[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: continuations

That's not how I would have explained the difference. Consider this. 
Here is how you define the-current-continuation: 

 (define (the-current-continuation) (call/cc (lambda (x) x)))

Now implement call/cc. Hint: The solution is in one of my early papers,
including calculations. Hint-: It's not in the on-line biblio we just
saw. So don't peek :-) 

More tomorrow -- Matthias