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RE: can s-exprs represent a graph without eval?
Shriram Krishnamurthi wrote:
> and you want their background colors to alternate: white, grey, white,
> grey, .... Set COLORS to
> '#0=("white" "grey" #0#)
> Now you can peel off the CAR and CDR of COLORS for as many names as
> there are on your list.
First Guy, now you - clear evidence that these list shenanigans are too much
for the human brain! ;) If that's Scheme, I think you mean:
'#0=("white" "grey" . #0#)
Ever since I first saw it, I've liked the way lazy languages allow you to
achieve the same end, e.g. in Haskell:
colors = "white" : "grey" : colors
It's a very direct expression of the desired result.