.
FirstChildUserIdTAG: 1009374
FirstChildUserNameTAG: JMoolay
FirstChildCreateTimeTAG: 2013-02-27T04:12:54Z
FirstChildVoteTAG: 1
SecondChildTAG: That's because it's not correct.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T04:21:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Correct answer is 80, though I definitely not understand why. The formal definition of the percentile states that it is larger than, not larger or equal than.
SecondChildUserIdTAG: 307887
SecondChildUserNameTAG: vitaliidaniuk
SecondChildCreateTimeTAG: 2013-02-27T16:50:09Z
SecondChildVoteTAG: 0
SecondChildTAG: bec the median value is the 14th value when u count it's 80
SecondChildUserIdTAG: 625229
SecondChildUserNameTAG: alshaimaahmed
SecondChildCreateTimeTAG: 2013-02-27T19:03:10Z
SecondChildVoteTAG: 0
FirstChildTAG: It uses a technique that was explained in the Lectures. The Lectures are *long* but are worth listening to, and please refrain from posting answers (even incorrect ones). Thank you~
FirstChildUserIdTAG: 243804
FirstChildUserNameTAG: JanJo
FirstChildCreateTimeTAG: 2013-02-27T04:19:01Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree. Lecture 2.5 clearly describes how to solve such a problem although it doesn't show in stem and leaf format, the concept is clear.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-02-27T06:21:25Z
SecondChildVoteTAG: 0
SecondChildTAG: > the concept is clear.
Yes, the stem and leaf is just another way to order the data.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T06:24:16Z
SecondChildVoteTAG: 0
SecondChildTAG: cant get the correct answer stuck with this excersize
SecondChildUserIdTAG: 393580
SecondChildUserNameTAG: Aditiak
SecondChildCreateTimeTAG: 2013-02-27T10:22:40Z
SecondChildVoteTAG: 0
FirstChildTAG: Did you watch the lecture? The method for calculating the percentiles in this course was *clearly explained*. You have not followed that procedure.
It was also clearly explained that there are *several* methods for calculating percentiles. And we were clearly told which method to use.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T04:21:20Z
FirstChildVoteTAG: 0
FirstChildTAG: There are 28 varibles in the stem leaf graft. The varible in the median (50th percential) position is 80. On the audio powerpoint lecture this technique is demonstrated.
She multiplies the varible count by the precential to locate the position.
FirstChildUserIdTAG: 1289698
FirstChildUserNameTAG: smpauline
FirstChildCreateTimeTAG: 2013-02-27T05:43:17Z
FirstChildVoteTAG: 0
FirstChildTAG: I appreciate the comments. I understand the lecture. My point is that it's an incorrect method. The definition of the median is the middle value, not the middle number or 50 percentile. Otherwise we would have inaccurate measures of central tendency. For example, if the the two middle numbers were 30 and 81, choosing 80 would lead viewers to believe that the middle 50% is near 80. Calculating the average of the two middle numbers of an even set is the measure of median by definition. In addition, there is no such thing as bi-median as in mode because by definition there is only one median (the middle value).
I appreciate the exercise on data, but it bothers me that we now have two definitions of median. In my humble opinion, there is only one and our course is following one that is incorrect. This is true of range. In secondary science, range is expressed as minimum to maximum. In math, it is expressed as maximum - minimum. The latter is wrong. It is correct if you are talking about the size of the range, but here we are not. So, now students across the US are now working with two definitions. The former gives meaningful data, the latter is a calculation that tells me nothing about variability, the data and its relationship with the mean, and so much more.
On an instructional note, students of statistics find it confusing because of the gray. The average is mean unless the data is skewed, then it's median, for example. It's much like the exception rule for English language learners. It creates a barrier to applying the content at a higher level.
FirstChildUserIdTAG: 1167478
FirstChildUserNameTAG: KidOregon
FirstChildCreateTimeTAG: 2013-03-02T14:03:18Z
FirstChildVoteTAG: 0
IndexTAG: 2234
TitleTAG: Practice Problems a) and b) under Lectures 2.2 and 2.3
The solution provided to Problem a) is incorrect. The interval between -10 and 20 is 30 and NOT 10 as the solution shows.
Problem b) marks answers up to 2 decimals as incorrect. Up to what decimal places should answers be provided?
UserIdTAG: 1139936
UserNameTAG: SundarV
CreateTimeTAG: 2013-02-27T03:45:48Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Gosh!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T04:18:43Z
FirstChildVoteTAG: 1
IndexTAG: 2235
TitleTAG: Stem and leaf plot problem 2
4/5 ] 89
6/7 ] 00023333557
8/9 ] 00112345556788
10/ ] 0
Is this a valid reclassification of the Stem and Leaf plot? Is it possible to use these plots to summarize larger data set this way?
UserIdTAG: 74817
UserNameTAG: benmatthews
CreateTimeTAG: 2013-02-27T03:13:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: This is problematic, benmatthews, as I don't know which elements of your 6/7 leaf should have 6 as the leading digit and which should have 7.
Here's what's commonly done for large datasets that can sensibly be broken into 10's, like scores. The line
6 | 0001233455567778999
can be written as
6 | 00012334
6 | 55567778999
That is, the 10 digits in each "leaf" are split into two sets of two, creating two shorter leaves. Or you could split them into five sets of two, or even ten sets of one.
But unless there's some specific reason for wanting to look at all the numbers on your long list, it might be better to move to a histogram. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-27T03:22:11Z
FirstChildVoteTAG: 3
IndexTAG: 2236
TitleTAG: Lecture notes in Wiki
I've posted highlights from my notes from the first week of class on the Wiki in the Lecture Notes section. They probably won't help you learn the material for the first time, but hopefully they're a good summary and tool for studying down the road. Of course, anyone can contribute to the Wiki, so please add, edit, and improve!
UserIdTAG: 975514
UserNameTAG: sswerdlow
CreateTimeTAG: 2013-02-27T02:55:49Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Awesome, thank you!
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T04:33:03Z
FirstChildVoteTAG: 0
IndexTAG: 2237
TitleTAG: question 3 item a
I have a big doubt for me the graph clearly represent the situation, can someone tell me why not?
UserIdTAG: 427080
UserNameTAG: Drkmarvin
CreateTimeTAG: 2013-02-27T02:55:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I got it wrong as well but realized why afterwards. Read the question CAREFULLY three times and then look at the graph again. This question is more about "did you read it well" than "did you calculate it well"
-Gabriel
FirstChildUserIdTAG: 203329
FirstChildUserNameTAG: gabieee
FirstChildCreateTimeTAG: 2013-02-27T03:04:05Z
FirstChildVoteTAG: 1
SecondChildTAG: Totally agree with all of you！
SecondChildUserIdTAG: 1074160
SecondChildUserNameTAG: CheungA
SecondChildCreateTimeTAG: 2013-02-27T07:54:48Z
SecondChildVoteTAG: 0
IndexTAG: 2238
TitleTAG: Lecture 2.2 and 2.3
Question (a) Height of -10 to 20 bar:
Should the answer be 0.4666 % per unit? The explanation says "Width of the bin" = 10 but I think that width of -10 to 20 is 30. so the answer would be 14/30 = 0.4666? Please explain.
UserIdTAG: 546553
UserNameTAG: kurnala
CreateTimeTAG: 2013-02-27T02:38:11Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: I think my head just exploded.
A picture of the posts beneath yours:
![enter image description here][1]
Just a handful of the hundreds of posts about this. yes it is a mistake.
[1]: https://edxuploads.s3.amazonaws.com/13619329601343657.png
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T02:40:01Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree with kurnala
SecondChildUserIdTAG: 1072042
SecondChildUserNameTAG: onawa
SecondChildCreateTimeTAG: 2013-02-27T02:49:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I found the same mistake. Redid this for half an hour until I realized I wasn't the only one!
SecondChildUserIdTAG: 1274227
SecondChildUserNameTAG: wreaves
SecondChildCreateTimeTAG: 2013-02-27T05:03:17Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with kurnala
FirstChildUserIdTAG: 1072042
FirstChildUserNameTAG: onawa
FirstChildCreateTimeTAG: 2013-02-27T02:50:39Z
FirstChildVoteTAG: 0
SecondChildTAG: The width from -10 to 20 is 30. Thanks.
SecondChildUserIdTAG: 937399
SecondChildUserNameTAG: fernandocalero
SecondChildCreateTimeTAG: 2013-02-27T03:32:37Z
SecondChildVoteTAG: 0
IndexTAG: 2239
TitleTAG: Any chance staff can take control of discussion forum?
Is there any chance the staff can step in and make a statement about the correct use of the discussion forum? It's really frustrating to read 50+ posts about the exact same question. Please insist that people search the forum to see if their question has already been posted and answered before they make a new post.
And, fellow students, please don't post a question with a subject line of "help" or "please help" or "help please" or "help pleazzzzzzzz" as a) you can't search well on them and b) other students are likely to ignore posts with non-specific subject lines.
I'm loving this class. The professor does an excellent job of explaining topics clearly and thoroughly. And we're very lucky that the professor plays such an active roll in the discussion forum. Unfortunately the discussion forum is losing its effectiveness rapidly because so many students don't know to use it correctly. I think a short statement from the staff could be very helpful.
Thanks for letting me vent :)
UserIdTAG: 161449
UserNameTAG: merhutchin
CreateTimeTAG: 2013-02-27T02:15:14Z
VoteTAG: 8
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Thanks, merhutchin. We're about to make some suggestions about how to use the forum and help to make it more usable for others. At the moment I've made it my priority to minimize (preferably down to 0) the instances of student frustration with strangely graded answers. Once that's done, I hope as soon as Week 2 is uploaded, I'll upload a set of documents about how to work through the material, how to use the forum, how to search for terms in the lectures, etc. Most people have figured all this out for themselves, but you're right that there is a great deal of repetition that could be avoided. Thanks to all students who have patiently helped their fellow students and the staff by answering these all-too-frequently asked questions. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-27T02:34:19Z
FirstChildVoteTAG: 6
SecondChildTAG: Keep up the good work!
I do realize the implications (which are minor in **practice** exercises, by the way), but still would suggest that **immediate** correction of a wrong answer would significantly reduce the avalanche of posts.
While on the subject, would you please have a good look at the third histogram of Problem 3b, Exercise Set 2? Compare, for example, bar heights for intervals 9-12 and 13-16.
SecondChildUserIdTAG: 1310109
SecondChildUserNameTAG: COELHO50
SecondChildCreateTimeTAG: 2013-02-27T04:14:12Z
SecondChildVoteTAG: 0
SecondChildTAG: In most grading systems you can not actually change the answer in the multiple choice section or it will change the grades of students who have previously completed the problem set. Some people change their answers to give the computer what it wants for the correct answer and they would then have their grades lowered. This is somewhat of a conundrum for instructors.
SecondChildUserIdTAG: 453550
SecondChildUserNameTAG: DebbieSmith
SecondChildCreateTimeTAG: 2013-02-27T11:30:48Z
SecondChildVoteTAG: 0
SecondChildTAG: As a teacher, I would simply drop such a problem question from the grades completely.
Prof A, when writing the guidance, would you please include how a student can search for discussion posts by staff members? I have not been able to figure this out.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T12:56:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed, DebbieSmith. That is why I pointed out that it would not be a major problem in **practice** exercises, as is the case.
SecondChildUserIdTAG: 1310109
SecondChildUserNameTAG: COELHO50
SecondChildCreateTimeTAG: 2013-02-27T14:38:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Dianebefd, have you figured out a way to do that yet? I'm also interested in seeing staff posts.
SecondChildUserIdTAG: 1181396
SecondChildUserNameTAG: ETurner
SecondChildCreateTimeTAG: 2013-03-02T01:44:49Z
SecondChildVoteTAG: 0
FirstChildTAG: Let's just hope that those who need to read the documents do so.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T02:39:35Z
FirstChildVoteTAG: 0
SecondChildTAG: You have been very patiently answering numerous queries. Thank you, ChristineStv. Hang in there.
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-27T03:23:27Z
SecondChildVoteTAG: 0
IndexTAG: 2240
TitleTAG: AYUDA PARA EL CÁLCULO DE LOS QUARTILES Y PERCENTILES
POR FAVOR, EN DONDE O CON QUÉ DOCUMENTO ME PUEDO APOYAR PARA RESOLVER EL PROBLEMA DE LOS CUARTILES, MEDIANA Y PERCENTILES DEL CONJUNTO DE PROBLEMAS 3.
GRACIAS . IDELFONSO
UserIdTAG: 903196
UserNameTAG: ITZ
CreateTimeTAG: 2013-02-27T02:12:32Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Prueba con esto.
[http://www.purplemath.com/modules/boxwhisk.htm][1]
Y es posible que desee probar el traductor de google para ayudar. Existe una extensión para Chrome y Firefox para traducir páginas web al español
[Google Translate][2]
[1]: http://www.purplemath.com/modules/boxwhisk.htm
[2]: https://chrome.google.com/webstore/detail/google-translate/aapbdbdomjkkjkaonfhkkikfgjllcleb?hl=en
FirstChildUserIdTAG: 243804
FirstChildUserNameTAG: JanJo
FirstChildCreateTimeTAG: 2013-02-27T04:33:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Preuba 'Dave's ESL Cafe'. Hay una seccion para los estudiantes, 'for students'. Hay ayuda para lenguage colliquial, la jerga, y gramática.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T13:04:10Z
SecondChildVoteTAG: 0
IndexTAG: 2241
TitleTAG: Respectfully suggest that the answer for practice problem a) for sections 2.2-3 is incorrect
The explanation states that "The height of a bar is equal to: relative frequency in the class interval/width of class interval. Therefore, the height of the -10 to 20 bar is 14/10 = 1.4% per unit."
However, it should be 14/30, because 20 - (-10) = 30, so % per unit should be .467
UserIdTAG: 1280636
UserNameTAG: jonnybravo9
CreateTimeTAG: 2013-02-27T02:01:20Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Yes, I do agree with jonnybravo9. width of the class should 30, instead of 10.
FirstChildUserIdTAG: 546007
FirstChildUserNameTAG: dpatial
FirstChildCreateTimeTAG: 2013-02-27T02:08:02Z
FirstChildVoteTAG: 0
SecondChildTAG: So do I. The width of the class interval is 30.
SecondChildUserIdTAG: 1199074
SecondChildUserNameTAG: VeraA
SecondChildCreateTimeTAG: 2013-02-27T02:24:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed.
SecondChildUserIdTAG: 1013509
SecondChildUserNameTAG: Martha123
SecondChildCreateTimeTAG: 2013-02-27T02:30:30Z
SecondChildVoteTAG: 0
SecondChildTAG: i concur
SecondChildUserIdTAG: 1223498
SecondChildUserNameTAG: shiloheflavien
SecondChildCreateTimeTAG: 2013-02-27T02:33:15Z
SecondChildVoteTAG: 0
FirstChildTAG: I respectfully suggest that you read just one of the hundreds of posts about this.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T02:34:11Z
FirstChildVoteTAG: 2
IndexTAG: 2242
TitleTAG: Rounding Decimals
When we are dividing fractions how many decimal points should we round to? I haven't been rounding at all (just taking it straight from the calculator as it) and my answers frequently come up wrong. It seems as if there needs to be a consistent rule for this.
UserIdTAG: 1109996
UserNameTAG: ARober
CreateTimeTAG: 2013-02-27T01:56:13Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: right thing is to take 3 decimal point after
FirstChildUserIdTAG: 1076694
FirstChildUserNameTAG: CFERRER
FirstChildCreateTimeTAG: 2013-02-27T02:04:32Z
FirstChildVoteTAG: 0
FirstChildTAG: Round to one decimal point (00.0). Seems to be the norm unless otherwise specified.
FirstChildUserIdTAG: 243804
FirstChildUserNameTAG: JanJo
FirstChildCreateTimeTAG: 2013-02-27T04:20:46Z
FirstChildVoteTAG: 0
IndexTAG: 2243
TitleTAG: CALCULO DE LA MEDIANA
ESTOY CASI SEGURO QUE LA MEDIANA EN EL CONJUNTO DE EJERCICIOS 3 ES 80.5. POR QUÉ ME SALE ERROR?
UserIdTAG: 903196
UserNameTAG: ITZ
CreateTimeTAG: 2013-02-27T01:56:00Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: well, you should check the lecture! there it says why. It is because the formal definition of percentile
FirstChildUserIdTAG: 1081681
FirstChildUserNameTAG: Gabv105
FirstChildCreateTimeTAG: 2013-02-27T03:51:38Z
FirstChildVoteTAG: 0
SecondChildTAG: para ser honesta, claro algo fuera de foco en el tema pero a mi me parece muy raro 3 pruebas en una semana con notas. porque digo qeu me parece raro es porque estudio en la univercidad de estocolmo y por muy rapidos que los temas hayan sido como ej introduccion, analisis, poder etc jamas te han dado 3 pruebas en menos de una semana. esto sera un tipo de estudio para ver que inividuos tiene memoria corta o que inividuos tienen memoria larga? la verdad no me entra en la mente tres pruebas en una semana :-s quisiera saber de como piensa el profesor. ya voy para mi segundo termin de sociologia pero este estilo de estudio no tiene ni pies ni cabez para mi gusto :-s
SecondChildUserIdTAG: 1212522
SecondChildUserNameTAG: Cessan
SecondChildCreateTimeTAG: 2013-02-27T05:52:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Utiliza técnica incorrecta
FirstChildUserIdTAG: 243804
FirstChildUserNameTAG: JanJo
FirstChildCreateTimeTAG: 2013-02-27T04:22:01Z
FirstChildVoteTAG: 0
IndexTAG: 2244
TitleTAG: CÁLCULO DE CUARTILES Y PERCENTILES
SOLICITO UNA NUEVA OPORTUNIDAD PARA REVISAR LOS EJERCICIO EN LOS QUE NO ACERTÉ Y CREO CONOCER YA EL PROCESO. GRACIAS
UserIdTAG: 903196
UserNameTAG: ITZ
CreateTimeTAG: 2013-02-27T01:52:21Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: ?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T02:34:37Z
FirstChildVoteTAG: 0
FirstChildTAG: Translation:
"I REQUEST A NEW OPPORTUNITY TO CHECK THE EXERCISE IN THAT I WAS NOT RIGHT AND I AM ALREADY THINKING ABOUT KNOWING THE PROCESS. THANK YOU"
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-27T18:14:09Z
FirstChildVoteTAG: 0
IndexTAG: 2245
TitleTAG: 20/20
I am very happy, because I get 20 points.
UserIdTAG: 1237522
UserNameTAG: Gabrielavedano
CreateTimeTAG: 2013-02-27T01:42:26Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: impressive
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-27T01:52:32Z
FirstChildVoteTAG: 0
FirstChildTAG: God job anyway
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-27T01:55:33Z
FirstChildVoteTAG: 0
IndexTAG: 2246
TitleTAG: pass mark
how many percent is required to pass this course?
UserIdTAG: 1093720
UserNameTAG: Bookjunk1e
CreateTimeTAG: 2013-02-27T01:41:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Have you read the General Course Information documents?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T01:44:16Z
FirstChildVoteTAG: 3
SecondChildTAG: 35% overall. There is a nice function where you can track your progress under the "Progress" heading. Good luck!
SecondChildUserIdTAG: 811172
SecondChildUserNameTAG: MarianB
SecondChildCreateTimeTAG: 2013-02-27T01:52:44Z
SecondChildVoteTAG: 0
IndexTAG: 2247
TitleTAG: Started
I love the way you explain statistic, because I looks simple and clear
UserIdTAG: 1160694
UserNameTAG: mfvargas
CreateTimeTAG: 2013-02-27T01:12:38Z
VoteTAG: 1
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 0
IndexTAG: 2248
TitleTAG: Problem 7
This is not taking the value corrected upto 2 decimal places.
UserIdTAG: 1147139
UserNameTAG: AnaAggarwal
CreateTimeTAG: 2013-02-27T01:09:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Why did you use 2 decimal places? The other decimal value in the chart has one decimal place. This would lead me to believe that the answer should be rounded to one decimal place.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T02:00:10Z
FirstChildVoteTAG: 0
SecondChildTAG: I found out, I made a mistake in calculation and landed up with a wrong answer.
SecondChildUserIdTAG: 1147139
SecondChildUserNameTAG: AnaAggarwal
SecondChildCreateTimeTAG: 2013-02-27T02:36:09Z
SecondChildVoteTAG: 0
FirstChildTAG: I found out, I made a mistake in calculation and landed up with a wrong answer.
FirstChildUserIdTAG: 1147139
FirstChildUserNameTAG: AnaAggarwal
FirstChildCreateTimeTAG: 2013-02-27T02:36:26Z
FirstChildVoteTAG: 0
IndexTAG: 2249
TitleTAG: Materials of the lecture in RStudio
# We're creating a vector of numeric data
Data <- c(7, 2, 7, 4, 0)
# and then we're sorting them.
Data <- sort(Data)
# Let's look at our sorted data
Data
# Let's see a median of our data
summary(Data)
# Let's add 12 into position 6 of our vector
Data <- append(Data, 12)
summary(Data)
# Let's calculate 25% percentile manually
6 * 25 / 100
# and using a generic function
quantile(Data, type = 6)
![Percentiles][1]
[1]: http://savepic.ru/4157572.png
UserIdTAG: 209516
UserNameTAG: Andrey_K
CreateTimeTAG: 2013-02-27T00:57:57Z
VoteTAG: 6
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 1
FirstChildTAG: Really enjoying your posts Audrey about how you solve particular items in R. Could you possibly post them in the wiki rather than the discussion forum to make it easier to find then troll through all the posts?
Thanks,
Daniel
FirstChildUserIdTAG: 1181263
FirstChildUserNameTAG: drush
FirstChildCreateTimeTAG: 2013-02-27T02:49:47Z
FirstChildVoteTAG: 2
SecondChildTAG: and why not start it for you https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/R/
SecondChildUserIdTAG: 1181263
SecondChildUserNameTAG: drush
SecondChildCreateTimeTAG: 2013-02-27T03:26:38Z
SecondChildVoteTAG: 0
IndexTAG: 2250
TitleTAG: Doubt
On READING AND PRACTICE FOR EXERCISE SET 2, Lectures 2.2 and 2.3, question a, when you ask to show the correct answer, it shows that the width of the range -10 to 20 is equal to 10 instead of 30 measurements units... is this correct?
UserIdTAG: 707898
UserNameTAG: meaugust
CreateTimeTAG: 2013-02-27T00:56:07Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Prof, Oh please please please fix mistakes when they are discovered. This **constant posting of the same problem** is ruining the experience.
meaugust, did you notice *any* of the posts on the page when you made yours? yes, it is a mistake.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T01:15:11Z
FirstChildVoteTAG: 0
FirstChildTAG: I think people should lose points if they post a question that's already been posted 20+ times.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-27T02:02:18Z
FirstChildVoteTAG: 4
IndexTAG: 2251
TitleTAG: Love this course!
I am so excited waiting for next week's lectures! I love this course and I am so impressed by your lectures Prof. Adhikari! You explain everything so clearly that I only made one silly mistake on the homework. I love the online textbook and ability to interact with the problem sets there.
You make the lectures so fun and interesting, that I am anxious for week 2 to start!
Thank you again for taking the time to make Stat2.1x available to us.
UserIdTAG: 664881
UserNameTAG: OKSue
CreateTimeTAG: 2013-02-27T00:41:18Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I am also excited for the arrival of Week 2 lecture and its assignments. You rightly said that how clearly Prof.Adhikari teaches us new concepts.
FirstChildUserIdTAG: 1256932
FirstChildUserNameTAG: SandeepNarang
FirstChildCreateTimeTAG: 2013-02-27T02:39:38Z
FirstChildVoteTAG: 2
FirstChildTAG: I would also like to extend my thanks to Prof Adhikari. I really appreciate her enthusiasm and passion for the topic!
FirstChildUserIdTAG: 1145404
FirstChildUserNameTAG: KimHill
FirstChildCreateTimeTAG: 2013-03-02T02:14:38Z
FirstChildVoteTAG: 0
IndexTAG: 2252
TitleTAG: Histogram area question
In an histogram if the area repersents percents, then what repersents the amount of the data you are measuring?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-27T00:31:06Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: The height of the histogram is the percentage per bin unit. This reflects how crowded the class range is for that particular bin. For example, if you have twice the number of samples in one bin then it will be twice the height if the bins are the same width. This is why it is an excellent indicator of where you have a proportionately high number of samples within a bin
FirstChildUserIdTAG: 920755
FirstChildUserNameTAG: hamptonjj
FirstChildCreateTimeTAG: 2013-02-27T02:04:28Z
FirstChildVoteTAG: 0
FirstChildTAG: The area
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T02:21:17Z
FirstChildVoteTAG: 0
FirstChildTAG: One way to think of it is that "amount of data" and "percent of the data" are the same measure just with different units, just as the vertical axis could be scaled in $/unit or #/units, and the two graphs will look the same, just with a different scale factor for the axis.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-27T05:42:36Z
FirstChildVoteTAG: 0
IndexTAG: 2253
TitleTAG: I am quite unhappy with this course
**General complaints why I am unhappy and I hope are constructive and might immediately improve this course**
*Executive summary (as per Mzvd):* The format of the course is unbearably confusing. It is not clear what I am supposed to do to prepare for the test questions. Do I listen to the narrated slide shows or do I read them? When should I watch the video lectures? When do I read the pages? And in what order do I do any of this? There is no clear process to follow, because it is not stated in the course material what to do. It's not consistent. What are the concepts? what are the relationships between the concepts taught and the formats? What is the relationship between the lectures by the two instructors?
**Additional points which are concerns of mine**
- *Overall request*: Please repair the learning structure
- Toggle powerpoints with scrolling transcripts
- Reduce demands on our time
- Reduce cognitive noise
- Failure or absence of instructional design
- Eliminate technical snafu in browser accessibility
- Clarify test formats
- Accommodate different learning styles
- Integrate video timestamps into the outlined material
- Clarify and emphasize answer formats required in the test question
**Overall Request: Please repair the learning structure**
So many formatting errors are made in this course that are confusing and do not follow the conventions of what we know to be successful online learning formats. As you can tell by the length of this post, I am very unhappy and I may drop this class and wait until EdX makes it easier to follow.
**Toggle Powerpoints with scrolling transcripts**
It is well known that learning does not take place with powerpoints if all they do is repeat verbatim the words of the lecturer. There should be a synthesis of the high points or takeaway concepts which should be highlighted in the slides and I should be able to access them at any time of the audio if I need to. Furthermore, the most important concepts should be presented in a hierarchy as an outline somewhere on the page. What are the subset topics? What are the relationships between concepts? How am I to pick out the lecture material I hope to lay my hands on tomorrow or a week from now to review?
**Reduce demands on our time**
Is it correct to make the student view an entire lecture twice to review? How much time do you think we have to watch videos, listen to audio, and to read? to do that twice? How do I find content in the video lecture or slideshow if I want to review? How am I supposed to synthesize all this material if it is not structured for me by the subject matter experts (SME)? Single headers is not enough.
**Reduce cognitive noise**
In this course, cognitive noise is rampant.
For readers who don't know what cognitive noise is, here's a study from 1987 that discusses it: http://psycnet.apa.org/index.cfm?fa=buy.optionToBuy&id=1987-24023-001.
Sometimes people refer to a related concept in Instructional Design called *cognitive load*, and you can learn about that here:
- http://theelearningcoach.com/learning/what-is-cognitive-load/
- http://en.wikipedia.org/wiki/Cognitive_load
The worst thing to do in an online course is to have a moving transcript while someone is speaking, next to visual slides. In Instructional Design it is well understood that this creates cognitive friction (listening and looking are different cognitive operations when they are not generated in the same location). This format interferes with learning because it creates attentional noise! You must pick one or the other for the viewer and guide us how to connect the conceptual dots. For example, if you want the viewer to look at a chart, perhaps indicate to stop the recording and review the chart for a minute and then resume the recording. (This can be done with the video lectures with overlays.) Tell the viewer what to look for in the material, relationships, etc. Or create animated highlights as the audio is running. Sorry, but waving a cursor around doesn't cut it.
If you don't believe in the coordination of the visual and the audio with the conceptual, ask yourself why watching a subtitled foreign movie is annoying when the subtitles flash too quickly across the screen or are out of synch with the picture. Try to watch a video with the soundtrack synched 1 second too soon or too late. Or say you sit in the dark movie theater and an usher is waving a flashlight around? Inevitably you will miss the movie by having something pulling your attention away in your peripheral vision because it's human reflex to attend to what is moving over what is heard. You can't read text, listen to the audio AND ON TOP OF THAT sort out the important points all at the same time.
I'd hate to think what students must do who aren't native English speakers, they must be totally lost.
**Failure or absence of instructional design**
It is the job of the instructor to explain what is to be learned beforehand then to highlight the concepts, illustrate with examples, and then to review what the concepts are, and perhaps where mistakes are frequently made by novices or even experts to reveal complexities and assumptions. I suspect this is evident if I'm just reading the text material, or just viewing the video, or just listening to the audio, but not if they are combined. There is also no topic overview or review in the materials. This would help immensely in creating cohesion among the different materials.
It is the job of the instructional designer to format this content on the screen according to priorities that the instructor deems vital to learn the topic. That is not done here.
Taking practice test questions is NOT review. It's practicing for the test, it isn't review for learning.
I find a lack of coordination here between the instructors and the designers. It is unfortunate.
**Eliminate technical snafu in browser accessibility**
If I put the audio slideshow on full screen I can't see the bottom of the screen (it goes off the page) and the animated transcript lays on top of the slides so the slide content is cut off to the right. There should be a way to toggle the transcript so that if I want to turn it off I can. Please fix this (I am using Firefox).
**Clarify test formats**
Then, the format of the test questions is EXTREMELY confusing. Being forced to scroll high above or far below the content in the browser to access data or to visit another page is plain laziness by whoever formatted this course. Having more than one window open makes it very difficult and confusing to collect the information necessary to get the test questions correct. What if people are using their mobile phones to view the lesson? Each question should have all the content right to the side of it so that it can be referenced easily and reduce cognitive noise.
Then, at least once it is stated "Look at data above this section" when it is not stated what "THIS SECTION" is???? When I go to the page linked there are several sections on it, it's a hugely long page without basic page structure (there are headers but that's all). Anchor tags are not good enough because what if I scroll up or down and then loose my place because I walked away from the screen and forgot where I was? Interruptions happen, you know? Why not just put the content/data on the same page as the test question appears????
**Accommodate different learning styles**
Or is it "spaghetti and meatballs for everyone!" ?
Everyone has a unique way of learning. One size doesn't fit all. For people who are visual learners (which is why I took this course...it is descriptive stats, right?) there are very few visual aids. I'm not talking about tables or barcharts. I mean the text. I must read all the text and pick out the pertinent points, which is most times a guessing game. I can't scan the text. There are no headers and subheaders, nothing in bold, no bullet points, and I already mentioned there is no overview or review to alert me to what is important to know in a given lesson. Text formatting is just good document design. These are *visual aids* used to format content. Think about newspapers, books, indexes. What I do see is textual spaghetti with an occasional visual meatball. :)
**Integrate video timestamps into the outlined material**
If you are going to use video from previous lectures, there should be an outline of critical concepts with timestamp indexes. That way, if I want to review after getting the general overview, I can spool the video to the right place and listen to the lecture accordingly.
**Clarify and emphasize answer formats required in the test question**
It is not always clear what answers are being requested from me on the test. Specifically concerning formats (in some cases it is "round off to one decimal" in another it is two). There should be a convention over the course. Do you want to test us on formats? or on the content of this course to see if we learned something about descriptive statistics?
If I got (in reality) a right answer from reading the data offered and made a correct calculation, but rounded it incorrectly, that means I am penalized for formatting and NOT for the knowledge gained. I doubt that the instructors believe it is vital to enriched learning to pay attention to the decimal placement of answers. Regardless, formats requested should be emphasized in the text of the test question. Such as placing it in BOLD, or in a callout right next to the question.
**Reduce cultural barriers**
Please don't assume so much of students who come from very different cultures, as well as the variety of students who are used to learning in different ways (i.e. verbal learners, visual learners, kinesthetic learners).
It is clear to me that there has been a lot of work done to put this course online, but the learning structure is incomplete and therefore confusing (for reasons stated already). If you are going to have a course of over 40K students and not give the time to create a positive learning experience using basic conventions to structure learning materials (known in learning science for quite sometime now), I can't imagine the experience will be beneficial, particularly to students who are second-language learners. Visual structure can be immensely helpful, as well as provide more scaffolding to indicate how to engage with the material.
**I wrote this post because I want to learn descriptive statistics**
I am sorry for the negativity, but if EdX cares about creating stellar learning experiences, please refine what work you've done here and make it consistent (AKA "dummy-proofing") so that we can pay attention to the content and not the format issues.
My comments are intended to be constructive and specific and are not meant to denigrate the instructors or the designers, or even my fellow students.
**Review**
There is far too much cognitive noise in this course format. Please fix it. It's like turning in a term paper with typos!
Thank you!
UserIdTAG: 963897
UserNameTAG: lightbulb
CreateTimeTAG: 2013-02-27T00:30:50Z
VoteTAG: 9
CoursewareTAG: undefined
NumberOfReplyTAG: 14
FirstChildTAG: Could you, please, make an 'executive summary' of your post or at least a bullet point list with the most important ideas and put it on top of your post. It is really difficult to follow what you are trying to convey through a waterfall of question marks (too much noise, I guess).
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-27T00:50:21Z
FirstChildVoteTAG: 6
SecondChildTAG: The executive summary is: "I am unhappy with this course."
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-27T04:37:16Z
SecondChildVoteTAG: 0
FirstChildTAG: I too, am confused about what to do and in what order. I think I need to drop this course until the whole process is better defined.
FirstChildUserIdTAG: 916419
FirstChildUserNameTAG: Greg-In-KS
FirstChildCreateTimeTAG: 2013-02-27T00:56:51Z
FirstChildVoteTAG: 2
FirstChildTAG: **General complaints why I am unhappy and I hope are constructive and might immediately improve this course**
Um, yeah. You obviously watch the lectures, and do the problems. That's how courses work...
**Please repair the learning structure**
I agree, sometimes there are bugs in the program, though they will eventually decrease as the website gets older.
**Powerpoints with scrolling transcripts**
Do you have a suggestion? She lectures, and her main points appear on the screen. It's no different than being in a college lecture, in fact, it's easier.
**Demands on our time**
If you can't remember the lectures, take notes. I, personally, remember most things, but I write the important points in Notepad, and go back to them to study later. The lecture titles cover basically what is in the lectures, so if you have a problem you can't answer, you can review that lecture.
**Cognitive noise is rampant**
Turn the subtitles off, if you don't like them. Our professor talks slowly, giving you time to think, but if she's too fast, you can slow down the recording. If you need to stop to review a chart, do it. Why waste lecture time telling you to? If you missed something, back it up.
**Failure or absence of instructional design**
There's always the wiki, and you can buy a textbook, if that's what you want. The tests cover what you learn, so that is an exercise to help you remember.
**Technical snafu in browser accessibility**
It works fine for me in Firefox. Try a different browser.
**Test formats**
There's always some problem for someone. Deal with it.
**No accommodation of different learning styles or "spaghetti and meatballs for everyone!"**
Sorry, there's nothing you can do. You can read the subtitles, the powerpoint slides, or whatever. But I do like spaghetti! :)
**Video integration into the material**
You can scroll through the subtitles, find what you want, and click on it. The video will skip to that moment.
**Test answer formats**
I agree, once they didn't tell you what to round it to, but they told you on the test. Hopefully that mistake won't be made again!
**Cultural barriers**
If you are a kinesthetic learner, you write down what you are learning. Visual, you read the subtitles. Auditory, you listen. Of course, there's always a few that don't work out, but it works for most.
Sorry if I offended you, but really. You need to use your brain and solve problems.
FirstChildUserIdTAG: 484877
FirstChildUserNameTAG: Andre97
FirstChildCreateTimeTAG: 2013-02-27T01:02:35Z
FirstChildVoteTAG: 8
SecondChildTAG: I'm sure you have a brain too. But it's clear you do not know what Instructional Design is.
That's OK.
Sorry if I offended you. :)
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-27T04:39:46Z
SecondChildVoteTAG: 0
FirstChildTAG: Oh dear. Psych babble. Always bad.
>The format of the course is unbearably confusing.
The set up is quite clear. The lectures are in the Courseware section. Watch them. The assessments are clearly indicated. Do them. What is the problem?
If you have to go elsewhere for the data, so what? I've looked at other courses where you have to go download data from a different website to do assessments.
>Please don't assume so much of students who come from very different cultures and the variety of students who are used to learning in different ways
The course has English has a prerequisite. And being an online course the trendy "I learn this way" really can't be catered to. You just have to adapt to the format as given. edX is doing a magnificent job in trying to provide education access to people who, quite honestly, would never gain formal admission to a university.
There are issues. For instance correcting known mistakes asap so those who are incapable of following the instructions for forum use just might, might mind you, stop posting the same thing over and over and over and over.........
> I am very unhappy and I may drop this class and wait until EdX makes it easier to follow.
The only reason I am thinking of moving on, or dismissing the discussion board, is because most problems are caused by people who cannot, or will not, read the information posted - but bomb the forum with questions that would have been answered had they bothered to look first.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T01:06:20Z
FirstChildVoteTAG: 6
SecondChildTAG: Yet another person who doesn't know what Instructional Design is...
The set up is **not** clear. Where is the overview? Where is the review section? What is the relationship between the offsite Stark material and the EdX onsite stuff? Which should I cover FIRST?
Cultural barriers have nothing to do with the language that you speak. I said cultural barriers, not language barriers.
As far as learning styles maybe try reading up on the field of online learning and instructional design. Learning styles can be catered to and quite easily. I guess you haven't experienced it. As someone else commented here, HarvardX got it right.
This is my first EdX course and it isn't a magnificent job. It's a pretty UI, sure, but I've had several online courses using Blackboard (which is quite the ugly duckling) where I've not been half as confused as here.
If I was paying for this course I'd demand a refund right away.
I came to learn descriptive statistics, instead there is too much confusion in the format, which makes learning the material difficult - material which I'm sure the professors are totally competent to instruct in person and who I'm sure care very much about this topic.
I can see that.
That is why I'm showing that I care, by writing my post, which if it is too much trouble for you, you do not have to read it, by all means.
Have a nice day.
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-27T04:59:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Course is very clear for me. Why do you think that whoever wrote "Instructional Design" concepts know better what will be easy for most of people?
This is course with lectures and exercises, that is it. Review sections is something you do on your digital or paper notebook.
knowing term "Instructional Design" and using it in evey sentence doesn't make you smarter. People with 10+ years experience don't even use that term, they use completely different one, which means that you most likely just learned it and think that you are expert on that.
Just my thoughts. In any case we all should write our ideas and suggestions in as polite way as possible, simply because by statistics there is bigger chance that somebody will read, understand and adjust when you are polite.
SecondChildUserIdTAG: 127421
SecondChildUserNameTAG: apbyte
SecondChildCreateTimeTAG: 2013-03-18T23:46:21Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with most of the statements made by lightbulb. I've taken (and completed) another course at edX (MITx) and it was far more organized than this one (even considering that schedule of the MITx course was six times longer than that of Stat2.1x).
Anyway, I'm not saying that this course is bad, quite the contrary, I fully understand the effort that all the BerkeleyX staff is doing to take it forward and I'm grateful for that. However, like lightbulb, I too would have expected that his comments have been taken as constructive criticism.
FirstChildUserIdTAG: 518419
FirstChildUserNameTAG: fabianp
FirstChildCreateTimeTAG: 2013-02-27T01:39:10Z
FirstChildVoteTAG: 4
SecondChildTAG: Thank you fabianp.
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-27T04:59:28Z
SecondChildVoteTAG: 0
FirstChildTAG: Get over it.
This is not perfect, but it is by far a great tool for personal improvement.
Although there are some points that can - and probably will be enhanced - this is an exceptional opportunity for thousands of students around the globe to share a common learning experience. I don't even care about the financial issue - aka free - but there are multiple people out there helping us out and trying - to their best - to provide timely and informed answers. They deserve some academic respect.
If you don't believe that the PDF or the videos - or the subtitles - are enough (well, I never had subtitles at my undergraduate or graduate classes) - take notes. That is what I do. And if the issue is not clear, then there are so many sources of data out there to help you. believe me - it works - even if myself and my wife work full time, I travel for business - we have children, and i still manage my time enough to get this squared.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-27T01:41:27Z
FirstChildVoteTAG: 4
SecondChildTAG: I think my comments are coherent and valid. Sorry you disagree.
If edX is using the big name universities to draw in students to sign up, then they should also have the big-name quality down too.
This course should have been tested beforehand with a small control group. Any wrinkles should have been ironed out BEFORE over 40K students signed up. That's a catastrophe on so many levels, if you were to ask me... though I know you are not asking me.
It's worse than a Microsoft Windows release!
We are all guinea pigs, I guess.
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-27T05:07:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Though I am not disappointed with the course, I somewhat concur and am impressed with the great indepth analytical ability of "lightbulb" to the acquisition of knowledge and the modality of learnng used by different learners. I strive to use them all and have made a mention of this in my e-book "Simple and Not So Simple Proven Ways to Sharpen Memory" available at Kindle and Smashwords.com
I did feel a little bit disappointed on one practice test or other to see that answering to two decimal places made my answer wrong and to one decimal place was right! I hear this has been fixed.
Since storage space is not an issue, data can be printed again near the test question OR providing hyperlink to data and back to the test questions can alleviate the problem of solving the problem by looking at data and then coming back to the test portion to answer the questions. In the absence of such a setup, one needs to scroll down a lot of pages on screento get to where one may need to be and make some frequent to-and-fro movements on the scroll bar. This may be a little extra-wrok to put hyperlinks for the organizers, but IT Department can facilitate this process, and may simply be a piece of cake for them to do.
Summing up, thanks to all involved in organizing and presenting the course material and the opportunity to listen to candid, constructive criticism.
With regards and best wishes to all.
FirstChildUserIdTAG: 987158
FirstChildUserNameTAG: vijaysharma1122
FirstChildCreateTimeTAG: 2013-02-27T01:48:43Z
FirstChildVoteTAG: 1
SecondChildTAG: lol
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T01:51:11Z
SecondChildVoteTAG: 0
FirstChildTAG: I wish they at Berkeley would learn from Harvard Edx (Ph207x) on providing a very clear and helpful materials to guide students
in their learning. I have seen the videos, read the sticigui materials, and did some of the exercise, but these did not help me completed the graded exercise with 100% confidence.
Do i have to memorise everything before attempting the exercise??
as there are no reading materials to refer to, except some pointers from pdf slides
FirstChildUserIdTAG: 199205
FirstChildUserNameTAG: ririana
FirstChildCreateTimeTAG: 2013-02-27T03:20:28Z
FirstChildVoteTAG: 3
SecondChildTAG: +1
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-27T05:00:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Get a pen and paper. Write notes. That is a great way to learn.
SecondChildUserIdTAG: 954932
SecondChildUserNameTAG: hellothomasjohnson
SecondChildCreateTimeTAG: 2013-03-07T09:49:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Sorry, guys, but some complaints such as
> Do i have to memorise everything before attempting the exercise??
make me weep. What will come next? "Do I have to study for the midterm?"
As per course organization: the first thing to do when a course starts is to read its schedule. For example, it helped me to learn that Section 2 comes after the Section 1 as well as Lec. 2.2 is comes before Lec 2.3. As a result, I sleep better at now - no confusion at all.
Regarding other questions Andre97 gave a nice summary. Nothing to add.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-27T10:43:13Z
FirstChildVoteTAG: 1
SecondChildTAG: Perhaps you might look into what instructional design is! Clearly you don't know what it is.
I did post some links, if you care to understand what I'm addressing, read them. You might pick something up. :)
I didn't ask anyone for advice how to use the website, that includes you. I made some valid observations about the design of this course. I even made specific suggestions.
Perhaps you should not take things so personally. Weeping? really?
I will take you at your word that you have nothing to add.
I'm at a loss why people have to use the discussion forum to put down people with snark rather than deal with the spirit of the post.
Good day to you.
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-02-27T21:53:31Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks lightbulb
SecondChildUserIdTAG: 199205
SecondChildUserNameTAG: ririana
SecondChildCreateTimeTAG: 2013-02-27T23:37:20Z
SecondChildVoteTAG: 0
SecondChildTAG: Maybe lightbulb it's just that once the pretentious psychobabble claptrap hits the forums, heads explode.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-03-05T02:56:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for your comment, SusanAust. They are always so helpful!
Have a great day!
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-03-13T05:57:38Z
SecondChildVoteTAG: 0
FirstChildTAG: And now, the recent complaints about whether the closing time for the graded excercises was GMT or not... Certainly, it is stated on the "Course policy and requirements" as it was the case on other edX courses, but... why there were no misunderstandings in the other courses? (even when some of them had far more students than this one?) ...not that things really are not so clear?
FirstChildUserIdTAG: 518419
FirstChildUserNameTAG: fabianp
FirstChildCreateTimeTAG: 2013-02-28T02:02:27Z
FirstChildVoteTAG: 0
FirstChildTAG: Oh my, it really sounds like you would like someone to come to your home and make the course fit to your personal requirements. I understand some people may have suggestions for improvement, but really I think these requests are, on the whole, very very unreasonable.
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T11:45:48Z
FirstChildVoteTAG: 1
FirstChildTAG: edX is a wonderful platform, but this course doesn't take advantage of the features available. And it is not a BerkeleyX's problem. From all the edX courses I've seen (MITx 6.00x, MITx 6.002x and BerkeleyX CS188.1x), this is the less organized.
I have 2 specific complaints:
- The lack of exercises and example and review questions **during** the lecture sequences. This is wonderfully implemented in the other edX courses, but not here.
- The division of the contents between here and Stark's page.
As a solution, the exercises in Stark's page we're asked to do, could be implemented as exercises in the middle of lectures. And Stark's videos could be optional sequences here.
In other edX courses, generally there're exercises, quizzes and examples between one video and another of the lecture sequences. This is one of the best features, giving a pause to think and allowing students to practise and review immediatelly after learning the concepts. And, in general, there's one exercise set (or project) per week, reviewing the concepts of the entire week. Not one after each sequence.
FirstChildUserIdTAG: 188586
FirstChildUserNameTAG: FLara
FirstChildCreateTimeTAG: 2013-03-05T08:52:47Z
FirstChildVoteTAG: 1
FirstChildTAG: The course is really not all that hard.
FirstChildUserIdTAG: 1158056
FirstChildUserNameTAG: CanuckistaniPhilosopher
FirstChildCreateTimeTAG: 2013-03-07T01:35:06Z
FirstChildVoteTAG: 0
SecondChildTAG: You are right. The course is not that hard.
It's the formatting.
SecondChildUserIdTAG: 963897
SecondChildUserNameTAG: lightbulb
SecondChildCreateTimeTAG: 2013-03-13T06:33:24Z
SecondChildVoteTAG: 0
FirstChildTAG: To the Professors and BerkeleyX Staff for of Stat2.1:
(not to those who have nothing better to do than snark)
**EdX Intro Videos**
I have signed up to another class on EdX, at MITx, and there are a few things I notice there that I hope you will include in your list for improving this course.
The problem I now see that I encountered in this course when I began is that there was no Intro to EdX which explains how to use the UI. There were a few things I did not figure out until I was in another class. For example that I could turn off close-captioning.
BTW, discussion board snark would also be minimized, as the intro also explains how to be considerate in the discussion forums. Although... anonymity does seem to breed contempt in some more than others... :) The intro from EdX also says that staff will prune discussion of unhelpful posts and comments, I hope that will be done for all courses, not just some. There is a lot of trolling going on that I think detracts from the caliber of what this experience could be.
And so, would you mind terribly to place the EdX Intro videos at the beginning of the lecture panels (left nav bar) to appear before we start on the material? In my case, I had not taken an EdX course before, and there were several formatting issues I experienced that made it impossible to concentrate on the material. This has nothing to do with your teaching knowledge of Stats, but working through the presentation, that is, the instructional design. I was very exasperated when I made my original post, because these are simple things to correct, since it is formatting and only formatting.
**Offsite and onsite lectures and study materials**
Another issue is the division of lectures on EdX (provided by Prof Adhikari), and those offsite (provided by Prof Stark). I have noticed that there are now more explicit instructions of where to stop on the Stark lecture pages, when going off the EdX site. Thank you for doing that, it is making it far easier to follow.
It seems though, for easier for instructional flow, that the Stark videos could be included directly into this presentation at EdX, and then the text and applets divided by a section per page, also to appear here, rather than one long page (as it appears offsite currently). I'm not sure why that couldn't be done quite easily, unless it has to do with copyrights or something of that nature.
I think going off the site does create confusion, and it gives a feeling that people scrambled to get material ready for this course, since the course already started late.
If we students have hard and fast deadlines to get in homework, shouldn't you also have hard and fast deadlines to make sure the material is prepped and tested for quality assurance?
**Missing tagging/linking of sequenced material**
I am also noticing that there are some EdX lectures segments that do not have proper headings to indicate where they are in the sequence. For example, lectures 5.3 and 5.4 are not labeled so.
Then, as many people are posting, there is no download link for lecture 5.4's video.
**YouTubes have errored out**
For some reason as well, the youtube videos are erroring out. It may be because of my own internet access, as I was able to see them earlier today. I tried to search on youtube for the Stat2.1x videos to watch them there, and they are not appearing in any searches. I'm not sure what is happening there. I have downloaded all the videos save one, that is missing a download link.
Thanks for reading this and all your efforts.
FirstChildUserIdTAG: 963897
FirstChildUserNameTAG: lightbulb
FirstChildCreateTimeTAG: 2013-03-13T06:35:40Z
FirstChildVoteTAG: 0
IndexTAG: 2254
TitleTAG: Posting Exercises
I did not know if I got it right, I just inserted or picked the answers where appropriate and click on Final Check and Save. Please is that all I need to do so as to submit the exercises?
UserIdTAG: 801873
UserNameTAG: atejikay
CreateTimeTAG: 2013-02-27T00:21:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Check grades the question. You will get a green tick or red cross. If you are allowed more than one submission, you can try again. But don't change any answers you got a green tick for!
Save just saves your answer, without grading. So you can go away, think about it, come back and submit for grading.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-27T01:07:46Z
FirstChildVoteTAG: 0
IndexTAG: 2255
TitleTAG: additional literature
I've had pleasure to study statistics in my native language, therefore I only know one english book -> Aczel's "Complete Business Statistics". I heard that it's standard in higher education. Please let me know is it useful in this course, what do you think about this book. Is content modern? It will be pleasure for me to hear what's the most popular literature in this topic in the USA.
UserIdTAG: 1083985
UserNameTAG: noneA
CreateTimeTAG: 2013-02-27T00:08:36Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thanks for your suggestion. I'll check out this book as well. I love the online text supplied for this course, I just need additional practice problems since this is my first statistics class.
FirstChildUserIdTAG: 1298590
FirstChildUserNameTAG: DancingShiva
FirstChildCreateTimeTAG: 2013-02-27T01:25:52Z
FirstChildVoteTAG: 0
IndexTAG: 2256
TitleTAG: suggestion for class interval
how do you decide for a class interval?
UserIdTAG: 1311779
UserNameTAG: maryannevilla
CreateTimeTAG: 2013-02-26T23:55:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: In the lecture I recall it being called a "Black Art." I understand that it depends on the comparison that you want to observe under the requirement that they are stratified with sufficient samples in each class for the histogram to be useful. So there are multiple right and wrong ways to make a histogram.
FirstChildUserIdTAG: 920755
FirstChildUserNameTAG: hamptonjj
FirstChildCreateTimeTAG: 2013-02-27T02:19:34Z
FirstChildVoteTAG: 0
IndexTAG: 2257
TitleTAG: Course Material One week in Advance?
Is there any possibility of having course material available for more than a week in advance? It would be beneficial to have a larger window of opportunity to work on material, especially when I anticipate that problems will become challenging.
I imagine most online students fall into the category of "non traditional" students, who could benefit from that flexibility.
Please note - I am not asking for a change of due dates. I think it would help to allow us to complete an additional week ahead of time. Sort of an educational time-buffer, if you will.
UserIdTAG: 40598
UserNameTAG: jstarkey
CreateTimeTAG: 2013-02-26T23:46:03Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: This is a new course. So maybe materials aren't available in advance. They could still be preparing them.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T23:59:39Z
FirstChildVoteTAG: 1
FirstChildTAG: ChristineStv is right, and also partly I would prefer to release one week at a time as that allows me to take into account issues raised by students (both logistical and statistical) in past weeks. As this is a first-time course, we only have educated guesses about what will work with our students, rather than specific knowledge. So I would prefer not to present "canned" material far in advance.
So I guess it's me using the time buffer to make changes as needed to reduce potentially large numbers of student queries.
I realize that's not a satisfactory answer for you, and I'm sorry, but it's the balance that I must strike. I'll post some reference materials for those who want to "read ahead." Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-27T00:31:54Z
FirstChildVoteTAG: 3
SecondChildTAG: Hey, as I've said before - I can't really complain about FREE :) Thanks for the prompt reply!
SecondChildUserIdTAG: 40598
SecondChildUserNameTAG: jstarkey
SecondChildCreateTimeTAG: 2013-02-27T02:06:34Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks, been wondering whether it was possible, but apparently not.
Keep up the great work though - looking forward to Stat2.2x!
SecondChildUserIdTAG: 229679
SecondChildUserNameTAG: Ahsen
SecondChildCreateTimeTAG: 2013-02-27T15:45:23Z
SecondChildVoteTAG: 0
IndexTAG: 2258
TitleTAG: Class intervals..
Surely the width of -20 to 10 is 30...not 10?
UserIdTAG: 1317628
UserNameTAG: sampatankar
CreateTimeTAG: 2013-02-26T23:34:58Z
VoteTAG: 11
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Surely you read the other posts in the subforum to see if anyone else had commented?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T23:56:25Z
FirstChildVoteTAG: 4
SecondChildTAG: Where can I find that forum?
SecondChildUserIdTAG: 928962
SecondChildUserNameTAG: DianaMarcela
SecondChildCreateTimeTAG: 2013-02-27T00:17:36Z
SecondChildVoteTAG: 0
SecondChildTAG: there are discussion links at the bottom of every question page and every lecture page. you should use the forum on the appropriate page to ask questions - and to look to see if you question has already been asked and answered.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T01:09:11Z
SecondChildVoteTAG: 0
IndexTAG: 2259
TitleTAG: Calculations upto how many decimal points?
With reference to Lecture 1.3 and related exercise, I made percent calculations up to two decimal points and my answers were shown as wrong. The correct answers were shown up to one decimal point. Is it desirable to make calculations up to one decimal fraction only for all exercises? I would like that this should be clarified to all students so that answers are not marked wrong for more or less precise values.
Regards.
Dr. Balraj, India.
UserIdTAG: 229040
UserNameTAG: DrBalraj
CreateTimeTAG: 2013-02-26T23:29:10Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: 3a in problem set 2 says to answer in units, and I thought that meant no decimal parts. I haven't used my second chance yet, so I'd love to know if it is indeed a whole number. I also wonder if we ever get responses from the TA or faculty within a thread.
FirstChildUserIdTAG: 1232482
FirstChildUserNameTAG: bhunji
FirstChildCreateTimeTAG: 2013-02-27T00:18:15Z
FirstChildVoteTAG: 0
SecondChildTAG: I tried putting 4 or 5 decimal places on graded exercises and the system always accepted them as correct... except when they were the wrong answers, lol.
SecondChildUserIdTAG: 920755
SecondChildUserNameTAG: hamptonjj
SecondChildCreateTimeTAG: 2013-02-27T02:22:08Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree to the point raised by Dr. Balraj.
FirstChildUserIdTAG: 987158
FirstChildUserNameTAG: vijaysharma1122
FirstChildCreateTimeTAG: 2013-02-27T01:12:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Exactly the same happened with me: two decimal points; then I changed to no decimal point, but the answer was considered wrong again... This point should be clarified.
SecondChildUserIdTAG: 1072042
SecondChildUserNameTAG: onawa
SecondChildCreateTimeTAG: 2013-02-27T01:47:10Z
SecondChildVoteTAG: 0
FirstChildTAG: Things must have changed since I went to school. I was always told to round to the same decimal as the question. Has this changed? I rounded to whole numbers and it was wrong for some reason they want 1 decimal and I do not understand why.
FirstChildUserIdTAG: 453550
FirstChildUserNameTAG: DebbieSmith
FirstChildCreateTimeTAG: 2013-02-27T03:08:56Z
FirstChildVoteTAG: 0
FirstChildTAG: I had the same problem which I consider a little bit unfair since nobody told us how many decimals. I got 11,11111111 and so. And the system told me wrong, proposing instead only 11,1. Maybe my calcultor was wrong?
FirstChildUserIdTAG: 705507
FirstChildUserNameTAG: EdmundoIZ
FirstChildCreateTimeTAG: 2013-02-27T04:33:02Z
FirstChildVoteTAG: 0
IndexTAG: 2260
TitleTAG: A bit confused...
Did I miss something terribly sophisticated, or was this lecture mostly a guide to using the java applets from the other course's lecture?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-26T23:28:54Z
VoteTAG: 2
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 1
FirstChildTAG: You probably lost patience. Start at about 11:25 into Lec 2.4.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-27T00:45:12Z
FirstChildVoteTAG: 2
IndexTAG: 2261
TitleTAG: 20/20
Finally perfect score
UserIdTAG: 1107978
UserNameTAG: betoagto
CreateTimeTAG: 2013-02-26T23:27:05Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Great job!
FirstChildUserIdTAG: 920755
FirstChildUserNameTAG: hamptonjj
FirstChildCreateTimeTAG: 2013-02-27T02:24:00Z
FirstChildVoteTAG: 0
IndexTAG: 2262
TitleTAG: Box and Plot graphs???
>This exercise test was regarding Histograms, then why were the Box and Plot questions included? The examiners must consider that there are students in the course who have no background of Statistics and who are learning only with the weekly material provided.
>Also i wrote the answer to percentiles along with decimal places. Is it wrong to write the exact percentile with decimals??
UserIdTAG: 918707
UserNameTAG: nishasandeepkumar
CreateTimeTAG: 2013-02-26T23:25:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 3
FirstChildTAG: We expect no statistical knowledge beyond what is in the lectures. That's why the box plot was described in such detail in the exercise.
Please expect Exercise Sets to involve reading descriptions of statistical methods that are based on the concepts that are the main topics of the lectures, and then applying those methods. The box plot is based entirely on percentiles, which were the sole topic of Lectures 2.4 and 2.5.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-27T00:39:07Z
FirstChildVoteTAG: 0
SecondChildTAG: I thought it was a great addition to the exercise set! I had never seen such a graph. It was a good way to apply the concepts learned in the study of histograms and percentiles.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T13:12:55Z
SecondChildVoteTAG: 0
FirstChildTAG: How to accede to lectures 2.4 and 2.5?
FirstChildUserIdTAG: 1291666
FirstChildUserNameTAG: norabram
FirstChildCreateTimeTAG: 2013-02-27T20:34:13Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Professor,
Thanks a lot for replying.
I guess i missed some lectutres.
Its a great course and i am glad to be here exploring Statistics.
Thanks & Regards
FirstChildUserIdTAG: 918707
FirstChildUserNameTAG: nishasandeepkumar
FirstChildCreateTimeTAG: 2013-02-28T18:29:27Z
FirstChildVoteTAG: 0
IndexTAG: 2263
TitleTAG: EXERCISE SET 3 : Box and Plot graphs??
> This exercise test was regarding Histograms, then why were the Box and Plot questions included? The examiners must consider that there are students in the course who have no background of Statistics and who are learning only with the weekly material provided.
> Also i wrote the answer to percentiles along with decimal places.
Is it wrong to write the exact percentile with decimals??
UserIdTAG: 918707
UserNameTAG: nishasandeepkumar
CreateTimeTAG: 2013-02-26T23:19:25Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2264
TitleTAG: Correlation between Practices Sets and Exercise Sets
I don't see much correlation between the what we do in the practices and then what we actually get graded on.
UserIdTAG: 4612
UserNameTAG: Susnaj
CreateTimeTAG: 2013-02-26T23:15:01Z
VoteTAG: 12
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: There is .You need to do a bit of analytical reasoning based on what you read and additional use of couresware to solve the problems.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-27T02:27:56Z
FirstChildVoteTAG: 2
FirstChildTAG: I agree. What can we do.
FirstChildUserIdTAG: 1194804
FirstChildUserNameTAG: myermo1
FirstChildCreateTimeTAG: 2013-02-27T03:09:17Z
FirstChildVoteTAG: 0
FirstChildTAG: NO CORRELATION
FirstChildUserIdTAG: 938670
FirstChildUserNameTAG: JeffVirginia
FirstChildCreateTimeTAG: 2013-02-28T03:39:45Z
FirstChildVoteTAG: 0
IndexTAG: 2265
TitleTAG: week one done
Week one exercises done... I'm actually surprised! I've never done any statistics before... I don't like maths either LOL But I decided to give it a try... and so far the only errors came from me rushing to do exercises without reading carefully explanations... wow... to all of you that created this course... WELL DONE!
UserIdTAG: 905926
UserNameTAG: MarcinJ77
CreateTimeTAG: 2013-02-26T23:12:08Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2266
TitleTAG: Exercise set 3 problem 1
not sure exactly what they are looking for the quartile of the age groups and how would I put them in order somebody please eplain
UserIdTAG: 1101106
UserNameTAG: Sheldon1982
CreateTimeTAG: 2013-02-26T23:07:32Z
VoteTAG: 1
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 0
IndexTAG: 2267
TitleTAG: Percent/ student
Please do include if we need to submit with the '%' / 'student' unit as a requirement. Furthermore, please also state the number of decimal point required.
Many thanks.
UserIdTAG: 946512
UserNameTAG: nicoleha
CreateTimeTAG: 2013-02-26T23:03:41Z
VoteTAG: 9
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2268
TitleTAG: applets
Hello,
I can't see any of apllets in textbook. I can't see the histogram. I've tried to open the textbook in mozzila, google chrome and internet explorer and nothing. It doesn't work. Please help me. I'll be really grateful,
Best,
DP
UserIdTAG: 943583
UserNameTAG: Dorota23
CreateTimeTAG: 2013-02-26T23:01:17Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Try Firefox. And make sure Java is enabled.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T23:21:12Z
FirstChildVoteTAG: 1
SecondChildTAG: Oh, so it is in Java… well, the textbook certainly could have some replacement text saying that!
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-27T23:15:49Z
SecondChildVoteTAG: 0
SecondChildTAG: This worked for me! The applets in the online textbook didn't work in chromium/chrome, but they appear in Firefox.
SecondChildUserIdTAG: 267644
SecondChildUserNameTAG: gojun077
SecondChildCreateTimeTAG: 2013-02-28T05:40:51Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you for your advice, but unfortunatelly it still doesn't work... Does anybody know how to solve this problem?
DP
FirstChildUserIdTAG: 943583
FirstChildUserNameTAG: Dorota23
FirstChildCreateTimeTAG: 2013-02-27T09:07:31Z
FirstChildVoteTAG: 1
IndexTAG: 2269
TitleTAG: starting
Great voice! now it seems that we're gonna make it!
UserIdTAG: 689072
UserNameTAG: pato54
CreateTimeTAG: 2013-02-26T22:46:35Z
VoteTAG: 1
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 0
IndexTAG: 2270
TitleTAG: problem in submitting answers
I have a problem in checking and saving my answers, the program does not respond in exercise 1 and 2 , so what can I do?
UserIdTAG: 1214628
UserNameTAG: Madani1973
CreateTimeTAG: 2013-02-26T22:28:27Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Try refreshing the page. Or you might need to change browsers. Either Firefox or Chrome, depending on what you are already using.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T22:29:20Z
FirstChildVoteTAG: 0
SecondChildTAG: I found that it wasn't working for IE, but switching to Firefox worked.
SecondChildUserIdTAG: 1311471
SecondChildUserNameTAG: kdeppe
SecondChildCreateTimeTAG: 2013-02-27T01:12:41Z
SecondChildVoteTAG: 0
FirstChildTAG: I am also having a proglem logging in to do the assignments. I've entered my name and email address. Do I need a student ID? Clicking on the link for the first assignment "Have you read the syllabus" doesn't seem to work.
FirstChildUserIdTAG: 913981
FirstChildUserNameTAG: DSamuel
FirstChildCreateTimeTAG: 2013-02-26T22:49:45Z
FirstChildVoteTAG: 0
FirstChildTAG: > I am also having a proglem logging in to do the assignments
The text book assignments are *not* the course assignments. Our problems are in the Courseware section, indicated by the blue alarm clock icon.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T22:54:33Z
FirstChildVoteTAG: 0
IndexTAG: 2271
TitleTAG: What is the correct order of studying the materials and where are they exactly?
Hi everyone,
started late due to circumstances and trying to catch up with things. Find the layout a bit confusing and counter-intuitive - can you please help?
1. What is the correct order of reading and/or listening to lectures? I found a link which starts with lecture 2 or 3 - do we need to go down the page, find the menu and go back to lecture 1?
Are we expected to listen to all the video lectures in that "bottom of the page"
menu?
2. The second audio lecture by our professor starts as if some things have been explained BETWEEN the Introduction audio lecture and this second one. What am I missing? Is it hiding somewhere?
3. All in all, what is THE main reading or listening material?
I would be grateful for some help.
UserIdTAG: 990364
UserNameTAG: Oksana1511
CreateTimeTAG: 2013-02-26T22:20:18Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: > What is the correct order of reading and/or listening to lectures?
Start with the first and listen in order. I found this post describing the layout:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5129096f872f381f00000093
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T22:27:24Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you for that, ChristineStv.
I am still confused, though. :-(
I see the lecture "Introduction".
Then the next one I see is Lecture 2.1
Where is the lecture 1.3 that is mentioned somewhere later on (in Histograms, I think?)
Also, my main question is, for First set of exercises, there are questions in there which are NOT covered in Introduction Lecture - f.ex., quantitative, discreet variables, etc) - where were we supposed to read or listen to all this info?
Where do I study the material prior to doing the exercises?
Please help!
FirstChildUserIdTAG: 990364
FirstChildUserNameTAG: Oksana1511
FirstChildCreateTimeTAG: 2013-02-26T22:44:43Z
FirstChildVoteTAG: 0
SecondChildTAG: Hello. Try the Courseware tab. Then select the week Feb 20 -Feb 26 (near the bottom). There is the Introdution and then the study material. There are 3 Excercises that are due Feb 27th. They were due on different days this week, but it was changed. I hope this helps.
SecondChildUserIdTAG: 1109918
SecondChildUserNameTAG: Richards1
SecondChildCreateTimeTAG: 2013-02-27T05:37:49Z
SecondChildVoteTAG: 0
FirstChildTAG: > Where do I study the material prior to doing the exercises?
you watch the videos. you do the practice exercises, and read the linked sections of the text book for more info (linked on the practice exercises).
>Where is the lecture 1.3 that is mentioned somewhere later on (in Histograms, I think?)
The Introduction has 3 lectures. The icons along the filmstrip link to them (the last image on the link I posted shows the filmstrip with L1, L2, L3 indicated)
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T22:53:24Z
FirstChildVoteTAG: 0
SecondChildTAG: Right, I see. Thank you! I thought I was going potty and did not see L 1.2 and 1.3, only saw Introduction.
Will have a look - thanks for your help, Christine.
SecondChildUserIdTAG: 990364
SecondChildUserNameTAG: Oksana1511
SecondChildCreateTimeTAG: 2013-02-26T22:58:57Z
SecondChildVoteTAG: 0
IndexTAG: 2272
TitleTAG: Additional Textbook for this course
Could one of the professors or participants please provide the name of a textbook that can be used in addition to the online text to study for this course. Thanks.
UserIdTAG: 1298590
UserNameTAG: DancingShiva
CreateTimeTAG: 2013-02-26T22:16:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: http://books.wwnorton.com/books/detail.aspx?ID=11597
It's pricey, I can't afford it at this moment, but I've read very good reviews as a classic textbook for statistics without heavy math.
I have two Wilcox's works in my bookshelf. Among them, I find http://www.oup.com/us/catalog/general/subject/Mathematics/ProbabilityStatistics/~~/dmlldz11c2EmY2k9OTc4MDE5NTMxNTEwMw== a good intro book, with some glimpses to modern methods.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-26T22:53:25Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you very much for your suggestions. I'll definitely purchase at least one of these books.
SecondChildUserIdTAG: 1298590
SecondChildUserNameTAG: DancingShiva
SecondChildCreateTimeTAG: 2013-02-27T00:55:10Z
SecondChildVoteTAG: 0
FirstChildTAG: The Friedman,Pisani, Purves textbook is available in an international edition and is not so expensive compared to the original one.It is INP (Rs) 495 in India which comes to less than 10$
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T03:23:48Z
FirstChildVoteTAG: 0
FirstChildTAG: I got the Friedman,Pisani and Purves book.It is available in India for Rs 495.You can order it online at
https://sapnaonline.com/statistics-119082
It is the Student edition to be sold in the Indian subcontinent as per the cover so is cheap here.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-03-03T06:42:18Z
FirstChildVoteTAG: 0
IndexTAG: 2273
TitleTAG: EX.3. problem 3. part b
Dear Professor
Thank you so much to this nice course, I m refreshing what I knew in my BSc and some more knowledge.
By the way I couldn't find the compatible histogram in Ex. Set 2, problem 3, part b. in the problem there are 6 intervals but in the two graphs there are just five, and not compatible with the Intervals, so I chose "A" but I knew it wasn't the correct answer though. I will be so thankful if you would answer after the grading time end.
Best regards
UserIdTAG: 1259656
UserNameTAG: tarannomkhak
CreateTimeTAG: 2013-02-26T22:15:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2274
TitleTAG: Exercise set 3, Problem 2
Hey guys. I just tried exercise set 3 and had no problem with Problem 1. But then I tried Problem 2 and what I did is, I took all the parts of the stem and leaf plot and wrote a list in the right order, with 28 entries. But my answers were all wrong... Can someone explain this to me? Thanks for you help!
UserIdTAG: 1275617
UserNameTAG: SarahLie
CreateTimeTAG: 2013-02-26T22:13:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 4
FirstChildTAG: Did you use the method as described on the video?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T22:25:28Z
FirstChildVoteTAG: 0
SecondChildTAG: yes I did, at least I thought I did...
SecondChildUserIdTAG: 1275617
SecondChildUserNameTAG: SarahLie
SecondChildCreateTimeTAG: 2013-02-26T22:30:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Did you follow the example on the lecture?
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec2.5.pdf
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T22:38:05Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes this is exactly what I did. I mean there was no example of retrieving the data from a stem and leaf plot but I made a list in the right order from 4.8 to 10.0 with 28 entries and did as described in the lecture :/
SecondChildUserIdTAG: 1275617
SecondChildUserNameTAG: SarahLie
SecondChildCreateTimeTAG: 2013-02-26T22:56:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Ah. No, the number is 48, not 4.8. There are no decimals at all,they are all integers.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-26T22:58:26Z
SecondChildVoteTAG: 0
SecondChildTAG: So they go from 48 to 100
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-26T22:58:46Z
SecondChildVoteTAG: 0
SecondChildTAG: oh, okay, so that was my mistake then! Thank you so much Christine !
SecondChildUserIdTAG: 1275617
SecondChildUserNameTAG: SarahLie
SecondChildCreateTimeTAG: 2013-02-26T23:00:40Z
SecondChildVoteTAG: 0
FirstChildTAG: I did the same, but answered the exact percentile with decimal places..and it came wrong.. Can someone answer why??
FirstChildUserIdTAG: 918707
FirstChildUserNameTAG: nishasandeepkumar
FirstChildCreateTimeTAG: 2013-02-26T23:22:07Z
FirstChildVoteTAG: 0
SecondChildTAG: If you had decimals, then you are not using the correct method.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T00:00:33Z
SecondChildVoteTAG: 0
FirstChildTAG: The exercise set uses "greater than or equal" definition of percentile, not "greater than" that the book uses. So first number is 3.5%ile and the last is 100%ile.
See this discussion: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Section2b_Lec_2_5/threads/512c81b867cc5f1f00000137
Answer should be an integer (don't interpolate).
FirstChildUserIdTAG: 1080056
FirstChildUserNameTAG: alexd457
FirstChildCreateTimeTAG: 2013-02-27T15:38:41Z
FirstChildVoteTAG: 0
IndexTAG: 2275
TitleTAG: That was am experience..
Done!
UserIdTAG: 1317628
UserNameTAG: sampatankar
CreateTimeTAG: 2013-02-26T22:13:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: omg - I just started started the course today - i've still got the last one to watch and do! It will have to wait til tomorrow - I'm shattered!
FirstChildUserIdTAG: 900898
FirstChildUserNameTAG: Jameelah
FirstChildCreateTimeTAG: 2013-02-26T22:50:51Z
FirstChildVoteTAG: 0
IndexTAG: 2276
TitleTAG: problem 2.b
Ummm. have selected options a & b by mistake for Q 2.b. could have done better for others too. is it final test?
UserIdTAG: 1261388
UserNameTAG: PadmaUpp
CreateTimeTAG: 2013-02-26T22:06:32Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2277
TitleTAG: Problem with exercise 1.3
I clicked by mistake before doing it so it gave me wrong in both... Is there anyway to uncheck it???
:-(
UserIdTAG: 1014297
UserNameTAG: segurajuanj
CreateTimeTAG: 2013-02-26T21:55:53Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: hahaha no
FirstChildUserIdTAG: 1221332
FirstChildUserNameTAG: ahsanmemon
FirstChildCreateTimeTAG: 2013-02-26T22:06:34Z
FirstChildVoteTAG: 0
SecondChildTAG: lol
SecondChildUserIdTAG: 1221332
SecondChildUserNameTAG: ahsanmemon
SecondChildCreateTimeTAG: 2013-02-26T22:06:41Z
SecondChildVoteTAG: 0
IndexTAG: 2278
TitleTAG: Changing due dates hurt me......
I would like to request a second opportunity on Exercise Set 1 & Exercise Set 2. When the original due dates were Feb. 22 & Feb 25 I rushed through to complete the exercises to meet the deadlines without fully viewing the video portion. When due date was pushed back to Feb 27th I was not able to have this time and could have done better (horrible scores achieved), I was afraid of getting zero's for missing deadline....
UserIdTAG: 1028974
UserNameTAG: RobertArthurs
CreateTimeTAG: 2013-02-26T21:53:58Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Best Of luck
FirstChildUserIdTAG: 1221332
FirstChildUserNameTAG: ahsanmemon
FirstChildCreateTimeTAG: 2013-02-26T22:07:17Z
FirstChildVoteTAG: 0
FirstChildTAG: With the passing grade of 35% for the course, you should be fine if you do well in other assignments. Good luck in this course.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-02-27T00:54:51Z
FirstChildVoteTAG: 0
IndexTAG: 2279
TitleTAG: Isn't income Quantitative?
Unless its assumed you can receive an infinitely small fraction of a dollar, I believe it should be.
UserIdTAG: 955096
UserNameTAG: yoav_v
CreateTimeTAG: 2013-02-26T21:43:24Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Read some of the dozens of posts about this question.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:46:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Kind of like tour attitude, I mean it!
SecondChildUserIdTAG: 26776
SecondChildUserNameTAG: aleguillen
SecondChildCreateTimeTAG: 2013-02-26T21:49:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks. Your directive assistance is much of help.
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-03-19T05:46:09Z
SecondChildVoteTAG: 0
FirstChildTAG: And if you take into account Planck length, in theory the shortest measurable length, then measurements too are actually quantitative. Crazy, huh? No.
What does this mean? Get real. You're arguing about minuscule amounts nobody cares about. Yes, nobody will probably ever have to deal with 0.0000000000000000000001 dollars, but **for all intents and purposes, income is quantitative**.
FirstChildUserIdTAG: 438931
FirstChildUserNameTAG: pavemina
FirstChildCreateTimeTAG: 2013-02-26T22:08:05Z
FirstChildVoteTAG: 0
SecondChildTAG: You can find this info on the intro at the top there is a url - with a lecture, and charts that show which category they are in. .. Planck length reminds me of the math I learned in Pro. Cima's Stolid State Chem. Class. I hope we don't have to do that sort of math in this class - That wore me out. ( I learned a lot tho) I guess this makes it obvious that I'm not an MIT math wiz=)
SecondChildUserIdTAG: 247732
SecondChildUserNameTAG: Snazzy2
SecondChildCreateTimeTAG: 2013-02-26T22:48:49Z
SecondChildVoteTAG: 0
FirstChildTAG: Can anyone explain to me why income should be quantitative rather than quantitative discrete? Money comes in fixed intervals of dollars and cents, right? There's no such thing as making 2002.43948392 dollars per month...
FirstChildUserIdTAG: 1025842
FirstChildUserNameTAG: mspijksma
FirstChildCreateTimeTAG: 2013-02-26T23:31:08Z
FirstChildVoteTAG: 0
IndexTAG: 2280
TitleTAG: not intuitive...
I didn't know i needed to listen to all the lectures to complete exercise set 2... plus i'm still not certain how to access the online text book...
UserIdTAG: 1030944
UserNameTAG: jeniannmay
CreateTimeTAG: 2013-02-26T21:39:43Z
VoteTAG: 2
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 2
FirstChildTAG: > I didn't know i needed to listen to all the lectures to complete exercise set 2
Of course you need to listen to the lectures on the Courseware page.
> plus i'm still not certain how to access the online text book...
There are links to this book on the course policy page, on the practice exercise pages. Lots of links in lots of places.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:45:45Z
FirstChildVoteTAG: 1
SecondChildTAG: "Of course you need to listen to the lectures on the Courseware page."
I think you missed her point. It's not that she eventually has to listen to all of the lectures, it's that this lecture deals specifically with questions that were in the exercises that came BEFORE it.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-02-27T20:36:52Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with that. I will watch the lectures first and then attempt the exercises.
SecondChildUserIdTAG: 1206104
SecondChildUserNameTAG: Lupita_amancio
SecondChildCreateTimeTAG: 2013-02-28T05:07:51Z
SecondChildVoteTAG: 0
FirstChildTAG: True, this is not a user friendly interface. With all of the experience implied by the promotion of this courseware, I would expect a clearer outline of our study path, or perhaps a forced path for the students to follow. For now, I just open all links in new pages to determine their usefulness. If they appear to be part of the course path, I leave them open for reference as I find my way through the material.
FirstChildUserIdTAG: 909175
FirstChildUserNameTAG: GeorgeJetson
FirstChildCreateTimeTAG: 2013-02-27T17:17:13Z
FirstChildVoteTAG: 0
IndexTAG: 2281
TitleTAG: One or many?
In Problem 2 part b we ask: Which of the following bar graphs are derived from the data above? Select all that are correct. So I check multiple correct answers and I'm good.
In Problem 3 part b we ask: Which is the correct bar graph? So I check one answer, even though I noticed there were 2 correct answers because I thought I was supposed to just check 1!
Next time I will try to be less literal, especially when confronted with multiple answers. How about "Which are the correct bar graphs, if any?" if you really want to get people frustrated.
UserIdTAG: 994938
UserNameTAG: keithlhatfield
CreateTimeTAG: 2013-02-26T21:37:13Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: > n Problem 3 part b we ask: Which is the correct bar graph? So I check one answer, even though I noticed there were 2 correct answers
Look again. There is only one correct bar graph in the last question.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:44:04Z
FirstChildVoteTAG: 0
IndexTAG: 2282
TitleTAG: Exercise set 3: question
Hey guys.
I just tried exercise set 3 and had no problem with Problem 1. But then I tried Problem 2 and what I did is, I took all the parts of the stem and leaf plot and wrote a list in the right order, with 28 entries. But my answers were all wrong... Can someone explain this to me?
Thanks for you help!
UserIdTAG: 1275617
UserNameTAG: SarahLie
CreateTimeTAG: 2013-02-26T21:35:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: so did I.quite frustrating.i dont know what i missed.
FirstChildUserIdTAG: 773306
FirstChildUserNameTAG: naason
FirstChildCreateTimeTAG: 2013-02-26T22:26:12Z
FirstChildVoteTAG: 0
IndexTAG: 2283
TitleTAG: Technical Problem with Problem Nr. 5
I checked my answers in problem nr. 4 and the program set the answer in problem nr. 5 automatically wrong. Has somebody the same problem?
UserIdTAG: 975223
UserNameTAG: Ludwig12
CreateTimeTAG: 2013-02-26T21:34:39Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I got the same thing. I thought I hit the wrong button. I'm bumming as problem 5 is worth 5 points.
FirstChildUserIdTAG: 411079
FirstChildUserNameTAG: CliffD
FirstChildCreateTimeTAG: 2013-02-27T01:54:08Z
FirstChildVoteTAG: 1
SecondChildTAG: I got the same technical issue in problem #4. I answered 4a, then b, then c, then hit check, and then I found that the program changed my answer in 4a to the same as 4b automatically, which was obviously incorrect. :-(((
SecondChildUserIdTAG: 709402
SecondChildUserNameTAG: javarda
SecondChildCreateTimeTAG: 2013-02-28T01:11:26Z
SecondChildVoteTAG: 0
IndexTAG: 2284
TitleTAG: Problem 7
Hi
I know the formula etc , obviously being a bit dense can anyone prompt me inot working this out for myself? Would be most grateful. I'm obviously overlooking some vital data.
UserIdTAG: 927476
UserNameTAG: leomas
CreateTimeTAG: 2013-02-26T21:34:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Think about the connections between the values in the table. There are actually three values in play in every row: interval, percentage and hight. You can compute one of these columns for almost every row. You did it for one of them in the previous problem. You should deduce some obvious thing about the percentage column. Based on this deduction, the value of the '?' in the exercise is easy to find.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-26T23:40:46Z
FirstChildVoteTAG: 0
SecondChildTAG: I appreciate the heads up, thanks.
SecondChildUserIdTAG: 927476
SecondChildUserNameTAG: leomas
SecondChildCreateTimeTAG: 2013-02-27T09:09:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Got it first time, huge thanks.
SecondChildUserIdTAG: 927476
SecondChildUserNameTAG: leomas
SecondChildCreateTimeTAG: 2013-02-27T18:30:33Z
SecondChildVoteTAG: 0
IndexTAG: 2285
TitleTAG: Is there a typo on here or what?
For the last problems, where it says "suppose you add 20 green/green plants to the experiment," is that a typo or are you really introducing a new color plant (none of the preexisting color combinations are green/green)? I really am not sure because the rest of the questions don't make sense after that.
UserIdTAG: 1301569
UserNameTAG: rosemary7913
CreateTimeTAG: 2013-02-26T21:23:44Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You are adding another 20 plants, these ones are green/green, to the plants you already had (none of which were green/green). The wording is confusing.
FirstChildUserIdTAG: 1281619
FirstChildUserNameTAG: sfc17
FirstChildCreateTimeTAG: 2013-02-26T21:30:44Z
FirstChildVoteTAG: 1
IndexTAG: 2286
TitleTAG: Ex set 3 is done
Hura!!!! I ve done with this staff !!! All correct from the first shot!)))
UserIdTAG: 1103272
UserNameTAG: Soroka1
CreateTimeTAG: 2013-02-26T21:19:19Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: Bravo!!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T21:28:00Z
FirstChildVoteTAG: 0
FirstChildTAG: Could you explain me how you did problem 2? :)
FirstChildUserIdTAG: 1275617
FirstChildUserNameTAG: SarahLie
FirstChildCreateTimeTAG: 2013-02-26T22:08:56Z
FirstChildVoteTAG: 0
FirstChildTAG: exercise set 3 problem 2: Should we rount it off to whole numbers? I checked my answers(whole numbers) and they were wrong.
FirstChildUserIdTAG: 773306
FirstChildUserNameTAG: naason
FirstChildCreateTimeTAG: 2013-02-26T22:29:16Z
FirstChildVoteTAG: 0
SecondChildTAG: You should follow the example on the video lecture. You are taking the data value that is the "smallest number that is at least as large as p% of the list."
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec2.5.pdf
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-26T22:36:16Z
SecondChildVoteTAG: 0
FirstChildTAG: It was the first Exercise Set in which I got 100%...
FirstChildUserIdTAG: 210054
FirstChildUserNameTAG: Ank_S
FirstChildCreateTimeTAG: 2013-02-27T12:52:43Z
FirstChildVoteTAG: 0
IndexTAG: 2287
TitleTAG: how to round?
round up, down or if over 0.5 round up and if under 0.5 round down
so 7.66 is 7.6 or 7.7?
UserIdTAG: 1054707
UserNameTAG: btingu
CreateTimeTAG: 2013-02-26T21:08:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: That would be a 7.7 :)
FirstChildUserIdTAG: 1275617
FirstChildUserNameTAG: SarahLie
FirstChildCreateTimeTAG: 2013-02-26T21:32:19Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes. 7.7 indeed
SecondChildUserIdTAG: 1194804
SecondChildUserNameTAG: myermo1
SecondChildCreateTimeTAG: 2013-02-27T03:10:52Z
SecondChildVoteTAG: 0
FirstChildTAG: it's 7.7
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-02-27T06:15:49Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, thanks for your help, I have been arguing with myself for over an hour about this not wanting to get it wrong!
SecondChildUserIdTAG: 1115165
SecondChildUserNameTAG: Abbyjohnson
SecondChildCreateTimeTAG: 2013-02-27T20:38:07Z
SecondChildVoteTAG: 0
IndexTAG: 2288
TitleTAG: Question:
In the link for lecture 1.2, it separates qualitative with categorical. From the lecture, I thought they were the same, and I cant figure out what's the difference from the site. Does anyone know? Thanks!
UserIdTAG: 484877
UserNameTAG: Andre97
CreateTimeTAG: 2013-02-26T21:06:27Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2289
TitleTAG: Seriously...
Who's favorite color is mauve?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-26T20:53:59Z
VoteTAG: 1
CoursewareTAG: Section 1: Introduction / Lec 1.3. Bar graphs: describing categorical data
NumberOfReplyTAG: 1
FirstChildTAG: lol i don't even know what mauve is
FirstChildUserIdTAG: 838733
FirstChildUserNameTAG: Ronnicus
FirstChildCreateTimeTAG: 2013-03-05T06:02:07Z
FirstChildVoteTAG: 0
IndexTAG: 2290
TitleTAG: How to know if one has finished week 1?
I think I read and completed 1st weeks mission. But how can I check that to be 100% sure?
I found the answer myself. You can find your progress here:
[Progress][1]
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/progress
UserIdTAG: 1041942
UserNameTAG: JohanLinden
CreateTimeTAG: 2013-02-26T20:50:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If the progress tab shows the scores for the 3 set of exercises then you are done. We have to wait for the second week, I´m guessing tomorrow or the day after.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-26T20:54:14Z
FirstChildVoteTAG: 0
IndexTAG: 2291
TitleTAG: second opportunity please
Please give me a second opportunity to do the Problem one in this exercise. I made a blunder, despite knowing the methods and logic.
UserIdTAG: 966764
UserNameTAG: profanilc
CreateTimeTAG: 2013-02-26T20:42:39Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2292
TitleTAG: Tricky Questions :)
Scored 60% in this first set. I liked the tricky part in Problem 2 & 3. Hated problem 1 to be worth 5 marks mostly for cramming part.
UserIdTAG: 841834
UserNameTAG: Kushal4698
CreateTimeTAG: 2013-02-26T20:40:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2293
TitleTAG: OMG
I have made a blunder. I used a wrong dataset for the Problem 1. please be careful if you are working with other things and doing the course.
UserIdTAG: 966764
UserNameTAG: profanilc
CreateTimeTAG: 2013-02-26T20:40:37Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2294
TitleTAG: TO FIND THE INCOME DATA SET...
click on the "Lecture 2.4 Slides" below the starting window for the lecture.
UserIdTAG: 559760
UserNameTAG: arnie_z
CreateTimeTAG: 2013-02-26T20:17:23Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: Found it - thankyou so much ANN
FirstChildUserIdTAG: 1209211
FirstChildUserNameTAG: Ann3067
FirstChildCreateTimeTAG: 2013-02-26T21:12:49Z
FirstChildVoteTAG: 0
IndexTAG: 2295
TitleTAG: Number formats expected
It would be beneficial to be clear about the number format and precision required here.
UserIdTAG: 1154427
UserNameTAG: AngieT
CreateTimeTAG: 2013-02-26T20:17:15Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I agree. I got number 3 wrong, because I put xx.xxx when they wanted xx.x
(I don't want to post the answer)
FirstChildUserIdTAG: 484877
FirstChildUserNameTAG: Andre97
FirstChildCreateTimeTAG: 2013-02-26T21:13:12Z
FirstChildVoteTAG: 0
IndexTAG: 2296
TitleTAG: Would like to see more visual than verbal in requests for formats
For question #2: I did not receive correct answers because I rounded off my answer, not having read clearly that you wanted it rounded off to 2 decimals.
It would have been better if the question read, "..round the answer off to two decimal points (example: 22.66, 10.50, 13.75)."
This means that instead of being tested on the content I was tested for how well I read the question, yet I am being graded as if I didn't know the content. Sorry for sounding negative, but that is one dubious aspect of online learning that I despise.
I hope you will consider this point when writing test questions in the future. :)
UserIdTAG: 963897
UserNameTAG: lightbulb
CreateTimeTAG: 2013-02-26T20:15:53Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2297
TitleTAG: Stem and Leaf and H/Grams in Excel
Does anyone have a easy way to put either of these in excel, I have found some very long winded ways, but would appreciate a simpler method
UserIdTAG: 7545
UserNameTAG: jasontimothyjones
CreateTimeTAG: 2013-02-26T19:53:18Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: use python instead
FirstChildUserIdTAG: 716613
FirstChildUserNameTAG: Emjiz
FirstChildCreateTimeTAG: 2013-02-26T20:06:28Z
FirstChildVoteTAG: 0
SecondChildTAG: :)
I was thinking the same, as I just have finished the MIT 6.0x course. Will probably try my hand at using Python to solve some of the problems in this course.
SecondChildUserIdTAG: 511105
SecondChildUserNameTAG: FrankTR
SecondChildCreateTimeTAG: 2013-02-26T20:51:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I wish I had the time to learn python :)
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-02-26T21:44:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Excel has a free add on analysis pack that includes histograms
http://support.microsoft.com/kb/214269
best
drew
SecondChildUserIdTAG: 1080353
SecondChildUserNameTAG: drew_g
SecondChildCreateTimeTAG: 2013-02-27T14:27:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Analize-it & XLSTAT 30 days evaluation versions. I prefer to learn how to calculate and make them even by hand rather than use those though.
FirstChildUserIdTAG: 1239975
FirstChildUserNameTAG: Xenofon
FirstChildCreateTimeTAG: 2013-02-26T22:46:16Z
FirstChildVoteTAG: 0
IndexTAG: 2298
TitleTAG: Please specify rounding rules
I, like many here, was confused when I was told I got the two percentage problems wrong, as I too had put "11.11%" and "22.22%" and was told I was wrong. Should we always assume we should round to the nearest tenth and not NOT put "%"s in our answers?
UserIdTAG: 651863
UserNameTAG: lauraliz
CreateTimeTAG: 2013-02-26T19:43:55Z
VoteTAG: 14
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2299
TitleTAG: Only 45% completed?
In my progress area, it says that I've only done 45% of the exam, but I've finished it. I counted the points and I know I've done them all. I'm confused. Is anyone else having this problem? I don't want a bad score just because of a technical issue. Thanks a lot!
UserIdTAG: 711458
UserNameTAG: RobbyDeMenezesMontefusco
CreateTimeTAG: 2013-02-26T19:42:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: 45% does not indicate 'completed', but it means 'completed successfully'. So, if 55% of your answers were wrong, then the chart is right. Otherwise, a technical problem OR :- Check, if you have 'final check'ed your answers, otherwise it will not be counted as 'submitted'.
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-02-27T06:19:29Z
FirstChildVoteTAG: 0
IndexTAG: 2300
TitleTAG: Exercise Set 3, Problem 1 - What am I missing?
For this Problem I sorted by Percent, categorized the percentages into quartiles and first entered the Age(Years) reference relative to the quartile as my answer which was wrong for all 3 inputs. I then went back and entered the Percent relative to the quartile and that also was wrong. I can't wait to find out the answers.
UserIdTAG: 1090257
UserNameTAG: BVogen
CreateTimeTAG: 2013-02-26T19:37:28Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Too difficult excercise set 3 problems
FirstChildUserIdTAG: 638753
FirstChildUserNameTAG: ssoniau
FirstChildCreateTimeTAG: 2013-02-26T20:51:01Z
FirstChildVoteTAG: 0
IndexTAG: 2301
TitleTAG: problem 3
icant anderstand
UserIdTAG: 776071
UserNameTAG: phaliaa
CreateTimeTAG: 2013-02-26T19:33:50Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2302
TitleTAG: answer changes to some default
I had selected the correct answer for the 1.c, while I was working for the 1.b, and when I checked the answer for 1.b the answer for 1.c changed to the other option and i have got 5% less. Looks like the answers are to be done in the given order. else the others change to some weird selection of its own. I am now less by 5% that has demoralised me.
UserIdTAG: 966764
UserNameTAG: profanilc
CreateTimeTAG: 2013-02-26T19:24:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I'm sorry to hear that, there have been a lot of technical difficulties, but things are getting better... If it's any consolation, they will remove your two lowest scores.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-26T19:28:12Z
FirstChildVoteTAG: 0
SecondChildTAG: Do not worry, the pass mark is 35% (in general it does not motivate at all)
SecondChildUserIdTAG: 741165
SecondChildUserNameTAG: yared1972
SecondChildCreateTimeTAG: 2013-02-26T19:41:34Z
SecondChildVoteTAG: 0
IndexTAG: 2303
TitleTAG: Solution of practice 2.1 b in RStudio
# Let's copy a right sides of a stem-and-leaf plot into a character vector
Men <- c("56778", "0012234444", "55666788889", "0111234", "56")
# Let's calculate the number of characters in each element
# of the vector and summarize these numbers
sum(nchar(Men))
**R's output:**
[1] 35
![Nchar][1]
[1]: http://savepic.ru/4180338.png
UserIdTAG: 209516
UserNameTAG: Andrey_K
CreateTimeTAG: 2013-02-26T19:17:20Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Hey Andrey, very good that you add R solutions.
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-02-26T20:07:53Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks! :) Calculating numbers of men manually is too boring for me... :)
SecondChildUserIdTAG: 209516
SecondChildUserNameTAG: Andrey_K
SecondChildCreateTimeTAG: 2013-02-26T20:13:02Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks for adding the R solution.
FirstChildUserIdTAG: 1055515
FirstChildUserNameTAG: Eracles
FirstChildCreateTimeTAG: 2013-02-27T05:17:44Z
FirstChildVoteTAG: 0
IndexTAG: 2304
TitleTAG: plotting deviations
if the lowest and maximum ranges of a histogram is given can we plot the histogram as a single bar? or if we need to split up bars how to? do we need the values of lower and upper quartiles for that?
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-02-26T19:15:56Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 1
FirstChildTAG: I would think you could pick points along the number line
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-27T00:29:16Z
FirstChildVoteTAG: 0
IndexTAG: 2305
TitleTAG: Ravi
Hi, I hv tried the answers but seems end up with 90% wrong entry..please let me know if anybody completed all correctly..knowing the answers will clear the doubts even if i do not score!!
UserIdTAG: 888729
UserNameTAG: Ravi1976
CreateTimeTAG: 2013-02-26T19:13:15Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I got 90% right in that one, bet there´s a lot of people with 100%.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-26T20:27:59Z
FirstChildVoteTAG: 0
IndexTAG: 2306
TitleTAG: box whisker plot -->Histogram?
How do i convert box whisker plot to a histogram?
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-02-26T19:07:56Z
VoteTAG: 2
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 3
FirstChildTAG: You don't have to, if you really wanted to it wouldn't be 100% accurate because you don't know the exact numbers.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-26T19:12:33Z
FirstChildVoteTAG: 1
FirstChildTAG: Hi thekid, if I´m not wrong, I think that you can perfectly draw a 100% accurate histogram from a box and whiskers data. I hope someone else, with more statistics knowledge, confirms it.
A box plot gives you all the information needed to write the distribution table, calculate densities (heights of bars) and then plot the histogram; the problem in the exercise was that it was hard to read numbers directly from the screen, but using the numbers described for experiment 1 (in the explanation of the interpretation of a box plot) you know the following:
Min: 650
25th percentile: 850
median (50th percentile): 940
75th percentile: 980
Max: 1070
Therefore:
1st interval: 650-850 --> percent(area): 25% & width: 200 --> density: percent/width = 25/200 = 0.125
2nd interval: 850-940 --> percent: 25%, cum %: 50 & width: 90 --> density = 0.277
3rd interval: 940-980 --> percent: 25%, cum %: 75 & width: 40 --> density = 0.625
4th interval: 980-1070 --> percent: 25%, cum %: 100 & width: 90 --> density = 0.277
With this information we can plot the histogram:
x-axis units: speed of light (km/s - 299.000)
y-axis units: percent per speed of light
I hope it makes sense and that what I´ve written is correct.
Have a nice day.
FirstChildUserIdTAG: 491947
FirstChildUserNameTAG: Lamiak
FirstChildCreateTimeTAG: 2013-02-26T20:04:06Z
FirstChildVoteTAG: 1
SecondChildTAG: thank you your reply was very usefuk
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-02-27T13:46:56Z
SecondChildVoteTAG: 0
SecondChildTAG: usefu'l'
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-02-27T14:09:39Z
SecondChildVoteTAG: 0
SecondChildTAG: sorry typographic mistake
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-02-27T14:09:57Z
SecondChildVoteTAG: 0
FirstChildTAG: It's a good traditional way of summarizing lots of histograms.
Have you checked though how box plot behaves in a double peak histogram or to other "inflections" of a bell shaped or skewed shaped distr. curves?
That would be a good topic to discuss ,I suppose.
FirstChildUserIdTAG: 1239975
FirstChildUserNameTAG: Xenofon
FirstChildCreateTimeTAG: 2013-02-26T23:02:27Z
FirstChildVoteTAG: 1
IndexTAG: 2307
TitleTAG: Exercise set 2 Problem7
What is correct answer to problem no. 7?
UserIdTAG: 1294730
UserNameTAG: shubhankari
CreateTimeTAG: 2013-02-26T19:06:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: You will have to wait until Thursday I believe.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-26T19:09:08Z
FirstChildVoteTAG: 1
SecondChildTAG: Possibly 8.8 if I did it right.
SecondChildUserIdTAG: 1194804
SecondChildUserNameTAG: myermo1
SecondChildCreateTimeTAG: 2013-02-27T03:12:10Z
SecondChildVoteTAG: 0
SecondChildTAG: No. That's wrong
SecondChildUserIdTAG: 1194804
SecondChildUserNameTAG: myermo1
SecondChildCreateTimeTAG: 2013-02-27T03:16:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Be sure that you understand that the correct entry is height and not the percentage. Then, you will be able to do it easily.
SecondChildUserIdTAG: 1069242
SecondChildUserNameTAG: kdnyanesh
SecondChildCreateTimeTAG: 2013-02-27T06:22:44Z
SecondChildVoteTAG: 0
SecondChildTAG: 4.4 but my answer is wrong, why?
SecondChildUserIdTAG: 1128257
SecondChildUserNameTAG: tanfrioza123
SecondChildCreateTimeTAG: 2013-02-27T06:29:57Z
SecondChildVoteTAG: 0
FirstChildTAG: The answer is: Maths
FirstChildUserIdTAG: 243804
FirstChildUserNameTAG: JanJo
FirstChildCreateTimeTAG: 2013-02-27T01:48:50Z
FirstChildVoteTAG: 1
FirstChildTAG: Be sure that you understand that the correct entry is height and not the percentage. Then, you will be able to do it easily.
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-02-27T06:23:26Z
FirstChildVoteTAG: 0
IndexTAG: 2308
TitleTAG: Ex 3 Last problem
The way the question is posed is misleading. If I am looking at histogram frequency distribution, the whisker can represent a low frequency outlier and NOT the peak. If you are assigning 4 points to such a problem, then you should be more precise.
Regards,
Susant
UserIdTAG: 246991
UserNameTAG: spatra
CreateTimeTAG: 2013-02-26T18:54:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi Susant,
Without giving you the answer here is a hint.
Go back and study both how the boxplot and the histogram works... Especially around how the lower quartile and median are drawn in a boxplot. Think for yourself and you will realise that the proximity of those to each other represent a spike. You have two options is the closer they are a spike or the further away a spike? Once you figure that out you have the answer to the question.
Daniel
FirstChildUserIdTAG: 1181263
FirstChildUserNameTAG: drush
FirstChildCreateTimeTAG: 2013-02-27T02:35:58Z
FirstChildVoteTAG: 0
SecondChildTAG: This was really helpful! Thank you so much, Daniel :)
SecondChildUserIdTAG: 1171764
SecondChildUserNameTAG: SaraEPP
SecondChildCreateTimeTAG: 2013-02-27T22:27:20Z
SecondChildVoteTAG: 0
IndexTAG: 2309
TitleTAG: Lack of continuity?
The second lecture (2.1 in section 2a) starts with "...And finally, a quantitative variable -- after all those reds, blues, and greens, a few numbers."
This was a jarring start. What "reds, blues, and greens" is this referring to? Haven't we been working with quantitative vars in the first exercises? I fear it's indicative of a possible lack of continuity over the course, and is a bit of a warning flag, frankly.
Still, appreciate something for nothing, and I'm sticking with it for now! Just wanted to make sure I'm not missing anything and see if anyone else had thought the same thing.
UserIdTAG: 118792
UserNameTAG: tonyrobots
CreateTimeTAG: 2013-02-26T18:50:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: See Lec 1.3. No quantitative variable was examined in any previous lecture segment, nor in Exercise Set 1; some variables were classified as quantitative, but the only variable that was studied in that set was the color of plants, which is qualitative. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T19:50:30Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Professor. I think my bigger problem (as I just realized), was that I was in face missing something -- I missed the "next" button in the interface below the video lecture, so didn't realize that there were 2 more lectures in the "introductory" sequence. I instead got that material (more or less) from the supplemental "practice" links.
Thanks for the quick response, and for the course!
SecondChildUserIdTAG: 118792
SecondChildUserNameTAG: tonyrobots
SecondChildCreateTimeTAG: 2013-02-26T20:05:02Z
SecondChildVoteTAG: 0
IndexTAG: 2310
TitleTAG: Set 2 exercise 3 - help
Does anybody can help me, please? In my calculations the densities in Set2 Exercise 3 are: 0.5%, 2.33%,30%,8.67%,20%,2.4%. However, I can't find a histogram that is compatible in the heights to those values. Thanks.
UserIdTAG: 1270758
UserNameTAG: leonardolamas
CreateTimeTAG: 2013-02-26T18:45:39Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: Same are my observations
FirstChildUserIdTAG: 1294730
FirstChildUserNameTAG: shubhankari
FirstChildCreateTimeTAG: 2013-02-26T19:13:39Z
FirstChildVoteTAG: 0
SecondChildTAG: yehh true
SecondChildUserIdTAG: 1127915
SecondChildUserNameTAG: HelloFriend
SecondChildCreateTimeTAG: 2013-02-27T09:03:43Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi leonardolamas:
When solving the problem focus more on what variable are you calculating, and how would you plot it, than in the numbers.
Hope that gives you the clue.
FirstChildUserIdTAG: 491947
FirstChildUserNameTAG: Lamiak
FirstChildCreateTimeTAG: 2013-02-26T19:15:35Z
FirstChildVoteTAG: 0
FirstChildTAG: you get 2 tries
so pick the one who's shape seems closest
if it's wrong then pick your 2nd choice
FirstChildUserIdTAG: 373054
FirstChildUserNameTAG: Torchlight2
FirstChildCreateTimeTAG: 2013-02-27T06:58:40Z
FirstChildVoteTAG: 0
FirstChildTAG: I am frustrated too, since there is no correct answer given to this and other questions. It appears that we are the random sample chosen to beta test this material. Please refer to Lamiak's response above, as this should provide enough of a clue to decipher which graph to select.
FirstChildUserIdTAG: 909175
FirstChildUserNameTAG: GeorgeJetson
FirstChildCreateTimeTAG: 2013-02-27T14:35:39Z
FirstChildVoteTAG: 0
IndexTAG: 2311
TitleTAG: To The Professor
I just found this page and this course, I have some very basic experience in statistics so will try to learn in 1 day what takes a week, there is any change that if tomorrow i will be not able to send all the exercises for the week, you could give me some more days?
Regards.
UserIdTAG: 1316389
UserNameTAG: camavego
CreateTimeTAG: 2013-02-26T18:34:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No, sorry; but we drop the two lowest scores, and threshold for getting the certificate is 35%. You'll be fine. Welcome to the course.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T19:15:24Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you.
SecondChildUserIdTAG: 1316389
SecondChildUserNameTAG: camavego
SecondChildCreateTimeTAG: 2013-02-26T20:11:08Z
SecondChildVoteTAG: 0
IndexTAG: 2312
TitleTAG: Question for the Professors : 50th Percentile and Median
1. In many books the 50th percentile and median are considered the same
whereas we do not consider it necessarily so in our discussions
2. The Median is defined as the middle value or average of two central values(if the number of members of the set is even) whereas for eg in a set of 6 members we consider in this discussion the 3rd member as the median whereas in others it is the $3rd+4th/2$
How are these two differences in interpretations explained ?
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-26T18:24:55Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: 50th percentile = median, in our class and elsewhere.
"The middle value or halfway between two middle values" is what I would call a "definition" rather than a definition. It doesn't extend in any reasonable way to other percentiles, nor to the case where the distribution is a mix of discrete and continuous (yes, these do arise, in probability theory), and so on. I referred to it in lecture because so many people think it's "the" definition, but the definition in the text covers all percentiles, and those who go on to study the theory of probability and statistics more carefully will find that it extends in a natural manner to more complex situations.
Hope that helps. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T19:33:44Z
FirstChildVoteTAG: 2
SecondChildTAG: This raises an important challenge for those of us who use programs like MS Excel for our basic descriptive statistics (mean, median, max, min, etc.). In Excel, I used the 0,2,4,7,7,12 dataset and it calculated the median as 5.5 both when I used the =median([range]) and =percentile([range],0.5).
Do you have a suggestion on how those of us who use such programs should handle this discrepancy? I work with large numbers of datasets and doing these calculations by hand is not an option.
Danelle
SecondChildUserIdTAG: 1082561
SecondChildUserNameTAG: Streams
SecondChildCreateTimeTAG: 2013-02-26T21:50:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the clarification. So in essence the definition we use here will also cover non uniform class intervals compared to the commonly touted average of two middle values and thus is mathematically more precise?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-27T01:43:27Z
SecondChildVoteTAG: 0
FirstChildTAG: > This raises an important challenge for those of us who use programs like MS Excel for our basic descriptive statistics (mean, median, max, min, etc.).
My impression of the course so far, is that we have small data sets so as to work things out by hand. This makes us understand the process. Just getting the computer to spit out an answer doesn't mean that you know how that answer came about.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T22:24:05Z
FirstChildVoteTAG: 0
SecondChildTAG: Christine,
For this course: yes, I am doing this by hand so that I can learn the method. This is a very valid point regarding the use of Excel for assignments.
In 'real life': my employer will not want me to spend 5 hours of my day to determine basic data characteristics of my ecological monitoring data - that is why we have computers in the office. While taking a class for the sake of the knowledge is wonderful for some, I am in a position in which I am taking this class so that I can apply what I learn.
SecondChildUserIdTAG: 1082561
SecondChildUserNameTAG: Streams
SecondChildCreateTimeTAG: 2013-03-05T21:22:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Actually when you know the basis then you can correctly apply the test. In fact of you are not careful the excel calculations may come out wrong if applied inappropriately for eg using SD for sample instead of for a population etc.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-03-06T08:15:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Prasnnasimha is right that the definition of the median in this course is mathematically better in the sense that it is a special case of a more general and consistent definition of percentiles. But Streams is right that many "canned" packages don't compute the median this way.
The good news is that for most large datasets, the two methods are unlikely to produce vastly different answers. Most large datasets don't have lots of repeated values (also known as "ties") nor large gaps between values. So even though you might get different values using the two definitions, they won't be far off.
For datasets with ties and big gaps, the answers can differ noticeably. In such a situation you can use your package to get the "median", but should probably also say something like, "Note that 53% of the data were 108 or less; 6% were equal to 108," if e.g. the reported median is 108. That way the person using your analysis can make an informed judgment.
There's no perfect solution here. That's one of the reasons the average (mean) is used more often than the median. That, at least, is uniquely defined. Stay tuned for Week 2. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-27T02:51:04Z
FirstChildVoteTAG: 3
SecondChildTAG: I realised that I needed this course when Excel and R were giving me different percentiles and I tried to de-code R's explanation of the quantile function! (and yes, it's helping a lot)
SecondChildUserIdTAG: 1193788
SecondChildUserNameTAG: MarianW
SecondChildCreateTimeTAG: 2013-02-27T09:24:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the response!
Danelle
SecondChildUserIdTAG: 1082561
SecondChildUserNameTAG: Streams
SecondChildCreateTimeTAG: 2013-03-05T21:24:06Z
SecondChildVoteTAG: 0
IndexTAG: 2313
TitleTAG: Can somene explain prob. 6 and 7
I dont want to lose my last submision with wrong answer, and even if i do i want to know logic of problem 6 and 7.
Is there someone who done it correctly and know procedure..
UserIdTAG: 1202387
UserNameTAG: Danny1412
CreateTimeTAG: 2013-02-26T18:16:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Helooo! The height of the bar is density or crowdness which means that if you get the percentage of the stutdents in a given interval and divide it by the it´s length you get the corresponding height!
The answers of both are based equaly but will follow two diferents paths just because you´re going to another results .
I hope this is enough. Good luck.
FirstChildUserIdTAG: 1277369
FirstChildUserNameTAG: Ascensor
FirstChildCreateTimeTAG: 2013-02-26T18:42:05Z
FirstChildVoteTAG: 3
SecondChildTAG: I am doing everythng as it was explained but all my answers that involve percentages come out wrong while the rest is correct. What am I doing wrong?
SecondChildUserIdTAG: 1015835
SecondChildUserNameTAG: Aytaj
SecondChildCreateTimeTAG: 2013-02-26T19:22:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Ascensor, your explanation set me on the right track and sincerely helped me to link all of the pieces together. Thank you very much for your helpful post.
SecondChildUserIdTAG: 982787
SecondChildUserNameTAG: annettedonnelly
SecondChildCreateTimeTAG: 2013-02-26T22:36:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Ascensor THANX a lot. That was great explation, now i get it.
SecondChildUserIdTAG: 1202387
SecondChildUserNameTAG: Danny1412
SecondChildCreateTimeTAG: 2013-02-27T00:34:06Z
SecondChildVoteTAG: 0
SecondChildTAG: In fact folks! Ascensor, many thanks for the clever tip you posted. Cheers!!!
SecondChildUserIdTAG: 652456
SecondChildUserNameTAG: NMCFilho
SecondChildCreateTimeTAG: 2013-02-27T02:32:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi, it seems to me that I have done right the same way as it was described by Ascensor, so my lengths for this table were 4-6-5-10, percentages were 10-1-79-10, then I found missed height... it wasn't right. so where was my mistake?
SecondChildUserIdTAG: 892435
SecondChildUserNameTAG: anni2b
SecondChildCreateTimeTAG: 2013-02-27T14:59:18Z
SecondChildVoteTAG: 0
FirstChildTAG: Only realised it was due in today! So everything is fairly rushed and, well, crap. Enjoy
FirstChildUserIdTAG: 1265802
FirstChildUserNameTAG: GMORRIS010
FirstChildCreateTimeTAG: 2013-02-28T12:23:01Z
FirstChildVoteTAG: 0
IndexTAG: 2314
TitleTAG: no histogram is correct
in problem 3 b)
UserIdTAG: 1258339
UserNameTAG: Dondic
CreateTimeTAG: 2013-02-26T18:10:31Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: I think a lot of people missed that one.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-26T19:04:56Z
FirstChildVoteTAG: 1
FirstChildTAG: I agree with you guys, no histogram is correct.....tough I took a chance and got wrong answer....
FirstChildUserIdTAG: 759233
FirstChildUserNameTAG: ARIIDO
FirstChildCreateTimeTAG: 2013-02-26T22:02:09Z
FirstChildVoteTAG: 1
SecondChildTAG: you get 2 tries
so try again
SecondChildUserIdTAG: 373054
SecondChildUserNameTAG: Torchlight2
SecondChildCreateTimeTAG: 2013-02-27T07:00:15Z
SecondChildVoteTAG: 0
FirstChildTAG: well, there are not all intervals included as distinct on horizontal axis. Yet, there is nothing that would give you wrong answer. Firstly, check units. Then, check for the shown intervals etc. Generally, checking the intervals at the ends helps (especially if the distribution is behaving 'normally').
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-02-27T06:27:42Z
FirstChildVoteTAG: 0
IndexTAG: 2315
TitleTAG: STAFF
Is there a bug or some kind of mistake in grading the bar graphs questions? I think it's important to solve this, in case there was a problem, because we students get confused.
UserIdTAG: 663497
UserNameTAG: perlariosv
CreateTimeTAG: 2013-02-26T18:09:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Too late - massive chaos and confusion has already broken out. In some cases, outright indignation, too, followed by a couple of swift (and publicized) exits.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T21:24:00Z
FirstChildVoteTAG: 0
FirstChildTAG: The correct answers for the charts on this page (exercise Set 1) are just that - correct.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:34:54Z
FirstChildVoteTAG: 0
IndexTAG: 2316
TitleTAG: Problem 4c
I feel like this question would be more valuable with a conversation regarding why or why not. I'm interested in understanding why I'm wrong. I had a rationale for the wrong answer, and I can't come up with anything substantial for the other answer.
UserIdTAG: 141717
UserNameTAG: eralon
CreateTimeTAG: 2013-02-26T18:00:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: what meaning would you like to assign to 12.43568708 years of education? (*continuous distribution)
!
FirstChildUserIdTAG: 1069242
FirstChildUserNameTAG: kdnyanesh
FirstChildCreateTimeTAG: 2013-02-27T06:31:53Z
FirstChildVoteTAG: 0
SecondChildTAG: I still think the questions is aiming for discrete distribution
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-02-27T07:00:47Z
SecondChildVoteTAG: 0
IndexTAG: 2317
TitleTAG: spanish
Is it possible that this course is imparted in Spanish?.
I have very basic knowledge of their language.
As are so many students, I think many of us could benefit from this facility.
thank you very much
UserIdTAG: 989938
UserNameTAG: JuanaTM
CreateTimeTAG: 2013-02-26T17:58:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I doubt it, I am not 100% English proficient, but if you need some help, just let me know.
Regards
FirstChildUserIdTAG: 1316389
FirstChildUserNameTAG: camavego
FirstChildCreateTimeTAG: 2013-02-26T18:30:20Z
FirstChildVoteTAG: 0
FirstChildTAG: A requirement of the course is good English comprehension.
There are non-English universities joining edX, but it does come down to the fact that free education does not mean that every language and every ability can be catered to.
You want Spanish. I'm sure the Chinese, Indians, French, etc would like multi-language too.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:32:46Z
FirstChildVoteTAG: 0
FirstChildTAG: Juana, I am not 100% English proficient either, but I can help you if you need. Anyway, I think this course is a good way to practice and improve our English, don't you think? ;-)
FirstChildUserIdTAG: 1081098
FirstChildUserNameTAG: BrilloBox
FirstChildCreateTimeTAG: 2013-02-26T23:29:43Z
FirstChildVoteTAG: 0
IndexTAG: 2318
TitleTAG: observation
why the right answer does not have % sign?
UserIdTAG: 989111
UserNameTAG: cholo
CreateTimeTAG: 2013-02-26T17:57:27Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Because the question asks us to find the percent of seniors. A % sign would be equivalent to saying "11.1%%" in this case.
Hope this helps.
FirstChildUserIdTAG: 1260768
FirstChildUserNameTAG: Arjunkh
FirstChildCreateTimeTAG: 2013-02-27T15:54:42Z
FirstChildVoteTAG: 0
IndexTAG: 2319
TitleTAG: Problem in Calculating 60th percentile.
The lecture 2.5 says that the 60th, 70th and the 80th percentile will all be equal to 7 whereas if we calculate the 60th percentile as taught to us i.e.
0.6 * 6 = 0.36, and the next number to it is 4 which implies that the 60th percentile should be equal to 4. Isn't it ?
UserIdTAG: 1140631
UserNameTAG: PrateekNarang
CreateTimeTAG: 2013-02-26T17:54:58Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 2
FirstChildTAG: Hi PrateekNarang, I´ll try to explain following step by step.
Ordered list = 0,2,4,7,7,12; it has six elements.
60th percentile means you have to move that % of places into the list, so:
0.60*6 elements = 3.6 **places/elements** (not a number itself) that you have to count/move into the list.
If you count 3.6 places, starting at 0, you´ll be somewhere between 4 (3rd place) and 7 (4th place). And since these are whole numbers, according to the **formal** definition of percentile, if that´s not a place in the list (wich it isn´t), you take the next number in the list (which is the one that satisfies the definition: **smallest** number that is **at least** as large as p% (60% in this case) of the list.)
The 70th (0.7*9 = 4.2 places) and the 80th (0.8*6 = 4.8 places) are both somewhere between the 4th element (a 7) and the 5th element (another 7), thus in both cases the answer is 7.
Hope it´s clear now.
Have a nice day.
FirstChildUserIdTAG: 491947
FirstChildUserNameTAG: Lamiak
FirstChildCreateTimeTAG: 2013-02-26T18:47:50Z
FirstChildVoteTAG: 3
FirstChildTAG: No, the 3.6 refers to the position. I'm assuming you had a typo when you said .36. If you round up to position 4, that position has the value of 7 in the list.
- value, position
- 0, 1
- 2, 2
- 4, 3
- 7, 4
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-02-26T18:49:54Z
FirstChildVoteTAG: 1
SecondChildTAG: Heyy there.. 60th percentile = 0.6*6 = 3.6 "places".
Now you cannot have a 3.6th place in this list hence you take the next "place" i.e the 4th "place". Hence start counting from the list (arranged in increasing order) to the 4th place.
0 = 1st place
2 = 2nd place
4 = 3rd place
7 = 4th place.
Therefore, 60th percentile = 7. Hope this helped. :)
SecondChildUserIdTAG: 379141
SecondChildUserNameTAG: NitishRaole
SecondChildCreateTimeTAG: 2013-02-27T19:00:57Z
SecondChildVoteTAG: 0
IndexTAG: 2320
TitleTAG: Included units in answer and got it wrong
Hi. I was trying to follow the "always show units in answer" rule and this resulted in me getting a few answers for percents wrong even though the numerical value was correct. It would have been nice if this was stated in the instructions.
UserIdTAG: 2625
UserNameTAG: Shalini
CreateTimeTAG: 2013-02-26T17:44:18Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Additionally, I followed the convention from the practice problems where it was necessary to add the % sign in order for the answer to be marked correctly. For anyone who is reading this, submit only numerical answer for problems 2, 3, 6 and 7.
FirstChildUserIdTAG: 2625
FirstChildUserNameTAG: Shalini
FirstChildCreateTimeTAG: 2013-02-26T18:11:15Z
FirstChildVoteTAG: 7
SecondChildTAG: Thank you soooo much!
SecondChildUserIdTAG: 1015835
SecondChildUserNameTAG: Aytaj
SecondChildCreateTimeTAG: 2013-02-26T19:25:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot Shalini.
The staff needs to get this right. It is bad for student morale and continued interest in the course, if answers are marked incorrect, not because of wrong application of concepts and ideas but due to some silly technical setting.
SecondChildUserIdTAG: 1139936
SecondChildUserNameTAG: SundarV
SecondChildCreateTimeTAG: 2013-02-27T05:02:00Z
SecondChildVoteTAG: 0
IndexTAG: 2321
TitleTAG: Problem 3b help needed
Hi All,
I hope u all would have solved exercises by now. I got this wrong. Can anyone help me with problem 3b for histogram. My Height for the bins are 0.55%, 2.33%, 30%, 8.67%, 20%, 2.4%. Don't know how to construct Histogram with this. Are these represent height of Histograms?
UserIdTAG: 985263
UserNameTAG: santhosh_chn
CreateTimeTAG: 2013-02-26T17:43:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 3b
with green-380
without green-120
FirstChildUserIdTAG: 950764
FirstChildUserNameTAG: drspdhanya
FirstChildCreateTimeTAG: 2013-02-26T18:07:43Z
FirstChildVoteTAG: 1
IndexTAG: 2322
TitleTAG: readings
I dont know if this will help but so far it has helped me.
http://www.harding.edu/sbreezeel/460%20Files/Statbook/Chapter5.pdf
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-26T17:35:24Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Thanks for the link. Do you have the link for the full book ?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T17:54:39Z
FirstChildVoteTAG: 0
SecondChildTAG: sorry no I dont.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-03-01T22:52:46Z
SecondChildVoteTAG: 0
IndexTAG: 2323
TitleTAG: Question 1A
I think this is fuzzy, income can be in discrete units (annual salary in dollars, hourly rate in dollars and cents, etc.) so although I think of this as continuous it is also reported in discrete increments. I went back and forth as to which answer to select, "quantitative" and "quantitative discrete," ultimately selecting the "incorrect" "quantitative discrete".
UserIdTAG: 1034369
UserNameTAG: kvaldes
CreateTimeTAG: 2013-02-26T17:32:33Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I agree. I also selected quantitative discrete, because income is accurately measurable and definable in discrete units whether it is expressed as annual salary or hourly rate. At least my incomes have all been expressed that way on my paychecks and W2 forms!
FirstChildUserIdTAG: 1130547
FirstChildUserNameTAG: nluetteke
FirstChildCreateTimeTAG: 2013-02-26T20:32:02Z
FirstChildVoteTAG: 1
SecondChildTAG: I too had selected the same option.
SecondChildUserIdTAG: 841834
SecondChildUserNameTAG: Kushal4698
SecondChildCreateTimeTAG: 2013-02-26T20:34:42Z
SecondChildVoteTAG: 0
FirstChildTAG: The SticiGui link we were supposed to read beforehand mentions income and its variable type specifically. It is worth reviewing it. Even though there is no explanation exactly, the answer was given there and you shoulda/coulda/woulda remembered it perhaps.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T21:22:02Z
FirstChildVoteTAG: 0
IndexTAG: 2324
TitleTAG: solution in practice 2.2 a) is false
it should be 14%/(20-(-10))=14%/30=0.467%
not 14%/10=1.4%
UserIdTAG: 1258339
UserNameTAG: Dondic
CreateTimeTAG: 2013-02-26T17:30:26Z
VoteTAG: 34
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 6
FirstChildTAG: ys i think that also
FirstChildUserIdTAG: 776071
FirstChildUserNameTAG: phaliaa
FirstChildCreateTimeTAG: 2013-02-26T18:22:32Z
FirstChildVoteTAG: 0
FirstChildTAG: +1 ))
FirstChildUserIdTAG: 759395
FirstChildUserNameTAG: Gen_Art
FirstChildCreateTimeTAG: 2013-02-26T18:30:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, I Thik to same like Dondic
SecondChildUserIdTAG: 1266100
SecondChildUserNameTAG: sklaos
SecondChildCreateTimeTAG: 2013-02-26T20:22:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, I agree with you.
SecondChildUserIdTAG: 1243742
SecondChildUserNameTAG: AnaMenezes
SecondChildCreateTimeTAG: 2013-02-26T20:36:00Z
SecondChildVoteTAG: 0
SecondChildTAG: You are so right
SecondChildUserIdTAG: 104881
SecondChildUserNameTAG: Rutherford
SecondChildCreateTimeTAG: 2013-02-27T17:19:46Z
SecondChildVoteTAG: 0
SecondChildTAG: That's true.
SecondChildUserIdTAG: 1170684
SecondChildUserNameTAG: Jovanooo
SecondChildCreateTimeTAG: 2013-02-27T19:42:25Z
SecondChildVoteTAG: 0
SecondChildTAG: true
SecondChildUserIdTAG: 931470
SecondChildUserNameTAG: sarabjeet1991
SecondChildCreateTimeTAG: 2013-03-05T18:02:46Z
SecondChildVoteTAG: 0
FirstChildTAG: But this has already been said in the forum like (and I am not exaggerating here) 100 times before.
FirstChildUserIdTAG: 250161
FirstChildUserNameTAG: gaurwraith
FirstChildCreateTimeTAG: 2013-02-26T19:11:21Z
FirstChildVoteTAG: 2
FirstChildTAG: +1. The range should be 30
FirstChildUserIdTAG: 1248471
FirstChildUserNameTAG: yingchenid
FirstChildCreateTimeTAG: 2013-02-26T19:34:46Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, range is 30 making the height .467
FirstChildUserIdTAG: 462806
FirstChildUserNameTAG: hayesmi1
FirstChildCreateTimeTAG: 2013-02-26T20:23:02Z
FirstChildVoteTAG: 0
FirstChildTAG: oh good grief.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:27:35Z
FirstChildVoteTAG: 1
IndexTAG: 2325
TitleTAG: Practice Lec 2.2 & 2.3
I am thinking that the height of -10 to 20 is not 14/10 but 14/(20-(-10)) therefore 14/30 = 0.46% per unit. Is that right?
UserIdTAG: 86033
UserNameTAG: ManjunathK
CreateTimeTAG: 2013-02-26T17:18:46Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Please check courseware errata. If I see one more such post I think everyone will explode !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T17:47:17Z
FirstChildVoteTAG: 0
SecondChildTAG: Agree, is tiresome read about the same once and again, and then again. Al least half the posts have been about this, like nobody really checks for existing discussions.
SecondChildUserIdTAG: 26776
SecondChildUserNameTAG: aleguillen
SecondChildCreateTimeTAG: 2013-02-26T17:51:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Why can't it just be fixed?
SecondChildUserIdTAG: 1029329
SecondChildUserNameTAG: EdSperr
SecondChildCreateTimeTAG: 2013-02-26T17:54:03Z
SecondChildVoteTAG: 0
FirstChildTAG: > Why can't it just be fixed?
Indeed. If we are going to go through this every week, well I just lost the will to participate.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:27:04Z
FirstChildVoteTAG: 0
FirstChildTAG: yes I agree its should be like that
FirstChildUserIdTAG: 1162240
FirstChildUserNameTAG: Sudhadhayalan
FirstChildCreateTimeTAG: 2013-03-06T12:35:31Z
FirstChildVoteTAG: 0
IndexTAG: 2326
TitleTAG: Stem-and-Leaf Plot in RStudio
# Let's create a vector of students' scores (quantitative variable)
Scores <- c(48, 59, 63, 63, 63, 67, 70, 70, 70, 72, 73, 75, 75, 80, 81, 82, 83, 84, 87, 88, 88, 90, 91, 95, 95, 95, 96, 100)
# Let's construct a stem-and-leaf plot based on the vector
stem(Scores)
![Stem-and-Leaf Plot][1]
[1]: http://savepic.ru/4161891.png
UserIdTAG: 209516
UserNameTAG: Andrey_K
CreateTimeTAG: 2013-02-26T17:17:57Z
VoteTAG: 5
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.1. Describing one quantitative variable
NumberOfReplyTAG: 4
FirstChildTAG: where do I find this program?
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-26T17:34:32Z
FirstChildVoteTAG: 0
SecondChildTAG: R (language for statistical computing) can be downloaded [here][1]. R is necessary for work of RStudio.
RStudio (graphical front-end for R) can be downloaded [here][2].
Good luck! :)
[1]: http://www.r-project.org/
[2]: http://www.rstudio.com/
SecondChildUserIdTAG: 209516
SecondChildUserNameTAG: Andrey_K
SecondChildCreateTimeTAG: 2013-02-26T17:44:36Z
SecondChildVoteTAG: 0
SecondChildTAG: http://www.r-project.org/
Be warned that it is not directly user friendly (The dreaded command line interface) but is a powerful software used by statisticians. I am trying to learn it in stuttering steps)
I do wish that the Professors had a course for "dummies" on it as it would be a very useful course.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-26T17:46:37Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-27T00:30:44Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks I also dabbled with R and managed to replicate what you did.Thanks.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T17:44:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks.
FirstChildUserIdTAG: 46420
FirstChildUserNameTAG: passoret
FirstChildCreateTimeTAG: 2013-02-26T18:52:36Z
FirstChildVoteTAG: 0
FirstChildTAG: SherryJo, R is not an ideal entry level program, unless you are having face-to-face lectures where you can be walked through the process. Or you have some programming experience.
There are easier to use stats programs, but they cost money. R is free.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:26:22Z
FirstChildVoteTAG: 0
SecondChildTAG: I jsut want to take a look at it. i do programming a bit so it shouldnt be to hard to just take a look at it
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-27T00:31:52Z
SecondChildVoteTAG: 0
IndexTAG: 2327
TitleTAG: Problem 2 question a)
I answered 0.19 and 0.1875 for this question it's equals 3/16 but it was wrong , why is that please ?!!
UserIdTAG: 919422
UserNameTAG: tarwateanas
CreateTimeTAG: 2013-02-26T17:13:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: (3/16)*100=18.75
FirstChildUserIdTAG: 1053909
FirstChildUserNameTAG: mon8721
FirstChildCreateTimeTAG: 2013-02-26T17:30:22Z
FirstChildVoteTAG: 0
SecondChildTAG: ya u should multiply by 100
SecondChildUserIdTAG: 950764
SecondChildUserNameTAG: drspdhanya
SecondChildCreateTimeTAG: 2013-02-26T18:06:11Z
SecondChildVoteTAG: 0
IndexTAG: 2328
TitleTAG: To teachers staff: Midterm exam
how long we will have to solve the Midterm exam?
Just as say on Course Schedule:
MIDTERM, WED MAR 13: Describing one variable (Sections 15)
It means 1 day?
or the time corresponding to Week 4: Wed Mar 13 Tue Mar 19?
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-26T17:11:10Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: One day, not one week. If you do the exam in one sitting, I expect it will take about 45 minutes. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T19:16:57Z
FirstChildVoteTAG: 6
SecondChildTAG: Professor Ani:
Is it possible to put this exam on a Saturday or Sunday instead a working day? keeping the one day limit.
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-02-26T19:57:52Z
SecondChildVoteTAG: 0
SecondChildTAG: I am working out in the field for work all that week, and so this would be problematic for me too. Being in the UK, the mid-term will only come online for me in the late evening, not leaving a lot of time to complete this. I realise this is going to be awkward to solve though! Perhaps some sort of timed release based on timezones?
I'm really enjoying the course so far, so thank you for all your hard work.
Best wishes, Hen
SecondChildUserIdTAG: 1226786
SecondChildUserNameTAG: goodhen
SecondChildCreateTimeTAG: 2013-02-27T14:09:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Saturday or Sunday would not be that helpful, conventional nonworking days vary from country to country and many people work on 'nonworking' days. Also, I assume the exam will be available for 24 hours so when it comes online in a specific time zone is also irrelevant.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-27T14:50:00Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree about the variation in conventional working days - you're never going to please everyone,and certainly there will be those who have certain restrictions on weekends due to religious/cultural reasons.
I think the timezone thing is more about perception. For example, having from 8pm until 8pm the following day just feels more restrictive than having midnight-midnight, even though technically you have the same amount of time. I know if I sat down in the evening to do it, I would feel rushed to complete before the 8pm deadline. Saying that, I'm sure we'll manage! :)
SecondChildUserIdTAG: 1226786
SecondChildUserNameTAG: goodhen
SecondChildCreateTimeTAG: 2013-03-01T17:55:25Z
SecondChildVoteTAG: 0
FirstChildTAG: Prof Ani
Much appreciated if you can reschedule MID-TERM and FINAL either on weekend or deadline changed to 2359 pacific time instead of GMT considering a small set of students are working professional. Thanks!
FirstChildUserIdTAG: 1181586
FirstChildUserNameTAG: eumannu
FirstChildCreateTimeTAG: 2013-03-08T17:10:15Z
FirstChildVoteTAG: 0
IndexTAG: 2329
TitleTAG: Reasonable to assume uniform distribution
I reviewed the lectures twice, it was not taught how to assume or not to assume, if someone has the reference please let me know, I thought the Prof said if the tops of the histograms were level it was safe to assume uniform distribution
UserIdTAG: 831934
UserNameTAG: DrRonLewis
CreateTimeTAG: 2013-02-26T17:08:37Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 5
FirstChildTAG: I agree with you.It is reasonable such like is reasonable assume it on those exercises that you say. Reasonable is not mandatory. It is reasonable to assume as uniform distribution such like is not reasonable to assume as uniform distribution. But, if you say:is it mandatory to assume as uniform distribution?, clearly it is not.
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-02-26T17:18:40Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree with you. I think the question is not reasonable. And looking at the data, especially because the ranges are small mostly, I feel it's reasonable to assume they are uniformly distributed.
SecondChildUserIdTAG: 1242451
SecondChildUserNameTAG: gurinovich
SecondChildCreateTimeTAG: 2013-02-26T17:22:39Z
SecondChildVoteTAG: 0
FirstChildTAG: So in the 0 -9 group, is it reasonable to assume that the same $\%$ had 1 year of education in total as the $\%$ who had 8 years in total?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:23:45Z
FirstChildVoteTAG: 0
FirstChildTAG: The clues were in 4a and 4b. If 12 years is considered finishing high school, is it reasonable to consider the bin in which 12 falls to have uniform distribution? Some high school graduates will not go on to higher education. Same with 16 years for bachelor's degree.
FirstChildUserIdTAG: 459910
FirstChildUserNameTAG: AlanJayWeiner
FirstChildCreateTimeTAG: 2013-02-27T08:19:22Z
FirstChildVoteTAG: 0
SecondChildTAG: No, it is not reasonable, and that's thy there is separate bin for 12-13 years - so my guess was, excluding this age we can more safely assume the more homogenous distribution.
SecondChildUserIdTAG: 517550
SecondChildUserNameTAG: Ewa_G
SecondChildCreateTimeTAG: 2013-03-01T11:46:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Dumb question. Define the word "reasonable."
I thought the groups were chosen well, and the shape of the histogram approximates the shape of the true distribution. That's what matters.
Yet, the answer is "not reasonable."
FirstChildUserIdTAG: 1080056
FirstChildUserNameTAG: alexd457
FirstChildCreateTimeTAG: 2013-02-27T10:37:31Z
FirstChildVoteTAG: 1
FirstChildTAG: I chose to say that they were reasonable on technical grounds because the histograms in the previous question had flat tops. That said, I can understand how a majority of people would cluster near the completion of major educational milestones. Eg. there would be a large cluster where people had finished high school around.
FirstChildUserIdTAG: 1082322
FirstChildUserNameTAG: CharlesHall
FirstChildCreateTimeTAG: 2013-02-28T07:18:01Z
FirstChildVoteTAG: 0
IndexTAG: 2330
TitleTAG: Porcentajes
No encontre la forma de trabajar el porcentaje... Gracias
UserIdTAG: 1033735
UserNameTAG: nelsiton
CreateTimeTAG: 2013-02-26T17:08:03Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2331
TitleTAG: Required Help
I don't understand about problem no. 2(a),2(b) & 2(c)
please help me....... to find the answers.......
thank you.
UserIdTAG: 1312779
UserNameTAG: SwapnilMane
CreateTimeTAG: 2013-02-26T17:06:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: 2a)
Which group contains 30 year olds? What would be the % per year of the that group? What would be the total percent which would be 30 year olds? The practice exercises help a lot for these.
FirstChildUserIdTAG: 150589
FirstChildUserNameTAG: TriciaC
FirstChildCreateTimeTAG: 2013-02-26T18:11:16Z
FirstChildVoteTAG: 0
SecondChildTAG: my confusion is what is meant by "people in thirties"?
if we said that we can define the group within bars how can we say how many in this case?
SecondChildUserIdTAG: 1015835
SecondChildUserNameTAG: Aytaj
SecondChildCreateTimeTAG: 2013-02-26T19:37:02Z
SecondChildVoteTAG: 0
SecondChildTAG: 30-45 is not people in thirties, and when I take only 30-40 answers come out wrong even when i calculate hight
SecondChildUserIdTAG: 1015835
SecondChildUserNameTAG: Aytaj
SecondChildCreateTimeTAG: 2013-02-26T19:38:00Z
SecondChildVoteTAG: 0
SecondChildTAG: I assumed that "people in thirties" are all people who are 30 years old and all between 30-39. That means two groups have "thirties". I am not sure if that is correct assumption.
SecondChildUserIdTAG: 1262910
SecondChildUserNameTAG: dashacoop
SecondChildCreateTimeTAG: 2013-02-26T19:59:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Dashacoop - have a look at the endpoint convention that is specified in the exercise. There is only one group with thirties if you check that.
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-26T23:29:12Z
SecondChildVoteTAG: 0
FirstChildTAG: You want $30 \le X \lt 40$, so you have to calculate how many in the 30 -45 interval are in this age bracket. Using the assumtpion you are given about distribution.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:17:51Z
FirstChildVoteTAG: 0
SecondChildTAG: I did all that, we know it's that interval and after getting the percent / year and considering a uniform distribution multiplying by the number of the many thirties, i still get wrong
SecondChildUserIdTAG: 1078871
SecondChildUserNameTAG: CarlosMartin2013
SecondChildCreateTimeTAG: 2013-02-27T09:37:40Z
SecondChildVoteTAG: 0
IndexTAG: 2332
TitleTAG: Please include data sets in problems
Some of us have slow internet connections or slow computers that are not very agile in switching from the practices to videos and back again. Whenever possible, when we have to refer to a data set, table, histogram, etc in order to solve a problem in the practice sets, please include the information on the practice set page.
UserIdTAG: 1053002
UserNameTAG: ChristinainPanama
CreateTimeTAG: 2013-02-26T17:01:22Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: Elizabeth Holmes
I am frantic, I can't find any income data either
FirstChildUserIdTAG: 1209211
FirstChildUserNameTAG: Ann3067
FirstChildCreateTimeTAG: 2013-02-26T20:47:11Z
FirstChildVoteTAG: 0
SecondChildTAG: Just look at the slides for the lectures for Lec 2.4 - slide 2
https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec2.4.pdf
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-26T21:15:19Z
SecondChildVoteTAG: 0
IndexTAG: 2333
TitleTAG: Pls help
I dont understand the meaning of the following
1. which interval was more crowded 5-15 or 15-20. (Here 5-15 contains more people, so I thought it was 5-15 and I am wrong! How?)
2. Were there more 5 year olds or 15 year olds? (How to find the answer)
Was it a problem of my poor reading of the course material?
UserIdTAG: 1194422
UserNameTAG: sajannt
CreateTimeTAG: 2013-02-26T16:48:39Z
VoteTAG: 5
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: The problem is the term "crowded". It's a relative term. So, you have to think if the interval have more or less people in each fraction of it.
If there are 20 people within a 5-years interval (4 per year, if the ages are uniformly distributed), this is more crowded than one wich have only 10 people within the same interval (2 per year), or 30 people within a 20-years interval (1,5 per year).
FirstChildUserIdTAG: 1222674
FirstChildUserNameTAG: r2s2
FirstChildCreateTimeTAG: 2013-02-26T17:19:53Z
FirstChildVoteTAG: 0
FirstChildTAG: 1. If you go back to the course material preceding the exercise, you will find that it is mentioned how to calculate the crowdedness. This will help you answer your first query.
2. Also, in the course material, it is mentioned how to calculate the percentage of a certain interval which may be a subset of the intervals provided in the question.For eg: It is possible to calculate the percentage of the interval 8-15 from the interval 5-15. Grasping this concept will help you answer your second query.
Sorry, as per the honour code I am trying to help you without giving away too much. I hope it helps.
If it is of any help, I can assure you that the the concepts are explained in the videos preceding the exercise and if you work your way through it carefully, you will be able to answer it. Good luck!
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-02-26T17:24:15Z
FirstChildVoteTAG: 2
IndexTAG: 2334
TitleTAG: Practice on types of variables
Dear professors,
after having taken the Set 1 Exercise, I truly think that I need far more practice in identifying the different types of variables. Perhaps a more complete explanation on the criteria for being able to correctly label them would help too, since I do not totally understand the rationale behind those labels. Is there any other source of practice or further reading that I can use for this issue?
Thank you very much in advance.
UserIdTAG: 1076185
UserNameTAG: msBiosca
CreateTimeTAG: 2013-02-26T16:32:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: [http://www.onlinestatbook.com/2/introduction/variables.html][1]
[1]: http://www.onlinestatbook.com/2/introduction/variables.html
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T16:48:09Z
FirstChildVoteTAG: 0
IndexTAG: 2335
TitleTAG: You could have made it clear that scores are in % and not up to 10!
Some of the questions are so vague there is no straight forward way of trying to calculate the required answer e.g.
With respect to problem two here, scores discussed in Lecture 2.1. (I could not get the link to get back to the lecture).
Did I also miss the whole section on quartiles for tree and stem plots? No clue on number of decimal places either.
Is any one else finding these question hard to understand?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-26T16:23:45Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: Not really, at least for me so far, so good. No problems with lessons and the problems I have answer wrong has been for not putting enough attention on what I was doing. Once I have seen the wright answer I understood what I have done wrong and the ones I had doubts where address in some of the posts (or a lot of the posts, in some cases)
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-26T16:29:15Z
FirstChildVoteTAG: 1
FirstChildTAG: There is a link to a section in the book that deals with quartiles. It followed the lectures. The information needed to answer the questions was there.
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-26T16:32:44Z
FirstChildVoteTAG: 1
FirstChildTAG: This is not the first online course I'm taking, even using this engine. The point is that, since the engine for answer recognition is somewhat sensitive, it is absolutely imperative to provide every necessary information regarding the format of the answer: decimal points, percentages etc. I will agree with the friend who posted the original comment - and this has nothing to do with how well one studies the lectures.
FirstChildUserIdTAG: 687022
FirstChildUserNameTAG: ThanosT
FirstChildCreateTimeTAG: 2013-02-26T17:51:55Z
FirstChildVoteTAG: 1
FirstChildTAG: Problem one was not clear about what you should round your answers to. Rounding to one decimal place for all three parts worked for me.
Only other thing I found unclear was the use of the word peak, which I don' think was ever properly defined in the lectures, though it's not too hard to figure out.
As for the stem and leaf plot, remember that it provides all of the data, so you should proceed with that problem how you would proceed with the complete, raw data set.
FirstChildUserIdTAG: 398536
FirstChildUserNameTAG: liguoric
FirstChildCreateTimeTAG: 2013-02-26T19:13:29Z
FirstChildVoteTAG: 1
IndexTAG: 2336
TitleTAG: Percentages
What is the formula to find the percentages?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-26T16:01:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Your sample / the whole group of your sample.
For example: you have 80 pandas. If you kill 20 of them, you have killed 20/80 = 0,25, or 25/100, wich is exactly 25%.
I hope you understand.
Best regards
FirstChildUserIdTAG: 1222674
FirstChildUserNameTAG: r2s2
FirstChildCreateTimeTAG: 2013-02-26T17:12:22Z
FirstChildVoteTAG: 1
IndexTAG: 2337
TitleTAG: Uniform distribution
How do we know when it's reasonable to assume uniform distribution?
UserIdTAG: 993630
UserNameTAG: ccchng
CreateTimeTAG: 2013-02-26T15:43:44Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: If the situation is such that a uniform distribution is a fair approximation or assumption
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T17:36:27Z
FirstChildVoteTAG: 0
FirstChildTAG: Short answer: The narrower the bar, the more likely it is that the distribution within that bar will be uniformly (evenly) distributed. The wider the bar, the less likely it is for the data to be uniformly distributed.
For example, in the education histogram it is safe to assume that people who got 12-13 years of education are uniformly distributed (the bin really couldn't get narrower, given the units), but in the 0-9 years bin it is not safe to assume that an equal number of people had 0, 1, 2, 3, 4, etc years of schooling. One assumption might be that the data in that bin could be clustered around 7,8 and 9 (with fewer people who got zero or close to zero years of school) but we can't tell since the bin is so wide.
FirstChildUserIdTAG: 1009374
FirstChildUserNameTAG: JMoolay
FirstChildCreateTimeTAG: 2013-02-27T01:36:42Z
FirstChildVoteTAG: 0
IndexTAG: 2338
TitleTAG: Practice Lec 2.2 & 2.3
I am thinking that the height of -10 to 20 is not 14/10 but 14/(20-(-10)) therefore 14/30 = 0.46% per unit. Is that right?
UserIdTAG: 377232
UserNameTAG: KChoutas
CreateTimeTAG: 2013-02-26T15:28:21Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Look for the courseware errata, you´ll find the answer there, you are like the 110th person saying the same.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-26T15:34:18Z
FirstChildVoteTAG: 0
SecondChildTAG: The answer 1.4% is incorrect. It should be 0.46%. Otherwise what would be the height of -70 to -40 for example?
SecondChildUserIdTAG: 1293475
SecondChildUserNameTAG: kandysl
SecondChildCreateTimeTAG: 2013-02-26T16:20:47Z
SecondChildVoteTAG: 0
IndexTAG: 2339
TitleTAG: Volume very low
Is anybody else experiencing the volume on these videos being very low, or is it just me?
UserIdTAG: 82472
UserNameTAG: SSchocke
CreateTimeTAG: 2013-02-26T14:56:31Z
VoteTAG: 3
CoursewareTAG: Section 1: Introduction / Lec 1.3. Bar graphs: describing categorical data
NumberOfReplyTAG: 1
FirstChildTAG: yess this video has a low volume , but the script beside the video can help you :)
FirstChildUserIdTAG: 1041182
FirstChildUserNameTAG: mita09002
FirstChildCreateTimeTAG: 2013-02-26T15:09:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Same here, low volume
SecondChildUserIdTAG: 743321
SecondChildUserNameTAG: Pa_CR
SecondChildCreateTimeTAG: 2013-02-27T15:47:41Z
SecondChildVoteTAG: 0
SecondChildTAG: The volume is so low, I can't hear it through headphones. It must be handled.
SecondChildUserIdTAG: 313892
SecondChildUserNameTAG: doronko4
SecondChildCreateTimeTAG: 2013-03-01T16:22:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I have the same issue. I could barely hear the lecture even though I maximized my computer volume.
SecondChildUserIdTAG: 1238004
SecondChildUserNameTAG: MoonBurnett
SecondChildCreateTimeTAG: 2013-03-01T23:41:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here. The volume is low even with headphones.
SecondChildUserIdTAG: 1144890
SecondChildUserNameTAG: ltavares
SecondChildCreateTimeTAG: 2013-03-13T02:35:37Z
SecondChildVoteTAG: 0
IndexTAG: 2340
TitleTAG: Width of the Class Interval is not 10 but 30
The exercise is incorrect. The width of the Class interval -20 to 10 is 30, not 10.
Have a question, how many decimals should we use to express the height of the bins?
UserIdTAG: 1145881
UserNameTAG: brunoa
CreateTimeTAG: 2013-02-26T14:46:54Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Regarding the first question, you've probably found out in 100 other post.
Regarding decimals, unless stated otherwise, you should use 1 decimal place.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-26T14:53:00Z
FirstChildVoteTAG: 0
IndexTAG: 2341
TitleTAG: Question (a) Lecture 2.2 to 2.3
The answer given to be corrent is in fact incorrect as the interval width of -10 to 20 is rather 30 and not 10. Therefore the correcct answer should be 14/30 which is 0.467.
Please do correct this.
Thank you in advance.
UserIdTAG: 1149526
UserNameTAG: LoneBTsie
CreateTimeTAG: 2013-02-26T14:37:35Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: It has been asked 100 times already. You are right indeed but...
1) It is in the errata.
2) You can do a search on the left side rather fast
3) It was just practice.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-26T14:52:14Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm looking at the past post headings. Shame none of the post repeaters did the same before posting.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:07:37Z
FirstChildVoteTAG: 0
IndexTAG: 2342
TitleTAG: Incorrect answer
Just as following classmates said...,
the answer for the question:
a) Height of -10 to 20 bar = ____________ % per unit
appears to be wrong.
It should be 0.47% (rounded to second decimal place.)
Thank you.
UserIdTAG: 1267422
UserNameTAG: paristung
CreateTimeTAG: 2013-02-26T14:22:20Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: No news there, we have like 100 posts about it... everybody knows already, even the staff and it is included in the courseware errata...
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-26T14:29:43Z
FirstChildVoteTAG: 0
FirstChildTAG: In the time it took you to write that all out so very nicely, you could have answered the question on your own by using the resources we all have available to us.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T14:36:59Z
FirstChildVoteTAG: 0
FirstChildTAG: LOL
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:06:56Z
FirstChildVoteTAG: 0
IndexTAG: 2343
TitleTAG: Problem 3b; bug?
I believe none of the histograms is correct, but this is not accepted as the right answer. In fact, the correct answer to problem 3a gives the height of 4th bar (13-16) and none of the histograms comply with it.
Thanks!
D
UserIdTAG: 1249212
UserNameTAG: db75
CreateTimeTAG: 2013-02-26T13:55:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Look at past posts, there are quite a few about this problem. Pick the one that is almost correct.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:06:44Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks for your answer. Indeed, that's what I had done at my second attempt, but I still got a wrong answer... something went wrong with the webpage I guess...
SecondChildUserIdTAG: 1249212
SecondChildUserNameTAG: db75
SecondChildCreateTimeTAG: 2013-02-26T21:41:09Z
SecondChildVoteTAG: 0
IndexTAG: 2344
TitleTAG: exrsise 3 prob 3 ans plzzzz sm1 hlp me with a,b
3-3
UserIdTAG: 1042429
UserNameTAG: Rifayat
CreateTimeTAG: 2013-02-26T13:55:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If this is for Exercise 3, then you should use the Exercise 3 subforum. Look at past posts in the subforum and if your question is answered, ask. But please check first.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:05:17Z
FirstChildVoteTAG: 0
IndexTAG: 2345
TitleTAG: Ejercicios set 3 : Problema 4
Hay alguien que me pueda explicar este ejercicio en español? porque no creo estar entendiéndolo en inglés.
UserIdTAG: 526713
UserNameTAG: Miolan
CreateTimeTAG: 2013-02-26T13:33:36Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Lo que ese ejercicio pide es que, comparando las cajas 4 y 5 del gráfico del ejercicio 3, si los datos se hubieran presentado en forma de histograma cuál de ellos tendría un pico.
Para esto lo que hay que tener claro es que representa cada una de las partes de la caja, que se explica al inicio del ejercicio 3.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-26T14:26:35Z
FirstChildVoteTAG: 2
SecondChildTAG: Entonces para resolver eso tengo que hacer un histograma con los experimentos 4 y 5?
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-02-26T14:52:09Z
SecondChildVoteTAG: 0
SecondChildTAG: No se puede hacer el histograma porque no tenemos los datos completos del experimento, es saber conceptualmente como se genera un histograma y como se interpreta en este los datos que nos dan las cajas, así es como podemos averiguar aproximadamente la forma que tendrá el histograma y saber cual contaría con un pico.
Q: So in order to solve this I have to make the histogram from experiments 4 and 5?
A: We can´t make the histogram because we don´t have all data from the experiment. What you need is to know the concepts behind making an histogram and how to interpreted on it the data given in the box, so you can generate an approximation on how the histogram shape would be and which one might have a peak on it.
SecondChildUserIdTAG: 26776
SecondChildUserNameTAG: aleguillen
SecondChildCreateTimeTAG: 2013-02-26T15:07:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Hola ! En este problema ud deves pensar como densidad. hay uno boxplot donde los valores están más concentrados. recorda-te que en la caixa están marcados los percentiles 25, 50 ,75. Quanto más lárgo menor densidad. Mientras maior densidad maior será la columna en el histograma.
SecondChildUserIdTAG: 416422
SecondChildUserNameTAG: edujara
SecondChildCreateTimeTAG: 2013-02-26T16:45:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Correct! You should think that this box is as bar chart. The online book, you can try. the graphic blue-yellow. (sorry by my english)
-Spanish- Correcto! Tu debes pensar que el diagrama de caja es como el de barras. En el libro de texto online que tenemos puedes probar con la gráfica esa interactiva que hay, la azul y amarilla.
SecondChildUserIdTAG: 1183170
SecondChildUserNameTAG: kungan
SecondChildCreateTimeTAG: 2013-02-26T16:53:39Z
SecondChildVoteTAG: 0
FirstChildTAG: Please post translation of questions and answers so that we can all benefit from them. English is required for the course. Thank you.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T14:35:11Z
FirstChildVoteTAG: 2
SecondChildTAG: ponte a estudiar español
, you should study spanish
SecondChildUserIdTAG: 1107978
SecondChildUserNameTAG: betoagto
SecondChildCreateTimeTAG: 2013-02-26T21:28:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Miolan was asking if someone could explain the problem 4 from exercise set 3 in Spanish, because is not sure if was understanding it in English.
What I did is basically translate the exercise to Spanish, that´s the first paragraph. The second is a small explanation, so what I said is that in order to answer that what we have to do is clearly understand what every part of the box mean.
Sorry, will translate at one the next time.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-26T14:42:37Z
FirstChildVoteTAG: 4
SecondChildTAG: Thank you so much! (Muchisimas gracias - I believe?) I really appreciate it.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-26T16:39:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Aleguillen gracias por su ayuda! Si alguien necesita traducirlo, pueden usar Google Translate - http://translate.google.com. :-)
SecondChildUserIdTAG: 673325
SecondChildUserNameTAG: coutlay
SecondChildCreateTimeTAG: 2013-02-27T21:31:45Z
SecondChildVoteTAG: 0
IndexTAG: 2346
TitleTAG: bellcurve
I wonder if the stem and leaf could actually show skewness
UserIdTAG: 1023813
UserNameTAG: John_Apolinario
CreateTimeTAG: 2013-02-26T13:26:07Z
VoteTAG: 2
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.1. Describing one quantitative variable
NumberOfReplyTAG: 1
FirstChildTAG: It can if you see how the leaves lie in relation to the stem
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T13:36:40Z
FirstChildVoteTAG: 1
IndexTAG: 2347
TitleTAG: What is the meaning of button save ?
I just wonder what is the use of button save ?
UserIdTAG: 1079437
UserNameTAG: banhbeodauden
CreateTimeTAG: 2013-02-26T13:20:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Perhaps to save the answer, for a future session, without submitting for grading?
FirstChildUserIdTAG: 321955
FirstChildUserNameTAG: pfialho
FirstChildCreateTimeTAG: 2013-02-26T13:21:51Z
FirstChildVoteTAG: 1
SecondChildTAG: that´s precisely it!
SecondChildUserIdTAG: 1277369
SecondChildUserNameTAG: Ascensor
SecondChildCreateTimeTAG: 2013-02-26T18:49:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Save your answer does not submit it for marking. You have an answer, but aren't sure enough to commit to grading. So you go away and think about it some more. By saving you don't have to re-enter the answer when you return.
Check submits it for grading - shown by a green tick or red cross.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:02:55Z
FirstChildVoteTAG: 1
IndexTAG: 2348
TitleTAG: the width of the class interval -10 to 20 bar
hello!
the width of the class interval -10 to 20 bar is 20-(-10)=20+10=30 not 10, so the height of the bar is 14/30=0.47% instead of 1.4%
UserIdTAG: 893749
UserNameTAG: Areti7
CreateTimeTAG: 2013-02-26T13:04:10Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Seriously... Do a search of the forum first? It has been mentioned to death... see https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/ for the official response.
FirstChildUserIdTAG: 1181263
FirstChildUserNameTAG: drush
FirstChildCreateTimeTAG: 2013-02-26T13:08:43Z
FirstChildVoteTAG: 0
FirstChildTAG: Agree with drush. The forum is being flooded with the same question.
1) There is an errata.
2) You can easily browse for questions on the left.
3) It is only a practice exercise set.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-26T13:18:12Z
FirstChildVoteTAG: 0
IndexTAG: 2349
TitleTAG: Practice Exercise Set1 completed but not marked.
I have completed my practice exercise Set 1, but when I go to "Progress" to check my performance, I seem to not have been marked for my Practice Exercise Set 1. Does it affect the overall percentage?
Can anyone please enlighten?
UserIdTAG: 1237295
UserNameTAG: tanushree31
CreateTimeTAG: 2013-02-26T12:57:38Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is "Practice Exercise"....doesn't matter basically. Only the actual Exercise Sets do.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-26T13:16:37Z
FirstChildVoteTAG: 3
SecondChildTAG: Good comment, practice makes perfect
SecondChildUserIdTAG: 686611
SecondChildUserNameTAG: wmutabaazi
SecondChildCreateTimeTAG: 2013-02-26T15:17:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks!
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-26T17:15:25Z
SecondChildVoteTAG: 0
IndexTAG: 2350
TitleTAG: Q 4,5, 6
all the three are needing trick solution and should the submission be more than 2 may be three
UserIdTAG: 689363
UserNameTAG: sehamballa
CreateTimeTAG: 2013-02-26T12:56:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Not so trick, put your mind to run faster and this may help!
FirstChildUserIdTAG: 1277369
FirstChildUserNameTAG: Ascensor
FirstChildCreateTimeTAG: 2013-02-26T18:54:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Why do so many think these are "tricks"? They are not! Everything has been explained in the lectures and practice exercises. Needing think about something does not make it a "trick".
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T21:00:51Z
FirstChildVoteTAG: 0
IndexTAG: 2351
TitleTAG: submissions
It's also a bit sad that easier tasks can be made 2 times, while hard ones have only one attempt.
UserIdTAG: 1309661
UserNameTAG: Grammer
CreateTimeTAG: 2013-02-26T12:54:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: On the bright side, 35% is a passing score. I don't think we're meant to be perfect on these, we're meant to make mistakes and then figure out what we did wrong.
FirstChildUserIdTAG: 423206
FirstChildUserNameTAG: yperil
FirstChildCreateTimeTAG: 2013-02-26T13:07:49Z
FirstChildVoteTAG: 1
IndexTAG: 2352
TitleTAG: Problem 5
Can someone explain this exercise for me? If the bar changed by 10 and 1 cm=10mm, whouldn't there be 1 percent per centimeter?
UserIdTAG: 1309661
UserNameTAG: Grammer
CreateTimeTAG: 2013-02-26T12:47:23Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 5
FirstChildTAG: Yup. I don't get it either.
FirstChildUserIdTAG: 423206
FirstChildUserNameTAG: yperil
FirstChildCreateTimeTAG: 2013-02-26T13:06:38Z
FirstChildVoteTAG: 0
FirstChildTAG: Won't tell the answer of course, but remember the width, height and area bits from the lesson :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-26T13:14:55Z
FirstChildVoteTAG: 0
FirstChildTAG: But the proportion is still the same, or isn't it?
FirstChildUserIdTAG: 321955
FirstChildUserNameTAG: pfialho
FirstChildCreateTimeTAG: 2013-02-26T13:23:05Z
FirstChildVoteTAG: 4
SecondChildTAG: 1%=x/20; there x=20%, so for cm, 20%/2=10 % per cm
SecondChildUserIdTAG: 831934
SecondChildUserNameTAG: DrRonLewis
SecondChildCreateTimeTAG: 2013-02-26T17:04:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you Dr. Ron. It is good to be reminded of the basics - which are essentially very beautiful. I got the answer wrong because I tried to find what value of x = 0.05 for the centimeters! Not thinking!
SecondChildUserIdTAG: 845389
SecondChildUserNameTAG: jonellevillar
SecondChildCreateTimeTAG: 2013-02-26T22:50:21Z
SecondChildVoteTAG: 0
SecondChildTAG: What made sense for me is that when you change from mm to cm, you are changing the number of divisions in the range. For 20 - 40 mm, you have 20 divisions: 20 mm, 21 mm, 22 mm, etc. For 2 - 4 cm, you only have 2 divisions: 2 cm, 3 cm. This is the same explanation as Dr. Ron's calculation. It's just a slightly different way to look at it.
SecondChildUserIdTAG: 1342025
SecondChildUserNameTAG: mbunch25
SecondChildCreateTimeTAG: 2013-03-03T05:14:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Calculate it out...
$height\ of\ bar = \frac{\%\ of\ interval}{width\ of\ interval} = \frac{\%\ of\ interval}{(right\ endpoint) - (left\ endpoint)}$
$1\ \%\ per\ mm = \frac{x}{40-20} = \frac{x}{20}$
$y\ \%\ per\ cm = \frac{x}{4-2} = \frac{x}{2}$
FirstChildUserIdTAG: 1181263
FirstChildUserNameTAG: drush
FirstChildCreateTimeTAG: 2013-02-26T13:27:32Z
FirstChildVoteTAG: 4
FirstChildTAG: 1% / mm = ? % / cm
(Remember 1 cm = 10 mm)
FirstChildUserIdTAG: 177112
FirstChildUserNameTAG: manikghosh
FirstChildCreateTimeTAG: 2013-02-27T06:25:06Z
FirstChildVoteTAG: 1
IndexTAG: 2353
TitleTAG: Where is the math behind Problem 2(b) covered in the course material
Hello, I'm doing my best to answer the question about senior citizens (problem 2-b). Can anyone point me to the relevant course material that covers the concept? Perhaps I don't have the math prerequisites needed to succeed in this course because this problem is currently not making any sense given what I've read in the material or watched in the videos. Thank you in advance for your help.
UserIdTAG: 1182448
UserNameTAG: dcwebster
CreateTimeTAG: 2013-02-26T12:29:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: There is not much maths needed to solve this problem. All you need to do is identify the correct interval/s and you will find your answer.
Hope this helps. As per the honour code, I am trying my best to offer my help without giving away too much.
Don't doubt yourself. Keep at it. We are all here to learn. You will do just fine.
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-02-26T12:54:31Z
FirstChildVoteTAG: 0
SecondChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#histograms
SecondChildUserIdTAG: 423206
SecondChildUserNameTAG: yperil
SecondChildCreateTimeTAG: 2013-02-26T13:10:32Z
SecondChildVoteTAG: 0
FirstChildTAG: Just knowing how to start would be a help - thanks!!
FirstChildUserIdTAG: 1048486
FirstChildUserNameTAG: Netsville
FirstChildCreateTimeTAG: 2013-02-26T14:33:39Z
FirstChildVoteTAG: 0
FirstChildTAG: Units and Density lecture.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T20:58:53Z
FirstChildVoteTAG: 0
IndexTAG: 2354
TitleTAG: BUG
Stat2.1x -> Courseware -> Practice for Exercise Set2 -> Lecture 2.2 and 2.3
a) Height of -10 to 20 bar = ________ % per unit.
System Ans : 14/10 = 1.4.
Correct Ans : 14/30 = 0.47
UserIdTAG: 556698
UserNameTAG: GGG
CreateTimeTAG: 2013-02-26T12:08:50Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Please check courseware errata.
Admins I think it may be easier to change the entry and correct it rather than have a zillion posts !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T12:31:55Z
FirstChildVoteTAG: 3
FirstChildTAG: Yes, I gather it must be on the "impossible to fix" list. But a note on the landing page, or anything would help!
But given that all these dozens/hundreds of posts are made by people who can't/won't read past posts, what makes us think they would read anything at all?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T20:53:15Z
FirstChildVoteTAG: 0
IndexTAG: 2355
TitleTAG: My answer is 0.46 %.
height of the -10 to 20 bar is 14/10 = 1.4% per unit?
height of the -10 to 20 bar is 14/(20-(-10)=0.46%
right answer is 0.46% or 1.4%?
UserIdTAG: 644945
UserNameTAG: Peterpo
CreateTimeTAG: 2013-02-26T11:44:12Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Please check courseware errata in the wiki section.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T11:59:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi there!
The discussion is for solving doubts only. You shouldn't ask for or give answers of the graded exercises. Remember this course is going to give a certificate to the passing students.
Anyway, the height of a bar histogram equals the percent of individuals within the interval dibided by the **total width** of the interval. Give it a go this way, I'm sure you won't encounter any problem from now on.
I hope It will be useful my friend.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-26T12:39:41Z
FirstChildVoteTAG: 0
IndexTAG: 2356
TitleTAG: correct answer?
problem 3b, what is correct answer
UserIdTAG: 578925
UserNameTAG: mzeeshansarwar
CreateTimeTAG: 2013-02-26T11:11:33Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: This is an assessment. So you have to figure that out for yourself.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T11:21:14Z
FirstChildVoteTAG: 0
SecondChildTAG: Good advice, provide this person guidance on how to get the answer but not the answer itself.
SecondChildUserIdTAG: 686611
SecondChildUserNameTAG: wmutabaazi
SecondChildCreateTimeTAG: 2013-02-26T15:18:53Z
SecondChildVoteTAG: 0
SecondChildTAG: If they had done the practice exercise and read the paragraph on interpreting graphs, they wouldn't need to ask this question.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-26T20:55:08Z
SecondChildVoteTAG: 0
IndexTAG: 2357
TitleTAG: incorrect answer
the two answers gave by the machine are incorrect. i had follow the steps and i am confident that i've done the right process.
UserIdTAG: 977559
UserNameTAG: MarieYolande
CreateTimeTAG: 2013-02-26T10:28:10Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Hi Marie!
What exercise are you refering to?
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-26T10:35:41Z
FirstChildVoteTAG: 0
FirstChildTAG: There is one incorrect answer on this page. I'm sure you have read the other posts here and know which question.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T10:44:09Z
FirstChildVoteTAG: 0
FirstChildTAG: I don't know which question you are refering to...
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-26T12:49:20Z
FirstChildVoteTAG: 0
IndexTAG: 2358
TitleTAG: To course staff: is it possible to advance the Lectures and excercises....
.... for the next week?
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-26T10:18:14Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: I second this idea.
FirstChildUserIdTAG: 18529
FirstChildUserNameTAG: Bedilu
FirstChildCreateTimeTAG: 2013-02-26T11:14:09Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi,
I think spreading the lectures over a period of time helps in grasping the idea.Actually the main aim of this course is to grasp the concept and not just finish it.So lets just go a step after the other coz it makes the class feel real and enjoyable.
FirstChildUserIdTAG: 1209905
FirstChildUserNameTAG: Josmal
FirstChildCreateTimeTAG: 2013-02-26T12:19:58Z
FirstChildVoteTAG: 2
FirstChildTAG: i agree with that idea in that one gets the concept. ...the scoring is more of a bonus
FirstChildUserIdTAG: 1033614
FirstChildUserNameTAG: neo8701
FirstChildCreateTimeTAG: 2013-02-26T12:28:49Z
FirstChildVoteTAG: 0
FirstChildTAG: I understand that we need to grasp the concepts -- but the pace is far too slow. I want to learn statistics -- and am looking for alternatives that let me go at my own pace.
When all students are forced to work at the same pace, the pace has to be slowed down to the average -- average intelligence, average effort. Students who are above average (intelligence or motivation) will be frustrated.
FirstChildUserIdTAG: 1284635
FirstChildUserNameTAG: ed45626
FirstChildCreateTimeTAG: 2013-02-26T12:53:08Z
FirstChildVoteTAG: 0
SecondChildTAG: You can check udacity, they have a statistics course that is self paced.
SecondChildUserIdTAG: 1209905
SecondChildUserNameTAG: Josmal
SecondChildCreateTimeTAG: 2013-02-26T14:11:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Some students might want a lower pace not because they're "only of average intelligence," but also because they're busy and can only spare an hour or two per week.
SecondChildUserIdTAG: 913805
SecondChildUserNameTAG: maiagerlinger
SecondChildCreateTimeTAG: 2013-02-26T14:45:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Maiagerlinger -- still penalizes those who are able to go faster.
Josmal -- thanks, looking into it.
I've also gone and found some great lectures from UC Berkeley on youtube so I'll probably work ahead there and then just come back and fill in the excercises...
SecondChildUserIdTAG: 1284635
SecondChildUserNameTAG: ed45626
SecondChildCreateTimeTAG: 2013-02-27T19:11:19Z
SecondChildVoteTAG: 0
SecondChildTAG: maiagerlinger, if I recall correctly, this course was advertised as requiring 12h/weekly. People who knew they can only spare an hour or two per week either weren't the target of this course or don't want a certificate.
SecondChildUserIdTAG: 1097026
SecondChildUserNameTAG: aiS2ru
SecondChildCreateTimeTAG: 2013-02-27T23:13:51Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree, maybe post the following week's work on the Monday rather than the Wednesday. That way those of us who cant work on a weekend have a bit more time during the week to work on this.
Is this a fair enough compromise?
FirstChildUserIdTAG: 959823
FirstChildUserNameTAG: rasneer
FirstChildCreateTimeTAG: 2013-02-26T13:25:48Z
FirstChildVoteTAG: 0
FirstChildTAG: > I understand that we need to grasp the concepts -- but the pace is far too slow
For you maybe. But not for others. This is the first week, the pace could pick up. This is a course for beginners, so is paced accordingly.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T20:51:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Well, if you just advance a couple of days, what's the problem?..
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-02-26T21:09:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Maybe the problem is that the material is not yet written? As the Prof has already explained.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-27T23:43:36Z
SecondChildVoteTAG: 0
IndexTAG: 2359
TitleTAG: Why is 11.11% wrong?
My answer is 11.11%, but it was wrong. The right answer is 11.1%.
What is different between 11.11% and 11.1%?
UserIdTAG: 644945
UserNameTAG: Peterpo
CreateTimeTAG: 2013-02-26T10:15:03Z
VoteTAG: 8
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: I had exactly the same issue. I used two decimal places instead of one and for that I was told that my answers were wrong. I'd suggest that if we're supposed to use a specific number of decimal places, that should be stated in the question. (Or instead just recognize both 11.11% and 11.1%...)
FirstChildUserIdTAG: 703576
FirstChildUserNameTAG: cmonteiro
FirstChildCreateTimeTAG: 2013-02-26T12:28:12Z
FirstChildVoteTAG: 1
SecondChildTAG: i´m too.
SecondChildUserIdTAG: 907661
SecondChildUserNameTAG: Rebustini
SecondChildCreateTimeTAG: 2013-02-26T12:47:27Z
SecondChildVoteTAG: 0
SecondChildTAG: same for me
SecondChildUserIdTAG: 1083357
SecondChildUserNameTAG: SureshKumarK
SecondChildCreateTimeTAG: 2013-02-26T15:32:57Z
SecondChildVoteTAG: 0
SecondChildTAG: I just put in 11.11 and got it correct.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-26T16:34:59Z
SecondChildVoteTAG: 0
SecondChildTAG: :-)
SecondChildUserIdTAG: 1276315
SecondChildUserNameTAG: RHSAJID
SecondChildCreateTimeTAG: 2013-02-26T18:13:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Same happened with me. 2 decimals with no units wrong, 1 decimal after and no units right. Meaning 11.11 was incorrect but 11.1 was correct. Is there a guideline for plugging in numbers somewhere that I missed??
SecondChildUserIdTAG: 896245
SecondChildUserNameTAG: Ingrid90
SecondChildCreateTimeTAG: 2013-02-26T19:49:24Z
SecondChildVoteTAG: 0
SecondChildTAG: I took another edx statistics course about a month ago (by Harvard), and I must say it was better organized, serious and and more reliable compared to this one.
SecondChildUserIdTAG: 662184
SecondChildUserNameTAG: VCampa
SecondChildCreateTimeTAG: 2013-02-27T21:00:38Z
SecondChildVoteTAG: 0
FirstChildTAG: It's the precision...but it's only a practice exercise really.
Unless stated otherwise, use 1 decimal place.
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-26T13:12:50Z
FirstChildVoteTAG: 0
FirstChildTAG: MrKesh...
the standard is to leave your answer in 2dp. so the questioner must state to which d.p. to leave answer in to avoid guess-work.in this case it was not stated so the prudent way is 2d.p.
thanks
FirstChildUserIdTAG: 799816
FirstChildUserNameTAG: JAMINx
FirstChildCreateTimeTAG: 2013-02-26T13:24:24Z
FirstChildVoteTAG: 0
SecondChildTAG: It's not 2 dp according to the exercises....
SecondChildUserIdTAG: 1068140
SecondChildUserNameTAG: MrKeSh
SecondChildCreateTimeTAG: 2013-02-26T15:00:43Z
SecondChildVoteTAG: 0
FirstChildTAG: You are not suppose to enter "%" symbol
FirstChildUserIdTAG: 1152215
FirstChildUserNameTAG: Mantou
FirstChildCreateTimeTAG: 2013-02-27T04:10:07Z
FirstChildVoteTAG: 0
IndexTAG: 2360
TitleTAG: i need help with exercise 3- 10
I have been trying to do this particular exercise and have failed a couple of times. can someone please clarify how the answers are derived? i need to understand it before i do the Exercise. Thank you
UserIdTAG: 1242644
UserNameTAG: Danje
CreateTimeTAG: 2013-02-26T10:00:34Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: Did you read the mechanics from Lec 2.5 "Applying the definition"?
1. put the list in increasing order: already done for you
2. identify the place that is p% of the bottom of the list
3. if that's a place on the list, take the number in that place; if not, take the next one up
So the answer is always a number out of the list provided, no decimals or the like. Hope that helps?
FirstChildUserIdTAG: 389451
FirstChildUserNameTAG: senta
FirstChildCreateTimeTAG: 2013-02-26T10:45:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you very much. It's quite clear now.
SecondChildUserIdTAG: 1242644
SecondChildUserNameTAG: Danje
SecondChildCreateTimeTAG: 2013-02-26T21:55:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Well, you should see the second of the videos posted in 2b. It is very well explained Danje. Anyway, for example, to find the 21st percentile you have to find the first number in the list that "contains" at least the 21% of the numbers in the list. Lets do it:
In the list there (in 3-10) there are 25 numbers in total. Let's do it:
0.21*25 = 5.25
(5/25)*100 = 20%
(6/25)*100 = 24%
As you can see the number in the sixth position of the list is the first number in the list that contains at least the 21% of the numbers of the list. This number is -32 and there fore -32 is the 21th percentile.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-26T10:53:47Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks a million. Your explanation helped me a lot.
SecondChildUserIdTAG: 1242644
SecondChildUserNameTAG: Danje
SecondChildCreateTimeTAG: 2013-02-26T21:56:21Z
SecondChildVoteTAG: 0
SecondChildTAG: This made a lot more sense to me than the lecture slides. Thanks for sharing.
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-02-27T21:23:41Z
SecondChildVoteTAG: 0
IndexTAG: 2361
TitleTAG: Percentile definition
Hi
Although the course definition of percentile is:"The pth percentile of a list is the smallest number that is at least as large as p% of the numbers in the list."
I saw another definition from the Rice University (Lead Developer), University of Houston Clear Lake, and Tufts University on their online statistics education website that states the following:
"There is **no universally accepted definition of a percentile**. Using the 65th percentile as an example, some statisticians define the 65th percentile as the **lowest score that is greater than** 65% of the scores. Others have defined the 65th percentile as **the lowest score that is greater than or equal to** 65% of the scores. A more sophisticated definition is given below. The first step is to compute the rank (R) of the percentile in question. This is done using the following formula:
R = P/100 x (N + 1)
where P is the desired percentile and N is the number of numbers. If R is an integer, then the Pth percentile is the number with rank R. When R is not an integer, we compute the Pth percentile by interpolation as follows:
1. Define IR as the integer portion of R (the number to the left of the decimal point).
2. Define FR as the fractional portion or R.
3. Find the scores with Rank IR and with Rank IR + 1.
4. Interpolate by multiplying the difference between the scores by FR and add the result to the lower score.
Please confirm that the definition used by this course is indeed the same as **the lowest score that is greater than or equal to**.
Can you address the use of the third method since it does give different answers to the examples shown.
Thanks
Moshiko
UserIdTAG: 1240022
UserNameTAG: Moshiko
CreateTimeTAG: 2013-02-26T09:34:48Z
VoteTAG: 4
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 2
FirstChildTAG: I like very much this definition from Rice University. I wonder if it does not have these appealing mathematical properties, as mentioned by Prof.?
FirstChildUserIdTAG: 517550
FirstChildUserNameTAG: Ewa_G
FirstChildCreateTimeTAG: 2013-02-27T20:16:48Z
FirstChildVoteTAG: 0
FirstChildTAG: > Please confirm that the definition used by this course is indeed the
> same as the lowest score that is greater than or equal to.
"the smallest number that is at least as large" is the same as "the lowest score that is greater than or equal to"
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T20:59:08Z
FirstChildVoteTAG: 0
IndexTAG: 2362
TitleTAG: Solutions Posted?
Will the answers/explanations to the homework problems be posted at some point? I missed one of the problems and used up my allotted guesses, but I still want to learn the concept I'm missing.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-26T09:20:50Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: 7/10 :)
FirstChildUserIdTAG: 1265802
FirstChildUserNameTAG: GMORRIS010
FirstChildCreateTimeTAG: 2013-02-26T09:47:10Z
FirstChildVoteTAG: 0
FirstChildTAG: > Will the answers/explanations to the homework problems be posted at some point?
I gather you haven't read the course policies?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T09:47:59Z
FirstChildVoteTAG: 0
IndexTAG: 2363
TitleTAG: The height of the 20 to 50 bar is 5/30 = 0.167% per unit
The height of the 20 to 50 bar is 5/30 = 0.167% per unit
in 5/ 30 ..5 is come from where?
with 30 ok ..its rang 30=50-20
but 5??
UserIdTAG: 1158215
UserNameTAG: umar07
CreateTimeTAG: 2013-02-26T08:44:54Z
VoteTAG: 6
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: From Table 3-4: Sorted gravity data from http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#frequency_tables. There are 5 observations in interval (20,50] : {24,29,29,41,45} :)
FirstChildUserIdTAG: 1013706
FirstChildUserNameTAG: Magda_k
FirstChildCreateTimeTAG: 2013-02-26T09:34:27Z
FirstChildVoteTAG: 0
SecondChildTAG: You can also get the number from the histogram applet (Figure 3.2). Just put 20 in the "Area from:" box and 50 in the "to:" box and hit return. I will give you a "Selected area:" of 5%.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-02-26T23:49:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Me too having the same doubt. How to find out the relative frequency in the class-interval when the complete data is not given. Any example problem may help me in solving this. Please help regarding this. Thank you...
SecondChildUserIdTAG: 921013
SecondChildUserNameTAG: Jaleel
SecondChildCreateTimeTAG: 2013-02-27T04:35:20Z
SecondChildVoteTAG: 0
IndexTAG: 2364
TitleTAG: question regarding lecture 2.2-2.3 example a)
In example question a), the answer is explained as being 1.4% per unit (units, of course, the base unit defined described in the description of the gravitational variance measurements), due to "the height of the -10 to 20 bar is 14/10 = 1.4% per unit."
My understanding is that the height of the bar should be constrained so that the area visually represents the percentage of the total points of data falling into the bin.
In this case, wouldn't the interval from -10 to 20 represent an interval of 30 units, constraining the height of the bar to 14% / 30 units ~= 0.47 % per unit?
Thank you much for your patience and time, and thank you so much for this wonderful course.
Jake
UserIdTAG: 1284156
UserNameTAG: Dispader
CreateTimeTAG: 2013-02-26T08:42:41Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Sorry... sorry. I didn't see the user interface for previous discussions under the "post" button.
Jake
FirstChildUserIdTAG: 1284156
FirstChildUserNameTAG: Dispader
FirstChildCreateTimeTAG: 2013-02-26T08:44:33Z
FirstChildVoteTAG: 0
IndexTAG: 2365
TitleTAG: Please, add a link to subtitules
Please, add a link to subtitules =) It's very useful for persons who see the lectures offline
UserIdTAG: 413771
UserNameTAG: doublethinker
CreateTimeTAG: 2013-02-26T08:32:33Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2366
TitleTAG: Pass percentage 35%. Only?!
Hi all!
I was checking the Progress Page and found that the cutoff percentage for passing is 35%.
Too low for an online MOOC and given the questions, in my opinion.
I think the pass percentage could be higher, just to motivate some studying; participation in a MOOC should not be for the sake of getting a certificate only. I only hope that it was set to prevent massive drop-outs in MOOCs, and was not meant to imply that this course is passable for anybody.
And the course might have been a little more than a simplistic discourse on descriptive statistics, given that Berkeley has offered some great online courses - Quantum Computing, AI, etc.
Thanks.
UserIdTAG: 190804
UserNameTAG: rito
CreateTimeTAG: 2013-02-26T08:29:17Z
VoteTAG: 6
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Participants will be preoccupied with several tasks other than doing the course.To award certificate of completion 35% is reasonable.Even for regular students in many Universities 35% is the pass percent.
FirstChildUserIdTAG: 1064651
FirstChildUserNameTAG: siddhardh13
FirstChildCreateTimeTAG: 2013-02-26T10:37:57Z
FirstChildVoteTAG: 3
FirstChildTAG: > Even for regular students in many Universities 35% is the pass percent.
That would be at Clayton's University?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T10:43:03Z
FirstChildVoteTAG: 1
FirstChildTAG: Well I think maybe this is to motivate people ,not to drop the course and maybe some sort of onboarding ,look my scores were 70 90 and 100 (yes in that order ,I didnt sleep for almost a day for most of them and I didnt really feel like going through with the course because I read it was so hard and i didnt give the first one much effort also did i mention I didnt sleep ,for the last one I had a nice long nap haha )but that wont be the same every week and I imagine as my workload gets harder and this course also gets harder it might make it more difficult to keep up ,but remember its about learning ,the certificate is like sprinkles ,and it just motivates us not to drop the course ,plus if we have the bare minimum here maybe then we still move on to 2.2 and 2.3 ,I mean if I have the certificate for this one ill feel more confident to move on to those .So I dont know ,yes I think it should probably be higher ,but eh ,its not an issue is it ,besides you can never please everyone its always to high or too low or something so good luck to the staff here haha .What I do think though is this is one of the courses that would be amazing if they offered it on the pearson vue testing ,at least just the 3rd one ,then they could have a 80 or 90 percent pass requirement and that would be awesome ,better than ap for one and definitely better than a level exams ,so im hoping i hear something about that testing sometime soon
FirstChildUserIdTAG: 20186
FirstChildUserNameTAG: vikashx1
FirstChildCreateTimeTAG: 2013-02-26T23:38:12Z
FirstChildVoteTAG: 1
FirstChildTAG: A little secret about teaching: grades are fuzzy and easily manipulated by the teacher. It does not matter where the passing mark is set. If too many students are not passing, more points and/or easier questions can be added in later assignments. If too many students get a particular question wrong, that question and its point value can be dropped from the mark and the content of the question reviewed and tested again. If a very high percentage of the students are earning 100% on everything, concepts can be enriched with more detail, concepts can be added to the course, more difficult application of concepts can be added. So, wherever a teacher sets a passing percentage is really irrelevant.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-02-27T15:02:22Z
FirstChildVoteTAG: 0
IndexTAG: 2367
TitleTAG: Future Graphs
Would it be possible for future graphs to have horizontal leader lines that extend from left to right across the graph? I find it difficult at times to track an imaginary horizontal axis from left to right on a computer screen (up to which it's difficult to hold a ruler).
If it is possible, it would be one of the small things that would enhance the virtual nature of this course.
UserIdTAG: 1160419
UserNameTAG: nicholasgalano
CreateTimeTAG: 2013-02-26T08:26:14Z
VoteTAG: 7
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: great comment! i have difficulty at exercise 3
FirstChildUserIdTAG: 416422
FirstChildUserNameTAG: edujara
FirstChildCreateTimeTAG: 2013-02-26T16:47:33Z
FirstChildVoteTAG: 0
FirstChildTAG: Lol, I felt like a weirdo holding a piece of paper up to my monitor (you know, so the ruler doesn't accidentally scratch the screen...wait, who are we kidding, I don't have a ruler. Sad face)
FirstChildUserIdTAG: 986805
FirstChildUserNameTAG: perlickm
FirstChildCreateTimeTAG: 2013-02-27T01:33:30Z
FirstChildVoteTAG: 1
IndexTAG: 2368
TitleTAG: How to find percentile and median
I find median is 80.5 it wrong why?
-------------------------------------------------------------
Percentiles Smallest
1% 48 48
5% 59 59
10% 63 63 Obs 28
25% 70 63 Sum of Wgt. 28
50% 80.5 Mean 78.67857
Largest Std. Dev. 13.15732
75% 89 95
90% 95 95 Variance 173.1151
95% 96 96 Skewness -.3056256
99% 100 100 Kurtosis 2.340647
UserIdTAG: 1273583
UserNameTAG: Kachamas044
CreateTimeTAG: 2013-02-26T07:21:57Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Because you are not using the method as described in the lectures. You don't need to use any sort of computer program for this, you don't even need pen and paper. Just follow the lecture.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T07:27:10Z
FirstChildVoteTAG: 5
SecondChildTAG: You can get the sample in video lecture as well as recommended links that is provided in the practice set. If in case still you cannot undertand I suggest you copy the question and paste it in search box in the youtube website I try it before and there are more videos which explains at a very simple approach.
SecondChildUserIdTAG: 1274660
SecondChildUserNameTAG: ridodirected
SecondChildCreateTimeTAG: 2013-02-26T09:17:01Z
SecondChildVoteTAG: 0
IndexTAG: 2369
TitleTAG: Rereading chapter 3
In chapter three, it says "Statistics is the science of drawing conclusions about the world from data. Data are observations (measurements) of some quantity or quality of something in the world." how can this be the case when the data is more prone to not being valid or sound due to Fallacies and other errorsUserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-26T06:24:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: If you believe this, then why are you here studying statistics?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T07:03:38Z
FirstChildVoteTAG: 1
SecondChildTAG: I did not say I believe this.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-26T16:46:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Data is normally correct, its the interpretation of data that is often flawed
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-26T08:11:50Z
FirstChildVoteTAG: 2
FirstChildTAG: Statistics helps us to understand the reality in a precise manner. In other words, the world is reflected in numbers. However,validity of data is a matter of concern. Its validity and reliability depends on various factors. Data collection methods and the time required and spent in data collection is a matter of a concern to a great extent.
FirstChildUserIdTAG: 1064651
FirstChildUserNameTAG: siddhardh13
FirstChildCreateTimeTAG: 2013-02-26T11:17:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Of course there will be errors in data collection and that is studied as a part of statistics too! Error estimation is a part of statistics too.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T11:49:14Z
FirstChildVoteTAG: 0
IndexTAG: 2370
TitleTAG: Dear Prof Ani
Thank you for your introductory week lectures and agreeing to extending the deadlines of all the exercises. It would be nice that solutions for week 1 also be posted with explanations for the exercises.
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-02-26T05:54:45Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They will, once the due date has passed. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T19:20:40Z
FirstChildVoteTAG: 2
SecondChildTAG: mam, are median always the 50th percentiles of a data table or are there any exceptions to this case. if there please list them?
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-02-27T13:33:05Z
SecondChildVoteTAG: 0
IndexTAG: 2371
TitleTAG: Lectures 2.2 and 2.3 Answer
a) Height of -10 to 20 bar = ____________ % per unit
incorrect
Answer:
1.4
UserIdTAG: 1289698
UserNameTAG: smpauline
CreateTimeTAG: 2013-02-26T05:27:10Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: gasp
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T05:31:16Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank God I'm not the only one.
SecondChildUserIdTAG: 1123909
SecondChildUserNameTAG: SPiedt
SecondChildCreateTimeTAG: 2013-02-26T06:27:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Why nobody not use search first? I read again and again the same messages.
P.S. Also check [errata page][1] for this course.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
SecondChildUserIdTAG: 610852
SecondChildUserNameTAG: maMykola
SecondChildCreateTimeTAG: 2013-02-26T07:17:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Personally, my apologies. I didn't see a search button in the user interface before I posted. Sorry.
Jake
SecondChildUserIdTAG: 1284156
SecondChildUserNameTAG: Dispader
SecondChildCreateTimeTAG: 2013-02-26T08:43:55Z
SecondChildVoteTAG: 0
IndexTAG: 2372
TitleTAG: I think the answer to question: a) Height of -10 to 20 bar is wrong
The math should be 14%/(20-(-10))=0.4667%
UserIdTAG: 972440
UserNameTAG: gbma5
CreateTimeTAG: 2013-02-26T05:08:39Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Yes, it should. It has been discussed. Please use the search function, or just look through topics when you post below the problem.
FirstChildUserIdTAG: 83185
FirstChildUserNameTAG: oysteingrondahl
FirstChildCreateTimeTAG: 2013-02-26T06:38:55Z
FirstChildVoteTAG: 1
IndexTAG: 2373
TitleTAG: Some suggestions
First, I wanted to thank you for the great class.
Next, could the exercises be a little more precise on what the result template is? I mean it's just stupid to get downgraded because you wrote 2.3% and not just 2.3.
And aslo there's a mistake in Exercise set 2, problem 3 (b).
Best regards to the lector and fellow students!
UserIdTAG: 1111798
UserNameTAG: kammolch
CreateTimeTAG: 2013-02-26T05:08:23Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: When you're asked "How many percent?" your answer should just be the numerical value, without the sign.
If you're asked how far is it from NY to LA, you can't answer "16532" because no-one knows in what units. If you're asked "How many kilometers is it from NY to LA?", your answer should be "3933".
As far as I know, all answers in this course should be rounded to one decimal, except if we're specifically told otherwise.
FirstChildUserIdTAG: 83185
FirstChildUserNameTAG: oysteingrondahl
FirstChildCreateTimeTAG: 2013-02-26T06:43:46Z
FirstChildVoteTAG: 5
SecondChildTAG: Sorry, but I disagree. Linguistically, an answer should never be invalidated by repeating the requested format. So if I ask how many percent, I expect either ten (in which case there is an implied percent), or 10%.
Course builders: Please consider adding a 'sample answer' or similar to questions to eliminate this vagueness about answer formats. At this point the majority of comments appear to be complaints about how to format the answers such that they are acceptable to the automated system.
It's an interesting course thus far - please fix the answer formats (or clearly tell us what's expected for every question) so we can concentrate on learning about describing statistics.
Thanks :)
SecondChildUserIdTAG: 81246
SecondChildUserNameTAG: bigbro
SecondChildCreateTimeTAG: 2013-02-26T22:52:42Z
SecondChildVoteTAG: 0
IndexTAG: 2374
TitleTAG: quality issues
I hope to pick up this course at a later time, after the bugs get worked out a bit more.
I am finding the opportunities to learn from my mistakes too limited by 1 or 2 submissions, on top of the errors in the practice exercises and the errors in the practice questions from http://statistics.berkeley.edu/. I am just getting confused because I can't check for the correct answer if I miss a question.
UserIdTAG: 369570
UserNameTAG: slromero
CreateTimeTAG: 2013-02-26T04:52:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2375
TitleTAG: Box plots
http://www.brainingcamp.com/resources/math/box-plots/lesson.php
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-02-26T04:46:51Z
VoteTAG: 13
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Sanjay, that was most excellent!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T05:45:42Z
FirstChildVoteTAG: 0
SecondChildTAG: for problem 7 do we have to consider the whiskers as well. please explain.
SecondChildUserIdTAG: 976798
SecondChildUserNameTAG: Vassri
SecondChildCreateTimeTAG: 2013-02-26T22:48:39Z
SecondChildVoteTAG: 0
SecondChildTAG: It's SUPER
SecondChildUserIdTAG: 1236052
SecondChildUserNameTAG: neelam25
SecondChildCreateTimeTAG: 2013-02-28T09:30:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks for this!! Good explanation!
FirstChildUserIdTAG: 1243910
FirstChildUserNameTAG: Diddi
FirstChildCreateTimeTAG: 2013-02-26T19:48:42Z
FirstChildVoteTAG: 1
SecondChildTAG: Bravo Sanjay, you made me score 20
SecondChildUserIdTAG: 702999
SecondChildUserNameTAG: bazim
SecondChildCreateTimeTAG: 2013-02-27T02:30:34Z
SecondChildVoteTAG: 0
IndexTAG: 2376
TitleTAG: Question 2 and 3
lot of silly mistakes! Thank God for 2 submissions for some questions! Wish I had the option for all the questions!!
Question2 and 3-just cannot figure it out!!
UserIdTAG: 1032356
UserNameTAG: Deepasriram
CreateTimeTAG: 2013-02-26T04:32:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2377
TitleTAG: Why isn't it reasonable to assume an even distribution?
When I came to the answer of "yes", I did because I made logical assumptions such as "If a student makes it through the first year of college, he will probably make it all the way" or "If a student enters grade school, he will generally graduate". These sorts of assumptions made sense at the time.
Are we not allowed to make such assumptions without data to back it up?
UserIdTAG: 1160419
UserNameTAG: nicholasgalano
CreateTimeTAG: 2013-02-26T04:24:38Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Think about the interval in part a -- the interval that contains people who completed high school after 12 years of schooling. In that interval, there are likely a lot of people who completed 12 years of high school but not more.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-26T04:35:21Z
FirstChildVoteTAG: 0
FirstChildTAG: Indeed, this interval is a good example. It is just one year wide and considering the variable is discrete (only full years of schooling, not months) it can only be an even distribution. The same for the interval 16-17 years.
I assumed that there were no such discontinuity as end of high school in other interval. Isn't it true?
FirstChildUserIdTAG: 1245404
FirstChildUserNameTAG: jpguisset
FirstChildCreateTimeTAG: 2013-02-26T05:51:08Z
FirstChildVoteTAG: 0
SecondChildTAG: Perhaps it's incorrect to assume that the variable is discrete. Years of schooling is the unit of measurement, but that doesn't meant that schooling can only occur in chunks of 1 year. If we measured height of a person in meters, that doesn't mean that person can only be 1m, 2m, or 3m, with nothing possible in between.
SecondChildUserIdTAG: 161449
SecondChildUserNameTAG: merhutchin
SecondChildCreateTimeTAG: 2013-02-26T17:53:47Z
SecondChildVoteTAG: 0
SecondChildTAG: I think you have to assume that the variable is discrete. While education is a continuous variable, the unit that we were given is years. The value was 'discretized'. The question asks whether or not it's safe to assume a uniform distribution, and since the unit is year, that is the smallest division of bins that we can make. Hence a bin of only 1 year is automatically uniform.
SecondChildUserIdTAG: 597934
SecondChildUserNameTAG: TPerez
SecondChildCreateTimeTAG: 2013-02-27T14:14:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Think about primary school (0 ≤ y < 9 years): the percentage of kids completing the primary is much-much higher than those who do not. I assume that generally 98%+ of kids finish primary school, so the percentage of completing only, say 5 years is insignificant. Thus the distribution cannot be uniform. The same applies to high school and higher education (although the total percentage of drop outs is higher)
(Wish I explained it to myself first before selecting the wrong answer.)
FirstChildUserIdTAG: 1084999
FirstChildUserNameTAG: szilardb
FirstChildCreateTimeTAG: 2013-02-26T15:17:20Z
FirstChildVoteTAG: 0
SecondChildTAG: Fortunately life is not a succession of quizzes. In the real world you would discuss with others the reasons for assuming or not assuming a uniform distribution. The choice depends frequently on the nature of the decisions you plan to make on the basis of the number you get from summarizing the data.
SecondChildUserIdTAG: 1310109
SecondChildUserNameTAG: COELHO50
SecondChildCreateTimeTAG: 2013-02-27T04:39:32Z
SecondChildVoteTAG: 0
IndexTAG: 2378
TitleTAG: Other Resources
Where might I find more practice problems to help strengthen my understanding of histograms. I have done all the pnes in the online textbook.
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-26T04:00:03Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2379
TitleTAG: Where is the online textbook?
Hi everyone,
In the section 2b Lec 2.4 the teacher talked about how to calcul the median or the lower quartile of the histogram of the fluctuation of the value of the gravity from the online textbook just cliking or taping something but mmm how do we get access to this online textbook please :)
And good luck everyone.
UserIdTAG: 1151142
UserNameTAG: Mohamed-Salmane
CreateTimeTAG: 2013-02-26T03:54:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Look on the course wiki under the Resources heading. You'll find the link to the online textbook there.
FirstChildUserIdTAG: 161449
FirstChildUserNameTAG: merhutchin
FirstChildCreateTimeTAG: 2013-02-26T04:01:30Z
FirstChildVoteTAG: 1
FirstChildTAG: Also, we should be reviewing **every** section under Courseware. If you had reviewed the Practice 1 section, you would have seen the link right there at the top. Don't skip any sections by just going straight to the exercises.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T04:07:07Z
FirstChildVoteTAG: 1
SecondChildTAG: Reading the General Course Information should also be on the list of things to do.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-26T04:31:40Z
SecondChildVoteTAG: 0
IndexTAG: 2380
TitleTAG: endpoints too
As peterson said, why can't we have endpoints for each interval as 20-29 30-39 40-49 etc ?
Can we adopt this in a presentation or it would sound as bad statistis interpretation ?
UserIdTAG: 1153259
UserNameTAG: Thiago_NascimentoBR
CreateTimeTAG: 2013-02-26T03:23:01Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 3
FirstChildTAG: Hmm, i think i understood what it means, on a table it will not make any difference at all, but, when you decide to make a histogram using these intervals, the graphic will not be correct, the areas may not represent the original data...
Am i right ?
FirstChildUserIdTAG: 1153259
FirstChildUserNameTAG: Thiago_NascimentoBR
FirstChildCreateTimeTAG: 2013-02-26T04:06:11Z
FirstChildVoteTAG: 0
FirstChildTAG: What happens to the value 29.5 then? We still come to the same need to establish a convention beyond the stated interval for these border cases.
FirstChildUserIdTAG: 217043
FirstChildUserNameTAG: jacksonk
FirstChildCreateTimeTAG: 2013-02-26T05:14:38Z
FirstChildVoteTAG: 0
FirstChildTAG: This is where discrete and continuous variables come in. Since income is continuous the intervals have to be flow into the next higher one and so on.
FirstChildUserIdTAG: 1259097
FirstChildUserNameTAG: SanjoyGupta
FirstChildCreateTimeTAG: 2013-02-26T13:38:29Z
FirstChildVoteTAG: 1
IndexTAG: 2381
TitleTAG: ? on Question 3 a.
I said "Yes" this graph is correct, but that answer was wrong. I cannot see why. If there are 500 plants, then 9:3:3:1 gives 281:94:94:31. Because there are 16 parts so each part = 6.25%. Then multiplying and rounding to the nearest whole number - either we have a plant or we don't, so this variable is quantitative discrete - I get the numbers given. Going to the bar graph, this seems to be what is represented. But the answer is "no". Why?
UserIdTAG: 1119025
UserNameTAG: Dooie
CreateTimeTAG: 2013-02-26T03:06:08Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I got tricked too, because I didn't pay attention to the question. There were 480 plants total (270 m/g, 90 m/r, 90 r/g and 30 r/r) and they introduced the 5th category g/g. So the graph should have a 5th bar....
It does not affect the question #2 because you still have 380 plants with green (m/g, r/g and g/g) and 120 without (m/r, r/r) so the last graph is correct
FirstChildUserIdTAG: 1293145
FirstChildUserNameTAG: amcmd
FirstChildCreateTimeTAG: 2013-02-26T03:50:58Z
FirstChildVoteTAG: 2
SecondChildTAG: Lesson learned for myself: read the problem description more thoroughly.
SecondChildUserIdTAG: 1084999
SecondChildUserNameTAG: szilardb
SecondChildCreateTimeTAG: 2013-02-26T07:40:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Reading the question is important. I made the same mistake
SecondChildUserIdTAG: 194929
SecondChildUserNameTAG: DylanBailey75
SecondChildCreateTimeTAG: 2013-02-26T09:58:17Z
SecondChildVoteTAG: 0
SecondChildTAG: I made the same mistake too. It seems like 3b is testing how properly you read the description, not how well you have understood the topic.
SecondChildUserIdTAG: 1269427
SecondChildUserNameTAG: jessicadehler
SecondChildCreateTimeTAG: 2013-02-26T16:15:15Z
SecondChildVoteTAG: 0
FirstChildTAG: Honor code, all....
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-26T12:15:12Z
FirstChildVoteTAG: 0
IndexTAG: 2382
TitleTAG: Histogram
Hello, everyone. I need help! I can't create a histograma. How should I do?
Thanks.
UserIdTAG: 1031814
UserNameTAG: Marivaldo
CreateTimeTAG: 2013-02-26T02:47:07Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Lecture 2.2: How to draw a histogram
FirstChildUserIdTAG: 682760
FirstChildUserNameTAG: JUANBE
FirstChildCreateTimeTAG: 2013-02-26T19:33:57Z
FirstChildVoteTAG: 1
SecondChildTAG: Good, Juanbe. I have found out it on time and finished my work. Thank you.
SecondChildUserIdTAG: 1031814
SecondChildUserNameTAG: Marivaldo
SecondChildCreateTimeTAG: 2013-02-27T00:43:37Z
SecondChildVoteTAG: 0
IndexTAG: 2383
TitleTAG: Grading method is incorrelative
There exists so many mathematically correct ways of answering those questions.
Grading us under the biasis of hitting and corresponding to a fixed answer is no way of describing the statistical information in the fine exercises.
I tend to propose that the next test should be answered textually in the discussion forum, and graded percentually by the teacher, not the central computer.
UserIdTAG: 935373
UserNameTAG: DKJakobsen
CreateTimeTAG: 2013-02-26T02:27:41Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: Imagine if Answers of 47000 people are getting corrected by two people or even 6 ? It is impossible physically to do it !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T02:35:01Z
FirstChildVoteTAG: 2
FirstChildTAG: 47000 posts? For *every* question? I suggest we immediately start a mental health repair fund for the Profs. Maybe a nice long holiday on a tropical island.
> There exists so many mathematically correct ways of answering those questions.
Doesn't matter. And "so many" is a bit of a stretch. The Profs use the methods that they prefer. We either go along with it, or fail. Quite simple. Just like in real life universities. And sometimes questions relate to a specific method, so you use that method.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T02:41:24Z
FirstChildVoteTAG: 0
FirstChildTAG: I'd love it if we could develop the facility to automate the textual analysis of answers. DKjakobsen is right that some issues raised in the material are subtle enough that it would be better if students could give longer answers. I looked into this, believe me. But it's not available, and as Prasannasimha and ChristineStv have pointed out, our small staff (two assistants and me) grading all those answers would be the path to lunacy for us all, not just the staff.
So, sadly, I have to stick with single-figure answers or multiple choice. It's not my preference. But it's the limit of current technology, at least on this platform. Very likely in a few years we will wonder how we ever lived with such constraints, but at this point that's what we've got. Hang in there, and thanks for your patience and good cheer.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T03:03:36Z
FirstChildVoteTAG: 4
SecondChildTAG: Prof. A, it is very nice to "see" you in these discussions. So maybe you are a real live person and not just recorded voice?
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-26T04:00:36Z
SecondChildVoteTAG: 0
SecondChildTAG: About `such constrains in the current technology` this is quite futuristic like "2001: a space odyssey" where time bounds reality, which means not just that she is a real person but a brillant MIT mind.
SecondChildUserIdTAG: 1277369
SecondChildUserNameTAG: Ascensor
SecondChildCreateTimeTAG: 2013-02-26T19:08:44Z
SecondChildVoteTAG: 0
FirstChildTAG: I can't find any discussion of "Histogram of lengths" either in the course materials or for that matter on the internet. Could we get a little explanation as to what that is about? Thanks! I don't mind losing a few points here and there, but I would like to understand what I did wrong. I'm here to learn the material, not to make a perfect score :)
FirstChildUserIdTAG: 423206
FirstChildUserNameTAG: yperil
FirstChildCreateTimeTAG: 2013-02-26T13:02:43Z
FirstChildVoteTAG: 0
SecondChildTAG: "Histogram of lengths" is not a special term or anything. All it means is that this histogram displays the lengths of different objects that have been measured instead of ages of people or years of education.
Though all the question is asking about is unit conversion which wasn't directly covered in the lectures.
SecondChildUserIdTAG: 398536
SecondChildUserNameTAG: liguoric
SecondChildCreateTimeTAG: 2013-02-26T18:41:17Z
SecondChildVoteTAG: 0
IndexTAG: 2384
TitleTAG: types of variables
for me is difficult understand the differences between the types of variables.... i cant understand the differences between qualitative and categorical, and between quantitative continuous and discrete...
UserIdTAG: 1165114
UserNameTAG: SusanaLilian
CreateTimeTAG: 2013-02-26T02:24:37Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi Susana,
Qualitative and categorical are the same, so no worries there.
Quantitative continuous variables can be any amount apart. Think of an experiment where you're measuring average height. You could have a group of people who are 5'6 3/4", 5'7", 6'4 1/2", 5'11 1/4." They can be any number of inches, or fraction of an inch, apart, because there's no rule saying each person has to grow in increments of one or two inches.
Quantitative discrete variables have to be a set amount apart. So imagine that if instead of measuring height, your measuring how many children are in each class in a school. You can't have 1/2 or 1/4 of a child in a class. So if numbers vary, they have to vary by at least one. You could have 5 classes with 15, 14, 19, 23, and 15 students. But you couldn't have a class with 14.2 students.
That help?
-Jordan
FirstChildUserIdTAG: 930264
FirstChildUserNameTAG: JHWeissmann
FirstChildCreateTimeTAG: 2013-02-26T02:43:43Z
FirstChildVoteTAG: 2
IndexTAG: 2385
TitleTAG: Salman
I just ignored decimal and put round of % answer and don't understand why i got incorrect?
UserIdTAG: 330198
UserNameTAG: ssyed
CreateTimeTAG: 2013-02-26T02:19:20Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: This has been discussed.Use a decimal to single place and do not include % sign.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-26T02:25:13Z
FirstChildVoteTAG: 0
SecondChildTAG: oh..ok... sorry missed that...Thnx
SecondChildUserIdTAG: 330198
SecondChildUserNameTAG: ssyed
SecondChildCreateTimeTAG: 2013-02-26T03:05:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, I ignored the decimal and now learnt the rule for next time. But the exercise was good.
SecondChildUserIdTAG: 1311961
SecondChildUserNameTAG: Small
SecondChildCreateTimeTAG: 2013-02-26T04:53:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here.
SecondChildUserIdTAG: 773396
SecondChildUserNameTAG: Nita8
SecondChildCreateTimeTAG: 2013-02-26T04:54:29Z
SecondChildVoteTAG: 0
IndexTAG: 2386
TitleTAG: Percentage of people who alerted us to the error and provided the correct answer, without reading all the other posts:
97.36
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-26T02:04:58Z
VoteTAG: 16
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: LOL. Welcome to mooc-world. Also known as frustration central.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T02:19:05Z
FirstChildVoteTAG: 0
SecondChildTAG: Massive indeed!!
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-26T03:55:43Z
SecondChildVoteTAG: 0
IndexTAG: 2387
TitleTAG: PROBLEM 2 a real problem
Why cant I use an histogram to guess the percentiles insted of the stem and leaf plot? The results are quite different.
UserIdTAG: 1222835
UserNameTAG: CatonElMenor
CreateTimeTAG: 2013-02-26T01:57:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Because the question is asking you to use the stem and leaf plot. We just can't decide to answer the question that we would have rather been asked. We are not politicians.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T02:13:53Z
FirstChildVoteTAG: 1
SecondChildTAG: ChristineStv LOL that was a good one! :D
CatonElMenor Of course results would be different - histogram is interpreted as continious data with uniform distribution in bars, while steam and leaf plot is discrete. What is that you don't understand, exactly?
SecondChildUserIdTAG: 413698
SecondChildUserNameTAG: YuriV
SecondChildCreateTimeTAG: 2013-02-26T02:46:43Z
SecondChildVoteTAG: 0
FirstChildTAG: The stem and leaf plot has all the details of the data, hence you get percentiles accurately from it. From a histogram, you're estimating the percentiles assuming that the data are evenly distributed within bars (as YuriV has pointed out). The answers are different because in this case the data really aren't distributed uniformly in the histogram intervals that you selected, nor indeed in any reasonable selection of intervals. That's why I asked you to work with the stem and leaf plot. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T03:07:20Z
FirstChildVoteTAG: 8
FirstChildTAG: In fact, the stem and leaf plot has the discrete data already sorted so it is just a matter of counting once you have calculated the position corresponding to the percentile that you are looking for. For me, it is indeed very similar to the excersice 3-10 suggested in the previous practice set. Good luck!
FirstChildUserIdTAG: 534535
FirstChildUserNameTAG: hectorgz
FirstChildCreateTimeTAG: 2013-02-26T15:36:53Z
FirstChildVoteTAG: 1
IndexTAG: 2388
TitleTAG: How many were in their thirties?
I assume that two thirds of the people between 30 and 45 were in their thirties.
UserIdTAG: 935373
UserNameTAG: DKJakobsen
CreateTimeTAG: 2013-02-26T01:37:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: people in their thirties are between 30-40 years old.
FirstChildUserIdTAG: 46420
FirstChildUserNameTAG: passoret
FirstChildCreateTimeTAG: 2013-02-26T03:51:57Z
FirstChildVoteTAG: 0
FirstChildTAG: It means the percentage between age 30 to 40 from the interval of 30-45, so we get 10/15 and simply multiply it with 19.8%=13.2%
FirstChildUserIdTAG: 1274748
FirstChildUserNameTAG: kusumawati
FirstChildCreateTimeTAG: 2013-02-26T03:53:40Z
FirstChildVoteTAG: 1
FirstChildTAG: Common folks. For goodness sake, you're are not supposed to be posting answers to the test questions here in the discussion forum. Please take a moment to familiarize yourselves with the rules here, and for that matter, simply exercise some common sense. Obviously it's quite inappropriate to post answers to the questions in an exercise that is being graded!
FirstChildUserIdTAG: 1295616
FirstChildUserNameTAG: RobertMWright
FirstChildCreateTimeTAG: 2013-02-26T11:16:26Z
FirstChildVoteTAG: 5
IndexTAG: 2389
TitleTAG: Bargraph in RStudio
# Let's create an empty variable
Colours <- NULL
# Colours' names
Colours$Colour <- c("Red", "Blue", "Green")
# Number of people
Colours$NumberOfPeople <- c(30, 10, 10)
# Let's create a data frame from the list:
# it's more convinient to view as a table
Colours <- data.frame(Colours)
# Let's create a barplot
barplot(Colours$NumberOfPeople, names.arg = Colours$Colour, main = "Distribution of picked colours", xlab = "Colour", ylab = "Number of people", col = c("red", "blue", "green"))
# Let's add a percent of people picked colours into our table
Colours$Percent <- paste(round(100 * Colours$NumberOfPeople / sum(Colours$NumberOfPeople)), "%", sep = "")
# and view it
rstudio::viewData(Colours)
![Barplot in RStudio][1]
[1]: http://savepic.ru/4130051.png
UserIdTAG: 209516
UserNameTAG: Andrey_K
CreateTimeTAG: 2013-02-26T01:32:07Z
VoteTAG: 4
CoursewareTAG: Section 1: Introduction / Lec 1.3. Bar graphs: describing categorical data
NumberOfReplyTAG: 2
FirstChildTAG: Yup. I use R. Why is someone who can do R programming taking an intro Stat class? Not that I mind; just curious. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-26T02:50:24Z
FirstChildVoteTAG: 5
SecondChildTAG: Ability to program with R does not mean automatic comprehension of statistics. I am just a physician who tries to make myself familiar with this subject a little. :) A post above is just a note on margins.
SecondChildUserIdTAG: 209516
SecondChildUserNameTAG: Andrey_K
SecondChildCreateTimeTAG: 2013-02-26T03:49:15Z
SecondChildVoteTAG: 0
FirstChildTAG: It will be very useful to add some R solutions to this course
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-02-26T20:06:13Z
FirstChildVoteTAG: 1
IndexTAG: 2390
TitleTAG: Heading of lecture 2.4
Hi,
Can somebody tell me heading of lecture 2.4. I think I am missing this part. Practice exercise 3 says from the lec 2.4 data find the percentile . I am not able to do it. Can anybody help me here??
UserIdTAG: 1177608
UserNameTAG: Gayatris
CreateTimeTAG: 2013-02-26T01:05:13Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: Go to section 2b and the data is in the Lec 2.4 video.
FirstChildUserIdTAG: 1298590
FirstChildUserNameTAG: DancingShiva
FirstChildCreateTimeTAG: 2013-02-26T01:08:30Z
FirstChildVoteTAG: 0
SecondChildTAG: When I go to section 2b, I can only see the video 2.5 and not 2.4.
SecondChildUserIdTAG: 1177608
SecondChildUserNameTAG: Gayatris
SecondChildCreateTimeTAG: 2013-02-26T01:15:40Z
SecondChildVoteTAG: 0
SecondChildTAG: At the top there is a bar with two arrows on either side and blocks inside which can be individualy cliocked.Click on onthe non highlighted one to move between videos.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-26T01:38:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Hello there, Prasannasimha - do you have some beautiful words for us today? (Please???)
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-26T03:51:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you.
SecondChildUserIdTAG: 1177608
SecondChildUserNameTAG: Gayatris
SecondChildCreateTimeTAG: 2013-02-26T13:43:13Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you! This class will be much easier now that I know how to access all of the lectures! I watched lecture 2.4 and had no idea where to find 2.5
SecondChildUserIdTAG: 1143871
SecondChildUserNameTAG: CarolPeterman
SecondChildCreateTimeTAG: 2013-02-27T07:34:17Z
SecondChildVoteTAG: 0
FirstChildTAG: Lecture 2.4 is the Video in Section 2b. Hope this helps.
FirstChildUserIdTAG: 1242910
FirstChildUserNameTAG: sleekchic
FirstChildCreateTimeTAG: 2013-02-26T13:32:59Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you.
SecondChildUserIdTAG: 1177608
SecondChildUserNameTAG: Gayatris
SecondChildCreateTimeTAG: 2013-02-26T13:44:52Z
SecondChildVoteTAG: 0
IndexTAG: 2391
TitleTAG: intervals, bar graph , and histogram
If we had evenly spaced intervals, would it ever matter which graphical representation we used in regard to a bar graph and histogram.
UserIdTAG: 1202785
UserNameTAG: sjmadden
CreateTimeTAG: 2013-02-26T01:04:30Z
VoteTAG: 1
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 2
FirstChildTAG: I think the basic difference between a bar chart and a histogram is that the bars represent categorical data and a histogram deals with continuous quantitative data.
I think our class is progressing in a way that gets us ready to look for trending in the data (remember very early in the first lecture the instructor mentioned seeing a curve in the example).
Trends are the core of statistics, and we are gearing up to learn more about them by understanding histograms, which convey more data (information) than bar charts.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-26T03:49:55Z
FirstChildVoteTAG: 2
FirstChildTAG: actually, I think that if the intervals are evenly spaced, then a histogram is more or less a bar graph, correct me if I'm wrong.
FirstChildUserIdTAG: 838733
FirstChildUserNameTAG: Ronnicus
FirstChildCreateTimeTAG: 2013-03-09T21:43:10Z
FirstChildVoteTAG: 1
IndexTAG: 2392
TitleTAG: histograms and bar Charts
Until this class I thought histograms and bar charts were the same ... I am enjoying the lesson. Thank you.
UserIdTAG: 1202785
UserNameTAG: sjmadden
CreateTimeTAG: 2013-02-26T01:01:16Z
VoteTAG: 4
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 0
IndexTAG: 2393
TitleTAG: Practice for exercise set #2
Where do you find the "Exercise 3-6" referenced in the Practice for Exer set #2
UserIdTAG: 906316
UserNameTAG: rbudi
CreateTimeTAG: 2013-02-26T00:27:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2394
TitleTAG: Practice exercise - histogram
Hi. In practice exercise a) Height of -10 to 20 bar = ____________ % per unit
my answer was 14%/30=0.466.
As I understand it, from -10 to 20 is 30 units not 10 as the explanation says. What did I misunderstand?
UserIdTAG: 1001073
UserNameTAG: lrodz
CreateTimeTAG: 2013-02-26T00:14:30Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Nothing. There are dozens, if not hundreds, of posts about this. It helps to look at other posts before posting. It is an error on their side.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T00:16:53Z
FirstChildVoteTAG: 0
IndexTAG: 2395
TitleTAG: set your calculator to NOT round up
I did not realize it while taking the test but the calculator I was using was automatically rounding up. Which in turn was giving me an incorrect answer for the percentage of red/green plants.
UserIdTAG: 1179590
UserNameTAG: TigressSky
CreateTimeTAG: 2013-02-26T00:04:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2396
TitleTAG: I like
I like the course but i have problems to manager the schedule, but is interesting the schedule
UserIdTAG: 1060786
UserNameTAG: Julieth1
CreateTimeTAG: 2013-02-26T00:02:43Z
VoteTAG: 0
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 0
IndexTAG: 2397
TitleTAG: problem
Thee problem 2 (a) the answer I gave is 0.18,I want to know if we have to round it up to 0.19 because my answer was wrong.
UserIdTAG: 1093938
UserNameTAG: Douna
CreateTimeTAG: 2013-02-25T23:56:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You're almost there!! Read the questions carefully.
0.18.. is how many percent? :))
FirstChildUserIdTAG: 267427
FirstChildUserNameTAG: Davorin
FirstChildCreateTimeTAG: 2013-02-26T00:04:57Z
FirstChildVoteTAG: 0
SecondChildTAG: you forgot something that is a percent %!!!
SecondChildUserIdTAG: 1165114
SecondChildUserNameTAG: SusanaLilian
SecondChildCreateTimeTAG: 2013-02-26T02:25:29Z
SecondChildVoteTAG: 0
IndexTAG: 2398
TitleTAG: [staff] Practice for Exercise Set 2
There should be a mistake in the following exercise from the practice set:
a) Height of -10 to 20 bar = ____________ % per unit
The correct answer is given as 14%/10=1.4%; whereas, I think, it should really be 14%/(20-(-10))=14%/30=0.47% per unit of horizontal axis.
UserIdTAG: 252722
UserNameTAG: vaboro
CreateTimeTAG: 2013-02-25T23:44:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I do not understand this exercise.Can I have some helpbecause I was totally wrong in both.
FirstChildUserIdTAG: 1093938
FirstChildUserNameTAG: Douna
FirstChildCreateTimeTAG: 2013-02-25T23:58:12Z
FirstChildVoteTAG: 0
SecondChildTAG: This exercise is actually very easy if one follows the online text and listens to lectures. Everything is explained in detail. So, the (a) asks for density of the bin, right, and the width of the interval from -10 to 20 is 20-(-10) = 30 observations, the total number of observations within this bin is 14 out of 100, hence 14%; therefore, the density of this bin should be 14%/30 observations(units)=0.47% per unit (of the horizontal axis; the horizontal axis contains the number of observations).
SecondChildUserIdTAG: 252722
SecondChildUserNameTAG: vaboro
SecondChildCreateTimeTAG: 2013-02-26T00:16:28Z
SecondChildVoteTAG: 0
IndexTAG: 2399
TitleTAG: exercise set 2
what is the correct answers for problem 5,6,7 ? i need explanation thanks
UserIdTAG: 984053
UserNameTAG: Okheir82
CreateTimeTAG: 2013-02-25T23:08:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: How to get this answer is explained really well in the video 2.3!
FirstChildUserIdTAG: 267427
FirstChildUserNameTAG: Davorin
FirstChildCreateTimeTAG: 2013-02-25T23:41:57Z
FirstChildVoteTAG: 0
SecondChildTAG: thz video 3 is not disponible for me since I started
SecondChildUserIdTAG: 1093938
SecondChildUserNameTAG: Douna
SecondChildCreateTimeTAG: 2013-02-26T00:51:39Z
SecondChildVoteTAG: 0
IndexTAG: 2400
TitleTAG: Problem with exercise in link?
In the link under Lec 2.5, I think that there is a problem with exercise 3-9. Using the histogram in Figure 3.2, if I enter -160 in the first box and -43 in the second, it gives me an area of exactly 50%, but when I enter that answer (-43) in the second question of exercise 3.9 calling for the 50th percentile, it marks me wrong. It says that the answer should be in the range of -47.47 to -46.53, but when I enter either of these into the histogram, the area is significantly smaller than 50%. Is it just me, or is anyone else getting this problem? Thanks for your input!
UserIdTAG: 1173445
UserNameTAG: TheBookworm
CreateTimeTAG: 2013-02-25T22:53:40Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 3
FirstChildTAG: same observation on my side
FirstChildUserIdTAG: 1231201
FirstChildUserNameTAG: wolkoe
FirstChildCreateTimeTAG: 2013-02-25T23:13:23Z
FirstChildVoteTAG: 0
FirstChildTAG: Its the same problem I experienced. The 25th, 90th and 90.5th are correct but the 50th, 65th and 75th percentiles just keep coming up as wrong answers and am at a loss as to how come. Have done the calculations over and over again.
FirstChildUserIdTAG: 1113204
FirstChildUserNameTAG: Laeida
FirstChildCreateTimeTAG: 2013-02-26T12:40:29Z
FirstChildVoteTAG: 3
FirstChildTAG: I experienced the same problem.
FirstChildUserIdTAG: 682727
FirstChildUserNameTAG: CediCed
FirstChildCreateTimeTAG: 2013-02-27T04:26:12Z
FirstChildVoteTAG: 0
IndexTAG: 2401
TitleTAG: Set 2/Problem 2
It is not clear, but the answer is NOT expecting a % sign...if added answer is considered wrong
UserIdTAG: 1212655
UserNameTAG: Doug1776
CreateTimeTAG: 2013-02-25T22:37:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: It's quite clear, actually.
FirstChildUserIdTAG: 267427
FirstChildUserNameTAG: Davorin
FirstChildCreateTimeTAG: 2013-02-25T23:48:28Z
FirstChildVoteTAG: 2
FirstChildTAG: -sigh- Okay, I'll bite....How is it quite clear?
FirstChildUserIdTAG: 1212655
FirstChildUserNameTAG: Doug1776
FirstChildCreateTimeTAG: 2013-02-26T20:33:45Z
FirstChildVoteTAG: 0
SecondChildTAG: You will notice that there is significant confusion about this issue if you review the Discussions. So perhaps it is clear to you, but not all?
SecondChildUserIdTAG: 1212655
SecondChildUserNameTAG: Doug1776
SecondChildCreateTimeTAG: 2013-02-26T20:40:50Z
SecondChildVoteTAG: 0
IndexTAG: 2402
TitleTAG: add 20 green/green to 480 to make 500
There is no green/green category, I suppose they meant red/red....
-D
UserIdTAG: 453524
UserNameTAG: davewil90
CreateTimeTAG: 2013-02-25T22:34:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No. They mean Green/Green.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T22:35:12Z
FirstChildVoteTAG: 0
IndexTAG: 2403
TitleTAG: Problem 2
Please, explain me how you get the results . I tried 2 slightly different approaches and both were wrong. Thank you.
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-02-25T22:24:44Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: For first part of question 1 your trying to get 25% so 0-5 and 5-15 have 13.3 and 6.6%, which equals 19.9, so the next 5.1% comes from the next interval 15-20, which has 7.1%, so you have to divide 5.1\7.1 and multiply by the difference in the interval
FirstChildUserIdTAG: 844365
FirstChildUserNameTAG: jeremyliver
FirstChildCreateTimeTAG: 2013-02-25T22:45:09Z
FirstChildVoteTAG: 0
SecondChildTAG: dear jeremyliver, you speak about problem 1, but the question is about problem 2. The same about me, both my answers were wrong. Can somebody help to find an explanation of this problem in a forum?
SecondChildUserIdTAG: 903016
SecondChildUserNameTAG: Sasha_K
SecondChildCreateTimeTAG: 2013-02-26T00:43:24Z
SecondChildVoteTAG: 0
SecondChildTAG: In this course n-th percentile for discrete data is defined as the element of the data set, that is >= that n% of the set (watch Lect 2.5 for examples) - that's not how it's usually defined for discrete data, so it got me confused too.
If that is clear (and examples in Lect 2.5 - that looks pretty like Problem 2 - aren't helpful), but you are still getting wrong answers, then please can you tell more about how are you trying to solve Problem 2?
SecondChildUserIdTAG: 413698
SecondChildUserNameTAG: YuriV
SecondChildCreateTimeTAG: 2013-02-26T02:33:47Z
SecondChildVoteTAG: 0
SecondChildTAG: Hey sorry i didnt realize it was question 2, 2 is simpler really, your going to add up all the numbers in the boxplot, then for each part of the question get the number that refers to the percentile, so for instance if there are 35 numbers in the boxplot and your trying to get 25% then multiply .25 by 35 and get a number, this is the number in the list that will be equivalent to that percentile, remember though that if the number has an additional part eg 11.1 use the 12th number as the percentile
SecondChildUserIdTAG: 844365
SecondChildUserNameTAG: jeremyliver
SecondChildCreateTimeTAG: 2013-02-26T14:13:52Z
SecondChildVoteTAG: 0
IndexTAG: 2404
TitleTAG: Some explanations about the practice exercise set 1
I do not understand why my answers 11.11 percent for the percentage of seniors and 22.22percent for the percentage of fresmen is wrong?somebody give me some explanations,because the answers are 11.1 and 22.2 percent which is the same I think
UserIdTAG: 1093938
UserNameTAG: Douna
CreateTimeTAG: 2013-02-25T22:22:58Z
VoteTAG: 8
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is most certainly not the same!
I did the same mistake, though. Don't worry. The instructions for the real exercise sets are better.
FirstChildUserIdTAG: 267427
FirstChildUserNameTAG: Davorin
FirstChildCreateTimeTAG: 2013-02-25T23:45:25Z
FirstChildVoteTAG: 2
SecondChildTAG: It also doesn't accept the answer if you put in the % sign.
SecondChildUserIdTAG: 1271516
SecondChildUserNameTAG: DawnSofie
SecondChildCreateTimeTAG: 2013-02-26T00:40:34Z
SecondChildVoteTAG: 0
IndexTAG: 2405
TitleTAG: HELP!
PLEASE HELP ME !HOW CAN I SOLVE PROBLM 3 & 4 ??! EXCPLAIN IT TO ME !!
UserIdTAG: 920087
UserNameTAG: Areejo33
CreateTimeTAG: 2013-02-25T22:12:10Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Aree
For question 3 your just reading the boxplot like a normal graph, so for first part just look to see which experiment has the highest median, which is the line in the box, and second part do the same, looking for an experiment with the values they mentioned.
For question 4, im not sure how to explain it without giving you the answer, but just read the question carefully and look at the two boxplots, and remember what each point in the box plot represents, median, lower and upper quartiles, and the max and minimum values, what effect will these different values have on a peak?
FirstChildUserIdTAG: 844365
FirstChildUserNameTAG: jeremyliver
FirstChildCreateTimeTAG: 2013-02-25T22:22:09Z
FirstChildVoteTAG: 0
SecondChildTAG: In question 3 and 4.. Are we supposed to consider the peak values as well to answer the questions and esp. in Q4
SecondChildUserIdTAG: 976798
SecondChildUserNameTAG: Vassri
SecondChildCreateTimeTAG: 2013-02-26T02:09:15Z
SecondChildVoteTAG: 0
SecondChildTAG: For question 3 & 4 just answer what is being as for ... Like in problem 3.a you were only ask the lowest median measurement by comparing the 5 experiments in the diagram and its very obvious without doing any computation you can easily identify the lowest median by just looking at the box plot of the 5 experiments and same thing with the other question at the bottom.
SecondChildUserIdTAG: 1274660
SecondChildUserNameTAG: ridodirected
SecondChildCreateTimeTAG: 2013-02-26T09:09:32Z
SecondChildVoteTAG: 0
SecondChildTAG: thanQ i got it true :)
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-02-26T20:17:43Z
SecondChildVoteTAG: 0
SecondChildTAG: For problem 3, we have to compare median measurements of all 5 experiments and you could find lowest median measurement.
For problem 4,in comparison experiment 4 & 5, find whisker line from upper quartile of experiment 5 is taller than experiment 4.
SecondChildUserIdTAG: 827695
SecondChildUserNameTAG: hhayedr
SecondChildCreateTimeTAG: 2013-02-27T04:00:36Z
SecondChildVoteTAG: 0
IndexTAG: 2406
TitleTAG: to help us
As a comments, i think it´s better write the unit of the variables, because it´s easier to classify. I had problems with that and i use to do this kind of thinks. It´s in my opinion, I hope wasn´t a problem about my comments. It was very useful exercise...
UserIdTAG: 1219973
UserNameTAG: micaelacerezoli
CreateTimeTAG: 2013-02-25T21:56:02Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2407
TitleTAG: Where do I find the solutions for the exercise sets after due date?
Are those being posted somewhere?
Thanks!
UserIdTAG: 1141415
UserNameTAG: Humble_learner
CreateTimeTAG: 2013-02-25T21:42:00Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: They will appear in the exercise page itself, just like in the Practice Sets(the "Show Answer" button).
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T21:56:08Z
FirstChildVoteTAG: 0
SecondChildTAG: thats strange because they won't appear
SecondChildUserIdTAG: 1141415
SecondChildUserNameTAG: Humble_learner
SecondChildCreateTimeTAG: 2013-02-26T10:30:41Z
SecondChildVoteTAG: 0
FirstChildTAG: This is all explained in the course policies document.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T22:13:26Z
FirstChildVoteTAG: 0
IndexTAG: 2408
TitleTAG: what's highest score of ES1
Got 9 out of 10 correct :)
UserIdTAG: 1053569
UserNameTAG: nicola2003
CreateTimeTAG: 2013-02-25T21:31:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2409
TitleTAG: I can't find a correct histogram in problem 3b.
The first one is definitely out of question.
The second and third ones have only 5 bars and the units of the heights seem all wrong. I only see three histograms in this problem.
It doesn't make sense to me.
UserIdTAG: 1106581
UserNameTAG: Beann
CreateTimeTAG: 2013-02-25T21:26:49Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: look at the vertical axis...
which one is correct?
FirstChildUserIdTAG: 1202828
FirstChildUserNameTAG: zam1991
FirstChildCreateTimeTAG: 2013-02-25T21:28:52Z
FirstChildVoteTAG: 3
FirstChildTAG: I actually agree, you can see right histogram because of the label of vertical axis, but heights and bars are all wrong
FirstChildUserIdTAG: 769377
FirstChildUserNameTAG: Magnalle
FirstChildCreateTimeTAG: 2013-02-26T03:24:48Z
FirstChildVoteTAG: 4
FirstChildTAG: Agreed. I got marked wrong when I selected the first and the second. Didn't pick the third because the y-axis is NOT density. She made this quite clear in the lecture. But if the third choice is the right answer, then the y-axis was mislabeled and this problem should be thrown out for lack of clarity. This is similar to her point about requiring correct labeling of units. Click on the plus for this comment if you agree!
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-02-26T17:34:21Z
FirstChildVoteTAG: 3
SecondChildTAG: Actually, she made it quite clear the y-axis IS density. This is clear since the units are compound (if the horizontal axis is in x units, the vertical unit is in y units per x units, like people per $1000 in income: when the area is found by multiplying the two axes together, the units cancel out to give only the number of people in that range). Remember, the method a histogram provides information is very different from the method a regular bar graph does so.
SecondChildUserIdTAG: 1304034
SecondChildUserNameTAG: AndrewTung
SecondChildCreateTimeTAG: 2013-02-26T21:09:45Z
SecondChildVoteTAG: 0
SecondChildTAG: I disagree. Look carefully. The answer c is not the correct one. There is no correct answer in the question.
SecondChildUserIdTAG: 1106581
SecondChildUserNameTAG: Beann
SecondChildCreateTimeTAG: 2013-03-02T23:27:13Z
SecondChildVoteTAG: 0
IndexTAG: 2410
TitleTAG: Problem 4: a & b
Those are tricky questions....please analyzed them carefully before stating your answers...I got them wrong because I didn't see all options before stating my answer. Ghrrr...I'm mad at me :( hehehe
UserIdTAG: 1131693
UserNameTAG: Catica
CreateTimeTAG: 2013-02-25T21:12:04Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Which is the entry age to school,is it necessary in order to know the interval?
FirstChildUserIdTAG: 1158693
FirstChildUserNameTAG: dabad
FirstChildCreateTimeTAG: 2013-02-26T13:50:53Z
FirstChildVoteTAG: 0
IndexTAG: 2411
TitleTAG: Terrible usability to not include the data or at least direct slides to the data
This violates a basic heuristic of recognition rather than recall. The data should be provided here or linked to.
UserIdTAG: 1260235
UserNameTAG: ashleyroe
CreateTimeTAG: 2013-02-25T21:02:27Z
VoteTAG: 8
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: Recall? They tell you where the data is! No recall needed, just an extra click or two on your part. Maybe they are treating you like an adult and not a child.
But from what I've seen in my limited time here, I think child describes far too many.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T21:07:10Z
FirstChildVoteTAG: 1
SecondChildTAG: The Data is in the lecture slides, which is linked underneath the video 2.4
SecondChildUserIdTAG: 1125759
SecondChildUserNameTAG: John-Jack
SecondChildCreateTimeTAG: 2013-02-26T18:10:36Z
SecondChildVoteTAG: 0
FirstChildTAG: The Data is in the lecture slides, which is linked underneath the video 2.4
FirstChildUserIdTAG: 1125759
FirstChildUserNameTAG: John-Jack
FirstChildCreateTimeTAG: 2013-02-26T18:10:56Z
FirstChildVoteTAG: 0
IndexTAG: 2412
TitleTAG: Error
Bad
UserIdTAG: 1107978
UserNameTAG: betoagto
CreateTimeTAG: 2013-02-25T20:58:37Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 0
IndexTAG: 2413
TitleTAG: Please don't count "empty" submissions...
Don't know if this has happened to anyone else, but I ve lost my first answer in which I pressed "FinalCheck" without noticing that none of the answers was actually selected although I thought I checked a box...
I was THAT sure I was right, that I made 2 lightning-fast clicks and got a nice red X in reply... :)
UserIdTAG: 902212
UserNameTAG: trigeor
CreateTimeTAG: 2013-02-25T20:30:56Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The same thing happened to me in Exercise 1. I got 3 "empty" submissions since it is my first time to use this technology. LOL Well that's a lesson learned for me.
FirstChildUserIdTAG: 1188300
FirstChildUserNameTAG: cqprivado
FirstChildCreateTimeTAG: 2013-02-25T22:13:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Yeah, only 1 attempt is quite cruel - I spend a few minutes even for the most obvious answers, nervously checking for mismatches, inaccurate clicks, missed checkboxes etc :)
SecondChildUserIdTAG: 413698
SecondChildUserNameTAG: YuriV
SecondChildCreateTimeTAG: 2013-02-26T02:50:35Z
SecondChildVoteTAG: 0
IndexTAG: 2414
TitleTAG: Lectures issued
If they are done, wouldn't it be nice to have them released? Cause maybe some have more free times now than they will have in let's say 4 weeks from now.
thanks.
UserIdTAG: 22929
UserNameTAG: kraster
CreateTimeTAG: 2013-02-25T20:27:11Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2415
TitleTAG: Lecture 2.4
I cannot find lecture 2.4. When I click lec 2.4-2.5 the 2.5 lecture starts immediately . Has anybody had similar problem?
UserIdTAG: 1177608
UserNameTAG: Gayatris
CreateTimeTAG: 2013-02-25T20:20:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Have you tried clicking the bar at the top of the lecture? It should be broken into 2 separate areas, one for each lecture. The one being played is shown in white. Have you tried clicking the greyed-out one?
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T20:56:57Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you I will check
SecondChildUserIdTAG: 1177608
SecondChildUserNameTAG: Gayatris
SecondChildCreateTimeTAG: 2013-02-26T13:46:37Z
SecondChildVoteTAG: 0
IndexTAG: 2416
TitleTAG: Exercise set 3 part 4
Please what do they mean by the peak in that question?
UserIdTAG: 1187096
UserNameTAG: Chinonso411
CreateTimeTAG: 2013-02-25T20:15:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Go back to any of the lecture slides that have the Histogram. The peak is the tallest bar.
Also, the lower quartile is the 25th percent quartile. The upper quartile is the 75th percent quartile. The lower quartile doesn't mean that it is the lowest or the minimum. The upper quartile doesn't mean that it is the maximum.
The peak is the maximum limit of the data. Hint - look at the whiskers of the box plot.
Hope this helps.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-25T20:30:45Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks.
SecondChildUserIdTAG: 1187096
SecondChildUserNameTAG: Chinonso411
SecondChildCreateTimeTAG: 2013-02-25T22:29:20Z
SecondChildVoteTAG: 0
IndexTAG: 2417
TitleTAG: Unable to play mp4's at work
Can the videos be provided in a format compatible with Windows Media Player? This is my only option at work for playing downloaded videos and it seems to be unable to play mp4 files.
UserIdTAG: 1013909
UserNameTAG: sarah_s
CreateTimeTAG: 2013-02-25T20:14:35Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Can´t you convert them to mp3? There is a free site on line to do that: http://www.convertfiles.com/
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-25T20:21:13Z
FirstChildVoteTAG: 1
SecondChildTAG: mp4 is video, mp3 is audio, so, definitely not.
sarah, unless you are *really* restricted at work, you should be able to download and use [VLC Portable][1].
It will play almost anything you throw at it and doesn't require installation.
[1]: http://portableapps.com/apps/music_video/vlc_portable
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-25T21:41:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks very much! I will give it a shot.
SecondChildUserIdTAG: 1013909
SecondChildUserNameTAG: sarah_s
SecondChildCreateTimeTAG: 2013-02-26T21:04:34Z
SecondChildVoteTAG: 0
IndexTAG: 2418
TitleTAG: exercise 3
Here is another distribution you have seen before; it is the distribution of scores discussed in Lecture 2.1.
4|8
5|9
6|3337
7|0002355
8|01234788
9|015556
10|0
: 6.0 POINTS
Each part is worth 2 points.
a) Use the stem and leaf plot to find the 20th percentile:
b) Use the stem and leaf plot to find the median:
c) Use the stem and leaf plot to find the 90th percentile:
UserIdTAG: 1302054
UserNameTAG: tayyabarawjani25
CreateTimeTAG: 2013-02-25T19:30:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: i can not get how to solve them.. em getting my answers wrong..
please help me..
i want some guidance
FirstChildUserIdTAG: 1302054
FirstChildUserNameTAG: tayyabarawjani25
FirstChildCreateTimeTAG: 2013-02-25T19:31:31Z
FirstChildVoteTAG: 1
SecondChildTAG: tay, you can solve this probleme by writing down all the numbers in increasing order let's say 48, 59, 63,63,63,67,....,96,100. from this list you can take the 20th percentile (count of numbers * 0.2). this will give you the position of the 20th percetile. the median is the 50th percentile, and so on. Hope that helps you solve the problem.
SecondChildUserIdTAG: 46420
SecondChildUserNameTAG: passoret
SecondChildCreateTimeTAG: 2013-02-25T20:12:21Z
SecondChildVoteTAG: 0
FirstChildTAG: Taya, for the stem and leaf chart, the number to the Left side of the dash is the stem. And the number to the Right side of the dash is the leaf. So if you want to know how many data there are in the Stem and Leaf chart, you simply count the leaves for each stem.
Ex:
5 | 2 3 4
In this example, 5 is the stem because it is on the Left side of the vertical dash. 2 , 3 , and 4 are the leaves because they are on the Right side of the dash. Lets assume that 5 stands for 50. So instead of writing 52, 53, and 54. We use the Stem and Leaf chart and only have to write 5 once. so
5| 2 3 4 -----is the same as 52, 53, and 54. For this stem and leaf chart we have 3 entries (52, 53, and 54).
Now you can use this to help you count how many entries there are in the Stem and Leaf chart in the Exercise. Then use the technique by Passoret to answer the questions.
20th percentile is 20%. Example: What is 20% of 10 entries? The answer is 2. Then you count, entry 1, entry 2 in the data set that you have rearrange in increasing order. Whatever the number that is in entry 2, that is your answer.
Example 2 : What is 20% of 11 entries? The answer is 2.2. You count entry 1, entry 2, in the data set that you have rearrange in increasing order. Whatever the number that is in entry 2.2, that is your answer. However, there are no entry 2.2. So you go to the next one and that is entry 3. Whatever the number in entry 3 is the answer.
I hope this helps. If it doesn't, please go back and review Lecture 4 for the stem and leaf and lecture 8 for how to get the data for each percentile.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-25T20:56:55Z
FirstChildVoteTAG: 0
IndexTAG: 2419
TitleTAG: Problem 1 (a) and (d)
I selected quantitative discrete because I thought income is generally rounded to the nearest dollar and forearms would be measured to the nearest inch. I even seem to recall the lecture mentioned rounded measurements.
UserIdTAG: 916746
UserNameTAG: RonDallmeier
CreateTimeTAG: 2013-02-25T19:13:05Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: This is where we need to review ALL the resources available to us. In the case of income, the sticigui textbook was referenced in the first Practice, and clearly explains income specifically.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T19:35:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Where in the textbook do you mean? Income is listed as a quantitative variable in the graphic, but that doesn't differentiate discrete and continuous. In fact, on the practice question, the correct answer for "per capita income in us dollars" was quantitative discrete.
I, too, am confused.
SecondChildUserIdTAG: 833174
SecondChildUserNameTAG: MES93
SecondChildCreateTimeTAG: 2013-02-25T20:54:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Yeah, I answered the income one as 'quantitative discrete' because I was thinking that it could only be measured in pre-defined amounts - the lowest unit of currency.
I think the question could have been worded better, possibly income per person or income category.
No big deal though, I understand there is some subjectivity in these labels.
SecondChildUserIdTAG: 1297672
SecondChildUserNameTAG: SFGeoff
SecondChildCreateTimeTAG: 2013-02-26T04:31:11Z
SecondChildVoteTAG: 0
SecondChildTAG: By the way - I had read the sticigui section on income specifically, and just re-read it. I guess the point is income can be more randomly distributed, as opposed to within a pre-defined set of boundaries. Kind-of, sort-of makes more sense to me now.
SecondChildUserIdTAG: 1297672
SecondChildUserNameTAG: SFGeoff
SecondChildCreateTimeTAG: 2013-02-26T04:36:34Z
SecondChildVoteTAG: 0
IndexTAG: 2420
TitleTAG: hi more information i need
hi
i would like more information to be added on discrimination between different types of stat. i know the material contain a lot but still i feel like missing some points specially about qualitative ordinal and quantitative discrete , and continuous or add source
one last thing i don't know whether the attached material we should go all through it or certain parts plz verify more
thanks in advance
UserIdTAG: 1292897
UserNameTAG: DrMahmut
CreateTimeTAG: 2013-02-25T19:09:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: DrMahmut - very good example on qualitative ordinal and quantitative discrete here, from the online textbook: http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm
FirstChildUserIdTAG: 46420
FirstChildUserNameTAG: passoret
FirstChildCreateTimeTAG: 2013-02-25T20:16:33Z
FirstChildVoteTAG: 0
IndexTAG: 2421
TitleTAG: Histogram
Hello ma'am,
How do you get these kind of histogram with varied width of the interval?
I tried it in MS excel its evenly distributed.
regards,
Alban
UserIdTAG: 1151604
UserNameTAG: albanmathias
CreateTimeTAG: 2013-02-25T19:04:48Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 1
FirstChildTAG: I have the same question too. Can this kind of histogram be drawn using MS Excel? But I haven't attempt yet.
FirstChildUserIdTAG: 1082215
FirstChildUserNameTAG: Ayee
FirstChildCreateTimeTAG: 2013-02-27T03:32:50Z
FirstChildVoteTAG: 0
IndexTAG: 2422
TitleTAG: Problem in saving the answers
After solving the problems Iclick on Final Check, but nothing happens. The result Can't be saved. Kindly guide me.
UserIdTAG: 838200
UserNameTAG: soumenghosh
CreateTimeTAG: 2013-02-25T18:44:33Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Have you investigated the "Progress" area next to "Wiki" to see if it has registered?
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T19:27:48Z
FirstChildVoteTAG: 0
SecondChildTAG: yes
SecondChildUserIdTAG: 1026345
SecondChildUserNameTAG: Wanauk
SecondChildCreateTimeTAG: 2013-02-25T20:48:03Z
SecondChildVoteTAG: 0
FirstChildTAG: Refresh the page and try again. Or you might need a different browser (Chrome or Firefox)
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T21:08:30Z
FirstChildVoteTAG: 0
IndexTAG: 2423
TitleTAG: How to write figures
Sometimes, i don't know wether i can truncate a figure or let it untruncated. for example. 0,1666 may be truncated by 0.167. it will be an uncorrected answer if the figure: 0.166 were recorded as the only correct one. the course staff may provide a protocol to avoid this kind of troubles. they can change to multiple-choices-questions.
UserIdTAG: 1036430
UserNameTAG: Ricardp
CreateTimeTAG: 2013-02-25T18:30:52Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Always *round*, not truncate, your answers. 0.16666 would be 0.2 with 1 decimal place. If using 2 decimals, it would be 0.17, and so on. Unless the exercise text says otherwise, round to 1 decimal place.
Oh, and be sure to use American notation and separate decimals with a dot(.), not a comma(,) ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T21:47:27Z
FirstChildVoteTAG: 0
IndexTAG: 2424
TitleTAG: First answer wrong
So glad I'm not the only one who was confused! Definitely an error in the first exercise.
UserIdTAG: 1260235
UserNameTAG: ashleyroe
CreateTimeTAG: 2013-02-25T18:21:09Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Answer says that the height of the -10 to 20 bar is 14/10 but it should be 14/**30**, since **20-(-10)=30**
FirstChildUserIdTAG: 198357
FirstChildUserNameTAG: whbogado
FirstChildCreateTimeTAG: 2013-02-25T23:05:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Im with you in this one. That is exactly how i calculated it.
SecondChildUserIdTAG: 979865
SecondChildUserNameTAG: Chrisgk
SecondChildCreateTimeTAG: 2013-02-26T04:04:24Z
SecondChildVoteTAG: 0
IndexTAG: 2425
TitleTAG: Staff: Revisit questions and answers
I urge the Staff to ensure that they have all questions well phrased to avoid confusion among students and plugged answers in the questions should be correct and the systems should be able to recognize answers by the students e.g. they should explicitly guide us as to how many decimal places should be used in providing answers, i provided 60 for answers 1(d) and i got it wrong only to be surprised when i checked the answers that the correct answer is actually the same 60 as i put !! It can be a disaster and frustrating for homeworks if the Staff will not do the needful
UserIdTAG: 689593
UserNameTAG: Muhadili
CreateTimeTAG: 2013-02-25T18:14:42Z
VoteTAG: 6
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2426
TitleTAG: problem 3,4
plz could any one explain the last 2 problems
UserIdTAG: 704053
UserNameTAG: jehadhassan
CreateTimeTAG: 2013-02-25T17:37:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Not yet. After the deadline for the exercises(February 27th) there will be solutions and explanations.
In the meanwhile, I suggest you review the practice Set 1, as many hints about what you need to know are there...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T17:46:26Z
FirstChildVoteTAG: 1
IndexTAG: 2427
TitleTAG: formulae
how can i get all formulaes?
UserIdTAG: 1043829
UserNameTAG: 49141
CreateTimeTAG: 2013-02-25T17:31:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: No shortcuts. Go through every lecture and exercise and write them down in one place.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:38:50Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/table-formulae/
This is the link to the table of formulae on the Wiki page.
FirstChildUserIdTAG: 47031
FirstChildUserNameTAG: PrernaDewan
FirstChildCreateTimeTAG: 2013-02-25T20:02:09Z
FirstChildVoteTAG: 0
IndexTAG: 2428
TitleTAG: stem and leaf plot
I cannot find where appears the definitions of the words of the title. I thought that I followed all the lectures but, obviously, I missed something. Thank you.
UserIdTAG: 1291666
UserNameTAG: norabram
CreateTimeTAG: 2013-02-25T17:13:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 5
FirstChildTAG: These words were used in speech by the instructor and not "defined" in words, perhaps because they are common words. Is it that you would like them defined better in written form? (Sorry, not sure if I understand your question exactly.)
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:22:37Z
FirstChildVoteTAG: 0
FirstChildTAG: It's just how that kind of data representation is called.
Why? Because that kind of graph, namely this: ![enter image description here][1]
does remind a bit of this: ![enter image description here][2]
Which is..you guessed it...a stem with leaves attached.
The "stem" would be the left column, and the numbers on the right are all "leaves".
[1]: http://www.webquest.hawaii.edu/kahihi/mathdictionary/images/stem_leaf_graph1.gif
[2]: http://demml.org/images/branches04.gif
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T17:41:03Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you. Excellent!!
SecondChildUserIdTAG: 1291666
SecondChildUserNameTAG: norabram
SecondChildCreateTimeTAG: 2013-02-27T14:12:03Z
SecondChildVoteTAG: 0
FirstChildTAG: It's in Lecture 2.1.
FirstChildUserIdTAG: 337046
FirstChildUserNameTAG: axilleas
FirstChildCreateTimeTAG: 2013-02-25T18:07:16Z
FirstChildVoteTAG: 0
FirstChildTAG: Klionheart, could you tell me how you are able to enter the Stem and Leaf chart like that in your post? I try to enter the stem and leaf chart like that in one of my response but I couldn't. Can you show me how?
Thanks.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-25T21:01:29Z
FirstChildVoteTAG: 0
SecondChildTAG: That's an image I got from Google, and linked using the button in the editor. Just the same as the tree ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-25T21:51:59Z
SecondChildVoteTAG: 0
SecondChildTAG: OK, Thanks.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-02-25T23:38:50Z
SecondChildVoteTAG: 0
FirstChildTAG: Time 2:29 of video
>It's called a stem and leaf plot.
This vertical part is the stem, and these things hanging off
here are the leaves.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T21:15:46Z
FirstChildVoteTAG: 0
IndexTAG: 2429
TitleTAG: To course staff: I feel this course is not very well organized.
This course is so weird, most of the time I don't know where everything is. READING AND PRACTICE FOR EXERCISE SET 3 is an excellent example, where is the data? Yes, in the video, do you know I have to open two tabs just for doing this question (sometime 3-4 tabs). I also notice the instructions are not very clear, here are some things, there are some things. Maybe it is just me, but I do feel disoriented and lost in the first week course.
This is an online course, I really hope you can organize everything better, since we have no classmate or instructor to help us find information and switching between tabs really makes me loose the track of everything!!!
UserIdTAG: 60773
UserNameTAG: billchenxi
CreateTimeTAG: 2013-02-25T17:08:46Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: In a "real life" class, things are not always in one place. In such a class we are expected to go to one textbook for one thing, the chalkboard for another, and our written notes for more info. Online classes should not be any different. IMO.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:24:51Z
FirstChildVoteTAG: 0
FirstChildTAG: It's their first shot at this online format, so a bit of rough edges were probably to be expected.
Prof Adhikari and the others are probaly learning as much as we are, and hopefully we'll see improvements in the coming weeks :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T17:28:35Z
FirstChildVoteTAG: 3
SecondChildTAG: **click the wiki icon you will find table of formula
SecondChildUserIdTAG: 901562
SecondChildUserNameTAG: adsadsads
SecondChildCreateTimeTAG: 2013-02-25T17:51:48Z
SecondChildVoteTAG: 0
FirstChildTAG: I disagree with the statement that the course is disorganised, I think the course has been very well put together with the focus on learning statistics, it's up to the participants to navigate the technology to find the info. The videos introduce the other relevant information, my advice is don't try to take short cuts, just follow it linearly.
FirstChildUserIdTAG: 895423
FirstChildUserNameTAG: joshea68
FirstChildCreateTimeTAG: 2013-02-25T18:33:05Z
FirstChildVoteTAG: 5
FirstChildTAG: I think a little more guidance about what lectures to watch. I found myself watching 4 different lectures on the practice pages. It wasn't clear that I wasn't suppose to do that as they were all presented with the problem. That was several hours.
FirstChildUserIdTAG: 4612
FirstChildUserNameTAG: Susnaj
FirstChildCreateTimeTAG: 2013-02-25T18:48:59Z
FirstChildVoteTAG: 0
FirstChildTAG: An excellent experience! Very well organized, a lot of info. I just pray I have the time to chew and digest all this up!
FirstChildUserIdTAG: 993834
FirstChildUserNameTAG: Thanyakishore
FirstChildCreateTimeTAG: 2013-02-25T20:50:14Z
FirstChildVoteTAG: 1
FirstChildTAG: I am Autistic and dyslexic and I managed pretty well so far, I think the Profs have done a brilliant job...just watch the lectures, read the text and take the exercises
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-25T22:52:35Z
FirstChildVoteTAG: 4
IndexTAG: 2430
TitleTAG: Would you mind to post the data here?https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/36bcbc2a9dbd4f4b8546f13c035b2759/91b004d939924a538fcb9762d499358b/#
This course is so weird, most of the time I don't know where everything is. READING AND PRACTICE FOR EXERCISE SET 3 is an excellent example, where is the data? Also did you guys notice the instructions are not very clear, here are some things, there are some things. Maybe it is just me, but I do feel disoriented and lost in the first week.
UserIdTAG: 60773
UserNameTAG: billchenxi
CreateTimeTAG: 2013-02-25T17:04:51Z
VoteTAG: 6
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: Yeah, its true. Im not a native English speaker = x2 headache
FirstChildUserIdTAG: 242303
FirstChildUserNameTAG: Lancelote
FirstChildCreateTimeTAG: 2013-02-25T17:20:29Z
FirstChildVoteTAG: 2
SecondChildTAG: i think reading the syllbus and shedule will help to direct you to steps
SecondChildUserIdTAG: 901562
SecondChildUserNameTAG: adsadsads
SecondChildCreateTimeTAG: 2013-02-25T17:48:24Z
SecondChildVoteTAG: 0
FirstChildTAG: It tells you the data is from lecture 2.4, assuming you watched it. It is also on the pdf of the slides.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T20:42:53Z
FirstChildVoteTAG: 0
IndexTAG: 2431
TitleTAG: practice for exercise set 1 ?
should we read and see all the content present in the page of "practice for exercise set 1" ??? http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#variables
UserIdTAG: 1157536
UserNameTAG: PERIO81
CreateTimeTAG: 2013-02-25T17:02:39Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is not "required" to read the ENTIRE sticigui. It IS required to read the area of it that is linked to in the Courseware. I did in fact read the whole thing just to see what was in it. It takes a very long time, but is worthwhile (but again, not necessary in its entirety) IF you have the time and inclination. If not, make sure you read the specific part of it that has been linked to.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:28:31Z
FirstChildVoteTAG: 0
IndexTAG: 2432
TitleTAG: practice for exercise set 1
responding to question 1,
UserIdTAG: 919422
UserNameTAG: tarwateanas
CreateTimeTAG: 2013-02-25T16:52:44Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2433
TitleTAG: Introduction
I like the way she started the course.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-25T16:21:37Z
VoteTAG: 3
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 1
FirstChildTAG: And hopefully some of us will like the way she ends it, also!
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:57:21Z
FirstChildVoteTAG: 1
IndexTAG: 2434
TitleTAG: available online textbook
Hi,
Where can I find the online textbook?
UserIdTAG: 1201500
UserNameTAG: julieca
CreateTimeTAG: 2013-02-25T16:11:26Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 3
FirstChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/
It is mentioned in the wiki section
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-25T16:23:10Z
FirstChildVoteTAG: 0
FirstChildTAG: It is also in the Practice for Exercise Set 1. This is why we need to go through every single part of the Courseware, even if it says "practice". I learned very early (ie, immediately) there will be no shortcuts here. I think a lot of needless questions (not that yours is one, necessarily) are because students are not reading every resource available to us.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:31:42Z
FirstChildVoteTAG: 0
FirstChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#frequency_tables
FirstChildUserIdTAG: 1151604
FirstChildUserNameTAG: albanmathias
FirstChildCreateTimeTAG: 2013-02-25T19:07:11Z
FirstChildVoteTAG: 0
IndexTAG: 2435
TitleTAG: This Lecture is Needed for Exercise Set 2
I did them before and have to make some assumptions on my own... It would have been so much simpler to have this lecture before the exercises...
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-25T15:54:41Z
VoteTAG: 4
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 3
FirstChildTAG: I think the software is being tweaked and the "Lec" parts were not in correct order relative to the "Exercise" parts. (They look in different order now than when I did them a couple of days ago.) In general, I think, try to read all Lec parts before their relevant Exercise parts. Sorry if I am being confusing. This software is frequently being adjusted, which ultimately is a good thing for us.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:37:58Z
FirstChildVoteTAG: 0
FirstChildTAG: I totally second this opinion. Please also make it clear that as one of the video lectures end, that it there maybe another. I think its a great course but I missed some of the lecture before I attempted the practice. I have gone back to the lectures several times just to make sure that I didn't miss anything, only to find that I did. S
FirstChildUserIdTAG: 4612
FirstChildUserNameTAG: Susnaj
FirstChildCreateTimeTAG: 2013-02-25T18:45:54Z
FirstChildVoteTAG: 0
FirstChildTAG: I don't think you needed to listen to this part before doing lecture set 2 problems. the questions are so different and the way they should be answered are different too.
FirstChildUserIdTAG: 606994
FirstChildUserNameTAG: Makiblue
FirstChildCreateTimeTAG: 2013-02-28T05:43:12Z
FirstChildVoteTAG: 0
IndexTAG: 2436
TitleTAG: Problem 5 in Exercise Set 2
What is the right answer? Explanation please.
UserIdTAG: 877817
UserNameTAG: sreedhara
CreateTimeTAG: 2013-02-25T15:43:39Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I believe answers will be giving after due date passes, according to the honor code we should not discuss answers before that.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-25T15:57:43Z
FirstChildVoteTAG: 0
IndexTAG: 2437
TitleTAG: I love this course.
This to express my heartfelt gratitude to the technical staff and all those in one way or another had contributed to making this course possible. I have just joined the course. Though bit late, but I am on my way to finishing the exercise sets for Week 1.
What's great about this media is that you'll get to study well for you to be able to answer the questions. More than everything, learning is fostered through sharing of viewpoints and discussions, with the emphasis of being able to grasp the basic principles of descriptive statistics aside from just passing the exams.
I'm so excited for the lessons to come. Kudos everyone!
UserIdTAG: 1300259
UserNameTAG: princejune86
CreateTimeTAG: 2013-02-25T15:10:13Z
VoteTAG: 23
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I agree. Don't let it be lost among the complaints, which I'm sure will be addressed.
FirstChildUserIdTAG: 537121
FirstChildUserNameTAG: kelceywilson
FirstChildCreateTimeTAG: 2013-02-25T22:53:15Z
FirstChildVoteTAG: 1
IndexTAG: 2438
TitleTAG: Incorrect answer after scoring 100%.
Hello.
I did exercise set 1 some days ago and I scored 100%.
Somehow an answer with 2 possible submissions was changed and now it is rated as having an incorrect answer.
In my opinion I shouldn't be able to change a correct submitted answer.
Can that be reversed?
Thank you for this great course.
Luisa
UserIdTAG: 1156003
UserNameTAG: MariaLuisaLeite
CreateTimeTAG: 2013-02-25T14:52:22Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Weird! Maybe you've changed the answer and submitted it again without noticing. The first action is familiar to me. This is something I've experienced in another course: scrolling with the track-pad located not completely out off the "white" canvas can change unintentionally a selection and if you submit the answer without taking note of that change, you know what could happen. If this has been the case, be careful for the rest of the course.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-25T15:46:44Z
FirstChildVoteTAG: 0
SecondChildTAG: Maria Luisa... are you from Brazil??
SecondChildUserIdTAG: 1051932
SecondChildUserNameTAG: LARISSAMROCHA2013
SecondChildCreateTimeTAG: 2013-02-25T20:28:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you.
I think something must have happened but if an answer is submitted correctly it shouldn't be possible to change it, even when there are more attempts left.
I had an 100% score on this exercise for quite some days now so I'm a bit disapointed that my score changed.
As for where I'm from, it's Portugal.
SecondChildUserIdTAG: 1156003
SecondChildUserNameTAG: MariaLuisaLeite
SecondChildCreateTimeTAG: 2013-02-25T21:49:20Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you guys this has been helpful, reading through your comments and queries has answered many of my own queries.
Though just one that hasnt been addressed is the practice exercise in the reading text named exercise 3 to 10 to find the right percentiles. I really didnt make sense of the answers that were being given.
Thanks waiting for someone to come to my aid on this one.
Cheers
Chrsgk
FirstChildUserIdTAG: 979865
FirstChildUserNameTAG: Chrisgk
FirstChildCreateTimeTAG: 2013-02-26T02:46:17Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi.
Let me see if I can help you.
Take the practice data sorted into increasing order.
You have 25 data.
In order to find the percentile 18th you do this math: 18/100x25. That will give you 4,5. You round that number up, so you get 5. Then you count the datum until you reach the 5th one and there's your percentile 18th.
The steps are:
- Sort the data into increasing order
- Count the datum (n)
- percentile x n
- round that up
- count the datum up until you reach that number
- the datum reached is the percentile you are looking for.
Best of luck,
Luisa
P.S. - It's really hard to explain something like this without some visual aid. I think our teacher explains it much better in the videos.
SecondChildUserIdTAG: 1156003
SecondChildUserNameTAG: MariaLuisaLeite
SecondChildCreateTimeTAG: 2013-02-27T01:33:08Z
SecondChildVoteTAG: 0
IndexTAG: 2439
TitleTAG: Thank you
I would like to thank all who thought about this free course. Again more power to you.
Ed Labay
UserIdTAG: 1307955
UserNameTAG: edlabay
CreateTimeTAG: 2013-02-25T14:43:23Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2440
TitleTAG: Practice 2 Lec 2.2 2.3 a)
I have not found anything about that question on the forum, so I would like to clarify for myself:
Practice for Exercise Set 2 Lectures 2.2 and 2.3 Q. a)
the given answer is 14%/10=1.4%
but the width of the bar -10 to 20 is 30, not 10, isn't it so?
In this case the answer should be 14%/30=0.47%
Did I understand something wrong?
UserIdTAG: 1172197
UserNameTAG: ancor88
CreateTimeTAG: 2013-02-25T14:42:43Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: "I have not found anything about that question on the forum" -- haven't you? Every fifth post is about this same exercise ;]
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-25T15:03:12Z
FirstChildVoteTAG: 0
FirstChildTAG: You're right ancor88...they're wrong, but no worries...it is just the example ;)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-25T15:22:12Z
FirstChildVoteTAG: 0
FirstChildTAG: There´s even a post from the staff saying that there is indeed a mistake. Not much mystery in this one.
FirstChildUserIdTAG: 26776
FirstChildUserNameTAG: aleguillen
FirstChildCreateTimeTAG: 2013-02-25T16:00:14Z
FirstChildVoteTAG: 0
FirstChildTAG: It may just be a practice exercise, but it's frustrating anyway.
FirstChildUserIdTAG: 1260533
FirstChildUserNameTAG: kijones
FirstChildCreateTimeTAG: 2013-02-25T19:36:47Z
FirstChildVoteTAG: 0
FirstChildTAG: > I have not found anything about that question on the forum,
Really? Well for starters, if you had made the post on the *correct forum page* instead of the page for Exercise 1 you would have seen over a good dozen posts about this.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T20:51:49Z
FirstChildVoteTAG: 0
IndexTAG: 2441
TitleTAG: Enlarging the picture
Hi,
think there should be an option of enlarging the pictures...font 6 or 7 hardly qualifies the graphs as legible.
best luck to all:)
UserIdTAG: 1155645
UserNameTAG: pixbix
CreateTimeTAG: 2013-02-25T13:32:11Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: right click and open image in other tab. It works when I've done it in other images.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-25T13:45:52Z
FirstChildVoteTAG: 1
FirstChildTAG: Or use your browser's zoom function!
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T20:46:23Z
FirstChildVoteTAG: 0
SecondChildTAG: Usually, CTRL-plus and CTRL-minus. Or CTRL+your mouse wheel ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-25T21:53:42Z
SecondChildVoteTAG: 0
IndexTAG: 2442
TitleTAG: no bases
I have no basis for this course and I understand this course easily
UserIdTAG: 1113812
UserNameTAG: REDA85
CreateTimeTAG: 2013-02-25T13:26:51Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Congratulations. Now, is that really a topic worth debating?
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-25T14:29:39Z
FirstChildVoteTAG: 0
SecondChildTAG: No more out of place than all the repeat posts about decimal places, wrong answers, etc.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-25T20:44:54Z
SecondChildVoteTAG: 0
FirstChildTAG: Finishing elementary school(I think it's 5th grade in USA?) is enough to give you the needed basis for the course as it is for now.
Surely you got past that xD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T16:18:51Z
FirstChildVoteTAG: 0
FirstChildTAG: Ok, good for you
FirstChildUserIdTAG: 1180593
FirstChildUserNameTAG: CARLOSJAV
FirstChildCreateTimeTAG: 2013-02-25T17:51:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Agree. The first week was a breeze. It can only get harder.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T20:45:29Z
FirstChildVoteTAG: 0
IndexTAG: 2443
TitleTAG: What is the difference between Qualitative and Categorical data?
Is there any difference between Qualitative and Categorical Data? If yes then what is it? For example from the accompanying link in the practise exercise "http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#frequency_tables" ...it says Hot/Warm/Cold is qualitative but Pleasant/Unpleasant is categorical? Aren't these two interchangeable? ...Thanks
UserIdTAG: 936640
UserNameTAG: Amit7urmc
CreateTimeTAG: 2013-02-25T13:21:25Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: In the same link it says "if there is an implicit ordering of the values the variable can take (hot is warmer than warm, which is warmer than cold), there is a tendency to call a variable qualitative rather than categorical". Makes sense but still the Pleasant/Unpleasant looks like an abbreviated version of Hot/Warm/Cold .. Looks like I got stuck with this example as other examples in the categorical and qualitative makes some sense to me.
FirstChildUserIdTAG: 936640
FirstChildUserNameTAG: Amit7urmc
FirstChildCreateTimeTAG: 2013-02-25T13:26:42Z
FirstChildVoteTAG: 3
SecondChildTAG: I think Qualitative and categorical data are the same. They both do not have absolute numerical values like favourite color, gender, nationality.
SecondChildUserIdTAG: 1246920
SecondChildUserNameTAG: dzame
SecondChildCreateTimeTAG: 2013-02-25T14:02:17Z
SecondChildVoteTAG: 0
SecondChildTAG: In qualitative, as given in example Hot/Warm/Cold also refers to as qualitative or **Ordinal**. Ordinal as in order. For ease, I usually refers qualitative = ordinal. In Hot/Warm/Cold there is an 'order' that you could place the 'categories' in. These order could be based by the **quantitative** data located within each of the qualitative ordinal classes or categories.
For example for a recorded annual temperature in the city, the average monthly temperature could consists of 15, 20, 30, 70, 90, 70, 50, 40, 20, 10, 0, 0 in degrees. These values can be assorted into categories or classes. Lets say 0-20 (cold), 20-70 (warm), 90 (hot) thus with the given classes could be assorted into ascending order. These type of categories or classes refer to as qualitative or ordinal.
In pleasant/unpleasant category the data you might have in either category is either 'Yes' of 'No' without no discerning quantitative value that could be put into order. Same as Endomorph, Mesomorph, Ectomorph. The values are 'Yes' or 'No' since there is no continuous quantitative values that could be placed on.
However, i have to put the quotes from the text book
> The distinction between these types of variables is somewhat blurry. For example, we might group ages into categories such as under 5 years old, between 5 and 15, between 15 and 25, between 25 and 40, and over 40. Similarly, whether gender or climate types are qualitative or categorical variables is not clear-cut.
Personally for me, I found Prof Adhikari's lectures are easier to understand compares to the text book itself. You might want to watch her lecture few more times.
SecondChildUserIdTAG: 1208879
SecondChildUserNameTAG: deqalb
SecondChildCreateTimeTAG: 2013-02-25T14:23:46Z
SecondChildVoteTAG: 0
IndexTAG: 2444
TitleTAG: Decimals
I second Jaminx's question...I went even further and "rounded" the answer to 9 decimals, but was marked wrong...I guess the app should mark the answer as correct no matter how many decimals.
UserIdTAG: 1155645
UserNameTAG: pixbix
CreateTimeTAG: 2013-02-25T13:21:14Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2445
TitleTAG: Exercise 2b
I do not understand what is wrong with my answer on exercise set1 2a.I think the answer is yes but I was marked wrong.Can anyone tell me how else they calculated the answer?
UserIdTAG: 1246920
UserNameTAG: dzame
CreateTimeTAG: 2013-02-25T13:18:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: here it is about the combined data, means all the 500 plants. I have missed this point as well.
FirstChildUserIdTAG: 981511
FirstChildUserNameTAG: Clde
FirstChildCreateTimeTAG: 2013-02-25T14:29:24Z
FirstChildVoteTAG: 0
IndexTAG: 2446
TitleTAG: Decimal places
how many decimal places are we to leave our answers in? it appears i left mine in the standard two decimal places and i was marked wrong, but i had my number of students right.thank you
UserIdTAG: 799816
UserNameTAG: JAMINx
CreateTimeTAG: 2013-02-25T12:54:38Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Totally agree, the same happened with me
FirstChildUserIdTAG: 1020704
FirstChildUserNameTAG: JoseAC
FirstChildCreateTimeTAG: 2013-02-25T13:08:19Z
FirstChildVoteTAG: 0
SecondChildTAG: If the answer is say 4.6354, you can write as 4.6 (please correct me if I am mistaken)
SecondChildUserIdTAG: 99863
SecondChildUserNameTAG: pramode_ce
SecondChildCreateTimeTAG: 2013-02-25T16:47:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I got the same problem. I rounded my answers to 2 decimal places and i got them wrong.
SecondChildUserIdTAG: 689593
SecondChildUserNameTAG: Muhadili
SecondChildCreateTimeTAG: 2013-02-25T17:59:05Z
SecondChildVoteTAG: 0
SecondChildTAG: same answer here : 11.11 % and 22.22 %
SecondChildUserIdTAG: 389424
SecondChildUserNameTAG: jmlietaer
SecondChildCreateTimeTAG: 2013-02-25T20:55:33Z
SecondChildVoteTAG: 0
SecondChildTAG: One decimal place. No percent symbol.
Unless otherwise specified in the exercise text.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-25T21:54:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree
SecondChildUserIdTAG: 945881
SecondChildUserNameTAG: SarahHarman
SecondChildCreateTimeTAG: 2013-02-26T01:55:07Z
SecondChildVoteTAG: 0
IndexTAG: 2447
TitleTAG: problem 1 (c) verificatoin
I tried to solve all 3 problems in the same way and I got the first 2 correct but the 3rd one is wrong . How? ...like I got the answer as 49.6 but it is wrong. Is it because I didnt round the number to 49.7?
UserIdTAG: 1242151
UserNameTAG: lhasan
CreateTimeTAG: 2013-02-25T12:45:58Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: it may well be that you got it wrong because you put the wrong answer in?
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-25T12:53:53Z
FirstChildVoteTAG: 0
SecondChildTAG: ok but what is the actual answer ? Is it 49.6 or 49.7?
SecondChildUserIdTAG: 1242151
SecondChildUserNameTAG: lhasan
SecondChildCreateTimeTAG: 2013-02-25T13:16:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I cant put the answer as per the Course policy, but its neither
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-02-25T14:42:47Z
SecondChildVoteTAG: 0
SecondChildTAG: lhasan, you did just like me, you calculated there the 75th percentile
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-25T19:44:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Please disregard my answer.
It's indeed 75th percentile what should go there, I thought it was 90th. But no clue why your number (mine too) is wrong
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-25T19:54:04Z
SecondChildVoteTAG: 0
SecondChildTAG: if I don't mistake 1c is 55,35 but not 49,6 or 49.7
SecondChildUserIdTAG: 336649
SecondChildUserNameTAG: Roksolana
SecondChildCreateTimeTAG: 2013-02-26T13:20:45Z
SecondChildVoteTAG: 0
SecondChildTAG: please dont ask for nor give out the answers. lets work thru the course asking for methods to arrrive at the answers.
SecondChildUserIdTAG: 390463
SecondChildUserNameTAG: DrPatilShrish
SecondChildCreateTimeTAG: 2013-02-28T07:33:02Z
SecondChildVoteTAG: 0
IndexTAG: 2448
TitleTAG: Student IDs
I have emailed the EdX help desk on several occasions as I don't a note of my student ID and don't know where to get this from. Any ideas out there gratefully received.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-25T12:35:46Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You don't need a student ID for the EdX course.
If you are talking about the form that's in the online textbook, that's for actual Berkeley students who take the classroom course ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T16:20:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks i had the same question
SecondChildUserIdTAG: 508471
SecondChildUserNameTAG: TreborR
SecondChildCreateTimeTAG: 2013-02-25T16:49:38Z
SecondChildVoteTAG: 0
IndexTAG: 2449
TitleTAG: proportions, percents, and counts
very usual.i got the proportions right as well as the counts and percentage,although i used two decimal places instead of one..does this mean that its more accurate to use one decimal place ?
UserIdTAG: 1307022
UserNameTAG: philister
CreateTimeTAG: 2013-02-25T12:14:42Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: More decimal places is more accurate.
Which is closer to 1.8889, 2.0 (1 dp) or 1.889 (3 dp)?
2.0-1.8889 = 0.1111
1.889-1.88889 = 0.0001
The difference between true answer and the rounded answer is smaller when more dp are used.
The question though should be how accurate do I need to be?
Does the answer to Q2 change if you use 1 or 2 decimal places bearing in mind that we need the students to be whole?
Does this help?
FirstChildUserIdTAG: 1071395
FirstChildUserNameTAG: lewendon
FirstChildCreateTimeTAG: 2013-02-25T12:50:17Z
FirstChildVoteTAG: 0
SecondChildTAG: yep thanks
SecondChildUserIdTAG: 799816
SecondChildUserNameTAG: JAMINx
SecondChildCreateTimeTAG: 2013-02-25T12:57:00Z
SecondChildVoteTAG: 0
IndexTAG: 2450
TitleTAG: Is that it for ex.1? and thanks UBerkeley
I take it that the test is automatically submitted? I don't have to "submit"? Thanks to all involved with this course, excellent!
UserIdTAG: 1284323
UserNameTAG: markjohnconley
CreateTimeTAG: 2013-02-25T11:57:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: If you have a result(green V or red X), it means that your answer has been submit :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T16:14:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Klionheart
SecondChildUserIdTAG: 1284323
SecondChildUserNameTAG: markjohnconley
SecondChildCreateTimeTAG: 2013-02-26T04:04:01Z
SecondChildVoteTAG: 0
IndexTAG: 2451
TitleTAG: Decimal places on problem 1
How many decimal .places do we need ?
Only the c) has specification
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-25T11:48:47Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Usually it is one.... unless specified otherwise :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-25T12:03:54Z
FirstChildVoteTAG: 0
FirstChildTAG: You're right Jorge, the number of decimal places required in the response is only mentioned in Problem 1, c).
I used the same specification for all the questions in Problem 1, and got my responses right.
FirstChildUserIdTAG: 598623
FirstChildUserNameTAG: dkv
FirstChildCreateTimeTAG: 2013-02-25T14:54:27Z
FirstChildVoteTAG: 1
SecondChildTAG: the first two answers 1a and 1b, i used two decimals and got it right. so only in 1c it matters
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-02-25T16:52:36Z
SecondChildVoteTAG: 0
FirstChildTAG: My calculations were all right, but I reported result for 1c with two decimal places and the answer was WRONG. So use only one decimal.
FirstChildUserIdTAG: 570075
FirstChildUserNameTAG: NikiSadovski
FirstChildCreateTimeTAG: 2013-02-25T16:34:09Z
FirstChildVoteTAG: 0
FirstChildTAG: Even in the 1a if you use one decimal it works , 1 b doesn't need a decimal
FirstChildUserIdTAG: 984232
FirstChildUserNameTAG: Selwyn1977
FirstChildCreateTimeTAG: 2013-02-25T19:44:08Z
FirstChildVoteTAG: 0
SecondChildTAG: yes it works) I used for 1a and 1b and for 1c too)
SecondChildUserIdTAG: 336649
SecondChildUserNameTAG: Roksolana
SecondChildCreateTimeTAG: 2013-02-26T13:18:27Z
SecondChildVoteTAG: 0
FirstChildTAG: The questions are poorly set... full stop
FirstChildUserIdTAG: 597013
FirstChildUserNameTAG: drizham
FirstChildCreateTimeTAG: 2013-02-26T16:20:15Z
FirstChildVoteTAG: 0
IndexTAG: 2452
TitleTAG: There is something wrong??
Hi, I think that there is a mistake in the first exercise. I think that the right answer is 0.47%
UserIdTAG: 230105
UserNameTAG: dmayorgavega
CreateTimeTAG: 2013-02-25T11:45:25Z
VoteTAG: 23
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Yup, I think they are calculating 20-10 instead of 20-(-10) thus making the calculation with a skewed interval...
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-25T12:10:24Z
FirstChildVoteTAG: 1
FirstChildTAG: Exactly, range[-10,20) = 30, NOT 10 as the explanation says
FirstChildUserIdTAG: 731428
FirstChildUserNameTAG: mjgarciam
FirstChildCreateTimeTAG: 2013-02-25T12:39:48Z
FirstChildVoteTAG: 1
FirstChildTAG: Yes. Look at the [Errata][1], or just read a couple other topics here xD
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-25T16:22:11Z
FirstChildVoteTAG: 0
IndexTAG: 2453
TitleTAG: problem 6
how can i know the height if the percent also is not given? help
UserIdTAG: 1231135
UserNameTAG: shie112709
CreateTimeTAG: 2013-02-25T11:27:57Z
VoteTAG: 11
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Think about this, "(%) percent / width = Heigth ".
You know each interval width, and you know the percert must be 100 % adding all the intervals.
FirstChildUserIdTAG: 1227759
FirstChildUserNameTAG: SVRLU
FirstChildCreateTimeTAG: 2013-02-25T11:47:50Z
FirstChildVoteTAG: 5
SecondChildTAG: Yeah but I used the same formular but I got the wrong answer for Problem 6 and 7. So please i need explanation. Thanks for help.
SecondChildUserIdTAG: 433691
SecondChildUserNameTAG: kpogmarce
SecondChildCreateTimeTAG: 2013-02-25T15:28:17Z
SecondChildVoteTAG: 0
SecondChildTAG: @SVRLU
thanks, i do understand now.. and my answer is correct..thanks for the help..
SecondChildUserIdTAG: 1231135
SecondChildUserNameTAG: shie112709
SecondChildCreateTimeTAG: 2013-02-25T15:46:32Z
SecondChildVoteTAG: 0
SecondChildTAG: @kpogmarce
in the question, "fewer than 4 hours, so it means less than or below 4hours, so find where it belong to find the interval (width). and compute for the percent, height and width are already given in the above..
SecondChildUserIdTAG: 1231135
SecondChildUserNameTAG: shie112709
SecondChildCreateTimeTAG: 2013-02-25T15:49:53Z
SecondChildVoteTAG: 0
SecondChildTAG: so may ask whts the answer for problem 7 ???
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-02-25T18:05:47Z
SecondChildVoteTAG: 0
SecondChildTAG: i follow this way in ques 7 but i get wrong answer
i think we need a way to at least understand not to repeat the mistake
SecondChildUserIdTAG: 679973
SecondChildUserNameTAG: mirroraziz
SecondChildCreateTimeTAG: 2013-02-25T20:41:48Z
SecondChildVoteTAG: 0
SecondChildTAG: I am having some problems with question number 7. I have the correct %-Percentage for questions 6. I have turned each height into a percentage, but I get the wrong answer. Could someone please give me some guidance?
SecondChildUserIdTAG: 142791
SecondChildUserNameTAG: jvacarchuk
SecondChildCreateTimeTAG: 2013-02-26T00:12:16Z
SecondChildVoteTAG: 0
FirstChildTAG: just see that you have heights and no percents and remember that the sum of all percents will be 100
FirstChildUserIdTAG: 427080
FirstChildUserNameTAG: Drkmarvin
FirstChildCreateTimeTAG: 2013-02-27T05:08:50Z
FirstChildVoteTAG: 0
IndexTAG: 2454
TitleTAG: how many numbers after the comma in the percentage?
i put 11,11 % in the percentage of seniors but the answer was: " Invalid input: could not interpret '11,11%' as a number "
UserIdTAG: 1157536
UserNameTAG: PERIO81
CreateTimeTAG: 2013-02-25T11:19:15Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You have to put a dot in and not a comma - U.S. style vs. continental Europe.
FirstChildUserIdTAG: 901519
FirstChildUserNameTAG: jmr12
FirstChildCreateTimeTAG: 2013-02-25T11:41:12Z
FirstChildVoteTAG: 2
SecondChildTAG: I used dots but i still got a cross. May be they want us to use one decimal place. The staff must have their instructions be as clear as possible.
SecondChildUserIdTAG: 689593
SecondChildUserNameTAG: Muhadili
SecondChildCreateTimeTAG: 2013-02-25T18:02:19Z
SecondChildVoteTAG: 0
IndexTAG: 2455
TitleTAG: Wrong evaluation
a) the percent of seniors
11.11 (incorrect - right answer 11.1)
c) the percent of freshmen
22.22 (incorrect - right answer 22.2)
This means that we should write the answers with only one decimal of accuracy?
UserIdTAG: 1011814
UserNameTAG: Jfmontoto
CreateTimeTAG: 2013-02-25T11:07:31Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: This means we should use the search button first because with over 45 thousand participants it is very likely that somebody already asked that question and received answer...
FirstChildUserIdTAG: 1263818
FirstChildUserNameTAG: Ruteq
FirstChildCreateTimeTAG: 2013-02-25T12:03:16Z
FirstChildVoteTAG: 2
FirstChildTAG: I wrote the percentages without decimal
FirstChildUserIdTAG: 1305915
FirstChildUserNameTAG: Lattaa
FirstChildCreateTimeTAG: 2013-02-25T12:04:24Z
FirstChildVoteTAG: 0
SecondChildTAG: And did right?
SecondChildUserIdTAG: 1264808
SecondChildUserNameTAG: Viviane_Uller
SecondChildCreateTimeTAG: 2013-02-25T16:30:47Z
SecondChildVoteTAG: 0
IndexTAG: 2456
TitleTAG: Where is the feedback?
Just saying correct or incorrect is not enough. There must be a more detailed feedback. Is it somewhere but somehow I missed it?
Ethnicity is definitely qualitative. Lecture says that qualitative variables that can be ranked are cardinal. Ordinal is not defined in the lecture.Assuming ordinal is the opposite of cardinal, and since ethnicity cannot be ranked, would ethnicity not be qualitative ordinal?
Really, getting something like this wrong at the beginning puts off a learner and a feedback, quick and easy, would be a big help.
UserIdTAG: 1139936
UserNameTAG: SundarV
CreateTimeTAG: 2013-02-25T11:04:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Oh come on! This is an assessment. Ya don't get the answer until after the due date. As clearly spelled out in the course policy document.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T11:35:22Z
FirstChildVoteTAG: 0
FirstChildTAG: The answers will come after the submission deadline (which 27th of February), dont worry.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-25T11:40:22Z
FirstChildVoteTAG: 0
FirstChildTAG: A feedback is not getting the "correct answer". It is also about knowing why you got an answer wrong. "Oh come on"? Can we have some respect here?
FirstChildUserIdTAG: 1139936
FirstChildUserNameTAG: SundarV
FirstChildCreateTimeTAG: 2013-02-25T11:48:34Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes but the point is, they can't give the feedback yet because the deadline hasn't passed. Previous courses I've taken have released a document with the answers (and workings) after the deadline for submission. Be patient, the profs on this course seem very keen to promote *learning*, not just exam-passing, so I'm sure we'll get feedback.
SecondChildUserIdTAG: 176771
SecondChildUserNameTAG: nancykane
SecondChildCreateTimeTAG: 2013-02-25T13:20:51Z
SecondChildVoteTAG: 0
FirstChildTAG: How will the assignment be graded without the check option????
FirstChildUserIdTAG: 925342
FirstChildUserNameTAG: anita1991
FirstChildCreateTimeTAG: 2013-02-25T15:01:40Z
FirstChildVoteTAG: 0
IndexTAG: 2457
TitleTAG: problem working out the (20/28) part!!!
**Help**. i have being doing very well till this part. what does 20/28 mean? is it 20 devided by 28? or is there more to it than that? my answers are way off
UserIdTAG: 290947
UserNameTAG: medb71
CreateTimeTAG: 2013-02-25T11:01:17Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: thats correct
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-25T12:57:02Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks but I'm still not getting the answer...20/28=.714.....10+.714*15=160.714......they give the answer as 20.7? where am i going wrong?
SecondChildUserIdTAG: 290947
SecondChildUserNameTAG: medb71
SecondChildCreateTimeTAG: 2013-02-25T16:14:20Z
SecondChildVoteTAG: 0
SecondChildTAG: first multiply 0.714 with 15 and then add 10 you have to use BEDMAS rule which is ( Bracket, Exponential, Division, Multiplication, Addition and Subtraction)
10 + 20/28 * (25-10)
SecondChildUserIdTAG: 976798
SecondChildUserNameTAG: Vassri
SecondChildCreateTimeTAG: 2013-02-25T21:39:40Z
SecondChildVoteTAG: 0
SecondChildTAG: thank you very much. will look that rule up
SecondChildUserIdTAG: 290947
SecondChildUserNameTAG: medb71
SecondChildCreateTimeTAG: 2013-02-25T22:56:07Z
SecondChildVoteTAG: 0
SecondChildTAG: Just a clarification please. The first 10 in the formula 10+20/28*(25-10) is the $10,000 from the first twenty percent or the interval we know?
for example if I wanted to know the 50th percentile the formula would be 25 +2/27*(50-25) ?
SecondChildUserIdTAG: 1125759
SecondChildUserNameTAG: John-Jack
SecondChildCreateTimeTAG: 2013-02-26T18:19:13Z
SecondChildVoteTAG: 0
IndexTAG: 2458
TitleTAG: Ghada Radwan
I did problem 1 right I guess but I inserted 2 decimals instead of one that is why it appeared wrong??
Would the instructors check that please and advise if they are correct1
Thanks
UserIdTAG: 749490
UserNameTAG: ghadanasr
CreateTimeTAG: 2013-02-25T11:00:25Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I don't know why you got it wrong, but unless stated otherwise, stick to the "rounding to one decimal" routine :)
FirstChildUserIdTAG: 1068140
FirstChildUserNameTAG: MrKeSh
FirstChildCreateTimeTAG: 2013-02-25T14:37:00Z
FirstChildVoteTAG: 0
IndexTAG: 2459
TitleTAG: Exercise instructions and uncertainty about what it is due to do.
In my view, some exercises are not explain with enough accuracy and this leads doubts and to incorrect answers in the end. Please, be more precise at writing the explanaitions for us not to get confused. Remind that one of the best things to have enthusiastic and engaged students is not to confuse them but inaccuracies or errors.
Anyway, thanks because I'm well aware of the effort you're doing.
UserIdTAG: 1176613
UserNameTAG: Asrael
CreateTimeTAG: 2013-02-25T10:46:22Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2460
TitleTAG: Time exercise
the first week exam is in feb 27 at 23.30! please in witch time we work ? GMT?!!
UserIdTAG: 919422
UserNameTAG: tarwateanas
CreateTimeTAG: 2013-02-25T10:33:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Am I the only one here who has read the course policy document?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T11:36:49Z
FirstChildVoteTAG: 2
FirstChildTAG: Exercise Sets are due at specified dates and times. **All times are in Greenwich Mean Time (GMT).**
edit: from Policies and Requirements, under "Grading".
FirstChildUserIdTAG: 230828
FirstChildUserNameTAG: alanis
FirstChildCreateTimeTAG: 2013-02-25T12:16:24Z
FirstChildVoteTAG: 3
IndexTAG: 2461
TitleTAG: Width of the interval 10 - 20
width of the interval -10 - 20 will be 20-(-10)=30. So height of the bar = 14%/30 = 0.47% per unit
UserIdTAG: 1105885
UserNameTAG: AJITHABK
CreateTimeTAG: 2013-02-25T09:58:20Z
VoteTAG: 30
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Hi my friend!
You shouldn't post answers before due dates. This is a course with grades and certificates for the passing students. By the contrary, doubts are very welcome.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-25T10:24:36Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi Asrael, this is a practice test so you don't get graded.
SecondChildUserIdTAG: 337046
SecondChildUserNameTAG: axilleas
SecondChildCreateTimeTAG: 2013-02-25T12:12:15Z
SecondChildVoteTAG: 0
SecondChildTAG: no
SecondChildUserIdTAG: 931470
SecondChildUserNameTAG: sarabjeet1991
SecondChildCreateTimeTAG: 2013-03-05T18:04:25Z
SecondChildVoteTAG: 0
IndexTAG: 2462
TitleTAG: Histograms can not be seen
I can not see any histogram on Figure 3-2 and Figure 3-3. What should I do?
UserIdTAG: 1140594
UserNameTAG: Renata333
CreateTimeTAG: 2013-02-25T09:55:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Try a different browser or clear your browser's cache.
FirstChildUserIdTAG: 337046
FirstChildUserNameTAG: axilleas
FirstChildCreateTimeTAG: 2013-02-25T10:07:36Z
FirstChildVoteTAG: 0
SecondChildTAG: I used the recommended moxilla firefox version 19, but couldn't still view the histogram. How does one go about clearing the browser's cache?
SecondChildUserIdTAG: 1252192
SecondChildUserNameTAG: Imesidayo
SecondChildCreateTimeTAG: 2013-02-25T10:45:04Z
SecondChildVoteTAG: 0
SecondChildTAG: I have the same problem, I've already tried mozilla and chrome, I cleared cache in both of browsers, I checked if javascript is enabled. Do you have any other ideas? What can I do?
SecondChildUserIdTAG: 1248636
SecondChildUserNameTAG: zofiap
SecondChildCreateTimeTAG: 2013-02-25T15:39:09Z
SecondChildVoteTAG: 0
IndexTAG: 2463
TitleTAG: Exercise 3b from exercise set 2 (interpreting the Histograms)
My problem with this exercise is that I think they all three are incorrect, but I supose It can't be possible unless there's an error. Can anyone tell me what i'm overlooking? Please help and thanks in advence.
UserIdTAG: 1176613
UserNameTAG: Asrael
CreateTimeTAG: 2013-02-25T09:52:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: They are not all incorrect Asreal, try and calculate the actual number of plants for each group of colours, then add up the ones with Green seperately. Also add up the ones without Green. This will give the number in both groups ie With Green and Without Green.
FirstChildUserIdTAG: 1173471
FirstChildUserNameTAG: jides
FirstChildCreateTimeTAG: 2013-02-25T11:04:44Z
FirstChildVoteTAG: 0
IndexTAG: 2464
TitleTAG: Text book
Where can I get an online text book for this course?
Thank you for help.
UserIdTAG: 1089620
UserNameTAG: yes1ade
CreateTimeTAG: 2013-02-25T09:52:01Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: If I am not wrong, you can get it over here - http://statistics.berkeley.edu/~stark/SticiGui/index.htm
FirstChildUserIdTAG: 359904
FirstChildUserNameTAG: Abhijeetsafai
FirstChildCreateTimeTAG: 2013-02-25T11:37:53Z
FirstChildVoteTAG: 0
IndexTAG: 2465
TitleTAG: late requirements
may i be late in answering exercises? just this time. how will it probably affect my registration? i mean late just for this week.
UserIdTAG: 1061545
UserNameTAG: rence
CreateTimeTAG: 2013-02-25T09:51:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: From what I understand, you wouldn't be getting any points (if submissions after the due date are even possible). Do your best to at least answer some :) in any case:
"Your two lowest Exercise Set scores will not be used in the calculation of your overall grade." (from Policies and requirements)
FirstChildUserIdTAG: 230828
FirstChildUserNameTAG: alanis
FirstChildCreateTimeTAG: 2013-02-25T12:20:29Z
FirstChildVoteTAG: 0
IndexTAG: 2466
TitleTAG: Can anyone tell what we have to do in exercise 2b (exercise set 2)?
I understand we have to use people aged more than 65 (excluding the age of 65) till the age of 100 (included) . That is, from 66 to 74 for interval [60-75) and from 75 to 100 for interval [75 to 100]. What am I missing?
UserIdTAG: 1176613
UserNameTAG: Asrael
CreateTimeTAG: 2013-02-25T09:40:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: That happened to me too, but then I realized that I needed to include 65. I don't understand why, cause the problem says "over 65". English isn't my native language, but I think "over 65" means "65 not included". Am I right?
FirstChildUserIdTAG: 1081098
FirstChildUserNameTAG: BrilloBox
FirstChildCreateTimeTAG: 2013-02-25T10:02:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Oh, I think "over 65" means more than 65. Well, I don't know for sure cause I'm Spanish. Then, I have to include the age of 65. Did you include the age of 100? As I understand we do have to include it, but...
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-25T10:08:51Z
FirstChildVoteTAG: 0
SecondChildTAG: Sorry, Asrael, but I don't want to be in trouble with the honor code revealing more details about the answer. In any case, the problem is clear about the point you mention ;-)
Saludos desde Madrid.
SecondChildUserIdTAG: 1081098
SecondChildUserNameTAG: BrilloBox
SecondChildCreateTimeTAG: 2013-02-25T10:23:55Z
SecondChildVoteTAG: 0
FirstChildTAG: When someone is aged 65 and 7 months, they are still considered aged 65.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T15:57:00Z
FirstChildVoteTAG: 0
IndexTAG: 2467
TitleTAG: Low resolution video download
Thanks for the downloadable links. Unfortunately, it is for 1280 X 720 which makes the file size larger, Is it possible to download 640 X 360 videos to reduce the size.
UserIdTAG: 99047
UserNameTAG: taminur
CreateTimeTAG: 2013-02-25T09:17:23Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2468
TitleTAG: For next exercises, please tell us the precision of the answers
like many others, 11.11% is wrong (the right answer is 11.1%)...
Here it is not a problem, but for a graded work...
Enjoy !
Gabriel
UserIdTAG: 1133870
UserNameTAG: legual
CreateTimeTAG: 2013-02-25T09:14:36Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I agree. Please mention it in the brackets next to the question.
FirstChildUserIdTAG: 975609
FirstChildUserNameTAG: PRPant
FirstChildCreateTimeTAG: 2013-02-25T10:21:04Z
FirstChildVoteTAG: 3
SecondChildTAG: The question should be more precise about:
- number of decimals required
- with our without the unit (% in this case)
SecondChildUserIdTAG: 389424
SecondChildUserNameTAG: jmlietaer
SecondChildCreateTimeTAG: 2013-02-25T20:58:21Z
SecondChildVoteTAG: 0
IndexTAG: 2469
TitleTAG: question 3 a
Should we give a percent symbol at the end of the numeric answer?
UserIdTAG: 1056571
UserNameTAG: JayashreeGopalakrishnan
CreateTimeTAG: 2013-02-25T08:34:34Z
VoteTAG: 7
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: No
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-25T09:07:11Z
FirstChildVoteTAG: 0
SecondChildTAG: how many decimal point here?
SecondChildUserIdTAG: 1231135
SecondChildUserNameTAG: shie112709
SecondChildCreateTimeTAG: 2013-02-25T10:23:26Z
SecondChildVoteTAG: 0
SecondChildTAG: No! it's quite stupid box. The unit should be mentioned in the question. I did several times for that mistake
SecondChildUserIdTAG: 809403
SecondChildUserNameTAG: ladykiller
SecondChildCreateTimeTAG: 2013-02-25T15:12:51Z
SecondChildVoteTAG: 0
FirstChildTAG: how many decimal point for the answer in question 3a? thanks
FirstChildUserIdTAG: 1231135
FirstChildUserNameTAG: shie112709
FirstChildCreateTimeTAG: 2013-02-25T15:52:06Z
FirstChildVoteTAG: 0
SecondChildTAG: I think rounding it to one decimal is good enough with out any units or symbols next to it.
SecondChildUserIdTAG: 976798
SecondChildUserNameTAG: Vassri
SecondChildCreateTimeTAG: 2013-02-25T19:43:18Z
SecondChildVoteTAG: 0
IndexTAG: 2470
TitleTAG: 11.1 or 11.11
How is 11.1 different from 11.11? I got my answer wrong! help;(
UserIdTAG: 483549
UserNameTAG: karma_lh
CreateTimeTAG: 2013-02-25T08:33:19Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: actually the answer should be 100/9 which equal 11.111111111...
so 11.11 is more accurate than 11.1 but I think it's a bug in the site, they should correct it
FirstChildUserIdTAG: 715663
FirstChildUserNameTAG: GeorgeDaoud
FirstChildCreateTimeTAG: 2013-02-25T08:39:25Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, the decimals are really a problem. Please mention clearly to how many decimal places are required in the answer.
SecondChildUserIdTAG: 975609
SecondChildUserNameTAG: PRPant
SecondChildCreateTimeTAG: 2013-02-25T10:20:13Z
SecondChildVoteTAG: 0
IndexTAG: 2471
TitleTAG: Thanks to the Staff
Hi, I just wanted to say a big thank you to the staff for this course. I know there are a lot of comments with "suggestions" on how else this could be run, but I think its spot on. I spent the weekend revising and looking at where I went wrong on the exercises, and to be honest, if I paid a little more attention the first time around I would have got 100% (maybe)
Hopefully the 2.2 and 2.3.x will be available this year,
Good work team
UserIdTAG: 7545
UserNameTAG: jasontimothyjones
CreateTimeTAG: 2013-02-25T08:01:08Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I have to agree with this, I think the course is fantastic so far. I have really enjoyed the first week and love the fact I am able to study alongside work and get a real sense of personal progression. Thank you very much!
FirstChildUserIdTAG: 1242147
FirstChildUserNameTAG: VickyUK
FirstChildCreateTimeTAG: 2013-02-25T12:53:57Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks, both of you. I'm glad the course is going well for you. My aim is to make the course enjoyable and informative, and not rely too much on people's prior background in maths.
Jasontimothyjones is right that "a little more attention" is what's needed if answers don't turn out the way you first thought they should.
2.2X is due to start two weeks after 2.1X ends. I don't have the start date for 2.3X nailed down yet, but unless something unusual happens, it should start a couple of weeks after the end of 2.2X. I'll announce to the class when everything is confirmed.
Cheers,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T22:31:24Z
FirstChildVoteTAG: 0
IndexTAG: 2472
TitleTAG: Mistake in the subtitle
At 1:34 of the video, it is rather "It's a count" not "It a count".
UserIdTAG: 1088741
UserNameTAG: haalmo
CreateTimeTAG: 2013-02-25T08:00:29Z
VoteTAG: 2
CoursewareTAG: Section 1: Introduction / Lec 1.2. Variables: terminology
NumberOfReplyTAG: 0
IndexTAG: 2473
TitleTAG: Question 2 A
What does thirties mean? Is it the age group from 30 to 39 or only 30. Please help
UserIdTAG: 679068
UserNameTAG: Suneev
CreateTimeTAG: 2013-02-25T07:57:02Z
VoteTAG: 9
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: I already lost both the attempts still curious to find the right answer. Please explain.
FirstChildUserIdTAG: 221357
FirstChildUserNameTAG: drmonik
FirstChildCreateTimeTAG: 2013-02-25T08:00:17Z
FirstChildVoteTAG: 0
SecondChildTAG: This would be all in the age of 30s which means 30 31 32 and so on but not 40
SecondChildUserIdTAG: 358255
SecondChildUserNameTAG: drnidhi27
SecondChildCreateTimeTAG: 2013-02-25T08:58:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Already did.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-25T09:00:03Z
SecondChildVoteTAG: 0
SecondChildTAG: yeap people hwho has more than 29 years but not more than 39
SecondChildUserIdTAG: 427080
SecondChildUserNameTAG: Drkmarvin
SecondChildCreateTimeTAG: 2013-02-27T05:09:43Z
SecondChildVoteTAG: 0
FirstChildTAG: 30-39 inclusive.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T08:23:38Z
FirstChildVoteTAG: 4
FirstChildTAG: The question says the data interval is left-end point. In lecture how to draw histogram explained this concept at 3:22
Hope this will help you solve the question!
FirstChildUserIdTAG: 1278232
FirstChildUserNameTAG: eirras
FirstChildCreateTimeTAG: 2013-02-26T14:45:09Z
FirstChildVoteTAG: 0
IndexTAG: 2474
TitleTAG: Mistake in the subtitle
At 7:35 of the video, "... green bar represents 1/5 **off** the data".
It must be "of".
UserIdTAG: 1088741
UserNameTAG: haalmo
CreateTimeTAG: 2013-02-25T07:52:29Z
VoteTAG: 0
CoursewareTAG: Section 1: Introduction / Lec 1.3. Bar graphs: describing categorical data
NumberOfReplyTAG: 0
IndexTAG: 2475
TitleTAG: Problem 5 - Tricky - More attempts for such problem would be good
This is a good problem which forces us to think about the formula and grasp it more deeply. However, it carries 5 points. I suggest that for such 'costly' questions at least one more attempt should be given. To avoid chances of guesses, you can increase the number of choices.
UserIdTAG: 278932
UserNameTAG: Rahulsv
CreateTimeTAG: 2013-02-25T07:21:58Z
VoteTAG: 11
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: yah that's right.. my answer is wrong
FirstChildUserIdTAG: 1231135
FirstChildUserNameTAG: shie112709
FirstChildCreateTimeTAG: 2013-02-25T11:11:36Z
FirstChildVoteTAG: 1
SecondChildTAG: true
SecondChildUserIdTAG: 1278060
SecondChildUserNameTAG: Rukmini2908
SecondChildCreateTimeTAG: 2013-02-25T18:33:13Z
SecondChildVoteTAG: 0
SecondChildTAG: ya thats true..
SecondChildUserIdTAG: 1293847
SecondChildUserNameTAG: shailesh1984
SecondChildCreateTimeTAG: 2013-02-25T19:34:47Z
SecondChildVoteTAG: 0
SecondChildTAG: true.. mine was wrong too but after two chances realised the right answer..:(
SecondChildUserIdTAG: 976798
SecondChildUserNameTAG: Vassri
SecondChildCreateTimeTAG: 2013-02-25T19:45:11Z
SecondChildVoteTAG: 0
SecondChildTAG: I got this one wrong too. It's really tricky. And I have another wrong answer in problem 1 because of carelessness. Still, I'm proud of myself. I work so hard for this exercise. T.T
SecondChildUserIdTAG: 1188300
SecondChildUserNameTAG: cqprivado
SecondChildCreateTimeTAG: 2013-02-25T22:23:34Z
SecondChildVoteTAG: 0
SecondChildTAG: agreed
SecondChildUserIdTAG: 1305066
SecondChildUserNameTAG: btr
SecondChildCreateTimeTAG: 2013-02-25T22:32:05Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree
SecondChildUserIdTAG: 428076
SecondChildUserNameTAG: AALEJANDROCC
SecondChildCreateTimeTAG: 2013-02-27T04:42:04Z
SecondChildVoteTAG: 0
IndexTAG: 2476
TitleTAG: Can't include unit
I wrote % with my answer and it screams 'Incorrect!' Wish there were some instructions before on what exactly to enter into the boxes, i.e. units, decimal places, etc.
UserIdTAG: 1305736
UserNameTAG: nisads
CreateTimeTAG: 2013-02-25T07:14:09Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hi there!
You must not enter any unit or % sign in your responses. Enter the numbers only. I've done this way and I haven't had any problems untill now.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-25T09:23:56Z
FirstChildVoteTAG: 0
IndexTAG: 2477
TitleTAG: Timeframe for Mid term and final exam?
Is the planned time frame for the mid term and the final exam going to be just 24 hours?
This might cause problems for some people and might be an issue worth thinking about now rather than having a flood of complaints closer to the date.
MOOC students often aren't as flexible as full-time students in they have jobs and other commitments. It might also depend on how searching these exams are intended to be - for a five week course it may be that we aren't expected to spend more than an hour on the exams.
UserIdTAG: 881870
UserNameTAG: tomboyoung
CreateTimeTAG: 2013-02-25T06:14:38Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I'm planning about 45 minutes for the midterm and 1.5 hours for the final. We are indeed considering the timing issue, but with exams it's not easy to spread them out over many days, so there are a few things to balance. I'll be in touch with the class about that soon. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T22:12:58Z
FirstChildVoteTAG: 1
FirstChildTAG: Hi,
I am also going to miss the mid term if there can be no change to the date or times because I'll be flying from Sydney to London on the 13th. After a 24hr flight, arriving at 5am, then having to get through customs, get bags etc. I am not going to make the deadline (and would not be in a fit state to either). This is a big blow for me as so far I'm doing quite well and am taking this course very seriously.
David
FirstChildUserIdTAG: 946554
FirstChildUserNameTAG: DavidH-Aus
FirstChildCreateTimeTAG: 2013-03-03T11:35:01Z
FirstChildVoteTAG: 0
IndexTAG: 2478
TitleTAG: how to download Subtitle, please
my English level is very very low
UserIdTAG: 1061541
UserNameTAG: print
CreateTimeTAG: 2013-02-25T06:12:15Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: see the wiki: "Subtitle files of lecture videos in .srt format"
FirstChildUserIdTAG: 34618
FirstChildUserNameTAG: scriba
FirstChildCreateTimeTAG: 2013-02-25T06:24:48Z
FirstChildVoteTAG: 0
SecondChildTAG: and please use the search function of the discussion forum
this question was already answered before
SecondChildUserIdTAG: 34618
SecondChildUserNameTAG: scriba
SecondChildCreateTimeTAG: 2013-02-25T06:26:05Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/subtitle-files/
SecondChildUserIdTAG: 1039699
SecondChildUserNameTAG: VickyO
SecondChildCreateTimeTAG: 2013-02-27T20:14:45Z
SecondChildVoteTAG: 0
IndexTAG: 2479
TitleTAG: Got it
I guess with percent you don't add too many numbers after the decimal point
UserIdTAG: 296540
UserNameTAG: mickalla2002
CreateTimeTAG: 2013-02-25T05:33:49Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2480
TitleTAG: Answers
All the answer is in one decimals and you have to use only point no commas
UserIdTAG: 1041097
UserNameTAG: JUANADORIS2013
CreateTimeTAG: 2013-02-25T04:53:09Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2481
TitleTAG: Practice for Exercise set 1
Can someone give a hint on how to work the Practice for Exercise set 1?
UserIdTAG: 174302
UserNameTAG: noelsfwatson
CreateTimeTAG: 2013-02-25T04:49:18Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: For a total number of 270 students, you're given a ratio of 2:3:3:1 with altogether 2+3+3+1 units of students.
Unit;
2 refers to as 'freshmen'
3 refers to as 'sophomores'
3 refers to as 'juniors'
1 refers to as 'seniors'
9/9 units would be 100%.
FirstChildUserIdTAG: 1208879
FirstChildUserNameTAG: deqalb
FirstChildCreateTimeTAG: 2013-02-25T14:36:05Z
FirstChildVoteTAG: 0
IndexTAG: 2482
TitleTAG: Height of -10 to 20 bar
The correct answer, for height, would appear to be 14%/30 units=0.467% per unit
UserIdTAG: 945738
UserNameTAG: ttrant
CreateTimeTAG: 2013-02-25T04:13:32Z
VoteTAG: 17
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: effectively,
it needs to be corrected!
FirstChildUserIdTAG: 1036430
FirstChildUserNameTAG: Ricardp
FirstChildCreateTimeTAG: 2013-02-25T04:58:05Z
FirstChildVoteTAG: 0
SecondChildTAG: I guess the program has considered the HEIGHT of 10 to 20 bar instead of THE HEIGHT -10 TO 20 BAR ....
SecondChildUserIdTAG: 1207265
SecondChildUserNameTAG: CesarCataldi
SecondChildCreateTimeTAG: 2013-02-25T07:35:47Z
SecondChildVoteTAG: 0
FirstChildTAG: algunas preguntas no se si respondo en % , en cantidad .
Me gustaria saber que caracteristica discreta puede tomas valores 0.5, 1.0, 1.5, 2.0, ...
FirstChildUserIdTAG: 1272928
FirstChildUserNameTAG: yatalo
FirstChildCreateTimeTAG: 2013-02-25T05:00:54Z
FirstChildVoteTAG: 0
SecondChildTAG: La cantidad de cerveza consumida en un bar que sirve medio litro (esto es un ejemplo incomparable !)
SecondChildUserIdTAG: 1191661
SecondChildUserNameTAG: ancelin
SecondChildCreateTimeTAG: 2013-02-25T14:22:16Z
SecondChildVoteTAG: 0
FirstChildTAG: yes. It is wrong
FirstChildUserIdTAG: 1294449
FirstChildUserNameTAG: jesse9
FirstChildCreateTimeTAG: 2013-02-25T05:33:35Z
FirstChildVoteTAG: 0
FirstChildTAG: Is it?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T07:56:09Z
FirstChildVoteTAG: 0
SecondChildTAG: I also encountered the same problem..because the width of the interval should be 30 and not 10.....?
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-25T09:04:32Z
SecondChildVoteTAG: 0
IndexTAG: 2483
TitleTAG: Greetings from Timor-Leste
Hi All,
It is a pleasure that I am brushing up my Statistics after having studied it years ago in Australi.
Tony
Dili - Timor-Leste
UserIdTAG: 1239876
UserNameTAG: tonyduarte
CreateTimeTAG: 2013-02-25T04:02:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2484
TitleTAG: What is the answer of question 6
I got 10%, 4 times the height 2.5. Why I am wrong?
UserIdTAG: 1253579
UserNameTAG: wetao
CreateTimeTAG: 2013-02-25T04:00:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Perhaps the system requires just the number without percent sign.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-02-25T07:05:45Z
FirstChildVoteTAG: 1
SecondChildTAG: you should out only 10, without %
SecondChildUserIdTAG: 1261536
SecondChildUserNameTAG: Andrebello
SecondChildCreateTimeTAG: 2013-02-25T14:36:38Z
SecondChildVoteTAG: 0
SecondChildTAG: ya//write only 10..thats true answer..
SecondChildUserIdTAG: 1293847
SecondChildUserNameTAG: shailesh1984
SecondChildCreateTimeTAG: 2013-02-25T19:35:43Z
SecondChildVoteTAG: 0
SecondChildTAG: I wrote 10, but im still wrong, maybe im calculating it in a bad way.
SecondChildUserIdTAG: 1055354
SecondChildUserNameTAG: jardouin
SecondChildCreateTimeTAG: 2013-02-26T17:14:04Z
SecondChildVoteTAG: 0
SecondChildTAG: What percent of students spent **fewer** than 4 hours - so I don't think its right to multiply 2.5 by 4 (as it is excluded).
However, I wish to ask - is the correct answer written with the % sign or without?
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-02-27T07:22:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Forget about what I just wrote - its wrong :)
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-02-27T07:24:40Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi there!
Yes, as said above by our friend You must not enter the % sign. Try to enter the numerical part of your responses only and you'll not have any problems next time.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-25T09:27:15Z
FirstChildVoteTAG: 0
IndexTAG: 2485
TitleTAG: Question 1b about test score is also ambiguious.
If a a student gets one answer out of ten correct (1/10) that is the same percentage as getting five points out of fifty possible (5/50) on a ten question test. 1/10 = 5/50. Therefore there is no distinction between a 'yes' value of 5 points and a 'no' value of 0 points. I thought in the lecture the prof said these special cases were not actually numerical but qualitative? I answered qualitative ordinal and was given a red x.
UserIdTAG: 31722
UserNameTAG: eDavis
CreateTimeTAG: 2013-02-25T03:55:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: i agree, this question is puzzling me - if right if 5 and wrong is 0, that would seem like a category, rather than anything else.
also, can you explain the first question - income would definitively be quantitative, but would also have to be discrete, due to the nature of money?
FirstChildUserIdTAG: 1122064
FirstChildUserNameTAG: BarbaraNK
FirstChildCreateTimeTAG: 2013-02-25T16:32:18Z
FirstChildVoteTAG: 0
FirstChildTAG: Math can still be done on this data, so ...
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:00:04Z
FirstChildVoteTAG: 0
IndexTAG: 2486
TitleTAG: Lec 1.3
I did the practice for Lec 1.3 but could not find the actual lecture. Was there one; and if yes, where can it be found? There is not a Chapter 1 in the e-book text.
UserIdTAG: 1138487
UserNameTAG: gperry
CreateTimeTAG: 2013-02-25T03:49:43Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: On top of the video square you could see a bar with three icons in the image of film. Clicking each film would play a new lecture video. You have to click all three film icons to watch all three lectures.
FirstChildUserIdTAG: 1208879
FirstChildUserNameTAG: deqalb
FirstChildCreateTimeTAG: 2013-02-25T14:39:43Z
FirstChildVoteTAG: 1
IndexTAG: 2487
TitleTAG: Question 1 **Solution **
A lot of people seem to be asking how to solve Question 1. This is how I did it.
Step 1: Age of the 6.6th percentile is 5.
Step 2: Age of the 19.9th (6.6 + 13.3) percentile is 15.
Step 3: Age of the 25th percentile is somewhere between 15 and 20.
Step 4: For each year within the third distribution, you have 0.7% people, assuming equal distribution. So, for 5.1 percent of people, you have 3.6 years (0.7 * (25 - 19.9)).
Step 5: Add 3.6 + 15 = 18.6 is the lower percentile.
Same idea for median and upper percentile.
Hope this helps. Thanks.
UserIdTAG: 1212282
UserNameTAG: kchavan
CreateTimeTAG: 2013-02-25T03:47:42Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: No, age of the 6.6th percentile is 4.
> Intervals include the left endpoint but not the right
That means that the first interval of 6.6% includes 0,1,2,3,and 4.
FirstChildUserIdTAG: 1284382
FirstChildUserNameTAG: kite420
FirstChildCreateTimeTAG: 2013-02-25T06:28:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Your statement is valid. But, when you make the computation, you have to view it from a slightly different perspective. In the third interval, you find that you get 3.6 years for 5.1 % people, however you cannot add that to 14 (where the second interval ends), you have to add that to 15.
SecondChildUserIdTAG: 1212282
SecondChildUserNameTAG: kchavan
SecondChildCreateTimeTAG: 2013-02-25T12:29:52Z
SecondChildVoteTAG: 0
SecondChildTAG: you just said it includes 0,1,2,3,4 which are really 5 not 4 as 0 is included and considered as a value
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-02-25T17:02:53Z
SecondChildVoteTAG: 0
SecondChildTAG: still cant understand why 15?
SecondChildUserIdTAG: 1051710
SecondChildUserNameTAG: VictorBeliakov
SecondChildCreateTimeTAG: 2013-02-26T16:53:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Look at it this way - the value you are trying to find is in the 15-20 yrs interval, right? So in order to gain the cumulative percentile, you work out how many years into the 15-20 intervals in needs to go to achieve the lower quartile. For the end result, you have to add up the years from the previous intervals to the value of 3.6 you have come up with.
SecondChildUserIdTAG: 919769
SecondChildUserNameTAG: MSpirova
SecondChildCreateTimeTAG: 2013-02-26T17:01:53Z
SecondChildVoteTAG: 0
SecondChildTAG: previous (second) interval ends at 14, right? so, 14+3.6=17.6, but it will be wrong answer
SecondChildUserIdTAG: 1051710
SecondChildUserNameTAG: VictorBeliakov
SecondChildCreateTimeTAG: 2013-02-26T17:45:16Z
SecondChildVoteTAG: 0
SecondChildTAG: iam sorry i cant unterstand the 4th & the 5th step i thougt the equation is for the lowr quartile is 15+(5.1/27)x(20-15) but didnt got the rigt answer iam little confused!!!
SecondChildUserIdTAG: 920087
SecondChildUserNameTAG: Areejo33
SecondChildCreateTimeTAG: 2013-02-26T20:41:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Lower quartile: 15+(5.1/7.1)*5. Note that you divide per 7.1 which is total percentage of the interval.
SecondChildUserIdTAG: 1270758
SecondChildUserNameTAG: leonardolamas
SecondChildCreateTimeTAG: 2013-02-26T22:41:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I got Problem 1 (a) wrong, too, because I also added 3.6 to 14. I got two different answers for Problem 1 (b) depending on whether I worked my calculations from the "bottom up" (i.e., Ages 0-45) or the "top down" (ages 100-30). I gave the apparently incorrect answer as 37 (because calculating from the bottom up, the answer is 36.97 years, even rounding to the nearest one decimal point pushes it up to a whole number of 37.0). However, when I calculated from the top down, the answer is 36.2. Is 36.2 the correct answer??? If yes, then why is it that we must calculate from the top down? If no, what am I doing wrong? I got Problem 1 (c) correct using the exact same method, but just working top down.
SecondChildUserIdTAG: 1091958
SecondChildUserNameTAG: DEnoch
SecondChildCreateTimeTAG: 2013-02-27T20:39:53Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with Guinto90, it's how many years on the horizontal axis should I move to raise the mark on the vertical axis to reach the 25, 50, and 75 points, so twill be (number of years in the interval/number of %age the mark moved on the vertical axis in the same interval). the same as our progress bars in the course, every time we finish a question the bars goes up by x%.
FirstChildUserIdTAG: 749006
FirstChildUserNameTAG: hishamhosny
FirstChildCreateTimeTAG: 2013-02-25T10:28:26Z
FirstChildVoteTAG: 0
FirstChildTAG: they probably don't care, but in case they do, better don't post solutions under the exercise. it's very nice for you to do so, but it's against policy: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
FirstChildUserIdTAG: 1207892
FirstChildUserNameTAG: triplebee
FirstChildCreateTimeTAG: 2013-02-25T16:59:57Z
FirstChildVoteTAG: 4
IndexTAG: 2488
TitleTAG: Course dateline
I just join the course today (02-24-13). I do not know if I am behind so that I can drop?
UserIdTAG: 1251294
UserNameTAG: deangawum
CreateTimeTAG: 2013-02-25T03:32:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I recomend you watch all the lectures. If you can watch all of them and do the exercises until their due date, great! But even if you don't finish the exercises in time, they will be available to you later. So keep calm and watch all the lectures at your pace. And try not to stay behind in the following weeks!
FirstChildUserIdTAG: 188586
FirstChildUserNameTAG: FLara
FirstChildCreateTimeTAG: 2013-02-25T03:43:52Z
FirstChildVoteTAG: 1
IndexTAG: 2489
TitleTAG: To staff: exercises data.
The data for the exercises should **always** be given. It is too hard to read what the exercise are asking, then going back to the video, forgeting what was being asked, going back to answer... I is so much simpler if the data is presented in the same page (unless it's too big to be shown, in wich case there should be a link directly to the data, not inside the videos).
Thanks.
UserIdTAG: 188586
UserNameTAG: FLara
CreateTimeTAG: 2013-02-25T02:57:56Z
VoteTAG: 27
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: I agree. To have to look through the video to find the data again is counterproductive, wastes time that could be spent working on the problems.
FirstChildUserIdTAG: 1180501
FirstChildUserNameTAG: apolubi
FirstChildCreateTimeTAG: 2013-02-25T03:38:31Z
FirstChildVoteTAG: 5
SecondChildTAG: thats a bit hectic but one can use the slide given below the videos
SecondChildUserIdTAG: 72412
SecondChildUserNameTAG: Manasvi
SecondChildCreateTimeTAG: 2013-02-25T05:41:18Z
SecondChildVoteTAG: 0
FirstChildTAG: This is why we were instructed to use the old-fashioned pencil and paper; we must write things down as necessary. This is a small requirement. You can also screen print stuff and save it in another window.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:04:30Z
FirstChildVoteTAG: 1
SecondChildTAG: Of course you can, but you don't know while watching the lectures, what you'll be asked about later on.
SecondChildUserIdTAG: 517550
SecondChildUserNameTAG: Ewa_G
SecondChildCreateTimeTAG: 2013-02-27T20:33:01Z
SecondChildVoteTAG: 0
IndexTAG: 2490
TitleTAG: Suggestion for Study materials
Two suggestions -
For the Slides link - I print for section prep, notes and later reference- Would it be possible to give the completed sheets within a set and not each step of development. Could be the difference of 5 pages and 25 pages for each section (saves trees - and page counting time to locate pages to print)
Also along with the Slides link or on the Syllabus - Could you list related recommended reading sections for the book? I noticed with the 1st problem set it linked to chapter 3.
Thank you for considering this.
UserIdTAG: 504031
UserNameTAG: Lindy7
CreateTimeTAG: 2013-02-25T02:42:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2491
TitleTAG: quest 1
I am bit confused with quest 1, I was able to get 100% of quest 2 and I applied the same principle to quest 1. Can anyone see why I am missing question 1? This is what I did.
I placed all the data in order 6 6.6 7.1 12.5 13.3 13.8 19.8 20.9
I then calculated 25% which was 6.6 but the answer is wrong
2. median was 50%
3. for upper quartile was 75%
Thank You..
UserIdTAG: 199172
UserNameTAG: Jani802
CreateTimeTAG: 2013-02-25T02:42:06Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: i'm sorry, i just can't understand this. where are the exercises or problems and where the 'classes'?
thank you
FirstChildUserIdTAG: 1305043
FirstChildUserNameTAG: zemariamunoz
FirstChildCreateTimeTAG: 2013-02-25T02:55:55Z
FirstChildVoteTAG: 0
FirstChildTAG: Step 1: Age of the 6.6th percentile is 5.
Step 2: Age of the 19.9th (6.6 + 13.3) percentile is 15.
Step 3: Age of the 25th percentile is somewhere between 15 and 20.
Step 4: For each year within the third distribution, you have 0.7% people, assuming equal distribution. So, for 5.1 percent of people, you have 3.6 years (0.7 * (25 - 19.9)).
Step 5: Add 3.6 + 15 = 18.6 is the lower percentile.
Same idea for median and upper percentile.
Hope this helps. Thanks.
FirstChildUserIdTAG: 1212282
FirstChildUserNameTAG: kchavan
FirstChildCreateTimeTAG: 2013-02-25T03:45:23Z
FirstChildVoteTAG: 0
IndexTAG: 2492
TitleTAG: .
This part was too confusing, I didn't know that if I had to put the answer in % or with decimals, I have checked some statistics books and the histogram part was one of the easiest in the book, and in here not!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-25T02:22:08Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: It would be more helpful if you would provide a title for your question so everyone can see the specific nature of your question.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-25T17:08:07Z
FirstChildVoteTAG: 0
IndexTAG: 2493
TitleTAG: Terminology
This post resulted from reading the linked descriptive text, wherein "Precision" is used and "Accuracy" is probably the meaning.
Some people believe that the two words Accuracy, and Precision, are equivalent in meaning. For the purposes of this course, I would suggest that this is not the case.
Accuracy refers to the closeness of a set of results to the true or desired value.
Precision refers to the closeness of each individual result to each other result, and has no relationship in measurement to accuracy.
Here is an example:
Accuracy in target shooting refers to the closeness to the centre or bullseye.
Precision refers to the grouping or spread of hits no matter where on the target the group appears.
Ten centre hits is superb accuracy, and also implies good precision, whilst ten hits at the target edge with same spread is good precision and poor accuracy.
Cheers,
Trance
UserIdTAG: 71796
UserNameTAG: Trance
CreateTimeTAG: 2013-02-25T02:13:36Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2494
TitleTAG: Density
In terms of 3b,I am wondering whether the lecture covers "density". If i would like to know more about this, where would you suggest i would go for these references. Thanks
UserIdTAG: 547145
UserNameTAG: Pronectar
CreateTimeTAG: 2013-02-25T01:38:05Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: density is defined as percent per unit, is it not? Percent per unit is covered in the lecture.
FirstChildUserIdTAG: 1284382
FirstChildUserNameTAG: kite420
FirstChildCreateTimeTAG: 2013-02-25T03:24:39Z
FirstChildVoteTAG: 2
FirstChildTAG: See Lecture 2-3: Units and Density
FirstChildUserIdTAG: 682760
FirstChildUserNameTAG: JUANBE
FirstChildCreateTimeTAG: 2013-02-26T19:46:01Z
FirstChildVoteTAG: 0
IndexTAG: 2495
TitleTAG: Anssers will not post
My answers will not post. What do I do. Is anybody out there?
UserIdTAG: 385997
UserNameTAG: Bruce909
CreateTimeTAG: 2013-02-25T01:11:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Click on the "check" or "Final check" button and your answer is recrded.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-25T02:13:56Z
FirstChildVoteTAG: 0
SecondChildTAG: In Problem 2, I only used one of my two submissions (and hit "check" to grade them). I am receiving a message that says my answers have been saved, but not graded. It says I should hit "check" to grade them. It looks like they have been graded though, since they have green check marks next to them. Can you please tell me if they have been graded? If not, what should I do? There is a "Final Check" button, but it doesn't seem to do anything.
SecondChildUserIdTAG: 1203606
SecondChildUserNameTAG: CarieK
SecondChildCreateTimeTAG: 2013-02-25T03:00:06Z
SecondChildVoteTAG: 0
IndexTAG: 2496
TitleTAG: Problem 3, Exercise Set 1- Error
Suppose another 20 green/green plants are introduced into the experiment above. ??? Impossible. The experiment above (Problem 2) has no green/green plants. Does this perhaps mean "Suppose 20 green/green plants"? What was intended.
Thanks
UserIdTAG: 385997
UserNameTAG: Bruce909
CreateTimeTAG: 2013-02-25T00:58:53Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You are correct, a better-worded question would have stated, "Supposed another 20 plants, which are green/green, are introduced into the experiment above."
FirstChildUserIdTAG: 1304034
FirstChildUserNameTAG: AndrewTung
FirstChildCreateTimeTAG: 2013-02-25T02:11:12Z
FirstChildVoteTAG: 1
FirstChildTAG: Nothing prevents a person adding cases as a follow on in an experiment.The another is referring to the plants.Not the attributes.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-25T02:12:58Z
FirstChildVoteTAG: 1
FirstChildTAG: That one messed me up as well. The wording was off, but I need to pay more attention.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-25T03:11:25Z
FirstChildVoteTAG: 0
IndexTAG: 2497
TitleTAG: Uniform distribution discussion
Some of you may think I should not post this, but in my understanding, discussion is fundamental in learning. And each student is responsible for his actions... If one looks at the discussions before answering the problems, he is the one being dishonest. I answered question 4c correctly, but I don't completely understand why, and thus we should discuss it. Why do you think the answer is what it is?
----------
I believe that the number of people who give up at one stage of education is a lot higher at the start of that stage. Many more people give up in university at the first year, than at the last year. That's why I think it is not reasonable to assume a uniform distribution at each interval. If it was a continuous curve, I think each interval would be like a decrasing exponential curve.
UserIdTAG: 188586
UserNameTAG: FLara
CreateTimeTAG: 2013-02-25T00:43:39Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 5
FirstChildTAG: I think it's also because the more spread out an interval, the more error is created in assuming a uniform distribution, and no body likes error.
FirstChildUserIdTAG: 21477
FirstChildUserNameTAG: SpecialKM
FirstChildCreateTimeTAG: 2013-02-25T00:56:45Z
FirstChildVoteTAG: 0
FirstChildTAG: > If one looks at the discussions before answering the problems, he is the one being dishonest
Okay. So someone who has agreed to the honor code can basically do whatever they like, as long as they preface it with "it's your fault if you look". Okay.
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-25T01:13:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Have you read the honor code? It says:
----------
Unless otherwise indicated by the instructor of an edX course, learners on edX are encouraged to:
- Collaborate with others on the lecture videos, exercises, homework and labs.
- Discuss with others general concepts and materials in each course.
SecondChildUserIdTAG: 188586
SecondChildUserNameTAG: FLara
SecondChildCreateTimeTAG: 2013-02-25T01:56:59Z
SecondChildVoteTAG: 0
SecondChildTAG: I have.
>Not post answers to problems that are being used to assess student performance.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-25T02:05:14Z
SecondChildVoteTAG: 0
SecondChildTAG: It's up to you, to see this post as an answer to the problem, or as a discussion to improve our understandig of a concept.
I'm trying to understand when it is reasonable to use that assumption. If you know, please tell me.
SecondChildUserIdTAG: 188586
SecondChildUserNameTAG: FLara
SecondChildCreateTimeTAG: 2013-02-25T02:41:34Z
SecondChildVoteTAG: 0
SecondChildTAG: In the lecture it was stated:
> So if we make the simplifying assumption that those 20% of people are
> **evenly spread over this interval**, **which is reflected in this bar
> having a flat top**, the same height throughout, then under those
> assumptions, we can do some calculations within the bar.
Since the correct histogram has a flat top why shouldn't I assume that the distribution is evenly spread out within the intervals?
SecondChildUserIdTAG: 1284382
SecondChildUserNameTAG: kite420
SecondChildCreateTimeTAG: 2013-02-25T04:00:21Z
SecondChildVoteTAG: 0
SecondChildTAG: @kite420 I wondered at that a bit. However, the histogram is an approximation of the data, and the question is about the data in the table. So, the question is asking you to make up your own mind about the data.
I'm certain you felt the data was a little bit of a simplified view because it reflects the real world, being pull from a 2012 census. It's almost poking a little fun at the insincerity of the histogram.
I got this one wrong, myself.
SecondChildUserIdTAG: 1253879
SecondChildUserNameTAG: ChrisKlaiber
SecondChildCreateTimeTAG: 2013-02-25T06:20:17Z
SecondChildVoteTAG: 0
SecondChildTAG: I am pleased by Flara's desire to have in-depth discussions about problems. Unfortunately, Christine and Aaron are pretty clearly correct that this post broke Coursera's honor code.
This does create a problem though. Most people aren't going to go back to this discussion area after the problem sets are due (I know I don't). I think discussion like this is vital to education, but what is the best way to allow it?
Personally I don't care about Coursera's honor code, and it didn't break my own personal honor code to post below the answer to Flara's (and other's) confusion.
SecondChildUserIdTAG: 398536
SecondChildUserNameTAG: liguoric
SecondChildCreateTimeTAG: 2013-02-26T18:53:59Z
SecondChildVoteTAG: 0
FirstChildTAG: The answer was not so much because of when people drop out of school. It's more about when people graduate from certain levels. By far the most common situations would be 12 (for those who stopped after high school) and 16 (for those who stopped after a Bachelors Degree). We could include two-year degrees and the like, but the point is that numbers like 12 and 16 are clearly going to be more popular than 13 and 17.
FirstChildUserIdTAG: 398536
FirstChildUserNameTAG: liguoric
FirstChildCreateTimeTAG: 2013-02-25T18:02:51Z
FirstChildVoteTAG: 1
SecondChildTAG: Also wanted to point out that this question is less about being able to decipher a histogram than it is about knowing the limits of it, notably its lack of precision.
SecondChildUserIdTAG: 398536
SecondChildUserNameTAG: liguoric
SecondChildCreateTimeTAG: 2013-02-26T18:56:29Z
SecondChildVoteTAG: 0
SecondChildTAG: But that's the point... The groups were chosen *well*, and the years 12 and 16 were separated out. That's why it was a "reasonable" approximation.
Otherwise, it's a trick question. It is never reasonable to assume uniform distribution.
SecondChildUserIdTAG: 1080056
SecondChildUserNameTAG: alexd457
SecondChildCreateTimeTAG: 2013-02-27T10:40:54Z
SecondChildVoteTAG: 0
SecondChildTAG: I forgot that 12-13 really only meant 12 due to the endpoint convention, which screwed up my explanation. My point remains mostly true, though my examples are no good. Alternatively, if we look at the 0-9 group, it is safe to assume that most of these people completed 8 years (graduating grade school) and so we cannot assume uniform distribution.
To re-itterate the main point. We cannot assume uniform distribution because, given the situation, some years are far more probable than others in the same range.
I'm pretty sure it's not the trick question you mention. My explanation should still be valid, but after realizing my endpoint mistake, the question is less obvious.
SecondChildUserIdTAG: 398536
SecondChildUserNameTAG: liguoric
SecondChildCreateTimeTAG: 2013-02-27T19:21:16Z
SecondChildVoteTAG: 0
FirstChildTAG: Flara, you wrote:
> Unless otherwise indicated by the instructor of an edX course, learners on edX are encouraged to:
Collaborate with others on the lecture videos, exercises, homework and labs.
Discuss with others general concepts and materials in each course.
Well, here is the text from the Discussion forum Guidelines issued by the instructors of this course:
> • Please do not post problem solutions. If you need help, post
errors you’re encountering, but not your answers.
Maybe it's just my interpretation, but I am pretty sure that qualifies as the instructors indicating we should "Not post problem solutions".
You posted the solution to 4c. That is not an opinion, it's right there, explicitly stated in your post.
Wait until the problem set closes if you want to discuss specific solutions.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-25T21:43:43Z
FirstChildVoteTAG: 0
SecondChildTAG: This is not a solution to this specific problem. This is a general discussion, trying to find when it is correct to use such assumptions, not for this specific case. The goal is not to give any answer, the goal is to learn in group.
SecondChildUserIdTAG: 188586
SecondChildUserNameTAG: FLara
SecondChildCreateTimeTAG: 2013-02-26T03:51:50Z
SecondChildVoteTAG: 0
FirstChildTAG: This is a statistics course, not one in epistemology. It is an un-reasonable question! As posted above, the professor's clues led one to believe that it is reasonable to expect an even distribution. As a trick question, it behooves the students to be tricky, IMHO. (You can assume I got the wrong answer!)
FirstChildUserIdTAG: 3044
FirstChildUserNameTAG: Gnasher
FirstChildCreateTimeTAG: 2013-02-28T17:32:22Z
FirstChildVoteTAG: 1
IndexTAG: 2498
TitleTAG: Wrong method
I'm sorry, but I must say that I think that the method exposed in minute 9.0 is wrong. In my opinion, Estimated_Median = 24 + 2/27 * (50 -25), for obvious mathematical reasons.
UserIdTAG: 43116
UserNameTAG: secobau
CreateTimeTAG: 2013-02-25T00:39:18Z
VoteTAG: 0
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 3
FirstChildTAG: I believe this histogram is assuming the left boundary is inclusive and the right boundary is exclusive, correct? In that case, your estimated median would exclude all incomes between 24,000.01 and 25,000.
FirstChildUserIdTAG: 1304034
FirstChildUserNameTAG: AndrewTung
FirstChildCreateTimeTAG: 2013-02-25T02:09:18Z
FirstChildVoteTAG: 1
SecondChildTAG: Please, could You explain why we are not including all incomes from 24,000.01 to 25,000? I thought that excluding 25,000 meant include up to 25000 - something like include up to 24,999.9(9).
SecondChildUserIdTAG: 197621
SecondChildUserNameTAG: quilombolo
SecondChildCreateTimeTAG: 2013-02-26T22:28:42Z
SecondChildVoteTAG: 0
FirstChildTAG: Since we are assuming uniform distribution in each category, then it doesn't matter if we are including left or right limits in a category, because a vanishing small amount will be at exactly the boundary, thus when interpolating into the region to find the given percentile you use the boundary value.
Another way to look at this method is to think about drawing a graph of the cumulative sum value. It will start at 0 at the lowest value, and (assuming uniform distribution in each category), rise linearly to the value at the end of the category. The slope of the line will be the density value for that category. (SO X axis is our variable measured, and the Y value will go from 0 to 100%)
To find a given %ile value, go across from that Y value till you cross the line, and see what X value that corresponds to, and that is what that formula does.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T02:53:18Z
FirstChildVoteTAG: 3
FirstChildTAG: Thanks, RichardDamon, you've got it exactly. The assumption of uniform distribution within bars removes all discreteness. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T22:20:23Z
FirstChildVoteTAG: 0
IndexTAG: 2499
TitleTAG: 0.16 <> 0.16% but 16%
It seems we have an issue with the % ...
UserIdTAG: 839804
UserNameTAG: M21
CreateTimeTAG: 2013-02-25T00:16:51Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: I rounded to .17% and was marked wrong. Is there a rounding convention?
FirstChildUserIdTAG: 252779
FirstChildUserNameTAG: msushi
FirstChildCreateTimeTAG: 2013-02-25T00:45:22Z
FirstChildVoteTAG: 0
FirstChildTAG: Except you are already calculating in percents, M21. The area of that bar is 5%, or .05. Divide that by 30 and you get .16%, or .0016.
FirstChildUserIdTAG: 1304034
FirstChildUserNameTAG: AndrewTung
FirstChildCreateTimeTAG: 2013-02-25T02:17:49Z
FirstChildVoteTAG: 1
IndexTAG: 2500
TitleTAG: Money ,incomes, accounts and variables.
My question is in US currency less than 0.01 USD does not exist. So differences less than 0.01 USD in accuracy should not exist also.That means that for different incomes and bank accounts one can assume that by default are measured down to 0.01 and so are discreet variables. E.g. The smallest difference of an income of 25000 USD can not be less than 25000.01 USD or more than 24999.99 USD.Or else a smart guy say of the federal bank can collect the unpaid differences less than that after rounding the amounts and become the new Gates in one day. If anyone wants to discuss please feel free.
UserIdTAG: 1239975
UserNameTAG: Xenofon
CreateTimeTAG: 2013-02-25T00:09:46Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I came to the same conclusion. Income, is most definitely discrete, as there is no unit less than .01 (for countries that still use a penny or its equivalent.) In addition, adding, subtracting, or taking the average of incomes results in relevant data. Some surveys and forms list income in ranges, but that was not specified in this question.
FirstChildUserIdTAG: 979415
FirstChildUserNameTAG: dhinck
FirstChildCreateTimeTAG: 2013-02-25T02:10:09Z
FirstChildVoteTAG: 0
SecondChildTAG: If the minimal incremental difference is much smaller than the numbers being measured, then for practical purposes we can ignore the discrete nature of the variable.
It is also possible to keep track of monetary values to a finer precision than the currency, you just can't settle the residual, but it can be applied to future transactions. (Not all/many place keep track of that, but I regularly by items with prices that go into fractions of pennies in precision, that become meaning full when purchasing large quantities).
A company could easily pay a person an annual salary that wasn't an integral number of pennies a year (at least on the average), by some years paying a bit more, and some year a bit less.
SecondChildUserIdTAG: 1222946
SecondChildUserNameTAG: RichardDamon
SecondChildCreateTimeTAG: 2013-02-25T03:05:07Z
SecondChildVoteTAG: 0
SecondChildTAG: I do not think income is discrete. if you say so, then a person's height is also discrete - as you can not, using normal tools, measure less than a millimeter; and so would be the amount of liquid in a container.
Another way to look at is - income is always relative to a time period. You can convert an annual income to monthly, weekly, daily, hourly income. In all these cases, a perfectly round figure annual income could become an irregular fraction. For example if someone earns $32000 per year, it is 2666.666666666... per month, 615.384 per week approx. and so on.
A discrete or a continuous variable definition is relative to a framework, and in our real-life practical framework, income - as well as height - should be considered continuous.
SecondChildUserIdTAG: 44426
SecondChildUserNameTAG: nmadhuusa
SecondChildCreateTimeTAG: 2013-02-25T03:47:25Z
SecondChildVoteTAG: 0
SecondChildTAG: There is a difference.
You can make a better and better ruler to figure out height with more and more accuracy but you cant for income.
The base unit of income in the US is a cent as that was what decided by the government. There is no improvement in measuring income that can change this base precision.
" For example if someone earns $32000 per year, it is 2666.666666666... per month, 615.384 per week approx. and so on."
You can make any discrete variable into a continuous variable by using that logic -of dividing the base unit so that it is effectively not discrete anymore.
SecondChildUserIdTAG: 1294449
SecondChildUserNameTAG: jesse9
SecondChildCreateTimeTAG: 2013-02-25T05:20:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Could you make number pages of a book into a continous variable?
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-25T09:56:44Z
SecondChildVoteTAG: 0
SecondChildTAG: While residuals and fractions of a penny (USD) are reasonable concepts, I wouldn't expect them to be universally understood as intended to be included in response to the question, "What is your income?" I considered both of those options before concluding that "discrete" was more appropriate, so I'm obviously biased, but the question seems ambiguous at best if continuous is the intended answer.
SecondChildUserIdTAG: 972389
SecondChildUserNameTAG: finedaniels
SecondChildCreateTimeTAG: 2013-02-25T09:56:48Z
SecondChildVoteTAG: 0
IndexTAG: 2501
TitleTAG: Lot of people having problems with Set 2 , problem 3, b)
Is there some error on that problem?
Do we need some assistance from Teacher?
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-24T23:30:24Z
VoteTAG: 2
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 3
FirstChildTAG: Yes, it would be helpful if a member of the faculty/staff would clarify whether or not there is a error. I suppose many students are reserving their "tries" until it is confirmed that there actually IS a correct graph among the three choices. It is only 8:30 in the morning in California so I will check back for a staff response later.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-02-25T16:33:15Z
FirstChildVoteTAG: 0
FirstChildTAG: There is no error there is a correct answer.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-25T18:39:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Are you a staff member?
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-02-25T18:55:47Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm not, but there is a correct answer.
SecondChildUserIdTAG: 1158056
SecondChildUserNameTAG: CanuckistaniPhilosopher
SecondChildCreateTimeTAG: 2013-02-26T00:37:11Z
SecondChildVoteTAG: 0
SecondChildTAG: I am not but there is indeed a correct answer !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-26T02:15:35Z
SecondChildVoteTAG: 0
SecondChildTAG: The link doesn't go to Set 2, it goes to Set 3. Why? One can only wonder.
SecondChildUserIdTAG: 845623
SecondChildUserNameTAG: ChristineStv
SecondChildCreateTimeTAG: 2013-02-26T02:17:48Z
SecondChildVoteTAG: 0
FirstChildTAG: Why have you put this question in the subforum for Set 3, if your question relates to Set 2?
FirstChildUserIdTAG: 845623
FirstChildUserNameTAG: ChristineStv
FirstChildCreateTimeTAG: 2013-02-26T02:16:18Z
FirstChildVoteTAG: 0
SecondChildTAG: you are write, is there an easy way to change it to the correct thread?
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-02-26T13:28:21Z
SecondChildVoteTAG: 0
IndexTAG: 2502
TitleTAG: Accidentally pressed final check before even looking at the problem
Completely inadvertently pressed final check on problem 4. There should be come kind of warning pop up when one has not answered all the questions, so that a person can cancel the action. Depressing to get points subtracted without even being able to attempt it.
UserIdTAG: 537121
UserNameTAG: kelceywilson
CreateTimeTAG: 2013-02-24T23:28:00Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Sorry to hear that, it kills me to see those red x's, especially if it isn't your fault.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-25T00:10:27Z
FirstChildVoteTAG: 0
SecondChildTAG: totally agree. Did the same thing yesterday. Any pop up warning would be a great add on in the future. I'm quite sure there are more people who did same mistake.
Thanks, M
SecondChildUserIdTAG: 1270740
SecondChildUserNameTAG: martinov
SecondChildCreateTimeTAG: 2013-02-28T08:14:38Z
SecondChildVoteTAG: 0
IndexTAG: 2503
TitleTAG: A proposed solution to a repeated post-generating question
I have a suggestion to make everyone's lives easier, both staff and students.
For any question where the answer is a number typed into a text box, have the question include an example of the format expected, as in:
"For this answer, we want a percent to two decimal places. For example, if your result could be expressed by the fraction 1/3, you would enter 33.33 (no percent symbol)."
That would reduce: the frustration of students; the number of submissions burned through on testing formatting, rather than math or concept errors; the volume of discussion posts written on the same issue; the number of posts on new issues to scroll through for readers; the posts to respond to for staff.
It's a simple adjustment and would just generally make for a better experience for all.
It is also much clearer than "...a percent to two decimal places." Is that two decimal places *before* converting to a percent, or after?
For example, take 1/3 or .3333, would one then enter .33, or 33 or 33.33? The correct answer format is less important than the fact that all three answers are correct, but the auto-grader will only take one of the formats.
Best to make it clear with an example.
UserIdTAG: 972465
UserNameTAG: ToddCioffi
CreateTimeTAG: 2013-02-24T23:21:36Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: seems reasonable
FirstChildUserIdTAG: 966752
FirstChildUserNameTAG: FDB623
FirstChildCreateTimeTAG: 2013-02-25T02:28:12Z
FirstChildVoteTAG: 0
IndexTAG: 2504
TitleTAG: Problem with getting all formulaes together
how can i get all formulaes together related to my course? in WIKI there's only updates.
UserIdTAG: 1043829
UserNameTAG: 49141
CreateTimeTAG: 2013-02-24T22:48:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Your best bet is to write them down in a notebook as they come up in the lectures and textbook. You can also edit the Wiki yourself and add to the formulas that are already there.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-25T21:50:26Z
FirstChildVoteTAG: 0
IndexTAG: 2505
TitleTAG: ??
Deberían ser mas claros con los formatos de las respuestas si en . o , y si lleva el signo de porcentaje...
UserIdTAG: 1232447
UserNameTAG: LinaQuevedo
CreateTimeTAG: 2013-02-24T22:29:09Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Translation:
They should be clearer with the formats of the responses if in. or, y if it takes the sign of percentage...
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-25T02:59:59Z
FirstChildVoteTAG: 0
IndexTAG: 2506
TitleTAG: problem 1 b
guys what is the correct answer of question 1 (b) score on a test where each answer gets 5 points if it is right, and 0 points otherwise??
UserIdTAG: 1045331
UserNameTAG: manoj12690
CreateTimeTAG: 2013-02-24T22:18:48Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/honor
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T22:48:54Z
FirstChildVoteTAG: 3
SecondChildTAG: I think the correct answer is Quantitative discreet
SecondChildUserIdTAG: 1173471
SecondChildUserNameTAG: jides
SecondChildCreateTimeTAG: 2013-02-25T11:07:07Z
SecondChildVoteTAG: 0
IndexTAG: 2507
TitleTAG: Excelent
Excelent
UserIdTAG: 1232447
UserNameTAG: LinaQuevedo
CreateTimeTAG: 2013-02-24T22:17:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2508
TitleTAG: Respuestas
Ser mas claros con los formatos de las respuestas!
UserIdTAG: 1232447
UserNameTAG: LinaQuevedo
CreateTimeTAG: 2013-02-24T21:55:34Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Se ha dicho muchas veces ya. Ellos lo entiendo.
Also, please stick to English in this discussion forum.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T22:05:49Z
FirstChildVoteTAG: 0
SecondChildTAG: It has been said in a lot of posts, but in English ;-)
I agree with you. We should stick to English, but, IMHO, it doesn't hurt to answer **occasionally** in other language, if someone has real problems and needs help.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-24T22:35:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Maybe. But a requirement of the course is a good comprehension of English.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-24T22:48:22Z
SecondChildVoteTAG: 0
SecondChildTAG: You are right, Susan. But I'm trying to put me in the place of someone who, urged by anxiety and without enough confidence to write in English, ask for help in her native language. Maybe I'm wrong.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-24T23:36:03Z
SecondChildVoteTAG: 0
FirstChildTAG: Lina, el tema se ha comentado ya, los responsables son conscientes y tratarán de dejar esto más claro en los próximos problemas.
Si tienes dificultades con el idioma, puedes hacer alguna pregunta en español, siempre que sea sólo en contadas ocasiones (es mi opinión, no sé si no debería hacerse en absoluto, pero en algún otro curso ha sucedido). Yo, si puedo responder, lo haré con gusto.
Hay aquí más hispanohablantes. Quizá alguien haya creado un grupo para discutir en español temas del curso. Busca en el foro por si ves algo en este sentido (Facebook, ...). Un saludo.
----
Lina, this issue has been already discussed. The staff is working to make it clearer for the next assignments.
If you have problems with English, you can occasionally ask for help in Spanish. If I can, I'll be glad to answer.
There are Spanish speakers here. Search the form for other possible and better paths (Facebook, etc.) to discuss about the course in Spanish. Greetings!
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-24T22:51:52Z
FirstChildVoteTAG: 0
IndexTAG: 2509
TitleTAG: For Staff: are courses 2.2 and 2.3 to be offered also?
Hi,
Into lecture for 2.1 mentioned courses 2.2 (probability) and 2.3 (inferential). Will these also be offered after 2.1 ends?
Thanks
Paul
UserIdTAG: 678934
UserNameTAG: Paul_Thomas
CreateTimeTAG: 2013-02-24T21:45:29Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: That would be cool!
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-25T00:12:06Z
FirstChildVoteTAG: 0
FirstChildTAG: We're planning on Stat 2.2X to start two weeks after the end of 2.1X. Date for 2.3X still not nailed down, but unless something awful happens, I expect it will start a week or two after 2.2X. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T03:28:50Z
FirstChildVoteTAG: 17
SecondChildTAG: ***high5*** to Prof A
SecondChildUserIdTAG: 7545
SecondChildUserNameTAG: jasontimothyjones
SecondChildCreateTimeTAG: 2013-02-25T08:02:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Nice
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-25T15:27:55Z
SecondChildVoteTAG: 0
SecondChildTAG: fantastic
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-02-27T09:57:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Cool! Thanks
SecondChildUserIdTAG: 678934
SecondChildUserNameTAG: Paul_Thomas
SecondChildCreateTimeTAG: 2013-03-04T17:40:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for that Info.
You lectures have been a saviour. Excellent methods, Perfect Rate of Speech and Simple approach.
Thanks! :)
SecondChildUserIdTAG: 786512
SecondChildUserNameTAG: shoaibkhanz
SecondChildCreateTimeTAG: 2013-03-07T10:41:25Z
SecondChildVoteTAG: 0
SecondChildTAG: cool :)
SecondChildUserIdTAG: 1258339
SecondChildUserNameTAG: Dondic
SecondChildCreateTimeTAG: 2013-03-08T13:53:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Yay!! Can't wait. :D
SecondChildUserIdTAG: 230828
SecondChildUserNameTAG: alanis
SecondChildCreateTimeTAG: 2013-03-11T17:10:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I am in for all of 2.2x and 2.3x if it is offered for sure. I have thoroughly enjoyed this course. Thanks
SecondChildUserIdTAG: 139386
SecondChildUserNameTAG: Pembertonbc
SecondChildCreateTimeTAG: 2013-03-21T17:26:29Z
SecondChildVoteTAG: 0
IndexTAG: 2510
TitleTAG: Exercise Set 2 Problem 4(c)
Hi Everybody,
Why is it unreasonable to assume a uniform distribution of educational level in each interval?
Thanks
UserIdTAG: 914120
UserNameTAG: TezzieTiger
CreateTimeTAG: 2013-02-24T21:33:05Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Please edit your post and remove this answer to a graded question. We're still under honor code.
We'll be able to discuss it after the due date, but until then, please refrain from posting other answers.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T22:08:40Z
FirstChildVoteTAG: 0
IndexTAG: 2511
TitleTAG: set 2 Problem 2 (a) and (b)
I do not understand that from a range of 60 to 75 how can 65 be separately taken...like how can we find the value of % of people agedabove 65 when th range is from 60 years. Please help me out with his as I am stuck up with this problem.
UserIdTAG: 1242151
UserNameTAG: lhasan
CreateTimeTAG: 2013-02-24T21:30:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: In part (b), we made the assumption that the ages are uniformly distributed within each interval. This means that in the interval 60-75, the same percent of people are aged 60 as those aged 61,62,63... and so on up to 74. Therefore we can divide the 60-75 interval into 15 equal pieces. 12.5 / 15 = 0.83. Multiply that by 10 to get the percent of people aged between 65-75. 0.83*10 = 8.3. Add to that the percent in the interval 75-100 and you get 8.3+6.0 = 14.3.
The assumption won't be true in real life but we made the assumption for this histogram.
FirstChildUserIdTAG: 914120
FirstChildUserNameTAG: TezzieTiger
FirstChildCreateTimeTAG: 2013-02-24T21:47:13Z
FirstChildVoteTAG: 7
SecondChildTAG: And here I was just making a post about the futility of honour codes. Thanks for proving a point.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-24T21:51:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Quick question.. the answer I put in for 2b had a % sign at the end - was that incorrect as the software marked it as wrong? (I believe the answer was correct and showed it to one dp as requested)
SecondChildUserIdTAG: 1190144
SecondChildUserNameTAG: Paul100
SecondChildCreateTimeTAG: 2013-02-24T22:44:55Z
SecondChildVoteTAG: 0
SecondChildTAG: SusanAust, I think most of the people taking this class are doing so to increase their knowledge. I highly doubt people are asking questions just so they can mark the correct answers and move on - those type of people probably wouldn't sign up anyway. You can tell from this person's question that he/she is genuinely interested in learning.
I understand the value of an honor code but it's not like we're sitting in a classroom at individual desks taking a test that is going to affect our GPA. These grades aren't going to affect our GPAs or give us class credit so why does it really matter if we discussed the answer beforehand? And I don't think the point of these classes are to see who can get the right answers by working in isolation but to help each other understand by collaboration.
So, go easy on this :)
SecondChildUserIdTAG: 1081125
SecondChildUserNameTAG: umanb89
SecondChildCreateTimeTAG: 2013-02-25T07:20:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't understand what means 12.5,can someone explain me ?
SecondChildUserIdTAG: 1158693
SecondChildUserNameTAG: dabad
SecondChildCreateTimeTAG: 2013-02-25T21:10:18Z
SecondChildVoteTAG: 0
SecondChildTAG: I have a different answer to this question. Since the senior citizen is defined as people aged over 65, so the senior citizen should have a interval between 66-100. Thus, we should multiply the height 0.83 by 9 to get the percent of people aged between 66-75. 0.83*9=7.5. Add the percent in the 75-100 and I get 7.5+6.0=13.5. However, the grader includes 65 as the boundary of senior citizen, which I don't think it is correct.
SecondChildUserIdTAG: 312887
SecondChildUserNameTAG: Bird
SecondChildCreateTimeTAG: 2013-02-25T21:59:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I too excluded 65 at first but then thought that these are continuous and not discrete. So 65 and 1 day is over 65 as would be 65 and one millisecond. Hence the inclusion...I think
SecondChildUserIdTAG: 504031
SecondChildUserNameTAG: Lindy7
SecondChildCreateTimeTAG: 2013-02-26T03:13:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Love the columns,by Lindy7 and Bird.Actually i was thinking like Bird,and to make it clear 60-75(makes 75 a right endpoint that is excluded from our calculations despite being over 65).And with me it is inclusively taken careof in the 75-100 range because the left endpoints are inclusive of the calculation.Adding it to our age of >65 in both ranges makes me feel we are taking care of it twice!!!!!Any help!!!
SecondChildUserIdTAG: 596280
SecondChildUserNameTAG: Rousseus
SecondChildCreateTimeTAG: 2013-02-28T11:12:01Z
SecondChildVoteTAG: 0
FirstChildTAG: It appears that the software wants to see answers without the % sign in them (as should have been found playing with the sample questions)
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T03:09:14Z
FirstChildVoteTAG: 0
IndexTAG: 2512
TitleTAG: Lecture 1.1
Dr. ANI ADHIKARI's voice is so calm and interesting, I'm already enjoying the STATISTICS and trying to learn as much as I can !
cheer up
Bill
UserIdTAG: 967906
UserNameTAG: Billchau2013
CreateTimeTAG: 2013-02-24T21:27:02Z
VoteTAG: 7
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 1
FirstChildTAG: Yeah, she's good! The pauses were a little annoying in an introduction, but i suppose they'll be helpful later, when you need to think
FirstChildUserIdTAG: 484877
FirstChildUserNameTAG: Andre97
FirstChildCreateTimeTAG: 2013-02-25T19:18:31Z
FirstChildVoteTAG: 0
IndexTAG: 2513
TitleTAG: Error
I didn't expect this kind of errors... the explanation of exercise "a" (14/10) is flat-out wrong, as everybody already noticed.
UserIdTAG: 1116891
UserNameTAG: HoraCL
CreateTimeTAG: 2013-02-24T21:22:48Z
VoteTAG: 12
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: >as everybody already noticed
Then why didn't you respond to one of the existing hundreds of posts instead of adding to the clutter?
>I didn't expect this kind of errors..
This is a new course, on a revamped platform. Of course there are going to be errors, crashes, hiccoughs.
It seems that hundreds here can't follow basic instructions, can't read the syllabus or policies, yet are quite happy to jump all over the staff for any technical mishap or error.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:31:44Z
FirstChildVoteTAG: 2
IndexTAG: 2514
TitleTAG: Not happy withe the format of the answer to Lec 2.4 (b)
Im finding it a little difficult to understand the exact requirements in the questions. I have recorded several wrong answers as the unit request isn't clear.
To me, if the question asks for an answer (in $) to one decimal point it should have been 37321.4 rather than 37.3 (i.e. 37.3 thousand)
UserIdTAG: 896043
UserNameTAG: Mike503
CreateTimeTAG: 2013-02-24T21:22:47Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: Part a of the problem explicitly says that the answer must be "in thousands of dollars", and then part b makes a reference to the instructions of part a.
It's fairly obvious that the two answers are supposed to have the same format, or at least it is to me ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T21:57:40Z
FirstChildVoteTAG: 1
SecondChildTAG: I thought part B) meant actual decimals also and that the instructors were testing us to see if we were paying attention. I bet this software could recognize a correct answer entered either way.
SecondChildUserIdTAG: 945143
SecondChildUserNameTAG: joddde
SecondChildCreateTimeTAG: 2013-03-05T13:17:56Z
SecondChildVoteTAG: 0
IndexTAG: 2515
TitleTAG: Journalist in the class
Hi all,
I'm Byrhonda, a graduate student at UC Berkeley. I'm taking this class because I need to sharpen my stats skills. I'm also working on a story about how these classes work. I guess I'm killing two birds with one stone. :-)
If any of you are interested in talking about your MOOC experience, email me at byrhondal@gmail.com.
Best,
B
UserIdTAG: 1224942
UserNameTAG: byrhonda8
CreateTimeTAG: 2013-02-24T21:22:37Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Hello byrhonda8.... I will be happy to let you know my experience. By the way, what does MOOC stand for?
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-25T03:31:27Z
FirstChildVoteTAG: 0
IndexTAG: 2516
TitleTAG: Histograms
The discussion on histograms makes no sense! Not mathematically incorrect but practically. The graphs are intended to be misleading! For example a width of 100 - 150 does not include any income over 150! Period. This is not correct to include incomes over 150 in this category.
Also, I can easily divide 0 to 150 into equal intervals. Again this is misleading graphs. Why would anyone want to graph intervals that are not equal unless the idea is to complicate and confuse.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-24T21:12:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: The page you link to has bar charts. So what question are you talking about?
The correct use of subforums will make it easier for everyone.
>The discussion on histograms makes no sense!
To some.
> The graphs are intended to be misleading!
No. I don't understand why so many believe that the questions are "trick questions". If you understand the material, there is no "trick" or "misleading" involved.
> For example a width of 100 - 150 does not include any income over 150! Period. This is not correct to include incomes over 150 in this category.
You lost me here.
>Why would anyone want to graph intervals that are not equal unless the idea is to complicate and confuse.
It makes perfect sense.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:30:08Z
FirstChildVoteTAG: 0
FirstChildTAG: As I see it, data, in its raw form, is all but useless. To make some sort of sense, it needs to be organized in a way that conveys some meaningful information, and that's the job of graphs like the histogram.
In some cases, it's easier to convey information if you divide the data into ranges that represent certain categories, and these ranges might need to be uneven.
Take the income table, for example. The range of 0-10 thousand dollars represents the "poor" strata of the population, while 100-150 represents the "rich" strata, and the others in the middle are intermediate styles of life. This conveys additional information about the people whose income you are summarizing, that might be very useful to understand the financial situation of the country.
Dividing 0-150 into 5 even ranges is certainly possible, but loses that additional information. People who make 9000USD a year and people who make 20000 live very differently, and if you clump them together in the graph, you lose that difference between them and are **not** accurately describing the different "classes" of population.
Of course, you(and the ones that the table/graph is intended for) might not care about that additional information. In that case, feel free to compile your data using even ranges. It all depends on what your goal is.
As for including 150+ into the 0-150 range: again, it's a question of having meaningful information. If that 150+ range represents a really low, even insignificant part of the total, it's just a waste of time and space to have a different range for them.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T21:52:42Z
FirstChildVoteTAG: 1
FirstChildTAG: sure, the histogram does not tell the whole story; we do not know how many made over 150k;but it tells the story about 99% of the population. It comes down to what portion of the population is relevant to us. As far as the uniform interval assumption ; it meant to simplify ; it gets more complicated later on.
FirstChildUserIdTAG: 142494
FirstChildUserNameTAG: jaria101
FirstChildCreateTimeTAG: 2013-02-24T22:32:07Z
FirstChildVoteTAG: 0
FirstChildTAG: The lecture video explained the issue of the 150+ contingent. Basically, it is such a small proportion, spread over such a large interval as to be visually minimal. Instead of losing the data altogether, it is "swept in" to the last data set.
If one instead changed the category to be 100+ (or 100 - infinity), how could you calculate the width - and therefore the height - of the bar in the histogram? As the bar approaches infinite width, it approaches zero height. Visually, you have stretched the data to the point that all you have done is turn the 100-150 data set into the 150+ data set - the one that you can't see.
If the bulk of the 100+ data is between 100-150, isn't it a more accurate visual representation to use that as a bar in your histogram, as long as you note the part about the upper values being swept in?
If you are using categories rather than a list of raw numbers, you sacrifice the level of detail that makes the level of accuracy you're concerned about matter.
If you're showing a graph using units of Millions of Euros, it is pointless to worry about showing cents. That's like arguing over the precision of the width of the line used to enclose the bar (actually, the line width would be more useful).
If you want real numbers, if these are US figures, you'd be talking about an income-earning population on the scale of xxx,000,000. I believe that stat is that the richest 400 make more than the bottom half combined. That's about 0.000002. The data entry error on 200 million people is going to be higher than that.
In theory, I totally get why you're concerned. In reality, it's precision without value, like calculating the height of people out to the [Angstrom][1].
[1]: http://en.wikipedia.org/wiki/Angstrom
FirstChildUserIdTAG: 972465
FirstChildUserNameTAG: ToddCioffi
FirstChildCreateTimeTAG: 2013-02-25T00:38:57Z
FirstChildVoteTAG: 0
FirstChildTAG: The other part of your concern assumes that there is one "best" way to represent an idea.
"Why do people speak Greek when we should all just speak Latin?" "Why do we have pie charts, or scatter plots, or stacked bars, or trend lines, or ... , when I already understand bar charts?"
"Why did Mondrian use color blocking or Pollock drizzle paint or Monet's haystacks come out so fuzzily? Buy a 10 mpx camera already!"
A picture may be worth a thousand words, but only if it's the *right* picture.
The intro materials to this class expressed that one of the course goals was to show people (and for the students to learn) how to understand and to present complex data in forms that other people can then understand.
You're two days in to being taught how to be a painter and you're complaining about how they're making you hold your first brush.
FirstChildUserIdTAG: 972465
FirstChildUserNameTAG: ToddCioffi
FirstChildCreateTimeTAG: 2013-02-25T00:50:15Z
FirstChildVoteTAG: 0
FirstChildTAG: The including of data past the top end of the range is done to simplify the data. If we were doing serious analysis of this data, we would likely be using many more finer division (to get around the problems of needing to assume uniform distribution over large ranges).
For the small number of categories we are using, to extend the top one to the real top value would drop the density for that box to almost nothing, and stretch the horizontal scale such that the data we are looking for would be all bunched up to the left. You could also add an extra box for those above 150k, but its area would be extremely small, and again, would stretch out the axis. (Since we are plotting density, it CAN'T be just 150k and up). When dealing with the type of statistics that we are here, the very small numbers on the very long tail don't affect things and can be ignored (this is one advantage of working with percentiles, they tend to minimize the effect of a small number of outlier data points). Later, I suspect that we will be doing other operations to summarize data which don't have this property and then it will be important to be careful with the simplifications.
As to not using equal intervals, often it is important to show more details in certain ranges than in others, there may be key values that it is good to be able to show, and these may not be on nice spaced grid points, or to sample data tighter in regions with more data in them. As an example, if you evenly space the income chart, and really include all levels, then unless you had a very large number of divisions, almost everyone would end up in the bottom one, and only that negligible tail would show up in the rest. Not very useful data.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T03:31:01Z
FirstChildVoteTAG: 0
IndexTAG: 2517
TitleTAG: Width of Class -10 to 20
I cant understand, how the width of this is +10 and not 30.
UserIdTAG: 1151770
UserNameTAG: mmussani
CreateTimeTAG: 2013-02-24T20:36:28Z
VoteTAG: 33
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: It's an mistake. The correct width is 30. the grader is wrong
FirstChildUserIdTAG: 804886
FirstChildUserNameTAG: marlasinger1470
FirstChildCreateTimeTAG: 2013-02-24T20:48:31Z
FirstChildVoteTAG: 0
FirstChildTAG: Use the search function, read other posts directly below this one. You'd be surprised at what you find.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T20:57:13Z
FirstChildVoteTAG: 0
SecondChildTAG: I have the same question as mmussani but do not understand your response. Is it an error or no? The interval from -10 to 20 is 30, no? I have searched histogram and checked a couple dozen posts now, and have not been able to find a definitive answer...
SecondChildUserIdTAG: 537121
SecondChildUserNameTAG: kelceywilson
SecondChildCreateTimeTAG: 2013-02-24T22:09:40Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-24T22:11:23Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, the correct width should be 30.
FirstChildUserIdTAG: 1087697
FirstChildUserNameTAG: coynesa
FirstChildCreateTimeTAG: 2013-02-25T00:35:48Z
FirstChildVoteTAG: 1
SecondChildTAG: I agree--frustrating when you're a beginner and unsure of yourself to get the wrong answer due to their error.
SecondChildUserIdTAG: 252779
SecondChildUserNameTAG: msushi
SecondChildCreateTimeTAG: 2013-02-25T00:42:44Z
SecondChildVoteTAG: 0
SecondChildTAG: +20 - (-10) = 20 + 10 = 30
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-02-25T12:20:30Z
SecondChildVoteTAG: 0
SecondChildTAG: the negative numbers, -10, for example, are always to be put in bracelets (), witch means calculating them in modulus (-10) when used in mathematical operations
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-02-25T12:23:06Z
SecondChildVoteTAG: 0
SecondChildTAG: totally agree with you
SecondChildUserIdTAG: 234269
SecondChildUserNameTAG: Gauravarora
SecondChildCreateTimeTAG: 2013-02-27T21:47:51Z
SecondChildVoteTAG: 0
FirstChildTAG: I have the same question, I think they make a mistake.
FirstChildUserIdTAG: 60773
FirstChildUserNameTAG: billchenxi
FirstChildCreateTimeTAG: 2013-02-25T02:34:44Z
FirstChildVoteTAG: 0
IndexTAG: 2518
TitleTAG: Histograms and scatter graphs
Does the data from a histogram translate visually to a scatter graph?
UserIdTAG: 1136968
UserNameTAG: susanmack
CreateTimeTAG: 2013-02-24T20:34:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Scatter graphs are used for different purposes than a histogram. Histograms plot the distribution of a population where values are the density, and areas of curves show population (and the form we are using are for a single valued measurement).
Scatter graphs do not have areas, but, at least as I tend to use them, each data point represents a single sample and relates typically 2 values of that sample.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T03:38:14Z
FirstChildVoteTAG: 0
IndexTAG: 2519
TitleTAG: Problem 7
Your table that you reference in Problem 7 is too unclear and hard to read. The item under height beside "10-15" looks like a number "7", when it is actually supposed to be a question mark.
UserIdTAG: 211303
UserNameTAG: DLT28
CreateTimeTAG: 2013-02-24T20:33:45Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: YEs, at first glance i didnt notice it was a question mark.
FirstChildUserIdTAG: 1222835
FirstChildUserNameTAG: CatonElMenor
FirstChildCreateTimeTAG: 2013-02-24T23:02:05Z
FirstChildVoteTAG: 1
IndexTAG: 2520
TitleTAG: Histograms
What are the value of histograms with regard to data interpretation is the incremental size of each unit is not the same? I see a purpose distribution wise, but how would you use non-comparable data in analysis?
UserIdTAG: 1212633
UserNameTAG: DavidKStern
CreateTimeTAG: 2013-02-24T20:10:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: I'm not sure I've understood your question, but I'll try to answer what I've understood. There's no problem with saying, for example, that 20% of the people are in the 10-15 interval and 25% are in the 15-25 interval. What the height of the histogram allows you to do is to say that there was a greater concentration of people in the 10-15 interval (height 4% per unit) compared to the 15-25 interval (height 2.5% per unit).
Often you don't want equal-width intervals, for example when the range of data is large and there's very little data out at the edges.
No "non-comparable" data are being used. Maybe I haven't understood your question?
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T03:35:48Z
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IndexTAG: 2521
TitleTAG: drdenx
I was marked wrong for adding the % to the answers
UserIdTAG: 1024394
UserNameTAG: drdenx
CreateTimeTAG: 2013-02-24T20:01:45Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2522
TitleTAG: Problem 5
Please, I can't find where I'm wrong...
Isn't an area of 20 square millimeters equivalent to 0.2 square centimeters?
Thanks...
UserIdTAG: 865773
UserNameTAG: Edxcs
CreateTimeTAG: 2013-02-24T19:31:58Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Yes, but you shouldn't think of the area in terms of mm or cm for the purposes of that problem.
Honor code prevents me to say much else...but, just think of what the area represents in the histogram ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T20:35:20Z
FirstChildVoteTAG: 0
SecondChildTAG: You are correct, but the question isn't asking for the units of the area.
SecondChildUserIdTAG: 1304034
SecondChildUserNameTAG: AndrewTung
SecondChildCreateTimeTAG: 2013-02-25T02:24:48Z
SecondChildVoteTAG: 0
FirstChildTAG: I understand that at this time answer can't (and shouldn't) be given. However will an explanation be given after the deadline of submissions? This is a very important point. I hope some explanation is given to make the point clear. Thanks.
FirstChildUserIdTAG: 278932
FirstChildUserNameTAG: Rahulsv
FirstChildCreateTimeTAG: 2013-02-25T07:11:20Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree. In some questions it is difficult to see how one failed. An explanation will go a long way.
SecondChildUserIdTAG: 1242644
SecondChildUserNameTAG: Danje
SecondChildCreateTimeTAG: 2013-02-25T13:01:40Z
SecondChildVoteTAG: 0
IndexTAG: 2523
TitleTAG: where are the applets
Where do we get the applets? The examples mention them but are blank.
UserIdTAG: 942289
UserNameTAG: davidbos
CreateTimeTAG: 2013-02-24T19:14:34Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Try using another browser to open the online textbook. The best two for this purpose are Mozilla Firefox and Google Chrome.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T20:37:03Z
FirstChildVoteTAG: 0
FirstChildTAG: I got them when I downloaded Chrome
FirstChildUserIdTAG: 160934
FirstChildUserNameTAG: DonnaC
FirstChildCreateTimeTAG: 2013-02-24T22:31:09Z
FirstChildVoteTAG: 0
FirstChildTAG: I have the same problem as davidbos. I've tried all the browsers and it doesn't work. Java is enabled. Please help...
FirstChildUserIdTAG: 943583
FirstChildUserNameTAG: Dorota23
FirstChildCreateTimeTAG: 2013-02-27T22:21:43Z
FirstChildVoteTAG: 0
IndexTAG: 2524
TitleTAG: I got 2b right but I don't know how
Please stop reading if you have not completed question 2b.
I got a 20/20 here, but I'm confused about 2b. In fact I'm not comfortable with the whole finding percentile from data thing. There were 28 pieces of data, meaning that the median fell between 80 and 81. I thought we were supposed to take the larger of those two, as only the larger value met the requirements of the definition. I tried 81 first, got it wrong, and then guessed the right answer. A formula that seems to work is [Target Percentile] / [Number of Datum] ==round_up==> gives you an integer *n*. The *nth* piece of data is the percentile. This seems to work for the questions here, but I don't understand how the median is the 14th number of 28 numbers. That's like saying the median is the 2nd number of 4 numbers. Shouldn't it be the 3rd?
UserIdTAG: 266427
UserNameTAG: RapidE
CreateTimeTAG: 2013-02-24T18:48:37Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: "Please stop reading if you have not completed question 2b."
Would it help if you had posted it after the due date to open the floor for discussion? ;)
FirstChildUserIdTAG: 1003872
FirstChildUserNameTAG: Marcela_JH
FirstChildCreateTimeTAG: 2013-02-24T19:10:06Z
FirstChildVoteTAG: 1
SecondChildTAG: RapidE help on question 4. how to relate box plots to histograms??
SecondChildUserIdTAG: 1229470
SecondChildUserNameTAG: AVIRAL777
SecondChildCreateTimeTAG: 2013-02-24T19:44:05Z
SecondChildVoteTAG: 0
SecondChildTAG: I was under the impression that in a set of even numbers, the median would be the average of the central two numbers. Why is that not applicable here?
SecondChildUserIdTAG: 1140357
SecondChildUserNameTAG: bhavanarao
SecondChildCreateTimeTAG: 2013-02-25T16:42:12Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem arises when you have three or four numbers wich are the same. For example. 79-80-81-81-81-81-85! I dont know what to do beacause if you count from left to right assuming that each value is 3.75% of the 28 total dataset you could not guess the exact percentile. So I used the assumtion of even distribution in each interval and.... totally failled! jejeje
SecondChildUserIdTAG: 1222835
SecondChildUserNameTAG: CatonElMenor
SecondChildCreateTimeTAG: 2013-02-26T01:45:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Watch the last part of the video and see how she uses a multiplication rule that enables you to configure computationally(in your head for that matter) on how to get the places. Once you get the result it will be a whole integer that has no need to be moved to the right as long as its falling on a non-abstract number.
FirstChildUserIdTAG: 990423
FirstChildUserNameTAG: George95
FirstChildCreateTimeTAG: 2013-02-24T19:39:40Z
FirstChildVoteTAG: 1
IndexTAG: 2525
TitleTAG: Exercise Set 3 Problem 1
Hello guys!
don't know where I am doing a mistake.
My calculations are like this:
lowest quartile:
1. 6.6 + 13.3 = 19.9
2. 19.9 - 25 = 5.1
3. 19.9 + (5,1/7,1)*(5-0) = 2X.4915... rounding it to 1 decimal ≈ 2X.5 and its wrong.
I am doing the same calculations with medium and highest quartile and it is also marked as wrong.
Could you please tell me where do I make mistake?
Thanks and good luck!
Mike.
UserIdTAG: 1297999
UserNameTAG: Turbomike
CreateTimeTAG: 2013-02-24T18:44:59Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: You dont add the 19.9 again. You just use that to find the percentage you need to add. You should be adding to the years:
15 + the rest.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-24T19:11:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Formula is:
Left end of the next interval + (fraction of next interval needed/% in next interval) x width of next interval
Fraction first, then multiply, then add
FirstChildUserIdTAG: 160934
FirstChildUserNameTAG: DonnaC
FirstChildCreateTimeTAG: 2013-02-24T22:35:59Z
FirstChildVoteTAG: 0
SecondChildTAG: Yup, that's what I did and got three nice red crosses. I'm eager for the correct answers to be posted... whenever that happens, because this has been driving me nuts all weekend! :-)
SecondChildUserIdTAG: 1055674
SecondChildUserNameTAG: SocProf
SecondChildCreateTimeTAG: 2013-02-25T01:02:44Z
SecondChildVoteTAG: 0
SecondChildTAG: On your third step you are adding 19.9, when you should be adding 15
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-25T03:05:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Guys, I'm using same formula, but the answer is wrong. Could you write one example with numbers?
19.9 + (5,1/7,1)*5 = 2X.4915
What's wrong?
Thanks!
SecondChildUserIdTAG: 1297999
SecondChildUserNameTAG: Turbomike
SecondChildCreateTimeTAG: 2013-02-26T14:36:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Sansquamtch, why should I add 15 instead of 19.9? From where should we take this 15?
SecondChildUserIdTAG: 1297999
SecondChildUserNameTAG: Turbomike
SecondChildCreateTimeTAG: 2013-02-26T14:37:23Z
SecondChildVoteTAG: 0
FirstChildTAG: Adding 19.9 is just adding in the percentage. You only need to use it to find out the difference between the lower quartile and 19.9. Which is your 5.1. After you have done that you don't add to it again, it is done. After you figure out how many you need to add in the 15-20 range, you would add that to the prior interval. You are doing everything right besides adding it to the years, instead of the percentage.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-27T04:29:50Z
FirstChildVoteTAG: 0
IndexTAG: 2526
TitleTAG: Problem 1 Question a and b
should I round my answer to 1 decimal place?
or two decimal place?
in case of my answer have 2 decimal place, example: 10000.59
which one is the right answer 1000.5 or 1000.6 ?
UserIdTAG: 1213285
UserNameTAG: JUSTANDY
CreateTimeTAG: 2013-02-24T18:40:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: I wrote . 59 and it worked, didn't round up (Exercise set 3). I should mention that, where necessary, I didn't write the "%" at the end. Cheers.
FirstChildUserIdTAG: 1216723
FirstChildUserNameTAG: Darkennoia
FirstChildCreateTimeTAG: 2013-02-24T19:22:10Z
FirstChildVoteTAG: 0
SecondChildTAG: Round to one decimal place as it says in 1c. It applies to the two above too. Your example of 10000.59 would be 10000.6.
If it worked with 2 decimal digits too, that's nice. Means the checker finally gets around to rounding itself :)
But I know for sure it works with 1 decimal since that's how I did it.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-24T20:41:13Z
SecondChildVoteTAG: 0
IndexTAG: 2527
TitleTAG: problem(6)
What percent of students spent fewer than 4 hours in preparation?
I answered 2.5 and it was wrong what is the correct answer.
UserIdTAG: 773422
UserNameTAG: heledum
CreateTimeTAG: 2013-02-24T18:21:09Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: 2.5 is the height of the bar, and height does not correspond to percentage
FirstChildUserIdTAG: 434869
FirstChildUserNameTAG: patey
FirstChildCreateTimeTAG: 2013-02-24T18:46:26Z
FirstChildVoteTAG: 1
SecondChildTAG: I think height shows the density.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-02-25T07:12:08Z
SecondChildVoteTAG: 0
FirstChildTAG: posting that would break the honor code...
FirstChildUserIdTAG: 70894
FirstChildUserNameTAG: dantegl36
FirstChildCreateTimeTAG: 2013-02-24T18:46:55Z
FirstChildVoteTAG: 2
SecondChildTAG: 2.5 is the height or density already distributed in the interval in %/hours which means that in four hours you´ll get ...?! easy!
SecondChildUserIdTAG: 1277369
SecondChildUserNameTAG: Ascensor
SecondChildCreateTimeTAG: 2013-02-26T19:15:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Problem 6 is very vague.. very little information to solve.
FirstChildUserIdTAG: 976798
FirstChildUserNameTAG: Vassri
FirstChildCreateTimeTAG: 2013-02-24T22:17:04Z
FirstChildVoteTAG: 0
SecondChildTAG: % in interval / width of interval = height of bar
You know the height of the bar, and you know the width of the interval.
That's two pieces of information, solve for the third.
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-02-27T16:15:02Z
SecondChildVoteTAG: 0
FirstChildTAG: How can I submit my excercises
FirstChildUserIdTAG: 1265218
FirstChildUserNameTAG: hkdshah
FirstChildCreateTimeTAG: 2013-03-17T14:19:25Z
FirstChildVoteTAG: 0
IndexTAG: 2528
TitleTAG: percent or fractions?
Hi,
I notice that the SticiGui content flips between percent and fractions, incorrectly IMHO, and in more than one place. Look at exercise 3-2 - asks for fraction but uses percentage in the answer. Also, at the gravity exercise worked out - that asks for the fraction of data in the class interval, but uses the percentage, as do your examples above.
This makes following along rather difficult. I expected better quality control.
regards,
JP Lee
UserIdTAG: 1272310
UserNameTAG: JPLee
CreateTimeTAG: 2013-02-24T18:08:15Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: A percent is a fraction. 3/100 is 3% is .03.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-02-24T23:22:43Z
FirstChildVoteTAG: 0
FirstChildTAG: Actually, a percent and a fraction are two "forms" of the same thing. If you use the wrong form, you're graded as incorrect in the SticiGui. It's not that big a deal since it's not part of the grade, but it's a bit distracting as you're working. Take a look at Exercise 3-6 (histogram section), and you'll see what we're talking about. It's a legitimate issue. He explains what he wants in the video, but the question itself is easy to misunderstand what form they want.
However, I can't begin to imagine how hard putting all this together for us has been, so it would be nice to cut them a little slack on that. Giving everyone a head's up allows them to keep correcting and adjusting so the course continues to improve as we go along. For my part, I'm grateful that they're willing to offer this at all. I'll accept a few quirks along the way.
FirstChildUserIdTAG: 773396
FirstChildUserNameTAG: Nita8
FirstChildCreateTimeTAG: 2013-02-26T23:07:34Z
FirstChildVoteTAG: 0
IndexTAG: 2529
TitleTAG: where is the income data "from Lec 2.4"?
in the practice for exercise three is the following:
a) For the income data in Lec 2.4, find the 40th percentile in thousands of dollars. Please enter only your numerical answer, and please round to one decimal place
where is the income data? I only found gravity data.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-24T18:02:49Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 3
FirstChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec2.4.pdf
FirstChildUserIdTAG: 1134470
FirstChildUserNameTAG: cpaula
FirstChildCreateTimeTAG: 2013-02-24T18:18:58Z
FirstChildVoteTAG: 1
SecondChildTAG: thank..you I was lost finding this data.
SecondChildUserIdTAG: 893518
SecondChildUserNameTAG: Martha1
SecondChildCreateTimeTAG: 2013-02-26T20:58:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for your help!
SecondChildUserIdTAG: 1115165
SecondChildUserNameTAG: Abbyjohnson
SecondChildCreateTimeTAG: 2013-02-27T16:07:05Z
SecondChildVoteTAG: 0
FirstChildTAG: check again the video from lec.2.4.
FirstChildUserIdTAG: 1213285
FirstChildUserNameTAG: JUSTANDY
FirstChildCreateTimeTAG: 2013-02-24T18:24:04Z
FirstChildVoteTAG: 0
FirstChildTAG: You can download the slides of lec.2.4 so you can read the data income without to check again the video
FirstChildUserIdTAG: 941908
FirstChildUserNameTAG: katecat
FirstChildCreateTimeTAG: 2013-02-24T19:50:43Z
FirstChildVoteTAG: 0
IndexTAG: 2530
TitleTAG: Submission Trial
Is that possible to change number of submission to 2? That way we can at least have a second chance to review and fix our wrong answers.
Thanks
UserIdTAG: 1212970
UserNameTAG: Lvvu
CreateTimeTAG: 2013-02-24T17:57:40Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I'd like to add to the proposal: and to provide slightly clearer instructions in terms of rounding, adding or omitting signs and so on
FirstChildUserIdTAG: 1003872
FirstChildUserNameTAG: Marcela_JH
FirstChildCreateTimeTAG: 2013-02-24T19:07:48Z
FirstChildVoteTAG: 1
FirstChildTAG: All of this has been covered, talked about, addressed by Prof, talked about again, talked about again, rpt. There is a search feature.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T20:50:09Z
FirstChildVoteTAG: 0
IndexTAG: 2531
TitleTAG: Ghada Radwan
Would you please advise how can I download applet ..."the link"..As I cannot see or work on the histogram
UserIdTAG: 749490
UserNameTAG: ghadanasr
CreateTimeTAG: 2013-02-24T17:57:24Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 1
FirstChildTAG: Use Chrome or Firefox. Make sure you have Java enabled.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T20:50:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Welcome Susan from Australia. I wonder how many other refugees from PH207x are taking this course.
Arnie from WA (Washington not Western Australia)
SecondChildUserIdTAG: 559760
SecondChildUserNameTAG: arnie_z
SecondChildCreateTimeTAG: 2013-02-26T19:54:15Z
SecondChildVoteTAG: 0
IndexTAG: 2532
TitleTAG: Problem 2 how am i wrong
Here's my logic:
1. find total number of people (all ranges summed)
2. Find number of people in age ranges
3. Find percents using above two answers
I believe my math in Excel to be correct but im not yielding the correct answer...
Is my logic busted?
UserIdTAG: 70894
UserNameTAG: dantegl36
CreateTimeTAG: 2013-02-24T17:53:00Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: For 2a, I can't say much due to honor code. Just be careful about how many people you include into your ranges.
For 2b, the wording is a bit misleading. What you need to find is the percent of people who are **65 and over**, and not, as the text suggests, 66 and over.
Hope this helps.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T20:24:43Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks Klion heart i hate being stuck on something.
SecondChildUserIdTAG: 815453
SecondChildUserNameTAG: warinda
SecondChildCreateTimeTAG: 2013-02-25T05:15:04Z
SecondChildVoteTAG: 0
SecondChildTAG: thirties by an online definition is from 30 to 39..
http://www.thefreedictionary.com/thirties
hope this helps
SecondChildUserIdTAG: 358255
SecondChildUserNameTAG: drnidhi27
SecondChildCreateTimeTAG: 2013-02-25T09:16:15Z
SecondChildVoteTAG: 0
SecondChildTAG: My confusion was with the definition of the problem namely, over 65, which I assumed is > 65 (more than 65), not >=65 (65 and more), in which case the percent of people in the interval between 60 and 75 is obtained by multiplying by 9 not 10. The way my answer was graded suggests that 65 must be included in the calculations. And indeed the % sign should not be written otherwise, the answer would be graded as incorrect.
SecondChildUserIdTAG: 536157
SecondChildUserNameTAG: vess
SecondChildCreateTimeTAG: 2013-02-25T15:55:19Z
SecondChildVoteTAG: 0
SecondChildTAG: I had the same problem, though fortunately was able to figure it out within 2 guesses. I'd go further than saying that the wording is misleading. I'd call it outright wrong. When the question puts in quotes "over the age of 65" I would consider that to clearly mean 66 and older.
SecondChildUserIdTAG: 398536
SecondChildUserNameTAG: liguoric
SecondChildCreateTimeTAG: 2013-02-25T17:46:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you drnidhi27!
SecondChildUserIdTAG: 326601
SecondChildUserNameTAG: JonasSilveira
SecondChildCreateTimeTAG: 2013-02-26T22:59:18Z
SecondChildVoteTAG: 0
FirstChildTAG: You could try thinking in geometric terms. The height of the rectangle is the density and the base the interval or subinterval (as requested in problem 2 you have both data). Hope that helps.
FirstChildUserIdTAG: 1222835
FirstChildUserNameTAG: CatonElMenor
FirstChildCreateTimeTAG: 2013-02-24T23:06:07Z
FirstChildVoteTAG: 0
IndexTAG: 2533
TitleTAG: ATTENTION!
They should tell qunto that is rounded, the exercises. If ace tenths, hundredths, or units ...
UserIdTAG: 869994
UserNameTAG: toniasgt
CreateTimeTAG: 2013-02-24T17:46:36Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: thanks for repeating, what abut 5000 people wrote just before you
FirstChildUserIdTAG: 986512
FirstChildUserNameTAG: Thorem
FirstChildCreateTimeTAG: 2013-02-24T19:33:42Z
FirstChildVoteTAG: 2
FirstChildTAG: Wonder why no-one has thought to post this before?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T20:51:11Z
FirstChildVoteTAG: 0
IndexTAG: 2534
TitleTAG: Problem 5
Do not rush to click on 5. Think!
UserIdTAG: 678202
UserNameTAG: dperepolkin
CreateTimeTAG: 2013-02-24T17:46:29Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: As you should for every exercise.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T20:51:27Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, I lost 5 points there, and then I realized why... :-(
FirstChildUserIdTAG: 1081098
FirstChildUserNameTAG: BrilloBox
FirstChildCreateTimeTAG: 2013-02-24T21:08:43Z
FirstChildVoteTAG: 0
IndexTAG: 2535
TitleTAG: Under resourced
I have finally found some material to watch/read. Access via unlabelled rectangles which look as if they are decoration. Set aside time to study. Then told my browser not supported. Could understand if it was something unusual but was Explorer. No idea what chrome or Firefox are.
I did ask last week if course had started. No response as far as I know.
Asked where material was to be found. Again no response.
Great idea and to have so many students interested is wonderful but you need to have corrresponding resources allocated.
Final straw, just found a schedule. On holiday for last 10 days, perhaps because of delayed start.
Good luck with the course. Think you will need it.
UserIdTAG: 1067676
UserNameTAG: JohnKay
CreateTimeTAG: 2013-02-24T17:45:49Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Chrome and Firefox are browsers.Google it and you can download it. We all got emaisl when the courseware was put up.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T18:01:49Z
FirstChildVoteTAG: 0
SecondChildTAG: No we did not
SecondChildUserIdTAG: 1067676
SecondChildUserNameTAG: JohnKay
SecondChildCreateTimeTAG: 2013-02-25T21:38:41Z
SecondChildVoteTAG: 0
FirstChildTAG: Explorer is a bad browser, for a number of reasons that are apparent to anyone who knows some notions of website writing.
I understand that you might not be one of them...I still encourage you to drop it and get either Mozilla Firefox or Google Chrome. If you don't know what they are, Google them. Explorer is good for that, at least.
As for the course schedule, it had some problems starting, that's true...but the due dates for the homework have been moved to the 27th, so there's still plenty of time to get on par.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T20:47:44Z
FirstChildVoteTAG: 0
FirstChildTAG: The course material has been available since the course opened. It is up to everyone to click on the tabs and explore the site.
> Asked where material was to be found. Again no response.
Your post probably got lost among the dozens of people who thought they would post the same post. Over and over. And they continue to do so. This is why efficient forum use is important. But, no. Too many think they are the only ones that matter, and need personal answers. So sorry if your post was missed.
However, when you login to the site you land on the course info page. The last comment:
> The videos and exercise sets are found in the courseware tab on the top left corner of your screen.
See also:
[How to find lectures][1]
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5129096f872f381f00000093
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T20:56:05Z
FirstChildVoteTAG: 0
FirstChildTAG: You've learned something valuable. Online learning isn't for you. Online learning requires that you have some degree of technical know how and some willingness to find and try new software. It also requires a lot of independent work and study. Free courses simply ramp up those requirements. Stick to traditional forms of school.
FirstChildUserIdTAG: 1253174
FirstChildUserNameTAG: danrodz
FirstChildCreateTimeTAG: 2013-02-24T23:14:51Z
FirstChildVoteTAG: 0
SecondChildTAG: The course is about statistics. The course team needs to ensure that it easy to use in whatever browser or state very clearly before registration what is needed.
SecondChildUserIdTAG: 1067676
SecondChildUserNameTAG: JohnKay
SecondChildCreateTimeTAG: 2013-02-25T21:42:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I have very successfully undertaken distance and on-line learning. It needs to be immaculate, not full of ambiguities.
I hope the course succeeds as a great idea.
SecondChildUserIdTAG: 1067676
SecondChildUserNameTAG: JohnKay
SecondChildCreateTimeTAG: 2013-02-25T21:46:40Z
SecondChildVoteTAG: 0
IndexTAG: 2536
TitleTAG: Hi
Hello, already realized all my exercises. :) I'm from Portugal, and study at the University of Coimbra, Coimbra, Portugal, Europe :) I am loving this course!! My English is not the best, but I hope they can understand! Study Management at the Faculty of Economics.
UserIdTAG: 869994
UserNameTAG: toniasgt
CreateTimeTAG: 2013-02-24T17:30:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Coimbra is also famous for cardiac surgery -Manuel Antunes is a great surgeon from there !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T17:36:40Z
FirstChildVoteTAG: 0
FirstChildTAG: Nice to mee you toni!, hello i am from Peru,
FirstChildUserIdTAG: 1302930
FirstChildUserNameTAG: WendyFlores
FirstChildCreateTimeTAG: 2013-02-24T19:03:08Z
FirstChildVoteTAG: 0
IndexTAG: 2537
TitleTAG: Quest 3a
Why does this not represent the plants?
MG-282
MR 94
RG 94
RR 31
UserIdTAG: 199172
UserNameTAG: Jani802
CreateTimeTAG: 2013-02-24T17:27:20Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Because, uh, it doesn't?
We are still under honor code, so we can't really say much more. Review your calculations...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T20:51:25Z
FirstChildVoteTAG: 0
IndexTAG: 2538
TitleTAG: @Staff: to include or not to include the % sign
I'd be grateful if the lecturer or the TAs for this course could clarify whether or not the percentage sign should be added to the answers in the graded exercises. Thanks, Marcela
UserIdTAG: 1003872
UserNameTAG: Marcela_JH
CreateTimeTAG: 2013-02-24T17:13:19Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: What is a TA
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T17:35:50Z
FirstChildVoteTAG: 0
SecondChildTAG: TA = Teaching Assistant
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-24T17:37:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Not a TA, but question is easy-
No % sign is needed in these answers. In the question it states:
> Do not include % sign.
Also round to 2 decimal places for this problem set when requested in the question.
SecondChildUserIdTAG: 369936
SecondChildUserNameTAG: vanzilar
SecondChildCreateTimeTAG: 2013-02-24T18:37:36Z
SecondChildVoteTAG: 0
SecondChildTAG: It's easy to know what to do when it's part of the instructions (don't include the % sign or round to 1 or 2 decimal digits), but not all the exercises have those indications. That's why I'm seeking clarification from the staff. It's true that sometimes you can submit twice, but if the question did not tell you exactly what to do, you don't know why you got the wrong answer.
SecondChildUserIdTAG: 1003872
SecondChildUserNameTAG: Marcela_JH
SecondChildCreateTimeTAG: 2013-02-24T19:05:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Don't ever include % in *any* answers for any of the 3 exercise sets.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-24T20:53:09Z
SecondChildVoteTAG: 0
IndexTAG: 2539
TitleTAG: want solution
I m not able get the first problem correct,what can be the solution for it?
UserIdTAG: 994416
UserNameTAG: 97524059501
CreateTimeTAG: 2013-02-24T16:40:59Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: draw yourself a graph as seen before and label everything you have and it will look familiar
FirstChildUserIdTAG: 1202634
FirstChildUserNameTAG: ChMe
FirstChildCreateTimeTAG: 2013-02-24T16:42:42Z
FirstChildVoteTAG: 0
SecondChildTAG: yeah its effective
thank you so much
SecondChildUserIdTAG: 994416
SecondChildUserNameTAG: 97524059501
SecondChildCreateTimeTAG: 2013-02-24T17:18:59Z
SecondChildVoteTAG: 0
IndexTAG: 2540
TitleTAG: problem 5
please anyone can help me with the answer of problem 5 ??
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-24T16:29:39Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: its simple if 1cm = 100mm then try to put that value further into the bars
FirstChildUserIdTAG: 994416
FirstChildUserNameTAG: 97524059501
FirstChildCreateTimeTAG: 2013-02-24T17:32:27Z
FirstChildVoteTAG: 1
SecondChildTAG: remember the equation for height? work it another way to find the unknown value. Use the unknown value with the centimeter parameters to find a new answer.
SecondChildUserIdTAG: 70894
SecondChildUserNameTAG: dantegl36
SecondChildCreateTimeTAG: 2013-02-24T18:24:59Z
SecondChildVoteTAG: 0
SecondChildTAG: 1cm = 10mm actually
SecondChildUserIdTAG: 907272
SecondChildUserNameTAG: Fedor_Igntakin
SecondChildCreateTimeTAG: 2013-02-24T19:59:40Z
SecondChildVoteTAG: 0
SecondChildTAG: 1cm = 10mm)))
SecondChildUserIdTAG: 1251447
SecondChildUserNameTAG: garry02135
SecondChildCreateTimeTAG: 2013-02-24T20:11:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Think about the equation for the height. The point is to think about the proportion.
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-02-25T02:29:03Z
SecondChildVoteTAG: 0
IndexTAG: 2541
TitleTAG: SticGui content - error
Hi, Not to beat a dead horse, but the exercise 3-2 on the SticGui page is incorrect - it asks for a fraction, but is graded on a percentage.
thanks,
JP
UserIdTAG: 1272310
UserNameTAG: JPLee
CreateTimeTAG: 2013-02-24T15:57:25Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: That is a decimal fraction
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T16:07:05Z
FirstChildVoteTAG: 0
SecondChildTAG: I noticed that too.
SecondChildUserIdTAG: 127549
SecondChildUserNameTAG: ochavoya
SecondChildCreateTimeTAG: 2013-02-24T16:27:00Z
SecondChildVoteTAG: 0
IndexTAG: 2542
TitleTAG: number of submission
on Exercise set 1, problem 2, I answered all questions correctly at the first attempt then when I saved it, it suggested me to submit again. Does the number of allowed submission have anything to do with the outcome of the result?
UserIdTAG: 377342
UserNameTAG: Mparvez82
CreateTimeTAG: 2013-02-24T15:46:33Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I did the same thing once. It is confusing.
FirstChildUserIdTAG: 270738
FirstChildUserNameTAG: sheardp
FirstChildCreateTimeTAG: 2013-02-24T17:34:47Z
FirstChildVoteTAG: 1
FirstChildTAG: No - you do not have to use all of the submissions.
Once you have a green check, it is marked correct. However, if you then change your answer and click the Check button again, you will be marked incorrect. So be careful where you click!
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-24T19:58:59Z
FirstChildVoteTAG: 0
FirstChildTAG: Saving is for work that is incomplete so you do not lose your place. :)
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-25T03:12:37Z
FirstChildVoteTAG: 0
IndexTAG: 2543
TitleTAG: READING AND PRACTICE FOR EXERCISE SET 2,Lectures 2.2 and 2.3,question a doubt
a) Height of -10 to 20 bar = ____________ % per unit
this should be 0.467 not 1.4%, because width of class interval is 30 not 10. any clarifications
UserIdTAG: 1162855
UserNameTAG: SAISATISH
CreateTimeTAG: 2013-02-24T15:24:06Z
VoteTAG: 30
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T15:50:52Z
FirstChildVoteTAG: 3
SecondChildTAG: I totally agree that the difference is 30 not 10
SecondChildUserIdTAG: 731331
SecondChildUserNameTAG: Nanni
SecondChildCreateTimeTAG: 2013-02-24T20:26:14Z
SecondChildVoteTAG: 0
SecondChildTAG: yes the diff b/w -10 and 20 is 30.
SecondChildUserIdTAG: 1293941
SecondChildUserNameTAG: CHHAVIMEHROTRA
SecondChildCreateTimeTAG: 2013-02-26T03:41:04Z
SecondChildVoteTAG: 0
SecondChildTAG: yes,because -- = +, so 20- (-10)= 30
SecondChildUserIdTAG: 591948
SecondChildUserNameTAG: Auwalu
SecondChildCreateTimeTAG: 2013-02-27T11:12:01Z
SecondChildVoteTAG: 0
IndexTAG: 2544
TitleTAG: Which chapter to which lecture?
How do I connect a lecture to a chapter in the on-line textbook? What I mean is, how do I find out which chapter in the book corresponds with a particular lecture?
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-02-24T15:22:16Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: There are links in the Practice Exercises. Lectures so far correspond with chapter3 of TB. It seems that next week lectures correspond with chapter4 of TB.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-24T15:43:25Z
FirstChildVoteTAG: 0
SecondChildTAG: chapter one in the book is an introduction and doesnt cover information related to what we need to read. when reading the text book there are two things you can do. Go through the lectures and read the links provided with the lecture or just read both chapter 2 and 3
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-25T02:38:31Z
SecondChildVoteTAG: 0
IndexTAG: 2545
TitleTAG: The number of decimal places
I think it would be good if rounding decimals worked.
UserIdTAG: 759395
UserNameTAG: Gen_Art
CreateTimeTAG: 2013-02-24T15:07:13Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2546
TitleTAG: Lecture 2.2 and 2.3 Question (a)
Answer to the question (a) under lecture 2.2 and 2.3 is 14/30 not 14/10.
UserIdTAG: 1121929
UserNameTAG: ravikd
CreateTimeTAG: 2013-02-24T14:48:15Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Congratulations! You are the 1000th person to start a post about this.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:01:08Z
FirstChildVoteTAG: 0
FirstChildTAG: Susan, I really wish you wouldn't be so rude.
FirstChildUserIdTAG: 160934
FirstChildUserNameTAG: DonnaC
FirstChildCreateTimeTAG: 2013-02-24T22:41:43Z
FirstChildVoteTAG: 0
SecondChildTAG: lol
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-24T22:56:33Z
SecondChildVoteTAG: 0
IndexTAG: 2547
TitleTAG: histograms and intervals
Is it possible to express these numbers in a logarithmic way?
UserIdTAG: 864596
UserNameTAG: Rubenjtj
CreateTimeTAG: 2013-02-24T14:11:52Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 4
FirstChildTAG: Why ?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T14:40:18Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you for elaborating on it. I was just curious, since I have been doing some work in Excel, made a graph that had two y-axis, and wanted to se the difference better.
SecondChildUserIdTAG: 864596
SecondChildUserNameTAG: Rubenjtj
SecondChildCreateTimeTAG: 2013-02-24T18:20:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, good/bad choosing of the scale might be illuminating/misleading. Probably we will hear of these issues in next lectures.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-24T14:41:34Z
FirstChildVoteTAG: 0
FirstChildTAG: I just read about it and they can use logarithmic bins.I believe that people doing image processing may use logarithmic bins to construct histograms in cases with a high contrast with a small array. It is also used when a log transformation may make a particular value linear
You would have to make either the X or Y axis to a log scale depending on the problem and requirements.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T14:52:55Z
FirstChildVoteTAG: 1
FirstChildTAG: Yes, histograms, like many graphs, can use non-linear scales (like a log scale). Since there are properties like "area = population", that are good to maintain, you likely want to be careful of the units you use to express the histogram. For a log axis, expressing the density in terms of per decade or per octave of value probably makes sense. (I imagine that sometimes you might need to relax the idea the idea of area = population in some cases too).
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T03:52:57Z
FirstChildVoteTAG: 0
IndexTAG: 2548
TitleTAG: Certificates of completion
Certificates of completion go to those who score 35% or higher on the course... which makes the certificate worthless. Are standards that low at Berkley?
UserIdTAG: 1081022
UserNameTAG: Paul02035
CreateTimeTAG: 2013-02-24T13:55:01Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 11
FirstChildTAG: I believe you would have to be accepted, pay tuition and take some actual courses on-campus to find out.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-24T13:57:51Z
FirstChildVoteTAG: 0
SecondChildTAG: ... or hire a recent Berkeley grad! ;)
SecondChildUserIdTAG: 1081022
SecondChildUserNameTAG: Paul02035
SecondChildCreateTimeTAG: 2013-02-24T14:04:47Z
SecondChildVoteTAG: 0
SecondChildTAG: I think they are also placing grades on the certificates
SecondChildUserIdTAG: 1238655
SecondChildUserNameTAG: myrmidon1011
SecondChildCreateTimeTAG: 2013-02-26T19:55:14Z
SecondChildVoteTAG: 0
FirstChildTAG: Lets see how many actually score above for 35 % for starters.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T14:04:50Z
FirstChildVoteTAG: 4
SecondChildTAG: I agree!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-24T14:37:36Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, you are absolutely right.
SecondChildUserIdTAG: 1293981
SecondChildUserNameTAG: Hassan_1
SecondChildCreateTimeTAG: 2013-02-26T14:38:09Z
SecondChildVoteTAG: 0
FirstChildTAG: Seriously? We have a chance here at a free bit of education. Free. From Berkeley. You misspelled "Berkeley"; does that make your education up to this point "worthless"? Sorry for the snark, but really?
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-24T14:58:55Z
FirstChildVoteTAG: 4
SecondChildTAG: If someone scores only 35% they didn't get much free education, did they?
SecondChildUserIdTAG: 1081022
SecondChildUserNameTAG: Paul02035
SecondChildCreateTimeTAG: 2013-02-25T14:01:41Z
SecondChildVoteTAG: 0
FirstChildTAG: I wouldn't say worthless, however, I agree it does seem a bit low.
FirstChildUserIdTAG: 1197352
FirstChildUserNameTAG: geradthefan
FirstChildCreateTimeTAG: 2013-02-24T18:34:23Z
FirstChildVoteTAG: 1
FirstChildTAG: anybody tried 2b?
FirstChildUserIdTAG: 720154
FirstChildUserNameTAG: LUCALOTTO2012
FirstChildCreateTimeTAG: 2013-02-24T20:48:18Z
FirstChildVoteTAG: 0
FirstChildTAG: There was another edX course with passing grade of 55%.
Less than 10% from the 60k+ students passed.
Judging by the many students who can't/haven't managed to get the very basic and simple lessons in Week 1 correctly, I think 35% is a blessing to encourage those students to continue learning and not give up.
MOOC/edX is here to educate the world for all levels of students. You don't have to be the 'best' to learn the subject. If you fail this time round, you can always take the next offering until you master the subject. Different people learn at a different pace.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-24T21:00:23Z
FirstChildVoteTAG: 3
SecondChildTAG: So true jimbangun. If you can't master reading the syllabus and past posts, then maybe 35% is appropriate.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-24T21:03:02Z
SecondChildVoteTAG: 0
SecondChildTAG: lol...true indeed...
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-24T21:04:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Susan, but following this logic someone who manages to give a correct answer more often than one time out of three is rather punished. If the goal is to encourage students of all levels to stick the course as long as possible why not just simply get rid off grades completely. Instead, everyone would get a "a smiling sun" if he/she knows the right answer. In the end, grades just introduce competition and may upset if you make a mistake.
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-24T21:55:51Z
SecondChildVoteTAG: 0
SecondChildTAG: You guys are not allowing for the variables of technoligical glitches, a persons lack of exposure to stats and language difficulties. I find this conversation a bit on the offensive.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-25T02:41:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Whether it is worthless or not, it depends on each one's effort and attitude...
FirstChildUserIdTAG: 1081098
FirstChildUserNameTAG: BrilloBox
FirstChildCreateTimeTAG: 2013-02-24T21:14:12Z
FirstChildVoteTAG: 3
SecondChildTAG: I totally agree.
Nothing is worthless if you put effort and worked hard to achieve it!
Worthless is if you cheated.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-24T21:20:01Z
SecondChildVoteTAG: 0
SecondChildTAG: If someone gets a score of 35% do you think they put much effort into it? Did they work hard? Do they have the understanding to move on to the next level?
Or, as an alternative, does the score indicate very little understanding of basic statistics and the need to re-take the course?
SecondChildUserIdTAG: 1081022
SecondChildUserNameTAG: Paul02035
SecondChildCreateTimeTAG: 2013-02-25T14:06:52Z
SecondChildVoteTAG: 0
FirstChildTAG: > Certificates of completion go to those who score 35% or higher on the course... which makes the certificate worthless.
The certificate is devalued by every person who posts their answers on the forum, or asks for the answer, or goes to other websites and asks for the answers.
Come exam time, questions will be posted all over the web. As they were in PH207x and other courses.
So that is what makes your certificate worthless. Not the mark required. Though given the low requirement, the fact that so many are already screaming foul about errors/number of submissions/answer format/etc, does not bode well.
If you want the certificate to have worth, then everyone here has to follow the honour code that we agreed to.
I think honour codes are a nice idea but unworkable, in that only those who were going to be honest anyway will follow them. Everyone else will laugh, and just go their merry way.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:49:40Z
FirstChildVoteTAG: 3
SecondChildTAG: ya susan you are right. Its ones personnel interest which is going to make you learn more through this course and not about 35% and higher.
SecondChildUserIdTAG: 1162240
SecondChildUserNameTAG: Sudhadhayalan
SecondChildCreateTimeTAG: 2013-03-06T10:59:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Honor codes do work when students are enrolled in a university. You break the code you get expelled. Education is about learning not grades. Here the world gets to learn from the best of the best for free. When you cheat you are only cheating yourself. Yes, that sounds like what your high school teachers use to say. That's because I am a teacher with 31 years of experience, but it is still the truth.
FirstChildUserIdTAG: 1138487
FirstChildUserNameTAG: gperry
FirstChildCreateTimeTAG: 2013-02-24T22:55:58Z
FirstChildVoteTAG: 2
FirstChildTAG: I don't see a problem, do you think that people know passing grade for every course in whole world? They don't know what is passing grade for completion certificates you show them.
If you want to have value with it, simply print out your scores graph and keep it together with your certificate. Then they all will know how good exactly you are and will not make assumptions about passing grade.
FirstChildUserIdTAG: 127421
FirstChildUserNameTAG: apbyte
FirstChildCreateTimeTAG: 2013-02-26T08:56:50Z
FirstChildVoteTAG: 2
FirstChildTAG: Rules must not be changed during the course.
FirstChildUserIdTAG: 1107133
FirstChildUserNameTAG: Shumanova
FirstChildCreateTimeTAG: 2013-03-01T17:28:48Z
FirstChildVoteTAG: 0
SecondChildTAG: but they did a couple of times :)
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-03-01T19:57:02Z
SecondChildVoteTAG: 0
IndexTAG: 2549
TitleTAG: The John Turkey method - an observation
This reminds me a bit of the way one can view words in linguistics, where you have a prefix, and all the possible combinations of the continuation of this prefix become leaves. Since we only get descendants on the same level here, this is more like hashing numbers in computer science; i.e. numbers are operated on as characters. And again, we've got bins.
UserIdTAG: 864596
UserNameTAG: Rubenjtj
CreateTimeTAG: 2013-02-24T13:27:35Z
VoteTAG: 2
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.1. Describing one quantitative variable
NumberOfReplyTAG: 0
IndexTAG: 2550
TitleTAG: Problem with Progress Status Bar: Exercise 1
In general I have noticed issues with the progress bar in edX, but for exercise 1 the progress bar was less than half-way mark despite a score of 90%. Neither refreshing or coming back from the Courseware Menu helped in this regard
I am using the lastest Chrome browser.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-24T13:23:43Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The progress bars above the exercises only have three settings: empty if none of the problems have been attempted, approximately half-full (or half-empty depending on your view of life) if at least one problem has been attempted, and completely full if the entire set is correct.
The fullness of the bar is not indicative of the percentage correct.
EDIT: The above refers to the icon above the Exercises in the Courseware. My apologies, I did not read the question correctly.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-24T13:55:58Z
FirstChildVoteTAG: 0
SecondChildTAG: Aaronrod, when I hover over the bars in my Progress area, it quite clearly shows the percentage correct; there is none of this "three settings" you mention.
OP, are you really sure you got a 90%? Each problem in that exercise set is weighted differently. Try factoring in the different point values.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-24T14:55:17Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry if I misunderstood. Perhaps we are talking about 2 different places: Courseware vs. Progress?
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-24T15:02:39Z
SecondChildVoteTAG: 0
SecondChildTAG: You are right, we are talking about two different things. I'll edit my previous post now.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-24T20:03:36Z
SecondChildVoteTAG: 0
FirstChildTAG: And there are times when the icon does not automatically update when it should. So you do need to refresh the page. When this happens we of course will know about it. As we will be flooded with anxious queries from students who, for some reason, have never had to refresh a page before.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:05:22Z
FirstChildVoteTAG: 0
IndexTAG: 2551
TitleTAG: 2.2 and 2.3 on a) why 1.4? not 0.467?
widht of bin for -10 to 20 its 30 not 10? why the result its 10? its make me confused. please check again for the result.
UserIdTAG: 930677
UserNameTAG: raifadwi
CreateTimeTAG: 2013-02-24T13:07:47Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Is a mistake. The answer is .467 and the range is 30, not 10.
FirstChildUserIdTAG: 976341
FirstChildUserNameTAG: ErnestoAngulo
FirstChildCreateTimeTAG: 2013-02-24T13:19:42Z
FirstChildVoteTAG: 0
SecondChildTAG: the width of the bin is 20 - (-10) = 30. the number of items in the bin is 14. 14/30 = .467.
SecondChildUserIdTAG: 1020734
SecondChildUserNameTAG: godelstein
SecondChildCreateTimeTAG: 2013-02-28T01:44:45Z
SecondChildVoteTAG: 0
FirstChildTAG: there's no mistake... -10 to 20 = 20 - (-10) = 30 ...are you sure?
take a look at the question "width?"... it's mean that you have to ignore the "minus"
so the answer is 20-10=10...
FirstChildUserIdTAG: 1213285
FirstChildUserNameTAG: JUSTANDY
FirstChildCreateTimeTAG: 2013-02-24T17:44:12Z
FirstChildVoteTAG: 0
SecondChildTAG: No you ae wrong-please see the courseware errata in the wiki
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T17:56:12Z
SecondChildVoteTAG: 0
FirstChildTAG: lol
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:05:42Z
FirstChildVoteTAG: 1
IndexTAG: 2552
TitleTAG: Suggestion for answer formats
Hi,
Given the frustration with trying to figure out the format an answer is expected in through trial and error, would it be possible for future questions to include an 'example answer' in the correct format, please?
This is a reasonably standard technique to clue computer users into the format their input is expected in, and would be very helpful here.
e.g. "59.1%" indicates to the user that the right format might be a percentage, rounded to one decimal place and followed by the percent sign.
"59.11" indicates that the percentage symbol is not required and implies rounding to two decimal places is expected.
Hope that helps.
Best regards,
-->Gar
UserIdTAG: 81246
UserNameTAG: bigbro
CreateTimeTAG: 2013-02-24T13:03:38Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Second that.
FirstChildUserIdTAG: 1060592
FirstChildUserNameTAG: Lucius513
FirstChildCreateTimeTAG: 2013-02-24T15:56:07Z
FirstChildVoteTAG: 0
FirstChildTAG: The Prof has responded to all this. And there are so many posts about it now, that I have lost hope for the next generation.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:06:34Z
FirstChildVoteTAG: 0
IndexTAG: 2553
TitleTAG: suggested improvement
Admittedly these were due to my not being alert, however the fact that I got these wrong dont reflect on my knowledge of the subject matter
1) In the first problem there were 3 parts, I marked one of them and pressed "check" before I had filled in the answers for the second part. This meant I got two answers wrong simply because of the scrolling past the other two 2 fast. It would be better if we were prompted to fill in the unanswered one
2) I think a lot of people have pointed out that using the percentage sign is marked wrong. Marking these questions wrong is really a bit extreme.
UserIdTAG: 1093884
UserNameTAG: farrukhazfar
CreateTimeTAG: 2013-02-24T12:58:12Z
VoteTAG: 7
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: I totally agree with you !
FirstChildUserIdTAG: 915427
FirstChildUserNameTAG: MarioL
FirstChildCreateTimeTAG: 2013-02-24T16:42:58Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, especially when the other instructor in the video emphasized the importance of the % sign w.r.t. correct answers.
SecondChildUserIdTAG: 1272310
SecondChildUserNameTAG: JPLee
SecondChildCreateTimeTAG: 2013-02-24T18:48:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Good feedback. I am sure designers will take this into consideration in future.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-02-25T07:14:52Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes I was unsure if the percent sign was what was wrong, or if the answer was wrong.
FirstChildUserIdTAG: 1260235
FirstChildUserNameTAG: ashleyroe
FirstChildCreateTimeTAG: 2013-02-25T19:26:45Z
FirstChildVoteTAG: 0
FirstChildTAG: you have to improve your system, maybe multiple choice
FirstChildUserIdTAG: 1107978
FirstChildUserNameTAG: betoagto
FirstChildCreateTimeTAG: 2013-02-25T23:15:28Z
FirstChildVoteTAG: 0
IndexTAG: 2554
TitleTAG: yes, its o.467% rather than 1.4%
it seemed to me like simple mistake not intended, because it's obvious that the range from -20 to 10 is 30 not 10, if we can recall well, the range is subtraction of smallest number from the bigger, i.e. 10 -(-20)= rather than 10 and thus give us width of 30 and answer of 0.47% :)
UserIdTAG: 831043
UserNameTAG: Amjad27
CreateTimeTAG: 2013-02-24T12:42:45Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Yes, it's a known error, as you could have easily realized by looking around the discussion forum before posting. I see at least 4 topics on it on the first page, just now xD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-24T14:55:33Z
FirstChildVoteTAG: 0
FirstChildTAG: > I see at least 4 topics on it on the first page
Oh for a $\$ $ for every post I've seen about this.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:07:39Z
FirstChildVoteTAG: 0
IndexTAG: 2555
TitleTAG: Continuous precision in answers is marked wrong?!
E.g. **Question**:
>1. A class of 270 students consists of freshmen, sophomores, juniors, and seniors, in the proportions 2:3:3:1. Find
>>b) the number of seniors
**My answer**
~11.11111111111111111111
**Answer**
11.1
Specifically since all that matters is the formula, I put this in the field:
100*(1/9)
Is there any way we can get support for arbitrary precision in EdX?
UserIdTAG: 352989
UserNameTAG: SamuelMarks
CreateTimeTAG: 2013-02-24T12:05:21Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: this question was asked about 100 times here. pls. use search function first.
next time, you know ;)
FirstChildUserIdTAG: 986512
FirstChildUserNameTAG: Thorem
FirstChildCreateTimeTAG: 2013-02-24T12:16:30Z
FirstChildVoteTAG: 0
IndexTAG: 2556
TitleTAG: answer of 2.2 and 2.3 a
Hello ! Should the answer not be .467% ?
UserIdTAG: 715609
UserNameTAG: Girdhari
CreateTimeTAG: 2013-02-24T12:02:34Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: pls don't discuss answers with us. other people like to do their own work.
pls discuss the learning stuff, but not the answers.
FirstChildUserIdTAG: 986512
FirstChildUserNameTAG: Thorem
FirstChildCreateTimeTAG: 2013-02-24T12:17:27Z
FirstChildVoteTAG: 0
SecondChildTAG: I suppose it is not about discussing answers but pointing out a mistake in an exercise.
SecondChildUserIdTAG: 1038790
SecondChildUserNameTAG: esthom
SecondChildCreateTimeTAG: 2013-02-24T12:33:18Z
SecondChildVoteTAG: 0
SecondChildTAG: i agree..it's only a practice and ungraded..how can we solve the graded exercise if we still stuck in the confusing practice problem? besides, after practice, the next is graded exercise..we will wait for the due date of graded exercise before we know the explanation of how it was happen about the practice exercises? what if in the graded exercise has a problem like in the practice exercise?
SecondChildUserIdTAG: 1231135
SecondChildUserNameTAG: shie112709
SecondChildCreateTimeTAG: 2013-02-24T12:43:25Z
SecondChildVoteTAG: 0
SecondChildTAG: yes, mistakes should be discussed here. Don't speaking clear text is a misinterpretation of the honor code.
SecondChildUserIdTAG: 1174304
SecondChildUserNameTAG: ThomasHGMann
SecondChildCreateTimeTAG: 2013-02-24T13:53:22Z
SecondChildVoteTAG: 0
SecondChildTAG: The problem is rather: why start a new discussion thread now, when all was said days ago ...
SecondChildUserIdTAG: 1174304
SecondChildUserNameTAG: ThomasHGMann
SecondChildCreateTimeTAG: 2013-02-24T13:55:00Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok. Let me say it in other words. From the lecture we learned that the height of the histogram is the %/width. From the practice one can assume that is %/width/3 also!! Silly one can say. Mistakes are for people and so obvious ones doesn't need to be discussed by educated people. This thread should just stop growing. Thank you.
SecondChildUserIdTAG: 1239975
SecondChildUserNameTAG: Xenofon
SecondChildCreateTimeTAG: 2013-02-24T20:14:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Did you happen to look at any of the other posts in this subforum before you posted?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T21:08:33Z
FirstChildVoteTAG: 0
IndexTAG: 2557
TitleTAG: Answers
I have done got some answers wrong. How will i know what are the correct answers?
pLZ HELP
UserIdTAG: 904879
UserNameTAG: ziadnabee
CreateTimeTAG: 2013-02-24T11:06:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: This is an assessment. If you get the answer correct, you will get a green tick. Wrong and you get a red cross. The course policy document tells you when the answers are released.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T11:10:56Z
FirstChildVoteTAG: 0
IndexTAG: 2558
TitleTAG: Decimal place and symbol
While answering how many decimal places should we consider and should we include symbols like % etc. it is not clear
UserIdTAG: 1105885
UserNameTAG: AJITHABK
CreateTimeTAG: 2013-02-24T11:02:16Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: One decimal place.Do not use a % sign
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T12:03:13Z
FirstChildVoteTAG: 0
SecondChildTAG: % = 1/100
5% = 0.05
SecondChildUserIdTAG: 986512
SecondChildUserNameTAG: Thorem
SecondChildCreateTimeTAG: 2013-02-24T12:27:22Z
SecondChildVoteTAG: 0
IndexTAG: 2559
TitleTAG: Interval from -10 to 20
The width of the interval from -10 to 20 is clearly 30!
UserIdTAG: 859273
UserNameTAG: G66
CreateTimeTAG: 2013-02-24T10:15:33Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Please check course ware errata in the wiki section
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T10:30:39Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Practice_for_ES2/threads/5129c64f6f15a32005000094
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T11:03:42Z
FirstChildVoteTAG: 0
SecondChildTAG: Susan must be getting carpal tunnel syndrome with the clicking on that link ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T12:02:47Z
SecondChildVoteTAG: 0
IndexTAG: 2560
TitleTAG: I am having trouble taking data from stem leaf plot
how do you find the median and 25th etc from a stem leaf plot?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-24T09:31:36Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: It was easier for me to take steam and leaf plot and make it a series of numbers, and after that you just apply definition from lectures :)
FirstChildUserIdTAG: 1196355
FirstChildUserNameTAG: EmilyEly87
FirstChildCreateTimeTAG: 2013-02-24T09:54:34Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5128e3828297391f00000013
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-24T10:12:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Counted them
FirstChildUserIdTAG: 1002821
FirstChildUserNameTAG: Urimare
FirstChildCreateTimeTAG: 2013-02-24T10:26:37Z
FirstChildVoteTAG: 0
SecondChildTAG: First of arrange the data of stem and leaf plot in a normal list than for pth percentile multiply the total no of list with pth % rest is simple counting to reach the desired number in the list
SecondChildUserIdTAG: 1248908
SecondChildUserNameTAG: babarbaig
SecondChildCreateTimeTAG: 2013-02-24T12:25:21Z
SecondChildVoteTAG: 0
IndexTAG: 2561
TitleTAG: The interval width of -10 to 20
I agree the interval width should be 30 not 10 as 20-(-10)= 30.
UserIdTAG: 1049901
UserNameTAG: ChristineAV
CreateTimeTAG: 2013-02-24T08:33:52Z
VoteTAG: 4
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: Please search the forums and courseware errata This ahs been discussed before
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T09:09:10Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Practice_for_ES2/threads/5129c64f6f15a32005000094
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T09:42:20Z
FirstChildVoteTAG: 0
FirstChildTAG: i agree on that..it was a rule of subtraction of negative signs..
FirstChildUserIdTAG: 1231135
FirstChildUserNameTAG: shie112709
FirstChildCreateTimeTAG: 2013-02-24T12:34:47Z
FirstChildVoteTAG: 0
IndexTAG: 2562
TitleTAG: Interesting theoretical question on learning that can be answered with data from this course ...
In exercise set 3, do more people get problem 3 right than any of the other problems? If they do, that would seem to be preliminary evidence that the written word is a more effective way to learn that video lectures...
But you would need to confirm by checking whether the time lapse between the learning and answering the question had more of an effect, (in the problem 3 case, the time gap is really small), and whether text is more effective in short bursts (do people lose concentration when reading large amounts of text, but have better understanding of what they did focus on?) That would mean text is more useful for explaining short, problems, whereas videos are better for longer stretches of teaching.
Ani Adhikari and Philip B. Stark, I get co-authorship credits if you ever write this! :)
UserIdTAG: 229679
UserNameTAG: Ahsen
CreateTimeTAG: 2013-02-24T08:14:42Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2563
TitleTAG: width of interval -10 to 20
I think it is 20-(-10) = 30
and the answer is 14/30 = 0.466666
UserIdTAG: 324672
UserNameTAG: drfatahiya
CreateTimeTAG: 2013-02-24T07:50:39Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: You posted in the subforum. If before posting you had read what was already posted, you would have seen the following (the first one is yours) and there are another five beyond these. And dozens in the general tab. Please everyone, read before posting!
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13616926261343684.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T07:53:22Z
FirstChildVoteTAG: 2
IndexTAG: 2564
TitleTAG: No Captions for lection 2.5
Yeah, I have same trouble ....
UserIdTAG: 719514
UserNameTAG: JasonDinAlt
CreateTimeTAG: 2013-02-24T07:24:42Z
VoteTAG: 7
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 0
IndexTAG: 2565
TitleTAG: Hi Staff, please give answers for the exercises.
Please give answers for the exercises, we should be able to see the answers after completing the exercise. We can know where we were wrong and correct it.
UserIdTAG: 451012
UserNameTAG: swamydkv
CreateTimeTAG: 2013-02-24T07:22:41Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: There are still people answering and obviously they cannot give the answers out till the last dat/time to answer the questions !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T07:27:42Z
FirstChildVoteTAG: 2
FirstChildTAG: Read the course policies, they will tell you when the answers are released.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T07:39:56Z
FirstChildVoteTAG: 2
IndexTAG: 2566
TitleTAG: Where is the online textbook?
I am pretty tech savy, so I can find my way around websites - but I simply cannot find a link to the online textbook!
UserIdTAG: 229679
UserNameTAG: Ahsen
CreateTimeTAG: 2013-02-24T07:18:28Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: Look at the URL in the wiki
This is the link
http://statistics.berkeley.edu/~stark/SticiGui/
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T07:26:45Z
FirstChildVoteTAG: 1
FirstChildTAG: I believe this is the link, it's referred to in several places throughout the practice exercises :)
http://statistics.berkeley.edu/~stark/SticiGui/Text/
FirstChildUserIdTAG: 1230511
FirstChildUserNameTAG: Christeph
FirstChildCreateTimeTAG: 2013-02-24T07:27:00Z
FirstChildVoteTAG: 1
SecondChildTAG: Link should be clickable and available at Wiki or the Course contents to make it user friendly.
SecondChildUserIdTAG: 987158
SecondChildUserNameTAG: vijaysharma1122
SecondChildCreateTimeTAG: 2013-02-24T09:08:13Z
SecondChildVoteTAG: 0
FirstChildTAG: And the link can be found in the course policies/requirements.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T07:40:44Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks everyone! Should read the text more carefully! Spoilt a bit by Coursera putting everything you need in a single menu.
Appreciate the prompt responses!
FirstChildUserIdTAG: 229679
FirstChildUserNameTAG: Ahsen
FirstChildCreateTimeTAG: 2013-02-24T07:42:22Z
FirstChildVoteTAG: 0
SecondChildTAG: Interestingly, the fact that each of you has pointed to a separate source for the link also suggests that it isn't the one obvious place. :)
Thanks again!
SecondChildUserIdTAG: 229679
SecondChildUserNameTAG: Ahsen
SecondChildCreateTimeTAG: 2013-02-24T07:44:09Z
SecondChildVoteTAG: 0
SecondChildTAG: No indeed theya re all in the same place and is in the wiki-All of us are pasting the URL but nesting from different pages. The basic URL is the same.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T07:48:18Z
SecondChildVoteTAG: 0
FirstChildTAG: If doing the exercises, saving them and hitting check is all that is needed for each exercises or there is some other way to submit them?
If the practice exercises are the same as assignment or one needs to look for them at some other place, if so where?
FirstChildUserIdTAG: 987158
FirstChildUserNameTAG: vijaysharma1122
FirstChildCreateTimeTAG: 2013-02-24T09:12:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Save just saves and allows modification Check checks them and submits them too !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T10:12:24Z
SecondChildVoteTAG: 0
IndexTAG: 2567
TitleTAG: I don´t understand =(
Hi
Can anybody explain me, how to do the exercise 1??
Thank you!!
UserIdTAG: 263932
UserNameTAG: muveokte
CreateTimeTAG: 2013-02-24T06:39:26Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: you have to use cumulative frequency here, go through the lecture once again where they have described income in dollars.. Its same like that..
also in part a and b, don't round off the decimals,
i gave the ans up to two decimal points
I rounded off only in part c..
i hope my ans was useful
FirstChildUserIdTAG: 330656
FirstChildUserNameTAG: docpriti
FirstChildCreateTimeTAG: 2013-02-24T08:53:40Z
FirstChildVoteTAG: 0
SecondChildTAG: If you want to answer questions ,listen the videos and sometimes read the chapters. It will really help you, believe me
SecondChildUserIdTAG: 1059155
SecondChildUserNameTAG: gasimovilkin
SecondChildCreateTimeTAG: 2013-02-24T14:37:45Z
SecondChildVoteTAG: 0
SecondChildTAG: "You survive the winter if you harvest your grain, you harvest your grain if you planted in the summer" You have to watch the videos and rely on that knowledge and not use guess work. That is the only way that you will be able to use to get that shiny certificate.
SecondChildUserIdTAG: 990423
SecondChildUserNameTAG: George95
SecondChildCreateTimeTAG: 2013-02-24T19:43:16Z
SecondChildVoteTAG: 0
IndexTAG: 2568
TitleTAG: Issue with Exercies questions 1a
From what I can see, the subnotes in Exercies 3-1 indicate that a 'bank account balance is discrete' (arguing that countries have a smallest unit currency). Given a close relationship between the two, I would fail to see the distinction between an income and a bank balance, unless catagorized , and that was not done here within question 1.
So, because both are decimal numbers and again, as the exercise footnote calls bank balance discrete - and since discrete is a subset of quantatative, I don't see how income could not be quantatative discrete according to that logic. (marked wrong)
UserIdTAG: 1252131
UserNameTAG: BrianF73
CreateTimeTAG: 2013-02-24T06:00:57Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Agreed!
Though I suppose the reason it's marked wrong is that income is mentioned as a continuous variable several times (I think?) in the lectures.
But as far as I'm concerned, Income and bank balances are both discrete quantitative variables - percentage charges (bank accounts) or tax deducations (incomes) are always deducted to the pence/cent/paisa, and not a fraction of either of those.
FirstChildUserIdTAG: 229679
FirstChildUserNameTAG: Ahsen
FirstChildCreateTimeTAG: 2013-02-24T07:50:49Z
FirstChildVoteTAG: 1
FirstChildTAG: I totally agree. I also checked "qualitative discrete" for income and got it wrong though strictly speaking it has to be treated as such.
FirstChildUserIdTAG: 1226464
FirstChildUserNameTAG: szymooon
FirstChildCreateTimeTAG: 2013-02-24T08:54:43Z
FirstChildVoteTAG: 0
FirstChildTAG: Whatever your thoughts are, please do NOT discuss them until the deadline has elapsed for this graded exercise. Otherwise you are breaking the honor code, i.e. cheating.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-24T10:07:33Z
FirstChildVoteTAG: 0
IndexTAG: 2569
TitleTAG: New Assignment dates
I'm happy to see that the course is trying hard to accommodate everyone's schedules, especially those who are traveling and unable to meet various deadlines. I am keeping the original schedule only because it breaks down the due dates and will ensure that I stay on track. Not sure if anyone else is doing this, but it will certainly help keep me from procrastinating. :)
UserIdTAG: 983599
UserNameTAG: IvyGarson
CreateTimeTAG: 2013-02-24T05:33:29Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2570
TitleTAG: Quantitative or qualitative?
In the lecture it was said "If you measure job performance, poor, satisfactory, excellent, there's a
clear ranking relative to each other.
Such variables are called quantitative ordinal, because their values have an
order relative to each other."
Shouldn't that be qualitative ordinal?
UserIdTAG: 1284382
UserNameTAG: kite420
CreateTimeTAG: 2013-02-24T05:29:12Z
VoteTAG: 5
CoursewareTAG: Section 1: Introduction / Lec 1.2. Variables: terminology
NumberOfReplyTAG: 4
FirstChildTAG: Yes, i agree with you.
FirstChildUserIdTAG: 1115908
FirstChildUserNameTAG: rochak_khandelwal
FirstChildCreateTimeTAG: 2013-02-24T06:19:07Z
FirstChildVoteTAG: 3
SecondChildTAG: You are right, that what the instructor tells us in the video "Qualitative ordinal" , but the text scrolling along the video mentions it as Quantitative ordinal which is incorrect.
SecondChildUserIdTAG: 558560
SecondChildUserNameTAG: wasimpak
SecondChildCreateTimeTAG: 2013-02-24T06:49:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Good observation.
SecondChildUserIdTAG: 1058400
SecondChildUserNameTAG: Rayde
SecondChildCreateTimeTAG: 2013-02-24T15:00:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Its Qualitative ordinal from what I read in the slides
SecondChildUserIdTAG: 1246920
SecondChildUserNameTAG: dzame
SecondChildCreateTimeTAG: 2013-02-25T12:24:07Z
SecondChildVoteTAG: 0
SecondChildTAG: is the cc caption that is wrong, the slides are ok.
SecondChildUserIdTAG: 1316542
SecondChildUserNameTAG: Dodavor
SecondChildCreateTimeTAG: 2013-02-27T02:17:55Z
SecondChildVoteTAG: 0
FirstChildTAG: I do agree too!
FirstChildUserIdTAG: 1088741
FirstChildUserNameTAG: haalmo
FirstChildCreateTimeTAG: 2013-02-25T07:59:03Z
FirstChildVoteTAG: 0
FirstChildTAG: correct
FirstChildUserIdTAG: 1198994
FirstChildUserNameTAG: parthkelkar
FirstChildCreateTimeTAG: 2013-02-26T13:53:32Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree with you also because you can not add or subtract poor from satisfactory. If it was quantitative you would be able to.
FirstChildUserIdTAG: 453550
FirstChildUserNameTAG: DebbieSmith
FirstChildCreateTimeTAG: 2013-02-27T02:47:15Z
FirstChildVoteTAG: 0
IndexTAG: 2571
TitleTAG: STAFF - TEXTBOOK READINGS
Please advise what readings we should be reading that corresponds with the lessone. This would be truly helpful. Also is there an easy way to print the textbook completely?
Please advise thanks
Amy
UserIdTAG: 411228
UserNameTAG: aimster
CreateTimeTAG: 2013-02-24T05:23:02Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: no. there is no such provision.
FirstChildUserIdTAG: 1115908
FirstChildUserNameTAG: rochak_khandelwal
FirstChildCreateTimeTAG: 2013-02-24T06:24:27Z
FirstChildVoteTAG: 0
FirstChildTAG: The reading are broken down into sections. On the lecture pages if there is a section to read there is a link posted.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/36bcbc2a9dbd4f4b8546f13c035b2759/ca2db05b6d7a4e1b9ffd57e5b8b5c740/
Go to this page and about midway on the page there are links to sections in the textbook.
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-24T06:36:42Z
FirstChildVoteTAG: 0
IndexTAG: 2572
TitleTAG: Postings of the Staff and Professors
Is there a way to ahve posting of staff and Professors searchable.I was manually going through various posts when I saw Prof Adhikari's answer to one of the questions and I think most of us would love to read such responses.I fortuitously found a psot which I had missed today.
Is it possible to also have a "Unread" post sorter(just like the All and Followed etc in the discussion area ? It would be helpful to check only New posts or unread posts
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-24T05:19:25Z
VoteTAG: 5
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2573
TitleTAG: Mendel Genetics problem i UNDERSTAND BUT SOMEHOW ANSWERS ARE WRONG
tHIS PROBLEM WAS THE MENDEL RATIO BUT I DO NOT UNDERSTAND HOW MY ANSWERS WERE WRONG
Mendel ratio for 500 plants
RATIO 9:3:3:1
9/16= 0.5625 OR 281.25 PLANTS
3/16= 0.1875 OR 93.75 PLANTS THAT WOULD BE 18.75 PERCENT
3/16 = 0.1875 OR 93.75 PLANTS
1/16= 0.0625 or 31.25 PLANTS
for 480 plants 0.5625*480= 270 plants
for 500 plants YOU GET THE 9/16 = 281.25 PLANTS
i KNOW HOW TO DO THE PROBLEMS BUT SOMEHOW THE NUMBERS ARE WRONG IN THE ANSWERS AND i CAN NOT GO BACK AND FIX THEM
UserIdTAG: 168169
UserNameTAG: Elainethorne
CreateTimeTAG: 2013-02-24T05:14:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: All caps is equivalent of shouting so please refrain from using it.Please remember that you were asked to determine the ratios of 480 plants and then 20 were added to it !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T05:21:32Z
FirstChildVoteTAG: 0
SecondChildTAG: green/green was not a classification in the original experiment, so adding another 20 green/green plants is not possible unless you are changing the parameters of the experiment and that was not made clear. In the chart problem, 3a, there was no green/green column added so it is a bit confusing.
SecondChildUserIdTAG: 1284382
SecondChildUserNameTAG: kite420
SecondChildCreateTimeTAG: 2013-02-24T08:00:11Z
SecondChildVoteTAG: 0
SecondChildTAG: You can add a whole new set of plants.We are not conducting an experiment here but counting and doing ratios and proportions !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T08:55:09Z
SecondChildVoteTAG: 0
FirstChildTAG: And the honour code you agreed to should also be remembered.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T08:01:25Z
FirstChildVoteTAG: 0
SecondChildTAG: 20 plants were added to the second part of the exercise. I agree, your logic is correct but for the first part all calculations should be done with 480 plants only.
SecondChildUserIdTAG: 1003872
SecondChildUserNameTAG: Marcela_JH
SecondChildCreateTimeTAG: 2013-02-24T12:56:14Z
SecondChildVoteTAG: 0
IndexTAG: 2574
TitleTAG: Problem 1... A-C
I got all answers correct in all other problems, but none in problem 1.
I used the correct methods, I think. I got confused a bit because the data sets are not discrete numbers, but ranges, and I think I made an error because of this.
Without stating the answers, can anyone point out to me where I made a mistake?
UserIdTAG: 1118796
UserNameTAG: SFPrichard
CreateTimeTAG: 2013-02-24T05:02:54Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: How can one say how you did something wrong when we do not knwo what you did ;)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T05:22:20Z
FirstChildVoteTAG: 0
SecondChildTAG: ya its lower quartile is 25% and upper is 75%.my all answers correct.
SecondChildUserIdTAG: 488171
SecondChildUserNameTAG: kirtisundar
SecondChildCreateTimeTAG: 2013-02-24T06:30:56Z
SecondChildVoteTAG: 0
SecondChildTAG: I started with the formal definition, got my values, plugged them in, and big red X. I'm not sure how the values were supposed to be entered - even though 1c said round to one decimal. So I did that, and big red X.
I'm sure about the material - it's easy as it can be. But I just don't know how I was supposed to enter the values.
SecondChildUserIdTAG: 1118796
SecondChildUserNameTAG: SFPrichard
SecondChildCreateTimeTAG: 2013-02-24T16:31:21Z
SecondChildVoteTAG: 0
SecondChildTAG: I am in the same situation. I already have my answers but don´t know how to insert them. The last one says to round to one decimal places, but the other two what? One decimal places or two?
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-02-24T16:44:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Round all to one decimal place.
You dont have to draw any histogram for this. Watch Lec 2.4 while working out the problem.
I recommend practicing the excersises in the textbook.
SecondChildUserIdTAG: 254949
SecondChildUserNameTAG: stormshadow
SecondChildCreateTimeTAG: 2013-02-24T17:03:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Am i the only person here who got 20/20 in this exam?
FirstChildUserIdTAG: 1104740
FirstChildUserNameTAG: dramrali
FirstChildCreateTimeTAG: 2013-02-24T15:11:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Me too :)
SecondChildUserIdTAG: 31529
SecondChildUserNameTAG: abbass
SecondChildCreateTimeTAG: 2013-02-24T15:56:54Z
SecondChildVoteTAG: 0
SecondChildTAG: 20/20 actually found this easier than the previous exercises :)
SecondChildUserIdTAG: 254949
SecondChildUserNameTAG: stormshadow
SecondChildCreateTimeTAG: 2013-02-24T17:23:19Z
SecondChildVoteTAG: 0
SecondChildTAG: This was my first 100% group.
SecondChildUserIdTAG: 1174310
SecondChildUserNameTAG: Catprog
SecondChildCreateTimeTAG: 2013-02-25T03:05:38Z
SecondChildVoteTAG: 0
SecondChildTAG: I got 100% too :)
SecondChildUserIdTAG: 1053569
SecondChildUserNameTAG: nicola2003
SecondChildCreateTimeTAG: 2013-02-25T21:22:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Did the calculation with cumulated percent....I'm way too tired, insomnia....shit! how to lose 6 points so stupidly!!! I want my brain back!!!!!!
SecondChildUserIdTAG: 1013822
SecondChildUserNameTAG: FaizaHarbi
SecondChildCreateTimeTAG: 2013-02-27T23:06:12Z
SecondChildVoteTAG: 0
IndexTAG: 2575
TitleTAG: Problem 3 (a)
I do not understand the wording of "over the interval 13-16"; do you mean this "13-16"group or do you mean "16-22"group. Thanks a lot.
UserIdTAG: 547145
UserNameTAG: Pronectar
CreateTimeTAG: 2013-02-24T04:57:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: There IS no 16-22 interval. The problem specifies 13-16. What are you really asking?
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-24T05:09:41Z
FirstChildVoteTAG: 0
SecondChildTAG: by "over" we should be thinking "throughout" (not "above"). Is that what you mean?
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-24T05:11:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes. Thanks a lot. English is not my first language.
SecondChildUserIdTAG: 547145
SecondChildUserNameTAG: Pronectar
SecondChildCreateTimeTAG: 2013-02-25T01:52:15Z
SecondChildVoteTAG: 0
IndexTAG: 2576
TitleTAG: Practice Set for 2.2
Is the answer to (a) in the practice set correct? Isn't the width of the class interval 30 rather than 10 (-10 to 20)?
UserIdTAG: 919673
UserNameTAG: ldh
CreateTimeTAG: 2013-02-24T04:56:13Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: This has been discussed ad nauseum !! .Please check Courseware errata
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T04:59:28Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks for the link to the errata :)
SecondChildUserIdTAG: 1230511
SecondChildUserNameTAG: Christeph
SecondChildCreateTimeTAG: 2013-02-24T07:30:49Z
SecondChildVoteTAG: 0
IndexTAG: 2577
TitleTAG: Estimating the median
Yellow bars have a total area of 48%.
Area of 25-50 bar = 27%, and we want 2% of it to get to the median.
estimated median = 25 + 2/27 x (50-25)= 26.85 thousand dollars = $26,850, roughly
In the problem above do we multiply the (50-25) so the equation appears to be 25+100-50 or how does the interval work into the equation?
Okay writing it down like i did helped. Here is how I solved it and I hope it is right.
25+2/27 x (50-25)
25+.0704 x 25
25+1.85
26.85
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-24T04:45:10Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 50-25 is the width of the interval. You're going a fraction of 2/27 of that width into the interval, starting at the left end. So the general form is:
left end + fraction*width
Does that help?
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T03:42:39Z
FirstChildVoteTAG: 0
IndexTAG: 2578
TitleTAG: Exercise Set 1 - Problems
Hi,
I do agree with some other students that correct answer with logic may be shown at some point. Like, e.g., Answer of the Problem 2 (b) does not seem to match the logic, at least to me and same is with few other problem's.
UserIdTAG: 955530
UserNameTAG: BUpadhyay
CreateTimeTAG: 2013-02-24T04:36:23Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Look at the question and the options carefully.There is a right answer - you need to inspect and check all possibilities and multiple possibilities
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T05:00:54Z
FirstChildVoteTAG: 0
IndexTAG: 2579
TitleTAG: Ability to view correct answers after submitting our answers?
Hello Professors and Teaching Assistants,
Just wondering if it could be possible for students to see the correct answers or model answers for the questions after they have submitted their answers?
I think this would benefit us greatly. Thanks for your consideration.
Kim.
UserIdTAG: 1221482
UserNameTAG: Kimmy2013
CreateTimeTAG: 2013-02-24T04:05:27Z
VoteTAG: 8
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: I do agree
FirstChildUserIdTAG: 955530
FirstChildUserNameTAG: BUpadhyay
FirstChildCreateTimeTAG: 2013-02-24T04:37:16Z
FirstChildVoteTAG: 0
FirstChildTAG: This will be done after the due date- You can't get the answers open prematurely or else people can cross consult and defeats the purpose of assessment
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-24T05:01:43Z
FirstChildVoteTAG: 2
FirstChildTAG: This is all detailed in the course handouts. These are made available for a reason. We are supposed to read them!
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T07:43:37Z
FirstChildVoteTAG: 0
FirstChildTAG: I second Kim, its frustrating not to know where my answer was faulty.
FirstChildUserIdTAG: 1091140
FirstChildUserNameTAG: EdithS
FirstChildCreateTimeTAG: 2013-02-24T10:29:41Z
FirstChildVoteTAG: 0
FirstChildTAG: yes plz
FirstChildUserIdTAG: 704053
FirstChildUserNameTAG: jehadhassan
FirstChildCreateTimeTAG: 2013-02-25T17:33:22Z
FirstChildVoteTAG: 0
IndexTAG: 2580
TitleTAG: It would be helpful...
If the format of the answers was available or made known, i.e the number of decimal places we should be expected to round to, or if and when % signs are needed etc. Saul Kahn's website is very accommodating that way.
Thanks for offering this wonderful free knowledge. This is quite a paradigm shift for education!
UserIdTAG: 74817
UserNameTAG: benmatthews
CreateTimeTAG: 2013-02-24T03:21:50Z
VoteTAG: 11
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Agree 100%. The problem needs to accept all possible answers or tell us the format they wish it to be in. Otherwise answering is impossible.
FirstChildUserIdTAG: 369936
FirstChildUserNameTAG: vanzilar
FirstChildCreateTimeTAG: 2013-02-24T04:18:01Z
FirstChildVoteTAG: 3
FirstChildTAG: This has been brought up previously and addressed by staff. Future exercises will take this into consideration.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-24T07:11:01Z
FirstChildVoteTAG: 1
IndexTAG: 2581
TitleTAG: hello please help me
I have used all the submissions in the exercises,so anything more to be done,I mean submission some were 1 out of 1,then 2 out of 2,so so after getting correct in the first attempt I used the second submission to final check,so are the scores submitted properly?Or anything extra needs to be done?And though I can see my scores in Progress section,so please help me out,after final check anything needs to be done?And for the later problems,if I do get some question correct in 1st chance,then do I need to submit it again if there are 2 out of 2 submissions?Please help....
UserIdTAG: 1177236
UserNameTAG: SOHAM1989
CreateTimeTAG: 2013-02-24T03:14:24Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No. If you get it right the first time then there is no need to resubmit. Check your score in the progress bar to verify if you got credit for the correct submission.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-02-24T03:24:30Z
FirstChildVoteTAG: 0
IndexTAG: 2582
TitleTAG: non-uniform distribution and 75%
If instead of the 25-50 being 27% you had 25-30 26% and 30-50 being 1% wouldn't the cumulative 75% still be at the end of the bar 49,999 is in?
UserIdTAG: 1174310
UserNameTAG: Catprog
CreateTimeTAG: 2013-02-24T02:53:06Z
VoteTAG: 1
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 4
FirstChildTAG: This is what I was wondering, too, because the intervals include the left endpoint but not the right, right?
FirstChildUserIdTAG: 703962
FirstChildUserNameTAG: NataliaWeil
FirstChildCreateTimeTAG: 2013-02-24T02:57:30Z
FirstChildVoteTAG: 1
SecondChildTAG: Given how the histogram is displayed, under either scenario, either including the right endpoint and excluding the left or excluding the left and including the right, bunching closer to the beginning of 25-50 would still have no effect on $50,000 being the 75th percentile, right?
SecondChildUserIdTAG: 967698
SecondChildUserNameTAG: cb1667
SecondChildCreateTimeTAG: 2013-02-24T18:59:16Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes it would be. 50% of results would still be to the left of $50,000, regardless of how you split up the histogram to the left.
Using the above example, if the 30-50 interval was changed to 30-60 containing 2%, then your values would change, due to the distribution in the interval containing the 50th percentile.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-24T07:14:57Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree and came to the discussion just to check that.
FirstChildUserIdTAG: 266427
FirstChildUserNameTAG: RapidE
FirstChildCreateTimeTAG: 2013-02-24T15:14:59Z
FirstChildVoteTAG: 0
FirstChildTAG: I think the point being made was that if instead of 25-50 being 27% it was
25-45 27%
45-50 0%
then the 75 %ile point changes to 45, not 50.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T04:04:17Z
FirstChildVoteTAG: 1
SecondChildTAG: Exactly. As long as there is at least one value of 50, the median does not change. But it does change if in this interval there is no one earning 50000.
On the other hand: as long as we assumed our intervals don't include the right end-point, does it not mean that the median value cannot anyway be equal to 50000, it can only be really really close to this value?
SecondChildUserIdTAG: 517550
SecondChildUserNameTAG: Ewa_G
SecondChildCreateTimeTAG: 2013-02-25T11:16:39Z
SecondChildVoteTAG: 0
IndexTAG: 2583
TitleTAG: Question on the way questions are set up
Is it possible to set the questions that are for practice so they break down the steps to solving the question into chunks that can be easily managed?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-24T02:42:56Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2584
TitleTAG: Inquiry on Joining the course on its 4th day- For the Instructors
Hi,
I would like to inquire if it is still possible to join the course on its 4th day. I just got to know about edX and just signed up today, February 24. I know that the course started Feb 20. but I am very interested in taking this course. Would it still be possible to submit the practice exercises that I have missed and take the tests or exams for this course and hopefully if I pass, will I still be able to get the certification?
This humanitarian project is a great help for us especially those living in the 3rd world country who cannot afford to go to universities such as MIT, Harvard, or Berkeley. This gives us hope that we can survive and help our families. You are God's Blessing to people like us.
Your response to this query will be greatly appreciated.
Thanks!
UserIdTAG: 1298973
UserNameTAG: vivensdios88
CreateTimeTAG: 2013-02-24T02:22:03Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Just join the course and start doing the exercises. They have due dates.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-02-24T03:26:11Z
FirstChildVoteTAG: 0
FirstChildTAG: Absolutely. If the goal is a certificate, you only need 35% to pass the course. This is still achievable.
Also, all of the course material stays up on the page for the entire course, so you can always go back and review what you may have missed.
Good luck!
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-24T07:16:27Z
FirstChildVoteTAG: 0
FirstChildTAG: You have posted to the forum, so you have joined the course.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T07:45:42Z
FirstChildVoteTAG: 0
IndexTAG: 2585
TitleTAG: confusssed sec 2
Are we still using chapter 3 for this section of do we need to read chapter 4
UserIdTAG: 264805
UserNameTAG: staci
CreateTimeTAG: 2013-02-24T01:49:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: We have not been instructed to use Chapter 4 yet, and none of the exercises or practices link or refer to anything but Chapter 3.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-24T02:00:22Z
FirstChildVoteTAG: 0
FirstChildTAG: Well, awesome. Thanksfor the answer.
FirstChildUserIdTAG: 264805
FirstChildUserNameTAG: staci
FirstChildCreateTimeTAG: 2013-02-24T22:47:17Z
FirstChildVoteTAG: 0
IndexTAG: 2586
TitleTAG: About Lectures 2.2 and 2.3 a)
I think the answer is 0.46 because is (14/30) the diference between -10 t0 20 is 30
UserIdTAG: 1235463
UserNameTAG: marychiri
CreateTimeTAG: 2013-02-24T01:26:39Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Yes answer should be .46%. I am enjoying the course too :-)
FirstChildUserIdTAG: 1261388
FirstChildUserNameTAG: PadmaUpp
FirstChildCreateTimeTAG: 2013-02-24T03:04:12Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, and if you had read past posts in this subforum you would have noticed that the vast majority refer to this very question.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-24T07:47:39Z
FirstChildVoteTAG: 0
IndexTAG: 2587
TitleTAG: Availability of prior lectures when we move on to subsequent lectures?
When we move on to subsequent lectures, will the previous lectures, practices, and exercises still be available for reviewing in Courseware?
UserIdTAG: 1235638
UserNameTAG: MyOwnCamera
CreateTimeTAG: 2013-02-24T01:13:56Z
VoteTAG: 1
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.4. Percentiles: estimating from a histogram
NumberOfReplyTAG: 3
FirstChildTAG: Obviously...and better you can also download them...
FirstChildUserIdTAG: 795482
FirstChildUserNameTAG: VIVEK_88
FirstChildCreateTimeTAG: 2013-02-24T01:27:43Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you. It was obviously not obvious to me they would still be in Courseware.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-24T01:46:05Z
FirstChildVoteTAG: 0
FirstChildTAG: They'll be there. As will the answers to previous exercise sets. This is quite important as the course builds on itself. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T03:44:38Z
FirstChildVoteTAG: 1
SecondChildTAG: that's really helpful for all of us.
SecondChildUserIdTAG: 1236052
SecondChildUserNameTAG: neelam25
SecondChildCreateTimeTAG: 2013-02-27T14:57:16Z
SecondChildVoteTAG: 0
IndexTAG: 2588
TitleTAG: About the lec 1.3 a) and c)
The porcent of seniors is 11.11 because is (1/9)*100
The percent of freshmen is 22.22 because is (2/9)*100
UserIdTAG: 1235463
UserNameTAG: marychiri
CreateTimeTAG: 2013-02-24T01:08:46Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: u r right, but the system accepted only one decimal point.
FirstChildUserIdTAG: 390463
FirstChildUserNameTAG: DrPatilShrish
FirstChildCreateTimeTAG: 2013-02-24T17:25:25Z
FirstChildVoteTAG: 0
IndexTAG: 2589
TitleTAG: left tail options
I was wondering: would gestation in humans be an example where there is more likely to be a left tail? i.e., as medical technology advances, earlier and earlier births are possible... but maybe not so much after, say, 42 weeks?
UserIdTAG: 961272
UserNameTAG: CuriousCatastrophe
CreateTimeTAG: 2013-02-24T00:18:18Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Good point.
It may be possible up to a specific biologic threshold.
But there are a lot of interactions between the mother and the fetus that will ensure the successful viability of the offspring. (look at the literature about this) - Without them, no medical advances can cope.
Our gestation period - IS - The gestation period determined as per our genetically evolutionary mechanisms and cannot be confused with gestation speed.
If you ask me if there will be traits or physiological mechanisms that could evolve to a somehow different birth experience (e.g. the conditions behind less and less natural births versus C-sections), then - as an evolutionary biologist - I would agree that the future may be a surprise. But again - evolution doesn't work like that. That's the beauty of it.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-24T00:35:49Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, I guess I was trying to get more at survival rates... and I imagine that as medical technology advances there could eventually be more of a right tail...??
SecondChildUserIdTAG: 961272
SecondChildUserNameTAG: CuriousCatastrophe
SecondChildCreateTimeTAG: 2013-02-26T14:42:00Z
SecondChildVoteTAG: 0
FirstChildTAG: I actually have some data on gestation days, and yes, there's a left tail. Want me to use it in a future lecture or exercise?
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-25T03:47:40Z
FirstChildVoteTAG: 0
SecondChildTAG: If it's not too much trouble. Thanks.
SecondChildUserIdTAG: 961272
SecondChildUserNameTAG: CuriousCatastrophe
SecondChildCreateTimeTAG: 2013-02-26T14:39:21Z
SecondChildVoteTAG: 0
IndexTAG: 2590
TitleTAG: Problem 2 a
"About what percent of the people were in their thirties?3"
What does it mean "in their thirties"?
Should we understand people aged within the interval 30-39?
Thanks for any explanation!
UserIdTAG: 636013
UserNameTAG: ABARIGOU
CreateTimeTAG: 2013-02-23T23:42:35Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: People aged in their 30s, so $30 \le X \lt 40$
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T23:49:41Z
FirstChildVoteTAG: 4
FirstChildTAG: You got it: 30-39, it's a frequently-used expression in English.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-23T23:50:55Z
FirstChildVoteTAG: 1
IndexTAG: 2591
TitleTAG: We would need increase the number of submitions
Coursera let us submit at less 3 times each exercise.
On each submit we get the answer about if our job is
correct or not.
Also we need 70% to get certificate.
I think it is better to refine and increase our work
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-23T23:03:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: This is not Coursera. And there are some courses on Coursera where you are *not* given the answer on submission. You wait until after the deadline before you know your grade. Multiple submissions allowed, but no instant grading. Your last attempt is the one that is graded.
>We would need increase the number of submitions
This has already been explained by the Prof.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5125aceb9914d22b0000019d
>Also we need 70% to get certificate.
That is for the organisers to decide. No matter what the required grade, someone will be unhappy. Someone will always consider the grade is too high or too low. Then the requests for "with distinction" or the actual grade to be included on the certificate. Then the hardcopy requests. Every course goes through this.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T23:06:54Z
FirstChildVoteTAG: 3
SecondChildTAG: Susan... couldn't agree more with you.
SecondChildUserIdTAG: 206086
SecondChildUserNameTAG: pedrocas1972
SecondChildCreateTimeTAG: 2013-02-23T23:19:01Z
SecondChildVoteTAG: 0
SecondChildTAG: (Correct plaToo much information and not very nice. The link e) enough answer Thanks anyway
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-02-24T12:19:01Z
SecondChildVoteTAG: 0
FirstChildTAG: Too much information and not very nice. The link is enough answer
Thanks anyway
FirstChildUserIdTAG: 692378
FirstChildUserNameTAG: JorgeSeifert
FirstChildCreateTimeTAG: 2013-02-23T23:44:53Z
FirstChildVoteTAG: 0
IndexTAG: 2592
TitleTAG: Always wrong answer
All the combinations (11,1 or 11,11 or 11,1% etc.) are wrong for the system! This is not possible! What does it want exactly?
UserIdTAG: 1252051
UserNameTAG: Stefymonte
CreateTimeTAG: 2013-02-23T22:45:15Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 5
FirstChildTAG: try 11.1 (point not comma)
FirstChildUserIdTAG: 1241198
FirstChildUserNameTAG: lms17685
FirstChildCreateTimeTAG: 2013-02-23T22:48:17Z
FirstChildVoteTAG: 3
FirstChildTAG: > What does it want exactly?
It wants the non-European version. Remember where the course is based.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:57:52Z
FirstChildVoteTAG: 0
SecondChildTAG: the same thing happend to me! =(
SecondChildUserIdTAG: 1086212
SecondChildUserNameTAG: JesusArriaga
SecondChildCreateTimeTAG: 2013-02-24T01:28:29Z
SecondChildVoteTAG: 0
SecondChildTAG: And too me, we need to put a "." and not a ","
SecondChildUserIdTAG: 1044317
SecondChildUserNameTAG: Mlaknin
SecondChildCreateTimeTAG: 2013-02-24T20:55:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Well, it should not mark answer 11.11% as incorrect, because it is correct. If percentage symbol is not obligatory, then it would be good idea to put it at the end of the answer box.
On the other hand, as 11.11 has two decimal places, and "correct answer" 11.1 only one, then it should be stated in the text of the problem how many decimals should be included in the answer.
FirstChildUserIdTAG: 1261562
FirstChildUserNameTAG: AleksandraR
FirstChildCreateTimeTAG: 2013-02-23T23:09:20Z
FirstChildVoteTAG: 3
FirstChildTAG: It's because of the use of "," instead of "."
FirstChildUserIdTAG: 329709
FirstChildUserNameTAG: January
FirstChildCreateTimeTAG: 2013-02-24T04:59:40Z
FirstChildVoteTAG: 0
FirstChildTAG: If you search the discussions, you will see that precision has been raised and addressed by the staff. They will be designing future exercises with this issue in mind.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-24T07:19:43Z
FirstChildVoteTAG: 0
IndexTAG: 2593
TitleTAG: Excercise Set 2 Applet
I can not see the histogram that is the applet in Figure 3-2 so I cannot complete the questions. Do you have suggestions?
UserIdTAG: 160934
UserNameTAG: DonnaC
CreateTimeTAG: 2013-02-23T22:27:54Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I couldn't using either using IE or PaleMoon browsers. I installed Firefox and when I use it I can see the applet.
FirstChildUserIdTAG: 1223711
FirstChildUserNameTAG: Poddar22947
FirstChildCreateTimeTAG: 2013-02-23T22:37:22Z
FirstChildVoteTAG: 0
FirstChildTAG: > I can not see the histogram that is the applet in Figure 3-2 so I cannot complete the questions. Do you have suggestions?
You don't need any applet. Just answer the questions as demonstrated during the lectures.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:50:38Z
FirstChildVoteTAG: 0
SecondChildTAG: I couldn't see the histogram. I downloaded Chrome and can now see it.
SecondChildUserIdTAG: 160934
SecondChildUserNameTAG: DonnaC
SecondChildCreateTimeTAG: 2013-02-24T10:08:15Z
SecondChildVoteTAG: 0
IndexTAG: 2594
TitleTAG: a little mistake
think the same about exercise a), the width of class interval must be 30, a little mistake. anyway i'm enjoying this course ;)
UserIdTAG: 944404
UserNameTAG: heytati
CreateTimeTAG: 2013-02-23T22:13:25Z
VoteTAG: 9
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I would enjoy it more if people would stop posting the same thing repeatedly. We now have subforums, so comments should be added existing posts about a particular topic.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:18:22Z
FirstChildVoteTAG: 1
SecondChildTAG: Thats OK heytati
We are all learning at our own pace and abilities.
Do not be concerned re asking for clarification, if we do make an odd "error" all part of the learning experiance.
Thanks!
SecondChildUserIdTAG: 313672
SecondChildUserNameTAG: blinxnot
SecondChildCreateTimeTAG: 2013-02-24T02:06:51Z
SecondChildVoteTAG: 0
IndexTAG: 2595
TitleTAG: Answers to graded exercises
It's a bit frustrating to not get solutions to the graded exercises after submission because if the course is cumulative, then we need to know whether our errors are just notations errors or calculation errors. If it is just a notation error, then, I know "I got it" and it was a technical mistake. If it's a calculation error, then, I want to review before moving on. I do not want to move on with something I did not properly understand.
And I know it has been discussed before but the lack of clear instructions as to how to submit (the proper notation, unit, decimals, etc.) is a major source of frustration.
UserIdTAG: 1055674
UserNameTAG: SocProf
CreateTimeTAG: 2013-02-23T22:11:27Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes, and it will be fixed for future assessments.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
>It's a bit frustrating to not get solutions to the graded exercises after submission
And this is how assessment generally works. You don't get answers while people are still doing the assessment. Rather defeats the purpose.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:20:04Z
FirstChildVoteTAG: 1
IndexTAG: 2596
TitleTAG: last question
this one is really good trick questuion
UserIdTAG: 1014435
UserNameTAG: Kevin14158
CreateTimeTAG: 2013-02-23T22:03:14Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: It is not a trick question. It is seeing if you understood everything. that is not a trick.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:20:39Z
FirstChildVoteTAG: 0
FirstChildTAG: The box plot question is not a tricky question. its actually a pretty easy one.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-23T23:26:39Z
FirstChildVoteTAG: 0
IndexTAG: 2597
TitleTAG: Missing transcript?
I can see no transcript for Lec 2.5 - are others having this problem?
UserIdTAG: 900260
UserNameTAG: joecoward
CreateTimeTAG: 2013-02-23T21:59:50Z
VoteTAG: 23
CoursewareTAG: Section 2b: The Histogram (Lec 2.4 - 2.5) / Lec 2.5. Percentiles: more carefully, from the data
NumberOfReplyTAG: 4
FirstChildTAG: Yes, I noticed that also. I enjoy the transcript part of the lecture as well.
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-23T22:19:03Z
FirstChildVoteTAG: 1
SecondChildTAG: there is a reference to the section in the textbook on histograms I've been studying it religiously
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-24T02:10:41Z
SecondChildVoteTAG: 0
SecondChildTAG: You can see them a speed 1.0x
SecondChildUserIdTAG: 657394
SecondChildUserNameTAG: doris_rosario78
SecondChildCreateTimeTAG: 2013-02-27T11:58:42Z
SecondChildVoteTAG: 0
SecondChildTAG: I can't seem that at speed 1.0x or any other speed. I really rely on them to take notes/study. Is there a way to fix this problem??
SecondChildUserIdTAG: 896245
SecondChildUserNameTAG: Ingrid90
SecondChildCreateTimeTAG: 2013-02-27T18:12:38Z
SecondChildVoteTAG: 0
FirstChildTAG: It has been commented on.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:24:15Z
FirstChildVoteTAG: 0
FirstChildTAG: me too.
FirstChildUserIdTAG: 1022813
FirstChildUserNameTAG: shadowinder
FirstChildCreateTimeTAG: 2013-02-25T06:40:49Z
FirstChildVoteTAG: 0
FirstChildTAG: No, I could not see the text. Is it missing?
FirstChildUserIdTAG: 997487
FirstChildUserNameTAG: supriya9772
FirstChildCreateTimeTAG: 2013-02-27T16:21:24Z
FirstChildVoteTAG: 0
IndexTAG: 2598
TitleTAG: Applet figure 3-2
The applet is not working for me - suggestions?
UserIdTAG: 160934
UserNameTAG: DonnaC
CreateTimeTAG: 2013-02-23T21:35:31Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: What browser are you using? Also, which applet are you referring to?
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T21:40:31Z
FirstChildVoteTAG: 0
SecondChildTAG: online text book
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-24T00:46:47Z
SecondChildVoteTAG: 0
FirstChildTAG: Is Java enabled?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:22:05Z
FirstChildVoteTAG: 0
FirstChildTAG: Use Chrome or Mozilla
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-24T00:37:28Z
FirstChildVoteTAG: 0
SecondChildTAG: I downloaded chrome and now can see it. Thx.
SecondChildUserIdTAG: 160934
SecondChildUserNameTAG: DonnaC
SecondChildCreateTimeTAG: 2013-02-24T10:08:54Z
SecondChildVoteTAG: 0
IndexTAG: 2599
TitleTAG: point A and C answer
the answer i give to point a) is 11.111111 which is the exact value
but the system consider it wrong because it is consider the correct answer is 11.1 only
and same in case of c) my answer is 22.222222 and the system answer is 22.2
UserIdTAG: 146746
UserNameTAG: AhmedFouad
CreateTimeTAG: 2013-02-23T20:58:28Z
VoteTAG: 6
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Yes, as has been commented on dozens of times. Including several posts on the newly created subforum you used.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:16:37Z
FirstChildVoteTAG: 0
IndexTAG: 2600
TitleTAG: I love the teacher
Her voice is so calm and interesting, (which is GREAT!) I just saw the fist video and I'm already enjoying the course.
What do you think of her?
UserIdTAG: 910472
UserNameTAG: GiancarloM
CreateTimeTAG: 2013-02-23T20:35:43Z
VoteTAG: 25
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 4
FirstChildTAG: Yes - she has an excellent presentation style
FirstChildUserIdTAG: 20879
FirstChildUserNameTAG: forevergreen
FirstChildCreateTimeTAG: 2013-02-23T21:08:06Z
FirstChildVoteTAG: 3
SecondChildTAG: wonderful presentation style
SecondChildUserIdTAG: 1034344
SecondChildUserNameTAG: satishmahankali
SecondChildCreateTimeTAG: 2013-02-23T23:10:43Z
SecondChildVoteTAG: 0
SecondChildTAG: i really like the way she is doing her presentation !!
SecondChildUserIdTAG: 1062477
SecondChildUserNameTAG: alejandra-hd
SecondChildCreateTimeTAG: 2013-02-24T06:41:01Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes she is just wonderful..explain in simpler way....I am just enjoying
SecondChildUserIdTAG: 1236052
SecondChildUserNameTAG: neelam25
SecondChildCreateTimeTAG: 2013-02-24T14:13:31Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree! Wonderful teacher!
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-23T21:55:14Z
FirstChildVoteTAG: 1
FirstChildTAG: Agree!
Lectures are excellent! And her voice and intonation are crystal clear (something really important for non-native English speakers).
P.S. Maybe she is using LaTeX/Beamer to do her well-prepared slides. Not sure, but the slide theme is familiar to me.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-23T22:42:29Z
FirstChildVoteTAG: 2
SecondChildTAG: It definitely seems to be LaTeX/Beamer!
SecondChildUserIdTAG: 99863
SecondChildUserNameTAG: pramode_ce
SecondChildCreateTimeTAG: 2013-02-24T02:33:25Z
SecondChildVoteTAG: 0
SecondChildTAG: You got it. LaTex/Beamer, theme Ann Arbor. Thanks for the kind words. Best,
Prof. A.
SecondChildUserIdTAG: 1019686
SecondChildUserNameTAG: AniAdhikari
SecondChildCreateTimeTAG: 2013-02-25T03:48:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Great! LaTeX rocks!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-25T11:15:56Z
SecondChildVoteTAG: 0
SecondChildTAG: what is LaTeX?
SecondChildUserIdTAG: 1303647
SecondChildUserNameTAG: Aggers
SecondChildCreateTimeTAG: 2013-02-25T12:55:37Z
SecondChildVoteTAG: 0
SecondChildTAG: http://en.m.wikipedia.org/wiki/LaTeX
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-25T13:21:19Z
SecondChildVoteTAG: 0
FirstChildTAG: Fabulous teacher. Excellent tone and voice. The information is very clearly organized and presented. Thank you to our Professor!
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-28T02:03:18Z
FirstChildVoteTAG: 0
IndexTAG: 2601
TitleTAG: multiple Answers
**Can i take multiple answers of a question**
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-23T20:21:40Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: You can't in this set 2, if I recall well. But it's easy to test, if you select a second option and your previous first selection is automatically unselected :)
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-23T22:52:15Z
FirstChildVoteTAG: 0
FirstChildTAG: In this set, no. You can tell by the check boxes.
Round means only one choice allowed.
![enter image description here][1]
Square means multiple choices.
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13616605621343689.png
[2]: https://edxuploads.s3.amazonaws.com/13616605821343679.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T23:03:23Z
FirstChildVoteTAG: 0
IndexTAG: 2602
TitleTAG: precision
Hello
please make clear how many decimal digits must we use on giving answers.
I've typed the right ones but the system has told me taht it was wrong. The reason: it expected ony one decimal digit and I gave two.
UserIdTAG: 98221
UserNameTAG: afgerman
CreateTimeTAG: 2013-02-23T20:14:45Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:14:27Z
FirstChildVoteTAG: 0
FirstChildTAG: Susan is as kind as to rewrite the same links again and again, but, guys, please, take notice of the search button (the magnifying glass icon), it is there for something :-)
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-23T23:23:51Z
FirstChildVoteTAG: 0
IndexTAG: 2603
TitleTAG: What means "Uniformly distributed within each interval" ?
You can assume that the ages are uniformly distributed within each interval.??
Could some one provide a brief example?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-23T19:27:24Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: If the interval is for example from 20 to 30 and you have 20 person in the interval you assume that there are 2 people (20 persons/10 years from 20 to 30) with 20 years, 2 with 21 years,....
FirstChildUserIdTAG: 196427
FirstChildUserNameTAG: Larrey
FirstChildCreateTimeTAG: 2013-02-23T19:54:17Z
FirstChildVoteTAG: 2
SecondChildTAG: if you allow them to stand side by side in the range 20 to 30 years, then there would be an equal distribution of people of all ages between 20 to 30. Suppose there were 10 boxes to stand side by side, then the 10 boses would be filled up by ages 20 to 29. And if there were 5 boxes, then each box would have 20/21, 22/23, 24/25, 26/27, 28/29
SecondChildUserIdTAG: 1094779
SecondChildUserNameTAG: NatarajaC
SecondChildCreateTimeTAG: 2013-02-24T17:21:28Z
SecondChildVoteTAG: 0
SecondChildTAG: equal distribution is that all the intervals are assumed to have equal number of objects. Ex: there is an interval 10 to 20 years of age with 20%and the other is 20 to 25 years of age with 40%.
Assumptions: all the interval have a difference of 1 unit
10-20 20-25
Width 10(10-11,11-12,12-13,13-14...19-20) 5
Each unit has 20/10=2% of people 40/5=8% in each interval.
Hope this helps
SecondChildUserIdTAG: 358255
SecondChildUserNameTAG: drnidhi27
SecondChildCreateTimeTAG: 2013-02-25T09:05:09Z
SecondChildVoteTAG: 0
FirstChildTAG: say u have a range of 30 to 50 with 'uniform distribution within it'. this means that if u further break up the range into four subset ranges of 30-35, 35-40, 40-45 & 45-50 then each will have a weight of 0.25% ie one fourth. say there are 60 people in the group 30-50, then it means that there are 15 people in each subset
FirstChildUserIdTAG: 390463
FirstChildUserNameTAG: DrPatilShrish
FirstChildCreateTimeTAG: 2013-02-24T18:23:15Z
FirstChildVoteTAG: 0
IndexTAG: 2604
TitleTAG: Oh you
Got caught in that probability/number trap in the very last exercise. Should check the pictures more carefully next time.
UserIdTAG: 907272
UserNameTAG: Fedor_Igntakin
CreateTimeTAG: 2013-02-23T19:26:17Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Me too! tricky one!
FirstChildUserIdTAG: 1081681
FirstChildUserNameTAG: Gabv105
FirstChildCreateTimeTAG: 2013-02-24T05:07:39Z
FirstChildVoteTAG: 0
FirstChildTAG: I did better! got me on the yes/no bargraph question...Seriously....I need to sleep!!!!!!!!!!!!!!!!!!!!!*Insomnia, if I tell you I m gonna miss you, will you go away?*
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-26T18:38:40Z
FirstChildVoteTAG: 0
IndexTAG: 2605
TitleTAG: More stat courses
I like this class. When will the other stats.2 and .3 run?
UserIdTAG: 901894
UserNameTAG: joansilver
CreateTimeTAG: 2013-02-23T19:10:01Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Soon after this one finishes.
FirstChildUserIdTAG: 1181029
FirstChildUserNameTAG: Ilya19
FirstChildCreateTimeTAG: 2013-02-23T22:37:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Ah yes ,I was wondering if that was what she meant ,I mean it was pretty clear but I wasnt sure ,so glad I decided to take this class .
SecondChildUserIdTAG: 20186
SecondChildUserNameTAG: vikashx1
SecondChildCreateTimeTAG: 2013-02-24T11:36:23Z
SecondChildVoteTAG: 0
IndexTAG: 2606
TitleTAG: Estimating percentiles using bins
I did not see any lectures on estimation of percentiles from the histograms. Did anyone get that?
UserIdTAG: 516121
UserNameTAG: cdesire
CreateTimeTAG: 2013-02-23T18:58:39Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Refer to the below link. At the bottom you will find a video under the header "Estimating Percentiles from Histograms". Each rectangle in the Histogram is called as bins. You can change the number of bins in the app & find the percentiles accordingly. Hope you are referring to that, if not I apologize for providing a wrong direction.
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#histograms
FirstChildUserIdTAG: 1214737
FirstChildUserNameTAG: Lipin
FirstChildCreateTimeTAG: 2013-02-23T19:13:32Z
FirstChildVoteTAG: 0
FirstChildTAG: That was in lecture 2.4, corresponding to slides in the 3 through the end of lecture. Prof A used some demonstration from the link that Lipin (above) supplied as well.
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-02-23T20:27:26Z
FirstChildVoteTAG: 0
IndexTAG: 2607
TitleTAG: Problem 3b
Does anyone notice something wrong with 3b? I'm not going to write anything more so as to not give away any solution.
UserIdTAG: 60581
UserNameTAG: ashah
CreateTimeTAG: 2013-02-23T18:54:12Z
VoteTAG: 33
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: I agree that there's probably a small problem with the correct histogram. But, you can still figure out the solution by exclusion. Two of the graphs are "more wrong", if you forgive the expression.
Can't really say anymore than this.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T19:00:50Z
FirstChildVoteTAG: 13
SecondChildTAG: I just got stuck on this excercice too. As for me the CORRECT answer DOESN'T match the data at all :/
SecondChildUserIdTAG: 581326
SecondChildUserNameTAG: tomekster
SecondChildCreateTimeTAG: 2013-02-23T19:52:11Z
SecondChildVoteTAG: 0
SecondChildTAG: to me everything is fine with the correct answer
SecondChildUserIdTAG: 1263818
SecondChildUserNameTAG: Ruteq
SecondChildCreateTimeTAG: 2013-02-23T20:22:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Yep; something is missing in the "correct" histogram.
SecondChildUserIdTAG: 734304
SecondChildUserNameTAG: sudinb
SecondChildCreateTimeTAG: 2013-02-23T20:45:13Z
SecondChildVoteTAG: 0
SecondChildTAG: I have this problem too. I still thinking that my answer is right and I couldn´t figure out how one of the other two could be the right answer :/
SecondChildUserIdTAG: 526713
SecondChildUserNameTAG: Miolan
SecondChildCreateTimeTAG: 2013-02-23T21:12:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I noticed that heights of the bars didn't match with my calculations. Beside that, there is only one graph that is correct. Look how y axis are identified.
SecondChildUserIdTAG: 1222641
SecondChildUserNameTAG: StBiljana
SecondChildCreateTimeTAG: 2013-02-23T22:55:27Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree, all seem to be wrong but one is the "better" among them
SecondChildUserIdTAG: 27536
SecondChildUserNameTAG: juanmd
SecondChildCreateTimeTAG: 2013-02-24T01:44:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree there is something wrong with the "correct" one. By my calculations, it almost seems as if two of the bars are swapped.
SecondChildUserIdTAG: 1117832
SecondChildUserNameTAG: Kindree
SecondChildCreateTimeTAG: 2013-02-24T01:51:12Z
SecondChildVoteTAG: 0
SecondChildTAG: I am worried! For me all the histograms are wrong!!! Help!
SecondChildUserIdTAG: 730908
SecondChildUserNameTAG: GabiNet
SecondChildCreateTimeTAG: 2013-02-24T11:42:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Not really. For y axis, consider 100%=1
SecondChildUserIdTAG: 382959
SecondChildUserNameTAG: RajdeepSingh
SecondChildCreateTimeTAG: 2013-02-24T12:50:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed a poor mc mmcs should have one correct answer
SecondChildUserIdTAG: 731309
SecondChildUserNameTAG: eesterbauer
SecondChildCreateTimeTAG: 2013-02-24T13:12:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Yup. None of the histograms are correct, but if you miss marking one you got the wrong answer. Not cool.
SecondChildUserIdTAG: 1264964
SecondChildUserNameTAG: ChaosCreator
SecondChildCreateTimeTAG: 2013-02-24T13:40:24Z
SecondChildVoteTAG: 0
SecondChildTAG: ChaosCreator: I agree with you!!!
SecondChildUserIdTAG: 730908
SecondChildUserNameTAG: GabiNet
SecondChildCreateTimeTAG: 2013-02-24T13:47:03Z
SecondChildVoteTAG: 0
SecondChildTAG: I can't figure out where I did wrong.
SecondChildUserIdTAG: 925684
SecondChildUserNameTAG: KamLoong
SecondChildCreateTimeTAG: 2013-02-24T15:06:05Z
SecondChildVoteTAG: 0
SecondChildTAG: To solve this problem with 3 incorrect answers by excluding the even wronger ones, you have to decide what is more important: the data or the terminology. Data: look at the numbers in the graphs and the axes, and only one diagram is representing the data correctly. Terminology: look at the labels of y-axes and recall the definitions of histogram vs. bar chart, and only one diagram is correcterv than the others.
Unfortunately, in my understanding, those choices are different ...
SecondChildUserIdTAG: 1174304
SecondChildUserNameTAG: ThomasHGMann
SecondChildCreateTimeTAG: 2013-02-24T15:10:19Z
SecondChildVoteTAG: 0
SecondChildTAG: i think that it's just a simulation for the true graph but not exact one
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-02-24T16:31:09Z
SecondChildVoteTAG: 0
SecondChildTAG: RajdeepSingh: what do you mean, could you explain?
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-02-24T16:33:49Z
SecondChildVoteTAG: 0
SecondChildTAG: There is a missing rectangle!
SecondChildUserIdTAG: 859273
SecondChildUserNameTAG: G66
SecondChildCreateTimeTAG: 2013-02-24T16:59:46Z
SecondChildVoteTAG: 0
SecondChildTAG: No, there is no rectangle missing.
The chart does not match the data.
SecondChildUserIdTAG: 911606
SecondChildUserNameTAG: ExpatKyle
SecondChildCreateTimeTAG: 2013-02-24T17:33:43Z
SecondChildVoteTAG: 0
SecondChildTAG: It does not match the data - I agree. This needs to be corrected by the course organizers
SecondChildUserIdTAG: 678202
SecondChildUserNameTAG: dperepolkin
SecondChildCreateTimeTAG: 2013-02-24T17:38:09Z
SecondChildVoteTAG: 0
SecondChildTAG: yup there is a problem
SecondChildUserIdTAG: 1239112
SecondChildUserNameTAG: Zawara
SecondChildCreateTimeTAG: 2013-02-24T19:39:04Z
SecondChildVoteTAG: 0
SecondChildTAG: The diagram type is correct, but the first two heights are wrong. The heights should be: 0.005 (0.55%), 0.023 (2.33%), 0.3 (30%) etc. For example, the second height should be (7% / (12-9 years) = 2.33% or 0.023
SecondChildUserIdTAG: 984829
SecondChildUserNameTAG: aishchenko
SecondChildCreateTimeTAG: 2013-02-24T20:24:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, there is a problem! I got it right because I knew 2 were definitely wrong, and this one was less wrong! But yes - there was a problem.
SecondChildUserIdTAG: 1302407
SecondChildUserNameTAG: HelenES
SecondChildCreateTimeTAG: 2013-02-25T03:45:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Your observation seems to be accurate. I was also confused. But by the process of elimination I could figure out the correct answer.
SecondChildUserIdTAG: 278932
SecondChildUserNameTAG: Rahulsv
SecondChildCreateTimeTAG: 2013-02-25T07:17:48Z
SecondChildVoteTAG: 0
SecondChildTAG: The data doesn't match...
SecondChildUserIdTAG: 250639
SecondChildUserNameTAG: taubau
SecondChildCreateTimeTAG: 2013-02-25T16:47:48Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree. Using the same equations which gives you the correct answer for 2a gives you heights for some bins which are inconsistent with all options.
SecondChildUserIdTAG: 1106281
SecondChildUserNameTAG: selinsky
SecondChildCreateTimeTAG: 2013-02-26T05:59:39Z
SecondChildVoteTAG: 0
SecondChildTAG: That was so frustrating. I drew the histogram, and non of them matched. Th " correct" one was missing something, but they all had something wrong. I stopped trusting myself.
SecondChildUserIdTAG: 1223461
SecondChildUserNameTAG: Mudtea
SecondChildCreateTimeTAG: 2013-02-26T08:10:16Z
SecondChildVoteTAG: 0
SecondChildTAG: The density units are incorrect.
SecondChildUserIdTAG: 459314
SecondChildUserNameTAG: SHarmony
SecondChildCreateTimeTAG: 2013-02-26T10:26:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Can anyone from staff please settle the confusion?
SecondChildUserIdTAG: 955096
SecondChildUserNameTAG: yoav_v
SecondChildCreateTimeTAG: 2013-02-27T06:56:42Z
SecondChildVoteTAG: 0
SecondChildTAG: definitely a problem....plz check Prof.Ani
SecondChildUserIdTAG: 1063817
SecondChildUserNameTAG: PriyankaChaman
SecondChildCreateTimeTAG: 2013-02-27T09:26:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Guys read how probability density is calculated and don't cry about a missing interval. You are giving the completely wrong answers and remarks. To calculate density you need to include the range of the interval in your calculations.And what if I decide to merge two intervals in my diagram or not to include for presentation purposes a very short pick in a very large data set. If my calculations are ok then the result won't have much difference. Try to recognize the most appropriate diagram that's what you asked to do. Try to understand not to calculate...
Better now?
SecondChildUserIdTAG: 1239975
SecondChildUserNameTAG: Xenofon
SecondChildCreateTimeTAG: 2013-03-05T02:08:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Basically it's not to scale right
SecondChildUserIdTAG: 838733
SecondChildUserNameTAG: Ronnicus
SecondChildCreateTimeTAG: 2013-03-10T01:37:51Z
SecondChildVoteTAG: 0
SecondChildTAG: whats wrong with 3 b ? @ashah
3 b is absolutely correct. Reread the question and understand it.
3 is darn easy one
PS: actually all problems are infantile ;)
SecondChildUserIdTAG: 450282
SecondChildUserNameTAG: Astute
SecondChildCreateTimeTAG: 2013-03-13T01:42:36Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, the heights of the bars are obviously incorrect. They should be:
0.0055; 0.023; 0.3 ; 0.087; 0.2; 0.024
SecondChildUserIdTAG: 1389686
SecondChildUserNameTAG: WaelRamadan
SecondChildCreateTimeTAG: 2013-03-20T19:47:46Z
SecondChildVoteTAG: 0
FirstChildTAG: The "wording" of Problem 3b: "Over age 65".... are we talking those who are age 66, or are we talking anyone age 65 or older?
FirstChildUserIdTAG: 910191
FirstChildUserNameTAG: MrMikeB
FirstChildCreateTimeTAG: 2013-02-23T20:34:24Z
FirstChildVoteTAG: 3
SecondChildTAG: 65 or older, based on the results.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-23T20:36:36Z
SecondChildVoteTAG: 0
SecondChildTAG: 65 or older
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-02-24T16:31:44Z
SecondChildVoteTAG: 0
SecondChildTAG: example: you have to be over 21 to drink. What does that mean? It means that after you have completed 21 years you are over 21.
SecondChildUserIdTAG: 1284382
SecondChildUserNameTAG: kite420
SecondChildCreateTimeTAG: 2013-02-25T03:17:59Z
SecondChildVoteTAG: 0
SecondChildTAG: About 65 and older. Senior citizenship starts at 65. You must include all cases falling within 65 years.
SecondChildUserIdTAG: 609816
SecondChildUserNameTAG: Oscar7000
SecondChildCreateTimeTAG: 2013-02-27T06:14:39Z
SecondChildVoteTAG: 0
SecondChildTAG: where is the exercise please??
SecondChildUserIdTAG: 1159679
SecondChildUserNameTAG: lamaamallah
SecondChildCreateTimeTAG: 2013-02-27T15:31:19Z
SecondChildVoteTAG: 0
SecondChildTAG: yes go look at some AARP broshures
SecondChildUserIdTAG: 838733
SecondChildUserNameTAG: Ronnicus
SecondChildCreateTimeTAG: 2013-03-10T01:38:38Z
SecondChildVoteTAG: 0
FirstChildTAG: Just take your time there is nothing rong with the answers
FirstChildUserIdTAG: 919347
FirstChildUserNameTAG: umareei
FirstChildCreateTimeTAG: 2013-03-02T09:43:13Z
FirstChildVoteTAG: 0
FirstChildTAG: I still don't understand this problem. I do understand that the correct histogram is correct because it is labelled 'density' on the y axis. However, I am absolutely at a loss at the height, and number, of bins. Please explain the histogram more completely.
FirstChildUserIdTAG: 986983
FirstChildUserNameTAG: Dianebefd
FirstChildCreateTimeTAG: 2013-03-06T20:51:03Z
FirstChildVoteTAG: 1
SecondChildTAG: Actually, no need. My teenage son just explained it to me. So, now I get it, although I feel a bit chagrined at the fact that my child knows more than I do. :) But, I knew that already. I stopped helping him with his math--oh, about when he was eleven.
SecondChildUserIdTAG: 986983
SecondChildUserNameTAG: Dianebefd
SecondChildCreateTimeTAG: 2013-03-07T12:42:35Z
SecondChildVoteTAG: 0
IndexTAG: 2608
TitleTAG: where the 14 and the 5 came out?
It's probably in those links, but i didn't get where this information is...
UserIdTAG: 77396
UserNameTAG: estheraraujo
CreateTimeTAG: 2013-02-23T18:54:03Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Look at the Table 3-4, and do exercise 3-6. The data you're looking for is there ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T19:06:21Z
FirstChildVoteTAG: 1
FirstChildTAG: open the 1st link then just type the end points into the boxes in the histogram tool you will get the area or the % then divide on the interval you will get the hight
FirstChildUserIdTAG: 907217
FirstChildUserNameTAG: somayyah
FirstChildCreateTimeTAG: 2013-02-23T20:35:07Z
FirstChildVoteTAG: 0
IndexTAG: 2609
TitleTAG: PROBLEM 3 and PROBLEM 4c
I´m waiting for the explanation of these questions, because I did them wrong and I don´t know why. Well, we have to wait until 28.
In general, I like the course and material given.
Agur (goodbye)
UserIdTAG: 1002821
UserNameTAG: Urimare
CreateTimeTAG: 2013-02-23T18:45:44Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Got 4c wrong too...I *think* I've figured out why, but it will be interesting to see the "official" explanation...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T19:09:02Z
FirstChildVoteTAG: 0
SecondChildTAG: I also got 4C wrong. But I was not sure what was the focus of the question. In the lecture we heard that you could assume that the distribution in each interval was even. But that was a choice. We didnt learn the tools to know how much error are we assuming.
SecondChildUserIdTAG: 1222835
SecondChildUserNameTAG: CatonElMenor
SecondChildCreateTimeTAG: 2013-02-24T23:11:26Z
SecondChildVoteTAG: 0
FirstChildTAG: There's no correct answer listed in problem 3. The data are wrong.
As to problem 4c, let's think about this. Most of us would take our entire middle schools, high schools and even colleges. Few of us chose to drop out.
Hope it's helpful to you.
FirstChildUserIdTAG: 724149
FirstChildUserNameTAG: BillZhao
FirstChildCreateTimeTAG: 2013-02-24T01:55:55Z
FirstChildVoteTAG: 1
SecondChildTAG: With yours explanation, I figured out one of them. Thanks
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-02-24T10:35:45Z
SecondChildVoteTAG: 0
IndexTAG: 2610
TitleTAG: Where to find the lecture notes and videos?
i am unable to find the videos of the course.Can anyone please help me out?
UserIdTAG: 1264910
UserNameTAG: Fahadnaeem
CreateTimeTAG: 2013-02-23T18:24:47Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: There you go: http://statistics.berkeley.edu/~stark/SticiGuiText/histograms.htm#variables
FirstChildUserIdTAG: 896931
FirstChildUserNameTAG: tomsanchez
FirstChildCreateTimeTAG: 2013-02-23T18:49:30Z
FirstChildVoteTAG: 0
SecondChildTAG: these are not the course videos!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-23T22:01:32Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm afraid this link is dead, error message. Any other suggestions?
SecondChildUserIdTAG: 990364
SecondChildUserNameTAG: Oksana1511
SecondChildCreateTimeTAG: 2013-02-26T22:38:22Z
SecondChildVoteTAG: 0
FirstChildTAG: > i am unable to find the videos of the course.Can anyone please help me out?
Go to the Courseware tab
![enter image description here][1]
The arrows indicate the lecture sequences, the blue alarm clocks indicate graded exercises.
![enter image description here][2]
The lectures are shown by icons on the film strip.
![enter image description here][3]
[1]: https://edxuploads.s3.amazonaws.com/13616572171343614.png
[2]: https://edxuploads.s3.amazonaws.com/13616573321343672.png
[3]: https://edxuploads.s3.amazonaws.com/13616573688474444.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:09:42Z
FirstChildVoteTAG: 1
IndexTAG: 2611
TitleTAG: exercise set 2 problem 3
if one looks at the numbers, the histogram height looks wrong.
UserIdTAG: 1262111
UserNameTAG: konx
CreateTimeTAG: 2013-02-23T17:58:53Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Whats wrong - it is right.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T18:03:36Z
FirstChildVoteTAG: 0
SecondChildTAG: In my opinion histograms given didn´t match data
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-02-23T18:11:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Incidentally are you talking about bar charts or HistogramsIn exercise 1Set 1 there are bar charts - Not histograms !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T18:19:12Z
SecondChildVoteTAG: 0
FirstChildTAG: The area of the bars should represent the percentage.
Hence, the area of 12-13 (30%) should be about 4 times as large as 9-12 (7%) and 6 times as large as 0-9 (5%)
Looking at the "correct" histogram, however, it rather appears that 12-13 is about as large as 9-12 and 0-9. Hence, the correct answer should be "all histograms are wrong"
FirstChildUserIdTAG: 388844
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FirstChildCreateTimeTAG: 2013-02-24T21:37:29Z
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IndexTAG: 2612
TitleTAG: confusing
i understand the classification of variables, quantitative, qualitative, etc.. but sometimes it's confusing.. could anyone here explain to me the easiest way to differentiate the four kinds? thanks..
UserIdTAG: 1231135
UserNameTAG: shie112709
CreateTimeTAG: 2013-02-23T17:57:10Z
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: This is my modest attempt at explaining it.I hope it helps
[variables and beauty ;)][1] Click on the link to see the question and I ahve made an attempt to explain it.
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/51289310112b09480900006a
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
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IndexTAG: 2613
TitleTAG: how to fill in answers??
Hi,
Do we need to include "%" sign while filling the answers. As I did that for Exercise 2-problem 7.I got wrong answer for first attempt. So I rechecked my calculation. I think its correct.I do not want to attempt second submission before i get clarity on this.
Please help!!
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UserNameTAG: Abhipuri
CreateTimeTAG: 2013-02-23T17:53:37Z
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Do not use % sign.Round off answers to the first decimal as per rounding off rules to the right.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T17:58:43Z
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SecondChildTAG: thanks!!
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SecondChildUserNameTAG: Abhipuri
SecondChildCreateTimeTAG: 2013-02-23T18:05:13Z
SecondChildVoteTAG: 0
IndexTAG: 2614
TitleTAG: Average ES Scores Till ES3
After solving all those percentiles, I am quite excited to know my percentile. I am excited to know how well I'm doing. I know not all are interested to share their scores. But all those interested buddies, let's share here (I guess it is not violating any EDX codes). Mine is 80%, 95% and 100% for three sets. so my avg ES score is 28%.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-23T17:42:05Z
VoteTAG: 1
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 2
FirstChildTAG: Braggart :-)
I was confounded by many of the ways to input responses so not so well I'm afraid. But I'll get the hang of it soon, especially now that we have downloadable materials.
70,35,100
Mean 68.33333333
Standard Error 18.78237945
Median 70
Mode #N/A
Standard Deviation 32.53203549
Sample Variance 1058.333333
Kurtosis #DIV/0!
Skewness -0.229936887
Range 65
Minimum 35
Maximum 100
Sum 205
Count 3
Largest(1) 100
Smallest(1) 35
Confidence Level(95.0%) 80.81405621
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-02-23T20:34:59Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, show off but posted as anonymous...lol.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T20:43:00Z
SecondChildVoteTAG: 0
SecondChildTAG: don't use Excel. It will give you the incorrect results
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SecondChildUserNameTAG: pedrocas1972
SecondChildCreateTimeTAG: 2013-02-23T23:41:26Z
SecondChildVoteTAG: 0
SecondChildTAG: with R, I get:
* kurtosis: -2.333333
* skewness: -0.05109709
===
Even with software you need to understand the stuff. There are many subtleties. I'm a novice, but just before this course I begin to take a look to R, and I found things like these:
R provides different algorithms to calculate quantiles. I don't know what they do, but there are 10 of them! :O
Other example, R has a `summary()` function that gives 6 nums for your sample, 1st quart. and 3rd quart. among them. But there is also a `fivenum()` function that gives *hinges* instead of quartiles. For your sample hinges and quartiles are the same, but they can differ in other cases.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-24T00:24:33Z
SecondChildVoteTAG: 0
SecondChildTAG: So did you get >90 atopos? :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-24T10:12:10Z
SecondChildVoteTAG: 0
SecondChildTAG: I got it, really unexpectedly, in 6.00x :) Not as high as you, btw.
Here, I've failed a bit in the first two Ex.Sets. A simple typo or a lazy answer with only one available attempt has sometimes nightmarish consequences in the form of that creepy big red X ;-) Anxiety grows thinking about what could happen if some server crash (remember!) makes its day in between of an only-one-try-available problem.
I wanted to work a bit on R, what better excuse than this course! It's fun!
But, hey, jim, you know that Python can also do all of this. So I'm sure you got that 90+.
I made myself a little function yesterday, tired of doing again and again the same hand calculations:
def percentile_from_hist(n, hist):
"""
n: a num
hist: a list a tuples in the form
(interval, percentage)
where an interval is itself
a tuple (num, num)
returns: the n-th percentile for hist
"""
I was thinking in posting it here or in the wiki, but I've decided that it would be an HC violation.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-24T14:29:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Nice, stuff! Good to know that all those restless hours of coding in 6.00x paid off!
Why didn't I think of that? I used Excel....dooohhhh!
I hate to show off, but every now and then its OK..to motivate fellow students.
Yes, I got 100 on this week's exercise.
Don't be intimidated with the low submissions, read the question carefully and don't answer until you are 100% certain. Review the lectures, search in Google and these forums to get a better understanding.
How is R anyway? I took the CS169.1x SaaS course which taught Ruby on Rails. Ruby is like Python but very 'loose' in syntax.
Although I scored 100%, I will never use that program because it is more for web application and if you actually work in that industry (which I don't). It was enlightening, though.
I am taking CS188.1x Artificial Intelligence now. This one is full on Python and a lot of fun. Week 2 material was released yesterday but I finished it in 8 hours...lol...had nothing else to do. :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-24T21:14:51Z
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SecondChildTAG: I was writing more little functions, but, actually, I'm trying just now to implement a TableDist class (and a Bin class) to merge some common stuff and avoid repetitions. Only for fun during weekend!
Well, R is very peculiar. I cannot answer with confidence, because I have only a minimal exposure and, at this moment, I'm approaching to the language only as a statistical tool (understanding typical data structures and functions), not to the language itself.
If you remember numpy, R has some similarities. Vectors are the fundamental data structure, all operations are vectorized, and over vectors is built probably the more characteristic and useful R data structure: the data.frame, a multidimensional vector suitable for the typical tabular data handled by statisticians. Functions are very flexible with a lot of optional arguments. There are a lot of libraries for whatever statistics you can imagine, written by statisticians.
R is something like a specialized language, though it's a general purpose language as well. However I don't know whether it's at the level of other general purpose languages, even interpreted languages, in terms of efficiency.
As side comments: I've found some typical Unix smell, and the built-in help is very good.
Ha! Your scores keep being, as I guessed, terrific ;-)
I miss the AI course. To be honest, I'm sure that I would not be able to cope with its pace, given my typical time constraints.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-24T23:26:41Z
SecondChildVoteTAG: 0
SecondChildTAG: > Don't be intimidated with the low submissions, read the question
> **carefully** and **don't answer until you are 100% certain**
I forget that. It's a lost battle for me, character is destiny. I always behave badly in quizzes.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-24T23:48:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Your function definition inspired me to complete it - and in the process I realized how I'd be curious to see your program, and compare it to my own, after the due date!
I'm actually doing 6.00x again just to get the Psets we missed last time. I ended up getting pretty lost in the last third of the course once the finger Exercises petered out.
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SecondChildUserNameTAG: Lasker
SecondChildCreateTimeTAG: 2013-02-27T04:34:53Z
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SecondChildTAG: Ok, I'll post it the function after the due date.
The third part of 6.00x was a bit hard. I expected that. Graph algorithms and dynamic programming are not, by no means, easy material. Good luck with you second try in that excellent course!
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-27T08:43:34Z
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SecondChildTAG: The due date has passed. So this is my function. It's actually a method of a `DistributionTable` class. This class is an aggregation class: a list of objects of the class `Bin`. You cannot execute the method "as-is", but I'm sure you can understand it or implement yourself the class `Bin`. Instance attributes of `Bin` are self-explaining.
Note that, for brevity, I named `frequency` the relative frequency or proportion of a bin.
Yeah, I don't use getters, I prefer simple fields in Python.
You might find weird the trailing underscore in the name variable `bin_`. It's a Python convention to add this underscore when a variable name is the same as a Python name, and that's the case here, because `bin` is a the name of a built-in Python function.
My function assumes the interval convention of the exercises: the interval (a, b) is taken as a the interval [a, b).
Beware! I haven't tested the function thoroughly neither coded any exception mechanism. Error reports are welcomed.
def percentile(self, n):
"""
compute the n-th percentile of the distribution table
"""
total_freq = 0
total_width = 0
for bin_ in self.bins:
bin_width = bin_.calc_width()
bin_freq = bin_.frequency
prev_total_freq = total_freq
total_freq += bin_freq
# n is the end of this bin
if n == total_freq:
return total_width + bin_width
# n is within the base of this bin
elif n < total_freq:
offset_freq = n - prev_total_freq
percentile = total_width + \
(offset_freq / bin_freq) * bin_width
return percentile
else:
total_width += bin_width
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-01T00:47:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for sharing - the basic idea behind our functions seems to be the same, although yours is much more useful since it is embedded within a larger class. I had not appreciated until seeing this example the degree to which classes, with their named attributes could contribute to readability as well - referencing tuples within tuples within lists by element is far from ideal!
Here is mine for comparison:
def percentile_from_hist(n, hist, accuracy=0):
"""
n: a num
hist: a list a tuples in the form
(interval, percentage)
where an interval is itself
a tuple (num, num)
accuracy: an int giving the number of
digits desired after the
decimal point
assumes normal distribution within bins
returns: the n-th percentile for hist
"""
percentile = 0
for bin in range(len(hist)):
if percentile + hist[bin][1] <= n:
percentile += hist[bin][1]
else:
percentLeft = n - percentile
#what percentage of this bin we need
ratio = float(percentLeft)/hist[bin][1]
#take that percentage of the values
toAdd = ratio * (hist[bin][0][1]-hist[bin][0][0])
#and add them to the starting value of the bin
return (round(hist[bin][0][0] + toAdd, accuracy))
SecondChildUserIdTAG: 529507
SecondChildUserNameTAG: Lasker
SecondChildCreateTimeTAG: 2013-03-01T02:59:51Z
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SecondChildTAG: Thanks!
Functions instead of methods are perfectly fine. You can get the same readability if you use variables. For example:
bin_percentage = hist[bin][1]
The minimal advantage of using classes here is that you can reuse some code for other possible functions you want to create, and, in my case, just for the sake of refreshing my Python skill after 6.00x ;-)
BTW. I think that 'percentage' (or proportion) is a better name than my name 'frequency'. frequency (or relative_frequency) seems to me now somewhat misleading in this function.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-03-01T21:27:10Z
SecondChildVoteTAG: 0
FirstChildTAG: I would hope that a statistics course would provide the statistics of the grades. But of course, they can't give us the first rankings until the first grading period closes.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T04:13:19Z
FirstChildVoteTAG: 0
IndexTAG: 2615
TitleTAG: Question about Lecture 1.2
Hi:
Lecture 1.2 starts at variables and moves on to data etc.
The associated videos are nearly 1 hr or more. Do we have
to go through all the materials in sticGui for this lecture?
Thanks & regards
sharma
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UserNameTAG: ssharma123
CreateTimeTAG: 2013-02-23T17:41:41Z
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CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: No the total video is an hour or so but the actual portion is a few minutes- click and see !!
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T17:52:04Z
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FirstChildTAG: Lecture 1.2 is 7.39 minutes long, and is found on the courseware Introduction page. The lectures embedded in the text are from Statistics21 - a Berkeley course. I'm sure you would benefit from watching them, but they are not part of this course (unless told otherwise).
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13616566951343662.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:59:20Z
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FirstChildTAG: Thanks Prasanna & Susan. I figured that out a little later after I posted. Appreciate it.
-Sharma
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FirstChildUserNameTAG: ssharma123
FirstChildCreateTimeTAG: 2013-02-23T23:14:17Z
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IndexTAG: 2616
TitleTAG: Too close
Problem 2a of Exercise Set 1 is a little deceptive.
Since the vertical axis is labelled with an interval of 50, it's a little difficult to draw the line between 290 and 270.
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CreateTimeTAG: 2013-02-23T17:39:47Z
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Do you mean Problem 3a? If so, I too had this issue.
FirstChildUserIdTAG: 1109996
FirstChildUserNameTAG: ARober
FirstChildCreateTimeTAG: 2013-02-23T17:45:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Same here for 3a - it looks good to me!
FirstChildUserIdTAG: 244776
FirstChildUserNameTAG: Artsy4ever
FirstChildCreateTimeTAG: 2013-02-23T21:13:32Z
FirstChildVoteTAG: 0
FirstChildTAG: If you mean 3a, then you did to think more about the question.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:54:14Z
FirstChildVoteTAG: 0
FirstChildTAG: > Problem 3
Suppose another 20 green/green plants are introduced into the experiment above, so that there are now 500 plants in all.
I totally missed that part. Was wondering where the 500 came from. Oops.
FirstChildUserIdTAG: 150589
FirstChildUserNameTAG: TriciaC
FirstChildCreateTimeTAG: 2013-02-24T13:47:17Z
FirstChildVoteTAG: 0
IndexTAG: 2617
TitleTAG: Histogram?
I would have represented the income groups in a pie chart, not as a histogram. Would that be wrong?
UserIdTAG: 682892
UserNameTAG: FMA-Austria
CreateTimeTAG: 2013-02-23T17:34:08Z
VoteTAG: 1
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 6
FirstChildTAG: That is a different method of representation.Pictorial representation are of different types and the Histogram has got its own advantages.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T18:00:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Probably not, but the section is on Histograms...
I'm sure when we get to pie charts, the example will pop out again ;)
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FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T18:01:22Z
FirstChildVoteTAG: 0
FirstChildTAG: AFAIK pie charts are currently disregarded in favour of bar charts for categorical/qualitative data. Histograms are excellent for quantitative data because they present clearly at a glance the distribution and its properties (shape, central tendency, dispersion).
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-23T18:19:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Pie charts ahve their won representation advantages.Incidentally Florence Nightingale (The famous nurse)depicted the first popular pie charts in relation to war injuries and deaths during the Crimean war (Playfair described it first)!!
the reson Pie charts seem to be deprecated by statisticians(though popular with the media) as comparision by angles is poorer visually compare to length.
Karl Pearson introduced the Histogram.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T18:29:10Z
SecondChildVoteTAG: 0
SecondChildTAG: ps ahve should read as have and won as own !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T18:30:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Pie charts have their uses, but are pretty much despised in statistical circles. Used properly, they are effective tools. But not many use them properly, and too many just use the default Excel pie.
Florence Nightingale adapted the Pie chart to her famous Rose type chart. Same, but different.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:50:17Z
FirstChildVoteTAG: 1
SecondChildTAG: Actually the rose chart is a modified pie chart called the "Multistep pie chart"
![Florence nightingales "Rose" pie chart][1]
[1]: http://leadinganswers.typepad.com/.a/6a00d834527c1469e20128768d0a6f970c-500wi
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T04:51:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, adapted from a pie chart.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-24T07:52:10Z
SecondChildVoteTAG: 0
SecondChildTAG: I had never seen this type of diagramming circular, with which computer programs can be made please
SecondChildUserIdTAG: 1100404
SecondChildUserNameTAG: marielmpg
SecondChildCreateTimeTAG: 2013-02-24T10:50:07Z
SecondChildVoteTAG: 0
FirstChildTAG: not wrong, it's just that a histogram is one of the first graph types one learns when first taking statistics.
people generally like to walk before they run, and histograms in the beginning is just the convention, at least in the many examples of statistics courses I've come across.
maybe it was different when you took statistics.
FirstChildUserIdTAG: 609485
FirstChildUserNameTAG: Shokodemon
FirstChildCreateTimeTAG: 2013-02-24T08:53:17Z
FirstChildVoteTAG: 0
FirstChildTAG: can some one explain how to apply the endpoint rule to calculate the exact number of items in a particular interval. for example if they say how many people earned exactly 2000 in the intervals 0-2000 and 2000-3000
FirstChildUserIdTAG: 402350
FirstChildUserNameTAG: DUNEER
FirstChildCreateTimeTAG: 2013-02-27T01:15:00Z
FirstChildVoteTAG: 0
SecondChildTAG: You have two intervals [0,2000) and [2000,3000). Based on the end point assumption, people earning 2000 is the second interval. How many people in that interval earn that quantity? If you assume, but only if you assume, a thoroughly uniform distribution in that interval (something unrealistic, btw) you could then begin to do computations as simple ratios.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-27T08:39:47Z
SecondChildVoteTAG: 0
IndexTAG: 2618
TitleTAG: Wrong Answer
Why I am getting 2a wrong - the answer is 19% .19 or .2 rounded.
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UserNameTAG: dfer
CreateTimeTAG: 2013-02-23T17:30:26Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: We shouldn't discuss answers as long as the Honor Code is holding.
But in your case, I think it can safely be said that you should **not** put the % symbol in the answer, or convert to 0.xx. **For exercise 2a**, treat the percent value as a 0-100 number, with 2 decimal places.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T18:11:10Z
FirstChildVoteTAG: 0
FirstChildTAG: As an additional note, perhaps it's a European thing, but when I'm asked for a "fraction" i assume the answer should be represented as numerator over denominator.
I note some questions ask for a decimal fraction, which is more helpful as it indicates the acceptable form of the answer to me.
Perhaps you could consider making this more consistent to at least give us a clue as to the appropriate representation for answers, please? There's little more frustrating than having the right answer but battling the computer since it's opinion as to representation is different to the student's.
Thanks :)
FirstChildUserIdTAG: 81246
FirstChildUserNameTAG: bigbro
FirstChildCreateTimeTAG: 2013-02-23T21:19:08Z
FirstChildVoteTAG: 0
IndexTAG: 2619
TitleTAG: Round to 1 decimal only Problem 1 c?....
Why not 1 A and 1 B?
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-23T17:28:05Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: If you mean for Exercise Set 3: it applies to 1a and 1b too.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T18:13:54Z
FirstChildVoteTAG: 0
FirstChildTAG: I worked these off line (made copy in WORD) and in that way I could read and think about all the information provided. I worked P1, c first which was to one decimal place and then just naturally did the others (a,b)the same way. Got those all correct in that manner
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-02-23T19:25:24Z
FirstChildVoteTAG: 0
SecondChildTAG: I found it useful to make an Excel table. I computed the cumulative percentages for each range. According to my table, the answer to part c should be between 45 (60%) and 60 (80.9%). I used the formulas in slide 7 for Lecture 2.4 and got a and b right but c wrong. My wrong answer for the upper quartile was found using 45 + (60-45)/20.9 * (75-60) = 55.8. Anybody has a hint on why the answer is wrong?
SecondChildUserIdTAG: 152379
SecondChildUserNameTAG: icastes
SecondChildCreateTimeTAG: 2013-02-24T14:38:11Z
SecondChildVoteTAG: 0
SecondChildTAG: You are making two mistakes in your calculation bro.Do you have one good reason to justify the numerator of 20.9? How come its (60-45)? And when the left most number in your calculation is 45, how come the right most be (75-60).
P.S. Although 75-60 wouldn't affect your answer, its logically incorrect
SecondChildUserIdTAG: 31529
SecondChildUserNameTAG: abbass
SecondChildCreateTimeTAG: 2013-02-24T15:45:02Z
SecondChildVoteTAG: 0
SecondChildTAG: Got it. Thank you very much.
SecondChildUserIdTAG: 152379
SecondChildUserNameTAG: icastes
SecondChildCreateTimeTAG: 2013-02-25T00:37:08Z
SecondChildVoteTAG: 0
IndexTAG: 2620
TitleTAG: Endpoint convention - Exclusive and Inclusive class intervals
I was really intrigued by the endpoint convention and did a bit of reading about it and thought I would share with the members and also could the Professors also comment further especially if I have made any errors.
Basically there are two types of class interval definitions
They are
1. Inclusive
2. Exclusive
3. Open ended
class intervals.
Inclusive class intervals are where there is no overlap for eg 0-9,10-19 etc when discrete variables are used and hence the "jump" is discrete so there would be no problem in relation to continuity.I think that in medical statistics we use this because we have a limit to the precision of any measurement so setting the "jump" less than the measurement limit automatically ensures that the measurements "appear" contiguous in calculations etc.
Exclusive intervals are those in which one limit (typically the lower limit in left endpoint convention )is included and the upper limit is excluded for eg 0-10,10-20 and so on and so forth. So when dealing with a continuous variate an exclusive class interval may be used.
Conversion of an inclusive to an exclusive class interval is typically done by extending the class intervals at both ends to overlap for eg 0-9.5,9.5-19.5 and so on and so forth.
Open ended intervals are one wherein the lower or upper limit is "open" ie are missing for eg less than 5,5-10.......20 and more or less than 5,6-10,11-20,more than 20 These are open ended and have a limit at infinity.usually for ease of compuatation such series 9if the remaining mumbers are small) ae made the same as the other class intervals and as described in the problems a mention is made that all values above the upperpoint are clubbed in the defined class interval.
This is one such reference
[Google book reference][1]
Hope this helps and I would appreciate comments from the Professors so that we could gain more insight.
It is so fantastic that things we take for granted are challenged when we formally study !!
[1]: http://books.google.co.in/books?id=tWmoP49v1cIC&pg=PA26&lpg=PA26&dq=inclusive%20and%20exclusive%20class%20intervals%20in%20statistics&source=bl&ots=29DDcQ_6hK&sig=aBd7oup8iWBZnseIXfdv8vX2gDo&hl=en&sa=X&ei=8_YoUa-sM4iyrAeek4CwCQ&sqi=2&ved=0CG4Q6AEwCQ#v=onepage&q=inclusive%20and%20exclusive%20class%20intervals%20in%20statistics&f=false
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-23T17:22:06Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2621
TitleTAG: Quiz 1 answer
Hello,when and where the answers of this exercise will get?
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UserNameTAG: kirtisundar
CreateTimeTAG: 2013-02-23T17:08:03Z
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CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The Due Data has been moved to the end of February 27. After that we'll get the answers and explanations ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T18:15:35Z
FirstChildVoteTAG: 0
FirstChildTAG: This is detailed in the course policies document.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:20:42Z
FirstChildVoteTAG: 0
IndexTAG: 2622
TitleTAG: problem1
does anybody get the correct answer in 1a and 1b?
I think that my method is ok because i find the correct answer in 1c, but i dont know in 1a and 1b.
UserIdTAG: 1134470
UserNameTAG: cpaula
CreateTimeTAG: 2013-02-23T16:56:30Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Please do not post /reveal answers as it will break the Honor Code.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T17:48:25Z
FirstChildVoteTAG: 0
SecondChildTAG: I do not want to know the answer. I only want to know if anybody knows it. I think that this do not break the honor code.
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-02-23T17:52:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Well I got it right if it helps !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T18:04:03Z
SecondChildVoteTAG: 0
SecondChildTAG: ya i got the right answers for 1A and 1B.
SecondChildUserIdTAG: 85891
SecondChildUserNameTAG: rajivverma88
SecondChildCreateTimeTAG: 2013-02-23T18:29:24Z
SecondChildVoteTAG: 0
SecondChildTAG: **"You can assume that the ages are uniformly distributed within each interval."**
That is the key if you still have some problems.
SecondChildUserIdTAG: 16448
SecondChildUserNameTAG: Arttu
SecondChildCreateTimeTAG: 2013-02-23T19:20:27Z
SecondChildVoteTAG: 0
SecondChildTAG: I do the same in 1a and 1c, but I have the answer correct in 1c but not in 1a. I have to think about it.
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-02-23T20:54:49Z
SecondChildVoteTAG: 0
SecondChildTAG: yes assume uniformly distributed
SecondChildUserIdTAG: 1245055
SecondChildUserNameTAG: newstat
SecondChildCreateTimeTAG: 2013-02-24T01:00:27Z
SecondChildVoteTAG: 0
SecondChildTAG: don't round off the answers in a and b, give your answer up to two decimal points
SecondChildUserIdTAG: 330656
SecondChildUserNameTAG: docpriti
SecondChildCreateTimeTAG: 2013-02-24T08:55:22Z
SecondChildVoteTAG: 0
FirstChildTAG: what does it mean each column in problem numer two? maybe the first one is the number of scores and the second one how many times this score has been reached? thanks
FirstChildUserIdTAG: 56238
FirstChildUserNameTAG: pablomp92
FirstChildCreateTimeTAG: 2013-02-24T21:53:41Z
FirstChildVoteTAG: 0
IndexTAG: 2623
TitleTAG: Problem 2 (B)
when we count people 75+ should we include those, who are 100 (so, that will be 26 of them)?
UserIdTAG: 1133964
UserNameTAG: Catherine93
CreateTimeTAG: 2013-02-23T16:50:19Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Without breaking the honor code, I think I can safely quote part of the exercise text for emphasis:
> the number of people aged 100 or more was not zero but it was so small that it makes no difference to the table
Also, in case you didn't follow the discussions, it should be safe to warn you that the text of the problem is actually misleading. "person over the age of 65" is actually supposed to read "person who is 65 and over".
Good luck!
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T19:17:45Z
FirstChildVoteTAG: 1
SecondChildTAG: Yup. I got it wrong the first time because it said "over the age of 65", so I didn't count those who were 65...
SecondChildUserIdTAG: 230828
SecondChildUserNameTAG: alanis
SecondChildCreateTimeTAG: 2013-02-23T23:08:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Isn't it wrong to count the people @ the age of 65 based on the question format ?I got the answer wrong (may be because I didn't count 65 not sure) but I am curious.
SecondChildUserIdTAG: 1214737
SecondChildUserNameTAG: Lipin
SecondChildCreateTimeTAG: 2013-02-24T18:12:22Z
SecondChildVoteTAG: 0
IndexTAG: 2624
TitleTAG: Faulty answer checking
First I entered 11.1% = wrong
Then I answered .111111111 = wrong
Then, 11.111111111111% = wrong
Finally I check, 11.1 (no percent sign) is the only way this software will accept the answer. This needs to be addressed for more accurate grading.
UserIdTAG: 931308
UserNameTAG: bwilhite
CreateTimeTAG: 2013-02-23T16:29:17Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: Has anyone found guidance in any of the course material about the level of accuracy required in answers? 11 is an incorrect answer and 11.11111... is over the top. Do we infer that one decimal accuracy fits in all answers?
FirstChildUserIdTAG: 398274
FirstChildUserNameTAG: aremh
FirstChildCreateTimeTAG: 2013-02-23T17:40:30Z
FirstChildVoteTAG: 1
SecondChildTAG: i face the same problem...
its weird...
SecondChildUserIdTAG: 1239112
SecondChildUserNameTAG: Zawara
SecondChildCreateTimeTAG: 2013-02-23T17:57:27Z
SecondChildVoteTAG: 0
SecondChildTAG: One decimal point works and also do not ad dpercentage sign
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T18:04:28Z
SecondChildVoteTAG: 0
SecondChildTAG: I think is unfair and potencially dangerous the fact that you can´t be sure if the number of decimals that you write is good enough for an answer.
If things stay that way, we´re gonna have serious problems in the activities...
SecondChildUserIdTAG: 376173
SecondChildUserNameTAG: nacho110987
SecondChildCreateTimeTAG: 2013-02-23T18:29:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Please search the forums before posting (or at least look at the discussions on the page) - this issue has been brought up dozens (if not hundreds) of times, including at least 6 times in the first page of discussions for this exercise.
The staff are aware of it and have addressed the issue.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T18:35:15Z
FirstChildVoteTAG: 1
FirstChildTAG: Okey, The Rules of entering answers ARE TO BE TOLD BEFORE!!!!
FirstChildUserIdTAG: 1103272
FirstChildUserNameTAG: Soroka1
FirstChildCreateTimeTAG: 2013-02-23T20:41:27Z
FirstChildVoteTAG: 0
SecondChildTAG: And you should search the discussion forums before, as this is a known issue which hopefully will be rectified for future lectures.
Also, please read the discussion forum guidelines, specifically the section about netiquette.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T21:31:29Z
SecondChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:21:11Z
FirstChildVoteTAG: 0
IndexTAG: 2625
TitleTAG: endpoints
Would it not be more sensible just to avoid overlapping endpoints and have the values be 10-24 and 25-49? In what situation would this be unavoidable or what's the advantage to having these overlapping numbers?
UserIdTAG: 1151964
UserNameTAG: jspeterson
CreateTimeTAG: 2013-02-23T16:12:06Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 3
FirstChildTAG: But where would you put numbers between 24 and 25 then? :)
FirstChildUserIdTAG: 1196355
FirstChildUserNameTAG: EmilyEly87
FirstChildCreateTimeTAG: 2013-02-23T16:23:00Z
FirstChildVoteTAG: 0
SecondChildTAG: We discussed this already and you can see with the search function.(It all depends on the end point convention defined. Nonoverlap can be used if you use the appropriate level of precision but the endpoint convention statement with overlap is one way to remove the ambiguity. (I don't like it but then well I believe statisticians like it ;) In some medical statistics courses it is considered an anathema to overlap (using the precision of measurement as the index of nonoverlap) but then here it is considered OK provided the endpoint convention is defined as histogram smoothness is ensured)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T16:32:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Here is the conversation where Prof Adhikari gives a clarification
[End point convention discussion][1]
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/51267233e32777220000006c
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T16:34:25Z
FirstChildVoteTAG: 1
FirstChildTAG: I have added a little note related to a bit of reading that I did on this and this may be helpful
[endpoints of class intervals][1]
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/Stat2_1x_Exercise_Set_1/threads/5128fabe0853312b00000029
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T17:50:47Z
FirstChildVoteTAG: 0
IndexTAG: 2626
TitleTAG: To allow "check" in answers instead of a final submission ..
Hello Professor,
It might help to allow "check" in all answers instead of just one final submission for the exercises.
The one final submission could be used for the exams instead of the weekly assignments (as is the case in all other EdX courses).
Could you please consider?
UserIdTAG: 65480
UserNameTAG: Ansh04
CreateTimeTAG: 2013-02-23T16:03:25Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: To be honest, I like this system.
It better resembles *real* graded homework and exercises from a classroom course, since when you do those, you don't really have the luxury of taking them back and correct your answer if the professor finds it wrong ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T19:22:24Z
FirstChildVoteTAG: 1
SecondChildTAG: I agree with you on this matter. Graded exercises are not meant to be 'easy' as they are to test your understanding, logic and reasoning. You have the practice/finger exercises for practicing.
The fact that the graded tests are all open book with days for the deadline should suffice. If you are not sure of the answer and there are only 1-2 chances to submit, then don't guess. Go back to the lectures, search the internet or text books.
We are only in week 1 and the material is really basic and still relatively easy so make sure you grasp the fundamentals properly otherwise you will struggle in the coming weeks. Just my 2 cents.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T21:12:39Z
SecondChildVoteTAG: 0
FirstChildTAG: The Prof has already responded to this.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5125aceb9914d22b0000019d
> The one final submission could be used for the exams instead of the weekly assignments (as is the case in all other EdX courses).
Actually, not *all*. I have done courses where (very) limited checks are given. This is supposed to be some form of assessment.
Some courses do give you unlimited checks in graded assessments. But the ones I have seen involve programming or complicated maths.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:17:31Z
FirstChildVoteTAG: 1
IndexTAG: 2627
TitleTAG: Problem 4 and 1 Ex. Set 3
The problem 4 says-
> When drawn on the same scale, the histogram for one of them has a noticeably higher peak the histogram for the other.
I cannot understand the basis of the construction of the histogram. Please assist me a bit to clarify the formation of this Histogram.
Also I wanted to know about problem 1. I followed all the things taught in lecture and applied it but unfortunately didn't got the exact answer. Please provide a pathway to proceed in the question or for any guidance towards the problem.
UserIdTAG: 18215
UserNameTAG: mhr201
CreateTimeTAG: 2013-02-23T15:47:41Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I got it wrong, so I thought a little about it and I think it is quite simple actually.... Just need to look at which experiment has highest maximum value measured (the line above the box) and that one will have highest peak if you represent it with histogram...
FirstChildUserIdTAG: 1196355
FirstChildUserNameTAG: EmilyEly87
FirstChildCreateTimeTAG: 2013-02-23T16:21:26Z
FirstChildVoteTAG: 0
SecondChildTAG: That is unfortunately false.
Problem 4 rephrased would sound like:
In which experiment are the observations more dense?
SecondChildUserIdTAG: 1209636
SecondChildUserNameTAG: adrian_1d
SecondChildCreateTimeTAG: 2013-02-23T16:45:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Ok... and how to determine that based on boxplot?
SecondChildUserIdTAG: 1196355
SecondChildUserNameTAG: EmilyEly87
SecondChildCreateTimeTAG: 2013-02-23T16:48:09Z
SecondChildVoteTAG: 0
SecondChildTAG: By the lower distance between quartile. That mean more data fall in a lower interval.
SecondChildUserIdTAG: 183861
SecondChildUserNameTAG: Xelio
SecondChildCreateTimeTAG: 2013-02-23T17:13:25Z
SecondChildVoteTAG: 0
SecondChildTAG: IMO the max value is not what most matters here. Consider that max values might consist of very few observations.
I don't want to be too explicit, but there are other noticeable differences. The location of the median tells us something about.. what? And what about the very acute IQR difference?
To make a conclusion I think we need assume that both experiments has an equal, or nearly equal, sample length.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-23T17:19:16Z
SecondChildVoteTAG: 0
SecondChildTAG: @adrian_d Exactly. That's what I thought too. Cause the height reflects the density. But how were we supposed to figure it out from a box plot huh? Apparently, it seems that the experiment having a larger box i.e. between the lower and the upper quartiles will have a greater area in the histogram. Hence, a smaller height between intervals ?
But I may be wrong. I need to be guided myself.
SecondChildUserIdTAG: 1249072
SecondChildUserNameTAG: noorfatima
SecondChildCreateTimeTAG: 2013-02-23T17:28:57Z
SecondChildVoteTAG: 0
SecondChildTAG: @noorfatima. I think the question can be solved only seeing boxplots, and assuming same number of observations for experiment. Lower and upper quartiles give a sense of where there are the first and last 25% of observations, and, hence, the area of the boxplot gives a visual representation of the 50% of the observations. The location of the median gives a sense of the symmetry or asymmetry of the distribution. If we consider all these facts, and the length of the whiskers, we can make an approximately good enough mental "picture" of the resulting histograms.
However, the problem is not easy. Do you note something? Every ex. set so far contains at least one problem to think deeply.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-23T17:57:02Z
SecondChildVoteTAG: 0
SecondChildTAG: I a similar way I marked the lower and upper quartile values (approximates only) and simply calculated the difference which I assumed to be the horizontal units if plotted as histogram. I excluded the whiskers from consideration, though maybe I should not have done so. In any case, I obtained the desired result from my method. I will be following what the correct method is once the deadline has past.
SecondChildUserIdTAG: 242480
SecondChildUserNameTAG: cobradav
SecondChildCreateTimeTAG: 2013-02-23T19:32:23Z
SecondChildVoteTAG: 0
SecondChildTAG: Comparing height of histogram is equal to comparing density. Thus it's easier to find out which plot is more dense.
SecondChildUserIdTAG: 1245055
SecondChildUserNameTAG: newstat
SecondChildCreateTimeTAG: 2013-02-24T01:06:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I found out the skewness of the graph using the box plot and i got an idea of how the histograph looks like and then i figured out the highest point by comparing although i made the assumption that one of the graphs height may be a bit more than the other and so i am not sure on my method although my answer was right
SecondChildUserIdTAG: 628966
SecondChildUserNameTAG: AniketShroff
SecondChildCreateTimeTAG: 2013-02-25T18:26:00Z
SecondChildVoteTAG: 0
SecondChildTAG: it is easy one you see that the upper quartile and the median are the samefor both experiments. That leaves you with the lower quartile which is bunched in !
SecondChildUserIdTAG: 341206
SecondChildUserNameTAG: laxmishac
SecondChildCreateTimeTAG: 2013-02-25T22:59:12Z
SecondChildVoteTAG: 0
SecondChildTAG: Look at where the median appears in box5 ... it isn't close to the middle of the box ... indicating that the distribution is skewed ... then think about the affect of skewing the data ...
SecondChildUserIdTAG: 1287965
SecondChildUserNameTAG: ReadeDavis
SecondChildCreateTimeTAG: 2013-02-26T14:28:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Think of a spring or coil.Now if I hold it in the middle it stays as the median (middle coil) and the two ends can be considered as upper or lower quartiles to simplify things (and the spring represents the box and let us forget the whiskers) and now I can move the stretched spring by the middle on either side holding the middle coil keeping the two ends constant in position so things crowd when I move it to one end- extend this concept including the concept of crowding or density of the spring to the histogram as described by Prof Adhikari and you should get an idea.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T18:09:24Z
FirstChildVoteTAG: 12
SecondChildTAG: You are an expert, Prasannasimha! I like your explanations.
They should make you a community TA... :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T20:51:07Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks a lot for your explanation. its been a great help.
SecondChildUserIdTAG: 749334
SecondChildUserNameTAG: j_diares
SecondChildCreateTimeTAG: 2013-02-24T09:16:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you :)
SecondChildUserIdTAG: 1196355
SecondChildUserNameTAG: EmilyEly87
SecondChildCreateTimeTAG: 2013-02-24T09:53:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Great explanation Prasannasimha! Helped me clarify my doubt. Thank you!
SecondChildUserIdTAG: 150999
SecondChildUserNameTAG: ankurwidguitar
SecondChildCreateTimeTAG: 2013-02-25T10:10:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't get your explanation Prasannasimha. Can you explain it again please?
For me, I just looked at the median and thought that one is more dense than the other and the one that is more dense will have a higher peak.
But I'm interested to understand your perspective. Can you kindly explain again?
thank you.
SecondChildUserIdTAG: 897162
SecondChildUserNameTAG: kymwkl
SecondChildCreateTimeTAG: 2013-02-27T13:45:30Z
SecondChildVoteTAG: 0
FirstChildTAG: One way to think about this is imagine drawing a histogram for the data with 4 division, one for each quartile of the data (0-25%, 25%-50%, 50%-75%, 75%-100%). This is different from what we have seen in the past, where we started from end point ranges and counted how much was in each range, but is a valid way of partitioning the data. Building the histogram this way make the answer obvious. In actuality, if you built the histogram from equally spaced ranges as might be more normal, you might get a different answer if one of the experiments had a "lumpy" distribution given a very high density for 1 piece of the histogram, while the rest was almost empty.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T02:17:28Z
FirstChildVoteTAG: 1
SecondChildTAG: I thought exactly that. You can build the histogram with only the information shown in the box plot, by doing the opposite of what we've been doing for calculating the percentiles. That histogram would have 4 divisions, as there are 4 divisions in the box plot.
SecondChildUserIdTAG: 188586
SecondChildUserNameTAG: FLara
SecondChildCreateTimeTAG: 2013-02-25T03:37:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Box Size:
The size of the box can provide an estimate of the kurtosis - the peakedness - of the distribution. A very thin box relative to the whiskers indicates that a very high number of cases are contained within a very small segment of the sample. This signifies a distribution with a thinner peak. A wider box relative to the whiskers indicates a wider peak. The wider the box, the more U-shaped the distribution becomes
FirstChildUserIdTAG: 569767
FirstChildUserNameTAG: SanjayS72
FirstChildCreateTimeTAG: 2013-02-26T04:52:48Z
FirstChildVoteTAG: 1
SecondChildTAG: http://www.helium.com/items/1275773-how-to-read-and-interpret-a-box-plot
SecondChildUserIdTAG: 569767
SecondChildUserNameTAG: SanjayS72
SecondChildCreateTimeTAG: 2013-02-26T04:56:19Z
SecondChildVoteTAG: 0
IndexTAG: 2628
TitleTAG: Not easy
Definitely is not easy, but with clear explanations and instructions I am sure we will make it.
I am confuse on how to calculate quartiles using the stem and leaf plot.
UserIdTAG: 976341
UserNameTAG: ErnestoAngulo
CreateTimeTAG: 2013-02-23T15:42:58Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I had the same problem, it seams i missed lec 2.5, this had the instructions, its quite simple once you have seen the vid
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-23T16:12:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Also-there are some great practice exercises on Stigigui Ch. 3 Exercise 3.10
SecondChildUserIdTAG: 1024913
SecondChildUserNameTAG: akaren65
SecondChildCreateTimeTAG: 2013-02-23T22:54:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Try 'un'summarizing the stem and leaf plot by writing down all the numbers. The it''ll look exactly like Exercise 3-10 in the text book.
SecondChildUserIdTAG: 254949
SecondChildUserNameTAG: stormshadow
SecondChildCreateTimeTAG: 2013-02-24T17:29:31Z
SecondChildVoteTAG: 0
FirstChildTAG: Quartiles using a stem and leaf plot are calculated the same way as without one - the benefit of the stem and leaf plot is that you have the numbers in order.
Imagine the following data:
0|122
1|258
2|0889
This means that you have 10 numbers total, which are:
1 2 2 12 15 18 20 28 28 29
To find a quartile, you have to take the lowest number that is equal to or greater than the the number that would represent the actual quartile. In other words, for this example:
25% would be found as follows:
1) Multilply the total numbers * quartile. $10 * .25 = 2.5$
2) Round up to the nearest whole number: $2.5 -> 3$
3) Take the third highest number: $2$ - that's your 20th percentile.
The other thing to keep in mind is that the 50% is NOT the same as the median (as commonly understood). The 50th percentile in this case would be $15$, not the mean of 15 and 18 (which would be the median).
Hope this helps!
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T18:47:25Z
FirstChildVoteTAG: 6
SecondChildTAG: another way to do it:
Percentile is known, need to find the value.
(Percentile/100) x total # of values
For me, this way is less complicated.
SecondChildUserIdTAG: 1040395
SecondChildUserNameTAG: Bcandelario
SecondChildCreateTimeTAG: 2013-02-24T01:39:00Z
SecondChildVoteTAG: 0
FirstChildTAG: consider the stem and leaf plot as a whole data list. You will find the solution is exactly the same as is described in Lec.2.5
FirstChildUserIdTAG: 1245055
FirstChildUserNameTAG: newstat
FirstChildCreateTimeTAG: 2013-02-24T01:10:43Z
FirstChildVoteTAG: 0
FirstChildTAG: Try 'un'summarizing the stem and leaf plot by writing down all the numbers. The it''ll look exactly like Exercise 3-10 in the text book.
FirstChildUserIdTAG: 254949
FirstChildUserNameTAG: stormshadow
FirstChildCreateTimeTAG: 2013-02-24T17:30:50Z
FirstChildVoteTAG: 0
IndexTAG: 2629
TitleTAG: income
What choice is income?
UserIdTAG: 1295801
UserNameTAG: Rex1385
CreateTimeTAG: 2013-02-23T15:33:45Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Honor code - please do not ask for solutions to open problems.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T18:48:10Z
FirstChildVoteTAG: 0
FirstChildTAG: Let me help answer this for you...
Income is a personal choice in life, often related to personal traits and capabilities as well as luck.
The choices are limited, you may have no income, a single income or multiple incomes.
Some people do not have a choice in income and have to live with what they have.
Some people have limitless choices as they inherited a large sum of money or won the lottery.
Choices of income is somewhat affected by the other choices one has made during his/her life.
Some people are happy with their choice, some are not and some feel trapped with their choices.
Hope this helped... =P
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T21:39:09Z
FirstChildVoteTAG: 1
IndexTAG: 2630
TitleTAG: Problem 4 and Question c
Please explain why it is not reasonable to assume Uniform distribution for the problem 4 and question c
For this dataset, is it reasonable to assume a uniform distribution of educational level in each interval?
the above correct answer NO. Please explain.
UserIdTAG: 918305
UserNameTAG: venkareddy
CreateTimeTAG: 2013-02-23T15:29:26Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: You need to think about it.If I pass a certain class and stop my education thereafter what happens ?
Prasanna
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T15:31:46Z
FirstChildVoteTAG: 0
SecondChildTAG: I am not what you are saying . Please be specific.
SecondChildUserIdTAG: 918305
SecondChildUserNameTAG: venkareddy
SecondChildCreateTimeTAG: 2013-02-24T18:37:40Z
SecondChildVoteTAG: 0
SecondChildTAG: If you think that one interval got a high school degree but not a banchellor one, the answer would be no. But if you think in terms of years the question maybe yes. Depends in how are you meassuring educational level, by years or by degrees. 12 years of study does not grant you automatically a high school degree.
SecondChildUserIdTAG: 1222835
SecondChildUserNameTAG: CatonElMenor
SecondChildCreateTimeTAG: 2013-02-24T23:22:41Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Caton.
SecondChildUserIdTAG: 918305
SecondChildUserNameTAG: venkareddy
SecondChildCreateTimeTAG: 2013-02-25T02:27:05Z
SecondChildVoteTAG: 0
SecondChildTAG: I am still confusing on this question. I think the educational systems are different everywhere. If someone went through 12 years of pain, he deserve a degree!!!
SecondChildUserIdTAG: 60773
SecondChildUserNameTAG: billchenxi
SecondChildCreateTimeTAG: 2013-02-25T03:01:04Z
SecondChildVoteTAG: 0
FirstChildTAG: Venkareddy, please do not provide correct answers before due date!
FirstChildUserIdTAG: 517550
FirstChildUserNameTAG: Ewa_G
FirstChildCreateTimeTAG: 2013-02-23T15:58:54Z
FirstChildVoteTAG: 4
SecondChildTAG: Exercise set 2
Problem 1
Point b. I confuse anybody can explain me?
SecondChildUserIdTAG: 1050924
SecondChildUserNameTAG: leap
SecondChildCreateTimeTAG: 2013-02-26T11:58:36Z
SecondChildVoteTAG: 0
FirstChildTAG: > Please explain
No. I realise this is an online course and it is impossible to maintain total academic honesty. But you did agree to an honour code.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:13:09Z
FirstChildVoteTAG: 0
FirstChildTAG: Also couldn't get it for a while. The thing I missed was the first sentence of the problem:
> ...adults aged 25 and over in the United States...
So these are people who won't get (most likely) more education in primary school.
0-9 range means all people who have less than 9 years of education. So they stopped at 1,2,3 etc. year for some reason. It is very unlikely that number of people who left school after 4th year and after 7th year will be equal.
FirstChildUserIdTAG: 1222487
FirstChildUserNameTAG: OlegDudkin
FirstChildCreateTimeTAG: 2013-02-26T19:14:09Z
FirstChildVoteTAG: 0
IndexTAG: 2631
TitleTAG: confusing
i'm confusing about the graph..
UserIdTAG: 1231135
UserNameTAG: shie112709
CreateTimeTAG: 2013-02-23T15:27:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: the 4 graphs are different the first is not true count
the second dose not have the right "category" also the 3rd
bec. the graph is "counting" the "green color"
FirstChildUserIdTAG: 1275942
FirstChildUserNameTAG: Mohd80
FirstChildCreateTimeTAG: 2013-02-23T16:02:33Z
FirstChildVoteTAG: 0
SecondChildTAG: Honor code - please do not post solutions to open homework assignments.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-23T18:50:07Z
SecondChildVoteTAG: 0
IndexTAG: 2632
TitleTAG: Practise for Exercise set 2 error?
Hi,
The 1st question of the section Lectures 2.2 and 2.3 seem to be wrong.
a) Height of the -10 to 20 bar = ______% per unit
the width of the bin is 30, and the number of units is 14 out of 100, therefore my calulation is: 14%/30 = 0.4666667, yet this is marked wrong, and the answer shows as 1.4, based on 14 units divided by 10, which is indicated as the width of the bin.
Now, from -10 to 20 there are 30 units, not 10, and according to the book, this is what should be in the denominator there, not 10.
Am I interpreting this incorrectly?
Many thanks
UserIdTAG: 9433
UserNameTAG: pecolombo
CreateTimeTAG: 2013-02-23T15:13:57Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I got the same result.... I think it's an error and I think I saw some other posts about it ;)
FirstChildUserIdTAG: 1196355
FirstChildUserNameTAG: EmilyEly87
FirstChildCreateTimeTAG: 2013-02-23T16:27:12Z
FirstChildVoteTAG: 1
FirstChildTAG: Yes, there are certainly other posts about this. If you had posted on the question's discussion page, you would have see a lot of posts about this.
This is from the practice set 2, yet you posted your question on Set 1. The idea of subforums is to keep relevant posts together.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:03:52Z
FirstChildVoteTAG: 0
IndexTAG: 2633
TitleTAG: Confused
Why is the width of the interval -10 to 20 given as 10 and not 30 ?
UserIdTAG: 930387
UserNameTAG: Kamakama
CreateTimeTAG: 2013-02-23T15:04:54Z
VoteTAG: 24
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 6
FirstChildTAG: I have same question , spent a lot time to obtain an relation
FirstChildUserIdTAG: 1147522
FirstChildUserNameTAG: mostafafarouk
FirstChildCreateTimeTAG: 2013-02-23T15:15:41Z
FirstChildVoteTAG: 0
SecondChildTAG: same goes for me
SecondChildUserIdTAG: 1291622
SecondChildUserNameTAG: fcavada
SecondChildCreateTimeTAG: 2013-02-23T19:17:07Z
SecondChildVoteTAG: 0
SecondChildTAG: take only the difference between the two endpoints regardless off +ve or -ve...example -10 and 20 the difference is 10 not 30
SecondChildUserIdTAG: 907217
SecondChildUserNameTAG: somayyah
SecondChildCreateTimeTAG: 2013-02-23T20:39:13Z
SecondChildVoteTAG: 0
SecondChildTAG: ?
SecondChildUserIdTAG: 639284
SecondChildUserNameTAG: grcinica
SecondChildCreateTimeTAG: 2013-02-23T21:06:14Z
SecondChildVoteTAG: 0
SecondChildTAG: 20-(-10)=20+10
SecondChildUserIdTAG: 639284
SecondChildUserNameTAG: grcinica
SecondChildCreateTimeTAG: 2013-02-23T21:07:16Z
SecondChildVoteTAG: 0
SecondChildTAG: I sure it is 30 and not 10, in intervals, - and + are important. So, 20-(-10)=30 not 10!
SecondChildUserIdTAG: 871691
SecondChildUserNameTAG: MHBN
SecondChildCreateTimeTAG: 2013-02-23T22:01:24Z
SecondChildVoteTAG: 0
SecondChildTAG: boo.
SecondChildUserIdTAG: 967698
SecondChildUserNameTAG: cb1667
SecondChildCreateTimeTAG: 2013-02-24T00:54:12Z
SecondChildVoteTAG: 0
SecondChildTAG: See courseware errata
SecondChildUserIdTAG: 1153412
SecondChildUserNameTAG: FPesante
SecondChildCreateTimeTAG: 2013-02-25T00:37:27Z
SecondChildVoteTAG: 0
SecondChildTAG: So, it means that we have to take relative values of numbers, I mean: /20/-/-10/= 20 - 10 = 10, is that correct?
SecondChildUserIdTAG: 1131693
SecondChildUserNameTAG: Catica
SecondChildCreateTimeTAG: 2013-02-25T18:53:07Z
SecondChildVoteTAG: 0
SecondChildTAG: we have to consider the sign, so i we are in the right thing 20 -(-10) = 20+10 =30. Courseware is wrong
SecondChildUserIdTAG: 1208284
SecondChildUserNameTAG: Raquel90
SecondChildCreateTimeTAG: 2013-02-25T23:17:17Z
SecondChildVoteTAG: 0
SecondChildTAG: It is 3o, even if we say upper limit- lower limit i.e. 20-(-10)=30
SecondChildUserIdTAG: 1043835
SecondChildUserNameTAG: anubhav_maini
SecondChildCreateTimeTAG: 2013-02-27T07:05:17Z
SecondChildVoteTAG: 0
SecondChildTAG: I think the answer is 30
SecondChildUserIdTAG: 1267784
SecondChildUserNameTAG: TrinhNguyen256
SecondChildCreateTimeTAG: 2013-02-27T08:29:01Z
SecondChildVoteTAG: 0
FirstChildTAG: yeap... the same here. should be 30
FirstChildUserIdTAG: 905926
FirstChildUserNameTAG: MarcinJ77
FirstChildCreateTimeTAG: 2013-02-23T15:24:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Its wrong. I think so.
SecondChildUserIdTAG: 434437
SecondChildUserNameTAG: KalashnikovYuriy
SecondChildCreateTimeTAG: 2013-02-23T18:47:23Z
SecondChildVoteTAG: 0
SecondChildTAG: I think so, too
SecondChildUserIdTAG: 1153020
SecondChildUserNameTAG: minasy
SecondChildCreateTimeTAG: 2013-02-24T04:15:36Z
SecondChildVoteTAG: 0
SecondChildTAG: See courseware errata.
SecondChildUserIdTAG: 1153412
SecondChildUserNameTAG: FPesante
SecondChildCreateTimeTAG: 2013-02-25T00:37:49Z
SecondChildVoteTAG: 0
FirstChildTAG: I think so, too.
FirstChildUserIdTAG: 222713
FirstChildUserNameTAG: SandeepBavdekar
FirstChildCreateTimeTAG: 2013-02-23T18:00:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Please check the discussions - 7 of the 8 discussion items that appear on the first page page of the topic are about this very question.
It is a known issue and staff are aware.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T18:52:48Z
FirstChildVoteTAG: 0
FirstChildTAG: Last I checked the difference between -10 and 20 is
$20 - (-10) = 20 + 10 = 30$
Hence, $\frac{14\%}{30} \neq 1.4\% $
It would seem to me that someone overlooked the negative sign, causing the range of coverage of the $14\%$ to appear to be over $10$ units instead of the true $30 units
FirstChildUserIdTAG: 151933
FirstChildUserNameTAG: WildW1ill
FirstChildCreateTimeTAG: 2013-02-23T19:51:33Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you read any of the other posts in this subforum? With 47,000 people enrolled, efficient use of the forums is a must.
There are dozens of questions about this under the General tab. And of the 8 in this question subforum, 7 relate to this.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:06:04Z
FirstChildVoteTAG: 0
SecondChildTAG: Where on this forums can I find the answer? I can't find it
SecondChildUserIdTAG: 928962
SecondChildUserNameTAG: DianaMarcela
SecondChildCreateTimeTAG: 2013-02-27T00:26:32Z
SecondChildVoteTAG: 0
IndexTAG: 2634
TitleTAG: Right answer diffrent method!
I first got the secondan answer right by finding the right ration and then I dividing the total number of students. But the first answer I got by the following by takiing the clue formthe second answer((30/270)*100). Am I in good shape?
UserIdTAG: 1295629
UserNameTAG: Jobb
CreateTimeTAG: 2013-02-23T14:38:51Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's one of only two valid methods I can think of :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T14:59:43Z
FirstChildVoteTAG: 0
IndexTAG: 2635
TitleTAG: wrong answers
am finding it difficult to solve most of the questions here can anybody help me out cos i need to pass this course
UserIdTAG: 917742
UserNameTAG: samuelemmanuel
CreateTimeTAG: 2013-02-23T14:24:28Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: me tooo can someone help uss
FirstChildUserIdTAG: 1228979
FirstChildUserNameTAG: khadija454
FirstChildCreateTimeTAG: 2013-02-23T14:49:43Z
FirstChildVoteTAG: 0
FirstChildTAG: Maybe if you let us know what problems are you having, we can help.
Watching the lectures and reading the text should be more than enough to answer *most* of the questions, however.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T14:56:44Z
FirstChildVoteTAG: 0
FirstChildTAG: I suggest, the following:
1- go through the lecture again (video & practise )
2- try to do the exercises again
3- post questions here about specific exercises you are having difficulties with.
thx!
FirstChildUserIdTAG: 1057409
FirstChildUserNameTAG: srtam
FirstChildCreateTimeTAG: 2013-02-23T15:15:05Z
FirstChildVoteTAG: 1
IndexTAG: 2636
TitleTAG: Comentario
La traducción decia porcentaje de estudiantes, yo coloqué el 100%. En el problema original pregunta el porcentaje de Seniors y por eso tuve mal la respuesta
UserIdTAG: 903196
UserNameTAG: ITZ
CreateTimeTAG: 2013-02-23T14:06:50Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/courseware/847291eea63447c485e96d34b99e5a23/212c9504070f4afa9f39c39dc351036f/
I have nothing against Spanish, but we're supposed to write and read English here...
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T14:54:05Z
FirstChildVoteTAG: 2
FirstChildTAG: Spanish to English translation of above comment.
"Percentage of students was saying the translation, I placed 100 %. In the original problem he asks about the percentage of Seniors and that's why I had badly the response"
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-23T22:59:43Z
FirstChildVoteTAG: 0
IndexTAG: 2637
TitleTAG: SticiGui Online Assignments
Dear Prof. A,
I happened to go through this link "(http://statistics.berkeley.edu/~stark/SticiGui/Problems/assign-2x-s13.htm)" which has online assignments and a schedule too.
Plus, it makes references to the edX Stat 2.1x course and also says it will affect the grades if I submit the answers. I'm not sure I understand this scenario completely.
Are these SticiGui online assignments part of the Courseware or not ? Or are they just for practice ?
I'm a first-timer here at edX, so please bear with me.
Awaiting your response.
Yours sincerely,
Nitish Raole.
UserIdTAG: 379141
UserNameTAG: NitishRaole
CreateTimeTAG: 2013-02-23T13:54:36Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I *strongly* suspect that that link is for actual Berkeley students taking the course at the University.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T14:48:24Z
FirstChildVoteTAG: 1
FirstChildTAG: Unless otherwise specified by the staff, our assessments are only those listed on the courseware page.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T21:00:32Z
FirstChildVoteTAG: 1
IndexTAG: 2638
TitleTAG: confuse..
i was really confused on how to compute the number of students out of 270..now in the explanation, i do understand how do i get it..
UserIdTAG: 1231135
UserNameTAG: shie112709
CreateTimeTAG: 2013-02-23T13:54:16Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2639
TitleTAG: Lecture 2.2 histogram
Sorry but I do not agree w/the histogram's visual representation. Starting w/the low income range which is the higher bar it visually induce us to believe that the percentage of the higher incomes decrease from the 15K to the 150K and while it is true for the 50K - 100K range and the 100K - 150K range it is not true for the 10K - 25K range and the 25K - 50K range according to the table.A correct visualization should show an increase for the 25K a little decrease for the 50K (but higher than 10K) and after that the progressive decrease.Am I right or not ?
UserIdTAG: 326257
UserNameTAG: hinno
CreateTimeTAG: 2013-02-23T13:53:37Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 5
FirstChildTAG: The height of the histogram suggests density, not pure quantity. In order to get the quantity you need the area of the bar, thus the width of the base is significant. you would be correct if the income ranges were of equal amounts per group. At least that's what I think. Hope that helps.
FirstChildUserIdTAG: 283474
FirstChildUserNameTAG: Methuselah
FirstChildCreateTimeTAG: 2013-02-23T14:55:25Z
FirstChildVoteTAG: 3
SecondChildTAG: strictly speaking Methuselah is right, but I agree with hinno's underlying idea - to represent this data I would rather use bars, which would fit under a bell shaped kind of curve, which, contrary to what the prof says, is what incomes are distributed like (imho) - middle incomes dominate and poor and rich ppl are on both sides, with slopes downwards... true, how you label the horizontal units then is not "statistical" but is rather based on a societal convention - what amount (or range) constitutes as middle, higher middle, high, etc income...
SecondChildUserIdTAG: 953527
SecondChildUserNameTAG: Marton
SecondChildCreateTimeTAG: 2013-02-27T20:48:59Z
SecondChildVoteTAG: 0
FirstChildTAG: The Chinese saying :"A picture is worth more than a thousand words" holds true.
In the Distribution Table Histogram, some of the groups are tall and narrow, and some are short and wide. Instead of clarifying and simplifying, it gives a confusing picture to the novice and the lay person. If the histogram could be laid out with **equal bin or group width**, we would still get our representative area of width x height, but then the different heights will DIRECTLY point out the various percentages in each group without effort or confusion.
FirstChildUserIdTAG: 1053143
FirstChildUserNameTAG: tasmaniantiger
FirstChildCreateTimeTAG: 2013-02-23T16:56:46Z
FirstChildVoteTAG: 1
SecondChildTAG: aka bar graph
SecondChildUserIdTAG: 838733
SecondChildUserNameTAG: Ronnicus
SecondChildCreateTimeTAG: 2013-03-09T21:56:56Z
SecondChildVoteTAG: 0
FirstChildTAG: This histogram must have an application in the real world but not for real people. I think a histogram with unequal intervals is called misleading no matter how carefully I label the unit on the y axis.
FirstChildUserIdTAG: 1015152
FirstChildUserNameTAG: MrKK
FirstChildCreateTimeTAG: 2013-02-24T21:18:12Z
FirstChildVoteTAG: 0
SecondChildTAG: I agree it can be easily misunderstood, for example if incomes above 150k are "swept-in", then the label should read "150+"
SecondChildUserIdTAG: 1020498
SecondChildUserNameTAG: cgorski
SecondChildCreateTimeTAG: 2013-02-27T20:47:53Z
SecondChildVoteTAG: 0
FirstChildTAG: One way to think about why the graph with height as density and not population in that category, is that the categories are really somewhat arbitrary and done to make simple analysis easy. If you were really going to do some serious evaluation, you would generate the chart with MANY more categories, each much small in range. One key fact about plotting densities, is that the shape of the graph doesn't radically change with a change in the sampling intervals, it just gets more resolution. If an area was at a density of 2%/$1000 income, then dividing the region into more regions, these will likely also have values around 2%/$1000 income, maybe some higher or some lower, but on average they will have this value. If we plotted population levels (% of population), then when we divide the areas in two, the values for each will go down by that factor. It means that we have as a standard basis that the height of the curve is the density, and the area under the curve for any interval is the population.
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T04:37:34Z
FirstChildVoteTAG: 0
FirstChildTAG: I think this kind of histogram can be very well used to mislead people rather than inform them! In my almost five-year experience with scientific papers, I have never seen one such histogram. It is always the case that the horizontal axis is divided into bins of equal widths, so that the y-axis is the frequency.
Imagine I wanted to say to a commoner that people with higher income are in larger numbers, using the same data set. To do so, I would easily have shorter bin widths (denominator) for higher incomes that would lead to higher heights...
FirstChildUserIdTAG: 1141818
FirstChildUserNameTAG: Reza123
FirstChildCreateTimeTAG: 2013-02-26T16:48:07Z
FirstChildVoteTAG: 0
SecondChildTAG: No matter how many bins you divide the highest income group into, all of the resulting bin heights will still have to -- on average -- equal the height of the original bin in our example histogram. As RichardDamon said above, increasing intervals only increases resolution, it does not change the basic shape of the graph.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-02-26T21:37:44Z
SecondChildVoteTAG: 0
IndexTAG: 2640
TitleTAG: Set 3 - Problem 2
Answers are wrong. I made calculations. Median shoud be 80.5. Similar are 20th and 90th percentile.
UserIdTAG: 570075
UserNameTAG: NikiSadovski
CreateTimeTAG: 2013-02-23T13:44:38Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: Try and answer those question in accordance with the definition of percentile given in the lecture
FirstChildUserIdTAG: 1123565
FirstChildUserNameTAG: arjitanand
FirstChildCreateTimeTAG: 2013-02-23T13:49:52Z
FirstChildVoteTAG: 5
SecondChildTAG: Answers are correct...please follow the lectures carefully..
SecondChildUserIdTAG: 1268152
SecondChildUserNameTAG: naniglavs
SecondChildCreateTimeTAG: 2013-02-23T17:00:42Z
SecondChildVoteTAG: 0
SecondChildTAG: go through the basic formal definition of percentile. you will get the right answer.
SecondChildUserIdTAG: 85891
SecondChildUserNameTAG: rajivverma88
SecondChildCreateTimeTAG: 2013-02-23T18:31:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Works exactly as lecture described. I did, however, make it a single long list in excel so that I could do it in the same manner Professor A did in lecture 2.5 slides 1 though 3. It was easier for me to see the process in this manner. It could have just as easily been a list (not Stem and leaf) hand written - again it was just easier for me to see the process that way.
SecondChildUserIdTAG: 242480
SecondChildUserNameTAG: cobradav
SecondChildCreateTimeTAG: 2013-02-23T19:37:52Z
SecondChildVoteTAG: 0
SecondChildTAG: The answers are perfectly right.
SecondChildUserIdTAG: 1057432
SecondChildUserNameTAG: achalrm
SecondChildCreateTimeTAG: 2013-02-23T20:34:38Z
SecondChildVoteTAG: 0
SecondChildTAG: As, likely, are Niki's. I was in the same boat, Niki, but there are different methods of calculating these values and you have to be sure to utilize the method shown in the lectures.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-24T00:09:22Z
SecondChildVoteTAG: 0
SecondChildTAG: Answers are correct. I have found 20th and 90th percentile correctly , but my median percentile answer was wrong , maybe I had make a mistake
SecondChildUserIdTAG: 1059155
SecondChildUserNameTAG: gasimovilkin
SecondChildCreateTimeTAG: 2013-02-24T14:39:12Z
SecondChildVoteTAG: 0
SecondChildTAG: How did you get 80.5? There's no data entry 80.5 in the problem! Find the smallest number from the given data.
SecondChildUserIdTAG: 254949
SecondChildUserNameTAG: stormshadow
SecondChildCreateTimeTAG: 2013-02-24T17:08:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Answers are definitely correct. You deal with the list of numbers in that problem. Look at the lec 2.5.
SecondChildUserIdTAG: 1264964
SecondChildUserNameTAG: ChaosCreator
SecondChildCreateTimeTAG: 2013-02-24T20:57:09Z
SecondChildVoteTAG: 0
SecondChildTAG: answers are fine - i messed up the rounding personally. pretty sure i did.
SecondChildUserIdTAG: 609485
SecondChildUserNameTAG: Shokodemon
SecondChildCreateTimeTAG: 2013-02-27T23:29:59Z
SecondChildVoteTAG: 0
FirstChildTAG: Answers are correct...please follow the lectures carefully..
FirstChildUserIdTAG: 1268152
FirstChildUserNameTAG: naniglavs
FirstChildCreateTimeTAG: 2013-02-23T17:00:59Z
FirstChildVoteTAG: 1
SecondChildTAG: Agreed. Follow the lesson instructions. Do not use excel to find results. The examples provided in the exam are actually very accessible if you follow the rationale provided in all lectures.
I made some mistakes due to rushing.... Always double check your numbers before answering.
SecondChildUserIdTAG: 206086
SecondChildUserNameTAG: pedrocas1972
SecondChildCreateTimeTAG: 2013-02-24T00:18:13Z
SecondChildVoteTAG: 0
SecondChildTAG: And remember they are American style grades (/100) and not "European" ones (/10). Mine got wrong because of it. And if you want to double check with R, use option 1 of quantiles.
SecondChildUserIdTAG: 738171
SecondChildUserNameTAG: quevedin
SecondChildCreateTimeTAG: 2013-02-25T18:09:35Z
SecondChildVoteTAG: 0
FirstChildTAG: The median and the 50th percentile are not the same thing. Watch the lectures, as this is a pretty important point.
Also, honor code - please do not post your answers to homework assignments that are still open, even if they are wrong.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T19:01:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Per the text, the median and the 50th percentile are EXACTLY the same thing, and I also recorded the same information in my notes when writing them ver batim from the lecture slides.
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#percentiles_from_histograms
See table 3.5 in the text (link above).
Something is not correct in the computer grading on ES3 Problem 2b.
I used the exact same formula method to calculate a and c for this problem, and those the computer graded correctly. I checked my math and my inputs 3 times, they were correct.
SecondChildUserIdTAG: 1165890
SecondChildUserNameTAG: sandigarcia
SecondChildCreateTimeTAG: 2013-02-23T20:19:59Z
SecondChildVoteTAG: 0
SecondChildTAG: They are not the same and it is clearly mentioned in the lectures.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T20:55:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Watch the part about the definition of the p-th percentile.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T20:56:41Z
SecondChildVoteTAG: 0
SecondChildTAG: I think the problem here is that Lecture 2.4 and part of the textbook describe percentiles/medians in "conventional" terms (including the slide ~1:18 in Lec 2.4 where it's written explicitly) for histograms. Lecture 2.5 then sees the professor adopting a different convention as the preferred way for lists of numbers. That is to say, you're both right.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-24T00:34:51Z
SecondChildVoteTAG: 0
SecondChildTAG: From the page you linked to:
> The median is the 50th percentile: the smallest number that is at least as large as half the data.
This is not the same as taking the mean of the middle two numbers if the total number of entries is even (the common definition of the median). The terminology is very specific for the course.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-24T14:22:53Z
SecondChildVoteTAG: 0
FirstChildTAG: Is there some reason we are using this definition of the median? It is more usual to define it as the mean of the middle two numbers when a sample/population has an even number of observations. What are the benefits of instead rounding down as the lecure suggests?
FirstChildUserIdTAG: 678934
FirstChildUserNameTAG: Paul_Thomas
FirstChildCreateTimeTAG: 2013-02-24T21:40:52Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree with you i find in exel by command
=PERCENTILE(A1:A28,0.5)
the answer is 80.5 but it wrong
FirstChildUserIdTAG: 1273583
FirstChildUserNameTAG: Kachamas044
FirstChildCreateTimeTAG: 2013-02-26T07:25:50Z
FirstChildVoteTAG: 0
FirstChildTAG: In order to use the method in the lectures and get the right answer, you can use Excel in the following manner.
1. Enter the data from the stem and leaf plot into column A.
2. Enter the position numbers from 1 to 28 in column B.
3. Set the calculation for all rows in column C to equal column A value divided by 28.
The result in C will be the % value of the position relative to the length of the list, which is 28.
Once you have this set up, you'll see that the sixth position on the list is the 20th percentile, the 14th position is the 50th percentile, and the 26th position is the 90th percentile, as defined in the lecture.
The percentile function in Excel uses interpolation based on your input of k. I think there's way too much reliance these days on calculators and spreadsheets that don't require you to know what you're doing and trap you into thinking you're doing things right.
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-02-26T19:45:45Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you @m2foster .
SecondChildUserIdTAG: 681788
SecondChildUserNameTAG: sk797
SecondChildCreateTimeTAG: 2013-02-27T18:23:02Z
SecondChildVoteTAG: 0
IndexTAG: 2641
TitleTAG: Aha! Dont put % in answeres! It marKs them wrong! I think we need to be allowed to redo this module.
So! Most of my answers were correct, but I ma going to fail this exercise because I put % in them all! I think we were rather misled by the lecturer who made a special point of saying that it is important to include the units in results or risk being marked down! I suggest we be allowed to redo this module due to the general confusion.
UserIdTAG: 919769
UserNameTAG: MSpirova
CreateTimeTAG: 2013-02-23T13:39:31Z
VoteTAG: 13
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: My sentiments exactly !
FirstChildUserIdTAG: 1093884
FirstChildUserNameTAG: farrukhazfar
FirstChildCreateTimeTAG: 2013-02-23T13:45:23Z
FirstChildVoteTAG: 0
SecondChildTAG: i agree .. so kind of hint would help
SecondChildUserIdTAG: 1221321
SecondChildUserNameTAG: edX2403
SecondChildCreateTimeTAG: 2013-02-23T14:53:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes but surely percents aren't units ?
SecondChildUserIdTAG: 119039
SecondChildUserNameTAG: Alan56
SecondChildCreateTimeTAG: 2013-02-23T18:23:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes I have the same problem they should specify percent or use a decimal as I have gotten several problems incorrect because of the format.
SecondChildUserIdTAG: 168169
SecondChildUserNameTAG: Elainethorne
SecondChildCreateTimeTAG: 2013-02-24T05:33:49Z
SecondChildVoteTAG: 0
FirstChildTAG: I learned the hard way that I must read the question carefully. If the question asks for a percentage it means just that, a decimal answer will not do (.25 is not correct, 25 is, no % sign since the question defines the answer: "What *percent* is ...."
FirstChildUserIdTAG: 398274
FirstChildUserNameTAG: aremh
FirstChildCreateTimeTAG: 2013-02-23T17:19:16Z
FirstChildVoteTAG: 2
FirstChildTAG: Live and learn.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-24T00:19:12Z
FirstChildVoteTAG: 2
FirstChildTAG: The double submissions are super useful for getting used to the phrasing for the inputs. In most of my education, I've never had to think about whether including the percent sign or not would result in an incorrect answer.
FirstChildUserIdTAG: 967698
FirstChildUserNameTAG: cb1667
FirstChildCreateTimeTAG: 2013-02-24T10:21:03Z
FirstChildVoteTAG: 0
IndexTAG: 2642
TitleTAG: General confusion re: input of answers! Instructor's input needed!
There appears to be general confusion regarding the ways in which the answers should be calculate and entered into the answer fields. Rounding up seems to be highly arbitrary, as well the instruction regarding which endpoint are included in the intervals, since I tried it both ways and the answer appears to be still wrong. I think moderators/lecturers should perhaps introduce a short tutorial about interpreting tasks. Apparently lots of us have backgrounds that make reading the instructions quite difficult.
UserIdTAG: 919769
UserNameTAG: MSpirova
CreateTimeTAG: 2013-02-23T13:34:45Z
VoteTAG: 7
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: or just make instructions more explicit :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T14:44:34Z
FirstChildVoteTAG: 1
FirstChildTAG: For this exercise, they were pretty explicit regarding the intervals. Direct from the text of the question:
> Intervals include the left endpoint but not the right;
They also asked you to round to one decimal place for all but the last question, and asked for either units of percent per year or a percent.
A big part of this course (and statistical analysis in general) is reading carefully and making sure you understand what you hav read.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T19:05:10Z
FirstChildVoteTAG: 1
SecondChildTAG: The common trap is "I'm an expert already on this subject, so I will make my own assumptions" when we should be humble and read all the instructions carefully.
There was an exam question in one of the computer science courses about a particular algorithm. A lot of students got it wrong because they assumed and did not read the codes properly (or not even read it at all). In fact the staff had reversed the algorithm so that the answer will be totally different to the common logic.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T21:03:20Z
SecondChildVoteTAG: 0
SecondChildTAG: I may never look at my credit card the same way again... ;)
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-24T14:24:37Z
SecondChildVoteTAG: 0
FirstChildTAG: Instructor input already given.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:31:04Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes. Read the question.
Half the work is done if you understand what is being asked.
FirstChildUserIdTAG: 206086
FirstChildUserNameTAG: pedrocas1972
FirstChildCreateTimeTAG: 2013-02-24T00:21:16Z
FirstChildVoteTAG: 0
SecondChildTAG: True! I had been assuming info all along! >.<
SecondChildUserIdTAG: 1018933
SecondChildUserNameTAG: IsisN
SecondChildCreateTimeTAG: 2013-02-24T03:00:50Z
SecondChildVoteTAG: 0
IndexTAG: 2643
TitleTAG: Problem 1 parts a) b) and c)
I know these are easy but I answered the first one and pressed check ! As a result got the next two wrong since I hadn't yet selected an answer !
Is there a way to rectify this ?
UserIdTAG: 1093884
UserNameTAG: farrukhazfar
CreateTimeTAG: 2013-02-23T13:08:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: and I guess question 2 doesnt want the % symbol !
FirstChildUserIdTAG: 1093884
FirstChildUserNameTAG: farrukhazfar
FirstChildCreateTimeTAG: 2013-02-23T13:30:12Z
FirstChildVoteTAG: 0
IndexTAG: 2644
TitleTAG: Built-in Calculator
In a previous edx-course which I completed, there was a built-in calculator provided at the bottom of the page. It was quite handy and I would suggest building a similar feature in this course.
UserIdTAG: 591304
UserNameTAG: KMV
CreateTimeTAG: 2013-02-23T12:56:57Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: KMV, where can i find about the calculator you had said?thanks
FirstChildUserIdTAG: 1231135
FirstChildUserNameTAG: shie112709
FirstChildCreateTimeTAG: 2013-02-23T15:26:42Z
FirstChildVoteTAG: 0
SecondChildTAG: In the top left of the screen when you are inthe courseware there is a menu drop down that has a calculator
SecondChildUserIdTAG: 160934
SecondChildUserNameTAG: DonnaC
SecondChildCreateTimeTAG: 2013-02-23T21:37:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you Donna, unfortunately, I cant seem to find it. Could you post a screenshot?
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-02-26T18:34:20Z
SecondChildVoteTAG: 0
FirstChildTAG: Wouldn't you have one from your operating system already?
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T21:25:11Z
FirstChildVoteTAG: 0
SecondChildTAG: May be but flipping between windows is at times painful(especially if you are doing it on a smartphone !!I anyway went and rewarded myself by going and buying a scientific calculator from Casio ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T05:04:33Z
SecondChildVoteTAG: 0
SecondChildTAG: A built-in feature is way handier than flipping between windows. I am not in desperate need of it, it was merely a suggestion.
SecondChildUserIdTAG: 591304
SecondChildUserNameTAG: KMV
SecondChildCreateTimeTAG: 2013-02-26T18:36:15Z
SecondChildVoteTAG: 0
IndexTAG: 2645
TitleTAG: Decimal places required not indicated in question
If the question asks for the percent, I take this to mean the integer value - so 11% of the students are seniors. The most accurate answer is 11.111111111% and recurring in fact. 11.11% is actually a more accurate answer than 11.1% which is given as the correct answer. The question should indicate how many decimal places required or accept 11% or 11.1% or 11.11% etc. All are correct, in my view.
UserIdTAG: 1295529
UserNameTAG: Paul246
CreateTimeTAG: 2013-02-23T12:52:57Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: I totally agree.Was shocked to see i was wrong in putting 11 as the answer
FirstChildUserIdTAG: 1121678
FirstChildUserNameTAG: Zumnan
FirstChildCreateTimeTAG: 2013-02-23T13:31:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Hey guys, I think here is some kind of a convention on a number of decimal places to be used.
Still, I do agree with you that all the answers should be correct unless there is clearly stated different in the question itself.
I also noticed that if the question says "How much perecents...", the answer should be only the number without "%" sign. And I think that is not so relevant, and should be taken as correct answer as well.
SecondChildUserIdTAG: 1218100
SecondChildUserNameTAG: Draxita
SecondChildCreateTimeTAG: 2013-02-23T13:58:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Hello. I agree. My answers were marked wrong just because I used 2 decimal places... Moving on, questions should state how many decimal places is required, otherwise, the number of decimals should not matter.
SecondChildUserIdTAG: 902949
SecondChildUserNameTAG: Leitich2012
SecondChildCreateTimeTAG: 2013-02-23T16:02:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Check the discussions - this has been talked about a lot and the staff are aware.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T19:08:48Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:35:06Z
FirstChildVoteTAG: 0
IndexTAG: 2646
TitleTAG: Discussion Forum Guidelines
Fellow students, apart from the honor code please also read the discussion forum guidelines as posted by staff.
You can find this on the right hand side of the Course Info, under Course Handouts or at https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/GuidelinesforStat2xDiscussionForum.pdf
UserIdTAG: 170290
UserNameTAG: jimbangun
CreateTimeTAG: 2013-02-23T12:51:07Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2647
TitleTAG: Format of answers? Exercise Set 3 Question 1
I know the whole decimal point thing has been done to death but I have just entered my first submission of answers for this question (and have got all the answers wrong. I believe my answers were correct and it is a formatting issue.
It is somewhat confusing because I am not sure if we are meant to be rounding to thousands of dollars, dollars or 1 decimal space (10's of cents) as it says in the last question.
So. How are we meant to format answers to this question?
So let us say the answer to the lower quartile is 25,003.86 (Note: That isn't the answer it is just a random number)
Do we answer: a) 25,000 b) 25,004 c) 25,003.8
I want to compliment you on the course which is very good but I do have to say these answer format issues are really frustrating me. I know you have heard that before though so sorry for moaning I just thought I would put it on record.
Thanks in advance.
UserIdTAG: 954932
UserNameTAG: hellothomasjohnson
CreateTimeTAG: 2013-02-23T12:47:09Z
VoteTAG: 1
CoursewareTAG: Exercise Set 3 / Exercise Set 3
NumberOfReplyTAG: 4
FirstChildTAG: Though it's in a funny place, the instructions next to Part c:
> Round your answer to one decimal place:
apply to all answers in Problem 1.
As a side note, if your answers are 1000 or more, do not use commas to seperate the numbers. The grader will mark it wrong. In other words, using your example, you should answer c) 25003.8 (without the comma).
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T13:00:22Z
FirstChildVoteTAG: 1
SecondChildTAG: Ok. See I thought that was only for question c since it was next to question c.
Thing is I got my question c wrong. I think I need to re-check my math.
I wasn't answering the questions with a comma but duly noted.
SecondChildUserIdTAG: 954932
SecondChildUserNameTAG: hellothomasjohnson
SecondChildCreateTimeTAG: 2013-02-23T13:08:08Z
SecondChildVoteTAG: 0
FirstChildTAG: WOW. I made the dumbest mistake. Right this is why I was so confused. I was still thinking in terms of thousands of dollars from the lecture. I just realised the data set is in age. That was my issue.
*slaps forehead*
FirstChildUserIdTAG: 954932
FirstChildUserNameTAG: hellothomasjohnson
FirstChildCreateTimeTAG: 2013-02-23T13:15:16Z
FirstChildVoteTAG: 0
SecondChildTAG: So to clarify, with the example I gave above I was entering 25003.86 rather than 25.
SecondChildUserIdTAG: 954932
SecondChildUserNameTAG: hellothomasjohnson
SecondChildCreateTimeTAG: 2013-02-23T13:19:07Z
SecondChildVoteTAG: 0
FirstChildTAG: frustrating that this thread OP titled it Set 3 Question 1 when there is actually no discussion on Set 3 Question 1.
I will pose my question in another thread.
FirstChildUserIdTAG: 501764
FirstChildUserNameTAG: dasMetzger
FirstChildCreateTimeTAG: 2013-02-23T15:12:13Z
FirstChildVoteTAG: 0
FirstChildTAG: I answered 1a with 1 decimel, 1b with 2 decimels and 1c with one decimel. All are correct. I donno if it is an issue for some.
FirstChildUserIdTAG: 1268152
FirstChildUserNameTAG: naniglavs
FirstChildCreateTimeTAG: 2013-02-23T17:07:10Z
FirstChildVoteTAG: 0
IndexTAG: 2648
TitleTAG: The decimals?
It's better solution 1/9 and 2/9.
UserIdTAG: 1265154
UserNameTAG: ToniEscudero
CreateTimeTAG: 2013-02-23T12:27:53Z
VoteTAG: 2
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: helo!!yes I like this answers.Is it possible to use them?
FirstChildUserIdTAG: 1093938
FirstChildUserNameTAG: Douna
FirstChildCreateTimeTAG: 2013-02-25T22:56:42Z
FirstChildVoteTAG: 0
IndexTAG: 2649
TitleTAG: Exercise 2, problem 3.b
diagram b & c showed only 5 column, missing 16-17.
diagram a gets incorrect response. Why?
UserIdTAG: 538792
UserNameTAG: HtayOung
CreateTimeTAG: 2013-02-23T12:23:52Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I think all answers are incorrect. I only see three graphs, the only one with all the ranges is the first one, but in my opinion this is not a correct histogram for the data in the table.
Is this a tricky question where you don't have to select any answer?
FirstChildUserIdTAG: 892513
FirstChildUserNameTAG: rfvizarra
FirstChildCreateTimeTAG: 2013-02-23T12:46:50Z
FirstChildVoteTAG: 1
FirstChildTAG: There is a "correct" answer, that is "less wrong" than the other 2.
Honor Code prevents going into anymore detail.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T13:04:02Z
FirstChildVoteTAG: 1
SecondChildTAG: That is my point, "less wrong" is not correct. Is that intentional (meaning it is really correct)? or is it a mistake/error?
SecondChildUserIdTAG: 892513
SecondChildUserNameTAG: rfvizarra
SecondChildCreateTimeTAG: 2013-02-23T16:10:45Z
SecondChildVoteTAG: 0
IndexTAG: 2650
TitleTAG: Correct answer
It is actually 11.11 & 22.22 I wrote that the answer was wrong is there a different between 11.1 and 11.1
UserIdTAG: 1028056
UserNameTAG: Neamat
CreateTimeTAG: 2013-02-23T12:14:49Z
VoteTAG: 1
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Same happened to me! I used two decimal places and it was considered wrong!! this should be clear
FirstChildUserIdTAG: 950592
FirstChildUserNameTAG: natisanga
FirstChildCreateTimeTAG: 2013-02-24T23:58:57Z
FirstChildVoteTAG: 0
IndexTAG: 2651
TitleTAG: To the teachers: exercises in PDF
Please, it will be greatly appreciated if we can have the exercises or problem sets in downloadable PDF so that we can print it out and work it out offline and link up to insert the solutions online due to limited internet access. Thank you.
UserIdTAG: 781221
UserNameTAG: Toluvic
CreateTimeTAG: 2013-02-23T11:50:52Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: If you use Chrome as your browser, it has Print to PDF functionality built in. Just print, and select "Save as PDF" as your printer.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T12:09:32Z
FirstChildVoteTAG: 2
SecondChildTAG: yes, or just use Print Screen and print as an image file (paste to PowerPoint for example, then print the PowerPoint page).
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T12:13:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Best bet - for offline access, just print direct to a printer and don't worry about being fancy. :)
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-23T13:05:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes, just print them yourself!
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T22:36:43Z
FirstChildVoteTAG: 1
FirstChildTAG: I use Firefox, v. 19.0. I'd like to print my completed quiz (before submission, or in this case because I'm too late for submission) to PDF. But printing to PDF gives me garbled text. Nothing readable.
For example, under Exercise 2:
This exercise set is worth 20 points. A m ore detailed breakdow n is provided in each problem . If a problem has several
steps, try not to round off too m uch in the early steps, or else your later calculations m ight end up quite far from the
correct answ er.
OK, that is bizarre -- in the PDF, the above shows up as junk text -- unreadable.
Well, I no longer know what to ask. Is "print to PDF" working for others in a different browser? For now I'm selecting text and copying it into Word. I have to reinsert my answers, but at least I get the context along with my answers.
Thanks for any advice.
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-02-28T02:32:47Z
FirstChildVoteTAG: 1
IndexTAG: 2652
TitleTAG: % symbol in answers
All my answers were correct but the system cut all the answers that had the % symbol in it. For instance, in Problem 6 the question "What percent of students spent fewer than 4 hours in preparation?". I answered "10%" and it was wrong.
Can you be more specific about the type of characters that are required on each answer?
I should have had a 100% score on this test.
Thank you
UserIdTAG: 1217888
UserNameTAG: salomeareias
CreateTimeTAG: 2013-02-23T11:46:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Man, take a good look at the "Practice for Exercise Set 1". There you can find how to write the percent answers.
FirstChildUserIdTAG: 1091568
FirstChildUserNameTAG: Yughues
FirstChildCreateTimeTAG: 2013-02-23T12:21:11Z
FirstChildVoteTAG: 0
SecondChildTAG: salomerais has a point I submitted one answer with the percentage symbol and one without, the one without was marked correct.
I think when the question says "what percent of such and such.." the units of percentage have already been implied. So even if it is correct and you insert % there, you will get it wrong.
Which is a bit odd
SecondChildUserIdTAG: 1093884
SecondChildUserNameTAG: farrukhazfar
SecondChildCreateTimeTAG: 2013-02-23T13:32:15Z
SecondChildVoteTAG: 0
IndexTAG: 2653
TitleTAG: Incorrect Calculation
The height of -10 to 20 bar is calculated as 14%/(20-(-10)), which gives 0.467% per unit. Surely, there has been a mistake by the person who input the Answer in the system.
UserIdTAG: 1245010
UserNameTAG: JBenkie
CreateTimeTAG: 2013-02-23T11:41:18Z
VoteTAG: 10
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: Yes, it is a mistake.
And perhaps your mistake was to not search the other posts before posting this one as the issue has been discussed in so many other posts. :-)
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T11:48:54Z
FirstChildVoteTAG: 3
FirstChildTAG: Yes, that's a mistake. The difference between -10 and 20 is 30.
FirstChildUserIdTAG: 996971
FirstChildUserNameTAG: ntanhhong
FirstChildCreateTimeTAG: 2013-02-24T06:01:22Z
FirstChildVoteTAG: 0
IndexTAG: 2654
TitleTAG: Questions 2 and 4!!!!!! Please help
I can't figure out how these two questions should be done. Please help me to understand.
UserIdTAG: 1053356
UserNameTAG: Evakant
CreateTimeTAG: 2013-02-23T11:25:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: What exactly are you having trouble with?
I suggest reviewing the lecture videos, particularly the lecture, "Units and Density". The professor explains how to solve these types of problems.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T12:12:28Z
FirstChildVoteTAG: 1
FirstChildTAG: Don't get intimidated with the long sentences....keep it simple....everything has been discussed in the lectures although we are expected to use some common sense and logic as well.
Have a look at the other posts on the same subject. They could help too.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T12:16:24Z
FirstChildVoteTAG: 2
IndexTAG: 2655
TitleTAG: where are the data?
i don´t find the data for this exercise. They are not figure 3.3
UserIdTAG: 1134470
UserNameTAG: cpaula
CreateTimeTAG: 2013-02-23T11:22:55Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 3 / Reading and practice for Exercise Set 3
NumberOfReplyTAG: 3
FirstChildTAG: You are told that the first question uses data from the lecture. Then the last question uses the gravity data, which is in the course online text book (scroll up to Table 3-4)
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:28:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Table 3-4: Sorted gravity data.
These data are not income data .
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-02-23T14:45:38Z
SecondChildVoteTAG: 0
SecondChildTAG: You can get the income data in the Lecture 2.4 slides or by pausing the lecture when Prof A reviews them. If you click on the left, Section 2b The Histogram, there is Lecture 2.4 and 2.5. If your screen only shows option for Lecture 2.5 slides, click at the top to change to the first portion of the lecture. Good luck!
SecondChildUserIdTAG: 919227
SecondChildUserNameTAG: L_Newman
SecondChildCreateTimeTAG: 2013-02-24T17:14:02Z
SecondChildVoteTAG: 0
SecondChildTAG: it s above in the online textbook, quite a bit above, scroll up til u find the gravity data, it s neatly sorted in a hundred data points for you.
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-02-25T16:10:37Z
SecondChildVoteTAG: 0
FirstChildTAG: cpaula, I think you are confusing **"textbook"** (male instructor, real live video, gravity data) and **"lecture"** (female instructor, animated video, income data). In Courseware/General Course Information/Week 1, look for entries starting with Lec for LECTURE. You have to play these lectures to get the income data.
It is very helpful to write the income data and supporting info down on paper or screen-print it.
Hope this helps.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-23T17:36:52Z
FirstChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/lec2.4.pdf
SecondChildUserIdTAG: 971201
SecondChildUserNameTAG: peterlaube
SecondChildCreateTimeTAG: 2013-02-24T18:06:40Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks
SecondChildUserIdTAG: 1134470
SecondChildUserNameTAG: cpaula
SecondChildCreateTimeTAG: 2013-02-25T18:49:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Staff: Recommend putting data next to the questions - on practice and exercises.
Why: Trying to find the data set the question is referring to on a different webpage, during the recorded lecture, or at the top of a scrolling screen, and then trying to look between the two sources on a laptop computer screen...this is not efficient or user-friendly. I believe this change will improve the value of your course. Thank you.
FirstChildUserIdTAG: 1040692
FirstChildUserNameTAG: viperdriver
FirstChildCreateTimeTAG: 2013-02-25T00:18:30Z
FirstChildVoteTAG: 3
SecondChildTAG: i actually like it. statistics os griddy and dirty and you sometimes have to find your data at different locations... it's just a few clicks.
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-02-25T16:11:44Z
SecondChildVoteTAG: 0
IndexTAG: 2656
TitleTAG: decimal point
It is not described that how many decimal points we have to use in the question.
UserIdTAG: 1106581
UserNameTAG: Beann
CreateTimeTAG: 2013-02-23T11:18:21Z
VoteTAG: 11
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Use one dp.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:19:41Z
FirstChildVoteTAG: 1
IndexTAG: 2657
TitleTAG: kindly sent to me lecture link
kindly sent to me lecture link n study material asap
UserIdTAG: 1269647
UserNameTAG: abdaal
CreateTimeTAG: 2013-02-23T11:16:28Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Why? You can get them yourself on the courseware tab. You need to explore the course webpages, and see what's what.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:20:02Z
FirstChildVoteTAG: 1
IndexTAG: 2658
TitleTAG: To Teacher: is it possible to have lecture slides on PDF?
It would be nice, to have slides to review the lectures easiest when we are doing the Problem Sets, thanks.
UserIdTAG: 692378
UserNameTAG: JorgeSeifert
CreateTimeTAG: 2013-02-23T10:54:12Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: The lecture slides are available as a pdf.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:04:39Z
FirstChildVoteTAG: 0
FirstChildTAG: you can. Check below the video, where it says "Lecture X.X slides" ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T11:38:46Z
FirstChildVoteTAG: 0
SecondChildTAG: Ohh!, I`m sorry, Thanks!!
SecondChildUserIdTAG: 692378
SecondChildUserNameTAG: JorgeSeifert
SecondChildCreateTimeTAG: 2013-02-23T12:02:10Z
SecondChildVoteTAG: 0
IndexTAG: 2659
TitleTAG: more than 3 minutes...
if I say " I spend more than 3 min in bathroom",... I spend 4 min or more ... or I spend 3 min or more...
UserIdTAG: 1134470
UserNameTAG: cpaula
CreateTimeTAG: 2013-02-23T10:37:38Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: 3 minutes and 1 second is more than 3 minutes
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:05:29Z
FirstChildVoteTAG: 0
SecondChildTAG: where can i get the homework and lecture notes for the course?
SecondChildUserIdTAG: 1297223
SecondChildUserNameTAG: FRANKQUAQUAH
SecondChildCreateTimeTAG: 2013-02-23T17:58:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Homework is at the end of each lecture- look at the exercise sets in the courseware section.The lectures are there in the courseware too.Also the textbook Online) is mentioned in the wiki section incidentally the URL is
http://statistics.berkeley.edu/~stark/SticiGui/
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T05:06:52Z
SecondChildVoteTAG: 0
IndexTAG: 2660
TitleTAG: Problem 1.b
One of the answers was spelled wrongly.That is catagorical instead of categorical.I don't really know if it was deliberately done. it really affected the choice of my answer.I really want to know if that was a wrong spelling or it was deliberate.
UserIdTAG: 1197575
UserNameTAG: asanteenock74
CreateTimeTAG: 2013-02-23T10:31:12Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It is a typographical error, as 'catagorical' is not a word. It was not deliberately done.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T12:16:03Z
FirstChildVoteTAG: 0
SecondChildTAG: Does not seem fair, doesn't it?
SecondChildUserIdTAG: 400714
SecondChildUserNameTAG: edipasquale
SecondChildCreateTimeTAG: 2013-02-23T15:33:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Not fair? Really?
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T21:44:18Z
SecondChildVoteTAG: 0
IndexTAG: 2661
TitleTAG: problem 4
I don´t understand the question. Perhaps it´s due the english language. Can anybody translate me the question into spanish?
En EEUU los diplomas se dan tras pasar 12 años en la escuela. Qué intervalo contiene a los alumnos que han pasado 12 años en la escuela y no han obtenido su diploma? Es asi?
UserIdTAG: 1134470
UserNameTAG: cpaula
CreateTimeTAG: 2013-02-23T10:22:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: Don't translate into Spanish please!!! Rather, explain it to all who need. I also don't see how it is done but I don't speak Spanish.
FirstChildUserIdTAG: 1053356
FirstChildUserNameTAG: Evakant
FirstChildCreateTimeTAG: 2013-02-23T11:22:04Z
FirstChildVoteTAG: 0
FirstChildTAG: You have a choice between several intervals. You need to choose the one that includes the people who had exactly 12 years of education(schooling). Part b is the same, only it's about those with 16 years of education.
With Honor Code still holding, I really can't say more than this.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T11:44:41Z
FirstChildVoteTAG: 3
FirstChildTAG: cpuala: Si, es asi.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T12:19:34Z
FirstChildVoteTAG: 0
FirstChildTAG: Hello,
May be this link to Wiki will help: in English –
http://en.wikipedia.org/wiki/Education_in_the_United_States, and in Spanish –
http://es.wikipedia.org/wiki/Sistema_educativo_de_Estados_Unidos.
Me too, I live on another continent how I can know something about American education? When children go to school for the first time? Google always help :)
FirstChildUserIdTAG: 1071309
FirstChildUserNameTAG: _Helena_
FirstChildCreateTimeTAG: 2013-02-25T12:13:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Any way, I lost! Even Wiki doesn’t help.
SecondChildUserIdTAG: 1071309
SecondChildUserNameTAG: _Helena_
SecondChildCreateTimeTAG: 2013-02-25T12:18:27Z
SecondChildVoteTAG: 0
IndexTAG: 2662
TitleTAG: Judwin
what is an ordinate variable? Didnt quite get that
UserIdTAG: 1040144
UserNameTAG: Judwin
CreateTimeTAG: 2013-02-23T09:59:44Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: My mnemonic is Nominal - **N**ame ie *N*ominal variables have a name like blue/green etc.*Ord*inal variables have an *Ord*er ie they can be ordered - for eg big bigger and best.
thus beauty- beautiful and ugly is categorical whereas if you where to call people as good looking , wonderful looking and ravishing it is ordinal whereas if we were to use a scale of milliHelens (The face which can launch one thousand boats = One Helen ala the Iliad) then milliHelens is a discrete quantitative data if we can categorize by a face that can launch of discrete number of boats whereas if we could launch 1.5 or 1.3 boats (imagine miniboats or lifeboats with the main boat) then it becomes quantitative continuous variable ;)
Hope this helps.
The Professors ("Tell me O Muse") please correct my description if there are errors!!
Sorry for the Iliad rant - weekend and couldn't resist.Calliope and Thalia got the better of me.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T10:33:50Z
FirstChildVoteTAG: 3
SecondChildTAG: Prasannasimha, THAT was an unexpectedly lovely response. Thank you for adding a bit of beauty to our statistics course!
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-23T15:26:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks .I am a teacher by profession (Professor of cardiac surgery) (in the difficult position of being a student now !!) and so love to make visual allegories when teaching as it helps learning and the technique helps retain information too.Anyway we do need some fun too when learning and clicking the answers to check if right or wrong is giving me the heejibeejies so need to "loosen up" intermittently for efficiency-Easier to be a teacher than a student when being assessed ;)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T17:32:51Z
SecondChildVoteTAG: 0
SecondChildTAG: ps MyOwnCamera I did like the play and pun on the beauty thing !!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T17:34:10Z
SecondChildVoteTAG: 0
IndexTAG: 2663
TitleTAG: problem1(e)
i don't understand the type of variable about "weight to the nearest kilogram". Does Anyone can help me?
UserIdTAG: 1031881
UserNameTAG: 19850524
CreateTimeTAG: 2013-02-23T09:19:58Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Discrete quantitative as you are making the intervals of measurement discrete(ie you are approximating to the nearest Kg ) So 2.4 Kg would be 2 Kg and 2.6 Kg is 3 Kg and 3.2 Kg is 3 Kg if the measurement precision is kept at one kg.(Using the 0.5 principle of rounding of.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T09:57:38Z
FirstChildVoteTAG: 1
FirstChildTAG: It means you round up the value to the closest integer number of kg. For example,
3.72 kg -> 4 kg
16.18 kg -> 16 kg
35.48 kg -> 35 kg
FirstChildUserIdTAG: 272376
FirstChildUserNameTAG: massys
FirstChildCreateTimeTAG: 2013-02-23T10:00:39Z
FirstChildVoteTAG: 1
FirstChildTAG: Well, I would debate this.
If we are in a scale of human weights then this might be true, but say, for example, we are looking at the weight of blue whales or elephants or perhaps asteroids that might hit earth... then the rounding off is about the precision of measurement and not about discrete quantities.
FirstChildUserIdTAG: 917995
FirstChildUserNameTAG: bainusanet
FirstChildCreateTimeTAG: 2013-02-23T21:57:25Z
FirstChildVoteTAG: 0
SecondChildTAG: Indeed it is always related to the precision of measurement and heasked to "the nearest kilogram"
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T05:08:12Z
SecondChildVoteTAG: 0
IndexTAG: 2664
TitleTAG: Anand
Under Lectures 2.2 and 2.3, for a), the width of the interval -10 to 20 is 30. But in the solution you have taken it as 10
UserIdTAG: 1245847
UserNameTAG: anandareddyn
CreateTimeTAG: 2013-02-23T09:19:21Z
VoteTAG: 13
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: It's a mistake. Its reported in the courseware errata in the Wiki!
FirstChildUserIdTAG: 272376
FirstChildUserNameTAG: massys
FirstChildCreateTimeTAG: 2013-02-23T10:02:01Z
FirstChildVoteTAG: 2
SecondChildTAG: I think the +/- sign doesn not matter when we are considering the width, only the numericals matter. Hence the width would be 20-10= 10
SecondChildUserIdTAG: 169509
SecondChildUserNameTAG: rajeevbasapathy
SecondChildCreateTimeTAG: 2013-02-23T10:42:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, its been driving crazy, glad to know its an error.
SecondChildUserIdTAG: 1247361
SecondChildUserNameTAG: Jay595
SecondChildCreateTimeTAG: 2013-02-23T10:52:03Z
SecondChildVoteTAG: 0
SecondChildTAG: rajeevbasapathy: That is not correct; the signs definitely matter. Imagine a number line. The distance from 10 to 20 is different than the distance from -10 to 20.
However, as mentioned, this has been covered a lot. Search the discussions and/or check the Wiki.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-23T12:22:17Z
SecondChildVoteTAG: 0
FirstChildTAG: > It's a mistake. Its reported in the courseware errata in the Wiki!
And not only there! A quick look at past posts, made much easier now, would show multiple posts about this.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:09:32Z
FirstChildVoteTAG: 0
IndexTAG: 2665
TitleTAG: problem 3 (b)
i don't understand how plants contain green is equal to which not contain green.
thank you
UserIdTAG: 1180746
UserNameTAG: ahmadalshalaby
CreateTimeTAG: 2013-02-23T08:10:49Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No one said they are equal. You just have to do the math: add the number of plants that contain green (magenta-green + red-green) and then the number of plants that not contain green (magenta red + red red). It helps to do a graph of how they would look like after having the numbers.
FirstChildUserIdTAG: 647201
FirstChildUserNameTAG: Andrei_Mihai
FirstChildCreateTimeTAG: 2013-02-23T11:10:20Z
FirstChildVoteTAG: 0
IndexTAG: 2666
TitleTAG: Exercises
Would it be possible to have clearer guidance with the exercises please? About:
How many decimal points
are fractions accepted (when relevant)
whether to include percentage sign
I have found the wording of some of the questions potentially ambiguous (e.g., 'over 65' to mean 65 or over)
And there appear to be one or two errors too in the answers treated as correct
Sorry for moaning, the course is great
UserIdTAG: 1004185
UserNameTAG: ale1808
CreateTimeTAG: 2013-02-23T08:09:09Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I would also appreciate some clarity on how the answers are expected e.g. when asked about a percentage when should we include the percentage sign and when not to and how many decimal points are wanted, etc. I got the practice exercise wrong several times simply because I did not know the convention needed, rather than because I didn't know the answer or how to work it out, and I would hate to get the graded exercises wrong for this reason!
Many thanks!
FirstChildUserIdTAG: 970593
FirstChildUserNameTAG: justpenny
FirstChildCreateTimeTAG: 2013-02-23T11:06:47Z
FirstChildVoteTAG: 0
FirstChildTAG: This has been addressed. Hopefully in future questions these issues won't arise.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:10:36Z
FirstChildVoteTAG: 0
IndexTAG: 2667
TitleTAG: endpoint convention
Can we not have a category that says >150000 U S dollars?
UserIdTAG: 1258579
UserNameTAG: shalinicn
CreateTimeTAG: 2013-02-23T07:43:37Z
VoteTAG: 1
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.2. How to draw a histogram
NumberOfReplyTAG: 3
FirstChildTAG: Not really, as that category would have an infinite width and thus render the histogram impossible to draw.
**But** if you were the one compiling the table, you *could* have put other higher categories, like 150-1000 and 1000-2000, but the percentages for them would be so small that they would hardly be significant(less that 1%), and the compiler decided to include them into the 100-150 category.
At least, that's how I see it. Feel free to correct if necessary ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-23T11:52:34Z
FirstChildVoteTAG: 2
FirstChildTAG: You can have open categories but then the problem is that it will be difficult to calculate as the final interval will be infinite.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T12:13:49Z
FirstChildVoteTAG: 0
FirstChildTAG: If the number of people in the category are so insignificant, why include them in the data at all, one could just make a graph about the distribution of incomes <150,000. How would we even know if the data was swept in, would the graph explicitly say so, or do we just assume it?
FirstChildUserIdTAG: 838733
FirstChildUserNameTAG: Ronnicus
FirstChildCreateTimeTAG: 2013-03-09T21:47:57Z
FirstChildVoteTAG: 0
IndexTAG: 2668
TitleTAG: Stat2.1x hashtag? #bxstat
Hello all, does this course have a twitter hashtag? I've found that being able to share impressions with fellow students on twitter is a very helpful factor both in mutual motivation and identifying any problems quickly.
If there is not one yet, may I suggest #bxstat
Fellow tweeps can find me on @BrynRWilliams
PS Anyone else here referred by #LAK13 ?
UserIdTAG: 1286101
UserNameTAG: myndworkz
CreateTimeTAG: 2013-02-23T07:07:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Agree. Twitter interaction is very useful.
I second the motion to use #bxstat
FirstChildUserIdTAG: 1295317
FirstChildUserNameTAG: AprilH
FirstChildCreateTimeTAG: 2013-02-23T12:25:45Z
FirstChildVoteTAG: 0
IndexTAG: 2669
TitleTAG: Task error
Excercise set 2, task to lecture 2.2, a.
a) Height of -10 to 20 bar = ____________ % per unit
EXPLANATION
The height of a bar is equal to: relative frequency in the class interval/width of class interval. Therefore, the height of the -10 to 20 bar is 14/10 = 1.4% per unit.
BUT! width of class interval is 20 - (-10) = 30 units? just like in task b), where class interval is (from 20 to 50)
Thanks.
UserIdTAG: 719514
UserNameTAG: JasonDinAlt
CreateTimeTAG: 2013-02-23T07:01:18Z
VoteTAG: 5
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: there are already numerous posts on this subject, so feel free to use the search function of the discussion forum.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T07:27:25Z
FirstChildVoteTAG: 1
FirstChildTAG: Please, read the forum. Now that we have subforums there should be no need for repeat posts. Just look before posting!
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:11:20Z
FirstChildVoteTAG: 2
IndexTAG: 2670
TitleTAG: Improvement suggestion
i suggest to add an example of the expected answer
because i believe many people are getting the correct answers but losing points
because they do not know how to enter the number
for example :
if i get 11.96 with one decimal round off
should i enter 11.9 or 12
please remember some of us are not aware of the terminology in English
UserIdTAG: 1047522
UserNameTAG: daveBen
CreateTimeTAG: 2013-02-23T06:33:59Z
VoteTAG: 14
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: I agree. What happens to 11.95? There should be the answer with explanation. Thanks.
FirstChildUserIdTAG: 1193379
FirstChildUserNameTAG: Iraj
FirstChildCreateTimeTAG: 2013-02-23T11:27:17Z
FirstChildVoteTAG: 0
SecondChildTAG: 11.95 rounds of even at one decimal place to 12 as every decimal .....5 and above gets shifted over and added by .....1(respective place) so this causes a cascading effect on the 9's which adds up till the initial digit.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T12:20:32Z
SecondChildVoteTAG: 0
SecondChildTAG: This may help
[Rounding numbers][1]
Some more help from Wikipedia
Tie-breaking
Rounding a number y to the nearest integer requires some tie-breaking rule for those cases when y is exactly half-way between two integers — that is, when the fraction part of y is exactly 0.5.
[edit]Round half up
The following tie-breaking rule, called round half up (or round half towards plus infinity), is widely used in many disciplines. That is, half-way values y are always rounded up.
If the fraction of y is exactly 0.5, then q = y + 0.5.
For example, by this rule the value 23.5 gets rounded to 24, but −23.5 gets rounded to −23.
This is one of two rules generally taught in US elementary mathematics classes.[citation needed] However, some programming languages (such as Java) define HALF_UP as round half away from zero.[2]
If it were not for the 0.5 fractions, the roundoff errors introduced by the round to nearest method would be symmetric: for every fraction that gets rounded up (such as 0.268), there is a complementary fraction (namely, 0.732) that gets rounded down by the same amount. When rounding a large set of numbers with random fractional parts, these rounding errors would statistically compensate each other, and the expected (average) value of the rounded numbers would be equal to the expected value of the original numbers.
However, the round half up tie-breaking rule is not symmetric, as the fractions that are exactly 0.5 always get rounded up. This asymmetry introduces a positive bias in the roundoff errors. For example, if the fraction of y consists of three random decimal digits, then the expected value of q will be 0.0005 higher than the expected value of y. For this reason, round-to-nearest with the round half up rule is also (ambiguously) known as asymmetric rounding.
One reason for rounding up at 0.5 is that for positive decimals, only the one figure before the decimal point needs be examined. For example, when looking at 17.5000…, the "5" alone determines that the number should be rounded up, to 18 in this case. This is not true for negative decimals, such as −17.5000…, where all the fractional figures of the value need to be examined to determine if it should round to −17, if it were −17.5000000, or to -18, if it were −17.5000001 or larger.
If you want to read more of the intricacies
[Rounding from Wikipedia][2]
Hope these help
[1]: http://academic.brooklyn.cuny.edu/geology/leveson/core/linksa/roundoff.html
[2]: http://en.wikipedia.org/wiki/Rounding
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T12:24:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Prasannasimha, it was really interesting, thank you. I believe I have once heard of another rule for 0.5 rounding: that you should round to the even numbers. So 4.5 would give 4, while 5.5 would give 6.
Oh, I just found it:
http://mathforum.org/library/drmath/view/58972.html
SecondChildUserIdTAG: 517550
SecondChildUserNameTAG: Ewa_G
SecondChildCreateTimeTAG: 2013-02-23T14:56:31Z
SecondChildVoteTAG: 0
SecondChildTAG: Indeed there are different conventions to add to the confusion but usually rounding off is done inthe manner mentioned in the main section.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-24T05:10:00Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree! Other EdX courses gave up to 10 tries to realize what you were doing wrong with the units (I wouldn't have known not to put % or how many decimal places if it weren't for the retries and then reading people's comments). Also having a built in calculator would be nice to.
SecondChildUserIdTAG: 466283
SecondChildUserNameTAG: optobeagle
SecondChildCreateTimeTAG: 2013-02-27T06:53:57Z
SecondChildVoteTAG: 0
FirstChildTAG: > please remember some of us are not aware of the terminology in English
A prerequisite of the course is good comprehension of English.
If you are rounding 11.96 it depends on the dps you want. If you want one dp, then you would round to 12. As you round the 9 up one.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:34:48Z
FirstChildVoteTAG: 1
SecondChildTAG: Many people do understand English but there are particular usages that may be confusing so I would not be so harsh on that;)
As far as rounding of 11.96 it still remains 12 whether it is to one decimal point or none as every value 0.5 and above moves up so for eg 11.999 still rounds up to 12 whether rounding off to one or two decimal places.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-23T12:18:18Z
SecondChildVoteTAG: 0
SecondChildTAG: More correctly, 11.96 rounded to one decimal place is 12.0; rounded to none it is 12. The zero after the decimal point is required in the first instance. Similarly, 11.999 to 2 decimal places is 12.00.
SecondChildUserIdTAG: 57456
SecondChildUserNameTAG: CCS
SecondChildCreateTimeTAG: 2013-02-27T18:07:59Z
SecondChildVoteTAG: 0
IndexTAG: 2671
TitleTAG: about the steam and leaf
you said that it is a wonderful way to summarize a simple and modest data set, can you quantify it? i.e upto what maximum no. we can use that steam and leaf model easily
UserIdTAG: 786009
UserNameTAG: amolg83
CreateTimeTAG: 2013-02-23T06:23:54Z
VoteTAG: 2
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.1. Describing one quantitative variable
NumberOfReplyTAG: 1
FirstChildTAG: I think this was mentioned by the professor in the videos. There is no exact figure but as it gets larger or if the data set all starts with the same digits (e.g. '6') then this method is no longer effective, hence the method(s) described in the next videos
are used instead.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T07:25:27Z
FirstChildVoteTAG: 2
SecondChildTAG: I'd agree that larger data sets fall of in effectiveness with the tastes and laziness of the user, but I think you can easily get round all the data starting with the same digit with a quick reformat of the diagram
63 | 7899
64 | 01124589
65 | 01335
SecondChildUserIdTAG: 1030056
SecondChildUserNameTAG: RBartram
SecondChildCreateTimeTAG: 2013-02-23T10:33:04Z
SecondChildVoteTAG: 0
SecondChildTAG: yes, you can do that too.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T10:56:58Z
SecondChildVoteTAG: 0
SecondChildTAG: but then, you would have a lot of rows instead of a lot of columns(10 rows per first digit instead of 1).
A slight improvement, perhaps, but still limited in how far it can go.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-23T11:56:20Z
SecondChildVoteTAG: 0
SecondChildTAG: lol, I guess that is why this method is not the best method to use,... :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T12:07:51Z
SecondChildVoteTAG: 0
SecondChildTAG: Tukeys stem and leaf plot is and excellent way of deducing inferences from a small set of data may be upto 50 variables....
SecondChildUserIdTAG: 898629
SecondChildUserNameTAG: sureshag27
SecondChildCreateTimeTAG: 2013-02-25T05:04:03Z
SecondChildVoteTAG: 0
IndexTAG: 2672
TitleTAG: will Practice session include in total grade?
will Practice session include in total grade?
UserIdTAG: 222188
UserNameTAG: DrArya2012
CreateTimeTAG: 2013-02-23T06:22:19Z
VoteTAG: 0
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: No. You can click on 'Progress' on the top'menu bar and it will show you a graph of course elements counted towards the total grade.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T07:30:34Z
FirstChildVoteTAG: 1
IndexTAG: 2673
TitleTAG: QUESTION 2. B
QUESTION 2. B, I got the wrong answer assuming that by over 65 we were not meant to include the percentage of people exactly 65, as you did not say "including", then I got the right answer by including the percentage who were exactly 65 in the calculation, was this a coincidence? or was the question worded wrong?
UserIdTAG: 968266
UserNameTAG: bubblemuffin
CreateTimeTAG: 2013-02-23T06:05:46Z
VoteTAG: 13
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 4
FirstChildTAG: oh. thanks for this information. i was also wondering what is wrong with my answer, as i was also not including 65.
FirstChildUserIdTAG: 532707
FirstChildUserNameTAG: S_Q
FirstChildCreateTimeTAG: 2013-02-23T06:09:22Z
FirstChildVoteTAG: 1
SecondChildTAG: yeah I got it wrong to as I excluded people with age 65. thanks for sharing.
SecondChildUserIdTAG: 358255
SecondChildUserNameTAG: drnidhi27
SecondChildCreateTimeTAG: 2013-02-23T06:19:06Z
SecondChildVoteTAG: 0
SecondChildTAG: that's why they gave two submissions for that i guess.
SecondChildUserIdTAG: 1096291
SecondChildUserNameTAG: Mercurian
SecondChildCreateTimeTAG: 2013-02-23T06:27:37Z
SecondChildVoteTAG: 0
SecondChildTAG: Common!
"person over the age of 65", it is the same is "people are allowed to buy alcohol if their age is over 21". It DOES mean you can buy it of you are 21.
Same with senior citizen.
SecondChildUserIdTAG: 1286060
SecondChildUserNameTAG: Calliditas
SecondChildCreateTimeTAG: 2013-02-23T07:30:35Z
SecondChildVoteTAG: 0
SecondChildTAG: Callidas independently whether or not it is in common use at times, it is still misleading and not the phrasing adopted in law. I do hope that problems such as this one are avoided in future
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-23T07:54:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Can someone please explain me the right answer. i'm not able to figure it out.
SecondChildUserIdTAG: 169509
SecondChildUserNameTAG: rajeevbasapathy
SecondChildCreateTimeTAG: 2013-02-23T10:55:17Z
SecondChildVoteTAG: 0
SecondChildTAG: In my native language "over' means without 65 so 66+, so I wonder if this is my error or EDX error, or am I completely wrong with procedure, previous answer was correct so the algorithm is similar I think
SecondChildUserIdTAG: 1215306
SecondChildUserNameTAG: bkaczy
SecondChildCreateTimeTAG: 2013-02-23T18:04:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Well.. you are 65 on your 65th birthday. Every day after that you are 65.003, 65.006, etc..
i.e. "over 65"
SecondChildUserIdTAG: 1244133
SecondChildUserNameTAG: SQL-man
SecondChildCreateTimeTAG: 2013-02-26T03:24:45Z
SecondChildVoteTAG: 0
SecondChildTAG: Correct English would say A common (though not universal) definition of "senior citizen" is "person aged 65 or over". It did not occur to me that you were defining "person over the age of 65" to include 65 so i got the question wrong.
SecondChildUserIdTAG: 475252
SecondChildUserNameTAG: pkennedy7
SecondChildCreateTimeTAG: 2013-02-27T01:25:51Z
SecondChildVoteTAG: 0
SecondChildTAG: hmm,I got the wrong answer. But did you add up the (percentage)people over the 75. By how much do you multiply the hеight of the 65-75 range?
thanks,
(:
SecondChildUserIdTAG: 1270740
SecondChildUserNameTAG: martinov
SecondChildCreateTimeTAG: 2013-02-27T22:51:12Z
SecondChildVoteTAG: 0
FirstChildTAG: As per the include left point convention used you would include 65
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-23T08:40:58Z
FirstChildVoteTAG: 0
SecondChildTAG: The convention given, is related to the data in the histogram. The definition of "senior citizen" might be coming from a different system, with a different convention.
Though this information is missing, thus one should assume that the same convention should be used...
SecondChildUserIdTAG: 922465
SecondChildUserNameTAG: vhermecz
SecondChildCreateTimeTAG: 2013-02-23T13:00:26Z
SecondChildVoteTAG: 0
SecondChildTAG: I also think the question was worded wrong. "Over 65" is not the same as "65 and over". This is a math course and specificity is important.
SecondChildUserIdTAG: 1085170
SecondChildUserNameTAG: LionelHutz
SecondChildCreateTimeTAG: 2013-02-23T18:49:11Z
SecondChildVoteTAG: 0
SecondChildTAG: yeah right!!!....65 and over should have been the statement of the question instead....coz using "over 65"...i got the wrong answer too.
SecondChildUserIdTAG: 432151
SecondChildUserNameTAG: rgdixit
SecondChildCreateTimeTAG: 2013-02-23T20:06:24Z
SecondChildVoteTAG: 0
SecondChildTAG: I think in answering that question you have to take into consideration the fact that the endpoint convention says to include from the left and not the right.
SecondChildUserIdTAG: 606994
SecondChildUserNameTAG: Makiblue
SecondChildCreateTimeTAG: 2013-02-28T04:58:01Z
SecondChildVoteTAG: 0
FirstChildTAG: > Can someone please explain me the right answer. i'm not able to figure it out.
No. This is an assessment item. That means it should be your own work, not someone else's.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T11:12:48Z
FirstChildVoteTAG: 5
SecondChildTAG: Why is it so hard for many students to understand this?
I hate to point out the facts, but in several other edX courses I see many students do exactly the same, not putting the effort to read instructions, exhaust all troubleshooting options, outright 'lazy' and expect other students to give out answers, blame the question/staff/teacher blindly when so many other students have found the correct answer, and so on...and unfortunately those students end up not finishing the course.
Try your best, but try yourself first. If you can't solve it then don't worry as the answers will be revealed after the deadline. The passing grade is so low, so you don't need to break the rules to finish the course. It is better to finish the course at 50% but understand the subject and uphold the honor code, rather than cheat away and pass with flying colors.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T12:02:50Z
SecondChildVoteTAG: 0
FirstChildTAG: +1
Poorly worded, indeed.
FirstChildUserIdTAG: 1176044
FirstChildUserNameTAG: ArtVandelay
FirstChildCreateTimeTAG: 2013-02-27T01:32:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Agreed. Hopefully our first (incorrect) answer is recorded with the first submission and we get double marks ;-) But seriously, I think you would be marked correctly on this question if you (correctly, in my opinion) excluded the 65 bin, but (incorrectly) included the right endpoint bin 75....
SecondChildUserIdTAG: 934648
SecondChildUserNameTAG: Boderick
SecondChildCreateTimeTAG: 2013-02-27T06:23:49Z
SecondChildVoteTAG: 0
IndexTAG: 2674
TitleTAG: Unable to view the videos
Hello Prof.
I am unable to view the videos , I am worried is it something serious.
Please help me out
Thanks in advance
Dhanashree.
UserIdTAG: 948983
UserNameTAG: DhanashreeV
CreateTimeTAG: 2013-02-23T05:48:11Z
VoteTAG: 1
CoursewareTAG: Section 1: Introduction / Lec 1.1. Why study descriptive statistics?
NumberOfReplyTAG: 4
FirstChildTAG: It would be helpful to others if you gave more information about your problem & instead of creating new threads minutes apart, edit your original posts as so not to clutter up the place.
:)
FirstChildUserIdTAG: 1253130
FirstChildUserNameTAG: Eternalight
FirstChildCreateTimeTAG: 2013-02-23T06:12:31Z
FirstChildVoteTAG: 1
FirstChildTAG: Is youtube banned where you are? If yes, then I believe you will need to download the videos instead. Or there are other methods/workaround. Go ahead and use the search function of the discussion
forum.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T07:33:09Z
FirstChildVoteTAG: 0
FirstChildTAG: video shows perfectly well in germany. I would assume something with your flash player.
I would propose to use the discussion board only for technical stuff and use the comment page at the video for content-related comments.
does youtube.com works with you?
FirstChildUserIdTAG: 986512
FirstChildUserNameTAG: Thorem
FirstChildCreateTimeTAG: 2013-02-23T09:15:53Z
FirstChildVoteTAG: 0
FirstChildTAG: have you tried using other browser? Because I encountered problem like that, but when I use the other browser it played the video.
FirstChildUserIdTAG: 708598
FirstChildUserNameTAG: Ollie07
FirstChildCreateTimeTAG: 2013-02-26T04:54:18Z
FirstChildVoteTAG: 0
IndexTAG: 2675
TitleTAG: Disappointed by decimal placing of the answer
it was astonishing that i calculated the right answer to ten decimal places but was said to be wrong by the software. I gave answer for part a) & c) as 11.11 & 22.22 respectively but both of them were marked as incorrect rather both were correct to 2nd place after decimal.
as we are discussing stat give us liberty for the decimal placing..
UserIdTAG: 333888
UserNameTAG: brar_84
CreateTimeTAG: 2013-02-23T05:46:19Z
VoteTAG: 7
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: Your disappointment is the same as the other fellow students who have posted the same subject numerous times. I suggest next time use the search function of the discussion forum and post your disappointment collectively together there.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T07:35:10Z
FirstChildVoteTAG: 1
SecondChildTAG: also 'vote' for the thread so it will be noticed by staff sooner.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T07:36:23Z
SecondChildVoteTAG: 0
IndexTAG: 2676
TitleTAG: Course material???
Hello
Please anybody will help me out I am unable to find the course material could you please guide me through because it is saturday now and I have only 3 days left to work out for this week.
Thanks in advance
Dhanashree V.
UserIdTAG: 948983
UserNameTAG: DhanashreeV
CreateTimeTAG: 2013-02-23T05:37:34Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: You need to go to "Courseware" top left of page, you can't miss it. Click on Week 1: Feb 20-26. to drop the course schedule & material down in a drop-boxlike' menu.
As you go through each section, you'll see videos, links to other material, practice exercises, exams.
Everything you need is there.
:)
FirstChildUserIdTAG: 1253130
FirstChildUserNameTAG: Eternalight
FirstChildCreateTimeTAG: 2013-02-23T05:57:19Z
FirstChildVoteTAG: 1
IndexTAG: 2677
TitleTAG: Initial perception
I am enjoying the challenge after not handling numbers for over 10 years. Ratios were never my strength to begin with. I did enjoy the quiz challenge.
UserIdTAG: 1061410
UserNameTAG: BNRivera
CreateTimeTAG: 2013-02-23T05:22:57Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: Me too!!
FirstChildUserIdTAG: 1193628
FirstChildUserNameTAG: FLupia
FirstChildCreateTimeTAG: 2013-02-23T08:36:38Z
FirstChildVoteTAG: 0
FirstChildTAG: and just to say something... i am just watching the videos. great work!
FirstChildUserIdTAG: 986512
FirstChildUserNameTAG: Thorem
FirstChildCreateTimeTAG: 2013-02-23T09:31:22Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too, i cant remember how long ago i lastly did maths. Im enjoying this.
FirstChildUserIdTAG: 1040144
FirstChildUserNameTAG: Judwin
FirstChildCreateTimeTAG: 2013-02-23T09:58:37Z
FirstChildVoteTAG: 0
IndexTAG: 2678
TitleTAG: interpretation and bar area...
histogram so looks simple till date but now understand the interpretation of it and which is so informative....
UserIdTAG: 688322
UserNameTAG: kiranpiparva
CreateTimeTAG: 2013-02-23T05:20:44Z
VoteTAG: 1
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 0
IndexTAG: 2679
TitleTAG: Width of class interval
How come "-10 to 20" = 10? I thought it should be equal to 30.
UserIdTAG: 1040079
UserNameTAG: amecronin
CreateTimeTAG: 2013-02-23T05:17:26Z
VoteTAG: 11
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: This question has its own forum now. The idea is to avoid these multiple posts.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13615975361343668.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T05:32:26Z
FirstChildVoteTAG: 1
SecondChildTAG: yes, the range 20-(-10) = 30
so the answer = 0.46%
SecondChildUserIdTAG: 791460
SecondChildUserNameTAG: Hemattota
SecondChildCreateTimeTAG: 2013-02-23T06:45:13Z
SecondChildVoteTAG: 0
IndexTAG: 2680
TitleTAG: Height of -10 to 20 bar = ____________ % per unit?? Range ?
Shouldn't the range or width be 30 and not 10 ? so the answer would be 14/30 and not 14/10 . Am I missing something ?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-23T05:10:11Z
VoteTAG: 10
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: > Am I missing something ?
Yes. You missed looking at the other posts in this discussion.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13615974321343611.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T05:30:43Z
FirstChildVoteTAG: 1
IndexTAG: 2681
TitleTAG: more material
I really like the course, the system is ok, the videos are ok. but I think should be nice have an additional online book.
thanks
UserIdTAG: 1153075
UserNameTAG: Jimenezrjp
CreateTimeTAG: 2013-02-23T04:58:07Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2682
TitleTAG: Question
I don't understand the difference between interval contained more people and interval was more crowded
UserIdTAG: 1266052
UserNameTAG: ymmedina
CreateTimeTAG: 2013-02-23T04:52:57Z
VoteTAG: 3
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: The professor used an example of there being fewer people in Japan than in the US, but because Japan's area is so much smaller, it's a more crowded country.
Or consider 5 people in a 5m x 1m area vs. 15 people in a 5m x 30m area. Even though there are fewer people in the 5m x 1m area, it is more crowded than the larger area with more people -- it has more people per square meter.
Hope this helps.
FirstChildUserIdTAG: 914245
FirstChildUserNameTAG: dbaPlanB
FirstChildCreateTimeTAG: 2013-02-23T05:23:54Z
FirstChildVoteTAG: 4
SecondChildTAG: Thanks, this makes sense now
SecondChildUserIdTAG: 818658
SecondChildUserNameTAG: sheilal
SecondChildCreateTimeTAG: 2013-02-23T15:42:10Z
SecondChildVoteTAG: 0
IndexTAG: 2683
TitleTAG: tip
you just need to see very carefully to the graphs, they are telling you the answer by it self
UserIdTAG: 616129
UserNameTAG: ssantonio
CreateTimeTAG: 2013-02-23T04:43:04Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2684
TitleTAG: Percent symbol
It should be specified whether or not to write the percent symbol after the answer. I got the second exercise wrong the first time because I wrote it down. Thank you.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-23T04:36:43Z
VoteTAG: 4
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: Same here :|
If the percent symbol is not required, it should be already there, right next to the answer or something. Thank you.
FirstChildUserIdTAG: 1217888
FirstChildUserNameTAG: salomeareias
FirstChildCreateTimeTAG: 2013-02-23T11:59:22Z
FirstChildVoteTAG: 0
SecondChildTAG: yep.
SecondChildUserIdTAG: 967698
SecondChildUserNameTAG: cb1667
SecondChildCreateTimeTAG: 2013-02-24T10:22:40Z
SecondChildVoteTAG: 0
IndexTAG: 2685
TitleTAG: I think I'm missing something
In the second problem set where it asked wether or not the graph is correct for the data with 500 plants, I chose yes but it was marked incorrect. It is possible I missed something but I can't figure out what. My calculations for the number of plants in each category seemed to work for the other questions.
UserIdTAG: 1091276
UserNameTAG: HestiaArglye
CreateTimeTAG: 2013-02-23T04:03:28Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Hi Hestia
It is incorrect because remember they have now added green/green (20 extra plants). When you look at the graph it only includes M/G, M/R, R/G and R/R; there is no sign of green/green. Hence the graph does not show 500 plants but still continues to show the previous 480 plants. The graph is therefore an incorrect representation of the 500 plants.
Hope this helps
FirstChildUserIdTAG: 1184014
FirstChildUserNameTAG: slorde
FirstChildCreateTimeTAG: 2013-02-23T04:11:47Z
FirstChildVoteTAG: 2
SecondChildTAG: I think that's not very instructive. This graph are just a trick..
SecondChildUserIdTAG: 434437
SecondChildUserNameTAG: KalashnikovYuriy
SecondChildCreateTimeTAG: 2013-02-23T10:39:22Z
SecondChildVoteTAG: 0
FirstChildTAG: > Hope this helps
As you have just supplied an answer, it will help everyone else.
Everyone agreed to an honour code, whereby you don't discuss answers until after the deadline.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T04:13:57Z
FirstChildVoteTAG: 3
IndexTAG: 2686
TitleTAG: Difference between graph 2 & 4 on Problem 4?
I see no difference between the 2nd and 4th bar set. Is this true?
UserIdTAG: 177319
UserNameTAG: crob1977
CreateTimeTAG: 2013-02-23T03:46:59Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: Assuming you mean Problem 3.
> Is this true?
Can't say. This is an assessment item.
When looking at a graph you need to look at the *entire* graph. The scale. The axis label. The bars. Everything.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T04:00:14Z
FirstChildVoteTAG: 1
SecondChildTAG: I should have reviewed the discussion prior to answering the last question. Note to self: Review all data!
SecondChildUserIdTAG: 831391
SecondChildUserNameTAG: rpowell118
SecondChildCreateTimeTAG: 2013-02-23T05:59:15Z
SecondChildVoteTAG: 0
FirstChildTAG: Ahhhh...I see my error. Thank you.
FirstChildUserIdTAG: 177319
FirstChildUserNameTAG: crob1977
FirstChildCreateTimeTAG: 2013-02-23T16:38:16Z
FirstChildVoteTAG: 0
IndexTAG: 2687
TitleTAG: Wrong answer?
I put the results of percentage with two decimals (22.22%, 11.11%) and the answer appears with one decimal... the answer was incorrect?
UserIdTAG: 957844
UserNameTAG: JessicaVGarcia
CreateTimeTAG: 2013-02-23T03:18:41Z
VoteTAG: 25
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 3
FirstChildTAG: The system was set to accept only 1 decimal place. This has been discussed many times in past posts. Future exercises will, hopefully, have these requirements clearly stated so as to avoid this sort of issue.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T03:26:43Z
FirstChildVoteTAG: 6
SecondChildTAG: please don't use percentile symbol
SecondChildUserIdTAG: 393580
SecondChildUserNameTAG: Aditiak
SecondChildCreateTimeTAG: 2013-02-23T07:31:09Z
SecondChildVoteTAG: 0
SecondChildTAG: The decimal requirements should be specified.You cannot be marked wrong for being more accurate .
SecondChildUserIdTAG: 367029
SecondChildUserNameTAG: PoojaMukul
SecondChildCreateTimeTAG: 2013-02-23T08:16:20Z
SecondChildVoteTAG: 0
SecondChildTAG: 2 decimal places or rounded to nearest integer seems like a more sensible default considering currency is based on a unit starts out at 0.01 of a dollar.
SecondChildUserIdTAG: 1294449
SecondChildUserNameTAG: jesse9
SecondChildCreateTimeTAG: 2013-02-23T08:25:06Z
SecondChildVoteTAG: 0
SecondChildTAG: PLEASE SPECIFY THE NUMBER OF DECIMAL DIGITS NEAR THE QUESTION IN THE FUTURE
SecondChildUserIdTAG: 1183660
SecondChildUserNameTAG: m_orouk
SecondChildCreateTimeTAG: 2013-02-23T09:12:24Z
SecondChildVoteTAG: 0
SecondChildTAG: haha..it is correct if you guys add all the percent off total the amount od studens...is equal 100%...
SecondChildUserIdTAG: 1284506
SecondChildUserNameTAG: QuanNguyen
SecondChildCreateTimeTAG: 2013-02-23T16:39:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Same here....
SecondChildUserIdTAG: 1327998
SecondChildUserNameTAG: Redrover
SecondChildCreateTimeTAG: 2013-03-01T02:14:10Z
SecondChildVoteTAG: 0
FirstChildTAG: pls don't post answers here. against the rules and it is really annoying
FirstChildUserIdTAG: 986512
FirstChildUserNameTAG: Thorem
FirstChildCreateTimeTAG: 2013-02-23T10:03:07Z
FirstChildVoteTAG: 1
FirstChildTAG: the first time, i did right for the numbers of students, but i did wrong the percent of student. then check the answer i knew i was wrong...
FirstChildUserIdTAG: 1284506
FirstChildUserNameTAG: QuanNguyen
FirstChildCreateTimeTAG: 2013-02-23T16:41:47Z
FirstChildVoteTAG: 0
IndexTAG: 2688
TitleTAG: problem 1b and 1c
in the question 1b, we think the uniform distribuition in interval, so higher percerntual indicate high density. I think if there are more people, more crowd. i am correct?
the question 1c, for example a interval 100-200 include 100 but not include 200. i am correct?
UserIdTAG: 416422
UserNameTAG: edujara
CreateTimeTAG: 2013-02-23T03:05:03Z
VoteTAG: 6
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: > I think if there are more people, more crowd. i am correct?
We can't tell you if you are correct. This is an assessment. Just follow what was done in the lecture.
> for example a interval 100-200 include 100 but not include 200. i am correct?
Yes. The question tells you about endpoints:
>Intervals include the left endpoint but not the right
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T03:13:02Z
FirstChildVoteTAG: 2
SecondChildTAG: Thanks a lot @SusanAust. In video Lecture 2.1-2.3 dont appears the term "crowded" . It´s the same as density? Number of people by unit of interval?
... Sorry only now I see that the intervals have different length.
SecondChildUserIdTAG: 416422
SecondChildUserNameTAG: edujara
SecondChildCreateTimeTAG: 2013-02-23T21:48:33Z
SecondChildVoteTAG: 0
IndexTAG: 2689
TitleTAG: Q2c wrong answer
O2c
how 9.5 can be wrong?
UserIdTAG: 675409
UserNameTAG: avoevodin
CreateTimeTAG: 2013-02-23T02:51:13Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: Please use the forum link at the bottom of the question page so we can see what it is you are talking about. So, which problem set and question is this? And remember the honour code.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T02:53:45Z
FirstChildVoteTAG: 0
SecondChildTAG: Go through basic formal definition of percentile. you will get the right answer.
SecondChildUserIdTAG: 85891
SecondChildUserNameTAG: rajivverma88
SecondChildCreateTimeTAG: 2013-02-23T18:34:07Z
SecondChildVoteTAG: 0
FirstChildTAG: Assuming this is the one:
![enter image description here][1]
This set was used, and stem and leaf plot explained, in the lecture.
The first data entry is 48, then 59, 63, 63, etc. No decimals involved.
[1]: https://edxuploads.s3.amazonaws.com/13615883881343638.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T03:01:57Z
FirstChildVoteTAG: 2
SecondChildTAG: Ok I though 4.8, 5.9.........
SecondChildUserIdTAG: 675409
SecondChildUserNameTAG: avoevodin
SecondChildCreateTimeTAG: 2013-02-23T03:09:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Thank you!
SecondChildUserIdTAG: 675409
SecondChildUserNameTAG: avoevodin
SecondChildCreateTimeTAG: 2013-02-23T03:10:58Z
SecondChildVoteTAG: 0
SecondChildTAG: I also thought 4.8, 5.9... It is now clear no decimals are involved. Not all cultures in the world base scores on 100, so its is not an uncommon assumption to think test results are espressed on base 10. There is a certain degree of ambiguity on some of this questions that go beyond the understanding of the simple concepts underlying them... I guess the "2 submissions" limit in some exercises are there for a reason.
SecondChildUserIdTAG: 882815
SecondChildUserNameTAG: ChiscodeA
SecondChildCreateTimeTAG: 2013-02-23T14:32:23Z
SecondChildVoteTAG: 0
SecondChildTAG: I meant "expressed"; sorry for the typo.
SecondChildUserIdTAG: 882815
SecondChildUserNameTAG: ChiscodeA
SecondChildCreateTimeTAG: 2013-02-23T14:33:11Z
SecondChildVoteTAG: 0
FirstChildTAG: it seems answers to Problem 2 Exercise Set 3 contain error,at least it is relevant to Problem 2c answer
FirstChildUserIdTAG: 675409
FirstChildUserNameTAG: avoevodin
FirstChildCreateTimeTAG: 2013-02-23T03:06:11Z
FirstChildVoteTAG: 0
SecondChildTAG: No, the answer for the question is correct. You need to use the correct method, which is described in the video. Your answer is impossible, as the data ranges from 48 - 100.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-23T03:09:26Z
SecondChildVoteTAG: 0
SecondChildTAG: yes its correct!! I agree with SusanAust
SecondChildUserIdTAG: 18215
SecondChildUserNameTAG: mhr201
SecondChildCreateTimeTAG: 2013-02-23T15:42:44Z
SecondChildVoteTAG: 0
FirstChildTAG: Stem and Leaf charts should normally provide scale factor information, and it seems to default to being integral numbers. In this case, the problem statement referred to the source of the data, where it was clearly stated that these were integral scores out of 100. (I remember the comment that it was an undergrad in the grad course that got the 100).
FirstChildUserIdTAG: 1222946
FirstChildUserNameTAG: RichardDamon
FirstChildCreateTimeTAG: 2013-02-25T02:25:24Z
FirstChildVoteTAG: 0
IndexTAG: 2690
TitleTAG: Question 1a about income is ambiguous
How can income not be a quantitative discrete variable? The smallest unit of measurement for income is a cent (US currency), not fractions of cents (unless you are doing statistical calculations i suppose - but in that case this needs to be clarified in the question)
UserIdTAG: 656073
UserNameTAG: Saqib_Qazi
CreateTimeTAG: 2013-02-23T02:46:45Z
VoteTAG: 22
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 6
FirstChildTAG: I agree with you. Another perspective to your point: the set of all possible values of the variable "income" is a subset of the set of rational numbers which is a countable set. Therefore, this subset is also countable, thus income should be a quantitative discrete variable.
FirstChildUserIdTAG: 1003677
FirstChildUserNameTAG: CValladaress
FirstChildCreateTimeTAG: 2013-02-23T02:56:23Z
FirstChildVoteTAG: 2
SecondChildTAG: Discrete variables are ones that can be counted in whole numbers. Like you said, income can be measured in cents. You can make a $1000 or $1000.05 which makes it continuous and so not discrete.
This is why "weight to the nearest kilogram" is quantitative discrete. Weight can be measured as something weighing 11 kilograms or 11.5 kilograms - this makes it quantitative but not discrete but the question specifies "to the nearest kilogram" so it either weighs 11 kg or 12 kg and so is discrete. The same distinction is not made for income so it is not discrete.
Hope this helps!
SecondChildUserIdTAG: 1081125
SecondChildUserNameTAG: umanb89
SecondChildCreateTimeTAG: 2013-02-25T06:00:08Z
SecondChildVoteTAG: 0
SecondChildTAG: it was mentioned as we should be using dollar as the base of currency so as cent appears it makes it not discrete
i can be wrong as it is confusing
SecondChildUserIdTAG: 330083
SecondChildUserNameTAG: ARUNAVA1993
SecondChildCreateTimeTAG: 2013-02-27T17:20:49Z
SecondChildVoteTAG: 0
SecondChildTAG: I disagree with umanb89. If you measure income in cents, it is a discrete variable.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-05T09:31:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree. I followed the same line of reasoning as you and was of course marked wrong. This question was vague.
SecondChildUserIdTAG: 1291617
SecondChildUserNameTAG: Hultman21
SecondChildCreateTimeTAG: 2013-03-06T00:50:51Z
SecondChildVoteTAG: 0
FirstChildTAG: and another perspective would be this:
suppose, one day the government comes up with an ingenious plan to introduce a new sub-unit which is equal to 1/1000 of dollar / pound / whatever. It would be conceptually the same as millimeters and meters. After all, we don't say that millimeter is the smallest possible unit to measure, lets say, length only because a ruler does not have any smaller units.
On the other hand, could someone think of a sub-unit for the number of pages in a book? It just would not make a sense.
Thus, income is continuous variable and not continuous discrete.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-23T03:55:37Z
FirstChildVoteTAG: 1
SecondChildTAG: i m totally agree with you!
SecondChildUserIdTAG: 1157536
SecondChildUserNameTAG: PERIO81
SecondChildCreateTimeTAG: 2013-02-25T16:56:34Z
SecondChildVoteTAG: 0
SecondChildTAG: I disagree. Even if there are sub-units involved, at a certain moment in time, the variable is discrete. On the other hand, it is possible to measure income as 'low', 'middle' and 'high', for instance. But then, it is not a quantitative variable.
SecondChildUserIdTAG: 1159651
SecondChildUserNameTAG: KatrienJ
SecondChildCreateTimeTAG: 2013-03-05T09:35:18Z
SecondChildVoteTAG: 0
FirstChildTAG: You are correct although I knew they wanted quantitative as the answer. Choose quantitative discrete as a matter of principle.
FirstChildUserIdTAG: 1294449
FirstChildUserNameTAG: jesse9
FirstChildCreateTimeTAG: 2013-02-23T08:35:53Z
FirstChildVoteTAG: 8
FirstChildTAG: How do we bring such cases to the notice of Prof. Adhikari ? Does anyone know the process?
FirstChildUserIdTAG: 1008753
FirstChildUserNameTAG: Ankur_Aggarwal
FirstChildCreateTimeTAG: 2013-02-23T17:29:47Z
FirstChildVoteTAG: 2
FirstChildTAG: arg!!!!!! hard to get... Someone correct me if I'm wrong: Income is too vague in the way that you can easily reduce it: Income of what? year,month,week? In $, £,€?
But if there were to be something like 'Income currency', it would be categorical.
I think 'monthly Income' is a discrete.
FirstChildUserIdTAG: 1013822
FirstChildUserNameTAG: FaizaHarbi
FirstChildCreateTimeTAG: 2013-02-26T18:34:55Z
FirstChildVoteTAG: 0
FirstChildTAG: If income is a continuous quantitative variable "because of the decimals that arise due to currency conversions etc" (Answer of exerc 1a in ES1), should we treat all variables with a currency as unit as continuous? For example, the price of a car, house prices, price of bread, ... Or is this specific for income?
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-03-25T11:38:27Z
FirstChildVoteTAG: 0
IndexTAG: 2691
TitleTAG: I never knew we can do so many things with a histogram.
Interpretation of the histogram has never been that rich to me. Possibilities abound here.
UserIdTAG: 925684
UserNameTAG: KamLoong
CreateTimeTAG: 2013-02-23T02:16:21Z
VoteTAG: 1
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 0
IndexTAG: 2692
TitleTAG: Please show decimal points required in answers
Hi - currently you aren't showing how many decimal points are required in answers. Please specify them as its making me get answers wrong )-:
Rick
UserIdTAG: 46111
UserNameTAG: rickschmoo
CreateTimeTAG: 2013-02-23T01:55:05Z
VoteTAG: 21
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T02:34:32Z
FirstChildVoteTAG: 0
SecondChildTAG: having same problem
SecondChildUserIdTAG: 688322
SecondChildUserNameTAG: kiranpiparva
SecondChildCreateTimeTAG: 2013-02-24T16:29:26Z
SecondChildVoteTAG: 0
IndexTAG: 2693
TitleTAG: "another 20 green/green"?
Is this right? There magneta/green, red/green, red/red but no green/green...
UserIdTAG: 665198
UserNameTAG: AdamMo
CreateTimeTAG: 2013-02-23T01:50:00Z
VoteTAG: 1
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: (Problem 3)
FirstChildUserIdTAG: 665198
FirstChildUserNameTAG: AdamMo
FirstChildCreateTimeTAG: 2013-02-23T01:54:47Z
FirstChildVoteTAG: 0
SecondChildTAG: it is right. they add a new combination
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-23T02:15:02Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks
SecondChildUserIdTAG: 665198
SecondChildUserNameTAG: AdamMo
SecondChildCreateTimeTAG: 2013-02-23T02:27:47Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't think they intend to add a new combination, because the graphs do not display green/green. I will try to figure out where the new 20 should be added.
SecondChildUserIdTAG: 1107493
SecondChildUserNameTAG: Sufil
SecondChildCreateTimeTAG: 2013-02-23T03:26:34Z
SecondChildVoteTAG: 0
SecondChildTAG: It is a totally new grouping. So it is not a mistake.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-23T03:34:26Z
SecondChildVoteTAG: 0
SecondChildTAG: Its not a mistake. That is the actual question. Just follow through with the question based on what is there and there should be no problem.
SecondChildUserIdTAG: 1184014
SecondChildUserNameTAG: slorde
SecondChildCreateTimeTAG: 2013-02-23T04:21:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Hello Susan,
Nice to see you again and thank you for all the help you gave us on PH207x.
-Vladek
SecondChildUserIdTAG: 183869
SecondChildUserNameTAG: vladek
SecondChildCreateTimeTAG: 2013-02-23T18:00:56Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes that is right
FirstChildUserIdTAG: 1084609
FirstChildUserNameTAG: smolnar1
FirstChildCreateTimeTAG: 2013-02-23T22:56:42Z
FirstChildVoteTAG: 1
IndexTAG: 2694
TitleTAG: UNIFORMITY OF BARS
when do we know uniformity of sub intervals is a good assumption or not?
is it based on wideness of the intervals or the height or area? give some example for cases where the uniformity is a wrong assumption please.
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-02-23T01:46:44Z
VoteTAG: 0
CoursewareTAG: Section 2a: The Histogram (Lec 2.1 - 2.3) / Lec 2.3. Units and density
NumberOfReplyTAG: 1
FirstChildTAG: In general, the wider the interval, the less faith you should have in uniformity within bars. For example, in the income histogram that is used as an example in Lec 2.2, you can see the distribution "tailing off" as you get towards the larger incomes. In such a situation, assuming uniformity in the bars at the right end of the income scale is probably not such a good idea. It might be better towards the low end or middle of the data.
In every case, the assumption is just that: an assumption, which has to be remembered when doing calculations. Under the assumption, all you get are estimates of percentiles, not the exact percentiles.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-23T05:15:22Z
FirstChildVoteTAG: 6
IndexTAG: 2695
TitleTAG: Question 2b
Hello
I really cannot see any difference between 1st and 3rd bar graphs in question 2b.
They both seem correct to me ...
Any pointers?
Will solutions be posted?
Thanks
UserIdTAG: 1144392
UserNameTAG: lmbacelar
CreateTimeTAG: 2013-02-23T01:31:38Z
VoteTAG: 2
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: That question asked you to select all that apply. When you see squares beside the answers, you need to select multiple. The round/radial buttons indicate that only one answer is correct.
FirstChildUserIdTAG: 1145404
FirstChildUserNameTAG: KimHill
FirstChildCreateTimeTAG: 2013-02-23T01:38:43Z
FirstChildVoteTAG: 3
SecondChildTAG: What I learned today is that I have to read carefully each sentence and question!
SecondChildUserIdTAG: 1145881
SecondChildUserNameTAG: brunoa
SecondChildCreateTimeTAG: 2013-02-23T03:39:05Z
SecondChildVoteTAG: 0
SecondChildTAG: duh ! shame on me ...
Thank you
SecondChildUserIdTAG: 1144392
SecondChildUserNameTAG: lmbacelar
SecondChildCreateTimeTAG: 2013-02-23T14:10:14Z
SecondChildVoteTAG: 0
FirstChildTAG: Solutions will be posted a day after the deadline, according to the course introduction (see the Courseware section).
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T01:50:02Z
FirstChildVoteTAG: 0
IndexTAG: 2696
TitleTAG: Problem 1 (E)
This particular problem gave me a headache...I don't get how I got that wrong...what am I not comprehending
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-23T01:23:17Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: It's because of the nearest kilogram. Your data set wouldn't include 11.8 kilograms, it would be 12 kilograms.
FirstChildUserIdTAG: 1145404
FirstChildUserNameTAG: KimHill
FirstChildCreateTimeTAG: 2013-02-23T01:41:05Z
FirstChildVoteTAG: 0
IndexTAG: 2697
TitleTAG: set 2 problem 7 (3 pts)
Did Any One use the "sum of the percentages" and get the wrong answer for it?
i just want to know if my approach is right don't give the value.but pls pt out any irregularity in my approach.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-23T01:14:51Z
VoteTAG: 2
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: I did, and yes my answer was wrong. wish i could find out the right answer. Don't know what was wrong with my approach.
FirstChildUserIdTAG: 1231552
FirstChildUserNameTAG: Albertson
FirstChildCreateTimeTAG: 2013-02-23T01:25:06Z
FirstChildVoteTAG: 2
SecondChildTAG: Never mind, just realized what I did wrong.
SecondChildUserIdTAG: 1231552
SecondChildUserNameTAG: Albertson
SecondChildCreateTimeTAG: 2013-02-23T01:25:53Z
SecondChildVoteTAG: 0
SecondChildTAG: Hey, I used the "sum of percentages" and got the wrong answer. Would you mind explaining in general terms what's the problem with this approach? Thanks in advance.
SecondChildUserIdTAG: 80436
SecondChildUserNameTAG: bmp
SecondChildCreateTimeTAG: 2013-02-23T01:29:00Z
SecondChildVoteTAG: 0
SecondChildTAG: The question was asking for height, not percentage.
SecondChildUserIdTAG: 1084733
SecondChildUserNameTAG: GSDeOrio
SecondChildCreateTimeTAG: 2013-02-23T06:19:10Z
SecondChildVoteTAG: 0
SecondChildTAG: I also found my error :-(
SecondChildUserIdTAG: 288327
SecondChildUserNameTAG: IsabellaVel
SecondChildCreateTimeTAG: 2013-02-23T20:54:58Z
SecondChildVoteTAG: 0
SecondChildTAG: Your approach is right,but before you check your answer make sure you are entering the value what is being asked and not something else. :)
SecondChildUserIdTAG: 933932
SecondChildUserNameTAG: Shadybog
SecondChildCreateTimeTAG: 2013-02-25T11:39:40Z
SecondChildVoteTAG: 0
SecondChildTAG: I have done the same.. like found the missing percentage and then deduced the height but I find it wrong !! what is it actually ?
SecondChildUserIdTAG: 1035321
SecondChildUserNameTAG: Phaniyannam
SecondChildCreateTimeTAG: 2013-02-26T09:50:19Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, I would like to know the correct option too. I know that the sum of percentages must be 100% and thus the missing interval is 44%. Applying the height formula it gives an height of 2.93% per hour. But this is still incorrect, what am I doing wrong? Thanks!
SecondChildUserIdTAG: 243424
SecondChildUserNameTAG: FernandoSaez
SecondChildCreateTimeTAG: 2013-02-26T15:24:55Z
SecondChildVoteTAG: 0
SecondChildTAG: 44% of the entire interval. Think of how many hours in a given interval. sorry, i dont speak english well. this is not my first language
SecondChildUserIdTAG: 1214264
SecondChildUserNameTAG: IamReallyHeisenberg
SecondChildCreateTimeTAG: 2013-02-26T20:49:02Z
SecondChildVoteTAG: 0
SecondChildTAG: The % in the interval is 44, but that is not what the missing entry is.
height = % in interval / width
You have the % in the interval and you have the width, so solve for the missing entry from there.
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-02-27T16:34:45Z
SecondChildVoteTAG: 0
IndexTAG: 2698
TitleTAG: set 2 problem 3
i need to know how many decimal points we need to take for the first question? one or two
(b) how do we measure probability distribution chart from given histogram data set? it wasn't discussed in lectures can you suggest some references?
UserIdTAG: 1028247
UserNameTAG: thekid
CreateTimeTAG: 2013-02-23T01:02:20Z
VoteTAG: 0
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: > i need to know how many decimal points we need to take for the first question?
I used 2 places.
> how do we measure probability distribution chart from given histogram data set
You look at the overall shape of the histogram. Symmetric? Normal? Skewed?
But I *think* you mean the distribution within the bars for the question 4c?
The question says to assume a uniform distribution. Then you are asked if this is a reasonable assumption to make. So is it reasonable to assume that there will be an even distribution of years of education within each bar? Would the same $\%$ have 0 years, 1 year, 2 years, $\ldots$, 8 years education - for the first bar?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T03:23:22Z
FirstChildVoteTAG: 0
SecondChildTAG: thank you
SecondChildUserIdTAG: 1028247
SecondChildUserNameTAG: thekid
SecondChildCreateTimeTAG: 2013-02-26T18:56:45Z
SecondChildVoteTAG: 0
FirstChildTAG: someone please help!! explain to me how to solve question 2 and 3 b i am stuck there.
FirstChildUserIdTAG: 815453
FirstChildUserNameTAG: warinda
FirstChildCreateTimeTAG: 2013-02-23T09:49:33Z
FirstChildVoteTAG: 1
IndexTAG: 2699
TitleTAG: % sign with the answer
Do we need to enter the the % sign with the answers.
UserIdTAG: 358255
UserNameTAG: drnidhi27
CreateTimeTAG: 2013-02-23T00:53:05Z
VoteTAG: 12
CoursewareTAG: Exercise Set 2 / Exercise Set 2
NumberOfReplyTAG: 2
FirstChildTAG: No
FirstChildUserIdTAG: 1270186
FirstChildUserNameTAG: anar0sa
FirstChildCreateTimeTAG: 2013-02-23T00:54:57Z
FirstChildVoteTAG: 0
SecondChildTAG: I answered a question with the % sign ie 42% and was marked as incorrect. When I changed the answer to 42 it was marked as correct.
Note 42 is a random made up number - except for readers of "the hitchhiker's guide to the galaxy"
Honor code remaining intact!
SecondChildUserIdTAG: 313672
SecondChildUserNameTAG: blinxnot
SecondChildCreateTimeTAG: 2013-02-23T01:33:51Z
SecondChildVoteTAG: 0
SecondChildTAG: I see you have found the answer to the universe...lol
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T01:51:23Z
SecondChildVoteTAG: 0
SecondChildTAG: :)
SecondChildUserIdTAG: 314594
SecondChildUserNameTAG: Mzvd
SecondChildCreateTimeTAG: 2013-02-23T02:15:44Z
SecondChildVoteTAG: 0
SecondChildTAG: no
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-02-24T16:32:06Z
SecondChildVoteTAG: 0
FirstChildTAG: When time to do the exercise will pass the deadline, are you going to upload the right answers to the exercises? It would be great, thanks
FirstChildUserIdTAG: 56238
FirstChildUserNameTAG: pablomp92
FirstChildCreateTimeTAG: 2013-02-23T11:35:39Z
FirstChildVoteTAG: 1
SecondChildTAG: read the Course policies.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-23T11:36:56Z
SecondChildVoteTAG: 0
SecondChildTAG: I think Susan is trying to answer your question in her own special way w a yes :)
SecondChildUserIdTAG: 1207892
SecondChildUserNameTAG: triplebee
SecondChildCreateTimeTAG: 2013-02-24T01:20:58Z
SecondChildVoteTAG: 0
SecondChildTAG: yeah, so **rough**! lol
SecondChildUserIdTAG: 1140340
SecondChildUserNameTAG: heartmind
SecondChildCreateTimeTAG: 2013-02-24T13:21:09Z
SecondChildVoteTAG: 0
SecondChildTAG: yes we need right answers
SecondChildUserIdTAG: 704053
SecondChildUserNameTAG: jehadhassan
SecondChildCreateTimeTAG: 2013-02-24T16:32:35Z
SecondChildVoteTAG: 0
IndexTAG: 2700
TitleTAG: Course Material
Hi,
Where can I find the textbook for the course?
Thank you.
Cecilia
UserIdTAG: 1020867
UserNameTAG: CGSA
CreateTimeTAG: 2013-02-23T00:31:22Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 1
FirstChildTAG: http://statistics.berkeley.edu/~stark/SticiGui/index.htm
"Practice for exercises" sections (see Courseware) contain links to relevant parts of the textbook.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-23T00:48:45Z
FirstChildVoteTAG: 0
IndexTAG: 2701
TitleTAG: Exercise sets
Hi all!
I think it is quite difficult if even for exercises sets so many exercises are having only one check. It does not allow us to express ourselves completely. I think we should be allowed to make mistakes during our learning time then the final check may be keep for exams. It is much more scaring than encouraging to see a batch of final check while we are still learning.
UserIdTAG: 418877
UserNameTAG: Jackcarnot
CreateTimeTAG: 2013-02-23T00:18:41Z
VoteTAG: 3
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: I guess the total weight of Exercise Sets (50%) in the final score has something to do with that decision. Doing relatively well in exercises is enough to get the certificate (+35%).
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-23T00:44:18Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5125aceb9914d22b0000019d
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T02:36:50Z
FirstChildVoteTAG: 0
IndexTAG: 2702
TitleTAG: STAFF: NUMBER OF SUBMISSION EXERCISE SET
how do you determine that a set of question should have one submission or two submission. I was answering to the exercise SET 1. Problem 1 has only one submission with many questions to respond and higher marks while Problem 2 has very few questions which are straight forward but you have given it two submissions. From Problem 3, the nature of questions are similar to those of problem 2 yet you have given it one submission. i expected that part one could have been given two submission considering that the questions demand reading between lines and have high marks while problem 2 and 3 could have 1 submission each.
similarly I suggest that the exercise sets should be given more submission like 2 to 3 considering that we are expected to write mid term and final exam whose submission are supposed to be limited
i suggest that the number of questions per problem to be submitted at once is reduced to increase the chance of getting correct answer. This is statistics, it is very easy to make a mistake when entering the responses. Therefore reducing the number of questions and increasing submission time gives opportunity to a student to correct the mistake
bye
UserIdTAG: 510759
UserNameTAG: SELEMANI
CreateTimeTAG: 2013-02-23T00:12:35Z
VoteTAG: 4
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 2
FirstChildTAG: well, this is the life. you should spend more time on practice tests if you dont feel confident you can do problem sets correct within given number of submissions. even more than one submission seems odd to me.
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-23T02:20:33Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5125aceb9914d22b0000019d
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T02:37:05Z
FirstChildVoteTAG: 0
IndexTAG: 2703
TitleTAG: width of class interval
How come the width of the class interval from -10 to 20 is 10 (see Explanation to question 2a)? Shouldn't it be 30?
UserIdTAG: 1290606
UserNameTAG: nataliya365
CreateTimeTAG: 2013-02-23T00:04:53Z
VoteTAG: 58
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 3
FirstChildTAG: This has been discussed several times already.
Next time, please use the search function before posting to avoid multiple duplicate postings.
It is also documented in the Wiki:
https://www.edx.org/wiki/Stat2.1x/courseware-errata
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T00:08:36Z
FirstChildVoteTAG: 3
SecondChildTAG: Thanks for pointing out the errata. For those of us new to this course & the courseware system, this is new information!
Where is the search function you describe? I don't see one for this discussion.
SecondChildUserIdTAG: 338887
SecondChildUserNameTAG: judielaine
SecondChildCreateTimeTAG: 2013-02-23T03:22:03Z
SecondChildVoteTAG: 0
FirstChildTAG: > Where is the search function you describe? I don't see one for this discussion.
You need to use the Search feature on the main Discussion tab. Not sure if you can restrict to a subforum.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13615902451343698.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T03:31:44Z
FirstChildVoteTAG: 6
SecondChildTAG: filter to subforum first, then search...I think...can't remember.
Nice pics and guides, SusanAust. Thanks!
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T07:21:41Z
SecondChildVoteTAG: 0
SecondChildTAG: ... 10 is wrong; the interval width should be 30..
SecondChildUserIdTAG: 1056161
SecondChildUserNameTAG: aseanmaverick
SecondChildCreateTimeTAG: 2013-02-27T09:30:49Z
SecondChildVoteTAG: 0
FirstChildTAG: Yes Natalia365, it should be 30 according to me too.
And the answer should be 14/30, i.e. 0.467
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 1115908
FirstChildUserNameTAG: rochak_khandelwal
FirstChildCreateTimeTAG: 2013-02-23T10:39:46Z
FirstChildVoteTAG: 0
SecondChildTAG: ... the answer is 0.467% per unit
SecondChildUserIdTAG: 1056161
SecondChildUserNameTAG: aseanmaverick
SecondChildCreateTimeTAG: 2013-02-27T09:32:09Z
SecondChildVoteTAG: 0
IndexTAG: 2704
TitleTAG: Alternative A
is not 14/30? the range of -10 to 20 = 30
Therefore, answer = 0.46666%
UserIdTAG: 223078
UserNameTAG: Rhadames
CreateTimeTAG: 2013-02-23T00:04:10Z
VoteTAG: 34
CoursewareTAG: Practice for Exercise Set 2 / Reading and practice for Exercise Set 2
NumberOfReplyTAG: 1
FirstChildTAG: If you searched the discussion forum, you would have found at least 5 other posts with an answer to your question. Please use the search function next time to avoid multiple posts on the same topic.
It is also available in the course errata.
https://www.edx.org/wiki/Stat2.1x/courseware-errata
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-23T00:34:28Z
FirstChildVoteTAG: 2
IndexTAG: 2705
TitleTAG: FORUM use
For those not used to the edX platform. Now that the subforums have been activated it will help if everyone uses the correct forum to post.
At the bottom of every lecture page and every question page, there is a discussion link. Please post your questions on the relevant page, that way it will be easier to locate posts relevant to that topic.
![enter image description here][1]
You can navigate to specific forums using the menu to the left:
![enter image description here][2]
When you post on the subforum, a link after your post identifies the relevant page. This makes it easier for people to look at what you are referring to. And it makes it a lot easier to find posts that have already been made about a question. So, hopefully, this will reduce repeat posts.
![enter image description here][3]
[1]: https://edxuploads.s3.amazonaws.com/13615765991343687.png
[2]: https://edxuploads.s3.amazonaws.com/13615767541343663.png
[3]: https://edxuploads.s3.amazonaws.com/13615769181343619.png
UserIdTAG: 629320
UserNameTAG: SusanAust
CreateTimeTAG: 2013-02-22T23:49:44Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I wonder if the staff will be able to 'reallocate' the current posts to their relevant sections?
Maybe it is too much work and too late now.
At least for future posts and the next course offering it should be better.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:53:14Z
FirstChildVoteTAG: 0
IndexTAG: 2706
TitleTAG: Needs in practise
I need exercises. Thank for making others available
UserIdTAG: 1225965
UserNameTAG: sylvanus
CreateTimeTAG: 2013-02-22T23:26:42Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 0
IndexTAG: 2707
TitleTAG: Lecture 1.2 and 1.3
Does anyone see the lecture for 1.2 and 1.3?
UserIdTAG: 900614
UserNameTAG: pa3cr
CreateTimeTAG: 2013-02-22T23:23:30Z
VoteTAG: 0
CoursewareTAG: Exercise Set 1 / Exercise Set 1
NumberOfReplyTAG: 9
FirstChildTAG: I don't. It's often difficult to get it. It depends on your network
FirstChildUserIdTAG: 1225965
FirstChildUserNameTAG: sylvanus
FirstChildCreateTimeTAG: 2013-02-22T23:29:07Z
FirstChildVoteTAG: 0
FirstChildTAG: I can see them. Browser: Chrome
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T23:33:08Z
FirstChildVoteTAG: 0
SecondChildTAG: Can Safari be use from Apple?
SecondChildUserIdTAG: 900614
SecondChildUserNameTAG: pa3cr
SecondChildCreateTimeTAG: 2013-02-23T00:01:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry, no idea.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-23T03:06:11Z
SecondChildVoteTAG: 0
FirstChildTAG: I can see them both on my Chrome and Android (Galaxy Tab) built in browser.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:35:52Z
FirstChildVoteTAG: 0
FirstChildTAG: I can see them. Browser: Firefox. However, you can choose to download the video. There is a link in the web page to download the video.
FirstChildUserIdTAG: 1246961
FirstChildUserNameTAG: guzhenyu
FirstChildCreateTimeTAG: 2013-02-22T23:52:45Z
FirstChildVoteTAG: 0
FirstChildTAG: I do not see these lectures either-- browser; fIREfOX
FirstChildUserIdTAG: 1187063
FirstChildUserNameTAG: kqazi
FirstChildCreateTimeTAG: 2013-02-23T01:18:56Z
FirstChildVoteTAG: 0
FirstChildTAG: I'm using Firefox and am able to watch the lectures.
FirstChildUserIdTAG: 1145404
FirstChildUserNameTAG: KimHill
FirstChildCreateTimeTAG: 2013-02-23T01:36:22Z
FirstChildVoteTAG: 0
FirstChildTAG: I can't see them neither on both Chrome and IE9.
FirstChildUserIdTAG: 608203
FirstChildUserNameTAG: chauct
FirstChildCreateTimeTAG: 2013-02-23T01:39:12Z
FirstChildVoteTAG: 0
FirstChildTAG: You mean the introduction?
FirstChildUserIdTAG: 1288656
FirstChildUserNameTAG: Damaritos
FirstChildCreateTimeTAG: 2013-02-23T02:20:10Z
FirstChildVoteTAG: 0
FirstChildTAG: > I think the question is.... -where- are the lectures for 1.2 and 1.3?
For those who are lost. The Introduction section has 3 videos. Click on the filmstrip icons.
![enter image description here][1]
Likewise for other lecture sequences (arrow indicates the lectures).
Anything with a blue alarm clock is a graded exercise. Practice exercises are not graded.
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13615874741343624.png
[2]: https://edxuploads.s3.amazonaws.com/13615877791343685.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-23T02:50:41Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you Susan. I found it after a few -hours- of going all over the place, but I got to them by clicking on the next arrows at the bottom of the page where the videos load... -underneath- where you can click to see discussion comments. It looks like they are tabs to click through discussion comments, but they actually load the next lecture. I am so upset right now, I am going to sleep, but I appreciate your help. Thank you.
SecondChildUserIdTAG: 975799
SecondChildUserNameTAG: lmacareo
SecondChildCreateTimeTAG: 2013-02-23T02:53:50Z
SecondChildVoteTAG: 0
SecondChildTAG: There used to be a set of edX introductory videos that explained the system. They were here, but vanished a week or so before the course started. I asked if they could be put up again, but don't know if the staff saw my post.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-23T03:04:40Z
SecondChildVoteTAG: 0
SecondChildTAG: I don't think they did. but you can always register on any other course and it usually it would still be there.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T12:12:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Many thanks for clarifying. I was lost too. In my time zone the material doesn't appear until after 9pm on the each wednesday so I was getting worries about wed 27th! Thanks for clarifying.
Joe
SecondChildUserIdTAG: 956182
SecondChildUserNameTAG: JoeClaxton
SecondChildCreateTimeTAG: 2013-02-24T13:15:01Z
SecondChildVoteTAG: 0
IndexTAG: 2708
TitleTAG: Error in "Exercise Set 2 - Problem 3b" ?
Hello,
I'm resolving Exercise Set 2 Problem 3b and I found an (likely) error in this question, it gives three histograms, one of them is the answer, the option A has 6 bins according to above table however this options is not the answer, the following options have only "5 bins", so none of them cannot be the answer obviously. So there is no solutions for that problem? Moreover the option tagged as the right answer its graphic is drawn incorrectly. Well I think so.
UserIdTAG: 651580
UserNameTAG: AAchilles
CreateTimeTAG: 2013-02-22T23:23:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: This has been brought up before. Please use the search function next time before posting a question to avoid duplicate postings.
However, due to the HONOR CODE, we cannot discuss about this until
the deadline has elapsed.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:26:05Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks jimbangun, and I've used search before posting my message. This mail list is not very friendly to user. The mail list or discussion group in Harvard is more ordered and friendly to user.
SecondChildUserIdTAG: 651580
SecondChildUserNameTAG: AAchilles
SecondChildCreateTimeTAG: 2013-02-22T23:51:58Z
SecondChildVoteTAG: 0
SecondChildTAG: I just did a search and immediately found similar topics.
Yes, I agree about the Harvard thing (having completed CS50x), but they have their own platform/servers and are just using edX as a gateway/link using the student's ID.
This course initially did not have the option to post topics in different sections, but now it does. So hopefully students will start posting in the relevant sections and make the search easier.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T23:58:31Z
SecondChildVoteTAG: 0
FirstChildTAG: go by Exclusion. 2 of the graphs are utterly wrong, while the other only has a minor problem, but is otherwise correct, and you'll need to pick it ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T23:42:44Z
FirstChildVoteTAG: 1
SecondChildTAG: Klionheart, please refrain from breaking the honor code. Thank you.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T23:45:40Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/honor
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T23:46:09Z
SecondChildVoteTAG: 0
SecondChildTAG: I've given no answers, just a minor tip that might or might not help since there may be a problem in the exercise...if one has no idea of what I'm talking about, it's not going to give him/her the answer.
So I don't think I've broken the code ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T23:54:37Z
SecondChildVoteTAG: 0
SecondChildTAG: well your post above just described/discussed about the answer (as well as your other posts in other threads). It is vague, so probably best not to discuss them at all to avoid the possibility of breaking the code.
In other edX courses that I have taken, during midterm and final exams, the discussion board is locked (read only) to avoid 'accidental' discussions.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T00:02:38Z
SecondChildVoteTAG: 0
IndexTAG: 2709
TitleTAG: Is there another exercise to practice
I mistakenly calculated the ratio with 7 instead of 9,that's the drawback of night shift when you tried to awake but failed to be alert.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-22T23:15:43Z
VoteTAG: 3
CoursewareTAG: Practice for Exercise Set 1 / Reading and practice for Exercise Set 1
NumberOfReplyTAG: 4
FirstChildTAG: you are right, it does affect me, too sometimes.
FirstChildUserIdTAG: 264202
FirstChildUserNameTAG: sameziuzor
FirstChildCreateTimeTAG: 2013-02-22T23:42:09Z
FirstChildVoteTAG: 0
SecondChildTAG: I am awake AND alert and STILL got some things wrong.
Yikes.
SecondChildUserIdTAG: 1235638
SecondChildUserNameTAG: MyOwnCamera
SecondChildCreateTimeTAG: 2013-02-23T02:49:21Z
SecondChildVoteTAG: 0
FirstChildTAG: I haven't checked yet, but there might be some more in the Berkeley site/link.
On that site, there are some practice questions that will give you different questions each time to refresh/reload the webpage.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:50:12Z
FirstChildVoteTAG: 0
FirstChildTAG: i think the university should of inform persons when performing the exercise to either round off their answers to the nearest whole number or by one or two decimal points when it came to calculating the percentage.
FirstChildUserIdTAG: 1138388
FirstChildUserNameTAG: Deborah22
FirstChildCreateTimeTAG: 2013-02-23T00:27:46Z
FirstChildVoteTAG: 0
SecondChildTAG: this has been suggested and noted by the staff/teacher in another thread.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T00:31:02Z
SecondChildVoteTAG: 0
FirstChildTAG: I just rounded off to the nearest tenth and that helped
FirstChildUserIdTAG: 641661
FirstChildUserNameTAG: ChemStem
FirstChildCreateTimeTAG: 2013-02-23T00:54:45Z
FirstChildVoteTAG: 0
IndexTAG: 2710
TitleTAG: Captions for Lecture 2.5 don't work
Hello!I'm trying to watch the Lecture 2.5 but, althought I have turned on the captions, they are not shown. I'm not a native english speaker so it will be very helpul to have the captions fixed soon!
UserIdTAG: 1259481
UserNameTAG: MrsFounta
CreateTimeTAG: 2013-02-22T22:53:02Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2711
TitleTAG: question related to set 2 questions
i want to know why my answers was in correct how i could do that
UserIdTAG: 625229
UserNameTAG: alshaimaahmed
CreateTimeTAG: 2013-02-22T22:21:31Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You wait until after the deadline for the assessment. Then the answers will be released and you discuss your issues.
There is a known error, that might or might not still exist.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
And 3b has raised issues too.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T22:50:36Z
FirstChildVoteTAG: 0
IndexTAG: 2712
TitleTAG: Practice exercise lecture 2.2 and 2.3 is wrong I think?
In part a of the practice exercise, the answer states that the width of the class interval is 10; however, the class goes from -10 to 20, which is an interval of 30. Therefore, the answer of 1.4% (14%/10) is incorrect. I think that the correct answer is 0.467% (14%/30). Am I missing something here?
UserIdTAG: 1207647
UserNameTAG: lsummary
CreateTimeTAG: 2013-02-22T22:16:34Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: You are right. I also wanted to point out that mistake.
FirstChildUserIdTAG: 1159651
FirstChildUserNameTAG: KatrienJ
FirstChildCreateTimeTAG: 2013-02-22T22:39:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Same here.
SecondChildUserIdTAG: 955652
SecondChildUserNameTAG: jacopo86
SecondChildCreateTimeTAG: 2013-02-22T22:44:30Z
SecondChildVoteTAG: 0
FirstChildTAG: Searching would show that this is a well documented error.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T22:49:58Z
FirstChildVoteTAG: 0
IndexTAG: 2713
TitleTAG: Professors and Staff: Regarding ES 02
Are you going to correct the grade for the ES 02?
I mean, taking in count that you evaluated as wrong an answer that was actually right, I deserve a 100%, not a 95%.
Thanks for your attention.
UserIdTAG: 797704
UserNameTAG: Hersan13
CreateTimeTAG: 2013-02-22T21:50:21Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:59:45Z
FirstChildVoteTAG: 0
IndexTAG: 2714
TitleTAG: Materials Problem
Help, I can't see the questions at the end of each segment. Where I think they must be, all I see are horizontal blue lines. I am not very "computer smart," but I have tried downloading Chrome, as advised, but I still see the recommendation to install Chrome or Firefox, and still no questions on the page. Thanks for your help.
UserIdTAG: 1036216
UserNameTAG: Parttimer
CreateTimeTAG: 2013-02-22T21:28:50Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: If you installed Chrome, and are using it as your browser, then you shouldn't be getting a message advising you to use it. So not sure what is happening.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T22:02:30Z
FirstChildVoteTAG: 0
FirstChildTAG: have you actually *installed* Chrome after downloading it? And are you using it? If you downloaded Chrome but are still starting Internet Explorer to get on this site it won't help you.
Notice the image of the program you're opening:
This is Chrome: ![Chrome][1] **Double-click this**
This is Internet Explorer: ![enter image description here][2] **Don't touch this one**
Hope this helps ;)
[1]: https://encrypted-tbn3.gstatic.com/images?q=tbn:ANd9GcS5OfjAnhSDOZw4RmMJPXUw9DFgauTQwRRYUHHMS7PnEoW1dQmp
[2]: https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcRod89TtDcrqAUjSnoNeFXXccACZo5-HnyZKgybEQc25-ilKbw7kQ
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T23:06:59Z
FirstChildVoteTAG: 1
IndexTAG: 2715
TitleTAG: Electronic Mails
Hi everibody, warm greetings from Colombia!
For writing them, I am very interested in Latinamerican People E - mails. Please write them in your responses.
Thanks for your polite answers
UserIdTAG: 1240706
UserNameTAG: remipole
CreateTimeTAG: 2013-02-22T20:50:16Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2716
TitleTAG: Exercise Set 2 Problem 2
Why is the answer not 1.3 %? 19.8 / 15
: 2.0 points
Each part is worth 1 point.
a) About what percent of the people were in their thirties? Round your answer to one decimal place.
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-02-22T20:23:25Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I think your issue comes from "Thirties", thats ages 30 - 39 not just one year.
FirstChildUserIdTAG: 1030056
FirstChildUserNameTAG: RBartram
FirstChildCreateTimeTAG: 2013-02-22T20:32:15Z
FirstChildVoteTAG: 1
SecondChildTAG: Yes the question is about people in the 30-39 years of age range
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-22T20:37:10Z
SecondChildVoteTAG: 0
FirstChildTAG: Please uphold the HONOR CODE and refrain from discussing graded exercises until after the deadline.
https://www.edx.org/honor
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:10:40Z
FirstChildVoteTAG: 1
SecondChildTAG: According to the Honor Code we are not allowed to "post answers to problems that are being used to assess student performance". No one said we cannot discuss the problems themselves, especially if it's about understanding specific English words, like "thirties". I believe it's still fair and helps very much to learn. As long as no one posts the correct answer, of course :)
SecondChildUserIdTAG: 517550
SecondChildUserNameTAG: Ewa_G
SecondChildCreateTimeTAG: 2013-02-23T14:24:53Z
SecondChildVoteTAG: 0
SecondChildTAG: This is where this course fails. I don't see any TA's in the discussion forum.
Questions like these should be asked to TA/staff and not to other students.
When you are in a real life classroom and have questions on the graded test, you ask the teacher or staff instead of another student (as the latter could constitute breaking the honor code and may get you expelled from the classroom).
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T21:54:18Z
SecondChildVoteTAG: 0
SecondChildTAG: You are correct it is a violation of the honor code but your comments are more about grades than an education. I have another question on the quiz that I got wrong but if I have to wait because of the honor code than I will probably forget to post it because it is all about grades and not my education.
SecondChildUserIdTAG: 277481
SecondChildUserNameTAG: scott520
SecondChildCreateTimeTAG: 2013-02-27T03:20:43Z
SecondChildVoteTAG: 0
IndexTAG: 2717
TitleTAG: Exercise set 3 problem 1
what are your answers to problem 1? should they be whole numbers (age in years) with no decimals? for example, 18 is the lower quartile, correct?
UserIdTAG: 1249880
UserNameTAG: xuy1
CreateTimeTAG: 2013-02-22T20:07:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: my answers had 1 digit after decimal point and were correct
FirstChildUserIdTAG: 525070
FirstChildUserNameTAG: YL_
FirstChildCreateTimeTAG: 2013-02-22T20:53:30Z
FirstChildVoteTAG: 0
SecondChildTAG: might I ask whether my methods to get there are correct or not?
SecondChildUserIdTAG: 501764
SecondChildUserNameTAG: dasMetzger
SecondChildCreateTimeTAG: 2013-02-23T07:27:58Z
SecondChildVoteTAG: 0
FirstChildTAG: And remember, this is an assessment. Discussing answers, mistakes, asking for help, etc are all against the honour code you agreed to.
You are estimating, so you could have decimal places. When required I used 1dp.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:10:58Z
FirstChildVoteTAG: 0
IndexTAG: 2718
TitleTAG: assignment submissions
If I submit an assignment, may I get an acknowledgment that it has been received?
UserIdTAG: 797869
UserNameTAG: edoz
CreateTimeTAG: 2013-02-22T19:36:11Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Go to the "Progress" tab at the top of the page and you should see your marks.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-02-22T19:37:50Z
FirstChildVoteTAG: 0
SecondChildTAG: You should also get a big red x or green tick next to the question. That means it's been submitted.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-22T19:42:58Z
SecondChildVoteTAG: 0
IndexTAG: 2719
TitleTAG: Entering answers to quizes.
When I try to enter answers to quizzes nothing happens. What do I do?
UserIdTAG: 385997
UserNameTAG: Bruce909
CreateTimeTAG: 2013-02-22T19:06:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Try a different browser. If you are using Firefox, try Chrome. If you are using Chrome, try Firefox.
There are weird browser issues. Some can use Firefox (I can't), some can use Chrome (I can).
The site is apparently optimised for Firefox and Chrome, not other browsers. So if you are using Opera or IE you could have problems.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T23:18:35Z
FirstChildVoteTAG: 0
FirstChildTAG: Did you click on 'Check' or 'Final Check'? Sorry, just had to check to make sure.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:22:42Z
FirstChildVoteTAG: 0
IndexTAG: 2720
TitleTAG: Assignments posted
I have loaded all the technical requirements for the course ware, but when I click through to the assignments, The dates are from January, and say 'yes' to completed. Very odd. I can't seem to change this. Also, I cannot find a student number to complete the top of the form.
UserIdTAG: 1087210
UserNameTAG: AHE
CreateTimeTAG: 2013-02-22T19:00:49Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Where did you click through to? You don't need a student number. Just complete the form on the course page. Exercise Sets 1-3 (ones with the blue alarm clock icon)
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13615670051343609.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:04:12Z
FirstChildVoteTAG: 2
IndexTAG: 2721
TitleTAG: Exercise Set 1 Prob 1
Why isn't income quantitative discrete? If my income is 1234.56, you can't have an arbitrarily larger income. It must jump to 1234.57
UserIdTAG: 917446
UserNameTAG: oherman
CreateTimeTAG: 2013-02-22T18:49:14Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I agree. Almost every currency in the world has a smallest unit of value and every successive value above that is an exact multiple of that smallest unit. Can't get any more discrete than that.
FirstChildUserIdTAG: 144006
FirstChildUserNameTAG: keeny5
FirstChildCreateTimeTAG: 2013-02-22T19:02:58Z
FirstChildVoteTAG: 0
FirstChildTAG: I got that wrong too, and am not sure why.
FirstChildUserIdTAG: 1281619
FirstChildUserNameTAG: sfc17
FirstChildCreateTimeTAG: 2013-02-22T19:28:06Z
FirstChildVoteTAG: 0
FirstChildTAG: Do a search on income in the discussion forum, you'll find lots of reasons.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-22T19:43:37Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/honor
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:30:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Discussion about ambiguous question is not subject of honor code.
SecondChildUserIdTAG: 499526
SecondChildUserNameTAG: nataraja
SecondChildCreateTimeTAG: 2013-02-23T20:43:08Z
SecondChildVoteTAG: 0
IndexTAG: 2722
TitleTAG: Safety issues while Downloading Slides...
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/1361558558134366.png
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-02-22T18:43:01Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: It is a certificate issue.I downloaded it anyway without problems.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T18:45:13Z
FirstChildVoteTAG: 1
SecondChildTAG: So is there no threat if you enter the site anyways?
SecondChildUserIdTAG: 786512
SecondChildUserNameTAG: shoaibkhanz
SecondChildCreateTimeTAG: 2013-02-22T18:46:44Z
SecondChildVoteTAG: 0
FirstChildTAG: nothing to be worried about - see [here][1] ;)
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5127878b8902522700000007
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T18:46:11Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks! :)
SecondChildUserIdTAG: 786512
SecondChildUserNameTAG: shoaibkhanz
SecondChildCreateTimeTAG: 2013-02-22T18:50:00Z
SecondChildVoteTAG: 0
IndexTAG: 2723
TitleTAG: decimals/rounding clarified yet?
Has the decimals/rounding question(s) been clarified yet?
UserIdTAG: 1259984
UserNameTAG: mcc
CreateTimeTAG: 2013-02-22T18:36:06Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes - I'm scared to answer Exercise set 2:3 - I could guess to round my answer to one decimal, because that's what was asked for in the previous problem, but I don't want to get it wrong just for having the wrong number of digits, you know?
FirstChildUserIdTAG: 1002202
FirstChildUserNameTAG: ury949
FirstChildCreateTimeTAG: 2013-02-22T19:12:29Z
FirstChildVoteTAG: 0
SecondChildTAG: If you mean Set 2, Problem 3-a), I rounded to hundredths and got the green tick.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-22T19:31:27Z
SecondChildVoteTAG: 0
SecondChildTAG: i used 1 digit after decimal point, was ok
SecondChildUserIdTAG: 525070
SecondChildUserNameTAG: YL_
SecondChildCreateTimeTAG: 2013-02-22T20:58:30Z
SecondChildVoteTAG: 0
IndexTAG: 2724
TitleTAG: cant view the videoes
hi,
i am unable to view the videos, as youtube is blocked in our country
UserIdTAG: 431054
UserNameTAG: Aishamaryam
CreateTimeTAG: 2013-02-22T18:24:59Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Can't you download them either? There's a link below the video that should work for you, it uses Amazon servers.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T18:47:28Z
FirstChildVoteTAG: 0
IndexTAG: 2725
TitleTAG: When is it planned to correct score for Ex2 P1a?
So, are there any plans to correct scores for the answer on P1a of Exercise set 2?
UserIdTAG: 524348
UserNameTAG: cdracer
CreateTimeTAG: 2013-02-22T18:10:34Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: What was the problem? My answer for Problem 1a on Set 2 when graded was correct.
FirstChildUserIdTAG: 501764
FirstChildUserNameTAG: dasMetzger
FirstChildCreateTimeTAG: 2013-02-22T18:52:23Z
FirstChildVoteTAG: 0
SecondChildTAG: I see that now all is corrected. Issue has been resolved.
SecondChildUserIdTAG: 524348
SecondChildUserNameTAG: cdracer
SecondChildCreateTimeTAG: 2013-02-23T14:10:35Z
SecondChildVoteTAG: 0
IndexTAG: 2726
TitleTAG: Exercise 1 A
Please discuss answers for exercise set-1 Problem 1-a'1-b and 1-d. I got them wrong.
Thanks,
Abhinaya
UserIdTAG: 1195486
UserNameTAG: Abhipuri
CreateTimeTAG: 2013-02-22T18:06:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I know, the answers cannot be discussed before the end of the deadline. Though my answers resemble yours, I have later come to know the answer of 1-d and I can explain it. Now, I would also like to know the explanations for the remaining two after completion of the deadline.
Regards, Asif
FirstChildUserIdTAG: 1093291
FirstChildUserNameTAG: asif8110
FirstChildCreateTimeTAG: 2013-02-22T18:50:02Z
FirstChildVoteTAG: 3
SecondChildTAG: I would suggest going back and looking at the slides and see the examples of each type of variable given there in the lecture
SecondChildUserIdTAG: 160934
SecondChildUserNameTAG: DonnaC
SecondChildCreateTimeTAG: 2013-02-23T00:04:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Can't do it yet - honor code is in effect until the extended due date on the 27th.
1b and 1d should be easy though - 1a might be argued - but that has to come later.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T18:52:00Z
FirstChildVoteTAG: 1
FirstChildTAG: Yes,
there is an issue with 1a that needs to be discussed ;)
FirstChildUserIdTAG: 1011204
FirstChildUserNameTAG: micbog
FirstChildCreateTimeTAG: 2013-02-22T21:12:44Z
FirstChildVoteTAG: 0
IndexTAG: 2727
TitleTAG: Practice for Exercise Set & Answers for graded exercises
Hi all,
Just want to confirm that the practice sets are not counted toward our evaluation, right?
I also have a question about how we can learn from our mistakes for the graded exercises if explanation of answers are not shown after we finish the exercises. I know some problems have 2 attempts, but how about showing the answers after all attemps have been used up. There are a couple of questions where I really don't know why my answers were wrong.
Thanks,
Pyt
UserIdTAG: 1178106
UserNameTAG: pyt
CreateTimeTAG: 2013-02-22T18:03:00Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You'll be able to see the answer, and likely an explanation too, after the deadline - on the 27th. Until then, you can still try to figure it out on your own as an exercise :)
Practice Problems are not counted - check the "Progress" tab for the details of the evaluation.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T18:54:40Z
FirstChildVoteTAG: 1
SecondChildTAG: Do you know where we can find the explanations to wrong answers?
SecondChildUserIdTAG: 1131693
SecondChildUserNameTAG: Catica
SecondChildCreateTimeTAG: 2013-03-02T20:43:21Z
SecondChildVoteTAG: 0
IndexTAG: 2728
TitleTAG: Surely, videos are so interesting. The course is well conceived
Looking forward to succeeding well
UserIdTAG: 875174
UserNameTAG: tuyibona2020
CreateTimeTAG: 2013-02-22T17:39:55Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The videos are very informative and present good information to help conceptualize the topic of instruction.
FirstChildUserIdTAG: 4612
FirstChildUserNameTAG: Susnaj
FirstChildCreateTimeTAG: 2013-02-22T20:21:30Z
FirstChildVoteTAG: 0
IndexTAG: 2729
TitleTAG: Bonaventure/Rwanda
videos are so interesting. This course is well conceived
UserIdTAG: 875174
UserNameTAG: tuyibona2020
CreateTimeTAG: 2013-02-22T17:36:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Hello, tuyibona2020. Thanks for the kind words.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-23T05:17:33Z
FirstChildVoteTAG: 0
IndexTAG: 2730
TitleTAG: Problem 1 A
In Problem 1.a) Which interval contained more people: 5-15 or 15-20?
I think the answer is 5 -15, but contained incorrect.
UserIdTAG: 278833
UserNameTAG: Camila_Adorno
CreateTimeTAG: 2013-02-22T16:56:36Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I've seen this already reported on the forum. It didn't happen to me, strangely, but yes, if it's marked incorrect for you, it's a bug.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T17:35:56Z
FirstChildVoteTAG: 0
FirstChildTAG: This is a known issue. Those who were marked wrong incorrectly will be given the mark. Don't know when.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:13:59Z
FirstChildVoteTAG: 0
IndexTAG: 2731
TitleTAG: Provided details for proper answer submition
Greetings instructors. I have just begun the class and am working my way through the first few exercises. I was hoping that for exercise it could be made clear what the proper form for a particular answer should look like. As a teacher myself I know that it is hard to predict what a student is going to plug in as an answer and while we (as humans) have the ability to comprehend 14.1% and 14.1 percent as the same thing a computer struggles with this type of thinking. Any clarification would be greatly appreciated.
Thank you,
Benjamin Childers
UserIdTAG: 840238
UserNameTAG: bchilders
CreateTimeTAG: 2013-02-22T16:52:13Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: All the examples so far require number only and, unless specified, seem to expect one decimal place. The course team are, apparently, going to make expectations more explicit in future exercises.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-02-22T19:40:01Z
FirstChildVoteTAG: 0
IndexTAG: 2732
TitleTAG: Excercise 1 Problem 3 b
Choose the appropriate graph for data
270 - M/G
90 - R/G
20 - G/G
= 380 With Green
30 - R/R
90 - M/R
= 120 without green
Chose Bar option 2 but answer came up wrong. Answer 4 looked like the same graph too.
Confused??
UserIdTAG: 1062898
UserNameTAG: KabirGrewal
CreateTimeTAG: 2013-02-22T16:49:35Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: The vertical axis is different. Got me as well.
FirstChildUserIdTAG: 840238
FirstChildUserNameTAG: bchilders
FirstChildCreateTimeTAG: 2013-02-22T16:52:42Z
FirstChildVoteTAG: 0
SecondChildTAG: yeah very tricky indeed
SecondChildUserIdTAG: 1247416
SecondChildUserNameTAG: Gmamout
SecondChildCreateTimeTAG: 2013-02-22T17:09:27Z
SecondChildVoteTAG: 0
FirstChildTAG: I was caught too. I scrolled up and down to compare many times and they look identical.
bchilders, how is the vertical axis different? They look identical to me.
FirstChildUserIdTAG: 897162
FirstChildUserNameTAG: kymwkl
FirstChildCreateTimeTAG: 2013-02-22T17:39:15Z
FirstChildVoteTAG: 0
SecondChildTAG: Read the text ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T17:54:30Z
SecondChildVoteTAG: 0
SecondChildTAG: the units are different - one is probablity one is number of plants
SecondChildUserIdTAG: 160934
SecondChildUserNameTAG: DonnaC
SecondChildCreateTimeTAG: 2013-02-22T20:25:02Z
SecondChildVoteTAG: 0
FirstChildTAG: the vertical axis is different one named percentile (2nd graph) and the other is number pf plants (4th one)
FirstChildUserIdTAG: 625229
FirstChildUserNameTAG: alshaimaahmed
FirstChildCreateTimeTAG: 2013-02-22T18:24:26Z
FirstChildVoteTAG: 0
FirstChildTAG: Me too. I didn't recognize the difference between 2nd and 4th choice.
FirstChildUserIdTAG: 1248471
FirstChildUserNameTAG: yingchenid
FirstChildCreateTimeTAG: 2013-02-22T20:51:02Z
FirstChildVoteTAG: 0
FirstChildTAG: Does anyone here understand the concept of HONOR CODE at all?
You are NOT supposed to discuss graded exercises until after the deadline.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:07:05Z
FirstChildVoteTAG: 0
IndexTAG: 2733
TitleTAG: Exercise Set 2 Problem 2
I think that 'over the age of 65' in the question actually needs to be read as '65 or over' - a rather different meaning from that actually stated which affects the correct answer (or otherwise I got my calculations wrong)
UserIdTAG: 1004185
UserNameTAG: ale1808
CreateTimeTAG: 2013-02-22T15:45:56Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 8
FirstChildTAG: Pretty sure it actually means 66+, since I did my calculations based on that, and I got the right answer ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T15:50:07Z
FirstChildVoteTAG: 0
SecondChildTAG: then I got the math wrong- thanks
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-22T15:52:40Z
SecondChildVoteTAG: 0
SecondChildTAG: you have taken into account the endpoint convention that exclude the right end point (75 years for the case in point)
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-22T15:55:16Z
SecondChildVoteTAG: 0
SecondChildTAG: If I use 66+ I'm having the wrong answer, but I'm pretty sure that I'm doing it well. Are you sure that you only counted nine items in the class (66-67-68-69-70-71-72-73-74, because you have to exclude the 75)?
SecondChildUserIdTAG: 1000285
SecondChildUserNameTAG: Zanot
SecondChildCreateTimeTAG: 2013-02-22T16:40:52Z
SecondChildVoteTAG: 0
SecondChildTAG: mmm. Doing the problem again, I see your point now.
Yes, when I did it yesterday, I must have incorrectly included the 75, because you're right, it turns out wrong using 66+ properly :o
So, ale1808, you're right...unless this is a bug in the problem and the correct answer is actually different, the question needs to read "65 or over".
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T17:05:33Z
SecondChildVoteTAG: 0
SecondChildTAG: How do you guys check if the question is right or not? I dont know about you but i added up both intervals (60-75, of course counting from 65 to 74,and 75 to 100) since the question addresses the seniors among the whole population and not only in the interval 60-75. A common (though not universal) definition of "senior citizen" is "person over the age of 65". About what percent of the **population** were senior citizens?
SecondChildUserIdTAG: 1256931
SecondChildUserNameTAG: Jhoara
SecondChildCreateTimeTAG: 2013-02-22T17:19:44Z
SecondChildVoteTAG: 0
SecondChildTAG: by the way it was right!
SecondChildUserIdTAG: 1256931
SecondChildUserNameTAG: Jhoara
SecondChildCreateTimeTAG: 2013-02-22T17:45:56Z
SecondChildVoteTAG: 0
SecondChildTAG: That's the procedure, yes. Of course you can't just add up both intervals, since 60-75 includes people who are *not* seniors. The proportion that you take of that interval depends on whether we include people who are 65 or not.
We're skirting the honor code enough already, so I can't be more specific.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T17:47:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Im confued about this question too. thought to calculate 65-100
SecondChildUserIdTAG: 1271797
SecondChildUserNameTAG: luvmissellie
SecondChildCreateTimeTAG: 2013-02-22T19:32:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Ihave a problem with this problem. I have solved it taking into account 66+ but got wrong answers. Have you written the answers in percentage?
SecondChildUserIdTAG: 1270084
SecondChildUserNameTAG: ArminDani
SecondChildCreateTimeTAG: 2013-02-26T18:04:15Z
SecondChildVoteTAG: 0
SecondChildTAG: I gave up on this...
SecondChildUserIdTAG: 1112435
SecondChildUserNameTAG: Chena
SecondChildCreateTimeTAG: 2013-02-27T21:44:41Z
SecondChildVoteTAG: 0
FirstChildTAG: You need to include 65 as well then you get 14.3; it says this is the right answer. But if you proceed according to the question, that is, you do not include 65, then you get 13.5; then it says your answer is wrong. So basically i guess the question should have been 65 and above and not above 65.
FirstChildUserIdTAG: 1057432
FirstChildUserNameTAG: achalrm
FirstChildCreateTimeTAG: 2013-02-22T18:20:23Z
FirstChildVoteTAG: 0
SecondChildTAG: too late for me, but worth pointing out that this is a mistake in the way the question is worded
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-22T20:41:37Z
SecondChildVoteTAG: 0
FirstChildTAG: I too get the wrong answer for this question. The question is
b) A common (though not universal) definition of "senior citizen" is "person over the age of 65". About what percent of the population were senior citizens? Round your answer to one decimal place.
1) My first step is to calculate the density of the 60-75 interval.
12.5 / 75-60 = 12.5 / 15 = 0.83333
2) Then I calculate the percent of the people in this interval who are not consider senior (i.e. those younger than 66 year old). (60, 61, 62, 63, 64, 65) = 6. 0.8333 * 6 = 5%
3) Then I calculate the percent of people in this group who are considered Senior. 12.5% - 5% = 7.5%.
4) Then I add this 7.5% with the 6% for the last interval to arrive at 13.5%. But my answer is mark incorrect.
Can someone tell me where did I go wrong?
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-22T18:46:50Z
FirstChildVoteTAG: 1
SecondChildTAG: It's either a bug in the program that is including 75 in the 60-75 bin... or the instructor incorrectly wrote the problem where people of age 65 ARE considered senior citizens.
Your method tho does have an extra step, though. Combine Steps 2 and 3 by just multiplying your found per unit % by the number of units in the bin that are considered 'senior citizens'. In this case, everything 65 and up (10 units). Multiple .833 by 10 to get 8.3%... then add your 6% from the 75+ bin, to get the correct answer of 14.3
SecondChildUserIdTAG: 501764
SecondChildUserNameTAG: dasMetzger
SecondChildCreateTimeTAG: 2013-02-22T19:10:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Pls I need to know what you got for the percentage of those in their thirties as I obtained 5.3 and I was told I am wrong
SecondChildUserIdTAG: 828309
SecondChildUserNameTAG: Uforoabaz
SecondChildCreateTimeTAG: 2013-02-27T23:00:57Z
SecondChildVoteTAG: 0
FirstChildTAG: Regarding Problem No. 2., what irritates me is when the directions state: "[i]ntervals include left endpoint but not the right"-when in order to derive what the program is considering as the 'correct' answer, for 2a., in finding the height of the actual class interval, you have to include the right endpoint as well; whereas the correct answer for 2b., actually corresponds with the way the initial instructions are given.
FirstChildUserIdTAG: 7286
FirstChildUserNameTAG: ptfrizz
FirstChildCreateTimeTAG: 2013-02-22T20:59:35Z
FirstChildVoteTAG: 1
FirstChildTAG: Does anyone seem to have a problem with Question 3b of Exercise Set 2?
"b) Which of the following is a correct histogram based on this table?"
I don't think any of them are correct considering all the intervals labelled on the x-axis are equal. Although through process of elimination I can maybe arrive at the right answer but somehow am not convinced that any of the options are correct(!). Its not meant as a challenge, but am I missing something obvious...?
Can anyone please enlighten me? I am very confused..
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-02-22T22:35:57Z
FirstChildVoteTAG: 0
SecondChildTAG: There is an issue with the histograms. One is almost correct, and is given the green tick.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-23T03:49:29Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks very much. Good to know that I am not the only one left bewildered!
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-23T11:14:04Z
SecondChildVoteTAG: 0
SecondChildTAG: The correct one is almost correct! Just go with the best answer...
SecondChildUserIdTAG: 1247915
SecondChildUserNameTAG: Iliri2013
SecondChildCreateTimeTAG: 2013-02-24T08:10:45Z
SecondChildVoteTAG: 0
FirstChildTAG: Does anyone here understand the concept of the HONOR CODE at all?
You are NOT supposed to discuss the graded exercises until after the deadline.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:05:40Z
FirstChildVoteTAG: 1
SecondChildTAG: https://www.edx.org/honor
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T23:32:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I very much appreciate your campaign to get people to stop posting answers. That said, for situations where they are informing staff and students that the approved answer is incorrect, I think it is pardonable.
SecondChildUserIdTAG: 969411
SecondChildUserNameTAG: McAlary
SecondChildCreateTimeTAG: 2013-02-23T00:43:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, I agree with you.
Questions and responses of such should OK.
Responses such as 'you need to use 66 and not 65' or 'there are 2 options that are incorrect' etc. are the sketchy ones.
Put it this way, if you are doing a 'personal' graded test or quiz or exam in school, are students allowed to talk to each other and provide tips/hints? I don't think so, right? But a student is allowed to ask the teacher/TA to confirm any potential errors in the question or answer options.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T00:56:14Z
SecondChildVoteTAG: 0
SecondChildTAG: Also responses where one divulges his/her method and calculations of deriving the potential answer is also not OK in my opinion. A simple 'yes, i believe there is an error and could the staff/TA please confirm' would suffice. :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T00:59:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I think I was overly sympathetic to the answer posters because of the frustration and feeling of stupidity I experienced trying to sort out why I wasn't getting the right answer. I agree with everything you said. And fwiw, if staff is reading this, the frustration I experienced pales in comparison to my great appreciation for this wonderful treasure of a course! :)
SecondChildUserIdTAG: 969411
SecondChildUserNameTAG: McAlary
SecondChildCreateTimeTAG: 2013-02-23T09:08:00Z
SecondChildVoteTAG: 0
FirstChildTAG: exer set2 prob. 2 wording is messed up. plain and simple.
FirstChildUserIdTAG: 1259984
FirstChildUserNameTAG: mcc
FirstChildCreateTimeTAG: 2013-02-22T23:23:50Z
FirstChildVoteTAG: 0
FirstChildTAG: The staff should reconsider of excluding this question from the test as it is not clear what over 65 means. It is that or they've included 75 in the 60-75 interval, as someone already stated. So, at least, I think the staff should address the students and clarify this issue.
FirstChildUserIdTAG: 302329
FirstChildUserNameTAG: markomarkovic
FirstChildCreateTimeTAG: 2013-02-28T23:19:19Z
FirstChildVoteTAG: 0
IndexTAG: 2734
TitleTAG: Thank you, Prof. Adhikari
Prof. Adhikari - I work within the learning organization of a multi-national technology consulting firm. This is the first class I've taken a course on edX and was so pleased with the first few lectures you gave. Still working my way through the rest, now. :)
I just wanted to say how much I appreciate your delivery style - it is clear, concise, and entertaining - 3 adjectives I would have never associated with instruction in statistics. Teaching is definitely in your DNA - thank you for sharing your gifts with us!
UserIdTAG: 1268544
UserNameTAG: TWStiles
CreateTimeTAG: 2013-02-22T15:30:53Z
VoteTAG: 13
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: I second that. I am a teacher myself and she has become my role model. The Professor is really gifted.
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-02-22T17:13:31Z
FirstChildVoteTAG: 3
FirstChildTAG: I would like to say thank to Professors Ani Adhikari and Philip B. Stark, the University of California Berkeley, and EdX, and Universities, and all the good people involve in this great and generous undertaking to share and enrich our world with your kindness, knowledge, and intelligence. Thank you so much. We are greatly appreciate it.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-22T18:51:01Z
FirstChildVoteTAG: 3
FirstChildTAG: I "second" what's been said. I've found the videos to be wonderfully done, very clear, and with great content. I'm so appreciative of the effort it took to put them together, and can't wait for the course to continue. Kudos to all involved!
Terry
FirstChildUserIdTAG: 1271361
FirstChildUserNameTAG: TerryBot
FirstChildCreateTimeTAG: 2013-02-22T18:56:25Z
FirstChildVoteTAG: 1
FirstChildTAG: I don't know it has been planned or not, but the selection of Prof. Adhikari to give vocal of the lectures is truly convenient, especially for us who belong Indian subcontinent because of her pronunciation.
Asif
FirstChildUserIdTAG: 1093291
FirstChildUserNameTAG: asif8110
FirstChildCreateTimeTAG: 2013-02-22T19:02:05Z
FirstChildVoteTAG: 1
FirstChildTAG: I am very satisfied at the first part end. It was something difficult but very interesting, exciting and amazing! Thanks
FirstChildUserIdTAG: 1240706
FirstChildUserNameTAG: remipole
FirstChildCreateTimeTAG: 2013-02-22T20:46:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you all for the kind words. It's my goal to make this course enjoyable and informative for you. Most of you are taking it over and above your regular work, family responsibilities, and so on, and I know how hard that is. Thanks for joining me in this venture; it's new for me, and very rewarding already.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-23T05:32:33Z
FirstChildVoteTAG: 1
IndexTAG: 2735
TitleTAG: No caption in lecture 2.5
There's no caption available for video lecture 2.5; is it possible to provide it? It's very useful for people (like me...) that have some problems with spoken english.
Thank you
UserIdTAG: 937105
UserNameTAG: Peppone1965
CreateTimeTAG: 2013-02-22T15:28:59Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I assume you meant the lecture transcript. There are on-screen captions, but no transcript. I find both useful as I cannot hear the audio very well.
FirstChildUserIdTAG: 441413
FirstChildUserNameTAG: coyotecoach
FirstChildCreateTimeTAG: 2013-02-22T18:32:54Z
FirstChildVoteTAG: 0
IndexTAG: 2736
TitleTAG: Textbook additional videos are too long
Are we supposed to watch the videos in the textbook? The first one, trade secret data, is more than one hour long.
UserIdTAG: 937399
UserNameTAG: fernandocalero
CreateTimeTAG: 2013-02-22T15:07:44Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: That is the video of the whole book.Only the relevant part is shown which is a few minutes long.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T15:08:58Z
FirstChildVoteTAG: 0
IndexTAG: 2737
TitleTAG: Exercise Set 3
Hello. Can it be checked the solution for the 3b question? I read carefully but I always get the same uncorrect answer. Thanks
UserIdTAG: 249419
UserNameTAG: mgmartinez
CreateTimeTAG: 2013-02-22T15:01:39Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: There is a correct answer.Since it is still open for evaluation we cannot discuss it but using a scale /ruler can help evaluate the points.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T15:03:55Z
FirstChildVoteTAG: 0
FirstChildTAG: I wonder if we need to do all the calculations (i.e lower+upper bounds and result with one decimal place) or just use the stem graphic to look for the "exact" numbers (and asking the question of % of observations before the given percentile). Thanks!
FirstChildUserIdTAG: 437379
FirstChildUserNameTAG: MaisaSM
FirstChildCreateTimeTAG: 2013-02-22T15:57:16Z
FirstChildVoteTAG: 0
SecondChildTAG: No calculations needed. Just look at the graphs, and it should be easy to spot the right one(*hint:* look at the lower quartile first)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T16:09:34Z
SecondChildVoteTAG: 0
SecondChildTAG: I made a mistake with this one too - I was using Excel to make the stem and leaf plots which meant that the leading zeroes were lost. Therefore the number of classes and the answers were wrong. Fortunately that question allowed two goes, so I got the opportunity to work out the problem and fix it.
SecondChildUserIdTAG: 1226786
SecondChildUserNameTAG: goodhen
SecondChildCreateTimeTAG: 2013-02-22T17:17:50Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/honor
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T23:32:46Z
SecondChildVoteTAG: 0
IndexTAG: 2738
TitleTAG: Sticky Posts
Is there a way to have a "Sticky Post" that stays on the top - for eg the courseware errata(regarding the question which has an error has been repeated ad nauseum so if it would be up on the top as a sticky note it would decrease such requests.
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-22T15:00:11Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: based on my personal experience having taken 5 edX courses, I believe the current edX platform does not have this capability.
However there is the Wiki, where you can post links and share topics.
You can also 'follow' the posts you like by clicking on the star at the top right hand corner of the first message in the thread.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:42:23Z
FirstChildVoteTAG: 0
IndexTAG: 2739
TitleTAG: For Staff - Warning message received when trying to download slides
Pressing the Lecture 2.3 Slides caused this warning to appear on Screen:
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13615450671343665.jpg
UserIdTAG: 482610
UserNameTAG: Atir
CreateTimeTAG: 2013-02-22T14:58:19Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: You can use proceed anyway - it is related to some web certificates.Check the header of the URL if it is correct.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T15:01:03Z
FirstChildVoteTAG: 0
FirstChildTAG: I got this message - an over-sensitive virus checker perhaps. I downloaded the slide and ran a check on it alone - seems OK. You should be safe enough downloading it.
FirstChildUserIdTAG: 20879
FirstChildUserNameTAG: forevergreen
FirstChildCreateTimeTAG: 2013-02-22T15:46:54Z
FirstChildVoteTAG: 0
FirstChildTAG: Virus checker has nothing to do with it - it's a slight configuration error that your browser is picking up.
In layman's terms, the server uses a certificate to prove it's what it says it is. Problem is, the certificate used here is only valid for *something*.edx.org. For example, www.edx.org, or ftp.edx.org.
The slides, on the other hand, are linked to edx.org - the lack of www isn't really a problem for the webserver, but registers as a different website to the browser - hence the warning.
Nothing serious in this case, don't worry ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T16:04:29Z
FirstChildVoteTAG: 0
SecondChildTAG: If you are **really** worried about clicking that "Proceed anyway" button, though, there's a trick you can use.
Right click on the slide link-->click *"Copy link address"*, then paste into the browser's address bar. Manually add *www.* between *https://* and *edx.org*, and press enter. Voila ;)
*(though, really, it's much easier to just ignore the warning and proceed in this case)*
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T16:18:04Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks everybody for your advice,however:
I think that in a "well behaved" system, intended to support thouthands of users it should not happen, thous, I addressed it to the "Staff".
Again, thank you for your help.
FirstChildUserIdTAG: 482610
FirstChildUserNameTAG: Atir
FirstChildCreateTimeTAG: 2013-02-22T17:18:16Z
FirstChildVoteTAG: 0
IndexTAG: 2740
TitleTAG: Question to PRACTICE FOR EXERCISE SET 2
Hi everyone.
Here's what I encountered.
"Height of -10 to 20 bar = ____________ % per unit". It's a problem in the "practice for exercise set 2".
So we need to simply divide 14% by the width of class interval. And that's where I faced a problem. The solution shows the width of class interval of (-10 to 20) as 10, while I think it should be 30.
Could anyone explain, please?
UserIdTAG: 1254814
UserNameTAG: Denys1
CreateTimeTAG: 2013-02-22T14:09:03Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Please use the search function.This has already been described in the errata as a mistake.
[Courseware errata][1]
Click on the link to go there
[1]: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T14:20:33Z
FirstChildVoteTAG: 3
SecondChildTAG: So fix the problem and solution
SecondChildUserIdTAG: 274577
SecondChildUserNameTAG: scanning
SecondChildCreateTimeTAG: 2013-02-22T14:44:09Z
SecondChildVoteTAG: 0
SecondChildTAG: Sorry I cannot as I am not an admin but checking the list using the search function also has been recommended :)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T14:51:39Z
SecondChildVoteTAG: 0
FirstChildTAG: Your answer is correct. I believe the staff simply make a mistake that needs to be correct. The formula for the height of a bar is
height for bar = area / right end point - left end point
The right end point is 20 and the left end point is -10. So 20 - (-10) = 20 + 10 = 30 units. If we go from -10 to +20 there are 30 steps or units. 30 is the absolute value. There is nothing wrong with our answers.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-22T17:35:13Z
FirstChildVoteTAG: 0
SecondChildTAG: I just encountered the same problem, and I had gotten a width interval of 30 units as well; whereas, the height of the bar is equal to the rate of the percentage in the interval, and the width of the interval-width of the interval meaning the difference of the right endpoint and the left endpoint.
What a relief, I really thought I was going crazy for a moment.
SecondChildUserIdTAG: 7286
SecondChildUserNameTAG: ptfrizz
SecondChildCreateTimeTAG: 2013-02-22T19:40:01Z
SecondChildVoteTAG: 0
IndexTAG: 2741
TitleTAG: Chapter 2 of the textbook
I was very surprised to see the following argument described as logically valid in one of the exercises in chapter 2 of the texbook:
It is warm. Therefore, it is not cold.
In propositional logic this is of the form. P therefore not-Q
Hence clearly fallacious. It is an example of material inference which could be turned into a valid argument by the addition of the premise:
If P then not-Q
UserIdTAG: 1004185
UserNameTAG: ale1808
CreateTimeTAG: 2013-02-22T14:00:31Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Assuming that cold is the exact opposite of warm (cold = not warm), the argument is 'If P then not(not p)'.
FirstChildUserIdTAG: 178532
FirstChildUserNameTAG: CruiZen
FirstChildCreateTimeTAG: 2013-02-22T14:16:05Z
FirstChildVoteTAG: 0
SecondChildTAG: But that presupposes that you understand the meaning of the words, which is precisely what you are not allowed to presuppose in formal logic. Trust me it is a material inference. I teach logic
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-22T14:22:44Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree--it does depend on the meaning of the propositions, and formally it is [if P then (not Q)]. I'll change it.
Thank you for the careful reading!
Philip
SecondChildUserIdTAG: 990671
SecondChildUserNameTAG: pstark
SecondChildCreateTimeTAG: 2013-02-22T15:10:57Z
SecondChildVoteTAG: 0
SecondChildTAG: While I agree with your point, after re-reading the questions in this chapter (which is supposed to be rather informal, compared with the chapter on propositional logic), I beg you to indulge me by reading "not warm" for "cold" and "not cold" for warm.
Thank you,
Philip
SecondChildUserIdTAG: 990671
SecondChildUserNameTAG: pstark
SecondChildCreateTimeTAG: 2013-02-22T15:16:57Z
SecondChildVoteTAG: 0
IndexTAG: 2742
TitleTAG: How do I add my name to the student list
I tried to add my name to the student list. I just can't get the bullet point down. Help
UserIdTAG: 1246920
UserNameTAG: dzame
CreateTimeTAG: 2013-02-22T13:42:47Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: plz could i get the time table of the class so that i can access the course , and even my name is not appearing the class .thanks
FirstChildUserIdTAG: 1166704
FirstChildUserNameTAG: cabdijalil
FirstChildCreateTimeTAG: 2013-02-22T14:05:51Z
FirstChildVoteTAG: 0
SecondChildTAG: [Course schedule][1] (Click on the link)
[1]: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Course_Schedule.pdf
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T14:25:05Z
SecondChildVoteTAG: 0
SecondChildTAG: the student list in the Wiki is not compulsory and if you want your name there then you need to add it yourself. The list has no effect to the pass/fail of the course, so don't worry if your name is not there.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T23:44:29Z
SecondChildVoteTAG: 0
FirstChildTAG: Dzame, you have to use an asterisk (*) for the bullet point in the students' directory.
FirstChildUserIdTAG: 47031
FirstChildUserNameTAG: PrernaDewan
FirstChildCreateTimeTAG: 2013-02-22T22:39:14Z
FirstChildVoteTAG: 0
IndexTAG: 2743
TitleTAG: Smart trick !!! Being Lazy
DESCRIBING ONE QUANTITATIVE VARIABLE.
6 | 337
I've to admit it. I've never think like that before.
That a very smart why to optimize data !!! I need this in algorithmic.
UserIdTAG: 147126
UserNameTAG: simopr
CreateTimeTAG: 2013-02-22T13:37:10Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: True!
Love that idea
FirstChildUserIdTAG: 1286060
FirstChildUserNameTAG: Calliditas
FirstChildCreateTimeTAG: 2013-02-22T21:40:44Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, Tukey was brilliant at coming up with simple ways to see the major aspects of a dataset, "on the back of an envelope". I too am a fan of the lazy path to insight! Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-23T05:20:32Z
FirstChildVoteTAG: 0
IndexTAG: 2744
TitleTAG: Exercise Set 2
In exercise set 2,nothing seems to work right.. At problem 4, there is no mentions at the age the kids start their 12 years of school. Seems guessing didn't awarded my 3 points. At the other problems, everything seems to work wrong, because the decimal numbers or the fact that one decimal wrong will bury the entire result. Anyway, hope the problem will be fixed. Cheers!
UserIdTAG: 1216723
UserNameTAG: Darkennoia
CreateTimeTAG: 2013-02-22T13:30:10Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: exactly i m also facing same problem...not getting even how to do questions....all the answers are cuming wrong
FirstChildUserIdTAG: 907864
FirstChildUserNameTAG: TANVI11
FirstChildCreateTimeTAG: 2013-02-22T13:43:52Z
FirstChildVoteTAG: 0
SecondChildTAG: those exercise me i have not seen so plz were i can get ???
SecondChildUserIdTAG: 1166704
SecondChildUserNameTAG: cabdijalil
SecondChildCreateTimeTAG: 2013-02-22T14:08:09Z
SecondChildVoteTAG: 0
SecondChildTAG: age of the student is not relevant for this problem. The intervals are years of education or learning.
SecondChildUserIdTAG: 374969
SecondChildUserNameTAG: kjinjil
SecondChildCreateTimeTAG: 2013-02-22T16:56:51Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/honor
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T23:33:52Z
SecondChildVoteTAG: 0
FirstChildTAG: For problem 4: what do you need the starting ages for? The data measures the years of schooling, **not** the ages of the people. Maybe that's the point you're getting confused on. If a child starts school at 5, or if he starts at 10, he'll still need to do 12 years to get his diploma.
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T14:19:01Z
FirstChildVoteTAG: 3
SecondChildTAG: this is what I meant in the other thread, my friend. :-)
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T00:06:21Z
SecondChildVoteTAG: 0
FirstChildTAG: I think it would be better if you include the question in your post so that we know exactly what question and which part.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-22T18:54:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Once again, does anyone here understand the HONOR CODE at all?
You are NOT supposed to discuss the graded exercises until after the deadline.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:08:55Z
FirstChildVoteTAG: 1
FirstChildTAG: https://www.edx.org/honor
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:33:22Z
FirstChildVoteTAG: 1
IndexTAG: 2745
TitleTAG: Practice set 2
Problems for lec 2.2and 2.3
the second last question, the interval width for -10 to 20 should be 30 and not 10, right?
UserIdTAG: 1032929
UserNameTAG: Sailee
CreateTimeTAG: 2013-02-22T13:28:00Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: I came to the same conclusion... based on the provided material, the width of the bin is 20-(-10) = 30, and not 10 as given in the answer
Please correct me if I'm wrong
FirstChildUserIdTAG: 82472
FirstChildUserNameTAG: SSchocke
FirstChildCreateTimeTAG: 2013-02-22T13:41:32Z
FirstChildVoteTAG: 0
SecondChildTAG: You're right buddy!
SecondChildUserIdTAG: 787465
SecondChildUserNameTAG: Andrey-Serge
SecondChildCreateTimeTAG: 2013-02-22T14:05:33Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree with that too... the height must be 0.467% not 1.4% as the answer suggests!
FirstChildUserIdTAG: 987667
FirstChildUserNameTAG: adikt
FirstChildCreateTimeTAG: 2013-02-22T13:53:18Z
FirstChildVoteTAG: 0
FirstChildTAG: do you people bother to use search function in this forum?
This has been already discussed ad nauseam
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-22T13:55:56Z
FirstChildVoteTAG: 0
SecondChildTAG: value added comment
SecondChildUserIdTAG: 501764
SecondChildUserNameTAG: dasMetzger
SecondChildCreateTimeTAG: 2013-02-22T14:38:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I find "you people" offensive
SecondChildUserIdTAG: 7854
SecondChildUserNameTAG: pejic
SecondChildCreateTimeTAG: 2013-02-22T15:30:06Z
SecondChildVoteTAG: 0
FirstChildTAG: Just came by to check for it as I thought I was seeing things. The width of the interval is definitely 30 and not 10.
FirstChildUserIdTAG: 1234540
FirstChildUserNameTAG: suspor
FirstChildCreateTimeTAG: 2013-02-22T14:03:51Z
FirstChildVoteTAG: 2
FirstChildTAG: Explanation
The height of a bar is equal to: relative frequency in the class interval/width of class interval. Therefore, the height of the -10 to 20 bar is 14/10 = 1.4% per unit. WRONG!!!!! RIGHT ANSWER IS 0.47! Please check all exersises for this mistake!
FirstChildUserIdTAG: 787465
FirstChildUserNameTAG: Andrey-Serge
FirstChildCreateTimeTAG: 2013-02-22T14:03:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Not fixed yet. I tried to solve it right away but it is still 10.
I think these kind of bugs should be handled faster.
FirstChildUserIdTAG: 147126
FirstChildUserNameTAG: simopr
FirstChildCreateTimeTAG: 2013-02-22T14:44:45Z
FirstChildVoteTAG: 0
SecondChildTAG: I guess they miss "-" and calculate as from 10 to 20, if so they could be right :) but anyway they mistaken, not we :)
SecondChildUserIdTAG: 787465
SecondChildUserNameTAG: Andrey-Serge
SecondChildCreateTimeTAG: 2013-02-22T14:57:30Z
SecondChildVoteTAG: 0
SecondChildTAG: As long as the bug only affects an ungraded exercise, the fix isn't all that time-critical. Though it *should* be easy to fix.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T16:12:57Z
SecondChildVoteTAG: 0
IndexTAG: 2746
TitleTAG: Suggestion of Discussion Board
I have a suggestion to make this discuss board much better. Staffs can divide this board into several sections, like Lecture 1, Lecture 2,..., Exercise 1, Exercise 2,..., Practice 1, Practice 2,... and move all the discussion into corresponding sections. I think this could make students make the most of the discussion board and avoid post the same questions again.
UserIdTAG: 892981
UserNameTAG: YuanjiSun
CreateTimeTAG: 2013-02-22T13:25:07Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: That would make it more efficient than it currently is. Unless you know what you are searching for - it's a bit hit and miss at present.
FirstChildUserIdTAG: 20879
FirstChildUserNameTAG: forevergreen
FirstChildCreateTimeTAG: 2013-02-22T15:49:41Z
FirstChildVoteTAG: 1
FirstChildTAG: YuanjiSun, forevergreen -- that organizational improvement for discussion forums is coming your way shortly!
FirstChildUserIdTAG: 469111
FirstChildUserNameTAG: romyr
FirstChildCreateTimeTAG: 2013-02-22T16:38:06Z
FirstChildVoteTAG: 2
SecondChildTAG: Great, thanks a lot!
SecondChildUserIdTAG: 892981
SecondChildUserNameTAG: YuanjiSun
SecondChildCreateTimeTAG: 2013-02-23T00:31:43Z
SecondChildVoteTAG: 0
FirstChildTAG: That is how the forums are supposed to work. At least, they do on all other edX courses I have looked at.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:20:45Z
FirstChildVoteTAG: 0
FirstChildTAG: And it has been activated!
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T23:34:51Z
FirstChildVoteTAG: 0
IndexTAG: 2747
TitleTAG: Submission of solutions
I seem to be unable to submit solutions. How does one know if a solution set has been submitted?
UserIdTAG: 731309
UserNameTAG: eesterbauer
CreateTimeTAG: 2013-02-22T13:10:27Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: You have used #noCount of 2 submissions. #noCount would increase by one
FirstChildUserIdTAG: 157670
FirstChildUserNameTAG: _Nelson_
FirstChildCreateTimeTAG: 2013-02-22T13:14:49Z
FirstChildVoteTAG: 0
FirstChildTAG: ![enter image description here][1]
If you have submitted you will have either a green tick or a red cross (if you are wrong). Your number of submissions will be noted. The example above allows 2 submissions. I used one, and the comment acknowledges that. If you make a mistake and you are allowed more than 1 submission, then you can try again.
If you used all X submissions allowed you would have a message saying "Used X of X submissions" and the Check and Save buttons would not be visible.
![enter image description here][2]
[1]: https://edxuploads.s3.amazonaws.com/13615680951343663.png
[2]: https://edxuploads.s3.amazonaws.com/13615683291343661.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:26:42Z
FirstChildVoteTAG: 0
IndexTAG: 2748
TitleTAG: Decimal places have to be clear for each question and may be the answer format
1/9 = 0.1111111111..., the "correct answer" was in set problem was 11.1. But some people could set 11.111111111... or whatever. And may be someone else could set 0.111111... as a fraction of one. So 11.1% = 0.111. Please clarify
UserIdTAG: 731428
UserNameTAG: mjgarciam
CreateTimeTAG: 2013-02-22T13:04:37Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: Yes, hopefully when a homework question doesn't specify significant digits, we won't be penalized for providing more/less than the magic mystery number the problem is set to grade for, like 11.1 in this case, which is of course less accurate than my 11.11111...
FirstChildUserIdTAG: 1277574
FirstChildUserNameTAG: KatherineAnderson
FirstChildCreateTimeTAG: 2013-02-22T13:11:09Z
FirstChildVoteTAG: 1
FirstChildTAG: Whoops, there's already a thread addressing this issue, though it's title is a bit general: "Marked incorrect for correct answers"
We should try to stick with one thread I guess?
FirstChildUserIdTAG: 1277574
FirstChildUserNameTAG: KatherineAnderson
FirstChildCreateTimeTAG: 2013-02-22T13:16:20Z
FirstChildVoteTAG: 0
SecondChildTAG: > We should try to stick with one thread I guess?
Only in my dreams.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T21:27:45Z
SecondChildVoteTAG: 0
FirstChildTAG: hey im a facing a prob... suppose answer is 19.976567 (this is jus an example) but "QUESTION SAYS ROUND YOUR ANSWER TO ONE DECIMAL PLACE" den wats d answer??
FirstChildUserIdTAG: 674042
FirstChildUserNameTAG: sumedbsk
FirstChildCreateTimeTAG: 2013-02-22T13:28:58Z
FirstChildVoteTAG: 0
SecondChildTAG: 20.0 would be the correct answer in that case.
SecondChildUserIdTAG: 1241616
SecondChildUserNameTAG: Larsfl
SecondChildCreateTimeTAG: 2013-02-22T13:33:35Z
SecondChildVoteTAG: 0
SecondChildTAG: There is one place like that )
SecondChildUserIdTAG: 1286060
SecondChildUserNameTAG: Calliditas
SecondChildCreateTimeTAG: 2013-02-22T21:42:16Z
SecondChildVoteTAG: 0
SecondChildTAG: The answer would be 20.0
SecondChildUserIdTAG: 731428
SecondChildUserNameTAG: mjgarciam
SecondChildCreateTimeTAG: 2013-02-23T16:08:28Z
SecondChildVoteTAG: 0
FirstChildTAG: This has been noted, and a request made to the Prof that future questions have requirements stated.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:28:16Z
FirstChildVoteTAG: 0
IndexTAG: 2749
TitleTAG: cant c the video and slides
is there any problem to any 1 while seeing the video lectures ?
UserIdTAG: 1285571
UserNameTAG: nelam
CreateTimeTAG: 2013-02-22T13:02:55Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2750
TitleTAG: Bank account balance is Quantitative Discrete Variable?
I don´t agree. A bank account is the net amount after factoring in all debits and credits that you have, and that is not a discrete varible. Please some suggestion are very wellcome
UserIdTAG: 731428
UserNameTAG: mjgarciam
CreateTimeTAG: 2013-02-22T12:59:38Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I think that it is, since You do not cut your money with a pair of scissors to pay your taxes exactlly. :-)
FirstChildUserIdTAG: 63180
FirstChildUserNameTAG: ianton
FirstChildCreateTimeTAG: 2013-02-22T16:06:58Z
FirstChildVoteTAG: 0
FirstChildTAG: I think is a discrete variable because your balance can take three possibles states: on debit, on credit and balance (or equal...forgive my english if i not clear)... take the example of colours: red and blue are discrete, independent of ammount (intensity) of red or blue are you have.
i hope this help
FirstChildUserIdTAG: 1114777
FirstChildUserNameTAG: fviertel
FirstChildCreateTimeTAG: 2013-02-22T16:24:44Z
FirstChildVoteTAG: 0
FirstChildTAG: Maybe to you, but not to the bank.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:28:38Z
FirstChildVoteTAG: 0
IndexTAG: 2751
TitleTAG: i have a question :)
Hello Prof,
i just got a question about the bar chart in the leture ?? do we really need the vertical componant ? do it make a difference in interperting the data if it is present ? Thank you :)
UserIdTAG: 902503
UserNameTAG: Elham1409
CreateTimeTAG: 2013-02-22T12:46:41Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: As I understand it from the lecture, you don't need the vertical axis to compare different bars in the chart, but you lose the *exact* number represented by each bar and are left with proportions only.
FirstChildUserIdTAG: 979052
FirstChildUserNameTAG: Hannah13
FirstChildCreateTimeTAG: 2013-02-22T14:01:00Z
FirstChildVoteTAG: 0
IndexTAG: 2752
TitleTAG: Exercise 2. P5. Heads Explode.
I still don't get it. I made a new post yesterday stating that the question was ambiguous. Then I thought I had understand it and deleted my post. But this morning it still looks ambiguous to me.
> *In a histogram of lengths measured in millimeters, the height of **the 20-40 bar** is 1 percent per millimeter. If I measure all the lengths in
> centimeters instead, then **the corresponding bar** would be labeled 2-4.
> The height of **this bar** would be:*
I do think the use of `*this bar*` is confusing. Which bar does it refer to?
Yes, one could infer from the answers. But many different inferences can be made. It would be clearer to refer to the bars as the former / the latter, or the original bar, the transformed bar.
Just wanted to bring attention on this, though maybe it's my morning unsolidified brain.
UserIdTAG: 250161
UserNameTAG: gaurwraith
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FirstChildTAG: The latter bar as the former bar is already defined.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T13:15:30Z
FirstChildVoteTAG: 1
SecondChildTAG: I am afraid you would need to explain more to make me understand, and the exercise is still open...
But, as a I see it, if the latter bar is just a proportional transformation of the former, everything is the same but with cm.
Sorry if I'm going too far here, I guess I'll have to wait for the explanation.
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-22T13:35:27Z
SecondChildVoteTAG: 0
SecondChildTAG: Please consider ratio and proportion.You must ultimately get the same answer/For eg in the lecture An answer of "12" may mean 12 inches but is also one foot and also 12X2.54 cms all represent the fundamental truth of the actual length described in different methods.So you should not get a different "truth" just by changing the measuring units so the percentage change ratio has to be the same but the proportions may be different for eg 1/2 =50/100 and 1/10=10/100.I hope you cna get the idea and work around that as the answer should still not be declared but I am giving you the concept.
You cannot get two different lengths or percentage change or whatever when you change your units of measurement.You may express it differently but the actual length cannot be different or similarly percentage change cannot be different.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T14:11:54Z
SecondChildVoteTAG: 0
SecondChildTAG: Gotcha. It's not that messy. I overthought it. Too much points for the question though, I lost them.
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-22T14:51:08Z
SecondChildVoteTAG: 0
SecondChildTAG: Should have expressed mm and cm as division of a meter, not as units, that would have helped.
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-22T14:52:56Z
SecondChildVoteTAG: 0
SecondChildTAG: Well the question was foxy enough to make you overthink it:)I don't look at the marks as what they are really looking for is concepts.(I am not a mathematician but am a Professor too and what we look for is concepts in relation to the question and scores are secondary.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T15:17:20Z
SecondChildVoteTAG: 0
FirstChildTAG: ![enter image description here][1]
[1]: http://ubuntuone.com/3zI9DNrBKY2QPMSqmUbdyI
And this was the picture in my mind
The height of this bar would be:
- 1 percent per centimeter
- 10 percent per centimeter
- 0.1 percent per centimeter
It all depends if we are talking about putting the red bar on the blue bar axis (here the ***this*** would refer to the first bar) or we are talking of the red bar transformed into blue bar (here the ***this*** would refer to the last bar mentioned).
Confusing.
FirstChildUserIdTAG: 250161
FirstChildUserNameTAG: gaurwraith
FirstChildCreateTimeTAG: 2013-02-22T13:23:49Z
FirstChildVoteTAG: 0
FirstChildTAG: I hadn't problems with the wording and I got the right answer, but now you emphasize certain sentences it seems a bit confusing.
BTW. Glad to see you again. Hope you are lucky with the NLP course!
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-22T15:55:13Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi Atopos!
Well, it did confuse me, but it's allright.
And thanks!
See you around
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-22T18:28:51Z
SecondChildVoteTAG: 0
FirstChildTAG: > In a histogram of lengths measured in millimeters, the height of the 20-40 bar is 1 percent per millimeter
So you have a bar in mm
> If I measure all the lengths in centimeters instead,
Now you measure in cm instead of mm.
>then the corresponding bar would be labeled 2-4.
So, in the cm bars the bar for 2-4cm corresponds to the 20-40mm bar (1cm = 10mm). Same length, just in a different scale so height the of bar will be in different units.
>The height of this bar would be
So what height is the 2-4cm bar?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:34:17Z
FirstChildVoteTAG: 1
FirstChildTAG: Hello fellow ex-6.00x, gaurwraith.... please remember not to discuss the graded exercises until after the deadline. Remember the honor code. :-)
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:13:55Z
FirstChildVoteTAG: 0
SecondChildTAG: I see your good advise here and there, you deserves a premium as a TA :), I agree, HC is something very important in online certified courses. However, I'm a little confused about the HC in this course.
Do you remember 6.00x discussions (long and vivid discussions about PSets)? I wonder whether providing some general hints to clarify doubts on a particular problem implies a violation of the HC. It seems more difficult here to decide when one is about to cross the line of revealing more than it's licit to talk about.
You know I was very picky on that issue during 6.00x, and I used to refrain (myself and others) from being too explicit. But, to be honest, the level of licit hints in this course so far seems to me somehow closer to no hints at all, due to the nature of the problems and available answers and attempts. What do you think?
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-23T00:24:57Z
SecondChildVoteTAG: 0
SecondChildTAG: > It seems more difficult here to decide when one is about to cross the
> line of revealing more than it's licit to talk about
.. or, from the other side, when one is about to ask for excessive help.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-23T00:30:44Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, I agree with you that is is vague.
In the programming courses we are encouraged to collaborate with others, providing hints, tips, pseudo code, but never to actually post your code.
In exams the discussion forum is locked though, to ensure no 'accidental' discussions take place.
Students asking the question are allowed to post a snippet of their code where they think they have a problem, and we were allowed to help troubleshoot provided that the student has exhausted his/her troubleshooting skills.
However, the graded exercises to date in this course in my opinion do not warrant the hints or tips as it would easily point out the answer. Questions such as 'is there really an answer' or 'is there an issue with the question/answer' in my opinion is OK as long as the respond from fellow students are limited to simple 'yes' or 'no' and not something like 'option a and b seems wrong but c might be ok'.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T00:48:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Basically this is my own conclusion.
SecondChildUserIdTAG: 461686
SecondChildUserNameTAG: atopos
SecondChildCreateTimeTAG: 2013-02-23T00:53:44Z
SecondChildVoteTAG: 0
SecondChildTAG: What we really need is staff/TA to intervene and communicate, I guess.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T01:03:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi Jim, nice to see you here.
I had exhausted my troubleshooting skills indeed. Well, I clicked the wrong answer after quite some time trying to figure it out. Then I kept wondering. Oh my, this question got me mad. I started drawing and thinking too much, and a part of me still believes that my answer makes sense with a certain interpretation of the premises.
But you're right, if everybody starts talking too much it would be so easy for the lazy one to just make a search and obtain the answers
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-23T02:25:58Z
SecondChildVoteTAG: 0
SecondChildTAG: gaurwraith, you just need to take some guttagonol and all will be revealed...lol
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T04:55:49Z
SecondChildVoteTAG: 0
IndexTAG: 2753
TitleTAG: Section 1 Practice exercise
In practice exercise 1 the answers are rounded off the 1 decimal place!! Which is not indicated anywhere in the instruction. As a result the answers correct upto two decimal places have been marked wrong.
Is there any explanation to retain only one decimal place?
UserIdTAG: 974461
UserNameTAG: ncscaks
CreateTimeTAG: 2013-02-22T12:46:02Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Decimal places have to be indicated, and may be the format of the answer. eg 10% = 0.1.
FirstChildUserIdTAG: 731428
FirstChildUserNameTAG: mjgarciam
FirstChildCreateTimeTAG: 2013-02-22T12:49:38Z
FirstChildVoteTAG: 1
FirstChildTAG: I also had the same problem. I first used 2 decimal places and was graded as wrong. I even used a fractional form to be totally accurate (e.g. 11.1111 = 100/9) and it was also graded as wrong. Thanks to ncscaks' comment I just used 1 decimal digit and then everything was OK. Hopefully, there will be a coherent and consistent way to answer for future exercises.
Thanks.
FirstChildUserIdTAG: 534535
FirstChildUserNameTAG: hectorgz
FirstChildCreateTimeTAG: 2013-02-22T13:00:59Z
FirstChildVoteTAG: 0
SecondChildTAG: I put down 11.1% and was marked wrong. What is wrong with that? I was taught to put down the sign "%" when percentage was asked.
Another point about Lec 1.2 --Fig 3-1 **ELEMENTS OF A HISTOGRAM**
The text says that the Area of bin and not Height that represent the relative frequencey of data in bin.
Now a chart, picture, graph, etc. is supposed to make the data clear to an observer, be he a novice or an expert. In that histogram the BIN WIDTH are NOT THE SAME: the area represented could be narrow and tall or wide and short, thus making comparison difficult. I wonder why can we not USE EQUAL OR CONSISTENT WIDTH for the bins, so visually the HEIGHT will represent the relative frequency.
SecondChildUserIdTAG: 1053143
SecondChildUserNameTAG: tasmaniantiger
SecondChildCreateTimeTAG: 2013-02-22T15:56:08Z
SecondChildVoteTAG: 0
FirstChildTAG: I have the same problem and another one. Here in South America we use comma as decimal mark, so mi response was not accepted as correct.
FirstChildUserIdTAG: 1055354
FirstChildUserNameTAG: jardouin
FirstChildCreateTimeTAG: 2013-02-22T15:19:57Z
FirstChildVoteTAG: 0
SecondChildTAG: You need to use the accepted American way of writing things. So 10.6 not 10,6
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T21:36:24Z
SecondChildVoteTAG: 0
IndexTAG: 2754
TitleTAG: Number of submissions rule
It seems that when we are allowed to submit twice, we actually have to press twice to validate the submission, even if the answer is correct first time. Am I correct?
At the same time, I got worried wondering that actually using a second submission affect the marking negatively.
I would be grateful if this could be clarified.
Many thanks and kind regards.
UserIdTAG: 1178410
UserNameTAG: Pti_Lu
CreateTimeTAG: 2013-02-22T12:43:50Z
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NumberOfReplyTAG: 2
FirstChildTAG: I think, pressing once is OK. Since, if you look at "Progress" tab after pressing, you see the result already. No need to press a second time. The button should be named "Submit" and not "Check", Check is something more than Save, but just check and not yet Submit.
FirstChildUserIdTAG: 1174304
FirstChildUserNameTAG: ThomasHGMann
FirstChildCreateTimeTAG: 2013-02-22T12:55:49Z
FirstChildVoteTAG: 1
SecondChildTAG: I agree, the user interface seems to be common across a number of edx courses and is confusing at first glance. I've never felt the need to use the Save button which, I imagine, you might use if you had an incomplete answer which you needed to come back to later.
The 'Check' button, by contrast, should really be 'Submit' for marked assignments as this is its function. Check may be appropriate for ungraded practice exercises but could certainly be misleading for some, especially when so many students might reasonably be expected to have English as a second or other language and where only a single submission is permitted.
SecondChildUserIdTAG: 952145
SecondChildUserNameTAG: PaulJM
SecondChildCreateTimeTAG: 2013-02-22T20:03:53Z
SecondChildVoteTAG: 0
FirstChildTAG: > we actually have to press twice to validate the submission, even if the answer is correct first time. Am I correct?
No. Once you have the green tick you don't have to do anything. If you get a red cross and you have another submission, try again.
If you do click Check again, as long as you haven't altered your answer you will still have a green check and you will have used all your submissions.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:38:38Z
FirstChildVoteTAG: 0
IndexTAG: 2755
TitleTAG: I think there is no correct answer in one off the problem question, who can check?
Hello, can the Exercise 2, problem 3, question b be checked for validity. Either I am missing something or their is no valid answer.
Many thanks and kind regards,
UserIdTAG: 1178410
UserNameTAG: Pti_Lu
CreateTimeTAG: 2013-02-22T12:39:35Z
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NumberOfReplyTAG: 3
FirstChildTAG: I agree - and this was mentioned somewhere in an earlier post too. Guess we'll just have to wait for the full explanations after the homework submission dates to see if we're right! In a funny sort of way, not being totally confident of the automatic marker is making me think harder about what i'm submitting :)
FirstChildUserIdTAG: 1193788
FirstChildUserNameTAG: MarianW
FirstChildCreateTimeTAG: 2013-02-22T12:45:02Z
FirstChildVoteTAG: 2
FirstChildTAG: Same, my histogram are different from the choices. I have tried it several times but it doesn't look like any of the choices.
FirstChildUserIdTAG: 1211582
FirstChildUserNameTAG: flake
FirstChildCreateTimeTAG: 2013-02-22T13:16:10Z
FirstChildVoteTAG: 0
SecondChildTAG: Same
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-02-22T13:31:29Z
SecondChildVoteTAG: 0
FirstChildTAG: There is one graph that is *more correct* than the others.
It does clump two different brackets together, with results that did put me off a little, and I'm not entirely sure that it's completely correct...but, it's close enough, and the other two are **clearly** wrong, so the choice was fairly obvious :)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T14:12:39Z
FirstChildVoteTAG: 1
IndexTAG: 2756
TitleTAG: Set 1 graphs
I got all questions right bar two of the graph ones, which look like I should have them right. Anyone else with a similar issue?
UserIdTAG: 883512
UserNameTAG: Ragnarson
CreateTimeTAG: 2013-02-22T12:29:35Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Nope.
FirstChildUserIdTAG: 979052
FirstChildUserNameTAG: Hannah13
FirstChildCreateTimeTAG: 2013-02-22T14:01:59Z
FirstChildVoteTAG: 0
FirstChildTAG: The question is correct.If you did not get the answer as marked correct then you have made a mistake.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T14:17:42Z
FirstChildVoteTAG: 0
IndexTAG: 2757
TitleTAG: How to add my profile?
I don't see any link to my profile ...
UserIdTAG: 1174304
UserNameTAG: ThomasHGMann
CreateTimeTAG: 2013-02-22T12:03:27Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You need to create it in the wiki
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T14:12:50Z
FirstChildVoteTAG: 0
SecondChildTAG: You mean, add there my name in "Students directory"?
And where do I find my version of https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/users/1006030 when I don't know my users/number, except by creating a dumb discussion entry like this in order to have link to klick on? Isn't that (a link to my own discussions) part of a profile one expects in all kinds of social web sites? ?-)
SecondChildUserIdTAG: 1174304
SecondChildUserNameTAG: ThomasHGMann
SecondChildCreateTimeTAG: 2013-02-22T14:32:43Z
SecondChildVoteTAG: 0
SecondChildTAG: if you right click on your name in this thread and copy the url or open in a new tab then you will find your user id.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-23T01:05:08Z
SecondChildVoteTAG: 0
SecondChildTAG: OK, thanks. I thought there would be a direct way ...
SecondChildUserIdTAG: 1174304
SecondChildUserNameTAG: ThomasHGMann
SecondChildCreateTimeTAG: 2013-02-23T15:47:43Z
SecondChildVoteTAG: 0
IndexTAG: 2758
TitleTAG: Suggestion :)
Dear Professor A.,
I think that in the case of the stem and leaf plot (exactly in the median and the percentile case) it may be be better (I am of course not shor) to round the values to the nearest integer). Then, for data 0, 2, 4, 7, 7 the 40-percentile is the value for Round(0,4*6, 0) = 2. So, the value may be 2 instead of 4, best regards.
UserIdTAG: 426127
UserNameTAG: hurgadion
CreateTimeTAG: 2013-02-22T11:56:01Z
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FirstChildTAG: It is like jumping from one cliff to another- if you miss even by a bit you are in the pit/valley.Similarly once you cross a number - no going back but only front.So 2.2 implies you have crossed 2.and youhave to goahead.This is because percentiles deal with residuals ie all these are ***less than*** x percent when you say that a person or thing is x percentile
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T14:16:00Z
FirstChildVoteTAG: 1
SecondChildTAG: I understand this, but in my opinion rounding the values may be more effective... :)
SecondChildUserIdTAG: 426127
SecondChildUserNameTAG: hurgadion
SecondChildCreateTimeTAG: 2013-02-22T16:38:36Z
SecondChildVoteTAG: 0
IndexTAG: 2759
TitleTAG: Marked incorrect for correct answers
In exercise 1.3 when i wrote the answer for proportion of seniors as 11.11 it was marked wrong while the answer was 11.1 ( i wrote answer up to 2 decimal places while it was the correct answer & got it wrong). i encountered similar problem for the next.... proportion of juniors..
UserIdTAG: 395303
UserNameTAG: Manish78
CreateTimeTAG: 2013-02-22T11:38:30Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: I has the same problem...I cannot understand why...
FirstChildUserIdTAG: 1266083
FirstChildUserNameTAG: Asimina
FirstChildCreateTimeTAG: 2013-02-22T11:41:59Z
FirstChildVoteTAG: 1
SecondChildTAG: ditto.
SecondChildUserIdTAG: 834676
SecondChildUserNameTAG: vmvedad
SecondChildCreateTimeTAG: 2013-02-22T12:06:35Z
SecondChildVoteTAG: 0
FirstChildTAG: yes, it should be stated how many digits are to be entered. Fortunately, in the "real" exercises, this info is given.
It would be better, if the grading software could do the rounding in order not to punish correct answers ...
FirstChildUserIdTAG: 1174304
FirstChildUserNameTAG: ThomasHGMann
FirstChildCreateTimeTAG: 2013-02-22T11:43:53Z
FirstChildVoteTAG: 1
SecondChildTAG: /agreed.
This isn't even a physics course where significant figures actually sort of matter.
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T12:02:34Z
SecondChildVoteTAG: 0
FirstChildTAG: so what was the correct format then?
FirstChildUserIdTAG: 883512
FirstChildUserNameTAG: Ragnarson
FirstChildCreateTimeTAG: 2013-02-22T12:04:19Z
FirstChildVoteTAG: 0
SecondChildTAG: one decimal place
I was marked wrong as well...it should have been stated
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-22T12:22:58Z
SecondChildVoteTAG: 0
SecondChildTAG: same
SecondChildUserIdTAG: 1216723
SecondChildUserNameTAG: Darkennoia
SecondChildCreateTimeTAG: 2013-02-22T12:24:54Z
SecondChildVoteTAG: 0
FirstChildTAG: There obviously seems to be some glitch somewhere and I seem to be getting the correct answers marked wrong - *Please rectify!!*:
**Ex Set 1:Prob 2** - 1st and 3rd graphs are same and both correct - nor order for categorical variables!
**Ex Set 1:Prob 3** - 1st and 3rd graphs are identical and both correct!
**Practice for Ex Set 1 Lect 2,2/2.3** should be 14/30 = .46 as the interval should be 30 (-10 to 20)
**Ex Set 2 Pr 1** Surely 5-15 has more people *(13.3% of the population)* compared to 15-20 *(7.1% of the population)*!! ??
FirstChildUserIdTAG: 1129036
FirstChildUserNameTAG: Dileepk
FirstChildCreateTimeTAG: 2013-02-22T12:37:58Z
FirstChildVoteTAG: 1
SecondChildTAG: Dileepk,
Ex set1: is says select ALL that are correct; you can choose more than one.
Ex set 1 prob 3: I guess you want to say that 2nd and 3rd graphs are identical, but they are not: look at the vertical axis!! (in one it says number of plants, in the other probability)
I agree with practice for ex set1 , i also this it should be 0.46!
SecondChildUserIdTAG: 1260396
SecondChildUserNameTAG: elisaluzon
SecondChildCreateTimeTAG: 2013-02-22T12:55:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Also, for Set2 Pr1...well, yes. 5-15 is correct and is marked correct. What's the problem?
Unless you mean for question b. Then, we're talking about *density*, and things might change then. 15-20 only covers 5 years, while 5-15 covers 10 ;)
SecondChildUserIdTAG: 604636
SecondChildUserNameTAG: Klionheart
SecondChildCreateTimeTAG: 2013-02-22T14:06:06Z
SecondChildVoteTAG: 0
SecondChildTAG: I marked 5-15 and i got a "wrong" !! ... Hope this has got fixed by now in the grader correction ...Thanx, anyway - we were not supposed to discuss the answer that specifically due to the HONOR CODE!!
SecondChildUserIdTAG: 1129036
SecondChildUserNameTAG: Dileepk
SecondChildCreateTimeTAG: 2013-02-22T16:17:21Z
SecondChildVoteTAG: 0
FirstChildTAG: > There obviously seems to be some glitch somewhere and I seem to be getting the correct answers marked wrong
You also have issues with the honour code.
>Ex Set 2 Pr 1 Surely 5-15 has more people
A search of the forum will show you that this has been noted, dozens upon dozens of times.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
>Ex Set 1:Prob 2
Read honour code. And the question. ALL that are correct.
>Ex Set 1:Prob 3
Read honour code. No, they are not.
>Practice for Ex Set 1 Lect 2,2/2.3
Again, noted many times.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:48:28Z
FirstChildVoteTAG: 0
IndexTAG: 2760
TitleTAG: Problem set 2
Hi all,
Working on problem set number and for some reason all my answers are wrong although I believe I understood the course. Anybody else having same problem?
UserIdTAG: 1267141
UserNameTAG: Khadra
CreateTimeTAG: 2013-02-22T11:23:08Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Hi,
I think you talk about every problem on set 2. I did it, and I have only 3 wrong answers (1.b, 1.c and 2.b) and the only one I cannot understand why it has a red cross is 2.b.
Lucky in your review looking for the mistake.
FirstChildUserIdTAG: 1226025
FirstChildUserNameTAG: Alaisa
FirstChildCreateTimeTAG: 2013-02-22T11:48:55Z
FirstChildVoteTAG: 0
SecondChildTAG: Did you select "all that are correct" in 2b?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T21:50:01Z
SecondChildVoteTAG: 0
IndexTAG: 2761
TitleTAG: Inconsistencies when rounding up or down
There is no indication or instruction as to how many significant figures or decimal places are required for each answer in the example questions, either in the courseware section or the web book. This can result in the answer being marked as incorrect when in fact it is correct. Can anyone provide any guidance? Maybe this is why the pass mark threshold is so low.
UserIdTAG: 900452
UserNameTAG: PBOD
CreateTimeTAG: 2013-02-22T10:59:51Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: This has been raised with the Prof, and hopefully future questions will have the dp places defined.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
For the current set of exercises **where there is no guidance** on dps: 1 dp seems to be okay for all except Set 2 Problem 3a, where I used 2dp.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T11:08:18Z
FirstChildVoteTAG: 0
SecondChildTAG: Thankyou.
SecondChildUserIdTAG: 900452
SecondChildUserNameTAG: PBOD
SecondChildCreateTimeTAG: 2013-02-22T18:43:45Z
SecondChildVoteTAG: 0
IndexTAG: 2762
TitleTAG: Dumb Question : Help from the Class
I feel really dumb in asking this question,but I do need the help. In chapter 3, exercise 3-2, 3-3, and 3-4, what is the formula for figuring out the fractions? I am at a loss. thanks
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UserNameTAG: lawtec
CreateTimeTAG: 2013-02-22T10:42:27Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: About problem 2, I wrong 2.a and 2.b (I don't know why), then, I cannot help you on this.
Problem 3 and 4: the horizonal line inside the box (on diagram) is the median, the upper and lower side of the box are the upper and lower percentil. The beginning and ending of vertical line is the max. and min. value of the data.
I hope this help you.
FirstChildUserIdTAG: 1226025
FirstChildUserNameTAG: Alaisa
FirstChildCreateTimeTAG: 2013-02-22T12:00:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Are you referring to the process of converting a fraction to a percent or to a decimal? If so, you divide the top number (numerator) by the bottom number (denominator) using long division.
Watch this KhanAcademy video as a review: [Converting Fractions to Decimals][1]
[1]: http://www.youtube.com/watch?v=Gn2pdkvdbGQ
FirstChildUserIdTAG: 144162
FirstChildUserNameTAG: Rena2012
FirstChildCreateTimeTAG: 2013-02-22T12:08:30Z
FirstChildVoteTAG: 0
IndexTAG: 2763
TitleTAG: Relative frequency
I would like to know if the following definitions are correct
Relative frequency = frequency/total observations
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-22T10:29:40Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I think so. Always I have to use the relative frequency, I calculate it according to this definition and it works.
FirstChildUserIdTAG: 1226025
FirstChildUserNameTAG: Alaisa
FirstChildCreateTimeTAG: 2013-02-22T11:53:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, correct. "Frequency" is the number of times something occurs. "Relative frequency" is the proportion of times it occurs. Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-23T05:36:11Z
FirstChildVoteTAG: 0
IndexTAG: 2764
TitleTAG: question Exercise Set 1 Problem 3
for the question Exercise Set 1 Problem 3 : Im confused about the answer. whether 20 green/green will be added to existing magenta/green and red/green to get 500 or some other way there will be a fifth option. help me please...
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-22T10:24:31Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: You are adding a totally new group green/green (20 ) to the original 480 which makes a larger set of 500 which contains the original 480 + the newly added 20 to make a total of 500. Please note that Magenta /Green is one plant having magenta and green flowers , green green means only green flowers and red green means a plant having red+green flowers and so on and so forth so you are not adding green to a plant but adding plants that flower a green/green combo .
Hope this helps.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T10:28:32Z
FirstChildVoteTAG: 3
SecondChildTAG: An excellent clarification.
SecondChildUserIdTAG: 191877
SecondChildUserNameTAG: cuddiheer1
SecondChildCreateTimeTAG: 2013-02-22T11:40:49Z
SecondChildVoteTAG: 0
FirstChildTAG: I had the same issue what they should have written 'a further 20 green/green plants'. Their use of 'another' in that context is confusing (it confused me too) and not grammatically apt.
FirstChildUserIdTAG: 1004185
FirstChildUserNameTAG: ale1808
FirstChildCreateTimeTAG: 2013-02-22T10:29:23Z
FirstChildVoteTAG: 2
SecondChildTAG: Agreed, the wording there was not entirely clear.
SecondChildUserIdTAG: 1281619
SecondChildUserNameTAG: sfc17
SecondChildCreateTimeTAG: 2013-02-22T16:48:02Z
SecondChildVoteTAG: 0
FirstChildTAG: thanx....helped to solve
FirstChildUserIdTAG: 720707
FirstChildUserNameTAG: zuberm
FirstChildCreateTimeTAG: 2013-02-22T10:44:30Z
FirstChildVoteTAG: 0
FirstChildTAG: Please uphold the HONOR CODE and refrain from discussing graded exercises until after the deadline.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:15:57Z
FirstChildVoteTAG: 0
IndexTAG: 2765
TitleTAG: Exercise 3.9:Text
The calculated values of percentiles for the gravity data do not match the given answers. Please check. For Example: 71st percentile = -40 + (71-52)*30/25 = -17.2 Accepted answer is -16. If I enter -17.2 for the upper limit, it says 71% of yellow color-so I am right on the money. The slider is very difficult to work with-I would rather calculate and check. Please point out my error.
UserIdTAG: 237509
UserNameTAG: Mundi
CreateTimeTAG: 2013-02-22T10:21:47Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Exercise 3.9 asks for the percentiles, not an approximation of the percentiles from the histogram. You cannot read actual percentiles from a histogram, because the histogram does not tell you where in each bin the data are, only the total for the bin. To find the percentiles, you have to refer to the original list of data.
Cheers,
Philip
FirstChildUserIdTAG: 990671
FirstChildUserNameTAG: pstark
FirstChildCreateTimeTAG: 2013-02-22T15:34:00Z
FirstChildVoteTAG: 0
SecondChildTAG: How can I submit my exercise answers.
SecondChildUserIdTAG: 972972
SecondChildUserNameTAG: 0123
SecondChildCreateTimeTAG: 2013-02-27T21:58:33Z
SecondChildVoteTAG: 0
IndexTAG: 2766
TitleTAG: Exercise set 1 Problem 3
Sorry if I am missing something obvious. The question asks us to consider the case when 'another 20 green/green plants' are added to the set. But the original set has no green/green plants in it. Is this a typo? What is meant?
Sorry if others have already asked, could not find it in the discussion
UserIdTAG: 1004185
UserNameTAG: ale1808
CreateTimeTAG: 2013-02-22T10:19:18Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: It is correct. Read the problem carefully. It increases the total count to 500 plants. Add a new row to your data table.
FirstChildUserIdTAG: 237509
FirstChildUserNameTAG: Mundi
FirstChildCreateTimeTAG: 2013-02-22T10:23:51Z
FirstChildVoteTAG: 0
SecondChildTAG: I figured out what they meant, but I am afraid their formulation is not grammatically apt given the meaning of the word 'another'
SecondChildUserIdTAG: 1004185
SecondChildUserNameTAG: ale1808
SecondChildCreateTimeTAG: 2013-02-22T10:30:41Z
SecondChildVoteTAG: 0
FirstChildTAG: That was a tricky one! If you do not pay attention to that detail then you will fail the next question as I did! Next time I will be sure to read carefully the information given...
FirstChildUserIdTAG: 534535
FirstChildUserNameTAG: hectorgz
FirstChildCreateTimeTAG: 2013-02-22T13:24:20Z
FirstChildVoteTAG: 0
FirstChildTAG: Please uphold the HONOR CODE and refrain from discussing graded exercises until after the deadline.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:16:44Z
FirstChildVoteTAG: 0
IndexTAG: 2767
TitleTAG: Exercise 2 P7 : Has anyone got the correct answer? Just answer Yes or No
Please do not divulge the answer. I just want to confirm that I really didn't get it right.
Thanks.
UserIdTAG: 329709
UserNameTAG: January
CreateTimeTAG: 2013-02-22T09:59:33Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: I got the correct answer~
FirstChildUserIdTAG: 1262183
FirstChildUserNameTAG: hsinling
FirstChildCreateTimeTAG: 2013-02-22T10:06:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Yeah, it has a correct answer!!
SecondChildUserIdTAG: 897908
SecondChildUserNameTAG: joetom
SecondChildCreateTimeTAG: 2013-02-22T10:25:04Z
SecondChildVoteTAG: 0
FirstChildTAG: I got the correct answer.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T10:09:03Z
FirstChildVoteTAG: 0
FirstChildTAG: Ok thanks. Will have a look again and see why I got it wrong.
FirstChildUserIdTAG: 329709
FirstChildUserNameTAG: January
FirstChildCreateTimeTAG: 2013-02-22T10:16:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Did you get there?
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T21:51:14Z
SecondChildVoteTAG: 0
FirstChildTAG: is there associated histogram?
FirstChildUserIdTAG: 1009064
FirstChildUserNameTAG: saroia
FirstChildCreateTimeTAG: 2013-02-22T11:21:51Z
FirstChildVoteTAG: 0
FirstChildTAG: I had no clue how to do E2P6 or 7...
FirstChildUserIdTAG: 47618
FirstChildUserNameTAG: almoore
FirstChildCreateTimeTAG: 2013-02-22T18:04:43Z
FirstChildVoteTAG: 0
SecondChildTAG: I got it incorrect
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-22T23:09:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you for upholding the honor code, January. Hope you found the correct answer.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T23:18:14Z
FirstChildVoteTAG: 1
IndexTAG: 2768
TitleTAG: Practice for exercise set 2
Hi,
I think either there is an error in the second part of the set or I did not understand anything.
Height of -10 to 20 bar = ____________ % per unit
I found the result 0.46 but the answer is 1.4 which I don't think is correct because it should be `20 - (-10)` = 30 not `20 - 10 = 10`
And to confirm this the second one:
Height of 20 to 50 bar = ____________ % per unit
they use `50 - 20 = 30`
??????????????
UserIdTAG: 947576
UserNameTAG: j__med
CreateTimeTAG: 2013-02-22T09:58:13Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I agree with you, I don't understant why the first one is 1.4.
FirstChildUserIdTAG: 1262183
FirstChildUserNameTAG: hsinling
FirstChildCreateTimeTAG: 2013-02-22T10:10:23Z
FirstChildVoteTAG: 0
SecondChildTAG: 20 - (-10) is 30 and 14/30 = 0.47. It's a mistake in a grader.
SecondChildUserIdTAG: 610852
SecondChildUserNameTAG: maMykola
SecondChildCreateTimeTAG: 2013-02-22T10:13:51Z
SecondChildVoteTAG: 0
SecondChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
SecondChildUserIdTAG: 610852
SecondChildUserNameTAG: maMykola
SecondChildCreateTimeTAG: 2013-02-22T10:18:52Z
SecondChildVoteTAG: 0
SecondChildTAG: It is clearly a grader error because is you do the exact same thing in the second part, you do get the right answer. And if you visualize the numberline with -10 to 20, you'll see it can not be 10. it's 30.
SecondChildUserIdTAG: 804886
SecondChildUserNameTAG: marlasinger1470
SecondChildCreateTimeTAG: 2013-02-22T10:48:01Z
SecondChildVoteTAG: 0
SecondChildTAG: It must be an error, the width is clearly 30.
SecondChildUserIdTAG: 1227917
SecondChildUserNameTAG: marianafff
SecondChildCreateTimeTAG: 2013-02-22T11:00:28Z
SecondChildVoteTAG: 0
SecondChildTAG: I can get the real answer but how did you get 1.4 and then what is the answer to B
SecondChildUserIdTAG: 883512
SecondChildUserNameTAG: Ragnarson
SecondChildCreateTimeTAG: 2013-02-22T13:08:15Z
SecondChildVoteTAG: 0
SecondChildTAG: oh nevermind
SecondChildUserIdTAG: 883512
SecondChildUserNameTAG: Ragnarson
SecondChildCreateTimeTAG: 2013-02-22T13:11:07Z
SecondChildVoteTAG: 0
FirstChildTAG: I got the same answer and was surprised that my answer of 0.4666...7 wrong.
I supposed it is an error with the different signs, one being + and the other being -
FirstChildUserIdTAG: 1211582
FirstChildUserNameTAG: flake
FirstChildCreateTimeTAG: 2013-02-22T11:33:25Z
FirstChildVoteTAG: 0
FirstChildTAG: I hope they don't make mistakes like these in the final exams
FirstChildUserIdTAG: 674722
FirstChildUserNameTAG: imranlp_687
FirstChildCreateTimeTAG: 2013-02-22T12:22:21Z
FirstChildVoteTAG: 1
FirstChildTAG: this is a known error and is posted in courseware errata.
FirstChildUserIdTAG: 1262111
FirstChildUserNameTAG: konx
FirstChildCreateTimeTAG: 2013-02-23T17:54:35Z
FirstChildVoteTAG: 0
IndexTAG: 2769
TitleTAG: Hi everyone.
I'm Saeed from Iran.
UserIdTAG: 1042271
UserNameTAG: Saeed19
CreateTimeTAG: 2013-02-22T09:56:31Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Welcome Saeed. I am Derick Sullivan from Cameroon
FirstChildUserIdTAG: 585153
FirstChildUserNameTAG: princelobga
FirstChildCreateTimeTAG: 2013-02-22T10:41:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi Saeed19.
SecondChildUserIdTAG: 313672
SecondChildUserNameTAG: blinxnot
SecondChildCreateTimeTAG: 2013-02-22T10:43:37Z
SecondChildVoteTAG: 0
FirstChildTAG: Hello Saeed! Welcome to the class!
FirstChildUserIdTAG: 1024913
FirstChildUserNameTAG: akaren65
FirstChildCreateTimeTAG: 2013-02-23T02:25:55Z
FirstChildVoteTAG: 0
IndexTAG: 2770
TitleTAG: Do we have to do the "Practice for Exercise Set 1" section? Will it be reflected in the scores somewhat or is it there only for training?
I've done this preparatory part but it's not reflected in the progress section. I supose it's not important but I would like to know from anyone who knows that for sure. Thanks in advance...
UserIdTAG: 1176613
UserNameTAG: Asrael
CreateTimeTAG: 2013-02-22T09:51:57Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Only for training
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-22T10:01:03Z
FirstChildVoteTAG: 0
FirstChildTAG: The clue is in the title "Practice"! To confirm this, look at the "Progress" tab at the top of the page - the scores for the practice exercises are not included in the overall progress mark which includes only the graded exercises and exams.
By all means skip the practice if you are confident of the material but, so far, the practice examples have been very close to the graded exercises in content and style - and can be re-submitted as many times as you need to get to the right answer (and show the required answers on request).
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-02-22T19:46:54Z
FirstChildVoteTAG: 0
IndexTAG: 2771
TitleTAG: Applets
Hello everyone. Even though I have tried Chrome and Firefox I cannot see the applets (Figure 3-2 for example). Any suggestions???
UserIdTAG: 1266083
UserNameTAG: Asimina
CreateTimeTAG: 2013-02-22T09:50:14Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Make sure you have Java enabled?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T10:43:56Z
FirstChildVoteTAG: 0
SecondChildTAG: There's no Java in chapter 3. The histograms use pure Javascript. It should work in Chrome.
Cheers,
Philip
SecondChildUserIdTAG: 990671
SecondChildUserNameTAG: pstark
SecondChildCreateTimeTAG: 2013-02-22T15:31:09Z
SecondChildVoteTAG: 0
IndexTAG: 2772
TitleTAG: new dates for submission?
hi. ...great work on the course progress.in as much as the submission dates have been moved( which is ok), i have submitted mine and have exhausted my submission option. can i suggest that the submission option be increased from just one or two in some cases..
UserIdTAG: 1033614
UserNameTAG: neo8701
CreateTimeTAG: 2013-02-22T09:46:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: The Prof has addressed this. I believe future assignments will have more submissions (can't find the actual post), but this will depend on the complexity of the question. MCQ will have fewer options than numerical ones. And tricky numerical more options than not so tricky.
Edit. Comment re submissions from Prof. A
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5125aceb9914d22b0000019d
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T10:43:35Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks for the help an reply...
SecondChildUserIdTAG: 1033614
SecondChildUserNameTAG: neo8701
SecondChildCreateTimeTAG: 2013-02-22T19:11:15Z
SecondChildVoteTAG: 0
FirstChildTAG: The limited number of "chances" is, I think, intended so we don't just start guessing at the answer until we hit the right one.
We need to understand the problem, figure it out, and *only then* answer.
Also consider this: in a classroom test or homework, such as these problems are supposed to represent, you do the work, turn it in, and wait for the result. If the professor spots a mistake, s/he doesn't call you back, say "Hey, you made a mistake here pal. Try again and then turn the paper in again". S/he just marks the answer wrong. So, you always get *one* chance.
The system here is actually a lot more permissive ;)
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T10:49:49Z
FirstChildVoteTAG: 0
FirstChildTAG: What's the point of increasing the number submissions?
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-22T14:36:06Z
FirstChildVoteTAG: 1
IndexTAG: 2773
TitleTAG: Lecture Slides Undownloadable
Hi guys, I have been able to download the lecture videos but NOT able to download the lecture slides (which are indicated to be in PDF). Is this my problem alone or we are many facing this problem, and how can this be resolved?
When I click the lecture slides link, it returns the following message:
"This Connection is Untrusted
You have asked Firefox to connect
securely to edx.org, but we can't confirm that your connection is secure.
Normally, when you try to connect securely,
sites will present trusted identification to prove that you are
going to the right place. However, this site's identity can't be verified.
What Should I Do?
If you usually connect to
this site without problems, this error could mean that someone is
trying to impersonate the site, and you shouldn't continue.
edx.org uses an invalid security certificate.
The certificate is only valid for *.edx.org
(Error code: ssl_error_bad_cert_domain)"
UserIdTAG: 1245010
UserNameTAG: JBenkie
CreateTimeTAG: 2013-02-22T09:38:29Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I just viewed the slides. I told the browser to ignore the warning, and the pdf downloaded.
Might need to email the tech people to tell them there is an issue with the certificate?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T10:39:26Z
FirstChildVoteTAG: 0
FirstChildTAG: I also have the same problem. This is the message:
> This is probably not the site you are looking for!
You attempted to reach edx.org, but instead you actually reached a server identifying itself as *.edx.org. This may be caused by a misconfiguration on the server or by something more serious. An attacker on your network could be trying to get you to visit a fake (and potentially harmful) version of edx.org.
You should not proceed, especially if you have never seen this warning before for this site.
FirstChildUserIdTAG: 461074
FirstChildUserNameTAG: sherwinverdun
FirstChildCreateTimeTAG: 2013-02-22T12:08:37Z
FirstChildVoteTAG: 1
SecondChildTAG: Click OK anyway and it goes to the site.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T14:56:59Z
SecondChildVoteTAG: 0
IndexTAG: 2774
TitleTAG: Weightage of Assignments ?
Hello,
Could anyone tell me about the overall weightage the weekly assignments marked as 'ES' would carry in the final grade ?
Regards
UserIdTAG: 97340
UserNameTAG: AnkitRana
CreateTimeTAG: 2013-02-22T09:26:54Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Policies_and_requirements.pdf
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T10:35:47Z
FirstChildVoteTAG: 0
FirstChildTAG: It's worth noting that the graded exercise sets (ES) account for 50% of the overall score meaning that it would be perfectly possible to achieve the required pass mark of 35% without even attempting the midterm or final exams. This makes the exercises the most important assessment element and give a great encouragement to keep up to schedule and work through in sequence, which I assume to be a deliberate design feature.
FirstChildUserIdTAG: 952145
FirstChildUserNameTAG: PaulJM
FirstChildCreateTimeTAG: 2013-02-22T19:54:15Z
FirstChildVoteTAG: 0
IndexTAG: 2775
TitleTAG: Course Overview/Syllabus
Just entered the course today, and want to make sure I'm heading down the right path....
1. Is there a course syllabus?
2. Is the textbook Dr. Stark's 'SticiGui?' If so, are the embedded videos in SticiGui part of the course and required or recommended?
Seems like there are two courses to pull information from, one basic (Dr. Adhikari) and one more advanced (Dr. Stark)....any clarity here is greatly appreciated!
UserIdTAG: 1268336
UserNameTAG: djb2573
CreateTimeTAG: 2013-02-22T09:21:13Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: > 1. Is there a course syllabus?
See the Course info page for relevant handouts.
> 2. Is the textbook Dr. Stark's 'SticiGui?'
Yes
> If so, are the embedded videos in SticiGui part of the course and required or recommended?
I don't believe so. Watch for your own benefit if you want, but this course has its own videos on the Courseware page. References are made to the text.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T10:35:17Z
FirstChildVoteTAG: 0
IndexTAG: 2776
TitleTAG: StudyRoom for everyone!
Don't forget that there is a study room for this class at the link below! And if you joined my study group over there it would be awesome too!
http://www.getstudyroom.com/course/42002
See you there!
UserIdTAG: 455902
UserNameTAG: emersonmalca
CreateTimeTAG: 2013-02-22T09:04:50Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: thanks this is great. how did you create this cause this would be great for my other classes. also is there a way to get notifications when people do things. has anyone found an easy way to print the posts in this discussion area?
FirstChildUserIdTAG: 411228
FirstChildUserNameTAG: aimster
FirstChildCreateTimeTAG: 2013-02-22T09:51:56Z
FirstChildVoteTAG: 1
SecondChildTAG: From what I could see, anyone can create their own room :) If you're already logged in, there's a Create Room button on the right on www.getstudyroom.com
I haven't tried it yet, since so far all the rooms I've needed were already there, but I really doubt all the rooms end up on that main list, so once you create a room I think it's best you post the link to it on the discussion forums or email it to your classmates (if you know them :)
SecondChildUserIdTAG: 230828
SecondChildUserNameTAG: alanis
SecondChildCreateTimeTAG: 2013-02-23T10:58:26Z
SecondChildVoteTAG: 0
FirstChildTAG: Thanks for the reminder emersonmalca :) See you there!
FirstChildUserIdTAG: 230828
FirstChildUserNameTAG: alanis
FirstChildCreateTimeTAG: 2013-02-23T11:00:08Z
FirstChildVoteTAG: 1
IndexTAG: 2777
TitleTAG: Thank You professor A
Thank you for great material, very interesting lectures and challenging exercises! And huge thanks for your efforts in making this available for all of us around the world.
It is very nice to see how you adapt and work with us and listen to suggestions we post here on forum, that make our life easier like with due dates not being so strict.
All the best and hope to hear new lectures and even new courses stat 2.2 and 2.3 in future.
Thank you!
UserIdTAG: 127421
UserNameTAG: apbyte
CreateTimeTAG: 2013-02-22T08:54:38Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It is a very exciting and very refreshing way to learn.I had tried to do a statistics course in vain and being a cardiac surgeon it was impossible with work constraints but I am happy that I can pursue this.We use a lot of statistics in cardiac surgery but most of it was self learnt hodge podge and having a structured course is fantastic.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T09:17:01Z
FirstChildVoteTAG: 0
IndexTAG: 2778
TitleTAG: Practice for Exercises set 2
a) Height of -10 to 20 bar = ____________ % per unit
incorrect 1.4
EXPLANATION
The height of a bar is equal to: relative frequency in the class interval/**width of class interval**. Therefore, the height of the -10 to 20 bar is 14/10 = 1.4% per unit.
**However, Width of the class should be 20-(-10)= 30 units and so 14/30= 0.46% per unit.** **Please Clarify**
UserIdTAG: 786512
UserNameTAG: shoaibkhanz
CreateTimeTAG: 2013-02-22T08:37:36Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: it's solved right here,
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5126f6ed3e23fe220000011b
it says, Its a Mistake...
14/30 is correct.
FirstChildUserIdTAG: 786512
FirstChildUserNameTAG: shoaibkhanz
FirstChildCreateTimeTAG: 2013-02-22T08:42:28Z
FirstChildVoteTAG: 1
FirstChildTAG: I have the same answer : -10 to 20 is 30. Therefore the answer should be 14/30. But its been marked wrong!!
FirstChildUserIdTAG: 1129036
FirstChildUserNameTAG: Dileepk
FirstChildCreateTimeTAG: 2013-02-22T12:08:17Z
FirstChildVoteTAG: 0
IndexTAG: 2779
TitleTAG: Histograms, definition and clarification request
Hi
a couple of days ago I have posted a comment regarding histograms in Excel but since then I have searched more and saw that the statistical software package called STATA under their Histogram do accept several representations of histogram charts, such that the Y axis can be either: Density, Fraction, Frequency or Percent.
http://www.youtube.com/watch?v=nPqNZVToGx8&feature=plcp
This brings me to the point that maybe the explanation of equal size bins compared to uneven sized bins should be elaborated a bit more and so the definitions of the different ways and type of histograms in representation of the Y axis.
For myself not fully understanding the differance led me to giving several wrong answers.
Can this be elaborated more before we move to next topic in our class.
Thanks
Moshiko
UserIdTAG: 1240022
UserNameTAG: Moshiko
CreateTimeTAG: 2013-02-22T08:32:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: inline with histograms, i would like some help in creating one using MS Excel. my data analysis is installed and i can be able to access the histogram but it asks for bins range and input range but when i select what i want i get zeros. for instance if i wanted to have a histogram of the incomes table we created with the percents and heights. thanks
FirstChildUserIdTAG: 818658
FirstChildUserNameTAG: sheilal
FirstChildCreateTimeTAG: 2013-02-22T13:11:24Z
FirstChildVoteTAG: 0
SecondChildTAG: Dear sheilal
Look at this tutorial or other that can be foundon the internet
http://www.youtube.com/watch?v=xe2Q6z6PTqk
Moshiko
SecondChildUserIdTAG: 1240022
SecondChildUserNameTAG: Moshiko
SecondChildCreateTimeTAG: 2013-02-22T14:36:59Z
SecondChildVoteTAG: 0
SecondChildTAG: Dedicated stats packages are much easier to manipulate than Excel - which is a spreadsheet not an analysis program.
R is a free open source stats program, but it has a rather steep learning curve.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T23:29:38Z
SecondChildVoteTAG: 0
IndexTAG: 2780
TitleTAG: i can't see the video? what should i do now?
i can't see the video? what should i do now?please help me.
rashu
UserIdTAG: 1116406
UserNameTAG: RashuS
CreateTimeTAG: 2013-02-22T08:16:31Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You might need to use a different browser. Try Chrome or, if you are using Chrome, try Firefox.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T08:20:16Z
FirstChildVoteTAG: 0
IndexTAG: 2781
TitleTAG: how to give answers by rounding off
hey if the answer is 3.5539..... and not said after the question for rounding off what should we write
and if answer is 3.59 and said round off by one place should we write 3.6
UserIdTAG: 995201
UserNameTAG: p-yash
CreateTimeTAG: 2013-02-22T07:31:09Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It depends on the context. for 3.5539, I would round off depending on how many significant figures were used in the question. In other words, if all of the information was given in tenths, then I would round my answer to tenths. If hundredths were given, round to hundredths.
For your second question, you are correct. 3.59 rounded to tenths is 3.6.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-23T13:13:36Z
FirstChildVoteTAG: 0
IndexTAG: 2782
TitleTAG: Additional Resources
My biggest weakness is being able to read information from the following kinds of charts
The distribution of ages in the United States in the year 2010 is given below. Intervals include the left endpoint but not the right; the number of people aged 100 or more was not zero but it was so small that it makes no difference to the table. You can assume that the ages are uniformly distributed within each interval.
Age (Years) Percent
0-5 6.6
5-15 13.3
15-20 7.1
20-30 13.8
30-45 19.8
45-60 20.9
60-75 12.5
75-100 6.0Source: Adapted from Statistical Abstract 2012
to answer questions like
Each part is worth 1 point.
a) About what percent of the people were in their thirties? Round your answer to one decimal place.
incorrect
b) A common (though not universal) definition of "senior citizen" is "person over the age of 65". About what percent of the population were senior citizens? Round your answer to one decimal place.
incorrect
I was wondering if there were problems elsewhere besides the book that would help me to learn to translate the data?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-22T07:27:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2783
TitleTAG: Picky rules for percent signs
I just did a 1 of 2 submission for Week 1 Exercise Set 2 Problem 2 a & b. I got red X for both. When I deleted the percent signs for both I got green check for one, red check for the other. But the website's picky rules for percent signs effectively denied me a chance to review the real wrong answer (i.e., in reality, not a and b but only b deserved a red X).
Can the website be adjusted to always accept percent signs?
No doubt a clarification will be handed down, but with 47,000 enrolled for the course thousands, including me, will forget which is acceptable: a percent sign or no percent sign.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-22T07:14:26Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2784
TitleTAG: submission of assignments
Hi
I have just seen the revised schedule, and i want to find out,do we to wait until the actual due date for us to submit our assignments or we can even do it earlier.
UserIdTAG: 959663
UserNameTAG: Alefa
CreateTimeTAG: 2013-02-22T06:54:44Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I dont think you have to wait. I've submitted some of my assignments already
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-22T06:56:13Z
FirstChildVoteTAG: 0
SecondChildTAG: I did the same for Exercise 1; only, I miss-clicked an answer and I got it wrong.
SecondChildUserIdTAG: 288327
SecondChildUserNameTAG: IsabellaVel
SecondChildCreateTimeTAG: 2013-02-22T07:02:41Z
SecondChildVoteTAG: 0
FirstChildTAG: > do we to wait until the actual due date for us to submit our assignments or we can even do it earlier.
Do them whenever you like, as long as you submit before the due time. Just don't leave to the last minute.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T07:20:53Z
FirstChildVoteTAG: 2
IndexTAG: 2785
TitleTAG: " A more detailed breakdown is provided in each problem"
This is stated for Week 1 Exercise 2. What does this mean?
I don't see a more detailed breakdown, either before or after I hit the "Final Check" button.
Also, if we make mistakes in our homework submissions, when can we get feedback? For Week 1 HW, for example, do we have to wait until after Wed. next week?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-22T06:45:41Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: > This exercise set is worth 20 points. A more detailed breakdown is provided in each problem.
This refers to the mark allocation. So $20$ points allocated over $7$ problems.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T07:22:27Z
FirstChildVoteTAG: 0
IndexTAG: 2786
TitleTAG: question related to set 2 questions
Problem 6
A histogram shows the number of hours students spent preparing for a test. The table below gives the intervals and the heights of the bars (in percent per hour). Intervals contain the left endpoint but not the right. No student spent 25 hours or more in preparation.
time (hours) height
0-4 2.5
4-10 6
10-15 ?
15-25 1
I am confused on how to tell which end point is included and which one is not. I am assuming that in this problem that the right end-point is not included. How would I tell if it wasnt?
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-22T06:27:34Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: > Intervals contain the left endpoint but not the right.
So for the interval $0 - 4$ , $0$ is included in the interval and $4$ is not.
This would be $0\le X \lt 4$.
> How would I tell if it wasnt?
You need the question to tell you. This info should be included somewhere in the question. Either a sentence, like that given, or a formula like I wrote above.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T06:31:21Z
FirstChildVoteTAG: 0
SecondChildTAG: so what would be a general formula to use if your missing data as we were in problem 6?
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-22T06:52:29Z
SecondChildVoteTAG: 0
SecondChildTAG: I am looking in the text found at http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#histograms and the answer is eluding me.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-22T06:59:05Z
SecondChildVoteTAG: 0
FirstChildTAG: > so what would be a general formula to use if your missing data as we were in problem 6?
In this question, you are told that it includes the left but not the right endpoint. Think back to the formula for calculating the height. Here you have the height, so can you use that knowledge to find the value?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T07:24:29Z
FirstChildVoteTAG: 0
SecondChildTAG: Histograms are going to be the death of me.
What do i know?
not much. I know the time(hours) and am seeking the height for the time(hours) 10-15.
found the formula(I think.)
height of bin=fraction of data in class interval/ width of class interval
6=x/5=> 5x6=30
I am not going to know for sure I am headed in the right direction until I can see the riht answer.
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-22T08:15:08Z
SecondChildVoteTAG: 0
SecondChildTAG: You need to do a bit more before you can work out the missing value. More information is required.
You can work out the percentage in the other categories. That should give you the percentage in the $?$ category. Then you can work out the height.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T08:27:23Z
SecondChildVoteTAG: 0
FirstChildTAG: Because in the problem description it should say it, like in this exercise: "Intervals contain the left endpoint but not the right"
FirstChildUserIdTAG: 150897
FirstChildUserNameTAG: my-mitx
FirstChildCreateTimeTAG: 2013-02-22T13:04:26Z
FirstChildVoteTAG: 0
IndexTAG: 2787
TitleTAG: progress question
I have already turned in the first assignment and received a grade on it. When would it show up in the progress section. I want to track my grades
UserIdTAG: 1132017
UserNameTAG: SherryJo
CreateTimeTAG: 2013-02-22T05:56:55Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It should be immediate. If it doesn't show, just refresh the page.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T06:14:12Z
FirstChildVoteTAG: 0
SecondChildTAG: thanks
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-22T06:24:44Z
SecondChildVoteTAG: 0
IndexTAG: 2788
TitleTAG: 35% is a passing grade?
I would think that such a low passing grade is representative of a class that is extremely difficult and well beyond the heads of 80% of the people taking this course. Is this is mistake? I feel like I don't even have to try or learn anything to pass this course. I'm not doing this strictly to get a certificate, but I feel like there is no way I could show this to anyone and honestly ask for their respect if I did show it.
For example, I signed up for Quantum Computing, which needs a background in linear algebra, basic probability, and programming. To pass, you'd need an 80% passing grade, and that course isn't really that easy. Other courses I've taken on other sites do have as low as 55% passing, but those classes are very challenging. What is the meaning of such a low passing grade in this class?
Regardless of this disappointing passing grade, I look forward to learning some new perspectives.
UserIdTAG: 627857
UserNameTAG: dt1
CreateTimeTAG: 2013-02-22T05:29:10Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 11
FirstChildTAG: The point you have raised are valid if you compare it with so many courses available online and the passing percentage on those.
However, I think learning should never be evaluated with the passing percentage. This is an open course for so many people who don't really get the chance to avail such exposure and they should be able to enjoy the learning here without taking pressure of performance like high schools.
FirstChildUserIdTAG: 1162288
FirstChildUserNameTAG: AbhiT
FirstChildCreateTimeTAG: 2013-02-22T05:50:53Z
FirstChildVoteTAG: 9
SecondChildTAG: Lovely philosophy. I like :-)
SecondChildUserIdTAG: 921219
SecondChildUserNameTAG: ObiOneCannotBe
SecondChildCreateTimeTAG: 2013-02-22T06:41:37Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with this. All the learning I've done over the past few years has been by myself for no good reason and no "certified" proof of success, so my personal reasons align with what you are saying.
You raise a valid point about the dropout rate. I agree that it is very high and it is likely high regardless of what passing grade they offer.
I disagree with the idea that you shouldn't be pressured. If you don't like pressure, there are plenty of excellent and free resources out there where you can learn practical statistics. The difference is that they are offering a certificate from a presumably reputable site (EdX) which implies that you did the requisite coursework that is demanded from a prestigious institution (Berkeley). I specifically made the comparison between this course and Quantum Computing because they are both offered by Berkeley, they have very different baseline challenges, and they have widely divergent definitions of success. The entire point of offering a cert is to show you demonstrated some minimal competency. Getting just over 1/3 on a course with multiple chances at multiple choice questions makes it nearly possible to blindly click buttons and pass the course. This is pretty unfair to the people who took the time to master the material as this dilutes the perceived value of attaining a certificate for the student, prospective employer, and really the statistics that EdX gathers and possibly shows off to the world. Even without the certificate, which I don't care about, my own perceived value of passing this course is diluted: if someone tells me they passed this course, I simply won't know what to make of that statement.
SecondChildUserIdTAG: 627857
SecondChildUserNameTAG: dt1
SecondChildCreateTimeTAG: 2013-02-22T06:47:26Z
SecondChildVoteTAG: 0
SecondChildTAG: I get your frustration. However I feel that it is good to be also considerate of those who really want to learn statistics but have a challenge in mathematics. Putting a high pass mark will put a lot of pressure on them to the point of quitting midway. I dont know how the edx certificate looks like, but my suggestion would be maybe they grade the certificate, and indicate whether one got a pass(starting from 35%) or the highest a distinction
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-02-22T17:45:29Z
SecondChildVoteTAG: 0
SecondChildTAG: There was a story I heard that goes like this:
If you see a butterfly struggling to get out of his pupa, you are not to help it: the struggle causes her wings to become strong enough to fly and live a wonderful life. If you do help it, you have only freed it in the short-term; you have crippled it for life for now her wings are no longer strong enough to lift her body.
Look. Not everyone is supposed to be a programmer, statistician, mathematician, etc, no more than I can expect to be a lawyer or historian. I don't know what happened to the world that everyone feels like everyone should learn to be everything. So what if people have a weakness in math? Isn't the entire point of college-level courses to be to challenge you?
SecondChildUserIdTAG: 627857
SecondChildUserNameTAG: dt1
SecondChildCreateTimeTAG: 2013-02-22T22:11:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Unlike a liberal arts course in, say, philosophy, where all answers are relative, a math based course is quantifiable. If you learned the material, you get the right answers and a high grade. If you didn't, then you give wrong answers and get a low grade.
A low grade - whether it's 'passing' or not - means you didn't learn the material. Giving a certificate of completion or participation to these people simply devalues it to anyone who makes a sincere effort to learn the subject.
SecondChildUserIdTAG: 1081022
SecondChildUserNameTAG: Paul02035
SecondChildCreateTimeTAG: 2013-02-25T23:47:50Z
SecondChildVoteTAG: 0
FirstChildTAG: I think dT1 makes a very valid point. I would also like to know what the reasons might be for setting the passing grade at 35%?
Taking into consideration that the certificate does not reveal one's final grade for the Stat2.1X course; if I should decide to use the certificate for potential career opportunities, it is a tad bit challenging to explain that the course has a set pass grade of 35% (if/when asked about the course in future).
Suggested pass grade: 50%
FirstChildUserIdTAG: 1207788
FirstChildUserNameTAG: NRHassan
FirstChildCreateTimeTAG: 2013-02-22T06:41:51Z
FirstChildVoteTAG: 3
SecondChildTAG: If I showed this to a prospective employer, I'd probably attach a screenshot of my real grade so that despite the funny conversation about 35%, I still showed that I did my best to crush the courseware.
SecondChildUserIdTAG: 627857
SecondChildUserNameTAG: dt1
SecondChildCreateTimeTAG: 2013-02-22T07:11:49Z
SecondChildVoteTAG: 0
FirstChildTAG: The certificate issue is a never ending dilemma. I just completed a course that had an $85\%$ requirement, dopped to $80\%$ when the final marks were tallied.
This mark caused a huge amount of drama. Too high! was a frequent complaint. It should be lowered to $70\%$, $60\%$, or whatever mark the particular poster thought they were going to get. If you scored $1$ less than the magic mark, then you should be bumped up. And lots more variations on the theme.
Then there were pleas for everyone to get a certificate of some sort - if not the completion certificate then at least a "participation" certificate. Otherwise all that hard work was for "nothing".
Then, when the mark was lowered there were more complaints. It apparently "devalued" the effort of those who scored $85 \%+$.
So, I don't envy the course admins. Regardless, there will be complaints.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T06:52:56Z
FirstChildVoteTAG: 0
SecondChildTAG: I most certainly didn't want to spark off a drama bomb. No matter where you land on the spectrum, you have to admit that 35% is a tad low for "passing" by any measure.
As the NRHassan you said, if he was using this with the intention of showing his knowledge to future employers -- and you have to accept this is the reality of the situation for many students here -- it is going to be hard to have them swallow that you "earned" a cert in a class with a 35% passing grade. I guess you could just take a screenshot of your real score and show it off to people, but the point is that future employers may eventually get wind of the low standard and roll their eyes at you.
If you do have the stance that the only reason people do these classes is strictly for an improved sense of self-worth, then your reasoning is completely valid, but it is nonsensical for anyone to assume that there isn't some people who would like to use this resource as a tool to advance their own standing life.
For whatever it's worth, my job involves a lot of statistics and data-crunching, so while I don't technically need this certificate to "prove" I can do the work, I feel it wouldn't hurt to have it.
SecondChildUserIdTAG: 627857
SecondChildUserNameTAG: dt1
SecondChildCreateTimeTAG: 2013-02-22T07:07:38Z
SecondChildVoteTAG: 0
FirstChildTAG: I think this is encourage more students to complete this course who will then enroll for 2.2x where the passing grade will be 50% and finally 2.3x will have passing grade of 80%. Once students have invested some time they will be more motivated to continue in spite of more difficult grading in future.
FirstChildUserIdTAG: 523705
FirstChildUserNameTAG: IITian
FirstChildCreateTimeTAG: 2013-02-22T07:43:56Z
FirstChildVoteTAG: 1
FirstChildTAG: I would have though that there is a good reason for the 35%, for me personally the pass mark is irrelevant, if I get less than 80% overall I will do the course again and again until I do
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-22T07:45:05Z
FirstChildVoteTAG: 0
FirstChildTAG: Just my two cents but perhaps there is a statistically significant reason for the 35% mark?
Also, don't forget that this entire EdX platform is relatively new and is really a joint experiment with many of these universities to figure out what enables people to learn best. Along the way we're sure to find things we disagree with or don't like and other things that we love. But, in order for EdX to be a success they're going to have to pull data from a wide variety of different subsets... You know... Do statistics and stuff. :-)
I'm content in the fact that I've been with EdX from the beginning and I'm willing to be a guinea pig for this massive scientific experiment. Oh, and I get to learn something too.
The worst case scenario in all of this is that someone who makes a 35% as their total overall score gets to pass off their unaccredited certificate to a prospective employer who may or may not accept it. On the flip side, those of us who finish the course and have applied ourselves will get a certificate and know the "real value" behind it all while making EdX a better platform for everyone.
I'm OK with whatever the course designers deign necessary or think sufficient. If there's a flaw in the logic it'll get unveiled with the data they get after the course is over and they'll know better next time.
Just go with the flow... Challenge yourself to double the minimum score or even to get a 100%. You'll know what you put into it in the end anyway and that's all I care about.
FirstChildUserIdTAG: 87103
FirstChildUserNameTAG: fjbasile
FirstChildCreateTimeTAG: 2013-02-22T08:52:08Z
FirstChildVoteTAG: 1
FirstChildTAG: I am a bit surprised that people are pronouncing judgments about the quality of the course and the passing grade even before the full material and course work is at hand.While I am not a statistician, I am a teacher and I jolly well know that the usual method is to go slow and easy as the course progresses make it tougher.Of course I am sure that while things may appear easy remember there is a diverse group with some even having problems with language etc.Also I bet our Professors can make you dance in circles if they so wish ;)
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-22T09:25:38Z
FirstChildVoteTAG: 1
FirstChildTAG: Indeed, it seems a very low pass grade but it has nothing to do with the quality of the contents and the learning possibilities of the course. It's true that what we've seen till now may not be very challenging for some people but it's a good warm-up for many of us. And I'm sure that the course will get more and more difficult with the pass of weeks. So, lets be patient and enjoy this oportunity.
FirstChildUserIdTAG: 1176613
FirstChildUserNameTAG: Asrael
FirstChildCreateTimeTAG: 2013-02-22T10:03:54Z
FirstChildVoteTAG: 0
FirstChildTAG: The passing grade is too low. It should be around 70%. With 35% a coin can get the certificate.
FirstChildUserIdTAG: 334059
FirstChildUserNameTAG: RafaelNeumann
FirstChildCreateTimeTAG: 2013-02-24T22:51:43Z
FirstChildVoteTAG: 1
SecondChildTAG: Agree!
SecondChildUserIdTAG: 1081022
SecondChildUserNameTAG: Paul02035
SecondChildCreateTimeTAG: 2013-02-25T16:18:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Well I dont know lecture 2.1 in her grad class had someone with a score of 48 and I doubt he failed ,I dont know I just think they might have some logical reasoning to this ,maybe as its a class where theres 3 follow ups its not necessary because to move on to 2.2x youd have to have this material down ? I dont know ,im sure theres no reason to worry about this ,besides who exactly do you think will sign up for a stats class for fun ,they clearly want to learn .And well another thing is maybe ,just maybe edx is considering adding your grade on it ,so maybe you can get the option of letter grade or completion score (its what mit does for freshmen ,so i dont know its possible ,and also it wont really do anything negative I mean all the older students with certificates would just have to opt into it ) ,but I dont know ,were all just debating on this and it could even be a bug ,point it ,just go in do your best and learn the most you can ,besides a certificate here without the skill to back it up is just dumb ,so im sure were safe .
FirstChildUserIdTAG: 20186
FirstChildUserNameTAG: vikashx1
FirstChildCreateTimeTAG: 2013-02-26T01:15:18Z
FirstChildVoteTAG: 1
FirstChildTAG: Very interesting topic, and very difficult since we all come from different backgrounds and have different goals to enroll.
I read some numbers on another course offered here at edX (I think it was 6.02x):
- Enrollment: **200.000**
- Opened the first PS: **40.000**
- Got at least a point in the first PS: **20.000**
- Got at least a point in the final exam: **10.000**
- Passed the class: **5.000**
The first jump from 200.000 to 40.000 it's very difficult to avoid, is people that signed but latter had no interest (or time) to actually do it. I think the 35% comes in an attempt to minimize the jump from 40.000 to 5.000, almost 90% of the people "lost" along the way. The idea might go that if the course looks very accessible, more people will persevere and finish, if it looks too difficult to the point of being unattainable, people will quit.
If this analysis is true or not, and if it is desirable or not, remains to be seen. My personal opinion is that you shouldn't give a certificate to people just because they were able to listen to a few hours of videos (as it is now with the 35%), you need to prove that you understand "some" of the concepts, and go back to the videos if you didn't. A 50 - 60% works much better in my opinion. The best solution also includes several grades (>90%) so that it remains a challenge for everybody, the ones that just want to pass, and the ones that want a perfect score. It doesn't make any sense that many people have already passed this class before even the 1st midterm has taken place.
FirstChildUserIdTAG: 1024715
FirstChildUserNameTAG: iparrajorge
FirstChildCreateTimeTAG: 2013-03-08T19:17:51Z
FirstChildVoteTAG: 0
IndexTAG: 2789
TitleTAG: pdf for problem sets
to the staff at Stat2.1X: will it not be nice if pdf is available for the problem sets. it helps to sit down and work thru the problems even in case of connectivity problems.
UserIdTAG: 390463
UserNameTAG: DrPatilShrish
CreateTimeTAG: 2013-02-22T04:55:08Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Yes it will be helps alot
FirstChildUserIdTAG: 1240674
FirstChildUserNameTAG: WadEljack
FirstChildCreateTimeTAG: 2013-02-22T05:11:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Sir / Madam
Just a question regarding the lecture material. Should we go through all the material in "**Practice for exercise set 1**" to be equipped to answer questions for for "**Exercise set 1**" and to move on to "**Exercise set 2**" for week 1? Or should we focus on following the course schedule layout when going through each "Practice for exercise n"?
Regards
Shantelle Claassen
FirstChildUserIdTAG: 1098795
FirstChildUserNameTAG: shantelle
FirstChildCreateTimeTAG: 2013-02-22T06:23:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Dear Sir
Yes this will help us also as we can not download the lecture .
FirstChildUserIdTAG: 633923
FirstChildUserNameTAG: Fahmil
FirstChildCreateTimeTAG: 2013-02-22T06:47:03Z
FirstChildVoteTAG: 0
IndexTAG: 2790
TitleTAG: Problem set 1 discrete vs non-discrete
Income is actually a discrete quantitative variable as it can be divided no smaller than into cents or pennies (or other distinct small units depending on the country). I disagree with the answer
UserIdTAG: 406503
UserNameTAG: Wind
CreateTimeTAG: 2013-02-22T04:53:13Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: There are a number of threads on this (search for income)
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/51256a35191b9b28000000d9
As mentioned in the lecture, the distinction between the two is somewhat blurry. I look at income as continuous because you can earn in the many decimal places depending on your hourly rate and hours worked.
$7.25$ hours at $\$21.23$ per hour will give you $\$153.9175$. Before the tax man takes his cut.
But, your money in hand is discrete as you can't be given $\$153.9175$, just $\$153.92$. Maybe one day when money is the stuff of legends, we will keep all those decimals.
However, the distinction between the two seems to cause more discussion than most other topics.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T05:10:48Z
FirstChildVoteTAG: 2
IndexTAG: 2791
TitleTAG: Week 1 - Exercise Set 2
Where are the technical definitions of "uniformly distributed" and "crowded", two terms used in Ex. Set 2? They are not in the textbook at http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#frequency_tables
nor in the course thesaurus.
Thus I hesitate to answer until I know what the course intends these terms to mean.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-22T04:43:29Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: They were explained in the lecture.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T04:59:12Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, in the lecture Prof. A says that uniform means that inside each interval you can divide the total % of the interval between all the unit of the interval. Example, assume an interval with 20% and comprised of 30 units, then each unit carries 2/3 % per unit. So if say you need to know what percent comprises 5 units of the interval you take 5(units)*2/3 (% per units)= 10/3 %. The point is that you can assign to each unit of the interval the same 2/3 % so the 30 units give the 20%, and you can do this because the interval is uniformly distributed, each unit with the same % share.
FirstChildUserIdTAG: 150897
FirstChildUserNameTAG: my-mitx
FirstChildCreateTimeTAG: 2013-02-22T05:25:31Z
FirstChildVoteTAG: 3
IndexTAG: 2792
TitleTAG: Lecture 2.2 nd 2.3
Why isn't it 14/30 because the difference between -10 and 20 is 30?
The height of a bar is equal to: relative frequency in the class interval/width of class interval. Therefore, the height of the -10 to 20 bar is 14/10 = 1.4% per unit.
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-02-22T04:41:17Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Because it is a mistake.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T04:44:16Z
FirstChildVoteTAG: 0
FirstChildTAG: Yes, I also thought so, but it would be nice to have the instructors reassure us.
FirstChildUserIdTAG: 150897
FirstChildUserNameTAG: my-mitx
FirstChildCreateTimeTAG: 2013-02-22T04:56:01Z
FirstChildVoteTAG: 0
FirstChildTAG: I was getting pretty worried when I got to that exercise.
It shook all my certainties about basic arithmetic after more than 20 years of having to work with numbers!
Then of course, I accepted that the text is just wrong XD
FirstChildUserIdTAG: 604636
FirstChildUserNameTAG: Klionheart
FirstChildCreateTimeTAG: 2013-02-22T11:58:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, sometimes it is they who are wrong, not us. Though it doesn't happen as often as some here think!
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T21:53:33Z
SecondChildVoteTAG: 0
IndexTAG: 2793
TitleTAG: Hi
Great to be part of this course. I'm currently taking a course at my university and I feel this course came at a timely manner.
UserIdTAG: 1182221
UserNameTAG: mefor01
CreateTimeTAG: 2013-02-22T04:40:23Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2794
TitleTAG: Lecture 2.1 Ques 1
I do not understand what they mean by **the decimal point is 1 digit to the right of the |** How is this possible if the numbers are 165 166 167 167 168. With her reasoning it sounds like 165.6 166.7. It makes no sense what she says. Please explain.
Here is a stem and leaf plot of the heights (in centimeters) of a group of men. Computer programs that generate such plots have to explain where they chose to place the vertical bar; the one I used says, “The decimal point is 1 digit to the right of the |”
UserIdTAG: 277481
UserNameTAG: scott520
CreateTimeTAG: 2013-02-22T04:34:08Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: scott520
The layout is height in cm ie 165cm etc.
they are describing the above as 165.0 cm.
hope this helps.
FirstChildUserIdTAG: 313672
FirstChildUserNameTAG: blinxnot
FirstChildCreateTimeTAG: 2013-02-22T05:07:18Z
FirstChildVoteTAG: 0
IndexTAG: 2795
TitleTAG: Excercise Set 1 Problem 2b
for the question Exercise Set 1 Problem 2b : Im confused about the asnwer. i chose A for the Histogram graph but wrong. so which one is the correct answer? help me please...
UserIdTAG: 1193006
UserNameTAG: makmursp
CreateTimeTAG: 2013-02-22T04:24:41Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Obviously we can't tell you the answer.
Look at the entire graph, not just the bars. And note that the questions says:
> Which of the following bar graphs are derived from the data above? **Select all that are correct**
So there might be more than one correct answer.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T04:29:56Z
FirstChildVoteTAG: 0
SecondChildTAG: Susan, you're back!!!! So nice to see you (or at least your postings) again
SecondChildUserIdTAG: 406503
SecondChildUserNameTAG: Wind
SecondChildCreateTimeTAG: 2013-02-22T04:55:22Z
SecondChildVoteTAG: 0
FirstChildTAG: Thank you susan. i have looked the entire graph and yes i found 2 correct asnwers. am i right? as i know that in Multiple Choice Question there is only one correct answer...
FirstChildUserIdTAG: 1193006
FirstChildUserNameTAG: makmursp
FirstChildCreateTimeTAG: 2013-02-22T05:25:30Z
FirstChildVoteTAG: 0
SecondChildTAG: where are you from susan?
SecondChildUserIdTAG: 1193006
SecondChildUserNameTAG: makmursp
SecondChildCreateTimeTAG: 2013-02-22T05:25:50Z
SecondChildVoteTAG: 0
SecondChildTAG: I'm Australian.
MCQs don't always have just one answer. It depends on the question and how it has been formatted.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T05:35:52Z
SecondChildVoteTAG: 0
SecondChildTAG: oh ok Susan. Im from Indonesia. Nice to meet you here Susan.. and thanks for the explanation. seems that you are a smart one.
SecondChildUserIdTAG: 1193006
SecondChildUserNameTAG: makmursp
SecondChildCreateTimeTAG: 2013-02-22T06:12:52Z
SecondChildVoteTAG: 0
SecondChildTAG: I was wondering about that. Wishing that I had looked at the discussion before answering. Completely missed the "select all" part. Thanks, Susan.
SecondChildUserIdTAG: 868694
SecondChildUserNameTAG: NancyE
SecondChildCreateTimeTAG: 2013-02-22T15:13:29Z
SecondChildVoteTAG: 0
IndexTAG: 2796
TitleTAG: Practice for Ex 1
The exact percentage of seniors is 100 x 30/270 = 11.1111 etc repeating fraction. The idiot software marks wrong both 11% and 11.111% This is ridiculous.
UserIdTAG: 1284385
UserNameTAG: EdMeasure
CreateTimeTAG: 2013-02-22T04:10:27Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: > The idiot software marks wrong both 11% and 11.111% This is ridiculous.
This issue has been raised, in far more reasoned terms. Many times. And addressed.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T04:17:54Z
FirstChildVoteTAG: 1
FirstChildTAG: I have had the same problem - a clarification about decimal places is needed
FirstChildUserIdTAG: 1004185
FirstChildUserNameTAG: ale1808
FirstChildCreateTimeTAG: 2013-02-22T10:13:35Z
FirstChildVoteTAG: 0
IndexTAG: 2797
TitleTAG: Seems it is not difficult to get the Cert
From "policies and requirements":
> Certificates of completion will be awarded to those who score 35% or higher overall.
35%......
UserIdTAG: 699049
UserNameTAG: JackYang
CreateTimeTAG: 2013-02-22T03:50:34Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Extremely low... I guess society should be happy with a grade as low as 35%. (In stats at least)
FirstChildUserIdTAG: 1207788
FirstChildUserNameTAG: NRHassan
FirstChildCreateTimeTAG: 2013-02-22T06:44:40Z
FirstChildVoteTAG: 0
FirstChildTAG: well, I'm here to learn, so a certificate is just a bonus. :-)
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-22T06:56:45Z
FirstChildVoteTAG: 3
IndexTAG: 2798
TitleTAG: Error on READING AND PRACTICE FOR EXERCISE SET 2?
Question A on Practice Exercise Set 2 says that the width of the interval is 10. Isn't it 30?
UserIdTAG: 824227
UserNameTAG: dcorneli
CreateTimeTAG: 2013-02-22T03:15:48Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I think the interval is 30.
FirstChildUserIdTAG: 653718
FirstChildUserNameTAG: Ranchu
FirstChildCreateTimeTAG: 2013-02-22T03:19:20Z
FirstChildVoteTAG: 1
FirstChildTAG: This issue has been raised several times on these forums. Please use the search button before posting. Credit will be given for correct answers.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-22T03:25:26Z
FirstChildVoteTAG: 0
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T03:26:37Z
FirstChildVoteTAG: 0
FirstChildTAG: I believe it is 30. -10 to +20 = 30.
FirstChildUserIdTAG: 1231390
FirstChildUserNameTAG: Chuck2008
FirstChildCreateTimeTAG: 2013-02-22T03:37:51Z
FirstChildVoteTAG: 0
IndexTAG: 2799
TitleTAG: Exercise Set 2 - Problem 4
Why can't we assume the dataset to be uniformly distributed ?
UserIdTAG: 653718
UserNameTAG: Ranchu
CreateTimeTAG: 2013-02-22T03:09:15Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: This is supposed to be an assessment item, so you should not be giving answers or asking for them. You will have to wait until after the due date for explanations.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T03:29:14Z
FirstChildVoteTAG: 1
SecondChildTAG: I thought its a question, not an answer!
SecondChildUserIdTAG: 346428
SecondChildUserNameTAG: aranic
SecondChildCreateTimeTAG: 2013-02-22T04:20:31Z
SecondChildVoteTAG: 0
SecondChildTAG: But the question is the answer.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T04:23:11Z
SecondChildVoteTAG: 0
FirstChildTAG: Look at the percent of people who had completed 12 years of school and did not proceed with higher education vs. those who completed 16 years of schooling and did not proceed with further education.
FirstChildUserIdTAG: 346428
FirstChildUserNameTAG: aranic
FirstChildCreateTimeTAG: 2013-02-22T04:22:45Z
FirstChildVoteTAG: 0
IndexTAG: 2800
TitleTAG: http://statistics.berkeley.edu/~stark/SticiGui/Problems/assign-2x-s13.htm
http://statistics.berkeley.edu/~stark/SticiGui/Problems/assign-2x-s13.htm
I am confused.Are we to submit these as assignments too ?
Also what is the "Student ID"
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-22T03:07:58Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: If you search the forum, you'll learn how to find out your Student ID.
FirstChildUserIdTAG: 252722
FirstChildUserNameTAG: vaboro
FirstChildCreateTimeTAG: 2013-02-22T03:24:51Z
FirstChildVoteTAG: 0
SecondChildTAG: I did try to use the methods described but when I click on my name nothing happens!!
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T03:34:51Z
SecondChildVoteTAG: 0
SecondChildTAG: sorry but where should i find my Student ID? please advise or email me at aimstermill51@aol.com the information. thanks so much
amy
SecondChildUserIdTAG: 411228
SecondChildUserNameTAG: aimster
SecondChildCreateTimeTAG: 2013-02-22T09:39:45Z
SecondChildVoteTAG: 0
SecondChildTAG: 411228
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T15:50:13Z
SecondChildVoteTAG: 0
FirstChildTAG: You don't submit the text problems. The assessment for this course is in the Courseware section.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T03:27:38Z
FirstChildVoteTAG: 0
IndexTAG: 2801
TitleTAG: Section 2a: The Histogram (Lec 2.1 - 2.3)
How can I get the video or text for **Section 2a: The Histogram (Lec 2.1 - 2.3)** if when I click on it I get the video for "Describing One Quantitative Variable"?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-22T01:52:27Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: That's correct. There are 3 videos for this section, this is the first. The remaining 2 are the icons on the filmstrip.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13614996121343634.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T01:54:50Z
FirstChildVoteTAG: 0
IndexTAG: 2802
TitleTAG: Exercise set 2 problem 3b
Can I assume that one of the 3 available answers is correct? (because it doesn't appear to be so) I got the coveted green check mark but none of the 3 available charts appear to be correct by area.
UserIdTAG: 1270753
UserNameTAG: RobLL
CreateTimeTAG: 2013-02-22T01:05:24Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Yes, it doesn't appear to match the data. With a bit of maths and Stata I reproduced their "correct" histogram, so I have an idea of what happened.
But even though it is wrong, it is the least wrong of the 3.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T01:32:31Z
FirstChildVoteTAG: 4
SecondChildTAG: Thank you, that is how I eventually approached it. (choosing the least wrong answer)
SecondChildUserIdTAG: 1270753
SecondChildUserNameTAG: RobLL
SecondChildCreateTimeTAG: 2013-02-22T01:34:18Z
SecondChildVoteTAG: 0
FirstChildTAG: Really . . . we need to select the least wrong answer? With an audience of > 40,000 it seems that they would do a bit more checking for errors.
FirstChildUserIdTAG: 917446
FirstChildUserNameTAG: oherman
FirstChildCreateTimeTAG: 2013-02-22T21:14:11Z
FirstChildVoteTAG: 2
SecondChildTAG: Well, hopefully someone will explain at some point why there's a correct answer. I care not about the grade. I'd like to understand what's teh rationale behind the correct answer
SecondChildUserIdTAG: 338910
SecondChildUserNameTAG: emiliobr
SecondChildCreateTimeTAG: 2013-02-23T18:10:47Z
SecondChildVoteTAG: 0
FirstChildTAG: > Really . . . we need to select the least wrong answer? With an audience of > 40,000 it seems that they would do a bit more checking for errors.
True. But it is a new course, on a revamped platform. Mistakes happen. And those who do the first offering of a course have to expect a bump or two. The staff are probably new at this, so they are learning too.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T21:56:56Z
FirstChildVoteTAG: 1
IndexTAG: 2803
TitleTAG: How do you know if your scores have saved?
Is there a simple way of knowing your work for the exercises has saved or submitted? I have done all of the ones for this week, however I'm still not sure they are saved if you understand what I mean... Is there a way of clarifying this?
Cheers, Jack
UK
UserIdTAG: 658901
UserNameTAG: jkelehar
CreateTimeTAG: 2013-02-22T00:51:28Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: ![enter image description here][1]
When you click Save, you should see the above message. If you have clicked Check, you will have either a green tick or a red cross. And the submission tally will increase. So, for example:
![enter image description here][2]
If you leave and then return to a question page later, your saved answers will still be visible. So even if you forget which ones you saved, the system remembers.
If you have completed the problems, and submitted for grading, then it really doesn't matter if you saved or not.
[1]: https://edxuploads.s3.amazonaws.com/13614945931343647.png
[2]: https://edxuploads.s3.amazonaws.com/13614947931343658.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T00:57:00Z
FirstChildVoteTAG: 0
IndexTAG: 2804
TitleTAG: Fuzzy math in Exercise 2 Practice?
The interval -10 to 20 is *30* units long, not 10. Why is the correct answer 1.4 when it should be 0.466666...?
UserIdTAG: 224280
UserNameTAG: Ryusui
CreateTimeTAG: 2013-02-22T00:50:08Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T00:51:04Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you. Yes, the interval is 30. I have not gone beyond this problem, because the answer in clearly wrong and I don't want to get any more answers wrong.
SecondChildUserIdTAG: 538232
SecondChildUserNameTAG: ANNECBH
SecondChildCreateTimeTAG: 2013-02-22T01:55:55Z
SecondChildVoteTAG: 0
SecondChildTAG: I was puzzled how my answer was marked incorrect.
Still enjoying the course so far. lectures are well presented and very informative.
SecondChildUserIdTAG: 313672
SecondChildUserNameTAG: blinxnot
SecondChildCreateTimeTAG: 2013-02-22T04:41:40Z
SecondChildVoteTAG: 0
IndexTAG: 2805
TitleTAG: Exercise set 2 problem 2a
If senior citizen is defined as "a person over 65", then can I assume that you do not mean to include people aged exactly 65?
UserIdTAG: 1270753
UserNameTAG: RobLL
CreateTimeTAG: 2013-02-22T00:46:26Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Age $\ge 65$
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T00:55:11Z
FirstChildVoteTAG: 1
SecondChildTAG: The wording of the question appears to be incorrect. Susan's correction should be included.
SecondChildUserIdTAG: 1270753
SecondChildUserNameTAG: RobLL
SecondChildCreateTimeTAG: 2013-02-22T01:31:53Z
SecondChildVoteTAG: 0
SecondChildTAG: The reasoning being, for example, that 10 is not over 10.
SecondChildUserIdTAG: 1270753
SecondChildUserNameTAG: RobLL
SecondChildCreateTimeTAG: 2013-02-22T01:33:03Z
SecondChildVoteTAG: 0
FirstChildTAG: Apparently not as a correctly marked answer is inclusive of age 65. At least to my calculations and I see that Susan agrees.
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-02-22T01:17:12Z
FirstChildVoteTAG: 0
IndexTAG: 2806
TitleTAG: Exercise Set 2, Problem 1, Question c
> Were there more 5-year-olds or 15-year-olds?
Well, this is exactly the kind of things we can not know for sure from a histogram. We may only estimate that number based upon the assumption of a particular distribution (in our case this is a uniform distribution) of values inside each interval. All in all, the question in this form is not well posed, I think.
UserIdTAG: 411014
UserNameTAG: evarga
CreateTimeTAG: 2013-02-22T00:37:46Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I think using the formula for percent per unit and the assumptions given you can reach the correct response without ambiguity.
FirstChildUserIdTAG: 242480
FirstChildUserNameTAG: cobradav
FirstChildCreateTimeTAG: 2013-02-22T01:27:28Z
FirstChildVoteTAG: 1
SecondChildTAG: Agree with cobradav. Look at each of the groups seperately.
Hope you get the correct answer evarga.
SecondChildUserIdTAG: 313672
SecondChildUserNameTAG: blinxnot
SecondChildCreateTimeTAG: 2013-02-22T05:01:51Z
SecondChildVoteTAG: 0
SecondChildTAG: You misunderstood my point. It is not about how to reach the correct answer, but the meaning of the question itself. I have arrived at the correct answer without any problems, although it still did not make me happy about how the question was posed.
SecondChildUserIdTAG: 411014
SecondChildUserNameTAG: evarga
SecondChildCreateTimeTAG: 2013-02-22T11:00:29Z
SecondChildVoteTAG: 0
IndexTAG: 2807
TitleTAG: 2X vs AP Statistics?
I am taking this course with some of my friends, and we are sophomores in an American high school. We finished taking 3.091x - Solid State Chemistry and found it a great help to AP Chemistry, which we are currently taking. It wasn't enough to cover the entirety of the course, but it did greatly clarify and expose some topics to us. I was wondering if anyone knew how this three-set series of courses compared to AP Statistics, because after finishing these, we are hoping to study some more and take the AP Statistics exam. Does anyone know how these compare?
UserIdTAG: 296450
UserNameTAG: Termiteruler
CreateTimeTAG: 2013-02-22T00:25:58Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2808
TitleTAG: [staff] Textbook reading schedule
Can you kindly provide a textbook reading schedule so that it's clear what should be read during particular weeks? I found one form of such a schedule on http://statistics.berkeley.edu/~stark/SticiGui/Problems/assign-2x-s13.htm but the dates are outdated, unfortunately.
UserIdTAG: 252722
UserNameTAG: vaboro
CreateTimeTAG: 2013-02-22T00:11:42Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I agree, this would be very helpful. Or under the practice sections indicate what specific sections of the book to read next to the link.
FirstChildUserIdTAG: 1197961
FirstChildUserNameTAG: JulieSCannon
FirstChildCreateTimeTAG: 2013-02-22T00:44:06Z
FirstChildVoteTAG: 1
FirstChildTAG: i agree this would be very helpful
FirstChildUserIdTAG: 411228
FirstChildUserNameTAG: aimster
FirstChildCreateTimeTAG: 2013-02-22T00:53:02Z
FirstChildVoteTAG: 0
FirstChildTAG: I agree too, very helpful.
FirstChildUserIdTAG: 891244
FirstChildUserNameTAG: JZatarain
FirstChildCreateTimeTAG: 2013-02-22T02:54:57Z
FirstChildVoteTAG: 0
FirstChildTAG: Supplementary materials will be provided in the Assets section of the course website.
I found the above in the course structure, does anyone know what the 'ASSETS' section is
FirstChildUserIdTAG: 1181314
FirstChildUserNameTAG: SolomonT
FirstChildCreateTimeTAG: 2013-02-22T04:06:02Z
FirstChildVoteTAG: 0
SecondChildTAG: no please advise. Is there anyway for the STAFF to add the reading scedule to the course syllabus?
SecondChildUserIdTAG: 411228
SecondChildUserNameTAG: aimster
SecondChildCreateTimeTAG: 2013-02-22T09:42:24Z
SecondChildVoteTAG: 0
IndexTAG: 2809
TitleTAG: Can we have the slides, please?
The videos are already brilliant as they are, but a chance to scroll back and forth through the slides would improve the experience enormously.
And I don't think I'm only speaking for myself here. Beamer files or pdfs, or both. And don't bother about the bread - just give us the files, please, if at all possible.
UserIdTAG: 1044850
UserNameTAG: tiktaalik
CreateTimeTAG: 2013-02-22T00:03:35Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Being addressed.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T00:16:23Z
FirstChildVoteTAG: 0
FirstChildTAG: Great news! Thanks.
FirstChildUserIdTAG: 1044850
FirstChildUserNameTAG: tiktaalik
FirstChildCreateTimeTAG: 2013-02-22T01:14:02Z
FirstChildVoteTAG: 0
IndexTAG: 2810
TitleTAG: Significant figures
In the very first exercise set where they asked for percentage of seniors I placed my answer to 5 significant figures or 3 decimal places, admittedly I chose this arbitrarily, and got the answer wrong. Is there any particular reason why the answer should have been to 1 decimal place?
UserIdTAG: 1260983
UserNameTAG: RhysaD
CreateTimeTAG: 2013-02-21T23:56:56Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Because that is what the grader was programmed to accept. This issue has been raised, and is being looked in to for future assessments.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T00:17:28Z
FirstChildVoteTAG: 3
SecondChildTAG: Am running into same problem. "Correct" answers vary in exactitude. Already seen 1 and 2 decimal places as the varying standard. Makes me wonder how insignificant rounding "errors" will affect grades.
SecondChildUserIdTAG: 975527
SecondChildUserNameTAG: Betachi8
SecondChildCreateTimeTAG: 2013-02-22T02:05:31Z
SecondChildVoteTAG: 0
IndexTAG: 2811
TitleTAG: STAFF_to unregister
Dear professors, thank you very much for such a great opportunity. I really appreciate all your activities in education dimension. But for the whole bunch of circumstances, I would go deeply into this course. But I can't. Nowadays I'm unavailable to cope with this course. So could you be so kind to understand me and forgive for your time. I wish you all good luck and thank you one more time! I hope next time I'll manage to. Sincerely yours, Svetlana
UserIdTAG: 1075425
UserNameTAG: ArefyevaS
CreateTimeTAG: 2013-02-21T23:39:39Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2812
TitleTAG: Ajuda
Boa noite!
Professores, parabéns pela iniciativa. A interatividade com os alunos está sendo ótima.
Mas preciso de ajuda! Não consegui acessar a palestra que consta nos comentários e nem a introdução. Podem me ajudar?
Agradeço
UserIdTAG: 1252854
UserNameTAG: Joycemelo100
CreateTimeTAG: 2013-02-21T23:12:18Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: From Google translate:
>Teachers, congratulations for the initiative. The interaction with students is great. But I need help! Unable to access the lecture contained in comments nor introduction. Can you help?
Are you using Chrome? Você está usando o Chrome? (I hope!)
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T00:18:50Z
FirstChildVoteTAG: 0
FirstChildTAG: Cara, você sabe inglês? Se não souber vai ser impossível completar este curso.
FirstChildUserIdTAG: 491226
FirstChildUserNameTAG: gdsimoes
FirstChildCreateTimeTAG: 2013-02-22T02:40:39Z
FirstChildVoteTAG: 0
IndexTAG: 2813
TitleTAG: Reading and practice for exercise set 2 / Lecture 2.2 and 2.3 / Exercise a
It looks to me that the width of the bar from -10 to 20 is 30 and not as 10 as stated in the correction 20 - (-10) = 30 ? Am I completly wrong here or is it a small discrepancy ?
UserIdTAG: 809365
UserNameTAG: mathmonde
CreateTimeTAG: 2013-02-21T22:52:27Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: This error has been posted several times. The professor has indicated she will correct this and other errors on the back-end.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T22:57:57Z
FirstChildVoteTAG: 0
FirstChildTAG: I have no idea but I have a question
a) Height of -10 to 20 bar = ____________ % per unit
incorrect The answer should be 1.4
I wrote it down as 14/-10-(20). In order for the math to work the 20 has to be negative so that when you multiple through by the implied negative one it becomes a positive number so that you can subtract the -10. This was the only way I could get it to work.
My math looked like this 14/-10-(-20)
FirstChildUserIdTAG: 1132017
FirstChildUserNameTAG: SherryJo
FirstChildCreateTimeTAG: 2013-02-21T23:00:03Z
FirstChildVoteTAG: 0
FirstChildTAG: See the errata page:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 684211
FirstChildUserNameTAG: bdt2110
FirstChildCreateTimeTAG: 2013-02-21T23:00:32Z
FirstChildVoteTAG: 1
IndexTAG: 2814
TitleTAG: Another Request: edX introductory videos
Just wondering if the videos that introduce the edX platform could be made available again.
There seem to be a few here who are new to edX and they are a bit confused about the system. The video was there before the course started, but vanished a couple of weeks ago.
UserIdTAG: 629320
UserNameTAG: SusanAust
CreateTimeTAG: 2013-02-21T22:47:11Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I would like to see those Susan...thx!
FirstChildUserIdTAG: 993968
FirstChildUserNameTAG: ccornwel
FirstChildCreateTimeTAG: 2013-02-22T01:22:49Z
FirstChildVoteTAG: 1
SecondChildTAG: Me too.
I am still confused whether there should be an "Introductory" video for me to see. There is a reference to it in the first "video" of this course - saying something like "you have seen the introductory video and know that the type of questions we will be answering will include .....". Is there an introductory video giving this information somewhere?
SecondChildUserIdTAG: 41340
SecondChildUserNameTAG: FPike
SecondChildCreateTimeTAG: 2013-02-22T20:20:51Z
SecondChildVoteTAG: 0
IndexTAG: 2815
TitleTAG: Due Date (Exercise Submission)
Due dates on COURSEWARE and Course schedule do not match.
UserIdTAG: 1181586
UserNameTAG: eumannu
CreateTimeTAG: 2013-02-21T22:41:31Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You should have received an email about the change in due dates. The due date on the Courseware page is correct.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T22:44:14Z
FirstChildVoteTAG: 0
SecondChildTAG: All good, thanks!
SecondChildUserIdTAG: 1181586
SecondChildUserNameTAG: eumannu
SecondChildCreateTimeTAG: 2013-02-22T02:44:23Z
SecondChildVoteTAG: 0
IndexTAG: 2816
TitleTAG: Can not "save" homework.
After I have completed the first set of problems and try to click on the "save" or "check" buttons they do not do anything. Is there a way to fix this?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-21T22:31:02Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I happen to try this as well and I found the same problem. I'm using IE 10 on Windows 8. I tried Firefox and that fixed it. Is this site cross-browser?
FirstChildUserIdTAG: 1281803
FirstChildUserNameTAG: mgarner
FirstChildCreateTimeTAG: 2013-02-21T22:34:42Z
FirstChildVoteTAG: 2
FirstChildTAG: I use google chrome and save works for me.
FirstChildUserIdTAG: 367736
FirstChildUserNameTAG: susihere
FirstChildCreateTimeTAG: 2013-02-22T00:08:35Z
FirstChildVoteTAG: 0
FirstChildTAG: Try Chrome if you are using Firefox, or Firefox if you are using Chrome.
Browsers seem to be a bit of a hit and miss affair. Some can use Firefox, others can't. At the moment I can't use Firefox for edX, but Chrome is fine. A couple of weeks ago it was the reverse.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T00:23:05Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you guys a ton! Google Chrome fixed the problem!
FirstChildUserIdTAG: 1136455
FirstChildUserNameTAG: Ethan1017
FirstChildCreateTimeTAG: 2013-02-22T01:46:18Z
FirstChildVoteTAG: 0
IndexTAG: 2817
TitleTAG: Google+ community
Hi guys,
Here is a Google+ group for support and additional material.
https://plus.google.com/communities/115902746625142429277
Best of luck!
UserIdTAG: 166082
UserNameTAG: Eb0la
CreateTimeTAG: 2013-02-21T21:41:21Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: hi,
from nigeria. we have very poor audio quality of the videos.
is it general. please comments from others
FirstChildUserIdTAG: 489811
FirstChildUserNameTAG: ifedolla
FirstChildCreateTimeTAG: 2013-02-21T22:35:26Z
FirstChildVoteTAG: 0
SecondChildTAG: No, audio is good for me
SecondChildUserIdTAG: 166082
SecondChildUserNameTAG: Eb0la
SecondChildCreateTimeTAG: 2013-02-21T23:48:55Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi,
Audio is good (in UK), maybe it is all about internet speed?
SecondChildUserIdTAG: 1141835
SecondChildUserNameTAG: TrissMerigold
SecondChildCreateTimeTAG: 2013-02-21T23:58:05Z
SecondChildVoteTAG: 0
IndexTAG: 2818
TitleTAG: Excellent lectures!
As a statisti-phobe, I want to say how much I appreciate Prof. Adhikari's animated (in the sense of delivery style) bite-size lectures. I also like how she is introducing equations slowly, because when I see a page of equations in an intro to statistics book, I have to look away. Thank you, Professor Adhikari!
UserIdTAG: 914245
UserNameTAG: dbaPlanB
CreateTimeTAG: 2013-02-21T21:40:14Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Couldn't agree more, well done
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-21T21:47:42Z
FirstChildVoteTAG: 0
SecondChildTAG: also agree - well presented and informative.
SecondChildUserIdTAG: 313672
SecondChildUserNameTAG: blinxnot
SecondChildCreateTimeTAG: 2013-02-22T05:43:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Where are lectures ?
FirstChildUserIdTAG: 1067676
FirstChildUserNameTAG: JohnKay
FirstChildCreateTimeTAG: 2013-02-21T22:18:03Z
FirstChildVoteTAG: 0
SecondChildTAG: Uh, courseware tab? I'm talking about the videos for the course -- slides and lectures.
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-02-21T23:09:37Z
SecondChildVoteTAG: 0
SecondChildTAG: What do you mean in the courseware tab? Only the intro lecture pops up when I click "Intro" ... even that does not say "Lec1.1" it just runs. Where are Lec1.2 and Lec1.3 etc.?
SecondChildUserIdTAG: 975799
SecondChildUserNameTAG: lmacareo
SecondChildCreateTimeTAG: 2013-02-23T02:43:21Z
SecondChildVoteTAG: 0
SecondChildTAG: OK, I can't answer this question. Perhaps search the discussions for problems navigating the Courseware tab for an answer? Sorry to be snide in my previous reply. Not helpful, I apologize.
In case this helps, in the Courseware tab, on the left, is a menu with "General Course Information" and "Week 1: [Dates]." When I click "Week 1" it expands to show the following -- each heading is a link to a page of either video/slide lectures or a page of more info:
Section 1: Introduction
Practice for Exercise Set 1
Exercise Set 1
graded exercises due February 27 23:30
Section 2a: The Histogram (Lec 2.1 - 2.3)
Practice for Exercise Set 2
Exercise Set 2
graded exercises due February 27 23:30
Section 2b: The Histogram (Lec 2.4 - 2.5)
Practice for Exercise Set 3
Exercise Set 3
graded exercises due February 27 23:30
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-02-23T05:10:16Z
SecondChildVoteTAG: 0
IndexTAG: 2819
TitleTAG: How can't we download the videos for Offline use?
I would love to be able to download the lecture videos to my hard-drive so that I can view them whenever and as many times as I would like after the course is over. However, there is no option for me to download the videos. Is there a reason for this or the staffs just forgot to include the option?
Thank you.
UserIdTAG: 861599
UserNameTAG: Nam2point0
CreateTimeTAG: 2013-02-21T21:36:20Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: I wondered the same thing as I have an issue with my internet connection. However, I noticed the videos are hosted on YouTube and used a free software called iLivid to download the videos from YouTube using the url of the video.
I must remind anyone who uses the above method to download the videos that if they are copyrighted it would be an infringement to recirculate them after doing so.
FirstChildUserIdTAG: 1103741
FirstChildUserNameTAG: TaniaD
FirstChildCreateTimeTAG: 2013-02-21T21:49:52Z
FirstChildVoteTAG: 1
SecondChildTAG: Thanks Tania, but do I have to download iLivid first? Could you help me with the process?
As for the copyright, the reasons I want to download the videos are for my personal use and to use them as reference to teach my children when I am able and willing to have kids - just so that they can have a head start. Something I didn't have:)
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-02-21T23:38:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Tania, you don't have to response to my request as I have already done so. Thank you so much:)
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-02-21T23:45:08Z
SecondChildVoteTAG: 0
FirstChildTAG: Downloading would be excellent, I using my iPad to view this course and although its only started I'm impressed with what I have seen to date
FirstChildUserIdTAG: 895245
FirstChildUserNameTAG: Ezegoing
FirstChildCreateTimeTAG: 2013-02-21T22:12:50Z
FirstChildVoteTAG: 0
FirstChildTAG: Request seconded. I'd love to watch these videos at the gym on my Android phone, and I don't think I can install YouTube download software to Android.
A direct download link next to/under each video would be awesome!
FirstChildUserIdTAG: 214952
FirstChildUserNameTAG: soyossif
FirstChildCreateTimeTAG: 2013-02-22T00:24:53Z
FirstChildVoteTAG: 0
SecondChildTAG: You can follow Tania advice and download iLivid onto your computer and use it to download the videos via YouTube. Once you have the videos onto your hard drive, you can then put the videos to your Android or whatever mobile devices you have that can play videos.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-02-22T01:08:48Z
SecondChildVoteTAG: 0
FirstChildTAG: I am not sure if this helps anyone but I have found a link on Youtube called
http://www.youtube.com/watch?v=4AZ8G_MqyiM&list=PLFAD0C5745D4A1F60
It is called ExcelisFun where you can learn how to do Statistics using Excel. You can learn Excel as well as Statistics. It will be a great compliment to this course because here we learn the concepts. The videos on YouTube show us how to perform data analysis using Excel.
Also if anyone of us had or have been taking Introduction to Computer Science and Programming would know that we can use Python for Data Analysis. It is actually much more powerful and better than Excel once you know how to use Python. I still don't know how to program in Python yet although I took the course. My goal then was to download the videos for self learning. Now I am starting to view the videos and try to combine that with Excel Statistics and this course.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-22T00:29:53Z
FirstChildVoteTAG: 0
SecondChildTAG: Use a program to download YouTube videos. I should say upload... In any case, save them as MP4 in your hard drive.
Right click on the video posted as a lesson and copy the link. All you have to do is paste the link to the upload software.
SecondChildUserIdTAG: 206086
SecondChildUserNameTAG: pedrocas1972
SecondChildCreateTimeTAG: 2013-02-22T01:05:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Pedro.
SecondChildUserIdTAG: 861599
SecondChildUserNameTAG: Nam2point0
SecondChildCreateTimeTAG: 2013-02-22T18:55:37Z
SecondChildVoteTAG: 0
FirstChildTAG: On my FireFox 19.0, I have the "Flash Video Downloader Youtube Downloader 3.8.2" add-on installed.
With this I have had no problems with saving the video from the lectures.
FirstChildUserIdTAG: 151933
FirstChildUserNameTAG: WildW1ill
FirstChildCreateTimeTAG: 2013-02-28T16:35:49Z
FirstChildVoteTAG: 1
IndexTAG: 2820
TitleTAG: Exercise Mistakes
Quite a few have found mistakes in the exercise set. These have been noted - many many times - and reported.
Please see this post from Prof A regarding issues and fixes in the pipeline.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5125bb66e072011f0000013e
Also remember to check the errata page:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
UserIdTAG: 629320
UserNameTAG: SusanAust
CreateTimeTAG: 2013-02-21T21:26:25Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2821
TitleTAG: Why income is a not a "quantitative discrete" variable?
1. In one of the lectures/videos it is mentioned that quantitative discrete variables don't have to be a whole number - it can be e.g. 1.5.
2. Quote: "There is no minimum spacing between the possible values of a continuous variable"
[SticiGui][1]
Since quantitative discrete variables don't have to be a whole number but there has to be a minimum spacing income seems to be a very good example of this type. You can't go "below" one cent/pence/etc... this is your minimum spacing.
[1]: http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#variables
UserIdTAG: 191555
UserNameTAG: IanRad
CreateTimeTAG: 2013-02-21T21:26:08Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: I think, "cent, pence, etc." may represent different small portions of a continuous value. I mean, you just only can't measure income with exact accuracy with that "cent, pence, etc." values. Or you may say; you can only represent it with nearest discrete value, but it is continuous in its nature(?).
This is my trial. I need an answer for your question too.
FirstChildUserIdTAG: 1080753
FirstChildUserNameTAG: HakanY
FirstChildCreateTimeTAG: 2013-02-21T21:45:07Z
FirstChildVoteTAG: 1
FirstChildTAG: I had the same thought. To me, income is discrete. There are only so many amounts of money I can get paid as income. Note, this did *not* say currency or money, the item in question was income. As far as I know, I can only be paid by the penny and not in fractions of a penny. Maybe that is different in other countries, but in the US, you can only write checks and interact with your bank at the penny increment. Therefore I think income is discrete.
FirstChildUserIdTAG: 1281803
FirstChildUserNameTAG: mgarner
FirstChildCreateTimeTAG: 2013-02-21T22:40:33Z
FirstChildVoteTAG: 0
FirstChildTAG: I had the wrong answer because I also picked quantitative discrete as my answer. My reasoning was the same as you. When I saw the result and ask myself why did I get it wrong, I started to remember that in finance, especially with the stock price, option prices, or bond prices etc, the prices can be 1/10, 1/20, 2/10... of a penny or pence or whatever the currencies are.
Since the question doesn't state where we should stop, I guess it's continuous. Unlike the question about the points score 5 for correct and 0 for incorrect. That question tells us that it is discrete because it is either 5 or 0. There can not be anything in between. With regards to income, it is depending on who is running the experiment. You can be as precise as you like. So we have a choice of making a discrete into a continuous and vice versa.
Not sure this will help. It might confuse you further. If so, I apologize.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-22T00:40:59Z
FirstChildVoteTAG: 0
FirstChildTAG: I also thought this didn't make sense. How is income *not* quantitative discrete?
FirstChildUserIdTAG: 224280
FirstChildUserNameTAG: Ryusui
FirstChildCreateTimeTAG: 2013-02-22T00:46:47Z
FirstChildVoteTAG: 0
FirstChildTAG: Take exactly one dollar and divide it among 3 persons. You will get 0.333333(3) cents but you will have to discretize this amount to the nearest cent.
FirstChildUserIdTAG: 252722
FirstChildUserNameTAG: vaboro
FirstChildCreateTimeTAG: 2013-02-22T00:50:35Z
FirstChildVoteTAG: 0
FirstChildTAG: > Blockquote
Since quantitative discrete variables don't have to be a whole number but there has to be a minimum spacing income seems to be a very good example of this type. You can't go "below" one cent/pence/etc... this is your minimum spacing.
Well, you can go below. Let's say one day someone comes up with the great idea of having a new subunit which represents 1/1000 of a pound / dollar / etc. Would it make sense? Yes, afterwards, it is conceptually equivalent to meters / centimeters / millimeters. You can't claim that length is a continues discrete because you have only millimeters on your scale.
On the other hand, you can not do the same with, lets say, pages of abook - does not make sense to subdivide it into smaller units, does it?
FirstChildUserIdTAG: 314594
FirstChildUserNameTAG: Mzvd
FirstChildCreateTimeTAG: 2013-02-22T10:18:39Z
FirstChildVoteTAG: 0
IndexTAG: 2822
TitleTAG: Income as a quantitative variable
In a certain perspective, it could be recognized income as a quantitative variable. However, we could ask, for example, what is the scale to measure income, and how many divisions can we do for this variable?.
How many numbers can we truly (physically)write after decimal point.
Can we consider this variable as a quantitative discrete variable.
I think, yes, we can do it.
UserIdTAG: 1007639
UserNameTAG: leomesh
CreateTimeTAG: 2013-02-21T21:19:36Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The answer to this would depend on how the answers are represented. Income could be also expressed as qualitative in some cases (eg "Poor" "Middleclass" etc).
Keep in mind that ANY quantitative variable is discreet if you follow it to enough decimals - but it is not the PRACTICE of writing decimals that makes it discreet - its the rigid data that goes in which makes it discreet. (eg 2,3,4 VS 2.3456938679, 2.405828)
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:25:42Z
FirstChildVoteTAG: 0
SecondChildTAG: I think it is quantitative discrete, since there is a minimum spacing between the numbers i.e. every country has a minimum currency amount, Eg. 1 cent. Hence, anything that has to be priced more than 1 Cent has to be 2 Cents, since there is no currency available in between 1 and 2. Which again means there is a minimum spacing, in this case '1' is the minimum spacing between 1 and 2 Cents or between 2 and 3 Cents.
SecondChildUserIdTAG: 1117098
SecondChildUserNameTAG: yash286
SecondChildCreateTimeTAG: 2013-02-21T22:32:08Z
SecondChildVoteTAG: 0
SecondChildTAG: I agree with yash286. I know that shares can be income and that share price can be a dollar value with more than 2 decimal places, but when it arrives in my bank a/c, it'll be in dollars and cents. So income has to be quantitive discreet doesn't it?
SecondChildUserIdTAG: 1088010
SecondChildUserNameTAG: russep3
SecondChildCreateTimeTAG: 2013-02-22T00:54:05Z
SecondChildVoteTAG: 0
IndexTAG: 2823
TitleTAG: plug-in
Hi,
I'm very new to online courses. I hope this is the correct way to get help. I cannot watch the video because it indicated that I do not have a plug-in. I checked system preferences for any updates and found none. How do I find the missing plug-in?
Thanks
UserIdTAG: 251147
UserNameTAG: sciguy
CreateTimeTAG: 2013-02-21T21:18:37Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The plug in is the same one used for most YouTube videos - Adobe Flash. You can get it by visiting http://get.adobe.com/flashplayer/
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:22:49Z
FirstChildVoteTAG: 0
IndexTAG: 2824
TitleTAG: Love the overall design
Thank you for teaching this class, so far it's actually fun. I'm taking another EdX course which is a video of the professor lecturing. She's super fun to watch and listen to (as I bet you are) BUT the slides are only shown as a video of what's projected and sometimes the camera is not even on the slide when she uses the pointer. I like how your course sits on the slide and that it is easy to follow along with the pointer as you speak. It's also less distracting to not be viewing a person. Lively people are hard to keep from watching! Thanks a million (or at least 47,000!)
UserIdTAG: 1097545
UserNameTAG: TWheeler
CreateTimeTAG: 2013-02-21T21:17:29Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Yes, I like Ms Duflo as well :), but this is sooo much easier to follow. Only thing I would add is downloadable slides in pdf.
FirstChildUserIdTAG: 162039
FirstChildUserNameTAG: ghromis
FirstChildCreateTimeTAG: 2013-02-21T21:21:49Z
FirstChildVoteTAG: 0
SecondChildTAG: I've been pausing the video and using the "Prnt Scrn" key to take screen shots of slides, then pasting those in a Word document (on a PC). I'm taking notes in the Word doc as well as on paper.
SecondChildUserIdTAG: 914245
SecondChildUserNameTAG: dbaPlanB
SecondChildCreateTimeTAG: 2013-02-21T21:43:59Z
SecondChildVoteTAG: 0
FirstChildTAG: I agree. My only feedback is that it might be beneficial to offer the 1.25x and 1.5x videos with re-sampled audio, rather than compressed. The lecture audio is easier to understand at different speeds, but also more difficult to understand without being re-sampled.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:21:57Z
FirstChildVoteTAG: 0
FirstChildTAG: Downloadable slides and video will be up by tomorrow (Fri) Berkeley time.
Thanks for the kind words. I want to make this course both enjoyable and informative for students, and it helps me to know what you like - typically I hear about what's broken!
I'll pass on the request about resampled audio. I know EdX is working to improve that aspect of our course.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-22T00:11:43Z
FirstChildVoteTAG: 0
SecondChildTAG: We do appreciate your efforts and while we may be "cribbing" it is of course with the idea that this "IS" the best course for the same :)
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T13:58:50Z
SecondChildVoteTAG: 0
IndexTAG: 2825
TitleTAG: Exercise Set 1, Problem 2b
Can anyone please tell me what the correct answer to this is?
UserIdTAG: 1237295
UserNameTAG: tanushree31
CreateTimeTAG: 2013-02-21T20:59:44Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Not now as that would violate the honor code.
After the deadline we can discuss if you haven't found it by then.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T21:15:10Z
FirstChildVoteTAG: 0
SecondChildTAG: I totally did not realise this...I think I gave the write anser but was marked wrong..and do not know what the correct answer is...
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-22T08:02:42Z
SecondChildVoteTAG: 0
SecondChildTAG: right*
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-22T13:00:57Z
SecondChildVoteTAG: 0
FirstChildTAG: I can't give you the answer but I will try to help you figure it out. The question is as follow.
Problem 2
In a genetic experiment, plants are classified as magenta/green, magenta/red, red/green, and red/red, and appear in the proportions 9:3:3:1.
1) Step one is to know what 9:3:3:1 is. It is the proportion or percentage. You can go back to the video lecture and review if you don't know.
Anyway, you first have to add those values 9:3:3:1 = 9 + 3 + 3 + 1 = 16. So basically you can rewrite 9:3:3:1 as
9/16 ; 3/16; 3/16; and 1/16.
Now you can answer the questions in Problem 2. Hope this helps.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-21T21:32:31Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks for your reply. I probably should have worded my question correctly. I have submitted my assignment and was marked wrong for it but do not know what the correct answer is? I came to the answer in exactly the same way as you have mentioned here...but feel that there is some problem...
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-22T07:59:42Z
SecondChildVoteTAG: 0
SecondChildTAG: I missed this one first time as well, but noticed this tiny thing on the instruction that reads:
*Select all that are correct.*
Quite tricky...
SecondChildUserIdTAG: 329709
SecondChildUserNameTAG: January
SecondChildCreateTimeTAG: 2013-02-22T11:18:11Z
SecondChildVoteTAG: 0
SecondChildTAG: Precisely...I took that into account as well...still don't know what went wrong!
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-22T12:20:58Z
SecondChildVoteTAG: 0
SecondChildTAG: The answer/s are pretty obvious...and I just cannot understand what actually went wrong..
SecondChildUserIdTAG: 1237295
SecondChildUserNameTAG: tanushree31
SecondChildCreateTimeTAG: 2013-02-22T12:21:56Z
SecondChildVoteTAG: 0
IndexTAG: 2826
TitleTAG: Possible error in Practice for Exercise 2
In the answer of "Lecture 2.2 and 2.3" exercise I assumed that the width of the interval was 30 and not 10. Why is 10 and not 30? ![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13614801141343621.png
UserIdTAG: 465745
UserNameTAG: OdiseoPY
CreateTimeTAG: 2013-02-21T20:59:27Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I agree. It's 20-(-10) = 20 + 10 = 30. This is Width. Not 20-10 = 10.
My R code:
y = c( -152, -132, ... , 150, 155);
len=length(y[(y>=-10)&(y<=20)]);
h=20-(-10);
hight=len/h;
hight=0.46;
FirstChildUserIdTAG: 1170861
FirstChildUserNameTAG: jj_1983
FirstChildCreateTimeTAG: 2013-02-21T21:16:58Z
FirstChildVoteTAG: 0
FirstChildTAG: See the errata page.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T21:29:44Z
FirstChildVoteTAG: 2
IndexTAG: 2827
TitleTAG: Practice Set 1 - Data Validation Issue
I included % in my answers for questions A and C which made them incorrect. Deleting the % symbol made them correct. Perhaps the software marking these things should account for removing the % when validating the answer? I only mention this because it may have implications on the marked sets and cause people problems.
UserIdTAG: 909166
UserNameTAG: KeithJordan
CreateTimeTAG: 2013-02-21T20:59:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Typically the way this is handled by making it more obvious when units are included. I had a problem with one question involving the units being "in thousands" and I put an answer of 27888.etc instead of simply 2.7. If the course material is saved and re-used for the second offering I'm sure it would be easy to add.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:12:15Z
FirstChildVoteTAG: 0
FirstChildTAG: I had the same issue with the practice Exercise Set 1 as well. I had the right answer but included the percent sign and didn't round to the correct decimal position. However, in the actual Exercise Set, it did provide instruction for not including the number sign and to round to the nearest hundredth or thousandth (can't remember which it was).
FirstChildUserIdTAG: 895319
FirstChildUserNameTAG: katedahl
FirstChildCreateTimeTAG: 2013-02-21T23:10:13Z
FirstChildVoteTAG: 0
IndexTAG: 2828
TitleTAG: Typo in Exercise Set 1: "Catagorical"
Problem 1, part c says that ethnicity is catagorical, rather than categorical.
UserIdTAG: 164614
UserNameTAG: LuketheEngineer
CreateTimeTAG: 2013-02-21T20:56:51Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2829
TitleTAG: For a TA or Teacher - question on practice set 2
Trying to do this without spoiling the question: you say "height of the -10 to 20 bar is 14/10" but doesn't -10 minus 20 = 30?
UserIdTAG: 1097545
UserNameTAG: TWheeler
CreateTimeTAG: 2013-02-21T20:56:24Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Please see the errata page:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T21:27:43Z
FirstChildVoteTAG: 1
SecondChildTAG: the math should appear as such 14/-10-(20). The problem that I have is that the 20 inside the parentesis should be negative otherwise the math does not work
SecondChildUserIdTAG: 1132017
SecondChildUserNameTAG: SherryJo
SecondChildCreateTimeTAG: 2013-02-21T23:05:08Z
SecondChildVoteTAG: 0
IndexTAG: 2830
TitleTAG: Late updates
I received the message about the change in the due date for the first part of the course. I hurried to get it done and in so doing I answered some questions wrong. I would like to know if I can get a chance to re-submit my answers because I had already finished the exam before I saw the message about the change in the due date. :(
UserIdTAG: 602270
UserNameTAG: molandra_clarke
CreateTimeTAG: 2013-02-21T20:53:51Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2831
TitleTAG: videos are not playing
I cant play lecture videos, I have tried Mozilla Firefox and Google chrome so I need help!
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-21T20:45:52Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Me too. I can't find the videos to even try to play them.
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-02-21T20:48:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Same Problem. There's neither a download link nor a video playback option.
FirstChildUserIdTAG: 31529
FirstChildUserNameTAG: abbass
FirstChildCreateTimeTAG: 2013-02-21T20:53:57Z
FirstChildVoteTAG: 0
SecondChildTAG: I had this problem in 6.002x last year. Clearing my cookies helped.
SecondChildUserIdTAG: 40598
SecondChildUserNameTAG: jstarkey
SecondChildCreateTimeTAG: 2013-02-21T21:13:26Z
SecondChildVoteTAG: 0
FirstChildTAG: Do you have Adobe Flash installed?
FirstChildUserIdTAG: 956316
FirstChildUserNameTAG: MSSmith
FirstChildCreateTimeTAG: 2013-02-21T20:59:13Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, still not playing
SecondChildUserIdTAG: 122562
SecondChildUserNameTAG: rzaghum
SecondChildCreateTimeTAG: 2013-02-21T21:01:46Z
SecondChildVoteTAG: 0
SecondChildTAG: reinstalled Flash but still no evidence of videos - except mentions in the Discussion area and the audio file saying "you've seen the introductory video" so it must exist!
SecondChildUserIdTAG: 41340
SecondChildUserNameTAG: FPike
SecondChildCreateTimeTAG: 2013-02-21T21:07:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Do you think we can complete the course without watching any videos? If we can't I'll have to withdraw.
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-02-21T21:08:20Z
FirstChildVoteTAG: 0
FirstChildTAG: I had this problem in 6.002x last year. Clearing my cookies and browser cache helped.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:13:44Z
FirstChildVoteTAG: 0
IndexTAG: 2832
TitleTAG: Another error, this time at Excercise Set 2
At Problem 1, a): There are more people in the interval 5-15, it has the 13.3% of the people. The 15-20 has only the 7.1%, and they are giving the second option as correct.
UserIdTAG: 797704
UserNameTAG: Hersan13
CreateTimeTAG: 2013-02-21T20:42:42Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I agree with you
FirstChildUserIdTAG: 422336
FirstChildUserNameTAG: lilian2012
FirstChildCreateTimeTAG: 2013-02-21T20:44:40Z
FirstChildVoteTAG: 0
FirstChildTAG: Please use the SEARCH function before posting. This issue has already been discussed many times.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T20:44:54Z
FirstChildVoteTAG: 2
FirstChildTAG: You haven't taken account of the density of the histogram.
FirstChildUserIdTAG: 909166
FirstChildUserNameTAG: KeithJordan
FirstChildCreateTimeTAG: 2013-02-21T22:35:38Z
FirstChildVoteTAG: 0
SecondChildTAG: It doesn't have anything to do with it. The density is about how crowded is that area, still there are more people in the interval 5-15, no matter that is more crowded the interval 15-20.
SecondChildUserIdTAG: 797704
SecondChildUserNameTAG: Hersan13
SecondChildCreateTimeTAG: 2013-02-22T01:38:52Z
SecondChildVoteTAG: 0
IndexTAG: 2833
TitleTAG: ES11 ES12
I scored 60% in Exercise set 1. and now on ES11 and ES12 there are two cross X X and it says that the lowest 2 graded exercises scores are dropped.
UserIdTAG: 1191859
UserNameTAG: sidkapure
CreateTimeTAG: 2013-02-21T20:33:00Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Yes, that's because according to the progress list you scored 0% on ES11 and ES12 even though you haven't finished those yet. And since the 0% score is lower than the 60% you scored on ES1 they drop ES11 and ES12.
FirstChildUserIdTAG: 1212168
FirstChildUserNameTAG: nickyvs
FirstChildCreateTimeTAG: 2013-02-21T20:41:49Z
FirstChildVoteTAG: 0
FirstChildTAG: the x will remain on those two assessment items until you actually do one of them. This is because they are currently the two lowest scores. If you score better on one of them than a previous assessment, the x will move.
For instance, this is from another course where the lowest 3 marks were dropped. The x marks the lowest 3. If you scored 100% for all the assessments, the x marks would remain on the last 2.
![enter image description here][1]
[1]: https://edxuploads.s3.amazonaws.com/13614807491343682.png
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T21:03:52Z
FirstChildVoteTAG: 2
SecondChildTAG: Congrats!
SecondChildUserIdTAG: 346428
SecondChildUserNameTAG: aranic
SecondChildCreateTimeTAG: 2013-02-22T04:31:15Z
SecondChildVoteTAG: 0
IndexTAG: 2834
TitleTAG: Suggestion about Subtitles
Thanks for the effort to build this course!
I just want to raise the issue of Subtitles. Is there any option for us to put it back to its traditional position, which is horizontally at the bottom of the screen?
The content on the far right side is often hidden by the subtitles.
Also, the way the eyes work is that both eyes look in the same direction. It's hard to divide the focus between the right side (subtitle) and the left side (content).
Hope we can have this flexibility in future courses.
UserIdTAG: 905675
UserNameTAG: TrucHawaii
CreateTimeTAG: 2013-02-21T20:32:57Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I think this very important too, can you please put an option to put it at rigth side or bottom, thanks!!!
FirstChildUserIdTAG: 983293
FirstChildUserNameTAG: jaerazo
FirstChildCreateTimeTAG: 2013-02-21T20:53:56Z
FirstChildVoteTAG: 0
FirstChildTAG: I think this would be good feedback for the software developers. In my browser I don't have any issues with the captions "covering" anything. Perhaps you could let us know what OS and browser(with version) you are using?
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:15:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Go to full screen on the video and you'll should what they are talking about. The captions run along the right side of the screen, over the video.
SecondChildUserIdTAG: 142402
SecondChildUserNameTAG: aaronrod
SecondChildCreateTimeTAG: 2013-02-21T22:08:06Z
SecondChildVoteTAG: 0
FirstChildTAG: If you click on the YouTube icon on the lower right of the video, it will open the video on the YouTube page. From there, if you turn the captions on, they will run across the bottom of the screen.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-21T22:09:19Z
FirstChildVoteTAG: 0
IndexTAG: 2835
TitleTAG: Due date time - Greenwich Mean Time (GMT)?
Hi, I want to make sure I understand the due date time. I read online that the time is in Greenwich Mean Time (GMT). So, to confirm, if the due date time on the schedule says 23:30, this means that the assignment is due 6:30 p.m., Eastern Standard Time (EST)? Thanks so much. And thank you very much for adjusting the schedule for assignment deadlines and offering this course.
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-21T20:27:21Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: That's correct. As For an easy way to figure out time zone changes, check out this page: http://www.timeanddate.com/worldclock/meeting.html
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-21T22:11:29Z
FirstChildVoteTAG: 0
FirstChildTAG: I live in India, which is +530 than GMT. So if the due date time is 27th February 23.30 it means i can submit my work till 28th February, 0500 hrs.. is that correct ?
FirstChildUserIdTAG: 379141
FirstChildUserNameTAG: NitishRaole
FirstChildCreateTimeTAG: 2013-02-27T17:37:56Z
FirstChildVoteTAG: 1
IndexTAG: 2836
TitleTAG: Are there Course Notes?
I can't find any. Do you have the Course Notes available with the videos?
I'm new here, so still exploring the platform.
UserIdTAG: 905675
UserNameTAG: TrucHawaii
CreateTimeTAG: 2013-02-21T20:21:16Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Course notes are available in the Wiki, which can be accessed at the top of the page. https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:16:16Z
FirstChildVoteTAG: 0
IndexTAG: 2837
TitleTAG: To the staff-Videos for offline use
I'd like to know will the videos available for offline like the other courses?
UserIdTAG: 87907
UserNameTAG: helectra
CreateTimeTAG: 2013-02-21T20:19:44Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I'd love to know where the videos to view are to be found. I've tried using Firefox and Chrome and there is no link to videos which I can see.
The audio file says "you've seen the video" but I haven't! Are the links supposed to be on the righthand side of the screen?
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-02-21T20:29:48Z
FirstChildVoteTAG: 0
FirstChildTAG: I think this is very important beacuse some times we can have problems with our internet connection, even if you have a slow connection you can get download the videos at night and read it all day long. If there is some problem with the CC, you can create a Software that you only can open the videos with it, this to avoid copies.
FirstChildUserIdTAG: 983293
FirstChildUserNameTAG: jaerazo
FirstChildCreateTimeTAG: 2013-02-21T20:57:54Z
FirstChildVoteTAG: 0
FirstChildTAG: Thanks 10^6, but I think it would have cost less if you have torrented them.
FirstChildUserIdTAG: 87907
FirstChildUserNameTAG: helectra
FirstChildCreateTimeTAG: 2013-02-22T18:27:16Z
FirstChildVoteTAG: 0
IndexTAG: 2838
TitleTAG: Error at the "READING AND PRACTICE FOR EXERCISE SET 2" section
In the part corresponding to the Lectures 2.2 and 2.3, at the a), the answer they give as correct is actually wrong, because of a procedure error while calculating the interval width. The regarding interval is -10 to 20, so the interval width is 20-(-10)=20+10=30, not 10 as they say. Therefore, the height of the corresponding bin must be 14/30=.47% approximately.
UserIdTAG: 797704
UserNameTAG: Hersan13
CreateTimeTAG: 2013-02-21T20:01:21Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2839
TitleTAG: Forms of input
Hello! I had found a video explaining everything about the forms of input in the exercises, but now i can't find it. Could anyone please help me?
UserIdTAG: 1094545
UserNameTAG: Lacilia
CreateTimeTAG: 2013-02-21T19:59:41Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2840
TitleTAG: Please respect the HONOR CODE
Fellow students, I understand your frustration with some of the grader errors, however please:
1. Use the search function before posting your question, to minimize multiple postings on the same issue.
2. Remember the honor code for graded tests. We are NOT supposed to discuss them while giving out potential answers until after the deadline has elapsed.
Yes, we are all eager to learn and ensure that our understanding on the subject is correct, but please remember the rules set by the staff, professors and edX.
Thank you.
UserIdTAG: 170290
UserNameTAG: jimbangun
CreateTimeTAG: 2013-02-21T19:51:24Z
VoteTAG: 63
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Excellent point. The purpose of this course is learning, not hassling staff who've made content available for free.
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T21:17:11Z
FirstChildVoteTAG: 21
FirstChildTAG: Additionally, an error in a problem can be pointed out by just stating which problem it is and not discussing which answer is wrong and which should be correct. The staff are smart enough to figure out if there really is a problem.
FirstChildUserIdTAG: 878440
FirstChildUserNameTAG: rosewoodbay
FirstChildCreateTimeTAG: 2013-02-22T00:41:46Z
FirstChildVoteTAG: 5
FirstChildTAG: Oops, sorry! .... I goofed!!! Forgot the Honor Code in my discussion of the grader issues by discussing the answer - Sorry!
You are doing a great job, Profs A & S ... managing 47,000 students - Keep up the good work!!
FirstChildUserIdTAG: 1129036
FirstChildUserNameTAG: Dileepk
FirstChildCreateTimeTAG: 2013-02-22T15:48:33Z
FirstChildVoteTAG: 2
IndexTAG: 2841
TitleTAG: Dominican Republic
Hi! I'm from the Dominican Republic! Good luck to everyone!!
UserIdTAG: 1279129
UserNameTAG: AnserCabrera
CreateTimeTAG: 2013-02-21T19:42:20Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Welcome!
FirstChildUserIdTAG: 1268175
FirstChildUserNameTAG: MarquisDeMizzle
FirstChildCreateTimeTAG: 2013-02-21T19:47:36Z
FirstChildVoteTAG: 0
IndexTAG: 2842
TitleTAG: Closed Captions (SRT file)
I can get subtitle/captions while viewing lectures online. If I download the lecture to view offline, I lose the captioning. I can get by using the transcript but it would be nice to have the lecture captions available. Is it possible to get the SRT files for the lectures so that I can have the captions show up on my media player?
UserIdTAG: 441413
UserNameTAG: coyotecoach
CreateTimeTAG: 2013-02-21T19:38:21Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: What are SRT files ?.I do wish the transcript of the lecture is also posted as files so that we can read it when we are offline or having spotty internet access.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-21T19:54:22Z
FirstChildVoteTAG: 0
SecondChildTAG: SRT is the subtitle file that can be viewed together with the videos.
I'm having the same question. English is not my 1st language and it's hard to hear everything.
SecondChildUserIdTAG: 905675
SecondChildUserNameTAG: TrucHawaii
SecondChildCreateTimeTAG: 2013-02-21T20:17:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Try this tiny software:
[http://google2srt.sourceforge.net/en/][1]
[1]: http://google2srt.sourceforge.net/en/
FirstChildUserIdTAG: 34618
FirstChildUserNameTAG: scriba
FirstChildCreateTimeTAG: 2013-02-22T16:23:45Z
FirstChildVoteTAG: 0
FirstChildTAG: I have converted the youtube subtitles into srt format. You can use it offline with your favorite media player now.
[week1][1]
Check the wiki page for updates during the upcoming weeks.
[1]: https://www.dropbox.com/sh/h7hs61wr71qd2nl/3u21Eh3kHj/week1.zip
FirstChildUserIdTAG: 34618
FirstChildUserNameTAG: scriba
FirstChildCreateTimeTAG: 2013-02-24T18:39:09Z
FirstChildVoteTAG: 0
SecondChildTAG: I am using my android and downloaded the dropbox app to view these files. However I can't view this zip files on my android. I am new this. Can someone recommend an app for this?
SecondChildUserIdTAG: 4612
SecondChildUserNameTAG: Susnaj
SecondChildCreateTimeTAG: 2013-02-25T15:27:24Z
SecondChildVoteTAG: 0
SecondChildTAG: Susnaj, you can use Winzip on Android, too. Androzip is an other option.
SecondChildUserIdTAG: 34618
SecondChildUserNameTAG: scriba
SecondChildCreateTimeTAG: 2013-02-25T16:54:32Z
SecondChildVoteTAG: 0
FirstChildTAG: SRT FILES SHOULD BE HERE: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/subtitle-files/
FirstChildUserIdTAG: 1039699
FirstChildUserNameTAG: VickyO
FirstChildCreateTimeTAG: 2013-02-27T20:15:23Z
FirstChildVoteTAG: 1
IndexTAG: 2843
TitleTAG: Greeting from Indianapolis, IN
My introduction is a bit delayed; my apologies. This course seems rigorous, which is exciting! Good luck to all.
Best,
Meredith
UserIdTAG: 931416
UserNameTAG: mlollier
CreateTimeTAG: 2013-02-21T19:35:25Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: good luck.
FirstChildUserIdTAG: 1113869
FirstChildUserNameTAG: djr270
FirstChildCreateTimeTAG: 2013-02-22T00:32:23Z
FirstChildVoteTAG: 0
IndexTAG: 2844
TitleTAG: exercise-1 due date
the due date for submission of exercise set 1 is different on course schedule vs course-ware tab. As per course schedule due date for exercise 1 is 22 feb whereas courseware tab says 27 feb. which one to follow??
UserIdTAG: 1195486
UserNameTAG: Abhipuri
CreateTimeTAG: 2013-02-21T19:34:57Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Just received email to say it is 27 February. Future deadlines will also be on Wednesdays.
FirstChildUserIdTAG: 41340
FirstChildUserNameTAG: FPike
FirstChildCreateTimeTAG: 2013-02-21T20:31:03Z
FirstChildVoteTAG: 1
IndexTAG: 2845
TitleTAG: Exercise 2, Problem 1a
Hello,
I have a question concerning the exercise 1a. When you ask "Which interval contained more people". You should answer based in the amount of people, right?
The 1st category have 13.3% against 7.1%, of the 2nd, the amount of individuals in each category is not going to be considered in the question: Which interval CONTAINED more people", or should it be considered?
Thank you for now.
UserIdTAG: 1250606
UserNameTAG: kauemw
CreateTimeTAG: 2013-02-21T19:32:24Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I didn't get the right answer for this one either and I don't understand why 13.3% is less than 7.1% of a given population. We are not talking about density, just total amount. And lo and behold, 7.1% > 13.3%? Either I shouldn't take this course or I should go back to my elementary school study.
FirstChildUserIdTAG: 733902
FirstChildUserNameTAG: Trabing
FirstChildCreateTimeTAG: 2013-02-21T19:45:41Z
FirstChildVoteTAG: 0
SecondChildTAG: it has been already clarified in a previous post and the correct answer indeed is 13.3% so this will be corrected.I hope we get the credit for the answer shortly.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-21T19:52:35Z
SecondChildVoteTAG: 0
SecondChildTAG: See the professor's explanation in this thread: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T19:54:46Z
SecondChildVoteTAG: 0
FirstChildTAG: Please respect the honor code.
However, if you search the discussion forum you will find that this subject has already been discussed several times even with a response from the professor.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T19:54:23Z
FirstChildVoteTAG: 0
IndexTAG: 2846
TitleTAG: Exercise Set 1 - Problem 1
talking about variables there are many ambiguous questions that someone can put about variables.
For example if I ask for expense
It can be quantitative discrete (if the contexts is talking about thousands)
It can also be quantitative continuous (if the contexts is talking about exact number including cents)
Also it can be categorical (but only in the context we are talking about low medium and high)
So there were some some variables where the context was not described.
In that case I thing any response described above can be correct given the corresponding explanation.
I'd like to know if I have a bad appreciation about the possible answers.
UserIdTAG: 923436
UserNameTAG: edsonterceros
CreateTimeTAG: 2013-02-21T19:27:35Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Actually, income (or expense) IS discrete, especially when you're talking about cents. All possible incomes are separated by a certain number of cents. There are no fractional cents, which means values can only increase or decrease by a hole number of cents. If you look at it like dollar is the base unit, it still is discrete, since it can increase or decrease only by a certain number of 1/100s of a dollar at a time. In the lecture, we're told that something that increases by 1/2 at a time is discrete (which it is).
I agree with what you're saying about context missing for this problem, but I disagree that income is continous.
FirstChildUserIdTAG: 83185
FirstChildUserNameTAG: oysteingrondahl
FirstChildCreateTimeTAG: 2013-02-21T20:04:27Z
FirstChildVoteTAG: 1
SecondChildTAG: **At first** I thought that income could be: high, low..., in that case, it would be qualitative. I did´t take as quantitative because the unit wasn´t given (in dollars, euros...)
NOTE: sorry for my english, but I am learning it.
SecondChildUserIdTAG: 1002821
SecondChildUserNameTAG: Urimare
SecondChildCreateTimeTAG: 2013-02-21T20:32:39Z
SecondChildVoteTAG: 0
SecondChildTAG: So we are agree that a good answer could be: quantitative discrete
I answer quantitative discrete in the Exercise
the correction marks categorical
Are you agree with that for a inverse concept of expense concept?
That why I feel disappointed
SecondChildUserIdTAG: 923436
SecondChildUserNameTAG: edsonterceros
SecondChildCreateTimeTAG: 2013-02-21T20:40:36Z
SecondChildVoteTAG: 0
SecondChildTAG: I think I confuse the correct result interpretation
because I though the correct answer is the one besides the X mark.
Even though the response should be correct don't you?
SecondChildUserIdTAG: 923436
SecondChildUserNameTAG: edsonterceros
SecondChildCreateTimeTAG: 2013-02-21T20:48:58Z
SecondChildVoteTAG: 0
FirstChildTAG: Please respect the honor code and refrain from discussing the answers until after the deadline. Thank you.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T21:03:20Z
FirstChildVoteTAG: 0
IndexTAG: 2847
TitleTAG: End point convention clarification
I was previously taught that class intervals should never overlap when constucting any chart or frequency table .So in essence we should have groups of say 0-9,10-19 etc or 0-10,11-20 etc.The same can apply to even decimal classes and there should be no overlap related to the degree of precision of recording etc.I find in this set of discussions that you can have an overlap and then mention which endpoint is to be included or not.While this may be so isn't it more ambiguous compared to the former method and why should such possible ambiguity be allowed in mathematical discussions ?
How are the two approaches reconciled.Is not the former method more accurate,precise and unambiguous to anyone looking at a table or chart ?
UserIdTAG: 1006030
UserNameTAG: Prasannasimha
CreateTimeTAG: 2013-02-21T19:14:59Z
VoteTAG: 5
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: While your 0-9, 10-19 notation would exclude continuous values between 9 and 10 a notation that uses greater than or equal to, e.g. 0 <= x < 10 and 10 <= x < 20, would certainly be more obvious, in my opinion, than the endpoint statements. Seeing the overlaps makes me cringe a bit.
FirstChildUserIdTAG: 1268175
FirstChildUserNameTAG: MarquisDeMizzle
FirstChildCreateTimeTAG: 2013-02-21T19:24:50Z
FirstChildVoteTAG: 2
SecondChildTAG: Yes but you can extend it to any amount of decimals as the precision of recording for eg 0-9.9999 ,10-19.9999 and so on and so forth. In medical statistics we use tables with a precision rate that is predetermined and so you cannot measure with a value lower than your least accurate measurement (precision).(You can also even keep a recurring decimal (a dot over the last decimal if you want to indicate precision to infinity).
Somehow having the same number overlapping seems very imprecise.I do hope the Professors comment on this.
It used to be a big No no for us to overlap class intervals in medical school statistics so this came as a surprise to me.
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-21T19:51:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Agreed, I'm curious to know if this is common practice in some fields.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T19:58:24Z
SecondChildVoteTAG: 0
FirstChildTAG: Two useful observations:
1. The intervals don't overlap, as the table is to be read along with its endpoint convention. The table does not exist by itself separated from that convention. So for example you'll see intervals like 0-10 and 10-25 that appear to overlap, but the endpoint convention says "intervals include the left endpoint but not the right", and therefore 10 belongs to the 10-25 interval only, and there is no overlap nor any imprecision.
2. MarquisDeMizzle has noticed correctly that continuity is what we need to be thinking about. Writing the tables as we do in Stat 2.1X (and is done routinely in statistics) eliminates the "any amount of decimals" issue, as it becomes unnecessary to specify the number of decimals. More importantly, not having gaps (even tiny gaps) in histograms will become crucial when we start approximating them with smooth curves.
Best,
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-21T20:11:15Z
FirstChildVoteTAG: 4
SecondChildTAG: Thanks for the feedback. I don't think either of us was arguing that the endpoint convention lacked accuracy, rather that it was a less apparent way of showing the data. I certainly should have chosen my wording better and stated that the "apparent" overlap at first glance made me cringe.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T20:16:30Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks for the clarification.
If the endpoint convention is not mentioned (as it should be)then how does one read such tables(ie is there any common "understanding" or "convention" that a left end point is to be used ?
I have seen a lot of tables where such end point conventions are not used (though to be fair they do not allow overlap) and was wondering if such conventions are "presumed" ?
SecondChildUserIdTAG: 1006030
SecondChildUserNameTAG: Prasannasimha
SecondChildCreateTimeTAG: 2013-02-22T09:45:04Z
SecondChildVoteTAG: 0
SecondChildTAG: Maybe this is a silly question, but I want to get this perfectly clear; would you then say that the interval between 5-15 is 10, or is it 9?
SecondChildUserIdTAG: 864596
SecondChildUserNameTAG: Rubenjtj
SecondChildCreateTimeTAG: 2013-02-24T18:15:39Z
SecondChildVoteTAG: 0
SecondChildTAG: I think it should be 10, although my conundrum is about the 14.999999 there :-)
SecondChildUserIdTAG: 864596
SecondChildUserNameTAG: Rubenjtj
SecondChildCreateTimeTAG: 2013-02-24T18:26:38Z
SecondChildVoteTAG: 0
SecondChildTAG: I also believe the interval should be 10, or better 9,99 !
SecondChildUserIdTAG: 975742
SecondChildUserNameTAG: MarcoP
SecondChildCreateTimeTAG: 2013-02-26T08:47:03Z
SecondChildVoteTAG: 0
SecondChildTAG: @Prasannasimha - In one of the linked videos in the online textbook, Professor Stark mentioned that the common convention is to use left-inclusive, right-exclusive.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-02-26T21:47:48Z
SecondChildVoteTAG: 0
SecondChildTAG: @Rubenjtj - In the video, Professor Adhikari divided all of the percentages by whole number ranges to come up with heights for the histogram, so I would say the answer should be 10.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-02-26T21:58:49Z
SecondChildVoteTAG: 0
IndexTAG: 2848
TitleTAG: I am master degree student in community medicine
Happy to see you all in this class I hope we can help each other
but I have done 2 mistakes in the first exercise . I feel so sad!!!
UserIdTAG: 1050924
UserNameTAG: leap
CreateTimeTAG: 2013-02-21T19:13:50Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: which were the mistakes?
FirstChildUserIdTAG: 1231201
FirstChildUserNameTAG: wolkoe
FirstChildCreateTimeTAG: 2013-02-21T19:18:08Z
FirstChildVoteTAG: 0
SecondChildTAG: Nice to have you here. Don't you worry. We all have mistakes :)
Good luck
SecondChildUserIdTAG: 1042271
SecondChildUserNameTAG: Saeed19
SecondChildCreateTimeTAG: 2013-02-21T19:23:42Z
SecondChildVoteTAG: 0
SecondChildTAG: we're kinda here to make and correct our mistakes. ...lol
SecondChildUserIdTAG: 1239363
SecondChildUserNameTAG: drpopee
SecondChildCreateTimeTAG: 2013-02-21T19:36:31Z
SecondChildVoteTAG: 0
IndexTAG: 2849
TitleTAG: Mistake in exercise 1
to my view "Income" is a discrete numerical variable as I've never seen any fractions of any currency in an income statement...
What do you think?
UserIdTAG: 1231201
UserNameTAG: wolkoe
CreateTimeTAG: 2013-02-21T19:12:26Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I am speaking of exercise 1 in exercise set 1
FirstChildUserIdTAG: 1231201
FirstChildUserNameTAG: wolkoe
FirstChildCreateTimeTAG: 2013-02-21T19:17:37Z
FirstChildVoteTAG: 0
SecondChildTAG: Though we round off any currency in an income statement. Having said that the variable remains continuous and not discrete.
SecondChildUserIdTAG: 1017258
SecondChildUserNameTAG: writetoprithvi
SecondChildCreateTimeTAG: 2013-02-21T19:39:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Income is discrete, since noone operates with fractions of cents (or whatever the base unit of your currency system is).
SecondChildUserIdTAG: 83185
SecondChildUserNameTAG: oysteingrondahl
SecondChildCreateTimeTAG: 2013-02-21T20:06:04Z
SecondChildVoteTAG: 0
SecondChildTAG: If you click "+Solution" under Exercise 3.1 in the SticiGui, it says the following:
"if you view money as having a smallest unit (for example, a cent in the USA), then per-capita income is a rational number (a fraction). Because fractions are countable, per-capita income would be discrete. For all practical purposes, however, per-capita income could be treated as a continuous quantitative variable."
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm#variables
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-02-21T20:22:56Z
SecondChildVoteTAG: 0
SecondChildTAG: That is like saying the average family has 2.4 kids. Rubbish. Income is discrete!
SecondChildUserIdTAG: 164614
SecondChildUserNameTAG: LuketheEngineer
SecondChildCreateTimeTAG: 2013-02-21T20:59:58Z
SecondChildVoteTAG: 0
IndexTAG: 2850
TitleTAG: E3 P1 which value
What variable are you looking for regarding the specific quartile?
UserIdTAG: 1133083
UserNameTAG: mmmaloyan
CreateTimeTAG: 2013-02-21T19:03:41Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2851
TitleTAG: Audio/video file lecture downloads?
Would it be possible to have the audio lectures as mp3 files that I could listen to while traveling? (and/or the video file) There is also a thread for pdf files and both would be very helpful.
UserIdTAG: 1009037
UserNameTAG: rorywilsonis
CreateTimeTAG: 2013-02-21T19:02:32Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It would be great if we have such feature.
FirstChildUserIdTAG: 1017258
FirstChildUserNameTAG: writetoprithvi
FirstChildCreateTimeTAG: 2013-02-21T19:41:09Z
FirstChildVoteTAG: 0
IndexTAG: 2852
TitleTAG: Exercise 2 pt 4
Please can someone explain, I got 13.2% as my answer and was marked wrong.
UserIdTAG: 1187096
UserNameTAG: Chinonso411
CreateTimeTAG: 2013-02-21T18:48:14Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The grader is a bit sensitive is all I can say. Also, try following the homework videos extremely close and exercises carefully, they they can help tip you off with regards to how they want answers answered. Good luck
FirstChildUserIdTAG: 1131322
FirstChildUserNameTAG: rooster23
FirstChildCreateTimeTAG: 2013-02-21T20:45:49Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you...
SecondChildUserIdTAG: 1187096
SecondChildUserNameTAG: Chinonso411
SecondChildCreateTimeTAG: 2013-02-21T20:52:46Z
SecondChildVoteTAG: 0
IndexTAG: 2853
TitleTAG: Practice for Exercise Set 2 Mistake
Lectures 2.2 and 2.3, question a:
interval -10 to 20, the height will be not 14/10 but 14/30 (the width of the interval is 30!)
UserIdTAG: 524348
UserNameTAG: cdracer
CreateTimeTAG: 2013-02-21T18:44:55Z
VoteTAG: 7
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I too think there is a mistake in that question
FirstChildUserIdTAG: 892513
FirstChildUserNameTAG: rfvizarra
FirstChildCreateTimeTAG: 2013-02-21T18:46:21Z
FirstChildVoteTAG: 1
SecondChildTAG: i also think there is a mistake. The width of the interval is 30 not ten. 20-(-10)=30
SecondChildUserIdTAG: 422336
SecondChildUserNameTAG: lilian2012
SecondChildCreateTimeTAG: 2013-02-21T19:09:03Z
SecondChildVoteTAG: 0
SecondChildTAG: Agree!
SecondChildUserIdTAG: 1081022
SecondChildUserNameTAG: Paul02035
SecondChildCreateTimeTAG: 2013-02-21T19:12:45Z
SecondChildVoteTAG: 0
SecondChildTAG: me too
SecondChildUserIdTAG: 162722
SecondChildUserNameTAG: FDA2
SecondChildCreateTimeTAG: 2013-02-21T19:23:32Z
SecondChildVoteTAG: 0
SecondChildTAG: Unless we are all terrible at this, I too agree :)
SecondChildUserIdTAG: 407852
SecondChildUserNameTAG: Diamantius
SecondChildCreateTimeTAG: 2013-02-21T19:23:40Z
SecondChildVoteTAG: 0
IndexTAG: 2854
TitleTAG: Open Educational Resources
Hi all,
Does anyone know if the videos and other materials for this course are licensed to the public as [Open Educational Resources][1]? I.e. are the materials [Creative Commons][2] licensed, or some similar [Public Domain][3] designation?
[1]: http://www.oercommons.org/
[2]: http://creativecommons.org
[3]: https://en.wikipedia.org/wiki/Public_domain
UserIdTAG: 767139
UserNameTAG: brylie
CreateTimeTAG: 2013-02-21T18:37:17Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2855
TitleTAG: Can't view the course material
Hi
This is my first course with edx and i am unable to view the course material. I clicked the first lecture introduction but its showing a blank page. can anybody help me with this problem.
UserIdTAG: 923944
UserNameTAG: aib536pk
CreateTimeTAG: 2013-02-21T18:36:43Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Are you using Google Chrome? I found that with Internet Explorer 10 and Windows 8 I could not access large parts of edx.
FirstChildUserIdTAG: 1235638
FirstChildUserNameTAG: MyOwnCamera
FirstChildCreateTimeTAG: 2013-02-21T18:51:10Z
FirstChildVoteTAG: 0
SecondChildTAG: I used IE9 but i also tried the material over Mozilla Firefox. Results are the same. i cant access material.
SecondChildUserIdTAG: 923944
SecondChildUserNameTAG: aib536pk
SecondChildCreateTimeTAG: 2013-02-21T18:52:26Z
SecondChildVoteTAG: 0
SecondChildTAG: I had to download Chrome to get it to work properly on my computer.
SecondChildUserIdTAG: 950537
SecondChildUserNameTAG: cjc71
SecondChildCreateTimeTAG: 2013-02-21T20:24:10Z
SecondChildVoteTAG: 0
FirstChildTAG: Could be a few things:
1) Are you in a country that blocks Youtube? If so, the lectures won't be available.
2) What browser are you using? From other discussions, Chrome seems to be the most likely to work with edX, followed by Firefox. There have been a number of issues with Internet Explorer, so you may want to try another browser. I've used Safari and Chrome on an iPad and that seems to work fine for videos (although other content doesn't always display).
3) Is your Flash installation working? The site also uses Flash to display content, so you can try downloading the latest version here: http://get.adobe.com/flashplayer/otherversions/
Hope this helps!
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-21T18:51:51Z
FirstChildVoteTAG: 2
SecondChildTAG: Is the material in a pdf version? or only in videos?
SecondChildUserIdTAG: 1012988
SecondChildUserNameTAG: Jherreran
SecondChildCreateTimeTAG: 2013-02-21T20:25:30Z
SecondChildVoteTAG: 0
FirstChildTAG: Try Chrome. I recently had to switch from Firefox to Chrome because I couldn't view the Coursework pages. Today I can't even log in on Firefox.
They apparently changed the system recently. That might explain some of the problems.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T21:15:50Z
FirstChildVoteTAG: 0
IndexTAG: 2856
TitleTAG: Practice and Graded Problem Answers Inquiry
I've found on multiple occasions where the answer the computer is looking for is an exact answer stopping at two decimal places, as opposed to a range for which the answer can be counted correctly. For instance, in practice for Section 2.1, I entered 0.167 and got a "red x", but 0.17 was the "correct" answer. Can a range of values be stipulated in the computer for grading purposes, or do we simple select show answer to confirm. How about for graded problems where only one answer is allowed? Request clarity or guidance be provided on this grading issue.
UserIdTAG: 1186269
UserNameTAG: jhsmith
CreateTimeTAG: 2013-02-21T18:36:05Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I agree it is a bit of a pain for the practice problems. However, the graded problems have thus far specified where to round your answers and the format required, so it's not an issue for these questions.
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-21T18:39:51Z
FirstChildVoteTAG: 0
SecondChildTAG: I request the course facilitators specify the number of decimals for the calculations. Imagine for the practice exercises, one can check but imagine the graded exercises and one gets the answer wrong cause of decimals and yet they are few chances of trying. thanks
SecondChildUserIdTAG: 818658
SecondChildUserNameTAG: sheilal
SecondChildCreateTimeTAG: 2013-02-22T07:34:49Z
SecondChildVoteTAG: 0
IndexTAG: 2857
TitleTAG: Has the course started ?
Just found a couple of exercises. When do we get any tuition or something to read ?
UserIdTAG: 1067676
UserNameTAG: JohnKay
CreateTimeTAG: 2013-02-21T18:32:15Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Yes it has, the lecture videos should also be available under the Courseware link, titled starting with Section (like Section 1: Introduction). The videos are hosted on YouTube, if you're not seeing them are you in an area that blocks access to YouTube?
FirstChildUserIdTAG: 1268175
FirstChildUserNameTAG: MarquisDeMizzle
FirstChildCreateTimeTAG: 2013-02-21T18:38:27Z
FirstChildVoteTAG: 0
SecondChildTAG: Got the introduction plus exercise practice and something due tomorrow. Intro says nothing.
Where is the tuition ?
SecondChildUserIdTAG: 1067676
SecondChildUserNameTAG: JohnKay
SecondChildCreateTimeTAG: 2013-02-21T18:40:39Z
SecondChildVoteTAG: 0
SecondChildTAG: Clicking the 'Section 1: Introduction' should load a page with 3 lecture videos on the right. It sounds like this is not loading for you so perhaps there is a techinical issue here that the staff can address.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T18:54:08Z
SecondChildVoteTAG: 0
IndexTAG: 2858
TitleTAG: HW2 P1
I've submitted an answer for this, and am confused as to why the answer is what it is.
The question asks about density, number, and frequency.
Frequency I got correct, as it can be found by figuring even distribution: % / W and comparing the two ranges.
I got the first two incorrect and am wanting to understand why. The first question asks which interval contains more people. Based on what I understand - AREA of the plot on a histogram is the actual data - which would mean height x width. Apparently this is wrong?
The second asks which is more CROWDED - again - HEIGHT shows density - %/W. Again, why is this incorrect?
I would appreciate any enlightenment that could be shared. Please do not use numbers as that would likely violate the homework and honor system for this class.
UserIdTAG: 40598
UserNameTAG: jstarkey
CreateTimeTAG: 2013-02-21T18:03:43Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Regarding 2.1a, the system has it wrong, please see the professor's explanation in this thread: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
As for 2.1b, your statements about height and density are correct so take another look at your #s.
FirstChildUserIdTAG: 1268175
FirstChildUserNameTAG: MarquisDeMizzle
FirstChildCreateTimeTAG: 2013-02-21T18:09:03Z
FirstChildVoteTAG: 1
SecondChildTAG: Many thanks! I see my error on the second now :)
SecondChildUserIdTAG: 40598
SecondChildUserNameTAG: jstarkey
SecondChildCreateTimeTAG: 2013-02-21T20:49:36Z
SecondChildVoteTAG: 0
FirstChildTAG: I completed the rest of the homework perfectly. I must have missed something obvious. Help?
FirstChildUserIdTAG: 40598
FirstChildUserNameTAG: jstarkey
FirstChildCreateTimeTAG: 2013-02-21T18:15:14Z
FirstChildVoteTAG: 0
SecondChildTAG: Unfortunately there's no way for us to privately communicate here, so while there's no harm in both of us who have completed the exercises discussing the specifics, it wouldn't be right discussing them until the exercises are closed.
I urge you to take a *very* close look at your numbers. Redo the exact calculations you mention and you should see your error.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T18:21:42Z
SecondChildVoteTAG: 0
SecondChildTAG: I suppose it's also possible that they could have changed the grading logic since my exercise was graded and what's right for me was graded wrong for you. I would hope the system was more consistent than that, but we can't really rule it out. :(
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T18:33:17Z
SecondChildVoteTAG: 0
IndexTAG: 2859
TitleTAG: Exercise Set 1 - Problem 3b
I'd like you to please check the correct answer I think there is a mistake.
If so all questions and answers should be reviewed.
Thanks
UserIdTAG: 923436
UserNameTAG: edsonterceros
CreateTimeTAG: 2013-02-21T17:55:56Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: I'm just another student, but it appears correct to me. Maybe give it another look?
FirstChildUserIdTAG: 1268175
FirstChildUserNameTAG: MarquisDeMizzle
FirstChildCreateTimeTAG: 2013-02-21T18:03:41Z
FirstChildVoteTAG: 1
SecondChildTAG: i've made the same mistake... the propblem is is that one says possibility and the other say number of plants :((((
SecondChildUserIdTAG: 290674
SecondChildUserNameTAG: yambanis
SecondChildCreateTimeTAG: 2013-02-22T05:43:16Z
SecondChildVoteTAG: 0
SecondChildTAG: Holy son of a ,ouch ,why in the blazes would they do that ,I mean ahh ,not cool ,but I suppose I shouldve read the little side first blah ,well glad it happened early on ,at least ill know now and maybe itll happen with even more important questions
SecondChildUserIdTAG: 20186
SecondChildUserNameTAG: vikashx1
SecondChildCreateTimeTAG: 2013-02-26T01:01:17Z
SecondChildVoteTAG: 0
FirstChildTAG: for me it's correct.
FirstChildUserIdTAG: 898634
FirstChildUserNameTAG: danipopa
FirstChildCreateTimeTAG: 2013-02-21T18:19:17Z
FirstChildVoteTAG: 0
FirstChildTAG: There are differences in even the graphs that look alike.
I was also confused here, but if you look closely at the graphs you will find the one you are looking for. Don't just look at the bars, look at the axis labels.
I hope I haven't said too much now.
FirstChildUserIdTAG: 511105
FirstChildUserNameTAG: FrankTR
FirstChildCreateTimeTAG: 2013-02-21T18:31:28Z
FirstChildVoteTAG: 2
FirstChildTAG: Make sure you read the question carefully. The second sentence is:
> Select all that are correct.
Could this be the issue you are having?
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-21T18:37:54Z
FirstChildVoteTAG: 0
SecondChildTAG: the order at 3 b) is:
"Which is the correct bar graph?"
I don't know if the questions for everybody are the same.
SecondChildUserIdTAG: 923436
SecondChildUserNameTAG: edsonterceros
SecondChildCreateTimeTAG: 2013-02-21T19:14:16Z
SecondChildVoteTAG: 0
SecondChildTAG: It appears aaronrod was looking at 2b instead of 3b
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T19:17:12Z
SecondChildVoteTAG: 0
SecondChildTAG: another green/green ... category? anyway I can't find a way to sum the answer it appears as correct.
SecondChildUserIdTAG: 923436
SecondChildUserNameTAG: edsonterceros
SecondChildCreateTimeTAG: 2013-02-21T19:18:56Z
SecondChildVoteTAG: 0
FirstChildTAG: You need to read all the labels, as well as noting the size of the bars.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T22:42:15Z
FirstChildVoteTAG: 0
IndexTAG: 2860
TitleTAG: Issue with Excercise Set 3 Problem 2 b (3.2b) [Edit: Also 3.2a]
I believe there is an issue with problem 2b in exercise set 3. I've entered the answer to one decimal place but have been marked wrong.
UserIdTAG: 1268175
UserNameTAG: MarquisDeMizzle
CreateTimeTAG: 2013-02-21T17:53:46Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: i think I have a problem with that one too, using the same formula I get 2 out of 3 wrong, im pretty confident that I got it right, but the 2 wrong ones have a decimal and the right one does not?
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-21T17:58:17Z
FirstChildVoteTAG: 1
SecondChildTAG: Yeah, it appears I'm in the same boat. 3.2a and 3.2b are graded wrong but I'm quite certain of my values.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T19:44:17Z
SecondChildVoteTAG: 0
FirstChildTAG: I don't believe there is anything wrong with Ex 3. Please check your answers.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T19:58:22Z
FirstChildVoteTAG: 1
SecondChildTAG: Indeed I have, via 2 different methods. Will be interesting to discuss after the exercises are closed to see where the misunderstanding is.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-21T20:05:33Z
SecondChildVoteTAG: 0
SecondChildTAG: The grader is quite sensitive. Reading your initial question, I suggest reviewing lecture 2.1 again, also the lecture on the p-th percentile definition.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-21T20:41:27Z
SecondChildVoteTAG: 0
SecondChildTAG: I see, different definitions. Thanks.
SecondChildUserIdTAG: 1268175
SecondChildUserNameTAG: MarquisDeMizzle
SecondChildCreateTimeTAG: 2013-02-22T17:53:41Z
SecondChildVoteTAG: 0
FirstChildTAG: If you answer according to the method described in the lecture, there should not be any decimal places to enter.
As jimbangun said, review the p-th percentile definition.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T21:19:28Z
FirstChildVoteTAG: 2
SecondChildTAG: then for exercise set 3 problem 1c why does it say to round to one decimal place if we should just go by the p-th percentile definition like 1a and 1b?? i have not submitted it even once yet but im confused on this 1 so ya
SecondChildUserIdTAG: 985560
SecondChildUserNameTAG: zoe3456
SecondChildCreateTimeTAG: 2013-02-21T23:46:33Z
SecondChildVoteTAG: 0
SecondChildTAG: Because Q1 is asking you to *estimate* from a table of frequencies. You can't give an exact answer as you don't have the full data set.
But with the stem and leaf of the next part, you can - because you have the actual data.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T00:14:45Z
SecondChildVoteTAG: 0
SecondChildTAG: im not talking about the stem and leaf plot. im talking about question 1c. are we supposed to just use the pth percentile definition for 1a and 1b where it says to estimate the percentile but does NOT say ROUND to one decimal place? if we are not supposed to use the pth percentile definition for 1a and 1b then why does it not also say to round to one decimal space on 1a and 1b??? it only says to round to one decimal point on 1c and this makes no sense whatsoever to me. we have the interval table so we could get a more accurate like 25th percentile than the pth percentile definition but it does not say to round on the 15th percentile and the median questions so 1a and 1b and it only says to round to a decimal point on 1c which is the 75th percentile question. so im asking why is this??
SecondChildUserIdTAG: 985560
SecondChildUserNameTAG: zoe3456
SecondChildCreateTimeTAG: 2013-02-22T00:49:15Z
SecondChildVoteTAG: 0
SecondChildTAG: typo corrected 25th percentile not 15th percentile
SecondChildUserIdTAG: 985560
SecondChildUserNameTAG: zoe3456
SecondChildCreateTimeTAG: 2013-02-22T00:51:06Z
SecondChildVoteTAG: 0
FirstChildTAG: > im not talking about the stem and leaf plot. im talking about question 1c.
This is an estimation, so there might be decimal places. If required by your answer, use 1dp. Worked for me.
> why does it not also say to round to one decimal space on 1a and 1b???
I have no idea. Perhaps just something they overlooked. Or maybe they meant to put the instruction at the beginning of the question, but didn't.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-22T01:10:02Z
FirstChildVoteTAG: 0
SecondChildTAG: and me too.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-22T02:18:34Z
SecondChildVoteTAG: 0
FirstChildTAG: Actually it turns out I got it wrong because I was calculating it wrong :)
FirstChildUserIdTAG: 7545
FirstChildUserNameTAG: jasontimothyjones
FirstChildCreateTimeTAG: 2013-02-26T19:56:05Z
FirstChildVoteTAG: 0
IndexTAG: 2861
TitleTAG: Exce Set 2 Problem 1c
c) where there more 5-year-olds or 15-year-old?
by looking at the table one really cannot answer with any certainty.
but considering that the 5-year-olds belong the second interval 5-15 with the higher percentage 13.3,
in the 3rd interval 15-20, percentage is 7.1
then assuming that all individual in the 2nd group are 5-year olds, and that all in the 3rd group are 15-year olds, then one can only infer that that there are more 5-year olds. G.Luck
UserIdTAG: 875906
UserNameTAG: AzizAlkhater
CreateTimeTAG: 2013-02-21T17:41:09Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: "You can assume that the ages are uniformly distributed within each interval." - from execise text. use this.
FirstChildUserIdTAG: 324774
FirstChildUserNameTAG: eduard_k
FirstChildCreateTimeTAG: 2013-02-21T17:44:11Z
FirstChildVoteTAG: 1
SecondChildTAG: thanks, but can u elaborate
SecondChildUserIdTAG: 875906
SecondChildUserNameTAG: AzizAlkhater
SecondChildCreateTimeTAG: 2013-02-21T17:51:42Z
SecondChildVoteTAG: 0
SecondChildTAG: thanks, but can you elaborate
SecondChildUserIdTAG: 875906
SecondChildUserNameTAG: AzizAlkhater
SecondChildCreateTimeTAG: 2013-02-21T17:55:23Z
SecondChildVoteTAG: 0
FirstChildTAG: You must consider density, thus percent **per unit**.
FirstChildUserIdTAG: 769728
FirstChildUserNameTAG: JaimeBM
FirstChildCreateTimeTAG: 2013-02-21T17:56:58Z
FirstChildVoteTAG: 0
FirstChildTAG: thanks eduard and jaime, then when considering the problem one need to figure
the % per unit and assuming uniform distribution then:
the percentage of 5 year olds is 13.3/10 = 1.33%,
the percentage of 15 year olds is 7.1/5 = 1.42
FirstChildUserIdTAG: 875906
FirstChildUserNameTAG: AzizAlkhater
FirstChildCreateTimeTAG: 2013-02-21T18:17:52Z
FirstChildVoteTAG: 0
IndexTAG: 2862
TitleTAG: How many decimal places we have to work?
I think it is important that the exercises specify the number of decimal places to be given the answers. Otherwise, the corrector marks as erroneous the correct answers
UserIdTAG: 296838
UserNameTAG: andoria
CreateTimeTAG: 2013-02-21T17:29:50Z
VoteTAG: 6
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I absoluetly agree...
FirstChildUserIdTAG: 1237295
FirstChildUserNameTAG: tanushree31
FirstChildCreateTimeTAG: 2013-02-21T17:34:50Z
FirstChildVoteTAG: 0
SecondChildTAG: Agreed
SecondChildUserIdTAG: 1017258
SecondChildUserNameTAG: writetoprithvi
SecondChildCreateTimeTAG: 2013-02-21T19:37:43Z
SecondChildVoteTAG: 0
FirstChildTAG: And this has been raised with the Prof. She is in the process of making changes.
Please read this post:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/undefined/threads/5125bb66e072011f0000013e
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T21:23:14Z
FirstChildVoteTAG: 0
IndexTAG: 2863
TitleTAG: Query/Complaint
Hi All, Firstly let me apologise if this has already been covered or is just unique to me, I did try searching for it on the forums and couldn't find it.
I just signed up today and tried the first exercise after reading through the lectures. I felt I understood everything, however, I found the graphs are designed to give as little information as possible, to the point of being misleading. In I think the first question I remember the ratios being 6:2:2:1 or something along those lines. But the bar chart not quite going up to 6, but if it had, it would have been correct. I checked it and it informed me I'd gotten it wrong - i.e. it went up to 6 and just didn't look that way. I had similar problems later in the exercise, and I was wondering if anyone has experienced similar difficulties/confusion?
**My Background** - it's not relevant but if you're curious - loved maths as a child, however had learning difficulties which included terrible spatial awareness. I really enjoyed statistics but had to drop maths after AS Level (after 17) because of difficulties with other areas of the subject. Use amateurish statistics as a keen poker player, though that involves incomplete information and more akin to game theory than descriptive stats. Still, I felt understanding this topic could help me in this field, and possibly in derivatives trading which I'm considering getting involved with.
UserIdTAG: 216795
UserNameTAG: Philosophyx
CreateTimeTAG: 2013-02-21T17:26:58Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Do you mean problem 2b?
The Y axis of the bar charts does not directly show the ratios given in the text of the question. It shows the proportion of the total with a Y axis value of 1.0 being equivalent to all of the samples.
With the ratios you give 6:2:2:1, the 6 as a proportion of all the samples is 6/11, slightly less than 0.6 as you have seen in the chart.
FirstChildUserIdTAG: 23266
FirstChildUserNameTAG: dnc
FirstChildCreateTimeTAG: 2013-02-21T18:19:52Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you for your reply.
My Problem was with Problem 2
In a genetic experiment, plants are classified as magenta/green, magenta/red, red/green, and red/red, and appear in the proportions 9:3:3:1
The graphs represented them as 6:2:2:0.5 I can see your point that the top wouldn't be exactly 6 etc., but I'd still like to know what level they are equal to for my own piece of mind, so I can work it out exactly. Having checked the question I had a later graph problem with, that was entirely my mistake. I ignored the description of the y axis, where it described probability, and I had just assumed all the graphs represented number of plants. Live and learn. Although, despite that, I'd still like to know what exact level the graph was at, even if I'd have gotten it wrong.
FirstChildUserIdTAG: 216795
FirstChildUserNameTAG: Philosophyx
FirstChildCreateTimeTAG: 2013-02-22T08:24:53Z
FirstChildVoteTAG: 0
SecondChildTAG: With 9:3:3:1 ratios, the proportion of magenta/green is 9/(9+3+3+1)=9/16=0.5625 or 56.25%.
Magenta/red is 3/16=0.1875 or 18.75%
etc.
SecondChildUserIdTAG: 23266
SecondChildUserNameTAG: dnc
SecondChildCreateTimeTAG: 2013-02-22T21:10:53Z
SecondChildVoteTAG: 0
IndexTAG: 2864
TitleTAG: Help Please
I need help from someone who started today. I m new to edx and I m lost.....
UserIdTAG: 585992
UserNameTAG: SabrinaAdeel
CreateTimeTAG: 2013-02-21T17:24:23Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I don't see the exercises. Please direct me to this information. I need to submit by tomorrow. Thank you very much.
FirstChildUserIdTAG: 1206081
FirstChildUserNameTAG: anusimw
FirstChildCreateTimeTAG: 2013-02-21T17:27:03Z
FirstChildVoteTAG: 0
SecondChildTAG: I m not sure where to find them. I just started a few minutes ago... Sorry..
SecondChildUserIdTAG: 585992
SecondChildUserNameTAG: SabrinaAdeel
SecondChildCreateTimeTAG: 2013-02-21T17:30:44Z
SecondChildVoteTAG: 0
SecondChildTAG: They are in courseware
SecondChildUserIdTAG: 310963
SecondChildUserNameTAG: TwinOtter
SecondChildCreateTimeTAG: 2013-02-21T17:30:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Click the Courseware button on the top left of your screen.
On the top left of the next screen, click Section 1: Introduction to access the first set of lecture videos (there are 3 in this section).
Click "Practice Set for Exercise 1" to do the practice problems. They will give you a feel for answering the homework.
When you are ready, click "Exercise Set 1" to access the first homework assignment, which is due tomorrow. Be advised the "Final Check" button on each problem will submit your homework answer for grading and you cannot change after clicking final check.
Good luck!
Sandi
SecondChildUserIdTAG: 1165890
SecondChildUserNameTAG: sandigarcia
SecondChildCreateTimeTAG: 2013-02-21T17:34:42Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks Sandi :)
SecondChildUserIdTAG: 585992
SecondChildUserNameTAG: SabrinaAdeel
SecondChildCreateTimeTAG: 2013-02-21T17:52:23Z
SecondChildVoteTAG: 0
FirstChildTAG: You should find lectures, practice sets, and exercise sets under the Courseware tab.
FirstChildUserIdTAG: 956316
FirstChildUserNameTAG: MSSmith
FirstChildCreateTimeTAG: 2013-02-21T17:31:37Z
FirstChildVoteTAG: 1
SecondChildTAG: Thank you
SecondChildUserIdTAG: 585992
SecondChildUserNameTAG: SabrinaAdeel
SecondChildCreateTimeTAG: 2013-02-21T17:52:40Z
SecondChildVoteTAG: 0
IndexTAG: 2865
TitleTAG: Recommendation to blockout all accounts with sarcastic remarks
I feel and believe students who register for any of these free online courses with edx.org should be people with dignity and integrity from organized family or background. With this in mind, i have critically read unrepresented remarks from students in this community and i therefore recommend to the body of this noble institution to not let us read such sarcastic expressions but to rather delete their accounts subsequently, since they can't post comments inline with the this community Discussion Forum Guidelines.
UserIdTAG: 824988
UserNameTAG: KongorJ
CreateTimeTAG: 2013-02-21T17:20:40Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 7
FirstChildTAG: Chalk it up to frustration, not malice.
FirstChildUserIdTAG: 310963
FirstChildUserNameTAG: TwinOtter
FirstChildCreateTimeTAG: 2013-02-21T17:23:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Your suggestion seems a little harsh. I agree with TwinOtter that people got frustrated and impatient. I don't think that much harm was done and I believe that a notice from the people managing the course can remedy most of the problem. We're intelligent, responsible adults, but sometimes we need to be reminded of that fact. I think things will go much more smoothly from here on out.
FirstChildUserIdTAG: 956316
FirstChildUserNameTAG: MSSmith
FirstChildCreateTimeTAG: 2013-02-21T17:30:00Z
FirstChildVoteTAG: 3
FirstChildTAG: I think these comments are quite right - much frustration and, because many were accessing the course late at night in their own time zone, a degree of fatigue. I suspect things are better in the cold light of day.
Banning people for venting their frustration does seem a tad extreme!
FirstChildUserIdTAG: 20879
FirstChildUserNameTAG: forevergreen
FirstChildCreateTimeTAG: 2013-02-21T17:55:31Z
FirstChildVoteTAG: 0
SecondChildTAG: In a sense I think what we are seeing, while perhaps not a display of the best of manners, is an indication of how seriously we take our studies, and that's good.
SecondChildUserIdTAG: 310963
SecondChildUserNameTAG: TwinOtter
SecondChildCreateTimeTAG: 2013-02-21T18:09:16Z
SecondChildVoteTAG: 0
FirstChildTAG: Just ignore them. From past experience, most of the people making unhelpful remarks generally drop out by the third or fourth week.
(Maybe by the end of the course, I can express this data in a helpful format!)
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-21T18:42:43Z
FirstChildVoteTAG: 1
FirstChildTAG: Hello all,
Thank you for your concern about civility on the forum. The overwhelming majority of students are very polite, and while frustration understandably leads people to sound irritated, so far it doesn't seem to be any more than that. For my part, I'm working at this end to reduce the number of instances of frustration - a new course on a new (really, it changed recently) platform is a fertile ground for errors, and each error affects almost 50,000 students. Things will get better as the course progresses and we at the development end learn the kinds of things that are most likely to lead to student frustration.
I'm very invested in students having an enjoyable time in this course, both with the course material and in the discussion groups, and I appreciate all of your suggesting ways to help. Best wishes,
Prof. A.
P.S. Aaronrod: Sounds like you've got yourself a project. I'll help!
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-21T20:21:44Z
FirstChildVoteTAG: 5
FirstChildTAG: Ah, so the platform changed recently? Maybe that explains why I recently had to switch back to Chrome. Firefox won't log me in now, and last couple of weeks it wouldn't let me see the coursework pages.
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T21:03:34Z
FirstChildVoteTAG: 0
FirstChildTAG: Do you have a working sarcasm filter ? Otherwise someone will have to go over each posting one by one and decide. What will be the criteria? And, no, this is not being said with sarcasm, just curiosity. I have some teenagers I'd like to plug into a sarcasm filter some days.
FirstChildUserIdTAG: 937396
FirstChildUserNameTAG: m2foster
FirstChildCreateTimeTAG: 2013-03-12T20:54:22Z
FirstChildVoteTAG: 0
IndexTAG: 2866
TitleTAG: video download
sir/mam ,
I have problem in downloading the lectures . what should i do?
UserIdTAG: 573692
UserNameTAG: Roop_kaur
CreateTimeTAG: 2013-02-21T17:09:03Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I believe they are Youtube videos. I've never used any Youtube video downloader, but you can probably do a quick Google search. If you mean you cannot access the videos at all, you may need the prerequisite software to view Youtube videos. One important plugin is Adobe Flash Player. I'm afraid I don't know what else might be needed.
FirstChildUserIdTAG: 956316
FirstChildUserNameTAG: MSSmith
FirstChildCreateTimeTAG: 2013-02-21T17:36:30Z
FirstChildVoteTAG: 0
FirstChildTAG: There are probably many ways to download the videos. I use Internet Download Manager, but you can probably find other means. With IDM installed, it detects the video automatically when I enter the Course page and offers me the option to download. I download as an FLV file and view later using a media player (I use VLC Media Player). Sadly, the downloaded video does not include the closed captions or subtitles. Being rather hard of hearing, subtitles help me. I'll try contacting the instructor or EdX to make available the SRT file that will display subtitles.
Here are the relevant links:
Internet Download Manager: http://www.internetdownloadmanager.com/
VLC Media Player: http://www.videolan.org/vlc/index.html
FirstChildUserIdTAG: 441413
FirstChildUserNameTAG: coyotecoach
FirstChildCreateTimeTAG: 2013-02-21T18:17:44Z
FirstChildVoteTAG: 1
SecondChildTAG: You can download the SRT subttiles from youtube, using the Google2SRT software [http://google2srt.sourceforge.net/][1]
[1]: http://google2srt.sourceforge.net/
SecondChildUserIdTAG: 599480
SecondChildUserNameTAG: ggkoumas
SecondChildCreateTimeTAG: 2013-02-21T18:56:06Z
SecondChildVoteTAG: 0
SecondChildTAG: Unless Google2SRT has been fixed, this is not available. It was always a race for Google2SRT to keep up with changes in the presentation format by YouTube. The last time I tried this, it could not locate the SRT files.
SecondChildUserIdTAG: 441413
SecondChildUserNameTAG: coyotecoach
SecondChildCreateTimeTAG: 2013-02-21T19:44:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Are the youtube videos "the" lectures? The intro lecture pops up when you click "intro" in the courseware. How do you find Lec1.2 and Lec1.3? I see them referenced under exercise 1.... the organization of what is where makes no sense to me at all.
SecondChildUserIdTAG: 975799
SecondChildUserNameTAG: lmacareo
SecondChildCreateTimeTAG: 2013-02-23T02:41:53Z
SecondChildVoteTAG: 0
IndexTAG: 2867
TitleTAG: lecture notes
Can we please have lecture notes in a PDf format so that we can download and read. helps if video/audio not clear.
thanks
Madhuri
UserIdTAG: 258527
UserNameTAG: drmadhurichandra
CreateTimeTAG: 2013-02-21T17:07:21Z
VoteTAG: 7
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Thank you Madhuri, I am also begging for the same. The PDF downloads can be very help full if want to read in a public place incase do not have head sets or better still download when have internet access and read later since may not have access to internet all through the exercise or when reading.
Thanks Albert.
FirstChildUserIdTAG: 691586
FirstChildUserNameTAG: twinoalbo
FirstChildCreateTimeTAG: 2013-02-21T18:33:02Z
FirstChildVoteTAG: 1
SecondChildTAG: The PDf will be very much helpful to me and I do think to other students because internet connectivity is not as fast in my country, so I often have difficulty viewing video files. Thank you
SecondChildUserIdTAG: 787228
SecondChildUserNameTAG: RutazDamian
SecondChildCreateTimeTAG: 2013-02-21T18:50:08Z
SecondChildVoteTAG: 0
SecondChildTAG: The pdf files, and audio files that I can listen to offline would both be helpful.
SecondChildUserIdTAG: 1009037
SecondChildUserNameTAG: rorywilsonis
SecondChildCreateTimeTAG: 2013-02-21T19:00:03Z
SecondChildVoteTAG: 0
IndexTAG: 2868
TitleTAG: Ex2 P3
Hi
It looks to me that all chart are wrong, I wanted to check chart #3 but the bin of 16-17 is missing and that should be a two modal chart since is has two high density bins
can anyone explain this?
Moshiko
UserIdTAG: 1240022
UserNameTAG: Moshiko
CreateTimeTAG: 2013-02-21T16:51:34Z
VoteTAG: 2
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: I need help with that as well.
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-21T17:08:30Z
FirstChildVoteTAG: 2
FirstChildTAG: Hi,
I agree, the chart seems to be off. Based on the table, there should be six bins, not five. Also, the height of the second bin should be about 0.02 (as it is built based on the 7% observations spread over 3 years of schooling), while the height of the third bin should be 0.30, etc...
Could someone explain?
Thank you!
FirstChildUserIdTAG: 511399
FirstChildUserNameTAG: leylae
FirstChildCreateTimeTAG: 2013-02-21T18:15:36Z
FirstChildVoteTAG: 0
FirstChildTAG: Please remember the honor code. No discussion until the deadline has elapsed.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T19:44:14Z
FirstChildVoteTAG: 0
FirstChildTAG: It seems to be a tricky exercise :) One chart must be selected. Grader produces that nice red 'X' ;-) if the exercise is submitted with no selections.
FirstChildUserIdTAG: 461686
FirstChildUserNameTAG: atopos
FirstChildCreateTimeTAG: 2013-02-22T00:23:37Z
FirstChildVoteTAG: 0
FirstChildTAG: The values in the chart are incorrect, however there's only one "type" of chart that answers the question. And I think they have aggregated the 5th and 6th bin.
FirstChildUserIdTAG: 31693
FirstChildUserNameTAG: sjfeg
FirstChildCreateTimeTAG: 2013-02-22T13:52:30Z
FirstChildVoteTAG: 0
IndexTAG: 2869
TitleTAG: Ex2 p4
Why not to assume a uniform distribution of educational level in each interval? Please help me understand
UserIdTAG: 159507
UserNameTAG: manirana
CreateTimeTAG: 2013-02-21T16:24:46Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: uniform distribution of educational level in each interval would result in each interval to have similar percentage share
best regards
Jakub
FirstChildUserIdTAG: 1263818
FirstChildUserNameTAG: Ruteq
FirstChildCreateTimeTAG: 2013-02-21T16:40:17Z
FirstChildVoteTAG: 0
FirstChildTAG: Sorry, Ruteq, that's not true, as the intervals are of different widths. Also, I believe the question here is whether the distribution is uniform WITHIN each interval, not across various different intervals.
Manirana, since this is a hw exercise which is not yet due, I won't discuss the exact details, but it will help you to think about the previous parts of the question, e.g. about people who finish high school and go no further. Think about them, and compare with others in their interval.
Prof. A.
FirstChildUserIdTAG: 1019686
FirstChildUserNameTAG: AniAdhikari
FirstChildCreateTimeTAG: 2013-02-21T16:57:59Z
FirstChildVoteTAG: 0
FirstChildTAG: I am also unsure about why this problem is being scored as it is. I would be very eager to discuss the details after the due date.
FirstChildUserIdTAG: 597934
FirstChildUserNameTAG: TPerez
FirstChildCreateTimeTAG: 2013-02-21T17:32:03Z
FirstChildVoteTAG: 0
IndexTAG: 2870
TitleTAG: Exercise 2.2 (a)
Hi guys!
I have a question about the first exercise about lecture 2.2. According to the formula the height of the bar in the histogram is (%/width). Shouldn't the width be 20-(-10)=30 and so the height 14/30?
Thanks!
UserIdTAG: 1023413
UserNameTAG: Atreviso
CreateTimeTAG: 2013-02-21T16:16:30Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: I came up with the same answer for width as you, and it appears others did too so I'm thinking it was just an error, perhaps whomever created the question entered 20-10 as opposed to 20-(-10).
FirstChildUserIdTAG: 824186
FirstChildUserNameTAG: jN7
FirstChildCreateTimeTAG: 2013-02-21T16:28:08Z
FirstChildVoteTAG: 3
SecondChildTAG: It sure looks like error, I think there is reply from staff about this but I can't find exact forum message now.
SecondChildUserIdTAG: 127421
SecondChildUserNameTAG: apbyte
SecondChildCreateTimeTAG: 2013-02-21T16:29:27Z
SecondChildVoteTAG: 0
FirstChildTAG: im so confused on this one..where does the 14 come from?
FirstChildUserIdTAG: 1220167
FirstChildUserNameTAG: maxinerae87
FirstChildCreateTimeTAG: 2013-02-21T16:38:43Z
FirstChildVoteTAG: 0
SecondChildTAG: If you click on one of the links it will guide you to a table with 100 data elements(Sorted gravity data). In that table between -10 and 20 there are 14 data elements. And 14 is 14% of 100.
SecondChildUserIdTAG: 46554
SecondChildUserNameTAG: Szenko
SecondChildCreateTimeTAG: 2013-02-21T18:22:47Z
SecondChildVoteTAG: 0
IndexTAG: 2871
TitleTAG: Exercise Set 2-1 - BUG, MISTAKE
Exercise 2-1 asks, "Which interval contained more people: 5-15 or 15-20?
The percent for 5-15 is 13.7
The percent for 15-20 is 7.1
Yet, I chose 5-15 and was marked wrong.
Isn't the point of this question that the 15-20 range is more dense but the 5-15 range has more people?
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-21T16:11:18Z
VoteTAG: 4
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NumberOfReplyTAG: 1
FirstChildTAG: See the professor's answer in the discussion linked below and please try and search existing discussions before posting problems: https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
FirstChildUserIdTAG: 1268175
FirstChildUserNameTAG: MarquisDeMizzle
FirstChildCreateTimeTAG: 2013-02-21T16:18:12Z
FirstChildVoteTAG: 1
IndexTAG: 2872
TitleTAG: Hello everyone.....
Today I completed the three exercise tests,so I would like to know,when will be the next tests available?From when can I get my Lectures & further exercises after exercise 3?Also I had checked my answers so it is automatically saved?So,thought of getting some help out here in these two things....
UserIdTAG: 1177236
UserNameTAG: SOHAM1989
CreateTimeTAG: 2013-02-21T16:01:26Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I'll tackle your questions in order:
1 )Check the Course Schedule - https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Course_Schedule.pdf - to see when the next set of exercises are released. It says 27 Feb.
2) Same as 1, see the Course Schedule.
3) You are correct, when you submit your answers, thyey are automatically saved and your progress is recorded.
Hope this helps!
FirstChildUserIdTAG: 142402
FirstChildUserNameTAG: aaronrod
FirstChildCreateTimeTAG: 2013-02-21T18:47:26Z
FirstChildVoteTAG: 0
IndexTAG: 2873
TitleTAG: Ex set 2 (*)
Why 13.5% of Senior Cit. isn't correct? I mean, if there are 0.83333% (12.5/15) of people per year in the interval 60-75, there are 7.5% of people in the interval 66-75 and 7.5 + 6.0 = 13.5
UserIdTAG: 110987
UserNameTAG: Matias208
CreateTimeTAG: 2013-02-21T16:00:46Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I have also done that but me too got it wrong...I would also like to know if there is any other concept out here,please help me too..
FirstChildUserIdTAG: 1177236
FirstChildUserNameTAG: SOHAM1989
FirstChildCreateTimeTAG: 2013-02-21T16:03:02Z
FirstChildVoteTAG: 0
SecondChildTAG: 12.5/15=0.83; 0.83*10+6.0=14.3 Is this answer correct?
SecondChildUserIdTAG: 1239689
SecondChildUserNameTAG: Jamie425
SecondChildCreateTimeTAG: 2013-02-21T16:17:10Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes
SecondChildUserIdTAG: 1267277
SecondChildUserNameTAG: margaretha
SecondChildCreateTimeTAG: 2013-02-21T16:24:35Z
SecondChildVoteTAG: 0
SecondChildTAG: But should it be 0.83*9 instead or 0.83*10 if we are looking for people OVER 65? What am I missing?
SecondChildUserIdTAG: 344405
SecondChildUserNameTAG: AMariani
SecondChildCreateTimeTAG: 2013-02-21T17:07:33Z
SecondChildVoteTAG: 0
SecondChildTAG: That's what I got Jamie
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-21T17:10:14Z
SecondChildVoteTAG: 0
SecondChildTAG: I got 14.3% and it marked it wrong! Help please
SecondChildUserIdTAG: 1187096
SecondChildUserNameTAG: Chinonso411
SecondChildCreateTimeTAG: 2013-02-21T18:42:49Z
SecondChildVoteTAG: 0
SecondChildTAG: Q says above 65 year, so 65 itself becomes an exclusion and thus should not be part of section of interval being considered. 66-100 is the range which should be considered.
SecondChildUserIdTAG: 971465
SecondChildUserNameTAG: RajSingh81
SecondChildCreateTimeTAG: 2013-02-21T21:51:25Z
SecondChildVoteTAG: 0
IndexTAG: 2874
TitleTAG: Unofficial Class Calendar on Google
Using the current [Lecture, Exercise Set, and Exam Schedule][1] document, I created a public Google calendar that anyone can subscribe to or view online. **Note - this is not an official calendar for the class!** You can access the calendar in one of several ways:
- [HTML][2]
- [iCal][4]
- [XML][3]
All exercise sets are listed as being due at 23:30 GMT on the date listed in the schedule. I didn't include times for the midterm or final as none are listed in the schedule.
Please let me know if you have any corrections. I'll do my best to keep it current.
[1]: https://www.edx.org/c4x/BerkeleyX/Stat2.1x/asset/Course_Schedule.pdf
[2]: http://bit.ly/VzaBAI
[3]: http://bit.ly/15yL5Qb
[4]: http://bit.ly/YF9r5j
UserIdTAG: 1116003
UserNameTAG: umeditor
CreateTimeTAG: 2013-02-21T15:53:26Z
VoteTAG: 9
CoursewareTAG: undefined
NumberOfReplyTAG: 6
FirstChildTAG: This is great, thank you so much! :D
FirstChildUserIdTAG: 859593
FirstChildUserNameTAG: AlvFdezFdez
FirstChildCreateTimeTAG: 2013-02-21T16:24:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Thank you SO much! ;-)
FirstChildUserIdTAG: 933606
FirstChildUserNameTAG: charlesfactor77
FirstChildCreateTimeTAG: 2013-02-21T17:48:42Z
FirstChildVoteTAG: 0
FirstChildTAG: Update 1: I've moved the due date for all exercise sets to Wednesdays, per the email from Professor Adhikari. I didn't move exercise set 12 as there is no corresponding Wednesday; the last class is on a Tuesday.
FirstChildUserIdTAG: 1116003
FirstChildUserNameTAG: umeditor
FirstChildCreateTimeTAG: 2013-02-21T21:40:59Z
FirstChildVoteTAG: 2
SecondChildTAG: Thank you, classmate!
SecondChildUserIdTAG: 933606
SecondChildUserNameTAG: charlesfactor77
SecondChildCreateTimeTAG: 2013-02-23T10:37:13Z
SecondChildVoteTAG: 0
FirstChildTAG: Update 2: I've moved exercise set 12 to March 25th per the updated schedule.
FirstChildUserIdTAG: 1116003
FirstChildUserNameTAG: umeditor
FirstChildCreateTimeTAG: 2013-02-25T15:04:08Z
FirstChildVoteTAG: 1
FirstChildTAG: Thanks!
FirstChildUserIdTAG: 521310
FirstChildUserNameTAG: Larry1964
FirstChildCreateTimeTAG: 2013-03-09T15:19:39Z
FirstChildVoteTAG: 0
SecondChildTAG: Glad to help.
SecondChildUserIdTAG: 1116003
SecondChildUserNameTAG: umeditor
SecondChildCreateTimeTAG: 2013-03-12T13:44:35Z
SecondChildVoteTAG: 0
FirstChildTAG: Update 3: I've updated the Midterm with the recent time and date details. Good luck to everyone!
FirstChildUserIdTAG: 1116003
FirstChildUserNameTAG: umeditor
FirstChildCreateTimeTAG: 2013-03-12T13:44:26Z
FirstChildVoteTAG: 0
IndexTAG: 2875
TitleTAG: Additional lecture per week
Since many of us travel and are unable to view the lectures every week, it would be useful to have an additional week of lectures ahead of time also available so that we can coordinate our viewing with travel and keep up with the lectures. This has worked well in other online courses I have taken
UserIdTAG: ANONYMOUS
UserNameTAG: ANONYMOUS
CreateTimeTAG: 2013-02-21T15:44:08Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: It would be great to have additional week ahead, i would solve some problems for me.
FirstChildUserIdTAG: 524447
FirstChildUserNameTAG: Dalius_LT
FirstChildCreateTimeTAG: 2013-02-26T15:15:06Z
FirstChildVoteTAG: 0
IndexTAG: 2876
TitleTAG: Ex set 2
Why the interval 5-15 contains more people than the interval 15-20? If 5-15 has 13.3%, Isn't that greater than the 7.1% of the 15-20 int?
UserIdTAG: 110987
UserNameTAG: Matias208
CreateTimeTAG: 2013-02-21T15:43:42Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 4
FirstChildTAG: I am also confused on this. Can anyone clarify?
FirstChildUserIdTAG: 54581
FirstChildUserNameTAG: rijultakkar
FirstChildCreateTimeTAG: 2013-02-21T15:48:20Z
FirstChildVoteTAG: 2
SecondChildTAG: You have to look at the difference of intervals
5-15 (10)
15-20 (5)
so you would have 13.3/10 and 7.1/5
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-21T16:27:57Z
SecondChildVoteTAG: 0
SecondChildTAG: But wouldn't that give us the density? We want to know the which has more population.
SecondChildUserIdTAG: 54581
SecondChildUserNameTAG: rijultakkar
SecondChildCreateTimeTAG: 2013-02-21T16:28:57Z
SecondChildVoteTAG: 0
SecondChildTAG: Exactly! That should give us the density and that's ehat the next question asks for!
SecondChildUserIdTAG: 427652
SecondChildUserNameTAG: KostasKotoulas
SecondChildCreateTimeTAG: 2013-02-21T16:37:28Z
SecondChildVoteTAG: 0
FirstChildTAG: percentage given in the table corresponds to the frequency or fraction of individuals in an age group. in relation to total population.
so it follows that the higher the percentage the higher the number of people.
example: in a population of 1000 people 13% is 130
7% is 70
FirstChildUserIdTAG: 875906
FirstChildUserNameTAG: AzizAlkhater
FirstChildCreateTimeTAG: 2013-02-21T15:59:44Z
FirstChildVoteTAG: 0
SecondChildTAG: Yes, I get it. But what's your point. People in the age group 5-15 contribute to 13.3% of the "total population" and hence why shouldn't that be the answer?
SecondChildUserIdTAG: 54581
SecondChildUserNameTAG: rijultakkar
SecondChildCreateTimeTAG: 2013-02-21T16:09:30Z
SecondChildVoteTAG: 0
SecondChildTAG: it is the answer, there are more people in the 5-15 group, that is if you are referring to question a), however if it is b) that is confusing you the correct answer is the one that result in a higher/taller bin, the height being =(percent/width of interval)
SecondChildUserIdTAG: 875906
SecondChildUserNameTAG: AzizAlkhater
SecondChildCreateTimeTAG: 2013-02-21T16:37:37Z
SecondChildVoteTAG: 0
SecondChildTAG: I am referring to question a)Which interval contained more people? I answered 5-15 and it says that's wrong.
SecondChildUserIdTAG: 54581
SecondChildUserNameTAG: rijultakkar
SecondChildCreateTimeTAG: 2013-02-21T16:56:03Z
SecondChildVoteTAG: 0
SecondChildTAG: well actually you answered correctly, but the system returned an error because it was programmed with the wrong answer. Professor is aware of problem and you will get credit.
SecondChildUserIdTAG: 875906
SecondChildUserNameTAG: AzizAlkhater
SecondChildCreateTimeTAG: 2013-02-21T17:16:13Z
SecondChildVoteTAG: 0
SecondChildTAG: just to make happy go to the link below and see comment by Professor at bottom of page.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
SecondChildUserIdTAG: 875906
SecondChildUserNameTAG: AzizAlkhater
SecondChildCreateTimeTAG: 2013-02-21T17:19:14Z
SecondChildVoteTAG: 0
FirstChildTAG: You have to look at the difference of intervals
5-15 (10) 15-20 (5)
so you would have 13.3/10 and 7.1/5
FirstChildUserIdTAG: 1018852
FirstChildUserNameTAG: sansquamtch
FirstChildCreateTimeTAG: 2013-02-21T16:35:27Z
FirstChildVoteTAG: 0
SecondChildTAG: No, that is the density (how crowded is the interval).
SecondChildUserIdTAG: 427652
SecondChildUserNameTAG: KostasKotoulas
SecondChildCreateTimeTAG: 2013-02-21T16:38:25Z
SecondChildVoteTAG: 0
SecondChildTAG: Oh sorry, I read it wrong.
SecondChildUserIdTAG: 1018852
SecondChildUserNameTAG: sansquamtch
SecondChildCreateTimeTAG: 2013-02-21T17:14:02Z
SecondChildVoteTAG: 0
FirstChildTAG: This is error, see main topic here with professor confirm.
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
FirstChildUserIdTAG: 127421
FirstChildUserNameTAG: apbyte
FirstChildCreateTimeTAG: 2013-02-21T16:35:49Z
FirstChildVoteTAG: 0
SecondChildTAG: Good to see that.
SecondChildUserIdTAG: 54581
SecondChildUserNameTAG: rijultakkar
SecondChildCreateTimeTAG: 2013-02-21T16:59:32Z
SecondChildVoteTAG: 0
IndexTAG: 2877
TitleTAG: Please, expressly define "Greenwhich Mean Time"(GMT). Consider the ambiguity about whether or not "zero hours corresponds to "mid-night" or "noon"?
I am not sure at this point which way this 24 hour clock is running and I am trying to sync a calendar I have built with time zone support for the events. Any clarity would be greatly appreciated!
UserIdTAG: 1154718
UserNameTAG: Anti-gravity42
CreateTimeTAG: 2013-02-21T15:42:22Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: GMT is the time defined for Great Britain, Portugal and other countries.
[http://en.wikipedia.org/wiki/Gmt][1]
it corresponds to EST + 5 hours. it is later in the day in Great Britain 5 hours than it is in USA East Coast.
not only in GMT but in all time zones:
00:00 corresponds to midnight
12:00 corresponds to noon
I suppose zero hours corresponds to midnight.
but for the exercise sets available so far, the deadline is set to 23:30 which unambiguously refer to 11 hours and 30 minutes PM.
[1]: http://GMT%20in%20Wikipedia
FirstChildUserIdTAG: 916555
FirstChildUserNameTAG: josecanica
FirstChildCreateTimeTAG: 2013-02-21T15:50:16Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you for the help here. I got confused precisely because of the Wikipedia article you reference. It discusses this "ambiguity" therein?
If you might speak to that, and for the "time" being I will greatfully accept your explanation.
SecondChildUserIdTAG: 1154718
SecondChildUserNameTAG: Anti-gravity42
SecondChildCreateTimeTAG: 2013-02-21T16:25:26Z
SecondChildVoteTAG: 0
FirstChildTAG: The day starts at 00:00:00 (12 PM) and ends at 23:59:59, the next second, ends the day.
FirstChildUserIdTAG: 66629
FirstChildUserNameTAG: jilanca
FirstChildCreateTimeTAG: 2013-02-21T16:15:07Z
FirstChildVoteTAG: 0
SecondChildTAG: Do you mean twelve AM (00:00:000) for the time you mention, at which,the day starts?
SecondChildUserIdTAG: 1154718
SecondChildUserNameTAG: Anti-gravity42
SecondChildCreateTimeTAG: 2013-02-21T16:22:01Z
SecondChildVoteTAG: 0
SecondChildTAG:
Also, I built a calendar in "ical" and it has "time zone" support wherein I could sync the events/assignment due dates to make this conversion and allow me to see it relative to EST. I found that it made some of the events at 7:30 and others at 8:30 does this reflect a shift/ "Spring forward" at some time in the near future for that time zone? In other words does the GMT employ a daylight savings convention per some near date?
SecondChildUserIdTAG: 1154718
SecondChildUserNameTAG: Anti-gravity42
SecondChildCreateTimeTAG: 2013-02-21T16:30:05Z
SecondChildVoteTAG: 0
SecondChildTAG: the daylight time shifts at 31-3-2013
fot GMT
SecondChildUserIdTAG: 1195844
SecondChildUserNameTAG: irenelok82
SecondChildCreateTimeTAG: 2013-02-21T18:26:13Z
SecondChildVoteTAG: 0
FirstChildTAG: To avoid these types of discussion, I really cannot understand why we do not use the unambiguous 24 hour clock which runs from 00:00 (midnight) to 23:59:59. As they say in. British advert - simples.
Greenwich Meantime (GMT) because London is where longitude is at zero degrees. All other times emanate from there.
For this course 23:30 seems pretty unambiguous though.
FirstChildUserIdTAG: 20879
FirstChildUserNameTAG: forevergreen
FirstChildCreateTimeTAG: 2013-02-21T16:30:06Z
FirstChildVoteTAG: 0
SecondChildTAG: yes, unambiguous seems a good word.
23:30 leaves no doubts to me. I have until 23:29 to crack my head ahahahahah
:)
SecondChildUserIdTAG: 916555
SecondChildUserNameTAG: josecanica
SecondChildCreateTimeTAG: 2013-02-21T16:50:02Z
SecondChildVoteTAG: 0
IndexTAG: 2878
TitleTAG: Error on schedule for exercise set 9
The current schedule list exercise set 9 as being due on Friday, March 16, which can't be correct - March 16th is a Saturday. Is it supposed to be Friday, March 15?
UserIdTAG: 1116003
UserNameTAG: umeditor
CreateTimeTAG: 2013-02-21T15:39:40Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: You know, it appears that this has occurred on a couple of the dates, I am wondering if it is the result of GMT?
FirstChildUserIdTAG: 1154718
FirstChildUserNameTAG: Anti-gravity42
FirstChildCreateTimeTAG: 2013-02-21T15:44:57Z
FirstChildVoteTAG: 0
SecondChildTAG: It might be. Hopefully someone from the course can get the document updated.
SecondChildUserIdTAG: 1116003
SecondChildUserNameTAG: umeditor
SecondChildCreateTimeTAG: 2013-02-21T15:56:29Z
SecondChildVoteTAG: 0
IndexTAG: 2879
TitleTAG: Incorrect answer given for an excersise in set 2
Now that the course is up and running, we can now concentrate on the subject of the course.
While working on exercise set 2
question a)Height of -10 to 20 bar, the answer given the explanation is *wrong*, the correct answer should be: 14/30 and not 14/10
since the the width of the bar = 20-(-10)=30
Good Luck all you wonderful global classmates and enjoy your course.
UserIdTAG: 875906
UserNameTAG: AzizAlkhater
CreateTimeTAG: 2013-02-21T15:37:46Z
VoteTAG: 9
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Glad to see that i was not the only one that had that issue.
FirstChildUserIdTAG: 1031310
FirstChildUserNameTAG: rheit
FirstChildCreateTimeTAG: 2013-02-21T16:08:26Z
FirstChildVoteTAG: 4
SecondChildTAG: Me too.
SecondChildUserIdTAG: 1267277
SecondChildUserNameTAG: margaretha
SecondChildCreateTimeTAG: 2013-02-21T16:22:21Z
SecondChildVoteTAG: 0
SecondChildTAG: Just got there and I was wondering whether I should post a comment, but fell onto yours. It has to be 30 and not 10 in the denominator.
SecondChildUserIdTAG: 427652
SecondChildUserNameTAG: KostasKotoulas
SecondChildCreateTimeTAG: 2013-02-21T16:28:44Z
SecondChildVoteTAG: 0
FirstChildTAG: This is well known, and has dozens of posts. See the errata page:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/wiki/Stat2.1x/courseware-errata/
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T23:12:48Z
FirstChildVoteTAG: 0
IndexTAG: 2880
TitleTAG: Problem 3 a)
Please explain the right answer.
Given the proportion 9:3:3:1, there fore adding we would get 16. Therefore, the number of magenta/green would be 9/16*500= 374 which is almost coinciding in the bar graph too.
UserIdTAG: 169509
UserNameTAG: rajeevbasapathy
CreateTimeTAG: 2013-02-21T15:33:29Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: why 500 ? and not 480?
FirstChildUserIdTAG: 610852
FirstChildUserNameTAG: maMykola
FirstChildCreateTimeTAG: 2013-02-21T15:39:55Z
FirstChildVoteTAG: 0
SecondChildTAG: 9:3:3:1 ratio is when the number of trees is 480.
SecondChildUserIdTAG: 610852
SecondChildUserNameTAG: maMykola
SecondChildCreateTimeTAG: 2013-02-21T15:43:47Z
SecondChildVoteTAG: 0
SecondChildTAG: In the next question, they ask you to add a new group (Green/Green) that has 20 trees in it. This will increase the total amt of trees to 500.
SecondChildUserIdTAG: 983599
SecondChildUserNameTAG: IvyGarson
SecondChildCreateTimeTAG: 2013-02-21T17:59:43Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, but ratio also change. With 20 green/green trees ratio is 27:9:9:3:2.
SecondChildUserIdTAG: 610852
SecondChildUserNameTAG: maMykola
SecondChildCreateTimeTAG: 2013-02-21T18:06:14Z
SecondChildVoteTAG: 0
IndexTAG: 2881
TitleTAG: Question 3.2 asks for fraction and correct answer must be a percent. Sorry to be a purest but I got it wrong at 7/10.
Can this be corrected??
UserIdTAG: 908129
UserNameTAG: WebbSF
CreateTimeTAG: 2013-02-21T15:27:46Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: I'm not sure just which question you are talking about. Set 3, question 2 are whole numbers. So I assume that is not what you mean?
FirstChildUserIdTAG: 629320
FirstChildUserNameTAG: SusanAust
FirstChildCreateTimeTAG: 2013-02-21T23:25:49Z
FirstChildVoteTAG: 0
IndexTAG: 2882
TitleTAG: Ex Set 1, Problem 1, b)
score on a test where each answer gets 5 points if it is right, and 0 points otherwise..
Can Some one please explain me the right answer?
Considering the final answer as right or wrong for 5 and 0 respectively, shouldn't the data be categorical?
UserIdTAG: 169509
UserNameTAG: rajeevbasapathy
CreateTimeTAG: 2013-02-21T15:26:15Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: I made the same mistake but it is not categorical.The score is a quantitiative discrete number isn't it ?
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-21T15:41:28Z
FirstChildVoteTAG: 0
SecondChildTAG: yes
SecondChildUserIdTAG: 266427
SecondChildUserNameTAG: RapidE
SecondChildCreateTimeTAG: 2013-02-21T15:58:41Z
SecondChildVoteTAG: 0
SecondChildTAG: it is mentioned in the video that test score is considered as discrete but can be considered as continuous which will b explained in another lecture.
SecondChildUserIdTAG: 1048539
SecondChildUserNameTAG: Reham1989
SecondChildCreateTimeTAG: 2013-02-21T16:13:35Z
SecondChildVoteTAG: 0
FirstChildTAG: The problem is that you have a test where **each** answer is scored with 5 or 0. The value for the entire test will have a maximum of 5 times the number of answers, so if you have, say, 10 answers in the test every student will score a value between 0 and 50 with an interval of 5 (5, 10, 15 etc.).
Remember: Categorical variables do **not** have any natural order between them!
FirstChildUserIdTAG: 1099041
FirstChildUserNameTAG: KristinB
FirstChildCreateTimeTAG: 2013-02-21T16:01:31Z
FirstChildVoteTAG: 0
FirstChildTAG: The question is asking about test score - in point basis. So we know that this is quantitative variable. And since the scores can only by 5 or 0, this means that they are discrete or separate. There can't be any arbitrary points in between 0 and 5. It cannot be 0.1,...0.12,...0.5...1,...5. It is either 0 points or 5 points. So it's cannot be Quantitative which I will assume to represent Continuous Quantitative variable.
FirstChildUserIdTAG: 861599
FirstChildUserNameTAG: Nam2point0
FirstChildCreateTimeTAG: 2013-02-21T19:07:20Z
FirstChildVoteTAG: 0
IndexTAG: 2883
TitleTAG: lecture1.3
Hi, i wrote 11.11 and 22.22 for answers to 1.3(1)(a)(1) and 1.3(1(a)(3) and both were marked wrong. :-(
UserIdTAG: 902930
UserNameTAG: DamnLies
CreateTimeTAG: 2013-02-21T15:03:31Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Have you searched the forum? There are a few posts on this topic already.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T15:05:22Z
FirstChildVoteTAG: 0
SecondChildTAG: Because it only admits one decimal number. I had the same mistake too
SecondChildUserIdTAG: 65048
SecondChildUserNameTAG: Adolfojambrina
SecondChildCreateTimeTAG: 2013-02-21T16:21:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks @jimbangun. You caught me napping. Will be more careful next time.
SecondChildUserIdTAG: 902930
SecondChildUserNameTAG: DamnLies
SecondChildCreateTimeTAG: 2013-02-22T17:13:28Z
SecondChildVoteTAG: 0
IndexTAG: 2884
TitleTAG: calculator
the course must have a calculator!!!!!!!
UserIdTAG: 265077
UserNameTAG: VIDALITA
CreateTimeTAG: 2013-02-21T14:57:31Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Modern computers and operating software usually comes with a built in calculator software. But in saying that, out of the 5 edX courses I have taken, only 1 has provided a calculator on the bottom right of the course page.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T15:03:58Z
FirstChildVoteTAG: 0
FirstChildTAG: There is calculator provided:
http://statistics.berkeley.edu/~stark/SticiGui/Text/histograms.htm
Click on "Menu" on the top left corner.
FirstChildUserIdTAG: 933606
FirstChildUserNameTAG: charlesfactor77
FirstChildCreateTimeTAG: 2013-02-21T15:28:07Z
FirstChildVoteTAG: 1
IndexTAG: 2885
TitleTAG: [STUDENTS] : Please read
For the sake of the discussion forum effectiveness, please put some effort and use the SEARCH function BEFORE posting your questions.
Most likely issues on graders, tests, etc. would have been asked by another student to which the staff could have already posted an answer/reply.
Thanks!
UserIdTAG: 170290
UserNameTAG: jimbangun
CreateTimeTAG: 2013-02-21T14:56:49Z
VoteTAG: 20
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: seriously people do this ,really I understand wanting someone to answer your question specifically ,but the constant hellos and duplicate questions get old (a suggestion to edx ,get a dislike button or these forums will be useless eventually )
FirstChildUserIdTAG: 20186
FirstChildUserNameTAG: vikashx1
FirstChildCreateTimeTAG: 2013-02-26T00:45:22Z
FirstChildVoteTAG: 3
IndexTAG: 2886
TitleTAG: Just 35% for passing?
Shouldn't it be at least 50-60? I get that the main goal of the course is the difference between what you'll know after the course ends and what you knew before you started regarding the subject, but since grades&certificates are involved imo the passing bar should be raised, giving the certificate a greater value. Thanks!
UserIdTAG: 22929
UserNameTAG: kraster
CreateTimeTAG: 2013-02-21T14:55:26Z
VoteTAG: 8
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Dear Kraster,
I had signed up for the ph207x course offered by HarvardX earlier. They had a cut-off of 80 or 85% (can't remember exact value) for passing. I tried keeping up with the required level for 2-3 weeks, then gave up since I realized that it was extremely stressful. I stopped active participation soon after, choosing only to download the courseware instead.
I appreciate the "low" cut-off primarily on account of it eliminating anxiety associated with evaluation and allowing us to concentrate on learning rather than just trying to "somehow make the grade" (even if at the expense of true learning).
This way passing becomes secondary to learning- the real purpose of offering these courses in this manner.
I would suggest that "certificates of distinction" be offered to those who score >75 or 80%, though.
Regards,
Give2Receive
FirstChildUserIdTAG: 600581
FirstChildUserNameTAG: Give2Receive
FirstChildCreateTimeTAG: 2013-02-21T15:31:24Z
FirstChildVoteTAG: 11
SecondChildTAG: I've done ph207x and although i found myself the cutoff challeging at the beginning, it actually made me be more precise and paying more attention before submitting and revisiting the stuff I've had for the exam. It just seems to easy, since you can do 35% easily only from homeworks.
And since the learning is the real purpose as you say, why then bother with the certificate? And yea, i've passed ph207x although I'm far from related to medical field and that cutoff was a big part of what motivated me to understand better and look deeper on the internet for things i didn't know.
SecondChildUserIdTAG: 22929
SecondChildUserNameTAG: kraster
SecondChildCreateTimeTAG: 2013-02-21T16:48:46Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, the cutoff for PH207x was brutal - and it was relaxed a tad to 80% once they reviewed the overall marks.
A high standard meant you took care in your answers. Unfortunately it also encouraged the outsourcing of some questions, as for some the certificate meant everything. The learning was optional. But I think that (breaking honour code) will happen regardless of the certificate mark. It is just a sad fact of life.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-21T23:30:16Z
SecondChildVoteTAG: 0
IndexTAG: 2887
TitleTAG: Exercise set 2-problem 7
Anyone has any idea on how to proceed with the problem ?? I think the area or something needs to be given in order to proceed with the calculation.
UserIdTAG: 1078880
UserNameTAG: chetansrinivas93
CreateTimeTAG: 2013-02-21T14:52:49Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: This is actually not that complex. I suggest reviewing the lectures, somewhere about the maximum percentage. Sorry, can't say anymore without possibly breaking the honor code.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T15:01:46Z
FirstChildVoteTAG: 2
SecondChildTAG: Yes thank you. I appreciate it.
SecondChildUserIdTAG: 1078880
SecondChildUserNameTAG: chetansrinivas93
SecondChildCreateTimeTAG: 2013-02-22T13:28:01Z
SecondChildVoteTAG: 0
IndexTAG: 2888
TitleTAG: Courseware
I can't view the courseware.
UserIdTAG: 537551
UserNameTAG: elginalim
CreateTimeTAG: 2013-02-21T14:50:00Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2889
TitleTAG: Firefox histograms?
I had a problem seeing histograms of Ex1 in Firefox. Maybe it only happened to me but if not, could this problem, please, be considered for fixing? Thank you in advance.
UserIdTAG: 1218100
UserNameTAG: Draxita
CreateTimeTAG: 2013-02-21T14:34:10Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2890
TitleTAG: Practice for Exercise Set 1
I've just had a little play with Exercise Set 1 and noticed that the Question concerning Percentage of Students requires an answer to just 1 decimal place. My initial answer contained 2 decimal places and was marked as incorrect. The same can be said for entering the nearest whole number in that it is also marked incorrect.
Will there be greater clarity in future exercise sets regarding accuracy of the final answer to a particular format constraint?
UserIdTAG: 16957
UserNameTAG: DavidXRobinson
CreateTimeTAG: 2013-02-21T14:24:16Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Hi David,
I had the percent answers incorrect as well because I am used to writing percents in decimal form. I hope for either clarification or consistency as well.
FirstChildUserIdTAG: 1021739
FirstChildUserNameTAG: ERitsema
FirstChildCreateTimeTAG: 2013-02-21T14:35:15Z
FirstChildVoteTAG: 0
FirstChildTAG: Just a note, students should really start using the search feature to avoid multiple posts of the same subject. There are already plenty of posts on the grader errors, in Ex1 and 2.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T14:47:16Z
FirstChildVoteTAG: 0
IndexTAG: 2891
TitleTAG: Course Progress/scores?
I thought I was doing pretty well (having not done any maths study for 28 years) but despite the fact that I've scored 90% (or over) in the first three tests the progress bars are in red and I'm showing a graded exercises average of 27% and a graded exercises total of 14%.
Am I missing something here? Is this a cumulative score and therefore having only completed 3 of a possible 12 tests I've nothing to worry about. Or will I need to achieve 100% in all the remaining tests to achieve a pass?
:-(
UserIdTAG: 1184906
UserNameTAG: TheAdamGray
CreateTimeTAG: 2013-02-21T14:22:21Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Hover your mouse on each red bar and you should see the actual score for each. The scores on the right hand side of the progress is the average or cumulative. We have only done 3 tests so you are fine. The red color has nothing to do with your achievement, it is just the color edX decided to use.
FirstChildUserIdTAG: 170290
FirstChildUserNameTAG: jimbangun
FirstChildCreateTimeTAG: 2013-02-21T14:39:34Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks Jim...earlier today I went from a position of mild smugness to mild panic in just under 90 seconds!
SecondChildUserIdTAG: 1184906
SecondChildUserNameTAG: TheAdamGray
SecondChildCreateTimeTAG: 2013-02-21T14:42:13Z
SecondChildVoteTAG: 0
SecondChildTAG: No worries...good job on the scores, by the way.
SecondChildUserIdTAG: 170290
SecondChildUserNameTAG: jimbangun
SecondChildCreateTimeTAG: 2013-02-21T14:44:40Z
SecondChildVoteTAG: 0
SecondChildTAG: Thanks...I'm a bit annoyed that I didn't get them all correct...made the schoolboy error of not reading the question twice! Silly mistakes...always silly mistakes. :-/
SecondChildUserIdTAG: 1184906
SecondChildUserNameTAG: TheAdamGray
SecondChildCreateTimeTAG: 2013-02-21T14:48:01Z
SecondChildVoteTAG: 0
SecondChildTAG: I had the same problem as u ,TheaAdamGray, and I was just like :0
jimbangun, do u mean the average and total scores are low because we haven't finished the whole exercises yet? So, at the end of the course they will be much higher?
Thanks
SecondChildUserIdTAG: 1048539
SecondChildUserNameTAG: Reham1989
SecondChildCreateTimeTAG: 2013-02-22T11:52:23Z
SecondChildVoteTAG: 0
IndexTAG: 2892
TitleTAG: "Check" vs. "Save" in exercises
I just completed the first part of Exercise 1 and didn't realize that the "Check" button actually submitted/saved my answers. So now it appears as though I got two of those questions wrong even though I didn't mean to _submit_ them.
The "Check" button in the other sections work as I expect - it allows me to check my answers *before* I submit them.
Has anyone else run into this issue?
Thanks
UserIdTAG: 814198
UserNameTAG: rmangino
CreateTimeTAG: 2013-02-21T14:20:44Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: The "Check" button always submits your answers. In the practices, the answers are not graded, so you can submit (= check) your answers as often as you'd like.
In the excercises, however, it does not really make sense to see the correct answer before you submit your own, so you can only save or check, but not see the answer before checking. Otherwise, everybody would just have perfect answers in all excercises, it just doesn't make sense.
FirstChildUserIdTAG: 1099041
FirstChildUserNameTAG: KristinB
FirstChildCreateTimeTAG: 2013-02-21T15:18:23Z
FirstChildVoteTAG: 0
SecondChildTAG: Thank you for your response. If Check submits then why does the Save button exist? (so that I can finish the exercise later?) I ask because I don't want to make the same mistake again.
SecondChildUserIdTAG: 814198
SecondChildUserNameTAG: rmangino
SecondChildCreateTimeTAG: 2013-02-21T15:23:52Z
SecondChildVoteTAG: 0
SecondChildTAG: Yes, by using the Save button you can "record" your answer without it being graded if you are not sure, so you do not have to write down your assumption elsewhere. You can even log out and start over on another computer, your saved answer will still be there.
Before the actual course material was uploaded, there was a nice introduction video with tests and exams just for trying all this stuff out, this is where I found out. It seems to be gone now...
SecondChildUserIdTAG: 1099041
SecondChildUserNameTAG: KristinB
SecondChildCreateTimeTAG: 2013-02-21T16:07:04Z
SecondChildVoteTAG: 0
IndexTAG: 2893
TitleTAG: Video and other suggestions
Could we have the video of the person giving the lecture? It makes it more interactive with emotions rather than drab numbers. Also provide PDF copies of the slides/jotters. A download link to video would be helpful. Since most of us are working, it is good to have week end deadlines rather than throughout the whole week. It really is tough to complete assignments with diferring time schedules.
UserIdTAG: 569767
UserNameTAG: SanjayS72
CreateTimeTAG: 2013-02-21T14:18:20Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 1
FirstChildTAG: Videos did not show up in my account :( why is that soo????
FirstChildUserIdTAG: 737976
FirstChildUserNameTAG: Vexin
FirstChildCreateTimeTAG: 2013-02-21T14:55:09Z
FirstChildVoteTAG: 1
IndexTAG: 2894
TitleTAG: pdf materials needed
Hello,
We would request pdf materials apart from videos, as our internet connection is not fair enough.
Regards,
Pascal TSHIMANGA
UserIdTAG: 611586
UserNameTAG: Tshimanga
CreateTimeTAG: 2013-02-21T14:08:54Z
VoteTAG: 7
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: i truly agree with you.
FirstChildUserIdTAG: 1247759
FirstChildUserNameTAG: fessydamsel
FirstChildCreateTimeTAG: 2013-02-21T15:25:19Z
FirstChildVoteTAG: 1
FirstChildTAG: I second that.
FirstChildUserIdTAG: 933606
FirstChildUserNameTAG: charlesfactor77
FirstChildCreateTimeTAG: 2013-02-21T15:51:17Z
FirstChildVoteTAG: 1
IndexTAG: 2895
TitleTAG: Quantitative or quantitative discrete
What is weight? What is the difference between quantitative or qualitative discrete?
UserIdTAG: 1173402
UserNameTAG: beth-ann
CreateTimeTAG: 2013-02-21T14:07:03Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: weight is quantitative continuous, because it can be represented as a point along a continuous line. You can be 150 pounds, or 151 pounds, or anywhere in between. Maybe you're 150.0004321. How precisely you state your weight is only limited by how precise your scale is, and how much you care about precision.
Quantitative discrete is when only certain values make sense, and the values in between are impossible. The number of books on my table is five. The number on your table is six. I might add one book and then have as many as you do, but I wouldn't be moving through 5.01, 5.02, 5.03 on the way. When the number changes it changes in steps of one, and if I told you I have five and a quarter books on my table you'd laugh.
Hope that helps!
FirstChildUserIdTAG: 1154356
FirstChildUserNameTAG: TomFaber
FirstChildCreateTimeTAG: 2013-02-21T14:35:04Z
FirstChildVoteTAG: 6
FirstChildTAG: In exercise set 1 - Problem 1 - I marked that "weight to the nearest kilogram" is a quantitative variable but when I checked, it resulted to be a mistake.
Does it make any sense??
FirstChildUserIdTAG: 961907
FirstChildUserNameTAG: ngarin
FirstChildCreateTimeTAG: 2013-02-21T14:58:00Z
FirstChildVoteTAG: 0
SecondChildTAG: Well, would it make sense when someone asked you "what is your weight **to the nearest kilogram**" to answer 80.5, 77.51576 or 70 2/3?
SecondChildUserIdTAG: 1099041
SecondChildUserNameTAG: KristinB
SecondChildCreateTimeTAG: 2013-02-21T15:13:34Z
SecondChildVoteTAG: 0
SecondChildTAG: So then why is the answer, quantitative discrete and not quantitative?
SecondChildUserIdTAG: 1173402
SecondChildUserNameTAG: beth-ann
SecondChildCreateTimeTAG: 2013-02-21T15:29:50Z
SecondChildVoteTAG: 0
SecondChildTAG: Because the possible values for "weight to the nearest kilogram" is discrete! From my example above, this would be 81, 78 and 71 kg. While weight itself is continuous, weight to the nearest kilogram is discrete because the only possible values are whole numbers.
SecondChildUserIdTAG: 1099041
SecondChildUserNameTAG: KristinB
SecondChildCreateTimeTAG: 2013-02-21T15:54:55Z
SecondChildVoteTAG: 0
IndexTAG: 2896
TitleTAG: summary of section 2a
can one one do summary of section 2a,i will appreciate!
UserIdTAG: 1256626
UserNameTAG: Elibahati84
CreateTimeTAG: 2013-02-21T13:31:42Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2897
TitleTAG: There is not any link for videos
hello every one,
in my profile, I do not see any link for videos, is it for my browser? my browser is fire fox.
please help me
thanks
UserIdTAG: 1230477
UserNameTAG: masomeh
CreateTimeTAG: 2013-02-21T13:29:21Z
VoteTAG: 3
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Hello every one,
We have encountered the same problem: there is no download link. We would also request pdf materials as our Internet connection is not fair.
Cheers;
Pascal TSHIMANGA
(DRC/Kinshasa)
FirstChildUserIdTAG: 611586
FirstChildUserNameTAG: Tshimanga
FirstChildCreateTimeTAG: 2013-02-21T14:05:38Z
FirstChildVoteTAG: 2
FirstChildTAG: is youtube banned in your area?
FirstChildUserIdTAG: 899355
FirstChildUserNameTAG: nelolo
FirstChildCreateTimeTAG: 2013-02-21T14:09:29Z
FirstChildVoteTAG: 0
FirstChildTAG: Hi Everyone
Yes I have same problem , youtube is banned here in Iran
Regards
Mehran
FirstChildUserIdTAG: 931299
FirstChildUserNameTAG: MehranMohtadi
FirstChildCreateTimeTAG: 2013-02-21T14:55:16Z
FirstChildVoteTAG: 0
FirstChildTAG: yeah, in my area it´s not banned but it would help if i could download the video so i can view it correctly and without any pause .. does anyone knows if we can download any lecture video???
best regards
José
Perú
FirstChildUserIdTAG: 1166847
FirstChildUserNameTAG: Jriveraespejo
FirstChildCreateTimeTAG: 2013-02-21T15:35:50Z
FirstChildVoteTAG: 0
FirstChildTAG: I am using tubemate app for android and downloading the lectures on my smartphone so that I can view them at lesiure when I cannot access my computer.
FirstChildUserIdTAG: 1006030
FirstChildUserNameTAG: Prasannasimha
FirstChildCreateTimeTAG: 2013-02-21T15:46:21Z
FirstChildVoteTAG: 0
IndexTAG: 2898
TitleTAG: Hello
Hi everybody!
My name is Sávio and I'm from Vitória-Brazil.
UserIdTAG: 1036923
UserNameTAG: Bertochi
CreateTimeTAG: 2013-02-21T13:10:25Z
VoteTAG: 0
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: Hey Savio,
My name is Dave and I'm from the state of Rhode Island in the U.S.,
Goodluck....
FirstChildUserIdTAG: 1069519
FirstChildUserNameTAG: dwamback
FirstChildCreateTimeTAG: 2013-02-21T13:19:45Z
FirstChildVoteTAG: 0
SecondChildTAG: Hi everybody.
My name is Camilo, I am from Bogotá, Colombia
SecondChildUserIdTAG: 1173031
SecondChildUserNameTAG: ccgalindo
SecondChildCreateTimeTAG: 2013-02-21T14:04:15Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi nice to meet you. I'm Ana Maria from Medellin Colombia. Goodluck.....=D
SecondChildUserIdTAG: 1153452
SecondChildUserNameTAG: Anita910210
SecondChildCreateTimeTAG: 2013-02-21T14:57:38Z
SecondChildVoteTAG: 0
SecondChildTAG: Hi to all of you! My Name is Salomón, I'm from Perú best wishes!
SecondChildUserIdTAG: 1118636
SecondChildUserNameTAG: schambi
SecondChildCreateTimeTAG: 2013-02-21T15:35:36Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi,
I am Devanshi from India
FirstChildUserIdTAG: 1254655
FirstChildUserNameTAG: Devanshi1208
FirstChildCreateTimeTAG: 2013-02-21T13:42:28Z
FirstChildVoteTAG: 0
FirstChildTAG: Hello everyone,
My name is Demetria White from Jackson, MS. I am excited about working with each of you.
FirstChildUserIdTAG: 44587
FirstChildUserNameTAG: decled
FirstChildCreateTimeTAG: 2013-02-21T15:29:21Z
FirstChildVoteTAG: 0
IndexTAG: 2899
TitleTAG: lecture slides pdf copies
I have a same suggestion for obtaining lecture slides or pdf copies of the lectures. I cannot have a good internet connexion the whole day.So i am waiting it soon
UserIdTAG: 974147
UserNameTAG: scad
CreateTimeTAG: 2013-02-21T13:08:50Z
VoteTAG: 12
CoursewareTAG: undefined
NumberOfReplyTAG: 0
IndexTAG: 2900
TitleTAG: Why is income not considered discrete?
The correct answer in the quiz was that income is quantitative (and not discrete, because "quantitative discrete" was another possible answer). But money comes in discrete units - pennies. Why is 1/2 of a unit (the example in the lecture) a valid example of a quantitative discrete variable, but 1/100 of a unit not a valid example? These definitions seem to be of limited semantic utility.....
UserIdTAG: 141629
UserNameTAG: Neuronal
CreateTimeTAG: 2013-02-21T13:07:06Z
VoteTAG: 8
CoursewareTAG: undefined
NumberOfReplyTAG: 5
FirstChildTAG: Well, I think a variable such as "Income in thousands of dollars" would clearly have to be considered quantitative discrete, but if you have "income" only you could argue about that point... for example, if you ask people in different countries for their annual income, you might get answers like "40000 Euros, which corresponds to 52770.44855 USD according to the current exchange rate" - and here you have your continuous value. No one said you have to round to pennies. Another example is, you could use not the annual or monthly income but calculate the income per hour or minute (for some obscure reason, but it is definitely possible). Then you also might want to use more decimals.
FirstChildUserIdTAG: 1099041
FirstChildUserNameTAG: KristinB
FirstChildCreateTimeTAG: 2013-02-21T13:24:52Z
FirstChildVoteTAG: 3
FirstChildTAG: I also answered discrete and was marked incorrect for this. I disagree with the grader:
1. In the lecture, income is described as being counted in thousands of dollars. This is discrete.
2. If you go all the way and count it in dollars and/or cents, it still is discrete. There are no fractions of cents.
Even if you were to say "you can have fractions of dollars", it's not correct to say income is continous, because cents are money too, and they are discrete.
Edit: Also, as you say it can be discrete with increasing fractions like 1/100.
FirstChildUserIdTAG: 83185
FirstChildUserNameTAG: oysteingrondahl
FirstChildCreateTimeTAG: 2013-02-21T13:24:58Z
FirstChildVoteTAG: 4
FirstChildTAG: Because when you work with income ,it is dependent on the currency in question and also when you talk about income , you talk in terms of thousands of dollars p.a. so 1 dollar added or subtracted doesn't make a large difference .
So by definition .. it should be a continuous quantitative variable.
But when you talk per day income for labor in a currency like pounds. Then 1 pound change in income amounts to significance. so it becomes discrete.
Therefore we surely know that it is quantitative but it can be classified as both continuous and discrete in different situations. ( so you just can't pick one)
I Hope this helps you :-)
FirstChildUserIdTAG: 815079
FirstChildUserNameTAG: rchannan
FirstChildCreateTimeTAG: 2013-02-21T13:25:48Z
FirstChildVoteTAG: 0
SecondChildTAG: Thanks
SecondChildUserIdTAG: 266427
SecondChildUserNameTAG: RapidE
SecondChildCreateTimeTAG: 2013-02-21T16:00:05Z
SecondChildVoteTAG: 0
SecondChildTAG: Not really. It is not the significance of the difference that makes it discrete. It is that there are regular intervals (i.e. I get paid £1000.01 or £1000.02)
SecondChildUserIdTAG: 164614
SecondChildUserNameTAG: LuketheEngineer
SecondChildCreateTimeTAG: 2013-02-21T21:02:15Z
SecondChildVoteTAG: 0
FirstChildTAG: I was thinking the same thing! After getting it wrong I was thinking an extreme example..lets say that your income is only 1 cent and your job cuts 50% off of all salaries..well you will end up theoretically with half cent income..it can happen but it's a tricky question..and in real world u would take zero or one cents..I guess banks deal with these weird numbers a lot..I am not sure though that this is the right answer
FirstChildUserIdTAG: 1235644
FirstChildUserNameTAG: Evmorfili
FirstChildCreateTimeTAG: 2013-02-21T13:33:21Z
FirstChildVoteTAG: 0
FirstChildTAG: > for example, if you ask people in different countries for their annual income, you might get answers like "40000 Euros, which corresponds to 52770.44855 USD according to the current exchange rate"
No, that is just a unit conversion problem.
Income is a discrete quantity, as there is no way you can have arbitrarily many income levels, given the currency.
To be honest, to have the first question already graded 'wrongly' is not a good introduction to this course. Hopefully it will improve.
FirstChildUserIdTAG: 1261484
FirstChildUserNameTAG: Saverio001
FirstChildCreateTimeTAG: 2013-02-21T18:05:16Z
FirstChildVoteTAG: 1
SecondChildTAG: I would say that currency is a discrete quantity, but income can be quite continuous, when you apply all the taxes and whatnot you could get an amount which goes to a number smaller than cents. Think about gas prices. That we don't care about certain quantities doesn't mean that they are not important on a bigger scale.
My two cents ;)
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-21T19:55:28Z
SecondChildVoteTAG: 0
SecondChildTAG: Well, currency is not a *quantity* just something to account for discrete quantities of "money"
SecondChildUserIdTAG: 250161
SecondChildUserNameTAG: gaurwraith
SecondChildCreateTimeTAG: 2013-02-21T19:57:06Z
SecondChildVoteTAG: 0
IndexTAG: 2901
TitleTAG: Downloadable video
Hi,
In CS169,1x, they offered a way to download videos from youtube. It was very useful because you don't need to stream it everytime. Is there any way we can get same here?
Thanks,
Santhosh
UserIdTAG: 985263
UserNameTAG: santhosh_chn
CreateTimeTAG: 2013-02-21T13:04:26Z
VoteTAG: 4
CoursewareTAG: undefined
NumberOfReplyTAG: 2
FirstChildTAG: Nice Suggestion
FirstChildUserIdTAG: 169509
FirstChildUserNameTAG: rajeevbasapathy
FirstChildCreateTimeTAG: 2013-02-21T15:21:58Z
FirstChildVoteTAG: 0
FirstChildTAG: Friends we have a download option right below the video. You can also try this YouTube channel.
https://www.youtube.com/watch?feature=player_embedded&v=avdX8vhEqTc
FirstChildUserIdTAG: 985263
FirstChildUserNameTAG: santhosh_chn
FirstChildCreateTimeTAG: 2013-02-22T15:05:37Z
FirstChildVoteTAG: 0
IndexTAG: 2902
TitleTAG: Format of answer required when it is a percentage e.g. Ex Set 2 prob 2
Before I get downgraded by an automatic grader, could someone please confirm whether you enter 3.4 or 3.4% as an answer to a question like Ex Set 2 Prob 2 (just using random numbers not a real answer by the way!) Also Ex Set Prob 6 does not specify decimal place - is it to 1 decimal place even if the answer is a whole number e.g. 3.0, 3, 3.0% or 3%
UserIdTAG: 18229
UserNameTAG: TonyRBH
CreateTimeTAG: 2013-02-21T13:03:36Z
VoteTAG: 1
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: you can check the practice sheet if you already haven't .
i have given the test and i have observed that in case of a value like 3.0 just writing 3 will do but for a value like 3.46 ..... answers are taken to one decimal place .... i.e. 3.4
Hope this helps.
FirstChildUserIdTAG: 815079
FirstChildUserNameTAG: rchannan
FirstChildCreateTimeTAG: 2013-02-21T13:30:57Z
FirstChildVoteTAG: 0
SecondChildTAG: for the 2nd last question where they hv asked for the ht f the bar from -10 to 20 why is the width=10
is it not 20-(-10)=30?
SecondChildUserIdTAG: 584622
SecondChildUserNameTAG: deepikavora
SecondChildCreateTimeTAG: 2013-02-21T13:42:27Z
SecondChildVoteTAG: 0
FirstChildTAG: I was graded wrong when giving the answer 11.11% while the answer is 11.1%
FirstChildUserIdTAG: 996971
FirstChildUserNameTAG: ntanhhong
FirstChildCreateTimeTAG: 2013-02-21T13:55:26Z
FirstChildVoteTAG: 4
FirstChildTAG: This really annoying when your answer is more accurate than the expected one and you get that horrible cross. The cross should go to whoever set the question without specifying the accuracy required. And with all the delay surely the material could have been spell-checked.
FirstChildUserIdTAG: 7854
FirstChildUserNameTAG: pejic
FirstChildCreateTimeTAG: 2013-02-21T14:22:49Z
FirstChildVoteTAG: 4
IndexTAG: 2903
TitleTAG: Exercise set 2, Problem 1 a)
Are you certain that the supplied answer to this problem is correct?
When considering the question of which interval contains the most people don't we look at the percentage (area of the bar in a histogram) provided in the table?
I understand that the 15-20 bin is more crowded, however, doesn't the question relate to the number of people in regards to total population, i.e., the percentage?
UserIdTAG: 1229358
UserNameTAG: Outbound
CreateTimeTAG: 2013-02-21T12:27:16Z
VoteTAG: 11
CoursewareTAG: undefined
NumberOfReplyTAG: 3
FirstChildTAG: true, I made the same mistake (?)
FirstChildUserIdTAG: 916306
FirstChildUserNameTAG: GMakl
FirstChildCreateTimeTAG: 2013-02-21T12:45:04Z
FirstChildVoteTAG: 0
SecondChildTAG: As did I
SecondChildUserIdTAG: 15436
SecondChildUserNameTAG: peterprinciple
SecondChildCreateTimeTAG: 2013-02-21T14:30:55Z
SecondChildVoteTAG: 0
FirstChildTAG: Within these part the "good" answers are not the good answers.
It has been discussed already in these topic:
https://www.edx.org/courses/BerkeleyX/Stat2.1x/2013_Spring/discussion/forum/i4x-BerkeleyX-Stat2_1x-course-2013_Spring/threads/5125802a191b9b2200000112
FirstChildUserIdTAG: 1232601
FirstChildUserNameTAG: Firefly-2009
FirstChildCreateTimeTAG: 2013-02-21T12:50:01Z
FirstChildVoteTAG: 2
SecondChildTAG: well done, Firefly-2009!!!
SecondChildUserIdTAG: 975492
SecondChildUserNameTAG: alexmc1973
SecondChildCreateTimeTAG: 2013-02-21T14:09:10Z
SecondChildVoteTAG: 0
FirstChildTAG: Hi Susan Austin could you please help(again)
FirstChildUserIdTAG: 360390
FirstChildUserNameTAG: sangeetasaxena
FirstChildCreateTimeTAG: 2013-02-21T13:47:47Z
FirstChildVoteTAG: 0
SecondChildTAG: As said above, this is a true mistake. It will be fixed, eventually, and marks awarded.
SecondChildUserIdTAG: 629320
SecondChildUserNameTAG: SusanAust
SecondChildCreateTimeTAG: 2013-02-22T02:31:01Z
SecondChildVoteTAG: 0
IndexTAG: 2904
TitleTAG: For those having trouble reading the online textbook
If you're like me, the formatting of this course's online textbook is a real pain to read because of its width.
Here's how to fix that in Google Chrome:
Right click near the top of the page, and select 'Inspect Element'.
In the left pane, you should see a bunch of HTML. Find the tag '